TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k = int(input())
s = input()
print(s[:k])


k = int(input())
s = input()

length = len(s)

if length <= k:
  print(s)
else:
  print(s[:k] + "...")

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = input()
S = input()
if len(S) <= int(K):
    print(S)
else:
     print(S[0:int(K)])

K = input()
S = input()
if len(S) <= int(K):
    print(S)
else:
     print(S[0:int(K)] +'...')

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
import sys

K = int(input())
S = input()

print(K,len(S))

if K >= len(S):
    print(S)
else:
    print(S[:K]+'...')

import sys

K = int(input())
S = input()

print(K,len(S))

if K > len(S):
    print(S)
else:
    print(S[:K]+'...')


import sys

K = int(input())
S = input()

if K >= len(S):
    print(S)
else:
    print(S[:K]+'...')

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
40
ferelibenterhominesidquodvoluntcredunt

n=int(input())
s=input()
if len(s)>n:
  print(s[:n]+"...")
else:
  print(s)

Verdicts: Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k = int(input())
s = input()
if k == len(s):
    print(s)
else:
    print(s[:k]+"."*(len(s) - k))

k = int(input())
s = input()
if k >= len(s):
    print(s)
else:
    print(s[:k]+"...")

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
def triple_dot():
    k = int(input())
    s = list(input())
    len_s =len(s)
    result_s = []
    
    if len_s > k:
        for i in range(k):
            result_s.append(s[i])
    if len_s < k:
        print("".join(s))

triple_dot()

def triple_dot():
    k = int(input())
    s = input()
    len_s =len(s)
    result_s = []
    
    if len_s > k:
        for i in range(k):
            result_s.append(s[i])
        print("".join(result_s) + "...")
    else:
        print("".join(s))
triple_dot()

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = int(input())
S = input()
if len(s)>K:
    s = s[:k] + "..."

print(s)

K = int(input())
S = input()
if len(S)>K:
   print( S[:K] + "...")
else:
    print(S)

Verdicts: Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k = input()
s = input()
if len(s)>=int(k):
    print(s)
else:
    print(s[0:int(k)]+'...')

k = input()
s = input()
if len(s)<=int(k):
    print(s)
else:
    print(s[0:int(k)]+'...')

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k = input()
s = input()

if len(s) <= int(k):
  print(s)
else:
  print(s[0:k] + "...")

k = input()
s = input()

if len(s) <= int(k):
  print(s)
else:
  print(s[0:int(k)] + "...")

Verdicts: Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K=int(input())
s =input()
x = len(s)

if x<=K:
    print(s)
else:
    print(S[:K]+'...')

K=int(input())
s =input()
x = len(s)

if x<=K:
    print(s)
else:
    print(s[:K]+'...')

Verdicts: Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = int(input())
S = input()

length = len(S)

if length <= K:
  print(S)
  
else:
  S = S[K:]
  print(S.apend("..."))
  

K = int(input())
S = input()

length = len(S)

if length <= K:
  print(S)
  
else:
  S = S[K:]
  print(S + "...")
  


K = int(input())
S = input()

length = len(S)

if length <= K:
  print(S)
  
else:
  S = S[:K]
  print(S + "...")
  


Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
a=input()
a=int(a)
b=input()
c=""
if a>=len(b):
  print(b)
else:
  for i in range(a):
    c=c+b[i]
  print(c)

a=input()
a=int(a)
b=input()
c=""
if a>=len(b):
  print(b)
else:
  for i in range(a):
    c=c+b[i]
  print(c+"...")

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = input()
S = int(input())

if len(K) <= S:
    print(K)
else:
    print(K[0:S] + '...')

K = int(input())
S = input()

if len(S) <= K:
    print(S)
else:
    print(S[0:K] + '...')

