TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
a = [list(map(int, input().split())) for _ in range(3)]
    n = int(input())
    b = [int(input()) for i in range(n)]
    ai = [[1]*3 for _ in range(3)]
    for i in range(3):
        for j in range(3):
            if a[i][j] in b:
                ai[i][j] = 0
    ans = "No"
    for k in range(3):
        if sum(ai[k])== 0:
            ans = "Yes"
    for l in range(3):
        if ai[0][k]+ai[1][k]+ai[2][k] == 0:
            ans = "Yes"
    if ai[0][0]+ai[1][1]+ai[2][2] == 0 or ai[0][2]+ai[2][0]+ai[1][1] == 0:
        ans = "Yes"
    print(ans)

c = list(map(int,input().split())) + list(map(int,input().split())) + list(map(int,input().split()))
n = int(input())
d = [0]*9
for i in range(n):
    m = int(input())
    for j in range(9):
        if c[j] == m:
            d[j] = 1
if (d[0],d[1],d[2]) == (1,1,1) or (d[3],d[4],d[5]) == (1,1,1) or (d[6],d[7],d[8]) == (1,1,1)\
    or (d[0],d[3],d[6]) == (1,1,1) or (d[1],d[4],d[7]) == (1,1,1) or (d[2],d[5],d[8]) == (1,1,1)\
        or (d[0],d[4],d[8]) == (1,1,1) or (d[2],d[4],d[6]) == (1,1,1):
        print("Yes")
else:
    print("No")

Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
A = [0]*3
for i in range(0,3):
    A[i] = list(map(int, input().split()))
N = int(input())
b = [int(input()) for i in range(N)]

count = 0
while count < N:
    for i in range(0,3):
      for j in range(0,3):
        if b[count] == A[i][j]:
          A[i][j] = 0
    count += 1
            
print(A)
sum_y = [0]*3                
for i in range(0,3):
  for j in range(0,3):
    sum_y[i] += A[i][j]

sum_t = [0]*3
for i in range(0,3):
  for j in range(0,3):
    sum_t[i] += A[j][i]
    

sum1 = A[0][0] + A[1][1] + A[2][2]
sum2 = A[0][2] + A[1][1] + A[0][2]

if sum_y[0] == 0:
    print("Yes")
elif sum_y[1] == 0:
    print("Yes")
elif sum_y[2] == 0:
    print("Yes")
elif sum_t[0] == 0:
    print("Yes") 
elif sum_t[1] == 0:
    print("Yes") 
elif sum_t[2] == 0:
    print("Yes") 
elif sum1 == 0:
  print("Yes")
elif sum2 == 0:
  print("Yes")
else:
  print("No")


A = [0]*3
for i in range(0,3):
    A[i] = list(map(int, input().split()))
N = int(input())
b = [int(input()) for i in range(N)]
 
count = 0
while count < N:
    for i in range(0,3):
      for j in range(0,3):
        if b[count] == A[i][j]:
          A[i][j] = 0
    count += 1
            

sum_y = [0]*3                
for i in range(0,3):
  for j in range(0,3):
    sum_y[i] += A[i][j]
 
sum_t = [0]*3
for i in range(0,3):
  for j in range(0,3):
    sum_t[i] += A[j][i]
    
 
sum1 = A[0][0] + A[1][1] + A[2][2]
sum2 = A[0][2] + A[1][1] + A[0][2]
 
if sum_y[0] == 0:
    print("Yes")
elif sum_y[1] == 0:
    print("Yes")
elif sum_y[2] == 0:
    print("Yes")
elif sum_t[0] == 0:
    print("Yes") 
elif sum_t[1] == 0:
    print("Yes") 
elif sum_t[2] == 0:
    print("Yes") 
elif sum1 == 0:
  print("Yes")
elif sum2 == 0:
  print("Yes")
else:
  print("No")

Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):

a = list(list(map(int,input().split())) for _ in range(3))

N = int(input())

b = list(int(input()) for _ in range(N))


ax = [[0]*3]*3

for k in range(N):
    for i in range(3):
        for j in range(3):
            if a[i][j] == b[k]:ax[i][j]= 1


for i in range(3):
    xcnt = 0
    ycnt = 0
    for j in range(3):
        if ax[i][j] == 1:xcnt +=1
        if ax[j][i] == 1:ycnt +=1


xxcnt = 0
for i in range(3):
    if ax[i][i] == 1:xxcnt+=1

for i in range(3):
    if ax[3-i][i] == 1:xycnt+=1

for i in range(3):
    if ax[i][3-i] == 1:yxcnt+=1

if xcnt == 3 or ycnt == 3 or xxcnt == 3 or xycnt == 3 or yxcnt == 3:
    print("Yes")

else:
    print("No")



# -*- coding:utf-8 -*-
A = []
bingo = 0
for i in range(3):
    a = list(map(int, input().split()))
    A.append(a)

n = int(input())

for i in range(n):
    b = int(input())
    for ai in A:
        if b in ai:
            ai[ai.index(b)] = None

for i in range(3):
    if A[i] == [None, None, None]:
        bingo = 1

    if [A[0][i], A[1][i], A[2][i]] == [None, None, None]:
        bingo = 1

if [A[0][0], A[1][1], A[2][2]] == [None, None, None] or [A[0][2], A[1][1], A[2][0]] == [None, None, None]:
    bingo = 1

print("Yes") if bingo == 1 else print("No")


Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
t = [0] * 3
x = [0] * 3
y = [0] * 3
a=[]
for i in range(3):
    t[i], x[i], y[i] = map(int, input().split())
a.append(t)
a.append(x)
a.append(y)
n=int(input())
li=[input() for i in range(n)]

ctr=[[0,0,0],[0,0,0],[0,0,0]]
for i in range(3):
    for j in range(3):
        for k in range(n):
            if int(a[i][j])==int(li[k]):
                ctr[i][j]+=1
print(ctr)
if ctr[0][0]==ctr[0][1]==ctr[0][2]==1:
    print('Yes')
elif ctr[1][0]==ctr[1][1]==ctr[1][2]==1:
    print('Yes')
elif ctr[2][0]==ctr[2][1]==ctr[2][2]==1:
    print('Yes')
elif ctr[0][0]==ctr[1][0]==ctr[2][0]==1:
    print('Yes')
elif ctr[0][1]==ctr[1][1]==ctr[2][1]==1:
    print('Yes')
elif ctr[0][2]==ctr[1][2]==ctr[2][2]==1:
    print('Yes')
elif ctr[0][0]==ctr[1][1]==ctr[2][2]==1:
    print('Yes')
elif ctr[0][2]==ctr[1][1]==ctr[2][0]==1:
    print('Yes')
else:
    print('No')


t = [0] * 3
x = [0] * 3
y = [0] * 3
a=[]
for i in range(3):
    t[i], x[i], y[i] = map(int, input().split())
a.append(t)
a.append(x)
a.append(y)
n=int(input())
li=[input() for i in range(n)]

ctr=[[0,0,0],[0,0,0],[0,0,0]]
for i in range(3):
    for j in range(3):
        for k in range(n):
            if int(a[i][j])==int(li[k]):
                ctr[i][j]+=1
if ctr[0][0]==ctr[0][1]==ctr[0][2]==1:
    print('Yes')
elif ctr[1][0]==ctr[1][1]==ctr[1][2]==1:
    print('Yes')
elif ctr[2][0]==ctr[2][1]==ctr[2][2]==1:
    print('Yes')
elif ctr[0][0]==ctr[1][0]==ctr[2][0]==1:
    print('Yes')
elif ctr[0][1]==ctr[1][1]==ctr[2][1]==1:
    print('Yes')
elif ctr[0][2]==ctr[1][2]==ctr[2][2]==1:
    print('Yes')
elif ctr[0][0]==ctr[1][1]==ctr[2][2]==1:
    print('Yes')
elif ctr[0][2]==ctr[1][1]==ctr[2][0]==1:
    print('Yes')
else:
    print('No')


Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
A = [list(map(int,input().split())) for i in range(3)]
N = int(input())
b = [int(input()) for i in range(N)]

for i in range(3):
    for j in range(3):
        if A[i][j] in b:
            A[i][j] = 0

for i in range(3):
    if A[i][0] == A[i][1] == A[i][2]:
        print("Yes")
        exit(0)
    if A[0][1] == A[1][i] == A[2][i]:
        print("Yes")
        exit(0)

elif A[0][0] == A[1][1] == A[2][2]:
    print("Yes")
elif A[0][2] == A[1][1] == A[2][0]:
    print("Yes")
else:
    print("No")

A = [list(map(int,input().split())) for i in range(3)]
N = int(input())
b = [int(input()) for i in range(N)]

for i in range(3):
    for j in range(3):
        if A[i][j] in b:
            A[i][j] = 0

if A[0][0] == A[1][0] == A[2][0]:
    print("Yes")
elif A[0][0] == A[0][1] == A[0][2]:
    print("Yes")
elif A[0][1] == A[1][1] == A[2][1]:
    print("Yes")
elif A[0][2] == A[1][2] == A[2][2]:
    print("Yes")
elif A[1][0] == A[1][1] == A[1][2]:
    print("Yes")
elif A[2][0] == A[2][1] == A[2][2]:
    print("Yes")
elif A[0][0] == A[1][1] == A[2][2]:
    print("Yes")
elif A[0][2] == A[1][1] == A[2][0]:
    print("Yes")
else:
    print("No")

Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
nums = []

for i in range(3):
    nums.append([int(n) for n in input().split(" ")])
print(nums)

bingo_list = []

bingo_list.extend(nums)
for i in range(3):
    bingo_list.append([nums[0][i], nums[1][i], nums[2][i]])
bingo_list.append([nums[0][0], nums[1][1], nums[2][2]])
bingo_list.append([nums[2][0], nums[1][1], nums[0][2]])

print(bingo_list)

is_bingo = False
n = int(input())
for i in range(n):
    num = int(input())
    for bingo in bingo_list:
        if num in bingo:
            bingo.remove(num)
            if not bingo:
                is_bingo = True

if is_bingo:
    print("Yes")
else:
    print("No")

nums = []

for i in range(3):
    nums.append([int(n) for n in input().split(" ")])
print(nums)

bingo_list = []

bingo_list.extend(nums)
for i in range(3):
    bingo_list.append([nums[0][i], nums[1][i], nums[2][i]])
bingo_list.append([nums[0][0], nums[1][1], nums[2][2]])
bingo_list.append([nums[2][0], nums[1][1], nums[0][2]])

print(bingo_list)

is_bingo = False
n = int(input())
for i in range(n):
    num = int(input())
    for bingo in bingo_list:
        if num in bingo:
            bingo.remove(num)
            if not bingo:
                print("Yes")
                is_bingo = True

if not is_bingo:
    print("No")

nums = []

for i in range(3):
    nums.append([int(n) for n in input().split(" ")])

bingo_list = []

bingo_list.extend(nums)
for i in range(3):
    bingo_list.append([nums[0][i], nums[1][i], nums[2][i]])
bingo_list.append([nums[0][0], nums[1][1], nums[2][2]])
bingo_list.append([nums[2][0], nums[1][1], nums[0][2]])

