TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: There are N people, conveniently numbered 1 through N. They were standing in a row yesterday, but now they are unsure of the order in which they were standing. However, each person remembered the following fact: the absolute difference of the number of the people who were standing to the left of that person, and the number of the people who were standing to the right of that person. According to their reports, the difference above for person i is A_i.  Based on these reports, find the number of the possible orders in which they were standing. Since it can be extremely large, print the answer modulo 10^9+7. Note that the reports may be incorrect and thus there may be no consistent order. In such a case, print 0.

Submission attempts (in order):
n=int(input())
a=list(map(int,input().split()))
a.sort()
if n%2==1:
    if a[0]!=0:
        print(0)
        exit()
    for i in range(n//2):
        if a[2*i+1]!=2*(i+1) or a[2*(i+1)]!=2*(i+1):
            print(0)
            exit()
    print((pow(2,n//2))%(1e9+7))
else:
    for i in range(n//2):
        if a[2*i]!=2*i+1 or a[2*i+1]!=2*i+1:
            print(0)
            exit()
    print(((pow(2,n//2))%(1e9+7)))

n=int(input())
a=list(map(int,input().split()))
a.sort()
if n%2==1:
    if a[0]!=0:
        print(0)
        exit()
    for i in range(n//2):
        if a[2*i+1]!=2*(i+1) or a[2*(i+1)]!=2*(i+1):
            print(0)
            exit()
    print(pow(2,n//2)%(1e9+7))
else:
    for i in range(n//2):
        if a[2*i]!=2*i+1 or a[2*i+1]!=2*i+1:
            print(0)
            exit()
    print(pow(2,n//2)%(1e9+7))

n=int(input())
a=list(map(int,input().split()))
a.sort()
if n%2==1:
    if a[0]!=0:
        print(0)
        exit()
    for i in range(n//2):
        if a[2*i+1]!=2*(i+1) or a[2*(i+1)]!=2*(i+1):
            print(0)
            exit()
    print((pow(2,n//2))%(1e9+7))
else:
    for i in range(n//2):
        if a[2*i]!=2*i+1 or a[2*i+1]!=2*i+1:
            print(0)
            exit()
    print((pow(2,n//2))%(1e9+7))

n=int(input())
a=list(map(int,input().split()))
a.sort()
if n%2==1:
    if a[0]!=0:
        print(0)
        exit()
    for i in range(n//2):
        if a[2*i+1]!=2*(i+1) or a[2*(i+1)]!=2*(i+1):
            print(0)
            exit()
    print(pow(2,n//2)%(10**9+7))
else:
    for i in range(n//2):
        if a[2*i]!=2*i+1 or a[2*i+1]!=2*i+1:
            print(0)
            exit()
    print(pow(2,n//2)%(10**9+7))

Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: There are N people, conveniently numbered 1 through N. They were standing in a row yesterday, but now they are unsure of the order in which they were standing. However, each person remembered the following fact: the absolute difference of the number of the people who were standing to the left of that person, and the number of the people who were standing to the right of that person. According to their reports, the difference above for person i is A_i.  Based on these reports, find the number of the possible orders in which they were standing. Since it can be extremely large, print the answer modulo 10^9+7. Note that the reports may be incorrect and thus there may be no consistent order. In such a case, print 0.

Submission attempts (in order):
# -*- coding: utf-8 -*-

people_num = int(input())
line_list = list(map(int, input().split()))

num_odd = True
bool_false = True

line_list.sort()

if(people_num%2 == 0):
    num_odd = False

for i in range(people_num):

    if(num_odd):
        if(line_list[i] == 2*((i+1)//2)):
            continue
        else:
            bool_false = False
            break
    else:
        if(line_list[i] == 2*((i)//2) +1):
            continue
        else:
            bool_false = False
            break

print(bool_false)
if(bool_false):
    print((people_num//2) **2)
else:
    print(0)

# -*- coding: utf-8 -*-

people_num = int(input())
line_list = list(map(int, input().split()))

num_odd = True
bool_false = True

line_list.sort()

if(people_num%2 == 0):
    num_odd = False



for i in range(people_num):

    if(num_odd):
        if(line_list[i] == 2*((i+1)//2)):
            continue
        else:
            bool_false = False
            break
    else:
        if(line_list[i] == 2*((i)//2) +1):
            continue
        else:
            bool_false = False
            break

if(len(people_num) == 1):
    print(1)
elif(bool_false):
    print((people_num//2) **2)
else:
    print(0)

# -*- coding: utf-8 -*-

people_num = int(input())
line_list = list(map(int, input().split()))

num_odd = True
bool_false = True

line_list.sort()

if(people_num%2 == 0):
    num_odd = False

for i in range(people_num):

    if(num_odd):
        if(line_list[i] == 2*((i+1)//2)):
            continue
        else:
            bool_false = False
            break
    else:
        if(line_list[i] == 2*(i//2) +1):
            continue
        else:
            bool_false = False
            break

if(people_num == 1):
    print(1)
elif(bool_false):
    print((2**(people_num // 2) % (10**9 +7)))
else:
    print(0)

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: There are N people, conveniently numbered 1 through N. They were standing in a row yesterday, but now they are unsure of the order in which they were standing. However, each person remembered the following fact: the absolute difference of the number of the people who were standing to the left of that person, and the number of the people who were standing to the right of that person. According to their reports, the difference above for person i is A_i.  Based on these reports, find the number of the possible orders in which they were standing. Since it can be extremely large, print the answer modulo 10^9+7. Note that the reports may be incorrect and thus there may be no consistent order. In such a case, print 0.

