TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
a=int(input())
k=[]
for i in range(1,a+1):
    k.append(i)
for i in k:
    if i%3==0 or i%5==0:
        k.remove(i)
        
s=sum(k)
print(s)

a=int(input())
l=[]
for i in range(1,a+1):
    l.append(i)
k=[]
for i in range(1,a+1):
    if not i % 5 or not i % 3:
        k.append(i)
s=sum(k)
k=sum(l)
print(k-s)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())
l=[]
sum=0
for i in range(1,n+1):
         if  i%3==0 and i%5 ==0:
                    l.apoend("FizzBuzz")
         elif i%3==0 and i%5!=0:
                    l.append("Fizz")
         elif i%5==0 and i%3!=0:
                    l.append("Buzz")
         else:
                    l.append(i)
                    sum+=i
print(sum)
         
                   


n=int(input())
l=[]
sum=0
for i in range(1,n+1):
         if  i%3==0 and i%5 ==0:
                    l.apoend("FizzBuzz")
         elif i%3==0 and i%5!=0:
                    l.append("Fizz")
         elif i%5==0 and i%3!=0:
                    l.append("Buzz")
         elif i%3!=0 and i%5!=0:
                    l.append(i)
                    sum+=i
print(sum)
         
                   

n=int(input())
l=[]
sum=0
for i in range(1,n+1):
         if i%3!=0 and i%5!=0:
                    l.append(i)
                    sum+=i
print(sum)
         
                   


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
print(["FizzBuzz" if i%15==0 else "Fizz" if i%3==0 else "Buzz" if i%5==0 else i for i in range(1,int(input()))])


input_n = input()
N = int(input_n)
print(["FizzBuzz" if i%15==0 else "Fizz" if i%3==0 else "Buzz" if i%5==0 else i for i in range(1,N+1)])


print(["FizzBuzz" if i%15==0 else "Fizz" if i%3==0 else "Buzz" if i%5==0 else i for i in range(1,101)])


N = int(input())
sum = 0
for i in range(1,N+1):
    if i%15!=0 and i%3!=0 and i%5!=0:
         sum = sum + i
print(sum)


Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())
ans = 0
for i in range(1,i+1):
    if i % 3 != 0 and i % 5 != 0:
        ans += i
print(ans)

n=int(input())
ans = 0
for i in range(1,n+1):
    if i % 3 != 0 and i % 5 != 0:
        ans += i
print(ans)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
def main():
    n = int(input())
    ans = 0
    for i in range(n):
        if (i%3==0) and (i%5==0):
            continue
        if (i%3==0):
            continue
        if (i%5==0):
            continue
        ans += i
    print(ans)
main(

def main():
    n = int(input())
    ans = 0
    for i in range(1, n+1):
        if (i%3==0) and (i%5==0):
            continue
        if (i%3==0):
            continue
        if (i%5==0):
            continue
        ans += i
    print(ans)
main()

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
sum = 0
for i in range(N):
	if (i+1) % 5 != 0 and (i+1) % 3 != 0:
		sum += i
print(sum)

N = int(input())
sum = 0
for i in range(N):
	if (i+1) % 5 != 0 and (i+1) % 3 != 0:
		sum += i+1
print(sum)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
c=0
for i in range (1,N+1):
  if i%15==0:
    c += i//15
  elif i%3==0:
    c += i//3
  elif i%5==0:
    c += i//5
  else:
    c += i
    
print(c)
 
    
  

N = int(input())
c=0
for i in range (1,N+1):
  if i%15==0:
    c += 0
  elif i%3==0:
    c += 0
  elif i%5==0:
    c += 0
  else:
    c += i
    
print(c)
 
    
  


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
num = int(input())
a = [i for i in range(1,num)]
for f in a:
  if f % 3 == 0:
    del a[a.index(f)]
  elif f % 5 == 0:
    del a[a.index(f)]
print(sum(a))    

num = int(input())
a = [i for i in range(1, num + 1)]
for f in a:
  if f % 3 == 0:
    a.remove(f)
  elif f % 5 == 0:
    a.remove(f)
print(sum(a))    

n = int(input())
a = 0
for i in range(1, n+1):
  if i % 3 != 0 and i % 5 != 0:
    a += i
print(a)    

