Go: package main

import (
	"bufio"
	"fmt"
	"io"
	"os"
	"strconv"
)

const (
	initialBufSize = 100000
	maxBufSize     = 1000000
)

var sc *bufio.Scanner

func initScanner(r io.Reader) *bufio.Scanner {
	buf := make([]byte, initialBufSize)

	sc := bufio.NewScanner(r)
	sc.Buffer(buf, maxBufSize)
	sc.Split(bufio.ScanWords) // bufio.ScanLines
	return sc
}

func main() {
	sc = initScanner(os.Stdin)
	resolve()
}

func resolve() {
	n := scanInt(sc)
	results := []int{}
	for i := 0; i < n; i++ {
		results = append(results, resolveInstance())
	}
	for _, v := range results {
		fmt.Println(v)
	}
	return
}

func resolveInstance() int {
	x, y := scanString(sc), scanString(sc)
	lx, ly := len(x), len(y)
	dp := make([][]int, lx+1)
	dp[0] = make([]int, ly+1)
	for i := 1; i <= lx; i++ {
		dp[i] = make([]int, ly+1)
		dp[i][0] = dp[i-1][0]
		for j := 1; j <= ly; j++ {
			dp[i][j] = dp[i-1][j]
			if dp[i][j] < dp[i][j-1] {
				dp[i][j] = dp[i][j-1]
			}
			if x[i-1] == y[j-1] {
				cL := dp[i-1][j-1] + 1
				if dp[i][j] < cL {
					dp[i][j] = cL
				}
			}
		}
	}
	return dp[lx][ly]
}

const (
	remove = 0 + iota
	match
)

// snip-scan-funcs
func scanInt(sc *bufio.Scanner) int {
	sc.Scan()
	i, _ := strconv.Atoi(sc.Text())
	return int(i)
}
func scanString(sc *bufio.Scanner) string {
	sc.Scan()
	return sc.Text()
}

C++: #include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>

using namespace std;

int q;
char X[1000], Y[1000];
int dp[1001][1001];

int main(void) {

    scanf("%d", &q);

    for (int i = 0; i < q; ++i) {
        scanf("%s %s", X, Y);
        int xlen = strlen(X), ylen = strlen(Y);
        for (int x = 0; x < xlen; ++x) {
            for (int y = 0; y < ylen; ++y) {
                if (X[x] == Y[y]) {
                    dp[x + 1][y + 1] = dp[x][y] + 1;
                }
                else {
                    if (dp[x + 1][y] > dp[x][y + 1]) {
                        dp[x + 1][y + 1] = dp[x + 1][y];
                    }
                    else {
                        dp[x + 1][y + 1] = dp[x][y + 1];
                    }
                }
            }
        }
        printf("%d\n", dp[xlen][ylen]);
//        memset(dp, 0, sizeof(int)*1001*1001);
    }

    return 0;
}

C++: #include <iostream>
#include <vector>
#include <algorithm>
#include <string>
#define rep(i, n) for(int i = 0; i < n; i++)
using namespace std;
typedef long long ll;

int calcAns(string s, string t) {
    int r = s.size() + 1;
    int c = t.size() + 1;

    int dp[r][c];
    rep(i, r)rep(j,c) dp[i][j] = 0;

    for(int i = 1; i < r; i++) {
        for(int j = 1; j < c; j++) {
            dp[i][j] = max(dp[i-1][j], dp[i][j-1]);
            if(s[i-1] == t[j-1]) dp[i][j] = dp[i-1][j-1] + 1;
        }
    }
    return dp[r-1][c-1];
}

int main(void)
{
    int q;
    cin >> q;

    rep(i, q) {
        string s, t;
        cin >> s >> t;
        int ans = calcAns(s, t);
        cout << ans << endl;
    }
    return 0;
}

C++: #ifdef DEBUG
#include "../utils.cpp"
#endif
#include <bits/stdc++.h>
/*
Problem
最長共通部分列

 
Category
DP
 
URL:
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=ALDS1_10_C&lang=ja

考察:
dp[X][Y] := Xに対するYのLCSを作るのに必要なXの部分文字列のindexの最小値
--> LCSのサイズの情報がないのでダメ。

dp[X][Y] := XとYで作れる LCS の長さ
--> 素直な定義。でも漸化式が作れるのか？
dp[0][Y] = 0
dp[i][j] = X[i] == Y[j] ? dp[i-1][j-1] + 1 : max(dp[i][j-1], dp[i-1][j])



Date: 2020/04/18
*/
 

using namespace std;
using ll = int64_t;
#define int int64_t
#define INF 10e9

 
/* ==== declarations ====== */
// functions
void solve();
void getInput();
 
// global variables
int Q;
vector<vector<int>> dp;
vector<int> V;
string X, Y;

/* ======================== */

void getInput() {
    cin>>X;
    cin>>Y;
}
 
 
void solve() {
    dp = vector<vector<int>>(X.size(), vector<int>(Y.size(), 0));

    for (int i=0; i<X.size(); ++i) {
        for (int j=0; j<Y.size(); ++j) {
            int a = (i>0 and j>0) ? dp[i-1][j-1] : 0;
            int b = (j>0) ? dp[i][j-1] : 0;
            int c = (i>0) ? dp[i-1][j] : 0;
            if (X[i] == Y[j]) {
                dp[i][j] = max(a + 1, max(b, c));
            }
            else {
                dp[i][j] = max(b, c);
            }
        }
    }
    // print(dp);
    cout<<dp[X.size()-1][Y.size()-1]<<endl;
}
 
