Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

const BIG_COST = 200000

type Path struct {
	node int
	cost int
}

func main() {
	sc := bufio.NewScanner(os.Stdin)
	sc.Split(bufio.ScanWords)

	nNodes := scanInt(sc)

	// 各頂点につながる頂点一覧を得るための隣接リスト
	graph := make([][]Path, nNodes)

	for i := 0; i < nNodes; i++ {
		u := scanInt(sc)
		k := scanInt(sc)
		graph[i] = make([]Path, k)
		for d := 0; d < k; d++ {
			graph[u][d] = Path{
				node: scanInt(sc),
				cost: scanInt(sc),
			}
		}
	}

	// 0 から各頂点への最小コストを保存する配列
	minCosts := make([]int, nNodes)

	minCosts[0] = 0
	for i := 1; i < nNodes; i++ {
		minCosts[i] = BIG_COST
	}

	// 各頂点が調査済みかどうかを保持する配列
	checked := make([]bool, nNodes)

	// 最小コストのパスを高速に取得するためのヒープ。
	// コストが小さいものほどルートに来るようにする。
	heap := NewHeap(func(a, b Path) bool {
		return a.cost < b.cost
	})

	heap.insert(Path{node: 0, cost: 0})
	for heap.size > 0 {
		u := heap.extractMax()

		// 隣接行列を使っていた時とは違い、ヒープには
		// 同じノードへのパスが複数含まれうる。そのため既によりコストの低い
		// パスが見つかっている場合は無視する。
		if minCosts[u.node] < u.cost {
			continue
		}

		checked[u.node] = true

		for _, v := range graph[u.node] {
			cost := v.cost + u.cost
			if !checked[v.node] && cost < minCosts[v.node] {
				minCosts[v.node] = cost
				heap.insert(Path{node: v.node, cost: cost})
			}
		}
	}

	w := bufio.NewWriter(os.Stdout)
	for i, cost := range minCosts {
		fmt.Fprintf(w, "%d %d\n", i, cost)
	}
	w.Flush()
}

func scanInt(sc *bufio.Scanner) int {
	sc.Scan()
	v, _ := strconv.Atoi(sc.Text())
	return v
}

// --- From ALDS1_9_C: Priority Queue

type Heap struct {
	size   int
	heap   []Path
	isHigh func(a, b Path) bool
}

func NewHeap(isHigh func(a, b Path) bool) Heap {
	heap := make([]Path, 1) // 先頭は不使用
	return Heap{size: 0, heap: heap, isHigh: isHigh}
}

func (h *Heap) insert(v Path) {
	h.size += 1
	if h.size > len(h.heap)-1 {
		h.heap = append(h.heap, v)
	} else {
		h.heap[h.size] = v
	}

	for i := h.size; i > 1; {
		parent := i / 2
		if h.isHigh(h.heap[parent], h.heap[i]) {
			break
		}
		h.heap[i], h.heap[parent] = h.heap[parent], h.heap[i]
		i = parent
	}
}

func (h *Heap) extractMax() Path {
	if h.size <= 0 {
		panic("cannot extract from empty heap")
	}

	max := h.heap[1]
	h.heap[1] = h.heap[h.size]
	h.size -= 1
	h.maxHeapify(1)

	return max
}

func (h *Heap) maxHeapify(idx int) {
	left := idx * 2
	right := left + 1
	largest := idx

	if left <= h.size {
		if h.isHigh(h.heap[left], h.heap[idx]) {
			largest = left
		}
		if right <= h.size && h.isHigh(h.heap[right], h.heap[largest]) {
			largest = right
		}
	}

	if largest != idx {
		h.heap[idx], h.heap[largest] = h.heap[largest], h.heap[idx]
		h.maxHeapify(largest)
	}
}

C++: #include <bits/stdc++.h>

using namespace std;

vector<int> adja[10000], cost[10000];

#define INF (1 << 30)

int main() {
	int n, id, k;

	cin >> n;
	for (int i = 0; i < n; ++i) {
		cin >> id >> k;
		adja[id].resize(k);
		cost[id].resize(k);
		for (int j = 0; j < k; ++j) {
			cin >> adja[id][j] >> cost[id][j];
		}
	}

	priority_queue<pair<int, int>> que;
	que.push(make_pair(0, 0)); //cost, node
	int best[10000];
	fill(best, best + n, INF);
	best[0] = 0;

	while (!que.empty()) {
		pair<int, int> top = que.top();
		que.pop();

		if (best[top.second] < top.first) {
			continue;
		}

		for (int j = 0, len = adja[top.second].size(); j < len; ++j) {
			if (best[adja[top.second][j]] > top.first + cost[top.second][j]) {
				best[adja[top.second][j]] = top.first + cost[top.second][j];
				que.push(make_pair(top.first + cost[top.second][j], adja[top.second][j]));
			}
		}
	}

	for (int i = 0; i < n; ++i) {
		cout << i << " " << best[i] << endl;
	}

	return 0;
}

C++: #include <iostream>
#include <cstdio>
#include <vector>
#include <queue>
using namespace std;
const int num = 10000, num1 = 500000, INF = 20000000;
int n, d[num], c[num];
vector<pair<int, int> > v[num];
priority_queue<pair<int, int> > q;
inline void mini() {
	q.push(make_pair(0, 0));
	while (!q.empty()) {
		pair<int, int> p = q.top(); q.pop();
		int a = p.second;
		c[a] = 1;
		for (int i = 0; i < v[a].size(); i++) {
			int b = v[a][i].first;
			if (c[b] == 0 && d[b] > d[a] + v[a][i].second) {
				d[b] = d[a] + v[a][i].second;
				q.push(make_pair(d[b] * -1, b));
			}
		}
	}
		
