TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
#ABC153B
h,n = map(int,input().split())
a = list(map(int,inout().split()))
print("Yes" if sum(a) >= h else "No")

#ABC153B
h,n = map(int,input().split())
a = list(map(int,input().split()))
print("Yes" if sum(a) >= h else "No")

Verdicts: Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
h, n=map(int, input().split())
a=list(map(int, input().split()))
dmg=0
for i in range(n):
  dmg+=a[i]
if dmg<=0:
  print("Yes")
else:
  print("No")

h, n=map(int, input().split())
a=list(map(int, input().split()))
dmg=0
for i in range(n):
  dmg+=a[i]
if dmg>=h:
  print("Yes")
else:
  print("No")

Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
import numpy as np
H,N=input().split()
H=int(H)
N=int(N)

A=list(map(int, input().split()))

count=0
for i in range(N):
  count+=A[i]

if count=>H:
  print("yes")
else:
  print("no")

# coding: utf-8
# Your code here!


h,a=map(int,input().split())
A=list(map(int,input().split()))
sum_A=sum(A)
if h>sum_A:
    print("No")

else:
    print("Yes")

Verdicts: Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H,N = map(int,input().split())
total_attack_damage = sum(list(map(int,input().split())))

result = H = total_attack_damage

if result <= 0:
	print('Yes')
else:
	print('No')

H,N = map(int,input().split())
total_attack_damage = sum(list(map(int,input().split())))

result = H - total_attack_damage
if result > 0:
	print("NO")
elif result <= 0:
	print("YES")

H,N = map(int,input().split())
total_attack_damage = sum(list(map(int,input().split())))

if H <= total_attack_damage:
	print('YES')
else:
	print('NO')

H,N = map(int,input().split())
total_attack_damage = sum(list(map(int,input().split())))

result = H - total_attack_damage
if result > 0:
	print("No")
elif result <= 0:
	print("Yes")

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
h,n = (int(i) for i in input().split())
a=input().split()
if sum(a)>=h:
  print('Yes')
else:
  print('No')

h,n = (int(i) for i in input().split())
a=[]
for i in input().split():
  a.append(int(i))
if sum(a)>=h:
  print('Yes')
else:
  print('No')

Verdicts: Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
h, n = map(int , input().split())
a = list(map(int, input().split()))
sum = 0
for i in range(n):
    sum += a[i]
print(sum)
if (sum >= h):
    print("Yes")
else:
    print("No")

h, n = map(int , input().split())
a = list(map(int, input().split()))
sum = 0
for i in range(n):
    sum += a[i]
print(sum)
if (h <= sum):
    print("Yes")
else:
    print("No")

h, n = map(int , input().split())
a = list(map(int, input().split()))
sum = 0
for i in range(n):
    sum += a[i]
if (h <= sum):
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H,N=[int(s) for s in input().split()]
ls=[int(s) for s in input().split()]
if H<sum(ls):
  print('No')
else:
  print('Yes')

H,N=[int(s) for s in input().split()]
ls=[int(s) for s in input().split()]
if H>sum(ls):
  print('No')
else:
  print('Yes')


Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
h, n = map(int, input().split())
a = list(map(int, input().split()))
ans = ""
if sum(a) >= h:
  ans = "Yes"
else:
  ans = "No"

h, n = map(int, input().split())
a = list(map(int, input().split()))
ans = ""
if sum(a) >= h:
  ans = "Yes"
else:
  ans = "No"
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
h,n = map(int,input().split())
a = list(map(int,input().split()))
p = sum(a)
print("Yes" if h < =p else "No")

h,n = map(int,input().split())
a = list(map(int,input().split()))
p = sum(a)
print("Yes" if h <= p else "No")

Verdicts: Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H, N = map(int, input().split())
A = sum(list(map(int, input().split())))

if H <= A:
    print("YES")
else:
    print("NO")

H, N = map(int, input().split())
A = [int(i) for i in input().split()]

if sum(A) >= H:
    print("YES")
else:
    print("NO")

