Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

//util
var sc = bufio.NewScanner(os.Stdin)

func nextStr() string {
	sc.Scan()
	return sc.Text()
}

func nextInt() int {
	sc.Scan()
	i, e := strconv.Atoi(sc.Text())
	if e != nil {
		panic(e)
	}
	return i
}

func printList(list []int) {
	buf := bufio.NewWriter(os.Stdout)
	for _, v := range list {
		buf.Write([]byte(fmt.Sprintf(" %d", v)))
	}
	buf.Write([]byte("\n"))
	buf.Flush()
}

//solve
//単純な場合
func matrixChainMultiplication() {
	//行列が1つだけのとき
	for i := 1; i <= n; i++ {
		m[i][i] = 0
	}
	for l := 2; l <= n; l++ {
		for i := 1; i <= n-l+1; i++ {
			j := i + l - 1
			m[i][j] = 1 << 21
			//kまでで区切る
			for k := i; k <= j-1; k++ {
				m[i][j] = min(m[i][j], m[i][k]+m[k+1][j]+p[i-1]*p[k]*p[j])
			}
		}
	}
}

func max(a, b int) int {
	if a > b {
		return a
	} else {
		return b
	}
}

func min(a, b int) int {
	if a > b {
		return b
	} else {
		return a
	}
}

const MAX = 100

var n int
var p [MAX + 1]int

//m[i][j]: Mi * Mi+1 * ... * Mjを計算するときに必要なスカラー乗算の最小回数
var m [MAX + 1][MAX + 1]int

func main() {
	sc.Split(bufio.ScanWords)
	n = nextInt()
	for i := 1; i <= n; i++ {

		p[i-1] = nextInt() //行数
		p[i] = nextInt()   //列数
	}

	matrixChainMultiplication()
	fmt.Println(m[1][n])
}

Python: 
from functools import lru_cache


@lru_cache(maxsize=None)
def multi(ms):
    """Matix multiplication. returns minimum number of scalar
    multiplications to compute all matrix multiplications.

    >>> multi(((30, 35), (35, 15), (15, 5), (5, 10), (10, 20), (20, 25)))
    15125
    """
    size = len(ms)
    if size <= 1:
        return 0
    elif size == 2:
        r1, c1 = ms[0]
        r2, c2 = ms[1]
        return c1 * r1 * c2

    costs = []
    for i in range(size-1):
        cost = ms[i][1] * ms[0][0] * ms[-1][1]
        costs.append(multi(ms[:i+1]) + multi(ms[i+1:]) + cost)

    return min(costs)


def run():
    n = int(input())
    ms = []

    for i in range(n):
        m = tuple([int(x) for x in input().split()])
        ms.append(m)

    print(multi(tuple(ms)))


if __name__ == '__main__':
    run()

Python: import sys
n=int(input())+1
e=list(map(lambda x:x.split(),sys.stdin))
p=[int(e[0][0])]+list(int(x[1])for x in e)
m=[[0]*n for _ in[0]*n]
for l in range(2,n):
 for i in range(1,n-l+1):
  j=i+l-1;m[i][j]=1e6
  for k in range(i,j):m[i][j]=min(m[i][j],m[i][k]+m[k+1][j]+p[i-1]*p[k]*p[j])
print(m[1][n-1])

Python: import sys
INF = float("inf")
n = int(input())
A = [0]
for i, a in enumerate(sys.stdin):
    a = list(map(int, a.split()))
    if i == 0:
        A.extend(a)
    else:
        A.append(a[1])
C = [[INF] * (n + 1) for _ in range(n + 1)]
for i in range(n + 1):
    C[i][i] = 0
for j in range(1, n):
    for i in range(1, n - j + 1):
        for k in range(i + 1, i + j + 1):
            cost = C[i][k - 1] + C[k][i + j] + A[i] * A[k] * A[i + j + 1]
            if cost < C[i][i + j]:
                C[i][i + j] = cost
print(C[1][n])

Python: # Solution to this problem using memoization
# https://onlinejudge.u-aizu.ac.jp/problems/ALDS1_10_B

import math

# Optimal cost of multiplying A_1 A_2 ... A_j
def cost(i, j):
    if (i, j) in cost_dict.keys():
        return cost_dict[(i, j)]
    elif i == j:
        cost_dict[(i, j)] = 0
    else:
        mincost = math.inf
        for k in range(i, j):
            estimate = cost(i, k) + cost(k + 1, j) + dims[i - 1] * dims[k] * dims[j]
            mincost = min(estimate, mincost)
        cost_dict[(i, j)] = mincost
    return cost_dict[(i, j)]


if __name__ == '__main__':
    # Number of matrices
    n = int(input())
    # A dictionary to store costs
    cost_dict = dict()
    # Take input dimensions
    dims = []
    for _ in range(n - 1):
        first = int(input().split()[0])
        dims.append(first)
    dims.extend(list(map(int, input().split())))
    # Calculate the optimal cost
    print(cost(1, n))

