Go: package main

import (
	"bufio"
	"container/heap"
	"fmt"
	"os"
)

type Item struct {
	value    int // The value of the item; arbitrary.
	priority int // The priority of the item in the queue.
	// The index is needed by update and is maintained by the heap.Interface methods.
	index int // The index of the item in the heap.
}
type PriorityQueue []*Item

func (pq PriorityQueue) Len() int { return len(pq) }
func (pq PriorityQueue) Less(i, j int) bool {
	return pq[i].priority < pq[j].priority
}
func (pq PriorityQueue) Swap(i, j int) {
	pq[i], pq[j] = pq[j], pq[i]
	pq[i].index = i
	pq[j].index = j
}
func (pq *PriorityQueue) Push(x interface{}) {
	n := len(*pq)
	item := x.(*Item)
	item.index = n
	*pq = append(*pq, item)
}
func (pq *PriorityQueue) Pop() interface{} {
	old := *pq
	n := len(old)
	item := old[n-1]
	item.index = -1 // for safety
	*pq = old[0 : n-1]
	return item
}

type Q struct {
	pq *PriorityQueue
	ds map[int]int // It has always same value as pq. For random access.
}

func newQ() *Q {
	pq := new(PriorityQueue)
	heap.Init(pq)
	return &Q{
		pq: pq,
		ds: make(map[int]int),
	}
}
func (q *Q) pop() (u, d int) {
	item := heap.Pop(q.pq).(*Item)
	delete(q.ds, item.value)
	return item.value, item.priority
}
func (q *Q) get(u int) (int, bool) { // returns d
	d, ok := q.ds[u]
	return d, ok
}
func (q *Q) set(u, d int) {
	q.ds[u] = d
	for _, item := range *q.pq {
		if item.value != u {
			continue
		}

		item.priority = d
		heap.Fix(q.pq, item.index)
		return
	}
	heap.Push(q.pq, &Item{
		priority: d,
		value:    u,
	})
}
func (q *Q) len() int {
	return len(q.ds)
}

func main() {
	r := bufio.NewReader(os.Stdin)

	var n int
	fmt.Fscan(r, &n)
	cs := make([]map[int]int, n) // []v_i -> c_i
	for h := 0; h < n; h++ {
		var u, k int
		fmt.Fscan(r, &u, &k)
		m := make(map[int]int)
		for i := 0; i < k; i++ {
			var v, c int
			fmt.Fscan(r, &v, &c)
			m[v] = c
		}

		cs[u] = m
	}

	q := newQ()
	q.set(0, 0)
	visited := make(map[int]struct{})
	out := make([]int, n)

	for q.len() > 0 {
		u, d := q.pop()
		for uu, c := range cs[u] {
			// Consider the connection between u and uu.
			if _, ok := visited[uu]; ok {
				continue
			}
			dd := d + c
			if d, ok := q.get(uu); !ok || d > dd {
				q.set(uu, dd)
			}
		}

		out[u] = d
		visited[u] = struct{}{}
	}

	for u, d := range out {
		fmt.Println(u, d)
	}
}

Python: from collections import namedtuple
import heapq

Edge = namedtuple('Edge', ('fr', 'to', 'cost'))
inf = int(1e9)


def bellman_ford(n, start, edges):
    dists = [inf for _ in range(n)]
    dists[start] = 0
    while True:
        updated = False
        for e in edges:
            if dists[e.fr] != inf and dists[e.fr] + e.cost < dists[e.to]:
                updated = True
                dists[e.to] = dists[e.fr] + e.cost

        if not updated:
            break

    return dists


def dijkstra(n, costs):
    dists = [inf for _ in range(n)]
    dists[0] = 0

    queue = []
    for (i, d) in enumerate(dists):
        heapq.heappush(queue, (d, i))

    while len(queue) > 0:
        d, i = heapq.heappop(queue)
        if d > dists[i]:
            continue

        for v in range(n):
            if v == i or costs[i][v] == inf:
                continue

            if dists[i] + costs[i][v] < dists[v]:
                dists[v] = dists[i] + costs[i][v]
                heapq.heappush(queue, (dists[v], v))

    return dists


def warshall_floyd(n, costs):
    dists = [[costs[i][j] if i != j else 0 for i in range(n)] for j in range(n)]

    for k in range(n):
        for i in range(n):
            for j in range(n):
                dists[i][j] = min(dists[i][j], dists[i][k] + dists[k][j])

    return dists


n = int(input())

m = [[inf for _ in range(n)] for _ in range(n)]
es = []
for i in range(n):
    fs = list(map(int, input().split()))
    ne = fs[1]
    for j in range(ne):
        v = fs[2+2*j]
        c = fs[2+2*j+1]
        m[i][v] = c
        es.append(Edge(i, v, c))


