Go: package main

import (
	"fmt"
	"container/heap"
)

type Node struct {
	Id int
	Dis int
}

type PriorityQueue []*Node

func (pq PriorityQueue) Len() int { return len(pq) }

func (pq PriorityQueue) Less(i, j int) bool {
	return pq[i].Dis < pq[j].Dis
}

func (pq PriorityQueue) Swap(i, j int) {
	pq[i], pq[j] = pq[j], pq[i]
}

func (pq *PriorityQueue) Push(x interface{}) {
	*pq = append(*pq, x.(*Node))
}

func (pq *PriorityQueue) Pop() interface{} {
	n := len(*pq)
	pop := (*pq)[n-1]
	*pq = (*pq)[0:n-1]
	return pop
}

func main() {
	var n int
	fmt.Scan(&n)

	g := make([][]int, n)
	c := make([][]int, n)
	pq := make(PriorityQueue, 0, n)
	d := make([]int, n)
	for i := 0; i < n; i++ {
		var u,k int
		fmt.Scan(&u)
		fmt.Scan(&k)
		g[u] = make([]int, k)
		c[u] = make([]int, k)
		for j := 0; j < k; j++ {
			fmt.Scan(&g[u][j])
			fmt.Scan(&c[u][j])
		}

		if u == 0 {
			d[u] = 0
		} else {
			d[u] = 1 << 30
		}
		pq.Push(&Node{u, d[u]})
	}
	heap.Init(&pq)

	for pq.Len() > 0 {
		node := heap.Pop(&pq).(*Node)
		for i := 0; i < len(g[node.Id]); i++ {
			nextId := g[node.Id][i]
			nextDis := node.Dis + c[node.Id][i]
			if nextDis < d[nextId] {
				d[nextId] = nextDis
				heap.Push(&pq, &Node{nextId, nextDis})
			}
		}
	}

	for i := 0; i < n; i++ {
		fmt.Println(i, d[i])
	}
}

C++: #include<iostream>
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define rep(i,n) for(int i=0;i<n;i++)

/* 大文字を小文字に変換 */
char tolower(char c) {return (c + 0x20);}
/* 小文字を大文字に変換 */
char toupr(char c) {return (c - 0x20);}

// if('A'<=s[i] && s[i]<='Z') s[i] += 'a'-'A';

/*
string s = "abcdefg"
s.substr(4) "efg"
s.substr(0,3) "abc"
s.substr(2,4) "cdef"
*/
static const int MAX_N = 110;
static const int WHITE=0, GRAY=1, BLACK=2;
static const int INF = pow(10,8);

int color[MAX_N], M[MAX_N][MAX_N], d[MAX_N], p[MAX_N];
int N;

void dijkstra(int s){
    d[s] = 0; p[s] = -1;
    color[s] = GRAY;
    while(true){
        int minv = INF;
        int u = -1;
        rep(i,N){
            if(color[i] != BLACK && d[i] < minv){
                minv = d[i];
                u = i;
            }
        }

        if(u == -1) break;   // 全頂点への最短経路を調べ終えたということ

        color[u] = BLACK;
        rep(v,N){
            if(color[v] != BLACK && M[u][v] != INF){
                if(d[u]+M[u][v] < d[v]){
                    d[v] = d[u] + M[u][v];
                    p[v] = u;
                    color[v] = GRAY;
                }
            }
        }
    }
    rep(i,N){
        printf("%d %d\n", i, d[i]);
    }
}

int main()
{
    cin >> N;
    // 初期化
    rep(i,N){
        color[i] = WHITE; d[i] = INF;
        rep(j,N) M[i][j] = INF;
    }
    // 読み込み
    rep(i,N){
        int u, k; cin >> u >> k;
        rep(j,k){
            int v, c; cin >> v >> c;
            M[u][v] = c;
        }
    }
    dijkstra(0);
}

