TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
ans = 0
for i in range(n+1):
  if not (i % 3 == 0 or i % 5 == 0):
	ans += i
   
print(ans)

n = int(input())
ans = 0
for i in range(n+1):
  if not (i % 3 == 0 or i % 5 == 0):
    ans += i
print(ans)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=1000000
sum=0
for i in range(1,N+1):
    if i % 3 != 0 and i % 5 != 0:
        #print(i)
        sum += i
print(sum)


N=input()
sum=0
for i in range(1,N+1):
    if i % 3 != 0 and i % 5 != 0:
        #print(i)
        sum += i
print(sum)


N=input()
sum=0
for i in range(1,int(N)+1):
    if i % 3 != 0 and i % 5 != 0:
        #print(i)
        sum += i
print(sum)


Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
t=int(input())
S=0
for i in list(range(t+1)):
  if t%5!=0 and t%3!=0:
    sum += i
print(S)

t=int(input())
S=0
for i in range(t):
  if t%5!=0 and t%3!=0:
    sum += 1
print(S)

t=int(input())
S=0
for i in list(range(t+1)):
  if i%5!=0 and i%3!=0:
    S += i
print(S)


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
def main():
    n=int(input())
    sum=0

    for count in range(n):
        if(count%3==0)|(count%5==0):
            continue
        else:
            sum=sum+count
        
print(str(sum))


n=int(input())
sum=0

for count in range(1,n+1):
    if(count%3==0)|(count%5==0):
        continue
    else:
        sum=sum+count
        
print(sum)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
ans = 0
for i in range(n):
  if n % 3 != 0 and n % 5 != 0:
    ans += i
print(ans)

n = int(input())
ans = 0
for i in range(n + 1):
  if i % 3 != 0 and i % 5 != 0:
    ans += i
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = input()

answer = 'Yes' if '7' in N else 'No'

print(answer)


N = int(input())

is_Fizz = lambda number: number % 3 == 0
is_Buzz = lambda number: number % 5 == 0

answer = 0
for i in range(N + 1):
    if is_Fizz(i) or is_Buzz(i): continue
    
    answer += i

print(answer)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
sum = 0

for i in range(1,N+1):
    if not (i % 3  == 0) and not (i % 5 == 0):
        print(i)
        sum += i

print(sum)

N = int(input())
sum = 0

for i in range(1,N+1):
    if not (i % 3  == 0) and not (i % 5 == 0):
        sum += i

print(sum)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
#B
N = int(input())
A = list(range(1, N + 1))
ans = 0
for a in A:
    if (a % 3 == 0 and a % 5 == 0) or (a % 3 == 0) or (a % 5 == 0):
        pass
    else:
        ans += A[a - 1]
print(A)
print(ans)



#B
N = int(input())
A = list(range(1, N + 1))
ans = 0
for a in A:
    if (a % 3 == 0) or (a % 5 == 0):
        pass
    else:
        ans += A[a - 1]
print(A)



N = int(input())
A = list(range(1, N))
ans = 0
for a in A:
    if (a % 3 == 0 and a % 5 == 0) or (a % 3 == 0) or (a % 3 == 0):
        pass
    else:
        ans += A[a - 1]
print(ans)

#B
N = int(input())
A = list(range(1, N + 1))
ans = 0
for a in A:
    if (a % 3 == 0) or (a % 5 == 0):
        pass
    else:
        ans += A[a - 1]
print(ans)

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
li = []
for i in range(N):
  if i % 3 != 0 and i % 5 != 0 :
    li.append(i)
print(sum(li))
print(li)


N = int(input())
li = 0
for i in range(1,N+1,1):
  if i % 3 != 0 and i % 5 != 0 :
    li += i
print(li)



Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N,=map(int, input().split())  
for i in range(1,N+1):
    if (i % 15==0):
        print("FizzBizz")
    elif(i % 5==0):
        print("Fizz")
    elif(i % 3==0):
        print("Bizz")
    else:
        print(i)

