TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M = map(int,input().split())
X = []
for i in range(M):
  L,R = map(int,input().split())
  for j in range (R-L+1):
    A = L + j
    X.append(A)
X_duplicate = [x for x in set(X) if X.count(x) > 1]
L=[str(a) for a in X_duplicate]
L=" ".join(L)
print(L)

N,M = map(int,input().split())
L= 0
R = 10 ** 5
for i in range(M):
  Lm,Rm = map(int,input().split())
  L = max(L,Lm)
  R = min(R,Rm)
if R - L < 0:
  print(0)
else:
  print(R - L + 1)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = [int(i) for i in input().split()]
L = 1
R = 100000
for _ in range(M):
    l, r = [int(i) for i in input().split()]
    L = max(L, l)
    R = min(R, r)
if L <= R:
    print(0)
else:
    print(R-L+1)

N, M = [int(i) for i in input().split()]
L = 1
R = 100000
for _ in range(M):
    l, r = [int(i) for i in input().split()]
    L = max(L, l)
    R = min(R, r)
if L > R:
    print(0)
else:
    print(R-L+1)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
l_max = -float("inf")
r_min = float("inf")

for i in range(M):
    l, r = map(int, input().split())
    if l > l_max:
        l_max = l
    if r < r_min:
        r_min = r
if r_min>N:
    r_min = N
len(range(l_max, r_min+1))

N, M = map(int, input().split())
l_max = -float("inf")
r_min = float("inf")

for i in range(M):
    l, r = map(int, input().split())
    if l > l_max:
        l_max = l
    if r < r_min:
        r_min = r
if r_min>N:
    r_min = N
print(len(range(l_max, r_min+1)))

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
# -*- coding: utf-8 -*-
import sys

s = (input().split(' '))

n,m = [int(i) for i in s]

l_list = []
r_list = []

for i in range(m):
    s = (input().split(' '))
    l,r = [int(i) for i in s]
    l_list.append(l)
    r_list.append(r)

range = (max(l_list), min(r_list))

print(min(0, range[1] - range[0] + 1))

# -*- coding: utf-8 -*-
import sys

s = (input().split(' '))

n,m = [int(i) for i in s]

l_list = []
r_list = []

for i in range(m):
    s = (input().split(' '))
    l,r = [int(i) for i in s]
    l_list.append(l)
    r_list.append(r)

range = (max(l_list), min(r_list))

if range[0] > range[1]:
    print(0)
else:
    print(range[1] - range[0] + 1))

# -*- coding: utf-8 -*-
import sys

s = (input().split(' '))

n,m = [int(i) for i in s]

l_list = []
r_list = []

for i in range(m):
    s = (input().split(' '))
    l,r = [int(i) for i in s]
    l_list.append(l)
    r_list.append(r)

range = (max(l_list), min(r_list))

if range[0] > range[1]:
    print(0)
else:
    print(range[1] - range[0] + 1)

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
#
import sys
import math
import numpy as np
import itertools



n, m = (int(i) for i in input().split())  



lr = [[int(i) for i in input().split()] for i in range(m)] 

l=1
r=n
for i in range(m):
    l=max(l,lr[i][0])
    r=min(r,lr[i][1])

print(l,r)

a=r-l+1
if a < 0:
    a=0
print(a)



#
import sys
import math
import numpy as np
import itertools



n, m = (int(i) for i in input().split())  



lr = [[int(i) for i in input().split()] for i in range(m)] 

l=1
r=n
for i in range(m):
    l=max(l,lr[i][0])
    r=min(r,lr[i][1])

#print(l,r)

a=r-l+1
if a < 0:
    a=0
print(a)



Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input().split())
l=1
r=m
for _ in range(m):
  l2,r2=map(int,input().split())
  l=max(l,l2)
  r=min(r,r2)
print(r-l+1)


n,m=map(int,input().split())
l=1
r=10**5
for _ in range(m):
  l2,r2=map(int,input().split())
  l=max(l,l2)
  r=min(r,r2)
print(max(r-l+1,0))


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())

ans=set()
l, r = map(int, input().split())
for j in range(l,r+1):
    ans.add(j)

for i in range(m-1):
  l, r = map(int, input().split())
  temp=set()
  lm=min(list(ans))
  rm=min(list(ans))
  for j in range(min(l,lm), min(r,rm)+1):
    temp.add(j)
  ans=temp & ans

print(len(ans))

n, m = map(int, input().split())

ans=set()
lm=0
rm=n
for i in range(m):
  l, r = map(int, input().split())
  lm=max(l, lm)
  rm=min(r, rm)
if rm - lm < 0:
  print(0)
else:
  print(rm - lm + 1)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,k = map(int,input().split())
rc = [list(map(int,input().split())) for i in range(k)]

tmp = set(range(1,n+1))

for i in rc:
    tmp = tmp & set(range(i[0],i[1]))

print(len(tmp))


n,k = map(int,input().split())
rc = [list(map(int,input().split())) for i in range(k)]
transpose = [x for x in zip(*rc)]

ans = min(transpose[1]) - max(transpose[0])

if ans<0:
    print(0)
else:
    print(ans+1)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input().split())
l=[]
r=[]
for i in range(m):
  a,b=map(int,input().split())
  l.append(a)
  r.append(b)
lm=max(l)
rm=min(r)
if lm-rm<0:
  print(0)
else:
  print(lm-rm+1)


n,m=map(int,input().split())
L=100000
R=100000
for i in range(m):
  l=int(input())
  r=int(input())
  L=max(L,l)
  R=min(R,r)
print(max(0,R-L+1))