Python: def s():
 n=int(input())+1
 e=[input().split()for _  in[0]*~-n]
 p=[int(e[0][0])]+list(int(x[1])for x in e)
 m=[[0]*n for _ in[0]*n]
 for i in range(n):
  for r in range(n-i-1):
   c=r+i+1
   for j in range(r+1,c):
    x=m[r][j]+m[j][c]+p[r]*p[j]*p[c]
    if 1>m[r][c]or m[r][c]>x:m[r][c]=x
 print(m[r][c])
if'__main__'==__name__:s()

Python: n = int(input())
p = list(range(n+2))

for i in range(1,n+1):
    p[i], p[n+1] = map(int, input().split())

# table[i][j] : M_i??????M_j??????????????????????°?????????°
table = [[0] * (n+1) for i in range(n+1)]

# ??£????????£???2????????????????????????
for i in range(1,n):  # 1<=i,i+1<=n
    table[i][i+1] = p[i]*p[i+1]*p[i+2]


for k in range(3, n+1):    # ?????????k???????????????????????????3<=k<=n
    for i in range(1,n+2-k): # M_i?????????1<=i<=n-k+1
        j = i + k - 1      # M_j?????§???k??????

        table[i][j] = float('inf')

        for x in range(i, j+1): # M_i~M_x??¨M_(x+1)~M_j??§????????????(i<=x,x+1<=j<=n)
            # print(i, x, j)
            cost = table[i][x] + table[x+1][j] + p[i]*p[x+1]*p[j+1]
            table[i][j] = min(table[i][j], cost)
            

print(table[1][n])

Python: n = int(input())
c = [0] * (n+1)

c[0], c[1] = map(int, input().split())

for i in range(2, n+1):
    c[i] = int(input().split()[1])
 
array = [[10**7]*(n+1) for i in range(n+1)]
 
for i in range(1, n+1):
    array[i][i] = 0
 
for l in range(2, n+1):
    for i in range(1, n-l+2):
        j = i+l-1
        for k in range(i, j):
            array[i][j] = min(array[i][j], array[i][k] + array[k+1][j] + c[i-1]*c[k]*c[j])
 
print(array[1][n])

Python: INF = float("inf")
MAX = 101
n = int(input())
z = []
m = [[0] * MAX for _ in range(MAX)]
for i in range(1, n + 1):
    a, b = map(int, input().split())
    z.append(a)
z.append(b)
for l in range(2, n + 1):
    for i in range(1, n - l + 2):
        j = i + l - 1
        m[i][j] = INF
        for k in range(i, j):
            m[i][j] = min(m[i][j], m[i][k] + m[k + 1][j] + z[i - 1] * z[k] * z[j])
print(m[1][n])

Python: import sys
from functools import lru_cache
input = sys.stdin.readline
sys.setrecursionlimit(2 * 10**6)


def inpl():
    return list(map(int, input().split()))


def main():
    @lru_cache(maxsize=None)
    def recur(i, j):
        # print(i, j)
        if i == j:
            return 0
        for k in range(i, j):
            c = recur(i, k) + recur(k + 1, j) + P[i] * P[k + 1] * P[j + 1]
            if c < cost[i][j]:
                cost[i][j] = c
        return cost[i][j]

    N = int(input())
    RC = [inpl() for _ in range(N)]
    cost = [[float('inf')] * (N + 1) for a in range(N + 1)]
    P = [0] * (N + 1)
    for i, rc in enumerate(RC):
        P[i] = rc[0]
    P[N] = RC[N - 1][1]

    print(recur(0, N - 1))


if __name__ == '__main__':
    main()

Python: import sys
import itertools

n = int(sys.stdin.readline())
MM = [list(map(int, sys.stdin.readline().split())) for _ in range(n)]

amin=1000000000000
for t in itertools.permutations(range(n-1)):
    mm=[m[:] for m in MM]
    o = list(t)
    ans=0
    for _ in range(n-1):
        i = o.pop(0)
        ans += mm[i][0]*mm[i+1][1]*mm[i][1]

        mm[i][1] = mm[i+1][1]
        mm.pop(i+1)
        
        for j in range(len(o)):
            if o[j]>i: o[j] -=1

    if amin>ans: amin=ans


print(amin)

Python: N = int(input())
P = []
for i in range(N):
	ta,tb = map(int ,input().split())
	if i == N-1:
		P.append(ta)
		P.append(tb)
	else:
		P.append(ta)
inf = float('inf')
dp = [[inf] * N for _ in range(N)]
for i in range(N):
	if i == N-1:
		dp[i][i] = 0
	else:
		dp[i][i] = 0
		dp[i][i+1] = P[i]*P[i+1]*P[i+2]

for right in range(2,N):
	for i in range(N):
		j = i + right
		if j > N-1:
			break

		for k in range(i,j):
			dp[i][j] = min(dp[i][j], dp[i][k]+dp[k+1][j]+P[i]*P[k+1]*P[j+1])

		

print(dp[0][N-1])