Go: package main

import (
	"fmt"
	"math"
)

type Position struct {
	X int64
	Y int64
}

func (one Position) Distance(another Position) int64 {
	return int64(math.Abs(float64(one.X-another.X)) + math.Abs(float64(one.Y-another.Y)))
}

type PersonPosition struct {
	Takayuki Position
	Kazuyuki Position
}

func (one PersonPosition) Distance() int64 {
	return one.Takayuki.Distance(one.Kazuyuki)
}

type Status struct {
	Person PersonPosition
	Turn   int64
}

type PQStatus []*Status

func solve(h, w int64) {
	var tx, ty, kx, ky int64
	fmt.Scan(&tx, &ty, &kx, &ky)
	tx--
	ty--
	kx--
	ky--
	m := make([][]int64, h)
	for i := range m {
		m[i] = make([]int64, w)
		for j := int64(0); j < w; j++ {
			fmt.Scan(&m[i][j])
		}
	}
	start := &Status{Person: PersonPosition{Takayuki: Position{X: tx, Y: ty}, Kazuyuki: Position{X: kx, Y: ky}}, Turn: 0}
	pq := make(PQStatus, 0)
	pq = append(pq, start)
	dx := []int64{0, 1, 0, -1}
	dy := []int64{1, 0, -1, 0}
	memo := make(map[PersonPosition]int64, 0)
	ans := int64(102)
	for len(pq) > 0 {
		now := &Status{}
		now = pq[0]
		pq = pq[1:]
		if ans <= now.Turn {
			continue
		}
		if _, ok := memo[now.Person]; ok {
			continue
		}
		memo[now.Person] = now.Turn

		if now.Person.Distance() == 0 && ans > now.Turn {
			ans = now.Turn
		}

		for i := 0; i < 4; i++ {
			next := &Status{}
			next = now
			next.Person.Kazuyuki.X += dx[i]
			next.Person.Kazuyuki.Y += dy[i]
			if next.Person.Kazuyuki.X < 0 || next.Person.Kazuyuki.X >= w ||
				next.Person.Kazuyuki.Y < 0 || next.Person.Kazuyuki.Y >= h ||
				m[next.Person.Kazuyuki.Y][next.Person.Kazuyuki.X] == 1 {
				next.Person.Kazuyuki.X -= dx[i]
				next.Person.Kazuyuki.Y -= dy[i]
			}
			next.Person.Takayuki.X -= dx[i]
			next.Person.Takayuki.Y -= dy[i]
			if next.Person.Takayuki.X < 0 || next.Person.Takayuki.X >= w ||
				next.Person.Takayuki.Y < 0 || next.Person.Takayuki.Y >= h ||
				m[next.Person.Takayuki.Y][next.Person.Takayuki.X] == 1 {
				next.Person.Takayuki.X += dx[i]
				next.Person.Takayuki.Y += dy[i]
			}
			next.Turn++
			if next.Turn <= 100 {
				pq = append(pq, next)
			}
		}
	}
	if ans == 102 {
		fmt.Println("NA")
	} else {
		fmt.Println(ans)
	}
}

func main() {
	var h, w int64
	for {
		fmt.Scan(&h, &w)
		if h == 0 && w == 0 {
			break
		}
		solve(h, w)
	}
}

C++: #include<bits/stdc++.h>
using namespace std;
#define fi first
#define sc second
#define pb push_back
typedef pair<int,int> P;
typedef pair<P,P> PP;
typedef pair<int,PP> PPP;
int dx[4]={-1,0,0,1};
int dy[4]={0,-1,1,0};
int S[51][51][51][51];
int S1[51][51][51][51];
int main()
{
	while(true){
		int X,Y;
		int tx;int ty;
		int kx;int ky;
		scanf("%d%d",&X,&Y);
		if(X==0&&Y==0)break;
		scanf("%d%d%d%d",&tx,&ty,&kx,&ky);tx--;ty--;kx--;ky--;
		int grid[51][51];
		for(int i=0;i<Y;i++){
			for(int j=0;j<X;j++){
				scanf("%d",&grid[i][j]);
			}
		}
		
		for(int i=0;i<Y;i++){
			for(int j=0;j<X;j++){
				for(int k=0;k<Y;k++){
					for(int l=0;l<X;l++){
						S[i][j][k][l]=1001;
						S1[i][j][k][l]=1001;
					}
				}
			}
		}
		
		priority_queue<PPP>s;
		PP x;
		x.fi.sc=tx;x.fi.fi=ty;x.sc.sc=kx;x.sc.fi=ky;
		s.push(PPP(0,x));
		int ans=1001;
		while(!s.empty()){
			//printf("%d\n",(int)s.size());
			PPP p=s.top();s.pop();
			if(S[p.sc.fi.fi][p.sc.fi.sc][p.sc.sc.fi][p.sc.sc.sc]<=p.fi)continue;
			
			if(p.sc.fi.fi==p.sc.sc.fi&&p.sc.fi.sc==p.sc.sc.sc){
				ans=min(ans,p.fi);
				
