Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

const BIG_COST = 200000

const (
	ST_NOT_YET = iota
	ST_JOINED
)

func main() {
	sc := bufio.NewScanner(os.Stdin)
	sc.Split(bufio.ScanWords)

	nNodes := scanInt(sc)

	costs := make([][]int, nNodes)
	graph := make([][]int, nNodes)

	states := make([]int, nNodes)
	costSums := make([]int, nNodes)

	for i := 0; i < nNodes; i++ {
		costs[i] = make([]int, nNodes)
		costSums[i] = BIG_COST
	}

	for i := 0; i < nNodes; i++ {
		u := scanInt(sc)
		k := scanInt(sc)
		graph[u] = make([]int, k)
		for d := 0; d < k; d++ {
			v := scanInt(sc)
			graph[u][d] = v
			costs[u][v] = scanInt(sc)
		}
	}

	costSums[0] = 0
	for {
		minCost := BIG_COST
		var u int

		for i, cost := range costSums {
			if states[i] != ST_JOINED && cost < minCost {
				minCost = cost
				u = i
			}
		}

		if minCost == BIG_COST {
			break
		}

		states[u] = ST_JOINED

		for _, v := range graph[u] {
			cost := minCost + costs[u][v]
			if cost < costSums[v] {
				costSums[v] = cost
			}
		}
	}

	w := bufio.NewWriter(os.Stdout)
	for i, cost := range costSums {
		fmt.Fprintf(w, "%d %d\n", i, cost)
	}
	w.Flush()
}

func scanInt(sc *bufio.Scanner) int {
	sc.Scan()
	v, _ := strconv.Atoi(sc.Text())
	return v
}

C++: #include <bits/stdc++.h>
using namespace std;

#define FOR(i,a,b) for(int i=(a);i<(b);++i)
#define REP0(i,n) for(int i=0, i##_len=(n); i<i##_len; ++i)
#define REP1(i,n) for(int i=1, i##_len=(n); i<=i##_len; ++i)
#define RREP0(i,n) for(int i=n-1; i>=0; --i)
#define RREP1(i,n) for(int i=n; i>=1; --i)

#define SORT(c) sort((c).begin(),(c).end())
#define whole(f,x,...) ([&](decltype((x)) whole) { return (f)(begin(whole), end(whole), ## __VA_ARGS__); })(x)
#define PB push_back
#define MP make_pair
#define SZ(a) int((a).size())
#define EXIST(s,e) ((s).find(e)!=(s).end())
#define CLR(a) memset((a), 0 ,sizeof(a))

inline int toInt(string s) {int v; istringstream sin(s);sin>>v;return v;}
template<class T> inline string toString(T x) {ostringstream sout;sout<<x;return sout.str();}
int gcd(int a,int b){return b?gcd(b,a%b):a;}
int dx[4]={1,0,-1,0};
int dy[4]={0,1,0,-1};

typedef long long LL;
typedef vector<int> VI;
typedef vector<VI> VVI;
typedef vector<string> VS;
typedef pair<int, int> PII;

const int INTINF = 2147483647;
const LL LLINF = 9223372036854775807;
const double EPS = 1e-10;
const double PI  = acos(-1.0);
const int WHITE = 0;
const int GRAY = 1;
const int BLACK = 2;
const int MAX = 100;
int n, M[MAX][MAX];
int d[MAX], color[MAX];

struct init{
    init(){
        cin.tie(0); ios::sync_with_stdio(0); cout<<fixed<<setprecision(20);
    };
} init;


void dijkstra(){
  int minv;

  REP0(i,n){
    d[i] = INTINF;
    color[i] = WHITE;
  }

  d[0] = 0;
  color[0] = GRAY;

  while (1) {
    minv = INTINF;
    int u = -1;
    // 未確定頂点のうち最も近いもの := u を選んで確定
    REP0(i,n){
      if ( minv > d[i] && color[i] != BLACK ){
        u = i;
        minv = d[i];
      }
    }
    if ( u == -1 ) break;
    color[u] = BLACK;
    // uから到達可能な未確定頂点を選んで最短距離を更新していく
    REP0(v,n){
      if ( color[v] != BLACK && M[u][v] != INTINF) {
        if ( d[v] > d[u] + M[u][v] ) {
          d[v] = d[u] + M[u][v];
          color[v] = GRAY;
        }
      }
    }
  }
}



void input() {
  std::cin >> n;
  REP0(i,n) REP0(j,n) M[i][j] = INTINF;

  int u, k, v, c;
  REP0(i,n){
    std::cin >> u >> k;
    REP0(j,k){
      std::cin >> v >> c;
      M[u][v] = c;
    }
  }
}


void output(){
  REP0(i,n){
    std::cout << i << " " << ( d[i] == INTINF ? -1 : d[i] ) << '\n';
  }
}


int main(int argc, char const *argv[]) {
  input();
  dijkstra();
  output();
  return 0;
}

C++: #include<bits/stdc++.h>
using namespace std;
#define rp(i,j) for(long long i=0;i<j;i++)
#define rep(i,j,k) for(long long i=j;i<k;i++)
#define mod 1000000007
#define NIL -1
#define MAX 100
static const int INFTY=(1<<21);
typedef long long ll;
int n,u;
int M[MAX][MAX];
int d[MAX];
int color[MAX];
void dijkstra(){
    rp(i,n){
        d[i]=INFTY;
        color[i]=0;
    }
    d[0]=0;
    color[0]=1;
    while(1){
        int minv=INFTY;
        rp(i,n){
            if(color[i]!=2&&d[i]<minv){
                minv=d[i];
                u=i;
            }
        }
        if(minv==INFTY)break;
        color[u]=2;
        rp(i,n){
            if(d[u]+M[u][i]<d[i]){
                d[i]=d[u]+M[u][i];
                color[i]=1;
            }
        }

    }
}
int main(){
    int u,k,v,c;
    cin>>n;
    rp(i,n){
        rp(j,n)M[i][j]=INFTY;
        cin>>u>>k;
        rp(j,k){
            cin>>v>>c;
            M[u][v]=c;
        }
    }
    dijkstra();
    rp(i,n)cout<<i<<" "<<d[i]<<endl;
}

C++: #include <cstdio>
#include <algorithm>
#include <queue>
using namespace std;
static const int INFTY = (1 << 21);
static const int WHITE = 0;
static const int GRAY = 1;
static const int BLACK = 2;

int n;
vector<pair<int, int>> adj[100];
int *d;

void dijkstra() {
    priority_queue<pair<int, int>> PQ;
    int d[n], color[n];

    for (int i = 0; i < n; i++) {
        d[i] = INFTY;
        color[n] = WHITE;
    }
    d[0] = 0;
    PQ.push(make_pair(0, 0));

    while (!PQ.empty()) {
        pair<int, int> f = PQ.top();
        PQ.pop();

        int u = f.second;
        color[u] = BLACK;

        if (d[u] < f.first * (-1)) { continue; }

        for (int j = 0; j < adj[u].size(); j++) {
            int v = adj[u][j].first;
            if (color[v] == BLACK) { continue; }
            if (d[u] + adj[u][j].second < d[v]) {
                d[v] = d[u] + adj[u][j].second;
                // printf("d[%d] = %d\n", v, d[v]);
                PQ.push(make_pair(d[v] * (-1), v));
                color[v] = GRAY;
            }
        }
    }
    
    for (int i = 0; i < n; i++) {
        printf("%d %d\n", i, d[i]);
    }
}

int main() {
    scanf("%d", &n);

    // adj = new vector<pair<int, int>>[n];

    for (int i = 0; i < n; i++) {
        int u, k;
        scanf("%d %d", &u, &k);
        for (int j = 0; j < k; j++) {
            int v, c;
            scanf("%d %d", &v, &c);
            adj[u].push_back(make_pair(v, c));
        }
    }

    dijkstra();

    return 0;
}

C++: #include<iostream>
#include<sstream>
#include<vector>
#include<climits>

using namespace std;

struct E
{
	int from, to;
	long cost;
};

int main(){
	ostringstream out;

	int n, u, k;
	cin >> n;

	vector<long> d(n);
	vector<E> e;

	fill(d.begin(),d.end(),LONG_MAX);
	d[0]=0;

	for(int i=0;i<n;i++){
		cin >> u >> k;
		for(int j=0;j<k;j++){
			E es={u,0,0};
			cin >> es.to >> es.cost; 
			e.push_back(es);
		}
	}

	while(true){
		bool update=false;
		for(int i=0;i<e.size();i++){
			if(d[e[i].from]!=LONG_MAX&&d[e[i].to]>d[e[i].from]+e[i].cost){
				d[e[i].to]=d[e[i].from]+e[i].cost;
				update=true;
			}
		}
		if(!update)break;
	}

	for(int i=0;i<n;i++)
		out << i << " " << d[i] << endl;

	cout << out.str();
	return 0;
}