N,=map(int, input().split())  
sum=0
for i in range(1,N+1):
    if (i % 3==0 or i% 5==0):
        continue
    sum=sum+i
print(sum)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
m = 0

for i in rane(n+1):
  if n%3 != 0 and n%5 != 0:
    m += i

print(m)



n = int(input())
m = 0

for i in range(n+1):
  if i%3 != 0 and i%5 != 0:
    m += i

print(m)



Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())
s=(N*(N-1))/2-(int(N/3)*3+3)*int(N/3)/2-(int(N/5)*5+5)*int(N/5)/2+(int(N/15)*15+15)*int(N/15)/2


print(s)  


N=int(input())
s=(N*(N+1))/2-(int(N/3)*3+3)*int(N/3)/2-(int(N/5)*5+5)*int(N/5)/2+(int(N/15)*15+15)*int(N/15)/2


print(int(s))  

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = input()

a = 0

for val in range(1, N+1):
  if val%3 != 0 and val%3 != 0:
    a += val
  
print(a)

N = input()

a = 0

for val in range(1, N+1):
  if val%3 != 0 and val%3 != 0:
    a += val
  else:
    pass
  
print(a)

N = int(input())

a = 0

for val in range(1, N+1):
  if val%3 != 0 and val%5 != 0:
    a += val
  
print(a)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
total = 0
for i in range(1,N + 1):
    if i % 3 == 0 or i % 5 == 0:
        continue
    t = t + i
print(total)

N = int(input())
total = 0
for i in range(1,N + 1):
    if i % 3 == 0 or i % 5 == 0:
        continue
    total = total + i
print(total)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):

import sys
sys.setrecursionlimit(10**6)
N = int(input())

fizzbuzz = []

for i in range(1, N):
    if i % 15 == 0:
        fizzbuzz.append('0')
    elif i % 3 == 0:
        fizzbuzz.append('0')
    elif i % 5 == 0:
        fizzbuzz.append('0')
    else:
        fizzbuzz.append(str(i))

num = [int(s) for s in fizzbuzz]
print(int(sum(num))




N = int(input())

fizzbuzz = []

for i in range(1, N):
    if i % 15 == 0:
        fizzbuzz.append('0')
    elif i % 3 == 0:
        fizzbuzz.append('0')
    elif i % 5 == 0:
        fizzbuzz.append('0')
    else:
        fizzbuzz.append(str(i))

num = [int(s) for s in fizzbuzz]
print(int(sum(num))L)



N = int(input())

fizzbuzz = []

for i in range(1, N+1):
    if i % 3 == 0 or i % 5 == 0:
        fizzbuzz.append('0')
    else:
        fizzbuzz.append(str(i))

num = [int(s) for s in fizzbuzz]
print(sum(num))

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
i = 0
result = 0
while i <= N:
    i += 1
    if i % 3 != 0 and i % 5 != 0:
        result += i
print(result)

N = int(input())
i = 1
result = 0
while i <= N:
    if i % 3 != 0 and i % 5 != 0:
        result += i
    i += 1
print(result)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
print(n*(n+1)//2 - n//3 - n//5 + n//15)

n = int(input())
a = n//3
b = n//5
c = n//15
def s(x):
  return x*(x+1)//2
print(s(n) - 3*s(a) - 5*s(b) + 15*s(c))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
s = N*(N+1)/2

p = N//3
q = N//5
r = N//15

pp = p*(p+1)*3/2
qq = q*(q+1)*5/2
rr = r*(r+1)*15/2

print(s-pp-qq+rr)

N = int(input())
s = N*(N+1)/2

p = N//3
q = N//5
r = N//15

pp = p*(p+1)*3/2
qq = q*(q+1)*5/2
rr = r*(r+1)*15/2

print(int(s-pp-qq+rr))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = input()
tip = "No"
if (N[0] == 7) or (N[1] == 7) or (N[2] == 7):
  tip = "Yes"
print(tip)

