TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
n=int(input())
if n<100:
  print(n)
elif 100 <= n < 10000:
  print(n-90)
elif 10000 <= n < 100000:
  print(n-9090)
elif n==100000:
  print(90909)

n=int(input())
if n<10:
  print(n)
if 10<=n<100:
  print(9)
elif 100 <= n < 1000:
  print(n-90)
elif 1000 <= n < 10000:
  print(909)
elif 10000 <= n < 100000:
  print(n-9090)
elif n==100000:
  print(90909)

Verdicts: Wrong Answer

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
#<B>
N = input()
ans = 0
for i in range(1, int(N + 1)):
    if len(str(i)) % 2 != 0:
        ans += 1

print(ans)

#<B>
N = int(input())
ans = 0
for i in range(1, N + 1):
    if len(str(i)) % 2 == 1:
        ans += 1

print(ans)

Verdicts: Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
a = int(input())

if a < 10:
  print(a)
elif a < 100:
  print(9)
elif a < 1000:
  print(a - 90)
elif a < 10000:
  print(910)
elif a < 100000:
  print(a - 90 - 9000)
elif a = 100000:
  print(90909)

a = int(input())

if a < 10:
  print(a)
elif a < 100:
  print(9)
elif a < 1000:
  print(a - 90)
elif a < 10000:
  print(909)
elif a < 100000:
  print(a - 90 - 9000)
elif a == 100000:
  print(90909)


Verdicts: Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
n int(input())
c = 0
for i in range(1, n+1):
  if len(list(str(i))) % 2 != 0:
    c += 1

print(c)

n = int(input())
c = 0
for i in range(1, n+1):
  if len(list(str(i))) % 2 != 0:
    c += 1

print(c)


Verdicts: Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
N = input()
digit = len(N)
num = int(N)

ans = 0
for i in range(1, digit, 2):
        ans += 9 * (10**i)

if digit % 2 == 1:
    ans += num - 10 ** (digit - 1) +1

print(ans)

N = input()
digit = len(N)
num = int(N)

ans = 0
for i in range(1, digit, 2):
        ans += 9 * (10**(i-1))

if digit % 2 == 1:
    ans += num - 10 ** (digit - 1) +1

print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
m=int(input())
ans=0
for i in range(m+1):
  if len(str(i))%2==1:
    ans+=1
print(ans)



m=int(input())
ans=0
for i in range(n+1):
  if len(str(i))%2==1:
    ans+=1
print(ans)



m=int(input())
ans=0
for i in range(1,m+1):
  if len(str(i))%2==1:
    ans+=1
print(ans)




Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
import math
import copy
from copy import deepcopy
import sys
import fractions
# import numpy as np
from functools import reduce
# import statistics
import decimal
import heapq
import collections
import itertools
from operator import mul

sys.setrecursionlimit(100001)


# input = sys.stdin.readline


# ===FUNCTION===

def getInputInt():
    inputNum = int(input())
    return inputNum


def getInputListInt():
    outputData = []
    inputData = input().split()
    outputData = [int(n) for n in inputData]

    return outputData


def getSomeInputInt(n):
    outputDataList = []
    for i in range(n):
        inputData = int(input())
        outputDataList.append(inputData)

    return outputDataList


def getSomeInputListInt(n):
    inputDataList = []
    outputDataList = []
    for i in range(n):
        inputData = input().split()
        inputDataList = [int(n) for n in inputData]
        outputDataList.append(inputDataList)

    return outputDataList


# ===CODE===

n = int(input())

ans = 0
for i in range(n + 1):
    s = str(i)
    if len(s) % 2 == 1:
        ans += 1

print(ans)


import math
import copy
from copy import deepcopy
import sys
import fractions
# import numpy as np
from functools import reduce
# import statistics
import decimal
import heapq
import collections
import itertools
from operator import mul

sys.setrecursionlimit(100001)


# input = sys.stdin.readline


# ===FUNCTION===

def getInputInt():
    inputNum = int(input())
    return inputNum


def getInputListInt():
    outputData = []
    inputData = input().split()
    outputData = [int(n) for n in inputData]

    return outputData


def getSomeInputInt(n):
    outputDataList = []
    for i in range(n):
        inputData = int(input())
        outputDataList.append(inputData)

    return outputDataList


def getSomeInputListInt(n):
    inputDataList = []
    outputDataList = []
    for i in range(n):
        inputData = input().split()
        inputDataList = [int(n) for n in inputData]
        outputDataList.append(inputDataList)

    return outputDataList


# ===CODE===

n = int(input())

ans = 0
for i in range(1, n + 1, 1):
    s = str(i)
    if len(s) % 2 == 1:
        ans += 1

print(ans)


Verdicts: Wrong Answer

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
N = int(input())

count = 0
for i in range(1,N+1):
  Nstr = str(N)
  if len(Nstr) % 2 == 1:
  	count += 1
print(count)


N = int(input())

count = 0
for i in range(1,N+1):
  istr = str(i)
  if len(istr) % 2 == 1:
  	count += 1
print(count)


Verdicts: Wrong Answer

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
n = input()
digit = len(str(n))

count = -1
for i in range(digit - 1):
  if (i + 1) % 2 == 1:
    count += 10 ** i

if digit % 2 == 1:
  count += n - 10 ** (digit - 1)

print(count)

n = int(input())
digit = len(str(n))

count = 0
for i in range(digit - 1):
  if (i + 1) % 2 == 1:
    count += 10 ** (i + 1) - (10 ** i)

if digit % 2 == 1:
  count += n - 10 ** (digit - 1) + 1

print(count)

Verdicts: Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
N = int(input())
ans = 0 
for i in range(1, N+1):
  if len(str(N)) % 2 ==1:
    ans += 1
print(ans)
  
  


N = int(input())
ans = 0 
for i in range(1, N+1):
  if len(str(i)) % 2 ==1:
    ans += 1
print(ans)
  
  


Verdicts: Wrong Answer

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
n=int(input())
ans=0
for i in range(1,n+1):
    if not len(i)%2==0:
        ans+=1
print(ans)

n=int(input())
ans=0
for i in range(1,n+1):
    if not len(str(i))%2==0:
        ans+=1
print(ans)

Verdicts: Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
N = int(input())
ans = 0
for i in range(1, N + 1):
  if len(str(i)) % 2 != 1:
    ans += 1
print(ans)

N = int(input())
ans = 0
for i in range(1, N + 1):
    if len(str(i)) % 2 == 1:
        ans += 1
print(ans)


Verdicts: Wrong Answer

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
ans=0
for i in range(int(input())):
  if len(str(i))%2:
    ans+=1
print(ans)

ans=0
for i in range(1,int(input())+1):
  if len(str(i))%2:
    ans+=1
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
if N < 10 ** 1:
    print(N)
elif N < 10 ** 2:
    print(9)
elif N < 10 ** 3:
    print(N - 90)
elif N < 10 ** 4:
    print(909)
elif N < 10 ** 5:
    print(N - 9090)
else:
     print(90909)

if N < 10 ** 1:
    print(N)
elif N < 10 ** 2:
    print(9)
elif N < 10 ** 3:
    print(N - 90)
elif N < 10 ** 4:
    print(909)
elif N < 10 ** 5:
    print(N - 9090)
else:
     print(90909)

N = int(input())
if N < 10:
    print(N)
elif N < 100:
    print(9)
elif N < 1000:
    print(N - 90)
elif N < 10000:
    print(909)
elif N < 100000:
    print(N - 9090)
else:
     print(90909)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
#! /usr/bin/env python3
# -*- coding:utf-8 -*-

n = int(input())
d = len(str(n))
count = 0
ans = n

for i in range(d):
    print(i, i%2, min(ans, 9*(10**i)))
    if i%2 == 0: count += min(ans, 9*(10**i))
    ans -= 9*(10**i)

print(count)


#! /usr/bin/env python3
# -*- coding:utf-8 -*-

n = int(input())
d = len(str(n))
count = 0
ans = n

for i in range(d):
    if i%2 == 0: count += min(ans, 9*(10**i))
    ans -= 9*(10**i)

print(count)


Verdicts: Wrong Answer

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
N=int(input())
if N<10:
  print(N)
elif 10=<N<100:
  print(9)
elif 100=<N<1000:
  print(N-90)
elif 1000=<N<10000:
  print(909)
elif 10000=<N<100000:
  print(N-9090)
else:
  print(90909)

N=int(input())
if N<10:
  print(N)
elif 10<=N<100:
  print(9)
elif 100<=N<1000:
  print(N-90)
elif 1000<=N<10000:
  print(909)
elif 10000<=N<100000:
  print(N-9090)
else:
  print(90909)

Verdicts: Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
N = input()
if N < 10:
  print(N)
else:
  if 9 < N < 100:
    print("9")
  else:
    if 99 < N < 1000:
      print(N - 90)
    else:
      if 999 < N < 10000:
        print("909")
      else:
        if 9999 < N < 100000:
          print(909 +  N - 9999)
        else:
          if N = 100000:
            print("90909")


N = int(input())
if N < 10:
  print(N)
else:
  if 9 < N < 100:
    print("9")
  else:
    if 99 < N < 1000:
      print(N - 90)
    else:
      if 999 < N < 10000:
        print("909")
      else:
        if 9999 < N < 100000:
          print(909 +  N - 9999)
        else:
          if N == 100000:
            print("90909")

Verdicts: Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
import math
n=int(input())
num=math.log(n,10)
if 0<=num<1:
  print(n)
elif 1<=num<2:
  print(n-90)
elif 2<=num<3:
  print(909)
elif 3<=num<4:
  print(909)
elif 4<=n<5:
  print(n-9090)
else:
  print(90909)

import math
n=int(input())
num=math.log(n,10)
if 0<=num<1:
  print(n)
elif 1<=num<2:
  print(n-90)
elif 2<=num<3:
  print(909)
elif 3<=num<4:
  print(909)
else:
  print(n-9090)


n=int(input())
num=math.log(n,10)
if 0<=num<1:
  print(n)
elif 1<=num<2:
  print(n-90)
elif 2<=num<3:
  print(909)
elif 3<=num<4:
  print(909)
elif 4<=num<5:
  print(n-9090)
else:
  print(90909)

n=int(input())
num=math.log(n,10)
if 0<=num<1:
  print(n)
elif 1<=num<2:
  print(9)
elif 2<=num<3:
  print(n-90)
elif 3<=num<4:
  print(909)
elif 4<=num<5:
  print(n-9090)
else:
  print(90909)

n=int(input())
ans=0
for i in range(1,n+1):
  if len(str(i))%2!=0:
    ans+=1
print(ans)

Verdicts: Wrong Answer

Wrong Answer

Runtime Error

Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
n = int(input())
sum = 0
if n//10!=0:
  sum+=9
  if n//1000!=0:
    sum+=900
    if n//100000!=0:
      sum+=90000
    else:
      sum+=n-9999
  else:
    sum+=n-99
else:
  sum+=n
print(sum)

n = int(input())
sum = 0
if n//10!=0:
  sum+=9
  if n//1000!=0:
    sum+=900
    if n//100000!=0:
      sum+=90000
    elif n//10000!=0:
      sum+=n-9999
  elif n//100!=0:
    sum+=n-99
else:
  sum+=n
print(sum)

Verdicts: Wrong Answer

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
keta = (len(n))
max = int(keta/2)+1

count = 0
t = int(n)
if(keta%2==0):
    for i in range(1,max):
        count += 9*10**((2*(i-1)))
else:
    for i in range(1,max):
        count += 9*10**((2*(i-1)))
    t = t - 10**(keta-1)
    count += t
    count +=1
print(count)

import math
n = str(input()) 
keta = (len(n))
max = int(keta/2)+1

count = 0
t = int(n)
if(keta%2==0):
    for i in range(1,max):
        count += 9*10**((2*(i-1)))
else:
    for i in range(1,max):
        count += 9*10**((2*(i-1)))
    t = t - 10**(keta-1)
    count += t
    count +=1
print(count)


Verdicts: Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
import numpy as np

N = int(input())
A = np.array(list(map(float, input().split())))

print(np.reciprocal(np.sum(np.reciprocal(A))))

N = int(input())
number = len(str(N))
count = 0

if number % 2 == 0:
    for i in range(1, number, 2):
        count += 10 ** i - 10 ** (i - 1)
    print(count)
else:
    for i in range(2, number, 2):
        count += 10 ** i - 10 ** (i - 1)
    print(N - count)

Verdicts: Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
N = int(input())
i = 0
u = int(0)

for i in range(N):
    I = str(i+1)
    L=int(len(I))


    if L % 2 == 1:
        u = u + 1
        print(u)

print(u)

N = int(input())
i = 0
u = int(0)

for i in range(N):
    I = str(i+1)
    L=int(len(I))


    if L % 2 == 1:
        u = u + 1

print(u)

Verdicts: Wrong Answer

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
n=int(input())
c=0
for i in range(n):
    if len(str(i))%2==1:
        c+=1
print(c)

n=int(input())
c=0
for i in range(1,n+1):
    if len(str(i))%2==1:
        c+=1
print(c)

Verdicts: Wrong Answer

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
N = int(input())
ans = 0
for i in range(1, N + 1):
if len(i) % 2 == 1:
ans += 1
print(ans)

N = int(input())
ans = 0
for i in range(1, N + 1):
	if len(str(i)) % 2 == 1:
		ans += 1
print(ans)

Verdicts: Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
N = int(input())
odd_num = 0
for i in range (1,N+1):
    if i%2==0:
        odd_num += 1
print(odd_num)

N = int(input())
count = 0
for i in range(1, N + 1):
    if 1<=i <=9 or 100<=i <= 999 or 10000<= i <= 99999:
        count += 1
    else:
    
        count +=0
print(count)

Verdicts: Wrong Answer

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
n=int(ibput())

r=0

for i in range(1,n+1)
	if len(str(i))%2==1:
    	r+=1
print(r)

n=int(input())
 
r=0
 
for i in range(1,n+1)
	if len(str(i))%2==1:
    	r+=1
print(r)

n=int(ibput())
 
r=0
 
for i in range(1,n+1):
	if len(str(i))%2==1:
    	r+=1
print(r)

n=int(ibput())
 
r=0
 
for i in range(1,n+1):
	if len(str(i))%2==1:
		r+=1
print(r)

n=int(input())
 
r=0
 
for i in range(1,n+1):
	if len(str(i))%2==1:
		r+=1
print(r)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
n = int(input())

ans = 0

if n >= 10:
  ans += 10
  if n >= 10**2:
    if n >= 10**3:
      ans += 10**3 - 10**2
      if n >= 10**4:
        if n == 10**5:
          ans += 10**5 - 10**4
        else:
          ans += n - 10**4 + 1
    else:
      ans += n - 10**2 + 1
else:
  ans += n + 1

print(ans)

n = int(input())
 
ans = 0
 
if n >= 10:
  ans += 10 - 1
  if n >= 10**2:
    if n >= 10**3:
      ans += 10**3 - 10**2
      if n >= 10**4:
        if n == 10**5:
          ans += 10**5 - 10**4
        else:
          ans += n - 10**4 + 1
    else:
      ans += n - 10**2 + 1
else:
  ans += n
 
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
N = int(input())
total = 0
for i in range(1,N+1):
    if digits%2 != 0:
        total += 1
print(total)        
    



N = int(input())
total = 0
for i in range(1,N+1):
    if len(str(i))%2 != 0:
        total += 1
print(total)

Verdicts: Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
N = input()

res=0
for i in range(1, int(N)+1):
    if(les(N)//2==1):
        rea+=1

print(res)

N = int(input())

res=0
for i in range(1, N+1):
    if(les(N)//2==1):
        rea+=1

print(res)

N = int(input())

res=0
for i in range(1, N+1):
    if(len(str(i))//2==1):
        res+=1

print(res)

N = int(input())

res=0
for i in range(1, N+1):
    if(N//2==1):
        rea+=1

print(res)

N = int(input())

res=0
for i in range(1, N+1):
    if(len(str(i)) % 2==1):
        res+=1

print(res)

Verdicts: Runtime Error

Runtime Error

Wrong Answer

Wrong Answer

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
num = list(range(1, (int(input()-1))))

count = 0
for i in num:
    if len(str(i)) % 2 == 1:
        count += 1

print(count)


num = list(range(1, (int(input()-1))))

count = 0
for i in num:
    if len(str(i)) % 2 == 1:
        count += 1

print(count)


num = list(range(1, (int(input())+1)))

count = 0
for i in num:
    if len(str(i)) % 2 == 1:
        count += 1

print(count)


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
a = input()
b = 0
for i in range(1,int(a)+1):
  if len(a)%2 ==1:
    b+=1
print(b)

a = input()
if len(a) ==6:
  print(90909)
elif len(a) == 5:
  print(90909-90000 +int(a)-9999)
elif len(a) == 4:
  print(90909-90000)
elif len(a) ==3:
  print(90909-90000-900b+int(a)-99)
elif len(a) ==2:
  print(90909-90000-900)
else:
  print(int(a))
  

a = input()
b = 0
for i in range(1,int(a)+1):
  if len(str(i))%2 ==1:
    b+=1
print(b)

