Go: package main

import (
	"fmt"
)

func main() {
	var n int
	fmt.Scan(&n)
	a := make([]int, n+1)
	for i := 0; i < n; i++ {
		fmt.Scan(&a[i])
		fmt.Scan(&a[i+1])
	}

	m := make([][]int, n+1)
	for i := 0; i <= n; i++ {
		m[i] = make([]int, n+1)
	}

	for d := 2; d <= n; d++ {
		for s := 0; s+d <= n; s++ {
			min := 1 << 30
			for j := s+1; j < s+d; j++ {
				val := m[s][j] + m[j][s+d] + a[s]*a[j]*a[s+d]
				if val < min {
					min = val
				}
			}
			m[s][s+d] = min
		}
	}
	fmt.Println(m[0][n])
}

C++: #include <bits/stdc++.h>
#define ALL(a)  (a).begin(),(a).end()
#define rep(i,n) for(int (i)=0;(i)<(n);(i)++)
using namespace std;
typedef long long ll;
typedef pair<int, int> P;
typedef pair<long long, long long> Pll;
typedef vector<int> vi;
typedef vector<vector<int>> vvi;
typedef vector<long long> vll;
typedef vector<vector<long long>> vvll;
template <typename T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template <typename T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }
const long long INF = 1LL << 60;
const int INT_INF = 1LL << 30;

int N;
vll m(110), n(110);
vvll dp(110, vll(110, INF));

ll res(int l, int r){ //[l, r)での最小回数
  if(dp.at(l).at(r) != INF) return dp.at(l).at(r);
  if(r-l == 1) return dp.at(l).at(r) = 0;
  if(r-l == 2) return dp.at(l).at(r) = m.at(l) * n.at(l) * n.at(r-1);

  ll result = INF;
  for(int i = l+1; i <= r-1; i++){ //[l, i), [i, r)に分割
    chmin(result, res(l, i) + res(i, r) + m.at(l) * m.at(i) * n.at(r-1));
  }
  return dp.at(l).at(r) = result;
}

int main(){
  cin >> N;
  for(int i = 0; i < N; i++){
    cin >> m.at(i) >> n.at(i);
  }

  cout << res(0, N) << endl;
}

C++: // 連鎖行列積 問題
#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<stack>
#include<algorithm>
#include<iostream>
#include<cmath>
#include<vector>

using namespace std;

#define MAX_N 100
#define ELE_NUM 2
// 無効な値の定義
const int INV = -1;

const int colNo = 0;
const int rowNo = 1;
const int IntMAX = 	2147483647;

int ChainedMatrixtMultiplication(int n, int m, int matrixData[][ELE_NUM]);

int main(void)
{

    int n, count;
    int matrix_data[MAX_N + 1][ELE_NUM];

    cin >> n;

    for(int i = 1; i <= n; i++)
    {
        // 行
        cin >> matrix_data[i][colNo];
        // 列
        cin >> matrix_data[i][rowNo];
    }

    count = ChainedMatrixtMultiplication(n, ELE_NUM, matrix_data);
    printf("%d\n", count);

    return 0;
}

// 連鎖行列積の最小の乗算回数を演算する関数
// n : 積を求める行列の数
// m : 行列の情報 : 0 - 行の情報, 1 - 列の情報
// matrixData[][] : 各行列の行、列情報を保持する配列
int ChainedMatrixtMultiplication(int n, int m, int matrixData[][ELE_NUM])
{

    // 第1要素 : 演算開始のNo., 第2要素 : 演算終了のNo.
    int dp[MAX_N + 1][MAX_N + 1];
    int calcResult = 0;

    // 配列の初期化
    for(int i = 0; i <= n; i++)
    {
        for(int j = 0; j <= n; j++)
        {
            dp[i][j] = INV;

            if( i == j )
            {
                // 同じ要素同士の積は演算することが不可能
                dp[i][j] = 0;
            }
        }
    }

