TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: Serval is fighting with a monster.  The _health_ of the monster is H.  In one attack, Serval can decrease the monster's health by A. There is no other way to decrease the monster's health.  Serval wins when the monster's health becomes 0 or below.  Find the number of attacks Serval needs to make before winning.

Submission attempts (in order):
H,A=map(int,input().split())
ans=(H-0.5)//A+1
print(ans)

H,A=map(int,input().split())
ans=((H-1)//A)+1
print(ans)


Verdicts: Wrong Answer

Accepted
Problem: Serval is fighting with a monster.  The _health_ of the monster is H.  In one attack, Serval can decrease the monster's health by A. There is no other way to decrease the monster's health.  Serval wins when the monster's health becomes 0 or below.  Find the number of attacks Serval needs to make before winning.

Submission attempts (in order):
H,A = map(int,input().split())
if H%A == 0:
        print(H/A)
else:
        print((H/A)+1)

H,A = map(int,input().split())
if H%A == 0:
        print(int(H/A))
else:
        print(int(H/A)+1)

Verdicts: Wrong Answer

Accepted
Problem: Serval is fighting with a monster.  The _health_ of the monster is H.  In one attack, Serval can decrease the monster's health by A. There is no other way to decrease the monster's health.  Serval wins when the monster's health becomes 0 or below.  Find the number of attacks Serval needs to make before winning.

Submission attempts (in order):
H, A = map(int, input().split())
 
if A > H:
  print(1)
  
else:
  if H % A = 0:
    answer = H // A
  else:
    answer = H // A + 1
  
  print(answer)

H, A = map(int, input().split())

if A > H:
  print(1)
  
else:
  answer = H // A
  print(answer)

H, A = map(int, input().split())
 
if A > H:
  print(1)
  
else:
  if H % A == 0:
    answer = H // A
  else:
    answer = H // A + 1
  
  print(answer)

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: Serval is fighting with a monster.  The _health_ of the monster is H.  In one attack, Serval can decrease the monster's health by A. There is no other way to decrease the monster's health.  Serval wins when the monster's health becomes 0 or below.  Find the number of attacks Serval needs to make before winning.

Submission attempts (in order):
h, a = map(int, input().split())
h1 = h
x = 0
while h1 <= 0:
  h1 -= a
  x++
print(x)

h, a = map(int, input().split())
x = 0
while h > 0:
  h -= a
  x += 1

else:
  print(x)

Verdicts: Runtime Error

Accepted
Problem: Serval is fighting with a monster.  The _health_ of the monster is H.  In one attack, Serval can decrease the monster's health by A. There is no other way to decrease the monster's health.  Serval wins when the monster's health becomes 0 or below.  Find the number of attacks Serval needs to make before winning.

Submission attempts (in order):
H, A = map(int, input().split())
print(int(H/A))

H, A = map(int, input().split())

print(-(-H//A))

Verdicts: Wrong Answer

Accepted
Problem: Serval is fighting with a monster.  The _health_ of the monster is H.  In one attack, Serval can decrease the monster's health by A. There is no other way to decrease the monster's health.  Serval wins when the monster's health becomes 0 or below.  Find the number of attacks Serval needs to make before winning.

Submission attempts (in order):
H = int(input())

cnt = 0
ans = 0

while H >= 1:
    H = H / 2
    if cnt == 0:
        cnt += 1
        ans += 1
    else:
        ans += cnt * 2
        cnt = cnt * 2

print(ans)


H, A = map(int, input().split())

cnt = 0

while H > 0:
    H = H - A
    cnt += 1
print(cnt)


Verdicts: Runtime Error

Accepted
Problem: Serval is fighting with a monster.  The _health_ of the monster is H.  In one attack, Serval can decrease the monster's health by A. There is no other way to decrease the monster's health.  Serval wins when the monster's health becomes 0 or below.  Find the number of attacks Serval needs to make before winning.

