TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: Given is a positive integer N.  We will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.    * Operation: if K divides N, replace N with N/K; otherwise, replace N with N-K.  In how many choices of K will N become 1 in the end?

Submission attempts (in order):
MAX_PRIME = 10**5
is_prime = [1] * MAX_PRIME
primes = []
is_prime[0] = 0
is_prime[1] = 0
for i in range(MAX_PRIME):
    if is_prime[i]:
        primes.append(i)
        for j in range(2, ((MAX_PRIME-1)//i) + 1):
            is_prime[i*j] = 0

def factorization(n):
    factor = {}
    for p in primes:
        if p ** 2 > n:
            break
        while n % p == 0:
            n //= p
            if p not in factor:
                factor[p] = 1
            else:
                factor[p] += 1
    if n > 1:
        factor[n] = 1
    return factor

n = int(input())
ans = 1
for _, c in factorization(n-1).items():
    ans *= c + 1

f = factorization(n)
k = list(f.keys())
def dfs(num, i, cum, searched):
    if num not in searched:
        x = n
        while x % num == 0 and x > 0:
            x //= num
        if x % num == 1:
            cum += 1
    searched.add(num)
    if i < len(k):
        p = k[i]
        for j in range(f[p]+1):
            cum = dfs(num * p ** j, i+1, cum, searched)
    return cum

print(f)
print(dfs(1, 0, 0, set()) + ans - 1, ans)

MAX_PRIME = 10 ** 6
is_prime = [1] * MAX_PRIME
primes = []
is_prime[0] = 0
is_prime[1] = 0
for i in range(MAX_PRIME):
    if is_prime[i]:
        primes.append(i)
        for j in range(2, ((MAX_PRIME-1)//i) + 1):
            is_prime[i*j] = 0

def factorization(n):
    factor = {}
    for p in primes:
        if p ** 2 > n:
            break
        while n % p == 0:
            n //= p
            if p not in factor:
                factor[p] = 1
            else:
                factor[p] += 1
    if n > 1:
        factor[n] = 1
    return factor

n = int(input())
ans = 1
for _, c in factorization(n-1).items():
    ans *= c + 1

f = factorization(n)
k = list(f.keys())
def dfs(num, i):
    ret = 0
    if i == len(k):
        if num != 1:
            x = n
            while x % num == 0:
                x //= num
            if x % num == 1:
                ret += 1
        return ret
    else:
        p = k[i]
        for j in range(f[p]+1):
            ret += dfs(num * p ** j, i+1)
        return ret

print(dfs(1, 0) + ans - 1)

Verdicts: Time Limit Exceeded

Accepted
Problem: Given is a positive integer N.  We will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.    * Operation: if K divides N, replace N with N/K; otherwise, replace N with N-K.  In how many choices of K will N become 1 in the end?

Submission attempts (in order):

# -*- coding: utf-8 -*-


def make_divisors(n):
    divisors = []
    for i in range(1, int(n**0.5)+1):
        if n % i == 0:
            divisors.append(i)
            if i != n // i:
                divisors.append(n//i)

    
    return divisors


N_given = int(input())


list_found_K = []



divisors_N_minus_1 = make_divisors(N_given-1)

for divs in divisors_N_minus_1:
	if divs != 1:
		list_found_K.append(divs)



divisors_N = make_divisors(N_given)
divisors_N.remove(1)





for candidate_K in divisors_N:
	N_wk = N_given
	
	while N_wk % candidate_K == 0:
		N_wk //=candidate_K

	
	if (N_wk-1) % candidate_K == 0:
		list_found_K.append(candidate_K)

print(list_found_K)
print(len(list_found_K))



# -*- coding: utf-8 -*-


def make_divisors(n):
    divisors = []
    for i in range(1, int(n**0.5)+1):
        if n % i == 0:
            divisors.append(i)
            if i != n // i:
                divisors.append(n//i)

    
    return divisors


N_given = int(input())


list_found_K = []



divisors_N_minus_1 = make_divisors(N_given-1)

for divs in divisors_N_minus_1:
	if divs != 1:
		list_found_K.append(divs)



divisors_N = make_divisors(N_given)
divisors_N.remove(1)


for candidate_K in divisors_N:
	N_wk = N_given
	
	while N_wk % candidate_K == 0:
		N_wk //=candidate_K

	
	if (N_wk-1) % candidate_K == 0:
		list_found_K.append(candidate_K)

print(len(list_found_K))


Verdicts: Wrong Answer

Accepted
Problem: Given is a positive integer N.  We will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.    * Operation: if K divides N, replace N with N/K; otherwise, replace N with N-K.  In how many choices of K will N become 1 in the end?