H, N = map(int, input().split())
A = [int(i) for i in input().split()]

if sum(A) >= H:
    print("YES")
else:
    print("NO")

H, N = map(int, input().split())
A = sum(list(map(int, input().split())))

if H <= A:
    print("YES")
else:
    print("NO")

h, n = map(int, input().split())
s = sum(list(map(int, input().split())))

if h <= s:
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
l1 = input().strip().split()
h = int(l1[0])
n = int(l1[1])
a = sorted([int(i) for i in input().strip().split()], reverse=True)
print(a)
if h < sum(a[:n]):
    print("Yes")
else:
    print("No")


l1 = input().strip().split()
h = int(l1[0])
n = int(l1[1])
asum = sum([int(i) for i in input().strip().split()])
if h <= asum:
    print("Yes")
else:
    print("No")


Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
import numpy as np
 
N, M = map(int, input().split())
A = []
A = map(int, input().split())
 
dif = N - sum(A)
 
if dif >= 0:
  print(dif)
else:
  print('-1')

H, N = map(int, input().split())
special_move = input().split()
def answer(H: int, N: int, special_move: list) -> str:
    damage = 0
    for i in range(0, N):
        damage += int(special_move[i])
    if damage >= H:
        return 'Yes'
    else:
        return 'No'
print(answer(H, N, special_move))

Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
import sys

def main():

    

    h, n = map(int, input().split())
    a = list(map(int, input().split()))

    if h > sum(a):
        print('NO')
    else:
        print('YES')

if __name__ == '__main__':
    main()


import sys

def main():

    

    h, n = map(int, input().split())
    a = list(map(int, input().split()))

    if h > sum(a):
        print('No')
    else:
        print('Yes')

if __name__ == '__main__':
    main()


Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H, N = map(int, input().split())
A = list(map(int, input().split()))
ans = 'No'
print(H, N, A)

for i in A:
    H -= i
    if H <= 0:
        ans = 'Yes'
        break

print(ans)


H, N = map(int, input().split())
A = list(map(int, input().split()))
ans = 'No'

for i in A:
    H -= i
    if H <= 0:
        ans = 'Yes'
        break

print(ans)


Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H,N = map(int, input().split())
lists = [] lists.append(int, input().split())
lists = lists.sort()
if N>=2 and lists[N-1]+lists[N-2]>=H:
  print('Yes')
If N==1 and lists[0]>=H:
  print('Yes')
if N==1 and lists[0]<H:
  print('No')
else:
  print('No')

H,N = map(int, input().split())
lists = list(map(int, input().split()))
lists.sort()
SAM = sum(lists)
if SAM>=H:
    print('Yes')
else:
    print('No')


Verdicts: Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H, N = map(int,input().split())
A = input().split()

sumA = 0
for i in range(N):
  sumA += int(A[i])

#print(A)
if H-sumA <= 0:
  print('yes')
else:
  print('no')

H, N = map(int,input().split())
A = input().split()

sumA = 0
for i in range(N):
  sumA += int(A[i])

#print(A)
if H-sumA <= 0:
  print('Yes')
else:
  print('No')

Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
h,n = input().split()
w = [0]*int(n)

for i in range(0,int(n)):
    w[i] = input()

for i in range(0,int(n)):
    h = int(h) - int(w[i])

if(h<=0):
    print("Yes")
else:
    print("No")

h,n = input().split()
w = input().split()

for i in range(0,int(n)):
    h = int(h) - int(w[i])

if(h<=0):
    print("Yes")
else:
    print("No")

Verdicts: Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H, N = map(int, input().split())
A = map(int, input().split())
sum = 0

for val in A
	sum = sum + val

if sum >= H 
	print("Yes")
  
print("No")

H, N = map(int, input().split())
A = list(map(int, input().split()))
sum = 0

for val in A
	sum = sum + val

if sum >= H 
	print("Yes")
  
print("No")


H, N = map(int, input().split())
A = map(int, input().split())
sum = 0

for val in A:
	sum = sum + val

if sum >= H 
	print("Yes")
  
print("No")


