TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n = int(input())
h = list(map(int,input().split()))
cnt = 0
for i in range(n-1):
    cnt +=min(h[i],h[i+1])
print(sum[h]-cnt)

n = int(input())
h = list(map(int,input().split()))
cnt = 0
for i in range(n-1):
    cnt +=min(h[i],h[i+1])
print(sum(h)-cnt)


Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
import numpy as np
N = int(input())
H = np.array(list(map(int,input().split())))

ans = 0
while np.max(H) != 0:
    min_h_p = 0
    for i in range(N):
        if H[i] == 0 and min_h_p > 0:
            ans += min_h_p
            H[st:i] -= min_h_p
            break
        elif i == N-1:
            if min_h_p == 0:
                min_h_p = H[i]
            if st == 0:
                H[i] -= min_h_p
                ans += min_h_p
            else:
                ans += min_h_p
                H[st:] -= min_h_p
            break
        else:
            if min_h_p == 0:
                min_h_p = H[i]
                st = i
            else:
                min_h_p = min(H[i],min_h_p)

print(ans)


import numpy as np
N = int(input())
H = np.array(list(map(int,input().split())))

ans = 0
while np.max(H) != 0:

    min_h_p = 0
    st = -1
    for i in range(N):
        if st == -1:
            if H[i] > 0:
                st = i
            if i == N-1:
                ans += H[i]
                H[i] = 0
                break
        elif H[i] == 0:
            min_h_p = min(H[st:i])
            ans += min_h_p
            H[st:i] -= min_h_p
            break
        elif i == N-1:
            min_h_p = min(H[st:])
            ans += min_h_p
            H[st:] -= min_h_p
            break
print(ans)


Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n = int(input())
list = input().split()

for t in range(len(list)):
    list[t] = int(list[t])

cnt = 0

for idx in range(n):
    t_min = min(list[idx:n])
    for idx2 in range(idx,n):
        if 0 != list[idx2]:
            break
        else:
            list[idx2] = list[idx2]-1
    cnt += 1

print(cnt)


n = int(input())
list = input().split()

for t in range(len(list)):
    list[t] = int(list[t])

cnt = 0

for idx in range(n):
    
    
    for t in range(101):
        if 0 != list[idx]:
            
            idx2 = n
            t_cnt = min(list[idx:n])
            
            
            
            if t_cnt == 0:
                idx2 = list[idx:n].index(0) + idx
                t_cnt = min(list[idx:idx2])

            for idx3 in range(idx,idx2):
                list[idx3] = list[idx3] - t_cnt
            cnt += t_cnt
        else:
            break
        
print(cnt)


Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N = int(input())
h = list(map(int, input().split()))

peak = []
trough = []
h = [0] + h + [0]
for a, b, c in zip(h[:-2], h[1:-1], h[2:]):
    ab = b - a
    bc = c - b
    if ab * bc < 0:
        if bc < 0:
            peak.append(b)
        else:
            trough.append(b)

print(sum(peak) - sum(trough))

N = int(input())
h = list(map(int, input().split()))

peak = []
trough = []
h = [0] + h + [0]
before = 0
for a, b in zip(h[:-1], h[1:]):
    after = b - a
    if after == 0:
        continue
    elif before > 0 > after:
        peak.append(a)
    elif before < 0 < after:
        trough.append(a)
    before = after

print(sum(peak) - sum(trough))

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n = int(input())
h = list(map(int,input().split()))
ans = 0
for _ in range(100):
  streak = False
  for i in range(n):
    if h[i] > 0:
      h[i] -= 1
      if streak:
        pass
      else:
        ans += 1
    else:
      streak = False
print(ans)


n = int(input())
h = list(map(int,input().split()))
ans = 0
for _ in range(100):
  streak = False
  for i in range(n):
    if h[i] > 0:
      if streak:
        pass
      else:
        ans += 1
    else:
      streak = False
print(ans)

n = int(input())
h = list(map(int,input().split()))
ans = 0
for _ in range(100):
  streak = False
  for i in range(n):
    if h[i] > 0:
      h[i] -= 1
      if streak:
        pass
      else:
        ans += 1
        streak = True
    else:
      streak = False
print(ans)


