TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
def b(n): 
    if n == 0:
        return("P")
    else:
        return("B",b(n-1),"P",b(n-1),"B")
n, x= map(int, input().split())
print(b(n).split("", x).count("P"))


n, x = map(int, input().split())
def patty(L):

    p = 1
    for i in range(L):
        p = 2 * p + 1
    return (p)
def vol(L):

    m = 1
    for i in range(L):
        m  = m * 2 + 3
    return (m)
def eated(L, X):

    if L == 0:
        return 1
    m = vol(L)
    if X == 1 or X == 0:
        
        return 0
    elif X == (m + 1) / 2:
        
        
        return patty(L-1) + 1
    elif X < (m + 1) / 2:
        
        
        return eated(L-1, X-1)
    else:
        
        
        return patty(L) - eated(L, m - X)
print(eated(n, x))

Verdicts: Runtime Error

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
def make(n,x):
    if n==0:
        return 1
    elif x==1:
        return 0
    elif x>=b_memo[n-1]+1:
        return p_memo[n-1]+1+make(n-1,x-b_memo[n-1]-2)
    elif x<b_memo[n-1]+1:
        return make(n-1,x-1)
  
n,k=map(int,input().split())
b_memo=[0]*51
p_memo=[0]*51
b_memo[0]=1
p_memo[0]=1
for i in range(50):
    b_memo[i+1]=2*b_memo[i]+3
for i in range(50):
    p_memo[i+1]=2*p_memo[i]+1

print(make(n,k))

def f(n,x):
    if n==0:
        return 1
    elif x==1:
        return 0
    elif x==b_memo[n]//2+1:
        return p_memo[n-1]+1
    elif x<=b_memo[n]//2:
        return f(n-1,x-1)
    else:
        return 1+p_memo[n-1]+f(n-1,x-b_memo[n-1]-2)

n,x=map(int,input().split())

b_memo=[0]*51
p_memo=[0]*51
b_memo[0]=1
p_memo[0]=1

for i in range(50):
    b_memo[i+1]=b_memo[i]*2+3
    p_memo[i+1]=p_memo[i]*2+1
    
print(f(n,x))

Verdicts: Wrong Answer

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
N, X = map(int, input().split())

a, p = [1], [1]

for i in range(N):
	a.append(a[i] * 2 + 3)
	p.append(p[i] * 2 + 1)

def f(N, X):
	if N == 0:
		return 0 if X <= 0 else 1
	elif X <= 1 + a[N+1]:
		return f(N-1, X-1)
	else:
		return p[N-1] + 1 + f(N-1, X-2-a[N-1])

print(f(N, X))

N, X = map(int, input().split())

a, p = [1], [1]

for i in range(N):
	a.append(a[i] * 2 + 3)
	p.append(p[i] * 2 + 1)

def f(N, X):
	if N == 0:
		return 0 if X <= 0 else 1
	elif X <= 1 + a[N-1]:
		return f(N-1, X-1)
	else:
		return p[N-1] + 1 + f(N-1, X-2-a[N-1])

print(f(N, X))

Verdicts: Runtime Error

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):

ans = 0
def count_ans(level, index, len_dic, p_dic):
    global ans

    if level == 0:
        if index == 0:
            ans += 1
    elif index == 0:
        pass
    else:
        if index == len_dic[level - 1] // 2 + 1:
            ans += 1
            ans += p_dic[level - 1]
        elif index > len_dic[level] // 2 + 1:
            ans += p_dic[level - 1] + 1
            index_next = index - len_dic[level - 1] - 2
            count_ans(level - 1, index_next, len_dic, p_dic)
        else:
            index_next = index - 1
            count_ans(level - 1, index_next, len_dic, p_dic)


def get_len_dic(level):
    len_dic = [1]
    for i in range(level):
        len_dic.append(len_dic[-1] * 2 + 3)
    return len_dic

def get_p_dic(level):
    p_dic = [1]
    for i in range(level - 1):
        p_dic.append(p_dic[-1] * 2 + 1)
    return p_dic

def main():
    global ans
    level, eat_num = map(int, input().split())
    len_dic = get_len_dic(level)
    p_dic = get_p_dic(level)
    count_ans(level, eat_num, len_dic, p_dic)
    print(ans)





if __name__ == '__main__':
    main()


ans = 0
def count_ans(level, index, len_dic, p_dic):
    global ans
    if level == 0:
        ans += 1
    else:
        if index == 0:
            pass
        elif index == len_dic[level] // 2:
            ans += 1
            ans += p_dic[level - 1]
        elif index == len_dic[level] - 1:
            ans += p_dic[level]
        elif index > len_dic[level] // 2:
            ans += p_dic[level - 1] + 1
            index_next = index - len_dic[level - 1] - 2
            count_ans(level - 1, index_next, len_dic, p_dic)
        else:
            index_next = index - 1
            count_ans(level - 1, index_next, len_dic, p_dic)


def get_len_dic(level):
    len_dic = [1]
    for i in range(level):
        len_dic.append(len_dic[-1] * 2 + 3)
    return len_dic

def get_p_dic(level):
    p_dic = [1]
    for i in range(level):
        p_dic.append(p_dic[-1] * 2 + 1)
    return p_dic

def main():
    global ans
    level, eat_num = map(int, input().split())
    len_dic = get_len_dic(level)
    p_dic = get_p_dic(level)
    count_ans(level, eat_num - 1, len_dic, p_dic)
    print(ans)


if __name__ == '__main__':
    main()

Verdicts: Wrong Answer

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
def eat(L,X):
    if L == 0: return 1
    if X == 1: return 0
    elif X <= len_burger(L-1)+1: return eat(L-1,X-1)
    elif X == len_burger(L-1)+2: return num_ban(L-1)+1
    elif X < 2*len_burger(L-1)+3: return num_ban(L-1)+1+eat(L-1,X-len_burger(L-1)-2)
    elif X == len_burger(L): return num_ban(L)

def solve():
    N,X = [int(s) for s in input().split() if s]
    
    print(eat(N,X))

solve()

def len_burger(L):
    return 2**(L+2)-3
def num_ban(L):
    return 2**(L+1)-1

def eat(L,X):
    if L == 0: return 1
    if X == 1: return 0
    elif X <= len_burger(L-1)+1: return eat(L-1,X-1)
    elif X == len_burger(L-1)+2: return num_ban(L-1)+1
    elif X < 2*len_burger(L-1)+3: return num_ban(L-1)+1+eat(L-1,X-len_burger(L-1)-2)
    elif X == len_burger(L): return num_ban(L)

def solve():
    N,X = [int(s) for s in input().split() if s]
    
    print(eat(N,X))
    
solve()

Verdicts: Runtime Error

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
#!/usr/bin/env python
# -*- coding: utf-8 -*-

al = [0, 5] + [0] * 49
bl = [0, 3] + [0] * 49


def solve2(ans, x, idx, cnt):
    print(ans, x, idx)
    if idx == 1:
        return ans + (0, 0, 1, 2, 3, 3, 3)[x] + [0, 1][cnt >= 1]
    if x == (al[idx] // 2) + 1:
        return ans + bl[idx - 1] + 1 + [0, 1][cnt >= 1]
    elif x > (al[idx] // 2) + 1:
        ans += bl[idx - 1]
        x -= (al[idx] // 2)
        cnt += 1
    return solve2(ans, x, idx - 1, cnt)


def solve():
    n, x = map(int, input().split())
    for i in range(2, n + 1):
        al[i] = al[i - 1] * 2 + 3
        bl[i] = bl[i - 1] * 2 + 1
    ans = solve2(0, x, n, 0)
    print(ans)


if __name__ == "__main__":
    solve()


#!/usr/bin/env python
# -*- coding: utf-8 -*-

al = [0, 5] + [0] * 49
bl = [0, 3] + [0] * 49


def solve2(ans, x, idx):
    if idx == 1:
        if x >= 5:
            return ans + 3
        if x <= 0:
            return ans
        return ans + (0, 0, 1, 2, 3, 3)[x]
    if x >= al[idx - 1] + 1:
        ans += bl[idx - 1]
        x -= al[idx - 1] + 1
        if x >= 1:
            ans += 1
            x -= 1
    else:
        x -= 1
    return solve2(ans, x, idx - 1)


def solve():
    n, x = map(int, input().split())
    for i in range(2, n + 1):
        al[i] = al[i - 1] * 2 + 3
        bl[i] = bl[i - 1] * 2 + 1
    print(solve2(0, x, n))


if __name__ == "__main__":
    solve()


Verdicts: Runtime Error

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
N, K = map(int, input().split())
S = [tuple(map(int, input().split())) for _ in range(N)]

S.sort(key=lambda x: -x[1])
st = set()
first_acc, other_acc = [0], [0]
for t, d in S:
  if t in st:
    other_acc.append(other_acc[-1] + d)
  else:
    st.add(t)
    first_acc.append(first_acc[-1] + d)

ans = 0
for i in range(K + 1):
  if len(first_acc) <= i or len(other_acc) <= K - i:
    continue
  ans = max(ans, first_acc[i] + other_acc[K - i] + i * i)

print(ans)