Verdicts: Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = input()
S = input()


K = int(K)
 
s_length = len(S)


if s_length > K:
    val = S[0:K]
    print(val,'...')
else :
    print(S)

K = input()
S = input()


K = int(K)
print(K) 
s_length = len(S)


if s_length > K:
    val = S[0:K]
    print(val,'...')
else :
    print(S)

K = int(input())
S = input()

if len(S) > K:
    S = S[:K] +'...'

print(S)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = input()
S = input()
if len(s) > int(k):
  print(s[:k]+'...')
else:
  print(s)

K = int(input())
S = input()
if len(S) > K:
	print(S[:K] + '...')
else:
	print(S)

Verdicts: Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k = int(input())
s = input()
ls = len(s)

if ls <=k:
    print(s)
else:
    print(s+'...')

k = int(input())
s = input()
ls = len(s)

if ls <=k:
    print(s)
else:
    print(s[:k]+'...')

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
n=int(input())
s=input()
while len(s)<n:
    s=s[:n]+"..."
print(s)  

n=int(input())
s=input()
if len(s)>n:
    s=s[:n]+"..."
print(s) 

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
 k=int(input())
s=input()
if len(s) <= k:
    print(s)
else:
    print("{fname}...".format(fname = s[:k]))

k=int(input())
s=input()
if len(s) <= k:
    print(s)
else:
    print(s[:k]+'...')

Verdicts: Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = int(input())
S = input()

#print(len(S))
#print(S[1:3])

if len(S) <= K :
  print(S)
else:
  print(S[1:K])

K = int(input())
S = input()

#print(len(S))
#print(S[1:3])

if len(S) <= K :
  print(S)
else:
  print(S[1:K] + "...")

K = int(input())
S = input()

#print(len(S))
#print(S[1:3])

if len(S) > K :
  print(S[1:K] + "...")
else:
  print(S)

K = int(input())
S = input()

#print(len(S))
#print(S[1:3])

if len(S) <= K :
  print(S)
else:
  print(S[0:K] + "...")

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k = int(input())
s = []
s = str(input())
if len(s)<= k:
    print(s)
else:
    print(s[0:k],'...')

k = int(input())
s = []
s = str(input())
if len(s)<= k:
    print(s)
else:
    print(s[0:k]+'...')

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = int(input())
S = input()

if len(S) <+ K:
    print(S)
elif len(S) > K:
    SK = S[: K]+ "…"
    print(SK)

K = int(input())
S = input()

if len(S) <= K:
    print(S)
elif len(S) > K:
    SK = S[: K]+ "..."
    print(SK)

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):

k=input()
s=input()

if len(s)<int(k):
    print(s)
else:
    print(s+"...")


k=input()
s=input()

if len(s)<=k:
    print(s)
else:
    print(s+"...")


k=int(input())
s=input()

if len(s)<k:
    print(s)
else:
    print(s+"...")


k=input()
s=input()

if len(s)<=k:
    print(s)
else:
    print(s+"...")


k=int(input())
s=input()

if len(s)<=k:
    print(s)
else:
    print(s+"...")


k=int(input())
s=input()

#if len(s)<=k:
    #  print(s)
    #else:
    #print(s+"...")








if len(s)<=k:
      print(s)
else:
    print(s[:k] + '...')
    



Verdicts: Wrong Answer

Runtime Error

Wrong Answer

Runtime Error

Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = str(input)
S = input()
if len(S)<=K:
    print(S)
else:
    print(S[:K]+'...')

K = int(input())
S = input()
if len(S)<=K:
    print(S)
else:
    print(S[:K]+'...')

Verdicts: Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = int(input())
S = input()
 
if len(S) <= K:
  print(S)
elif len(S) > K:
  print(S[0:K-1]+"...")

K = int(input())
Sub = input()

if len(Sub) <= K:
  print(Sub)
elif len(Sub) > K:
  print(Sub[0:K-1]+"...")

K = int(input())
S = input()
 
if len(S) <= K:
  print(S)
elif len(S) > K:
  print(S[0:K]+"...")

