TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
def bingo(A, B):
  for i in range(3):
    if A[i][0] == "o" and A[i][1] == "o" and A[i][2] == "o":
      return True
    elif A[0][i] == "o" and A[1][i] == "o" and A[2][i] == "o":
      return True
    
  if A[0][0] == "o" and A[1][1] == "o" and A[2][2] == "o":
    return True
  elif A[0][2] == "o" and A[1][1] == "o" and A[2][0] == "o":
    return True
    
  return False

A = []
for i in range(3):
  A.append(list(map(int, input().split())))
           
N = int(input())
B = []
for i in range(N):
  B.append(int(input()))

for b in B:
  for i in range(3):
    for j in range(3):
      if A[i][j] == b:
        A[i][j] = "o"

if bingo(A, B):
  print("YES")
else:
  print("No")

def bingo(A, B):
  for i in range(3):
    if A[i][0] == "o" and A[i][1] == "o" and A[i][2] == "o":
      return True
    elif A[0][i] == "o" and A[1][i] == "o" and A[2][i] == "o":
      return True
    
  if A[0][0] == "o" and A[1][1] == "o" and A[2][2] == "o":
    return True
  elif A[0][2] == "o" and A[1][1] == "o" and A[2][0] == "o":
    return True
    
  return False

A = []
for i in range(3):
  A.append(list(map(int, input().split())))
           
N = int(input())
B = []
for i in range(N):
  B.append(int(input()))

for b in B:
  for i in range(3):
    for j in range(3):
      if A[i][j] == b:
        A[i][j] = "o"

if bingo(A, B):
  print("Yes")
else:
  print("No")

Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
A = [list(map(int,input().split())) for a in range(3)]
N = int(input())
for i in range(N):
  B = int(input())
  for t in range(3):
    for s in range(3):
      if B == A[t][s]:
        A[t][s] == 0

if A[0][0] == A[0][1] == A[0][2] or A[1][0] == A[1][1] == A[1][2] or A[2][0] == A[2][1] == A[2][2] or A[0][0] == A[1][0] == A[2][0] or A[1][0] == A[1][1] == A[1][2] or A[2][0] == A[2][1] == A[2][2] or A[0][0] == A[1][1] == A[2][2] or A[0][2] == A[1][1] == A[2][0]:
  print('Yes')
else:
  print('No')

a=[list(map(int,input().split())) for A in range(3)]
n=int(input())

for i in range(n):
  b=int(input())
  for j in range(3):
    for k in range(3):
      if b==a[j][k]:
        a[j][k]=0

if a[0][0]==a[0][1]==a[0][2] or a[1][0]==a[1][1]==a[1][2] or a[2][0]==a[2][1]==a[2][2]\
or a[0][0]==a[1][0]==a[2][0] or a[0][1]==a[1][1]==a[2][1] or a[0][2]==a[1][2]==a[2][2]\
or a[0][0]==a[1][1]==a[2][2] or a[2][0]==a[1][1]==a[0][2]:
  print("Yes")
else:
  print("No")


Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
import numpy as np
tmps = []
for i in range(3):
    tmp = list(map(int, input().split(' ')))
    tmps.append(tmp)
bingo = np.array(tmps)
N = int(input())
for i in range(N):
    bingo = np.where(bingo==i, -1, bingo)
c = 2
x1 = 0
x2 = 0
ret = []
for i in range(3):
    row = np.sum(bingo[i, :])
    col = np.sum(bingo[:, i])
    x1 += np.sum(bingo[i, i])
    x2 += np.sum(bingo[i, c-i])
    ret.append(row)
    ret.append(col)
ret.append(x1)
ret.append(x2)
if -3 in ret:
    print('Yes')
else:
    print('No')

import numpy as np
tmps = []
for i in range(3):
    tmp = list(map(int, input().split(' ')))
    tmps.append(tmp)
bingo = np.array(tmps)
N = int(input())
for i in range(N):
    bingo = np.where(bingo==int(input()), -1, bingo)
c = 2
x1 = 0
x2 = 0
ret = []
for i in range(3):
    row = np.sum(bingo[i, :])
    col = np.sum(bingo[:, i])
    x1 += np.sum(bingo[i, i])
    x2 += np.sum(bingo[i, c-i])
    ret.append(row)
    ret.append(col)
ret.append(x1)
ret.append(x2)
if -3 in ret:
    print('Yes')
else:
    print('No')

Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
import sys
L = []
bingo = set()
Numbers = []
testor = 0
for i in range(3):
  a,b,c = map(int,input().split())
  L.append((a,b,c)) #00 10 20/ 01 11 21/ 02 12 22/00 11 22/ 20 11 02/
N = int(input())
for i in range(3):
  a = L[0][i] 
  b = L[1][i]
  c = L[2][i]
  L.append((a,b,c))
a = L[0][0]
b = L[1][1]
c = L[2][2]
L.append((a,b,c))
a = L[2][0] 
b = L[1][1]
c = L[0][2]
L.append((a,b,c))
print(L)
for i in range(N):
  Numbers.append(int(input()))
for i in range(8): 
  bingo = L[i]
  for k in range(N):
    if Numbers[k] in bingo:
      testor += 1
    if testor == 3:
        print('Yes')
        sys.exit(0)
  testor = 0
print('No')

import sys
L = []
bingo = set()
Numbers = []
testor = 0
for i in range(3):
  a,b,c = map(int,input().split())
  L.append((a,b,c)) #00 10 20/ 01 11 21/ 02 12 22/00 11 22/ 20 11 02/
N = int(input())
for i in range(3):
  a = L[0][i] 
  b = L[1][i]
  c = L[2][i]
  L.append((a,b,c))
a = L[0][0]
b = L[1][1]
c = L[2][2]
L.append((a,b,c))
a = L[2][0] 
b = L[1][1]
c = L[0][2]
L.append((a,b,c))
for i in range(N):
  Numbers.append(int(input()))
for i in range(8): 
  bingo = L[i]
  for k in range(N):
    if Numbers[k] in bingo:
      testor += 1
    if testor == 3:
        print('Yes')
        sys.exit(0)
  testor = 0
print('No')

Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
l = []
flag = 0
for i in range(3):
  for j in input().split():
    l.append(j)
n = int(input())
for i in range(n):
  a = input()
  if a in l:
    l[l.index(a)] = 0
if l[0:3] == 0 or l[3:6] == 0 or l[6:9] == 0:
  flag = 1
if l[0::3] == 0 or l[1::3] == 0 or l[2::3] == 0:
  flag = 1
if l[0::4] == 0 or l[2::2] == 0:
  flag = 1
if flag:
  print("Yes")
else:
  print("No")

l = []
flag = 0
for i in range(3):
  l.append(list(input().split()))
n = int(input())
for i in range(n):
  a = int(input())
  for j in range(3):
    for m in l[j]:
      if m == a:
        l[j][l.index(m)] = 0
for i in range(3):
  if not any(l[i]):
    flag = 1
if l[0][0] == l[1][0] == l[2][0] or l[0][1] == l[1][1] == l[2][1] or l[0][2] == l[1][2] == l[2][2]:
  flag = 1
if l[0][0] == l[1][1] == l[2][2] or l[0][2] == l[1][1] == l[2][0]:
  flag = 1
if flag == 1:
  print("Yes")
else:
  print("No")

l = []
flag = 0
for i in range(3):
  for j in input().split():
    l.append(j)
n = int(input())
for i in range(n):
  a = input()
  if a in l:
    l[l.index(a)] = 0
if not any(l[0:3])  or not any(l[3:6]) or not any(l[6:9]):
  flag = 1
if not any(l[0::3]) or not any(l[1::3]) or not any(l[2::3]):
  flag = 1
if not any(l[0::4]) or not any(l[2:7:2]):
  flag = 1
if flag:
  print("Yes")
else:
  print("No")

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
if __name__ == '__main__':
    m = [input() for _ in range(3)]
    n = input()
    a = [int(input()) for _ in range(int(n))]
    c =[]
    for i in m:
        b = [int(j) for j in i.split()]
        c.append(b)

    for n,i in enumerate(c):
        for m,j in enumerate(i):
            if j in a:
                print("A")
                c[n][m] = -1
                
    re = []
    for i in range(3):
        tmp = []
        tmp2 = []
        for j in range(3):
            tmp.append([i,j])
            tmp2.append([j,i])
        re.append(tmp)
        re.append(tmp2)
    re.append([[0,2],[1,1],[2,0]])
    re.append([[0,0],[1,1],[2,2]])

    f = 0
    for i in re:
        flg =[]
        for n,j in enumerate(i):
            if c[j[0]][j[1]] == -1:
                flg.append(1)
            else:
                flg.append(0)
        if flg == [1,1,1]:
            f = 1
    
    if f == 1:
        print('Yes')
    else:
        print('No')

A = []
for _ in range(3):
    A.append([int(i) for i in input().split(' ')])
N = int(input())
a = []
for _ in range(N):
    a.append(int(input()))

for num in a:
    for i in range(3):
        for j in range(3):
            if num == A[i][j]:
                A[i][j] = '*'

ans = 'No'
for i in range(3):
    flg = 0 
    b1 = all(A[i][j] == '*' for j in range(3))
    b2 = all(A[j][i] == '*' for j in range(3))
    b3 = all(A[j][j] == '*' for j in range(3))
    b4 = all(A[2-j][j] == '*' for j in range(3))
    if b1 or b2 or b3 or b4:
        ans = 'Yes'

print(ans)
        

Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
mat=[]

for i in range(3):
    inp = [int(x) for x in input().split()]
    mat.append(inp)
    
n = int(input())

for _ in range(n):
    q = int(input())
    for i in range(3):
        if q in mat[i]:
            ind = mat[i].index(q)
            mat[i][ind] = '1'
            break
    
if mat[0][0]=='1' and mat[0][1]=='1' and mat[0][2]=='1':
    print('YES')
    
elif mat[1][0]=='1' and mat[1][1]=='1' and mat[1][2]=='1':
    print('YES')

elif mat[2][0]=='1' and mat[2][1]=='1' and mat[2][2]=='1':
    print('YES')

#col
elif mat[0][0]=='1' and mat[1][0]=='1' and mat[2][0]=='1':
    print('YES')

elif mat[0][1]=='1' and mat[1][1]=='1' and mat[2][1]=='1':
    print('YES')

elif mat[0][2]=='1' and mat[1][2]=='1' and mat[2][2]=='1':
    print('YES')

#diag
elif mat[0][0]=='1' and mat[1][1]=='1' and mat[2][2]=='1':
    print('YES')

elif mat[0][2]=='1' and mat[1][1]=='1' and mat[2][0]=='1':
    print('YES')
else:
    print('NO')
    

mat=[]

for i in range(3):
    inp = [int(x) for x in input().split()]
    mat.append(inp)
    
n = int(input())

for _ in range(n):
    q = int(input())
    for i in range(3):
        if q in mat[i]:
            ind = mat[i].index(q)
            mat[i][ind] = '1'
            break
    
if mat[0][0]=='1' and mat[0][1]=='1' and mat[0][2]=='1':
    print('Yes')
    
elif mat[1][0]=='1' and mat[1][1]=='1' and mat[1][2]=='1':
    print('Yes')

elif mat[2][0]=='1' and mat[2][1]=='1' and mat[2][2]=='1':
    print('Yes')

#col
elif mat[0][0]=='1' and mat[1][0]=='1' and mat[2][0]=='1':
    print('Yes')

elif mat[0][1]=='1' and mat[1][1]=='1' and mat[2][1]=='1':
    print('Yes')

elif mat[0][2]=='1' and mat[1][2]=='1' and mat[2][2]=='1':
    print('Yes')

#diag
elif mat[0][0]=='1' and mat[1][1]=='1' and mat[2][2]=='1':
    print('Yes')

elif mat[0][2]=='1' and mat[1][1]=='1' and mat[2][0]=='1':
    print('Yes')
else:
    print('No')
    

Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
a = [list(map(int, input().split())) for _ in range(3)]
n = int(input())
b = [int(input()) for _ in range(n)]

for i in range(3):
    for j in range(3):
        for k in range(n):
            if a[i][j] == b[k]:
                a[i][j] = 0

ans = "No"
for i in range(3):
    if a[i][0] + a[i][1] + a[i][2] == 0:
        ans = "Yes"
    if a[0][i] + a[1][i] + a[2][i] == 0:
        ans = "Yes"
if a[0][0] == a[1][1] == a[2][2] == 0 or a[0][2] == a[1][1] == a[2][0] == 0:
    ans = "Yes
print(ans)

a = [list(map(int, input().split())) for _ in range(3)]
n = int(input())
b = [int(input()) for _ in range(n)]

for i in range(3):
    for j in range(3):
        for k in range(n):
            if a[i][j] == b[k]:
                a[i][j] = 0

ans = "No"
for i in range(3):
    if a[i][0] + a[i][1] + a[i][2] == 0:
        ans = "Yes"
    if a[0][i] + a[1][i] + a[2][i] == 0:
        ans = "Yes"
if a[0][0] == a[1][1] == a[2][2] == 0 or a[0][2] == a[1][1] == a[2][0] == 0:
    print("Yes")
print(ans)

a = [list(map(int, input().split())) for _ in range(3)]
n = int(input())
b = [int(input()) for _ in range(n)]

for i in range(3):
    for j in range(3):
        for k in range(n):
            if a[i][j] == b[k]:
                a[i][j] = 0

ans = "No"
for i in range(3):
    if a[i][0] + a[i][1] + a[i][2] == 0:
        ans = "Yes"
    if a[0][i] + a[1][i] + a[2][i] == 0:
        ans = "Yes"
if a[0][0] == a[1][1] == a[2][2] == 0 or a[0][2] == a[1][1] == a[2][0] == 0:
    ans = "Yes"
print(ans)

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
b = []
for i in range(3):
  lst = list(map(int,input().split()))
  b.append(lst)
n = int(input())
for i in range(n):
  a = int(input())
  for j in range(3):
    for k in range(3):
      if (b[j][k] == a):
        b[j][k] = 0
if (b[0][0] = b[0][1] = b[0][2] or b[1][0] = b[1][1] = b[1][2] or b[2][0] = b[2][1] = b[2][2] or b[0][0] = b[1][0] = b[2][0] or b[0][1] = b[1][1] = b[2][1] or b[0][2] = b[1][2] = b[2][2] or b[0][0] = b[1][1] = b[2][2] or b[0][2] = b[1][1] = b[2][0]):
  print("Yes")
else:
  print("No")
  

b = []
for i in range(3):
  lst = list(map(int,input().split()))
  b.append(lst)
n = int(input())
for i in range(n):
  a = int(input())
  for j in range(3):
    for k in range(3):
      if (b[j][k] == a):
        b[j][k] = 0
if (b[0][0] == b[0][1] == b[0][2] or b[1][0] == b[1][1] == b[1][2] or b[2][0] == b[2][1] == b[2][2] or b[0][0] == b[1][0] == b[2][0] or b[0][1] == b[1][1] == b[2][1] or b[0][2] == b[1][2] == b[2][2] or b[0][0] == b[1][1] == b[2][2] or b[0][2] == b[1][1] == b[2][0]):
  print("Yes")
else:
  print("No")
  


Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
import sys
A = list(map(int,input().split()))
B = list(map(int,input().split()))
C = list(map(int,input().split()))
N = int(input())
M = [int(input()) for i in range(N)]

for m in range(M):
  if M[m] in A:
    A[M[m]] = 0
  elif M[m] in B:
    B[M[m]] = 0
  elif M[m] in C:
    C[M[m]] = 0

for t in range(3):
  if A[t] + B[t] + C[t] ==0:
    print("Yes")
    sys.exit()
if sum(A) == 0 or sum(B) == 0 or sum(c) ==0:
  print("Yes")
  sys.exit()
elif A[0] + B[1] + C[2] == 0:
  print("Yes")
  sys.exit()
elif A[2] + B[1] +C[0] == 0:
  print("Yes")
else:
  print("No")