N, X = map(int, input().split())
a,p=[1],[1]
for i in range(N):
  a.append(a[i] * 2 + 3) 
  p.append(p[i] * 2 + 1)

def f(N,X):
  if N == 0:
    return 0 if X <= 0 else 1 
  elif X <= 1 + a[N-1]:
    return f(N-1, X-1) 
  else:
    return p[N-1] + 1 + f(N-1, X-2-a[N-1])

print(f(N, X))

Verdicts: Runtime Error

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
n,k=map(int,input().split())
burger=[None]*n
burger[0]="P"
for i in range(1,n):
  burger[i]="B"+burger[i-1]+"P"+burger[i-1]+"B"
print(sum(1 for i in burger[-1][:k] if i=="P"))

n,x=map(int,input().split())
length=[0]*n;p=[0]*n
length[0]=1
p[0]=1
for i in range(1,n):
  length[i]=length[i-1]*2+3
  p[i]=p[i-1]*2+1
def meat(n,x):
  if n==0:
    return 0 if x<=0 else 1
  elif x<=1+length[n-1]:
    return meat(n-1,x-1)
  elif x==2+length[n-1]:
    return p[n-1]+1
  else:
    return p[n-1]+1+meat(n-1,x-length[n-1]-2)
print(meat(n,x))


Verdicts: Runtime Error

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
n, x = map(int, input().split())
l = ["P"]
def lvup(n):
  if n == 0:
    pass
  else:
    lvup(n-1)
    l.append("B"+l[n-1]+"P"+l[n-1]+"B")
print(l[n][0:x].count("P"))

n, x = map(int, input().split())
 
def count_p(n, x):
  if n == 0:
    return x
  elif x > 2**(n+1)-2:
    return 2**(n)-1 + 1 + count_p(n-1, min(x-(2**(n+1)-1), 2**(n+1)-3))
  else:
    return count_p(n-1, x-1)
  
print(count_p(n,x))

n, x = map(int, input().split())

def count_p(n, x):
  if x == 0:
    return 0
  elif n == 0:
    return 1
  elif x > 2**(n+1)-2:
    return 2**(n)-1 + 1 + count_p(n-1, min(x-(2**(n+1)-1), 2**(n+1)-3))
  else:
    return count_p(n-1, x-1)
  
print(count_p(n,x))


Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
n,x=map(int,input().split())
p=[1]
a=[1]
for i in range(0,n-1):
  p.append(p[i]*2+1)
  a.append(a[i]*2+3)
def f(n,x):
  if x==1:
    return 0
  elif x<=1+a[n-1]:
    return f(n-1,x-1)
  else:
    return p[n-1]+f(n-1,x-a[n-1]-2)+1
print(f(n,x))

n,x=map(int,input().split())
p=[1]
a=[1]
for i in range(0,n):
  p.append(p[i]*2+1)
  a.append(a[i]*2+3)
def f(n,x):
  if n==0 and x<=0:
    return 0
  elif n==0:
    return 1
  elif x<=1+a[n-1]:
    return f(n-1,x-1)
  else:
    return p[n-1]+f(n-1,x-a[n-1]-2)+1
print(f(n,x))

Verdicts: Runtime Error

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
import sys
stdin = sys.stdin
 
sys.setrecursionlimit(10**5) 
 
def li(): return map(int, stdin.readline().split())
def li_(): return map(lambda x: int(x)-1, stdin.readline().split())
def lf(): return map(float, stdin.readline().split())
def ls(): return stdin.readline().split()
def ns(): return stdin.readline().rstrip()
def lc(): return list(ns())
def ni(): return int(stdin.readline())
def nf(): return float(stdin.readline())

n,x = li()
ln = [1]
for i in range(n):
    ln.append(3+2*ln[-1])

st = 0
ed = ln[n]-1

ans = 0
while True:
    half = st + (ed-st)//2
    
    if x == half:
        ans += ((half-st)//2 + 1)
        break
        
    elif x < half:
        st += 1
        ed = half-1
        
    else:
        ans += ((half-st)//2 + 1)
        st = half+1
        ed -= 1
        
print(ans)

import sys
stdin = sys.stdin

sys.setrecursionlimit(10 ** 7)

def li(): return map(int, stdin.readline().split())
def li_(): return map(lambda x: int(x) - 1, stdin.readline().split())
def lf(): return map(float, stdin.readline().split())
def ls(): return stdin.readline().split()
def ns(): return stdin.readline().rstrip()
def lc(): return list(ns())
def ni(): return int(stdin.readline())
def nf(): return float(stdin.readline())


