TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = list(map(int, input().split()))
Ls, Rs = [], []
for i in range(M):
    n, m = list(map(int, input().split()))
    Ls.append(n)
    Rs.append(m)


# rr  =Rs[0]


#     rr = min(rr, Rs[i])
#

print(min(0, min(Rs) - max(Ls) + 1))



N, M = list(map(int, input().split()))
Ls, Rs = [], []
for i in range(M):
    n, m = list(map(int, input().split()))
    Ls.append(n)
    Rs.append(m)


# rr  =Rs[0]


#     rr = min(rr, Rs[i])
#

print(max(0, min(Rs) - max(Ls) + 1))



Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
gate = [input().split() for i in range(M)]

MIN = 0
MAX = float('inf')

for i in range(M):
    MIN = max(MIN, int(gate[i][0]))
    MAX = min(MAX, int(gate[i][1]))
    print(MIN, MAX)

print(max(MAX - MIN + 1, 0))

N, M = map(int, input().split())
gate = [input().split() for i in range(M)]

MIN = 0
MAX = float('inf')

for i in range(M):
    MIN = max(MIN, int(gate[i][0]))
    MAX = min(MAX, int(gate[i][1]))

print(max(MAX - MIN + 1, 0))

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M=map(int, input().split())

L=[]
R=[]

for i in range(M):
    a,b=map(int, input().split())
    L.append(a)
    R.append(b)


ans=max(R)-max(L)+1
if ans<0:
  print(0)
else:
  prnit(ans)

N,M=map(int, input().split())

L=[]
R=[]

for i in range(M):
    a,b=map(int, input().split())
    L.append(a)
    R.append(b)

print(max(R)-max(L)+1)

N,M=map(int, input().split())

L=[]
R=[]

for i in range(M):
    a,b=map(int, input().split())
    L.append(a)
    R.append(b)

ans=min(R)-max(L)+1
print("0" if ans<0 else ans)


Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
gates = [tuple(map(int, input().split())) for _ in range(M)]

lmax = max(gates, key=lambda x: x[0])[0]
rmin = min(gates, key=lambda x: x[1])[1]

print(max(rmin-lmax+1), 0)

N, M = map(int, input().split())
gates = [tuple(map(int, input().split())) for _ in range(M)]

lmax = max(gates, key=lambda x: x[0])[0]
rmin = min(gates, key=lambda x: x[1])[1]

print(max(rmin-lmax+1, 0))

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = list(map(int,input().split()))

Nmin = 1
Nmax = N

for i in range(M):
    L, R = list(map(int,input().split()))
    Nmin = max(L,Nmin)
    Nmax = min(R,Nmax)

print(max(Nmax-Nmin+1),0)

N, M = list(map(int,input().split()))

Nmin = 1
Nmax = N

for i in range(M):
    L, R = list(map(int,input().split()))
    Nmin = max(L,Nmin)
    Nmax = min(R,Nmax)

print(max(Nmax-Nmin+1,0))

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M = map(int,input().split())
count = 0
for i in range(M):
    a,b = map(int,input().split())
    if count == 0:
        min = a
        max = b
        count = 1
    else:
        if min < a && a<max:
            min =a
        else:
            break
    if max > b && b >min:
        max = b
    else:
            break
if M == i+1:
    print(max-min+1)
else:
    print(0)

N,M = map(int,input().split())
count = 0
for i in range(M):
    a,b = map(int,input().split())
    if count == 0:
        L = a
        R = b
        count = 1
    else:
        if L < a and a<R:
            L =a
        else:
            break
        if R > b and L < b:
            R = b
        else:
            break
if M == i+1:
    print(max-min+1)
else:
    print(0)

N,M = map(int,input().split())
count = 0
for i in range(M):
    a,b = map(int,input().split())
    if count == 0:
        min = a
        max = b
        count = 1
    else:
        if min < a && a<max:
            min =a
        else:
            break
        if max > b && b >min:
            max = b
        else:
            break
if M == i+1:
    print(max-min+1)
else:
    print(0)


N,M = map(int,input().split())
count = 0
for i in range(M):
    a,b = map(int,input().split())
    if count == 0:
        L = a
        R = b
        count = 1
    else:
        if L < a:
            L =a
            if L>R:
                break
        if R > b:
            R = b
            if R < L:
                break
if M == i+1:
    print(max-min+1)
else:
    print(0)

N,M = map(int,input().split())
count = 0
for i in range(M):
    a,b = map(int,input().split())
    if count == 0:
        min = a
        max = b
        count = 1
    else:
        if min < a && a<max:
            min =a
        if max > b && b >min:
            max = b
if M == i+1:
    print(max-min+1)
else:
    print(0)

N,M = map(int,input().split())
count = 0
for i in range(M):
    a,b = map(int,input().split())
    if count == 0:
        L = a
        R = b
        count = 1
    else:
        if L < a:
            L =a
            if L>R:
                break
        if R > b:
            R = b
            if R < L:
                break
if M == i+1:
    print(R-L+1)
else:
    print(0)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):