H, N = map(int, input().split())
A = list(map(int, input().split()))
sum = 0

for val in A:
	sum = sum + val

if sum >= H 
	print("Yes")
  
print("No")


H, N = map(int, input().split())
A = map(int, input().split())
sum = 0

for val in A:
	sum = sum + val

if sum >= H:
	print("Yes")
  
print("No")


H, N = map(int, input().split())
A = map(int, input().split())
sum = 0

for val in A:
	sum = sum + val

if sum >= H:
	print("Yes")
else:  
	print("No")


Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H, N = map(int, input().split())
lis = list(input().split())
if sum(lis) >= H:
  print("Yes")
else:
  print("No")

H, N = map(int, input().split())
lis = list(map(input().split()))
if sum(lis) >= H:
  print("Yes")
else:
  print("No")

H, N = input().split()
lis = list(map(int, input().split()))
if sum(lis) >= H:
  print("Yes")
else:
  print("No")

H, N = map(int, input().split())
lis = list(map(int, input().split()))
if sum(lis) >= H:
  print("Yes")
else:
  print("No")

Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
h,n=map(int,inuput().split())
a=list(map(int,input().split()))

if h>sum(a):
    print('No')
else:
    print('Yes')

h,n=map(int,input().split())
a=list(map(int,input().split()))

if h>sum(a):
    print('No')
else:
    print('Yes')

Verdicts: Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H,N = input().split()
A = input().split()
H = int(H)
N = int(N)
Aintlist = [int(s) for s in A]
print(Aintlist)
sumdata = 0
for i in range(0,len(Aintlist)):
    sumdata += Aintlist[i]

if sumdata >= H:
    print('Yes')
else:
    print('No')

H,N = input().split()
A = input().split()
H = int(H)
N = int(N)
Aintlist = [int(s) for s in A]
sumdata = 0
for i in range(0,len(Aintlist)):
    sumdata += Aintlist[i]

if sumdata >= H:
    print('Yes')
else:
    print('No')

Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H,N = map(int,input().split())
a = 0
for i in range(N):
        c = int(input())
        a+=c
if a>=H:
        print("Yes")
else:
        print("No")


H,N = map(int,input().split())
A = list(map(int,input().split()))
a = 0
for i in A:
        a+=i
if a>=H:
        print("Yes")
else:
        print("No")

Verdicts: Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
a = input().split()
h, n = int(a[0]), int(a[1])
nums = input().split()
nums = list(map(int, nums))
x = sum(nums)
if x >= h:
  print("yes")
else:
  print("no")


a = input().split()
h, n = int(a[0]), int(a[1])
nums = input().split()
nums = list(map(int, nums))
x = max(nums)
xx = nums.index(x)
del nums[xx]
y = max(nums)
z = x + y

if z >= h:
  print("yes")
else:
  print("no")

a = input().split()
h, n = int(a[0]), int(a[1])
nums = input().split()
nums = list(map(int, nums))
x = sum(nums)

if x >= h:
  print("yes")
else:
  print("no")

a = input().split()
h, n = int(a[0]), int(a[1])
nums = input().split()
nums = list(map(int, nums))
nums = sorted(nums, reverse=True)
x = nums[0] + nums[1]
if x >= h:
  print("yes")
else:
  print("no")

a = input().split()
h, n = int(a[0]), int(a[1])
nums = input().split()
nums = list(map(int, nums))
x = h - sum(nums)
if x <= 0:
  print("Yes")
else:
  print("No")


Verdicts: Wrong Answer

Runtime Error

Wrong Answer

Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
A, B = map(int, input().split())
input_list = input().split( )

for i in (range(input_list)):
  input_list[i] = int(input_list)

input_sum = sum(input_list)

if(A <= input_sum):
  print("Yes")
else:
  print("No")


A, B = map(int, input().split())
input_list = input().split( )

for i in (range(len(input_list))):
  input_list[i] = int(input_list)

input_sum = sum(input_list)

if(A <= input_sum):
  print("Yes")
else:
  print("No")


A, B = map(int, input().split())
input_list = input().split( )

input_sum = sum(input_list)

if(A <= input_sum):
  print("Yes")
else:
  print("No")

