goris-crush
Source: hackerearth
Difficulty: EASY

Our web developer Gori is having this huge crush on a girl of his batch. But he is very afraid of proposing her. He does not know whether to do it or not. He told this to his best friend Micro, who is an astrologer. Micro came up with an idea to help Gori. He is having a list of N fortune numbers. He asked Gori two numbers , say a & b (a ≤ b). He also asked two numbers from Gori's crush, say c & d (c ≤ d) (The numbers a, b, c & d do not necessarily belong to the list). Then he made two lists from fortune numbers. One having fortune numbers which lie between a & b (inclusive) and one having fortune numbers which lie between c & d (inclusive). Then he counted the number of same elements in the two lists and called it the Matching factor, say m. Micro has a special number say k, now if m ≥ k, then Gori should propose his crush, otherwise not.
But Gori was not satisified with just one result. So they followed above procedure several times for different values of a, b , c & d and Micro also kept updating the list of fortune numbers. This became a hectic task. So they asked you to make a program for it.

Input:
The first line consists of three space separated integers N, Q and k.
Second line consists of N space separated integers, the initial list of fortune numbers.
The following Q lines contain Q queries. There are two types of queries:
i) 0 x y, replace xth element in the list by y.
ii) 1 a b c d, print answer for given value of a, b, c, d

Output:
For each query of type 1, print "Propose" (without quotes) in a new line if for given a, b, c & d value of matching factor, m ≥ k, otherwise print "Do not propose" (without quotes) in a new line.

Constraints:
1 ≤ N, Q, k ≤ 10^5
1 ≤ Fortune Numbers ≤ 10^9
1 ≤ x ≤ N
1 ≤ a, b, c, d,  y ≤ 10^9

SAMPLE INPUT
5 3 3 
1 2 3 4 5
1 2 3 3 7
0 5 6
1 1 6 3 7SAMPLE OUTPUT
Do not propose
ProposeExplanation

For first query the lists are (2,3) and (3,4,5). Common element is 3 only. So matching factor = 1 which is less than given k.
So answer is Do not propose.
Second query updates list to 1 2 3 4 6.
For third query the lists are (1,2,3,4,6) and (3,4,6). Common elements are 3, 4 & 6. So matching factor = 3 which is equal to given k. So answer is Propose.