Task: Fraction reduction

C: #include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

typedef struct IntArray_t {
    int *ptr;
    size_t length;
} IntArray;

IntArray make(size_t size) {
    IntArray temp;
    temp.ptr = calloc(size, sizeof(int));
    temp.length = size;
    return temp;
}

void destroy(IntArray *ia) {
    if (ia->ptr != NULL) {
        free(ia->ptr);

        ia->ptr = NULL;
        ia->length = 0;
    }
}

void zeroFill(IntArray dst) {
    memset(dst.ptr, 0, dst.length * sizeof(int));
}

int indexOf(const int n, const IntArray ia) {
    size_t i;
    for (i = 0; i < ia.length; i++) {
        if (ia.ptr[i] == n) {
            return i;
        }
    }
    return -1;
}

bool getDigits(int n, int le, IntArray digits) {
    while (n > 0) {
        int r = n % 10;
        if (r == 0 || indexOf(r, digits) >= 0) {
            return false;
        }
        le--;
        digits.ptr[le] = r;
        n /= 10;
    }
    return true;
}

int removeDigit(IntArray digits, size_t le, size_t idx) {
    static const int POWS[] = { 1, 10, 100, 1000, 10000 };
    int sum = 0;
    int pow = POWS[le - 2];
    size_t i;
    for (i = 0; i < le; i++) {
        if (i == idx) continue;
        sum += digits.ptr[i] * pow;
        pow /= 10;
    }
    return sum;
}

int main() {
    int lims[4][2] = { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
    int count[5] = { 0 };
    int omitted[5][10] = { {0} };
    size_t upperBound = sizeof(lims) / sizeof(lims[0]);
    size_t i;

    for (i = 0; i < upperBound; i++) {
        IntArray nDigits = make(i + 2);
        IntArray dDigits = make(i + 2);
        int n;

        for (n = lims[i][0]; n <= lims[i][1]; n++) {
            int d;
            bool nOk;

            zeroFill(nDigits);
            nOk = getDigits(n, i + 2, nDigits);
            if (!nOk) {
                continue;
            }
            for (d = n + 1; d <= lims[i][1] + 1; d++) {
                size_t nix;
                bool dOk;

                zeroFill(dDigits);
                dOk = getDigits(d, i + 2, dDigits);
                if (!dOk) {
                    continue;
                }
                for (nix = 0; nix < nDigits.length; nix++) {
                    int digit = nDigits.ptr[nix];
                    int dix = indexOf(digit, dDigits);
                    if (dix >= 0) {
                        int rn = removeDigit(nDigits, i + 2, nix);
                        int rd = removeDigit(dDigits, i + 2, dix);
                        if ((double)n / d == (double)rn / rd) {
                            count[i]++;
                            omitted[i][digit]++;
                            if (count[i] <= 12) {
                                printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit);
                            }
                        }
                    }
                }
            }
        }

        printf("\n");

        destroy(&nDigits);
        destroy(&dDigits);
    }

    for (i = 2; i <= 5; i++) {
        int j;

        printf("There are %d %d-digit fractions of which:\n", count[i - 2], i);

        for (j = 1; j <= 9; j++) {
            if (omitted[i - 2][j] == 0) {
                continue;
            }
            printf("%6d have %d's omitted\n", omitted[i - 2][j], j);
        }

        printf("\n");
    }

    return 0;
}





Java: import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

public class FractionReduction {

    public static void main(String[] args) {
        for ( int size = 2 ; size <= 5 ; size++ ) {
            reduce(size);
        }
    }
    
    private static void reduce(int numDigits) {
        System.out.printf("Fractions with digits of length %d where cancellation is valid.  Examples:%n", numDigits);
        
        
        int min = (int) Math.pow(10, numDigits-1);
        int max = (int) Math.pow(10, numDigits) - 1;
        List<Integer> values = new ArrayList<>();
        for ( int number = min ; number <= max ; number++ ) {
            if ( isValid(number) ) {
                values.add(number);
            }
        }
        
        Map<Integer,Integer> cancelCount = new HashMap<>(); 
        int size = values.size();
        int solutions = 0;
        for ( int nIndex = 0 ; nIndex < size - 1 ; nIndex++ ) {
            int numerator = values.get(nIndex);
            
            for ( int dIndex = nIndex + 1 ; dIndex < size ; dIndex++ ) {
                int denominator = values.get(dIndex);
                for ( int commonDigit : digitsInCommon(numerator, denominator) ) {
                    int numRemoved = removeDigit(numerator, commonDigit);
                    int denRemoved = removeDigit(denominator, commonDigit);
                    if ( numerator * denRemoved == denominator * numRemoved ) {
                        solutions++;
                        cancelCount.merge(commonDigit, 1, (v1, v2) -> v1 + v2);
                        if ( solutions <= 12 ) {
                            System.out.printf("    When %d is removed, %d/%d = %d/%d%n", commonDigit, numerator, denominator, numRemoved, denRemoved);
                        }
                    }
                }
            }
        }
        System.out.printf("Number of fractions where cancellation is valid = %d.%n", solutions);
        List<Integer> sorted = new ArrayList<>(cancelCount.keySet());
        Collections.sort(sorted);
        for ( int removed : sorted ) {
            System.out.printf("    The digit %d was removed %d times.%n", removed, cancelCount.get(removed));
        }
        System.out.println();
    }
    
    private static int[] powers = new int[] {1, 10, 100, 1000, 10000, 100000};
    
    
    private static int removeDigit(int n, int removed) {
        int m = 0;
        int pow = 0;
        while ( n > 0 ) {
            int r = n % 10;
            if ( r != removed ) {
                m = m + r*powers[pow];
                pow++;
            }
            n /= 10;
        }
        return m;
    }
        
    
    private static List<Integer> digitsInCommon(int n1, int n2) {
        int[] count = new int[10];
        List<Integer> common = new ArrayList<>();
        while ( n1 > 0 ) {
            int r = n1 % 10;
            count[r] += 1;
            n1 /= 10;
        }
        while ( n2 > 0 ) {
            int r = n2 % 10;
            if ( count[r] > 0 ) {
                common.add(r);
            }
            n2 /= 10;
        }
        return common;
    }
    
    
    private static boolean isValid(int num) {
        int[] count = new int[10];
        while ( num > 0 ) {
            int r = num % 10;
            if ( r == 0 || count[r] == 1 ) {
                return false;
            }
            count[r] = 1;
            num /= 10;
        }
        return true;
    }

}