Go: package main

import (
	"bufio"
	"container/heap"
	"fmt"
	"os"
)

type Item struct {
	value    int // The value of the item; arbitrary.
	priority int // The priority of the item in the queue.
	// The index is needed by update and is maintained by the heap.Interface methods.
	index int // The index of the item in the heap.
}
type PriorityQueue []*Item

func (pq PriorityQueue) Len() int { return len(pq) }
func (pq PriorityQueue) Less(i, j int) bool {
	return pq[i].priority < pq[j].priority
}
func (pq PriorityQueue) Swap(i, j int) {
	pq[i], pq[j] = pq[j], pq[i]
	pq[i].index = i
	pq[j].index = j
}
func (pq *PriorityQueue) Push(x interface{}) {
	n := len(*pq)
	item := x.(*Item)
	item.index = n
	*pq = append(*pq, item)
}
func (pq *PriorityQueue) Pop() interface{} {
	old := *pq
	n := len(old)
	item := old[n-1]
	item.index = -1 // for safety
	*pq = old[0 : n-1]
	return item
}

type Q struct {
	pq *PriorityQueue
	ds map[int]int // It has always same value as pq. For random access.
}

func newQ() *Q {
	pq := new(PriorityQueue)
	heap.Init(pq)
	return &Q{
		pq: pq,
		ds: make(map[int]int),
	}
}
func (q *Q) pop() (u, d int) {
	item := heap.Pop(q.pq).(*Item)
	delete(q.ds, item.value)
	return item.value, item.priority
}
func (q *Q) get(u int) (int, bool) { // returns d
	d, ok := q.ds[u]
	return d, ok
}
func (q *Q) set(u, d int) {
	q.ds[u] = d
	for _, item := range *q.pq {
		if item.value != u {
			continue
		}

		item.priority = d
		heap.Fix(q.pq, item.index)
		return
	}
	heap.Push(q.pq, &Item{
		priority: d,
		value:    u,
	})
}
func (q *Q) len() int {
	return len(q.ds)
}

func main() {
	r := bufio.NewReader(os.Stdin)

	var n int
	fmt.Fscan(r, &n)
	cs := make([]map[int]int, n) // []v_i -> c_i
	for h := 0; h < n; h++ {
		var u, k int
		fmt.Fscan(r, &u, &k)
		m := make(map[int]int)
		for i := 0; i < k; i++ {
			var v, c int
			fmt.Fscan(r, &v, &c)
			m[v] = c
		}

		cs[u] = m
	}

	q := newQ()
	q.set(0, 0)
	visited := make(map[int]struct{})
	out := make([]int, n)

	for q.len() > 0 {
		u, d := q.pop()
		for uu, c := range cs[u] {
			// Consider the connection between u and uu.
			if _, ok := visited[uu]; ok {
				continue
			}
			dd := d + c
			if d, ok := q.get(uu); !ok || d > dd {
				q.set(uu, dd)
			}
		}

		out[u] = d
		visited[u] = struct{}{}
	}

	for u, d := range out {
		fmt.Println(u, d)
	}
}

Python: n = int(input())
from collections import defaultdict
G = defaultdict(list)
for i in range(n):
    i = [int(i) for i in input().split()]
    k = i[1]
    G[i[0]] = list(zip(i[2::2],i[3::2]))

def mind(Q, d):
    c = float('inf')
    ret = 0
    for i, j in enumerate(d):
        if c > j and i in Q:
            c = j
            ret = i
    return ret

def dijkstra(G):
    d = [0] + [float('inf')] * (n - 1)
    Q = set(range(n))
    while len(Q) != 0:
        u = mind(Q, d)
        Q = Q - set([u])
        for v, c in G[u]:
            if d[v] > d[u] + c:
                d[v] = d[u] + c
    return d

for i,j in enumerate(dijkstra(G)):
    print(i, j)

