Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

//util
var sc = bufio.NewScanner(os.Stdin)

func nextStr() string {
	sc.Scan()
	return sc.Text()
}

func nextInt() int {
	sc.Scan()
	i, e := strconv.Atoi(sc.Text())
	if e != nil {
		panic(e)
	}
	return i
}

func printList(list []int) {
	n := len(list)
	buf := bufio.NewWriter(os.Stdout)
	for _, v := range list[0 : n-1] {
		buf.Write([]byte(fmt.Sprintf("%d ", v)))
	}
	buf.Write([]byte(fmt.Sprintf("%d\n", list[n-1])))
	buf.Flush()
}

func max(a, b int) int {
	if a > b {
		return a
	} else {
		return b
	}
}

func min(a, b int) int {
	if a > b {
		return b
	} else {
		return a
	}
}

//solve
const (
	MAX   = 100
	INFTY = (1 << 21)
	WHITE = 0
	GRAY  = 1
	BLACK = 2
)

//V: グラフの頂点全体の集合
//T: MSTに属する頂点の集合
var (
	n     int
	M     [MAX][MAX]int //重みを記録する隣接行列
	color [MAX]int
	p     [MAX]int //MSTにおける頂点の親を記録
	d     [MAX]int //Tに属する頂点と、V−Tに属する頂点を繋ぐ辺の中で、重みが最小のものを記録
)

func prim() int {
	var u, minv int
	//初期化
	for i := 0; i < n; i++ {
		d[i] = INFTY
		p[i] = -1
		color[i] = WHITE
	}

	d[0] = 0

	for {
		//頂点uを決めていく
		//つまり、Tに属する頂点と、V−Tに属する頂点を繋ぐ辺の中で、重みが最小のものを決める
		minv = INFTY
		u = -1
		for i := 0; i < n; i++ {
			//未訪問かつ、辺の重みが最小となるuを選ぶ
			if minv > d[i] && color[i] != BLACK {
				u = i
				minv = d[i]
			}
		}

		if u == -1 {
			break
		}

		color[u] = BLACK
		for v := 0; v < n; v++ {
			//未訪問かつ、辺が存在するとき
			if color[v] != BLACK && M[u][v] != INFTY {
				if d[v] > M[u][v] {
					d[v] = M[u][v]
					p[v] = u
					color[v] = GRAY
				}
			}
		}
	}

	sum := 0
	for i := 0; i < n; i++ {
		if p[i] != -1 {
			sum += M[i][p[i]]
		}
	}
	return sum
}

func main() {
	sc.Split(bufio.ScanWords)
	n = nextInt()

	for i := 0; i < n; i++ {

		for j := 0; j < n; j++ {
			tmp := nextInt()
			if tmp == -1 {
				tmp = INFTY
			}
			M[i][j] = tmp
		}

	}

	fmt.Println(prim())

}

C++: #include <iostream>
#include <climits>
using namespace std;
#define MAX 100
static const int WHITE=0;
static const int GRAY=1;
static const int BLACK=2;

int n,d[MAX+10],p[MAX+10],color[MAX+10];
int W[MAX+10][MAX+10];

int prim()
{
  int v,k,mini,flag,u=0;
  for(int i=0;i<n;i++)
  {
      d[i]=INT_MAX;
      p[i]=-1;
  }
  d[0]=0;
  while(1)
  {
      mini=INT_MAX;
      flag=1;
      for(int i=0;i<n;i++)
      {
          if(d[i]<mini&&color[i]!=BLACK)
          {
              u=i;
              mini=d[i];
              flag=0;
          }
      }
      if(flag) break;
      color[u]=BLACK;
      for(v=0;v<n;v++)
      {
          if(W[u][v]!=INT_MAX&&color[v]!=BLACK)
          {
            if(d[v]>W[u][v])
            {
              d[v]=W[u][v];//更新当前点到最小生成树的距离
              p[v]=u;//每一轮都需要跑更新前驱结点
            }
          }
      }
  }
  int sum=0;
  for(int i=0;i<n;i++)
  {
      if(p[i]!=-1) sum+=W[i][p[i]];
  }
  return sum;
}

int main()
{
    cin>>n;
    for(int i=0;i<n;i++)
    {
        for(int j=0;j<n;j++)
        {
         int e;
         cin>>e;
         W[i][j]=(e==-1)?INT_MAX:e;
        }
        color[i]=WHITE;
    }
    cout<<prim()<<endl;
}

C++: #include <stdio.h>
#include <iostream>
#include <utility>
#include <algorithm>
#include <math.h>
#include <vector>
using namespace std;

class edge
{
  public:
    int i, j, weigt;
    bool operator()(edge e1, edge e2)
    {
        return e1.weigt < e2.weigt;
    }
};
edge e[10000];
int main()
{
    int n;
    cin >> n;
    int b[n][n] = {};
    int k = 0;
    int tmp = 0;
    int sum = 0;
    for (int i = 0; i < n; i++)
    {
        for (int j = 0; j < n; j++)
        {
            cin >> tmp;
            if (j < i + 1 || tmp < 0)
                continue;
            e[k].i = i;
            e[k].j = j;
            e[k].weigt = tmp;
            k++;
        }
    }
    sort(e, e + k, edge());
    for (int i = 0; i < k; i++)
    {
        if (b[e[i].i][e[i].j] == 0)
        {
            cout << e[i].weigt << "\n";
            sum += e[i].weigt;
            b[e[i].i][e[i].j] = 1;
            b[e[i].j][e[i].i] = 1;
            for (int j = 0; j < n; j++)
            {
                if (b[e[i].i][j] == 1 || b[e[i].j][j] == 1)
                    b[e[i].i][j] = b[e[i].j][j] = b[j][e[i].i] = b[j][e[i].j] = 1;
            }
        }
    }
    cout << sum << "\n";
    return 0;
}

