m的平方加m减1等于0,试求代数式m的3次方加2m的平方加2000的值
因为:
m^2+m-1=0
所以,乘以m得到:
m^3+m^2=m
m^3+2m^2+2000
=m^2+m+2000
=1+2000
=2001
M^2+m-1=0
m^2=1-m
m^3+2m^2+2000
=m(1-m)+2m^2+2000
=m-m^2+2m^2+2000
=m^2+m-1+2001
=0+2001
=2001
绝对是2001
m^3+2m^2+2000=m(m^2+m-1)+(m^2+m-1)+1+2000=2001