Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

//util
var sc = bufio.NewScanner(os.Stdin)

func nextStr() string {
	sc.Scan()
	return sc.Text()
}

func nextInt() int {
	sc.Scan()
	i, e := strconv.Atoi(sc.Text())
	if e != nil {
		panic(e)
	}
	return i
}

func printList(list []int) {
	buf := bufio.NewWriter(os.Stdout)
	for _, v := range list {
		buf.Write([]byte(fmt.Sprintf(" %d", v)))
	}
	buf.Write([]byte("\n"))
	buf.Flush()
}

//solve
//単純な場合
func matrixChainMultiplication() {
	//行列が1つだけのとき
	for i := 1; i <= n; i++ {
		m[i][i] = 0
	}
	for l := 2; l <= n; l++ {
		for i := 1; i <= n-l+1; i++ {
			j := i + l - 1
			m[i][j] = 1 << 21
			//kまでで区切る
			for k := i; k <= j-1; k++ {
				m[i][j] = min(m[i][j], m[i][k]+m[k+1][j]+p[i-1]*p[k]*p[j])
			}
		}
	}
}

func max(a, b int) int {
	if a > b {
		return a
	} else {
		return b
	}
}

func min(a, b int) int {
	if a > b {
		return b
	} else {
		return a
	}
}

const MAX = 100

var n int
var p [MAX + 1]int

//m[i][j]: Mi * Mi+1 * ... * Mjを計算するときに必要なスカラー乗算の最小回数
var m [MAX + 1][MAX + 1]int

func main() {
	sc.Split(bufio.ScanWords)
	n = nextInt()
	for i := 1; i <= n; i++ {

		p[i-1] = nextInt() //行数
		p[i] = nextInt()   //列数
	}

	matrixChainMultiplication()
	fmt.Println(m[1][n])
}

C++: #include"bits/stdc++.h"
using namespace std;

int mcm(int N, vector<int>& p, vector<vector<int>>& M)
{
	for (int l = 1; l < N; l++)
	{
		for (int i = 1; i <= N - l; i++)
		{
			int j = i + l;
			M[i][j] = (1 << 21);
			for (int k = i; k < j; k++)
			{
				M[i][j] = min(M[i][j], M[i][k] + M[k + 1][j] + p[i - 1] * p[k] * p[j]);
			}
		}
	}
	return M[1][N];
}

int main(void)
{
	int N;
	cin >> N;
	vector<int> p;
	vector<vector<int>> M(N + 1, vector<int>(N + 1, 0));

	for (int i = 0; i < N; i++)
	{
		int x, z;
		cin >> x >> z;
		if (!i) p.push_back(x);
		p.push_back(z);
	}

	cout << mcm(N, p, M) << endl;

	return 0;
}

C++: #include <cstdio>
#include <algorithm>

using namespace std;

const int kMax = 100 + 5;

int n;
int num[kMax], dp[kMax][kMax];

int main() {
    scanf("%d", &n);
    for(int i = 1;i <= n;++ i) scanf("%d%d", &num[i-1], &num[i]);
    for(int l = 2;l <= n;++ l) {
        for(int i = 1;i <= n - l + 1;++ i) {
            int j = i + l - 1;
            dp[i][j] = (1 << 30);
            for(int k = i;k < j;++ k) dp[i][j] = min(dp[i][j], dp[i][k] + dp[k+1][j] + num[i-1] * num[k] * num[j]);
        }
    }
    printf("%d\n", dp[1][n]);
    return 0;
}

C++: #define _CRT_SECURE_NO_WARNINGS
#include <cstdio>
#include <cstdlib>
#include <string>
#include <iostream>
#include <climits>

using namespace std;

int main() {
	int i, j, k, to, min, temp_result;
	int n;
	int r[100], c[100];
	int result[100][100];
	cin >> n;
	for (i = 0; i < n; i++) {
		cin >> r[i] >> c[i];
		result[i][i] = 0;
	}
	
	i = 0;
	j = 1;
	to = n - 2;
	while (j <= n - 1) {
		while (i <= to) {
			//computation of result[i][i+j]
			min = INT_MAX;
			k = i;
			while (k <= i + j - 1) {
				temp_result = c[k] * r[i] * c[i + j] + result[i][k] + result[k + 1][i + j];
				if (temp_result < min) {
					min = temp_result;
				}
				k++;
			}
			result[i][i + j] = min;
			i++;
		}
		i = 0;
		j++;
		to--;
	}
	printf("%d", result[0][n - 1]);
}

C++: #include<iostream>
#include<cstdio>
#define INT_MAX 100000000
using namespace std;
int index;
int mm[1000][1000];
int mine = INT_MAX;

void solve(int p[]){
  int n = index-1,j,q;
  for(int i=1;i<=n;i++)mm[i][i]=0;
  for(int l=2;l<=n;l++){
    for(int i=1;i<=n-l+1;i++){
      j = i+l-1;
      mm[i][j] = INT_MAX;
      for(int k=i;k<=j-1;k++){
	q = mm[i][k] + mm[k+1][j] + p[i-1]*p[k]*p[j];
	if(q<mm[i][j]){
	  mm[i][j] = q;
       
	}

      }
    }
  }




}

int main(){
  int p[1000],a,b;
  scanf("%d",&index);
  //for(int i=0;i<=index;i++)for(int j=0;j<=n;j++)mm[i][j] = INT_MAX;
  for(int i=0;i<index;i++){
    scanf("%d %d",&a,&b);
    p[i] = a;
    if(i == index-1)p[i+1] = b;
  }

  index = index+1;
  solve(p);
 
  printf("%d\n",mm[1][index-1]);
  return 0;
}

C++: #include <iostream>
#include <string>
#include <vector>
#include <algorithm>
using namespace std;

int n;

int main(void) {

    cin >> n;
    int m[n + 1][n + 1] = {};
    int p[n + 1] = {}; // p[i - 1] x p[i]の行列を表す

    for (int i = 0; i < n; ++i) {
        cin >> p[i] >> p[i + 1];
    }

    // 範囲が1の場合は計算しないので0
    for (int i = 1; i <= n; ++i) {
        m[i][i] = 0;
    }

    // l    : 対象とする行列の個数
    // i    : スタート地点
    // j    : ゴール地点
    // k    : 括弧を切るポイント
    for (int l = 2; l <= n; ++l) {
        for (int i = 1; i <= n - l + 1; ++i) {
            int j = i + l - 1;
            m[i][j] = INT32_MAX;
            for (int k = i; k <= j - 1; ++k) {
                m[i][j] = min(m[i][j], m[i][k] + m[k + 1][j] + p[i - 1] * p[k] * p[j]);
            }
        }
    }

    // for (int i = 1; i <= n; ++i) {
    //     for (int j = i + 1; j <= n; ++j) {
    //         m[i][j] = INT32_MAX;
    //         for (int k = i; k < j; ++k) {
    //             // i ~ k, (k + 1) ~ jの行列計算
    //             // それまでの計算回数 + 新しい計算回数
    //             // それまでの計算回数はm[i][k] + m[k + 1][n]
    //             // 新しい計算回数は左の行 * 中間の列 * 右の列
    //             m[i][j] = min(m[i][j], m[i][k] + m[k + 1][j] + p[i - 1] * p[k] * p[j]);
    //         }
    //     }

    // }

    cout << m[1][n] << endl;

    return 0;
}

C++: #include <algorithm>
#include <iostream>
#include <vector>

#define INF 1000000007

int main(){
    int n;
    std::cin >> n;

    std::vector<int> row(n), col(n);
    for(int i = 0; i < n; ++i){
        std::cin >> row.at(i) >> col.at(i);
    }

    // consider a n * n dp matrix with INF as the minimum value is the interest of this exercise
    std::vector<std::vector<int>> dp(n, std::vector<int>(n, INF));
    for(int l = n - 1; 0 <= l; --l){
        for(int r = 0; r < n; ++r){
            if(r == l){
                // set the dp value at self multiplication zero
                dp.at(l).at(r) = 0;
            }else if(r == l + 1){
                // multiply 2 matrixes
                dp.at(l).at(r) = row.at(l) * col.at(l) * col.at(r);
            }else if(r > l + 1){
                for(int m = l; m < r; ++m){
                    // examine the all dp values in every case where a separating point differs each other
                    dp.at(l).at(r) = std::min(dp.at(l).at(r), dp.at(l).at(m) + row.at(l) * col.at(m) * col.at(r)+ dp.at(m + 1).at(r));
                }
            }
        }
    }

    std::cout << dp.at(0).at(n - 1) << std::endl;

    return 0;
}

C++: #include<bits/stdc++.h>
#define INF 1e9

using namespace std;

int main()
{
  int n;
  int a[105];
  
  cin >> n;

  for(int i=0;i < n;i++){
    cin >> a[i] >> a[i+1];
  }
  //dp[i][j] := iからj番目の行列積に必要なスカラー積の最小値
  int dp[105][105] = {};

  //init
  for(int i=0;i < n;i++){
    for(int j=0;j < n;j++){
      if(i == j) dp[i][j] = 0;//iからiまでは当然 0回
      else dp[i][j] = INF;
    }
  }
  
  for(int m = 0; m < n ;m++){
    for(int i = 0; i+m < n ;i++){
      int j = i+m;
      for(int k = i; k < j ;k++){
	dp[i][j] = min(dp[i][j], dp[i][k] + dp[k+1][j] + a[i]*a[k+1]*a[j+1]);
      }
    }
  }
  cout << dp[0][n-1] << endl;
  return 0;
}

C++: #include <iostream>
#include <vector>
using namespace std;

static const int INF = 1000000000;

int main() {
    int n;
    cin >> n;
    vector<int> p(n + 1);
    vector< vector<int> > dp(n + 1, vector<int>(n + 1));
    for (int i = 1; i <= n; i++)
        cin >> p[i - 1] >> p[i];

    for (int i = 1; i <= n; i++) dp[i][i] = 0;
    for (int l = 2; l <= n; l++) {
        for (int i = 1;  i <= n - l + 1; i++) {
            int j = i + l - 1;
            dp[i][j] = INF;
            for (int k = i; k <= j - 1; k++) {
                dp[i][j] = min(dp[i][j], dp[i][k] + dp[k + 1][j] + p[i - 1] * p[k] * p[j]);
            }
        }
    }

    cout << dp[1][n] << endl;
    return 0;
}