Go: package main

import "fmt"

func main() {
	const MAX = 1000000
	prime := make([]int, MAX, MAX)
	check := make([]int, MAX, MAX)
	count := make([]int, MAX, MAX)

	prime[0] = 1
	prime[1] = 1

	// prime init
	for i := 2; i < MAX; i++ {
		if check[i] == 1 {
			continue
		}

		if prime[i] == 0 {
			for j := i * 2; j < MAX; j += i {
				check[j] = 1
				prime[j] = 1
			}
		}
	}

	for i := 2; i < MAX; i++ {
		cnt := 0

		if prime[i] == 0 {
			cnt = 1
		}

		count[i] = count[i-1] + cnt
	}

	for {
		var input int
		inputCount, _ := fmt.Scanf("%d", &input)
		if inputCount != 1 {
			break
		}

		fmt.Println(count[input])
	}
}

C++: #include <iostream>
#include <vector>
//#include <math.h>
//#include <string>
#include <cmath>
#include <iomanip>

int main();
int count_prime_number(int n);
std::vector<int> return_prime_number(int n);

//最初に素数リストを作成し、入力された値に対してリストを参照する。
int main(){
	std::vector<int> prime_numbers;		//素数リスト
	int input;
	std::vector<int> answer;

	prime_numbers = return_prime_number(999999);
	//for (int i = 0; i < 3; i++){
	//std::cin >> input;
	while (std::cin >> input){
		//素数の探索
		for (int i = 0; i < input; i++){
			if (input == prime_numbers[i]){
				answer.push_back(i + 1);
				break;
			}
			else if (input < prime_numbers[i]){
				answer.push_back(i);
				break;
			}
			else{
				//何もしない
			}
		}
	}

	for (int i = 0; i < answer.size(); i++){
		std::cout << answer[i] << std::endl;
	}

	//while (1);
	return 0;
}


//入力のたびに素数のチェックをする
/*
int main(){
	int input;
	std::vector<int> answer;
	
	//for (int i = 0; i < 3; i++){
		//std::cin >> input;
	while (std::cin >> input){
		answer.push_back(count_prime_number(input));
	}

	for (int i = 0; i < answer.size(); i++){
		std::cout << answer[i] << std::endl;
	}

	//while (1);
	return 0;
}
*/

/**
* nまでの素数の個数を出力する
* args:数値n
* return:素数の個数
* 参考:http://tsg.ne.jp/TT/tsg/c/mansaku/P01.html
*/
int count_prime_number(int n){
	int rtn = 0;

	//2だけ個別チェック
	if (n >= 2){
		rtn++;
	}

	for (int i = 3; i <= n; i += 2)
	{
		bool is_prime_num = true;
		for (int j = 3; j <= sqrt(i); j += 2)		//ルートi以上のiの約数はルートi以下のiの約数と対になっているので範囲はルートiまででいい
		{
			if (i % j == 0)
			{
				is_prime_num = false;
				break;
			}
		}

		if (is_prime_num){
			rtn++;

			//デバッグ
			//std::cout << i << std::endl;
		}
	}

	return rtn;
}

/**
* nまでの素数を返す
* args:任意の数値n
* return:素数を格納したvector
*/
std::vector<int> return_prime_number(int n){
	std::vector<int> rtn;

	//2だけ個別チェック
	if (n >= 2){
		rtn.push_back(2);
	}

	for (int i = 3; i <= n; i += 2)
	{
		bool is_prime_num = true;
		for (int j = 3; j <= sqrt(i); j += 2)		//ルートi以上のiの約数はルートi以下のiの約数と対になっているので範囲はルートiまででいい
		{
			if (i % j == 0)
			{
				is_prime_num = false;
				break;
			}
		}

		if (is_prime_num){
			rtn.push_back(i);

			//デバッグ
			//std::cout << i << std::endl;
		}
	}

	return rtn;
}

C++: #include<stdio.h>
#include<math.h>
#define DB(x) (x)
int prime[80000];
int GetPrime(int num);

int main(){
	int count = GetPrime(1000000);
	DB(printf("%d\n",count));
	int n,ans[100],cor = 0;
	int i;
	while(scanf("%d",&n) != EOF){
		for(i = 0;n >= prime[i] && i < count;i++);
		ans[cor] = i;
		cor++;
	}
	for(i = 0;i < cor;i++)
		printf("%d\n",ans[i]);
	return 0;
}

int GetPrime(int num){
	int i,j,count = 0;
	int sqnum = sqrt((double)num);
	for(i = 2;i <= num;i++){
		for(j = 0;j < count;j++){
			if(prime[j] > sqnum)
				goto COUNT;
			if(i%prime[j] == 0)
				break;
		}
		if(j < count)
			continue;
		COUNT:
		prime[count] = i;
		count++;
	}
	return count;
}

