TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())

N_list = list(range(1, N + 1))

ans = 0

for i in N_list:
    if not i % 3 == 0 or i % 5 == 0:
        ans += i
print(ans)

N = int(input())

N_list = list(range(1, N + 1))

ans = 0

for i in N_list:
    if not (i % 3 == 0 or i % 5 == 0):
        ans += i
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
ans = sum([i for i in range(n) if i % 3 != 0 or i % 5 != 0])
print(ans)


n = int(input())
ans = sum([i for i in range(n) if i % 3 == 0 or i % 5 == 0])
print(ans)


n = int(input())
ans = sum([i for i in range(n+1) if i % 3 != 0 and i % 5 != 0])
print(ans)


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
line = input()
if int(line) %3  ==0and int(line)%5==0:
  print("FizzBuzz")
elif int(line) %3 ==0:
  print("Fizz")
elif int(line) %5 ==0:
  print("Buzz")
else:
  print(int(line))


line = input()
cnt =0
for i in range(1,1+int(line)):
  if i %3  !=0:
    if i %5  !=0:
      cnt +=i
      
print(cnt)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
s = input()
ans = 'Yes' if '7' in s else 'No'
print(ans)


n = int(input())
print(sum(i for i in range(1, n+1) if i % 3 != 0 and i % 5 != 0))


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
count = 0
for i in range(n):
  if (n % 3 != 0) and (n % 5 != 0):
    count += i
print(count)

n = int(input())
count = 0
for i in range(n+1):
  if (i % 3 != 0) and (i % 5 != 0):
    count += i
print(count)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
sum = 0

for i in range(1, n + 1):
    if i % 3 != 0 && i % 5 != 0:
        sum += i

print(sum)


n = int(input())
sum = 0

for i in range(1, n + 1):
    if i % 3 != 0 and i % 5 != 0:
        sum += i

print(sum)


Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())
a=[i for i in range(N+1)]
for i in range(N+1):
  if i%3==0 or i%5==0:
    a[i]=0
sum(a)

N=int(input())
a=[i for i in range(N+1)]
for i in range(N+1):
  if i%3==0 or i%5==0:
    del(a[i])
sum(a)

N=int(input())
a=[i for i in range(N+1)]
for i in range(N+1):
  if i%3==0 or i%5==0:
    a[i]=0
print(sum(a))

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())
cnt=0
for i in range(1,n+1):
    if i%3 != 0 or i%5 != 0:
        cnt+=i
print(cnt)


n=int(input())
cnt=0
for i in range(1,n+1):
    if i%3 != 0:
        if i%5 != 0:
            cnt+=i
print(cnt)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
print(N//15*3)

N = int(input())

print(sum(filter(lambda x : (x%3 != 0) or (x%5 !=0), range(N)))) 



N = int(input())

print(sum(filter(lambda x : x%3 != 0 or x%5 !=, range(N)))) 



N = int(input())
a = 0
for i in range(1, N+1):
    if i%3 != 0 and i%5 != 0:
        a += i

print(a)

Verdicts: Wrong Answer

Wrong Answer

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())

l=list(range(1,n+1))
print(l)

count=0

for i in range(1,n+1) :
    if i%3!=0 and i%5!=0:
        count += i
print(count)        
    
 

n = int(input())

l=list(range(1,n+1))

count=0

for i in range(1,n+1) :
    if i%3!=0 and i%5!=0:
        count += i
print(count)        
    
 

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
FBSum = 0
for i in N:
    j = i+1
    if j % 3 != 0 and j % 5 != 0:
    FBSum +=j

print(FBSum)

N = int(input())
FBSum = 0
for i in range(N):
    j = i+1
    if j % 3 != 0 and j % 5 != 0:
        FBSum +=j

print(FBSum)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())
ans=0
for i in range (N+1):
  if i%3!=0 and i%5!=0:
    ans+=0
print(ans)

N=int(input())
ans=0
for i in range (N+1):
  if i%3!=0 and i%5!=0:
    ans+=1
print(ans)

