Go: package main

import (
	"fmt"
	"math"
)

type Position struct {
	X int64
	Y int64
}

func (one Position) Distance(another Position) int64 {
	return int64(math.Abs(float64(one.X-another.X)) + math.Abs(float64(one.Y-another.Y)))
}

type PersonPosition struct {
	Takayuki Position
	Kazuyuki Position
}

func (one PersonPosition) Distance() int64 {
	return one.Takayuki.Distance(one.Kazuyuki)
}

type Status struct {
	Person PersonPosition
	Turn   int64
}

type PQStatus []*Status

func solve(h, w int64) {
	var tx, ty, kx, ky int64
	fmt.Scan(&tx, &ty, &kx, &ky)
	tx--
	ty--
	kx--
	ky--
	m := make([][]int64, h)
	for i := range m {
		m[i] = make([]int64, w)
		for j := int64(0); j < w; j++ {
			fmt.Scan(&m[i][j])
		}
	}
	start := &Status{Person: PersonPosition{Takayuki: Position{X: tx, Y: ty}, Kazuyuki: Position{X: kx, Y: ky}}, Turn: 0}
	pq := make(PQStatus, 0)
	pq = append(pq, start)
	dx := []int64{0, 1, 0, -1}
	dy := []int64{1, 0, -1, 0}
	memo := make(map[PersonPosition]int64, 0)
	ans := int64(102)
	for len(pq) > 0 {
		now := &Status{}
		now = pq[0]
		pq = pq[1:]
		if ans <= now.Turn {
			continue
		}
		if _, ok := memo[now.Person]; ok {
			continue
		}
		memo[now.Person] = now.Turn

		if now.Person.Distance() == 0 && ans > now.Turn {
			ans = now.Turn
		}

		for i := 0; i < 4; i++ {
			next := &Status{}
			next = now
			next.Person.Kazuyuki.X += dx[i]
			next.Person.Kazuyuki.Y += dy[i]
			if next.Person.Kazuyuki.X < 0 || next.Person.Kazuyuki.X >= w ||
				next.Person.Kazuyuki.Y < 0 || next.Person.Kazuyuki.Y >= h ||
				m[next.Person.Kazuyuki.Y][next.Person.Kazuyuki.X] == 1 {
				next.Person.Kazuyuki.X -= dx[i]
				next.Person.Kazuyuki.Y -= dy[i]
			}
			next.Person.Takayuki.X -= dx[i]
			next.Person.Takayuki.Y -= dy[i]
			if next.Person.Takayuki.X < 0 || next.Person.Takayuki.X >= w ||
				next.Person.Takayuki.Y < 0 || next.Person.Takayuki.Y >= h ||
				m[next.Person.Takayuki.Y][next.Person.Takayuki.X] == 1 {
				next.Person.Takayuki.X += dx[i]
				next.Person.Takayuki.Y += dy[i]
			}
			next.Turn++
			if next.Turn <= 100 {
				pq = append(pq, next)
			}
		}
	}
	if ans == 102 {
		fmt.Println("NA")
	} else {
		fmt.Println(ans)
	}
}

func main() {
	var h, w int64
	for {
		fmt.Scan(&h, &w)
		if h == 0 && w == 0 {
			break
		}
		solve(h, w)
	}
}

