WeixiangYan/CodeTransOcean huggingface dataset:
Task: Verify distribution uniformity_Naive


C++: #include <map>
#include <iostream>
#include <cmath>

template<typename F>
 bool test_distribution(F f, int calls, double delta)
{
  typedef std::map<int, int> distmap;
  distmap dist;

  for (int i = 0; i < calls; ++i)
    ++dist[f()];

  double mean = 1.0/dist.size();

  bool good = true;

  for (distmap::iterator i = dist.begin(); i != dist.end(); ++i)
  {
    if (std::abs((1.0 * i->second)/calls - mean) > delta)
    {
      std::cout << "Relative frequency " << i->second/(1.0*calls)
                << " of result " << i->first
                << " deviates by more than " << delta
                << " from the expected value " << mean << "\n";
      good = false;
    }
  }

  return good;
}




Java: import static java.lang.Math.abs;
import java.util.*;
import java.util.function.IntSupplier;

public class Test {

    static void distCheck(IntSupplier f, int nRepeats, double delta) {
        Map<Integer, Integer> counts = new HashMap<>();

        for (int i = 0; i < nRepeats; i++)
            counts.compute(f.getAsInt(), (k, v) -> v == null ? 1 : v + 1);

        double target = nRepeats / (double) counts.size();
        int deltaCount = (int) (delta / 100.0 * target);

        counts.forEach((k, v) -> {
            if (abs(target - v) >= deltaCount)
                System.out.printf("distribution potentially skewed "
                        + "for '%s': '%d'%n", k, v);
        });

        counts.keySet().stream().sorted().forEach(k
                -> System.out.printf("%d %d%n", k, counts.get(k)));
    }

    public static void main(String[] a) {
        distCheck(() -> (int) (Math.random() * 5) + 1, 1_000_000, 1);
    }
}
Task: Recaman's sequence


C++: #include <iostream>
#include <ostream>
#include <set>
#include <vector>

template<typename T>
std::ostream& operator<<(std::ostream& os, const std::vector<T>& v) {
    auto i = v.cbegin();
    auto e = v.cend();
    os << '[';
    if (i != e) {
        os << *i;
        i = std::next(i);
    }
    while (i != e) {
        os << ", " << *i;
        i = std::next(i);
    }
    return os << ']';
}

int main() {
    using namespace std;

    vector<int> a{ 0 };
    set<int> used{ 0 };
    set<int> used1000{ 0 };
    bool foundDup = false;
    int n = 1;
    while (n <= 15 || !foundDup || used1000.size() < 1001) {
        int next = a[n - 1] - n;
        if (next < 1 || used.find(next) != used.end()) {
            next += 2 * n;
        }
        bool alreadyUsed = used.find(next) != used.end();
        a.push_back(next);
        if (!alreadyUsed) {
            used.insert(next);
            if (0 <= next && next <= 1000) {
                used1000.insert(next);
            }
        }
        if (n == 14) {
            cout << "The first 15 terms of the Recaman sequence are: " << a << '\n';
        }
        if (!foundDup && alreadyUsed) {
            cout << "The first duplicated term is a[" << n << "] = " << next << '\n';
            foundDup = true;
        }
        if (used1000.size() == 1001) {
            cout << "Terms up to a[" << n << "] are needed to generate 0 to 1000\n";
        }
        n++;
    }

    return 0;
}




Java: import java.util.ArrayList;
import java.util.HashSet;
import java.util.List;
import java.util.Set;

public class RecamanSequence {
    public static void main(String[] args) {
        List<Integer> a = new ArrayList<>();
        a.add(0);

        Set<Integer> used = new HashSet<>();
        used.add(0);

        Set<Integer> used1000 = new HashSet<>();
        used1000.add(0);

        boolean foundDup = false;
        int n = 1;
        while (n <= 15 || !foundDup || used1000.size() < 1001) {
            int next = a.get(n - 1) - n;
            if (next < 1 || used.contains(next)) {
                next += 2 * n;
            }
            boolean alreadyUsed = used.contains(next);
            a.add(next);
            if (!alreadyUsed) {
                used.add(next);
                if (0 <= next && next <= 1000) {
                    used1000.add(next);
                }
            }
            if (n == 14) {
                System.out.printf("The first 15 terms of the Recaman sequence are : %s\n", a);
            }
            if (!foundDup && alreadyUsed) {
                System.out.printf("The first duplicate term is a[%d] = %d\n", n, next);
                foundDup = true;
            }
            if (used1000.size() == 1001) {
                System.out.printf("Terms up to a[%d] are needed to generate 0 to 1000\n", n);
            }
            n++;
        }
    }
}
Task: Memory allocation


