TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input().split())
lr=[]
result=0
for i in range(m):
  lr.append(input().split())
for k in range(1,n+1):
  for h in range(m):
    if int(k)<=int(lr[h][0]) or int(k)>=int(lr[h][1]):
      break
    result+=1
print(result)

n,m=map(int,input().split())
l=0
r=n
lr=[]
for i in range(m):
  lr.append(input().split())
for j in lr:
  print(j)
  if l<int(j[0]):
    l=int(j[0])
  if r>int(j[1]):
    r=int(j[1])
print(r-l+1)

n,m=map(int,input().split())
lr=[]
result=0
gates=0
for i in range(m):
  lr.append(input().split())
for k in range(1,n+1):
  gates=0
  for h in range(m):
    if not(int(k)>=int(lr[h][0]) and int(k)<=int(lr[h][1])):
      break
  result+=1
print(result)

n,m=map(int,input().split())
l=1
r=n
lr=[]
for i in range(m):
  lr.append(input().split())
for j in lr:
  if l<int(j[0]):
    l=int(j[0])
  if r>int(j[1]):
    r=int(j[1])
if r>=l:
  print(int(r-l+1))
else:
  print(0)

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
li = [list(map(int,input().split())) for _ in range(m)]
maxl = max(li, key=lambda x:x[0])[0]
minr = min(li, key=lambda x:x[1])[1]
if maxl <= minr:
    print(r-l+1)
else:
    print(0)

n,m = map(int,input().split())
li = [list(map(int,input().split())) for _ in range(m)]
maxl = max(li, key=lambda x:x[0])[0]
minr = min(li, key=lambda x:x[1])[1]
if maxl <= minr:
    print(minr-maxl+1)
else:
    print(0)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
100000 1
1 100000


n, m = map(int, input().split())
l, r = 0, 100001
for i in range(m):
    x, y = map(int, input().split())
    if l <= x:
        l = x
    if r >= y:
        r = y
print(len([x for x in range(l, r+1)]))

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
_, __, *d = map(int, open(0).read().split())
print(max(min(d[1::2]) - max(d[::2]) + 1), 0)

_, __, *d = map(int, open(0).read().split())
print(max(min(d[1::2]) - max(d[::2]) + 1, 0))

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import heapq                        
hq_left = []
hq_right = []


listA=[] 
N,M= map(int,input().split())

for i in range(M):
    listA.append(list(map(int,input().split())))


candidate_list = [i for i in range(1,N+1)]

for i in range(M):
    hq_left.append(listA[i][0])
    hq_right.append(listA[i][1])
    
if max(hq_left)-min(hq_right) <0:
    print(0)
else:
    print(max(hq_left)-min(hq_right)+1)

import heapq                        
hq_left = []
hq_right = []


listA=[] 
N,M= map(int,input().split())

for i in range(M):
    listA.append(list(map(int,input().split())))


candidate_list = [i for i in range(1,N+1)]

for i in range(M):
    hq_left.append(listA[i][0])
    hq_right.append(listA[i][1])

if max(hq_left)-min(hq_right) <0:
    print(0)
else:
    print(len(candidate_list[max(hq_left):min(hq_right)])+1)

hq_left = []
hq_right = []


listA=[] 
N,M= map(int,input().split())

for i in range(M):
    listA.append(list(map(int,input().split())))


candidate_list = [i for i in range(1,N+1)]

for i in range(M):
    hq_left.append(listA[i][0])
    hq_right.append(listA[i][1])

if min(hq_right)-max(hq_left) <0:
    print(0)
else:
    print(len(candidate_list[max(hq_left):min(hq_right)])+1)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,(input().split())
          
l=[]
for i in range(m):
	l,r = map(int,input().split())
    li = range(l,r)

for i in li:
	print(i)

	

n,m = map(int,input().split())

li=[]
for i in range(m):
	l,r = map(int,input().split())
	li.append(list(range(l,r+1)))

for i in li:
	print(i)

n,m = map(int,input().split())

ll=[]
rr =[]
for i in range(m):
	l,r = map(int,input().split())
	ll.append(l)
	rr.append(r)

an = min(rr)-max(ll)+1
print(max(0,an))

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
from itertools import accumurate
N,M=map(int,input().split())
L = [0]*(N+1)
for _ in range(M):
  l,r = map(lambda x:int(x)-1,input().split())
  L[l]+=1
  L[r+1]+=1

L = list(accumurate(L))
print(L.count(M)) 

from itertools import accumulate
N,M=map(int,input().split())
L = [0]*(N+1)
for _ in range(M):
  l,r = map(lambda x:int(x)-1,input().split())
  L[l]+=1
  L[r+1]-=1

L = list(accumulate(L))
print(L.count(M))