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
x = int(input())

if x % 3 == 0 and x % 5 == 0:
    print('FizzBuzz')
elif x % 3 == 0 and x % 5 != 0:
    print('Fizz')
elif x % 3 != 0 and x % 5 == 0:
    print('Buzz')
else:
    print(x)

x = int(input())

if x % 3 == 0 and x % 5 == 0:
    print('FizzBuzz')
elif x % 3 == 0 and x % 5 != 0:
    print('Fizz')
elif x % 3 != 0 and x % 5 == 0:
    print('Buzz')
else:
    print(str(x))


x = int(input())

if x % 3 == 0 and x % 5 == 0:
    print('FizzBuzz')
elif x % 3 == 0 and x % 5 != 0:
    print('Fizz')
elif x % 3 != 0 and x % 5 == 0:
    print('Buzz')
else:
    print(x)
    

x = int(input())

digit = 0
for i in range(x):
    x = i + 1

    if x % 3 == 0 and x % 5 == 0:
        continue
    elif x % 3 == 0 and x % 5 != 0:
        continue
    elif x % 3 != 0 and x % 5 == 0:
        continue
    else:
        digit += x



print(digit)

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
import sys
import numpy as np
n = int(input())
A = np.arrange(N+1)
count=0

for i in range(N+1):
  if A[i]%3 !=0 and A[i]%5 != 0 and A[i]%15 != 0:
	count = count + A[i]
print(count)

import sys
import numpy as np

N=int(input())
A=np.arange(N+1)
count = 0

for i in range(N+1):
    if A[i]%3 != 0 and A[i]%5 != 0 and A[i]%15 != 0:
        count = count + A[i]
print(count)


Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())
l=[]
for i in range(n+1):
    if i%3==0:
        pass
    elif i%5==0:
        pass
    elif i%15==0:
        pass
    else:
        l.append(i)
print('l',l)
        
print(sum(l))


n=int(input())
l=[]
for i in range(n+1):
    if i%3==0:
        pass
    elif i%5==0:
        pass
    elif i%15==0:
        pass
    else:
        l.append(i)

        
print(sum(l))


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
import sys
N=input()
N=int(N)
a=int(N/3)
b=int(N/5)
c=int(N/15)
S=N*(N+1)/2 - 3*a*(a+1)/2 - 5*b*(b+1)/2 + 15*c*(c+1)/2
print(S)

#b
import sys
N=input()
N=int(N)
a=int(N/3)
b=int(N/5)
c=int(N/15)
S=N*(N+1)/2 - 3*a*(a+1)/2 - 5*b*(b+1)/2 + 15*c*(c+1)/2
print(int(S))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
kazuof3 = N // 3
kazuof5 = N // 5
kazuof15 = N//15

ans = N * (N + 1) / 2 - kazuof3 * (kazuof3 + 1) * 3 / 2 - kazuof5 * (kazuof5 + 1) * 5 / 2 + kazuof15 * (kazuof15 + 1) * 15 / 2
print(ans)

N = int(input())
kazuof3 = N // 3
kazuof5 = N // 5
kazuof15 = N//15

ans = N * (N + 1) // 2 - kazuof3 * (kazuof3 + 1) * 3 //2 - kazuof5 * (kazuof5 + 1) * 5 // 2 + kazuof15 * (kazuof15 + 1) * 15 // 2
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
sum = 0
 
for i in range(n+1):
    if i % 3 == 0:
        print(Fizz)
    elif i % 5 == 0:
        print(Buzz)
    elif i % 15 == 0:
        print(FizzBuzz)
    else:
     sum += i
 
print (sum)

N = int,input()
sum = 0


for i in range(N):
    if i % 3 == 0:
        pass
    elif i % 5 == 0:
        pass
    elif i % 15 == 0 :
        pass
    else:
         sum +=  i

print(sum)


N = map(int,input().split())
sum = 0


for i in range(N):
    if i % 3 == 0:
        pass
    elif i % 5 == 0:
        pass
    elif i % 15 == 0 :
        pass
    else:
         sum +=  i

print(sum)


n = input()
N = int(n)
sum = 0

for i in range(N+1):
    if N % 3 == 0:
        print(Fizz)
    elif N % 5 == 0:
        print(Buzz)
    elif N % 15 == 0:
        print(FizzBuzz)
    else:
     sum += N

print (sum)

