TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: Ibis is fighting with a monster.  The _health_ of the monster is H.  Ibis can cast N kinds of spells. Casting the i-th spell decreases the monster's health by A_i, at the cost of B_i Magic Points.  The same spell can be cast multiple times. There is no way other than spells to decrease the monster's health.  Ibis wins when the health of the monster becomes 0 or below.  Find the minimum total Magic Points that have to be consumed before winning.

Submission attempts (in order):
H, N = map(int, input().split())

C = [0]*N
for i in range(N):
  a,b = map(int, input().split())
  cp = b/a
  C[i]=[a,b,b/a]

print(C)
def battle(hp,magic):
  print(hp,magic,end=' ')
  if hp==0:
    return magic
  for i,[a,b,cp] in enumerate(C):
    if a>hp:
      C[i][0]=hp
      C[i][2]=b/hp
  C.sort(key=lambda x:x[2])
  print(*C[0])
  a,b,cp = C[0]
  num = hp//a
  hp -= a*num
  magic += b*num
  return battle(hp,magic)

magic = 0
ans = battle(H,magic)
print(ans)

import numpy as np
import numba
from numba import njit, b1, i4, i8, f8

@njit((i8,i8,i8[:],i8[:]), cache=True)
def main(H,N,A,B):
  INF = 1<<30
  dp = np.full(H+1,INF,np.int64)
  dp[0] = 0
  for i in range(N):
    for h in range(A[i],H):
      dp[h] = min(dp[h],dp[h-A[i]]+B[i])
    dp[H] = min(dp[H],min(dp[H-A[i]:H]+B[i]))
  ans = dp[-1]
  return ans

H, N = map(int, input().split())
A = np.zeros(N,np.int64)
B = np.zeros(N,np.int64)
for i in range(N):
  A[i],B[i] = map(int, input().split())
print(main(H,N,A,B))

Verdicts: Wrong Answer

Accepted
Problem: Ibis is fighting with a monster.  The _health_ of the monster is H.  Ibis can cast N kinds of spells. Casting the i-th spell decreases the monster's health by A_i, at the cost of B_i Magic Points.  The same spell can be cast multiple times. There is no way other than spells to decrease the monster's health.  Ibis wins when the health of the monster becomes 0 or below.  Find the minimum total Magic Points that have to be consumed before winning.

Submission attempts (in order):
inf = 10 ** 18
h, n = map(int, input().split())
ab = [list(map(int, input().split())) for _ in range(n)]
max_a = max(a for a, _ in ab)
dp = [inf] * (h + max_a)
dp[0] = 0
for i in range(1, h + max_a):
    dp[i] = min(dp[i-a] + b for a, b in ab)
print(dp[h:])


h, n = map(int, input().split())
ab = [list(map(int, input().split())) for _ in range(n)]
max_a = max(a for a, _ in ab)
dp = [10 ** 18 for _ in range(h + max_a)]
dp[0] = 0
for i in range(1, h + max_a):
    dp[i] = max(dp[i-a] + b for a, b in ab)
print(min(dp[h:]))

h, n = map(int, input().split())
ab = [list(map(int, input().split())) for _ in range(n)]
max_a = max(a for a, _ in ab)
dp = [10 ** 18 for _ in range(h + max_a)]

dp[0] = 0
for i in range(1, h + max_a):
    dp[i] = min(dp[i-a] + b for a, b in ab)
print(min(dp[h:]))


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Ibis is fighting with a monster.  The _health_ of the monster is H.  Ibis can cast N kinds of spells. Casting the i-th spell decreases the monster's health by A_i, at the cost of B_i Magic Points.  The same spell can be cast multiple times. There is no way other than spells to decrease the monster's health.  Ibis wins when the health of the monster becomes 0 or below.  Find the minimum total Magic Points that have to be consumed before winning.

Submission attempts (in order):
h,n= map(int, input().split())
p = [list(map(int, input().split())) for _ in range(n)] 
m = 10**4
dp = [0]*(h+m+1)
for i in range(m+1,h+m+1):
  dp[i] = min(dp[i-a] + b for a,b in p)
print(dp[h+m+])

h,n= map(int, input().split())
p = [list(map(int, input().split())) for _ in range(n)] 
i = 10**4
dp = [0]*(h+i)
for i in range(i,h+i+1):
  dp[i] = min(dp[i-a] + b for a,b in p)
print(dp[h])

h,n= map(int, input().split())
p = [list(map(int, input().split())) for _ in range(n)] 
m = 10**4
dp = [0]*(h+m+1)
for i in range(m+1,h+m+1):
  dp[i] = min(dp[i-a] + b for a,b in p)
print(dp[h+m])

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Ibis is fighting with a monster.  The _health_ of the monster is H.  Ibis can cast N kinds of spells. Casting the i-th spell decreases the monster's health by A_i, at the cost of B_i Magic Points.  The same spell can be cast multiple times. There is no way other than spells to decrease the monster's health.  Ibis wins when the health of the monster becomes 0 or below.  Find the minimum total Magic Points that have to be consumed before winning.

Submission attempts (in order):
h, n = map(int,input().split())
a = []
b = []
for i in range(n):
    ai, bi = map(int,input().split())
    a.append(ai)
    b.append(bi)

dp = [0]*10001

for i in range(10001):
    dp[i] = (dp[i-a]+b).min()

print(dp[h])


h, n = map(int,input().split())
a = []
b = []
for i in range(n):
    ai, bi = map(int,input().split())
    a.append(ai)
    b.append(bi)

m = 0
minc = 10**9
newi = -1
oldi = -2
cost = 0
while not newi == oldi:
    oldi = newi
    for i in range(len(n)):
        cost = b[i]*int((h-1)/a[i]+1)
        if cost < minc:
            newi = i
    h -= a[newi]*int((h-1)/a[newi])
    m += b[newi]*int((h-1)/a[newi])
    if newi == oldi:
        m += b[newi]

print(m)


import numpy as np

h, n = map(int,input().split())
a = np.zeros(n, dtype = int)
b = np.zeros(n, dtype = int)
for i in range(n):
    a[i], b[i] = map(int,input().split())

dp = np.zeros(10001, dtype = int)

for i in range(1,10001):
    dp[i] = (dp[i-a]+b).min()

print(dp[h])


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Ibis is fighting with a monster.  The _health_ of the monster is H.  Ibis can cast N kinds of spells. Casting the i-th spell decreases the monster's health by A_i, at the cost of B_i Magic Points.  The same spell can be cast multiple times. There is no way other than spells to decrease the monster's health.  Ibis wins when the health of the monster becomes 0 or below.  Find the minimum total Magic Points that have to be consumed before winning.

