Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

//util
var sc = bufio.NewScanner(os.Stdin)

func nextStr() string {
	sc.Scan()
	return sc.Text()
}

func nextInt() int {
	sc.Scan()
	i, e := strconv.Atoi(sc.Text())
	if e != nil {
		panic(e)
	}
	return i
}

func printList(list []int) {
	buf := bufio.NewWriter(os.Stdout)
	for _, v := range list {
		buf.Write([]byte(fmt.Sprintf(" %d", v)))
	}
	buf.Write([]byte("\n"))
	buf.Flush()
}

//solve
//単純な場合
func matrixChainMultiplication() {
	//行列が1つだけのとき
	for i := 1; i <= n; i++ {
		m[i][i] = 0
	}
	for l := 2; l <= n; l++ {
		for i := 1; i <= n-l+1; i++ {
			j := i + l - 1
			m[i][j] = 1 << 21
			//kまでで区切る
			for k := i; k <= j-1; k++ {
				m[i][j] = min(m[i][j], m[i][k]+m[k+1][j]+p[i-1]*p[k]*p[j])
			}
		}
	}
}

func max(a, b int) int {
	if a > b {
		return a
	} else {
		return b
	}
}

func min(a, b int) int {
	if a > b {
		return b
	} else {
		return a
	}
}

const MAX = 100

var n int
var p [MAX + 1]int

//m[i][j]: Mi * Mi+1 * ... * Mjを計算するときに必要なスカラー乗算の最小回数
var m [MAX + 1][MAX + 1]int

func main() {
	sc.Split(bufio.ScanWords)
	n = nextInt()
	for i := 1; i <= n; i++ {

		p[i-1] = nextInt() //行数
		p[i] = nextInt()   //列数
	}

	matrixChainMultiplication()
	fmt.Println(m[1][n])
}

C++: #define _USE_MATH_DEFIMES
#include <algorithm>
#include <array>
#include <bitset>
#include <cassert>
#include <cctype>
#include <climits>
#include <clocale>
#include <cmath>
#include <complex>
#include <cstdio>
#include <cstdlib>
#include <ctime>
#include <deque>
#include <fstream>
#include <functional>
#include <iomanip>
#include <iostream>
#include <iterator>
#include <list>
#include <map>
#include <numeric>
#include <queue>
#include <regex>
#include <set>
#include <sstream>
#include <stack>
#include <string>
#include <tuple>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>

const int MOD = 1'000'000'007;
const int INF = 1'000'000'000; //1e9
const int NIL = -1;
const long long LINF = 1'000'000'000'000'000'000; // 1e18
const long double EPS = 1E-10;

template<class T, class S> inline bool chmax(T &a, const S &b){
    if(a < b){
        a = b; return true;
    }
    return false;
}
template<class T, class S> inline bool chmin(T &a, const S &b){
    if(b < a){
        a = b; return true;
    }
    return false;
}








int main(){
    int n; std::cin >> n;
    std::vector<int> r(n), c(n);
    for(int i(0); i < n; ++i) std::cin >> r[i] >> c[i];
    //dp[i][j] := iからjまでの計算に必要な回数
    std::vector<std::vector<int>> dp(n, std::vector<int>(n, 0));
    for(int d(1); d < n; ++d){
        for(int i(0), i_len(n - d); i < i_len; ++i){
            int j(i + d);
            dp[i][j] = INF;
            for(int k(i); k < j; ++k){
                chmin(dp[i][j], dp[i][k] + dp[k+1][j] + r[i]*c[k]*c[j]);
            }
        }
    }
    std::cout << dp[0][n-1] << std::endl;
    return 0;
}

C++: #include<cstdio>
#include<cstdlib>
#include<cstring>
#include<cmath>
#include<climits>
#include<iostream>
#include<sstream>
#include<utility>
#include<map>
#include<vector>
#include<queue>
#include<algorithm>
#include<set>
#include<stack>
using namespace std;
typedef long long ll;
typedef pair<int,int>P;
int N;
int r[105],c[105];
ll dp[105][105]={0};

void dbg()
{
	for(int i=0;i<N;i++,puts(""))
		for(int j=0;j<N;j++)
			printf("%7d ",dp[i][j]);
}

int main()
{
	scanf("%d",&N);
	for(int i=0;i<N;i++)
		scanf("%d%d",&r[i],&c[i]);
	for(int i=0;i<N;i++)dp[i][i]=0;
	for(int l=1;l<N;l++)
		for(int i=0;i<N-l;i++)
		{
			int j=i+l;
			dp[i][j]=10000000;
			for(int k=0;k<j;k++)
				dp[i][j]=min(dp[i][j],dp[i][k]+dp[k+1][j]+r[i]*c[k]*c[j]);
		}
	dbg();
	printf("%d\n",dp[0][N-1]);
	return 0;
}

C++: #include<bits/stdc++.h>
using namespace std;
#define N 100
#define INF 1<<25
int n,p[N+1],m[N+1][N+1];
int matrixchainmultiplication(){
  for(int i=1;i<=n;i++) m[i][i]=0;
  for(int l=2;l<=n;l++){
    for(int i=1;i<=n-l+1;i++){
      int j=i+l-1;
      m[i][j]=INF;
      for(int k=i;k<=j-1;k++){
	m[i][j]=min(m[i][j],m[i][k]+m[k+1][j]+p[i-1]*p[k]*p[j]);
      }
    }
  }
  return m[1][n];
}
int main(){
  cin>>n;
  for(int i=0;i<n;i++) cin>>p[i]>>p[i+1];
  cout<<matrixchainmultiplication()<<endl;
  return 0;
}
/*
verified on 2017/04/26
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=ALDS1_10_B
*/