def rec(n: int, x: int, a: list, p: list) -> int:
    if x <= 0:
        raise ValueError

    elif n == 0:
        return 1

    elif x == 1:
        return 0

    elif 1 < x < a[n-1] + 2:
        return rec(n-1, x-1, a, p)

    elif x == a[n-1] + 2:
        return p[n-1] + 1

    elif a[n-1] + 2 < x < 2*a[n-1] + 3:
        return p[n-1] + 1 + rec(n-1, x - a[n-1] - 2, a, p)

    elif x == 2*a[n-1] + 3:
        return 2 * p[n-1] + 1

n,x = li()
a = [1]
p = [1]

for i in range(n):
    a.append(2*a[-1]+3)
    p.append(2*p[-1]+1)

print(rec(n, x, a, p))

Verdicts: Wrong Answer

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
def PAndB(n):
    return (2 ** (n + 2)) - 3


def allPatty(n):
    return (2 ** (n + 1)) - 1


def count(N, X):
    if N == 0:
        return 1
    elif X <= N:
        return 0
    elif X >= PAndB(N) - (N - 1):
        return allPatty(N)
    elif X == PAndB(N - 1) + 2:
        print('center')
        return allPatty(N - 1) + 1
    elif X <= PAndB(N - 1) + 1:
        return count(N - 1, X - 1)
    else:
        return allPatty(N - 1) + 1 + count(N - 1, X - (PAndB(N - 1) + 2))


def main():
    N, X = map(int, input().split())
    print(count(N, X))


if __name__ == '__main__':
    main()

def PAndB(n):
    return (2 ** (n + 2)) - 3


def allPatty(n):
    return (2 ** (n + 1)) - 1


def count(N, X):
    if N == 0:
        return 1
    elif X <= N:
        return 0
    elif X >= PAndB(N) - (N - 1):
        return allPatty(N)
    elif X == PAndB(N - 1) + 2:
        return allPatty(N - 1) + 1
    elif X <= PAndB(N - 1) + 1:
        return count(N - 1, X - 1)
    else:
        return allPatty(N - 1) + 1 + count(N - 1, X - (PAndB(N - 1) + 2))


def main():
    N, X = map(int, input().split())
    print(count(N, X))


if __name__ == '__main__':
    main()

Verdicts: Wrong Answer

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
N, X = map(int, input().split())
burger  = [1] * (N+1)
patty = [1] * (N+1)
for i in range(1, N+1):
    burger[i] = burger[i-1] * 2 + 3
    patty[i] = patty[i-1] * 2 + 1


def func(level, x):
    if level == 0:
        return 0 if x <= 0 else 1
    if burger[level] + 1 < x:
        return func(level-1, x-burger[level]-2) + patty[level] + 1
    else:
        return func(level-1, x-1)


print(func(N, X))


N, X = map(int, input().split())
burger  = [1] * (N+1)
patty = [1] * (N+1)
for i in range(1, N+1):
    burger[i] = burger[i-1] * 2 + 3
    patty[i] = patty[i-1] * 2 + 1


def func(level, x):
    if burger[level-1] + 1 <= x:
        return func(level-1, x-burger[level-1]-2) + patty[level-1] + 1
    else:
        return func(level-1, x-1)
    if level == 0:
        return 0


print(func(N, X))


N, X = map(int, input().split())
burger  = [1] * N
patty = [1] * N
for i in range(1, N):
    burger[i] = burger[i-1] * 2 + 3
    patty[i] = patty[i-1] * 2 + 1


def func(level, x):
    if level == 0:
        return 0 if x <= 0 else 1
    if burger[level-1] + 1 < x:
        return func(level-1, x-burger[level-1]-2) + patty[level-1] + 1
    else:
        return func(level-1, x-1)


print(func(N, X))


Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
N,X = map(int,input().split())

n_sum= X
answer = [0]
def saiki(layer,n_sum,sum_p):
    # print(layer,n_sum,sum_p)
    # if layer == 0:
    #     answer[0] = sum_p
    #     return
    if layer == 1:
        if n_sum == 1:
            answer[0] = sum_p
        elif n_sum == 2:
            answer[0] = sum_p+1
        elif n_sum ==3:
            answer[0] = sum_p+2
        else:
            answer[0] = sum_p+3
        return

    
    layer_sum = 2**(layer+2)-3
    
    pre_layer_sum = 2**(layer+1)-3
    pre_p_sum = 2**(layer)-1
    
    if n_sum  < layer_sum //2 +1 :
        # print("left")
        n_sum -= 1
        saiki(layer-1,n_sum,sum_p)
    
    else:
        # print("right")
        n_sum -= (pre_layer_sum+2)
        sum_p += (1+pre_p_sum)
        saiki(layer-1,n_sum,sum_p)

saiki(N,X,0)

print(answer[0])








