TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N  = int(input())
num3 = N//3
sum3 = 3*num3*(num3+1)//2
num5 = N//5
sum5 = 5*num5*(num5+1)//2
num15 = N//15
sum15 = 15*num15*(num15+1)//215

_sum = N*(N+1)//2

print(_sum-sum3-sum5+sum15)

N  = int(input())
num3 = N//3
sum3 = num3*(num3+1)//2
num5 = N//5
sum5 = num5*(num5+1)//2
num15 = N//15
sum15 = num15*(num15+1)//2
_sum = N*(N+1)//2

print(_sum-sum3-sum15+sum15)

N  = int(input())
num3 = N//3
sum3 = 3*num3*(num3+1)//2
num5 = N//5
sum5 = 5*num5*(num5+1)//2
num15 = N//15
sum15 = 15*num15*(num15+1)//2

_sum = N*(N+1)//2

print(_sum-sum3-sum5+sum15)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
ans = 0
for i in range(1, N+1):
    if i%3 == 0 or i%5 == 0:
        pass
    else:
        ans += i
print(i)

N = int(input())
ans = 0
for i in range(N+1):
    if i%3 != 0 and i%5 != 0:
        ans += i
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())
S=1/2*N*(N+1)
FB=N//15
F=N//3
B=N//5

sum_FB=15*1/2*FB*(FB+1)
sum_F=3/2*F*(F+1)
sum_B=5/2*B*(B+1)
print(S-sum_B-sum_F+sum_FB)

N=int(input())
S=1/2*N*(N+1)
FB=N//15
F=N//3
B=N//5

sum_FB=15*1/2*FB*(FB+1)
sum_F=3/2*F*(F+1)
sum_B=5/2*B*(B+1)
print(int(S-sum_B-sum_F+sum_FB))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())
result=0
a
for i in range(n): 
    if i % 3 == 0 and i % 5 == 0:
        a=result    
    elif i % 3 == 0:
        a=result
    elif i % 5 == 0:
        a=result
    else:
        result=result+i
    
print(result)
        

n=int(input())
result=0
for i in range(n+1): 
    if i % 3 == 0 and i % 5 == 0:
        result=result    
    elif i % 3 == 0:
        result=result
    elif i % 5 == 0:
        result=result
    else:
        result=result+i
    
print(result)
        

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
def sum(n):
    return n*(n+1)/2
N=int(input())
print(sum(N)-sum(N/3)*3-sum(N/5)*5+sum(N/15)*15)

def sum(n):
    return n*(n+1)//2
N=int(input())
print((sum(N)-sum(N//3)*3-sum(N//5)*5+sum(N//15)*15))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(intput())
cnt=0
for i in range(n+1):
  if i%3!=0:
    if i%5!=0:
      cnt=cnt+i
print(cnt)

n=int(input())
cnt=0
for i in range(n+1):
  if i%3!=0:
    if i%5!=0:
      cnt=cnt+i
print(cnt)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
k = n//3
l = n//5
m = n//15
print(n*(n+1)/2-5*l*(l+1)/2-3*k*(k+1)/2+15*m*(m+1)/2)

n = int(input())
k = n//3
l = n//5
m = n//15
print(int(n*(n+1)/2-5*l*(l+1)/2-3*k*(k+1)/2+15*m*(m+1)/2))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())

print(int(n * (n+1)/2 - n//3 - n//5 + n//15))

n = int(input())

sumall = int(n * (n+1)/2)
sum3 = int(n//3 * (n//3 + 1) * 3/2)
sum5 = int(n//5 * (n//5 + 1) * 5/2)
sum15 = int(n//15 * (n//15 + 1) * 15/2)

print(sumall - sum3 - sum5 + sum15)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input)
count = 0
for i in range(0,n):
  if (i+1)//3==0:
    count = count
  elif (i+1)//5==0:
    count = count
  else:
    count = count + i + 1

