TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
# coding=utf-8

# write code...
import math

a=int(input())
b=int(input())
c=int(input())
d=int(input())
e=int(input())
List1=[a,b,c,d,e]
List2=[(a-1)%10,(b-1)%10,(c-1)%10,(d-1)%10,(e-1)%10]


index=List2.index(min(List2))


ans = math.ceil(a/10)+math.ceil(b/10)+math.ceil(c/10)+math.ceil(d/10)+math.ceil(e/10)-math.ceil(List1[index]/10)+List1[index]/10
ans = int(ans*10)

print(math.ceil(a),index, ans)


# coding=utf-8

# write code...
import math

a=int(input())
b=int(input())
c=int(input())
d=int(input())
e=int(input())
List1=[a,b,c,d,e]
List2=[(a-1)%10,(b-1)%10,(c-1)%10,(d-1)%10,(e-1)%10]


index=List2.index(min(List2))


ans = math.ceil(a/10)+math.ceil(b/10)+math.ceil(c/10)+math.ceil(d/10)+math.ceil(e/10)-math.ceil(List1[index]/10)+List1[index]/10
ans = int(ans*10)

print(ans)


Verdicts: Wrong Answer

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
a = []
for i in range(5):
  a.append(int(input()))

b = [[i, i%10] for i in a]

b.sort(key=lambda x:x[1])
s=b[0][0]
for i in range(1,5):
  s += b[i][0] if b[i][1] == 0 else (b[i][0]+10)//10*10
print(s)

from math import floor, ceil
a = [int(input()) for i in range(5)]
c = sorted(a, key = lambda x: 10 if x % 10 == 0 else x % 10)
ans = c[0]
for i in c[1:]:
  ans += ceil(i/10) * 10
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
foods = [int(input()) for i in range(5)]

li = []
for i in range(5):
    if foods[i] % 10 != 0:
        li.append(10-foods[i]%10)
        foods[i] += (10-foods[i]%10)
if li = []:
    ans = sum(foods)
else:    
    ans = sum(foods) - max(li)
print(ans)

foods = [int(input()) for i in range(5)]

li = []
for i in range(5):
    if foods[i] % 10 != 0:
        li.append(10-foods[i]%10)
        foods[i] += (10-foods[i]%10)
if li == []:
    ans = sum(foods)
else:    
    ans = sum(foods) - max(li)
print(ans)

Verdicts: Runtime Error

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
import sys

lines = [int(input()) for i in range(5)]

time = 0
count = 0

for i,item in enumerate(lines):
	if item%10 == 0:
		time += item
		lines[i] = 0
		count += 1
		print(item)

for i in reversed(range(9)):
	print("#",i)
	for j,item in enumerate(lines):
		if item%10 == i+1:
			time += item
			lines[j] = 0
			count += 1
			if count != 5:
				time += (10 - (i+1))
			print(item,time)

print(time)



import sys

lines = [int(input()) for i in range(5)]

time = 0
count = 0

for i,item in enumerate(lines):
	if item%10 == 0:
		time += item
		lines[i] = 0
		count += 1
		#print(item)

for i in reversed(range(9)):
	#print("#",i)
	for j,item in enumerate(lines):
		if item%10 == i+1:
			time += item
			lines[j] = 0
			count += 1
			if count != 5:
				time += (10 - (i+1))
			#print(item,time)

print(time)



Verdicts: Wrong Answer

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
t = []
ans = 0
for i in range(5):
    a = int(input())
    if a%10 == 0:
        ans += a
    
    else:
         x = 10-a%10
         ans += a + (x)
         t.append(x)
    
print(t)
ans -= max(t)
print(ans)

t = []
ans = 0
for i in range(5):
    a = int(input())
    if a%10 == 0:
        ans += a
        t.append(0)
    
    else:
        x = 10-a%10
        ans += a + x
        t.append(x)
    
ans -= max(t)
print(ans)

Verdicts: Runtime Error

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
time = []
rem = []
for _ in range(5):
    n = int(input())
    time.append(n)
    if n % 10 != 0:
        rem.append(10 - n % 10)

rem.sort()
ans = sum(time) + sum(rem[:4])
# print(time, rem)
print(ans)


time = []
rem = []
for _ in range(5):
    n = int(input())
    time.append(n)
    if n % 10 != 0:
        rem.append(10 - n % 10)

rem.sort()
ans = sum(time) + sum(rem[:len(rem)-1])
# print(time, rem)
print(ans)


Verdicts: Wrong Answer

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
menu,fir_digi=[int(input()) for i in range(5)],[]
for i in range (5):
    fir_digi.append(menu[i]%10)
for i in range (5):
    if i!=fir_digi.index(min(fir_digi)) and fir_digi[i]!=0:
            menu[i]=int(menu[i]/10)*10+10
print(sum(menu))

menu=[int(input()) for i in range(5)]
fir_digi=[menu[i]%10 for i in range(5)]
for i in range (5):
    if i!=fir_digi.index(min(fir_digi)) and fir_digi[i]!=0:
            menu[i]=int(menu[i]/10)*10+10
print(sum(menu))

menu,fir_digi=[int(input()) for i in range(5)],[]
for i in range (5):
    fir_digi.append(menu[i]%10)
while min(fir_digi)==0:
    fir_digi[fir_digi.index(0)]=10
for i in range (5):
    if i!=fir_digi.index(min(fir_digi)) and fir_digi[i]!=10:
            menu[i]=int(menu[i]/10)*10+10
print(sum(menu))

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
s = []
for i in range(5):
    s.append(int(input()))
s1 = [str(e)[-1] for e in s]
s2 = [int(e) if e != '0' else 10 for e in s1]
time_min = s2.index(min(s2))
s_min = s.pop(time_min)
s3 = [-(-e//10)*10 for e in s]
result = sum(s3) + s_min
print(s2, s_min)
print(result)

s = []
for i in range(5):
    s.append(int(input()))
s1 = [str(e)[-1] for e in s]
s2 = [int(e) if e != '0' else 10 for e in s1]
time_min = s2.index(min(s2))
s_min = s.pop(time_min)
s3 = [-(-e//10)*10 for e in s]
result = sum(s3) + s_min
print(result)

Verdicts: Wrong Answer

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
ans=0
t=[]
tmp=10
for i in range(5):
    t.append(int(input()))
    if t[i]%10!=0 and t[i]%10<tmp:
        tmp=t[i]%10
print(tmp)
flg=0
for i in range(5):
    if (t[i]%10!=tmp or flg==1) and t[i]%10==0:
        ans+=t[i]
    elif (t[i]%10!=tmp or flg==1) and t[i]%10!=0:
        ans+=(t[i]//10+1)*10
    elif t[i]%10==tmp and flg==0:
        ans+=t[i]
        flg=1
print(ans)


ans=0
t=[]
tmp=10
for i in range(5):
    t.append(int(input()))
    if t[i]%10!=0 and t[i]%10<tmp:
        tmp=t[i]%10
#print(tmp)
flg=0
for i in range(5):
    if (t[i]%10!=tmp or flg==1) and t[i]%10==0:
        ans+=t[i]
    elif (t[i]%10!=tmp or flg==1) and t[i]%10!=0:
        ans+=(t[i]//10+1)*10
    elif t[i]%10==tmp and flg==0:
        ans+=t[i]
        flg=1
print(ans)


Verdicts: Wrong Answer

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
a = int(input())
b = int(input())
c = int(input())
d = int(input())
e = int(input())
def f(x):
  return -(-x // 10) * 10
def g(x):
  return x % 10
ans = sum(f(i) for i in [a,b,c,d,e])
ans += min(g(i) for i in [a,b,c,d,e])

a = int(input())
b = int(input())
c = int(input())
d = int(input())
e = int(input())
def f(x):
  return -(-x // 10) * 10
def g(x):
  return x % 10
ans = sum(f(i) for i in [a,b,c,d,e])
mo = min(g(i) for i in [a,b,c,d,e])
if mo:
  ans += mo - 10
print(ans)

a = int(input())
b = int(input())
c = int(input())
d = int(input())
e = int(input())
def f(x):
  return -(-x // 10) * 10
def g(x):
  return (x-1) % 10 + 1
ans = sum(f(i) for i in [a,b,c,d,e])
mi = min(g(i) for i in [a,b,c,d,e])
ans += mi - 10
print(ans)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
import math
l = [int(input()) for _ in range(5)]
l_1st = [int(str(0 - int(str(i)[-1]))[-1]) for i in l]
l_rm_i = l_1st.index(max(l_1st))
l_rm = l[l_rm_i]
del l[l_rm_i]

