TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n = int(input())
a = list(map(int, input().split()))

b = [0 for i in range(n)]

A = 0

for i in range(n):
  A = A ^ a[i]
  
for i in range(n):
  b[i] = A ^ a[i]

print(b)

n = int(input())
a = list(map(int, input().split()))

b = [0 for i in range(n)]

A = 0

for i in range(n):
  A = A ^ a[i]
  
for i in range(n):
  b[i] = A ^ a[i]

print(' '.join(map(str, b)))

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n = int(input())
arr = list(map(int,input().split()))
xors = 0
for val in arr:
  xors^=val
ans = []
for i in range(n):
  ans.append(xros^arr[i])
  
print(*ans)

n = int(input())
arr = list(map(int,input().split()))
xors = 0
for val in arr:
  xors^=val
ans = []
for i in range(n):
  ans.append(xors^arr[i])
  
print(*ans)


Verdicts: Runtime Error

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
N = int(input())
A = list(map(int, input().split()))
count = 0
for i in A:
    count ^= x
for i in range(len(A)):
    A[i] ^= count
    
    
    
print(*A)

N = int(input())
A = list(map(int, input().split()))
count = 0
for i in A:
    count ^= i
for i in range(len(A)):
    A[i] ^= count
    
    
print(*A)

Verdicts: Runtime Error

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
N = int(input())
aaa = list(map(int, input().split()))
bbb = list(aaa[i] ^ aaa[i+1] for i in range(N-1))
ans = [0] * N
ans[0] = 1
for i, b in enumerate(bbb):
    ans[i+1] = b ^ ans[i]
print(*ans,sep=' ')


N = int(input())
aaa = list(map(int, input().split()))
a_all = 0
for a in aaa:
    a_all ^= a
print(*list(a_all ^ a for a in aaa))


Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
from sys import stdin
input = stdin.readline

N = int(input())
a = list(map(int, input().split()))

ans = []

for i in range(N - 1):
    ans.append(a[i] ^ a[i + 1])

ans.append(a[0] ^ a[N - 1])

print(*ans)


from sys import stdin
input = stdin.readline

N = int(input())
a = list(map(int, input().split()))

ans = []

for i in range(N - 1):
    ans.append(a[i] & a[i + 1])

ans.append(a[0] & a[N - 1])

print(*ans)


from sys import stdin
input = stdin.readline

N = int(input())
A = list(map(int, input().split()))

xor_all = 0

for a in A:
    xor_all = xor_all ^ a

ans = []

for a in A:
    ans.append(xor_all ^ a)

print(*ans)


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n=int(input())
a=list(map(int,input().split()))
p=0
for x in a:
	p^=x
ans=[]
for x in a:
	ans.append(p^x)
print(ans)

n=int(input())
a=list(map(int,input().split()))
p=0
for x in a:
	p^=x
ans=[]
for x in a:
	ans.append(p^x)
print(*ans)

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n = int(input())
lis = list(map(int, input().split()))

s = 0
for i in lis:
    s = s^i
lis = list(map(lambda x: str(-(-s^x)), lis))
st = ' '.join(lis)
print(st)

n = int(input())
lis = list(map(int, input().split()))

s = 0
for i in lis:
    s = s^i
lis = list(map(lambda x: str(s^x), lis))
st = ' '.join(lis)
print(st)

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
import sys
sys.setrecursionlimit(10**6)

n = int(input())
a = list(map(int, input().split()))
#n, m = map(int, input().split())
#s = input()
#s,t = input().split()
#a = [int(input()) for _ in range(n)]
#
#readline = sys.stdin.readline

#ab = [[int(i) for i in readline().split()] for _ in range(n)]

su = 0

for i in range(1, n):
    su ^= a[i]
    
ans = [su]

for i in range(n-1):
    su = su ^ a[i] ^ a[i+1]
    ans.append(su)
    
print(*su)

import sys
sys.setrecursionlimit(10**6)

n = int(input())
a = list(map(int, input().split()))
#n, m = map(int, input().split())
#s = input()
#s,t = input().split()
#a = [int(input()) for _ in range(n)]
#
#readline = sys.stdin.readline

