TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
n = int(input())
nums = list(map(int, input().split()))
nums.sort()
if nums[n] < sum(nums[:n]):
    print("Yes")
else:
    print("No")

n = int(input())
nums = list(map(int, input().split()))
nums.sort()
if nums[n-1] < sum(nums[:n-1]):
    print("Yes")
else:
    print("No")

Verdicts: Runtime Error

Accepted
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
N = int(input())
L = list(map(int,input().split()))
L_copy = L.copy()
max = max(L)
L_copy.pop(L.index(max))

if max > sum(L_copy):
  print("Yes")
else:
  print("No")

N = int(input())
L = list(map(int,input().split()))
L_copy = L.copy()
max = max(L)
L_copy.pop(L.index(min))

if max > sum(L_copy):
  print("Yes")
else:
  print("No")


N = int(input())
L = list(map(int,input().split()))
L_copy = L.copy()
MAX = max(L)
L_copy.pop(L.index(MAX))


if MAX < sum(L_copy):
  print("Yes")
else:
  print("No")

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
N = int(input())
L = input().split()
L = [int(i) for i in L]
L = sorted(L, reverse=True)
hen = 0

for i in range(1, N):
    hen += L[i]
if L[0] < hen:
    print('YES')
else:
    print('NO')

N = int(input())
L = input().split()
L = [int(i) for i in L]
L = sorted(L, reverse=True)
hen = 0

for i in range(1, N):
    hen += L[i]
if L[0] < hen:
    print('Yes')
else:
    print('No')

Verdicts: Wrong Answer

Accepted
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
size = int(input())
sides = []
for _ in range(len):
  sides.append(int(input()))
big = max(sides)
together = sum(sides)
if(big < together):
  print("Yes")
else:
  print("No")

size = int(input())
sides = input().split()
ss = []
for x in sides:
  ss.append(int(x))
big = max(ss)
together = sum(ss)
if(big < together-big):
	print("Yes")
else:
	print("No")


Verdicts: Runtime Error

Accepted
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
N = int(input())
l = list[]

for i in N:
  n = int(input())
  l.append(n)

m = l.max()
SUM = l.sum() - m

if m > SUM:
  print("YES")
else:
  print("NO")


N = int(input())
l = list()

for i in range(N):
  n = int(input())
  l.append(n)
 
m = max(l)
SUM = sum(l) - m
 
if m > SUM:
  print("YES")
else:
  print("NO")

N = int(input())
l = list()

for i in range(N):
  n = int(input())
  l.append(n)
 
m = max(l)
SUM = sum(l) - m
 
if m > SUM:
  print("Yes")
else:
  print("No")

N = int(input())
l = list()

for i in range(N):
  n = int(input())
  l.append(n)
  
m = max(l)
SUM = sum(l) - m
 
if m < SUM:
  print('Yes')
else:
  print('No')

N = int(input())
l = list()

for i in range(N):
  n = int(input())
  l.append(n)
 
m = max(l)
SUM = sum(l) - m
 
if m < SUM:
  print("Yes")
else:
  print("No")

N = int(input())
l = list(map(int, input().split()))

m = max(l)
SUM = sum(l) - m

if m < SUM:
  print('Yes')
else:
  print('No')

Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
N = int(input())
L = list(map(int,input().split()))

s = 0
maxL = 0
maxi = -1

for i in range(N):
    if L[i] > maxL:
        maxL = L[i]
        maxi = i
    
    else:
        s = s+L[i]

if s  > L[maxi]:
    print("Yes")
else:
    print("No")

N = int(input())
L = list(map(int,input().split()))

s = 0
maxL = 0

for i in range(N):
    if L[i] > maxL:
        maxL = L[i]
       
    
    s = s+L[i]


if s-maxL  > maxL:
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Accepted
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
N = int(input())
L = [int(i) for i in input().split()]

L.sort()
ans = 'YES' if sum(L[:N - 1]) > L[N - 1] else 'NO'
print(ans)

N = int(input())
L = [int(i) for i in input().split()]

L.sort()
ans = 'Yes' if sum(L[:N - 1]) > L[N - 1] else 'No'
print(ans)


