TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
A=[list(map(int,input().split())) for _ in range(3)]
N=int(input())
bn=[int(input()) for _ in range(N)]
ans=False
for ver in zip(*A):
    if all(item in bn for item in ver):
        ans=True
for wide in A:
    if all(item in bn for item in wide):
        ans=True
if all(A[i][i] in bn for i in range(3)):
    ans=True
if all(A[i][3-i] in bn for i in range(3)):
    ans=True
if ans==True:
    print("Yes")
else:
    print("No")

A=[list(map(int,input().split())) for _ in range(3)]
N=int(input())
bn=[int(input()) for _ in range(N)]
ans=False
for ver in zip(*A):
    if all(item in bn for item in ver):
        ans=True
for wide in A:
    if all(item in bn for item in wide):
        ans=True
if all(A[i][i] in bn for i in range(3)):
    ans=True
if all(A[i][3-i-1] in bn for i in range(3)):
    ans=True
if ans==True:
    print("Yes")
else:
    print("No")

Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
t=[]
for i in range(3):
    t.append([int(i) for i in input().split()])
n = int(input())
lst = []
for i in range(n):lst+=[int(input())]
def ligne(i):
    for j in range(3):
        if not t[i][j] in lst:
            return False
    return True
def col(j):
    for i in range(3):
        if not t[i][j] in lst:
            retur False
    return True
def diag1():
    for i in range(3):
        if not t[i][i] in lst:
            return False
    return True
def diag2():
    for i in range(3):
        if not t[2-i][i] in lst:
            return False
    return True
ans = False
for i in range(3):
    ans = ans or ligne(i)
    ans = ans or col(i)
ans  = ans or diag1() or diag2()
if ans :
    print("Yes")
else:
    print("No")

t=[]
for i in range(3):
    t.append([int(i) for i in input().split()])
n = int(input())
lst = []
for i in range(n):lst+=[int(input())]
def ligne(i):
    for j in range(3):
        if not t[i][j] in lst:
            return False
    return True
def col(j):
    for i in range(3):
        if not t[i][j] in lst:
            return False
    return True
def diag1():
    for i in range(3):
        if not t[i][i] in lst:
            return False
    return True
def diag2():
    for i in range(3):
        if not t[2-i][i] in lst:
            return False
    return True
ans = False
for i in range(3):
    ans = ans or ligne(i)
    ans = ans or col(i)
ans  = ans or diag1() or diag2()
if ans :
    print("Yes")
else:
    print("No")

Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
a = [list(map(int, input().split())) for _ in range(3)]
n = int(input())
b = [int(input() for _ in range(n))]

flag = False
for i in range(3):
    if a[i][0] in b and a[i][1] in b and a[i][2] in b:
        flag = True
        break
    if a[0][i] in b and a[1][i] in b and a[2][i] in b:
        flag = True
        break
if a[0][0] in b and a[1][1] in b and a[2][2] in b:
    flag = True
if a[2][0] in b and a[1][1] in b and a[0][2] in b:
    flag = True
    
print("Yes" if flag else "No")

a = [list(map(int, input().split())) for _ in range(3)]
n = int(input())
b = [int(input()) for _ in range(n)]

flag = False
for i in range(3):
    if a[i][0] in b and a[i][1] in b and a[i][2] in b:
        flag = True
        break
    if a[0][i] in b and a[1][i] in b and a[2][i] in b:
        flag = True
        break
if a[0][0] in b and a[1][1] in b and a[2][2] in b:
    flag = True
if a[2][0] in b and a[1][1] in b and a[0][2] in b:
    flag = True
    
print("Yes" if flag else "No")

Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
loopin=input()

bingolist = []



A11,A12,A13,A21,A22,A23,A31,A32,A33=0,0,0,0,0,0,0,0,0


for i in range(int(loopin)):
	bingo = input()
	if bingo==a:
		A11=1
	elif bingo==b:
		A12=1	
	elif bingo==c:
		A13=1	
	elif bingo==d:
		A21=1	
	elif bingo==e:
		A22=1	
	elif bingo==f:
		A23=1	
	elif bingo==g:
		A31=1	
	elif bingo==h:
		A32=1	
	elif bingo==i:
		A33=1	

if (A11+A12+A13)==3:
	print("Yes")
elif (A21+A22+A23)==3:
	print("Yes")
elif (A31+A32+A33)==3:
	print("Yes")
elif (A11+A22+A33)==3:
	print("Yes")
elif (A13+A22+A31)==3:
	print("Yes")
else:
	print("No")


a,b,c=input().split()
d,e,f=input().split()
g,h,i=input().split()

loopin=input()

A11,A12,A13,A21,A22,A23,A31,A32,A33=0,0,0,0,0,0,0,0,0


for x in range(int(loopin)):
	bingo = input()
	if bingo==a:
		A11=1
	elif bingo==b:
		A12=1	
	elif bingo==c:
		A13=1	
	elif bingo==d:
		A21=1	
	elif bingo==e:
		A22=1	
	elif bingo==f:
		A23=1	
	elif bingo==g:
		A31=1	
	elif bingo==h:
		A32=1
	elif bingo==i:
		A33=1


if (A11+A12+A13)==3:
	print("Yes")
elif (A21+A22+A23)==3:
	print("Yes")
elif (A31+A32+A33)==3:
	print("Yes")
elif (A11+A21+A31)==3:
	print("Yes")
elif (A12+A22+A32)==3:
	print("Yes")
elif (A13+A23+A33)==3:
	print("Yes")
elif (A11+A22+A33)==3:
	print("Yes")
elif (A13+A22+A31)==3:
	print("Yes")
else:
	print("No")


Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
a=[]
for i in range(3):
    a.append(list(map(int,input().split())))
b=[[0 for i in range(3)] for j in range(3)]
n=int(input())
for i in range(n):
    p=int(input())
    for j in range(3):
        for k in range(3):
            if p==a[i][j]:
                b[i][j]=1
for i in range(3):
    x=0
    y=0
    for j in range(3):
        if b[i][j]==1:
            x+=1
        if b[j][i]==1:
            y+=1
    if x==3 or y==3:
        print('Yes')
        exit()
if b[0][0]==b[1][1]==b[2][2]==1:
    print('Yes')
    exit()
if b[2][0]==b[1][1]==b[0][2]==1:
    print('Yes')
    exit()
print('No')

a=[]
for i in range(3):
    a.append(list(map(int,input().split())))
b=[[0 for i in range(3)] for j in range(3)]
n=int(input())
for i in range(n):
    p=int(input())
    for j in range(3):
        for k in range(3):
            if p==a[j][k]:
                b[j][k]=1
for i in range(3):
    x=0
    y=0
    for j in range(3):
        if b[i][j]==1:
            x+=1
        if b[j][i]==1:
            y+=1
    if x==3 or y==3:
        print('Yes')
        exit()
if b[0][0]==b[1][1]==b[2][2]==1:
    print('Yes')
    exit()
if b[2][0]==b[1][1]==b[0][2]==1:
    print('Yes')
    exit()
print('No')


Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
a=[]
for i in range (2):
  for j in range(2):
    a.append(int(input()))
N=int(input())
for i in range(N):
  b[i]=int(input())
  
for i in range(2):
  for j in range(2):
    for k in range(N):
      if a[i][j]==b[k]:
        a[i][j]=1
      else:
        a[i][j]=0
        
if a[0][0]=1 and a[0][1]=1 and a[0][2]=1:
  print("Yes")
elif a[1][0]=1 and a[1][1]=1 and a[1][2]=1:
  print("Yes")
elif a[2][0]=1 and a[2][1]=1 and a[2][2]=1:
  print("Yes")
elif a[0][0]=1 and a[1][0]=1 and a[2][0]=1:
  print("Yes")
elif a[0][1]=1 and a[1][1]=1 and a[2][1]=1:
  print("Yes")
elif a[0][2]=1 and a[1][2]=1 and a[2][2]=1:
  print("Yes")
elif a[0][0]=1 and a[1][1]=1 and a[2][2]=1:
  print("Yes")
elif a[0][2]=1 and a[1][1]=1 and a[2][0]=1:
  print("Yes")
else:
  print("No")


A=[list(map(int,input().split())) for i in range(3)]
N=int(input())
B=list(int(input()) for i in range(N))
x=[]
for i in range(3):
  for j in range(3):
    if A[i][j] in B:
      x.append(A[i][j])
if A[0][0] in x and A[1][0] in x and A[2][0] in x:
  print("Yes")
elif A[0][1] in x and A[1][1] in x and A[2][1] in x:
  print("Yes")
elif A[0][2] in x and A[1][2] in x and A[2][2] in x:
  print("Yes")
elif A[0][0] in x and A[0][1] in x and A[0][2] in x:
  print("Yes")
elif A[1][0] in x and A[1][1] in x and A[1][2] in x:
  print("Yes")
elif A[2][0] in x and A[2][1] in x and A[2][2] in x:
  print("Yes")
elif A[0][0] in x and A[1][1] in x and A[2][2] in x:
  print("Yes")
elif A[0][2] in x and A[1][1] in x and A[2][0] in x:
  print("Yes")
else:
  print("No")

Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
a=[[int(input())for _ in range(3)]for _ in range(3)]
n=int(input())
b=[int(input())for _ in range(n)]
for i in b:
  for j in range(3):
    for k in range(3):
      if i==a[j][k]:a[j][k]=0
ans="No"
for i in range(3):
  if a[i][0]==a[i][1]==a[i][2]:ans="Yes"
  if a[0][i]==a[1][i]==a[2][i]:ans="Yes"
if a[0][0]==a[1][1]==a[2][2]:ans="Yes"
if a[0][2]==a[1][1]==a[2][0]:ans="Yes"
print(ans)

a=[list(map(int,input().split())) for _ in range(3)]
n=int(input())
b=[int(input())for _ in range(n)]
for i in b:
  for j in range(3):
    for k in range(3):
      if i==a[j][k]:a[j][k]=0
ans="No"
for i in range(3):
  if a[i][0]==a[i][1]==a[i][2]:ans="Yes"
  if a[0][i]==a[1][i]==a[2][i]:ans="Yes"
if a[0][0]==a[1][1]==a[2][2]:ans="Yes"
if a[0][2]==a[1][1]==a[2][0]:ans="Yes"
print(ans)


Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
A = []
for i in range(3):
    array = list(map(int, input().strip().split()))
    A.append(array)

# A = [input().split() for l in range(3)] 

N = int(input())
b = []
flag = 0
for i in range(N):
    b.append(int(input()))

print(type(int(A[0][0])))
print(type(b[0]))

if A[0][0] == b[0]:
    print("Yes")

for i in range(3):
    for j in range(3):
        for k in range(N):
            #print(A[i][j], b[k])
            if A[i][j] == b[k]:
                A[i][j] = 1000

for i in range(3):
    if A[i][0] == A[i][1] and A[i][1] == A[i][2] and A[i][2] == 1000:
        flag = 1
    if A[0][i] == A[1][i] and A[1][i] == A[2][i] and A[2][i] == 1000:
        flag = 1
    if A[0][0] == A[1][1] and A[1][1] == A[2][2] and A[2][2] == 1000:
        flag = 1
    if A[0][2] == A[1][1] and A[1][1] == A[2][0] and A[2][0] == 1000:
        flag = 1

if flag == 1:
    print("Yes")
else:
    print("No")

