TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: Snuke is conducting an optical experiment using mirrors and his new invention, the rifle of _Mysterious Light_.  Three mirrors of length N are set so that they form an equilateral triangle. Let the vertices of the triangle be a, b and c.  Inside the triangle, the rifle is placed at the point p on segment ab such that ap = X. (The size of the rifle is negligible.) Now, the rifle is about to fire a ray of Mysterious Light in the direction of bc.  The ray of Mysterious Light will travel in a straight line, and will be reflected by mirrors, in the same ways as "ordinary" light. There is one major difference, though: it will be also reflected by its own trajectory as if it is a mirror! When the ray comes back to the rifle, the ray will be absorbed.  The following image shows the ray's trajectory where N = 5 and X = 2.    It can be shown that the ray eventually comes back to the rifle and is absorbed, regardless of the values of N and X. Find the total length of the ray's trajectory.

Submission attempts (in order):
n, x = map(int, input().split())
a, b = max(n-x,x),min(n-x,x)
res = a+b
while b!=0:
    q = a/b
    r = a%b
    res += (b*2)*q
    if (r==0):
        res -= b
    a, b = b, r

print(res)

n, x = map(int, input().split())
ans = 0
a, b = max(n-x,x),min(n-x,x)
res = a+b
while b:
    q = a/b
    r = a%b
    res += (b*2)*q
    if (r==0):
        res -= b
    a, b = b, r

print(res)

n, x = map(int, input().split())
a, b = max(n-x,x),min(n-x,x)
res = a+b
while b!=0:
    q = a//b
    r = a%b
    res += (b*2)*q
    if (r==0):
        res -= b
    a, b = b, r

print(res)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Snuke is conducting an optical experiment using mirrors and his new invention, the rifle of _Mysterious Light_.  Three mirrors of length N are set so that they form an equilateral triangle. Let the vertices of the triangle be a, b and c.  Inside the triangle, the rifle is placed at the point p on segment ab such that ap = X. (The size of the rifle is negligible.) Now, the rifle is about to fire a ray of Mysterious Light in the direction of bc.  The ray of Mysterious Light will travel in a straight line, and will be reflected by mirrors, in the same ways as "ordinary" light. There is one major difference, though: it will be also reflected by its own trajectory as if it is a mirror! When the ray comes back to the rifle, the ray will be absorbed.  The following image shows the ray's trajectory where N = 5 and X = 2.    It can be shown that the ray eventually comes back to the rifle and is absorbed, regardless of the values of N and X. Find the total length of the ray's trajectory.

Submission attempts (in order):
N, X = map(int, input().split())
path = N
a, b = X, N - X
if a < b:
    a, b = b, a
while b > 0:
    print(a, b)
    path += b * (a // b) * 2
    a, b = b, a % b
path -= a
print(path)

N, X = map(int, input().split())
path = N
a, b = X, N - X
if a < b:
    a, b = b, a
while b > 0:
    path += b * (a // b) * 2
    a, b = b, a % b
path -= a
print(path)

Verdicts: Wrong Answer

Accepted
Problem: Snuke is conducting an optical experiment using mirrors and his new invention, the rifle of _Mysterious Light_.  Three mirrors of length N are set so that they form an equilateral triangle. Let the vertices of the triangle be a, b and c.  Inside the triangle, the rifle is placed at the point p on segment ab such that ap = X. (The size of the rifle is negligible.) Now, the rifle is about to fire a ray of Mysterious Light in the direction of bc.  The ray of Mysterious Light will travel in a straight line, and will be reflected by mirrors, in the same ways as "ordinary" light. There is one major difference, though: it will be also reflected by its own trajectory as if it is a mirror! When the ray comes back to the rifle, the ray will be absorbed.  The following image shows the ray's trajectory where N = 5 and X = 2.    It can be shown that the ray eventually comes back to the rifle and is absorbed, regardless of the values of N and X. Find the total length of the ray's trajectory.

Submission attempts (in order):
N,X = input().split()
N,X = int(N), int(X)
answer = X+ (N-X)


def rhombus(N,X):
  	if N<X:
        temp = N
        N = X
        X = temp 
        
    if X==1: 
        return N+1
    if X==0:
        return 0

    if N%X == 0:
        return X*(N//X)*2-X
      
    else: 
        k = N//X
        return k*2*X + rhombus(X,N-(k*X))

      

answer = answer + rhombus(N-X,X)
print(answer)

N,X = input().split()
N,X = int(N), int(X)
answer = X+ (N-X)


def rhombus(N,X):
  	
    if X==1: 
        return N*2-1
    if X==0:
        return 0

    if N%X == 0:
        return X*(N//X)*2-X
      
    else: 
        k = N//X
        return k*2*X + rhombus(X,N-(k*X))

      

answer = answer + rhombus(N-X,X)
print(answer)

Verdicts: Runtime Error

Accepted
Problem: Snuke is conducting an optical experiment using mirrors and his new invention, the rifle of _Mysterious Light_.  Three mirrors of length N are set so that they form an equilateral triangle. Let the vertices of the triangle be a, b and c.  Inside the triangle, the rifle is placed at the point p on segment ab such that ap = X. (The size of the rifle is negligible.) Now, the rifle is about to fire a ray of Mysterious Light in the direction of bc.  The ray of Mysterious Light will travel in a straight line, and will be reflected by mirrors, in the same ways as "ordinary" light. There is one major difference, though: it will be also reflected by its own trajectory as if it is a mirror! When the ray comes back to the rifle, the ray will be absorbed.  The following image shows the ray's trajectory where N = 5 and X = 2.    It can be shown that the ray eventually comes back to the rifle and is absorbed, regardless of the values of N and X. Find the total length of the ray's trajectory.

