Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

var scanner = bufio.NewScanner(os.Stdin)

func nextString() string {
	scanner.Scan()
	return scanner.Text()
}

func nextInt() int {
	n, err := strconv.Atoi(nextString())
	if err != nil {
		fmt.Printf("strconv.Atoi failed: %v\n", err)
	}
	return n
}

var infty = 1000000000

type DirectedGraphNodeID int

type DirectedGraphNode struct {
	key         DirectedGraphNodeID
	adjacents   []*DirectedGraphNode
	costs       []int
	distance    int
	predecessor *DirectedGraphNode
}

func newDirectedGraph(nNodes int) *DirectedGraph {
	graph := DirectedGraph{}
	graph.nodes = make([]*DirectedGraphNode, nNodes)
	for i := 0; i < nNodes; i++ {
		node := DirectedGraphNode{}
		node.key = DirectedGraphNodeID(i)
		node.distance = infty
		graph.nodes[i] = &node
	}
	return &graph
}

type DirectedGraph struct {
	nodes []*DirectedGraphNode
}

func (g *DirectedGraph) setAdjacency(i, j DirectedGraphNodeID, cost int) {
	g.nodes[i].adjacents = append(g.nodes[i].adjacents, g.nodes[j])
	g.nodes[i].costs = append(g.nodes[i].costs, cost)
}

func (g *DirectedGraph) print() {
	for i := 0; i < len(g.nodes); i++ {
		node := g.nodes[i]
		key := node.key
		strings := []string{strconv.Itoa(int(key)), strconv.Itoa(node.distance)}
		for j := 0; j < len(node.adjacents); j++ {
			nodeJ := fmt.Sprintf("(%v, %v)", node.adjacents[j].key, node.costs[j])
			strings = append(strings, nodeJ)
		}
		fmt.Printf("%v\n", strings)
	}
}

func (g *DirectedGraph) relaxEdge(l, r *DirectedGraphNode, w int) {
	if r.distance > l.distance+w {
		// fmt.Printf("%v -> %v, %v\n", l.key, r.key, l.distance+w)
		r.distance = l.distance + w
		r.predecessor = l
	}
}

func main() {
	scanner.Split(bufio.ScanWords)

	nNodes := nextInt()
	graph := newDirectedGraph(nNodes)

	for i := 0; i < nNodes; i++ {
		iNode := DirectedGraphNodeID(nextInt())
		nAdjacent := nextInt()
		for j := 0; j < nAdjacent; j++ {
			jNode := DirectedGraphNodeID(nextInt())
			cost := nextInt()
			graph.setAdjacency(iNode, jNode, cost)
		}
	}

	graph.nodes[0].distance = 0
	for iNode := 0; iNode < nNodes; iNode++ {
		for iLeft := 0; iLeft < len(graph.nodes); iLeft++ {
			nodeLeft := graph.nodes[iLeft]
			for iRight := 0; iRight < len(nodeLeft.adjacents); iRight++ {
				nodeRight := nodeLeft.adjacents[iRight]
				cost := nodeLeft.costs[iRight]
				graph.relaxEdge(nodeLeft, nodeRight, cost)
			}
		}
	}

	// graph.print()

	for iNode := 0; iNode < len(graph.nodes); iNode++ {
		node := graph.nodes[iNode]
		fmt.Println(node.key, node.distance)
	}
}

C++: #include <bits/stdc++.h>
using namespace std;

const int MAX=10005;
int state[MAX],N,D[MAX];
vector<pair<int,int>> S[MAX];
priority_queue<pair<int,int>> Q;

void dijkstra(){
    int cnt=1;
    for(int i=0;i<N;i++){
        state[i]=0;
        D[i]=10000000;
    }
    state[0]=1;
    D[0]=0;
    for(int i=0;i<S[0].size();i++){
        Q.push(make_pair(-S[0][i].second,S[0][i].first));
        D[S[0][i].first]=min(D[S[0][i].first],D[0]+S[0][i].second);
    }
    while(1){
        int a=Q.top().second;
            if(state[a]==0){
            Q.pop();
            state[a]=1;
            for(int i=0;i<S[a].size();i++){
                if(state[S[a][i].first]==0){
                    Q.push(make_pair(-(D[a]+S[a][i].second),S[a][i].first));
                    D[S[a][i].first]=min(D[S[a][i].first],D[a]+S[a][i].second);
                }
            }
                cnt++;
        }
        else Q.pop();
        if(cnt==N) break;
    }
    return;
}


int main(){
    
    cin>>N;
    for(int i=0;i<N;i++){
        int l,a;cin>>l>>a;
        for(int j=0;j<a;j++){
            int b,c;cin>>b>>c;
            S[i].push_back(make_pair(b,c));
        }
    }
    dijkstra();
    for(int i=0;i<N;i++){
        cout<<i<<" "<<D[i]<<endl;
    }
}

