TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: There are N islands lining up from west to east, connected by N-1 bridges.  The i-th bridge connects the i-th island from the west and the (i+1)-th island from the west.  One day, disputes took place between some islands, and there were M requests from the inhabitants of the islands:  Request i: A dispute took place between the a_i-th island from the west and the b_i-th island from the west. Please make traveling between these islands with bridges impossible.  You decided to remove some bridges to meet all these M requests.  Find the minimum number of bridges that must be removed.

Submission attempts (in order):
n,m=map(int,input().split())
A=list(tuple(map(int,input().split())) for i in range(m))
A.sort(key=lambda x:x[1])

point,count=0,0
for x,y in A:
    if point<x:
        point=x
        count +=1
print(count)

n,m=map(int,input().split())
A=list(tuple(map(int,input().split())) for i in range(m))
A.sort(key=lambda x:x[1])

point,count=0,0
for x,y in A:
    if point<=x:
        point=x
        count +=1

print(count)

n,m=map(int,input().split())
AB=[tuple(map(int,input().split())) for _ in range(m)]

AB=sorted(AB, key=lambda x: x[1])
cnt,cut=0,0

for a,b in AB:
    if cut<=a:
        cnt +=1
        cut=b

print(cnt)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: There are N islands lining up from west to east, connected by N-1 bridges.  The i-th bridge connects the i-th island from the west and the (i+1)-th island from the west.  One day, disputes took place between some islands, and there were M requests from the inhabitants of the islands:  Request i: A dispute took place between the a_i-th island from the west and the b_i-th island from the west. Please make traveling between these islands with bridges impossible.  You decided to remove some bridges to meet all these M requests.  Find the minimum number of bridges that must be removed.

Submission attempts (in order):
nm = input()
n, m = nm.split()
n = int(n)
m = int(m)

arr = [[] for i in range(n)]

for i in range(m):
	ab = input()
	a, b = ab.split()
	a = int(a)
	b = int(b)
	arr[a-1].append(b)	

cnt = 0	
sting = 0
for i,isl in enumelate(arr):
	sting = isl[0]
	for j in arr[i:sting]:
		if (i == sting):
			cnt += 1
print(cnt)

nm = input()
n, m = nm.split()
n = int(n)
m = int(m)

arr = [[] for i in range(n)]

for i in range(m):
	ab = input()
	a, b = ab.split()
	a = int(a)
	b = int(b)
	arr[a-1].append(b)	

cnt = 0	
sting = 0
for i,isl in enumerate(arr):
	sting = isl[0]
	for j in arr[i:sting]:
		if (i == sting):
			cnt += 1
print(cnt)

import bisect
n,m = list(map(int, input().split()))

arr = [[] for i in range(n)]

for i in range(m):
	a, b = list(map(int, input().split()))
	bisect.insort_left(arr[a-1],b)

print(arr)
cnt = 0	
sting = n+1
for i,isl in enumerate(arr):
	if sting == i+1:
		cnt += 1
		sting = n+1

	if len(isl) == 0:
		continue
		
	if isl[0] < sting:
		sting = isl[0]
print(cnt)

nm = input()
n, m = nm.split()
n = int(n)
m = int(m)

arr = [[] for i in range(n)]

for i in range(m):
	ab = input()
	a, b = ab.split()
	a = int(a)
	b = int(b)
	arr[a-1].append(b)	

cnt = 0	
sting = 0
for i,isl in enumerate(arr):
	sting = isl[0]
	for j in arr[i:sting]:
		if (i == sting):
			cnt += 1
print(cnt)

n,m = list(map(int, input().split()))

arr = [[] for i in range(n)]

for i in range(m):
	a, b = list(map(int, input().split()))
	arr[a-1].append(b)	

cnt = 0	
sting = n+1
for i,isl in enumerate(arr):
	isl.sort()
	if sting == i+1:
		cnt += 1
		sting = n+1

	if len(isl) == 0:
		continue
		
	if isl[0] < sting:
		sting = isl[0]
print(cnt)

Verdicts: Runtime Error

Runtime Error

Wrong Answer

Runtime Error

Accepted
Problem: There are N islands lining up from west to east, connected by N-1 bridges.  The i-th bridge connects the i-th island from the west and the (i+1)-th island from the west.  One day, disputes took place between some islands, and there were M requests from the inhabitants of the islands:  Request i: A dispute took place between the a_i-th island from the west and the b_i-th island from the west. Please make traveling between these islands with bridges impossible.  You decided to remove some bridges to meet all these M requests.  Find the minimum number of bridges that must be removed.