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
l = []
r = []

for i in range(m):
    a,b = map(int,input().split())
    l.append(a)
    r.append(b)


if min(r) < max(l):
    print(min(r) - max(l) + 1)
else:
    print(0)

n,m = map(int,input().split())
l = []
r = []

for i in range(m):
    a,b = map(int,input().split())
    l.append(a)
    r.append(b)


if min(r) >= max(l):
    print(min(r) - max(l) + 1)
else:
    print(0)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import sys

n,m = input().split()
n,m = int(n), int(m)

l, r = [],[]

count = 0

for i in range(1,m) :
    l[i], r[i] = input().split()
    l[i], r[i]  = int(l[i]), int( r[i] )

    if l[i] <= m and m <= r[i] :
        count = count + m - l[i] 


import sys

n,m = input().split()
n,m = int(n), int(m)


list = []

count = 0
lMin, rMax = -1, -1

for i in range(0,m) :
    l, r = input().split()

    list.append((int(l),int(r)))

    if lMin == -1 and rMax == -1:
        lMin, rMax = list[i]
    else:
        if lMin < list[i][0] :
            lMin = list[i][0]
            
        if rMax > list[i][1] :
            rMax = list[i][1]

count = rMax - lMin +1

if count < 0 : 
    count = 0

print(count)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
# -*- coding: utf-8 -*-
     
z = []
id, gate = map(int, input().split())
for i in range(gate)
    a = [list(map(int,input().split()))]
    z.append(a)
b = []

for i in range(gate)
    c = range(a[i, 0], a[i, 1])
    b.extend(c)

d = range(id)

d = set(d)
b = set(b)

list = list(b&d)
print(len(list))

# -*- coding: utf-8 -*-
     
id, gate = map(int, input().split())
for i in range(gate)
    a = [list(map(int,input().split()))]
b = []

for i in range(gate)
    c = range(a[i, 0], a[i, 1])
    b.extend(c)

d = range(id)

d = set(d)
b = set(b)

list = list(b&d)
print(len(list))

# -*- coding: utf-8 -*-
     
id, gate = map(int, input().split())
a = [list(map(int,input().split())) for i in range(gate)]
b = []

for i in range(gate)
    c = range(a[i, 0], a[i, 1])
    b.extend(c)

d = range(id)

d = set(d)
b = set(b)

list = list(b&d)
print(len(list))

n, m = map(int, input().split())

ans = 0
L, R = 0, 114514

for i in range(m):
    l, r = map(int, input().split())
    L, R = max(L, l), min(R, r)

print(R - L + 1 if R - L + 1 >= 1 else 0)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import sys

N, M = map(int,input().split())
L = [0] * M
R = [0] * M
for i in range(M):
    L[i], R[i] = map(int, input().split())
if M == 1:
    print(N)
else:
    G = []
    for i in range(M):
        G1 = []
        for j in range(len(L[i:])):
            G1.append(L[i:][j])
        for k in range(len(R[:(i+1)])):
            G1.append(R[:(i+1)][k])
        G.append(G1)

    print(G)
    count_list = [0]*N
    for i in range(1, N+1):
        for j in range(M):
            if not G[j-1].count(i):
                count_list[i-1] += 1

    print(count_list.count(0))

import sys

N, M = map(int,input().split())
L = [0] * M
R = [0] * M
for i in range(M):
    L[i], R[i] = map(int, input().split())
if M == 1:
    print(R[0] - L[0] + 1)
else:
    G = []
    for i in range(M):
        G1 = []
        for j in range(len(L[i:])):
            G1.append(L[i:][j])
        for k in range(len(R[:(i+1)])):
            G1.append(R[:(i+1)][k])
        G.append(G1)

    print(G)
    count_list = [0]*N
    for i in range(1, N+1):
        for j in range(M):
            if not G[j-1].count(i):
                count_list[i-1] += 1

    print(count_list.count(0))

N, M = map(int,input().split())
L = [0] * M
R = [0] * M
for i in range(M):
    L[i], R[i] = map(int, input().split())

G = []
for i in range(M):
    G1 = []
    for j in range(len(L[i:])):
        G1.append(L[i:][j])
    for k in range(len(R[:(i+1)])):
        G1.append(R[:(i+1)][k])
    G.append(G1)

print(G)
count_list = []
for i in range(1, N+1):
    for j in range(M):
        if not G[j-1].count(i):
            j = -1
            break
    if j+1 == M:
        count_list.append(1)

print(len(count_list))

N, M = map(int,input().split())
L = [0] * M
R = [0] * M
for i in range(M):
    L[i], R[i] = map(int, input().split())

if min(R) >= max(L):
    print(min(R) - max(L) + 1)
else:
    print(0)

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
l_max = 1
r_min = N + 1
for _ in range(M):
    L, R = map(int, input().split())
    if l_max < L:
        l_max = L
    if r_min > R:
        r_min = R
if r_min < l_max:
    print(r_min - l_max + 1)
else:
    print(0)