Submission attempts (in order):
import numpy as np
import sys
read=sys.stdin.read

h,n,*ab=map(int,read().split())
a=np.array(ab[::2])
b=np.array(ab[1::2])

magic=np.zeros(h+1)
for i in range(1,1+h):
  magic[i]=np.min(dp[np.maximum(i-a, 0)]+b)
print(magic[h])

import numpy as np
import sys
read=sys.stdin.read

h,n,*ab=map(int,read().split())
a=np.array(ab[::2])
b=np.array(ab[1::2])

magic=np.zeros(h+1,dtype=np.int64)
for i in range(1,1+h):
  magic[i]=np.min(magic[np.maximum(i-a, 0)]+b)
print(magic[h])

Verdicts: Runtime Error

Accepted
Problem: Ibis is fighting with a monster.  The _health_ of the monster is H.  Ibis can cast N kinds of spells. Casting the i-th spell decreases the monster's health by A_i, at the cost of B_i Magic Points.  The same spell can be cast multiple times. There is no way other than spells to decrease the monster's health.  Ibis wins when the health of the monster becomes 0 or below.  Find the minimum total Magic Points that have to be consumed before winning.

Submission attempts (in order):
import sys
def input(): return sys.stdin.readline().rstrip()
import numpy as np
def main():
    h,n=map(int,input().split())
    lis=np.array([list(map(int,input().split())) for _ in range(n)])
    a_max=np.max(lis[:,0])
    dp=np.zeros(h+a_max+1,int)
    for i in range(1,h+1):
        dp[i+lis[:,0]]=np.min(dp[i+lis[:,0]],dp[i]+lis[:,1])
    print(dp[h])

if __name__=='__main__':
    main()

import sys
def input(): return sys.stdin.readline().rstrip()
import numpy as np
def main():
    h,n=map(int,input().split())
    lis=np.array([list(map(int,input().split())) for _ in range(n)])
    a_max=np.max(lis[:,0])
    dp=np.zeros(h+a_max+1,int)
    for i in range(1,h+1):
        dp[i+lis[:,0]]=np.minimum(dp[i+lis[:,0]],dp[i]+lis[:,1])
    print(dp[h])

if __name__=='__main__':
    main()

import sys
def input(): return sys.stdin.readline().rstrip()
from collections import Counter
def main():
    n=int(input())
    A=list(map(int,input().split()))
    X,Y=[0]*n,[0]*n
    for i in range(n):
        X[i]=i+A[i]
        Y[i]=i-A[i]
    set_x=set(X)
    yc=Counter(Y)
    xc=Counter(X)
    ans=0
    for x in set_x:
        ans+=xc[x]*yc[x]
    print(ans)

if __name__=='__main__':
    main()

import sys
def input(): return sys.stdin.readline().rstrip()
import numpy as np
def main():
    h,n=map(int,input().split())
    lis=np.array([list(map(int,input().split())) for _ in range(n)])
    a_max=np.max(lis[:,0])
    dp=np.full(h+a_max+1,10**10)
    dp[0]=0
    for l in lis:
        dp[i:i+l[0]+1]=np.minimum(dp[i:i+l[0]+1],dp[i]+l[1])
    print(dp)
    print(dp[h])

if __name__=='__main__':
    main()

import sys
def input(): return sys.stdin.readline().rstrip()
import numpy as np
def main():
    h,n=map(int,input().split())
    lis=np.array([list(map(int,input().split())) for _ in range(n)])
    a_max=np.max(lis[:,0])
    dp=np.zeros(h+a_max+1,int)
    for i in range(a_max+1,a_max+h+1):
        dp[i]=np.min(dp[i-lis[:,0]]+lis[:,1])
    print(dp[a_max+h])

if __name__=='__main__':
    main()

Verdicts: Runtime Error

Wrong Answer

Runtime Error

Runtime Error

Accepted
Problem: Ibis is fighting with a monster.  The _health_ of the monster is H.  Ibis can cast N kinds of spells. Casting the i-th spell decreases the monster's health by A_i, at the cost of B_i Magic Points.  The same spell can be cast multiple times. There is no way other than spells to decrease the monster's health.  Ibis wins when the health of the monster becomes 0 or below.  Find the minimum total Magic Points that have to be consumed before winning.

Submission attempts (in order):
INF=10**10
def main():
  H,N=map(int,input().split())
  AB=[]
  for i in range(N):
    AB.append(list(map(int,input().split())))
  dp=[INF]*(H+1)
  dp[0]=0
  for a,b in AB:
    for k in range(H+1):
      tmp=k-a
      if tmp<0:
        tmp=0
      need_magic=dp[tmp]+b
      if need_magic<dp[k]:
        dp[k]=need_magic
  print(dp[H+1])
main()
      

INF=10**10
def main():
  H,N=map(int,input().split())
  AB=[]
  for i in range(N):
    AB.append(list(map(int,input().split())))
  dp=[INF]*(H+1)
  dp[0]=0
  for a,b in AB:
    for k in range(H+1):
      tmp=k-a
      if tmp<0:
        tmp=0
      need_magic=dp[tmp]+b
      if need_magic<dp[k]:
        dp[k]=need_magic
  print(dp[H])
main()
      


Verdicts: Runtime Error

Accepted
Problem: Ibis is fighting with a monster.  The _health_ of the monster is H.  Ibis can cast N kinds of spells. Casting the i-th spell decreases the monster's health by A_i, at the cost of B_i Magic Points.  The same spell can be cast multiple times. There is no way other than spells to decrease the monster's health.  Ibis wins when the health of the monster becomes 0 or below.  Find the minimum total Magic Points that have to be consumed before winning.