Submission attempts (in order):
n, m = map(int, input().split())
x = [[0, 0] for i in range(m)]
ans = 0
for i in range(m):
    x[i][0], x[i][1] = map(int, input().split())

    # print(x[i])
# print('-'*20)
x = sorted(x, key=lambda y: y[1])

#    print(x[i])
tmp = x[0][1]
for i in range(1, m):
    if x[i][0] < tmp < x[i][1]:
        continue
    else:
        ans += 1
        tmp = x[i][1]
        if i == m-1:
            ans += 1
print(ans)


n, m = map(int, input().split())
x = [[0, 0] for i in range(m)]
ans = 0
for i in range(m):
    x[i][0], x[i][1] = map(int, input().split())

    # print(x[i])
# print('-'*20)
x = sorted(x, key=lambda y: y[1])
for i in range(m):
    print(x[i])
tmp = x[0][1]
for i in range(1, m):
    if x[i][0] < tmp < x[i][1]:
        continue
    else:
        ans += 1
        tmp = x[i][1]
        if i == m-1:
            ans += 1
print(ans)


n, m = map(int, input().split())
# stdin.readlines?
x = [[0, 0] for i in range(m)]
for i in range(m):
    x[i][0], x[i][1] = map(int, input().split())
x = sorted(x, key = lambda y: y[0])
ans = 1
mx = max(x[0])
while len(x) > 0:
    for i in range(len(x)):
        if mx <= x[i][1]:
            x.pop(i)
        else:
            mx = x[i][0]
            ans += 1
            break
prin(ans)


n, m = map(int, input().split())
x = [[0, 0] for i in range(m)]
ans = 0
for i in range(m):
    x[i][0], x[i][1] = map(int, input().split())

    # print(x[i])
# print('-'*20)
x = sorted(x, key=lambda y: y[1])

#    print(x[i])
tmp = x[0][1]
for i in range(1, m):
    if x[i][0] < tmp < x[i][1]:
        continue
    else:
        ans += 1
        tmp = x[i][1]
        if i == m-1:
            ans += 1
print(ans)


n, m = map(int, input().split())
# stdin.readlines?
x = [[0, 0] for i in range(m)]
for i in range(m):
    x[i][0], x[i][1] = map(int, input().split())
x = sorted(x, key=lambda y: y[0])
ans = 1
mx = max([x[i][0] for i in range(m)])
while len(x) > 0:
    for i in range(len(x)-1, -1, -1):
        if mx < x[i][1]:
            x.pop(i)
            break
        else:
            mx = x[i][0]
            ans += 1
            break
print(ans)


Verdicts: Wrong Answer

Wrong Answer

Runtime Error

Wrong Answer

Accepted
Problem: There are N islands lining up from west to east, connected by N-1 bridges.  The i-th bridge connects the i-th island from the west and the (i+1)-th island from the west.  One day, disputes took place between some islands, and there were M requests from the inhabitants of the islands:  Request i: A dispute took place between the a_i-th island from the west and the b_i-th island from the west. Please make traveling between these islands with bridges impossible.  You decided to remove some bridges to meet all these M requests.  Find the minimum number of bridges that must be removed.

Submission attempts (in order):
n,m = map(int,input().split())
ts = [list(map(int,input().split()))[::-1]]

count += 0
t = 0

for i in range(m):
  if ts[i][1]>=t:
    count+=1
    t = ts[i][0]
    
print(count)

N,M = map(int,input().split())
ts = []
for i in range(M):
    a,b = map(int,input().split())
    ts.append([b,a])
ts.sort()
tmp = 0
count = 0
for i in range(M):
    if ts[i][1]>=tmp:
        tmp = ts[i][0]
        count += 1
print(count)

Verdicts: Runtime Error

Accepted
Problem: There are N islands lining up from west to east, connected by N-1 bridges.  The i-th bridge connects the i-th island from the west and the (i+1)-th island from the west.  One day, disputes took place between some islands, and there were M requests from the inhabitants of the islands:  Request i: A dispute took place between the a_i-th island from the west and the b_i-th island from the west. Please make traveling between these islands with bridges impossible.  You decided to remove some bridges to meet all these M requests.  Find the minimum number of bridges that must be removed.