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = int(input("K:"))
S = str(input("S:"))

s = len(S)

if s <= K:
    print(S)
else:
    print(S[:K] + "...")


K = int(input())
S = str(input())

s = len(S)

if s <= K:
    print(S)
else:
    print(S[:K] + "...")


Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k=int(input())
s=input()
lng=len(s)
x=s[:k]
if k < lng:
    print(s)
else:
    print(x+'...')

k=int(input())
s=input()
lng=len(s)
x=s[:k]
if k >= lng:
    print(s)
else:
    print(x+'...')



Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k = int(input())
s = input()

if len(s) <= k:
    print(s)
else:
    print(s[:k])

k = int(input())
s = input()

if len(s) <= k:
    print(s)
else:
    print(s[:k] + "...")

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k=input()
n=input()

m=len(n)

t=int (k)



if(m==t):
  print("n")
  
else:
  for i, name in enumerate(n):
    if i==t:
      break
    print(name,end='')
    
    



k=input()
n=input()

m=len(n)

t=int (k)



if(m<=t):
  print("n")
  
else:
  for i, name in enumerate(n):
    if i==t:
      break
    print(name,end='')
    
    



k=input()
n=input()

m=len(n)

t=int (k)



if(m<=t):
  print("n")
  
else:
  for i, name in enumerate(n):
    if i==t:
      break
    print(name,end='')
    
    



k=input()
n=input()

m=len(n)

t=int (k)



if(m<=t):
  print(n)
  
else:
  for i, name in enumerate(n):
    if i==t:
      print("...")
      break
    print(name,end='')
    
    



Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = input()
try:
  if 0 > int(K) or int(K) >= 100:
    print("K's value must be over 1 and under 100")
    exit()
except ValueError:
  print("K's value must be integer")
  exit()

S = input()
if 1 > len(S) or 100 < len(S):
  print("S's length must be over 1 and under 100")
  exit()
  
if len(S) <= int(K):
  print(S)
else:
  S = S[:K]
  S.append('...')
  print(S)
  

K = input()

try:
   if 0 > int(K) or int(K) >= 100:
      print("K's value must be over 1 and under 100")
      exit()
except ValueError:
   print("K's value must be integer")
   exit() 

S = input()
  if 1 > len(S) or 100 < len(S):
    print("S's length must be over 1 and under 100")
    exit()
   
  if len(S) <= int(K):
    print(S)
  else:
    S = S[:int(K)]
    S += '...'
    print(S)


K = input()

try:
   if 0 > int(K) or int(K) >= 100:
      print("K's value must be over 1 and under 100")
      exit()
except ValueError:
   print("K's value must be integer")
   exit() 

S = input()
  if 1 > len(S) or 100 < len(S):
    print("S's length must be over 1 and under 100")
    exit()
   
  if len(S) <= int(K):
    print(S)
  else:
  S = S[:int(K)]
  S += '...'
  print(S)


K = input()
S = input()

   
if len(S) <= int(K):
  print(S)
else:
  S = S[:int(K)]
  S += '...'
  print(S)


Verdicts: Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = int(input())
S = str(input())

if K >= S:
  print(S)
else:
  print(S[:K] + '...')

k = int(input())
s = input()

if len(s) > k:
  s = s[:k] + '...'
  
print(s)

Verdicts: Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
import math
def heikatu(A,B):
    if A % abs(B) ==0:
        return (A//abs(B),B//abs(B))
    if abs(B) % A == 0:
        return (1,B//A)
    
    c = 2
    while c <=math.sqrt(max(A,abs(B))):
        while A % c ==0 and B% c ==0:
            A //=c
            B//=c
        c+=1

    return (A,B)


def pow_r(x, n,mod=10**9+7):
    
    if n == 0:  # exit case
        return 1
    if n % 2 == 0:  # standard case ① n is even
        return pow_r((x ** 2)%1000000007 , n // 2) % mod
    else:  # standard case ② n is odd
        return (x * pow_r((x ** 2)%1000000007, (n - 1) // 2) % mod) % mod