Verdicts: Wrong Answer

Accepted
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
n=int(input())
t=list(map(int,input().split(" ")))

t_max=max(t)

j=0
t_sum=0
while j<=n-1:
    t_sum+=t[j]
    j+=1
        
if t_sum>2*t_max:
    print("YES")
else:
    print("NO")

n=int(input())
t=list(map(int,input().split(" ")))

t_max=max(t)

j=0
t_sum=0
while j<=n-1:
    t_sum+=t[j]
    j+=1
        
if t_sum>2*t_max:
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Accepted
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
n = int(input())
l = list(int,input().split())

l_max = max(l)
if sum(l) - l_max > l_max:
    print("Yes")
else:
    print("No")

N =int(input())
L =[int(j) for j in input().split()]
if max(L) < sum(L)-max(L):
    print('Yes')
else:
    print('No')


Verdicts: Runtime Error

Accepted
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
n = int(input())
a = input().split()
i = 0
while i < n:
  a[i] = int(a[i])
  i = i + 1 
 
i = 0
while i < n:
  j = i + 1
  while j < n:
    if a[i] < a[j]:
      temp = a[i]
      a[i] = a[j]
      a[j] = temp
    j = j + 1
  i = i + 1
 
sums = sum(a)
print(a[0])
if(sums - a[0] > a[0]):
  print("Yes")
else:
  print("No")

n = int(input())
a = input().split()
i = 0
while i < n:
  a[i] = int(a[i])
  i = i + 1 

i = 0
while i < n:
  j = i + 1
  while j < n:
    if a[i] < a[j]:
      temp = a[i]
      a[j] = a[i]
      a[j] = temp
    j = j + 1
  i = i + 1

sum = sum(a)
print(a[0])
if(sum-a[0] > a[0]):
  print("Yes")
else:
  print("No")

n = int(input())
a = input().split()
i = 0
while i < n:
  a[i] = int(a[i])
  i = i + 1 

i = 0
while i < n:
  j = i + 1
  while j < n:
    if a[i] < a[j]:
      temp = a[i]
      a[j] = a[i]
      a[i] = temp
    j = j + 1
  i = i + 1

sum = sum(a)
print(a[0])
if(sum-a[0] > a[0]):
  print("Yes")
else:
  print("No")

n = int(input())
a = input().split()
i = 0
while i < n:
  a[i] = int(a[i])
  i = i + 1 
 
i = 0
while i < n:
  j = i + 1
  while j < n:
    if a[i] < a[j]:
      temp = a[i]
      a[i] = a[j]
      a[j] = temp
    j = j + 1
  i = i + 1
 
sums = sum(a)

if(sums - a[0] > a[0]):
  print("Yes")
else:
  print("No")
sum = sum(a)

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
import numpy as np
import sys

N = int(input())
L = list(map(int, input().split()))

if max(L) > sum(L) - max(L):
	print('Yes')
else:
	print('No')


import numpy as np
import sys

N = int(input())
L = list(map(int, input().split()))

if max(L) < sum(L) - max(L):
	print('Yes')
else:
	print('No')


Verdicts: Wrong Answer

Accepted
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
n = int(input)
l = list(map(int, input().split()))
x = max(l)
s = sum(l)
if x < (s-x):
    print("Yes")

n = int(input)
l = list(map(int, input().split()))
x = max(l)
s = sum(l)
if x < (s-x):
    print("Yes")
else:
    print("No")

n = int(input)
l = list(map(int, input().split()))
x = max(l)
s = sum(l)
if x < (s-x):
    print("Yes")
else:
    print("No")

n = int(input)
l = list(map(int, input().split()))


n = int(input())
l = list(map(int, input().split()))
x = max(l)
s = sum(l)
if x < (s-x):
    print("Yes")
else:
    print("No")

Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
n = int(input())
e = list(map(int, input().split))
if max(e) < sum(e) - max(e):
  print('Yes')
else:
  print('No')


n = int(input())
e = list(map(int, input().split()))
if max(e) < sum(e) - max(e):
  print('Yes')
else:
  print('No')


