问: (1)每小时用水为多少吨? (2)填料层高度为多少米?(塔径定为1.5m) 解:(1)qn,B = eq \f(2240,22.4) ? (1 - 0.1) = 90koml·h-1 X2 = 0 X1 ? x1 = 0.0006 Y2 ? y2 = 0.005 Y1 = eq \f(0.1,1 - 0.1) = 0.111 ∵ qn,c(X1 - X2) = qn,B(Y1 - Y2) ∴ qn,c = 90 ? eq \f(0.111 - 0.005,0.0006 - 0) = 1.59 ? 104 koml·h-1 用水量 = eq \f(1.59 ? 104 ? 18,1000) = 286.2 t·h-1 (2) m = eq \f(E,P总) = eq \f(2 ? 105,2 ? 103) = 100 ∵ x1* = eq \f(y1,m) = eq \f(0.1,100) =0.001 ∴X1* ? x1* = 0.001 同理:X2*? x2* = eq \f(y2,m) = eq \f(0.005,100) = 5 ? 10-5 NOL = eq \f(X1 - X2,?Xm) = eq \f(0.0006 - 0,1.68 ? 104) = 3.57 S = eq \f(?,4) ? 1.52 = 1.77m2 HOL = eq \f(qn.c,KxaS) = eq \f(1.59 ? 104,2780 ? 1.77) = 3.23 m H = 3.57 ? 3.23 = 11.53m