Submission attempts (in order):
from functools import lru_cache
import sys

sys.setrecursionlimit(10 ** 8)

H, N = map(int, input().split())
AB = [tuple(map(int, input().split())) for _ in range(N)]


AB.sort(key=lambda ab: (ab[1] / ab[0], ab[0]))


@lru_cache(maxsize=None)
def dp(h):
    if h <= 0:
        return 0
    else:
        for a, b in AB:
            val = b + dp(h - a)
            if val < best:
                best = val
            else:
                
                break
        return best


print(dp(H))


from functools import lru_cache
import sys

sys.setrecursionlimit(10 ** 8)

H, N = map(int, input().split())
AB = [tuple(map(int, input().split())) for _ in range(N)]


AB.sort(key=lambda ab: (ab[1] / ab[0], ab[0]))


@lru_cache(maxsize=None)
def dp(h):
    if h <= 0:
        return 0
    else:
        best = float("inf")
        for a, b in AB:
            val = b + dp(h - a)
            if val < best:
                best = val
            else:
                
                break
        return best


print(dp(H))


Verdicts: Runtime Error

Accepted
Problem: Ibis is fighting with a monster.  The _health_ of the monster is H.  Ibis can cast N kinds of spells. Casting the i-th spell decreases the monster's health by A_i, at the cost of B_i Magic Points.  The same spell can be cast multiple times. There is no way other than spells to decrease the monster's health.  Ibis wins when the health of the monster becomes 0 or below.  Find the minimum total Magic Points that have to be consumed before winning.

Submission attempts (in order):
import sys
input = sys.stdin.readlin
INF = float('INF')


def main():
    H, N = map(int, input().split())
    skills = [None] * N
    max_a = 0
    for i in range(N):
        a, b = map(int, input().split())
        if a > max_a:
            max_a = a
        skills[i] = (a, b)

    
    
    dp = [INF] * (H + max_a + 1111
    dp[0]=0


    
    for i in range(H):
        
        if dp[i] == INF:
            continue

        
        for a, b in skills:
            
            mp=dp[i] + b
            
            
            if mp < dp[i + a]:
                dp[i + a]=mp

    
    print(min(dp[H:]))


 if __name__ == "__main__":
     main()


import sys
input = sys.stdin.readline
INF = float('INF')


def main():
    H, N = map(int, input().split())
    skills = [None] * N
    max_a = 0
    for i in range(N):
        a, b = map(int, input().split())
        if a > max_a:
            max_a = a
        skills[i] = (a, b)

    
    
    dp = [INF] * (H + max_a + 1)
    dp[0] = 0

    
    for i in range(H):
        
        if dp[i] == INF:
            continue

        
        for a, b in skills:
            
            mp = dp[i] + b
            
            
            if mp < dp[i + a]:
                dp[i + a] = mp

    
    print(min(dp[H:]))

if __name__ == "__main__":
    main()


Verdicts: Runtime Error

Accepted
Problem: Ibis is fighting with a monster.  The _health_ of the monster is H.  Ibis can cast N kinds of spells. Casting the i-th spell decreases the monster's health by A_i, at the cost of B_i Magic Points.  The same spell can be cast multiple times. There is no way other than spells to decrease the monster's health.  Ibis wins when the health of the monster becomes 0 or below.  Find the minimum total Magic Points that have to be consumed before winning.

Submission attempts (in order):
import numpy as np
H, N = map(int, input().split())
A = []
B = []
for _ in range(N):
  ai, bi = map(int, input().split())
  A.append(ai)
  B.append(bi)

# process
dp = np.zeros(H+1, dtype=np.int64)
dp[0] = 0

for i in range(1, H + 1):
    dp[i] = np.amin(dp[np.maximum(i - A, 0)] + B)

# output
print(dp[H])


import numpy as np
H, N = map(int, input().split())
A = []
B = []
for _ in range(N):
  ai, bi = map(int, input().split())
  A.append(ai)
  B.append(bi)

A = np.array(A)
B = np.array(B)
# process
dp = np.zeros(H+1, dtype=np.int64)
dp[0] = 0

for i in range(1, H + 1):
    dp[i] = np.amin(dp[np.maximum(i - A, 0)] + B)

# output
print(dp[H])



Verdicts: Runtime Error

Accepted
Problem: Ibis is fighting with a monster.  The _health_ of the monster is H.  Ibis can cast N kinds of spells. Casting the i-th spell decreases the monster's health by A_i, at the cost of B_i Magic Points.  The same spell can be cast multiple times. There is no way other than spells to decrease the monster's health.  Ibis wins when the health of the monster becomes 0 or below.  Find the minimum total Magic Points that have to be consumed before winning.

Submission attempts (in order):
import math
import numpy as np
H,N=map(int,input().split)
A=[]
B=[]
for i in range(N):
    n,a=input().split()
    A.append(int(n))
    B.append(int(a))
C=[]
for i in range(N):
  C.append(A[i]/B[i])
sub=0
for i in range(N):
  if C[i]>=C[sub]:
    sub=i
sub2=math.ceil(H/A[sub])
sub3=sub2*B[sub]
for ia in range(H,sub2):
  t = ia
  M = len(A) - 1
  elm = []
  for i, step in enumerate(A):
    temp = [1] * (M - i)
    elm.append(np.arange(0, t+1, step).reshape(-1, *temp))
  res = 0
  for x in elm:
    res = res + x
  sub4=0
  for x in np.argwhere(res == t):
    for ib in range(N):
    sub4+=B[ib]*x[ib]
  if sub4<=sub3:
    sub3=sub4
print(sub3)

H,N=map(int,input().split())
A=[]
B=[]
for i in range(N):
    n,a=input().split()
    A.append(int(n))
    B.append(int(a))
def f(x):
    if x<=0:
        return 0
    else:
        mini=g(x-A[0])+B[0]
        for i in range (1,N):
            sub=g(x-A[i])+B[i]
            if sub<mini:
                mini=sub
        return mini
def g(x):
    if x<0:
        return 0
    else:
        return g_list[x]
g_list=[]
g_list.append(0)
for i in range(1,H+1):
    g_list.append(f(i))
print(g_list[-1])

Verdicts: Runtime Error

Accepted
Problem: Ibis is fighting with a monster.  The _health_ of the monster is H.  Ibis can cast N kinds of spells. Casting the i-th spell decreases the monster's health by A_i, at the cost of B_i Magic Points.  The same spell can be cast multiple times. There is no way other than spells to decrease the monster's health.  Ibis wins when the health of the monster becomes 0 or below.  Find the minimum total Magic Points that have to be consumed before winning.

