Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

//util
var sc = bufio.NewScanner(os.Stdin)

func nextStr() string {
	sc.Scan()
	return sc.Text()
}

func nextInt() int {
	sc.Scan()
	i, e := strconv.Atoi(sc.Text())
	if e != nil {
		panic(e)
	}
	return i
}

func printList(list []int) {
	n := len(list)
	buf := bufio.NewWriter(os.Stdout)
	for _, v := range list[0 : n-1] {
		buf.Write([]byte(fmt.Sprintf("%d ", v)))
	}
	buf.Write([]byte(fmt.Sprintf("%d\n", list[n-1])))
	buf.Flush()
}

func max(a, b int) int {
	if a > b {
		return a
	} else {
		return b
	}
}

func min(a, b int) int {
	if a > b {
		return b
	} else {
		return a
	}
}

//solve
const (
	MAX   = 100
	INFTY = (1 << 21)
	WHITE = 0
	GRAY  = 1
	BLACK = 2
)

//V: グラフの頂点全体の集合
//T: MSTに属する頂点の集合
var (
	n     int
	M     [MAX][MAX]int //重みを記録する隣接行列
	color [MAX]int
	p     [MAX]int //MSTにおける頂点の親を記録
	d     [MAX]int //Tに属する頂点と、V−Tに属する頂点を繋ぐ辺の中で、重みが最小のものを記録
)

func prim() int {
	var u, minv int
	//初期化
	for i := 0; i < n; i++ {
		d[i] = INFTY
		p[i] = -1
		color[i] = WHITE
	}

	d[0] = 0

	for {
		//頂点uを決めていく
		//つまり、Tに属する頂点と、V−Tに属する頂点を繋ぐ辺の中で、重みが最小のものを決める
		minv = INFTY
		u = -1
		for i := 0; i < n; i++ {
			//未訪問かつ、辺の重みが最小となるuを選ぶ
			if minv > d[i] && color[i] != BLACK {
				u = i
				minv = d[i]
			}
		}

		if u == -1 {
			break
		}

		color[u] = BLACK
		for v := 0; v < n; v++ {
			//未訪問かつ、辺が存在するとき
			if color[v] != BLACK && M[u][v] != INFTY {
				if d[v] > M[u][v] {
					d[v] = M[u][v]
					p[v] = u
					color[v] = GRAY
				}
			}
		}
	}

	sum := 0
	for i := 0; i < n; i++ {
		if p[i] != -1 {
			sum += M[i][p[i]]
		}
	}
	return sum
}

func main() {
	sc.Split(bufio.ScanWords)
	n = nextInt()

	for i := 0; i < n; i++ {

		for j := 0; j < n; j++ {
			tmp := nextInt()
			if tmp == -1 {
				tmp = INFTY
			}
			M[i][j] = tmp
		}

	}

	fmt.Println(prim())

}

Python: # coding: utf-8

n = int(input())
ew = [None] * n
for i in range(n):
    ew[i] = list(map(int, input().split()))

elist = []
for i in range(n):
    for j in range(i+1, n):
        if ew[i][j] > -1:
            elist.append((ew[i][j], i, j))


class UnionFind(object):
    def __init__(self, n):
        self.parent = [i for i in range(n)]

    def find_root(self, i):
        if self.parent[i] != i:
            p = self.parent[i]
            self.parent[i] = self.find_root(p)
        return self.parent[i]

    def same_group(self, i, j):
        return self.find_root(i) == self.find_root(j)

    def union(self, i, j):
        i = self.find_root(i)
        j = self.find_root(j)
        if i != j:
            self.parent[j] = i


uf = UnionFind(n)
esum = 0
for edge in sorted(elist):
    if not uf.same_group(edge[1], edge[2]):
        uf.union(edge[1], edge[2])
        esum += edge[0]

print(esum)

Python: # -*- coding: utf-8 -*-
"""
Created on Sat Apr  6 18:01:32 2019

@author: Yamazaki Kenichi
"""

n = int(input())
A = [list(map(int,input().split())) for i in range(n)]
INFTY = 10**6
T = [-1 for i in range(n)]
d = [INFTY for i in range(n)]
p = [0 for i in range(n)]
d[0], p[0] = 0, -1
for j in range(n):
    mincost = 10**6
    for i in range(n):
        if T[i] != 1 and d[i] < mincost:
            mincost = d[i]
            u = i
    T[u] = 1
    for v in range(n):
        if T[v] != 1 and A[u][v] != -1:
            if A[u][v] < d[v]:
                d[v] = A[u][v]
                p[v] = u
                T[v] = 0
print(sum(d))

Python: n = int(input())
edgeArray = [list(map(int, input().split())) for i in range(n)]
edgeList = []
rootList = [-1 for i in range(n)]
sumLength = 0

def getRoot(x):
    r = rootList[x]
    if r < 0:
        rootList[x] = x
    elif r != x:
        rootList[x] = getRoot(r)
    return rootList[x]
        
for i in range(n):
    for j in range(i):
        if edgeArray[i][j] != -1:
            edgeList.append([edgeArray[i][j], i, j])
edgeList.sort(key=lambda x: x[0])
for e in edgeList:
    x = getRoot(e[1])
    y = getRoot(e[2])
    if x != y:
        sumLength += e[0]
        rootList[x] = rootList[y] = min(x, y)
print(sumLength)

Python: import sys
from collections import deque

sys.setrecursionlimit(1000000)
n = int(input())
graph = [[] for _ in range(n)]

global visited 
visited = [0 for _ in range(n)]
global Q, S, T

S = [0] #訪れた順
T = []
visited[0] = 1 #開始位置はすでに訪れたことにする

def input_graph(n):
  for i in range(n):
    vs = list(map(int, input().split()))
    graph[i] = vs
    """for j in range(n):
      if vs[j] != -1:
        tree[i].append([j, vs[j]])"""

def prim():
  global S
  cost = 0
  while len(S) < n:
    max_e = 3000
    ad_v = 0
    ad_list = []
    for s in S:
      for j in range(n):
        if graph[s][j] != -1 and j not in S:
          ad_list.append(graph[s][j])
          #print("s: ",s, " j: ",j, graph[s][j])
          if max_e > graph[s][j]:
            max_e = graph[s][j]
            ad_v = j
    S.append(ad_v)
    cost += max_e
  print(cost)
  

if __name__ == "__main__":
  input_graph(n)
  prim()

Python: import heapq
n = int(input())
ans = 0
cost = []
for i in range(n):
    L = list(map(int,input().split()))
    cost.append(L)
used = [False]*n
used[0] = True #島0から探索を始める。
edge = []
for i in range(n):
    T = []
    edge.append(T)
for i in range(n):
    for j in range(n):
        if cost[i][j] != -1:
            edge[i].append([cost[i][j],j])
P = edge[0]
P.sort()
while len(P) != 0:
    cur = heapq.heappop(P)
    d = cur[0]
    next = cur[1]
    if used[next] == True:
        continue
    used[next] = True
    ans += d
    for e in edge[next]:
        heapq.heappush(P,[e[0],e[1]])
print(ans)

Python: import heapq


class MinimumSpanningTree:
    """ Prim's algorithm: find minimum spanning tree
        Complexity: O(E log(V))
        used in GRL2A(AOJ)
    """

    def __init__(self, V, E, start=0, INF=10**9):
        """ V: the number of vertexes
            E: adjacency list (undirected graph)
            start: start vertex
            INF: Infinity cost
        """
        self.prim(V, E, start, INF)

    def prim(self, V, E, start=0, INF=10**9):
        used = [False] * V
        self.mincost = 0
        que = []
        heapq.heappush(que, (0, 0))
        while len(que) > 0:
            cost, v = heapq.heappop(que)
            if used[v]:
                continue
            used[v] = True
            self.mincost += cost
            for to, c in E[v]:
                heapq.heappush(que, (c, to))

    def minCost(self):
        return self.mincost

V = int(input())
edge = [[] for _ in range(V)]
for i in range(V):
    for j, d in enumerate(map(int, input().split())):
        if d != -1:
            edge[i].append((j, d))
mst = MinimumSpanningTree(V, edge)
print(mst.minCost())

Python: n = int(input())
m = []

for _ in range(n):
    tmp = [int(x) for x in input().split()]
    m.append(tmp)

edge_list = [] 

j = 1
for i in range(n-1):
    for k,x in enumerate(m[i][j:]):
        if x != -1:
            edge_list.append((x,i,k))
        else:
            pass
    j += 1
edge_list.sort()

root_list = [i for i in range(n)]

def root(x):
    path_to_root = []
    while root_list[x] != x:
        path_to_root.append(x)
        x = root_list[x]
    for node in path_to_root:
        root_list[node] = x
    return x

def is_same_root(x,y):
    return root(x) == root(y)

def unite(x,y):
    root_list[root(x)] = root(y)

cost = 0
for x in edge_list:
    w,p,q = x
    if is_same_root(p,q):
        pass
    else:
        cost += w
        unite(p,q)

print(cost)

Python: n = int(input())

a = []
for i in range(n):
    a.append(list(map(int, input().split())))

ans = 0
mincost = [2001] * n
flag = [0] * n
mincost[0] = 0

while 1:
    v = -1
    for j in range(n):
        if flag[j] != 1 and (v == -1 or mincost[j] < mincost[v]):
            v = j
    if v == -1:
        break
    flag[v] = 1
    ans += mincost[v]
    for j in range(n):
        if a[v][j] == -1:
            continue
        mincost[j] = min(mincost[j], a[v][j])
print(ans)