N,X = map(int,input().split())

n_sum= X
answer = [0]
def saiki(layer,n_sum,sum_p):
    # print(layer,n_sum,sum_p)
    # if layer == 0:
    #     answer[0] = sum_p
    #     return
    if n_sum == 0:
        answer[0] = sum_p
        return 
    if layer == 1:
        if n_sum == 1:
            answer[0] = sum_p
        elif n_sum == 2:
            answer[0] = sum_p+1
        elif n_sum ==3:
            answer[0] = sum_p+2
        else:
            answer[0] = sum_p+3
        return

    
    layer_sum = 2**(layer+2)-3
    
    pre_layer_sum = 2**(layer+1)-3
    pre_p_sum = 2**(layer)-1
    
    if n_sum  < layer_sum //2 +1 :
        # print("left")
        n_sum -= 1
        saiki(layer-1,n_sum,sum_p)
    
    else:
        # print("right")
        n_sum -= (pre_layer_sum+2)
        sum_p += (1+pre_p_sum)
        saiki(layer-1,n_sum,sum_p)

saiki(N,X,0)

print(answer[0])








Verdicts: Wrong Answer

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
def f(n, x):
	if n==0:
		return 0 if x<= 0 else 1
	elif x<=1+a[n-1]:
		return f(n-1,x-1)
	else:
		return p[n-1]+1+f(n-1,x-2-a[n-1])


n,x=map(int, input().split())
a,p=[1],[1]
for i in range(N):
	a.append(a[i] * 2 + 3)
	p.append(p[i] * 2 + 1)
    
print(f(n, x))

def f(n, x):
	if n==0:
		return 0 if x<= 0 else 1
	elif x<=1+a[n-1]:
		return f(n-1,x-1)
	else:
		return p[n-1]+1+f(n-1,x-2-a[n-1])


n,x=map(int, input().split())
a,p=[1],[1]
for i in range(n):
	a.append(a[i] * 2 + 3)
	p.append(p[i] * 2 + 1)
    
print(f(n, x))

Verdicts: Runtime Error

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
n, x = map(int, input().split())
flg = False 
L = None
for i in range(n+1):
    if i+1 <= x <= i+2**(n-i+3)-3:
        flg = True
        L = i
        break
    if i+1 <= 2**(n+2)-3-x <= i+2**(n-i+3)-3:
        L = i
        break
print(L)
ans = None
if flg==True:
    if x-L==1:
        ans = 0
    elif x==L+2**(n-L+3)-3:
        ans = 2**(n-L+2)-1
    else:
        ans = 2**(n-L+1)-1
else:
    if 2**(n+2)-3-x==L:
        ans = 2**(n+1)-1
    elif 2**(n+2)-3-x==L+2**(n-L+3)-3:
        ans = 2**(n+1)-2**(n-L+2)
    else:
        ans = 2**(n+1)-2**(n-L+1)
print(ans)


n, x = map(int, input().split())
flg = False 
L = None
for i in range(n, -1, -1):
    if i+1 <= x <= i+2**(n-i+3)-3:
        flg = True
        L = i
        break
    if i+1 <= 2**(n+2)-3-x <= i+2**(n-i+3)-3:
        L = i
        break
ans = None
if flg==True:
    if x-L==1:
        ans = 0
    elif x==L+2**(n-L+3)-3:
        ans = 2**(n-L+2)-1
    else:
        ans = 2**(n-L+1)-1
else:
    if 2**(n+2)-3-x==L:
        ans = 2**(n+1)-1
    elif 2**(n+2)-3-x==L+2**(n-L+3)-3:
        ans = 2**(n+1)-2**(n-L+2)
    else:
        ans = 2**(n+1)-2**(n-L+1)
print(ans)


n, x = map(int, input().split())

def p(n):
    return 2**(n+1)-1

def a(n):
    return 2**(n+2)-3

def f(n, x):
    if n==0:
        return 0 if x<=0 else 1
    elif x<=1+a(n-1):
        return f(n-1, x-1)
    else:
        return p(n-1)+1+f(n-1, x-2-a(n-1))

print(f(n, x))