N=int(input())
ans=0
for i in range (N+1):
  if i%3!=0 and i%5!=0:
    ans+=i
print(ans)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
x = input()
sum = 0
for i in range(x+1):
    if i % 3 or i % 5:
        pass
    else:
        sum += i
print(sum)

x = input()
sum = 0
for i in range(x):
  if i % 3 or i % 5:
    pass
  else:
    sum += i
print(sum)
    

x = int(input())
sum = 0
for i in range(x+1):
    if i % 3 or i % 5:
        pass
    else:
        sum += i
print(sum)

x = int(input())
sum = 0
for i in range(x+1):
    if i % 3 == 0 or i % 5 == 0:
        pass
    else:
        sum += i
print(sum)

Verdicts: Runtime Error

Runtime Error

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
res = n*(n+1)/2
uc = n/3
bes = n/5
onbes = n/15
print(res - 3*uc*(uc+1)/2 - 5*bes*(bes+1)/2 + 15*onbes*(onbes+1)/2)

n = int(input())
res = n*(n+1)//2
uc = n//3
bes = n//5
onbes = n//15
print(res - 3*uc*(uc+1)//2 - 5*bes*(bes+1)//2 + 15*onbes*(onbes+1)//2)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())

sum_ = 0
for i in range(1, n+1):
  if n%15 !=0:
    sum += i
    
print(sum_)

n = int(input())

sum_ = 0
for i in range(1, n+1):
  if i%15 !=0:
    sum += i
    
print(sum_)

n = int(input())

sum_ = 0
for i in range(1, n+1):
  if i%15 !=0 and i%3 !=0 and i%5 !=0:
    sum_ += i
    
print(sum_)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())
ans=n*(n+1)//2
k=n//3
l=n//5
m=n//15
k=k*(k+1)//2
l=l*(l+1)//2
m=m*(m+1)//2
ans=ans-k-l+m
print(ans)

n=int(input())
ans=n*(n+1)//2
k=n//3
l=n//5
m=n//15
k=k*(k+1)*3//2
l=l*(l+1)*5//2
m=m*(m+1)*15//2
ans=ans-k-l+m
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
given = [int(x) for x in range(1, int(input()) + 1) if x % 3 != 0 or x % 5 != 0]
print(sum(given))



given = int(input())
sums = 0
for i in range(1, given + 1):
    if i % 15 == 0:continue
    if i % 3 == 0:continue
    if i % 5 == 0:continue
    sums += i
print(sums)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
total = 0
for i in range(n+1):
  if n % 3 != 0 and n % 5 != 0:
    total += n
    
print(total)

n = int(input())
total = 0
for i in range(n+1):
  if i % 3 != 0 and i % 5 != 0:
    total += i
    
print(total)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = input()

s = 0
for n in range(1, N+1):
    if n % 3 != 0 and n % 5 != 0:
        s += n
print(s)

N = int(input())
 
s = 0
for n in range(1, N+1):
    if n % 3 != 0 and n % 5 != 0:
        s += n
print(s)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())
an=[a for a in range(1,n+1)]
o=[]
def ass(an):
    for c in an
        if c%3==0 or c%5==0:
             continue
        else:
            o.append(c)
    return sum(o)
print(ass(an))

n=int(input())
an=[a for a in range(1,n+1)]
o=[]
def ass(an):
    for c in an:
        if c%3==0 or c%5==0:
             continue
        else:
            o.append(c)
    return sum(o)
print(ass(an))

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())

for i in n:
  
    if i %15==0:
        print('Fizz Buzz')
    elif i % 3==0:
        print('Fizz')
    elif i % 5 ==0:
        print('Buzz')
    else:
        print(i)


n = int(input())
sum=0

for i in range(1,n+1):
    if i % 15 == 0:
        print('Fizz Buzz')
    elif i % 3 == 0:
        print('Fizz')
    elif i % 5 == 0:
        print('Buzz')
    else:
		sum=sum+i

n = int(input())

for i in range(1,n+1):
    if i % 15 == 0:
        print('Fizz Buzz')
    elif i % 3 == 0:
        print('Fizz')
    elif i % 5 == 0:
        print('Buzz')
    else:
        sum=sum+i

n=int(input())

for i in range(1,n+1):

