prakhar-and-aavartanland
Source: hackerearth
Difficulty: UNKNOWN_DIFFICULTY

Prakhar lives in Avartanland. Avartanland consists of N vertices and N-1 directed edges. i-th edge is a directed edge either from i-th vertex to i+1-th vertex or from i+1-th vertex to i-th vertex. You are given M Queries. 

Queries are 2 types:

1 l r - Reverse the direction of the edges between l-th vertex and r-th vertex.
2 f t - Output the minimum number of edges which you have to reverse the direction to arrive from f to t.  

Input:
The first line contains two integers N, the number of vertices and M, the number of queries. The next line will contains N-1 characters which represent the direction of the edges. i-th character is either '>' or '<': '>' represents that only i -> i+1 is valid, '<' represents that only i+1 -> i is valid. The following M lines will each contain a query like the ones mentioned above.

Output:
For query 2, print the answer in a new line.

Constraints:
2< = N ≤ 200000
1 ≤ M ≤ 200000
1 ≤ l < r ≤ N
1 ≤ f , t ≤ N  

SAMPLE INPUT
6 6
>><<>
2 1 6
2 6 1
1 3 5
2 1 6
1 1 6
2 6 1

SAMPLE OUTPUT
2
3
0
0

Explanation

In the sample testcase the graph is like this, 1->2->3<-4<-5->6. At the first query,Prakhar have to reverse the direction of 3rd edge and 4th edges to arrive from 1st vertex to 6th vertex. Second, Prakhar have to reverse the direction of 1st, 2nd, and 5th edges to arrive from 6th vertex to 1st vertex. Third, Reverse the direction of the edges between 3rd vertex and 5th vertex. After the query, graph is like this, 1->2->3->4->5->6. Fourth, Prakhar don't have to reverse the direction of any edge. Fifth, Reverse the direction of the edges between 1st vertex and 6th vertex. After the query, graph is like this, 1<-2<-3<-4<-5<-6. Sixth, Prakhar don't have to reverse the direction of any edge.