Go: package main

import (
	"fmt"
	"bufio"
	"os"
	"strconv"
	"container/heap"
)

type Node struct {
	Id int
	Dis int
}

type PriorityQueue []*Node

func (pq PriorityQueue) Len() int { return len(pq) }

func (pq PriorityQueue) Less(i, j int) bool {
	return pq[i].Dis < pq[j].Dis
}

func (pq PriorityQueue) Swap(i, j int) {
	pq[i], pq[j] = pq[j], pq[i]
}

func (pq *PriorityQueue) Push(x interface{}) {
	*pq = append(*pq, x.(*Node))
}

func (pq *PriorityQueue) Pop() interface{} {
	n := len(*pq)
	pop := (*pq)[n-1]
	*pq = (*pq)[0:n-1]
	return pop
}

func main() {
	var n int
	fmt.Scan(&n)

	sc := bufio.NewScanner(os.Stdin)
	sc.Split(bufio.ScanWords)

	g := make([][]int, n)
	c := make([][]int, n)
	pq := make(PriorityQueue, 0, n)
	d := make([]int, n)
	for i := 0; i < n; i++ {
		sc.Scan()
		u, _ := strconv.Atoi(sc.Text())
		sc.Scan()
		k, _ := strconv.Atoi(sc.Text())
		g[u] = make([]int, k)
		c[u] = make([]int, k)
		for j := 0; j < k; j++ {
			sc.Scan()
			g[u][j], _ = strconv.Atoi(sc.Text())
			sc.Scan()
			c[u][j], _ = strconv.Atoi(sc.Text())
		}

		if u == 0 {
			d[u] = 0
		} else {
			d[u] = 1 << 30
		}
		pq.Push(&Node{u, d[u]})
	}
	heap.Init(&pq)

	for pq.Len() > 0 {
		node := heap.Pop(&pq).(*Node)
		for i := 0; i < len(g[node.Id]); i++ {
			nextId := g[node.Id][i]
			nextDis := node.Dis + c[node.Id][i]
			if nextDis < d[nextId] {
				d[nextId] = nextDis
				heap.Push(&pq, &Node{nextId, nextDis})
			}
		}
	}

	wr := bufio.NewWriter(os.Stdout)
	for i := 0; i < n; i++ {
		wr.WriteString(strconv.Itoa(i))
		wr.WriteString(" ")
		wr.WriteString(strconv.Itoa(d[i]))
		wr.WriteString("\n")
	}
	wr.Flush()
}

C++: #define ll long long
#define MAX 10000

#include <vector.h>
#include <algorithm.h>
#include <queue.h>

using namespace std;
static const int INF = (1 << 21);

int n;
priority_queue<pair<int,int>> PQ;
vector<pair<int, int>> adj[MAX];
int color[MAX];
int d[MAX];

void dj(int s){
	for (int i = 0;i < n;i++) {
		d[i]=INF;
		color[i] = 0;
	}
	
	d[s] = 0;
	PQ.push(make_pair(0, 0));
	color[0] = 1;

	while (!PQ.empty()) {
		pair<int, int> f = PQ.top(); 
		PQ.pop();
		int u = f.second;
		color[u] = 2;

		if (d[u] < f.first*(-1)) continue;

		for(int j=0;j<adj[u].size();j++){
			int v = adj[u][j].first;
			if (color[v] == 2) continue;
			if (d[v] > d[u] + adj[u][j].second) {
				d[v] = d[u] + adj[u][j].second;
				PQ.push(make_pair(d[v] * (-1), v));
				color[v] = 1;
			}
		}
	}

	for (int i = 0;i < n;i++) {
		cout << i << " " << (d[i] == INF ? -1 : d[i]) << endl;
	}

}

int main() {
	cin >> n;
	for (int i = 0;i < n;i++) {
		int u, k;
		cin >> u >> k;
		for (int j = 0;j < k;j++) {
			int v, c;
			cin >> v >> c;
			adj[u].push_back(make_pair(v,c));
		}
	}

	dj(0);

}

C++: include <iostream>
#include <algorithm>
#include <queue>
using namespace std;

#define MAX   10000
#define INFTY (1 << 20)
#define WHITE 0
#define GRAY  1
#define BLACK 2

int n;
vector<pair<int, int> > adj[MAX];

void dijkstra() {
  priority_queue<pair<int, int> > PQ;
  int color[MAX], d[MAX];
  for ( int i = 0; i < n; i++ ) {
    color[i] = WHITE;
    d[i] = INFTY;
  }

  d[0] = 0;
  PQ.push(make_pair(0, 0));
  color[0] = GRAY;

  while ( !PQ.empty() ) {
    pair<int, int> f = PQ.top(); PQ.pop();
    int u = f.second;
    color[u] = BLACK;

    if ( d[u] < f.first * (-1) ) continue;

    for ( int j = 0; j < adj[u].size(); j++ ) {
      int v = adj[u][j].first;
      if ( color[v] == BLACK ) continue;
      if ( d[v] > d[u] + adj[u][j].second ) {
        d[v] = d[u] + adj[u][j].second;
        PQ.push(make_pair(d[v] * (-1), v));
        color[v] = GRAY;
      }
    }
  }

  for ( int i = 0; i < n; i++ ) {
    cout << i << " " << ( d[i] == INFTY ? -1 : d[i] ) << endl;
  }
}


int main() {
  int u, k, c, v;
  cin >> n;
  for ( int i = 0; i < n; i++ ) {
    cin >> u >> k;
    for ( int j = 0; j < k; j++ ) {
      cin >> v >> c;
      adj[u].push_back(make_pair(v, c));
    }
  }

  dijkstra();

  return 0;
}

C++: #include <bits/stdc++.h>
using namespace std;
static const int INFTY = 2000000000;
static const int NIL = -1;
static const int MAX = 10000;
static const int WHITE = 0;
static const int GRAY = 1;
static const int BLACK = 2;

int n;
vector<pair<int,int> > adj[MAX];

void dijkstra(){
    priority_queue<pair<int,int> > PQ;
    int color[MAX];
    int d[MAX];
    for(int i=0;i<n;i++){
        d[i] = INFTY;
        color[i] = WHITE;
    }

    d[0] = 0;
    PQ.push(make_pair(0,0));
    color[0] = GRAY;

    while(!PQ.empty()){
        pair<int,int> f = PQ.top(); PQ.pop();
        int u = f.second;
        color[u] = BLACK;
        //????°???????????????????????????????????????§???????????°??????
        if(d[u] < f.first * (-1)) continue;

        for(int j=0;j<adj[u].size();j++){
            int v = adj[u][j].first;
            if(color[v] == BLACK) continue;
            if(d[v] > d[u] + adj[u][j].second){
                d[v] = d[u] + adj[u][j].second;
                //priority_queue???DEFAULT??§??§?????????????????????????????????-1??????????????????
                PQ.push(make_pair(d[v] * (-1),v));
                color[v] = GRAY;
            }
        }
    }

    for(int i=0;i<n;i++){
        printf("%d %d\n",i,d[i]);
    }
}

int main(){
    int k,u,v,c;

    scanf("%d",&n);
    for(int i=0;i<n;i++){
        scanf("%d %d",&u,&k);
        for(int j=0;j<k;j++){
            scanf("%d %d",&v,&c);
            adj[u].push_back(make_pair(v,c));
        }
    }
}

C++: #include <iostream>
#include <cstdio>
#include <vector>
#include <queue>
#include <climits>
#include <map>
using namespace std;

const int WHITE = 0;
const int GRAY = 1;
const int BLACK = 2;

int n;
vector<vector<pair<int,int>>> G;
vector<int> d;
multimap<int,int> pri_m;
vector<int> colors;

//失败了，怀疑是因为相同的cost的情况覆盖了...
void dijkstra(int s){
    d[s] = 0;
    pri_m.insert(make_pair(0,s));

    while(!pri_m.empty()){
        int cost = pri_m.begin()->first;
        int u = pri_m.begin()->second;
        //pri_m.erase(cost);
        map<int,int>::iterator it=pri_m.find(cost);//删除(c,5)
        pair<map<int,int>::iterator,map<int,int>::iterator> pos=pri_m.equal_range(it->first);//利用一对multimap<string,int>指向第一个出现(c,5)的位置和最后一个出现(c,5)的位置
        while (pos.first!=pos.second)
        {
            if (pos.first->second==u)//当pos指向5时
            {
                pos.first=pri_m.erase(pos.first);//删除后会改变pos迭代器，故赋值给自身，指向删除后的下一个键值对
            }
            else
                ++pos.first;//不进行删除操作则自增

        }
        if(d[u] < cost) continue;
        colors[u] = BLACK;
        for(int i = 0;i<G[u].size();i++){
            int v = G[u][i].first;
            if(colors[v] != BLACK){
                if(d[u]+G[u][i].second < d[v]){
                    d[v] = d[u]+G[u][i].second;
                    pri_m.insert(make_pair(d[v],v));
                }
            }
        }
    }
    for(int i=0;i<n;i++) printf("%d %d\n",i,d[i]);
}

int main(){
    //freopen("data.txt","r",stdin);
    cin >> n;
    G.resize(n);
    d.resize(n,INT_MAX);
    colors.resize(n,WHITE);
    int u,k,v,c;
    for(int i = 0;i<n;i++){
        cin >> u >> k;
        for(int j = 0;j<k;j++){
            cin >> v >> c;
            G[u].push_back(make_pair(v,c));
        }
    }
    dijkstra(0);

    return 0;
}