Task: Code to Text
Input (English): and { only { filter_eq { all_rows ; density ; 33 } } ; eq { hop { filter_eq { all_rows ; density ; 33 } ; english name } ; luobei county } } = true
Output (English): select the rows whose density record is equal to 33 . there is only one such row in the table . the english name record of this unqiue row is luobei county .