TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
N,L = list(map(int,input().split()))


i = 0
taste = []

while i <= N:
        taste.append(L + i - 1)
        i += 1
      
if L <= 0:
        print(sum(taste))
elif L > 0:
        print(sum(taste[1:N]))


N,L = list(map(int,input().split()))


i = 1
taste = []

while i <= N:
        taste.append(L + i - 1)
        i += 1
print(taste)

if L > 0 :
        print(sum(taste[1:N]))
elif L < N and N + L < 0:
        print(sum(taste[0:N-1]))
elif L <= 0 and N - L >= 0:
        print(sum(taste))
   

N,L = list(map(int,input().split()))


i = 1
taste = []

while i <= N:
        taste.append(L + i - 1)
        i += 1

print(taste)
      
if L > 0 :
        print(sum(taste[1:N]))
elif L < N and N + L < 0:
        print(sum(taste[0:N-1]))
elif L <= 0 and N - L >= 0:
        print(sum(taste))

N,L = list(map(int,input().split()))


i = 1
taste = []

while i <= N:
        taste.append(L + i - 1)
        i += 1


if L > 0 :
        print(sum(taste[1:N]))
elif L <= 0 and N + L < 0:
        print(sum(taste[0:N-1]))
elif L <= 0 and N + L > 0:
        print(sum(taste[0:N]))
elif L <= 0 and N + L == 0:
        print(sum(taste[0:N-1]))

   

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
N,K = [int(i) for i in input().split()] 
bi=None
if 2<=1-L and 1-L<=N:
    bi =1-L
elif 1-L>=N:
    bi = N
elif 2>=1-L:
    bi =1
ajis = [L+i for i in range (N)]
org_sum = sum(ajis)
ans = org_sum -(L+bi-1)
print(ans)

N,L = [int(i) for i in input().split()] 
bi=None
if 2<=1-L and 1-L<=N:
    bi =1-L
elif 1-L>=N:
    bi = N
elif 2>=1-L:
    bi =1
ajis = [L+i for i in range (N)]
org_sum = sum(ajis)
ans = org_sum -(L+bi-1)
print(ans)

Verdicts: Runtime Error

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
n,l=map(int,input().split())

x=[l+i-1 for i in range(1,n+1)]

min_val=None
idx=0
for i in x:
  if min_val is None or abs(l+i-1) < min_val:
    min_val=abs(l+i-1)
    idx=i-1

x.pop(idx)
print(sum(x))

n,l=map(int,input().split())

x=[l+i-1 for i in range(1,n+1)]
x.remove(min(x, key=abs))
print(sum(x))

Verdicts: Runtime Error

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
import math
import re
import time

N,L=map(int,input().split())

total=(L-1)*N+((1+N)/2)*N
mn=1e9
for a in range(N):
    l=L+(a+1)-1
    total2+=l
    mn=min([mn,abs(l)])

print(int(total-mn))

import math
import re
import time

N,L=map(int,input().split())

total=(L-1)*N+((1+N)/2)*N
mn=1e9
ans=1e9
for a in range(N):
    l=L+(a+1)-1
    print(l)
    if abs(l)<mn:
        mn=min([mn,abs(l)])
        ans=l
print(int(total-ans))

import math
import re
import time

N,L=map(int,input().split())

total=(L-1)*N+((1+N)/2)*N
mn=1e9
ans=1e9
for a in range(N):
    l=L+(a+1)-1
    print(l)
    if abs(l)<mn:
        mn=min([mn,abs(l)])
        ans=l
print(int(total-ans))

import math
import re
import time

N,L=map(int,input().split())

total=(L-1)*N+((1+N)/2)*N
mn=1e9
ans=1e9
for a in range(N):
    l=L+(a+1)-1
    if abs(l)<mn:
        mn=min([mn,abs(l)])
        ans=l
print(int(total-ans))

Verdicts: Runtime Error

Wrong Answer

Wrong Answer

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
n, l = map(int, input().split())

r = l + n - 1

if r <= 0:
    eat = r
elif l >= 0:
    eat = l
else:
    eat = 0
print((R + L) * (R - L + 1) / 2 - eat)


import numpy as np

N, L = map(int, input().split())

apple = np.array([L + i - 1 for i in range(1, N + 1)])
abs_apple = np.abs(apple)
idx = abs_apple.argmin()
print(apple.sum() - apple[idx])