l = [math.ceil(i/10)*10 for i in l]
ans = int((sum(l) + l_rm))
print(ans)

import math
l = [int(input()) for _ in range(5)]
l_1st = [int(str(10 - int(str(i)[-1]))[-1]) for i in l]
print(l_1st)
l_rm_i = l_1st.index(max(l_1st))
l_rm = l[l_rm_i]
del l[l_rm_i]

l = [math.ceil(i/10)*10 for i in l]
ans = int((sum(l) + l_rm))
print(ans)

import math
l = [int(input()) / 10 for i in range(5)]
min_l = min(l)
l.remove(min_l)
l = [math.ceil(i) for i in l]
ans = int((sum(l) + min_l)*10)
print(ans)

import math
l = [int(input()) for _ in range(5)]
l_1st = [int(str(10 - int(str(i)[-1]))[-1]) for i in l]
l_rm_i = l_1st.index(max(l_1st))
l_rm = l[l_rm_i]
del l[l_rm_i]

l = [math.ceil(i/10)*10 for i in l]
ans = int((sum(l) + l_rm))
print(ans)

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
l = [int(input())for i in range(5)]
ans = 0
amari = []
for i in l:
    amari.append(i%10)
amarii = sorted(amari,reverse=True)
amamari = []
for j in amarii:
    amamari.append(10-j)
sumsum = sum(l)
sumsumamari = sum(amamari[:4])
ans = sumsum+sumsumamari
print(ans)

l = [int(input())for i in range(5)]
ans = 0
amari = []
for i in l:
    amari.append(i%10)
amamari = []
for j in amari:
    if j == 0:
        amamari.append(0)
    else:
        amamari.append(10-j)    
amarii = sorted(amamari)
sumsum = sum(l)
sumsumamari = sum(amarii[:4])
ans = sumsum+sumsumamari
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
dishes = [input() for i in range(5)]

sum_time = 0
last_order_surplus = 10

for dish in dishes:
  if last_order_surplus > int(dish) % 10 & int(dish) % 10 != 0:
    last_order_surplus = int(dish) % 10
  if int(dish) % 10 != 0:
    sum_time += int(int(dish) / 10 + 1)
  else:
    sum_time = int(int(dish) / 10)

print (sum_time * 10 + last_order_surplus - 10)

dishes = [input() for i in range(5)]

sum_time = 0
last_order_surplus = 10

for dish in dishes:
  if last_order_surplus > int(dish) % 10 & int(dish) % 10 != 0:
    last_order_surplus = int(dish) % 10
  if int(dish) % 10 != 0:
    sum_time += int(int(dish) / 10 + 1)
  else:
    sum_time += int(int(dish) / 10)

print (sum_time * 10 + last_order_surplus - 10)

Verdicts: Wrong Answer

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
n = [int(input()) for _ in range(5)]
first_digit = []
for num in n:
    z = int(str(num)[-1])
    if z > 0:
        first_digit.append(z)
    else:
        first_digit.append(0.001)


t = 0
for i in range(len(n)):
    t += -(-n[i] // 10) * 10

print(int(t - (10 - min(first_digit))))


n = [int(input()) for _ in range(5)]
first_digit = []
for num in n:
    z = int(str(num)[-1])
    if z > 0:
        first_digit.append(z)



t = 0
for i in range(len(n)):
    t += -(-n[i] // 10) * 10
if len(first_digit) == 0:
    print(t)
else:
    print(t - (10 - min(first_digit)))


Verdicts: Wrong Answer

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
import math

cook = []
for i in range (5):
    cook.append(int(input()))

times = 0

min_10 = []
for c in range(len(cook)):
    min_10.append((cook[c] - 1) % 10)  

min_index = min_10.index(min(min_10))
print(min_10, min_index)
total_time = 0
for c in range(len(cook)):
    if min_index == c:
        continue
    else:
        total_time += int(math.ceil(cook[c] / 10) * 10)
total_time += cook[min_index]

print(total_time)

import math

cook = []
for i in range (5):
    cook.append(int(input()))

times = 0

min_10 = []
for c in range(len(cook)):
    min_10.append((cook[c] - 1) % 10)  

min_index = min_10.index(min(min_10))
total_time = 0
for c in range(len(cook)):
    if min_index == c:
        continue
    else:
        total_time += int(math.ceil(cook[c] / 10) * 10)
total_time += cook[min_index]

print(total_time)