  


n,m=map(int,input().split())
L=100000
R=100000
for i in range(m):
  l=int(input())
  r=int(input())
  L=max(L,l)
  R=min(R,r)
print(max(0,R-L+1))

  


n,m=map(int,input().split())
lst=[]
for i in range(m):
  l=int(input())
  r=int(input())
  for j in range(l,r+1):
    lst.append(j)
print(len(set(lst)))


n,m=map(int,input().split())
lst=[]
L=100000
R=100000
for i in range(m):
  l=int(input())
  r=int(input())
  L=max(L,l)
  R=min(R,r)
print(max(0,R-L+1))

  


n,m=map(int,input().split())
lst=[]
for i in range(n):
  l=int(input())
  r=int(input())
  for j in range(l,r+1):
    lst.append(j)
print(len(set(lst)))


n,m=map(int,input().split())
L=100000
R=100000
for i in range(m):
  l,r=map(int,input().split())
  L=max(L,l)
  R=min(R,r)
print(max(0,R-L+1))

  


n,m=map(int,input().split())
L=0
R=100001
for i in range(m):
  l,r=map(int,input().split())
  L=max(L,l)
  R=min(R,r)
print(max(0,R-L+1))

  


Verdicts: Wrong Answer

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int, input().split())

l = []
r = []

for i in range(M):
  ln, rn = map(int, input().split())
  l.append(ln)
  r.append(rn)
  
lmax = max(l)
rmin = min(r)

ans = rmin - lmax + 1

print(ans)


n,m = map(int, input().split())

l, r = []

for i in range(M):
  ln, rn = map(int, input().split())
  l.append(ln)
  r.append(rn)
  
lmax = max(l)
rmin = min(r)

ans = rmin - lmax + 1

print(ans)

n, m = map(int, input().split())

l = []
r = []

for i in range(m):
  ln, rn = map(int, input().split())
  l.append(ln)
  r.append(rn)
  
lmax = max(l)
rmin = min(r)


ans = rmin - lmax + 1
if (ans < 0):
  ans = 0

print(ans)


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
L_list = []
R_list = []

for i in range(M):
    l, r = map(int, input().split())
    L = max(L, l)
    R = min(R, r)

print(L - R + 1)

N, M = map(int, input().split())
L = 0
R = N
for i in range(M):
    l, r = map(int, input().split())
    L = max(L, l)
    R = min(R, r)

print(L - R + 1)

N, M = map(int, input().split())
L = 0
R = N
for i in range(M):
    l, r = map(int, input().split())
    L = max(L, l)
    R = min(R, r)

print(max(0, L - R + 1))

N, M = map(int, input().split())

l_max = 0
r_min = N
for i in range(M):
    l, r = map(int, input().split())
    if l > l_max:
        l_max = l
    if r < r_min:
        r_min = r

print(max(0, r_min - l_max + 1))

Verdicts: Runtime Error

Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
L = [0] * M
R = [0] * M
L, R = map(int, input().split())
ans = set(list(range(L, R+1)))
for i in range(M-1):
  L, R = map(int, input().split())
  ans = ans & set(list(range(L, R+1)))
  if len(ans) == 0:
    print(0)
print(len(ansN, M = map(int, input().split())
L = [0] * M
R = [0] * M
L, R = map(int, input().split())
for i in range(M-1):
  l, r = map(int, input().split())
print(R-l+1)
  


N,M = map(int,input().split())
L = []
R = []
for i in range(M):
    l,r = map(int,input().split())
    L.append(l)
    R.append(r)
ans = list(range(max(L),min(R)+1))
print(len(ans))


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
from sys import stdin

n, m = (int(x) for x in stdin.readline().rstrip().split())
lr = [stdin.readline().rstrip().split() for _ in range(m)]
l = max([i[0] for i in lr])
r = min([i[1] for i in lr])

if l <= r:
    print(r-l+1)
else:
    print(0)


from sys import stdin

n, m = (int(x) for x in stdin.readline().rstrip().split())
lr = [stdin.readline().rstrip().split() for _ in range(m)]
l = max([int(i[0]) for i in lr])
r = min([int(i[1]) for i in lr])

if l <= r:
    print(r-l+1)
else:
    print(0)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())

import numpy as np

rets = np.array([0] * n)
lmax = n
rmin = 0
for _ in range(m):
  l, r = map(int, input().split())
  lmax = max(l, lmax)
  rmin = min(r, rmin)
print(rmin - lmax + 1 if rmin - lmax + 1 > 0 else 0)




n, m = map(int, input().split())

import numpy as np

rets = np.array([0] * n)
lmax = 1
rmin = n
for _ in range(m):
  l, r = map(int, input().split())
  lmax = max(l, lmax)
  rmin = min(r, rmin)
print(rmin - lmax + 1 if rmin - lmax + 1 > 0 else 0)




Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
from sys import stdin
N, M = [int(x) for x in stdin.readline().rstrip().split()]
l = [[int(x) for x in stdin.readline().rstrip().split()] for _ in range(M)]

sMax = 0
eMin = 0
for s, e in l:
  if sMax < s or sMax == 0:
    sMax = s
  if eMin > e or eMin == 0:
    eMin = e

print(len(range(eMin, sMax))+1)

from sys import stdin
N, M = [int(x) for x in stdin.readline().rstrip().split()]
l = [[int(x) for x in stdin.readline().rstrip().split()] for _ in range(M)]

sMax = 0
eMin = 0
for s, e in l:
  if sMax < s:
    sMax = s
  if eMin > e or eMin == 0:
    eMin = e

print(sMax - eMin +1)

N, M = map(int, input().split())

lmax = 1
rmin = N
for _ in range(M):
  l, r = map(int, input().split())
  lmax = max(lmax, l)
  rmin = min(rmin, r)
  
print(rmin - lmax + 1 if rmin - lmax + 1 > 0 else 0)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):

N, M = map(int,input().split())

from itertools import accumulate
imos = [0]*(N+1)
for i in range(M):
    L,R = map(int,input().split())
    imos[L] += 1
    imos[R+1] -= 1
acc = list(accumulate(imos))
print(sum([1 for a in acc if a == M]))



N, M = map(int,input().split())
from itertools import accumulate
imos = [0]*(N+2)
for i in range(M):
    L,R = map(int,input().split())
    imos[L] += 1
    imos[R+1] -= 1
acc = list(accumulate(imos))
print(sum([1 for a in acc if a == M]))

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input().split())
L,R=10**18,0
for i in range(m):
  l,r=map(int,input().split())
  L=max(L,l)
  R=min(R,r)
if R<L:
  print(0)
else:
  print(R-L+1)

n,m=map(int,input().split())
L,R=0,10**18
for i in range(m):
  l,r=map(int,input().split())
  L=max(L,l)
  R=min(R,r)
if R<L:
  print(0)
else:
  print(R-L+1)


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M=map(int,input().split())
LR=[list(map(int,input().split())) for _ in range(M)]

l=1
r=N

for i in LR:
    print(i)
    if i[0]>l:
        l=i[0]
    if i[1]<r:
        r=i[1]

if r>=l:
    print(r-l+1)
else:
    print(0)

N,M=map(int,input().split())
LR=[list(map(int,input().split())) for _ in range(M)]

l=1
r=N

for i in LR:
    #print(i)
    if i[0]>l:
        l=i[0]
    if i[1]<r:
        r=i[1]

if r>=l:
    print(r-l+1)
else:
    print(0)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
isstr=input()
n,m = [int(i) for i in isstr.split(' ')]
gate=[0]*m
for i in range(m):
    a,b=[int(i) for i in input().split(' ')]
    gate[i]=set([j for j in range(a,b+1)])
result=reduce(lambda x,y:x&y, gate)
count=0
for re in result:
  if re <=n:
    count+=1
print(count)
  	

isstr=input()
n,m = [int(i) for i in isstr.split(' ')]
mini=-1
maxi=1000000000000000
for i in range(m):
    a,b=[int(i) for i in input().split(' ')]
	tmp_mini=max(mini,a)
    tmp_maxi=min(maxi,b)
    if(tmp_mini<tmp_maxi):
      mini=tmp_mini
      maxi=tmp_maxi
    elif(tmp_mini==tmp_maxi):
      if tmp_mini<=n:
        print(1)
        break
      else:
        print(0)
        break
    else:
      print(0)
      break
if(mini<maxi):      
  if n>=maxi:
    print(maxi-mini+1)
  elif maxi>n>=mini:
    print(n-mini+1)
  else:
    print(0)

  	

from functools import reduce
isstr=input()
n,m = [int(i) for i in isstr.split(' ')]
mini=-1
maxi=1000000000000000
for i in range(m):
    a,b=[int(i) for i in input().split(' ')]
	tmp_mini=max(mini,a)
    tmp_maxi=min(maxi,b)
    if(tmp_mini<tmp_maxi):
      mini=tmp_mini
      maxi=tmp_maxi
    elif(tmp_mini==tmp_maxi):
      if tmp_mini<=n:
        print(1)
        break
      else:
        print(0)
        break
    else:
      print(0)
      break
      
if n>=maxi:
  print(maxi-mini+1)
elif maxi>n>=mini:
  print(n-mini+1)
else:
  print(0)

  	

isstr=input()
n,m = [int(i) for i in isstr.split(' ')]
l=[0]*m
r=[0]*m
for i in range(m):
    l[i],r[i]=[int(i) for i in input().split(' ')]
count=0
for i in range(n):
  if i>=min(l) and i<=max(r):
    count+=1
print(count)
  	

isstr=input()
n,m = [int(i) for i in isstr.split(' ')]
l=[0]*m
r=[0]*m
for i in range(m):
    l[i],r[i]=[int(i) for i in input().split(' ')]
result=min(r)-max(l)+1
result=result if result>0 else 0
print(result)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):


v = [int(d) for d in input().split()]

