Go: package main

import (
	"bufio"
	"fmt"
	"math"
	"os"
	"strconv"
)

type Matrix struct {
	r int // num of row
	c int // num of column
}

type Range struct {
	start int // index, inclusive
	end   int // index, inclusive
}

func calcMultiplication(x, y Matrix) (Matrix, int) {
	if x.c != y.r {
		panic("cannnot calculate")
	}
	return Matrix{x.r, y.c}, x.r * y.c * x.c
}

func calcMinMatrixChainMultiplication(matrices []Matrix, r Range, memo map[Range]int) (Matrix, int) {
	if v, ok := memo[r]; ok {
		return Matrix{matrices[0].r, matrices[len(matrices)-1].c}, v
	}
	if len(matrices) == 0 {
		panic("must not be empty")
	} else if len(matrices) == 1 {
		return matrices[0], 0
	} else if len(matrices) == 2 {
		return calcMultiplication(matrices[0], matrices[1])
	}

	var minCount int = math.MaxInt32

	for i := 0; i < len(matrices)-1; i++ {
		formerMatrices := matrices[:i+1]
		latterMatrices := matrices[i+1:]
		matF, countF := calcMinMatrixChainMultiplication(formerMatrices, Range{0, i}, memo)
		matL, countL := calcMinMatrixChainMultiplication(latterMatrices, Range{i + 1, len(matrices) - 1}, memo)
		_, countFL := calcMultiplication(matF, matL)
		count := countF + countL + countFL
		if count < minCount {
			minCount = count
		}
	}
	return Matrix{matrices[0].r, matrices[len(matrices)-1].c}, minCount
}

func main() {
	sc := bufio.NewScanner(os.Stdin)
	sc.Split(bufio.ScanWords)
	n, _ := nextInt(sc)
	matrices := make([]Matrix, n)
	for i := 0; i < n; i++ {
		r, _ := nextInt(sc)
		c, _ := nextInt(sc)
		matrices[i] = Matrix{r, c}
	}
	memo := make(map[Range]int)
	_, resultCount := calcMinMatrixChainMultiplication(matrices, Range{0, len(matrices) - 1}, memo)
	fmt.Println(resultCount)
}

func nextInt(sc *bufio.Scanner) (int, error) {
	sc.Scan()
	return strconv.Atoi(sc.Text())
}

C++: #include <iostream>
#include <vector>

using namespace std;

struct matrix {
  int r;
  int c;
};

int main() {
  vector<matrix> mat;
  int n;
  cin >> n;
  for (int i = 0; i < n; i++) {
    int tmp1,tmp2;
    cin >> tmp1 >> tmp2;
    matrix m = {tmp1, tmp2};
    mat.push_back(m);
  }
  
  int** memo = new int*[n];
  for (int s = 0; s < n; s++) {
    memo[s] = new int[n];
  }

  for (int l = 1; l < n; l++) {
    for (int s = 0; s < n; s++) {
      if (s + l >= n) {
        break;
      }
      
      int minval = 1000000000;
      int sum = 0;
      for (int i = 0; i < l; i++) {
        sum = memo[s][s+i] + memo[s+i+1][s+l];
        matrix m1 = mat[s];
        matrix m2 = mat[s+i];
        matrix m3 = mat[s+l];

        sum += m1.r * m2.c * m3.c;

        minval = min(minval, sum);
      }
      memo[s][s+l] = minval;
    }
  }

  cout << memo[0][n-1] << endl;
  return 0;
}

C++: #include<iostream>
#include<algorithm>
using namespace std;
#define INF (99999999)
int main(){

  //-------データの入力------------
  int n;
  cin >> n;
  int row[n];
  int column[n];
  for(int i = 0; i < n; i++){
    cin >> row[i] >> column[i];
  }
  //-----------------------------

  //[始点][終点（始点+幅）]の最小コスト
  int dp[n][n];

  //INFで初期化
  for(int i = 0; i < n; i++){
    for(int j = 0; j < n; j++){
      dp[i][j] = INF;
    }
  }

  //幅0はコスト0
  //dp[i][i+0] = 0
  for(int i = 0; i < n; i++){
    dp[i][i] = 0;
  }

  //幅:j = 0 から探索開始
  for(int j = 0; j < n; j++){
    //始点: i
    for(int i = 0; i < n - j; i++){
      //仕切りを置く位置: k
      // (M_0, M_1, M_2, M_3) | (M_4, M_5)
      for(int k = i + 1; k <= i + j; k++){
        //現在のdp[i][i+j]より小さければ更新
        dp[i][i+j] = min(dp[i][i+j], dp[i][k-1] + dp[k][i+j] + row[i] * column[k-1] * column[i+j]);
      }
    }
  }
  /*
  for(int i = 0; i < n; i++){
    for(int j = 0; j < n; j++){
      cout << dp[i][j] << " ";
    }
    cout << endl;
  }
  */
  //始点０、幅n-1の最小コスト=> n個の行列の連鎖の計算に最低限必要な乗算の回数　を出力
  cout << dp[0][n-1] << endl;
  return 0;
}