def resolve():
    N = int(input())

    kp = dict()
    km = dict()
    zero = [0,0]
    zerozero = 0
    for i in range(N):
        A,B = map(int,input().split())
        if A <0:
            A *= -1
            B *= -1
        if A == 0 and B == 0:
            zerozero+=1
            continue

        if A == 0:
            zero[0]+=1
            continue
        if B == 0:
            zero[1]+=1
            continue

        xx = heikatu(A,B)



        if B < 0:
            if not xx in km:
                km[xx]=0
            km[xx]+=1
        else:
            if not xx in kp:
                kp[xx]=0
            kp[xx]+=1

    tx = []
    if zero != [0,0]:
        tx.append(zero)

    for key in kp:
        A,B = key
        cou = kp[key]    
        if (B,-A) in km:
            tx.append([cou,km[(B,-A)]])
            km.pop((B,-A))
        else:
            tx.append([cou,0])
    for key in km:
        tx.append([0,km[key]])

    ans = 1
    mod = 1000000007
    for a,b in tx:
        xxx = 0
        if a != 0:
            xxx=(xxx+pow_r(2,a)) %mod
        if b != 0:
            xxx=(xxx+pow_r(2,a)) %mod
        if a !=0 and b!=0:
            xxx-=1
        ans = (ans*xxx) % mod

    ans = (ans+mod-1+zerozero) % mod 

    print(ans)       


        







resolve()

def resolve():
    K= int(input())
    S = input()

    if len(S) <= K:
        print(S)
    else:
        print(S[:K]+"...")



if __name__ == "__main__":
    resolve()

Verdicts: Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
import itertools
import sys

def main():
    # n, m, x = map(int, input().split())
    k = int(input())
    s = input()
    print(len(s))
    if len(s) > k:
        s = s[:k] + '...'

    print(s)


if __name__ == '__main__':
    main()

import itertools
    k = int(input())
    s = input()
    if len(s) > k:
        s = s[:k] + '...'
    print(s)

if __name__ == '__main__':
    main()


def main():
    k = int(input())
    s = input()
    if len(s) > k:
        s = s[:k] + '...'

    print(s)


if __name__ == '__main__':
    main()


Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k=int(input())
s=input()

if len(s)<=k:
  print(s)
else:
  print(s[:k])

k=int(input())
s=input()

if len(s)<=k:
  print(s)
else:
  print(s[:k]+'...')

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = int(input())
S = input()
Sl = len(S)
if Sl <= K:
  ans = S
else:
  newS = S[0 : Sl - 1]
  ans = (newS + "...")
print(ans)

K = int(input())
S = input()
Sl = len(S)
if Sl <= K:
  ans = S
else:
  newS = S[0 : Sl - 1].append("...")
  ans = newS
print(ans)
  

K = int(input())
S = input()
Sl = len(S)
if Sl <= K:
  ans = S
else:
  newS = S[0 : K-1]
  ans = (newS + "...")
print(ans)

K = int(input())
S = input()
Sl = len(S)
if Sl <= K:
  ans = S
else:
  newS = S[0 :: K - 1]
  ans = (newS + "...")
print(ans)

K = int(input())
S = input()
Sl = len(S)
if Sl <= K:
  ans = S
else:
  newS = S[0 : K]
  ans = (newS + "...")
print(ans)

Verdicts: Wrong Answer

Runtime Error

Wrong Answer

Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
#-*-coding:utf-8-*-

def main():
    k = int(input().strip())
    s = input().strip()
    if len(s) <= k:
        print(s)
    else:
        print(s[:k]+"…")

if __name__=="__main__":
    main()

#-*-coding:utf-8-*-

def main():
    k = int(input().strip())
    s = input().strip()
    if len(s) <= k:
        print(s)
    elif len(s) > k:
        print(s[:k]+"...")

if __name__=="__main__":
    main()

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K=int(input())
S=input()

if len(S)<=K:
    print(S)
else:
    print(S[:K],'...')

