TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
N = int(input())
ans = N * (N - 1) // 2
print(ans)

S = input().split()
T = input().split()
S = list(S[0])
T = list(T[0])

count = 0
for i in range(3):

    if S[i] == T[i]:
        count += 1


print(count)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
A = input()
B = input()
x = 0
for i in range(3):
  if a(i) == b(i):
    x += 1
print(x)

A = input()
B = input()
x = 0
for i in range(3):
  if A[i] == B[i]:
    x += 1
print(x)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
a, b = map(int, input().split())

cnt = 0
p = 1

while p < b:
    p += a - 1
    cnt += 1
    
print(cnt)

a=input()
b=input()

cnt=0

for i, j in zip(a, b):
  if i==j:
    cnt+=1
    
print(cnt)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
    A,B = map(int,input().split())
     
    ans = 0
    if B / A == 1:
        ans = 1
    else:
        ans = 1 + -(-(B - A) // (A - 1))
    print(ans)

A,B = map(int,input().split())
    
ans = 0
if B / A == 1:
    ans = 1
else:
    ans = 1 + -(-(B - A) // (A - 1))
print(ans)

S = input()
T = input()

ret = 0
for i in range(3):
    if S[i] == T[i]:
        ret += 1
print(ret)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
n = int(input())
a = [list(map(int,input().split())) for _ in range(n)]

total = [0]*n

i = 0
count = 0
day = 0
while count < (n*(n-1))//2:
    while total[i] < n-1:
        game = [0] * n
        flag = False
        for j in range(i,n):
            if total[j] == n-1 or game[j] == 0:
                continue
            tmp = a[j][total[j]]
            if game[tmp-1] == 0 and a[tmp-1][total[tmp-1]] == j+1:
                total[j] += 1
                total[tmp-1] += 1
                game[j] += 1
                game[tmp-1] += 1
                count += 1
                flag = True
        if flag == False:
            break
        day += 1
    if flag == False:
        break
    i += 1

if flag == False:
    print(-1)
else:
    print(day)

s = input()
t = input()

ans = 0
for i in range(3):
    if s[i] == t[i]:
        ans += 1
print(ans)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
a, b = list(map(int, input().split()))

c = 0

if b == 1:
    c = 0
elif b / a == 1:
    c = b // a
else:
    c = b // a + 1

print(c)

s = input()
t = input()
count = 0

for i in range(len(s)):
    if s[i] == t[i]:
        count = count + 1

print(count)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s = input()
t = input()

x = 0

for i in range(1,3):
    if s[i] == t[i]:
        x = x + 1

print(x)

s = input()
t = input()

x = 0

for i in range(0,3):
    if s[i] == t[i]:
        x = x + 1

print(x)

Verdicts: Wrong Answer

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s,t=input(),input() print((s[0]==t[0])+(s[1]==t[1])+(s[2]==t[2]))

s,t=input(),input() 
print((s[0]==t[0])+(s[1]==t[1])+(s[2]==t[2]))

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
N = int(input())
A = []
c=0
f = True
for i in range(N):
  A.append(list(map(int, input().split())))
idx = [0 for i in range(N)]

a = 0

cc = 0

ccc = 0

btlf = [False for i in range(N)]
m = (N*(N-1))//2
n = 100000
for i in range(min(m,n)):
  btlf = [False for i in range(N)]
  ccc = 0
  for j in range(N):
    #print(idx)
    if idx[j] != N-1:
      a = A[j][idx[j]]
      if a>j:
        if A[a-1][idx[a-1]]-1==j and btlf[a-1] == False and btlf[j] == False:
          idx[a-1]+=1
          btlf[a-1] = True
          idx[j]+=1
          btlf[j] = True
          cc+=1
          ccc+=1
  if cc == m:
    print(i+1)
    f = False
    break
  if ccc == 0:
    break
if f:
  print(-1)

S = input()
T = input()
c = 0
if S[0]==T[0]:
  c += 1
if S[1]==T[1]:
  c += 1
if S[2]==T[2]:
  c += 1
print(c)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
S=input()
T=input()
print(S.count(T))

S=input()
T=input()
count=0
for i in range(3):
  if S[i]==T[i]:
    count+=1
print(count)

Verdicts: Wrong Answer

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
a, b = map(int, input().split())
for i in range(30):
  if (a + (a-1) * i) >= b:
    break
print(i+1)

