TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
# coding: utf8

if __name__ == "__main__":
    n = int(input())
    w = []
    flag = True
    for _ in range(n):
        a = input()
        last = w[len(w)-1]
        if a[0] != last[len(last)-1] and a in w:
            flag = False
            print("No")
            break
        w.append(a)
    if flag == True:
        print("Yes")



# coding: utf8

n = int(input())
w = []
flag = True
for _ in range(n):
    a = input()
    last = w[len(w)-1]
    if a[0] != last[len(last)-1] and a in w:
        flag = False
        print("No")
        break
    w.append(a)
if flag == True:
    print("Yes")



# coding: utf8

if __name__ == "__main__":
    n = int(input())
    w = []
    flag = True
    for _ in range(n):
        a = input()
        if len(w) == 0:
            continue
        last = w[len(w)-1]
        if a[0] != last[len(last)-1] or a in w:
            flag = False
            print("No")
            break
        w.append(a)
    if flag == True:
        print("Yes")



# coding: utf8

if __name__ == "__main__":
    n = int(input())
    w = []
    flag = True
    for _ in range(n):
        a = input()
        if len(w) == 0:
            continue
        last = w[len(w)-1]
        if a[0] != last[len(last)-1] and a in w:
            flag = False
            print("No")
            break
        w.append(a)
    if flag == True:
        print("Yes")



# coding: utf8

if __name__ == "__main__":
    n = int(input())
    w = []
    flag = True
    for _ in range(n):
        a = input()
        if len(w) == 0:
            w.append(a)
            continue
        last = w[len(w)-1]
        if a[0] != last[len(last)-1] or a in w:
            flag = False
            break
        w.append(a)
    if flag == True:
        print("Yes")
    else:
        print("No")



Verdicts: Runtime Error

Runtime Error

Wrong Answer

Wrong Answer

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
N = int(input())
w_list = ""
is_cor = True
for i in range(N):
  w_list[i] = input()
a = w_list[0]
for i in range(1, N-1):
  b = w_list
  b[i] = 0
  if a[len(a)-1] != w_list[i][0] or w_list[i] in b:
    print("No")
    is_cor = False
    break
if is_cor:
  print("Yes")

N = int(input())
w_list = [""]*N
is_cor = True
for i in range(N):
  w_list[i] = input()
for i in range(N-1):
  b = w_list.copy()
  b[i] = ""
  if w_list[i][len(w_list[i])-1] != w_list[i+1][0] or w_list[i] in b:
    print("No")
    is_cor = False
    break
if is_cor:
  print("Yes")

Verdicts: Runtime Error

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
N = int(input())
word_list = []
for i in range(N):
    w = str(input())
    if w not in word_list:
        word_list.append(w)
    elif w in word_list:
        print('No')
        break
        
    if i == 0:
        continue
    else:
        if w[0] == word_list[i-1][-1]:
            print('Yes')
        else:
            print('No')
            break

N = int(input())
word_list = []
yes_or_no = []
for i in range(N):
    w = str(input())
    if w not in word_list:
        word_list.append(w)
    elif w in word_list:
        yes_or_no.append('No')
        
    if i == 0:
        continue
    else:
        if w[0] == word_list[i-1][-1]:
            yes_or_no.append('Yes')
        else:
            yes_or_no.append('No')
if 'No' in yes_or_no:
    print('No')
else:
    print('Yes')

Verdicts: Wrong Answer

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
word_num = int(input())

word_list=[]
for i in range(word_num):
  word_list.append(str(input()))

# print(word_list)
temp = 0
for item in word_list:
  initial_word = item[0]
  last_word = item[-1]
  if(temp != initial_word and temp != 0):
      print("No")
      exit()
  temp = last_word
  # print("Ok")
print("Yes")


def is_unique(seq):
    return len(seq) == len(set(seq))

word_num = int(input())

word_list=[]
for i in range(word_num):
  word_list.append(str(input()))
  if(is_unique(word_list) == False):
      print("No")
      exit()