A = []
for i in range(3):
    array = list(map(int, input().strip().split()))
    A.append(array)

# A = [input().split() for l in range(3)] 

N = int(input())
b = []
flag = 0
for i in range(N):
    b.append(int(input()))

print(type(int(A[0][0])))
print(type(b[0]))

if A[0][0] == b[0]:
    print("Yes")

for i in range(3):
    for j in range(3):
        for k in range(N):
            #print(A[i][j], b[k])
            if A[i][j] == b[k]:
                A[i][j] = 1000

for i in range(3):
    if A[i][0] == A[i][1] and A[i][1] == A[i][2] and A[i][2] == 1000:
        flag = 1
    if A[0][i] == A[1][i] and A[1][i] == A[2][i] and A[2][i] == 1000:
        flag = 1
    if A[0][0] == A[1][1] and A[1][1] == A[2][2] and A[2][2] == 1000:
        flag = 1
    if A[0][2] == A[1][1] and A[1][1] == A[2][0] and A[2][0] == 1000:
        flag = 1

if flag == 1:
    print("Yes")
else:
    print("No")
print(A)

A = []
for i in range(3):
    array = list(map(int, input().strip().split()))
    A.append(array)

# A = [input().split() for l in range(3)] 

N = int(input())
b = []
flag = 0
for i in range(N):
    b.append(int(input()))

#print(type(int(A[0][0])))
#print(type(b[0]))

for i in range(3):
    for j in range(3):
        for k in range(N):
            #print(A[i][j], b[k])
            if A[i][j] == b[k]:
                A[i][j] = 1000

for i in range(3):
    if A[i][0] == A[i][1] and A[i][1] == A[i][2] and A[i][2] == 1000:
        flag = 1
    if A[0][i] == A[1][i] and A[1][i] == A[2][i] and A[2][i] == 1000:
        flag = 1
    if A[0][0] == A[1][1] and A[1][1] == A[2][2] and A[2][2] == 1000:
        flag = 1
    if A[0][2] == A[1][1] and A[1][1] == A[2][0] and A[2][0] == 1000:
        flag = 1

if flag == 1:
    print("Yes")
else:
    print("No")


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
a11, a12, a13 = map(int, input().split())
a21, a22, a23 = map(int, input().split())
a31, a32, a33 = map(int, input().split())

N = int(input())

bingo = [a11, a12, a13, a21, a22, a23, a31, a32, a33]

num = []
for _ in range(N):
  num.append(_)

for _ in range(len(bingo)):
  if bingo[_] in num:
    bingo[_] = 0

row1 = a11 + a12 + a13
row2 = a21 + a22 + a23
row3 = a31 + a32 + a33
col1 = a11 + a21 + a31
col2 = a12 + a22 + a32
col3 = a13 + a23 + a33
cross1 = a11 + a22 + a33
cross2 = a13 + a22 + a31

if 0 in [row1, row2, row3, col1, col2, col3, cross1, cross2]:
  print("Yes")
else:
  print("No")




a11, a12, a13 = map(int, input().split())
a21, a22, a23 = map(int, input().split())
a31, a32, a33 = map(int, input().split())
N = int(input())
num = []
for _ in range(N):
  num.append(int(input()))

row1 = a11 + a12 + a13
row2 = a21 + a22 + a23
row3 = a31 + a32 + a33
col1 = a11 + a21 + a31
col2 = a12 + a22 + a32
col3 = a13 + a23 + a33
cross1 = a11 + a22 + a33
cross2 = a13 + a22 + a31

if 0 in [row1, row2, row3, col1, col2, col3, cross1, cross2]:
  print("Yes")
else:
  print("No")

a11, a12, a13 = map(int, input().split())
a21, a22, a23 = map(int, input().split())
a31, a32, a33 = map(int, input().split())
N = int(input())
num = []
for _ in range(N):
  num.append(int(input()))
  
bingo = [
  [a11, a12, a13], 
  [a21, a22, a23], 
  [a31, a32, a33]
]
 
for n in range(3):
  for m in range(3): 
    if bingo[n][m] in num:
      bingo[n][m] = 0
 
row1 = bingo[0][0] + bingo[0][1] + bingo[0][2]
row2 = bingo[1][0] + bingo[1][1] + bingo[1][2]
row3 = bingo[2][0] + bingo[2][1] + bingo[2][2]
 
col1 = bingo[0][0] + bingo[1][0] + bingo[2][0]
col2 = bingo[0][1] + bingo[1][1] + bingo[2][1]
col3 = bingo[0][2] + bingo[1][2] + bingo[2][2]
 
cross1 = bingo[0][0] + bingo[1][1] + bingo[2][2]
cross2 = bingo[2][0] + bingo[1][1] + bingo[2][0]
 
if 0 in [row1, row2, row3, col1, col2, col3, cross1, cross2]:
  print("Yes")
else:
  print("No")