print(count)


n = int(input)
count = 0
for i in range(0,n):
  if (i+1)%3==0:
    count = count
  elif (i+1)%5==0:
    count = count
  else:
    count = count + i + 1

print(count)


n = int(input())
count = 0
tenwari = n%10
baiwari = n%100
ichi = tenwari
jyu = (baiwari-tenwari)//10
hyaku = (n-jyu*10-ichi)//100

if ichi != 7:
  count = count + 1
if jyu != 7:
  count = count + 1
if hyaku != 7:
  count = count + 1
  
if count == 3:
  print('No')
else:
  print('Yes')


n = int(input())
count = 0
for i in range(0,n):
  if (i+1)%3==0:
    count = count
  elif (i+1)%5==0:
    count = count
  else:
    count = count + i + 1

print(count)


Verdicts: Runtime Error

Runtime Error

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
from math import gcd

k = int(input())

cnt = 0
for i in range(1, k+1):
    for j in range(1, k+1):
        for k in range(1, k+1):
            cnt += gcd(gcd(i, j), k)

print(cnt)


n = int(input())

cnt = 0
for i in range(1, n+1):
    if i % 15 != 0 and i % 3 != 0 and i % 5 != 0:
        cnt += i

print(cnt)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())
U=(1/2)*n*(n+1)
U3=(3/2)*(n//3)*(n//3+1)
U5=(5/2)*(n//5)*(n//5+1)
U15=(15/2)*(n//15)*(n//15+1)
ans=U-U3-U5+U15
print(ans)


n=int(input())
U=(1/2)*n*(n+1)
U3=(3/2)*(n//3)*(n//3+1)
U5=(5/2)*(n//5)*(n//5+1)
U15=(15/2)*(n//15)*(n//15+1)
ans=U-U3-U5+U15
print(int(ans))


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
m = n//15
l = n%15
x = 60*(m**2)
y = [0,1,2,0,4,0,0,7,8,0,0,11,0,13,14,0]
for i in range(1,l+1):
    if(y[i] != 0):
        x += y[i]+m*15
print(x)a

n = int(input())
m = n//15
l = n%15
x = 60*(m**2)
y = [0,1,2,0,4,0,0,7,8,0,0,11,0,13,14,0]
for i in range(1,l+1):
    if(y[i] != 0):
        x += y[i]+m*15
print(x)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
total = []

N = int(input())

for i in range(1, N):
    if i % 3 == 0 and i % 5 == 0:
        pass
    elif i % 3 == 0:
        pass
    elif i % 5 == 0:
        pass
    else:
        total.append(i)

print(total)


total = []

N = int(input())

for i in range(1, N + 1):
    if i % 3 == 0 and i % 5 == 0:
        pass
    elif i % 3 == 0:
        pass
    elif i % 5 == 0:
        pass
    else:
        total.append(i)

print(sum(total))


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
number = int(input())

for i in range(1, 1000000 + 1):
    Total = []

    if (i % 3 == 0) and (i % 5 ==0):
        print('FizzBuzz')
    elif i % 3 == 0:
        print('Fizz')
    elif i % 5 == 0:
        print('Buzz')
    else:
        print(str(i))

        print(sum(Total))

i = int(input())
Total = []

for i in range(1, i + 1):

    if (i % 3 == 0) and (i % 5 == 0):
        'FizzBuzz'
    elif i % 3 == 0:
        'Fizz'
    elif i % 5 == 0:
        'Buzz'
    else:
        Total.append(i)

        print(sum(Total))

number = int(input())
Total = []

for i in range(1, number + 1):

    if (i % 3 == 0) and (i % 5 ==0):
        print('FizzBuzz')
    elif i % 3 == 0:
        print('Fizz')
    elif i % 5 == 0:
        print('Buzz')
    else:
        Total.append(i)

        print(sum(Total))

number = int(input())
Total = []

for i in range(1, number + 1):