C++: #include <iostream>
using namespace std;
static const int MAX = 100;
static const int INFTY = (1 << 21);
static const int WHITE = 0;
static const int GRAY = 1;
static const int BLACK = 2;

int n, M[MAX][MAX];

void dijkstra()  {
  int minv;
  int d[MAX], color[MAX];
  
  for (int i = 0; i < n; i++)  {
    d[i] = INFTY;
    color[i] = WHITE;
  }
  
  d[0] = 0;
  color[0] = GRAY;
  while ( 1)  {
    minv = INFTY;
    int u = -1;
    for ( int i = 0; i < n; i++)  {
      if (minv > d[i] && color[i] != BALCK )  {
        u = i;
        minv = d[i];
      }
    }
    if (u == -1)  break;
    color[u] = BLACK;
    for (int v = 0; v < n; v++)  {
      if (color[v] != BLACK && M[u][v] != INFTY)  {
        if (d[v] > d[u] + M[u][v] )  {
          d[v] = d[u] + M[u][v];
          color[v] = GRAY;
        }
      }
    }
  }

  for (inti = 0; i < n; i++)  {
    cout << i << " " << ( d[i] == INFTY ? -1 : d[i]) << endl;
  }
}

int main()  {
  cin >> n;
  for (int i = 0; i < n; i++)  {
    for (int j = 0; j < n; j++)  {
      M[i][j] = INFTY;
    }
  }
  
  int k, c, u, v;
  for (int i = 0; i < n; i++)  {
    cin >> u >> k;
    for (int j = 0; j < k; j++)  {
      cin >> v >> c;
      M[u][v] = c;
    }
  }
 
  dijkstra();
  
  return 0;
}

C++: #include <iostream>
using namespace std;

const int MAX = 100;
const int INFINITY = 2 << 21;
int n;
int G[MAX][MAX];
int distances[MAX];
int states[MAX];

void dijkstra() {
  int id = 0;
  distances[id] = 0;

  while (1) {
    int min = INFINITY;

    for (int i = 0; i < n; i++) {
      if (states[i] == 0 && distances[i] < min) {
        min = distances[i];
        id = i;
      }
    }

    if (min == INFINITY) break;

    for (int i = 0; i < n; i++) {
      if (states[i] != 0 || G[id][i] == -1) continue;
      if (distances[id] + G[id][i] < distances[i]) {
        distances[i] = distances[id] + G[id][i];
      }
    }

    states[id] = 1;
  }

  for (int i = 0; i < n; i++) {
    cout << i << " " << (distances[i] == INFINITY ? -1 : distances[i]) << endl;
  }
}

int main() {
  cin.tie(0);
  ios::sync_with_stdio(false);

  cin >> n;

  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) G[i][j] = INFINITY;
  }

  int u, k, v, c;
  for (int i = 0; i < n; i++) {
    distances[i] = INFINITY;
    states[i] = 0;
    cin >> u >> k;
    for (int j = 0; j < k; j++) {
      cin >> v >> c;
      G[i][v] = c;
    }
  }

  dijkstra();

  return 0;
}

C++: #include <iostream>
#include <cstdio>
#include <cmath>
#include <algorithm>
// N 为邻接矩阵的大小
#define N 101
#define WHITE 0
#define GRAY 1
#define BLACK 2
#define INFTY 1 << 21

using namespace std;

int color[N], d[N], p[N], M[N][N];

void dijkstra (int s, int n) {
  for (int i = 0; i < n; i++) {
    color[i] = WHITE;
    d[i] = INFTY;
  }

  d[s] = 0;
  p[s] = -1;

  while (1) {
    int mincost = INFTY, u;

    for (int i = 0; i < n; i++) {
      if (color[i] != BLACK && d[i] < mincost) {
        mincost = d[i];
        u = i;
      }
    }

    if (mincost == INFTY)
      break;

    color[u] = BLACK;
    
    for (int v = 0; v < n; v++) {
      if (color[v] != BLACK && M[u][v] >= 0 && M[u][v] < INFTY) {

        if (d[u] + M[u][v] < d[v]) {
          d[v] = d[u] + M[u][v];
          p[v] = u;
          color[v] = GRAY;
        }        
      }
    }
  }
}

int main () {
  int n, u, v, degree, cost;
  
  cin >> n;

  for (int i = 0; i < n; i++)
    for (int j = 0; j < n; j++)
      M[i][j] = INFTY;

  for (int i = 0; i < n; i++) {
    cin >> u >> degree;
    
    for (int j = 0; j < degree; j++) {
      cin >> v >> cost;

      M[u][v] = cost;
    }
  }

  dijkstra(0, n);

  for (int i = 0; i < n; i++)
    cout << i << " " << d[i] << endl;

  return 0;
}