Submission attempts (in order):
h, n = map(int, input().split())
2.ab = [list(map(int, input().split())) for _ in range(n)]
3.dp =[0]*(h+max(ab[0:n][0]))
4.for i in range(1, h+1):
5.  dp[i] = min(dp[i-a]+b for a,b in ab)
6.print(dp[h])

def main():
    h, n = map(int, input().split())
    ab = [list(map(int, input().split())) for _ in range(n)]
    dp =[0]*(h+max(a for a,b in ab))
    for i in range(1, h+1):
        dp[i] = min(dp[i-a]+b for a,b in ab)
    print(dp[h])
      
if __name__ == '__main__':
    main()

Verdicts: Runtime Error

Accepted
Problem: Ibis is fighting with a monster.  The _health_ of the monster is H.  Ibis can cast N kinds of spells. Casting the i-th spell decreases the monster's health by A_i, at the cost of B_i Magic Points.  The same spell can be cast multiple times. There is no way other than spells to decrease the monster's health.  Ibis wins when the health of the monster becomes 0 or below.  Find the minimum total Magic Points that have to be consumed before winning.

Submission attempts (in order):
def main():
    h, n = map(int, input().split())
    ab = [list(map(int, input().split())) for _ in range(n)]

    dp = [0] + [0] * h
    for i in range(1, h + 1):
        dp[i] = min(dp[i - a] + b for a, b in ab)


if __name__ == '__main__':
    main()


def main():
    h, n = map(int, input().split())
    ab = [list(map(int, input().split())) for _ in range(n)]

    amax = max(a for a, b in ab)
    dp = [0] + [0] * (h + amax)
    for i in range(1, h + 1):
        dp[i] = min(dp[i - a] + b for a, b in ab)
    print(dp[h])


if __name__ == '__main__':
    main()


Verdicts: Runtime Error

Accepted
Problem: Ibis is fighting with a monster.  The _health_ of the monster is H.  Ibis can cast N kinds of spells. Casting the i-th spell decreases the monster's health by A_i, at the cost of B_i Magic Points.  The same spell can be cast multiple times. There is no way other than spells to decrease the monster's health.  Ibis wins when the health of the monster becomes 0 or below.  Find the minimum total Magic Points that have to be consumed before winning.

Submission attempts (in order):
(h,n),*c=[[*map(int,i.split())]for i in open(0)]
dp=[10**9]*(2*10**4+1)
c.sort()
dp[0]=0
for i in range(h):
    if dp[i]==10**9:break
    for a,b in c:
        if i+a<=2*10**4:
            dp[i+a]=min(dp[i+a],dp[i]+b)
        else:break    
print(min(dp[h:]))

(h,n),*c=[[*map(int,i.split())]for i in open(0)]
d=[0]*20002
for i in range(h):d[i]=min(d[i-a]+b for a,b in c)
print(d[h-1])

Verdicts: Wrong Answer

Accepted
Problem: Ibis is fighting with a monster.  The _health_ of the monster is H.  Ibis can cast N kinds of spells. Casting the i-th spell decreases the monster's health by A_i, at the cost of B_i Magic Points.  The same spell can be cast multiple times. There is no way other than spells to decrease the monster's health.  Ibis wins when the health of the monster becomes 0 or below.  Find the minimum total Magic Points that have to be consumed before winning.

Submission attempts (in order):
import sys
import numpy as np
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
sys.setrecursionlimit(500000)

H, N = map(int, readline().split())
m = map(int, read().split())
AB = np.array(zip(m, m))

INF = 10**18

dp = [INF] * (H + 1)
dp[0] = 0
for a, b in AB:
    for n in range(H + 1):
        k = max(0, n - a)
        acc = dp[k] + b
        if acc < dp[n]:
            dp[n] = acc

print(dp[H])

import sys
import numpy as np
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
sys.setrecursionlimit(500000)

H, N = map(int, readline().split())
AB = np.array([list(map(int,
                        readline().split())) for _ in range(N)],
              dtype=np.int64)

A = AB[:, 0]
B = AB[:, 1]

dp = np.zeros(H + 1, dtype=np.int64)
for n in range(1, H + 1):
    dp[n] = np.amin(dp[np.maximum(n - A, 0)] + B)

print(dp[H])

Verdicts: Runtime Error

Accepted
Problem: Ibis is fighting with a monster.  The _health_ of the monster is H.  Ibis can cast N kinds of spells. Casting the i-th spell decreases the monster's health by A_i, at the cost of B_i Magic Points.  The same spell can be cast multiple times. There is no way other than spells to decrease the monster's health.  Ibis wins when the health of the monster becomes 0 or below.  Find the minimum total Magic Points that have to be consumed before winning.

Submission attempts (in order):

H,N = map(int,input().split())
li=[]
x=[]
for i in range(N):
    A,B = map(int,input().split())
    x.append(A)
    li.append([A,B])
dp = [10**9]*(H+max(x))
dp[0] = 0
for i in range(1,len(dp)):
    dp[i] = min(dp[i-a] + b for a,b in li)
print(min(dp[h:]))



H,N = map(int,input().split())
li=[]
x=[]
for i in range(N):
    A,B = map(int,input().split())
    x.append(A)
    li.append([A,B])
dp = [10**9]*(H+max(x))
dp[0] = 0
for i in range(1,len(dp)):
    dp[i] = min(dp[i-a] + b for a,b in li)
print(min(dp[H:]))


Verdicts: Runtime Error

Accepted
Problem: Ibis is fighting with a monster.  The _health_ of the monster is H.  Ibis can cast N kinds of spells. Casting the i-th spell decreases the monster's health by A_i, at the cost of B_i Magic Points.  The same spell can be cast multiple times. There is no way other than spells to decrease the monster's health.  Ibis wins when the health of the monster becomes 0 or below.  Find the minimum total Magic Points that have to be consumed before winning.

