TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n=int(input())
l=list(map(int,input().split()))
for t in range(len(l)):
    l[t]-=1
ans=1
f=1
m=max(l)
for j in range(m):
    for i in range(len(l)):
        if l[i]==0:
            f=1
        elif f==0:
            l[i]-=1
        else:
            ans+=1
            l[i]-=1
            f=0
        print(l,ans)
print(ans)


n=int(input())
l=list(map(int,input().split()))
ans=0
f=1
m=max(l)
for j in range(m):
    for i in range(n):
        if l[i]==0:
            f=1
        elif f==0:
            l[i]-=1
        else:
            ans+=1
            l[i]-=1
            f=0
    f=1
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N = int(input())
h = list(map(int, input().split()))

ans = 0
while max(h):
    current_hight = 0
    for i in range(len(h)):
        if not h[i]:
            if not current_hight:
                continue
            else:
                break
        elif h[i] < current_hight:
            break
        else:
            current_hight = h[i]
            h[i] -= 1
    ans += 1
    if ans == 75:

print(ans)

N = int(input())
h = list(map(int, input().split()))

ans = 0
while max(h):
    current_hight = 0
    for i in range(len(h)):
        if not h[i]:
            if not current_hight:
                continue
            else:
                break
        elif h[i] < current_hight:
            break
        else:
            current_hight = h[i]
            h[i] -= 1
    ans += 1

print(ans)

Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N = int(input())
h = list(map(int, input().split()))
ans = 0
for i in range(N-1):
  if h[i+1] > h[i]:
    ans += h[i+1]-h[i]
print(ans)

N = int(input())
h = list(map(int, input().split()))
ans = h[0]
for i in range(N-1):
  if h[i+1] > h[i]:
    ans += h[i+1]-h[i]
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
"main.py" 5L, 116C written
def calc_watering_num(h, offset, left, right):
        if left > right:
                return 0
        min_h = None
        min_h_indices = []
        for i in range(left, right + 1):
                if min_h is None or min_h > h[i] - offset:
                        min_h = h[i] - offset
                        min_h_indices = [i]
                elif min_h == h[i] - offset:
                        min_h_indices.append(i)
        if len(min_h_indices) == right - left + 1:
                return min_h
        num = min_h
        prev = left
        for i in min_h_indices:
                num += calc_watering_num(h, offset + min_h, prev, i - 1)
                prev = i + 1
        num += calc_watering_num(h, offset + min_h, prev, right)
        return num


input()
h = [int(v) for v in input().split()]
print(calc_watering_num(h, 0, 0, len(h) - 1))

def calc_watering_num(h, offset, left, right):
        if left > right:
                return 0
        min_h = None
        min_h_indices = []
        for i in range(left, right + 1):
                if min_h is None or min_h > h[i] - offset:
                        min_h = h[i] - offset
                        min_h_indices = [i]
                elif min_h == h[i] - offset:
                        min_h_indices.append(i)
        if len(min_h_indices) == right - left + 1:
                return min_h
        num = min_h
        prev = left
        for i in min_h_indices:
                num += calc_watering_num(h, offset + min_h, prev, i - 1)
                prev = i + 1
        num += calc_watering_num(h, offset + min_h, prev, right)
        return num


input()
h = [int(v) for v in input().split()]
print(calc_watering_num(h, 0, 0, len(h) - 1))

Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N = int(input())
H = list(int(i) for i in input().split())


def count(h):
    print(h)
    if len(h) != 0:
        output = 0
        min_elem = min(h)
        output += min_elem
        for index in range(0, len(h)):
            h[index] -= min_elem
        tmp_h = []
        for index in range(0, len(h)):
            if (h[index] > 0):
                tmp_h.append(h[index])
            else:
                output += count(tmp_h)
                tmp_h = []
        output += count(tmp_h)
        print(output)
        return output
    else:
        return 0

h = H
print(count(h))

N = int(input())
H = list(int(i) for i in input().split())


def count(h):
    if len(h) != 0:
        output = 0
        min_elem = min(h)
        output += min_elem
        for index in range(0, len(h)):
            h[index] -= min_elem
        tmp_h = []
        for index in range(0, len(h)):
            if (h[index] > 0):
                tmp_h.append(h[index])
            else:
                output += count(tmp_h)
                tmp_h = []
        output += count(tmp_h)
        return output
    else:
        return 0

h = H
print(count(h))

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):


#include <algorithm>
using namespace std;

int f(vector<int> v, int i, int a) {
    vector<int>::iterator maxIt = max_element(v.begin(), v.end());
    vector<int>::iterator minIt = min_element(v.begin(), v.end());
    if (v.size() == 0){
        return a;
    }
    if(*maxIt == *minIt) {
        return a + (*minIt) - i;
    }
    a+=*minIt-i;
    i = *minIt;
    size_t minIndex = distance(v.begin(), minIt);
    if (minIndex == 0) {
        vector<int> vec;
        copy(next(v.begin()), v.end(), back_inserter(vec));
        a = f(vec, i, a);
    } else if (minIndex == v.size()) {
        vector<int> vec;
        copy(v.begin(), prev(v.end()), back_inserter(vec));
        a = f(vec, i, a);
    } else {
        vector<int> vec1;
        copy(v.begin(), minIt, back_inserter(vec1));
        a = f(vec1, i, a);
        vector<int> vec2;
        copy(next(minIt), v.end(), back_inserter(vec2));
        a = f(vec2, i, a);
    }
    return a;
}


int main() {
    int n;
    cin >> n;
    vector<int> v(n);
    for (int i=0; i<n; i++) {
        cin >> v[i];
    }
    int a = f(v, 0, 0);

    return 0;
}

n = int(input())
h = list(map(int, input().split()))

maxNum = max(h)
countNumber = 0
countWatering = 0
isfinished = False
for c in range(1, maxNum+1):
    array = []
    for index, num in enumerate(h):
        if (num >= c):
            array.append(index)
    if (len(array) == 0 or c > maxNum):
        break
    startIndex = 0
    beforeVlaue  = array[0]-1
    for a in array:
        if (a-1 != beforeVlaue):
            countWatering+=1
        if (a == array[-1]):
            countWatering+=1
        beforeVlaue = a
    
print(countWatering)

Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n=int(input())
h=list(map(int,input.split()))
hm=max(h)
t=1
for i in range(hm,-1,-1):
    for j in range(n)
        if h[j]=i:
            ans+=t
            t=0
        else:
            t=1

print(ans)


n=int(input())
h=list(map(int,input().split()))
hm=max(h)
t=1
ans=0
for i in range(hm,-1,-1):
    for j in range(n):
        if h[j]=i:
            ans+=t
            t=0
        else:
            t=1

print(ans)


n=int(input())
h=list(map(int,input().split()))
hm=max(h)
t=1
ans=0
for i in range(hm,-1,-1):
    for j in range(n):
        if h[j]==i:
            ans+=t
            t=0
        else:
            t=1

print(ans)


n=int(input())
h=list(map(int,input.split()))
hm=max(h)
t=1
for i in range(hm,-1,-1):
    for j in range(n):
        if h[j]=i:
            ans+=t
            t=0
        else:
            t=1

print(ans)


n=int(input())
h=list(map(int,input().split()))
hm=max(h)

ans=0
for i in range(hm,-1,-1):
    t=1
    for j in range(n):
        if h[j]=i:
            ans+=t
            t=0
        else:
            t=1

print(ans)


n=int(input())
h=list(map(int,input.split()))
hm=max(h)
t=1
ans=0
for i in range(hm,-1,-1):
    for j in range(n):
        if h[j]=i:
            ans+=t
            t=0
        else:
            t=1

print(ans)


n=int(input())
h=list(map(int,input().split()))
hm=max(h)

ans=0
for i in range(hm,0,-1):
    t=1
    for j in range(n):
        if h[j]>=i:
            ans+=t
            t=0
        else:
            t=1

print(ans)


Verdicts: Runtime Error

Runtime Error

Wrong Answer

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
# -*- coding: utf-8 -*-




def mizuyari(ary):
    n = 0
    ary2 = distinctAry(ary)
    
    
    if min(ary) > 0:
        n += 1 + mizuyari([s - 1 for s in ary2])
    
    
    else:
        print(ary2)
        
    return n


def distinctAry(ary):
    
    for i, j in enumerate(ary):
        
        if i + 1 >= len(ary):
            break;
        else:
            if (ary[i] == ary[i + 1]):
                del(ary[i])
    return ary

