Go: package main

import "fmt"

func abs(a int) int {
	if a >= 0 {
		return a
	}
	return -a
}

func min(a, b int) int {
	if a < b {
		return a
	}
	return b
}

func main() {
	var a, b, c, d int
	fmt.Scan(&a, &b, &c, &d)
	ans := 10000
	ans = min(ans, abs((a+b)-(c+d)))
	ans = min(ans, abs((a+c)-(b+d)))
	ans = min(ans, abs((a+d)-(b+c)))
	fmt.Println(ans)
}

C++: #include <bits/stdc++.h>
#define int long long
#define ll long long
using ull = unsigned long long;
using namespace std;
const int INF = 1e10;
const int MOD = 1e9 + 7;
#define dump(x)                             \
    if (dbg) {                              \
        cerr << #x << " = " << (x) << endl; \
    }
#define overload4(_1, _2, _3, _4, name, ...) name
#define FOR1(n) for (ll i = 0; i < (n); ++i)
#define FOR2(i, n) for (ll i = 0; i < (n); ++i)
#define FOR3(i, a, b) for (ll i = (a); i < (b); ++i)
#define FOR4(i, a, b, c) for (ll i = (a); i < (b); i += (c))
#define FOR(...) overload4(__VA_ARGS__, FOR4, FOR3, FOR2, FOR1)(__VA_ARGS__)
#define FORR(i, a, b) for (int i = (a); i <= (b); ++i)
#define bit(n, k) ((n >> k) & 1) /*nのk bit目*/
template <class T>
bool chmin(T& a, const T& b) {
    if (a > b) {
        a = b;
        return 1;
    } else
        return 0;
}
template <class T>
bool chmax(T& a, const T& b) {
    if (a < b) {
        a = b;
        return 1;
    } else
        return 0;
}
void Yes(bool flag = true) {
    if (flag)
        cout << "Yes" << endl;
    else
        cout << "No" << endl;
}
void No(bool flag = true) {
    Yes(!flag);
}
void YES(bool flag = true) {
    if (flag)
        cout << "YES" << endl;
    else
        cout << "NO" << endl;
}
void NO(bool flag = true) {
    YES(!flag);
}
#define pb push_back
#define mp make_pair
#define lb lower_bound
#define ub upper_bound
#define all(v) (v).begin(), (v).end()
#define SZ(x) ((int)(x).size())
#define P pair<int, int>
//#define V vector<int>
//#define S set<int>
#define itn int
bool dbg = false;

int a[10];

void solve() {
}

signed main() {
    cin.tie(nullptr);
    ios::sync_with_stdio(false);
    FOR(4)
        cin >> a[i];
    sort(a, a + 4);
    int ans = abs(a[0] + a[3] - a[1] - a[2]);
    cout << ans << endl;


    solve();
    return 0;
}

C++: #include <bits/stdc++.h>
using namespace std;
template <class T> inline bool chmax(T &a, T b) {
    if(a < b) {
        a = b;
        return 1;
    }
    return 0;
}
template <class T> inline bool chmin(T &a, T b) {
    if(a > b) {
        a = b;
        return 1;
    }
    return 0;
}
typedef long long int ll;

#define ALL(v) (v).begin(), (v).end()
#define RALL(v) (v).rbegin(), (v).rend()
#define endl "\n"
const double EPS = 1e-7;
const int INF = 1 << 30;
const ll LLINF = 1LL << 60;
const double PI = acos(-1);
const int MOD = 1000000007;
const int dx[4] = {1, 0, -1, 0};
const int dy[4] = {0, 1, 0, -1};

//-------------------------------------

int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);
    vector<int> v(4);
    for(int i = 0; i < 4; i++) {
        cin >> v[i];
    }
    int ans = INF;
    for(int i = 0; i < 4; i++) {
        for(int j = i + 1; j < 4; j++) {
            vector<bool> used(4, 0);
            used[i] = used[j] = 1;
            int sum1 = v[i] + v[j];
            int sum2 = accumulate(ALL(v), 0) - sum1;
            chmin(ans, abs(sum1 - sum2));
        }
    }
    cout << ans << endl;
}

