TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: You are given strings S and T consisting of lowercase English letters.  You can perform the following operation on S any number of times:  Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.  Determine if S and T can be made equal by performing the operation zero or more times.

Submission attempts (in order):
import numpy as np

s=input()
t=input()
s_cnt=np.zeros(26)
s_letterPlace=[[] for _ in range(26)]
for i,si in enumerate(s):
    num=ord(si)-ord('a')
    s_cnt[num]+=1
    s_letterPlace[num].append(i)

s_multiLetter=[]
for cnt,place in zip(s_cnt,s_letterPlace):
    if cnt>1:
        s_multiLetter.append(place)

t_cnt=np.zeros(26)
t_letterPlace=[[] for _ in range(26)]
for i,ti in enumerate(t):
    num=ord(ti)-ord('a')
    t_cnt[num]+=1
    t_letterPlace[num].append(i)

t_multiLetter=[]
for cnt,place in zip(t_cnt,t_letterPlace):
    if cnt>1:
        t_multiLetter.append(place)
print(len(s_multiLetter))
print(len(t_multiLetter))

flag=1
if len(s_multiLetter)!=len(t_multiLetter):
    flag=0
else:
    for s_place in s_multiLetter:
        if(flag==1):
            for t_place in t_multiLetter:
                if(s_place==t_place):
                    flag=1
                    break
                else:
                    flag=0

print('Yes' if flag==1 else 'No')

import numpy as np

s=input()
t=input()
s_cnt=np.zeros(26)
s_letterPlace=[[] for _ in range(26)]
for i,si in enumerate(s):
    num=ord(si)-ord('a')
    s_cnt[num]+=1
    s_letterPlace[num].append(i)

s_multiLetter=[]
for cnt,place in zip(s_cnt,s_letterPlace):
    if cnt>1:
        s_multiLetter.append(place)

t_cnt=np.zeros(26)
t_letterPlace=[[] for _ in range(26)]
for i,ti in enumerate(t):
    num=ord(ti)-ord('a')
    t_cnt[num]+=1
    t_letterPlace[num].append(i)

t_multiLetter=[]
for cnt,place in zip(t_cnt,t_letterPlace):
    if cnt>1:
        t_multiLetter.append(place)
# print(len(s_multiLetter))
# print(len(t_multiLetter))

flag=1
if len(s_multiLetter)!=len(t_multiLetter):
    flag=0
elif len(s_multiLetter)==0 & len(t_multiLetter)==0:
    flag=1
elif len(s_multiLetter)*len(t_multiLetter)==0:
    flag=0
else:
    for s_place in s_multiLetter:
        if(flag==1):
            for t_place in t_multiLetter:
                if(s_place==t_place):
                    flag=1
                    break
                else:
                    flag=0

print('Yes' if flag==1 else 'No')

Verdicts: Wrong Answer

Accepted
Problem: You are given strings S and T consisting of lowercase English letters.  You can perform the following operation on S any number of times:  Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.  Determine if S and T can be made equal by performing the operation zero or more times.

Submission attempts (in order):
import sys
import defaultdict
input=sys.stdin.readline()
s=input().rstrip()
t=input().rstrip()
dct=defaultdict(int)
for i in range(len(s)):
  if not dct[s[i]]:
    dct[s[i]]=t[i]
  elif dct[s[i]]!=t[i]:
    print("No")
    exit()
ls=[]
for i in dct.values():
  if i in ls:
    print("No")
    exit()
  else:
    ls.append(i)
print("Yes")

from collections import defaultdict
s=input()
t=input()
dct=defaultdict(int)
for i in range(len(s)):
  if not dct[s[i]]:
    dct[s[i]]=t[i]
  elif dct[s[i]]!=t[i]:
    print("No")
    exit()
ls=[]
for i in dct.values():
  if i in ls:
    print("No")
    exit()
  else:
    ls.append(i)
print("Yes")

Verdicts: Runtime Error

Accepted
Problem: You are given strings S and T consisting of lowercase English letters.  You can perform the following operation on S any number of times:  Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.  Determine if S and T can be made equal by performing the operation zero or more times.

Submission attempts (in order):
S = input()
T = input()
alphabet_pairs = [None] * 26

def convert_alphabet_to_int(s):
  return ord(s) - ord('a')


for i, s in enumerate(S):
  t = T[i]
  int_s = convert_alphabet_to_int(s)
  int_t = convert_alphabet_to_int(t)
  alphabet_pairs[int_s] = int_t
  alphabet_pairs[int_t] = int_s
print(alphabet_pairs)
new_T = ''
for i, s in enumerate(S):
  string = chr(ord('a') + alphabet_pairs[convert_alphabet_to_int(s)])
  print(string)
  new_T += string
print(new_T, T)
print(len(new_T), len(T))
if new_T == T:
  print('Yes')
else:
  print('No')
    
  

S = input()
T = input()
s_pairs = [-1] * 26
t_pairs = [-1] * 26

def convert_alphabet_to_int(s):
  return ord(s) - ord('a')


for i, s in enumerate(S):
  t = T[i]
  int_s = convert_alphabet_to_int(s)
  int_t = convert_alphabet_to_int(t)
  if s_pairs[int_s] >= 0:
    if s_pairs[int_s] != int_t:
      print('No')
      exit()
  else:
    s_pairs[int_s] = int_t
  
  if t_pairs[int_t] >= 0:
    if t_pairs[int_t] != int_s:
      print('No')
      exit()
  else:
    t_pairs[int_t] = int_s
print('Yes')
    
  

Verdicts: Wrong Answer

Accepted
Problem: You are given strings S and T consisting of lowercase English letters.  You can perform the following operation on S any number of times:  Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.  Determine if S and T can be made equal by performing the operation zero or more times.

Submission attempts (in order):
# 2019/08/16

s=list(input())
t=list(input())

c1={}
c2={}
for ss,tt in zip(s,t):
    c1[ss]=c1.get(ss,'')+tt
    c2[tt]=c2.get(tt,'')+ss
    if len(c1[ss])<2 and len(c2[tt])<2:continue
    if set(c1[ss])==ss and set(c2[tt])==tt:continue
    else:
        print('No')
        exit()

print('Yes')


# 2019/08/16

s=list(input())
t=list(input())

c1={}
c2={}
for ss,tt in zip(s,t):
    if c1.get(ss) is None:
        c1[ss]=tt
    if c2.get(tt) is None:
        c2[tt]=ss
    if c1[ss]==tt and c2[tt]==ss:continue
    else:
        print('No')
        exit()

print('Yes')


Verdicts: Wrong Answer

Accepted
Problem: You are given strings S and T consisting of lowercase English letters.  You can perform the following operation on S any number of times:  Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.  Determine if S and T can be made equal by performing the operation zero or more times.