Submission attempts (in order):
def make_divisors(n):
    divisors = []
    for i in range(1, int(n**0.5)+1):
        if n % i == 0:
            divisors.append(i)
            if i != n // i:
                divisors.append(n//i)
    divisors.sort()
    return divisors

def all_pattern(n):
    ans=0
    for ds in make_divisors(n):
        k=n
        if ds==1:
            continue
        while k%ds==0:
            k//=ds
        ans+=(k%ds==1 or k-k%ds==1)

n=int(input())
print(all_pattern(n)+all_pattern(n-1))

def make_divisors(n):
    divisors = []
    for i in range(1, int(n**0.5)+1):
        if n % i == 0:
            divisors.append(i)
            if i != n // i:
                divisors.append(n//i)
    divisors.sort()
    return divisors

def all_pattern(l):
    global n
    ans=0
    for ds in make_divisors(l)[1:]:
        k=n
        while k%ds==0:
            k//=ds
        ans+=(k%ds==1)
    return ans

n=int(input())
print(all_pattern(n)+all_pattern(n-1))

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
s = input()

if s[2] == s[3] and s[4] == s[5]:
    print("yes")
else:
    print("no")

n=str(input())
if n[2] == n[3] and n[4] == n[5]:
    print("yes")
else:
    print("no")

n = input()

if n[2] == n[3] and n[4] == n[5]:
    print("yes")
else:
    print("no")

s = input()
 
if s[2] == s[3] and s[4] == s[5]:
     print('Yes')
else:
     print('No')

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
#S = 'coffee'

S = input('6文字の文字列を入力してください:')

if S[2] == S[3] and S[4] == S[5] :
  print('YES')
  
else :
  print('No')
  

S = input()

if S[2] == S[3] and S[4] == S[5] :
  print('Yes')

else :
  print('No')
  

Verdicts: Wrong Answer

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
"""
"""


def int_as_array(num): return list(map(int, [y for y in str(num)]))


def array_as_int(arr): return int(''.join(map(str, arr)))


def read_int(): return int(input())


def read_array(): return list(map(int, input().split(' ')))


def array_to_string(arr, sep=' '): return sep.join(map(str, arr))


def matrix_to_string(arr, sep=' '): return '[\n' + '\n'.join(
    [sep.join(map(str, row)) for row in arr]) + '\n]'


def solve(string):
    if string[2] == string[3] and string[4] == string[5]:
        print('Yes')
    else:
        print('No')


T = read_int()

string = input()
solve(string)


"""
"""


def int_as_array(num): return list(map(int, [y for y in str(num)]))


def array_as_int(arr): return int(''.join(map(str, arr)))


def read_int(): return int(input())


def read_array(): return list(map(int, input().split(' ')))


def array_to_string(arr, sep=' '): return sep.join(map(str, arr))


def matrix_to_string(arr, sep=' '): return '[\n' + '\n'.join(
    [sep.join(map(str, row)) for row in arr]) + '\n]'


def solve(string):
    if string[2] == string[3] and string[4] == string[5]:
        print('Yes')
    else:
        print('No')


string = input()
solve(string)


Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
w = input(':')

if w[2] == w[3] and w[4] == w[5]:
    print('Yes')
    
else :
    print('No')

s = input()

if s[2] == s[3] and s[4] == s[5]:
  print('Yes')
  
else :
  print('No')

Verdicts: Wrong Answer

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
s=input();print('NYOE S'[s[2]==s[3]and s[4]==s[5]and s[2]!=s[4]::2])

s=input();print('NYOE S'[s[2]==s[3]and s[4]==s[5]::2])

s=input();print('NYoe s'[s[2]==s[3]and s[4]==s[5]::2])

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
S = list(str.imput())

if S[2] == S[3]:
  if S[4] == S[5]:
    print("Yes")
  else:
    print("No")
else:
  print("No")


S = list(str, input())

if S[2] == S[3]:
  if S[4] == S[5]:
    print("Yes")
  else:
    print("No")
else:
  print("No")

S = list(input())

if S[2] == S[3]:
  if S[4] == S[5]:
    print("Yes")
  else:
    print("No")
else:
  print("No")

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
S = list(input().split())
if S[2] == S[3] or S[4] == S[5]:
  print("Yes")
else:
  print("No")