A, B = map(int, input().split())
input_list = input().split( )

for i in (range(len(input_list))):
  input_list[i] = int(input_list[i])

input_sum = sum(input_list)

if(A <= input_sum):
  print("Yes")
else:
  print("No")


Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H, N = map(int, input().split())
Atack = list(map(int, input().split()))

total = 0
for i in range(N):
  total += Atack[i-1]
  if total >= H:
    print('Yes')
    
if total < H:
  print('No')

H, N = map(int, input().split())
Atack = list(map(int, input().split()))

if sum(Atack) < H:
  print('No')
  
else:
  print('Yes')

Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
211 5
31 41 59 26 53

h, m = map(int, input().split())
A = sum(list(map(int, input().split())))

if h <= A:
    print("Yes")
else:
    print("No")

Verdicts: Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
def main(h: int, n: int, a: list):
    for i in sorted(a):
        h -= i
        if h <= 0:
            print("Yes")
            return

    print("No")


if __name__ == "__main__":
    h, n = map(int, input().split())
    a = list(map(int, input().split()))


def main(h: int, n: int, a: list):
    for i in sorted(a):
        h -= i
        if h <= 0:
            print("Yes")
            return

    print("No")


if __name__ == "__main__":
    h, n = map(int, input().split())
    a = list(map(int, input().split()))

    main(h, n, a)


Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H,N = map(int,input().split())
A = list(map(int,input().split()))


ans = 'yes'


if sum(A) < H:
    ans = 'No'


print(ans)


H,N = map(int,input().split())
A = list(map(int,input().split()))
new_A = sorted(A,reverse=True)

ans = 'yes'

for i in range(N + 1):
    if new_A[1] + new_A[2] < H:
        ans = 'No'
    if N < 2:
        ans = 'No'

print(ans)


H,N = map(int,input().split())
A = list(map(int,input().split()))


ans = 'Yes'


if sum(A) < H:
    ans = 'No'


print(ans)

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H, N = map(int, input().split())
lst = [int(x) for x in input().split()]
if N >= sum(lst):
    print("Yes")
else:
    print("No")

H, N = map(int, input().split())
lst = [int(x) for x in input().split()]
if sum(lst) >= H:
    print("Yes")
else:
    print("No")


Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):

# ABC153

h, n = map(int, input().split())
a = list(map(int, input().split()))
s = sum(a)
if a <= s:
    print("Yes")
else:
    print("No")


# ABC153

h, n = map(int, input().split())
a = list(map(int, input().split()))
s = sum(a)
if h <= s:
    print("Yes")
else:
    print("No")


Verdicts: Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
s = input().split()
s2 = list(map(int, input().split()))

if sum(s2) >= int(s[0]):
    print("YES")
else:
    print("NO")

s = input().split()  
s2 = list(map(int, input().split()))  

if sum(s2) > int(s[0]):
    print("YES")
else:
    print("NO")


s = input().split()  
s2 = list(map(int, input().split()))  

# print(sum(s2))


if sum(s2) >= int(s[0]):
    print("Yes")
else:
    print("No")


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):

H,N=map(int, input().split())
A=list(map(int,input().split()))
A.sort()
count=0
print(A)
for i in range(N):
    count=count+A[i]

if H<=count:
    print("Yes")
else:
    print("No")


H,N=map(int, input().split())
A=list(map(int,input().split()))
A.sort(reverse=True)
count=0
#print(A)
for i in range(N):
    count=count+A[i]

if H<=count:
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
a,b=map(int,input().split())
l=list(map(int,input().split()))
if max(l)>=a:
	print('Yes')
else:
	print("No")


a,b=map(int,input(.split()))
aa=max(map(int,input().split()))
if aa>=a:
    print("yes")
else:
    print('no')


a,b=map(int,input(.split()))
aa=max(map(int,input().split()))
if aa>=a:
    print("yes")
else:
    print('No')


a,b=map(int,input(.split()))
*aa,=map(int,input().split())
if max(aa)>=a:
    print("yes")
else:
    print('no')


a,b=map(int,input().split())
l=list(map(int,input().spliit()))
if max(l)>=a:
	print('Yes')
else:
	print("No")

a,b=map(int,input().split())
l=list(map(int,input().split()))
if sum(l)>=a:
	print('Yes')
else:
	print("No")