A = list(map(int,input().split()))
B = list(map(int,input().split()))
C = list(map(int,input().split()))
N = int(input())
M = [int(input()) for i in range(N)]
for m in range(M):
	if M[m] in A:
		A[M[m]] = 0
	elif M[m] in B:
		B[M[m]] = 0
	elif M[m] in C:
		C[M[m]] = 0
for t in range(3):
	if A[t] + B[t] + C[t] == 0:
		print('Yes')
		sys.exit()
if sum(A) == 0 or sum(B) == 0 or sum(C) ==0:
	print('Yes')
	sys.exit()
elif A[0] + B[1] + C[2] == 0:
	print('Yes')
	sys.exit()
elif A[2] + B[1] +C[0] == 0:
	print('Yes')
else:
	print('No')

import sys
A = list(map(int,input().split()))
B = list(map(int,input().split()))
C = list(map(int,input().split()))
N = int(input())
M = [int(input()) for i in range(N)]

for m in range(M):
  if M[m] in A:
    A[M[m]] = 0
  elif M[m] in B:
    B[M[m]] = 0
  elif M[m] in C:
    C[M[m]] = 0

for t in range(3):
  if A[t] + B[t] + C[t] ==0:
    print("Yes")
    sys.exit()
if sum(A) == 0 or sum(B) == 0 or sum(C) ==0:
  print("Yes")
  sys.exit()
elif A[0] + B[1] + C[2] == 0:
  print("Yes")
  sys.exit()
elif A[2] + B[1] +C[0] == 0:
  print("Yes")
else:
  print("No")


import sys
A = list(map(int,input().split()))
B = list(map(int,input().split()))
C = list(map(int,input().split()))
N = int(input())
M = [int(input()) for i in range(N)]
for m in range(len(M)):
	if M[m] in A:
		A[A.index(M[m])] = 0
	elif M[m] in B:
		B[B.index(M[m])] = 0
	elif M[m] in C:
		C[C.index(M[m])] = 0
for t in range(3):
	if A[t] + B[t] + C[t] == 0:
		print('Yes')
		sys.exit()
if sum(A) == 0 or sum(B) == 0 or sum(C) ==0:
	print('Yes')
	sys.exit()
elif A[0] + B[1] + C[2] == 0:
	print('Yes')
	sys.exit()
elif A[2] + B[1] +C[0] == 0:
	print('Yes')
else:
	print('No')

Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
bingo = []
tmp = input()
bingo.append(tmp.split(' '))
tmp = input()
bingo.append(tmp.split(' '))
tmp = input()
bingo.append(tmp.split(' '))
for i in len(bingo):
    bingo[i] = [int(bingo[i][0]), int(bingo[i][1]), int(bingo[i][2])]

n = input()
data = []
arr = range(int(n))
arr = list(arr)
for count in arr:
    tmp = input()
    data.append(int(tmp))

ans = []
for num in data:
    for i in len(bingo):
        for j in [0, 1, 2]:
            if bingo[i][j] is num:
                ans.append([i, j])

# 1 2 3
# 4 5 6
# 7 8 9

# 6 15 12 15 15 24 18
# more 3

# 11 12 13
# 21 22 23
# 31 32 33

if [0, 0] in ans and [0, 1] in ans and [0, 2] in ans:
    print('Yes')
    exit(0)

if [1, 0] in ans and [1, 1] in ans and [1, 2] in ans:
    print('Yes')
    exit(0)

if [2, 0] in ans and [2, 1] in ans and [2, 2] in ans:
    print('Yes')
    exit(0)

if [0, 0] in ans and [1, 0] in ans and [2, 0] in ans:
    print('Yes')
    exit(0)

if [0, 1] in ans and [1, 1] in ans and [2, 1] in ans:
    print('Yes')
    exit(0)

if [0, 2] in ans and [1, 2] in ans and [2, 2] in ans:
    print('Yes')
    exit(0)

if [0, 0] in ans and [1, 1] in ans and [2, 2] in ans:
    print('Yes')
    exit(0)

if [0, 2] in ans and [1, 1] in ans and [2, 0] in ans:
    print('Yes')
    exit(0)

print('No')


bingo = []
tmp = input()
bingo.append(tmp.split(' '))
tmp = input()
bingo.append(tmp.split(' '))
tmp = input()
bingo.append(tmp.split(' '))
for i in range(len(bingo)):
    bingo[i] = [int(bingo[i][0]), int(bingo[i][1]), int(bingo[i][2])]

n = input()
data = []
arr = range(int(n))
arr = list(arr)
for count in arr:
    tmp = input()
    data.append(int(tmp))

ans = []
for num in data:
    for i in range(len(bingo)):
        for j in [0, 1, 2]:
            if bingo[i][j] is num:
                ans.append([i, j])

# 1 2 3
# 4 5 6
# 7 8 9

# 6 15 12 15 15 24 18
# more 3

# 11 12 13
# 21 22 23
# 31 32 33

if [0, 0] in ans and [0, 1] in ans and [0, 2] in ans:
    print('Yes')
    exit(0)

if [1, 0] in ans and [1, 1] in ans and [1, 2] in ans:
    print('Yes')
    exit(0)

if [2, 0] in ans and [2, 1] in ans and [2, 2] in ans:
    print('Yes')
    exit(0)

if [0, 0] in ans and [1, 0] in ans and [2, 0] in ans:
    print('Yes')
    exit(0)

if [0, 1] in ans and [1, 1] in ans and [2, 1] in ans:
    print('Yes')
    exit(0)

if [0, 2] in ans and [1, 2] in ans and [2, 2] in ans:
    print('Yes')
    exit(0)

if [0, 0] in ans and [1, 1] in ans and [2, 2] in ans:
    print('Yes')
    exit(0)

if [0, 2] in ans and [1, 1] in ans and [2, 0] in ans:
    print('Yes')
    exit(0)

print('No')


Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
mat = [[False]*3 for i in range(3)]
a_mat = []
for i in range(3):
  a_list = list(map(int, input().split()))
  a_mat.append(a_list)
n = int(input())
for i in range(n):
  b = int(input())
  for x in range(3):
    for y in range(3):
      if a_mat[x][y] == b:
        mat[x][y] = True

if mat[0][0] and mat[0][1] and mat[0][2] ¥
or mat[1][0] and mat[1][1] and mat[1][2] ¥
or mat[2][0] and mat[2][1] and mat[2][2] ¥
or mat[0][0] and mat[1][0] and mat[2][0] ¥
or mat[0][1] and mat[1][1] and mat[2][1] ¥
or mat[0][2] and mat[1][2] and mat[2][2] ¥
or mat[0][0] and mat[1][1] and mat[2][2] ¥
or mat[0][2] and mat[1][1] and mat[2][0]:
  print("Yes")
else:
  print("No")

mat = [[False]*3 for i in range(3)]
a_mat = []
for i in range(3):
  a_list = list(map(int, input().split()))
  a_mat.append(a_list)
n = int(input())
for i in range(n):
  b = int(input())
  for x in range(3):
    for y in range(3):
      if a_mat[x][y] == b:
        mat[x][y] = True

if mat[0][0] and mat[0][1] and mat[0][2] \
or mat[1][0] and mat[1][1] and mat[1][2] \
or mat[2][0] and mat[2][1] and mat[2][2] \
or mat[0][0] and mat[1][0] and mat[2][0] \
or mat[0][1] and mat[1][1] and mat[2][1] \
or mat[0][2] and mat[1][2] and mat[2][2] \
or mat[0][0] and mat[1][1] and mat[2][2] \
or mat[0][2] and mat[1][1] and mat[2][0]:
  print("Yes")
else:
  print("No")


Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34



import sys
input = sys.stdin.buffer.readline


from collections import defaultdict

con = 10 ** 9 + 7

def getlist():
	return list(map(int, input().split()))


def main():
	A = []
	for i in range(3):
		a = getlist()
		A.append(a)
	bingo = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]

	N = int(input())
	for k in range(N):
		b = int(input())
		for i in range(3):
			for j in range(3):
				if A[i][j] == b:
					bingo[i][j] = 1
	
	judge = "No"
	for i in range(3):
		if bingo[i][0] == 1 and bingo[i][1] == 1 and bingo[i][2] == 1:
			judge = "Yes"
	for i in range(3):
		if bingo[0][i] == 1 and bingo[1][i] == 1 and bingo[2][i] == 1:
			judge = "Yes"

	if bingo[0][0] == 1 and bingo[1][1] == 1 and bingo[2][2] == 1:
		judge = "Yes"
	if bingo[2][0] == 1 and bingo[1][1] == 1 and bingo[0][2] == 1:
		judge = "Yes"

	print(judge)

if __name__ == '__main__':
	main()

Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
a=[]
for i in range(3):
  a1,a2,a3=map(int,input().split())
  a.append(a1,a2,a3)
n=int(input())
for i in range(n):
  b=int(input())
  for j in range(9):
    if a[j]==b:
      a[j]=0
if a[0]==0 and a[1]==0 and a[2]==0:
  print("Yes")
elif a[3]==0 and a[4]==0 and a[5]==0:
  print("Yes")
elif a[6]==0 and a[7]==0 and a[8]==0:
  print("Yes")
elif a[0]==0 and a[3]==0 and a[6]==0:
  print("Yes")
elif a[1]==0 and a[4]==0 and a[7]==0:
  print("Yes")
elif a[2]==0 and a[5]==0 and a[8]==0:
  print("Yes")
elif a[0]==0 and a[4]==0 and a[8]==0:
  print("Yes")
elif a[2]==0 and a[4]==0 and a[6]==0:
  print("Yes")
else:
  print("No")

a=[]
for i in range(3):
  a1,a2,a3=map(int,input().split())
  a.append(a1)
  a.append(a2)
  a.append(a3)
n=int(input())
for i in range(n):
  b=int(input())
  for j in range(9):
    if a[j]==b:
      a[j]=0
if a[0]==0 and a[1]==0 and a[2]==0:
  print("Yes")
elif a[3]==0 and a[4]==0 and a[5]==0:
  print("Yes")
elif a[6]==0 and a[7]==0 and a[8]==0:
  print("Yes")
elif a[0]==0 and a[3]==0 and a[6]==0:
  print("Yes")
elif a[1]==0 and a[4]==0 and a[7]==0:
  print("Yes")
elif a[2]==0 and a[5]==0 and a[8]==0:
  print("Yes")
elif a[0]==0 and a[4]==0 and a[8]==0:
  print("Yes")
elif a[2]==0 and a[4]==0 and a[6]==0:
  print("Yes")
else:
  print("No")

Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
a = [list(map(int,input().split())) for i in range(3)]
n = int(input())
for k in range(n):
    b = int(input())
    for i in range(3):
        for j in range(3):
            if a[i][j] == b:
                a[i][j] = -1
f = False
for i in range(3):
    for j in range(3):
        if (a[0][0] == a[0][1] == a[0][2]== -1) or (a[1][0] == a[1][1] == a[1][2]== -1) or (a[2][0] == a[2][1] == a[2][2]== -1):
            f = True
        elif (a[0][0] == a[1][0] == a[2][0] == -1) or (a[0][1] == a[1][1] == a[2][1] == -1) or (a[0][2] == a[1][2] == a[2][2] == -1):
            f = True
        elif (a[0][0] == a[1][1] == a[2][2] == -1) or (a[2][0] == a[1][1] == a[0][2] == -1):
            f = True
print(a)
if f:
    print('Yes')
else:
    print('No')

a = [list(map(int,input().split())) for i in range(3)]
n = int(input())
for k in range(n):
    b = int(input())
    for i in range(3):
        for j in range(3):
            if a[i][j] == b:
                a[i][j] = -1
f = False
for i in range(3):
    for j in range(3):
        if (a[0][0] == a[0][1] == a[0][2]== -1) or (a[1][0] == a[1][1] == a[1][2]== -1) or (a[2][0] == a[2][1] == a[2][2]== -1):
            f = True
        elif (a[0][0] == a[1][0] == a[2][0] == -1) or (a[0][1] == a[1][1] == a[2][1] == -1) or (a[0][2] == a[1][2] == a[2][2] == -1):
            f = True
        elif (a[0][0] == a[1][1] == a[2][2] == -1) or (a[2][0] == a[1][1] == a[0][2] == -1):
            f = True
if f:
    print('Yes')
else:
    print('No')

Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
x = [input().split() for i in range(3)]
N = int(input())
b = [int(input()) for n in range(N)]
l = [[0]*3, [0]*3, [0]*3]
for val in b:
    for i in range(3):
        for j in range(3):
            print(val)
            if val == int(x[i][j]):
                l[i][j] = 1
if l[0][0] + l[0][1] + l[0][2] == 3:
    print('Yes')
elif l[1][0] + l[1][1] + l[1][2] == 3:
    print('Yes')
elif l[2][0] + l[2][1] + l[2][2] == 3:
    pritn('Yes')
elif l[0][0] + l[1][0] + l[2][0] == 3:
    print('Yes')
elif l[0][1] + l[1][1] + l[2][1] == 3:
    print('Yes')
elif l[0][2] + l[1][2] + l[2][2] == 3:
    print('Yes')
elif l[0][0] + l[1][1] + l[2][2] == 3:
    print('Yes')
elif l[0][2] + l[1][1] + l[2][0] == 3:
    print('Yes')
else:
    print('No')

x = [input().split() for i in range(3)]
N = int(input())
b = [int(input()) for n in range(N)]
l = [[0]*3, [0]*3, [0]*3]
for val in b:
    for i in range(3):
        for j in range(3):
            if val == int(x[i][j]):
                l[i][j] = 1
if l[0][0] + l[0][1] + l[0][2] == 3:
    print('Yes')
elif l[1][0] + l[1][1] + l[1][2] == 3:
    print('Yes')
elif l[2][0] + l[2][1] + l[2][2] == 3:
    print('Yes')
elif l[0][0] + l[1][0] + l[2][0] == 3:
    print('Yes')
elif l[0][1] + l[1][1] + l[2][1] == 3:
    print('Yes')
elif l[0][2] + l[1][2] + l[2][2] == 3:
    print('Yes')
elif l[0][0] + l[1][1] + l[2][2] == 3:
    print('Yes')
elif l[0][2] + l[1][1] + l[2][0] == 3:
    print('Yes')
else:
    print('No')

Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
li_a = list(map(int, input().split()))
li_b = list(map(int, input().split()))
li_c = list(map(int, input().split()))
li_d = [li_a[0], li_b[0], li_c[0]]
li_e = [li_a[1], li_b[1], li_c[1]]
li_f = [li_a[2], li_b[2], li_c[2]]
li_g = [li_a[0], li_b[1], li_c[2]]
li_h = [li_a[2], li_b[1], li_c[0]]
n = int(input())
li_call = []
for i in range(n):
  li_call.append(int(input()))
for i in range(n):
  for j in range(2):
    if li_a[j] == li_call[i]:
      li_a[j] = 0
  for k in range(2):
    if li_b[k] == li_call[i]:
      li_b[k] = 0
  for l in range(2):
    if li_c[l] == li_call[i]:
      li_c[l] = 0
li_o = 0
if li_a == li_o or li_b == li_o or li_c == li_o or li_d == li_o or li_e == li_o or li_f == li_o or li_g == li_o or li_h == [0, 0, 0]:
  print("Yes")
else:
  print("No")

li_a = list(map(int, input().split()))
li_b = list(map(int, input().split()))
li_c = list(map(int, input().split()))

n = int(input())
li_call = []
for i in range(n):
  li_call.append(int(input()))
for i in range(n):
  for j in range(3):
    if li_a[j] == li_call[i]:
      li_a[j] = 0
  for k in range(3):
    if li_b[k] == li_call[i]:
      li_b[k] = 0
  for l in range(3):
    if li_c[l] == li_call[i]:
      li_c[l] = 0
li_o = 0
li_d = [li_a[0], li_b[0], li_c[0]]
li_e = [li_a[1], li_b[1], li_c[1]]
li_f = [li_a[2], li_b[2], li_c[2]]
li_g = [li_a[0], li_b[1], li_c[2]]
li_h = [li_a[2], li_b[1], li_c[0]]
if li_a == li_o or li_b == li_o or li_c == li_o or li_d == li_o or li_e == li_o or li_f == li_o or li_g == li_o or li_h == [0, 0, 0]:
  print("Yes")
else:
  print("No")

li_a = list(map(int, input().split()))
li_b = list(map(int, input().split()))
li_c = list(map(int, input().split()))

n = int(input())
li_call = []
for i in range(n):
  li_call.append(int(input()))
for i in range(n):
  for j in range(3):
    if li_a[j] == li_call[i]:
      li_a[j] = 0
  for k in range(3):
    if li_b[k] == li_call[i]:
      li_b[k] = 0
  for l in range(3):
    if li_c[l] == li_call[i]:
      li_c[l] = 0
li_o = [0, 0, 0]
li_d = [li_a[0], li_b[0], li_c[0]]
li_e = [li_a[1], li_b[1], li_c[1]]
li_f = [li_a[2], li_b[2], li_c[2]]
li_g = [li_a[0], li_b[1], li_c[2]]
li_h = [li_a[2], li_b[1], li_c[0]]
if li_a == li_o:
  print("Yes")
elif li_b == li_o:
  print("Yes")
elif li_c == li_o:
  print("Yes")
elif li_d == li_o:
  print("Yes")
elif li_e == li_o:
  print("Yes")
elif li_f == li_o:
  print("Yes")
elif li_g == li_o:
  print("Yes")
elif li_h == li_o:
  print("Yes")

else:
  print("No")

