Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

//util
var sc = bufio.NewScanner(os.Stdin)

func nextStr() string {
	sc.Scan()
	return sc.Text()
}

func nextInt() int {
	sc.Scan()
	i, e := strconv.Atoi(sc.Text())
	if e != nil {
		panic(e)
	}
	return i
}

func printList(list []int) {
	n := len(list)
	buf := bufio.NewWriter(os.Stdout)
	for _, v := range list[0 : n-1] {
		buf.Write([]byte(fmt.Sprintf("%d ", v)))
	}
	buf.Write([]byte(fmt.Sprintf("%d\n", list[n-1])))
	buf.Flush()
}

func max(a, b int) int {
	if a > b {
		return a
	} else {
		return b
	}
}

func min(a, b int) int {
	if a > b {
		return b
	} else {
		return a
	}
}

//solve
const (
	MAX   = 100
	INFTY = (1 << 21)
	WHITE = 0
	GRAY  = 1
	BLACK = 2
)

//V: グラフの頂点全体の集合
//T: MSTに属する頂点の集合
var (
	n     int
	M     [MAX][MAX]int //重みを記録する隣接行列
	color [MAX]int
	p     [MAX]int //MSTにおける頂点の親を記録
	d     [MAX]int //Tに属する頂点と、V−Tに属する頂点を繋ぐ辺の中で、重みが最小のものを記録
)

func prim() int {
	var u, minv int
	//初期化
	for i := 0; i < n; i++ {
		d[i] = INFTY
		p[i] = -1
		color[i] = WHITE
	}

	d[0] = 0

	for {
		//頂点uを決めていく
		//つまり、Tに属する頂点と、V−Tに属する頂点を繋ぐ辺の中で、重みが最小のものを決める
		minv = INFTY
		u = -1
		for i := 0; i < n; i++ {
			//未訪問かつ、辺の重みが最小となるuを選ぶ
			if minv > d[i] && color[i] != BLACK {
				u = i
				minv = d[i]
			}
		}

		if u == -1 {
			break
		}

		color[u] = BLACK
		for v := 0; v < n; v++ {
			//未訪問かつ、辺が存在するとき
			if color[v] != BLACK && M[u][v] != INFTY {
				if d[v] > M[u][v] {
					d[v] = M[u][v]
					p[v] = u
					color[v] = GRAY
				}
			}
		}
	}

	sum := 0
	for i := 0; i < n; i++ {
		if p[i] != -1 {
			sum += M[i][p[i]]
		}
	}
	return sum
}

func main() {
	sc.Split(bufio.ScanWords)
	n = nextInt()

	for i := 0; i < n; i++ {

		for j := 0; j < n; j++ {
			tmp := nextInt()
			if tmp == -1 {
				tmp = INFTY
			}
			M[i][j] = tmp
		}

	}

	fmt.Println(prim())

}

C++: #include <iostream>
using namespace std;
static const int MAX=101;
static const int INFTY=(1<<21);
static const int WHITE=0;
static const int GRAY=1;
static const int BLACK=2;

int n,M[MAX][MAX];

int prim(){
    int u,minv;
    int d[MAX],p[MAX],color[MAX];
    for(int i=0;i<n;i++){
        d[i]=INFTY;
        p[i]=-1;
        color[i]=WHITE;
    }
    
    d[0]=0;
    
    while(1){
        minv=INFTY;
        u=-1;
        for(int i=0;i<n;i++){
            if(minv>d[i] && color[i]!=BLACK){
                u=i;
                minv=d[i];
            }
        }
        if(u==-1) break;
        color[u] = BLACK;
        for(int i=0;i<n;i++){
            if(color[i]!=BLACK && M[u][i]!=INFTY){
                if(d[i]>M[u][i]){
                    d[i]=M[u][i];
                    p[i]=u;
                    color[i]=GRAY;
                }
            }
        }
    }
    int sum=0;
    for(int i=0;i<n;i++){
        if(p[i]!=-1) sum += M[i][p[i]];
    }
    
    return sum;
}

int main(){
    cin >> n;
    for(int i=0;i<n;i++){
        for(int j=0;j<n;j++){
            cin >> M[i][j];
            if(M[i][j]==-1) M[i][j]=INFTY;
        }
    }
    
    cout << prim() << endl;
    
    return 0;
}

C++: #include <iostream>
using namespace std;
static const int MAX = 100;
static const int INFTY = (1 << 21);
static const int NOT_VISIT = 0;
static const int VISITING = 1;
static const int VISITED = 2;
int n;
int M[MAX][MAX];
int prim()
{
    int minv, u;
    int isVisited[MAX], d[MAX], p[MAX];
    for (int i = 0; i < n; i++) {
	isVisited[i] = NOT_VISIT;
	d[i] = INFTY;
	cout << "d[i]: " << d[i] << endl;
	p[i] = -1;
    }
    d[0] = 0;
    while (1) {
	minv = INFTY;
	cout << "minv: " << minv << endl;
	u = -1;
	for (int i = 0; i < n; i++) {
	    if (minv > d[i] && isVisited[i] != VISITED) {
		u = i;
		minv = d[i];
	    }
	}
	if (u == -1) {
	    break;
	}