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
n, x = map(int, input().split())
a, p = [1], [1]
for i in range(n):
    a.append(a[i] * 2 + 3)
    p.append(p[i] * 2 + 1)


def f(N, X):
    if N == 0:
        return 0 if X <= 0 else 1
    elif X <= 1 + a[N-1]:
        return f(N-1, X-1)
    else:
        return p[N-1] + 1 + f(N-1, X - 2 - a[N-1])


print(f(N, X))


n, x = map(int, input().split())
a, p = [1], [1]
for i in range(n):
    a.append(a[i] * 2 + 3)
    p.append(p[i] * 2 + 1)


def f(N, X):
    if N == 0:
        return 0 if X <= 0 else 1
    elif X <= 1 + a[N-1]:
        return f(N-1, X-1)
    else:
        return p[N-1] + 1 + f(N-1, X - 2 - a[N-1])


print(f(N=n, X=x))


Verdicts: Runtime Error

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
n,x = map(int,input().split())

a,p = [1],[1]

for i in range(n):
    a.append(a[i]*2+3)
    p.append(p[i]+2+1)

def f(n,x):
    if n==0:
        return 0 if x <= 0 else 1
    elif x <= 1 + a[n-1]:
        return f(n-1,x-1)
    else:
        return p[n-1] + 1 + f(n-1,x-2-a[n-1])

print(f(n,x))

n,x = map(int,input().split())

a,p = [1],[1]
for i in range(n):
    a.append(a[i]*2+3)
    p.append(p[i]*2+1)

def f(n,x):
    if n==0:
        return 0 if x <= 0 else 1
    elif x <= 1 + a[n-1]:
        return f(n-1,x-1)
    else:
        return p[n-1] + 1 + f(n-1,x-2-a[n-1])

print(f(n,x))

Verdicts: Wrong Answer

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
[N,X] = list(map(int,input().split(' ')))

def paty(n,x):
  if n == 0:
    if x == 1:
      return 1
    else:
      return 0
  elif int((2**(n+2)-3 + 1) / 2) >= x:
    return paty(n-1,x-1)
  else:
    return 2**n + paty(n-1, x-(2**(n+1)-3) -2)
  
ans = paty(N,X)
print(ans)

[N,X] = list(map(int,input().split(' ')))

def paty(n,x):
  if n == 0:
    if x == 1:
      return 1
    else:
      return 0
  elif int((2**(n+2)-3 - 1) / 2) >= x:
    return paty(n-1,x-1)
  elif int((2**(n+2)-3 + 1) / 2) == x:
    return paty(n-1,x-1) + 1
  else:
    return 2**n + paty(n-1, x-(2**(n+1)-3) -2)
  
ans = paty(N,X)
print(ans)

[N,X] = list(map(int,input().split(' ')))

def paty(n,x):
  #print('n:{}'.format(n))
  #print('x:{}'.format(x))
  if n == 0:
    if x == 1:
      return 1
    else:
      return 0
  elif int((2**(n+2)-3 - 1) / 2) >= x:
    return paty(n-1,x-1)
  elif int((2**(n+2)-3 + 1) / 2) == x:
    return paty(n-1,x-2) + 1
  elif (2**(n+2)-3) - 1 <= x:
    return 2*paty(n-1, x-(2**(n+1)-3) -2) + 1
  else:
    return 2**n + paty(n-1, x-(2**(n+1)-3) -2)
  
ans = paty(N,X)
print(ans)

[N,X] = list(map(int,input().split(' ')))

def paty(n,x):
  if n == 0:
    if x == 1:
      return 1
    else:
      return 0
  elif int((2**(n+2)-3 + 1) / 2) >= x:
    return paty(n-1,x-1) + 1
  else:
    return 2**n + paty(n-1, x-(2**(n+1)-3) -2)
  
ans = paty(N,X)
print(ans)

[N,X] = list(map(int,input().split(' ')))

def paty(n,x):
  #print('n:{}'.format(n))
  #print('x:{}'.format(x))
  if x == 0:
    return 0
  if n == 0:
    return x
  elif ((2**(n+2))-3 - 1) / 2 >= x:
    return paty(n-1,x-1)
  elif ((2**(n+2))-3 + 1) / 2 == x:
    return 2**n
  elif ((2**(n+2))-3) - 1 <= x:
    return 2**(n+1) - 1
  else:
    return 2**n + paty(n-1, x-((2**(n+1))-3) -2)
  
ans = paty(N,X)
print(ans)

