y=xy+lnxy两边求导得:dy/dx=y+xdy/dx+(1/xy)(y+xdy/dx)=y+xdy/dx+1/x+(1/y)dy/dx(1-x-1/y)dy/dx=y+1
求导y'=2xf'(x^2)y'=2f(sinx)f'(sinx)cosx
求导,y=x^(1/x)*(e^x)=e^[(1/x)*(lnx)+x]dy/dx=e^[(1/x)*(lnx)+x]*[-lnx/(x^2)+1/(x^2)+1]=x^(1/x)e^x[1+(1-lnx)/(x^2)]用键盘输不太好看,你
求导, 好复杂,y'=arctanx=1/(1+x),剩下的自己慢慢算吧
求导 12x-1cosx-16x²+6x-241/(xln2)-3sinx-4cosx