Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

const BIG_COST = 200000

const (
	ST_NOT_YET = iota
	ST_JOINED
)

func main() {
	sc := bufio.NewScanner(os.Stdin)
	sc.Split(bufio.ScanWords)

	nNodes := scanInt(sc)

	costs := make([][]int, nNodes)
	graph := make([][]int, nNodes)

	states := make([]int, nNodes)
	costSums := make([]int, nNodes)

	for i := 0; i < nNodes; i++ {
		costs[i] = make([]int, nNodes)
		costSums[i] = BIG_COST
	}

	for i := 0; i < nNodes; i++ {
		u := scanInt(sc)
		k := scanInt(sc)
		graph[u] = make([]int, k)
		for d := 0; d < k; d++ {
			v := scanInt(sc)
			graph[u][d] = v
			costs[u][v] = scanInt(sc)
		}
	}

	costSums[0] = 0
	for {
		minCost := BIG_COST
		var u int

		for i, cost := range costSums {
			if states[i] != ST_JOINED && cost < minCost {
				minCost = cost
				u = i
			}
		}

		if minCost == BIG_COST {
			break
		}

		states[u] = ST_JOINED

		for _, v := range graph[u] {
			cost := minCost + costs[u][v]
			if cost < costSums[v] {
				costSums[v] = cost
			}
		}
	}

	w := bufio.NewWriter(os.Stdout)
	for i, cost := range costSums {
		fmt.Fprintf(w, "%d %d\n", i, cost)
	}
	w.Flush()
}

func scanInt(sc *bufio.Scanner) int {
	sc.Scan()
	v, _ := strconv.Atoi(sc.Text())
	return v
}

C++: #include <iostream>
using namespace std;

static const int MAX = 100;
static const int UNVISITED = 0;
static const int VISITING = 1;
static const int VISITED = 2;

static const int INFTY = (1 << 21);


int n, M[MAX][MAX];

void Dijkstra() {
	
   int d[MAX], s[MAX];
   int  minv;

   for( int i = 0; i < n; i++) {
    	d[i] = INFTY;
       	s[i] = UNVISITED;
    }
    
   d[0] = 0;
  int u = 0;
   while( u != -1 ) {
      s[u] = VISITED; 
   	  minv = INFTY;
      int e = -1;
      for( int v = 0; v < n; v++ ) {

      	if( s[v] != VISITED && M[u][v] !=INFTY ) {
      		if( d[v] > d[u] + M[u][v] ) {
      			d[v] = d[u] + M[u][v];
      		}
      	}

      	if( s[v] != VISITED  && minv > d[v]) {
           
        		e = v;
        		minv = d[v];
     		}
      }
        
      u = e;
    }  

  
   for(int i = 0; i < n; i++ ) {
   	
   	cout << i << ' ' << d[i] << endl;
   }
   	
   
}


int main() {
   cin >> n;

   for( int i = 0; i < n; i++ ) {
   	for( int j = 0; j < n; j++ ) {
      	M[i][j] =  INFTY ;
   	}
   }
   
   int u, k, v, c;
   for( int i = 0; i < n; i++) {
   	cin >> u >> k;
   	while( k-- ) {
   		cin >> v >> c;
   		M[u][v] = c;
   	}
   }

    Dijkstra() ;

   return 0;
}

C++: #include<iostream>
#define MAX 100
#define INFTY 1<<21
#define WHITE 0
#define GRAY 1
#define BLACK 2
#define NIL -1

int M[MAX][MAX];
int d[MAX], color[MAX];
int n;

// ダイクストラのアルゴリズムを用いて、最短経路上の各頂点まで道のりを求めて出力する。
void dijkstra()
{
	for (int i = 0; i < n; i++)
	{
		d[i] = INFTY;
		color[i] = WHITE;
	}

	d[0] = 0;
	color[0] = GRAY;

	while (true)
	{
		int u = NIL;
		int minv = INFTY;
		for (int i = 0; i < n; i++)
		{
			if (color[i] != BLACK && d[i] < minv)
			{
				u = i;
				minv = d[i];
			}
		}

		if (u == NIL) break;

		color[u] = BLACK;

		for (int v = 0; v < n; v++)
		{
			if (color[v] != BLACK && M[u][v] != INFTY)
			{
				if (d[u] + M[u][v] < d[v])
				{
					d[v] = d[u] + M[u][v];
					color[v] = GRAY;
				}
			}
		}
	}

	for (int i = 0; i < n; i++)
	{
		int x = d[i] == INFTY ? -1 : d[i];
		std::cout << i << " " << x << std::endl;
	}

}

int main()
{
	std::cin >> n;

	for (int i = 0; i < n; i++)
	{
		for (int j = 0; j < n; j++)
		{
			M[i][j] = INFTY;
		}
	}

	int u, k, v, c;
	for (int i = 0; i < n; i++)
	{
		std::cin >> u >> k;

		for (int j = 0; j < k; j++)
		{
			std::cin >> v >> c;

			M[u][v] = c;
		}
	}

	dijkstra();
}

C++: #include<bits/stdc++.h>
using namespace std;
using UL = unsigned int;
using ULL = unsigned long long;
using LL = long long;
#define rep(i,n) for(UL i=0; i<(n); i++)

template<class E>
using nega_queue=priority_queue<E,vector<E>,greater<E>>;

UL N;
ULL D[100];
vector<pair<UL,ULL>> E[100];

int main() {
 scanf("%u",&N);
 rep(i,N){
  UL u,k; scanf("%u%u",&u,&k);
  rep(j,k){
   UL v,c; scanf("%u%u",&v,&c);
   E[u].push_back({v,c});
  }
 }
 rep(i,N) D[i]=~0u;
 nega_queue<pair<ULL,UL>> G;
 G.push({0,0});
 int ans=0;
 while(G.size()){
  ULL d=G.top().first;
  UL p=G.top().second;
  G.pop();
  if(D[p]!=~0u) continue;
  D[p]=d;
  for(auto e:E[p]) G.push({d+e.second,e.first});
 }
 rep(i,N) printf("%u %llu\n",i,D[i]);
 return 0;
}

C++: #include<iostream>
using namespace std;

static const int MAX = 100;
static const int INFTY = (1 << 21);
static const int WHITE = 0;
static const int GRAY = 1;
static const int BLACK = 2;

int n, M[MAX][MAX];

void dijkstra() {
    
    int minv;
    int d[MAX], color[MAX];
    
    for (int i = 0; i < n; i ++) {
        
        d[i] = INFTY;
        color[i] = WHITE;
        
    }
    
    d[0] = 0;
    
    while(1) {
        
        minv = INFTY;
        int u = -1;
        
        for (int i = 0; i < n; i ++) {
            
            if (minv > d[i] && color[i] != BLACK) {
                
                u = i;
                minv = d[i];
                
            }
            
        }
        
        if (u == -1) {
            
            break;
            
        }
        
        color[u] = BLACK;
        
        for(int v = 0; v < n; v ++) {
            
            if (color[v] != BLACK && M[u][v] != INFTY) {
                
                if (d[v] > d[u] + M[u][v]) {
                    
                    d[v] = d[u] + M[u][v];
                    color[v] = GRAY;
                    
                }
                
            }
            
        }
        
    }
    
    for (int i = 0; i < n; i ++) {
        
        cout << i << " " << (d[i] == INFTY ? -1 : d[i]) << endl;
        
    }
    
}

int main() {
    
    cin >> n;
    
    for (int i = 0; i < n; i ++) {
        
        for (int j = 0; j < n; j ++) {
            
            M[i][j] = INFTY;
            
        }
        
    }
    
    int k, c, u, v;
    
    for (int i = 0; i < n; i ++) {
        
        cin >> u >> k;
        
        for (int j = 0; j < k; j ++) {
            
            cin >> v >> c;
            
            M[u][v] = c;
            
        }
        
    }
    
    dijkstra();
    
    return 0;
    
}

C++: #include<stdio.h>
#define N 101
 
int main()
{
  int i,j,n,count=0,v,c,c1,v1;
  int G[N][N],col[N],d[N],pi[N],mincost,i2;
 
  for(i = 0; i < N; i++){
    for(j = 0; j < N; j++)
      G[i][j] = -1;
  }
 
  scanf("%d",&n);
 
  for(i = 0; i < n; i++){
    scanf("%d%d",&v,&c);
    for(j = 0; j < c; j++){
      scanf("%d%d",&v1,&c1);
      G[v][v1] = c1;
    }
  }
 
  for(i = 0; i < n; i++){
    col[i] = 0;
    pi[i] = -1;
    d[i] = 10000001;
  }
 
  d[0] = 0;
 
  while(1){
    mincost = 10000001;
    for(i = 0; i < n; i++){
      if(col[i] != 2 && d[i] < mincost){
        mincost = d[i];
        i2 = i;
      }
    }
    if(mincost == 10000001)break;
 
    col[i2] = 2;
 
 
    for(i = 0; i < n; i++){
      if(G[i2][i] != -1 && col[i] != 2 && (G[i2][i]+d[i2]) < d[i]){
        pi[i] = i2;
        d[i] = G[i2][i] + d[i2];
        col[i] = 1;
      }
    }
  }
  for(i = 0; i < n; i++)printf("%d %d\n",i,d[i]);
    return 0;
}