TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
n=int(input())
val=n
for i in range(2,n):
    val+=n//i
print(val+1)

k=int(input())
n=k-1
val=n
if k==2:
    print(1)
else:
    for i in range(2,n):
        val+=n//i
    print(val+1)

Verdicts: Wrong Answer

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
N = int(input())
count = 0

for a in range(1, N+1):
  tmp = (N-1) // a
  if a == tmp:
    count += 1
  if a < N // 2:
    count += tmp
  else:
    count += 1          

print(count-1)

N = int(input())
count = 0

for a in range(1, N):
  tmp = (N-1) // a
  if a < (N) // 2:
    count += tmp
  else:
    count += 1          

print(count)

N = int(input())
count = 0

for a in range(1, N):
  tmp = (N-1) // a
  if a <= (N) // 2:
    count += tmp
  else:
    count += 1          

print(count)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
N = int(input())

ans = 0

for a in range(1, N + 1):
   for b in range(1, N // a):
      if a * b <= N:
         ans += 1

print(ans)

N = int(input())

ans = 0

for a in range(1, N + 1):
   for b in range(1, N + 1):
      if a * b <= N:
         ans += 1

print(ans)

n = int(input())
ans = 0
for a in range(1, n):
  ans += (n - 1) // a
print(ans)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
n = int(input())

cnt = 0
for r in range(1, n):
    for a in range(1, (a // 2) +1):
        if r % a == 0:
            cnt += 1
print(cnt)


cnt = 0
for a in range(1, n):
    cnt +=(n -1)// a
print(cnt)

n = int(input())

cnt = 0
for a in range(1, n):
    cnt +=(n -1)// a
print(cnt)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
def make_divisors(n):
    lower_divisors , upper_divisors = [], []
    i = 1
    while i*i <= n:
        if n % i == 0:
            lower_divisors.append(i)
            if i != n // i:
                upper_divisors.append(n//i)
        i += 1
    return lower_divisors + upper_divisors[::-1]

n = int(input())
count = 0
for i in range(n):
    i += 1
    count += len(make_divisors(n))
print(count)

import math

n = int(input())
count = 0
for i0 in range(n):
    i0 += 1
    count += math.floor(n / i0)
    if n - (math.floor(n / i0) * i0) == 0:
        count -= 1
print(count)

Verdicts: Wrong Answer

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
N  =int(input())
c = 0
for i in range(N):
  c += n-1//i+1
print(c)  
  


N  =int(input())
c = 0
for i in range(N):
  c += N-1//i+1
print(c)  
  


N  =int(input())
c = 0
for i in range(N):
  c += (N-1)//(i+1)
print(c)  
  


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
n = int(input())

ans = 0

print((n-1)+len(range(n**(1/2))))

n = int(input())
ans = 0
for a in range(1, n):
  ans += (n - 1) // a
print(ans)

Verdicts: Runtime Error

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
import numpy as np
num=int(input())-1
m=np.outer([a+1 for a in range(num)],[a+1 for a in range(num)])
print(m)
m=np.where(m<=num,1,0)
print(np.sum(m))

import numpy as np
num=int(input())
count=0
for a in range(num-1):
  tmp=int(num/(a+1))
  if num%(a+1)==0:
    count+=tmp-1
  else:
    count+=tmp
print(count)

Verdicts: Runtime Error

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
N=int(input())
#A,B,C>0 C=N-A*B
count=0
for A in range(1,N):
    for B in range(1,N):
        print(A,B,N-A*B)
        if N-(A*B)>0:
            count+=1
print(count)

N=int(input())
count=0
for A in range(1,N):
    count+=int((N-1)/A)
print(count)

Verdicts: Wrong Answer

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
n = int(input())
ans = 0
for i in range(1,n-1):
  ans+= (n-1)//i
print(ans);
  

n = int(input())
ans = 0
if n == 1:
  print(0)
elif n == 2:
  print(1)
else:
  for i in range(1,n-1):
    ans+= (n-1)//i
  print(ans);  


N = int(input())
 
result = 0
for A in range(1, N + 1):
    result += (N - 1) // A
print(result)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
n = int(input())
count = 0
for c in range(n):
    ab = n - c
    if ab % a == 0:
        count += 1
print(count)

n = int(input())
count = 0
for c in range(n):
	ab = n - c
    if ab % a = 0:
      count += 1
print(count)

n = int(input())
count = 0
for a in range(1,n):
    count += int((n-1)/a)
print(count)n = int(input())
count = 0
for a in range(1,n):
    count += int((n-1)/a)
print(count)

n = int(input())
count = 0
for a in range(1,n):
    count += (n-1)//a
print(count)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
n = int(input())
cnt = 0
for a in range(1,n):
    cnt += (n-1)//a
print(cnt)n = int(input())
cnt = 0
for a in range(1,n):
    cnt += (n-1)//a
print(cnt)

n = int(input())
cnt = 0
for a in range(1,n):
    cnt += (n-1)//a
print(cnt)