S = input()
 
if S[2]==S[3] and S[4]==S[5]:
    print("Yes")
else:
    print("No")

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
#! env/bin/local python3
# -*- coding: utf-8 -*-

s = input()
if s[2] == s[3] and s[4] == 2[6]:
    print('Yes')
else:
    print('No')

#! env/bin/local python3
# -*- coding: utf-8 -*-

s = input()
if s[2] == s[3] and s[4] == s[5]:
    print('Yes')
else:
    print('No')

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
s = input()
if s[3] == s[4] and s[5] == s[6]:
  print('Yes')
else:
  print('No')

s = input()
if s[2] == s[3] and s[4] == s[5]:
  print('Yes')
else:
  print('No')

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
a = str(input().split())
s = list(a)
print(s)
if s[4] == s[5] and s[7] == s[6]:
      print("Yes")
else :
      print("No")

a = str(input().split())
s = list(a)
if s[4] == s[5] and s[7] == s[6]:
      print("Yes")
else :
      print("No")

Verdicts: Wrong Answer

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
s = input()
print('YNeos'[s[2::2] != s[3::2]])


s = input()
print('YNeos'[s[2::2] != s[3::2]::2])

Verdicts: Wrong Answer

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
S = input()
if S[2] == S[3] and S[4] == S[5]:
  print(Yes)
else:
  print(No)

s = input()
if s[2] == s[3] and s[4] == s[5]:
  print("Yes")
else:
  print("No")

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
S = input()
if S[2]==S[3] and S[4]==S[5]:
  print("YES")
else:
  print("NO")

import sys
input = sys.stdin.readline

S = input().split()
if S[2]==S[3] and S[4]==S[5]:
  print("YES")
else:
  print("NO")

S = (input().split())

if S[2]==S[3] and S[4]==S[5]:
  print("YES")
else:
  print("NO")

s = input()
if s[2]==s[3] and s[4]==s[5]:
  print("Yes")
else:
  print("No")

Verdicts: Wrong Answer

Runtime Error

Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
a=list.input()

if a[2]==a[3] and a[4]==a[5]:
  print("Yes")
else:
  print("No")

a=list(input())
 
if a[2]==a[3] and a[4]==a[5]:
  print("Yes")
else:
  print("No")

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
s = input()
if(s[1:2]==s[2:3] and s[3:4]==s[4:5]){print("Yes")}
else{print("No")}

s = input()
if(s[2]==s[3] and s[4]==s[5]){print("Yes")}
else{print("No")}

s = input()
if(s[2:3]==s[3:4] and s[4:5]==s[5:6]){print("Yes")}
else{print("No")}

s = input()
if(s[2:3]==s[3:4] and s[4:5]==s[5:6]):
  print("Yes")
else:
  print("No")

Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
lst = list(input())

if lst[2] == lst[3] and lst[4] == lst[5]:
    print('True')
else:
    print('No')


lst = list(input())

if lst[2] == lst[3] and lst[4] == lst[5]:
    print('Yes')
else:
    print('No')


Verdicts: Wrong Answer

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
s = input()
s.lower()

if s[2] == s[3] and s[4] == s[5]:
    print("yes")
else:
    print("no")

s = input()
s.lower()

if s[2] == s[3] and s[4] == s[5]:
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
S = input()
T = input()
hit = 0
for i in range(3):
    if S[i] == T[i]:
        hit = hit + 1
print(hit)

S = input()
if S[2]==S[3] and S[4]==S[5]:
    print("Yes")
else:
    print("No")


Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
string = []

string = input('')

if string[2] == string[3] and string[4] == string[5]:
    print('YES')
else:
    print('NO')

string = []

string = input('')

if string[2] == string[3] and string[4] == string[5]:
    print('Yes')
else:
    print('No')

Verdicts: Wrong Answer

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
S = input()

if S[3]==S[4] and S[5] == S[6]:
  print("Yes")
else:
  print("No")

S = input()

if S[2]==S[3] and S[4] == S[5]:
  print("Yes")
else:
  print("No")

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
S = input()
if len(S) != 6:
    print('No')
    return

if S[2]==S[3] and S[4]==S[5]:
    print('Yes')
else:
    print('No')


S = input()

if S[2]==S[3] and S[4]==S[5] and len(S)==6 :
    print('Yes')
else:
    print('No')


Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
S = input()
if S[2] == S[3] and S[4] == S[5]:
    print("Yes")
else:
    print("No"