N,M=map(int,input().split())

result=0
LR=[]
for i in range(M):
        LR.append(input().split())


numbers=[]
for i in range(N+1):
    numbers.append(i)




Lmax=0
Rmax=0
for j in LR:

    L=int(j[0])
    R=int(j[1])

    if Lmax<L:
        Lmax=L
    if Rmax<R:
        Rmax=R
for i in numbers:
    if i>Lmax:
        if i<Rmax:
            result+=1


print(result)



N,M=map(int,input().split())

result=0
LR=[]
for i in range(M):
        LR.append(input().split())


for i in range(N+1):
    counter=0
    flag=False
    for j in LR:

        L=int(j[0])
        R=int(j[1])
        if i<L or R<i:
            flag=True
            break
        if L<=i and i<=R:
            counter+=1
    if flag:
        break
    if counter==M:
        result+=1
print(result)



N,M=map(int,input().split())


LR=[]
for i in range(M):
        LR.append(input().split())


numbers=[]
for i in range(N+1):
    numbers.append(i)




Lmax=1
Rmax=100000
for j in LR:

    L=int(j[0])
    R=int(j[1])

    if Lmax<L:
        Lmax=L
    if Rmax>R:
        Rmax=R
result=0

for i in numbers:

    if i>=Lmax:

        if i<=Rmax:
            result+=1



print(result)


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M = map(int,input().split())
X = [list(map,int(input().split())) for i in range(M)]

keymax = 10**6
keymin = 0
for i in range(M):
	if X[i][0] > keymin:
		keymin = X[i][0]
	if X[i][1] < keymax:
		keymax = X[i][1]

print(keymax-keymin+1)

N,M = map(int,input().split())
X = [list(map(int,input().split())) for i in range(M)]

keymax = 10**6
keymin = 0
for i in range(M):
	if X[i][0] > keymin:
		keymin = X[i][0]
	if X[i][1] < keymax:
		keymax = X[i][1]

if keymax >= keymin:
	print(keymax-keymin+1)
else:
	print("0")

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
from itertools import accumulate
N, M = map(int, input().split())

left = 1
right = M

for i in range(M):
    a,b = map(int, input().split())
    left = max(left,a)
    right = min(right, b)

print(max(0,right-left+1))




#     l, r = map(int, input().split())


#

#
# ans = 0
# for im in imos:
#     ans += (im == M)
#
# print(ans)


from itertools import accumulate
N, M = map(int, input().split())

# left = 1
# right = N
#

#     a,b = map(int, input().split())
#     left = max(left,a)
#     right = min(right, b)
#
# print(max(0,right-left+1))

imos = [0] * (N + 2)
for i in range(M):
    l, r = map(int, input().split())
    imos[l] += 1
    imos[r + 1] -= 1

imos = list(accumulate(imos))

ans = 0
for im in imos:
    ans += (im == M)

print(ans)


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m= map(int,input().split())
lr = [0]*m
import numpy as np
for i in range(m):
    lr[i]=list(map(int, input().split()))

#1~10**5
# print(10**5)
allcount = np.zeros(10**5,dtype=np.int)
# print(allcount)
for i in range(m):
    st = lr[i][0]-1
    g = lr[i][1]
    allcount=np.hstack((allcount[:st],allcount[st:g]+1,allcount[g:]))

# print(allcount)

allcount = list(allcount)
print(allcount.count(m))


    



n,m= map(int,input().split())
lr = [0]*m
for i in range(m):
    lr[i]=list(map(int, input().split()))


left = lr[0][0]
right = lr[0][1]
for i in range(1,m):
    if left < lr[i][0]:
        left = lr[i][0]
    if right > lr[i][1]:
        right = lr[i][1]
    
    if left > right:
        break




if left > right:
    print(0)

if left <= right:
    print(right-left+1)
    



Verdicts: Time Limit Exceeded

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())

l, r = [], []
for i in range(m):
    tmpa, tmpb = map(int, input().split())
    l.append(tmpa)
    r.append(tmpb)

print(min(r) - max(l) + 1 if min(r) < max(l) else 0)


n, m = map(int, input().split())

l, r = [], []
for i in range(m):
    tmpa, tmpb = map(int, input().split())
    l.append(tmpa)
    r.append(tmpb)

print(min(r) - max(l) + 1 if min(r) >= max(l) else 0)


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
l_max,r_min = 0,n
for i in range(m):
    l,r = map(int,input().split())
    l_max = max(l,ll)
    r_min = min(r,rr)
print(max(r_min - l_max +1 , 0))


n,m = map(int,input().split())
ans = 0
for i in range(m):
  l,r = map(int,input().split())
  d = range(l,r+1)
  for j in range(n):
    if j+1 in d:
      ans += 1
print(ans)

n,m = map(int,input().split())
l_max,r_min = 0,n
for i in range(m):
    l,r = map(int,input().split())
    l_max = max(l,l_max)
    r_min = min(r,r_min)
print(max(r_min - l_max +1 , 0))


Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
a, b= map(int, input().split())
A=[]
A = [list(input().split())   for i in range(a)]
B=[]
for i in A:
  s=int(i[0])
  v=int(i[1])+1
  for j in range(s,v):
    B.append(j)
C = [x for x in set(B) if B.count(x) > 1]
print(len(C))
 

n,m = [int(i) for i in input().split()]
rang = []
lmax = 0
rmin = 10**10
for i in range(m):
    l,r = [int(i) for i in input().split()]
    lmax = max(l,lmax)
    rmin = min(r,rmin)

print(max(rmin - lmax + 1,0))


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M = list(map(int,input().split()))
ans = [0 for i in range(N)]
anss = 0

for i in range(M):
    L,R = list(map(int,input().split()))
    if L == R:
      ans[L-1]+=1
    else:
      for j in range(L-1,R,1):
        ans[j]+=1

maxn = 0
for i in range(M):
    if ans[i] > maxn:
        maxn = ans[i]
        
for i in range(M):
    if ans[i] == maxn:
        anss += 1
print(anss)

N,M = list(map(int,input().split()))
L = 0
R = N

for i in range(M):
    tL,tR = list(map(int,input().split()))
    if tL > L:
        L = tL
    if tR < R:
        R = tR
    print(L,R)
print(R-L+1)

N,M = list(map(int,input().split()))
ans = [0 for i in range(N)]
anss = 0

for i in range(M):
    L,R = list(map(int,input().split()))
    if L == R:
        ans[L-1]+=1
    else:
        for j in range(L-1,R,1):
            ans[j]+=1

maxn = 0
for i in range(M):
    if ans[i] > maxn:
        maxn = ans[i]
        
for i in range(M):
    if ans[i] == maxn:
        anss += 1
print(anss)

N,M = list(map(int,input().split()))
L = 1
R = N+1
ans = N*2

for i in range(M):
    tL,tR = list(map(int,input().split()))
    if tR < L or R < tL:
        ans = 0
        break
    if tL > L:
        L = tL
    if tR < R:
        R = tR

print(min(ans,R-L+1))

Verdicts: Runtime Error

Wrong Answer

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import numpy as np

n,m = map(int, input().split())
LR = [list(map(int, input().split())) for _ in range(m)]
n = np.array([0]*n)
for l,r in LR:
  n[l-1:r] += 1.
print(sum(n == m))

n,m = map(int, input().split())
LR = [list(map(int, input().split())) for _ in range(m)]
L = max([i[0] for i in LR])
R = min([i[1] for i in LR])
print(max(R-L+1,0))

Verdicts: Time Limit Exceeded

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = list(map(int, input().split()))
L, R = [], []
for i in range(M):
    L[i], R[i] = list(map(int, input().split()))

ans = min(R) - max(L) + 1
if ans < 0:
    ans = 0
print(ans)

N, M = list(map(int, input().split()))
L, R = [None] * M, [None] * M
for i in range(M):
    L[i], R[i] = list(map(int, input().split()))

ans = min(R) - max(L) + 1
if ans < 0:
    ans = 0
print(ans)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M = map(int,input().split())
l=[]
r=[]
for i in range(M):
  a,b=map(int,input().split())
  l.append(a)
  r.append(b)
  
  
ans=min(b)-max(a)+1
print(ans)

N,M = map(int,input().split())
l=[]
r=[]
for i in range(N):
  a,b=map(int,input().split())
  l.append(a)
  r.append(b)
  
  
ans=min(r)-max(l)+1
print(ans)

N,M = map(int,input().split())
l=[]
r=[]
for i in range(N):
  a,b=map(int,input().split())
  l.append(a)
  r.append(b)
  
  
ans=min(b)-max(a)+1
print(ans)

N,M = map(int,input().split())
a,b=map(int,input().split())
ans=0
l_=[int(n) for n in range(a,b+1)]
 
for i in range(M-1):
  c,d=map(int,input().split())
  if max(c,d)< a or min(c,d) > b:
    pass
  else:
    l__=[n for n in range(c,d+1)]
    l_=list(set(l_)&set(l__))
    ans+=1
    
print(ans)

N,M = map(int,input().split())
a,b=map(int,input().split())
 
l_=[int(n) for n in range(a,b+1)]
 
for i in range(M-1):
  c,d=map(int,input().split())
  if max(c,d)<= a or min(c,d) => b:
    pass
  else:
    l__=[n for n in range(c,d+1)]
    l_=list(set(l_)&set(l__))
  
  
print(len(l_))

n,m=map(int,input().split())
l=[list(map(int,input().split())) for i in range(m)]
L=[]
R=[]
for i in range(m):
  L.append(l[i][0])
  R.append(l[i][1])
print(max(min(R)-max(L)+1,0))