is_bingo = False
n = int(input())
for i in range(n):
    num = int(input())
    for bingo in bingo_list:
        if num in bingo:
            bingo.remove(num)
            if not bingo:
                is_bingo = True

if is_bingo:
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
a1,a2,a3 = map(int,input().split())
b1,b2,b3 = map(int,input().split())
c1,c2,c3 = map(int,input().split())
N = int(input())
b =  [int(input()) for _ in range(N)]

if a1 and a2 and a3 in b or
    b1 and b2 and b3 in b or
    c1 and c2 and c3 in b or
    a1 and b1 and c1 in b or
    a2 and b2 and c2 in b or
    a3 and b3 and c3 in b or
    a1 and b2 and c3 in b or
    a3 and b2 and c1 in b:
    print('Yes')
else:
    print('No')

A = [list(map(int, input().split())) for _ in range(3)]
N = int(input())
B =  [int(input()) for _ in range(N)]

for b in B:
  if i in range(3):
    for j in range(3):
      if A[i][j] == b:
        A[i][j] = 0

for i in range(3):
  if A[i][0] == A[i][1] == A[i][2] == 0:
    print('Yes')
    exit()

  if A[0][i] == A[1][i] == A[2][i] == 0:
    print('Yes')
    exit()
    
if A[0][0] == A[1][1] == A[2][2] == 0:
    print('Yes')
    exit()
 

if A[0][2] == A[1][1] == A[2][0] == 0:
    print('Yes')
    exit()
    
  
print('No')


A = [list(map(int, input().split())) for _ in range(3)]
N = int(input())
B =  [int(input()) for _ in range(N)]

for b in B:
  for i in range(3):
    for j in range(3):
      if A[i][j] == b:
        A[i][j] = 0

for i in range(3):
  if A[i][0] == A[i][1] == A[i][2] == 0:
    print('Yes')
    exit()

  if A[0][i] == A[1][i] == A[2][i] == 0:
    print('Yes')
    exit()
    
if A[0][0] == A[1][1] == A[2][2] == 0:
    print('Yes')
    exit()
 

if A[0][2] == A[1][1] == A[2][0] == 0:
    print('Yes')
    exit()
    
  
print('No')


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
import sys
A = [list(map(int,input().split())) for i in range(3)]
N = int(input())
b = [int(input()) for i in range(N)]
ans_flag = True
ans_flag2 = True
ans = [[False, False, False], [False, False, False], [False, False, False]]

for i in range(3):
    for j in range(3):
        if A[i][j] in b:
            ans[i][j] = True

for i in range(3):
    if ans[0][i] and ans[1][i] and ans[2][i]:
        print('Yes')
        sys.exit()
    if ans[i][0] and ans[i][1] and ans[i][2]:
        print('Yes')
        sys.exit()
    if not ans[i][i]:
        ans_flag = False
    if not ans[i][2-i]:
        ans_flag2 = False

print(ans)

if ans_flag or ans_flag2:
    print('Yes')
else:
    print('No')

import sys
A = [list(map(int,input().split())) for i in range(3)]
N = int(input())
b = [int(input()) for i in range(N)]
ans_flag = True
ans = [[False, False, False], [False, False, False], [False, False, False]]

for i in range(3):
    for j in range(3):
        if A[i][j] in b:
            ans[i][j] = True

print(ans)

for i in range(3):
    if ans[0][i] and ans[1][i] and ans[2][i]:
        print('Yes')
        sys.exit()
    if ans[i][0] and ans[i][1] and ans[i][2]:
        print('Yes')
        sys.exit()
    if not ans[i][i]:
        ans_flag = False

if ans_flag:
    print('Yes')
else:
    print('No')

import sys
A = [list(map(int,input().split())) for i in range(3)]
N = int(input())
b = [int(input()) for i in range(N)]
ans_flag = True
ans_flag2 = True
ans = [[False, False, False], [False, False, False], [False, False, False]]

for i in range(3):
    for j in range(3):
        if A[i][j] in b:
            ans[i][j] = True

for i in range(3):
    if ans[0][i] and ans[1][i] and ans[2][i]:
        print('Yes')
        sys.exit()
    if ans[i][0] and ans[i][1] and ans[i][2]:
        print('Yes')
        sys.exit()
    if not ans[i][i]:
        ans_flag = False
    if not ans[i][2-i]:
        ans_flag2 = False

if ans_flag or ans_flag2:
    print('Yes')
else:
    print('No')

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
a = [list(map(int, input().split())) for i in range(3)]
N = int(input())
b = [int(input()) for i in range(N)]

a = np.array(a)
b = np.array(b)

after = np.zeros((3,3))
for i in range(N):
    after += a == b[i]
    
bool1 = (np.sum(after, axis=0)==3).sum()
bool2 = (np.sum(after, axis=1)==3).sum()
bool3 = (after[0,0]+after[1,1]+after[2,2])==3
bool4 = (after[0,2]+after[1,1]+after[2,0])==3

if bool1+bool2+bool3+bool4>0:
    ans = 'Yes'
else:
    ans = 'No'
    
print(ans)

import numpy as np

a = [list(map(int, input().split())) for i in range(3)]
N = int(input())
b = [int(input()) for i in range(N)]

a = np.array(a)
b = np.array(b)

after = np.zeros((3,3))
for i in range(N):
    after += a == b[i]
    
bool1 = (np.sum(after, axis=0)==3).sum()
bool2 = (np.sum(after, axis=1)==3).sum()
bool3 = (after[0,0]+after[1,1]+after[2,2])==3
bool4 = (after[0,2]+after[1,1]+after[2,0])==3

if bool1+bool2+bool3+bool4>0:
    ans = 'Yes'
else:
    ans = 'No'
    
print(ans)

Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
A = list(map(int, input().split()))
B = list(map(int, input().split()))
C = list(map(int, input().split()))
X = A + B + C
N = int(input())
L = []
for i in range (N):
  K = int(input())
  L.append(K)
ck = 'No'
if A[1] in L and A[2]in L and A[3] in L:
  ck == 'Yes'
elif B[1] in L and B[2]in L and B[3] in L:
  ck == 'Yes'
elif C[1] in L and C[2]in L and C[3] in L:
  ck == 'Yes'
elif A[1] in L and B[1]in L and C[1] in L:
  ck == 'Yes'
elif A[2] in L and B[2]in L and C[2] in L:
  ck == 'Yes'
elif A[3] in L and B[3]in L and C[3] in L:
  ck == 'Yes'
elif A[1] in L and B[2] in L and C[3] in L:
  ck = 'Yes'
elif A[3] in L and B[2] in L and C[1] in L:
  ck = 'Yes'
print(ck)

A = list(map(int, input().split()))
B = list(map(int, input().split()))
C = list(map(int, input().split()))
X = A + B + C
N = int(input())
L = []
for i in range (N):
  K = int(input())
  L.append(K)
ck = 'No'
if A[0] in L and A[1]in L and A[2] in L:
  ck = 'Yes'
elif B[0] in L and B[1]in L and B[2] in L:
  ck = 'Yes'
elif C[0] in L and C[1]in L and C[2] in L:
  ck = 'Yes'
elif A[0] in L and B[0]in L and C[0] in L:
  ck = 'Yes'
elif A[1] in L and B[1]in L and C[1] in L:
  ck = 'Yes'
elif A[2] in L and B[2]in L and C[2] in L:
  ck = 'Yes'
elif A[0] in L and B[1] in L and C[2] in L:
  ck = 'Yes'
elif A[2] in L and B[1] in L and C[0] in L:
  ck = 'Yes'
print(ck)

Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
yoko_1 = [int(i) for i in input().split()]
yoko_2 = [int(i) for i in input().split()]
yoko_3 = [int(i) for i in input().split()]
tate_1 = [yoko_1[0], yoko_2[0], yoko_3[0]]
tate_2 = [yoko_1[1], yoko_2[1], yoko_3[1]]
tate_3 = [yoko_1[2], yoko_2[2], yoko_3[2]]
naname_1 = [yoko_1[0], yoko_2[1], yoko_3[2]]
naname_2 = [yoko_1[2], yoko_2[1], yoko_3[0]]

n = int(input())
bs = [int(input()) for i in range(n)]

def bingo(card, call):
    cnt = 0
    for i in card:
        for j in call:
            if i == j:
                cnt += 1
                break
    if cnt == 3:
        return 1
    else:
        return 0

if bingo(yoko_1, bs) + \
bingo(yoko_2, bs) + \
bingo(yoko_3, bs) + \
bingo(tate_1, bs) + \
bingo(tate_2, bs) + \
bingo(tate_3, bs) + \
bingo(naname_2, bs) + \
bingo(naname_2, bs) > 0:
    print("Yes")
else:
    print("No")

# coding: utf-8
# Your code here!

yoko_1 = [int(i) for i in input().split()]
yoko_2 = [int(i) for i in input().split()]
yoko_3 = [int(i) for i in input().split()]
tate_1 = [yoko_1[0], yoko_2[0], yoko_3[0]]
tate_2 = [yoko_1[1], yoko_2[1], yoko_3[1]]
tate_3 = [yoko_1[2], yoko_2[2], yoko_3[2]]
naname_1 = [yoko_1[0], yoko_2[1], yoko_3[2]]
naname_2 = [yoko_1[2], yoko_2[1], yoko_3[0]]

n = int(input())
bs = [int(input()) for i in range(n)]

def bingo(card, call):
    cnt = 0
    for i in card:
        for j in call:
            if i == j:
                cnt += 1
                break
    if cnt == 3:
        return 1
    else:
        return 0

if bingo(yoko_1, bs) + \
bingo(yoko_2, bs) + \
bingo(yoko_3, bs) + \
bingo(tate_1, bs) + \
bingo(tate_2, bs) + \
bingo(tate_3, bs) + \
bingo(naname_1, bs) + \
bingo(naname_2, bs) > 0:
    print("Yes")
else:
    print("No")

# print(bingo(yoko_1, bs))
    



Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
A1 = list(map(int,input().split()))
A2 = list(map(int,input().split()))
A3 = list(map(int,input().split()))
N = int(input())
b_list=[]
for i in range(N):
  b_list.append(int(input))

for i in b_list:
  A1 = [x in A1 if x != i else -1]
  A2 = [y in A2 if y != i else -1]
  A3 = [z in A3 if z != i else -1]

if sum(A1)==-3 or sum(A2)==-3 or sum(A3)==-3:
  print('Yes')
  exit()
for t in range(3)
  if A1[t]+A2[t]+A3[t] == -3:
    print('Yes')
    exit()
if A1[0]+A2[1]+A3[2] == -3 or A1[2]+A2[1]+A3[0] == -3:
  print('Yes')
  exit()
print('No')

import sys
A1 = list(map(int,input().split()))
A2 = list(map(int,input().split()))
A3 = list(map(int,input().split()))
N = int(input())
b_list=[]
for i in range(N):
  b_list.append(int(input()))
 
for i in b_list:
  A1 = [x if x != i else -1 for x in A1]
  A2 = [y if y != i else -1 for y in A2]
  A3 = [z if z != i else -1 for z in A3]
 
if sum(A1)==-3 or sum(A2)==-3 or sum(A3)==-3:
  print('Yes')
  sys.exit()
for t in range(3):
  if A1[t]+A2[t]+A3[t] == -3:
    print('Yes')
    sys.exit()
if A1[0]+A2[1]+A3[2] == -3 or A1[2]+A2[1]+A3[0] == -3:
  print('Yes')
  sys.exit()
print('No')

Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
A=[]
for i in range(3):
    A.extend(list(map(int, input().split())))
N = int(input())
n=[]
while N>0:
    inp = int(input())
    if inp in A:
        n.append(inp)
    N-=1
A = [A[:3],A[3:6],A[6:9], [A[0], A[4], A[8]], [A[2], A[4], A[6]], [A[0], A[3], A[6]], [A[1], A[4], A[7]], [A[2], A[5], A[8]]]
for ele in A:
    if ele[0] in n and ele[1]in n and ele[2]in n:
        print ("Yes")
print ("No")

def bingo():    
    A=[]
    for i in range(3):
        A.extend(list(map(int, input().split())))
    N = int(input())
    n=[]
    while N>0:
        inp = int(input())
        if inp in A:
            n.append(inp)
        N-=1
    A = [A[:3],A[3:6],A[6:9], [A[0], A[4], A[8]], [A[2], A[4], A[6]], [A[0], A[3], A[6]], [A[1], A[4], A[7]], [A[2], A[5], A[8]]]
    for ele in A:
        if ele[0] in n and ele[1]in n and ele[2]in n:
            return 'Yes'
    return 'No'
print(bingo())

Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
import numpy as np

A = []
for _ in range(3):
    A.append([int(x) for x in input().split()])
A = np.array(A)
R = np.zeros((3,3))
N = int(input())
B = []

for _ in range(N):
    b = int(input())
    x, y = np.where(A == b)
    if len(x) > 0:
        for i in range(len(x)):
            R[x[i], y[i]] = 1


row1 = (np.sum(R, axis=1) > 3).sum()
row2 = (np.sum(R, axis=0) > 3).sum()


c1 = R[0][0] + R[1][1] + R[2][2]
c2 = R[0][2] + R[1][1] + R[2][0]

if row1 > 0 or row2 > 0 or c1 > 3 or c2 > 3:
    print('Yes')
else:
    print('No')


import numpy as np

A = []
for _ in range(3):
    A.append([int(x) for x in input().split()])
A = np.array(A)
R = np.zeros((3,3))
N = int(input())
B = []

for _ in range(N):
    b = int(input())
    x, y = np.where(A == b)
    if len(x) > 0:
        for i in range(len(x)):
            R[x[i], y[i]] = 1


row1 = np.sum(R, axis=1).sum()
row2 = np.sum(R, axis=0).sum()


c1 = R[0][0] + R[1][1] + R[2][2]
c2 = R[0][2] + R[1][1] + R[2][0]
print(R)
if row1 > 0 or row2 > 0 or c1 > 3 or c2 > 3:
    print('Yes')
else:
    print('No')




import numpy as np

A = []
for _ in range(3):
    A.append([int(x) for x in input().split()])
A = np.array(A)
R = np.zeros((3,3))
N = int(input())
B = []

for _ in range(N):
    b = int(input())
    x, y = np.where(A == b)
    if len(x) > 0:
        for i in range(len(x)):
            R[x[i], y[i]] = 1


row1 = (np.sum(R, axis=1) >= 3).sum()
row2 = (np.sum(R, axis=0) >= 3).sum()

c1 = R[0][0] + R[1][1] + R[2][2]
c2 = R[0][2] + R[1][1] + R[2][0]
if row1 > 0 or row2 > 0 or c1 >= 3 or c2 >= 3:
    print('Yes')
else:
    print('No')

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
import numpy as np
S = np.array([list(map(int, input().split())) for _ in range(3)])
n = int(input())
for _ in range(n):
    S = np.where(S==int(input()), 0, S)
if min(np.sum(S, axis=0))==0 or min(np.sum(S, axis=1))==0:
    print('Yes')
    exit()
if (S[0][0] == 0 and S[1][1] == 0 and S[2][2]) or (S[2][0] == 0 and S[1][1] == 0 and S[0][2]):
    print('Yes')
    exit()
print('No')

import numpy as np
S = np.array([list(map(int, input().split())) for _ in range(3)])
n = int(input())
for _ in range(n):
    S = np.where(S==int(input()), 0, S)
    HBingo = min(np.sum(S, axis=0)) == 0
    WBingo = min(np.sum(S, axis=1)) == 0
    SBingo = S[2][0] == 0 and S[1][1] == 0 and S[0][2] == 0
    BSBingo = S[0][0] == 0 and S[1][1] == 0 and S[2][2] == 0
if HBingo or WBingo or SBingo or BSBingo:
    print('Yes')
    exit()
print('No')

Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
def get(A, ar, ac):
    if ar > 2 or ar < -2 or ac > 2 or ar < -2:
        return 0
    return A[ar][ac]

def check(A, ar, ac):
    if 0 == get(A, ar-1, ac-1) and 0 == get(A, ar-2, ac-2) and 0 == get(A, ar+1, ac+1) and 0 == get(A, ar+2, ac+2):
        return True
    if 0 == get(A, ar+1, ac-1) and 0 == get(A, ar+2, ac-2) and 0 == get(A, ar-1, ac+1) and 0 == get(A, ar-2, ac+2):
        return True
    if 0 == get(A, ar+1, ac) and 0 == get(A, ar+2, ac) and 0 == get(A, ar-1, ac) and 0 == get(A, ar-2, ac):
        return True
    if 0 == get(A, ar, ac+1) and 0 == get(A, ar, ac+2) and 0 == get(A, ar, ac-1) and 0 == get(A, ar, ac-2):
        return True
    return False