S = input()
if S[2] == S[3] and S[4] == S[5]:
    print("Yes")
else:
    print("No")

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
a,b,c,d,e,f = input().split()
if c == d and e == f:
    print('Yes')
else:
    print('No')

a,b,c,d,e,f = list(input())
if c == d and e == f:
    print('Yes')
else:
    print('No')

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):


st = input()

if ( (st[2] == st[3]) and (st[4] == st[5]) ) :
    print ('YES')
else:
    print ('NO')



st = input()

if ( (st[2] == st[3]) and (st[4] == st[5]) ) :
    print ('Yes')
else:
    print ('No')

Verdicts: Wrong Answer

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
if num[2] == num[3] and num[-1] == num[-2]:
    print('Yes')
else:
    print('No')

S = input()
if S[2] == S[3] and S[-1] == S[-2]:
    print('Yes')
else:
    print('No')

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
s = input()
if  s[3] == s[4] and s[5] == s[6]:
  print(yes)
else:
  print(no)

S = input()
if S[3] == S[4] and S[5] == S[6]:
  print(Yes)
else:
  print(No)
  


n = int(input())
m = n%500
print(int((n - m)*1000/ 500 + m*5//5))

S = input()
if S[3] == S[4] and S[5] == S[6]:
  print('Yes')
else:
  print('No')
  


input()
s = [input()]
if s[3] == [4] and s[5] == s[6]:
  print('yes')
else:
  print('no')

s = input()
if  s[3] == s[4] and s[5] == s[6]:
  print('yes')
else:
  print('no')


S = input()
if S[2] == S[3] and S[4] == S[5]:
  print('Yes')
else:
  print('No')
  


Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
S = list(input())
cond1 = S[2] == S[3]
cond2 = S[3] == S[4]
if cond1 & cond2:
  print('Yes')
else:
  print('No')

S = list(input())
cond1 = S[2] == S[3]
cond2 = S[4] == S[5]
if cond1 & cond2:
  print('Yes')
else:
  print('No')

Verdicts: Wrong Answer

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
s=input()
flag=1
if list(s)[2]==list(s)[3]:
  if list(s)[4]==list(s)[5]:
    flag=0
if flag=0:
  print("Yes")
else:
  print("No")
  


X,Y,A,B,C = map(int, input().split())
p=list(map(int,input().split()))
q=list(map(int,input().split()))
r=list(map(int,input().split()))
p.sort()
p.reverse()
q.sort()
q.reverse()
r.sort()
r.reverse()
ans=0
ccounter=0
for i in range(0,X):
    ans=p[i]+ans
for i in range(0,Y):
    ans=q[i]+ans
for i in range(0,X):
    if i>=C:
      break
    if p[X-1-i]<=r[i]:
        ccounter=ccounter+1
        ans=ans-p[X-1-i]+r[i]
    else:
        break
for i in range(0,Y):
    if i+ccounter>=C:
        break
    if q[Y-1-i]<=r[i+ccounter]:
        ans=ans-q[Y-1-i]+r[i+ccounter]
        ccounter=ccounter+1
    else:
        break
print(ans)


s=input()
if s[2]==s[3] and s[4]==s[5]:
  print('Yes')
else:
  print('No')

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
N, x, y = [int(i) for i in input().split()]

cnt = [0] * N
for i in range(1, N+1):
  for j in range(i+1, N+1):
    temp = min(abs(j-i), abs(x-i) + 1 + abs(j-y), abs(y-i) + 1 + abs(j-x))
    cnt[temp] += 1

for i in range(1, N):
  print(cnt[i])

s = input()
print("Yes" if s[2] == s[3] and s[4] == s[5] else "No")

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
S = str(input()) 
print('YES' if S[2] == S[3] and S[4] ==S[5] else 'NO' ) 

S = str(input()) 
print('YES' if S[2] ==S[3] and 'NO' if S[4]==S[5] 

S = str(input())

print('Yes' if S[2]==S[3] and S[4]==S[5] else 'No')

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
S = input()

if S[3] == S[4] and S [5] == S[6]:
	print("Yes")
else:
	print("No")

S = input()

if S[2] ==S[3] and S[4] == S[5]:
	print("Yes")
else:
	print("No")

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
A = input()

if A[2]==A[3] and A[4]==A[5]: 
    print("yes")
else:
    print("no")

