判断一个字符串是否为回文（即正读和反读都一样），如果是，返回True，否则返回False。忽略字符串中的空格和标点符号。


def is_palindrome(string):
"""Take a string and check if it's a palindrome""" 
string = "A man, a plan, a canal, Panama!"
# TODO: check if the string is a palindrome and return the result
print(is_palindrome(string))
Here's an implementation of the function is_palindrome() that takes a string and returns True if it's a palindrome, ignoring whitespace and punctuation:

```python
import re

def is_palindrome(string):
    # Remove whitespace and punctuation from the string
    string = re.sub(r'\W+', '', string).lower()
    # Check if the string is equal to its reverse
    return string == string[::-1]

string = "A man, a plan, a canal, Panama!"
print(is_palindrome(string))  # True
```

This function first removes all non-alphanumeric characters using a regular expression, and then converts the string to lowercase. It then uses the slicing operator [::-1] to reverse the string and checks if it's equal to the original string. If so, it returns True, and otherwise it returns False.