Verdicts: Wrong Answer

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
import math

A = int(input())
B = int(input())
C = int(input())
D = int(input())
E = int(input())

def roof(n):
    return math.ceil(n/10) * 10

def mod(n):
    return n % 10

low = map(mod, [A,B,C,D,E])
top = map(roof, [A,B,C,D,E])

low = [i for i in low if i != 0]

ans = sum(top) + min(low)
print(ans)


import math

A = int(input())
B = int(input())
C = int(input())
D = int(input())
E = int(input())

def roof(n):
    return math.ceil(n/10) * 10

def mod(n):
    return n % 10

low = map(mod, [A,B,C,D,E])
top = map(roof, [A,B,C,D,E])

low = [i for i in low if i != 0]

if low == []: low = [10]
ans = sum(top) + min(low) - 10
print(ans)


Verdicts: Runtime Error

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
import math
time_list=[]

for _ in range(5):
    time_list.append(int(input()))
# print(1, time_list)

time_list2=[]
for x in time_list:
    m = x % 10
    if m!=0:
        time_list2.append(x+(10-m))
    else:
        time_list2.append(x)
# print("2", time_list2)
# print(round(102,-1))

mod_list = []
for x in time_list:
    m = x % 10
    mod_list.append(10-m)

        
min_ = max(mod_list)
# print(mod_list)



print(sum(time_list2)-min_)

import math
time_list=[]

for _ in range(5):
    time_list.append(int(input()))
# print(1, time_list)

time_list2=[]
for x in time_list:
    m = x % 10
    time_list2.append(x+(10-m))
# print("2", time_list2)
# print(round(102,-1))

mod_list = []
for x in time_list:
    m = x % 10
    if m!=0:
        mod_list.append(10-m)
min_ = max(mod_list)
# print(mod_list)



print(sum(time_list2)-min_)

import math
time_list=[]

for _ in range(5):
    time_list.append(int(input()))
# print(1, time_list)

time_list2=[]
for x in time_list:
    m = x % 10
    if m!=0:
        time_list2.append(x+(10-m))
    else:
        time_list2.append(x)
# print("2", time_list2)

mod_list = []
for x in time_list:
    m = x % 10
    if m!=0:
        mod_list.append(m)
    else:
        mod_list.append(10)
min_ = min(mod_list)
# print(mod_list)



print(sum(time_list2)-(10-min_))

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
l=[]
for i in range(5):
  n=[]
  a=input()
  n.append(int(a[-1]))
  n.append(int(a))
  l.append(n)
t=0
for i in l:
  if i[0]==0:
    t=t+i[1]
    l.remove(i)
print(t)
    

import math
L1=[int(input())/10 for i in range(5)]
L2=[]
for i in L1:
  L2.append(math.ceil(i)*10)
L3=[]
for i in range(5):
  L3.append(sum(L2)-L2[i]+L1[i]*10)
print(int(min(L3)))

Verdicts: Wrong Answer

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
# -*- coding: utf-8 -*-

import math

a, b, c, d, e = int(input()), int(input()), int(input()), int(input()), int(input())

ans = math.ceil(a / 10)
ans += math.ceil(b / 10)
ans += math.ceil(c / 10)
ans += math.ceil(d / 10)
ans += math.ceil(e / 10)
ans *= 10
ans += min(a % 10, b % 10, c % 10, d % 10, e % 10) - 10

print(ans)


# -*- coding: utf-8 -*-

import math

As = [int(input()) for _ in range(5)]

ans = 0
for A in As:
    ans += math.ceil(A / 10) * 10

ans += min([(A - 1) % 10 for A in As]) - 10 + 1
print(ans)


