Go: package main

/*
連鎖行列積
*/

import (
	"bufio"
	"bytes"
	"fmt"
	"log"
	"math"
	"os"
	"strconv"
	"strings"
)

func min(a, b int) int {
	if a < b {
		return a
	}
	return b
}

type mem *[][]int

func main() {
	scanner := makeScanner(1024)
	n := eGetInt(scanner)
	p := make([]int, n+1)
	for i := 0; i < n; i++ {
		rowcol := eGetInts(scanner)
		p[i] = rowcol[0]
		p[i+1] = rowcol[1]
	}
	m := make([][]int, n)
	for i := 0; i < n; i++ {
		m[i] = make([]int, n)
	}
	// 初期値の格納
	for i := 0; i < n; i++ {
		for j := i; j < n; j++ {
			if i == j {
				m[i][j] = 0 //  同じ行列へのコストは当然0
			} else {
				m[i][j] = math.MaxInt64
			}
		}
	}

	// num : 行列の数. num == 1の場合は初期値0を格納ずみ
	for num := 2; num <= n; num++ {
		// s : スタート行列番号
		for s := 0; s+num <= n; s++ {
			// t : 終了行列番号
			t := s + num - 1
			// k : 仕切
			for k := s; k < t; k++ {
				m[s][t] = min(m[s][t], m[s][k]+m[k+1][t]+p[s]*p[k+1]*p[t+1])
			}
		}
	}
	fmt.Println(m[0][n-1])
}

////////////////////////////////////////////////////////////////////////////////
// ライブラリ
////////////////////////////////////////////////////////////////////////////////
func makeScanner(maxByte int) *bufio.Scanner {
	scanner := bufio.NewScanner(os.Stdin)
	scanner.Buffer(make([]uint8, 0, 8192), maxByte)
	return scanner
}
func makeWordScanner() *bufio.Scanner {
	scanner := makeScanner(8192)
	scanner.Split(bufio.ScanWords)
	return scanner
}
func eGetLine(r *bufio.Scanner) string {
	if r.Scan() {
		return r.Text()
	}
	err := r.Err()
	if err != nil {
		log.Fatal(err)
	}
	// EOF
	return ""
}
func eGetInt(r *bufio.Scanner) int {
	line := eGetLine(r)
	return eAtoi(line)
}
func eGetFields(r *bufio.Scanner) []string {
	line := eGetLine(r)
	return strings.Fields(line)
}
func eGetInts(r *bufio.Scanner) []int {
	fields := eGetFields(r)
	ints := make([]int, len(fields))
	for i := 0; i < len(ints); i++ {
		ints[i] = eAtoi(fields[i])
	}
	return ints
}
func eGetChars(r *bufio.Scanner) []string {
	line := eGetLine(r)
	return strings.Split(line, "")
}
func eAtoi(s string) int {
	n, err := strconv.Atoi(s)
	if err != nil {
		log.Fatal(err)
	}
	return n
}

type ints []int

func (s ints) String() string {
	var buf bytes.Buffer
	buf.WriteString("[")
	sep := ""
	for _, v := range s {
		buf.WriteString(fmt.Sprintf("%s%d", sep, v))
		sep = ", "
	}
	buf.WriteString("]")
	return buf.String()
}

func reverse(a ints) ints {
	r := make(ints, len(a))
	for i := 0; i < len(a); i++ {
		r[i] = a[len(a)-1-i]
	}
	return r
}
func max(a ints) (int, bool) {
	if len(a) == 0 {
		return 0, false
	}
	m := a[0]
	for _, e := range a {
		if e > m {
			m = e
		}
	}
	return m, true
}

// func min(a []int) int {
// 	m := a[0]
// 	for _, v := range a {
// 		if v < m {
// 			m = v
// 		}
// 	}
// 	return m
// }

func sum(a ints) int {
	if len(a) == 0 {
		return 0
	}
	sum := 0
	for _, e := range a {
		sum += e
	}
	return sum
}
func find(n int, a ints) int {
	for i, v := range a {
		if n == v {
			return i
		}
	}
	return -1
}

C++: #include<iostream>
#include<algorithm>
using namespace std;

static const int N = 200;

int main(){
    int n, p[N+1],m[N+1][N+1];
    cin >> n;
    for(int i=1; i<=n;i++){
        cin >> p[i-1] >> p[i];
    }

    for(int i=1;i<=n;i++)m[i][i] = 0;
    
    for(int l = 2;l<=n;l++){
        for(int i=1;i<=n;i++){
            int j = i+l-1;
            m[i][j] = (1<<21);
            for(int k=i;k<=j-1;k++){
                m[i][j] = min(m[i][j],m[i][k]+m[k+1][j]+p[i-1]*p[k]*p[j]);
            }
         }
    }
    cout << m[1][n] << endl;

    return 0;
}

C++: #include <bits/stdc++.h>
using namespace std;
#define INF 1e8;

int matrixChainMultiplication(int *p, int n) {
  int m[n+1][n+1];
  for (int i = 0; i <= n; i++) m[i][0] = 0;
  for (int j = 0; j <= n; j++) m[0][j] = 0;
  for (int i = 1; i <= n; i++) m[i][i] = 0;

  for (int l = 2; l <= n; l++) {
    //対象とする行列の数
    for (int i = 1; i <= n-l+1; i++) {
      //左端の行列
      int j = i + l - 1;
      //右端の行列
      m[i][j] = INF;
      for (int k = i; k <= j-1; k++) {
        m[i][j] = min(m[i][j], m[i][k] + m[k+1][j] + p[i-1]*p[k]*p[j]);
      }
    }
  }
  //上のループで、DPテーブル対角線上のゼロに近接するマスが順に埋まっていく
  //最終的に右端のm[1][n]がM1M2...Mnを計算する際の最小計算回数になる

  return m[1][n];
}

int main() {
  int n;
  cin >> n;
  int p[n+1];
  for (int i = 1; i <= n; i++) cin >> p[i-1] >> p[i];
  cout << matrixChainMultiplication(p, n) << endl;
  return 0;
}