Verdicts: Runtime Error

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
import sympy
N=int(input())
count=0
for i in range(1,N)
  count=count+sympy.divisor_count(i)
print (count)

N=int(input())
a=1
count=0
while a<N:
  count=count+(N-1)//a
  a=a+1
else:
  print(count)

Verdicts: Runtime Error

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
N = int(input())
L=[0]*N

for i in range (1,N):
  L[i]=(N-1)//i
  #print(i)

print(L)
ans = sum(L)
print(ans)

N = int(input())
L=[0]*N

for i in range (1,N):
  L[i]=(N-1)//i
  #print(i)

#print(L)
ans = sum(L)
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
n=int(input())
ans=0
for a in range(1,n-1):
	for b in range(1,n-a):
		if n-a*b<=0:
			continue
		else:
			ans=+=1
print(ans)

n=int(input())
ans=0
for a in range(1,n-1):
	for b in range(1,n-a):
		if n-a*b<=0:
			continue
		else:
			ans+=1
print(ans)

def resolve():
    #n=int(input())
    #a,b=map(int,input().split())
    #x=list(map(int,input().split()))
    #a=[list(map(lambda x:int(x)%2,input().split())) for _ in range(h)]
    n=int(input())
    ans=0
    for a in range(1,n):
      if n-a*a<=0:
        break
      else:
        ans+=1
    for a in range(1,n-1):
      for b in range(a+1,n):
        if n-a*b<=0:
          break
        else:
          ans+=2
    print(ans)

if __name__ == '__main__':
    resolve()

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
n=it(input())
ans=0
for i in range(1,n):
  ans+=int((n-1)/i)
print(ans)

n=int(input())
ans=0
for i in range(1,n):
  ans+=int((n-1)/i)
print(ans)

Verdicts: Runtime Error

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
#c
import sys
n = int(input())
import math

ans = 0
for i in range(1,n):
    before = n
    for j in range(1,n):
        if before <= j:
            print(j)
            break
        if (n-i)%j==0 :
            
            
            if j==(n-i)/j:
                ans+=1
            else:
                ans+=2
        before = (n-i)/j
print(ans)

#c
import sys
n = int(input())
import math

ans = 0

for i in range(1,n):
    ans += (n-1)//i
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
import itertools
import math

n = int(input())
s_n = math.floor(math.sqrt(n))

ans = 0
z = 0
l = []


for i in range(1,n):
    l.append(i) 

for x in itertools.combinations(l, 2):
    if x[0] * x[1] < n:
        ans += 2

for y in range(1,s_n):
    if y ** 2 < n :
        ans+=1
    
        
print(ans)

 = int(input())

ans = 0

for i in range(1,n):
    s = (n-1)//i
    if  0< s < n:
        ans += s
print(ans)

n = int(input())

ans = 0

for i in range(1,n):
    s = (n-1)//i
    if  0< s < n:
        ans += s
print(ans)

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
N = int(input())
count = 0
for i in range(1, N):
    AB_product = N - i
    count += count_divisors(AB_product)

print(count)

# A * B  = N - C
N = int(input())
count = 0
for i in range(1, N):
    AB = N - i
    count += len(make_divisors(AB))

print(count)

N = int(input())

N_m1 = N - 1
counter = 0
for i in range(1, N_m1 + 1):
    counter += N_m1 // i

print(counter)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
N=int(input(''))
C=0
F=N-C

a=0
k=0
v=0

while C<N-1:
  C=C+1
  while a<=F:
      a=a+1
      v=v+(F%a)
      if v==0:
          k=k+1
      v=0
      a=0
  F=N-C
print(k)


N=int(input(''))
a=1
k=0
F=int(N**(1/2))

while a<N:
  if N%a>0:
    b=N//a
    k=k+b
    b=0
  else:
    b=N//a
    k=k+b-1
    b=0
  a=a+1

print(k)

Verdicts: Time Limit Exceeded

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
import math
t = 1
for tc in range(t):
    N = 1000005
    div = [0] * N
    for i in range(1,N):
        for j in range(i,N,i):
            div[j] += 1
    n = int(input())
    ans = 0
    for i in range(1,n):
        ans += div[n-c]
    print(ans)
        

    
    


import math
t = 1
for tc in range(t):
    n = int(input())
    ans = 0
    for i in range(1,n+1):
        j = 1
        ans += (n-1) // i
        # while i*j + 1 <= n:
        #     ans += 1
        #     j += 1
    print(ans)


Verdicts: Runtime Error

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
n = int(input())
ans = 0
for a in range(1, n):
  ans += (n - 1) / a
print(ans)

n = int(input())
ans = 0
for a in range(1, n):
  ans += (n - 1) // a
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
N=int(input())
ans=0
for i in range(1,int(N**(1/2))+1):
    a=N//i
    ans+=(a-i)*2+1
print(ans)

N=int(input())
ans=0
for i in range(1,int(N**(1/2))+1):
    a=(N-1)//i
    ans+=(a-i)*2+1
if int(N**(1/2))**2==N:
    ans+=1
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
N=int(input())
ans=0

for i in range(1,10**6):
  for j in range(1,(10**6)//i+1):
    if N > i*j:
      ans += 1

print(ans)