Python: from collections import namedtuple

Edge = namedtuple('Edge', ('fr', 'to', 'cost'))
inf = 1e9


def bellman_ford(n, start, edges):
    dists = [inf for _ in range(n)]
    dists[start] = 0
    while True:
        updated = False
        for e in edges:
            if dists[e.fr] != inf and dists[e.fr] + e.cost < dists[e.to]:
                updated = True
                dists[e.to] = dists[e.fr] + e.cost

        if not updated:
            break

    return dists


def dijkstra(n, costs):
    dists = [inf for _ in range(n)]
    dists[0] = 0
    determined = [False for _ in range(n)]

    while True:
        v, min_d = -1, inf
        for i in range(n):
            if determined[i]:
                continue
            if dists[i] < min_d:
                v, min_d = i, dists[i]

        if v == -1:
            break

        determined[v] = True

        for i in range(n):
            if determined[i] or costs[v][i] == -1:
                continue

            dists[i] = min(dists[i], dists[v] + costs[v][i])

    return dists


n = int(input())

m = [[-1 for _ in range(n)] for _ in range(n)]
es = []
for i in range(n):
    fs = list(map(int, input().split()))
    ne = fs[1]
    for j in range(ne):
        v = fs[2+2*j]
        c = fs[2+2*j+1]
        m[i][v] = c
        es.append(Edge(i, v, c))


# d = bellman_ford(n, 0, es)
d = dijkstra(n, m)
for (i, di) in enumerate(d):
    print(i, di)

Python: 
def graph_to_edges(graph):
    '''(cosr,from,to)を要素に持つリストに変換 未verify'''
    # edgeへの変換
    edges = []
    for ot, v in graph.items():
        for to, c in v:
            edges.append((c, ot, to))
    return edges

def bellman_ford(edges, s, N):
    '''
    edges ... (cost,from,to)を各要素に持つリスト
    s...始点ノード
    N...頂点数

    return
    ----------
    D ... 各点までの最短距離
    P ... 最短経路木における親
    '''
    P = [None] * N
    inf = float('inf')
    D = [inf] * N
    D[s] = 0
    for n in range(N):  # N-1回で十分だけど、N回目にもアップデートがあったらnegative loopを検出できる
        update = False  # 早期終了用
        for c, ot, to in edges:
            if D[ot] != inf and D[to] > D[ot] + c:
                update = True
                D[to] = D[ot] + c
                P[to] = ot
        if not update:
            break  # 早期終了
        if n == len(edges) - 1:
            raise ValueError('NegativeCycleError')
    return D, P

# load datas
N = int(input())
from collections import defaultdict
adj = defaultdict(lambda:[])
'''
例
[
(0について) [(1,1235), (4,65)]
(1について) [(20,6000)]
...
]
'''
for _ in range(N):
    tmp = list(map(int, input().split()))
    if tmp[1] != 0:
        node = tmp[0]
        for i in range(2, 2 + tmp[1] * 2, 2):
            adj[node].append((tmp[i], tmp[i + 1]))
            
edges=graph_to_edges(adj)


D, P = bellman_ford(edges,0,N)

for i in range(N):
    print(i, D[i])

Python: n = int(input())

adj = [[100001 for j in range(n)] for i in range(n)]

for u in range(n):
    x = list(map(int, input().split()))
    for v, c in zip(x[2::2], x[3::2]):
        adj[u][v] = c

unvisited = {v for v in range(n)}

distance = [9900001] * n


def dijkstra(s):
    distance[s] = 0

    while True:
        mincost = 9900001
        for i in unvisited:
            if distance[i] < mincost:
                mincost = distance[i]
                u = i

        if mincost == 9900001:
            break

        unvisited.discard(u)

        for v in unvisited:
            weight_uv = adj[u][v]
            if weight_uv != 100001:
                t_d = distance[u] + weight_uv
                if t_d < distance[v]:
                    distance[v] = t_d



dijkstra(0)

for v, d in enumerate(distance):
    print(v, d)

Python: INFTY = 1 << 21
WHITE = 0
GRAY = 1
BLACK = 2

def dijkstra(n, m):
    d = [INFTY] * n
    color = [WHITE] * n

    d[0] = 0
    color[0] == GRAY

    while True:
        minv = INFTY
        u = -1
        for i in range(n):
            if minv > d[i] and color[i] != BLACK:
                u = i
                minv = d[i]
        if u == -1:
            break
        color[u] = BLACK
        for v in range(n):
            if color[v] != BLACK and m[u][v] != INFTY:
                if d[v] > d[u] + m[u][v]:
                    d[v] = d[u] + m[u][v]
                    color[v] = GRAY

    for i in range(n):
        out = d[i]
        if out == INFTY:
            out = -1
        print('{0} {1}'.format(i, out))


n = int(input())
m = [[INFTY] * n for i in range(n)]
for i in range(n):
    line = [int(v) for v in input().split()]
    u = line[0]
    k = line[1]
    for j in range(k):
        v = line[2*j + 2]
        c = line[2*j + 3]
        m[u][v] = c

dijkstra(n, m)