Go: package main

import (
	"bufio"
	"bytes"
	"fmt"
	"io"
	"os"
	"strconv"
	"strings"
)

const N = 1001

func max(x, y int) int {
	if x > y {
		return x
	}
	return y
}

func lcs(x, y string) int {
	var c [N][N]int
	m := len(x)
	n := len(y)
	var maxl int

	x = " " + x
	y = " " + y

	for i := 1; i <= m; i++ {
		for j := 1; j <= n; j++ {
			if x[i] == y[j] {
				c[i][j] = c[i-1][j-1] + 1
			} else {
				c[i][j] = max(c[i-1][j], c[i][j-1])
			}
			maxl = max(maxl, c[i][j])
		}
	}
	return maxl
}

func answer(reader io.Reader) string {
	sc := bufio.NewScanner(reader)
	sc.Split(bufio.ScanWords)

	sc.Scan()
	q, _ := strconv.Atoi(sc.Text())

	var out bytes.Buffer
	for i := 0; i < q; i++ {
		sc.Scan()
		s1 := sc.Text()
		sc.Scan()
		s2 := sc.Text()
		out.WriteString(fmt.Sprintf("%d\n", lcs(s1, s2)))
	}
	return strings.TrimRight(out.String(), "\n")
}

func main() {
	fmt.Println(answer(os.Stdin))
}

C++: #include <iostream>
#include <cstring>
using namespace std;
int main(void)
{
    int n;
    cin>>n;
    for(int i=0;i<n;i++)
    {
        string str1,str2;
        cin>>str1>>str2;
        int lenth1,lenth2;
        lenth1=(int)str1.length();
        lenth2=(int)str2.length();
        int dp[lenth1+1][lenth2+1];
        for(int j=0;j<=lenth1;j++)dp[j][0]=0;
        for(int j=0;j<=lenth2;j++)dp[0][j]=0;
        for(int j=1;j<=lenth1;j++)
        {
            for(int k=1;k<=lenth2;k++)
            {
                if(str1[j-1]==str2[k-1])
                {
                    dp[j][k]=dp[j-1][k-1]+1;
                }
                else dp[j][k]=max(dp[j-1][k],dp[j][k-1]);
            }
        }
        cout<<dp[lenth1][lenth2]<<endl;
    }
    return 0;
}

C++: #include<iostream>
#include<string>
#include<algorithm>
using namespace std;
static const int N = 1000;

int lcs(string X,string Y){
  int c[N + 1][N + 1];
  int m=X.size();
  int n=Y.size();
  int maxl=0;
  X= ' ' + X;
  Y= ' ' + Y;
 
  for(int i=1;i<=m;i++) c[i][0]=0;
  for(int j=1;j<=n;j++) c[0][j]=0;

  for(int i=1;i<=m;i++){
    for(int j=1;j<=n;j++){
      if(X[i]==Y[j]){
        c[i][j]=c[i-1][j-1]+1;
      }else{
        c[i][j]=max(c[i-1][j],c[i][j-1]);
      }
      maxl=max(maxl,c[i][j]);
    }
  }
  return maxl;
}

int main(){
  string s1,s2;
  int n; cin >> n;
  for(int i=0;i<n;i++){
    cin >> s1 >> s2;
    cout << lcs(s1,s2) << endl;
  }
  return 0;
}

C++: #include <iostream>
#include <string>
using namespace std;

int lcs(string X, string Y) {
  int cs[1000][1000];
  int m = X.size();
  int n = Y.size();
  int answer = 0;
  for (int i = 0; i < m; i++) cs[m][0] = 0;
  for (int i = 0; i < n; i++) cs[0][n] = 0;

  for (int i = 0; i < m; i++) {
    for (int j = 0; j < n; j++) {
      if (X[i] == Y[j]) {
        cs[i][j] = 1 + cs[i - 1][j - 1];
      } else {
        cs[i][j] = max(cs[i - 1][j], cs[i][j - 1]);
      }
      answer = max(answer, cs[i][j]);
    }
  }

  return answer;
}

int main() {
  cin.tie(0);
  ios::sync_with_stdio(false);

  int n;
  cin >> n;

  string X, Y;
  for (int i = 0; i < n; i++) {
    cin >> X >> Y;
    cout << lcs(X, Y) << endl;
  }

  return 0;
}

C++: #include<bits/stdc++.h>
using namespace std;

