Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

//util
var sc = bufio.NewScanner(os.Stdin)

func nextStr() string {
	sc.Scan()
	return sc.Text()
}

func nextInt() int {
	sc.Scan()
	i, e := strconv.Atoi(sc.Text())
	if e != nil {
		panic(e)
	}
	return i
}

func printList(list []int) {
	buf := bufio.NewWriter(os.Stdout)
	for _, v := range list {
		buf.Write([]byte(fmt.Sprintf(" %d", v)))
	}
	buf.Write([]byte("\n"))
	buf.Flush()
}

//solve
//単純な場合
func matrixChainMultiplication() {
	//行列が1つだけのとき
	for i := 1; i <= n; i++ {
		m[i][i] = 0
	}
	for l := 2; l <= n; l++ {
		for i := 1; i <= n-l+1; i++ {
			j := i + l - 1
			m[i][j] = 1 << 21
			//kまでで区切る
			for k := i; k <= j-1; k++ {
				m[i][j] = min(m[i][j], m[i][k]+m[k+1][j]+p[i-1]*p[k]*p[j])
			}
		}
	}
}

func max(a, b int) int {
	if a > b {
		return a
	} else {
		return b
	}
}

func min(a, b int) int {
	if a > b {
		return b
	} else {
		return a
	}
}

const MAX = 100

var n int
var p [MAX + 1]int

//m[i][j]: Mi * Mi+1 * ... * Mjを計算するときに必要なスカラー乗算の最小回数
var m [MAX + 1][MAX + 1]int

func main() {
	sc.Split(bufio.ScanWords)
	n = nextInt()
	for i := 1; i <= n; i++ {

		p[i-1] = nextInt() //行数
		p[i] = nextInt()   //列数
	}

	matrixChainMultiplication()
	fmt.Println(m[1][n])
}

C++: #include <iostream>
#include <cstdlib>
#include <climits>

/*
 * http://ttrsq.exblog.jp/24318687/
 */

const int MAX_N = 100;
int DP[MAX_N + 1][MAX_N + 1] = {0};
int *p;

int best(int r, int c) {
  int min = INT_MAX;
  int num = c - r;

  for (int i = 0; i < num; i++) {
    min = std::min(min, DP[r][r + i] + DP[r + i + 1][c] + p[r - 1] * p[r + i] * p[c]);
  }
  
  return min;
}

int main() {
  std::cin.tie(0);
  std::ios::sync_with_stdio(false);

  int n = 0;
  std::cin >> n;

  if (n == 1) {
    std::cout << "0" << std::endl;
  }
  
  p = (int *) std::malloc(sizeof(int) * n + 1);

  int bb = 0;

  std::cin >> p[0];
  std::cin >> p[1];
  
  for (int i = 2; i <= n; i++) {
    std::cin >> bb;
    std::cin >> p[i];
  }

  for (int i = 1; i < n; i++) {
    DP[i][i + 1] = p[i - 1] * p[i] * p[i + 1];
  }

  for (int j = 0; j <= n - 3; j++) {
    for (int i = j + 3; i <= n; i++) {
      DP[i - 2 - j][i] = best(i - 2 - j, i);
    }
  }

  std::cout << DP[1][n] << std::endl;

  return 0;
}

C++: #include <bits/stdc++.h>
#define r(i,n) for(int i=0;i<n;i++)
using namespace std;
int dp[111][111],n,L[111],R[111];

int dfs(int l,int r){
	if(dp[l][r]!=-1)return dp[l][r];
	int res=1e9;
	for(int i=l;i<r;i++){
		res=min(res,dfs(l,i)+dfs(i+1,r)+L[l]*R[i]*R[r]);
	}
	return dp[l][r]=res;
}

signed main(){
	memset(dp,-1,sizeof(dp));
	r(i,111)dp[i][i]=0;
	cin>>n;
	r(i,n)cin>>L[i]>>R[i];
	cout<<dfs(0,n-1)<<endl;
}

C++: /*
** Matrix Chain Multiplication
*/

# include <cstdio>
# include <algorithm>
using namespace std;

const int MAX = 100 + 5;

int n, m[MAX][MAX], p[MAX];

void matrixCM() {
    for (int i = 1; i <= n; i++) {
        m[i][i] = 0;
    }

    for (int l = 2; l <= n; l++) {
        for (int i = 1; i <= n - l + 1; i++) {
            int j = i + l - 1;
            m[i][j] = (1 << 21);
            for (int k = i; k < j; k++) {
                m[i][j] = min(m[i][j], m[i][k] + m[k+1][j] + p[i - 1] * p[k] * p[j]);
            }
        }
    }
}

void solve() {
    scanf("%d", &n);
    for (int i = 0; i < n; i++) {
        scanf("%d%d", &p[i], &p[i + 1]);
    }
    matrixCM();
    printf("%d\n", m[1][n]);
}

int main() {
    // freopen("infile", "r", stdin);
    // freopen("outfile", "w", stdout);
    solve();
    return 0;
}