			}
			if(ans<=p.fi+1)continue;
			S[p.sc.fi.fi][p.sc.fi.sc][p.sc.sc.fi][p.sc.sc.sc]=p.fi;
			S1[p.sc.fi.fi][p.sc.fi.sc][p.sc.sc.fi][p.sc.sc.sc]=p.fi;
			if(p.fi==100)continue;
			for(int k=0;k<4;k++){
				PP t;
				if(p.sc.fi.fi+dy[k]<0||p.sc.fi.fi+dy[k]>=Y||p.sc.fi.sc+dx[k]<0||p.sc.fi.sc+dx[k]>=X){
					t.fi.fi=p.sc.fi.fi;t.fi.sc=p.sc.fi.sc;
				}
				else if(grid[p.sc.fi.fi+dy[k]][p.sc.fi.sc+dx[k]]==1){
					t.fi.fi=p.sc.fi.fi;t.fi.sc=p.sc.fi.sc;
				}
				else{
					t.fi.sc=p.sc.fi.sc+dx[k];t.fi.fi=p.sc.fi.fi+dy[k];
				}
				if(p.sc.sc.fi-dy[k]<0||p.sc.sc.fi-dy[k]>=Y||p.sc.sc.sc-dx[k]<0||p.sc.sc.sc-dx[k]>=X){
					t.sc.sc=p.sc.sc.sc;t.sc.fi=p.sc.sc.fi;
				}
				else if(grid[p.sc.sc.fi-dy[k]][p.sc.sc.sc-dx[k]]==1){
					t.sc.sc=p.sc.sc.sc;t.sc.fi=p.sc.sc.fi;
				}
				else{
					t.sc.fi=p.sc.sc.fi-dy[k];t.sc.sc=p.sc.sc.sc-dx[k];
				}
				if(S[t.fi.fi][t.fi.sc][t.sc.fi][t.sc.sc]<=p.fi+1)continue;
				if(S1[t.fi.fi][t.fi.sc][t.sc.fi][t.sc.sc]<=p.fi+1)continue;
				S1[t.fi.fi][t.fi.sc][t.sc.fi][t.sc.sc]=p.fi+1;
				s.push(PPP(p.fi+1,t));
			}
		}
		if(ans==1001)printf("NA\n");
		else printf("%d\n",ans);
		
	}
	return 0;
}

C++: #include <iostream>
#include <queue>
#include <cstring>
using namespace std;


int H,W;
bool F[52][52]; //障害物
bool D[52][52][52][52]; //探索済みかの判定用
int inc_tx[4] = {1,-1,0,0};
int inc_ty[4] = {0,0,1,-1};
int inc_kx[4] = {-1,1,0,0};
int inc_ky[4] = {0,0,-1,1};

class Point{
public:
  int tx; //タカユキの座標
  int ty;
  int kx; //カズユキの座標
  int ky;
  int d; //ターン回数
  void set(int a,int b,int c,int d){
    tx = a;
    ty = b;
    kx = c;
    ky = d;
  }
};

bool is_out_of_area(int y,int x) //座標が範囲内か確認する関数
{
  return x < 1 || x > W || y < 1 || y > H || F[y][x];
}

int main(){

  while(1){

    Point p,q;
    int tx,ty,kx,ky;
    queue<Point> qa;
    cin >> W >> H;
    if(W == 0 && H == 0)
    break;
    cin >> tx >> ty >> kx >> ky;
    memset(F,1,sizeof(F));
    for(int y=1;y<=H;y++){
      for(int x=1;x<=W;x++){
        cin >> F[y][x];
      }
    }
    memset(D,1,sizeof(D));
    p.set(tx,ty,kx,ky);
    D[ty][tx][ky][kx] = 0;
    p.d = 0;
    qa.push(p);
    while(1){
      if(qa.empty()){
        cout << "NA" <<endl;
        break;
      }
      p = qa.front();
      qa.pop();
      if(p.d >= 100){
        cout << "NA" << endl;
        break;
      }
      if(p.tx == p.kx && p.ty == p.ky){
        cout << p.d << endl;
        break;
      }
      for(int i=0;i<4;i++){
        q.tx = p.tx + inc_tx[i]; q.ty = p.ty + inc_ty[i];
        q.kx = p.kx + inc_kx[i]; q.ky = p.ky + inc_ky[i];
        if(D[q.ty][q.tx][q.ky][q.kx]){
          if(is_out_of_area(q.ty ,q.tx) == 0 || is_out_of_area(q.ky ,q.kx) == 0){
            if(is_out_of_area(q.ty ,q.tx)){
              q.ty = p.ty; q.tx = p.tx;
            }
            if(is_out_of_area(q.ky ,q.kx)){
              q.ky = p.ky; q.kx = p.kx;
            }
            q.d = p.d + 1;
            qa.push(q);
            D[q.ty][q.tx][q.ky][q.kx] = 0;
          }
        }
      }
    }
  }
  return 0;
}