TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
for i in N:
  if (i+1) % 3 == 0 or (i+1) % 5 == 0:
    pass
  else:
    m = i + 2

print(int(m))

N = int(input())
i = 1
m = 0
for i in range(N+1):
  if not i % 3 == 0 or i % 5 == 0:
    m += i
    i += 1
 
print (m)

N = int(input())
i = 1
m = 0
for i in range(N+1):
  if not i % 3 == 0 or i % 5 == 0:
    m += i
 
print (m)

N = int(input())
m = 0
for i in range(N+1):
  if not i % 3 == 0 or i % 5 == 0:
    m += i
 
print (m)

N = int(input())
i = 1
for i in N+1:
  if not i % 3 == 0 or i % 5 == 0:
    m += i

print (m)

N = int(input())
m = 0
for i in range(N+1):
  if not (i % 3 == 0 or i % 5 == 0):
    m += i
 
print (m)

Verdicts: Runtime Error

Wrong Answer

Wrong Answer

Wrong Answer

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
def fizz_buzz_sum(N):
  not_fizz_buzz = [i for i in range(N) if (i%3 != 0) and (i%5 != 0)]
  return sum(not_fizz_buzz)

def fizz_buzz_sum(N):
  not_fizz_buzz = [i for i in range(1, N+1) if (i%3 != 0) and (i%5 != 0)]
  return sum(not_fizz_buzz)

print(fizz_buzz_sum(int(input())))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
total_sum=[]


for i in range(1, n + 1 ):
    if i % 15 ==0:
     "FizzBuzz"
    if i % 3 == 0:
      "Fizz"
    if i % 5 == 0:
      "Buzz"
    else:
     total_sum.append(i)
        
print(sum(total_sum))

n = int(input())

total = []


for i in range(1, n + 1):
    if i % 15 == 0:
        "FizzBuzz"
    elif i % 5 == 0:
        "Buzz"
    elif i % 3 == 0:
        "Fizz"
    else:
        total.append(i)  
print(sum(total))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())
array=[]
for i in range(N+1):
    if i%3!=0 and i%5!=0:
        array.append(i)

print(array)
value=sum(array)
print(value)

N=int(input())
array=[]
N+=1

for i in range(1,N):
    if i%3!=0 and i%5!=0:
        array.append(i)

value=sum(array)
print(value)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
n3=N//3
n5=N//5
n15=N//15
S3 = 0.5*n3*(2*3+(n3-1)*3)
S5 = 0.5*n5*(2*5+(n5-1)*5)
S15 = 0.5*n15*(2*15+(n15-1)*15)
S=(N+1)*N/2
print(S-S3-S5+S15)

N = int(input())
n3=N//3
n5=N//5
n15=N//15
S3 = 0.5*n3*(2*3+(n3-1)*3)
S5 = 0.5*n5*(2*5+(n5-1)*5)
S15 = 0.5*n15*(2*15+(n15-1)*15)
S=(N+1)*N/2
print(int(S-S3-S5+S15))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
fizz = []
buzz = []
fizzbuzz = []
other = []
n = int(input())
for i in range(n):
    temp = i+1
    if (temp % 3 != 0) & (temp % 5 != 0):
        print(i+1)
        other.append(i+1)

b = sum(other)

print(b)





fizz = []
buzz = []
fizzbuzz = []
other = []
n = int(input())
for i in range(n):
    temp = i+1
    if (temp % 3 != 0) & (temp % 5 != 0):
        other.append(temp)

b = sum(other)

print(b)





Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
x=int(input())
t=0
for i in range(1,x+1):
  print(i)
  if i%3!=0 and i%5!=0:
    t+=i
print(t)


x=int(input())
t=0
for i in range(1,x+1):
  if i%3!=0 and i%5!=0:
    t+=i
print(t)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
tmp = n // 15
tmp2 = n % 15
d = [(15*(tmp) + i) for i in [0,1,2,0,4,0,0,7,8,0,0,11,0,13,14]]
for i in [0,3,5,6,9,10,12]:
    d[i] = 0
(tmp **2 * 60) + sum(d[:(tmp2+1)])

n = int(input())
tmp = n // 15
tmp2 = n % 15
d = [(15*(tmp) + i) for i in [0,1,2,0,4,0,0,7,8,0,0,11,0,13,14]]
for i in [0,3,5,6,9,10,12]:
    d[i] = 0
print((tmp **2 * 60) + sum(d[:(tmp2+1)]))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
D = [1, 3, 3, 7, 7, 7, 14, 22, 22, 22, 33, 33, 46, 60, 60]