N = int(input())
sum = 0


for i in range(N+1):
    if i % 3 == 0:
        pass
    elif i % 5 == 0:
        pass
    elif i % 15 == 0 :
        pass
    else:
         sum +=  i

print(sum)


Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())
A=N//500
print(A)
B=N-A*500
print(A)

N=int(input())
ans=0
for i in range (N+1):
    if i%3!=0 and i%5!=0:
        ans=ans+i
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())

a=0
b=0
c=0

for i in range(1,n//3+1):
  a+=3*i

for i in range(1,n//5+1):
  b+=5*i
 
for i in range(1,n//15+1):
  c+=15*i
  
print(1/2*n*(n+1)-(a+b-c))


n=int(input())

a=0
b=0
c=0

for i in range(n//3):
  a+=3*i

for i in range(n//5):
  b+=5*i
 
for i in range(n//15):
  c+=15*i
 
print(1/2*n*(n+1)-(a+b-c))

n=int(input())

a=0
b=0
c=0

for i in range(1,n//3+1):
  a+=3*i

for i in range(1,n//5+1):
  b+=5*i
 
for i in range(1,n//15+1):
  c+=15*i

print(1//2*n*(n+1)-(a+b-c))

n=int(input())

a=0
b=0
c=0

for i in range(1,n//3+1):
  a+=3*i

for i in range(1,n//5+1):
  b+=5*i
 
for i in range(1,n//15+1):
  c+=15*i
  
print(int(1/2*n*(n+1)-(a+b-c)))


Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
a=input()
total=0
while i < a:
  if i %5 != 0 and i %3 != 0:
    total += a
 
	print(total)

a = int(input())
total=0
while i < a:
  if i %5 != 0 and i %3 != 0:
    total += a
print(total)

a = int(input())
total = 0
for i in range(1, a+1):
  if i % 5 != 0 and i % 3 != 0:
    total += a
print(total)

a = int(input())
total = 0
for i in range(1, a+1):
  if i % 5 != 0 and i % 3 != 0:
    total += a

print(total)

a=input()
total=0
while i < a:
  if i %5 != 0 and i %3 != 0:
    total += a

print(total)

a=input()
total=0
for i in range(1, a):
  if i %5 != 0 and i %3 != 0:
    total += a
print(total)

a = int(input())
while i < a:
  if i %5 != 0 and i %3 != 0:
    total += a
print(total)

a = int(input())
total = 0
while i < a:
  if i %5 != 0 and i %3 != 0:
    total += a
  else:
    continue
print(total)

a = int(input())
total = 0
for i in range(1, a+1):
  if i % 5 != 0 and i % 3 != 0:
    total += i

print(total)

Verdicts: Runtime Error

Runtime Error

Wrong Answer

Wrong Answer

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = input()

k = N // 3
l = N // 5
m = N // 15

sum = (N * (N + 1) / 2) - (3 * (-1 + 3**k)/2) - (5 * (-1 + 5**l)/4) + (15 * (-1 + 15**k)/14)
print(sum)

N = int(input())
 
k = N // 3
l = N // 5
m = N // 15
 
sum = (N * (N + 1) / 2) - (3* k * (k + 1) / 2) - (5* l * (l + 1) / 2) + (15* m * (m + 1) / 2)
print(int(sum))

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
answer = 0 

for i in range(1, n + 1):
    if i % 3 == 0 or i % 5 == 0:
        continue
    else:
        answer += i



n = int(input())
answer = 0
for i in range(1, n + 1):

    if n % 15 == 0:
        continue
    elif n % 3 == 0:
        continue
    elif n % 5 == 0:
        continue
    else:
        answer += i

print(answer)

n = int(input())
answer = 0 

for i in range(1, n + 1):
    if i % 3 == 0 or i % 5 == 0:
        continue
    else:
        answer += i

print(answer)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
ans = 0
for i in range(n+1):
    if (i % 3 != 0) or (i % 5 != 0):
        ans += 0
print(ans)

n = int(input())
ans = 0
for i in range(n+1):
    if (i % 3 != 0) and (i % 5 != 0):
        ans += 0
print(ans)

n = int(input())
ans = 0
for i in range(n+1):
    if (i % 3 != 0) and (i % 5 != 0):
        ans += i
print(ans)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())

