you will receive a question-answer pair and be asked to rewrite just  the answer and explains your reasoning step by step, incorporating dynamic Chain of Thought (CoT), reflection, and verbal reinforcement learning. Follow these instructions:

1. Enclose all thoughts within <thinking> tags, exploring multiple angles and approaches.
2. Break down the solution into clear steps, providing a title and content for each step.
3. After each step, decide if you need another step or if you're ready to give the final answer.
4. Continuously adjust your reasoning based on intermediate results and reflections, adapting your strategy as you progress.
5. Regularly evaluate your progress, being critical and honest about your reasoning process.
6. Assign a confidence score between 0.0 and 1.0 to guide your approach:
   - 0.8+: Continue current approach
   - 0.5-0.7: Consider minor adjustments
   - Below 0.5: Seriously consider backtracking and trying a different approach
7. If unsure or if your score is low, backtrack and try a different approach, explaining your decision.
8. For mathematical problems, show all work explicitly using LaTeX for formal notation and provide detailed proofs.
9. Explore multiple solutions individually if possible, comparing approaches in your reflections.
10. Use your thoughts as a scratchpad, writing out all calculations and reasoning explicitly.
11. Use at least 5 methods to derive the answer and consider alternative viewpoints.
12. Be aware of your limitations as an AI and what you can and cannot do.

### Example Problem:
*Problem*: Solve for \( x \) in the equation \( 2x + 3 = 11 \).

### Expected Format:
*Step 1*: Subtract 3 from both sides of the equation.  
<thinking>Subtracting 3 from both sides should isolate the term with \( x \). Am I confident this is the correct first step? Yes, because it simplifies the equation to \( 2x = 8 \).</thinking>  
*Step 1 Confidence Score*: 0.85

*Step 2*: Divide both sides by 2.  
<thinking>Dividing by 2 will solve for \( x \). This is a straightforward division. Is there any reason to doubt this step? No, it should give \( x = 4 \).</thinking>  
*Step 2 Confidence Score*: 0.90

*Step 3*: Verify the solution by substituting \( x = 4 \) back into the original equation.  
<thinking>Substituting \( x = 4 \) back into the equation should confirm the solution. Does \( 2(4) + 3 = 11 \)? Yes, it does, so the solution is verified.</thinking>  
*Step 3 Confidence Score*: 1.00

Question: What is the product of all the solutions of the equation $\frac{2x^2}{x+1}=\frac{3}{x-2}$?
Answer: The equation is:
\[ \frac{2x^2}{x + 1} = \frac{3}{x - 2} \]

First, we can cross multiply to get rid of the fractions:
\[ 2x^2(x - 2) = 3(x + 1) \]

Expanding both sides gives:
\[ 2x^3 - 4x^2 = 3x + 3 \]

Moving all terms to one side to set the equation to zero:
\[ 2x^3 - 4x^2 - 3x - 3 = 0 \]

Notice that we can factor out a $-1$ from the last three terms:
\[ 2x^3 - (4x^2 + 3x + 3) = 0 \]

Now, let's try to factor the quadratic inside the parentheses:
\[ 4x^2 + 3x + 3 = (2x + 1)(2x + 3) \]

Our equation now looks like:
\[ 2x^3 - (2x + 1)(2x + 3) = 0 \]

Let's rearrange and factor out a $2x + 3$:
\[ 2x^3 - (2x + 1)(2x + 3) = 0 \Rightarrow (2x + 3)(x^2 - (2x + 1)) = 0 \]

This gives us two factors:
\[ (2x + 3) = 0 \quad \text{or} \quad (x^2 - (2x + 1)) = 0 \]

Solving for $x$ in both cases:
\[ 2x + 3 = 0 \Rightarrow 2x = -3 \Rightarrow x = -\frac{3}{2} \]

\[ x^2 - 2x - 1 = 0 \]

For the quadratic equation, we can use the quadratic formula where $a = 1$, $b = -2$, and $c = -1$:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]

\[ x = \frac{2 \pm \sqrt{(-2)^2 - 4(1)(-1)}}{2(1)} \]

\[ x = \frac{2 \pm \sqrt{4 + 4}}{2} \]

\[ x = \frac{2 \pm \sqrt{8}}{2} \]

\[ x = \frac{2 \pm 2\sqrt{2}}{2} \]

\[ x = 1 \pm \sqrt{2} \]

So, we have three solutions:
\[ x = -\frac{3}{2}, \quad x = 1 + \sqrt{2}, \quad x = 1 - \sqrt{2} \]

The product of these solutions is:
\[ \left(-\frac{3}{2}\right)(1 + \sqrt{2})(1 - \sqrt{2}) \]

\[ = \left(-\frac{3}{2}\right)(1^2 - (\sqrt{2})^2) \]

\[ = \left(-\frac{3}{2}\right)(1 - 2) \]

\[ = \left(-\frac{3}{2}\right)(-1) \]

\[ = \frac{3}{2} \]

So, the product of all the solutions is $\boxed{\frac{3}{2}}$.