    if (i % 3 == 0) and (i % 5 == 0):
        'FizzBuzz'
    elif i % 3 == 0:
        'Fizz'
    elif i % 5 == 0:
        'Buzz'
    else:
        Total.append(i)

        print(sum(Total))

number = int(input())

for i in range(1, number + 1):
    Total = []

    if (i % 3 == 0) and (i % 5 ==0):
        print('FizzBuzz')
    elif i % 3 == 0:
        print('Fizz')
    elif i % 5 == 0:
        print('Buzz')
    else:
        print(str(i))

        print(sum(Total))

n = int(input())
Total = []

for i in range(1, n + 1):

    if (i % 3 == 0) and (i % 5 == 0):
        "FizzBuzz"
    elif i % 3 == 0:
        "Fizz"
    elif i % 5 == 0:
        "Buzz"
    else:
        Total.append(i)

        print(sum(Total))

n = int(input())
Total = []

for i in range(1, n + 1):

    if (i % 3 == 0) and (i % 5 == 0):
        "FizzBuzz"
    elif i % 3 == 0:
        "Fizz"
    elif i % 5 == 0:
        "Buzz"
    else:
        Total.append(i)

print(sum(Total))

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
sum = 0
for i in range(n+1):
    not (i % 3 == 0 and i % 5 ==0):
        sum += i
print(sum)

n = int(input())
sum = 0
for i in range(n+1):
    if not (i % 3 == 0 and i % 5 ==0):
        sum += i
print(sum)


n = int(input())
sum = 0
for i in range(n+1):
    if not (i % 3 == 0 or i % 5 ==0):
        sum += i
print(sum)


Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
 
org_sum = 1/2 * N * (N+1)
div3 = N // 3
sum3 = 3/2 * div3 * (div3+1)
div5 = N // 5
sum5 = 5/2 * div5 * (div5+1)
div15 = N // 15
sum15 = 15/2 * div15 * (div15+1)
 
print(org_sum - sum3 - sum5 + sum15)

N = input()
 
org_sum = 1/2 * N * (N+1)
div3 = N // 3
sum3 = 3/2 * div3 * (div3+1)
div5 = N // 5
sum5 = 5/2 * div5 * (div5+1)
div15 = N // 15
sum15 = 15/2 * div15 * (div15+1)
 
return org_sum - sum3 - sum5 + sum15

N = input()
 
org_sum = 1/2*N*(N+1)
div3 = N // 3 * 3
div5 = N // 5 * 5
div15 = N // 15 * 15
 
return org_sum - div3 - div5 + div15

N = input()

org_sum = 1/2*N*(N+1)
div3 = N // 3
div5 = N // 5
div15 = N // 15

return org_sum - div3 - div5 + div15

N = int(input())
 
org_sum = 1/2 * N * (N+1)
div3 = N // 3
sum3 = 3/2 * div3 * (div3+1)
div5 = N // 5
sum5 = 5/2 * div5 * (div5+1)
div15 = N // 15
sum15 = 15/2 * div15 * (div15+1)
 
return org_sum - sum3 - sum5 + sum15

N = int(input())
 
org_sum = 1 * N * (N+1) // 2
div3 = N // 3
sum3 = 3 * div3 * (div3+1) //2
div5 = N // 5
sum5 = 5 * div5 * (div5+1) // 2
div15 = N // 15
sum15 = 15 * div15 * (div15+1) // 2
 
print(org_sum - sum3 - sum5 + sum15)