Submission attempts (in order):
N, X = input().split()

print(3 * int(N))

N, X = map(int, input().split())
q, p = sorted((N - X, X))

r = 1
while r:
    p, r = divmod(p, q)
    N += (2 * p - (r == 0)) * q
    p, q = q, r

print(N)

Verdicts: Wrong Answer

Accepted
Problem: Snuke is conducting an optical experiment using mirrors and his new invention, the rifle of _Mysterious Light_.  Three mirrors of length N are set so that they form an equilateral triangle. Let the vertices of the triangle be a, b and c.  Inside the triangle, the rifle is placed at the point p on segment ab such that ap = X. (The size of the rifle is negligible.) Now, the rifle is about to fire a ray of Mysterious Light in the direction of bc.  The ray of Mysterious Light will travel in a straight line, and will be reflected by mirrors, in the same ways as "ordinary" light. There is one major difference, though: it will be also reflected by its own trajectory as if it is a mirror! When the ray comes back to the rifle, the ray will be absorbed.  The following image shows the ray's trajectory where N = 5 and X = 2.    It can be shown that the ray eventually comes back to the rifle and is absorbed, regardless of the values of N and X. Find the total length of the ray's trajectory.

Submission attempts (in order):
import sys
sys.setrecursionlimit(10**12+1)

N,X = map(int,input().split())

def f(a,b) :
    if a < b :
        return 2*a + f(a,b-a)
    elif a > b :
        a,b = b,a
        return 2*a + f(a,b-a)
    else :
        return a

ans = N + f(X,N-X)

print(ans)


N,X = map(int,input().split())

def f(a,b) :
    if a > b :
        a,b = b,a
    if b % a == 0 :
        return 2*(b//a-1)*a + a
    else :
        return 2*(b//a)*a + f(a,b%a)
        
ans = N + f(X,N-X)

print(ans)


Verdicts: Runtime Error

Accepted
Problem: Snuke is conducting an optical experiment using mirrors and his new invention, the rifle of _Mysterious Light_.  Three mirrors of length N are set so that they form an equilateral triangle. Let the vertices of the triangle be a, b and c.  Inside the triangle, the rifle is placed at the point p on segment ab such that ap = X. (The size of the rifle is negligible.) Now, the rifle is about to fire a ray of Mysterious Light in the direction of bc.  The ray of Mysterious Light will travel in a straight line, and will be reflected by mirrors, in the same ways as "ordinary" light. There is one major difference, though: it will be also reflected by its own trajectory as if it is a mirror! When the ray comes back to the rifle, the ray will be absorbed.  The following image shows the ray's trajectory where N = 5 and X = 2.    It can be shown that the ray eventually comes back to the rifle and is absorbed, regardless of the values of N and X. Find the total length of the ray's trajectory.

Submission attempts (in order):
import fraction

li = [int(i) for i in input().split(" ")]
res = (li[0] // fraction.gcd(li[0], li[1]) -1) * 3 * fraction.gcd(li[0], li[1])
print(res)

def gcd(a, b):
	while b:
		a, b = b, a % b
	return a

li = [int(i) for i in input().split(" ")]
res = (li[0] // gcd(li[0], li[1]) -1) * 3 * gcd(li[0], li[1])
print(res)

Verdicts: Runtime Error

Accepted
Problem: Snuke got a present from his mother on his birthday. The present was a pair of two sequences a and b, consisting of positive integers. They satisfied all of the following properties:    * The sum of all elements of a is N.   * The sum of all elements of b is N.   * Any string of length N that satisfies the following two conditions (1) and (2) will also satisfy the condition (3).     * **(1)** Any of the following forms a palindrome: the first a_1 letters, the following a_2 letters, the following a_3 letters and so on.     * **(2)** Any of the following forms a palindrome: the first b_1 letters, the following b_2 letters, the following b_3 letters and so on.     * **(3)** All N letters are the same.  He was happy, until one day he lost both of the sequences. Now, he only remembers that the sequence a was a permutation of another sequence A of length M.  To bring him happiness again, his mother has decided to give him another pair of sequences a and b that satisfies his favorite properties and is consistent with his memory.