Submission attempts (in order):
inf = 10**10
H, N = map(int, input().split())
A = []
B = []
for n in range(N):
    a, b = map(int, input().split())
    A.append(a)
    B.append(b)
dp = [inf] * (H + 10 ** 4)
for n in range(N):
    for h in range(H):
        if dp[h] == inf:
            continue
        dp[h + A[n]] = min(dp[h + A[n]], dp[h] + B[n])
print(min(dp[H:]))


def main():
    inf = 10**9
    H, N = map(int, input().split())
    AB = []
    for n in range(N):
        a, b = map(int, input().split())
        AB.append((a, b))
    AB.sort(reverse=True, key=lambda x: x[0])
    dp = [inf] * (H + 10 ** 4)
    dp[0] = 0
    for a, b in AB:
        for h in range(H):
            if dp[h] != inf:
                tmp = dp[h] + b
                if tmp < dp[h + a]:
                    dp[h + a] = tmp
    print(min(dp[H:]))


main()


Verdicts: Wrong Answer

Accepted
Problem: Silver Fox is fighting with N monsters.  The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the _health_ of H_i.  Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.  Silver Fox wins when all the monsters' healths become 0 or below.  Find the minimum number of bombs needed to win.

Submission attempts (in order):
from math import ceil
import bisect

N, D, A = map(int, input().split())
Monsters = sorted([list(map(int, input().split())) for i in range(N)])
X = [x for x, h in Monsters]
H = [ceil(h / A) for x, h in Monsters]

min_n = 0

for i in range(N):
  if H[i] <= 0:
    continue
  i_2Di = bisect.bisect_left(X, X[i]+2*D)
  H[i:i_2Di] -= A * ni
  min_n += ni
  
print(min_n)

from math import ceil
import bisect

N, D, A = map(int, input().split())
Monsters = sorted([list(map(int, input().split())) for i in range(N)])
X = [x for x, h in Monsters]
H = [ceil(h / A) for x, h in Monsters]

min_n = 0

for i in range(N):
  if H[i] <= 0:
    continue
  
  for j in range(i+1,N):
    if X[j] - X[i] > 2*D:
      i_2Di = j
      break
  H[i:i_2Di] -= A * ni
  min_n += ni
  
print(min_n)

from math import ceil
from collections import deque
N, D, A = map(int, input().split())
Monsters = sorted([list(map(int, input().split())) for i in range(N)])
Monsters = [[x, ceil(h / A)] for x, h in Monsters]


acc_damage = 0
que = deque([])

ans = 0
for x, h in Monsters:
    
    while que and x > que[0][0]:
        limit, damage = que.popleft()
        acc_damage -= damage

    need = max(0, h - acc_damage)
    ans += need
    acc_damage += need

    if need:
        que.append([x + 2 * D, need])

print(ans)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Silver Fox is fighting with N monsters.  The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the _health_ of H_i.  Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.  Silver Fox wins when all the monsters' healths become 0 or below.  Find the minimum number of bombs needed to win.

Submission attempts (in order):
n, d, a = map(int, input().split())
xh = [list(map(int, input().split())) for _ in range(n)]
xh.sort()

target = 0
cnt = 0
while target < n:
    x, h = xh[target]
    atk_end = x + d + d
    atk_cnt = (h + a - 1) // a
    cnt += atk_cnt
    for i in range(target, n):
        if xh[i][0] > atk_end:
            break
        xh[i][1] -= a * atk_cnt
        if xh[i][1] < 1 and i == target+1:
            target += 1
    # while xh[target][1] < 1:
    #     target += 1
    #     if target >= n:
    #         break

print(cnt)

n, d, a = map(int, input().split())
xh = [list(map(int, input().split())) for _ in range(n)]
xh.sort()

target = 0
cnt = 0
while xh[n-1][1] > 0:
    x, h = xh[target]
    atk_end = x + d + d
    atk_cnt = (h + a - 1) // a
    cnt += atk_cnt
    for i in range(target, n):
        if xh[i][0] > atk_end:
            break
        xh[i][1] -= a * atk_cnt
        if xh[i][1] < 1 and i == target+1:
            target += 1

print(cnt)

import math
from collections import deque

n, d, a = map(int, input().split())
xh = [list(map(int, input().split())) for _ in range(n)]
xh.sort(key=lambda x:x[0])
xh = deque(xh)

xh_field = deque()

cnt = 0
now_damage = 0
while xh:
    pos, hp = xh.popleft()
    if xh_field:
        while (xh_field and xh_field[0][0] < pos) :
            now_damage -= a * xh_field[0][1]
            xh_field.popleft() 
    if hp <= now_damage:
        pass
    elif hp > now_damage:
        atk_cnt = math.ceil((hp - now_damage) / a)
        cnt += atk_cnt
        now_damage += atk_cnt * a
        xh_field.append((2*d + pos, atk_cnt))        
print(cnt)


Verdicts: Time Limit Exceeded

Wrong Answer

Accepted
Problem: Silver Fox is fighting with N monsters.  The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the _health_ of H_i.  Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.  Silver Fox wins when all the monsters' healths become 0 or below.  Find the minimum number of bombs needed to win.

Submission attempts (in order):
from bisect import bisect_left, bisect_right
import sys
import numpy as np
input = sys.stdin.readline
N,D,A=map(int, input().split())
mg = [None]*N
X = [None]*N
H = [None]*N
XD = [None]*N
for i in range(N):
  mg[i]=list(map(int, input().split()))
mg.sort(key=lambda x:x[0])
mg = (np.array(mg)).T
X = mg[0]
H = mg[1]
for i in range(N):
  XD[i] = bisect_right(X[i+1:],X[i]+2*D) + i
XD = np.array(XD)
i = 0
ans = 0
while i<N:
  if H[i]>0:
    k = (H[i]+A-1)//A
    ans +=k
    H[i:XD[i]]=np.maximum(0,H[i:XD[i]]-k*A)
  i+=1
print(ans)

#!/usr/bin python3
# -*- coding: utf-8 -*-

from bisect import bisect_left, bisect_right

n, d, a = map(int, input().split())
x = []
xh = dict()
for _ in range(n):
    xi, hi = map(int, input().split())
    x.append(xi)
    xh[xi] = hi
x.sort()

l = 0
ret = 0
ai = [0] * (n+1)
anow = 0
while l < n:
    xl = x[l]
    hl = xh[xl]
    anow += ai[l]
    hl -= a * anow
    if hl > 0:
        r = bisect_right(x, xl+2*d)
        k = (hl+(a-1))//a
        ret += k
        anow += k
        ai[r] -= k
    l += 1
print(ret)


Verdicts: Wrong Answer

Accepted
Problem: Silver Fox is fighting with N monsters.  The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the _health_ of H_i.  Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.  Silver Fox wins when all the monsters' healths become 0 or below.  Find the minimum number of bombs needed to win.