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
N=int(input())
s=list(N)
h=len(s)
if h%2==1:
  a=N-(10**(h-1))+1
  a=a+((100**((h-1)/2))-1)/11
  print(a)
elif h%2==0:
  a=((100**(h/2))-1)/11
  print(a)
  

N=int(input())
h=len(str(N))
if h%2==1:
  a=N-(10**(h-1))+1
  a=a+((100**((h-1)/2))-1)//11
  print(a)
elif h%2==0:
  a=((100**(h/2))-1)//11
  print(a)
  

N=int(input())
h=len(str(N))
if h%2==1:
  a=N-(10**(h-1))+1
  a=a+((100**((h-1)/2))-1)/11
  print(a)
elif h%2==0:
  a=((100**(h/2))-1)/11
  print(a)
  

N=int(input())
h=len(str(N))
if h%2==1:
  a=N-(10**(h-1))+1
  a=a+((100**((h-1)/2))-1)//11
  print(a)
elif h%2==0:
  a=((100**(h/2))-1)//11
  print(a)
  

N=int(input())
h=len(str(N))
if h%2==1:
  a=N-(10**(h-1))+1
  a=a+((100**((h-1)//2))-1)//11
  print(a)
elif h%2==0:
  a=((100**(h//2))-1)//11
  print(a)
   
  

Verdicts: Runtime Error

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
n = int(input())

ans = 0
for i in range(1, n+1):
  num = i
  digits=0
  while num:
    digits += 1
    num//=10
  if digit%2==1:
    ans+=1
    
print(ans)

n = int(input())

ans = 0
for i in range(1, n + 1):
    num = i
    digits = 0
    while num:
        digits += 1
        num //= 10
    if digits % 2 == 1:
        ans += 1

print(ans)


Verdicts: Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
def main(n):
    count = 0

    for i in range(n + 1):
        if len(str(i)) % 2 == 1:
            count += 1

    print(count)


if __name__ == "__main__":
    n = int(input())

    main(n)


def main(n):
    count = 0

    for i in range(n + 1):
        if str(i).__len__ % 2 == 1:
            count += 1

    print(count)


if __name__ == "__main__":
    n = int(input())

    main(n)


def main(n):
    count = 0

    for i in range(1, n + 1):
        if len(str(i)) % 2 == 1:
            count += 1

    print(count)


if __name__ == "__main__":
    n = int(input())

    main(n)


Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
if N < 10:
    print(N)
elif 10 <= N < 100:
    print(9)
elif 100 <= N < 1000:
    print(N - 90)
elif 1000 <= N < 10000:
    print(909)
elif 10000 <= N < 100000:
    print(N-9090)
else:
    print(90909)

if N < 10:
    print(N)
elif N >= 10 and N < 100:
    print(9)
elif N >= 100 and N < 1000:
    print(N - 90)
elif N >= 1000 and N < 10000:
    print(909)
elif N >= 10000 and N < 100000:
    print(N-9090)
else:
    print(90909)

ans = 0

for i in range(1, N + 1):
    if len(str(i)) % 2 == 1:
        ans += 1
print(ans)

ans = 0

for i in range(1, N + 1):
    if len(str(i)) % 2 == 1:
        ans += 1
print(ans)

if N < 10:
    print(N)
elif N >= 10 and N < 100:
    print(9)
elif N >= 100 and N < 1000:
    print(N - 90)
elif N >= 1000 and N < 10000:
    print(909)
elif N >= 10000 and N < 100000:
    print(N-9090)
else:
    print(90909)

N = int(input())

if N < 10:
    print(N)
elif 10 <= N < 100:
    print(9)
elif 100 <= N < 1000:
    print(N-90)
elif 1000 <= N < 10000:
    print(909)
elif 10000 <= N <100000:
    print(N-9090)
else:
    print(90909)

Verdicts: Runtime Error

Runtime Error

Runtime Error

Runtime Error

Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
n = int(input())
ct = 0
for i in range(n):
    if len(str(i)) % 2:
        ct +=1
print(ct)


# ABC136
# B Uneven Numbers

n = int(input())
ct = 0
for i in range(1,n+1):
    if len(str(i)) % 2:
        ct +=1
print(ct)


Verdicts: Wrong Answer

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
2 print(len(list(filter(lambda x: len(str(x)) % 2 == 1, range(1, int(input()) + 1)))))

n = int(input())
ans = 0
for i in range(1, n+1):
    if 1 <= i < 10 or 100 <= i < 1000 or 10000 <= i < 100000:
        ans += 1
print(ans)


Verdicts: Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
n = int(input())
a = 0
for i in range(1,n+1):
    if (i//10)%2 == 1:
        b += 1

print(b)

n = int(input())
a = 0
for i in range(1,n+1):
    if (i//10)%2 == 1:
        a += 1

print(a)

n = int(input())
a = 0
for l in range(1,n+1):
    s = list(str(l))
    if len(s)%2 == 1:
        a += 1

print(a)

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
n=int(input())
n_d=len(str(n))
ans=1
for i in range(1,n,2):
	part1=9
	part2=10**i
	total=part1*part2
	total/=10
	ans+=total
part1=10**n
part2=n-part1
ans+=(part2+1)
print(ans)


n=int(input())
n_d=len(str(n))
ans=0
if n_d >1:
	for i in range(1,n_d,2):
		part1=9
		part2=10**i
		total=part1*part2
		total=total//10
		ans+=total
if n_d%2!=0:		
	part1=10**(n_d-1)
	part2=n-part1
	ans+=(part2+1)
print(int(ans))
# your code goes here

