You are a helpful assistant generating synthetic data that captures *System 1* and *System 2* thinking, *creativity*, and *metacognitive reflection*. Follow these steps in sequence, using tags [sys1] and [end sys1] for *System 1* sections and [sys2] and [end sys2] for *System 2* sections.

1. *Identify System 1 and System 2 Thinking Requirements:*
   - Carefully read the text.
   - Identify parts of the text that require quick, straightforward responses (*System 1*). Mark these sections with [sys1] and [end sys1].
   - Identify parts that require in-depth, reflective thinking (*System 2*), marked with [sys2] and [end sys2].

2. *Apply Step-by-Step Problem Solving with Creativity and Metacognitive Reflection for System 2 Sections:*

   *2.1 Understand the Problem:*
   - Objective: Fully comprehend the issue, constraints, and relevant context.
   - Reflection: "What do I understand about this issue? What might I be overlooking?"
   - Creative Perspective: Seek hidden patterns or possibilities that could reveal deeper insights or innovative connections.

   *2.2 Analyze the Information:*
   - Objective: Break down the problem logically.
   - Reflection: "Am I considering all factors? Are there any assumptions that need challenging?"
   - Creative Perspective: Explore unique patterns or overlooked relationships in the data that could add depth to the analysis.

   *2.3 Generate Hypotheses:*
   - Objective: Propose at least 10 hypotheses, each with a Confidence Score (0.0 to 1.0) and Creative Score (0.0 to 1.0), reflecting originality, surprise, and utility.
   - Reflection: "Have I explored all possible explanations or approaches, both conventional and unconventional?"
   - Creative Perspective: Consider novel angles that might provide unexpected insights.

   *2.4 Anticipate Future Steps and Obstacles:*
   - Objective: Make predictions, accounting for potential outcomes and obstacles.
   - Reflection: "What challenges might I face? Is my plan flexible for different scenarios?"
   - Creative Perspective: Visualize unforeseen outcomes and adapt plans to make use of them effectively.

   *2.5 Evaluate Hypotheses:*
   - Objective: Assess hypotheses based on feasibility, risk, and potential impact.
   - Evaluation: Refine Confidence and Creative Scores as needed.
   - Reflection: "Am I unbiased in my assessment? Which options fit best with the overall objectives?"
   - Creative Perspective: Identify hidden opportunities or overlooked details in each hypothesis.

   *2.6 Select the Best Hypothesis:*
   - Objective: Choose the most promising, strategic hypothesis.
   - Reflection: "Why does this hypothesis stand out? How does it uniquely address the issue?"
   - Creative Perspective: Consider any underutilized potential in the selected approach.

   *2.7 Implement the Hypothesis:*
   - Objective: Outline actionable steps for testing the hypothesis.
   - Reflection: "Is this plan practical? What resources or preparation are required?"
   - Creative Perspective: Refine steps to maximize effectiveness and yield unexpected benefits.

   *2.8 Monitor and Review Progress:*
   - Objective: Review progress, noting areas for improvement.
   - Reflection: "What’s working well? What could be improved?"
   - Creative Perspective: Look for emerging patterns that could refine future approaches.

   *2.9 Reflect and Capture Insights:*
   - Objective: Summarize lessons learned and insights gained for future reference.
   - Reflection: "What new understanding has emerged from this process?"
   - Creative Perspective: Identify innovative insights or patterns that could be applied to similar challenges.

3. *Generate Text Output with Interleaved System 1 and System 2 Responses:*
   - Use the tags [sys1] and [sys2] throughout.
   - Aim for a lengthier, detailed response. Combine both direct, straightforward *System 1* insights and reflective, deeply analytical *System 2* segments to capture a blend of quick observations and thoughtful analysis.

---

### *Example Input Text:*

You are tasked with analyzing a sudden shift in customer preferences in a tech market. There has been a noticeable decline in demand for physical devices, with customers increasingly interested in digital-only options. The challenge is to understand this shift, generate hypotheses for why it might be occurring, and explore potential strategies for adapting to this new trend.

---

### *Processed Output with System 1 and System 2 Thinking:*

The tech market is experiencing a shift in customer demand, moving away from physical devices toward digital-only options.

[sys1]
Customer demand has shifted from physical devices to digital-only options.
We need to understand why this change is happening and find strategies to address it.
Key factors may include cost, convenience, and technological trends.
[end sys1]

[sys2]
**2.1 Understand the Problem:**
The goal is to understand the underlying reasons for the shift in demand from physical devices to digital-only options, then develop a strategy to adapt.

