TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = input()
Sum = 0

for k in range(N):
    i = k+1

    if i % 3 != 0:
        if i % 5 != 0:
            Sum = Sum + i

print(Sum)

N = input()
Sum = 0

for k in range(N):
    i = k+1

    if i % 3 != 0 and i % 5 != 0:
        Sum = Sum + i

print(Sum)

N = input()
Sum = 0

for k in range(N):
    i = k+1

    if i % 3 != 0 and i % 5 != 0:
        Sum = Sum + i

print(str(Sum))

N = input()
Sum = 0

for k in range(int(N)):
    i = k+1

    if i % 3 != 0:
        if i % 5 != 0:
            Sum = Sum + i

print(Sum)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
s = 0
for i in range(n+1):
  if i % 3 != 0 or i % 5 != 0:
    s += i
print(s)

n = int(input())
s = 0
for i in range(n+1):
  if i % 3 != 0 and i % 5 != 0:
    s += i
print(s)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
import sys
import math
readline = sys.stdin.readline


def main():
    n = int(readline().rstrip())
    allSum = n * (n + 1) // 2
    threeNum = math.floor(n / 3)
    threeSum = 3 * threeNum * (threeNum + 1) // 2
    fiveNum = math.floor(n / 5)
    fiveSum = 5 * fiveNum * (fiveNum + 1) // 2
    bothNum = math.floor(n / 15)
    bothSum = 15 * bothNum * (bothNum + 1) // 2
    print(allSum, bothSum, threeSum, fiveSum)
    print(allSum + bothSum - threeSum - fiveSum)


if __name__ == '__main__':
    main()


import sys
import math
readline = sys.stdin.readline


def main():
    n = int(readline().rstrip())
    allSum = n * (n + 1) // 2
    threeNum = math.floor(n / 3)
    threeSum = 3 * threeNum * (threeNum + 1) // 2
    fiveNum = math.floor(n / 5)
    fiveSum = 5 * fiveNum * (fiveNum + 1) // 2
    bothNum = math.floor(n / 15)
    bothSum = 15 * bothNum * (bothNum + 1) // 2
    print(allSum + bothSum - threeSum - fiveSum)


if __name__ == '__main__':
    main()


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
for i in range(n):
    if i % 3 != 0 and i % 5 != 0:
        ans += i
print(ans)

n = int(input())

ans = 0

for i in range(1,n+1):
    if (i % 3 != 0) and (i % 5 != 0):
        ans += i
print(ans)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = input()
a = 0
for i in range(1, N + 1):
    if i % 5 != 0 and i % 3 != 0:
        a += i
print(a)

k = int(input())
a = (1 + k) * k // 2
three = (3+3*(k//3)) * (k // 3) // 2
five = (5+5*(k//5)) * (k // 5) // 2
fifteen = (15+15*(k//15)) * (k // 15) // 2
print(a-three-five+fifteen)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())
sum_ = 0
for i in range(1,N+1):
  if (i % 3 != 0) and (i % 5 != 0):
    sum_ += 1
print(sum_)

N=int(input())
sum_ = 0
for i in range(1,N+1):
  if (i % 3 != 0) and (i % 5 != 0):
    sum_ += i
print(sum_)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
a = int(input())

b = 0

for i in range(0,a):
    print(i)
    if i % 3 == 0:
        continue
    elif i % 5 == 0:
        continue
    else:
        b += i

print(b)

a = int(input())

b = 0

for i in range(0,a+1):
    if i % 3 == 0:
        continue
    elif i % 5 == 0:
        continue
    else:
        b += i

print(b)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
fizzbuzz = 0
fizz = 0
buzz = 0

for i in range(n):
  if i % 15 == 0:
    fizzbuzz += i
  elif i % 3 == fizz:
    fizz += i
  elif i % 5 == buzz:
    buzz += i

print(fizzbuzz + fizz +buzz)

n = int(input())
ans = 0

for i in range(1:n+1):
  if i % 5 != 0 and i % 3 !=0:
    ans += i

print(ans)

n = int(input())
ans = 0

for i in range(1,n+1):
  if i % 5 != 0 and i % 3 !=0:
    ans += i

print(ans)