N, M = map(int, input().split())
l_max = 1
r_min = N + 1
for _ in range(M):
    L, R = map(int, input().split())
    if l_max < L:
        l_max = L
    if r_min > R:
        r_min = R
if r_min + 1 > l_max:
    print(r_min - l_max + 1)
else:
    print(0)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = list(map(int, input().split()))
l_max = 1
r_min = n
for i in range(m):
    l,r = list(map(int, input().split()))
    if l > l_max:
        l_max = l
    if r < r_min:
        r_min = r
print(r-l+1 if r>=l else 0)

n,m = list(map(int, input().split()))
l_max = 1
r_min = n
for i in range(m):
    l,r = list(map(int, input().split()))
    if l > l_max:
        l_max = l
    if r < r_min:
        r_min = r
print(r_min-l_max+1 if r_min>=l_max else 0)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import numpy as np
from sys import stdin

def main():
    nm = [int(x) for x in stdin.readline().rstrip().split()]
    gate = np.zeros([nm[1], 2], dtype=int)
    
    for i in range(nm[1]):
        g = [int(x) for x in stdin.readline().rstrip().split()]
        gate[i] = g
    
    l_max = np.max(gate[:, 0])
    r_min = np.min(gate[:, 1])
    
    print(r_min-l_max)

if __name__ == "__main__":
    main()

import numpy as np
from sys import stdin

def main():
    nm = [int(x) for x in stdin.readline().rstrip().split()]
    gate = np.zeros([nm[1], 2], dtype=int)
    
    for i in range(nm[1]):
        g = [int(x) for x in stdin.readline().rstrip().split()]
        gate[i] = g
    
    l_max = np.max(gate[:, 0])
    r_min = np.min(gate[:, 1])
    c = 0
    if l_max <= r_min:
        c = r_min-l_max+1
    print(c)

if __name__ == "__main__":
    main()

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = list(map(int, input().split()))
mn = 0
mx = N
f = False
for i in range(M):
    tmn, tmx = list(map(int, input().split()))
    if mn < tmn < mx:
        mn = tmn
    else:
        f = True
        break
    if mn < tmx < mx:
        mx = tmx
    else:
        f = True
        break
if f:
    print(0)
else:
    print(mx - mn + 1)


N, M = list(map(int, input().split()))
mn = 0
mx = N
f = False
for i in range(M):
    tmn, tmx = list(map(int, input().split()))
    if mn < tmn:
        mn = tmn
    if tmx < mx:
        mx = tmx
    if mx < mn:
        f = True
        break
if f:
    print(0)
else:
    print(mx - mn + 1)


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M=map(int,input().split())
Key=[0]*(N+1)
for i in range(M):
    L,R = map(int,input().split())
    Key[L-1] += 1
    Key[R] -= 1
for i in range(N):
    Key[i+1] += Key[i] 
print(Key)
print(Key.count(M))

N,M=map(int,input().split())
Key=[0]*(N+1)
for i in range(M):
    L,R = map(int,input().split())
    Key[L-1] += 1
    Key[R] -= 1
for i in range(N):
    Key[i+1] += Key[i] 
print(Key)
print(Key.count(m))


N,M=map(int,input().split())
Key=[0]*(N+1)
for i in range(M):
    L,R = map(int,input().split())
    Key[L-1] += 1
    Key[R] -= 1
for i in range(N):
    Key[i+1] += Key[i] 
print(Key.count(M))

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import sys
args = sys.stdin.readlines()
n, m = map(int, args[0].split(' '))
gates = []
for gate in args[1:]:
  l, r = map(int, gate.split(' '))
  gates.append((l, r))
  
ids = gates[0]
for gate in gates[1:]:
  l, r = gate
  ids = [x for x in ids in range(l, r+1)]
  
print(len(ids))


import sys
args = sys.stdin.readlines():
n, m = map(int, args[0].split(' '))
gates = []
for gate in args[1:]:
  l, r = map(int, gate.split(' '))
  gates.append((l, r))
  
ids = gates[0]
for gate in gates[1:]:
  l, r = gate
  ids = [x for x in ids in range(l, r+1)]
  
print(len(ids))

import sys
args = sys.stdin.readlines()
n, m = map(int, args[0].split(' '))
gates = []
for gate in args[1:]:
  l, r = map(int, gate.split(' '))
  gates.append((l, r))
  
ids = gates[0]
for gate in gates[1:]:
  l, r = gate
  ids = [x for x in ids if x in range(l, r+1)]
  
print(len(ids))


import sys
args = sys.stdin.readlines()
n, m = map(int, args[0].split(' '))
gates = []
for gate in args[1:]:
  l, r = map(int, gate.split(' '))
  gates.append((l, r))
  
ids = gates[0]
for gate in gates[1:]:
  l, r = gate
  ids = ids[l-ids[0]:r-ids[-1]+1]
  
print(len(ids))


import sys
args = sys.stdin.readlines()
n, m = map(int, args[0].split(' '))
l_1 = 1
r_1 = n

for gate in args[1:]:
  l, r = map(int, gate.split(' '))  
  if l > l_1:
    l_1 = l
  if r < r_1:
    r_1 = r

ids = r_1 - l_1 + 1
if ids < 0:
  print(0)
else:
  print(ids)

