Task: Text to Code
Input (English): Step 1: For each row in broadcast table, find corresponding rows in program table and in channel table.
Step 2: find channel's Name of the results of step 1 whose Origin not equals Beijing
Output (English): SELECT T2.Name FROM program AS T1 JOIN channel AS T2 JOIN broadcast AS T3 ON T1.Program_ID = T3.Program_ID AND T3.Channel_ID = T2.Channel_ID WHERE T1.Origin ! = "Beijing"