LM = []
for d in range(v[1]):
   LM.append([int(d) for d in input().split()])

L = [d[0] for d in LM]
M = [d[1] for d in LM]
L.sort()
M.sort()
if M[0] <= L[-1]:
    if M[0] <= v[0]:
        print(M[0]-L[-1]+1)
        exit()
    else:
        print(v[0]-L[-1]+1)
        exit()
else:
    print('0')



v = [int(d) for d in input().split()]

LM = []
for d in range(v[1]):
   LM.append([int(d) for d in input().split()])

L = [d[0] for d in LM]
M = [d[1] for d in LM]
L.sort()
M.sort()
if L[-1] <= M[0]:
    if M[0] <= v[0]:
        print(M[0]-L[-1]+1)
        exit()
    else:
        print(v[0]-L[-1]+1)
        exit()
else:
    print('0')

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
l, r = map(int, input().split())
for i in range(m-1):
    l, _ = map(int, input().split()) 
print(max(l-r+1, 0))


n, m = map(int, input().split())
l, r = map(int, input().split())
for i in range(m-1):
    l_c, r_c = map(int, input().split()) 
    l = max(l, l_c)
    r = min(r, r_c)
print(max(r-l+1, 0))

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
l = []
r = []
for _ in range(M):
  s, t = map(int, input().split())
  l.append(s)
  r.append(t)
  
lm = max(l)
rm = min(r)
print(max[rm - lm + 1, 0])

N, M = map(int, input().split())
l = []
r = []
for _ in range(M):
  s, t = map(int, input().split())
  l.append(s)
  r.append(t)
  
lm = max(l)
rm = min(r)
print(max([rm - lm + 1, 0]))

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M=map(int,input().split())
L=[]
R=[]
for i in range(M):
    l,r=map(int,input().split())
    L.append(l)
    R.append(r)
max_l=max(L)
min_r=min(R)
if max_l-min_r>=0:
    print(max_l-min_r+1)
else:
    print(0)

N,M=map(int,input().split())
L=[]
R=[]
for i in range(M):
    l,r=map(int,input().split())
    L.append(l)
    R.append(r)
max_l=max(L)
min_r=min(R)
if min_r-max_l>=0:
    print(min_r-max_l+1)
else:
    print(0)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
ls = [[int(x) for x in input().split()]for i in range(m)]
lst = []
ans = 0
ans_2 = 0
for i in range(m):
    a,b = ls[i][0],ls[i][1]
    for j in range(n):
        if a<=j<=b:
            lst.append(j)
        if lst(j) == m:
          break
for k in range(n):
    if (lst.count(k)) == m:
        ans_2 += 1
print(ans_2)

,m = map(int,input().split())
ls = [[int(x) for x in input().split()]for i in range(m)]
lst = []
ans = 0
ans_2 = 0
for i in range(m):
    a,b = ls[i][0],ls[i][1]
    for j in range(n):
        if a<=j<=b:
          lst.append(j)
for _ in range(n):
    if lst.count(_) == m:
        ans += 1
print(ans)

n,m = map(int,input().split())
Low = []
Right = []
for i in range(m):
  l,r = map(int,input().split())
  Low.append(l)
  Right.append(r)
if min(Right) < max(Low):
  print(0)
else:
  print(min(Right)- max(Low) + 1)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M=map(int,input().split())
L=[0]*M
R=[0]*M
for i range(M):
  L[i],R[i]=map(int,input().split())

def prison(N,M,L,R):
    count=0
    for n in range(N):
        num_of_truth=0
        for l,r in zip(L,R):
            if l<=(n+1)<=r:
                num_of_truth+=1
        if num_of_truth==M:
            count+=1
    return count

print(prison(N,M,L,R))

N,M=map(int,input().split())
L=[0]*M
R=[0]*M
for i range(M):
  L[i],R[i]=map(int,input().split())

def prison(N,M,L,R):
  count=0
  for n in range(N):
    num_of_truth=0
    for l,r in zip(L,R):
      if l<=(n+1)<=r:
        num_of_truth+=1
    if num_of_truth==M:
      count+=1
  return count
 
print(prison(N,M,L,R))


N,M=map(int,input().split())

L=[0]*M
R=[0]*M

for i in range(M):
  L[i],R[i]=map(int,input().split())

def prison(N,M,L,R):
  max_val=min(R)
  min_val=max(L)
  num=max_val-min_val+1
  if num<=0:
    num=0
  return(num)

print(prison(N,M,L,R))

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
i = input().split(" ")

N = int(i[0])
M = int(i[1])

mi = 0
ma = N

for j in range(M):
	i = input().split(" ")
	l = int(i[0])
	r = int(i[1])
	if l > mi:
		mi = l
	if r < ma:
		ma = r
	print(mi, ma)

print(ma - mi + 1)


i = input().split(" ")

