Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
# B - Bingo
import itertools
A = list()
for o in range(3):
    a = list(map(int, input().split()))
    A.append(a)
N = int(input())
b = list(int(input()) for p in range(N))

bingo = [[A[0],A[1],A[2]],[A[0][0],A[1][0],A[2][0]],[A[1][0],A[1][1],A[2][1]],[A[2][0],A[2][1],A[2][2]],[A[0][0],A[1][1],A[2][2]],[A[0][2],A[1][1],A[2][0]]]
print(bingo)

B_perm = []    
B = itertools.permutations(b,3)
for i in B:
    B_perm.append(list(i))
    
result = 'No'
for j in range(len(B_perm)):
    if B_perm[j] in bingo: 
        result = 'Yes'

print(result)

# B - Bingo
import itertools
A = list()
for o in range(3):
    a = list(map(int, input().split()))
    A.append(a)
N = int(input())
b = list(int(input()) for p in range(N))

bingo = [A[0],A[1],A[2],[A[0][0],A[1][0],A[2][0]],[A[1][0],A[1][1],A[2][1]],[A[2][0],A[2][1],A[2][2]],[A[0][0],A[1][1],A[2][2]],[A[0][2],A[1][1],A[2][0]]]

B_perm = []    
B = itertools.permutations(b,3)
for i in B:
    B_perm.append(list(i))
print(B_perm)
    
result = 'No'
for j in range(len(B_perm)):
    if B_perm[j] in bingo: 
        result = 'Yes'

print(result)

# B - Bingo
import itertools
A = list()
for o in range(3):
    a = list(map(int, input().split()))
    A.append(a)
N = int(input())
b = list(int(input()) for p in range(N))

bingo = [A[0],A[1],A[2],[A[0][0],A[1][0],A[2][0]],[A[1][0],A[1][1],A[1][2]],[A[2][0],A[2][1],A[2][2]],[A[0][0],A[1][1],A[2][2]],[A[0][2],A[1][2],A[2][2]],[A[0][2],A[1][1],A[2][0]]]

B_perm = []    
B = itertools.permutations(b,3)
for i in B:
    B_perm.append(list(i))
    
result = 'No'
for j in range(len(B_perm)):
    if B_perm[j] in bingo: 
        result = 'Yes'
        print('yes',B_perm[j])

print(result)

# B - Bingo
import itertools
A = list()
for o in range(3):
    a = list(map(int, input().split()))
    A.append(a)
N = int(input())
b = list(int(input()) for p in range(N))

bingo = [A[0],A[1],A[2],[A[0][0],A[1][0],A[2][0]],[A[0][1],A[1][1],A[2][1]],[A[0][0],A[1][1],A[2][2]],[A[0][2],A[1][2],A[2][2]],[A[0][2],A[1][1],A[2][0]]]

B_perm = []    
B = itertools.permutations(b,3)
for i in B:
    B_perm.append(list(i))
    
result = 'No'
for j in range(len(B_perm)):
    if B_perm[j] in bingo: 
        result = 'Yes'
        print('yes',B_perm[j])

print(result)

# B - Bingo
import itertools
A = list()
for o in range(3):
    a = list(map(int, input().split()))
    A.append(a)
N = int(input())
b = list(int(input()) for p in range(N))

bingo = [A[0],A[1],A[2],[A[0][0],A[1][0],A[2][0]],[A[0][1],A[1][1],A[2][1]],[A[0][0],A[1][1],A[2][2]],[A[0][2],A[1][2],A[2][2]],[A[0][2],A[1][1],A[2][0]]]

B_perm = []    
B = itertools.permutations(b,3)
for i in B:
    B_perm.append(list(i))

result = 'No'
for j in range(len(B_perm)):
    if B_perm[j] in bingo: 
        result = 'Yes'

print(result)

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Accepted