Submission attempts (in order):
import sys
input = sys.stdin.readline

N, D, A = map(int, input().split())
S = [0]*N
for i in range(N):
    x, h = map(int, input().split())
    S[i] = [x, -(-h//A)]

S.sort()
print()
cnt = 0

for i in range(N):
    if S[i][1] <= 0:
        continue
    cnt += S[i][1]
    dmg = S[i][1]
    max_X = S[i][0] + D*2
    for j in range(i+1, N):
        if S[j][0] > max_X:
            break
        S[j][1] -= dmg

print(cnt)


import sys
input = sys.stdin.readline

N, D, A = map(int, input().split())
S = [0]*N
for i in range(N):
    x, h = map(int, input().split())
    if h % A == 0:
        h //= A
    else:
        h = h//A + 1
    S[i] = [x, h]

S.sort()
print()
cnt = 0

for i in range(N):
    if S[i][1] <= 0:
        continue
    cnt += S[i][1]
    dmg = S[i][1]
    max_X = S[i][0] + D*2
    for j in range(i+1, N):
        if S[j][0] > max_X:
            break
        S[j][1] -= dmg

print(cnt)


from collections import deque
import math

import sys
input = sys.stdin.readline

N, D, A = map(int, input().split())
S = [0]*N
atack = deque()
for i in range(N):
    x, h = map(int, input().split())
    S[i] = [x, h]

S.sort()
cnt = 0
dmg = 0
for i in range(N):
    while atack:
        if atack[0][0] < S[i][0]:
            x, d = atack.popleft()
            dmg -= d
        else:
            break

    if S[i][1] <= dmg:
        continue
    bomb = math.ceil((S[i][1]-dmg)/A)
    atack.append([S[i][0]+2*D, A*bomb])
    cnt += bomb
    dmg += A*bomb

print(cnt)


Verdicts: Time Limit Exceeded

Time Limit Exceeded

Accepted
Problem: Silver Fox is fighting with N monsters.  The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the _health_ of H_i.  Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.  Silver Fox wins when all the monsters' healths become 0 or below.  Find the minimum number of bombs needed to win.

Submission attempts (in order):
#153_F
from bisect import bisect_right
n, d, a = map(int, input().split())
mons = sorted([tuple(map(int, input().split())) for _ in range(n)])
x = [mons[i][0] for i in range(n)]
h = [mons[i][1] for i in range(n)]
damage = [0 for _ in range(n+1)]
cnt = 0
for i in range(n):
    if i > 0:
        damage[i] += damage[i-1]
        if h[i] <= damage[i] - damage[i-1]:
            continue
    
    cur_cnt = -(-(h[i]-damage[i]) // a)
    cnt += cur_cnt
    damage[i] += cur_cnt * a
    idx = bisect_right(x, x[i] + 2 * d)
    damage[idx] -= cur_cnt * a
    
print(cnt)
print(damage)

#153_F
from bisect import bisect_right
n, d, a = map(int, input().split())
mons = sorted([tuple(map(int, input().split())) for _ in range(n)])
x = [mons[i][0] for i in range(n)]
h = [mons[i][1] for i in range(n)]
damage = [0 for _ in range(n+1)]
cnt = 0
for i in range(n):
    if i > 0:
        damage[i] += damage[i-1]
        if h[i] <= damage[i]:
            continue
    
    cur_cnt = -(-(h[i]-damage[i]) // a)
    cnt += cur_cnt
    damage[i] += cur_cnt * a
    idx = bisect_right(x, x[i] + 2 * d)
    damage[idx] -= cur_cnt * a
    
print(cnt)

Verdicts: Wrong Answer

Accepted
Problem: Silver Fox is fighting with N monsters.  The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the _health_ of H_i.  Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.  Silver Fox wins when all the monsters' healths become 0 or below.  Find the minimum number of bombs needed to win.

Submission attempts (in order):
import math
n, d, a = map(int,input().split())
e = [[] for i in range(n)]
for i in range(n):
    x, h = map(int,input().split())
    e[i] = [x,h]
num = 0

e.sort()
sd = [0 for i in range(n)]
l = [i for i in range(n)]
for i in range(n):
    for j in range(l[i-1],i):
        if e[i][0]-e[j][0] <= 2*d:
            l[i] = j
            break

for i in range(n):
    res = x[i][1] - sd[i-1] + sd[l[i]-1]
    if res < 0:
        sd[i] = sd[i-1]
    else:
        k = math.ceil(res/a)
        sd[i] = sd[i-1]+k*a
        num += k
        
print(num)


import math
n, d, a = map(int,input().split())
e = [[] for i in range(n)]
for i in range(n):
    x, h = map(int,input().split())
    e[i] = [x,h]
num = 0

e.sort()
sd = [0 for i in range(n)]
l = [i for i in range(n)]
for i in range(n):
    for j in range(l[i-1],i):
        if e[i][0]-e[j][0] <= 2*d:
            l[i] = j
            break

for i in range(n):
    res = e[i][1] - sd[i-1] + sd[l[i]-1]
    if res < 0:
        sd[i] = sd[i-1]
    else:
        k = math.ceil(res/a)
        sd[i] = sd[i-1]+k*a
        num += k

print(num)


Verdicts: Runtime Error

Accepted
Problem: Silver Fox is fighting with N monsters.  The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the _health_ of H_i.  Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.  Silver Fox wins when all the monsters' healths become 0 or below.  Find the minimum number of bombs needed to win.

