Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

const (
	MAX_N      = 200
	MAX_WEIGHT = 2000
)

type Edge struct {
	start  int
	end    int
	weight int
}

type ShortestInfo struct {
	edges    []Edge
	shortest int
}

func main() {
	sc := bufio.NewScanner(os.Stdin)
	sc.Split(bufio.ScanWords)

	n, err := nextInt(sc)
	if err != nil {
		panic(err)
	}

	shortestList := make([]ShortestInfo, n)
	for i := 1; i < n; i++ {
		shortestList[i] = ShortestInfo{edges: []Edge{}, shortest: MAX_N*MAX_WEIGHT + 1}
	}

	adjacentMatrix := make([][]int, n)
	for i := 0; i < n; i++ {
		adjacentMatrix[i] = make([]int, n)
		for j := 0; j < n; j++ {
			v, err := nextInt(sc)
			if err != nil {
				panic(err)
			}
			adjacentMatrix[i][j] = v
		}
	}

	mst([]int{1}, shortestList, adjacentMatrix)
	fmt.Println(shortestList)
	fmt.Println(calculateMinWeight(shortestList))
}

func calculateMinWeight(shortestList []ShortestInfo) int {
	visitedList := make([]bool, len(shortestList))
	visitedList[0] = true
	sumWeight := 0
	for !visitedAll(visitedList) {
		shortestInfo := shortestList[0]
		shortestList = shortestList[1:]
		edges := shortestInfo.edges
		for _, edge := range edges {
			if !visitedList[edge.end-1] {
				visitedList[edge.end-1] = true
				sumWeight += edge.weight
			}
		}
	}
	return sumWeight
}

func visitedAll(visitedList []bool) bool {
	for _, v := range visitedList {
		if !v {
			return false
		}
	}
	return true
}

func mst(nodeStack []int, shortestList []ShortestInfo, adjacentMatrix [][]int) {
	for len(nodeStack) > 0 {
		currentNode := nodeStack[0]
		nodeStack = nodeStack[1:]
		currentShortest := getShortest(currentNode, shortestList)
		adjacents := findAdjacents(currentNode, adjacentMatrix)
		for i := 0; i < len(adjacents); i++ {
			adj := adjacents[i]
			s := getShortest(adj.end, shortestList)
			if currentShortest.shortest+adj.weight < s.shortest || (currentShortest.shortest+adj.weight == s.shortest && len(currentShortest.edges)+1 > len(s.edges)) {
				setShortest(adj.end, adj, currentShortest, shortestList)
				nodeStack = append(nodeStack, adj.end)
			}
		}
	}
}

func getShortest(node int, shortestList []ShortestInfo) ShortestInfo {
	return shortestList[node-1]
}

func setShortest(node int, edge Edge, currentShortest ShortestInfo, shortestList []ShortestInfo) {
	newEdges := make([]Edge, len(currentShortest.edges)+1)
	for i := 0; i < len(newEdges)-1; i++ {
		newEdges[i] = currentShortest.edges[i]
	}
	newEdges[len(newEdges)-1] = edge
	shortestInfo := ShortestInfo{edges: newEdges, shortest: currentShortest.shortest + edge.weight}
	shortestList[node-1] = shortestInfo
}

func findAdjacents(currentNode int, adjacentMatrix [][]int) []Edge {
	adjacents := adjacentMatrix[currentNode-1]
	edges := []Edge{}
	for i, v := range adjacents {
		if v > 0 {
			edges = append(edges, Edge{start: currentNode, end: i + 1, weight: v})
		}
	}
	return edges
}

func nextInt(sc *bufio.Scanner) (int, error) {
	sc.Scan()
	return strconv.Atoi(sc.Text())
}

C++: #include <bits/stdc++.h>
#define endl "\n"
using namespace std;

int n;
vector<vector<double>>v;
vector<double>w;
vector<int>pre;
double inf=1e7;
void solve(){
	for(int i=0;i<n;i++)w.push_back(inf);
	for(int i=0;i<n;i++)pre.push_back(-1);
	w[0]=0;
	int k=0;
	double res=0;
	while(k++!=n){
		// 选一个最小的 
		double mi=inf;
		int id=-1;
		for(int i=0;i<n;i++)
			if(w[i]!=-1&&w[i]<mi)mi=w[i],id=i;
		w[id]=-1;
		for(int i=0;i<n;i++){
			if(w[i]!=-1&&v[id][i]!=-1&&v[id][i]<w[i]){
				w[i]=v[id][i];
				pre[i]=id;
			}
		}
		res+=mi;
	}
	cout<<res<<endl;
}
int main(){
	int t;
	cin>>n;
	for(int i=0;i<n;i++){
		v.push_back(vector<double>());
		for(int j=0;j<n;j++){
			cin>>t;
			v[i].push_back(t);
		}
	}
	solve();	
	return 0;
}