C++: #include <iostream>
using namespace std;

int main()
{
	int n, p = 0, m = 101, mini;
	int v[101];

	cin >> n;

	for (int i = 0; i < n; i++) {
		cin >> v[i] >> v[i + 1];
		if (m > v[i]) {
			m = v[i];
			mini = i;
		}
	}

	if (n > 1) {
		for (int j = 0; j < n; j++)
			p += v[j] * v[j + 1];

		if (mini == 0) {
			p -= v[0] * v[1];
			p *= v[0];
		}
		else if (mini == n) {
			p -= v[n - 1] * v[n];
			p *= v[n];
		}
		else {
			p -= v[mini] * (v[mini + 1] + v[mini - 1]);
			p *= v[mini];
			p += v[0] * v[mini] * v[n];
		}
	}

	cout << p << endl;

	return 0;
}

C++: #include<iostream>
#include<algorithm>
using namespace std;
static const int N=100;
int main(){
  int n,p[N+1],m[N+1][N+1];
  cin >> n;
  for(int i=1;i<=n;i++){
    cin >> p[i-1] >> p[i];
  }
  for(int i=1;i<=n;i++) m[i][i]=0;
  for(int l=2;l<=n;l++){
    for(int i=1;i<=n-l+1;i++){
      int j=i+l-1;
      m[i][j]=(1<<21);
	for(int k=i;k<=j-1;k++){
	  m[i][j]=min(m[i][j],m[i][k]+m[k+1][j]+p[i-1]*p[k]*p[j]);
        }
    }
  }
  cout << m[1][n] << endl;
  return 0;
}

C++: #include<iostream>
#include<algorithm>
using namespace std;

#define MAX_N 10000
#define INF 10000000LL

long long n, j, x[MAX_N][MAX_N], p[MAX_N + 2], sum;

int matrix() {
	for (int i = 0; i < n; i++) { x[i][i] = 0; }
	for (int h = 2; h <= n; h++) {
		for (int i = 1; i <= n - h + 1; i++) {
			j = i + h - 1;
			x[i][j] = INF;
			for (int k = i; k < j; k++) {
				x[i][j] = min(x[i][j], x[i][k] + x[k + 1][j] + p[i - 1] * p[k] * p[j]);
			}
		}
	}
	sum = x[1][n];
	return sum;
}

int main() {
	cin >> n;
	for (int i = 1; i <= n; i++) {
		cin >> p[i - 1] >> p[i];
	}
	cout << matrix() << endl;
	return 0;
}

C++: 
// #define _GLIBCXX_DEBUG

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using P = pair<int, int>;

#define rep(i, n) for (int i = 0; i < n; ++i)
#pragma region Debug
template <typename T>
void view(const std::vector<T> &v)
{
    for (const auto &e : v)
    {
        std::cout << e << " ";
    }
    std::cout << std::endl;
}
template <typename T>
void view(const std::vector<std::vector<T>> &vv)
{
    for (const auto &v : vv)
    {
        view(v);
    }
}
#pragma endregion
#pragma region chminmax
template <typename T>
inline bool chmin(T &a, T b)
{
    if (a > b)
    {
        a = b;
        return true;
    }
    return false;
}
template <typename T>
inline bool chmax(T &a, T b)
{
    if (a < b)
    {
        a = b;
        return true;
    }
    return false;
}
#pragma endregion

ll INF = 1LL << 31;
int main()
{
    int n;
    cin >> n;
    vector<P> m(n);
    rep(i, n) cin >> m[i].first >> m[i].second;

    vector<vector<ll>> dp(n + 1, vector<ll>(n + 1, INF));
    rep(i, n + 1) dp[i][i] = 0;

    // start by doing a 1 matrix times 1 matrix multiplication
    // AB = A.x * A.y * B.y
    for (int w = 1; w <= n; w++)
    {
        // for each possible left most matrix for each width
        // i.e. until your "right" matrix defined by the width is m[n-1]
        for (int l = 0; l <= n - w; l++)
        {
            // as seen here.
            int r = l + w - 1;

            // for every matrix inbetween:
            for (int k = l; k < r; k++)
            {
                // multiplying (AB)(CDE) gives you an (A.x * B.y) x (C.x=B.y * E.y) mult.
                // Thus, this is a A.x * B.y * E.y + dp[A][B] + dp[C][E].

                // Do this for all possible combinations
                // e.g. A(BCD), (AB)(CD), (ABC)D where ABC-> A(BC) or (AB)C , etc.
                chmin(dp[l][r], m[l].first * m[k].second * m[r].second + dp[l][k] + dp[k + 1][r]);
            }
        }
    }

    cout << dp[0][n - 1] << endl;

    return 0;
}

C++: /*
 * Problem Description: Matrix Chain Multiplication
 * Category: Dynamic Programming
 * Author: Khan
 * Date: 20th October, 2017
 */

#include <iostream>
#include <algorithm>

using namespace std;

#define N 100

int main(int argc, char const *argv[])
{
    //freopen("sample.txt", "r", stdin);
    int n, p[N + 1], m[N + 1][N + 1];
    cin >> n;
    for (int i = 1; i <= n; ++i)
        cin >> p[i - 1] >> p[i];
    for (int i = 1; i <= n; ++i)
        m[i][i] = 0;
    for (int l = 2; l <= n; ++l)
    {
        for (int i = 1; i <= n - l + 1; ++i)
        {
            int j = i + l - 1;
            m[i][j] = (1 << 21);
            for (int k = i; k <= j - 1; ++k)
                m[i][j] = min(m[i][j], m[i][k] + m[k + 1][j] + p[i - 1] * p[k] * p[j]);
        }
    }
    cout << m[1][n] << endl;
    return 0;
}