Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

const BIG_COST = 200000

type Path struct {
	node int
	cost int
}

func main() {
	sc := bufio.NewScanner(os.Stdin)
	sc.Split(bufio.ScanWords)

	nNodes := scanInt(sc)

	// 各頂点につながる頂点一覧を得るための隣接リスト
	graph := make([][]Path, nNodes)

	for i := 0; i < nNodes; i++ {
		u := scanInt(sc)
		k := scanInt(sc)
		graph[i] = make([]Path, k)
		for d := 0; d < k; d++ {
			graph[u][d] = Path{
				node: scanInt(sc),
				cost: scanInt(sc),
			}
		}
	}

	// 0 から各頂点への最小コストを保存する配列
	minCosts := make([]int, nNodes)

	minCosts[0] = 0
	for i := 1; i < nNodes; i++ {
		minCosts[i] = BIG_COST
	}

	// 各頂点が調査済みかどうかを保持する配列
	checked := make([]bool, nNodes)

	// 最小コストのパスを高速に取得するためのヒープ。
	// コストが小さいものほどルートに来るようにする。
	heap := NewHeap(func(a, b Path) bool {
		return a.cost < b.cost
	})

	heap.insert(Path{node: 0, cost: 0})
	for heap.size > 0 {
		u := heap.extractMax()

		// 隣接行列を使っていた時とは違い、ヒープには
		// 同じノードへのパスが複数含まれうる。そのため既によりコストの低い
		// パスが見つかっている場合は無視する。
		if minCosts[u.node] < u.cost {
			continue
		}

		checked[u.node] = true

		for _, v := range graph[u.node] {
			cost := v.cost + u.cost
			if !checked[v.node] && cost < minCosts[v.node] {
				minCosts[v.node] = cost
				heap.insert(Path{node: v.node, cost: cost})
			}
		}
	}

	w := bufio.NewWriter(os.Stdout)
	for i, cost := range minCosts {
		fmt.Fprintf(w, "%d %d\n", i, cost)
	}
	w.Flush()
}

func scanInt(sc *bufio.Scanner) int {
	sc.Scan()
	v, _ := strconv.Atoi(sc.Text())
	return v
}

// --- From ALDS1_9_C: Priority Queue

type Heap struct {
	size   int
	heap   []Path
	isHigh func(a, b Path) bool
}

func NewHeap(isHigh func(a, b Path) bool) Heap {
	heap := make([]Path, 1) // 先頭は不使用
	return Heap{size: 0, heap: heap, isHigh: isHigh}
}

func (h *Heap) insert(v Path) {
	h.size += 1
	if h.size > len(h.heap)-1 {
		h.heap = append(h.heap, v)
	} else {
		h.heap[h.size] = v
	}

	for i := h.size; i > 1; {
		parent := i / 2
		if h.isHigh(h.heap[parent], h.heap[i]) {
			break
		}
		h.heap[i], h.heap[parent] = h.heap[parent], h.heap[i]
		i = parent
	}
}

func (h *Heap) extractMax() Path {
	if h.size <= 0 {
		panic("cannot extract from empty heap")
	}

	max := h.heap[1]
	h.heap[1] = h.heap[h.size]
	h.size -= 1
	h.maxHeapify(1)

	return max
}

func (h *Heap) maxHeapify(idx int) {
	left := idx * 2
	right := left + 1
	largest := idx

	if left <= h.size {
		if h.isHigh(h.heap[left], h.heap[idx]) {
			largest = left
		}
		if right <= h.size && h.isHigh(h.heap[right], h.heap[largest]) {
			largest = right
		}
	}

	if largest != idx {
		h.heap[idx], h.heap[largest] = h.heap[largest], h.heap[idx]
		h.maxHeapify(largest)
	}
}

