TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
n,a,b,c,d=map(int,input().split());s=input();print('YNeos'[not'...'in s[b-2:d+1]or'##'in s[a:d]::2])

n,a,b,c,d=map(int,input().split())
s=input()
f=0;F=0
for i in range(a,max(c,d)-1):
  if s[i]=='#' and s[i+1]=='#':f=1
for i in range(b-2,d-1):
  if s[i]=='.' and s[i+1]=='.' and s[i+2]=='.':F=1
if F==0 and c>d:f=1
print('YNeos'[f::2])

n,a,b,c,d=map(int,input().split())
s=list(input())
if c<d:
  f=0
  for i in range(b,d-1):
    if s[i]=='#' and s[i+1]=='#':
      f==1
      break
  if f==0:
    for i in range(a,c-1):
      if s[i]=='#' and s[i+1]=='#':
        f=1
  if f==1:print('No')
  else:print('Yes')
else:
  f=0
  for i in range(b,d-1):
    if s[i]=='#' and s[i+1]=='#':
      f=1
      break
  if f==1:
    print('No')
  else:
    for i in range(a,c-1):
      if s[i]=='#' and s[i+1]=='#':
        f=1
        break
    if f==1:
      print('No')
    else:
      if s[d-2]=='#' or s[d]=='#':
        ct=0
        for i in range(b,d-2):
          if s[i]=='.' and s[i+1]=='.' and s[i+2]=='.':
            ct=1
            break
        if ct==0:
          if s[b-2]=='#' or s[b]=='#':
          print('No')
        else:
          print('Yes')
      else:
        print('Yes')

n,a,b,c,d=map(int,input().split());s=input();print('YNeos'[not'...'*(d<c)in s[b-2:d+1]or'##'in s[a:d]::2])

Verdicts: Wrong Answer

Runtime Error

Runtime Error

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
n,a,b,c,d = map(int, input().split())
​
s = input()
​
​

if c > d:
  
  if s[a:].count("##") == 0:
    if s[b-1:d+1].count("...") >= 1:
      print("Yes")
    else:
      print("No")
  else:
    print("No")
else:
  if s[a:].count("##") == 0:
    print("Yes")
  else:
    print("No")


n,a,b,c,d = map(int, input().split())

s = input()


if c > d:
  
  if s[a:c].count("##") == 0 and s[b:d].count("##") == 0:
    if s[b-1:d+1].count("...") >= 1:
      print("Yes")
    else:
      print("No")
  else:
    print("No")
else:
  s[a:c].count("##") == 0 and s[b:d].count("##") == 0:
    print("Yes")
  else:
    print("No")

n,a,b,c,d = map(int, input().split())
a -= 1
b -= 1
s = input()
ans = "No"
snk = s[a:c].count("##")
fnk = s[b:d].count("##")
if snk == 0 and fnk == 0:
  if c > d:
    if s[b-1:d+1].count("...") >= 1:
      ans = "Yes"
  else:
    ans = "Yes"
    
print(ans)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
N,A,B,C,D=map(int,input().split())
S=input()
if C<D and B<C:
    for i in range(A-1,D-2):
        if S[i]=='#' and S[i+1]=='#':
            print('No')
            exit()
    print('Yes')
    exit()
elif C<D and B>C:
    for i in range(A-1,C-2):
        if S[i] == '#' and S[i + 1] == '#':
            print('No')
            exit()
    for p in range(B-1,D-2):
        if S[p] == '#' and S[p + 1] == '#':
            print('No')
            exit()
    print('Yes')
    exit()
elif C>D:
    for j in range(A-1,D-2):
        if S[j]=='#' and S[j+1]=='#':
            print('No')
            exit()
    if any(S[k-1]=='.' and S[k]=='.' and S[k+1]=='.' for k in range(B-1,D-1)):
        print('Yes')
        exit()
        
elif 
print('No')


N,A,B,C,D=map(int,input().split())
S=input()
if C<B and B<D:
    for i in range(A-1,C-1):
        if S[i] == '#' and S[i + 1] == '#':
            print('No')
            exit()
    for p in range(B-1,D-1):
        if S[p] == '#' and S[p + 1] == '#':
            print('No')
            exit()
    print('Yes')
    exit()
elif B<C and C<D:
    for i in range(A-1,D-1):
        if S[i]=='#' and S[i+1]=='#':
            print('No')
            exit()
    print('Yes')
    exit()
elif D<C:
    for j in range(A-1,C-1):
        if S[j]=='#' and S[j+1]=='#':
            print('No')
            exit()
    if any(S[k-1]=='.' and S[k]=='.' and S[k+1]=='.' for k in range(B-1,D)):
        print('Yes')
        exit()
print('No')


