TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
def resolve():
    N, M = [int(i) for i in input().split()]
    llrr = [list(map(int, input().split())) for _ in range(M)]
    maxL = 1
    minR = N
    for l, r in llrr:
        maxL = max(maxL, l)
        minR = min(minR, r)
    ans = minR - maxL + 1
    if ans < 0:
        print(0)
    else:
        print(ans)


def resolve():
    N, M = [int(i) for i in input().split()]
    llrr = [list(map(int, input().split())) for _ in range(M)]
    maxL = 1
    minR = N
    for l, r in llrr:
        maxL = max(maxL, l)
        minR = min(minR, r)
    ans = minR - maxL + 1
    if ans < 0:
        print(0)
    else:
        print(ans)


resolve()

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
LR = [list(map(int,input().split())) for i in range(M)]
count = 0

for i in range(N):
  for j in range(M):
    if LR[j][0] <= i <= LR[j][1]:
      count += 1

print(count)

N, M = map(int, input().split())
L = [0] * M
R = [0] * M

for i in range(M):
  L[i], R[i] = map(int,input().split())
  
count = 1

for i in range(N):
  if max(L) <= i <= min(R):
    count += 1

print(count)

N, M = map(int, input().split())
L = [0] * M
R = [0] * M

for i in range(M):
  L[i], R[i] = map(int,input().split())

print(max(0, min(R) - max(L) + 1))

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
from collections import defaultdict
n, m = map(int, input().split())
left = []
right = []
for i in range(m):
    l, r = map(int, input().split())
    left.append(l)
    right.append(r)

if min(right) < max(left):
    print(min(right) - max(left) + 1)
else:
    print(0)


from collections import defaultdict
n, m = map(int, input().split())
left = []
right = []
for i in range(m):
    l, r = map(int, input().split())
    left.append(l)
    right.append(r)

if min(right) >= max(left):
    print(min(right) - max(left) + 1)
else:
    print(0)


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input().split())
a=0
b=n*10**9
A=True
for i in range(m):
  x,y=map(int,input().split())
    a=max(a,x)
    b=min(b,y)
if b>=a:
  ans=b-a+1
  print(ans)
else:
  print(0)

n,m=map(int,input().split())
a=0
b=n*10**9
for i in range(m):
  x,y=map(int,input().split())  
  a=max(a,x)
  b=min(b,y)
if b>=a:
  ans=b-a+1
  print(ans)
else:
  print(0)


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
l = []
r = []
for i in range(m):
    a,b = map(int,input().split())
    l.append(a)
    r.append(b)
ans = 0
for j in range(1,n+1):
    cnt = 0
    for i in range(m) :
        if l[i] <= j or r[i] == j:
            cnt += 1
            continue
        break
    if cnt == m:
        ans += 1

print(ans)

n,m=map(int,input().split())
l=0
r=99999999
for i in range(m):
  a,b=map(int,input().split())
  l=max(l,a)
  r=min(r,b)
if r>=l:
  print(r-l+1)
else:
  print(0)


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M=map(int,input().split())
l=1
r=N
for i in range(M):
  L,R=map(int,input().split())
  if L>l:
    l=L
  if R<r:
    r=R
    
if l<=r:
  print(l-r+1)
  
else:
  print(0)
  

N,M=map(int,input().split())
l=1
r=N
for i in range(M):
  L,R=map(int,input().split())
  if L>l:
    l=L
  if R<r:
    r=R
    
if l<=r:
  print(r-l+1)
  
else:
  print(0)
  


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
# -*- coding: utf-8 -*-
n, m = map(int, input().split())
ids = [list(map(int, input().split())) for _ in range(m)]
l = []
r = []
for id in ids:
        l.append(id[0])
        r.append(id[1])
if max(r) <= min(r):
        print(min(r) - max(l) + 1)
else:
        print(0)


# -*- coding: utf-8 -*-
n, m = map(int, input().split())
ids = [list(map(int, input().split())) for _ in range(m)]
l = []
r = []
for id in ids:
        l.append(id[0])
        r.append(id[1])
if min(r) < max(r):
        print(0)
else:
        print(min(r) - max(l) + 1)


# -*- coding: utf-8 -*-
n, m = map(int, input().split())
ids = [list(map(int, input().split())) for _ in range(m)]
l = []
r = []
for id in ids:
        l.append(id[0])
        r.append(id[1])
if max(l) <= min(r):
        print(min(r) - max(l) + 1)
else:
        print(0)


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
left, right = 1, n
for _ in range(m):
  l, r = map(int, input().split())
  if l > left:
    left = l
  if r < right:
    right = r
  if l > r:
    print(0)
    quit()
if right > n:
  
print(right - left + 1)

n, m, *lst = map(int, input().split())
l = max(lst[::2])
r = min(lst[1::2])
if l > r:
  print(0)
else:
  print(r - l + 1)


def main():
  _, _, *lst = map(int, open(0).read().split())
  l, r = max(lst[::2]), min(lst[1::2])
  print(0 if l > r else r - l + 1)

main()

