TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
S=str(input())
T=int(input())
ans=0
for i in range (3)
	if S[i]==T[i]:
    	ans=ans+a
print(ans)

S=str(input())
T=str(input())
ans=0
for i in range (3):
    if S[i]==T[i]:
        ans=ans+1
print(ans)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
n = int(input())
inp = list(map(int, input().split()))
length = len(inp)
ans = 0
curr_max = 0
for i in range(-1,-length,-1):
    if inp[i] <= inp[i-1]:
        ans += 1
        if ans > curr_max:
            curr_max = ans
    else:
        ans = 0
print(curr_max)

s = input()
t = input()
ans = 0
for i in range(3):
    if s[i] == t[i]:
        ans += 1
print(ans)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
# -*- coding: utf-8 -*-
n = int(input())
nt = []
for i in range(n):
  tmp = input().split()
  for j in range(n-1):
    tmp[j] = int(tmp[j])
  nt.append(tmp)

day = 0
j = []
for i in range(n):
  j.append(0)
  
while(True):
  #print(j)
  tmp = []
  for i in range(n):
    if j[i] < n-1 and nt[nt[i][j[i]]-1][j[nt[i][ j[i] ]-1]] == i+1:
      tmp.append(i)
  #print(tmp)
  if len(tmp) == 0:
    break
  for i in tmp:
    j[i] += 1
  day += 1
  
error = 0
for i in range(n):
  if j[i] != n-1:
    day = -1

print(day)

# -*- coding: utf-8 -*-
y = input()
t = input()
ylist = list(y)
tlist = list(t)
seikai = 0
for i in range(3):
  if ylist[i] == tlist[i]:
    seikai += 1
    
print(seikai)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
S,T=input().split()
count=0
for i in range(3):
  if S[i] == T[i]:
    count += 1
print(count)

S = input()
T = input()
count=0
for i in range(3):
  if S[i] == T[i]:
    count += 1
print(count)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
N = int(input())
H = [int(x) for x in input().split()]
x = 1
ans = 1

for i in range(1,len(H)):
    if H[i] <= H[i-1]:
        x += 1
        if x > ans:
            ans = x
    else:
        x = 1
print(ans)

S = input()
T = input()
c = 0
for i in range(3):
    if S[i] == T[i]:
        c += 1
print(c)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
# -*- coding: utf-8 -*-
S = str(input())
T = str(input())

counter = 0
for i in range(S):
    if S[i] == T[i]:
        counter += 1

print(counter)

# -*- coding: utf-8 -*-
S = str(input())
T = str(input())

counter = 0
for i in range(len(S)):
    if S[i] == T[i]:
        counter += 1

print(counter)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
S=input()
T=input()

output=0

for i in range(3):
    if int(S[0,i])==int(T[0,i]):
        output=output+1
    else :
        pass
    
print(output)

S=input()
T=input()

output=0

for i in range(3):
    if S[0,i]==T[0,i]:
        output=output+1
    else :
        pass
    
print(output)
        

S=input()
T=input()

output=0

for i in range(3):
    if S[i]==T[i]:
        output=output+1
    else :
        pass
    
print(output)
        

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
N=int(input())
H=list(map(int,input().split()))
ans=0
tmp=0
for i in range(N-1):
  if H[i]>=H[i+1]:
    tmp+=1
  else:
    tmp=0
  anｓ=max(tmp,ans)
  
print(ans)


S = input()
T = input()
count = 0
for i in range(3):
    if S[i] == T[i]:
        count += 1
print(count)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
x = input("Enter the forecast: ")
y = input("Enter the actual weather: ")

success=0
for cnt in range(3):
    if x[cnt]==y[cnt]:
        success+=1
    
print(success)


S = input()
T = input()
count = 0
for i in range(0,3):
    if S[i] == T[i]:
        count +=1
print(count)


Verdicts: Wrong Answer

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
import sys
a = sys.stdin.readline().rstrip()
b = sys.stdin.readline().rstrip()
i = 0
cnt = 0
while i <= 3:
  cnt += 1 if a[i] == b[i] else 0
  i += 1
print(cnt)

import sys
a = sys.stdin.readline().rstrip()
b = sys.stdin.readline().rstrip()
i = 0
cnt = 0
while i <= 2:
  cnt += 1 if a[i] == b[i] else 0
  i += 1
print(cnt)


Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
#!/usr/bin/env python
# -*- coding: utf-8 -*-

from sys import stdin
import math


int_list  = [int(x) for x in stdin.readline().rstrip().split()]

N = int_list[0]


total = int(N*(N-1)/2)
print(total)


#!/usr/bin/env python
# -*- coding: utf-8 -*-
 
from sys import stdin
import math
 

#int_list  = [int(x) for x in stdin.readline().rstrip().split()]
N = int(input())
 
total = int(N*(N-1)/2)
print(total)

#!/usr/bin/env python
# -*- coding: utf-8 -*-

from sys import stdin
import math


S = stdin.readline()
T = stdin.readline()

cnt=0
for i in range(3):
    if S[i] == T[i]:
        cnt+=1


print(cnt)


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
import math

a,b = map(int, input().split())
av = num =  a
n = 1
if num < b:
  n+=1
  num = num+av-1
elif num > b:
  pass
print(n)

a = str(input())
b = str(input())
n = 0
for sa in a:	
  if sa == b[n]:
    print(sa+'='+b[n])
  else:
    print(sa+'≠'+b[n])
  n +=1

import math

a,b = map(int, input().split())
av = num =  a
n = 1
while num =< b:
  n+=1
  num = num+av-1
print(n)

a = str(input())
b = str(input())
#print(a[n])
#print(b[n])
x=0
for n in range(3):
  if a[n] == b[n]:
    x+=1
print(x)

Verdicts: Runtime Error

Wrong Answer

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s = input()
t = input()
ans = 0
for i in range(3):
	if s[i] == t[i]:
        ans += 1
print(ans)

s = input()
t = input()
ans = 0
for i in range(3):
	if s[i] == t[i]:
    	ans += 1
print(ans)

s = input()
t = input()
ans = 0
for i in range(3):
    if s[i] == t[i]:
        ans += 1
print(ans)


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
days = list(str(input()))
days_real = list(str(input()))
for i in range(3):
  if days[i] == days_real[i]:
    count += 1
print(count)

days = list(str(input()))
days_real = list(str(input()))
count = 0
for i in range(3):
  if days[i] == days_real[i]:
    count += 1
print(count)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
a, b = map(int, input().split())

need = 1
tap = a


while tap < b:
	if a == 0 or a == 1 or b < a or b == 0:
		need = 0
		break
	tap += (a - 1)
	need += 1
print (need)


s = input()
t = input()

cnt = 0
if s[0] == t[0] :
	cnt += 1

if s[1] == t[1] :
	cnt += 1

if s[2] == t[2] :
	cnt += 1

print (cnt)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
num = list(input().split(" "))
a = int(num[0])
b = int(num[1])

count = 1

while True:
  if count == 1:
  	plug = a
  else:
    plug = plug + (a - 1) 
  if plug >= b:
    break
  count += 1

print(count)

cnt = int(input())
nums = list(input().split(" "))
current = 0
maxCnt = 0

for i in range(cnt - 1):
  if int(nums[i]) >= int(nums[i+1]):
    current += 1
  else:
    if maxCnt < current:
    	maxCnt = current
    current = 0

if maxCnt < current:
  maxCnt = current

print(maxCnt)

s = input()
s2 = input()
cnt = 0
for st, st2 in zip(s, s2):
  if st == st2:
    cnt += 1
  
print(cnt)

  

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
import numpy as np


def main():
	#N, D = [int(x) for x in input().split()]
	S = input()
	T = input()

	print(S, T)
	count = 0
	for s, t in zip(S, T):
		if s == t:
			count += 1
	print(count)
	
if __name__ == "__main__":
	main()


import numpy as np


def main():
	#N, D = [int(x) for x in input().split()]
	S = input()
	T = input()

	count = 0
	for s, t in zip(S, T):
		if s == t:
			count += 1
	print(count)
	
if __name__ == "__main__":
	main()