# print(word_list)
temp = 0
for item in word_list:
  initial_word = item[0]
  last_word = item[-1]
  if(temp != initial_word and temp != 0):
      print("No")
      exit()
  temp = last_word
  # print("Ok")
print("Yes")


Verdicts: Wrong Answer

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
    w=[input() for _ in range(n)]
    chk=[]
    chk.append(w[0])
    ans='Yes'
    for i in range(1,n):
        if w[i-1][-1]!=w[i][0] or (w[i] in chk):
            ans='No'
            break
        chk.append(w[i])
    print(ans)

if __name__ == '__main__':
    resolve()

def resolve():
    n=int(input())
    w=[input() for _ in range(n)]
    chk=[]
    chk.append(w[0])
    ans='Yes'
    for i in range(1,n):
        if w[i-1][-1]!=w[i][0] or (w[i] in chk):
            ans='No'
            break
        chk.append(w[i])
    print(ans)

if __name__ == '__main__':
    resolve()

Verdicts: Runtime Error

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
args = input().split("\n")
count = args[0]
words = [word for word in args[1:]]
result = "Yes"
if len(words) == len(list(set(words))):
  for i in range(len(words)-1):
    if words[i][-1] != words[i+1][0]:
    	result = "No"
else:
  result = "No"
print(result)




args = input().split("\n")
count = args[0]
words = [word for word in args[1:]]
result = "Yes"
if len(words) == len(list(set(words))):
  for i in range(len(words)-1):
    if words[i] != words[i+1]:
    	result = "No"
else:
  result = "No"
print(result)




N = int(input())
Ws = [input() for i in range(N)]

if len(Ws) != len(list(set(Ws))):
    print("No")
    exit(0)

for i in range(N-1):
    if Ws[i][-1] != Ws[i+1][0]:
        print("No")
        exit(0)

print("Yes")


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
import os
import sys
from collections import defaultdict, Counter, deque
from itertools import product, permutations,combinations, accumulate
from operator import itemgetter
from bisect import bisect_left,bisect
from heapq import heappop,heappush,heapify
from math import ceil, floor, sqrt
from copy import deepcopy


def main():
    n = int(input())
    vectoer = []
    flag = True
    for i in range(n):
        s = input()
        vectoer.append(s)

    if len(vectoer) != len(set(vectoer)):
        flag = False

    print(n)
    for i in range(n-1):
        if vectoer[i][-1] !=  vectoer[i+1][0]:
            flag = False
            break

    if flag:
        print("Yes")
    else:
        print("No")
    

if __name__ == '__main__':
	main()


import os
import sys
from collections import defaultdict, Counter, deque
from itertools import product, permutations,combinations, accumulate
from operator import itemgetter
from bisect import bisect_left,bisect
from heapq import heappop,heappush,heapify
from math import ceil, floor, sqrt
from copy import deepcopy


def main():
    n = int(input())
    vectoer = []
    flag = True
    for i in range(n):
        s = input()
        vectoer.append(s)

    if len(vectoer) != len(set(vectoer)):
        flag = False
        
    for i in range(n-1):
        if vectoer[i][-1] !=  vectoer[i+1][0]:
            flag = False
            break

    if flag:
        print("Yes")
    else:
        print("No")
    

if __name__ == '__main__':
	main()


Verdicts: Wrong Answer

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
# -*- coding: utf-8 -*-
N = int(input())
a = [input() for i in range(N)]
for i in range(N):
  if a[i][len(a[i])]==a[i+1][0]:
    continue
  else:
    break
    print("No")
print("Yes")

# -*- coding: utf-8 -*-
N = int(input())
a = [input() for i in range(N)]
for i in range(N):
  if a[i][len(a[i])]=a[i+1][0]:
    continue
  else:
    break
    print("No")
print("Yes")
    