C++: #include <string>

int main()
{
  int* p;

  p = new int;    
  delete p;       

  p = new int(2); 
  delete p;       

  std::string* p2;

  p2 = new std::string; 
  delete p2;            

  p = new int[10]; 
  delete[] p;      

  p2 = new std::string[10]; 
  delete[] p2;              
}




Java: 

Object foo = new Object(); 
int[] fooArray = new int[size]; 
int x = 0;
Task: Integer sequence


C++: #include <cstdint>
#include <iostream>
#include <limits>

int main()
{
  auto i = std::uintmax_t{};
  
  while (i < std::numeric_limits<decltype(i)>::max())
    std::cout << ++i << '\n';
}




Java: public class Count{
    public static void main(String[] args){
        for(long i = 1; ;i++) System.out.println(i);
    }
}
Task: Entropy_Narcissist


C++: #include <iostream>
#include <fstream>
#include <cmath>

using namespace std;

string readFile (string path) {
    string contents;
    string line;
    ifstream inFile(path);
    while (getline (inFile, line)) {
        contents.append(line);
        contents.append("\n");
    }
    inFile.close();
    return contents;
}

double entropy (string X) {
    const int MAXCHAR = 127;
    int N = X.length();
    int count[MAXCHAR];
    double count_i;
    char ch;
    double sum = 0.0;
    for (int i = 0; i < MAXCHAR; i++) count[i] = 0;
    for (int pos = 0; pos < N; pos++) {
        ch = X[pos];
        count[(int)ch]++;
    }
    for (int n_i = 0; n_i < MAXCHAR; n_i++) {
        count_i = count[n_i];
        if (count_i > 0) sum -= count_i / N * log2(count_i / N);
    }
    return sum;
}

int main () {
    cout<<entropy(readFile("entropy.cpp"));
    return 0;
}




Java: import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
import java.util.HashMap;
import java.util.Map;

public class EntropyNarcissist {

    private static final String FILE_NAME = "src/EntropyNarcissist.java";
    
    public static void main(String[] args) {
        System.out.printf("Entropy of file \"%s\" = %.12f.%n", FILE_NAME, getEntropy(FILE_NAME));
    }
    
    private static double getEntropy(String fileName) {
        Map<Character,Integer> characterCount = new HashMap<>();
        int length = 0;

        try (BufferedReader reader = new BufferedReader(new FileReader(new File(fileName)));) {        
            int c = 0;
            while ( (c = reader.read()) != -1 ) {
                characterCount.merge((char) c, 1, (v1, v2) -> v1 + v2);
                length++;
            }
        }
        catch ( IOException e ) {
            throw new RuntimeException(e);
        }
        
        double entropy = 0;
        for ( char key : characterCount.keySet() ) {
            double fraction = (double) characterCount.get(key) / length;
            entropy -= fraction * Math.log(fraction);
        }

        return entropy / Math.log(2);
    }

}
Task: DNS query


C++: #include <Rcpp.h>
#include <arpa/inet.h>
#include <sys/types.h>
#include <sys/socket.h>
#include <netdb.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

using namespace Rcpp ;


CharacterVector getNameInfo(std::string fqdn) {

  struct addrinfo hints, *res, *res0;
	int error;
	char host[NI_MAXHOST];

  memset(&hints, 0, sizeof hints);
	hints.ai_family = PF_UNSPEC;
	hints.ai_socktype = SOCK_DGRAM;

	error = getaddrinfo(fqdn.c_str(), NULL, &hints, &res0);
	if (error) { return(NA_STRING);	}

  int i = 0 ;
	for (res = res0; res; res = res->ai_next) {
  	error = getnameinfo(res->ai_addr, res->ai_addrlen,
		    host, sizeof host, NULL, 0, NI_NUMERICHOST);
		if (!error) { i++ ; }
	}

  CharacterVector results(i) ;

  i = 0;

  for (res = res0; res; res = res->ai_next) {
		error = getnameinfo(res->ai_addr, res->ai_addrlen,
		    host, sizeof host, NULL, 0, NI_NUMERICHOST);
		if (!error) { results[i++] = host ; }
	}

  freeaddrinfo(res0);

  return(results) ;

