Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

//util
var sc = bufio.NewScanner(os.Stdin)

func nextStr() string {
	sc.Scan()
	return sc.Text()
}

func nextInt() int {
	sc.Scan()
	i, e := strconv.Atoi(sc.Text())
	if e != nil {
		panic(e)
	}
	return i
}

func printList(list []int) {
	n := len(list)
	buf := bufio.NewWriter(os.Stdout)
	for _, v := range list[0 : n-1] {
		buf.Write([]byte(fmt.Sprintf("%d ", v)))
	}
	buf.Write([]byte(fmt.Sprintf("%d\n", list[n-1])))
	buf.Flush()
}

func max(a, b int) int {
	if a > b {
		return a
	} else {
		return b
	}
}

func min(a, b int) int {
	if a > b {
		return b
	} else {
		return a
	}
}

//solve
const (
	MAX   = 100
	INFTY = (1 << 21)
	WHITE = 0
	GRAY  = 1
	BLACK = 2
)

//V: グラフの頂点全体の集合
//T: MSTに属する頂点の集合
var (
	n     int
	M     [MAX][MAX]int //重みを記録する隣接行列
	color [MAX]int
	p     [MAX]int //MSTにおける頂点の親を記録
	d     [MAX]int //Tに属する頂点と、V−Tに属する頂点を繋ぐ辺の中で、重みが最小のものを記録
)

func prim() int {
	var u, minv int
	//初期化
	for i := 0; i < n; i++ {
		d[i] = INFTY
		p[i] = -1
		color[i] = WHITE
	}

	d[0] = 0

	for {
		//頂点uを決めていく
		//つまり、Tに属する頂点と、V−Tに属する頂点を繋ぐ辺の中で、重みが最小のものを決める
		minv = INFTY
		u = -1
		for i := 0; i < n; i++ {
			//未訪問かつ、辺の重みが最小となるuを選ぶ
			if minv > d[i] && color[i] != BLACK {
				u = i
				minv = d[i]
			}
		}

		if u == -1 {
			break
		}

		color[u] = BLACK
		for v := 0; v < n; v++ {
			//未訪問かつ、辺が存在するとき
			if color[v] != BLACK && M[u][v] != INFTY {
				if d[v] > M[u][v] {
					d[v] = M[u][v]
					p[v] = u
					color[v] = GRAY
				}
			}
		}
	}

	sum := 0
	for i := 0; i < n; i++ {
		if p[i] != -1 {
			sum += M[i][p[i]]
		}
	}
	return sum
}

func main() {
	sc.Split(bufio.ScanWords)
	n = nextInt()

	for i := 0; i < n; i++ {

		for j := 0; j < n; j++ {
			tmp := nextInt()
			if tmp == -1 {
				tmp = INFTY
			}
			M[i][j] = tmp
		}

	}

	fmt.Println(prim())

}

C++: //Minimum Spannig Tree
#include <iostream>
#include <climits>

using namespace std;

static const int N = 100;
static const int WHITE = 0;
static const int BLACK = 1;
int n, A[N][N], colors[N], d[N], p[N];

int prim() {
    int l = 0, mincost, u;
    for(int i = 0; i < N; i++) {
        colors[i] = WHITE;
        d[i] = INT_MAX;
    }
    d[0] = 0;
    p[0] = -1;
    while(1) {
        mincost = INT_MAX;
        for(int i = 0; i < n; i++) {
            if(colors[i] == WHITE && d[i] < mincost) {
                mincost = d[i];
                u = i;
            }
        }
        if(mincost == INT_MAX) break;
        colors[u] = BLACK;
        l += mincost;
        for(int v = 0; v < n; v++) {
            if(colors[v] == WHITE && A[u][v] != -1) {
                if(A[u][v] < d[v]) {
                    d[v] = A[u][v];
                    p[v] = u;
                }
            }
        }
    }
    return l;
}

int main() {
    int a;
    cin >> n;
    for(int i = 0; i < N; i++) {
        for(int j = 0; j < N; j++) A[i][j] = -1;
    }
    for(int i = 0; i < n; i++) {
        for(int j = 0; j < n; j++){
            cin >> a;
            A[i][j] = a;
        }
    }
    cout << prim() << endl;
}

C++: #include<iostream>

using namespace std;
static const int MAX = 100;
static const int INFTY = (1<<21);
static const int WHITE = 0;
static const int GRAY = 1;
static const int BLACK = 2;

int n, M[MAX][MAX];

int prim() {
   int a, min;
   int d[MAX], p[MAX], color[MAX];
 
   for ( int i = 0; i < n; i++) {
      d[i] = INFTY;
      p[i] = -1;
      color[i] = WHITE;
   }

   d[0] = 0;

   while ( 1 ) {
      min = INFTY;
      u = -1;

      for ( int i = 0; i < n; i++ ) {
         if ( min > d[i] && color[i] != BLACK ) {
            a = i;
            min = d[i];
         }
      }

      if ( a == -1 ) break;
      color[a] = BLACK;
      for ( int v = 0; v < n; v++ ) {
         if ( color[v] != BLACK && M[a][v] != INFTY ) {
            if ( d[v] > M[a][v] ) {
               d[v] = M[a][v];
               color[v] = GRAY;
            }
         }
      }
   }

   int sum = 0;
   for ( int i = 0; i < n; i++ ) {
      if ( p[i] != -1 ) sum = sum + M[i][p[i]];
   }
 
   return sum;
}

int main() {
   cin >> n;

   for ( int i = 0; i < n; i++ ) {
      for ( int j = 0; j < n; j++ ) { 
         int e; cin >> e;
         M[i][j] = (e == -1) ? INFTY : e;
      }
   }

   cout << prim() << endl;

   return 0;
}

C++: #include <iostream>
using namespace std;
#define N 100
#define WHITE 0
#define GRAY 1
#define BLACK 2
#define INFTY 10000

int n, M[N][N];


int prim(){
  int u, mincost;
  int color[N], d[N], p[N];
  for(int i = 0 ; i < n ; i++){
    color[i] = WHITE;
    d[i] = INFTY;
    p[i] = -1;
  }
  d[0] = 0;

  while(true){
    mincost = INFTY;
    u = -1;
    //TとV-Tをつなぐ辺の中で最小のものを探す
    for(int i = 0 ; i < n ; i++){
      if(color[i] != BLACK && d[i] < mincost ){
        mincost = d[i];
        u = i;
      }
    }
    if(u == -1){
      break;
    }
    color[u] = BLACK;

    //Tの中の各頂点からのV-Tの頂点への最短辺の長さをd[v]に入れる
    for(int v = 0 ; v < n ; v++){
      if(color[v] != BLACK && M[u][v] != INFTY){
        if(M[u][v] < d[v]){
          d[v] = M[u][v];
          p[v] = u;
          color[v] = GRAY;
        }
      }
    }

  }
  int sum = 0;
  for(int i = 0 ; i < n ; i ++){
    if(p[i] != -1){
      sum += M[i][p[i]];
    }
  }
  return sum;
}

int main(){
  cin >> n ;
  for(int i = 0; i < n ; i++){
    for(int j = 0 ; j < n ; j++){
      int e;
      cin >> e;
      M[i][j] = (e == -1) ? INFTY: e;
    }
  }
  //int sum = prim();
  cout << prim() << "\n";
  return 0;

}

C++: #include<iostream>
using namespace std;

const int I_MAX = 0xfffffff;
const int MAX = 100;


int main() {
	int n;
	int graph[MAX][MAX];
	bool table[MAX] = { false };
	int sum = 0;

	cin >> n;
	for (int i = 0; i < n; i++) {
		for (int j = 0; j < n; j++) {
			int temp;
			cin >> temp;
			if (temp == -1)temp = I_MAX;
			graph[i][j] = temp;
		}
	}

	table[0] = true;

	for (int i = 0; i < n - 1; i++) {
		int cost = I_MAX;
		int m;

		for (int j = 0; j < n; j++) {
			if (table[j] == false)continue;

			for (int k = 0; k < n; k++) {
				if (graph[j][k] < cost && table[k] == false) {
					cost = graph[j][k];
					m = k;
				}
			}
		}

		sum += cost;
		table[m] = true;
	}

	cout << sum << endl;

	return 0;
}

C++: 
#include<bits/stdc++.h>

using namespace std;

const int maxn=1e2+5;
const int inf=(1<<21);
const int white=0;
const int gray=1;
const int black=2;

int n,m[maxn][maxn];

int prim()
{
    int u,minv;
    int d[maxn],p[maxn],color[maxn];
    for(int i=0;i<n;i++){
        d[i]=inf;
        p[i]=-1;
        color[i]=white;
    }
    d[0]=0;
    while(1){
        minv=inf;
        u=-1;
        for(int i=0;i<n;i++){
            if(minv>d[i]&&color[i]!=black){
                u=i;
                minv=d[i];
            }
        }
        if(u==-1){
            break;
        }
        color[u]=black;
        for(int v=0;v<n;v++){
            if(color[v]!=black&&m[u][v]!=inf){
                if(d[v]>m[u][v]){
                    d[v]=m[u][v];
                    p[v]=u;
                    color[v]=gray;
                }
            }
        }
    }
    int sum=0;
    for(int i=0;i<n;i++){
        if(p[i]!=-1){
            sum+=m[i][p[i]];
        }
    }
    return sum;
}

int main()
{
    scanf("%d",&n);
    for(int i=0;i<n;i++){
        for(int j=0;j<n;j++){
            int e;
            cin>>e;
            m[i][j]=(e==-1)?inf:e;
        }
    }
    cout<<prim()<<endl;
    return 0;
}
/*
5
-1 2 3 1 -1
2 -1 -1 4 -1
3 -1 -1 1 1
1 4 1 -1 3
-1 -1 1 3 -1
*/