Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

const BIG_COST = 3000

const (
	ST_NOT_YET = iota
	ST_JOINED
)

func main() {
	sc := bufio.NewScanner(os.Stdin)
	sc.Split(bufio.ScanWords)

	nNodes := scanInt(sc)
	costs := make([][]int, nNodes)

	for r := 0; r < nNodes; r++ {
		costs[r] = make([]int, nNodes)
		for c := 0; c < nNodes; c++ {
			costs[r][c] = scanInt(sc)
		}
	}

	states := make([]int, nNodes)
	minCosts := make([]int, nNodes)

	for i := 1; i < nNodes; i++ {
		minCosts[i] = BIG_COST
	}

	for {
		var u int
		minCost := BIG_COST

		for i := 0; i < nNodes; i++ {
			if states[i] != ST_JOINED && minCosts[i] < minCost {
				minCost = minCosts[i]
				u = i
			}
		}

		// 全てのノードが MST に JOIN できたので終了。
		if minCost == BIG_COST {
			break
		}

		states[u] = ST_JOINED

		for v := 0; v < nNodes; v++ {
			cost := costs[u][v]

			// MST内の u と MST外の v との辺の重みをそれぞれ minCosts[v] として
			// 保存しておく。このうち辺の重みが最小となる v が次のループで MST に JOIN する。
			if states[v] != ST_JOINED && cost != -1 && cost < minCosts[v] {
				minCosts[v] = cost
			}
		}
	}

	sum := 0
	for _, cost := range minCosts {
		sum += cost
	}
	fmt.Println(sum)
}

func scanInt(sc *bufio.Scanner) int {
	sc.Scan()
	v, _ := strconv.Atoi(sc.Text())
	return v
}

C++: #include <iostream>

using namespace std;

#define N_MAX 100
#define W_MAX 2000

int Adj[N_MAX][N_MAX] = {};

int color[N_MAX] = {};

int sum_mst_path = 0;
int n;

int prim(void);

int main(){
    int i, j;

    cin >> n;
    for (i = 0; i < n; i++) {
        for (j = 0; j < n; j++) {
            cin >> Adj[i][j];
        }
    }

    color[0] = 1;
    while ( prim() );

    cout << sum_mst_path << endl;

    return 0;
}

//[?????????
//0 : MST????§???????????????????
//1 : ???????????????????????????
int prim(void) {
    int i, j, min, next_node;

    min = W_MAX + 1;
    next_node = N_MAX + 1;

    //?¢????node???????????????????¢????node??????????????§???????°??????¢???path?????¢?´¢
    for (i = 0; i < n; i++) {
        if (color[i] != 1)
            continue;

        for (j = 0; j < n; j++) {
            if (color[j] != 0)
                continue;

            if (Adj[i][j] != -1 && Adj[i][j] < min) {
                min = Adj[i][j];
                next_node = j;
            }
        }
    }

    if (next_node == N_MAX + 1) //??????????¢??????????
        return 0;

    //next_node????¢????
    color[next_node] = 1;
    sum_mst_path += min;

    return 1;
}

C++: #include <algorithm>
#include <iostream>
#include <vector>
#include <math.h>
#include <set>
#include <map>
#include <string>
#include <stack>
#include <queue>
#include <iomanip>
#include <numeric>
#include <tuple>
#define _USE_MATH_DEFINES
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef tuple<int, int, int> tiii;
double pi = 3.141592653589793;
ll mod = 1000000007;
int intmax = 2147483647;
int intmin = -2147483648;
ll llmax = 9223372036854775807;
ll llmin = -9223372036854775807;

struct unionFind {
    vector<int> data;
    unionFind(int size) : data(size, -1) {}
    
    bool unite(int x, int y) {
        x = root(x);
        y = root(y);
        if (x != y) {
            if(data[y] < data[x]) {
                swap(x, y);
            }
            data[x] += data[y];
            data[y] = x;
        }
        return x != y;
    }

    bool same(int x, int y) {
        return root(x) == root(y);
    }

    int root(int x) {
        return (data[x] < 0) ? x : data[x] = root(data[x]);
    }

    int rank(int x) {
        return -data[root(x)];
    }
};

//cost,from,toの順
vector<tiii> T;
vector<tiii> Krusans;

ll Kruskal(int n) {
    sort(T.begin(), T.end());
    ll ans = 0;
    ll num = 0;
    unionFind u(n);
    int size = T.size();
    for (int i = 0; i < size; i++) {
        int cost = get<0>(T[i]);
        int from = get<1>(T[i]);
        int to = get<2>(T[i]);
        if (u.root(from) != u.root(to)) {
            u.unite(from, to);
            ans += cost;
            num++;
            tiii t = make_tuple(cost, from, to);
            Krusans.push_back(t);
        }
        if (num == n - 1) {
            break;
        }
    }
    return ans;
}

int mat[200][200];

int main() {
    int N;
    cin >> N;
    for (int i = 0; i < N; i++) {
        for (int j = 0; j < N; j++) {
            cin >> mat[i][j];
        }
    }
    for (int i = 0; i < N; i++) {
        for (int j = i + 1; j < N; j++) {
            if (mat[i][j] != -1) {
                tiii e = make_tuple(mat[i][j], i, j);
                T.push_back(e);
            }
        }
    }
    ll ans = Kruskal(N);
    cout << ans << endl;
}

C++: //include
//------------------------------------------
#include <iostream>
#include <vector>
#include <list>
#include <map>
#include <set>
#include <queue>
#include <deque>
#include <stack>
#include <bitset>
#include <algorithm>
#include <functional>
#include <numeric>
#include <utility>
#include <sstream>
#include <iomanip>
#include <cstdio>
#include <cmath>
#include <cstdlib>
#include <cctype>
#include <string>
#include <cstring>
#include <ctime>
#include <limits>
using namespace std;

//repetition
//------------------------------------------
#define FOR(i,a,b) for(int i=(a);i<(b);i++)
#define FORR(i,a,b) for(int i=(a);i>(b);i--)
#define REP(i,n)  FOR(i,0,n)

//conversion
//------------------------------------------
inline int toInt(string s) {int v; istringstream sin(s);sin>>v;return v;}
template<class T> inline string toString(T x) {ostringstream sout;sout<<x;return sout.str();}

//debug
//-------------------------------------------
#define dump(x)  cerr << #x << " = " << (x) << endl;
#define debug(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ")" << " " << __FILE__ << endl;
#define INF std::numeric_limits<int>::max()

//typedef
//-------------------------------------------
typedef long long ll;

int n;
int g[101][101];

int prim(int used, int sum) {
    if (used == 0) return sum;

    int tmp = INF;
    int use = -1;
    REP(i, n) {
        if ((used>>i)&1) {
            continue;
        }
        REP(j, n) {
            if (((used>>j)&1) && g[i][j] < tmp) {
                tmp = g[i][j];
                use = j;
            }
        }
    }
    return prim(used&~(1<<use), sum + tmp);
}

int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);

    cin >> n;
    REP(i, n) REP(j, n) {
        cin >> g[i][j];
        if (g[i][j] < 0) g[i][j] = INF;
    }
    int used = (1<<n) - 1;
    cout << prim(used&~1, 0) << endl;

    return 0;
}

C++: #include<iostream>
using namespace std;
static const int MAX = 100;
static const int INFTY = (1 <<21);
static const int WHITE = 0;
static const int GRAY = 1;
static const int BLACK = 2;

int n, M[MAX][MAX];

int prim() {
   int u,minv;
   int d[MAX], p[MAX],color[MAX];

   for(int i = 0; i < n; i++){
    d[i] = INFTY;
    p[i] = -1;
    color[i] = WHITE;
  }

  d[0] = 0;

  while( 1 ){
   minv = INFTY;
   u = -1;
   for(int i = 0; i < n;i++){
   if(minv > d[i] && color[i] != BLACK){
   u = i;
   minv = d[i];
   }
 }
 if( u == -1) break;
 color[u] = BLACK;
 for(int v = 0; v < n; v++){
  if(color[v] != BLACK && M[u][v] != INFTY){
    if(d[v] > M[u][v]){
       d[v] = M[u][v];
       p[v] = u;
    color[v] = GRAY;
   }
  }
 }
}
 int sum = 0;
 for(int i = 0; i < n; i++){
   if(p[i] != -1) sum += M[i][p[i]];
   }

   return sum;
}
   
int main(){
  cin >> n;

  for(int i = 0; i < n; i++){
   for(int j = 0; j < n; j++){
     int e; cin >> e;
     M[i][j] = (e == -1) ? INFTY : e;
   }
  }

  cout << prim() << endl;

  return 0;
}