Verdicts: Wrong Answer

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
h,n = map(int,input().split())
waza = sorted([int(x) for x in input().split()],reverce=True)

ans=0

for i in range(n):
    ans+=waza[i]

if ans >= h:
    print("Yes")
else:
    print("No")


h,n=map(int,input().split())

a=[int(x) for x in input().split()]

flag=False

for aa in a:
    h-=aa
    if h <= 0:
        flag=True
        break
    
if flag:
    print("Yes")
else:
    print("No")


Verdicts: Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
[H, N] = [int(x) for x in input().split()]
A = list(map(int, input().split()))
count = 0
for x in A:
    count += x
if count >= H:
    print("yes")
else:
    print("no")

[H, N] = [int(x) for x in input().split()]
A = list(map(int, input().split()))
count = 0
for x in A:
    count += x
print("Yes" if count >= H else "No")

Verdicts: Wrong Answer

Accepted
Problem: Fennec is fighting with N monsters.  The _health_ of the i-th monster is H_i.  Fennec can do the following two actions:    * Attack: Fennec chooses one monster. That monster's health will decrease by 1.   * Special Move: Fennec chooses one monster. That monster's health will become 0.  There is no way other than Attack and Special Move to decrease the monsters' health.  Fennec wins when all the monsters' healths become 0 or below.  Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.

Submission attempts (in order):
import numpy as np
N,K = map(int,input().split())
H = list(map(int,input().split()))
H.sort
j=0
if K >= N:
    print(N)
else:
    for i in range (N-K):
        j+=H[i]
    print(j+K)

import numpy as np
N,K = map(int,input().split())
H = list(map(int,input().split()))
H.sort()
j=0
if K >= N:
    print(0)
else:
    for i in range (N-K):
        j+=H[i]
    print(j)

Verdicts: Wrong Answer

Accepted
Problem: Fennec is fighting with N monsters.  The _health_ of the i-th monster is H_i.  Fennec can do the following two actions:    * Attack: Fennec chooses one monster. That monster's health will decrease by 1.   * Special Move: Fennec chooses one monster. That monster's health will become 0.  There is no way other than Attack and Special Move to decrease the monsters' health.  Fennec wins when all the monsters' healths become 0 or below.  Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.

Submission attempts (in order):
import sys
input = sys.stdin.readline
input_line = list(map(int,input().split()))
input_hp = list(map(int,input().split()))

input_hp.sort(reverse=True)
try:
    [input_hp.pop(_) for _ in range(input_line[1])]
    print(sum(input_hp))
except IndexError:
    print(‘0’)

import sys
input = sys.stdin.readline
input_line = list(map(int,input().split()))
input_hp = list(map(int,input().split()))
try:
    [(input_hp.sort(reverse=True) ,input_hp.pop(_)) for _ in range(input_line[1])]
    print(sum(input_hp))
except IndexError:
    print(‘0’)

input_line = list(map(int,input().split()))
input_hp = list(map(int,input().split()))

if input_line[0] <= input_line[1]:
    print('0')
else:
    input_hp.sort()
    result_input_hp = len(input_hp) - input_line[1]
    sum_total = sum(input_hp[:result_input_hp])
    print(sum_total)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Fennec is fighting with N monsters.  The _health_ of the i-th monster is H_i.  Fennec can do the following two actions:    * Attack: Fennec chooses one monster. That monster's health will decrease by 1.   * Special Move: Fennec chooses one monster. That monster's health will become 0.  There is no way other than Attack and Special Move to decrease the monsters' health.  Fennec wins when all the monsters' healths become 0 or below.  Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.

