TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
n, x = map(int, input().split())
l = [int(i) for i in input().split()]
d = 0
i = 0
while d <= x:
    d += l[i]
    i += 1
    print('i:', i, 'd:', d)

print(i)

n, x = map(int, input().split())
l = [int(i) for i in input().split()]
print(l)
d = 0
i = 0
while (d <= x) and (i < n):
    d += l[i]
    i += 1
print(i)

n, x = map(int, input().split())
l = [int(i) for i in input().split()]
l.insert(0, 0)
d = 0
i = 0
while True:
    d += l[i]
    if d > x:
        break
    i += 1
    if i > n:
        break
print(i)

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
N, X =map(int,input().split())
a = list(map(int,input().split()))
print(a)
x = 0
count = 0
for i in range(len(a)):
    count += 1
    x += a[i]
    if x > X:
        break
print(count)

N, X =map(int,input().split())
a = list(map(int,input().split()))
x = 0
count = 0
for i in range(len(a)+1):
    count += 1
    if not i == len(a):
        x += a[i]
    else:
        break
    if x > X:
        break
print(count)

Verdicts: Wrong Answer

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
N, X = map(int, input().split())
L = list(map(int, input().split()))

D = [0]
for l in L:
  d = D[-1] + L
  if d <= X:
    D.append(d)
  else:
    break

print(len(D))

N, X = map(int, input().split())
L = list(map(int, input().split()))

D = [0]
for l in L:
  d = D[-1] + l
  if d <= X:
    D.append(d)
  else:
    break

print(len(D))


Verdicts: Runtime Error

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
oukei=0 
count=1

N,X =map(int, input().split())
L= list(map(int, input().split()))
    

for i in range(N-1):
    goukei +=L[i]
    
    if(goukei>X):
        break
    else:
        count +=1
        
print(count)

oukei=0 
count=1

N,X =map(int, input().split())
L= list(map(int, input().split()))
    

for i in range(N):
    goukei +=L[i]
    
    if(goukei>X):
        break
    else:
        count +=1
        
print(count)

goukei=0 
count=1

N,X =map(int, input().split())
L= list(map(int, input().split()))
    

for i in range(N):
    goukei +=L[i]
    
    if(goukei>X):
        break
    else:
        count +=1
        
print(count)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
n,x = map(int,input().split())
l = [int(i) for i in input().split()]
print(l)
d = [0]
count = 1
for i in range(1,n+1):
    d.append(d[i-1]+l[i-1])
    print(d)
    if d[i] <= x:
        count += 1
print(count)

n,x = map(int,input().split())
l = [int(i) for i in input().split()]
d = [0]
count = 1
for i in range(1,n+1):
    d.append(d[i-1]+l[i-1])
    if d[i] <= x:
        count += 1
print(count)

Verdicts: Wrong Answer

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
N,X=map(int,input().split())
L=list(map(int,input().split()))
x=0
time=1
while x<=X and time<=len(L):
    x+=L[time-1]
    time+=1
print(time)


N,X=map(int,input().split())
L=list(map(int,input().split()))
x=0
time=0
for i in range(N+1):
  if x<=X:
    time+=1
  if i<N:
    count+=1
print(time)


N,X=map(int,input().split())
L=list(map(int,input().split()))
xs=[]
x=0
time=1
for i in range(N):
  x+=L[i]
  xs.append(x)
for i in range(N):
  if xs[i]<=X:
    time+=1
  else:
    break
print(time)


Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
n,x=map(int,input().split())
listl=list(map(int,input().split()))
sum=0
for k in range(2,n+1):
  while sum<=x:
    sum+=listl[k-2]
print(k)

n,x=map(int,input().split())
listl=list(map(int,input().split()))
sum=0
count=0
for k in range(2,n+1):
  sum+=listl[k-2]
  while sum<=x:
    count+=1
print(count+1)

n,x=map(int,input().split())
l=list(map(int,input().split()))
d=[0]
for i in range(n):
  d.append(d[i]+l[i])
cnt=0
for dd in d:
  if dd>x:
    break
  cnt+=1
print(cnt)

Verdicts: Wrong Answer

Time Limit Exceeded

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
N, X = [int(i) for i in input().strip().split()]
L = [int(i) for i in input().strip().split()]

pos = 0
res = 1
for i in range(N):
  if X < pos:
    break
  pos += L[i]
  res += 1
print(res)


N, X = [int(i) for i in input().strip().split()]
L = [int(i) for i in input().strip().split()]

pos = 0
res = 1
for i in range(N):
  pos += L[i]
  if X < pos:
    break
  res += 1
print(res)


