Go: package main

import (
        "fmt"
        "math/big"
)

func main() {
        var x1, x2, x3, x4, y1, y2, y3, y4 big.Float
        var n int
        fmt.Scanf("%d", &n)
        for i := 0; i < n; i++ {
                fmt.Scanf("%f %f %f %f %f %f %f %f",
                        &x1, &y1, &x2, &y2, &x3, &y3, &x4, &y4)
                var lx, ly, mx, my, mul1, mul2, sub, zz big.Float
                lx.Sub(&x2, &x1)
                ly.Sub(&y2, &y1)
                mx.Sub(&x4, &x3)
                my.Sub(&y4, &y3)
                mul1.Mul(&lx, &my)
                mul2.Mul(&ly, &mx)
                sub.Sub(&mul1, &mul2)
                zz.SetFloat64(0.0)

                if sub.Cmp(&zz) == 0 {
                        fmt.Println("YES")
                } else {
                        fmt.Println("NO")
                }
        }
}

C++: #include<bits/stdc++.h>
#define P pair<int,int>
using namespace std;
 
int main(){
    int a;
    cin>>a;
    double b[12];
    for(int c=0;c<a;c++){
	for(int d=0;d<8;d++)scanf("%lf",&b[d]);
	b[8]=b[2]-b[0];
	b[9]=b[3]-b[1];
	b[10]=b[6]-b[4];
	b[11]=b[7]-b[5];
	if(b[8]==0&&b[10]==0){
	    if(b[9]==b[11])puts("YES");
	    else puts("NO");
	    return 0;
	    }
	    if(b[9]==0&&b[11]==0){
	    if(b[8]==b[10])puts("YES");
	    else puts("NO");
	    return 0;
	    }
	if(b[8]/b[9]==b[10]/b[11])puts("YES");
	else puts("NO");
	}
    }

C++: #include <iostream>

double EPS = 1e-17;
// BEGIN //////////////////////////////////////////////////////////////
int main() {
	int N;
	scanf("%d", &N);
	for (int i = 0; i < N; i++) {
		double x1, y1, x2, y2, x3, y3, x4, y4;
 		scanf("%lf%lf%lf%lf%lf%lf%lf%lf",&x1,&y1,&x2,&y2,&x3,&y3,&x4,&y4);
	 	double s = x1 - x2, t = y1 - y2, u = x3 - x4, v = y3 - y4;
	 	if (s * v == t * u) {
		 	printf("YES\n");
	 	} else {
		 	printf("NO\n");
	 }
	}

	return 0;
}

// END   //////////////////////////////////////////////////////////////

C++: #include<stdio.h>

int main(void)
{
	double a[2]={0},b[2]={0},c[2]={0},d[2]={0},x1,x2,y1,y2;
	int i;
	scanf("%d",&i);//繰り返す回数の入力

	while(i!=0)
	{
		scanf("%lf %lf %lf %lf %lf %lf %lf %lf",&a[0],&a[1],&b[0],&b[1],&c[0],&c[1],&d[0],&d[1]);//入力した数の読み込み
		x1 = b[0]-a[0];   y1 = b[1]-a[1];//傾きを求めるのに必要な数を求める
		x2 = d[0]-c[0];   y2 = d[1]-c[1];
		if(y1==0 && y2==0)//傾き0のときは０で割ることができないため
			printf("YES\n");
		else if(y1==0 || y2==0)//片方が傾き0のとき
			printf("NO\n");
		else if(x1/y2 == x2/y2)//傾きが等しい＝平衡
			printf("YES\n");
		else //傾きが等しくない＝平衡ではない
			printf("NO\n");

		i-=1;
	}
 return 0;
}

C++: #include <iostream>
#include <cmath>
using namespace std;

int main(void){

	int n;
	double x1,y1,x2,y2,x3,y3,x4,y4;
	cin>>n;
	for (int i=0; i<n; i++){
		cin>>x1>>y1>>x2>>y2>>x3>>y3>>x4>>y4;
		if(abs((y1-y2)*(x3-x4)-(y3-y4)*(x1-x2))<1e-10) cout<<"YES"<<endl;
		else cout<<"NO"<<endl;
	}