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N = int(input())
H = list(map(int, input().split()))

res = 0; i = 0
while True:
    if max(H) == 0:
        break

    while i < N:
        if H[i] == 0:
            i += 1
        else:
            res += 1
            while i < N and H[i] > 0:
                H[i] -= 1
                i += 1
print(res)


N = int(input())
H = list(map(int, input().split()))

def flower(lst=H):
    if not lst:
        return 0
    ans = min(lst)
    lst = list(map(lambda x:x-ans, lst))
    indexes = [-1]
    indexes.extend([i for i, j in enumerate(lst) if j == 0])
    m = len(indexes)
    indexes.append(len(lst))
    for i in range(m):
        ans += flower(lst[indexes[i]+1:indexes[i+1]])
    return ans

print(flower())


Verdicts: Time Limit Exceeded

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
# coding: utf-8
# Your code here!
import numpy as np
N = int(input())
L = np.array(list(map(int, input().split())))

cnt = 0
while np.any(L > 0):
    for i in range(N):
        if L[i] > 0:
            start = i
            end = i + 1
            for j in range(start+1, N):
                end = j
                if not L[j] > 0:
                    break
                end += 1
            break
        
    
    cnt += L[start:end].min()
    L[start:end] -= L[start:end].min()
    print(L, cnt, start, end)

# coding: utf-8
# Your code here!
import numpy as np
N = int(input())
L = np.array(list(map(int, input().split())))

cnt = 0
while np.any(L > 0):
    for i in range(N):
        if L[i] > 0:
            start = i
            end = i + 1
            for j in range(start+1, N):
                end = j
                if not L[j] > 0:
                    break
                end += 1
            break
        
    
    cnt += L[start:end].min()
    L[start:end] -= L[start:end].min()
    print(cnt)

# coding: utf-8
# Your code here!
import numpy as np
N = int(input())
L = np.array(list(map(int, input().split())))

cnt = 0
while np.any(L > 0):
    for i in range(N):
        if L[i] > 0:
            start = i
            end = i + 1
            for j in range(start+1, N):
                end = j
                if not L[j] > 0:
                    break
                end += 1
            break
        
    
    cnt += L[start:end].min()
    L[start:end] -= L[start:end].min()

print(cnt)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N = int(input())
h = list(map(int,input().split()))

lmin = [] 
lmax = [] 

for i in range(i,N-1):
    if (h[i] >= h[i-1]) and (h[i] > h[i+1]):
        lmax.append(h[i])
    
for k in range(i,N-1):
    if (h[i] <= h[i-1]) and (h[i] < h[i+1]):
        lmin.append(h[i])

ans = sum(lmax) - sum(lmin)

print(ans)


N = int(input())
h = list(map(int,input().split()))

lmin = [] 
lmax = [] 

for i in range(1,N-1):
    if (h[i] >= h[i-1]) and (h[i] > h[i+1]):
        lmax.append(h[i])
    
for k in range(1,N-1):
    if (h[i] <= h[i-1]) and (h[i] < h[i+1]):
        lmin.append(h[i])

ans = sum(lmax) - sum(lmin

print(ans)


N = int(input())
h = list(map(int,input().split()))
if max(h) == min(h):
    ans = h[0]

else:
    same = []
    for i in range(N-1):
        if h[i] == h[i+1]:
            same.append(i)
    
    if len(same) >= 1:
        for k in range (len(same))[::-1]:
            del h[same[k]]
    
    N = len(h)

    lmin = [] 
    lmax = [] 

    if N >=3:
        for i in range(1,N-1):
            if (h[i] > h[i-1]) and (h[i] > h[i+1]):
                lmax.append(h[i])
        
        for k in range(1,N-1):
            if (h[k] < h[k-1]) and (h[k] < h[k+1]):
                lmin.append(h[k])

        if h[0] > h[1]:
            lmax.append(h[0])
            
        if h[N-1] > h[N -2]:
            lmax.append(h[N-1])
                
        if (len(lmax) == 1) :
            ans = max(h)

        else:
            ans = sum(lmax) - sum(lmin)
    
    if N == 2:
        ans = max(h)

    if N == 1:
        ans = h[0]