Verdicts: Runtime Error

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
N, A, B, C, D = [int(i) - 1 for i in input().strip().split(' ')]
N += 1
S = [c for c in input().strip()]


def get(a, b):
  s = S[:]
  s[a] = 'A'
  s[b] = 'B'

  return s


def check(s, i, dest):
  while i < dest:
    i += 1
    if i <= dest and s[i] == '.':
      continue
    i += 1
    if i <= dest and s[i] == '.':
      continue

    return False

  return i == dest


def move(s, i, dest):
  if i == dest:
    return -1

  while i < dest:
    i = i + 1
    if i + 1 < N:
      if s[i - 1] == '.' and s[i] == '.' and s[i + 1] == '.':
        return i

  return i if i == dest else -1


def main():
  a = A
  b = B

  for _ in range(1000):
    s = get(a, b)

    is_a = check(s, a, C)
    is_b = check(s, b, D)
    print((is_a, is_b), s)
    if is_a and is_b:
      return True

    if C > D:
      if is_a:
        a = C
      elif is_b:
        b = move(s, b, D)
      else:
        a = move(s, a, C)
    else:
      if is_b:
        b = D
      elif is_a:
        a = move(s, a, C)
      else:
        b = move(s, b, D)

    if a < 0 or b < 0:
      return False


print('Yes' if main() else 'No')

N, A, B, C, D = [int(i) - 1 for i in input().strip().split(' ')]
N += 1
S = [c for c in input().strip()]
S += '#'


def check(current, dest):
  i = current + 1
  while True:
    if i >= dest:
      return True
    elif S[i] == '.':
      i = i + 1
    elif S[i + 1] == '.':
      i = i + 2
    else:
      return False


def passable():
  i = B
  while True:
    if i > D:
      return False
    elif S[i - 1] == '.' and S[i] == '.' and S[i + 1] == '.':
      return True
    else:
      i = i + 1


def main():
  if D > C:
    return check(B, D) and check(A, C)
  else:
    return passable() and check(A, C)


print('Yes' if main() else 'No')

Verdicts: Wrong Answer

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
n,a,b,c,d = map(int,input().split())
s = input()

ans = "No"
if "##" in s[a-1:c] or "##" in s[b-1:d]: pass
else:
    
    l = list(s) ; l[d-1]="#" ; s2 = "".join(l)
    if "##" in s2[0:c]:
        
        if "..." in s[b:d-1]:
            s = s[0:b] + s[b:d].replace("...",".#.") + s[d:n]
            if s[c-1]=="
            else:
                l = list(s) ; l[c-1]="#" ; s3 = "".join(l)
                if "##" in s3[0:d]: pass
                else: ans = "Yes"
    else: ans = "Yes"


print(ans)


n,a,b,c,d = map(int,input().split())
s = input()

ans = "No"
if "##" in s[0:d] or "##" in s[0:c]: pass
else:
    
    l = list(s) ; l[d-1]="#" ; s2 = "".join(l)
    if "##" in s2[0:c]:
        
        if "..." in s[b:d-1]:
            s[b:d-1].replace("...",".#.")
            if s[c-1]=="
            else:
                l = list(s) ; l[c-1]="#" ; s3 = "".join(l)
                if "##" in s3[0:d]: pass
                else: ans = "Yes"
    else: ans = "Yes"


print(ans)


n,a,b,c,d = map(int,input().split())
s = input()

ans = "No"
if "##" in s[0:d] or "##" in s[0:c]: pass
else:
    
    l = list(s) ; l[d-1]="#" ; s2 = "".join(l)
    if "##" in s2[0:c]:
        
        if "..." in s[b:d-1]:
            s = s[0:b] + s[b:d].replace("...",".#.") + s[d:n]
            if s[c-1]=="
            else:
                l = list(s) ; l[c-1]="#" ; s3 = "".join(l)
                if "##" in s3[0:d]: pass
                else: ans = "Yes"
    else: ans = "Yes"


print(ans)


n,a,b,c,d = map(int,input().split())
s = input()

ans = "No"
if "##" in s[a-1:c] or "##" in s[b-1:d]: pass
else:
    if c<d: ans = "Yes"
    else:
        if "..." in s[b-2:d+1]: ans = "Yes"


print(ans)


Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
judge = True
if "##" in s[a - 1:c] or "##" in s[b - 1:d]:
    judge = False

if judge and c > d:
    if not "..." in s[b - 2:d + 1]:
        judge = False

print("Yes") if judge else print('No')    

n, a, b, c, d = map(int, input().split())
s = input()

judge = True
if "##" in s[a - 1:c] or "##" in s[b - 1:d]:
    judge = False

if judge and c > d:
    if not "..." in s[b - 2:d + 1]:
        judge = False

print("Yes") if judge else print('No')    

