Go: package main

import (
	"bufio"
	"os"
	"strconv"
	"fmt"
	"strings"
)

var scanner = bufio.NewScanner(os.Stdin)

func nextInt() int {
	scanner.Scan()
	i, e := strconv.Atoi(scanner.Text())
	if e != nil {
		panic(e)
	}
	return i
}

func main() {
	n := nextInt()
	for i := 0; i < n; i++ {
		scanner.Scan()
		points := strings.Split(scanner.Text(), " ")
		fpoints := make([]float64, 0)
		for _, v := range points {
			tmp, _ := strconv.ParseFloat(v, 64)
			fpoints = append(fpoints, tmp)
		}
		if fpoints[0] == fpoints[2] && fpoints[4] == fpoints[6] {
			fmt.Println("YES")
			continue
		}
		a := (fpoints[1]-fpoints[3])/(fpoints[0]-fpoints[2])
		b := (fpoints[5]-fpoints[7])/(fpoints[4]-fpoints[6])
		if a == b {
			fmt.Println("YES")
		} else {
			fmt.Println("NO")
		}
	}
}

C++: #include <iostream>
main(){int n,i,j;double x[4],y[4];std::cin>>n;for(i=0;i<n;i++){for(j=0;j<4;j++)std::cin>>x[j]>>y[j];if(y[0]-y[1]==y[2]-y[3]&&x[0]-x[1]==x[2]-x[3])std::cout<<"YES\n";else std::cout<<"NO\n";}}

C++: #include <iostream>
#include <vector>
#include <algorithm>
#include <map>
#include <cmath>
#include <complex>
using namespace std;
#define rep(i,n) for (int i=0; i < (n); i++)

typedef double D;
typedef complex<D> P;
typedef pair<P, P> L;
typedef vector<P> VP;
const D EPS = 1e-5;
#define X real()
#define Y imag()
#define LE(n,m) ((n) < (m) + EPS)
#define GE(n,m) ((n) + EPS > (m))
#define EQ(n,m) (abs((n)-(m)) < EPS)

D dot(P a, P b) {
  return (conj(a)*b).X;
}

D cross(P a, P b) {
  return (conj(a)*b).Y;
}

int main() {
  int n;
  cin >> n;
  for (int i = 0; i < n; i++) {
    double x1, y1, x2, y2, x3, y3, x4, y4;
    cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3 >> x4 >> y4;
    P a, b, c, d;
    a = P(x1, y1);
    b = P(x2, y2);
    c = P(x3, y3);
    d = P(x4, y4);
    if (EQ(cross(b-a, d-c), 0)) {
      std::cout << "YES" << std::endl;
    }else {
      std::cout << "NO" << std::endl;
    }
  }

}

C++: #include<cstdio>
#include<vector>
#include<algorithm>
using namespace std;
int main(){
    int n;
    scanf("%d",&n);
    while(n--){
        double x1,y1,x2,y2,x3,y3,x4,y4;
        scanf("%lf%lf%lf%lf%lf%lf%lf%lf",&x1,&y1,&x2,&y2,&x3,&y3,&x4,&y4);
        if(x1==x2||x3==x4){
            if(x1==x2&&x3==x4)puts("YES");
            else puts("NO");
        }
        else{
            double d=(y2-y1)/(x2-x1),d_=(y4-y3)/(x4-x3);
            if(d-d_<=0.0000001&&d-d_>=-0.0000001)puts("YES");
            else puts("NO");

        }
    }
    return 0;
}

C++: #include <iostream>
#include <cmath>
 
using namespace std;
 
int main (void) {
  double x1, y1, x2, y2, x3, y3, x4, y4;
  int n;
    
  cin >> n;
   
  for(int i = 0; i < n; i++) {
    cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3 >> x4 >> y4;
    double t1 = (y1-y2)/(x1-x2);
    double t2 = (y3-y4)/(x3-x4);
    //cout << t1 << " " << t2 << endl;
    if ( t1 == t2 ) {
      cout << "YES" << endl;
    } else {
      cout << "NO" << endl;
    }
  }
   
  return 0;
}

C++: #include <iostream>
#include <vector>
#include <algorithm>
#include <map>
#include <math.h>
#include <complex>
using namespace std;
#define rep(i,n) for (int i=0; i < (n); i++)

typedef double D;      // 座標値の型。doubleかlong doubleを想定
typedef complex<D> P;  // Point
typedef pair<P, P> L;  // Line
typedef vector<P> VP;
const D EPS = (1e-10);    // 許容誤差。問題によって変える
#define X real()
#define Y imag()
#define LE(n,m) ((n) < (m) + EPS)
#define GE(n,m) ((n) + EPS > (m))
#define EQ(n,m) (abs((n)-(m)) < EPS)