#print(lmax)

print(ans)


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N = int(input())
arr = list(map(int,input().split()))
N+=1
arr.append(0)
now = 0
min = 100
count = 0
print(arr)

while True:
  min = 100
  if arr[now] == 0:
    now += 1
    if now == N:
      break
  else:
    for i in range(now,N):
      if min > arr[i]:
        if arr[i] == 0:
          last = i
          for j in range(now,i):
            arr[j] = arr[j] - min
          count+=min
          break
        else:
          min = arr[i]
print(count)
          

N = int(input())
arr = list(map(int,input().split()))
N+=1
arr.append(0)
now = 0
min = 100
count = 0

while True:
  min = 100
  if arr[now] == 0:
    now += 1
    if now == N:
      break
  else:
    for i in range(now,N):
      if min > arr[i]:
        if arr[i] == 0:
          last = i
          for j in range(now,i):
            arr[j] = arr[j] - min
          count+=min
          break
        else:
          min = arr[i]
print(count)
          

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N = int(input())
H = list(map(int, input().split()))
num = 0
while H:
    
    for i in range(N):
        if H[i] != 0:
            while H[i] != 0:
                H[i] -= 1
                i += 1
    num += 1
print(num)

def get_nonzero_range(A):
    start, end = None, None
    N = len(A)
    for i in range(N):
        if A[i] != 0:
            start = i
            for j in range(i+1, N):
                if A[j] == 0:
                    end = j
                    return start, end
    else:
        return start, end

N = int(input())
H = list(map(int, input().split()))
H.append(0)
num = 0
print(H)
while True:
    start, end = get_nonzero_range(H)
    if start == None:
        break
    else:
        for i in range(start, end):
            H[i] -= 1
        num += 1
print(num)

def get_nonzero_range(A):
    start, end = None, None
    N = len(A)
    for i in range(N):
        if A[i] != 0:
            start = i
            for j in range(i+1, N):
                if A[j] == 0:
                    end = j
                    return start, end
    else:
        return start, end

N = int(input())
H = list(map(int, input().split()))
H.append(0)
num = 0
print(H)
while True:
    start, end = get_nonzero_range(H)
    print(start, end)
    if start == None:
        break
    else:
        for i in range(start, end):
            H[i] -= 1
        num += 1
print(num)

def get_nonzero_range(A):
    start, end = None, None
    N = len(A)
    for i in range(N):
        if A[i] != 0:
            start = i
            for j in range(i+1, N):
                if A[j] == 0:
                    end = j
                    return start, end
    else:
        return start, end

N = int(input())
H = list(map(int, input().split()))
H.append(0)
num = 0
while True:
    start, end = get_nonzero_range(H)
    if start == None:
        break
    else:
        for i in range(start, end):
            H[i] -= 1
        num += 1
print(num)


Verdicts: Runtime Error

Wrong Answer

Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
import numpy as np
#from numba import njit


#A = np.array(list(map(int, input().split())))
N = int(input())
h = np.array(list(map(int, input().split())))



def solve(N,h):
    s = 0
    while (np.all(h > 0)):
        w = np.where(h > 0)[0]
        l = w[0]
        r = w[0]
        i = 1
        while (i < len(w)):
            if (w[i] == r + 1):
                r = w[i]
            i += 1
        
        h = np.concatenate([h[:l], h[l:r+1]-1, h[r+1:]])
        s += 1
    return s
        
print(solve(N,h))


import numpy as np
#from numba import njit


#A = np.array(list(map(int, input().split())))
N = int(input())
h = np.array(list(map(int, input().split())))



def solve(N,h):
    s = 0
    while (np.any(h > 0)):
        w = np.where(h > 0)[0]
        l = w[0]
        r = w[0]
        i = 1
        while (i < len(w)):
            if (w[i] == r + 1):
                r = w[i]
            i += 1
        
        h = np.concatenate([h[:l], h[l:r+1]-1, h[r+1:]])
        s += 1
    return s

print(solve(N,h))


Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
import cython

n = int(input())
h = list(map(int, input().split())) + [0]

ans,cnt = 0, sum(h)
while cnt > 0:
    l, r = -1, n
    for num, i in enumerate(h):
        if (l == -1) and (i > 0):
            l = num
        if (l > -1) and (i == 0):
            r = num
            ans += 1
            cnt -= r - l
            for i in range(l, r):
                h[i] -= 1
            break
print(ans)


n = int(input())
h = list(map(int, input().split())) + [0]

ans,cnt = 0, sum(h)
while cnt > 0:
    l, r = -1, n
    for num, i in enumerate(h):
        if (l == -1) and (i > 0):
            l = num
        if (l > -1) and (i == 0):
            r = num
            ans += 1
            cnt -= r - l
            for i in range(l, r):
                h[i] -= 1
            break
print(ans)


Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n=int(input())
l=list(map(int,input().split()))

def yama(l):
    r=0
    zf=0
    a=[0]*(len(l)+2)
    for i in range(1,len(l)+1):
        a[i]=l[i-1]
    for i in range(0,len(l)+1):
        if a[i]>0 and zf==1:
            r+=1
            zf=0
        else:
            zf=1
ans=0
while yama(l)==0:
    for i in range(n):
        l[i]-=1
        ans+=yama(l)
print(ans)
    
            

n=int(input())
l=list(map(int,input().split()))

def yama(l):
    r=0
    zf=0
    a=[0]*(len(l)+2)
    for i in range(1,len(l)+1):
        a[i]=l[i-1]
    for i in range(0,len(l)+1):
        if a[i]>0 and zf==1:
            r+=1
            zf=0
        elif a[i]<=0:
            zf=1
    return r
ans=0
while yama(l)>0:
    ans+=yama(l)
    for i in range(n):
        l[i]-=1
   
print(ans)
    
            

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N=int(input())
h=list(map(int,input().split()))
ans=0
flag = False
for hei in range(1,101):
  for i in range(N+1):
    if h[i] >= hei or i!=N:
      flag = True
    else:
      if flag:
        ans+=1
        flag = False
print(ans)


N=int(input())
h=list(map(int,input().split()))
ans=0
flag = False
for hei in range(1,101):
  for i in range(N+1):
    if h[i] >= hei and i!=N:
      flag = True
    else:
      if flag:
        ans+=1
        flag = False
print(ans)

N=int(input())
h=list(map(int,input().split()))
h.append(0)
ans=0
flag = False
for hei in range(1,101):
  for i in range(N+1):
    if h[i] >= hei and i!=N:
      flag = True
    else:
      if flag:
        ans+=1
        flag = False
print(ans)


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n=int(input())
h=list(map(int,input().split()))
ans=0
while h!=[0]*n:
  b=(h[0]!=0)+0
  for i in range(n):
    if b==1 and h[i]==0:ans+=1;b=0
    if h[i]!=0:h-=1;b=1
  if b==1:ans+=1
print(ans)

n=int(input())
h=list(map(int,input().split()))+[0]
ans=0
while sum(h):
  for i in range(n):
    if h[i]>0 and h[i+1]==0:ans+=1
    h[i]=max(0,h[i]-1)
print(ans)

Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N = int(input())
h = [int(i)-1 for i in input().split()]
h.append(0)

cnt = 1
for H in range(max(h)-1):
    #print(h)
    for i in range(N):
        if h[i] >0:
            h[i] -= 1
            if h[i+1] == 0:
                cnt +=1

print(cnt)

N = int(input())
h = [int(i) for i in input().split()]
h.append(0)

cnt = 0
for H in range(max(h)):
    #print(h)
    for i in range(N):
        if h[i] >0:
            h[i] -= 1
            if h[i+1] == 0:
                cnt +=1

print(cnt)