 
 
signed main(){
    cin>>Q;
    for(int i=0; i<Q; ++i) {
        getInput();
        solve();
    }
    return 0;
}

C++: #include <iostream>
#include <algorithm>
#include <vector>
#define rep(i, n) for(int i = 0; i < (int)(n); i++)
#define repR(i, n) for(int i = (n) - 1; i > -1; i--)
#define rep1(i, n) for(int i = 1; i < (int)(n + 1); i++)
#define rep1R(i, n) for(int i = (n); i > 0; i--)
using namespace std;

int q;
int dp[1010][1010];

int lcs(string& X, string& Y) {
  int m = X.size(), n = Y.size();
  X = ' ' + X, Y = ' ' + Y;
  int result = 0;
  rep1(i, m) dp[i][0] = 0;
  rep1(j, n) dp[0][j] = 0;
  rep1(i, m) rep1(j, n) {
    if (X[i] == Y[j]) dp[i][j] = dp[i - 1][j - 1] + 1;
    else dp[i][j] = max(dp[i][j - 1], dp[i - 1][j]);
    result = max(result, dp[i][j]);
  }
  return result;
}

int main() {
  cin >> q;
  rep(i, q) {
    string X, Y;
    cin >> X;
    cin >> Y;
    cout << lcs(X, Y) << endl;
  }
  return 0;
}

C++: #include <iostream>
#include <algorithm>
#define LENGTH 1000

using namespace std;

int LCSLength(string X, string Y){
    int m = X.size();
    int n = Y.size();
    int c[LENGTH+1][LENGTH+1];
    int maxLength = 0;
    for(int i = 1; i <= m; i++) c[i][0] = 0;
    for(int j = 0; j <= n; j++) c[0][j] = 0;
    for(int i = 1; i <= m; i++){
        for(int j = 1; j <= n; j++){
            if(X[i] == Y[j]) c[i][j] = c[i-1][j-1] + 1;
            else if(c[i-1][j] >= c[i][j-1]) c[i][j] = c[i-1][j];
            else c[i][j] = c[i][j-1];
            maxLength = max(maxLength, c[i][j]);
        }
    }
    return maxLength;
}

int main(){
    int n;
    string X, Y;
    cin >> n;
    for(int i = 0; i < n; i++){
        cin >> X >> Y;
        cout << LCSLength(X, Y) << endl;
    }
    return 0;
}

C++: #include "bits/stdc++.h"
using namespace std;
typedef long long ll;
#define INF (1<<30)
#define INFLL (1ll<<60)
typedef pair<int, int> P;
typedef pair<ll, P> E;
#define MOD (1000000007ll)
#define l_ength size
#define PI 3.14159265358979
 
void mul_mod(ll& a, ll b){
    a *= b;
    a %= MOD;
}
 
void add_mod(ll& a, ll b){
    b += MOD;
    a += b;
    a %= MOD;
}

int main(void){
    int q,k,dp[1234][1234],i,j,n,m;
    string x,y;
    cin >> q;
    for(k=0; k<q; ++k){
        fill(dp[0],dp[1234],0);
        cin >> x >> y;
        n = x.l_ength();
        m = y.l_ength();
        for(i=0; i<n; ++i){
            for(j=0; j<m; ++j){
                dp[i+1][j+1] = max(dp[i][j+1],dp[i+1][j]);
                if(x[i] == y[j]){
                    dp[i+1][j+1] = max(dp[i][j]+1,dp[i+1][j+1]);
                }
            }
        }
        cout << dp[n][m] << endl;
    }
    return 0;
}

C++: #include <stdio.h>
#include <string.h>
#define N 1010
char a[N];
char b[N];
int dp[N][N];
//int LCS(int i, int j){
//    if(i == -1 || j == -1) return 0;
//    if(a[i] == b[j]) return LCS(i-1, j-1) + 1;
//    else return LCS(i-1, j) > LCS(i, j-1) ? LCS(i-1, j) : LCS(i, j-1);
//}
int main(){
    int k;
    scanf("%d", &k);
    while(k--){
        scanf("%s", a);
        scanf("%s", b);
        int n = strlen(a);
        int m = strlen(b);
        for(int i = n-1; i >= 0; i--) a[i+1] = a[i];
        for(int i = m-1; i >= 0; i--) b[i+1] = b[i];
        int max = n > m ? n : m;
        for(int i = 0; i <= max; i++) dp[0][i] = dp[i][0] = 0;
        for(int i = 1; i <= n; i++){
            for(int j = 1; j <= m; j++){
                if(a[i] == b[j]) dp[i][j] = dp[i-1][j-1] + 1;
                else {
                    dp[i][j] = dp[i-1][j] > dp[i][j-1] ? dp[i-1][j] : dp[i][j-1];
                }
            }
        }
        printf("%d\n", dp[n][m]);
        //printf("%d\n", LCS(strlen(a)-1, strlen(b)-1));
    }
    return 0;
}