Verdicts: Wrong Answer

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
S = input()
T = input()

count = 0

for i,j in S,T:
  if S[i] == T[j]:
    count +=1
print(count)


S = input()
T = input()

count = 0

for i in S,T:
  if S[i] == T[i]:
    count +=1
print(count)

S = input()
T = input()

count = 0

if S[0] == T[0]:
  count += 1
if S[1] == T[1]:
  count +=1
if S[2] == T[2]:
  count +=1
print(count)


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
S=input()
T=input()
ans=0
for i in range(3):
  if(S[i]==T[i])ans+=1
print(ans)

S=input()
T=input()
ans=0
for i in range(3):
  if S[i]==T[i]:
    ans+=1
print(ans)


Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s = input()
t = input()

ans = 0
for i in range(len(s)):
  if s[i] == t[i]:
    ans += 1
print ans


s = input()
t = input()

ans = 0
for i in len(s):
  if s[i] == t[i]:
    ans += 1
print ans

s = input()
t = input()
ans = 0
for i in range(len(s)):
  if s[i] == t[i]:
    ans += 1
print(ans)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
n = int(input())
if n > 1:
    ans = n*(n-1)/2
else:
    ans = 0
print(ans)

s = input()
t = input()
c = 0
for i in range(3):
    if s[i] == t[i]:
        c+=1
print(c)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
S = list(map(input()))
T = list(map(input()))
ctr = 0
for i in range (3):
  if S[i] == T[i]:
    ctr += 1
print(ctr)

S = list(input())
T = list(input())
ctr = 0
for i in range (3):
  if S[i] == T[i]:
    ctr += 1
print(ctr)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s = list(input())
t = list(input())

cnt = 0
for i in range(2)
    if s[i]==s[t]:
        cnt =+1
print(cnt)

s = list(input())
t = list(input())

cnt = 0
for i in range(2):
    if s[i]==s[t]:
        cnt =+1
print(cnt)


s = list(input())
t = list(input())

cnt = 0
for i in range(len(s)):
    if s[i] == t[i]:
        cnt += 1
        continue
print(cnt)


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
a = input()
b = input()
count = 0
for i in renge(3):
	if a[i] == b[i]:
    	count += 1
print(count)


a = str(input())
b = str(input())
count = 0
for i in renge(3):
	if a[i] == b[i]:
    	count += 1
print(count)


a = input()
b = input()
count = 0
for i in renge(3):
	if a[i] == b[i]:
    	count += 1
print(count)


a = str(input())
b = str(input())
count = 0
for i in renge(3)
	if a[i] == b[i]:
    	count += 1
print(count)


a = input()
b = input()
count = 0
for i in renge(3)
	if a[i] == b[i]:
    	count += 1
print(count)

s, t = [input() for _ in range(2)]

count = 0
for i in range(3):
		if s[i] == t[i]:
				count += 1

print(count)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
A , B = map(int , input().split())

plug = 1
tap = 0

for i in range():
    if plug >= B:
        break
    else:
        prug += A - 1
        tap += 1

print(tap)

S = input()
T = input()

result = 0

for i in range(0,3):
    if S == T:
        result += 1

print (result)

A , B = map(int , input().split())

plug = 1
tap = 0

for i in range(20):
    if plug >= B:
        break
    else:
        prug += A - 1 and tap += 1

print(tap)

S = input()
T = input()

result = 0
for i in range(0,3):
    if S[i] == T[i]:
        result += 1

print (result)

Verdicts: Runtime Error

Wrong Answer

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s=input()
t=input()
for i in range(3)
ans=0
if s[i]==t[i]:
  ans+=1
print(ans)

s=input()
t=input()
ans=0
for i in range(3):
  if s[i]==t[i]:
    ans+=1
print(ans)


Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
S = [str(i) for i in input().split()]
T = [str(i) for i in input().split()]
ans = 0
for i in range(len(S)):
    if S[i] == T[i]:
        ans +=1
print(ans)