Verdicts: Runtime Error

Runtime Error

Runtime Error

Wrong Answer

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
ID_num, gate_num = tuple([int(i) for i in input().split(" ")])
min_list = []
max_list = []
for i in range(gate_num):
  	min_ID, max_ID = tuple([int(i) for i in input().split(" ")])
    min_list.append(min_ID)
    max_list.append(max_ID)
print(min(max_list) - max(min_list))

ID_num, gate_num = tuple([int(i) for i in input().split(" ")])
min_list = []
max_list = []
for i in range(gate_num):
  	min_ID, max_ID = tuple([int(i) for i in input().split(" ")])
    min_list.append(min_ID)
    max_list.append(max_ID)
print(min(max_list) - max(min_list) + 1)

ID_num, gate_num = tuple([int(i) for i in input().split(" ")])
min_list = []
max_list = []
for i in range(gate_num):
    min_ID, max_ID = tuple([int(i) for i in input().split(" ")])
    min_list.append(min_ID)
    max_list.append(max_ID)
M = min(max_list)
m = max(min_list)
if M >= m:
    print(min(max_list) - max(min_list) + 1)
else:
    print(0)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M=map(int, input().split())
pass_id = range(1,N+1)

for i in range(M):
    L,R=map(int, input().split())
    for id in pass_id:
        if not id in range(L,R+1):
            pass_id.pop(pass_id.index(id))
print(len(pass_id))

N, M = map(int, input().split())
l, r = 1, N
for i in range(M):
    L, R = map(int, input().split())
    l = max(l, L)
    r = min(r, R)

print(max(0, r - l + 1))


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int,input().split())
 
l_p = 1
r_p = n
 
for j in range(m+1):
  l, r = map(int,input().split())
  if l > l_p:
    l_p = l
  if r < r_p:
    r_p = r

a = r_p - l_p + 1

print(a)

n, m = map(int,input().split())
 
l_p = 1
r_p = n
 
for j in range(m):
  l, r = map(int,input().split())
  if l > l_p:
    l_p = l
  if r < r_p:
    r_p = r

a = r_p - l_p + 1

if a > 0:
  print(a)
else:
  print(0)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())

hashset = None

for _ in range(M):
	for L, R in map(int, input().split()):
      if hashset is None:
        hashset = set(range(L, R+1))
      else:
        hashset = hashset & set(range(L, R+1))

print(len(hashset))

N, M = map(int, input().split())
 
left, right = 1, N
 
for _ in range(M):
  L, R = map(int, input().split())
  
  left = max(L, left)
  right = min(R, right)

ans = right - left + 1 if left <= right else 0 
print(ans)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
mi, ma = 1, n
for _ in range(m):
    l, r = map(int, input().split())
    mi = max(l, mi)
    ma = min(r, ma)
print(ma - mi)

n, m = map(int, input().split())
mi, ma = 1, n
for _ in range(m):
    l, r = map(int, input().split())
    mi = max(l, mi)
    ma = min(r, ma)
print(max(0, ma - mi + 1))


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):

n,m = map(int, input().split())
maxlist = []
minlist = []

for i in range(m):
	
	l , r = list(map(int, input().split()))
	minlist.append(l)
	if r > 0:
		maxlist.append(r)

minid = max(minlist)
maxid = min(maxlist)
okgate = maxid - minid + 1

if okegate >= 0:
	print(okgate)
else:
	print(0)


n,m = map(int, input().split())
maxlist = []
minlist = []

for i in range(m):
	
	l , r = list(map(int, input().split()))
	minlist.append(l)
	if r > 0:
		maxlist.append(r)

minid = max(minlist)
maxid = min(maxlist)
okgate = maxid - minid + 1

if okgate >= 0:
	print(okgate)
else:
	print(0)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
LR = [list(map(int,input().split())) for i in range(M)]

G=[]
for i in range(N):
    G.append(0)

for i in LR:
    G[i[0]-1]=G[i[0]-1]+1
    G[i[1]-1]=G[i[1]-1]+1

G.count(max(G))



LL=[]
RR=[]
N,M=map(int,input().split())
for i in range(M):
    L,R=map(int,input().split())
    LL.append(L)
    RR.append(R)
    
L1=max(LL)
R1=min(RR)
if L1>R1:
    print(0)
else:
    print(R1-L1+1)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import numpy as np
N,M = map(int,input().split())
min_num,max_num = 0,10**6
for i in range(M):
  n_i,n_j = map(int,input().split())
  min_num = n_i if n_i > min_num else min_num
  max_num = n_j if n_j < max_num else max_num

if max_num - min_num > 0:
  print(0)
else:
  print(max_num - min_num +1)

import numpy as np
N,M = map(int,input().split())
min_num,max_num = 0,10**6
for i in range(M):
  n_i,n_j = map(int,input().split())
  min_num = n_i if n_i > min_num else min_num
  max_num = n_j if n_j < max_num else max_num

if max_num - min_num < 0:
  print(0)
else:
  print(max_num - min_num +1)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())