Verdicts: Wrong Answer

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
N, X = map(int,input().split())
L = list(map(int,input().split()))

ans = 0
D = 0
for i in range(N + 1):
  if i == 0:
    ans += 1
  else:
    D += L[i - 1]
    ans += 1

print(ans)



N, X = map(int,input().split())
L = list(map(int,input().split()))

ans = 0
D = 0
for i in range(N + 1):
  if i == 0:
    ans += 1
  else:
    D += L[i - 1]
    if D <= X:
      ans += 1
    else:
      break

print(ans)


Verdicts: Wrong Answer

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
N,X=map(int,input().split())
L=list(map(int,input().split()))
bound=1
D=0
for i in range(N+1):
  D+=L[i]
  if D<=X:
    bound+=1
  else:
    pass
print(bound)

N,X=map(int,input().split())
L=list(map(int,input().split() ) )
bound=1
D=0
for n in L:
  D+=n
  if D<=X:
    bound+=1
  else:
    break
print(bound)

Verdicts: Runtime Error

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
n,x=map(int,input().split())
l=[int(i) for i in input().split()]
m=[0]
for i in range(n):
    m.append(m[i]+l[i])
a=0
for i in range(n):
    a+=l[i]
    if a>x:
        ans=i+1
    else:
        ans=n+1
print(ans)

n,x=map(int,input().split())
l=[int(i) for i in input().split()]
a=0
for i in range(n):
    a+=l[i]
    if a>x:
        ans=i+1
        break
    else:
        ans=n+1
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
N, X = map(int, input().split())
L = list(map(int, input().split()))
bound = 0
D = 0
i = 0
while D =< X and i < N:
    bound += 1
    D = D + L[i]
    i += 1
print(bound)

N, X = map(int, input().split())
L = list(map(int, input().split()))
bound = 1
D = 0
i = 0
for i in range(N):
    if X >= D + L[i]:
        bound += 1
        D = D + L[i]
    else:
        break
print(bound)


Verdicts: Runtime Error

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
n,x = map(int,input().split())
l=list(map(int,input().split()))

plot=0
cnt=0

for i in range(n):
    plot += l[i]
    if l[i] <= x:
        cnt += 1

print(cnt)

n,x = map(int,input().split())
l=list(map(int,input().split()))

plot=0
cnt=1

for i in range(n):
    plot += l[i]
    if plot <= x:
        cnt += 1

print(cnt)

Verdicts: Wrong Answer

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
N,X=map(int, input().split()) 
L=list(map(int, input().split())) 
D = 0
for i in range(N):
  D = D + L[i]
  if D > X:
    print(i+1)
    break
  if D == X:
    print(i+2)
    break
print(i+2)

N,X=map(int, input().split()) 
L=list(map(int, input().split())) 
D = 0
for i in range(N):
  D = D + L[i]
  if D > X:
    print(i+1)
    break
  if D == X:
    print(i+2)
    break
  if D < X and i == N-1:
    print(i+2)
    break
  



Verdicts: Wrong Answer

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
n, x = [int(i) for i in input().split()]
l = [int(i) for i in input().split()]

cnt = 0
di = 0
if sum(l) <= x:
  print(n+1)
else:
  while di <= x:
    cnt += 1
    di += l[cnt-1]
    print(cnt)

n, x = [int(i) for i in input().split()]
l = [int(i) for i in input().split()]

cnt = 0
di = 0

if sum(l) < x or sum(l) is x:
  print(n + 1)
else:
  for i, li in enumerate(l, 1):
    di += li
    if di > x:
      i -= 1
      break
    if di is x:
      break
    
  print(i+1)


Verdicts: Wrong Answer

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
n, x = map(int, input().split())
l = list(map(int,(input().split())))

d = [0]
for i in range(1,n):
    d.append(d[i-1]+l[i-1])
    if sum(d) <=x:
        print(d)
    else:
        break

print(len(d))

n, x = map(int, input().split())
l = list(map(int,(input().split())))

d = 0
cnt = 1
for i in range(n):
    d += l[i]
    if d <=x:
        cnt += 1
    else:
        break

print(cnt)

Verdicts: Wrong Answer

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
n, x = map(int, input().split())
print("n:%d" %n)
print("x:%d" %x)
l = list(map(int, input().split()))
sum = 0
b = 1;
for i in range(n):
	sum = sum + l[i]
	if(sum > x):
		print(b)
		break
	else:
		if(i == n-1):
			print(n+1)
			break
		else:
			b=b+1

n, x = map(int, input().split())
l = list(map(int, input().split()))
sum = 0
b = 1;
for i in range(n):
	sum = sum + l[i]
	if(sum > x):
		print(b)
	else:
		if(i == n-1):
			print(n+1)
		else:
			b=b+1