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
A = [list(map(int, input().split())) for i in range(0,3)]
N = int(input())
b_list =list([int(input()) for i in range(0,N)])
count = 0
for i in range(0,3):
    for j in range(0,3):
        if A[i][j] in b_list:
            count = count + (i+1)*(j+1)
if count % 3 == 0:
    print('Yes')
else:
    print('No')

import numpy as np
A = [list(map(int, input().split())) for i in range(0,3)]
N = int(input())
b_list =list([int(input()) for i in range(0,N)])
count = np.zeros((3,3))
for i in range(0,3):
    for j in range(0,3):
        if A[i][j] in b_list:
            count[i][j] = count + 1
if (count.sum(axis=1) % 3 ==0).any():
    print('Yes')
elif (count.sum(axis=0) % 3 ==0).any():
    print('Yes')
elif count[0][0] + count[1][1] + count[2][2]:
    print('Yes')
elif count[2][0] + count[1][1] + count[0][2]:
    print('Yes')
else:
    print('No')

import numpy as np
A = [list(map(int, input().split())) for i in range(0,3)]
N = int(input())
b_list =list([int(input()) for i in range(0,N)])
count = np.zeros(3,3)
for i in range(0,3):
    for j in range(0,3):
        if A[i][j] in b_list:
            count[i][j] = count + (i+1)*(j+1)
if (count.sum(axis=1) % 3 ==0).any():
    print('Yes')
elif (count.sum(axis=0) % 3 ==0).any():
    print('Yes')
elif count[0][0] + count[1][1] + count[2][2]:
    print('Yes')
elif count[2][0] + count[1][1] + count[0][2]:
    print('Yes')
else:
    print('No')

import numpy as np
A = [list(map(int, input().split())) for i in range(0,3)]
N = int(input())
b_list =list([int(input()) for i in range(0,N)])
count = np.zeros((3,3))
for i in range(0,3):
    for j in range(0,3):
        if A[i][j] in b_list:
            count[i][j] = count[i][j] + 1
if (count.sum(axis=1)  ==3).any():
    print('Yes')
elif (count.sum(axis=0) ==3).any():
    print('Yes')
elif count[0][0] + count[1][1] + count[2][2]==3:
    print('Yes')
elif count[2][0] + count[1][1] + count[0][2]==3:
    print('Yes')
else:
    print('No')

Verdicts: Wrong Answer

Runtime Error

Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

if __name__ == '__main__':
    a = [list(map(int, input().split())) for e in range(3)]
    n = int(input())
    b = [int(input()) for _ in range(n)]
    c = 'No'
    for i in range(len(a)):
        for j in range(len(a)):
            if a[i][j] in b:
                a[i][j] = 0

    for i in range(len(a)):
         if {a[i][j] for j in range(len(a))} == {0}:
             c = 'Yes'
         if {a[j][i] for j in range(len(a))} == {0}:
            c = 'Yes'
    if {a[j][j] for j in range(len(a))} == {0}:
        c = 'Yes'
    if {a[-(j+1)][j] for j in range(len(a))} == {0}:
        c = 'Yes'
    print(c)

Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
a=[list(map(int,input().split())) for i in range(3)]
n=int(input())
b=[]
for i in range(n):
    b.append(int(input()))
for j in range(3):
    for k in range(3):
        if a[j][k] == b:
            a[j][k] = 0
ans='No'
for i in range(3):
    if a[i][0]==a[i][1]==a[i][2]==0:
        ans='Yes'
    if a[0][i]==a[1][i]==a[2][i]==0:
        ans='Yes'
if a[0][0]==a[1][1]==a[2][2]==0:
    ans='Yes'
if a[2][0]==a[1][1]==a[0][2]==0:
    ans='Yes'
print(ans)

a=[list(map(int,input().split())) for i in range(3)]
n=int(input())
for i in range(int(input())):
  b=int(input())
  for j in range(3):
    for k in range(3):
      if a[j][k]==b:a[j][k]=0
ans='No'
for i in range(3):
    if a[i][0]==a[i][1]==a[i][2]==0:
        ans='Yes'
    if a[0][i]==a[1][i]==a[2][i]==0:
        ans='Yes'
if a[0][0]==a[1][1]==a[2][2]==0:
    ans='Yes'
if a[2][0]==a[1][1]==a[0][2]==0:
    ans='Yes'
print(ans)

a=[list(map(int,input().split()))for _ in range(3)]
for i in range(int(input())):
  b=int(input())
  for j in range(3):
    for k in range(3):
      if a[j][k]==b:a[j][k]=0
ans="No"
for i in range(3):
  if a[i][0]==a[i][1]==a[i][2]==0:ans="Yes"
  if a[0][i]==a[1][i]==a[2][i]==0:ans="Yes"
if a[0][0]==a[1][1]==a[2][2]==0:ans="Yes"
if a[2][0]==a[1][1]==a[0][2]==0:ans="Yes"
print(ans)

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
list1 = list(map(int, input().split()))
list2 = list(map(int, input().split()))
list3 = list(map(int, input().split()))
n = int(input())
num_list = []
for i in range(n):
    b = int(input())
    num_list.append(b)
for num in num_list:
    if num in list1:
        x = list1.index(num)
        list1.pop(x)
        list1.insert(x, 'bingo')
    if num in list2:
        x = list2.index(num)
        list2.pop(x)
        list2.insert(x, 'bingo')
    if num in list3:
        x = list3.index(num)
        list3.pop(x)
        list3.insert(x, 'bingo')
result = 'No'
if list1[0] == list1[1] == list1[2] == 'bingo':
    result = 'Yes'
if list2[0] == list2[1] == list2[2] == 'bingo':
    result = 'Yes'
if list3[0] == list3[1] == list3[2] == 'bingo':
    result = 'Yes'
if list1[0] == list2[0] == list3[0] == 'bingo':
    result = 'Yes'
if list1[1] == list2[1] == list3[1] == 'bingo':
    result = 'Yes'
if list1[2] == list2[2] == list3[2] == 'bingo':
    result = 'Yes'
if list1[0] == list2[1] == list3[2] == 'bingo':
    result = 'Yes'
if list1[2] == list2[1] == list3[0] == 'bingo':
    result = 'Yes'
print(list1)
print(list2)
print(list3)
print(result)

