Go: // ダイクストラのアルゴリズム
package main

import (
	"bufio"
	"fmt"
	"log"
	"math"
	"os"
	"strconv"
	"strings"
)

type color int

const (
	white color = iota // 未訪問
	mst                // MSTとして確定
)

// 頂点
type node struct {
	num     int         // 頂点の番号
	weights map[int]int // 重みMAP
	parent  *node       // MSTへの重み最小の親
	sum     int         // 始点からの距離
	color   color
}

func (p *node) getMinToMst() int {
	if p.parent == nil {
		return math.MaxInt32
	}
	return p.weights[p.parent.num]
}

func main() {
	scanner := bufio.NewScanner(os.Stdin)
	n := eGetInt(scanner)

	nodes := make([]*node, n)
	for i := 0; i < n; i++ {
		weights := eAtoi((strings.Fields(eGetline(scanner))))
		v := &node{weights[0], make(map[int]int, weights[1]), nil, 0, white}
		for j := 0; j < weights[1]; j++ {
			k := weights[j*2+2] // 相手の頂点名
			w := weights[j*2+3] // 重み
			v.weights[k] = w
		}
		nodes[i] = v
	}

	// 初回はnode[0]がMSTに入るように
	nodes[0].parent = nodes[0]

	for { // 全部チェックするまで

		// どの頂点を新たにMSTに取り込むか

		var minNode *node
		min := math.MaxInt32
		for _, v := range nodes {
			if v.color == mst {
				continue
			}
			if v.getMinToMst() < min {
				min = v.getMinToMst()
				minNode = v
			}
		}
		if minNode == nil {
			// すべて完了している.
			break
		}

		// MSTに追加する頂点決定
		minNode.color = mst
		// 自分の親の合計値と合算する
		minNode.sum = minNode.parent.sum + min

		// MSTに属していない頂点それぞれについて,MSTとの最小の重みの距離を加算
		for _, v := range nodes {
			if v.color == mst {
				continue
			}
			w, ok := v.weights[minNode.num]
			if !ok {
				// minNodeと接してない
				continue
			}

			if w < v.getMinToMst() {
				// minNodeへの距離がもっとも重みが少ないので親を変更
				v.parent = minNode
			}
		}
	}

	for i, v := range nodes {
		fmt.Printf("%d %d\n", i, v.sum)
	}
}

func eGetInt(scanner *bufio.Scanner) int {
	t := eAtoi(strings.Fields(eGetline(scanner)))
	return t[0]
}

func eGetline(p *bufio.Scanner) string {
	if !p.Scan() {
		if err := p.Err(); err != nil {
			log.Fatal(err.Error())
		}
		return ""
	}
	return p.Text()
}

func eAtoi(s []string) []int {
	ints := make([]int, len(s))
	var err error
	for i, e := range s {
		ints[i], err = strconv.Atoi(e)
		if err != nil {
			log.Fatal(err.Error())
		}
	}
	return ints
}

C++: #include<cstdio>
#include<queue>
#include<vector>
#define MA 10005
#define INF (1<<30)
using namespace std;
struct Node{
    short id;//根据题意，id最大在short有效范围内
    int weight;
};

short n;
vector<pair<int, int> >adj[MA];//加权有向图的邻接表
priority_queue<Node> PQ;//优先级队列
bool state[MA];//节点状态，false为未访问
int dis[MA];//节点到0点的权值总和

/**重载'<'以自定义优先级队列的优先级，这里定义为权值小优先，与默认的大优先相反*/
bool operator < (const Node node1, const Node node2){
    if(node1.weight==node2.weight)
        return node1.id > node2.id;//权值相同比id，意义不大
    return node1.weight > node2.weight;//返回与正常比较相反的结果
}

/**初始化*/
void init(){
    for(short i=0;i<n;i++)
        dis[i] = INF;//初始权值置为无穷
    dis[0] = 0;//0点权值为0
    Node ini;//0点
    ini.id=0;ini.weight = 0;//0点初始值
    PQ.push(ini);//将0点推入队列
}

/**狄克斯特拉算法*/
void dijkstra(){
    while(!PQ.empty()){//执行至队列为空
        Node nowNode = PQ.top();//从队列中取出元素
        PQ.pop();//清除取出的元素
        short nowId = nowNode.id;//当前元素的ID
        state[nowId] = true;//该节点已从队列中清除，设为访问完毕
        if(dis[nowId]>nowNode.weight)continue;//取出最小值，如果不是最短路径则忽略
        int nowSize = adj[nowId].size();//空间换时间，减少部分运算量
        for(int i=0; i<nowSize; i++){//遍历当前元素的邻接节点
            short nextId = adj[nowId][i].first;//下一个节点的ID
            if(state[nextId]) continue;//如果该节点已被读取则跳过
            int nextWeight = dis[nowId] + adj[nowId][i].second;//0到下一个节点的权值
            if(dis[nextId] > nextWeight){//发现了更短的路径
                dis[nextId] = nextWeight;//更新权值数组对应的数据
                Node nextNode;//即将推入队列的节点
                nextNode.id=nextId; nextNode.weight = nextWeight;//将数据存入节点
                PQ.push(nextNode);//将存有数据的节点推入队列
            }
        }
    }
}

int main(){
    int id, flag, nextId, weight;
    scanf("%d", &n);
    for(int i=0;i<n;i++){
        scanf("%d%d",&id, &flag);
        while(flag--){
            scanf("%d%d", &nextId, &weight);//读取邻接表
            adj[id].push_back(make_pair(nextId, weight));
        }
    }
    init();//执行初始化
    dijkstra();//执行狄克斯特拉算法
    for(short i=0;i<n;i++){//输出全部节点数据
        printf("%d %d\n", i, ((dis[i]==INF)?(-1):(dis[i])));
    }
    return 0;
}

C++: #include<bits/stdc++.h>
using namespace std;
int n;
const int INF=123456789;
const int MAX=100;
int color[MAX];
const int BLACK=2;
const int WHITE=0;
const int GRAY=1;
int d[MAX],M[MAX][MAX];

void ds(){
  int minv,u;

  d[0]=0;color[0]=GRAY;
  while(1){
    minv=INF;u=-1;
    for(int i=0;i<n;i++){
      if(minv>d[i]&&color[i]!=BLACK){
        minv=d[i];
        u=i;
      }
    }

    if(u==-1) break;
    color[u]=BLACK;

    for(int i=0;i<n;i++){
      if(M[u][i]!=INF&&color[i]!=BLACK){
        if(d[i]>d[u]+M[u][i]){
          d[i]=d[u]+M[u][i];
          color[i]=GRAY;
        }
      }
    }
  }
}

int main(){
  int u,k,v,c;
  cin>>n;
  for(int i=0;i<n;i++){
    color[i]=WHITE; d[i]=INF;
    for(int j=0;j<n;j++){
      M[i][j]=INF;
    }
  }

  for(int i=0;i<n;i++){
    cin>>u>>k;
    for(int j=0;j<k;j++){
      cin>>v>>c;
      M[u][v]=c;
    }
  }

  ds();
  for(int i=0;i<n;i++){
  if(d[i]!=INF)  cout<<i<<" "<<d[i]<<endl;
  else cout<<i<<" "<<-1<<endl;
  }
  return 0;
}

C++: #ifdef LOCAL_BUILD
#include "pch.h"
#define DLOG(msg) cout << "#" << __LINE__ << ":" << msg << endl;
#define DLOG_V(var) \
  cout << "#" << __LINE__ << ":" << #var << " : " << var << endl;
#else
#include <bits/stdc++.h>
#define DLOG(msg)
#define DLOG_V(var)
#endif
using namespace std;

int main() {
  int n;
  cin >> n;
  vector<vector<pair<int, int>>> edges(n, vector<pair<int, int>>());
  for (int i = 0; i < n; ++i) {
    int u, k;
    cin >> u >> k;
    for (int j = 0; j < k; ++j) {
      int v, c;
      cin >> v >> c;
      edges[i].push_back(make_pair(v, c));
    }
  }
  int count = 1;
  constexpr auto not_yet = numeric_limits<int>::max();
  vector<int> costs(n, not_yet);
  costs[0] = 0;
  auto cmp = [](const pair<int, int>& lhs, const pair<int, int>& rhs) {
    return lhs.second > rhs.second;
  };
  priority_queue<pair<int, int>, vector<pair<int, int>>, decltype(cmp)> q(cmp);
  for (auto&& edge : edges[0]) {
    q.push(edge);
  }
  while (true) {
    auto state = q.top();
    q.pop();
    if (costs[state.first] > state.second) {
      assert(costs[state.first] == not_yet);
      for (auto&& edge : edges[state.first]) {
        q.push(make_pair(edge.first, edge.second + state.second));
      }
      costs[state.first] = state.second;
      if (++count == n) {
        break;
      }
    }
  }
  for (int i = 0; i < n; ++i) {
    cout << i << " " << costs[i] << endl;
  }
}

C++: #include <iostream>
const int MAX_N = 100;
const int INF = 999999999;
const int WHITE = 0;
const int GRAY = 1;
const int BLACK = 2;
using namespace std;

int n;
int adj[MAX_N][MAX_N];
int color[MAX_N];
int d[MAX_N];

void dijkstra(int s) {
    for (int i = 0; i < n; i++) {
        color[i] = WHITE;
        d[i] = INF;
    }
    d[s] = 0;
    color[s] = GRAY;

    while (1) {
        int minv = INF;
        int u = -1;
        for (int i = 0; i < n; i++) {
            if (color[i] != BLACK && d[i] < minv) {
                minv = d[i];
                u = i;
            }
        }
        if (u == -1) break;

        color[u] = BLACK;
        for (int v = 0; v < n; v++) {
            if (color[v] != BLACK && adj[u][v] != INF) {
                if (d[v] > d[u] + adj[u][v]) {
                    d[v] = d[u] + adj[u][v];
                    color[v] = GRAY;
                }
            }
        }
    }
}

int main(void) {
    cin >> n;
    for (int i = 0; i < n; i++)
        for (int j = 0; j < n; j++) adj[i][j] = INF;

    for (int i = 0; i < n; i++) {
        int u, k; cin >> u >> k;
        for (int j = 0; j < k; j++) {
            int v, c; cin >> v >> c;
            adj[u][v] = c;
        }
    }

    dijkstra(0);

    for (int i = 0; i < n; i++) {
        cout << i << " " << d[i] << endl;
    }
    return 0;
}