N = int(input())
W = []
for i in range(N):
    W.append(str(input()))
ans = "No"
startwith = []
endwith = []
if len(set(W)) == len(W):
   for i in W:
       startwith.append(i[0])
       endwith.append(i[-1])
   startwith.pop(0)
   endwith.pop(-1)
   if startwith == endwith:
    ans = "Yes"

print(ans)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
n=int(input())
w=[]
ws=[]
count=1
for i in range(n):
    w.append(input())
    ws.append(list(w[i]))
for i in range(n):
    if (w.count(w[i]))>1:
        count-=1
for j in range(n-1):
    if (ws[j][len(w[j])-1])==(ws[j+1][0]):
        count+=1
if count==(n):
    print('Yes')
else:
    print('N0')

n=int(input())
w=[]
ws=[]
count=1
for i in range(n):
    w.append(input())
    ws.append(list(w[i]))
for i in range(n):
    if (w.count(w[i]))>1:
        count-=1
for j in range(n-1):
    if (ws[j][len(w[j])-1])==(ws[j+1][0]):
        count+=1
if count==int(n):
    print('Yes')
else:
    print('No')

Verdicts: Wrong Answer

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
import collections
n = int(input())
k = []
result=[]
for i in range(n):
    a = input()
    k.append(a)
ans = collections.Counter(k)
for i in range(1,n):
    if k[i-1][-1] == k[i][0] and ans.most_common()[0][1] == 1:
        result.append("1")
    else:
        result.append("0")
print(result)
aim = collections.Counter(result)
print(aim.most_common()[0][1])
if aim.most_common()[0][1] != n-1 or aim.most_common()[0][0] =='0':
    print('No')
else:
    print('Yes')

import collections
n = int(input())
k = []
result=[]
for i in range(n):
    a = input()
    k.append(a)
ans = collections.Counter(k)
for i in range(1,n):
    if k[i-1][-1] == k[i][0] and ans.most_common()[0][1] == 1:
        result.append("1")
    else:
        result.append("0")
aim = collections.Counter(result)
if aim.most_common()[0][1] != n-1 or aim.most_common()[0][0] =='0':
    print('No')
else:
    print('Yes')


Verdicts: Wrong Answer

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
N = int(input())
W = {}
last=""
flg = True

w =[]

for i in range(N):
    w.append(str(input()))
    
    
for i in w:
    temp = i
    
    if temp in W:
        flg = False
        break
    else:
        W[temp] = 1
        
    if i !=0:
        if temp[0] == last:
            last  = temp[-1]
        else:
            flg = False
            break
    else:
        last = temp[-1]
            
            
            
if(flg == True):
    print("Yes")
else:
    print("No",last)
        

N = int(input())
W = {}
last=""
flg = True

for i in range(N):
    temp = str(input())
    
    if temp in W:
        flg = False
        break
    else:
        W[temp] = 1
        
    if i !=0:
        if temp[0] == last:
            last  = temp[-1]
        else:
            flg = False
            break
    else:
        last = temp[-1]
            
            
            
if(flg == True):
    print("Yes")
else:
    print("No",last)

N = int(input())
W = {}
last=""
flg = True

w =[]

for i in range(N):
    w.append(str(input()))
    
cnt=0
for i in w:
    
    if i in W:
        flg = False
        break
    else:
        W[i] = 1
        
    if cnt !=0:
        if i[0] == last:
            last = i[-1]
        else:
            flg = False
            break
    else:
        last = i[-1]
            
    cnt+=1
        
if(flg == True):
    print("Yes")
else:
    print("No")
        

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
n = int(input())
a = []
flag = 1
before = ""
for i in range(n):
    a1 = input()

    if i == 0:
        before = a1[len(a1)-1]
        continue
    if before != a1[0]:
        flag = 0
    before = a1[len(a1)-1]
if flag==0:
    print("No")
else:
    print("Yes")

n = int(input())
a = []
flag = 1
before = ""
def is_unique(seq):
    return len(seq) == len(set(seq))
for i in range(n):
    a1 = input()
    a.append(a1)
    if i == 0:
        before = a1[len(a1)-1]
        continue
    if before != a1[0]:
        flag = 0
    before = a1[len(a1)-1]
if is_unique(a) == False:
    flag = 0
if flag==0:
    print("No")
else:
    print("Yes")

