Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

//util
var sc = bufio.NewScanner(os.Stdin)

func nextStr() string {
	sc.Scan()
	return sc.Text()
}

func nextInt() int {
	sc.Scan()
	i, e := strconv.Atoi(sc.Text())
	if e != nil {
		panic(e)
	}
	return i
}

func printList(list []int) {
	n := len(list)
	buf := bufio.NewWriter(os.Stdout)
	for _, v := range list[0 : n-1] {
		buf.Write([]byte(fmt.Sprintf("%d ", v)))
	}
	buf.Write([]byte(fmt.Sprintf("%d\n", list[n-1])))
	buf.Flush()
}

func max(a, b int) int {
	if a > b {
		return a
	} else {
		return b
	}
}

func min(a, b int) int {
	if a > b {
		return b
	} else {
		return a
	}
}

//solve
const (
	MAX   = 100
	INFTY = (1 << 21)
	WHITE = 0
	GRAY  = 1
	BLACK = 2
)

//V: グラフの頂点全体の集合
//T: MSTに属する頂点の集合
var (
	n     int
	M     [MAX][MAX]int //重みを記録する隣接行列
	color [MAX]int
	p     [MAX]int //MSTにおける頂点の親を記録
	d     [MAX]int //Tに属する頂点と、V−Tに属する頂点を繋ぐ辺の中で、重みが最小のものを記録
)

func prim() int {
	var u, minv int
	//初期化
	for i := 0; i < n; i++ {
		d[i] = INFTY
		p[i] = -1
		color[i] = WHITE
	}

	d[0] = 0

	for {
		//頂点uを決めていく
		//つまり、Tに属する頂点と、V−Tに属する頂点を繋ぐ辺の中で、重みが最小のものを決める
		minv = INFTY
		u = -1
		for i := 0; i < n; i++ {
			//未訪問かつ、辺の重みが最小となるuを選ぶ
			if minv > d[i] && color[i] != BLACK {
				u = i
				minv = d[i]
			}
		}

		if u == -1 {
			break
		}

		color[u] = BLACK
		for v := 0; v < n; v++ {
			//未訪問かつ、辺が存在するとき
			if color[v] != BLACK && M[u][v] != INFTY {
				if d[v] > M[u][v] {
					d[v] = M[u][v]
					p[v] = u
					color[v] = GRAY
				}
			}
		}
	}

	sum := 0
	for i := 0; i < n; i++ {
		if p[i] != -1 {
			sum += M[i][p[i]]
		}
	}
	return sum
}

func main() {
	sc.Split(bufio.ScanWords)
	n = nextInt()

	for i := 0; i < n; i++ {

		for j := 0; j < n; j++ {
			tmp := nextInt()
			if tmp == -1 {
				tmp = INFTY
			}
			M[i][j] = tmp
		}

	}

	fmt.Println(prim())

}

Python: # -*- coding: utf-8 -*-


if __name__ == '__main__':

    n = int(input())
    M = [list(map(int, input().split(" ")[1:])) for _ in range(n)]

    color = [0] * n
    d = [float("inf")] * n
    p = [None] * n

    def prim():
        d[0] = 0
        p[0] = -1

        while True:
            mincost = float("inf")
            for i in range(n):
                if color[i] != 2 and d[i] < mincost:
                    mincost = d[i]
                    u = i

            if mincost == float("inf"):
                break

            color[u] = 2

            for v in range(n):
                if color[v] != 2 and M[u][v] != -1:
                    if M[u][v] < d[v]:
                        d[v] = M[u][v]
                        p[v] = u
                        color[v] = 1

    prim()
    sum = 0
    for i in range(n):
        if p[i] != -1:
            sum += M[i][p[i]]

    print(sum)