Submission attempts (in order):
def list_check2(list1, list2):
    return set(list1).issubset(list2)
s = input()
t = input()
s_list = [x for x in s]
stra = 'ae'
ss_list = []
for i in s_list:
    if stra != i:
        ss_list.append(i)
    stra = i
stra = 'ae'
tt_list = []
xxx = [x for x in t]
for i in xxx:
    if stra != i:
        tt_list.append(i)
    stra = i
if list_check2(tt_list,ss_list):
    print("Yes")
else:
    print("No")

def list_check2(list1, list2):
    return set(list1).issubset(list2)
s = input()
t = input()
s_list = [x for x in s]
stra = 'ae'
ss_list = []
for i in s_list:
    if stra != i:
        ss_list.append(i)
    stra = i
stra = 'ae'
tt_list = []
xxx = [x for x in t]
for i in xxx:
    if stra != i:
        tt_list.append(i)
    stra = i
if list_check2(tt_list,ss_list):
    print("Yes")
else:
    print("No")

s = input()
t = input()
check = {}
ans = 0
for i in range(len(s)):
    if s[i] in check.keys():
        if t[i] != check[s[i]]:
            ans = 1
            break
    else:
        check[s[i]] = t[i]
if ans == 1 or len(check.values()) != len(set(check.values())):
    print('No')
else:
    print('Yes')

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: You are given strings S and T consisting of lowercase English letters.  You can perform the following operation on S any number of times:  Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.  Determine if S and T can be made equal by performing the operation zero or more times.

Submission attempts (in order):
S=input()
T=input()

Sc=[[] for i in range(26)]
Tc=[[] for i in range(26)]

for i in range(len(S)):
    Sc[ord(S[i])-97].append(i)
for i in range(len(S)):
    Tc[ord(T[i])-97].append(i)
print(Sc)
print(Tc)

for i in range(len(S)):
    if(Sc[ord(S[i])-97]!=Tc[ord(T[i])-97]):
        print("No")
        exit()
print("Yes")

from collections import Counter
S=input()
T=input()
cS=Counter(S).most_common()
cT=Counter(T).most_common()

for k,j in zip(cS,cT):
    if(k[1]!=j[1]):
        print("No")
        exit()
print("Yes")

Verdicts: Wrong Answer

Accepted
Problem: You are given strings S and T consisting of lowercase English letters.  You can perform the following operation on S any number of times:  Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.  Determine if S and T can be made equal by performing the operation zero or more times.

Submission attempts (in order):
S = input()
T = input()

ans = "Yes"
s2t = {}
for s, t in zip([S, T]):
  if s == t:
    pass
  else:
    if s in s2t:
      if s2t[s] != t:
        ans = "No"
    else:
      s2t[s] = t

print(ans)


import sys
from collections import Counter

input = sys.stdin.readline


def main():
    S = input().rstrip()
    T = input().rstrip()

    c_S = Counter(S)
    c_T = Counter(T)
    count_S = list(c_S.values())
    count_T = list(c_T.values())
    count_S.sort()
    count_T.sort()
    is_same = True
    for s, t in zip(count_S, count_T):
        if s != t:
            is_same = False
            break

    ans = "Yes" if is_same else "No"
    print(ans)


if __name__ == "__main__":
    main()


Verdicts: Runtime Error

Accepted
Problem: You are given strings S and T consisting of lowercase English letters.  You can perform the following operation on S any number of times:  Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.  Determine if S and T can be made equal by performing the operation zero or more times.

Submission attempts (in order):
s = input()
t = input()
d_s = dict()
d_t = dict()
for i in range(len(s)):
  if not s[i] in d:
    d_s[s[i]] = t[i]
  elif d_s[s[i]] != t[i]:
    print('No')
    exit()
  if not t[i] in d:
    d_t[t[i]] = s[i]
  elif d_t[t[i]] != s[i]:
    print('No')
    exit()
print('Yes')

s = input()
t = input()
d_s = dict()
d_t = dict()
for i in range(len(s)):
  if not s[i] in d_s:
    d_s[s[i]] = t[i]
  elif d_s[s[i]] != t[i]:
    print('No')
    exit()
  if not t[i] in d_t:
    d_t[t[i]] = s[i]
  elif d_t[t[i]] != s[i]:
    print('No')
    exit()
print('Yes')

Verdicts: Runtime Error

Accepted
Problem: You are given strings S and T consisting of lowercase English letters.  You can perform the following operation on S any number of times:  Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.  Determine if S and T can be made equal by performing the operation zero or more times.

Submission attempts (in order):
s = input()
t = input()
i = 0
flag = True
d = dict()
for i in range(len(s)):
    





#        if not t[i] in keys:

#    else:
#        d[s[i]] = t[i]
    if s[i] == t[i]:
        continue
    else:
        s.translate(str.maketrans({s[i]: t[i]}))
if s == t:
    flag =True
else:
    flag = False
if flag:
    print("Yes")
else:
    print("No")

s = input()
t = input()
i = 0
flag = True
d = dict()
for i in range(len(s)):
    





#        if not t[i] in keys:

#    else:
#        d[s[i]] = t[i]
    if s[i] == t[i]:
        continue
    else:
        s.translate(str.maketrans({s[i]: t[i]}))
        s.translate(str.maketrans({t[i]: s[i]}))
        
if s == t:
    flag =True
else:
    flag = False
if flag:
    print("Yes")
else:
    print("No")
    

s = input()
t = input()
flag = True
d1,d2 = dict(),dict()
for i in range(len(s)):
    if s[i] in d1:
        if d1[s[i]] != t[i]:
            flag = False
    else:
        d1[s[i]] = t[i]
        
for i in range(len(s)):
    if t[i] in d2:
        if d2[t[i]] != s[i]:
            flag = False
    else:
        d2[t[i]] = s[i]

if flag:
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: You are given strings S and T consisting of lowercase English letters.  You can perform the following operation on S any number of times:  Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.  Determine if S and T can be made equal by performing the operation zero or more times.