Verdicts: Wrong Answer

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
n = input()
w = []
Flag = Trure 
for i in range(n):
  w.append(input())
for i in range(n-1):
  if w[i][-1] != w[i+1][0]:
    Flag = False
if len(w) = len(set(w)):
  Flag = False
print("Yes" if Flag else "No")

n = int(input())
w = []
Flag = True 
for i in range(n):
  w.append(input())
for i in range(n-1):
  if w[i][-1] != w[i+1][0]:
    Flag = False
if len(w) != len(set(w)):
  Flag = False
print("Yes" if Flag else "No")

Verdicts: Runtime Error

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
n = int(input())
w = [input().rsprit() for i in range(n)]
use = [w[0]]
for i in range(1,n):
  if w[i][0] == w[i-1][-1] and w[i] not in use:
    use.append(w[i])
  else:
    print('No')
    exit()
print('Yes')

n = int(input())
w = [input().rstrip() for i in range(n)]
use = [w[0]]
for i in range(1,n):
  if w[i][0] == w[i-1][-1] and w[i] not in use:
    use.append(w[i])
  else:
    print('No')
    exit()
print('Yes')

Verdicts: Runtime Error

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
N = int(input())
S = []
for i in range(N):
    S.append(input())



www = "YYY"
for i in range(N-2):

    if S[i][-1] != S[i+1][0]:
        www = "fuck"


qqq = "ZZZ"
S.sort()
for i in range(N-2):
    if S[i] == S[i+1]:
        qqq = "bich"

if www == "YYY" and qqq == "ZZZ":
    print("Yes")
else:
    print("No")


N = int(input())
S = []
for i in range(N):
    S.append(input())



www = "YYY"
for i in range(N-1):
    if S[i][-1] != S[i+1][0]:
        www = "fuck"

qqq = "ZZZ"
S.sort()
for i in range(N-1):
    if S[i] == S[i+1]:
        qqq = "bich"

if www == "YYY" and qqq == "ZZZ":
    print("Yes")
else:
    print("No")


Verdicts: Wrong Answer

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
n=int(input())
ww=[input() for i in range(n)]

if len(set(ww))==n:
    print('No')
else:
    for i in range(1,n):
        if ww[i-1][-1] != ww[i][0]:
            print('No')
            break
    else:
        print('Yes')

n = int(input())

ww = [input() for _ in range(n)]
# print(ww)

for i,w in enumerate(ww[:-1]):
    if ww[i][-1] != ww[i+1][0] or ww.count(w)>1:
        print('No')
        # print(w)
        break
else:
    print('Yes')

Verdicts: Wrong Answer

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
n=int(input())
a=[]
x=str(input())
a[0]=x
d=bool(True)
for i in range(1, n):
  y=str(input)
  if x[len(x)]!=y[0]:
    d=False
  for i in range(a.size()):
    if y==a[i]:
      d=False
  a.append(y)

if  d:
  print("Yes")
else:
  print("No")

n=int(input())
a=[]
x=str(input())
a.append(x)
d=bool(True)

for i in range(1, n):
  y=str(input())
  if x[len(x)-1]!=y[0]:
    d=False
    
  for j in range(len(a)):
    if y==a[j]:
      d=False
  a.append(y)
  x=y

if  d==True:
  print("Yes")
else:
  print("No")

Verdicts: Runtime Error

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
count = input()
inputed = []
last = ""
judge = "Yes"
for i in range(int(count)):
    new_inputed = input()
    if i != 0 and (new_inputed[0] != last or new_inputed in inputed):
        judge = "No"
        print(last, new_inputed[-1], new_inputed in inputed)
    last = new_inputed[-1]
    inputed.append(new_inputed)
print(judge)

count = input()
inputed = []
last = ""
judge = "Yes"
for i in range(int(count)):
    new_inputed = input()
    if i != 0 and (new_inputed[0] != last or new_inputed in inputed):
        judge = "No"
    last = new_inputed[-1]
    inputed.append(new_inputed)
print(judge)