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
#C
N, M = map(int, input().split())
Table = [list(map(int, input().split())) for _ in range(M)]
Table.sort(key=lambda x:x[0])
Table.sort(key=lambda x:x[1])
#print(f'Table:{Table}')
first = Table[0][0]
end = Table[0][1]
Table.pop(0)

#print(f'first:{first} end:{end}')
for task in Table:
    #print(f'task:{task}')
    num = task[0]
    #print(f'num:{num}')
    if num <= end:
        first = num
    else:
        ans = 0
        break

if ans == 0:
    print(ans)
else:
    print(end-first+1)

#C
N, M = map(int, input().split())
Table = [list(map(int, input().split())) for _ in range(M)]
Table.sort(key=lambda x:x[0])
Table.sort(key=lambda x:x[1])
#print(f'Table:{Table}')
first = Table[0][0]
end = Table[0][1]
Table.pop(0)
ans = 1
#print(f'first:{first} end:{end}')
for task in Table:
    #print(f'task:{task}')
    num = task[0]
    #print(f'num:{num}')
    if num <= end:
        if num > first:
            first = num
    else:
        ans = 0
        break
    #print(f'first:{first}')
if ans == 0:
    print(ans)
else:
    print(end-first+1)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=list(map(int, input().split() ))
Firstlis=[]
Secondlis=[]
for i in range(m):
  s=list(map(int,inout().split()))
S1=s[0]
S2=s[1]
Firstlis.append(S1)
Secondlis.append(S2)
Min=max(Firstlis)
Max=min(Secondlis)
print(Max-Min)


  


n,m=list(map(int, input().split() ))
Firstlis=[]
Secondlis=[]
for i in range(m):
  s=list(map(int,input().split()))
S1=s[0]
S2=s[1]
Firstlis.append(S1)
Secondlis.append(S2)
Min=max(Firstlis)
Max=min(Secondlis)
print(Max-Min+1)



  


n,m=list(map(int, input().split() ))
Firstlis=[]
Secondlis=[]
for i in range(m):
  s=list(map(int,input().split()))
S1=s[0]
S2=s[1]
Firstlis.append(S1)
Secondlis.append(S2)
Min=max(Firstlis)
Max=min(Secondlis)
if Max>=Min:
    print(Max-Min+1)
else:
    print(0)




  


n,m=list(map(int, input().split() ))
ists=[]
for i in range(m):
  s=list(map(int,inout().split()))
  ists.append(s)
ans=0
justified=True
for j in range(n):
  for k in range(m):
    if ists[k][0]<=j<=ists[k][1]:
      continue
    else:
      justified=False
      break
  if justified:
    ans+=1
    justified=True

print(ans)
  


n,m=list(map(int,input().split()))
ists=[]
for i in range(m):
  s=list(map(int,inout().split()))
  ists.append(s)
ans=0
justified=True
for j in range(n):
  for k in range(m):
    if ists[k][0]<=j<=ists[k][1]:
      continue
    else:
      justified=False
      break
  if justified:
    ans+=1
print(ans)
  

n,m=list(map(int, input().split() ))
Firstlis=[]
Secondlis=[]
for i in range(m):
  s=list(map(int,input().split()))
  S1=s[0]
  S2=s[1]
  Firstlis.append(S1)
  Secondlis.append(S2)
Min=max(Firstlis)
Max=min(Secondlis)
if Max>=Min:
    print(Max-Min+1)
else:
    print(0)




  


Verdicts: Runtime Error

Wrong Answer

Wrong Answer

Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
L, R = [0] * M, [0] * M
Lmax, Rmin = 0, 1e10
for i in range(M):
    L, R = map(int, input().split())
    if L > Lmax:
        Lmax = L
    if R < Rmin:
        Rmin = R

print(Lmax, Rmin)
print(max(Rmin - Lmax + 1, 0))

N, M = map(int, input().split())
L, R = [0] * M, [0] * M
Lmax, Rmin = 0, 1e10
for i in range(M):
    L, R = map(int, input().split())
    if L > Lmax:
        Lmax = L
    if R < Rmin:
        Rmin = R

print(max(Rmin - Lmax + 1, 0))

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
def resolve():
    n, m = map(int, input().split())
    for i in range(m):
        l, r = map(int, input().split())
        if i == 0:
            start = l
            end = r
        else:
            if start <= l:
                start = l
            if r <= end:
                end = r
    if start > end:
        print(0)
    else:
        print(end-start+1)

def resolve():
    n, m = map(int, input().split())
    for i in range(m):
        l, r = map(int, input().split())
        if i == 0:
            start = l
            end = r
        else:
            if start <= l:
                start = l
            if r <= end:
                end = r
    if start > end:
        print(0)
    else:
        print(end-start+1)
resolve()