    if i %15==0:
        print('Fizz Buzz')
    elif i % 3==0:
        print('Fizz')
    elif i % 5 ==0:
        print('Buzz')
    else:
        print(i)


n = int(input())

for i in range(1,n+1):
    if i % 15 == 0:
        print('Fizz Buzz')
    elif i % 3 == 0:
        print('Fizz')
    elif i % 5 == 0:
        print('Buzz')
    else:
        print(i)

n = int(input())
sum = 0

for i in range(1, n + 1):

    if i % 3 != 0 and i % 5 != 0:
        sum = sum + i

print(sum)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
answer = 0
for i in range(1, n + 1):
    if i % 3 and i % 5:
        answer += i
        print(i)
print(answer)

n = int(input())
answer = 0
for i in range(1, n + 1):
    if i % 3 and i % 5:
        answer += i

print(answer)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
all_sum = n * (n + 1)/2

number_3 = n//3
number_5 = n//5
number_15 = n//15

sum_number_3 = number_3 * (number_3 + 1)/2
sum_number_5 = number_5 * (number_5 + 1)/2
sum_number_15 = number_15 * (number_15 + 1)/2

sum_not_number = sum_number_3 + sum_number_5 - sum_number_15

s = all_sum - sum_not_number

print(s)

n = int(input())
all_sum = n * (n + 1)/2

number_3 = n//3
number_5 = n//5
number_15 = n//15

sum_number_3 = 3 * (number_3 * (number_3 + 1)/2)
sum_number_5 = 5 * (number_5 * (number_5 + 1)/2)
sum_number_15 = 15 * (number_15 * (number_15 + 1)/2)

sum_not_number = sum_number_3 + sum_number_5 - sum_number_15

s = all_sum - sum_not_number

print(s)


n = int(input())
all_sum = n * (n + 1)//2

number_3 = n//3
number_5 = n//5
number_15 = n//15

sum_number_3 = 3 * (number_3 * (number_3 + 1)//2)
sum_number_5 = 5 * (number_5 * (number_5 + 1)//2)
sum_number_15 = 15 * (number_15 * (number_15 + 1)//2)

sum_not_number = sum_number_3 + sum_number_5 - sum_number_15

s = all_sum - sum_not_number

print(s)


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
num = int(input())
fizz_buzz_sum = 0
for i in range(1, num + 1):
  if i % 3 != 0 or i % 5 != 0:
    fizz_buzz_sum += i

print(fizz_buzz_sum)

num = int(input())
fizz_buzz_sum = 0
for i in range(1, num + 1):
  if i % 3 != 0 and i % 5 != 0:
    fizz_buzz_sum += i

print(fizz_buzz_sum)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
def f(i,j,k):
  if(i==1 or j==1 or k==1):
  	return 1
  l=[i,j,k]  
  l.sort()
  i=l[0]
  j=l[1]
  k=l[2]
  if j%i !=0 or k%i !=0 or k%j !=0:
    return 1
  if (j%i ==0):
    if k%(j//i)==0:
      return j//i
    
    

n=int(input())
sum=0
for i in range(1,n):
  for j in range(1,n):
    for k in range(1,n):
      print(i," ",j," ",k, " ")
      sum+=f(i,j,k)
print(sum)
      

n=int(input())
sum=0
for i in range(1,n+1):
  if i%3!=0 and i%5 !=0:
    sum+=i
print(sum)    

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
i = 1
sum_ = 0
while n:
  if i % 15 == 0:
    n -= 1
  elif i % 3 != 0 and i % 5 != 0:
    sum_ += i
  i += 1
print(sum_)

n = int(input())
sum_ = 0
for i in range(1, n + 1):
  if i % 3 != 0 and i % 5 != 0:
    sum_ += i
print(sum_)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
import sys
input=sys.stdin.readline
N = int(input())
ans = 0
for i in range(1,N+1):
    if i%3!=0 or i%5!=0:
        print(i)
print(ans)


import sys
input=sys.stdin.readline
N = int(input())
ans = 0
for i in range(1,N+1):
    if i%3!=0 and i%5!=0:
        ans+=i
print(ans)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
count = 0
for i in range(N+1):
  if i % 3 != 0 and i % 5 != 0:
  print(i)
print(count)