Submission attempts (in order):
n, m = map(int, input().split())

ab = []

for i in range(m):
    a, b = map(int, input().split())
    ab.append((a,b))

ab = sorted(ab, key = lambda x: x[[1])

left = 0
ans = 0


for a, b in ab:
    if a < left:
        ans += 1
        left = b-1
    
print(ans)
        

n, m = map(int, input().split())

ab = []

for i in range(m):
    a, b = map(int, input().split())
    ab.append((a,b))

ab = sorted(ab, key = lambda x: x[1])

left = 0
ans = 0


for a, b in ab:
    if a > left:
        ans += 1
        left = b-1
    
print(ans)
        

Verdicts: Runtime Error

Accepted
Problem: There are N islands lining up from west to east, connected by N-1 bridges.  The i-th bridge connects the i-th island from the west and the (i+1)-th island from the west.  One day, disputes took place between some islands, and there were M requests from the inhabitants of the islands:  Request i: A dispute took place between the a_i-th island from the west and the b_i-th island from the west. Please make traveling between these islands with bridges impossible.  You decided to remove some bridges to meet all these M requests.  Find the minimum number of bridges that must be removed.

Submission attempts (in order):
import sys
input = sys.stdin.readline
def solve():
  n,m = (int(i) for i in input().split())
  query = []
  for i in range(m):
    a,b = (int(i) for i in input().split())
    query.append((b-1,a-1))
  query.sort()
  ans = 0
  bridge = [True]*(n-1)
  remove = 10**15
  for i in range(m):
    b,a = query[i]
    if not remove < a:
      if bridge[b-1]:
        ans += 1
        bridge[b-1] = False
        remove = b-1
  print(ans)
    
solve()
  

import sys
input = sys.stdin.readline
def solve():
  n,m = (int(i) for i in input().split())
  query = []
  for i in range(m):
    a,b = (int(i) for i in input().split())
    query.append((b-1,a-1))
  query.sort()
  ans = 0
  remove = 10**15
  for i in range(m):
    b,a = query[i]
    if a > remove or remove >= b:
        ans += 1
        remove = b-1
  print(ans)
    
solve()
  

Verdicts: Wrong Answer

Accepted
Problem: There are N islands lining up from west to east, connected by N-1 bridges.  The i-th bridge connects the i-th island from the west and the (i+1)-th island from the west.  One day, disputes took place between some islands, and there were M requests from the inhabitants of the islands:  Request i: A dispute took place between the a_i-th island from the west and the b_i-th island from the west. Please make traveling between these islands with bridges impossible.  You decided to remove some bridges to meet all these M requests.  Find the minimum number of bridges that must be removed.

Submission attempts (in order):
n,m=map(int,input().split())
AB=[]
for i in range(m):
  a,b=map(int,input().split())
  AB.append([a,b])
AB.sort()
AB.append([float('inf'),float('inf')])
ans,reset,left,right=0,1,0,float('inf')
for i in range(m)t:
    right=min(right,AB[i][1])
    left=AB[i][0]
    if right==left+1 and left!=AB[i+1][0]:
      ans+=1
      right=float('inf')
if right!=float('inf'):
  ans+=1
print(ans)

n,m=map(int,input().split())
AB=[]
append=AB.append
for i in range(m):
  a,b=map(int,input().split())
  append([ra,b])
AB.sort(key=lambda x:x[1])
c,ans=0,0
for a,b in AB:
  if a>=c:
    ans+=1
    c=b
print(ans)

n,m=map(int,input().split())
AB=[]
append=AB.append
for i in range(m):
  a,b=map(int,input().split())
  append([a,b])
AB.sort(key=lambda x:x[1])
c,ans=0,0
for a,b in AB:
  if a>=c:
    ans+=1
    c=b
print(ans)


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: There are N islands lining up from west to east, connected by N-1 bridges.  The i-th bridge connects the i-th island from the west and the (i+1)-th island from the west.  One day, disputes took place between some islands, and there were M requests from the inhabitants of the islands:  Request i: A dispute took place between the a_i-th island from the west and the b_i-th island from the west. Please make traveling between these islands with bridges impossible.  You decided to remove some bridges to meet all these M requests.  Find the minimum number of bridges that must be removed.

Submission attempts (in order):
n, m = map(int, input().split())
SG = sorted([[int(i) for i in input().split()] for i in range(m)], key = lambda x: x[1])

cnt = 0
b = 0
for s, g in SG:
    if s >= b:
        b = s + 1
        cnt += 1
        
print(cnt)

N, M = map(int, input().split())
AB = sorted([[int(i) for i in input().split()] for i in range(M)], key = lambda x: x[1])

cnt = 1
posi = AB[0][1]
for i in range(1, M):
    if AB[i][0] >= posi:
        cnt += 1
        posi = AB[i][1]

print(cnt)

Verdicts: Wrong Answer

Accepted
Problem: There are N islands lining up from west to east, connected by N-1 bridges.  The i-th bridge connects the i-th island from the west and the (i+1)-th island from the west.  One day, disputes took place between some islands, and there were M requests from the inhabitants of the islands:  Request i: A dispute took place between the a_i-th island from the west and the b_i-th island from the west. Please make traveling between these islands with bridges impossible.  You decided to remove some bridges to meet all these M requests.  Find the minimum number of bridges that must be removed.

