Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

func main() {
	sc := bufio.NewScanner(os.Stdin)
	sc.Split(bufio.ScanWords)
	sc.Scan()
	num, _ := strconv.Atoi(sc.Text())
	for i := 0; i < num; i++ {
		sc.Scan()
		in1 := sc.Text()
		sc.Scan()
		in2 := sc.Text()
		countMax(in1, in2)
	}
}

func countMax(in1 string, in2 string) {
	counta := make([][]int, len(in2)+1)
	for i := 0; i < len(in2)+1; i++ {
		for j := 0; j < len(in1)+1; j++ {
			counta[i] = append(counta[i], 0)
		}
	}

	// fmt.Println(counta)
	for a1, v1 := range in1 {
		i1 := a1 + 1
		for a2, v2 := range in2 {
			i2 := a2 + 1
			// fmt.Printf("1:%v 2:%v\n", i1, i2)
			if v1 == v2 {
				counta[i2][i1] = counta[i2-1][i1-1] + 1
				continue
			}
			val := counta[i2-1][i1]
			if val < counta[i2][i1-1] {
				val = counta[i2][i1-1]
			}

			counta[i2][i1] = val
		}
	}
	fmt.Println(counta[len(in2)][len(in1)])
}

C++: #include<iostream>
#include<string>
int main()
{
  int n;
  int an[1000];
  int l=0;
  std::cin>>n;
  std::string x;
  std::string y;
  int ans[1001][1001];
  int j,k;
  for(int i=0;i<n;i++){
    std::cin>>x;
    std::cin>>y;
    for(int j=0;j<=1000;j++){
      for(int k=0;k<=1000;k++){
	ans[j][k]=0;
      }
    }
    for(int j=0;j<=x.size();j++){
      for(int k=0;k<=y.size();k++){
	if(x[j]==y[k]){
	  ans[j][k]=ans[j-1][k-1]+1;
	}else{
	  if(ans[j][k-1]>ans[j-1][k]){
	    ans[j][k]=ans[j][k-1];
	  }else{
	    ans[j][k]=ans[j-1][k];
	  }
	}
      }
    }
    std::cout<<ans[x.size()-1][y.size()-1]<<'\n';  
  }
  return 0;
}

C++: #include <bits/stdc++.h>
typedef long long ll;
using namespace std;
ll MOD = 1000000007;

#define vec                vector<int>
#define vecll              vector<ll>
#define vecd               vector<double>
#define vecst              vector<string>
#define vecb               vector<bool>
#define vec2(var, n, m)    vector<vector<int>> var(n, vector<int>(m, 0))
#define vecll2(var, n, m)  vector<vector<ll>> var(n, vector<ll>(m, 0))

#define rep(i,n)         for(ll i=(ll)0; i<(ll)n; i++)
#define REP(i,m,n)       for(ll i=(ll)m; i<(ll)n; i++)
#define arr(var, n)      vec var(n); rep(i,n){cin >> var[i];}
#define arrll(var, n)    vecll var(n); rep(i,n){cin >> var[i];}
#define arrst(var, n)    vecst var(n); rep(i,n){cin >> var[i];}
#define all(var)         (var).begin(), (var).end()
#define sortall(var)     sort(all(var))
#define uniqueall(v)     v.erase(unique(v.begin(), v.end()), v.end());
#define f_sum(var)       accumulate(all(var), 0)
#define f_sumll(var)     accumulate(all(var), 0LL)
#define chmin(v1, v2)    v1 = min(v1, v2)
#define chmax(v1, v2)    v1 = max(v1, v2)
#define pb(var)          push_back(var)
#define prt(var)         cout << (var) << "\n"
#define prtd(n, var)     cout << fixed << setprecision(n) << (var) << "\n"
#define prtfill(n, var)  cout << setw(n) << setfill('0') << (var);
#define prt2(v1, v2)     cout << (v1) << " " << (v2) << "\n"
#define prt3(v1, v2, v3) cout << (v1) << " " << (v2) << " " << (v3) << "\n"
#define prtall(v)        rep(i,v.size()){cout<<v[i]<<(i!=v.size()-1?" ":"\n");}
void prtok(bool ok){prt(ok ? "Yes" : "No");}
//----------------------------------------------------------------

int main(void) {
  int q;
  cin >> q;

  rep(_,q){
    string s, t;
    cin >> s >> t;
    int ns = s.size();
    int nt = t.size();

    vec2(dp, ns+1, nt+1);

    rep(i,ns){
      rep(j,nt){
        if(s[i]==t[j]){
          chmax(dp[i+1][j+1], dp[i][j]+1);
        }
        chmax(dp[i+1][j+1], dp[i+1][j]);
        chmax(dp[i+1][j+1], dp[i][j+1]);
      }
    }

    prt(dp[ns][nt]);
  }
}

C++: #include <iostream>
#include <vector>
#include <string>
#include <algorithm>
using namespace std;

int q;
string X, Y;
vector< vector<int> > L;

int rec(int i, int j){
  if(i < 0 || j < 0)
    return 0;
  else{
    if(L[i][j] < 0){
      if(X[i] == Y[j])
        L[i][j] = 1+rec(i-1, j-1);
      else
        L[i][j] = max(rec(i, j-1), rec(i-1, j));
    }
    return L[i][j];
  }
}

int main(){
  cin >> q;
  for(int i=0;i<q;i++){
    cin >> X >> Y;
    int m=X.length(), n=Y.length();
    L.assign(m, vector<int>(n, -1));
    int ans;
    ans= rec(m-1, n-1);
    cout << ans << endl;
  }
}

C++: #include <bits/stdc++.h>
#define REP(i,n) for (int i = 0; i <(n); ++i)
#define REP2(i,x,n) for (int i = x; i <(n); ++i)
#define ALL(v) v.begin(), v.end()
#define RALL(v) v.rbegin(), v.rend()
using namespace std;
using ll = long long;
using P = pair<int,int>;
static const double PI = acos(-1);
static const int INF = 1e9+7;

/*
  最長共通部分列　LCS
*/

void solve(){
  string s, t;
  cin >> s >> t;
  int n = s.size();
  int m = t.size();

  int dp[n+1][m+1];
  REP(i,n+1) dp[i][0] = 0;
  REP(j,m+1) dp[0][j] = 0;

  for(int i = 1; i <= n; i++){
    for(int j = 1; j <= m; j++){
      if(s[i-1] == t[j-1]){
        dp[i][j] = max({dp[i-1][j], dp[i][j-1],dp[i-1][j-1]+1});
        //最後の項が，最長距離を更新できるかを決める．
      }
      else{
        dp[i][j] = max(dp[i-1][j], dp[i][j-1]);
      }
    }
  }


  cout << dp[n][m]  << endl;
  return;

}

int main(){
  int t;
  cin >> t;
  REP(i,t) solve();

  return 0;
}