TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M = map(int,input().split())
L = []
R = []
for i in range(1,M+1):
  x,y = map(int,input().split())
  L.append(L_val)
  R.append(R_val)
ans = max(min(R) - max(L) + 1,0)
print(ans)

N,M = map(int,input().split())
L = []
R = []
for i in range(M+1):
  L_val,R_val = map(int,input().split())
  L.append(L_val)
  R.append(R_val)
ans = max(min(R) - max(L) + 1,0)
print(ans)

N,M = map(int,input().split())
L = []
R = []
for i in range(1,M+1):
  L_val,R_val = map(int,input().split())
  L.append(L_val)
  R.append(R_val)
ans = max(min(R) - max(L) + 1,0)
print(ans)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
ans_l = 1
ans_r = 10 ** 5
l_list = []
r_list = []
for i in range(m):
    l, r = map(int, input().split())
    l_list.append(l)
    r_list.append(r)
for r in r_list:
    if ans_r > r:
        ans_r = r
for l in l_list:
    if ans_l <= l:
        asn_l = l
if ans_r > ans_l:
    print(ans_r - ans_l + 1)
else:
    print(0)

a = 1

n, m = map(int, input().split())
ans_r = 10 ** 5

l_list = []
r_list = []
for i in range(m):
    l, r = map(int, input().split())
    l_list.append(int(l))
    r_list.append(int(r))
for r in r_list:
    if ans_r > r:
        ans_r = r
for l in l_list:
    if a < l:
        a = l

if ans_r >= a:
    print(ans_r - a + 1)
else:
    print(0)


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
B = set()
for i in range(M):
  L, R = map(int, input().split())
  A = set(for j in range(L, R+1))
  if i == 0:
    B = A
  B = A & B
print(len(B))

N, M = map(int, input().split())
maxL = 1
minR = 1
for i in range(M):
  L, R = map(int, input().split())
  maxL = max(maxL, L)
  minR = min(minR, R)
print(max(minR - maxL +1, 0))


N, M = map(int, input().split())
maxL = 1
minR = N
for i in range(M):
  L, R = map(int, input().split())
  maxL = max(maxL, L)
  minR = min(minR, R)
print(max(minR - maxL +1, 0))

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
# coding: utf-8

import sys
input = sys.stdin.readline

# N = int(input())
# L = [int(x) for x in input().split()]
N, M = map(int, input().split())
# S = input()

ok = [0] * (N + 2)
for i in range(M):
    L, R = map(int, input().split())
    print(L, R)
    ok[L] += 1
    ok[R + 1] -= 1

ans = 0
tmp = 0
for i in range(1, N + 1):
    tmp += ok[i]
    
    if tmp == M:
        ans += 1

print(ans)


# coding: utf-8

import sys
input = sys.stdin.readline

# N = int(input())
# L = [int(x) for x in input().split()]
N, M = map(int, input().split())
# S = input()

ok = [0] * (N + 2)
for i in range(M):
    L, R = map(int, input().split())
    ok[L] += 1
    ok[R + 1] -= 1

ans = 0
tmp = 0
for i in range(1, N + 1):
    tmp += ok[i]
    
    if tmp == M:
        ans += 1

print(ans)


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
left,right = 1,n
for i in range(m):
    l,r = map(int,input().split())
    left = max(left,1)
    right = min(right,r)
print(max(0,right-left+1))


n,m = map(int ,input().split())
left,right = 1,n
for i in range(m):
    l,r = map(int,input().split())
    left = max(left,l)
    right = min(right,r)
print(max(0,right - left + 1))


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
ans = [0 for _ in range(n+1)]
for i in range(m):
  l,r = map(int,input().split())
  ans[l] += 1
  ans[r+1] += -1
  
from itertools import accumulate
ans = list(accumulate(ans))
count = 0
for a in ans:
  if a == n:
    count +=1
print(count)

n,m = map(int,input().split())
ans = [0 for _ in range(n+2)]
for i in range(m):
  l,r = map(int,input().split())
  ans[l] += 1
  ans[r+1] += -1
  
from itertools import accumulate
ans = list(accumulate(ans))
count = 0
for a in ans:
  if a == m:
    count +=1
print(count)



Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
list_open = []
for i in range(m):
  list_open.append(list((int(i) for i in input().split())))
dict_open = {}
for i in range(m):
  for j in range(list_open[i][0], list_open[i][1] + 1):
    try:
      dict_open[j] += 1
    else:
      dict_open[j] = 1
print(list(dict_open.values()).count(m)

n, m = map(int, input().split())
list_open = []
for i in range(m):
  list_open.append(list((int(i) for i in input().split())))
dict_open = {}
for i in range(m):
  for j in range(list_open[i][0], list_open[i][1] + 1):
    try:
      dict_open[j] += 1
    else:
      dict_open[j] = 1
print(list(dict_open.values()).count(m))

n, m = map(int, input().split())
min_num = 0
max_num = 10**5
           
for i in range(m):
  min_temp, max_temp = map(int, input().split())
  if min_temp > min_num:
    min_num = min_temp
  if max_temp < max_num:
    max_num = max_temp
print(max(max_num - min_num + 1, 0))
  