#ab = [[int(i) for i in readline().split()] for _ in range(n)]

su = 0

for i in range(1, n):
    su ^= a[i]
    
ans = [su]

for i in range(n-1):
    su = su ^ a[i] ^ a[i+1]
    ans.append(su)
    
print(*ans)

Verdicts: Runtime Error

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
N = int(input())
A_list = [int(e) for e in input().split()]

all_A_xor = A_list[0]
#print(A_list[0],bin(A_list[0]))

for i in range(1,N):
    #print(A_list[i],bin(A_list[i]))
    all_A_xor ^= A_list[i]

#print(all_A_xor,bin(all_A_xor))

ans = [A^all_A_xor for A in A_list]
print(ans)

N = int(input())
A_list = [int(e) for e in input().split()]

all_A_xor = A_list[0]
#print(A_list[0],bin(A_list[0]))

for i in range(1,N):
    #print(A_list[i],bin(A_list[i]))
    all_A_xor ^= A_list[i]

#print(all_A_xor,bin(all_A_xor))

ans = [A^all_A_xor for A in A_list]
print(' '.join(map(str, ans)))

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
import sys
from collections import Counter
readline = sys.stdin.buffer.readline

n = int(readline())
a = list(map(int, readline().split()))

for j in range(n):
  b = 0
  for i, v in enumerate(a):
    if i != j:
      b ^= v
  print(b)

import sys
from functools import reduce
from operator import xor
readline = sys.stdin.buffer.readline

n = int(readline())
a = tuple(map(int, readline().split()))

s = reduce(xor, a[1:], a[0])
# print(s)
b = tuple(str(s ^ v) for v in a)
print(' '.join(b))

Verdicts: Time Limit Exceeded

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
N = int(input())
a_list = list(map(int, input().split()))
all_xor = 0
res = []

for a in a_list:
    all_xor ^= a

for a in a_list:
    res.append(a ^ all_xor)

print(res)


N = int(input())
a_list = list(map(int, input().split()))
all_xor = 0
res = []

for a in a_list:
    all_xor ^= a

for a in a_list:
    res.append(a ^ all_xor)

print(*res)


Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n = int(input())
a = list(map(int, input().split()))
x = 0
for i in range(1, n):
  x = x^a[i]
  
l = [x]
for i in range(n-1):
  x = a[i]^a[i+1]
  l.append(l[i]^x)
print(l)



n = int(input())
a = list(map(int, input().split()))
x = 0
for i in range(1, n):
  x = x^a[i]
  
l = [x]
for i in range(n-1):
  x = a[i]^a[i+1]
  l.append(l[i]^x)
print(*l)



Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
N = int(input())
A = list(map(int, input().split()))

p = 0
for i in range(1, N):
    p ^= A[i]
print(p)

ans = [str(p)]
for i in range(1, N):
    t = A[i-1] ^ A[i]
    p = p ^ t
    ans.append(str(p))
print(" ".join(ans))


N = int(input())
A = list(map(int, input().split()))

p = 0
for i in range(1, N):
    p ^= A[i]

ans = [str(p)]
for i in range(1, N):
    t = A[i-1] ^ A[i]
    p = p ^ t
    ans.append(str(p))
print(" ".join(ans))


Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
N = int(input())
A = list(map(int, input().split()))

s = 0
for a in A:
	s ^= a
	print(s)
ans = []

for a in A:
	ans += [str(a ^ s)]
print(' ' .join(ans))

N = int(input())
A = list(map(int, input().split()))

s = 0
for a in A:
	s ^= a
ans = []

for a in A:
	ans += [str(a ^ s)]
print(' ' .join(ans))

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
N = int(input())
a = list(map(int, input().split()))

b = [0]*N

for i in range(1,N):
    b[i] = b[i-1] ^ a[i-1] ^ a[i]

print(" ".join(map(str, b)))

N = int(input())
a = list(map(int, input().split()))

b = [0]*N

xorsum = 0
for i in range(1,N):
    b[i] = b[i-1] ^ a[i-1] ^ a[i]
    xorsum = xorsum ^ b[i]

b[0] = xorsum ^ a[0]

for i in range(1,N):
    b[i] = b[i-1] ^ a[i-1] ^ a[i]

print(" ".join(map(str, b)))

