Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

//util
var sc = bufio.NewScanner(os.Stdin)

func nextStr() string {
	sc.Scan()
	return sc.Text()
}

func nextInt() int {
	sc.Scan()
	i, e := strconv.Atoi(sc.Text())
	if e != nil {
		panic(e)
	}
	return i
}

func printList(list []int) {
	n := len(list)
	buf := bufio.NewWriter(os.Stdout)
	for _, v := range list[0 : n-1] {
		buf.Write([]byte(fmt.Sprintf("%d ", v)))
	}
	buf.Write([]byte(fmt.Sprintf("%d\n", list[n-1])))
	buf.Flush()
}

func max(a, b int) int {
	if a > b {
		return a
	} else {
		return b
	}
}

func min(a, b int) int {
	if a > b {
		return b
	} else {
		return a
	}
}

//solve
const (
	MAX   = 100
	INFTY = (1 << 21)
	WHITE = 0
	GRAY  = 1
	BLACK = 2
)

//V: グラフの頂点全体の集合
//T: MSTに属する頂点の集合
var (
	n     int
	M     [MAX][MAX]int //重みを記録する隣接行列
	color [MAX]int
	p     [MAX]int //MSTにおける頂点の親を記録
	d     [MAX]int //Tに属する頂点と、V−Tに属する頂点を繋ぐ辺の中で、重みが最小のものを記録
)

func prim() int {
	var u, minv int
	//初期化
	for i := 0; i < n; i++ {
		d[i] = INFTY
		p[i] = -1
		color[i] = WHITE
	}

	d[0] = 0

	for {
		//頂点uを決めていく
		//つまり、Tに属する頂点と、V−Tに属する頂点を繋ぐ辺の中で、重みが最小のものを決める
		minv = INFTY
		u = -1
		for i := 0; i < n; i++ {
			//未訪問かつ、辺の重みが最小となるuを選ぶ
			if minv > d[i] && color[i] != BLACK {
				u = i
				minv = d[i]
			}
		}

		if u == -1 {
			break
		}

		color[u] = BLACK
		for v := 0; v < n; v++ {
			//未訪問かつ、辺が存在するとき
			if color[v] != BLACK && M[u][v] != INFTY {
				if d[v] > M[u][v] {
					d[v] = M[u][v]
					p[v] = u
					color[v] = GRAY
				}
			}
		}
	}

	sum := 0
	for i := 0; i < n; i++ {
		if p[i] != -1 {
			sum += M[i][p[i]]
		}
	}
	return sum
}

func main() {
	sc.Split(bufio.ScanWords)
	n = nextInt()

	for i := 0; i < n; i++ {

		for j := 0; j < n; j++ {
			tmp := nextInt()
			if tmp == -1 {
				tmp = INFTY
			}
			M[i][j] = tmp
		}

	}

	fmt.Println(prim())

}

C++: #include<iostream>
using namespace std;
#define REP(i,n) for(unsigned int i=0;i<(n);i++)
#define MAX 101
#define INF (1<<21)
#define NONE -1
#define WHITE 0
#define GRAY 1
#define BLACK 2


int node[MAX][MAX];
int N;

int prim()
{
	int cost[MAX];
	int color[MAX];
	int parent[MAX];
	REP(i, N)
	{
		cost[i] = INF;
		color[i] = WHITE;
		parent[i] = NONE;
	}

	cost[0] = 0;
	
	while (true)
	{
		int min_index = NONE;
		int min_value = INF;
		REP(i, N)
		{
			if (color[i] !=BLACK)
			{
				if (cost[i] < min_value)
				{
					min_index = i;
					min_value = cost[i];
				}
			}
		}
		if (min_index == NONE)break;
		color[min_index] = BLACK;
		REP(i, N)
		{
			if (color[i] != BLACK)
			{
				if (node[min_index][i] != INF)
				{
					if (cost[i] > node[min_index][i])
					{
						cost[i] = node[min_index][i];
						parent[i] = min_index;
						color[i] = GRAY;
					}
				}
			}
		}
	}
	int ans = 0;
	REP(i, N)
	{
		if (parent[i]!=NONE)
		{
			ans += node[i][parent[i]];
		}
	}
	return ans;
}


int main()
{
	REP(i, MAX)
	{
		REP(j, MAX)
		{
			node[i][j] = INF;
		}
	}
	cin >> N;
	REP(i, N)
	{
		REP(j, N)
		{
			int tmp;
			cin >> tmp;
			if (tmp == -1)
			{
				node[i][j] = INF;
			}
			else node[i][j] = tmp;
		}
	}
	cout << prim() << endl;
	return 0;
}

C++: #include<iostream>
#include<cstring>
#include<algorithm>
using namespace std;

int x[10000][10000];
int MIN[10000];
int MINX = 0;
int MINZ = 10000000;

int main() {
	memset(MIN, 127, sizeof(MIN));
	int n, a;
	cin >> n;
	for (int i = 0; i < n; i++) {
		for (int j = 0; j < n; j++) {
			cin >> a;
			x[i][j] = a;
		}
	}
	for(int h=0;h<n;h++){
		memset(MIN, 127, sizeof(MIN));
		MINX=0;
		MIN[h] = 0;
		for (int i = 0; i < n; i++) {
			for (int j = 0; j < n; j++) {
				for (int k = 0; k < n; k++) {
					if (x[j][k] != -1) {
						MIN[k] = min(MIN[k], x[j][k]);
					}
				}
			}
		}
		for (int i = 0; i < n; i++) {
			MINX += MIN[i];
		}
		MINZ=min(MINZ,MINX);
	}
	cout << MINZ << endl;
	return 0;
}