C++: /*??£?¨?*/
#include<cstdio>
#include<iostream>
#include<algorithm>
#include<math.h>
#include<queue>
#include<string.h>
#include<string>
#include<vector>
using namespace std;
#define rep(i,n) for(int i=0;i<n;i++)
#define rep1(i,n) for(int i=1;i<=n;i++)
struct X
{
	int tx, ty, t, kx, ky;
};
int java[51][51][51][51] = { 0 };
int main()
{
	int w, h, map[52][52] = { 0 };
		int mx[4] = { 0,1,0,-1 }, my[4] = { 1,0,-1,0 };
		while (1)
		{
			queue<X> que;
			X c,as;
			cin >> w >> h;
			if (w == 0 && h == 0)
				break;
			memset(java, 0, sizeof(java));
			cin >> c.tx >> c.ty >> c.kx >> c.ky;
			c.t = 0;
			que.push(c);
			rep1(i, h)
			{
				rep1(j, w)
				{
					cin >> map[i][j];
				}
			}
			/*?£???????*/
			rep(i, h + 2)//n???????????°,m????¨??????°
			{
				map[i][0] = 1;
				map[i][w + 1] = 1;
			}
			rep(i, w + 2)
			{
				map[0][i] = 1;
				map[h + 1][i] = 1;
			}
			while (!que.empty())
			{
				c = que.front();
				que.pop();
				java[c.tx][c.ty][c.kx][c.ky] = 1;
				if (c.tx == c.kx&&c.ty == c.ky||c.t >= 100)
				{
					break;
				}
				c.t++;
				as = c;
				rep(i, 4)
				{
					if (java[c.tx + mx[i]][c.ty + my[i]][c.kx - mx[i]][c.ky - my[i]] == 0 && map[c.tx + mx[i]][c.ty + my[i]] == 0 && map[c.kx - mx[i]][c.ky - my[i]] == 0)
					{
						as.tx = c.tx + mx[i];
						as.ty = c.ty + my[i];
						as.kx = c.kx - mx[i];
						as.ky = c.ky - my[i];
						que.push(as);
						java[as.tx][as.ty][as.kx][as.ky] = 1;
					}
					else if (java[c.tx][c.ty][c.kx - mx[i]][c.ky - my[i]] == 0 && map[c.tx + mx[i]][c.ty + my[i]] != 0 && map[c.kx - mx[i]][c.ky - my[i]] == 0)
					{
						as.kx = c.kx - mx[i];
						as.ky = c.ky - my[i];
						que.push(as);
						java[as.tx][as.ty][as.kx][as.ky] = 1;
					}
					else if (java[c.tx + mx[i]][c.ty + my[i]][c.kx][c.ky] == 0 && map[c.tx + mx[i]][c.ty + my[i]] == 0 && map[c.kx - mx[i]][c.ky - my[i]] != 0)
					{
						as.tx = c.tx + mx[i];
						as.ty = c.ty + my[i];
						que.push(as);
						java[as.tx][as.ty][as.kx][as.ky] = 1;
					}
				}
			}
			if (c.tx == c.kx&&c.ty == c.ky)
				cout << c.t << endl;
			else
				cout << "NA" << endl;
		}
	return 0;
}

C++: #include<iostream>
#include<cstdio>
#include<queue>
#include<map>
#include<algorithm>
#include<cstring>
#include<string>
using namespace std;
struct P{
  int tx,ty;
  int kx,ky;
  int cost;
  P(int _tx, int _ty, int _kx, int _ky, int _cost) : tx(_tx), ty(_ty), kx(_kx), ky(_ky), cost(_cost) {};
};
int hx,hy,rx,ry;
int X,Y;
int mas[110][110];
bool d[51][51][51][51];
int dx[4] = {0,1,0,-1},dy[4] = {1,0,-1,0};
int bfs();
int main(){
  while(1){
    scanf("%d %d",&X,&Y);
    if(X == 0 && Y == 0)break;
    scanf("%d %d",&hx,&hy);
    scanf("%d %d",&rx,&ry);
    for(int i = 1; i <= Y; i++){
      for(int j = 1; j <= X; j++){
	scanf("%d",&mas[i][j]);
      }
    }
    int ans = bfs();
    if(ans == -1)cout << "NA" << endl;
    else cout << ans << endl;
  }
}
int bfs(){
  queue<P> que;
  memset(d,0,sizeof(d));
  que.push(P(hx,hy,rx,ry,0));
  d[hx][hy][rx][ry] = 0;
  while(!que.empty()){
    P p = que.front();
    que.pop();
    if(p.cost >= 100)return -1;
    if(p.tx == p.kx && p.ty == p.ky){
      return p.cost;
    }
    for(int i = 0; i < 4; i++){
      int nx = p.tx + dx[i], ny = p.ty + dy[i];
      int ux = p.kx - dx[i], uy = p.ky - dy[i];
      if(nx > 0 && ny > 0 && ux > 0 && uy > 0 && nx <= X && ny <= Y && ux <= X && uy <= Y && mas[ny][nx] != 1 && mas[uy][ux] != 1 && d[nx][ny][ux][uy] == 0){
	que.push(P(nx,ny,ux,uy,p.cost++));
	d[nx][ny][ux][uy] =  1;
      }
      else if((nx <= 0 || nx > X || ny <= 0 || ny > Y || mas[ny][nx] == 1) && ux <= X && uy <= Y && ux > 0 && uy > 0 && mas[uy][ux] != 1 && d[p.tx][p.ty][ux][uy] == 0){
	que.push(P(p.tx,p.ty,ux,uy,p.cost++));
	d[p.tx][p.ty][ux][uy] = 1;
      }
      else if((ux <= 0 || ux > X || uy <= 0 || uy > Y || mas[uy][ux] == 1) && nx <= X && ny <= Y && nx > 0 && ny > 0 && mas[ny][nx] != 1 && d[nx][ny][p.kx][p.ky] == 0){
	que.push(P(nx,ny,p.kx,p.ky,p.cost++));
	d[nx][ny][p.kx][p.ky] = 1;
      }
    }
  }
  return -1;
}