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
a,b = map(int,input().split())
# a=int(input())
lmax=0
rmin=b
for i in range(b):
    l,r = map(int,input().split())
    if l >= lmax:
        lmax = l
    if r <= rmin:
        rmin = r
print(max(rmin-lmax+1,0))

a,b = map(int,input().split())
# a=int(input())
lmax=0
rmin=a
for i in range(b):
    l,r = map(int,input().split())
    if l >= lmax:
        lmax = l
    if r <= rmin:
        rmin = r
print(max(rmin-lmax+1,0))

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M=map(int,input().split())
list1=[list(map(int,input().split())) for i in range(M)]
start=[]
end=[]
for i in range(M):
    start.append(list1[i][0])
    end.append(list1[i][1])
stmax=max(start)
print(stmax)
enmax=min(end)
print(enmax)
print(enmax-stmax+1)


N,M=map(int,input().split())
list1=[list(map(int,input().split())) for i in range(M)]
start=[]
end=[]
for i in range(M):
    start.append(list1[i][0])
    end.append(list1[i][1])
stmax=max(start)
#print(stmax)
enmax=min(end)

if enmax>=stmax:
    print(enmax-stmax+1)
else:
    print(0)


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
def main():
    LR = open(0).read().split()[2:]
    max_L = max(map(int, LR[::2]))
    min_R = min(map(int, LR[1::2]))
    print(min_R - max_L + 1 if max_L <= min_M else 0)
    return


main()

def main():
    LR = open(0).read().split()[2:]
    MAX_L = max(map(int, LR[::2]))
    MIN_R = min(map(int, LR[1::2]))
    print(MIN_R - MAX_L + 1 if MAX_L <= MIN_R else 0)
    return


main()

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M = map(int,input().split())

Ss = [list(map(int,input().split()))[1:] for _ in range(M)]
Ps = list(map(int,input().split()))

ans = 0
switch_pattern_num = 2**N

for i in range(switch_pattern_num):
    binary = format(i,'0%ib'%N)
    satisfied = True
    for j,S in enumerate(Ss):
        count = 0
        for e in S:
            if int(binary[e-1]):
                count += 1
        if count % 2 != Ps[j]:
            satisfied = False
    if satisfied:
        ans += 1
print(ans)



N, M = map(int,input().split())
LRs = [list(map(int,input().split())) for _ in range(M)]

current_L = 1
current_R = N
for L,R in LRs:
    if current_L < L:
        current_L = L
    if current_R > R:
        current_R = R


if current_R < current_L:
    print(0)
else:
	print(current_R-current_L+1)
        


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
ll = []
rl = []

for i in range(m):
  l,r = list(map(int,input().split()))
  ll.append(l)
  rl.append(r)
  
if min(rr)<max(ll):
  print("0")

else:
  print(abs(max(rr)-min(ll)+1))

n,m = map(int,input().split())
ll = []
rl = []
 
for i in range(m):
  l,r = list(map(int,input().split()))
  ll.append(l)
  rl.append(r)
  
if min(rl)<max(ll):
  print("0")
 
else:
  print(abs(min(rl)-max(ll)+1))

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
l = 1
r = m
for _ in range(m):
    li, ri = map(int, input().split())
    l = max(l, li)
    r = min(r, ri)

print(r - l + 1 if r >= 1 else 0)


n, m = map(int, input().split())
l = 1
r = 10 ** 5
for _ in range(m):
    li, ri = map(int, input().split())
    l = max(l, li)
    r = min(r, ri)

print(r - l + 1 if r >= l else 0)


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
S = []
N, M = input().split(" ")
for m in range(len(int(M))):
  S.append(set([i for i in range(int(a),int(b)+1)]))
if M == 1:
  print(len(S[0]))
else:
  sets = S[0]
  for i in range(1,M):
    sets = sets & S[i]
  print(len(sets))

N, M = input().split(" ")
#S = []
if M == 1:
    a, b = input().split(" ")
    print(int(b)-int(a)+1)
else:    
    a, b = input().split(" ")
    aM, bm = int(a),int(b)
    
    for m in range(int(M)-1):
        a, b = input().split(" ")
        aM = max(aM,int(a))
        bm = min(bm,int(b))
        
    if(bm<aM):
        print(0)
    else:
        print(int(bm)-int(aM)+1)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
l = []
r = []
for i in range(m):
  A, B = list(map(int,input().split()))
  l.append(A)
  r.append(B)

min = 0
max = n
for i in range(m):
  if min < l[i]:
    min = l[i]
  if max > r[i]:
    max = r[i]

print(min, max)
if max - min + 1 > 0:
  print(max - min + 1)
else:
  print(0)

n,m = map(int,input().split())
l = []
r = []
for i in range(m):
  A, B = list(map(int,input().split()))
  l.append(A)
  r.append(B)