Verdicts: Wrong Answer

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input() )
 
sum=0
for i in range(n):
    if i%3 != 0 and i%5 != 0:
        sum+=i
    elif i%3 !=0:
        sum+=i
    elif  i%5 !=0:
        sum+=i
 
print(sum)

n = int(input() )
 
sum=0
for i in range(n):
#    print(i+1)
    j=i+1
    if j%3 != 0 and j%5 != 0:
        sum+=j
        #print(sum)

print(sum)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
sum = 0
for i in range(n):
    if i%3 ==0 and i%5 == 0:
        sum += i
print(sum)

n = int(input())
sum = 0
for i in range(n+1):
    if i%3!=0 and i%5!=0:
        sum = sum+i
print(sum)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
a = 0
n = int(N)
for i in range(1,n+1):
    if i % 5 != 0 and i % 3 != 0:
        a = a + i
    else:
        continue
print(a)

a = 0
N = input()
n = int(N)
for i in range(1,n+1):
    if i % 5 != 0 and i % 3 != 0:
        a = a + i
    else:
        continue
return(a)

a = 0
n = int(N)
for i in range(1,n+1):
    if i % 5 != 0 and i % 3 != 0:
        a = a + i
    else:
        continue
return(a)

a = 0
N = input()
n = int(N)
for i in range(1,n+1):
    if i % 5 != 0 and i % 3 != 0:
        a = a + i
    else:
        continue
print(a)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
import sys
n = int(sys.stdin)
print(sum(i for i in range(1, n + 1) if i % 3 and i % 5))

import sys
n = int(sys.stdin.read())
print(sum(i for i in range(1, n + 1) if i % 3 and i % 5))

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
a = int(input())
sum = 0
for i in range(a):
    if i % 3 != 0 or i % 5 != 0:
        sum += i
    else:
        pass
print(sum)

n = int(input())
lsum = []
for i in range(1, n+1):
    if i % 3 or i % 5 == 0:
        pass
    else:
        lsum.append(i)
print(sum(lsum))

a = int(input())
sum = 0
for i in range(a):
    if i % 3 != 0 or i % 5 != 0:
        sum += i
    else:
        pass
print(sum)

a = int(input())
sum = 0
for i in range(a):
    if i % 3 != 0 or i % 5 != 0:
        sum += i
    else:
        pass
print(sum)

n = int(input())
lsum = []
for i in range(1, n+1):
    if i % 3 or i % 5 == 0:
        pass
    else:
        lsum.append(i)
print(sum(lsum))

a = int(input())
lnum = []
for i in range(1, a+1):
    if i % 3 == 0 or i % 5 == 0:
        pass
    else:
        lnum.append(i)
print(sum(lnum))

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
a = N//3
b = N//5
c = N//15

ans = (N*(N+1)/2) - 3*a(a+1)/2 -5*b(b+1)/2 + 15*c(c+1)/2
print(int(ans))

N = int(input())
a = N//3
b = N//5
c = N//15

ans = (N*(N+1)//2) - (3*a*(a+1)//2) -(5*b*(b+1)//2) + (15*c*(c+1)//2)
print(ans)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
count = 0
for x in range(1, N+1):
    if x%3==0 or x%5==0:
       count=count+x
       print(count)
print(count)


N = int(input())
count = 0
for x in range(1, N):
    if x%3==0 or x%5==0:
       count=count+x
print(count)

N = int(input())
count = 0
for x in range(0, N+1):
    if x%3!=0 and x%5!=0:
       count=count+x
print(count)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
def is_fb(i):
    if i % 3 == 0:
        return True
    if i % 5 == 0:
        return True
    return False

N = int(input())

print(sum([a for a in range(1, N - 1) if not is_fb(a)]))


N = int(input())

print(
    sum(
        filter(
            lambda x: bool(x % 3) and bool(x % 5),
            range(1, N+1)
        )
    )
)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
import sys