Verdicts: Runtime Error

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
N,A,B,C,D = map(int,input().split())
S = input()
sunuke = A
hunuke = B

def syori1(sunuke,hunuke):
    while hunuke<D:
        if hunuke+1 == N:
            return "YES"
        if S[hunuke+1] == ".":
            hunuke += 2
        elif S[hunuke] == ".":
            hunuke += 1
        else:
            return "NO"
    
    while sunuke<C:
        if sunuke + 1 == N:
            return "YES"
        if S[sunuke+1] == ".":
            sunuke += 2
        elif S[sunuke] == ".":
            sunuke += 1
        else:
            return "NO"
    
    return "YES"

def canover():
    for i in range(min(C,D)-2):
        if S[i] == "." and S[i+1] == "." and S[i+2]==".":
            return True
        else:
            pass
    return False

if C > D:
    if canover():
        print(syori1(sunuke,hunuke))
    else:
        print("NO")
else:
    print(syori1(sunuke,hunuke))
    

N,A,B,C,D = map(int,input().split())
S = input()
sunuke = A
hunuke = B

def syori1(sunuke,hunuke):
    while hunuke<D:
        if hunuke+1 == N:
            return "Yes"
        if S[hunuke+1] == ".":
            hunuke += 2
        elif S[hunuke] == ".":
            hunuke += 1
        else:
            return "No"
    
    while sunuke<C:
        if sunuke + 1 == N:
            return "Yes"
        if S[sunuke+1] == ".":
            sunuke += 2
        elif S[sunuke] == ".":
            sunuke += 1
        else:
            return "No"
    
    return "Yes"

def canover():
    for i in range(B-2,D-1):
        if S[i] == "." and S[i+1] == "." and S[i+2]==".":
            return True
        else:
            pass
    return False
    
def tonari():
    if S[B]==".":
        return True
    else:
        return False

if C > D:
    if A+1 == B:
        if tonari():
            print(syori1(sunuke,hunuke))
            exit()
            
    if canover():
        print(syori1(sunuke,hunuke))
    else:
        print("No")
else:
    print(syori1(sunuke,hunuke))

Verdicts: Wrong Answer

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
n,a,b,c,d = map(int,input().split())
s = input()
S = s[:max(c,d)]
print(S)
l = len(S)
C = True
D = False
for i in range(l-1):
  if i >= min(a,b) and S[i]=='#' and S[i+1]=='#':
    C = False
    break
  if c > d and d > i >= max(a,b)-1:
    if S[i-1]=='.' and S[i]=='.' and S[i+1]=='.':
      D = True
      
if not C:
  print('No')
elif C and not D:
  if c < d:
    print('Yes')
  else:
    print('No')
else:
  print('Yes')

n,a,b,c,d = map(int,input().split())
s = input()
S = s[:max(c,d)]
#print(S)
l = len(S)
C = True
D = False
for i in range(l-1):
  if i >= min(a,b) and S[i]=='#' and S[i+1]=='#':
    C = False
    break
  if c > d and d > i >= max(a,b)-1:
    if S[i-1]=='.' and S[i]=='.' and S[i+1]=='.':
      D = True
      
if not C:
  print('No')
elif C and not D:
  if c < d:
    print('Yes')
  else:
    print('No')
else:
  print('Yes')

Verdicts: Wrong Answer

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
import sys

n,a,b,c,d=map(int, input().split()) 
s=input()

sl=list(s)

sl[a-1]="A"
sl[b-1]="B"
sl[c-1]="a"
sl[d-1]="b"
print(sl)

if c>d:
    g_far=c
else:
    g_far=d


for i in range(a-1,g_far-2):
    if sl[i]=="#" and sl[i+1]=="#":
        #print("No")
        sys.exit()



if c>d:
    for j in range(b-1-1,d-1-1):
        #print(sl[j],sl[j+1],sl[j+2])
        if sl[j] !="#" and sl[j+1] !="#" and sl[j+2] !="#":
            print("Yes")
            sys.exit()
else:
    print("Yes")
    sys.exit()

print("No")



import sys

n,a,b,c,d=map(int, input().split()) 
s=input()

sl=list(s)

sl[a-1]="A"
sl[b-1]="B"
sl[c-1]="a"
sl[d-1]="b"
print(sl)

if c>d:
    g_far=c
else:
    g_far=d


for i in range(a-1,g_far-2):
    if sl[i]=="#" and sl[i+1]=="#":
        print("No")
        sys.exit()



if c>d:
    for j in range(b-1-1,d-1-1):
        print(sl[j],sl[j+1],sl[j+2])
        if sl[j] !="#" and sl[j+1] !="#" and sl[j+2] !="#":
            print("Yes")
            sys.exit()
else:
    print("Yes")
    sys.exit()

