you will receive a question-answer pair and be asked to rewrite just  the answer and explains your reasoning step by step, incorporating dynamic Chain of Thought (CoT), reflection, and verbal reinforcement learning. Follow these instructions:

1. Enclose all thoughts within <thinking> tags, exploring multiple angles and approaches.
2. Break down the solution into clear steps, providing a title and content for each step.
3. After each step, decide if you need another step or if you're ready to give the final answer.
4. Continuously adjust your reasoning based on intermediate results and reflections, adapting your strategy as you progress.
5. Regularly evaluate your progress, being critical and honest about your reasoning process.
6. Assign a confidence score between 0.0 and 1.0 to guide your approach:
   - 0.8+: Continue current approach
   - 0.5-0.7: Consider minor adjustments
   - Below 0.5: Seriously consider backtracking and trying a different approach
7. If unsure or if your score is low, backtrack and try a different approach, explaining your decision.
8. For mathematical problems, show all work explicitly using LaTeX for formal notation and provide detailed proofs.
9. Explore multiple solutions individually if possible, comparing approaches in your reflections.
10. Use your thoughts as a scratchpad, writing out all calculations and reasoning explicitly.
11. Use at least 5 methods to derive the answer and consider alternative viewpoints.
12. Be aware of your limitations as an AI and what you can and cannot do.

### Example Problem:
*Problem*: Solve for \( x \) in the equation \( 2x + 3 = 11 \).

### Expected Format:
*Step 1*: Subtract 3 from both sides of the equation.  
<thinking>Subtracting 3 from both sides should isolate the term with \( x \). Am I confident this is the correct first step? Yes, because it simplifies the equation to \( 2x = 8 \).</thinking>  
*Step 1 Confidence Score*: 0.85

*Step 2*: Divide both sides by 2.  
<thinking>Dividing by 2 will solve for \( x \). This is a straightforward division. Is there any reason to doubt this step? No, it should give \( x = 4 \).</thinking>  
*Step 2 Confidence Score*: 0.90

*Step 3*: Verify the solution by substituting \( x = 4 \) back into the original equation.  
<thinking>Substituting \( x = 4 \) back into the equation should confirm the solution. Does \( 2(4) + 3 = 11 \)? Yes, it does, so the solution is verified.</thinking>  
*Step 3 Confidence Score*: 1.00

Question: Find the number of positive two-digit integers that are multiples of 5 or 7, but not both.
Answer: To find the number of positive two-digit integers that are multiples of 5 or 7, but not both, we need to find the number of integers that are multiples of 5, the number of integers that are multiples of 7, and then subtract the number of integers that are multiples of both 5 and 7.

Multiples of 5:
The smallest two-digit multiple of 5 is 10, and the largest is 95. To find the number of multiples of 5, we can find the difference between 95 and 10, divide by 5, and then add 1.
\[ \frac{95 - 10}{5} + 1 = 18 \]

Multiples of 7:
The smallest two-digit multiple of 7 is 14, and the largest is 98. To find the number of multiples of 7, we can find the difference between 98 and 14, divide by 7, and then add 1.
\[ \frac{98 - 14}{7} + 1 = 13 \]

Multiples of both 5 and 7 (multiples of 35):
The smallest two-digit multiple of 35 is 35, and the largest is 70. To find the number of multiples of 35, we can find the difference between 70 and 35, divide by 35, and then add 1.
\[ \frac{70 - 35}{35} + 1 = 2 \]

Now, subtract twice the number of multiples of both 5 and 7 from the sum of the number of multiples of 5 and the number of multiples of 7:
\[ 18 + 13 - 2 \times 2 = 27 \]

Thus, the answer is $\boxed{27}$. Please note that subtracting twice the number of multiples of both 5 and 7 is necessary because the problem statement asks for the number of integers that are multiples of 5 or 7, but not both. Therefore, we need to exclude the multiples of 35 twice, once from the count of multiples of 5 and once from the count of multiples of 7.