Verdicts: Runtime Error

Accepted
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
n = int(input())
li = list(map(int,input().split()))

li.sort()

if sum(li[:-1]) > li[i]:
    print("Yes")
else:
    print("No")

n = int(input())
li = list(map(int,input().split()))

li.sort()

if sum(li[:-1]) > li[-1]:
    print("Yes")
else:
    print("No")

Verdicts: Runtime Error

Accepted
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
# B Polygon
N = int(input())
L = list(map(int, input().split()))
mx = L.pop(L.index(max(L)))
if mx > sum(L):
    print("Yes")
else:
    print("No")
pass


# B Polygon
N = int(input())
L = list(map(int, input().split()))
mx = L.pop(L.index(max(L)))
if mx < sum(L):
    print("Yes")
else:
    print("No")
pass


Verdicts: Wrong Answer

Accepted
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
# a,b=map(float,input().split())
# print(a/b)

N = int(input())
# L = []
#L = map(int, input().split())
L = [int(i) for i in input().split()]
#L.append(int(input()))

# print(a/b)
print(L)
s = sum(L)
m = max(L)
#f = 0
#for x in L:

#        f = 1

if (m < s - m):
    print('Yes')
else:
    print('No')
    

N = int(input())
# L = []
#L = map(int, input().split())
L = [int(i) for i in input().split()]
#L.append(int(input()))

# print(a/b)
print(L)
s = sum(L)
m = max(L)
print(s)
print(m)
#f = 0
#for x in L:

#        f = 1

if (m < s - m):
    print('Yes')
else:
    print('No')
    

N = int(input())
# L = []
#L = map(int, input().split())
L = [int(i) for i in input().split()]
#L.append(int(input()))

# print(a/b)
print(L)
s = sum(L)
m = max(L)
#f = 0
#for x in L:

#        f = 1

if (m < s):
    print('Yes')
else:
    print('No')

N = int(input())
# L = []

# L = map(int, input().split())
# = list(map(int, input().split()))
L = [int(i) for i in input().split()]
#L.append(int(input()))
#s = 0
#for x in L:
    
#print(s)

# print(a/b)
#print(L)
s = sum(L)
m = max(L)
#print(s)
#print(m)
#f = 0
#for x in L:

#        f = 1

if (m < s - m):
    print('Yes')
else:
    print('No')

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
s = [input() for i in range(2)]
sides = [int(i) for i in s[1].split()]
sides = sorted(sides,reverse=True)
long_side= sides.pop(0)

total = 0
for side in sides:
  total += side
  
if long_side < total:
  print("YES")
else:
  print("NO")

s = [input() for i in range(2)]
sides = [int(i) for i in s[1].split()]
sides = sorted(sides,reverse=True)
long = sides.pop(0)

total = 0
for side in sides:
  total += side
  
if long < total:
  print("YES")
else:
  print("NO")

s = [input() for i in range(2)]
sides = [int(i) for i in s[1].split()]
sides = sorted(sides,reverse=True)
long_side= sides.pop(0)

total = 0
for side in sides:
  total += side
  
if long_side < total:
  print("Yes")
else:
  print("No")

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
N=int(input())
L=list(map(int,input().split()))

for i in range(N):
    if max(L)<sum(L)-max(L):
        print('Yes')
    else:
        print('No')

N=int(input())
L=list(map(int,input().split()))

if max(L)<sum(L)-max(L):
    print('Yes')
else:
    print('No')

Verdicts: Wrong Answer

Accepted
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
n = int(input())
a = [int(e) for e in input().split()]

print('Yes' if max(a)>= sum([e for e in a]-max(a)) else 'No')

n = int(input())
a = [int(e) for e in input().split()]

ans ='Yes' if max(a)>= sum([e for e in a]-max(a)) else 'No'
print(ans)

n = int(input())
a = [int(e) for e in input().split()]

ans ='No' if max(a)>= sum([e for e in a])-max(a) else 'Yes'
print(ans)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
N=int(input())
li=list(map(int,input().split()))
li.sort()
if li.pop()>sum(li):
    print("Yes")
else:
    print("No")