N = int(i[0])
M = int(i[1])

mi = 0
ma = N

for j in range(M):
	i = input().split(" ")
	l = int(i[0])
	r = int(i[1])
	if l >= mi:
		mi = l
	if r <= ma:
		ma = r
	print(mi, ma)

r = ma - mi + 1

if r > 0:
	print(r)
else:
	print(0)


i = input().split(" ")

N = int(i[0])
M = int(i[1])

mi = 0
ma = N

for j in range(M):
	i = input().split(" ")
	l = int(i[0])
	r = int(i[1])
	if l >= mi:
		mi = l
	if r <= ma:
		ma = r

r = ma - mi + 1

if r > 0:
	print(r)
else:
	print(0)


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M = map(int,input().split())
min = 0
max = N

for _ in range(M):
    L_i,R_i = map(int,input().split())
    if L_i > min:
        min = L_i
    if R_i < max:
        max = R_i

if min > max:
    print("0")
else:
    print(max - max + 1)



N,M = map(int,input().split())
min = 0
max = N

for _ in range(M):
    L_i,R_i = map(int,input().split())
    if L_i > min:
        min = L_i
    if R_i < max:
        max = R_i

if min > max:
    print(0)
else:
    print(max - max + 1)



N,M = map(int,input().split())
min = 0
max = N

for _ in range(M):
    L_i,R_i = map(int,input().split())
    if L_i > min:
        min = L_i
    if R_i < max:
        max = R_i

if min > max:
    print(0)
else:
    print(max - min + 1)



Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
ls = [i for i in range(m)]
rs = [i for i in range(m)]
cnt = 0
for _ in range(m):
    ls[_],rs[_] = map(int,input().split())

maxl = max(ls)
minr = min(rs)

for nn in range(1,n+1):
    if maxl <= nn or minr >= nn:
        cnt += 1

print(cnt)

n,m = map(int,input().split())
ls = [i for i in range(m)]
rs = [i for i in range(m)]
cnt = 0
for _ in range(m):
    ls[_],rs[_] = map(int,input().split())

maxl = max(ls)
minr = min(rs)

for nn in range(1,n+1):
    if maxl <= nn and minr >= nn:
        cnt += 1
print(cnt)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
L = []
R = []

for _ in range(M):
    l, r = map(int, input().split())
    L.append(l)
    R.append(r)
print(max(L)-min(R)+1)

N, M = map(int, input().split())
L = []
R = []

for _ in range(M):
    l, r = map(int, input().split())
    L.append(l)
    R.append(r)
ans = min(R)-max(L)+1
print(ans if ans>0 else 0)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M = map(int,input().split())
L = []
R = []
LR = [list(map(int,input().split())) for _ in range(M)]
for i in range(M):
    L.append(LR[i][0])
countL = 0
countL = max(L)
for j in range(M):
    R.append(LR[j][1])
countR = 0
countR = min(R)
if countR >= countL:
    print(0)
else:
    print(countR-countL+1)
    


    



N,M = map(int,input().split())
L = []
R = []
LR = [list(map(int,input().split())) for _ in range(M)]
for i in range(M):
    L.append(LR[i][0])
countL = 0
countL = max(L)
for j in range(M):
    R.append(LR[j][1])
countR = 0
countR = min(R)
if countR - countL + 1 <= 0:
    print(0)
else:
    print(countR-countL+1)
    


    



Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input().split())
a=0
b=float('inf')
for i in range(m):
      c,d=map(int,input().spilt())
      a=max(a,c)
      b=min(b,d)
print(max(0,b-a+1))


n,m=map(int,input().split())
ll=0
rr=n+1
for i in range(m):
    l,r=map(int,input().split())
    ll=max(ll,l)
    rr=min(rr,r)

if rr<ll:
    print(0)
else:
    print(rr-ll+1)


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
t = input().split()
n = int(t[0])
m = int(t[1])

low = 0
high = n
for i in range(0, m):
  tmp = input().split()
  if int(tmp[0]) > low:
    low = int(tmp[0])
  if int(tmp[1]) < high:
    high = int(tmp[1])

if high =< low:
  num = 0
else:
  num = high-low+1
print(num)

t = input().split()
n = int(t[0])
m = int(t[1])

low = 0
high = n
for i in range(0, m):
  tmp = input().split()
  if int(tmp[0]) > low:
    low = int(tmp[0])
  if int(tmp[1]) < high:
    high = int(tmp[1])

if (high-low)<0:
  num = 0
else:
  num = high-low+1
print(num)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M  = map(int, input().split())
x_min, x_max = [], []
for i in range(M):
  L, R = map(int, input().split())
  x_min.append(L)
  x_max.append(R)
  
print(max(x_max) - min(x_min) + 1)

N, M  = map(int, input().split())
x_min, x_max = [], []
for i in range(M):
  L, R = map(int, input().split())
  x_min.append(L)
  x_max.append(R)
  
if min(x_max) - max(x_min) >= 0:
  print(min(x_max) - max(x_min) + 1)
else:
  print(0)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
#coding:utf-8
n, m = map(int, input().split())
l, r = 0, 10**6
for i in range(m):
    a, b = map(int, input().split())
    l = max(l, a)
    r = min(r, b)
print(r - l + 1 if r <= l else 0)

