TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
num = int(input())
a_i = list(map(int, input().split()))
s = 0
for x in a_i:
    s ^= x
ans = []
for x in a_i:
    ans.append(x ^ s)
print(ans)

num = int(input())
a_i = list(map(int, input().split()))
s = 0
for x in a_i:
    s ^= x
ans = []
for x in a_i:
    ans.append(x ^ s)
print(' '.join(map(str, ans)))

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
import numpy as np

n = int(input())
a = list(map(int, input().split()))

b = [0]*n
for i in range(n):
  b[i] = list(map(int, bin(a[i])[2:][::-1]))

l = max(map(len, b))
b_pad = list(map(lambda x: x + [0]*(l-len(x)), b))

for j in range(n):
  b_add = (np.sum(b_pad,axis=0) - np.array(b_pad[j])) % 2
  ans = 0
  for k in range(l):
    ans += (2**(k))*b_add[k]
  print(ans,end=" ")

n = int(input())
a = list(map(int, input().split()))

s = a[0]
for i in range(1,n):
  s ^= a[i]

ans = [0]*n
for j in range(n):
  ans[j] = s ^ a[j]

print(*ans)

Verdicts: Time Limit Exceeded

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
import copy


n = int(input())
lst = list(map(int,input().split(' ')))

for i in range(n):
    l = copy.deepcopy(lst)
    del l[i]
    buf = 0
    for ll in l:
        buf ^= ll
    print(buf)

n = int(input())
lst = list(map(int,input().split(' ')))

x = 0
for l in lst:
    x ^= l
out = ''
for l in lst:
    out += ' ' + str(x^l)
print(out[1:])

Verdicts: Time Limit Exceeded

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n = int(input())
a = list(map(int,input().split()))
ans = []
tmp = a[0]
for i in range(1,n):
    tmp = tmp^a[i]
for i in range(n):
    ans.append(tmp^a[i])
print(ans)

n = int(input())
a = list(map(int,input().split()))
ans = []
tmp = a[0]
for i in range(1,n):
    tmp = tmp^a[i]
ans = ''
for i in range(n):
    ans += str(int(tmp^a[i]))+' '
print(ans[:-1])

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
N = int(input())
a = list(map(int,input().split()))
#xor_a = [bin(x) for x in a]
#print(xor_a)
b = [sum(a) ^ a[x] for x in range(N)]

print(' '.join(map(str, b))) 

N = int(input())
a = list(map(int, input().split()))
b = [sum(a) ^ a[x] for x in range(N)]
print(' '.join(map(str, b)))

#N = int(input())
a = list(map(int,input().split()))
#xor_a = [bin(x) for x in a]
#print(xor_a)
#sum_xor = bin(sum(a))
b = [sum(a) ^ a[x] for x in range(len(a))]
print(b)

N = int(input())
a = list(map(int,input().split()))
#xor_a = [bin(x) for x in a]
#print(xor_a)
x = 0
for i in a:
    x ^= i
b = [x^y for y in a]
print(' '.join(map(str, b))) 


Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
N = int(input())
A = [int(i) for i in input().split()]
  
O = [0] * N

for i in range(N):
  for j in range(N):
    if i == j:
      continue
    O[i] ^= A[j]

print(O)

N = int(input())
A = [int(i) for i in input().split()]
  
O = [0] * 4

for i in range(N):
  for j in range(N):
    if i == j:
      continue
    O[i] ^= A[j]

print(O)

N = int(input())
SUM = 0
A = []
O = []
for i in input().split():
  i = int(i)
  SUM ^= i
  A.append(i)

for a in A:
  O.append(SUM ^ a)

print(' '.join([str(s) for s in O]))

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
N = int(input())
A = list(map(int, input().split()))

lis = []
for a in A:
    stra = str(a)
    S = '0b'
    i = 0
    for s in stra:
        s = 0 | (a >> i)
        if i%2 == 0:
            S = s + S
        else:
            if s == '0':
                S = '1' + S
            else:
                S = '0' + S
        i += 1
    lis.append(int(S))
print(*S)

N = int(input())
A = list(map(int, input().split()))

lis = []
for a in A:
    S = 0
    i = 0
    for i in range(30):
        s = 0 | (a >> i)
        if i%2 == 0:
            if s == 1:
                S += 2**i
        else:
            if s == 0:
                S += 2**i
        i += 1
    lis.append(S)
print(*lis)

N = int(input())
A = list(map(int, input().split()))

X = 0
for a in A:
    X = X ^ a

lis = []
for a in A:
    Y = X ^ a
    lis.append(Y)
print(*lis)

