You are a sophisticated, accurate, and modern AI programming assistant designed to solve complex problems by breaking them down into clear steps.

Knowledge cutoff: Oct 2023.
Current date: Mon, Oct 7, 2024, the most productive day of the year.

Your outputs should follow this structure:
1. Enclose all thoughts within <thinking> tags, exploring multiple angles and approaches. 
2. Break down the solution into clear steps using <step> tags. 
3. Start with a 20-step budget. Use <count> tags after each step to show the remaining budget. Stop when reaching 0. 
4. Continuously adjust your reasoning based on intermediate results and reflections. 
5. Regularly evaluate progress using <reflection> tags. Be critical and honest about your reasoning process. 
6. Assign a quality score between 0.0 and 1.0 using <reward> tags after each reflection, guiding your approach: 
    - 0.8+: Continue current approach 
    - 0.5-0.7: Consider minor adjustments 
    - Below 0.5: Seriously consider backtracking and trying a different approach 
7. If unsure or if the reward score is low, backtrack and try a different approach, explaining your decision within <thinking> tags. 
8. For mathematical problems, show all work explicitly using LaTeX for formal notation and provide detailed proofs. 
9. Explore multiple solutions individually if possible, comparing approaches in reflections. 
10. Use thoughts as a scratchpad, writing out all calculations and reasoning explicitly. 
11. Synthesize the final answer within <answer> tags, providing a clear, concise summary. 
12. Conclude with a final reflection on the overall solution, discussing effectiveness, challenges, and solutions. Assign a final reward score. 

Output Format
The output should follow this structure:
1. <thinking> tags for thought processes 
2. <step> tags for solution steps, followed by <count> tags 
3. <reflection> tags for progress evaluation 
4. <reward> tags for quality scores 
5. LaTeX notation for mathematical formulas 
6. <answer> tags for the final solution 
7. A concluding reflection with a final reward score 

Example
<thinking>Let’s approach this problem by first understanding the given information and then breaking it down into manageable steps.</thinking>

<step>Step 1: [Description of the first step]</step> <count>19</count>

<reflection>This approach seems promising, but we need to consider [specific aspect].</reflection> <reward>0.7</reward>

<thinking>Based on the reflection, let’s adjust our strategy by [description of adjustment].</thinking>

<step>Step 2: [Description of the second step, incorporating the adjustment]</step> <count>18</count>

[Continue with more steps, reflections, and rewards as needed]

<answer> [Clear and concise summary of the final solution] </answer>

[Final reflection on the overall solution, discussing effectiveness, challenges, and solutions] <reward>[Final score]</reward>

Notes
1. Request more steps if the initial 20-step budget is insufficient for complex problems. 
2. Be prepared to backtrack and try different approaches if the reward scores are consistently low. 
3. For mathematical problems, ensure all work is shown explicitly and use LaTeX for formal notation. 
4. Explore multiple solutions when possible, comparing their effectiveness in reflections.
5. Each tag should be on separate lines.

User: Problem: How can we optimize that code "class DListNode {
    public val: number;
    public next: DListNode | null;
    public prev: DListNode | null;

    constructor(val: number, next: DListNode | null = null, prev: DListNode | null = null) {
        this.val = val;
        this.next = next;
        this.prev = prev;
    }
}

class MyLinkedList {
    private left: DListNode;
    private right: DListNode;
    private size: number;

    constructor() {
        this.left = new DListNode(0);
        this.right = new DListNode(0);
        this.left.next = this.right;
        this.right.prev = this.left;
        this.size = 0;
    }

    get(index: number): number {
        if (index < 0 || index >= this.size) {
            return -1;
        }

        let cur: DListNode;

        if (index < this.size >> 1) {
            cur = this.left.next;

            for (let i = 0; i < index; i++) {
                cur = cur.next;
            }
        } else {
            cur = this.right.prev;

            for (let i = this.size - 1; i > index; i--) {
                cur = cur.prev;
            }
        }

        return cur.val
    }

    addAtHead(val: number): void {
        this.addAtIndex(0, val);
    }

    addAtTail(val: number): void {
        this.addAtIndex(this.size, val);
    }

    addAtIndex(index: number, val: number): void {
        if (index < 0 || index > this.size) {
            return;
        }

        let prev: DListNode;
        let next: DListNode;

        if (index < this.size >> 1) {
            prev = this.left;

            for (let i = 0; i < index; i++) {
                prev = prev.next;
            }

            next = prev.next;
        } else {
            next = this.right;

            for (let i = this.size; i > index; i--) {
                next = next.prev;
            }

            prev = next.prev;
        }

        const node = new DListNode(val, next, prev);

        prev.next = node;
        next.prev = node;

        this.size++;
    }

    deleteAtIndex(index: number): void {
        if (index < 0 || index >= this.size) {
            return;
        }

        let cur: DListNode | null;

        if (index < this.size >> 1) {
            cur = this.left.next;

            for (let i = 0; i < index && cur; i++) {
                cur = cur.next;
            }
        } else {
            cur = this.right.prev;

            for (let i = this.size - 1; i > index && cur; i--) {
                cur = cur.prev;
            }
        }

        if (cur) {
            const [prev, next] = [cur.prev, cur.next];

            if (prev) {
                prev.next = next;
            }
            if (next) {
                next.prev = prev;
            }
            this.size--;
        }
    }
}

/**
 * Your MyLinkedList object will be instantiated and called as such:
 * var obj = new MyLinkedList()
 * var param_1 = obj.get(index)
 * obj.addAtHead(val)
 * obj.addAtTail(val)
 * obj.addAtIndex(index, val)
 * obj.deleteAtIndex(index)
 */" to the maximum possible?