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n=int(input())
a=list(map(int,input().split()))
wk=0
for i in range(0,n,2):
  wk^=a[i]^a[i+1]
ans=[]
for i in range(n):
  ans.append(str(wk^a[i]))
print(" ".join(list(set(ans))))

n=int(input())
a=list(map(int,input().split()))
wk=0
for i in range(0,n,2):
  wk^=a[i]^a[i+1]
ans=[]
for i in range(n):
  ans.append(str(wk^a[i]))
print(" ".join(ans))

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n = int(input())
a = list(map(int, input().split()))

keta = len(bin(max(a))) - 2
tmp = [0] * keta
for i in a:
    for j, k in enumerate(bin(i)[2:][::-1]):
        tmp[j] += int(k)
tmp = tmp[::-1]

ans = [""] * n
for i in tmp:
    for j in range(n):
        if i > 0:
            ans[j] += "0"
            i -= 1
        else:
            ans[j] += "1"

ans_ = []
for i in ans:
    ans_.append(int(i, 2))
print(*ans_)

n = int(input())
a = list(map(int, input().split()))

xor = 0
for i in a:
    xor ^= i

ans = []
for i in a:
    ans.append(xor ^ i)
print(*ans)


Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n=int(input())
a_array=list(map(int,input().split()))
next_xor=[0 for _ in range(n-1)]
for i in range(n-1):
    next_xor[i]=a_array[i]^a_array[i+1]
ans=[2<<28]
for xo in next_xor:
    ans.append(ans[-1]^xo)
print(" ".join(map(str,ans)))

import math

n=int(input())
a_array=list(map(int,input().split()))
next_xor=[0 for _ in range(n-1)]
max_dig=math.floor(math.log2(a_array[0]))
for i in range(n-1):
    next_xor[i]=a_array[i]^a_array[i+1]
    max_dig=math.floor(math.log2(a_array[i+1]))
flag_1=True
ans_1=[0]
ans_2=[2<<max_dig]
SUP=10**9
for xo in next_xor:
    if ans_1[-1]^xo >= SUP:
        flag_1=False
    ans_1.append(ans_1[-1]^xo)
    ans_2.append(ans_2[-1]^xo)
print(" ".join(map(str,ans_1 if flag_1 else ans_2)))

n=int(input())
a_array=list(map(int,input().split()))
all_xor=0
for a in a_array:
    all_xor^=a
print(" ".join([str(all_xor^a) for a in a_array]))

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
N=int(input())
a=list(map(int,input().split()))
S=0
for i in a:
  S^=i
print([i^S for i in a])

N=int(input())
a=list(map(int,input().split()))
S=0
for i in a:
  S^=i
a=[S^i for i in a]  
print(*a)

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
def main():
    N = int(input())
    a = list(map(int, input().split()))
    
    ans = a
    for i in range(10):
        c0,c1 = 0,0
        for j in range(N):
            if (a[j]>>i)&1:
                c1+=1
        if c1%2==0:
            ans[j] += (a[j]>>i)*pow(2,i)
        else:
            ans[j] += (((a[j]>>i)+1)%2)*pow(2,i)
    print(*ans)

main()


def main():
    N = int(input())
    a = list(map(int, input().split()))
    
    ans = a
    for i in range(10):
        c0,c1 = 0,0
        for j in range(N):
            if (a[j]>>i)&1:
                c1+=1
        if c1%2==0:
            ans[j] += (a[j]>>i)*pow(2,i)
    print(*ans)

main()


def main():
    N = int(input())
    a = list(map(int, input().split()))
    
    s = a[0]
    for i in range(1,N):
        s ^= a[i]
    ans = a
    for i in range(N):
        ans[i] ^= s
    print(*ans)

main()