sum = 0
for i in range(n+1):
    if i%3 != 0 and i%5 != 0:
        print(i)
        sum += i

print(sum)

n = int(input())

sum = 0
for i in range(n+1):
    if i%3 != 0 and i%5 != 0:
        sum += i

print(sum)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
def fizzbuzz_cul(number):
    if number % 15 == 0:
        return "FizzBuzz"
    if number % 3 == 0:
        return "Fizz"
    if number % 5 == 0:
        return "Buzz"
    return str(number)


def main():
    number = int(input())
    if 1 <= number <= 10 ** 6:
        result = fizzbuzz_cul(number)
        print(result)


if __name__ == '__main__':
    main()


def fizzbuzz_cul(number):
    if number % 15 == 0:
        return "FizzBuzz"
    if number % 3 == 0:
        return "Fizz"
    if number % 5 == 0:
        return "Buzz"
    return str(number)


def main():
    for number in range(1, 31):
        result = fizzbuzz_cul(number)
        print(result)


if __name__ == '__main__':
    main()


count = 0
for i in range(1, int(input()) + 1):
    if not(i % 5 == 0) and not(i % 3 == 0):
        count = count + i

print(count)




Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
import sys
n = int(sys.stdin.readline())
t = 0
for i in range(n):
  if i%3 != 0 or i%5 != 0:
    t += i
print(t)


import sys
n = int（sys.stdin.readline())
t = 0
for i in range(N):
  if i%3 != 0 or i%5 != 0:
    t += i
print(t)

import sys
n = int(sys.stdin.readline())
t = 0
for i in range(N):
  if i%3 != 0 or i%5 != 0:
    t += i
print(t)


import sys
n = sys.stdin.readline()
t = 0
for i in range(N):
  if i%3 != 0 or i%5 != 0:
    t += i
print(t)


import sys
n = int(sys.stdin.readline())
t = 0
for i in range(n+1):
  if i%3 != 0 and i%5 != 0:
    t += i
print(t)


Verdicts: Wrong Answer

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())

list = []

count = 1

for i in range(n):
  if count % 15 == 0:
    list.append(count)
  count += 1
    
print(sum(list))
    

N = int(input())

count = 0

for i in range(N):
	num = int(input())
    if num % 3 == 0 and num % 5 == 0:
    	continue
    elif num % 3 == 0:
    	continue
    elif num % 5 == 0:
    	continue
    else:
    	count += num

print(count)

n = int(input())

list = []

count = 1

for i in range(n):
  if count % 3 != 0 and count % 5 != 0:
    list.append(count)
  count += 1
    
print(sum(list))

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
ans = 0

for i in range(N + 1):
  if i % 15 == 0:
    ai = FizzBuzz
  if i % 3 == 0 and i % 5 =! 0:
    ai = Fizz
  if i % 3 =! 0 and i % 5 == 0:
    ai = Buzz
  else:
    ai = i
  
  ans = ans + ai

print(ans)


N = int(input())
ans = 0

for i in range(N + 1):
  if i % 15 == 0:
    ai = 0
  if i % 3 == 0 and i % 5 =! 0:
    ai = 0
  if i % 3 =! 0 and i % 5 == 0:
    ai = 0
  else:
    ai = i
  
  ans = ans + ai

print(ans)


N = int(input())
ans = 0

for i in range(N + 1):
  if i % 3 == 0 or i % 5 == 0:
    ai = 0 
  else:
    ai = i
  
  ans = ans + ai

print(ans)


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
(N*(N+1)/2)-(N//3*(N//3+1)/2)-(N//5*(N//5+1)/2)+(N//15*(N//15+1)/2)

N=int(input())
print(((N*(N+1))-(N//3*(N//3+1)*3)-(N//5*(N//5+1)*5)+(N//15*(N//15+1)*15))/2)

N=int(input())
print(str(((N*(N+1))-(N//3*(N//3+1)*3)-(N//5*(N//5+1)*5)+(N//15*(N//15+1)*15))/2))

print((N*(N+1)/2)-(N//3*(N//3+1)/2)-(N//5*(N//5+1)/2)+(N//15*(N//15+1)/2))


N=int(input())
print((N*(N+1)/2)-(N//3*(N//3+1)/2)-(N//5*(N//5+1)/2)+(N//15*(N//15+1)/2))