# coding:utf-8
a = list(input())
b = list(input())
count = 0

for i in range(3):
  if a[i] == b[i]:
    count += 1
    
print(count)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s,t=open(0);print(sum([i==j for i,j in zip(s,t)]))

s,t=open(0);a=[i==j for i,j in zip(s,t)];print(sum(a))

print(sum(s == t for s, t in zip(input(), input())))

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
print(sum([s == t fot s, t in zip(input(), input())]))

print(sum([s == t for s, t in zip(input(), input())]))

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s,t=input().splitlines()
c=0
for i in range(3):
  if s[i]==t[i]:c+=1
print(c)

s,t=input().split()
c=0
for i in range(3):
  if s[i]==t[i]:c+=1
print(c)

s=input()
t=input()
c=0
for i in range(3):
  if s[i]==t[i]:c+=1
print(c)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s=input()
t=input()
count=0
for i in range(3):
    if s(i)==t(i):
      count+=1
print(count)

s=input()
t=input()
count=0
for i in range(3):
    if s(i)=t(i):
      count+=1
print(count)

s=input()
t=input()
count=0
for i in range(3):
    if s(i)==t(i):
      count+=1
print(count)


s=input()
t=input()
count=0
for i in range(3):
    if s[i]==t[i]:
      count+=1
print(count)


Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s=input()
t=input()
ans=0
for i in range(len(s)):
  if s[i]=t[i]:
    ans+=1
print(ans)

s=input()
t=input()
ans=0
for i in range(len(s)):
  if s[i]==t[i]:
    ans+=1
print(ans)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
limit=int(input())
sum=((limit-1)*limit//2)
print(sum)

s=input()
t=input()
cnt=0
for i in range(3):
	if s[i]==t[i]:
		cnt+=1
		continue
	else:
		continue
print(cnt)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
result = 0
for i in range(3):
  if T[i] == S[i]:
    result +=1
print(result)

S = input()
T = input()
result = 0
for i in range(3):
  if T[i] == S[i]:
    result +=1
print(result)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
S=input()
T=input()
ans=0
for x in range(3)
if S[i]==T[i]:
  ans+=1
print(ans)

S=input()
T=input()
ans=0
for i in range(3)
if S[i]==T[i]:
  ans+=1
print(ans)

S=input()
T=input()
ans=0
for i in range(3):
if S[i]==T[i]:
  ans+=1
print(ans)

n=int(input())
H=list(map(int,input().split()))

ans = 0
i = 0
cnt = 0
for i in range(N-1):
    if H[i] >= H[i+1]:
       cnt += 1
    else:
        ans = max(ans, cnt)
        cnt = 0
ans = max(ans, cnt)
print(ans)


S=input()
T=input()
ans=0
for i in range(3):
    if S[i]==T[i]:
      ans+=1
print(ans)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
S = input()
T = input()
cnt = 0
for i in S:
  if S[i] == T[i]:
    cnt += 1
print(cnt)

S = input()
T = input()
cnt = 0
loop = 0
for i in S:
  if i == T[loop]:
    cnt += 1
  loop += 1
print(cnt)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s,t=input().split()
if s==t:
  print(3)
elif s!=t:
  for i in range(3):
    if s[i]==t[i]:
      i+=1
      print(i)

s = input()
t = input()

count = 0

for i in range(3):
  count += 1
  print(count)

a, b, c = input()
d, e, f = input()
if a, b, c == d, e, f:
  print(3)
elif a == b and b == e:
  print(2)
elif b == e and c == f:
  print(2)
elif c == f and a == b:
  print(2)
elif a == d or b == e or c == f:
  print(1)
else:
  peint(0)

s = input()
t = input()
 
count = 0
 
for i in range(3):
	if s[i] == t[i]
	count += 1  
  	print(count)

s = input()
t = input()

count = 0

if s[i] == t[i]:
  count += 1
  print(count)

s = input()
t = input()

count = 0

for i in range(3)
	if s[i] == t[i]
	count += 1  
  	print(count)

a, b, c = input()
d, e, f = input()
if a == d and b == e and c == f:
  print(3)
elif a == b and b == e:
  print(2)
elif b == e and c == f:
  print(2)
elif c == f and a == b:
  print(2)
elif a == d or b == e or c == f:
  print(1)
else:
  peint(0)

a, b, c = input()
d, e, f = input()
if a == d and b == e and c == f:
  print(3)
elif a == b and b == e, b == e and c == f, c == f and a == b:
  print(2)
elif a == d or b == e or c == f:
  print(1)
else:
  peint(0)