L = []
R = []

for i in range(M):
    inp = input().split()
    L.append(inp[0])
    R.append(inp[1])
    
if max(L) <= min(R):
    print(min(R)-max(L)+1)
else:
    print(0)

N, M = map(int, input().split())

L = []
R = []

for i in range(M):
    inp = input().split()
    L.append(int(inp[0]))
    R.append(int(inp[1]))
    
if max(L) <= min(R):
    print(min(R)-max(L)+1)
else:
    print(0)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m= input().split()
n = int(n)
m = int(m)
g=[input().split() for i in range(m)]
av =[0,1000000]
for i in range(m):
  av[0] = max(int(g[i][0]),av[0])
  av[1] = min(int(g[i][1]),av[1])
print(av[1])
print(av[0])
print(av[1] -av[0]+1)

n,m= input().split()
n = int(n)
m = int(m)
g=[input().split() for i in range(m)]
av =[0,0]
for i in range(m):  
  av[0] = max(int(g[i][0]),av[0])
  av[1] = min(int(g[i][1]),av[1])
print(av[1])
print(av[0])
print(av[1] -av[0]+1)

n,m= input().split()
n = int(n)
m = int(m)
g=[input().split() for i in range(m)]
 
for i in range(m):
  av =[0,0]
  av[0] = max(int(g[i][0]),av[0])
  av[1] = min(int(g[i][1]),av[1])
print(av[1] -av[0]+1)

n,m= input().split()
n = int(n)
m = int(m)
g=[input().split() for i in range(m)]

for i in int(m):
  av =[0,0]
  av[0] = max(int(g[i][0]),av[0])
  av[1] = min(int(g[i][1]),av[1])
print(av[1] -av[0]+1)

n,m= input().split()
n = int(n)
m = int(m)
g=[input().split() for i in range(m)]
av =[-1,1000000]
for i in range(m):
  av[0] = max(int(g[i][0]),av[0])
  av[1] = min(int(g[i][1]),av[1])
print(max(av[1] -av[0]+1,0))

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
    import sys
     
    def main():
        sinputl = sys.stdin.readline
     
        num_card, num_gate = [int(x) for x in sinputl().split()]
        input = [[int(x) for x in sinputl().split()] for _ in range(num_gate)]
     
        under_limit = [x[0] for x in input]
        over_limit = [x[1] for x in input]
     
        print(max(min(over_limit) - max(under_limit) + 1, 0))
     
     
    if __name__ == "__main__":
        main()

import sys
     
def main():
    sinputl = sys.stdin.readline

    num_card, num_gate = [int(x) for x in sinputl().split()]
    input = [[int(x) for x in sinputl().split()] for _ in range(num_gate)]
   
    under_limit = [x[0] for x in input]
    over_limit = [x[1] for x in input]
     
    print(max(min(over_limit) - max(under_limit) + 1, 0))
     
     
if __name__ == "__main__":
    main()

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
l = [0]*m
r = [0]*m
for i in range(m):
    l[i], r[i] = map(int, input().split())

print(max(min(r) - max(l)+1, n))


n, m = map(int, input().split())
l = [0]*m
r = [0]*m
for i in range(m):
    l[i], r[i] = map(int, input().split())

print(max(min(r) - max(l)+1, 0))

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input().split())
L=[list(map(int,input().split()) for _ in range(m)]
  
a=max(L)
b=min(M)
if a<=b:
  print(b-a+1)
else:
  print(0)

n,m=map(int,input().split())
l=[]
m=[]
for i in range(m):
  ll,mm=map(int,input().split())
  l.append(ll)
  m.append(mm)
a=max(l)
b=min(m)
if a<=b:
  print(b-a+1)
else:
  print(0)

n,m=map(int,input().split())
L=[]
M=[]
for i in range(m):
  l,m=map(int,input().split())
  L.append(l)
  M.append(m)
  
a=max(L)
b=min(M)
if a<=b:
  print(b-a+1)
else:
  print(0)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
l = 1
r = N
for i in range(M):
  L, R = map(int, input().split())
  if l < L:
    l = L
  if r < R:
    r = R
if l > r:
  print(0)
else:
  print(r-l+1)

N, M = map(int, input().split())
l = 1
r = N
for i in range(M):
  L, R = map(int, input().split())
  if L < l:
    l = L
  if r < R:
    r = R
if l > r:
  print(0)
else:
  print(r-l+1)

N, M = map(int, input().split())
l = 1
r = N
for i in range(M):
  L, R = map(int, input().split())
  if l < L:
    l = L
  if r < R:
    r = R
if l > r:
  print(0)
else:
  print(r-l+1)

N, M = map(int, input().split())
l = 1
r = N
for i in range(M):
  L, R = map(int, input().split())
  if L > l:
    l = L
  if r > R:
    r = R
if l > r:
  print(0)
else:
  print(r-l+1)