Python: def kruskal(edges):
    edges.sort(key=lambda pair:pair[2])
    uf_tree = UnionFindTree(n_node)
    total_cost = 0
    for i, j, cost in edges:
        if cost < 0:
            continue

        if not uf_tree.have_same_root(i, j):
            uf_tree.unite(i, j)
            total_cost += cost
    return total_cost


class UnionFindTree:
    def __init__(self, n_node):
        self.parent = [i for i in range(n_node)]
        self.rank = [0] * n_node

    def find(self, x):
        if self.parent[x] != x:
            self.parent[x] = self.find(self.parent[x])
        return self.parent[x]

    def unite(self, x, y):
        x = self.find(x)
        y = self.find(y)

        if x != y:
            if self.rank[x] < self.rank[y]:
                self.parent[x] = y
            else:
                self.parent[y] = x
                if self.rank[x] == self.rank[y]:
                    self.rank[x] += 1

    def have_same_root(self, x, y):
        return self.find(x) == self.find(y)

if __name__ == "__main__":
    n_node = int((input()))
    edges = []
    for i in range(n_node):
        for j, cost in enumerate(map(int, input().split())):
            edges.append((i, j, cost))

    print(kruskal(edges))

Python: class UnionFindTree:
    """Disjoint-Set Data Structure
       Union-Find Tree
       complexity:
          init: O(n)
          find, unite, same: O(alpha(n))
       used in SRM505 div.2 900, ATC001 A, DSL1A(AOJ)
    """
    def __init__(self, n):
        self.par = list(range(n))  # parent
        self.rank = [0] * n  # depth of tree

    def find(self, x):
        if self.par[x] == x:
            return x
        else:
            self.par[x] = self.find(self.par[x])
            return self.par[x]

    def unite(self, x, y):
        x, y = self.find(x), self.find(y)
        if x == y:
            return
        if self.rank[x] < self.rank[y]:
            self.par[x] = y
        else:
            self.par[y] = x
            if self.rank[x] == self.rank[y]:
                self.rank[x] += 1

    def same(self, x, y):
        return self.find(x) == self.find(y)


class Kruskal:
    """ Kruskal's algorithm: find minimum spanning tree
        Complexity: O(E log(V))
        used in GRL2A(AOJ)
    """

    def __init__(self, V, E, start=0, INF=10**9):
        """ V: the number of vertexes
            E: adjacency list (undirected graph)
        """
        self.kruskal(V, E)

    def kruskal(self, V, E):
        edges = []
        for v1 in range(V):
            for v2, cost in E[v1]:
                if v1 < v2:
                    edges.append((cost, v1, v2))
        edges.sort(reverse=True)
        self.mincost = 0
        self.minSpanningTree = []
        uf = UnionFindTree(V)
        while len(self.minSpanningTree) < V-1:
            cost, v1, v2 = edges.pop()
            if uf.same(v1, v2) == False:
                self.mincost += cost
                uf.unite(v1, v2)
                self.minSpanningTree.append((v1, v2, cost))

    def minCost(self):
        return self.mincost

    def getMinSpanningTree(self):
        return sorted(self.minSpanningTree)

V = int(input())
edge = [[] for _ in range(V)]
for i in range(V):
    for j, d in enumerate(map(int, input().split())):
        if d != -1:
            edge[i].append((j, d))
mst = Kruskal(V, edge)
print(mst.minCost())

Python: from sys import stdin
INF = 1<<21
WHITE, GRAY, BLACK = 0, 1, 2
n = int(stdin.readline())
M = [[INF] * n for _ in range(n)]
for i in range(0, n):
    for j, e in enumerate(list(map(int, stdin.readline().split()))):
        if e != -1: M[i][j] = e
d = [INF] * n
d[0] = 0
color = [0] * n
def prim():
    while True:
        minv = INF
        u = -1
        for i in range(0, n):
            if minv > d[i] and color[i] != BLACK:
                u = i
                minv = d[i]
        if u == -1: break
        color[u] = BLACK
        for v in range(0, n):
            if color[v] != BLACK and d[v] > M[u][v]:
                d[v] = M[u][v]
    return sum(d)
print(prim())

Python: # -*- coding: utf_8 -*-
level = False
def debug(v):
    if level:
        print(v)

n = int(input())
g = []

for i in range(n):
    v = input().split()
    g.append([int(x) for x in v]) 

debug(g)

def prim(n):
    visited = [False] * n
    d = [0] + [2001] * (n - 1)
    p = [-1] * n

    while True:
        mincost = 2001

        for i in range(n):
            if (not visited[i]) and (d[i] < mincost):
                mincost = d[i]
                u = i
        if mincost == 2001:
            break
        visited[u] = True

        for v in range(n):
            if (not visited[v]) and (g[u][v] != -1):
                if g[u][v] < d[v]:
                    d[v] = g[u][v]
                    p[v] = u

    print(sum(d))

prim(n)