N = int(input())

N -= 1
s = N//15
t = (60*s)*(s+1)

m = s*15
t += D[N-m] + 15*(N-m+1)

print(t)


D = [0, 1, 3, 3, 7, 7, 7, 14, 22, 22, 22, 33, 33, 46, 60, 0]
E = [0, 1, 2, 2, 3, 3, 3,  4,  5,  5,  5,  6,  6,  7,  8, 0]

N = int(input())

s = N//15
t = (60*s)*(s)

m = s*15

t += D[N-m] + 15*E[N-m]*s

print(t)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = input()
xx= 0
for i in range(1,N+1):
    if((i%3!=0)&(i%5!=0)):
        xx += i
print(xx)

N = int(input())
xx= 0
for i in range(1,N+1):
    if((i%3!=0)&(i%5!=0)):
        xx += i
print(xx)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
def palin(x):
    #print(x)
    if x == x[::-1]: return True
    return False
 
a = input()
n = len(a)
if palin(a) and palin(a[:int((n-1)/2)]) and palin(a[int((n+3)/2)-1:]):
    print("Yes")
else: print("No")

N = int(input())
ans = 0
for i in range(1, N + 1):
    if i % 3 != 0 and i % 5 != 0:
        ans += i
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
x = 0
n = input(input())
for i in range(1,n+1):
    if i % 3 != 0 and i % 5 != 0:
        x += i
print(x)


n = int(input())
ans = 0
for i in range(n+1):
    if i%15!=0 and i%3!=0 and i%5!=0:
        ans += i
print(ans)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())

sum=0
while a in range(N+1):
  if a%3 !=0 and a%5 !=0:
    sum=sum+a
    a = a + 1
  else:a=a+1
print(sum)


N=input()
a=1
sum=0
while a in range(N):
  if a%3 !=0 and a%5 !=0:
    sum=sum+a
    a = a + 1
print(sum)

N=int(input())
a=1
sum=0
while a in range(N):
  if a%3 !=0 and a%5 !=0:
    sum=sum+a
    a = a + 1
print(sum)


N=int(input())
a=1
sum=0
while a in range(N+1):
  if a%3 !=0 and a%5 !=0:
    sum=sum+a
    a = a + 1
  else:a=a+1
print(sum)


Verdicts: Runtime Error

Runtime Error

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
sum =0
for i in range(1,n+1):
  if i%3 !=0 and i%5 !=0:
    sum += i
    print(sum)

n = int(input())
sum =0
for i in range(1,n+1):
  if i%3 !=0 and i%5 !=0:
    sum += i
print(sum)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
total = 0
for i in range(1, N+1):
  if （i%3) !=0 and (i%5) !=0:
    total += i
print(total)


N = int(input())
total = 0
for i in range(1, N+1):
  if N%3 == 0 and N%5 == 0:
    total += i
print(total)

N = int(input())
total = 0
for i in range(1, N+1):
  if (i%3) != 0 and (i%5) != 0:
    total += i
print(total)


Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
ret = 0
for i in range(1, N):
  if N % 3 != 0 and N % 5 != 0:
    ret += i
print(ret)

N = int(input())
ret = 0
for i in range(1,N+1):
    if i % 3 != 0 and i % 5 != 0:
        ret += i
print(ret)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
str = input()
if str[0] == "7" or str[1] == "7" or str[2] == "7": print("Yes")
else: print("No")

num = int(input())
ans = 0
for x in range(num + 1):
    if x % 3 == 0 or x % 5 == 0: pass
    else: ans += x
print(ans)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
sol = 0
for x in range(1, n+1):
  if x%3 != 0 and x%5 != 0:
    sol += x
print(x)

n = int(input())
sol = 0
for x in range(1, n+1):
  if x%3 != 0 and x%5 != 0:
    sol += x
print(sol)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
import numpy as np
def main():
    n = int(input())
    arr = np.arange(n + 1)
    arr[3::3] = 0
    arr[5::5] = 0
    print(arr)
    print(arr.sum())
if __name__ =='__main__':
    main()  

import numpy as np
def main():
    n = int(input())
    arr = np.arange(n + 1)
    arr[3::3] = 0
    arr[5::5] = 0
    print(arr.sum())
if __name__ =='__main__':
    main()  

