Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

var scanner = bufio.NewScanner(os.Stdin)

func nextString() string {
	scanner.Scan()
	return scanner.Text()
}

func nextInt() int {
	n, err := strconv.Atoi(nextString())
	if err != nil {
		fmt.Printf("strconv.Atoi failed: %v\n", err)
	}
	return n
}

var infty = 1000000000

type DirectedGraphNodeID int

type DirectedGraphNode struct {
	key         DirectedGraphNodeID
	adjacents   []*DirectedGraphNode
	costs       []int
	distance    int
	predecessor *DirectedGraphNode
}

func newDirectedGraph(nNodes int) *DirectedGraph {
	graph := DirectedGraph{}
	graph.nodes = make([]*DirectedGraphNode, nNodes)
	for i := 0; i < nNodes; i++ {
		node := DirectedGraphNode{}
		node.key = DirectedGraphNodeID(i)
		node.distance = infty
		graph.nodes[i] = &node
	}
	return &graph
}

type DirectedGraph struct {
	nodes []*DirectedGraphNode
}

func (g *DirectedGraph) setAdjacency(i, j DirectedGraphNodeID, cost int) {
	g.nodes[i].adjacents = append(g.nodes[i].adjacents, g.nodes[j])
	g.nodes[i].costs = append(g.nodes[i].costs, cost)
}

func (g *DirectedGraph) print() {
	for i := 0; i < len(g.nodes); i++ {
		node := g.nodes[i]
		key := node.key
		strings := []string{strconv.Itoa(int(key)), strconv.Itoa(node.distance)}
		for j := 0; j < len(node.adjacents); j++ {
			nodeJ := fmt.Sprintf("(%v, %v)", node.adjacents[j].key, node.costs[j])
			strings = append(strings, nodeJ)
		}
		fmt.Printf("%v\n", strings)
	}
}

func (g *DirectedGraph) relaxEdge(l, r *DirectedGraphNode, w int) {
	if r.distance > l.distance+w {
		// fmt.Printf("%v -> %v, %v\n", l.key, r.key, l.distance+w)
		r.distance = l.distance + w
		r.predecessor = l
	}
}

func main() {
	scanner.Split(bufio.ScanWords)

	nNodes := nextInt()
	graph := newDirectedGraph(nNodes)

	for i := 0; i < nNodes; i++ {
		iNode := DirectedGraphNodeID(nextInt())
		nAdjacent := nextInt()
		for j := 0; j < nAdjacent; j++ {
			jNode := DirectedGraphNodeID(nextInt())
			cost := nextInt()
			graph.setAdjacency(iNode, jNode, cost)
		}
	}

	graph.nodes[0].distance = 0
	for iNode := 0; iNode < nNodes; iNode++ {
		for iLeft := 0; iLeft < len(graph.nodes); iLeft++ {
			nodeLeft := graph.nodes[iLeft]
			for iRight := 0; iRight < len(nodeLeft.adjacents); iRight++ {
				nodeRight := nodeLeft.adjacents[iRight]
				cost := nodeLeft.costs[iRight]
				graph.relaxEdge(nodeLeft, nodeRight, cost)
			}
		}
	}

	// graph.print()

	for iNode := 0; iNode < len(graph.nodes); iNode++ {
		node := graph.nodes[iNode]
		fmt.Println(node.key, node.distance)
	}
}

C++: #include <stdio.h>
int a[10000][10000];
int d[10000];
int p[10000];
int q[10000];
int main(){
    int n, i, j, t, u, v,c=0;
    scanf("%d", &n);
    for(i = 0; i < n; i++)
        for(j = 0; j < n; j++){
            a[i][j]=1000000000;
            if(i == j) a[i][j] = 0;
        }
    for(i = 0; i < n; i++) {
        scanf("%d", &j);
        scanf("%d", &c);
        for(j = 0; j < c; j++) {
            scanf("%d %d", &t, &u);
            a[i][t] = u;
        }
        d[i] = 1e9;
        q[i] = 0;
    }
    d[0] = 0;
    c = 0;
    while(c != n) {
        t = 0;
        j = 1000000001;
        for(i = 0; i < n;i++) {
            if(!q[i]&&d[i] < j) {
                t = i;
                j = d[i];
            }
        }
        q[t] = 1;c++;
        for(i = 0; i < n; i++) {
            if(a[t][i] != 1000000000) {
                if(d[i] > d[t] + a[t][i]) {
                    d[i] =  d[t] + a[t][i];
                }
            }
        }
    }
    for(i = 0; i < n; i++) {
        printf("%d %d\n", i, d[i]);
    }
    return 0;
}

C++: #include <iostream>
using ll = long long;
using namespace std;
/* initialize */
int n, u, k, v, c, A[100][100];

void dijkstra(){
    int c[100], d[100], p[100];
    for (int i = 0; i < n; ++i) { c[i] = 0;  d[i] = 100000000;}
    d[0] = 0;
    p[0] = -1;
    int minc;
    while(true){
        minc = INT32_MAX;
        int u = -1;
        for (int i = 0; i < n; ++i) {
            if (c[i] != 2 && d[i] < minc){
                minc = d[i];
                u = i;
            }
        }
        if(u == -1) break;

        c[u] = 2;

        for (int v = 0; v < n; ++v) {
            if (c[v] != 2 && A[u][v] != 100000000){
                if(d[u] + A[u][v] < d[v]){
                    d[v] = d[u] + A[u][v];
                    p[v] = u;
                    c[v] = 1;
                }
            }
        }
    }
    for (int i = 0; i < n; ++i) {
        cout << i << " " << (d[i] == 100000000 ? -1 : d[i]) << "\n";
    }
};
/* main */
int main() {
    cin >> n;
    for (int l = 0; l < n; ++l) {
        for (int i = 0; i < n; ++i) {
            A[l][i] = 100000000;
        }
    }
    for (int i = 0; i < n; ++i) {
        scanf("%d %d", &u, &k);
        for (int j = 0; j < k; ++j) {
            scanf("%d %d", &v, &c);
            A[u][v] = c;
        }
    }
    dijkstra();
    return 0;
}

C++: #include <iostream>
#include <algorithm>
using namespace std;
#define MAX_N 100
#define INF 1e9

int cost[MAX_N][MAX_N];
int d[MAX_N];
bool used[MAX_N];
int n, u, k, c, v;

void dijkstra(int s){
  fill(d, d + n, INF);
  fill(used, used + n, false);
  d[s] = 0;

  while(true){
    int v = -1;

    for(int u = 0; u < n; u++){
      if(!used[u] && (v == -1 || d[u] < d[v])) v = u;
    }

    if(v == -1) break;
    used[v] = true;

    for(int u = 0; u < n; u++){
      d[u] = min(d[u], d[v] + cost[v][u]);
    }
  }
}

int main(void){
  cin >> n;
  for(int i = 0; i < n; i++){
    for(int j = 0; j < n; j++){
      cost[i][j] = INF;
    }
  }
  for(int i = 0; i < n; i++){
    cin >> u >> k;
    for(int j = 0; j < k; j++){
      cin >> v >> c;
      cost[u][v] = c;
    }
  }
  dijkstra(0);
  for(int i = 0; i < n; i++){
    cout << i << " " << d[i] << endl;
  }
  return 0;
}

C++: #include<cstdio>
#include<queue>
#include<vector>
#define MA 10005
#define INF (1<<30)
using namespace std;
struct Node{
    short id;//根据题意，id最大在short有效范围内
    int weight;
};

short n;
vector<pair<int, int> >adj[MA];//加权有向图的邻接表
priority_queue<Node> PQ;//优先级队列
bool state[MA];//节点状态，false为未访问
int dis[MA];//节点到0点的权值总和

/**重载'<'以自定义优先级队列的优先级，这里定义为权值小优先，与默认的大优先相反*/
bool operator < (const Node node1, const Node node2){
    if(node1.weight==node2.weight)
        return node1.id > node2.id;//权值相同比id，意义不大
    return node1.weight > node2.weight;//返回与正常比较相反的结果
}

/**初始化*/
void init(){
    for(short i=0;i<n;i++)
        dis[i] = INF;//初始权值置为无穷
    dis[0] = 0;//0点权值为0
    Node ini;//0点
    ini.id=0;ini.weight = 0;//0点初始值
    PQ.push(ini);//将0点推入队列
}

/**狄克斯特拉算法*/
void dijkstra(){
    while(!PQ.empty()){//执行至队列为空
        Node nowNode = PQ.top();//从队列中取出元素
        PQ.pop();//清除取出的元素
        short nowId = nowNode.id;//当前元素的ID
        state[nowId] = true;//该节点已从队列中清除，设为访问完毕
        if(dis[nowId]>nowNode.weight)continue;//取出最小值，如果不是最短路径则忽略
        int nowSize = adj[nowId].size();//空间换时间，减少部分运算量
        for(int i=0; i<nowSize; i++){//遍历当前元素的邻接节点
            short nextId = adj[nowId][i].first;//下一个节点的ID
            if(state[nextId]) continue;//如果该节点已被读取则跳过
            int nextWeight = dis[nowId] + adj[nowId][i].second;//0到下一个节点的权值
            if(dis[nextId] > nextWeight){//发现了更短的路径
                dis[nextId] = nextWeight;//更新权值数组对应的数据
                Node nextNode;//即将推入队列的节点
                nextNode.id=nextId; nextNode.weight = nextWeight;//将数据存入节点
                PQ.push(nextNode);//将存有数据的节点推入队列
            }
        }
    }
}

int main(){
    int id, flag, nextId, weight;
    scanf("%d", &n);
    for(int i=0;i<n;i++){
        scanf("%d%d",&id, &flag);
        while(flag--){
            scanf("%d%d", &nextId, &weight);//读取邻接表
            adj[id].push_back(make_pair(nextId, weight));
        }
    }
    init();//执行初始化
    dijkstra();//执行狄克斯特拉算法
    for(short i=0;i<n;i++){//输出全部节点数据
        printf("%d %d\n", i, ((dis[i]==INF)?(-1):(dis[i])));
    }
    return 0;
}