Database: food_inspection
Question: List the business' name and risk category of businesses with a score greater than the 80% of average score of all businesses.
SQL: SELECT DISTINCT T1.name, T3.risk_category FROM businesses AS T1 INNER JOIN inspections AS T2 ON T1.business_id = T2.business_id INNER JOIN violations AS T3 ON T1.business_id = T3.business_id WHERE T2.score > 0.8 * ( SELECT AVG(score) FROM inspections )