Submission attempts (in order):
h,a = map(int, input().split())

print(math.ceil(h/a))

import math

h, a = map(int, input().split())

print(math.ceil(h / a))



Verdicts: Runtime Error

Accepted
Problem: Serval is fighting with a monster.  The _health_ of the monster is H.  In one attack, Serval can decrease the monster's health by A. There is no other way to decrease the monster's health.  Serval wins when the monster's health becomes 0 or below.  Find the number of attacks Serval needs to make before winning.

Submission attempts (in order):
N, K = map(int, input().split())
H = list(map(int, input().split()))
if N <= K:
  print(0)
elif K == 0:
  print(sum(H))
else:
	H = sort(H)
	print(sum(H[:-K]))

def serveal_monter(input):
  H, A = input.split(" ")
  if H % A > 0:
    return (H // A) + 1
  return H // A

def serveal_monter(input):
  H, A = input.split(" ")
  H = int(H)
  A = int(A)
  if H % A > 0:
    return (H // A) + 1
  return H // A

S = input()
H, A = S.split(" ")
H = int(H)
A = int(A)
if H%A == 0:
  print(H/A)
else:
  print(H/A + 1)

S = input()
H, A = S.split()
H = int(H)
A = int(A)
if H%A == 0:
  print(int(H/A))
else:
  print(int(H/A) + 1)

Verdicts: Runtime Error

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Serval is fighting with a monster.  The _health_ of the monster is H.  In one attack, Serval can decrease the monster's health by A. There is no other way to decrease the monster's health.  Serval wins when the monster's health becomes 0 or below.  Find the number of attacks Serval needs to make before winning.

Submission attempts (in order):
h, a = [int(i) for i in input("").split(" ")]
print((h+a-1)/a)

h, a = [int(i) for i in input("").split(" ")]
print((h+a-1)//a)

Verdicts: Wrong Answer

Accepted
Problem: Serval is fighting with a monster.  The _health_ of the monster is H.  In one attack, Serval can decrease the monster's health by A. There is no other way to decrease the monster's health.  Serval wins when the monster's health becomes 0 or below.  Find the number of attacks Serval needs to make before winning.

Submission attempts (in order):
H = input()
A = input()
c = 0
while true:
  H = H - A
  c = c+1
  if H < 0:
    print(c)
    

H,A = map(int, input().split())
c = 0
while True:
  H = H - A
  c = c+1
  if H <= 0:
    print(c)
    break
    


Verdicts: Runtime Error

Accepted
Problem: Serval is fighting with a monster.  The _health_ of the monster is H.  In one attack, Serval can decrease the monster's health by A. There is no other way to decrease the monster's health.  Serval wins when the monster's health becomes 0 or below.  Find the number of attacks Serval needs to make before winning.

Submission attempts (in order):
x = [int(x) for x in input().split()]

import math

print(math.ceil(x[0]/x[1])

x = [int(x) for x in input().split()]

import math

print(math.ceil(x[0]/x[1]))

Verdicts: Runtime Error

Accepted
Problem: Serval is fighting with a monster.  The _health_ of the monster is H.  In one attack, Serval can decrease the monster's health by A. There is no other way to decrease the monster's health.  Serval wins when the monster's health becomes 0 or below.  Find the number of attacks Serval needs to make before winning.

Submission attempts (in order):
H,A = map(int,input().split())
print(H // A)

H,A = map(int,input().split())
if (H % A) == 0:
    print(H // A)
else:
    print((H // A) + 1)
  

Verdicts: Wrong Answer

Accepted
Problem: Serval is fighting with a monster.  The _health_ of the monster is H.  In one attack, Serval can decrease the monster's health by A. There is no other way to decrease the monster's health.  Serval wins when the monster's health becomes 0 or below.  Find the number of attacks Serval needs to make before winning.

