Go: package main

import (
	"bufio"
	"container/heap"
	"fmt"
	"os"
	"strconv"
)

//make priority queue
type Item struct {
	id       int
	priority int // this state is priority and distans from start
	index    int
}

type PriorityQueue []*Item

func (pq PriorityQueue) Len() int { return len(pq) }

// we want the ascending-priority-queue.
// So we use less than here.
func (pq PriorityQueue) Less(i, j int) bool {
	return pq[i].priority < pq[j].priority
}

func (pq PriorityQueue) Swap(i, j int) {
	pq[i], pq[j] = pq[j], pq[i]
	pq[i].index = j
	pq[j].index = i
}

func (pq *PriorityQueue) Push(x interface{}) {
	n := len(*pq)
	item := x.(*Item)
	item.index = n
	*pq = append(*pq, item)
}

func (pq *PriorityQueue) Pop() interface{} {
	old := *pq
	n := len(old)
	item := old[n-1]
	item.index = -1 //for safety
	*pq = old[0 : n-1]
	return item
}

func (pq *PriorityQueue) update(dist int, id int) {
	for _, i := range *pq {
		if i.id == id {
			if i.priority > dist {
				i.priority = dist
			}
		}
	}
}

// the main code
func nextInt(sc *bufio.Scanner) int {
	sc.Scan()
	n, _ := strconv.Atoi(sc.Text())
	return n
}

func dikstra(dist [][]int, n int) []int {
	// preparate priority queue
	inf := 1 << 30
	pq := make(PriorityQueue, n)
	shortests := make([]int, n)
	for i := 0; i < n; i++ {
		pq[i] = &Item{
			id:       i,
			priority: inf,
			index:    i,
		}

		shortests[i] = inf
	}
	pq[0].priority = 0
	shortests[0] = 0
	heap.Init(&pq)

	for pq.Len() > 0 {
		item := heap.Pop(&pq).(*Item)
		shortests[item.id] = item.priority
		for id, d := range dist[item.id] {
			if d != -1 {
				pq.update(item.priority+d, id)
			}
		}
		heap.Init(&pq)
	}
	return shortests
}

func main() {
	sc := bufio.NewScanner(os.Stdin)
	sc.Split(bufio.ScanWords)

	// init
	n := nextInt(sc)
	dist := make([][]int, n)
	for i := 0; i < n; i++ {
		dist[i] = make([]int, n)
		for j := 0; j < n; j++ {
			dist[i][j] = -1
		}
	}

	// std Input
	for i := 0; i < n; i++ {
		u := nextInt(sc)
		k := nextInt(sc)
		for j := 0; j < k; j++ {
			v, c := nextInt(sc), nextInt(sc)
			dist[u][v] = c
		}
	}

	shortests := dikstra(dist, n)
	for i, d := range shortests {
		fmt.Printf("%d %d\n", i, d)
	}
}

Python: from collections import namedtuple
import heapq

Edge = namedtuple('Edge', ('fr', 'to', 'cost'))
inf = int(1e9)


def bellman_ford(n, start, edges):
    dists = [inf for _ in range(n)]
    dists[start] = 0
    while True:
        updated = False
        for e in edges:
            if dists[e.fr] != inf and dists[e.fr] + e.cost < dists[e.to]:
                updated = True
                dists[e.to] = dists[e.fr] + e.cost

        if not updated:
            break

    return dists


def dijkstra(n, costs):
    dists = [inf for _ in range(n)]
    dists[0] = 0

    queue = []
    for (i, d) in enumerate(dists):
        heapq.heappush(queue, (d, i))

    while len(queue) > 0:
        d, i = heapq.heappop(queue)
        if d > dists[i]:
            continue

        for v in range(n):
            if v == i or costs[i][v] == inf:
                continue

            if dists[i] + costs[i][v] < dists[v]:
                dists[v] = dists[i] + costs[i][v]
                heapq.heappush(queue, (dists[v], v))

    return dists


def warshall_floyd(n, costs):
    for i in range(n):
        print(costs[i])

    dists = [[costs[i][j] for j in range(n)] for i in range(n)]

    for k in range(n):
        for i in range(n):
            for j in range(n):
                dists[i][j] = min(dists[i][j], dists[i][k] + dists[k][j])

    return dists


n = int(input())

m = [[inf if i != j else 0 for i in range(n)] for j in range(n)]
es = []
for i in range(n):
    fs = list(map(int, input().split()))
    ne = fs[1]
    for j in range(ne):
        v = fs[2+2*j]
        c = fs[2+2*j+1]
        m[i][v] = c
        es.append(Edge(i, v, c))


