Task: Text to Code
Input (English): Step 1: For each row in Person table, find the corresponding rows in PersonFriend table.
Step 2: find rows in the results of step 1 whose age greater than engineer.
Step 3: find the number of rows of each value of friend in step 1 rsults.
Step 4: find Person's name in the results of step 1 whose corresponding value in step 2 is greater than or equals 1
Output (English): SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T1.age > "engineer" GROUP BY T2.friend HAVING Count ( * ) > = 1