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
k = 0
int n = int(input())
for i in range(n):
  if i % 3 != 0 and i % 5 != 0:
    k += i

print(k)

k = 0
n = int(input())
for i in range(n+1):
  if i % 3 != 0 and i % 5 != 0:
    k += i
 
print(k)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
if __name__ == "__main__":
    n = int(input())
    if "7" in str(n):
        print("Yes")
    else:
        print("No")


if __name__ == "__main__":
    n = int(input())

    sum_ = 0

    for i in range(n):
        num = i + 1
        if num % 3 == 0 or num % 5 == 0:
            continue
        else:
            sum_ += num

    print(sum_)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
list = []
for i in range(1, N + 1):
    if i % 3 == 0 and i % 5 == 0:
        print("FizzBuzz")
    elif i % 3 == 0:
        print("Fizz")
    elif i % 5 == 0:
        print("Buzz")
    else:
        list.append(i)
print(sum(list))

N = int(input())
list = []
for i in range(1, N + 1):
    if i % 3 == 0 and i % 5 == 0:
        "FizzBuzz"
    elif i % 3 == 0:
        "Fizz"
    elif i % 5 == 0:
        "Buzz"
    else:
        list.append(i)
print(sum(list))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())

def judge(x):
  if x % 15 == 0:
    return 0
  elif x % 3 == 0:
    return 0
  elif x % 5 == 0:
    return 0
  else:
    return x

l =[]
i = 0
for i in range(N):
  l.append(i)
  
print(sum(l))
  

N = int(input())

def judge(x):
  if x % 15 == 0:
    return 0
  elif x % 3 == 0:
    return 0
  elif x % 5 == 0:
    return 0
  else:
    return x

l =[]
for i in range(1,N+1):
  l.append(i)
  
print(sum(l))
  


N = int(input())

def judge(x):
  if x % 15 == 0:
    return 0
  elif x % 3 == 0:
    return 0
  elif x % 5 == 0:
    return 0
  else:
    return x

l =[]
for i in range(1,N+1):
  l.append(judge(i))
  
print(sum(l))
  


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = input()

list = [i for i in range(1, N+1) if not (i % 3 == 0 or i % 5 ==0)]
print(sum(list))

N = int(input())

list = [i for i in range(1, N+1) if not (i % 3 == 0 or i % 5 ==0)]
print(list)
print(sum(list))

N = input()

list = [i for i in range(1, N+1) if  (i % 3 != 0 or i % 5 !=0)]
print(sum(list))

N = int(input())

list = [i for i in range(1, N+1) if not (i % 3 == 0 or i % 5 ==0)]

print(sum(list))

Verdicts: Runtime Error

Wrong Answer

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
import sys
import numpy as np

N=int(input())
A=np.arange(N+1)
count = 0

for i in range(N+1):
    if A[i]%3 != 0 and A[i]%5 != 0 and A[i]%15 != 0:
        count = count + A[i]
        print(A[i])
print(count)

import sys
import numpy as np

N=int(input())
A=np.arange(N+1)
count = 0

for i in range(N+1):
    if A[i]%3 != 0 and A[i]%5 != 0 and A[i]%15 != 0:
        count = count + A[i]
print(count)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())

for i in range(1,N+1):
    if i%3==0 or i%5==0 or i%15==0:
        continue
        cal+=i

print(cal)


N=int(input())
cal=0
for i in range(1,N+1):
    if i%3==0 or i%5==0 or i%15==0:
        continue
    cal+=i

print(cal)


Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=map(int,input().split())
num=0
for i in range(n):
    if (i%3!=0) and (i%5!=0):
        num+=i
print(num)


n=map(int,input().split())
for i in range(n):
    if (i%3==0) and (i%5==0):
        print("FizzBuzz")
    elif (i%3==0) and (i%5!=0):
        print("Fizz")
    elif (i%3!=0) and (i%5==0):
        print("Buzz")
    else:
        print(i)
    


n=int(input())
num=0
for i in range(1,n+1):
    if (i%3!=0) and (i%5!=0):
        num+=i
print(num)


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())
sum=N*(N+1)/2
for i in range(N+1):
    if i%3==0 or i%5==0:
        sum-=i
print(sum)       

N=int(input())
sum=N*(N+1)/2
for i in range(N):
    if i%3==0 or i%5==0:
        sum-=i
print(sum)  

N=int(input())
sum=N*(N+1)/2
for i in range(N+1):
    if i%3==0 or i%5==0:
        sum-=i
print(int(sum))       