C++: #include <iostream>
#include <limits.h>
using namespace std;

int main(void)
{
	int n, now = 0, flag[101];
	long ans = 0, an[100][100], min[100];

	cin >> n;

	for(int i = 0; i < n; i++) {
		for(int j = 0; j < n; j++) {
			cin >> an[i][j];
		}
		min[i] = LONG_MAX - 1;
		flag[i] = 0;
	}

	do {
		flag[now] = 1;
		flag[100] = 0;

		for(int j = 0; j < n; j++) {
			if(an[now][j] != -1 && an[now][j] < min[j] && flag[j] == 0) {
				min[j] = an[now][j];
			}
		}

		int key = LONG_MAX - 1, key_j;

		for(int j = 0; j < n; j++) {
			if(flag[j] == 0 && min[j] < key) {
				key = min[j];
				key_j = j;
			}
		}

		now = key_j;
		ans += key;

		for(int i = 0; i < n; i++) {
			if(flag[i] == 1) {
				flag[100]++;
			}
		}
	
	}while(flag[100] != n - 1);

	cout << ans << endl;

	return 0;
}

C++: #include <utility>
#include <string>
#include <vector>
#include <algorithm>
#include <iostream>
using namespace std;

int n;					//えぬ
int a[100][100] = {0};	//辺の重さ
int f[100] = {0};		//その頂点がすでに連結済みかどうか、その集団の番号
int c = 0;				//全体の重さ
int d = 1;				//次につける集団番号
int s = 0;				//選んだ本数
vector<int> w;			//木のリスト、軽いもの順
int wc = 0;				//見てる木のリストの位置

int main(){
	cin >> n;
	//まず辺の重さをaに入れる
	//wに辺のリストを入れる
	for ( int i = 0; i < n; i++ ) {
		for ( int j = 0; j < n; j++ ) {
			cin >> a[i][j];
			if ( a[i][j] != -1 && i < j ) w.push_back( a[i][j] );
		}
	}
	sort( w.begin(),w.end() );
	while(true) {									//n-1本選ぶまで無限ループ
		for ( int i = 0; i < n - 1; i++ ) {			// i < j を満たすように木を調べ続ける
			for ( int j = i + 1; j < n; j++ ) {
				if ( a[i][j] != w[wc] ) continue;	//その木が一番軽い木だったらそれを対象に検査を始める
				if ( f[i] > 0 && f[j] > 0 ) {		//その木の両端が両方とも連結済みだったら
					if ( f[i] != f[j] ) {
						int y = f[j];
						for ( int x = 0; x < n; x++ ) {
							if ( f[x] == y ) f[x] = f[i];
						}
						c += a[i][j];
						s++;
					}
				}else if ( f[i] == 0 && f[j] == 0 ) {
					f[i] = d;
					f[j] = d;
					d++;
					c += a[i][j];
					s++;
				}else {
					if ( f[i] == 0 ) {
						f[i] = f[j];
						c += a[i][j];
						s++;
					}else {
						f[j] = f[i];
						c += a[i][j];
						s++;
					}
				}
				wc++;
				a[i][j] = -1;
				if ( s == n-1 ) break;
			}
			if ( s == n-1 ) break;
		}
		if ( s == n-1 ) break;
	}
	cout << c << endl;
	return 0;
}

C++: #include <bits/stdc++.h>

using namespace std;

#define Vi vector<int>
#define FOR(i,s,e) for (int i=s; i<e; i++)
#define ITER(v) v.begin(), v.end()

constexpr int N_MAX = 100;

int weight[N_MAX][N_MAX];

int mst(const int n) {
    bool ismember[n] = {false};
    Vi members;

    members.push_back(0);
    ismember[0] = true;
    int cost = 0;

    FOR(t,1,n) {
        int addcost = -1;
        int newmember = -1;
        for (const int i : members)
        FOR(j,0,n) {
            if (ismember[j]) { continue; }
            const int w = weight[i][j];
            if (w < 0) { continue; }
            if (addcost < 0 || addcost > w) {
                addcost = w;
                newmember = j;
            }
        }
        members.push_back(newmember);
        ismember[newmember] = true;
        cost += addcost;
        //cout << "#" << newmember << endl;
    }
    return cost;
}

int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);

    int n;
    cin >> n;

    FOR(i,0,n) {
        FOR(j,0,n) {
            cin >> weight[i][j];
        }
    }

    int cost = mst(n);
    cout << cost << endl;

    return 0;
}