Task: Text to Code
Input (English): Which address holds the most number of students currently? List the address id and all lines.
Output (English): SELECT T1.address_id ,  T1.line_1 ,  T1.line_2 FROM Addresses AS T1 JOIN Students AS T2 ON T1.address_id  =  T2.current_address_id GROUP BY T1.address_id ORDER BY count(*) DESC LIMIT 1