#s = input().split()
#n = int(s[0])
#x = int(s[1])
n, x = map(int, input().split())
l = list(map(int, input().split()))
if sum(l) <= x:
	print(n)
else :
	for i in range(n):
		ll=l[:i+1]
		#print("sum:%d" % sum(ll))
		if sum(ll) > x:
			print(i+1)

n, x = map(int, input().split())
#print("n:%d" %n)
#print("x:%d" %x)
l = list(map(int, input().split()))
sum = 0
b = 1;
for i in range(n):
	sum = sum + l[i]
	if(sum > x):
		print(b)
		break
	else:
		if(i == n-1):
			print(n+1)
			break
		else:
			b=b+1

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
# -*- coding: utf-8 -*-
import sys




#Given:
    #N X
    #L1, L2, L3, ... LN-1, LN




i = input()
lis = i.split()

N = int(lis[0])

X = int(lis[1])




i = input()
lis = i.split()

L = list()
for k in lis:
    print(k)
    L.append(int(k)) 
#print(L)


if N != len(L):
    print("跳ねる回数と跳ねる位置のリスト数が一致していません。")
    sys.exit()


D = list()

#D0 = 0
D.append(0)
for k in range(0,len(L)):
    D.append(D[k]+L[k]) 
#print(D)


n = sum(test <= X for test in D)  


print(n)


# -*- coding: utf-8 -*-
import sys




#Given:
    #N X
    #L1, L2, L3, ... LN-1, LN




i = input()
lis = i.split()

N = int(lis[0])

X = int(lis[1])




i = input()
lis = i.split()

L = list()
for k in lis:
    #print(k)
    L.append(int(k)) 
#print(L)


if N != len(L):
    print("跳ねる回数と跳ねる位置のリスト数が一致していません。")
    sys.exit()


D = list()

#D0 = 0
D.append(0)
for k in range(0,len(L)):
    D.append(D[k]+L[k]) 
#print(D)


n = sum(test <= X for test in D)  


print(n)


Verdicts: Wrong Answer

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
from itertools import accumlate
n,x = map(int,input().split())
lst_l = [0] + list(map(int,input().split()))
lst_wa = list(accumulate(lst_l))
cnt = 0
for i in lst_wa:
    if i < x:
        cnt += 1
print(cnt)

import itertools
n,x = map(int,input().split())
lst_l = [0] + list(map(int,input().split()))
lst_wa = list(accumulate(lst_l))
cnt = 0
for i in lst_wa:
    if i < x:
        cnt += 1
print(cnt)

from itertools import accumulate
n,x = map(int,input().split())
lst_l = [0] + list(map(int,input().split()))
lst_wa = list(accumulate(lst_l))
cnt = 0
for i in lst_wa:
    if i <= x:
        cnt += 1
print(cnt)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
n, x = list(map(int, input().split()))
l = list(map(int, input().split()))
c = 0
total = 0
for i in l:
  total += i
  if total > x:
    print(c+1)
    break
  c += 1
print(c)

n, x = list(map(int, input().split()))
l = list(map(int, input().split()))
c = 1
total = 0
for i in l:
  total += i
  if total <= x:
    c+=1
print(c)

Verdicts: Wrong Answer

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
N,X= map(int,input().split())
li = list(map(int,input().split()))
count = 0
for i in range(len(li)):
    if li[i]<=X:
        count +=1
    else:
        pass
print(count)

n, x = map(int, input().split())
li = list(map(int, input().split()))

num = 0
ans = 1

for i in range(n):
    num += li[i]
    if num <= x:
        ans += 1

print(ans)

Verdicts: Wrong Answer

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
import sys

if __name__ == '__main__':
  N = 0
  X = 0
  L = []
  for i, line in enumerate(sys.stdin):
    if i == 2:
      break
    line = line.split()
    if i == 0:
      N = line[0]
      X = line[1]
    if i == 1:
      L = line
  D = 0
  count = 0
  for l in L:
    if D < X:
      count += 1
    D += int(l)
  print(count)

N, X = map(int, input().split())
L = map(int, input().split())
D = 0
count = 1
for i, l in enumerate(L):
  if D <= X:
      count += 1
  D += l
print(count)

N, X = map(lambda x: int(x), input().split())[:2]
L = map(lambda x: int(x), input().split())
D = 0
count = 0
for i, l in enumerate(L):
if D <= X:
    count += 1
D += int(l)
print(count)

N, X = map(lambda x: int(x), input().split())
L = map(lambda x: int(x), input().split())
D = 0
count = 0
for i, l in enumerate(L):
if D <= X:
    count += 1
D += int(l)
print(count)

import sys

if __name__ == '__main__':
  N, X = map(input().split(), lambda x: int(x))
  L = map(input().split(), lambda x: int(x))
  D = 0
  count = 0
  for i, l in enumerate(L):
    if D <= X:
      count += 1
    D += l
  print(count)