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
import sys
N = int(sys.stdin.readline().rstrip())
A = list(map(int, sys.stdin.readline().rstrip().split()))
S= 0
for n in range(N):
  S = S^A[n]
  print(S)
  
ans = ''
for n in range(N):
  m = S^A[n]
  ans += str(m) + ' '

print(ans)

import sys
N = int(sys.stdin.readline().rstrip())
A = list(map(int, sys.stdin.readline().rstrip().split()))
S= 0
for n in range(N):
  S = S^A[n]
  
ans = ''
for n in range(N):
  m = S^A[n]
  ans += str(m) + ' '

print(ans[:-1])

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n=int(input())
A=list(map(int,input().split()))
A.append(A[0])
B=[]
C=[]

def xor(C):
  total=0
  for i in range(1,len(C)):
    total^=C[i]
  return total

for i in range(n):
  B.append(A[i]^A[i+1])

for i in range(1,100000):
  C.append(i)
  p=i
  for j in range(n-1):
    C.append(B[j]^p)
    p^=B[j]
  if xor(C)==A[0]:
    break
  else:
    C.clear()

print(C)

def xsum(A):
    total=0
    for i in range(len(A)):
        total^=A[i]
    return total

n=int(input())
A=list(map(int,input().split()))
B=[0]*n
total=xsum(A)
for i in range(n):
    B[i]=total^A[i]
B_str=[str(i) for i in B]
print(' '.join(B_str))

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n=int(input())
a=list(map(int,input().split()))

for i in range(n-1):
    c=a[i]^a[i+1]

ans=[0]*n
for i in range(n):
    ans[i]=c^a[i]
L=[str(a) for a in ans]
L=" ".join(L)
print(L)


n=int(input())
a=list(map(int,input().split()))

c=a[0]
for i in range(n-1):
    c=c^a[i+1]

ans=[0]*n
for i in range(n):
    ans[i]=c^a[i]
L=[str(a) for a in ans]
L=" ".join(L)
print(L)


Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
N = int(input())
A = list(map(int, input().split()))
sum_of_A = sum(A)
ans = []
for a in A:
    ans.append((sum_of_A-a)^a)
print(" ".join(map(str, ans)))


N = int(input())
A = list(map(int, input().split()))
sum_of_A = sum(A)
ans = []
for a in A:
    ans.append(sum_of_A^a)
print(" ".join(map(str, ans)))


N = int(input())
A = list(map(int, input().split()))
sum_of_A = A[0]
for a in A[1:]:
    sum_of_A ^= a
ans = []
for a in A:
    ans.append((sum_of_A)^a)
print(" ".join(map(str, ans)))


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n = int(input())
a = sorted(list(map(int, input().split())))
x = 0
for i in a:
    x ^= i
for i in range(n):
    a[i] ^= x
print(*a)

n = int(input())
a = list(map(int, input().split()))
x = 0
for i in a:
    x ^= i
for i in range(n):
    a[i] ^= x
print(*a)

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n = int(input())
A = list(map(int, input().split()))
ans = list()
for i in range(n-2):
    for j in range(i+1, n-1):
        for k in range(j+1, n):
            ans.append(A[i]^A[j]^A[k])
print(*ans)

n = int(input())
A = list(map(int, input().split()))
base = 0
for a in A:
    base = base ^ a
ans = [base^a for a in A]
print(*ans)

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
N = int(input())
a = [int(i) for i in input().split()]

now = 1
print(now)

for i in range(N-1):
    A = a[i]^a[i+1]
    now = A^now
    print(now)

N = int(input())
a = [int(i) for i in input().split()]

all_a = 0
for i in range(N):
    all_a = all_a^a[i]

ans = []
for i in range(N):
    ans.append(all_a^a[i])
print(*ans)

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n = int(input())
a = input().split(" ")

s = a[0]

for num in a[1:]:
	s^=num

ans = [0]*n

for i, num in enumerate(a):
	ans[i] = s^num

print(*ans)


n = int(input())
a = input().split(" ")

s = a[0]

for num in a[1:]:
	s ^= num

ans = [0]*n

for i, num in enumerate(a):
	ans[i] = s^num

print(*ans)

n = int(input())
aa = input().split(" ")
a = [int(c) for c in aa]

s = a[0]

for num in a[1:]:
	s ^= num

ans = [0]*n

for i, num in enumerate(a):
	ans[i] = s^num

print(*ans)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n = int(input())
aa = map(int,input().split())
x = 0
for a in aa:
  x^=a
print(" ".join(str(x^a) for a in aa ))

n = int(input())
aa = list(map(int,input().split()))
x = 0
for a in aa:
  x^=a
print(" ".join([str(x^a) for a in aa ]))

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
# import sys
# readline = sys.stdin.readline
# generator = (readline().strip() for _ in range(N))

