Domain: Boron cluster chemistry

\(\mathrm{CH_3CH_2OH}\), a primary alcohol, was reacted with \(\mathrm{SOCl_2}\) in the presence of pyridine to form compound A, along with the liberation of gaseous by-products. Compound A was then treated with \(\mathrm{[Bu_4N]_2[B_6H_6]}\) in \(\mathrm{CH_2Cl_2}\), resulting in the formation of compound B. Subsequent reaction of compound B with \(\mathrm{CsOH}\) in ethanol produced a precipitate identified as compound C. Determine the molecular formula of the chemical species obtained as compound C.

Grading rubric:
criterion: Explicitly categorizes the formation of Compound A as an SN2 mechanism facilitated by the nucleophilic catalysis of pyridine.
weight: 10
criterion: Identifies the exact molecular formula of the intermediate Compound B as [Bu_4N][B_6H_5(mu3-H)C_2H_5] 
weight: 10
criterion: Utilizes the explicit coordination notation mu3 to describe the face-bridging position of the extra-polyhedral hydrogen in Compound B.
weight: 20
criterion: Explicitly defines the substituted borane cluster in Compound B as a monoanionic species (1-).
weight: 10
criterion: The final answer specifies the molecular formula of Compound C as exactly Cs_2C_2H_10B_6.
weight: 20
criterion: Explicitly states the presence of two cesium (Cs) counter-cations to satisfy the charge balance of the dianionic ethyl-substituted cluster.
weight: 10
criterion: The chemical equation for the final step explicitly lists [Bu4N]OH as one of the secondary products formed alongside the precipitate.
weight: 20

Answer:
Cs2C2H10B6