K=int(input())
S=input()

if len(S)<=K:
    print(S)
else:
    print(S[:K],'...',sep='')

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k = int(input())
s = list(input())
if k=>len(s):
    print(s)
else print(s[for k i in range k+1]+"...")

k = int(input())
s = list(input())
if k>=len(s):
    print(s)
else:
    for i in range (k):
        print(s[i])
    print("...")
  

k = int(input())
s =input()
if k>=len(s):
    print(s)
else:
    for i in range (k):
        print(s[i],end="")
    print("...")

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
def main():
    K = int(input())
    S = input()
    ans = S if len(S) <= K else S[:K + 1] + "..."
    print(ans)


if __name__ == "__main__":
    main()


def main():
    K = int(input())
    S = input()
    ans = S if len(S) <= K else S[:K] + "..."
    print(ans)


if __name__ == "__main__":
    main()


Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = int(input())
S = input()
if len(S) <= K:
    print(S)
else:
    print(S[:K+1]+'...')

K = int(input())
S = input()
if len(S) <= K:
    print(S)
else:
    print(S[:K]+'...')

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k = int(input())
s = input()
#a, b = map(int, input().split())
#l = list(map(int, input().split()))
#s = input()


if len(s) <= k:
    print(s)
else:
    s += "..."
    print(s)


k = int(input())
s = input()
#a, b = map(int, input().split())
#l = list(map(int, input().split()))
#s = input()


if len(s) <= k:
    print(s)
else:
    t = s[0:k] + "..."
    print(t)


Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k=int(input())
s=input()
print(s if len(s)<=k else s[0]+"...")

k=int(input())
s=input()
print(s if len(s)<=k else s[0:k+1]+"...")

k=int(input())
s=input()
print(s if len(s)<=k else s[1:k+1]+"...")

k=int(input())
s=input()
print(s if len(s)<=k else s[0:k]+"...")

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = int(input())
S = input()

if K < len(S):
  S = S[0:K-1]
  S = S+"..."
  
print(S)

K = int(input())
S = input()

if K < len(S):
  S = S[0:K]
  S = S+"..."
  
print(S)

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = int(input())
S = input()

if len(S) <= K:
    print(S)
else:
    print(S[K:] + "." * 3)


K = int(input())
S = input()

if len(S) <= K:
    print(S)
else:
    print(S[0:K] + "." * 3)


Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k = int(input())
s = input()

print(s if len(s)<=k else s[0:k] + "...")a

k = int(input())
s = input()

print(s if len(s)<=k else s[0:k] + "...")

Verdicts: Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k = int(input())
s = input()
if len(s) <= k:
	print(s)
else:
	res = s[0:(k-1)]
	res += "..."
	print(res)



k = int(input())
s = input()
if len(s) <= k:
	print(s)
else:
	res = s[1:k]
	res += "..."
	print(res)



k = int(input())
s = input()
if len(s) <= k:
	print(s)
else:
	res = s[0:k]
	res += "..."
	print(res)


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K=int(input())
S=input()

if len(S)<=K:
    print(S)
else:
    print(S[:K+1]+"...")

K=int(input())
S=input()

if len(S)<=K:
    print(S)
else:
    print(S[:K]+"...")

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k=int(input())
s=input()
t=len(list(s))
print(t)
n=""
if(t<=k):
    print(s)
else:
    for i in range(k):
        n=n+s[i]
    n=n+"..."
    print(n)

k=int(input())
s=input()
t=len(list(s))
#print(t)
n=""
if(t<=k):
    print(s)
else:
    for i in range(k):
        n=n+s[i]
    n=n+"..."
    print(n)

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k = int(input())
s = input()

if len(s) <= k:
    print(s)
else:
    print(s+"...")

k = int(input())
s = input()

if len(s) <= k:
    print(s)
else:
    print(s[:k]+"...")