X = input()
count = 0
for num in range(X):
  if not num % 3 == 0 or num % 5 == 0:
    count = count + num
print(count)

import sys
 
X = int(input())
count = 0
for num in range(1, X+1):
  if num % 3 == 0 or num % 5 == 0:
    continue
  else:
    count = count + num
print(count)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
a = int(input())
sum = 0
list_number = []
for i in range(a):
    list_number.append(i)
for i in list_number:
    if i % 3 == 0 and i % 5 == 0:
        list_number.remove(i)
for i in list_number:
    if i % 3 == 0:
        list_number.remove(i)
for i in list_number:
    if i % 5 == 0:
        list_number.remove(i)
for i in list_number:
    sum = sum + i
print(list_number)
print(sum)

n = int(input())
sum = 0
for i in range(1, n + 1):
  if i !% 3 or i !% 5:
    sum = sum + i
print(sum)

n = int(input())
sum = 0
for i in range(1, n+1):
    if i % 3 != 0 and i % 5 != 0:
        sum += i
print(sum)


Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N1 = int(input())
c = []
for i in range(1,3*N1):
    if i%3 != 0 and i%5 != 0:
        c.append(i)
        print(i)
    if i ==N1:
        break
sum(c)

c = []
for i in range(1,3*N1):
    if i%3 != 0 and i%5 != 0:
        c.append(i)
        print(i)
    if i ==N1:
        break
sum(c)

N1 = int(input())
c = []
for i in range(1,3*N1):
    if i%3 != 0 and i%5 != 0:
        c.append(i)
    if i ==N1:
        break
sum(c)

n = int(input())
c = []
for i in range(1,3*n):
    if i%3 != 0 and i%5 != 0:
        c.append(i)
sum(c)

N1 = int(input())
c = []
for i in range(1,3*N1):
    if i%3 != 0 and i%5 != 0:
        c.append(i)
    if i ==N1:
        break
print(sum(c))

Verdicts: Wrong Answer

Runtime Error

Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
a = list()

for i in range(1,N+1):
    print(i)
    if i % 3 == 0:
        continue
    if i % 5 == 0:
        continue
    else:
        a.append(i)
# print(a)
print(sum(a))

N = int(input())
a = list()

for i in range(1,N+1):
    # print(i)
    if i % 3 == 0:
        continue
    if i % 5 == 0:
        continue
    else:
        a.append(i)
# print(a)
print(sum(a))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
Q = 0
for i in range(N+1):
  if(N%3 !== 0 or N%5 !== 0):
      Q += i
print(Q)

 = input()
Q = 0
for i in range(int(N)):
  P = []
  for j in range(len(str(i))):
    k= str(i)
    P.append(int(k[j]))
  if(sum(P)%3 == 0 and P[-1]/5 == 0):
      Q += 0
  elif(sum(P)%3 == 0):
      Q += 0
  elif(P[-1] == 0 or P[-1] == 5):
      Q += 0
  else:
      Q += i
print(Q)

N = int(input())
Q = 0
for i in range(N+1):
  if(N%3 !== 0 and N%5 !== 0):
      Q += i
print(Q)

N = input()
Q = 0
for i in range(int(N)):
  P = []
  for j in range(len(str(i))):
    k= str(j)
    P.append(int(k[j]))
  if(sum(P)%3 == 0 and P[-1] == 0 or P[-1] == 5):
    Q += 0
  elif(sum(P)%3 == 0):
    Q += 0
  elif(P[-1] == 0 or L[-1] == 5):
    Q += 0
  else:
    Q += i
print(Q)

N = int(input())
Q = 0
for i in range(1,N+1):
  if(i%3 !== 0 and i%5 !== 0):
      Q += i
print(Q)

N = int(input())

for i in range(N+1):
  if(N%3 !> 0 !< N%5):
    M += i
print(M)
        

N = int(input())
Q = 0
for i in range(1,N+1):
  if(i%3 != 0 and i%5 != 0):
      Q += i
print(Q)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
import math
 
K = int(input())
 
_sum = 0
 
for a in range(1, K):
    for b in range(1, K):
        for c in range(1, K):
            _sum += math.gcd(math.gcd(a, b), c)
print(_sum)

N = int(input())
 
