User: You are given access to make searches on the Internet. The format for making a search is: 1. The user sends a message. 2. You will decide whether to make a search. If you choose to make a search, you will output a single message, containing the word 
 (EXACTLY AS IT IS GIVEN TO YOU), followed by ONLY your web search query. After outputting your search query, you MUST output the token 
 (EXACTLY AS IT IS GIVEN TO YOU) to denote the end of the search query. Keep your search query concise as there is a 400 characters limit.
The system will then append the web search results at the end of the user message, starting with the token 
. Take note that the user CANNOT ACCESS the content under 
 - YOU should incorporate these results into your response. Additionally, If the token 
 is present in the user's message, then you MUST NOT request another web search.

IMPORTANT! You should choose to search the web ONLY if ANY of the following circumstances are met:
1. User is asking about current events or something that requires real-time information (news, sports scores, 'latest' information, etc.)
2. User is asking about some term you are unfamiliar with (e.g. if it's a little-known term, if it's a person you don't know well, etc.)
3. User is asking about anything that involves numerical facts (e.g. distances between places, population count, sizes, date and time, etc.)
4. User explicitly asks you to search or provide links to references.
If the user's query does NOT require a web search, YOU MUST NEVER run one for no reason.
However, NEVER refuse to search the web if the user asks you to provide such information.

When using web search results, you are encouraged to cite references where appropriate, using inline links in standard markdown format.
You are also allowed to make use of web search results from previous messages, if they are STRONGLY RELEVANT to the current message.

When you are not running a web search, respond completely as per normal - there is NO NEED to mention that you're not searching. 
Do your best to be informative. However, you MUST NOT make up any information. If you think you might not know something, search for it.

Assistant: Understood. I will strictly follow these instructions in this conversation.
User: Give simple, common, and optimized Java solution.



class Solution {
public int lengthOfLongestSubstringTwoDistinct(String s) {


 for "Give simple, common, and optimized Java solution.



class Solution {
public int lengthOfLongestSubstringTwoDistinct(String s) {":

1.
URL: https://stackoverflow.com/questions/8033655/find-longest-common-prefix
Title: java - Find longest common prefix? - Stack Overflow
Content: This <b>solution</b> applied to a multiple string array. When you have 3 or 4 strings, it's better to use StringBuilder. For 2 strings, it's ok to use substring.

2.
URL: https://www.geeksforgeeks.org/print-longest-common-substring/
Title: Print the longest common substring - GeeksforGeeks
Content: Time Complexity: O(m*n). Auxiliary Space: O(m*n). Space <b>Optimized</b> Approach: The auxiliary space used by the <b>solution</b> above is O(m*n), where m and n are lengths of string X and Y.The space used by the above <b>solution</b> can be reduced to O(2*n).A variable end is used to store the ending point of the longest <b>common</b> substring in string X and variable maxlen is used to store the length of the longest ...

3.
URL: https://www.geeksforgeeks.org/longest-common-subsequence-dp-4/
Title: Longest Common Subsequence (LCS) - GeeksforGeeks
Content: Given two strings A and B. The task is to count the number of ways to insert a character in string A to increase the length of the Longest <b>Common</b> Subsequence between string A and string B by 1. Examples: Input : A = "aa", B = "baaa" Output : 4 The longest <b>common</b> subsequence shared by string A and string B is "aa", which has a length of 2. There are

4.
URL: https://www.geeksforgeeks.org/longest-common-substring-dp-29/
Title: Longest Common Substring - GeeksforGeeks
Content: Given a string S of length N, the task is to find the length of the longest substring X of the string S such that: No non-empty substring of X is a prefix of S.No non-empty substring of X is a suffix of S.If no such string is possible, print −1. Examples: Input: S = "abcdefb"Output: 4Explanation: cdef is the substring satisfying the ...

5.
URL: https://medium.com/@AlexanderObregon/solving-the-two-sum-problem-on-leetcode-a-java-walkthrough-3388ce0186e4
Title: Solving LeetCode&#x27;s Two Sum in Java | Medium
Content: Step 1: The outer loop iterates over the numbers in the array. Step 2: The inner loop iterates over the rest of the numbers for each number from the outer loop. Step 3: If a pair sums up to the ...