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
ls = []
rs = []

for _ in range(m):
    l, r = map(int, input().split())
    ls.append(l)
    rs.append(r)

l_max = max(l)
r_min = min(r)
master_card_num = r_min - l_max

if master_card_num < 0:
    print(0)
else:
    print(master_card_num + 1)

n, m = map(int, input().split())
ls = []
rs = []

for _ in range(m):
    l, r = map(int, input().split())
    ls.append(l)
    rs.append(r)

l_max = max(ls)
r_min = min(rs)
master_card_num = r_min - l_max

if master_card_num < 0:
    print(0)
else:
    print(master_card_num + 1)
    



Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = list(map(int, input().split()))
l = []
r = []
for i in range(m):
    x, y=[int(i) for i in input().split()]
    l.append(x)
    r.append(y)
ans = 0
for i in range(n):
    cnt = 0
    for j in range(m):

        for k in range(l[j], r[j]+1):
            print(l[j], end=' ')
            print(r[j])
            if i + 1 == k:
                cnt += 1
        if cnt == m:
            ans += 1
print(ans)

n, m = list(map(int, input().split()))
maxl = 0
minr = 10000
for i in range(m):
    l, r = list(map(int, input().split()))
    maxl = max(maxl, l)
    minr = min(minr, r)
if minr > maxl:
    print(0)
else:
    print(maxl - minr + 1)

n, m = list(map(int, input().split()))
l = []
r = []
for i in range(m):
    x, y=[int(i) for i in input().split()]
    l.append(x)
    r.append(y)
ans = 0
for i in range(n):
    cnt = 0
    for j in range(m):

        for k in range(l[j], r[j]+1):S
            if i + 1 == k:
                cnt += 1
        if cnt == m:
            ans += 1
print(ans)

n, m = list(map(int, input().split()))
l = []
r = []
for i in range(m):
    x, y=[int(i) for i in input().split()]
    l.append(x)
    r.append(y)
ans = 0
for i in range(n):
    cnt = 0
    for j in range(m):

        for k in range(l[j], r[j]+1):
            print(l[j], end=' ')
            print(r[j])
            if i + 1 == k:
                cnt += 1
                print('cnt='+ str(cnt))
        if cnt == m:
            ans += 1
print(ans)

n, m = list(map(int, input().split()))
maxl = 0
minr = 1000000
for i in range(m):
    l, r = list(map(int, input().split()))
    maxl = max(maxl, l)
    minr = min(minr, r)
if minr < maxl:
    print(0)
else:
    print(minr - maxl + 1)

Verdicts: Wrong Answer

Wrong Answer

Runtime Error

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
nm = [int(i) for i in input().split()]
lr = [[int(i) for i in input().split()] for i in range(nm[1])]


a = [{j for j in range(lr[i][0], lr[0][1]+1)} for i in range(nm[1])]
b = set()
for i in range(len(a)):
    if b == set():
        b = a[i]
    b = b & a[i]
    print(b)
print(len(b))

nm = [int(i) for i in input().split()]
lr = [[int(i) for i in input().split()] for i in range(nm[1])]


a = [{j for j in range(lr[i][0], lr[0][1]+1)} for i in range(nm[1])]
print(a)
b = set()
for i in range(len(a)):
    if b == set():
        b = a[i]
    b = b & a[i]
    print(b)
print(len(b))

nm = [int(i) for i in input().split()]
lr = [[int(i) for i in input().split()] for i in range(nm[1])]

l = [i[0] for i in lr]
r = [i[1] for i in lr]
print(len(range(max(l), min(r)+1)))

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input().split())
lm,mr=0,n
for i in range(m):
  l,r=map(int(input()).split())
  lm=max(lm,l)
  mr=min(mr,r)
  x=mr-lm+1

if x>=0:
  print(x)
else:
  print(0)


n,m=map(int,input().split())
lm,mr=0,n
for i in range(m):
  l,r=map(int(input()))
  lm=max(lm,l)
  mr=min(mr,r)
  x=mr-lm+1

if x>=0:
  print(x)
else:
  print(0)


n,m=map(int,input().split())
l,r=[list(map(int,input().split())) for i in range(m)]

lm=max(l)
mr=min(r)
x=mr-lm+1

if x>=:
  print(x)
else:
  print(0)


n,m=map(int,input().split())
l=[list(map(int,input().split()))[0] for i in range(m)]
r=[list(map(int,input().split()))[1] for i in range(m)]
lm=max(l)
mr=min(r)
x=mr-lm+1

if x>=0:
  print(x)
else:
  print(0)


n,m=map(int,input().split())
l=[list(map(int,input().split()))[0] for i in range(m)]
r=[list(map(int,input().split()))[1] for i in range(m)]
lm=max(l)
mr=min(r)
x=mr-lm+1

if x>=:
  print(x)
else:
  print(0)

n,m=map(int,input().split())
lm,mr=0,n
for i in range(m):
  l,r=map(int,input().split())
  lm=max(lm,l)
  mr=min(mr,r)
  x=mr-lm+1

if x>=0:
  print(x)
else:
  print(0)


Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = list(map(int, input().split()))
a = []
b = [] * M
r = []
for i in range(M):
    x, y = map(int, input().split())
    for j in range(x, y):
        a.append(j)
    b.append(a)
    a = []
for i in range(M - 1):
    r = list(set(b[i]) & set(b[i + 1]))

if M >= 2:
    print(len(r))

else:
    print(len(b[0]) + 1)

N, M = list(map(int, input().split()))
l = []
r = []
for i in range(M):
    x, y = map(int, input().split())
    l.append(x)
    r.append(y)

print(max(l) - min(r) + 1 if l <= r else 0)


N, M = list(map(int, input().split()))
l = 0
r = 10000000
for i in range(M):
    x, y = map(int, input().split())
    l = max(l, x)
    r = min(r, y)

print(r - l + 1 if l <= r else 0)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
def solve():
    maxCards, gates = map(int, input().split())
    gateRanges = [tuple(map(int, input().split())) for i in range(gates)]

    for i, permitRange in enumerate(gateRanges):
        if i == 0:
            activeBegin, activeEnd = permitRange
            continue
        begin, end = permitRange
        if not (begin <= activeEnd and end >= activeBegin):
            print(0)
            break
        else:
            activeBegin, activeEnd = max(activeBegin, begin), min(activeEnd, end)
    else:
        if (maxCards < activeBegin):
            return print(0)
        print(activeBegin, activeEnd)
        ans = min(activeEnd, maxCards) - activeBegin + 1
    print(ans)
solve()

def solve():
    maxCards, gates = map(int, input().split())
    gateRanges = [tuple(map(int, input().split())) for i in range(gates)]

    for i, permitRange in enumerate(gateRanges):
        if i == 0:
            activeBegin, activeEnd = permitRange
            continue
        begin, end = permitRange
        if not (begin <= activeEnd and end >= activeBegin):
            return print(0)
        else:
            activeBegin, activeEnd = max(activeBegin, begin), min(activeEnd, end)
    else:
        if (maxCards < activeBegin):
            return print(0)
        ans = min(activeEnd, maxCards) - activeBegin + 1
    print(ans)
solve()

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, Q = map(int, input().split())
l = [list(map(int, input().split())) for i in range(Q)]

s_ids = []
m_ids = []

for i in range(Q):
    s_ids.append(l[i][0])
    m_ids.append(l[i][1])

max_s_id = max(s_ids)
min_m_id = min(m_ids)

print(max_s_id)
print(min_m_id)

diff = abs(max_s_id - min_m_id)
print(diff+1)


N, Q = map(int, input().split())
l = [list(map(int, input().split())) for i in range(Q)]

s_ids = []
m_ids = []

for i in range(Q):
    s_ids.append(l[i][0])
    m_ids.append(l[i][1])

max_s_id = max(s_ids)
min_m_id = min(m_ids)

# diff = abs(max_s_id - min_m_id)
# print(diff+1)

if max_s_id <= min_m_id:
    print(abs(max_s_id - min_m_id) +1)
else:
    print(0)


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M=map(int,input().split())
l=[list(map(int,input().split())) for i in range(M)]
kyotu=[]

for m in range(M):
  code="name{}=[]".format(m)
  exec(code)

for j in range(M):
  "name{}=range(l[j][0],l[j][1]+1)".format(j)
  codea=print("name{}").format(j)
  exec(codea)
  
  
for k in range(M):
  co="kyotu=set(name{}) & set(name{})".format(k,k+1)
  za="name{}=kyotu".format(k+1)
  exec(co)
  exec(za)
  
  
print(kyotu)

    


N,M=map(int,input().split())
l=[list(map(int,input().split())) for i in range(M)]
maxL=1
minR=N
for j in range(M):
  maxL=max(maxL,l[j][0])
  minR=min(minR,l[j][1])

ans=minR-maxL+1
ans=max(ans,0)
print(ans)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
# import math
# import statistics
# a=input()
#b,c=int(input()),int(input())
# c=[]

#     c.append(i)
e1,e2 = map(int,input().split())
#f = list(map(int,input().split()))
#g = [input() for _ in range(a)]
h = []
for i in range(e2):
    h.append(list(map(int,input().split())))

ans=[]
ha1=[]
ha = [k for i in range(e2) for k in range(1,e1+1) if h[i][0]<=k<=h[i][1]]
sha=sorted(ha)

ma=0
count=1

for i in range(len(sha)-1):
    if sha[i]==sha[i+1]:
        count+=1
    else:
        ma=max(ma,count)
        count=1
ma=max(ma,count)

print(ma//e2)

#     count=0
#     for k in range(e2):
#         if h[k][0]<=i<=h[k][1]:
#             count+=1
#     if count==e2:
#         ans.append(count)

# print(len(ans))
    




# import math
# import statistics
# a=input()
#b,c=int(input()),int(input())
# c=[]

#     c.append(i)
e1,e2 = map(int,input().split())
#f = list(map(int,input().split()))
#g = [input() for _ in range(a)]
h = []
for i in range(e2):
    h.append(list(map(int,input().split())))

ans=[]

for i in range(1,e1+1):
    count=0
    for k in range(e2):
        if h[k][0]<=i<=h[k][1]:
            count+=1
        else:
            print(0)
            break
    if count==e2:
        ans.append(count)

print(len(ans))
    




