Go: package main

/*
連鎖行列積
*/

import (
	"bufio"
	"bytes"
	"fmt"
	"log"
	"math"
	"os"
	"strconv"
	"strings"
)

func min(a, b int) int {
	if a < b {
		return a
	}
	return b
}

type mem *[][]int

func main() {
	scanner := makeScanner(1024)
	n := eGetInt(scanner)
	p := make([]int, n+1)
	for i := 0; i < n; i++ {
		rowcol := eGetInts(scanner)
		p[i] = rowcol[0]
		p[i+1] = rowcol[1]
	}
	m := make([][]int, n)
	for i := 0; i < n; i++ {
		m[i] = make([]int, n)
	}
	// 初期値の格納
	for i := 0; i < n; i++ {
		for j := i; j < n; j++ {
			if i == j {
				m[i][j] = 0 //  同じ行列へのコストは当然0
			} else {
				m[i][j] = math.MaxInt64
			}
		}
	}

	// num : 行列の数. num == 1の場合は初期値0を格納ずみ
	for num := 2; num <= n; num++ {
		// s : スタート行列番号
		for s := 0; s+num <= n; s++ {
			// t : 終了行列番号
			t := s + num - 1
			// k : 仕切
			for k := s; k < t; k++ {
				m[s][t] = min(m[s][t], m[s][k]+m[k+1][t]+p[s]*p[k+1]*p[t+1])
			}
		}
	}
	fmt.Println(m[0][n-1])
}

////////////////////////////////////////////////////////////////////////////////
// ライブラリ
////////////////////////////////////////////////////////////////////////////////
func makeScanner(maxByte int) *bufio.Scanner {
	scanner := bufio.NewScanner(os.Stdin)
	scanner.Buffer(make([]uint8, 0, 8192), maxByte)
	return scanner
}
func makeWordScanner() *bufio.Scanner {
	scanner := makeScanner(8192)
	scanner.Split(bufio.ScanWords)
	return scanner
}
func eGetLine(r *bufio.Scanner) string {
	if r.Scan() {
		return r.Text()
	}
	err := r.Err()
	if err != nil {
		log.Fatal(err)
	}
	// EOF
	return ""
}
func eGetInt(r *bufio.Scanner) int {
	line := eGetLine(r)
	return eAtoi(line)
}
func eGetFields(r *bufio.Scanner) []string {
	line := eGetLine(r)
	return strings.Fields(line)
}
func eGetInts(r *bufio.Scanner) []int {
	fields := eGetFields(r)
	ints := make([]int, len(fields))
	for i := 0; i < len(ints); i++ {
		ints[i] = eAtoi(fields[i])
	}
	return ints
}
func eGetChars(r *bufio.Scanner) []string {
	line := eGetLine(r)
	return strings.Split(line, "")
}
func eAtoi(s string) int {
	n, err := strconv.Atoi(s)
	if err != nil {
		log.Fatal(err)
	}
	return n
}

type ints []int

func (s ints) String() string {
	var buf bytes.Buffer
	buf.WriteString("[")
	sep := ""
	for _, v := range s {
		buf.WriteString(fmt.Sprintf("%s%d", sep, v))
		sep = ", "
	}
	buf.WriteString("]")
	return buf.String()
}

func reverse(a ints) ints {
	r := make(ints, len(a))
	for i := 0; i < len(a); i++ {
		r[i] = a[len(a)-1-i]
	}
	return r
}
func max(a ints) (int, bool) {
	if len(a) == 0 {
		return 0, false
	}
	m := a[0]
	for _, e := range a {
		if e > m {
			m = e
		}
	}
	return m, true
}

// func min(a []int) int {
// 	m := a[0]
// 	for _, v := range a {
// 		if v < m {
// 			m = v
// 		}
// 	}
// 	return m
// }

func sum(a ints) int {
	if len(a) == 0 {
		return 0
	}
	sum := 0
	for _, e := range a {
		sum += e
	}
	return sum
}
func find(n int, a ints) int {
	for i, v := range a {
		if n == v {
			return i
		}
	}
	return -1
}