Verdicts: Runtime Error

Runtime Error

Wrong Answer

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
l = 0
r = N + 1
for _ in range(M):
  ll, rr = map(int, input().split())
  l = max(l, ll)
  r = min(r, rr)
print(max(0, r - l))

N, M = map(int, input().split())
l = 0
r = N + 1
for _ in range(M):
  ll, rr = map(int, input().split())
  l = max(l, ll)
  r = min(r, rr)
print(max(0, r - l + 1))

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import sys
input = sys.stdin.readline
n,m = input().split()
n = int(n)
m = int(m)
l = 0
r = n+1
a = input().split()
for i in range(m):
    l2,r2 = input().split()
    l2 = int(l2)
    r2 = int(r2)
    if l2 > l:
        l = l2
    if r2 < r:
        r = r2
if (r - l + 1) >= 0:
    print(r-l+1)
else:
    print("0")

import sys
input = sys.stdin.readline
n,m = input().split()
n = int(n)
m = int(m)
l = 0
r = n+1
for i in range(m):
    l2,r2 = input().split()
    l2 = int(l2)
    r2 = int(r2)
    if l2 > l:
        l = l2
    if r2 < r:
        r = r2
if (r - l + 1) >= 0:
    print(r-l+1)
else:
    print("0")

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
gates = [list(map(int,input().split())) for _ in range(m)]
l = []
r = []
for gate in gates:
    l.append(gate[0])
    r.append(gate[1])
ans = min(r)+1 - max(l)


n,m = map(int,input().split())
gates = [list(map(int,input().split())) for _ in range(m)]
l = []
r = []
for gate in gates:
    l.append(gate[0])
    r.append(gate[1])
ans = min(r)+1 - max(l)
print(ans if ans > 0 else 0)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
ans = 0
l_max = 0
r_min = 0
for i in range(1,m+1):
  l, r = map(int, input().split())
  if r < r_min:
    r_min = r
  if l_max > l:
    l_max = l
for i in range(1, n+1):
  if i > l_max and i < r_min:
    ans += 1
print(ans)



n, m = map(int, input().split())
ans = 0
l_max = 0
r_min = n+1
for i in range(m):
  l, r = map(int, input().split())
  if r < r_min:
    r_min = r
  if l > l_max:
    l_max = l
for i in range(1, n+1):
  if i >= l_max and i <= r_min:
    ans += 1
print(ans)





Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import numpy as np
n,m = map(int, input().split())
ls = []
for i in range(m):
    l,r = map(int, input().split())
    tmp = list(range(l,r+1))
    ls.append(tmp)
binary = [0] * n

for i in ls:
    for j in i:
        binary[j] += 1
print(binary.count(m))  

import numpy as np
n,m = map(int, input().split())
ls = []
for i in range(m):
    l,r = map(int, input().split())
    tmp = list(range(l,r+1))
    ls.append(tmp)

print(ls)

binary = [0] * n

for i in ls:
    for j in i:
        binary[j] += 1
print(binary.count(m))    

import numpy as np
n,m = map(int, input().split())
ls = []
for i in range(m):
    l,r = map(int, input().split())
    tmp = list(range(l,r+1))
    ls.append(tmp)
binary = [0] * n
ls = [flatten for inner in ls for flatten in inner]
for i in ls:
    binary[i] += 1
print(binary.count(m))    

n, m = map(int, input().split())
left = 0
right = n
ls = list(range(n))

for i in range(m):
    l, r = map(int, input().split())
    if left < l-1:
        left = l-1
    if right > r:
        right = r
print(len(ls[left:right]))

Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
#!/usr/bin/env python3

def main():
    N, M = map(int, input().split())
    Card = [[] for i in range(M)]
    Diff = [i for i in range(1, N + 1)]

    for i in range(0, M):
        L, R = map(int, input().split())
        tmp = []
        for j in range(L, R + 1):
            if j in Diff:
                tmp.append(j)
        Diff = tmp
        print(len(Diff))


main()

#!/usr/bin/env python3

def main():
    N, M = map(int, input().split())
    L =[0 for i in range(M)]
    R = [0 for i in range(M)]

    for i in range(0, M):
        L[i], R[i] = map(int, input().split())
    
    print(max(min(R) - max(L) + 1, 0))


main()

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
cannot understand the q



import sys
input = sys.stdin.readline
sys.setrecursionlimit(10**6)
##############################

N, M = map(int, input().split())
L = [0] * M
R = [0] * M
for i in range(M):
    l, r = map(int, input().split())
    L[i] = l
    R[i] = r

left = max(L)
right = min(R)

if left <= right:
    print(right-left+1)
else:
    print(0)



Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int,input().split())
L = [0] * M
R = [0] * M
for i in range(M):
    L[i], R[i] = map(int,input().split())
ans = 0
A = [0] * N
for i in range(M):
    A[L[i]:R[i]+1] += 1
for i in range(N):
    if A[i] == M:
        ans += 1
print(ans)