Verdicts: Wrong Answer

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
n=int(input())
S=[input() for _ in range(n)]
ans=0
for i in range(n-1):
    if S[i][-1] != S[i+1][0]:
        ans = 1
        break
print("Yes" if ans == 0 else "No")

n=int(input())
S=[input() for _ in range(n)]
ans=1
for i in range(n-1):
    if S[i][-1] == S[i+1][0]:
        ans += 1
print("Yes" if ans == n else "No")

n=int(input())
S=[input() for _ in range(n)]
ans=1
for i in range(n-1):
    if (S[i][-1] == S[i+1][0])*(S[i+1] not in S[:i+1]):
        ans += 1
print("Yes" if ans == n else "No")

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
N=int(input())
last = input()
wds = set([last])
for i in range(N-1):
    wd = input()
    if wd in wds or last[-1]!=wd[0]: 
        print('No')
        break
    last = wd
    wds.add(wd)
print('Yes')

N=int(input())
last = input()
wds = set([last])
for i in range(N-1):
    print(i)
    wd = input()
    if wd in wds or last[-1]!=wd[0]: 
        print('No')
        break
    last = wd
    wds.add(wd)
print('Yes')

N=int(input())
last = input()
wds = set([last])
res = "Yes"
for i in range(N-1):
    wd = input()
    if wd in wds or last[-1]!=wd[0]: 
        res = "No"
        break
    last = wd
    wds.add(wd)
print(res)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
import sys
n = int(input())
words = input().split()
for i in range(n-1)
    for j in range(1, i):
        if words[i] == words[j]:
                print('No')
                sys.exit()
    if words[i][-1] != words[i+1][1]:
        print('No')
        sys.exit()
print('Yes')

import sys
n = int(input())
words=[]
for i in range(n):
	words += [input()]
for i in range(n-1):
	for j in range(i+1, n):
		if words[i] == words[j]:
			print('No')
			sys.exit()
	if words[i][-1] != words[i+1][0]:
		print('No')
		sys.exit()
print('Yes')

Verdicts: Runtime Error

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
N = int(input())
flag = False
dic = []

word = input()
dic.append(word)

for i in range(N-1):
    word = input()
    if(word not in dic and word[0] == dic[-1][-1]):
        dic.append(word)
    else:
        flag = True
        break
if(flag == True):
    print('NO')
else:
    print('YES')

N = int(input())
flag = False
dic = []

word = input()
dic.append(word)

for i in range(N-1):
    word = input()
    if(word not in dic and word[0] == dic[-1][-1]):
        dic.append(word)
    else:
        flag = True
        break
if(flag == True):
    print('No')
else:
    print('Yes')

Verdicts: Wrong Answer

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
n=int(input())
w=[input() for i in range(n)]    
count=0
if len(set(w))<len(w):
    print('No')
else:
    for i in range(n-1):
        if w[i][-1]==w[i+1][0]:
            count+=1
    if count==n-1:
        print('Yes')
    else:
        print('No')
print(count)

n=int(input())
w=[input() for i in range(n)]    
count=0
if len(set(w))<len(w):
    print('No')
else:
    for i in range(n-1):
        if w[i][-1]==w[i+1][0]:
            count+=1
    if count==n-1:
        print('Yes')
    else:
        print('No')

Verdicts: Wrong Answer

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
n = int(input())
lst = [iuput() for _ in range(n-1)]
lstset = set(lst)
if len(lst) != len(lstset):
    print("No")
else:
    cnt = 0
    for i in range(n-1):
        if lst[i][-1] == lst[i][0]:
            cnt += 1
        else:
            break
    if cnt == len(lst):
        print('Yes')
    else:
        print('No')
    

n = int(input())
lst = [input() for _ in range(n)]
lstset = set(lst)

if len(lst) != len(lstset):
    print("No")
else:
    cnt = 0
    for i in range(n-1):
        if lst[i][-1] == lst[i + 1][0]:
            cnt += 1
        else:
            break
    if cnt + 1 == len(lst):
        print('Yes')
    else:

n = int(input())
lst = [input() for _ in range(n)]
lstset = set(lst)

if len(lst) != len(lstset):
    print("No")
else:
    cnt = 0
    for i in range(n-1):
        if lst[i][-1] == lst[i + 1][0]:
            cnt += 1
        else:
            break
    if cnt + 1 == len(lst):
        print('Yes')
    else:
        print('No')

