TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
def main2():
    strbuf = input("");
    strbufs = strbuf.split();
    buf = [];
    for i in range(2):
        buf.append(int(strbufs[i]));
    sa = buf[1] - buf[0];
    takasa = sa * (sa + 1) / 2;
    result = takasa - buf[1];
    print(result);


if __name__ == '__main__':
    main2()

def main2():
    strbuf = input("");
    strbufs = strbuf.split();
    buf = [];
    for i in range(2):
        buf.append(int(strbufs[i]));
    sa = strbufs[1] - strbufs[0];
    takasa = sa * (sa + 1) / 2;
    result = takasa - strbufs[1];
    print(result);


if __name__ == '__main__':
    main2()

def main2():
    strbuf = input("");
    strbufs = strbuf.split();
    buf = [];
    for i in range(2):
        buf.append(int(strbufs[i]));
    sa = buf[1] - buf[0];
    takasa = sa * (sa + 1) / 2;
    result = takasa - buf[1];
    print(int(result));


if __name__ == '__main__':
    main2()

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a, b = map(int, input().split())

def calc(n):
    count = 0
    for i in range(1, n+1):
        count += i
    reversed(count)

print(calc(b - a) - b)

import sys
sys.setrecursionlimit(100000)
a, b = map(int, input().split())

def calc(n):
    if n == 1:
        return 1
    else:
        return calc(n-1) + n

for i in range(1, 999+1):
    print(i, calc(i))

print(calc(b - a) - b)

a, b = map(int, input().split())

def calc(n):
    count = 0
    for i in range(1, n+1):
        count += i
    return count

print(calc(b - a) - b)

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a,b=map(int,input().split())
n=b-a
print(n(n+1)//2-b)

a,b=map(int,input().split())
n=b-a
print(n*(n+1)//2-b)

Verdicts: Runtime Error

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a, b = map(int, input().split())

print((b-a)*(b-a + 1)/2 - b)


a, b = map(int, input().split())

print(int((b-a)*(b-a + 1)/2 - b))


Verdicts: Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a, b = map(int, input().split())
b_index = b-a
a_index = b_index - 1
get_height = lambda n: n*(n+1)/2

a_height = get_height(a_index)
b_height = get_height(b_index)
snow_height = b_height - b
print(snow_height)

a, b = map(int, input().split())
b_index = b-a
a_index = b_index - 1
get_height = lambda n: n*(n+1)/2

a_height = get_height(a_index)
b_height = get_height(b_index)
snow_height = b_height - b
print(int(snow_height))

Verdicts: Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a,b = map(int,input().split())
sum=0
cnt=0
while(cnt<b-a):
    cnt+=1
    l+=cnt
print(l-b)

a=int(input())
b=int(input())
print((b-a-1)*(b-a)//2-a)

a=int(input())
b=int(input())
print((b-a-1)*(b-a)//2-a)

a,b=map(int,input().split())
print((b-a-1)*(b-a)/2-a)

a,b = map(int,input().split())
sum=0
cnt=0
while(cnt<b-a):
    cnt+=1
    sum+=cnt
print(sum-b)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
N = input()
N = N.split(" ")
N = [int(i) for i in N]

sub = N[1] - N[0]
high = 0 
for i in range(sub):
    high += i

print(high)

snow = high - N[0]
print(snow)

N = input()
N = N.split(" ")
N = [int(i) for i in N]

sub = N[1] - N[0]
high = 0 
for i in range(sub):
    high += i
snow = high - N[0]
print(snow)

Verdicts: Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
#B - Stone Monument
a,b=map(int,input().split())
d=b-a
b0=d*(d+1)/2
snow=b0-b
int(snow)

#B - Stone Monument
a,b=map(int,input().split())
d=b-a
b0=d*(d+1)/2
snow=b0-b
print(snow)

#B - Stone Monument
a,b=map(int,input().split())
d=b-a
b0=d*(d+1)/2
snow=b0-b
snow

#B - Stone Monument
a,b=map(int,input().split())
d=b-a
b0=d*(d+1)/2
snow=b0-b
print(int(snow))


Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a, b = map(int, input())

n = b - a
original_b = n * (n + 1) // 2

print(original_b - b)

a, b = map(int, input().split())
 
n = b - a
original_b = n * (n + 1) // 2
 
print(original_b - b)

