TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
import numpy as np
n=int(input())
l=np.array(list(map(int,input().split())))
c=0
for i in range(n):
  for j in range(i,n):
    if 0 in l[i:j+1]:
      pass
    else:
      l[i:j+1]=l[i:j+1]-np.array([min(l[i:j+1])]*(j-i+1))
      c+=min(l[i:j+1])
print(c)


n=int(input())
l=list(map(int,input().split()))
c=0
for i in range(n):
  for j in range(i,n):
    if 0 in l[i:j+1]:
      pass
    else:
      l[i:j+1]-=1
      c+=1
print(c)

import numpy as np
n=int(input())
l=np.array(list(map(int,input().split())))
c=0
for i in range(n):
  for j in range(i,n):
    if 0 in l[i:j+1]:
      pass
    else:
      l[i:j+1]=l[i:j+1]-np.array([1]*(j-i+1))
      c+=1
print(c)

import numpy as np
n=int(input())
l=np.array(list(map(int,input().split())))
c=0
for i in range(n):
  for j in range(n-i):
    if 0 in l[i:n-j]:
      pass
    else:
      c+=min(l[i:n-j])
      l[i:n-j]=l[i:n-j]-np.array([min(l[i:n-j])]*(n-j-i))
print(c)

Verdicts: Wrong Answer

Runtime Error

Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n=int(input())
h=list(map(int,input().split()))
ans=0
while any(h)==True:
    flag=0
    for i in range(n):
        if h[i]>0:
            h[i]-=1
            flag=1
        else:
            if flag==1:
                ans+=1
                flag=0
        if i==n-2:
            if h[n-1]>0:
                h[n-1]-=1
                ans+=1
                break
            else:
                if h[i]>0:
                    ans+=1
                break
print(ans)


n=int(input())
h=list(map(int,input().split()))
ans=0
if n==1:
    print(h[0])
    exit()
while any(h)==True:
    flag=0
    for i in range(n-1):
        if h[i]>0:
            h[i]-=1
            flag=1
        else:
            if flag==1:
                ans+=1
                flag=0
        if i==n-2:
            if h[n-1]>0:
                h[n-1]-=1
                ans+=1
            else:
                if flag==1:
                    ans+=1
print(ans)


Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N = int(input().strip())
H = list(map(int, input().strip().split(' ')))+[0]
count = 0
for _ in range(max(H)-1):
  l = 0
  for r in range(1,len(H)):
    if H[r] < H[l]:
      
      H[l:r] = [h-1 for h in H[l:r]]
      count += 1
      l = r
    elif H[r] > H[l]:
      しない
      l = r
    else:
      continue
print(count+1)

N = int(input().strip())
H = list(map(int, input().strip().split(' ')))+[0]
count = 0
for _ in range(max(H)):
  l = 0
  m = max(H)
  for r in range(1,len(H)):
    if H[r] != m:
      if H[l] == m:
        
        H[l:r] = [h-1 for h in H[l:r]]
        count += 1
      l = r
    else:
      if H[l] != m:
        l = r
print(count)

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n = int(input())
hn = list(map(int, input().split()[:n]))

i = 0
res = []
while True:
    for h in hn:
        if h > 0:
            res.append(h-1)
        else:
            res.append(h)
    hn = res
    res = []
    if sum(hn) == 0:
        print(i)
        break
    i += 1


n = int(input())
hn = list(map(int, input().split()[:n]))

count = 0
prev = 0

for h in hn:
    count += max(0, h-prev)
    prev = h

print(count)


Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
import sys
n=int(input())
h=list(map(int,input().split()))
if len(set(h))==1:
  print(h[0])
  sys.exit()
h.append(1-2)
totl=0
for i in range(1,max(h)+1):
  cnt=1	
  for j in range(n):
    if h[j]<i:
      if i<=h[j+1]:
        cnt+=1
  totl+=cnt
print(totl)
        
       
    


import sys
n=int(input())
h=list(map(int,input().split()))
if len(set(h))==1:
  print(h[0])
  sys.exit()
totl=0
for i in range(1,max(h)+1):
  cnt=0
  if i<=h[0]:
    cnt+=1
  for j in range(n-1):
    if h[j]<i:
      if i<=h[j+1]:
        cnt+=1
  totl+=cnt
print(totl)
        
       
    


Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
import numpy as np
N = int(input())
h = list(map(int, input().split()))
h = np.array(h)
h_diff = h[1:] - h[:N-1]
count = 0
print(h_diff)
for i in range(N-1):
    count -= min(h_diff[i], 0)
    
print(count + h[N-1])

import numpy as np
N = int(input())
h = list(map(int, input().split()))
h = np.array(h)
h_diff = h[1:] - h[:N-1]
count = 0
for i in range(N-1):
    count -= min(h_diff[i], 0)
    
print(count + h[N-1])

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
def down(H, n):
  x = min(H)
  n += x
  for i in range(len(H)):
    H[i] -= x
  return H, n

N = int(input())
H = list(map(int, input().split()))
n = 0
H, n = down(H, n)
print(H)

while not all(h == 0 for h in H):
  L = []
  H0 =[]
  for h in H:
    if h != 0:
      L.append(h)
    else:
      if L:
        L, n = down(L, n)
      H0 += L
      H0.append(0)
      L = []
  if L:
    L, n = down(L, n)
    H0 += L
  H = H0
  print(H)

print(n)

def down(H, n):
  x = min(H)
  n += x
  for i in range(len(H)):
    H[i] -= x
  return H, n

N = int(input())
H = list(map(int, input().split()))
n = 0
H, n = down(H, n)

while not all(h == 0 for h in H):
  L = []
  H0 =[]
  for h in H:
    if h != 0:
      L.append(h)
    else:
      if L:
        L, n = down(L, n)
      H0 += L
      H0.append(0)
      L = []
  if L:
    L, n = down(L, n)
    H0 += L
  H = H0
  print(H)

print(n)

def down(H, n):
  x = min(H)
  n += x
  for i in range(len(H)):
    H[i] -= x
  return H, n

N = int(input())
H = list(map(int, input().split()))
n = 0
H, n = down(H, n)
print(H)

while not all(h == 0 for h in H):
  L = []
  H0 =[]
  for h in H:
    if h != 0:
      L.append(h)
    else:
      if L:
        L, n = down(L, n)
      H0 += L
      H0.append(0)
      L = []
  if L:
    L, n = down(L, n)
    H0 += L
  H = H0

print(n)

def down(H, n):
  x = min(H)
  n += x
  for i in range(len(H)):
    H[i] -= x
  return H, n

N = int(input())
H = list(map(int, input().split()))
n = 0
H, n = down(H, n)

while not all(h == 0 for h in H):
  L = []
  H0 =[]
  for h in H:
    if h != 0:
      L.append(h)
    else:
      if L:
        L, n = down(L, n)
      H0 += L
      H0.append(0)
      L = []
  if L:
    L, n = down(L, n)
    H0 += L
  H = H0

print(n)

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N = int(input())
array = input().split(' ')
harray = []
for z in array:
    z = int(z)
    harray.append(z)
counter = 0
while harray != [0]*N:
    if 0 not in harray:
        a = min(harray)
        for i in range(len(harray)):
            harray[i] -= a
        counter += a
    else:
        zeroarray = [j for j, x in enumerate(harray) if x == 0]
        if len(zeroarray) == 1:
            if zeroarray[0] == 0:
                a = min(harray[1:])
                for y in range(1,N):
                    harray[y] -= a
                counter += a
            elif zeroarray[0] == N-1:
                a = min(harray[:N-1])
                for y in range(N-1):
                    harray[y] -= a
                counter += a
            else:
                a = min(harray[:zeroarray[0]])
                for y in range(zeroarray[0]):
                    harray[y] -= a
                counter += a
                a = min(harray[zeroarray[0]+1:])
                for y in range(zeroarray[0]+1,N):
                    harray[y] -= a
                counter += a
        else:
            for k in range(len(zeroarray)-1):
                if zeroarray[0] != 0:
                    a = min(harray[:zeroarray[0]])
                    for y in range(zeroarray[0]):
                        harray[y] -= a
                    counter += a
                if zeroarray[k+1] - zeroarray[k] == 1:
                    continue
                else:
                    a = min(harray[zeroarray[k]+1:zeroarray[k+1]])
                    for y in range(zeroarray[k]+1,zeroarray[k+1]+1):
                        harray[y] -= a
                    counter += a
                if zeroarray[-1] != N-1:
                    a = min(harray[zeroarray[-1]+1:])
                    for y in range(zeroarray[-1]+1,N):
                        harray[y] -= a
                    counter += a
        

print(counter)