}
int main() {
	int u, k, s, t;
	cin >> n;
	for (int i = 1; i < n; i++) {
		d[i] = INF;
		c[i] = 0;
	}
	d[0] = 0;
	for (int i = 0; i < n; i++) {
		scanf("%d%d", &u, &k);
		for (int j = 0; j < k; j++) {
			scanf("%d%d", &s, &t);
			v[u].push_back(make_pair(s, t));
		}
	}
	mini();
	for (int i = 0; i < n; i++) {
		printf("%d %d\n", i, d[i]);
	}
	return 0;
}

C++: #include <iostream>
#include <limits.h>
#include <vector>
#include <queue>

using namespace std;

struct Node {
    int cost = INT_MAX;
    int color = 0;
    vector<int> next_node;
    vector<int> len_cost;
} node[100];

int main() {
    int n, id, k;

    cin >> n;
    for (int i = 0; i < n; i++) {
        cin >> id >> k;
        node[id].next_node.resize(k);
        node[id].len_cost.resize(k);
        for (int j = 0; j < k; j++) {
            cin >> node[id].next_node[j] >> node[id].len_cost[j];
        }
    }

    int size1, size2;
    vector<int> vec;
    node[0].cost = 0;
    node[0].color = 1;
    vec.push_back(0);
    while (1) {
        size1 = vec.size();
        if (size1 == n) {
            break;
        }
        for (int i = 0; i < size1; i++) {
            size2 = node[vec[i]].next_node.size();
            for (int j = 0; j < size2;) {
                if (node[node[vec[i]].next_node[j]].cost > node[vec[i]].cost + node[vec[i]].len_cost[j]) {
                    node[node[vec[i]].next_node[j]].cost = node[vec[i]].cost + node[vec[i]].len_cost[j]; //????????????????????\????????\??????
                    j++;
                }
                else if (node[node[vec[i]].next_node[j]].cost < node[vec[i]].cost + node[vec[i]].len_cost[j]) { //?°????????????¨??????????????????????????¨??????
                    node[vec[i]].next_node.erase(node[vec[i]].next_node.begin() + j);
                    node[vec[i]].len_cost.erase(node[vec[i]].len_cost.begin() + j);
                    size2--;
                }
                else {
                    j++;
                }
            }
        }
        //?????\??????????????????????????????
        int min = INT_MAX, mini;
        for (int i = 0; i < size1; i++) {
            size2 = node[vec[i]].next_node.size();
            for (int j = 0; j < size2; j++) {
                if (min > node[node[vec[i]].next_node[j]].cost && node[node[vec[i]].next_node[j]].color == 0) {
                    min = node[node[vec[i]].next_node[j]].cost;
                    mini = node[vec[i]].next_node[j];
                }
            }
        }
        vec.push_back(mini);
        node[mini].color = 1;
    }

    for (int i = 0; i < n; i++) {
        cout << i << " " << node[i].cost << endl;
    }
    
    return 0;
}

C++: #include<bits/stdc++.h>
using namespace std;
typedef long long LL;
typedef pair<LL,LL> P;
const LL mod=1e9+7;
const LL LINF=1LL<<62;
string u="abcdefghijklmnopqrstuvwxyz";

struct edge {int to;LL cost;};

const int M_N=10000;

vector<edge> G[M_N+1];
LL d[M_N+1];

struct Dijkstra{

    void dijkstra(int s){
        priority_queue<P,vector<P>,greater<P>> que;
        que.push(P(0,s));
        while(!que.empty()){
            P p=que.top();
            que.pop();
            int v=p.second;
            if(d[v]<p.first) continue;
            for(int i=0;i<G[v].size();i++){
                edge e=G[v][i];
                if(d[e.to]>d[v]+e.cost){
                    d[e.to]=d[v]+e.cost;
                    que.push(P(d[e.to],e.to));
                }
            }
        }
    }

};

int main(){
    Dijkstra Ds;
    fill(d,d+M_N+1,LINF);
    d[0]=0;
    int N;
    cin >> N;
    int u,k,v,c;
    while(cin >> u >> k){
        for(int i=0;i<k;i++){
            cin >> v >> c;
            G[u].push_back({v,c});
        }
    }
    Ds.dijkstra(0);
    for(int i=0;i<N;i++){
        cout << i <<" "<< d[i] << endl;
    }
    return 0;
}