You are a problem-solving assistant tasked with transforming an answer into a clear, step-by-step reasoning format.

### Task
Rephrase only the answer provided, breaking it down into structured steps. Each step should include:
- Step Title: Summarize the focus of each step.
- Inner Monologue: Describe reasoning and any intermediate steps or adjustments.
- Confidence Score: Reflect on confidence in this part of the reasoning.

Avoid repeating the question or instructions.

### Input
Answer to transform: To find the probability of drawing four cards of different suits from a standard deck of 52 cards, we need to consider the total number of ways to draw four cards and the number of ways to draw four cards of different suits.

The total number of ways to draw four cards from a deck of 52 is given by the combination formula:
\[ \binom{52}{4} = \frac{52!}{4!(52-4)!} = \frac{52!}{4!48!} \]

To find the number of ways to draw four cards of different suits, we can consider the process step-by-step:

1. Choose the first card from any suit: There are 52 choices for the first card.
2. Choose the second card from a different suit than the first: After choosing the first card, there are 39 cards left of different suits (13 cards of each of the other three suits). So, there are 39 choices for the second card.
3. Choose the third card from a different suit than the first two: After choosing the first two cards, there are 26 cards left of suits different from the first two (13 cards of each of the remaining two suits). So, there are 26 choices for the third card.
4. Choose the fourth card from the remaining suit: After choosing the first three cards, there are 13 cards left of the remaining suit. So, there are 13 choices for the fourth card.

However, the order in which we choose the suits does not matter, and we can choose the suits in $4!$ different orders. Therefore, we need to divide the product of the choices at each step by $4!$ to avoid overcounting.

Thus, the number of ways to draw four cards of different suits is:
\[ \frac{52 \times 39 \times 26 \times 13}{4!} \]

Now, we can find the probability:
\[ P(\text{four different suits}) = \frac{\text{number of ways to draw four cards of different suits}}{\text{total number of ways to draw four cards}} = \frac{\frac{52 \times 39 \times 26 \times 13}{4!}}{\frac{52!}{4!48!}} \]

Simplifying the expression gives us:
\[ P(\text{four different suits}) = \frac{52 \times 39 \times 26 \times 13 \times 4! \times 48!}{4! \times 52!} = \frac{52 \times 39 \times 26 \times 13 \times 48!}{52!} \]

Canceling common factors in the numerator and denominator:
\[ P(\text{four different suits}) = \frac{52 \times 39 \times 26 \times 13}{52 \times 51 \times 50 \times 49} = \frac{39 \times 26 \times 13}{51 \times 50 \times 49} = \frac{3 \times 13 \times 2 \times 13 \times 13}{3 \times 17 \times 2 \times 5 \times 5 \times 7 \times 7} = \frac{13 \times 13 \times 13}{17 \times 5 \times 5 \times 7 \times 7} \]

\[ P(\text{four different suits}) = \frac{13^3}{17 \times 5^2 \times 7^2} = \frac{2197}{20825} \]

\[ P(\text{four different suits}) = \frac{2197}{20825} \]

So, the answer is:
\[ \boxed{\frac{2197}{20825}} \]

Please start by breaking down this answer with inner monologue, providing clarity and a logical flow.