#main start
import copy

n = int(input())
ary = [int(s) for s in input().split()]

mizuyari(ary)



n = int(input())
l = [int(i) for i in input().split()]

def out(l):
    ll = bunkatu(l)
    
    res = 0
    
    for l in ll:
        
        
        l2 = [i - 1 for i in l]
        
        
        if not l2:
            continue
        
        if max(l2) > 0:
            res += 1 + out(l2)
        else:
            res += 1
        
    return res

def bunkatu(l):
    
    s = 0 #start
    ll = []
    
    for k, v in enumerate(l) :
        
        if v <= 0 :
            ll.append(l[s:k])
            s = k + 1
    
    else:
        if s != k + 1:
            ll.append(l[s:k + 1])
    return ll


print(out(l))

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n=int(input())
h=list(map(int,input().split()))
ans=0
while sum(h)>0:
  for i in range(n):
    if i<n-1 and h[i]>0 and h[i+1]==0:
      ans+=1
    else:
      if i==N-1 and h[i]>0:
        ans+=1
    if h[i]>0:
      h[i]-=1
print(ans)      

n=int(input())
h=list(map(int,input().spliy()))
ans=0
while sum(h)>0:
  for i in range(n):
    if i<n-1 and h[i]>0 and h[i+1]==0:
      ans+=1
    else:
      if i==N-1 and h[i]>0:
        ans+=1
    if h[i]>0:
      h[i]-=1
print(ans)      

n=int(input())
h=list(map(int,input().split()))

ans=0
while sum(h)>0:
  for i in range(n):
    if i<n-1 and h[i]>0 and h[i+1]==0:
      ans+=1
    else:
      if i==N-1 and h[i]>0:
        ans+=1
    if h[i]>0:
      h[i]-=1
print(ans)      

N=int(input())
h=list(map(int,input().split()))

ans=0
while sum(h)>0:
  for i in range(N):
    if i<N-1 and h[i]>0 and h[i+1]==0:
      ans+=1
    else:
      if i==N-1 and h[i]>0:
        ans+=1
    if h[i]>0:
      h[i]-=1
print(ans)      

Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
def mizuyari2(l):
    count = 0
    stopper = 0

    for i in l:
        stopper+=i 
    if(stopper == 0):
        return 0        

    if(l[0]!=0):
        count+=1
    for i in range(len(l)-1):
        if(l[i]==0 and l[i+1]!=0):
            count+=1

    for index,i in enumerate(l):           
        l[index]-=1
        if(l[index]<0):
            l[index]=0

    return count+mizuyari2(l)

N = int(input())
h = []

for i in range(N):
    h.append(int(input()))

print(mizuyari2(h))

def mizuyari2(l):
    count = 0
    stopper = 0

    for i in l:
        stopper+=i 
    if(stopper == 0):
        return 0        

    if(l[0]!=0):
        count+=1
    for i in range(len(l)-1):
        if(l[i]==0 and l[i+1]!=0):
            count+=1
    if(l[len(l)-2]==0 and l[len(l)-1!=0]):
        count+=1

    for index,i in enumerate(l):           
        l[index]-=1
        if(l[index]<0):
            l[index]=0

    return count+mizuyari2(l)

N = int(input())
h = []

for i in range(N):
    h.append(int(input()))

print(mizuyari2(h))

def mizuyari2(l):
    count = 0
    stopper = 0

    for i in l:
        stopper+=i 
    if(stopper == 0):
        return 0        

    if(l[0]!=0):
        count+=1
    for i in range(len(l)-1):
        if(l[i]==0 and l[i+1]!=0):
            count+=1

    for index,i in enumerate(l):           
        l[index]-=1
        if(l[index]<0):
            l[index]=0

    return count+mizuyari2(l)

N = int(input())
h = []

for i in range(N):
    h.append(int(input()))

print(mizuyari2(h))

import array
def count_mizuyari(l):
    count = 0
    arr = array.array('i',[0])
    arr.extend(l)
    for i in range(len(arr)-1):
        if(arr[i]==0 and arr[i+1]!=0):
            count += 1
    return count
    

def mizuyari2(l):
    count = 0
    stopper = 0

    
    for i in l:
        stopper+=i 
    if(stopper == 0):
        return 0 
    else:     
        count=count_mizuyari(l)
    for index,i in enumerate(l):           
        l[index]-=1
        if(l[index]<0):
            l[index]=0

    return count+mizuyari2(l)

