Go: package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
	"strings"
	"unicode/utf8"
)

func main() {
	scanner := bufio.NewScanner(os.Stdin)
	var strs []string
	var a, b, sum int64
	var digits int
	for scanner.Scan() {
		strs = strings.Split(scanner.Text(), " ")
		a, _ = strconv.ParseInt(strs[0], 10, 64)
		b, _ = strconv.ParseInt(strs[1], 10, 64)

		sum = a + b
		// goでlen(string)はbyte数が返る
		digits = utf8.RuneCountInString(strconv.FormatInt(sum, 10))

		fmt.Printf("%d\n", digits)
	}
}

C++: #include <bits/stdc++.h>

#define rep(i,n) for(long long int (i)=0;(i)<(int)(n);(i)++)
#define rrep(i,a,b) for(long long int i=(a);i<(b);i++)
#define rrrep(i,a,b) for(long long int i=(a);i>=(b);i--)
#define all(v) (v).begin(), (v).end()
#define pb(q) push_back(q)
#define Abs(a,b) max(a,b)-min(a,b)
#define YES(condition) if(condition){cout << "YES" << endl;}else{cout << "NO" << endl;}
#define Yes(condition) if(condition){cout << "Yes" << endl;}else{cout << "No" << endl;}
#define Cout(x) cout<<(x)<<endl
#define POSSIBLE(condition) if(condition){cout << "POSSIBLE" << endl;}else{cout << "IMPOSSIBLE" << endl;}
#define Possible(condition) if(condition){cout << "Possible" << endl;}else{cout << "Impossible" << endl;}
#define possible(condition) if(condition){cout << "possible" << endl;}else{cout << "impossible" << endl;}
#define Size(n) (n).size()

typedef long long ll;


using namespace std;

const int INF = 1e9,MOD = 1e9 + 7,ohara=1e6;
const ll LINF = 1e18;

/*---------------------------------------------------------------
long long int kaizyo(long long int hh){
    cmp=1;
    while(hh>1){
        cmp=(cmp*hh)%MOD;
        hh--;
    }
    return cmp;
}
long long int ruizyo(long long int aa, long long int bb){
    if(aa==0){
        return 1;
    }
    else if(aa%2==0){
        long long int tt=ruizyo(aa/2,bb);
        return (tt*tt)%MOD;
    }
    else{
        return (ruizyo(aa-1,bb)*bb)%MOD;
    }
}フェルマ－のア
---------------------------------------------------------------

while(x!=0){
            sum+=x%10;
          / x/=10;
        }
        各桁の和
---------------------------------------------------------------

pair<int,int> p[100000];
cin >> tmp;
p[i]=make_pair(tmp,i);
cout << p[i].second+1 << endl;//ペアの右側つまりiを出力

---------------------------------------------------------------

bool f[100001];//1000000以下の素数を調べよう！
rrep(i,2,100001){
       f[i]=false;
    }
rrep(i,2,100001){
        if(!f[i]){
            for(int j=i+i;j<=100000;j+=i){
                f[j]=true;
            }
        }
    }
    for(int i=3;i<=100000;i+=2){
        if(!f[i]){
            c[i]++;
        }
    }

---------------------------------------------------------------

long long gcd(long long aaa,long long bbb){
    if(bbb==0){
        return aaa;
    }
    return gcd(bbb,aaa%bbb);
}
 
long long lcm(long long aaa,long long bbb){
    long long g = gcd(aaa,bbb);
    return aaa/g * bbb;
}左から最大公約数と最小公倍数


---------------------------------------------------------------

long long int prime_cnt[10000];
       for(int i=2;i*i<=n;i++){
           while(n%i==0){
               n/=i;
               prime_cnt[i]+=1;
           }
           if(n>1){
               prime_cnt[n]+=1;
               break;
           }
      }ある数nを素因数分解しましょう

---------------------------------------------------------------
debug:
cout<<"i: "<<i<<" j: "<<j<<" cnt: "<<cnt<<"\n";