N=int(input())
ans=0

for i in range(1,10**6):
  for j in range(i,10**6//i+1):
    if N > i*j:
      if i==j:
        ans += 1
      else:
        ans += 2

print(ans)

Verdicts: Time Limit Exceeded

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
N = int(input())
for i in range(1,n):
    ans += (n-1) // i
print(ans)

N = int(input())
ans = 0
for i in range(1,n):
    ans += (n-1) // i
print(ans)

def factorization(n):
    arr = []
    temp = n
    for i in range(2, int(-(-n**0.5//1))+1):
        if temp%i==0:
            cnt=0
            while temp%i==0:
                cnt+=1
                temp //= i
            arr.append([i, cnt])

    if temp!=1:
        arr.append([temp, 1])

    if arr==[]:
        arr.append([n, 1])
    t = (arr[0][1]+1)*(arr[1][1]+1)
    print(t) 

    return arr

factorization(int(input())) 

N = int(input())
ans = 0
for i in range(1,N):
    ans += (N - 1) // i
print(ans)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
import math
N = int(input())
result = 0
for i in range(1, N + 1):
    s = math.ceil(N / i)
    for j in range(1, s + 1):
        a = N - i * j
        if a > 0:
            result = result + 1
print(s, result)


N = int(input())
result = 0
for i in range(1, N + 1):
    s = int(N / i) + 1
    for j in range(s + 1, 0, -1):
        if N - i * j > 0:
            result = result + j
            break
print(result)


Verdicts: Wrong Answer

Accepted
Problem: Given is a positive integer N. How many tuples (A,B,C) of positive integers satisfy A \times B + C = N?

Submission attempts (in order):
n = int(input())

ans = 0
for a in range(1,int(n**(1/2))):
  tmp = 0
  if n%a == 0:
    tmp += ((n//a)-1-a)*2
    tmp += 1
  else:
    tmp += (n//a-a)*2
    tmp += 1
  #print(tmp)
  ans += tmp
print(ans)



n = int(input())

ans = 0
for a in range(1,int(n**(1/2)+1)):
  tmp = 0
  if (a**2) == n:
    break
  elif n%a == 0:
    tmp += ((n//a)-1-a)*2
    tmp += 1
  elif (a * (n//a)) < n:
    tmp += (n//a-a)*2
    tmp += 1
  #print(tmp)
  ans += tmp
print(ans)



Verdicts: Wrong Answer

Accepted
Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.  Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.  You are given an integer K that is less than or equal to 10, and K non- intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.    * When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.  To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Submission attempts (in order):
n,k=map(int,input().split())
lr=[list(map(int,input().split())) for _ in range(k)]

mod = 998244353

dp = [0] * (n+1)
sdp = [0] * (n+1)
dp[1] = 1
sdp[1] = 1

for i in range(n+1):
  for j in range(k):
    left = max(0, i-lr[j][1])
    right = max(0, i-lr[j][0]+1)
    
    dp[i] += sdp[right] - sdp[left]
  if i+1 <= n:
    sdp[i+1] = sdp[i]%mod + dp[i]%mod

print(dp%mod)

n,k=map(int,input().split())
lr=[list(map(int,input().split())) for _ in range(k)]

mod = 998244353

dp = [0] * (n+1)
sdp = [0] * (n+1)
dp[1] = 1
sdp[1] = 1

for i in range(n+1):
  for j in range(k):
    left = max(0, i-lr[j][1])
    right = max(0, i-lr[j][0]+1)
    
    dp[i] += sdp[right] - sdp[left]
  if i+1 <= n:
    sdp[i+1] = sdp[i]%mod + dp[i]%mod

print(dp[n]%mod)

Verdicts: Runtime Error

Accepted
Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.  Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.  You are given an integer K that is less than or equal to 10, and K non- intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.    * When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.  To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Submission attempts (in order):
n , k = map(int, input().split())

li = [0]*(n+2)
lis = []
lr=[]
lis2 =[0]*(3*n)
lis2[1]=1

for i in range(k):
    l,r = map(int, input().split())
    lr.append((l,r))

for i in range(1,n+1):
    lis2[i]+=lis2[i-1]
    lis2[i]%=998244353
    for j,k in lr:
        lis2[i+j]+=lis2[i]
        lis2[i+k+1]-=lis2[i]

for i in range(1,n+1):
    lis2[i]+=lis2[i-1]

print(lis2[n]%998244353)


n , k = map(int, input().split())

li = [0]*(n+2)
lis = []
lr=[]
lis2 =[0]*(3*n)
lis2[1]=1
lis2[2]=-1

for i in range(k):
    l,r = map(int, input().split())
    lr.append((l,r))

for i in range(1,n+1):
    lis2[i]+=lis2[i-1]
    lis2[i]%=998244353

    for j,k in lr:
        lis2[i+j]+=lis2[i]
        lis2[i+k+1]-=lis2[i]

print(lis2[n]%998244353)