N=int(input())
li=list(map(int,input().split()))
if 2*max(li)<sum(li):
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Accepted
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
N = int(input())
Ls = input().split()
for i in range(N):
    Ls[i] = int(Ls[i])
print(Ls)
max_L = max(Ls)
sum_others = sum(Ls) - max_L
if max_L < sum_others:
    print("Yes")
else:
    print("No")

N = int(input())
Ls = input().split()
for i in range(N):
    Ls[i] = int(Ls[i])
max_L = max(Ls)
sum_others = sum(Ls) - max_L
if max_L < sum_others:
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Accepted
Problem: Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.  You can use the following theorem:  **Theorem** : an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Submission attempts (in order):
N = int(input())
L = [int(i) for i in input().split()]

L = sorted(L)

if L[len(L)-1] < sum(L[0:len(L)-1]):
    print('yes')
else:
    print('No')


N = int(input())
L = [int(i) for i in input().split()]

L.sort()
if L[N-1] < sum(L[0:N-1]):
    print('yes')
else:
    print('No')


N = int(input())
L = [int(i) for i in input().split()]

if max(L) < sum(L)-max(L):
    print('yes')
else:
    print('No')


N = int(input())
L = [int(i) for i in input().split()]

L.sort()
if L[N-1] < sum(L[0:N-1]):
    print('Yes')
else:
    print('No')


Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
import numpy as np 
n,m = map(int, input().split())

X = np.array(list(map(int, input().split())))

print(X)
X.sort()
X = np.diff(X)
X.sort()
if n >= m:
    print(0)
else:
    print(X[:m-n].sum())

import numpy as np 
n,m = map(int, input().split())

X = np.array(list(map(int, input().split())))

X.sort()
X = np.diff(X)
X.sort()
if n >= m:
    print(0)
else:
    print(X[:m-n].sum())

Verdicts: Wrong Answer

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
n,m=map(int,input().split())
line=list(map(int,input().split()))
if n >= m:
  print(0)
line.sort()
stock=0
distance=[]
for i in line:
  stock=i
  distance.append(i-stock)
distance.pop(0)
for i in range(n-1):
  distance.pop(distance.index(max(distance)))
ans=0
for i in distance:
  ans+= i
print(ans)


n,m=map(int,input().split())
line=list(map(int,input().split()))
if n >= m:
  print(0)
else:
  line.sort()
  stock=0
  distance=[]
  for i in line:
    distance.append(i-stock)
    stock=i
  distance.pop(0)
  distance.sort()
  ans=0
  for i in range(m-n):
    ans+= distance[i]
  print(ans)

Verdicts: Runtime Error

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
import sys

for line in sys.stdin:
    print(line)

import sys

input = sys.stdin.readlines()
N, M = map(int, input[0].strip().split(' '))
Xs = list(map(int, input[1].strip().split(' ')))
s = sorted(Xs)
gaps = [s[i+1]-s[i] for i in range(len(s)-1)]
sgaps = sorted(gaps)
if N>=M:
    print(0)
else:
    print(sum(sgaps[:(M-N)]))



Verdicts: Wrong Answer

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
n,m = list(map(int, input().split()))
a=list(map(int, input().split()))
a.sorted()
d=[a[i+1]-a[i] for i in range(n-1)]
d.sorted()
print(sum(d[:m-n]) if m>n else 0)

n,m = list(map(int, input().split()))
a=list(map(int, input().split()))
a.sorted()
d=[a[i+1]-a[i] for i in range(n)]
d.sorted()
print(sum(d[:m-n]) if m>n else 0)

n,m = list(map(int, input().split()))
a=list(map(int, input().split()))
a.sorted()
d=[a[i+1]-a[i] for i in range(m-1)]
d.sorted()
print(sum(d[:m-n]) if m>n else 0)

n,m = list(map(int, input().split()))
a=list(map(int, input().split()))
a.sort()
d=[a[i+1]-a[i] for i in range(m-1)]
d.sort()
print(sum(d[:m-n]) if m>n else 0)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
n,m=map(int,input().split())
x=list(map(int,input().split()))
x.sort()
c=0
l=[]
if m==1 and x.length()==1:
    print("0")
else:
    for i in range(m-1):
        l.append(abs(x[i]-x[i+1]))
    l.sort()
    if range(len(l)-n+1)<=0:
        print("0")
    else:
        for i in range(len(l)-n+1):
            c+=l[i]
        print(c)

