Go: package main

import (
	"bufio"
	"container/heap"
	"fmt"
	"os"
)

type Item struct {
	value    int // The value of the item; arbitrary.
	priority int // The priority of the item in the queue.
	// The index is needed by update and is maintained by the heap.Interface methods.
	index int // The index of the item in the heap.
}
type PriorityQueue []*Item

func (pq PriorityQueue) Len() int { return len(pq) }
func (pq PriorityQueue) Less(i, j int) bool {
	return pq[i].priority < pq[j].priority
}
func (pq PriorityQueue) Swap(i, j int) {
	pq[i], pq[j] = pq[j], pq[i]
	pq[i].index = i
	pq[j].index = j
}
func (pq *PriorityQueue) Push(x interface{}) {
	n := len(*pq)
	item := x.(*Item)
	item.index = n
	*pq = append(*pq, item)
}
func (pq *PriorityQueue) Pop() interface{} {
	old := *pq
	n := len(old)
	item := old[n-1]
	item.index = -1 // for safety
	*pq = old[0 : n-1]
	return item
}

type Q struct {
	pq *PriorityQueue
	ds map[int]int // It has always same value as pq. For random access.
}

func newQ() *Q {
	pq := new(PriorityQueue)
	heap.Init(pq)
	return &Q{
		pq: pq,
		ds: make(map[int]int),
	}
}
func (q *Q) pop() (u, d int) {
	item := heap.Pop(q.pq).(*Item)
	delete(q.ds, item.value)
	return item.value, item.priority
}
func (q *Q) get(u int) (int, bool) { // returns d
	d, ok := q.ds[u]
	return d, ok
}
func (q *Q) set(u, d int) {
	q.ds[u] = d
	for _, item := range *q.pq {
		if item.value != u {
			continue
		}

		item.priority = d
		heap.Fix(q.pq, item.index)
		return
	}
	heap.Push(q.pq, &Item{
		priority: d,
		value:    u,
	})
}
func (q *Q) len() int {
	return len(q.ds)
}

func main() {
	r := bufio.NewReader(os.Stdin)

	var n int
	fmt.Fscan(r, &n)
	cs := make([]map[int]int, n) // []v_i -> c_i
	for h := 0; h < n; h++ {
		var u, k int
		fmt.Fscan(r, &u, &k)
		m := make(map[int]int)
		for i := 0; i < k; i++ {
			var v, c int
			fmt.Fscan(r, &v, &c)
			m[v] = c
		}

		cs[u] = m
	}

	q := newQ()
	q.set(0, 0)
	visited := make(map[int]struct{})
	out := make([]int, n)

	for q.len() > 0 {
		u, d := q.pop()
		for uu, c := range cs[u] {
			// Consider the connection between u and uu.
			if _, ok := visited[uu]; ok {
				continue
			}
			dd := d + c
			if d, ok := q.get(uu); !ok || d > dd {
				q.set(uu, dd)
			}
		}

		out[u] = d
		visited[u] = struct{}{}
	}

	for u, d := range out {
		fmt.Println(u, d)
	}
}

Python: from collections import namedtuple
import heapq

Edge = namedtuple('Edge', ('fr', 'to', 'cost'))
inf = int(1e9)


def bellman_ford(n, start, edges):
    dists = [inf for _ in range(n)]
    dists[start] = 0
    while True:
        updated = False
        for e in edges:
            if dists[e.fr] != inf and dists[e.fr] + e.cost < dists[e.to]:
                updated = True
                dists[e.to] = dists[e.fr] + e.cost

        if not updated:
            break

    return dists


def dijkstra(n, costs):
    dists = [inf for _ in range(n)]
    dists[0] = 0

    queue = []
    for (i, d) in enumerate(dists):
        heapq.heappush(queue, (d, i))

    while len(queue) > 0:
        d, i = heapq.heappop(queue)
        if d > dists[i]:
            continue

        for v in range(n):
            if v == i or costs[i][v] == inf:
                continue

            if dists[i] + costs[i][v] < dists[v]:
                dists[v] = dists[i] + costs[i][v]
                heapq.heappush(queue, (dists[v], v))

    return dists


def warshall_floyd(n, costs):
    dists = [[costs[i][j] if i != j else 0 for i in range(n)] for j in range(n)]

    for k in range(n):
        for i in range(n):
            for j in range(n):
                dists[i][j] = min(dists[i][j], dists[i][k] + dists[k][j])

    return dists


n = int(input())

m = [[inf for _ in range(n)] for _ in range(n)]
es = []
for i in range(n):
    fs = list(map(int, input().split()))
    ne = fs[1]
    for j in range(ne):
        v = fs[2+2*j]
        c = fs[2+2*j+1]
        m[i][v] = c
        es.append(Edge(i, v, c))


# d = bellman_ford(n, 0, es)
# d = dijkstra(n, m)
d = warshall_floyd(n, m)
for (i, di) in enumerate(d[0]):
    print(i, di)

Python: from heapq import *

#edge {to cost}
#P {mindirection, modeNum}
#G a list which contain informations of nodes

# building G from input
V=int(input())
G=[]
for _ in range(V):
    temp=list(map(int,input().split()))
    l=[]
    for i in range(1,temp[1]+1):
        l.append(temp[2*i:2*(i+1)])
    G.append(l)

que=[] #having the minimum distance
INF=1e8
d=[INF for i in range(V)] #having the distance
d[0]=0
heappush(que,[0,0])

while len(que)!=0:
    p=heappop(que)
    v=p[1]
    if(d[v]<p[0]):
        continue
    for i in range(len(G[v])):
        e=G[v][i]
        if(d[e[0]]>d[v]+e[1]):
            d[e[0]]=d[v]+e[1]
            heappush(que,[d[e[0]],e[0]])
            
for i in range(V):
    print(i,d[i])

Python: from enum import Enum, auto

INFTY = float('inf')

class Color(Enum):
    WHITE = auto()
    GRAY = auto()
    BLACK = auto()

n = int(input())
M = [[-1 for i in range(n)] for i in range(n)]
for i in range(n):
    line = list(map(int, input().split(' ')))
    if line[1] == 0: continue
    for j in range(2, 2+2*line[1], 2):
        M[i][line[j]] = line[j+1]


colors = []
d = []
p = [-1 for i in range(n)]

def dijkstra(s):
    global d
    colors = [Color.WHITE for i in range(n)]
    d = [INFTY for i in range(n)]
    d[s] = 0
    p[s] = -1

    while True:
        mincost = INFTY
        for i in range(n):
            if colors[i] != Color.BLACK and d[i] < mincost:
                mincost = d[i]
                u = i

        if mincost == INFTY: break
        colors[u] = Color.BLACK

        for v in range(n):
            if colors[v] != Color.BLACK and M[u][v] != -1:
                if d[u] + M[u][v] < d[v]:
                    d[v] = d[u] + M[u][v]
                    p[v] = u
                    colors[v] = Color.GRAY

dijkstra(0)
for i in range(n):
    print(i, d[i])

Python: #coding:utf-8
def Dijkestra(G,n):
    d=[100000000000]*n
    pi=[None]*n
    d[0]=0
    C=[]
    for i in range(n):
        C.append(i)
    
    while len(C)!=0:
        u=C[0]
        for i in range(1,len(C)):
            if d[u]>d[C[i]]:
                u=C[i]
        C.remove(u)
        for i in range(len(G[u])):
            if G[u][i]==-1:
                continue
            elif d[i]>d[u]+G[u][i]:
                d[i]=d[u]+G[u][i]
                pi[i]=u                
    for i in range(n):
        print(i,d[i])
    

if __name__=="__main__":
    n=int(input())
    G=[]
    for i in range(n):
        a=[]
        ele=list(map(int,input().split()))
        k=ele[1]
        t=ele[2:]
        v=c=[]
        for j in range(k):
            v=v+[t[2*j]]
            c=c+[t[2*j+1]]
        for j in range(n):
            if j in v:
                a.append(c[v.index(j)])
            else:
                a.append(-1)
        G.append(a)
    for i in range(n):
        print(G[i])
    Dijkestra(G,n)

Python: n = int(input())
INF = float("inf")
edges = [[] for _ in range(n)]
visited = [False]*n
# edges = [[INF for _ in range(n)] for _ in range(n)]
edges = [[] for _ in range(n) for _ in range(n)]
d = [INF]*n
d[0] = 0

for _ in range(n):
    ls = list(map(int, input().split()))
    u = ls[0]
    degrees = ls[1]
    data = ls[2:]
  
    for i in range(degrees):
        v = data[i*2]
        cost = data[i*2+1]
        edges[u].append((v, cost))
        # edges[u][v] = cost

#通常版
# for _ in range(n):
#     dmin = float("inf")
#     for i in range(n):
#         if not visited[i] and d[i] < dmin:
#             dmin = d[i]
#             u = i
#     visited[u] = True
#     for v, c in enumerate(edges[u]):
#         d[v] = min(d[v], d[u] + c)

# for i in range(n):
#     print(i, d[i])
    
#heap版
import heapq

heap = [(0, 0)]
d[0] = 0


while heap:
    du, u = heapq.heappop(heap)
    for v, cost in edges[u]:
        if du + cost < d[v]:
            d[v] = du +  cost
            heapq.heappush(heap, (d[v], v))

for i in range(n):
    print(i, d[i])