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n = int(input())
xor_arr = list(map(int, input().split()))
xor_of_xor = 0
for elm in xor_arr:
    xor_of_xor = xor_of_xor ^ elm
scarf_val = [xor_of_xor ^ elm for elm in xor_arr]

print(scarf_val)

    n = int(input())
    xor_arr = list(map(int, input().split()))
    xor_of_xor = 0
    for elm in xor_arr:
        xor_of_xor = xor_of_xor ^ elm
    scarf_val = [xor_of_xor ^ elm for elm in xor_arr]
     
    print(" ".join(str(x) for x in scarf_val))

        n = int(input())
        xor_arr = list(map(int, input().split()))
        xor_of_xor = 0
        for elm in xor_arr:
            xor_of_xor = xor_of_xor ^ elm
        scarf_val = [xor_of_xor ^ elm for elm in xor_arr]
        print(" ".join(str(x) for x in scarf_val))

n = int(input())
xor_arr = list(map(int, input().split()))
xor_of_xor = 0
for elm in xor_arr:
    xor_of_xor = xor_of_xor ^ elm
scarf_val = [xor_of_xor ^ elm for elm in xor_arr]
         
print(" ".join(str(x) for x in scarf_val))

Verdicts: Wrong Answer

Runtime Error

Runtime Error

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
N = int(input())
A = list(map(int,input().split()))

l = [0]*(2**max(A))
ll = []
for a in A:
  pattern = bin(a)[2:].zfill(N)
  for i in range(len(pattern)):
    if pattern[i] == '1':
      l[i] += 1

for a in A:
  ans = ''
  pattern = bin(a)[2:].zfill(N)
  for i in range(len(pattern)):
    if pattern[i] == '1' and int(l[i])%2 == 0:
      ans += '1'
    elif pattern[i] == '0' and int(l[i])%2 != 0:
      ans += '1'
    else:
      ans += '0'
  ll.append(int(ans,2))
print(*ll)

N = int(input())
A = list(map(int,input().split()))
num = 0
for a in A:
  num ^= a

l = []

for a in A:
  ans = a^num
  l.append(ans)
print(*l)

Verdicts: Runtime Error

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n=int(input(""))
a=[]
ans=[1]
ain=input("").split(" ")
for i in range(n):
    a+=[int(ain[i])]
s=a[1]
for i in range(n-2):
    s^=a[i+2]
ans[0]=s
for i in range(n-1):
    s=s^a[i]
    s^=a[i+1]
    ans+=s
print(" ".join(ans))


    


n=int(input(""))
a=[]
ans=[1]
ain=input("").split(" ")
for i in range(n):
    a+=[int(ain[i])]
s=a[1]
for i in range(n-2):
    s^=a[i+2]
ans[0]=s
for i in range(n-1):
    s=s^a[i]
    s^=a[i+1]
    ans+=[s]
b=[]
for i in range(n):
    b+=[str(ans[i])]
print(" ".join(b))


    


Verdicts: Runtime Error

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
from functools import reduce
def resolver(N, A):
    X = reduce(int.__xor__, A)
    ans = [X^a for a in A]
    
    return ans

def test():
    pass

def main():

    #test()

    N = int(input())
    A = list(map(int, input().split()))
    ans = resolver(N, A)

    print(ans)



if __name__ == '__main__':
    main()

from functools import reduce
def resolver(N, A):
    X = reduce(int.__xor__, A)
    ans = [str(X^a) for a in A]
    
    return ans

def test():
    pass

def main():

    #test()

    N = int(input())
    A = list(map(int, input().split()))
    ans = resolver(N, A)

    print(" ".join(ans))
    



if __name__ == '__main__':
    main()

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n=int(input())
alist=list(map(int,input().split()))

allh=alist[0]^alist[1]
for i in range(n-1):
    allh = allh ^ alist[i+2]

outlist=[]
for a in alist:
    outlist.append(str(allh ^ a))
    outlist.append(" ")
outlist.pop()
print("".join(outlist))


n=int(input())
alist=list(map(int,input().split()))

allh=alist[0]^alist[1]
for i in range(n-1):
    allh = allh ^ alist[i+1]

outlist=[]
for a in alist:
    outlist.append(str(allh ^ a))
    outlist.append(" ")
outlist.pop()
print("".join(outlist))


n=int(input())
alist=list(map(int,input().split()))

allh=alist[0]^alist[1]
for i in range(n-2):
    allh = allh ^ alist[i+2]

outlist=[]
for a in alist:
    outlist.append(str(allh ^ a))
    outlist.append(" ")
outlist.pop()
print("".join(outlist))


Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
#!/usr/bin/env python3
import sys
import numpy as np
input = sys.stdin.readline
n=int(input())
A =  list(map(int,input().split()))
B = []
ans = A[0]
for i in range(1,n):
    ans = ans ^ A[i]

for i in range(n):
    B.append(ans ^ A[i])
print(B)
    