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
i = int(input())
s= input()
if len(s) > k:
  s=s[:k] + "..."
print(s)

i = int(input())
s= input()
if len(s) > i:
	s=s[:i] + "..."
print(s)

Verdicts: Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k = int(input())
s = input()
l = len(list(s))
if l <=k:
    print(s)
else:
    t = s+"..."
    print(t)


k = int(input())
s = input()
n = len(list(s))
if n <= k:
    print(s)
else:
    t = s[:k]+"..."
    print(t)

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k=int(input()) 
s=str(input()) 

if len(s)<=k:
  print(s[:k])
else:
  print(s[:k]+"....")

k=int(input()) 
s=str(input()) 

if len(s)<=k:
  print(s[:k])
else:
  print(s[:k]+"...")

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = int(input())
S = input()

if K <= len(S):
  print(S)
else:
  print(S[:K] + "...")

K = int(input())
S = input()
 
if K >= len(S):
  print(S)
else:
  print(S[:K] + "...")

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K=input()
S=input()
S=str(S)
C=len(S)
print(C)
if(int(C)<=int(K)):
  print(S)
else:
  print((S[:int(K)])+"...")

K=input()
S=input()
S=str(S)
C=len(S)

if(int(C)<=int(K)):
  print(S)
else:
  print((S[:int(K)])+"...")

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k = int(input())
s = list(input())
result =[]
for i,letter in enumerate(s):
    result.append(letter)
    if k == 0:
        print("...")
        break
    elif i+1 == k:
        break
    elif i+1 > k:
        result.append("...")
        break
print("".join(result))


k = int(input())
s = list(input())
result =[]
for i,letter in enumerate(s):
    if k == 0:
        result.append("...")
        break
    elif i+1 <= k:
        result.append(letter)
    else:
        result.append("...")
        break
print("".join(result))


Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = int(input())
S = input()
if len(S) <= K:
  print(S)
else:
  print(S[K:]+"...")


K = int(input())
S = input()
if len(S) <= K:
  print(S)
else:
  print(S[K:]+...)

K = int(input())
S = input()
if len(S) <= K:
  print(S)
else:
  print(S[:K]+"...");


Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
def moji(S,K):
    if len(S)<=K:
        print(S)
    else:
        T=""
        for i in range(len(S)):
            if i <K:
                 T+=S[i]
            if i >=K:
                continue
        T+="..."
        print(T)
        

K=int(input())
S=input()

def moji(S,K):
    if len(S)<=K:
        print(S)
    else:
        T=""
        for i in range(len(S)):
            if i <K:
                 T+=S[i]
            if i >=K:
                continue
        T+="..."
        print(T)

K=int(input())
S=input()

def moji(S,K):
    if len(S)<=K:
        print(S)
    else:
        T=""
        for i in range(len(S)):
            if i <K:
                 T+=S[i]
            if i >=K:
                continue
        T+="..."
        print(T)

moji("S",K)


K=int(input())
S=input()

def moji(S,K):
    if len(S)<=K:
        print(S)
    else:
        T=""
        for i in range(len(S)):
            if i <K:
                 T+=S[i]
            if i >=K:
                continue
        T+="..."
        print(T)

moji(S,K)

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
# program to print the new string after performing append operation in the string s "..." 
# if only the character s is more than k but if the character s is at most k
# the output will not change
#first we will define the new string

k =int(input())
s = input()

str = s
dots = "..."
if len(s) == k:
print(s)
elif len(s) > k:
print (str[0:k],"...")



string=input()
number=int(input())
characters=len(string)
empty=""
if characters<=number:
    print(string)
else:
   i=0
   while i<=number-1:
       empty+=string[i]
       i=i+1
   print(f"{empty}...")