N = int(input())
h = list(map(int,input().split()))
count = 0

def devide(h):
    global count
    while 0 not in h:
        for i in range(len(h)):
            h[i] -= 1
        count += 1
    h2 = []
    h3 = []
    for i in h:
        if i == 0:
            h2.append(h3)
            h3 = []
        if i != 0:
            h3.append(i)
    h2.append(h3)

    for i in h2:
        if i == []:
            continue
        else:
            devide(i)
            
devide(h)
print(count)

Verdicts: Time Limit Exceeded

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N = int(input())
h = list(map(int, input().split()))

print(h)

ans = 0

while True:
  given_water = False
  is_continuous = False
  for i in range(N):
    if h[i] > 0:
      if is_continuous is False:
        ans += 1
        is_continuous = True
      h[i] -= 1
      given_water = True
    else: # h[i] == 0
      is_continuous = False
  print(ans)
  print(h)
  if given_water is False:
    break
      
print(ans)

N = int(input())
h = list(map(int, input().split()))

ans = 0
given_water = False
while True:
  is_continuous = False
  for i in range(N):
    if h[i] > 0:
      if is_continuous is False:
        ans += 1
        is_continuous = True
      h[i] -= 1
      given_water = True
    else: # h[i] == 0
      is_continuous = False
  if given_water is False:
    break
      
print(ans)

N = int(input())
h = list(map(int, input().split()))

ans = 0

while True:
  given_water = False
  is_continuous = False
  for i in range(N):
    if h[i] > 0:
      if is_continuous is False:
        ans += 1
        is_continuous = True
      h[i] -= 1
      given_water = True
    else: # h[i] == 0
      is_continuous = False
  if given_water is False:
    break
      
print(ans)

Verdicts: Wrong Answer

Time Limit Exceeded

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n=int(input())
h=list(map(int,input().split()))
def dfs(l,r):
  if l==r:
    return h[l]
  if r<l:
    return 0
  res=10**18
  for i in range(l,r+1):
    res=min(res,h[i])
  for i in range(l,r+1):
    h[i]-=res
  for i in range(l,r):
    if h[i]==0:
      return dfs(l,i-1)+dfs(i+1,r)+res
  return 0
print(dfs(0,n-1))

n=int(input())
h=list(map(int,input().split()))
def dfs(l,r):
  if l==r:
    return h[l]
  if r<l:
    return 0
  res=10**18
  for i in range(l,r+1):
    res=min(res,h[i])
  for i in range(l,r+1):
    h[i]-=res
  for i in range(l,r+1):
    if h[i]==0:
      return dfs(l,i-1)+dfs(i+1,r)+res
  return 0
print(dfs(0,n-1))

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
def block():
    block=0
    count=0
    while count<=(n-1):
        if h[count]>=1:
            block+=1
            count+=1
            while count<=(n-1):
                if h[count]>=1:
                    count+=1
                else:
                    count+=1
                    break
    return block
                
n=int(input())
h=list(map(int,input().split()))
ans=0
while sum(h)>0:
    bl=block()
    mini=min(h)
    ans+=mini*bl
    for i in range(n):
        h[i]-=mini
    
print(ans)

def block():
    block=0
    count=0
    mini=200
    while count<=(n-1):
        if h[count]>=1:
            block+=1
            if h[count]<mini:
                mini=h[count]
            count+=1
            while count<=(n-1):
                if h[count]>=1:
                    if h[count]<mini:
                        mini=h[count]
                    count+=1
                else:
                    count+=1
                    break
    return block,mini
                
n=int(input())
h=list(map(int,input().split()))
ans=0
while sum(h)>0:
    bl,m=block()
    ans+=m*bl
    for i in range(n):
        h[i]-=m
    
print(ans)

N = int(input())
h = list(map(int,input().split()))
cnt = 0
 
while sum(h) > 0:
    min_h = max(h)
    i = h.index(min_h)
    #print(i)
    while i < len(h):
        if h[i] == min_h:
            h[i] -= 1
            i += 1
        else:
            break
    cnt += 1
 
print(cnt)

Verdicts: Time Limit Exceeded

Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
#include <bits/stdc++.h>
using namespace std;
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }
typedef long long unsigned int ll;