N = int(input())

x = N // 3
y = N // 5
z = N // 15

p = N * (N + 1) / 2
q = 3 * x * (x + 1) / 2
r = 5 * y * (y + 1) / 2
s = 15 * z * (z + 1) / 2
Sum = p - q - r + s
print(int(Sum))

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
print(sum(n)-sum(n/3)*3-sum(n/5)*5+sum(n/15)*15)

n = int(input())
s = 0
for i in range(1, n+1):
    if i % 15 == 0:
        pass
    elif i % 3 == 0:
        pass
    elif i % 5 == 0:
        pass
    else:
        s += i
print(s)


Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
import math
Nstring=int(input())
ans=(N*(N+1))/2
ans=ans-math.floor(N/3)
ans=ans-math.floor(N/5)
ans=ans+math.floor(N/15)
print(ans)

import math
N=int(input())
ans=(N*(N+1))/2
ans=ans-3*math.floor(N/3)*(math.floor(N/3)+1)/2
ans=ans-5*math.floor(N/5)*(math.floor(N/5)+1)/2
ans=ans+15*math.floor(N/15)*(math.floor(N/15)+1)/2
print(int(ans))

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
def solve(string):
    return str(sum(i for i in range(n + 1) if i % 3 > 1 and i % 5 > 1))


if __name__ == '__main__':
    import sys
    print(solve(sys.stdin.read().strip()))


def solve(string):
    return str(sum(i for i in range(int(string) + 1) if i % 3 > 1 and i % 5 > 1))


if __name__ == '__main__':
    import sys
    print(solve(sys.stdin.read().strip()))


def f(n):
    return n * (n + 1) // 2


def solve(string):
    n = int(string)
    return str(f(n) - 3 * f(n // 3) - 5 * f(n // 5) + 15 * f(n // 15))


if __name__ == '__main__':
    import sys
    print(solve(sys.stdin.read().strip()))


Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
for number in range(1, 30 + 1):
    if (number % 3 == 0) and (number % 5 == 0):
        print('FizzBuzz')
    elif number % 3 == 0:
        print('Fizz')
    elif number % 5 == 0:
        print('Buzz')
    else:
        print(str(number))


n = int(input())
total = []  

for i in range(1, n + 1):
    if i % 3 == 0 and i % 5 == 0:
        "FizzBuzz"
    elif i % 3 == 0:
        "Fizz"
    elif i % 5 == 0:
        "Buzz"
    else:
        total.append(i)  
print(sum(total))  

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = input()
ans=0
for i in range(1,n):
    if i%3==0 or i%5==0:
        continue
    ans+=i
print(ans)

n = input()
ans=0
for i in range(1,n+1):
    if i%3==0 or i%5==0:
        continue
    ans+=i
print(ans)

n = int(input())
ans=0
for i in range(1,n+1):
    if i%3==0 or i%5==0:
        continue
    ans+=i
print(ans)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())

sum = 0

for i in N + 1:
    if i % 3 == 0 or i % 5 == 0:
        continue
    else:
        sum += i

print(sum)

N = int(input())

sum = 0

for i in range(N + 1):
    if i % 3 == 0 or i % 5 == 0:
        continue
    else:
        sum += i

print(sum)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
x = int(input())
ans = 0

for i in range(x+1):
  if i % 15 == 0 :
    pass
  elif i % 3 == 0:
    pass
  elif i % 5 == 0:
    pass
  else:
    ans += i
  print(i)

print(ans)

x = int(input())
ans = 0

for i in range(1, x+1):
  if i % 3 != 0 and i % 5 != 0:
    ans += i
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=1000000
n=N//15
ans=60*(n**2)
if N%15==1:
	ans+=(1+15*(n))
elif N%15==2 or N%15==3:
	ans+=(3+30*(n))
elif N%15==4 or N%15==5 or N%15==6:
	ans+=(7+45*(n))
elif N%15==7:
	ans+=(14+60*(n))
elif N%15==8 or N%15==9 or N%15==10:
	ans+=(22+75*(n))
elif N%15==11 or N%15==12:
	ans+=(33+90*(n))
elif N%15==13:
	ans+=(46+105*(n))
elif N%15==14:
	ans+=(60+120*(n))
print(ans)

N=int(input())
n=N//15
ans=60*(n**2)
if N%15==1:
	ans+=(1+15*(n))
elif N%15==2 or N%15==3:
	ans+=(3+30*(n))
elif N%15==4 or N%15==5 or N%15==6:
	ans+=(7+45*(n))
elif N%15==7:
	ans+=(14+60*(n))
elif N%15==8 or N%15==9 or N%15==10:
	ans+=(22+75*(n))
elif N%15==11 or N%15==12:
	ans+=(33+90*(n))
elif N%15==13:
	ans+=(46+105*(n))
elif N%15==14:
	ans+=(60+120*(n))
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())
ans=0
for i in range(N):
  if N%3!=0 and N%5!=0:
    ans+=i
print(ans)

N=int(input())
ans=0
for i in range(1,N+1):
  if i%3!=0 and i%5!=0:
    ans+=i
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())
k=0
for i in range(N):
  if ((i+1)%3!=0)&&((i+1)%5!=0):
    k=k+i
print(k)
  

N=int(input())
k=0
for i in range(N):
  j=i+1
  if (j%3!=0)&&(j%5!=0):
    k=k+j
print(k)


N=int(input())
k=0
for i in range(N):
  if (i%3!=0)&&(i%5!=0):
    k=k+i
print(k)

N=int(input())
k=0
for i in range(N):
  j=i+1
  if (j%3!=0)and(j%5!=0):
    k=k+j
print(k)


Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
import itertools
import math

k=200
klis = list(range(1,k+1))
lis = list(itertools.product(klis, klis, klis))
temp = []
for i in range(len(lis)):
    temp.append(math.gcd(math.gcd(lis[i][0],lis[i][1]),lis[i][2]))

print(sum(temp))

n = int(input())

all = int((n+1)*(n/2))
fizz = int(3*((n//3 + 1)*((n//3)/2)))
buzz = int(5*((n//5 + 1)*((n//5)/2)))
fizzbuzz = int(15*((n//15 + 1)*((n//15)/2)))

result =  all - fizz - buzz + fizzbuzz
print(result)

Verdicts: Time Limit Exceeded

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
ans = n*(n+1)//2
d = n%3
ans -= 3*(d+1)*d//2
e = n%5
ans -= 5*(e+1)*e//2
f = n%15
ans -= 15*(f+1)*f//2
print(ans)

n = int(input())
ans = n*(n+1)//2
d = n//3
ans -= 3*(d+1)*d//2
e = n//5
ans -= 5*(e+1)*e//2
f = n//15
ans -= 15*(f+1)*f//2
print(ans)


n = int(input())
ans = n*(n+1)//2
d = n//3
ans -= 3*(d+1)*d//2
e = n//5
ans -= 5*(e+1)*e//2
f = n//15
ans += 15*(f+1)*f//2
print(ans)


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
A=int(input())
Sum= A*(A+1)/2
B=(A//3)
C=(A//5)
D=(A//15)

E=B*(6+(B-1)*3)/2
F=C*(10+(C-1)*5)/2
G=D*(30+(D-1)*15)/2

print(Sum-E-F+G)

A=int(input())
Sum= A*(A+1)/2
B=(A//3)
C=(A//5)
D=(A//15)

E=B*(6+(B-1)*3)/2
F=C*(10+(C-1)*5)/2
G=D*(30+(D-1)*15)/2

print(int(Sum-E-F+G))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
sum = 0
for i in range(1,N +1):
    if i % 3 == 0 and i % 5 == 0:
        print('FizzBuzz')
    if i % 3 == 0:
        print('Fizz')
    if i % 5 == 0:
        print('Buzz')
    else:
        sum = sum + i
print(sum)