print("No")



import sys

n,a,b,c,d=map(int, input().split()) 
s=input()

sl=list(s)

sl[a-1]="A"
sl[b-1]="B"
sl[c-1]="a"
sl[d-1]="b"
#print(sl)

if c>d:
    g_far=c
else:
    g_far=d


for i in range(a-1,g_far-2):
    if sl[i]=="#" and sl[i+1]=="#":
        print("No")
        sys.exit()



if c>d:
    for j in range(b-1-1,d-1):
        #print(sl[j],sl[j+1],sl[j+2])
        if sl[j] !="#" and sl[j+1] !="#" and sl[j+2] !="#":
            print("Yes")
            sys.exit()
else:
    print("Yes")
    sys.exit()

print("No")



Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
N, A, B, C, D = map(int, input().split())
S = input()

AtoC = True
BtoD = True
replace = False

for n in list(range(A-1,C)):
    if S[n] =='#' and S[n+1] =='#':
        AtoC = False
        
for n in list(range(B-1,D)):
    if S[n] =='#' and S[n+1] == '#':
        BtoD = False
        
for n in list(range(B-2,D-1)):
    if S[n] =='.' and S[n+1] == '.' and S[n+2] == '.':
        replace = True
if C<D:
    if AtoC == True and BtoD == True:
        print('Yes')
    else:
        print('No')
else:
    if AtoC == True and BtoD == True and replace == True:
        print('Yes')
    else:
        print('No')

N, A, B, C, D = map(int, input().split())
S = input()

AtoC = True
BtoD = True
replace = False

for n in list(range(A-1,C)):
    if S[n] =='#' and S[n+1] =='#':
        AtoC = False
        
for n in list(range(B-1,D)):
    if S[n] =='#' and S[n+1] == '#':
        BtoD = False
        
if C<D:
    if AtoC == True and BtoD == True:
        print('Yes')
    else:
        print('No')
else:
    for n in list(range(B-2,D-1)):
        if S[n] =='.' and S[n+1] == '.' and S[n+2] == '.':
            replace = True
    if AtoC == True and BtoD == True and replace == True:
        print('Yes')
    else:
        print('No')

Verdicts: Runtime Error

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
# -*- coding: utf-8 -*-
# agc034/agc034_a
import sys

s2nn = lambda s: [int(c) for c in s.split(' ')]
ss2nn = lambda ss: [int(s) for s in list(ss)]
ss2nnn = lambda ss: [s2nn(s) for s in list(ss)]
i2s = lambda: sys.stdin.readline().rstrip()
i2n = lambda: int(i2s())
i2nn = lambda: s2nn(i2s())
ii2ss = lambda n: [i2s() for _ in range(n)]
ii2nn = lambda n: ss2nn(ii2ss(n))
ii2nnn = lambda n: ss2nnn(ii2ss(n))

def main():
    N, A, B, C, D = i2nn()
    S = i2s()
    print('No')
    return

main()


# -*- coding: utf-8 -*-
# agc034/agc034_a
import sys

s2nn = lambda s: [int(c) for c in s.split(' ')]
ss2nn = lambda ss: [int(s) for s in list(ss)]
ss2nnn = lambda ss: [s2nn(s) for s in list(ss)]
i2s = lambda: sys.stdin.readline().rstrip()
i2n = lambda: int(i2s())
i2nn = lambda: s2nn(i2s())
ii2ss = lambda n: [i2s() for _ in range(n)]
ii2nn = lambda n: ss2nn(ii2ss(n))
ii2nnn = lambda n: ss2nnn(ii2ss(n))

def main():
    N, A, B, C, D = i2nn()
    S = i2s()
    if '##' not in S[B-1:D] and '##' not in S[A-1:C]:
        if C < D:
            print('No')
        elif  '...' in S[A:D]:
            print('Yes')
        else:
            print('No')
    else:
        print('No')
    return

main()


# -*- coding: utf-8 -*-
# agc034/agc034_a
import sys

s2nn = lambda s: [int(c) for c in s.split(' ')]
ss2nn = lambda ss: [int(s) for s in list(ss)]
ss2nnn = lambda ss: [s2nn(s) for s in list(ss)]
i2s = lambda: sys.stdin.readline().rstrip()
i2n = lambda: int(i2s())
i2nn = lambda: s2nn(i2s())
ii2ss = lambda n: [i2s() for _ in range(n)]
ii2nn = lambda n: ss2nn(ii2ss(n))
ii2nnn = lambda n: ss2nnn(ii2ss(n))

def main():
    N, A, B, C, D = i2nn()
    S = i2s()
    if '##' not in S[B-1:D] and '##' not in S[A-1:C]:
        if C < D:
            print('Yes')
        elif  '...' in S[B-2:D+1]:
            print('Yes')
        else:
            print('No')
    else:
        print('No')
    return

main()


