Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
	"strings"
)

var scanner = bufio.NewScanner(os.Stdin)

func nextString() string {
	scanner.Scan()
	return scanner.Text()
}

func nextInt() int {
	n, err := strconv.Atoi(nextString())
	if err != nil {
		fmt.Printf("strconv.Atoi failed: %v\n", err)
	}
	return n
}

func stringifyArray(arr []int) string {
	return strings.TrimRight(fmt.Sprintf("%+v", arr)[1:], "]")
}

var infty = 1000000000

type nodeKey int

type DirectedGraphNode struct {
	key       nodeKey
	adjacents []*DirectedGraphNode
	visited   bool
	d         int
	parent    *DirectedGraphNode
}

type DirectedGraph struct {
	nodes []DirectedGraphNode
}

func (g *DirectedGraph) setAdjacency(l, r nodeKey) {
	g.nodes[l].adjacents = append(g.nodes[l].adjacents, &g.nodes[r])
}

func newDirectedGraph(nNodes int) *DirectedGraph {
	graph := DirectedGraph{}
	graph.nodes = make([]DirectedGraphNode, nNodes)
	for iNodes := 0; iNodes < nNodes; iNodes++ {
		graph.nodes[iNodes].key = nodeKey(iNodes)

		graph.nodes[iNodes].visited = false
		graph.nodes[iNodes].d = infty
		graph.nodes[iNodes].parent = nil
	}
	return &graph
}

type QueueEntry struct {
	node *DirectedGraphNode
	next *QueueEntry
}

type Queue struct {
	head, tail *QueueEntry
}

func (q *Queue) enqueue(node *DirectedGraphNode) {
	entry := QueueEntry{}
	entry.node = node

	if q.tail == nil {
		q.head = &entry
		q.tail = &entry
		return
	}

	q.tail.next = &entry
	q.tail = q.tail.next
}

func (q *Queue) dequeue() *QueueEntry {
	if q.head == nil {
		return nil
	}
	poped := q.head
	q.head = q.head.next
	if q.head == nil {
		q.tail = nil
	}
	return poped
}

func (q *Queue) isEmpty() bool {
	return q.head == nil
}

func fillDistancesByBreadthFirstSearch(g *DirectedGraph, startNode *DirectedGraphNode) {
	startNode.visited = true
	startNode.d = 0

	queue := Queue{}
	queue.enqueue(startNode)
	for !queue.isEmpty() {
		u := queue.dequeue().node
		for _, adjacent := range u.adjacents {
			if !adjacent.visited {
				adjacent.visited = true
				adjacent.d = u.d + 1
				adjacent.parent = u
				queue.enqueue(adjacent)
			}
		}
		u.visited = true
	}
}

func main() {
	scanner.Split(bufio.ScanWords)

	nNodes := nextInt()
	g := newDirectedGraph(nNodes + 1)

	for iNode := 0; iNode < nNodes; iNode++ {
		nodeKeyLeft := nodeKey(nextInt())
		nAdj := nextInt()
		for iAdj := 0; iAdj < nAdj; iAdj++ {
			nodeKeyRight := nodeKey(nextInt())
			g.setAdjacency(nodeKeyLeft, nodeKeyRight)
		}
	}

	// fmt.Println(g)
	fillDistancesByBreadthFirstSearch(g, &g.nodes[1])
	// fmt.Println(g)

	for iNode := 1; iNode <= nNodes; iNode++ {
		node := g.nodes[iNode]
		distance := node.d
		if distance == infty {
			distance = -1
		}
		fmt.Println(node.key, distance)
	}
}

C++: #include <bits/stdc++.h>
#define rep(i,n) for(int i=0;i<n;i++)
#define Graph vector<vector<int>>
using namespace std;

//そのまま再帰にかけて実行しては間に合わない。先に各部分木の根に対して、子に分配する数値を加算しておき、
//根である1から子に対して、根の数値を加算していく作業を一回だけ行えば条件は満たされる

void DFS(const Graph &G,int v,vector<bool> &seen,vector<int> &counter){//深さ優先探索。
//引数は順にグラフ、始点(注目点)、探索済みかどうか、各点の持つ値を記録するカウンタ
  
  seen[v]=true;

  for(auto next_v : G[v]){
    if(seen[next_v]) continue;
    counter[next_v]+=counter[v];
    DFS(G,next_v,seen,counter);
  }

  return ;

}

 
int main() {

  int N ;  cin >> N ;

  Graph G(N+1);//頂点はn個。今回は数値にそのまま対応させるために+1した

  rep(i,N){
    int u,k;
    cin >> u >> k;//頂点番号、頂点の数
    rep(j,k){
      int x; cin >> x;
      G[u].push_back(x);
    }
  }//入力終了

  vector<int> dist(N+1,-1);//全地点を未訪問で初期化
  
  dist[1]=0;//頂点1（スタート）の距離を0にする

  queue<int> que;//BFS用キュー

  que.push(1);

  while(!que.empty()){
    int v = que.front();
    que.pop();          //先頭頂点を取り出す
    
    for(int nv : G[v]){
      if(dist[nv]!=-1) continue;//探索済みならスルー

      //初めて候補に挙がった点は距離を入力し、キューに入れる
      dist[nv]= dist[v]+1;
      que.push(nv);
    }