}




Java: import java.net.InetAddress;
import java.net.Inet4Address;
import java.net.Inet6Address;
import java.net.UnknownHostException;

class DnsQuery {
    public static void main(String[] args) {
        try {
            InetAddress[] ipAddr = InetAddress.getAllByName("www.kame.net");
            for(int i=0; i < ipAddr.length ; i++) {
                if (ipAddr[i] instanceof Inet4Address) {
                    System.out.println("IPv4 : " + ipAddr[i].getHostAddress());
                } else if (ipAddr[i] instanceof Inet6Address) {
                    System.out.println("IPv6 : " + ipAddr[i].getHostAddress());
                }
            }
        } catch (UnknownHostException uhe) {
            System.err.println("unknown host");
        }
    }
}
Task: Seven-sided dice from five-sided dice


C++: template<typename F> class fivetoseven
{
public:
  fivetoseven(F f): d5(f), rem(0), max(1) {}
  int operator()();
private:
  F d5;
  int rem, max;
};

template<typename F>
 int fivetoseven<F>::operator()()
{
  while (rem/7 == max/7)
  {
    while (max < 7)
    {
      int rand5 = d5()-1;
      max *= 5;
      rem = 5*rem + rand5;
    }

    int groups = max / 7;
    if (rem >= 7*groups)
    {
      rem -= 7*groups;
      max -= 7*groups;
    }
  }

  int result = rem % 7;
  rem /= 7;
  max /= 7;
  return result+1;
}

int d5()
{
  return 5.0*std::rand()/(RAND_MAX + 1.0) + 1;
}

fivetoseven<int(*)()> d7(d5);

int main()
{
  srand(time(0));
  test_distribution(d5, 1000000, 0.001);
  test_distribution(d7, 1000000, 0.001);
}




Java: import java.util.Random;
public class SevenSidedDice 
{
	private static final Random rnd = new Random();
	public static void main(String[] args)
	{
		SevenSidedDice now=new SevenSidedDice();
		System.out.println("Random number from 1 to 7: "+now.seven());
	}
	int seven()
	{
		int v=21;
		while(v>20)
			v=five()+five()*5-6;
		return 1+v%7;
	}
	int five()
	{
		return 1+rnd.nextInt(5);
	}
}
Task: Solve the no connection puzzle


C++: #include <array>
#include <iostream>
#include <vector>

std::vector<std::pair<int, int>> connections = {
    {0, 2}, {0, 3}, {0, 4}, 
    {1, 3}, {1, 4}, {1, 5}, 
    {6, 2}, {6, 3}, {6, 4}, 
    {7, 3}, {7, 4}, {7, 5}, 
    {2, 3}, {3, 4}, {4, 5}, 
};
std::array<int, 8> pegs;
int num = 0;

void printSolution() {
    std::cout << "----- " << num++ << " -----\n";
    std::cout << "  "  << pegs[0] << ' ' << pegs[1] << '\n';
    std::cout << pegs[2] << ' ' << pegs[3] << ' ' << pegs[4] << ' ' << pegs[5] << '\n';
    std::cout << "  "  << pegs[6] << ' ' << pegs[7] << '\n';
    std::cout << '\n';
}

bool valid() {
    for (size_t i = 0; i < connections.size(); i++) {
        if (abs(pegs[connections[i].first] - pegs[connections[i].second]) == 1) {
            return false;
        }
    }
    return true;
}

void solution(int le, int ri) {
    if (le == ri) {
        if (valid()) {
            printSolution();
        }
    } else {
        for (size_t i = le; i <= ri; i++) {
            std::swap(pegs[le], pegs[i]);
            solution(le + 1, ri);
            std::swap(pegs[le], pegs[i]);
        }
    }
}

int main() {
    pegs = { 1, 2, 3, 4, 5, 6, 7, 8 };
    solution(0, pegs.size() - 1);
    return 0;
}




Java: import static java.lang.Math.abs;
import java.util.*;
import static java.util.stream.Collectors.toList;
import static java.util.stream.IntStream.range;

public class NoConnection {

    
    static int[][] links = {
        {2, 3, 4}, 
        {3, 4, 5}, 
        {2, 4},    
        {5},       
        {2, 3, 4}, 
        {3, 4, 5}, 
    };

    static int[] pegs = new int[8];

    public static void main(String[] args) {

        List<Integer> vals = range(1, 9).mapToObj(i -> i).collect(toList());
        do {
            Collections.shuffle(vals);
            for (int i = 0; i < pegs.length; i++)
                pegs[i] = vals.get(i);