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
l = 1
r = n
for i in range(m):
  li, ri = map(int, input().split())
  l = max(l, li)
  r = min(r, ri)
print(max(l - r + 1), 0)

n, m = map(int, input().split())
l = 1
r = n
for i in range(m):
  li, ri = map(int, input().split())
  l = max(l, li)
  r = min(r, ri)
print(max(r - l + 1, 0))


Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
l = [0]*N

for i in range(M):
        L, R = map(int, input().split())
        for j in range(L, R+1):
                l[j-1] += 1
        print(l)
print(l.count(M))

N, M = map(int, input().split())
l = [0]*(N+1)

for i in range(M):
        L, R = map(int, input().split())
        l[L-1] += 1
        l[R] -= 1
        

k = 0
ans = 0
for i in l:
        k += i
        if k == M:
                ans += 1
print(ans)


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M=map(int,input().split())
ans=0
L,R=0,10**5
for i in range(M):
    l,r=map(int,input().split())
    L=max(L,l); R=min(R,r)
print(L,R)
R=min(R,N)
print(abs((L-1)-R))

N,M=map(int,input().split())
ans=0
L,R=0,(10**5)+1
for i in range(M):
    l,r=map(int,input().split())
    L=max(L,l); R=min(R,r)
    if r<l: break
R=min(R,N)
print(abs((L-1)-R) if 0<=R-L else 0)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
num = [list(map(int, input().split())) for _ in range(m)]
num1 = 1
num2 = n

for j in range(m):
  num1 = max(num[j][0], num1)
  num2 = min(num[j][1], num2)

ans = num2 - num1 + 1

if ans > 0
  print(ans)
else:
  print(0)

n, m = map(int, input().split())
num = [list(map(int, input().split())) for _ in range(m)]
num1 = 1
num2 = n

for j in range(m):
  num1 = max(num[j][0], num1)
  num2 = min(num[j][1], num2)

ans = num2 - num1 + 1

if ans > 0:
  print(ans)
else:
  print(0)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m=map(int,input().split())
l=1
r=n
for i in range(m):
	a,b=map(int,input().split())
	l=max(l,a)
	r=max(r,b)
print(max(r-l+1,0))

n,m=map(int,input().split())
l=1
r=n
for i in range(m):
	a,b=map(int,input().split())
	l=max(l,a)
	r=min(r,b)
print(max(r-l+1,0))

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = [int(i) for i in input().split()]
left = 0
right = M
for _ in range(N):
  L, R = [int(i) for i in input().split()]
  if left < L:
    left = L
  if right > R:
    right = R
print(R-L+1)

N, M = [int(i) for i in input().split()]
left = 0
right = N
for _ in range(M):
  L, R = [int(i) for i in input().split()]
  if left < L:
    left = L
  if right > R:
    right = R
print(R-L+1)

N, M = [int(i) for i in input().split()]
left = 1
right = N
for _ in range(M):
  L, R = [int(i) for i in input().split()]
  if left < L:
    left = L
  if right > R:
    right = R
if left <= right:
  print(right-left+1)
else:
  print(0)


Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())
L = []
R = []
for i in range(M):
    x, y = [int(i) for i in input().split()]
    L.append(x)
    R.append(y)

id = []
for i in range(M):
    id += [L[i:] + R[:i + 1]]
print(id)
com = set(id[0])
for j in range(1, M):
    com = com & set(id[j])
com_max = max(com)
com_min = min(com)
print(com_max - com_min + 1)

N, M = map(int, input().split())
L = [0 for _ in range(M)]
R = [0 for _ in range(M)]
for i in range(M):
    L[i], R[i] = map(int, input().split())

l = max(L)
r = min(R)
print(r - l + 1 if l <= r else 0)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N_M = list(map(int, input().split()))
Lock_min = []
Lock_max = []
for i in range(N_M[1]):
    ADD = list(map(int,input().split()))
    Lock_min.append(ADD[0])
    Lock_max.append(ADD[1])
if min(Lock_max) - max(Lock_min) >= 1:
        print(min(Lock_max) - max(Lock_min))
 else:
        print(0)

N_M = list(map(int, input().split()))
Lock_min = []
Lock_max = []
for i in range(1,N_M[1]+1):
    ADD = list(map(int,input().split()))
    Lock_min.append(ADD[0])
    Lock_max.append(ADD[1])
if min(Lock_max) - max(Lock_min) >= 1:
        print(min(Lock_max) - max(Lock_min))
else:
        print(0)

N,M = map(int,input().split())
L = [0]*M
R = [0]*M
for i in range(M):
  l,r = map(int,input().split())
  L[i] = l
  R[i] = r
if min(R)-max(L) >= 0:
  print(min(R)-max(L)+1)
else:
  print(0)

