TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
print(input().replace("," " "))

print(input().replace(',', ' '))


Verdicts: Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
a,b,c=input().split(",")
print("a","b","c")

a,b,c=input().split(",")
print(a,b,c)

Verdicts: Wrong Answer

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
s = input()
print(s.split(',')

s = input()
print(*s.split(","))

Verdicts: Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
s=input()
print(s.split(","))

s=input()
print(s.split(,))

s=input()
print(s.replace(","," "))

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
A,B,C =map(str, input().split(,))
print(A,B,C)

a, b, c = input().split(",")
print(a, b, c)

Verdicts: Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
a,s,d=input(),split(',')
print(a,s,d)

a,s,d=input().split(',')
print(a,s,d)

Verdicts: Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
input_ = inpur().split(",")
print(" ".join(str for i in input))

inp = input().split(",")

print(" ".join(inp))

Verdicts: Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
a,b,c=input().split()
print(a+" "+b+" "+c)

a=input()
l=a.split(",")
print(l[0]+" "+l[1]+" "+l[2])

Verdicts: Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
x, y ,z = input().split(,)
print(x, y, z)

a, b, c = input().split(,)
print(a, b, c)

a, b, c = input().split(",")
print(a, b, c)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
a = input()
b = a.split(",")
print(b)

s = input().split(",")
print(*s, sep=" ")

Verdicts: Wrong Answer

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
k,s=map(int,input().split())
ans = 0
for i in range(k+1):
  if k<=s-i<=2*k:
      ans+= s-i+1
  elif 0<=s-i<=k:
      ans+= k*2-s+1
print(ans)

k,s=map(int,input().split())
ans = 0
for i in range(k+1):
  if k <=s-i<=2*k:
    ans+= s-i+1
  elif 0<=s-i<=k:
    ans+= k*2-s+1
print(ans)

print(input().replace(","," "))

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
s = [input().split()]
print('{} {} {}'.format(s))


print(*input().split(','))

Verdicts: Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
a,b,c=input().split(' ')
if b=='+':
    print(int(a)+int(c))
else:
    print(int(a)-int(c))


a,b,c=map(str,input().split(','))
print(a,b,c)


Verdicts: Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
s = input()
s.replace(',', ' ')
print(s)

s = input()
s = s.replace(',', ' ')
print(s)

Verdicts: Wrong Answer

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
s=input()
print(f"{} {} {}".format( s[0,5], s[6,13],s[14,19] ) )

s=input()
print("{} {} {}".format( s[0,5], s[6,13],s[14,19] ) )

s=list(input()
print("{} {} {}".format( s[0,5], s[6,13],s[14,19] ) )

s=input()
print("{} {} {}".format( s[0:5], s[6:13],s[14:19] ) )

Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
k,s = map(int,input().split())
count = 0
for i in range(k+1):
    for j in range(k+1):
        if s-i-j <= k:
            count += 1
print(count)


k,s = map(int,input().split())
count = 0
for i in range(k+1):
    for j in range(k+1):
        if s-(i+j) <= k and s-(i+j) >= 0:
            count += 1
print(count)


line = input()
print(line.replace(","," "))


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
x, y, z = input().split
print(x, y, z)

x,y,z = int().split(',')
print(x,y,z)

x,y,z = input().split(',')
print(x,y,z)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
s = input()
for i in range(len(s)):
  if s[i]==',':
    s[i]==' '
print(s)

s = list(input())
for i in range(len(s)):
  if s[i]==',':
    s[i]=' '
print(''.join(s))

Verdicts: Wrong Answer

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
a = str(input())

a.replace(","," ")

print(a)

a = str(input())

a=a.replace(","," ")

print(a)

Verdicts: Wrong Answer

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
s = input()
s.replace(',',' ')

s = input()
p = s.replace(',',' ')
print(p)

Verdicts: Wrong Answer

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
a,b,c=input().split()
print(a,b,c)

print(input().split())

a,b,c=input().split(",")
print(a,b,c)

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
s=input()
print(s.replace(",","/"))


s=input()
print(s.replace(","," "))


Verdicts: Wrong Answer

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
s = input()
s_list = [s.strip() for x in s.split(',')]
print(' '.join(s_list))

s = input()
s_list = [x.strip() for x in s.split(',')]
print(' '.join(s_list))

Verdicts: Wrong Answer

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
a,b,c = input().split(,)
print(a+" "+b+" "+c)

a,b,c = input().split(",")
print(a+" "+b+" "+c)