N, X = list(int, input().split()[:2])
L = map(int, input().split())
D = 0
count = 0
for l in L:
  if D <= X:
      count += 1
  D += l
print(count)

N, X = map(lambda x: int(x), input().split())[:2]
L = map(lambda x: int(x), input().split())
D = 0
count = 0
for l in L:
  if D <= X:
      count += 1
  D += l
print(count)

import sys

if __name__ == '__main__':
  N = 0
  X = 0
  L = []
  for i, line in enumerate(sys.stdin):
    if i == 2:
      break
    line = line.split()
    if i == 0:
      N = line[0]
      X = line[1]
    if i == 1:
      L = line
  D = 0
  count = 0
  for l in L:
    if D < X:
      count += 1
    D += int(l)
  print(count)

N, X = list(int, input().split()))[:2]
L = map(int, input().split())
D = 0
count = 0
for l in L:
  if D <= X:
      count += 1
  D += l
print(count)

N, X = map(lambda x: int(x), input().split())[:2]
L = map(lambda x: int(x), input().split())
D = 0
count = 0
for l in L:
  if D <= X:
      count += 1
  D += int(l)
print(count)

N, X = map(int, input().split())
L = map(int, input().split())
D = 0
count = 1
for i, l in enumerate(L):
  D += l
  if D <= X:
      count += 1
print(count)

Verdicts: Runtime Error

Wrong Answer

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
# Input
N, X = map(int, input().split())
L = [int(l) for l in input().split()]
#
d, i, c = 0, 0, 1
for i in range(N):
    print(i,d, c)
    d = d + L[i]
    if (d > X):
        break
    c += 1
print(c)


# Input
N, X = map(int, input().split())
L = [int(l) for l in input().split()]
#
d, i, c = 0, 0, 1
for i in range(N):
    d = d + L[i]
    if (d > X):
        break
    c += 1
    
print(c)


Verdicts: Wrong Answer

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
# -*- coding: utf-8 -*-
def main():
    N,X = map(int,input().split())
    L=[int(i) for i in input().split()]
    Ls = 0
    count = 1
    for i in range(N):
        Ls = Ls+L[i]
        print(Ls)
        if Ls<=X:
            count+=1
    print(count)


if __name__ == '__main__':
    main()

# -*- coding: utf-8 -*-
def main():
    N,X = map(int,input().split())
    L=[int(i) for i in input().split()]
    Ls = 0
    count = 1
    for i in range(N):
        Ls = Ls+L[i]
        #print(Ls)
        if Ls<=X:
            count+=1
    print(count)


if __name__ == '__main__':
    main()

Verdicts: Wrong Answer

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
def main():
    N, X = map(int, input().split())
    L = list(map(int, input().split()))

    ans = 0
    D = 0
    for i in range(N):
        D = D + L[i]
        if D > X:
            break
        ans+=1
    return ans
    
if __name__ == '__main__':
    print(main())


def main():
    N, X = map(int, input().split())
    L = list(map(int, input().split()))
 
    ans = 1
    D = 0
    for i in range(N):
      D = D + L[i]
      if D <= X:
        ans+=1
        
    return ans
    
if __name__ == '__main__':
    print(main())

Verdicts: Wrong Answer

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
n, x = (int(c) for c in input().split())
l = (int(c) for c in input().split())
l.insert(0,0)
flag = 0
count = 0
for i in range(int(n)+1):
    count = count + int(l[i])

    if count > int(x):
        print(i)
        flag = 1
        break

if flag == 0:
    print(int(n)+1)

n, x = input().split()
l = input().split()
l.insert(0,0)
a = 0
flag = 0
for i in range(int(n)+1):
    a = a + int(l[i])

    if a > int(x):
        print(i)
        flag = 1
        break

if flag == 0:
    print(int(n)+1)

Verdicts: Runtime Error

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
N,X = map(int,input().split())
L = list(map(int,input().split()))

D = [0] * (N + 1)

counter = 0

for i in range(1,len(L)):
	D[i] = D[i - 1] + L[i - 1]
	print(D)
	
	
for i in range(0,len(D)):
	if D[i] <= X:
	counter += 1
	
print(counter)

N,X = map(int,input().split())
L = list(map(int,input().split()))

D = [0] * (N + 1)

counter = 0

for i in range(1,len(L)+1):
	D[i] = D[i - 1] + L[i - 1]
	
	
for i in range(0,len(D)):
	if D[i] <= X:
		counter += 1
	
print(counter)

Verdicts: Runtime Error

Accepted
Problem: A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.  How many times will the ball make a bounce where the coordinate is at most X?