C++: #include "taichitary.h"
#define V_MAX 100
#define INFTY 5000
#define WHITE 0
#define GRAY 1
#define BLACK 2

int M[V_MAX][V_MAX];
int d[V_MAX], p[V_MAX];
int n;
int color[V_MAX];

int Prim(int u){
    p[u] = -1; //p??????????????????????¨????

    for(int i=0; i<n; i++){
        d[i] = INFTY;
        p[i] = -1;
        color[i] = WHITE;
    }

    d[u] = 0; //d?????????????????????

    while(1){
        int mincost = INFTY;
        int from = -1;

        //??????????????§???????°?????????¨??????????¨???¶????????????
        for(int i=0; i<n; i++){
            if(color[i] != BLACK && d[i] < mincost){
                mincost = d[i];
                from = i;
            }
        }

        if(from == -1) break;

        color[from] = BLACK;

        for(int v=0; v<n; v++){
            if(color[v] != BLACK && M[from][v] != INFTY){
                if(M[from][v] < d[v]){
                    d[v] = M[from][v];
                    p[v] = from; //???????¨??????????
                    color[v] = GRAY;
                }
            }
        }
    }

    int sum = 0;

    for(int j=0; j<n; j++){
       if(p[j] != -1) sum += M[j][p[j]];
    }

    return sum;
}

int main(){

    cin >> n;

    for(int k=0; k<n; k++) color[k] = WHITE;

    for(int i=0; i<n; i++){
        for(int j=0; j<n; j++){
            int tmp;
            cin >> tmp;
            if(tmp != -1) M[i][j] = tmp;
            else M[i][j] = INFTY;
        }
    }

    int sum = Prim(0);

    cout << sum << endl;
}

C++: #include <iostream>
#include <algorithm>
#include <vector>
#include <numeric>
#include <climits>
#define rep(i, n) for(int i = 0; i < (int)(n); i++)
#define repR(i, n) for(int i = (n) - 1; i > -1; i--)
#define rep1(i, n) for(int i = 1; i < (int)(n + 1); i++)
#define rep1R(i, n) for(int i = (n); i > 0; i--)
using namespace std;
static const int INF = INT_MAX;
static const int WHITE = 0;
static const int GRAY = 1;
static const int BLACK = 2;

static const int N = 2010;
int M[N][N];
int color[N];
int d[N];
int p[N];
int n;

void prim() {
  rep(u, n) {
    color[u] = WHITE;
    d[u] = INF;
  }
  d[0] = 0;
  p[0] = -1;

  while (true) {
    int mincost = INF;
    int u;
    rep(i, n) {
      if (color[i] != BLACK && d[i] < mincost) {
        mincost = d[i];
        u = i;
      }
    }

    if (mincost == INF) break;

    color[u] = BLACK;

    rep(v, n) {
      if (color[v] == BLACK || M[u][v] == INF) continue;
      if (M[u][v] < d[v]) {
        d[v] = M[u][v];
        p[v] = u;
        color[v] = GRAY;
      }
    }
  }
}

int main() {
  cin >> n;
  rep(y, n) rep(x, n) {
    int a;
    cin >> a;
    if (a != -1) M[y][x] = a;
    else M[y][x] = INF;
  }
  prim();
  cout << accumulate(d, d + n, 0) << endl;
  return 0;
}

C++: #include <iostream>
using namespace std;
static const int MAX = 100;
static const int INFTY = (1<<21);

int n, M[MAX][MAX];

int prim()
{
    int u, minv;
    int d[MAX], p[MAX], color[MAX];

    for(int i=0; i<n; i++)
    {
        d[i] = INFTY;
        p[i] = -1;
        color[i] = 0;
    }
    d[0] = 0;
    
    while(true)
    {
        minv = INFTY;
        u = -1;
        for(int i=0; i<n; i++)
        {
            if(minv > d[i] && color[i] != 2)
            {
                u = i;
                minv = d[i];
            }
        }
        if(u == -1) break;
        color[u] = 2;
        for(int v=0; v<n; v++)
        {
            if(color[v] != 2 && M[u][v] != INFTY)
            {
                if(d[v] > M[u][v])
                {
                    d[v] = M[u][v];
                    p[v] = u;
                    color[v] = 1;
                }
            }
        }
    }
    int sum = 0;
    for(int i=0; i<n; i++)
    {
        if(p[i] != -1) sum += M[i][p[i]];
    }
    return sum;
}

int main() 
{
    ios::sync_with_stdio(false);
    
    cin >> n;
    
    for(int i=0; i<n; i++)
    {
        for(int j=0; j<n; j++)
        {
            int e;
            cin >> e;
            M[i][j] = (e == -1) ? INFTY : e;
        }
    }
    
    cout << prim() << endl;

    return 0;
}