C++: #include <bits/stdc++.h>
using namespace std;

static const int N=100;

int main(){
  int i,l,n,p[N+1],m[N+1][N+1];
  cin >> n;
  for(i=1;i<=n;i++) cin >> p[i-1] >> p[i];

  for(i=1;i<=n;i++) m[i][i]=0;
  for(l=2;l<=n;l++){
    for(i=1;i<=n-1;i++){
      int j=i+l-1;
      m[i][j]=(1 << 21);
      for(int k=i;k<=j-1;k++){
	m[i][j]=min(m[i][j], m[i][k]+m[k+1][j]+p[i-1]*p[k]*p[j]);
      }
    }
  }
  cout << m[1][n] << endl;
  
  return 0;
}

C++: #include <iostream>
#include <vector>
#include <array>
#include <string>

const int size = 105;
const int NIL = -1;
int dp[size][size];
int ps[size];

int min_cost(int i, int j)
{
  if (dp[i][j] != NIL)
    return dp[i][j];

  int k=i;
  int min = min_cost(i,k) + min_cost(k+1,j) + ps[i-1]*ps[k]*ps[j];
  for (k=i+1; k<=j-1; ++k)
    {
      int tmp = min_cost(i,k) + min_cost(k+1,j) + ps[i-1]*ps[k]*ps[j];
      if (tmp < min) min = tmp;
    }
  dp[i][j] = min;
  return min;
}


int main()
{
  int n;
  std::cin >> n;

  for (int i=0; i<n; ++i)
    {
      std::cin >> ps[i];
      std::cin >> ps[i+1];
    }

  for (int i=0; i<size; ++i)
    for (int j=0; j<size; ++j)
      dp[i][j] = NIL;

  for (int i=1; i<=n; ++i)
    {
      dp[i][i] = 0;
    }

  std::cout << min_cost(1,n) << std::endl;
}

C++: #include<bits/stdc++.h>
#define ll long long int
#define FOR(i,a,b) for(ll i=(ll)(a);i<(ll)(b);i++)
#define REP(i,n) FOR(i,0,n)
#define REP1(i,n) FOR(i,1,n)
using namespace std;

static const int N = 100;

int main() {
  int n, p[N + 1], m[N + 1][N + 1];
  cin >> n;
  REP1(i, n + 1) {
    cin >> p[i - 1] >> p[i];
  }

  REP1(i, n + 1) m[i][i] = 0;
  FOR(l, 2, n + 1) {
    REP1(i, n - l + 2) {
      int j = i + l - 1;
      m[i][j] = (1 << 21);
      FOR(k, i, j) {
        m[i][j] = min(m[i][j], m[i][k] + m[k + 1][j] + p[i - 1] * p[k] * p[j]);
      }
    }
  }

  cout << m[1][n] << endl;

  return 0;
}

C++: #include <iostream>
#include <algorithm>
using namespace std;

static const int N=100;

int main(){
    int n,p[N+1],m[N+1][N+1];
    cin>>n;
    for(int i=1;i<=n;i++)
        cin>>p[i-1]>>p[i];
    
    for(int i=1;i<=n;i++)
        m[i][i]=0;
    
    for(int l=2;l<=n;l++)
        for(int i=1;i<=n-l+1;i++){
            int j=i+l-1;
            m[i][j]=(1<<21);
            for(int k=i;k<=j-1;k++)
                m[i][j]=min(m[i][j],m[i][k]+m[k+1][j]+p[i-1]*p[k]*p[j]);
        }

    cout<<m[1][n]<<endl;
}

C++: #include<bits/stdc++.h>

using namespace std;

typedef long long ll;
#define endl '\n'

int n;
ll r[111],c[111],d[111];
ll dp[111][111];
const ll oo = 1000000000000000LL;

int main()
{
	ios_base::sync_with_stdio(0);
	cin.tie(0);

	cin >> n;
	for(int i = 1; i <= n; i++)
		cin >> r[i] >> c[i];
	d[0] = r[1];
	for(int i = 1; i <= n; i++)
		d[i] = c[i];
	for(int size = 1; size <= n;size++){
		for(int i = 1; i <= n - size; i++){
			int j = i + size;
			dp[i][j] = oo;
			for(int k = i; k <= j - 1;k++){
				ll cost = dp[i][k] + dp[k + 1][j] + d[i - 1]*d[k]*d[j];
				dp[i][j] = min(dp[i][j],cost);
			}
		}
	}
	
	cout << dp[1][n] << endl;

	return 0;
}