A = input()

if A[2]==A[3] and A[4]==A[5]: 
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
print("No")

a=input()

if a[2]==a[3]:
    if a[4]==[5]:
        print("Yes")
    else:
        print("No")

a=input()


b=False
if a[2]==a[3]:
    if a[4]==a[5]:
        a=True
    
print(b)

a=input()


b=False
if a[2]==a[3]:
    if a[4]==a[5]:
        b=True
    
print(b)

a=input()


b=False
if a[2]==a[3]:
    if a[4]==a[5]:
        b=True
    
print(b)

a=input()


b=False
if a[2]==a[3]:
    if a[4]==a[5]:
        b=True


if b==True:
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
n,x,y = map(int,input().split())
m = {}
for i in range(1,n):
    m[i] = 0
for i in range(1,n):
    for j in range(i+1,n+1):
        dif = min(abs(j-i),(abs(x-i)+1+abs(j-y)),(abs(y-i)+1+abs(j-x)))
        m[dif]+=1
[print(m[i]) for i in range(1,n)]


N, X, Y = map(int,input().split())
l = [0]*(N-1)
for i in range(1,N):
    for j in range(i+1,N+1):
        d=min(j-i,abs(X-i)+1+abs(Y-j),abs(Y-i)+1+abs(X-j))
        l[d-1] += 1
for a in l:
    print(a)


N, X, Y = map(int,input().split())
l = [0]*(N-1)
for i in range(1,N):
    for j in range(i+1,N+1):
        d=min(j-i,abs(X-i)+1+abs(Y-j),abs(Y-i)+1+abs(X-j))
        l[d-1] += 1
for k in range(N-1):
    print(l[k])


N, X, Y = map(int,input().split())
l = [0]*(N-1)
for i in range(1,N):
    for j in range(i+1,N+1):
        d=min(j-i,abs(X-i)+1+abs(Y-j),abs(Y-i)+1+abs(X-j))
        l[d-1] += 1
for k in range(N-1):
    print(l[k])

S = input()
if S[2] == S[3] and S[4] == S[5]:
    print("Yes")
else:
    print("No")

Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
##A
s = input()
if s[2] == s[3] and s[4] == s[5]:
    print("yes")
else:
    print("No")   

##A
s = input()
if s[2] == s[3] and s[4] == s[5]:
    print("Yes")
else:
    print("No")


Verdicts: Wrong Answer

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
S = list(input())
S = S[2:6:1]
coffee = ["f","f","e","e"]
  
if S == coffee:
    print("Yes")
else:
    print("no")

S = list(input())
S = S[2:5:1]
coffee = ["f","f","e","e"]
  
if S == coffee:
    print("Yes")
else:
    print("no")

S = list(input())
coffee = ["c","o","f","f","e","e"]
  
if S == coffee:
    print("Yes")
else:
    print("no")

S = list(input())
coffee = ["c","o","f","f","e","e"]
if S == coffee:
    print("Yes")
  else:
    print("no")

S = list(input())
S =[2:5:1]
coffee = ["f","f","e","e"]
  
if S == coffee:
    print("Yes")
else:
    print("no")

S = list(input())

if S[2] == S[3] and S[4] == S[5]:
  print("Yes")
else:
  print("No")

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Runtime Error

Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
X, Y, num_red_apple, num_green_apple, num_apple = map(int, input().strip().split())
red_apples = list(map(int, input().strip().split()))
green_apples = list(map(int, input().strip().split()))
apples = list(map(int, input().strip().split()))

good_apples = []
for i in range(1, X+1):
    good_apples.append(sorted(red_apples)[-i])

for i in range(1, Y+1):
    good_apples.append(sorted(green_apples)[-i])

while(1):
    if max(apples) > min(good_apples):
        good_apple = apples.pop(apples.index(max(apples)))
        good_apples.remove(min(good_apples))
        good_apples.append(good_apple)
    else:
        break
    
print(sum(good_apples))
        

X, Y, num_red_apple, num_green_apple, num_apple = map(int, input().strip().split())
red_apples = list(map(int, input().strip().split()))
green_apples = list(map(int, input().strip().split()))
apples = list(map(int, input().strip().split()))

good_apples = []
for i in range(1, X+1):
    good_apples.append(sorted(red_apples)[-i])

for i in range(1, Y+1):
    good_apples.append(sorted(green_apples)[-i])

while(1):
    if max(apples) > min(good_apples):
        good_apple = apples.pop(apples.index(max(apples)))
        good_apples.remove(min(good_apples))
        good_apples.append(good_apple)
    else:
        break
    
print(good_apples)

word = input()

def Coffee(word):
  if word[2] == word[3] and word[4] == word[5]:
    print("Yes")
  else:
    print("No")
      
