TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
A,B,C,D = map(int,input().split())
for num in range(0,):
    aoki = C - B
    taka = A - D
    if (aoki or taka) <= 0 : break
    else : pass

#print(aoki,taka)
if aoki <= 0 : print("Yes")
elif taka <= 0 : print("No")

import math
A,B,C,D = map(int,input().split())
if (math.ceil(A/D)) >= (math.ceil(C/B)) : print("Yes") 
else : print("No")

Verdicts: Runtime Error

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
N = int(input())

goods = {}
for i in range(N):
  name = input().rstrip()
  if name in goods.keys():
    goods[name] += 1
  else:
    goods[name] = 1
print(len(goods.keys()))

a, b, c, d = map(int, input().split())
while(a > 0 and c > 0):
  c -= b
  if c <= 0:
    break
  a -= d
  if a <= 0:
    break
if a > c:
  print('Yes')
else:
  print('No')

Verdicts: Runtime Error

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
import math
a, b, c, d = map(int, input().split())
if math.ceil(c / b) =< math.ceil(a / d):
  print("Yes")
else:
  print("No")


a, b, c, d = map(int, input().split())
while 1:
    c -= b
    if(c <= 0):
        print("Yes")
        break
    a -= d:
    if(a <= 0):
        print("No")
        break


a, b, c, d = map(int, input().split())
while 1:
    c -= b
    if(a <= 0):
        print("Yes")
        break
    a -= d:
    if(d <= 0):
        print("No")
        break

import math
a, b, c, d = map(int, input().split())
if math(c / b) < math(a / d):
  print("Yes")
else:
  print("No")

import math
a, b, c, d = map(int, input().split())
if math.ceil(c / b) <= math.ceil(a / d):
  print("Yes")
else:
  print("No")


Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
a,b,c,d = map(int,input().split())
if c%b==0 and a%d!=0:
	print('yes')
else:
	print('no')

a,b,c,d = map(int,input().split())
chance = 0
while a>0 and c>0:
	if chance==0:
		c-=b
		chance=1
	else:
		a-=d
		chance=0
if a<=0 and c>0:
	print('No')
else:
	print('Yes')

Verdicts: Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
a, b, c, d = map(int, input().split())

print('Yes' if c//b>=a//d else 'No')

a,b,c,d = map(int, input().split())
print('Yes' if (-(-c // b)) <= (-(-a // d)) else 'No')


Verdicts: Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
import sys

A,B,C,D = map(int,input().split())


while True:
  C = C - B
  if C <= 0:
    print('Yes')
    sys.exit()
  
  A = A - D
  if A <= 0:
    print('no')
    sys.exit()

import sys

A,B,C,D = map(int,input().split())

aoki = C
takahasi = A
while True:
  aoki = aoki - B
  if aoki <= 0:
    print('Yes')
    sys.exit()
  
  takahasi = takahasi - D
  if takahasi <= 0:
    print('no')
    sys.exit()

import sys

A,B,C,D = map(int,input().split())


while True:
  C = C - B
  if C <= 0:
    print('Yes')
    sys.exit()
  
  A = A - D
  if A <= 0:
    print('No')
    sys.exit()

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
import sys
input = sys.stdin.readline
ma = lambda : map(int,input().split())
ni = lambda : int(input())
a,b,c,d = ma()
import math
ceil =math.ceil
if ceil(c/b) <=ceil(a/d)+1:print("Yes")
else:print("No")


import sys
input = sys.stdin.readline
ma = lambda : map(int,input().split())
ni = lambda : int(input())
a,b,c,d = ma()
import math
ceil =math.ceil
if ceil(c/b) <=ceil(a/d):print("Yes")
else:print("No")


Verdicts: Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
a, b, c, d = map(int,input().split())
e = a / d 
f = c / b
g = e - f
h = abs(g)
if h < 1:
    print("Yes")
elif e >= f:
    print("Yes")
else:
    print("No")

import math

a, b, c, d = map(int,input().split())
e = math.ceil(a / d)
f = math.ceil(c / b)

if e >= f:
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
h1,s1,h2,s2=map(int,input().split())
while True:
    h2 -= s1
    if h2 <= s1:
        print('Yes')
        break
    h1-=s2
    if h1<=0:
        print('No')
        break

h1,s1,h2,s2=map(int,input().split())
while True:
    h2 -= s1
    if h2 <= 0:
        print('Yes')
        break
    h1-=s2
    if h1<=0:
        print('No')
        break


Verdicts: Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
th,ts,ah,as = map(int,input().split())
while Ture:
  ah -= ts
  if ah <= 0:
    print('Yes')
    break
  else:
    th -= as
    if th <= 0:
      print('No')
      break

TH,TS,AH,AS = map(int,input().split())
while Ture:
  AH -= TS
  if AH <= 0:
    print('Yes')
    break
  else:
    TH -= AS
    if TH <= 0:
      print('No')
      break

TH,TS,AH,AS = map(int,input().split())
while True:
  AH -= TS
  if AH <= 0:
    print('Yes')
    break
  else:
    TH -= AS
    if TH <= 0:
      print('No')
      break

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
a,b,c,d = map(int, input().split())


print(5//6)
#print(a//d)
if c//b<a//d:
    print('No')
elif c//b==a//d==0:
    print('No')
elif c//b==a//d and a%d==0:
    print('No')
else:
    print('Yes')


a,b,c,d = map(int, input().split())



if c//b<a//d:
    print('No')
else:
    print('Yes')

a,b,c,d = map(int, input().split())



#print(a//d)
for _ in range(200):
    c-=b
    if c<=0:
        print("Yes")
        break
    else: pass
    a-=d
    if a<=0:
        print("No")
        break
    else: pass

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
def resolve():
    a,b,c,d = map(int,input().split())
    A = math.ceil(c/b)
    B = math.ceil(a/d)
    print('Yes' if A <= B else 'No')
    
resolve()

import math
def resolve():
    a,b,c,d = map(int,input().split())
    A = math.ceil(c/b)
    B = math.ceil(a/d)
    print('Yes' if A <= B else 'No')
resolve()

Verdicts: Runtime Error

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
a,b,c,d = input().split(' ')
a = int(a)
b = int(b)
c = int(c)
d = int(d)

r1 = a // d
r2 = c // b
if r1 >= r2:
  print('Yes')
else:
  print('No')

a,b,c,d = input().split(' ')

a = int(a)
b = int(b)
c = int(c)
d = int(d)
 
r1 = c // b
r2 = a // d 

for i in range(1000):
  c -= b
  if c <= 0 :
    print('Yes')
    break
  a -= d
  if a <= 0:
    print('No')
    break
  

Verdicts: Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
a, b, c, d = map(int, input().split())


while a>0:

    c = c - b
    if c < 0:
        print("Yes")
        break

    
    a = a- d
    if a <0:
        print("NO")
        break

a, b, c, d = map(int, input().split())


while a>0:

    c = c - b
    if c <= 0:
        print("Yes")
        break

    
    a = a- d
    if a <=0:
        print("NO")
        break

a, b, c, d = map(int, input().split())


while a>0:

    c = c - b
    if c <= 0:
        print("Yes")
        break

    
    a = a- d
    if a <= 0:
        print("No")
        break

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
a,b,c,d=map(int,input().split())
x=0
while(True):
    if x%2==0:
        if c-b>0:
            c=c-b 
        elif(c-b<=0):
            print("yes")
            break
        x+=1
    else:
        if a-d>0:
            a=a-d
        else:
            print("no")
            break 
        x+=1
        
    
        

a,b,c,d=map(int,input().split())

if a+b>=c+d:
    print("yes")
else:
    print("no")

a,b,c,d=map(int,input().split())
x=0
while(True):
    if x%2==0:
        if c-b>0:
            c=c-b 
        elif(c-b<=0):
            print("Yes")
            break
        x+=1
    else:
        if a-d>0:
            a=a-d
        else:
            print("No")
            break 
        x+=1
        
    
        

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
A,B,C,D=map(int,input().split())
while A==0 or C==0:
     a-d
     c-b
if A>=C:
	print('Yes')
else:
	print('No')

a,b,c,d = map(int,input().split())
while True:
	c=c-b
	if c<=0:
		print('Yes')
		break
	a=a-d
	if a<=0:
		print('No')
		print(a)
		break

A,B,C,D=map(int,input().split())
while A==0 or C==0:
     a-d
     c-b
     a-d
     c-b
if A>=C:
	print('Yes')
else:
	print('No')

a,b,c,d = map(int,input().split())
e=(a+d-1)//d
f=(c+b-1)//b
if e>=f:
	print('Yes')
else:
	print('No')

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
import sys
input = sys.stdin.readline

# B - Battle
def win_takahashi(A, B, C, D):

	for i in range(300):
		if i % 2 == 0:
			C -= B
			
			if C <= 0:
				return True
		else:
			D -= A
			
			if A <= 0:
				return False
			

A, B, C, D = map(int, input().split())

if win_takahashi(A, B, C, D):
	print('Yes')
else:
	print('No')

import sys
input = sys.stdin.readline

# B - Battle
a, b, c, d = map(int, input().split())

while True:
	c -= b
	if c <= 0:
		print('Yes')
		sys.exit()
	
	a -= d
	if a <= 0:
		print('No')
		sys.exit()

Verdicts: Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
from math import ceil
A, B, C, D = map(int, input().split())

print(ceil(C/B) -1 ,ceil(A/D))
if (ceil(C/B) <= ceil(A/D)):
  print("Yes")

else:
  print("No")

from math import ceil
A, B, C, D = map(int, input().split())

if (ceil(C/B) -1 <= ceil(A/D)):
  print("Yes")

else:
  print("No")

from math import ceil
A, B, C, D = map(int, input().split())
t_s = ceil(C/B)
a_s = ceil(A/D)

if ( t_s - a_s < 1 ):
  print("Yes")

else:
  print("No")

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
A,B,C,D=map(int,input().split())
a1=C-B
if a1 <=0 :
    print("Yes")
a2=A-D
if a2 <=0 :
    print("No")
a3=a1-B
if a3 <=0 :
    print("Yes")
a4=a2-D
if a4 <=0 :
    print("No")
a5=a3-B
if a5 <=0 :
    print("Yes")
a6=a4-D
if a6 <=0 :
    print("No")
a7=a5-B
if a7 <=0 :
    print("Yes")
a8=a6-D
if a8 <=0 :
    print("No")
a9=a7-B
if a9 <=0 :
    print("Yes")
a10=a8-D
if a10 <=0 :
    print("No")
a11=a9-B
if a11 <=0 :
    print("Yes")
a12=a10-D
if a12 <=0 :
    print("No")
a13=a11-B
if a13 <=0 :
    print("Yes")
a14=a12-D
if a14 <=0 :
    print("No")
a15=a13-B
if a15 <=0 :
    print("Yes")
a16=a14-D
if a16 <=0 :
    print("No")
a17=a15-B
if a17 <=0 :
    print("Yes")
a18=a16-D
if a16 <=0 :
    print("No")
a19=a17-B
if a19 <=0 :
    print("Yes")
a20=a18-D
if a20 <=0 :
    print("No")
a21=a19-B
if a21 <=0 :
    print("Yes")
a22=a20-D
if a22 <=0 :
    print("No")
a23=a21-B
if a23 <=0 :
    print("Yes")
a24=a22-D
if a24 <=0 :
    print("No")
a25=a23-B
if a25 <=0 :
    print("Yes")
a26=a24-D
if a26 <=0 :
    print("No")

A,B,C,D=map(int,input().split())
while all:
    C=C-B
    if C <=0:
        print("Yes")
        break
    A=A-D
    if A <=0:
        print("No")
        break

Verdicts: Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
a,b,c,d = list(map(int,input().split()))

t_win_turn = a // d
if a % d > 0:
  t_win_turn += 1

a_win_turn = c // b
if c % b > 0:
  a_win_turn += 1

if t_win_turn <= a_win_turn:
  print('Yes')
else:
  print('No')

a,b,c,d = list(map(int,input().split()))

t_win_turn = c // b
if c % b > 0:
  t_win_turn += 1

a_win_turn = a // d
if a % d > 0:
  a_win_turn += 1

if t_win_turn <= a_win_turn:
  print('Yes')
else:
  print('No')


Verdicts: Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
a,b,c,d = map(int, input().split())
i = 0
while True:
    if i % 2 == 0:
        c -= b
    else:
        a -= d
    i += 1
    if a <= 0:
        print("Yes")
        break
    elif c <= 0:
        print("No")
        break


a,b,c,d = map(int, input().split())
i = 0
while True:
    if i % 2 == 0:
        c -= b
    else:
        a -= d
    i += 1
    if a <= 0:
        print("No")
        break
    elif c <= 0:
        print("Yes")
        break


Verdicts: Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
A, B, C, D= map(int, input().split())
a_score=A/D
t_score=C/B
if a_score<t_score:
    print("Yes")
else:
    print("No")

A, B, C, D= map(int, input().split())
i=0
while True:
    count=i%2
    if count==0:
        C=C-B
        if C<=0:
            print("Yes")
            break
    elif count==1:
        A=A-D
        if A<=0:
            print("No")
            break
    i+=1