C++: #include <stdio.h>
#include <stdlib.h>
#include <stdlib.h>
#include <math.h>
#define MAX 100
void min(int,int);
int p[MAX]={},m[MAX][MAX]={};

void min(int n1,int n2){
  if(n1>n2) n1=n2;
}
    
int main()
{
  int n,r,l,i,j,k;

  scanf("%d",&n);

  for(i=1;i<=n;i++){
    scanf("%d %d",&p[i-1],&p[i]);
  }

  for(i=1;i<=n;i++){
    m[i][i]=0;
  }

  for(l=2;l<=n;l++){
    for(i=1;i<=n-l+1;i++){
      j=i+l-1;
      m[i][j]=(1<<21);
      for(k=i;k<=j-1;k++){
	min(m[i][j],m[i][k]+m[i][k]+m[k+1][j]+p[i-1]*p[k]*p[j]);
      }
    }
  }

  printf("%d\n",m[1][n]);

  return 0;
}

C++: #include <iostream>
#include <algorithm>
using namespace std;

static const int N = 100;

int main() {
	int n, p[N + 1], m[N + 1][N + 1];
	cin >> n;
	for (int i = 1; i <= n; i++) {
		cin >> p[i - 1] >> p[i];
	}

	for (int i = 1; i <= n; i++) m[i][i] = 0;
	for (int l = 2; l <= n; l++) {
		for (int i = 1; i <= n - l + 1; i++) {
			int j = i + l - 1;
			m[i][j] = (1 << 21);
			for (int k = i; k <= j - 1; k++) {
				m[i][j] = min(m[i][j], m[i][k] + m[k + 1][j] + p[i - 1] * p[k] * p[j]);
			}
		}
	}

	cout << m[1][n] << endl;


	return 0;
}

C++: #include<iostream>
#include<vector>
using namespace std;

int min_ex_o(int a,int b){
  if((a==0)||(b==0)){
    return a>b?a:b;
  }else{
    return a>b?b:a;
  }
}
int main(){
  vector<int> rc;
  vector<vector<int> > mm;
  int n;

  cin >> n;
  rc.resize(n+1);
  mm.resize(n+1);
  for(int i=0;i<n+1;i++){
    mm[i].resize(n+1);
  }
  for(int i=1;i<=n;i++){
    mm[i][i]=0;
  }
  for(int i=1;i<=n;i++){
    cin >> rc[i-1] >> rc[i];
  }

  for(int l=2;l<=n;l++){
    for(int i=1;i<=n-l+1;i++){
      int j=i+l-1;
      for(int k=i;k<=j-1;k++){
        mm[i][j]=min_ex_o(mm[i][j],mm[i][k]+mm[k+1][j]+rc[i-1]*rc[k]*rc[j]);
      }
    }
  }

  cout << mm[1][n] << endl;
}

C++: #include <iostream>
#include <climits>

using namespace std;
int main() {
	int n;
	cin >> n;



	int dp[n][n];

	for( int i = 0; i < n; i++) {
		for (int j = 0; j < n; j++) {
			dp[i][j] = 0;
		}
	}

	int p[n + 1];

	for ( int i = 0; i < n; i++) {
		cin >> p[i] >> p[i+1];
	}


	// |--**+-|

	// |+*---| l = 2, i = 0, j=0 : p(0) * P(1) * P (2)
	// |-+*--| l = 2, i = 1, j = 1 : p(1) * p(2) * p (3); p (i) * p(j+1) * p(i+l+1)
	// |---+*| l = 2, i = 1, j = 2
	// |-++*-| l = 3, i = 1, j = 3 : p(1) * p(3) * p(4)
	// |-****| 

	// 1 2 3   1 * 2 * 3

	for (int l = 2; l <= n; l++) {
		for (int i = 0; i < n - l + 1; i++) {
			int min = INT_MAX;
			for (int j = i; j < i + l - 1;j++ ) {
				int t = dp[i][j] + p[i] * p[j + 1] * p[i + l] + dp[j+1][i + l - 1];
				if (t < min) {
					min = t;
				}
			}
			dp[i][i + l - 1] = min;
			//cout << "i:" << i << " j:" << i + l - 1 << " max:" << min << endl;
		}
	}

	cout << dp[0][n -1] << endl;
}

C++: #include <iostream>
using namespace std;
int n, r[111], c[111], dp[111][111];
int main() {
	cin >> n;
	for(int i = 0; i < n; i++) cin >> r[i] >> c[i];
	for(int i = 2; i <= n; i++) {
		for(int j = 0; j <= n - i; j++) {
			int l = j, r = j + i; // [l, r)
			dp[l][r] = 999999999;
			for(int k = l + 1; k < r; k++) {
				dp[l][r] = min(dp[l][r], dp[l][k] + dp[k][r] + r[l] * c[r]);
			}
		}
	}
	cout << dp[0][n] << endl;
}