Submission attempts (in order):
import itertools

H,N = map(int,input().split())
A = list(map(int,input().split()))
l = list(itertools.permutations(A,N))

ans = []
for i in l:
    if sum(i) >= H:
        ans.append("Yes")
    else:
        ans.append("No")

if "Yes" in ans:
    print("Yes")
else:
    print("No")

H,A = map(int,input().split())

if H % A >= 1:
    ans = (H//A) +1
    print(ans)
else:
    ans = (H//A)
    print(ans)

Verdicts: Runtime Error

Accepted
Problem: Serval is fighting with a monster.  The _health_ of the monster is H.  In one attack, Serval can decrease the monster's health by A. There is no other way to decrease the monster's health.  Serval wins when the monster's health becomes 0 or below.  Find the number of attacks Serval needs to make before winning.

Submission attempts (in order):

h, a = map(int, input().split())
ans = 0
while True:
    if h > 0:
        h = h - a
        ans += 0
    else:
        print(ans)
        exit()


h, a = map(int, input().split())
ans = 0
while True:
    if h > 0:
        h = h - a
        ans += 1
    else:
        print(ans)
        exit()


Verdicts: Wrong Answer

Accepted
Problem: Serval is fighting with a monster.  The _health_ of the monster is H.  In one attack, Serval can decrease the monster's health by A. There is no other way to decrease the monster's health.  Serval wins when the monster's health becomes 0 or below.  Find the number of attacks Serval needs to make before winning.

Submission attempts (in order):
H,A=map(int,input().split())
a=int(H/A)
if H>=A:
    print(H)
else:
    print(a+1)


H,A=map(int,input().split())

if H%A==0:
    print(int(H/A))
else:
    print(int(H/A)+1)


Verdicts: Wrong Answer

Accepted
Problem: Serval is fighting with a monster.  The _health_ of the monster is H.  In one attack, Serval can decrease the monster's health by A. There is no other way to decrease the monster's health.  Serval wins when the monster's health becomes 0 or below.  Find the number of attacks Serval needs to make before winning.

Submission attempts (in order):
from math import floor
h,a = map(int,input().split())
print(floor(h//a))

from math import ceil
a,b = map(int,input().split())

print(ceil(a,b))

from math import ceil
h,a = map(int,input().split())

print(ceil(h//a))

from math import ceil

a,b = map(int,input().split())

print(ceil(a/b))

Verdicts: Wrong Answer

Runtime Error

Wrong Answer

Accepted
Problem: Serval is fighting with a monster.  The _health_ of the monster is H.  In one attack, Serval can decrease the monster's health by A. There is no other way to decrease the monster's health.  Serval wins when the monster's health becomes 0 or below.  Find the number of attacks Serval needs to make before winning.

Submission attempts (in order):

a,b=map(int,input().split())
print(a//b if a>=b else (a//b) +1)

import math
a,b=map(int,input().split())
print(math.ceil(a/b))

Verdicts: Wrong Answer

Accepted
Problem: Serval is fighting with a monster.  The _health_ of the monster is H.  In one attack, Serval can decrease the monster's health by A. There is no other way to decrease the monster's health.  Serval wins when the monster's health becomes 0 or below.  Find the number of attacks Serval needs to make before winning.

Submission attempts (in order):
h,a = map(int,input().split())
ans = 0
for h >0:
  h -= a
  ans += 1
print(ans)

h,a = map(int,input().split())
ans = 0
while h >0:
  h -= a
  ans += 1
print(ans)

Verdicts: Runtime Error

Accepted
Problem: Serval is fighting with a monster.  The _health_ of the monster is H.  In one attack, Serval can decrease the monster's health by A. There is no other way to decrease the monster's health.  Serval wins when the monster's health becomes 0 or below.  Find the number of attacks Serval needs to make before winning.

Submission attempts (in order):
H,A=map(int,input().spkit())
if H%A==0:
    print(H//A)
else:
    print((H//A)+1)

H,N=map(int,input().split())
if H%N==0:
    print(H//N)
else:
    print((H//N)+1)

Verdicts: Runtime Error

Accepted
Problem: Serval is fighting with a monster.  The _health_ of the monster is H.  In one attack, Serval can decrease the monster's health by A. There is no other way to decrease the monster's health.  Serval wins when the monster's health becomes 0 or below.  Find the number of attacks Serval needs to make before winning.