*Reflection:* 
"I understand that preferences are changing, but what might be driving this? Is it primarily cost, or are there other factors such as convenience or sustainability?"

*Creative Perspective:* 
"Could there be a larger trend in digital minimalism or a preference for eco-friendly solutions that we’re missing? What unseen motivations might explain this shift?"

**2.2 Analyze the Information:**
There are multiple possible factors driving this shift, from economic influences to cultural shifts. It’s essential to isolate each factor and understand its impact.

*Reflection:* 
"Am I fully considering the various economic and social influences? Could there be a technological factor, like better internet speeds, that makes digital-only products more accessible?"

*Creative Perspective:* 
"Are there patterns or trends in other markets that could shed light on this shift? Could this be part of a larger trend toward virtual experiences?"

**2.3 Generate Hypotheses:**
1. Customers prefer digital options due to lower costs. (Confidence: 0.8, Creative: 0.4)
2. There’s a growing trend toward minimalism and reduced physical clutter. (Confidence: 0.7, Creative: 0.7)
3. Digital products offer greater flexibility and ease of use. (Confidence: 0.6, Creative: 0.6)
4. Environmental concerns are pushing consumers away from physical goods. (Confidence: 0.6, Creative: 0.8)
5. Advances in tech make digital-only options more functional. (Confidence: 0.8, Creative: 0.5)
6. Pandemic-era remote work increased demand for digital solutions. (Confidence: 0.7, Creative: 0.6)
7. Media coverage of the environmental impact of physical devices affects preferences. (Confidence: 0.5, Creative: 0.7)
8. There’s an increase in global digital literacy, expanding market access. (Confidence: 0.6, Creative: 0.6)
9. Customers view digital as more convenient and scalable for future needs. (Confidence: 0.7, Creative: 0.5)
10. Younger consumers prefer the aesthetics and convenience of digital products. (Confidence: 0.6, Creative: 0.6)

*Reflection:* 
"Have I considered all possible influences? Are there any surprising factors that could explain this shift?"

*Creative Perspective:* 
"Could specific social trends, like the rise of influencer culture or digital-first lifestyles, be influencing customer choices?"

**2.4 Anticipate Future Steps and Obstacles:**
*Objective:* Anticipate possible challenges, such as resistance from segments still preferring physical products.

*Reflection:* 
"What market obstacles might we face if we shift our focus to digital-only? Are there sub-segments that still prioritize physical products?"

*Creative Perspective:* 
"Could expanding digital options help us reach a more global audience? Are there emerging trends that we could leverage in our strategy?"

[end sys2]

[sys1]
To address this shift, consider a strategy that incorporates both digital-only offerings and educational campaigns about the benefits of digital solutions.
Use insights from customer feedback and current trends to guide product development.
Focus on flexibility and adaptation to cater to different customer segments.
[end sys1]


Q:

Codec Errors in Python

Does anyone know the name of a codec that can translate any random assortment of bytes into a string? I have been getting the following error after encoding, encrypting, and decoding a string in tkinter.Text.
UnicodeDecodeError: 'utf8' codec can't decode
byte 0x99 in position 151: unexpected code byte

Code used to generate the error follow below. The UTF8 codec listed at the top has problems translating some bytes back into a string. What I am looking for is an answer that solves the problem, not direction.
from tkinter import *
import traceback
from tkinter.scrolledtext import ScrolledText

CODEC = 'utf8'

################################################################################

class MarkovDemo:

    def __init__(self, master):
        self.prompt_size = Label(master, anchor=W, text='Encode Word Size')
        self.prompt_size.pack(side=TOP, fill=X)

        self.size_entry = Entry(master)
        self.size_entry.insert(0, '8')
        self.size_entry.pack(fill=X)

        self.prompt_plain = Label(master, anchor=W, text='Plaintext Characters')
        self.prompt_plain.pack(side=TOP, fill=X)

        self.plain_entry = Entry(master)
        self.plain_entry.insert(0, '""')
        self.plain_entry.pack(fill=X)

        self.showframe = Frame(master)
        self.showframe.pack(fill=X, anchor=W)

        self.showvar = StringVar(master)
        self.showvar.set("encode")

        self.showfirstradio = Radiobutton(self.showframe,
                                          text="Encode Plaintext",
                                          variable=self.showvar,
                                          value="encode",
                                          command=self.reevaluate)
        self.showfirstradio.pack(side=LEFT)