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
FizzBuzz = int(input())

Sum = []
for i in range(FizzBizz):
    if FizzBuzz[i] % 3 == 0 and FizzBuzz[i] % 5 == 0:
        Sum.append(i)
    else:
        Sum.append(0)
print(sum(Sum))


FizzBizz = int(input())

Sum = []
for i in range(1, FizzBizz+1):
    if i % 3 != 0 and i % 5 != 0:
        Sum.append(i)
    else:
        Sum.append(0)
print(sum(Sum))

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
res = 0
for i in range(1,n+1):
  if i%3==0 or i%5: continue
  res+=i
print(res)

n = int(input())
res = 0
for i in range(1,n+1):
  if i%3 or i%5: continue
  res+=i
print(res)

n = int(input())
res = 0
for i in range(1,n+1):
  if i%3==0 or i%5==0: continue
  res+=i
print(res)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
import sys, os

if __name__ == '__main__':
    N = input()
    s = 0
    for i in range(1, N+1):
        if i % 3 ==0 or i % 5 ==0:
            continue
        else:
            s += i
    print(s)


import sys, os

if __name__ == '__main__':
    N = input()
    s = 0
    for i in range(1, N+1):
        if i % 3 ==0 or i % 5 ==0:
            continue
        else:
            s += i
    print(s)

import sys, os

if __name__ == '__main__':
    N = int(input())
    s = 0
    for i in range(1, N+1):
        if i % 3 ==0 or i % 5 ==0:
            continue
        else:
            s += i
    print(s)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
ans = 0
for i in range(1, N+1):
    if i % 15 == 0:
        continue
    elif i % 3 == 0:
        continue
    elif i % 5 == 0:
        continue
    else:
        ans += 1
print(ans)

N = int(input())
print("\n".join(["FizzBuzz" if n % 15 == 0 else "Fizz" if n % 3 == 0 else "Buzz" if n % 5 == 0 else str(n) for n in range(1,N+1)]))

N = int(input())
ans = 0
for i in range(1, N+1):
    if i % 15 == 0:
        continue
    elif i % 3 == 0:
        continue
    elif i % 5 == 0:
        continue
    else:
        ans+=i
print(ans)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
import sys

n = int(sys.argv[1])
total = 0

for i in range(n):
	if (i % 3 != 0) and (i % 5 != 0):
		total += i

print(total)

n = input()
total = 0

for i in range(n):
	if (i % 3 != 0) and (i % 5 != 0):
		total += i

print(total)

n = int(input())
total = 0

for j in range(n):
	i = j+1
	if (i % 3 != 0) and (i % 5 != 0):
		total += i

print(total)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
import math

x=int256(input())
s=math.floor(x/3)
f=math.floor(x/5)
sf=math.floor(x/15)

s_sum=math.floor(3*s*(s+1)/2)
f_sum=math.floor(5*f*(f+1)/2)
sf_sum=math.floor(15*sf*(sf+1)/2)

sum=s_sum+f_sum-sf_sum
print(math.floor(sum))


import math

x=int(input())
s=math.floor(x/3)
f=math.floor(x/5)
sf=math.floor(x/15)

s_sum=3*s*(s+1)/2
f_sum=5*f*(f+1)/2
sf_sum=15*sf*(sf+1)/2

sum=s_sum+f_sum-sf_sum
print(sum)


import math

x=int(input())
s=math.floor(x/3)
f=math.floor(x/5)
sf=math.floor(x/15)
sum=math.floor(x*(x+1)/2)

s_sum=math.floor(3*s*(s+1)/2)
f_sum=math.floor(5*f*(f+1)/2)
sf_sum=math.floor(15*sf*(sf+1)/2)

fl=sum-(s_sum+f_sum-sf_sum)
print(math.floor(fl))


Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())
if(n%3==0):
  if(n%5==0):
    print("FizzBuzz")
  else:
    print("Fizz")
else:
  if(n%5==0):
    print("Buzz")
  else:
    print(str(n))

def judge(num):
  if(n%3==0):
    if(n%5==0):
      print("FizzBuzz")
    else:
      print("Fizz")
  else:
    if(n%5==0):
      print("Buzz")
    else:
      print(str(n))

n=int(input())
for i in range(1,n+1):
  judge(i)

def judge(n):
  if(n%3==0):
    if(n%5==0):
      print("FizzBuzz",end="")
    else:
      print("Fizz",end="")
  else:
    if(n%5==0):
      print("Buzz",end="")
    else:
      print(str(n),end="")

m=int(input())
for i in range(1,m+1):
  judge(i)

def could_divide(num):
  return (num%3==0 or num%5==0)
n=int(input())
answer=0
for i in range(1,n+1):
  if(not could_divide(i)):
    answer+=i
print(answer)