Submission attempts (in order):
N,M=map(int,input().split())
AB=[[0,0] for i in range(M)]
for i in range(M):
    AB[i][0],AB[i][1]=map(int,input().split())
l=AB[0][0]
r=AB[0][1]
c=0
for i in range(1,M):
    if AB[i][0]<r:
        l=AB[i][0]
        if AB[i][1]<r:
            r=AB[i][1]
    else:
        c+=1
        l=AB[i][0]
        r=AB[i][1]
print(c-3)





N,M=map(int,input().split())
ab=[[0,0] for i in range(M)]
for i in range(M):
    ab[i][0],ab[i][1]=map(int,input().split())
r=0
ans=0
ab.sort()
for i in range(M):
    a=ab[i][0]
    b=ab[i][1]
    if a>=r:
        ans+=1
        r=b
    else:
        if b<r:
            r=b
print(ans)



Verdicts: Wrong Answer

Accepted
Problem: There are N islands lining up from west to east, connected by N-1 bridges.  The i-th bridge connects the i-th island from the west and the (i+1)-th island from the west.  One day, disputes took place between some islands, and there were M requests from the inhabitants of the islands:  Request i: A dispute took place between the a_i-th island from the west and the b_i-th island from the west. Please make traveling between these islands with bridges impossible.  You decided to remove some bridges to meet all these M requests.  Find the minimum number of bridges that must be removed.

Submission attempts (in order):
N,M=map(int,input().split())
ab=[]
for m in range(M):
  [a,b]=[int(i) for i in input().split()]
  ab.append([a,b])
ab.sort(key=lambda x:x[1])
count=[]
bmin=ab[0][1]
count.append(ab[0][1]-1)
for i in range(1,M):
  if ab[i][1]==b:
    count.remove(count[0])
    count.append(ab[i][1])
  else:
    pass
for i in range(1,M):
  if ab[i][0]<=count[-1]<ab[i][1]:
    pass
  else:
    count.append(ab[i][1])
print(len(count))

N,M=map(int,input().split())
ab=[]
for m in range(M):
  [a,b]=[int(i) for i in input().split()]
  ab.append([a,b])
ab.sort(key=lambda x:x[1])
count=[]
count.append(ab[0][1]-1)
for i in range(1,M):
  if ab[i][0]<=count[-1]<ab[i][1]:
    pass
  elif ab[i][0]<=count[-1] and ab[i][1]-1==count[-1]:
    count.remove(count[-1])
    count.append(ab[i][1]-1)
  else:
    count.append(ab[i][1]-1)
print(len(count))

Verdicts: Wrong Answer

Accepted
Problem: There are N islands lining up from west to east, connected by N-1 bridges.  The i-th bridge connects the i-th island from the west and the (i+1)-th island from the west.  One day, disputes took place between some islands, and there were M requests from the inhabitants of the islands:  Request i: A dispute took place between the a_i-th island from the west and the b_i-th island from the west. Please make traveling between these islands with bridges impossible.  You decided to remove some bridges to meet all these M requests.  Find the minimum number of bridges that must be removed.

Submission attempts (in order):
def main():
    N, M = map(int, input().split())
    y = []
    for i in range(M):
        y.append(list(map(int, input().split())))
    youbou = sorted(y, key = lambda x:x[1])
    
    cnt = 1
    k = 0
    for i in range(1, M):
        if(youbou[i][0] >= k):
            cnt += 1
            k = youbou[i][1]
    print(cnt)
main()

def main():
    N, M = map(int, input().split())
    island = []
    for i in range(M):
        a, b = map(int, input().split())
        island.append(tuple((a, b)))
    
    s = sorted(island, key=lambda x:x[1])
    
    base = s[0][1]
    cnt = 1
    for i in range(1, len(s)):
        if(s[i][0] >= base):
            base = s[i][1]
            cnt += 1
    print(cnt)
    
main()

