Go: // ダイクストラのアルゴリズム
package main

import (
	"bufio"
	"fmt"
	"log"
	"math"
	"os"
	"strconv"
	"strings"
)

type color int

const (
	white color = iota // 未訪問
	mst                // MSTとして確定
)

// 頂点
type node struct {
	num       int         // 頂点の番号
	weights   map[int]int // 重みMAP
	parent    *node       // MSTへの重み最小の親
	distFromS int         // 始点からの距離
	color     color
}

func main() {
	scanner := bufio.NewScanner(os.Stdin)
	n := eGetInt(scanner)

	nodes := make([]*node, n)
	for i := 0; i < n; i++ {
		weights := eAtoi((strings.Fields(eGetline(scanner))))
		v := &node{weights[0], make(map[int]int, weights[1]), nil, math.MaxInt32, white}
		for j := 0; j < weights[1]; j++ {
			k := weights[j*2+2] // 相手の頂点名
			w := weights[j*2+3] // 重み
			v.weights[k] = w
		}
		nodes[i] = v
	}

	// 初回はnode[0]がMSTに入るように
	nodes[0].distFromS = 0

	for { // 全部チェックするまで

		// どの頂点を新たにMSTに取り込むか

		var minNode *node
		min := math.MaxInt32
		for _, v := range nodes {
			if v.color == mst {
				continue
			}
			if v.distFromS < min {
				min = v.distFromS
				minNode = v
			}
		}
		if minNode == nil {
			// すべて完了している.
			break
		}

		// MSTに追加する頂点決定
		minNode.color = mst

		// fmt.Printf(">[%v]\n", minNode)
		// MSTに属していない頂点それぞれについて,Startからの最小の重みの距離を更新
		for i, v := range nodes {
			if v.color == mst {
				continue
			}
			w, ok := minNode.weights[i]
			if !ok {
				// minNodeと接してない
				continue
			}

			if minNode.distFromS+w < v.distFromS {
				// minNode経由の距離がもっとも重みが少ないので親を変更
				v.distFromS = minNode.distFromS + w
				v.parent = minNode
				// fmt.Printf("[%v %v]\n", v, minNode)
			}
		}
		// fmt.Printf("<\n")
	}

	for i, v := range nodes {
		fmt.Printf("%d %d\n", i, v.distFromS)
	}
}

func eGetInt(scanner *bufio.Scanner) int {
	t := eAtoi(strings.Fields(eGetline(scanner)))
	return t[0]
}

func eGetline(p *bufio.Scanner) string {
	if !p.Scan() {
		if err := p.Err(); err != nil {
			log.Fatal(err.Error())
		}
		return ""
	}
	return p.Text()
}

func eAtoi(s []string) []int {
	ints := make([]int, len(s))
	var err error
	for i, e := range s {
		ints[i], err = strconv.Atoi(e)
		if err != nil {
			log.Fatal(err.Error())
		}
	}
	return ints
}

C++: #include<iostream>
#include<vector>
#include<queue>
#define INF 2e9
using namespace std;

void Dikstra(const vector<vector<pair<int, int> > >& G, vector<int>& d){
    d[0] = 0;
    priority_queue<pair<int, int> , vector<pair<int, int> >, greater<pair<int, int> > > PQ;
    PQ.push(make_pair(0, 0));
    vector<bool> is_black(d.size(), false);
    is_black[0] = true;
    while (!PQ.empty()) {
        int t = PQ.top().second;
        PQ.pop();
        is_black[t] = true;
        for (int i = 0; i < G[t].size(); i++) {
            int v = G[t][i].first;
            int w = G[t][i].second;
            if (!is_black[v] && d[t] + w < d[v]) {
                d[v] = d[t] + w;
                PQ.push(make_pair(d[v], v));
            }
        }
    }
}

int main(){
    int n;
    cin >> n;
    vector<vector<pair<int, int> > > G(n);
    for (int i = 0; i < n; i++) {
        int u, k;
        cin >> u >> k;
        for (int j = 0; j < k; j++) {
            int v, c;
            cin >> v >> c;
            G[u].push_back(make_pair(v, c));
        }
    }
    vector<int> d(n, INF);
    Dikstra(G, d);
    for (int i = 0; i < n; i++) {
        cout << i << " " << d[i] << endl;
    }

    return 0;
}

C++: #include<iostream>
using namespace std;
static const int MAX = 100;
static const int INFTY = (1<<21);
static const int WHITE = 0;
static const int GRAY = 1;
static const int BLACK = 2;

int n, M[MAX][MAX];

void dijkstra(int s) {
    int color[n], d[n], p[n];
    for (int i=0; i<n; i++) {
        color[i] = WHITE;
        d[i] = INFTY;
    }
    d[s] = 0;
    color[s] = GRAY;

    while (1) {
        int mincost = INFTY;
        int u = -1;
        for (int i=0; i<n; i++) {
            if (color[i]!=BLACK && d[i]<mincost) {
                mincost = d[i];
                u = i;
            }
        }

        if (mincost == INFTY) {
            break; // All nodes visited
        }

        color[u] = BLACK;
        for (int v=0; v<n; v++) {
            if (color[v]!=BLACK && M[u][v]<INFTY) {
                if (d[u]+M[u][v]<d[v]) {
                    d[v] = d[u]+M[u][v];
                    color[v] = GRAY;
                }
            }
        }
    }

    for (int i=0; i<n; i++) {
        cout << i << " " << d[i] << endl;
    }
}

int main() {
    cin >> n;
    for (int i=0; i<n; i++) {
        for (int j=0; j<n; j++) {
            M[i][j] = INFTY;
        }
    }

    int u, k, v, c;
    for (int i=0; i<n; i++) {
        cin >> u >> k;
        for (int j=0; j<k; j++) {
            cin >> v >> c;
            M[u][v] = c;
        }
    }
 
    dijkstra(0);
    return 0;
}

C++: #include <iostream>

using namespace std;
#define MAX 100
#define NIL (1<<21)
#define WHITE 0
#define GRAY 1
#define BLACK 2
int G[MAX][MAX];//图的邻接矩阵
int color[MAX];//节点状态
int n;
int d[MAX];//最小权值
int p[MAX];//父亲节点
void dijkstra(){
    for(int i=0;i<n;i++){
        color[i] = WHITE;
        d[i] = NIL;
        p[i] = -1;
    }
    d[0] = 0;
    while(1){
        int u;
        int mincost = NIL;
        for(int i=0;i<n;i++){//循环找到下一个要加入到S中的(d[u]最小值)
            if(color[i]!=BLACK&&d[i]<mincost){
                mincost = d[i];
                u = i;
            }
        }
        if(mincost==NIL){
            break;
        }
        color[u] = BLACK;
        for(int v=0;v<n;v++){//给相邻顶点的d赋值（与之前的相比较，找到最小的）
            if(color[v]!=BLACK&&G[u][v]!=-1){
                    if(d[u]+G[u][v]<d[v]){
                        d[v] = d[u]+G[u][v];
                        p[v] = u;
                    }
                }
            }
        }



}
int main()
{
    cin>>n;
     for(int i=0;i<n;i++){
        for(int j=0;j<n;j++){
            G[i][j] = -1;
        }

    }
    for(int i=0;i<n;i++){
        int u,k;
        cin>>u>>k;
        for(int i=0;i<k;i++){
            int v,c;
            cin>>v>>c;
            G[u][v] = c;
        }
    }

    dijkstra();
    for(int i=0;i<n;i++){
        cout<<i<<" "<<d[i]<<endl;
    }
    return 0;
}