_sum = 0
for i in range(1, N+1):
    if i % 3 != 0 and i % 5 != 0:
        _sum += i
 
print(_sum)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input)

print(sum(i for i in range(1,N+1) if i%3==0 or  i%5==0))

N=int(input())

print(sum(i for i in range(1,N+1) if i%3 and  i%5))

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())

fb = long(0)
for i in range(n):
    if(i%5 != 0 and i%3 != 0):
        fb = fb + i

print(fb)

n = int(input())

fb = 0
for i in range(n+1):
    if(i%5 != 0 and i%3 != 0):
        fb = fb + i

print(fb)


Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = input()
sum = 0
for i in range(n):
  if i % 3 != 0 and i % 5 != 0:
    sum += i
    
print(sum)

n = input()
sum = 9
for i in range(n):
  if i % 3 != 0 and i % 5 != 0:
    sum += i
    
print(sum)

n = int(input())
sum = 0
for i in range(1, n+1):
  if i % 3 != 0 and i % 5 != 0:
    sum += i
    
print(sum)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
print(sum(i for i in range(i, n + 1) if i % 3 and i % 5))

n = int(input())
print(sum(i for i in range(1, n + 1) if i % 3 and i % 5))

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
ans = 0
for x in range(1,N+1):
    if(x % 3 == 0):
        ans += 0
    elif(x % 5 ==0):
        ans += 0
    else:
        ans += x
        print(x)

print(ans)

N = int(input())
ans = 0
for x in range(1,N+1):
    if(x % 3 == 0):
        ans += 0
    elif(x % 5 ==0):
        ans += 0
    else:
        ans += x
        #print(x)

print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())
sum=0

for i in range(n+1):
  if i%3==1 or i%3==2:
    if i%5==1 or i%5==2 or i%5==3 or i%5==4:
      sum+=i
print sum


n=int(input())
sum=0

for i in range[n+1]:
  if i%3==1 or i%3==2:
    if i%5==1 or i%5==2 or i%5==3 or i%5==4:
      sum+=i
print sum


n=int(input())
sum=0

for i in range(1,n+1):
  if i%3!=0 and i%5!=0:
    sum+=i
print(sum)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
s=0
for i in range(1, n+1):
	if i%3 != 0 and i%5 != 0:
		s+=i
print(i)

n = int(input())
s=0
for i in range(1, n+1):
	if i%3 != 0 and i%5 != 0:
		s+=i
print(s)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
ans=0
for i in range(N+1):
    if i%5!=0 or i%3!=0:
        ans+=i
print(ans)

N = int(input())
ans=0
for i in range(N+1):
    if i%5!=0:
        ans+=i
    elif i%3!=0:
         ans+=i
print(ans)

N = int(input())
ans=0
for i in range(N+1):
    if i%5!=0 and i%3!=0:
        ans+=i
print(ans)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
a=int(input())

print((1+a)*a/2-(a//3)*(3+a//3*3)/2-(a//5)*(5+a//5*5)/2+(a//15)*(15+a//15*15)/2)

a=int(input())

print(int((1+a)*a/2-(a//3)*(3+a//3*3)/2-(a//5)*(5+a//5*5)/2+(a//15)*(15+a//15*15)/2))


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
number_list = []
summury = 0
for i in range(N):
  if (i+1) % 3 != 0 or (i+1) % 5 != 0:
    number_list.append(i+1)
    
for i in range(len(number_list)):
  summury += number_list[i]

print(summury)

N = int(input())
number_list = []
summury = 0
for i in range(N):
  if (i+1) % 3 != 0 and (i+1) % 5 != 0:
    number_list.append(i+1)
    
for i in range(len(number_list)):
  summury += number_list[i]
 
print(summury)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
A = list(range(N+1))
S = sum(A)

n3 = N // 3
B = list(range(n3+1))
S3 = 3*sum(B)

n5 = N // 5
C = list(range(n5+1))
S5 = 5*sum(C)

n15 = N // 15
D = list(range(n15+1))
S15 = 15*sum(D)

print(S,S3,S5,S15)

print(S-S3-S5+S15)

