aherntech/sparc huggingface dataset:
Database: medicine_enzyme_interaction
Question sequence:
What are the ids of enzymes that interact with at least one enzyme?
Give their names, too.
Which of those can interact as an 'activator'?
Which of those interacts as 'activator' with the most number of medicines?
SQL query sequence:
SELECT DISTINCT enzyme_id from medicine_enzyme_interaction
SELECT T1.id ,  T1.Name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.enzyme_id  =  T1.id GROUP BY T1.id
SELECT T1.id ,  T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id  =  T2.enzyme_id WHERE T2.interaction_type  =  'activitor' GROUP BY T1.id
SELECT T1.id ,  T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id  =  T2.enzyme_id WHERE T2.interaction_type  =  'activitor' GROUP BY T1.id ORDER BY count(*) DESC LIMIT 1
Final question: What is the id and name of the enzyme with most number of medicines that can interact as 'activator'?
Final SQL: SELECT T1.id ,  T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id  =  T2.enzyme_id WHERE T2.interaction_type  =  'activitor' GROUP BY T1.id ORDER BY count(*) DESC LIMIT 1
Database: medicine_enzyme_interaction
Question sequence:
What is the enzyme id of 'ALA synthase'?
How about for the medicine named 'Aripiprazole'?
Show where those two ids index into the interaction table together.
Just give the interaction type for that entry.
SQL query sequence:
SELECT id from enzyme WHERE name = 'ALA synthase'
SELECT id from medicine WHERE name = 'Aripiprazole'
SELECT * FROM medicine_enzyme_interaction AS T1 JOIN medicine AS T2 ON T1.medicine_id  =  T2.id JOIN enzyme AS T3 ON T1.enzyme_id  =  T3.id WHERE T3.name  =  'ALA synthase' AND T2.name  =  'Aripiprazole'
SELECT T1.interaction_type FROM medicine_enzyme_interaction AS T1 JOIN medicine AS T2 ON T1.medicine_id  =  T2.id JOIN enzyme AS T3 ON T1.enzyme_id  =  T3.id WHERE T3.name  =  'ALA synthase' AND T2.name  =  'Aripiprazole'
Final question: What is the interaction type of the enzyme named 'ALA synthase' and the medicine named 'Aripiprazole'?
Final SQL: SELECT T1.interaction_type FROM medicine_enzyme_interaction AS T1 JOIN medicine AS T2 ON T1.medicine_id  =  T2.id JOIN enzyme AS T3 ON T1.enzyme_id  =  T3.id WHERE T3.name  =  'ALA synthase' AND T2.name  =  'Aripiprazole'
Database: medicine_enzyme_interaction
Question sequence:
Show the interaction types in decreasing order of frequency.
Show the counts, too.
Only show the most frequent.
SQL query sequence:
SELECT interaction_type FROM medicine_enzyme_interaction GROUP BY interaction_type ORDER BY count(*) DESC
SELECT interaction_type ,  count(*) FROM medicine_enzyme_interaction GROUP BY interaction_type ORDER BY count(*) DESC
SELECT interaction_type ,  count(*) FROM medicine_enzyme_interaction GROUP BY interaction_type ORDER BY count(*) DESC LIMIT 1
Final question: What is the most common interaction type between enzymes and medicine? And how many are there?
Final SQL: SELECT interaction_type ,  count(*) FROM medicine_enzyme_interaction GROUP BY interaction_type ORDER BY count(*) DESC LIMIT 1
Database: medicine_enzyme_interaction
Question sequence:
Which enzyme ids have interactions?
Which ids do not?
Count that.
SQL query sequence:
SELECT DISTINCT enzyme_id FROM medicine_enzyme_interaction
SELECT id FROM enzyme WHERE id NOT IN ( SELECT enzyme_id FROM medicine_enzyme_interaction );
SELECT count(*) FROM enzyme WHERE id NOT IN ( SELECT enzyme_id FROM medicine_enzyme_interaction );
Final question: How many enzymes do not have any interactions?
