vietnam-crisis
Source: hackerearth
Difficulty: UNKNOWN_DIFFICULTY

In 1945, Vietnam had a huge famine because of which thousands of Vietnamese people were dying everyday.
The Soviet Union wanted to help the Vietnamese. They were regualrly sending food supplies to Vietnam. The
Vietnamese officials decided that they would provide food to the children first. (Food supplies included 
food for an infant to very old man). Also food would be provided in increasing order of age.

Vietnamese officials have reached a village and have employed you to form a line of the people who will be getting
food in the order as they require (that is, in increasing order of age). When the officials landed, a line already existed 
but it was not in increasing order. You are required to make it as per the officials wishes.

The population of the village is very large (upto 20000000). Typically, in other countries, this much population would
constitute a town.

Input:

There are multiple test cases. Each case starts with an integer N, the total number of people. In the next line, there are N integers indicating the ages. Input is terminated with a case where N = 0 . This case should not be processed.

Output:

For each case, print a line with N space separated integers in the increasing order of age.

Note: Use faster IO since some test cases can be very large

Constraints:

1 ≤ T ≤ 10

1 ≤ N ≤ 20000000

All ages are in integers only

SAMPLE INPUT
13
78 12 60 78 68 37 57 40 49 13 94 91 89 
0

SAMPLE OUTPUT
12 13 37 40 49 57 60 68 78 78 89 91 94


'''
# Read input from stdin and provide input before running code

name = raw_input('What is your name?\n')
print 'Hi, %s.' % name
'''
#print 'Hello World!'
n=eval(input())
while(n!=0):
	l=[int(i) for i in input().split()]
	l.sort()
	print(" ".join(str(i) for i in l))
	n=eval(input())


'''
# Read input from stdin and provide input before running code

name = raw_input('What is your name?\n')
print 'Hi, %s.' % name
'''
#print 'Hello World!'
n=eval(input())
while(n!=0):
	l=[int(i) for i in input().split()]
	l.sort()
	print(" ".join(str(i) for i in l))
	n=eval(input())