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(iniput())
sm = 0
for i in range(1,n+1,1):
  if i%3 and i%5:
    sm+=i
print(sm)

n = int(input())
sm = 0
for i in range(1,n+1,1):
  if i%3 and i%5:
    sm+=i
print(sm)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())
s=[]
for i in range(1:n+1):
  if a%3==0:
    continue
  elif a%5==0:
    continue
  else
  	s.append(i)
print(sum(s))

n=int(input())
s=[]
for i in range(1,n+1):
  if i%3==0:
    continue
  elif i%5==0:
    continue
  else:
    s.append(i)
print(sum(s))

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):

N = input()
N = int(N)

s_all = sum(N)
fizz = sum(list(range(3,N,3)))
buzz = sum(list(range(5,N,5)))

fb = sum(list(range(15,N,15)))

print(s_all-fizz-buzz+fb)



N = input()
N = int(N)

s_all = sum(range(N+1))
fizz = sum(list(range(3,N+1,3)))
buzz = sum(list(range(5,N+1,5)))

fb = sum(list(range(15,N+1,15)))

print(s_all-fizz-buzz+fb)


Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
cnt += 0
for i in range(N):
  if i%5!=0 and i%3!=0:
    cnt += i
print(cnt)

N = int(input())
cnt = 0
for i in range(N+1):
    if i%5!=0 and i%3!=0:
        cnt += i
print(cnt)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())

three = (3+(n//3)*3) * (n//3)/2
five = (5+(n//5)*5) * (n//5)/2
cup = (15+(n//15)*15) * (n//15)/2
total = (1+n) * n/2

ans = total - three - five + cup

print(ans)


n = int(input())

three = (3+(n//3)*3) * (n//3)/2
five = (5+(n//5)*5) * (n//5)/2
cup = (15+(n//15)*15) * (n//15)/2
total = (1+n) * n/2

ans = total - three - five + cup

print(ans//1)


n = int(input())

three = (3+(n//3)*3) * (n//3)/2
five = (5+(n//5)*5) * (n//5)/2
cup = (15+(n//15)*15) * (n//15)/2
total = (1+n) * n/2

ans = total - three - five + cup

print(int(ans))


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
list = []

for i in range(1, n + 1):
    if i % 3 == 0 and i % 5 == 0:
        print('FizzBuzz')
    elif i % 3 == 0:
        print('Fizz')
    elif i % 5 ==0 :
        print('Buzz')
    else:
        list.append(i)

print(sum(list))

n = int(input())
list = []

for i in range(1, n + 1):
    if i % 3 == 0 and i % 5 == 0:
        'FizzBuzz'
    elif i % 3 == 0:
        'Fizz'
    elif i % 5 ==0 :
        'Buzz'
    else:
        list.append(i)

print(sum(list))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
ans = 0
for i in range(1,N+1):
  if i%3 == 0 or i%5 == 0:
    continue
  ans += i
  
print(i)

N = int(input())
ans = 0
for i in range(1,N+1):
  if i%3 == 0 or i%5 == 0:
    continue
  ans += i
  
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
from sys import stdin

def main():
  N = int(stdin.readline())
  print(sum([n for n in range(1, N+1) if (n%3 != 0) or (n%5 != 0)]))
  
if __name__ == '__main__':
  main()
  

from sys import stdin

def main():
  N = int(stdin.readline())
  print(sum([n for n in range(1, N+1) if (n%3 != 0) and (n%5 != 0)]))
  
if __name__ == '__main__':
  main()
  


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
S = []
for i in range(1, N + 1):
    if (i % 3 == 0) and (i % 5 == 0):
        "FizzBuzz"
    elif i % 3 == 0:
        "Fizz"
    elif i % 5 == 0:
        "Buzz"
    else:
        S.append(i)
        print(sum(S))


N = int(input())
S = 0

for i in range(1, N + 1):
    if i % 15 == 0:
        S += 0
    elif i % 3 == 0:
        S += 0
    elif i % 5 == 0:
        S += 0
    else:
        S += i
print(S)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = (int(input()))
sum = 0
for i in range(n):
  if not((i+1)%3 == 0 or (i+1)%5 == 0):
    sum += i+1
    print(i+1)
print(sum)

n = int(input())
sum = 0
for i in range(n):
  if not((i+1)%3 == 0 or (i+1)%5 == 0):
    sum += i+1
print(sum)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = input(int())
for i in range(1, N+1):
    if i % 15 == 0:
        i = "FizzBuzz"
    elif i % 3 == 0:
        i = "Fizz"
    elif i % 5 == 0:
        i = "Buzz"
    else:
        i = i
        print(sum(i))

