Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

// I/O
type Scanner struct {
	sc *bufio.Scanner
}

func NewScanner() *Scanner {
	sc := bufio.NewScanner(os.Stdin)
	sc.Split(bufio.ScanWords)
	sc.Buffer(make([]byte, 1024), int(1e+9))
	return &Scanner{sc}
}

func (s *Scanner) nextStr() string {
	s.sc.Scan()
	return s.sc.Text()
}

func (s *Scanner) nextInt() int {
	i, e := strconv.Atoi(s.nextStr())
	if e != nil {
		panic(e)
	}
	return i
}

func (s *Scanner) nextFloat() float64 {
	f, e := strconv.ParseFloat(s.nextStr(), 64)
	if e != nil {
		panic(e)
	}
	return f
}

func (s *Scanner) nextRuneSlice() []rune {
	return []rune(s.nextStr())
}

func (s *Scanner) nextIntSlice(n int) []int {
	res := make([]int, n)
	for i := 0; i < n; i++ {
		res[i] = s.nextInt()
	}
	return res
}

func (s *Scanner) nextFloatSlice(n int) []float64 {
	res := make([]float64, n)
	for i := 0; i < n; i++ {
		res[i] = s.nextFloat()
	}
	return res
}

// Arithmetic
func max(nums ...int) int {
	m := nums[0]
	for _, i := range nums {
		if m < i {
			m = i
		}
	}
	return m
}

func min(nums ...int) int {
	m := nums[0]
	for _, i := range nums {
		if m > i {
			m = i
		}
	}
	return m
}

func abs(x int) int {
	if x > 0 {
		return x
	}
	return -x
}

func pow(x, y int) int {
	res := 1
	for i := 0; i < y; i++ {
		res *= x
	}
	return res
}

func ceil(a, b int) int {
	if a%b == 0 {
		return a / b
	} else {
		return a/b + 1
	}
}

// Sort
type RuneSlice []rune

func (a RuneSlice) Len() int           { return len(a) }
func (a RuneSlice) Less(i, j int) bool { return a[i] < a[j] }
func (a RuneSlice) Swap(i, j int)      { a[i], a[j] = a[j], a[i] }

// Main
func main() {
	sc := NewScanner()
	wtr := bufio.NewWriter(os.Stdout)
	Q := sc.nextInt()
	for q := 0; q < Q; q++ {
		X, Y := sc.nextStr(), sc.nextStr()
		xLen, yLen := len(X), len(Y)
		dp := make([][]int, xLen+1)
		for i := 0; i <= xLen; i++ {
			dp[i] = make([]int, yLen+1)
		}
		for x := 0; x <= xLen; x++ {
			for y := 0; y <= yLen; y++ {
				if x == 0 || y == 0 {
					dp[x][y] = 0
				} else if X[x-1] == Y[y-1] {
					dp[x][y] = dp[x-1][y-1] + 1
				} else {
					dp[x][y] = max(dp[x-1][y], dp[x][y-1])
				}
			}
		}
		fmt.Fprintln(wtr, dp[xLen][yLen])
	}

	wtr.Flush()
}

C++: #include <bits/stdc++.h>
using namespace std;
using ll=long long;
using vb=vector<bool>;
using vvb=vector<vb>;
using vd=vector<double>;
using vvd=vector<vd>;
using vi=vector<int>;
using vvi=vector<vi>;
using vl=vector<ll>;
using vvl=vector<vl>;
using pll=pair<ll,ll>;
using tll=tuple<ll,ll>;
using vs=vector<string>;
#define all(a) a.begin(),a.end()
#define rall(a) a.rbegin(),a.rend()
#define rep(i,n) range(i,0,n)
#define rrep(i,n) for(int i=(n)-1;i>=0;i--)
#define range(i,a,n) for(int i=(a);i<(n);i++)

#define LINF    	((ll)1ll<<60)
#define INF     	((int)1<<30)
#define EPS     	(1e-9)
#define MOD     	(1000000007ll)
#define fcout(a)	cout<<setprecision(a)<<fixed
#define fs 			first
#define sc			second
#define PI			3.1415926535897932384

int dx[]={1,0,-1,0,1,-1,-1,1},dy[]={0,1,0,-1,1,1,-1,-1};
template<class S,class T>ostream&operator<<(ostream&os,pair<S,T>p){os<<"["<<p.first<<", "<<p.second<<"]";return os;};
template<class S>auto&operator<<(ostream&os,vector<S>t){bool a=1; for(auto s:t){os<<(a?"":" ")<<s; a=0;} return os;}
void OUT(bool b){cout<<(b?"YES":"NO")<<endl;}
void Out(bool b){cout<<(b?"Yes":"No")<<endl;}
void out(bool b){cout<<(b?"yes":"no")<<endl;}
int popcnt(int x) { return __builtin_popcount(x); }
int popcnt(ll x) { return __builtin_popcountll(x); }
int clz(int x) { return 31 - __builtin_clz(x); }
int clz(ll x) { return 63 - __builtin_clzll(x); }
int ctz(int x) { return __builtin_ctz(x); }
int ctz(ll x) { return __builtin_ctzll(x); }

class compare {
public:
	bool operator()(tuple<ll, ll> a, tuple<ll, ll> b) {
		return (get<1>(a) > get<1>(b));
	}
};

void solve(){
	string a,b;
	cin>>a>>b;
	vvi dp(a.size()+1,vi(b.size()+1));
	rep(i,a.size()){
		rep(j,b.size()){
			if(a[i]==b[j])dp[i+1][j+1]=dp[i][j]+1;
			else dp[i+1][j+1]=max(dp[i+1][j],dp[i][j+1]);
		}
	}
	cout<<dp[a.size()][b.size()]<<endl;
}

int main(){
	cin.tie(0);
	ios::sync_with_stdio(false);
	int n;
	cin>>n;
	rep(i,n)solve();
}