N = int(input())
count = 0
for i in range(N+1):
  if i % 3 != 0 and i % 5 != 0:
    count += i
print(count)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
ans = 0
for i in range(1, N+1):
  if not (i%3==0 or i%5==0 or i%15==0):
    ans += i
print(i)

N = int(input())
ans = 0
for i in range(1, N+1):
  if not (i%3==0 or i%5==0 or i%15==0):
    ans += i
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
a=[]
b=[]
for i in range(input()):
    if i%3!=0 and i%5!=0:
        a.append(i)
    else:
        b.append(i)
print(sum(a))

a=[]
for i in range(1,int(input())+1):
    if i%3!=0 and i%5!=0:
        a.append(i)
print(sum(a))

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())

k15 = N // 15
m = N - (15 * k15)

k3 = m // 3
k5 = m // 5

def sigma(n):
  ans = n * (n + 1) / 2
  return ans

sum = (3 * sigma(k3)) + (5 * sigma(k5)) - (15 * sigma(k15))

print(sum)

N = int(input())

k15 = N // 15
m = N - (15 * k15)

k3 = m // 3
k5 = m // 5

def sigma(n):
  ans = (n * (n + 1)) / 2
  return ans

sum = (3 * sigma((5 * k15) + k3)) + (5 * sigma((3 * k15) + k5)) - (15 * sigma(k15))
an = sigma(N) - sum
print(int(an))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
output_list = []

for i in range(N):
  if i % 3 == 0 or i % 5 == 0 or i % 15 == 0:
  else:
    output_list.append(i)
  
print(sum(output_list)

N = int(input())
output_list = [0]

for i in range(1,N+1):
  if i % 3 == 0 or i % 5 == 0 or i % 15 == 0:
    pass
  else:
    output_list.append(i)
  
print(sum(output_list))

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
ln = [i for i in range(1,N+1)]
for i in range(N):
  if ln[i] % 3 == 0:
    nl.pop(i)
  elif ln[i] % 5 == 0:
    nl.pop(i)
  elif ln[i] % 15 == 0:
    nl.pop(i)
print(sum(nl))

N = int(input())
ln = [i for i in range(1,N+1)]

for i in range(N):
  if ln[i] % 3 == 0:
    ln[i] = 0
  elif ln[i] % 5 == 0:
    ln[i] = 0
  elif ln[i] % 15 == 0:
    ln[i] = 0
print(sum(ln))

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=input()
N=int(N)
a=1

while a<N:
	a=a+1

b=1
while b<N//3:
	b=b+1
	
c=1
while c<N//5:
	c=c+1
	
d=1
while d<N//15:
	d=d+1
	

print(a+d-b-c)

N=input()
N=int(N)

a=1
sum_a=0
while a<=N:
	sum_a=sum_a+a
	a=a+1

b=1
sum_b=0
while b<=N//3:
	sum_b=sum_b+b
	b=b+1
	
c=1
sum_c=0
while c<=N//5:
	sum_c=sum_c+c
	c=c+1
	
d=1
sum_d=0
while d<=N//15:
	sum_d=sum_d+d
	d=d+1
	

print(sum_a+15*sum_d-3*sum_b-5*sum_c)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
count = 0;
 
for i in range(n):
  if i % 3 != 0 and i % 5 != 0:
    count+=i
   
print(i)

n = int(input())
count = 0;

for i in range(n):
  if i % 3 != 0 && i % 5 != 0:
    count+=i
   
print(i)

n = int(input())
count = 0;
 
for i in range(n):
  if (i + 1) % 3 != 0 and (i + 1) % 5 != 0:
    count+=(i+1)
   
print(count)

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
result = 0
for i in range(1,n+1):
  if n % 3 != 0 and n % 5 != 0:
    result += i
    
print(result)

n = int(input())
result = 0
for i in range(1,n+1):
  if i % 3 ==0:
    continue
  elif i % 5 == 0:
    continue
  else:
    result += i
    
    
print(result)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
sum = 0
for i in range(n):
    if i%5!=0 and i%3=0:
        sum = sum + 1
print(sum)

n = int(input())
sum = 0
for i in range(1,n+1):
    if i%5!=0 and i%3!=0:
        sum = sum + i
print(sum)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
ans = 0
for i in range1,(N+1):
    if i%3 != 0 and i%5 != 0:
        ans += i
print(ans)