Submission attempts (in order):
[n,k]=[int(x) for x in onput().split()]
h=[int(x) for x in lnput().split()]
if n<=k:
  print("0")
else:
  print(str(sum(h[k:])))

[n,k]=[int(x) for x in input().split()]
h=[int(x) for x in input().split()]
h.sort()
if n<=k:
  print("0")
else:
  print(str(sum(h[:len(h)-k])))

Verdicts: Runtime Error

Accepted
Problem: Fennec is fighting with N monsters.  The _health_ of the i-th monster is H_i.  Fennec can do the following two actions:    * Attack: Fennec chooses one monster. That monster's health will decrease by 1.   * Special Move: Fennec chooses one monster. That monster's health will become 0.  There is no way other than Attack and Special Move to decrease the monsters' health.  Fennec wins when all the monsters' healths become 0 or below.  Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.

Submission attempts (in order):
N,K=map(int,input().split())
H= list(map(int,input().split()))

y=sorted(H)
y.sort(reverse=True)
x=0
print(x)
for i in range (K,N):
    x=x+y[i]
    
print(x)

special_moves = input().split(" ")

_, special_moves = int(inputs[0]), int(inputs[1])

health= input().split(" ")
health= [int(h) for h in health]
health.sort(reverse=True)
print(sum(health[special_moves:]))

nk = list(map(int,input().split()))
n,k = nk
h = list(map(int,input().split()))
if k >= len(h):
    print(0)
else:
    h.sort()
    for i in range (k):
        h.pop()
    print(sum(h))

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: Fennec is fighting with N monsters.  The _health_ of the i-th monster is H_i.  Fennec can do the following two actions:    * Attack: Fennec chooses one monster. That monster's health will decrease by 1.   * Special Move: Fennec chooses one monster. That monster's health will become 0.  There is no way other than Attack and Special Move to decrease the monsters' health.  Fennec wins when all the monsters' healths become 0 or below.  Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.

Submission attempts (in order):
N,K = map(int, input().split())
A = list(map(int, input().split()))

A.sort
if N > K:
  for i in range(K):
    A.pop()
  print(A)
else:
  print("0")




N,K = map(int, input().split())
A = list(map(int, input().split()))

A.sort
if N >= K:
  for i in range(K):
    A.pop()
  print(A)
else:
  print("0")



N,K = map(int, input().split())
A = list(map(int, input().split()))

A.sort()
if N > K:
  for i in range(K):
    A.pop()
  print(sum(A))
else:
  print("0")




Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Fennec is fighting with N monsters.  The _health_ of the i-th monster is H_i.  Fennec can do the following two actions:    * Attack: Fennec chooses one monster. That monster's health will decrease by 1.   * Special Move: Fennec chooses one monster. That monster's health will become 0.  There is no way other than Attack and Special Move to decrease the monsters' health.  Fennec wins when all the monsters' healths become 0 or below.  Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.

Submission attempts (in order):
n,k=map(input().split())
l=list(map(int,input().split()))
l.sort()
print(sum(l[:n-k-1]))

n,k=map(int,input().split())
l=list(map(int,input().split()))
l.sort()
print(sum(l[:n-k]))
//print(l)

n,k=map(int,input().split())
h=list(map(int,input().split()))
h.sort()
print(sum(h[:max(0,n-k)]))

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Fennec is fighting with N monsters.  The _health_ of the i-th monster is H_i.  Fennec can do the following two actions:    * Attack: Fennec chooses one monster. That monster's health will decrease by 1.   * Special Move: Fennec chooses one monster. That monster's health will become 0.  There is no way other than Attack and Special Move to decrease the monsters' health.  Fennec wins when all the monsters' healths become 0 or below.  Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.

Submission attempts (in order):
n, k = (int(x) for x in input().split())
H = list(map(int, input().split()))
if k != 0:
    H.sort()
    del H[:k]
print(sum(H))

n, k = (int(x) for x in input().split())
H = list(map(int, input().split()))
H.sort(reverse=True)
if k != 0:
    H.sort(reverse=True)
    del H[:k]
print(sum(H))

Verdicts: Wrong Answer

Accepted
Problem: Fennec is fighting with N monsters.  The _health_ of the i-th monster is H_i.  Fennec can do the following two actions:    * Attack: Fennec chooses one monster. That monster's health will decrease by 1.   * Special Move: Fennec chooses one monster. That monster's health will become 0.  There is no way other than Attack and Special Move to decrease the monsters' health.  Fennec wins when all the monsters' healths become 0 or below.  Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.