N = int(input())
sum = 0
for i in range(1,N +1):
    if i % 5 != 0 and i % 3 != 0:
        sum += i
print(sum)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
S = 0
for i in range(1, N+1):
  if i%3==0 or i%5==0 or (i%3==0 and i%5==0):
	continue
  S+=i
print(S) 

N = int(input())
out = 0
for in in range(1,N+1):
  if i%3==0 and i%5==0 or i%3==0 or i%5==0
	continue
  out +=i
print(out) 

N = int(input())
S = 0
for i in range(1, N+1):
  if i%3==0 or i%5==0 or i%3==0 and i%5==0
	continue
  S+=i
print(S) 

N = int(input())
S = 0
for i in range(1,N+1):
  if i%3==0 or i%5==0 or i%3==0 and i%5==0
	continue
  S +=i
print(S) 

N = int(input())
S = 0
for i in range(1, N+1):
  if i%3==0 or i%5==0 or i%3==0 and i%5==0
		continue
  S+=i
print(S) 

N = int(input())
S = 0
for in in range(1,N+1):
  if i%3==0 or i%5==0 or i%3==0 and i%5==0
	continue
  S +=i
print(S) 

N = int(input())
out = 0
for i in range(1,N+1):
    if i%3 == 0 and i%5 == 0 or i%3==0 or i%5==0:
       continue
    out += i
print(out)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
res = 0
for i in range(1,N+1):
    if i%15==0:
        dp = 0
    elif i%5==0:
        dp = 0
    elif i%3==0:
        dp = 0
    else :å
        dp = i
    res = res+dp
print(res)

N = int(input())
res = 0
for i in range(1,N+1):
    if i%15==0:
        dp = 0
    elif i%5==0:
        dp = 0
    elif i%3==0:
        dp = 0
    else :
        dp = i
    res = res+dp
print(res)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
import math

I = int(input())

#H, W = map(int, input().split())

#N = input()

#listA = list(N)

a = 0
for num in range(I+1):
    print(num)
    if num%3 == 0 and num%5 == 0:
        print('FizzBuzz')
    elif num%3 == 0:
        print('Fizz')
    elif num%5 == 0:
        print('Buzz')
    else:
        a = a + num

print(a)

import math

I = int(input())

#H, W = map(int, input().split())

#N = input()

#listA = list(N)
a = 0
for num in range(I):
    if num%3 == 0 and num%5 == 0:

    elif num%3 == 0:

    elif num%5 == 0:

    else:
        a = a + num

print(a)

import math

I = int(input())

#H, W = map(int, input().split())

#N = input()

#listA = list(N)

a = 0
for num in range(I):
    print(num)
    if num%3 == 0 and num%5 == 0:
        print('FizzBuzz')
    elif num%3 == 0:
        print('Fizz')
    elif num%5 == 0:
        print('Buzz')
    else:
        a = a + num

print(a)


import math

I = int(input())

#H, W = map(int, input().split())

#N = input()

#listA = list(N)
a = 0
for num in range(I):
    if num%3 == 0 and num%5 == 0:
        print('FizzBuzz')
    elif num%3 == 0:
        print('Fizz')
    elif num%5 == 0:
        print('Buzz')
    else:
        a = a + num

print(a)


import math

I = int(input())

#H, W = map(int, input().split())

#N = input()

#listA = list(N)
I = I + 1
a = 0
for num in range(I):
    if num%3 == 0 and num%5 == 0:
        print('FizzBuzz')
    elif num%3 == 0:
        print('Fizz')
    elif num%5 == 0:
        print('Buzz')
    else:
        a = a + num

print(a)

import math

I = int(input())

#H, W = map(int, input().split())

#N = input()

#listA = list(N)
a = 0
I = I + 1
for num in range(I):
    if num%3 == 0 and num%5 == 0:
        a = a
    elif num%3 == 0:
        a = a
    elif num%5 == 0:
        a = a
    else:
        a = a + num

print(a)