Verdicts: Wrong Answer

Accepted
Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.  Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.  You are given an integer K that is less than or equal to 10, and K non- intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.    * When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.  To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Submission attempts (in order):
n,k = (int(x) for x in input().split())
lr = []
for _ in range(k):
    l,r = (int(x) for x in input().split())
    lr.append((l,r))
lr.sort()
print(lr)

mod = 998244353

dp= [0]*(n+1)
dp[1] = 1

for i in range(2,n+1):
    cnt = 0
    for l,r in lr:
        if l >= i:
            break
        else:
            cnt += dp[i-l] - dp[max(0,i-r-1)]
    dp[i] = (dp[i-1] + cnt) % mod

print(cnt%mod)

n,k = (int(x) for x in input().split())
lr = []
for _ in range(k):
    l,r = (int(x) for x in input().split())
    lr.append((l,r))
lr.sort()

mod = 998244353

dp= [0]*(n+1)
dp[1] = 1

for i in range(2,n+1):
    cnt = 0
    for l,r in lr:
        if l >= i:
            break
        else:
            cnt += dp[i-l] - dp[max(0,i-r-1)]
    dp[i] = (dp[i-1] + cnt) % mod

print(cnt%mod)

Verdicts: Wrong Answer

Accepted
Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.  Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.  You are given an integer K that is less than or equal to 10, and K non- intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.    * When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.  To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Submission attempts (in order):
#!/usr/bin/python3
# -*- coding: utf-8 -*-
import numpy as np
n, k = map(int, input().split())
s_list = []
a_list = np.zeros((n + 1), dtype=int)
a_list[1] = 1
for i in range(k):
    l, r = map(int, input().split())
    s_list.append([l, r + 1])

for i in range(1, n):
    if a_list[i] > 998244353:
        a_list[i] %= 998244353
    if a_list[i] == 0:
        continue
    for l, r in s_list:
        if i + l > n:
            continue
        if i + r > n + 1:
            a_list[(i+l):(n+1)] += a_list[i]
        else:
            a_list[(i+l):(i+r)] += a_list[i]
print(a_list)
print(a_list[n] % 998244353)



#!/usr/bin/python3
# -*- coding: utf-8 -*-
n, k = map(int, input().split())
s_list = []
a_list = [0] * (n + 1)
b_list = [0] * (n + 1)
a_list[1] = 1
b_list[1] = 1
for i in range(k):
    l, r = map(int, input().split())
    s_list.append([l, r + 1])

for i in range(2, n + 1):
    for l, r in s_list:
        t2 = max(0, i - l)
        t1 = max(0, i - r)
        a_list[i] += b_list[t2] - b_list[t1]
    b_list[i] = (b_list[i - 1] + a_list[i]) % 998244353

print(a_list[n] % 998244353)



Verdicts: Wrong Answer

Accepted
Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.  Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.  You are given an integer K that is less than or equal to 10, and K non- intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.    * When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.  To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Submission attempts (in order):
N,K = [int(i) for i in input().split()]
mod = 998244353
LR = []
S = []
dp = [0]*(N+1)
for i in range(K):
  LR.append([int(i) for i in input().split()])
for i in range(N):
  for lr in LR:
    if lr[0] <= i and i <= lr[1]:
      S.append(i)
S = list(set(S))
#print(S)

for i in range(1,N):
  if i in S:
    dp[i] = 1
  for j in range(len(S)):
    if i-S[j] < 1:
      break
    print(i, S[j], i-S[j])
    dp[i] += 1*dp[i-S[j]]
    dp[i] %= mod

print(dp[-2])

N,K = [int(i) for i in input().split()]
mod = 998244353
LR = []
S = []
dp = [0]*(N+1)
dps = [0]*(N+1)
dps[1] = 1
dp[1] = 1
for i in range(K):
  LR.append([int(i) for i in input().split()])

for i in range(1,N+1):
  for l,r in LR:
    l,r = i - r,i - l
    #print(l,r)
    if r < 1:
      continue
    l = max(1,l)
    dp[i] += dps[r] - dps[l-1]
    dp[i] %= mod
    #print(dp[i])
    
  dps[i] = dps[i-1] + dp[i]
  #print(dp, dps)
print(dp[-1])

Verdicts: Wrong Answer

Accepted
Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.  Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.  You are given an integer K that is less than or equal to 10, and K non- intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.    * When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.  To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Submission attempts (in order):
import numpy as np

N, K = map(int, input().split())

D = []

for _ in range(K):
    L, R = map(int, input().split())

    for i in range(L, R+1):
        D.append(i)

D.sort()

dp = np.zeros(300000)
dp[1] = 1

for d in D:
    for i in range(1, N//d)
        dp += np.roll(dp, i * d)
    dp %= 998244353

print(int(dp[N]))

import numpy as np

N, K = map(int, input().split())

D = []

for _ in range(K):
    L, R = map(int, input().split())

    for i in range(L, R+1):
        D.append(i)

D.sort()

dp = np.zeros(300000)
dp[1] = 1

for d in D:
    for i in range(1, N//d):
        dp += np.roll(dp, i * d)
    dp %= 998244353

print(int(dp[N]))