Submission attempts (in order):
N,D,A=map(int,input().split())
from heapq import heappop,heappush,heapify
B=[]
for _ in range(N):
    x,h=map(int,input().split())
    B.append((x,h))
heapify(B)

dic={}

ans=0
atk_cnt=0
while B:
    x,h=heappop(B)
    if h==-1:
        atk_cnt-=dic[x-1]
        continue
    if h<=A*atk_cnt:
        continue
    sup=x+2*D
    bomb=(h-1)//A+1
    ans+=bomb
    dic[sup]=bomb
    atk_cnt+=bomb
    heappush(B,(sup+1,-1))
    
print(ans)


N,D,A=map(int,input().split())
from heapq import heappop,heappush,heapify
B=[]
for _ in range(N):
    x,h=map(int,input().split())
    B.append((x,h))
heapify(B)

dic={}

ans=0
atk_cnt=0
while B:
    x,h=heappop(B)
    if h==-1:
        atk_cnt-=dic[x-1]
        continue
    if h<=A*atk_cnt:
        continue
    h-=A*atk_cnt
    sup=x+2*D
    bomb=(h-1)//A+1
    ans+=bomb
    dic[sup]=bomb
    atk_cnt+=bomb
    heappush(B,(sup+1,-1))
    
    
print(ans)


Verdicts: Wrong Answer

Accepted
Problem: Silver Fox is fighting with N monsters.  The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the _health_ of H_i.  Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.  Silver Fox wins when all the monsters' healths become 0 or below.  Find the minimum number of bombs needed to win.

Submission attempts (in order):
class BIT:
    def __init__(self, n):
        self.n = n
        self.bit = [0]*(self.n+1) # 1-indexed

    def init(self, init_val):
        for i, v in enumerate(init_val):
            self.add(i, v)

    def add(self, i, x):
        # i: 0-indexed
        i += 1 # to 1-indexed
        while i <= self.n:
            self.bit[i] += x
            i += (i & -i)

    def sum(self, i, j):
        # return sum of [i, j)
        
        return self._sum(j) - self._sum(i)

    def _sum(self, i):
        # return sum of [0, i)
        # i: 0-indexed
        res = 0
        while i > 0:
            res += self.bit[i]
            i -= i & (-i)
        return res

class RangeAddBIT:
    def __init__(self, n):
        self.n = n
        self.bit1 = BIT(n)
        self.bit2 = BIT(n)

    def init(self, init_val):
        self.bit2.init(init_val)

    def add(self, l, r, x):
        # add x to [l, r)
        # l, r: 0-indexed
        self.bit1.add(l, x)
        self.bit1.add(r, -x)
        self.bit2.add(l, -x*l)
        self.bit2.add(r, x*r)

    def sum(self, l, r):
        # return sum of [l, r)
        # l, r: 0-indexed
        return self._sum(r) - self._sum(l)

    def _sum(self, i):
        # return sum of [0, i)
        # i: 0-indexed
        return self.bit1._sum(i)*i + self.bit2._sum(i)

import sys
import io, os

input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline

def main():
    n, d, a = map(int, input().split())
    XH = []
    for i in range(n):
        x, h = map(int, input().split())
        XH.append((x-d, h))
    XH.sort()
    X = []
    H = []
    for x, h in XH:
        X.append(x)
        H.append(h)

    bit = RangeAddBIT(n+1)
    bit.init(H)
    import bisect
    ans = 0
    for i in range(n):
        h = bit.sum(i, i+1)
        if h > 0:
            q = (h+a-1)//a
            ans += q
            j = bisect.bisect_right(X, X[i]+2*d)
            bit.add(i, j, -q*a)
    print(ans)

if __name__ == '__main__':
    main()


n, d, a = map(int, input().split())
l = [[0, 0] for _ in range(n)]
for i in range(n):
  x, h = map(int, input().split())
  l[i][0] = x
  l[i][1] = h
  
l.sort()
from collections import deque
d = 2*d
q = deque([])
total = 0

ans = 0
for i in range(n):
  x = l[i][0]
  h = l[i][1]
  if q:
    while q[0][0] < x:
      total -= q[0][1]
      q.popleft()
      if not q:
        break
  h -= total
  if h > 0:
    num = (h+a-1)//a
    ans += num
    damage = num*a
    total += damage
    q.append([x+d, damage])

print(ans)

Verdicts: Time Limit Exceeded

Accepted
Problem: Silver Fox is fighting with N monsters.  The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the _health_ of H_i.  Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.  Silver Fox wins when all the monsters' healths become 0 or below.  Find the minimum number of bombs needed to win.

Submission attempts (in order):

#include <map>
typedef int64_t int64;
using namespace std;



int main() {
	int64 n, d, a;
	cin >> n;
	cin >> d;
	cin >> a;
	map<int64, pair<int64, int64>> m;
	for (int64 i=0; i<n; i++) {
		int64 b, c;
		cin >> b;
		cin >> c;
		m[b] = {c, 0};
	}
	int64 destroy = 0;
	int64 bombs = 0;

	for (auto [x, values]: m) {
		auto [health, update] = values;
		health -= destroy;
		if (health > 0) {
			int64 times = (health-1) / a + 1;
			bombs += times;
			if (d==0) continue;
			destroy += times*a;
			if (m.count(x+2*d)) m[x+2*d] = {m[x+2*d].first, times};
			else m[x+2*d] = {0, times};	
		}
		destroy -= update*a;
	}
	cout << bombs;
	return 0;
			
}	


n, d, a = map(int, input().split())

D = True

pos = []

for i in range(n):
	x, h = map(int, input().split())
	pos.append((x, h))

pos.sort(key=lambda x: x[0])

bombs = 0

for i, (x, h) in enumerate(pos):
	if h <= 0:
		continue
	new_x = x + 2*d
	number = (h-1) // a + 1
	bombs += number
	destroy = number*a
	for j, (x1, h1) in enumerate(pos[i:]):
		if x1 > new_x:
			break
		pos[j] = (x1, max(0, h1-destroy))

print(bombs)
		
	


n, d, a = map(int, input().split())

D = True

pos = []
pos1 = []

for i in range(n):
	x, h = map(int, input().split())
	pos.append((x, h))

pos.sort(key=lambda x: x[0])

bombs = 0
damage = 0
y, z = 0, 0


while y < n:
	x0 = pos[y][0]
	try:
		x1 = pos1[z][0]
	except IndexError:
		x1 = 1e16
	if x0 <= x1:
		health = pos[y][1]
		health -= damage
		number = max(0, (health-1) // a + 1)
		bombs += number
		damage += number*a
		pos1.append((x0+2*d, number*a))
		y+=1
	else:
		damage -= pos1[z][1]
		z += 1
	

print(bombs)



Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: Silver Fox is fighting with N monsters.  The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the _health_ of H_i.  Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.  Silver Fox wins when all the monsters' healths become 0 or below.  Find the minimum number of bombs needed to win.