Submission attempts (in order):
N,K = map(int, input().split())
H = list(map(int, input().split()))
H.sort(reverse=True)
print(sum(H)-sum([i for i in range(K)]))

N,K = map(int, input().split())
H = list(map(int, input().split()))
H.sort(reverse=True)
print(sum(H[K:]))

Verdicts: Wrong Answer

Accepted
Problem: Fennec is fighting with N monsters.  The _health_ of the i-th monster is H_i.  Fennec can do the following two actions:    * Attack: Fennec chooses one monster. That monster's health will decrease by 1.   * Special Move: Fennec chooses one monster. That monster's health will become 0.  There is no way other than Attack and Special Move to decrease the monsters' health.  Fennec wins when all the monsters' healths become 0 or below.  Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.

Submission attempts (in order):
n, k = map(int, input().split())
h = list(map(int, input().split()))

h.reverse

h = h[k:]

print(sum(h))

n, k = map(int, input().split())
h = list(map(int, input().split()))

h.sort(reverse=True)

h = h[k:]

print(sum(h))

Verdicts: Wrong Answer

Accepted
Problem: Fennec is fighting with N monsters.  The _health_ of the i-th monster is H_i.  Fennec can do the following two actions:    * Attack: Fennec chooses one monster. That monster's health will decrease by 1.   * Special Move: Fennec chooses one monster. That monster's health will become 0.  There is no way other than Attack and Special Move to decrease the monsters' health.  Fennec wins when all the monsters' healths become 0 or below.  Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.

Submission attempts (in order):
import numpy as np

N, K = map(int, input().split())
li = list(map(int,input().split()))
list.sort(li, reverse = True)


a = list(np.zeros(K))
if N - K>=0:
    b = list(np.ones(N-K))
    a.extend(b)
else:
    a = list(np.zeros(N))

print(np.dot(a, li))

import numpy as np

N, K = map(int, input().split())
li = list(map(int,input().split()))
list.sort(li, reverse = True)


a = list(np.zeros(K))
if N - K>0:
    b = list(np.ones(N-K))
    a.extend(b)
else:
    a = list(np.zeros(N))

print(np.dot(a, li))

import numpy as np

N, K = map(int, input().split())
li = list(map(int,input().split()))
list.sort(li, reverse = True)


a = list(np.zeros(K))
if N - K>=0:
    b = list(np.ones(N-K))
    a.extend(b)
else:
    a = list(np.zeros(N))

print(int(np.dot(a, li)))

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Fennec is fighting with N monsters.  The _health_ of the i-th monster is H_i.  Fennec can do the following two actions:    * Attack: Fennec chooses one monster. That monster's health will decrease by 1.   * Special Move: Fennec chooses one monster. That monster's health will become 0.  There is no way other than Attack and Special Move to decrease the monsters' health.  Fennec wins when all the monsters' healths become 0 or below.  Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.

Submission attempts (in order):
A,B=map(int,input().split())
C=list(map(int,input().split()))
C.sort(reverse=True)
sum(C[B:])

A,B=map(int,input().split())
C=list(map(int,input().split()))
C.sort(reverse=True)
print(sum(C[B:]))

Verdicts: Wrong Answer

Accepted
Problem: Fennec is fighting with N monsters.  The _health_ of the i-th monster is H_i.  Fennec can do the following two actions:    * Attack: Fennec chooses one monster. That monster's health will decrease by 1.   * Special Move: Fennec chooses one monster. That monster's health will become 0.  There is no way other than Attack and Special Move to decrease the monsters' health.  Fennec wins when all the monsters' healths become 0 or below.  Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.