	isVisited[u] = VISITED;
	for (int j = 0; j < n; j++) {
	    if (isVisited[j] != VISITED && M[u][j] != INFTY) {
		if (d[j] > M[u][j]) {
		    d[j] = M[u][j];
		    p[j] = u;
		    isVisited[j] = VISITING;
		}
	    }
	}
    }
    int sum = 0;
    for (int i = 0; i < n; i++) {
	if (p[i] != -1) {
	    sum += M[i][p[i]];
	}
    }
    return sum;
}

int main()
{
    cin >> n;
    for (int i = 0; i < n; i++) {
	for (int j = 0; j < n; j++) {
	    int e;
	    cin >> e;
	    M[i][j] = (e == -1) ? INFTY : e;
	}
    }
    cout << prim() << endl;
}

C++: #define _CRT_SECURE_NO_WARNINGS
#define _USE_MATH_DEFINES
//#include "MyMath.h"
//#include "MyDisjointset.h"
#include <iostream>
#include <vector>
#include <algorithm>
#include <queue>
#include <functional>
#include <stdio.h>
using namespace std;
typedef pair<int, int> P;
const int INF = 2000000000;
int main() {
	int n; cin >> n;
	int m[101][101];
	for (int i = 0; i < n; i++)for (int j = 0; j < n; j++)
		cin >> m[i][j];
	int res = 0;
	int *d = new int[n];
	fill(d, d + n, INF); 
	d[0] = 0;
	bool *visit = new bool [n];
	fill(visit, visit + n, false);
	priority_queue <P, vector<P>, greater<P> > q;
	q.push(P(d[0], 0));
	while (!q.empty()) {
		int f = q.top().first, s = q.top().second;
		visit[s] = true;
		res += f;
		q.pop();
		for (int i = 0; i < n; i++)
			if (!visit[i] && m[s][i] != -1 && d[s] > d[i] + m[s][i]) {
				d[s] = d[i] + m[s][i];
				q.push(P(d[i], i));
			}
	}
	cout << res << endl;
	delete[] d, visit;
	return 0;
}

C++: #include <bits/stdc++.h>
using namespace std;
int prim(void);

#define MAX 100
#define WHITE 0
#define GRAY 1
#define BLACK 2

int A[MAX][MAX];
int n;

int main(){
  int i,j,e;
  int u;
  cin >> n;
  for(i = 0; i < n; i++){
    for(j = 0; j < n; j++){
      cin >> e;
      A[i][j] = (e == -1) ? INFINITY : e;
    }
  }
  cout << prim() << endl;
  return 0;
}

int prim(){
  int sum = 0;
  int i,j,minV;
  int d[MAX],p[MAX],color[MAX];
  int u,v; 
  for(i = 0; i < n; i++){
    d[i] = INFINITY;
    p[i] = -1;
    color[i] = WHITE;
  }
  d[0] = 0;
  while(1){
    minV = INFINITY;
    u = -1;
    for(i = 0; i < n; i++){
      if(minV > d[i] && color[i] != BLACK){
        u = i;
        minV = d[i];
      }
    }
    if(u == -1){
      break;
    }
    color[u] = BLACK;
    for(v = 0; v < n; v++){
      if(color[v] != BLACK && A[u][v] != INFINITY){
        if(d[v] > A[u][v]){
          d[v] = A[u][v];
          p[v] = u;
          color[v] = GRAY;
        }
      }
    }
  }
  //sum = 0;
  for(i = 0; i < n; i++){
    if(p[i] != -1){
      sum += A[i][p[i]];
    }
  }
  return sum;
}

C++: #include <climits>
#include <iostream>
using namespace std;

#define MAX_N 2000
int n;
int A[MAX_N][MAX_N];

class Node
{
    public:
        int cost = INT_MAX;;
        bool used = false;
};

int prim()
{
    int i, u, v, minv, sum = 0;
    Node *nodes = new Node[n];
    nodes[0].cost = 0;
    while (true) {
        u = -1; minv = INT_MAX;
        for (i = 0; i < n; i++) {
            if (nodes[i].cost < minv && !nodes[i].used) {
                u    = i;
                minv = nodes[i].cost;
            }
        }
        if (-1 == u) break;
        nodes[u].used = true;
        sum += nodes[u].cost;
        for (v = 0; v < n; v++) {
            if (!nodes[v].used && A[u][v] != -1) {
                nodes[v].cost = A[u][v] < nodes[v].cost ? A[u][v] : nodes[v].cost;
            }
        }
    }
    return sum;
}

int main()
{
    cin >> n;
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++) {
            cin >> A[i][j];
        }
    }
    cout << prim() << endl;
    return 0;
}