        } while (!solved());

        printResult();
    }

    static boolean solved() {
        for (int i = 0; i < links.length; i++)
            for (int peg : links[i])
                if (abs(pegs[i] - peg) == 1)
                    return false;
        return true;
    }

    static void printResult() {
        System.out.printf("  %s %s%n", pegs[0], pegs[1]);
        System.out.printf("%s %s %s %s%n", pegs[2], pegs[3], pegs[4], pegs[5]);
        System.out.printf("  %s %s%n", pegs[6], pegs[7]);
    }
}
Task: Create a two-dimensional array at runtime


C++: #include <iostream>

int main()
{
  
  int dim1, dim2;
  std::cin >> dim1 >> dim2;

  
  double* array_data = new double[dim1*dim2];
  double** array = new double*[dim1];
  for (int i = 0; i < dim1; ++i)
    array[i] = array_data + dim2*i;

  
  array[0][0] = 3.5;

  
  std::cout << array[0][0] << std::endl;

  
  delete[] array;
  delete[] array_data;

  return 0;
}




Java: import java.util.Scanner;

public class twoDimArray {
  public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        
        int nbr1 = in.nextInt();
        int nbr2 = in.nextInt();
        
        double[][] array = new double[nbr1][nbr2];
        array[0][0] = 42.0;
        System.out.println("The number at place [0 0] is " + array[0][0]);
  }
}
Task: Chinese remainder theorem


C++: 
#include <iostream>
#include <numeric>
#include <vector>
#include <execution>

template<typename _Ty> _Ty mulInv(_Ty a, _Ty b) {
	_Ty b0 = b;
	_Ty x0 = 0;
	_Ty x1 = 1;

	if (b == 1) {
		return 1;
	}

	while (a > 1) {
		_Ty q = a / b;
		_Ty amb = a % b;
		a = b;
		b = amb;

		_Ty xqx = x1 - q * x0;
		x1 = x0;
		x0 = xqx;
	}

	if (x1 < 0) {
		x1 += b0;
	}

	return x1;
}

template<typename _Ty> _Ty chineseRemainder(std::vector<_Ty> n, std::vector<_Ty> a) {
	_Ty prod = std::reduce(std::execution::seq, n.begin(), n.end(), (_Ty)1, [](_Ty a, _Ty b) { return a * b; });

	_Ty sm = 0;
	for (int i = 0; i < n.size(); i++) {
		_Ty p = prod / n[i];
		sm += a[i] * mulInv(p, n[i]) * p;
	}

	return sm % prod;
}

int main() {
	vector<int> n = { 3, 5, 7 };
	vector<int> a = { 2, 3, 2 };
 
	cout << chineseRemainder(n,a) << endl;
 
	return 0;
}




Java: import static java.util.Arrays.stream;

public class ChineseRemainderTheorem {

    public static int chineseRemainder(int[] n, int[] a) {

        int prod = stream(n).reduce(1, (i, j) -> i * j);

        int p, sm = 0;
        for (int i = 0; i < n.length; i++) {
            p = prod / n[i];
            sm += a[i] * mulInv(p, n[i]) * p;
        }
        return sm % prod;
    }

    private static int mulInv(int a, int b) {
        int b0 = b;
        int x0 = 0;
        int x1 = 1;

        if (b == 1)
            return 1;

        while (a > 1) {
            int q = a / b;
            int amb = a % b;
            a = b;
            b = amb;
            int xqx = x1 - q * x0;
            x1 = x0;
            x0 = xqx;
        }

        if (x1 < 0)
            x1 += b0;

        return x1;
    }

    public static void main(String[] args) {
        int[] n = {3, 5, 7};
        int[] a = {2, 3, 2};
        System.out.println(chineseRemainder(n, a));
    }
}
Task: Pi


C++: #include <iostream>
#include <boost/multiprecision/cpp_int.hpp>

using namespace boost::multiprecision;

class Gospers
{
    cpp_int q, r, t, i, n;

public:    

    
    Gospers() : q{1}, r{0}, t{1}, i{1}
    {
        ++*this; 
    }

    
    Gospers& operator++()
    {
        n = (q*(27*i-12)+5*r) / (5*t);

        while(n != (q*(675*i-216)+125*r)/(125*t))
        {
            r = 3*(3*i+1)*(3*i+2)*((5*i-2)*q+r);
            q = i*(2*i-1)*q;
            t = 3*(3*i+1)*(3*i+2)*t;
            i++;

            n = (q*(27*i-12)+5*r) / (5*t);
        }

        q = 10*q;
        r = 10*r-10*n*t;

        return *this;
    }

    
    int operator*()
    {
        return (int)n;
    }
};

int main()
{
    Gospers g;

    std::cout << *g << ".";  

    for(;;) 
    {
        std::cout << *++g;  
    }
}




Java: import java.math.BigInteger ;

public class Pi {
  final BigInteger TWO = BigInteger.valueOf(2) ;
  final BigInteger THREE = BigInteger.valueOf(3) ;
  final BigInteger FOUR = BigInteger.valueOf(4) ;
  final BigInteger SEVEN = BigInteger.valueOf(7) ;