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
bingo_list = [list(map(int,input().split())) for i in range(3)]
bingo_list = sum(bingo_list,[])
n = int(input())
bingo_number = [int(input())for i in range(n)]
check_list = [0 for i in range(9)]

for j in bingo_number:
    if j in bingo_list:
        check_list[bingo_list.index(j)] = 1

if [1,1,1] in [check_list[:3],check_list[3:6],check_list[6:],check_list[0:7:3],check_list[1:8:3]check_list[2:9:3],check_list[0:9:4],check_list[2:8:2]]:
    print('Yes')
else:
    print('No')

bingo_list = [list(map(int,input().split())) for i in range(3)]
bingo_list = sum(bingo_list,[])
n = int(input())
bingo_number = [int(input())for i in range(n)]
check_list = [0 for i in range(9)]

for j in bingo_number:
    if j in bingo_list:
        check_list[bingo_list.index(j)] = 1

if [1,1,1]in [check_list[:3],check_list[3:6],check_list[6:],check_list[0:7:3],check_list[1:8:3]check_list[2:9:3],check_list[0:9:4],check_list[2:7:2]]:
    print('Yes')
else:
    print('No')

bingo_list = [list(map(int,input().split())) for i in range(3)]
bingo_list = sum(bingo_list,[])
n = int(input())
bingo_number = [int(input())for i in range(n)]
check_list = [0 for i in range(9)]

for j in bingo_number:
    if j in bingo_list:
        check_list[bingo_list.index(j)] = 1

if [1,1,1]in [check_list[:3],check_list[3:6],check_list[6:],
             check_list[0:7:3],check_list[1:8:3]check_list[2:9:3],
             check_list[0:9:4],check_list[2:7:2]]:
    print('Yes')
else:
    print('No')

bingo_list = [list(map(int,input().split())) for i in range(3)]
bingo_list = sum(bingo_list,[])
n = int(input())
bingo_number = [int(input())for i in range(n)]
check_list = [0 for i in range(9)]

for j in bingo_number:
    if j in bingo_list:
        check_list[bingo_list.index(j)] = 1

if  [1,1,1]  in [check_list[:3], check_list[3:6], check_list[6:], check_list[0:7:3], check_list[1:8:3],check_list[2:9:3],check_list[0:9:4],check_list[2:7:2]]:
    print('Yes')
else:
    print('No')

Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
a = [list(map(int, input().split())) for _ in range(3)]
n = int(input())
b = [int(input()) for _ in range(n)]
bingo = [[0 for _ in range(3)] for _ in range(3)]
print(bingo)
for i in range(n):
    for j in range(3):
        for k in range(3):
            if a[j][k] == b[i]:
                bingo[j][k] = True
if (bingo[0][0] and bingo[1][0] and bingo[2][0]) or (bingo[0][1] and bingo[1][1] and bingo[2][1]) or (bingo[0][2] and bingo[1][2] and bingo[2][2]):
    print('Yes')
elif (bingo[0][0] and bingo[0][1] and bingo[0][2]) or (bingo[1][0] and bingo[1][1] and bingo[1][2]) or (bingo[2][0] and bingo[2][1] and bingo[2][2]):
    print('Yes')
elif (bingo[0][0] and bingo[1][1] and bingo[2][2]) or (bingo[0][2] and bingo[1][1] and bingo[2][0]):
    print('Yes')
else:
    print('No')


a = [list(map(int, input().split())) for _ in range(3)]
n = int(input())
b = [int(input()) for _ in range(n)]
bingo = [[0 for _ in range(3)] for _ in range(3)]

for i in range(n):
    for j in range(3):
        for k in range(3):
            if a[j][k] == b[i]:
                bingo[j][k] += 1

for i in range(3):
    if bingo[0][i] * bingo[1][i] * bingo[2][i] > 0:
        print('Yes')
        exit()
for i in range(3):
    if bingo[i][0] * bingo[i][1] * bingo[i][2] > 0:
        print('Yes')
        exit()
if bingo[0][0] * bingo[1][1] * bingo[2][2] > 0:
    print('Yes')
    exit()
if bingo[0][2] * bingo[1][1] * bingo[2][0] > 0:
    print('Yes')
    exit()
print('No')


Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
import numpy as np

A = []
for _ in range(3):
    A.append(list(map(int, input().split())))
N = input()
N = int(N)
B = []
for _ in range(N):
    b = input()
    B.append(int(b))
npA = np.array(A)
check = 'no'
for a in npA:
    if a[0] in B and a[1] in B and a[2] in B:
        check = 'yes'
for a in npA.T:
    if a[0] in B and a[1] in B and a[2] in B:
        check = 'yes'
dia = np.diag(npA)
if dia[0] in B and dia[1] in B and dia[2] in B:
    check = 'yes'
diaT = np.diag(np.fliplr(npA))
if diaT[0] in B and diaT[1] in B and diaT[2] in B:
    check = 'yes'
print(check)

import numpy as np

A = []
for _ in range(3):
    A.append(list(map(int, input().split())))
N = input()
N = int(N)
B = []
for _ in range(N):
    b = input()
    B.append(int(b))
npA = np.array(A)
check = 'No'
for a in npA:
    if a[0] in B and a[1] in B and a[2] in B:
        check = 'Yes'
for a in npA.T:
    if a[0] in B and a[1] in B and a[2] in B:
        check = 'Yes'
dia = np.diag(npA)
if dia[0] in B and dia[1] in B and dia[2] in B:
    check = 'Yes'
diaT = np.diag(np.fliplr(npA))
if diaT[0] in B and diaT[1] in B and diaT[2] in B:
    check = 'Yes'
print(check)

Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
row_1 = list(map(int, input().split()))
row_2 = list(map(int, input().split()))
row_3 = list(map(int, input().split()))
N = int(input())
numbers_called = []
for i in range(N):
    b = int(input())
    numbers_called.append(b)

col_1 = [row_1[0], row_2[0], row_3[0]]
col_2 = [row_1[1], row_2[1], row_3[1]]
col_3 = [row_1[2], row_2[2], row_3[2]]
diagonal = [row_1[0], row_2[1], row_3[2]]
anti_diagonal = [[row_3[0], row_2[1], row_1[0]]]

winning_combinations = [row_1, row_2, row_3, col_1, col_2, col_3, diagonal, anti_diagonal]
for combination in winning_combinations:
    for number in combination:
        is_bingo = True
        if number not in numbers_called:
            is_bingo = False
        
        if is_bingo:
            print('Yes')
print('No')

row_1 = list(map(int, input().split()))
row_2 = list(map(int, input().split()))
row_3 = list(map(int, input().split()))
N = int(input())
numbers_called = []
for i in range(N):
    b = int(input())
    numbers_called.append(b)

col_1 = [row_1[0], row_2[0], row_3[0]]
col_2 = [row_1[1], row_2[1], row_3[1]]
col_3 = [row_1[2], row_2[2], row_3[2]]
diagonal = [row_1[0], row_2[1], row_3[2]]
anti_diagonal = [row_3[0], row_2[1], row_1[2]]

winning_combinations = [row_1, row_2, row_3, col_1, col_2, col_3, diagonal, anti_diagonal]

is_bingo = False
for combination in winning_combinations:
    # check if every number for this combination has been called
    is_bingo = all([number in numbers_called for number in combination])
    
    if is_bingo:
        break


if is_bingo:
    print('Yes')
else:
    print('No')

Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
a_1 = list(map(int,input().split()))
a_2 = list(map(int,input().split()))
a_3 = list(map(int,input().split()))
a = [a_1,a_2,a_3]
n = int(input())
for i in range(n):
  h = int(input())
  for j in range(3):
    for k in range(3):
      if(a[j][k]==h):
        a[j][k]=0
ans = "No"
for i in range(3):
  if(len(set(a[i]+[0]))==1):
    ans = "Yes"
for i in range(3):
  if(len(set([a[0][i],a[1][i],a[2][i],[0]]))==1):
    ans= "Yes"
if((a[0][0]==0)and(a[1][1]==a[2][2])and(a[0][0]==a[1][1]))or((a[0][2]==0)and(a[1][1]==a[2][0])and(a[0][2]==a[1][1])):
  ans = "Yes"
  
print(ans)
    


a_1 = list(map(int,input().split()))
a_2 = list(map(int,input().split()))
a_3 = list(map(int,input().split()))
a = [a_1,a_2,a_3]
n = int(input()):
for i in range(n):
  h = int(input())
  for j in range(3):
    for k in range(3):
      if(a[j][k]==h):
        a[j][k]=0
ans = "No"
for i in range(3):
  if(a[i][0]==0)and(a[i][0]==a[i][1])and(a[i][1]==a[i][2]):
    ans = "Yes"
for i in range(3):
  if(a[0][i]==0)and(a[0][i]==a[1][i])and(a[1][i]==a[2][i]):
    ans= "Yes"
if((a[0][0]==0)and(a[1][1]==a[2][2])and(a[0][0]==a[1][1]))or((a[0][2]==0)and(a[1][1]==a[2][0])and(a[0][2]==a[1][1])):
  ans = "Yes"
  
print(ans)
    
    

a_1 = list(map(int,input().split()))
a_2 = list(map(int,input().split()))
a_3 = list(map(int,input().split()))
a = [a_1,a_2,a_3]
n = int(input())
for i in range(n):
  h = int(input())
  for j in range(3):
    for k in range(3):
      if(a[j][k]==h):
        a[j][k]=0
ans = "No"
for i in range(3):
  if(a[i][0]==0)and(a[i][0]==a[i][1])and(a[i][1]==a[i][2]):
    ans = "Yes"
for i in range(3):
  if(a[0][i]==0)and(a[0][i]==a[1][i])and(a[1][i]==a[2][i]):
    ans= "Yes"
if((a[0][0]==0)and(a[1][1]==a[2][2])and(a[0][0]==a[1][1]))or((a[0][2]==0)and(a[1][1]==a[2][0])and(a[0][2]==a[1][1])):
  ans = "Yes"
  
print(ans)
    
    


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
map_list = [int,input().split() for x in range(3)]

n = int(input())
for i in range(n):
  a = int(input())
  

map_list = [list(map(int,input().split())) for x in range(3)]
 
n = int(input())
for i in range(n):
  a = int(input())
  for i in range(3):
    for j in range(3):
      if map_list[i][j] == a:
        map_list[i][j] = 0

ans = "No"
for k in range(3):
  if map_list[0][k] == map_list[1][k] == map_list[2][k] or \
     map_list[k][0] == map_list[k][1] == map_list[k][2]:
      ans = "Yes"
      break
  if map_list[0][0] == map_list[1][1] == map_list[2][2] or \
	 map_list[0][2] == map_list[1][1] == map_list[2][0]:
      ans = "Yes"
print(ans)

Verdicts: Runtime Error

Accepted