Verdicts: Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
A, B, C, D = map(int, input().split())

cnt = 0
while A <= 0 or C <= 0:
    if cnt % 2 == 0:
        C -= B
    else:
        A -= D
    cnt += 1

if A <= 0:
    print('No')
else:
    print('Yes')


A, B, C, D = map(int, input().split())

cnt = 0
while A < 0 or C < 0:
    if cnt % 2 == 0:
        C -= B
    else:
        A -= D
    cnt += 1

if A < 0:
    print('No')
else:
    print('Yes')


A, B, C, D = map(int, input().split())

cnt = 0
while ((A > 0) and (C > 0)):
    if cnt % 2 == 0:
        C -= B
    else:
        A -= D
    cnt += 1

if A <= 0:
    print('No')
else:
    print('Yes')


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
a,b,c,d = map(int,input().split())
if a//d < c//b or a/d == c/d:
    print("Yes")
else:
    print("No")

a,b,c,d = map(int,input().split())
if a//d <= c//b:
    print("Yes")
else:
    print("No")

a,b,c,d = map(int,input().split())
if -(-a // d) >= -(-c // b):
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
S_list = list(map(int,input().split()))
A,B,C,D = S_list
takahashi ,aoki = A, C
while takahashi > 0 or aoki > 0:
    aoki = aoki - B
    if aoki <=0:
        break
    takahashi = takahashi - D
    
if takahashi > aoki:
    result = "Yes"
else:
    result = "No"
print(result)

S_list = list(map(int,input().split()))
A,B,C,D = S_list
takahashi ,aoki = A, C
while takahashi > 0 or aoki > 0:
    aoki = aoki - B
    if aoki <=0 :
        break
    takahashi = takahashi - D
    if takahashi <=0:
        break
        
if takahashi > aoki:
    result = "Yes"
else:
    result = "No"
print(result)

Verdicts: Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
A,B,C,D=map(int,input().split())
if C//B<=A//D:
  print('Yes')
else:
  print('No')

A,B,C,D=map(int,input().split())
if C//B<=A//D and A/D!=A//D:
  print('Yes')
elif C//B==A//D and  A/D==A//D and C//B==C/B:
  print('Yes')
elif C//B-1==A//D and C//B==C/B and A//D!=A/D:
  print('Yes')
else:
  print('No')


Verdicts: Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
A, B, C, D = map(int, input().split())
count = 0
while True:
    if count % 2 == 0:
        C -= B
    else:
        A -= D
    count += 1
    if A <= 0:
        print("No")
        break
    else:
        print("Yes")
        break


A, B, C, D = map(int, input().split())
count = 0
while A <=0 or C<=0:
    if count % 2 == 0:
        C -= B
    else:
        A -= D
    count += 1
if A <= 0:
    print("No")
else:
    print("Yes")

A, B, C, D = map(int, input().split())
count = 0
while A <= 0 or C<= 0:
    if count % 2 == 0:
        C -= B
        if C <= 0:
            print("Yes")
    else:
        A -= D
        if A <= 0:
            print("No")
    count += 1


# A, B, C, D = map(int, input().split())
A, B, C, D = 46, 4, 40, 5
count = 0
while True:
    if count % 2 == 0:
        C -= B
        if C <= 0:
            print("Yes")
            break
    else:
        A -= D
        if A <= 0:
            print("No")
            break
    count += 1

A, B, C, D = map(int, input().split())
count = 0
while True:
    if count % 2 == 0:
        C -= B
        if C <= 0:
            print("Yes")
            break
    else:
        A -= D
        if A <= 0:
            print("No")
            break
    count += 1


Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
import math
a,b,c,d= map(int,input().split())
n=math.ceil(float(a)/d)
m=math.ceil(float(b)/c)
if n>=m:
  print("Yes")
else:
  print("No")

import math
a,b,c,d= map(int,input().split())
n=math.ceil(float(a)/d)
m=math.ceil(float(b)/c)
if n>=m:
  print("Yes")
else:
  print("No")

import math
a,b,c,d= map(int,input().split())
n=math.ceil(a/d)
m=math.ceil(b/c)
if n>=m:
  print("Yes")
else:
  print("No")

import math
a,b,c,d= map(int,input().split())
n=math.ceil(float(a+1)/d)
m=math.ceil(float(b+1)/c)
if n>=m:
  print("Yes")
else:
  print("No")

import math
a,b,c,d= map(int,input().split())
n=math.ceil(a/d)
m=math.ceil(b/c)
if m<=n:
  print("Yes")
else:
  print("No")

import math
a,b,c,d= map(int,input().split())
n=math.ceil(float(a)/d)
m=math.ceil(float(c)/b)
if m<=n:
  print("Yes")
else:
  print("No")