K=int(input())
S=input()
if len(S)==K:
    print (S)
else:
    print(S[K])  


k= input()
s= str(input())

while k==1 and k<=100 and len(s)==1 and len(s)<=100: #check if k and s are between 1 to 100

    if len(s) > k:
        #s.slice(k)
        print (s.slice(k)+"...") #cut the str until value of k and add ... to the end

    else:
        print (s)

K=int(input())
S=input()
if lens(s)>k:
    print(S[ :K ] + "...")
else:
    print(s)
S[]
S[5:]


#input an interget
K=int(input())
#input an string
S=str(input())
#get the length of the string
x=int(len(str1))
#get the difference in length between k and s
i=x-k

#make a second string for the appending
S2="..."

#if statement about how the string will function
#if the string is the same length as k then print it
if i==0:
    print(S)
#if not, delete the last character of the string
else:
    for i in range(x):
        S=S[i]
#and then join the two strings together
    newstr="".join((S,S2))
    print(newstr)


K=int(input())
S=input()

if len(S)<K or len(S)==K:
    print (S)
elif len(S)>K:
    print(S[K])  


number=int(input())
string=input()
characters=len(string)
empty=""
if characters<=number:
    print(string)
else:
   i=0
   while i<=number-1:
       empty+=string[i]
       i=i+1
   print(f"{empty}...")

Verdicts: Runtime Error

Runtime Error

Runtime Error

Wrong Answer

Runtime Error

Runtime Error

Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = int(input())
S = str(input())
if K > len(S):
    print (S)
else:
    print (S[0:K]+ " ... ") 


K = int(input())
S = str(input())
if K >= len(S):
    print (S)
else:
    print (S[0:K]+ "...") 


Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k=int(input())
s=input()
if len(s)<=k
    print('s')
else:
  print('s[:k+1]'+'...')
    

k=int(input())
s=input()
if int(len(s))<=k:
  print(s)
else:
  print(s[0:k]+'...')


Verdicts: Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = int(input())
S = input()

if(len(S)<=K):
    print(S)
else:
    print(S[0:K-1] + "...")

K = int(input())
S = input()

if(len(S)<=K):
    print(S)
else:
    print(S[0:k-1] + "...")

K = int(input())
S = input()

if(len(S)<=K):
    print(S)
else:
    print(S[0:K] + "...")


Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k = int(input())
s = input()

print(len(s))
if len(s)<=k: print(s)
else:
    print(s[:k]+'...')

k = int(input())
s = input()

print(len(s))
if len(s)<k: print(s)
else:
    print(s[:7]+'...')

k = int(input())
s = input()

if len(s)<=k: print(s)
else:
    print(s[:k]+'...')

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
N = int(input())
B = str(input())
if N > len(B):
    print(B)
else:
    print(B[:(len(B)-1)] +"...")

N = int(input())
B = str(input())
if N == len(B):
    print(B)
else:
    print(B[:(len(B)-1)] +"...")

N = int(input())
B = str(input())
c = []
if N > len(B):
    print(B)
else:
    c.append(B[:(len(B)-1)] + "...")
    c.append
    print(c)

N = int(input())
B = str(input())
if N == len(B):
    print(B)
else:
    print(B[:(len(B)-1)])

N = int(input())
s = input()
s = s.lower()
ls = []
if len(s) <= N:
    print(s)
else:
    c = s[:N] +"..."
    print(c)

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
# 168 B
K = int(input())
S = input()
if len(str(S)) =< K:
    print(S)
else:
    print(S[:K]+'...')

# 168 B
K = int(input())
S = input()
if len(str(S)) <= K:
    print(S)
else:
    print(S[:K]+'...')

Verdicts: Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K=int(input())
S=input()

s=len(S)

if K<s:
    print(S[0:s+1]+"...")
if s<=K:
    print(S)

K=int(input())
S=input()


if len(S)<=K:
    print(S)

else:
    print(S[0:K]+"...")


Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k=int(input())
s=input()
import numpy as np
p=list(s)
l=len(p)
if l<=k:
  print(s)
else:
  arr=np.array(p)
  print(p+'...')

k=int(input())
s=input()
import numpy as np
p=list(s)
l=len(p)
if l<=k:
  print(s)
else:
  arr=np.array(p)
  arr=arr[0:k]
  print(''.join(list(arr))+'...')

Verdicts: Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k=int(input())
s=input()
if len(s)<=k:
    print(s)
else:
    print(s[1:k+1]+"...")


k=int(input())
s=input()
if len(s)<=k:
    print(s)
else:
    print(s[0:k]+"...")


Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
def main():
    K = int(input())
    S = input()
    print(S[:K])

if __name__ == '__main__':
    main()

def main():
    K = int(input())
    S = input()

    if(len(S) <= K):
        print(S)
    else:
        print(S[:K]  + '...')

if __name__ == '__main__':
    main()

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
n=int(input())
K=input()
if len(k)<=n:
  print(k)
else:
  a=k[0:n+1]
  print(a+"...")

n=int(input())
k=input()
if len(k)<=n:
  print(k)
else:
  a=k[0:n+1]
  print(a+"...")

n=int(input())
k=input()
if len(k)<=n:
  print(k)
else:
  a=k[:n]
  print(a+"...")

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k, s = int(input()), input()
print(s[::k] + "..." if len(s) > k else s)

k, s = int(input()), input()
print(s[:k] + "..." if len(s) > k else s)

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K=int(input())
S=input()

def printt(S,K):
	if len(S)<=K:
      print(S)
    else:
      print(s[:k]+'...')
      
printt(S,K)

K=int(input())
S=input()
 
def printt(S,K):
  if len(S)<=K:
    print(S)
  else:
    print(S[:K]+'...')
      
printt(S,K)


Verdicts: Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
n=int(input())
s=input()
if len(s)>n:
    nl=s[0:n]
    print(nl,'...')
else:
    print(s)

n=int(input())
s=input()
nl=s[0:n]
print(nl,'...')

n=int(input())
s=input()
if len(s)>n:
    nl=s[0:n]
    print(nl+'...')
else:
    print(s)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K = int(input())
s = input()

if len(s) < K:
  print(s)
else:
  print(s[:K])
  

K = int(input())
s = input()

if len(s) <= K:
  print(s)
else:
  print(s[:K] + '...')
  

Verdicts: Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
K=input()
S=input()

len_S=len(S)

if K<=len_S:
  print(S)
  
else:
  print(S[K:], "...")

K=int(input())
S=str(input())


if K>=len(S):
  print(S)
  
else:
  print(S[:K]+ "...")



Verdicts: Runtime Error

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
n = int(input())
s = input()
len1 = len(s)
print(len1)
if(len1>=n):
    print(s[0:n]+"...")
else:
    print(s)

n = int(input())
s = input()
len1 = len(s)
print(len1)
if(len1>n):
    print(s[0:n]+"...")
else:
    print(s)

k = int(input())
s = input()
len1 = len(s)
if(len1>k):
    print(s[0:k]+"...")
else:
    print(s)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have a string S consisting of lowercase English letters.  If the length of S is at most K, print S without change.  If the length of S exceeds K, extract the first K characters in S, append `...` to the end of them, and print the result.

Submission attempts (in order):
k = int(input())
s = input()
print(len(s))

if len(s) > k:
  print(s[:k] + '...')
else:
  print(s)

s = int(input())
k = input()

if s < len(k):
  print(k + '...')
else:
  print(k)

s = int(input())
k = input()

if s <= len(k):
  print(k + '...')
else:
  print(k)

k = int(input())
s = input()

if len(s) > k:
  print(s[:k] + '...')
else:
  print(s)

Verdicts: Wrong Answer

Wrong Answer

Wrong Answer

Accepted