Verdicts: Runtime Error

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
s = input()
N = int(s)
odd_num = 0
for i in range(1,N+1):
    cnt = 1
    num = i
    while (num // 10) > 0:
        cnt += 1
        num = num//10
        print(num)
    if cnt % 2:
        odd_num += 1
print(odd_num)

s = input()
N = int(s)
odd_num = 0
for i in range(1,N+1):
    cnt = 1
    while i // 10 >= 0:
        cnt += 1
        i //= 10
    if cnt % 2:
        odd_num += 1
print(odd_num)

s = input()
N = int(s)
odd_num = 0
for i in range(1,N+1):
    cnt = 1
    num = i
    while (num // 10) > 0:
        cnt += 1
        num = num//10
    if cnt % 2:
        odd_num += 1
print(odd_num)

Verdicts: Wrong Answer

Time Limit Exceeded

Accepted
Problem: Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Submission attempts (in order):
N = int(input())

import math
order = int(math.log10(int(N)))
ans = 0

for i in range(order):
    if (i % 2) == 0:
        ans += 9 * 10 ** i

print(order)
if (order % 2) == 0:
    a = N - 10 ** order
    ans += a + 1 

print(ans)

N = int(input())

import math
order = int(math.log10(int(N)))
ans = 0

for i in range(order):
    if (i % 2) == 0:
        ans += 9 * 10 ** i

if (order % 2) == 0:
    a = N - 10 ** order
    ans += a + 1 

print(ans)

Verdicts: Wrong Answer

Accepted
Problem: There are N squares arranged in a row from left to right. The height of the i-th square from the left is H_i.  For each square, you will perform either of the following operations once:    * Decrease the height of the square by 1.   * Do nothing.  Determine if it is possible to perform the operations so that the heights of the squares are non-decreasing from left to right.

Submission attempts (in order):
N = int(input())
a = input().split()
for l in range(N):
    a[l] = int(a[l])
for i in range(N):
  if i < N:
    if a[N-i-1] >= a[N-i-2]:
    elif a[N-i-1] + 1 == a[N-i-2]:
      a[N-i-2] -= 1
    else:
      print('No')
      break
  else:
    print('Yes')

N = int(input())
a = input().split()
for l in range(N):
    a[l] = int(a[l])
for i in range(N):
  if i < N:
    if a[N-i-1] >= a[N-i-2]:
      continue
    elif a[N-i-1] + 1 == a[N-i-2]:
      a[N-i-2] -= 1
    else:
      print('No')
      break
  else:
    print('Yes')

N = int(input())
a = []
for i in range(N):
  a.append(input())
for i in range(N):
  if i < N:
    if int(a[N-i-1]) >= int(a[N-i-2]):
      continue
    elif int(a[N-i-1]) + 1 == int(a[N-i-2]):
      int(a[N-i-2]) -= 1
      continue
    else:
      print('No')
      break
  else:
    print('Yes')

N = int(input())
a = input().split()
for l in range(N):
    a[l] = int(a[l])
for i in range(N):
  if i < N-1:
    if a[N-i-1] >= a[N-i-2]:
      continue
    elif a[N-i-1] + 1 == a[N-i-2]:
      a[N-i-2] -= 1
    else:
      print('No')
      break
  else:
    print('Yes')

Verdicts: Runtime Error

Wrong Answer

Runtime Error

Accepted
Problem: There are N squares arranged in a row from left to right. The height of the i-th square from the left is H_i.  For each square, you will perform either of the following operations once:    * Decrease the height of the square by 1.   * Do nothing.  Determine if it is possible to perform the operations so that the heights of the squares are non-decreasing from left to right.

Submission attempts (in order):
N = int(input())
H = list(map(int, input().split()))

H = H[::-1]
for i in range(1, N):
    if H[i] > H[i-1] + 1:
        check = 1
        break
    if H[i] > H[i-1]:
        H[i] -= 1

if check:
    print('No')
else:
    print('Yes')

N = int(input())
H = list(map(int, input().split()))

H = H[::-1]
check = 0
for i in range(1, N):
    if H[i] > H[i-1] + 1:
        check = 1
        break
    if H[i] > H[i-1]:
        H[i] -= 1

if check:
    print('No')
else:
    print('Yes')

Verdicts: Runtime Error

Accepted
Problem: There are N squares arranged in a row from left to right. The height of the i-th square from the left is H_i.  For each square, you will perform either of the following operations once:    * Decrease the height of the square by 1.   * Do nothing.  Determine if it is possible to perform the operations so that the heights of the squares are non-decreasing from left to right.

Submission attempts (in order):
n = int(input())
A = list(map(int, input().split()))

flag = True
for i in range(n-1, 0, -1):
    if A[i-1] >= A[i] + 2:
        flag = False
        break
    elif A[i-1] == A[i] + 1:
        A[i-1] -= 1

if flag:
    print("YES")
else:
    print("NO")

n = int(input())
A = list(map(int, input().split()))

flag = True
for i in range(n-1, 0, -1):
    if A[i-1] >= A[i] + 2:
        flag = False
        break
    elif A[i-1] == A[i] + 1:
        A[i-1] -= 1

if flag:
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Accepted
Problem: There are N squares arranged in a row from left to right. The height of the i-th square from the left is H_i.  For each square, you will perform either of the following operations once:    * Decrease the height of the square by 1.   * Do nothing.  Determine if it is possible to perform the operations so that the heights of the squares are non-decreasing from left to right.