Submission attempts (in order):

def main():
    S = list(input())
    T = list(input())
    d = {}
    for k in set(T):
        d[k] = set()
    for s, t in zip(S, T):
        if s != t:
            d[t].add(s)
    if all([len(v) == 1 for v in d.values()]):
        print('Yes')
    else:
        print('No')

if __name__ == '__main__':
    main()



def main():
    S = list(input())
    T = list(input())
    d1 = {}
    d2 = {}
    for k in set(T):
        d1[k] = set()
    for k in set(S):
        d2[k] = set()
    for s, t in zip(S, T):
        d1[t].add(s)
        d2[s].add(t)
    if all([len(v) == 1 for v in d1.values()]) and all([len(v) == 1 for v in d2.values()]):
        print('Yes')
    else:
        print('No')

if __name__ == '__main__':
    main()


Verdicts: Wrong Answer

Accepted
Problem: You are given strings S and T consisting of lowercase English letters.  You can perform the following operation on S any number of times:  Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.  Determine if S and T can be made equal by performing the operation zero or more times.

Submission attempts (in order):
dict={
  'a':0,'b':1,'c':2,'d':3,'e':4,'f':5,'g':6,'h':7,'i':8,'j':9,'k':10,'l':11,'m':12,'n':13,'o':14,'p':15,'q':16,'r':17,'s':18,'t':19,'u':20,'v':21,'w':22,'x':23,'y':24,'z':25,
}
l1=['']*26
l2=['']*26
s1=input()
s2=input()
if s1=='azzel':
  exit()
f=0
for i in range(len(s1)):
  a=s1[i]
  b=s2[i]
  ind=dict[a]
  if l1[ind]=='':
    l1[ind]=b
  else:
    if l1[ind]!=b:
      f=1
      break
  ind=dict[b]
  if l2[ind]=='':
    l2[ind]=a
  else:
    if l2[ind]!=a:
      f=1
      break
if f==1:
  print('No')
else:
  print('Yes')

s1=input()
s2=input()
if s1=='azzel':
  exit()
for i in range(len(s2)):
  a=s1[i]
  b=s2[i]
  s1=s1.replace(a,'#')
  s1=s1.replace(b,'.')
  s1=s1.replace('#',b)
  s1=s1.replace('.',a)
if s1!=s2:
  print('No')
else:
  print('Yes')

import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time

sys.setrecursionlimit(10**7)
inf=10**20
mod=10**9+7

def LI(): return list(map(int,input().split()))
def I(): return int(input())
def LS(): return input().split()
def S(): return input()

def main():

  
  l=['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']

  l2=[list() for i in range(26)]
  l3=[list() for i in range(26)]

  s=S()
  t=S()

  for i in range(len(s)):
    if len(l2[l.index(s[i])])>0:
      if l2[l.index(s[i])][0]!=t[i]:
        return 'No'
    else:
      l2[l.index(s[i])].append(t[i])
    if len(l3[l.index(t[i])])>0:
      if l3[l.index(t[i])][0]!=s[i]:
        return 'No'
    else:
      l3[l.index(t[i])].append(s[i])

  return 'Yes'

print(main())


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: You are given strings S and T consisting of lowercase English letters.  You can perform the following operation on S any number of times:  Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.  Determine if S and T can be made equal by performing the operation zero or more times.

Submission attempts (in order):
from collections import Counter

S = list(input())
T = list(input())

if Counter(sorted(S)).values() == Counter(sorted(T)).values():
    print("Yes")
else:
    print("No")

from collections import Counter

S = input()
T = input()

if sorted(Counter(S).values()) == sorted(Counter(T).values()):
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Accepted
Problem: You are given strings S and T consisting of lowercase English letters.  You can perform the following operation on S any number of times:  Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.  Determine if S and T can be made equal by performing the operation zero or more times.

Submission attempts (in order):
s = list(set(sorted(input())))
t = list(set(sorted(input())))

cnt = 0

if len(s) != len(t):
    print('No')
    exit()

for i in range(len(s)):
    if s[i] != t[i]:
        cnt += 1

if cnt %2 == 0:
    print('Yes')
else:
    print('No')




s = sorted(list(set(input())))
t = sorted(list(set(input())))

cnt = 0

if len(s) != len(t):
    print('No')
    exit()

for i in range(len(s)):
    if s[i] != t[i]:
        cnt += 1

if cnt %2 == 0:
    print('Yes')
else:
    print('No')




from collections import Counter

s = input()
t = input()

S = sorted(Counter(s).values())
T = sorted(Counter(t).values())

if S==T:
    print('Yes')
else:
    print('No')

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: You are given strings S and T consisting of lowercase English letters.  You can perform the following operation on S any number of times:  Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.  Determine if S and T can be made equal by performing the operation zero or more times.

Submission attempts (in order):
S=input()
T=input()
pp=[]
for i in range(97,123):
  pp.append(i)
na=97
ans='Yes'
for i in range(len(S)):
  if pp[ord(S[i])-na]==ord(S[i]):
    pp[ord(S[i])-na]=ord(T[i])
  else:
    if pp[ord(S[i])-na]==ord(T[i]):
      pass
    else:
      ans='No'
      break
if len(pp)!=len(set(pp)):
  ans='No'
print(ans)

from collections import Counter
S=input()
T=input()
SS=Counter(S)
TT=Counter(T)
if sorted(SS.values())==sorted(TT.values()):
  print('Yes')
else:
  print('No')

Verdicts: Wrong Answer

Accepted
Problem: You are given strings S and T consisting of lowercase English letters.  You can perform the following operation on S any number of times:  Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.  Determine if S and T can be made equal by performing the operation zero or more times.

Submission attempts (in order):
def string_transformation():
    s = input()
    t = input()

    f = True
    dep = {}

    for sc,tc in zip(s,t):
        if dep.get(tc) is not None or (dep.get(tc) != sc and sc in dep.values()):
            print("No")
            f = False
            break
        else:
            dep[tc] = sc

    if f:
        print("Yes")

if __name__ == "__main__":
    string_transformation()

def string_transformation():
    s = input()
    t = input()

    f = True
    dep = {}

    for sc,tc in zip(s,t):
        if (dep.get(tc) is not None or sc in dep.values()) and sc != dep.get(tc):
            print("No")
            f = False
            break
        else:
            dep[tc] = sc

    if f:
        print("Yes")

if __name__ == "__main__":
    string_transformation()

Verdicts: Wrong Answer

Accepted
Problem: You are given strings S and T consisting of lowercase English letters.  You can perform the following operation on S any number of times:  Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.  Determine if S and T can be made equal by performing the operation zero or more times.

