TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
str = input().split()
N = int(str[0])
M = int(str[1])
L = []
R = []
for i in range(M):
    str = input().split()
    L.append(int(str[0]))
    R.append(int(str[1]))

mini = 1
maxi = N
    
for i in range(M):
    if mini <= L[i]:
        mini = L[i]
        print("mini")
        print(mini)
    if maxi >= R[i]:
        maxi = R[i]
        print("maxi")
        print(maxi)
        
print(maxi - mini+1)

str = input().split()
N = int(str[0])
M = int(str[1])
L = []
R = []
for i in range(M):
    str = input().split()
    L.append(int(str[0]))
    R.append(int(str[1]))

mini = 1
maxi = N
    
for i in range(M):
    if mini <= L[i]:
        mini = L[i]
    if maxi >= R[i]:
        maxi = R[i]
        
if (maxi - mini) >= 0:
    print(maxi - mini+1)
else:
    print(0)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
ans = [-1,10**6]

for i in range(m):
    tmp = list(map(int,input().split()))
    ans[0] = max(ans[0],min(tmp))
    ans[1] = min(ans[1],max(tmp))

print(max(ans[1]-ans[0]+1),0)

n,m = map(int,input().split())
ans = [-1,10**6]

for i in range(m):
    tmp = list(map(int,input().split()))
    ans[0] = max(ans[0],min(tmp))
    ans[1] = min(ans[1],max(tmp))

print(max(ans[1]-ans[0]+1,0))

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int,input().split())

L,R= map(int,input().split())

for i in range(M):
    x,y= map(int,input().split())
    L = max(L,x)
    R = min(R,y)

print(R-L+1)

N, M = map(int,input().split())

L,R= map(int,input().split())

for i in range(M-1):
    x,y= map(int,input().split())
    L = max(L,x)
    R = min(R,y)

print(R-L+1 if L<=R else 0)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())

haba = list()
max_L = 0
min_R = 10 ** 5 + 1
for i in range(M):
    L, R = map(int, input().split())
    haba.append([L, R])
    max_L = max(max_L, L)
    min_R = min(min_R, R)

min_haba = set(range(max_L, min_R + 1))
ids = set()
for L, M in haba:
    if max_L - 1 < L and R < min_R:
        h = set(range(L, R + 1))
        ids = ids.union(h.intersection(min_haba))

print(len(ids))

N, M = map(int, input().split())

haba = list()
max_L = 0
min_R = 10 ** 5 + 1
for i in range(M):
    L, R = map(int, input().split())
    haba.append([L, R])
    max_L = max(max_L, L)
    min_R = min(min_R, R)

print(max(min_R + 1 - max_L, 0))

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m =map(int,input().split())
a =[]*m
b =[]*m
for i in range(n):
        l,r =map(int,input().split())
        a.append(l)
        b.append(r)

if max(a) <=min(b):
        print(min(b)-max(a)+1)
else:
        print(0)


n,m =map(int,input().split())
a =[]*m
b =[]*m
for i in range(m):
        l,r =map(int,input().split())
        a.append(l)
        b.append(r)

if max(a) <=min(b):
        print(min(b)-max(a)+1)
else:
        print(0)


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
li = [list(map(int, input().split())) for _ in range(M)]
 
ans = 0
t = 0
 
for i in range(M): 
    t = 1
    if li[0][1] < li[i][1] and i != 0:
        t = 0
    else:
        for j in range(N):
            if not li[i][0] <= j+1 <= li[i][1]:
                t = 0
                break
    ans += t
 
print(ans)

N, M = map(int, input().split())
li = [list(map(int, input().split())) for _ in range(M)]
 
ans = 0
t = 0
 
for i in range(N): 
    t = 1
    for j in range(M):
        if not li[j][0] <= i+1:
            t = 0
            break
        elif not li[j][0] <= li[j][1]:
            t = 0
            break
    ans += t
 
print(ans)

N, M = map(int, input().split())
L = []
R = []
ans = 0

for i in range(M):
    l, r = map(int, input().split())
    L.append(l)
    R.append(r)
L_max = max(L)
L_min = min(R)

for i in range(N):
    if L_max <= i+1 <= L_min:
        ans += 1
print(ans)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M=map(int, input().split())
L = []
R = []
for i in range(M):
    l, r = input().split()
    L.append(int(l))
    R.append(r)


x = min(R)-max(L)


print(0 if x <0 else x+1)

N,M=map(int, input().split())
L = []
R = []
for i in range(M):
    l, r = input().split()
    L.append(int(l))
    R.append(int(r))


x = min(R)-max(L)


print(0 if x <0 else x+1)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import sys
n,m = map(int,input().split())
ls = [list(map(int,input().split())) for i in range(m)]
a = ls[0][0]
b = ls[0][1]
for j in range(1,m):
    a = max(a,ls[j][0])
    b = min(b,ls[j][1])
    print(a)
    print(b)
    if b-a<0:
        print(0)
        sys.exit()
print(b-a+1)

import sys
n,m = map(int,input().split())
ls = [list(map(int,input().split())) for i in range(m)]
a = ls[0][0]
b = ls[0][1]
for j in range(1,m-1):
    a = max(a,ls[j+1][0])
    b = min(b,ls[j+1][1])
    if b-a<0:
        print(0)
        sys.exit()
print(b-a+1)

import sys
n,m = map(int,input().split())
ls = [list(map(int,input().split())) for i in range(m)]
a = ls[0][0]
b = ls[0][1]
for j in range(1,m-1):
    a = max(a,ls[j+1][0])
    b = min(b,ls[j+1][1])
    if a-b<0:
        print(0)
        sys.exit()
print(a-b+1)

import sys
n,m = map(int,input().split())
ls = [list(map(int,input().split())) for i in range(m)]
a = ls[0][0]
b = ls[0][1]
for j in range(1,m):
    a = max(a,ls[j][0])
    b = min(b,ls[j][1])
    if b-a<0:
        print(0)
        sys.exit()
print(b-a+1)

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
#L = list(map(int,input().split()))
li = [0]*n
print(li)
for i in range(m):
    a,b = (map(int,input().split()))
    print(a,b)
    for j in range(a-1,b):
        li[j] += 1
print(li.count(m))


n,m = map(int,input().split())
min_ = 0
max_ = 100001
for i in range(m):
  li = list(map(int,input().split()))
  
  if min(li) >= min_ :
    min_ = min(li)
  if max(li) <= max_:
    max_ = max(li)
if min_ > max_:
    print(0)
else:
    print(max_ - min_ + 1)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int, input().split())
lmax,rmin=0,n+1
for i in range(m):
  l,r=map(int, input().split())
  lmax=max(l,lmax)
  rmin=min(r,rmin)
print(max(0,lmax-rmin+1))

n,m = map(int, input().split())
lmax,rmin=0,n+1
for i in range(m):
  l,r=map(int, input().split()
  lmax=max(l,lmax)
  rmin=min(r,rmin)
print(max(0,lmax-rmin+1))

n,m = map(int, input().split())
lmax,rmin=0,n+1
for i in range(m):
  l,r=map(int, input().split()
  lmax=max(l,lmax)
  rmin=min(r,rmin)
print(max(0,lmax-rmin+1)

n,m = map(int, input().split())
lmax,rmin=0,n+1
for i in range(m):
  l,r=map(int, input().split())
  lmax=max(l,lmax)
  rmin=min(r,rmin)
print(max(0,rmin-lmax+1))

Verdicts: Wrong Answer

Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M =  list(map(int, input().split()))
LR = [list(map(int, input().split())) for _ in range(M)]
left = 0
right = N -1 

for l,r in LR:
    left = max(left,l -1)
    right = min(right,r -1)

if l  > r:
    print(0)
else:
    print( r - l +1)


N,M =  list(map(int, input().split()))
LR = [list(map(int, input().split())) for _ in range(M)]
left = 0
right = N -1 

for l,r in LR:
    left = max(left,l -1)
    right = min(right,r -1)

if left > right:
    print(0)
else:
    print( right - left +1)


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import heapq
N,M = map(int, input().split())
A = list(map(int, input().split()))
BC = []

for i in range(M):
    BC.append(list(map(int, input().split())))

BC.sort(key=lambda x: x[1], reverse=True)
A_min = min(A)
heapq.heapify(A)
for i in range(M):
    for j in range(BC[i][0]):
        if BC[i][1] > min(A):
            heapq.heappush(A,BC[i][1])
            heapq.heappop(A)

    A_min = min(A)

print(sum(A))

N,M = map(int,input().split())
L = []
R = []
for i in range(M):
    l,r = map(int,input().split())
    L.append(l)
    R.append(r)

L_max = max(L)
R_min = min(R)

result = R_min - L_max + 1

if result < 0:
    print(0)
else:
    print(result)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
table = [[int(i) for i in input().split()] for _ in range(M)]

ans = [table[0], table[1]]

for i in table:
    if ans[0] >= i[0] <= ans[1]:
        ans[0] = i[0]
    if ans[0] >= i[1] <= ans[1]:
        ans[1] = i[1]

print(ans[1] - ans[0] + 1)


N, M = map(int, input().split())
table = [[int(i) for i in input().split()] for _ in range(M)]

ans = [table[0][0], table[0][1]]
cnt = 0

for i in table[1:]:
    if ans[0] <= i[0] <= ans[1]:
        ans[0] = i[0]
    if ans[0] <= i[1] <= ans[1]:
        ans[1] = i[1]
    if ans[1] < i[0] or i[1] < ans[0]:
        cnt += 1
        break

if cnt != 0:
    print(0)
else:
    print(ans[1] - ans[0] + 1)


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M = map(int, input().split())
L = ['']*M
R = ['']*M

for i in range(M):
    L[i],R[i] = map(int, input().split())

gate_l = max(L)
gate_r = min(R)
width = gate_l - gate_r + 1
sum = N*width


#     if L[i]<=gate_l:

#     elif gate_l<L[i] and L[i]<=gate_r:

#     else:

#         break
# 
#     if gate_r<=R[i]:

#     elif gate_r<R[i] and R[i]<=gate_r:

#     else:

#         break

print(width)

N,M = map(int, input().split())
L = ['']*M
R = ['']*M

for i in range(M):
    L[i],R[i] = map(int, input().split())

gate_l,gate_r = max(L),min(R)
width = gate_l - gate_r + 1 if max(L)>=min(R) else 0

print(width)


N,M = map(int, input().split())
L = ['']*M
R = ['']*M

for i in range(M):
    L[i],R[i] = map(int, input().split())

id_l,id_r = max(L),min(R)
width = id_r - id_l + 1 if max(L)>=min(R) else 0

print(width)


N,M = map(int, input().split())
L = ['']*M
R = ['']*M

for i in range(M):
    L[i],R[i] = map(int, input().split())

id_l,id_r = max(L),min(R)
width = id_r - id_l + 1 if max(L)<=min(R) else 0

print(width)


Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import sys
input = sys.stdin.readline
N,M = map(int,input().split())
lr =[[int(i)for i in input().split()]for _ in range(M)]
ans =[0,N+1]
for LR in lr:
    if ans[0] < LR[0]:
        ans[0]=LR[0]
    if LR[1] < ans[1]:
        ans[1] =LR[1]
print(min(0,ans[1]-ans[0]+1))


import sys
input = sys.stdin.readline
N,M = map(int,input().split())
lr =[[int(i)for i in input().split()]for _ in range(M)]
ans =[0,N+1]
for LR in lr:
    if ans[0] < LR[0]:
        ans[0]=LR[0]
    if LR[1] < ans[1]:
        ans[1] =LR[1]
print(max(0,ans[1]-ans[0]+1))


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())

L = []
R = []
for i in range(M):
  a, b = map(int, input().split())
  L.append(a)
  R.append(b)

min = min(L)
max = max(R)

ans = max(0, max - min + 1)
print(ans)

N, M = map(int, input().split())

L = []
R = []
for i in range(M):
  a, b = map(int, input().split())
  L.append(a)
  R.append(b)

minmin = max(L)
maxmax = min(R)

ans = maxmax - minmin + 1
if ans < 0:
  ans = 0
print(ans)


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
# input
N, M = map(int, input().split())
check = []
c_append = check.append
for i in range(1, M + 1):
    L, R = map(int, input().split())
    c_append(set(list(range(L, R + 1))))


mastar_keys = set(list(range(1, N + 1)))
for k in sorted(check, key=lambda x: len(x)):
    mastar_keys = mastar_keys & check[k]
    if len(mastar_keys) == 0:
        break

print(len(mastar_keys))


N, M = map(int, input().split())
x, y = 0, N
for i in range(1, M + 1):
    L, R = map(int, input().split())
    x = max(x, L)
    y = min(y, R)

print(len(range(x, y + 1)))

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
    a, b = map(int, input().split())
    list_a = list(range(1, a, 1))
    for num in range(b):
        c, d = map(int, input().split())
        for item in list_a:
            if item <= c and  item >= d:
                list_a.remove(item)
                
    print(len(list_a))

if __name__ == '__main__':
    n, m = map(int, input().split())
    max = 0
    min = n

    for i  in range(m):
        l,r = map(int, input().split())
        if l > max:
            max = l
        if r < min:
            min = r


    if max <= min:
        print(min - max +1)
    else:
        print(0)






Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
maxL = 0
minM = N
for x in range(M):
    l, m = map(int, input().split())
    maxL = max(maxL, l)
    minM = min(minM, m)

print(min(minM - maxL + 1, 0))

10 3
3 6
5 7
6 9

N, M = map(int, input().split())
maxL = 0
minM = N
for x in range(M):
    l, m = map(int, input().split())
    maxL = max(maxL, l)
    minM = min(minM, m)

print(max(minM - maxL + 1, 0))

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M=map(int,input().split())
L=[0]*M
R=[0]*M
for i in range(M):
  L[i],R[i]=map(int,input().split())

print(0 if min(R)>max(L) else min(R)-max(L)+1)
  