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import math

def main():
    n, m = [int(x) for x in input().split(" ")]
    gates = []
    mi = n
    ma = 0

    for x in range(m):
        l, r = [int(x) for x in input().split(" ")]
        gates.append((l, r))

    for gate in gates:
        # print(gate)
        if ma <= gate[0]:
            ma = gate[0]

        if mi >= gate[1]:
            mi = gate[1]
    res = 0
    if mi > ma:
        res = 0
    else:
        res = mi - ma + 1

    print(res)

if __name__ == "__main__":
    main()

import math

def main():
    n, m = [int(x) for x in input().split(" ")]
    gates = []
    mi = n
    ma = 0

    for x in range(m):
        l, r = [int(x) for x in input().split(" ")]
        gates.append((l, r))

    for gate in gates:
        # print(gate)
        if ma <= gate[0]:
            ma = gate[0]

        if mi >= gate[1]:
            mi = gate[1]

    print (mi)
    print (ma)
    res = 0
    if mi < ma:
        res = 0
    else:
        res = mi - ma + 1

    print(res)

if __name__ == "__main__":
    main()

import math

def main():
    n, m = [int(x) for x in input().split(" ")]
    gates = []
    mi = n
    ma = 0

    for x in range(m):
        l, r = [int(x) for x in input().split(" ")]
        gates.append((l, r))

    mi = gates[0][1]
    ma = gates[0][0]

    for gate in gates:
        # print(gate)
        if ma <= gate[0]:
            ma = gate[0]

        if mi >= gate[1]:
            mi = gate[1]

    res = 0
    if mi < ma:
        res = 0
    else:
        res = mi - ma + 1

    print(res)

if __name__ == "__main__":
    main()

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M = map(int,input().split())
LR = [list(map(int,input().split())) for i in range(M)]

maxi = 0
mini = 10**6
for lr in LR:
    maxi = max(lr[0],maxi)
    mini = min(lr[1],mini)

if mini-maxi+1 >= n:
    print(n)
else:
    print(mini-maxi+1)

import numpy as np
N,M = map(int,input().split())
LR = [list(map(int,input().split())) for i in range(M)]
LR = np.array(LR)

mini = max(LR[:,0])
maxi = min(LR[:,1])

if maxi-mini < 0:
    print(0)
else:
    print(maxi-mini+1)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = [int(x) for x in input().split()]

LR = []
for _ in range(M):
  LR.append([int(x) for x in input().split()])

print(sum(check(n) for n in range(1, N+1)))
def check(n):
  return 1 if all(l <= n <=r for l, r in range LR) else 0


N, M = [int(x) for x in input().split()]

def check(n, LR):
    return 1 if all(l <= n <=r for l, r in LR) else 0

L = 0
R = N
for _ in range(M):
    l, r = [int(x) for x in input().split()]
    if L < l:
        L = l
    if r < R:
        R = r

if L <= R:
    print(R - L + 1)
else:
    print(0)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
min = 0
max = 0
for i in range(m):
    l,r = map(int,input().split())
    min = min(min,l)
    max = max(max,r)
print(int(n-max+min))

n,m = map(int,input().split())
s = 0
t = n
for i in range(m):
    l,r = map(int,input().split())
    s = max(s,l)
    t = min(t,r)
print(int(t-s))


n,m = map(int,input().split())
s = 0
t = n
for i in range(m):
    l,r = map(int,input().split())
    s = max(s,l)
    t = min(t,r)
print(max(t-s+1,0))


Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):


def main():
    n, m = map(int, input().split())

    gate = []

    for _ in range(m):
        ngate = list(map(int, input().split()))
        gate.append(ngate)
    print(gate)

    result = 0
    for i in range(1, n + 1):
        for j in range(m):
            if gate[j][0] <= i and i <= gate[j][1]:
                if j == len(gate) - 1:
                    result += 1
                continue
            else:
                break

    
    return result


if __name__ == "__main__":
    print(main())

n, m = map(int , input().split())
# L = []
# R = []

l_max = 0
r_min = 10 ** 6
for _ in range(m):
    l, r = map(int, input().split())
    if l_max < l:
        l_max = l
    if r < r_min:
        r_min = r
if l_max <= r_min:
    print(r_min - l_max + 1)
else:
    print(0)

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
idCards, gates = input().split(" ")
idCards = int(idCards)
gates = int(gates)

for count in range(0, gates, 1):
    num1, num2 = input().split(" ")
    minNum.append(int(num1))
    maxNum.append(int(num2))

minId = max(minNum)
maxId = min(maxNum)
if minId > maxId:
    print("0")
else:
    print((maxId - minId) + 1)

idCards, gates = input().split(" ")
idCards = int(idCards)
gates = int(gates)
minNum = []
maxNum = []

for count in range(0, gates, 1):
    num1, num2 = input().split(" ")
    minNum.append(int(num1))
    maxNum.append(int(num2))

minId = max(minNum)
maxId = min(maxNum)
if minId > maxId:
    print("0")
else:
    print((maxId - minId) + 1)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int, input().split())

gate = []

l, r = map(int, input().split())


for i in range(M-1):
    tmpl, tmpr = map(int, input().split())
    if l < tmpl:
        l = tmpl
    if tmpr < r:
        r = tmpr

print(r, l)
if r - l < 0:
    print(0)
else:
    print(r - l + 1)