C++: #include <iostream>
#include <string>
#include <vector>
#include <algorithm>
#include <queue>
using namespace std;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define  all(x) (x).begin(),(x).end()
typedef long long ll;

int n;
vector<vector<pair<int, int>>> g;
const int INF = 1<<30;

void dijkstra(){
    vector<int> d(n), visited(n);
    priority_queue< pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>> > pq;
    rep(i,n) d[i] = INF;

    pq.push(make_pair(0,0));
    d[0] = 0;
    visited[0] = 1;

    while(!pq.empty()){
        pair<int, int> p = pq.top(); pq.pop();
        int u = p.second;

        visited[u] = 1;
        if (d[u] < p.first) continue;

        for(auto pp: g[u]){
            int v = pp.first;
            if (visited[v] == 1) continue;
            if (d[v] > d[u] + pp.second){
                d[v] = d[u] + pp.second;
                pq.push(make_pair(d[v], v));
            }
        }
    }
    rep(i,n){
        printf("%d %d\n", i, d[i]);
    }
}

int main(){
    cin >> n;
    g.resize(n);
    rep(i,n){
        int u, k;
        cin >> u >> k;
        rep(j, k){
            int to, cost;
            cin >> to >> cost;
            g[u].push_back(make_pair(to, cost));
        }
    }
    dijkstra();
}

C++: #include <bits/stdc++.h>
using namespace std;

struct Edge
{
        int to, cost;
        Edge () {}
        Edge ( int to, int cost ) : to(to), cost(cost) {}
};

struct Node
{
        int node, cost;
        Node () {}
        Node ( int node, int cost ) : node(node), cost(cost) {}
        bool operator < (const Node &d) const { return ( cost < d.cost ); }
        bool operator > (const Node &d) const { return ( cost > d.cost ); }
};

constexpr int INF = (1 << 30) - 1;
int n;
vector < Edge > G[100005];
int d[10005];

void Dijkstra()
{
        priority_queue < Node , vector < Node > , greater < Node > > pq;

        fill_n(d, 10005, INF);
        d[0] = 0;
        pq.emplace(0, 0);
        
        while ( !pq.empty() ) {
                Node u = pq.top(); pq.pop();
                for ( auto &x : G[u.node] ) {
                        int cost = u.cost + x.cost;
                        if ( d[x.to] > cost ) {
                                d[x.to] = cost;
                                pq.emplace(x.to, cost);
                        }
                }
        }
}

int main()
{
        cin >> n;
        for ( int i = 0; i < n; i++ ) {
                int u, k;
                cin >> u >> k;
                for ( int j = 0; j < k; j++ ) {
                        int v, c;
                        cin >> v >> c;
                        G[u].emplace_back(v, c);
                }
        }
        Dijkstra();
        for ( int i = 0; i < n; i++ ) {
                cout << i << " " << d[i] << endl;
        }

        return (0);
}

C++: #include<iostream>
#include<algorithm>
#include<queue>
using namespace std;
static const int MAX = 100;
static const int INFTY = (1 << 21);
static const int WHITE = 0;
static const int GRAY = 1;
static const int BLACK = 2;

int n;
vector<pair<int, int> > adj[MAX]; 

void dijkstra() {
    priority_queue<pair<int, int> > PQ;
	int d[MAX], color[MAX];
	
	for(int i = 0; i < n; i++) {
		d[i] = INFTY;
		color[i] = WHITE;
	}
	
	d[0] = 0;
	PQ.push(make_pair(0,0));
	color[0] =GRAY;	
    while(!PQ.empty()) {
    	pair<int, int> f = PQ.top();
    	PQ.pop();
		int u = f.second;
		
		color[u] = BLACK;
		
		if(d[u] < f.first * (-1)) continue;
		
		for(int j = 0; j < adj[u].size(); j++) {
			int v = adj[u][j].first;
			if(color[v] == BLACK) continue;
			if(d[v] > d[u] + adj[u][j].second) {
				d[v] = d[u] + adj[u][j].second;
				PQ.push(make_pair(d[v] * (-1), v));
				color[v] = GRAY;
			}
		}
    }
    
    for(int i = 0; i < n; i++) {
    	cout << i << " " << (d[i] == INFTY ? -1 : d[i]) << endl;
    }
}

int main() {
	int k, c, u, v;
	
	cin >> n;
	for(int i = 0; i < n; i++) {
		cin >> u >> k;
		for(int j = 0; j < k; j++) {
			cin >> v >> c;
		    adj[u].push_back(make_pair(v, c));
		}
	} 
	
	dijkstra();

	return 0;
}