Submission attempts (in order):
import bisect as bi
I=lambda:list(map(int,input().split()))
n,x=I()
l=I()
ans=0
t=0
for i in range(1,n):
  l[i]+=l[i-1]
an=bi.bisect(l,x)
print(an)


import bisect as bi
I=lambda:list(map(int,input().split()))
n,x=I()
l=I()
ans=0
t=0
for i in range(1,n):
  l[i]+=l[i-1]
an=bi.bisect(l,x)
print(an+1)


Verdicts: Wrong Answer

Accepted
Problem: There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H). You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Submission attempts (in order):
w, h, x, y = [int(s) for s in input().split(" ")]

a = w * h

print("%f %d" % (a * 0.5, int(w // 2 == x and h // 2 == y))

w, h, x, y = [int(s) for s in input().split(" ")]

a = w * h

print("%d %d" % (a * 0.5, int(w // 2 == x and h // 2 == y))

w, h, x, y = [int(s) for s in input().split(" ")]

a = w * h

print("%lf %d" % (a * 0.5, int(divmod(w, 2) == (x, 0) and divmod(h, 2) == (y, 0))))

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H). You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Submission attempts (in order):
W,H,x,y = map(int,input().split())

if W/2 == x and H/2 == y:
	S = W*H/2
	print("%f %d" % (S,1))
elif W*y == H*x or H*x + W*y == W*H:
	print("%f %d" % (W*H/2,0))
elif x == 0 or y == 0 or x == W or y == H:
	print("0.000000 0")
else:
	S1 = min(x,W-x) * H
	S2 = min(y,H-y) * W
	print("%f %d" % (max(S1,S2),1))


W,H,x,y = map(int,input().split())

if W/2 == x and H/2 == y:
	S = W*H/2
	print("%f %d" % (S,1))
elif x == 0 or y == 0 or x == W or y == H:
	print("0.000000 0")
else:
	S1 = min(x,W-x) * H
	S2 = min(y,H-y) * W
	print("%f %d" % (max(S1,S2),1))

W,H,x,y = map(int,input().split())
S = W*H/2

if W/2 == x and H/2 == y:
	print("%f %d" % (S,1))
else:
	print("%f %d" % (S,0))

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H). You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Submission attempts (in order):
w,h,x,y= map(int, input().split())

d=w*h/2
if x == w/2 or y == h/2:
    k = 0
if x == w/2 and y == h/2:
    k = 1
print(d, k)


w,h,x,y= map(int, input().split())

d=w*h/2
k = 1
if x == w/2 or y == h/2:
    k = 0

print(d, k)


w,h,x,y= map(int, input().split())

d=w*h/2
k = 1
if x == w/2 or y == h/2:
    k = 0
if x == w/2 and y == h/2:
    k = 1
print(d, k)


w,h,x,y= map(int, input().split())

k = 0
if x == w/2 or y == h/2:
    k = 0
if x == w/2 and y == h/2:
    k = 1

print("%f %d" %(w*h/2, k))

Verdicts: Runtime Error

Wrong Answer

Wrong Answer

Accepted
Problem: There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H). You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Submission attempts (in order):
while True:
    try:
        W, H, x, y = map(int, input().split())
        
        cut = (x == W // 2) + (y == H // 2)
        if cut > 0:
            area = (W * H) / 2
        else:
            area = min(x*H, y*W)
            
        print(area, 1 if cut > 1 else 0)
    except:
        break

while True:
    try:
        W, H, x, y = map(int, input().split())
        
        if (x*2 == W) and (y*2 == H):
            res = 1
        else:
            res = 0
            
        print("%.6f %d" % (W*H/2, res))
    except:
        break

Verdicts: Wrong Answer

Accepted
Problem: There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H). You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Submission attempts (in order):
    w,h,x,y = map(float, input().split())
    if (abs(w//2-x)>abs(h//2-y)):
        print("{:.6f} {}".format(min(y*w,(h-y)*w),0))
    elif (abs(w//2-x)<abs(h//2-y)):
        print("{:.6f} {}".format(min(x*h,(w-x)*h),0))
    else:
        print("{:.6f} {}".format(min(x*h,(w-x)*h),1))

w,h,x,y = map(float, input().split())
print('{:.6f} {}'.format(float(w)*float(h)/2, int(x+x==w and y+y==h)))

Verdicts: Runtime Error

Accepted
Problem: There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H). You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Submission attempts (in order):
W,H,x,y = map(int,input().split())

#print(W,H,x,y)
if x ==W/2 and y == H/2:
    area =  "{0:.6f}".format(float(x*H))
    print(area,1)
else:
    area ="{0:.6f}".format(float(min(W-x)*H,x*H))
    print(area,0)

