Problem: We have two desks: A and B. Desk A has a vertical stack of N books on it, and Desk B similarly has M books on it.  It takes us A_i minutes to read the i-th book from the top on Desk A (1 \leq i \leq N), and B_i minutes to read the i-th book from the top on Desk B (1 \leq i \leq M).  Consider the following action:    * Choose a desk with a book remaining, read the topmost book on that desk, and remove it from the desk.  How many books can we read at most by repeating this action so that it takes us at most K minutes in total? We ignore the time it takes to do anything other than reading.

Submission attempts (in order):
import sys
sys.setrecursionlimit(1000000)
N, M, K = map(int, input().split())
A = list(map(int, input().split()))
B = list(map(int, input().split()))

rest = K
ans = 0

def dfs(cost, aindex, bindex, score):

    if K == cost:
        print("1:", score, cost)
        return score
    elif K < cost:
        print("2:", score, cost)
        return score - 1
    
    if aindex == N and bindex == M:
        print("3:", score, cost)
        return score

    elif aindex >= N:
        return dfs(cost + B[bindex], aindex, bindex+1, score + 1)
    
    elif bindex >= M:
        return dfs(cost + A[aindex], aindex+1, bindex, score + 1)

    else:
        return max(dfs(cost + A[aindex], aindex+1, bindex, score + 1), dfs(cost + B[bindex], aindex, bindex + 1, score + 1))

print(max(dfs(A[0], 1, 0, 1), dfs(B[0], 0, 1, 1)))

N, M, K = map(int, input().split())
A = list(map(int, input().split()))
B = list(map(int, input().split()))

AA = list(reversed(A))
BB = list(reversed(B))

rest = K
ans = 0

def dfs(cost, aindex, bindex, score):

    if K == cost:
        # print("1:", score, cost)
        return score
    elif K < cost:
        # print("2:", score, cost)
        # return score - 2
        return -1
    
    if aindex == N and bindex == M:
        # print("3:", score, cost)
        return score

    if aindex >= N:
        return dfs(cost + B[bindex], aindex, bindex+1, score + 1)
    
    elif bindex >= M:
        return dfs(cost + A[aindex], aindex+1, bindex, score + 1)

    else:
        return max(dfs(cost + A[aindex], aindex+1, bindex, score + 1), dfs(cost + B[bindex], aindex, bindex + 1, score + 1))

print(max(dfs(A[0], 1, 0, 1), dfs(B[0], 0, 1, 1)))

import sys
sys.setrecursionlimit(10e9)
N, M, K = map(int, input().split())
A = list(map(int, input().split()))
B = list(map(int, input().split()))

AA = list(reversed(A))
BB = list(reversed(B))

rest = K
ans = 0

def dfs(cost, aindex, bindex, score):

    if K == cost:
        # print("1:", score, cost)
        return score
    elif K < cost:
        # print("2:", score, cost)
        return score - 1
        # return -1
    
    if aindex == N and bindex == M:
        # print("3:", score, cost)
        return score

    if aindex >= N:
        return dfs(cost + B[bindex], aindex, bindex+1, score + 1)
    
    elif bindex >= M:
        return dfs(cost + A[aindex], aindex+1, bindex, score + 1)

    else:
        return max(dfs(cost + A[aindex], aindex+1, bindex, score + 1), dfs(cost + B[bindex], aindex, bindex + 1, score + 1))

print(max(dfs(A[0], 1, 0, 1), dfs(B[0], 0, 1, 1)))

N, M, K = map(int, input().split())
A = list(map(int, input().split()))
B = list(map(int, input().split()))

a, b = [0], [0]
for ai in A:
    a.append(a[-1] + ai)

for bi in B:
    b.append(b[-1] + bi)

# print(a, b)
ans = 0
bs = M
for i in range(N+1):
    if a[i] > K:
        break
    for j in reversed(range(bs+1)):
        if a[i] + b[j] <= K:
            ans = max(ans, i + j)
            bs = j
            break

print(ans)

Verdicts: Wrong Answer

Runtime Error

Runtime Error

Accepted