N = int(input())
h = array.array('i')

li = input().rstrip().split()
for i in li:
    h.append(int(i))


print(mizuyari2(h))


Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n = int(input())
s = list(map(int,input().split()))
s = [i-1 for i in s]
ans = 0
while(sum(s)!=-n):
    s_new=[i.replace("-1","a") for i in map(str,s)]
    print(s_new)
    s_join = ''.join(s_new)
    non = s_join.split("a")
    num = len([x for x in non if x])
    ans += num
    s = [max(i-1,-1) for i in s]
print(ans)

n = int(input())
s = list(map(int,input().split()))
s = [i-1 for i in s]
ans = 0
while(sum(s)!=-n):
    s_new=[i.replace("-1","a") for i in map(str,s)]
    s_join = ''.join(s_new)
    non = s_join.split("a")
    num = len([x for x in non if x])
    ans += num
    s = [max(i-1,-1) for i in s]
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n = int(input())
h = list(map(int, input().split()))

count = 0

for i in range(n):    
    while h[i] >= 1:
        wid = 0
        for l in range(i,n):
            if h[l] >= 1:
                    wid = wid + 1
            else:
                break
        print(wid)
        
        for k in range(wid):
            h[i + k] = h[i+k] - 1
        print(h)
        count = count + 1

print(count)

n = int(input())
h = list(map(int, input().split()))

count = 0

for i in range(n):    
    while h[i] >= 1:
        wid = 0
        for l in range(i,n):
            if h[l] >= 1:
                    wid = wid + 1
            else:
                break
        
        
        for k in range(wid):
            h[i + k] = h[i+k] - 1
        
        count = count + 1

print(count)

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
import numpy as np
n=int(input())
h=list(map(int,input().split()))
h=np.array(h)
ans=0
while True:
  for i in range(n):
    k=n-i
    cnt=0
    for j in range(1,k):
      if all(hh!=0 for hh in h[i:i+j+1]):
        cnt+=1
    h[i:i+cnt+1]=-1
    ans+=1
print(ans)

n=int(input())
h=list(map(int,input().split()))
h=np.array(h)
ans=0
while True:
  if all(hhh==0 for hhh in h):
    print(ans)
    exit()
  for i in range(n):
    k=n-i
    cnt=0
  for j in range(1,k):
    if all(hh!=0 for hh in h[i:i+j+1]):
      cnt+=1
  h[i:i+cnt+1]=-1
  ans+=1


n=int(input())
h=list(map(int,input().split()))
sum=h[0]
for i in range(n-1):
  if h[i+1]>h[i]:
    sum+=h[i+1]-h[i]
print(sum)

Verdicts: Time Limit Exceeded

Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n=int(input()
h=list(map(int,input().split()))
ans=0
for i in range(max(h)):
      cnt=0
      for j in range(n):
            if h［j］>=i+1:
                  cnt+=1
            elif j==n-1:
                  ans+=cnt
            else:
                  ans+=cnt
                  cnt=0
print(ans)

n=int(input())
h=list(map(int,input().split()))
h.append(0)
ans=0
for i in range(max(h)):
    cnt=0
    for j in range(n+1):
        if h[j]>=i+1:
            cnt+=1
        else:
            if cnt>=1:
                ans+=1
            cnt=0
print(ans)

Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n = int(input())
h = list(map(int,input().split()))
count = h[0]
for i in range(n-1):
    if h[i+1]>h[i]:
        count += h[i+1]-h[i]
print(cnt)


n = int(input())
h = list(map(int,input().split()))
count = h[0]
for i in range(N-1):
    if h[i+1]>h[i]:
        count += h[i+1]-h[i]
print(cnt)

N = int(input())
h = list(map(int,input().split()))
cnt = h[0]
for i in range(N-1):
  if h[i+1]>h[i]:
    cnt += h[i+1]-h[i]
print(cnt)


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n = int(input())
h = list(map(int,input().split()))
ans = 0
while True:
  water = False
  for i in range(n):
    if h[i] > 0:
      h[i] -= 1
      water = True
    elif water:
      ans += 1
      water = False
  if water:
    ans += 1
print(ans)

n = int(input())
h = list(map(int,input().split()))
ans = 0
while True:
  water = False
  finish = True
  for i in range(n):
    if h[i] > 0:
      h[i] -= 1
      water = True
      finish = False
    elif water:
      ans += 1
      water = False
  if water:
    ans += 1
  if finish:
    break
print(ans)

