作者:patch时间:
还要说几句:推挽甲类和单端变压器输出的甲类,理论效率是50%;单端恒流源输出的甲类理论效率是25%。作者:电源开关时间:
Just how accurate is the spreadsheet I posted?
JLH in his original article about the design suggested the following idle current / load combination, to produce 10w rms output power:
Load 3ohm, Vdc 17v, Idle current 2amp;
Load 8ohm, Vdc 27v, idle current 1.2amp;
Load 15ohm, Vdc 36v, idle current 0.9amp.
if you load up the parameters in my spreadsheet, and assume saturation voltage loss of 1v, and idle current multiplier of 1.3x, you get idle current of 1.9amp (vs. 2amp), 1.2amp (vs. 1.2amp), 0.9amp (vs. 0.9amp), and the output power is around 10w rms.
so the spreadsheet is very accurate in setting the idle current, or calculate the required transformer voltage / power ratings.作者:hy1635时间:
P=1.414*I^2*R,式中的I是什么?既然有I^2,怎么1.414只有一次方呢?不懂作者:WANGCLZL时间:
支持!作者:WANGCLZL时间:
又认真看了一遍,支持楼主30楼的观点.应该加分.好帖!作者:911xp时间:
支持楼主的研究精神
我只知道厂家标推挽的甲类功率是P=I2 X 2R
但如果单端甲类效率达到50%,那就值得商榷
关于zen(就是196