N = int(input())
ans = 0
for i in range(N+1):
    if i%3 != 0 and i%5 != 0:
        ans += i
print(ans)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input()):
cnt=0
for i in range(1,N+1):
  if i%3==0:
    continue
  if i%5==0:
    continue
  if i%15==0:
    continue
  else:
    cnt+=i
print(cnt)

N=int(input())
cnt=0
for i in range(1,N+1):
  if i%3==0:
    continue
  if i%5==0:
    continue
  if i%15==0:
    continue
  else:
    cnt+=i
print(cnt)


Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
a = input()
aList = []
for i in range(1,int(a)+1):
    if i%3 == 0 and i%5 == 0:
        print('FizzBuzz')
    elif i%3 == 0:
        print('Fizz')
    elif i%5 == 0:
        print('Buzz')
    else:
        aList.append(i)
        print(i)
ans = 0
for _,b in enumerate(aList):
    ans = ans + b
print(ans)


a = input()
aList = []
for i in range(1,int(a)+1):
    if i%3 == 0 and i%5 == 0:
        pass
        
    elif i%3 == 0:
        pass
        
    elif i%5 == 0:
        pass
        
    else:
        aList.append(i)
        # print(i)
ans = 0
for _,b in enumerate(aList):
    ans = ans + b
print(ans)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
sum = 0

for i in range(1, N+1):
    if i % 15 == 0:
        print("FizzBuzz")
    elif i % 3 == 0:
        print("Fizz")
    elif i % 5 == 0:
        print("Buzz")
    else:
        print(i)
        sum = sum + i

print(sum)

N = int(input())
sum = 0

for i in range(1, N+1):
    if i % 15 == 0:
        print("FizzBuzz")
    elif i % 3 == 0:
        print("Fizz")
    elif i % 5 == 0:
        print("Buzz")
    else:
        print(i)
        sum = sum + i

print(sum)

N = int(input())
sum = 0

for i in range(1, N+1):
    if (i % 3 != 0) and (i % 5 != 0):
        sum = sum + i

print(sum)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
sum=0
for i in range( 1, N+1):
  if !(i%5==0) and !(i%3==0):
    sum+=i
print(sum)

N = int(input())
sum=0
for i in range(1,N+1):
  if ((i%3!=0)and(i%5!=0)):
    sum+=i
print(sum)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
from math import gcd
 
k = int(input())
sum_ = 0
for a in range(1, k + 1):
  for b in range(1, k + 1):
    gcd_ab = gcd(a, b)
    for c in range(1, k + 1):
      sum_ += gcd(c, gcd_ab)
print(sum_)

from collections import defaultdict, Counter
from heapq import heapify, heappop, heappush
from sys import stdin


def main():
    res = 0
    n = int(input())
    for i in range(n):
        if (i+1) % 3 != 0 and (i+1) % 5 != 0:
            res += (i+1)
    print(res)


def input(): return stdin.readline().rstrip()


main()


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())

SUM = N*(N+1)/2

Fizz_count = N//3
Buzz_count = N//5
FizzBuzz_count = N//15
## r>1
def GeometricProgression(a_1,r,n):
    return int(a_1*(r^n -1)/r-1)

SUM_Fizz = GeometricProgression(3,3,Fizz_count)
SUM_Buzz = GeometricProgression(5,5,Buzz_count)
SUM_FizzBuzz = GeometricProgression(15,15,FizzBuzz_count)

result = int(SUM - SUM_Fizz - SUM_Buzz + SUM_FizzBuzz)
print(result)

N = int(input())

SUM = N*(N+1)/2
# print(str(SUM))

Fizz_count = N//3
Buzz_count = N//5
FizzBuzz_count = N//15

## r>1
def GeometricProgression(a_1,r,n):
    return int(a_1*(r^n -1)/r-1)

def Touhi(a_1,d,n):
    return int(n*(2*a_1+(n-1)*d)/2)