N, M = map(int, input().split())

gate = []

l, r = map(int, input().split())


for i in range(M-1):
    tmpl, tmpr = map(int, input().split())
    if l < tmpl:
        l = tmpl
    if tmpr < r:
        r = tmpr


if r - l < 0:
    print(0)
else:
    print(r - l + 1)


Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = list(map(int, input("").split(" ")))
permit = [list(map(int, input("").split(" "))) for i in range(M)]
l,r = 1, N
for i,j in permit:
  l = max(l, i)
  r = min(r, j)
print(max(l-r+1,0))

N, M = list(map(int, input("").split(" ")))
permit = [list(map(int, input("").split(" "))) for i in range(M)]
l,r = 1, N
for i,j in permit:
  l = max(l, i)
  r = min(r, j)
print(max(r-l+1,0))

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n,m = map(int,input().split())
min,max = map(int,input().split())
for k in range(m-1):
  a,b = map(int,input().split())
  if min < a:
    min = a
  if max > b:
    max = b
if b < a:
  print(0)
else:
  print(b-a+1)

max,m = map(int,input().split())
min = 1
for k in range(m):
  a,b = map(int,input().split())
  if min < a:
    min = a
  if max > b:
    max = b
if max < min:
  print(0)
else:
  print(max-min+1)

Verdicts: Runtime Error

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
# -*- coding: utf-8 -*-
n,m=map(int,input().split())
L=[]
R=[]
for _ in range(m):
    a,b=map(int,input().split())
    L.append(a)
    R.append(b)
print(min(R)-max(L)+1,0)

# -*- coding: utf-8 -*-
n,m=map(int,input().split())
L=[]
R=[]
for _ in range(m):
    a,b=map(int,input().split())
    L.append(a)
    R.append(b)
print(max(min(R)-max(L)+1,0))

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
n, m = map(int, input().split())
_min = n
_max = 0
for _ in range(m):
  l, r = map(int, input().split())
  _min = min(_min, r)
  _max = max(_max, l)
  print(max(_min - _max + 1, 0))

n, m = map(int, input().split())
_min = 0
_max = n
for _ in range(m):
  l, r = map(int, input().split())
  _min = min(_min, r)
  _max = max(_max, l)
  print(max(_max - _min + 1, 0))

n, m = map(int, input().split())
_min = n
_max = 0
for _ in range(m):
  l, r = map(int, input().split())
  _min = min(_min, r)
  _max = max(_max, l)
  print(max(_max - _min + 1, 0))

def p_c():
    n, m = map(int, input().split())
    _min = n
    _max = 0
    for _ in range(m):
        l, r = map(int, input().split())
        _min = min(_min, r)
        _max = max(_max, l)
    print(max(_min - _max + 1, 0))

p_c()

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
import sys
N,M=map(int,input().split())
_min,_max=map(int,input().split())
for i in range(M-1):
   L,R=map(int,input().split())
   if R<_min or L>_max:
       print(0)
       sys.exit()
   _min,_max=max(_min,L),min(_max,R)
print(_min+1-_max)   

N,M=map(int,input().split())
_min,_max=map(int,input().split())
for i in range(M-1):
   L,R=map(int,input().split())
   _min,_max=max(_min,L),min(_max,R)
print(max(_max+1-_min,0))   

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N,M = map(int,input().split())
L1 = 0
R1 = N

for m in range(M):
  L2,R2 = map(int,input().split())
  L1 = min(L1,L2)
  R1 = max(R1,R2)
  
print(max(0,R1-L1))

N,M = map(int,input().split())
L = []
R = []

for m in range(M):
  l,r = map(int,input().split())
  L+=[l]
  R+=[r]

print(max(0,min(R)-max(L)+1))

Verdicts: Wrong Answer

Accepted
Problem: We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Submission attempts (in order):
N, M = map(int,input().split())


LR = [list(map(int,input().split())) for _ in range(M)]

max_L = 0
min_R = 10**5

for m in range(M):
  if max_L > LR[m][0]:
    max_L = LR[m][0]
  if min_R <LR[m][1]:
    min_R = LR[m][1]
    

L = [x[0] for x in LR]
R = [x[1] for x in LR]

if max(L) - min(R) >=0:
  print(max(L)-min(R)+1)
else:
  print(0)


N, M = map(int,input().split())


LR = [list(map(int,input().split())) for _ in range(M)]


    

L = [x[0] for x in LR]
R = [x[1] for x in LR]


if  min(R) - max(L)>=0:
  print(min(R)-max(L)+1)
else:
  print(0)


Verdicts: Wrong Answer

Accepted