N = int(input())
total = 0
for i in range(1, N+1):
    if (i % 3) != 0 and (i % 5) != 0:
        total = total+i
print(total)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
A = int(input())
total = 0L
for x in range(A+1):
  if x%5!=0 and x%3!=0:
    total += x
print(x)

A = int(input())
total = 0
for x in range(A+1):
  if x%5!=0 and x%3!=0:
    total += x
print(total)



Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
import math
n = int(input())
a = n//3
ans = ((a+1)*a//2)*3  
b = n//5
ans += ((b+1)*b//2)*5
print(ans)

n=int(input())
a=n//3
ans=(a+1)*a//2*3
b=n//5
ans+=(b+1)*b//2*5
c=n//15
ans-=(c+1)*c//2*15
ans=(n+1)*n//2-ans
print(ans)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = str(input())

ans = 0
for i in range(1, N+1):
  if i % 3 != 0 and i % 5 != 0:
    ans += i
print(ans)

N = int(input())
 
ans = 0
for i in range(1, N+1):
  if i % 3 != 0 and i % 5 != 0:
    ans += i
print(ans)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
for i in range(1, 30 + 1):
    if i % 15 == 0:
        print('Fizz Buzz')
    elif i % 3 == 0:
        print('Fizz')
    elif i % 5 == 0:
        print('Buzz')
    else:
        print(i) 

N = int(input())
result = 0
for i in range(1, (N + 1)):
    if i % 15 == 0:
        'Fizz Buzz'
    elif i % 3 == 0:
        'Fizz'
    elif i % 5 == 0:
        'Buzz'
    else:
        result = result + i
print(result)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
a=int(input())
c=0
for i in range(0,n+1):
	if(i%3!=0)and(i%5==0):
		continue
    if(i%3!=0):
    	continue
    if(i%5==0):
    	continue
  	else:
    	c+=i
print(c)  
   


n=int(input())
for i in range(1,n+1):
  if((i%3==0)and(i%5==0)):
    continue
  elif(i%3==0):
    continue
  elif((i%5==0)):
    continue
  else:
    c+=i
print(c)
  

a=int(input())
c=0
for i in range(0,a+1):
	if(i%3!=0)and(i%5==0):
		continue
    if(i%3!=0):
    	continue
    if(i%5==0):
    	continue
  	else:
    	c+=i
print(c)  
   


a=int(input())
c=0
for i in range(0,n+1):
  if(i%3!=0)and(i%5==0):
    continue
  if(i%3!=0):
    continue
  if(i%5==0):
    continue
  else:
    c+=i
print(c)  
   

a=int(input())
c=0
for i in range(0,n+1):
	if(i%3!=0)and(i%5==0):
		continue
    if(i%3!=0):
    	continue
    if(i%5==0):
    	continue
  	else:
    	c+=i
print(c)  
   


n=int(input())
c=0
for i in range(1,n+1):
  if((i%3==0)and(i%5==0)):
    continue
  elif(i%3==0):
    continue
  elif((i%5==0)):
    continue
  else:
    c+=i
print(c)
  


Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())

cnt = 0
for i in range(1, n):
  if i%3 != 0 and i%5 != 0:
    cnt += 1
    
print(cnt)


n = int(input())

cnt = 0
for i in range(1, n):
  if i%3 != 0 and i%5 != 0:
    cnt += 1
    
print(cnt)

n = int(input())

cnt = 0
for i in range(1, n+1):
  if i%3 != 0 and i%5 != 0:
    cnt += i

print(cnt)


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
a = 0
for i in range(N):
  x =i+1
  if x%3!=0 andx%5!=0:
    a+=x
print(x)

N = int(input())
a = 0
for i in range(N):
  x =i+1
  if x%3!=0 and x%5!=0:
    a+=x
print(a)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
total = 0
for i in range(int(input())):
  if (i+1 % 3 != 0) and (i+1 % 5 != 0):
    total += i+1
        
print(total)

n = [int(i+1) for i in range(input())]

total = 0
for i in n:
  	if (n % 3 =! 0) and (n % 5 =! 0):
      	total += i
        
print(total)

total = 0
for i in range(int(input())):
  if int((i+1) % 3) != 0:
    if int((i+1) % 5) != 0:
    	total += i+1
        
print(total)