C++: // 最小全域木 ( プリム法 )
#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<stack>
#include<algorithm>
#include<iostream>
#include<cmath>
#include<vector>

#include<queue>

using namespace std;

#define MAX_N 100
// 値の定義
const int INV = -1;
const int MAX_W = 2000;

// グラフ情報を保持する配列
int ary_graph[MAX_N + 1][MAX_N + 1];

// グラフを構成する頂点を保持するキュー
queue<int> Base_Queue;

int n = 0;

// プリム法で最小全域木を求める
int MinimumSpanningTree(void);

int main(void)
{
    int sum = 0;

    for(int i = 0; i < MAX_N + 1; i++)
    {
        for(int j = 0; j < MAX_N + 1; j++)
        {
            // 配列の初期化
            ary_graph[i][j] = INV;
        }
    }

    cin >> n;

    for(int i = 0; i < n; i++)
    {
        // グラフを構成する頂点の格納
        Base_Queue.push(i);

        for(int j = 0; j < n; j++)
        {
            // 隣接行列の設定
            cin >> ary_graph[i][j];
        }
    }

    // 頂点１から最小全域木を探索する
    sum = MinimumSpanningTree();

    // 結果の表示
    printf("%d\n", sum);

    return 0;
}

// 最小全域木を探索する関数
int MinimumSpanningTree(void)
{

    int q_size_1, q_size_2, min_val, min_ele, s, t, tmp;
    // 辺の和を保持する変数
    int sum = 0;

    // 最小全域木を構成する頂点を保持するキュー
    queue<int> Prim_Queue;

    // 検索する頂点の初期値の設定
    s = Base_Queue.front();
    Base_Queue.pop();
    Prim_Queue.push(s);

    while( !Base_Queue.empty() )
    {
        // ----------------------------------------------
        // Prim_Queueの頂点 から Base_Queueの頂点への辺の中で
        // 最小コストの辺を検索する方針で進める
        // ----------------------------------------------

        min_val = MAX_W;
        min_ele = INV;

        q_size_1 = Base_Queue.size();
        q_size_2 = Prim_Queue.size();

        for( int i = q_size_2; i > 0; i-- )
        {
            // --- s から t に向かう辺の重みを探索する ---
            s = Prim_Queue.front();
            Prim_Queue.pop();
            // Prim_Queue の要素が減らないように, 取り出したものを元に戻す
            Prim_Queue.push(s);

            for( int i = q_size_1; i > 0; i-- )
            {
                t = Base_Queue.front();
                Base_Queue.pop();

                if( ary_graph[s][t] != INV && min_val > ary_graph[s][t] )
                {
                    // 最小のコストを持つ辺を保存する
                    min_val = ary_graph[s][t];
                    min_ele = t;
                }

                // 取り出したものを, 一旦, 元に戻す
                Base_Queue.push(t);
            }
        }

        // 最小のコストを持つ辺の頂点を追加して
        // 最小全域木を構成する
        for(int i = 0; i < Base_Queue.size(); i++)
        {
            tmp = Base_Queue.front();
            Base_Queue.pop();

            if( tmp == min_ele )
            {
                // 最小コストの辺を持つ頂点を追加する
                Prim_Queue.push(tmp);
                break;
            }
            else
            {
                // 対象外なら元に戻す
                Base_Queue.push(tmp);
            }
        }

        // 辺の和を求める
        sum += min_val;
    }

    return sum;
}

C++: #include<iostream>
#include<cstdio>
#include<vector>
#include<queue>
#include<map>
#include<string>
#include<algorithm>
#include<functional>
#define ll long long
#define inf  999999999
#define pa pair<int,int>

using namespace std;

int n,a[200][200]={0};
void prim(){
	int d[200]={0};
	priority_queue<pair<int,pa> >  PQ; 
	pair<int,pa> q;
	pa r;
	int wei=0;
	int w=6;
	int u=w,z=0;
	d[w]=1;
	while(z!=n-1){
		for(int j=0;j<n;j++){
			if(a[u][j]<0 && d[j]==0 && u!=j) PQ.push(make_pair(a[u][j],make_pair(u,j)));
		}
	while(1){
		if(PQ.size()==0) {
			cout<<"dv"<<endl;
		break;
		}
		q=PQ.top();
		PQ.pop();
		r=q.second;
	//	cout<<"rsec"<<r.second<<endl;
		if(d[r.second]==0) break;
		
		}
	u=r.second;
//	cout<<"a" <<u<<endl;
	d[u]=1;
	wei=wei+q.first;
	z++;
//	cout<<z<<" "<<-q.first<<" "<<u<<" "<<r.first<<endl;
	
	}
	cout<<-wei<<endl;
}



int main(){
	// your code goes here
	int m;
	cin>>n;
	
	for(int i=0;i<n;i++){
		for(int j=0;j<n;j++){
		cin>>m;
		a[i][j]=-m;
		}
	}
	prim();

	return 0;
}