Task: Code to Text
Input (English): eq { diff { hop { filter_eq { all_rows ; city of license ; plainview , texas } ; frequency mhz } ; hop { filter_eq { all_rows ; city of license ; pampa , texas } ; frequency mhz } } ; -0.8 } = true
Output (English): select the rows whose city of license record fuzzily matches to plainview , texas . take the frequency mhz record of this row . select the rows whose city of license record fuzzily matches to pampa , texas . take the frequency mhz record of this row . the second record is 0.8 larger than the first record .