Go: package main

import (
	"bufio"
	"bytes"
	"fmt"
	"io"
	"os"
	"strconv"
	"strings"
)

const (
	INFTY = 1 << 21
	NIL   = -1
)

const (
	WHITE = iota
	GRAY
	BLACK
)

type Graph [][]int

func (g *Graph) dikstra(n int) string {
	var (
		u, minv = 0, 0
	)

	d := make([]int, n)
	color := make([]int, n)

	for i := 0; i < n; i++ {
		d[i] = INFTY
		color[i] = WHITE
	}
	d[0] = 0
	color[0] = GRAY

	for {
		minv = INFTY
		u = -1
		for i := 0; i < n; i++ {
			if minv > d[i] && color[i] != BLACK {
				u = i
				minv = d[i]
			}
		}

		if u == -1 {
			break
		}

		color[u] = BLACK
		for v := 0; v < n; v++ {
			if color[v] != BLACK && (*g)[u][v] != INFTY {
				if d[v] > d[u]+(*g)[u][v] {
					d[v] = d[u] + (*g)[u][v]
					color[v] = GRAY
				}
			}
		}
	}

	var out bytes.Buffer
	for i := 0; i < n; i++ {
		out.WriteString(fmt.Sprintf("%d ", i))
		if d[i] == INFTY {
			out.WriteString(fmt.Sprintf("%d\n", -1))
			continue
		}
		out.WriteString(fmt.Sprintf("%d\n", d[i]))
	}

	return strings.TrimRight(out.String(), "\n")
}

func answer(reader io.Reader) string {
	sc := bufio.NewScanner(reader)
	sc.Split(bufio.ScanWords)

	sc.Scan()
	n, _ := strconv.Atoi(sc.Text())

	g := make(Graph, n)
	for i := 0; i < n; i++ {
		g[i] = make([]int, n)
		for j := 0; j < n; j++ {
			g[i][j] = INFTY
		}
	}

	for i := 0; i < n; i++ {
		sc.Scan()
		u, _ := strconv.Atoi(sc.Text())
		sc.Scan()
		k, _ := strconv.Atoi(sc.Text())

		for j := 0; j < k; j++ {
			sc.Scan()
			v, _ := strconv.Atoi(sc.Text())
			sc.Scan()
			c, _ := strconv.Atoi(sc.Text())

			g[u][v] = c
		}
	}

	return g.dikstra(n)
}

func main() {
	fmt.Println(answer(os.Stdin))
}

C++: #include<iostream>
using namespace std;
static const int MAX=100;
static const int INFTY=(1<<21);
static const int WHITE=0;
static const int GRAY=1;
static const int BLACK=2;
int n,M[MAX][MAX];
void dijkstra(){
int minv;
int d[MAX],color[MAX];
for(int i=0;i<n;i++){
d[i]=INFTY;
color[i]=WHITE;
}
d[0]=0;
color[0]=GRAY;
while(1){
minv=INFTY;
int u=-1;
for(int i=0;i<n;i++){
if(minv>d[i]&&color[i]!=BLACK){
u=i;
minv=d[i];
}
}
if(u==-1)break;
color[u]=BLACK;
for(int v=0;v<n;v++){
if(color[v]!=BLACK&&M[u][v]!=INFTY){
if(d[v]>d[u]+M[u][v]){
d[v]=d[u]+M[u][v];
color[v]=GRAY;
}
}
}
}
for(int i=0;i<n;i++){
cout<<i<<" "<<(d[i]==INFTY？-1:d[i])<<endl;
}
}
int main(){
cin>>n;
for(int i=0;i<n;i++){
for(int j=0;j<n;j++){
M[i][j]=INFTY;
}
}
int k,c,u,v;
for(int i=0;i<n;i++){
cin>>u>>k;
for(int j=0;j<k;j++){
cin>>v>>c;
M[u][v]=c;
}
}
dijkstra();
return 0;
}

C++: #include <iostream>
using namespace std;
static const int MAX=100;
static const int INFTY=(1<<21);
static const int WHITE=0;
static const int GRAY=1;
static const int BLACK=2;