Verdicts: Time Limit Exceeded

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N=int(input())
h=list(map(int,input().split()))









def water(currentnum, currentlist): 
  global count

  
  
  partlist = [] 
  
  for i in range(currentnum):
    if currentlist[i] != 0:
      partlist.append(currentlist[i]) 
    else: 
      
      if len(partlist)==0:
        partlist=[]
      else:    
        water(len(partlist),partlist)
    
      partlist=[]
  
  newlist=[]
  print("")
  print(partlist)
  if len(partlist)==len(currentlist): 
    print(currentlist)
    count = count + 1
    
    for i in range(currentnum):
      newlist.append(currentlist[i]-1)
    water(len(newlist),newlist)
    print(newlist)
    print(count)


count=0
water(N,h)
print(count)


n=int(input())
h=[0]+list(map(int,input().split()))
ans=0
for i in range(n):
  ans += max(h[i+1]-h[i],0)
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
a = [int(i) for i in input().split()] 
n = 0
num = a[0]
for i in a:
  max = a[0]
  
  
  if i > a[n-1] and n > 0:
    num += (i-a[n-1])
  n += 1
print(num)  
  
  
  

l = input()
a = [int(i) for i in input().split()] 
n = 0
num = a[0]
for i in a:
  max = a[0]
  
  
  if i > a[n-1] and n > 0:
    num += (i-a[n-1])
  n += 1
print(num)  
  
  
  

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n = int(input())
h = map(int, input().split())

ans = 0
for i in range(1, n):
  d = h[i] - h[i-1]
  if d > 0:
    ans += d
print(ans)

n = int(input())
h = list(map(int, input().split()))
 
ans = h[0]
for i in range(1, n):
  d = h[i] - h[i-1]
  if d > 0:
    ans += d
print(ans)

Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
#coding: utf-8
import math
import heapq
import bisect
import numpy as np
#from scipy.misc import comb

N = int(input())
h = list(map(int, input().split()))

ans += h[0]
base = h[0]
for i in range(1,N):
    ans += max(h[i]-base,0)
    base = h[i]

print(ans)

#coding: utf-8
import math
import heapq
import bisect
import numpy as np
#from scipy.misc import comb

N = int(input())
h = list(map(int, input().split()))

ans = h[0]
base = h[0]
for i in range(1,N):
    ans += max(h[i]-base,0)
    base = h[i]

print(ans)

Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):

n=int(input())
h=list(map(int, input().split()))
sum=0
for i in range(max(h)):
    if 0 not in h:
        h=[i-1 if i>0 else 0 for i in h]
        sum+=1
        # print(h,1)
    else:
        count0=[i for i, j in enumerate(h) if j==0]
        a=count0.copy() 
        b=count0.copy()
        a.pop(0)
        b.pop(-1)
        c=[x-y for(x,y) in zip(a,b)]
        sum = sum + len(c)-c.count(1)
        print(count0)
        if count0[0]>0 and count0[-1]<n-1:
            sum +=2
            # print(1)
        elif count0[0]>0 or count0[-1]<n-1:
            sum +=1
            # print(2)
        else:
            sum +=0
        h=[i-1 if i>0 else 0 for i in h]
        # print(h,2)
print(sum)                
                

n=int(input())
h=list(map(int, input().split()))
sum=0
for i in range(max(h)):
    if 0 not in h:
        h=[i-1 if i>0 else 0 for i in h]
        sum+=1
    else:
        count0=[i for i, j in enumerate(h) if j==0]
        a=count0.copy() 
        b=count0.copy()
        del a[0]
        del b[-1]
        c=[x-y for(x,y) in zip(a,b)]　
        sum = sum + len(c)-c.count(1)
        if count0[0]>0 and count0[-1]<n-1:
            sum +=2
        elif count0[0]>0 or count0[-1]<n-1:
            sum +=1
        else:
            sum +=0
        h=[i-1 if i>0 else 0 for i in h]
print(sum)   

n,*h=map(int,open(0).read().split());h+=[0];print(sum(max(h[i]-h[i+1],0)for i in range(n)))