SUM_Fizz = Touhi(3,3,Fizz_count)
SUM_Buzz = Touhi(5,5,Buzz_count)
SUM_FizzBuzz = Touhi(15,15,FizzBuzz_count)



result = int(SUM - SUM_Fizz - SUM_Buzz + SUM_FizzBuzz)
print(result)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())

res = 0
for i in range(3, N+1):
  if i % 15 == 0 or i % 3 == 0 or i % 5 == 0:
    continue
  res += i

print(res)

N = int(input())

res = 0
for i in range(1, N+1):
  if i % 15 == 0 or i % 3 == 0 or i % 5 == 0:
    continue
  res += i

print(res)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int (input ())
S = 0

for i in range (1 , N+1):
    if (i % 3 != 0) and (i % 5 != 0):
        S += i

N = int (input ())
S = 0

for i in range (1 , N+1):
    if (i % 3 != 0) and (i % 5 != 0):
        S += i

print(S)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
L = [0 if x//3==0 or x//5==0 else x for x in range(1,16)]
Q = N//15
R = N%15
S = 30 * Q * (Q+1) + sum(L[R-1])
print(S)

N = int(input())
S = 0
for i in range(N+1):
  if i%3 != 0 and i%5 != 0:
    S += i
print(S)


Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
*x,=range(int(input())+1);x[::3]=x[::5]=0;print(sum(x))

from numpy import*;print(sum(arange(int(input())+1)[i%3>0<i%5]))

print(sum(i for i in range(int(input())+1)if i%3>0<i%5))

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
# -*- coding: <encoding name> -*-

n = int(input())
total = 0
for i in range(1, n + 1):
	if (i % 3) != 0 and (i % 5) != 0:
		total = total + 1
print(total)


# -*- coding: <encoding name> -*-

n = int(input())
total = 0
for i in range(1, n + 1):
	if i % 3 != 0 and i % 5 != 0:
		total +=
print(total)


# -*- coding: <encoding name> -*-

n = int(input())
total = 0
for i in range(1, n + 1):
	if (i % 3) != 0 and (i % 5) != 0:
		total +=
print(total)


# -*- coding: <encoding name> -*-

n = int(input())
total = 0
for i in range(1, n + 1):
	if (i % 3) != 0 and (i % 5) != 0:
		total += i
print(total)


Verdicts: Wrong Answer

Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
f=t//5
tt=t//3
ff=t//15
f=(f*(f+1)//2 )*5
tt=(tt*(tt+1)//2 )*3
ff =(ff*(ff+1)//2 )*15
print(t*(t+1)//2 - f -tt +ff)


t = int(input())
f=t//5
tt=t//3
ff=t//15
f=(f*(f+1)//2 )*5
tt=(tt*(tt+1)//2 )*3
ff =(ff*(ff+1)//2 )*15
print(t*(t+1)//2 - f -tt +ff)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
mxn = 10**6 + 11
arr = []
for i in range(1,mxn):
    if i % 3 == 0 and i % 5 == 0:
        arr.append(0)
    elif i % 3 == 0:
        arr.append(0)
    elif i%5 == 0:
        arr.append(0)
    else:
        arr.append(i)

n = int(input())
print(sum[:n])


mxn = 10**6 + 11
arr = []
for i in range(1,mxn):
    if i % 3 == 0 and i % 5 == 0:
        arr.append(0)
    elif i % 3 == 0:
        arr.append(0)
    elif i%5 == 0:
        arr.append(0)
    else:
        arr.append(i)

n = int(input())
print(sum(arr[:n]))


Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
import math

n = int(input())
ans = 0
for i in range(1,n+1):
    for j in range(1,n+1):
        c = math.gcd(i,j)
        for k in range(1,n+1):
            ans += math.gcd(c,k)
print(ans)


n = int(input())
ans = 0
for i in range(1,n+1):
    if i % 15 == 0:
        continue
    elif i % 5 == 0:
        continue
    elif i % 3 == 0:
        continue
    else:
        ans += i
print(ans)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
num=int(input())
sum=0
for i in range(1, num+1):
  if num%3!=0 and num%5!=0:
    sum=sum+i
print(sum)

num=int(input())
sum=0
for i in range(1,num+1):
  if i%3!=0 and i%5!=0:
    sum=sum+i
print(sum)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
¥N=int(input())
F=N//3
B=N//5
fb=N//15
S=(N*(N+1))//2
Fizz=(3*F*(F+1))//2
Buzz=(5*B*(B+1))//2
FizzBuzz=(15*fb*(fb+1))//2
print(S-Fizz-Buzz+FizzBuzz)