min = 0
max = n
for i in range(m):
  if min < l[i]:
    min = l[i]
  if max > r[i]:
    max = r[i]

if max - min + 1 > 0:
  print(max - min + 1)
else:
  print(0)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
res = [0,10**5]
for i in ragne(m):
    l, r = map(int, input().split())
    res[0] = max(res[0], l)
    res[1] = min(res[1], r)

print(max(res[1]-res[0]+1),0)

n, m = map(int, input().split())
res = [0,10**5]
for i in ragne(m):
    l, r = map(int, input().split())
    res[0] = max(res[0], l)
    res[1] = min(res[1], r)

print(max(res[1]-res[0]+1,0))

n, m = map(int, input().split())
res = [0,10**5]
for i in range(m):
    l, r = map(int, input().split())
    res[0] = max(res[0], l)
    res[1] = min(res[1], r)

print(max(res[1]-res[0]+1,0))

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
L, R = [], []

for i in range(M):
    l, r = map(int, input().split())
    L.append(l), R.append(r)

if max(L) <= min(R):
    print(max(R) - min(L) + 1)
else:
    print(0)

N, M = map(int, input().split())
L, R = [], []

for i in range(M):
    l, r = map(int, input().split())
    L.append(l), R.append(r)

if max(L) <= min(R):
    print(min(R) - max(L) + 1)
else:
    print(0)


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M=map(int,input().split())
L=[-1]*M
R=[-1]*M
for i in range(M):
  L[i],R[i] =map(input().split())
  
print(min(R)-max(L)+1)


N, M = map(int, input().split())
LR = [tuple(map(int, input().split())) for i in range(M)]

l = 1
r = N
for i in range(M):
    l = max(l, LR[i][0])
    r = min(r, LR[i][1])

ans = max(0, r - l + 1)
print(ans)


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import sys
import numpy as np

N, M = input().split()

N = int(N)
M = int(M)

cnt = 0

NM = np.zeros([M,N])

for i in range(M):
    A = input().split()
    NM[i,int(A[0]):int(A[1])] = 1.0

s = np.sum(NM,axis=0)

print(np.sum(s==M))

import sys
import numpy as np

N, M = input().split()

N = int(N)
M = int(M)

cnt = 0

NM = np.zeros([M,N])

for i in range(M):
    A = input().split()
    NM[i,int(A[0])-1:int(A[1])] = 1.0

print(NM)

s = np.sum(NM,axis=0)
print(s)

print(np.sum(s==M))

def main():
    N, M = map(int, input().split())

    left = 1
    right = N

    for _ in range(M):
        l, r = map(int, input().split())

        if left < l:
            left = l
        if right > r:
            right = r

    ans = right - left

    print(ans + 1 if ans >= 0 else 0)


main()


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
r={i for i in range(1,n+1)}
for i in range(m):
	l,r = map(int,input().split())
	g = { i for i in range(l,r+1)}
	r = r&g
	if r == {} :
		print(0)
		break
print(len(r))


n,m = map(int,input().split())
L = []
R = []
for i in range(m):
	l,r = map(int,input().split())
	L.append(l)
	R.append(r)

l = L[0]
r = R[0]
cnt = 0
for i in range(max(L),min(R)+1) :
	if 0<=i<=r :
		cnt += 1
print(cnt)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m  = map(int,input().split())
lr =[list(map(int,input().split()))for _ in range(m)]

lr.sort(reverse = True)
ansl = lr[0][0]
ansr = 10**9
for i in range(m):
    r = lr[i][1]
    if r < ansl:
        ansr = min(ansr,r)
ans = max(0,ansr-ansl+1)

print(ans)




n,m  = map(int,input().split())
lr =[list(map(int,input().split()))for _ in range(m)]

lr.sort(reverse = True)
ansl = lr[0][0]
ansr = 10**9
for i in range(m):
    r = lr[i][1]
    if r < ansr:
        ansr = min(ansr,r)
ans = max(0,ansr-ansl+1)

print(ans)




Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n = list(map(int,input().split()))
l = [list(map(int,input().split())) for i in range(n[1])]
minp = l[0][0]
maxp = l[0][1]
for t in range(n[1]):
    minp = max(minp,l[t][0])
    maxp = min(maxp,l[t][1])

print(max(0,minp-maxp)+1)

n = list(map(int,input().split()))
l = [list(map(int,input().split())) for i in range(n[1])]

passcard = []
for c in range(l[0][1] - l[0][0]+1):
    passcard.append(l[0][0]+c)

for t in range(n[1],0):
    for i in range(len(passcard)):
        if not(l[t][0] <= passcard[i] <= l[t][1]):
            passcard[i] = 0
        else:
            passcard[i] = passcard[i]
    passcard = [i for i in passcard if i!=0]
            
out = [i for i in passcard if i!=0]
print(len(out))

n = list(map(int,input().split()))
l = [list(map(int,input().split())) for i in range(n[1])]
minp = l[0][0]
maxp = l[0][1]
for t in range(n[1]):
    minp = max(minp,l[t][0])
    maxp = min(maxp,l[t][1])
print(max(0,maxp-minp+1))