n,m=map(int,input().split())
x=list(map(int,input().split()))
x.sort()
c=0
for i in range(n+1):
    c+=x[i]
print(c)

n,m=map(int,input().split())
x=list(map(int,input().split()))
x.sort()
c=0
l=[]
for i in range(m-1):
    l.append(abs(x[i]-x[i+1]))
l.sort()
if len(l)-n+1<=0:
    print("0")
else:
    for i in range(len(l)-n+1):
        c+=l[i]
    print(c)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
import sys
n, m = map(int,input().split())

if n >= m:
  print(0)
  sys.exit()
  
x = sorted(list(map(int,input().split())))
print(sum([x[i+1]-x[i] for i in range(len(x)-1)].sort(reverse = True)[n-1:]))


#!/usr/bin/env python3
import sys


def solve(N: int, M: int, X: "List[int]"):
    x = sorted(X)
    x_dif = []
    for i in range(M-1):
        x_dif.append(x[i+1]-x[i])
    x_dif.sort(reverse=True)
    print(sum(x_dif[N-1:]))


    return


def main():
    def iterate_tokens():
        for line in sys.stdin:
            for word in line.split():
                yield word
    tokens = iterate_tokens()
    N = int(next(tokens))  # type: int
    M = int(next(tokens))  # type: int
    X = [int(next(tokens)) for _ in range(M)]  # type: "List[int]"
    solve(N, M, X)

if __name__ == '__main__':
    main()


Verdicts: Runtime Error

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
diN, M = map(int,input().split())
L = sorted(list(map(int,input().split())))
distance = []
for i in range(len(L)-1):
    distance.append(abs(L[i]-L[i+1]))
distance = sorted(distance)
for _ in range(N-1):
    if len(distance) > 0:
        del distance[-1]
    else:
        print(0)
        quit()
print(sum(distance))


N, M = map(int,input().split())
L = sorted(list(map(int,input().split())))
distance = []
for i in range(len(L)-1):
    distance.append(abs(L[i]-L[i+1]))
distance = sorted(distance)
for _ in range(N-1):
    if len(distance) > 0:
        del distance[-1]
    else:
        print(0)
        quit()
print(sum(distance))


Verdicts: Runtime Error

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
n,m=map(int,input().split())
A=list(map(int,input().split()))

B=[]
for i in range(m-1):
  B.append(abs(A[i+1]-A[i]))
B.sort()
print(sum(B[:-n+1:]))


n,m=map(int,input().split())
A=list(map(int,input().split()))
A.sort()
B=[]
for i in range(m-1):
  B.append(abs(A[i+1]-A[i]))
B.sort()
if n==1:
  print(sum(B))

else:
  print(sum(B[:-n+1:]))


Verdicts: Wrong Answer

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
N, M = map(int, input().split())

if (M <= N):
    print(0)
else:
    Xs = list(map(int, input().split()))
    Xs.sort()
    W = Xs[-1] - Xs[0]
    Ds = [Xs[i+1]-Xs[i] for i in range(M-1)]
    Ds.sort(reverse=True)

    gaps = 0
    print(Ds)
    for i in range(N-1):
        gaps += Ds[i]

    print(W-gaps)


N, M = map(int, input().split())

if (M <= N):
    print(0)
else:
    Xs = list(map(int, input().split()))
    Xs.sort()
    W = Xs[-1] - Xs[0]
    Ds = [Xs[i+1]-Xs[i] for i in range(M-1)]
    Ds.sort(reverse=True)

    gaps = 0
    for i in range(N-1):
        gaps += Ds[i]

    print(W-gaps)