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
# 1 <= N <= 1000000
N = int(input())

total = []

for x in range(1, N+1):
    if not(x % 15 == 0 and x % 5 == 0 and x % 3 == 0):
        total.append(x)
        print(sum(total))
        

# 1 <= N <= 1000000
for i in range(0, 100001):
    if i % 3 and i % 5 == 0:
        print("FizzBuzz")
    elif i % 3 == 0:
        print("Fizz")
    elif i % 5 == 0:
        print("Buzz")
    else:
        print(i)




N = int(input())
# 1 <= N <= 1000000

for N in range(0, 100001):
    if N % 3 and N % 5 == 0:
        print("FizzBuzz")
    elif N % 3 == 0:
        print("Fizz")
    elif N % 5 == 0:
        print("Buzz")
    else:
        print(N)




# 1 <= N <= 1000000
N = int(input())

total = []

for x in range(1, N+1):
    if not(x % 15 == 0 or x % 5 == 0 or x % 3 == 0):
        total.append(x)
        print(sum(total))


# 1 <= N <= 1000000
N = int(input())

total = []


for x in range(1, N+1):
    if x % 15 == 0:
        "FizzBuzz"
    elif x % 5 == 0:
        "Buzz"
    elif x % 3 == 0:
        "Fizz"
    else:
        print(total)
        total.append(x) 
print(sum(total))

# 1 <= N <= 1000000
N = int(input())

total = []


for x in range(1, N+1):
    if x % 15 == 0:
        "FizzBuzz"
    elif x % 5 == 0:
        "Buzz"
    elif x % 3 == 0:
        "Fizz"
    else:
        print(total)
        total.append(x) 
print(sum(total))


# 1 <= N <= 1000000
for i in range(1, 10000):
    if i % 3 and i % 5 == 0:
        print("FizzBuzz")
    elif i % 3 == 0:
        print("Fizz")
    elif i % 5 == 0:
        print("Buzz")
    else:
        print(i)




# 1 <= N <= 1000000
N = int(input())

for i in range(0, N+1):
    if i % 15 == 0:
        print("FizzBuzz")
    elif i % 3 == 0:
        print("Fizz")
    elif i % 5 == 0:
        print("Buzz")
    else:
        print(i)





# 1 <= N <= 1000000
N = int(input())

total = []


for x in range(1, N+1):
    if x % 15 == 0:
        "FizzBuzz"
    elif x % 5 == 0:
        "Buzz"
    elif x % 3 == 0:
        "Fizz"
    else:
        total.append(x) 
print(sum(total))

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Runtime Error

Runtime Error

Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
# 1 <= N <= 1000000
N = int(input())
 
total = []
 
for x in range(1, N+1):
    if not(x % 15 == 0 or x % 5 == 0 or x % 3 == 0):
        total.append(x)
        print(sum(total))

N = int(input())
sum = 0

for i in range(1, N + 1):
    if i % 3 != 0 and i % 5 != 0:
        sum += i

print(sum)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())
n3=n//3
s3=((n3)*3)(n3+1)//2
n5=n//5
s5=((n5)*5)(n5+1)//2
n15=n//15
s15=((n15)*15)(n15+1)//2

s=n*(n+1)//2
s=s-s3-s5+s15
print(s)

n=int(input())
n3=n//3
s3=(n3*3)*(n3+1)//2
n5=n//5
s5=((n5)*5)*(n5+1)//2
n15=n//15
s15=((n15)*15)*(n15+1)//2
 
s=n*(n+1)//2
s=s-s3-s5+s15
print(s)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = 1000000#int(input())
a = list(range(1,N+1))
N_3 = N//3
N_5 = N//5
for i in range(1,N_3+1):
    a[3*i-1] = 0
for i in range(1,N_5+1):
    a[5*i-1] = 0
print(sum(a))

N = int(input())
a = list(range(1,N+1))
N_3 = N//3
N_5 = N//5
for i in range(1,N_3+1):
    a[3*i-1] = 0
for i in range(1,N_5+1):
    a[5*i-1] = 0
print(sum(a))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
ans = 0
for i in range(1, n):
    if 0 != i%3 and 0 != i%5:
        ans += i
print(ans)

n = int(input())
ans = 0
for i in range(1, n):
    if (0 != i%3) or (0 != i%5):
        ans += i
print(ans)

ans = 0
for i in range(int(input())+1):
    if i%3 != 0 and i%5 != 0:
        ans += i
print(ans)

