Go: package main

import (
	"fmt"
)

func main() {
	var n int
	fmt.Scan(&n)

	g := make([][]int, n+1)
	d := make([]int, n+1)
	for i := 0; i < n; i++ {
		var u,k int
		fmt.Scan(&u)
		fmt.Scan(&k)
		g[u] = make([]int, k)
		for j := 0; j < k; j++ {
			fmt.Scan(&g[u][j])
		}

		d[i+1] = -1
	}

	q := [][]int{}
	q = append(q, []int{1, 0})
	for len(q) > 0 {
		pop := q[0]
		if len(q) > 1 {
			q = q[1:]
		} else {
			q = [][]int{}
		}
		if d[pop[0]] >= 0 {
			continue
		}
		d[pop[0]] = pop[1]

		for j := 0; j < len(g[pop[0]]); j++ {
			q = append(q, []int{g[pop[0]][j], pop[1]+1})
		}
	}

	for i := 1; i <= n; i++ {
		fmt.Printf("%d %d\n", i, d[i])
	}
}

Python: # https://onlinejudge.u-aizu.ac.jp/courses/lesson/1/ALDS1/11/ALDS1_11_C
# 実家のような安心感
# 与えられるノード番号についてはすべて0based indexに治す

from collections import deque

# データの入力
N = int(input())
DG = {}
for i in range(N):
    tmp = input().split()
    if int(tmp[1]) != 0:
        DG[i] = [int(x)-1 for x in tmp[2:]]
    else:
        DG[i] = []


result = {}
is_visited = {key: False for key in range(N)}
# bfs
# 初期queue
que = deque([(0, 0)])  # 必要なものはnodeidと原点からの距離
while que:
    nodeid, cost = que.popleft()  # 先入れ先出し
    result[nodeid] = cost
    is_visited[nodeid] = True  # この文は最初の1for目しか意味ないんだけどなんかうまい方法ないのか
    for nextnode in DG[nodeid]:
        if is_visited[nextnode]:
            pass
        else:  # 未訪問のものについては探索候補に入れる
            que.append((nextnode, cost + 1))
            is_visited[nextnode] = True  # 探索候補に入れた瞬間に訪問管理しないと重複を生じる場合がある

for i in range(N):
    if is_visited[i]:
        print(i + 1, result[i])
    else:
        print(i+1, -1)

Python: N= int(input())
E = [input().split()[2:] for _ in range(N)]
frag, T, L,Q = [0]*N, [0]*N, [0]*N, [0]
a,frag[0] = 100, 1
def func(ide):
    for i in E[ide]:
        i = int(i) - 1
        if frag[i] != 1:frag[i] = 1;L[i] = L[ide] +1 ;Q.append(i) 
        else:return

while Q:top = Q[0];func(top);del Q[0]
for i in range(n):
    if L[i] == 0:
        L[i] == -1

for i in range(N):print(i + 1 ,int(L[i]))

Python: from collections import deque

N = int(input())

nodes = [tuple(map(int, input().split(' '))) for _ in range(N)]

distances = [-1] * (N + 1)

queue = deque()
queue.append((1, 0))

while len(queue) > 0:
    node, distance = queue.popleft()
    if distances[node] != -1:
        continue
    distances[node] = distance

    neighbors = nodes[node - 1][2:]
    for neighbor in neighbors:
        queue.append((neighbor, distance + 1))

for node in range(1, N + 1):
    print(node, distances[node])

Python: #coding: utf-8
inf = 100000000
n = int(input())

List = [0] + [list(map(int,input().split())) for i in range(n)]
color = [0] + ["white" for  i in range(n)]
d = [inf for i in range(n+1)]

s = 1
Q = [s]
d[s] = 0
while Q != []:
    q = Q.pop()
    if color[q] == "white":
        k = List[q][1]
        if k != 0:
            Q += List[q][2:2+k]
            for i in List[q][2:2+k]:
                d[i] = min(d[q] + 1, d[i])
    
    color[q] = "black"


for i, dis in enumerate(d[1:], 1):
    if dis == inf:
        dis = -1
    print(i, dis)

Python: # coding: utf-8
import queue

q = queue.Queue()
A = [[]*101 for _ in range(101)]
d = [-1]*101
visited = [False]*101

n = int(input().rstrip())
for i in range(n):
    line = [int(j) for j in input().rstrip().split()]
    A[i+1].extend(line[2:])

d[1] = 0

q.put(1)
while not q.empty():
    v = q.get()
    if visited[v] == True:
        continue
    visited[v] = True
    for i in A[v]:
        if d[i] == -1:
            d[i] = d[v] + 1
        else:
            d[i] = min(d[i],d[v] + 1)
        q.put(i)
        
for i in range(n):
    print(str(i+1)+" "+str(d[i+1]))

Python: import queue

n = int(input())

Graph = [[x-1 for x in list(map(int, input().split()))[2:]] for i in range(n)]


# for i in range(n):
#     li = list(map(int, input().split()))
#     a = li[0]
#     a-=1
#     b = li[2:]
#     Graph[a].append(b)


dist = [-1]*n
q = queue.Queue()

dist[0] = 0
q.put(0)

while not q.empty():
    v = q.get()

    for nv in Graph[v]:
        if dist[nv] != -1: continue

        dist[nv] = dist[v] + 1
        q.put(nv)


for v in range(n):
    print(v+1, dist[v])

Python: INF = 10**18 + 7


def main():
    from collections import deque
    N = int(input())
    G = [[] for _ in range(N)]
    for _ in range(N):
        u, k, *A = (int(i)-1 for i in input().split())
        G[u] = A

    def bfs(s=0):
        que = deque([])
        dist = [INF]*N
        dist[s] = 0
        que.append(s)
        while que:
            pos = que.popleft()
            for v in G[pos]:
                if dist[v] != INF:
                    continue
                dist[v] = dist[pos] + 1
                que.append(v)
        return dist

    dist = bfs()
    for i, d in enumerate(dist, start=1):
        print(i, d if d != INF else -1)


if __name__ == '__main__':
    main()

C++: #include<bits/stdc++.h>
using namespace std;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
using Graph = vector<vector<int>>;

int main(){
    int n; cin>>n;
    Graph G(n);
    rep(i,n){
        int u,k; cin>>u>>k;
        rep(j,k){
            int v; cin>>v;
            G[u-1].push_back(v-1);
        }
    }

    vector<int> dist(n,-1);
    queue<int> que;

    dist[0]=0;
    que.push(0);

    while(!que.empty()){
        int v = que.front();
        que.pop();

        for(auto nv : G[v]){
            if(dist[nv]!=-1)continue;
            dist[nv] = dist[v] + 1;
            que.push(nv);
        }
    }
    rep(i,n){
        cout<<i+1<<" "<<dist[i]<<endl;
    }
    return 0;
}

C++: #include <stdio.h>
#include <queue>
using namespace std;
struct bfs{
    int n;
    int l;
};
int main(){
    int n,a,m,temp,ans[101];
    bool graph[101][101];
    bfs t,b;
    queue<bfs> q;
    scanf("%d",&n);
    for(int i=0;i<101;i++){
        for(int j=0;j<101;j++){
            graph[i][j]=false;
        }
        ans[i]=-1;
    }
    for(int i=0;i<n;i++){
        scanf("%d%d",&a,&m);
        for(int j=0;j<m;j++){
            scanf("%d",&temp);
            graph[a][temp]=true;
        }
    }
    t.n=1;
    t.l=0;
    q.push(t);
    while(!q.empty()){
        t=q.front();
        q.pop();
        if(ans[t.n]==-1)ans[t.n]=t.l;
        else continue;
        t.l++;
        b=t;
        for(int i=1;i<=n;i++){
            if(graph[t.n][i]){
                b.n=i;
                q.push(b);
            }
        }
    }
    for(int i=1;i<=n;i++){
        printf("%d %d\n",i,ans[i]);
    }
}

C++: #define _CRT_SECURE_NO_WARNINGS
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <vector>
#include <queue>
#include <string.h>
#include <limits.h>
using namespace std;
vector<int> v[101];
int d[101];
queue<int> q;
bool flag[101];
int main(){
	int n, u, k; scanf("%d", &n);
	for (int i = 0; i < n; ++i){
		scanf("%d %d", &u, &k);
		for (int j = 0; j < k; ++j){
			int tmp; scanf("%d", &tmp);
			v[u].push_back(tmp);
		}
	}
	memset(d, -1, sizeof(d));
	d[1] = 0;
	q.push(1); flag[1] = true;
	while (!q.empty()){
		int m = q.front(); q.pop();
		for (int i = 0; i < v[m].size(); ++i){
			int tmp = v[m][i];
			if (!flag[tmp]){
				flag[tmp] = true;
				d[tmp]=d[m]+1;
				q.push(tmp);
			}
		}
	}
	for (int i = 1; i <= n; ++i){
		cout << i << ' ' << d[i] << '\n';
	}
}