N=int(input())
print(((N*(N+1))-(N//3*(N//3+1)*3)-(N//5*(N//5+1)*5)+(N//15*(N//15+1)*15))/2)

N=int(input())
print(str((N*(N+1)/2)-(N//3*(N//3+1)/2)-(N//5*(N//5+1)/2)+(N//15*(N//15+1)/2)))

print((N*(N+1)/2)-((N//3)*((N//3)+1)/2)-((N//5)*((N//5)+1)/2)+((N//15)*((N//15)+1)/2))


N=int(input())
print(((N*(N+1))-(N//3*(N//3+1)*3)-(N//5*(N//5+1)*5)+(N//15*(N//15+1)*15))//2)

Verdicts: Runtime Error

Wrong Answer

Wrong Answer

Runtime Error

Wrong Answer

Wrong Answer

Wrong Answer

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
ef to_fizzbuzz(number):
    if number % 15 == 0:
        return 'FizzBuzz'

    if number % 3 == 0:
        return 'Fizz'

    if number % 5 == 0:
        return 'Buzz'

    else:
        return str(number)
        # return i

def main():
    N = int(input())
    
    fblist = []
    for number in range(1, 10**6):
        result = to_fizzbuzz(number)
        fblist.append(result)

        # print(fblist)

    
    n_list = fblist[0:N]
    

    n_numlist = []

    for s in n_list:
        if s.isdigit() == True:
            n_numlist.append(int(s))

    print(sum(n_numlist))

main()

def to_fizzbuzz(number):
    if number % 15 == 0:
        return 'FizzBuzz'

    if number % 3 == 0:
        return 'Fizz'

    if number % 5 == 0:
        return 'Buzz'

    else:
        return str(number)
        # return i

def main():
    N = int(input())
    # this list concludes "FizzBuzz", "Fizz" or "Buzz"
    fblist = []
    for number in range(1, 10**6):
        result = to_fizzbuzz(number)
        fblist.append(result)

    # the list up to N
    n_list = fblist[0:N]
    # this list contains only numbers and up to N

    n_numlist = []

    for s in n_list:
        if s.isdigit() == True:
            n_numlist.append(int(s))

    print(sum(n_numlist))


main()

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
asn=int(0)
for i in range(int(input())):
    if i%3!=0 and i%5!=0:
        ans+=i
print(ans)

ans=int(0)
for i in range(int(input())+1):
    if i%3!=0 and i%5!=0:
        ans+=i
print(ans)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())

sum = 0
for i in range(1, N+1):
    if i != 3 and i != 5:
        sum += i

print(sum)


N = int(input())

sum = 0
for i in range(1, N+1):
    if (i % 3 != 0) and (i % 5 != 0):
        sum += i

print(sum)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
c = 0
for i in range(1, N+1):
  if i % 3 != 0 and i%5 != 0:
    c += i
print(i)

N = int(input())
c = 0
for i in range(1, N+1):
  if i % 3 != 0 and i%5 != 0:
    c += i
print(c)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
total = 0
for i in range(1,N+1):
	if i%3!=0 and i%5!=0:
    	total = total + 1
print(total)

N = int(input())
total = 0
for i in range(1,N+1):
	if i%3!=0 and i%5!=0:
    	total += i
print(total)

N = int(input())
total = 0
for i in range(1,N+1)
    if (i%3) != 0 and (i%5) ! =0:
        total += i
print(total)

N = int(input())
total = 0
for i in range(1,N+1):
	if N%3!=0 and N%5!=0:
    	total += i
print(total)    

N = int(input())
total = 0
for i in range(1,N+1):
	if i%3!=0 and i%5!=0:
    	total +=i
print(total)

N = int(input())
total = 0
for i in range(1,N+1)
    if i%3 != 0 and i%5 ! =0:
        total += i
print(total)

N = int(input())
total = 0
for i in range(1,N+1):
	if i%3 != 0 and i%5! = 0:
		total += i
print(total)    

N = int(input())
total = 0
for i in range(1,N+1)
    if i%3!=0 and i%5!=0:
        total += i
print(total)

N = int(input())
total = 0
for i in range(1,N+1):
	if i%3!=0 and i%5!=0:
    	total += i
print(total)    