A = [[0 for i in range(3)] for i in range(3)]
for i in range(3):
    A[i] = list(map(int, input().split()))
N = int(input())
for n in range(N):
    b = int(input())
    for ar in range(3):
        for ac in range(3):
            if A[ar][ac] == b:
                A[ar][ac] = 0
                if check(A, ar, ac):
                    print("Yes")
                    print(A)
                    import sys
                    sys.exit(0)
                continue
print("No")
print(A)


def get(A, ar, ac):
    if ar > 2 or ar < 0 or ac > 2 or ac < 0:
        return 0
    if A[ar][ac] == 0:
        return 1
    return 0

def check(A, ar, ac):
    
    if 2 == get(A, ar-1, ac-1) + get(A, ar-2, ac-2) + get(A, ar+1, ac+1) + get(A, ar+2, ac+2):
        return True
    if 2 == get(A, ar+1, ac-1) + get(A, ar+2, ac-2) + get(A, ar-1, ac+1) + get(A, ar-2, ac+2):
        return True
    if 2 == get(A, ar+1, ac) + get(A, ar+2, ac) + get(A, ar-1, ac) + get(A, ar-2, ac):
        return True
    if 2 == get(A, ar, ac+1) + get(A, ar, ac+2) + get(A, ar, ac-1) + get(A, ar, ac-2):
        return True
    return False

A = [[0 for i in range(3)] for i in range(3)]
for i in range(3):
    A[i] = list(map(int, input().split()))
N = int(input())
for n in range(N):
    b = int(input())
    for ar in range(3):
        for ac in range(3):
            if A[ar][ac] == b:
                A[ar][ac] = 0
                if check(A, ar, ac):
                    print("Yes")
                    # print(A)
                    import sys
                    sys.exit(0)
                continue
print("No")
# print(A)


Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
import numpy as np

a = []
ans = 'No'

a.append(list(map(int,input().split())))
a.append(list(map(int,input().split())))
a.append(list(map(int,input().split())))

n = int(input())

for i in range(n):
  d = int(input())
  for j in range(3):
    for k in range(3):
      if a[j][k] == n:
        a[j][k] = 0

if a[0][0] == a[1][0] == a[2][0]:
  ans = 'Yes'
elif a[0][1] == a[1][1] == a[2][1]:
  ans = 'Yes'
elif a[0][2] == a[1][2] == a[2][2]:
  ans = 'Yes'
elif a[0][0] == a[0][1] == a[0][2]:
  ans = 'Yes'
elif a[1][0] == a[1][1] == a[1][2]:
  ans = 'Yes'
elif a[2][0] == a[2][1] == a[2][2]:
  ans = 'Yes'
elif a[0][0] == a[1][1] == a[2][2]:
  ans = 'Yes'
elif a[2][0] == a[1][1] == a[0][2]:
  ans = 'Yes'

print(ans)

import numpy as np

a = []
ans = 'No'

a.append(list(map(int,input().split())))
a.append(list(map(int,input().split())))
a.append(list(map(int,input().split())))

n = int(input())

for i in range(n):
  d = int(input())
  for j in range(3):
    for k in range(3):
      if a[j][k] == d:
        a[j][k] = 0

if a[0][0] == a[1][0] == a[2][0] == 0:
  ans = 'Yes'
elif a[0][1] == a[1][1] == a[2][1] == 0:
  ans = 'Yes'
elif a[0][2] == a[1][2] == a[2][2] == 0:
  ans = 'Yes'
elif a[0][0] == a[0][1] == a[0][2] == 0:
  ans = 'Yes'
elif a[1][0] == a[1][1] == a[1][2] == 0:
  ans = 'Yes'
elif a[2][0] == a[2][1] == a[2][2] == 0:
  ans = 'Yes'
elif a[0][0] == a[1][1] == a[2][2] == 0:
  ans = 'Yes'
elif a[2][0] == a[1][1] == a[0][2] == 0:
  ans = 'Yes'

print(ans)

Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
l=[list(map(int,input().split())) for i in range(3)]
l=sum(l,[])
n=int(input())
li=set([input() for ini in range(n)])
d=[0 for i in range(9)]
for g in range(9):
  if l[g] in li:d[g]=1
if set([1]) in [set(d[h::3])for h in range(3)]+[set(d[h:h+3])for h in range(3)]+[set([d[0],d[4],d[8]]),set([d[2],d[4],d[6]])]:
  print("Yes")
else:print("No")


l=[list(map(int,input().split())) for i in range(3)]
n=int(input())
li=set(input() for ini in range(n))
d=[0 for i in range(9)]
for j in range(3):
  for i in range(3):
    if l[j][i] in li:d[3*j+i]=1
if set(1) in [set(l[h::3])for h in range(3)]+[set(l[h:h+3])for h in range(3)]+[set([l[0],l[4],l[8]]),set([l[2],l[4],l[6]])]:
  print("Yes")
else:print("No")

l=[list(map(int,input().split())) for i in range(3)]
l=sum(l,[])
n=int(input())
li=set([input() for ini in range(n)])
d=[0 for i in range(9)]
for g in range(9):
  if l[g] in li:d[g]=1
for a,s,x in [(0,1,2),(3,4,5),(6,7,8),(0,4,8),(2,4,6),(0,3,6),(1,4,7),(2,5,8)]:
  if d[a]==d[x]==d[s]==1:
    print("Yes");exit()
print("No")