Verdicts: Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
s,t,u=map(int,input().split(''))
print(s,t,u)

s,t,u=map(int,input().split(','))
print(s,t,u)

s,t,u=map(str,input().split(','))
print(s,t,u)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
K, S = list(map(int, input().split()))

a = 0
for i in range(K + 1):
    r = S - i
    if i <= S and r <= K * 2:
        t = (r + 1) - max(0, r - K) * 2
        a += t

print(a)


print(input().replace(',',' '))

Verdicts: Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
a,b,c=input()split(",")
print(a,b,c)

a,b,c=input().split(",")
print(a,b,c)


Verdicts: Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
list = list(map(str,input()))
list[5] = " "
list[13] = " "
print(list)

list = list(map(str,input()))
list[5] = " "
list[13] = " "
print("".join(list))


Verdicts: Wrong Answer

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
s=input()
print(s.replace(',',' ')

s=input()
print(s.replace(',',' '))

Verdicts: Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
s = input()
print(s[:5]+" "+s[7:14]+" "+s[16:])

s = input()
l = s.split(',')
ans = ' '.join(l)
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
a, b, c = input().split(",")
print(a+b+c)

a, b, c = input().split(",")
print(a, b, c)

Verdicts: Wrong Answer

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
s=str("haiku,atcoder,tasks")
print(s.replace(",", " "))

t=str(s)
print(t.replace(",", " "))

s = input()
print(s.replace(',', ' '))

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
k, s = list(map(int, input().split()))
num = 0

for x in range(k+1):
  for y in range(k+1):
    if s-k <= x+y <= s:
      num += 1

print(num)


s = input()
print(s.replace(',', ' '))


Verdicts: Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
a, b, c = input().split(sep = ", ")

print(a + " " + b + " " + c)


a, b, c = input().split(sep = ",")

print(a + b + c)



a, b, c = input().split(sep = ",")
print(a + b + c)


a, b, c = input().split(sep = ", ")
if(len(a) == 7):
    print(b.lower() + " " + a.lower() + " " + c.lower())
elif(len(b) == 7):
    print(a.lower() + " " + b.lower()  + " " + c.lower())
elif(len(c) == 7):
    print(a.lower() + " " + c.lower() + " " + b.lower*(()


a, b, c = input().split(sep = ",")
 
print(a, b, c)


Verdicts: Runtime Error

Wrong Answer

Wrong Answer

Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
s = input()
s = s.replace(",", "")

print(s)

s = input()
s = s.replace(',', ' ')
print(s)

Verdicts: Wrong Answer

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
import re
re.sub(","," ",str(input()))

import re
print(re.sub(","," ",str(input())))

Verdicts: Wrong Answer

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
a, b, c = input.split(",")
print(a,b,c)

a = input()
print(a.replace(',' , ' ')

a = input()
print(a.replace(',' , ' ')

a, b, c = input.split(",")
print(a, b, c)

print(*input.split(",")

s = input()
print(s.replace(',', ' '))
a = input()
print(a.replace(',' , ' ')

print(*input().split(',')

a = input()
print(a.replace(',' , ' '))

Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: As a New Year's gift, Dolphin received a string s of length 19.   The string s has the following format: `[five lowercase English letters],[seven lowercase English letters],[five lowercase English letters]`.   Dolphin wants to convert the comma-separated string s into a space-separated string.   Write a program to perform the conversion for him.

Submission attempts (in order):
happy,newyear,enjoy

a = input()

b = a.replace(",", " ")

print(b)

Verdicts: Runtime Error

Accepted
Problem: You are given an undirected connected weighted graph with N vertices and M edges that contains neither self-loops nor double edges.   The i-th (1≤i≤M) edge connects vertex a_i and vertex b_i with a distance of c_i.   Here, a _self-loop_ is an edge where a_i = b_i (1≤i≤M), and _double edges_ are two edges where (a_i,b_i)=(a_j,b_j) or (a_i,b_i)=(b_j,a_j) (1≤i<j≤M).   A _connected graph_ is a graph where there is a path between every pair of different vertices.   Find the number of the edges that are not contained in any shortest path between any pair of different vertices.

Submission attempts (in order):
import sys
from scipy.sparse.csgraph import dijkstra

input = sys.stdin.readline
N, M = map(int, input().split())

graph = [[0 if i == j else float("inf") for i in range(N)] for j in range(N)]
for i in range(M):
    ai, bi, ci = map(int, input().split())
    graph[ai - 1][bi - 1] = ci
    graph[bi - 1][ai - 1] = ci

dist1 = dijkstra(graph, directed=False)
print(graph)
print(dist1)

cnt = 0
for i in range(N):
    for j in range(N):
        used = False
        if i > j:
            continue
        for k in range(N):
            if graph[i][j] + dist1[k][i] == dist1[i][j]:
                used = True
                break
        if not used and graph[i][j] == "inf":
            cnt += 1
print(cnt)


