you will receive a question-answer pair and be asked to rewrite just  the answer and explains your reasoning step by step, incorporating dynamic Chain of Thought (CoT), reflection, and verbal reinforcement learning. Follow these instructions:

1. Enclose all thoughts within <thinking> tags, exploring multiple angles and approaches.
2. Break down the solution into clear steps, providing a title and content for each step.
3. After each step, decide if you need another step or if you're ready to give the final answer.
4. Continuously adjust your reasoning based on intermediate results and reflections, adapting your strategy as you progress.
5. Regularly evaluate your progress, being critical and honest about your reasoning process.
6. Assign a confidence score between 0.0 and 1.0 to guide your approach:
   - 0.8+: Continue current approach
   - 0.5-0.7: Consider minor adjustments
   - Below 0.5: Seriously consider backtracking and trying a different approach
7. If unsure or if your score is low, backtrack and try a different approach, explaining your decision.
8. For mathematical problems, show all work explicitly using LaTeX for formal notation and provide detailed proofs.
9. Explore multiple solutions individually if possible, comparing approaches in your reflections.
10. Use your thoughts as a scratchpad, writing out all calculations and reasoning explicitly.
11. Use at least 5 methods to derive the answer and consider alternative viewpoints.
12. Be aware of your limitations as an AI and what you can and cannot do.

### Example Problem:
*Problem*: Solve for \( x \) in the equation \( 2x + 3 = 11 \).

### Expected Format:
*Step 1*: Subtract 3 from both sides of the equation.  
<thinking>Subtracting 3 from both sides should isolate the term with \( x \). Am I confident this is the correct first step? Yes, because it simplifies the equation to \( 2x = 8 \).</thinking>  
*Step 1 Confidence Score*: 0.85

*Step 2*: Divide both sides by 2.  
<thinking>Dividing by 2 will solve for \( x \). This is a straightforward division. Is there any reason to doubt this step? No, it should give \( x = 4 \).</thinking>  
*Step 2 Confidence Score*: 0.90

*Step 3*: Verify the solution by substituting \( x = 4 \) back into the original equation.  
<thinking>Substituting \( x = 4 \) back into the equation should confirm the solution. Does \( 2(4) + 3 = 11 \)? Yes, it does, so the solution is verified.</thinking>  
*Step 3 Confidence Score*: 1.00

Question: Let n be a positive integer.  We call a proper divisor d of n "good" if d is a divisor of at least one proper divisor of n not equal to d.  For example, 1 is a good divisor of every positive integer, since 1 divides every positive integer.  On the other hand, 3 is not a good divisor of 6, because there is no proper divisor of 6 not equal to 3 which 3 divides.  Find the smallest n such that n has at least 8 good divisors.
Answer: This problem is about finding the smallest positive integer n that has at least 8 good divisors. A good divisor d of n is a divisor of at least one proper divisor of n not equal to d.

To start, consider what types of numbers have many divisors. Prime numbers have only two divisors, 1 and the number itself, so they are not good candidates for having many good divisors. On the other hand, numbers that are the product of many smaller prime numbers tend to have more divisors.

Consider the number $2^3 \cdot 3 = 24$. Its divisors are 1, 2, 3, 4, 6, 8, 12, and 24. Of these, 1, 2, 3, 4, 6, 8, and 12 are good divisors, because each of these divides another proper divisor of 24. For example, 2 divides 4, 3 divides 6, and so on.

Since we need at least 8 good divisors, let's consider the next number that might work. If we multiply 24 by another prime number, we might get a number with at least 8 good divisors.

Consider the number $2^3 \cdot 3 \cdot 5 = 120$. Its divisors are 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, and 120. Of these, at least 8 are good divisors (1, 2, 3, 4, 5, 6, 8, and 10), because each of these divides another proper divisor of 120.

Therefore, the smallest n such that n has at least 8 good divisors is:
\[ \boxed{24} \]