#!/usr/bin/env python3
import sys
import numpy as np
input = sys.stdin.readline
n=int(input())
A =  list(map(int,input().split()))
B = []
ans = A[0]
for i in range(1,n):
    ans = ans ^ A[i]


for i in range(n):
    B.append(ans ^ A[i])
L=[str(a) for a in B]
L=" ".join(L)
print(L)

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
n = int(input())
lis = list(map(int, input().split()))

t = lis[0]
for i in range(1, n):
    t ^= i

ans = [0] * n
for i , j in enumerate(lis):
    ans[i] = t ^ j

print(*ans)

n = int(input())
lis = list(map(int, input().split()))

t = lis[0]
for i in range(1, n):
    t ^= lis[i]

ans = [0] * n
for i , j in enumerate(lis):
    ans[i] = t ^ j

print(*ans)

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
import sys
import math
import itertools
import bisect
from copy import copy
from collections import deque,Counter
from decimal import Decimal
def s(): return input()
def i(): return int(input())
def S(): return input().split()
def I(): return map(int,input().split())
def L(): return list(input().split())
def l(): return list(map(int,input().split()))
def lcm(a,b): return a*b//math.gcd(a,b)
sys.setrecursionlimit(10 ** 9)
mod = 10**9+7

N = i()
a = l()
A = 0
for i in range(N):
    A = A^a[i]
bit = bin(A)[2:]
n = len(bit)
bits = []
for i in range(N):
    bits.append(bin(a[i])[2:])
ans = []
maxlen = len(bin(max(a))[2:])
bit = list(bit.zfill(maxlen))[::-1]
for i in range(N):
    b = list(bits[i].zfill(maxlen))[::-1]
    num = 0
    print(bit,b)
    for j in range(maxlen):
        if bit[j] != b[j]:
            num += 2**j
    ans.append(num)
print(*ans)

import sys
import math
import itertools
import bisect
from copy import copy
from collections import deque,Counter
from decimal import Decimal
def s(): return input()
def i(): return int(input())
def S(): return input().split()
def I(): return map(int,input().split())
def L(): return list(input().split())
def l(): return list(map(int,input().split()))
def lcm(a,b): return a*b//math.gcd(a,b)
sys.setrecursionlimit(10 ** 9)
mod = 10**9+7

N = i()
a = l()
A = 0
for i in range(N):
    A = A^a[i]
bit = bin(A)[2:]
n = len(bit)
bits = []
for i in range(N):
    bits.append(bin(a[i])[2:])
ans = []
maxlen = len(bin(max(a))[2:])
bit = list(bit.zfill(maxlen))[::-1]
for i in range(N):
    b = list(bits[i].zfill(maxlen))[::-1]
    num = 0
    for j in range(maxlen):
        if bit[j] != b[j]:
            num += 2**j
    ans.append(num)
print(*ans)

Verdicts: Wrong Answer

Accepted
Problem: There are N Snuke Cats numbered 1, 2, \ldots, N, where N is **even**.  Each Snuke Cat wears a red scarf, on which his favorite non-negative integer is written.  Recently, they learned the operation called xor (exclusive OR).  What is xor?  For n non-negative integers x_1, x_2, \ldots, x_n, their xor, x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is defined as follows:    * When x_1~\textrm{xor}~x_2~\textrm{xor}~\ldots~\textrm{xor}~x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.   For example, 3~\textrm{xor}~5 = 6.  They wanted to use this operation quickly, so each of them calculated the xor of the integers written on their scarfs except his scarf.  We know that the xor calculated by Snuke Cat i, that is, the xor of the integers written on the scarfs except the scarf of Snuke Cat i is a_i. Using this information, restore the integer written on the scarf of each Snuke Cat.

Submission attempts (in order):
import numpy as np
n=int(input())
*a,=map(int, input().split())
x=0
for ai in a:
    x^=ai

ans=[ai^x for ai in ans]
print(*ans)

n=int(input())
*a,=map(int, input().split())
x=0
for ai in a:
    x^=ai

a=[ai^x for ai in a]
print(*a)

Verdicts: Runtime Error

Accepted