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
sum = 0

for i in range(1, n):
    if i%3 == 0 and i%5 == 0:
        sum = sum
    else:
        sum += i

print(sum)


n = int(input())
sum = 0

for i in range(1, n+1):
    if i%3 != 0 and i%5 != 0:
        sum += i

print(sum)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())

count = 0
for in range(n):
    if i % 3 > 0 and i % 5 > 0:
        count += i
        
print(count)

n = int(input())

count = 0
for i in range(n + 1):
    if i % 3 > 0 and i % 5 > 0:
        count += i
        
print(count)


Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
ans = 0
for i in range(1,N+1):
    if i%3!=0 and i%5!=0 :
        ans += 1
print(ans)

N = int(input())
ans = 0
for i in range(N+1):
    if i%3!=0 and i%5!=0 :
        ans += 1
print(ans)

N = int(input())
ans = 0
for i in range(N+1):
  if i%3!=0 or i%5!=0:
    ans += i
print(ans)

N = input()
print('Yes' if '7' in N else 'No') 

N = int(input())
ans = 0
for i in range(0,N+1):
    if i%3!=0 and i%5!=0 :
        ans += 1
print(ans)

N = int(input())
ans = 0
for i in range(N+1):
    if i%3!=0 and i%5!=0 :
        ans += i
print(ans)

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
none_num = [i for i in range(1, N+1) if i%3 != 0 and i%5 != 0]
none = sum(none_num)

K = int(input())
x = (K+1) * K//2
num_devisible_three = (3+3*(K//3))*(K//3)//2
num_devisible_five = (5+5*(K//5))*(K//5)//2
num_devisible_fifteen = (15+15*(K//15))*(K//15)//2
print(x-num_devisible_three-num_devisible_five+num_devisible_fifteen)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):


number = int(input())
Total = []

for i in range(1, number + 1):
    if number % 3 == 0 and i % 5 == 0:
        print("FizzBuzz")
    elif i % 3 ==0:
        print("Fizz")
    elif i % 5 == 0:
        print("Buzz")
    else:
        Total.append(i)

print(sum(Total))


number = int(input())
Total = []

for i in range(1, number + 1):
    if number % 3 == 0 and i % 5 ==0:
        "FizzBuzz"
    elif i % 3 ==0:
        "Fizz"
    elif i % 5 == 0:
        "Buzz"
    else:
        Total.append(i)

print(sum(Total))


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = input()
sum = 0
for i in range(1, N+1):
    if i % 3 != 0 and i % 5 != 0:
        sum += i

print(sum)


N = int(input())
sum = 0
for i in range(1, N+1):
    if i % 3 != 0 and i % 5 != 0:
        sum += i

print(sum)


Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
l = [i for i in range(1,n+1)]
l = list(filter(lambda x: x%3 != 0,l))
l = list(filter(lambda x; x%5 != 0,l))
print(sum(l))

n = int(input())
l = [i for i in range(1,n+1)]
l = list(filter(lambda x: x%3 != 0,l))
l = list(filter(lambda x: x%5 != 0,l))
print(sum(l))


Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = input()
S = 0
for i in range(1, N+1):
	if i%3==0 or i%5==0 or (i%3==0 and i%5==0 ):
      continue
    S += i
    
print(S)

N = input()
S = 0
for i in range(1, N+1):
	if i%3==0 or i%5==0:
      continue
    S += i
    
print(S)

N = int(input())
S = 0
for i in range(1, N+1):
    if i%3==0 or i%5==0 or (i%3==0 and i%5==0):
        continue
    S+=i
print(S)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
term = int(input())
sum = 0
for i in range(1, N + 1):
    if i % 3 != 0 and i % 5 != 0:
        sum += i
print(sum)

N = int(input())
l = [i for i in range(1, int(input()) + 1) if i % 3 != 0 and i % 5 != 0]
s = sum(l)
print(s)

N = int(input())
l = i for i in range(1, int(input()) + 1) if i % 3 != 0 and i % 5 != 0
s = sum(l)
print(s)

