Go: package main

import (
	"fmt"
	"math"
)

func main() {
	var resultArr [100]int
	var inputCount, primeCount, input int
	for {
		fmt.Scanf("%d", &input)
		for i := 0; i <= input; i++ {
			if IsPrime(i) {
				primeCount++
			}
		}
		resultArr[inputCount] = primeCount
		if inputCount == 30 {
			break
		}
		primeCount = 0
		inputCount++
	}
	for _, v := range resultArr {
		fmt.Printf("%d\n", v)
	}
}

func IsPrime(num int) bool {
	switch {
	case num == 2:
		return true
	case num < 2 || num%2 == 0:
		return false
	}
	sqrt := math.Sqrt(float64(num))
	for i := 3; i <= int(sqrt); i += 2 {
		if num%i == 0 {
			return false
		}
	}
	return true
}

C++: #include <stdio.h>

long check_prime(int a)
{
   long c;

   for ( c = 2 ; c <= a-1; c++ )
   {
      if ( a%c == 0 )
      {
	    return 0;
      }

   }
   if ( c == a )
      return 1;
}

int main ()
{
    long  n=0,i=0,prime=0,result=0;

    scanf("%ld",&n);

 for(i=2;i<=n;i++)
 {

   result = check_prime(i);

   if ( result == 1 )
     prime = prime +1;
 }

 printf("%ld",prime);
 printf("\n");
 return 0;
}

C++: #include <iostream>
#include <map>
using namespace std;
#define MAX_N 999999
int main()
{
    int n;
    bool notPrime[MAX_N+2];
    int count[MAX_N+2];
    for (int i = 2 ; i <= MAX_N ; i++)
    {
        if (!notPrime[i])
        {
            for (int g = i+i ; g <= MAX_N ; g += i)
            {
                notPrime[g] = true;
            }
        }
    }
    int cnt = 0;
    count[1] = 0;
    for (int g = 2 ; g <= MAX_N ; g++)
    {
        if (!notPrime[g])
            cnt ++;
        count[g] = cnt;
    }
    while (cin >> n)
    {
        cout << count[n] << endl;
    }
    
}

C++: def sieve_prime(n): # return prime numbers within [1, n]
  primes = []
  is_prime = [True] * (n+1) # [0, n]
  for i in range(2, n+1):
    if not is_prime[i]:
      continue # need only primes

    primes.append(i)
    for j in range(i*2, n+1, i): # range(i*2, n+1, i) = {i*2, i*3, ...}
      is_prime[j] = False

    """
    Compare the above code with the below one in the view of time complexity
    for j in range(i*2, n+1):
      if j % i == 0:
        is_prime[j] = False
    """
        
  return primes
      
while True:
  try:
    n = int(input())
    print(len(sieve_prime(n))) # because T <= 30, you can simply use sieve_prime every time
  except EOFError:
    break

C++: #include<iostream>

using namespace std;

int main(){

int data[1000000];


 for(int i = 0; i < 1000000; i++) data[i] = 1;

 for(int i = 2; i*i < 1000000; i++){
   if(data[i] == 1){
     for(int j = i*2; j < 1000000; j+=i) data[j] = 0;
   }
 }
 int in;
 
 while(cin >> in){
   
   int sum = 0;
   for(int i = 2; i <= in; i++){
     if(data[i] == 1) sum++;
   }
   
   cout << sum <<endl;
 }
 return 0;
}

C++: #include <iostream>
using namespace std;

bool isPrime(int);

int main() {
	int n, p;
	while (cin >> n) {
		p = 0;
		if (cin.eof())
			return 0;
		for (int i = 2; i <= n; i++) {
			if (isPrime(i))
				p++;
		}
		cout << p << endl;
	}
	return 0;
}

bool isPrime(int x) {
	for (int j = 2; j * j <= x; j++) {
		if (x % j == 0)
			return false;
	}
	return true;
}

C++: #include <iostream>
#include <queue>
#include <stack>
#include <vector>
#include <stdio.h>
#include <algorithm>
#include <string.h>
#include <string>
using namespace std;

#define rep(i,n) for(int i=0;i<int(n);i++)

bool prime[1000000];
int cou[1000000]={0};

int main(){
	int n;
	
	rep(i, 1000000) prime[i] = true;
	prime[1]=false;
	for(int i=1;i*i<1000000;i++){
		if(prime[i]){
			for(int j=i*i;j<1000000;j+=i){
				prime[j]=false;
			}
		}
	}
	rep(i,999999){
		if(prime[i+1]) cou[i+1]=cou[i]+1;
		else cou[i+1]=cou[i];
	}
	while(cin>>n){
		cout<<cou[n]<<endl;
	}
	return 0;
}

C++: #include<iostream>
using namespace std;

int main(){
  
  int n,cnt = 0;

  while(cin >> n){
    int num[n] ={0};
    for(int i = 2; i  <= n; i++){
      if(num[i] == 0){
        for(int j = 1; j <(n/i); j++){
          num[i+(j*i)] = 1;
        }
        cnt++;
      }
    }
  cout << cnt << endl;
  }
}

