ShaysXIA/CodeInsightBench huggingface dataset:
Problem: 2062C - Cirno and Operations
Language: java

Solution 1 (runtime: 312 ms):
// package main;
import java.util.Scanner;
import java.io.PrintWriter;
import java.util.List;
import java.util.ArrayList;


// 100 * 50

public class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        PrintWriter out = new PrintWriter(System.out);

        int t = scanner.nextInt();
        for (int i = 0; i < t; i++) {
            int n = scanner.nextInt();
            List<Long> ar = new ArrayList<>();

            for (int j = 0; j < n; j++) {
                ar.add(scanner.nextLong());
            }

            long res = sum(ar);

            while (ar.size() > 1) {
                res = Math.max(res, sum(ar));

                List<Long> newAr = new ArrayList<>();
                for (int j = 1; j < ar.size(); j++) {
                    newAr.add(ar.get(j) - ar.get(j - 1));
                }
                res = Math.max(res, Math.abs(sum(newAr)));
                ar = newAr;
            }
            out.println(res);
        }
        out.flush();
        out.close();
        scanner.close();
    }

    private static long sum(List<Long> ar) {
        long sum = 0;
        for (long a : ar) {
            sum += a;
        }
        return sum;
    }
}


Solution 2 (runtime: 264 ms):
import java.util.Scanner;

public class Main
{
    private static void solve(Scanner in)
    {
        int n = in.nextInt();

        long[] a = new long[n];

        for (int i = 0; i < n; i++)
            a[i] = in.nextInt();

        long ans = 0;

        for (long el : a)
            ans += el;

        for (int it = 1; it < n; it++)
        {
            ans = Math.max(ans, Math.abs(a[n - it] - a[0]));

            for (int i = 0; i + it < n; i++)
                a[i] = a[i + 1] - a[i];
        }

        System.out.println(ans);
    }

    public static void main (String[] args)
    {
        Scanner in = new Scanner(System.in);

        int t = in.nextInt();

        for (int test = 0; test < t; test++)
            solve(in);
        
        in.close();
    }
}
Problem: 2060D - Subtract Min Sort
Language: java

Solution 1 (runtime: 702 ms):
import java.util.*;
public class subtractminsort {
    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        int t=sc.nextInt();
        for(int l=0;l<t;l++){
            int n=sc.nextInt();
            int arr[]=new int[n];
            for(int i=0;i<n;i++){
                arr[i]=sc.nextInt();
            }
            String res="YES";
            int a=Math.min(arr[0],arr[1]);
            arr[0]-=a;
            arr[1]-=a;
            if(arr[0]>arr[1]){
                res="NO";
            }
            if(res=="YES"){
                for(int i=1;i<n-1;i++){
                int min=Math.min(arr[i],arr[i+1]);
                arr[i]-=min;
                arr[i+1]-=min;
                if(arr[i-1]>arr[i]){
                    res="NO";
                    break;
                }
            }
            if(arr[n-2]>arr[n-1]){
                res="NO";
            }
        }
            System.out.println(res);
          
        }
        sc.close();
    }
}


Solution 2 (runtime: 499 ms):
import java.util.*;



public class Main {

    public static void main(String[] args) {

        Scanner sc = new Scanner(System.in);

        int t = sc.nextInt(); // Number of test cases

        

        while (t-- > 0) {

            int n = sc.nextInt(); // Length of sequence

            int[] a = new int[n];

            

            for (int i = 0; i < n; i++) {

                a[i] = sc.nextInt();

            }



            // Simulating the operation

            boolean possible = true;

            for (int i = 0; i < n - 1; i++) {

                int minValue = Math.min(a[i], a[i + 1]);

                a[i] -= minValue;

                a[i + 1] -= minValue;

            }



            // Check if the array is now non-decreasing

            for (int i = 0; i < n - 1; i++) {

                if (a[i] > a[i + 1]) {

                    possible = false;

                    break;

                }

            }



            System.out.println(possible ? "YES" : "NO");

        }



        sc.close();

    }

}
Problem: 2050E - Three Strings
Language: java

Solution 1 (runtime: 327 ms):
import java.util.*;

public class Main {
    public static void main(String[] args) {
        Scanner sc= new Scanner(System.in);
        int tes=sc.nextInt();
        StringBuilder sb=new StringBuilder();
        label:while(tes-->0){
            String a=sc.next(),b=sc.next(),c=sc.next();
            Integer dp[][]=new Integer[a.length()+1][b.length()+1];
            System.out.println(c.length()-memo(a,b,c,0,0,dp));
        }
        System.out.println(sb);
    }
    public static int memo(String a,String b,String c,int i,int j,Integer dp[][]){
        if(i==a.length() && j==b.length()) return 0;
        int ans=0;
        if(dp[i][j]!=null) return dp[i][j];
        if(i<a.length()) ans=Math.max(ans,((a.charAt(i)==c.charAt(i+j))?1:0)+memo(a,b,c,i+1,j,dp));
        if(j<b.length()) ans=Math.max(ans,((b.charAt(j)==c.charAt(i+j))?1:0)+memo(a,b,c,i,j+1,dp));
        //System.out.println(i+" "+j+" "+ans);
        return dp[i][j]=ans;
    }
}