# import math
# import statistics
# a=input()
#b,c=int(input()),int(input())
# c=[]

#     c.append(i)
e1,e2 = map(int,input().split())
#f = list(map(int,input().split()))
#g = [input() for _ in range(a)]
h = []
for i in range(e2):
    h.append(list(map(int,input().split())))
L=[]
R=[]
for i in range(len(h)):
    L.append(h[i][0])
for i in range(len(h)):
    R.append(h[i][1])

if min(R)>=max(L):
    print(min(R)-max(L)+1)
else:
    print(0)




Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M= map(int,input().split())
LRlis = [list(map(int, input().split())) for i in range(M)]
print(LRlis[0][0])
A = list(range(LRlis[0][0],LRlis[0][1]+1))
for i in range(M):
  B = list(range(LRlis[i][0],LRlis[i][1]+1))
  C = list(set(A) & set(B))

print(len(C))

N,M= map(int,input().split())
LRlis = [list(map(int, input().split())) for i in range(M)]
maxL = 0
minR = 10**5
for i in range(M):
  maxL = max(LRlis[i][0],maxL)
  minR = min(LRlis[i][1],minR)

ans = minR-maxL    
if ans>=0:
  print(ans+1)
else:
  print(0)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input().split())
L=[]
R=[]
for i in range(m):
    l,r=map(int,input().split())
    L[i],R[i]=l,r
print(abs(max(L)-min(R)+1)


n,m=map(int,input().split())
L=[0]*m
R=[0]*m
table=[0]*(n+2)
for i in range(m):
    L[i],R[i]=map(int,input().split())
    table[L[i]]+=1
    table[R[i]+1]-=1
s=[0]*(n+2)
for i in range(1,n+2):
    s[i]=s[i-1]+table[i]
print(s.count(m))


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import copy

n, m = list(map(int, input().split()))

lr = [list(map(int, input().split())) for i in range(m)]
lr.sort()
lr_min = 100000
lr_difference = 0

for i in range(m - 1):
    if max(lr[i]) >= min(lr[i + 1]):
        lr_difference = max(lr[i]) - min(lr[i + 1]) + 1
        print(lr_difference)
        if min(lr[i + 1]) < max(lr[i]):
            lr_difference += min(lr[i + 1]) - max(lr[i])
    else:
        lr_min = 0
        break
    lr_min = min(lr_difference, lr_min)

print(lr_min)


n, m = list(map(int, input().split()))
lr = [list(map(int, input().split())) for i in range(m)]
lr.sort()
lr_min = 100000
lr_difference = 0

for i in range(m - 1):
    if max(lr[0]) >= min(lr[i + 1]):
        lr_difference = max(lr[0]) - min(lr[i + 1]) + 1
        print(lr_difference)
        if max(lr[i + 1]) < max(lr[0]):
            lr_difference += max(lr[i + 1]) - max(lr[0])
    else:
        lr_min = 0
        break
    lr_min = min(lr_difference, lr_min)

print(lr_min)


import copy

n, m = list(map(int, input().split()))

lr = [list(map(int, input().split())) for i in range(m)]
lr_zero = copy.deepcopy(lr)

for i in range(m):
    lr_zero[i][0] = abs(lr[i][0] - lr[0][0])
    lr_zero[i][1] = abs(lr[i][1] - lr[0][0])

lr_zero_min = 100000
lr_zero_difference = 0

for i in range(m - 1):
    if lr_zero[0][1] >= lr_zero[i + 1][0]:
        lr_zero_difference = lr_zero[0][1] - lr_zero[i + 1][0] + 1
        print(lr_zero_difference)
        if lr_zero[i + 1][1] < lr_zero[0][1]:
            lr_zero_difference += lr_zero[i + 1][1] - lr_zero[0][1]
    else:
        lr_zero_min = 0
        break
    lr_zero_min = min(lr_zero_difference, lr_zero_min)

print(lr_zero_min)


import copy

n, m = list(map(int, input().split()))

lr = [list(map(int, input().split())) for i in range(m)]
lr.sort()
print(lr)
lr_min = 100000
lr_difference = 0

for i in range(m - 1):
    if max(lr[i]) >= min(lr[i + 1]):
        lr_difference = max(lr[i]) - min(lr[i + 1]) + 1
        print(lr_difference)
        if min(lr[i + 1]) < max(lr[i]):
            lr_difference += min(lr[i + 1]) - max(lr[i])
    else:
        lr_min = 0
        break
    lr_min = min(lr_difference, lr_min)

print(lr_min)


n, m = list(map(int, input().split()))
lr = [list(map(int, input().split())) for i in range(m)]
lr.sort()
r_min = 100000
l_max = 0
lr_min = 100000

for i in range(m):
    l_max = max(lr[i][0], l_max)
    r_min = min(lr[i][1], r_min)

lr_min = [r_min - l_max + 1 if l_max <= r_min else 0]
print(lr_min[0])


Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
mi = 1
ma = N

for i in range(M):
    if mi < List[i][0]:
        mi = List[i][0]
    if ma > List[i][1]:
        ma = List[i][1]

diff = ma - mi + 1
if diff < 0:
    diff = 0
print("{}".format(diff))