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import sys
import math
import itertools
import collections
import heapq
import re
import numpy as np

rr = lambda: sys.stdin.readline().rstrip()
rs = lambda: map(str, sys.stdin.buffer.readline().split())
ri = lambda: int(sys.stdin.readline())
rm = lambda: map(int, sys.stdin.buffer.readline().split())
rl = lambda: list(map(int, sys.stdin.readline().split()))
inf = float('inf')
mod = 10**9 + 7

n, m = rm()
l = 0
r = inf
for _ in range():
  a, b = rm()
  a = max(a, l)
  b = min(b, inf)
print(b-a+1)



import sys
import math
import itertools
import collections
import heapq
import re
import numpy as np

rr = lambda: sys.stdin.readline().rstrip()
rs = lambda: map(str, sys.stdin.buffer.readline().split())
ri = lambda: int(sys.stdin.readline())
rm = lambda: map(int, sys.stdin.buffer.readline().split())
rl = lambda: list(map(int, sys.stdin.readline().split()))
inf = float('inf')
mod = 10**9 + 7

n, m = rm()
l = 0
r = inf
for _ in range(m):
  a, b = rm()
  l = max(a, l)
  r = min(b, r)
c = r-l+1
if c >= 1:
  print(c)
else:
  print(0)



Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import sys
n ,m = map(int, input().split())
L = []
R = []
for i in range(m):
    l, r = map(int, input().split())
    if r - l <= 0:
        print(0)
        sys.exit(0) 
    L.append(l)
    R.append(r)

print(max(R) - max(L) + 1)

n ,m = map(int, input().split())
result = set()
first = True
for i in range(m):
    l, r = map(int, input().split())
    tmp = set()
    for i in range(l, r + 1):
        tmp.add(i)
    if first:
        result = tmp
        # print("tmp {}".format(tmp))
        first = False
    else:
        result = result.intersection(tmp)
        # print("result {} tmp {}".format(result, tmp))

print(len(result))n ,m = map(int, input().split())
result = set()
first = True
for i in range(m):
    l, r = map(int, input().split())
    tmp = set()
    for i in range(l, r + 1):
        tmp.add(i)
    if first:
        result = tmp
        first = False
    else:
        result = result.intersection(tmp)
print(len(result))

n ,m = map(int, input().split())
L = []
R = []
for i in range(m):
    l, r = map(int, input().split())
    L.append(l)
    R.append(r)
if max(L) <= min(R):
    print(min(R) - max(L) + 1)
else:
    print(0)

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = (int(x) for x in input().split())
A = [int(x) for x in input().split()]
B = [0] * M
C = [0] * M
Bsum = 0
for i in range(M):
    B[i], C[i] = (int(x) for x in input().split())
    Bsum += B[i]

N, M = (int(x) for x in input().split())
Lmax = -1
Rmin = N + 1
for i in range(M):
    L, R = (int(x) for x in input().split())
    if Lmax < L:
        Lmax = L
    if Rmin > R:
        Rmin = R
if (Rmin - Lmax) >= 0:
    print(Rmin - Lmax + 1)
else:
    print(0)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
ans = [i for i in range(1, n + 1)]

for _ in range(m):
    x, y = map(int, input().split())
    tmp = [i for i in range(x, y + 1)]
    for ele in tmp:
        ans.remove(ele)
print(n - len(ans))

n, m = map(int, input().split())
ans = [i for i in range(1, n + 1)]

l_max = 0
r_min = n

for _ in range(m):
    x, y = map(int, input().split())
    l_max = max(l_max, x)
    r_min = min(r_min, y)

print(len([i for i in range(l_max, r_min + 1)]))


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
l, r = 0, m
for _ in range(m):
    l_in, r_in = map(int, input().split())
    l = max(l, l_in)
    r = min(r, r_in)
print(max(r-l+1, 0))


n, m = map(int, input().split())
l, r = 0, n
for _ in range(m):
    l_in, r_in = map(int, input().split())
    l = max(l, l_in)
    r = min(r, r_in)
print(max(r-l+1, 0))


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input().split())
L=0
R=n
for i in range(m):
    l,r=map(int,input().split())
    if l>L:
        L=l
    if r<R:
        R=r
if R-L<0:
    print(0)
else:
    print(R-L)

n,m=map(int,input().split())
L=0
R=n
for i in range(m):
    l,r=map(int,input().split())
    if l>L:
        L=l
    if r<R:
        R=r
if R-L<0:
    print(0)
else:
    print(R-L+1)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
maxL = 1
minR = n
for i in range(m):
    l, r = map(int ,input().split())
    maxL = max(l, maxL)
    minR = min(r, minR)
if(maxL < minR):
    print(0)
else:
    print(minR - maxL + 1)


n, m = map(int, input().split())
maxL = 1
minR = n
for i in range(m):
    l, r = map(int ,input().split())
    maxL = max(l, maxL)
    minR = min(r, minR)
if(maxL > minR):
    print(0)
else:
    print(minR - maxL + 1)


