Task: Text to Code
Input (English): Step 1: For each row in city table, find the corresponding rows in address table.
Step 2: find the number of rows of each value of address's city_id in the results of step 1.
Step 3: find rows, city, address's city_id of step 1 results with largest value in the results of step 2
Output (English): SELECT * , T2.city , T1.city_id FROM address AS T1 JOIN city AS T2 ON T1.city_id = T2.city_id GROUP BY T1.city_id ORDER BY Count ( * ) Desc LIMIT 1