过点F作FH‖AE,交BC于点H.
则有:BE∶EH = BG∶GF = 1 ,EH∶HC = AF∶FC = 1∶2 ,
所以,BE = EH = (1/2)HC ,BH = BE+EH = HC = (1/2)BC ;
可得:BE = (1/4)BC ,EC = BC-BE = (3/4)BC ,
所以,BE∶EC = 1∶3 .
1年前