N = int(input())
a = 0
for i in range(1, N+1):
  if (i % 3) != 0 and (i % 5) != 0:
    a += i
print(a)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())
j = 0
for i  in range(1,N + 1):
    if i % 3 == 0 and i % 5 == 0:
        print('FizzBuzz')
    elif i % 3 == 0:
        print('Fizz')
    elif i % 5 == 0:
        print('Buzz')
    else:
        print(i)
        j = j + i

print(j)

N = int(input())
j = 0
for i  in range(0,N + 1):
    if i % 3 == 0 and i % 5 == 0:
        print('FizzBuzz')
    elif i % 3 == 0:
        print('Fizz')
    elif i % 5 == 0:
        print('Buzz')
    else:
        print(i)
        j = j + i

    print(j)

N = int(input())
j = 0
for i  in range(1,N + 1):
    if i % 3 == 0 and i % 5 == 0:
        pass 
    elif i % 3 == 0:
        pass 
    elif i % 5 == 0:
        pass 
    else:
        # print(i)
        j = j + i

print(j)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())
l = 1
li = []
while l < n+1:
  if l % 3 == 0 and l % 5 == 0 or l % 3 == 0 or l % 5 == 0:
    li.append(l)
    l+=1
  else:
    li+-1

print(li)
    

n = int(input())
l = 1
li = []
while l < n+1:
  if l % 3 == 0 and l % 5 == 0 or l % 3 == 0 or l % 5 == 0:
    li.append(l)
    l+=1
  else:
    li+=1

print(li)
    

n = int(input())
l = 1
li = []
while l < n+1:
  if l % 3 == 0 and l % 5 == 0 or l % 3 == 0 or l % 5 == 0:
    l+=1
  else:
    li.append(l)
    l+=1

print(sum(li))

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())

sum = (1+n)*n/2

n3 = n//3
n5 = n//5
n15 = n//15

sum3 = (1+n3)*n3/2 * 3
sum5 = (1+n5)*n5/2 * 5
sum15 = (1+n15)*n15/2 * 15

sum = sum + sum15 -sum3 -sum5

print(sum)

n = int(input())
 
sum = (1+n)*n/2
 
n3 = n//3
n5 = n//5
n15 = n//15
 
sum3 = (1+n3)*n3/2 * 3
sum5 = (1+n5)*n5/2 * 5
sum15 = (1+n15)*n15/2 * 15
 
sum = sum + sum15 -sum3 -sum5
 
print(int(sum))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
import numpy as np
N = int(input())
b = [i+1 for i in range(N)]
a = np.array(b)

c =[]

for i in range(N):
    if a[i] % 3 == 0:
        c.append(a[i])
    if a[i] % 5 == 0:
        c.append(a[i])
    if a[i] % 15 == 0:
        c.append(-a[i])

sum(c)

import numpy as np
N = int(input())
b = [i+1 for i in range(N)]
a = np.array(b)

c = a - a//3 *3
d = a - a//5 *5

e = c*d
sum(a*(e!=0))

import numpy as np
N = int(input())
b = [i+1 for i in range(N)]
a = np.array(b)

c = a - a//3 *3
d = a - a//5 *5

e = c*d
sum(a*(e!=0))


import numpy as np
N = int(input())
b = [i+1 for i in range(N)]
a = np.array(b)

c = a - a//3 *3
d = a - a//5 *5

e = c*d
print(sum(a*(e!=0)))


Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n = int(input())

s = 0
for i in range(1, n + 1):
    if i % 3 == 0 and i % 5 == 0:
        s += i
       
print(s)

n = int(input())

s = 0
for i in range(1, n + 1):
    if not i % 3 == 0 and not i % 5 == 0:
        s += i
       
print(s)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
sum = 0
for i in range(1, 10 ** 6 + 1):
    if i % 3 != 0 and i % 5 != 0:
        sum += i
print(sum)

n = int(input())
sum = 0

for i in range(1, n + 1):
    if i % 3 != 0 and i % 5 != 0:
        sum += i

print(sum)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = map(int,input().split())
fizz = list()
for i in range(N):
    if i // 3 == 0 and i // 5 == 0:
        i = FizzBuzz
    elif i // 3 == 0: 
        i = Fizz
    elif i // 5 == 0:
        i = Buzz
    else:
        fizz.append(i)
print(sum(fizz))