list1 = list(map(int, input().split()))
list2 = list(map(int, input().split()))
list3 = list(map(int, input().split()))
n = int(input())
num_list = []
for i in range(n):
    b = int(input())
    num_list.append(b)
for num in num_list:
    if num in list1:
        x = list1.index(num)
        list1.pop(x)
        list1.insert(x, 'bingo')
    if num in list2:
        x = list2.index(num)
        list2.pop(x)
        list2.insert(x, 'bingo')
    if num in list3:
        x = list3.index(num)
        list3.pop(x)
        list3.insert(x, 'bingo')
result = 'No'
if list1[0] == list1[1] == list1[2] == 'bingo':
    result = 'Yes'
if list2[0] == list2[1] == list2[2] == 'bingo':
    result = 'Yes'
if list3[0] == list3[1] == list3[2] == 'bingo':
    result = 'Yes'
if list1[0] == list2[0] == list3[0] == 'bingo':
    result = 'Yes'
if list1[1] == list2[1] == list3[1] == 'bingo':
    result = 'Yes'
if list1[2] == list2[2] == list3[2] == 'bingo':
    result = 'Yes'
if list1[0] == list2[1] == list3[2] == 'bingo':
    result = 'Yes'
if list1[2] == list2[1] == list3[0] == 'bingo':
    result = 'Yes'

print(result)

Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
a = [list(map(int, input().split())) for _ in range(3)]
N=int(input())
b = [input() for _ in range(N)]


cnt=0

for i in range(N):
    for j in range(3):
        for k in range(3):
            if b[i] == a[j][k]:
                a[j][k] =1000
                if sum(a[j]) ==3000 or a[0][k]+a[1][k]+a[2][k]==3000 or a[0][0]+a[1][1]+a[2][2]==3000 or a[0][2]+a[1][1]+a[2][0]==3000:
                    cnt +=1
print('Yes' if cnt>0 else 'No')

a = [list(map(int, input().split())) for _ in range(3)]
N=int(input())
b = [input() for _ in range(N)]


cnt=0

for i in range(N):
    for j in range(3):
        for k in range(3):
            if b[i] == a[j][k]:
                a[j][k] =1000
            if sum(a[j]) ==3000 or a[0][k]+a[1][k]+a[2][k]==3000 or a[0][0]+a[1][1]+a[2][2]==3000 or a[0][2]+a[1][1]+a[2][0]==3000:
                cnt +=1
print('Yes' if cnt>0 else 'No')

a = [list(map(int, input().split())) for _ in range(3)]
N=int(input())
b = [int(input()) for _ in range(N)]


cnt=0

for i in range(N):
    for j in range(3):
        for k in range(3):
            if b[i] == a[j][k]:
                a[j][k] =1000
                if sum(a[j]) ==3000 or a[0][k]+a[1][k]+a[2][k]==3000 or a[0][0]+a[1][1]+a[2][2]==3000 or a[0][2]+a[1][1]+a[2][0]==3000:
                    cnt +=1
print('Yes' if cnt>0 else 'No')

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
import sys
N = 3


A = []
for i in range(N):
    array = list(map(int, input().strip().split()))
    A.append(array)

A_t = [list(x) for x in zip(*A)]
A_n = [[A[0][0],A[1][1],A[2][2]],[A[0][2],A[1][1],A[2][0]]]
N = int(input())
B=[]
cnt = [0]*3
for i in range(N):
    B.append(int(input()))
    
cnt[0] =0
num = 0
for j in A:
    for i in j:
        if i in B:
            cnt[num] += 1
    num +=1
if 2 in cnt:
    print("yes")
    sys.exit(0)
cnt = [0,0,0]
num = 0
for j in A_t:
    for i in j:
        if i in B:
            cnt[num] += 1
    num +=1
if 2 in cnt:
    print("yes")
    sys.exit()
cnt = [0,0,0]
num = 0
for j in A_n:
    for i in j:
        if i in B:
            cnt[num] += 1
    num +=1
if 2 in cnt:
    print("yes")
else:
    print("no")

import sys
N = 3


A = []
for i in range(N):
    array = list(map(int, input().strip().split()))
    A.append(array)

A_t = [list(x) for x in zip(*A)]
A_n = [[A[0][0],A[1][1],A[2][2]],[A[0][2],A[1][1],A[2][0]]]
N = int(input())
B=[]
cnt = [0]*3
for i in range(N):
    B.append(int(input()))
    
num = 0
for j in A:
    for i in j:
        if i in B:
            cnt[num] += 1
    num +=1
if 3 in cnt:
    print("Yes")
    sys.exit(0)
cnt = [0,0,0]
num = 0
for j in A_t:
    for i in j:
        if i in B:
            cnt[num] += 1
    num +=1
if 3 in cnt:
    print("Yes")
    sys.exit()
cnt = [0,0,0]
num = 0
for j in A_n:
    for i in j:
        if i in B:
            cnt[num] += 1
    num +=1
if 3 in cnt:
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
A_1 = list(map(int, input().split()))
A_2 = list(map(int, input().split()))
A_3 = list(map(int, input().split()))
N = int(input())
b = [(int(input())) for _ in range(N)]
for i in range(3):
    for j in range(N):
        if A_1[i] == b[j]:
            A_1[i] = "a"
        elif A_2[i] == b[j]:
            A_2[i] = "a"
        elif A_3[i] == b[j]:
            A_3[i] = "a"
print(A_1, A_2, A_3)

if A_1[0] == A_1[1] == A_1[2]:
    print("Yes")
elif A_2[0] == A_2[1] == A_2[2]:
    print("Yes")
elif A_3[0] == A_3[1] == A_3[2]:
    print("Yes")
elif A_1[0] == A_2[0] == A_3[0]:
    print("Yes")
elif A_1[1] == A_2[1] == A_3[1]:
    print("Yes")
elif A_1[2] == A_2[2] == A_3[3]:
    print("Yes")
elif A_1[0] == A_2[1] == A_3[2]:
    print("Yes")
elif A_1[2] == A_2[1] == A_3[0]:
    print("Yes")
else:
    print("No")