Verdicts: Wrong Answer

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
from decimal import Decimal, ROUND_UP
 
l = [int(input()) for _ in range(5)]
min_remainder = 10 - min([x%10 for x in l if x%10 > 0]+[0])
print(sum([int(Decimal(x).quantize(Decimal("1E1"), rounding=ROUND_UP)) for x in l]) - min_remainder)

from decimal import Decimal, ROUND_UP
 
l = [int(input()) for _ in range(5)]
if len([x%10 for x in l if x%10 > 0]) > 0:
    min_remainder = 10 - min([x%10 for x in l if x%10 > 0])
    print(sum([int(Decimal(x).quantize(Decimal("1E1"), rounding=ROUND_UP)) for x in l]) - min_remainder)
else:
    print(sum([int(Decimal(x).quantize(Decimal("1E1"), rounding=ROUND_UP)) for x in l]))

Verdicts: Wrong Answer

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
inputs=[int(input()) for i in range(5)]
summ=0
k=0
for i in inputs:
    if i%10==0:
        summ=summ+i
    else:
        s,m=divmod(i,10)
        summ=summ+(s+1)*10
		if 10-m>10-k:
          k=m
summ=summ-10+k
print(summ)


inputs = [int(input()) for i in range(5)]
summ = 0
k = 10
for i in inputs:
    if i % 10 == 0:
        summ = summ + i
    else:
        s, m = divmod(i, 10)
        summ = summ + (s + 1) * 10
        if m < k:
            k = m

summ = summ +((10-k)%10)
print(summ)

inputs=[int(input()) for i in range(5)]
summ=0
for i in inputs:
    if i%10==0:
        summ=summ+i
    else:
        s=i//10
        summ=summ+(s+1)*10
print(summ)


inputs=[int(input()) for i in range(5)]
summ=0
k=0
for i in inputs:
    if i%10==0:
        summ=summ+i
    else:
        s,m=divmod(i,10)
        summ=summ+(s+1)*10
        if 10-m>10-k:
          k=m
summ=summ-10+k
print(summ)

inputs = [int(input()) for i in range(5)]
summ = 0
k = 10
for i in inputs:
    if i % 10 == 0:
        summ = summ + i
    else:
        s, m = divmod(i, 10)
        summ = summ + (s + 1) * 10
        if m < k:
            k = m

summ = summ -((10-k)%10)
print(summ)

Verdicts: Runtime Error

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
dish = []
for i in range(5):
    dish.append(int(input()))
print(sum([d // 10 + (d % 10 > 0) for d in dish]) * 10 + sorted([d % 10 for d in dish])[0] - 10)

dish = []
for i in range(5):
    dish.append(int(input()))
tmp1 = sum([d // 10 + (d % 10 > 0) for d in dish]) * 10
tmp2 = sum(sorted([d % 10 for d in dish if d % 10 > 0])[:1])
if tmp2 > 0:
    print(tmp1 + tmp2 - 10)
else:
    print(tmp1)

Verdicts: Wrong Answer

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
#! /usr/bin/env python3
# -*- coding: utf-8 -*-
ls = []
for i in range(5):
    ls.append(int(input()))

lasttime = 10
for a in ls:
    b = a%10
    if b < lasttime:
        lasttime = b
        ans =a

ls.remove(ans)
sum =0
for i in ls:
    if i%10 ==0:
        sum +=i
    else:
        p = i//10
        sum += (p+1)*10

print(int(sum + ans)



#! /usr/bin/env python3
# -*- coding: utf-8 -*-
ls = []
for i in range(5):
    ls.append(int(input()))

lasttime = 10
for a in ls:
    b = a%10
    if b < lasttime:
        lasttime = a

ls.pop(a)
sum =0
for i in ls:
    if i%10 ==0:
        sum +=i
    else:
        p = i//10
        sum += (p+1)*10

print(sum)



#! /usr/bin/env python3
# -*- coding: utf-8 -*-
ls = []
for i in range(5):
    ls.append(int(input()))

lasttime = 10
for a in ls:
    b = a%10
    if b < lasttime:
        lasttime = a

ls.remove(a)
sum =0
for i in ls:
    if i%10 ==0:
        sum +=i
    else:
        p = i//10
        sum += (p+1)*10

print(sum + a)



#! /usr/bin/env python3
# -*- coding: utf-8 -*-
ls = []
for i in range(5):
    ls.append(int(input()))

lasttime = 10
for a in ls:
    b = a%10
    if b < lasttime:
        lasttime = b
        ans =a

ls.remove(ans)
sum =0
for i in ls:
    if i%10 ==0:
        sum +=i
    else:
        p = i//10
        sum += (p+1)*10

print(int(sum + ans))