Submission attempts (in order):
from sys import stdin
import fractions

s = stdin.readline().rstrip()
t = stdin.readline().rstrip()
sli = []
li = []
for i in range(len(s)):
    sli.append(s[i])
    if s[i] != t[i]:
        li.append((s[i],t[i]))
li.sort()
sli = list(set(sli))

for i in range(len(li)-1):
    if li[i][0] == li[i+1][0]:
        if li[i][1] != li[i+1][1]:
            print("No")
            exit()
    if li[i][1] not in sli:
        print("No")
        exit()

li.sort(key=lambda x:(x[1]))

for i in range(len(li)-1):
    if li[i][0] != li[i+1][0]:
        if li[i][1] == li[i+1][1]:
            print("No")
            exit()

print("Yes")

s = input()
t = input()

dic = {}
dic2 = {}

for i,j in zip(s,t):
    if j not in dic:
        if i in dic2:
            print("No")
            exit()
        dic[j] = i
        dic2[i] = j
    else:
        if dic[j] != i:
            print("No")
            exit()
print("Yes")

Verdicts: Wrong Answer

Accepted
Problem: You are given strings S and T consisting of lowercase English letters.  You can perform the following operation on S any number of times:  Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.  Determine if S and T can be made equal by performing the operation zero or more times.

Submission attempts (in order):
S = input()
T = input()

if set(S) == set(T):
  print("Yes")
else:print("No")

S = input()
T = input()

con = 0

ans = "Yes"

for i in range(0,len(S)):
  cutS = S[i+1:]
  cutT = T[i+1:]
  if S[i] in cutS:
    print(S[i],cutS)
    j = cutS.index(S[i]) + (i + 1)
    print(T[i],T[j])
    if T[i] != T[j]:
      ans = "No"
      break
  if T[i] in cutT:
    k = cutT.index(T[i]) + (i + 1)
    if S[i] != S[k]:
      ans = "No"
      break

print(ans)

from collections import Counter

S = input()
T = input()

s = Counter(S)
t = Counter(T)


if (s.values())==(t.values()):
    print('Yes')
else:
    print('No')

S = input()
T = input()

con = 0

ans = "Yes"

for i in range(0,len(S)):
  for j in range(0,i):
    if T[i] == T[j]:
      if S[i] != S[j]:
        ans = "No"
        break
      break
    if S[i] == S[j]:
      if T[i] != T[j]:
        ans = "No"
        break
      break


print(ans)



Verdicts: Wrong Answer

Runtime Error

Wrong Answer

Accepted
Problem: You are given strings S and T consisting of lowercase English letters.  You can perform the following operation on S any number of times:  Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.  Determine if S and T can be made equal by performing the operation zero or more times.

Submission attempts (in order):
def check():
    s=input()
    t=input()

    d={}

    for i in range(len(s)):
        si=s[i]
        ti=t[i]
        if not si in d:
            d[si]=ti
        else:
            if d[si]==ti:
                continue
            else:
                return "No"
            
    vals=d.values()
    if len(vals)==len(set(vals)):
        return "Yes"
    else:
        return "No"
    

from collections import defaultdict
S = input()
T = input()

s_to_t = defaultdict(set)
t_to_s = defaultdict(set)

for s, t in zip(S, T):
    s_to_t[s].add(t)
    t_to_s[t].add(s)

for v in s_to_t.values():
    if len(v) > 1:
        print("No")
        exit()
for v in t_to_s.values():
    if len(v) > 1:
        print("No")
        exit()
print("Yes")


Verdicts: Wrong Answer

Accepted
Problem: You are given strings S and T consisting of lowercase English letters.  You can perform the following operation on S any number of times:  Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.  Determine if S and T can be made equal by performing the operation zero or more times.

Submission attempts (in order):
import collections

s=list(input())
t=list(input())

ss=collections.Counter(s)
tt=collections.Counter(t)

s_v = ss.values().sorted()
t_v = tt.values().sorted()

if s_v == t_v:
    print("Yes")
else:
    print("No")


import collections

s=list(input())
t=list(input())

ss=collections.Counter(s)
tt=collections.Counter(t)

s_v = sorted(ss.values())
t_v = sorted(tt.values())

if s_v == t_v:
    print("Yes")
else:
    print("No")


Verdicts: Runtime Error

Accepted
Problem: You are given positive integers N and M.  How many sequences a of length N consisting of positive integers satisfy a_1 \times a_2 \times ... \times a_N = M? Find the count modulo 10^9+7.  Here, two sequences a' and a'' are considered different when there exists some i such that a_i' \neq a_i''.

Submission attempts (in order):
import sys
input = sys.stdin.readline

N, M = (int(i) for i in input().split())

def soin(N):
	res = []
	i = 2
	while i < round(N**(1/2)) + 3:
		if N%i == 0:
			res.append(i)
			N = N//i
			i = 2
		else:
			i += 1
	if N != 1:
		res.append(N)
	return res

def power(a, b):
	if b == 0:
		return 0
	elif b == 1:
		return a % 1000000007
	elif b % 2 == 0:
		return (power(a, b//2) ** 2) % 1000000007
	else:
		return (power(a, b//2) ** 2 * a) % 1000000007

def divide(a, b):
	return (a * power(b, 1000000005)) % 1000000007

def combination(a, b):
	res = 1
	for i in range(b):
		res *= a - i
		res = res % 1000000007
	for i in range(b):
		res = divide(res, i+1)
	return res
	
L = soin(M)
cc = 1
res = 1
for i in range(len(L) -1):
	if L[i] == L[i+1]:
		cc += 1
	else:
		res *= combination(N + cc -1, cc)
		res = res % 1000000007
		cc = 1
res *= combination(N+cc -1, cc)
res = res % 1000000007
print(res)
print(soin(6))

import sys
input = sys.stdin.readline

N, M = (int(i) for i in input().split())

def soin(N):
	res = []
	i = 2
	while i < round(N**(1/2)) + 3:
		if N%i == 0:
			res.append(i)
			N = N//i
			i = 2
		else:
			i += 1
	res.append(N)
	return res

def power(a, b):
	if b == 0:
		return 0
	elif b == 1:
		return a % 1000000007
	elif b % 2 == 0:
		return (power(a, b//2) ** 2) % 1000000007
	else:
		return (power(a, b//2) ** 2 * a) % 1000000007

def divide(a, b):
	return (a * power(b, 1000000005)) % 1000000007

def combination(a, b):
	res = 1
	for i in range(b):
		res *= a - i
		res = res % 1000000007
	for i in range(b):
		res = divide(res, i+1)
	return res
	
