Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

const BIG_COST = 200000

type Path struct {
	node int
	cost int
}

func main() {
	sc := bufio.NewScanner(os.Stdin)
	sc.Split(bufio.ScanWords)

	nNodes := scanInt(sc)

	// 各頂点につながる頂点一覧を得るための隣接リスト
	graph := make([][]Path, nNodes)

	for i := 0; i < nNodes; i++ {
		u := scanInt(sc)
		k := scanInt(sc)
		graph[i] = make([]Path, k)
		for d := 0; d < k; d++ {
			graph[u][d] = Path{
				node: scanInt(sc),
				cost: scanInt(sc),
			}
		}
	}

	// 0 から各頂点への最小コストを保存する配列
	minCosts := make([]int, nNodes)

	minCosts[0] = 0
	for i := 1; i < nNodes; i++ {
		minCosts[i] = BIG_COST
	}

	// 各頂点が調査済みかどうかを保持する配列
	checked := make([]bool, nNodes)

	// 最小コストのパスを高速に取得するためのヒープ。
	// コストが小さいものほどルートに来るようにする。
	heap := NewHeap(func(a, b Path) bool {
		return a.cost < b.cost
	})

	heap.insert(Path{node: 0, cost: 0})
	for heap.size > 0 {
		u := heap.extractMax()

		// 隣接行列を使っていた時とは違い、ヒープには
		// 同じノードへのパスが複数含まれうる。そのため既によりコストの低い
		// パスが見つかっている場合は無視する。
		if minCosts[u.node] < u.cost {
			continue
		}

		checked[u.node] = true

		for _, v := range graph[u.node] {
			cost := v.cost + u.cost
			if !checked[v.node] && cost < minCosts[v.node] {
				minCosts[v.node] = cost
				heap.insert(Path{node: v.node, cost: cost})
			}
		}
	}

	w := bufio.NewWriter(os.Stdout)
	for i, cost := range minCosts {
		fmt.Fprintf(w, "%d %d\n", i, cost)
	}
	w.Flush()
}

func scanInt(sc *bufio.Scanner) int {
	sc.Scan()
	v, _ := strconv.Atoi(sc.Text())
	return v
}

// --- From ALDS1_9_C: Priority Queue

type Heap struct {
	size   int
	heap   []Path
	isHigh func(a, b Path) bool
}

func NewHeap(isHigh func(a, b Path) bool) Heap {
	heap := make([]Path, 1) // 先頭は不使用
	return Heap{size: 0, heap: heap, isHigh: isHigh}
}

func (h *Heap) insert(v Path) {
	h.size += 1
	if h.size > len(h.heap)-1 {
		h.heap = append(h.heap, v)
	} else {
		h.heap[h.size] = v
	}

	for i := h.size; i > 1; {
		parent := i / 2
		if h.isHigh(h.heap[parent], h.heap[i]) {
			break
		}
		h.heap[i], h.heap[parent] = h.heap[parent], h.heap[i]
		i = parent
	}
}

func (h *Heap) extractMax() Path {
	if h.size <= 0 {
		panic("cannot extract from empty heap")
	}

	max := h.heap[1]
	h.heap[1] = h.heap[h.size]
	h.size -= 1
	h.maxHeapify(1)

	return max
}

func (h *Heap) maxHeapify(idx int) {
	left := idx * 2
	right := left + 1
	largest := idx

	if left <= h.size {
		if h.isHigh(h.heap[left], h.heap[idx]) {
			largest = left
		}
		if right <= h.size && h.isHigh(h.heap[right], h.heap[largest]) {
			largest = right
		}
	}

	if largest != idx {
		h.heap[idx], h.heap[largest] = h.heap[largest], h.heap[idx]
		h.maxHeapify(largest)
	}
}

C++: #include<bits/stdc++.h>
using namespace std;

int cost[1000][1000];//cost[a][b] a??????b????§?????????????????????????
long long int d[1000];//??????s?????????????°??????¢
bool used[1000];
int arrow;//????????°

const int INF = 10000000;

void dijkstra(){
  fill(d,d+arrow,INF);
  fill(used,used + arrow,false);
  d[0] = 0;

  while(1){
    int v=-1;
    // ???????????????????????????????????????????????¢???????°???????????????¢???
    for(int u=0;u<arrow;u++){
      if(!used[u] && (v == -1 || d[u] < d[v])) v = u;
    }

    if(v == -1) break;

    used[v] = true;

    for(int u=0; u<arrow; u++){
      if(cost[v][u] != INF){
        d[u] = min(d[u],d[v] + cost[v][u]);
      }
    }
  }

  for(int u=0; u<arrow; u++){
    cout << u << " " << d[u] << endl;
  }

}

int main(){

    cin >> arrow;

    int n,a,v,c;



    for(int i=0;i<arrow;i++){
      for(int j=0;j<arrow;j++){
        cost[i][j] = INF;
      }
    }

    for(int u=0;u<arrow;u++){

      cin >> n >> a;

      for(int i=0; i<a;i++){
        cin >> v >> c;
        cost[n][v] = c;
      }
    }

    dijkstra();

    return 0;
}

C++: #include<iostream>
#include<algorithm>
#include<queue>
using namespace std;
static const int MAX = 10000;
static const int INFTY = (1 << 20);
static const int WHITE = 0;
static const int GRAY = 1;
static const int BLACK = 2;

int n;
vector<pair<int, int> > adj[MAX];

void dijkstra() {
	priority_queue<pair<int, int> > PQ;
	int color[MAX];
	int d[MAX];
	for (int i = 0; i < n; i++) {
		d[i] = INFTY;
		color[i] = WHITE;
	}

	d[0] = 0;
	PQ.push(make_pair(0, 0));
	color[0] = GRAY;

	while (!PQ.empty()) {
		pair<int, int> f = PQ.top();
		PQ.pop();
		int u = f.second;

		color[u] = BLACK;

		if (d[u] < f.first*(-1))continue;

		for (unsigned int j = 0; j < adj[u].size(); j++) {
			int v = adj[u][j].first;
			if (color[v] == BLACK)continue;
			if (d[v] > d[v] + adj[u][j].second) {
				d[v] = d[u] + adj[u][j].second;
				PQ.push(make_pair(d[v] * (-1), v));
				color[v] = GRAY;
			}
		}
	}

	for (int i = 0; i < n; i++) {
		cout << i << " " << (d[i] == INFTY ? -1 : d[i]) << endl;
	}
}

int main() {
	int k, u, v, c;

	cin >> n;
	for (int i = 0; i < n; i++) {
		cin >> u >> k;
		for (int j = 0; j < k; j++) {
			cin >> v >> c;
			adj[u].push_back(make_pair(v, c));
		}
	}

	dijkstra();

	return 0;
}

C++: #include <iostream>
#include <cstdio>
#include <algorithm>
#include <cmath>
#include <climits>
#include <string>
#include <vector>
#include <utility>
#include <functional>
#include <stack>
#include <queue>
#include <map>
#include <set>
#include <cassert>

using namespace std;

typedef long long ll;
typedef pair<ll, ll> P;

const ll MOD = ll(1e9) + 7;
const ll INF = LLONG_MAX;
const ll MAX_N = ll(1e5) + 5;
const double EPS = 10e-8;
const double PI = 3.14159265359;

#define REP(i, n) for (ll i = 0; i < n; i++)
#define REPR(i, n) for (ll i = n; i >= 0; i--)
#define FOR(i, m, n) for (ll i = m; i < n; i++)

int dx[] = {1, 0, -1, 0}, dy[] = {0, 1, 0, -1};

ll n, d[100000];
vector<P> g[100000];

void dijkstra(ll s) {
    fill(d, d + n, INF);
    d[s] = 0;
    priority_queue<P, vector<P>, greater<P> > que;
    que.push({0, s});
    while (!que.empty()) {
        P p = que.top();
        que.pop();
        ll u = p.second;
        if (p.first > d[u]) continue;
        REP(i, g[u].size()) {
            ll v = g[u][i].first, cost = g[u][i].second;
            if (d[v] > d[u] + cost) {
                d[v] = d[u] + cost;
                que.push({d[v], v});
            }
        }
    }
}

int main() {
    cin >> n;
    REP(i, n) {
        ll from, k;
        cin >> from >> k;
        REP(j, k) {
            ll to, c;
            cin >> to >> c;
            g[from].push_back({to, c});
        }
    }
    dijkstra(0);
    REP(i, n) printf("%ld %ld\n",i,d[i]);
    return 0;
}

C++: // ConanYu's https://vjudge.net/solution/13220749
// semon0x29a's https://vjudge.net/solution/13218148

#include <bits/stdc++.h>
using namespace std;
using LL = long long;
using pi = pair<int, int>;

const int INF = 0x3F3F3F3F;
const int maxN = 10010;

int n;
bool mark[maxN];
LL dis[maxN];
map<pi, LL> path;

void init() {
	memset(dis, 0x3F, sizeof(dis));
	for (int i=0; i<n; ++i) path[{i, i}] = 0;
}

void dijkstra() {
	dis[0] = 0;
	for (int i=0; i<n; ++i) {
		int marker = 0, amin = INF;
		for (int i=0; i<n; ++i) if (!mark[i]) {
			if (dis[i] < amin) {
				amin = dis[i];
				marker = i;
			}
		}
		mark[marker] = true;
		for (int i=0; i<n; ++i) if (!mark[i]) {
			if (path.count({marker, i}))
			if (dis[i] > dis[marker] + path[{marker, i}])	
				dis[i] = dis[marker] + path[{marker, i}];
		}
	}
}

int main()
{	
	scanf("%d", &n);
	init();
	
	for (int i=0; i<n; ++i) 
	{
		int u, k; scanf("%d%d", &u, &k);
		while (k--) {
			int v; LL c; scanf("%d%lld", &v, &c);
			if (path.count({u, v}))
				path[{u, v}] = min(path[{u, v}], c);
			else path[{u, v}] = c;
		}
	}
	
	dijkstra();
	for (int i=0; i<n; ++i) {
		printf("%d %lld\n", i, dis[i]);
	}
}