Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

const BIG_COST = 200000

type Path struct {
	node int
	cost int
}

func main() {
	sc := bufio.NewScanner(os.Stdin)
	sc.Split(bufio.ScanWords)

	nNodes := scanInt(sc)

	// 各頂点につながる頂点一覧を得るための隣接リスト
	graph := make([][]Path, nNodes)

	for i := 0; i < nNodes; i++ {
		u := scanInt(sc)
		k := scanInt(sc)
		graph[i] = make([]Path, k)
		for d := 0; d < k; d++ {
			graph[u][d] = Path{
				node: scanInt(sc),
				cost: scanInt(sc),
			}
		}
	}

	// 0 から各頂点への最小コストを保存する配列
	minCosts := make([]int, nNodes)

	minCosts[0] = 0
	for i := 1; i < nNodes; i++ {
		minCosts[i] = BIG_COST
	}

	// 各頂点が調査済みかどうかを保持する配列
	checked := make([]bool, nNodes)

	// 最小コストのパスを高速に取得するためのヒープ。
	// コストが小さいものほどルートに来るようにする。
	heap := NewHeap(func(a, b Path) bool {
		return a.cost < b.cost
	})

	heap.insert(Path{node: 0, cost: 0})
	for heap.size > 0 {
		u := heap.extractMax()

		// 隣接行列を使っていた時とは違い、ヒープには
		// 同じノードへのパスが複数含まれうる。そのため既によりコストの低い
		// パスが見つかっている場合は無視する。
		if minCosts[u.node] < u.cost {
			continue
		}

		checked[u.node] = true

		for _, v := range graph[u.node] {
			cost := v.cost + u.cost
			if !checked[v.node] && cost < minCosts[v.node] {
				minCosts[v.node] = cost
				heap.insert(Path{node: v.node, cost: cost})
			}
		}
	}

	w := bufio.NewWriter(os.Stdout)
	for i, cost := range minCosts {
		fmt.Fprintf(w, "%d %d\n", i, cost)
	}
	w.Flush()
}

func scanInt(sc *bufio.Scanner) int {
	sc.Scan()
	v, _ := strconv.Atoi(sc.Text())
	return v
}

// --- From ALDS1_9_C: Priority Queue

type Heap struct {
	size   int
	heap   []Path
	isHigh func(a, b Path) bool
}

func NewHeap(isHigh func(a, b Path) bool) Heap {
	heap := make([]Path, 1) // 先頭は不使用
	return Heap{size: 0, heap: heap, isHigh: isHigh}
}

func (h *Heap) insert(v Path) {
	h.size += 1
	if h.size > len(h.heap)-1 {
		h.heap = append(h.heap, v)
	} else {
		h.heap[h.size] = v
	}

	for i := h.size; i > 1; {
		parent := i / 2
		if h.isHigh(h.heap[parent], h.heap[i]) {
			break
		}
		h.heap[i], h.heap[parent] = h.heap[parent], h.heap[i]
		i = parent
	}
}

func (h *Heap) extractMax() Path {
	if h.size <= 0 {
		panic("cannot extract from empty heap")
	}

	max := h.heap[1]
	h.heap[1] = h.heap[h.size]
	h.size -= 1
	h.maxHeapify(1)

	return max
}

func (h *Heap) maxHeapify(idx int) {
	left := idx * 2
	right := left + 1
	largest := idx

	if left <= h.size {
		if h.isHigh(h.heap[left], h.heap[idx]) {
			largest = left
		}
		if right <= h.size && h.isHigh(h.heap[right], h.heap[largest]) {
			largest = right
		}
	}

	if largest != idx {
		h.heap[idx], h.heap[largest] = h.heap[largest], h.heap[idx]
		h.maxHeapify(largest)
	}
}

C++: #include <cmath>
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <climits>
#include <map>
#include <list>
#include <stack>
#include <queue>
#include <vector>
#include <string>
#include <sstream>
#include <fstream>
#include <iostream>
#include <algorithm>
using namespace std;

int *c;

struct job {
	int id;
	job(int i){
		this->id = i;
	}
	bool operator<(job j) const {
		return c[this->id] > c[j.id];
	}
};

int main() {
	int n;
	scanf("%d", &n);
	
	c = new int[n];
	vector<vector<pair<int, int> > > paths;
	
	for(int i = 0; i < n; i++){
		int u, k;
		scanf("%d %d", &u, &k);
		
		vector<pair<int, int> > path;
		c[u] = u ? INT_MAX : 0;
		while(k--){
			int v, c;
			scanf("%d %d", &v, &c);
			path.push_back(make_pair(v, c));
		}
		paths.push_back(path);
	}
	
	priority_queue<job> q;
	q.push(job(0));
	while(q.size()){
		int i = q.top().id;
		q.pop();
		
