Go: package main

/*
連鎖行列積
*/

import (
	"bufio"
	"bytes"
	"fmt"
	"log"
	"math"
	"os"
	"strconv"
	"strings"
)

func min(a, b int) int {
	if a < b {
		return a
	}
	return b
}

type mem *[][]int

func main() {
	scanner := makeScanner(1024)
	n := eGetInt(scanner)
	p := make([]int, n+1)
	for i := 0; i < n; i++ {
		rowcol := eGetInts(scanner)
		p[i] = rowcol[0]
		p[i+1] = rowcol[1]
	}
	m := make([][]int, n)
	for i := 0; i < n; i++ {
		m[i] = make([]int, n)
	}
	// 初期値の格納
	for i := 0; i < n; i++ {
		for j := i; j < n; j++ {
			if i == j {
				m[i][j] = 0 //  同じ行列へのコストは当然0
			} else {
				m[i][j] = math.MaxInt64
			}
		}
	}

	// num : 行列の数. num == 1の場合は初期値0を格納ずみ
	for num := 2; num <= n; num++ {
		// s : スタート行列番号
		for s := 0; s+num <= n; s++ {
			// t : 終了行列番号
			t := s + num - 1
			// k : 仕切
			for k := s; k < t; k++ {
				m[s][t] = min(m[s][t], m[s][k]+m[k+1][t]+p[s]*p[k+1]*p[t+1])
			}
		}
	}
	fmt.Println(m[0][n-1])
}

////////////////////////////////////////////////////////////////////////////////
// ライブラリ
////////////////////////////////////////////////////////////////////////////////
func makeScanner(maxByte int) *bufio.Scanner {
	scanner := bufio.NewScanner(os.Stdin)
	scanner.Buffer(make([]uint8, 0, 8192), maxByte)
	return scanner
}
func makeWordScanner() *bufio.Scanner {
	scanner := makeScanner(8192)
	scanner.Split(bufio.ScanWords)
	return scanner
}
func eGetLine(r *bufio.Scanner) string {
	if r.Scan() {
		return r.Text()
	}
	err := r.Err()
	if err != nil {
		log.Fatal(err)
	}
	// EOF
	return ""
}
func eGetInt(r *bufio.Scanner) int {
	line := eGetLine(r)
	return eAtoi(line)
}
func eGetFields(r *bufio.Scanner) []string {
	line := eGetLine(r)
	return strings.Fields(line)
}
func eGetInts(r *bufio.Scanner) []int {
	fields := eGetFields(r)
	ints := make([]int, len(fields))
	for i := 0; i < len(ints); i++ {
		ints[i] = eAtoi(fields[i])
	}
	return ints
}
func eGetChars(r *bufio.Scanner) []string {
	line := eGetLine(r)
	return strings.Split(line, "")
}
func eAtoi(s string) int {
	n, err := strconv.Atoi(s)
	if err != nil {
		log.Fatal(err)
	}
	return n
}

type ints []int

func (s ints) String() string {
	var buf bytes.Buffer
	buf.WriteString("[")
	sep := ""
	for _, v := range s {
		buf.WriteString(fmt.Sprintf("%s%d", sep, v))
		sep = ", "
	}
	buf.WriteString("]")
	return buf.String()
}

func reverse(a ints) ints {
	r := make(ints, len(a))
	for i := 0; i < len(a); i++ {
		r[i] = a[len(a)-1-i]
	}
	return r
}
func max(a ints) (int, bool) {
	if len(a) == 0 {
		return 0, false
	}
	m := a[0]
	for _, e := range a {
		if e > m {
			m = e
		}
	}
	return m, true
}

// func min(a []int) int {
// 	m := a[0]
// 	for _, v := range a {
// 		if v < m {
// 			m = v
// 		}
// 	}
// 	return m
// }

func sum(a ints) int {
	if len(a) == 0 {
		return 0
	}
	sum := 0
	for _, e := range a {
		sum += e
	}
	return sum
}
func find(n int, a ints) int {
	for i, v := range a {
		if n == v {
			return i
		}
	}
	return -1
}

C++: #include <bits/stdc++.h>
#ifdef _DEBUG
#include "debug.hpp"
#else
#define debug(...)
#endif
#define REP(i, m, n) for(int (i) = (m); (i) < (n); ++i)
#define rep(i, n) REP(i, 0, n)
using namespace std;
typedef long long ll;
typedef pair<ll, ll> P;
const int INF = 1e9 + 7;
const ll LINF = 1LL << 60;
template<class T, class U> inline bool chmax(T &a, const U &b) { if(a < b) { a = b; return true; } return false; }
template<class T, class U> inline bool chmin(T &a, const U &b) { if(a > b) { a = b; return true; } return false; }

ll dp[110][110];

int main() {
  cin.tie(0); ios::sync_with_stdio(false);
  int n;
  cin >> n;
  vector<int> rw(n), cl(n);
  rep(i,n) cin >> rw[i] >> cl[i];
  rep(i,110) rep(j,110) dp[i][j] = LINF;
  rep(i,110) dp[i][i] = 0;
  REP(i,1,n+1) rep(l,n) {
    int r = l+i;
    if(r >= n) continue;
    REP(j,l,r) {
      chmin(dp[l][r], dp[l][j]+dp[j+1][r]+rw[l]*cl[j]*cl[r]);
    }
  }
  cout << dp[0][n-1] << '\n';
  return 0;
}