L = soin(M)
cc = 1
res = 1
for i in range(len(L) -1):
	if L[i] == L[i+1]:
		cc += 1
	else:
		res *= combination(N + cc -1, cc)
		res = res % 1000000007
		cc = 1
res *= combination(N+cc -1, cc)
res = res % 1000000007
print(res)

import sys
input = sys.stdin.readline

N, M = (int(i) for i in input().split())

def soin(N):
	res = []
	i = 2
	while i < round(N**(1/2)) + 3:
		if N%i == 0:
			res.append(i)
			N = N//i
			i = 2
		else:
			i += 1
	if N != 1:
		res.append(N)
	return res

def power(a, b):
	if b == 0:
		return 0
	elif b == 1:
		return a % 1000000007
	elif b % 2 == 0:
		return (power(a, b//2) ** 2) % 1000000007
	else:
		return (power(a, b//2) ** 2 * a) % 1000000007

def divide(a, b):
	return (a * power(b, 1000000005)) % 1000000007

def combination(a, b):
	res = 1
	for i in range(b):
		res *= a - i
		res = res % 1000000007
	for i in range(b):
		res = divide(res, i+1)
	return res
if M == 1:
	res = 1
else:
	L = soin(M)
	cc = 1
	res = 1
	for i in range(len(L) -1):
		if L[i] == L[i+1]:
			cc += 1
		else:
			res *= combination(N + cc -1, cc)
			res = res % 1000000007
			cc = 1
	res *= combination(N+cc -1, cc)
	res = res % 1000000007
print(res)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: You are given positive integers N and M.  How many sequences a of length N consisting of positive integers satisfy a_1 \times a_2 \times ... \times a_N = M? Find the count modulo 10^9+7.  Here, two sequences a' and a'' are considered different when there exists some i such that a_i' \neq a_i''.

Submission attempts (in order):
import collections

def factor(m):
  q = m
  r = []
  i = 2
  while i * i <= m:
    if q % i:
      i += 1
    else:
      r.append(i)
      q //= i
  return r

n, m = map(int, input().split())
p = 10 ** 9 + 7

r = factor(m)
v = collections.Counter(r)
c = 1
for value in v.values():
  temp = 1
  for i in range(value):
    temp *= value + n - 1 - i
  for i in range(value):
    temp //= i + 1
  temp %= p
  c = c * temp % p
print(c)
  
  
  

import collections

def factor(m):
  q = m
  r = []
  i = 2
  while i * i <= m:
    if q % i:
      i += 1
    else:
      r.append(i)
      q //= i
  if q != 1:
    r.append(q)
  return r

n, m = map(int, input().split())
p = 10 ** 9 + 7

r = factor(m)
v = collections.Counter(r)
c = 1
for value in v.values():
  temp = 1
  for i in range(value):
    temp *= value + n - 1 - i
  for i in range(value):
    temp //= i + 1
  temp %= p
  c = c * temp % p
print(c)
  
  
  

Verdicts: Wrong Answer

Accepted
Problem: You are given positive integers N and M.  How many sequences a of length N consisting of positive integers satisfy a_1 \times a_2 \times ... \times a_N = M? Find the count modulo 10^9+7.  Here, two sequences a' and a'' are considered different when there exists some i such that a_i' \neq a_i''.

Submission attempts (in order):
def framod(n,mod):
    a=1
    for i in range(1,n+1):
        a=a * i % mod
    return a

def power(n,r,mod):
    if r == 0: return 1
    if r%2 == 0:
        return power(n*n % mod, r//2, mod) % mod
    if r%2 == 1:
        return n * power(n, r-1, mod) % mod
    
def comb(n,k,mod):
    if n<0 or k<0 or n<k: return 0
    if n==0 or k==0: return 1
    a=framod(n,mod)
    b=framod(k,mod)
    c=framod(n-k,mod)
    return (a * power(b, mod-2, mod) * power(c, mod-2, mod)) % mod

n,m=map(int, input().split())

pf={}
for i in range(2,int(m**0.5)+1):
    while m%i==0:
        pf[i]=pf.get(i,0)+1
        m//=i
if m>1:pf[m]=1
    
mblist=list()
for i in pf:
    a = comb(pf[i]+n-1,pf[i],mod)
    mblist.append(a)
ans=1
for i in mblist:
    ans=(ans*i)%mod
print(ans)

from collections import Counter
def cmb(n, r, mod):
    if ( r<0 or r>n ):
        return 0
    r = min(r, n-r)
    return g1[n] * g2[r] * g2[n-r] % mod

mod = 10**9+7 
N = 10**5+1000
g1 = [1, 1] 
g2 = [1, 1] 
inverse = [0, 1] 計算用テーブル

for i in range( 2, N + 1 ):
    g1.append( ( g1[-1] * i ) % mod )
    inverse.append( ( -inverse[mod % i] * (mod//i) ) % mod )
    g2.append( (g2[-1] * inverse[-1]) % mod )

n,m=map(int, input().split())
mb=[]
while m>1:
    for i in range(2,m+1):
        if m%i==0:
            mb.append(i)
            m//=i
            break

mb2=Counter(mb)
    
mblist=list()
for i in mb2:
    a = cmb(mb2[i]+n-1,mb2[i],mod)
    mblist.append(a)
ans=1
for i in mblist:
    ans=(ans*i)%mod
print(ans)

def framod(n,mod):
    a=1
    for i in range(1,n+1):
        a=a * i % mod
    return a

def power(n,r,mod):
    if r == 0: return 1
    if r%2 == 0:
        return power(n*n % mod, r//2, mod) % mod
    if r%2 == 1:
        return n * power(n, r-1, mod) % mod
    
def comb(n,k,mod):
    if n<0 or k<0 or n<k: return 0
    if n==0 or k==0: return 1
    a=framod(n,mod)
    b=framod(k,mod)
    c=framod(n-k,mod)
    return (a * power(b, mod-2, mod) * power(c, mod-2, mod)) % mod

n,m=map(int, input().split())
pf={}
for i in range(2,int(m**0.5)+1):
    while m%i==0:
        pf[i]=pf.get(i,0)+1
        m//=i
if m>1:pf[m]=1

mod=10**9+7   
ans=1
for i in pf:
    ans=(ans * comb(pf[i]+n-1,pf[i],mod)) % mod
print(ans)

Verdicts: Runtime Error

Time Limit Exceeded

Accepted
Problem: You are given positive integers N and M.  How many sequences a of length N consisting of positive integers satisfy a_1 \times a_2 \times ... \times a_N = M? Find the count modulo 10^9+7.  Here, two sequences a' and a'' are considered different when there exists some i such that a_i' \neq a_i''.