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
N = int(input())
W = [input() for i in range(N)]

word_stock = []

for word in W:
    
    if word in word_stock:
        print('No')
    
    try:
        if word_stock[-1][-1] != word[0]:
            print('No')
    except:
        pass
    word_stock.append(word)

print('Yes')

for word in word_list:
    
    if word in word_stock:
        print('No')
    
    try:
        if word_stock[-1][-1] != word[0]:
            print('No')
    except:
        pass
    word_stock.append(word)

print('Yes')

N = int(input())
W = [input() for i in range(N)]

word_stock = []

for word in word_list:
    
    if word in word_stock:
        print('No')
    
    try:
        if word_stock[-1][-1] != word[0]:
            print('No')
    except:
        pass
    word_stock.append(word)

print('Yes')

N = int(input())
W = [input() for i in range(N)]

for word in word_list:
    
    if word in word_stock:
        print('No')
    
    try:
        if word_stock[-1][-1] != word[0]:
            print('No')
    except:
        pass
    word_stock.append(word)

print('Yes')

N = int(input())
W = [input() for i in range(N)]

stock = []
last = W[0][0]

for i in range(0,len(W)):
    
    if W[i] in stock:
        print('No')
        break
    
    if W[i][0] != last:
        print('No')
        break
    stock.append(W[i])
    last = W[i][-1]
    
    if i+1 == len(W):
        print('Yes')

Verdicts: Wrong Answer

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
def si():

    n = int(input()) 
    tk = [input() for i in range(n)]
    tu = len(set(tk))
    l =[]
    k = []

 
        
    oo = 0


    while oo < tu:
        t = tk[oo]
        l.append(t[0])
        k.append(t[-1])
        oo += 1
        
    oo = 0


    while oo < tu-1:
        if k[oo] != l[oo+1]:
            return False
        
        oo += 1


    if tu != n:
        print(tu)
        print(n)
        
        return False
    
    return True
    
if si():
    print("Yes")
else:
    print("No")

def si():

    n = int(input()) 
    tk = [input() for i in range(n)]
    tu = len(set(tk))
    l =[]
    k = []

 
        
    oo = 0


    while oo < tu:
        t = tk[oo]
        l.append(t[0])
        k.append(t[-1])
        oo += 1
        
    oo = 0


    while oo < tu-1:
        if k[oo] != l[oo+1]:
            return False
        
        oo += 1


    if tu != n:
        return False
    
    return True
    
if si():
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
def check_words(w):
    if len(w) != len(set(w)):
        return False
    for i in range(n-1):
        if w[i][-1] != w[i+1][0]:
            return False
    return True

n = int(input())
w = list(map(str, input().split()))
ret = 'Yes' if check_words(w) else 'No'
print(ret)

n = int(input())
w = list(map(str, input().split()))
ret = 'Yes'
if len(w) == len(set(w)):
    for i in range(len(w)-1):
        if w[i][-1] != w[i+1][0]:
            ret = 'No'
            break
else:
    ret = 'No'
print(ret)

def check_words(w):
    if len(w) != len(set(w)):
        return False
    for i in range(n-1):
        if w[i][-1] != w[i+1][0]:
            return False
    return True

n = int(input())
w = list(map(str, input().split()))
if check_words(w):
    ret = 'Yes'
else:
    ret = 'No'
print(ret)

n = int(input())
w = [input() for i in range(N)]

if n != len(set(w)):
    print('No')
    exit()
for i in range(n-1):
    if w[i][-1] != w[i+1][0]:
        print('No')
        exit()

print('Yes')

def check_words(w):
    if len(w) != len(set(w)):
        return False
    for i in range(n-1):
        if w[i][-1] != w[i+1][0]:
            return False
    return True

n = int(input())
w = list(map(str, input().split()))
ret = 'Yes' if check_words(w) else 'No'
print(ret)

n = int(input())
w = [input() for i in range(n)]

if n != len(set(w)):
    print('No')
    exit()
for i in range(n-1):
    if w[i][-1] != w[i+1][0]:
        print('No')
        exit()

print('Yes')