Verdicts: Wrong Answer

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
import itertools
N,M = map(int,input().split())
ary1 = map(int,input().split())
ary2 = sorted(list(ary1))
#print(list(itertools.combinations(range(1,M),N)))
if N>=M:
  print(0)
elif N==1:
  print(ary2[-1]-ary2[0])
else :
  iter1 = itertools.combinations(range(1,M),N)
  ans = 2*10**5+1
  dist = [2*10**5+1]*N
  for nlist1 in itertools.combinations(range(1,M),N-1):
    nlist2 = [0] + list(nlist1)  +[M]
    print(nlist2)
    for i in range(N):
      dist[i] = ary2[nlist2[i+1]-1] - ary2[nlist2[i]]
    dist_sum = sum(dist)
    if dist_sum < ans:
      ans = dist_sum
  print(ans)


import itertools
N,M = map(int,input().split())
ary1 = map(int,input().split())
if N>=M:
  print(0)
else:
  ary2 = sorted(list(ary1))
  ary3 = ary2[1:]
  ary4 = ary2[:-1]
  d1  = ary2[M-1]-ary2[0]
  dist1 = sorted([i-j for i,j in zip(ary3,ary4)])[M-N:M]
  d2 =  sum(dist1)
  print(d1-d2)

Verdicts: Wrong Answer

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
n, m = map(int, input().split())
if n >= m:
  print(0)
else:
  x = sorted(list(map(int, input().split())))

  y = []
  for i in range(m-1):
    y.append(h[i+1] - h[i])

  y_sorted = sorted(y, reverse=True)

  ans = 0
  for _y in y[n:]:
    ans += _y
  print(ans)

n, m = map(int, input().split())
x = sorted(list(map(int, input().split())))

d = []
for i in range(m - 1):
  d.append(x[i+1] - x[i])
d.sort()

ans = 0
for i in range(m - n):
  ans += d[i]
  
print(ans)

Verdicts: Runtime Error

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
n,m=map(int,input().split())
x=list(map(int,input().split()))
x=sorted(x)
print(x)
sub=[]
for i in range(len(x)-1):
	sub.append(x[i+1]-x[i])
sub=sorted(sub)
print(sub)
print(sum(sub[:-(n-1)]))

n,m=map(int,input().split())
x=list(map(int,input().split()))
x=sorted(x)
sub=[]
for i in range(len(x)-1):
	sub.append(x[i+1]-x[i])
sub=sorted(sub)
if n==1:
	print(sum(sub))
else:
	print(sum(sub[:-(n-1)]))

Verdicts: Wrong Answer

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
import sys
from collections import deque


diff = deque()

N, M = map(int, input().split())
X = list(map(int, input().split()))

if N >= M:
    print(0)
    exit()

X.sort()

for i in range(len(X)-1):
    diff.append(X[i+1]-X[i])

diff = list(diff)
diff.sort()

print(diff)

for i in range(N-1):
    diff.pop()

print(sum(diff))


import sys

diff = deque()

N, M = map(int, input().split())
X = list(map(int, input().split()))
diff = []

if N >= M:
    print(0)
    exit()

X.sort()

for i in range(len(X)-1):
    diff.append(X[i+1]-X[i])

diff.sort()

for i in range(N-1):
    diff.pop()

print(sum(diff))


import sys

diff = deque()

N, M = map(int, input().split())
X = list(map(int, input().split()))

if N >= M:
    print(0)
    exit()

X.sort()

for i in range(len(X)-1):
    diff.append(X[i+1]-X[i])

diff.sort()

for i in range(N-1):
    diff.pop()

print(sum(diff))


import sys

diff = []

N, M = map(int, input().split())
X = list(map(int, input().split()))

if N >= M:
    print(0)
    exit()

X.sort()

for i in range(len(X)-1):
    diff.append(X[i+1]-X[i])

diff.sort()

for i in range(N-1):
    diff.pop()

print(sum(diff))


Verdicts: Wrong Answer

Runtime Error

Runtime Error

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
n, m = map(int, input().split())
if n >= m:
    print(0)
    exit()

lx = sorted(list(map(int, input().split())))

ld = sorted([lx[i+1]-lx[i] for i in range(m-1)])
if n == 1:
    print(sum(ld))
else:
    print(sum(ld[:-(n-1)]))
print(lx, ld)

n, m = map(int, input().split())
if n >= m:
    print(0)
    exit()

lx = sorted(list(map(int, input().split())))

ld = sorted([lx[i+1]-lx[i] for i in range(m-1)])
if n == 1:
    print(sum(ld))
else:
    print(sum(ld[:-(n-1)]))