C++: 

#include<iostream>
#include<cstdlib>

int main(){
  int n;
  std::string x,y;
  std::cin>>n;
  int a[1000][1000];
  int b[n];

  for(int i=0;i<n;i++){
    std::cin>>x;
    std::cin>>y;
    for(int j=0;j<1000;j++){
      for(int k=0;k<1000;k++){
	a[j][k]=0;
      }
    }
    for(int j=0;j<x.size();j++){
      for(int k=0;k<y.size();k++){
	if(x[j]==y[k]){
	  a[j][k]=a[j-1][k-1]+1;
	}else{
	  if(a[j-1][k]>a[j][k-1]){
	    a[j][k]=a[j-1][k];
	  }else{
	    a[j][k]=a[j][k-1];
	  }
	}
      }
    }
    b[i]=a[x.size()-1][y.size()-1];
  }

  for(int i=0;i<n;i++){
  std::cout<<b[i]<<"\n";
  }

  return 0;
}

C++: #include <bits/stdc++.h>
using namespace std;
#define int long long
#define rep(i, a, b) for (int i = (a); i < (int)(b); ++i)
#define rrep(i, a, b) for (int i = (int)(b) - 1; i >= (int)(a); --i)
#define all(c) c.begin(),c.end()
#define sz(x) ((int)x.size())
using pii = pair<int, int>;
using vvi = vector<vector<int>>;
using vi  = vector<int>;
constexpr int INF = 1001001001001001001LL;
/*
<NAME> 最長共通部分列 (Longest Common Subsequence)
<TRIGGER> LCS
<TAG> DP, etc
<*NOTE>
文字列の最長共通部分列を求める。$O(NM)$
<*CODE> */
int lcs(string a, string b) {
    int n = sz(a), m = sz(b);
    vvi dp(n + 1, vi(m + 1, 0));
    rep(i, 0, n) {
        rep(j, 0, m) {
            if (a[i] == b[j]) {
                dp[i + 1][j + 1] = dp[i][j] + 1;
            } else {
                dp[i + 1][j + 1] = max(dp[i][j + 1], dp[i + 1][j]);
            }
        }
    }
    return dp[n][m];
}

// hash : [59, 176, 206, 65, 188, 72, 103, 19]]

signed main() {
    int Q;
    cin >> Q;
    while (Q--) {
        string S, T;
        cin >> S >> T;
        cout << lcs(S, T) << endl;
    }
}

C++: #include<iostream>
#include<string>
#include<algorithm>
using namespace std;
#define MAX 1000
int dp[MAX + 1][MAX + 1];
int LCS(string STR1, string STR2)
{
	int length1 = STR1.size();
	int length2 = STR2.size();
	//???????????¨????????????????????????
	STR1 = ' ' + STR1;
	STR2 = ' ' + STR2;
	for (int i = 0; i < length1; i++)
	{
		for (int l = 0; l < length2; l++)dp[i][l] = 0;
	}
	for (int i = 1; i <= length1; i++)
	{
		for (int l = 1; l <= length2; l++)
		{
			if (STR1[i] == STR2[l])dp[i][l] =dp[i][l-1]+1;
			else
			{
				dp[i][l]=max(dp[i - 1][l], dp[i][l - 1]);
			}
		}
	}
	return dp[length1][length2];
}
int main()
{
	int q;
	cin >> q;
	for (int i = 0; i < q; i++)
	{
		string str1, str2;
		cin >> str1 >> str2;
		cout << LCS(str1, str2) << endl;
	}
	return 0;
}

C++: #include <iostream>
#include <stdio.h>
#include <string>
#include <cmath>

#define MAX_LENGTH 1000
#define NIL -1
using namespace std;
//think easy make easy

int q;//num of datasets
string X;
string Y;
char map[MAX_LENGTH+1][MAX_LENGTH+1];

int findMaxLength(int x,int y){//x:Xの終端.y:Yの終端(0オリジン)
	if(x < 0 || y < 0) return 0;
	if(map[x][y] == NIL){
		if(X.at(x) == Y.at(y)){
			return findMaxLength(x-1,y-1) +1;
		}else{
			return max(findMaxLength(x-1,y),findMaxLength(x,y-1));
		}
	}else return map[x][y];
}

int main(){
	
	scanf("%d",&q);

	for(int i=0;i<q;i++){
		cin >>X; cin >> Y;
		for(int i=0;i<X.size();i++){
			for(int j=0;j<Y.size();j++){
				map[i][j] = NIL;
			}
		}
	
		cout <<findMaxLength(X.size()-1,Y.size()-1) <<endl;
	}

	return 0;
}