N, M = map(int,input().split())
L = [0] * M
R = [0] * M
for i in range(M):
    L[i], R[i] = map(int,input().split())
ans = 0
A = [0] * N
L_max = max(L)
R_min = min(R)
if R_min >= L_max:
    ans = R_min - L_max + 1
else:
    ans = 0
print(ans)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())

l_max = 1
r_min = N
for _ in range(M):
    l, r = map(int, input().split())
    l_max = max(l_max, l)
    r_min = min(r_min, r)

if r_min > l_max:
    print(0)
else:
    print(r_min-l_max+1)

N, M = map(int, input().split())

l_max = 1
r_min = N
for _ in range(M):
    l, r = map(int, input().split())
    l_max = max(l_max, l)
    r_min = min(r_min, r)

if r_min < l_max:
    print(0)
else:
    print(r_min-l_max+1)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M = map(int,input().split())
L_list = []
R_list = []

for i in range(M):
  L,R = map(int,input().split())
  L_list.append(L)
  R_list.append(R)
  
if max(R_list) >= max(L_list):
  print(max(R_list)  - max(L_list) + 1)
else:
  print(0)

N,M = map(int,input().split())
list = []

for i in range(M):
  L,R = map(int,input().split())
  list.append(range(L,R))

unq = set(list)

counter = 0

for i in unq:
  if list.count(i) == M:
    counter +=1
    
print(counter)


N,M = map(int,input().split())
L_list = []
R_list = []

for i in range(M):
  L,R = map(int,input().split())
  L_list.append(L)
  R_list.append(R)
  
if min(R_list) >= max(L_list):
  print(min(R_list)  - max(L_list)+1)
else:
  print(0)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input().split())
ab=[map(int,input().split()) for _ in range(m)]
b=min(ab[i][1] for i in range(m))
a=max(ab[i][0] for i in range(m))
print(b-a+1)

n,m=map(int,input().split())
ab=[list(map(int,input().split())) for _ in range(m)]
b=min(ab[i][1] for i in range(m))
a=max(ab[i][0] for i in range(m))
if b-a+1<0:print(0)
else:print(b-a+1)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M = map(int,input().split())
L = list(map(int,input().split()))
R = list(map(int,input().split()))
L.sort()
R.sort()
count = 0
for i in range(1,N+1):
  if i >= L[-1] and i <= R[0]:
    count += 1
print(count)

N,M = map(int,input().split())
L = []
R = []
ans = 0
for _ in range(M):
  l, r = map(int, input().split())
  L.append(l)
  R.append(r)
ans = max(0,min(R) - min(L) + 1)
print(ans)

N,M = map(int,input().split())
L,R = [list(map(int,input().split())) for _ in range(M)]
count = 0
for i in range(N+1):
  if i > max(L) and i < min(R):
    count += 1
print(count)

N,M = map(int,input().split())
L,R = list(map(int,input().split()))
count = 0
for i in range(N+1):
  if i > max(L) and i < min(R):
    count += 1

N,M = map(int,input().split())
L = []
R = []
count = 0
for j in range(M):
  L,R = map(int,input().split())
for i in range(N+1):
  if i > max(L) and i < min(R):
    count += 1

N,M = map(int,input().split())
LR = [list(map(int,input().split())) for _ in range(N)]
count = 0
for i in range(N):
  for j,k in LR:
    if i >= j and i <= k:
      count += 1
print(count)


N,M = map(int,input().split())
L = [list(map(int,input().split())) for _ in range(M)]
R = [list(map(int,input().split())) for _ in range(M)]
L.sort()
R.sort()
count = 0
for i in range(1,N+1):
  if i >= L[-1] and i <= R[0]:
    count += 1
print(count)

N,M = map(int,input().split())
L = []
R = []
count = 0
for j in range(M):
  l,r = map(int,input().split())
  L.append(l)
  R.append(r)
for i in range(N+1):
  if i > max(L) and i < min(R):
    count += 1
print(count)

N,M = map(int,input().split())
LR = [list(map(int,input().split())) for _ in range(M)]
count = 0
for i in range(N):
  for j,k in LR:
    if i >= j and i <= k:
      count += 1
print(count)

N,M = map(int,input().split())
L = []
R = []
count = 0
for j in range(M):
  l,r = map(int,input().split())
  L.append(l)
  R.append(r)
print(max(0,min(R)-max(L)+1))

Verdicts: Runtime Error

Wrong Answer

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split(" "))
min_l = 1
max_r = N

for m in range(M):
    l, r = map(int, input().split(" "))
    if l > min_l:
        min_l = l
    if r < max_r:
        max_r = r
    print(min_l, max_r)
print((max_r-min_l)+1)

N, M = map(int, input().split(" "))
min_l = 1
max_r = N

for m in range(M):
    l, r = map(int, input().split(" "))
    if l > min_l:
        min_l = l
    if r < max_r:
        max_r = r

ans = (max_r-min_l)+1
if ans < 0:
    ans = 0

print(ans)