Submission attempts (in order):
def binary(N, LIST, num):  
    l, r = -1, N
    while r - l > 1:
        if LIST[(l + r) // 2] > num:  
            r = (l + r) // 2
        else:
            l = (l + r) // 2
    return r + 1


n, d, a = map(int, input().split())
xh = sorted(map(int, input().split()) for _ in range(n))
x = [i for i, j in xh]
h = [(j + a - 1) // a for i, j in xh]

bomb, bsum, ans = [0] * (n + 1), [0] * (n + 1), 0
for i in range(n):
    j = binary(n, x, x[i] + 2 * d) - 1
    bnum = max(h[i] - (bsum[i - 1] + bomb[i]), 0)
    bomb[i] += bnum
    bomb[j] -= bnum
    bsum[i] += bsum[i - 1] + bomb[i]
    ans += bnum
print(ans)


def binary(N, LIST, num):  
    l, r = -1, N
    while r - l > 1:
        if LIST[(l + r) // 2] > num:  
            r = (l + r) // 2
        else:
            l = (l + r) // 2
    return r + 1


n, d, a = map(int, input().split())
xh = sorted(list(map(int, input().split())) for _ in range(n))
x = [i for i, j in xh]
h = [(j + a - 1) // a for i, j in xh]

bomb, bsum, ans = [0] * (n + 1), [0] * (n + 1), 0
for i in range(n):
    j = binary(n, x, x[i] + 2 * d) - 1
    bnum = max(h[i] - (bsum[i - 1] + bomb[i]), 0)
    bomb[i] += bnum
    bomb[j] -= bnum
    bsum[i] += bsum[i - 1] + bomb[i]
    ans += bnum
print(ans)


Verdicts: Runtime Error

Accepted
Problem: Silver Fox is fighting with N monsters.  The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the _health_ of H_i.  Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.  Silver Fox wins when all the monsters' healths become 0 or below.  Find the minimum number of bombs needed to win.

Submission attempts (in order):
N,D,A=map(int,input().split())
XH=[]
for _ in range(N):
  x,h=map(int,input().split())
  XH.append([x,h])
XH=sorted(XH, key=lambda x:x[0])
X=[XH[i][0] for i in range(N)]
H=[XH[i][1] for i in range(N)]

from bisect import bisect_right
import numpy as np
H=np.array(H)
ans=0
js=[bisect_right(X, 2*D+X[i]) for i in range(N)]


N,D,A=map(int,input().split())
XH=[]
for _ in range(N):
  x,h=map(int,input().split())
  XH.append([x,h])
XH=sorted(XH, key=lambda x:x[0])
X=[XH[i][0] for i in range(N)]
H=[XH[i][1] for i in range(N)]
from math import ceil
from bisect import bisect_right
imos=[0]*(N+1)
hit=0
ans=0
for i in range(N):
  hit+=imos[i]
  restH=H[i]-hit*A
  if restH>0:
    ans+=ceil(restH/A)
    hit+=ceil(restH/A)
    ind=bisect_right(X,X[i]+2*D)
    imos[ind]-=ceil(restH/A)
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Silver Fox is fighting with N monsters.  The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the _health_ of H_i.  Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.  Silver Fox wins when all the monsters' healths become 0 or below.  Find the minimum number of bombs needed to win.

Submission attempts (in order):
N,D,A = map(int,input().split())
import numpy as np
import math
XH = [list(map(int,input().split())) for _ in range(N)]
XH = sorted(XH)
ans = 0
l=[0]*N
x = XH[0][0]
j = 0
while True:
  if j+1>=N:
    break
  if XH[j+1][0]<=x+D:
    j+=1
  else:
    break
l[0]=j
for i in range(1,N):
  x = XH[i][0]
  j = l[i-1]
  while True:
    if j+1>=N:
      break
    if XH[j+1][0]<=x+D:
      j+=1
    else:
      break
  l[i]=j
H = np.array([xh[1] for xh in XH])
for i,a in enumerate(l):
  h = H[i]
  if h<=0:
    continue
  else:
    b = math.ceil(h/A)
    ans += b
    H[i:l[a]+1:]-=b*A
print(ans)

def main():
  N,D,A = map(int,input().split())
  XH = [list(map(int,input().split())) for _ in range(N)]
  XH = sorted(XH)
  ans = 0
  S = [0]*(N+1)
  x = XH[0][0]
  h = XH[0][1]
  j = 0
  b = (h+A-1)//A
  ans += b
  y = b*A
  while True:
    if j+1>=N:
      break
    if XH[j+1][0]<=x+2*D:
      j+=1
    else:
      break
  S[0]+=y
  S[j+1]-=y
  S[1]+=S[0]
  for i in range(1,N):
    xh = XH[i]
    h = xh[1]
    s = S[i]
    rec = h-s
    if rec<=0:
      S[i+1]+=s
      continue
    else:
      x = xh[0]
      j = max(j,i)
      while True:
        if j+1>=N:
          break
        if XH[j+1][0]<=x+2*D:
          j+=1
        else:
          break
      b = (rec+A-1)//A
      ans += b
      y = b*A
      S[i]+=y
      S[j+1]-=y
      S[i+1]+=s+y
  print(ans)
main()

Verdicts: Wrong Answer

Accepted