N,M=map(int,input().split())
L=[0]*M
R=[0]*M
for i in range(M):
  L[i],R[i]=map(int,input().split())

print(0 if min(R)<max(L) else min(R)-max(L)+1)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = [int(i) for i in input().split()]

l =[]
r =[]
for i in range(m):
    l1, r1 = [int(i) for i in input().split()]
    l.append(l1)
    r.append(r1)

min = 1
max = n
for i in range(m):
    temp = l[i]
    min = min if min>temp else temp
    temp = r[i]
    max = max if max<temp else temp
    #print(min, max)

print(min,max)
ans = max-min+1
if min>max:
    print(0)
else:
    print(ans)

n,m = [int(i) for i in input().split()]

l =[]
r =[]
for i in range(m):
    l1, r1 = [int(i) for i in input().split()]
    l.append(l1)
    r.append(r1)

min = 1
max = n
for i in range(m):
    temp = l[i]
    min = min if min>temp else temp
    temp = r[i]
    max = max if max<temp else temp
    #print(min, max)

#print(min,max)
ans = max-min+1
if min>max:
    print(0)
else:
    print(ans)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())

lmax = -1
rmin = n * 100
for i in range(m):
    l, r = map(int, input().split())
    lmax = max(l, lmax)
    rmin = min(r, rmin)

print(max(lmax - rmin + 1, 0))

n, m = map(int, input().split())

lmax = -1
rmin = n * 100
for i in range(m):
    l, r = map(int, input().split())
    lmax = max(l, lmax)
    rmin = min(r, rmin)

print(max(rmin - lmax + 1, 0))

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
L = []
R = []
for i in range(m):
  l,r = map(int,input().split())
  L.append(l)
  R.append(r)

ans = max(L)-min(R)+1
print(ans if ans >0 else "0")

n,m = map(int,input().split())
s = {}
for i in range(m):
  l,r = map(int,input().split())
  for j in range(l,r+1):
    l = []
    l.append(i)
    newset = set(l)
  s = s&newset
print(len(s))
    

n,m = map(int,input().split())
L = []
R = []
for i in range(m):
  l,r = map(int,input().split())
  L.append(l)
  R.append(r)

ans = max(L)-min(R)+1
print(ans if ans >0 else 0)

n,m = map(int,input().split())
L = []
R = []
for i in range(m):
  l,r = map(int,input().split())
  L.append(l)
  R.append(r)

ans = min(R)-max(L)+1
print(ans if ans >0 else "0")

Verdicts: Wrong Answer

Runtime Error

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
list = []
for i in range(M):
    L, R = map(int, input().split())
    list.append([L,R])
anslist = [list[0][0],list[0][1]]
arukadouka = True
if M = 1:
    arukadouka = False
cnt = 0
for i in range(1,M):
    if arukadouka == True:
        if anslist[0] > list[i][1]:
            arukadouka = False
        elif anslist[1] < list[i][0]:
            arukadouka = False
        else:
            if (anslist[0]<=list[i][0]) and (anslist[1]<=list[i][1]):
                anslist[0] = list[i][0]
            elif (anslist[0]<=list[i][0]) and (anslist[1]>=list[i][1]):
                anslist[0] = list[i][0]
                anslist[1] = list[i][1]
            elif (anslist[0]>=list[i][0]) and (anslist[1]<=list[i][1]):
                pass
            elif (anslist[0]>=list[i][0]) and (anslist[1]>=list[i][1]):
                anslist[1] = list[i][1]
        cnt += 1
print(anslist[1]-anslist[0]+1)

N, M = map(int, input().split())
list = []
for i in range(M):
    L, R = map(int, input().split())
    list.append([L,R])
anslist = [list[0][0],list[0][1]]
arukadouka = True
cnt = 0
for i in range(1,M):
    if arukadouka == True:
        if anslist[0] > list[i][1]:
            arukadouka = False
        elif anslist[1] < list[i][0]:
            arukadouka = False
        elif list[i][0] == list[i][1]:
            anslist[0] = list[i][0]
            anslist[1] = list[i][1]
        else:
            if (anslist[0]<=list[i][0]) and (anslist[1]<=list[i][1]):
                anslist[0] = list[i][0]
            elif (anslist[0]<=list[i][0]) and (anslist[1]>=list[i][1]):
                anslist[0] = list[i][0]
                anslist[1] = list[i][1]
            elif (anslist[0]>=list[i][0]) and (anslist[1]<=list[i][1]):
                pass
            elif (anslist[0]>=list[i][0]) and (anslist[1]>=list[i][1]):
                anslist[1] = list[i][1]
        cnt += 1
if arukadouka == True:
    ans = anslist[1]-anslist[0]+1
else:
    ans = 0
print(ans)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())


L, R = map(int, input().split())
ar = [i for i in range(L, R+1)]
for i in range(M-1):
      L, R = map(int, input.split())
      if ar[-1] < L or ar[0] > R:
        break
      else:
        if ar[0] < L < ar[-1]:
          ar = [x for x in range(L, ar[-1]+1)]
        elif ar[0] < R <ar[-1]:
          ar = [x for x in range(ar[0], R+1)]
print(len(ar))