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
#n=int(input())
#s,t=input().split()
n,m = map(int, input().split())
#l=list(map(int, input().split()))
l=[0]*100005
r=[1000005]*100005
z=1000010
for i in range(m):
   l[i],r[i]=map(int,input().split()) 
mi=max(l)
ma=min(r)



if mi>ma:
    print(0)
else
    print(ma-mi+1)

#n=int(input())
#s,t=input().split()
n,m = map(int, input().split())
#l=list(map(int, input().split()))
l=[0]*100005
r=[1000005]*100005
z=1000010
for i in range(m):
   l[i],r[i]=map(int,input().split()) 
mi=max(l)
ma=min(r)



if mi>ma:
    print(0)
else:
    print(ma-mi+1)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
lr = [[map(int,input().split())] for i in range(m)]

max = 0
min = n+1
for i in range(m):
    if lr[i][0] > max :
        max = lr[i][0]
    if lr[i][1] < min :
        min = lr[i][1]

print(min-max+1)


n,m = map(int,input().split())
lr = [list(map(int,input().split())) for i in range(m)]

max = 0
min = n+1
for i in range(m):
    if lr[i][0] > max :
        max = lr[i][0]
    if lr[i][1] < min :
        min = lr[i][1]

if min-max >= 0:
    print(min-max+1)
else :
    print(0)


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
l_lst = list()
for i in range(m):
    l_lst.append(input().split())

for i in range(0, len(l_lst)):
    for j in range(0, len(l_lst[i])):
        l_lst[i][j] = int(l_lst[i][j])

temp_cnt = 0
cnt = 0
for i in range(1, n+1):
    for j in range(0, len(l_lst)):
        if l_lst[j][0] <= i and i <= l_lst[j][1]:
            temp_cnt += 1
        if temp_cnt == len(l_lst):
            cnt += 1
            temp_cnt = 0

print(cnt)

n, m = map(int, input().split())
l_lst = list()
for i in range(m):
    l_lst.append(input().split())

for i in range(0, len(l_lst)):
    for j in range(0, len(l_lst[i])):
        l_lst[i][j] = int(l_lst[i][j])

max_lst = list()
min_lst = list()
for i in range(0, len(l_lst)):
    max_lst.append(l_lst[i][0])
    min_lst.append(l_lst[i][1])

max_int = max(max_lst)
min_int = min(min_lst)

cnt = 0
for i in range(1, n+1):
    if max_int <= i and i <= min_int:
        cnt += 1

print(cnt)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
from sys import stdin

N, G = map(int, stdin.readline().split())
dic = {key: 0 for key in range(1, N+1)}
for i in range(G):
  l, r = map(int, stdin.readline().split())
  for j in range(l, r+1):
    dic[j] = -1
  
ans = 0
for key in dic:
  if dic[key] == 0:
    ans += 1
    
print(ans)

from sys import stdin, exit

N, G = map(int, stdin.readline().split())
left, right = 1, N
for i in range(G):
    l, r = map(int, stdin.readline().split())
    if l > left:
        left = l
    if r < right:
        right = r
    if right < left:
        print(0)
        exit()

print(right - left + 1)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M = map(int, input().split())

L=[0]*M
R=[0]*M
for i in range(M):
  L[i], R[i] = map(int, input().split())

keys = []

for i in range(M):
  keys.append(set(range(L[i],R[i]+1)))
  
common = set(range(1, N+1))
for i in range(M-1):
  common = common & keys[i]
    
print(len(common))

N,M = map(int, input().split())

L=[0]*M
R=[0]*M
for i in range(M):
  L[i], R[i] = map(int, input().split())
    
print(max(min(R)-max(L)+1,0))

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input().split())
a=list(map(int,input().split()))
s=[]
l= 0
r = n
for i in range(m):
    ln,rn=map(int,input().split())
    if ln>l:
        l=ln
    if rn<r:
        r=rn
print(rn-ln+1)

n,m=map(int,input().split())

s=[]
l= 0
r = n
for i in range(m):
    ln,rn=map(int,input().split())
    if ln>l:
        l=ln
    if rn<r:
        r=rn
if r-l+1>0:
    print(r-l+1)
else:
    print(0)


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
_, m = map(int, input().split())

mi, mx = map(int, input().split())
for i in range(m-1):
    l, r = map(int, input().split())
    if mi < l <= mx:
        mi = l
    if mi <= r < mx:
        mx = r
    if mx < l or r < mi:
        flag = True
        break

if flag:
    print(0)
else:
    print(mx - mi + 1)

_, m = map(int, input().split())

mi, mx = map(int, input().split())
flag = False
for i in range(m-1):
    l, r = map(int, input().split())
    if mi < l <= mx:
        mi = l
    if mi <= r < mx:
        mx = r
    if mx < l or r < mi:
        flag = True
        break

if flag:
    print(0)
else:
    print(mx - mi + 1)