Submission attempts (in order):
from math import sqrt, ceil, factorial
from collections import defaultdict


def prime_factors(n):
    i = 2
    factors = defaultdict(int)
    while i * i <= n:
        if n % i:
            i += 1
        else:
            n //= i
            factors[i] += 1
    if n > 1:
        factors[n] += 1
    return factors


N, M = [int(elem) for elem in input().split(' ')]


prime_numbers = prime_factors(M)
print(prime_numbers)
sum = 1
fac_N_m1 = factorial(N - 1)

for value in prime_numbers.values():
    bunshi = 1
    saisho = value + N - 1
    for _ in range(value):
        bunshi *= saisho
        saisho -= 1
    sum *= (bunshi // factorial(value))
print(sum % (10**9 + 7))



# space complexity: O(lgM)

from collections import defaultdict


def prime_factorize(num):
    prime_numbers = defaultdict(int)
    i = 2
    while i * i <= num:
        if num % i == 0:
            while num % i == 0:
                prime_numbers[i] += 1
                num //= i
        i += 1
    if num != 1:
        prime_numbers[num] += 1
    return prime_numbers


MOD = 10**9 + 7
N, M = [int(elem) for elem in input().split()]

prime_numbers = prime_factorize(M)

num_sequences = 1
for exponent in prime_numbers.values():
    denomimator = 1
    numerator = 1
    for i in range(1, exponent + 1):
        denomimator *= (N + exponent - i)
        numerator *= i
    num_sequences *= denomimator // numerator
    num_sequences %= MOD

print(num_sequences)



Verdicts: Wrong Answer

Accepted
Problem: You are given positive integers N and M.  How many sequences a of length N consisting of positive integers satisfy a_1 \times a_2 \times ... \times a_N = M? Find the count modulo 10^9+7.  Here, two sequences a' and a'' are considered different when there exists some i such that a_i' \neq a_i''.

Submission attempts (in order):
from operator import mul
from functools import reduce


n,m = map(int,input().split())
MOD = 10**9+7


def factorize(n):
    fct = [] 
    b, e = 2, 0
    while b*b <= n:
        while n % b == 0:
            n //= b
            e += 1
        if e > 0:
            fct.append((b,e))
        b, e = b+1, 0
    if n>1:
        fct.append((n,1))
    return fct


def nCr(n,r):
    r = min(r,n-r)
    if r == 0:
        return 1
    over = reduce(mul, range(n,n-r,-1))
    under = reduce(mul,range(1,r+1))
    return over // under

f = factorize(m)
ans=1
for p,num in f:
    ans *= nCb(num+n-1,num)
    ans %= 10**9+7
 
print(ans)

from operator import mul
from functools import reduce


n,m = map(int,input().split())
MOD = 10**9+7


def factorize(n):
    fct = [] 
    b, e = 2, 0
    while b*b <= n:
        while n % b == 0:
            n //= b
            e += 1
        if e > 0:
            fct.append((b,e))
        b, e = b+1, 0
    if n>1:
        fct.append((n,1))
    return fct


def nCr(n,r):
    r = min(r,n-r)
    if r == 0:
        return 1
    over = reduce(mul, range(n,n-r,-1))
    under = reduce(mul,range(1,r+1))
    return over // under

f = factorize(m)
ans=1
for p,num in f:
    ans *= nCr(num+n-1,num)
    ans %= MOD
    
print(ans)

Verdicts: Runtime Error

Accepted
Problem: You are given positive integers N and M.  How many sequences a of length N consisting of positive integers satisfy a_1 \times a_2 \times ... \times a_N = M? Find the count modulo 10^9+7.  Here, two sequences a' and a'' are considered different when there exists some i such that a_i' \neq a_i''.

Submission attempts (in order):
import sys

N, M = map(int, input().split())

factor = {}
tmp = 2
while(M // tmp >= 1):
    if(M % tmp != 0):
        if(tmp == 2):
            tmp += 1
        elif(M // tmp < tmp):
            tmp = M
        else:
            tmp += 2
        continue

    M = M // tmp
    factor[tmp] = factor.get(tmp, 0) + 1

if(factor == {}):
    pimport sys

N, M = map(int, input().split())

factor = {}
tmp = 2
while(M // tmp >= 1):
    if(M % tmp != 0):
        if(tmp == 2):
            tmp += 1rint(1)
    sys.exit()

ans = 1
max_a = 7 + 10 ** 9
max_value = max(list(factor.values()))
aho = {0: 1}
fact = {0: 1}
abc = {}
for i in range(1, max_value + 1):
    # print(i)
    aho[i] = ((aho[i - 1] * (i + N - 1)))
    fact[i] = (fact[i - 1] * i)
    abc[i] = (aho[i] // fact[i]) % max_a


# print(factor)
# print(aho, fact)
for i in factor.values():
    # print(i)
    ans = (ans * abc[i]) % max_a
print(ans)

import sys

N, M = map(int, input().split())

factor = {}
tmp = 2
while(M // tmp >= 1):
    if(M % tmp != 0):
        if(tmp == 2):
            tmp += 1
        elif(M // tmp < tmp):
            tmp = M
        else:
            tmp += 2
        continue

    M = M // tmp
    factor[tmp] = factor.get(tmp, 0) + 1

if(factor == {}):
    print(1)
    sys.exit()

ans = 1
max_a = 7 + 10 ** 9
max_value = max(list(factor.values()))
aho = {0: 1}
fact = {0: 1}
abc = {}
for i in range(1, max_value + 1):
    # print(i)
    aho[i] = ((aho[i - 1] * (i + N - 1)))
    fact[i] = (fact[i - 1] * i)
    abc[i] = (aho[i] // fact[i]) % max_a


# print(factor)
# print(aho, fact)
for i in factor.values():
    # print(i)
    ans = (ans * abc[i]) % max_a
print(ans)

Verdicts: Runtime Error

Accepted
Problem: You are given positive integers N and M.  How many sequences a of length N consisting of positive integers satisfy a_1 \times a_2 \times ... \times a_N = M? Find the count modulo 10^9+7.  Here, two sequences a' and a'' are considered different when there exists some i such that a_i' \neq a_i''.

Submission attempts (in order):
print(1)

n,m=map(int,input().split())
pem=1
if m==1:
    print(1)
def fctr2(n): 
    f=[]
    c=0
    r=int(n**0.5)
    for i in range(2,r+2):
        while n%i==0:
            c+=1
            n=n//i
        if c!=0:
            f.append(c)
            c=0
    if n!=1:
        f.append(1)
    return f

mod=10**9+7
fuc=[1]
def fucfun(n):
    for i in range(1,n):
        e=fuc[i-1]*i
        fuc.append(e%mod)
def com(n,k):
    com=(fuc[n]%mod)*pow(fuc[k],mod-2,mod)*pow(fuc[n-k],mod-2,mod)
    return com
f=fctr2(m)
if m!=1:
    a=max(f)+n
    fucfun(a)
    s=1
    for i in range(len(f)):
        t=com(f[i]+n-1,f[i])
        s=(s*t)%mod
    print(s)

Verdicts: Wrong Answer

Accepted
Problem: You are given positive integers N and M.  How many sequences a of length N consisting of positive integers satisfy a_1 \times a_2 \times ... \times a_N = M? Find the count modulo 10^9+7.  Here, two sequences a' and a'' are considered different when there exists some i such that a_i' \neq a_i''.

Submission attempts (in order):
def factorize(n):
    fct = []  
    b, e = 2, 0  
    while b * b <= n:
        while n % b == 0:
            n = n // b
            e = e + 1
        if e > 0:
            fct.append((b, e))
        b, e = b + 1, 0
    if n > 1:
        fct.append((n, 1))
    return fct

  
def cmb(n, r, mod):
    if ( r<0 or r>n ):
        return 0
    r = min(r, n-r)
    return g1[n] * g2[r] * g2[n-r] % mod
  
  
N,M = map(int, input().split())
m_factorized = factorize(M)
mod = 10 ** 9 + 7
g1 = [1, 1] 
g2 = [1, 1] 
inverse = [0, 1] 計算用テーブル
ans = 1
for i in range( 2, 2**N + 1 ):
  g1.append( ( g1[-1] * i ) % mod )
  inverse.append( ( -inverse[mod % i] * (mod//i) ) % mod )
  g2.append( (g2[-1] * inverse[-1]) % mod )
    
    
for i in m_factorized:
  k = i[1] 
  ans *= cmb(N-1+k,k,mod)
  ans %= mod
print(ans)
  

from functools import reduce
from operator import mul

def factorize(n):
    fct = []  
    b, e = 2, 0  
    while b * b <= n:
        while n % b == 0:
            n = n // b
            e = e + 1
        if e > 0:
            fct.append((b, e))
        b, e = b + 1, 0
    if n > 1:
        fct.append((n, 1))
    return fct

  
def cmb(n, r):
    
    r = min(n - r, r)
    if r == 0:
        return 1
    return reduce(mul, range(n, n - r, -1)) // reduce(mul, range(r, 0, -1))
  
  
N,M = map(int, input().split())
m_factorized = factorize(M)
mod = 10 ** 9 + 7

ans = 1

    
for i in m_factorized:
  k = i[1] 
  ans *= cmb(N-1+k,k)
  ans %= mod
print(ans)


Verdicts: Runtime Error

Accepted
Problem: You are given positive integers N and M.  How many sequences a of length N consisting of positive integers satisfy a_1 \times a_2 \times ... \times a_N = M? Find the count modulo 10^9+7.  Here, two sequences a' and a'' are considered different when there exists some i such that a_i' \neq a_i''.

Submission attempts (in order):
import math

N,M = map(int,input().split())

D = {}
m = M
for i in range(2, int M):
    while m % i == 0:
        D[i] = D.get(i,0)+1
        m = m//i

d = []
for v in D.values():
    d.append(v)

tmp = [0] * len(d)
for i in range(len(d)):
    tmp[i] = (math.factorial(N-1+d[i]) // (math.factorial(N-1)*math.factorial(d[i])))%(10**9 + 7)

ans = 1
for i in range(len(tmp)):
    ans = ans*tmp[i]%(10**9 +7)
print(ans)


N,M = map(int,input().split())

D = {}
m = M
for i in range(2, int(M**0.5)+2):
    while m % i == 0:
        D[i] = D.get(i,0)+1
        m = m//i
if D == {}:
    D[M] = 1

d = []
for v in D.values():
    d.append(v)

tmp = [0] * len(d)
for i in range(len(d)):
    tmp[i] = (math.factorial(N-1+d[i]) // (math.factorial(N-1)*math.factorial(d[i])))%(10**9 + 7)

ans = 1
for i in range(len(tmp)):
    ans = ans*tmp[i]%(10**9 +7)
print(ans)


N,M = map(int,input().split())

m = M
f = {}
while m%2==0:
    f[2] = f.get(2,0)+1
    m = m//2

l = int(m**0.5)+1
k = 3
while m != 1:
    if k>l:
        f[m] = f.get(m,0)+1
        break
    while m%k==0:
        f[k] = f.get(k,0)+1
        m = m//k
    k+=2
ans = 1
for k in f:
    for i in range(N-1+f[k],N-1,-1):
        ans = (ans * i) 
    for i in range(f[k]):
        ans = ans // (i+1)
    ans = ans % ((10**9)+7)
print(ans)


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: You are given positive integers N and M.  How many sequences a of length N consisting of positive integers satisfy a_1 \times a_2 \times ... \times a_N = M? Find the count modulo 10^9+7.  Here, two sequences a' and a'' are considered different when there exists some i such that a_i' \neq a_i''.

Submission attempts (in order):
# coding: utf-8
from collections import Counter


def ncr(n, r, mod):
    ret = 1
    for i in range(1, r+1):
        ret = (ret * (n-i+1) * pow(i, mod-2, mod)) % mod
    return ret


def solve(*args: str) -> str:
    n, m = map(int, args[0].split())
    mod = 10**9+7
    C = Counter()

    i = 2
    r = int(m**(1/2))
    while 1 < m:
        while m % i == 0:
            C[i] += 1
            m //= i
        if r < i:
            C[m] = 1
            break
        i += 1

    ret = 1
    for v, c in C.items():
        ret *= ncr(n+c-1, min(n-1, c), mod)
        ret %= mod

    return str(ret)


if __name__ == "__main__":
    print(solve(*(open(0).read().splitlines())))


# coding: utf-8
from collections import Counter


def ncr(n, r, mod):
    ret = 1
    for i in range(1, r+1):
        ret = (ret * (n-i+1) * pow(i, mod-2, mod)) % mod
    return ret


def solve(*args: str) -> str:
    n, m = map(int, args[0].split())
    mod = 10**9+7
    C = Counter()

    i = 2
    r = -int(-m**(1/2)//1)
    while 1 < m:
        while m % i == 0:
            C[i] += 1
            m //= i
        if r < i:
            C[m] = 1
            break
        i += 1

    ret = 1
    for v, c in C.items():
        ret *= ncr(n+c-1, min(n-1, c), mod)
        ret %= mod

    return str(ret)


if __name__ == "__main__":
    print(solve(*(open(0).read().splitlines())))


Verdicts: Wrong Answer

Accepted
Problem: You are given positive integers N and M.  How many sequences a of length N consisting of positive integers satisfy a_1 \times a_2 \times ... \times a_N = M? Find the count modulo 10^9+7.  Here, two sequences a' and a'' are considered different when there exists some i such that a_i' \neq a_i''.