N, M = map(int, input().split())
L, R = map(int, input().split())


for i in range(M-1):
      L1, R1 = map(int, input().split())
      if R1 < L or R < L1:
        print(0)
        exit()
      else:
        if L <= L1 <= R:
          L = L1
          
        elif L <= R1 <= R:
          R = R1
        
          
print(R-L+1)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
info = []
for _ in range(m):
    l, r = map(int, input().split())
    info.append([l, r])
print(info)
L = 0
R = 10**5 + 1
for l, r in info:
    Lb, Rb = True, True
    if l < L:
        Lb = False
    elif L <= l <= R:
        L = l
    else:
        print(0)
        exit()
    if R < r:
        Rb = False
    elif L <= r <= R:
        R = r
    else:
        print(0)
        exit()
    if not (Lb or Rb):
        print(0)
        exit()

print(R - L + 1)
    

n, m = map(int, input().split())
info = []
for _ in range(m):
    l, r = map(int, input().split())
    info.append([l, r])
# print(info)
L = 0
R = 10**5 + 1
for l, r in info:
    # Lb, Rb = True, True
    if l < L:
        pass
    elif L <= l <= R:
        L = l
    else:
        print(0)
        exit()
    if R < r:
        pass
    elif L <= r <= R:
        R = r
    else:
        print(0)
        exit()
    # if not (Lb or Rb):
    #     print(0)
    #     exit()
    # print(L, R)

print(R - L + 1)
    

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
from collections import Counter
import numpy as np

n, m = map(int, input().split())
tar = [0] * (1 + 10 ** 5)
tar = np.array(tar)

for i in range(m):
    l, r = map(int, input().split())
    tar[l:r + 1] += 1
    print(tar[:10])


# print(tar[0:5])
count = Counter(tar)
ans = count[m]
print(ans)



from collections import Counter
import numpy as np

n, m = map(int, input().split())
data = [0] * m

for i in range(m):
    data[i] = list(map(int, input().split()))


data = np.array(data)
ll = data[:, 0]
rr = data[:, 1]

ans = np.min(rr) - max(ll) + 1
ans = max(0, ans)
print(ans)




Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input().split())
count=0
for j in range(1,n+1):
  for i in range(m):
    l,r=map(int,input().split())
    if l<=j:
      if j<=r:
        count+=1
print(count)

n,m=map(int,input().split())
count=0
x=[]
for i in range(m):
  l,r=map(int,input().split())
  x.append([l,r])
  
for j in range(1,n+1):
  for k in range(m):
    if x[k,0]<=j:
      if x[k,1]>=j:
        count+=1
        
print(count)

n,m=map(int,input().split())
listl=[]
listr=[]
for i in range(m):
  l,r=map(int,input().split())
  listl.append(l)
  listr.append(r)
maxl=max(listl)
minr=min(listr)
if minr-maxl+1>=1:
  print(minr-maxl+1)
else:
  print(0)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = list(map(int, input().split()))
l, r = [], []

for _ in range(m):
    a, b = list(map(int, input().split()))
    l.append(a)
    r.append(b)

print(max(l) - min(r) + 1)

n, m = list(map(int, input().split()))
l, r = [], []

for _ in range(m):
    a, b = list(map(int, input().split()))
    l.append(a)
    r.append(b)

if min(r) < max(l):
    print("0")
else:
    print(min(r) - max(l) + 1)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
r=input().split()
N=int(r[0])
M=int(r[1])
data=[[int(s) for s in input().split()] for i in range(M)]
left=[]
right=[]
for i in range(M):
    left.append(data[i][0])
    right.append(data[i][1])
if min(right)-max(left)+1=<0:
    print(0)
else:
    print(min(right)-max(left)+1)

r=input().split()
N=int(r[0])
M=int(r[1])
data=[[int(s) for s in input().split()] for i in range(M)]
left=[]
right=[]
for i in range(M):
    left.append(data[i][0])
    right.append(data[i][1])
if min(right)-max(left)+1<=0:
    print(0)
else:
    print(min(right)-max(left)+1)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
l = [0]*m
r = [0]*m
for i in range(m):
  p, q = map(int, input().split())
  l[i], r[i] = map(int, input().split())
print(max(min[r] - max[l] + 1, 0))

n, m = map(int, input().split())
cnt = [0]*(n+1)
for i in range(n):
  l, r = map(int, input().split())
  for j in range(l, r+1):
    cnt[j] += 1
print(cnt.count(m))    


n, m = map(int, input().split())
l = [0]*m
r = [0]*m
for i in range(m):
  l[i], r[i] = map(int, input().split())
print(max(min(r) - max(l) + 1, 0))