A_1 = list(map(int, input().split()))
A_2 = list(map(int, input().split()))
A_3 = list(map(int, input().split()))
N = int(input())
b = [list(map(int, input().split()))for _ in range(N)]
for i in range(3):
    for j in range(N):
        if A_1[i] == b[j][0]:
            A_1[i] = "a"
        elif A_2[i] == b[j][0]:
            A_2[i] = "a"
        elif A_3[i] == b[j][0]:
            A_3[i] = "a"
print(A_1, A_2, A_3)

if A_1[0] == A_1[1] == A_1[2]:
    print("Yes")
elif A_2[0] == A_2[1] == A_2[2]:
    print("Yes")
elif A_3[0] == A_3[1] == A_3[2]:
    print("Yes")
elif A_1[0] == A_2[0] == A_3[0]:
    print("Yes")
elif A_1[1] == A_2[1] == A_3[1]:
    print("Yes")
elif A_1[2] == A_2[2] == A_3[3]:
    print("Yes")
elif A_1[0] == A_2[1] == A_3[2]:
    print("Yes")
elif A_1[2] == A_2[1] == A_3[0]:
    print("Yes")
else:
    print("No")

A_1 = list(map(int, input().split()))
A_2 = list(map(int, input().split()))
A_3 = list(map(int, input().split()))
N = int(input())
b = [(int(input())) for _ in range(N)]
Z_1 = [0, 0, 0]
Z_2 = [0, 0, 0]
Z_3 = [0, 0, 0]
for i in range(3):
    for j in range(N):
        if A_1[i] == b[j]:
            Z_1[i] = 1
        elif A_2[i] == b[j]:
            Z_2[i] = 1
        elif A_3[i] == b[j]:
            Z_3[i] = 1


if Z_1[0] == Z_1[1] == Z_1[2] == 1:
    print("Yes")
elif Z_2[0] == Z_2[1] == Z_2[2] == 1:
    print("Yes")
elif Z_3[0] == Z_3[1] == Z_3[2] == 1:
    print("Yes")
elif Z_1[0] == Z_2[0] == Z_3[0] == 1:
    print("Yes")
elif Z_1[1] == Z_2[1] == Z_3[1] == 1:
    print("Yes")
elif Z_1[2] == Z_2[2] == Z_3[2] == 1:
    print("Yes")
elif Z_1[0] == Z_2[1] == Z_3[2] == 1:
    print("Yes")
elif Z_1[2] == Z_2[1] == Z_3[0] == 1:
    print("Yes")
else:
    print("No")


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
R = 3
r = [ list(map(int, input().split(' '))) for i in range(R) ]

def check():
  for y in range(R):
    f = True
    for x in range(R):
      if r[y][x] != 0:
        f = False
        break
    if f:
      return True
 
  for x in range(R):
    f = True
    for y in range(R):
      if r[y][x] != 0:
        f = False
	    break
    if f:
      return True
 
  f = True
  for p in range(R):
    if r[p][p] != 0:
      f = False
      break
  if f:
    return True
 
  f = True
  for p in range(R):
    if r[R-1-p][p] != 0:
      f = False
      break
  return f
 
N = int(input())
for i in range(N):
  v = int(input())
  
  for y in range(R):
    for x in range(R):
      if r[y][x] == v:
        r[y][x] = 0
 
print('Yes' if check() else 'No')

R = 3
r = []
for i in range(R):
  r[i] = list(map(int, input().split(' ')))

def check():
  for y in range(R):
    f = True
    for x in range(R):
      if r[y][x] != 0:
        f = False
    if f:
      return True

  for x in range(R):
    f = True
    for y in range(R):
      if r[y][x] != 0:
        f = False
    if f:
      return True

  f = True
  for p in range(R):
    if r[p][p] != 0:
	    f = False
  if f:
    return True

  f = True
  for p in range(R):
    if r[R-1-p][p] != 0:
	    f = False
  return f

N = input()
for i in range(N):
  v = int(input())
  
  for y in range(R):
    for x in range(R):
      if r[y][x] == v:
        r[y][x] = 0

print('Yes' if check() else 'No')


R = 3
r = [ list(map(int, input().split(' '))) for i in range(R) ]

def check():
  for y in range(R):
    f = True
    for x in range(R):
      if r[y][x] != 0:
        f = False
        break
    if f:
      return True
 
  for x in range(R):
    f = True
    for y in range(R):
      if r[y][x] != 0:
        f = False
        break
    if f:
      return True
 
  f = True
  for p in range(R):
    if r[p][p] != 0:
      f = False
      break
  if f:
    return True
 
  f = True
  for p in range(R):
    if r[R-1-p][p] != 0:
      f = False
      break
  return f
 
N = int(input())
for i in range(N):
  v = int(input())
  
  for y in range(R):
    for x in range(R):
      if r[y][x] == v:
        r[y][x] = 0
 
print('Yes' if check() else 'No')

