Problem: We have two desks: A and B. Desk A has a vertical stack of N books on it, and Desk B similarly has M books on it.  It takes us A_i minutes to read the i-th book from the top on Desk A (1 \leq i \leq N), and B_i minutes to read the i-th book from the top on Desk B (1 \leq i \leq M).  Consider the following action:    * Choose a desk with a book remaining, read the topmost book on that desk, and remove it from the desk.  How many books can we read at most by repeating this action so that it takes us at most K minutes in total? We ignore the time it takes to do anything other than reading.

Submission attempts (in order):
N, M, K = map(int, input().split())
A = list(map(int, input().split()))
B = list(map(int, input().split()))

A_sum = 0
A_max = 0
B_sum = 0
B_max = 0
best_num = 0
A_max = N
flag = True 


for i in range(N):
    A_sum += A[i]
    if A_sum > K:
        A_sum -= A[i]
        A_max = i
        flag = False
        break
A = A[0:A_max]
now_num = A_max 
mixsum = A_sum 
b_num = 0 
if flag:
    now_num += M
    b_num = M
    for i in range(M):
        mixsum += B[i]
        if mixsum > K:
            mixsum -= B[i]
            now_num += i
            b_num = i  
            break
A.reverse()
best_num = now_num
for i in range(A_max):
    mixsum -= A[i]
    now_num -= 1
    for j in range(b_num, M):
        mixsum += B[j]
        now_num += 1
        if mixsum > K:
            mixsum -= B[j]
            now_num -= 1
            break
    if now_num > best_num:
        best_num = now_num
print(best_num)


N, M, K = map(int, input().split())
A = list(map(int, input().split()))
B = list(map(int, input().split()))


A_max = 0
B_sum = 0
B_max = 0
best_num = 0

flag = True 


A_max = N
A_sum = 0
for i in range(N):
    A_sum += A[i]
    if A_sum > K:
        A_sum -= A[i]
        A_max = i
        flag = False
        break
A = A[0:A_max]
now_num = A_max 
mixsum = A_sum 
b_num = 0 
if flag:
    now_num += M
    b_num = M
    for i in range(M):
        mixsum += B[i]
        if mixsum > K:
            mixsum -= B[i]
            now_num = A_max + i
            b_num = i  
            break
A.reverse()
best_num = now_num
for i in range(A_max):
    mixsum -= A[i]
    now_num -= 1
    for j in range(b_num, M):
        mixsum += B[j]
        now_num += 1
        if mixsum > K:
            mixsum -= B[j]
            now_num -= 1
            b_num = j
            break
    if now_num > best_num:
        best_num = now_num
print(best_num)


N, M, K = map(int, input().split())
A = list(map(int, input().split()))
B = list(map(int, input().split()))

A_sum = 0
A_max = 0
B_sum = 0
B_max = 0
best_num = 0
A_max = N
flag = True 


for i in range(N):
    A_sum += A[i]
    if A_sum > K:
        A_sum -= A[i]
        A_max = i
        flag = False
        break
A = A[0:A_max]
now_num = A_max 
mixsum = A_sum 
b_num = 0 
if flag:
    now_num += M
    b_num = M
    for i in range(M):
        mixsum += B[i]
        if mixsum > K:
            mixsum -= B[i]
            now_num = A_max + i
            b_num = i  
            break
A.reverse()
best_num = now_num
for i in range(A_max):
    mixsum -= A[i]
    now_num -= 1
    for j in range(b_num, M):
        mixsum += B[j]
        now_num += 1
        if mixsum > K:
            mixsum -= B[j]
            now_num -= 1
            break
    if now_num > best_num:
        best_num = now_num
print(best_num)


N, M, K = map(int, input().split())
A = list(map(int, input().split()))
B = list(map(int, input().split()))


A_max = 0
B_sum = 0
B_max = 0
best_num = 0

flag = True 


A_max = N
A_sum = 0
for i in range(N):
    A_sum += A[i]
    if A_sum > K:
        A_sum -= A[i]
        A_max = i
        break
A = A[0:A_max]
now_num = A_max 
mixsum = A_sum 
b_num = 0 
if flag:
    now_num += M
    b_num = M
    for i in range(M):
        mixsum += B[i]
        if mixsum > K:
            mixsum -= B[i]
            now_num = A_max + i
            b_num = i  
            break
A.reverse()
best_num = now_num
for i in range(A_max):
    mixsum -= A[i]
    now_num -= 1
    for j in range(b_num, M):
        mixsum += B[j]
        now_num += 1
        if mixsum > K:
            mixsum -= B[j]
            now_num -= 1
            b_num = j #miss
            break
    if now_num > best_num:
        best_num = now_num
print(best_num)


Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted