Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

var scanner = bufio.NewScanner(os.Stdin)

func nextString() string {
	scanner.Scan()
	return scanner.Text()
}

func nextInt() int {
	n, err := strconv.Atoi(nextString())
	if err != nil {
		fmt.Printf("strconv.Atoi failed: %v\n", err)
	}
	return n
}

var infty = 1000000000

type DirectedGraphNodeID int

type DirectedGraphNode struct {
	key         DirectedGraphNodeID
	adjacents   []*DirectedGraphNode
	costs       []int
	distance    int
	predecessor *DirectedGraphNode
}

func newDirectedGraph(nNodes int) *DirectedGraph {
	graph := DirectedGraph{}
	graph.nodes = make([]*DirectedGraphNode, nNodes)
	for i := 0; i < nNodes; i++ {
		node := DirectedGraphNode{}
		node.key = DirectedGraphNodeID(i)
		node.distance = infty
		graph.nodes[i] = &node
	}
	return &graph
}

type DirectedGraph struct {
	nodes []*DirectedGraphNode
}

func (g *DirectedGraph) setAdjacency(i, j DirectedGraphNodeID, cost int) {
	g.nodes[i].adjacents = append(g.nodes[i].adjacents, g.nodes[j])
	g.nodes[i].costs = append(g.nodes[i].costs, cost)
}

func (g *DirectedGraph) print() {
	for i := 0; i < len(g.nodes); i++ {
		node := g.nodes[i]
		key := node.key
		strings := []string{strconv.Itoa(int(key)), strconv.Itoa(node.distance)}
		for j := 0; j < len(node.adjacents); j++ {
			nodeJ := fmt.Sprintf("(%v, %v)", node.adjacents[j].key, node.costs[j])
			strings = append(strings, nodeJ)
		}
		fmt.Printf("%v\n", strings)
	}
}

func (g *DirectedGraph) relaxEdge(l, r *DirectedGraphNode, w int) {
	if r.distance > l.distance+w {
		// fmt.Printf("%v -> %v, %v\n", l.key, r.key, l.distance+w)
		r.distance = l.distance + w
		r.predecessor = l
	}
}

func main() {
	scanner.Split(bufio.ScanWords)

	nNodes := nextInt()
	graph := newDirectedGraph(nNodes)

	for i := 0; i < nNodes; i++ {
		iNode := DirectedGraphNodeID(nextInt())
		nAdjacent := nextInt()
		for j := 0; j < nAdjacent; j++ {
			jNode := DirectedGraphNodeID(nextInt())
			cost := nextInt()
			graph.setAdjacency(iNode, jNode, cost)
		}
	}

	graph.nodes[0].distance = 0
	for iNode := 0; iNode < nNodes; iNode++ {
		for iLeft := 0; iLeft < len(graph.nodes); iLeft++ {
			nodeLeft := graph.nodes[iLeft]
			for iRight := 0; iRight < len(nodeLeft.adjacents); iRight++ {
				nodeRight := nodeLeft.adjacents[iRight]
				cost := nodeLeft.costs[iRight]
				graph.relaxEdge(nodeLeft, nodeRight, cost)
			}
		}
	}

	// graph.print()

	for iNode := 0; iNode < len(graph.nodes); iNode++ {
		node := graph.nodes[iNode]
		fmt.Println(node.key, node.distance)
	}
}

Python: INFTY = 1 << 21
WHITE = 0
GRAY = 1
BLACK = 2
 
n = int(input())
M = [list(map(int, input().split())) for i in range(n)]
 
d = [INFTY for i in range(n)]
color = [INFTY for i in range(n)]
 
for i in range(n):
    u = int(input())
    k = int(input())
    for j in range(k):
        v = int(input())
        c = int(input())
        M[u][v] = c
        
def dijkstra():
    global M, d, p, color
    d[0] = 0
    color[0] = GRAY
    while(1):
        minv = INFTY
        u = -1
        for i in range(n):
            if (minv > d[i] and color[i] != BLACK):
                u = i
                minv = d[i]
        if (u == -1):
            break
        color[u] = BLACK
        for v in range(n):
            if (color[v] != BLACK and M[u][v] != INFTY):
                if (d[v] > d[u] + M[u][v]):
                    d[v] = d[u] + M[u][v]
                    color[v] = GRAY
    for i in range(n):
        print(str(i) + " " + str(d[i]))
print(dijkstra())