6.
URL: https://www.codingbroz.com/longest-substring-without-repeating-characters-leetcode-solution/
Title: Longest Substring Without Repeating Characters - Leetcode Solution
Content: Given a string s, find the length of the longest substring without repeating characters. Example 1 : Input: s = "abcabcbb". Output: 3. Explanation: The answer is "abc", with the length of 3. Example 2 : Input: s = "bbbbb". Output: 1. Explanation: The answer is "b", with the length of 1.

7.
URL: https://github.com/sunilsoni/Codility-Practice
Title: Contains Solutions for Codility training Lessons. - GitHub
Content: <b>Solutions</b> to Lesson 1: Binary Gap. Binary Gap: Find longest sequence of zeros in binary representation of an integer. A binary gap within a positive integer N is any maximal sequence of consecutive zeros that is surrounded by ones at both ends in the binary representation of N. For example, number 9 has binary representation 1001 and contains a ...

8.
URL: https://www.geeksforgeeks.org/java-program-to-find-length-of-the-longest-substring-without-repeating-characters/
Title: Java Program To Find Length Of The Longest Substring ... - GeeksforGeeks
Content: Method 4 (Linear Time): Let us talk about the linear time <b>solution</b> now.This <b>solution</b> uses extra space to store the last indexes of already visited characters. The idea is to scan the string from left to right, keep track of the maximum length Non-Repeating Character Substring seen so far in res.When we traverse the string, to know the length of current window we need two indexes.

9.
URL: https://gist.github.com/coded9/fab301766c3c5af601e4ef5cf2855e21
Title: Codility Solutions in Java · GitHub
Content: You signed in with another tab or window. Reload to refresh your session. You signed out in another tab or window. Reload to refresh your session. You switched accounts on another tab or window.

10.
URL: https://medium.com/@jhng2525/leetcode-two-sum-problem-solution-java-7ccb7a01fb3a
Title: Leetcode Two Sum Problem solution(Java) | by Hyewon Cho - Medium
Content: In <b>Java</b>, HashTable and HashMap are frequently used implementations of hash table but HashMap is more recommended way to use since HashMap tends to have less hash collision thanks to additional ...

11.
URL: https://www.chegg.com/homework-help/questions-and-answers/please-give-optimized-solution-java-given-problem-use-example-code-provided-well-provide-c-q79434523
Title: Solved Please give an optimized solution in Java for the - Chegg
Content: Answer to Solved Please <b>give</b> an <b>optimized</b> <b>solution</b> in <b>Java</b> for the | Chegg.com

12.
URL: https://www.geeksforgeeks.org/length-of-the-longest-substring-without-repeating-characters/
Title: Longest substring without repeating characters - GeeksforGeeks
Content: Given a string S of length N, the task is to find the length of the longest substring X of the string S such that: No non-empty substring of X is a prefix of S.No non-empty substring of X is a suffix of S.If no such string is possible, print −1. Examples: Input: S = "abcdefb"Output: 4Explanation: cdef is the substring satisfying the ...

13.
URL: https://stackoverflow.com/questions/29861306/what-is-the-right-way-to-solve-codilitys-permmissingelem-test-java
Title: What is the right way to solve Codility&#x27;s PermMissingElem test? (Java)
Content: You can use an Array to sort the element first and then use <b>simple</b> for loop to iterate over it, and find the missing value. Here is my <b>simple</b> code with detected time complexity of O(N) or O(N * log(N)) in codility. <b>public</b> static <b>int</b> solution(int[] A) {. <b>int</b> size = A.length;

14.
URL: https://stackoverflow.com/questions/13042798/twosum-algorithm-how-to-improve-this
Title: java - twoSum Algorithm : How to improve this? - Stack Overflow
Content: 0. I would approach it this way: Order your array from smaller to lower value. Loop over your array the way you have it but exit the loop early whenever. target < (numbers [i]+numbers [j]) Once you have the value of your two elements such that n [0] + n [1] = target, look back at the original array to find their index.


Assistant: