Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

const BIG_COST = 3000

const (
	ST_NOT_YET = iota
	ST_JOINED
)

func main() {
	sc := bufio.NewScanner(os.Stdin)
	sc.Split(bufio.ScanWords)

	nNodes := scanInt(sc)
	costs := make([][]int, nNodes)

	for r := 0; r < nNodes; r++ {
		costs[r] = make([]int, nNodes)
		for c := 0; c < nNodes; c++ {
			costs[r][c] = scanInt(sc)
		}
	}

	states := make([]int, nNodes)
	minCosts := make([]int, nNodes)

	for i := 1; i < nNodes; i++ {
		minCosts[i] = BIG_COST
	}

	for {
		var u int
		minCost := BIG_COST

		for i := 0; i < nNodes; i++ {
			if states[i] != ST_JOINED && minCosts[i] < minCost {
				minCost = minCosts[i]
				u = i
			}
		}

		// 全てのノードが MST に JOIN できたので終了。
		if minCost == BIG_COST {
			break
		}

		states[u] = ST_JOINED

		for v := 0; v < nNodes; v++ {
			cost := costs[u][v]

			// MST内の u と MST外の v との辺の重みをそれぞれ minCosts[v] として
			// 保存しておく。このうち辺の重みが最小となる v が次のループで MST に JOIN する。
			if states[v] != ST_JOINED && cost != -1 && cost < minCosts[v] {
				minCosts[v] = cost
			}
		}
	}

	sum := 0
	for _, cost := range minCosts {
		sum += cost
	}
	fmt.Println(sum)
}

func scanInt(sc *bufio.Scanner) int {
	sc.Scan()
	v, _ := strconv.Atoi(sc.Text())
	return v
}

C++: #include<iostream>
using namespace std;
static const int MAX = 100;
static const int INFTY = (1<<21);
static const int WHITE = 0;
static const int GRAY = 1;
static const int BLACK = 2;

int n,M[MAX][MAX];
int prim(){
    int u,minv;
    int d[MAX],p[MAX],color[MAX];
    for(int i=0;i<n;i++){
        d[i]=INFTY;
        p[i]=-1;
        color[i]=WHITE;
    }
    d[0]=0;
    while(1){
        minv=INFTY;
        u=-1;
        for(int i=0;i<n;i++){
            if(minv>d[i]&&color[i]!=BLACK){
                u=i;
                minv = d[i];
            }
        }
        if(u==-1) break;
        color[u]=BLACK;
        for(int v=0;v<n;v++){
            if(color[v]!=BLACK&&M[u][v]!=INFTY){
                if(d[v]>M[u][v]){
                    d[v]=M[u][v];
                    p[v]=u;
                    color[v]=GRAY;
                }
            }
        }
    }
    int sum=0;
    for(int i=0;i<n;i++){
        if(p[i]!=-1) sum+=M[i][p[i]];
    }
    return sum;
}

int main(){
    cin >> n;
    for(int i=0;i<n;i++){
        for(int j=0;j<n;j++){
            int e;
            cin >> e;
            M[i][j]=(e==-1)? INFTY : e;
        }
    }
    cout << prim() << endl;
    return 0;
}

C++: #include <bits/stdc++.h>

#define rep(i, a, b) for (int i = a; i < (int)(b); ++i)
#define rrep(i, a, b) for (int i = b - 1; i >= (int)(a); --i)

using namespace std;

using ll = long long;
using vi = vector<int>;
using vvi = vector<vi>;
using vll = vector<ll>;

int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);

    int n;
    cin >> n;

    vvi g(n, vi(n, INT_MAX));

    rep(i, 0, n) {
        rep(j, 0, n) {
            cin >> g[i][j];
            if (g[i][j] == -1) { g[i][j] = INT_MAX; }
        }
    }

    vector<bool> seen(n, false);
    vi d(n, INT_MAX);
    vi p(n, -1);

    d[0] = 0;

    while (true) {
        // Mimimum cost to connect T and V-T.
        int minv = INT_MAX;
        // A vertex in V-T, which has minimum cost.
        int u = -1;

        rep(i, 0, n) {
            if (!seen[i] && minv > d[i]) {
                u = i;
                minv = d[i];
            }
        }
        if (u == -1) { break; }

        // Append u into T.
        seen[u] = true;

        // Calculate minimum distance between u and v in V-T.
        rep(v, 0, n) {
            if (!seen[v] && g[u][v] != INT_MAX) {
                if (d[v] > g[u][v]) {
                    d[v] = g[u][v];
                    p[v] = u;
                }
            }
        }
    }

    int sum = 0;
    rep(i, 0, n) {
        if (p[i] != -1) { sum += g[i][p[i]]; }
    }
    cout << sum << endl;

    return 0;
}

C++: #include <iostream>
#include <vector>
#include <set>
using namespace std;

int main() {
    int i, j, n, res = 0;
    cin >> n;
    int a[n][n];

    for (i=0; i<n; i++) {
        for (j=0; j<n; j++) {
            cin >> a[i][j];
        }
    }

    vector<int> v;
    set<int> cons;
    v.push_back(0);
    while (v.size() != n) {
        int nearest_node = 9999;
        int nearest_distance = 9999;
        for (i=0; i<v.size(); i++) {
            for (j=0; j<n; j++) {
                if ((a[i][j] != -1) && (a[i][j] < nearest_distance) && (cons.count(j) == 0)) {
                    nearest_node = j;
                    nearest_distance = a[i][j];
                }
            }
        }
        res += nearest_distance;
        v.push_back(nearest_node);
        cons.insert(nearest_node);
    }
    cout << res << endl;
    return 0;
}

C++: #define _CRT_SECURE_NO_WARNINGS
#define _USE_MATH_DEFINES
#include <iostream>
using namespace std;
const int num = 100;
int v[num][num], n, c[num], p[num], d[num];;
inline int mini(int k) {
	for (int i = 0; i < n; i++) {
		d[i] = 99999999;
	}

	d[k] = 0;
	p[k] = -1;
	while (1) {
		int minv = 99999999, u = -1;
		for (int i = 0; i < n; i++) {
			if (d[i] < minv && c[i] == 0) {
				minv = d[i];
				u = i;
			}
		}
		if (u == -1) break;
		for (int i = 0; i < n; i++) {
			if (v[u][i] != -1 && c[i] == 0) {
				if (d[i] > v[u][i]) {
					d[i] = v[u][i];
					p[i] = u;
				}
			}
		}
		c[u] = 1;
	}
	int sum = 0;
	for (int i = 0; i < n; i++) {
		if(p[i] != -1) sum += v[i][p[i]];
	}
	return sum;
}
int main() {
	cin >> n;
	for (int i = 0; i < n; i++) {
		for (int j = 0; j < n; j++) {
			cin >> v[i][j];
		}
	}
	for (int i = 0; i < n; i++) {
		c[i] = 0;
	}
	cout << mini(0) << endl;
	for (int i = 0; i < n; i++) {
		if (p[i] != -1)cout << p[i] << "  " << v[i][p[i]] << endl;
	}
	return 0;
}