N, M = map(int,input().split())
List = [list(map(int,input().split())) for i in range(M)]

mi = 1
ma = N

for i in range(M):
    if mi < List[i][0]:
        mi = List[i][0]
    if ma > List[i][1]:
        ma = List[i][1]

diff = ma - mi + 1
if diff < 0:
    diff = 0
print("{}".format(diff))

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
li=[list(map(int,input().split())) for i in range(m)]
max_l,min_r=0,10**9

for i in li:
    max_l = max(max_l,li[0])
    min_r = min(min_r,li[1])
print(min_r-max_l+1)

n,m = map(int,input().split())
li=[list(map(int,input().split())) for i in range(m)]
cnt = ()
ans=[]

for j in li:
    cnt.add(set(num for num in range(j[0],j[1]+1)))

ans = cnt[0]
for k in range(len(cnt)-1):
    ans = ans & cnt[k+1]
print(len(ans))


n,m = map(int,input().split())
li=[list(map(int,input().split())) for i in range(m)]
max_l,min_r=0,10**9

for i in li:
    max_l = max(max_l,i[0])
    min_r = min(min_r,i[1])
if min_r >= max_l:
    print(min_r-max_l+1)
else:
  print(0)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())

left = 1
right = N

for i in range(M):
    L, R = map(int, input().split())
    if L > left :
        left = L
    if R < right:
        right = R

print(left-right+1)


N, M = map(int, input().split())

left = 1
right = N

for i in range(M):
    L, R = map(int, input().split())
    if L > left :
        left = L
    if R < right:
        right = R

print(R-L+1)


N, M = map(int, input().split())

left = 1
right = N

for i in range(M):
    L, R = map(int, input().split())
    if L > left :
        left = L
    if R < right:
        right = R
    print("left {} right{}".format(left,right))

if right-left+1 > 0:
    print(right-left+1)
else:
    print(0)


N, M = map(int, input().split())

left = 1
right = N

for i in range(M):
    L, R = map(int, input().split())
    if L > left :
        left = L
    if R < right:
        right = R

if right-left+1 > 0:
    print(right-left+1)
else:
    print(0)


Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
L = 0
R = 100000
for i in range(M):
  Li, Ri = map(int, input().split())
  if Li > L:
    L = Li
  if Ri < R:
    R = Ri
print(L - R + 1)

N, M = map(int, input().split())
L = 1
R = N
for i in range(M):
  Li, Ri = map(int, input().split())
  if Li > L:
    L = Li
  if Ri < R:
    R = Ri
print(L - R + 1)


N, M = map(int, input().split())
L = 1
R = N
for i in range(M):
  Li, Ri = map(int, input().split())
  if Li > L:
    L = Li
  if Ri < R:
    R = Ri
if L <= R:
  print(R - L + 1)
else:
  print(0)


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())

L, R = map(int, input().split())
ans = set(range(L, R + 1))

for i in range(1, M):
    L, R = map(int, input().split())
    ans -= set(range(L, R + 1))

print(len(ans))

N, M = map(int, input().split())

L = []
R = []

for i in range(M):
    l, r = map(int, input().split())
    L.append(l)
    R.append(r)

print(max(min(R) - max(L) + 1, 0))

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M - map(int, input())
gate_l = [[int(x) for x in input().split()] for _ in range(M)]

min_card = max(l[0] for l in gate_l)
max_card = min(l[1] for l in gate_l)

print(max_card - min_card +1)

N,M - map(int, input())
gate_l = [[int(x) for x in input().split()] for _ in range(M)]

min_card = max(l[0] for l in gate_l)
max_card = min(l[1] for l in gate_l)

if max_card > min_card:
    print(max_card - min_card +1)
    
else:
    print(0)

N,M = map(int, input().split())
gate_l = [[int(x) for x in input().split()] for _ in range(M)]

min_card = max(l[0] for l in gate_l)
max_card = min(l[1] for l in gate_l)

if max_card >= min_card:
    print(max_card - min_card +1)
    
else:
    print(0)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import sys
from sys import stdin
import numpy as np

N, M = map(int, input().split())
L, R = list(), list()
for i in range(M):
  l,r = map(int, input().split())
  L.append(int(l))
  R.append(int(r))

inputs = np.vstack((L, R)).T
  
count = 0
for i in range(1, N+1):
  out = (inputs[:, 0] >= i) & (inputs[:, 1] <= i)
  if out.all():
    count += 1
  
print(count)

import sys
from sys import stdin
import numpy as np

N, M = map(int, input().split())
L, R = list(), list()
for i in range(M):
  l,r = stdin.readline().rstrip().split()
  L.append(int(l))
  R.append(int(r))

inputs = np.vstack((L, R)).T
  
count = 0
for i in range(1, N+1):
  out = (inputs[:, 0] >= i) & (inputs[:, 1] <= i)
  if out.all():
    count += 0
  
print(count)
  

import sys
from sys import stdin
import numpy as np

N, M = map(int, input().split())
L, R - list(), list()
for i in range(M):
  l,r = stdin.readline().rstrip().split()
  L.append(int(l))
  R.append(int(r))

inputs = np.vstack(L, R).T
  
count = 0
for i in range(1, N+1):
  out = (inputs[:, 0] >= i) & (inputs[:, 1] <= i)
  if out.all():
    count += 0
  
print(count)
  

import sys
from sys import stdin
import numpy as np

N, M = map(int, input().split())
L, R = list(), list()
for i in range(M):
  l,r = stdin.readline().rstrip().split()
  L.append(int(l))
  R.append(int(r))