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
n,A,B,C,D = map(int,input().split())
s = input()[A-1:max(C,D)]
flag = 1
a,b,c,d = 0,B-A,C-A,D-A
if s[a]=='#' or s[b]=='#' or s[c]=='#' or s[d]=='#':
  flag = 0
if bool('##' in s) == 1:
  flag = 0
if c > d:
  scut = s[b-1:d+2]
  if bool('...' in scut) == 0:
    flag = 0
if flag == 1:
  print('YES')
else:
  print('NO')

n,A,B,C,D = map(int,input().split())
s = input()[A-1:max(C,D)]
flag = 1
a,b,c,d = 0,B-A,C-A,D-A
if s[a]=='#' or s[b]=='#' or s[c]=='#' or s[d]=='#':
  flag = 0
if bool('##' in s) == 1:
  flag = 0
if c > d:
  scut = s[b-1:d+2]
  if bool('...' in scut) == 0:
    flag = 0
if flag == 1:
  print('Yes')
else:
  print('No')

Verdicts: Wrong Answer

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
N,A,B,C,D = map(int,input().split())
S = input()
obs = [S[i] is "#" and S[i+1] is "#" for i in range(0,max(C,D)-1)]
space = [S[i] is "." and S[i+1] is "." and S[i+2] is "." for i in range(0,max(C,D)-2)]
if C < D:
  if True in obs[B:D] or True in obs[A:C]:
    print("No")
  else:
    print("Yes")
else:
  if True not in space[B-1:D]:
    print("No")
  elif True in obs[B:D-1] or True in obs[A:C-1]:
    print("No")
  else:
    print("Yes")
    
    
print(space)
  

    
  

N,A,B,C,D = map(int,input().split())
S = input()
obs = [S[i] is "#" and S[i+1] is "#" for i in range(max(C,D)-1)]
space = [S[i] is "." and S[i+1] is "." and S[i+2] is "." for i in range(max(C,D)-2)]
if C < D:
  if True in obs[B:D] or True in obs[A:C]:
    print("No")
  else:
    print("Yes")
else:
  if True not in space[B-1:D]:
    print("No")
  elif True in obs[B:D-1] or True in obs[A:C-1]:
    print("No")
  else:
    print("Yes")
    
    
print(space)
  

    
  

N,A,B,C,D = map(lambda x: int(x)-1,input().split())
S = input()

def obs(st,end):
  for i in range(st,end):
  	if S[i] is "#" and S[i+1] is "#": return True
  return False

if obs(B,D) or obs(A,C):
  print("No")
elif C > D:
  b = False
  for i in range(B-1,min(D,N-2)):
    if S[i] is "." and S[i+1] is "." and S[i+2] is ".":
      b = True
      break
  if b:
    print("Yes")
  else:
    print("No")
else:
  print("Yes")


    
  

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
N,A,B,C,D = map(int,input().split())
S = input()
right = max(C,D)-1
r = min(C,D)-1

if '##' in S[A-1:C-1] or '##' in S[B-1:D-1]:
  print('No')
else:
  if C < D:
  	print('Yes')
    break
  else:
    if '...' in S[B-1:right]:
      print('Yes')
      break
    else:
      if len(S[A-1:right])<=6:
        print('Yes')
        break
      print('No')


N,A,B,C,D = map(int,input().split())
S = input()
right = max(C,D)
r = min(C,D)-1

if '##' in S[A-1:C] or '##' in S[B-1:D]:
  print('No')
else:
  if C < D:
  	print('Yes')
  else:
    if '...' in S[B-2:D+1]:
      print('Yes')
    else:
      if len(S[A-1:right])<=6:
        if S[A-1:right].count('#')==2:
          print('No')
        else:
          print('Yes')
      else:
        print('No')


Verdicts: Runtime Error

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
import re

n,a,b,c,d = input().split()
li = input()

pat1 = '##'
pat2 = r'\.\.\.'

sm = int(c) if int(c) < int(d) else int(d)
lg = int(c) if int(c) > int(d) else int(d)

sh = li[:sm]
sh = [int(b) - 1:]
lo = li[:lg]
ret = ''

if re.match(pat1, lo):
    ret = 'No'
else:
    if c > d:
        if re.match(pat2, sh):
            ret = 'Yes'
        else:
            ret = 'No'
    else:
        ret = 'Yes'
    

print(ret)

import re

n,a,b,c,d = map(int, input().split())
li = input()

pat1 = '##'
pat2 = r'\.\.\.'