Submission attempts (in order):
n = int(input())
a = list(int(i) for i in input().split())
if n%2==0 and sum(a)==n*n//2 or n%2 ==1 and sum(a) == (n+1)*n//2:
    print(2**(n//2)%(10**9+7))

n = int(input())
a = list(int(i) for i in input().split())
if n%2==0 and sum(a)==n*n//2 or n%2 ==1 and sum(a) == (n+1)*n//2:
    print(2**(n//2)%(10**9+7))
else:
    print(0)

n = int(input())
a = list(int(i) for i in input().split())
if n%2==0 and sum(a)==n*n//2 or n%2==1 and sum(a) == (n+1)*(n//2):
    print(2**(n//2)%(10**9+7))
else:
    print(0)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: There are N people, conveniently numbered 1 through N. They were standing in a row yesterday, but now they are unsure of the order in which they were standing. However, each person remembered the following fact: the absolute difference of the number of the people who were standing to the left of that person, and the number of the people who were standing to the right of that person. According to their reports, the difference above for person i is A_i.  Based on these reports, find the number of the possible orders in which they were standing. Since it can be extremely large, print the answer modulo 10^9+7. Note that the reports may be incorrect and thus there may be no consistent order. In such a case, print 0.

Submission attempts (in order):
from collections import Counter

N = int(input())
A = map(int, input().split())
# N = 5
# A = [2, 4, 4, 0, 2]
mod = 10 ** 9 + 7

cnt = Counter(A)
if N % 2 == 0:
    if len(filter(lambda c: c == 2, cnt.values())) != 0:
        print(0)
    else:
        print(2 ** (N // 2))
else:
    if cnt[0] != 1:
        print(0)
    cnt.pop(0)
    if len(filter(lambda c: c == 2, cnt.values())) != 0:
        print(0)
    else:
        print(2 ** (N // 2))


#!/usr/bin/env python
# -*- coding:utf-8 -*-

from collections import Counter
import sys
N = int(input())
A = list(map(int, input().split()))

MOD = 10**9 + 7
A = Counter(A)

if N % 2 == 1:
    for num, cnt in A.items():
        # print(num, cnt)
        if (num == 0 and cnt != 1):
            print(0)
            sys.exit()
        elif not (num % 2 == 0 and cnt == 2):
            print(0)
            sys.exit()
    print(2 ** (N // 2))
else:
    for num, cnt in A.items():
        # print(num, cnt)
        if not (num % 2 == 1 and cnt == 2):
            print(0)
            sys.exit()
    print(2 ** (N // 2))


from collections import Counter

N = int(input())
A = map(int, input().split())
# N = 5
# A = [2, 4, 4, 0, 2]
mod = 10 ** 9 + 7

cnt = Counter(A)
if N % 2 == 0:
    if len(list(filter(lambda c: c != 2, cnt.values()))) != 0:
        print(0)
    else:
        print((2 ** (N // 2)) % mod)
else:
    if cnt[0] != 1:
        print(0)
    else:
        cnt.pop(0)
        if len(list(filter(lambda c: c != 2, cnt.values()))) != 0:
            print(0)
        else:
            print((2 ** (N // 2)) % mod)


Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: There are N people, conveniently numbered 1 through N. They were standing in a row yesterday, but now they are unsure of the order in which they were standing. However, each person remembered the following fact: the absolute difference of the number of the people who were standing to the left of that person, and the number of the people who were standing to the right of that person. According to their reports, the difference above for person i is A_i.  Based on these reports, find the number of the possible orders in which they were standing. Since it can be extremely large, print the answer modulo 10^9+7. Note that the reports may be incorrect and thus there may be no consistent order. In such a case, print 0.

Submission attempts (in order):
n = int(input())

a = list(map(int,input().split()))
a.sort()
if n % 2 == 0:
    b = 0
    for i in range(0,n,2):
        if a[i] == a[i+1] and a[i] == i+1:
            b = 1
    if b == 1:
        print(0)
    else:
        print(2**(n//2))
else:
    b = 0
    if a[0] != 0:
        b = 1
    else:
        for i in range(1,n,2):
            if a[i] == a[i+1] and a[i] == i+1:
                b = 1
    if b == 1:
        print(0)
    else:
        print(2**(n//2))

n = int(input())

a = list(map(int,input().split()))
a.sort()
if n % 2 == 0:
    b = 0
    for i in range(0,n,2):
        if a[i] != a[i+1] and a[i] != i+1:
            b = 1
    if b == 1:
        print(0)
    else:
        print((2**(n//2))%1000000007)
else:
    b = 0
    if a[0] != 0:
        b = 1
    else:
        for i in range(1,n,2):
            if a[i] != a[i+1] and a[i] != i+1:
                b = 1
    if b == 1:
        print(0)
    else:
        print((2**(n//2))%1000000007)

Verdicts: Wrong Answer

Accepted
Problem: There are N people, conveniently numbered 1 through N. They were standing in a row yesterday, but now they are unsure of the order in which they were standing. However, each person remembered the following fact: the absolute difference of the number of the people who were standing to the left of that person, and the number of the people who were standing to the right of that person. According to their reports, the difference above for person i is A_i.  Based on these reports, find the number of the possible orders in which they were standing. Since it can be extremely large, print the answer modulo 10^9+7. Note that the reports may be incorrect and thus there may be no consistent order. In such a case, print 0.

Submission attempts (in order):
n=int(input())
#ne,[7,5,3,1,1,3,5,7]8
#no,[8,6,4,2,0,2,4,6,8]9
m=[0]*n
for i in map(int,input().split()):
  m[i]+=1
ans=1
for i in range(n-1,0,-2):
  d[i]!=2:
    ans=0
if d[0]!=n%2:
  ans=0
if ans:
  print(2**(n//2)%1000000007)
else:
  print(0)
    

n=int(input())
#ne,[7,5,3,1,1,3,5,7]8
#no,[8,6,4,2,0,2,4,6,8]9
m=[0]*n
for i in map(int,input().split()):
  m[i]+=1
ans=1
for i in range(n-1,0,-2):
  if d[i]!=2:
    ans=0
if d[0]!=n%2:
  ans=0
if ans:
  print(2**(n//2)%1000000007)
else:
  print(0)
    

n=int(input())
#ne,[7,5,3,1,1,3,5,7]8
#no,[8,6,4,2,0,2,4,6,8]9
m=[0]*n
for i in map(int,input().split()):
  m[i]+=1
ans=1
for i in range(n-1,0,-2):
  if m[i]!=2:
    ans=0
if m[0]!=n%2:
  ans=0
if ans:
  print(2**(n//2)%1000000007)
else:
  print(0)
    

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: There are N people, conveniently numbered 1 through N. They were standing in a row yesterday, but now they are unsure of the order in which they were standing. However, each person remembered the following fact: the absolute difference of the number of the people who were standing to the left of that person, and the number of the people who were standing to the right of that person. According to their reports, the difference above for person i is A_i.  Based on these reports, find the number of the possible orders in which they were standing. Since it can be extremely large, print the answer modulo 10^9+7. Note that the reports may be incorrect and thus there may be no consistent order. In such a case, print 0.

Submission attempts (in order):
import sys
from collections import Counter

n = int(input())
arr = list(map(int, input().split()))

if arr.count(0) > 1:
    print(0)
    sys.exit()

if len(arr) % 2 == 0 and arr.count(0) > 0:
    print(0)
    sys.exit()

cnt = Counter(arr)

li = list(cnt.values())

if li.count(2) != n // 2:
    print(0)
    sys.exit()

if not all([x <= 2 for x in li]):
    print(0)
    sys.exit(0)

print(reduce(mul, li))

import sys
from collections import Counter

n = int(input())
arr = list(map(int, input().split()))

if len(arr) % 2 == 0:
    if 0 in arr:
        print(0)
        sys.exit()
else:
    if arr.count(0) != 1:
        print(0)
        sys.exit()
    else:
        arr.remove(0)

cnt = Counter(arr)

values = list(cnt.values())

if values.count(2) != len(values):
    print(0)
    sys.exit()

mod = 10**9 + 7

print(2**(n // 2) % mod)

Verdicts: Runtime Error

Accepted
Problem: There are N people, conveniently numbered 1 through N. They were standing in a row yesterday, but now they are unsure of the order in which they were standing. However, each person remembered the following fact: the absolute difference of the number of the people who were standing to the left of that person, and the number of the people who were standing to the right of that person. According to their reports, the difference above for person i is A_i.  Based on these reports, find the number of the possible orders in which they were standing. Since it can be extremely large, print the answer modulo 10^9+7. Note that the reports may be incorrect and thus there may be no consistent order. In such a case, print 0.

Submission attempts (in order):
from collections import Counter
n = int(input())
a = list(map(int,input().split()))
mod = 10 ** 9 + 7

cnt = Counter(a)
if n % 2 == 0:
    for i, j in cnt.items():
        if j != 2 or not(1 <= i <= n - 1) :
            print(0)
            exit()
else:
    for i, j in cnt.items():
        if i == 0:
            if j != 0:
                print(0)
                exit()
        else:
            if j != 2 or not(1 <= i <= n - 1):
                print(0)
                exit()

num = n // 2
ans = pow(2, num, mod)
print(ans)

from collections import Counter
n = int(input())
a = list(map(int,input().split()))
mod = 10 ** 9 + 7

cnt = Counter(a)
if n % 2 == 0:
    for i, j in cnt.items():
        if j != 2 or not(1 <= i <= n - 1) :
            print(0)
            exit()
else:
    for i, j in cnt.items():
        if i == 0:
            if j != 1:
                print(0)
                exit()
        else:
            if j != 2 or not(1 <= i <= n - 1):
                print(0)
                exit()

num = n // 2
ans = pow(2, num, mod)
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: There are N people, conveniently numbered 1 through N. They were standing in a row yesterday, but now they are unsure of the order in which they were standing. However, each person remembered the following fact: the absolute difference of the number of the people who were standing to the left of that person, and the number of the people who were standing to the right of that person. According to their reports, the difference above for person i is A_i.  Based on these reports, find the number of the possible orders in which they were standing. Since it can be extremely large, print the answer modulo 10^9+7. Note that the reports may be incorrect and thus there may be no consistent order. In such a case, print 0.

Submission attempts (in order):
N = int(input())
A = list(map(int, input().split()))

from collections import Counter
cd = Counter(A)
# A.sort()

if N & 1:
    
    if cd[0] != 1:
        print(0)
        exit(0)
    ng = False

    for ix in range(2, N//2 + 1, 2):
        if cd[ix] != 2:
            ng = True
            break

    if len(cd) != N//2 + 1:
        ng = True
    
    if ng:
        print(0)
    else:
        print(2**N//2)

else:
    # even
    ng = False
    for ix in range(1, N//2+1, 2):
        if cd[ix] != 2:
            ng = True
            break
    
    if len(cd) != N//2:
        ng = True
    
    if ng:
        print(0)
    else:
        print(2**N//2)