Verdicts: Runtime Error

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
n,l=map(int,input().split())
a=[l+n for i in range(n)]
dif = 10**18
for i in range(n):
  if dif > abs(a[i]):
    dif = abs(a[i])
    difr= a[i]
print(sum(a)-difr)

n,l=map(int,input().split())
a=[l+i for i in range(n)]
dif = 10**18
for i in range(n):
  if dif > abs(a[i]):
    dif = abs(a[i])
    difr= a[i]
print(sum(a)-difr)


Verdicts: Wrong Answer

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
    n,l = map(int,input().split())
    if l > 0:
        print(int(n*(l-1)+n*(n+1)/2-l))
    elif l <= 0 and l +n-1 >=0:
        print(int(n*(l-1)+n*(n+1)/2))
    else:
        print(int(n*(l-1)+n*(n+1)/2-l-n+1))

def solve():
    n,l = map(int,input().split())
    if l > 0:
        print(int(n*(l-1)+n*(n+1)/2-l))
    elif l <= 0 and l +n-1 >=0:
        print(int(n*(l-1)+n*(n+1)/2))
    else:
        print(int(n*(l-1)+n*(n+1)/2-l-n+1))
    return 0

solve()

Verdicts: Runtime Error

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
import numpy as np
a = input()
n, l= a.split(" ")
apples = [i for i in range(n)]
abs_app = np.abs(apples)
m = abs_app.min()
print((np.array(apples)[abs_app == m]).sum())


import numpy as np
a = input()
int(n), int(l) = a.split(" ")
apples = [i for i in range(n)]
abs_app = np.abs(apples)
m = abs_app.min()
app = np.array(apples)
app = app + l - 1
print(app[abs_app != m].sum())


import numpy as np
a = input()
n, l = [int(i) for i in a.split(" ")]
apples = np.array([i for i in range(n)])
aji = apples + l
abss = [np.abs(aji[apples != i].sum() - aji.sum()) for i in range(n)]
i = abss.index(np.min(abss))
print(aji[apples != i].sum())

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
N,L = map(int,input().split())

if L >= 1:
    print((N-1)*(2*L+N)/2)
elif L < 1 and N > -L:
    print(N*(2*L+N-1)/2)
else:
    print(N*(2*L+N-1)/2-N-L+1)

N,L = map(int,input().split())

if L >= 1:
    print((N-1)*(2*L+N)//2)
elif L < 1 and N > -L:
    print(N*(2*L+N-1)//2)
else:
    print(N*(2*L+N-1)//2-N-L+1)

Verdicts: Wrong Answer

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
N, L = map(int, input().split())


lis = []
for n in range(1, N+1):
    azi = L + n - 1
    lis.append(azi)

lis2 = [abs(l) for l in lis]

min = min(lis2)
del lis[min]

print(sum(lis))

N, L = map(int, input().split())


lis = []
for n in range(1, N+1):
    azi = L + n - 1
    lis.append(azi)

lis2 = [abs(l) for l in lis]

min = lis2.index(min(lis2))
del lis[min]

print(sum(lis))

Verdicts: Runtime Error

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
N,L = map( int, input().split() )

applePie = L*(N-1)
for i in range(N-1):
    applePie += i

print(applePie)

N,L = map( int, input().split() )

applePie = L*N
min = 20000

for i in range(N):
    applePie += i
    if (L+i)*(L+i) < min*min:
        min = L+i

applePie -= min

print(applePie)

Verdicts: Wrong Answer

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
n, l = map(int, input().split())

if l > 0:
  print((l + n-1+l) * n /2 - l)
elif n <= abs(l):
  print((2 * l + n - 2) * (n-1) / 2)
else:
  print(l - 1 * abs(l) / 2 + l + n - 1 + 1 * (l + n - 1) / 2)

n, l = map(int, input().split())