Submission attempts (in order):
h,a=map(int,input().split())
cnt=1
while(h>=0):
  h=h-a
  cnt+=1
print(cnt)

h,a=map(int,input().split())
cnt=0
while(h>0):
  h=h-a
  cnt+=1
print(cnt)


Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
import numpy as np
H,N = map(int,input().split())
A = list(map(int,input().split()))
if np.sum(A)>=H:
    print("yes")
else:
    print("no")

import numpy as np
H,N = map(int,input().split())
A = list(map(int,input().split()))
if np.sum(A)>=H:
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H,N=map(int,input().split())
A=list(map(int, input().split()))
if sum(A)>=H:
  print("YES")
else:
  print("NO")

H,N=map(int,input().split())
A=list(map(int, input().split()))
if sum(A)>=H:
  print("Yes")
else:
  print("No")

Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H,N=[int(x)for x in input().split()] attack=[int(x) for x in input().split()]
print("Yes"if H- sum(attack)<= 0 else "No")

H,N=[int(x)for x in input().split()]
attack=[int(x) for x in input().split()]
print("Yes"if H- sum(attack)<= 0 else "No")

Verdicts: Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H,N=map(int, input().split())
v = list(input().split())
v = [int(x) for x in v]
print(sum(v))
if H <= sum(v):
    print("Yes")
else:
    print("No")

H,N=map(int, input().split())
v = list(input().split())
v = [int(x) for x in v]
if H <= sum(v):
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
h,n = map(int,input().split())
ans = sum([int(i) for i in input().split()])

print(ans)
if ans >= h:
  print('Yes')
else:
  print('No')

h,n = map(int,input().split())
ans = sum([int(i) for i in input().split()])

if ans >= h:
  print('Yes')
else:
  print('No')

Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
h, a = map(int, input().split())
count = 0
while h > 0:
    h -= a
    count += 1
print(count)

h, n = map(int, input().split())
l = list(map(int, input().split()))
if h > sum(l):
    print("No")
else:
    print("Yes")

Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
h,n=map(int,input().split())
a=list(map(int,input().spliy()))
sum=0
for i in a:
  sum=sum+i
  
if sum >=h:
  print('Yes')
else:
  print('No')

h,n=map(int,input().split())
a=list(map(int,input().spliy()))
sum=0
for i in n:
  sum=sum+a[i]
  
if sum >=h:
  print('Yes')
else:
  print('No')


h,n=map(int,input().split())
a=list(map(int,input().split()))
sum=0
for i in a:
  sum=sum+i
  
if sum >=h:
  print('Yes')
else:
  print('No')

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
h, n = (int(x) for x in input().split())
A = list(map(int, input().split()))

if n == len(A):
    if sum(A) > h:
        print('yes')
    else:
        print('No')

h, n = (int(x) for x in input().split())
A = list(map(int, input().split()))

if n == len(A):
    if sum(A) >= h:
        print('yes')
    else:
        print('No')

h, n = (int(x) for x in input().split())
A = list(map(int, input().split()))

if n == len(A):
    if sum(A) >= h:
        print('Yes')
    else:
        print('No')

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
print('No' if int(input().split()[0])<sum(list(map(int, input().split()))) else 'Yes')

print('No' if int(input().split()[0])>sum(list(map(int, input().split()))) else 'Yes')

Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
h, n = map(int, input().split())
a = list(map(int, input().split()))

sum = 0
for i int range(n):
  sum += a[i]

if h <= sum:
  print('YES')
else:
  print('NO')


h, n = map(int, input().split())
a = list(map(int, input().split()))
 
sum = 0
for i in range(n):
  sum += a[i]
 
if h <= sum:
  print('YES')
else:
  print('NO')

h, n = map(int, input().split())
a = list(map(int, input().split()))
 
sum = 0
for i in range(n):
  sum += a[i]
 
if h <= sum:
  print('Yes')
else:
  print('No')

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
h, n = map(int, input().split())

a = [map(int, input().split()) for _ in range(n)]
print(a)
for i in a:
    h -= a
if h <= 0:
    print('Yes')
else:
    print('No')


h, n = map(int, input().split())

a = [map(int, input().split()) for _ in range(n)]

h -= sum(a)
if h <= 0:
    print('Yes')
else:
    print('No')

def can_win_without_repeated_move(health, special_moves_damages) -> str:
    """
    Given a monster's health and a number of special moves with differ damages,
    can we deplete the monster's health without repeating the same move twice?
    :param health: int
    :param special_moves_damages: list[int]
    :return: str
    """
    return 'Yes' if health <= sum(special_moves_damages) else 'No'


if __name__ == '__main__':
    print(can_win_without_repeated_move(list(map(int, input().split()))[0], list(map(int, input().split()))))


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
x, y = map(int, input().split())
a = list(map(int, input().split()))
print("yes" if sum(a) >= x else "no")

x, y = map(int, input().split())
a = list(map(int, input().split()))
print("Yes" if sum(a) >= x else "No")

Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
h, n = (int(x) for x in input().split())
a = list((int(x) for x in input().split()))
a.sort()
for num in range(n):
  h -= num
if h <= 0:
  print('Yes')
else:
  print('No')
      

h, n = (int(x) for x in input().split())
a = list((int(x) for x in input().split()))
a.sort()
k = 0
for num in a:
  h -= num
  k += 1
  if k == n:
    break
if h <= 0:
  print('Yes')
else:
  print('No')

Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H,N=map(int,input().split())
a=0
for i in range(N):
	b=int(input())
	a+=b
if H>a:
	print('No')
else:
	print('Yes')

H,N=map(int,input().split())
a=list(map(int,input().split()))
b=sum(a)
if H>b:
	print('No')
else:
	print('Yes')

Verdicts: Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H, N = map(int, input().split())
A= [0] * N
for i in range(N):
    A[i]= map(int, input().split())
 
if sum(A[i])>N:
    print("Yes")
else:
    print("No")

H, N = map(int, input().split())
A= [0] * N
for i in range(N):
    A[i]= map(int, input().split())
 
if (sum(A[i]>N):
    print("Yes")
else:
    print("No")

N = int(input())
A = list(map(int, input().split()))
if sum(A)>=H:
    print("Yes")
else:
    print("No")

H, N = map(int, input().split())
A= [0] * N
for i in range(N):
    A[i]= map(int, input().split())
 
if sum(A)>H:
    print("Yes")
else:
    print("No")

H, N = map(int, input().split())
A= [0] * N
for i in range(N):
    A[i]= map(int, input().split())

if (sum(A[i]>N);
    print("Yes")
else;
    print("No")

H, N = map(int, input().split())
A= [0] * N
for i in range(N):
    A[i]= map(int, input().split())
if sum(A)>=H:
    print("Yes")
else:
    print("No")

H, N = map(int, input().split())
A= [0] * N
for i in range(N):
    A[i]= map(int, input().split())
 
if sum(A[i])>H:
    print("Yes")
else:
    print("No")

H,N = int(input())
A = list(map(int, input().split()))
if sum(A)>=H:
    print("Yes")
else:
    print("No")


H,N = map(int,input().split())
A = list(map(int, input().split()))
if sum(A)>=H:
    print("Yes")
else:
    print("No")


Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
a,b = map(int,input().split())
print(sum(map(int,input().split())))

a,b = map(int,input().split());s=sum(map(int,input().split()));print('Yes' if s>=a else 'No')

Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H, N=map(int,input().split())
A=list(map(int,input().split())
if H<=sum(A):
       print('Yes')
else:
       print('No')

H,N=map(int,input().split())
A=list(map(int,input().split()))
if H<=sum(A):
    print('Yes')
else:
    print('No')

Verdicts: Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
h, n = map(int, input().split())
Deathblow = list(map(int, input().split()))
for i in n:
  h -= Deathblow[i]
if h < 1:
  print("Yes")
else:
  print("No")

h, n = map(int, input().split())
Deathblow = list(map(int, input().split()))
for i in range(n):
  h -= Deathblow[i]
if h < 1:
  print("Yes")
else:
  print("No")

Verdicts: Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H,N = (input()).split(" ")
H=(int)(H)
N=(int)(N)
As = (input()).split(" ")

sum=0

for A in As:
  sum+=(int)(A)
  
if sum>=A:
  print("Yes")
else:
  print("No")

H,N = (input()).split(" ")
H=(int)(H)
N=(int)(N)
As = (input()).split(" ")
 
sum=0
 
for A in As:
  sum+=(int)(A)
  
if sum>=H:
  print("Yes")
else:
  print("No")

Verdicts: Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
a,b=map(int,input().split(' '))
print((a+b-1)//b)


n,m=map(int,input().split(' '))
a=map(int,input().split(' '))
if sum(a)>=n:
  print("Yes")
else:
  print("No")


Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H, N = map(int, input().split())
A = map(int, input().split())
Ans = 0

for x in A:
  Ans += x
  
if(Ans >= H):
  print(`Yes`)
else:
  print(`No`)

H, N = map(int, input().split())
A = map(int, input().split())
Ans = 0
 
for x in A:
  Ans += x
  
if Ans >= H:
  print('Yes')
else:
  print('No')

Verdicts: Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
line=input()
data=input()
line=line.split()
data=data.split()
num=int(line[0])
print(num)
for i in range(int(line[1])):
    num-=int(data[i])
if num>0:
    print("No")
else:
    print("Yes")

line=input()
data=input()
line=line.split()
data=data.split()
num=int(line[0])
for i in range(int(line[1])):
    num-=int(data[i])
if num>0:
    print("No")
else:
    print("Yes")

Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
h, n = map(int, input().split())
a = input().split()

a.sort(reverse=True)

sum=0
for i in range(n):
  sum += a[i]
  
if sum>=h:
  print("Yes")
else:
  print("No")

h, n = map(int, input().split())
a = input().split()

a.sort(reverse=True)

sum=0
for i in Range(N):
  sum += a[i]
  
if sum>=h:
  print("Yes")
else:
  print("No")

h, n = map(int, input().split())
a = list(map(int, input().split()))

a.sort(reverse=True)

sum=0
for i in range(n):
  sum += a[i]
  
if sum>=h:
  print("Yes")
else:
  print("No")

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):

def main():
    H, _, *A = map(int, input().split())
    print("Yes" if sum(A) >= H else "No")


if __name__ == "__main__":
    main()



def main():
    H, _, *A = map(int, open(0).read().split())
    print("Yes" if sum(A) >= H else "No")


if __name__ == "__main__":
    main()


Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H, N = list(map(int, input().split(' ')))
# A_list = list(map(int, input().split(' ')))
A_list = [int(x) for x in input().split()]
sum_atack = sum(A_list)
if sum_atack >= H:
    print('YES')
else:
    print('NO')

H, N = list(map(int, input().split(' ')))
A_list = list(map(int, input().split(' ')))
sum_atack = sum(A_list)
if sum_atack >= H:
    print('YES')
else:
    print('NO')

H, N = list(map(int, input().split(' ')))
A_list = list(map(int, input().split(' ')))
sum_atack = sum(A_list)
if sum_atack >= H:
    print('Yes')
else:
    print('No')

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
l1 = list(map(int, input().split()))
l2 = list(map(int, input().split()))

def attack2(l1, l2):
    H = l1[0]
    N = l1[1]
    A = sum(l2)
    result = H - A
    if result >0:
        return "no"
    else:
        return "yes"
      
print(attack2(l1, l2))

l1 = list(map(int, input().split()))
def attack2(l1):
    H, N= l1[0], l1[1]
    v = 0
    for i in range(2, N):
        v += l1[i]
    result = H - v
    if result >0:
        return "no"
    else:
        return "yes"
print(attack2(l1))

l1 = list(map(int, input().split()))
l2 = list(map(int, input().split()))
 
