Problem: A maze is composed of a grid of H \times W squares - H vertical, W horizontal.  The square at the i-th row from the top and the j-th column from the left - (i,j) \- is a wall if S_{ij} is `#` and a road if S_{ij} is `.`.  There is a magician in (C_h,C_w). He can do the following two kinds of moves:    * Move A: Walk to a road square that is vertically or horizontally adjacent to the square he is currently in.   * Move B: Use magic to warp himself to a road square in the 5\times 5 area centered at the square he is currently in.  In either case, he cannot go out of the maze.  At least how many times does he need to use the magic to reach (D_h, D_w)?

Submission attempts (in order):
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines


h,w=map(int,readline().split())
ch, cw=map(int,readline().split())
dh, dw=map(int,readline().split())
m=list(map(lambda x: list(x.decode()), readlines()))


ch-=1; cw-=1; dh-=1; dw-=1

ad = [(-1,0), (0,-1), (1,0), (0,1)]
warp = [(-2, -2),(-2, -1),(-2, 0),(-2, 1),(-2, 2),
 (-1, -2),(-1, -1),(-1, 1),(-1, 2),
 (0, -2),(0, 2),
 (1, -2),(1, -1),(1, 1),(1, 2),
 (2, -2),(2, -1),(2, 0),(2, 1),(2, 2)]

def bfs4():
    
    for i in range(h):
        m[i] = ['#']*2 + m[i] + ['#']*2
    
    m = [['#']*(w+4)]*2 + m + [['#']*(w+4)]*2
    ch+=2; cw+=2; dh+=2; dw+=2
    
    que1=[]
    que2=[] 
    m[ch][cw]=str(0)
    que1.append((ch,cw))

    while que1!=[]:
        l1=len(que1)
        r1=0 

        
        while r1<l1:
            i, j=que1[r1]
            r1+=1
            
            for si, sj in ad:
                if m[i+si][j+sj]=='.': 
                    m[i+si][j+sj]=m[i][j]
                    que1.append((i+si, j+sj))
                    l1+=1

        
        for i,j in que1:
            for si, sj in warp:
                if m[i+si][j+sj]=='.':
                    m[i+si][j+sj]=str(int(m[i][j])+1)
                    que2.append((i+si, j+sj))

        que1=que2
        que2=[]
###---------------------------------------

bfs4()


if m[dh][dw] == '.':
    print(-1)
else:
    print(m[dh][dw])

import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines


h,w=map(int,readline().split())
ch, cw=map(int,readline().split())
dh, dw=map(int,readline().split())
m=list(map(lambda x: list(x.decode()), readlines()))


ad = [(-1,0), (0,-1), (1,0), (0,1)]
warp = [(-2, -2),(-2, -1),(-2, 0),(-2, 1),(-2, 2),
 (-1, -2),(-1, -1),(-1, 1),(-1, 2),
 (0, -2),(0, 2),
 (1, -2),(1, -1),(1, 1),(1, 2),
 (2, -2),(2, -1),(2, 0),(2, 1),(2, 2)]

def bfs6():
    
    que1=[]
    que2=[] 
    m[ch][cw]=str(0)
    que1.append((ch,cw))

    while que1!=[]:
        l1=len(que1)
        r1=0 

        
        while r1<l1:
            i, j=que1[r1]
            r1+=1
            for si, sj in ad:
                if m[i+si][j+sj]=='.': 
                    m[i+si][j+sj]=m[i][j]
                    que1.append((i+si, j+sj))
                    l1+=1

        
        for i,j in que1:
            if (m[i][j]==m[i-1][j] and m[i][j]==m[i+1][j]) or (m[i][j]==m[i][j-1] and m[i][j]==m[i][j+1]):
                continue
            for si, sj in warp:
                if m[i+si][j+sj]=='.':
                    m[i+si][j+sj]=str(int(m[i][j])+1)
                    que2.append((i+si, j+sj))

        que1=que2
        que2=[]
###---------------------------------------

for i in range(h):
    m[i] = ['#']*2 + m[i] + ['#']*2
    
m = [['#']*(w+4)]*2 + m + [['#']*(w+4)]*2
ch+=1; cw+=1; dh+=1; dw+=1

bfs6()

if m[dh][dw] == '.':
    print(-1)
else:
    print(m[dh][dw])

Verdicts: Runtime Error

Accepted