	return 0;
}

C++: 
#include <iostream>
#include <complex>
#include <cmath>

using namespace std;

typedef complex<double> Point;

int main() {
    int N;
    cin >> N;
    while(N--) {
        Point ps[4];
        for(int i = 0; i < 4; ++i) cin >> ps[i].real() >> ps[i].imag();
        Point v1 = ps[1]-ps[0], v2 = ps[3]-ps[2];
        /*
        double dot = v1.real()*v2.real() + v1.imag()*v2.imag();
        double n = norm(v1) * norm(v2);
        if(abs(dot*dot - n) < 1e-5) cout << "YES" << endl;
        else cout << "NO" << endl;
        */
        if(abs(arg(v1)-arg(v2)) < 1e-4) cout << "YES" << endl;
        else cout << "NO" << endl;
    }
    return 0;
}

C++: #include <cstdio>
#include <cmath>
#include <cstring>
#include <cstdlib>
#include <climits>
#include <ctime>
#include <queue>
#include <stack>
#include <algorithm>
#include <list>
#include <vector>
#include <set>
#include <map>
#include <iostream>
#include <deque>
#include <complex>
#include <string>
#include <iomanip>
#include <sstream>
#include <bitset>
#include <valarray>
#include <iterator>
using namespace std;
typedef long long int ll;
typedef unsigned int uint;
typedef unsigned char uchar;
typedef unsigned long long ull;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;

#define REP(i,x) for(int i=0;i<(int)(x);i++)
#define FOR(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();i++)
#define RREP(i,x) for(int i=((int)(x)-1);i>=0;i--)
#define RFOR(i,c) for(__typeof((c).rbegin())i=(c).rbegin();i!=(c).rend();i++)
#define ALL(container) container.begin(), container.end()
#define RALL(container) container.rbegin(), container.rend()
#define SZ(container) ((int)container.size())
#define mp(a,b) make_pair(a, b)
#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );

template<class T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class T> bool chmin(T &a, const T &b) { if (a>b) { a=b; return 1; } return 0; }
template<class T> ostream& operator<<(ostream &os, const vector<T> &t) {
os<<"["; FOR(it,t) {if(it!=t.begin()) os<<","; os<<*it;} os<<"]"; return os;
}
template<class T> ostream& operator<<(ostream &os, const set<T> &t) {
os<<"{"; FOR(it,t) {if(it!=t.begin()) os<<","; os<<*it;} os<<"}"; return os;
}
template<class S, class T> ostream& operator<<(ostream &os, const pair<S,T> &t) { return os<<"("<<t.first<<","<<t.second<<")";}
template<class S, class T> pair<S,T> operator+(const pair<S,T> &s, const pair<S,T> &t){ return pair<S,T>(s.first+t.first, s.second+t.second);}
template<class S, class T> pair<S,T> operator-(const pair<S,T> &s, const pair<S,T> &t){ return pair<S,T>(s.first-t.first, s.second-t.second);}

const int INF = 1<<28;
const double EPS = 1e-10;
const int MOD = 1000000007;

#define X real()
#define Y imag()

typedef complex<double> P;
struct L{
	P p1, p2;
	L(P p1, P p2):p1(p1), p2(p2){}
	L(){}
};
istream& operator>>(istream &is, P &p) {
	double x, y;
	is >> x >> y;
	p = P(x, y);
	return is;
}
inline int sig(double x) { return (abs(x) < EPS ? 0 : x > 0 ? 1 : -1); }
inline double norm(const P &p){return p.X*p.X+p.Y*p.Y;}
inline double inp(const P& a, const P& b){return (conj(a)*b).X;}
inline double outp(const P& a, const P& b){return (conj(a)*b).Y;}


int T;

int main(){
	ios::sync_with_stdio(false);
	cin >> T;
	while(T--){
		P p1, p2, p3, p4;
		cin >> p1 >> p2 >> p3 >> p4;
		p2 -= p1; p4 -= p3;
		puts(!sig(inp(p2, p4*P(0, 1))) ? "YES" : "NO");
	}
	return 0;
}