import sys
from scipy.sparse.csgraph import dijkstra

input = sys.stdin.readline
N, M = map(int, input().split())

graph = [[0 if i == j else float("inf") for i in range(N)] for j in range(N)]
for i in range(M):
    ai, bi, ci = map(int, input().split())
    graph[ai - 1][bi - 1] = ci
    graph[bi - 1][ai - 1] = ci

dist1 = dijkstra(graph, directed=False)
print(graph)
print(dist1)

cnt = 0
for i in range(N):
    for j in range(N):
        used = False
        if i > j:
            continue
        for k in range(N):
            if graph[i][j] + dist1[k][i] == dist1[i][j]:
                used = True
                break
        if not used and graph[i][j] != float("inf"):
            cnt += 1
print(cnt)


import sys
from scipy.sparse.csgraph import dijkstra

input = sys.stdin.readline
N, M = map(int, input().split())

graph = [[0 if i == j else float("inf") for i in range(N)] for j in range(N)]
for i in range(M):
    ai, bi, ci = map(int, input().split())
    graph[ai - 1][bi - 1] = ci
    graph[bi - 1][ai - 1] = ci

dist = dijkstra(graph, directed=False)

cnt = 0
for i in range(N):
    for j in range(N):
        used = False
        if i > j:
            continue
        for k in range(N):
            if graph[i][j] + dist[k][i] == dist[i][j]:
                used = True
                break
        if not used and graph[i][j] != float("inf"):
            cnt += 1
print(cnt)


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: You are given an undirected connected weighted graph with N vertices and M edges that contains neither self-loops nor double edges.   The i-th (1≤i≤M) edge connects vertex a_i and vertex b_i with a distance of c_i.   Here, a _self-loop_ is an edge where a_i = b_i (1≤i≤M), and _double edges_ are two edges where (a_i,b_i)=(a_j,b_j) or (a_i,b_i)=(b_j,a_j) (1≤i<j≤M).   A _connected graph_ is a graph where there is a path between every pair of different vertices.   Find the number of the edges that are not contained in any shortest path between any pair of different vertices.

Submission attempts (in order):
import sys
input = sys.stdin.readline

def main():
  n, m = map(int, input().split())
  road = [[100000]*n for _ in range(n)]
  count = [[-1]*n for i in range(n)]
  for _ in range(m):
    a, b, c = map(int, input().split())
    road[a-1][b-1] = c
    road[b-1][a-1] = c
    count[a-1][b-1] = 0
    count[b-1][a-1] = 0
  for k in range(n):
    for i in range(n):
      for j in range(n):
        if road[i][k]+road[k][j] < road[i][j]:
          if count[i][j] == 0:
            count[i][j] = 1
          road[i][j] = road[i][k]+road[k][j]
  print(count)
  ans = 0
  for i in range(n):
    ans += count[i].count(1)
  print(ans//2)
if __name__ == "__main__":
  main()

import sys
input = sys.stdin.readline

def main():
  n, m = map(int, input().split())
  road = [[100000]*n for _ in range(n)]
  count = [[-1]*n for i in range(n)]
  for _ in range(m):
    a, b, c = map(int, input().split())
    road[a-1][b-1] = c
    road[b-1][a-1] = c
    count[a-1][b-1] = 0
    count[b-1][a-1] = 0
  for k in range(n):
    for i in range(n):
      for j in range(n):
        if road[i][k]+road[k][j] < road[i][j]:
          if count[i][j] == 0:
            count[i][j] = 1
          road[i][j] = road[i][k]+road[k][j]
  ans = 0
  for i in range(n):
    ans += count[i].count(1)
  print(ans//2)
if __name__ == "__main__":
  main()

Verdicts: Wrong Answer

Accepted
Problem: You are given an undirected connected weighted graph with N vertices and M edges that contains neither self-loops nor double edges.   The i-th (1≤i≤M) edge connects vertex a_i and vertex b_i with a distance of c_i.   Here, a _self-loop_ is an edge where a_i = b_i (1≤i≤M), and _double edges_ are two edges where (a_i,b_i)=(a_j,b_j) or (a_i,b_i)=(b_j,a_j) (1≤i<j≤M).   A _connected graph_ is a graph where there is a path between every pair of different vertices.   Find the number of the edges that are not contained in any shortest path between any pair of different vertices.