s = input()
t = input()
 
count = 0
 
for i in range(3):
	if s[i] == t[i]:
	count += 1  
  	print(count)

a, b, c = input()
d, e, f = input()
if a == d and b == e and c == f:
  print(3)
elif a == b and b == e:
  print(2)
elif b == e and c == f:
  print(2)
elif c == f and a == b:
  print(2)
elif a == d or b == e or c == f:
  print(1)
elif a != d and b != e and c != f:
  peint(0)
else:
  pass

s = input()
t = input()
 
count = 0
 
for i in range(3):
		if s[i] == t[i]:
			count += 1  
    
print(count)

Verdicts: Runtime Error

Wrong Answer

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
import sys
from collections import deque
input = sys.stdin.readline
sys.setrecursionlimit(10 ** 7)

N = int(input())

A = []
for i in range(N):
    A.append(list(map(int, input().split())))

B = []
for i in range(N):
    tmp = [0] * N
    for j in range(N-1):
        tmp[A[i][j]-1] = j+1
    B.append(tmp)


ans = N-1
ans_tmp = 0
ans_tmp1 = 0
for i in range(N):
    ans_tmp = 0
    tmp = 0
    for j in A[i]:
        if B[j-1][i] > tmp:
            tmp = B[j-1][i]
        elif B[j-1][i] == tmp:
            ans_tmp += 1
        else:
            print(-1)
            sys.exit()
    ans_tmp1 = max(ans_tmp1, ans_tmp+tmp)

print(ans_tmp1)


import sys
input = sys.stdin.readline
sys.setrecursionlimit(10 ** 7)

S = list(input().strip())
T = list(input().strip())

ans = 0
for i in range(len(S)):
    if S[i] == T[i]:
        ans += 1

print(ans) 

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s = list(input())
t = list(input())
s = 0
for i in range(3):
  if s[i] = t[i]:
    s += 1
print(s)
  


S = list(input())
T = list(input())
s = 0
for i in range(3):
  if S[i] = T[i]:
    s += 1
print(s)
  


s = list(input())
t = list(input())
s = 0
for i in range(3):
  s[i] = t[i]
  s += 1
print(s)
  


S = list(input())
T = list(input())
s = 0
for i in range(3):
  if S[i] == T[i]:
    s += 1
print(s)
  


Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s = input()
t = input()
count = 0

for i in len(s):
	if s[i] == t[i]:
		count += 1

print(count)

s = input()
t = input()
count = 0

for i in range(len(s)):
	if s[i] == t[i]:
		count += 1

print(count)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s = list(input())
t = list(input())
ans = 0
for i in range (3):
    if S[i] == T[i]:
        ans += 1
print(ans)


s = list(input())
t = list(input())
ans = 0
for i in range (3):
    if s[i] == t[i]:
        ans += 1
print(ans)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s = list(input())
t = list(input())
ing_total = 0

for x in range(2):
    if s[x] == t[x]:
        ing_total+=1
    print(ing_total

s = list(input())
t = list(input())
ing_total = 0

for x in range(2):
    if s[x] == t[x]:
        ing_total+=1
    else:
        ing_total+=0
     print(ing_total)



s = list(input())
t = list(input())
ing_total = 0

for x in range(2):
    if s[x] == t[x]:
        ing_total+=1
        print(ing_total)


s = list(input())
t = list(input())
ing_total = 0

for x in range(3):
    if s[x] == t[x]:
        ing_total+=1
    else:
        ing_total+=0
print(ing_total)


Verdicts: Runtime Error

Runtime Error

Wrong Answer

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
print('test')


s=input()
t=input()
count=0


if s[0]==t[0]:
 count += 1
if s[1]==t[1]:
 count +=1
if s[2]==t[2]:
 count +=1
print(count)





Verdicts: Wrong Answer

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
a=input().split()
b=input().split()
count=0
for i in range(3):
  if a[i]==b[i]:
    count+=1
print(count)
  

a=input()
b=input()
count=0
for i in range(3):
  if a[i]==b[i]:
    count+=1
print(count)
  

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
S=input()
T=input()
ans=0
for i in range(3):
	if S[i] == T[i]:
  	ans += 1
    print(ans)

S=input()
T=input()
ans=0
for i in range(3):
	if S[i] == T[i]:
  	ans += 1
print(ans)