Submission attempts (in order):
h, k = map(int, input().split())
lis = list(map(int, input().split()))
if n >= k:
    lis.sort(reverse=True)
    lis = lis[k:]
else:
    lis = []
    
print(sum(lis))

h, k = map(int, input().split())
lis = list(map(int, input().split()))
if h >= k:
    lis.sort(reverse=True)
    lis = lis[k:]
else:
    lis = []
    
print(sum(lis))

Verdicts: Runtime Error

Accepted
Problem: Fennec is fighting with N monsters.  The _health_ of the i-th monster is H_i.  Fennec can do the following two actions:    * Attack: Fennec chooses one monster. That monster's health will decrease by 1.   * Special Move: Fennec chooses one monster. That monster's health will become 0.  There is no way other than Attack and Special Move to decrease the monsters' health.  Fennec wins when all the monsters' healths become 0 or below.  Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.

Submission attempts (in order):
N=list(map(int,input().split()))
H=list(map(int,input().split()))
count=0
H=sorted(H,reverse=True)
if N[1]>=len(H):
    print(len(H))
else:
    while N[1]>=1:
        del(H[0])
        N[1]-=1
        count+=1
    print(count+sum(H))
        

N=list(map(int,input().split()))
H=list(map(int,input().split()))
H=sorted(H,reverse=True)
if N[1]>=len(H):
    print(0)
else:
    del(H[0:N[1]])
    print(sum(H))
        

Verdicts: Wrong Answer

Accepted
Problem: Fennec is fighting with N monsters.  The _health_ of the i-th monster is H_i.  Fennec can do the following two actions:    * Attack: Fennec chooses one monster. That monster's health will decrease by 1.   * Special Move: Fennec chooses one monster. That monster's health will become 0.  There is no way other than Attack and Special Move to decrease the monsters' health.  Fennec wins when all the monsters' healths become 0 or below.  Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.

Submission attempts (in order):
n, k = map(int, input().split())
h = list(map(int, input().split()))
if h == 0:
  print(sum(h))
elif h >= n:
  print(0)
else:
  h.sort()
  print(sum(h[:n-k]))


n, k = map(int, input().split())
h = list(map(int, input().split()))
if k == 0:
  print(sum(h))
elif k >= n:
  print(0)
else:
  h.sort()
  print(sum(h[:n-k]))


Verdicts: Runtime Error

Accepted
Problem: Fennec is fighting with N monsters.  The _health_ of the i-th monster is H_i.  Fennec can do the following two actions:    * Attack: Fennec chooses one monster. That monster's health will decrease by 1.   * Special Move: Fennec chooses one monster. That monster's health will become 0.  There is no way other than Attack and Special Move to decrease the monsters' health.  Fennec wins when all the monsters' healths become 0 or below.  Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.

Submission attempts (in order):
n,k = map(int, input().split())
h = list(map(int, input().split()))
h.sort(reverse=True)
k = min(k,len(h))
print(h)
del h[:k]
print(h)
print(sum(h))

n,k = map(int, input().split())
h = list(map(int, input().split()))
h.sort()
k = min(k,len(h))
del h[:k]
print(sum(h))

n,k = map(int, input().split())
h = list(map(int, input().split()))
h.sort(reverse=True)
k = min(k,len(h))
del h[:k]
print(sum(h))

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Fennec is fighting with N monsters.  The _health_ of the i-th monster is H_i.  Fennec can do the following two actions:    * Attack: Fennec chooses one monster. That monster's health will decrease by 1.   * Special Move: Fennec chooses one monster. That monster's health will become 0.  There is no way other than Attack and Special Move to decrease the monsters' health.  Fennec wins when all the monsters' healths become 0 or below.  Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.

Submission attempts (in order):
n,k = map(int,input().split())
arr = list(map(int,input().split()))

arr = sorted(arr)
arr[:min(n,k)] = [0]*min(n,k)

print(sum(arr)) 

n,k = map(int,input().split())
arr = list(map(int,input().split()))

arr = sorted(arr,reverse=True)
arr[:min(n,k)] = [0]*min(n,k)

print(sum(arr))

Verdicts: Wrong Answer

Accepted