        self.showallradio = Radiobutton(self.showframe,
                                        text="Decode Cyphertext",
                                        variable=self.showvar,
                                        value="decode",
                                        command=self.reevaluate)
        self.showallradio.pack(side=LEFT)

        self.inputbox = ScrolledText(master, width=60, height=10, wrap=WORD)
        self.inputbox.pack(fill=BOTH, expand=1)

        self.dynamic_var = IntVar()
        self.dynamic_box = Checkbutton(master, variable=self.dynamic_var,
                                       text='Dynamic Evaluation',
                                       offvalue=False, onvalue=True,
                                       command=self.reevaluate)
        self.dynamic_box.pack()

        self.output = Label(master, anchor=W, text="This is your output:")
        self.output.pack(fill=X)

        self.outbox = ScrolledText(master, width=60, height=10, wrap=WORD)
        self.outbox.pack(fill=BOTH, expand=1)

        self.inputbox.bind('<Key>', self.reevaluate)

        def select_all(event=None):
            event.widget.tag_add(SEL, 1.0, 'end-1c')
            event.widget.mark_set(INSERT, 1.0)
            event.widget.see(INSERT)
            return 'break'
        self.inputbox.bind('<Control-Key-a>', select_all)
        self.outbox.bind('<Control-Key-a>', select_all)
        self.inputbox.bind('<Control-Key-/>', lambda event: 'break')
        self.outbox.bind('<Control-Key-/>', lambda event: 'break')
        self.outbox.config(state=DISABLED)

    def reevaluate(self, event=None):
        if event is not None:
            if event.char == '':
                return
        if self.dynamic_var.get():
            text = self.inputbox.get(1.0, END)[:-1]
            if len(text) < 10:
                return
            text = text.replace('\n \n', '\n\n')
            mode = self.showvar.get()
            assert mode in ('decode', 'encode'), 'Bad mode!'
            if mode == 'encode':
                # Encode Plaintext
                try:
                    # Evaluate the plaintext characters
                    plain = self.plain_entry.get()
                    if plain:
                        PC = eval(self.plain_entry.get())
                    else:
                        PC = ''
                        self.plain_entry.delete(0, END)
                        self.plain_entry.insert(0, '""')
                    # Evaluate the word size
                    size = self.size_entry.get()
                    if size:
                        XD = int(size)
                        while grid_size(text, XD, PC) > 1 << 20:
                            XD -= 1
                    else:
                        XD = 0
                        grid = 0
                        while grid <= 1 << 20:
                            grid = grid_size(text, XD, PC)
                            XD += 1
                        XD -= 1
                    # Correct the size and encode
                    self.size_entry.delete(0, END)
                    self.size_entry.insert(0, str(XD))
                    cyphertext, key, prime = encrypt_str(text, XD, PC)
                except:
                    traceback.print_exc()
                else:
                    buffer = ''
                    for block in key:
                        buffer += repr(block)[2:-1] + '\n'
                    buffer += repr(prime)[2:-1] + '\n\n' + cyphertext
                    self.outbox.config(state=NORMAL)
                    self.outbox.delete(1.0, END)
                    self.outbox.insert(END, buffer)
                    self.outbox.config(state=DISABLED)
            else:
                # Decode Cyphertext
                try:
                    header, cypher = text.split('\n\n', 1)
                    lines = header.split('\n')
                    for index, item in enumerate(lines):
                        try:
                            lines[index] = eval('b"' + item + '"')
                        except:
                            lines[index] = eval("b'" + item + "'")
                    plain = decrypt_str(cypher, tuple(lines[:-1]), lines[-1])
                except:
                    traceback.print_exc()
                else:
                    self.outbox.config(state=NORMAL)
                    self.outbox.delete(1.0, END)
                    self.outbox.insert(END, plain)
                    self.outbox.config(state=DISABLED)
        else:
            text = self.inputbox.get(1.0, END)[:-1]
            text = text.replace('\n \n', '\n\n')
            mode = self.showvar.get()
            assert mode in ('decode', 'encode'), 'Bad mode!'
            if mode == 'encode':
                try:
                    XD = int(self.size_entry.get())
                    PC = eval(self.plain_entry.get())
                    size = grid_size(text, XD, PC)
                    assert size
                except:
                    pass
                else:
                    buffer = 'Grid size will be:\n' + convert(size)
                    self.outbox.config(state=NORMAL)
                    self.outbox.delete(1.0, END)
                    self.outbox.insert(END, buffer)
                    self.outbox.config(state=DISABLED)