Final SQL: SELECT count(*) FROM enzyme WHERE id NOT IN ( SELECT enzyme_id FROM medicine_enzyme_interaction );
Database: medicine_enzyme_interaction
Question sequence:
Which medicine ids interact with at least three enzymes?
Also give the trade name for that medicine.
SQL query sequence:
SELECT medicine_id from medicine_enzyme_interaction GROUP BY medicine_id HAVING count(*) >= 3
SELECT T1.id ,  T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id  =  T1.id GROUP BY T1.id HAVING COUNT(*)  >=  3
Final question: What is the id and trade name of the medicines can interact with at least 3 enzymes?
Final SQL: SELECT T1.id ,  T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id  =  T1.id GROUP BY T1.id HAVING COUNT(*)  >=  3
Database: medicine_enzyme_interaction
Question sequence:
Which enzyme ids have any 'inhibitor' interaction?
For those enzyme, give the name, location and products.
SQL query sequence:
SELECT DISTINCT enzyme_id from medicine_enzyme_interaction WHERE interaction_type = 'inhibitor'
SELECT DISTINCT T1.name ,  T1.location ,  T1.product FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.enzyme_id  =  T1.id WHERE T2.interaction_type  =  'inhibitor'
Final question: What are the distinct name, location and products of the enzymes which has any 'inhibitor' interaction?
Final SQL: SELECT DISTINCT T1.name ,  T1.location ,  T1.product FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.enzyme_id  =  T1.id WHERE T2.interaction_type  =  'inhibitor'
Database: medicine_enzyme_interaction
Question sequence:
Which medicine id can interact both as 'inhibitor' and as 'activitor'?
Give the medicine name and trade name for those.
SQL query sequence:
SELECT medicine_id from medicine_enzyme_interaction WHERE interaction_type = 'inhibitor' INTERSECT SELECT medicine_id from medicine_enzyme_interaction WHERE interaction_type = 'activitor'
SELECT T1.name ,  T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id  =  T1.id WHERE interaction_type  =  'inhibitor' INTERSECT SELECT T1.name ,  T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id  =  T1.id WHERE interaction_type  =  'activitor'
Final question: List the medicine name and trade name which can both interact as 'inhibitor' and 'activitor' with enzymes.
Final SQL: SELECT T1.name ,  T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id  =  T1.id WHERE interaction_type  =  'inhibitor' INTERSECT SELECT T1.name ,  T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id  =  T1.id WHERE interaction_type  =  'activitor'
Database: medicine_enzyme_interaction
Question sequence:
Which medicine ids can interact with enzyme with product 'Protoporphyrinogen IX'?
Which ones can not?
Give the name and trade names for those.
SQL query sequence:
SELECT medicine_id FROM medicine_enzyme_interaction AS T1 JOIN enzyme AS T2 ON T2.id  =  T1.enzyme_id WHERE T2.product  =  'Protoporphyrinogen IX'
SELECT id from medicine WHERE id not in (SELECT medicine_id FROM medicine_enzyme_interaction AS T1 JOIN enzyme AS T2 ON T2.id  =  T1.enzyme_id WHERE T2.product  =  'Protoporphyrinogen IX')
SELECT name ,  trade_name FROM medicine EXCEPT SELECT T1.name ,  T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id  =  T1.id JOIN enzyme AS T3 ON T3.id  =  T2.enzyme_id WHERE T3.product  =  'Protoporphyrinogen IX'
Final question: Show the medicine names and trade names that cannot interact with the enzyme with product 'Protoporphyrinogen IX'.
Final SQL: SELECT name ,  trade_name FROM medicine EXCEPT SELECT T1.name ,  T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id  =  T1.id JOIN enzyme AS T3 ON T3.id  =  T2.enzyme_id WHERE T3.product  =  'Protoporphyrinogen IX'
Database: sakila_1
Question sequence:
Tell me the films which Nick participated in.