H  int(l1[0])
N = int(l1[1])
A = int(sum(l2))
result = H - A
if result <= 0:
    print("Yes")
else:
    print("No")

l1 = list(map(int, input().split()))

def attack2(l1):
    H, N= l1[0], l1[1]
    v=0
    for i in range(2, len(l1)):
        v += l1[i]
    result = H - v
    if result >0:
        return "no"
    else:
        return "yes"
print(attack2(l1))

l1 = list(map(int, input().split()))
l2 = list(map(int, input().split()))
 
H = int(l1[0])
A = int(sum(l2))
result = H - A
if result <= 0:
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Runtime Error

Runtime Error

Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
h, n = map(int, input().split())
an = list(map(int, input().split()))

if sum(an) > h:
  print('No')
else:
  print('Yes')

h, n = map(int, input().split())
an = list(map(int, input().split()))

if sum(an) >= h:
  print('Yes')
else:
  print('No')


Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H,N=map(int,input().split())
A=[]
for i in range(N):
  A.append(int(input()))
print('YNeos'[H<sum(A)::2])
           

H,N=map(int,input().split())
print('NYoe s'[H<=sum(list(map(int,input().split())))::2])

Verdicts: Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):

inputa = input()

h,n = inputa.split()
H=int(h)
N=int(n)
inputb=input()
Attacks=inputb.split()
Attacks.sort(reverse=True)
print(Attacks)
cnt=0
maxlen=len(Attacks)
for i in range(N):
  H=H-int(Attacks[maxlen-i-1])
  cnt=cnt+1

if(H >0):
  print("No")
else:
  print("Yes")


h, n = list (map (int, input ().split ()))
a = list (map (int, input ().split ()))
print ("Yes" if sum (a) >= h else "No")

Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
h,n = map(int,input().split())
alist = list(map(int,input().split()))
while n >0:
    n -= 1
    h = h-alist[n]
if h <=0:
    print('YES') 
else:
    print('NO')

h,n = map(int,input().split())
alist = list(map(int,input().split()))

while n >0:
    n -= 1
    h = h-alist[n]
if h <=0:
    print('YES') 
else:
    print('NO')

h,n = map(int,input().split())
alist = list(map(int,input().split()))
while n >=0:
    n -= 1
    h = h-alist[n]
if h <=0:
    print('YES') 
else:
    print('NO')

h,n = map(int,input().split())
alist = list(map(int,input().split()))
 
while n >0:
    n -= 1
    h = h-alist[n]
if h <=0:
    print('Yes') 
else:
    print('No')

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H, N = list(map(str, input().split()))
A = list(map(str, input().split()))

if sum(A)>=H:
    print("Yes")
else:
    print("No")

H, N = list(map(int, input().split()))
A = list(map(int, input().split()))

if sum(A)>=H:
    print("Yes")
else:
    print("No")

Verdicts: Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
a,b = map(int,input().split())
c = list(map(int,input().split()))

d = []

d = sorted(c, reverse = True)

i = sum(d[:2])

if a / i <= 0:
  print("yes")
else:
  print("no")










a,b = map(int,input().split())
c = list(map(int,input().split()))

d = sum(c)

if a <= d:
  print("Yes")
else:
  print("No")


Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):









h, n = map(int, input().split())
A = list(map(int, input(). split()))





def hp(h: int, n: int, A: list) -> str:
    damage = 0                   
    for i in range(0, n):        
        damage += int(A[i])      
        i += 1                 

    if damage < 0:     
        return 'No'
    else:              
        return 'Yes'










h, n = map(int, input().split())
A = list(map(int, input(). split()))





def hp(h: int, n: int, A: list) -> str:
    damage = 0                   
    for i in range(0, n):        
        damage += int(A[i])      
        i += 1                   

    if (h - damage) <= 0:     
        return 'Yes'
    else:              
        return 'No'


print(hp(h, n, A))