S = str(input())
T = str(input())
ans = 0
for i in range(0, 3):
    if S[i] == T[i]:
        ans += 1
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
N = int(input())
HL = list(map(int,input().split()))
HL.append(10**9+1)  
cnt = 0
tmp_c = 0

for i in range(N):
    if HL[i] >= HL[i+1]:
        tmp_c += 1
    else:
        if cnt <= tmp_c:
            cnt = tmp_c
            tmp_c = 0
        else:
            tmp_c = 0

print(cnt)

S = input()
T = input()
ans = 0

if S[0] == T[0]:
    ans += 1
if S[1] == T[1]:
    ans += 1
if S[2] == T[2]:
    ans += 1

print(ans)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
S,T=map(str,input().split())
count=0
for i in range(len(S)):
    if S[i]==T[i]:
        count+=1
print(count)

S,T=map(str,input().split())
count=0
for i in range(3):
    if S[i]==T[i]:
        count+=1
print(count)

S=str(input())
T=str(input())
count=0
for i in range(3):
    if S[i]==T[i]:
        count+=1
print(count)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
def main():
    N = int(input())
    B = [int(x) for x in input().split()]
    A = [0] * N
    A[0] = B[0]
    A[N-1] = B[-1]
    for i in range(1, N-1):
        if B[i - 1] <= B[i]:
            A[i] = B[i - 1]
        else:
            A[i] = B[i]
    print(sum(A))


if __name__ == "__main__":
    main()


def main():
    S = input()
    T = input()
    ans = 0
    for i in range(3):
        if S[i] == T[i]:
            ans += 1
    print(ans)

if __name__ == "__main__":
    main()

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):

def MAP():
    return map(int, input().split())

a,b=MAP()

t=1
cnt=0
while True:
    if b <= t:
        break
    t -= 1
    t += a
    cnt += 1
print(cnt)

s=input()
t=input()

cnt=0
for i in range(3):
    if s[i] == t[i]:
        cnt+=1
print(cnt)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
a =input().split()
b =input().split()
count=0
for i in range(a):
  if a[i] ==b[i]:
    count =+1
print(count)

a =list(input())
b =list(input())
count=0
for i in range(len(a)):
  if a[i] ==b[i]:
    count +=1
print(count)


Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
A,B = input().split()

A_ch = int(A)
B_ch = int(B)

cal = B_ch - A_ch
i = 0
n = 1
try:
    while (cal + i) > 0:
        n += 1
        i += 1
        cal = B_ch - A_ch * n - n
        
except:
    i = 1
print(i)

S = input()
T = input()

x = 0

for i in range(3):
    if S[i] == T[i]:
        x = x + 1

print(x)        

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
#ABC090
s = input()
t = input()
ans = 0
if s[0]=t[0]:
    ans+=1
if s[1]=t[1]:
    ans+=1
if s[2]=t[2]:
    ans+=1
print(ans)    

#ABC090
s = input()
t = input()
ans = 0
if s[0]==t[0]:
    ans+=1
if s[1]==t[1]:
    ans+=1
if s[2]==t[2]:
    ans+=1
print(ans)    


Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s=input()
t=input()
a=0
for i in range(3):
  if s[i]==s[t]:
    a+=1
print(a)

s=input()
t=input()
a=0
for i in range(3):
  if s[i]==t[i]:
    a+=1
print(a)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
S = input()
T = input()
ans = 0
for i in range(3):
  is S[i] == T[i]:
    ans += 1
print(ans)

S = input()
T = input()
ans = 0
for i in range(3):
  if S[i] == T[i]:
    ans += 1
print(ans)


Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
N = int(input())
H = list(map(int,input().split()))

l = len(H)
L = [0]
for i in range(l-1):
    if H[i] < H[i+1]:
        L.append(i)

L.append(l-1)

jump = [L[i+1] - L[i] - 1 for i in range(len(L)-1)]
print(max(jump))


S = list(input())
T = list(input())
ans = 0
for i in range(3):
  if S[i] == T[i]:
    ans += 1

print(ans)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s = input()
t = input()

for i in range len(s):
  if s[i] == t[i]:
    count +=
    print(count)
    
  else:
    print(0)

s = input()
t = input()


for i in range 3:
  if s[i] == t[i]:
    count += 1
    print(count)

a,b = map(int,input().split())

res = b // a + 1

if a == b:
  res = 1
  
print(res)


s = input()
t = input()
count = 0

for i in range(3):
  if s[i] == t[i]:
    count += 1

print(count)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
S,T = input().split()

count=0

for i in range(3):
    if S[i]==T[i]:
      count=count+1
print(count)

S= input()
T= input()
count=0

for i in range(3):
    if S[i]==T[i]:
      count=count+1
print(count)


Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s=input()
t=input()
num=0

for i in range(3):
  if s[i]==t[i]:
    num=num+1

num

s=input()
t=input()
num=0

for i in range(3):
  if s[i]==t[i]:
    num=num+1

print(num)

Verdicts: Wrong Answer

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
    S=input()
    T=input()
    a=0
    for i in range(3):
        if S[i]==T[i]:
            a+=1
    print(a)

S=input()
T=input()
a=0
for i in range(3):
    if S[i]==T[i]:
            a+=1
print(a)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
S=list(map(int.input().split()))
T=list(map(int.input().split()))
x==0
for i in range(2):
  if S[i]==T[i]:
    x=x+1
  else:
    x=x
print(x)    
  

n=int(input())
h=list(map(int,input().split()))
x=[]
y=0
for i in range (n-1):
  if h[i]>=h[i+1]:
    y+=1
    x.append(y)
    elif h[i]<h[i+1] :
    x.append(y)
    y=0
print(max(x))
  

S=input()
T=input()
x=0
for i in range(3):
  if S[i]==T[i]:
    x=x+1
  else:
    x=x
print(x)    


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
print(sum(int(i==j) for i,j in zip(*open(0))))

print(sum(i==j for i,j in zip(*open(0))))

print(sum(i==j for i,j in zip(*open(0))))

print(sum(i==j for i,j in zip(*open(0))))

print(sum(i==j for i,j in zip(*open(0))))

print(3-sum(i!=j for i,j in zip(*open(0))))

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
a, b=list(map(int,input().split()))
count=0
for i in range(0,21):
    if i*a<= b:
        count=count+1
print(count)

s=str(input())
t=str(input())
count=0
for i in range(0,3):
    if s[i]==t[i]:
        count=count+1
print(count)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s = input()
t = input()
count=0
for i in s:
    for j in t:
        if s==t:
            count+=1
print(count)

s = input()
t = input()
count=0
for i in range(0,3):
    if s[i] == t[i]:
        count+=1
print(count)

Verdicts: Wrong Answer

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s = input()
t = s[1]
s = s[0]
count = 0
for i in range(3):
	if s[i] == t[i]:
		count += 1

print(count)

s = input()
t = input()
count = 0
for i in range(3):
	if s[i] == t[i]:
		count += 1

print(count)


Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
N = int(input())
ans = N*(N-1)//2
print(int(ans))

pre = input()
gen = input()
ans=0
for i,k in zip(pre, gen):
    if i==k:
        ans+=1
print(ans)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s=list(int(input()))
t=list(int(input()))
count = 0
for i in range(len(s)):
  if s[i] == t[i]:
    count += 1
print(int(count))

s=list(input())
t=list(input())
count = 0
for i in range(len(s)):
  if s[i] == t[i]:
    count += 1
print(int(count))

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
a, b = map(str, input().split())
n = 0
for i in range(2):
  if a[i] == b[i]:
    n += 1
print(n)

a = input()
b = input()
n = 0
for i in range(3):
  if a[i] == b[i]:
    n += 1
print(n)


Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
N=int(input())

a=[]
for i in range(N):
    a.append([m-1 for m in map(int,input().split())])

b=[]
for i in range(N):
    b.append(a[i].pop(0))

an=0

while True:
    note=[]
    x=0
    for i in range(N):
        if b[i]!=N and b[b[i]]==i:
            x=1
            note.append(i)
    for i in note:
        try:
            b[i]=a[i].pop(0)
        except:
            b[i]=N
    if x==1:
        an+=1
    elif b==[N for i in range(N)]:
        print(an)
        break
    else:
        print(-1)
        break

S=input()
T=input()
an=0
for i in range(3):
    if S[i]==T[i]:
        an+=1
print(an)

Verdicts: Runtime Error

Accepted