Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

const (
	MAX_N      = 200
	MAX_WEIGHT = 2000
)

type Edge struct {
	start  int
	end    int
	weight int
}

type ShortestInfo struct {
	edges    []Edge
	shortest int
}

func main() {
	sc := bufio.NewScanner(os.Stdin)
	sc.Split(bufio.ScanWords)

	n, err := nextInt(sc)
	if err != nil {
		panic(err)
	}

	shortestList := make([]ShortestInfo, n)
	for i := 1; i < n; i++ {
		shortestList[i] = ShortestInfo{edges: []Edge{}, shortest: MAX_N*MAX_WEIGHT + 1}
	}

	adjacentMatrix := make([][]int, n)
	for i := 0; i < n; i++ {
		adjacentMatrix[i] = make([]int, n)
		for j := 0; j < n; j++ {
			v, err := nextInt(sc)
			if err != nil {
				panic(err)
			}
			adjacentMatrix[i][j] = v
		}
	}

	mst([]int{1}, shortestList, adjacentMatrix)
	fmt.Println(shortestList)
	fmt.Println(calculateMinWeight(shortestList))
}

func calculateMinWeight(shortestList []ShortestInfo) int {
	visitedList := make([]bool, len(shortestList))
	visitedList[0] = true
	sumWeight := 0
	for !visitedAll(visitedList) {
		shortestInfo := shortestList[0]
		shortestList = shortestList[1:]
		edges := shortestInfo.edges
		for _, edge := range edges {
			if !visitedList[edge.end-1] {
				visitedList[edge.end-1] = true
				sumWeight += edge.weight
			}
		}
	}
	return sumWeight
}

func visitedAll(visitedList []bool) bool {
	for _, v := range visitedList {
		if !v {
			return false
		}
	}
	return true
}

func mst(nodeStack []int, shortestList []ShortestInfo, adjacentMatrix [][]int) {
	for len(nodeStack) > 0 {
		currentNode := nodeStack[0]
		nodeStack = nodeStack[1:]
		currentShortest := getShortest(currentNode, shortestList)
		adjacents := findAdjacents(currentNode, adjacentMatrix)
		for i := 0; i < len(adjacents); i++ {
			adj := adjacents[i]
			s := getShortest(adj.end, shortestList)
			if currentShortest.shortest+adj.weight < s.shortest || (currentShortest.shortest+adj.weight == s.shortest && len(currentShortest.edges)+1 > len(s.edges)) {
				setShortest(adj.end, adj, currentShortest, shortestList)
				nodeStack = append(nodeStack, adj.end)
			}
		}
	}
}

func getShortest(node int, shortestList []ShortestInfo) ShortestInfo {
	return shortestList[node-1]
}

func setShortest(node int, edge Edge, currentShortest ShortestInfo, shortestList []ShortestInfo) {
	newEdges := make([]Edge, len(currentShortest.edges)+1)
	for i := 0; i < len(newEdges)-1; i++ {
		newEdges[i] = currentShortest.edges[i]
	}
	newEdges[len(newEdges)-1] = edge
	shortestInfo := ShortestInfo{edges: newEdges, shortest: currentShortest.shortest + edge.weight}
	shortestList[node-1] = shortestInfo
}

func findAdjacents(currentNode int, adjacentMatrix [][]int) []Edge {
	adjacents := adjacentMatrix[currentNode-1]
	edges := []Edge{}
	for i, v := range adjacents {
		if v > 0 {
			edges = append(edges, Edge{start: currentNode, end: i + 1, weight: v})
		}
	}
	return edges
}

func nextInt(sc *bufio.Scanner) (int, error) {
	sc.Scan()
	return strconv.Atoi(sc.Text())
}

Python: # https://onlinejudge.u-aizu.ac.jp/courses/lesson/1/ALDS1/12/ALDS1_12_A
# 本よりこっちのほうがぶっちゃけわかりやすい http://www.deqnotes.net/acmicpc/prim/
# 螺旋本ではダイクストラとの違いをあまり解説していないが、違いはダイクストラのところで考えよう
# 記号は本に合わせる。
# 制約条件によりノードはたかだか100なのでオーダーを木にせずにナイーブに実装できる。本ではdを導入することにより計算量を少し削減している

INF = 10**5
# load data
N = int(input())
M = []  # 隣接行列
Color = []  # 訪問状態を記録 0:未訪問, 1:訪問経験あり, 2:訪問済み(用済み) #そうはこいつが2になっているノードはMST
D = []  # 本で言うd #こいつの役割はP299の図を追うとわかりやすい #MSTに隣接しているノードへのコストをノードのところに記録する
P = []  # 本で言うp # MSTにおける親を記録

for _ in range(N):
    Color.append(0)  # ノードはすべて未訪問
    D.append(INF)  # 無限で初期化しておく
    P.append(None)
    M.append([x if x != -1 else INF for x in map(int, input().split())])

