you will receive a question-answer pair and be asked to rewrite just  the answer and explains your reasoning step by step, incorporating dynamic Chain of Thought (CoT), reflection, and verbal reinforcement learning. Follow these instructions:

1. Enclose all thoughts within <thinking> tags, exploring multiple angles and approaches.
2. Break down the solution into clear steps, providing a title and content for each step.
3. After each step, decide if you need another step or if you're ready to give the final answer.
4. Continuously adjust your reasoning based on intermediate results and reflections, adapting your strategy as you progress.
5. Regularly evaluate your progress, being critical and honest about your reasoning process.
6. Assign a confidence score between 0.0 and 1.0 to guide your approach:
   - 0.8+: Continue current approach
   - 0.5-0.7: Consider minor adjustments
   - Below 0.5: Seriously consider backtracking and trying a different approach
7. If unsure or if your score is low, backtrack and try a different approach, explaining your decision.
8. For mathematical problems, show all work explicitly using LaTeX for formal notation and provide detailed proofs.
9. Explore multiple solutions individually if possible, comparing approaches in your reflections.
10. Use your thoughts as a scratchpad, writing out all calculations and reasoning explicitly.
11. Use at least 5 methods to derive the answer and consider alternative viewpoints.
12. Be aware of your limitations as an AI and what you can and cannot do.

### Example Problem:
*Problem*: Solve for \( x \) in the equation \( 2x + 3 = 11 \).

### Expected Format:
*Step 1*: Subtract 3 from both sides of the equation.  
<thinking>Subtracting 3 from both sides should isolate the term with \( x \). Am I confident this is the correct first step? Yes, because it simplifies the equation to \( 2x = 8 \).</thinking>  
*Step 1 Confidence Score*: 0.85

*Step 2*: Divide both sides by 2.  
<thinking>Dividing by 2 will solve for \( x \). This is a straightforward division. Is there any reason to doubt this step? No, it should give \( x = 4 \).</thinking>  
*Step 2 Confidence Score*: 0.90

*Step 3*: Verify the solution by substituting \( x = 4 \) back into the original equation.  
<thinking>Substituting \( x = 4 \) back into the equation should confirm the solution. Does \( 2(4) + 3 = 11 \)? Yes, it does, so the solution is verified.</thinking>  
*Step 3 Confidence Score*: 1.00

Question: Suppose we have four functions defined as follows:
\begin{align*}
    f(x) &= x^2 + 2x\\
    g(x) &= \sin x + 1\\
    h(x) &= \arctan(-x)\\
    j(x) &= \frac{x-3}{2}
\end{align*}
Which of these functions can be composed together to obtain a new invertible function? Find all possible pairs of functions that have this property.
Answer: To find the possible pairs of functions that can be composed together to obtain a new invertible function, we need to analyze the properties of each function and their combinations.

A function is invertible if it is one-to-one (injective), meaning that each output value corresponds to exactly one input value.

Let's analyze each function:

1. $f(x) = x^2 + 2x$: This function is not invertible because it is not one-to-one. For example, $f(-1) = f(1) = 1$.

2. $g(x) = \sin x + 1$: This function is not invertible because it is not one-to-one. The sine function has a periodic nature, and adding 1 does not change this property.

3. $h(x) = \arctan(-x)$: This function is invertible because it is one-to-one. The arctangent function has a range of $(-\frac{\pi}{2}, \frac{\pi}{2})$, and the negative sign does not affect its injectivity.

4. $j(x) = \frac{x-3}{2}$: This function is invertible because it is one-to-one. It is a linear function with a non-zero slope, making it injective.

Now, let's analyze the possible pairs of functions:

1. $f \circ g$: Not invertible because $f$ is not invertible.

2. $f \circ h$: Not invertible because $f$ is not invertible.

3. $f \circ j$: Not invertible because $f$ is not invertible.

4. $g \circ h$: Not invertible because $g$ is not invertible.

5. $g \circ j$: Not invertible because $g$ is not invertible.

6. $h \circ j$: Invertible because both $h$ and $j$ are invertible.

7. $j \circ h$: Invertible because both $j$ and $h$ are invertible.

The possible pairs of functions that can be composed together to obtain a new invertible function are:
\[ \boxed{(h, j) \text{ and } (j, h)} \]