Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

const R = 100000000

var sc = bufio.NewScanner(os.Stdin)

var n int
var A [101][101]int

func nextInt() int {
	sc.Scan()
	i, _ := strconv.Atoi(sc.Text())
	return i
}
func prim() int {
	var u, Minimum, sum int
	var d, p, color [101]int

	for i := 0; i < n; i++ {
		d[i] = R
		p[i] = -1
		color[i] = 0
	}
	d[0] = 0

	for {
		Minimum = R
		u = -1
		for i := 0; i < n; i++ {
			if Minimum > d[i] && color[i] != 2 {
				u = i
				Minimum = d[i]
			}
		}
		if u == -1 {
			break
		}
		color[u] = 2
		for j := 0; j < n; j++ {
			if color[j] != 2 && A[u][j] != R {
				if d[j] > A[u][j] {
					d[j] = A[u][j]
					p[j] = u
					color[j] = 1
				}
			}
		}
	}

	for i := 0; i < n; i++ {
		if p[i] != -1 {
			sum += A[i][p[i]]
		}
	}
	return sum
}
func main() {
	sc.Split(bufio.ScanWords)
	n = nextInt()

	for i := 0; i < n; i++ {
		for j := 0; j < n; j++ {
			e := nextInt()
			if e == -1 {
				A[i][j] = R
			} else {
				A[i][j] = e
			}
		}
	}
	fmt.Println(prim())
}

C++: #include <bits/stdc++.h>
using namespace std;
typedef long long ll;
using vll = vector<ll>;
using vi = vector<int>;
using vb = vector<bool>;
using pii = pair<int, int>;

template <class T>
inline bool chmin(T &a, T b)
{
    if (a > b)
    {
        a = b;
        return true;
    }
    return false;
}
template <class T>
inline bool chmax(T &a, T b)
{
    if (a < b)
    {
        a = b;
        return true;
    }
    return false;
}

//pow(llpow,modpow)
template <class T>
ll llpow(ll x, T n)
{
    ll ans = 1;
    if (x == 0)
        ans = 0;
    while (n)
    {
        if (n & 1)
            ans *= x;
        x *= x;
        n >>= 1;
    }
    return ans;
}
long long modpow(long long a, long long n, long long mod)
{
    long long res = 1;
    while (n > 0)
    {
        if (n & 1)
            res = res * a % mod;
        a = a * a % mod;
        n >>= 1;
    }
    return res;
}
//最大公約数
template <class T>
inline T gcd(T x, T y)
{
    if (y == 0)
        return x;
    else
    {
        return gcd(y, x % y);
    }
}
//最小公倍数
template <class T>
inline T lcm(T x, T y) { return x / gcd(x, y) * y; }
//逆元
long long modinv(long long a, long long m)
{
    long long b = m, u = 1, v = 0;
    while (b)
    {
        long long t = a / b;
        a -= t * b;
        swap(a, b);
        u -= t * v;
        swap(u, v);
    }
    u %= m;
    if (u < 0)
        u += m;
    return u;
}

#define rep(i, begin_i, end_i) for (ll i = (ll)begin_i; i < (ll)end_i; i++)

long long INF = 1LL << 60;
int main()
{
    int n;
    cin >> n;
    vector<vi> a(n,vector<int> (n));
    rep(i, 0, n)
    {
        rep(j, 0, n)
        {
            cin >> a[i][j];
            if(a[i][j]==-1)a[i][j]=1<<30;
        }
    }
    ll res = 0;
    set<int> rem,visited;
    visited.insert(0);
    rep(i,1,n)rem.insert(i);
    while(!rem.empty()){
        int minv=1<<30,mini=-1;
        for(int prev:visited){
            for(int next:rem){
                if(a[prev][next]<minv){
                    minv=a[prev][next];
                    mini=next;
                }
            }
        }
        res+=minv;
        rem.erase(mini);
        visited.insert(mini);
    }
    cout<<res<<endl;
    return 0;
}

C++: /* minimum_spanning_tree_prim.cpp
    プリム法で最小全域木とそのコストを求める（隣接行列 向き）
    計算量: O(|E|log|V|)

    verified: AOJ ALDS1_12_A Minimum Spanning Tree
        http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=ALDS1_12_A&lang=jp
 */