#define EPS (1e-7)
#define INF (1e9)
#define PI (acos(-1))
int dx[4] = {1, 0, -1, 0};
int dy[4] = {0, 1, 0, -1}; // 移動方向


int n;
int h[101];

void input(){
    cin >> n;
    for(int i=0;i<n;i++) cin >> h[i];
}

int main()
{
    cin.tie(0);
    ios::sync_with_stdio(false);
    input();
    int cnt = 0;
    for(int l=0;l<n;l++){
        while(h[l] > 0){
            int r;
            for(r=l+1;r<n;r++){
                if (h[r] == 0) break; 
            }
            for(int x=l;x<r;x++) h[x]--;
            cnt++;
        }
    }
    cout << cnt << endl;
    return 0;
}

import sys
input = sys.stdin.readline

def lsearch(h): 
    for i in range(len(h)):
        if h[i] != 0:
            return i
    return len(h)-1

def rsearch(h, l): 
    for i in range(l, len(h)):
        if h[i] == 0:
            return i
    return len(h)

n=int(input())
h=list(map(int, input().split()))
cnt=0
while any(h):
    l=lsearch(h)
    r=rsearch(h, l)
    for i in range(l, r):
        h[i] -= 1
    cnt+=1
print(cnt)

Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n = int(input())
h = list(map(int, input().split()))
gap = [0]
mt = []
va = []
i = 0
while i+1 <= len(h)-1:
    if h[i+1]-h[i] != 0:
        gap.append(h[i+1]-h[i])
        i += 1
    else:
        h.pop(i+1)
for i in range(h):    
    if gap[i] >= 0: 
        if gap[i+1] < 0:
            mt.append(h[i])
    else:
        if gap[i+1] > 0:
            va.append(h[i])
if gap[-1] > 0 :
    mt.append(h[-1])
if mt == []:
    mt.append(h[0])
ans = 0
for x in mt:
    ans += x
for x in va:
    ans -= x
print(ans)

n = int(input())
h = list(map(int, input().split()))
gap = [0]*n
mt = []
va = []
for i in range(n-1):
    gap[i+1] = h[i+1]-h[i]
    if gap[i] > 0: 
        if gap[i+1] < 0:
            mt.append(h[i])
    else:
        if gap[i+1] > 0:
            va.append(h[i])
if gap[-1] > 0 :
    mt.append(h[-1])
if mt == []:
    mt.append(h[0])
ans = 0
for x in mt:
    ans += x
for x in va:
    ans -= x
print(ans)

n = int(input())
h = list(map(int, input().split()))
gap = [0]
mt = []
va = []
i = 0
while i+1 <= len(h)-1:
    if h[i+1]-h[i] != 0:
        gap.append(h[i+1]-h[i])
        i += 1
    else:
        h.pop(i+1)
for i in range(h)    
    if gap[i] >= 0: 
        if gap[i+1] < 0:
            mt.append(h[i])
    else:
        if gap[i+1] > 0:
            va.append(h[i])
if gap[-1] > 0 :
    mt.append(h[-1])
if mt == []:
    mt.append(h[0])
ans = 0
for x in mt:
    ans += x
for x in va:
    ans -= x
print(ans)

n = int(input())
h = list(map(int, input().split()))
gap = [0]
mt = []
va = []
i = 0
while i+1 <= len(h)-1:
    if h[i+1]-h[i] != 0:
        gap.append(h[i+1]-h[i])
        i += 1
    else:
        h.pop(i+1)
for i in range(len(h)-1):    
    if gap[i] >= 0: 
        if gap[i+1] < 0:
            mt.append(h[i])
    else:
        if gap[i+1] > 0:
            va.append(h[i])
if gap[-1] > 0 :
    mt.append(h[-1])
if mt == []:
    mt.append(h[0])
ans = 0
for x in mt:
    ans += x
for x in va:
    ans -= x
print(ans)

Verdicts: Runtime Error

Wrong Answer

Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N = int(input())
lst = list(map(int, input().split()))
cnt = 0
for i in range(N-1):
    if lst[i] < lst[i+1]:
        cnt += 
print(cnt)