# d = bellman_ford(n, 0, es)
# d = dijkstra(n, m)
d = warshall_floyd(n, m)
for (i, di) in enumerate(d[0]):
    print(i, di)

Python: #coding: utf-8

inf = 1000000000


def dijkstra(s):
    d = [inf for i in range(n)]
    color = ["white" for i in range(n)]
    p = [-1 for i in range(n)]
    d[s] = 0

    while True:
        mincost = inf
        for i in range(n):
            if color[i] != "black" and d[i] < mincost:
                mincost = d[i]
                u = i
        if mincost == inf:
            break

        color[u] = "black"

        for v in range(n):
            if color[v] != "black" and mtrx[u][v] != False:
                if d[u] + mtrx[u][v] < d[v]:
                    d[v] = d[u] + mtrx[u][v]
                    p[v] = u
                    color[v] = "gray"
    return d

n = int(input())
mtrx = [[False for j in range(n)] for i in range(n)]
for i in range(n):
    data = list(map(int,input().split()))
    k = data[1]
    for num in range(k):
        mtrx[i][data[2+2*num]] = data[2+2*num+1]

d = dijkstra(0)

for i, num in enumerate(d):
    print(i,num)

Python: # ALDS1_12_V Single Source Shortest Path I
import sys

n = int(input())
G = [[float('inf')] * n for _ in range(n)]
for i in range(n):
    ukvc = list(map(int, sys.stdin.readline().strip().split()))
    u = ukvc[0]
    k = ukvc[1]

    for j in range(k):
        G[u][ukvc[2 + 2 * j]] = ukvc[3 + 2 * j]

p = [n] * n  # 親を保存するリスト　親ノードとしてあり得ない n を初期リストとする
c = ['white'] * n # 最小経路木への接続チェック　white 未接続　black 接続済
d = [float('inf')] * n  # ノード i までの最小経路を保存するリスト
d[0] = 0  # 根への距離は0とする
p[0] = -1  # 根の親は -1 とする
u = 0  # 次のループで最小経路木につなげるノード

while 'white' in c:
    c[u] = 'black'

    v = None
    minpath = float('inf')
    for i in range(n):
        d[i] = min(d[i], d[u] + G[u][i])
        if (d[i] < minpath) & (c[i] == 'white'):
            minpath = d[i]
            v = i
            p[i] = u

    if v is None:
        break

    u = v

for i in range(n):
    print('{} {}'.format(i, d[i]))

Python: def dijkstra(n,s):
    inf=float("inf")
    color=["white" for i in range(n)]
    D=[inf for i in range(n)]
    P=[0 for i in range(n)]
    M=[[inf for i in range(n)] for j in range(n)]

    for i in range(n):
        weight=list(map(int,input().split()))[2:]
        for j in range(len(weight)//2):
            M[i][weight[2*j]]=weight[2*j+1]

    D[s]=0
    P[s]=-1

    while 1:
        cost,u=inf,0
        for i in range(n):
            if color[i]!="black" and D[i]<cost:
                cost=D[i]
                u=i

        if cost==inf:break

        color[u]="black"

        for i in range(n):
            if color[i]!="black" and M[u][i]!=inf:
                if D[u]+M[u][i]<D[i]:
                    D[i]=D[u]+M[u][i]
                    color[i]="gray"
                    P[i]=u

    return D


n=int(input())
distant=dijkstra(n,0)
for i in range(n):
    print(i,distant[i])

Python: def dijkstra():
    d[0] = 0
    color[0] = GRAY

    while True:
        minv = INF
        u = -1
        for i in range(N):
            if minv > d[i] and color[i] != BLACK:
                u = i
                minv = d[i]
        if u == -1:
            break
        color[u] = BLACK
        for i in range(N):
            if color[i] != BLACK and M[u][i] != INF:
                if d[i] > d[u] + M[u][i]:
                    d[i] = d[u] + M[u][i]
                    color[i] = GRAY

INF = 10 ** 18
WHITH = 0
GRAY = 1
BLACK = 2
N = int(input())
M = [[INF for _ in range(N)] for _ in range(N)]
d = [INF] * N
color = [WHITH] * N

for i in range(N):
    lst = list(map(int, input().split()))
    for j in range(lst[1]):
        M[lst[0]][lst[2 + (j * 2)]] = lst[3 + (j * 2)]

dijkstra()
for i in range(N):
    v = d[i]
    if v == INF:
        v = -1
    print(i, v)