# N, M = map(int, input().split())
# As = list(map(int, input().split()))
# queries = (input() for _ in range(N))


def solve():
    N = int(input())
    As = list(map(int, input().split()))

    digits = dict()
    for d in range(30):
        digits[d] = 0
        for a in As:
            digits[d] += a >> d & 1

    oore = dict()
    for k, v in digits.items():
        oore[k] = v % 2

    nums = [0] * N

    # for i, a in enumerate(As):
    #     for d in range(30):
    #         nums[i] += ((a >> d & 1) ^ (oore[d])) << d

    return nums


def main():
    print(*solve())


if __name__ == "__main__":
    main()


# import sys
# readline = sys.stdin.readline
# generator = (readline().strip() for _ in range(N))

# N, M = map(int, input().split())
# As = list(map(int, input().split()))
# queries = (input() for _ in range(N))


def solve():
    N = int(input())
    As = list(map(int, input().split()))

    digits = dict()
    for d in range(30):
        digits[d] = 0
        for a in As:
            digits[d] += a >> d & 1

    oore = 0
    for k, v in digits.items():
        oore += (v % 2) << k

    nums = [0] * N

    for i, a in enumerate(As):
        nums[i] = a ^ oore

    return nums


def main():
    print(*solve())


if __name__ == "__main__":
    main()


Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
import sys
sys.setrecursionlimit(10**9)

def mi(): return map(int,input().split())
def lmi(): return list(map(int,input().split()))
def ii(): return int(input())
def isp(): return input().split()



n=ii()
a=lmi()
S=0
for i in a:
  S=S^i

b=[]
for i in a:
  a_=S^i
  b.append(a_)

  print(' '.join(map(str,b)))

n=int(input())
a=list(map(int,input().split()))

s=0
for i in a:
  s^=i
 
t=[]
for i in a:
  t_=i^s
  t.append(t_)
  
print(' '.join(map(str,t)))
  

Verdicts: Runtime Error

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n = int( input() )
a = list( map(int, input().split()) )
x = 0
for i in a:
    x ^= i
print( * list( map( lamda y: x^y , a ) ) )

n = int( input() )
a = list( map(int, input().split()) )
x = 0
for i in a:
    x ^= i
print( * list( map( lambda y: x^y , a ) ) )

Verdicts: Runtime Error

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n = int(input())
a = list(map(int, input().split()))

m = max(a)
ans = [0] * n
z = 1
while True:
  b = False
  for i in range(n):
    if a[i] & z:
      b = not b
  for i in range(n):
    if b:
      if a[i] & z:
        ans[i] |= z
    else:
      if not (a[i] & z):
        ans[i] |= z

  z <<= 1
  if z > m:
    break

print(' '.join([str(x) for x in ans]))


n = int(input())
a = list(map(int, input().split()))

m = max(a)
ans = [0] * n
z = 1
while True:
  b = False
  for i in range(n):
    if a[i] & z:
      b = not b
  for i in range(n):
    if not b:
      if a[i] & z:
        ans[i] |= z
    else:
      if not (a[i] & z):
        ans[i] |= z

  z <<= 1
  if z > m:
    break

print(' '.join([str(x) for x in ans]))

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
N = int(input())
A = map(int, input().split())
total = 0
for a in A:
  total ^= a
result = []
for a in A:
  result.append(total ^ a)
print(*result)

N = int(input())
A = map(int, input().split())
total = 0
for a in A:
  total ^= a
result = []
for a in A:
  result.append(total ^ a)
print(result)

N = int(input())
A = list(map(int, input().split()))
total = 0
for a in A:
  total ^= a
result = []
for a in A:
  result.append(total ^ a)
print(*result)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
import sys
stdin = sys.stdin
sys.setrecursionlimit(10**6)
ni = lambda: int(ns())
na = lambda: list(map(int, stdin.readline().split()))
nn = lambda: list(stdin.readline().split())
ns = lambda: stdin.readline().rstrip()

n = ni()
a = na()

print(*a)

import sys
stdin = sys.stdin
sys.setrecursionlimit(10**6)
ni = lambda: int(ns())
na = lambda: list(map(int, stdin.readline().split()))
nn = lambda: list(stdin.readline().split())
ns = lambda: stdin.readline().rstrip()

n = ni()
a = na()
b = 0
for i in a:
    b ^= i

for i in range(n):
    a[i] ^= b

print(*a)

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
N = int(input())
a = list(map(int, input().split()))
ans = [0]
for i in range(N-1):
  ans.append(ans[-1]^a[i]^a[i+1])
print(" ".join(map(str,ans)))

N = int(input())
A = list(map(int, input().split()))
 
XOR = 0
for a in A:
  XOR ^= a
for i in range(N):
  A[i] = A[i]^XOR
print(*A)