Submission attempts (in order):
from collections import Counter
Q = 10**9+7
def primes(n):
    primfac = []
    d = 2
    while d*d <= n:
        while (n % d) == 0:
            primfac.append(d)  # supposing you want multiple factors repeated
            n //= d
        d += 1
    if n > 1:
       primfac.append(n)
    return primfac

def factorial(n):
    P = 1
    for i in range(1,n+1):
        P *= i
    return P

def combination(a,b):
    return int( (factorial(a)/factorial(b))/factorial(a-b))%Q
N, M = map( int, input().split())
C = Counter( primes(M))
ans = 1
print(C)
if N == 1:
    print(1)
else:
    for x in C:
        ans = (ans * combination(C[x]+N-1,N-1))%Q
    print(ans)


from math import factorial
Q = 10**9+7
def primes(n):
    primfac = [0]
    d = 2
    while d*d <= n:
        while n%d == 0:
            primfac[-1] += 1
            n //= d
        d += 1
        if primfac[-1] != 0:
            primfac.append(0)
    if n > 1:
        if primfac[-1] == 0:
            primfac[-1] += 1
        else:
            primfac.append(1)
    return primfac
N, M = map( int, input().split())
C = primes(M)
ans = 1
if N == 1:
    print(1)
else:
    for x in C:
        for i in range(x):
            ans *= N+i
        ans //= factorial(x)
        ans = ans%Q
    print(ans)


Verdicts: Wrong Answer

Accepted
Problem: You are given positive integers N and M.  How many sequences a of length N consisting of positive integers satisfy a_1 \times a_2 \times ... \times a_N = M? Find the count modulo 10^9+7.  Here, two sequences a' and a'' are considered different when there exists some i such that a_i' \neq a_i''.

Submission attempts (in order):
N, M = map(int, input().split())
rec = []
MOD = 10 ** 9 + 7
K = M
for i in range(2, int(M ** 0.5) + 1):
    if K % i == 0:
        tmp = 0
        while K % i == 0:
            tmp += 1
            K //= i

        rec.append((i, tmp))

Q = 10 ** 6 + 1
fact = [0] * Q
rfact = [0] * Q
fact[0] = 1
for i in range(1, Q):
    fact[i] = fact[i - 1] * i % MOD

rfact[Q - 1] = pow(fact[Q - 1], MOD - 2, MOD)
for i in range(Q - 2, -1, -1):
    rfact[i] = rfact[i + 1] * (i + 1) % MOD


def comb(n, r):
    return fact[n] * rfact[n - r] * rfact[r] % MOD


num = 1
for i in range(len(rec)):
    num *= comb(N + rec[i][1] - 1, rec[i][1])
    num %= MOD

print(num)


N, M = map(int, input().split())
rec = []
MOD = 10 ** 9 + 7
K = M
for i in range(2, int(M ** 0.5) + 1):
    if K % i == 0:
        tmp = 0
        while K % i == 0:
            tmp += 1
            K //= i

        rec.append((i, tmp))

if K != 1:
    rec.append((K, 1))
Q = 10 ** 6 + 1
fact = [0] * Q
rfact = [0] * Q
fact[0] = 1
for i in range(1, Q):
    fact[i] = fact[i - 1] * i % MOD

rfact[Q - 1] = pow(fact[Q - 1], MOD - 2, MOD)
for i in range(Q - 2, -1, -1):
    rfact[i] = rfact[i + 1] * (i + 1) % MOD


def comb(n, r):
    return fact[n] * rfact[n - r] * rfact[r] % MOD


num = 1
for i in range(len(rec)):
    num *= comb(N + rec[i][1] - 1, rec[i][1])
    num %= MOD

print(num)


Verdicts: Wrong Answer

Accepted
Problem: You are given positive integers N and M.  How many sequences a of length N consisting of positive integers satisfy a_1 \times a_2 \times ... \times a_N = M? Find the count modulo 10^9+7.  Here, two sequences a' and a'' are considered different when there exists some i such that a_i' \neq a_i''.

Submission attempts (in order):
def factorization(n):
    arr = []
    temp = n
    for i in range(2, int(-(-n**0.5//1))+1):
        if temp%i==0:
            cnt=0
            while temp%i==0:
                cnt+=1
                temp //= i
            arr.append([i, cnt])

    if temp!=1:
        arr.append([temp, 1])

    if arr==[]:
        arr.append([n, 1])

    return arr
n,m=map(int,input().split())
mod=10**9+7

a=factorization(m)
ans=1
for i in a:
    k=i[1]
    t=1
    for j in range(n+1,n+k-1+1):
        t*=j
    for j in range(1,n+1):
        t=t//j
    ans*=t
    ans%=mod
print(ans)


#!/usr/bin/env python3
import sys

MOD = 1000000007  # type: int
def comb(n, k):
    k = min(n-k,k)
    ans = 1
    for i in range(1, k + 1):
        ans = (ans * (n + 1 - i) // i)
    return ans

def prime_decomposition(n):
    i = 2
    table = []
    while i * i <= n:
        while n % i == 0:
            n //= i
            table.append(i)
        i += 1
    if n > 1:
        table.append(n)

    return table

def solve(N: int, M: int):
    from collections import Counter
    primes = prime_decomposition(M)

    counter = Counter(primes)
    answer = 1
    for count in counter.values():
        answer *= comb(count+N-1,count)
        answer %= MOD
    
    print(answer)
    return


def main():
    def iterate_tokens():
        for line in sys.stdin:
            for word in line.split():
                yield word
    tokens = iterate_tokens()
    N = int(next(tokens))  # type: int
    M = int(next(tokens))  # type: int
    solve(N, M)

if __name__ == '__main__':
    main()


Verdicts: Wrong Answer

Accepted