C++: #include <bits/stdc++.h>
using namespace std;
using ll = long long;
using P = pair<double, int>;

int main() {
    vector<bool> is_prime(1000000, true);
    vector<int> prime;
    is_prime[0] = is_prime[1] = false;
    for(int i=2; i<is_prime.size(); ++i) {
        if(is_prime[i]) {
            prime.push_back(i);
            for(int j=i+i; j<is_prime.size(); j+=i) {
                is_prime[j] = false;
            }
        }
    }
    int n;
    while(cin >> n) {
        cout << upper_bound(prime.begin(), prime.end(), n) - prime.begin() << endl;
    }
}

C++: #include <iostream>
using namespace std;

int main()
{
 bool prime[1000000];
 for(int i=0; i<1000000; i++) prime[i] = true;

 prime[0] = prime[1] = false;
 for(int i=0; i<1000000; i++)
  if(prime[i]){
   for(int j=i+i; j<1000000; j += i)
    prime[j] = false;
  }

 int n;
 while(cin >> n){
  int c = 0;
  for(int i=0; i<=n; i++)
   if(prime[i]) c++;
  
  cout << c << '\n';
 }

 return 0;
}

C++: #include <iostream>
using namespace std;

bool t[1000000] = {};

int is_prime(int n) {
  int i;
 
  for (i = 2; i * i <= n; i++) {
    if (n % i == 0) {
      return false;
    }
  }
 
  return true;
}

int main() {
  int n, i, r;
  n = 999999;

  for (i = 0; i < n; i++) {
    t[i] = is_prime(i);
  }

  while (cin >> n) {
    r = 0;
    for (i = 2; i <= n; i++) {
      if (t[i]) {
        r++;
      }
    }
    cout << r << endl;
  }

  return 0;
}

C++: #include<stdio.h>
#include<math.h>
int isprime(int x){
	int i;
	if(x == 2){
 		return 1;
	}
	i = 3;
	while( i <= sqrt(x) ){
		if(x%i==0){
			return 0;
		}
		i = i + 2;
	}
	return 1;
}
int main(){
	int n;
	while(scanf("%d",&n)!=EOF){
		int c=1;
		for(int i=3;i<=n;i+=2){
			if(isprime(i)){
				c++;
			}
		}
		printf("%d\n",c);
	}
	return 0;
}

C++: #include <iostream>
#include <cmath>
#include <vector>
using namespace std;

int main(){
    bool prime[1000000];
    int n;
    for(long int i=2;i<1000000;i++){
        bool isprime=true;
        for(long int j=2;j<=sqrt(i);j++){
            if(i%j==0){
                isprime=false;
                break;
            }
        }
        prime[i]=isprime;
    }
    while(cin >> n){
        int cnt = 0;
        for(int i=2;i<=n;i++){
            if(prime[i]) cnt++;
        }
        cout << cnt << endl;
    }
    return 0;
}

C++: #include<iostream>
#include<cstdio>
#include<cmath>

using namespace std;
#define MAX_N 999999
int n;//n以下の素数がいくつあるか出力する
int ans;//素数の数
int prime[MAX_N];//prime[i]が1ならば素数i+1は素数
int main(){
  while(scanf("%d",&n) != EOF){
    ans = 0;
    for(int i= 0;i < n;i++){
      prime[i]= 1;
    }
    prime[0] = 0;//1は素数でないので
    for(int i = 1;i <sqrt(n);i++){
      if(prime[i] == 1)
	for(int j =(i+1);(i+1)*j <=n;j++){
	  prime[(i+1)*j-1] = 0;
	}
  }
    for(int i = 0;i < n;i++){
      if(prime[i] == 1)
	ans++;
    }
      printf("%d\n",ans);
  }
  return 0;
}

C++: #include <bits/stdc++.h>
using namespace std;

int main(){
	int n;
	while(cin>>n){
		int cnt=0;
		vector<bool> v(n+1,true);
		for(int i=2; i<=sqrt(n); i++){
			if(v[i]){
				for(int j=2; i*j<=n;j++){
						v[i*j]=false;
				}
			}
		}
		for(int i=2;i<=n;i++){
			if(v[i]==true)
				cnt++;
		}
		cout << cnt << endl;
	}
}

C++: #include <iostream>
#include <math.h>
using namespace std;


int solve(int b){
    int m = 0;
    int x[1000000];
    if(b == 1){
        return 0;
    }else if(b==2){
        return 1;
    }
    x[m++] = 2;
    for(int i=3;i<=b;i+=2){
        bool a = true;
        for(int j=0;j<m;j++){
            if(i%x[j]==0){
                a = false;
                break;
            }
        }
        if(a){
            x[m++] = i;
        }
    }
    return m;
}

int main(){
    int n;
    while((cin>>n)){
        cout << solve(n) << endl;
    }
    return 0;
}