l=[list(map(int,input().split())) for i in range(3)]
l=sum(l,[])
n=int(input())
li=set([input() for ini in range(n)])
d=[0 for i in range(9)]
for g in range(9):
  if l[g] in li:d[g]=1
if set([1]) in [set(d[h::3])for h in range(3)]+[set(d[h:h+3])for h in {0,3,6}]+[set([d[0],d[4],d[8]]),set([d[2],d[4],d[6]])]:
  print("Yes")
else:print("No")


l=[list(map(int,input().split())) for i in range(3)]
l=sum(l,[])
n=int(input())
li=set([int(input()) for ini in range(n)])
d=[0 for i in range(9)]
for g in range(9):
  if l[g] in li:d[g]=1

for a,s,x in [(0,1,2),(3,4,5),(6,7,8),(0,4,8),(2,4,6),(0,3,6),(1,4,7),(2,5,8)]:
  if d[a]==d[x]==d[s]==1:
    print("Yes");exit()
print("No")


Verdicts: Wrong Answer

Runtime Error

Wrong Answer

Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
#include <bits/stdc++.h>
using namespace std;
void print() {
    cout << endl;
}
template <class Head, class... Tail>
void print(Head &&head, Tail &&... tail) {
    cout << head;
    if (sizeof...(tail) != 0)
        cout << " ";
    print(forward<Tail>(tail)...);
}
template <class T>
void print(vector<T> &vec) {
    for (auto &a : vec) {
        cout << a;
        if (&a != &vec.back())
            cout << " ";
    }
    cout << endl;
}
template <class T>
void print(vector<vector<T>> &df) {
    for (auto &vec : df) {
        print(vec);
    }
}


using ll = long long;
const int INF = 100100100;

vector<vector<int>> A(3);

bool bingo(vector<int> B) {
    int cnt1 = 0;
    for(int b: B) {
        rep(y, 3) {
            rep(x, 3) {
                if(A[y][x]==b) {
                    ++cnt1;
                }
            }
        }
    }
    if(cnt1==3) return true;
    int cnt2 = 0;
    for(int b: B) {
        rep(y, 3) {
            rep(x, 3) {
                if(A[x][y]==b) {
                    ++cnt2;
                }
            }
        }
    }
    if(cnt2==3) return true;
    int cnt3 = 0;
    for(int b: B) {
        rep(i, 3) {
            if(b==A[i][i]) ++cnt3;
        }
    }
    if(cnt3==3) {
        return true;
    }

    int cnt4 = 0;
    for(int b: B) {
        rep(i, 3) {
            if(b==A[2-i][i]) ++cnt4;
        }
    }
    if(cnt4==3) {
        return true;
    }
    return false; 
}

int main() {
    vector<int> row(3);
    rep(i, 3) {
        rep(j, 3) {
            cin >> row[j];
        }
        A[i] = row;
    }
    int N;
    cin >> N;
    vector<int> B(N);
    rep(i, N) {
        cin >> B[i];
    }

    bool flag = bingo(B);

    if(flag) {
        print("Yes");
    }
    else {
        print("No");
    }



    return 0;
}

if __name__ == '__main__':
    A = []
    for i in range(3):
        row = list(map(int, input().split()))
        A.append(row)
    
    N = int(input())
    B = []

    for i in range(N):
        B.append(int(input())) 
    
    for i in range(3):
        cnt = 0
        for j in range(3):
            if A[i][j] in B:
                cnt += 1
        if cnt==3:
            print('Yes')
            quit()
            
    for i in range(3):
        cnt = 0
        for j in range(3):
            if A[j][i] in B:
                cnt += 1
        if cnt==3:
            print('Yes')
            quit()

    if A[0][0] in B and A[1][1] in B and A[2][2] in B:
        print('Yes')
        quit()
    
    if A[0][2] in B and A[1][1] in B and A[2][0] in B:
        print('Yes')
        quit()
    
    print('No')

Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
#!/usr/bin/env python

a = []
a.append([int(i) for i in input().split()])
a.append([int(i) for i in input().split()])
a.append([int(i) for i in input().split()])
n = int(input())
c = [[0,0,0],[0,0,0],[0,0,0]]
for i in range(n):
    b = int(input())
    for j in range(3):
        for k in range(3):
            if a[j][k] == b:
                c[j][k] = 1

print(c)
flag = False

for i in range(3):
    if c[0][i] + c[1][i] + c[2][i] == 3 and flag == False:
        print("Yes")
        flag = True
        break
    if c[i][0] + c[i][1] + c[i][2] == 3 and flag == False:
        print("Yes")
        flag = True
        break
    if c[i%3][0] + c[(i+1)%3][1] + c[(i+2)%3][2] == 3 and flag == False:
        print("Yes")
        flag = True
        break


#!/usr/bin/env python

a = []
a.append([int(i) for i in input().split()])
a.append([int(i) for i in input().split()])
a.append([int(i) for i in input().split()])
n = int(input())
c = [[0,0,0],[0,0,0],[0,0,0]]

for i in range(n):
    b = int(input())
    for j in range(3):
        for k in range(3):
            if a[j][k] == b:
                c[j][k] = 1

flag = False

for i in range(3):
    if c[0][i] + c[1][i] + c[2][i] == 3 and flag == False:
        print("Yes")
        flag = True
        break
        
    if c[i][0] + c[i][1] + c[i][2] == 3 and flag == False:
        print("Yes")
        flag = True
        break