Verdicts: Wrong Answer

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
from numpy.random import randint
n = int(input())
l = list(map(int, input().split()))
ans = 0
for i in range (len(a)-1) :
  try:
    if l[i] == l[i + 1]:
        ans += 1
        l[i + 1] = randint(0, 10000)
  except:
    continue
print(ans)

from random import randint
n = int(input())
l = list(map(int, input().split()))
ans = 0
for i in range (len(a)-1) :
  try:
    if l[i] == l[i + 1]:
        ans += 1
        l[i + 1] = randint(0, 10000)
  except:
    continue
print(ans)

from random import randint
l = list(map(int, input().split()))
ans = 0
for i in range (len(a) - 1) :
  if l[i] == l[i + 1]:
    ans += 1
    l[i + 1] = randint(0, 10000)
print(ans)

from random import randint
n = int(input())
l = list(map(int, input().split()))
ans = 0
for i in range (len(l)-1) :
  try:
    if l[i] == l[i + 1]:
        ans += 1
        l[i + 1] = randint(0, 10000)
  except:
    continue
print(ans)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
n=int(input())
slime=list(map(int,input().split()))
stack=0
count=0
ans=0
for i in slime:
  if i!=stack:
    stack=i
    ans+=(count+1//2)
    count=0
    continue
  count+=1
  stack=i
ans+=(count+1//2)
print(ans)

n=int(input())
slime=list(map(int,input().split()))
stack=0
count=0
ans=0
for i in slime:
  if i!=stack:
    stack=i
    ans+=(count+1//2)
    count=0
    continue
  count+=1
ans+=(count+1//2)
print(ans)

n=int(input())
slime=list(map(int,input().split()))
stack=0
ans=0
for i in slime:
  if i!=stack:
    stack=i
    ans+=(count+1//2)
    count=0
    continue
  count+=1
ans+=(count+1//2)
print(ans)

n=int(input())
slime=list(map(int,input().split()))
stack=0
count=0
ans=0
for i in slime:
  if i!=stack:
    stack=i
    ans+=((count+1)//2)
    count=0
    continue
  count+=1
  stack=i
ans+=((count+1)//2)
print(ans)

Verdicts: Wrong Answer

Wrong Answer

Runtime Error

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
n=int(input())
a=list(map(int,input().split()))
c=0
l=[]
for i in range(1,n):
  l.append(a[i]-a[i-1])
p=l.pop(0)
while len(l)!=0:
  if p!=0:
    p=l.pop(0)
  if p==0:
    c+=1
    while len(l)>2:
      if l[0]==0 and l[1]==0:
        p=l.pop(0)
        p=l.pop(0)
        c+=1
      else:
        break
    if l[0]==0:
      p=l.pop(0)
      if len(l)>0:
        p=l.pop(0)
      else:
         break
    else:
      p=l.pop(0)
if p==0:c+=1
print(c)

n=int(input())
a=list(map(int,input().split()))
c=0
l=[]
for i in range(1,n):
  l.append(a[i]-a[i-1])
p=l.pop(0)
while len(l)!=0:
  if p!=0:
    p=l.pop(0)
  if p==0:
    c+=1
    while len(l)>1:
      if l[0]==0 and l[1]==0:
        p=l.pop(0)
        p=l.pop(0)
        c+=1
      else:
        break
    while len(l)>0:
      if l[0]==0:
        p=l.pop(0)
        if len(l)>0:
          p=l.pop(0)
        else:
          break
      else:
        p=l.pop(0)
print(c)

n=int(input())
a=list(map(int,input().split()))
c=0
l=[]
for i in range(1,n):
  l.append(a[i]-a[i-1])
p=l.pop(0)
while len(l)!=0:
  if p!=0:
    p=l.pop(0)
  if p==0:
    c+=1
    while l[0]==0 and l[1]==0:
      p=l.pop(0)
      p=l.pop(0)
      c+=1
    if l[0]==0:
      p=l.pop(0)
      p=l.pop(0)
    else:
      p=l.pop(0)
print(c)

n=int(input())
a=list(map(int,input().split()))
c=0
l=[]
for i in range(1,n):
  l.append(a[i]-a[i-1])
if len(l)==1 and l[n-2]==0:c+=1
if len(l)>1 and l[n-2]==0 and l[n-3]!=0:c+=1
p=l.pop(0)
while len(l)!=0:
  if p!=0:
    p=l.pop(0)
  else:
    c+=1
    while len(l)>1:
      if l[0]==0 and l[1]==0:
        p=l.pop(0)
        p=l.pop(0)
        c+=1
      else:
        break
    while len(l)>0:
      if l[0]==0:
        p=l.pop(0)
      else:
        p=l.pop(0)
        break
print(c)

Verdicts: Runtime Error

Wrong Answer

Runtime Error

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
def ii():return int(input())
def iim():return map(int,input().split())
def iil():return list(map(int,input().split()))
def ism():return map(str,input().split())
def isl():return list(map(str,input().split()))

n = ii()
A = iil()
ans = 0
for i in range(1,n)
    if A[i-1] == A[i]:
        ans += 1
        A[i] = -1
print(ans)

def ii():return int(input())
def iim():return map(int,input().split())
def iil():return list(map(int,input().split()))
def ism():return map(str,input().split())
def isl():return list(map(str,input().split()))

n = ii()
A = iil()
ans = 0
for i in range(1,n):
    if A[i-1] == A[i]:
        ans += 1
        A[i] = -1
print(ans)