N, K = map(int, input().split())

L, R = [], []

for _ in range(K):
    l, r = map(int, input().split())
    L.append(l)
    R.append(r)

dp = [0] * 300000
dpsum = [0] * 300000
dp[1] = 1
dpsum[1] = 1

for i in range(2, N+1):
    for j in range(K):
        li = min(L[j], i)
        ri = min(R[j], i + 1)
        dp[i] += dpsum[i - li] - dpsum[i - ri - 1]

    dp[i] %= 998244353
    dpsum[i] = dpsum[i-1] + dp[i]

print(dp[N])

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.  Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.  You are given an integer K that is less than or equal to 10, and K non- intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.    * When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.  To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Submission attempts (in order):
N, K = map(int, input().split())

idou = set()
for i in range(0, K):
    L, R = map(int, input().split())
    idou = idou | set(range(L, R + 1))

idou = list(idou)

moves = [0] * N
moves[0] = 1
for i in range(0, N):
    for j in range(0, len(idou)):
        if i + idou[j] < N:
            moves[i + idou[j]] += moves[i]

print(moves)
print(moves[N - 1] % 998244353)


N, K = map(int, input().split())

L = [0] * K
R = [0] * K
for i in range(0, K):
    L[i], R[i] = map(int, input().split())

moves = [0] * N
moves[0] = 1

rui_wa = [0] * N
rui_wa[0] = 1

for i in range(1, N):
    for j in range(0, K):
        l = max(i - L[j], 0)
        r = max(i - R[j], 0)
        if i - L[j] < 0:
            continue

        moves[i] += (rui_wa[l] - rui_wa[r - 1]) % 998244353

    rui_wa[i] = (moves[i] + rui_wa[i - 1])  % 998244353



print(moves[N - 1] % 998244353)


Verdicts: Wrong Answer

Accepted
Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.  Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.  You are given an integer K that is less than or equal to 10, and K non- intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.    * When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.  To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Submission attempts (in order):
# import numpy as np
# import math
# import copy
# from collections import deque
import sys
input = sys.stdin.readline

# from numba import njit,i8



def give_dp(N,K,mod,LR,dp,l,r):
    for i in range(N):
        if i > 0:
            dp[i] += dp[i-1]
            dp[i] %= mod
        for k in range(K):
            l = LR[k][0]
            r = LR[k][1]
            if i + l < N:
                dp[i+l] += dp[i]
                dp[i+1] %= mod
            if i + r < N:
                dp[i+r+1] -= dp[i]
                dp[i+1] %= mod
    return dp[-1]


def main():
    N,K = map(int,input().split())
    LR = [list(map(int,input().split())) for i in range(K)]
    # LR = np.array(LR)

    mod = 998244353

    dp = [0 for i in range(N)]
    dp[0] = 1
    dp[1] = -1
    # dp = np.array(dp)

    res = give_dp(N,K,mod,LR,dp,0,0)
    res %= mod

    print(res)



main()


# import numpy as np
# import math
# import copy
# from collections import deque
import sys
input = sys.stdin.readline

# from numba import njit,i8
 
 

def give_dp(N,K,mod,LR,dp,l,r):
    for i in range(N):
        if i > 0:
            dp[i] += dp[i-1]
            dp[i] %= mod
        for k in range(K):
            l = LR[k][0]
            r = LR[k][1]
            if i + l < N:
                dp[i+l] += dp[i]
                dp[i+1] %= mod
            if i + r + 1 < N:
                dp[i+r+1] -= dp[i]
                dp[i+1] %= mod
    return dp[-1]
 
 
def main():
    N,K = map(int,input().split())
    LR = [list(map(int,input().split())) for i in range(K)]
    # LR = np.array(LR)
 
    mod = 998244353
 
    dp = [0 for i in range(N)]
    dp[0] = 1
    dp[1] = -1
    # dp = np.array(dp)
 
    res = give_dp(N,K,mod,LR,dp,0,0)
    res %= mod
 
    print(res)
 
 
 
main()

Verdicts: Runtime Error

Accepted
Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.  Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.  You are given an integer K that is less than or equal to 10, and K non- intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.    * When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.  To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Submission attempts (in order):
n,k =map(int,input().split())
s =[]
for i in range(k):
    l,r=map(int,input().split())
    s+=(list(range(l,r+1)))
S= set(s)
print(S)

mod = 998244353

# How many are there to climb
step = [0] * (n+1)


for i in range(1,n+1):
    for s in S:
        if i+s<=n:
            step[i+s]+=1
print(step[n])

mod = 998244353
n,k =map(int,input().split())
step =[0]*(n+1)
# step[0]=1
step[1]=1
stepsum=[0]*(n+1)
stepsum[1]=1
l=[0]*k
r=[0]*k
for i in range(k):
    l[i],r[i]=map(int,input().split())

for i in range(2,n+1):
    for j in range(k):
        li = i - r[j]
        ri = i - l[j]
        if ri <= 0:
            continue
        
        step[i] += stepsum[ri] - stepsum[max(0,li-1)]
        # step[i] %= mod
        # print(step)
    stepsum[i] = ( stepsum[i-1] + step[i] )%mod


print(step[n]%mod)

