Go: package main

import (
	"bufio"
	"fmt"
	"math"
	"os"
	"strconv"
)

var cache [100][100]int

func main() {
	sc := bufio.NewScanner(os.Stdin)
	sc.Split(bufio.ScanWords)
	sc.Scan()
	num, _ := strconv.Atoi(sc.Text())
	tables := []table{}
	for i := 0; i < num; i++ {
		sc.Scan()
		num1, _ := strconv.Atoi(sc.Text())
		sc.Scan()
		num2, _ := strconv.Atoi(sc.Text())
		t := table{num1, num2}
		tables = append(tables, t)
	}

	fmt.Println(minimum(0, len(tables)-1, tables))
}

type table struct {
	v int
	h int
}

func minimum(i int, j int, t []table) int {
	if i == j {
		return 0
	}

	// fmt.Printf("i:%v j:%v\n", i, j)
	if cache[i][j] != 0 {
		return cache[i][j]
	}

	min := math.MaxInt64
	for k := i; k < j; k++ {
		p := t[i].v
		n := t[k].h
		q := t[j].h
		val := minimum(i, k, t) + minimum(k+1, j, t) + p*n*q
		if val < min {
			min = val
		}
	}

	cache[i][j] = min
	return min
}

C++: #include <iostream>
#include <algorithm>
#include <cstdio>
#include <cmath>
#include <string>
#include <cctype>
#include <stack>
#include <queue>
#include <vector>
#include <cstdlib>
#include <list>
#define _USE_MATH_DEFINES
#include <math.h>

using namespace std;

int main() {

	int n, p[101], m[101][101];

	cin >> n;
	for (int i = 1; i <= n; i++) {
		cin >> p[i - 1] >> p[i];
		m[i][i] = 0;
	}

	for (int i = 2; i <= n; i++) {
		for (int j = 1; j <= n - i + 1; j++) {
			int k = i + j - 1;
			m[j][k] = (1 << 21);
			for (int l = j; l <= k - 1; l++) {
				m[j][k] = min(m[j][k], m[j][l] + m[l + 1][k] + p[j - 1] * p[l] * p[k]);
			}
		}
	}
	cout << m[1][n] << endl;
	return 0;
}

C++: #include <bits/stdc++.h>

#define MAX ((int)110)
#define endl '\n'

using namespace std;

typedef long long ll;

int n, m[ MAX ];
ll DP[ MAX ][ MAX ];

ll solve(){
	int j;
	ll cost;
	for(int len = 2 ; len <= n ; len++){
		for(int i = 1 ; i <= n - len + 1 ; i++){
			j = i + len - 1;
			DP[ i ][ j ] = LONG_LONG_MAX;
			for(int k = i ; k < j ; k++){
				cost = DP[ i ][ k ] + DP[ k + 1 ][ j ] + m[ i - 1 ] * m[ k ] * m[ j ];
				DP[ i ][ j ] = min(DP[ i ][ j ], cost);
			}
		}
	}
	return DP[ 1 ][ n ];
}

int main(){
	ios_base::sync_with_stdio(0);
	cin.tie(0);
	cout.tie(0);

	cin >> n >> m[ 0 ];
	for(int i = 1 ; i < n ; i++)
		cin >> m[ i ] >> m[ i + 1 ];
	cin >> m[ n ];
	cout << solve() << endl;
	return 0;
}

C++: #include <bits/stdc++.h>
#define LOOP(n) for (int _i = 0; _i < (n); _i++)
#define REP(i, n) for (int i = 0; i < (n); ++i)
#define RREP(i, n) for (int i = (n); i >= 0; --i)
#define FOR(i, r, n) for (int i = (r); i < (n); ++i)
#define ALL(obj) begin(obj), end(obj)
using namespace std;
using ll = long long;
using ull = unsigned long long;
using P = pair<int, int>;
using Graph = vector<vector<int>>;

const int INF = 2100100100;
const int MOD = 1e9 + 7;

// 多次元 vector 生成
template <class T>
vector<T> make_vec(size_t a) {
    return vector<T>(a);
}
template <class T, class... Ts>
auto make_vec(size_t a, Ts... ts) {
    return vector<decltype(make_vec<T>(ts...))>(a, make_vec<T>(ts...));
}
template <class T>
bool chmax(T &a, const T &b) {
    if (a < b) {
        a = b;
        return 1;
    }
    return 0;
}
template <class T>
bool chmin(T &a, const T &b) {
    if (b < a) {
        a = b;
        return 1;
    }
    return 0;
}

int N, M, K, Q, W, H, R, C;
int dp[200][200];

int main() {
    // cin.tie(0);
    // ios::sync_with_stdio(false);

    cin >> N;
    vector<int> a(N), b(N);
    REP(i, N) cin >> a.at(i) >> b.at(i);

    REP(i, N + 1) {
        REP(j, N + 1) {
            dp[i][j] = INF;
            if (i + 1 == j) dp[i][j] = 0;
        }
    }

    FOR(len, 1, N) {
        REP(l, N) {
            int r = l + len + 1;
            if (r <= N) {
                FOR(h, l + 1, r) { chmin(dp[l][r], dp[l][h] + dp[h][r] + a[l] * b[h - 1] * b[r - 1]); }
            }
        }
    }

    cout << dp[0][N] << endl;

    return 0;
}

C++: #include <iostream>
#include <algorithm>
#include <vector>
#include <deque>
#include <queue>
#include <list>
#include <stack>
#include <string>
#include <tuple>
#include <functional>
#include <numeric>
#include <cmath>
#include <iomanip>
#include <map>
#include <random>
#include <cstdlib>
#define INT_MAX 2147483647
#define INT_MIN -2147483646
#define Loop(i, n) for(int i = 0; i < (int)n; i++)
#define Loop1(i, n) for(int i = 1; i <= (int)n; i++)
#define Loopr(i, n) for(int i = (int)n - 1; i >= 0; i--)
#define Loopr1(i, n) for(int i = (int)n; i >= 1; i--)
using namespace std;
typedef long long int ll;

int memo[105][105];
int r[105], c[105];

int func(int a, int b) {
	if (memo[a][b] != INT_MIN) return memo[a][b];
	if (b - a == 0) { 
		memo[a][b] = 0;
	}
	else {
		int m = INT_MAX;
		for (int k = a;k < b;k++) {
			m = min(m, func(a, k) + func(k + 1, b) + r[a] * c[k] * c[b]);
		}
		memo[a][b] = m;
	}
	return memo[a][b];
}

int main() {
	int n;
	cin >> n;
	Loop(i, n) {
		Loop(j, n) {
			memo[i][j] = INT_MIN;
		}
	}
	Loop(i, n) {
		cin >> r[i] >> c[i];
	}
	cout << func(0, n - 1) << endl;
	return 0;
}

C++: #include<iostream>
#include<stdio.h>
#include<stdlib.h>

using namespace std;

int minana(int a,int b){
  if(a<b){
    return a;
  }
  else if(a>b){
    return b;
  }
  else return a;
}


int main(){
  int n;
  cin>>n;
  int r[100];
  int m[101][101];
  int j;
  int q=0;
  //int c[n];
  for(int i=1;i<=n;i++){
    cin>>r[i-1]>>r[i];
  }
  for(int i=1;i<=n;i++){
    m[i][i]=0;
  }
  for(int l=2;l<=n;l++){
    for(int i=1;i<=n-l+1;i++){
      j=i+l-1;
      m[i][j]=(1<<21);
      for(int k=i;k<j;k++){
	q=m[i][k]+m[k+1][j]+r[i-1]*r[k]*r[j];
	m[i][j]=minana(m[i][j],q);
      }
    }
  }
  
  cout<<m[1][n]<<endl;
  return 0;
}

C++: #include "bits/stdc++.h"
using namespace std;
typedef long long ll;

template <typename TYPE>
void print_vec(const vector<TYPE>& v){
	for(int i=0; i<v.size(); i++){
		cout << v[i] << " ";
	}
	cout << endl;
}

template <typename TYPE>
void print_vec2(const vector<vector<TYPE>>& v){
  cout << endl; cout << "       ";
  for(int i=0; i<v[0].size(); i++) cout << i << "   "; 
  cout << endl;
	for(int i=0; i<v.size(); i++){
		cout << "i=" << i << ":   ";
		for(int j=0; j<v[i].size(); j++){
			if(v[i][j] == 0) cout << "\x1B[0m" << v[i][j] << "   ";
      else cout << "\x1B[31m" << v[i][j] << "   ";//https://stackoverrun.com/ja/q/12618775
		}
		cout << "\x1B[0m" << endl;
	}
}
 
ll chmin(ll &a, ll b) {return a = min(a, b);}

int main(){
	int n;
	cin >> n;
	vector<ll> row(n), col(n);// 計算に使うんでllにしときます
	for(int i=0; i<n; i++) cin >> row[i] >> col[i];
	const ll INF = 100100100100100;
	// dp[l][r]: 区間[l,r]の行列の積を計算するのに必要なスカラー乗算の最小回数 
	// ll ans = dp[0][n-1] となるよ
	vector<vector<ll>> dp(n+1, vector<ll>(n+1, INF));
	
	//初期化
	for(int l=0; l<n; l++){
		dp[l][l] = 0;//行列1つだけじゃあ計算回数は0
	}

	for(int w=1; w<n; w++){
		for(int l=0; l+w<n; l++){
			int r = l+w;
			for(int mid=l; mid<r; mid++){// 結合する位置をずらしていく
				ll num = row[l] * col[mid] * col[r];// a×b と b×c の計算回数は a * b * c
				num = row[l] * row[mid+1] * col[r];//こっちでもよい
				chmin(dp[l][r], dp[l][mid] + num + dp[mid+1][r]);// 例  a×b と b×c　と c×d　の計算回数は a*b*c + a*c*d 　と  b*c*d + a*b*d  の小さいほう 
			}
		}
	}

	cout << dp[0][n-1] << endl;
}