Submission attempts (in order):
N, M = map(int, input().split())
G = [[float('inf')]*N for i in range(N)]
G2 = [[float('inf')]*N for i in range(N)]
for i in range(M):
    a, b, c = map(int, input().split())
    G[a-1][b-1] = c
    G[b-1][a-1] = c
    G2[a-1][b-1] = c
    G2[b-1][a-1] = c

for i in range(N):
    for j in range(N):
        for k in range(N):
            if G[i][j] > G[i][k] + G[k][j]:
                G[i][j] = G[i][k] + G[k][j]

cnt = 0
for i in range(N):
    for j in range(N):
        for k in range(N):
            if G[i][j] != G2[i][j]:
                cnt += 1

print(M - cnt//2)


from copy import deepcopy
N, M = map(int, input().split())
G = [[float('inf')] * N for i in range(N)]
for i in range(M):
    a, b, c = map(int, input().split())
    a, b = a - 1, b - 1
    G[a][b] = c
    G[b][a] = c


Shortest = deepcopy(G)
for k in range(N):
    for i in range(N):
        for j in range(N):
            Shortest[i][j] = min(Shortest[i][j], Shortest[i][k] + Shortest[k][j])


ans = 0
for i in range(N):
    for j in range(N):
        if G[i][j] == float('inf'):
            continue
        if G[i][j] != Shortest[i][j]:
            ans += 1

print(ans // 2)


Verdicts: Wrong Answer

Accepted
Problem: You are given an undirected connected weighted graph with N vertices and M edges that contains neither self-loops nor double edges.   The i-th (1≤i≤M) edge connects vertex a_i and vertex b_i with a distance of c_i.   Here, a _self-loop_ is an edge where a_i = b_i (1≤i≤M), and _double edges_ are two edges where (a_i,b_i)=(a_j,b_j) or (a_i,b_i)=(b_j,a_j) (1≤i<j≤M).   A _connected graph_ is a graph where there is a path between every pair of different vertices.   Find the number of the edges that are not contained in any shortest path between any pair of different vertices.

Submission attempts (in order):
import heapq


def dijkstra(n, s, g):
    h = [(0, s)]
    heapq.heapify(h)
    cost = [float("Inf")] * (n + 1)  
    cost[s] = 0

    while h:
        c, v = heapq.heappop(h)
        if c > cost[v]:
            continue
        for d, u in g[v]:
            d_s_u = d + cost[v]
            if d_s_u < cost[u]:
                cost[u] = d_s_u
                heapq.heappush(h, (d_s_u, u))

    return cost


def main():
    n, m, *abc = map(int, open(0).read().split())
    g = [[] for _ in range(n + 1)]

    for a, b, c in zip(*[iter(abc)] * 3):
        g[a].append([c, b])
        g[b].append([c, a])

    ans = 0
    checkd = [[False] * (n + 1) for _ in range(n + 1)]
    for i in range(1, n + 1):
        cost = dijkstra(n, i, g)
        for j, k in g[i]:
            if checkd[i][j]:
                continue
            if j > cost[k]:
                ans += 1
            checkd[i][j] = True
            checkd[j][i] = True
    
    print(ans)


if __name__ == '__main__':
    main()


import heapq


def dijkstra(n, s, g):
    h = [(0, s)]
    heapq.heapify(h)
    cost = [float("Inf")] * (n + 1)  
    cost[s] = 0

    while h:
        c, v = heapq.heappop(h)
        if c > cost[v]:
            continue
        for d, u in g[v]:
            d_s_u = d + cost[v]
            if d_s_u < cost[u]:
                cost[u] = d_s_u
                heapq.heappush(h, (d_s_u, u))

    return cost


def main():
    n, m, *abc = map(int, open(0).read().split())
    g = [[] for _ in range(n + 1)]

    for a, b, c in zip(*[iter(abc)] * 3):
        g[a].append([c, b])
        g[b].append([c, a])

    ans = 0
    checked = [[False] * (n + 1) for _ in range(n + 1)]
    for i in range(1, n + 1):
        cost = dijkstra(n, i, g)
        for j, k in g[i]:
            if checked[i][k]:
                continue
            if j > cost[k]:
                ans += 1

            checked[i][k] = True
            checked[k][i] = True

    print(ans)


if __name__ == '__main__':
    main()


Verdicts: Runtime Error

Accepted
Problem: You are given an undirected connected weighted graph with N vertices and M edges that contains neither self-loops nor double edges.   The i-th (1≤i≤M) edge connects vertex a_i and vertex b_i with a distance of c_i.   Here, a _self-loop_ is an edge where a_i = b_i (1≤i≤M), and _double edges_ are two edges where (a_i,b_i)=(a_j,b_j) or (a_i,b_i)=(b_j,a_j) (1≤i<j≤M).   A _connected graph_ is a graph where there is a path between every pair of different vertices.   Find the number of the edges that are not contained in any shortest path between any pair of different vertices.