R = l + n - 1


if R <= 0:
  eat = R
elif l >= 0:
  eat = l
else:
  eat = 0


answer = round((R+l) * (R-l+1) / 2 - eat)
print(answer)


Verdicts: Wrong Answer

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
n,l=map(int,input().split())
ls=range(l,n+l)
if 0 in ls:
    x=0
elif all(i>0 for i in ls):
    x=ls[0]
else:
    x=ls[n-1]
print(n*l+(n-1)*n/2-x)

n,l=map(int,input().split())
ls=range(l,n+l)
if 0 in ls:
    x=0
elif all(i>0 for i in ls):
    x=ls[0]
else:
    x=ls[n-1]
print(int((n*l+(n-1)*n/2-x)))

Verdicts: Wrong Answer

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
n,l=map(int,input().split())
ls=[]
for i in range(1,n+1):
  ls.append(abs(l-1+i))
mi=l.index(min(ls))
print(n*(l-1)+sum(range(1,n+1))-l-mi)

n,l=map(int,input().split())
s=0
list=[]
for i in range(1,n+1):
  s+=i
  list.append(abs(l+i-1))
sum=n*(l-i)+s
if l-1<-n:
  print(sum+min(list))
else:
  print(sum-min(list))

l=[]
for i in range(1,n+1):
  l.append(abs(l-1+i))
mi=l.index(min(l))
print(n*(l-1)+sum(range(1,n+1)-l-mi)

n,l=map(int,input().split())
s=0
list=[]
for i in range(1,n+1):
  s+=i
  list.append(abs(l+i-1))
sum=n*(l-i)+s
if l-1<-n:
  print(sum+min(list))
elif l-1<=0<=l-1+n:
  print(sum)
else:
  print(sum-min(list))

l=[]
for i in range(1,n+1):
  l.append(abs(l-1+i))
mi=l.index(min(l))
print(n*(l-1)+sum(range(1,n+1))-l-mi)

n,l=map(int,input().split())
s=0
list=[]
for i in range(1,n+1):
  s+=i
  list.append(abs(l+i-1)
sum=n*(l-i)+s
if l-1<-n:
  print(sum+min(list))
else:
  print(sum-min(list))

n,l=map(int,input().split())
s=0
list=[]
for i in range(1,n+1):
  s+=i
  list.append(abs(l+i-1))
sum=n*(l-i)+s
m=list.index(min(list))
print(sum-l-m)

n,l=map(int,input().split())
ls=[]
for i in range(1,n+1):
  ls.append(abs(l-1+i))
mi=ls.index(min(ls))
print(n*(l-1)+sum(range(1,n+1))-l-mi)

Verdicts: Runtime Error

Wrong Answer

Runtime Error

Wrong Answer

Runtime Error

Runtime Error

Wrong Answer

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
n, l = map(int, input().split())
ans = int(n*(l+n-1)/2)
if l >= 0:
  print(ans - l)
elif n-1 >= -l:
  print(ans)
else:
  print(ans - (l+n-1))

n, l = map(int, input().split())
ans = int(n*(l+(n-1)/2))
if l >= 0:
  print(ans - l)
elif l+n-1 >= 0:
  print(ans)
else:
  print(ans - (l+n-1))

Verdicts: Wrong Answer

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
N, L = map(int, input().split())
if L <= 0 and L + N - 1 >= 0:
	print(N * ((N - 1) / 2 + L))
elif L > 0:
	print(N * ((N - 1) / 2 + L) - L)
else:
	print(N * ((N - 1) / 2 + L) - L - N + 1)

N, L = map(int, input().split())
if L <= 0 and L + N - 1 >= 0:
	print(int(N * ((N - 1) / 2 + L)))
elif L > 0:
	print(int(N * ((N - 1) / 2 + L) - L))
else:
	print(int(N * ((N - 1) / 2 + L) - L - N + 1))

Verdicts: Wrong Answer

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):

N,L=map(int,input().split())
#L+i-1,i>=1
nin=10**6
for i in range(N):
    if abs(L+i)<nin:
        nin=abs(L+i)
        nn=L+i

ans=N*(L-1)+N*(N+1)*0.5-(nn)

print(ans)