# d = bellman_ford(n, 0, es)
# d = dijkstra(n, m)
d = warshall_floyd(n, m)
for (i, di) in enumerate(d[0]):
    print(i, di)

Python: n = int(input())

graph = [[] for i in range(n)]

for i in range(n):
    a = list(map(int, input().split()))
    for j in range(a[1]):
        graph[a[0]].append(a[2+j*2:4+j*2])  #[頂点, cost]

memo = [10**10 for i in range(n)]
memo[0] = 0

import heapq
q = []
heapq.heappush(q, (0, 0))   #(それまでのcost, 頂点)
while len(q) != 0:
    top = heapq.heappop(q)
    for g in graph[top[1]]:
        cost = top[0] + g[1]
        if memo[g[0]] > cost:
            memo[g[0]] = cost
            heapq.heappush(q, (cost, g[0]))

for i in range(n):
    print(i, memo[i])

Python: inf = float("inf")


class Node():

    def __init__(self, _id):
        self.id = _id
        self.d = inf
        self.pi = None
        self.color = 0
        self.adj = {}

    def input_data(self, data):
        k = data[0]
        for i in range(k):
            self.adj[G[data[2 * i + 1]]] = data[2 * i + 2]

    def __hash__(self):
        return hash(self.id)

def dijkstra():
    while True:
        mincost = inf
        for i in G:
            if i.color != 1 and i.d < mincost:
                mincost = i.d
                u = i
        if mincost == inf:
            break
        u.color = 1
        for v in u.adj.keys():
            if v.color != 1 and u.d + u.adj[v] < v.d:
                v.pi = u
                v.d = u.d + u.adj[v]

if __name__ == "__main__":
    n = int(input())
    G = [Node(i) for i in range(n)]
    for _ in range(n):
        data = [int(i) for i in input().split()]
        G[data[0]].input_data(data[1:])
        if data[0] == 0:
            G[data[0]].d = 0
    dijkstra()
    [print(i.id, i.d) for i in G]

Python: #!/usr/bin/env python3
import sys
import heapq
input = lambda: sys.stdin.readline()[:-1]
sys.setrecursionlimit(10**8)
inf = float('inf')
mod = 10**9+7

n=int(input())
G=[[] for i in range(n)]
for _ in range(n):
    inp = list(map(int,input().split()))
    u,k=inp[:2]
    for i in range(k):
        G[u].append((inp[2+2*i],inp[3+2*i]))

def disktra(g,s):
    n=len(g)
    dist = [inf]*n
    dist[s] = 0
    hq=[]
    heapq.heappush(hq,(dist[s],s))
    while hq:
        cost,u =heapq.heappop(hq)
        if dist[u] < cost:
            continue
        for v,c in g[u]:
            if dist[v] <= dist[u] +c:
                continue
            dist[v] = dist[u] + c
            heapq.heappush(hq,(dist[v],v))
    return dist

d=disktra(G,0)
for i in range(n):
    print(i,d[i])

Python: # Single Source Shortest Path 1
INF = 10**10
N = int(input())
W = [[INF]*(N) for _ in [0]*(N)]

for _ in [0]*N:
    v, k, *A = map(int, input().split())
    for u, c in zip(*[iter(A)]*2):
        W[v][u] = c

S = set()
d = [INF]*N

d[0] = 0
while len(S) < N:
    dmin = INF
    v = -1
    for i in range(N):
        if i not in S and d[i] < dmin:
            dmin = d[i]
            v = i

    S.add(v)
    for u, w in enumerate(W[v]):
        if d[v]+w < d[u]:
            d[u] = d[v]+w

for i in range(N):
    print(i, d[i])

Python: import heapq
N=int(input())
ad_li=[[]for i in range(N)]
for i in range(N):
    nums=list(map(int,input().split()))
    f=nums[0]
    for j in range(nums[1]):
        t=nums[j*2+2]
        c=nums[j*2+3]
        ad_li[f].append([t,c])

memo=[1E18 for i in range(N)]
memo[0]=0
qu=[]
heapq.heappush(qu,(0,0))
while len(qu)!=0:
    atop=heapq.heappop(qu)
    for ne in ad_li[atop[1]]:
        next_cost=atop[0]+ne[1]
        if(memo[ne[0]]>next_cost):
            memo[ne[0]]=next_cost
            heapq.heappush(qu,(next_cost,ne[0]))
for i in range(N):
    print(i,memo[i])