Verdicts: Wrong Answer

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
N, M = map(int, input().split())
X = [0] * M
X[0:M] = map(int, input().split())
if N >= M:
    print(0)
else:
    Li = sorted(X)
    dff = [abs(X[i] - X[i - 1]) for i in range(1, M)]
    d = sorted(dff)
    out = sum(d[:M-N])
    print(out)

N, M = map(int, input().split())
X = [0] * M
X[0:M] = map(int, input().split())
if N >= M:
    print(0)
else:
    Li = sorted(X)
    dff = [abs(Li[i] - Li[i - 1]) for i in range(1, M)]
    d = sorted(dff)
    print(sum(d[:M - N]))

Verdicts: Wrong Answer

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
N, M, *X = map(int, open(0).read().split())

y = sorted([X[i + 1] - X[i] for i in range(len(X) - 1)])
print(sum(y[:-(N - 1)]))

N, M, *X = map(int, open(0).read().split())
X.sort()

y = sorted([X[i + 1] - X[i] for i in range(len(X) - 1)], reverse=True)
print(sum(y[N - 1:]))

Verdicts: Wrong Answer

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
n,m=map(int,input().split())

if n>=m:
    print(0)
    
else:
    li = sorted(list(map(int,input().split())),reverse=True)

    long=max(li)-min(li)
    dis=[li[i]-li[i+1] for i in range(m-1)]
    dis_sort=sorted(dis,reverse=True)
    print(sum(dis_sort[n:]))

n,m=map(int,input().split())

li = sorted(list(map(int,input().split())),reverse=True)
if n>=m:
    print(0)
    
else:
    long=max(li)-min(li)
    dis=[li[i]-li[i+1] for i in range(m-1)]
    dis_sort=sorted(dis,reverse=True)
    print(sum(dis_sort[n-1:]))

Verdicts: Wrong Answer

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
n , m =map(int,input().split ())
x = [int(i ) for i in input().split()]
y = []
for i in range(len(x)-1):
  y.append(x[i]-x[i-1])
y.sort()
print(sum(y[:n-1]))

n , m =map(int,input().split ())
x = [int(i ) for i in input().split()]
y = []
for i in range(m-1):
  y.append(x[i]-x[i-1])
y.sort()
print(sum(y[:m-n+1]))

n,m = map(int, input().split())
x = [int(i) for i in input().split()]
x.sort()
x2 = []
for i in range(len(x)-1):
  x2.append(x[i+1] - x[i])
x2.sort()
if n < m:
  print(sum(x2[:len(x2) - n + 1]))
else:
  print('0')

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
N, M = map(int, input().split())
X = list(map(int, input().split()))
ans = 0
if M-1-N < 0:
    pass
else:
    X.sort()
    dist = [X[i+1]-X[i] for i in range(M-1)]
    dist.sort()
    for i in range(M-1-N):
        ans += dist[i]
print(ans)

N, M = map(int, input().split())
X = list(map(int, input().split()))
ans = 0
if M-1-N <= 0:
    pass
else:
    X.sort()
    dist = [X[i+1]-X[i] for i in range(M-1)]
    dist.sort()
    for i in range(M-1-N):
        ans += dist[i]
print(ans)

N, M = map(int, input().split())
X = list(map(int, input().split()))
ans = 0
if (M-1)-(N-1) <= 0:
    pass
else:
    X.sort()
    dist = [X[i+1]-X[i] for i in range(M-1)]
    dist.sort()
    for i in range((M-1)-(N-1)):
        ans += dist[i]
print(ans)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
import sys
input=sys.stdin.readline
import math

def main():
    N,_ = map(int, input().split())
    X = list(map(int, input().split()))
    X.sort()
    D = []
    for i in range(len(X)-1):
        D.append([i+1] - X[i])
    D.sort(reverse=True)
    D = D[math.ceil(N/2):]
    n = 0
    for d in D:
        n += d[1]
    print(n)

if __name__ == '__main__':
    main()

import sys
input=sys.stdin.readline
import math

def main():
    N,M = map(int, input().split())
    X = sorted(list(map(int, input().split())))
    D = sorted([X[i+1]-X[i] for i in range(M-1)], reverse=True)
    print(sum(D[N-1:]))

if __name__ == '__main__':
    main()