W,H,x,y = map(int,input().split())

#print(W,H,x,y)
if x ==W/2 and y == H/2:
    area = x*H
    print(area,1)
else:
    area = min((W-x)*H,x*H)
    print(area,0)

W,H,x,y = map(int,input().split())

#print(W,H,x,y)
area =  "{0:.6f}".format(float(W*H/2))
if x == W/2 and y == H/2:
    print(area,1)
else:
    print(area,0)

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H). You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Submission attempts (in order):
W,H,x,y=list(map(int,input().split()))
print(W,H,x,y)
if x==W/2 and y==H/2:
  print("{:.6f} 1".format(W*H/2))
else:
  print("{:.6f} 0".format(W*H/2))


W,H,x,y=list(map(int,input().split()))
print(W,H,x,y)
if x==W/2 and y=H/2:
  print("{:.6f} 1".format(W*H/2))
else:
  print("{:.6f} 0".format(W*H/2))


W,H,x,y=list(map(int,input().split()))
print(W,H,x,y)
if x==0 or y==0 or x==W or y==H or (x==W/2 and y!=H/2) or (x!=W/2 and y==H/2):
  print("{:.6f} 0".format(W*H/2))
else:
  print("{:.6f} 1".format(W*H/2))


W,H,x,y=list(map(int,input().split()))
if x==0 or y==0 or x==W or y==H:
  print(W*H/2,0)
else:
  print(W*H/2,1)

W,H,x,y=list(map(int,input().split()))
if x==0 or y==0 or x==W or y==H:
  print("{:.6f} 0".format(W*H/2))
else:
  print("{:.6f} 1".format(W*H/2))


W,H,x,y=list(map(float,input().split()))
print(W,H,x,y)
if x==W/2 and y==H/2:
  print("{:.6f} 1".format(W*H/2))
else:
  print("{:.6f} 0".format(W*H/2))

W,H,x,y=list(map(int,input().split()))
print(W,H,x,y)
if x==0 or y==0 or x==W or y==H or x==W/2 or y==H/2:
  print("{:.6f} 0".format(W*H/2))
else:
  print("{:.6f} 1".format(W*H/2))


W,H,x,y=list(map(float,input().split()))
if x==W/2 and y==H/2:
  print("{:.6f} 1".format(W*H/2))
else:
  print("{:.6f} 0".format(W*H/2))

Verdicts: Wrong Answer

Runtime Error

Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H). You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Submission attempts (in order):
w,h,x,y = map(float,input().split(" "))

if a.count(max(a)) > 1:
    print('{:.6f}'.format(w*h/2,1)
else:
    print('{:.6f}'.format(w*h/2,0)


w,h,x,y = map(int,input().split(" "))

if y == h/w * x or y == (h/w * x * -1) + h or x == w/2 or y == h/2:
    print('{:.6f}'.format(w*h/2),1)
else:
    print('{:.6f}'.format(w*h/2),0)


w,h,x,y = map(int,input().split(" "))

if x == w/2 and y == h/2:
    print('{:.6f}'.format(w*h/2),1)
else:
    print('{:.6f}'.format(w*h/2),0)


Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H). You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Submission attempts (in order):
# -*- coding: utf-8 -*-
W,H,x_0,y_0 = map(float, input().split())

if W == 2 * x_0 or H == 2 * y_0:
    print(W*H/2, 0)
else:
    print(W*H/2, 1)

# -*- coding: utf-8 -*-
W,H,x_0,y_0 = map(float, input().split())

if W == 2 * x_0 or H == 2 * y_0:
    print(W*H/2, 0)
else:
    print(W*H/2, 1)

# -*- coding: utf-8 -*-


W,H,x_0,y_0 = map(float, input().split())

S = "{0:.6f}".format(float(W*H/2))
if W == 2 * x_0 or H == 2 * y_0:
    print(S, 1)
else:
    print(S, 0)


# -*- coding: utf-8 -*-


W,H,x_0,y_0 = map(float, input().split())

if W == 2 * x_0 and H == 2 * y_0:
    print(W*H/2, 0)
else:
    print(W*H/2, 1)


# -*- coding: utf-8 -*-


W,H,x_0,y_0 = map(float, input().split())

S = "{0:.6f}".format(float(W*H/2))
if W == 2 * x_0 and H == 2 * y_0:
    print(S, 0)
else:
    print(S, 1)


# -*- coding: utf-8 -*-


W,H,x_0,y_0 = map(float, input().split())

S = "{0:.6f}".format(float(W*H/2))
if W == 2 * x_0 and H == 2 * y_0:
    print(S, 1)
else:
    print(S, 0)


Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H). You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Submission attempts (in order):
W,H,x,y = map(int,input().split())
S_V = min(y*W, (H-y)*W)
S_A = min(x*H, (W-x)*H)
print(max(S_V,S_A), end=' ')
if S_V == S_A:
    print(1)
else:
    print(0)


W, H, x, y = map(int,input().split())
print("{0:6f}".format(W*H/2), end=' ')
if x == W/2 and y == H/2:
    print(1)
else:
    print(0)


Verdicts: Wrong Answer

Accepted
Problem: There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H). You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Submission attempts (in order):
w,h,x,y = list(map(int, input().split()))

if((x == w//2 and y == h//2) or (x == h//2 and y == w//2)):
  print((w*h)//2 , 1)
else:
  print((w*h)//2, 0)

coordinates = list(map(int, input().split()))
w = coordinates[0]
h = coordinates[1]
x = coordinates[2]
y = coordinates[3]
prod1 = x * h
prod2 = y * w
if x == w and y == h:
    prod1 = prod2 = (w * h) / 2
area = min(prod1, prod2)
# area = format(area, '.6f')
addit = 0 if prod1 != prod2 else 1
print(f"{area} {addit}")

W, H, x, y = map(int, input().split())
print('{:.6f}'.format(W/2*H), end=" ")
if x * 2 == W and y * 2 == H:
    print(1)
else:
    print(0)


Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H). You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Submission attempts (in order):
# Problem C - Rectangle Cutting

# input
W, H, x, y = map(int, input().split())


# area 1
tmp_1 = H * x
tmp_2 = H * (W - x)
ans_1 = min(tmp_1, tmp_2)

# area 2
tmp_3 = W * y
tmp_4 = W * (H - y)
ans_2 = min(tmp_3, tmp_4)

# output
if ans_1==ans_2:
    ans_list = [ans_1, 1]
    print(" ".join(list(map(str, ans_list))))
else:
    ans_num = max(ans_1, ans_2)
    ans_list = [ans_num, 0]
    print(" ".join(list(map(str, ans_list))))


# Problem C - Rectangle Cutting

# input
W, H, x, y = map(int, input().split())


ans = (W * H) / 2
is_ok = (x*2==W) and (y*2==H)

if is_ok:
    print("%f %d"%(ans, 1))
else:
    print("%f %d"%(ans, 0))


Verdicts: Wrong Answer

Accepted
Problem: There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H). You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Submission attempts (in order):
w,h,x,y = map(int,input.split())
s = float((w*h) / 2)
if x+x==w and y+y ==h:
  print(s+"1")
else:
  print(s + "0")

w,h,x,y = map(int,input.split())
s = float((w*h) / 2)
if x==y:
  print(s+"1")
else:
  print(s + "0")

w,h,x,y = map(int, input().split())
print('{:.6f} {}'.format(w*h/2, 1 if x+x==w and y+y==h else 0))

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H). You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Submission attempts (in order):
inp=list(map(int,input().split()))
if 2*inp[2]==inp[0] and 2*inp[3]==inp[1]:
  ans=1;
else:
  ans=0;
print('%d %d'%(inp[0]*inp[1]*0.5,ans))
inp=list(map(int,input().split()))
if 2*inp[2]==inp[0] and 2*inp[3]==inp[1]:
  ans=1;
else:
  ans=0;
print('%.6f %d'%(inp[0]*inp[1]*0.5,ans))
提出情報

inp=list(map(int,input().split()))
if 2*inp[2]==inp[0] and 2*inp[3]==inp[1]:
  ans=0;
else:
  ans=1;
printf('%d %d'%(inp[0]*inp[1]*0.5,ans))

inp=list(map(int,input().split()))
if 2*inp[2]==inp[0] and 2*inp[3]==inp[1]:
  ans=0;
else:
  ans=1;
print('%d %d'%(inp[0]*inp[1]*0.5,ans))

inp=list(map(int,input().split()))
if 2*inp[2]==inp[0] and 2*inp[3]==inp[1]:
  ans=1;
else:
  ans=0;
print('%d %d'%(inp[0]*inp[1]*0.5,ans))

inp=list(map(int,input().split()))
if 2*inp[2]==inp[0] and 2*inp[3]==inp[1]:
  ans=1;
else:
  ans=0;
print('%.6f %d'%(inp[0]*inp[1]*0.5,ans))

Verdicts: Runtime Error

Runtime Error

Wrong Answer

Wrong Answer

Accepted
Problem: There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H). You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Submission attempts (in order):
W, H, x, y = list(map(int, input().split()))

print("{:f} {}".format(float(W * H), int(x * 2 == W and y * 2 == H)))


W, H, x, y = list(map(int, input().split()))

print("{:f} {}".format(float(W * H), abs(1 - int(x * 2 == W and y * 2 == H))))