N = int(input())
A = list(range(N+1))
S = sum(A)

n3 = N // 3
B = list(range(n3+1))
S3 = 3*sum(B)

n5 = N // 5
C = list(range(n5+1))
S5 = 5*sum(C)

n15 = N // 15
D = list(range(n15+1))
S15 = 15*sum(D)

print(S-S3-S5+S15)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())

if N % 15 == 0 :
  print('FuzzBuzz')
elif N % 3 == 0:
  print('Fuzz')
elif N % 5 == 0:
  print('Buzz')
else:
  print(N)

def isFizzBuzz (N):
  if N % 15 == 0 :
    return 0
  elif N % 3 == 0:
    return 0
  elif N % 5 == 0:
    return 0
  else:
    return N

N = int(input())
ans = 0
for i in range(1,N+1):
  ans += isFizzBuzz(i)

print(ans)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
# 162 B
N = int(input())
ans = 0
for i in range(1,N+1):
    if i % 3 != 0 and i %5 != 0:
        print(i)
        ans += i

print(ans)

# 162 B
N = int(input())
ans = 0
for i in range(1,N+1):
    if i % 3 != 0 and i %5 != 0:
        ans += i

print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())
a=0
for i in range(1,n+1):
    if i%3==0:
        a+=0
    elif i%5==0:
        a+=0
    else:
        a+=i
print(i)


n=int(input())
a=0
for i in range(1,n+1):
    if i%3==0:
        a+=0
    elif i%5==0:
        a+=0
    else:
        a+=i
print(a)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())


ans=0
for i in range(n):
    if (i+1)//3!=0 and (i+1)//5!=0:
        ans+=i+1
print(ans)


n=int(input())


ans=0
for i in range(n):
    if (i+1)%3!=0 and (i+1)%5!=0:
        ans+=i+1
print(ans)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())

s = [i for i in range(1,n+1)]
print(sum(s))

n = int(input())

s = 0
for i in range(1,n+1):
    if i%15==0 or i%5==0 or i%3==0:
        pass
    else:
        s = s+i

print(s)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
print(len([i for i in range(1, int(input())+1) if i%3 and i%5]))

print(sum([i for i in range(1, int(input())+1) if i%3 and i%5]))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
m = int(input())

def fizz_buzz(i):
  fizz = i % 3
  buzz = i % 5
  
  return (fizz > 0) && (buzz > 1)

res = 0

for i in range(m):
  use_i = i+1
  if fizz_buzz(use_i):
    res += use_i
    
print(res)

m = int(input())
 
def fizz_buzz(i):
  fizz = i % 3
  buzz = i % 5
  
  return (fizz > 0) & (buzz > 1)
 
res = 0
 
for i in range(m):
  use_i = i+1
  if fizz_buzz(use_i):
    res += use_i

m = int(input())
     
def fizz_buzz(i):
  fizz = i % 3
  buzz = i % 5
      
  return (fizz > 0) & (buzz > 1)
     
res = 0
     
for i in range(m):
  use_i = i+1
  if fizz_buzz(use_i):
    res += use_i
        
print(res)

    m = int(input())
     
    def fizz_buzz(i):
      fizz = i % 3
      buzz = i % 5
      
      return (fizz > 0) && (buzz > 1)
     
    res = 0
     
    for i in range(m):
      use_i = i+1
      if fizz_buzz(use_i):
        res += use_i
        
    print(res)

m = int(input())
     
def fizz_buzz(i):
  fizz = i % 3
  buzz = i % 5
      
  return (fizz > 0) & (buzz > 0)
     
res = 0
     
for i in range(m):
  use_i = i+1
  if fizz_buzz(use_i):
    res += use_i
        
print(res)

