Task: Text to Code
Input (English): SQL: SELECT id , Trade_Name FROM medicine GROUP BY id HAVING Count ( * ) > = 3
Feedback: Use medicine id in medicine enzyme interaction table in place of id in medicine table in step 1.
Output (English): SELECT T1.id ,  T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id  =  T1.id GROUP BY T1.id HAVING COUNT(*)  >=  3