Submission attempts (in order):
import sys
N = int(input())
H = input().split()
for i in range(N):
    H[i] = int(H[i])

H = reversed(H)  
for i in range(N-1):
    if H[i] < H[i+1]:
        H[i+1] = H[i+1]-1
    if H[i] > H[i+1]:
        print('No')
        sys.exit() 
print('Yes')


import sys
N = int(input())
H = input().split()
for i in range(N):
    H[i] = int(H[i])
H.reverse()

for i in range(N-1):
    if H[i] < H[i+1]:
        H[i+1] = H[i+1]-1
    if H[i] > H[i+1]:
        print('No')
        sys.exit() 
print('Yes')


import sys
N = int(input())
H = input().split()
for i in range(N):
    H[i] = int(H[i])
H.reverse()

for i in range(N-1):
    if H[i] > H[i+1]:
        H[i+1] = H[i+1]-1
    if H[i] < H[i+1]:
        print('No')
        sys.exit() 
print('Yes')


import sys
N = int(input())
H = input().split()
for i in range(N):
    H[i] = int(H[i])
H.reverse()

for i in range(N-1):
    if H[i] < H[i+1]:
        H[i+1] = H[i+1]-1
    if H[i] < H[i+1]:
        print('No')
        sys.exit() 
print('Yes')


Verdicts: Runtime Error

Wrong Answer

Wrong Answer

Accepted
Problem: There are N squares arranged in a row from left to right. The height of the i-th square from the left is H_i.  For each square, you will perform either of the following operations once:    * Decrease the height of the square by 1.   * Do nothing.  Determine if it is possible to perform the operations so that the heights of the squares are non-decreasing from left to right.

Submission attempts (in order):
n= int(input())
h = list(map(int,input().split()))
count=0

for i in range(n-1):
  if h[i]==h[i+1] or (h[i]+1)==h[i+1] or (h[i]-1)==h[i+1]:
    count+=1 
if count==n-1:
  print("Yes")
else:
  print("No")
  

n= int(input())
h = list(map(int,input().split()))
count=0
mainasu=0
for i in range(n-1):
  if h[i]<=h[i+1]:
    count+=1 
  elif (h[i]-1)==h[i+1] and mainasu==0:
      mainasu+=1
if count==n-1:
  print("Yes")
else:
  print("No")

n= int(input())
h = list(map(int,input().split()))
count=0
a=h[0]
for i in range(n-1):
  if a<h[i+1]:
    count+=1
    a=(h[i+1]-1)
  if a==h[i+1]:
    a=h[i+1]
    count+=1
if count==(n-1):
  print("Yes")
else:
  print("No")
      



Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: There are N squares arranged in a row from left to right. The height of the i-th square from the left is H_i.  For each square, you will perform either of the following operations once:    * Decrease the height of the square by 1.   * Do nothing.  Determine if it is possible to perform the operations so that the heights of the squares are non-decreasing from left to right.

Submission attempts (in order):
n = int(input())
h = list(map(int, input().split()))

judge = 0
for i in range(n):
  if a[i] < judge:
    print("No")
    break
  judge = max(judge, a[i]-1)
else:
  print("Yes")

n = int(input())
a = list(map(int, input().split()))

judge = 0
for i in range(n):
  if a[i] < judge:
    print("No")
    break
  judge = max(judge, a[i]-1)
else:
  print("Yes")

Verdicts: Runtime Error

Accepted
Problem: There are N squares arranged in a row from left to right. The height of the i-th square from the left is H_i.  For each square, you will perform either of the following operations once:    * Decrease the height of the square by 1.   * Do nothing.  Determine if it is possible to perform the operations so that the heights of the squares are non-decreasing from left to right.

Submission attempts (in order):
def main():
    N = int(input())
    H = list(map(int, input().split(" ")))
    flag = True
    for i in range(1, N):
        if H[i] - H[i - 1] <= 0:
            H[i - 1] -= 1
    for j in range(N - 1):
        if H[j + 1] - H[j] < 0:
            flag = False
            break
    if flag:
        print("Yes")
    else:
        print("No")


if __name__ == '__main__':
    main()

def main():
    N = int(input())
    H = list(map(int, input().split(" ")))
    flag = True
    for i in range(N - 1):
        if H[i] - H[i + 1] <= 0:
            H[i + 1] -= 1
    for j in range(N - 1):
        if H[j + 1] - H[j] < 0:
            flag = False
            break
    if flag:
        print("Yes")
    else:
        print("No")


if __name__ == '__main__':
    main()

def main():
    N = int(input())
    H = list(map(int, input().split(" ")))
    flag = True
    for i in range(N - 1):
        if H[i] - H[i + 1] < 0:
            H[i + 1] -= 1
    for j in range(N - 1):
        if H[j + 1] - H[j] < 0:
            flag = False
            break
    if flag:
        print("Yes")
    else:
        print("No")


if __name__ == '__main__':
    main()

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: There are N squares arranged in a row from left to right. The height of the i-th square from the left is H_i.  For each square, you will perform either of the following operations once:    * Decrease the height of the square by 1.   * Do nothing.  Determine if it is possible to perform the operations so that the heights of the squares are non-decreasing from left to right.

Submission attempts (in order):


N = int(input())


H_list = int(input().split())

Judge = True


H_list(0)-=1

for i in range(N-1):
    
    if H_list(i) < H_list(i+1):
        H_list(i+1)-=1
    elif H_list(i) > H_list(i+1):
    
        Judge = False

if Judge == True:
    print('Yes')
else:
    print('No')

N = int(input())
H_list = list(map(int,input().split()))

diff = list(map(lambda a,b: b-a,H_list[1::],H_list))

cnt =0

for i in diff:
    if i <=-2:
        cnt =1
    else:
        pass

if cnt==1:
    print("No")
else:
    print("Yes") 



N = int(input())


H_list = list(map(int,input().split()))

Judge = True


H_list[0]-=1
print(H_list[0])

for i in range(N-1):
    
    if H_list[i] < H_list[i+1]:
        H_list[i+1]-=1
    elif H_list[i] > H_list[i+1]:
    
        Judge = False

if Judge == True:
    print('Yes')
else:
    print('No')



N = int(input())


H_list = int(input().split())