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time

sys.setrecursionlimit(10**7)
inf=10**20
mod=10**9+7

def LI(): return list(map(int,input().split()))
def I(): return int(input())
def LS(): return input().split()
def S(): return input()

def main():
  n=I()
  l=LI()

  sm=sum(l)

  c=1
  i=0
  while True:
    if l[i]>0:
      l[i]-=1
      sm-=1

      if i+1==n or l[i+1]==0:
        c+=1

    i+=1
    if i>=n:
      i=0

    if sm==0:
      return c

print(main())


import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time

sys.setrecursionlimit(10**7)
inf=10**20
mod=10**9+7

def LI(): return list(map(int,input().split()))
def I(): return int(input())
def LS(): return input().split()
def S(): return input()

def main():
  n=I()
  l=LI()

  sm=sum(l)

  c=1
  i=0
  while True:
    if l[i]>0:
      l[i]-=1
      sm-=1

      if i+1==n or l[i+1]==0:
        c+=1

    if i+1>=n:
      if l[-1]!=0:
        c+=1
      i=0
    else:
      i+=1

    if sm==0:
      return c

print(main())


import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time

sys.setrecursionlimit(10**7)
inf=10**20
mod=10**9+7

def LI(): return list(map(int,input().split()))
def I(): return int(input())
def LS(): return input().split()
def S(): return input()

def main():
  n=I()
  l=LI()

  sm=sum(l)

  c=0
  i=0
  while True:
    if l[i]>0:
      l[i]-=1
      sm-=1

      if i+1==n or l[i+1]==0:
        c+=1

    i+=1
    if i>=n:
      i=0

    if sm==0:
      return c

print(main())


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N = int(input())
h = list(map(int, input().split()))
ans = 0
for i in range(max(h)):
    h.append(0)
    count = 0
    for k in range(N):
        if h[k] != 0 and h[k + 1] == 0:
            count += 1
    ans += count
    print(count, h)
    h = list(map(lambda x: (x - 1, 0)[x == 0], h))
print(ans)

N = int(input())
h = list(map(int, input().split()))
ans = 0
count = 0
h.append(0)
f = set(h)
for i in range(max(h)):
    if i in f:
        count = 0
        for k in range(N):
            if h[k] != 0 and h[k + 1] == 0:
                count += 1
    ans += count
    h = list(map(lambda x: (x - 1, 0)[x == 0], h))
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
import sys
import numpy as np


def count_water(np_arr):
  least = min(np_arr)
  div_p = np.where(np_arr == least)[0]
  np_arr -= least
  return least + count_water(np_arr[:div_p]) + count_water(np_arr[div_p + 1:])


def main():
  readline = sys.stdin.readline
  
  n = int(readline().rstirp())
  h = np.array(tuple(int(_) for _ in readline().rstrip().split()))
  
  print(count_water(h))

 
if __name__ == "__main__":
  main()


import sys
import numpy as np


def count_water(np_arr):
  if not np_arr.any():
    return 0
  least = min(np_arr)
  div_p = np.where(np_arr == least)[0][0]
  np_arr -= least
  return least + count_water(np_arr[:div_p]) + count_water(np_arr[div_p + 1:])


def main():
  readline = sys.stdin.readline
  
  n = int(readline().rstrip())
  h = np.array(tuple(int(_) for _ in readline().rstrip().split()))
  
  print(count_water(h))

 
if __name__ == "__main__":
  main()


Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
def water(flowers, count):
    print(f'count : {count}')
    print(f'flowers : {flowers}')
    if len(flowers) is 0:
        return count
    count = count + min(flowers)
    flowers = [int(e-min(flowers)) for e in flowers]
    while 0 in flowers:
        count = water(flowers[:flowers.index(0)], count)
        flowers = flowers[flowers.index(0)+1: ]
    count = water(flowers, count)
    return count

n = int(input())
flowers = [int(e) for e in input().split()]

count = 0
print(f'Initialize : {flowers}')
water(flowers, count)
# while flowers.count(0) != 0:
#     print(f'{"="*20} iteration{i}')

#     print(f'flowers : {flowers}')
#     print(f'count : {count}')

def water(flowers, count):
    if len(flowers) is 0:
        return count
    count = count + min(flowers)
    flowers = [int(e-min(flowers)) for e in flowers]
    while 0 in flowers:
        count = water(flowers[:flowers.index(0)], count)
        flowers = flowers[flowers.index(0)+1: ]
    count = water(flowers, count)
    return count

n = int(input())
flowers = [int(e) for e in input().split()]

count = 0
count = water(flowers, count)
print(count)

Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n = int(input())
h = list(map(int,input().split()))
a = 0
while sum(h) > 0:
    lst = [i for i, x in enumerate(h) if x > 0]
    mx = min(lst)
    for i in range(len(lst) -1):
        if lst[i] + 1 == lst[i+1]:
            mx += 1
        else:
            break
    h = [x - 1 if i >= min(lst) and  i <= mx else x for i, x in enumerate(h)]
    a += 1
    print(h)
print(a)

n = int(input())
h = list(map(int,input().split()))
a = 0
while sum(h) > 0:
    lst = [i for i, x in enumerate(h) if x > 0]
    mx = min(lst)
    for i in range(len(lst) -1):
        if lst[i] + 1 == lst[i+1]:
            mx += 1
        else:
            break
    h = [x - 1 if i >= min(lst) and i <= mx else x for i, x in enumerate(h)]
    a += 1
print(a)

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
 = int(input())
h = list(map(int, input().split()))

ans = 0
cnt = 0

for i in range(1, max(h) + 1)[::-1]:
    cnt = 0
    for j in range(n):
        if h[j] == i:
            h[j] -= 1
            cnt += 1
            if j + 1 < n:
                if h[j + 1] == i:
                    cnt -= 1
    ans += cnt

print(ans)

n = int(input())
h = list(map(int, input().split())) + [0]

ans = 0
cnt = 0

for i in range(1, max(h) + 1)[::-1]:
    cnt = 0
    for j in range(n):
        if h[j] == i:
            h[j] -= 1
            cnt += 1
            if h[j + 1] == i:
                cnt -= 1
    ans += cnt

print(ans)

Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N = int(input())

height = list(map(int,input().split()))

ans = 0
interval = 0

for i in range(N):
  
  if height[i] > interval:
　　
　　
   
    ans += height[i] - interval
    interval += height[i] - interval
  
  else:
    interval = height[i]

print(ans)

N = int(input())
height = list(map(int,input().split()))

flowers = [0] * N

start = 0
end = 0
con = 0

while flowers != height:
  for i in range(0,N):
    if height[i] > flowers[i]:
      start = i
      print(flowers)
      for j in range(start,N):
        if height[j] > flowers[j]:
          flowers[j] += 1
        elif height[j] == flowers[j]:
          con += 1
          break

      else:
        con += 1
        break

print(con)

N = int(input())

height = list(map(int,input().split()))

ans = 0
interval = 0

for i in range(N):
  
  if height[i] > interval:
   
   
   
    ans += height[i] - interval
    interval += height[i] - interval
  
  else:
    interval = height[i]

print(ans)

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N = int(input())
H = list(map(int, input().split()))

ans = 0
while any(H):
    water = min(h for h in H if h)
    cnt = 0
    for x, y in zip(H[:-1], H[1:]):
        if x > y and y == 0:
            cnt += 1
        elif x < y and x == 0:
            cnt += 1
    ans += water * (cnt // 2 + 1)
    H = [max(0, h-water) for h in H]


print(ans)

N = int(input())
H = [0] + list(map(int, input().split())) + [0]

ans = 0
while any(H):
    water = min(h for h in H if h)

    cnt = 0
    bl = 0
    for x, y in zip(H[:-1], H[1:]):
        if x < y and x == 0:
            bl = 1
        elif x > y and y == 0 and bl:
            cnt += 1
            bl = 0
    ans += water * cnt
    H = [max(0, h-water) for h in H]


print(ans)

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n = int(input())
h = list(map(int, input().split()))
ans = 0
p = 0
for i in range(n):
    if p <= h[i]:
        ans += h[i]-p
    p = h[i]
    print(p)
print(ans)

n = int(input())
h = list(map(int, input().split()))
ans = 0
p = 0
for i in range(n):
    if p <= h[i]:
        ans += h[i]-p
    p = h[i]
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: There are N pieces of sushi. Each piece has two parameters: "kind of topping" t_i and "deliciousness" d_i. You are choosing K among these N pieces to eat. Your "satisfaction" here will be calculated as follows:    * The satisfaction is the sum of the "base total deliciousness" and the "variety bonus".   * The base total deliciousness is the sum of the deliciousness of the pieces you eat.   * The variety bonus is x*x, where x is the number of different kinds of toppings of the pieces you eat.  You want to have as much satisfaction as possible. Find this maximum satisfaction.