Verdicts: Runtime Error

Wrong Answer

Wrong Answer

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())

sum = 0
for i in range(N):
    j = i + 1
    if (j % 3 != 0) and (j % 5 != 0):
        print(j)
        sum += j

print(sum)


N = int(input())

sum = 0
for i in range(N):
    j = i + 1
    if (j % 3 != 0) and (j % 5 != 0):
        sum += j

print(sum)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())

sum = 0

for i in range(N):
    if not (i+1) % 3 == 0:
        if not (i+1) % 5 == 0:
            sum += i+1
            print(i+1)
print(sum)


N = int(input())

sum = 0

for i in range(N):
    if not (i+1) % 3 == 0:
        if not (i+1) % 5 == 0:
            sum += i+1
    
print(sum)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())
summ=0
for i in range(1,n):
    if i%3!=0 and i%5!=0:
        summ+=i
print(summ)n=int(input())
summ=0
for i in range(1,n):
    if i%3!=0 and i%5!=0:
        summ+=i
print(summ)


cnt=0
n=int(input())
for i in range(1,n+1):
    if i%3!=0 and i%5!=0:
        cnt+=i
print(cnt)


Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())
ans=0

for i in range(N):
  if (N+1)% !=3 and (N+1)% !=5:
    ans+=i
print(ans)

n=int(input())
sum=0
for i in range(1,n+1):
  if i%3!=0 and i%5 !=0:
    sum+=i
print(sum)    


Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())

l = list(range(0))

for i in range(N+1):
    if i % 3 == 0 and i % 5 == 0:
        pass
    elif i % 3 == 0:
        pass
    elif i % 5 == 0:
        pass
    else:
        l.append(i)

sum(l)

N = int(input())

sum = 0
for i in range(1, N+1):
    if i % 3 == 0 or i % 5 == 0:
        pass
    else:
        sum = sum + i
print(sum)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
a = input()
j = 0
for i in range(a):
    if i%3==0:
        continue
    if i%5==0:
        continue
    else:
        j+=i
print(j)

a = int(input())
j = 0
for i in range(1, a + 1):
    if i%3!=0 and i%5!=0:
        print(i)
        j+=i
print(j)




a = long(input())
j = 0
for i in range(a):
    if i%3==0:
        continue
    if i%5==0:
        continue
    else:
        j+=i
print(j)

a = int(input())
j = 0
for i in range(a + 1):
    if i%3!=0 and i%5!=0:
        print(i)
        j+=i
print(j)

a = input()
j = 0
for i in range(a):
    if i%3==0:
        continue
    if i%5==0:
        continue
    else:
        j+=i
print(j)



a = int(input())
j = 0
for i in range(a + 1):
    if i%3!=0 and i%5!=0:
        j+=i
print(j)




Verdicts: Runtime Error

Wrong Answer

Runtime Error

Wrong Answer

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())
ans=0
for i in range(n):
    if i%3!=0 and i%5=!=0:
        ans=ans+i
print(ans)

n=int(input())
ans=0
for i in range(n):
    if i%3!=0 and i%5=!=0:
        ans+=i:
print(ans)

n=int(input())
ans=0
for i in range(n+1):
    if i%3!=0 and i%5!=0:
        ans+=i
print(ans)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
seq = raw_input()

total = int(0)
for i in range(1, int(seq)+1, 1):
    if ((i % 3) != 0) & ((i % 5) != 0):
        total = total + i
print(total)


seq = raw_input()

total = int(0)
for i in range(1, int(seq)+1, 1):
    if ((i % 3) != 0) and ((i % 5) != 0):
        total = total + i
print(total)


seq = int(raw_input())

sum = 0
for i in range(1, seq+1, 1):
    if ((i % 3) != 0) & ((i % 5) != 0):
        sum = sum + i
print(sum)

seq = int(input())

total = int(0)
for i in range(1, seq+1, 1):
    if ((i % 3) != 0) and ((i % 5) != 0):
        total = total + i
print(total)


Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted