Go: package main

import "fmt"

func main() {
	var n int
	fmt.Scan(&n)

	for q := 0; q < n; q++ {
		var s1, s2 string
		fmt.Scan(&s1, &s2)
		s1, s2 = " " + s1, " " + s2

		dp := make([][]int, len(s1))
		for i := range dp {
			dp[i] = make([]int, len(s2))
		}

		max := 0

		for i := 1; i < len(s1); i++ {
			for j := 1; j < len(s2); j++ {
				if s1[i] == s2[j] {
					dp[i][j] = dp[i-1][j-1] + 1
				} else {
					dp[i][j] = Max(dp[i-1][j], dp[i][j-1])
				}
				max = Max(max, dp[i][j])
			}
		}

		fmt.Println(max)
	}
}

func Max(n ...int) int {
	max := n[0]
	for _, v := range n[1:] {
		if v > max {
			max = v
		}
	}
	return max
}

C++: #include<bits/stdc++.h>

using namespace std;
typedef pair<int, int>P;
typedef long long ll;
#define rep(i,n)for(ll i=0;i<n;++i)
#define exrep(i, a, b) for(ll i = a; i <= b; i++)
#define out(x) cout << x << endl
#define exout(x) printf("%.10f\n", x)
#define chmax(x, y) x = max(x, y)
#define chmin(x, y) x = min(x, y)
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define pb push_back
#define re0 return 0
const double pi = acos(-1.0);
const ll MOD = 1000000007;
const ll INF = 1e16;
const ll MAX_N = 1010;
//max=({});
//条件式が真ならwhileの中身を回し続ける
//printf("%d\n", ans);

//pairの入力
//vector<pair<ll, ll>>work(n);
//rep(i, n) {
//	ll a, b;
//	cin >> a >> b;
//	work[i] = make_pair(a, b);
//for(auto p:mp)(mapの探索)
//printf("%.10f\n",なんちゃら)
//最大公約数
ll gcd(ll x, ll y) {
	return y ? gcd(y, x % y) : x;
}

ll lcm(ll x, ll y) {
	if (x == 0 || y == 0)return 0;
	return (x / gcd(x, y) * y);
}

//組み合わせの余りを求める
ll fac[MAX_N], finv[MAX_N], inv[MAX_N];
void COMinit() {
	fac[0] = fac[1] = 1;
	finv[0] = finv[1] = 1;
	inv[1] = 1;
	for (int i = 2; i < MAX_N; i++) {
		fac[i] = fac[i - 1] * i % MOD;
		inv[i] = MOD - inv[MOD % i] * (MOD / i) % MOD;
		finv[i] = finv[i - 1] * inv[i] % MOD;
	}
}

// 二項係数計算
long long COM(ll n, ll k) {
	if (n < k) return 0;
	if (n < 0 || k < 0) return 0;
	return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;
}

ll dx[4] = { 0,0,-1,1 };
ll dy[4] = { -1,1,0,0 };

//union-find木について
ll par[101010];
ll rank2[101010];

void init(ll n) {
	rep(i, n) {
		par[i] = i;
		rank2[i] = 0;
	}
}

ll find(ll x) {
	if (par[x] == x) {
		return x;
	}
	else {
		return par[x] = find(par[x]);
	}
}

void unite(ll x, ll y) {
	x = find(x);
	y = find(y);
	if (x == y)return;
	if (rank2[x] < rank2[y]) {
		par[x] = y;
	}
	else {
		par[y] = x;
		if (rank2[x] == rank2[y]) {
			rank2[x]++;
		}
	}
}

long long modpow(long long a, long long n, long long mod) {
	long long res = 1;
	while (n > 0) {
		if (n & 1) res = res * a % mod;
		a = a * a % mod;
		n >>= 1;
	}
	return res;
}

ll dp[1010][1010];
ll v[110], w[110];

//long longしか使わない
//素数は1より大きい
int main() {
	ll n;
	cin >> n;
	rep(i, n) {
		string s, t;
		cin >> s >> t;
		rep(i, s.length()) {
			rep(j, t.length()) {
				if (s[i] == t[j]) {
					dp[i + 1][j + 1] = dp[i][j] + 1;
				}
				else {
					dp[i + 1][j + 1] = max(dp[i][j + 1], dp[i + 1][j]);
				}
			}
		}
		cout << dp[s.length()][t.length()] << endl;
	}
	return 0;
}

C++: #include <bits/stdc++.h>
#define REP0(i,n) for(int i=0;i<n;i++)
#define REP1(i,n) for(int i=1;i<=n;i++)
#define REPB0(i,n) for(int i=n-1;i>=0;i--)
#define REPB1(i,n) for(int i=n;i>0;i--)
#define llong long long
#define INF 2000000000
#define NIL -1
#define N 1000
using namespace std;
int LCS(string X,string Y){
  int C[N+1][N+1];
  int m=X.size();
  int n=Y.size();
  int maxl=0;
  X=' '+X;
  Y=' '+Y;
  REP1(i,m) C[i][0]=0;
  REP1(i,n) C[0][i]=0;
  REP1(i,m){
    REP1(j,n){
      if(X[i]==Y[j]) C[i][j]=C[i-1][j-1]+1;
      else C[i][j]=max(C[i-1][j],C[i][j-1]);
      maxl=max(maxl,C[i][j]);
    }
  }
  return maxl;
}
int main(){
  string s1,s2;
  int n;
  scanf("%d",&n);
  REP0(i,n){
    cin>>s1>>s2;
    printf("%d\n",LCS(s1,s2));
  }
  return 0;
}

C++: #include<bits/stdc++.h>
using namespace std;
	int dp[1005][1005];
int LCS(string A,string B){
	memset(dp,0,sizeof dp);
	int n=A.size();
	int m=B.size();
	A=' '+A;
	B=' '+B; 
	int max1=0;
	for(int i=1;i<=n;i++){
		for(int j=1;j<=m;j++){
			if(A[i]==B[j])	dp[i][j]=dp[i-1][j-1]+1;
			else dp[i][j]=max(dp[i-1][j],dp[i][j-1]);
			max1=max(max1,dp[i][j]);
		}
	}
	return dp[n][m];
}
int main(){
	int q;
	cin>>q;
	while(q--){
		string A,B;
		cin>>A>>B;
		cout<<LCS(A,B)<<endl;
	}
	return 0;
}

C++: #include <iostream>
#include <string>

int LCS(std::string X, std::string Y)
{
    int m = X.size();
    int n = Y.size();
    X = ' ' + X;
    Y = ' ' + Y;
    int c[m+1][n+1];
    for (int i = 0; i <= m; i++) c[i][0] = 0;
    for (int j = 0; j <= n; j++) c[0][j] = 0;

    for (int i = 1; i <= m; i++) {
        for (int j = 1; j <= n; j++) {
            if (X[i] == Y[j]) {
                c[i][j] = c[i - 1][j - 1] + 1;
            } else if (c[i-1][j] >= c[i][j-1]) {
                c[i][j] = c[i-1][j];
            } else {
                c[i][j] = c[i][j-1];
            }
        }
    }

    return c[m][n];
}

int main(int argc, char *argv[])
{
    int n;
    std::cin >> n;
    for (int i = 0; i < n; i++) {
        std::string X, Y;
        std::cin >> X;
        std::cin >> Y;
        std::cout << LCS(X, Y) << std::endl;
    }
}

C++: #pragma region template
#include "bits/stdc++.h"
using namespace std;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
const long long MOD = 1e9 + 7, MAX = 1e18, larg = 1e5, INF = -1e9;
long long A, B, C, D, E, F, G, H, I, J, K, L, N, M, O, P, Q, R, S, T, U, V, W, x, y, z;
long long max_value = INF, max_index = -1;
long long min_value = MAX, min_index = -1;
typedef long long ll;
typedef pair<ll, ll> Pa;

ll dp[1001][1001];
ll ans[150];
int main() {
	cin >> N;
	rep(n, N){
		string X, Y;
		cin >> X;
		cin >> Y;
		rep(i, 1001){
			rep(j, 1001){
				dp[i][j] = 0;
			}
		}
		ll maxv = 0;
		rep(i, X.size()){
			rep(j, Y.size()){
				if(X[i] == Y[j]) dp[i+1][j+1] = max(dp[i+1][j+1], dp[i][j]+1);
				dp[i+1][j] = max(dp[i+1][j], dp[i][j]);
				dp[i][j+1] = max(dp[i][j+1], dp[i][j]); 
			}
		}
		rep(i, X.size()+1){
			rep(j, Y.size()+1){
				maxv = max(maxv, dp[i][j]);
			}
		}
		ans[n] = maxv;
	}
	rep(i, N){
		cout << ans[i] << endl;
	}
}

C++: #include <bits/stdc++.h>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
typedef long long ll;
typedef pair<int,int> pp;
const int INF = 1e9;
const int MOD = 1000000007;


int main(){
        int q;
        cin >>q;
        rep(i,q){
                string x,y;
                cin >> x >>y;
                vector<vector<int>> dp(x.size()+1,vector<int>(y.size()+1,0));
                
                for(int i=1;i<=x.size();i++){
                        for(int j=1;j<=y.size();j++){
                                if(x.at(i-1) == y.at(j-1)) dp.at(i).at(j) = dp.at(i-1).at(j-1) + 1;
                                else dp.at(i).at(j) = max(dp.at(i-1).at(j),dp.at(i).at(j-1));
                        }
                }
                
                cout << dp.at(x.size()).at(y.size()) << endl;
        }

        return 0;
}