Judge = True

for i in H_list:
    if H_list(i) > H_list(i+1):
        H_list(i)-1
    elif:
        pass
    else :
        Judge = False

if Judge == True:
    print('Yes')
else:
    print('No')





N = int(input())


H_list = list(map(int,input().split()))

Judge = True


H_list[0]-=1

for i in range(N-1):
    
    if H_list[i] < H_list[i+1]:
        H_list[i+1]-=1
    elif H_list[i] > H_list[i+1]:
    
        Judge = False

if Judge == True:
    print('Yes')
elif Judge == False:
    print('No')

Verdicts: Runtime Error

Wrong Answer

Wrong Answer

Runtime Error

Accepted
Problem: There are N squares arranged in a row from left to right. The height of the i-th square from the left is H_i.  For each square, you will perform either of the following operations once:    * Decrease the height of the square by 1.   * Do nothing.  Determine if it is possible to perform the operations so that the heights of the squares are non-decreasing from left to right.

Submission attempts (in order):
N = int(input())
H = list(map(int, input().split()))
key = 0
for i in range(N-1, 1, -1):
    if H[i]>H[i+1]:
      H[i]-=1
    if H[i]>H[i+1]:
      key += 1
      break
if key == 0:
  print('Yes')
else:
  print('No')

N = int(input())
H = list(map(int, input().split()))
key = 0
for i in range(N-1):
    if H[i]<H[i+1]:
      H[i+1]-=1
    if H[i]<H[i+1]:
      key += 1
      break
if key == 0:
  print('Yes')
else:
  print('No')

N = int(input())
H = list(map(int, input().split()))
key = 0
for i in range(N-1):
    if H[i]>H[i+1]:
      H[i+1]-=1
    if H[i]>H[i+1]:
      key += 1
      break
if key == 0:
  print('Yes')
else:
  print('No')

N = int(input())
H = list(map(int, input().split()))
key = 0
for i in range(N-1):
    if H[i]>H[i+1]:
      H[i+1]-=1
    if H[i]<H[i+1]:
      key += 1
      break
if key == 0:
  print('Yes')
else:
  print('No')

N = int(input())
H = list(map(int, input().split()))
 
for i in range(1, N):
    if H[i] < H[i - 1]:
        H[i] += 1
for i in range(1, N):
    if H[i] < H[i - 1]:
        print('No')
        exit(0)
print('Yes')

Verdicts: Runtime Error

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: There are N squares arranged in a row from left to right. The height of the i-th square from the left is H_i.  For each square, you will perform either of the following operations once:    * Decrease the height of the square by 1.   * Do nothing.  Determine if it is possible to perform the operations so that the heights of the squares are non-decreasing from left to right.

Submission attempts (in order):
n=int(input())

h=[int(x) for x in input().split()]
m=h[0]
for i in range(n):
  #print(c,-i)
  if h[i]>=m-1:
    print("No")
    exit()
  m=max(m,h[i])
print("Yes")


n=int(input())

h=[int(x) for x in input().split()]
m=h[0]
for i in range(n):
  #print(c,-i)
  if h[i]>m-1:
    print("No")
    exit()
  m=max(m,h[i])
print("Yes")


n=int(input())

h=[int(x) for x in input().split()]
m=h[0]
for i in range(n):
  #print(c,-i)
  #print(m)
  if h[i]<m-1:
    print("No")
    exit()
  m=max(m,h[i])
print("Yes")


Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: There are N squares arranged in a row from left to right. The height of the i-th square from the left is H_i.  For each square, you will perform either of the following operations once:    * Decrease the height of the square by 1.   * Do nothing.  Determine if it is possible to perform the operations so that the heights of the squares are non-decreasing from left to right.

Submission attempts (in order):
for i in range(N - 1):
  if H[i] > H[i + 1] and H[i] - 1 <= H[i + 1]:
    H[i] = H[i] - 1
  elif H[i] > H[i + 1] or H[i] < max:
    ans = "No"
  max = H[i + 1]
if sorted(H) != H:
  ans = "No"
print(ans)

N = int(input())
H = list(map(int, input().split()))
ans = "Yes"
for i in range(N - 1):
  diff = H[i + 1] - H[i]
  if diff >= 1:
    H[i + 1] -= 1
  elif diff < 0:
    ans = "No"
print(ans)

Verdicts: Runtime Error

Accepted
Problem: There are N squares arranged in a row from left to right. The height of the i-th square from the left is H_i.  For each square, you will perform either of the following operations once:    * Decrease the height of the square by 1.   * Do nothing.  Determine if it is possible to perform the operations so that the heights of the squares are non-decreasing from left to right.

Submission attempts (in order):
n=int(input())
arr=list(map(int,input().split()))
for i in range(n-1,0,-1): 
 if arr[i]>arr[i-1]: 
   arr[i-1]-=1
   if arr[i]>arr[i-1]: 
     print('No')
     break
else:
 print('Yes')

n=int(input())
arr=list(map(int,input().split()))
for i in range(n-2,0,-1): 
 if arr[i]>arr[i+1]: 
   arr[i]-=1
   if arr[i]>arr[i+1]: 
     print('No')
     break
else:
 print('Yes')

Verdicts: Wrong Answer

Accepted
Problem: There are N squares arranged in a row from left to right. The height of the i-th square from the left is H_i.  For each square, you will perform either of the following operations once:    * Decrease the height of the square by 1.   * Do nothing.  Determine if it is possible to perform the operations so that the heights of the squares are non-decreasing from left to right.

