hard-job
Source: hackerearth
Difficulty: HARD

You are given a permutation of integers from 1 to N (very unusual :D). The only thing you should do is to process M queries. Each query has 2 parameters: number X from 1 to N and lowercase latin letter Y (either 'l' or 'r'). You do the following:
Calculate distances from the position of the number X to the left end and to the right end of the permutation. Let's call minimum of them accessibleness.
Erase number X from it's current position. If parameter Y is 'l' then insert X the very beginning of the permutation. Otherwise insert X after the last element of the permutation. 

Please find sum of accessibleness over all queries.

Input 
The first line contains two space-separated integers: N and M. The second line contains N space-separated integers: the initial permutation. After this M lines follow containing 2 space-separated parameters each in the way it's described in the statement above.

Output 
Output one number - answer for the question.

Constraints 
 0 < N, M  ≤ 500 000
 0 < N, M  ≤ 2 000 in 35 % of the test data.
 0 < N, M  ≤ 70 000 in 70 % of the test data.

SAMPLE INPUT
4 3
3 1 4 2
3 r
2 r
1 l

SAMPLE OUTPUT
1

Explanation

Permutation before the 1st query: 3 1 4 2. 3 has accessibleness  0. 
Permutation before the 2nd query: 1 4 2 3. 2 has accessibleness  1. 
Permutation before the 3rd query: 1 4 3 2. 1 has accessibleness  0. 
So the sum over all queries is 1.