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
L1, R1 = map(int, input().split())
flag = 0
def find_key(L1,R1,L2,R2):
  if R1 < L2 or R2 < L1:
    print(0)
    flag = 1
    break
  elif:
    a = [R1,L1,R2,L2]
    a.sort()
    return(a[1],a[2])
for i in range(M - 1):
  L,R = map(int, input().split())
  L1,R1 = find_key(L1,R1,L,R)
if flag == 1:
  print(L1,R1)

N, M = map(int, input().split())
L1, R1 = map(int, input().split())
flag = 0
def find_key(L1,R1,L2,R2):
  if R1 < L2 or R2 < L1:
    return(False)
  else:
    a = [R1,L1,R2,L2]
    a.sort()
    return(a[1],a[2])

for i in range(M - 1):
  L,R = map(int, input().split())
  if find_key(L1,R1,L,R) != False:
    L1,R1 = find_key(L1,R1,L,R)
  else:
    flag = 1
    print(0)
    break
if flag = 0:
  print(R1-L1+1)

n,m=map(int,input().split())
ml=0
mr=100000
for i in range(m):
  l,r=map(int,input().split())
  ml=max(ml,l)
  mr=min(mr,r)
  if ml>mr:
    break
if ml<=mr:
  print(mr-ml+1)
else:
  print(0)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())

allL = 1
allR = N
for L, R in map(int, input().split()) in range(M):
  allL = max(allL, L)
  allR = min(allR, R)

print(max(allR - allL + 1, 0))


N, M = map(int, input().split())

allL = 1
allR = N
for L, R in (map(int, input().split()) for _ in range(M)):
  allL = max(allL, L)
  allR = min(allR, R)

print(max(allR - allL + 1, 0))


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import sys
import numpy as np
N,M= (int(i) for i in input().split(" "))  

LR= np.array([[int(i) for i in input().split()] for i in range(M)]) 

L=LR[-1,0]
R=LR[0,1]

print(int(abs(L-R+1)))

import sys
import numpy as np
N,M= (int(i) for i in input().split(" "))  

LR= np.array([[int(i) for i in input().split()] for i in range(M)]) 

L=np.max(LR[-1,:])
R=np.min(LR[0,:])


el=np.sum(np.logical_and(LR>L,R>LR))


print(int(abs(R-L)+1))

import sys
import numpy as np
N,M= (int(i) for i in input().split(" "))  

LR= np.array([[int(i) for i in input().split()] for i in range(M)]) 

L=np.max(LR[:,0])
R=np.min(LR[:,1])


el=np.sum(np.logical_and(LR>L,R>LR))

if L>R:
    print(0)
else:
    
    print(int((R-L)+1))

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
l_lst, r_lst = [], []
for i in range(m):
  l,r = map(int, input().split())
  l_lst.append(l)
  r_lst.append(r)
res = min(r_lst)-max(l_lst)+1
if res > 0:
  print(res)
else:
  print(0)

n,m = map(int, input().split())
l_lst, r_lst = [], []
for i in range(m):
  l,r = map(int, input().split())
  l_lst.append(l)
  r_lst.append(r)
res = min(r_lst)-max(l_lst)+1
if res > 0:
  print(res)
else:
  print(0)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import numpy as np

N, M = [int(i) for i in input().split()]

LR = np.ones([M,2])

for i in range(M):
    LR[i][0],LR[i][1] = [int(i) for i in input().split()]
    
max_L = max(LR[:,0])
min_R = min(LR[:,1])
if max_L < min_R:
    ans = int(min_R - max_L)
else:
    ans =0
    
print(ans)


import numpy as np

N, M = [int(i) for i in input().split()]

LR = np.ones([M,2])

for i in range(M):
    LR[i][0],LR[i][1] = [int(i) for i in input().split()]
    
max_L = max(LR[:,0])
min_R = min(LR[:,1])
if max_L <= min_R:
    ans = int(min_R - max_L+1)
else:
    ans =0
    
print(ans)


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
#ABC 127 C Prison
N,M= map(int,input().split())
MIN=None
MAX=None
for i in range(M):
    L,R= map(int,input().split())
    if MIN is None:
        MIN=L
        MAX=R
    elif MIN <L:
        MIN=L
    elif MAX > R:
        MAX =R
    print()
print(MAX-MIN+1)

#ABC 127 C Prison
N,M= map(int,input().split())
MIN=0
MAX=N
for i in range(M):
    L,R= map(int,input().split())
    MAX=min(MAX,R)
    MIN=max(MIN,L)
ans =MAX-MIN+1
print(max(0,ans))

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())

for i in range(M):
  L, R = map(int, input().split())
  pass_card = [i for i in range(L, R+1)]
  if  i == 0:
    ans = pass_card
  elif i > 0:
    ans = list(set(pass_card[i - 1]) & set(pass_card[i]))

print(len(ans))

N, M = map(int, input().split())

L_list = []
R_list = []
for i in range(M):
  L, R = map(int, input().split())
  L_list.append(L)
  R_list.append(R)

L = max(L_list)
R = min(R_list)

if R < L:
  print(0)
else:
  print(R - L + 1)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
10 3
3 6
5 7
6 9