Submission attempts (in order):
#051_D
from heapq import heappop, heappush
inf = 10 ** 10
d = [[inf for _ in range(n)] for _ in range(n)]
for i in range(n):
    d[i][i] = 0
n, m = map(int, input().split())
edges = []
for _ in range(m):
    a, b, c = map(int, input().split())
    d[a-1][b-1] = c
    d[b-1][a-1] = c
    edges.append((a-1, b-1))

def warshall_floyd(d):
    for k in range(n):
        for i in range(n):
            for j in range(n):
                d[i][j] = min(d[i][j], d[i][k] + d[k][j])
                
warshall_floyd(d)

ans = 0
for u, v in edges:
    for i in range(n):
        if i == u or i == v:
            continue
        if d[u][i] + d[i][v] == d[u][v]:
            ans += 1
            break

print(ans)

#051_D
inf = 10 ** 10
n, m = map(int, input().split())
d = [[inf for _ in range(n)] for _ in range(n)]
for i in range(n):
    d[i][i] = 0
edges = []
for _ in range(m):
    a, b, c = map(int, input().split())
    d[a-1][b-1] = c
    d[b-1][a-1] = c
    edges.append((a-1, b-1, c))

def warshall_floyd(d):
    for k in range(n):
        for i in range(n):
            for j in range(n):
                d[i][j] = min(d[i][j], d[i][k] + d[k][j])
                
warshall_floyd(d)

ans = m
for u, v, c in edges:
    flg = False
    for i in range(n):
        if d[i][v] + c == d[i][u]:
            flg = True
    
    if flg:
        ans -= 1

print(ans)

Verdicts: Runtime Error

Accepted
Problem: You are given an undirected connected weighted graph with N vertices and M edges that contains neither self-loops nor double edges.   The i-th (1≤i≤M) edge connects vertex a_i and vertex b_i with a distance of c_i.   Here, a _self-loop_ is an edge where a_i = b_i (1≤i≤M), and _double edges_ are two edges where (a_i,b_i)=(a_j,b_j) or (a_i,b_i)=(b_j,a_j) (1≤i<j≤M).   A _connected graph_ is a graph where there is a path between every pair of different vertices.   Find the number of the edges that are not contained in any shortest path between any pair of different vertices.

Submission attempts (in order):
import math
#import numpy as np
import queue
from collections import deque,defaultdict
import heapq as hpq
from sys import stdin,setrecursionlimit
from scipy.sparse.csgraph import dijkstra
from scipy.sparse import csr_matrix
ipt = stdin.readline
setrecursionlimit(10**7)

def main():
    n,m = map(int,ipt().split())
    cos = []
    row = []
    col = []
    for _ in range(m):
        a,b,c = map(int,ipt().split())
        row.append(a-1)
        col.append(b-1)
        cos.append(c)
        cos.append(c)
    csr = csr_matrix((cos,(row,col)),shape=(n,n))
    d = dijkstra(csr,directed=False)
    ans = 0
    for i in range(m):
        csr = csr_matrix((cos[:i:]+cos[i+1::],(row[:i:]+row[i+1::],col[:i:]+col[i+1::])),shape=(n,n))
        di = dijkstra(csr)
        if (di == d).all():
            ans += 1
    print(ans)
    return

if __name__ == '__main__':
    main()


import math
#import numpy as np
import queue
from collections import deque,defaultdict
import heapq as hpq
from sys import stdin,setrecursionlimit
from scipy.sparse.csgraph import dijkstra
from scipy.sparse import csr_matrix
ipt = stdin.readline
setrecursionlimit(10**7)

def main():
    n,m = map(int,ipt().split())
    cos = []
    row = []
    col = []
    for _ in range(m):
        a,b,c = map(int,ipt().split())
        row.append(a-1)
        col.append(b-1)
        cos.append(c)
    csr = csr_matrix((cos,(row,col)),shape=(n,n))
    d = dijkstra(csr,directed=False)
    ans = 0
    for i in range(m):
        rwi = row[i]
        cli = col[i]
        csi = cos[i]
        dri = d[rwi]
        dci = d[cli]
        for j in range(n):
            if dri[j] + csi == dci[j]:
                break
            if j == n-1:
                ans += 1
    print(ans)
    return

if __name__ == '__main__':
    main()


Verdicts: Runtime Error

Accepted
Problem: You are given an undirected connected weighted graph with N vertices and M edges that contains neither self-loops nor double edges.   The i-th (1≤i≤M) edge connects vertex a_i and vertex b_i with a distance of c_i.   Here, a _self-loop_ is an edge where a_i = b_i (1≤i≤M), and _double edges_ are two edges where (a_i,b_i)=(a_j,b_j) or (a_i,b_i)=(b_j,a_j) (1≤i<j≤M).   A _connected graph_ is a graph where there is a path between every pair of different vertices.   Find the number of the edges that are not contained in any shortest path between any pair of different vertices.