Verdicts: Wrong Answer

Accepted
Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.  Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.  You are given an integer K that is less than or equal to 10, and K non- intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.    * When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.  To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Submission attempts (in order):
N,X,M = map(int,input().split())

ans = X
A = X
TF = True
srt = 1000000
retu = dict()
retu[X] = 1
loop = X
for i in range(N-1):
    if TF:
        A = A**2 % M
        if retu.get(A) != None:
          srt = j
          goal = i
          TF = False
          break   
        if TF:
          retu[A] = 1
          loop += A
    else:
      break
      
if N-1 > srt:
    n = (N-srt)//(goal-srt+1)
    saisyo = sum(retu[:srt])
    loop -= saisyo
    print(saisyo + loop*n + sum(retu[srt:N-n*(goal-srt+1)]))
    
else:
    print(sum(retu[:N]))


MOD = 998244353
N, K = map(int, input().split())
LR = [list(map(int, input().split())) for _ in range(K)]

dp = [0]*(N+1)
acc = [0]*(N+1) # acc[i] = dp[1] + ... dp[i]

dp[1] = 1
acc[1] = 1
for i in range(2, N+1):
    for lr in LR:
        l = lr[0]
        r = lr[1]

        dp[i] += (acc[max(0, i - l)] - acc[max(0, i - r - 1)] + MOD)
        dp[i] %= MOD
    acc[i] = (acc[i-1] + dp[i]) % MOD
    
    

print(dp[N])
# print(acc)
# print(dp[N])

Verdicts: Runtime Error

Accepted
Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.  Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.  You are given an integer K that is less than or equal to 10, and K non- intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.    * When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.  To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Submission attempts (in order):
n, k = map(int, input().split())
ls = []
rs = []
ps = []
MOD = 998244353
s = set()
for _ in range(k):
    l,r = map(int, input().split())
    for i in range(l,r+1):
        s.add(i)
dp = [0] * (n+1)
dp[0] = 1
imos = [0]
for i in range(n):
    for d in sorted(list(s), reverse=True):
        if i - d >= 0:
            dp[i] += dp[i-d]
            dp[i-1] -= dp[i]
            dp[i] %= MOD

print(dp[n-1])

n, k = map(int, input().split())
ps = []
MOD = 998244353
s = set()
for _ in range(k):
    l,r = map(int, input().split())
    ps.append([l,r])

dp = [0] * (n+1)
dp[0] = 1
acc = [0,1]

for i in range(1,n):
    for l, r in ps:
        dp[i] += acc[max(0,i-l+1)] - acc[max(0,i-r)]
    acc.append((acc[i] + dp[i])%MOD)
print(dp[n-1]%MOD)


Verdicts: Wrong Answer

Accepted
Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.  Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.  You are given an integer K that is less than or equal to 10, and K non- intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.    * When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.  To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Submission attempts (in order):
N, K = map(int, input().split())
S = []
for j in range(K):
    S.append(list(map(int, input().split())))

m =  998244353

print(S)

dp = [0] * N
dp[0] = 1
sum_of_region = [0] * K
for i in range(1, N):
    for j in range(K):
        if i - S[j][0] >= 0:
            sum_of_region[j] += dp[i - S[j][0]]
        if i - S[j][1] - 1 >= 0:
            sum_of_region[j] -= dp[i - S[j][1] - 1]
        dp[i] += sum_of_region[j] % m
        dp[i] %= m
    print(i, dp, sum_of_region)

ans = dp[N - 1]
print(ans)


N, K = map(int, input().split())
S = []
for j in range(K):
    S.append(list(map(int, input().split())))

m =  998244353

# print(S)

dp = [0] * N
dp[0] = 1
sum_of_region = [0] * K
for i in range(1, N):
    for j in range(K):
        if i - S[j][0] >= 0:
            sum_of_region[j] += dp[i - S[j][0]]
        if i - S[j][1] - 1 >= 0:
            sum_of_region[j] -= dp[i - S[j][1] - 1]
        dp[i] += sum_of_region[j] % m
        dp[i] %= m
    # print(i, dp, sum_of_region)

ans = dp[N - 1]
print(ans)


Verdicts: Wrong Answer

Accepted
Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.  Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.  You are given an integer K that is less than or equal to 10, and K non- intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.    * When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.  To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Submission attempts (in order):
N, K = map(int, input().split())

DP = [0]*(N+1)
DP[1] = 1

S = []
for i in range(K):
    S.append(list(map(int, input().split())))

S.sort()

for i in range(2, N+1):
    for l, r in S:
            DP[i] = (DP[max(i-l, 0)] - DP[max(i-r-1, 0)])%998244353
    DP[i] += DP[i-1]

print(DP[N]%998244353)

N, K = map(int, input().split())