# coding: utf-8
N, M = map(int, input().split())
L, R = 0, 10**6
card = []
for i in range(M):
    l, r = map(int, input().split())
    L = max(L, l)
    R = min(R, r)
print(R - L + 1 if L <= R else 0)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
card, gate = map(int, input().split())
max_l = 0
min_r = 100000
for i in range(gate):
  l, r = map(int, input().split())
  max_l = max(max_l, l)
  min_r = min(min_r, r)
print(max_l, min_r)    
print(len(range(max_l, min_r+1)))

N, M = map(int, input().split())

L = []
R = []
for _ in range(M):
  l, r = map(int, input().split())
  L.append(l)
  R.append(r)
  
max_L   = max(L)
min_R = min(R)
print(len(range(max_L, min_R+1)))

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
l = []
for i in range(m):
    l, r = map(int, input().split())
    l.append(list(range(l, m + 1)))
c = [0] * n
for i in range(m):
    for j in range(n):
        if (j + 1) in l[i]:
            c[j] += 1
counr = 0
for i in c:
    if m == c[i]:
        count += 1
print(count)

n, m = map(int, input().split())
L = []
R = []
for i in range(m):
    l, r = map(int, input().split())
    L.append(l)
    R.append(r)
count = min(R) - max(L) + 1
if count <= 0:
    print(0)
else:
    print(count)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
L_ans = 1
R_ans = N

for _ in range(M):
    L, R = map(int, input().split())
    L_ans = max(L, L_ans) 
    R_ans = min(R, R_ans) 
    print(L_ans, R_ans)

    if L_ans > R_ans:
        print(0)
        exit()

print(R_ans - L_ans + 1)


N, M = map(int, input().split())
L_ans = 1
R_ans = N

for _ in range(M):
    L, R = map(int, input().split())
    L_ans = max(L, L_ans) 
    R_ans = min(R, R_ans) 

    if L_ans > R_ans:
        print(0)
        exit()

print(R_ans - L_ans + 1)


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input().split())
a=[list(map(int,input().split())) for _ in range(n)]
mi=1
ma=n
for i in range(n):
  mi=max(mi,a[i][0])
  ma=min(ma,a[i][1])

if mi>ma:
  print("0")
else:
  print(ma-mi+1)



n,m=map(int,input().split())
a=[list(map(int,input().split())) for _ in range(m)]
mi=1
ma=n
for i in range(n):
  mi=max(mi,a[i][0])
  ma=min(ma,a[i][1])

if mi>ma:
  print("0")
else:
  print(ma-mi+1)



n,m=map(int,input().split())
a=[list(map(int,input().split())) for _ in range(m)]
mi=1
ma=n
for i in range(m):
  mi=max(mi,a[i][0])
  ma=min(ma,a[i][1])

if mi>ma:
  print("0")
else:
  print(ma-mi+1)



Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
10 3
3 6
5 7
6 9

n, m = map(int,input().split())

lefts = [0] * m
rights = [0] * m

for i in range(m):
	l, m = map(int,input().split())
	lefts[i] = l
	rights[i] = r

lefts_max = max(lefts)
rithts_min = min(rights)

result = rights_min - lefts_max + 1

print(max(result,0))



n, m = map(int,input().split())

lefts = [0] * m
rights = [0] * m

for i in range(m):
	l, r = map(int,input().split())
	lefts[i] = l
	rights[i] = r

lefts_max = max(lefts)
rights_min = min(rights)

result = rights_min - lefts_max + 1

print(max(result,0))

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M = map(int,input().split())
LR = [[int(x) for x in input().split()] for _ in range(M)]
L = 1
R = N
for l,r in LR:
  L = max(L,l)
  R = max(R,r)
  
if L > R:
  print(0)
else:
  print(R-L+1)


N,M = map(int,input().split())
LR = [[int(x) for x in input().split()] for _ in range(M)]
L = 1
R = N
for l,r in LR:
  L = max(L,l)
  R = min(R,r)
  
if L > R:
  print(0)
else:
  print(R-L+1)


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
from itertools import accumulate

N, M = map(int, input().split(" "))
LR = [list(map(int, input().split(" "))) for _ in range(M)]

q = [0] * (N+1)
for l, r in LR:
    print(l, r)
    q[l-1] += 1
    q[r] -= 1



print(sum(M == m for m in list(accumulate(q))[:-1]))

from itertools import accumulate

N, M = map(int, input().split(" "))
LR = [list(map(int, input().split(" "))) for _ in range(M)]

q = [0] * (N+1)
for l, r in LR:
    # print(l, r)
    q[l-1] += 1
    q[r] -= 1



print(sum(M == m for m in list(accumulate(q))[:-1]))

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M = map(int, input().split())
ar = [0,N]
for m in range(M):
    l,r = map(int, input().split())
    if l>ar[0]:
        ar[0] = l
    if r<ar[1]:
        ar[1]=r
print(max([0,ar[1]-ar[0]+1])