#include <bits/stdc++.h>
using namespace std;

vector<vector<int>> G;  // 隣接行列での表現

/* Prim : プリム法で minimum spanning tree を求める構造体
    入力: 隣接行列でのグラフ G
    最小全域木の重みの総和: sum
    計算量: O(|V|^2)
*/
struct Prim {
    const int INF = 1e9;
    int sum;              // MSTの重みの総和
    int n;                // 頂点数
    vector<int> mincost;  // 既に確定した頂点からの最小コスト（確定済みから行けない時は INF）
    vector<bool> used;    // 既に確定したかどうか
    Prim(vector<vector<int>> const& Graph) {
        init(Graph);
    }
    void init(vector<vector<int>> const& Graph) {
        n = (int)Graph.size();
        mincost.assign(n, INF);
        used.assign(n, false);
        sum = 0;
        mincost[0] = 0;  // 始め頂点0からスタートさせる
        while (true) {
            int v = -1;
            for (int u = 0; u < n; u++) {  // コストが最小で行ける頂点 v を探す
                if (!used[u] && (v == -1 || mincost[u] < mincost[v])) v = u;
            }
            if (v == -1) break;  // MST ができたので終了
            used[v] = true;
            sum += mincost[v];
            for (int u = 0; u < n; u++) {  // 確定した頂点から行ける頂点について、最小コストを更新
                if (Graph[v][u] != -1) mincost[u] = min(mincost[u], Graph[v][u]);
            }
        }
    }
};

int main() {
    int n;
    cin >> n;
    G.assign(n, vector<int>(n));
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++) {
            cin >> G[i][j];
        }
    }
    Prim prim(G);
    cout << prim.sum << endl;
    return 0;
}

C++: #include <iostream>

using namespace std;

#define INT_MIN     (-2147483647 - 1) /* minimum (signed) int value */
#define INT_MAX       2147483647    /* maximum (signed) int value */
static const int MAX = 100;
static const int WHITE = 0;
static const int GRAY = 1;
static const int BLACK = 2;

int n, m[MAX][MAX];

int prim()
{
	int color[MAX], p[MAX], d[MAX];
	int u, minv;

	for (int i = 0; i < n; ++i)
	{
		color[i] = WHITE;
		p[i] = -1;
		d[i] = INT_MAX;
	}

	d[0] = 0;

	while (1)
	{
		minv = INT_MAX;
		u = -1;
		for (int i = 0; i < n; ++i)
		{
			if (d[i] < minv && color[i] != BLACK)
			{
				u = i;
				minv = d[i];
			}
		}

		if (-1 == u) 
			break;
		color[u] = BLACK;

		for (int i = 0; i < n; ++i)
		{
			if (m[u][i] < d[i] && color[i] != BLACK)
			{
				d[i] = m[u][i];
				p[i] = u;
				color[i] = GRAY;
			}
		}
	}

	int sum = 0;
	for (int i = 0; i < n; ++i)
	{
		if (p[i] != -1) 
			sum += m[p[i]][i];
	}
	return sum;
}

int main()
{
	cin >> n;
	for (int i = 0; i < n; ++i)
	{
		for (int j = 0; j < n; ++j)
		{
			int e; cin >> e;
			m[i][j] = (e == -1) ? INT_MAX : e;
		}
	}
	cout << prim() << endl;
}

C++: #include <bits/stdc++.h>
#define rep(i,a) for(i=0;i<a;i++)
using namespace std;
static const int W 0
static const int G 1
static const int B 2

void prim(int n, int *total, vector<vector<int> > &M) {
    int i,u,min;
    vector<int> d(n);
    vector<int> p(n);
    vector<int> color(n);

    rep(i,n){
        d[i] = INT_MAX;
        p[i] = -1;
        color[i] = INT_MAX;
    }
    d[0] = 0;
    while(true){
        min = INT_MAX;
        u = -1;
        rep(i,n){
            if(min > d[i] && color[i] != B) {
                u = i;
                min = d[i];
            }
        }
        if(u==-1) break;
        color[u] = B;
        rep(i,n){
            if(color[i] != B && M[u][i])
                if(d[i] > M[u][i]) {
                    d[i] = M[u][i];
                    p[i] = u;
                    color[u] = G;
                }
        }
    }
    rep(i,n){
        if(p[i] != -1) total += M[i][p[i]]
    }
}

int main(void) {
    int i,j,n,total = 0;
    vector<vector<int> > M;
    cin >> n;
    M.resize(n);

    rep(i,n){
        M[i].resize(n);
    }
    rep(i,n){
        rep(j,n){
            cin >> M[i][j];
            if(M[i][j] != -1) M[i][j] = INT_MAX;

        }
    }
    prim(n,&total,M);
    cout << total;
    return 0;
}