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
gates = []
for i in range(m):
    gates.append(list(map(int, input().split())))
candidate = [1, n]
for gate in gates:
    if candidate[0] < gate[0]:
        candidate[0] = gate[0]
    if gate[1] < candidate[1]:
        candidate[1] = gate[1]
if candidate[1] == canditate[0]:
    print(0)
else:
    print(candidate[1] - candidate[0] + 1)

n, m = map(int, input().split())
gates = []
for i in range(m):
    gates.append(list(map(int, input().split())))
candidate = [1, n]
for gate in gates:
    if candidate[0] < gate[0]:
        candidate[0] = gate[0]
    if gate[1] < candidate[1]:
        candidate[1] = gate[1]
if (candidate[1] >= candidate[0]):
    print(candidate[1] - candidate[0] + 1)
else:
    print(0)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import bisect
N,M = map(int,input().split())
L_list,M_list = [],[]
for i in range(M):
    l,m = map(int,input().split())
    L_list.append(l)
    M_list.append(m)

L_list.sort()
M_list.sort()
lmax = L_list[-1]
mmin = M_list[0]
min = bisect.bisect_left(n,lmax)
max = bisect.bisect_left(n,mmin)
if min == max:
    ans = 1
else:
    ans = max - min
    ans += 1
print(ans)


N,M = map(int,input().split())
lmax,mmin = 0,1000000
for i in range(M):
    l,m = map(int,input().split())
    if lmax < l:
        lmax = l
    if mmin > m:
        mmin = m

if lmax > mmin:
    ans = 0
elif lmax == mmin:
    ans = 1
else:
    ans = mmin-lmax
    ans += 1
print(ans)


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input().split())
ltmp=1,rtmp=n
for i in range(m):
  l,r=map(int,input().split())
  ltmp=max(l,ltmp)
  rtmp=min(r,rtmp)
if ltmp>rtmp:
  print(0)
else:
  print(rtmp-ltmp+1)

n,m=map(int,input().split())
ltmp=1
rtmp=n
for i in range(m):
  l,r=map(int,input().split())
  ltmp=max(l,ltmp)
  rtmp=min(r,rtmp)
if ltmp>rtmp:
  print(0)
else:
  print(rtmp-ltmp+1)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M =map(int, input().split())
L,R =[],[]

for i in range(M+1):
  x,y = map(int,input().split())
  L.append(x)
  R.append(y)

print(max(0,min(R)-max(L))

N,M =map(int, input().split())
L,R =[],[]

for i in range(M+1):
  x,y = map(int,input().split())
  L.append(x)
  R.append(y)

print(max(0,min(R)-max(L)+1))

N,M =map(int, input().split())
L,R =[],[]
 
for i in range(M):
  x,y = map(int,input().split())
  L.append(x)
  R.append(y)
 
print(max(0,min(R)-max(L)+1))

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input().rstrip().split(' '))
maxL=0,minR=n+1
for i in range(m):
  l,r=map(int,input().rstrip().split(' '))
  maxL = max(maxL,l)
  minR = min(minR,r)
print(max(minR-maxL+1,0))

n,m=map(int,input().rstrip().split(' '))
maxL=0
minR=n+1
for i in range(m):
  l,r=map(int,input().rstrip().split(' '))
  maxL = max(maxL,l)
  minR = min(minR,r)
print(max(minR-maxL+1,0))

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
from itertools import accumulate

n, m = map(int, input().split())
cards = [0] * (n+1)
for i in range(m):
  s, e = map(int, input().split())
  cards[s] += 1
  cards[e] -= 1
valids = accumulate(cards)
print(valids.count(n))

from itertools import accumulate

n, m = map(int, input().split())
cards = [0] * (n+2)
for i in range(m):
  s, e = map(int, input().split())
  cards[s] += 1
  cards[e+1] -= 1
valids = list(accumulate(cards))
print(valids.count(m))


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
l = []
r = []
for i in range(m):
  t = tuple(map(int,input().split()))
  l.append(t[0])
  r.append(t[1])
l,r=max(l),min(r)
if l<=r:
  print(l-r+1)
else:
  print(0)

n,m = map(int,input().split())
l = []
r = []
for i in range(m):
  t = tuple(map(int,input().split()))
  l.append(t[0])
  r.append(t[1])
l,r=max(l),min(r)
if l<=r:
  print(abs(l-r)+1)
else:
  print(0)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M =list(map(int,input().split()))
la=1
rm=N
for i in range(M):
  a,b=list(map(int,input().split()))
  la=max(la,a)
  rm=min(rm,b)
print(max(0,la-rm+1))