ret = ''

a2c = li[a:c]
b2d = li[b:d]
if re.search(pat1, a2c) or re.search(pat1, b2d):
    ret = 'No'
else:
    if c > d:
        carea = li[b-2:d+1]
        if re.search(pat2, carea):
            ret = 'Yes'
        else:
            ret = 'No'
    else:
        ret = 'Yes'


print(ret)

Verdicts: Runtime Error

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
n,a,b,c,d = map(int,input().split())
s = input()
flag = 0
bleh = 0
for i in range(a,d-1):
    if s[i:i+2]=="##":
        print("No")
        flag = 1
if flag == 0:
    if c>d:
        for j in range(b,d):
            if s[j:j+3]=="...":
                bleh = 1
    else:
        print("Yes")            
if bleh == 1:
    print("Yes")     
else:
    print("No")    
                
   
      
    

N, A, B, C, D = map(int, input().split())
S = input()
p = 0
t = 0
stri = 0
for i in range(A-1, max(C, D) - 1):
  if S[i:i+2] == '##':
    p = 1
for j in range(B-1, min(C, D) - 1):  
  if S[j:j+3] == '...':
    if stri == 0:
      stri = j + 1
    t = 1
if S[B] == '.' and S[B-2] == '.':
  t = 1
if (C < D and p == 0) or (C > D and p == 0 and t == 1 and stri <= D-1):
  print('Yes')
else:
  print('No')

Verdicts: Wrong Answer

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
n,a,b,c,d=map(int,input().split())
s=str(input())
s=s.replace('.','0')
s=s.replace('#','1')
x=0
y=0
f=0
g=0
for i in range(c-a-2):
    x=int(s[i+a+1])
    y=int(s[i+a+2])
    if(x*y==1):
        f=-1
for j in range(d-b-2):
    x=int(s[j+b+1])
    y=int(s[j+b+2])
    if(x*y==1):
        g=-1
if(d<c):
    if(s[b+1:d].find('000')==-1 and ):
        f=-1
if(f==0 and g==0):
    print('Yes')
else:
    print('No')


n,a,b,c,d=map(int,input().split())
s=str(input())
s=s.replace('.','0')
s=s.replace('#','1')
x=0
y=0
f=0
g=0
for i in range(c-a-2):
    x=int(s[i+a+1])
    y=int(s[i+a+2])
    if(x*y==1):
        f=-1
for j in range(d-b-2):
    x=int(s[j+b+1])
    y=int(s[j+b+2])
    if(x*y==1):
        g=-1
x=s.replace('11','7')
x=x.replace('000','8')
x=x.replace('0','')
x=x.replace('1','')
if(d<c):
    if(s[b+1:d].find('000')==-1 and ):
        f=-1
if(f==0 and g==0):
    print('Yes')
else:
    print('No')




s=str(input())
a=0
b=0
c=0
s=s.replace('BC','0')
if(s.find('A0')==-1):
    print('{0}'.format(b))
    a=1
while (a==0):
    s=s.replace('A0','0A',1)
    b+=1
    if(s.find('A0')==-1):
        print('{0}'.format(b))
        a=1
    
    

n,a,b,c,d=map(int,input().split())
s=str(input())
s=s.replace('.','0')
s=s.replace('#','1')
x=0
y=0
f=0
g=0
for i in range(c-a-1):
    x=int(s[i+a])
    y=int(s[i+a+1])
    if(x*y==1):
        f=-1
for j in range(d-b-1):
    x=int(s[j+b])
    y=int(s[j+b+1])
    if(x*y==1):
        g=-1
if(d<c):
    if(s[b-2:d+1].find('000')==-1):
        f=-1
if(f==0 and g==0):
    print('Yes')
else:
    print('No')



Verdicts: Runtime Error

Runtime Error

Wrong Answer

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
s = input()
s = s.split('BC')
count = [0]
count_all = 0
Icount = 0

for i in range(0,len(s)-1):
    Icount = 0
    j = 1
    while(j<=len(s[i]) and s[i][-j]=='A'):
        Icount = Icount + 1
        j = j + 1
        
    if (s[i]=='' or s[i]=='A'*len(s[i])):
        Icount = Icount + count[-1]
   
    count.append(Icount)
  
        
count_all = sum(count)  
print(count_all)

n,a,b,c,d = map(int,input().split())
s = input()

e = 'Yes'
f = 0
g = 1

if c < d:
    for i in range(b-1,d-1):
        if s[i]=='#' and s[i+1]=='#':
            e ='No'
    if e =='Yes':
        for j in range(a-1,b-1):
            if s[j]=='#' and s[j+1]=='#':
                e ='No'
                        
if c > d:
    for i in range(a-1,c-1):
        if s[i]=='#' and s[i+1]=='#':
            f = 1
    
    for j in range(b-2,d-1):
        if s[j]=='.' and s[j+1]=='.' and s[j+2]=='.':
            g = 0

    if g == 0 and f ==0:
        e ='Yes'
    else:
        e ='No'
            
print(e)           