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
ctr = 0

def mizuyari(left, right, array):
    # left <= x <= right
    N = right - left
    if N == 0:
        global ctr
        ctr += array[left]
    elif N == 1:
        mini = max(array[left], array[right])
        ctr += mini
        if array[left] != 0:
            array[left] -= mini
        else:
            array[right] -= mini
    else:
        mini = 10000
        mini_index = -1
        for i in range(left, right+1):
            if mini > array[i]:
                mini = array[i]
                mini_index = i
        ctr += mini

        for i in range(left, right+1):
            array[i] -= mini

        print(array)
        print(ctr)
        
        if left != mini_index:
            mizuyari(left, mini_index-1, array)
        if mini_index != right:
            mizuyari(mini_index+1, right, array)


def solve_C():
    n = int(input())
    h = list(map(int, input().split()))

    mizuyari(0, n-1, h)

solve_C()
print(ctr)

ctr = 0

def mizuyari(left, right, array):
    # left <= x <= right
    N = right - left
    if N == 0:
        global ctr
        ctr += array[left]
    elif N == 1:
        mini = max(array[left], array[right])
        ctr += mini
        if array[left] != 0:
            array[left] -= mini
        else:
            array[right] -= mini
    else:
        mini = 10000
        mini_index = -1
        for i in range(left, right+1):
            if mini > array[i]:
                mini = array[i]
                mini_index = i
        ctr += mini

        for i in range(left, right+1):
            array[i] -= mini
        
        if left != mini_index:
            mizuyari(left, mini_index-1, array)
        if mini_index != right:
            mizuyari(mini_index+1, right, array)


def solve_C():
    n = int(input())
    h = list(map(int, input().split()))

    mizuyari(0, n-1, h)

solve_C()
print(ctr)

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N=int(input())
H=list(map(int,input().split()))
cnt=0
for i in range(len(H)-1):
    if H[i]>H[i+1]:
        cnt+=1
print(max(H)+cnt)

N=int(input());a=0;t=0
for h in map(int,input().split()):
    a+=max(h-t,0);t=h
print(a)

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
import numpy as np
n = int(input())
h = list(map(int, input().split()))

h = np.array(h)

h_zero = np.hstack([np.zeros(1), h, np.zeros(1)])

d = np.diff(h_zero)

a= (d[:-1] * d[1:]) < 0

h_a = h[a == True]

s = 0
for k in range(len(h_a)):
    
    if k%2 == 0:
        
            
        if k == 0:
            s += h_a[k] - h_a[k+1]
        elif k == len(h_a)-1:
            s += h_a[k] - h_a[k-1] 
        else:
            s += h_a[k] - np.max([h_a[k-1], h_a[k+1]])
    else:
        s += h_a[k]
#     print(k, s)
print(s)

import numpy as np
n = int(input())
h = list(map(int, input().split()))

h = np.array(h)


def calc(h, s):
#     print(h, s)
    a = np.min(h)
    s += a
    h = h - a
    ind = np.where(h == 0)[0][0]
    h1 = h[:ind]
    h2 = h[ind+1:]
    if len(h1) != 0:
        s = calc(h1, s)
    if len(h2) != 0:
        s = calc(h2, s)
    return s

calc(h, 0)

n = int(input())
h = list(map(int, input().split()))

h = np.array(h)

h_zero = np.hstack([np.zeros(1), h, np.zeros(1)])

d = np.diff(h_zero)

a= (d[:-1] * d[1:]) < 0

h_a = h[a == True]

s = 0
for k in range(len(h_a)):
    
    if k%2 == 0:
        
            
        if k == 0:
            s += h_a[k] - h_a[k+1]
        elif k == len(h_a)-1:
            s += h_a[k] - h_a[k-1] 
        else:
            s += h_a[k] - np.max([h_a[k-1], h_a[k+1]])
    else:
        s += h_a[k]
#     print(k, s)
print(s)

import numpy as np
n = int(input())
h = list(map(int, input().split()))

h = np.array(h)


def calc(h, s):
#     print(h, s)
    a = np.min(h)
    s += a
    h = h - a
    ind = np.where(h == 0)[0][0]
    h1 = h[:ind]
    h2 = h[ind+1:]
    if len(h1) != 0:
        s = calc(h1, s)
    if len(h2) != 0:
        s = calc(h2, s)
    return s

print(calc(h, 0))