  }

  for(int i=1;i<=N;i++){
    cout << i << ' ' << dist[i] <<endl ;
  }

  return 0;
}

C++: #include<iostream>
#include<vector>
#include<stack>
#include<cstdio>
using namespace std;
static const int MAX = 100000;
static const int NIL = -1;
int n ;
vector<int> G[MAX];
int color [MAX];
void dfs (int r,int c)
{
  stack <int> S;
  S.push(r);
  color[r] = c;
  while(!S.empty())
  {
    int u = S.top();
    S.pop();
    for(int i = 0;i<G[u].size();i++)
        {
          int v = G[u][i];
          if(color[v] == NIL)
          {
            color[v] = c;
            S.push(v);
          }
        }
  }
}
void ass()
{
  int id = 1;
  for(int i = 0;i<n;i++)
    color[i] = NIL;
  for(int u = 0;u<n;u++)
  {
    if(color[u] == NIL)
    dfs(u,id++);
  }
}
int main ()
{
  int s,t,m,q;
  cin>>n>>m;
  for(int i = 0;i<m;i++)
    {
      cin>>s>>t;
      G[s].push_back(t);
      G[t].push_back(s);
    }
  ass();
  cin>>q;
  for(int i = 0;i<q;i++)
  {
    cin>>s>>t;
    if(color[s] == color[t])
    {
      cout<<"yes"<<endl;
    }
    else cout<<"no"<<endl;
  }
  return 0 ;
}

C++: #include<iostream>
using namespace std;

typedef struct{
  int A[1000];
  int ans;
  bool c;
}node;
node T[1000];
int Q[100000000];
int head=0;
int tail=1;
int n;

void function(int num){
  while(true){
    if(head==tail)break;
    for(int i=2;i<=n;i++){
      if(T[num].A[i]==1){
	if(T[i].ans==0){
	  T[i].ans=T[num].ans+1;
	}
	Q[tail++]=i;
      }
    }
    //    cout<<"Q "<<Q[head]<<endl;
    num=Q[head++];
    //  cout<<head<<" "<<tail<<endl;
  }

}

int main(){
  int num;
  int son;
  int z;
  cin>>n;
  for(int i=0;i<n;i++){
    cin>>num;
    cin>>son;
    for(int j=0;j<son;j++){
      cin>>z;
      T[num].A[z]=1;
      }
  }
  Q[0]=1;
  function(1);
  T[1].ans=0;
  for(int i=2;i<=n;i++){
    if(T[i].ans==0){
      T[i].ans=-1;
    }
  }

  for(int i=1;i<=n;i++){
      cout<<i<<" "<<T[i].ans<<endl;
  }


  return 0;
}

C++: #include<iostream>
#include<vector>
#include<queue>

struct node {
	std::vector<int> child;
	int distance;
};

int main() {
	int node_num;

	std::cin >> node_num;

	std::vector<node> n(node_num);

	for (int i = 0; i < node_num; i++) {
		int num, to, node_val;
		std::cin >> node_val >> num;
		for (int j = 0; j < num; j++) {
			std::cin >> to;
			n[node_val - 1].child.push_back(to);
		}
		n[i].distance = -1;
	}

	//???????????????????????¢0
	n[0].distance = 0;
	std::queue<int> q;
	int dist = 1;
	q.push(1);
	while(q.size() != 0){
		int num = q.front();
		q.pop();
		for (std::vector<int>::iterator it = n[num - 1].child.begin(); it != n[num - 1].child.end(); it++) {
			if (n[*it - 1].distance > n[num - 1].distance + 1|| n[*it - 1].distance == -1) {
				n[*it - 1].distance = n[num - 1].distance + 1;
				q.push(*it);
			}
		}
	}

	for (int i = 0; i < node_num; i++) {
		std::cout << i + 1 << " " << n[i].distance << std::endl;
	}
	return 0;
}

C++: #include<iostream>
#include<vector>
#include<queue>
#include<map>
using namespace std;

int main() {
    int N;
    cin>>N;
    vector<vector<int> > graph(N);
    int u, k, tmp;
    for(int i=0;i<N;++i){
        cin>>u>>k;
        for(int j=0;j<k;++j){
            cin>>tmp;
            tmp--;
            graph[i].push_back(tmp);
        }
    }
    queue<int> que;
    queue<int> passque;
    que.push(0);
    passque.push(0);
    int node, pass;
    vector<int> ans(N);
    for(int i=0;i<N;++i){
        ans[i] = -1;
    }
    map<int, int> past;
    past[0]++;
    while(!que.empty()){
        node = que.front();que.pop();
        pass = passque.front();passque.pop();
        ans[node] = pass;
        for(int i=0;i<graph[node].size();++i){
            if(past[graph[node][i]]==0){
                que.push(graph[node][i]);
                passque.push(pass + 1);
            }
            past[graph[node][i]]++;
        }
    }
    for(int i=0;i<N;++i){
        cout<<i+1<<" "<<ans[i]<<endl;
    }
}