Verdicts: Runtime Error

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
n=input()
numbers=list(map(int,input().split()))
count=0
for i in range(1,n):
  if numbers[i] is numbers[i+1]:
    count+=1
print(count)

n=int(input())
numbers=list(map(int,input().split()))
count=1
c=0
for i in range(n-1):
  if numbers[i] is numbers[i+1]:
    count+=1
  else:
  	c+=count//2
  	count=1
if count-1:
	c+=count//2
print(c)


Verdicts: Runtime Error

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
import math
import heapq
import sys
from collections import Counter




N=int(input[0])
a=list(map(int,input[1].split()))  

cnt=0
for i in range(len(a)-1):
    if a[i]==a[i+1]:
        a[i+1]=-1
        cnt+=1
        #print(a)


print(cnt)


import math
import heapq
import sys
from collections import Counter




N=int(input())
a=list(map(int,input().split()))  

cnt=0
for i in range(len(a)-1):
    if a[i]==a[i+1]:
        a[i+1]=-1
        cnt+=1
        #print(a)


print(cnt)


Verdicts: Runtime Error

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
n=int(input())
a=list(map(int,input().split()))
a.append(0)
tl=0
count=0
for i in range(n):
    if a[i+1]==a[i]:
        tl+=1
    elif tl!=0:
        count+=tl//2
        tl=0
print(count)

n=int(input())
a=list(map(int,input().split()))
a.append(0)
tl=[]
count=0
for i in range(n):
    if a[i+1]==a[i]:
        tl.append(a[i])
    else:
        if len(tl)!=0:
            count+=len(tl)//2
            for j in range(len(tl)):
                del tl[0]
print(count)

n=int(input())
a=list(map(int,input().split()))
tl=1
count=0
for i in range(n-1):
    if a[i+1]==a[i]:
        tl+=1
    elif tl!=1:
        count+=tl//2
        tl=1
print(count)


n=int(input())
a=list(map(int,input().split()))
a.append(0)
tl=[]
count=0
for i in range(n):
    if a[i+1]==a[i]:
        tl.append(a[i])
    else:
        if len(tl)!=0:
            count+=len(tl)//2
            for j in tl:
                del tl[0]
print(count)

n=int(input())
a=list(map(int,input().split()))
a.append(0)
tl=1
count=0
for i in range(n):
    if a[i]==a[i+1]:
        tl+=1
    else:
        count+=tl//2
        tl=1
print(count)


Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
N = input()
A = [int(x) for x in input().split()]

answer = 0
for i in range(1,N):
  if A[i] == A[i-1]:
    A[i] = -1
    answer += 1
print(answer)

import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines

import itertools

N,*A = map(int,read().split())

answer = 0
for _,it in itertools.groupby(A):
    x = len(list(it))
    answer += x//2

print(answer)

Verdicts: Runtime Error

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
n = int(input())
a = list(map(int, input().split()))
count = 0
counter = 0

for i in range(len(a)-1):
    if a[i]==a[i+1] and i == len(a)-2:
        count += int((i+1-counter)//2)+1
    elif a[i]!=a[i+1] or i == len(a)-2:
        count += int((i+1-counter)//2)
        counter = i + 1

print(count)      

n = int(input())
a = list(map(int, input().split()))
count = 0
counter = 0

for i in range(len(a)-1):
    if i == len(a)-2 and a[i]==a[i+1]:
        count += int((i+2-counter)//2)
    if a[i]!=a[i+1]:
        count += int((i+1-counter)//2)
        counter = i + 1

print(count)      

Verdicts: Wrong Answer

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
N  = int(input())
a = [int(i) for i in input().split()]
a.append(N+1)
dupe = []

temp = 1
for i in range(N):
    if a[i] == a[i+1]:
        temp += 1
    elif temp != 0:
        dupe.append(temp)
        temp = 1

print(dupe)
b = [int(i/2) for i in dupe]
print(sum(b))

N  = int(input())
a = [int(i) for i in input().split()]
a.append(N+1)
dupe = []

temp = 1
for i in range(N):
    if a[i] == a[i+1]:
        temp += 1
    elif temp != 0:
        dupe.append(temp)
        temp = 1

b = [int(i/2) for i in dupe]
print(sum(b))