Verdicts: Runtime Error

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
n=eval('-'+input().replace(' ','+'))
s=0
for i in range(n+1):
  s+=i
print(s)

a,b=(int(i) for i in input().split(' '))
n=b-a
s=0
for i in range(n):
  s+=i
print(s-a)

Verdicts: Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a,b=map(int,input())
s=0
for i in range(b-a-1):
  s+=1+i
print(s-a)

a,b=map(int,input().split())
s=0
for i in range(b-a-1):
  s+=1+i
print(s-a)

Verdicts: Runtime Error

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a,b=map(int,input().split())
ans=-a
for i in range(1,b-a+1):
  ans+=i
print(ans)

a,b=map(int,input().split())
ans=-b
for i in range(1,b-a+1):
  ans+=i
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a, b = map(int, input().split())
t = b-a
b_true=0
for i in range(b+1):
    b_true += i
print(b_true-b)


a, b = map(int, input().split())
t = b-a
b_true=0
for i in range(b):
    b_true += i
print(b_true-b)

a, b = map(int, input().split())
t = b-a
b_true=0
for i in range(t+1):
    b_true += i
print(b_true-b)


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a, b = map(int, input().split())
diff = b - a

def generate(n):
    if n == 1:
        return 1
    return generate(n-1) + n

generate(diff) - b

a, b = map(int, input().split())

tower = 0

for i in range(1, b - a + 1):
    tower += i

print(tower - b)

Verdicts: Runtime Error

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a, b = map(int(), input())
x = 0
for i in range(b - a):
    x += x + i
    print(x - a)

a = int(input())
b = int(input())
c = int(b - a)
d = c * (c -1) / 2
e = int(c -1)
f = int(1 + d + e)
print(int(f - b))



a = int(input())
b = int(input())
c = int(b - a)
print(( c * (c - 1) //2 + c - b))


a = int(input())
b = int(input())
c = int(b - a)
d = c * (c -1) 
p = d / 2
e = int(c -1)
f = int(1 + p + e)
print(int(f - b))



a = int(input())
b = int(input())
c = int(b - a)
d = c * (c -1) 
p = d // 2
e = int(c -1)
f = int(1 + p + e)
print(int(f - b))



a, b = map(int(),  input())
c = int(b - a)
d =int( c * (c - 1) // 2 + c  -b)
print(d)

a = int(input())
b = int(input())
c = int(b - a)
d =int( c * (c - 1) // 2 + c  -b)
print(d)

a = int(input())
b = int(input())
c = int(b - a)
d =int( c * (c - 1) /2 + c  -b)
print(d)

a, b = map(int, input().split())
c = int(b - a)
d =int( c * (c - 1) // 2 + c  -b)
print(d)


Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a, b = map(int, input().split())
X = b - a
ans = 0
for i in range(X):
    ans += i
print(ans)

a, b = int(input())
X = b - a
ans = 0
for i in range(X):
    ans += i
print(ans)

a, b = map(int, input().split())
X = b - a
ans = 0
for i in range(X):
    ans += i
print(ans-a)


Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
def main():
    a, b = map(int, input().split())

    h = b - a

    i, ans = 0
    while True:
        i += 1
        ans += i

        if h == i:
            break

    print(ans)


if __name__ == "__main__":
    main()


def main():
    a, b = map(int, input().split())

    h = 0
    for i in range(1, 1000):
        h += i

        if (h - old_h) == (b - a):
            print(h - b)
            exit()

        old_h = h

if __name__ == "__main__":
    main()


def main():
    a, b = map(int, input().split())

    h = 0
    old_h = 0
    for i in range(1, 1000):
        h += i

        if (h - old_h) == (b - a):
            print(h - b)
            exit()

        old_h = h

if __name__ == "__main__":
    main()


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a,b = map(int,input().split( ))
ans = 1
i = 2

while a > ans:
    ans = ans + i
    i += 1
    print(ans)

print(ans-a)

a,b = map(int,input().split( ))
c = b-a
d = 0
i = 1
ans = 0

while c > i:
    d = d+i
    i += 1
ans = d-a
print(ans)


Verdicts: Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
# coding: utf-8
import time
import re
import math
import fractions

def main():
    A,B=map(int,input().split())
    index=B-A-1
    total=0
    for a in range(0,index+1):
        total+a+1
    print(total-B)
start=time.time()
main()

#"YNeos"[True::2]
#A=list(map(int,input().split()))
#A,B,C=map(int,input().split())
#n=int(input())




