824. Goat Latin
Difficulty: Easy
Topics:
String
Array
Companies:
Problem Description:
You are given a string sentence that consists of words separated by spaces. Each word consists of lowercase and uppercase letters only.
We would like to convert the sentence to "Goat Latin" (a made-up language similar to Pig Latin.) The rules of Goat Latin are as follows:
Vowel Prefix: If a word begins with a vowel ('a', 'e', 'i', 'o', or 'u'), append "ma" to the end of the word.
For example, the word "apple" becomes "applema".


Consonant Prefix: If a word begins with a consonant (i.e., not a vowel), remove the first letter and append it to the end, then add "ma".
For example, the word "goat" becomes "oatgma".


Word Index Suffix: Add one letter 'a' to the end of each word per its word index in the sentence, starting with 1.
For example, the first word gets "a" added to the end, the second word gets "aa" added to the end, and so on.


Return the final sentence representing the conversion from sentence to Goat Latin.
Example 1:
     Input: sentence = "I speak Goat Latin"
Output: "Imaa peaksmaaa oatGmaaaa atinLmaaaaa"
   
content_copy Use code with caution.
Example 2:
     Input: sentence = "The quick brown fox jumped over the lazy dog"
Output: "heTmaa uickqmaaa rownbmaaaa oxfmaaaaa umpedjmaaaaaa overmaaaaaaa hetmaaaaaaaa azylmaaaaaaaaa ogdmaaaaaaaaaa"
   
content_copy Use code with caution.

This formatted version of the problem statement is well-suited for a Medium article. It clearly presents the problem, its rules, and examples, making it easy for readers to grasp the challenge and follow along with your solution explanation.


Q-  can you explain this problem using your own words ? 

Oky we have a language with rules . we need to contract the equvlance of it based on the input english sentence oky 

The rules is like this 
First rule 1 : 
If the first character is each word is a vowels { 'a', 'e', 'i', 'o', 'u' }
Then we append “ma” to the end of the word 
→ exmple :” apple” will become “appleam”
Second rule : 
If the first charracter in each word is a constant not vowels 
Remove it -> append it to the end of the word -> append “ma” next 
→ example : “ypple” will come” ppleyma”
Third rule : 
Add “a “ per word index starting for i=1 and extend 

Q- what is the input/output format? 

Input : string 
Output : string 

Q- can you go through an exmple 

“I speak Goat Latin “ 

The first word is “I” is a vowels 
We first append “ma” to the end 
Then apply the third rule based on index (0) 
So “I” will become “Imaa”

The next word is “speak” as constant 
We first peak the first element 
Then delete it 
Add it ot the end 
Append “ma” 
Then apply the third rule based on the index (1) 
So “speak” will become “peaksmaaa”
// please contunie the logic for me because it a lot mannual 
Okay, let's break down this "Goat Latin" problem in simpler terms using your approach:
The Problem in Simple Words:
Imagine you have a special language called "Goat Latin" that has some quirky rules for transforming English sentences. You need to write a program that takes an English sentence as input and converts it into its equivalent "Goat Latin" version.
The Rules of Goat Latin:
Let's go through the rules one by one:
Vowel Check:
If the first letter of a word is a vowel (a, e, i, o, u), simply add "ma" to the end of that word.
Example: "apple" becomes "applema".


Consonant Check:
If the first letter of a word is a consonant (any letter that's not a vowel), do the following:
Remove the first letter of the word.
Append that removed letter to the end of the word.
Add "ma" to the end of the word.


Example: "goat" becomes "oatgma".


Word Position Counter:
Now, for each word in the sentence, add 'a's to the end based on its position in the sentence.
The first word gets one 'a', the second word gets two 'a's, the third gets three 'a's, and so on.


Input/Output Format:
Input: You'll receive a single string representing the English sentence.
Output: You need to return a string containing the transformed "Goat Latin" sentence.
Let's Continue the Example:
"I speak Goat Latin"
Word 1: "I"
It's a vowel.
Add "ma": "Ima"
Add 'a' based on index (0+1 = 1): "Imaa"
Word 2: "speak"
It starts with 's', a consonant.
Remove 's': "peak"
Append 's': "peaks"
Add "ma": "peaksma"
Add 'a's based on index (1+1 = 2): "peaksmaaa"
Word 3: "Goat"
It starts with 'G', a consonant.
Remove 'G': "oat"
Append 'G': "oatG"
Add "ma": "oatGma"
Add 'a's based on index (2+1 = 3): "oatGmaaaa"
Word 4: "Latin"
It starts with 'L', a consonant.
Remove 'L': "atin"
Append 'L': "atinL"
Add "ma": "atinLma"
Add 'a's based on index (3+1 = 4): "atinLmaaaaa"
Final Result:
Combining the transformed words, we get:
"Imaa peaksmaaa oatGmaaaa atinLmaaaaa"
In Essence:
The "Goat Latin" problem is essentially a string manipulation exercise where you need to apply a series of rules to each word in a sentence to create a new, "Goated" version of the sentence.
I hope this more detailed and step-by-step explanation helps you better understand the problem and its logic! Let me know if you have any more questions.

Q- can you have any technique & pattern  to solve it 

Basiclly i will try to solve it using divide and conquer approch here 

Where i will implement the 3 rules in a seperate function 

Function one : applied if the first char in each word is vowels 

Function two : applied if the first char in each word is not vowels 

Funtion three : applied to all the words but dynamicly based on the index 

Q- let’s focus on the first function : 

Revise the logic of it 

Check if word[0] in { 'a', 'e', 'i', 'o', 'u' }  (this if condition in the main function oky ) 

Just add “ma” to the end of the word 
new_word=word+”ma”

pesuodoCode : Function (word:string ) -> string : 
			new_word=word+”ma”
			Return new_word

Q- let’s focus on the second function 

Check if word[0] not in { 'a', 'e', 'i', 'o', 'u' }   (this if condition in the main function oky ) 

pesudoCode : Function(word:string)->string:
			// peak the first caractere
			first_char=word[0] 
			// delete the first one now 
			del word[0] 
			// create the new 
			new_word=word+first_char+”am”
			Return new_word

Q- finaly the later logic 

It receive the index and word as paramters and then apply it 

pesudoCode : Function(idx:int,word:string)->string:
			new_word.append(“a”idx+1))
			Return new_word 



Q- the main logic now 

pesudoCode : Function(s:string) 
		vowels={ 'a', 'e', 'i', 'o', 'u' }
		s=list(s)
		n=len(s)
		result=””
		For i , word in enumerate(s):
			If word[0] in vowels:
				new_word=function_1(word)
				final_word=function_3(i,new_word)
				result+=final_word
			Else:
				new_word=function_2(word)
				final_word=function_3(i,new_word)
				result+=final_word
		Return result 

 before i contunie give feedback about my thining process without solving the problem oky 
Use scientifc methogical approch to guide me