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
N, X = map(int, input().split())

def burger(N,X):
  print(N,X)
  if N == 0 and X == 1:
    return 1
  if X == 0:
    return 0
  twopow = pow(2,N)
  if X > 2*twopow-2:
    return twopow + burger(N-1,X-2*twopow+1)
  elif X <= 2*twopow-3:
    return burger(N-1,X-1)

print(burger(N,X))

N, X = map(int, input().split())

def burger(N,X):
  print(N,X)
  if N == 0 and X == 1:
    return 1
  if X == 0:
    return 0
  twopow = pow(2,N)
  if X == 4*twopow-3:
    return 2*twopow-1
  if X > 2*twopow-2:
    return twopow + burger(N-1,X-2*twopow+1)
  elif X <= 2*twopow-2:
    return burger(N-1,X-1)

print(burger(N,X))


N, X = map(int, input().split())

def burger(N,X):
  #print(N,X)
  if N == 0 and X == 1:
    return 1
  if X == 0:
    return 0
  twopow = pow(2,N)
  if X == 4*twopow-3:
    return 2*twopow-1
  if X > 2*twopow-2:
    return twopow + burger(N-1,X-2*twopow+1)
  elif X <= 2*twopow-2:
    return burger(N-1,X-1)

print(burger(N,X))

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
def feed_runrun(answer, burger_dimension, appetite):
    if appetite >= 0:
        return answer

    burger_size = 2 ** (burger_dimension + 2) - 3
    
    if appetite < burger_size:
        return feed_runrun(answer, burger_dimension - 1, appetite - 1)
    
    amount_of_p = 2 ** (burger_dimension + 1) - 1
    return feed_runrun(answer + amount_of_p + 1, burger_dimension, appetite - burger_size - 1)


n, x = map(int, input().split())
print(feed_runrun(0, n, x))

n, x = map(int, input().split())

answer = 0
red = x

searching_index = n
while red > 0:
    for i in reversed(range(searching_index + 1)):
        length = 2**(i + 2) - 3
        if red >= length:
            print("length", length, red)
            if red >= length + 1:
                print("contain p")
                answer += 1
                red -= 1
            searching_index = i
            answer += 2**(i+1) - 1
            red -= length
            print(answer, length)
            break
        red -= 1

print(answer)

def feed_runrun(burger_dimension, appetite):
    if appetite == 0:
        return 0

    burger_size = 2 ** (burger_dimension + 2) - 3
    amount_of_p = 2 ** (burger_dimension + 1) - 1

    if appetite == burger_size:
        return amount_of_p
    if appetite < burger_size:
        return feed_runrun(burger_dimension - 1, appetite - 1)
    if appetite > burger_size:
        return amount_of_p + 1 \
               + feed_runrun(burger_dimension, appetite - burger_size - 1)


n, x = map(int, input().split())
print(feed_runrun(n, x))

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
N, X = map(int, input().split())
def f(n, x):
    if x ==0:
        return 0
    elif n == 0:
        return 1
    elif x <= 2**(n+1) - 1:
        return f(n-1, x-1)
    else:
        return 2**n+f(n-1, x-2**(n+1)+1)
print(f(N, X))

N, X = map(int, input().split())
def f(n, x):
    if x ==0:
        return 0
    if n == 0:
        return 1
    if x <= 2**(n+1) - 1:
        return f(n-1, x-1)
    else:
        return 2**n+f(n-1, x-2**(n+1)+1)
print(f(N, X))

N, X = map(int, input().split())
def f(n, x):
    if x ==0:
        return 0
    if n == 0:
        return 1
    if x <= 2**(n+1) - 2:
        return f(n-1, x-1)
    else:
        return 2**n+f(n-1, x-2**(n+1)+1)
print(f(N, X))

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
from functools import lru_cache

@lru_cache()
def f(n):
    if n==0:
        return 1
    return 2*f(n-1)+1

@lru_cache()
def g(n):
    if n==0:
        return 1
    return 2*g(n-1)+3

N, X = map(int, input().split())
total = [g(i) for i in range(N+1)]
p = [f(i) for i in range(N+1)]
ans = 0

def search(x, n):
    global ans
    print(n, x)
    if n==0:
        if x:
            ans += 1
        return
    if x==0:
        return
    if x > total[n-1] + 2:
        ans += p[n-1] + 1
        search(x-(2 + total[n-1]), n-1)
    elif x == total[n-1] + 2:
        ans += p[n-1] + 1
    else:
        search(x-1, n-1)

search(X, N)
print(ans)

def f(n):
    if n==0:
        return 1
    return 2*f(n-1)+1

N, X = map(int, input().split())
l, r = 0, g(N)
ans = 0

while N:
    m = (l+r)//2
    if m<=X:
        l = m
        ans += f(N-1) + 1
    else:
        r = m
    N -= 1

print(ans)