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
a = []
for _ in range(3):
    a.append(list(map(int, input().split())))
n = int(input())
b = []
for _ in range(n):
    b.append(int(input()))

check = [[False] * 3 for _ in range(3)]

for b_one in b:
    for i in range(3):
        for j in range(3):
            if a[i][j] == b_one:
                check[i][j] = True

if check[0][0] and check[0][1] and check[0][2]:
    print('Yes')
    return
if check[1][0] and check[1][1] and check[1][2]:
    print('Yes')
    return
if check[2][0] and check[2][1] and check[2][2]:
    print('Yes')
    return
if check[0][0] and check[1][0] and check[2][0]:
    print('Yes')
    return
if check[0][1] and check[1][1] and check[2][1]:
    print('Yes')
    return
if check[0][2] and check[1][2] and check[2][2]:
    print('Yes')
    return
if check[0][0] and check[1][1] and check[2][2]:
    print('Yes')
    return
if check[0][2] and check[1][1] and check[2][0]:
    print('Yes')
    return

print('No')

def resolve():
    a = []
    for _ in range(3):
        a.append(list(map(int, input().split())))
    n = int(input())
    b = []
    for _ in range(n):
        b.append(int(input()))

    check = [[False] * 3 for _ in range(3)]

    for b_one in b:
        for i in range(3):
            for j in range(3):
                if a[i][j] == b_one:
                    check[i][j] = True

    if check[0][0] and check[0][1] and check[0][2]:
        print('Yes')
        return
    if check[1][0] and check[1][1] and check[1][2]:
        print('Yes')
        return
    if check[2][0] and check[2][1] and check[2][2]:
        print('Yes')
        return
    if check[0][0] and check[1][0] and check[2][0]:
        print('Yes')
        return
    if check[0][1] and check[1][1] and check[2][1]:
        print('Yes')
        return
    if check[0][2] and check[1][2] and check[2][2]:
        print('Yes')
        return
    if check[0][0] and check[1][1] and check[2][2]:
        print('Yes')
        return
    if check[0][2] and check[1][1] and check[2][0]:
        print('Yes')
        return

    print('No')

resolve()

Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
lines = [input().split() for i in range(3)]
 
num = int(input())
bs = []
for i in range(num):
  bs.append(input())
 
hits = []
for i in bs:
  for row_index in range(len(lines)):
    for col_index in range(len(line)):
      if lines[row_index][col_index] == i:
        hits.append((row_index,col_index))
row_hits = (0,0,0)
col_hits = (0,0,0)
stride_hits = (0,0)
 
for hit in hits:
  r = hit[0]
  c = hit[1]
  row_hits[r]+=1
  col_hits[c]+=1
  if r == c:
    stride_hits[0]+=1
  else if (r,c) == (0,2) or (r,c) == (1,1) or (r,c) == (2,0) :
    stride_hits[1]+=1
 
if max(row_hits)>= 3 or max(col_hits)>=3 or max(stride_hits)>= 3:
  print 'Yes'
else:
  print 'No'
  

lines = [input().split() for i in range(3)]

num = int(input())
bs = []
for i in range(num):
  bs.append(input())

hits = []
for i in bs:
  for row_index in range(len(lines)):
    for col_index in range(len(line)):
      if lines[row_index][col_index] == i:
        hits.append((row_index,col_index))
row_hits = (0,0,0)
col_hits = (0,0,0)
stride_hits = (0,0)

for hit in hits:
  r = hit[0]
  c = hit[1]
  row_hits[r]++
  col_hits[c]++
  if r == c:
    stride_hits[0]++
  else if (r,c) == (0,2) or (r,c) == (1,1) or (r,c) == (2,0) :
    stride_hits[1]++

if max(row_hits)>= 3 or max(col_hits)>=3 or max(stride_hits)>= 3:
  print 'Yes'
else:
  print 'No'
  

lines = [input().split() for i in range(3)]
 
num = int(input())
bs = []
for i in range(num):
  bs.append(input())
 
hits = []
for i in bs:
  for row_index in range(len(lines)):
    for col_index in range(len(lines[row_index])):
      if lines[row_index][col_index] == i:
        hits.append((row_index,col_index))
row_hits = [0,0,0]
col_hits = [0,0,0]
stride_hits = [0,0]
 
for hit in hits:
  r = hit[0]
  c = hit[1]
  row_hits[r]+=1
  col_hits[c]+=1
  if r == c:
    stride_hits[0]+=1
  if (r,c) == (0,2) or (r,c) == (1,1) or (r,c) == (2,0) :
    stride_hits[1]+=1
 
if max(row_hits)>= 3 or max(col_hits)>=3 or max(stride_hits)>= 3:
  print ('Yes')
else:
  print ('No')
  

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
A=sum([list(map(int,input().split())) for _ in range(3)],[])
N=int(input())
b=[int(input()) for _ in range(N)]
f=0
for i in range(9):if A[i]in b:f|=1<<i
print('Yes'if sum(f&v==v for v in[7,23,56,84,146,273,292,448])else'No')

A = [list(map(int, input().split())) for _ in range(3)]
N = int(input())
b = [int(input()) for _ in range(N)]

field = 0
for v in b:
	for i in range(9):
		if A[i // 3][i % 3] == v:
			f|=1<<i
ans = 0
for v in [7,56,73,84,146,273,292,448]:
  ans |= f&v==v;
print('Yes' if ans else 'No')


p,r=input,range
A=sum([list(map(int,p().split()))for _ in r(3)],[])
b=[int(p())for _ in r(int(p()))]
print('YNeos'[[v for v in[7,56,73,84,146,273,292,448]if sum(1<<i for i in r(9)if A[i]in b)&v==v]::2])

p,r=input,range
A=sum([list(map(int,p().split()))for _ in r(3)],[])
b=[int(p())for _ in r(int(p()))]
print('YNeos'[any([sum(1<<i for i in r(9)if A[i]in b)&v==v for v in[7,56,73,84,146,273,292,448]])::2])

p,r=input,range
A=sum([list(map(int,p().split()))for _ in r(3)],[])
b=[int(p())for _ in r(int(p()))]
print('YNeos'[all([sum(1<<i for i in r(9)if A[i]in b)&v!=v for v in[7,56,73,84,146,273,292,448]])::2])