Verdicts: Wrong Answer

Runtime Error

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())
sum=0

for i in range(1,N+1):
  if i%3==0 or i%5==0:
    pass
  else:
    ans += i
    
print(ans)

N=int(input())
ans=0

for i in range(1,N+1):
  if i%3==0 or i%5==0:
    pass
  else:
    ans += i
    
print(ans)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = input()
ans = 0

for i in range(1, n+1):
  if i%3!=0 and i%5!=0:
    ans += i
    
print(ans)

n = int(input())
ans = 0

for i in range(1, n+1):
  if i%3!=0 and i%5!=0:
    ans += i
    
print(ans)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
def main():
    n = int(input())
    a, b = n // 15, n % 15

    fbeg = [i for i in range(1, 16) if i % 3 != 0 and i % 5 != 0]
    fend = [i for i in range(a * 15, n + 1) if i % 3 != 0 and i % 5 != 0]

    ne = len(fbeg)
    fbs = sum(fbeg) # sum of first terms in [1, 15]
    fes = sum(fend)
    step = 15 * ne
    first = fbs
    last = fbs + (a-1) * step

    tot = (first + last) * (last - first + step) // step // 2 + sum(fend)

    print(tot)



def main():
    n = int(input())
    a, b = n // 15, n % 15

    fbeg = [i for i in range(1, 16) if i % 3 != 0 and i % 5 != 0]
    fend = [i for i in range(a * 15, n + 1) if i % 3 != 0 and i % 5 != 0]

    ne = len(fbeg)
    fbs = sum(fbeg) # sum of first terms in [1, 15]
    fes = sum(fend)
    step = 15 * ne
    first = fbs
    last = fbs + (a-1) * step

    tot = (first + last) * a // 2 + fes

    print(tot)

main()


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
s = input().split()
n = int(s)
sum = 0
for i range(1:n+1):
  #print(n)
  if ((i mod 3 )!=0 ) and ((i mod 5 )!=0 ) :
    sum += i
print(sum)


s = input().split()
n = int(s)
sum = 0
for i range(1,n+1):
  print(n)
  if ((i mod 3 )!=0 ) and ((i mod 5 )!=0 ) :
    sum += i
print(sum)


s = input().split()
n = int(s[0])
sum = 0
for i in range(1,n+1):
  #print(n)
  if ((i % 3 )!=0 ) and ((i % 5 )!=0 ) :
    sum += i
print(sum)


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
a = int(input())

b = range(1, a)

c = [i for i in b if i%15 == 0 and i%5 == 0 and i%3 == 0]

d = sum(c)
print(d)

a = int(input())
b = []
if a <= 1000000:
for i in range(a):
    if i % 15 == 0:
      pass
    elif i % 3 == 0:
      pass
    elif i % 5 == 0:
      pass
    else:
      b.append(i)
else:
  pass
print(sum(b))


a = int(input())
b = []

for i in range(a+1):
    if i % 3 == 0 and i % 5 == 0:
      pass
    elif i % 3 == 0:
      pass
    elif i % 5 == 0:
      pass
    else:
      b.append(i)
print(sum(b))



Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
text = ""
result = 0
for i in range(1, n+1,1):
    print("in loop",i)
    if (i/3 != 0):
        print("A",i)
        result +=i
    else:
        pass



print(result)

 fizzBuzz = []
 inputNumber = int(input())
 for i in range(inputNumber + 1):
     if i % 3 == 0 and i % 5 == 0:
         metCondition = 'FizzBuzz'
     elif i % 5 == 0:
         metCondition = 'Buzz'
     elif i % 3 == 0:
         metCondition = 'Fizz'
     else:
         metCondition = i
     fizzBuzz.append(metCondition)
 metCondition_2 = [num for num in fizzBuzz if isinstance(num, (int, float))]
 print(sum(metCondition_2))

fizzBuzz = []
inputNumber = int(input())
for i in range(inputNumber + 1):
    if i % 3 == 0 and i % 5 == 0:
        metCondition = 'FizzBuzz'
    elif i % 5 == 0:
        metCondition = 'Buzz'
    elif i % 3 == 0:
        metCondition = 'Fizz'
    else:
        metCondition = i
    fizzBuzz.append(metCondition)
metCondition_2 = [num for num in fizzBuzz if isinstance(num, (int, float))]
print(sum(metCondition_2))