Verdicts: Wrong Answer

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
from sys import stdin

t = stdin.readline()
t_i = int(t)
data = [stdin.readline().rstrip().split() for _ in range(t_i)]
#print(data)
for i in range(t_i) :
    a = int(data[i][0])
    b = int(data[i][1])
    c = int(data[i][2])
    d = int(data[i][3])
    #print(a, b, c, d)
    if a < b :
        print("No")
    elif b > d :
        print("No")
    elif a % b > c and a % b < b :
        print("No")
    else :
        #print("Yes")
    
        stock = a
        count = 0
        while True :
            stock = stock - b
            if stock < 0 :
                print("No")
                break
            if stock <= c :
                stock = stock + d
            count = count + 1
            if count > 10000 :
                print("Yes")
                break

        


from sys import stdin

n = stdin.readline()
n_i = int(n)

a = stdin.readline().rstrip().split()
a_list = list(a)

n_count = 0

if len(a_list) == 2 and a_list[0] == a_list[1] :
    print(n_count + 1)
else :
    for i in range(n_i):
        if i == n_i - 1 :
            break
        if a_list[i] == a_list[i + 1]:
            n_count = n_count + 1
            a_list[i + 1] = "X"

    print(n_count)

Verdicts: Runtime Error

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
N = int(input())
a = list(map(int,input().split()))
ans = 0
now = a[0]
i = 1
while i < N:
    if now == a[i]:
        ans += 1
        i += 2
        if i == N-1:
            break
        now = a[i+1]
    else:
        now = a[i]
        i += 1
print(ans)


N = int(input())
a = list(map(int,input().split()))
ans = 0
now = a[0]
i = 1
while i < N:
    if now == a[i]:
        ans += 1
        if i == N-1:
            break
        now = a[i+1]
        i += 2
        
    else:
        now = a[i]
        i += 1
print(ans)


Verdicts: Runtime Error

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
def main():
    n=int(input())
    a=list(map(int,input().split()))
    ans=0
    for i in range(n-1):
        if(a[i]==a[i+1]):
            a[i+1]=0
            ans+=1
        print(ans)

if __name__=="__main__":
    main()

def main():
    n=int(input())
    a=list(map(int,input().split()))
    ans=0
    for i in range(n-1):
        if(a[i]==a[i+1]):
            a[i+1]=0
            ans+=1
    print(ans)

if __name__=="__main__":
    main()

Verdicts: Wrong Answer

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
n = int(input())
l = [[int(i) for i in input().split()] for i in range(n)]
prev = 0
flag = False
result = 0
for i in l:
    if flag == False and i == prev:
        flag = True
        result += 1
    elif flag == True:
        flag = False
    prev = i
print(result)

n = int(input())
l = input().split()
prev = 0
flag = False
result = 0
for i in l:
    if flag == False and i == prev:
        flag = True
        result += 1
    elif flag == True:
        flag = False
    prev = i
print(result)

Verdicts: Runtime Error

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
N = int(input())
l = list(map(int,input().split()))

len_l = len(l)
st = l[0]
count = 1
count_l = []
for i in range(1,len_l):
    if l[i]==st:
        count+=1
    else:
        count_l.append(count//2)
        st = l[i]
        count = 1
print(sum(count_l))

N = int(input())
l = list(map(int,input().split()))

len_l = len(l)
st = l[0]
count = 1
count_l = []
for i in range(1,len_l):
    if l[i]==st:
        count+=1
    else:
        count_l.append(count//2)
        st = l[i]
        count = 1
count_l.append(count//2)
print(sum(count_l))

Verdicts: Wrong Answer

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
n = int(input())
a = list(map(int, input().split()))

ans = []

i = 1
adjacent = 1

while i < n:
  if a[i] == a[i - 1]:
    adjacent += 1
  else:
    ans.append((adjacent + 1) // 2)
    adjacent = 1
  i += 1
  
ans.append((adjacent + 1) // 2)
print(sum(ans))

n = int(input())
a = list(map(int, input().split()))

ans = []

i = 1
adjacent = 1

while i < n:
  if a[i] == a[i - 1]:
    adjacent += 1
  else:
    ans.append((adjacent + 1) // 2)
    adjacent = 1
  i += 1
  
print(sum(ans))

n = int(input())
a = list(map(int, input().split()))

ans = []

i = 1
adjacent = 1

while i < n:
  if a[i] == a[i - 1]:
    adjacent += 1
  else:
    ans.append(adjacent // 2)
    adjacent = 1
  i += 1
  
ans.append(adjacent // 2)
print(sum(ans))

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
n=int(input());a=list(map(int,input().split()));c,ans=1,0
for i in range(n-1):
  if a[i]==a[i+1]:c+=1
  else:
    if c>=2:ans+=c//2
    c=1
print(ans)

n=int(input());a=list(map(int,input().split()));c,ans=1,0
for i in range(n-1)
  if a[i]==a[i+1]:c+=1
  else:
    if c>=2:ans+=c//2
    c=1
print(ans)

n=int(input())
a=list(map(int,input().split()))
ans=0
for i in range(1,n):
  if a[i-1]==a[i]:
    a[i]=-1
    ans+=1
print(ans)