# TypeError: list expected at most 1 argument, got 2

Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):





h, m = map(int, input().split())
a = list(map(int, input().split()))





hissatu_hp = sum(a)


result = ""
if hissatsu_hp >= h:
    result = "Yes"
else:
    result = "No"

print(result)







h, m = map(int, input().split())
a = list(map(int, input().split()))


hissatsu_hp = 0
for i in range(0, m):
    hissatsu_hp += a[i]


result = ""
if hissatsu_hp >= h:
    result = "Yes"
else:
    result = "No"

print(result)


Verdicts: Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
H, N = map(int, input().split())
count = 0
A = list(map(int, input().split()))
for i in range(N):
    Ai = A[i]
    count += Ai
if H <= Ai:
    print('Yes')
else:
    print('No')


H, N = map(int, input().split())
count = 0
A = list(map(int, input().split()))
for i in range(N):
    Ai = A[i]
    count += Ai
if H <= count:
    print('Yes')
else:
    print('No')


Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
val = input().split(' ')
h = int(val[0])
n = int(val[1])
skills = [int(i) for i in input().split(' ')]

able = False
for i in skills:
    h -= i
    if h <= 0:
        able = True
        break

print(able)


val = input().split(' ')
h = int(val[0])
n = int(val[1])
skills = [int(i) for i in input().split(' ')]

able = 'No'
for i in skills:
    h -= i
    if h <= 0:
        able = 'Yes'
        break

print(able)


Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
n,k = map(int,input().split())
hs = list(map(int,input().split()))

hs.sort()

print(sum(hs[:len(hs)-k]))



h,n = map(int,input().split())
AS = list(map(int,input().split()))

print('Yes' if h <= sum(AS) else 'No')

Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
h,n = map(int,input().split())
a = list(map,input().split())

if sum(a) >= h:
    print('Yes')
else:
    print('No')


h,n = map(int,input.split())
a = list(map,input().split())

if sum(a) >= h:
    print('Yes')
else:
    print('No')


h,n = map(int,input().split())
a = list(map(int,input().split()))

if sum(a) >= h:
    print('Yes')
else:
    print('No')


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
a,b=map(int,input().split())
n=[int(input()) for i in reange(b+1)]
if a<=sum(n):
  print('Yes')
else:
  print('No')

a,b=map(int,input().split())
n=list(map(int,input().split()))
if a<=sum(n):
  print('Yes')
else:
  print('No')

Verdicts: Runtime Error

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
h, n = map(int, input().split())
A = list(map(int, input().split()))
A.sort(reverse=True)
if sum(A[:n]) >= h:
    print('YES')
else:
    print('NO')

h, n = map(int, input().split())
A = list(map(int, input().split()))
A.sort(reverse=True)
if sum(A[:n]) >= h:
    print('Yes')
else:
    print('No')

Verdicts: Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
a,b=map(int,input().split())
s=list(map(int,input().split()))
count=0
for i in range(b):
    if count==0:
        for j in range(i,b):
            if a<s[i]+s[j] and count==0:
                print("yes")
                count+=1
if count==0:
    print("no")


a,b=map(int,input().split())
s=list(map(int,input().split()))
if a<=sum(s):
    print ("yes")
else:
    print("no")



a,b=map(int,input().split())
s=list(map(int,input().split()))
if a<=sum(s):
    print ("Yes")
else:
    print("No")



Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: Raccoon is fighting with a monster.  The _health_ of the monster is H.  Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i. There is no other way to decrease the monster's health.  Raccoon wins when the monster's health becomes 0 or below.  If Raccoon can win without using the same move twice or more, print `Yes`; otherwise, print `No`.

Submission attempts (in order):
#!/usr/bin/env python3
# -*- coding: utf-8 -*-

h, n = map(int, input().split())
a = [int(i) for i in input().split()]

a.sort(key = lambda x : -1*x)

if h > a[0] + a[1]:
    print("Yes")
else:
    print("No")

#!/usr/bin/env python3
# -*- coding: utf-8 -*-

h, n = map(int, input().split())
a = [int(i) for i in input().split()]

d = 0
for i in a:
    d += i

if h > d:
    print("No")
else:
    print("Yes")

Verdicts: Runtime Error

Accepted