N = int(input())
l = [i for i in range(1, N + 1) if i % 3 != 0 and i % 5 != 0]
s = sum(l)
print(s)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
ans = 0
for i in range(1. n+1):
    if i%3 == 0 or i%5 == 0:
        ans += i
print(ans)

n = int(input())
ans = 0
for i in range(1, n+1):
    if i%3 != 0 and i%5 != 0:
        ans += i
print(ans)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())

sum_num = 0
for i in range(1, N+1):
    if N%3 and N%5:
        sum_num += i

print(sum_num)

N = int(input())

sum_num = 0
for i in range(1, N+1):
    if (i%3) and (i%5):
        sum_num += i

print(sum_num)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
#!/usr/bin/env python

import sys

N = int(sys.stdin.readline())

nfizz = N // 3
nbuzz = N // 5
nfizzbuzz = N // 15

tot = (1 + N) * N / 2
tot_fizz = 3 * (1 + nfizz) * nfizz / 2
tot_buzz = 5 * (1 + nbuzz) * nbuzz / 2
tot_fizzbuzz = 15 * (1 + nfizzbuzz) * nfizzbuzz / 2

tot = tot - (tot_fizz + tot_buzz - tot_fizzbuzz)

print(tot)




#!/usr/bin/env python

import sys

N = int(sys.stdin.readline())

nfizz = N // 3
nbuzz = N // 5
nfizzbuzz = N // 15

tot = (1 + N) * N // 2
tot_fizz = 3 * (1 + nfizz) * nfizz // 2
tot_buzz = 5 * (1 + nbuzz) * nbuzz // 2
tot_fizzbuzz = 15 * (1 + nfizzbuzz) * nfizzbuzz // 2

tot = tot - (tot_fizz + tot_buzz - tot_fizzbuzz)

print(tot)




Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
count = 0
for i in range(1, N+1):
  if N%3 != 0 and N%5 != 0:
    count = count + i
print(count)


N = int(input())
count = 0
for i in range(1, N+1):
  if N%3 != 0 and N%5 != 0:
    count = count + 1
print(count)

N = int(input())
count = 0
for i in range(1, N+1):
  if i%3 != 0 and i%5 != 0:
    count = count + i
print(count)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
i = int(input)
fizz=[]
for x in i:
  if x % 3 ==0 and x%5==0:
    return 
  elif x % 3==0:
    return
  elif x%5==0:
    return 
  else:
    fizz.append(i)
print(sum(fizz))

i = int(input())
fizz=[]
for x in range(1, i+1):
  if x % 3 ==0 and x%5==0:
    continue
  elif x % 3==0:
    continue
  elif x%5==0:
    continue 
  else:
    fizz.append(x)
print(fizz)
print(sum(fizz))

i = int(input())
fizz=[]
for x in range(i):
  if x % 3 ==0 and x%5==0:
    continue
  elif x % 3==0:
    continue
  elif x%5==0:
    continue 
  else:
    fizz.append(x)
print(fizz)
print(sum(fizz))

i = int(input())
fizz=[]
for x in range(1, i+1):
  if x % 3 ==0 and x%5==0:
    continue
  elif x % 3==0:
    continue
  elif x%5==0:
    continue 
  else:
    fizz.append(x)
print(sum(fizz))

Verdicts: Runtime Error

Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input(15))
count = 0
for i in range(1,n):
  if i%3!=0 and i%5!=0:
    count+=i
print(count)

n = int(input())
counter = 0
for i in range(1,n+1):
  if i%3==0 or i%5==0:
    counter+=0
  else:  
    counter+=i
  
print(counter)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
x = int(input())
ans = 0
for i in range(x+1):
    if (i%3 != 0) and (i%5 != 0):
      a += i

print(a)

x = int(input())
ans = 0
for i in range(x+1):
    if (i%3 != 0) and (i%5 != 0):
      ans += i

print(ans)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
x = 0
for i in range(1,1+N):
  if N % 3 != 0 or N%5 !=0:
    x += i
print(x)


N = int(input())
x=0
for i in range(1,1+N):
  if N % 3 != 0 and N%5 !=0:
    x += i
print(x)


N = int(input())
x=0
for i in range(1,1+N):
  if (N % 3) != 0 or (N%5) !=0:
    x = x + i
print(x)


N = int(input())
x=0
for i in range(1,1+N):
  if (N % 3) != 0 and (N % 5) !=0:
    x = x + i
print(x)


