Go: // ダイクストラのアルゴリズム
package main

import (
	"bufio"
	"fmt"
	"log"
	"math"
	"os"
	"strconv"
	"strings"
)

type color int

const (
	white color = iota // 未訪問
	mst                // MSTとして確定
)

// 頂点
type node struct {
	num     int         // 頂点の番号
	weights map[int]int // 重みMAP
	parent  *node       // MSTへの重み最小の親
	sum     int         // 始点からの距離
	color   color
}

func (p *node) getMinToMst() int {
	if p.parent == nil {
		return math.MaxInt32
	}
	return p.weights[p.parent.num]
}

func main() {
	scanner := bufio.NewScanner(os.Stdin)
	n := eGetInt(scanner)

	nodes := make([]*node, n)
	for i := 0; i < n; i++ {
		weights := eAtoi((strings.Fields(eGetline(scanner))))
		v := &node{weights[0], make(map[int]int, weights[1]), nil, 0, white}
		for j := 0; j < weights[1]; j++ {
			k := weights[j*2+2] // 相手の頂点名
			w := weights[j*2+3] // 重み
			v.weights[k] = w
		}
		nodes[i] = v
	}

	// 初回はnode[0]がMSTに入るように
	nodes[0].parent = nodes[0]

	for { // 全部チェックするまで

		// どの頂点を新たにMSTに取り込むか

		var minNode *node
		min := math.MaxInt32
		for _, v := range nodes {
			if v.color == mst {
				continue
			}
			if v.getMinToMst() < min {
				min = v.getMinToMst()
				minNode = v
			}
		}
		if minNode == nil {
			// すべて完了している.
			break
		}

		// MSTに追加する頂点決定
		minNode.color = mst
		// 自分の親の合計値と合算する
		minNode.sum = minNode.parent.sum + min

		// MSTに属していない頂点それぞれについて,MSTとの最小の重みの距離を加算
		for _, v := range nodes {
			if v.color == mst {
				continue
			}
			w, ok := v.weights[minNode.num]
			if !ok {
				// minNodeと接してない
				continue
			}

			if w < v.getMinToMst() {
				// minNodeへの距離がもっとも重みが少ないので親を変更
				v.parent = minNode
			}
		}
	}

	for i, v := range nodes {
		fmt.Printf("%d %d\n", i, v.sum)
	}
}

func eGetInt(scanner *bufio.Scanner) int {
	t := eAtoi(strings.Fields(eGetline(scanner)))
	return t[0]
}

func eGetline(p *bufio.Scanner) string {
	if !p.Scan() {
		if err := p.Err(); err != nil {
			log.Fatal(err.Error())
		}
		return ""
	}
	return p.Text()
}

func eAtoi(s []string) []int {
	ints := make([]int, len(s))
	var err error
	for i, e := range s {
		ints[i], err = strconv.Atoi(e)
		if err != nil {
			log.Fatal(err.Error())
		}
	}
	return ints
}

Python: from collections import namedtuple
import heapq

Edge = namedtuple('Edge', ('fr', 'to', 'cost'))
inf = int(1e9)


def bellman_ford(n, start, edges):
    dists = [inf for _ in range(n)]
    dists[start] = 0
    while True:
        updated = False
        for e in edges:
            if dists[e.fr] != inf and dists[e.fr] + e.cost < dists[e.to]:
                updated = True
                dists[e.to] = dists[e.fr] + e.cost

        if not updated:
            break

    return dists


def dijkstra(n, costs):
    dists = [inf for _ in range(n)]
    dists[0] = 0

    queue = []
    for (i, d) in enumerate(dists):
        heapq.heappush(queue, (d, i))

    while len(queue) > 0:
        d, i = heapq.heappop(queue)
        if d > dists[i]:
            continue

        for v in range(n):
            if v == i or costs[i][v] == inf:
                continue

            if dists[i] + costs[i][v] < dists[v]:
                dists[v] = dists[i] + costs[i][v]
                heapq.heappush(queue, (dists[v], v))

    return dists


def warshall_floyd(n, costs):
    for i in range(n):
        print(costs[i])

    dists = [[costs[i][j] for j in range(n)] for i in range(n)]

    for k in range(n):
        for i in range(n):
            for j in range(n):
                dists[i][j] = min(dists[i][j], dists[i][k] + dists[k][j])

    return dists


n = int(input())

m = [[inf if i != j else 0 for i in range(n)] for j in range(n)]
es = []
for i in range(n):
    fs = list(map(int, input().split()))
    ne = fs[1]
    for j in range(ne):
        v = fs[2+2*j]
        c = fs[2+2*j+1]
        m[i][v] = c
        es.append(Edge(i, v, c))