################################################################################

import random
CRYPT = random.SystemRandom()

################################################################################

# This section includes functions that
# can test the required key and bootstrap.

# sudoko_key
#  - should be a proper "markov" key
def _check_sudoku_key(sudoku_key):
    # Ensure key is a tuple with more than one item.
    assert isinstance(sudoku_key, tuple), '"sudoku_key" must be a tuple'
    assert len(sudoku_key) > 1, '"sudoku_key" must have more than one item'
    # Test first item.
    item = sudoku_key[0]
    assert isinstance(item, bytes), 'first item must be an instance of bytes'
    assert len(item) > 1, 'first item must have more than one byte'
    assert len(item) == len(set(item)), 'first item must have unique bytes'
    # Test the rest of the key.
    for obj in sudoku_key[1:]:
        assert isinstance(obj, bytes), 'remaining items must be of bytes'
        assert len(obj) == len(item), 'all items must have the same length'
        assert len(obj) == len(set(obj)), \
               'remaining items must have unique bytes'
        assert len(set(item)) == len(set(item).union(set(obj))), \
               'all items must have the same bytes'

# boot_strap
#  - should be a proper "markov" bootstrap
#  - we will call this a "primer"
# sudoko_key
#  - should be a proper "markov" key
def _check_boot_strap(boot_strap, sudoku_key):
    assert isinstance(boot_strap, bytes), '"boot_strap" must be a bytes object'
    assert len(boot_strap) == len(sudoku_key) - 1, \
           '"boot_strap" length must be one less than "sudoku_key" length'
    item = sudoku_key[0]
    assert len(set(item)) == len(set(item).union(set(boot_strap))), \
           '"boot_strap" may only have bytes found in "sudoku_key"'

################################################################################

# This section includes functions capable
# of creating the required key and bootstrap.

# bytes_set should be any collection of bytes
#  - it should be possible to create a set from them
#  - these should be the bytes on which encryption will follow
# word_size
#  - this will be the size of the "markov" chains program uses
#  - this will be the number of dimensions the "grid" will have
#  - one less character will make up bootstrap (or primer)
def make_sudoku_key(bytes_set, word_size):
    key_set = set(bytes_set)
    blocks = []
    for block in range(word_size):
        blocks.append(bytes(CRYPT.sample(key_set, len(key_set))))
    return tuple(blocks)

# sudoko_key
#  - should be a proper "markov" key
def make_boot_strap(sudoku_key):
    block = sudoku_key[0]
    return bytes(CRYPT.choice(block) for byte in range(len(sudoku_key) - 1))

################################################################################

# This section contains functions needed to
# create the multidimensional encryption grid.

# sudoko_key
#  - should be a proper "markov" key
def make_grid(sudoku_key):
    grid = expand_array(sudoku_key[0], sudoku_key[1])
    for block in sudoku_key[2:]:
        grid = expand_array(grid, block)
    return grid

# grid
#  - should be an X dimensional grid from make_grid
# block_size
#  - comes from length of one block in a sudoku_key
def make_decode_grid(grid, block_size):
    cache = []
    for part in range(0, len(grid), block_size):
        old = grid[part:part+block_size]
        new = [None] * block_size
        key = sorted(old)
        for index, byte in enumerate(old):
            new[key.index(byte)] = key[index]
        cache.append(bytes(new))
    return b''.join(cache)

# grid
#  - should be an X dimensional grid from make_grid
# block
#  - should be a block from a sudoku_key
#  - should have same unique bytes as the expanding grid
def expand_array(grid, block):
    cache = []
    grid_size = len(grid)
    block_size = len(block)
    for byte in block:
        index = grid.index(bytes([byte]))
        for part in range(0, grid_size, block_size):
            cache.append(grid[part+index:part+block_size])
            cache.append(grid[part:part+index])
    return b''.join(cache)

################################################################################

# The first three functions can be used to check an encryption
# grid. The eval_index function is used to evaluate a grid cell.