		for(int j = 0; j < paths[i].size(); j++){
			int dest = paths[i][j].first;
			int cost = paths[i][j].second;
			if(c[dest] > c[i] + cost){
				c[dest] = c[i] + cost;
				q.push(job(dest));
			}
		}
	}
	
	for(int i = 0; i < n; i++){
		printf("%d %d\n", i, c[i]);
	}
}

C++: #include <iostream>
#include <vector>
#include <queue>
using namespace std;
typedef long long ll;
typedef pair<ll, ll> Pair;
ll inf = 1e10;
int MAX_V;

ll V, E;
vector<Pair> G[100010];
ll d[100010];

void dijkstra(ll s) {
    priority_queue<Pair, vector<Pair>, greater<Pair>> que;
    fill(d, d + V, inf);
    d[s] = 0;
    que.push(Pair(0, s));
    
    while (!que.empty()) {
        Pair p = que.top();
        que.pop();
        
        ll v = p.second;
        if (d[v] < p.first) continue;
        for (int i = 0; i < G[v].size(); i++) {
            Pair e = G[v][i];
            if (d[e.first] > d[v] + e.second) {
                d[e.first] = d[v] + e.second;
                que.push(Pair(d[e.first], e.first));
            }
        }
    }
}

int main() {
    cin >> V;
    for (int i = 0; i < V; i++) {
        int a, et;
        cin >> a >> et;
        for (int j = 0; j < et; j++) {
            int b;
            ll r;
            cin >> b >> r;
            G[a].emplace_back(b, r);
            //G[b].emplace_back(a, r);
        }
    }

    dijkstra(0);
    for (int i = 0; i < V; i++) {
        cout << i << " " << d[i] << endl;
    }

}

C++: #include <bits/stdc++.h>
using namespace std;

static const int N = 10001;
static const int INF = (1 << 30);
static const int WHITE = 0;
static const int GRAY  = 1;
static const int BLACK = 2;

int n;
vector<pair<int ,int> > adj[N];

void dijkstra(){
    priority_queue<pair<int,int> > p_q;
    int color[N];
    int d[N];
    for(int i=0;i<n;i++){
        d[i] = INF;
        color[i] = GRAY;
    }

    d[0] = 0;
    p_q.push(make_pair(0,0));
    color[0] = GRAY;

    while(!p_q.empty()){
        pair<int,int> f = p_q.top();
        p_q.pop();
        int u = f.second;
        color[u] = BLACK;

        if(d[u] < f.first*-1) continue;

        for(int i=0;i<adj[u].size();i++){
            int v = adj[u][i].first;
            if(color[v] == BLACK) continue;
            if(d[v] > d[u]+adj[u][i].second){
                d[v] = d[u]+adj[u][i].second;
                p_q.push(make_pair(d[v]*-1,v));
                color[v] = GRAY;
            }
        }
    }

    for(int i=0;i<n;i++){
        cout << i << ' ';
        if(d[i] == INF)
            cout << -1;
        else 
            cout << d[i];
        cout << endl;
    }
}

int main(){
    int k,u,v,c;

    cin >> n;
    for(int i=0;i<n;i++){
        cin >> u >> k;
        for(int j=0;j<k;j++){
            cin >> v >> c;
            adj[u].push_back(make_pair(v,c));
        }
    }

    dijkstra();
}

C++: #include <iostream>
#include <limits.h>
#include <vector>
#include <queue>

using namespace std;

struct Node {
    int id;
    int cost;
    bool done;
    vector<int> next_node;
    vector<int> len_cost;

    bool operator<(const Node& right) const {
        return cost > right.cost;
    }
} node[10000];

int main() {
    int n, id, k;

    cin >> n;
    for (int i = 0; i < n; i++) {
        cin >> id >> k;
        node[id].id = id;
        node[id].cost = INT_MAX;
        node[id].done = false;
        node[id].next_node.resize(k);
        node[id].len_cost.resize(k);
        for (int j = 0; j < k; j++) {
            cin >> node[id].next_node[j] >> node[id].len_cost[j];
        }
    }

    priority_queue<Node> q;
    node[0].cost = 0;
    q.push(node[0]);
    while (!q.empty()) {
        Node temp = q.top();
        q.pop();

        if (temp.done == true) {
            continue;
        }
        node[temp.id].done = true;

        for (int i = 0; i < temp.next_node.size(); i++) {
            int to = temp.next_node[i];
            int cost = temp.cost + temp.len_cost[i];
            if (node[to].cost > cost) {
                node[to].cost = cost;
                q.push(node[to]);
            }
        }
    }

    for (int i = 0; i < n; i++) {
        cout << i << " " << node[i].cost << endl;
    }
    
    return 0;
}