DP = [0]*(N+1)
DP[1] = 1

S = []
for i in range(K):
    S.append(list(map(int, input().split())))

for i in range(2, N+1):
    for l, r in S:
            DP[i] += (DP[max(i-l, 0)] - DP[max(i-r-1, 0)])
    DP[i] += DP[i-1]
    DP[i] %= 998244353

print(DP[N]%998244353)

N, K = map(int, input().split())

DP = [0]*(N+1)
DP[1] = 1

S = []
for i in range(K):
    S.append(list(map(int, input().split())))

for i in range(2, N+1):
    for l, r in S:
            DP[i] += (DP[max(i-l, 0)] - DP[max(i-r-1, 0)])%998244353
    DP[i] += DP[i-1]

print(DP[N]%998244353)

N, K = map(int, input().split())

DP = [0]*(N+1)
DP[1] = 1

S = []
for i in range(K):
    S.append(list(map(int, input().split())))

for i in range(2, N+1):
    for l, r in S:
            DP[i] += (DP[max(i-r, 0)] - DP[max(i-l-1, 0)])%998244353
    DP[i] += DP[i-1]

print(DP[N]%998244353)

N, K = map(int, input().split())

DP = [0]*(N+1)
DP[1] = 1

S = []
for i in range(K):
    S.append(list(map(int, input().split())))

S.sort()

for i in range(2, N+1):
    for l, r in S:
        if 0 <= i - r <= N and 0 <= i - l - 1 <= N:
            DP[i] = (DP[i-r] - DP[i-l-1])%998244353
    DP[i] += DP[i-1]

print(DP[N]%998244353)

N, K = map(int, input().split())

DP = [0]*(N+1)
DP[1] = 1

S = []
for i in range(K):
    S.append(list(map(int, input().split())))

for i in range(2, N+1):
    for l, r in S:
            DP[i] += (DP[max(i-l, 0)] - DP[max(i-r-1, 0)])
    DP[i] += DP[i-1]
    DP[i] %= 998244353

print((DP[N] - DP[N-1])%998244353)

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.  Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.  You are given an integer K that is less than or equal to 10, and K non- intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.    * When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.  To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Submission attempts (in order):
import numpy as np

mod = 998244353
n, k = map(int, input().split())
left = []
right = []
for _ in range(k):
  l, r = map(int, input().split())
  left.append(l)
  right.append(r)
dp = np.zeros(n+1, dtype=np.int)
dp[1] = 1
for i in range(2, n+1):
  for j in range(k):
    dp[i] += dp[max(0, i - left[j])] - dp[max(0, i - right[j] - 1)]
    dp[i] %= mod
  dp[i] = (dp[i-1] + dp[i]) % mod
print((dp[n] - dp[n-1]) % mod)

import numpy as np

mod = 998244353
n, k = map(int, input().split())
left = []
right = []
for _ in range(k):
  l, r = map(int, input().split())
  left.append(l)
  right.append(r)
dp = np.zeros(n, dtype=np.int)
dp[0] = 1
for i in range(n-1):
  for j in range(k):
    dp[i + left[j] : i + right[j] + 1] += dp[i]
    dp[i + left[j] : i + right[j] + 1] %= mod
print(dp[-1])

mod = 998244353
n, k = map(int, input().split())
left = []
right = []
for _ in range(k):
  l, r = map(int, input().split())
  left.append(l)
  right.append(r)
dp = [0] * (n + 1)
dp[1] = 1
for i in range(2, n+1):
  for j in range(k):
    dp[i] += dp[max(0, i - left[j])] - dp[max(0, i - right[j] - 1)]
    dp[i] %= mod
  dp[i] = (dp[i-1] + dp[i]) % mod
print((dp[n] - dp[n-1]) % mod)

Verdicts: Time Limit Exceeded

Time Limit Exceeded

Accepted
Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.  Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.  You are given an integer K that is less than or equal to 10, and K non- intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.    * When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.  To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Submission attempts (in order):
root=[]
n,k = map(int,input().split())
for i in range(k):
    x,y = map(int,input().split())
    root.append([x,y])

toori=[0]*(2*10**5)+[0]*n+[0]*(2*10**5)
toori[2*10**5]=1
cum=[0]*k
for a,i in enumerate (root):
    s=0
    for j in range (i[0],i[1]+1):
        s+=toori[2*10**5+1-j]
    cum[a]=s
aaa=sum(cum)
toori[2*10**5+1]+=aaa

root=[]
n,k = map(int,input().split())
for i in range(k):
    x,y = map(int,input().split())
    root.append([x,y])

toori=[0]*(2*10**5)+[0]*n+[0]*(2*10**5)
toori[2*10**5]=1
cum=[0]*k
for a,i in enumerate (root):
    s=0
    for j in range (i[0],i[1]+1):
        s+=toori[2*10**5+1-j]
    cum[a]=s
aaa=sum(cum)%998244353
toori[2*10**5+1]+=aaa


for now in range(2,n):
    hueru=0
    for a,i in enumerate (root):
        hueru+=(toori[2*10**5+now-i[0]] - toori[2*10**5+now-1-i[1]])
    aaa+=hueru
    aaa%=998244353
    toori[2*10**5+now]+=aaa
    toori[2*10**5+now]%=998244353
    


print(toori[2*10**5+n-1]%998244353)

