Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

func main() {
	scanner := bufio.NewScanner(os.Stdin)

	for scanner.Scan() {
		num, _ := strconv.Atoi(scanner.Text())
		flag := false
		count := 0

		for i := 3; i <= num; i += 2 { //1を除く入力値以下の数字
			for j := 3; j < i; j += 2 {
				if i%j == 0 {
					flag = true
					//fmt.Println(i, "/", j)
					break
				}
			}
			if !flag {
				count++
			} else {
				flag = false
			}
		}
		fmt.Println(count + 1)
	}
}

C++: #include <algorithm>
#include <cmath>
#include <iomanip>
#include <iostream>
#include <list>
#include <vector>
using namespace std;

// chack wheather a number n is a natural number
bool checkNaturalNum(int n) {
  int count = 0;
  for (int i = 1; i < n + 1; i++) {
    if (n % i == 0) {
      count++;
    }
  }

  if (count == 2) {
    return true;
  } else {
    return false;
  }
}

int countNaturalNum(int n) {
  int count = 0;
  for (int i = 1; i < n + 1; i++) {
    if (checkNaturalNum(i)) {
      count++;
    }
  }
  return count;
}

int main(int argc, char const *argv[]) {
  int num;
  while (std::cin >> num) {
    std::cout << countNaturalNum(num) << '\n';
  }
  return 0;
}

C++: #include <iostream>
using namespace std;

int main() {
	// your code goes here
	int nu[30];
	int num;
	int count = 0;
	int max = 29;
	for(int x=0;x<30;x++){
		nu [x] = -1;
		cin >> nu[x];
		if (nu[x] == -1) {
			max = x;
			break;
		}
	}
	for (int y=0;y<max;y++) {
		num = nu[y];
		count = 0;
		
		for (int i = 1;i<=num;i++) {
		if(i%2==0) {
			//cout <<"2: "<<i<<endl;
			count ++;
			continue;
		}
		for (int j=3;j<i;j=j+2) {
			if (i%j==0) {
				count ++;
				//cout <<"i: "<<i<<" j: "<<j<<endl;
				break;
			}
		}
	}
	cout << (num-count) <<endl;
	//cout << endl;
	}
	return 0;
}

C++: #include <iostream>
using namespace std;
typedef long long int LL;
#define MOD 1000000007

LL pow(LL m, LL n)
{
	LL res = 1,x = 1,a = m;
	while (x <= n) {
		if ((x & n) > 0) {
			res *= a;
			res %= MOD;
			a %= MOD;
		}
		a *= a;
		x <<= 1;
	}
	res %= MOD;
	return res;
}

int main()
{
	LL m, n;
	cin >> m >> n;
	cout << pow(m,n) << endl;
	return 0;
}

C++: #include <iostream>
#include <vector>
#include <numeric>
using namespace std;
int main() {
  int n;
  vector<int> v;
  while (cin >> n) {
    if (v.size() >= n + 1) {
      cout << accumulate(v.begin(), v.end() - (v.size() - (n + 1)), 0) << endl;
      continue;
    }
    v.resize(n + 1);
    fill(v.begin(), v.end(), 1);
    v[0] = 0;
    v[1] = 0;
    for (int i = 0; i * i < v.size(); ++i) {
      while (v[i] == 0) ++i;
      for (int m = i + 1; m < v.size(); ++m) {
        if (m % i == 0) {
          v[m] = 0;
        }
      }
    }
    cout << accumulate(v.begin(), v.end(), 0) << endl;
  }
  return 0;
}

C++: /*
题意：给定整数 n， 请问 n 以内有多少个素数？
思路：如果对许多整数进行素性测试，则采用 埃氏筛法 （枚举 n 以内的素数，辗转相除）
		埃氏筛法：辗转相除：
			首先，将 2 到 n 范围内的所有整数写下来。其中最小的数字 2 是素数。将表中所有 2 的倍数都划去。
			表中剩余的最小数字是 3，它不能被更小的数整除，所以是素数。再将表中所有 3 的倍数都划去。
			以此类推，如果表中剩余的最小数字是 m 时，m就是素数。然后将表中所有 m 的倍数都划去。 
			像这样反复操作，就能依次枚举 n 以内的素数。 
*/

#include <iostream>
#include <stdio.h>
using namespace std;
#define MAX_N  999999

int prime[MAX_N];		// 第 i 个素数 
bool is_prime[MAX_N];	// is_prime[i] 为 true 表示 i 为素数 

// 返回 n 以内素数的个数 
int sieve( int n )
{
	int p = 0;
	for( int i = 0; i <= n; i++ )
		is_prime[i] = true;
	
	is_prime[0] = is_prime[1] = false;
	
	for( int i = 2; i <= n; i++ )
	{
		if( is_prime[i] )
		{
			prime[p++] = i;
			for( int j = 2 * i; j <= n; j += i )
				is_prime[j] = false;				
		}	
	}
	return p;
} 

int main()
{	
	int s;
//	while (cin  >>  s)
	while (scanf("%d", &s) != EOF) 
	{
		cout << sieve(s) << endl;
	}	
	return 0;
}

C++: #include <iostream>
#include <bitset>
#include <cmath>
using namespace std;

int main()
{
	int count=0,n;

	while(cin>>n)
	{
		int prime[1000001]={0};
		prime[0]=1;
		prime[1]=1;
		for(int i=2;i<=sqrt(n);i++)
			if(prime[i]==0)
				for(int j=i+1;j<=n;j++)
					if(i%j==0)
						prime[j]=1;
		for(int i=2;i<=n;i++)
			if(prime[i]==0)
				count++;
		cout<<count<<endl;
		count=0;
	}
}