C++: #include <iostream>
#include <algorithm>
#include <vector>
#include <utility>
#include <queue>

using namespace std;
 
vector<int> dijkstra(int s, vector<vector<pair<int, int> > >& G) {
	const int INF = 1e9;
	const int N = G.size();
	vector<int> cost(N, INF);
	priority_queue<pair<int, int>, vector<pair<int, int> >, greater<pair<int, int> > > pq;
	cost[s] = 0;
	pq.push(make_pair(0, s));
	while (!pq.empty()) {
		pair<int, int> p = pq.top(); pq.pop();
		int now = p.second;
		if (cost[now] < p.first) continue;
		for (auto next : G[now]) {
			int nv = next.first, nw = next.second;
			if (cost[nv] > cost[now] + nw) {
				cost[nv] = cost[now] + nw;
				pq.push(make_pair(cost[nv], nv));
			}
		}
	}
	return cost;
}

int main() {
	int n; cin >> n;
	vector<vector<pair<int, int> > > G(n);
	for (int i = 0; i < n; ++i) {
		int u, k; cin >> u >> k;
		while (k--) {
			int v, c; cin >> v >> c;
			G[u].push_back(make_pair(v, c));
		}
	}
	vector<int> ans(dijkstra(0, G));
	for (int i = 0; i < n; ++i)
		cout << i << " " << ans[i] << endl;

	return 0;
}

C++: #include <iostream>
using namespace std;
static const int MAX = 100;
static const int INFTY = (1 << 21);
static const int WHITE = 0;
static const int GRAY = 1;
static const int BLACK = 2;

int n, M[MAX][MAX];

void dijkstra()
{
    int minv; // 最小のコスト
    int d[MAX], color[MAX]; // d[n]は始点からnまでの最短コスト，color[v]はvの訪問状態

    for (int i = 0; i < n; i++) {
        // 最短コストと訪問状態の初期化
        d[i] = INFTY;
        color[i] = WHITE;
    }

    d[0] = 0; // 始点から始点までの最短コストは0
    color[0] = GRAY; // 始点を訪問済みにする
    while (1) {
        minv = INFTY; // 最小コストをINFで初期化
        int u = -1; // 現在の頂点を初期化
        for (int i = 0; i < n; i++) {
            if (minv > d[i] && color[i] != BLACK) { // 訪問するコストが最小コストより小さく，未訪問のとき
                u = i; // 現在の頂点を変える
                minv = d[i]; // 最小コストを変える
            }
        }
        if (u == -1) {
            break;
        }
        color[u] = BLACK; // 最小コストの頂点へ進み，訪問済みとする
        for (int v = 0; v < n; v++) {
            if (color[v] != BLACK && M[u][v] != INFTY) { // vに訪問済みでなくu->vへのコストがINFでないとき
                if (d[v] > d[u] + M[u][v]) { // 「vへの最小コスト」より「現在までのコストと現在地からvまでのコストを加えたもの」のほうが小さい時
                    d[v] = d[u] + M[u][v]; // vまでのコストを更新
                    color[v] = GRAY; // vへ訪問済みとする
                }
            }
        }
    }
    for (int i = 0; i < n; i++) {
        cout << i << " " << (d[i] == INFTY ? -1 : d[i]) << endl;
    }
}

int main()
{
    cin >> n;
    //
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++) {
            M[i][j] = INFTY;
        }
    }

    int k, c, u, v;
    for (int i = 0; i < n; i++) {
        cin >> u >> k;
        for (int j = 0; j < k; j++) {
            cin >> v >> c;
            M[u][v] = c;
        }
    }

    dijkstra();

    return 0;
}

C++: #include <iostream>
#include <utility>
#include <vector>
#include <queue>
using namespace std;
#define INF 2000000000
int Min(int x,int y){
        return x>y?y:x;
}
int main(){
        int N;
        cin >> N;
        vector <vector <int> > adjancent(N,vector <int>(N,INF));
        for(int i=0 ; i<N ; i++ ){
                int n,degree,to,cost;
                cin >> n >> degree;
                for(int l=0 ; l<degree ; l++ ){
                        cin >> to >> cost;
                        adjancent[n][to]=cost;
                }
        }
        vector<int> dp(N,INF);
        dp[0]=0;
        bool sign=true;
        while(sign){
                sign=false;
                for(int now=0 ; now<N ; now++){
                        for(int i=0 ; i<N ; i++ ){
                                int tmp=dp[i];
                                dp[i]=Min(dp[i],dp[now]+adjancent[now][i]);
                                if(tmp!=dp[i])
                                        sign=true;
                        }
                }
        }
        for(int i=0 ; i<N ; i++ )
                cout <<i<<" "<<dp[i]<<endl;
        return 0;
}