    // 行列の演算回数の計算
    // i : 行列の演算をする先頭の要素No.
    // j : 行列の演算をする最後の要素No.
    // k : i 〜 jまでの範囲を移動する変数
    for(int l = 2; l <= n; l++)
    {
        for(int i = 1; i <= n - l + 1; i++)
        {
            int j = i + l - 1;

            dp[i][j] = IntMAX;

            printf("i_s = %d i_e = %d j = %d\n", i, n - l + 1, j);

            for(int k = i; k <= j - 1; k++)
            {
                calcResult = dp[i][k] + dp[k + 1][j]
                            + ( matrixData[i][colNo] * matrixData[k][rowNo] * matrixData[j][rowNo]);

                dp[i][j] = min( dp[i][j], calcResult );
            }
        }
    }

    return dp[1][n];
}

C++: #include<cstdio>
#include<iostream>
#include<vector>
using namespace std;
const int MAX_V = 100;
vector<pair<int,int> > pairs;
int main(){
  int n; scanf("%d",&n);
  for(int i=0;i<n;i++){
    pair<int,int> p;
    scanf("%d %d",&p.first,&p.second);
    pairs.push_back(p);
  }
  long long int sum=0;
  while(pairs.size()>1){
    vector<pair<int,int> >::iterator min_ptr;
    int min=0x7fffffff;
    int mulMin=0x7fffffff;
    for(auto iter=pairs.begin()+1;iter<pairs.end();iter++){
      int localMin = (*(iter-1)).first;
      if(localMin > (*iter).second) localMin = (*iter).second;
      int mul=(*(iter-1)).first*(*iter).second;
      if(min>=localMin){
	if(mulMin>mul){
	  min=localMin;
	  mulMin=mul;
	  min_ptr=iter;
	}
      }
    }
    sum+=(*(min_ptr-1)).first*(*min_ptr).first*(*min_ptr).second;
    (*(min_ptr-1)).second=(*min_ptr).second;
    pairs.erase(min_ptr);
  }
  printf("%lld\n",sum);
}

C++: #include <iostream>
#include <algorithm>
#include <cmath>
using namespace std;

const int N = 100;
const long int Max = pow(10, 10);

int setmatrixmulti(int p[], int n){
    int m[N+1][N+1];
    int minval;
    for(int l=1; l<=n; l++){
        for(int i=1; i<=n - l + 1; i++){
            int j = i + l - 1;
            m[i][j] = Max;
            if(i == j){
                m[i][j] = 0;
            } else {
                for(int k=i; k<j; k++){
                    m[i][j] = min(m[i][j], m[i][k] + m[k+1][j] + p[i-1]*p[k]*p[j]);
                }
            }
        }
    }
    minval= m[1][n];
    return minval;
}

int main(){
    int n, p1, p2;
    cin >> n;
    int p[n+1];
    for(int i=0; i<n; i++){
        cin >> p1 >> p2;
        if(i == 0){
            p[i] = p1;
            p[i+1] = p2;
        } else {
            p[i+1] = p2;
        }
    }

    // for(int i=0; i<n+1; i++){
    //     cout << p[i] << " " ;
    // }

    int ans = setmatrixmulti(p, n);
    cout << ans << endl;

    return 0;
}

C++: #include<iostream>
#include<algorithm>
using namespace std;

void MatrixChainMultiplication(int n,int p[],int m[1000][1000]) {
	int i, j, k,l;
	for (i = 1; i <= n; i++) m[i][i] = 0;
	for (l = 2; l <= n; l++) {
		for (i = 1; i <= n - l - 1; i++) {
			j = i + l - 1;
			m[i][j] = (1<<21);
			for (k = i; k <= j - 1; k++) {
				m[i][j] = min(m[i][j], m[i][k] + m[k + 1][j] + p[i - 1] * p[k] * p[j]);
			}
		}
	}
}

int main() {
	int n, p[1000], m[1000][1000];
	cin >> n;
	for (int i = 1; i <= n; i++) cin >> p[i - 1] >> p[i];
	MatrixChainMultiplication(n, p, m);
	cout << m[1][n] << endl;

	
}

C++: #include <bits/stdc++.h>

using namespace std;

typedef long long ll;

const ll INF = (1LL << 60);

pair<ll, ll> A[110];
ll dp[110][110];

ll matrix_chain(int i, int j){
	if(i == j) return 0;
	if(dp[i][j] != INF) return dp[i][j];
	for(int k = i;k < j; ++k) dp[i][j] = min(dp[i][j], matrix_chain(i, k) 
			+ matrix_chain(k+1, j) + A[i].first*A[k].second*A[j].second);
	return dp[i][j];
}

int main(){

	ios::sync_with_stdio(0);
	cin.tie(0);

	int n;
	cin >> n;

	for(int i=0;i<n;++i) for(int j=0;j<n;++j) dp[i][j]=INF;

	for(int i=0;i<n;i++) cin >> A[i].first >> A[i].second;
	
	cout << matrix_chain(0, n-1);

	return 0;
} // br1