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
n = int(input())
li=[]
re=[]
for i in range(n):
	li.append(list(map(int,input().split())))
	if li[i][0] >= li[i][1] and li[i][1] <= li[i][3]:
		Lim=li[i][0]%li[i][1]
		if li[i][1] == li[i][3]:
			pass
		else:
			while Lim+li[i][3]-li[i][1]<li[i][1]:
				Lim=Lim+li[i][3]-li[i][1]
		if li[i][2] >= Lim:
			re.append("Yes")
		else:
			re.append("No")
	else:
		re.append("No")
for value in re:
 print(value)

N=int(input())
li = list(map(int,input().split()))
M=0
for i in range(N-1):
	if li[i]==li[i+1]:
		li[i+1]=li[i+1]+10000
		M=M+1
print(M)


Verdicts: Runtime Error

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
import fractions
T = int(input())

L = []
for i in range(0,T):
    L = list(map(int, input().split()))
    A = L[0]
    B = L[1]
    C = L[2]
    D = L[3]

    ans = "Yes"
    if A < B: 
        ans = "No"
    elif D < B: 
        ans = "No"
    elif B - C <= 1: 
        ans = "Yes"
    elif C < B-fractions.gcd(B,D)+(A%fractions.gcd(B,D)):
        ans = "No"


    print(ans)
    L = []



N = int(input())
L = list(map(int,input().split()))
count = 0

for i in range(0,N-1):
    if L[i] == L[i+1]:
        L[i+1] = 101
        count += 1

print(count)

Verdicts: Runtime Error

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
from sys import stdin
import math
columns = int(stdin.readline().rstrip())
datas = [stdin.readline().rstrip().split() for _ in range(columns)]
for data in datas:
    A = int(data[0])
    B = int(data[1])
    C = int(data[2])
    D = int(data[3])
    if A < B:
        print("No")
        continue
    if D < B:
        print("No")
        continue
    if C > B:
        print("Yes")
        continue
    g = math.gcd(B,D)
    if (B - g + A % g) >C :
        print("No")
    else:
        print("Yes")     
    


from sys import stdin
data = [stdin.readline().rstrip().split() for _ in range(2)]
count = 0
i = 0
while i + count+ 1 < int(data[0][0]):
    if (data[1][i + count+ 1] == data[1][i + count]):
        count = count + 1
    i = i + 1
print(count)

Verdicts: Runtime Error

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
n = int(input())
x = input().split(' ')
l = [int(i) for i in x]

c = 0
i = 0
def s():
    while i+2 < len(l):
        if l[i] == l[i+1]:
            if l[i+1] == l[i+2]:
                c += 1
                i += 2
            else:
                c += 1
                i += 2
        else:
            i += 1
    
    print(c)
    return 0

s()

n = int(input())
x = input().split(' ')
l = [int(i) for i in x]

c = 0


for i in range(1,n):
    if not boon and l[i] == l[i-1]:
        c += 1
        boon = True
    else:
        boon = False

print(c)


n = int(input())
x = input().split(' ')
l = [int(i) for i in x]

c = 0


boon = False

for i in range(1,n):
    if not boon and l[i] == l[i-1]:
        c += 1
        boon = True
    else:
        boon = False

print(c)


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Takahashi lives in another world. There are slimes (creatures) of 10000 colors in this world. Let us call these colors Color 1, 2, ..., 10000.  Takahashi has N slimes, and they are standing in a row from left to right. The color of the i-th slime from the left is a_i. If two slimes of the same color are adjacent, they will start to combine themselves. Because Takahashi likes smaller slimes, he has decided to change the colors of some of the slimes with his magic.  Takahashi can change the color of one slime to any of the 10000 colors by one spell. How many spells are required so that no slimes will start to combine themselves?

Submission attempts (in order):
n=int(input())
a=[int(i) for i in inpup().split()]
cnt=0
flag=False
for i in range(1,n):
    if a[i]==a[i-1]:
        if flag:
            flag=False
        else:
            cnt+=1
            flag=True
    else:
        flag=False
print(cnt)

n=int(input())
a=[int(i) for i in input().split()]
cnt=0
flag=False
for i in range(1,n):
    if a[i]==a[i-1]:
        if flag:
            flag=False
        else:
            cnt+=1
            flag=True
    else:
        flag=False
print(cnt)

Verdicts: Runtime Error

Accepted