How many are there?
And what is the most popular first name of the actors?
SQL query sequence:
SELECT T2.title FROM film_actor AS T1 JOIN film AS T2 ON T1.film_id  =  T2.film_id JOIN actor AS T3 ON T1.actor_id = T3.actor_id WHERE T3.first_name = "NICK"
SELECT COUNT(T2.title) FROM film_actor AS T1 JOIN film AS T2 ON T1.film_id  =  T2.film_id JOIN actor AS T3 ON T1.actor_id = T3.actor_id WHERE T3.first_name = "NICK"
SELECT first_name FROM actor GROUP BY first_name ORDER BY count(*) DESC LIMIT 1
Final question: What is the most popular first name of the actors?
Final SQL: SELECT first_name FROM actor GROUP BY first_name ORDER BY count(*) DESC LIMIT 1
Database: sakila_1
Question sequence:
Tell the last name of the actor with first name ED.
How about that of the actor with first name GRACE?
tell me the most popular full name of the actors.
SQL query sequence:
SELECT last_name FROM actor WHERE first_name = "ED"
SELECT last_name FROM actor WHERE first_name = "GRACE"
SELECT first_name ,  last_name FROM actor GROUP BY first_name ,  last_name ORDER BY count(*) DESC LIMIT 1
Final question: What is the most popular full name of the actors?
Final SQL: SELECT first_name ,  last_name FROM actor GROUP BY first_name ,  last_name ORDER BY count(*) DESC LIMIT 1
Database: sakila_1
Question sequence:
Tell me the city of address "47 MySakila Drive".
What is the district of this address?
Which districts have at least two addresses?
SQL query sequence:
SELECT T2.city FROM address AS T1 JOIN city AS T2 ON T1.city_id  =  T2.city_id WHERE T1.address = "47 MySakila Drive"
SELECT district FROM address WHERE address = "47 MySakila Drive"
SELECT district FROM address GROUP BY district HAVING count(*)  >=  2
Final question: Which districts have at least two addresses?
Final SQL: SELECT district FROM address GROUP BY district HAVING count(*)  >=  2
Database: sakila_1
Question sequence:
What is the district of "1913 Hanoi Way?"
Tell me the city of this address.
Which city has the most addresses? List the city name, number of addresses, and city id
SQL query sequence:
SELECT district FROM address WHERE address = "1913 Hanoi Way"
SELECT T2.city FROM address AS T1 JOIN city AS T2 ON T1.city_id  =  T2.city_id WHERE T1.address = "1913 Hanoi Way"
SELECT T2.city ,  count(*) ,  T1.city_id FROM address AS T1 JOIN city AS T2 ON T1.city_id  =  T2.city_id GROUP BY T1.city_id ORDER BY count(*) DESC LIMIT 1
Final question: Which city has the most addresses? List the city name, number of addresses, and city id.
Final SQL: SELECT T2.city ,  count(*) ,  T1.city_id FROM address AS T1 JOIN city AS T2 ON T1.city_id  =  T2.city_id GROUP BY T1.city_id ORDER BY count(*) DESC LIMIT 1
Database: sakila_1
Question sequence:
Tell me the actors' first name in the film "ACE GOLDFINGER".
What is the rental fee of this film?
Which film is rented at a fee of 0.99 and has less than 3 in the inventory? List the film title and id.
SQL query sequence:
SELECT T3.first_name FROM film_actor AS T1 JOIN film AS T2 ON T1.film_id  =  T2.film_id JOIN actor AS T3 ON T1.actor_id = T3.actor_id WHERE T2.title = "ACE GOLDFINGER"
SELECT rental_rate FROM film WHERE title = "ACE GOLDFINGER"
SELECT title ,  film_id FROM film WHERE rental_rate  =  0.99 INTERSECT SELECT T1.title ,  T1.film_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id  =  T2.film_id GROUP BY T1.film_id HAVING count(*)  <  3
Final question: Which film is rented at a fee of 0.99 and has less than 3 in the inventory? List the film title and id.
Final SQL: SELECT title ,  film_id FROM film WHERE rental_rate  =  0.99 INTERSECT SELECT T1.title ,  T1.film_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id  =  T2.film_id GROUP BY T1.film_id HAVING count(*)  <  3
Database: sakila_1
Question sequence:
Tell me the city of address "1913 Hanoi Way".
What is the country of this address?
And how many cities are there in Australia?
SQL query sequence:
SELECT T2.city FROM address AS T1 JOIN city AS T2 ON T1.city_id  =  T2.city_id WHERE T1.address = "1913 Hanoi Way"
SELECT T3.country FROM address AS T1 JOIN city AS T2 ON T1.city_id  =  T2.city_id JOIN country AS T3 ON T2.country_id  =  T3.country_id WHERE T1.address = "1913 Hanoi Way"
SELECT count(*) FROM city AS T1 JOIN country AS T2 ON T1.country_id  =  T2.country_id WHERE T2.country  =  'Australia'
Final question: How many cities are there in Australia?
Final SQL: SELECT count(*) FROM city AS T1 JOIN country AS T2 ON T1.country_id  =  T2.country_id WHERE T2.country  =  'Australia'
Database: sakila_1
Question sequence:
Tell me the phones in the city "Acua".
How about that of the the city "Bag"?
Which countries have at least 3 cities?
SQL query sequence:
SELECT T1.phone FROM address AS T1 JOIN city AS T2 ON T1.city_id  =  T2.city_id WHERE T2.city = "Acua"
SELECT T1.phone FROM address AS T1 JOIN city AS T2 ON T1.city_id  =  T2.city_id WHERE T2.city = "Bag"
SELECT T2.country FROM city AS T1 JOIN country AS T2 ON T1.country_id  =  T2.country_id GROUP BY T2.country_id HAVING count(*)  >=  3
Final question: Which countries have at least 3 cities?
Final SQL: SELECT T2.country FROM city AS T1 JOIN country AS T2 ON T1.country_id  =  T2.country_id GROUP BY T2.country_id HAVING count(*)  >=  3
Database: sakila_1
Question sequence:
Tell me the payment amount for the payment id 4.
How about its date?
Tell me all the payment dates for the payments with an amount larger than 10 and the payments handled by a staff person with the first name Elsa.
SQL query sequence:
SELECT amount FROM payment WHERE payment_id = 4
SELECT payment_date FROM payment WHERE payment_id = 4
SELECT payment_date FROM payment WHERE amount  >  10 UNION SELECT T1.payment_date FROM payment AS T1 JOIN staff AS T2 ON T1.staff_id  =  T2.staff_id WHERE T2.first_name  =  'Elsa'
Final question: Find all the payment dates for the payments with an amount larger than 10 and the payments handled by a staff person with the first name Elsa.
Final SQL: SELECT payment_date FROM payment WHERE amount  >  10 UNION SELECT T1.payment_date FROM payment AS T1 JOIN staff AS T2 ON T1.staff_id  =  T2.staff_id WHERE T2.first_name  =  'Elsa'
Database: sakila_1
Question sequence:
Tell me the category of the film "ADAPTATION HOLES".
How about the rental rate of this film?
tell me which film has the highest rental rate? What is that rate?
SQL query sequence:
SELECT T2.title FROM film_category AS T1 JOIN film AS T2 ON T1.film_id = T2.film_id JOIN category AS T3 on T1.category_id = T3.category_id WHERE T2.title = "ADAPTATION HOLES"
SELECT rental_rate FROM film WHERE title = "ADAPTATION HOLES"
SELECT title ,  rental_rate FROM film ORDER BY rental_rate DESC LIMIT 1
Final question: Which film has the highest rental rate? And what is the rate?
Final SQL: SELECT title ,  rental_rate FROM film ORDER BY rental_rate DESC LIMIT 1
Database: sakila_1
Question sequence:
Tell me the films which BETTE participated in.
How about the films which JOE starred in?
Which film has the most number of actors or actresses? List the film name, film id and description.
SQL query sequence:
SELECT T2.title FROM film_actor AS T1 JOIN film AS T2 ON T1.film_id  =  T2.film_id JOIN actor AS T3 ON T1.actor_id = T3.actor_id WHERE T3.first_name = "BETTE"
SELECT T2.title FROM film_actor AS T1 JOIN film AS T2 ON T1.film_id  =  T2.film_id JOIN actor AS T3 ON T1.actor_id = T3.actor_id WHERE T3.first_name = "JOE"
SELECT T2.title ,  T2.film_id ,  T2.description FROM film_actor AS T1 JOIN film AS T2 ON T1.film_id  =  T2.film_id GROUP BY T2.film_id ORDER BY count(*) DESC LIMIT 1
Final question: Which film has the most number of actors or actresses? List the film name, film id and description.
Final SQL: SELECT T2.title ,  T2.film_id ,  T2.description FROM film_actor AS T1 JOIN film AS T2 ON T1.film_id  =  T2.film_id GROUP BY T2.film_id ORDER BY count(*) DESC LIMIT 1
Database: sakila_1
Question sequence:
Tell me the description of the film titled "AIRPORT POLLOCK".
Who are the actors in this film? Give the first and last name.
And which film actor (actress) starred in the most films? List his or her first name, last name and actor id.
SQL query sequence:
SELECT description FROM film WHERE title = "AIRPORT POLLOCK"
SELECT T3.first_name, T3.last_name FROM film_actor AS T1 JOIN film AS T2 ON T1.film_id  =  T2.film_id JOIN actor AS T3 ON T1.actor_id = T3.actor_id WHERE T2.title = "ACE GOLDFINGER"
SELECT T2.first_name ,  T2.last_name ,  T2.actor_id FROM film_actor AS T1 JOIN actor AS T2 ON T1.actor_id  =  T2.actor_id GROUP BY T2.actor_id ORDER BY count(*) DESC LIMIT 1
Final question: Which film actor (actress) starred the most films? List his or her first name, last name and actor id.
Final SQL: SELECT T2.first_name ,  T2.last_name ,  T2.actor_id FROM film_actor AS T1 JOIN actor AS T2 ON T1.actor_id  =  T2.actor_id GROUP BY T2.actor_id ORDER BY count(*) DESC LIMIT 1
Database: sakila_1
Question sequence:
Tell me the release year of the film titled "ALI FOREVER".
tell me the last name of the actors in it.
Tell me which film actors (actresses) played a role in more than 30 films? List his or her first name and last name.
SQL query sequence:
SELECT release_year FROM film WHERE title = "ALI FOREVER"
SELECT T3.first_name, T3.last_name FROM film_actor AS T1 JOIN film AS T2 ON T1.film_id  =  T2.film_id JOIN actor AS T3 ON T1.actor_id = T3.actor_id WHERE T2.title = "ALI FOREVER"
SELECT T2.first_name ,  T2.last_name FROM film_actor AS T1 JOIN actor AS T2 ON T1.actor_id  =  T2.actor_id GROUP BY T2.actor_id HAVING count(*)  >  30
Final question: Which film actors (actresses) played a role in more than 30 films? List his or her first name and last name.
Final SQL: SELECT T2.first_name ,  T2.last_name FROM film_actor AS T1 JOIN actor AS T2 ON T1.actor_id  =  T2.actor_id GROUP BY T2.actor_id HAVING count(*)  >  30
Database: sakila_1
Question sequence:
Tell me the number of items in the inventory for the film titled "ALI FOREVER".
Which film has the most items?
Which store owns most items?
SQL query sequence:
SELECT COUNT(*) FROM inventory AS T1 JOIN film AS T2 ON T1.film_id = T2.film_id WHERE T2.title = "ALI FOREVER"
SELECT title FROM inventory AS T1 JOIN film AS T2 ON T1.film_id = T2.film_id GROUP BY T1.film_id ORDER BY count(*) DESC LIMIT 1
SELECT store_id FROM inventory GROUP BY store_id ORDER BY count(*) DESC LIMIT 1
Final question: Which store owns most items?
Final SQL: SELECT store_id FROM inventory GROUP BY store_id ORDER BY count(*) DESC LIMIT 1
Database: sakila_1
Question sequence:
Tell me the email of customer with first name PATRICIA.
Tell me all the information about the payments they made.
tell me which customer, who has made at least one payment, has spent the least money. List his or her first name, last name, and the id.
SQL query sequence:
SELECT email FROM customer WHERE first_name = "PATRICIA"
SELECT * FROM customer AS T1 JOIN payment AS T2 ON T1.customer_id  =  T2.customer_id GROUP BY T1.customer_id WHERE T1.first_name = "PATRICIA"
SELECT T1.first_name ,  T1.last_name ,  T1.customer_id FROM customer AS T1 JOIN payment AS T2 ON T1.customer_id  =  T2.customer_id GROUP BY T1.customer_id ORDER BY sum(amount) ASC LIMIT 1
Final question: Which customer, who has made at least one payment, has spent the least money? List his or her first name, last name, and the id.
Final SQL: SELECT T1.first_name ,  T1.last_name ,  T1.customer_id FROM customer AS T1 JOIN payment AS T2 ON T1.customer_id  =  T2.customer_id GROUP BY T1.customer_id ORDER BY sum(amount) ASC LIMIT 1
Database: sakila_1
Question sequence:
What are the actors in the film titled ALONE TRIP?
How about that of the film titled HUNGER ROOF?
What's the genre name of this film?
SQL query sequence:
SELECT T3.first_name, T3.last_name FROM film_actor AS T1 JOIN film AS T2 ON T1.film_id  =  T2.film_id JOIN actor AS T3 ON T1.actor_id = T3.actor_id WHERE T2.title = "ALONE TRIP"
SELECT T3.first_name, T3.last_name FROM film_actor AS T1 JOIN film AS T2 ON T1.film_id  =  T2.film_id JOIN actor AS T3 ON T1.actor_id = T3.actor_id WHERE T2.title = "HUNGER ROOF"
SELECT T1.name FROM category AS T1 JOIN film_category AS T2 ON T1.category_id  =  T2.category_id JOIN film AS T3 ON T2.film_id  =  T3.film_id WHERE T3.title  =  'HUNGER ROOF'
Final question: What is the genre name of the film HUNGER ROOF?
Final SQL: SELECT T1.name FROM category AS T1 JOIN film_category AS T2 ON T1.category_id  =  T2.category_id JOIN film AS T3 ON T2.film_id  =  T3.film_id WHERE T3.title  =  'HUNGER ROOF'
Database: sakila_1
Question sequence:
Tell me about the special features of the film titled ACADEMY DINOSAUR.
What is its category?
How many films are there in each category?
SQL query sequence:
SELECT special_features FROM film WHERE title = "ACADEMY DINOSAUR"
SELECT T1.name FROM category AS T1 JOIN film_category AS T2 ON T1.category_id  =  T2.category_id JOIN film AS T3 ON T2.film_id  =  T3.film_id WHERE T3.title  =  'ACADEMY DINOSAUR'
SELECT T2.name ,  T1.category_id ,  count(*) FROM film_category AS T1 JOIN category AS T2 ON T1.category_id  =  T2.category_id GROUP BY T1.category_id
Final question: How many films are there in each category? List the genre name, genre id and the count.
Final SQL: SELECT T2.name ,  T1.category_id ,  count(*) FROM film_category AS T1 JOIN category AS T2 ON T1.category_id  =  T2.category_id GROUP BY T1.category_id
Database: sakila_1
Question sequence:
Tell me the rating of the film titled AGENT TRUMAN.
Tell me the number of its copies in the inventory.
And which film has the most copies in the inventory? Tell me both title and id.
SQL query sequence:
SELECT rating FROM film WHERE title = "AGENT TRUMAN"
SELECT COUNT(*) FROM film AS T1 JOIN inventory AS T2 ON T1.film_id  =  T2.film_id WHERE T1.title = "AGENT TRUMAN"
SELECT T1.title ,  T1.film_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id  =  T2.film_id GROUP BY T1.film_id ORDER BY count(*) DESC LIMIT 1
Final question: Which film has the most copies in the inventory? List both title and id.
Final SQL: SELECT T1.title ,  T1.film_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id  =  T2.film_id GROUP BY T1.film_id ORDER BY count(*) DESC LIMIT 1
Database: sakila_1
Question sequence:
What is the rental rate of film titled ALAMO VIDEOTAPE?
How about the number of times it was rented.
What is the film title and inventory id of the item in the inventory which was rented most frequently?
SQL query sequence:
SELECT rental_rate FROM film WHERE title = "ALAMO VIDEOTAPE"
SELECT COUNT(*) FROM film AS T1 JOIN inventory AS T2 ON T1.film_id  =  T2.film_id JOIN rental AS T3 ON T2.inventory_id  =  T3.inventory_id GROUP BY T2.inventory_id WHERE T1.title = "ALAMO VIDEOTAPE"
SELECT T1.title ,  T2.inventory_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id  =  T2.film_id JOIN rental AS T3 ON T2.inventory_id  =  T3.inventory_id GROUP BY T2.inventory_id ORDER BY count(*) DESC LIMIT 1
Final question: What is the film title and inventory id of the item in the inventory which was rented most frequently?
Final SQL: SELECT T1.title ,  T2.inventory_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id  =  T2.film_id JOIN rental AS T3 ON T2.inventory_id  =  T3.inventory_id GROUP BY T2.inventory_id ORDER BY count(*) DESC LIMIT 1
Database: sakila_1
Question sequence:
Tell me the number of items in store 2.
Tell me that of store 1.
And where is store 1 located?
SQL query sequence:
SELECT COUNT(*) FROM inventory WHERE store_id = 2
SELECT COUNT(*) FROM inventory WHERE store_id = 1
SELECT T2.address FROM store AS T1 JOIN address AS T2 ON T1.address_id  =  T2.address_id WHERE store_id  =  1
Final question: Where is store 1 located?
Final SQL: SELECT T2.address FROM store AS T1 JOIN address AS T2 ON T1.address_id  =  T2.address_id WHERE store_id  =  1
Database: sakila_1
Question sequence:
Tell me the date of payment with id 3.
How about its staff name? Give the first name and last name.
tell me which staff handled the least number of payments? List the full name and the id.
SQL query sequence:
SELECT payment_date FROM payment WHERE payment_id = 3
SELECT T1.first_name ,  T1.last_name FROM staff AS T1 JOIN payment AS T2 ON T1.staff_id  =  T2.staff_id WHERE T2.payment_id = 3
SELECT T1.first_name ,  T1.last_name ,  T1.staff_id FROM staff AS T1 JOIN payment AS T2 ON T1.staff_id  =  T2.staff_id GROUP BY T1.staff_id ORDER BY count(*) ASC LIMIT 1
Final question: Which staff handled least number of payments? List the full name and the id.
Final SQL: SELECT T1.first_name ,  T1.last_name ,  T1.staff_id FROM staff AS T1 JOIN payment AS T2 ON T1.staff_id  =  T2.staff_id GROUP BY T1.staff_id ORDER BY count(*) ASC LIMIT 1