N = map(int,input().split())
fizz = list()
for i in range(N):
    if i // 3 = 0 and i // 5 = 0:
        i = FizzBuzz
    elif i // 3 = 0 
        i = Fizz
    elif i // 5 = 0
        i = Buzz
    else:
        fizz.append(i)
print(sum(fizz))

N = int(input())
a = 0
for i in range(N+1):
    if not i % 3==0 or not i % 5 == 0:
        a += i
print(a)

N = input()
fizz = list()
for i in range(int(N)):
    if i // 3 == 0 and i // 5 == 0:
        continue
    elif i // 3 == 0: 
        continue
    elif i // 5 == 0:
        continue
    else:
        fizz.append(i)
print(sum(fizz))

N = input()
fizz = list()
for i in range(int(N+1)):
    if not i // 3==0 or not i//5==0:
        fizz.append(i)
print(sum(fizz))

N = input()
fizz = list()
for i in range(int(N)):
    if not i // 3==0 and i//5==0
        fizz.append(i)
print(sum(fizz))

N = map(int,input().split())
fizz = list()
for i in range(N):
    if i // 3 = 0 and i // 5 = 0:
        i = FizzBuzz
    elif i // 3 = 0 
        i = Fizz
    elif i // 5 = 0
        i = Buzz
    else:
        fizz.append(i)
print(sum(fizz))

N = input()
fizz = list()
for i in range(int(N)):
    if not i // 3==0 and not i//5==0:
        fizz.append(i)
print(sum(fizz))

N = map(int,input().split())
fizz = list()
for i in range(N):
    if i // 3 = 0 and i // 5 = 0:
        i = FizzBuzz
    elif i // 3 = 0 
        i = Fizz
    elif i // 5 = 0
        i = Buzz
    else:
        fizz.append(i)
print(sum(fizz))

N = int(input())
a = 0
for i in range(N+1):
    if i % 3 != 0 and i % 5 != 0:
        a += i
print(a)

Verdicts: Runtime Error

Runtime Error

Wrong Answer

Wrong Answer

Runtime Error

Runtime Error

Runtime Error

Wrong Answer

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())
ans = 0
for i in range(1, N+1):
  ans += (i % 5 % 3)
  
print(ans)

N=int(input())
ans = 0
for i in range(1, N+1):
    if min(i % 5 , i % 3) == 0:
        continue
    else:
        ans += i
  
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
a=int(input("a"))
b=(sum(range(3,a+1,3)))
c=(sum(range(5,a+1,5)))
d=(sum(range(15,a+1,15)))
e=a*(a+1)/2
print(int(e-b-c+d))

a=int(input())
b=(sum(range(3,a+1,3)))
c=(sum(range(5,a+1,5)))
d=(sum(range(15,a+1,15)))
e=a*(a+1)/2
print(int(e-b-c+d))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
from sys import stdin



N = int(stdin.readline().rstrip().split()[0])
Sum = 0

for i in range(1, N+1):
    if i % 3 == 0 or i % 5 == 0 or i % 15 == 0:
        continue
    else:
        Sum += i
        print(i)

print(Sum)

from sys import stdin



N = int(stdin.readline().rstrip().split()[0])
Sum = 0

for i in range(1, N+1):
    if i % 3 == 0 or i % 5 == 0 or i % 15 == 0:
        continue
    else:
        Sum += i

print(Sum)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())
s=0
for i in range(1,n+1):
  if i%3==0 and i%5==0:
    s+=i
print(s)

n=int(input())
s=0
for i in range(1,n+1):
  if i%3!=0 and i%5!=0:
    s+=i
print(s)

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
# coding: utf-8
# Your code here!
# coding: utf-8
import sys
sys.setrecursionlimit(10000000)

#const
dxdy=((1,0),(0,1))
# my functions here!
def pin(type=int):
    return map(type,input().rstrip().split())

def resolve():
    k,=pin()
    ans=0
    for i in range(1,k+1):
        if i%3!=0 and i%5!=0:
            ans+=i
    print(ans)
    