Verdicts: Runtime Error

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
from itertools import combinations
n, m = map(int, input().split(" "))
if n >= m:
  print(0)
else:
  ls = list(sorted(map(int, input().split(" "))))
  idxes = set( i for i in range(m-1) )
  routes = []
  for v in combinations(idxes, n-1):
    print(v)
    c = 0
    tmp = 0
    for i in v:
      tg = ls[tmp:i+1]
      c += tg[-1] - tg[0]
      tmp = i+1
    c += ls[-1] - ls[tmp]
    routes.append(c)
  print(min(routes))
  

from itertools import combinations
n, m = map(int, input().split(" "))
if n >= m:
  print(0)
else:
  ls = list(sorted(map(int, input().split(" "))))
  total = ls[-1] - ls[0]
  sections = sorted([ls[i+1]-ls[i] for i in range(m-1)], reverse=True)
  print(total-sum(sections[:n-1]))
  


Verdicts: Wrong Answer

Accepted
Problem: We will play a one-player game using a number line and N pieces.  First, we place each of these pieces at some integer coordinate.  Here, multiple pieces can be placed at the same coordinate.  Our objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:  **Move** : Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.  Note that the coordinates where we initially place the pieces are already regarded as visited.  Find the minimum number of moves required to achieve the objective.

Submission attempts (in order):
N, M = map(int, input().split())
X = list(map(int, input().split()))
ans = 0
diff = []

X.sort()

for i in range(M-1):
  dif = X[i+1] -X[i]
  diff.append(dif)
  
diff.sort()

for n in range(N):
  diff.pop(-1)

for i in range(len(diff)):
  ans += diff[i]


N, M = map(int, input().split())
X = list(map(int, input().split()))
ans = 0
diff = []
 
X.sort()
 
for i in range(M-1):
  dif = X[i+1] -X[i]
  diff.append(dif)
  
diff.sort()
 
for n in range(N):
  diff.pop(-1)
 
for i in range(len(diff)):
  ans += diff[i]

print(ans)

N, M = map(int, input().split())
X = list(map(int, input().split()))
ans = 0
diff = []
 
X.sort()
 
for i in range(M-1):
  dif = X[i+1] -X[i]
  diff.append(dif)
  
diff.sort()
 
for n in range(N):
  diff.pop(-1)
 
for i in range(len(diff)):
  ans += diff[i]

print(ans)

N, M = map(int, input().split())
X = list(map(int, input().split()))
ans = 0
diff = []
 
X.sort()

if (N < M): 
  for i in range(M-1):
    dif = X[i+1] -X[i]
    diff.append(dif)
  
  diff.sort()
 
  for n in range(N):
    diff.pop(-1)
 
  for i in range(len(diff)):
    ans += diff[i]

print(ans)

N, M = map(int, input().split())
X = list(map(int, input().split()))
ans = 0
diff = []
 
X.sort()
 
for i in range(M-1):
  dif = X[i+1] -X[i]
  diff.append(dif)
  
diff.sort()

if (N < M):
  for n in range(N):
    diff.pop(-1)
 
  for i in range(len(diff)):
    ans += diff[i]

  print(ans)
else:
  print(ans)

N, M = map(int, input().split())
X = list(map(int, input().split()))
ans = 0
diff = []
 
X.sort()
 
if (N < M): 
    for i in range(M-1):
        dif = X[i+1] - X[i]
        diff.append(dif)
    
    diff.sort()
    
    for i in range(M-N):
        ans += diff[i]
    # for n in range(N):
    #     diff.pop(-1)
   
    
    #     ans += diff[i]
print(ans)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Wrong Answer

Wrong Answer

Accepted