int n,M[MAX][MAX];
int prim(){
    int minv;
    int d[MAX],color[MAX];
    for(int i=0;i<n;i++){
        d[i]=INFTY;
        color[i]=WHITE;
    }
    d[0]=0;
    color[0]=GRAY;
    while(1){
        minv=INFTY;
        int u=-1;
        for(int i=0;i<n;i++){
            if(minv>d[i]&&color[i]!=BLACK){
                u=i;
                minv=d[i];
            }
        }
        if(u==-1)break;
        color[u]=BLACK;
        for(int v=0;v<n;v++){
            if(color[v]!=BLACK&&M[u][v]!=INFTY){
             if(d[v]>d[u]+M[u][v]){
                 d[v]=d[u]+M[u][v];
                 color[v]=GRAY;
               }
            }
        }
    }
    for(int i=0;i<n;i++){
        cout<<i<<" "<<(d[i]==INFTY ? -1: d[i])<<endl;
    }
}
int main(){
    cin>>n;
    for(int i=0;i<n;i++){
        for(int j=0;j<n;j++){
            M[i][j]=INFTY;
        }
    }
    int k,c,u,v;
    for(int i=0;i<n;i++){
        cin>>u>>k;
        for(int j=0;j<k;j++){
            cin>>v>>c;
            M[u][v]=c;
        }
    }
    prim();
    return 0;
}

C++: // 単一始点最短経路 ( ダイクストラ法 )
#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<stack>
#include<algorithm>
#include<iostream>
#include<cmath>
#include<vector>

using namespace std;

static const int MAX = 100;
static const int INFTY = (1 <<21);
static const int WHITE = 0;
static const int GRAY = 1;
static const int BLACK = 2;

int n, M[MAX][MAX];

int Dijkstra()
{
    int u, minv;
    int d[MAX], p[MAX], color[MAX];

    for(int i = 0; i < n; i++)
    {
        d[i] = INFTY;
        p[i] = -1;
        color[i] = WHITE;
    }

    // 初期値の設定
    d[0] = 0;
    color[0] = GRAY;

    while(1)
    {
        minv = INFTY;
        // 次に移動するべき頂点
        u = -1;

        for(int i = 0; i < n; i++)
        {
            if( minv > d[i] && color[i] != BLACK )
            {
                // 未訪問の頂点の中で, 最小のコストを持つ辺を探索する
                u = i;
                minv = d[i];
            }
        }

        if( u == -1 )
        {
            // 最初全域木が完成した
            break;
        }

        color[u] = BLACK;

        for(int v = 0; v < n; v++)
        {
            if( color[v] != BLACK && M[u][v] != INFTY )
            {
                // u → v の辺の中で, 最小コストの辺のコストを記録する
                if( d[v] > d[u] + M[u][v] )
                {
                    // コストの記録
                    d[v] = d[u] + M[u][v];
                    // 頂点 v の親を記録する
                    p[v] = u;
                    // 訪問状態の記録
                    color[v] = GRAY;
                }
            }
        }
    }

    /*
    int sum = 0;

    for(int i = 0; i < n; i++)
    {
        if( p[i] != -1 )
        {
            // 最小コストの辺の和を求める
            sum += M[i][p[i]];
        }
    }
    */

    for(int i = 0; i < n; i++)
    {
        cout << i << " " << ( d[i] == INFTY ? -1 : d[i] ) << endl;
    }

    return 0;
}

int main(void)
{

    cin >> n;

    for(int i = 0; i < n; i++)
    {
        for(int j = 0; j < n; j++)
        {
            // 配列の初期化
            M[i][j] = INFTY;
        }
    }

    int k, c, u, v;

    for(int i = 0; i < n; i++)
    {
        cin >> u >> k;

        for(int j = 0; j < k; j++)
        {
            cin >> v >> c;

            M[u][v] = c;
        }
    }

    Dijkstra();

    return 0;

}

C++: #include <iostream>
#include <algorithm>
#include <cmath>
#include <cstdio>
using namespace std;
#define MAX 10000000

int b[110];
struct edge{int from, to, cost;};

int solve(edge a[10010], int n, int nn){
	b[0] = 0;
	while(1){
		int update = 0;
		for(int i = 0;i < nn;i++){
			if(b[a[i].from] != MAX && b[a[i].to] > b[a[i].from] + a[i].cost){
				b[a[i].to] = b[a[i].from] + a[i].cost;
				update = 1;
			}
		}
		if(update == 0)break;
	}
	return 0;
}

int main(){
	int n, nn = 0;
	edge a[10010];
	fill(b, b+110, MAX);
	cin >> n;
	for(int i = 0;i < n;i++){
		int u, k, c, d;
		cin >> u >> k;
		for(int j = 0;j < k;j++){
			cin >> c >> d;
			a[nn].from = u;
			a[nn].to = c;
			a[nn++].cost = d;
		}
	}
	
	solve(a, n, nn);
	for(int i = 0;i < n;i++){
		cout << i << " " << b[i] << endl;
	}
	
	return 0;
}
/*
5
0 3 2 3 3 1 1 2
1 2 0 2 3 4
2 3 0 3 3 1 4 1
3 4 2 1 0 1 1 4 4 3
4 2 2 1 3 3
*/