L = np.array(L)
R = np.array(R)

if R.min() - L.max() < 0:
  print(0)
else:
  print(R.min() - L.max() + 1)
  


Verdicts: Wrong Answer

Wrong Answer

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
l, r = [], []

for _ in range(m):
    s, t = map(int, input().split())
    l.append(s)
    r.append(t)

ans = min(r) - max(s) + 1
print(ans)

n, m = map(int, input().split())
l, r = [], []

for _ in range(m):
    s, t = map(int, input().split())
    l.append(int(s))
    r.append(int(t))

ans = min(r) - max(l) + 1 if min(r) >= max(l) else 0
print(ans)


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import numpy as np
N, M = [int(i) for i in input().split()]

gate = np.zeros(N+1)
for i in range(0, M):
    L, R = [int(j) for j in input().split()]
    gate[L-1] += 1
    gate[R] -=1

count = 0
for i in range(1, len(gate)):
    gate[i] = gate[i] + gate[i-1]

for i in range(0, M):
    if gate[i] == M:
        count += 1

print(count)

import numpy as np
N, M = [int(i) for i in input().split()]

gate = np.zeros(N+1)
for i in range(0, M):
    L, R = [int(j) for j in input().split()]
    gate[L-1] += 1
    gate[R] -=1

count = 0
for i in range(1, len(gate)):
    gate[i] = gate[i] + gate[i-1]
    if gate[i] == M:
        count += 1

if gate[0] == M:
    count += 1
print(count)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
L = [0] * M
R = [0] * M
min = 1
max = N
X = 0
for i in range(M):
    L[i], R[i] = map(int, input().split())
    if L[i] > min:
        min = L[i]
    if R[i] < max:
        max = R[i]
    if R[i] < min or L[i] > max:
        X +=1


if X = 0:
    print(max-min+1)
else:
    print(0)


N, M = map(int, input().split())
L = [0] * M
R = [0] * M
min = 1
max = N
X = 0
for i in range(M):
    L[i], R[i] = map(int, input().split())
    if L[i] > min:
        min = L[i]
    if R[i] < max:
        max = R[i]
    if R[i] < min or L[i] > max:
        X +=1


if X == 0:
    print(max-min+1)
else:
    print(0)


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import sys
input = sys.stdin.readline

n, m = map(int, input().split())
a = sorted(list(map(int, input().split())))
bc = sorted([list(map(int, input().split())) for i in range(m)], key = itemgetter(1), reverse=True)

ans = 0
for i in range(n):
    now = a[i]
    for rep, con in enumerate(bc):
        if now < con[1] and bc[rep][0] != 0:
            ans += con[1]
            bc[rep][0] -= 1
            break

    else:
        ans += now + sum(a[i+1:])
        break

print(ans)

n, m = map(int, input().split())
lr = [list(map(int, input().split())) for i in range(m)]

max_l = float("-inf")
min_r = float("inf")

for l, r in lr:
    max_l = max(max_l, l)
    min_r = min(min_r, r + 1)

ans = min_r-max_l
print("0" if ans <= 0 else ans if ans < n else n)


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
l = [0]*m
r = [0]*m
for i in range(m):
    l[i],r[i] = map(int,input().split())
if min(r)-max(l) < 0:
    print(0)
else:
    print(min(r)-max(l))

n,m = map(int,input().split())
l = [0]*m
r = [0]*m
for i in range(m):
    l[i],r[i] = map(int,input().split())
if min(r)-max(l)<0:
    print(0)
else:
    print(min(r)-max(l)+1

n,m = map(int,input().split())
l = [0]*m
r = [0]*m
for i in range(m):
    l[i],r[i] = map(int,input().split())
if min(r)-max(l) < 0:
    print(0)
else:
    print(min(r)-max(l)+1)

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int, input().split())
left = 0
right = 10**5
for _ in range(m):
    l,r = map(int,input().split())
    left = max(left, l)
    right = min(right,r)
print(r-l+1)

n,m = map(int, input().split())
left = 0
right = 10**5
for _ in range(m):
    l,r = map(int,input().split())
    left = max(left, l)
    right = min(right,r)
print(max(0,right-left+1))


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):

n, m = map(int, input().split())
card = [0 for _ in range(n+2)]

for _ in range(m):
    l, r = map(int, input().split())
    card[l] += 1
    card[r+1] -= 1

#print(card)

for i in range(n+1):
    card[i+1] += card[i]

#print(card)
print(card.count(3))



n, m = map(int, input().split())
card = [0 for _ in range(n+2)]

for _ in range(m):
    l, r = map(int, input().split())
    card[l] += 1
    card[r+1] -= 1

#print(card)

for i in range(n+1):
    card[i+1] += card[i]

#print(card)
print(card.count(m))


