Database: food_inspection_2
Question: Which business had the highest number of inspections done? Calculate the percentage of passed and failed inspections of the said business.
SQL: SELECT T2.dba_name , CAST(SUM(CASE WHEN T1.results = 'Pass' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T1.inspection_id) AS percentagePassed , CAST(SUM(CASE WHEN T1.results = 'Fail' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T1.inspection_id) FROM inspection AS T1 INNER JOIN establishment AS T2 ON T1.license_no = T2.license_no GROUP BY T2.dba_name ORDER BY COUNT(T1.license_no) DESC LIMIT 1