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())

sum = 0
for i in range(N):
  if i % 3 == 0 and i % 5 == 0:
    continue
  elif i % 3 == 0:
    continue
  elif i % 5 == 0:
    continue
  else:
    sum += i

print(i)

N = int(input())
total = 0
for i in range(1,N+1):
    if i % 3 == 0 and i % 5 == 0:
        continue
    elif i % 3 == 0:
        continue
    elif i % 5 == 0:
        continue
    else:
        total += i
    

print(total)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
#B
n = int(input())
ans=0
for i in range(1, n + 1):
    if i % 3 == 0 or i % 5 == 0:
        ans += i
        print(i)
print(ans)


#B
n = int(input())
ans=0
for i in range(1, n + 1):
    if i % 3 != 0 and i % 5 != 0:
        ans += i
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
s = 0
for  i  in range(1,N+1):
  if i % 3 != 0 and i % 5 != 0:
    s += i
print(s)

n = int(input())
s = 0
for  i  in range(1,n+1):
  if i % 3 != 0 and i % 5 != 0:
    s += i
print(s)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
sum = 0
for i in range(n):
  if n%3!==0 and n%5!==0:
    sum += i
print(sum)

n = int(input())
sum = 0
for i in range(n+1):
    if (i%3)!=0 and (i%5)!=0:
        sum += i
print(sum)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())
B=0
for i in range(N):
    if (i+1)%3!=0 and (i+1)%5!=0:
        B=i+B
        
print(B)
        
        
       
        


N=int(input())
B=0
for i in range(N):
    if (i+1)%3!=0 and (i+1)%5==0:
        B=i+B
        
print(B)
        
        
       
        


N=int(input())
B=0
for i in range(N):
    if (i+1)%3!=0 and (i+1)%5==0:
        B=i+B
        print(B)
        
        
       
        

N=int(input())
B=0
for i in range(N):
    if (i+1)%3!=0 and (i+1)%5!=0:
        B=i+1+B
        
print(B)
        
        
       
        


Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
s = 0
for i in range(1,N+1):
    if i%3 != 0 and i%5 != 0:
        s += i
    print(s)

N = int(input())
s = 0
for i in range(1,N+1):
    if i%3 != 0 and i%5 != 0:
        s += i
print(s)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())

ans = 0
for i in range(1, N + 1):
  if i % 3 !=0 and i %5 != 0:
    ans +=1
print(ans)

N = int(input())
  
ans = 0
for i in range(1, N + 1):
  if i % 3 !=0 and i %5 != 0:
    ans +=i
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())

total = 0

for i in range(n):
  if (i+1)%3 != 0 and (i+!)%5 != 0:
    total += i+1
    
print(total)

n = int(input())

total = 0

for i in range(n):
  if (i+1)%3 != 0 and (i+1)%5 != 0:
    total += i+1
    
print(total)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
sum = 0
for i in range(n):
  if i%3 == 0:
  elif i%5 == 0:
  else:
    sum += i
print(sum)


n = int(input())
sum = 0
for i in range(n+1):
  if i%3 == 0 or i%5 == 0:
    sum += 0
  else:
    sum += i
print(sum)


Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
s = int(input())
sum = 0
for i in range(1,s+1):
  if i!3 == 0 and i!5 == 0:
    i == 0
  elif i!3 or i!5==0:
    i ==0
  else:
    sum += i
print(sum)    

s = int(input())
sum = 0
for i in range(1,s+1):
    if i%3 == 0 and i%5 == 0:
        j=0
    elif i%3==0 or i%5==0:
        j=0
    else:
      
        sum += i
print(sum)    

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input());
sum = 0;

for i in range(N):
  num = i + 1;
  if num % 3 != 0 and num % 5 !=0:
    sum += num;
  else:
    pass;

print(num)

N = input();
sum = 0;

for i in range(N):
  num = i + 1;
  if num % 3 != 0 and num % 5 !=0:
    sum += num;
  else:
    pass;

print(num)
   
    

N = int(input());
sum = 0;

for i in range(N):
  num = i + 1;
  if num % 3 != 0 and num % 5 !=0:
    sum += num;
  else:
    pass;

print(sum)


Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
zinput = int(input())
a = []
b = []
i = 1
while(i <= input):
  if i%3 == 0 and i%5 == 0:
    a[i] = "FizzBuzz"
  elif i%3 == 0:
    a[i] = "Fizz"
  elif i%5 == 0:
    a[i] = "Buzz"
  else:
    a[i] = "i"
  i += 1
sum = 0
for j in a:
  if a[j] != "FizzBuzz" and a[j] != "Fizz" and a[j] != "Buzz":
    sum = sum + int(a[j])
print(sum)



input = int(input())
a = []
i = 1
while(i <= input):
  if i%3 == 0 and i%5 == 0:
    a[i] = FizzBuzz
  elif i%3 == 0:
    a[i] = Fizz
  elif i%5 == 0:
    a[i] = Buzz
  else:
    a[i] = i
  i += 1
sum = 0
for j in a:
  if a[i] != "Fizz" and a[i] != "Buzz" and a[i] != "FizzBuzz":
    sum = sum + a[i]
print(sum)

input = int(input())
a = []
i = 1
while(i <= input):
  if i%3 == 0 and i%5 == 0:
    a[i] = FizzBuzz
  elif i%3 == 0:
    a[i] = Fizz
  elif i%5 == 0:
    a[i] = Buzz
  else:
    a[i] = i
  i += 1
sum = 0
for j in a:
  if a[j] != "Fizz" and a[j] != "Buzz" and a[j] != "FizzBuzz":
    sum = sum + a[j]
print(sum)


input = int(input())
a = []
while(i <= input):
  if i%3 == 0 or i%5 == 0:
    pass
  else:
    a.append(i)
  i += 1
sum = 0
for j in a:
    sum = sum + a[j]
print(sum)



input = int(input())
a = []
while(i <= input):
    if i%3 == 0 or i%5 == 0:
        pass
    else:
        a.append(i)
    i += 1

print(sum(a))



zinput = int(input())
a = []
b = []
i = 1
while(i <= input):
  if i%3 == 0 and i%5 == 0:
    a[i] = "FizzBuzz"
  elif i%3 == 0:
    a[i] = "Fizz"
  elif i%5 == 0:
    a[i] = "Buzz"
  else:
    a[i] = i
    b.append(i)
  i += 1
sum = 0
for j in a:
    sum = sum + b[j]
print(sum)



input = input()
a = []
i = 1
while(i <= int(input)):
    if i%3 == 0 or i%5 == 0:
        pass
    else:
        a.append(i)
    i += 1
res = 0
for j in a:
  res = res + j
print(res)



Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())
Fi=N//3
Bu=N//5
FiBu=N//15
def ans(x):
    return x*(x+1)/2
print(ans(N)-ans(Fi)*3-ans(Bu)*5+ans(FiBu)*15)

N=int(input())
Fi=N//3
Bu=N//5
FiBu=N//15
def ans(x):
    return x*(x+1)//2
print(ans(N)-ans(Fi)*3-ans(Bu)*5+ans(FiBu)*15)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
list = []

for i in range(N):
	if (i+1) % 3 == 0:
	
	elif (i+1) % 5 == 0:
	
	else:
		list.append(i+1)

print(sum(list))

N = int(input())
list = []
 
for i in range(N):
  if (i+1) % 3 == 0:
    pass
  elif (i+1) % 5 == 0:
    pass
  else:
    list.append(i+1)
    
print(sum(list))

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())
count=0
for i in range(n+1):
    if i%5!=0 and i%3!=0:
        count+=i
        print(i)
print(count)


n=int(input())
count=0
for i in range(n+1):
    if i%5!=0 and i%3!=0:
        count+=i
print(count)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = input()
b = 0
s = 0
for i in n:
    if i%3 == 0 or i%5 == 0:
        continue
    else:
        s += i
        
print(s)

n = int(input())
b = 0
s = 0
for i in range(1,n+1):
    if i%3 == 0 or i%5 == 0:
        continue
    else:
        s += i
        
print(s)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())
a=[0 for i in range(n)]
for i in range(m): #0,1,
    if i%3!=0 and i%5!=0:
        a[i]=int(i+1)

print(sum(a))


n=int(input())
a=[0 for i in range(n+1)]
for i in range(n+1): 
    if i%3!=0 and i%5!=0:
        a[i]=int(i)

print(sum(a))


Verdicts: Runtime Error

Accepted