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
import numpy as np

N = int(input())
a = np.fromstring(input(), sep=" ", dtype=np.int64)
# b = np.bitwise_xor.reduce(a)
# c = np.bitwise_xor(a, b)
# print(*c, sep=" ")
for n in range(N):
    print(np.bitwise_xor.reduce(a) ^ a[n])


import numpy as np

N = int(input())
a = np.fromstring(input(), sep=" ", dtype=np.int64)
for n in range(N):
    print(np.bitwise_xor.reduce(a) ^ a[n])


import numpy as np

N = int(input())
a = np.fromstring(input(), sep=" ", dtype=np.int64)
b = np.bitwise_xor.reduce(a)
c = np.bitwise_xor(a, 0)
print(*c, sep=" ")


import numpy as np

N = int(input())
a = np.fromstring(input(), sep=" ", dtype=np.int64)
b = np.bitwise_xor.reduce(a)
c = np.bitwise_xor(a, b)
print(*c, sep=" ")


Verdicts: Time Limit Exceeded

Time Limit Exceeded

Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
N = int(input())
A = list(map(int, input().split()))
A = A + A
ans = [0] * N
a = 0
for i in range(N-1):
    a ^= A[i]
ans[N-1] = a
W = N - 1
for i in range(N-1):
    remove = A[i]
    addition = A[i+W]
    a = remove^a^addition
    ans[i] = a

print(" ".join([str(i) for i in ans))


N = int(input())
A = list(map(int, input().split()))
A = A + A
ans = [0] * N
a = 0
for i in range(N-1):
    a ^= A[i]
ans[N-1] = a
W = N - 1
for i in range(N-1):
    remove = A[i]
    addition = A[i+W]
    a = remove^a^addition
    ans[i] = a

print(" ".join([str(i) for i in ans]))


Verdicts: Runtime Error

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
import sys

input = sys.stdin.readline


def S():
    return input().rstrip()


def I():
    return int(input())


def MI():
    return map(int, input().split())


n = I()
A = list(MI())

s = 0
for a in A:
    s ^= a

ans = []
for a in A:
    ans.append(str(s ^ a))

print(" ".join(ans[::-1]))


import sys

input = sys.stdin.readline


def S():
    return input().rstrip()


def I():
    return int(input())


def MI():
    return map(int, input().split())


n = I()
al = list(MI())

s = 0
for a in al:
    s ^= a

ans = []
for a in al:
    ans.append(str(s ^ a))

print(" ".join(ans[::-1]))


import sys

input = sys.stdin.readline


def S():
    return input().rstrip()


def I():
    return int(input())


def MI():
    return map(int, input().split())


n = I()
A = list(MI())

s = 0
for a in A:
    s ^= a

ans = []
for a in A:
    ans.append(str(s ^ a))

print(*ans)


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n = int(input())
A = list(map(int, input().split()))

xor = 0
for a in A:
    xor ^= a
result = []
for a in A:
    result.append(xor ^ a)
print(result)

n = int(input())
A = list(map(int, input().split()))

xor = 0
for a in A:
    xor ^= a
result = []
for a in A:
    result.append(str(xor ^ a))
print(' '.join(result))

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
import sys
from typing import Callable, List, NoReturn

import numpy as np


def main() -> NoReturn:
    readline: Callable[[], str] = sys.stdin.readline
    n: int = int(readline().rstrip())
    a: np.ndarray = np.array(tuple(int(_) for _ in readline().rstrip().split()))

    xor_all: int = 0
    for a_n in a:
        xor_all ^= a_n

    values = np.bitwise_xor(a, xor_all)
    print(" ".join(values))


if __name__ == '__main__':
    main()


import sys
from typing import Callable, List, NoReturn

import numpy as np


def main() -> NoReturn:
    readline: Callable[[], str] = sys.stdin.readline
    n: int = int(readline().rstrip())
    a: np.ndarray = np.array(tuple(int(_) for _ in readline().rstrip().split()))

    xor_all: int = 0
    for a_n in a:
        xor_all ^= a_n

    values = np.bitwise_xor(a, xor_all)
    print(" ".join(tuple(str(v) for v in  values)))


if __name__ == '__main__':
    main()


Verdicts: Runtime Error

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
N = int(input())
A = map(int, input().split())
ax = 0
ans = []
for a in A:
  ax ^= a
for a in A:
  ans.append(a^ax)
  
print(" ".join(map(str,ans)))

N = int(input())
A = list(map(int, input().split()))
b = 0
for a in A:
    b ^= a
ans = []
for a in A:
    ans.append(str(a^b))
print(" ".join(ans))

Verdicts: Wrong Answer

Accepted