Coffee(word)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
n = int(input())
cnt = (n // 1000) * 2000
n -= (n // 1000) * 1000
cnt += (n // 5) * 5
print(cnt)

n = int(input())
cnt = (n // 1000) * 2000
n -= (n // 1000) * 1000
cnt += (n // 5) * 5
print(cnt)

s = input()
if s[2] == s[3] and s[4] == s[5]:
	print("Yes")
else:
	print("No")

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
s = int(input())
ans = "No"
if len(s) == 6:
  if s[2]==s[3] and s[4]==s[5]:
    ans = "Yes"
print(ans)

s = input()
ans = "No"
if len(s) == 6:
  if s[2]==s[3] and s[4]==s[5]:
    ans = "Yes"
print(ans)

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
import sys
def fastio():
    from io import StringIO
    from atexit import register
    global input
    sys.stdin = StringIO(sys.stdin.read())
    input = lambda : sys.stdin.readline().rstrip('\r\n')
    sys.stdout = StringIO()
    register(lambda : sys.__stdout__.write(sys.stdout.getvalue()))
fastio()

INF = 10**20
MOD = 10**9 + 7
I = lambda:list(map(int,input().split()))
# from math import gcd
from math import ceil
from collections import defaultdict as dd, Counter
from bisect import bisect_left as bl, bisect_right as br

s, = input()
ans = 'No'
if s[2] == s[3] and s[5] == s[6]:
    ans = 'Yes'
print(ans)

import sys
def fastio():
    from io import StringIO
    from atexit import register
    global input
    sys.stdin = StringIO(sys.stdin.read())
    input = lambda : sys.stdin.readline().rstrip('\r\n')
    sys.stdout = StringIO()
    register(lambda : sys.__stdout__.write(sys.stdout.getvalue()))
fastio()

INF = 10**20
MOD = 10**9 + 7
I = lambda:list(map(int,input().split()))
# from math import gcd
from math import ceil
from collections import defaultdict as dd, Counter
from bisect import bisect_left as bl, bisect_right as br

s = input()
ans = 'No'
if s[2] == s[3] and s[4] == s[5]:
    ans = 'Yes'
print(ans)

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
k, n = map(int, input().split())
a = list(map(int, input().split()))
a.sort()
b = []
c = abs(k+a[0]-a[n-1])
for i in range(1, n):
  b.append(abs(a[i] - a[i-1]))
  b.sort()
  p = b[-1]

if p > c:
  print(k - p)
else:
  print(k - c)


s = input()
if s[-1] == s[-2]:
  if s[-3] == s[-4]:
    print("Yes")
    exit()

print("No")

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
s = input()
if s[3] == s[4] and s[5] == s[6]:
  print("Yes")
else:
  print("No")

s = input()
if s[2] == s[3] and s[4] == s[5]:
  print("Yes")
else:
  print("No")


Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
a = int(input())
a -= a%5
print(2*a - a%500)

s = input()
if s[2] == s[3] and s[4] == s[5]:
    print("Yes")
else:
    print("No")

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
k , n = (int(x) for x in input().split())
a = [int(i) for i in input().split()]
b = []

for i in range(n-1):
    b.append(a[i+1] - a[i])
    
b.append(a[0] + k -a[n-1])

ans=0

b.sort()

for i in range(len(b)-1):
    ans = b[i] + ans
    
    
print(ans)
        

s = input()

if s[2] == s[3]:
    
    if s[4] == s[5]:
        print('Yes')
    else:
        print('No')

else:
    print('No')


Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
x, y, a, b, c = map(int, input().split())
pn = list(map(int, input().split()))
qn = list(map(int, input().split()))
rn = list(map(int, input().split()))

pn.sort(reverse=True)
qn.sort(reverse=True)

pqr = pn[:x] + qn[:y] + rn
pqr.sort(reverse=True)
  
print(sum(pqr[:x+y]))


s = input()
if s[2] == s[3] and s[4] == s[5]:
  print('Yes')
else:
  print('No')
  

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
def coffee(s):
  if len(s) < 6:
    return False
  if s[2] == s[3] and s[4] == s[5]:
    return True
  else:
    return False
  
string = input()
print(coffee(string))

def coffee(s):
  if len(s) < 6:
    return False
  if s[2] == s[3] and s[4] == s[5]:
    return 'Yes'
  else:
    return 'No'

string = input()
print(coffee(string))