  BigInteger q = BigInteger.ONE ;
  BigInteger r = BigInteger.ZERO ;
  BigInteger t = BigInteger.ONE ;
  BigInteger k = BigInteger.ONE ;
  BigInteger n = BigInteger.valueOf(3) ;
  BigInteger l = BigInteger.valueOf(3) ;

  public void calcPiDigits(){
    BigInteger nn, nr ;
    boolean first = true ;
    while(true){
        if(FOUR.multiply(q).add(r).subtract(t).compareTo(n.multiply(t)) == -1){
          System.out.print(n) ;
          if(first){System.out.print(".") ; first = false ;}
          nr = BigInteger.TEN.multiply(r.subtract(n.multiply(t))) ;
          n = BigInteger.TEN.multiply(THREE.multiply(q).add(r)).divide(t).subtract(BigInteger.TEN.multiply(n)) ;
          q = q.multiply(BigInteger.TEN) ;
          r = nr ;
          System.out.flush() ;
        }else{
          nr = TWO.multiply(q).add(r).multiply(l) ;
          nn = q.multiply((SEVEN.multiply(k))).add(TWO).add(r.multiply(l)).divide(t.multiply(l)) ;
          q = q.multiply(k) ;
          t = t.multiply(l) ;
          l = l.add(TWO) ;
          k = k.add(BigInteger.ONE) ;
          n = nn ;
          r = nr ;
        }
    }
  }

  public static void main(String[] args) {
    Pi p = new Pi() ;
    p.calcPiDigits() ;
  }
}
Task: Hofstadter Q sequence


C++: #include <iostream>
 
int main() {
   const int size = 100000;
   int hofstadters[size] = { 1, 1 };  
   for (int i = 3 ; i < size; i++) 
      hofstadters[ i - 1 ] = hofstadters[ i - 1 - hofstadters[ i - 1 - 1 ]] +
                             hofstadters[ i - 1 - hofstadters[ i - 2 - 1 ]];
   std::cout << "The first 10 numbers are: ";
   for (int i = 0; i < 10; i++) 
      std::cout << hofstadters[ i ] << ' ';
   std::cout << std::endl << "The 1000'th term is " << hofstadters[ 999 ] << " !" << std::endl;
   int less_than_preceding = 0;
   for (int i = 0; i < size - 1; i++)
      if (hofstadters[ i + 1 ] < hofstadters[ i ]) 
	     less_than_preceding++;
   std::cout << "In array of size: " << size << ", ";
   std::cout << less_than_preceding << " times a number was preceded by a greater number!" << std::endl;
   return 0;
}




Java: import java.util.HashMap;
import java.util.Map;

public class HofQ {
	private static Map<Integer, Integer> q = new HashMap<Integer, Integer>(){{
		put(1, 1);
		put(2, 1);
	}};
	
	private static int[] nUses = new int[100001];
	
	public static int Q(int n){
		nUses[n]++;
		if(q.containsKey(n)){
			return q.get(n);
		}
		int ans = Q(n - Q(n - 1)) + Q(n - Q(n - 2));
		q.put(n, ans);
		return ans;
	}
	
	public static void main(String[] args){
		for(int i = 1; i <= 10; i++){
			System.out.println("Q(" + i + ") = " + Q(i));
		}
		int last = 6;
		int count = 0;
		for(int i = 11; i <= 100000; i++){
			int curr = Q(i);
			if(curr < last) count++;
			last = curr;
			if(i == 1000) System.out.println("Q(1000) = " + curr);
		}
		System.out.println("Q(i) is less than Q(i-1) for i <= 100000 " + count + " times");
		
		
		int maxUses = 0, maxN = 0;
		for(int i = 1; i<nUses.length;i++){
			if(nUses[i] > maxUses){
				maxUses = nUses[i];
				maxN = i;
			}
		}
		System.out.println("Q(" + maxN + ") was called the most with " + maxUses + " calls");
	}
}
Task: Y combinator