---------------------------------------------------------------*/

long long int n,cnt=0,ans=0,a,b,c,d,cmp,cmpp,m,h,w,x,y,sum=0,pos;
int dy[]={1,0,-1,0};
int dx[]={0,1,0,-1};
string alph("abcdefghijklmnopqrstuvwxyz"),s,co;
bool fl=true;
struct edge{int to,cost;};

//-------------------------↓↓↓↓↓↓------------------------

int main(void){
       cin.tie(0);
    ios::sync_with_stdio(false);

      
       while(1){
           a=-1;b=-1;
           cin>>a>>b;
           pos=a+b;
           if(a==-1&&b==-1)break;
           s=to_string(pos);
          // co=to_string(b);
           Cout(Size(s));
       }
       
return 0;
}

C++: #include <iostream>
#include <sstream>
#include <string>
using namespace std;
int main(void){
	int n , i , j , k ;
	for( i=1 ; i<=3 ; i++ ){
		cin >> j >> k ;
		int x = j+k;
		stringstream str;
		str << x ;
		string st = str.str();
		cout << st.size() << endl;
	}	
}

C++: #include<iostream>
using namespace std;
int main(){
    int a,b,work;
    int count = 1;
    while(cin >> a >> b){
        work = a + b;
        while(work != 0){
            if(work / 10 != 0){
                 count++;
            }else{
                cout << count << endl;
            }
            count = 1;
        }
    }
    return 0;
}

C++: #include<iostream>
using namespace std;
int main(){
int a,b,i,c=0;
while(1){
cin>>a>>b;
a=a+b;
for(i=1;i<10000000000;i*=10){
	if(a/i==0)break;
	c++;
}

cout<<c<<endl;
}
return 0;
}

C++: #include<bits/stdc++.h>
using namespace std;
int main(){
  int a,b;
  cin>>a>>b;
  a+=b;
  int t=0;
  while(a>0){
    a/=10;
    t++;
  }
  cout<<t<<endl;
}

C++: #include <iostream>
#include <cmath>

using namespace std;

int main(){
	int a,b;

	while(cin>>a>>b){
		cout << (int)log10((double)(a+b))+1 << endl;
	}
	return 0;
}

C++: #include <iostream>
using namespace std;
 
int main()
{
    int sum, a, b, i,t;
     
    for(t = 0 ; t < 3 ; t++) 
   {
      cin >> a >> b;
 
      sum = a + b;
      i = 1;
      while(1)
      {
          sum = sum / 10;
 
          if(sum == 0)
             break;
 
          i++;
      }
 
      cout << i << endl;
   }
 
   return 0;
}

C++: #include<iostream>
using namespace std;

int main(){
    int i, a, b;
    int j[200];
    for(i=0; i<3; i++){
        cin>>a>>b;
        j[i]=a+b;
    }
    for(i=0; i<3; i++){
        if(a>=0 and b<= 1000000){
            cout<<j[i]<<endl;
        }
    }
    return 0;
}

C++: #include<iostream>
using namespace std;
int main()
	{
		int a, b, sum, result = 0;
		while (scanf("%d %d", &a, &b) != EOF)
		{
			sum = a + b;
			while (sum > 0){
				sum /= 10;
				result++;
			}
			cout << result<<endl;
		}

		return 0;
	
}

C++: #include <iostream>
using namespace std;

int main()
{
	int a, b;

	while (cin >> a >> b) {
		int s = a + b, t = 0;

		while (s > 0) {
			s /= 10;
			t++;
		}

		cout << t << endl;
	}

	return 0;
}

C++: #include<iostream>
using namespace std;
int main(){
long i,j,a,b,c;
for(i=0;i<200;i++){
cin>>a>>b;
if(cin.eof())break;
c=a+b;
for(j=0;j<6;j++){c/=10;if(c==0)break;}
cout<<j+1<<endl;
}
return 0;
}