#! /usr/bin/env python3
# -*- coding: utf-8 -*-
ls = []
for i in range(5):
    ls.append(int(input()))
ls2 = [i%10 for i in ls]
if ls2 == [0,0,0,0,0]:
    print(sum(ls))
else:
    lasttime = 10
    for a in ls:
        b = a%10
        if b < lasttime and b != 0:
            lasttime = b
            ans =a

    ls.remove(ans)
    sum =0
    for i in ls:
        if i%10 ==0:
            sum +=i
        else:
            p = i//10
            sum += (p+1)*10

    print(int(sum + ans))



Verdicts: Runtime Error

Runtime Error

Wrong Answer

Wrong Answer

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
import math
import sys
import numpy

a = list(mat(int,input().split()))
b = []
for i in range(5):
    b.append(a[i]%10)
mx = min(b)
ans = 0
for i in range(5):
    if mx == a[i]:
        continue
    else :
        ans += (a[i]+10-(a[i]%10))
ans += mx
print(ans)

import math
import sys
import numpy

a = []
for _ in range(5):
    a.append(int(input()))

ans = 0
Q = []
for i in a:
    if i % 10 != 0:
        Q.append(10 - i%10)
    ans += i
Q.sort(reverse=True)
print(ans + sum(Q[1:]))

Verdicts: Runtime Error

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
xs = [int(input()) for i in range(5)]
ps = []
for x in xs:
	ps.append(((x-1)%10+1, x))
ps.sort()
ans = 0
ans += ps[0][1]
for i in range(1, 5):
	print(ps[i])
	ans += (ps[i][1] + 9) // 10 * 10
print(ans)


xs = [int(input()) for i in range(5)]
ps = []
for x in xs:
	ps.append(((x-1)%10+1, x))
ps.sort()
ans = 0
ans += ps[0][1]
for i in range(1, 5):
	ans += (ps[i][1] + 9) // 10 * 10
print(ans)


Verdicts: Wrong Answer

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
flag = False
mini = 124
time = 0
for _ in range(5):
    A = int(input())
    if A%10 == 0:
        time += A
    else:
        time += A - A%10 + 10
        mini = min(A%10, mini)
    print(time)
time += mini - 10
print(time)

flag = False
mini = 124
time = 0
for _ in range(5):
    A = int(input())
    if A%10 == 0:
        time += A
    else:
        time += A - A%10 + 10
        mini = min(A%10, mini)
        flag = True
if flag:
    time += mini - 10
print(time)

Verdicts: Wrong Answer

Accepted
Problem: The restaurant AtCoder serves the following five dishes:    * ABC Don (rice bowl): takes A minutes to serve.   * ARC Curry: takes B minutes to serve.   * AGC Pasta: takes C minutes to serve.   * APC Ramen: takes D minutes to serve.   * ATC Hanbagu (hamburger patty): takes E minutes to serve.  Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.  This restaurant has the following rules on orders:    * An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).   * Only one dish can be ordered at a time.   * No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.  E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.   Here, he can order the dishes in any order he likes, and he can place an order already at time 0.

Submission attempts (in order):
lst = []
for i in range(5):
    lst.append(int(input()))
lst_f=[]
for i in range(5):
    lst_f.append(lst[i]%10)
while 0 in lst_f:
    lst_f.remove(0)
if len(lst_f) == 0:
    print(sum(lst))
else:
    print(sum(lst)-sum(lst_f)+10*(4-lst_f.count(0))+min(lst_f))

lst = []
for i in range(5):
    lst.append(int(input()))
lst_f=[]
for i in range(5):
    lst_f.append(lst[i]%10)
while 0 in lst_f:
    lst_f.remove(0)
if len(lst_f) == 0:
    lst_f.append(0)
print(sum(lst)-sum(lst_f)+10*(5-lst_f.count(0))+min(lst_f))

lst = []
for i in range(5):
    lst.append(int(input()))
lst_f=[]
for i in range(5):
    lst_f.append(lst[i]%10)
while 0 in lst_f:
    lst_f.remove(0)
if len(lst_f) == 0:
    print(sum(lst))
else:
    print(sum(lst)-sum(lst_f)+10*(len(lst_f)-1)+min(lst_f))

Verdicts: Wrong Answer

Wrong Answer

Accepted