#139 c
N = int(input())
H = list(map(int, input().split()))
max_lst = []
min_lst = []
max_h = H[0]
min_h = H[0]
s = 0
for i in range(1, N):
    if H[i-1] <= H[i]:
        if H[0] not in max_lst and H[0] not in min_lst:
            min_lst.append(H[0])
        if max_h == 0:
            min_lst.append(min_h)
        if i == N-1:
            max_lst.append(H[i])
        max_h = H[i]
        min_h = 0
    elif H[i-1] >= H[i]:
        if H[0] not in max_lst and H[0] not in min_lst:
            max_lst.append(H[0])
            s = 1
        if min_h == 0:
            max_lst.append(max_h)
        if i == N-1:
            min_lst.append(H[i])
        min_h = H[i]
        max_h = 0
cnt = 0
if s == 0:
    for i in range(len(min_lst)-1):
        cnt += max_lst[i] - min(min_lst[i], min_lst[i+1])
    cnt += max_lst[-1] - min_lst[-1]
else:
    for i in range(1, len(max_lst)):
        cnt += max_lst[i] - min(min_lst[i-1], min_lst[i])
    cnt += max_lst[0] - min_lst[0]
print(cnt)

N = int(input())
H = list(map(int, input().split()))
ans = 0
H.append(0)
for i in range(max(H)):
    cnt = 0
    for k in range(N):
        if H[k] != 0 and H[k+1] == 0:
            cnt += 1
    ans += cnt
    H = list(map(lambda x:(x-1, 0)[x == 0], H))
print(ans)

Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N = int(input().split())
H = list(map(int,input().split()))
y = 0
z = H[i]
ans = 0
for i in range(N):
    x = H[i]
    if x >= y:
        y = x
    else:
        ans += y
        z = min(z,x)
        for j in range(i,N):
            p = H[j]
            z = min(z,p)
            H[j] -= z
print(ans)
        

N = int(input())
H = list(map(int,input().split()))
y = 0
z = H[0]
ans = 0
while len(H) != 0:
    z = H[0]
    f = 1
    while z == 0:
        H.pop(0)
        if len(H) != 0:
            z = H[0]
        else:
            break
    for i in range(len(H)):
        x = H[i]
        if x == 0:
            ans += z
            for j in range(i):
                H[j] -= z
            z = H[0]
            f = 0
            break
        z = min(x,z)
    if f == 1:
        ans += z
        for i in range(len(H)):
            H[i] -= z
print(ans)

Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
from fractions import gcd
from functools import reduce

N = int(input())

H = list(map(lambda x: int(x) + 1, input().split()))

def it(items, count):
    if not items:
        return 0
    if len(items) == 1:
        return items[0] + count

    ids = [-1]
    for i in range(len(items)):
        items[i] -= 1
        if items[i] <= 0:
            ids.append(i)
    ids.append(len(items))

    ans = 0
    for i in range(len(ids)-1):
        next_items = items[ids[i]+1:ids[i+1]]
        ans += it(next_items, count+1)
        if next_items:
            count = -1

    return ans

print(it(H, -1))


import sys
sys.setrecursionlimit(10**8)
N = int(input())

H = list(map(lambda x: int(x) + 1, input().split()))

def it(items, count):
    if not items:
        return 0
    if len(items) == 1:
        return items[0] + count

    ids = [-1]
    for i in range(len(items)):
        items[i] -= 1
        if items[i] <= 0:
            ids.append(i)
    ids.append(len(items))

    ans = 0
    for i in range(len(ids)-1):
        next_items = items[ids[i]+1:ids[i+1]]
        ans += it(next_items, count+1)
        if next_items:
            count = -1

    return ans

print(it(H, -1))


n = int(input())
h = list(map(int, input().split()))
ans = 0
pre = 0
for i in h:
    ans += max(0, i-pre)
    pre = i
print(ans)


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
h_state=[0]*n

def water(n,h,h_state):
    for i in range(n):
        if h_state[i]<h[i]:
            l=i
            break
        elif i==n-1 and h_state[i]<h[i]:
            l=i
        else:
            l=i+1
    
    for j in range(l,n):
        if h_state[j]==h[j]:
            r=j-1
            break
        else:
            r=j
    
    for k in range(l,r+1):
        h_state[k]+=1

cnt=0
while h_state != h:
    for i in range(n):
        if h_state[i]<h[i]:
            cnt+=1
            water(n,h,h_state)
            break
print(cnt)
        

n=int(input())
h=[int(x) for x in input().split()]

h_state=[0]*n

def water(n,h,h_state):
    for i in range(n):
        if h_state[i]<h[i]:
            l=i
            break
        elif i==n-1 and h_state[i]<h[i]:
            l=i
        else:
            l=i+1
    
    for j in range(l,n):
        if h_state[j]==h[j]:
            r=j-1
            break
        else:
            r=j
    
    for k in range(l,r+1):
        h_state[k]+=1

cnt=0
while h_state != h:
    for i in range(n):
        if h_state[i]<h[i]:
            cnt+=1
            water(n,h,h_state)
            break
print(cnt)
        

Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n=int(input())
h=[0]+list(map(int,input().split()))+[0]
ma=0
mi=float('inf')
ans=0
for i in range(n+1):
  if h[i]<=h[i+1]:
    ma=max(ma,h[i+1],h[i])
    mi=min(mi,h[i])
  else:
    ans+=ma-mi
    ma=0
    mi=float('inf')
print(ans)

n=int(input())
h=[0]+list(map(int,input().split()))+[0]
ma=0
mi=float('inf')
ans=0
for i in range(n+1):
  if h[i]<=h[i+1]:
    ma=max(ma,h[i+1])
    mi=min(mi,h[i])
  else:
    ans+=ma-mi
    ma=0
    mi=float('inf')
print(ans)

n=int(input())
h=[0]+list(map(int,input().split()))+[0]
ma=0
mi=float('inf')
ans=0
for i in range(n+1):
  if h[i]<=h[i+1]:
    ma=max(ma,h[i+1])
    mi=min(mi,h[i])
  else:
    ans+=ma-mi
    ma=h[i+1]
    mi=h[i+1]
print(ans)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N = int(input())
H = list(map(int, input().split()))
H = [h - min(H) for h in H]

ans = 0
for i in range(N-1):
    diff = H[i+1] - H[i]
    if i != N-2:
        if diff < 0:
            ans += abs(diff)
    else:
        if diff < 0:
            ans += abs(diff)
        else:
            ans += H[-1]

print(ans + min(H))

N = int(input())
H = list(map(int, input().split()))

ans = H[0]
for i in range(N-1):
    dif = H[i+1] - H[i]
    if dif > 0:
        ans += dif

print(ans)

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n=int(input())
h=list(map(int,input().split()))
a=0
for i in range(1,max(h)+1):
    s=0
    while s<n:
        if h[s]>=i:
            a+=1
            while s<n and h[s]>=i:
                s+=1
    s+=1
print(a)

n=int(input())
h=list(map(int,input().split()))
a=0
for i in range(1,max(h)+1):
    s=0
    while s<n:
        if h[s]>=i:
            a+=1
        s+=1
print(a)

n=int(input())
h=list(map(int,input().split()))
a=0
for i in range(1,max(h)+1):
    s=0
    while s<n:
        if h[s]>=i:
            a+=1
            while s<n and h[s]>=i:
                s+=1 
        s+=1
print(a)

Verdicts: Time Limit Exceeded

Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n = int(input())
h_list = [int(i) for i in input().split()]

k = 0
while sum(h_list)>0:
  bool_list = [True if i==max(h_list) else False for i in h_list]
  indexes = []
  true_index = bool_list.index(True)
  indexes.append(true_index)
  while bool_list(true_index):
    true_index += 1
    indexes.append(true_index)
  h_list = [h_list[i]-1 for i in indexes]
  k += 1
  
print(k)
    

n = int(input())
h_list = [int(i) for i in input().split()]

k = 0
while any([i > 0 for i in h_list]):
    bool_list = [True if i==max(h_list) else False for i in h_list]
    indexes = []
    true_index = bool_list.index(True)
    while bool_list[true_index]:
        indexes.append(true_index)
        true_index += 1
        if true_index == len(h_list):
            break

    h_list = [h_list[i]-1 if i in indexes else h_list[i] for i in range(len(h_list))]
    k += 1
  
print(k)

Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
import sys
input = sys.stdin.readline
import numpy as np
N = int(input())
h = [int(x) for x in input().split()] + [0]
h = np.array(h,np.int64)
ans = 0
for i in range(N):
    if h[i] > 0:
        j = i + 1
        while h[j] > h[i]:
            h[j] -= h[i]
            j += 1
        nexth = h[j]
        ans += h[j]
        for k in range(i,j+1):
            h[k] -= h[j]
        ans += h[i]
        h[i] = 0
print(ans)

import sys
input = sys.stdin.readline
import numpy as np
N = int(input())
h = [int(x) for x in input().split()] + [0]
h = np.array(h,np.int64)
ans = 0
for i in range(N):
    if h[i] > 0:
        j = i + 1
        while h[j] > h[i]:
            h[j] -= h[i]
            j += 1
        nexth = h[j]
        h[i] -= h[j]
        ans += h[i]
        h[i] = 0
print(ans)

import sys
input = sys.stdin.readline
import numpy as np
N = int(input())
h = [int(x) for x in input().split()]
h = np.array(h,np.int64)
ans = 0
def split_(A):
    global ans
    if np.count_nonzero(A != 0) == 0:
        return
    else:
        minA = A.min()
        A -= minA
        ans += minA
        for i in range(len(A)):
            if A[i] == 0:
                split_(A[:i])
                split_(A[i+1:])
                break
split_(h)
print(ans)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N = int(input())
hList = list(map(int, input().split()))

ans = 0
cou = 0

hList = [0] + hList

for i in range(N):
    if hList[i] < hList[i+1]:
        cou = hList[i+1] - hList[i]
    else:
        ans += cou
        cou = 0
ans += cou
print(ans)

N = int(input())
hList = list(map(int, input().split()))

ans = 0
cou = 0

hList = [0] + hList

for i in range(N):
    if hList[i] < hList[i+1]:
        cou += (hList[i+1] - hList[i])
    else:
        ans += cou
        cou = 0
ans += cou
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N=int(input())
h=list(map(int,input().split()))
p=h[0]
for i in range(N-1):
  if h[i]<h[i+1]:
    p=h[i+1]
  else:
    p=p

q=1
r=0
if p==0:
    print(0)
else:
   while q<=p:
        if h[0]>=q:
            r=r+1
        else:
            r=r
        for i in range(N-1):
              if h[i]<q and h[i+1]>=q:
                r=r+1
              else:
                r=r
    q=q+1

print(r)

N=int(input())
h=list(map(int,input().split()))
p=h[0]
for i in range(N-1):
  if p<h[i+1]:
    p=h[i+1]
  else:
    p=p
 
q=1
r=0
if p==0:
    print(0)
else:
    while q<=p:
        if h[0]>=q:
            r=r+1
        else:
            r=r
        for i in range(N-1):
              if h[i]<q and h[i+1]>=q:
                r=r+1
              else:
                r=r
        q=q+1
    print(r)

Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n=int(input())
flowers=[0]+list(map(int,input().split()))
ans=0
for i in range(1,n+1):
  ans+=max(flowers[i+1]-flowers[i],0)
print(ans)

n=int(input())
flowers=[0]+list(map(int,input().split()))
ans=0
for i in range(n):
  ans+=max(flowers[i+1]-flowers[i],0)
print(ans)


Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n=int(input())
h=list(map(int,input()))
hm=max(h)
s=['']*hm
for k in range(hm+1):
  for i in range(n):
    if h[i]>=k:
      s[k]+='#'
    else:
      s[k]+=' '

ans=0
for k in range(hm+1):
  ans+=len(list(s[k].split()))
print(ans)

n=int(input())
h=list(map(int,input().split()))
hm=max(h)
s=['']*hm
for k in range(1,hm+1):
  for i in range(n):
    if h[i]>=k:
      s[k-1]+='#'
    else:
      s[k-1]+=' '

#print(s)
ans=0
for k in range(hm):
  ans+=len(list(s[k].split()))
print(ans)


Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N = int(input())
h_list = list(map(int, input().split(' ')))


def mizuyari(h_list, l, r):
    import pdb;pdb.set_trace()
    num_mizuyari = min(h_list[l:r+1])
    h_list = [h - num_mizuyari if l <= x and x <= r else h for x, h in enumerate(h_list)]
    zero_posi = h_list[l:].index(0) + l
    if l == zero_posi:
        first_non_zero_posi = [x for x, h in enumerate(h_list) if h != 0]
        if not first_non_zero_posi:
            print(sum_mizuyari + num_mizuyari)
            exit()
        l = first_non_zero_posi[0]
        if list(range(l, len(h_list))) == first_non_zero_posi:
            return h_list, num_mizuyari, l, len(h_list)
        zero_posi = h_list[l:].index(0) + l
    new_r = zero_posi - 1
    return h_list, num_mizuyari, l, new_r
l = 0
r = len(h_list) - 1
sum_mizuyari = 0
while True:
    h_list, num_mizuyari, l, r = mizuyari(h_list, l, r)
    sum_mizuyari += num_mizuyari