C++: // 連鎖行列積 問題
#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<stack>
#include<algorithm>
#include<iostream>
#include<cmath>
#include<vector>

using namespace std;

#define MAX_N 100
#define ELE_NUM 2
// 無効な値の定義
const int INV = -1;

const int colNo = 0;
const int rowNo = 1;
const int IntMAX = 	2147483647;

int ChainedMatrixtMultiplication(int n, int m, int matrixData[][ELE_NUM]);

int main(void)
{

    int n, count;
    int matrix_data[MAX_N + 1][ELE_NUM];

    cin >> n;

    for(int i = 1; i <= n; i++)
    {
        // 行
        cin >> matrix_data[i][colNo];
        // 列
        cin >> matrix_data[i][rowNo];
    }

    count = ChainedMatrixtMultiplication(n, ELE_NUM, matrix_data);
    printf("%d\n", count);

    return 0;
}

// 連鎖行列積の最小の乗算回数を演算する関数
// n : 積を求める行列の数
// m : 行列の情報 : 0 - 行の情報, 1 - 列の情報
// matrixData[][] : 各行列の行、列情報を保持する配列
int ChainedMatrixtMultiplication(int n, int m, int matrixData[][ELE_NUM])
{

    // 第1要素 : 演算開始のNo., 第2要素 : 演算終了のNo.
    int dp[MAX_N + 1][MAX_N + 1];
    int calcResult = 0;

    // 配列の初期化
    for(int i = 0; i <= n; i++)
    {
        for(int j = 0; j <= n; j++)
        {
            // 無効値の代入
            dp[i][j] = INV;

            if( i == j )
            {
                // 同じ要素同士の積は演算することが不可能
                dp[i][j] = 0;
            }
        }
    }

    // 行列の演算回数の計算
    // i : 演算対象の先頭の要素No.
    // j : 演算対象の最後の要素No.
    // k : i 〜 jまでの範囲を移動する変数
    // l : 演算対象とする行列の数 ( 2 〜 n 個まで )
    for(int l = 2; l <= n; l++)
    {
        for(int i = 1; i <= n - l + 1; i++)
        {
            int j = i + l - 1;
            // 最小値を求めるために, 仮に最大値を入れておく
            dp[i][j] = IntMAX;

            for(int k = i; k <= j - 1; k++)
            {
                // 要素が2つの時は, 式の後半の部分のみで演算する
                calcResult = dp[i][k] + dp[k + 1][j]
                            + ( matrixData[i][colNo] * matrixData[k][rowNo] * matrixData[j][rowNo]);

                dp[i][j] = min( dp[i][j], calcResult );
            }
        }
    }

    return dp[1][n];
}

C++: #include <iostream>
#include <algorithm>
#include <climits>
#include <vector>
#include <stack>
#include <queue>
#include <set>
#include <map>

using namespace std;

int n;
vector<int> d;
int dp[102][102];

void solve() {
    for (int i = 0; i < n; ++i) {
        dp[i][i] = 0;
    }
    for (int span = 2; span <= n; ++span) {
        for (int i = 0; i <= n - span; ++i) {
            int j = i + span - 1;
            dp[i][j] = INT_MAX;
            for (int k = i; k <j ; ++k) {
                dp[i][j] = min(dp[i][j], d[i] * d[j+1] * d[k+1] + dp[i][k] + dp[k+1][j]);
            }
        }
    }
}

int main() {
    cin >> n;
    d.resize(n + 1);
    int r, c;
    for (int i = 0; i < n; ++i) {
        cin >> r >> c;
        d[i] = r;
    }
    d[n] = c;
    solve();
    cout << dp[0][n-1] << endl;

    return 0;
}

C++: #include <bits/stdc++.h>
#define rep(i, n) for (int i = 0; i < (n); ++i)
using namespace std;
using ll = long long;
using P = pair<int, int>;

int dp[101][101];

int main() {
  int n;
  cin >> n;
  vector<int> p(n + 1);
  rep(i, n) cin >> p[i] >> p[i + 1];

  for (int l = 2; l <= n; ++l) {
    for (int i = 1; i <= n - l + 1; ++i) {
      int j = i + l - 1;
      dp[i][j] = __INT_MAX__;
      for (int k = i; k <= j - 1; ++k) {
        dp[i][j] =
            min(dp[i][j], dp[i][k] + dp[k + 1][j] + p[i - 1] * p[k] * p[j]);
      }
    }
  }
  cout << dp[1][n] << endl;

  return 0;
}