# d = bellman_ford(n, 0, es)
# d = dijkstra(n, m)
d = warshall_floyd(n, m)
for (i, di) in enumerate(d[0]):
    print(i, di)

Python: #coding: utf-8

inf = 1000000000


def dijkstra(s):
    d = [inf for i in range(n)]
    color = ["white" for i in range(n)]
    p = [-1 for i in range(n)]
    d[s] = 0

    while True:
        mincost = inf
        for i in range(n):
            if color[i] != "black" and d[i] < mincost:
                mincost = d[i]
                u = i
        if mincost == inf:
            break

        color[u] = "black"

        for v in range(n):
            if color[v] != "black" and mtrx[u][v] != False:
                if d[u] + mtrx[u][v] < d[v]:
                    d[v] = d[u] + mtrx[u][v]
                    p[v] = u
                    color[v] = "gray"
    return d

n = int(input())
mtrx = [[False for j in range(n)] for i in range(n)]
for i in range(n):
    data = list(map(int,input().split()))
    k = data[1]
    for num in range(k):
        mtrx[i][data[2+2*num]] = data[2+2*num+1]

d = dijkstra(0)

for i, num in enumerate(d):
    print(i,num)

Python: # ALDS1_12_V Single Source Shortest Path I
import sys

n = int(input())
G = [[float('inf')] * n for _ in range(n)]
for i in range(n):
    ukvc = list(map(int, sys.stdin.readline().strip().split()))
    u = ukvc[0]
    k = ukvc[1]

    for j in range(k):
        G[u][ukvc[2 + 2 * j]] = ukvc[3 + 2 * j]

p = [n] * n  # 親を保存するリスト　親ノードとしてあり得ない n を初期リストとする
c = ['white'] * n # 最小経路木への接続チェック　white 未接続　black 接続済
d = [float('inf')] * n  # ノード i までの最小経路を保存するリスト
d[0] = 0  # 根への距離は0とする
p[0] = -1  # 根の親は -1 とする
u = 0  # 次のループで最小経路木につなげるノード

while 'white' in c:
    c[u] = 'black'

    v = None
    minpath = float('inf')
    for i in range(n):
        d[i] = min(d[i], d[u] + G[u][i])
        if (d[i] < minpath) & (c[i] == 'white'):
            minpath = d[i]
            v = i
            p[i] = u

    if v is None:
        break

    u = v

for i in range(n):
    print('{} {}'.format(i, d[i]))

Python: def dijkstra(n,s):
    inf=float("inf")
    color=["white" for i in range(n)]
    D=[inf for i in range(n)]
    P=[0 for i in range(n)]
    M=[[inf for i in range(n)] for j in range(n)]

    for i in range(n):
        weight=list(map(int,input().split()))[2:]
        for j in range(len(weight)//2):
            M[i][weight[2*j]]=weight[2*j+1]

    D[s]=0
    P[s]=-1

    while 1:
        cost,u=inf,0
        for i in range(n):
            if color[i]!="black" and D[i]<cost:
                cost=D[i]
                u=i

        if cost==inf:break

        color[u]="black"

        for i in range(n):
            if color[i]!="black" and M[u][i]!=inf:
                if D[u]+M[u][i]<D[i]:
                    D[i]=D[u]+M[u][i]
                    color[i]="gray"
                    P[i]=u

    return D


n=int(input())
distant=dijkstra(n,0)
for i in range(n):
    print(i,distant[i])

Python: def dijkstra():
    d[0] = 0
    color[0] = GRAY

    while True:
        minv = INF
        u = -1
        for i in range(N):
            if minv > d[i] and color[i] != BLACK:
                u = i
                minv = d[i]
        if u == -1:
            break
        color[u] = BLACK
        for i in range(N):
            if color[i] != BLACK and M[u][i] != INF:
                if d[i] > d[u] + M[u][i]:
                    d[i] = d[u] + M[u][i]
                    color[i] = GRAY

INF = 10 ** 18
WHITH = 0
GRAY = 1
BLACK = 2
N = int(input())
M = [[INF for _ in range(N)] for _ in range(N)]
d = [INF] * N
color = [WHITH] * N

for i in range(N):
    lst = list(map(int, input().split()))
    for j in range(lst[1]):
        M[lst[0]][lst[2 + (j * 2)]] = lst[3 + (j * 2)]

dijkstra()
for i in range(N):
    v = d[i]
    if v == INF:
        v = -1
    print(i, v)