Verdicts: Runtime Error

Wrong Answer

Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):





n = int(input())
flower_height = list(map(int, input().split()))
count=0
def mizuyari(a):
    return a-1




for i in range(n):
    j=i
    while flower_height[i]!=0:
        while i < n-1:
            if flower_height[i+1] != 0: i+=1
            else: break
        flower_height = list(map(mizuyari,flower_height[:i+1])) + flower_height[i+1:]
        i=j
        count += 1
    






n = int(input())
flower_height = list(map(int, input().split()))
count=0
def mizuyari(a):
    return a-1




for i in range(n):
    j=i
    while flower_height[i]!=0:
        while i < n-1:
            if flower_height[i+1] != 0: i+=1
            else: break
        flower_height = list(map(mizuyari,flower_height[:i+1])) + flower_height[i+1:]
        i=j
        count += 1
    
print(count)


    

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n = int(input())
flowers = list(map(int, input().split()))
flowers.append(max(flowers))
cnt = 0
for i in range(sum(flowers)):
    if(all([x<0 for x in flowers])): break
    print(flowers, i, cnt)
    flowers = list(map(lambda x: (x-1), flowers))
    for j in range(n):
        if(flowers[j] > 0 and flowers[j+1] <= 0): cnt+=1
print(i + cnt)

n = int(input())
flowers = list(map(int, input().split()))
flowers.append(0)
cnt = 0
if(all([x<=0 for x in flowers])): print(0)
else: 
    for i in range(sum(flowers)+1):
        #print(i)
        if(all([x<=0 for x in flowers])): break
        #print(flowers, i, cnt)
        for j in range(n-2):
            if(flowers[j] > 0 and flowers[j+1] <= 0 and any([x>0 for x in flowers[j+2:]])): cnt+=1
        flowers = list(map(lambda x: (x-1), flowers))
    print(i + cnt)

Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N =int(input())
l =[int(i)for i in input().split()]

min = []
max = []
ans =0
while l !=[0]*N:
    ans += 1
    s =False
    for i,j in enumerate(l):
        if s:
            if j == 0:
                break
        if j !=0:
            s =True
            l[i]-=1
    print(l)
print(ans)


def f(l):
    sta = True
    for i,j in enumerate(l):
        if sta:
            if j!=0:
                sta=False
                l[i]-=1
        else:
            if j==0:
                break
            else:
                l[i]-=1
    return l



N =int(input())
h =[int(i) for i in input().split()]
m = 0
while h != [0]*N:
    h =f(h)
    m += 1
print(m)

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n = int(input())
h= list(map(int, input().split()))
cnt=0
for i in range(n-1):
    if h[i+1]-h[i]<0:
        print(str(i) + ";"  + str(h[i]) + str(h[i+1]))
        cnt = cnt + h[i]- h[i+1]
cnt += h[n-1]
print(cnt)

n = int(input())
h= list(map(int, input().split()))
cnt=0
for i in range(n-1):
    if h[i+1]-h[i]<0:
        cnt = cnt + h[i]- h[i+1]
cnt += h[n-1]
print(cnt)

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
count = 0

def rec(l, r):
    global count
    global h
    global s

    print(l, r)
    if l >= r:
        return

    zero = list()
    for i in range(l, r):
        if h[i] == 0:
            zero.append(i)

    if len(zero) > 0:
        for i in zero:
            if not (l, i) in s:
                rec(l, i)
                s.add((l, i))
            if not (i+1, r) in s:
                rec(i+1, r)
                s.add((i+1, r))
    else:
        for i in range(l, r):
            h[i] -= 1
        count += 1
        rec(l, r)

n = int(input())
h = list(map(int, input().split()))
s = set()

rec(0, len(h))
print(count)


count = 0

def rec(l, r):
    global count
    global h
    global s

    if l >= r:
        return

    zero = list()
    for i in range(l, r):
        if h[i] == 0:
            zero.append(i)

    if len(zero) > 0:
        for i in zero:
            if not (l, i) in s:
                rec(l, i)
                s.add((l, i))
            if not (i+1, r) in s:
                rec(i+1, r)
                s.add((i+1, r))
    else:
        for i in range(l, r):
            h[i] -= 1
        count += 1
        rec(l, r)

n = int(input())
h = list(map(int, input().split()))
s = set()

rec(0, len(h))
print(count)


Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
def solve():
	N = int(input())
	h = [int(i) for i in input().split()]
    return N * max(h) - sum(h)

print(solve())

def solve():
	N = int(input())
	h = [int(i) for i in input().split()]
    ans = 0
	for i in range(1, N):
		ans += max(h[i] - (0 if i - 1 < 0 else h[i - 1]), 0)
	return ans

print(solve())

def solve():
	N = int(input())
	h = [int(i) for i in input().split()]
	ans = 0
	for i in range(0, N):
		ans += max(h[i] - (0 if i - 1 < 0 else h[i - 1]), 0)
	return ans

print(solve())


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
# -*- coding: utf-8 -*-

N = int(input())
h = list(map(int, input().split()))


def calc(list_h):
    if not list_h:
        return 0

    min_height = min(list_h)
    list_h = [list_h[i] - min_height for i in range(len(list_h))]
    zero_indexes = [i for i, x in enumerate(list_h) if x == 0]

    if not any(list_h):
        return min_height

    left_list = list_h[:zero_indexes[0]]
    right_list = list_h[zero_indexes[0]+1:]
    return calc(left_list) + calc(right_list)


print(calc(h))


# -*- coding: utf-8 -*-

N = int(input())
h = list(map(int, input().split()))


def calc(list_h):
    if not list_h:
        return 0

    min_height = min(list_h)
    list_h = [list_h[i] - min_height for i in range(len(list_h))]
    zero_indexes = [i for i, x in enumerate(list_h) if x == 0]

    if not any(list_h):
        return min_height

    left_list = list_h[:zero_indexes[0]]
    right_list = list_h[zero_indexes[0]+1:]
    return calc(left_list) + calc(right_list) + min_height


print(calc(h))


Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n = int(input())
l = [0]+list(map(int,input().split()))
s = 0
while len(set(l))!=1:
  for i in range(n+1):
    if l[i]==0:
      if l[i+1]==0:
          break
      for j in range(i+1,n+2):
        if l[j]!=0:
          l[j] -=1
          continue
        else:
          s += 1
          break
print(s)

n = int(input())
l = list(map(int,input().split()))
c = 1
for q in range(10000000):
  for i in range(n-1):
    if l[i]==0:
      continue
    elif l[i]<=l[i+1] and i!=n-2:
      l[i] -= 1
    elif l[i]<=l[i+1] and i==n-2:
      l[i] -= 1
      l[i+1] -=1
    else:
      c += 1
      l[i] -= 1
      break

print(c)

n = int(input())
l = list(map(int,input().split()))
c = 0
if n==1:
  print(*l)
  exit()
while l.count(0)!=n:
  for i in range(n-1):
    if l[i]==0 and i!=n-2:
      continue
    elif l[i]==0 and i==n-2:
      c += 1
      l[n-1] -=1
    elif l[i]<=l[i+1] and i!=n-2:
      l[i] -= 1
    elif l[i]<=l[i+1] and i==n-2:
      l[i] -= 1
      l[i+1] -=1
      c += 1
    else:
      c += 1
      l[i] -= 1
      break
print(c)

Verdicts: Runtime Error

Time Limit Exceeded

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
多分再帰使うんだろうね


N = int(input())
*H, = map(int, input().split())
 
T = [0]*N
ans = 0
i = 0
while i<N:
    
    if T[i]<H[i]:
        start = i
        high  = T[i]+1
        ans = ans + 1
        i = 0
        for j in range(start, N, 1):
            if T[j]<H[j]:
                T[j] = T[j] + 1
            else:
                break
    else:
        i = i + 1

print(ans)

Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N=int(input())
h=list(map(int,input().split()))

w=0
while 1:
  if w==0 and h[0]>0:
    w+=1
  for i in range(N):
    if h[i]>0:
      h[i]-=1
    if i<N-1 and h[i]==0 and h[i+1]>0:
      w+=1
  #print(h) 
  if sum(h)==0:
    break
print(w)

N=int(input())
h=list(map(int,input().split()))

ans=0
while sum(h)>0:
  for i in range(N):
    if i<N-1 and h[i]>0 and h[i+1]==0:
      ans+=1
    else:
      if i==N-1 and h[i]>0:
        ans+=1
    if h[i]>0:
      h[i]-=1
  print(h)
print(ans)

N=int(input())
h=list(map(int,input().split()))

ans=0
while sum(h)>0:
  for i in range(N):
    if i<N-1 and h[i]>0 and h[i+1]==0:
      ans+=1
    else:
      if i==N-1 and h[i]>0:
        ans+=1
    if h[i]>0:
      h[i]-=1
  #print(h)
print(ans)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N = int(input())
A = [0] * N
for i in range(N):
    A[i] = int(input())

lst=sorted(set(A))

target = {}
for i in range(len(lst)):
    target[lst[i]] = i
    
for a in A:
    print(target[a])

N = int(input())
H = list(map(int, input().split()))

ans = 0
while(max(H)>=0):
    ans +=1
    for i in range(N):
        H[i] -= 1
        if (H[i] >= 0):
            if (i>=1):
                if (H[i-1] < 0 and max(H[:i])>=0):
                    ans += 1

print(ans-1)

Verdicts: Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
n = int(input())
h_list = list(map(int, input().split()))
left = 0
right = 0
cnt = 0
while True:
    stop = False
    for i in range(left, n):
        if h_list[i] <= 0:
            stop = True
            right = i
            break
    if not stop and cnt != 0:
        right = n
    else:
        break

    h_list[left:right] = [h - 1 for h in h_list[left:right]]
    cnt += 1

    stop = False
    for i in range(right, n):
        if h_list[i] > 0:
            stop = True
            left = i
            break
    if not stop:
        for i in range(0, n):
            if h_list[i] > 0:
                stop = True
                left = i
                break
        if not stop:
            break
print(cnt)


#include<stdio.h>

int main() {
	int n, h[100], i, flg, cnt, stop;
	scanf("%d", &n);
	for (i = 0; i < n; i++) scanf("%d", &h[i]);

	cnt = 0;
	while (1) {
		flg = 0;
		stop = 1;
		for (i = 0; i < n; i++) {
			if (h[i] > 0) {
				if (flg) h[i]--;
				else {
					flg = 1;
					stop = 0;
					cnt++;
					h[i]--;
				}
			}
			else flg = 0;
		}
		if (stop) break;
	}

	printf("%d", cnt);
}

def kuksan(array):
    for i in range(0, n):
        if array[i] > 0:
            left = i
            for j in range(left,n + 1):
                if array[j] <= 0:
                    right = j - 1
                    return left, right, True
    return 0,0,0

n = int(input())
h_list = list(map(int, input().split()))
cnt = 0
while True:
    h_list.append(0)
    kukan = kuksan(h_list)
    if kukan[2]:
        for i in range(kukan[0], kukan[1] + 1):
            h_list[i] -= 1
        cnt += 1
    else:
        break

print(cnt)

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
N=int(input())
L=[0]+list(map(int,input().split()))
L.append(0)
print(L)
M=0
for i in range(N+1):
  if L[i+1] > L[i] :
    M+=(L[i+1]-L[i])
print(M)
  

N=int(input())
L=[0]+list(map(int,input().split()))
M=0
for i in range(N):
  if L[i+1] > L[i] :
    M+=(L[i+1]-L[i])
print(M)

Verdicts: Wrong Answer

Accepted
Problem: In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0. You are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:    * Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.  Find the minimum number of watering operations required to satisfy the condition.

Submission attempts (in order):
h = list(map(int, input().split()))
ans = 0
while sum(h) != 0:
    left = float("inf")
    right = float("inf")
    for i in range(n):
        if h[i] > 0:
            left = i
            break
    for j in range(i + 1, n):
        if h[j] <= 0:
            right = j
            break
    if right == float("inf"):
        right = n
    for i in range(left, right):
        h[i] -= 1
    ans += 1
print(ans)

n = int(input())
h = list(map(int, input().split()))
ans = 0


while sum(h) != 0:
    
    left = float("inf")
    right = float("inf")
    
    
    for i in range(n):
        if h[i] > 0:
            left = i
            break
    
    for j in range(i + 1, n):
        if h[j] <= 0:
            right = j
            break
    if right == float("inf"):
        right = n
    
    for i in range(left, right):
        h[i] -= 1
    ans += 1
print(ans)

Verdicts: Runtime Error

Accepted