Verdicts: Wrong Answer

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
s = list(input())
if s[2] == s[3] and s[4] == s[5]:
  print("Yes")
  
else:
  print"No")


s =input()
if s[2] == s[3] and s[4] == s[5]:
  print("Yes")
  
else:
  print"No")


s = list(input())
if s[2] = s[3] and s[4] = s[5]:
  print("Yes")
  
else:
  print"No")

s =list(input())
if s[2] == s[3] and s[4] == s[5]:
  print("Yes")
  
else:
  print("No")


Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
S = input()
if len(S) < 5:
  return False
else:
  if s[2] == s[3] and s[4] == s[5]:
    return True
  
return False
  


s = input()

if len(s) < 5:
    print('No')

if s[2] == s[3] and s[4] == s[5]:
    print('Yes')
else:
    print('No')

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
S = list(input())
if S[2] == S[3]　and S[4] == S[5]:
    print("Yse")
else:
    print("No")


S = list(input())
if S[2] == S[3] and S[4] == S[5]:
    print("Yse")
else:
    print("No")


S = list(input())
if S[2] == S[3]:
  if S[4] == S[5]:
    print("Yse")
  else:
    print("No")
else:
  print("No")

S = list(input())
if S[2] == S[3] and S[4] == S[5]:
    print("Yes")
else:
    print("No")


Verdicts: Runtime Error

Wrong Answer

Wrong Answer

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
string = str(input())

def test(string):
    string.split()
    if string[2] == string[3] and string[4] == string[5]:
        return "Yes"
    else:
        return "No"

string = str(input())

def test(string):
    string.split()
    if string[2] == string[3] and string[4] == string[5]:
        print("Yes")
    else:
        print("No")

s = (str(i) for i in input().split())

def test(s):
    s.split()
    if s[2] == s[3] and s[4] == s[5]:
        print("Yes")
    else:
        print("No")

def test(string):
    string.split()
    if string[2] == string[3] and string[4] == string[5]:
        return "Yes"
    else:
        return "No"

def test(s):
    s.split()
    if s[2] == s[3] and s[4] == s[5]:
        print("Yes")
    else:
        print("No")

def test(s):
    s.split()
    if s[2] == s[3] and s[4] == s[5]:
        print("Yes")
    else:
        print("No")

s = input()

s.split()
    if s[2] == s[3] and s[4] == s[5]:
        print("Yes")
    else:
        print("No")

string = input()
string.split()
if string[2] == string[3] and string[4] == string[5]:
	print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
s = list(input())
if s[2] == s[3] & s[4] == s[5]:
  print('Yes')
else:
  print('No')

s = list(input())
if (s[2] == s[3]) & (s[4] == s[5]):
  print('Yes')
else:
  print('No')



Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
s=input()
if s[4] == s[5] and s[6] == s[7]:
  print('Yes')
else:
  print('No')

s=input()
if s[2] == s[3] and s[4] == s[5]:
  print('Yes')
else:
  print('No')


Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
A = input()

if A[0]!=A[1]!=A[2]!=A[4] andA[0]!=A[1]!=A[3]!=A[5] and  A[2]==A[3] and A[4] == A[5]:
    print("Yes")
else:
    print("No")

A = input()

if A[2]==A[3] and A[4] == A[5]:
    print("Yes")
else:
    print("No")

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
# -*- coding: utf-8 -*-
import sys
from collections import defaultdict


MAX_INT = 2**62-1
sys.setrecursionlimit(10**6)

input = sys.stdin.readline


N = 2 * (10**5) + 1
MOD = 10**9 + 7

fact = [1] * N
fact_inv = [0] * N

for i in range(1, 2 * (10**5)+1):
    fact[i] = fact[i-1] * i % MOD
    fact_inv[i] = pow(fact[i], MOD-2, MOD)


def solve(g):
    def dfs(pre, cur):
        if pre in memo and cur in memo[pre]:
            return memo[pre][cur]

        num, ways = 1, 1

        for nxt in g[cur]:
            if nxt == pre:
                continue
            n, w = dfs(cur, nxt)
            num += n
            ways = ways * w % m * fi[n] % m

        ways = ways * f[num-1] % m
        memo[pre][cur] = num, ways
        return num, ways

    m = MOD
    memo = defaultdict(dict)
    f, fi = fact, fact_inv

    for i in range(1, len(g)):
        print(dfs(None, i)[1])


def main():
    n = int(input())
    g = [[] for _ in range(n+1)]

    for _ in range(n-1):
        a, b = map(int, input().split())
        g[a].append(b)
        g[b].append(a)

    solve(g)


if __name__ == "__main__":

    main()


import sys


def input() -> str:
    return sys.stdin.readline().rstrip("\r\n")


def main():
    s = input()
    if len(s) == 6 and s[-2] == s[-1] and s[2] == s[3]:
        print('Yes')
    else:
        print('No')

if __name__ == "__main__":

    main()


Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
s = str(input())
if s[3] == s[4] and s[5] == s[6]:
    print('Yes')
else:
    print('No')

k, n = map(int, input().split())
arr = list(map(int, input().split()))
ans = 0
for i in range(n):
    if i + 1 <= n - 1:
        if arr[i + 1] - arr[i] > ans:
            ans = arr[i + 1] - arr[i]
    else:
        if arr[i] - arr[0] > ans:
            ans = arr[i] - arr[0]
print(ans)

k, n = map(int, input().split())
arr = list(map(int, input().split()))
ans = 0
for i in range(n):
    if i + 1 <= n - 1:
        if arr[i + 1] - arr[i] > ans:
            ans = arr[i + 1] - arr[i]
    else:
        if arr[i] - arr[0] > ans:
            ans = arr[i] - arr[0]
print(ans)

s = str(input())
if s[3] == s[2] and s[5] == s[4]:
    print('Yes')
else:
    print('No')

Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
S = input()
l = []
for i in S:
    l.append(i)

if l[3] == l[4]:
    if l[5] == l[6]:
        print('Yes')

print('No')

S = input()
l = []
cont = 0
for i in S:
    l.append(i)

if l[2] == l[3]:
    if l[4] == l[5]:
        cont = 1

if cont == 1:
    print('Yes')
else:
    print('No')

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
S=str(input())

if S[2]==S[3] and S[5]==S[6]:
    print("Yes")
else:
    print("No")

S=str(input())

if S[2]==S[3] and S[4]==S[5]:
    print("Yes")
else:
    print("No")

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
import itertools as it
import collections

n, x, y = list(map(int, input().split(' ')))

dist_list = []
dist_a = dist_list.append
for i, j in it.combinations(list(range(n)), 2):
    warp_dist = abs(i - (x - 1)) + 1 + abs(j - (y - 1))
    if abs(j - i) < warp_dist:
        dist_a(abs(j - i))
    else:
        dist_a(warp_dist)

dist_c = collections.Counter(dist_list)

for i in range(1, n):
    print(dist_c[i])


import itertools as it
import collections
 
n, x, y = list(map(int, input().split(' ')))
 
dist_list = []
dist_a = dist_list.append
for i, j in it.combinations(list(range(n)), 2):
    warp_dist = abs(i - (x - 1)) + 1 + abs(j - (y - 1))
    if abs(j - i) < warp_dist:
        dist_a(abs(j - i))
    else:
        dist_a(warp_dist)
 
dist_c = collections.Counter(dist_list)
 
for i in range(1, n):
    print(dist_c[i])

x, y, a, b, c = list(map(int, input().split(' ')))
p_list = sorted(list(map(int, input().split(' '))), reverse=True)
q_list = sorted(list(map(int, input().split(' '))), reverse=True)
r_list = sorted(list(map(int, input().split(' '))), reverse=True)

xy_list = sorted(p_list[:x] + q_list[:y])

i = 0
for r in range(c):
    if r_list[r] > xy_list[0]:
        i += 1
    else:
        break

if i == 0:
    print(sum(xy_list))
else:
    print(sum(xy_list[i:] + r_list[:i]))


s = input()

s_list = [i for i in s]

if s[2] == s[3] and s[4] == s[5]:
    print('Yes')
else:
    print('No')


Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
Str=list(input())
if Str[3]==Str[4] and Str[5]==Str[6]:
  print("Yes")
else:print("No")  

List=list(input())
if List[2]==List[3] and List[4]==List[5]:
  print("Yes")
else:print("No")

Verdicts: Runtime Error

Accepted
Problem: A string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.   Given a string S, determine whether it is coffee-like.

Submission attempts (in order):
S = input()

if S[2] == s[3] and s[4] == s[5]:
  print('Yes')

S = str(input())
 
if S[2] == S[3] and S[4] == S[5]:
  print('Yes')
else:
  print('No')

Verdicts: Runtime Error

Accepted