N,M = map(int, input().split())
ar = [0,N]
for m in range(M):
    l,r = map(int, input().split())
    if l>ar[0]:
        ar[0] = l
    if r<ar[1]:
        ar[1]=r
print(max([0,ar[1]-ar[0]+1]))

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
number = input().split()
i = 1
card_list = []

for i in range(int(number[1])):
    card = input().split()
    LR = int(card[1]) - int(card[0]) + 1
    j = 0
    if number[1] == "1":
        print(number[0])
        break
    while LR > 0:
        card_list.append(int(card[0]) + j)
        j += 1
        LR -= 1
        print("teest")
    i += 1
    print("test")

card_lists = [x for x in set(card_list) if card_list.count(x) > int(number[1]) - 1]

if number[1] != "1":
    print(len(card_lists))

n,m = map(int,input().split())
key = []
for i in range(1,n+1):
    key.append(i)
    
ls = [0,100000]
for i in range(m):
    L,R = map(int,input().split())
    if L > ls[0]:
        ls[0] = L
    if R < ls[1]:
        ls[1] = R
    
ans = []    
for i in range(ls[0],ls[1]+1):
    ans.append(i)
    
print(len(set(ans)&set(key)))


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):

def input2():
	return map(int,input().split())

N,M=input2()
L,R=[],[]
for i in range(M):
	l,r=input2()
	L.append(l)
	R.append(r)

MIN=0
MAX=N

for j in range(M):
	if L[j]>MIN and :
		MIN=L[j]
	if R[j]<MAX:
		MAX=R[j]

if MAX<MIN:
	print(0)
else:
	print((MAX-MIN)+1)


def input2():
	return map(int,input().split())

N,M=input2()
L,R=[],[]
for i in range(M):
	l,r=input2()
	L.append(l)
	R.append(r)

MIN=0
MAX=N

for j in range(M):
	if L[j]>MIN:
		MIN=L[j]
	if R[j]<MAX:
		MAX=R[j]

if MAX<MIN:
	print(0)
else:
	print((MAX-MIN)+1)


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
L = []
R = []
lan = 0
ran = 0
ans = 0
for i in range(M):
    l, r = map(int, input().split())
    L.append(l)
    R.append(r)

print(R)
print(L)
i = 0
for i in range(M):
    for j in range(M):
        if L[i] >= L[j] and L[i] <= R[j]:
            lan += 1
        if R[i] >= L[j] and R[i] <= R[j]:
            ran += 1
    else:
        if lan == M:
            ans += 1
        if ran == M:
            ans += 1
        lan = 0
        ran = 0
else:
    print(ans)

N, M = map(int, input().split())
L = []
R = []
lan = 0
ran = 0
ans = 0
for i in range(M):
    l, r = map(int, input().split())
    L.append(l)
    R.append(r)

i = 0
for i in range(M):
    for j in range(M):
        if L[i] >= L[j] and L[i] <= R[j]:
            lan += 1
        else:
            lan = 0
            ran = 0
            break
        if R[i] >= L[j] and R[i] <= R[j]:
            ran += 1
        else:
            lan = 0
            ran = 0
            break
    else:
        if lan == M:
            ans += 1
        if ran == M:
            ans += 1
        lan = 0
        ran = 0
else:
    print(ans)


N, M = map(int, input().split())
L = []
R = []
for i in range(M):
    l, r = map(int, input().split())
    L.append(l)
    R.append(r)

if min(R) < max(L):
    print(0)
else:
    print(min(R) - max(L) + 1)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
from operator import itemgetter
              

N, M = map(int, input().split())
#A = input().split()
#A = list(map(int, A))
#print(A)
#A.sort()
#print(A)

cng = []
L_max=0
R_min=1000000000000
for i in range(M):
    L, R = map(int, input().split())
    if(L_max<=L):
        L_max=L
    if(R_min>=R):
        R_min=R
        
if(R_min-L_max==0):
    print(1)
else:
    print(R_min-L_max)

from operator import itemgetter
import sys

N, M = map(int, input().split())


cng = []
L_max=0
R_min=float('inf')
for i in range(M):
    L, R = map(int, input().split())
    if(L_max<=L):
        L_max=L
    if(R_min>=R):
        R_min=R
        

if(R_min-L_max<0):
    print(0)
else:
    print(R_min-L_max+1)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split(' '))

data = []
l = 1
r = 10**5
for m in range(M):
    li, ri = map(int, input().split(' '))
    if li > l:
      l = li
    if ri < r:
      r = ri

if l<= N <= r:
  cnt = (N - l) + 1
elif r >= N:
  cnt = (r - l) + 1
else N < l:
  cnt = 0
  

N, M = map(int, input().split(' '))
 
data = []
l = 1
r = 10**5
for m in range(M):
    li, ri = map(int, input().split(' '))
    if li > l:
      l = li
    if ri < r:
      r = ri
 
if l<= N <= r:
  cnt = (N - l) + 1
elif l > r:
  cnt = 0
elif r < N:
  cnt = (r - l) + 1
else:
  cnt = 0
 
print(cnt)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M = map(int,input().split())
L = []
R = []
for i in range(M):
  l,r = map(int,input().split())
  L.append(l)
  R.append(r)
print(min(R)-min(L)+1)