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M = (int(i) for i in input().split())
e = [[int(i) for i in input().split()] for i in range(M)]
hoge = set()

zenbu = {int(i + 1) for i in range(N)}

for i in e:
    konkaino = {int(i) for i in range(e[0],e[1] + 1)}
    zenbu = zenbu & konkaino


print(len(zenbu))

N,M = (int(i) for i in input().split())
e = [[int(i) for i in input().split()] for i in range(M)]

right = N
left = 0

for i in e:
    if left < i[0]:
        left = i[0]
    if right > i[1]:
        right = i[1]
if right >= left:
    print(right - left)
else:
    print("0")

N,M = (int(i) for i in input().split())
e = [[int(i) for i in input().split()] for i in range(M)]

right = N
left = 0

for i in e:
    if left < i[0]:
        left = i[0]
    if right > i[1]:
        right = i[1]
if right >= left:
    print(right - left + 1)
else:
    print("0")

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import sys
def input():
    return sys.stdin.readline()
def main():
    N, M = map(int, input().split())
    dict = {}
    for _ in range(M):
        L, R = map(int, input().split())
        for x in range(L, R+1):
            if x in dict:
                dict[x] += 1
            else:
                dict[x] = 1
    return sum([1 for k, v in dict.items() if v == M])
main()

n, m = map(int, input().split())
L, R = 1, n
for i in range(m):
    l, r = map(int, input().split())
    L = max(L, l)
    R = min(R, r)
print(max(R-L+1, 0))

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
left = 0 
right = 10 ** 6 
for _ in range(m):
  l, r = map(int, input().split())
  left = max(left, l)
  right = min(right, r)
    right = r

print(r-l+1 if l <= r else 0)

n, m = map(int, input().split())
left = 0 
right = 10 ** 6 
for _ in range(m):
  l, r = map(int, input().split())
  left = max(left, l)
  right = min(right, r)

print(right-left+1 if left <= right else 0)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input().split())
l=0
r=10000000000000
for i in range(m):
  a,b=map(int,input().split())
  l=max(l,a)
  r=min(r,b)
print(l)
print(r)
print(r-l+1)

n,m=map(int,input().split())
l=0
r=10000000000000
for i in range(m):
  a,b=map(int,input().split())
  l=max(l,a)
  r=min(r,b)
if r-l+1 >0:
  print(r-l+1)
else:
  print(0)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N ,M = map(int , input().split())
max_L = []
min_R = []
gate_number = [i for i in range(1, M+1)]
for j in range(M):
    L , M = map(int,input().split())
    max_L.append(L)
    min_R.append(M)
print(len([s for s in range(max(max_L) , min(min_R))]))

N ,M = map(int , input().split())
max_L = []
min_R = []
gate_number = [i for i in range(1, M+1)]
for j in range(M):
    L , M = map(int,input().split())
    max_L.append(L)
    min_R.append(M)
print(len([i for i in range(max(max_L) , min(min_R))]))

    

N ,M = map(int , input().split())
max_L = []
min_R = []
gate_number = [i for i in range(1, M+1)]
for j in range(M):
    L , M = map(int,input().split())
    max_L.append(L)
    min_R.append(M)
print(len([s for s in range(max(max_L) , min(min_R) + 1)]))

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
#k = int(input())
#s = input()
#a, b = map(int, input().split())
#s, t = map(str, input().split())
#l = list(map(int, input().split()))

#a = [input() for _ in range(n)]

n,m = map(int, input().split())
l = [list(map(int,input().split())) for i in range(m)]





up = 10**5+1
lo = 0

for i in range(m):
    if lo < l[i][0]:
        lo = l[i][0]
    if  up > l[i][1]:
        up = l[i][1]

ans = 0
print(lo,up)
for i in range(1,n+1):
    if i >= lo and i <= up:
        ans+=1
print(ans)




#k = int(input())
#s = input()
#a, b = map(int, input().split())
#s, t = map(str, input().split())
#l = list(map(int, input().split()))

#a = [input() for _ in range(n)]

n,m = map(int, input().split())
l = [list(map(int,input().split())) for i in range(m)]





up = 10**5+1
lo = 0

for i in range(m):
    if lo < l[i][0]:
        lo = l[i][0]
    if  up > l[i][1]:
        up = l[i][1]


if (up - lo >= 0):
    print(up -lo+1)
else:
    print(0)




Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
a = sorted([int(x) for x in  input().split()])
for _ in range(m):
    b, c = map(int, input().split())
    if a[0] < c:
        for i in range(b):
            if a[i] < c:
                a[i] = c
        a.sort()
print(sum(a))

n, m = map(int, input().split())

gate_cond = [[int(x) for x in input().split()] for _ in range(m)]
max_under_th = max([l[0] for l in gate_cond])
min_upper_th = min([l[1] for l in gate_cond])
if min_upper_th - max_under_th >= 0:
    print(min_upper_th - max_under_th + 1)
else:
    print(0)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
left=0
right=0

for i in range(N):
    L, R = map(int, input().split())
    if L > left:
        left = L
    if R < left:
        right = R

if left <= right:
    print(right-left+1)
else:
    print(0)