Submission attempts (in order):
from heapq import heappop, heappush
N, K = map(int, input().split())
KMAX = 10 ** 5 + 1
TD = []
for _ in range(N):
    t, d = map(int, input().split())
    TD.append((d, t))

TD.sort(reverse=True)

pioneer = []
successor = []
appear = [False] * KMAX
cnt = 0
nsp = 0  # num of species
base = 0
best = []

for td in TD:
    d, t = td
    if cnt < K:
        heappush(successor if appear[t] else pioneer, (d, t))
        nsp += 0 if appear[t] else 1
        appear[t] = True
        base += d
        cnt += 1
        if cnt == K-1:
            heappush(best, -(base + nsp ** 2))
        continue
    if not successor:
        break
    if appear[t]:
        continue
    cd, ct = heappop(successor)
    appear[t] = True
    heappush(pioneer, (d, t))
    base += (d-cd)
    nsp += 1
    heappush(best, -(base + nsp ** 2))

print(-heappop(best))


from heapq import heappop, heappush
N, K = map(int, input().split())
KMAX = 10 ** 5 + 1
TD = []
for _ in range(N):
    t, d = map(int, input().split())
    TD.append((d, t))

TD.sort(reverse=True)

pioneer = []
successor = []
appear = [False] * KMAX
cnt = 0
nsp = 0  # num of species
base = 0
best = []

for td in TD:
    d, t = td
    if cnt < K:
        heappush(successor if appear[t] else pioneer, (d, t))
        nsp += 0 if appear[t] else 1
        appear[t] = True
        base += d
        cnt += 1
        if cnt == K:
            heappush(best, -(base + nsp ** 2))
        continue
    if not successor:
        break
    if appear[t]:
        continue
    cd, ct = heappop(successor)
    appear[t] = True
    heappush(pioneer, (d, t))
    base += (d-cd)
    nsp += 1
    heappush(best, -(base + nsp ** 2))

print(-heappop(best))


Verdicts: Runtime Error

Accepted
Problem: There are N pieces of sushi. Each piece has two parameters: "kind of topping" t_i and "deliciousness" d_i. You are choosing K among these N pieces to eat. Your "satisfaction" here will be calculated as follows:    * The satisfaction is the sum of the "base total deliciousness" and the "variety bonus".   * The base total deliciousness is the sum of the deliciousness of the pieces you eat.   * The variety bonus is x*x, where x is the number of different kinds of toppings of the pieces you eat.  You want to have as much satisfaction as possible. Find this maximum satisfaction.

Submission attempts (in order):
n, k = map(int, input().split())
sushi = []
for i in range(n):
    tmp = list(map(int, input().split()))
    sushi.append(tmp)
eaten = set() 
chohuku = [] 
scores = [] 

sushi.sort(key=lambda x:x[1])
sushi.reverse() 

tmp = 0 
for i in range(k): 
    if sushi[i][0] in eaten: 
        chohuku.append(sushi[i][1])
    else:
        eaten.add(sushi[i][0]) 
    tmp += sushi[i][1] 
chohuku.sort()
scores.append(tmp+len(eaten)**2) 
print(chohuku)

for i in range(k,n):
    if not sushi[i][0] in eaten:
        tmp -= chohuku.pop()
        eaten.add(sushi[i][0])
        tmp += sushi[i][1]
        scores.append(tmp+len(eaten)**2)
        
print(max(scores))

n, k = map(int, input().split())
sushi = []
for i in range(n):
    tmp = list(map(int, input().split()))
    sushi.append(tmp)
eaten = set() 
chohuku = [] 
scores = [] 

sushi.sort(key=lambda x:x[1])
sushi.reverse() 

tmp = 0 
for i in range(k): 
    if sushi[i][0] in eaten: 
        chohuku.append(sushi[i][1])
    else:
        eaten.add(sushi[i][0]) 
    tmp += sushi[i][1] 
chohuku.sort()
scores.append(tmp+len(eaten)**2) 

for i in range(k,n):
    if not sushi[i][0] in eaten and chohuku != []:
        tmp -= chohuku.pop(0)
        eaten.add(sushi[i][0])
        tmp += sushi[i][1]
        scores.append(tmp+len(eaten)**2)
        
print(max(scores))

Verdicts: Runtime Error

Accepted