Python: # Graph II - Single Source Shortest Path I
def dijkstra(length, adj_m):
    INFTY = float('inf')
    d = [INFTY for _ in range(length)]
    d[0] = 0
    Q = [i for i in range(length)]
    while Q:
        idx = INFTY
        minv = INFTY
        for q in Q:
            if d[q] < minv:
                idx, minv = q, d[q]
        u = Q.pop(Q.index(idx))
        for i, v in enumerate(adj_m[u]):
            if not v == -1:
                if d[i] > d[u] + v:
                    d[i] = d[u] + v
    return d

n = int(input())
adj_m = [[-1 for _ in range(n)] for _ in range(n)]
for _ in range(n):
    ss = list(map(int, input().split()))
    u, k = ss[0], ss[1]
    for i in range(k):
        vi,ci = ss[2*i+2], ss[2*i+3]
        adj_m[u][vi] = ci
d = dijkstra(n, adj_m)
for i,v in enumerate(d): print(i,v)

Python: import argparse
import sys
inf = sys.maxsize
import heapq

def dijkstra_heap(edge_list, node):    
    distance_list = n_node * [inf]
    distance_list[node] = 0
    heap = []
    heapq.heappush(heap, (0, 0))

    while(heap):
        temp_dist, from_node = heapq.heappop(heap)
        if distance_list[from_node] < temp_dist:
            continue
        
        for to_node, cost in edge_list[from_node].items():
            if distance_list[to_node] > distance_list[from_node] + cost:
                distance_list[to_node] = distance_list[from_node] + cost
                heapq.heappush(heap, (distance_list[to_node], to_node))
    
    return distance_list


if __name__ == "__main__":
    parser = argparse.ArgumentParser()
    parser.add_argument('--input', type=str)
    args = parser.parse_args()
    edge_input = []
    if args.input:
        f = open(args.input, 'r')
        n_node = int(f.readline())                
        for _ in range(n_node):            
            edge_input.append(tuple(map(int, f.readline().split()))[2:])
        f.close()
    else:
        n_node = int(input())
        for i in range(n_node):            
            edge_input.append(tuple(map(int, input().split()))[2:])
    
    edge_list = [None] * n_node
    for i in range(n_node):
        edge_list[i] = {}
        for j in range(0, len(edge_input[i]), 2):
            edge_list[i][edge_input[i][j]] = edge_input[i][j+1]

    distance_list = dijkstra_heap(edge_list, 0)

    # # bellman_ford(edge_list, 0)
    # distance_list = dijkstra(edge_list, 0)
    for i, ditance in enumerate(distance_list):
        print(i, distance_list[i])

Python: import sys
input = sys.stdin.readline


def dijkstra_v2(start: int, matrix: list) -> list:
    """dijkstra法: 始点startから各頂点への最短距離を求める
    計算量: O(V^2)
    """
    INF = 10 ** 18
    n = len(matrix)
    used = [False] * n
    dist = [INF] * n
    dist[start] = 0
    while True:
        v = -1
        for u in range(n):
            if not used[u] and (v == -1 or dist[u] < dist[v]):
                v = u
        if v == -1:
            break
        used[v] = True
        for nxt_v in range(n):
            dist[nxt_v] = min(dist[nxt_v], dist[v] + matrix[v][nxt_v])
    return dist
  

n = int(input())
info = [list(map(int, input().split())) for i in range(n)]
INF = 10 ** 18

matrix = [[INF] * n for i in range(n)]
for a in range(n):
    matrix[a][a] = 0
    for j in range(1, len(info[a]) // 2):
        b, cost = info[a][slice(2 * j, 2 * (j + 1))]
        matrix[a][b] = cost

dist = dijkstra_v2(0, matrix)
for v, ans in enumerate(dist):
    print(v, ans)

Python: #!/usr/bin/python3
from heapq import heappop, heappush
n = int(input())
inf = 100 * 100000

M = [[] for i in range(n)]

for i in range(n):
    L = list(map(int, input().split()))
    u = L[0]
    k = L[1]
    v = L[2::2]
    c = L[3::2]
    for j in range(k):
        M[u].append((v[j], c[j]))
result = [0] * n
S = set()
V = set(range(n))
S.add(0)
d = []
for m in M[0]:
    heappush(d, (m[1], m[0]))
T = V - S

while len(T) != 0:
    c, v = heappop(d)
    while v in S:
        c, v = heappop(d)
    result[v] = c
    S.add(v)
    T.remove(v)
    for m in M[v]:
        if m[0] in T:
            heappush(d, (result[v] + m[1], m[0]))

for i, v in enumerate(result):
    print(i, v)