N = int(input())
A = list(map(int, input().split()))
M = 10**9+7

from collections import Counter
cd = Counter(A)
# A.sort()

if N & 1:
    
    if cd[0] != 1:
        print(0)
        exit(0)
    ng = False

    for ix in range(2, N//2 + 1, 2):
        if cd[ix] != 2:
            ng = True
            break

    if len(cd) != N//2 + 1:
        ng = True
    
    if ng:
        print(0)
    else:
        # print(pow(2,(N//2),M))
        ans = 1
        for ix in range(N//2):
            ans *= 2
            ans %= M
        print(ans)

else:
    # even
    ng = False
    for ix in range(1, N//2+1, 2):
        if cd[ix] != 2:
            ng = True
            break
    
    if len(cd) != N//2:
        ng = True
    
    if ng:
        print(0)
    else:
        # print(pow(2,(N//2),M))
        ans = 1
        for ix in range(N//2):
            ans *= 2
            ans %= M
        print(ans)


Verdicts: Wrong Answer

Accepted
Problem: There are N people, conveniently numbered 1 through N. They were standing in a row yesterday, but now they are unsure of the order in which they were standing. However, each person remembered the following fact: the absolute difference of the number of the people who were standing to the left of that person, and the number of the people who were standing to the right of that person. According to their reports, the difference above for person i is A_i.  Based on these reports, find the number of the possible orders in which they were standing. Since it can be extremely large, print the answer modulo 10^9+7. Note that the reports may be incorrect and thus there may be no consistent order. In such a case, print 0.

Submission attempts (in order):
n = int(input())
dp = [2]*n
dp[0] = 1
mod = 10**9+7
an = [int(i) for i in input().split()]

if n % 2 == 1:
  for i in an:
    if i % 2 == 1 or dp[i] == 0:
      print(0)
      exit()
    else:
      dp[i] -= 1
  print(2**((n-1)//2)//mod)
else:
  for i in an:
    if i % 2 == 0 or dp[i] == 0:
      print(0)
      exit()
    else:
      dp[i] -= 1
  print(2**(n//2)//mod)

n = int(input())
dp = [2]*n
dp[0] = 1
mod = 10**9+7
an = [int(i) for i in input().split()]

if n % 2 == 1:
  for i in an:
    if i % 2 == 1 or dp[i] == 0:
      print(0)
      exit()
    else:
      dp[i] -= 1
  print(2**((n-1)//2)%mod)
else:
  for i in an:
    if i % 2 == 0 or dp[i] == 0:
      print(0)
      exit()
    else:
      dp[i] -= 1
  print(2**(n//2)%mod)

Verdicts: Wrong Answer

Accepted
Problem: There are N people, conveniently numbered 1 through N. They were standing in a row yesterday, but now they are unsure of the order in which they were standing. However, each person remembered the following fact: the absolute difference of the number of the people who were standing to the left of that person, and the number of the people who were standing to the right of that person. According to their reports, the difference above for person i is A_i.  Based on these reports, find the number of the possible orders in which they were standing. Since it can be extremely large, print the answer modulo 10^9+7. Note that the reports may be incorrect and thus there may be no consistent order. In such a case, print 0.

Submission attempts (in order):
# 2019/08/11

from collections import Counter

n=int(input())
a=list(map(int,input().split()))

c=Counter(a)

if c.most_common(1)[0][1]>2 or c[0]>1:
    print(0)
    exit()

for k,v in c.items():
    if k!=0 and v!=2:
        print(0)
        exit()
    if n%2==v%2:
        print(0)
        exit()
        
print(2**(n//2))

# 2019/08/11

from collections import Counter

n=int(input())
a=list(map(int,input().split()))

c=Counter(a)

if c.most_common(1)[0][1]>2 or c[0]>1:
    print(0)
    exit()

for k,v in c.items():
    if k!=0 and v!=2:
        print(0)
        exit()
    if n%2==k%2:
        print(0)
        exit()
        
print(2**(n//2)%(10**9+7))

Verdicts: Wrong Answer

Accepted
Problem: There are N people, conveniently numbered 1 through N. They were standing in a row yesterday, but now they are unsure of the order in which they were standing. However, each person remembered the following fact: the absolute difference of the number of the people who were standing to the left of that person, and the number of the people who were standing to the right of that person. According to their reports, the difference above for person i is A_i.  Based on these reports, find the number of the possible orders in which they were standing. Since it can be extremely large, print the answer modulo 10^9+7. Note that the reports may be incorrect and thus there may be no consistent order. In such a case, print 0.

Submission attempts (in order):
N,M=map(int,input().split())
mod=10**9+7
a=[]
for i in range(M):
    a.append(int(input()))


DP=[1]*(N+1)

if 1 in a:
    DP[1]=0

for i in range(2,N+1):
    if i in a:
        DP[i]=0
        if DP[i-1]==0:
            print(0)
            exit()
    else:
        DP[i]=DP[i-1]+DP[i-2]
        DP[i]=DP[i]%mod

print(DP[N])


import collections

N=int(input())
A_data=list(map(int,input().split()))
mod=10**9+7

A=collections.Counter(A_data)

if N%2==1:
    if not A[0]==1:
        ans=0
    else:
        for i in range(2,N,2):
            if not A[i]==2:
                ans=0
                break
        if ans!=0:
            ans=2**((N-1)//2)%mod
elif N%2==0:
    for i in range(1,N,2):
        if not A[i]==2:
            ans=0
            break
    if ans!=0:
        ans=2**(N//2)%mod

print(ans)

N=int(input())
A=list(map(int,input().split()))

mod=10**9+7

A.sort()
f=True
if N%2==1:
    if A[0]!=0:
        f=False
    else:
        for i in range(1,N,2):
            if not (A[i]==2*(i+1)//2 and A[i+1]==2*(i+1)//2):
                f=False
                break
elif N%2==0:
    for i in range(0,N,2):
        if not (A[i]==2*(i//2)+1 and  A[i+1]==2*(i//2)+1):
            f=False
            break

if f:
    print(2**(N//2)%mod)
else:
    print(0)


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: There are N people, conveniently numbered 1 through N. They were standing in a row yesterday, but now they are unsure of the order in which they were standing. However, each person remembered the following fact: the absolute difference of the number of the people who were standing to the left of that person, and the number of the people who were standing to the right of that person. According to their reports, the difference above for person i is A_i.  Based on these reports, find the number of the possible orders in which they were standing. Since it can be extremely large, print the answer modulo 10^9+7. Note that the reports may be incorrect and thus there may be no consistent order. In such a case, print 0.

Submission attempts (in order):
from collections import Counter

n = int(input())
a = list(map(int, input().split()))
h = Counter()
for x in a:
    h[x] += 1
f = True
for k, v in h..most_common():
    if n % 2 == 1 and k == 0:
        if v != 1:
            f = False
            break
    elif v != 2:
        f = False
        break
MOD = 1000000007
def mpow(n, p, mod):
    r = 1
    while p > 0:
        if p & 1 == 1:
            r = r * n % mod
        n = n * n % mod
        p >>= 1
    return r
print(mpow(2, int(n / 2), MOD) if f else 0) 

from collections import Counter

n = int(input())
a = list(map(int, input().split()))
h = Counter()
for x in a:
    h[x] += 1
f = True
for k, v in h.most_common():
    if n % 2 == 1 and k == 0:
        if v != 1:
            f = False
            break
    elif v != 2:
        f = False
        break
MOD = 1000000007
def mpow(n, p, mod):
    r = 1
    while p > 0:
        if p & 1 == 1:
            r = r * n % mod
        n = n * n % mod
        p >>= 1
    return r
print(mpow(2, n // 2, MOD) if f else 0)

Verdicts: Runtime Error

Accepted
Problem: You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Submission attempts (in order):
s=input()
s=s.replace('eraser','#')
s=s.replace('erase','#')
s=s.replace('dreamer','#')
s=s.replace('dream')
f=1
for it in s:
    if it !='#':
        f=0
        break

if f==1:
    print("YES")
else :
    print("NO")

s=input()
s=s.replace('eraser','*')
s=s.replace('erase','*')
s=s.replace("dreamer","*")
s=s.replace("dream","*")
f=1
for i in s:
    if i!='*':
        f=0
        break
if f:
    print("YES")
else:
    print("NO")


Verdicts: Runtime Error

Accepted
Problem: You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Submission attempts (in order):
s = input()
s = s[::-1]
hoge = ['maerd', 'remaerd', 'esare', 'resare']
i = 0
j = 0
while i < len(s):
    j += 1
    i = j
    ans = ''
    while j < len(s):
        ans += s[j]
        if len(ans) > 7:
            print('NO')
            quit()
        if ans in hoge:
            break
        else:
            j += 1
print('YES')

s = input()
s = s[::-1]
hoge = ['maerd', 'remaerd', 'esare', 'resare']
i = 0
j = 0
while i < len(s):
    ans = ''
    while j < len(s):
        ans += s[j]
        if len(ans) > 7:
            print('NO')
            quit()
        if ans in hoge:
            break
        else:
            j += 1
    j += 1
    i = j
print('YES')


Verdicts: Wrong Answer

Accepted
Problem: You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Submission attempts (in order):

s = input()
l = ["dream","dreamer","erase","eraser"]

while len(s) > 0:
    for i in range(len(l)):
        if l[i] in s:
            s = s.replase(l[i],"")
        else:
            break
            
if len(s) == 0:
    print("YES")
else:
    print("NO")



s = input()
l = ["eraser","erase","dreamer","dream"]

while len(s) > 0:
    for i in range(len(l)):
        if l[i] in s:
            s = s.replase(l[i],"")
        else:
            break
            
if len(s) == 0:
    print("YES")
else:
    print("NO")



S = input()
S = S[::-1]

l = ['maerd','remaerd','esare','resare']
i = 0
while i < len(S):
    for w in l:
        if w == S[i:i+len(w)]:
            i += len(w)
            break
    else:
        print('NO')
        exit()
print('YES')

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Submission attempts (in order):
s = input().strip()
strings = "eraser erase dreamer dream".split()
exceptions = "dreameraser dreamerase".split()
while 1:
  for string in strings:
    if s.startswith(string):
      if string == "dreamer":
        for exception in exceptions:
          if startswith(exception):
            s = s[len(exception):]
      else:
s = s[len(string):]
      break
  else:
    break
print("NO" if s else "YES")

dream, erase = "dream erase".split()

s = input().strip()
while 1:
  if s.startswith(dream):
     s = s[5:]
     if s.startswith("er") and not s.startswith("era"):
       s = s[2:]
  elif s.startswith(erase):
    s = s[5:]
    if s.startswith('r'):
      s = s[1:]
  else:
    break
print("NO" if s else "YES")


Verdicts: Runtime Error

Accepted
Problem: You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Submission attempts (in order):
S = input()
rS = S[::-1]
keys = ['dream', 'dreamer', 'erase', 'eraser']
reversed_keys = [keys[i][::-1] for i in range(len(keys))]
i = 0
print(reversed_keys)
while i < len(rS):
    if rS[i:i+5] in reversed_keys:
        i += 5
    elif rS[i:i+6] in reversed_keys:
        i += 6
    elif rS[i:i+7] in reversed_keys:
        i += 7
    else:
        break
if i == len(rS):
    print('YES')
else:
    print('NO')


S = input()
rS = S[::-1]
keys = ['dream', 'dreamer', 'erase', 'eraser']
reversed_keys = [keys[i][::-1] for i in range(len(keys))]
i = 0

while i < len(rS):
    if rS[i:i+5] in reversed_keys:
        i += 5
    elif rS[i:i+6] in reversed_keys:
        i += 6
    elif rS[i:i+7] in reversed_keys:
        i += 7
    else:
        break
if i == len(rS):
    print('YES')
else:
    print('NO')


Verdicts: Wrong Answer

Accepted
Problem: You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Submission attempts (in order):
s = input()
n = len(s)
idx = 0
while idx < n:
    if idx+5 <= n and s[idx:idx+5] == 'dream':
        idx += 5
    elif s[idx:idx+4] == 'eras':
        idx += 4
    else:
        break
    if idx+2 <= n and s[idx:idx+2] == 'er' and (idx+2 == n or s[idx+2:idx+3] != 'a'):
        idx += 2
if idx == n:
    print('YES')
else:
    print('NO')

s = input()
n = len(s)
idx = 0
while idx < n:
    if idx+5 > n:
        break
    if s[idx:idx+5] == 'dream':
        idx += 5
        if idx+2 <= n and s[idx:idx+2] == 'er' and (idx+2 == n or s[idx+2:idx+3] != 'a'):
            idx += 2
    elif s[idx:idx+5] == 'erase':
        idx += 5
        if idx+1 <= n and s[idx:idx+1] == 'r':
            idx += 1
    else:
        break

if idx == n:
    print('YES')
else:
    print('NO')

Verdicts: Wrong Answer

Accepted
Problem: You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Submission attempts (in order):
dreameraser

s=list(input())
n = len(s)

c=0
k=0
while c==0:
    if k ==n:
        c = 1
    else:
        
        if k + 7 <= n-1 and s[k]=='d' and s[k+1] == 'r' and s[k+2] == 'e' and s[k+3] == 'a' and s[k+4] == 'm' and s[k+5] == 'e' and s[k+6] == 'r' and s[k+7] == 'a':
            k += 5
        elif k + 6 <= n-1 and s[k]=='d' and s[k+1] == 'r' and s[k+2] == 'e' and s[k+3] == 'a' and s[k+4] == 'm' and s[k+5] == 'e' and s[k+6] == 'r':
            k += 7
        elif k + 4 <= n-1 and s[k]=='d' and s[k+1] == 'r' and s[k+2] == 'e' and s[k+3] == 'a' and s[k+4] == 'm':
            k += 5
        elif k+6 <= n-1 and s[k] == 'e' and s[k+1] == 'r' and s[k+2] == 'a' and s[k+3] == 's' and s[k+4] == 'e' and  s[k+5] == 'r' and s[k+6] == 'a':
            k+= 5
        elif k+5 <= n-1 and s[k] == 'e' and s[k+1] == 'r' and s[k+2] == 'a' and s[k+3] == 's' and s[k+4] == 'e' and  s[k+5] == 'r':
            k += 6
        elif k+4 <= n-1 and s[k] == 'e' and s[k+1] == 'r' and s[k+2] == 'a' and s[k+3] == 's' and s[k+4] == 'e':
            k += 5
        else:
            c = 1

if k == n:
    print('YES')
else:
    print('NO')

Verdicts: Runtime Error

Accepted
Problem: You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Submission attempts (in order):
s = input()

i = 0
while s:
    str = s[i:i+5]
    if str == "dream" or str == "erase":
        i += 5
    elif str[i:i+2] == "er":
        i += 2
    else:
        print("NO")
        exit()

ans = "YES"
print(ans)


import sys
sys.setrecursionlimit(10**9)
s1 = "maerd"
s2 = "remaerd"
s3 = "esare"
s4 = "resare"

i = input()
s = ''
for c in reversed(i):
    s += c

l = len(s)

i = 0


def dfs(i):
    if i == l:
        print("YES")
        exit()
    if i+5 <= l and s[i:i+5] == s1:
        dfs(i+5)
    elif i+7 <= l and s[i:i+7] == s2:
        dfs(i+7)
    elif i+5 <= l and s[i:i+5] == s3:
        dfs(i+5)
    elif i+6 <= l and s[i:i+6] == s4:
        dfs(i+6)
    else:
        print("NO")
        exit()


dfs(0)


Verdicts: Wrong Answer

Accepted
Problem: You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Submission attempts (in order):
S = input().replace('eraser','').replace('erase','').replace('dreamer','').replace('dream','')
if S == '':
    print('Yes')
else:
    print('No')

S = input().replace('eraser','').replace('erase','').replace('dreamer','').replace('dream','')
if S == '':
    print('YES')
else:
    print('NO')

Verdicts: Wrong Answer

Accepted
Problem: You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Submission attempts (in order):
s=input()
s＝s.replace("eraser","").replace("erase","").replace("dreamer","").replace("dream","")
if s:
    print("NO")
else:
    print("YES")

s=input()
s=s.replace("eraser","").replace("erase","").replace("dreamer","").replace("dream","")
if s:
    print("NO")
else:
    print("YES")

Verdicts: Runtime Error

Accepted
Problem: You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Submission attempts (in order):
s = list(input())
s.reverse()
s = ''.join(map(str, s))
count = 0
word = ['maerd', 'remaerd', 'resare', 'esare']

while count <= len(s)-8:
  counttemp = count
  for i in range(4):
    w = word[i]
    if s[count:count+len(w)] == w:
      count += len(w)
  if counttemp == count:
    break
if s[count:] in word:
  print('YES')
else:
  print('NO')
    


s = list(input())
s.reverse()
s = ''.join(map(str, s))
count = 0
word = ['maerd', 'remaerd', 'resare', 'esare']

while count <= len(s)-8:
  counttemp = count
  for i in range(4):
    w = word[i]
    if s[count:count+len(w)] == w:
      count += len(w)
  if counttemp == count:
    break

if s[count:] in word or s[count:] =='':
  print('YES')
else:
  print('NO')

Verdicts: Wrong Answer

Accepted
Problem: You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Submission attempts (in order):
import sys

def solve(s):
    sys.stderr.write(s)
    sys.stderr.write("\n")

    while(len(s) >= 1):
        if s == "":
            return True
        elif s.startswith("maerd"):
            s = s[5:]
        elif s.startswith("remaerd"):
            s = s[7:]
        elif s.startswith("esare"):
            s = s[5:]
        elif s.startswith("resare"):
            s = s[6:]
        else:
            return False



def main():
    line = sys.stdin.readline().rstrip()
    line_rev = line[::-1]

    if solve(line):
        print("YES")
    else:
        print("NO")

    return 0

if __name__ == '__main__':
    sys.exit(main())


import sys
sys.setrecursionlimit(10000)

def solve(s):
    if s == "":
        return True
    elif s.endswith("dream"):
        return solve(s[:-5])
    elif s.endswith("dreamer"):
        return solve(s[:-7])
    elif s.endswith("erase"):
        return solve(s[:-5])
    elif s.endswith("eraser"):
        return solve(s[:-6])
    else:
        return False
    return False


def main():
    line = sys.stdin.readline()

    if solve(line):
        print("YES")
    else:
        print("NO")

    return 0

if __name__ == '__main__':
    sys.exit(main())


import sys

def solve(s):
    if s == "":
        return True
    elif s.endswith("dream"):
        return solve(s[:-5])
    elif s.endswith("dreamer"):
        return solve(s[:-7])
    elif s.endswith("erase"):
        return solve(s[:-5])
    elif s.endswith("eraser"):
        return solve(s[:-6])
    else:
        return False
    return False


def main():
    line = sys.stdin.readline()

    if solve(line):
        print("YES")
    else:
        print("NO")

    return 0

if __name__ == '__main__':
    sys.exit(main())


import sys

def solve(s):
    tmp_s = s
    while(len(tmp_s) > 0):
        if tmp_s.startswith("maerd"):
            tmp_s = tmp_s[5:]
        elif tmp_s.startswith("remaerd"):
            tmp_s = tmp_s[7:]
        elif tmp_s.startswith("esare"):
            tmp_s = tmp_s[5:]
        elif tmp_s.startswith("resare"):
            tmp_s = tmp_s[6:]
        else:
            return False

    return True

def main():
    line = sys.stdin.readline().rstrip()
    line_rev = line[::-1]

    if solve(line_rev):
        print("YES")
    else:
        print("NO")

    return 0

if __name__ == '__main__':
    sys.exit(main())


Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Submission attempts (in order):
s = input()

def solve(s):
    i = 0
    n = len(s)

    while i < n:
        if s[i:i+5] == 'dream':
            if s[i+5:i+7] != 'er':
                i += 5
            elif i+7 < n and s[i+7] == 'a':
                i += 5
            else:
                i += 7
        elif s[i:i+5] == 'erase':
            if s[i+5] == 'r':
                i += 6
            else:
                i += 5
        else:
            return False
    return True

if solve(s):
    print("Yes")
else:
    print('No')


s = input()

def solve(s):
    i = 0
    n = len(s)

    while i < n:
        if s[i:i+5] == 'dream':
            if s[i+5:i+7] != 'er':
                i += 5
            elif i+7 < n and s[i+7] == 'a':
                i += 5
            else:
                i += 7
        elif s[i:i+5] == 'erase':
            if i+5 < n and s[i+5] == 'r':
                i += 6
            else:
                i += 5
        else:
            return False
    return True

if solve(s):
    print("YES")
else:
    print('NO')


Verdicts: Runtime Error

Accepted
Problem: You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Submission attempts (in order):
if not input().replace('eraser', '').replace('erase', '').replace('dream', '').replace('dreamer', ''):
  print('Yes')
else:
  print('No')

if not input().replace('eraser', '').replace('erase', '').replace('dreamer', '').replace('dream', ''):
  print('YES')
else:
  print('NO')

Verdicts: Wrong Answer

Accepted
Problem: You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Submission attempts (in order):
s=input(str())
lst=["eraser","erase","dreamer","dream"]
for t in lst:
    s=s.replace(t,"")
if s=="":
    print('NO')
else:
    print('YES')
    

s=input()
s=s.replace('eraser','')
s=s.replace('erase','')
s=s.replace('dreamer','')
s=s.replace('dream','')
if s=='':
    print("YES")
else :
    print("NO")

Verdicts: Wrong Answer

Accepted
Problem: You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Submission attempts (in order):
# coding: utf-8
# Your code here!
import sys
read = sys.stdin.read
readline = sys.stdin.readline

#n,*a = map(int,readline().split())


s = [*input()]
a = [*"dream"]
b = [*"dreamer"]
c = [*"erase"]
d = [*"eraser"]


while True:
    if not s:
        print("Yes")
        break
    elif s[-5:] == a:
        for _ in range(5): s.pop()
    elif s[-5:] == c:
        for _ in range(5): s.pop()
    elif s[-6:] == b:
        for _ in range(6): s.pop()
    elif s[-6:] == d:
        for _ in range(6): s.pop()
    else:
        print("No")
        break







# coding: utf-8
# Your code here!
import sys
read = sys.stdin.read
readline = sys.stdin.readline

#n,*a = map(int,readline().split())


s = [*input()]
a = [*"dream"]
b = [*"dreamer"]
c = [*"erase"]
d = [*"eraser"]

while True:
    if not s:
        print("YES")
        break
    elif s[-5:] == a:
        for _ in range(5): s.pop()
    elif s[-5:] == c:
        for _ in range(5): s.pop()
    elif s[-7:] == b:
        for _ in range(7): s.pop()
    elif s[-6:] == d:
        for _ in range(6): s.pop()
    else:
        print("NO")
        break






Verdicts: Wrong Answer

Accepted
Problem: You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Submission attempts (in order):
s=input()
d=['dream','dreamer','erase','eraser']
while s:
    for m in d:
        if s.endswith(m):
            s=s.rstrip(m)
            break
    else:
        print('NO')
        exit()
print('YES')


s=input()
d=['dream','dreamer','erase','eraser']
while s:
    for m in d:
        if s.endswith(m):
            s=s.strip(m)
            break
    else:
        print('NO')
        exit()
print('YES')


s=input()
d=['dream','dreamer','erase','eraser']
while s:
    for m in d:
        if s.endswith(m):
            s=s[:-len(m)]
            break
    else:
        print('NO')
        exit()
print('YES')


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Submission attempts (in order):
s = input()
copys = s
s += 'r'
i = 0
t = ''
while i <= len(s)-5:
  if s[i:i+5] == 'dream':
    if s[i+5] == 'r':
      i += 6
      t += 'dreamer'
    else:
      i += 5
      t += 'dream'
  elif s[i:i+5] == 'erase':
    if s[i+5] == 'r':
      i += 6
      t += 'eraser'
    else:
      i += 5
      t += 'erase'
  else:
    break

if t == copys:
  print('YES')
else:
  print('NO')

s = input()
t = s[::-1]
i = 0
k = len(s)
while i <= k-5:
  if k-i >= 7:
    if t[i] != 'r':
      if t[i:i+5] == 'maerd':
        i += 5
      elif t[i:i+5] == 'esare':
        i += 5
      else:
        i = k+1
    else:
      if t[i:i+6] == 'resare':
        i += 6
      elif t[i:i+7] == 'remaerd':
        i += 7
      else:
        i = k+1
  elif k-i == 6:
    if t[i:i+6] == 'resare':
      i = k
    else:
      i = k+1
  else:
    if t[i:i+5] == 'esare':
      i = k
    elif t[i:i+5] == 'maerd':
      i = k
    else:
      i = k+1
if i == k:
  print('YES')
else:
  print('NO')

Verdicts: Wrong Answer

Accepted
Problem: You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Submission attempts (in order):
S = input()
for i in ['eraser', 'erase', 'dreamer', 'dream']:
    S=S.replace(i, 'R')
print(['NO', 'YES'][len(s) == 1 and 'R' in s])

S = input()
for i in ['eraser', 'erase', 'dreamer', 'dream']:
    S=S.replace(i, 'R')
s = set(S)
print(['NO', 'YES'][len(s) == 1 and 'R' in s])

Verdicts: Runtime Error

Accepted
Problem: You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Submission attempts (in order):
S = input()
N = len(S)
i = 0
while i < N:
    sig = 0
    S5 = S[i:i+5]
    if S5 == 'dream':
        sig = 1
        if S[i+5:i+7] == 'er' and S[i+7] != 'a':
            i += 2
        i += 5
    elif S5 == 'erase':
        sig = 1
        if S[i+5:i+6] == 'r':
            i += 1
        i += 5
    if sig == 0:
        sig = 2
        Answer = 'No'
        break
if sig != 2:
    Answer = 'Yes'
print(Answer)

S = input()
N = len(S)
i = 0
while i < N:
    sig = 0
    S5 = S[i:i+5]
    if S5 == 'dream':
        sig = 1
        if S[i+5:i+7] == 'er' and S[i+7] != 'a':
            i += 2
        i += 5
    elif S5 == 'erase':
        sig = 1
        if S[i+5:i+6] == 'r':
            i += 1
        i += 5
    if sig == 0:
        sig = 2
        Answer = 'No'
        break
if sig != 2:
    Answer = 'Yes'
print(Answer)

S = input()
N = len(S)
i = 0
while i < N:
    sig = 0
    S5 = S[i:i+5]
    if S5 == 'dream':
        sig = 1
        if S[i+5:i+7] == 'er' and S[i+7:i+8] != 'a':
            i += 2
        i += 5
    elif S5 == 'erase':
        sig = 1
        if S[i+5:i+6] == 'r':
            i += 1
        i += 5
    if sig == 0:
        sig = 2
        Answer = 'NO'
        break
if sig != 2:
    Answer = 'YES'
print(Answer)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: There are N boxes arranged in a row. Initially, the i-th box from the left contains a_i candies.  Snuke can perform the following operation any number of times:    * Choose a box containing at least one candy, and eat one of the candies in the chosen box.  His objective is as follows:    * Any two neighboring boxes contain at most x candies in total.  Find the minimum number of operations required to achieve the objective.

Submission attempts (in order):
s=input();print(['Second','First'][(len(s)+(s[0]==s[-1]))%2])

n, x = map(int, input().split(' '))
a = list(map(int, input().split(' ')))
ans = 0
if a[0] > x:
    ans += a[0] - x
    a[0] = x
for i in range(1,len(a)):
    if a[i-1] + a[i] > x:
        ans += a[i-1] + a[i] - x
        a[i] = x - a[i-1]
print(ans)

Verdicts: Wrong Answer

Accepted