Submission attempts (in order):
N,M=map(int,input().split())
Islands=[[] for i in range(N)]
Edge=[]
S=0
for i in range(M):
  a,b,c=map(int,input().split())
  Islands[a-1].append([b-1,c])
  Islands[b-1].append([a-1,c])
  Edge.append([a-1,b-1])
for m in range(M):
  a=Edge[m][0]
  b=Edge[m][1]
  for i in Islands[a]:
    if i[0]==b:
      c_m=i[1]
  List=[[a,-1]]
  for l in List:
    print(List)
    c=(-1)*(l[-1]+1)
    if l[-2]==b:
      if c_m>c:
        S+=1
        break
    else:        
      for n in Islands[l[-2]]:
        if n[0] in l:
          pass
        else:
          c+=n[1]
          List.append(l[0:-1]+[n[0],(-1)*(c+1)])
          
print(S)      

N,M=map(int,input().split())
Islands=[[] for i in range(N)]
Edge=[]
S=0
for i in range(M):
  a,b,c=map(int,input().split())
  Islands[a-1].append([b-1,c])
  Islands[b-1].append([a-1,c])
  Edge.append([a-1,b-1])
for m in range(M):
  a=Edge[m][0]
  b=Edge[m][1]
  for i in Islands[a]:
    if i[0]==b:
      c_m=i[1]
  List=[[a,0]]
  for l in List:
    print(m,List)
    c_base=l[-1]
    c=c_base
    if l[-2]==b:
      if c_m>c:
        S+=1
        break
    else:        
      for n in Islands[l[-2]]:
        if n[0] in l[0:-1]:
          pass
        else:
          c+=n[1]
          List.append(l[0:-1]+[n[0],c])  
          c=c_base
print(S-1)      
    

N,M=map(int,input().split())
Islands=[[] for i in range(N)]
Edge=[]
S=0
for i in range(M):
  a,b,c=map(int,input().split())
  Islands[a-1].append([b-1,c])
  Islands[b-1].append([a-1,c])
  Edge.append([a-1,b-1,c])
for m in range(M):
  a=Edge[m][0]
  b=Edge[m][1]
  c_m=Edge[m][2]
  List=[[a,0]]
  for l in List:
    c_base=l[-1]
    c=c_base
    if l[-2]==b:
      if c_m>c:
        S+=1
        break
    else:        
      for n in Islands[l[-2]]:
        if n[0] in l[0:-1]:
          pass
        else:
          c+=n[1]
          List.append(l[0:-1]+[n[0],c])  
          c=c_base
print(S-1)      

N,M=map(int,input().split())
Islands=[[10**9]*N for i in range(N)]
Edge=[]
S=0
for i in range(M):
  a,b,c=map(int,input().split())
  Islands[a-1][b-1]=c
  Islands[b-1][a-1]=c
  Edge.append([a-1,b-1,c])
for k in range(N):
  for i in range(N):
    for j in range(N):
      Islands[i][j]=min(Islands[i][j],Islands[i][k]+Islands[k][j])

ans=0
for a,b,c in Edge:
  if Islands[a][b]!=c:
    ans+=1
print(ans)

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: You are given an undirected connected weighted graph with N vertices and M edges that contains neither self-loops nor double edges.   The i-th (1≤i≤M) edge connects vertex a_i and vertex b_i with a distance of c_i.   Here, a _self-loop_ is an edge where a_i = b_i (1≤i≤M), and _double edges_ are two edges where (a_i,b_i)=(a_j,b_j) or (a_i,b_i)=(b_j,a_j) (1≤i<j≤M).   A _connected graph_ is a graph where there is a path between every pair of different vertices.   Find the number of the edges that are not contained in any shortest path between any pair of different vertices.

Submission attempts (in order):

N, M = map(int, input().split())


dic_edge_dist = {(i, j) : float("inf") for i in range(1, N + 1) for j in range(1, N + 1)}
for i in range(1, N + 1):
    dic_edge_dist[(i, i)] = 0

list_edge = []

def warshall_floyd(dic_edge_dist):
    dic_shortest_dist = dic_edge_dist.copy()
    for i in range(1, N + 1):
        for j in range(1, N + 1):
            for k in range(1, N + 1):
                dic_shortest_dist[(j, k)] = min(dic_shortest_dist[(j, k)], dic_shortest_dist[(j, i)] + dic_shortest_dist[(i, k)])
    return dic_shortest_dist


for _ in range(M):
    
    a, b, c = map(int, input().split())
    
    dic_edge_dist[(a, b)] = c
    dic_edge_dist[(b, a)] = c
    
    list_edge.append((min(a, b), max(a, b)))

dic_shortest_dist = warshall_floyd(dic_edge_dist)
    
edge_count = 0
for i, j in list_edge:
    for k in range(1, N + 1):
        if dic_shortest_dist[(k, i)] + dic_edge_dist[(i, j)] == dic_shortest_dist[(k, j)]:
            edge_count += 1
            print(i, j, k)
            break
        if dic_shortest_dist[(k, j)] + dic_edge_dist[(j, i)] == dic_shortest_dist[(k, i)]:
            edge_count += 1
            print(i, j, k)
            break

print(dic_edge_dist)
print(dic_shortest_dist)
print(len(list_edge) - edge_count)