N = int(input())
for i in range(1,1+N):
  if N % 3 != 0 or N%5 !=0:
    x += i
print(x)

N = int(input())
x=0
for i in range(1,1+N):
  if N % 3 != 0 or N%5 !=0:
    x = x + i
print(x)


N = int(input())
for i in range N:
  if i % 3 ==0 or i % 5 ==0:
    x += i
print(x)
  

N = int(input())
x=0
for i in range(1,1+N):
  if N % 3 != 0 and N%5 !=0:
    x = x + i
print(x)


N = int(input())
x = 0
for i in range(1, N+1):
    if (i % 3) != 0 and (i % 5) != 0:
        x = x+i
print(x)

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Runtime Error

Wrong Answer

Runtime Error

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
for i in range(1, n+1):
  if i%3!==0 and i%5!==0:
    a+=i
print(i)

n = int(input())
for i in range(1, n+1):
  if i%3!=0 and i%5!=0:
    a+=i
print(i)

n = int(input())
a=0
for i in range(1, n+1):
  if i%3!=0 and i%5!=0:
    a=a+i
print(i)

n = int(input())
a=0
for i in range(1, n+1):
  if i%3!=0 and i%5!=0:
    a=a+i
print(a)

Verdicts: Runtime Error

Runtime Error

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())

a = N // 3
b = N // 5
c = N // 15

d = 3*a*(a+1)/2
e = 3*b*(b+1)/2
f = 3*c*(c+1)/2

g = N*(N+1)/2

print(g-d-e+f)

N = int(input())

import math
 
a = N // 3
b = N // 5
c = N // 15
 
d = 3*a*(a+1)/2
e = 5*b*(b+1)/2
f = 15*c*(c+1)/2
 
g = N*(N+1)/2
 
print(math.floor(g-d-e+f))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
sum([i for i in range(1, int(input())+1) if i % 3 != 0 and i % 5 != 0])

print(sum([i for i in range(1, int(input())+1) if i % 3 != 0 and i % 5 != 0]))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = input()
i = 1
result = 0
while (i <= n):
  if (i % 3 == 0 || i % 5 == 0):
    result += i
print(result)

n = input()
i = 1
result = 0
while (i <= n):
  if (i % 3 != 0 and i % 5 != 0):
    result += i
  i += 1
print(result)

n = int(input())
i = 1
result = 0
while (i <= n):
  if (i % 3 != 0 and i % 5 != 0):
    result += i
  i += 1
print(result)


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = input()
lit_N = []
for i in range(int(N)+1):
  if i % 5 == 0 and i % 3 == 0:
    lit_N.append("FizzBuzz")
  elif i % 3 == 0:
    lit_N.append("Fizz")
  elif i % 5 == 0:
  	lit_N.append("Buzz")
  else:
    lit_N.append(i)
print(sum(filter(int, lit_N[1:])))

N = input()
lit_N = []
for i in range(int(N)+1):
  if i % 5 == 0 and i % 3 == 0:
    lit_N.append("FizzBuzz")
  elif i % 3 == 0:
    lit_N.append("Fizz")
  elif i % 5 == 0:
  	lit_N.append("Buzz")
  else:
    lit_N.append(i)
print(sum(list(filter(lambda x: isinstance(x,int), lit_N))))

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())  
 
A = []
for i in range(1,N):
#    print(i)
    if i % 3 == 0:
        A.append(0)
    elif i % 5 == 0:
		A.append(0)
    else:
        A.append(i)
 
print(sum(A))

N = int(input())

sum = 0
for i in range(1, N + 1):
    if i % 3 == 0:
        continue
    elif i % 5 == 0:
        continue
    else:
        sum += i

print(sum)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
seq = [i for in range(1,N) 
count = 0
for t in range(len(seq)):
  if seq[t]%3 != 0 or seq[t]%5 != 0:
       count += seq[t]
print(count)