Verdicts: Runtime Error

Runtime Error

Runtime Error

Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
arr = []
ans = []
for i in range(3):
  arr.extend(list(map(int,input().split())))
N = int(input())
for j in range(N):
  num = int(input())
  if num in arr:
    ans.append(arr.index(num))
    print(ans)
ans = set(ans)
if (set([0,1,2])<=ans)or(set([3,4,5])<=ans)or(set([6,7,8])<=ans)or(set([0,3,6])<=ans)or(set([1,4,7])<=ans)or(set([2,5,8])<=ans)or(set([0,4,8])<=ans)or(set([2,4,6])<=ans):
  print('Yes')
else:
  print('No')


arr = []
ans = []
for i in range(3):
  arr.extend(list(map(int,input().split())))
N = int(input())
for j in range(N):
  num = int(input())
  if num in arr:
    ans.append(arr.index(num))
ans = set(ans)
if (set([0,1,2])<=ans)or(set([3,4,5])<=ans)or(set([6,7,8])<=ans)or(set([0,3,6])<=ans)or(set([1,4,7])<=ans)or(set([2,5,8])<=ans)or(set([0,4,8])<=ans)or(set([2,4,6])<=ans):
  print('Yes')
else:
  print('No')


Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
import numpy as np


A = np.array([list(map(int, input().split())) for _ in range(3)])
n = int(input())
for _ in range(n):
  b = int(input())
  A = np.where(A == b, 0, A)
  
x = np.all(A[[0, 1, 2], [0, 1, 2]] == 0)
y = np.all(A[[0, 1, 2], [2, 1, 0]] == 0)
z = np.any(np.sum(A, axis=0) == 0)
w = np.any(np.sum(A, axis=1) == 0)

print(['Yes', 'No'][!x and !y and !z and !w])

import numpy as np
 

A = np.array([list(map(int, input().split())) for _ in range(3)])
n = int(input())
for _ in range(n):
  b = int(input())
  A = np.where(A == b, 0, A)
  
x = np.all(A[[0, 1, 2], [0, 1, 2]] == 0)
y = np.all(A[[0, 1, 2], [2, 1, 0]] == 0)
z = np.any(np.sum(A, axis=0) == 0)
w = np.any(np.sum(A, axis=1) == 0)
 
print(['Yes', 'No'][not x and not y and not z and not w])

Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
import numpy as np
A = np.array([list(map(str, input().split())) for _ in range(3)])
N = int(input())
b = [input() for _ in range(N)]

for i in range(3):
    for j in range(3):
        if A[i][j] in b:
            A[i][j] = 'X'
print(A)

if A[0][0] == A[1][1] == A[2][2] == 'X':
    print('Yes')
    exit()

if A[0][2] == A[1][1] == A[2][0] == 'X':
    print('Yes')
    exit()

if A[0][0] == A[0][1] == A[0][2] == 'X':
    print('Yes')
    exit()

if A[1][0] == A[1][1] == A[1][2] == 'X':
    print('Yes')
    exit()

if A[2][0] == A[2][1] == A[2][2] == 'X':
    print('Yes')
    exit()

# t
if A[0][0] == A[1][0] == A[2][0] == 'X':
    print('Yes')
    exit()
if A[0][1] == A[1][1] == A[2][1] == 'X':
    print('Yes')
    exit()
if A[0][2] == A[1][2] == A[2][2] == 'X':
    print('Yes')
    exit()
print('No')

import numpy as np
A = np.array([list(map(str, input().split())) for _ in range(3)])
N = int(input())
b = [input() for _ in range(N)]

for i in range(3):
    for j in range(3):
        if A[i][j] in b:
            A[i][j] = 'X'

if A[0][0] == A[1][1] == A[2][2] == 'X':
    print('Yes')
    exit()

if A[0][2] == A[1][1] == A[2][0] == 'X':
    print('Yes')
    exit()

if A[0][0] == A[0][1] == A[0][2] == 'X':
    print('Yes')
    exit()

if A[1][0] == A[1][1] == A[1][2] == 'X':
    print('Yes')
    exit()

if A[2][0] == A[2][1] == A[2][2] == 'X':
    print('Yes')
    exit()

# t
if A[0][0] == A[1][0] == A[2][0] == 'X':
    print('Yes')
    exit()
if A[0][1] == A[1][1] == A[2][1] == 'X':
    print('Yes')
    exit()
if A[0][2] == A[1][2] == A[2][2] == 'X':
    print('Yes')
    exit()
print('No')

Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
import sys
a = [list(map(int, input().split())) for i in range(3)]
n = int(input())
b = [int(input()) for i in range(n)]

for i in range(3):
    ans = True
    for j in range(3):
        if a[i][j] not in b:
            ans = False
    if ans:
        print("Yes")
        sys.exit()
for j in range(3):
    ans = True
    for i in range(3):
        if a[i][j]  not in b:
            ans = False
    if ans:
        print("Yes")
        sys.exit()
if all([a[0][2] in b, a[1][1] in b, a[2][2] in b]) or all([a[0][2] in b, a[1][1] in b, a[2][0] in b]):
    print("Yes")
    sys.exit()

print("No")


import sys
a = [list(map(int, input().split())) for i in range(3)]
n = int(input())
b = [int(input()) for i in range(n)]

for i in range(3):
    ans = True
    for j in range(3):
        if a[i][j] not in b:
            ans = False
    if ans:
        print("Yes")
        sys.exit()
for j in range(3):
    ans = True
    for i in range(3):
        if a[i][j]  not in b:
            ans = False
    if ans:
        print("Yes")
        sys.exit()
if all([a[0][0] in b, a[1][1] in b, a[2][2] in b]) or all([a[0][2] in b, a[1][1] in b, a[2][0] in b]):
    print("Yes")
    sys.exit()

print("No")


Verdicts: Wrong Answer

Accepted