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):

N = int(input())


result = 0


for i in range(1,N + 1):
    if not (i % 15 == 0 or i % 5 == 0 or i % 3 == 0):
        result += i
    print(result)


N = int(input())


result = 0


for i in range(1, N + 1):
    if (i % 15 == 0 or i % 3 == 0 or i % 5 == 0):
        result += 0
    else:
        result += i
    print(result)















N = int(input())


result = 0


for i in range(1, N + 1):
    if not (i % 15 == 0 or i % 3 == 0 or i % 5 == 0):
        result += i
    print(result)


N = int(input())


result = 0


for i in range(1, N + 1):
    if i % 15 == 0:
        result += 0
    elif i % 3 == 0:
        result += 0
    elif i % 5 == 0:
        result += 0
    else:
        result += i
    print(result)


N = int(input())


result = 0


for i in range(1, N + 1):
    if i % 15 == 0:
        result += 0
    elif i % 3 == 0:
        result += 0
    elif i % 5 == 0:
        result += 0
    else:
        result += i
print(result)

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = 1000000

ans = 0

for i in range(1,N+1):
  if i%3 != 0 and i % 5 != 0:
    ans += i
print(ans)

N = int(input())

ans = 0

for i in range(1,N+1):
  if i%3 != 0 and i % 5 != 0:
    ans += i
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())

ans=0
for i in range(n+1):
    
    if not i%3==0 and i%5==0:
        ans+=i
    
print(ans)


n=int(input())

ans=0
for i in range(0,n+1):
    if  i%3!=0 and i%5!=0:
        ans+=i
    
print(ans)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
count_list = []
for i in range(N + 1):
    if i % 15 == 0:
        count_list.append('FizzBuzz')
    elif i % 3 == 0:
        count_list.append('Fizz')
    elif i % 5 == 0:
        count_list.append('Buzz')
    else:
        count_list.append(i)
int_list = []
for i in count_list:
    try:
        int_list.append(int(i))
    except:
        pass
print(int_list)


N = int(input())
count_list = []
for i in range(N * 15 + 1):
    if i % 15 == 0:
        count_list.append('FizzBuzz')
    elif i % 3 == 0:
        count_list.append('Fizz')
    elif i % 5 == 0:
        count_list.append('Buzz')
    else:
        count_list.append(i)
int_list = []
for i in count_list:
    try:
        int_list.append(int(i))
    except:
        pass
print(sum(int_list))


N = int(input())
count_list = []
for i in range(N + 1):
    if i % 15 == 0:
        count_list.append('FizzBuzz')
    elif i % 3 == 0:
        count_list.append('Fizz')
    elif i % 5 == 0:
        count_list.append('Buzz')
    else:
        count_list.append(i)
int_list = []
for i in count_list:
    try:
        int_list.append(int(i))
    except:
        pass
print(sum(int_list))


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
list = []
for i in range(1,1000010):
  if(i%3==0 or i%5==0):
    list.append(0)
  else:
    list.append(i)
n = int(input())
print(list[:n-1])

list = []
for i in range(1,1000010):
  if(i%3==0 or i%5==0):
    list.append(0)
  else:
    list.append(i)
n = int(input())
print(sum(list[:n]))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
import numpy as np

N = int(read())
x = np.arange(1, N + 1, dtype=np.int64)
x[::3] = 0
x[::5] = 0
print(x.sum())


import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
import numpy as np

N = int(read())
x = np.arange(N + 1, dtype=np.int64)
x[::3] = 0
x[::5] = 0
print(x.sum())