N, M = map(int, input().split())
left=0
right=N

for i in range(N):
    L, R = map(int, input().split())
    if L > left:
        left = L
    if R < right:
        right = R

if left <= right:
    print(right-left+1)
else:
    print(0)

N, M = map(int, input().split())
left=0
right=N

for i in range(M):
    L, R = map(int, input().split())
    if L > left:
        left = L
    if R < right:
        right = R

if left <= right:
    print(right-left+1)
else:
    print(0)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
lrs = [list(map(int, input().split())) for _ in range(m)]

l_max = 1
r_min = n
for l, r in lrs:
    l_max = max(l, l_max)
    r_min = min(r, r_min)

print(min(r_min - l_max + 1), 0)


n, m = map(int, input().split())
lrs = [list(map(int, input().split())) for _ in range(m)]

l_max = 1
r_min = n
for l, r in lrs:
    l_max = max(l, l_max)
    r_min = min(r, r_min)

print(min(r_min - l_max + 1, 0))


n, m = map(int, input().split())
lrs = [list(map(int, input().split())) for _ in range(m)]

l_max = 1
r_min = n
for l, r in lrs:
    l_max = max(l, l_max)
    r_min = min(r, r_min)

print(max(r_min - l_max + 1, 0))


Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
#! /usr/bin/env python3
# -*- coding: utf-8 -*-
N,M = [int(x) for x in input().split()]
Llist =[]
Rlist =[]
for i in range (M):
    L,R = [int(x) for x in input().split()]
    Llist.append(L)
    Rlist.append(R)
 
lmax = max(Llist)
Rmax = min(Rlist)

if lmax >= Rmax:
    print(0)
else:
    print(Rmax-lmax-1)



#! /usr/bin/env python3
# -*- coding: utf-8 -*-
N,M = [int(x) for x in input().split()]
Llist =[]
Rlist =[]
for i in range (M):
    L,R = [int(x) for x in input().split()]
    Llist.append(L)
    Rlist.append(R)
 
lmax = max(Llist)
Rmax = min(Rlist)

if lmax > Rmax:
    print(0)
else:
    print(Rmax-lmax+1)



Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import sys

n, m = list(map(int, input().split()))
l, r = 1, n
for line in sys.stdin:
    a, b = list(map(int, input().split()))
    l = max(a, l)
    r = min(b, r)
print(max(0, r - l + 1))


import sys

n, m = list(map(int, input().split()))
l, r = 1, n
for line in sys.stdin:
    a, b = list(map(int, line.split()))
    l = max(a, l)
    r = min(b, r)
print(max(0, r - l + 1))


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m=map(int, input().split())
l, r=list(map(int, input().split()))
l.sort()
r.sort()
if max(l) < min(r):
  print(0)
else:
  print(min(r) - max(l) + 1)

n,m=map(int,input().split())
left=0
right=10**5
for i in range(m):
  l,r=map(int,input().split())
  left=max(left,l)
  right=min(right,r)
print(right-left+1 if right-left+1>0 else 0)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())

left_max = -1
right_min = n+1

for i in range(m):
    s,t = map(int,input().split())
    left_max = max(left_max,s)
    right_min = min(right_min, t)
    
print(0, right_min - left_max +1)

n,m = map(int,input().split())

left_max = -1
right_min = n+1

for i in range(m):
    s,t = map(int,input().split())
    left_max = max(left_max,s)
    right_min = min(right_min, t)
    
print(max(0, right_min - left_max +1))

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
x = 0
y = n - 1
for _ in range(m):
  l, r = map(int, input().split())
  x = max(x, l - 1)
  y = min(y, r - 1)
  print(x, y)
print(max(y - x + 1, 0))



N, M = map(int, input().split())

cs = [0] * N
for _ in range(M):
    L, R = map(int, input().split())
    cs[L - 1] += 1
    if R != N:
        cs[R] -= 1

for i in range(1, N):
    cs[i] += cs[i - 1]

print(cs.count(M))


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
# C - Prison


n, m = map(int, input().split())
gates = [list(map(int, input().split())) for _ in range(m)]
# gates = []

#     gates.append(list(map(int, input().split())))


scope = [1, n]

for element in gates:
    

    if element[0] > scope[0]:
        scope[0] = element[0]

    if element[1] < scope[1]:
        scope[1] = element[1]




if scope[1] > n:
    print(n - scope[0] + 1)
else:
    print(scope[1] - scope[0] + 1)

print(scope)

N, M = map(int, input().split())
gates = [list(map(int, input().split())) for _ in range(M)]
scope = [1, N]


class CountedAcID():
    def __init__(self, gates):
        self.gates = gates
        self.scope = [1, N]

    def run(self):
        self.__get_range()
        self.total = self.__return_num()


    def __get_range(self):
        for element in self.gates:
            self.scope[0] = self.__get_left(element[0], self.scope[0])
            self.scope[1] = self.__get_right(element[1], self.scope[1])

    def __get_left(self, element, left):
        if element > left:
            return element
        else:
            return left

    def __get_right(self, element, right):
        if element < right:
            return element
        else:
            return right

    def __return_num(self):
        if self.scope[1] > N:
            return N - self.scope[0] + 1

        else:
            return self.scope[1] - self.scope[0] + 1


c = CountedAcID(gates)
c.run()
print(c.scope)
num = c.total

if num < 0:
    print(0)
else:
    print(num)

N, M = map(int, input().split())
gates = [list(map(int, input().split())) for _ in range(M)]
scope = [1, N]


class CountedAcID():
    def __init__(self, gates):
        self.gates = gates
        self.scope = [1, N]

    def run(self):
        self.__get_range()
        self.total = self.__return_num()


    def __get_range(self):
        for element in self.gates:
            self.scope[0] = self.__get_left(element[0], self.scope[0])
            self.scope[1] = self.__get_right(element[1], self.scope[1])

    def __get_left(self, element, left):
        if element > left:
            return element
        else:
            return left

    def __get_right(self, element, right):
        if element < right:
            return element
        else:
            return right

    def __return_num(self):
        if self.scope[1] > N:
            return N - self.scope[0] + 1

        else:
            return self.scope[1] - self.scope[0] + 1


c = CountedAcID(gates)
c.run()
num = c.total

if num < 0:
    print(0)
else:
    print(num)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())

L = 1
R = 10**5

for i in range(m):
    l, r = map(int, input().split())
    if L <= l <= R:
        L = l
    if L <= r <= R:
        R = r
    if R < l or r < L:
        ans = 0
        break

if ans != 0:
    ans = R - L + 1

print(ans)

n, m = map(int, input().split())

L = 1
R = 10**5
ans = 1

for i in range(m):
    l, r = map(int, input().split())
    if L <= l <= R:
        L = l
    if L <= r <= R:
        R = r
    if R < l or r < L:
        ans = 0
        break

if ans != 0:
    ans = R - L + 1

print(ans)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M=map(int, input().split())

max = 0
min = 0

for _ in range(M):
    L,R = map(int, input().split())

    if min < L:
        min = L
    elif min == 0:
        min = L

    if max > R:
        max = R
    elif max =+ 0:
        max = R

ans = max - min + 1

print(ans)


N,M=map(int, input().split())

max = 0
min = 0

for _ in range(M):
    L,R = map(int, input().split())

    if min < L:
        min = L
    elif min == 0:
        min = L

    if max > R:
        max = R
    elif max =+ 0:
        max = R

ans = max - min + 1

print(ans)

N,M=map(int, input().split())

max = 0
min = 0

for _ in range(M):
    L,R = map(int, input().split())

    if min <= L:
        min = L
    elif min == 0:
        min = L

    if max >= R:
        max = R
    elif max == 0:
        max = R

ans = max - min + 1

if ans < 0:
    ans = 0

print(ans)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M = map(int,input().split())
gate_list = []
while True:
  try:
    gate_list.append(list(map(int,input().split())))
  except:
    break

left_ = []
right_ = []

for i in gate_list:
  left_.append(i[0])
  right_.append(i[1])

min_ = max(left_)
max_ = min(right_)

N,M = map(int,input().split())
gate_list = []
while True:
  try:
    gate_list.append(list(map(int,input().split())))
  except:
    break

left_ = []
right_ = []

for i in gate_list:
  left_.append(i[0])
  right_.append(i[1])

min_ = max(left_)
max_ = min(right_)

counter = 0
for i in range(1,N+1):
  if i >= min_ and i<= max_:
    counter += 1
print(counter)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
L = list(list(map(int,input().split())) for i in range(M))
l = 0
r = N
for i in range(M):
    l = max(l,L[i][0])
    r = min(r,L[i][1])
print(l-r+1)

N, M = map(int, input().split())
L = list(list(map(int,input().split())) for i in range(M))
l = 1
r = N
for i in range(M):
    l = max(l,L[i][0])
    r = min(r,L[i][1])
print(min(r-l+1,0))

N, M = map(int, input().split())
L = list(list(map(int,input().split())) for i in range(M))
l = 1
r = N
for i in range(M):
    l = max(l,L[i][0])
    r = min(r,L[i][1])
print(max(r-l+1,0))


Verdicts: Wrong Answer

Wrong Answer

Accepted