N,M =list(map(int,input().split()))
la=1
rm=N
for i in range(M):
  a,b=list(map(int,input().split()))
  la=max(la,a)
  rm=min(rm,b)
print(max(0,rm-la+1))



Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
def main():

    N,M=map(int,input().split())
    #undivList=[map(int,(input().split())) for _ in range(N)]
    undivList=[]
    for _ in range(M):
        l=map(int,input().split())
        undivList +=l
    atmax=max(undivList[0::2])
    atmin=min(undivList[1::2])
    
    if atmax>atmin:
        print(0)
    else:
        print(atmax-atmin+1)



if __name__== "__main__":
    main() 

def main():

    N,M=map(int,input().split())
    #undivList=[map(int,(input().split())) for _ in range(N)]
    undivList=[]
    for _ in range(M):
        l=map(int,input().split())
        undivList +=l
    atmax=max(undivList[0::2])
    atmin=min(undivList[1::2])
    
    if atmax-atmin < 0:
		print(0)
    else:
		print(abs(atmax-atmin)+1)

    


if __name__== "__main__":
    main() 

def main():

    N,M=map(int,input().split())
    #undivList=[map(int,(input().split())) for _ in range(N)]
    undivList=[]
    for _ in range(M):
        l=map(int,input().split())
        undivList +=l
    atmax=max(undivList[0::2])
    atmin=min(undivList[1::2])
    
    if atmax>atmin:
        print(0)
    else:
        print(abs(atmax-atmin)+1)



if __name__== "__main__":
    main() 

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
def main():
    N, M = map(int, input().split())
    lr = [
        list(map(int, input().split()))
        for _ in range(M)
    ]

    ans = f(N, M, lr)
    
    print(ans)


def f(N, M, lr):
    
    import numpy as np
    a = np.zeros(N, dtype=int)
    for L, R in lr:
        a[L-1:R] += 1

    ans = (a == N).sum()
    return ans


def TLE(N, M, lr):
    ans = 0
    for i in range(1, N+1):
        g = 0
        for L, R in lr:
            if L <= i <= R:
                g += 1
        if g == M:
            ans += 1

    return ans


if __name__ == '__main__':
    main()


def main():
    N, M = map(int, input().split())
    LR = [
        list(map(int, input().split()))
        for _ in range(M)
    ]

    ans = f(N, M, LR)
    ans1 = cumsum(N, M, LR)
    assert ans == ans1
    # ans = WA(N, M, LR)
    # ans = TLE(N, M, LR)
    print(ans)


def cumsum(N, M, LR):
    a = [0] * (N + 1)
    for L, R in LR:
        a[L-1] += 1
        a[R] -= 1

    from itertools import accumulate
    a = accumulate(a)
    ans = sum(x == M for x in a)
    return ans


def WA(N, M, LR):
    import numpy as np
    a = np.zeros(N, dtype=int)
    for L, R in LR:
        a[L-1:R] += 1
    ans = (a == M).sum()
    return ans


def f(N, M, LR):
    l_max = max(L for L, _ in LR)
    r_min = min(R for _, R in LR)

    ans = r_min - l_max + 1
    ans = max(ans, 0)
    return ans


def TLE(N, M, LR):
    ans = 0
    for i in range(1, N+1):
        g = 0
        for L, R in LR:
            if L <= i <= R:
                g += 1
        if g == M:
            ans += 1

    return ans


if __name__ == '__main__':
    main()


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input().split())
l=-10000000
r=10000000

for i in range(m):
  c,d=map(int,input().split())
  if l<c:
    l=c
  if d<r:
    r=d
    
print(min(r-l+1,0))


n,m=map(int,input().split())
l=-10000000
r=10000000

for i in range(m):
  c,d=map(int,input().split())
  if l<c:
    l=c
  if d<r:
    r=d
    
print(max(r-l+1,0))


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int,input().split())
LR = set(list(map(int,input().split())) for _ in range(M))

cnt = 0
for i in range(N):
  tmp = 0
  for L, R in LR:
    if L-1 <= i <= R-1:
      tmp += 1
    else:
      break
    if tmp == M:
      cnt += 1
      break
print(cnt)

N, M = map(int,input().split())
LR = [list(map(int,input().split())) for _ in range(M)]

Lma = 0
Rmi = 0
for L, R in LR:
  Lma = max(L, Lma)
  Rmi = min(R, Rmi)

print(max(0, Rmi - Lma + 1))

N, M = map(int,input().split())
LR = [list(map(int,input().split())) for _ in range(M)]

Lma = 0
Rmi = 0
for L, R in LR:
  Lma = max(L, Lma)
  Rmi = min(R, Rmi)

print(max(0, Lma - Rmi + 1))

N, M = map(int,input().split())
LR = [list(map(int,input().split())) for _ in range(M)]