S=input()
T=input()
ans=0
for i in range(3)
	if S[i] == T[i]
  	ans += 1
    print(ans)

S=input()
T=input()
ans=0
for i in range(3):
	if S[i] == T[i]:
  	ans += 1
    print(ans)

a = input()
b = input()
c = 0
for i in range(3):
  if a[i] == b[i]:
    c += 1
print(c)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s,t=input().split()
count=0
for i in range(3):
    if s[i]==t[i]:
        count=count+1
print(count)

s,t=map(str,input().split())
count=0
for i in range(3):
    if s[i]==t[i]:
        count=count+1
print(count)

s = input()
t = input()
count=0
for i in range(3):
    if s[i]==t[i]:
        count=count+1
print(count)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
F = input().split()
A = input().split()
s = 0
s += F[0] == A[0] ? 1 : 0
s += F[1] == A[1] ? 1 : 0
s += F[1] == A[2] ? 1 : 0
print(s)

F = input()
A = input()
s = 0
s += 1 if F[0] == A[0] else 0
s += 1 if F[1] == A[1] else 0
s += 1 if F[2] == A[2] else 0
print(s)


Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
s=input()
t=input()
cnt=0
for i in rage(len(s)):
  if s[i]==t[i]:
    cnt+=1

print(cnt)

s=input()
t=input()
cnt=0
for i in range(len(s)):
  if s[i]==t[i]:
    cnt+=1
 
print(cnt)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
predict = input('predict')

actual = input('actual')

count = 0

for index in range(0, len(predict)):
    if predict[index] == actual[index]:
        count += 1
        
print (count)

predict = raw_input()

actual = raw_input()

count = 0

for index in range(0, len(predict)):
    if predict[index] == actual[index]:
        count += 1

print (count)

predict = input()

actual = input()

count = 0

for index in range(0, len(predict)):
    if predict[index] == actual[index]:
        count += 1

print (count)

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
#copy

s = chr(input())
t = chr(input())

ans = 0

for i in range(3):
    if s[i] == t[i]:
        ans += 1
print(ans)

#copy

s = input()
t = input()

ans = 0

for i in range(3):
    if s[i] == t[i]:
        ans += 1
print(ans)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
S=list(map(int.input().split()))
T=list(map(int.input().split()))
int x = 0

for i in range(3):
  if S[i] == T[i]:
    x += 1
print(x)


S=list(map(int.input().split()))
T=list(map(int.input().split()))
int x=0

for S[] in T[]:
  x += 1
  
print(x)
  

S=list(map(int.input().split()))
T=list(map(int.input().split()))
x = 0
for i in range(3):
  if S[i] == T[i]:
    x += 1
print(x)


S=input()
T=input()
x = 0
for i in range(3):
  if S[i] == T[i]:
    x += 1
print(x)


Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
S = input()
T = input()
c = 0
for a in S:
    for b in T:
        if a ==b:
            c +=1
print(c)
        
    

S = input()
T = input()
c = 0
for a in S:
    for b in T:
        if a == b:
            c += 1
print(c)

S = str(input())
T = str(input())
c = 0
for a in S:
    for b in T:
        if a == b:
            c += 1
print(c)

S = input()
T = input()
a = list(S)
b = list(T)
c = 0
if a[0] == b[0]:
    c +=1
if a[1] == b[1]:
    c +=1
if a[2] == b[2]:
    c +=1
print(c)


Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
n=int(input())-1;print(n*(n+1)//2)

#python3

def main():
    s = input()
    t = input()
    cnt = 0
    for i,j in zip(s,t):
        if i == j:
            cnt += 1
    print(cnt)
main()


Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
a = input()
b = input()
count = 0
for i in range (1,3):
  if a[i]==b[i]:
    count +=1
print(count)

a = input()
b = input()
count = 0
for i in range (3):
  if a[i]==b[i]:
    count +=1
print(count)

Verdicts: Wrong Answer

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
S = input()
T = input()
count = 0
for i in range(len(3)):
  if S[i] == T[i]:
    count += 1
print(count)

S = input()
T = input()
count = 0
for i in range(3):
  if S[i] == T[i]:
    count += 1
print(count)


Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
pred = input()
true = input()
cnt = 0
for i in range(len(pred)):
  if pred[i] == true[i]:
    cnt += 1
    

pred = input()
true = input()
cnt = 0
for i in range(3):
  if pred[i] == true[i]:
    cnt += 1
print(cnt)

