Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

var scanner = bufio.NewScanner(os.Stdin)

func nextString() string {
	scanner.Scan()
	return scanner.Text()
}

func nextInt() int {
	n, err := strconv.Atoi(nextString())
	if err != nil {
		fmt.Printf("strconv.Atoi failed: %v\n", err)
	}
	return n
}

func newGraph(nNodes int) *Graph {
	g := Graph{}
	g.nodes = make([]*GraphNode, nNodes)
	for iNode := 0; iNode < len(g.nodes); iNode++ {
		g.nodes[iNode] = &GraphNode{}
		g.nodes[iNode].key = GraphNodeKey(iNode)
	}
	return &g
}

var infty = 1000000000

type GraphNodeKey int

// GraphNode is a node for undirected graph
type GraphNode struct {
	key       GraphNodeKey
	adjacents []*GraphNode
	visited   bool
	d, f      int
	parent    *GraphNode
	cc        int
}

func (g *Graph) setAdjacent(l, r GraphNodeKey) {
	g.nodes[l].adjacents = append(g.nodes[l].adjacents, g.nodes[r])
}

// Graph is a undirected graph
type Graph struct {
	nodes []*GraphNode
}

func (g *Graph) initialize() {
	for iNode := 0; iNode < len(g.nodes); iNode++ {
		g.nodes[iNode].visited = false
		g.nodes[iNode].d = infty
		g.nodes[iNode].f = infty
		g.nodes[iNode].parent = nil
		g.nodes[iNode].cc = -1 // 22.3-12
	}
}

type QueueEntry struct {
	node *GraphNode
	next *QueueEntry
}

type Queue struct {
	head, tail *QueueEntry
}

func (q *Queue) enqueue(node *GraphNode) {
	entry := QueueEntry{}
	entry.node = node

	if q.tail == nil {
		q.head = &entry
		q.tail = &entry
		return
	}

	q.tail.next = &entry
	q.tail = q.tail.next
}

func (q *Queue) dequeue() *QueueEntry {
	if q.head == nil {
		return nil
	}
	poped := q.head
	q.head = q.head.next
	if q.head == nil {
		q.tail = nil
	}
	return poped
}

func (q *Queue) isEmpty() bool {
	return q.head == nil
}

var time = 0

func fillDistancesByDepthFirstSearch(g *Graph) {
	g.initialize()
	time = 0
	cc := 0

	for _, u := range g.nodes {
		if !u.visited {
			dfsVisit(g, u, cc)
			cc++
		}
	}
}

func dfsVisit(g *Graph, u *GraphNode, cc int) {
	time++
	u.d = time
	u.cc = cc

	u.visited = true
	for _, v := range u.adjacents {
		if !v.visited {
			v.parent = u
			dfsVisit(g, v, cc)
		}
	}
	time++
	u.f = time
}

func main() {
	scanner.Split(bufio.ScanWords)

	nUsers := nextInt()
	nEdges := nextInt()
	graph := newGraph(nUsers)
	for iEdge := 0; iEdge < nEdges; iEdge++ {
		l := GraphNodeKey(nextInt())
		r := GraphNodeKey(nextInt())
		graph.setAdjacent(l, r)
		graph.setAdjacent(r, l)
	}

	fillDistancesByDepthFirstSearch(graph)

	nQueries := nextInt()
	for iQuery := 0; iQuery < nQueries; iQuery++ {
		l := GraphNodeKey(nextInt())
		r := GraphNodeKey(nextInt())

		// fmt.Println(graph.nodes[l].d, graph.nodes[r].d, graph.nodes[r].f, graph.nodes[l].f)
		if graph.nodes[l].cc == graph.nodes[r].cc {
			fmt.Println("yes")
		} else {
			fmt.Println("no")
		}
	}
}

Python: def bfs(graph, start, goal, connection):
    visited = {start: None}
    unvisited = [start]
    while unvisited:
        now = unvisited[0]
        if now == goal or connection[1000000*now + goal] == 1:
            connection[1000000*start + goal] = 1
            return "yes"
        unvisited = unvisited[1:]
        for next in graph[now][1:]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return "no"

n, m = map(int, input().split())
g = [[i] for i in range(n)]
c = {}

for i in range(m):
    inp = list(map(int, input().split()))
    g[inp[0]].append(inp[1])
    g[inp[1]].append(inp[0])

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    print(bfs(g, s, t, c))

Python: n, m = map(int, input().split())

a = [[] for i in range(n)]

for i in range(m):
    com = list(map(int, input().split()))
    a[com[0]].append(com[1])
    a[com[1]].append(com[0])

q = int(input())

from collections import deque
queue = deque()


for j in range(q):
    memo = [0 for i in range(n)]
    data = list(map(int, input().split()))
    memo[data[0]] = 1
    queue.append(data[0])

    try:
        while len(queue) != 0:
            b = queue.popleft()
            if len(a[b]) != 0:
                for k in a[b]:
                    if memo[k] == 0:
                        memo[k] = 1
                        queue.append(k)
                        if k == data[1]:
                            print("yes")
                            raise Exception
        print("no")
    except Exception:
        pass

Python: #!/usr/bin/python3
n, m = map(int, input().split())

e = [None] * n

for i in range(m):
    s, t = map(int, input().split())
    if e[s] == None and e[t] == None:
        a = {s, t}
        e[s] = e[t] = a
    elif e[s] == None:
        e[t].add(s)
        e[s] = e[t]
    elif e[t] == None:
        e[s].add(t)
        e[t] = e[s]
    else:
        a = e[s] | e[t]
        for j in a:
            e[j] = a

q = int(input())
for i in range(q):
    s, t = map(int, input().split())
    if e[s] != None and t in e[s]:
        print('yes')
    else:
        print('no')

Python: from collections import defaultdict
import sys
sys.setrecursionlimit(1 << 25)

G = defaultdict(lambda: [])
n, m = map(int, input().split())
color = {key: None for key in range(n)}

for _ in range(m):
    s, t = map(int, input().split())
    G[s].append(t)
    G[t].append(s)

# 離接リストをもとに、たどり着ける友達関係をグループ化する #(union findが使える気もするけどここではDFSで領域を探索していく)


def dfs(node: int, co: int):
    if color[node] is not None:
        return
    color[node] = co

    for no in G[node]:
        dfs(no, co)
    return


# すべてのnodeを開始点としてdfsで領域わけしてみる
c = 1
for node in G.keys():
    dfs(node, c)
    c += 1

Q = int(input())
for _ in range(Q):
    s, t = list(map(int, input().split()))
    if color[s] and color[t] and color[s] == color[t]:
        print('yes')
    else:
        print('no')

Python: n, m = map(int, raw_input().split())
G = [[0 for i in range(n)] for j in range(n)]

for i in range(m):
    s, t = map(int, raw_input().split())
    G[s][t] = 1
    G[t][s] = 1

for i in range(2*n):
    for j in range(n):
        for k in range(j+1, n):
            if G[j][k] == 1:
                for l in range(k+1, n):
                    if G[k][l] == 1:
                        G[j][l] = 1
                        G[l][j] = 1

q = int(raw_input())
ans = ["no" for i in range(q)]
for i in range(q):
    s, t = map(int, raw_input().split())
    if G[s][t] == 1:
        ans[i] = "yes"
for i in range(q):
    print(ans[i])

Python: from collections import deque


user_num,rer_num=map(int,input().split())
graph=[[] for loop in range(user_num)]

for loop in range(rer_num):
    user1,user2=map(int,input().split())
    graph[user1].append(user2)
    graph[user2].append(user1)

#group[user1]はuser1が属するグループ.同じグループに属するuser同士は互いに到達可能
group=[-1]*user_num

que=deque([])
que.append(0)
tmp_group=0
for user in range(user_num):
    if(group[user]==-1):
        que.append(user)
        group[user]=tmp_group
        while(1):
            user1=que.popleft()
            for user2 in graph[user1]:
                if(group[user2]!=-1):
                    que.append(user2)
                    group[user2]=tmp_group
            if(len(que)==0):
                tmp_group+=1
                break


for loop in range(int(input())):
    user1,user2=map(int(input()))
    if(group[user1]==group[user2]):
        print("yes")
    else:
        print("no")