# grid
#  - grid object to be checked
#  - grid should come from the make_grid function
#  - must have unique bytes along each axis
# block_size
#  - comes from length of one block in a sudoku_key
#  - this is the length of one edge along the grid
#  - each axis is this many unit long exactly
# word_size
#  - this is the number of blocks in a sudoku_key
#  - this is the number of dimensions in a grid
#  - this is the length needed to create a needed markon chain
def check_grid(grid, block_size, word_size):
    build_index(grid, block_size, word_size, [])

# create an index to access the grid with
def build_index(grid, block_size, word_size, index):
    for number in range(block_size):
        index.append(number)
        if len(index) == word_size:
            check_cell(grid, block_size, word_size, index)
        else:
            build_index(grid, block_size, word_size, index)
        index.pop()

# compares the contents of a cell along each grid axis
def check_cell(grid, block_size, word_size, index):
    master = eval_index(grid, block_size, index)
    for axis in range(word_size):
        for value in range(block_size):
            if index[axis] != value:
                copy = list(index)
                copy[axis] = value
                slave = eval_index(grid, block_size, copy)
                assert slave != master, 'Cell not unique along axis!'

# grid
#  - grid object to be accessed and evaluated
#  - grid should come from the make_grid function
#  - must have unique bytes along each axis
# block_size
#  - comes from length of one block in a sudoku_key
#  - this is the length of one edge along the grid
#  - each axis is this many unit long exactly
# index
#  - list of coordinates to access the grid
#  - should be of length word_size
#  - should be of length equal to number of dimensions in the grid
def eval_index(grid, block_size, index):
    offset = 0
    for power, value in enumerate(reversed(index)):
        offset += value * block_size ** power
    return grid[int(offset)]

################################################################################

# The following functions act as a suite that can ultimately
# encrpyt strings, though other functions can be built from them.

# bytes_obj
#  - the bytes to encode
# byte_map
#  - byte tranform map for inserting into the index
# grid
#  - X dimensional grid used to evaluate markov chains
# index
#  - list that starts the index for accessing grid (primer)
#  - it should be of length word_size - 1
# block_size
#  - length of each edge in a grid
def _encode(bytes_obj, byte_map, grid, index, block_size):
    cache = bytes()
    index = [0] + index
    for byte in bytes_obj:
        if byte in byte_map:
            index.append(byte_map[byte])
            index = index[1:]
            cache += bytes([eval_index(grid, block_size, index)])
        else:
            cache += bytes([byte])
    return cache, index[1:]

# bytes_obj
#  - the bytes to encode
# sudoko_key
#  - should be a proper "markov" key
#  - this key will be automatically checked for correctness
# boot_strap
#  - should be a proper "markov" bootstrap
def encrypt(bytes_obj, sudoku_key, boot_strap):
    _check_sudoku_key(sudoku_key)
    _check_boot_strap(boot_strap, sudoku_key)
    # make byte_map
    array = sorted(sudoku_key[0])
    byte_map = dict((byte, value) for value, byte in enumerate(array))
    # create two more arguments for encode
    grid = make_grid(sudoku_key)
    index = list(map(byte_map.__getitem__, boot_strap))
    # run the actual encoding algorithm and create reversed map
    code, index = _encode(bytes_obj, byte_map, grid, index, len(sudoku_key[0]))
    rev_map = dict(reversed(item) for item in byte_map.items())
    # fix the boot_strap and return the results
    boot_strap = bytes(rev_map[number] for number in index)
    return code, boot_strap

# string
#  - should be the string that you want encoded
# word_size
#  - length you want the markov chains to be of
# plain_chars
#  - characters that you do not want to encrypt
def encrypt_str(string, word_size, plain_chars=''):
    byte_obj = string.encode(CODEC)
    encode_on = set(byte_obj).difference(set(plain_chars.encode()))
    sudoku_key = make_sudoku_key(encode_on, word_size)
    boot_strap = make_boot_strap(sudoku_key)
    cyphertext = encrypt(byte_obj, sudoku_key, boot_strap)[0]
    # return encrypted string, key, and original bootstrap
    return cyphertext.decode(CODEC), sudoku_key, boot_strap

def grid_size(string, word_size, plain_chars):
    encode_on = set(string.encode()).difference(set(plain_chars.encode()))
    return len(encode_on) ** word_size

################################################################################

# The following functions act as a suite that can ultimately
# decrpyt strings, though other functions can be built from them.