Verdicts: Wrong Answer

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
S = print()
T = print()
count = 0

for i in range(3):

    if S[i] == T[i] 
    print(I)
count(I)

S = print()

print(s | c | r)
T = print()

print((s | c | r))
S == T

S = input()
T = input()

count = 0

for i in range(3):

    if S[i]==T[i] 
    print(I)
count(I)

S = print()
T = print()
count == 0

for i in range(3)

if S[i] == T[i] 
    print(I)
count(I,num)

S = imput()
T = imput()

count = 0

for i in range(3):

    if S[i]==T[i] 
    count += 1
print(count)

S = input()
T = input()

count = 0

for i in range(3):

    if S[i]==T[i]:
    count += 1
print(count)

S = input()
T = input()

count = 0

for i in range(3):

    if S[i] == T[i] 
    print(I)
count(I)

S = input()
T = input()

count = 0

for i in range(3):

    if S[i]==T[i] 
    count += 1
print(count)

S = input()
T = input()

count = 0

for i in range(3):

    if S[i]==T[i]:
        count += 1
print(count)


Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
A,B = map(int, input().split())
count = 0
socketnumber = A
while socketnumber < B:
    socketnumber += (A-1)
    count += 1
count += 1
print (count)
    

S = input()
T = input()
count = 0
forecastlist = []
realweatherlist = []
for forecast in S:
  forecastlist.append(forecast)
for weather in T:
  realweatherlist.append(weather)
  
for i in range(3):
  if forecastlist[i] == realweatherlist[i]:
    count += 1
print(count)

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
    forecasts = list(input())
    actuals = list(input())
    ex_count = 0
    for x in range(3):
        if forecasts[x] == actuals[x]:
            ex_count = ex_count + 1
    print("{}".format(ex_count))

forecasts = list(input())
actuals = list(input())
ex_count = 0
for x in range(3):
    if forecasts[x] == actuals[x]:
        ex_count = ex_count + 1
print("{}".format(ex_count))

Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
from collections import deque
def main():
    N=int(input())
    A = [deque(map(int, input().split())) for _ in range(N)]

    days = 0
    changed = True
    played = set()
    while changed:
        played.clear()
        changed = False
        for i in range(N-1):
            if len(A[i]) == 0:
                continue
            a1 = A[i][0]
            if len(A[a1-1]) == 0:
                continue
            a2 = A[a1-1][0]
            if a1 in played or a2 in played:
                continue
            if a2-1 == i:
                A[a2-1].popleft()
                A[a1-1].popleft()
                played.add(a2)
                played.add(a1)
                changed = True
        if changed:
            days+=1

    for a in A:
        if len(a) > 0:
            print(-1)
            break
    else:
        print(days)

if __name__ == '__main__':
    main()

S=input()
T=input()
ans=0
for s,t in zip(S,T):
  if s==t:
    ans+=1
print(ans)


Verdicts: Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
S = input()
T = input()

cnt = 0

for i in range(0,3):
  if S[i] == T[i]:
    cnt += 1

pirn(cnt)
  


S = list(input())
T = list(input())

cnt = 0

for i in range(0,3):
  if S[i] == T[i]:
    cnt += 1

pirn(cnt)
  


S = list(input())
T = list(input())

cnt = 0

for i in range(0,3):
  if S[i] == T[i]:
    cnt += 1

pirn(cnt)
  

S = list(input())
T = list(input())

cnt = 0

for i in range(0,3):
  if S[i] == T[i]:
    cnt += 1

print(cnt)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
# -*- coding: utf-8 -*-
S = input()
T = input()
c = 0
for s,t in zip(S,T):
  if s == t:
    c +=1
print(c/3)


# -*- coding: utf-8 -*-
S = input()
T = input()
c = 0
for i in range(3):
  if S[i] == T[i]:
    c +=1
print(c/3)


# -*- coding: utf-8 -*-
S = input()
T = input()
c = 0
for i in range(3):
  if S[i] == T[i]:
    c +=1
print(c)


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: You will be given a string S of length 3 representing the weather forecast for three days in the past.  The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  You will also be given a string T of length 3 representing the actual weather on those three days.  The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.  Print the number of days for which the forecast was correct.

Submission attempts (in order):
import math
N = int(input())
print(math.floor(1 / 2 * N * (N - 1)))


S = input()
T = input()
count = 0
for (s, t) in zip(S, T):
    if s == t:
        count += 1
print(count)


Verdicts: Runtime Error

Accepted