# coding: utf-8
import time
import re
import math
import fractions

def main():
    A,B=map(int,input().split())
    index=B-A-1
    total=0
    for a in range(0,index+1):
        total+=a+1
    print(total-B)
start=time.time()
main()

#"YNeos"[True::2]
#A=list(map(int,input().split()))
#A,B,C=map(int,input().split())
#n=int(input())




Verdicts: Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a,b = int(input().split())
print((b-a)*(b-a-1)/2 - a)

a,b = int(input().split())
print((b-a)*(b-a-1)//2 - a)

a,b = map(int, input().split())
print((b-a)*(b-a-1)//2 - a)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
A,B=[int(s) for s in input().split()]
x=B-A
y=x*(x-1)//2
print(A+y)

A,B=[int(s) for s in input().split()]
x=B-A
y=x*(x-1)//2
print(y-A)


Verdicts: Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a, b = map(int, input().split())
print(sum(range(b - a)) - b)

a, b = map(int, input().split())
print(sum(range(b - a + 1)) - b)

Verdicts: Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
def Gauss_sum(n):
  return n*(n+1)//2
a,b=map(int,input())
for i in range(999):
  if Gauss_sum(i+1)-a == Gauss_sum(i+2)-b:
    print(Gauss_sum(i+1)-a)
    break

def Gauss_sum(n):
  return n*(n+1)//2
a,b=map(int,input().split())
for i in range(999):
  if Gauss_sum(i+1)-a == Gauss_sum(i+2)-b:
    print(Gauss_sum(i+1)-a)
    break

Verdicts: Runtime Error

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a,b = map(int,input().split())
h = ((b-a-1)*(b-a)//2)-a

a,b = map(int,input().split())
h = ((b-a-1)*(b-a)//2)-a
print(h)

Verdicts: Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a,b = map(int, input().split())
print((b-a)*(b-a-1)//2 - b)

n = int(input())
if n < 1000:
  print('ABC')
else:
  print('ABD')

a,b = map(int, input().split())
print((b-a)*(b-a-1)//2 - a)

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a,b = [int(i) for i in input().split()]
n = b-a-1
print(n*(n+1)/2-a)

a,b = [int(i) for i in input().split()]
n = b-a-1
print(int(n*(n+1)/2-a))

Verdicts: Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a, b = map(int,input().split())


b1 = 0
c = b - a

for i in range(b - a):
  b1 += i
print(b1 - b)

a, b = map(int,input().split())

c = b - a
b1 = 0
for i in range(1,c + 1):
  b1 += i
  
  
print(b1 - b)

Verdicts: Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a,b = map(int,input().split())
tmp = b - a
count = 0
for i in range(tmp):
  count += i+1
print(count - a)

a,b = map(int,input())
tmp = b - a
count = 0
for i in range(tmp):
  count += i+1
print(count - a)

a,b = map(int,input().split())
tmp = b - a
count = 0
for i in range(tmp):
  count += i
print(count - a)

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
, b = map(int, input().split())

i = 0
s = 0

for i in range(1, b - a):
    s += i
print(s - a)

a, b = map(int, input().split())

i = 0
s = 0

for i in range(1, b - a):
    s += i
print(s - a)


Verdicts: Runtime Error

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a,b = map(int,input().split())
t = b-a
print(t*(t-1)//2-b)

a,b = map(int,input().split())
t = b-a
print(t*(t+1)//2-b)

Verdicts: Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a,b = list(map(int, input().split()))
n = b-a
print(n*(n+1)/2 - b)

a,b = list(map(int, input().split()))
n = b-a
print(int(n*(n+1)/2 - b))

Verdicts: Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
import numpy as np
a, b = input().split(" ")
a = int(a)
b = int(b)

c = b - a
s = sum(list(np.arange(c)))
print(a - s)


import numpy as np
a, b = input().split(" ")
a = int(a)
b = int(b)

c = b - a
s = sum(list(np.arange(c)))
print(s - a)


Verdicts: Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a, b = map(int, input().split())
print((b - a) * (b - a - 1) / 2 - a)


a, b = map(int, input().split())
ans = (b - a) * (b - a - 1) / 2 - a
print(int(ans))


Verdicts: Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
from itertools import accumulate
t = [n for n in accumulate(range(10000))]

a, b = map(int, input().split())
print(t[b - a - 1] - b)


from itertools import accumulate
t = [n for n in accumulate(range(10000))]
 
a, b = map(int, input().split())
print(t[b - a] - b)


Verdicts: Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a,b = map(int,input().split())
n = b - a
s = 1/2 * n * (1 + n)
print(s - b)

a,b = map(int,input().split())
n = b - a
s = 1/2 * n * (1 + n)
x = s - b
print(int(x))

Verdicts: Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a,b = map(int,input().split())
print(1/2*(a**2-a-2*a*b-b+b**2))


a,b = map(int,input().split())
print(int(1/2*(a**2-a-2*a*b-b+b**2)))


Verdicts: Wrong Answer

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
a,b=map(int,input().split())
y=0
high=0
for i in range(1,1000):
    y+=i
    x.append(y)
for xz in x:
    if xz < b:
        high=xz
print(high-a)

a,b=map(int,input().split())
y=0
high=0
for i in range(1,1000):
    y+=i
    x.append(y)
for xz in x:
    if xz <= b:
        high=xz
        d=high-a
print(d)

def readQuestion(a,b):
    a,b=map(int,input().split())


def solve(x):
    a,b=map(int,input().split())
    x=[]
    y=0
    high=0
    z=0
    u=0
    for i in range(1,1000):
        y+=i
        x.append(y)
    high = b-a
    z=high-1
    u=x[z]-b
    return u


def main():
    x = readQuestion(a,b)
    answer = solve(x)
    print(answer)


if __name__ == '__main__':
    main()


def readQuestion(a,b):
    a,b=map(int,input().split())


def solve(x):
    a,b=map(int,input().split())
    x=[]
    y=0
    high=0
    z=0
    u=0
    for i in range(1,1000):
        y+=i
        x.append(y)
    high = b-a
    z=high-1
    u=x[z]-b
    print(u)


def main():
    x = readQuestion(a,b)
    answer = solve(x)
    print(answer)


if __name__ == '__main__':
    main()

import sys
def readQuestion():
    line = sys.stdin.readline()
    sline = line.rstrip()
    [rline,r1line]=sline.split(" ")
    a=int(rline)
    b=int(r1line)
    return a,b 

def solve(a,b):
    x=[]
    y=0
    high=0
    z=0
    u=0
    for i in range(1,1000):
        y+=i
        x.append(y)
    high = b-a
    z=high-1
    u=x[z]-b
    return u

def main():
    x,y = readQuestion()
    answer = solve(x, y)
    print(answer)


if __name__ == '__main__':
    main()

Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: In some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.  It had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.  Assuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.  Assume also that the depth of the snow cover is always at least 1 meter.

Submission attempts (in order):
n=input().split(" ")
a=int(n[0])
b=int(n[1])
c=b-a
print(((c*(c+1))/2)-b)

n=input().split(" ")
a=int(n[0])
b=int(n[1])
c=b-a
print (int(((c*(c+1))/2)-b))

Verdicts: Wrong Answer

Accepted
Problem: To make it difficult to withdraw money, a certain bank allows its customers to withdraw only one of the following amounts in one operation:    * 1 yen (the currency of Japan)    * 6 yen, 6^2(=36) yen, 6^3(=216) yen, ...    * 9 yen, 9^2(=81) yen, 9^3(=729) yen, ...  At least how many operations are required to withdraw exactly N yen in total?  It is not allowed to re-deposit the money you withdrew.

Submission attempts (in order):
import math

def A():
    x, a, b = [int(x) for x in input().split()]
    if abs(x-a) < abs(x-b):
        print('A')
    else:
        print('B')
def B():
    S = input()
    alphabet = [False for x in range(26)]
    for char in S:
        i = ord(char) - ord('a')
        alphabet[i] = True
    printed = False
    for i in range(len(alphabet)):
        if alphabet[i] == False:
            print(chr(ord('a')+i))
            printed = True
            break
    if printed == False:
        print("None")
def C():
    n = int(input())
    kazu = sorted([1] + [pow(6, x+1) for x in range(6)]+ [pow(9, x+1) for x in range(5)])
    stack = [(n, 0)]
    m = 9999999999
    while len(stack) > 0:
        node = stack.pop()
        for x in kazu:
            if x <= node[0]:
                if node[0] % x == 0:
                    m = min(m, node[1] + node[0] // x)
                else:
                    stack.append((node[0] % x, node[1] + node[0] // x))
        print(stack)
        print(m)
    print(m)
C()


import math

def A():
    x, a, b = [int(x) for x in input().split()]
    if abs(x-a) < abs(x-b):
        print('A')
    else:
        print('B')
def B():
    S = input()
    alphabet = [False for x in range(26)]
    for char in S:
        i = ord(char) - ord('a')
        alphabet[i] = True
    printed = False
    for i in range(len(alphabet)):
        if alphabet[i] == False:
            print(chr(ord('a')+i))
            printed = True
            break
    if printed == False:
        print("None")
def C():
    num = sorted([1] + [pow(6, x+1) for x in range(6)] + [pow(9, x+1) for x in range(5)])
    n = int(input())
    stack = [(n, 0)]
    memo = {}
    _min = 999999

    cost = {}

    while len(stack) > 0:
        node = stack.pop()
        for k in num:
            if node[0] >= k:
                ans = (node[0] - k, node[1] + 1)
                if ans[0] == 0:
                    _min = min(_min, ans[1])
                else:
                    if str(ans[0]) in memo and memo[str(ans[0])] <= ans[1]:
                        pass
                    else:
                        stack.append(ans)
                        memo[str(ans[0])] = ans[1]
    print(_min)

def E():
    n, m = [int(x) for x in input().split()]
    P = [[] for i in range(n)]
    for j in range(m):
        p, y = [int(x) for x in input().split()]
        P[p-1].append([y, ('000000'+str(p))[-6:], j])

    for i in range(n):
        P[i] = sorted(P[i], key=lambda x:x[0])
        for j in range(len(P[i])):
            P[i][j][1] += (('000000'+str(j+1))[-6:])
    P = [e for inner_list in P for e in inner_list]
    P = sorted(P, key=lambda x:x[2])
    for p in P:
        print(p[1])
C()


Verdicts: Wrong Answer

Accepted
Problem: To make it difficult to withdraw money, a certain bank allows its customers to withdraw only one of the following amounts in one operation:    * 1 yen (the currency of Japan)    * 6 yen, 6^2(=36) yen, 6^3(=216) yen, ...    * 9 yen, 9^2(=81) yen, 9^3(=729) yen, ...  At least how many operations are required to withdraw exactly N yen in total?  It is not allowed to re-deposit the money you withdrew.

Submission attempts (in order):
n = int(input())
payable = [1] + [6**(int(x)+1) for x in range(6)] + [9**(int(x)+1) for x in range(5)]
payable.sort()
ans = 0
while n > 0:
    for value in payable:
        if value > n:
            payable.remove(value)
    n -= max(payable)
    ans += 1
print(ans)

n = int(input())
payable = [1] + [6**(int(x)+1) for x in range(7)] + [9**(int(x)+1) for x in range(6)]
payable.sort(reverse=True)
ans = 0
while n > 0:
    for value in payable:
        if value > n:
            payable.remove(value)
        else:
            break
    n -= max(payable)
    ans += 1
print(ans)

n = int(input())
dp = [0 for x in range(n+1)]
key = 1
while key <= n:
  key *= 6
while key > 1:
  for j in range(n+1):
    if j == 0 or dp[j]:
      if j+key <= n:
        if dp[j+key]:
          dp[j+key] = min([dp[j]+1, dp[j+key]])
        else:
          dp[j+key] = dp[j]+1
  key //= 6

key = 1
while key <= n:
  key *= 9
while key > 1:
  for j in range(n+1):
    if j == 0 or dp[j]:
      if j+key <= n:
        if dp[j+key]:
          dp[j+key] = min([dp[j]+1, dp[j+key]])
        else:
          dp[j+key] = dp[j]+1
  key //= 9

for i in range(1, n+1):
  if dp[i]:
    dp[i] = min([dp[i-1]+1, dp[i]])
  else:
    dp[i] = dp[i-1]+1

print(dp[n])

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: To make it difficult to withdraw money, a certain bank allows its customers to withdraw only one of the following amounts in one operation:    * 1 yen (the currency of Japan)    * 6 yen, 6^2(=36) yen, 6^3(=216) yen, ...    * 9 yen, 9^2(=81) yen, 9^3(=729) yen, ...  At least how many operations are required to withdraw exactly N yen in total?  It is not allowed to re-deposit the money you withdrew.

Submission attempts (in order):
import sys
import itertools
# import numpy as np
import time
import math
import heapq
from collections import defaultdict
sys.setrecursionlimit(10 ** 7)
 
INF = 10 ** 18
MOD = 10 ** 9 + 7
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines

# map(int, input().split())
N = int(input())

coins = [(9 ** i) for i in range(1, 7)] + [(6 ** i) for i in range(1, 8)] + [1]
print(coins)
dp = [INF] * (N + 1)
dp[0] = 0
for i in range(len(coins)):
    for j in range(N + 1):
        if j + coins[i] > N:
            continue
        dp[j + coins[i]] = min(dp[j + coins[i]], dp[j] + 1)
print(dp[N])


import sys
import itertools
# import numpy as np
import time
import math
import heapq
from collections import defaultdict
sys.setrecursionlimit(10 ** 7)
 
INF = 10 ** 18
MOD = 10 ** 9 + 7
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines

# map(int, input().split())
N = int(input())

coins = [(9 ** i) for i in range(1, 7)] + [(6 ** i) for i in range(1, 8)] + [1]
dp = [INF] * (N + 1)
dp[0] = 0
for i in range(len(coins)):
    for j in range(N + 1):
        if j + coins[i] > N:
            continue
        dp[j + coins[i]] = min(dp[j + coins[i]], dp[j] + 1)
print(dp[N])


Verdicts: Wrong Answer

Accepted
Problem: To make it difficult to withdraw money, a certain bank allows its customers to withdraw only one of the following amounts in one operation:    * 1 yen (the currency of Japan)    * 6 yen, 6^2(=36) yen, 6^3(=216) yen, ...    * 9 yen, 9^2(=81) yen, 9^3(=729) yen, ...  At least how many operations are required to withdraw exactly N yen in total?  It is not allowed to re-deposit the money you withdrew.

Submission attempts (in order):
n = int(input())

min_cnt = float('inf')
for i in range(n//6+1):
  cnt = 0
  t = i
  while t>6:
	cnt += t%6
  	t //= 6
  cnt += t
  
  for j in range((n-6*i)//9+1):
    t = j
    while t>9:
      cnt += t%9
      t //= 9
    cnt += t
    cnt += (n-6*i-9*j)
    if cnt < min_cnt:
      min_cnt = cnt
print(min_cnt)


n = int(input())

min_cnt = float('inf')
for i in range(0, n+1, 9):
    cnt = 0
    t = i
    while t >= 9:
        cnt += t % 9
        t //= 9
    cnt += t

    t = (n-i)
    while t >= 1:
        cnt += t % 6
        t //= 6
    cnt += t

    if cnt < min_cnt:
        min_cnt = cnt
print(min_cnt)


Verdicts: Runtime Error

Accepted
Problem: To make it difficult to withdraw money, a certain bank allows its customers to withdraw only one of the following amounts in one operation:    * 1 yen (the currency of Japan)    * 6 yen, 6^2(=36) yen, 6^3(=216) yen, ...    * 9 yen, 9^2(=81) yen, 9^3(=729) yen, ...  At least how many operations are required to withdraw exactly N yen in total?  It is not allowed to re-deposit the money you withdrew.

Submission attempts (in order):
import math, sys
from bisect import bisect_left, bisect_right
from collections import Counter, defaultdict, deque
from copy import deepcopy
from functools import lru_cache
from heapq import heapify, heappop, heappush
from itertools import accumulate, combinations, permutations
input = sys.stdin.readline
mod = 10**9 + 7
ns = lambda: input().strip()
ni = lambda: int(input().strip())
nm = lambda: map(int, input().split())
nl = lambda: list(map(int, input().split()))

n = ni()

res = n
for i in range(n+1):
    cash = 0
    t = i
    while t > 0: 
        cash += t % 6
        t //= 6
    t = n - i
    while t > 0: 
        cc += t % 9
        t //= 9
    if res > cash: 
        res = cash

print(res)

import math, sys
from bisect import bisect_left, bisect_right
from collections import Counter, defaultdict, deque
from copy import deepcopy
from functools import lru_cache
from heapq import heapify, heappop, heappush
from itertools import accumulate, combinations, permutations
input = sys.stdin.readline
mod = 10**9 + 7
ns = lambda: input().strip()
ni = lambda: int(input().strip())
nm = lambda: map(int, input().split())
nl = lambda: list(map(int, input().split()))

n = ni()

res = n
for i in range(n+1):
    cash = 0
    t = i
    while t > 0: 
        cash += t % 6
        t //= 6
    t = n - i
    while t > 0: 
        cash += t % 9
        t //= 9
    if res > cash: 
        res = cash

print(res)

Verdicts: Runtime Error

Accepted