W, H, x, y = list(map(int, input().split()))

print("{:f} {}".format(float(W * H / 2), int(x * 2 == W and y * 2 == H)))


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H). You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Submission attempts (in order):
if __name__ == '__main__':
    w,h,x,y = map(int,input().split())
    if x + x == w and y + y == h::
        a = 1
    else:
        a = 0

    print("%f %d" %(w*h/2, a))

def rectangle_cutting(w,h,x,y):
    s = w * h

    s14 = (w - x) * h
    s23 = x * h

    s12 = w * (h - y)
    s34 = w * y

    sh = min([s14,s23])
    sw = min([s12,s34])

    if sh == sw:
        return sh,1
    elif sh > sw:
        return sh,0
    elif sh < sw:
        return sw,0

if __name__ == '__main__':
    w,h,x,y = map(int,input().split())
    sw,way = rectangle_cutting(w,h,x,y)
    print("%d %d" %(sw,way))

if __name__ == '__main__':
    w,h,x,y = map(int,input().split())
    if x + x == w and y + y == h:
        a = 1
    else:
        a = 0

    print("%f %d" %(w*h/2, a))

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H). You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Submission attempts (in order):
def solve(w, h, x, y):
    area = max(min(x*h, (w-x)*h), min(w*y, w*(h-y)))
    multiple = int((2*x == w) or (2*y == h))
    return (area, multiple)

w, h, x, y = map(int, input().split())
print("%f %d" % solve(w, h, x, y))

def solve(w, h, x, y):
    area = w*h / 2
    multiple = int((2*x == w) and (2*y == h))
    return (area, multiple)

w, h, x, y = map(int, input().split())
print("%f %d" % solve(w, h, x, y))

Verdicts: Wrong Answer

Accepted
Problem: There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H). You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Submission attempts (in order):
import sys
def input(): return sys.stdin.readline().strip()

mi = lambda: map(int, input().split())

W, H, x, y = mi()

if x == W/2 and y == H/2:
  print('%d 1' % (W*H/2))
else:
  print('%d 0' % (W*H/2))

import sys
def input(): return sys.stdin.readline().strip()

mi = lambda: map(int, input().split())

W, H, x, y = mi()

if x == W/2 and y == H/2:
  print('%d 1' % ((W*H)/2))
else:
  print('%d 0' % ((W*H)/2))

import sys
def input(): return sys.stdin.readline().strip()
 
mi = lambda: map(int, input().split())
 
W, H, x, y = mi()
 
if x == W/2 and y == H/2:
  print('%f 1' % ((W*H)/2))
else:
  print('%f 0' % ((W*H)/2))

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H). You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Submission attempts (in order):
w, h, x, y = map(int,input().split())
s = (w*h)/2
if x == int(w/2) and y == int(h/2):
  print(s, 1)
elif x == 0:
  print(s, 0)
elif y == 0:
  print(s, 0)
elif x == w:
  print(s, 0)
elif y == h:
  print(s, 0)
else:
  s1 = x*h
  s2 = s*2-s1
  s3 = y*w
  s4 = s*2-s3
  s5 = min(s1,s2)
  s6 = min(s3,s4)
  s7 = max(s5,s6)
  print(s7, 0)

w, h, x, y = map(int,input().split())
s = (w*h)/2
if x == w/2 and y == h/2:
  print("{0:.6f}".format(s), 1)
else:
  print("{0:.6f}".format(s), 0)

Verdicts: Wrong Answer

Accepted
Problem: There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H). You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Submission attempts (in order):
W,H,x,y=map(int, input().split())
s=format(W*H/2, ".6f")
if x*2 == W and y*2 == H:
    flag="1"
else:
    flag="0"
print("{}, {}".format(s,flag))

W,H,x,y=map(int, input().split())
s=format(W*H/2, ".6f")
if x*2 == W and y*2 == H:
    flag="1"
else:
    flag="0"
print("{} {}".format(s,flag))

Verdicts: Wrong Answer

Accepted
Problem: There is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H). You are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.

Submission attempts (in order):
import math
W, H, x, y = map(int, input().split(' '))

f_x, i_x = math.modf(W / x)
f_y, i_y = math.modf(H / y)

if f_x == 0 and f_y == 0:
    print(float(W * y), 1)
elif f_x == 0:
    print(float(H * x), 0)
elif f_y == 0:
    print(float(H * x), 0)


def main(W: int, H: int, x: int, y: int):
    area = W * H
    count = 0

    if x * 2 == W and y * 2 == H:
        count = 1

    print("{:.6f}".format(area / 2), count)


if __name__ == "__main__":
    W, H, x, y = map(int, input().split())

    main(W, H, x, y)


Verdicts: Runtime Error

Accepted