#C
n, m = map(int, input().split())
l = []
r = []
for _ in range(m):
    tmp=list(map(int,input().split()))
    l.append(tmp[0])
    r.append(tmp[1])
lmax = max(l)
rmin = min(r)
# print(lmax,rmin)
if rmin >= lmax:
    print(rmin -lmax + 1)
else:
    print(0)


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import numpy as np
n,m=map(int,input().split())
post_b = 0
post_c = n
for i in range(m):
    b,c=map(int,input().split())
    if post_b < b:
        post_b = b
    if post_c > c:
        post_c = c

print(c-b+1)


import numpy as np
n,m=map(int,input().split())
post_b = 0
post_c = n
for i in range(m):
    b,c=map(int,input().split())
    if post_b < b:
        post_b = b
    if post_c > c:
        post_c = c
    print(post_b)
    print(post_c)

if (post_c - post_b + 1)<0:
    print("0")
else:
    print(c-b+1)


import numpy as np
n,m=map(int,input().split())
post_b = 0
post_c = n
for i in range(m):
    b,c=map(int,input().split())
    if post_b < b:
        post_b = b
    if post_c > c:
        post_c = c

if (post_c - post_b + 1)<0:
    print("0")
else:
    print(post_c - post_b + 1)


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split(' '))
L_list=[]
R_list=[]

for i in range(M):
    l,r = map(int, input().split(' '))
    L_list.append(l)
    R_list.append(r)


all_list=[]
num_list = range(1,len(L_list))


cnt = 0
all_uniq = range(L_list[0],R_list[0]+1)
print(all_uniq)
for i in range(1,M):
    tmp_ran = range(L_list[i],R_list[i]+1)
    all_uniq = set(all_uniq) & set(tmp_ran)

all_uniq = list(all_uniq)

for i in all_uniq:
    if(i<=N):
        cnt+=1
print(cnt)

N, M = map(int, input().split(' '))
L_list=[]
R_list=[]

for i in range(M):
    l,r = map(int, input().split(' '))
    L_list.append(l)
    R_list.append(r)

L_list.sort(reverse=True)
R_list.sort()
MAX = L_list[0]
MIN = R_list[0]
cnt=0
for i in range(1,N+1):
    if(i<=MIN and i>=MAX):
        cnt+=1
print(cnt)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
Ls = []
Rs = []
for _ in range(M):
    L, R = map(int, input().split())
    Ls.append(L)
    Rs.append(R+1)
L_max = max(Ls)
R_min = min(Rs)
print(max(R_min - L_max, 0)

N, M = map(int, input().split())
Ls = []
Rs = []
for _ in range(M):
    L, R = map(int, input().split())
    Ls.append(L)
    Rs.append(R+1)
L_max = max(Ls)
R_min = min(Rs)
print(max(R_min - L_max, 0))

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, k = list(map(int, input().split()))
min_list = []
max_list = []
for i in range(k):
    j, l = list(map(int, input().split())):
    min_list.append(j)
    max_list.append(l)


print(max(0, min(max_list) - max(min_list) + 1))

n, k = list(map(int, input().split()))
min_list = []
max_list = []
for i in range(k):
    j, l = list(map(int, input().split()))
    min_list.append(j)
    max_list.append(l)


print(max(0, min(max_list) - max(min_list) + 1))

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N = int(input())
A = []
B = []
for _ in range(N):
    a, b = map(int, input().split())
    A.append(a)
    B.append(b)
ans = min(B) - max(A) + 1

if ans < 1:
    print(0)
else:
    print(ans)

N, M = map(int, input().split())
A = []
B = []
for _ in range(M):
    a, b = map(int, input().split())
    A.append(a)
    B.append(b)
ans = min(B) - max(A) + 1

if ans < 1:
    print(0)
else:
    print(ans)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
a = list(map(int,input().split()))
for i in range(m):
    b,c = map(int,input().split())
    a.extend([c] * b)
a.sort(reverse=True)
print(sum(a[:n]))

n,m = map(int,input().split())
L = []
R = []
for i in range(m):
    l,r = map(int,input().split())
    L.append(l)
    R.append(r)
ans = 0
L = max(L)
R = min(R)
for i in range(1,n+1):
    if L <= i and R >= i:
        ans += 1
print(ans)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):

n, m = map(int, input().split())
L = [0] * m
R = [0] * def funcname(self, parameter_list):
    pass
for i in range(m):
    L[i], R[i] = map(int, input().split())
print(min(R) - max(L) + 1)


n, m = map(int, input().split())
L = [0] * m
R = [0] * m
for i in range(m):
    L[i], R[i] = map(int, input().split())
print(min(R) - max(L) + 1 if min(R) >= max(L else 0))


n, m = map(int, input().split())
L = [0] * m
R = [0] * m
for i in range(m):
    L[i], R[i] = map(int, input().split())
print(min(R) - max(L) + 1 if min(R) >= max(L) else 0)

Verdicts: Runtime Error

Runtime Error

Accepted