Submission attempts (in order):
n,m=map(int,input().split())
a=list(map(int,input().split()))
b=[]
o=[]
for i in a:
  if i%2:o.append(i)
  else:b.append(i)
if len(o)>2:print("Impossible");exit()
if len(o)==1:b=o+b
elif len(o)==2:b=[o[0]]+b+[o[1]]
ans=[]
for i in range(len(b)):
  if i==0:ans.append(b[i]-1)
  elif i==len(b)-1:ans.append(b[i]+1)
  else:ans.append(b[i])
anss=[]
for i in ans:
  if i!=0:anss.append(i)
if sum(anss)!=n:anss.append(n-sum(anss))
print(*a)
print(len(anss))
print(*anss)

n,m=map(int,input().split())
a=list(map(int,input().split()))
b=[]
o=[]
for i in a:
  if i%2:o.append(i)
  else:b.append(i)
if len(o)>2:print("Impossible");exit()
if len(o)==1:b=o+b
elif len(o)==2:b=[o[0]]+b+[o[1]]
ans=[]
for i in range(len(b)):
  if i==0:ans.append(b[i]-1)
  elif i==len(b)-1:ans.append(b[i]+1)
  else:ans.append(b[i])
anss=[]
for i in ans:
  if i!=0:anss.append(i)
if sum(anss)!=n:anss.append(n-sum(anss))
print(*b)
print(len(anss))
print(*anss)

Verdicts: Wrong Answer

Accepted
Problem: Snuke is having another barbeque party.  This time, he will make one serving of _Skewer Meal_.  He has a stock of N _Skewer Meal Packs_. The i-th Skewer Meal Pack contains one skewer, A_i pieces of beef and B_i pieces of green pepper. All skewers in these packs are different and distinguishable, while all pieces of beef and all pieces of green pepper are, respectively, indistinguishable.  To make a Skewer Meal, he chooses two of his Skewer Meal Packs, and takes out all of the contents from the chosen packs, that is, two skewers and some pieces of beef or green pepper. (Remaining Skewer Meal Packs will not be used.) Then, all those pieces of food are threaded onto both skewers, one by one, in any order.  (See the image in the Sample section for better understanding.)  In how many different ways can he make a Skewer Meal? Two ways of making a Skewer Meal is different if and only if the sets of the used skewers are different, or the orders of the pieces of food are different. Since this number can be extremely large, find it modulo 10^9+7.

Submission attempts (in order):
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines

import numpy as np

MOD = 10 ** 9 + 7

N = int(readline())
m = map(int,read().split())
AB = zip(m,m)

D = 2000

def cumprod(arr,MOD):
    L = len(arr); Lsq = int(L**.5+1)
    arr = np.resize(arr,Lsq**2).reshape(Lsq,Lsq)
    for n in range(1,Lsq):
        arr[:,n] *= arr[:,n-1]; arr[:,n] %= MOD
    for n in range(1,Lsq):
        arr[n] *= arr[n-1,-1]; arr[n] %= MOD
    return arr.ravel()[:L]

def make_fact(U,MOD):
    x = np.arange(U,dtype=np.int64); x[0] = 1
    fact = cumprod(x,MOD)
    x = np.arange(U,0,-1,dtype=np.int64); x[0] = pow(int(fact[-1]),MOD-2,MOD)
    fact_inv = cumprod(x,MOD)[::-1]
    return fact,fact_inv

fact,fact_inv = make_fact(10 ** 4,MOD)
fact = fact.tolist()
fact_inv = fact_inv.tolist()

C_to_A = [[] for _ in range(D+D+1)]
remove = 0
for a,b in AB:
    c = a+b
    C_to_A[c].append(D-a)
    remove += fact[c+c] * fact_inv[a+a] * fact_inv[b+b]
remove %= MOD

dp = np.zeros(D+D+1,np.int64)
for A in C_to_A[::-1]:
    dp[:0:-1] += dp[-1::-1]
    np.add.at(dp,A,1)
    dp %= MOD

x = (dp * dp[::-1] % MOD).sum() % MOD
x -= remove
if x&1:
    x += MOD
x //= 2
x %= MOD

print(x)


import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines

import numpy as np

MOD = 10 ** 9 + 7

N = int(readline())
m = map(int,read().split())
AB = zip(m,m)

D = 2000

U = 10 ** 4
fact = [1] * U
for n in range(1,U):
    fact[n] = fact[n-1] * n % MOD
fact_inv = [1] * U
fact_inv[-1] = pow(fact[-1],MOD-2,MOD)
for n in range(U-1,0,-1):
    fact_inv[n-1] = fact_inv[n] * n % MOD

C_to_A = [[] for _ in range(D+D+1)]
Y = 0
for a,b in AB:
    c = a+b
    C_to_A[c].append(D-a)
    Y += fact[c+c] * fact_inv[a+a] * fact_inv[b+b]
Y %= MOD

f = np.zeros(D+D+1,np.int64)
for A in C_to_A[::-1]:
    f[1:] += f[:-1].copy()
    np.add.at(f,A,1)
    f %= MOD
X = (f * f[::-1] % MOD).sum() % MOD

answer = (X - Y) * fact_inv[2] % MOD
print(answer)

Verdicts: Runtime Error

Accepted