Lma = 0
Rmi = N + 1
for L, R in LR:
  Lma = max(L, Lma)
  Rmi = min(R, Rmi)

print(max(0, Rmi - Lma + 1))

Verdicts: Runtime Error

Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
#v = list(map(int,input().split()))

#a = [0 for _ in range(n+1)]
ml = -1
mr = 10**6
for i in range(m):
  l,r = map(int,input().split())
  ml = max(ml,l)
  mr = min(mr,r)
  
res = ml - mr + 1
print(res)

n,m = map(int,input().split())
#v = list(map(int,input().split()))

#a = [0 for _ in range(n+1)]
ml = -1
mr = 10**6
for i in range(m):
  l,r = map(int,input().split())
  ml = max(ml,l)
  mr = min(mr,r)
if mr < ml :
  res = 0
else:
  res = mr-ml + 1

print(res)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
l, m = map(int, input().split())
for _ in range(M-1):
    new_l, new_r = map(int, input().split())
    if l < new_l:
        l = new_l
    if new_r < r:
        r = new_r

print(r-l+1)


N, M = map(int, input().split())
l, r = map(int, input().split())
for _ in range(M-1):
    new_l, new_r = map(int, input().split())
    if l < new_l:
        l = new_l
    if new_r < r:
        r = new_r

score = r-l+1
if score > 0:
    print(score)
else:
    print(0)


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = [int(_) for _ in input().split()]

ls = []
rs = []
for i in range(m):
    lr = [int(_) for _ in input().split()]
    ls.append(lr[0])
    rs.append(lr[1])

print(min(min(rs) - max(ls) + 1, 0))


n, m = [int(_) for _ in input().split()]

ls = []
rs = []
for i in range(m):
    lr = [int(_) for _ in input().split()]
    ls.append(lr[0])
    rs.append(lr[1])

print(max(min(rs) - max(ls) + 1, 0))


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M=map(int,input().split())
L=[]
R=[]
for i in range(M):
  l,r=map(int,input().split())
  L.append(l)
  R.append(r)
count=0
for i in range(1,N+1):
  if min(L)>i or i>max(R):
    break
  else:
    count+=1
print(count)

N,M=map(int,input().split())
L=[]
R=[]
for i in range(M):
  l,r=map(int,input().split())
  L.append(l)
  R.append(r)
count=0
for i in range(1,N+1):
  if max(L)<=i<=min(R):
    count+=1
  else:
    break
print(count)

N,M=map(int,input().split())
L=[]
R=[]
for i in range(M):
  l,r=map(int,input().split())
  L.append(l)
  R.append(r)
count=0
if max(L)>min(R):
  print(0)
else:
  print(min(R)-max(L)+1)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())

l = []
r = []
for i in range(m):
    temp = input().split()
    l.append(int(temp[0]))
    r.append(int(temp[1]))

a = min(l)
b = max(r)

ans = b - a + 1
if ans <= 0:
    ans = 0
print(ans)

n, m = map(int, input().split())

l = []
r = []
for i in range(m):
    temp = tuple(map(int, input().split()))
    l.append(temp[0])
    r.append(temp[1])

a = min(l)
b = max(r)

print(b - a + 1)

n, m = map(int, input().split())

l = []
r = []
for i in range(m):
    temp = input().split()
    l.append(int(temp[0]))
    r.append(int(temp[1]))

a = max(l)
b = min(r)

ans = b - a + 1
if ans <= 0:
    ans = 0
print(ans)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = list(map(int, input().split()))
max_l = 1
min_r = 100000
for _ in range(m):
    l, r = list(map(int, input().split()))
    if l > max_l:
        max_l = l
    if r < min_r:
        min_r = r
ans = min_r - max_l -1
print(ans)

n, m = list(map(int, input().split()))
max_l = 0
min_r = 100000
for _ in range(m):
    l, r = list(map(int, input().split()))
    if l > max_l:
        max_l = l
    if r < min_r:
        min_r = r
ans = min_r - max_l
print(ans)

n, m = list(map(int, input().split()))
max_l = 1
min_r = 100000
for _ in range(m):
    l, r = list(map(int, input().split()))
    if l > max_l:
        max_l = l
    if r < min_r:
        min_r = r
ans = min_r - max_l + 1
if ans < 0:
    print(0)
else:
    print(ans)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
LR = [list(map(int, input().split())) for _ in range(N)]

l_list = [LR[i][0] for i in range(M)]
r_list = [LR[i][1] for i in range(M)]

l = max(l_list)
r = min(r_list)
if r-l <= 0:
    print(0)
else:
    print(r-l+1)

N, M = map(int, input().split())
LR = [list(map(int, input().split())) for _ in range(M)]

l_list = [LR[i][0] for i in range(M)]
r_list = [LR[i][1] for i in range(M)]

l = max(l_list)
r = min(r_list)

if r-l < 0:
  print(0)
else:
  print(r-l+1)

Verdicts: Runtime Error

Accepted