N=int(input())
F=N//3
B=N//5
fb=N//15
S=(N*(N+1))//2
Fizz=(3*F*(F+1))//2
Buzz=(5*B*(B+1))//2
FizzBuzz=(15*fb*(fb+1))//2
print(S-Fizz-Buzz+FizzBuzz)




Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())
print('N=',N)
sum=0
for i in range(N):
    if i % 3 != 0 and  i % 5 !=0:
        sum+=i

print(sum)

N=int(input())
sum=0
for i in range(1,N+1):
  if i%3 !=0 and i%5 !=0 :
    sum+=i

print(sum)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
a = n//3
b = n//5
c = n//15
A = 3*a*(a+1)/2
B = 5*b*(b+1)/2
C = 15*c*(c+1)/2
print(n*(n+1)/2 - A-B+C)

n = int(input())
a = n//3
b = n//5
c = n//15
A = 3*a*(a+1)/2
B = 5*b*(b+1)/2
C = 15*c*(c+1)/2
print(int(n*(n+1)/2 - A-B+C))


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())

samu = 0

for i in range(n):
    if(n % 3 != 0 and n % 5 != 0):
        samu += i

print(str(int(samu)))


n = int(input())

samu = 0

for i in range(n):
    if(n % 3 != 0 or n % 5 != 0):
        samu += i

print(str(int(samu)))


n = int(input())

samu = 0

for i in range(n):
    j = i + 1
    if(j % 3 != 0 and j % 5 != 0):
        samu += j

print(str(int(samu)))


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
list_a = []

for i in range(1, N+1):
    if i % 3 == 0 or i % 5 == 0:
        pass
    else:
        list_a.append(int(i))

print(list_a)
print(sum(list_a))


N = int(input())
list_a = []

for i in range(1, N+1):
    if i % 3 == 0 or i % 5 == 0:
        pass
    else:
        list_a.append(int(i))

print(sum(list_a))


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
K=int(input())
n=0
for i in range(1,K+1):
    if(i%3==0 and i%5==0):
        pass
    else:
        n+=i

print(n)

K=int(input())
n=0
for i in range(1,K+1):
    if(i%3==0):
        pass
    elif(i%5==0):
        pass
    elif(i%3==0 and i%5==0):
        pass
    else:
        n+=i

print()

K=int(input())
n=0
for i in range(1,K+1):
    if(i%3==0):
        pass
    elif(i%5==0):
        pass
    elif(i%3==0 and i%5==0):
        pass
    else:
        n+=i

print(n)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
a = int(input())
  
set3 = set(range(0, a+1, 3))
set5 = set(range(0, a+1, 5))
seta = set(range(0, a+1))

print(set3, set5)

print(sum(seta-set3-set5))


a = int(input())
  
set3 = set(range(0, a+1, 3))
set5 = set(range(0, a+1, 5))
seta = set(range(0, a+1))
 
print(sum(seta-set3-set5))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
ans = 0
for i in range(1,N+1): 
  print(i)
  if i%3!=0 and i%5!=0:
    ans += i
print(ans)

N = int(input())

ans = 0

for i in range(1,N+1): 
  print(i)
  if i%3!=0 and i%5!=0:
    ans += i
print(ans)

N = int(input())

ans = 0

for i in range(1,N+1): 
  ##print(i)
  if i%3!=0 and i%5!=0:
    ans += i
print(ans)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())
f=0
for i in range(1,N+1):
    if i %15==0:
        print ("FizzBizz")
    if i%3==0:
        print("Fizz")
    if i%5==0:
        print("Buzz")
    else:
        print(i)
        f=f+i
print(f)

n = int(input())
answer = 0

for i in range(1, n + 1):       
    if i % 3 != 0 and i % 5 != 0:
        answer += i             
print(answer)                   


Verdicts: Wrong Answer

Accepted