N, X = map(int, input().split())
q = [1]*(N+1)
p = [1]*(N+1)
for i in range(1, N+1):
    q[i] = 2*q[i-1]+3
    p[i] = 2*p[i-1]+1

ans = 0
s = [(X, N)]
while s:
    x, n = s.pop()
    if n==0:
        ans += x!=0
    if x:
        a = q[n-1] + 2
        b = p[n-1] + 1

        if x >= a:
            ans += b
            s += [(x-a, n-1)]
        else:
            s += [(x-1, n-1)]

print(ans)

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
import numpy as np
import sys
buf = sys.stdin.buffer

def main():
    N = int(buf.readline())
    A = np.frombuffer(buf.read(), dtype="int64")
    A = np.mod(A, 2)
    print("first") if np.count_nonzero(A) else print("second")
if __name__ == "__main__":
    main()

def main():

    burgur = [0] * 51
    burgur[0] = 1
    pate = [0] * 51
    pate[0] = 1
    for i in range(50):
        burgur[i+1] = burgur[i] * 2 + 3
        pate[i+1] = pate[i] * 2 + 1
    
    N, X = map(int, input().split())

    X -= 1
    ans = 0
    for i in reversed(range(1, N+1)):
        if X == burgur[i] - 1:
            ans += pate[i]
            break
        elif X >= burgur[i-1] + 1:
            ans += pate[i-1] + 1
            X -= (burgur[i-1] + 2)
        else: 
            X -= 1
    if X == 0:
        ans += 1
    print(ans)
    

if __name__ == "__main__":
    main()

Verdicts: Runtime Error

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
N, X = map(int, input().split())
a,p=[1],[1] for i in range(N):
    a.append(a[i] * 2 + 3)
    p.append(p[i] * 2 + 1)
deff(N,X): 
        return 0 if X <= 0 else 1
    elif X <= 1 + a[N-1]:
        return f(N-1, X-1)
    else:
        return p[N-1] + 1 + f(N-1, X-2-a[N-1])
print(f(N, X))

N, X = map(int, input().split())
a,p=[1],[1] 
for i in range(N):
    a.append(a[i] * 2 + 3)
    p.append(p[i] * 2 + 1)
deff(N,X): 
    if N == 0:
        return 0 if X <= 0 else 1
    elif X <= 1 + a[N-1]:
        return f(N-1, X-1)
    else:
        return p[N-1] + 1 + f(N-1, X-2-a[N-1])
print(f(N, X))

N,X=map(int,input().split())
def humberger(N):
    if N==0:
        return [1]
    else:
        return [0]+humberger(N-1)+[1]+humberger(N-1)+[0]
list1=humberger(N)
del list1[X:]
sum(list1)

N, X = map(int, input().split())
a,p=[1],[1] 
for i in range(N):
    a.append(a[i] * 2 + 3)
    p.append(p[i] * 2 + 1)
def f(N,X): 
    if N == 0:
        return 0 if X <= 0 else 1
    elif X <= 1 + a[N-1]:
        return f(N-1, X-1)
    else:
        return p[N-1] + 1 + f(N-1, X-2-a[N-1])
print(f(N, X))

Verdicts: Runtime Error

Runtime Error

Wrong Answer

Accepted
Problem: In some other world, today is Christmas.  Mr. Takaha decides to make a multi-dimensional burger in his party. A _level- L burger_ (L is an integer greater than or equal to 0) is the following thing:    * A level-0 burger is a patty.   * A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.  For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.  The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Submission attempts (in order):
import re

N, X = map(int, input().split())

burger = [None] * 51
burger[0] = "P"

for i in range(1, N + 1):
    burger[i] = "B" + burger[i - 1] + "P" + burger[i - 1] + "B"
    print(burger[i])

burger_x = burger[N][:X]
ans = len(re.findall("P", burger_x))
print(ans)

N, X = map(int, input().split())

a, p = [None] * (N + 1), [None] * (N + 1)
a[0], p[0] = 1, 1
for i in range(1, N + 1):
    a[i], p[i] = 2 * a[i - 1] + 3, 2 * p[i - 1] + 1


def f(N, X):
    if N == 0:
        return 0 if X <= 0 else 1
    elif X <= a[N - 1] + 1:
        return f(N - 1, X - 1)
    else:
        return p[N - 1] + 1 + f(N - 1, X - a[N - 1] - 2)

print(f(N, X))


Verdicts: Runtime Error

Accepted