# primのアルゴリズムを適応する
# ノード0からMSTを構築していく #まずはノード0をMSTに追加する
D[0] = 0
P[0] = None  # 親が存在しないことをNoneで示す

while True:  # MSTができるまで繰り返す ちなみにループの一周目は0をMSTに追加するところから始まる
    # MSTに隣接するノードへのpathの中で一番小さなコストを見つける、ついでにそのノード番号も
    min_cost = INF
    for i in range(N):
        if Color[i] != 2 and D[i] < min_cost:  # 訪問済みかつ最小値を更新したら
            min_cost = D[i]
            u = i  # uにはコストが一番小さい時のノードが追加される

    if min_cost == INF:
        break  # つながりがもうない

    Color[u] = 2  # つながるのに一番コストの小さい訪問済みに(MSTに追加)する

    for v in range(N):
        if Color[v] != 2 and M[u][v] != INF:  # MSTに追加されていなくてかつ、uとつながっている
            if M[u][v] < D[v]:  # 新たに追加したノードuからvに行くほうがコストが小さいならばそれをメモする
                D[v] = M[u][v]
                P[v] = u  # vの親の候補としてuを代入しておく(だいぶ無駄では？)
                Color[v] = 1  # 一度見たことあるのはgrayにしておくが、ぶっちゃけ意味はない

# これにてPに木構造が入ったのでこれをもとにコストを計算すれば良い
# ぶっちゃけこの操作は上のwhileに組み込み可能なんだけどあえてね
ans = 0
for i, p in enumerate(P[1:], start=1):
    ans += M[i][p]

print(ans)

Python: MAX = 100
INFTY = 1 << 21
WHITE = 0
GRAY = 1
BLACK = 2
d = [INFTY for i in range(n)]
p = [-1 for i in range(n)]
color = [WHITE for i in range(n)]

n = int(input())
M = [[map(int, input().split()) for i in range(n)] for j in range(n)]
for i in range(n):
    for j in range(n):
        if (M[i][j] == -1):
            M[i][j] = INFTY

def prim():
    global M, d, p, color
    d[0] = 0
    while(1):
        minv = INFTY
        u = -1
        for i in range(n):
            if (minv > d[i] and color[i] != BLACK):
                u = i
                minv = d[i]
        if (u == -1):
            break
        color[u] = BLACK
        for v in range(n):
            if (color[v] != BLACK and M[u][v] != INFTY):
                if (d[v] > M[u][v]):
                    d[v] = M[u][v]
                    p[v] = u
                    color[v] = GRAY
    
    _sum = sum([M[i][p[i]] for i in range(n) if (p[i] != -1)])
    return _sum

print(prim())

Python: # -*- coding: utf-8 -*-

"""Minimum Spanning Tree"""

import sys
import os
import pprint

DEBUG = False

#fd = os.open('ALDS1_12_A.txt', os.O_RDONLY)
#os.dup2(fd, sys.stdin.fileno())

n = int(input())

# n x n matrix
M = []
for i in range(n):
    l = list(map(int, input().split()))
    M.append(l)

# Prim's Algorithm
INF = 1000000
visited = [False] * n
parent = [None] * n

# 0 is in T (Tree)
parent[0] = None

# distance between T and T-V
distance = [INF] * n
distance[0] = 0

while True:
    min_dist = INF
    candidate_index = None
    for i in range(n):
        if not visited[i] and distance[i] < min_dist:
            min_dist = distance[i]
            candidate_index = i

    if candidate_index is None:
        break

    if DEBUG:
        print('accepted i', candidate_index)
    visited[candidate_index] = True
    distance[candidate_index] = -1  # done

    for i in range(n):
        if not visited[i] and M[candidate_index][i] != -1 and distance[i] > M[candidate_index][i]:
            distance[i] = M[candidate_index][i]
            parent[i] = candidate_index


# Trees length
_sum = 0
for i in range(n):
    if parent[i] is not None:
        d = M[i][parent[i]]
        _sum += d
print(_sum)

Python: n=int(input())
matrix=[list(map(int,input().split())) for _ in range(n)]
weight=[]
for x in range(n):
    for y in range(x,n):
        if matrix[x][y]>=0: weight.append((x,y,matrix[x][y]))
weight.sort(key=lambda x:x[2])
ans=0
p=[i for i in range(n)]

def root(x):
    path_to_root=[]
    while p[x]!=x:
        path_to_root.append(x)
        x=p[x]
    for node in path_to_root:
        p[node]=x
    return x
    
def is_same_set(x,y):
    return root(x)==root(y)
    
def unite(x,y):
    p[root(x)]=root(y)
        
for x,y,w in weight:
    if not is_same_set(x,y):
        unite(x,y)
        ans+=w
print(ans)