Submission attempts (in order):
N = input()
H = input()

N = int(N)
H = [int(x) for x in H.split(" ")]
C = 0
print(N, H)
for i in range(0, len(H)-1):
    m = min(H[i:len(H)])
    if H[i] > m:
        C = C + H[i] - m
    else:
        C = C
print(C)

N = input()
H = input()
N = int(N)
H = [int(x) for x in H.split(" ")]
C = 0

for i in range(0, N-1):
    m = min(H[i:N])
    if H[i] > m:
        C = C + H[i] - m
    else:
        C = C
print(C)

N = input()
H = input()


N = int(N)
H = [int(x) for x in H.split(" ")]
C = 0
R = 0
M = H[0]

while C < (N-1):
    if H[C] - H[C+1] > 1:
        R = 1
        C = N
    elif H[C] - H[C+1] == 1:
        if M > (H[C]-1):
            R = 1
            C = N
        else:
            M = max(M, H[C+1])
            C += 1
    else:
        C+=1

if R == 0:
    print("Yes")
else:
    print("No")

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: There are N squares arranged in a row from left to right. The height of the i-th square from the left is H_i.  For each square, you will perform either of the following operations once:    * Decrease the height of the square by 1.   * Do nothing.  Determine if it is possible to perform the operations so that the heights of the squares are non-decreasing from left to right.

Submission attempts (in order):

N=int(input())
stairs =input().rstrip().split(" ")
for i in range(N):
  stairs[i]=int(stairs[i])
standard =min(stairs)
#print(standard)
restairs =list(reversed(stairs))
position =restairs.index(standard)
trueindex =N-position-1
j=0
for i in range(trueindex):
  if int(stairs[i])<=standard+1:
    j=j+1
#print(j)
if j==N:
  print("Yes")
else:
  print("No")



import sys
input = sys.stdin.readline
sys.setrecursionlimit(10**7)
from collections import Counter, deque
from collections import defaultdict
from itertools import combinations, permutations, accumulate, groupby, product
from bisect import bisect_left,bisect_right
from heapq import heapify, heappop, heappush
from math import floor, ceil,pi,factorial
from operator import itemgetter
def I(): return int(input())
def MI(): return map(int, input().split())
def LI(): return list(map(int, input().split()))
def LI2(): return [int(input()) for i in range(n)]
def MXI(): return [[LI()]for i in range(n)]
def SI(): return input().rstrip()
def printns(x): print('\n'.join(x))
def printni(x): print('\n'.join(list(map(str,x))))
inf = 10**17
mod = 10**9 + 7

n=I()
lis=LI()
lis=list(reversed(lis))
st=lis[0]
for i in range(n-1):
    if lis[i+1]>lis[i]+1:
        print("No")
        sys.exit()
    elif lis[i+1]==lis[i]+1:
        lis[i+1]-=1
    else:
        continue
print("Yes")

Verdicts: Wrong Answer

Accepted
Problem: There are N squares arranged in a row from left to right. The height of the i-th square from the left is H_i.  For each square, you will perform either of the following operations once:    * Decrease the height of the square by 1.   * Do nothing.  Determine if it is possible to perform the operations so that the heights of the squares are non-decreasing from left to right.

Submission attempts (in order):
n=int(input())
h=list(map(int, input().split()))
c=0
if n!=1:
    for i in reversed(range(n-1)):
        if h[i]==h[i+1]+1:
            h[i]-=1
        elif h[i]-h[i+1]>=2:
            c=1
    if c==1:
        print("Yes")
    else:
        prin("No")
else:
    print("Yes")
            

n=int(input())
h=list(map(int, input().split()))
c=0
if n!=1:
    for i in reversed(range(n-1)):
        if h[i]==h[i+1]+1:
            h[i]-=1
        elif h[i]-h[i+1]>=2:
            c=1
    if c==0:
        print("Yes")
    else:
        print("No")
else:
    print("Yes")

Verdicts: Runtime Error

Accepted
Problem: There are N squares arranged in a row from left to right. The height of the i-th square from the left is H_i.  For each square, you will perform either of the following operations once:    * Decrease the height of the square by 1.   * Do nothing.  Determine if it is possible to perform the operations so that the heights of the squares are non-decreasing from left to right.

Submission attempts (in order):
N = int(input())
H = list(map(int,input().split(' ')))
if N == 1:
  print('Yes')
  exit()
for i in range(N-1,0,-1):
  if H[i-1] >= H[i-2]:
    pass
  elif H[i-2] - H[i-1] == 1:
    H[i-2] -= 1
  else:
    print('No')
    exit()
print('Yes')
    

N = int(input())
H = list(map(int,input().split(' ')))

for i in range(N-1,0,-1):
  if H[i-1] - H[i] >= 2:
    print('No')
    exit()
  elif  H[i-1] - H[i] == 1:
    H[i-1] -= 1
  else:
    pass
print('Yes')
    
    
    
    
  
    
  
  

Verdicts: Wrong Answer

Accepted
Problem: There are N squares arranged in a row from left to right. The height of the i-th square from the left is H_i.  For each square, you will perform either of the following operations once:    * Decrease the height of the square by 1.   * Do nothing.  Determine if it is possible to perform the operations so that the heights of the squares are non-decreasing from left to right.

Submission attempts (in order):
*- coding: UTF-8 -*-

n = int(input())
l = list(map(int, input().split()))
l.reverse()
f = 0

for i in range(len(l)-1):
    if l[i] >= l[i+1]:
        continue
    else:
        if l[i] >= l[i+1] - 1:
            l[i+1] -= 1
        else:
            f = 1

    if f == 1:
        break


if f == 1:
    print("No")
else:
    print("Yes")


# -*- coding: UTF-8 -*-

n = int(input())
l = list(map(int, input().split()))
l.reverse()
f = 0

for i in range(len(l)-1):
    if l[i] >= l[i+1]:
        continue
    else:
        if l[i] >= l[i+1] - 1:
            l[i+1] -= 1
        else:
            f = 1

    if f == 1:
        break

if f == 1:
    print('No')
else:
    print('Yes')


Verdicts: Runtime Error

Accepted