power-matrix
Source: hackerearth
Difficulty: UNKNOWN_DIFFICULTY

You are given a square matrix M and a positive integer N. You will have to compute M raised to the power N. (that is, M multiplied with itself N times.)

Input

First line of input is T ( number of test-cases) .

First line of each test-case contains two integer M , N where M is size of square array that you have to exponent and N is the power to which you have to exponent .

Next M lines describe the input matrix. Each line contains exactly M elements separated  by single space .

Output

Output M line corresponding to each row of resultant matrix .Each line must have M integers where jth element of ith line is jth element of resultant matrix taken modulo with 1000000007 (10^9+7).

Elements of each row of resultant matrix must be separated by single space.

Conatraints

1 ≤ T ≤ 10

1 ≤ M ≤ 50

1 ≤ N ≤ 100000

0 ≤ element of input matrix ≤ 10^9

SAMPLE INPUT
2
2 3
1 0 
1 1 
3 3
1 0 4 
1 2 2 
0 4 4

SAMPLE OUTPUT
1 0 
3 1 
17 112 116 
15 88 100 
28 144 160


def matrix_mult(A, B , m):
	C = [[0 for x in range(m)] for x in range(m)]
	for i in range(m):
		for j in range(m):
			for k in range(m):
				C[i][k] = (C[i][k] + A[i][j] * B[j][k]) % 1000000007
	return C

def fast_exponentiation(A, m,n):
	if n == 1:
		return A
	else:
		if n % 2 == 0:
			A1 = fast_exponentiation(A,m, n/2)
			return matrix_mult(A1, A1 , m)
		else:
			A1 = fast_exponentiation(A,m, n - 1)
			return matrix_mult(A, A1 , m)


t=eval(input())
while t:
	t-=1
	m,n = [int(x) for x in input().split()]
	mat = []
	for x in range(0,m):
			a = [int(x) for x in input().split()]
			mat.append(a)
	res = fast_exponentiation(mat,m,n)
	for x in res:
		for y in x:
			print((y), end=' ')
		print()