C++: #include<iostream>

using namespace std;

int n;
int prime[1000000];
int checked[1000000];
int primesum[1000000];
int checknum[30];
int datasets;

int main()
{
	prime[0] = 0;
	prime[1] = 0;
	prime[2] = 1;
	primesum[0] = 0;
	primesum[1] = 0;
	primesum[2] = 1;

	for(int a = 3;a<1000000;a++)
	{
		prime[a] = 1;
	}
	
	for(int a = 3;a<1000;a++)
	{
		if(checked[a] == 0)
		{
			checked[a] = 1;
			for(int b = 2;b<a;b++)
			{
				if(a%b==0)
				{
					prime[a] = 0;
					break;
				}
			}
			if(prime[a] == 1)
			{
				for(int c = 2*a ;c<1000000;c+=a)
				{
					checked[c] = 1;
					prime[c] = 0;
				}
			}
		}
	}

	for(int a = 3;a<1000000;a++)
	{
		primesum[a] = primesum[a-1]+prime[a];
	}
	
	while(cin >> n)
	{
		checknum[datasets] = n;
datasets++;
	}

for(int a = 0;a<datasets;a++)
{
cout << primesum[checknum[a]] << endl;
}

	return 0;
}

C++: #include<iostream>
using namespace std;
int main(){
	int N,count=0;
	while(cin >> N){
		count = 0;
	for(int x=2;x<=N;x++){
		int flag = 0;
		for(int y=2;y<x;y++){
			if((x%y)==0)	flag = 1;
		}
		if(flag == 0)	count++;
	}
	cout << count << endl;
	}
	return 0;
}

C++: #include <iostream>
using namespace std;

bool isPrime(int x){
	if(x == 0 || x == 1) return false;
	for(int i=2;i<x;i++){
		if(x % i == 0) return false;
	}
	return true;
}

int main(void){
	int n;
	int ans = 0;
	
	while(cin>>n){
		for(int i=2;i<=n;i++){
			if(isPrime(i)) ans++;
		}
		printf("%d\n",ans);
	}

	return 0;
}

C++: #include <bitset> // compact STL for Sieve, better than vector<bool>!
#include <vector>
#include <cstdio>
#include <iostream>
#define ll long long
#define vi vector<int>

using namespace std;

ll _sieve_size; // ll is defined as: typedef long long ll;
bitset<10000010> bs; // 10^7 should be enough for most cases
vi primes; // compact list of primes in form of vector<int>
void sieve(ll upperbound) { // create list of primes in [0..upperbound]
_sieve_size = upperbound + 1; // add 1 to include upperbound
bs.set(); // set all bits to 1
bs[0] = bs[1] = 0; // except index 0 and 1
for (ll i = 2; i <= _sieve_size; i++) if (bs[i]) {
// cross out multiples of i starting from i * i!
for (ll j = i * i; j <= _sieve_size; j += i) bs[j] = 0;
primes.push_back((int)i); // add this prime to the list of primes
} } // call this method in main method
bool isPrime(ll N) { // a good enough deterministic prime tester
if (N <= _sieve_size) return bs[N]; // O(1) for small primes
for (int i = 0; i < (int)primes.size(); i++)
if (N % primes[i] == 0) return false;
return true; // it takes longer time if N is a large prime!
} // note: only work for N <= (last prime in vi "primes")^2
// inside int main()
int main()
{
    int TestCase,x;
    int Counter;
sieve(1000000); // can go up to 10^7 (need few seconds)

    while(cin >> TestCase)
    {
        x=0;
        while(TestCase >= primes[x])
        {
            x++;
        }
        cout << x << endl;
    }
}

C++: #include <iostream>
#include <vector>
#include <string>
#include <algorithm>
#include <utility>
#include <stack>
#include <functional>
#include <queue>
#include <cmath>

#define rep(i,j,k) for(int i=j;i<k;i++)
#define drep(n,m) for(int i=0;i<n;i++)for(int j=0;j<m;j++)
#define fi first
#define se second
#define vi vector<int>
#define INF 1000000000
#define MOD 1000000009
#define pb push_back
#define mp make_pair
typedef long long ll;
int dx[4]={0,1,0,-1},dy[4]={1,0,-1,0};

using namespace std;

ll gcd(ll a,ll b){
    if(a<b){
        int t=a;a=b;b=t;
    }
    int c=a%b;
    while(c!=0){
        a=b;
        b=c;
        c=a%b;
    }
    return b;
}

ll lcm(ll a,ll b){
    return a*b/gcd(a,b);
}

bool isPrime(int x){
    if(x==1)return false;
    if(x==2)return true;
    if(x%2==0)return false;
    for(int i=3;i<=sqrt(x);i+=2){
        if(x%i==0)return false;
    }
    return true;
}

int main() {
   vector<int> v(1000000,0),rui(1000000,0);
   rep(i,1,999999)if(isPrime(i))v[i]=1;
   rui[0]=v[0];
   rep(i,1,999999)rui[i]=rui[i-1]+v[i];
   
   int n;
   while(cin>>n){
       cout<<rui[n]<<endl;
   }
   
    
    return 0;
}

C++: #include<iostream>
using namespace std;
int main(){
  int n;
  while(cin >> n){
    int ans=0,math[1000001]={0};
    math[1]=1;
    for(int i=2;i<n+1;i++){
      int bell=i;
      if(math[i]==0){
	ans++;
	math[i]=1;
      }
      while(bell<=n){
	bell+=i;
	if(math[bell]==0){
	  math[bell]=1;
	}
      } 
    }
    cout << ans << endl;
  }
}