Verdicts: Wrong Answer

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
import sys
from collections import defaultdict
sys.setrecursionlimit(200000)
input = sys.stdin.readline

N, A, B, C, D, = map(int, input().split())
L = list(input().strip())

A -= 1
B -= 1
C -= 1
D -= 1

m = [0] * N
m[A] = 1

for i in range(N):
    if m[i] > 0:
        if i + 1 < N and L[i + 1] == ".":
            m[i + 1] = 1

        if i + 2 < N and L[i + 2] == ".":
            m[i + 2] = 1

if m[C] == 0:
    print("No")
    exit()

m = [0] * N
m[B] = 1

for i in range(N):
    if m[i] > 0:
        if i + 1 < N and L[i + 1] == ".":
            m[i + 1] = 1

        if i + 2 < N and L[i + 2] == ".":
            m[i + 2] = 1

if m[D] == 0:
    print("No")
    exit()

if C > D:
    for i in range(B, C):
        if "#" not in L[i-1:i+2]:
            print("Yes")
            exit()
    print("No")
else:
    print("No")

import sys
from collections import defaultdict
sys.setrecursionlimit(200000)
input = sys.stdin.readline

N, A, B, C, D, = map(int, input().split())
L = list(input().strip())

A -= 1
B -= 1
C -= 1
D -= 1

m = [0] * N
m[A] = 1

for i in range(N):
    if m[i] > 0:
        if i + 1 < N and L[i + 1] == ".":
            m[i + 1] = 1

        if i + 2 < N and L[i + 2] == ".":
            m[i + 2] = 1

if m[C] == 0:
    print("No")
    exit()

m = [0] * N
m[B] = 1

for i in range(N):
    if m[i] > 0:
        if i + 1 < N and L[i + 1] == ".":
            m[i + 1] = 1

        if i + 2 < N and L[i + 2] == ".":
            m[i + 2] = 1

if m[D] == 0:
    print("No")
    exit()



import sys
from collections import defaultdict
sys.setrecursionlimit(200000)
input = sys.stdin.readline

N, A, B, C, D, = map(int, input().split())
L = list(input().strip())

A -= 1
B -= 1
C -= 1
D -= 1

m = [0] * N
m[A] = 1

for i in range(N):
    if m[i] > 0:
        if i + 1 < N and L[i + 1] == ".":
            m[i + 1] = 1

        if i + 2 < N and L[i + 2] == ".":
            m[i + 2] = 1

if m[C] == 0:
    print("No")
    exit()

m = [0] * N
m[B] = 1

for i in range(N):
    if m[i] > 0:
        if i + 1 < N and L[i + 1] == ".":
            m[i + 1] = 1

        if i + 2 < N and L[i + 2] == ".":
            m[i + 2] = 1

if m[D] == 0:
    print("No")
    exit()

if C > D:
    for i in range(B, D+1):
        if "#" not in L[i-1:i+2]:
            print("Yes")
            exit()
    print("No")
else:
    print("Yes")

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
n, a, b, c, d = map(int, input().split())
s = list(input())
for i in range(b, d - 1):
    if s[i] == '#' and s[i + 1] == '#':
        print('No')
        exit(0)
for i in range(a, c - 1):
    if s[i] == '#' and s[i + 1] == '#':
        print('No')
        exit(0)
if c < d:
    exit(1)
else:
    l, r = a - 1, a
    while l >= 0 and (s[l] != '#' or s[l + 1] != '#'):
        l -= 1
    l += 2 - int(l == -1)
    while r < n and (s[r - 1] != '#' or s[r] != '#'):
        r += 1
    r -= 2 - int(r == n)
    for i in range(l, r - 1):
        if s[i] == '.' and s[i + 1] == '.' and s[i + 2] == '.':
            print('Yes')
            break
    else:
        print('No')


n, a, b, c, d = map(int, input().split())
s = input()
if '##' in s[a:d+1]:
    print('No')
elif c < d or '...' in s[b-2:d+1]:
    print('Yes')
else:
    print('No')