    


import sys
from io import StringIO
import unittest


class TestClass(unittest.TestCase):
    def assertIO(self, input, output):
        stdout, stdin = sys.stdout, sys.stdin
        sys.stdout, sys.stdin = StringIO(), StringIO(input)
        resolve()
        sys.stdout.seek(0)
        out = sys.stdout.read()[:-1]
        sys.stdout, sys.stdin = stdout, stdin
        self.assertEqual(out, output)

    def test_入力例_1(self):
        input = """15"""
        output = """60"""
        self.assertIO(input, output)

    def test_入力例_2(self):
        input = """1000000"""
        output = """266666333332"""
        self.assertIO(input, output)


if __name__ == "__main__":
   　resolve()


# coding: utf-8
# Your code here!

# coding: utf-8
# Your code here!
# coding: utf-8
import sys
sys.setrecursionlimit(10000000)

#const
dxdy=((1,0),(0,1))
# my functions here!
def pin(type=int):
    return map(type,input().rstrip().split())

def resolve():
    k,=pin()
    ans=0
    for i in range(1,k+1):
        if i%3!=0 and i%5!=0:
            ans+=i
    print(ans)
    
    


import sys
from io import StringIO
import unittest


class TestClass(unittest.TestCase):
    def assertIO(self, input, output):
        stdout, stdin = sys.stdout, sys.stdin
        sys.stdout, sys.stdin = StringIO(), StringIO(input)
        resolve()
        sys.stdout.seek(0)
        out = sys.stdout.read()[:-1]
        sys.stdout, sys.stdin = stdout, stdin
        self.assertEqual(out, output)

    def test_入力例_1(self):
        input = """15"""
        output = """60"""
        self.assertIO(input, output)

    def test_入力例_2(self):
        input = """1000000"""
        output = """266666333332"""
        self.assertIO(input, output)


if __name__ == "__main__":
    resolve()


Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
import numpy
a = np.array([i for i in range(1, int(input())+1)])
print(a[np.where((a % 3 != 0) & (a % 5 !=0))].sum())

import numpy as np
a = np.array([i for i in range(1, int(input())+1)])
print(a[np.where((a % 3 != 0) & (a % 5 !=0))].sum())

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = int(input())

a = N//15
b = N%15
c = 0

for i in range(b+1):
  if i%3!=0 and i%5!=0:
    c=c+i+15*a

ans=(120*(a*(a-1)/2))+60*(a)+c

print(ans)

N = int(input())

a = N//15
b = N%15
c = 0

for i in range(b+1):
  if i%3!=0 and i%5!=0:
    c=c+i+15*a

ans=(120*(a*(a-1)/2))+60*(a)+c

print(int(ans))

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
num = int(input())
ans = 0
for i in range(num):
  i = i + 1
  if(i%3!=0 and i%5!=0):
    ans += i 
    print(i)
print(ans)
    

num = int(input())
ans = 0
for i in range(num):
  i = i + 1
  if(i%3!=0 and i%5!=0):
    ans += i 
print(ans)
    

Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
n=int(input())
c=0
for i in (0,n):
  if i%3==0 and i%5==0:
    c+=i
print(c)


n=int(input())
c=0
for i in range(0,n+1):
  if i%3!=0 and i%5!=0:
#    print(i)
    c+=i
print(c)


Verdicts: Wrong Answer

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N=int(input())
  total=0
  for i in range (1,N+1):
if i%3!=0 and i%5=0
  total+i
  print(total)

N=int(input())
  total=0
  for i in range (1,N+1):
if i%3!=0 and i%5=0
  total+=i
  print(total)

N = int(input())
total = 0
for i in range(1, N+1):
    if i % 3 != 0 and i % 5 != 0:
        total += i
print(total)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
N = input()


count = 0
for i in range(N):
    if N % 15 == 0:
        continue
    elif N % 3:
        continue
    elif N % 5:
        continue
    else:
        count += i
print(count)

N = int(input())


c = 0
for i in range(1,N+1):
    if i % 15 == 0:
        continue
    elif i % 5 == 0:
        continue
    elif i % 3 == 0:
        continue
    else:
        c += i

print(c)

Verdicts: Runtime Error

Accepted
Problem: Let us define the **FizzBuzz sequence** a_1,a_2,... as follows:    * If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.   * If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.   * If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.   * If none of the above holds, a_i=i.  Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Submission attempts (in order):
count = 0
for i in range(1, 61):
  if i%3 and i%5:
    count += i
print(count)

count = 0
n = int(input())
for i in range(1, n+1):
  if i%3 and i%5:
    count += i
print(count)

Verdicts: Wrong Answer

Accepted