N,L=map(int,input().split())
#L+i-1,i>=1
nin=10**6
for i in range(N):
    if abs(L+i)<nin:
        nin=abs(L+i)
        nn=L+i

ans=N*(L-1)+N*(N+1)*0.5-(nn)

print(int(ans))


Verdicts: Wrong Answer

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
N,L = map(int,input().split())
a_list = []
for i in range(N):
    diff = abs(((L-1)*(N-1)-i))
    a_list.append(diff)
    
print(sum(list(N+1))-((L-1)*(N-1) - min(a_list)))

N,L = map(int,input().split())
l = list(map(lambda x : L+x+1 , range(1,N+1)))
print(sum(l)-min(l,key=min))

N,L = map(int,input().split())
l = list(map(lambda x : L+x+1 , range(1,N+1)))
print(sum(l)-min(l,key=abs))

N,L = map(int,input().split())
apple_list = list(map(lambda x: L+x-1 , range(1,N+1)))
print(sum(apple_list) - min(apple_list,key=abs))

Verdicts: Runtime Error

Runtime Error

Wrong Answer

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
N, L =  (int(j) for j in input().split())  

taste = [L+i-1 for i in range(1,N)]

if L > 0:
  print(sum(taste)-taste[0])
else:
  print(sum(taste))

N, L =  (int(j) for j in input().split())  

taste = [L+i-1 for i in range(1,N+1)]

if L > 0:
  print(sum(taste)-taste[0])
elif L + N - 1 <= 0:
  print(sum(taste)-taste[N-1])
else:
  print(sum(taste))


Verdicts: Wrong Answer

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
N,L = list(map(int,input().split()))
taste = list(range(L,L+N))

m = max(taste)
for e in taste:
  if abs(e) < m:
    m = abs(e)
print(m,sum(taste) - m)

N,L = list(map(int,input().split()))
taste = list(range(L,L+N))

m = max(taste)
for e in taste:
  if abs(e) < m:
    m = abs(e)
print(sum(taste) - m)

Verdicts: Wrong Answer

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
apples =str(input())
apples_list = apples.split(" ")
N = int(apples_list[0])
L = int(apples_list[-1])
pai_values = []

for i in range(1,N+1):
    pai_value = i + L -1
    pai_values.append(pai_value)

min_pai = abs(pai_values[0])

for j in range(N):
    if min_pai > abs(pai_values[j]):
        min_pai = abs(pai_values[j])
        target_number = j

pai_values.pop(target_number)

answer = sum(pai_values)

print(int(answer))


apples =str(input())
apples_list = apples.split(" ")
N = int(apples_list[0])
L = int(apples_list[-1])
pai_values = []

for i in range(1,N+1):
    pai_value = i + L -1
    pai_values.append(pai_value)

min_pai = abs(pai_values[0])

for j in range(N):
    if min_pai > abs(pai_values[j]):
        min_pai = abs(pai_values[j])
        target_number = j

pai_values.pop(target_number)

print(sum(pai_values))

apples =str(input())
apples_list = apples.split(" ")
N = int(apples_list[0])
L = int(apples_list[-1])
pai_values = []
 
for i in range(1,N+1):
    pai_value = i + L -1
    pai_values.append(pai_value)
    
min_pai = abs(pai_values[0])
 
for j in range(N):
    if min_pai > abs(pai_values[j]):
        min_pai = abs(pai_values[j])
        target_number = j
        
pai_values.pop(target_number)
 
answer = sum(pai_values)
 
print(int(answer))

apples =str(input())
apples_list = apples.split(" ")
N = int(apples_list[0])
L = int(apples_list[-1])
pai_values = []
 
for i in range(1,N+1):
    pai_value = i + L -1
    pai_values.append(pai_value)
    
min_pai = abs(pai_values[0])
target_number = 0
 
for j in range(N):
    if min_pai > abs(pai_values[j]):
        min_pai = abs(pai_values[j])
        target_number = j
        
pai_values.pop(target_number)
 
answer = sum(pai_values)
 
print(int(answer))

Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
s = 0
num_min = L + 1 - 1
num_max = L + N - 1
if 0 < num_min:
    s = sum([L + i - 1 for i in range(1, N+1)] ) - num_min
elif num_max < 0:
    s = sum([L + i - 1 for i in range(1, N+1)] ) - num_max
else:
    s = sum([L + i - 1 for i in range(1, N+1)] )
print(s)

N, L = map(int, input().split())
num_min = L + 1 - 1
num_max = L + N - 1
if 0 < num_min:
    s = sum([L + i - 1 for i in range(1, N+1)] ) - num_min
elif num_max < 0:
    s = sum([L + i - 1 for i in range(1, N+1)] ) - num_max
else:
    s = sum([L + i - 1 for i in range(1, N+1)] )
print(s)

Verdicts: Runtime Error

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
n, l = map(int,input().split())
num = 0
l1 = []
for i in range(n):
  num += l + i
  print(num)
  if l + n-1 < 0:
    l1.append(num-(l+n-1))
  elif l > 0:
    l1.append(num-(l))
  else:
    l1.append(num)
if l + n-1 > 0:
  print(max(l1))
else:
  print(min(l1))

n, l = map(int,input().split())
sum1 = 0
num = 1000
for i in range(n):
  a = l+(i+1)-1
  sum1 += a
  if abs(a) < num:
    num1 = a
    num = abs(a)
if num1 == num:
  print(sum1-num)
else:
  print(sum1+num)

Verdicts: Wrong Answer

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
#ABC131 B

N,L = map(int,input().split())
aji = []
delta = []
for i in range(N):
    aji.append(L + i)
for j in range(N):
    delta.append(abs(aji[i]))
print(min(delta))

#ABC131 B

N,L = map(int,input().split())
aji = []
delta = []
for i in range(N):
    aji.append(L + i)
for j in range(N):
    delta.append(abs(aji[i]))
print(sum(aji) - min(delta))

#ABC131 B

N,L = map(int,input().split())
aji = []
for i in range(N):
    aji.append(L+i)
if L < 0 and L+N-1 > 0:
    print(sum(aji))
elif L+N-1 <= 0:
    print(sum(aji) - (L+N-1))
elif L >= 0:
    print(sum(aji) - L)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
N,L=map(int,input().split())

R=[0]*N

for kai in range(N):
    R[kai]=L+kai-1
    print(R[kai])


kotoae=0
kotae=0
if(R[kai]>0):
    for kai1 in range(N):
        kotoae=kotoae+R[kai]
    print(kotae-R[0])
else:
    for kai1 in range(N):
        kotae=kotae+R[kai]
    print(kotoae)

N,L=map(int,input().split())

R=[0]*N

for kai in range(N):
    R[kai]=L+kai


kotoae=0
kotae=0
if(R[0]>0):
    for kai1 in range(N):
        kotoae=kotoae+R[kai1]
    print(kotoae-R[0])
elif(R[N-1]<0):
    for kai1 in range(N):
        kotae=kotae+R[kai1]
    print(kotae-R[N-1])
else:
    for kai in range(N):
        kotae=kotae+R[kai]
    print(kotae)

Verdicts: Wrong Answer

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
n, l = map(int, input().split())
taste = [l+i-1 for i in range(1, n+1)]

apple1 = 10 ** 8
apple2 = -(10 ** 8)
for i in taste:
    if i == 0:
        apple = i
        break
    elif (apple2 < i < 0) or (0 < i < apple1):
        apple = i
        
pie = abs(sum(taste) - apple)
    
print(pie)

n, l = map(int, input().split())
taste = [l+i-1 for i in range(1, n+1)]

apple1 = float('inf')
apple2 = -float('inf')
flag = 0
for i in taste:
    if i == 0:
        apple = i
        flag = 0
        break
    elif (apple2 < i < 0):
        apple2 = i
        flag = 1
    elif (0 < i < apple1):
        apple1 = i
        flag = 2
        
if flag == 1:
    pie = (sum(taste) - apple2)
elif flag == 2:
    pie = (sum(taste) - apple1)
else:
    pie = (sum(taste) - apple)
    
print(pie)

Verdicts: Wrong Answer

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
N, X = map(int, input().split())
L = list(map(int, input().split()))
B=sum(L)
count=1
if X>=B:
  print(len(L)+1)
else:
  i=0
  H=0
  while H<=X:
    H=H+L[i]
    i=i+1
  print(i)