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input())

l=-1
r=10**6

for _ in range(m):
  il, ir=map(int,input())
  l=max(l,il)
  r=min(r,ir)
  
print(r-l+1)

n,m=map(int,input())
 
l=-1
r=10**6
 
for _ in range(m):
  il, ir=map(int,input())
  l=max(l,il)
  r=min(r,ir)
  
print(max(0,r-l+1))

n,m=map(int,input().split())
 
l=-1
r=10**6
 
for _ in range(m):
  il, ir=map(int,input().split())
  l=max(l,il)
  r=min(r,ir)
  
print(max(0,r-l+1))

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = list(map(int, input().split()))
high=10**10
low=0
for i in range(m):
    a,b = list(map(int, input().split()))
    if a>low:
        low=a
    if b<high:
        kigk=b
print(high-low+1)

n,m = list(map(int, input().split()))
high=10**10
low=0
for i in range(m):
    a,b = list(map(int, input().split()))
    if a>low:
        low=a
    if b<high:
        high=b
if low>high:
    print(0)
else:
    print(high-low+1)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M= list(map(int,input().split()))
end = []
start = []
for i in range(M):
    A,B = list(map(int,input().split()))
    end.append(B)
    start.append(A)
end_min = min(end)
start_max = max(start)
if start_max => end_min:
    print(0)
else:
    print(end_min-start_end+1)

N,M= list(map(int,input().split()))
end = []
start = []
for i in range(M):
    A,B = list(map(int,input().split()))
    end.append(B)
    start.append(A)
end_min = min(end)
start_max = max(start)
if start_max >= end_min:
    print(0)
else:
    print(end_min-start_end+1)

N,M= list(map(int,input().split()))
end = []
start = []
for i in range(M):
    A,B = list(map(int,input().split()))
    end.append(B)
    start.append(A)
end_min = min(end)
start_max = max(start)
if start_max > end_min:
    print(0)
else:
    print(end_min-start_max+1)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M = map(int, input().split())
L = []
R = []
for _ in range(M):
  l,r = map(int, input().split())
  L.append(l)
  R.append(r)

if min(R) <= max(L):
  print(min(R)-max(L)+1)
else:
  print(0)

n,m = map(int, input().split())
x = []
y = []
for _ in range(m):
  l,r = map(int, input().split())
  x.append(l)
  y.append(r)
x = max(x)
y = min(y)

if y-x >= 0: print(y-x+1)
else: print(0)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import sys
N, M = map(int, sys.stdin.readline().split())
LR = [list(map(int,sys.stdin.readline().split())) for i in range(N)]
B = list(range(0, 10 ** 5 + 1))
for i in LR:
	A = list(range(i[0], i[1]))
	B = set(A) & set(B)
print(len(B))

import sys
N, M = map(int, sys.stdin.readline().split())
LR = sorted([list(map(int,sys.stdin.readline().split())) for i in range(M)])
L = 1
R = 10 ** 5
for i in LR:
    L = max(L, i[0])
    R = min(R, i[1])
if R - L >= 0:
    print(R - L + 1)
else:
    print(0)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int,input().split())
L = []
R = []
for i in range(M):
    tmp_L, tmp_R = input().split()
    L.append(tmp_L)
    R.append(tmp_R)

left = max(L)
right = min(R)

if right - left < 0:
    print(0)
else:
    print(right - left + 1)

N, M = map(int,input().split())
L = []
R = []
for i in range(M):
    tmp_L, tmp_R = map(int,input().split())
    L.append(tmp_L)
    R.append(tmp_R)

left = max(L)
right = min(R)

if right - left < 0:
    print(0)
else:
    print(right - left + 1)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
L = []
R = []
ans = 0
for _ in range(M):
    inp = int(input().split())
    L.append(inp[0])
    R.append(inp[1])
for i in range(N):
    if L[i] < i + 1 <R[i]:
        ans += 1
print(ans)

N, M = map(int, input().split())
L = 0
R = N
for _ in range(M):
    inp = input().split()
    l = int(inp[0])
    r = int(inp[1])
    L = max(L,l)
    R = min(R,r)
print(max(0,R + 1 - L))

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M=map(int,input().split())
L=[]
R=[]
for _ in range(M):
  l,r=map(int,input().split())
  L.append(l)
  R.append(r+1)
L.sort()
R.sort()
ans=L[-1]-R[0]
print(0 if ans<0 else ans)

N,M=map(int,input().split())
L=[]
R=[]
for _ in range(M):
  l,r=map(int,input().split())
  L.append(l)
  R.append(r+1)
L.sort()
R.sort()
ans=R[0]-L[-1]
print(0 if ans<0 else ans)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
l,r = 1,n
for i in range(m):
  L,R = map(int,input().split())
  L = max(l,L)
  R = min(r,R)
print(max(0,L-R+1))

n,m = map(int,input().split())
l,r = 1,N
for i in range(m):
  L,R = map(int,input().split())
  L = max(l,L)
  R = min(r,R)
print(max(0,L-R+1))

n,m = map(int,input().split())
l,r = 1,n
for i in range(m):
  L,R = map(int,input().split())
  L = max(l,L)
  R = min(r,R)
print(max(0,R-L+1))

n,m = map(int,input().split())
l,r = 1,n
for i in range(m):
  L,R = map(int,input().split())
  l = max(l,L)
  r = min(r,R)
print(max(0,r-l+1))