#define _GLIBCXX_DEBUG
#define all(v) (v).begin(),(v).end()

using ll=long long;
using pii=pair<int, int>;
using vi=vector<int>;
using vii=vector<vector<int>>;

const ll LINF=1LL<<60;
const int INF=1<<29;
const int MOD=1e9+7;

template<typename T>
T chmin(T &a, T b){
    if(a > b){ a=b; return true;}
    return false;
}

template<typename T>
T chmax(T &a, T b){
    if(a < b){ a=b; return true;}
    return false;
}

int main(){
    int q; cin >> q;
    while(q--){
        string X, Y;
        cin >> X >> Y;

        vii dp(X.size()+1, vi(Y.size()+1, 0));
        for(int i=0; i<X.size(); i++){
            for(int j=0; j<Y.size(); j++){
                if(X[i] == Y[j]) chmax(dp[i+1][j+1], dp[i][j]+1);
                chmax(dp[i+1][j+1], max(dp[i+1][j], dp[i][j+1]));
            }
        }

        cout << dp[X.size()][Y.size()] << endl;
    }
    return 0;
}

C++: #include <iostream>
#include <string>
#include <vector>

template<class T>
T myMin(const T& arg){
	return arg;
}
template<class F, class... S>
F myMin(const F& first, const S&... second){
	F m = myMin(second...);
	if (m > first){
		return first;
	}else{
		return m;
	}
}
int f(std::string::iterator str1, const std::string& str2, const std::vector<int>& vec){
	std::vector<int> new_v;
	new_v.push_back(vec[0] + 1);
	{
		auto v = vec.begin() + 1;
		for (auto i = str2.begin(); i != str2.end(); ++i, ++v){
			if (*i == *str1){
				new_v.push_back(myMin(*v, *(v - 1), new_v.back()));
			}else{
				new_v.push_back(myMin(*v + 1, new_v.back() + 1));
			}
		}
	}
	if (*(++str1) != '\0'){
		return f(str1, str2, new_v);
	}else{
		return new_v.back();
	}
}
int main(){
	int n;
	std::cin >> n;
	for (int i = 0; i < n; ++i){
		std::string str1, str2;
		std::cin >> str1 >> str2;
		std::vector<int> vec;
    vec.push_back(0);
		for (int j = 0; j < str2.size(); ++j){
			vec.push_back(j);
		}
		std::cout << (str1.size() + str2.size() - f(str1.begin(), str2, vec)) / 2 << "\n";
	}
}

C++: /* Dynamic Programming C/C++ implementation of LCS problem */
#include <cstdio>
#include <iostream>
#include <string>
using namespace std;

int max(int a, int b);
/* Returns length of LCS for X[0..m-1], Y[0..n-1] */
int lcs( string X, string Y, int m, int n ) {
    int L[m + 1][n + 1];
    int i, j;
    /* Following steps build L[m+1][n+1] in bottom up fashion. Note
       that L[i][j] contains length of LCS of X[0..i-1] and Y[0..j-1]*/

 for (i=0; i<=m; i++) {
 for (j=0; j<=n; j++) {
 if (i == 0 || j == 0) L[i][j] = 0;
 else if (X[i-1] == Y[j-1]) {L[i][j] = L[i-1][j-1] + 1;}
 else
          L[i][j] = max(L[i-1][j], L[i][j-1]);
      }
 }

 //int index = L[m][n];

 /**if (index == 0) {printf("*"); return 0;}
 char lcs[index+1];
 lcs[index] = '\0'; // Set the terminating character

    // Start from the right-most-bottom-most corner and
    // one by one store characters in lcs[]
    i = m,
    j = n;
    while (i > 0 && j > 0 )
    {
        // If current character in X[] and Y are same, then
        // current character is part of LCS
        if (X[i-1] == Y[j-1])
        {
            lcs[index-1] = X[i-1]; // Put current character in result
            i--; j--; index--;     // reduce values of i, j and index
        }

            // If not same, then find the larger of two and
            // go in the direction of larger value
        else if (L[i-1][j] > L[i][j-1])
            i--;
        else
            j--;
    }

    printf("%s\n",lcs);**/

    /* L[m][n] contains length of LCS for X[0..n-1] and Y[0..m-1] */
    return L[m][n];
}

/* Utility function to get max of 2 integers */
int max(int a, int b) {
    return (a > b)? a : b; }

/* Driver program to test above function */
int main() {
    int N;
    scanf("%d",&N);
    for (int i = 0; i < N; i++) {
        int m ;
        int n ;
        string X;
        string Y;
        cin >> X >> Y;
        m = X.length();
        n = Y.length();
        cout << lcs(X, Y, m, n) << endl;
    }
    return 0;
}

C++: #include <iostream>
#include <string>
using namespace std;
int A[1005][1005]={};

int main() {
  int i,j,k,q;
  cin >> q;
  string a,b;
  for(i=0;i<q;i++) {
    cin  >> a >> b;
    int al = a.size();
    int bl = b.size();
    for(j=1;j<=al;j++) {
      for(k=1;k<=bl;k++) {
        if(a[j]==b[k]) {
          A[j][k]=A[j-1][k-1]+1;
        } else {
          A[j][k]=max(A[j][k-1],A[j-1][k]);
        }
      }
    }
    cout << A[al][bl] << endl;
  }
  return 0;
}