N = int(input())
seq = [i for i in range(1,N+1)]
count = 0
for t in range(0,N):
	if seq[t]%3 != 0 and seq[t]%5 != 0:
		count += seq[t]
print(count)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
ans = 0
x = int(n / 15)
for i in range(x):
    ans += 15 + i * 8 * 15

amari = n % 15

plus = int(n / 15) * 15

if amari == 1:
    ans += plus + 1
elif amari == 2 or amari == 3:
    ans += plus + plus + 3
elif amari == 4 or amari == 5 or amari == 6:
    ans += plus + plus + plus + 7
elif amari == 7:
    ans += plus + plus + plus + plus + 14
elif amari == 8 or amari == 9 or amari == 10:
    ans += plus + plus + plus + plus + plus + 22
elif amari == 11 or amari == 12:
    ans += plus + plus + plus + plus + plus + plus + 33
elif amari == 13:
    ans += plus + plus + plus + plus + plus + plus + plus + 46
elif amari == 14:
    ans += plus + plus + plus + plus + plus + plus + plus + plus + 60

print(ans)

n = int(input())
ans = 0
x = int(n / 15)
for i in range(x):
    ans += 60 + i * 8 * 15

amari = n % 15

plus = int(n / 15) * 15

if amari == 1:
    ans += plus + 1
elif amari == 2 or amari == 3:
    ans += plus + plus + 3
elif amari == 4 or amari == 5 or amari == 6:
    ans += plus + plus + plus + 7
elif amari == 7:
    ans += plus + plus + plus + plus + 14
elif amari == 8 or amari == 9 or amari == 10:
    ans += plus + plus + plus + plus + plus + 22
elif amari == 11 or amari == 12:
    ans += plus + plus + plus + plus + plus + plus + 33
elif amari == 13:
    ans += plus + plus + plus + plus + plus + plus + plus + 46
elif amari == 14:
    ans += plus + plus + plus + plus + plus + plus + plus + plus + 60

print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = input()
sum = 0

for i in range(1, n+1):
  if i % 3 != 0 and i % 5 != 0:
    sum += i

print(sum)

n = int(input())
sum = 0

for i in range(1, n+1):
  if i % 3 != 0 and i % 5 != 0:
    sum += i

print(sum)


Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
if n / 15 == 0:
    n = 8
elif n / 3 == 0:
    n = 4
elif n / 5 == 0:
    n = 4
    total = 0
    for i in range(1, n +1):
        total += i
        print(total)

n = int(input())
total = 0
for i in range(n+1):
    if i % 3 != 0 and i % 5 != 0:
        total += i
print(total)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())

ans = 0

for i in range(1, n + 1):
  if i % 3 != 0 or i % 5 != 0:
    ans += i

print(ans)

n = int(input())

ans = 0

for i in range(1, n + 1):
  if i % 3 != 0 ans i % 5 != 0:
    ans += i

print(ans)

n = int(input())

ans = 0

for i in range(1, n + 1):
  if i % 3 != 0 and i % 5 != 0:
    ans += i

print(ans)

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
print(sum([i for i in range(int(input()+1)) if (i % 3 != 0 and i % 5 != 0)]))


print(sum([i for i in range(int(input())+1) if (i % 3 != 0 and i % 5 != 0)]))


Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())
ans=0
N=1
for i in range(N):
  N+=1
  if N//3 and N//5:
    pass
  elif N//3:
    pass
  elif N//5:
    pass
  else:
    ans=ans+N
print(ans)    
   
    
  

N=int(input())
list_=[]
M=0
for i in range(N):
    M=M+1
    if M%3!=0 and M%5!=0:
        list_.append(M)

print(sum(list_))    


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n, m = map(int, input().split())
a = list(map(int, input().split()))
a.sort()
print(a)
if a[-m] > 1 / (4 * m):
    print("Yes")
else:
    print("No")

n = int(input())
tmp, ans = 0, 0

while tmp < n:
    tmp = tmp + 1
    if tmp % 3 != 0 and tmp % 5 != 0:
        ans = ans + tmp
print(ans)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = longlong(input())

a = 0


for i in n:
	if(n%i*3 == 0 and n%i*5 == 0):
      a += i
    elif(n%i*3 == 0):
      a += i
    elif(n%i*5 == 0):
      a += i
print(i)
      
  
 

n = int(input())

a = 0


for i in range(1,n+1):
  
  if(i%3 == 0 or i%5 == 0):
    pass
  else:
    a += i
print(a)


Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())
a=n//3
b=n//5
c=n//15
N=n*(1+n)//2
print(N-3*a-5*b+15*c)

n=int(input())
a=n//3
b=n//5
c=n//15
N=n*(1+n)//2
A=3*a*(1+a)//2
B=5*b*(1+b)//2
C=15*c*(1+c)//2
print(N-A-B+C)

Verdicts: Wrong Answer

Accepted