N = int(input())
h_list = list(map(int, input().split(' ')))

def grouping(h_list):
    groups = []
    group = []
    for h in h_list:
        if h == 0:
            if group != []:
                groups.append(group)
            group = []
            continue
        group.append(h)
    if group:
        groups.append(group)
    return groups


sum_mizuyari = []
def groups_mizuyari(h_list):
    num_mizuyari = min(h_list)
    h_list = [h - num_mizuyari  for h in h_list]
    sum_mizuyari.append(num_mizuyari)
    groups = grouping(h_list)
    for group in groups:
        groups_mizuyari(group)

groups_mizuyari(h_list)
print(sum(sum_mizuyari))

Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n = int(input())
h = list(map(int,input().split()))
ans = 0

while min(h) != 0:
    h = list(map(lambda x: x-1,h))
    ans += 1

while sum(h) != 0:
    flag = False
    for i in range(n):
        if i == n-1:
            h[i] -= 1
            ans += 1
            break
        if h[i] == 0 and flag:
            ans += 1
            break
        elif h[i] != 0:
            h[i] -= 1
            flag = True
else:
    print(ans)

def calc(list1,list2):
    for l in list2:
        list1[l] += 1
    return list1

n = int(input())
h = list(map(int,input().split()))
f = [0]*n
ans = 0

for i in range(min(h)):
    f = [x+1 for x in f]
    ans += 1

while sum(f) != sum(h):
    flag = False
    tmp = []
    for i in range(n):
        if i == n-1 and h[i] != f[i]:
            tmp.append(i)
            f = calc(f,tmp)
            ans+=1
        elif h[i] == f[i] and flag:
            f = calc(f,tmp)
            ans+=1
            break
        elif h[i] != f[i]:
            flag = True
            tmp.append(i)
else:
    print(ans)

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
import numpy as np

N = int(input())
H = np.array(input().split(), dtype=np.int32)

def myfunc(left, right):
    if right<left:
        return 0
    idx = left+H[left:right+1].argmin()
    m = H[idx]
    H[left:right+1]-=m
    return m+myfunc(left, idx-1)+myfunc(right, idx+1)

print(myfunc(0, N-1))

N = int(input())
H = np.array(input().split(), dtype=np.int32)

def myfunc(left, right):
    if right<left:
        return 0
    idx = left+H[left:right+1].argmin()
    m = H[idx]
    H[left:right+1]-=m
    return m+myfunc(left, idx-1)+myfunc(right, idx+1)

print(myfunc(0, N-1))

import numpy as np

N = int(input())
H = np.array(input().split(), dtype=np.int32)

def myfunc(left, right):
    if right<left:
        return 0
    idx = left+H[left:right+1].argmin()
    m = H[idx]
    H[left:right+1]-=m
    return m+myfunc(left, idx-1)+myfunc(idx+1, right)

print(myfunc(0, N-1))

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
def water(list_a):
    if list_a == [0] * len(list_a):
        return 0
    
    elif 0 in list_a:
        n = list_a.index(0)
        return water(list_a[:n]) + water(list_a[n+1:])

    else:
        mini = min(list_a)
        for i in range(len(list_a)):
            list_a[i] += mini
        return water(list_a) + mini

n = int(input())
list_h = list(map(int, input().split()))
print(list_h)


def water(list_a):
    if list_a == [0] * len(list_a):
        return 0
    
    elif 0 in list_a:
        n = list_a.index(0)
        return water(list_a[:n]) + water(list_a[n+1:])

    else:
        mini = min(list_a)
        for i in range(len(list_a)):
            list_a[i] -= mini
        return water(list_a) + mini

n = int(input())
list_h = list(map(int, input().split()))
print(list_h)


def water(list_a):
    if list_a == [0] * len(list_a):
        return 0
    
    elif 0 in list_a:
        n = list_a.index(0)
        return water(list_a[:n]) + water(list_a[n+1:])

    else:
        mini = min(list_a)
        for i in range(len(list_a)):
            list_a[i] -= mini
        return water(list_a) + mini

n = int(input())
list_h = list(map(int, input().split()))
print(water(list_h))

Verdicts: Wrong Answer

Wrong Answer

Accepted