Verdicts: Wrong Answer

Accepted
Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.  Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.  You are given an integer K that is less than or equal to 10, and K non- intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.    * When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.  To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Submission attempts (in order):
def resolve():
    n, k = map(int, input().split())
    S = []
    for _ in range(k):
        l1, r1 = map(int, input().split())
        S.append(l1)
        S.append(r1)
    S = list(set(S))

    dp = [[0 for i in range(n + 1)] for j in range(len(S) + 1)]
    for i in range(len(S) + 1):
        dp[i][1] = 1
    for i in range(1, len(S) + 1):
        for j in range(2, n + 1):
            if j - S[i - 1] >= 0 and dp[i][j - S[i - 1]] > 0:
                dp[i][j] = dp[i][j - S[i - 1]] + dp[i - 1][j]
            else:
                dp[i][j] = dp[i - 1][j]

    print(dp[-1][n])

resolve()

def resolve():
    n, k = map(int, input().split())
    S = []
    for _ in range(k):
        l1, r1 = map(int, input().split())
        S.append(l1)
        S.append(r1)
    S = list(set(S))

    dp = [[0 for i in range(n + 1)] for j in range(len(S) + 1)]
    for i in range(len(S) + 1):
        dp[i][1] = 1
    for i in range(1, len(S) + 1):
        for j in range(2, n + 1):
            if j - S[i - 1] >= 0 and dp[i][j - S[i - 1]] > 0:
                dp[i][j] = dp[i][j - S[i - 1]] + dp[i - 1][j]
            else:
                dp[i][j] = dp[i - 1][j]

    print(dp[-1][n] % 998244353)

resolve()


def resolve():
    n, k = map(int, input().split())
    S = []
    L, R = [], []
    for _ in range(k):
        l1, r1 = map(int, input().split())
        L.append(l1)
        R.append(r1)

    dp = [0 for i in range(n + 1)]
    dpsum = [0 for i in range(n + 1)]
    dp[1] = 1
    dpsum[1] = 1
    for i in range(2, n + 1):
        for j in range(k):
            Li = i - R[j]
            Ri = i - L[j]
            if Ri < 0:
                continue
            Li = max(1, Li)
            dp[i] += dpsum[Ri] - dpsum[Li - 1]  # dp[Li] ~ dp[Ri]
            dp[i] %=  998244353

        dpsum[i] = (dpsum[i - 1] + dp[i]) % 998244353

    print(dp[n])

resolve()

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.  Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.  You are given an integer K that is less than or equal to 10, and K non- intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.    * When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.  To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Submission attempts (in order):
N,K = map(int,input().split())
LR = [list(map(int,input().split())) for k in range(K)]

dp = (3*N)*[0]
dp[0] = 1
dp[1] = -1

for n in range(N):
  for L,R in LR:
    dp[L+n]+=dp[n]
    dp[n+R+1]-=dp[n]
    dp[n+1] = (dp[n]+dp[n+1])%998244353

print(dp[N-1])

from numpy import *
N,K = map(int,input().split())
LR = [list(map(int,input().split())) for k in range(K)]
D = (N+2)*[0]
dp = (N+1)*[0]
dp[1] = 1
mod = 998244353

for L,R in LR:
  D[L]+=1
  D[R+1]-=1

D = cumsum(D)

for i in range(1,N+1):
  for j in range(1,i):
    if D[j]==1:
      dp[i] = (dp[i]+dp[i-j])%mod

print(dp)

N,K = map(int,input().split())
LR = [list(map(int,input().split())) for k in range(K)]

dp = (3*N)*[0]
dp[0] = 1
dp[1] = -1

for n in range(N):
  for L,R in LR:
    dp[L+n]+=dp[n]
    dp[n+R+1]-=dp[n]
  dp[n+1] = (dp[n]+dp[n+1])%998244353

print(dp[N-1])

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.  Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.  You are given an integer K that is less than or equal to 10, and K non- intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.    * When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.  To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Submission attempts (in order):
N, K = map(int, input().split())
S = []

for _ in range(K):
  L, R = map(int, input().split())
  S.extend(range(L,R+1))
  
print(S)


DP =[0]*N
DP[0] = 1

for i in range(1,N):
  for j in S:
    if i >= j:
      DP[i] += DP[i-j]
      
print(DP[-1]%998244353)

N, K = map(int, input().split())

L = []
R = []

for _ in range(K):
  l, r = map(int, input().split())
  L.append(l)
  R.append(r)
  
dp = [0]*(N+5)
dp[1] = 1

for i in range(2, N+1):
  dp[i] = dp[i-1]
  for j in range(K):
    if i-L[j] >= 0:
      dp[i] += dp[i-L[j]]
    if i-R[j]-1 >= 0:
      dp[i] -= dp[i-R[j]-1]
    dp[i] %= 998244353
    
print((dp[N]-dp[N-1])%998244353)

Verdicts: Wrong Answer

Accepted