Verdicts: Wrong Answer

Runtime Error

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
li,lia = [],[]
for i in range(m):
    a,b = map(int,input().split())
    li.append(a)
    lia.append(b)
print(min(min(lia)-max(li)+1),0)

n,m = map(int,input().split())
li,lia = [],[]
for i in range(m):
    a,b = map(int,input().split())
    li.append(a)
    lia.append(b)
if min(lia)-max(li)+1 <= 0:
    print(0)
else:
    print(min(lia)-max(li)+1)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input().split())
L=[]
R=[]
for i in range(m):
    l,r=map(int,input().split())
    L.append(l)
    R.append(r)
if max(L)>min(R):
    print(0)
else:
    print(min(R)-min(L)+1)

n,m=map(int,input().split())
L=[]
R=[]
for i in range(m):
    l,r=map(int,input().split())
    L.append(l)
    R.append(r)
if max(L)>min(R):
    print(0)
else:
    print(min(R)-max(L)+1)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input().split())
for i in range(m):
  l,r=list(map(int,input().split()))
ans=0
dif=max(l)-min(r)
if(diff>=0):
  ans=diff+1
else:
  ans=0


minlist=[]
maxlist=[]

n,m=map(int,input().split())
for i in range(m):
  l,r=list(map(int,input().split()))
  minlist.append(l)
  if r>0:
    maxlist.append(r)
ans=0
dif=max(linlist)-min(maxlist)
if(diff>=0):
  ans=diff+1
else:
  ans=0
print(ans)

minlist=[]
maxlist=[]
 
n,m=map(int,input().split())
for i in range(m):
  l,r=list(map(int,input().split()))
  minlist.append(l)
  if r>0:
    maxlist.append(r)
ans=0
dif=max(minlist)-min(maxlist)
if(dif>=0):
  ans=dif+1
else:
  ans=0
print(ans)

n,m=map(int,input().split())
for i in range(m):
  l,r=list(map(int,input().split()))
ans=0
dif=max(l)-min(r)
if(diff>=0):
  ans=diff+1
else:
  ans=0
print(ans)

n,m=map(int,input().split())
for i in range(m):
  l,r=list(map(int,input().split()))
  minlist.append(l)
  if r>0:
    maxlist.append(r)
ans=0
dif=max(linlist)-min(maxlist)
if(diff>=0):
  ans=diff+1
else:
  ans=0
print(ans)

minlist=[]
maxlist=[]

n,m=map(int,input().split())
for i in range(m):
  l,r=list(map(int,input().split()))
  minlist.append(l)
  if r>0:
    maxlist.append(r)
ans=0
dif=max(minlist)-min(maxlist)
if(diff>=0):
  ans=diff+1
else:
  ans=0
print(ans)

minlist=[]
maxlist=[]
 
n,m=map(int,input().split())
for i in range(m):
  l,r=list(map(int,input().split()))
  minlist.append(l)
  if r>0:
    maxlist.append(r)
ans=0
dif=min(maxlist)-max(minlist)
if(dif>=0):
  ans=dif+1
else:
  ans=0
print(ans)

Verdicts: Runtime Error

Runtime Error

Wrong Answer

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split)
List = [map(int,input().split()) for i in range(M)]
count = 0

for i in range(N):
  if i+1 >= List[2*i] & i+1 <= List[2*i+1]:
    count = count + 1
print(count)

N, M = map(int, input().split)
List = [list(map(int,input().split())) for i in range(M)]

count = 0
for i in range(N):
  if i+1 >= List[i][0] & i+1 <= List[i][1]:
    count = count + 1

print(count)

N, M = map(int, input().split)
List_LR = [list(map(int,input().split())) for i in range(M)]
L = [List_LR[i][0] for i in range(len(List_LR))]
R = [List_LR[i][1] for i in range(len(List_LR))]

L_max = max(L)
R_min = min(R)

ans = R_min - L_max +1
print(ans)

N, M = int(int, input().split)
List = [map(int,input().split()) for i in range(M)]
count = 0
for i in range(N):
  if i+1 >= List[2*i] & i+1 <= List[2*i+1]:
    count = count + 1
  else:
    continue

print(count)

N, M = map(int, input().split())
List_LR = [list(map(int,input().split())) for i in range(M)]
L = [List_LR[i][0] for i in range(len(List_LR))]
R = [List_LR[i][1] for i in range(len(List_LR))]
 
L_max = max(L)
R_min = min(R)

ans = R_min - L_max +1
if ans < 0 : ans = 0
print(ans)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):

using namespace std;

int main()
{
	int n, m;
	cin >> n >> m;
	int a = 0;
	int b = n;
	for (int i = 0; i < m; i++){
		int l, r;
		cin >> l >> r;
		a = max(a, l);
		b = min(b, r);
	}

	cout << (a <= b ? b-a+1 : 0) << endl;
}


n, m = map(int, input().split())
a, b = 0, n;
for i in range(m):
	l, r = map(int, input().split())
	a, b = max(a, l), min(b, r)

print(b-a+1 if a <= b else 0)

Verdicts: Runtime Error

Accepted