N,L=map(int, input().split())
if N+L-1<=0:
  print(int(L*(N-1)+N*(N-1)/2-N+1))
elif L>=0:
  print(int(L*(N-1)+N*(N+1)/2-1-N+1))
else :
  print(int(L*N+N*(N+1)/2-N))

Verdicts: Runtime Error

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
N, L = map(int, input().split())
s = []
for i in N:
  s.append(i+L)
t = abs(s)
del s[t.index(min(s))]
print(sum(s))

N, L = map(int, input().split())
s = []
for i in range(N):
  s.append(i+L)
t = list(map(abs, s))
del s[t.index(min(t))]
print(sum(s))

Verdicts: Runtime Error

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
n,l = map(int,input().strip().split())

ringo=[]

for i in range(n):
	ringo.append(l+i)
print(ringo,sum(ringo))
min = abs(ringo[0])
min_num = 0
for i in range(len(ringo)):
	if min > abs(ringo[i]):
		min = abs(ringo[i])
		min_num = i
out = 0
for i in range(len(ringo)):
	if i != min_num:
		out = out + ringo[i]
print(out)





# -*- coding:utf-8 -*-

n,l = map(int,input().strip().split())

ringo=[]

for i in range(n):
	ringo.append(l+i)
min = abs(ringo[0])
min_nim = 0
for i in range(len(ringo)):
	if min > abs(ringo[i]):
		min = abs(ringo[i])
		min_num = i
out = 0
for i in range(len(ringo)):
	if i != min_num:
		out = out + ringo[i]
print(out)





# -*- coding:utf-8 -*-

n,l = map(int,input().strip().split())

ringo=[]

for i in range(n):
	ringo.append(l+i)
min = abs(ringo[0])
min_num = 0
for i in range(len(ringo)):
	if min > abs(ringo[i]):
		min = abs(ringo[i])
		min_num = i
out = 0
for i in range(len(ringo)):
	if i != min_num:
		out = out + ringo[i]
print(out)


Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
a,b = map(int, input().split())
tmp = []
for i in range(a):
  tmp.append(b+i)
if b < 0 and a <= abs(b):
  tmp = tmp[:-1]
elif b >= 0:
  tmp = tmp[1:]
print(tmp)

a,b = map(int, input().split())
tmp = []
for i in range(a):
  tmp.append(b+i)
if b < 0 and a <= abs(b):
  tmp = tmp[:-1]
elif b >= 0:
  tmp = tmp[1:]
print(sum(tmp))

Verdicts: Wrong Answer

Accepted
Problem: You have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The _flavor_ of Apple i is L+i-1, which can be negative.  You can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.  You planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.  You want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.  Find the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.  We can prove that this value is uniquely determined.

Submission attempts (in order):
# -*- coding: utf-8 -*-





spline = input().split()
N = int(spline[0])
L = int(spline[1])


taste = []
for i in range(0+1,N+1): 
    taste.append(L+i-1)  
#print(taste)


taste_max = sum(taste)
#print("max"+str(taste_max))


opt_coef = int()


for k in range(0,len(taste)):
    
    taste_any = sum(taste) - taste[k]
    #print("any"+str(taste_any))

    
    if abs(taste_max - taste_any) < opt_coef:
        
        opt_coef = taste_max - taste_any


print(opt_coef)



# -*- coding: utf-8 -*-
import numpy as np





spline = input().split()
N = int(spline[0])
L = int(spline[1])


taste = []
for i in range(1,N+1): 
    taste.append(L+i-1)  
#print(taste)


taste_max = sum(taste)
#print("max"+str(taste_max))



taste_any = []
for k in range(0,N):
    taste_any.append(sum(taste) - taste[k])
#print(taste_any)



taste_any = np.asarray(taste_any)
diff = abs(sum(taste) - taste_any)

diff_list = diff.tolist()
#print("diff_list"+str(diff_list))

coef = diff_list.index(min(diff_list))
#print(coef)

print(taste_any[coef])




Verdicts: Wrong Answer

Accepted