Python: # http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=ALDS1_10_B&lang=ja
# http://algorithms.blog55.fc2.com/blog-entry-66.html
# https://www.geeksforgeeks.org/python-program-for-matrix-chain-multiplication-dp-8/
import sys

sys.setrecursionlimit(10 ** 6)
n = int(input())
r = []
for i in range(n):
    a, b = map(int, input().split())
    if i == 0:
        r.append(a)
        r.append(b)
    else:
        r.append(b)

dp = [[float('inf')] * (n + 1) for _ in range(n + 1)]


# dp[i][j] MiMi+1...Mjを計算する最適なコスト
# M[1][2] = M[1][1] + M[2][2] +
def chain_order(i, j):
    if i == j:
        return 0
    if dp[i][j] != float('inf'):
        return dp[i][j]
    for k in range(i, j):
        dp[i][j] = min(dp[i][j], chain_order(i, k) + chain_order(k + 1, j) + r[i - 1] * r[k] * r[j])
    return dp[i][j]


# print(r)
print(chain_order(1, len(r)-1))

Python: n=int(input())
m=[]
for i in range(n-1):
    tmp=list(map(int,input().split()))
    m.append(tmp[0])
m.extend(list(map(int,input().split())))
dp=[[10**9]*n for i in range(n)]
for i in range(n):
    dp[i][i]=0
for W in range(1,n):
    for l in range(n-W):
        r=l+W
        for k in range(l,r+1):
            dp[l][r]=min(dp[l][r],m[l]*m[k]*m[r+1]+dp[l][k-1]+dp[k][r])
print(dp[0][n-1])

Python: def main():
    N = int(input())
    p = []
    for i in range(N):
        a, b = map(int, input().split())
        p.append(a)
    else:
        p.append(b)

    m = [[1e10]*(N+1) for _ in range(N+1)]
    for i in range(N+1):
        m[i][i] = 0

    for l in range(2, N+1):
        for i in range(1, N-l+2):
            j = i + l - 1

            m[i][j] = 1e10
            for k in range(i, j):
                m[i][j] = min(m[i][j], m[i][k] + m[k+1][j] + p[i-1]*p[k]*p[j])

    print(m[1][N])


if __name__ == '__main__':
    main()

Python: def resolve():
    # cf. http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=ALDS1_10_B&lang=ja
    # http://agent.inf.kyushu-u.ac.jp/~yokoo/lecture/DA2_03.pdf
    def matrix_chain_multiplication(n):
        """
        連鎖行列積問題：
        n 個の行列について、行列 M_i の次元が与えられたとき、
        積 M_1 M_2...M_n の計算に必要なスカラー乗算の最小の回数を返す
        """
        m = [[0 for x in range(n + 1)] for y in range(n + 1)]
        for l in range(2, n + 1):
            for i in range(1, n - l + 2):
                j = i + l - 1
                m[i][j] = 99000001
                for k in range(i, j):
                    m[i][j] = min(m[i][j], m[i][k] + m[k + 1][j] + p[i - 1] * p[k] * p[j])
        return m[1][n]

    # M1からMnの行数と、Mnの列数を格納。
    # 積が定義されている以上型が合っているはずなのでその他は不要
    p = []

    # 行列の数n
    n = int(input())

    # 行列Mi(i=1...n)の次元r、c
    # rは行数、cは列数
    for i in range(n):
        listed_input = input().split()
        p.append(int(listed_input[0]))

    p.append(int(listed_input[1]))

    print(matrix_chain_multiplication(n))


resolve()

Python: # -*- coding: utf-8 -*-

import random
import sys
import os
import pprint


"""Matrix Chain Multiplication"""

#fd = os.open('ALDS1_10_B.txt', os.O_RDONLY)
#os.dup2(fd, sys.stdin.fileno())

n = int(input())
col = [0] * (n + 1)
for i in range(n):
    row, column = map(int, input().split())
    col[i] = row
    col[i+1] = column

memo = [[0 for i in range(n+1)] for j in range(n+1)]
#pprint.pprint(memo)

for length in range(2, n+1):
    for start_index in range(1, n - length + 2):
        end_index = start_index + length - 1
        candidates = []
        for split_index in range(start_index, end_index):
            left = memo[start_index][split_index]
            right = memo[split_index + 1][end_index]
            plus = col[start_index - 1] * col[split_index] * col[end_index]
            candidates.append(left + plus + right)

        memo[start_index][end_index] = min(candidates)
        #print('memo', start_index, end_index, memo[start_index][end_index])

#pprint.pprint(memo)
print(memo[1][n])