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
import math

A, B, C, D = map(int, input().split())

num_A = math.floor(C/B)
num_B = math.floor(A/D)

if num_A >= num_B:
    print('Yes')
else:
    print('No')

import math

A, B, C, D = map(int, input().split())

num_A = math.ceil(C/B)
num_B = math.ceil(A/D)

if num_A <= num_B:
    print('Yes')
else:
    print('No')

Verdicts: Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
import sys

A, B, C, D = list(map(int, input().split()))

while True:
    C -= B
    if C <= 0:
        print("Yes")
        sys.exit()
    A -= D
    if D <= 0:
        print("No")
        sys.exit()

import sys

A, B, C, D = list(map(int, input().split()))

while True:
    C -= B
    if C <= 0:
        print("Yes")
        sys.exit()
    A -= D
    if A <= 0:
        print("No")
        sys.exit()

Verdicts: Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
a, b, c, d = map(int, input().split())

while c or a >= 0:
    c -= b
    a -= b
    if c <= 0:
        print('Yes')
        break
    if a <= 0:
        print('No')

a, b, c, d = map(int, input().split())

while c or a >= 0:
    c -= b
    a -= b
    if c <= 0:
        print("Yes")
        break
    if a <= 0:
        print("No")

a, b, c, d = map(int, input().split())

while c or a >= 0:
    c -= b
    a -= d
    if c <= 0:
        print("Yes")
        break
    if a <= 0:
        print("No")
        break

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
a,b,c,d=,map(int,input(),split())
hpa=a
hpc=c
while (hpa!=0) and (hpc!=0):
  hpa=hpa-c
  hpc=hpc-a

if hpa=0:
  print("No")

if hpc=0:
  print("Yes")
  
  

a,b,c,d=map(int,input().split())
while True:
  c-=b
  if c<=0:
    print("Yes")
    break
  
  a-=d
  if a<=0:
    print("No")
    break
    
    


Verdicts: Runtime Error

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
A, B, C, D = map(int, input().split())
counter = 1
while A > 0 and C > 0:
    if counter % 2 == 1:
        
        C -= B
    elif counter % 2 == 0:
        A -= D
if A <= 0:
    print('No')
else:
    print('Yes')

A, B, C, D = map(int, input().split())
counter = 1
while A > 0 and C > 0:
    if counter % 2 == 1:
        
        C -= B
    elif counter % 2 == 0:
        A -= D
    counter += 1
if A <= 0:
    print('No')
else:
    print('Yes')

Verdicts: Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
a, b, c, d = map(int, input().split())
if c % b == 0:
    x = c // b
else:
    x = c // b + 1
if d % a == 0:
    y = d // a
else:
    y = d // a + 1
if x >= y:
    print("Yes")
else:
    print("No")
# print(x, y)


a, b, c, d = map(int, input().split())
if c % b == 0:
    x = c // b
else:
    x = c // b + 1
if a % d == 0:
    y = a // d
else:
    y = a // d + 1
if x <= y:
    print("Yes")
else:
    print("No")
# print(x, y)


Verdicts: Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
A,B,C,D = map( int, input().split() )
while A > 0 and c > 0:
    C -= B
    if C <= 0:
        print( 'Yes' )
        exit()
    A -= D 
    if A <= 0:
        print( 'No' )
        exit()


A,B,C,D = map( int,input().split() )
while A > 0 and c > 0:
    C -= B
    if C <= 0 :
        print( 'Yes' )
        exit()
    A -= D 
    if A <= 0 :
        print( 'No' )
        exit()


A,B,C,D = map( int,input().split() )
while A > 0 and c > 0:
    C -= B
    if C <= 0 :
        print( "Yes" )
        exit()
    A -= D 
    if A <= 0 :
        print( "No" )
        exit()


A,B,C,D = map( int,input().split() )
while A > 0 and c > 0:
    C -= B
    if C <= 0:
        print( "Yes" )
        exit()
    A -= D 
    if A <= 0:
        print( "No" )
        exit()


A,B,C,D = map( int,input().split() )

while A > 0 and c > 0:
    C -= B
    if C <= 0 :
        print( "Yes" )
        exit()
    A -= D 
    if A <= 0 :
        print( "No" )
        exit()