C++: #include "stdafx.h"
#include <iostream>
#include <algorithm>
using namespace std;



static const int N = 100;

int main()
{
	int n, p[N + 1], m[N + 1][N + 1];
	cin >> n;
	for (int i = 1; i <= n; i++)
	{
		cin >> p[i - 1] >> p[i];
	}

	for (int i = 1; i <= n; i++) m[i][i] = 0;

	for (int l = 2; l <= n; l++)
	{
		for (int i = 1; i <= n - l + 1; i++)
		{
			int j = i + l - 1;
			m[i][j] = (1 << 21);
			for (int k = i; k <= j - 1; k++)
			{
				m[i][j] = min(m[i][j], m[i][k] + m[k + 1][j] + p[i - 1] * p[k] * p[j]);
			}
		}
	}

	cout << m[1][n] << endl;

    return 0;
}

C++: //全くわからんので解き方を見てみる
//行列dpを作って、dp[i][j]はi~jのかけ算をした際の最小の回数
//これを順に計算すれば確かに最小のものは出そう

#include<iostream>
#include<vector>
#include<utility>
#include<algorithm>

using namespace std;

int main(){
  int INF=1000000000;
  int n;cin >> n;
  vector< vector<int> > dp(n,vector<int>(n,INF));
  //vector< vector< pair<int,int> > > x(n,vector< pair<int,int> >(n,make_pair(0,0)));
  vector< pair<int,int> > m(n);
  for(int i=0;i<n;i++){
    int r,c;cin >> r >> c;
    m[i]=make_pair(r,c);
  }

  for(int i=0;i<n;i++){dp[i][i]=0;}

  for(int l=0;l<n;l++){//長さのループ
    for(int i=0;i<n-l;i++){//行のループ
      if(l==0){dp[i][i+l]=0;}
      for(int j=i;j<i+l;j++){//更新のループ(d[i][i+l])
        dp[i][i+l]=min({dp[i][i+l],dp[i][j]+dp[j+1][i+l]+m[i].first*m[j].second*m[i+l].second});
      }
    }

  }
  /*
  for(int i=0;i<n;i++){
    for(int j=0;j<n;j++){
      cout << dp[i][j] << " ";
    }
    cout << endl;
  }
  */
  cout<< dp[0][n-1] << endl;

}

C++: #include <bits/stdc++.h>
typedef long long ll;
using namespace std;
ll MOD = 1000000007;

#define vec                vector<int>
#define vecll              vector<ll>
#define vecd               vector<double>
#define vecst              vector<string>
#define vecb               vector<bool>
#define vec2(var, n, m)    vector<vector<int>>  var(n, vector<int>(m, 0))
#define vecb2(var, n, m)   vector<vector<bool>> var(n, vector<bool>(m, false))
#define vecll2(var, n, m)  vector<vector<ll>>   var(n, vector<ll>(m, INF))

#define rep(i,n)         for(ll i=(ll)0; i<(ll)n; i++)
#define REP(i,m,n)       for(ll i=(ll)m; i<(ll)n; i++)
#define arr(var, n)      vec var(n); rep(i,n){cin >> var[i];}
#define arrll(var, n)    vecll var(n); rep(i,n){cin >> var[i];}
#define arrst(var, n)    vecst var(n); rep(i,n){cin >> var[i];}
#define all(var)         (var).begin(), (var).end()
#define sortall(var)     sort(all(var))
#define uniqueall(v)     v.erase(unique(v.begin(), v.end()), v.end());
#define f_sum(var)       accumulate(all(var), 0)
#define f_sumll(var)     accumulate(all(var), 0LL)
#define chmin(v1, v2)    v1 = min(v1, v2)
#define chmax(v1, v2)    v1 = max(v1, v2)
#define pb(var)          push_back(var)
#define prt(var)         cout << (var) << "\n"
#define prtd(n, var)     cout << fixed << setprecision(n) << (var) << "\n"
#define prtfill(n, var)  cout << setw(n) << setfill('0') << (var);
#define prt2(v1, v2)     cout << (v1) << " " << (v2) << "\n"
#define prt3(v1, v2, v3) cout << (v1) << " " << (v2) << " " << (v3) << "\n"
#define prtall(v)        rep(i,v.size()){cout<<v[i]<<(i!=v.size()-1?" ":"\n");}
void prtok(bool ok){prt(ok ? "YES" : "NO");}
//----------------------------------------------------------------

int main(void) {
  int n;
  cin >> n;
  vecll r(n), c(n);
  rep(i,n){
    cin >> r[i] >> c[i];
  }

  ll INF = 1e18;
  vecll2(dp, n, n);

  rep(i,n){
    dp[i][i]=0;
  }

  REP(num,2,n+1){
    rep(i,n-num+1){
      REP(k,i,i+num-1){
        ll tmp = dp[i][k] + dp[k+1][i+num-1] + r[i]*c[k]*c[i+num-1];
        chmin(dp[i][i+num-1], tmp);
      }
    }
  }

  prt(dp[0][n-1]);
}