N,M = map(int,input().split())
a,b = map(int,input().split())
for i in range(M-1):
    c,d = map(int,input().split())
    a = max(a,c)
    b = min(b,d)
if b>=a:
	print(b-a+1)
else:
  print(0)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
# -*- coding: utf-8 -*-
n, m = map(int, input().split())

lst1 = [i for i in range(1, n + 1)]
print(lst1)

for i in range(m):
  l, r = map(int, input().split())
  lst = [l + j for j in range(r)]
  lst1 = lst if len(lst1) == 0 else list(set(lst1) & set(lst))
  print(lst)

print(len(lst1))


# -*- coding: utf-8 -*-
n, m = map(int, input().split())
max_value, min_value = -1, -1
for i in range(m):
  tmp_min_value, tmp_max_value = map(int, input().split())
  min_value = max([min_value, tmp_min_value]) if min_value >= 0 else tmp_min_value
  max_value = min([max_value, tmp_max_value]) if max_value >= 0 else tmp_max_value

min_value = min_value if min_value <= n else n
max_value = max_value if max_value <= n else n

ret = max_value - min_value + 1
if ret < 0:
  ret = 0
print(ret)


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
l_max=0
r_min=n 
for i in range(n):
  l,r = map(int,input().split())
  l_max = max(l_max,l)
  r_min = min(r_min,r)
print(r_min - l_max)

n,m = map(int,input().split())
l_max=1
r_min=10**5 
for i in range(m):
  l,r = map(int,input().split())
  l_max = max(l_max,l)
  r_min = min(r_min,r)
ans = r_min - l_max + 1
print(ans if ans >= 0 else 0 )

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
isstr=input()
n,m = [int(i) for i in isstr.split(' ')]
l=[0]*m
r=[0]*m
for i in range(m):
    l[i],r[i]=[int(i) for i in input().split(' ')]
a=[0]*n
for i in range(m):
    a[l[i]-1]=1
    a[l[i]]=1
    a[r[i]-1]=1
print(sum(a))

isstr=input()
n,m = [int(i) for i in isstr.split(' ')]
l=[0]*m
r=[0]*m
for i in range(m):
    l[i],r[i]=[int(i) for i in input().split(' ')]
a=[0]*n
for i in range(m):
    for j in range(l[i],r[i]+1):
        a[j+1]=1
print(sum(a))


isstr=input()
n,m = [int(i) for i in isstr.split(' ')]
l=[0]*m
r=[0]*m
for i in range(m):
    l[i],r[i]=[int(i)-1 for i in input().split(' ')]
a=[0]*n
for i in range(m):
    for j in range(l[i],r[i]+1):
        a[j]+=1
print(len([_ for i in a if i==m]))  

isstr=input()
n,m = [int(i) for i in isstr.split(' ')]
l=[0]*m
r=[0]*m
for i in range(m):
    l[i],r[i]=[int(i)-1 for i in input().split(' ')]
x=min(r)-max(l)+1
x=x if x>0 else 0
print(x)   

Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
c = []
d = []
n,m = map(int, input().split())
for i in range(m):
    a,b = map(int,input().split())
    c.append(a)
    d.append(b)
minl = max(c)   
maxr = min(d)
if min1>maxr:
    print(0)
else:
    print(maxr-minl+1)

a = []
b = []
n,m = map(int, input().split())
for i in range(m):
    a,b = map(int,input().split())
    a.append(a)
    b.append(b)
minl = max(a)   
maxr = min(b)
print(maxr-minl)

c = []
d = []
n,m = map(int, input().split())
for i in range(m):
    a,b = map(int,input().split())
    c.append(a)
    d.append(b)
minl = max(c)   
maxr = min(d)
if minl>maxr:
    print(0)
else:
    print(maxr-minl+1)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import sys
import os


def main():
    if os.getenv("LOCAL"):
        sys.stdin = open("input.txt", "r")

    N, M = list(map(int, sys.stdin.buffer.readline().split()))
    LR = [list(map(int, sys.stdin.buffer.readline().split())) for _ in range(M)]
    mi = 0
    mx = 10 ** 5 + 1

    for lr in LR:
        l = lr[0]
        r = lr[1]
        mi = max(mi, l)
        mx = min(mx, r)
        print(mi, mx)

    print(mx - mi + 1)


if __name__ == '__main__':
    main()


import sys
import os


def main():
    if os.getenv("LOCAL"):
        sys.stdin = open("input.txt", "r")

    N, M = list(map(int, sys.stdin.buffer.readline().split()))
    mi = 1
    mx = N

    for m in range(M):
        L, R = map(int, sys.stdin.buffer.readline().split())
        mi = max(mi, L)
        mx = min(mx, R)

    print(max(0, mx - mi + 1))


if __name__ == '__main__':
    main()


Verdicts: Wrong Answer

Accepted