C++: #include <iostream>
#include <functional>

template <typename F>
struct RecursiveFunc {
	std::function<F(RecursiveFunc)> o;
};

template <typename A, typename B>
std::function<B(A)> Y (std::function<std::function<B(A)>(std::function<B(A)>)> f) {
	RecursiveFunc<std::function<B(A)>> r = {
		std::function<std::function<B(A)>(RecursiveFunc<std::function<B(A)>>)>([f](RecursiveFunc<std::function<B(A)>> w) {
			return f(std::function<B(A)>([w](A x) {
				return w.o(w)(x);
			}));
		})
	};
	return r.o(r);
}

typedef std::function<int(int)> Func;
typedef std::function<Func(Func)> FuncFunc;
FuncFunc almost_fac = [](Func f) {
	return Func([f](int n) {
		if (n <= 1) return 1;
		return n * f(n - 1);
	});
};

FuncFunc almost_fib = [](Func f) {
	return Func([f](int n) {
	 	if (n <= 2) return 1;
		return  f(n - 1) + f(n - 2);
	});
};

int main() {
	auto fib = Y(almost_fib);
	auto fac = Y(almost_fac);
	std::cout << "fib(10) = " << fib(10) << std::endl;
	std::cout << "fac(10) = " << fac(10) << std::endl;
	return 0;
}




Java: import java.util.function.Function;

public interface YCombinator {
  interface RecursiveFunction<F> extends Function<RecursiveFunction<F>, F> { }
  public static <A,B> Function<A,B> Y(Function<Function<A,B>, Function<A,B>> f) {
    RecursiveFunction<Function<A,B>> r = w -> f.apply(x -> w.apply(w).apply(x));
    return r.apply(r);
  }

  public static void main(String... arguments) {
    Function<Integer,Integer> fib = Y(f -> n ->
      (n <= 2)
        ? 1
        : (f.apply(n - 1) + f.apply(n - 2))
    );
    Function<Integer,Integer> fac = Y(f -> n ->
      (n <= 1)
        ? 1
        : (n * f.apply(n - 1))
    );

    System.out.println("fib(10) = " + fib.apply(10));
    System.out.println("fac(10) = " + fac.apply(10));
  }
}
Task: Van Eck sequence


C++: #include <iostream>
#include <map>

class van_eck_generator {
public:
    int next() {
        int result = last_term;
        auto iter = last_pos.find(last_term);
        int next_term = (iter != last_pos.end()) ? index - iter->second : 0;
        last_pos[last_term] = index;
        last_term = next_term;
        ++index;
        return result;
    }
private:
    int index = 0;
    int last_term = 0;
    std::map<int, int> last_pos;
};

int main() {
    van_eck_generator gen;
    int i = 0;
    std::cout << "First 10 terms of the Van Eck sequence:\n";
    for (; i < 10; ++i)
        std::cout << gen.next() << ' ';
    for (; i < 990; ++i)
        gen.next();
    std::cout << "\nTerms 991 to 1000 of the sequence:\n";
    for (; i < 1000; ++i)
        std::cout << gen.next() << ' ';
    std::cout << '\n';
    return 0;
}




Java: import java.util.HashMap;
import java.util.Map;

public class VanEckSequence {

    public static void main(String[] args) {
        System.out.println("First 10 terms of Van Eck's sequence:");
        vanEck(1, 10);
        System.out.println("");
        System.out.println("Terms 991 to 1000 of Van Eck's sequence:");
        vanEck(991, 1000);
    }
    
    private static void vanEck(int firstIndex, int lastIndex) {
        Map<Integer,Integer> vanEckMap = new HashMap<>();        
        int last = 0;
        if ( firstIndex == 1 ) {
            System.out.printf("VanEck[%d] = %d%n", 1, 0);
        }
        for ( int n = 2 ; n <= lastIndex ; n++ ) {
            int vanEck = vanEckMap.containsKey(last) ? n - vanEckMap.get(last) : 0;
            vanEckMap.put(last, n);
            last = vanEck;
            if ( n >= firstIndex ) {
                System.out.printf("VanEck[%d] = %d%n", n, vanEck);
            }
        }
        
    }

}
Task: Loops_Continue


C++: for(int i = 1;i <= 10; i++){
   cout << i;
   if(i % 5 == 0){
      cout << endl;
      continue;
   }
   cout << ", ";
}




Java: for(int i = 1;i <= 10; i++){
   System.out.print(i);
   if(i % 5 == 0){
      System.out.println();
      continue;
   }
   System.out.print(", ");
}