N, M = map(int, input().split())


dic_edge_dist = {(i, j) : float("inf") for i in range(1, N + 1) for j in range(1, N + 1)}
for i in range(1, N + 1):
    dic_edge_dist[(i, i)] = 0

list_edge = []

def warshall_floyd(dic_edge_dist):
    dic_shortest_dist = dic_edge_dist.copy()
    for i in range(1, N + 1):
        for j in range(1, N + 1):
            for k in range(1, N + 1):
                dic_shortest_dist[(j, k)] = min(dic_shortest_dist[(j, k)], dic_shortest_dist[(j, i)] + dic_shortest_dist[(i, k)])
    return dic_shortest_dist


for _ in range(M):
    
    a, b, c = map(int, input().split())
    
    dic_edge_dist[(a, b)] = c
    dic_edge_dist[(b, a)] = c
    
    list_edge.append((min(a, b), max(a, b)))

dic_shortest_dist = warshall_floyd(dic_edge_dist)
    
edge_count = 0
for i, j in list_edge:
    for k in range(1, N + 1):
        if dic_shortest_dist[(k, i)] + dic_edge_dist[(i, j)] == dic_shortest_dist[(k, j)]:
            edge_count += 1
            break
        if dic_shortest_dist[(k, j)] + dic_edge_dist[(j, i)] == dic_shortest_dist[(k, i)]:
            edge_count += 1
            break

print(len(list_edge) - edge_count)

Verdicts: Wrong Answer

Accepted
Problem: You are given an undirected connected weighted graph with N vertices and M edges that contains neither self-loops nor double edges.   The i-th (1≤i≤M) edge connects vertex a_i and vertex b_i with a distance of c_i.   Here, a _self-loop_ is an edge where a_i = b_i (1≤i≤M), and _double edges_ are two edges where (a_i,b_i)=(a_j,b_j) or (a_i,b_i)=(b_j,a_j) (1≤i<j≤M).   A _connected graph_ is a graph where there is a path between every pair of different vertices.   Find the number of the edges that are not contained in any shortest path between any pair of different vertices.

Submission attempts (in order):
N,M=list(map(int,input().split()))
import numpy as np
from scipy.sparse.csgraph import floyd_warshall
from scipy.sparse import csr_matrix
l=[np.array([0]*N) for i in range(N)]
for i in range(M):
   tmp=(list(map(int,input().split())))
   l[tmp[0]-1][tmp[1]-1]=tmp[2]
   l[tmp[1]-1][tmp[0]-1]=tmp[2]
l2=csr_matrix(l)
l2=floyd_warshall(l2)
print(l,l2)
ans=0
for i in range(N):
   for j in range(i):
      if l[i][j] != l2[i][j] and l[i][j] != 0:
         ans+=1
print(ans)

N,M=list(map(int,input().split()))
import numpy as np
from scipy.sparse.csgraph import floyd_warshall
from scipy.sparse import csr_matrix
l=[np.array([0]*N) for i in range(N)]
for i in range(M):
   tmp=(list(map(int,input().split())))
   l[tmp[0]-1][tmp[1]-1]=tmp[2]
   l[tmp[1]-1][tmp[0]-1]=tmp[2]
l2=csr_matrix(l)
l2=floyd_warshall(l2)
ans=0
for i in range(N):
   for j in range(i):
      if l[i][j] != l2[i][j] and l[i][j] != 0:
         ans+=1
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: You are given an undirected connected weighted graph with N vertices and M edges that contains neither self-loops nor double edges.   The i-th (1≤i≤M) edge connects vertex a_i and vertex b_i with a distance of c_i.   Here, a _self-loop_ is an edge where a_i = b_i (1≤i≤M), and _double edges_ are two edges where (a_i,b_i)=(a_j,b_j) or (a_i,b_i)=(b_j,a_j) (1≤i<j≤M).   A _connected graph_ is a graph where there is a path between every pair of different vertices.   Find the number of the edges that are not contained in any shortest path between any pair of different vertices.