    """
    if c[i%3][0] + c[(i+1)%3][1] + c[(i+2)%3][2] == 3 and flag == False:
        print("Yes")
        flag = True
        break
    """
    if c[0][0] + c[1][1] + c[2][2] == 3 and flag == False:
        print("Yes")
        flag = True
        break

    if c[0][2] + c[1][1] + c[2][0] == 3 and flag == False:
        print("Yes")
        flag = True
        break

if flag == False:
    print("No")

Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
import sys
import numpy as np

bingo_list = np.array([list(map(int, input().split())) for _ in range(3)])
N = int(input())
n = [int(input()) for _ in range(N)]

A = np.array([[41,7,46],[26,89,2],[78,92,8]])

for i in range(3):
    for j in range(N):
        if A[i,0] == n[j]:
            for k in range(N):
                if A[i,1] == n[k]:
                    for l in range(N):
                        if A[i,2] == n[l]:
                            print('Yes')
                            sys.exit()

for j in range(N):
    if A[0,0] == n[j]:
        for k in range(N):
            if A[1,1] == n[k]:
                for l in range(N):
                    if A[2,2] == n[l]:
                        print('Yes')
                        sys.exit()

for j in range(N):
    if A[2,0] == n[j]:
        for k in range(N):
            if A[1,1] == n[k]:
                for l in range(N):
                    if A[2,0] == n[l]:
                        print('Yes')
                        sys.exit()

print('No')


import sys
import numpy as np

A = [list(map(int, input().split())) for _ in range(3)]
N = int(input())
n = [int(input()) for _ in range(N)]

for i in range(3):
    for j in range(N):
        if A[i][0] == n[j]:
            for k in range(N):
                if A[i][1] == n[k]:
                    for l in range(N):
                        if A[i][2] == n[l]:
                            print('Yes')
                            sys.exit()

for i in range(3):
    for j in range(N):
        if A[0][i] == n[j]:
            for k in range(N):
                if A[1][i] == n[k]:
                    for l in range(N):
                        if A[2][i] == n[l]:
                            print('Yes')
                            sys.exit()

for j in range(N):
    if A[0][0] == n[j]:
        for k in range(N):
            if A[1][1] == n[k]:
                for l in range(N):
                    if A[2][2] == n[l]:
                        print('Yes')
                        sys.exit()

for j in range(N):
    if A[2][0] == n[j]:
        for k in range(N):
            if A[1][1] == n[k]:
                for l in range(N):
                    if A[2][0] == n[l]:
                        print('Yes')
                        sys.exit()

print('No')


Verdicts: Wrong Answer

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
a = [list(map(int, input().split())) for _ in range(3)]
is_bingo = [[False]*3 for _ in range(3)]
n = int(input())
for _ in range(n):
    b = int(input())
    for i, ai in enumerate(a):
        for j, aii in enumerate(ai):
            if aii == b:
                is_bingo[i][j] = True
is_bingo_flat = [j for i in is_bingo for j in i]
for i in range(3):
    if all(is_bingo[i]) or all(list(zip(*is_bingo))[i]):
        print("Yes")
        break
else:
    if all(is_bingo_flat[::3]) or all(is_bingo_flat[2:7::2]):
        print("Yes")
    print("No")

        

a = [list(map(int, input().split())) for _ in range(3)]
is_bingo = [[False]*3 for _ in range(3)]
n = int(input())
for _ in range(n):
    b = int(input())
    for i, ai in enumerate(a):
        for j, aii in enumerate(ai):
            if aii == b:
                is_bingo[i][j] = True
is_bingo_flat = [j for i in is_bingo for j in i]
for i in range(3):
    if all(is_bingo[i]) or all(list(zip(*is_bingo))[i]):
        print("Yes")
        break
else:
    if all(is_bingo_flat[::4]) or all(is_bingo_flat[2:7:2]):
        print("Yes")
    else:
        print("No")

        

Verdicts: Runtime Error

Accepted
Problem: We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.  The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.  Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Submission attempts (in order):
array= []
for i in range(3):
    array.append(list(map(int,input().split())))
n= int(input())
number=[]
answer = "No"
for i in range(n):
    number.append(input())

for i in range (3):
    for j in range(3):
        for k in range(n):
            print(array[i][j])
            print(number[k])
            if int(array[i][j]) == int(number[k]):
                array[i][j] = 8101919

for i in range (3):
    if array[i][0] & array[i][1] & array[i][2] == 8101919:        
        answer = "Yes"

for i in range(3):
    if array[0][i] & array[1][i] & array[2][i] == 8101919:
        answer = "Yes"

if array[0][0] & array[1][1] & array[2][2] == 8101919:
    answer = "Yes"
           
if array[2][0] & array[1][1] & array [0][2] == 8101919:
    answer = "Yes"

print(answer)

array= []
for i in range(3):
    array.append(list(map(int,input().split())))
n= int(input())
number=[]
answer = "No"
for i in range(n):
    number.append(input())

for i in range (3):
    for j in range(3):
        for k in range(n):
            if int(array[i][j]) == int(number[k]):
                array[i][j] = 8101919

for i in range (3):
    if array[i][0] & array[i][1] & array[i][2] == 8101919:        
        answer = "Yes"

for i in range(3):
    if array[0][i] & array[1][i] & array[2][i] == 8101919:
        answer = "Yes"

if array[0][0] & array[1][1] & array[2][2] == 8101919:
    answer = "Yes"
           
if array[2][0] & array[1][1] & array [0][2] == 8101919:
    answer = "Yes"

print(answer)

Verdicts: Wrong Answer

Accepted