Verdicts: Runtime Error

Wrong Answer

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
n = int(input())
result = "Yes"
w = list(input())
for i in range(n - 1):
  s = input()
  if s in w:
    result = "No"
  elif s[0] != w[-1][-1]:
    result = "No"
  else:
    w.append(s)
print(result)

n = int(input())
result = "Yes"
w = list(input())
for i in range(n - 1):
  s = input()
  if s in w:
    result = "No"
    break
  elif s[0] != w[-1][-1]:
    result = "No"
    break
  else:
    w.append(s)
print(result)

n = int(input())
result = "Yes"
w = []
s = input()
w.append(s)
for i in range(n - 1):
  s = input()
  if s in w:
    result = "No"
    break
  elif s[0] != w[-1][-1]:
    result = "No"
    break
  else:
    w.append(s)
print(result)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
from sys import stdin
import fractions

n = int(stdin.readline().rstrip())

li = [stdin.readline().rstrip() for _ in range(n)]
k = len(li)
lin = list(set(li))

if len(li) != k:
    print("No")
    exit()

for i in range(len(li)-1):
    if li[i][-1] != li[i+1][0]:
        print("No")
        exit()
print("Yes")


from sys import stdin
import fractions

n = int(stdin.readline().rstrip())

li = [stdin.readline().rstrip() for _ in range(n)]
k = len(li)
lin = list(set(li))

if len(lin) != k:
    print("No")
    exit()

for i in range(len(li)-1):
    if li[i][-1] != li[i+1][0]:
        print("No")
        exit()
print("Yes")


Verdicts: Wrong Answer

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
# Shiritori
n = int(input())
li = []
for i in range(n):
    li.append(list(input()))
for j in range(n):
    if li[j][-1] != li[j+1][0]:
        print('No1')
        exit()
    for k in range(j):
        if li[j] == li[k]:
            print('No2')
            exit()
print('Yes')


# Shiritori
n = int(input())
li = []
for i in range(n):
    li.append(list(input()))
for j in range(n-1):
    if li[j][-1] != li[j+1][0]:
        print('No1')
        exit()
    for k in range(j):
        if li[j] == li[k]:
            print('No2')
            exit()
print('Yes')


# Shiritori
n = int(input())
li = []
for i in range(n):
    li.append(list(input()))
for j in range(n-1):
    if li[j][-1] == li[j+1][0]:
        for k in range(j):
            if li[j] == li[k] or li[-1] == li[k]:
                print('No')
                exit()
    else:
        print('No')
        exit()
print('Yes')


Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: Takahashi is practicing _shiritori_ alone again today.  Shiritori is a game as follows:    * In the first turn, a player announces any one word.   * In the subsequent turns, a player announces a word that satisfies the following conditions:     * That word is not announced before.     * The first character of that word is the same as the last character of the last word announced.  In this game, he is practicing to announce as many words as possible in ten seconds.  You are given the number of words Takahashi announced, N, and the i-th word he announced, W_i, for each i. Determine if the rules of shiritori was observed, that is, every word announced by him satisfied the conditions.

Submission attempts (in order):
N = int(input())

W = [input() for w in range(N)]

for i in range(1,len(W)):
  if (W[i-1][-1] != W[i][0]) or (W[i] in W[:i] == True):
    print("No")
    break
else:print("Yes")

N = int(input())

W = [input() for w in range(N)]

for i in range(1,len(W)):
  if (W[i-1][-1] != W[i][0]) or (W[i] in W[:i]):
    print("No")
    break
else:print("Yes")

Verdicts: Wrong Answer

Accepted