A,B,C,D = map( int,input().split() )
while A > 0 and c > 0:
    C -= B
    if C <= 0 :
        print( 'Yes' )
        exit()

    A -= D 
    if A <= 0 :
        print( 'No' )
        exit()

A,B,C,D = map( int,input().split() )
while A > 0 and c > 0:
    C -= B
    if C <= 0:
        print( 'Yes' )
        exit()
    A -= D 
    if A <= 0:
        print( 'No' )
        exit()


A,B,C,D = map( int,input().split() )
while A > 0 and c > 0:
    C -= B
    if C <= 0 :
        print( "Yes" )
        exit()
    A -= D 
    if A <= 0 :
        print( "No" )
        exit()


A,B,C,D = map( int,input().split() )
while A > 0 and c > 0:
    A -= D 
    if A <= 0 :
        print( 'No' )
        exit()
    B -= C
    if C <= 0 :
        print( 'Yes' )
        exit()

A,B,C,D = map( int,input().split() )
while A > 0 and c > 0:
    A -= D 
    if A <= 0 :
        print( 'No' )
        exit()
    C -= B
    if C <= 0 :
        print( 'Yes' )
        exit()


A,B,C,D = map( int,input().split() )
while A > 0 and C > 0:
    C -= B
    if C <= 0:
        print( 'Yes' )
        exit()
    A -= D 
    if A <= 0:
        print( 'No' )
        exit()


Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
A,B,C,D=map(int,input().split())
jud1=0
jud2=0

if A%D!=0:
  jud1=A//D+A%D
else:
  jud1=A//D

if C%B!=0:
  jud2=C//B+C%B
else:
  jud2=C//B
  
print(jud1,jud2)
if jud1>=jud2:
  print("Yes")
else:
  print("No")

A,B,C,D=map(int,input().split())
k1=0
k2=0

if C%B==0:
  k1=C//B
else:
  k1=C//B+1
if A%D==0:
  k2=A//D
else:
  k2=A//D+1
if k1<=k2:
  print("Yes")
else:
  print("No")
      

Verdicts: Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
a,b,c,d=map(int, input().split())
while True:
	b -= c
	if c<=0 print("Yes"):
      	break
	a -=d
	if a<=0 print("No"):
      	break


a,b,c,d=map(int, input().split())
while
	b -= c
	if c<=0
		print"Yes"
 		break
	a -=d
	if a<=0
      	print"No"
        break

a,b,c,d=map(int, input().split())
while True:
  	b -= c
 	if c<=0:
   		print("Yes")
    	break
    a -=d
    if a<=0:
		print("No")
      	break


a,b,c,d=map(int, input().split())
while True:
	b -= c
	if c<=0:
      print("Yes")
      break
	a -=d
	if a<=0:
      print("No")
      break


a,b,c,d=map(int, input().split())
while True:
	b -= c
	if c<=0 print"Yes" break
	a -=d
	if a<=0 print"No" break


a,b,c,d=map(int, input().split())
while True:
	b -= c
	if c<=0 print"Yes":
      	break
	a -=d
	if a<=0 print"No":
      	break


a,b,c,d=map(int, input().split())
while True:
  c -= b
  if c<=0:
    print("Yes")
    break
  a -=d
  if a<=0:
    print("No")
    break


Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
a,b,c,d = map(int,input().split())

if a - d >= b - c:
    print("Yes")
else:
    print("No")

a,b,c,d = list(map(int,input().split()))

for i in range(100):
    c= c - b 

    if c <=0:
        print("Yes")
        break
    a = a- d    
    if a <= 0 :
        print("No")
        break
    

Verdicts: Wrong Answer

Accepted
Problem: Takahashi and Aoki will have a battle using their monsters.  The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.  The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.  If Takahashi will win, print `Yes`; if he will lose, print `No`.

Submission attempts (in order):
list = list(map(int, input().split()))
A = list[0]
B = list[1]
C = list[2]
D = list[3]

while A > 0 and B >0:
    C = C - B
    if C =< 0:break
    A = A - D

if A > 0: print("Yes")
else: print("No")

list = list(map(int, input().split()))
A = list[0]
B = list[1]
C = list[2]
D = list[3]

while A > 0 and B >0:
    C = C - B
    if C <= 0:break
    A = A - D

if A > 0: print("Yes")
else: print("No")

  

Verdicts: Runtime Error

Accepted