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
ans = 0
for i in range(n):
    if i + 1 // 3 != 0 and i + 1 // 5 != 0:
        ans += i + 1
print(ans)

n = int(input())
ans = 0
for i in range(n):
    if (i + 1) % 3 != 0 and (i + 1) % 5 != 0:
        ans += i + 1
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())

result = 0

for i in range(1,N + 1):
    if i % 3 == 0 or i % 5 == 0:
      continue
    result += i
    
    print(result)
       

N = int(input())

result = 0
for i in range(N + 1):
    if i % 3 != 0 and i % 5 != 0:
       result += i
    
print(result)
 



Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
def main():
    N = input()
    sum = 0
    for i in range(N):
        i = i+1
        if i%3 ==0 or i%5 ==0 or i%15 ==0:
            continue
        else:
            sum = sum + i

    print(sum)




if __name__ == "__main__":
    main()

def main():
    N = int(input())
    sum = 0
    for i in range(N):
        i = i+1
        if i%3 == 0 or i%5 == 0 or i%15 == 0:
            continue
        else:
            sum = sum + i

    print(sum)




if __name__ == "__main__":
    main()

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
sum = int(0)
for i in range(1,n+1):
  if i%15==0:
    print('FizzBuzz')
  elif i%5==0:
    print('Buzz')
  elif i%3==0:
    print('Fizz')
  else:
    print(i)
    sum = sum+i
print(sum)

n = int(input())
sum = 0

for i in range(1,n+1):
  if i%15==0:
    print('FizzBuzz')
  elif i%5==0:
    print('Buzz')
  elif i%3==0:
    print('Fizz')
  else:
    print(i)
    sum += i
print(sum)

n = int(input())
sum = 0

for i in range(1,n+1):
  if i%15==0:
    print('FizzBuzz')
  elif i%5==0:
    print('Buzz')
  elif i%3==0:
    print('Fizz')
  else:
    print(i)
    sum += i
print(sum)

n = int(input())
sum = int(0)
for i in range(1,n+1):
  if i%15==0:
    print('FizzBuzz')
  elif i%5==0:
    print('Buzz')
  elif i%3==0:
    print('Fizz')
  else:
    print(i)
    sum += i
print(sum)

n = int(input())
sum = 0
for i in range(1,n+1):
  if i%15!=0:
    if i%5!=0:
      if i%3!=0:
        sum += i
print(sum)

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
S = 0
for i in range(N):
    if i+1%3 and i+1%5 or i+1%3 or i+1%5:
        break
    else:
        global S = S+1+i
        
    


N = int(input())
S = 0
for i in range(N):
    if (i+1)%3 == 0 and (i+1)%5==0 or (i+1)%3 ==0 or (1+i)%5 ==0 :
        continue
    else:
        S = S+1+i

print(S)
    


Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
a = int(input())
ans = 0
i = 1
while i <=a :
    if i%3 == 0:
        i += 1
        continue
    elif i%5 == 0:
        i += 1
        continue
    ans += a
    
print(ans)


a = input()
ans = 0
i = 1
for i in range(0,a,1):
    if i%3 == 0:
        i += 1
        continue
    elif i%5 == 0:
        i += 1
        continue
    ans += a
    
print(ans)


a = int(input())
ans = 0
i = 1
while i <= a:
    if i%15 == 0:
        i += 1
        continue
    elif i%3 == 0:
        i += 1
        continue
    elif i%5 == 0:
        i += 1
        continue
    ans += i
    i += 1
    
print(ans)


Verdicts: Time Limit Exceeded

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())
num_list=[]
for i in range(N+1):
  if i%3!=0 or i%5!=0:
    num_list.append(i)
print(sum(num_list))

N=int(input())
num_list=[]
for i in range(N+1):
  if i%3!=0 and i%5!=0:
    num_list.append(i)
    
print(num_list)
print(sum(num_list))

N=int(input())
num_list=[]
for i in range(N+1):
  if i%3!=0 and i%5!=0:
    num_list.append(i)
print(sum(num_list))

Verdicts: Wrong Answer

Wrong Answer

Accepted