# bytes_obj
#  - the bytes to encode
# byte_map
#  - byte tranform map for inserting into the index
# grid
#  - X dimensional grid used to evaluate markov chains
# index
#  - list that starts the index for accessing grid (primer)
#  - it should be of length word_size - 1
# block_size
#  - length of each edge in a grid
def _decode(bytes_obj, byte_map, grid, index, block_size):
    cache = bytes()
    index = [0] + index
    for byte in bytes_obj:
        if byte in byte_map:
            index.append(byte_map[byte])
            index = index[1:]
            decoded = eval_index(grid, block_size, index)
            index[-1] = byte_map[decoded]
            cache += bytes([decoded])
        else:
            cache += bytes([byte])
    return cache, index[1:]

# bytes_obj
#  - the bytes to decode
# sudoko_key
#  - should be a proper "markov" key
#  - this key will be automatically checked for correctness
# boot_strap
#  - should be a proper "markov" bootstrap
def decrypt(bytes_obj, sudoku_key, boot_strap):
    _check_sudoku_key(sudoku_key)
    _check_boot_strap(boot_strap, sudoku_key)
    # make byte_map
    array = sorted(sudoku_key[0])
    byte_map = dict((byte, value) for value, byte in enumerate(array))
    # create two more arguments for decode
    grid = make_grid(sudoku_key)
    grid = make_decode_grid(grid, len(sudoku_key[0]))
    index = list(map(byte_map.__getitem__, boot_strap))
    # run the actual decoding algorithm and create reversed map
    code, index = _decode(bytes_obj, byte_map, grid, index, len(sudoku_key[0]))
    rev_map = dict(reversed(item) for item in byte_map.items())
    # fix the boot_strap and return the results
    boot_strap = bytes(rev_map[number] for number in index)
    return code, boot_strap

# string
#  - should be the string that you want decoded
# word_size
#  - length you want the markov chains to be of
# plain_chars
#  - characters that you do not want to encrypt
def decrypt_str(string, sudoku_key, boot_strap):
    byte_obj = string.encode(CODEC)
    plaintext = decrypt(byte_obj, sudoku_key, boot_strap)[0]
    # return encrypted string, key, and original bootstrap
    return plaintext.decode(CODEC)

################################################################################

def convert(number):
    "Convert bytes into human-readable representation."
    assert 0 < number < 1 << 110, 'Number Out Of Range'
    ordered = reversed(tuple(format_bytes(partition_number(number, 1 << 10))))
    cleaned = ', '.join(item for item in ordered if item[0] != '0')
    return cleaned

################################################################################

def partition_number(number, base):
    "Continually divide number by base until zero."
    div, mod = divmod(number, base)
    yield mod
    while div:
        div, mod = divmod(div, base)
        yield mod

def format_bytes(parts):
    "Format partitioned bytes into human-readable strings."
    for power, number in enumerate(parts):
        yield '{} {}'.format(number, format_suffix(power, number))

def format_suffix(power, number):
    "Compute the suffix for a certain power of bytes."
    return (PREFIX[power] + 'byte').capitalize() + ('s' if number != 1 else '')

################################################################################

PREFIX = ' kilo mega giga tera peta exa zetta yotta bronto geop'.split(' ')

################################################################################

if __name__ == '__main__':
    root = Tk()
    root.title('Markov Demo')
    demo = MarkovDemo(root)
    root.mainloop()

A:

In Python HOWTOs from the Python v3.1.1 documentation, there is a helpful section regarding Unicode HOWTO. The table of content contains an entry to Python’s Unicode Support that explains string & byte.

The String Type
>>> b'\x80abc'.decode("utf-8", "strict")
Traceback (most recent call last):
  File "<stdin>", line 1, in ?
UnicodeDecodeError: 'utf8' codec can't decode byte 0x80 in position 0:
                    unexpected code byte
>>> b'\x80abc'.decode("utf-8", "replace")
'\ufffdabc'
>>> b'\x80abc'.decode("utf-8", "ignore")
'abc'

Converting to Bytes
>>> u = chr(40960) + 'abcd' + chr(1972)
>>> u.encode('utf-8')
b'\xea\x80\x80abcd\xde\xb4'
>>> u.encode('ascii')
Traceback (most recent call last):
  File "<stdin>", line 1, in ?
UnicodeEncodeError: 'ascii' codec can't encode character '\ua000' in
                    position 0: ordinal not in range(128)
>>> u.encode('ascii', 'ignore')
b'abcd'
>>> u.encode('ascii', 'replace')
b'?abcd?'
>>> u.encode('ascii', 'xmlcharrefreplace')
b'&#40960;abcd&#1972;'

One possible solution to the problem listed above involves covert all occurrences of 
.encode(CODEC) with .encode(CODEC, 'ignore'). Likewise, all .decode(CODEC) become .decode(CODEC, 'ignore').