C++: #include<iostream>
#include<cstdio>
using namespace std;
const int maxn=1e6+5,maxm=1e5+5;
int fac[maxn],pri[maxm],siz;
int a[maxn];
void euler(){
	int i,j;
	siz=0;
	for (i=0;i<maxn;i++) fac[i]=i;
	for (i=2;i<maxn;i++){
		if (fac[i]==i) pri[siz++]=i;
		for (j=0;j<siz&&pri[j]<=fac[i]&&i*pri[j]<maxn;j++)
			fac[i*pri[j]]=pri[j];
	}
}
int main(){
	int i,n;
	euler();
	a[0]=a[1]=0;
	for (i=2;i<maxn;i++)
		a[i]=a[i-1]+(fac[i]==i);
	while (scanf("%d",&n)!=EOF)
		printf("%d\n",a[n]);
	return 0;
}

C++: #include<iostream>
#include<cmath>
using namespace std;
int main(){
    int n;
    while(cin >> n){
        bool prime[1000000] = {false};
        prime[1] = true;
        prime[2] = false;
        int count = 0;
      
        for(int j = 2; j * j <= n ; j++){
            if(!prime[j]){
                for (int k = 2; k*j <= n;k++){
                   prime[j*k] = true;
                }
            }
        }
        for(int i = 1;i<=n;i++){
            if(!prime[i]) count = count +1;
        }
        cout << count << endl;
    }
    return 0;
}

C++: #include <iostream>
#include <string.h>
#define _USE_MATH_DEFINES
#include <math.h>
#define MAX_N 100000

void q9() {
	bool IsPrime[MAX_N];
	memset(IsPrime, 1, sizeof(IsPrime));
	IsPrime[0] = false;
	IsPrime[1] = false;
	for (int i = 0; i < sqrt(MAX_N); i++) {
		if (!IsPrime[i]) continue;
		for (int j = i * 2; j < MAX_N; j += i) {
			IsPrime[j] = false;
		}
	}

	int NofP[MAX_N];
	NofP[0] = 0;
	for (int i = 1; i < MAX_N; i++) {
		NofP[i] = NofP[i - 1] + IsPrime[i];
	}

	int n;
	for (; cin >> n;) {
		cout << NofP[n] << endl;
	}
}

int main() {
	q9();
	return 0;
}

C++: #include <iostream>
using namespace std;

int main(){
        int prime[999999];
        bool is_prime[1000000];
        int p =0;
        int n ;
        int i;
        while(cin >> n){
        for(i=0;i<=n;i++) is_prime[i] = true;
        is_prime[0] = is_prime[1] = false;
        for(i=2;i<=n;i++){
                if(is_prime[i]){
                        prime[p++] = i;
                        for(int j=2*i;j<=n;j+=i) is_prime[j] = false;
                }
        }
        cout << p << endl;
        p = 0;
        }
return 0;
}

C++: #include<iostream>
#include<vector>
using namespace std;

int main(){
int n;
vector<int> a;
  while(cin < n){
  a.push_back(n);
  }
for(int i=0;i<a.size();i++){
  int k = 0;
  for(int j=2;j<a[i];j++){
    if(a[i]%j == 0 ) k++;
	}
  cout << k ;
 }
}

C++: #include<bits/stdc++.h>
using namespace std;

const int N = 1000000;
int data[1000000];
int n;

void Eratosthenes(){
  for(int i=0; i<N; i++){
    data[i] = 1;
  }
  for(int i=2; i<sqrt(N); i++){
    if(data[i]){
      for(int j=0; i*(j+2)<N; j++){
	data[i *(j + 2)] = 0;
      }
    }
  }
}

int main()
{
  int cnt = 0;
  Eratosthenes();
  while( cin >> n ) {
    cnt = 0;
    for(int i=2; i<=n; i++) {
      if( data[i] ) cnt++;
    }

    cout << cnt << endl;
  }
}

C++: #include<iostream>

int n;
int p;
int prime[1000000];
bool isprime[1000000];

void sieve()
{
	p = 0;
	isprime[0] = isprime[1] = false;
	for( int i = 2; i <= n; i++ ) isprime[i] = true;
	
	for( int i = 2; i <= n; i++ ){
		if( isprime[i] ){
			isprime[i] = false;
			prime[p++] = i;
			for( int j = i * 2; j <= n; j += i ) isprime[j] = false;
		}
	}

 	return;
}

int main()
{
	while( std::cin >> n ){	
		sieve();
		std::cout << p << std::endl;
	}

 	return 0;
}

C++: #include <iostream>
#include <vector>
#include <algorithm>
#define pb(a) push_back(a) 
#define rep(i,a,n) for(int i=a; i<n; i++)
using namespace std;
 
int main() {
    int n = 1000000;
    vector<int> v;
    v.pb(2);
    for(int i=3;i<=n;i+=2) {
        bool add = true;
        rep(j,0,v.size()) {
            if(v[j] * v[j] > i) break;
            if(i % v[j] == 0) {
                add = false; 
                break;
            }
        }
        if(add) v.pb(i);
    }

    int m;
    while(cin >> m) {
        cout << upper_bound(v.begin(), v.end(), m) - v.begin() << endl;
    }
    return 0;
}