Verdicts: Runtime Error

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
n, a, b, c ,d = map(int, input().split())


def main():
    if "##" in s[b:d-2]:
        return "No"
    if "##" in s[c:c-2]:
        return "No"

    if c < d:
        return "Yes"
    
    else:

        if "..." in s[b-2:d-1]:
            return "Yes"
                
        return "No"

print(main())

n, a, b, c ,d = map(int, input().split())

flag = 1

def main():
    for i in range(len(s[b:d-2])):
        if s[i:i+2] == "##":
            return "No"
    for i in range(len(s[a:c-2])):
        if s[i:i+2] == "##":
            return "No"

    if c < d:
        return "Yes"
    
    else:

        if s[b-2] == "." and s[b] == ".":
            return "Yes"
        else:
            for i in range(len(s[b:d-3])):
                if s[i:i+3] == "...":
                    return "Yes"
                    
            return "No"

print(main())

n, a, b, c ,d = map(int, input().split())
s = input()[:max(c,d)]

def main():
    if "##" in s[b:d-2]:
        return "No"
    if "##" in s[a:c-2]:
        return "No"

    if c < d:
        return "Yes"
    
    else:

        if "..." in s[b-2:d+1]:
            return "Yes"
                
        return "No"

print(main())

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
n,a,b,c,d = ( int(i) for i in input().split())
s = input()

a_to_c = s[a-1:c-1]
b_to_d = s[b-1:d-1]
if (b-1)-2 < 0:
    b_to_d2 = s[b-1:d-1]
elif:
    b_to_d2 = s[b-1-2:d-1]

possibility = True

if a_to_c.find("##")!=-1 or b_to_d.find("##")!=-1:
    possibility = False
if c>d:
    if not(b_to_d2.find('...')!=-1):
        possibility = False

if possibility:
    print("Yes")
else:
    print("No")
    

n,a,b,c,d = ( int(i) for i in input().split())
s = input()

a_to_c = s[a-1:c-1]
b_to_d = s[b-1:d-1]
if (b-1)-2 >= 0:
    b_to_d2 = s[b-1-2:d-1]
elif:
    b_to_d2 = s[b-1:d-1]

possibility = True

if a_to_c.find("##")!=-1 or b_to_d.find("##")!=-1:
    possibility = False
if c>d:
    if not(b_to_d2.find('...')!=-1):
        possibility = False

if possibility:
    print("Yes")
else:
    print("No")
    

n,a,b,c,d = ( int(i) for i in input().split())
s = input()

a_to_c = s[a-1:c-1]
b_to_d = s[b-1:d-1]
if (b-1)-1 >= 0:
    b_to_d2 = s[b-1-1:d-1]
else:
    b_to_d2 = s[b-1:d-1]

possibility = True

if a_to_c.find("##")!=-1 or b_to_d.find("##")!=-1:
    possibility = False
if c>d:
    if s[d-1]='#':
        if not(s[b-3:d-1].find("...")!=-1):
            possibility = False
    if not(b_to_d2.find('...')!=-1):
        possibility = False


if possibility:
    print("Yes")
else:
    print("No")
    

n,a,b,c,d = ( int(i) for i in input().split())
s = input()

a_to_c = s[a:(c-1)-1]
b_to_d = s[b-1:d-1]

possibility = True

if c>d:
    b_to_d = s[(b-1)-1:(d-1)+1]
    if "##" in a_to_c or "..." not in b_to_d
        possibility = False
else:
    b_to_d = s[(b-1)+1:(d-1)-1]
    if "##" in a_to_c or "##" in b_to_d:
        possibility = False

if possibility:
    print("Yes")
else:
    print("No")

n,a,b,c,d = ( int(i) for i in input().split())
s = input()

a_to_c = s[(a-1)+1:(c-1)-1 +1]

possibility = True

if c>d:
    b_to_d = s[(b-1)-1:(d-1)+1 +1]
    if "##" in a_to_c or "..." not in b_to_d:
        possibility = False
else:
    b_to_d = s[(b-1)+1:(d-1)-1 +1]
    if "##" in a_to_c or "##" in b_to_d:
        possibility = False

if possibility:
    print("Yes")
else:
    print("No")

Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.  In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.  You can repeat the following operation any number of times:    * Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.  You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.  Determine whether this is possible.

Submission attempts (in order):
import re

count = 0

def count_inversion(sequence):
    return sum(sum(m>n for m in sequence[i+1:]) for i,n in enumerate(sequence))

s = input()
s = s.replace("BC", "D")
s = re.split(r"[B-C]+", s)

while "" in s:
    s.remove("")
for x in s:
    count += count_inversion(list(x))
        
print(count)

import sys
N, A, B, C, D = map(int, input().split())
S = input()

for x in S[A:max(C, D)-1].split("."):
    if len(x) > 1:
        print("No")
        sys.exit()
    else:
        pass

if C < D:
    print("Yes")
    sys.exit()

for x in S[B-2:D+1].split("#"):
    if len(x) > 2:
        print("Yes")
        sys.exit()
    else:
        pass

print("No")

Verdicts: Wrong Answer

Accepted