C++: #include<bits/stdc++.h>
using namespace std;
typedef unsigned long long int ull;
typedef long long int ll;
typedef pair<ll,ll> pll;
typedef long double D;
//typedef complex<D> P;
#define F first
#define S second
const ll MOD=1000000007;
//const ll MOD=998244353;

template<typename T,typename U>istream & operator >> (istream &i,pair<T,U> &A){i>>A.F>>A.S; return i;}
template<typename T>istream & operator >> (istream &i,vector<T> &A){for(auto &I:A){i>>I;} return i;}
template<typename T,typename U>ostream & operator << (ostream &o,const pair<T,U> &A){o<<A.F<<" "<<A.S; return o;}
template<typename T>ostream & operator << (ostream &o,const vector<T> &A){int i=A.size(); for(auto &I:A){o<<I<<(--i?" ":"");} return o;}



int main(){
  cin.tie(0);
  ios::sync_with_stdio(false);
  vector<ll> A(4);
  cin>>A;
  ll ans=1e18;
  for(int i=0;i<1<<4;i++){
    if(__builtin_popcount(i)!=2){continue;}
    ll tmp=0;
    for(int j=0;j<4;j++){
      tmp+=(i>>j&1?1:-1)*A[j];
    }
    ans=min(ans,abs(tmp));
  }
  cout<<ans<<endl;
  
  


  return 0;
}

C++: #include <iostream>
#include <algorithm>
#include <string>
#include <vector>
#include <cmath>
#include <map>
#include <queue>
#include <iomanip>
#include <set>
#include <tuple>
#define mkp make_pair
#define mkt make_tuple
#define rep(i,n) for(int i = 0; i < (n); ++i)
using namespace std;
typedef long long ll;
const ll MOD=1e9+7;
template<class T> void chmin(T &a,const T &b){if(a>b) a=b;}
template<class T> void chmax(T &a,const T &b){if(a<b) a=b;}

int main(){
  cin.tie(0);
  ios::sync_with_stdio(false);

  vector<int> A(4);
  rep(i,4) cin>>A[i];
  sort(A.begin(),A.end());

  cout<<abs(A[0]+A[3]-(A[1]+A[2]))<<endl;

  return 0;
}

C++: #include <bits/stdc++.h>
using namespace std;
using ll = long long;
const int mod = 1e9 + 7;
const int inf = (1 << 30) - 1;
const ll infll = (1LL << 61) - 1;
#define fast() ios::sync_with_stdio(false), cin.tie(0), cout.tie(0)
#define digit(N) cout << fixed << setprecision((N))
#pragma GCC target("avx2")
#pragma GCC optimization("O3")
#pragma GCC optimization("unroll-loops")

int main()
{
	vector<int> a(4);
	cin >> a[0] >> a[1] >> a[2] >> a[3];
	int ans = inf;
	sort(a.begin(), a.end());
	do
	{
		ans = min(ans, abs((a[0] + a[1]) - (a[2] + a[3])));
	} while (next_permutation(a.begin(), a.end()));

	cout << ans << "\n";
}

C++: #include<bits/stdc++.h>
using namespace std;
#define fs first
#define sc second
#define pb push_back
#define mp make_pair
#define eb emplace_back
#define ALL(A) A.begin(),A.end()
#define RALL(A) A.rbegin(),A.rend()
typedef long long LL;
typedef pair<int,int> P;
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }
template<typename T> T gcd(T a,T b){return b?gcd(b,a%b):a;}
const LL mod=998244353;
const LL LINF=1LL<<62;
const int INF=1<<30;
int dx[]={1,0,-1,0,1,-1,1,-1};
int dy[]={0,1,0,-1,1,-1,-1,1};


int main(){
    vector<int> a(4);
    for (int i = 0; i < 4; i++) {
        cin >> a[i];
    }
    sort(ALL(a));
    cout << min(abs(a[3] - a[2] - (a[1] - a[0])), abs(a[3] - a[1] - (a[2] - a[0]))) << endl;
    return 0;
}