Q- oky we have an array of string : words  -> example  [“a”,”m”,”i”] 
Q- oky we have a binary array “groups”  -> example [0,0,1] 
Q- both of length “n”  

Q- we have a definition here ? 
A subsequence of words is alternating is for any two consecutive strings in the sequence , 
If their corresponding elements in the binary array “groups” differ . 

→ m3na ke n9olo “susequence “ of words enha “alternatiing “ m3naha kol zoz kemlate alterny mbetnhom → el the element mapped 3lih howa bedo different oky 

Q- ntjm t3tino example en fly ? 

Sure! Let's break it down with an example:

Given:
- `words = ["a", "m", "i"]`
- `groups = [0, 0, 1]`

To find an **alternating subsequence** of words, we need to ensure that for any two consecutive strings in the subsequence, their corresponding values in the binary array `groups` are different (meaning they alternate between 0 and 1).

Let's check some subsequences:

1. **Subsequence: ["a", "m"]**  
   Corresponding `groups` values: `[0, 0]`  
   Since both values are 0 (not alternating), this subsequence is **not alternating**.

2. **Subsequence: ["a", "i"]**  
   Corresponding `groups` values: `[0, 1]`  
   The values alternate (0 and 1), so this subsequence **is alternating**.

3. **Subsequence: ["m", "i"]**  
   Corresponding `groups` values: `[0, 1]`  
   Again, the values alternate (0 and 1), so this subsequence **is alternating**.

4. **Subsequence: ["a", "m", "i"]**  
   Corresponding `groups` values: `[0, 0, 1]`  
   The first two elements (`0, 0`) do not alternate, so this subsequence is **not alternating**.

So, for this example, the alternating subsequences of words are:
- `["a", "i"]`
- `["m", "i"]`

I hope this makes sense! Let me know if you'd like further clarification.


Q- so we can have many sequence that have this property so we need to find the one with  
The longest length 

Q- so in this problem we have a constrains and descritoon cireteir 

Q- the constrain 

Is each groups[ij] != groups[ij+1] each two adjance element maps to different binaies 
The selection crieteris is to find the longest one : 


Q- what is the input & output format here ? 

Input : List[str] , List[int] 
Output : List[str] 

Q- can you go through an example ? 




Oky 3ana honi el lista ha4i : words = [‘“e”,”a”,”b”] , w groups ha4a = [0,0,1] 
Q- awl 7aje el problem 3ando mapping feature that need to be maintained oky 

Q- donc ntswer enou nts3mlem ds twin honi → eli hiya hashmap 

Q- bsh ykon kema hka 
hashmap={“e”:0,”a”:0,”b”:1} 

Q- dema kef mtjkech the ideas direct 7well enik tnsk3ml naive solution w b3ed 7wel optimizer oky 

Q- the naive solution hoi enik tl3 … el sequence lkol oky 

Kema hka 
Here are all the subsequences of ["e", "a", "b"]:
Length 0: [] (empty subsequence)
Length 1: ["e"], ["a"], ["b"]
Length 2: ["e", "a"], ["e", "b"], ["a", "b"]
Length 3: ["e", "a", "b"]


Q- b3ed lzemik t3ml initlizeation le variable update fih 7ate tl9a a9kber length possible oky 

Longest = float(inf) // initiate to the smallest possible one 

Q- b3ed for kol “ current “ subseaqunce 

Step 1 : verify enha verify the constrain mt3 el problem 
Enou kol “pairwize” element (word : str) yokon mapped into tw differents binaries 
—> njom enou implement the logic here in a helper function oky 

Step 2 : if we return True 
Compute the length of it and update with the longest marila 
longest=max(longest,computed_length ) 


Q- bahii nt7bik twa be tounis mt3tinich solution w n3edf fema solution plus optimize ame n7eb t3teni feabakc 3le my thiniking process so far oky ?