// 内積　dot(a,b) = |a||b|cosθ
D dot(P a, P b) {
  return (conj(a)*b).X;
}
// 外積　cross(a,b) = |a||b|sinθ
D cross(P a, P b) {
  // return (conj(a)*b).Y;
  return (a.X*b.Y-a.Y*b.X);
}

bool is_parallel(P a1, P a2, P b1, P b2) {
  return EQ(cross(a1-a2, b1-b2), 0.0);
}

int main() {
  int n;
  cin >> n;
  for (int i = 0; i < n; i++) {
    double x1, y1, x2, y2, x3, y3, x4, y4;
    cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3 >> x4 >> y4;
    
    if (is_parallel(P(x1, y1), P(x2, y2), P(x3, y3), P(x4, y4))) {
      std::cout << "YES" << std::endl;
    }else {
      std::cout << "NO" << std::endl;
    }
  }

  
  return 0;
}

C++: #include <iostream>
#include <algorithm>
#include <string>
#include <cmath>
#include <stack>
using namespace std;

int main(){
	int n;
	cin >> n;
	long double x1,y1,x2,y2,x3,y3,x4,y4;
	while(cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3 >> x4 >> y4){
		if(abs((y1 - y2)/(x1 - x2) - (x3 - x4)/(y3 - y4)) < 0.0000000001)cout << "YES" << endl;
		else cout << "NO" << endl;
	}
}

C++: #include<vector>
#include<iostream>
#include<math.h>
using namespace std;

#define REP(i, x, n) for(int i = x; i < n; i++)
#define rep(i, n) REP(i, 0, n)
#define lengthof(x) (sizeof(x) / sizeof(*(x)))
#define FILL(ptr, value) FILL_((ptr), sizeof(ptr)/sizeof(value), (value))
template <typename T>
void FILL_(void * ptr, size_t size, T value){
  std::fill((T*)ptr, (T*)ptr+size, value);
}
//4方向ベクトル→↑←↓
int dx[] ={1,0,-1,0};
int dy[] ={0,-1,0,1};
double x1,Y1,x2,y2,x3,y3,x4,y4;
int n;
int main()
{
  cin>>n;
  for(int i = 0;i < n;i++){
    cin>>x1>>Y1>>x2>>y2>>x3>>y3>>x4>>y4;
    double a =(Y1-y2)/(x1-x2);
    double b =(y4-y3)/(x4-x3);
    if(x1-x2==0 && x4-x3==0){
      cout <<"YES"<<endl;
      return 0;
    }
      if(a==b)
	cout <<"YES"<<endl;
      else
	cout<<"NO"<<endl;
  }
  return 0;
}

C++: #include <cstdio>
#include <algorithm>
#include <iostream>
#include <vector>
#include <string>
#include <cmath>
using namespace std;

int main(){
	int n;
	double x1,x2,x3,x4,y1,y2,y3,y4;
	cin >> n;
	for(int i=0;i<n;i++){
		cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3 >> x4 >> y4 ;
		if(
		if( ((y1-y2)/(x1-x2)) == ((y3-y4)/(x3-x4)) ){
			cout << "YES" << "\n" ;
		}
		else{
			cout << "NO" << "\n" ;
		}
	}
	return 0;
}

C++: #include<iostream>
#include<cstring>
#include<algorithm>
#include<string>
#include<vector>
#include<cstdio>
#include<cmath>
#define pb(in,tmp) in.push_back(tmp)
#define loop(i,a,b) for(int i=a;i<b;i++)
#define rep(i,b) loop(i,0,b)
#define all(in) in.begin(),in.end()
const double PI=acos(-1);
using namespace std;
int main(void)
{
  int n;
  int i;
  cin>>n;
  rep(i,n){
    double x1,x2,x3,x4;
	double y1,y2,y3,y4;
	scanf("%lf %lf %lf %lf %lf %lf %lf %lf",&x1,&y1,&x2,&y2,&x3,&y3,&x4,&y4);
	if((x2-x1)*(y4-y3)-(x4-x3)*(y2-y1)<1e-10)cout<<"YES"<<endl;
    else cout<<"NO"<<endl;
  }
}

C++: #include<complex>
#include<iostream>
using namespace std;

#define EPS (1e-10)
#define EQ(a,b) (abs((a)-(b)) < EPS)
#define EQV(a,b) ( EQ( (a).real() , (b).real() ) && EQ( (a).imag(), (b).imag() ) )

int main(){
  int n;
  double x1,y1,x2,y2,x3,y3,x4,y4;
  cin>>n;
  while(n--){
    cin>>x1>>y1>>x2>>y2>>x3>>y3>>x4>>y4;
    if( abs( (y2-y1)/x2-x1 - (y4-y3)/y4-y3) <= EPS ){
      cout<<"YES"<<endl;
    }else{
      cout<<"NO"<<endl;
    }
  }
}