Submission attempts (in order):

V, E=map(int,input().strip().split(' '))
inf=10**9
cost=[[inf]*V for i in range(V)]
edge=[]
for i in range(E):
    fr, to, co=map(int,input().strip().split(' '))
    cost[fr-1][to-1]=co
    cost[to-1][fr-1]=co
    edge.append([fr-1,to-1])
    
d=[]
for i in range(V):
    d.append(dijkstra(i))

cand=E
for i in range(E):
    fl=False
    for j in range(V):
        for k in range(V):
            if d[j][edge[i][0]]==cost[edge[i][0]][edge[i][1]]+d[k][edge[i][1]]:
                cand-=1
                fl=True
                break
        if fl:
            break

print(cand)

def dijkstra(s):
    d=[inf]*V
    used=[False]*V
    d[s]=0
    while True:
        v=-1
        for u in range(V):
            if used[u]==False and(v==-1 or d[u]<d[v]):
                v=u
        if v==-1:
            break
        used[v]=True
        for u in range(V):
            d[u]=min(d[u],d[v]+cost[v][u])
    return d




def dijkstra(s):
    d=[inf]*V
    used=[False]*V
    d[s]=0
    while True:
        v=-1
        for u in range(V):
            if used[u]==False and(v==-1 or d[u]<d[v]):
                v=u
        if v==-1:
            break
        used[v]=True
        for u in range(V):
            d[u]=min(d[u],d[v]+cost[v][u])
    return d



V, E=map(int,input().strip().split(' '))
inf=10**9
cost=[[inf]*V for i in range(V)]
edge=[]
for i in range(E):
    fr, to, co=map(int,input().strip().split(' '))
    cost[fr-1][to-1]=co
    cost[to-1][fr-1]=co
    edge.append([fr-1,to-1])
    
d=[]
for i in range(V):
    d.append(dijkstra(i))

cand=E
for i in range(E):
    fl=False
    for s in range(V):
        if d[s][edge[i][0]]+cost[edge[i][0]][edge[i][1]]==d[s][edge[i][1]]:
            cand-=1
            fl=True
            break

print(cand)

Verdicts: Runtime Error

Accepted
Problem: You are given an undirected connected weighted graph with N vertices and M edges that contains neither self-loops nor double edges.   The i-th (1≤i≤M) edge connects vertex a_i and vertex b_i with a distance of c_i.   Here, a _self-loop_ is an edge where a_i = b_i (1≤i≤M), and _double edges_ are two edges where (a_i,b_i)=(a_j,b_j) or (a_i,b_i)=(b_j,a_j) (1≤i<j≤M).   A _connected graph_ is a graph where there is a path between every pair of different vertices.   Find the number of the edges that are not contained in any shortest path between any pair of different vertices.

Submission attempts (in order):
n, m = list(map(int, input().split()))
connect = {}
dist = {}
for _ in range(m):
    a, b, c = list(map(int, input().split()))
    if not a in connect.keys(): connect[a] = [b]
    else: connect[a].append(b)
    if not b in connect.keys(): connect[b] = [a]
    else: connect[b].append(a)
    
    dist[tuple(sorted([a, b]))] = c

ans = 0
for s in range(1, n):
    for t in range(s+1, n+1):
        if not (s, t) in dist.keys():
            continue
        
        dists = [1000]*(n+1)
        dists[s] = 0
        stack = [(s, sc) for sc in connect[s]]
        while len(stack) > 0:
            s0, s1 = stack[0]
            stack = stack[1:]
            if dists[s0]+dist[tuple(sorted((s0, s1)))] >= dists[s1]:
                continue
            else:
                dists[s1] = dists[s0]+dist[tuple(sorted((s0, s1)))]
                for s2 in connect[s1]:
                    stack.append((s1, s2))
        print(dists)
        if dists[t] < dist[(s, t)]:
            ans += 1

print(ans)

n, m = list(map(int, input().split()))
dist_given = {}
dist = [[1000]*(n+1) for _ in range(n+1)]
for i in range(1, n+1): dist[i][i] = 0
for _ in range(m):
    a, b, c = list(map(int, input().split()))
    dist[a][b] = c
    dist[b][a] = c
    dist_given[tuple(sorted([a, b]))] = c

for k in range(1, n+1):
    for i in range(1, n+1):
        for j in range(1, n+1):
            dist[i][j] = min(dist[i][j], dist[i][k]+dist[k][j])
# print(dist)
ans = 0
for i in range(1, n):
    for j in range(i+1, n+1):
        if (i, j) in dist_given.keys() and dist[i][j] < dist_given[(i, j)]:
            ans += 1
print(ans)

Verdicts: Wrong Answer

Accepted