使用数字1-9
数独在9x9空白的网格上玩。每一行和每一列中有9个"正方块"(构成3x3的空格)。每一行、每一列和每一个正方块(共9个空格)需要被填上1-9数字。每一行、每一列或正方块内的数字都不能重复使用。听起来是否很复杂?您能在以下看见一个真实的数独网格图像,每一个数独网格都有几个已被填上的空格。所被填上的空格越多,游戏就越简单。困难的数独拼图只有少许已被填上的空格。
别重复使用任何数字
如您所能见到的,左上角的正方块(蓝色圈圈)中的9个空格已有7个被填上了。正方块中唯一缺乏的数字是5和6。通过得知每一个正方块、每一列或每一行缺少哪些数字,我们能采用淘汰过程和演绎推理来决定每一个空格中的数字。
比方说在左上角的正方块中,我们知道需要加上一个5或一个6来完成这个正方块。但根据相邻的行和正方块我们并不能清楚的推断出哪个号码该被加进哪一个空间。这意味着我们现在该先跳过左上角的正方块,以及尝试填充网格中其他的空格。
不要猜
数独是一个逻辑和推理游戏,因此您不该用猜的。您若并不知道该填上什么数字那么就继续扫描网格直到您看见填上一个数字的机会。别试图"强迫"以对- 数独奖励耐心、洞察力和模式识别,盲目的运气或猜测是不适用的。
采用淘汰过程
我们所说的使用"淘汰过程"来玩数独是什么意思?我们这就来解说。在这个数独网格中(如以下所示),最左边的垂直柱(蓝色圈圈)缺少了几个数字:1、5和6.
查出每一个空格该填上哪个数字的其中一个方法便是以查看哪个号码已被包括在正方块中的方式来使用"淘汰过程"- 因为每一个正方块(或每一行或每一列)都不能重复使用1-9数字。
在这个情况下,我们能够快速地发现网格左上角和左中角已有数字1(数字1以红色圈出)。这代表说最左边垂直柱只剩下唯一一个能够填上1的空格- 以绿色圈出。这是数独中的淘汰过程- 您找出哪个空格是可用的,哪个数字是缺乏的- 然后按照网格中的数字位置做出推理来判定哪个数字该填在哪个空格内。
数独规则是相当简单的- 但该游戏无限多变,备有上百万个数字组合和各种难度级别。但它都基于简单的1-9数字原理,根据推理逻辑和从不在每个正方块、每一行或每一列内重复使用任何号码来填充空格。

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