Task: Question Answering
Input (English): Passage: As of 2011 the 88,112 residents of Orem had a racial and ethnic composition of 89.3% White American, 0.9% black or African American, 0.9% Native Americans of the United States, 1.6% Asian American, 0.5% Pacific Islanders, 4% non-Hispanics reporting some other race, 2.9% two or more races reported and 14.8% Hispanic, as Orem has a large Mexican American community with other Latinos residing in the city. This contrasts with the census of 2000, which showed a racial makeup of 90.80% White (U.S. Census), 0.33% African American (U.S. Census), 0.73% Native American (U.S. Census), 1.45% Asian (U.S. Census), 0.86% Pacific Islander (U.S. Census), 3.64% from Race (United States Census), and 2.18% from two or more races. Hispanic (U.S. Census) or Latino (U.S. Census) of any race were 8.56% of the population. The 2000 Census counted 84,324 people, 23,382 households, and 19,079 families. The population density at that time was 4,572.6 people per square mile (1,765.6/km²). There were 24,166 housing units at an average density of 1,310.4 per square mile (506.0/km²). There were 23,382 households out of which 48.8% had children under the age of 18 living with them, 69.0% were Marriage living together, 9.5% had a female householder with no husband present, and 18.4% were non-families. 12.4% of all households were made up of individuals and 5.1% had someone living alone who was 65 years of age or older. The average household size was 3.57 and the average family size was 3.93. 
Question: How many percent of people were not white in 2000? 
Answer type: Number 
Output (English): 9.2.