Solution 2 (runtime: 327 ms):
import java.util.Scanner;



public class Main{

    public static void main(String[] args) {

        Scanner scanner = new Scanner(System.in);

        int t = scanner.nextInt();

        scanner.nextLine(); // Consume the newline



        for (int i = 0; i < t; i++) {

            String a = scanner.nextLine();

            String b = scanner.nextLine();

            String c = scanner.nextLine();



            System.out.println(minChanges(a, b, c));

        }

    }



    private static int minChanges(String a, String b, String c) {

        int lenA = a.length();

        int lenB = b.length();

        int lenC = c.length();



        int[][] dp = new int[lenA + 1][lenB + 1];

        for (int i = 0; i <= lenA; i++) {

            for (int j = 0; j <= lenB; j++) {

                dp[i][j] = Integer.MAX_VALUE;

            }

        }

        dp[0][0] = 0;



        for (int i = 0; i <= lenA; i++) {

            for (int j = 0; j <= lenB; j++) {

                if (i > 0) {

                    dp[i][j] = Math.min(dp[i][j], dp[i - 1][j] + (a.charAt(i - 1) != c.charAt(i + j - 1) ? 1 : 0));

                }

                if (j > 0) {

                    dp[i][j] = Math.min(dp[i][j], dp[i][j - 1] + (b.charAt(j - 1) != c.charAt(i + j - 1) ? 1 : 0));

                }

            }

        }



        return dp[lenA][lenB];

    }

}





// a9JHz5LCXExByemFvIG
Problem: 2057C - Trip to the Olympiad
Language: java

Solution 1 (runtime: 249 ms):
import java.util.*;
public class triptotheolympiad {
    public static void main(String[] arg){
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();
        for(int testCase = 0; testCase < t; testCase++){
            long l = sc.nextLong();
            long r = sc.nextLong();

            String lBinary = Long.toBinaryString(l);
            String rBinary = Long.toBinaryString(r);

            int bit = -1;
            if(lBinary.length() < rBinary.length()){
                bit = rBinary.length() - 1;
            }else{
                //System.out.println(lBinary + " " + rBinary);
                for(int i = 0; i < rBinary.length(); i++){
                    if(lBinary.charAt(i) == rBinary.charAt(i)){
                        continue;
                    }else{
                        bit = rBinary.length() - i - 1;
                        break;
                    }
                }
            }

            long val = (long) Math.pow(2, bit);
            long firstNumber = (r / val) * val;

            long secondNumber = firstNumber - 1;
            long thirdNumber = 0;
            if(firstNumber == r){
                thirdNumber = r - 2;
            }else{
                thirdNumber = r;
            }

            System.out.println(firstNumber + " " + secondNumber + " " + thirdNumber);
        }

    }
}


Solution 2 (runtime: 358 ms):
import java.util.*;
import java.lang.*;
import java.math.BigInteger;
import java.io.*;
public class cf{
    // public static long gcd(long a,long b){
    //     while(a!=0 && b!=0){
    //         if(a<b){
    //             b=b%a;
    //         }else{
    //             a=a%b;
    //         }
    //     }
    //     if(a!=0){
    //         return a;
    //     }else{
    //         return b;
    //     }
    // }  
    // public static long lcm(long a,long b){
    //     return (a/gcd(a,b))*b;
    // }

    public static void main(String args[]){
        Scanner sc=new Scanner(System.in);
        int tsts=sc.nextInt();
        for(int t=0;t<tsts;t++){
            int l=sc.nextInt();
            int r=sc.nextInt();
            // int a=sc.nextInt();
            // int b=sc.nextInt();
            // int r2=sc.nextInt();
            // StringBuilder s=new StringBuilder(sc.next());
            // String a=sc.next();
            // String b=sc.next();
            // String c=sc.next();

            // int[] a=new int[n];
            // for(int i=0;i<n;i++){
            //     a[i]=sc.nextInt();
            // }
            // int[] b=new int[n];
            // for(int i=0;i<n;i++){
            //     b[i]=sc.nextInt();
            // }
            // long x=sc.nextLong();
            // long m=sc.nextLong();
            // long r=sc.nextInt();
            // long c=sc.nextInt();
            int n=l^r;
            int i=0;
            while(n>0){
                n=n>>1;
                i++;
            }
            i--;
            int a=l|((1<<i)-1),b=a+1,c=(a==l)?r:l;
            System.out.println(a+" "+b+" "+c);
        }    
    }
}
Problem: 2050D - Digital string maximization
Language: java

Solution 1 (runtime: 234 ms):
import java.util.Scanner;

public class D_2050 {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();
        sc.nextLine();
        while (t-- > 0) {
            String s = sc.nextLine();
            char[] arr = s.toCharArray();
            int swapcount = 1;
            int ans = 0;
            while (swapcount != 0) {
                int sw = 0;
                for (int i = 1; i < arr.length; i++) {
                    char a = (char) (arr[i] - 1);
                    char b = arr[i - 1];
                    if ((arr[i] != '1' || arr[i] != '0') && a - b > 0) {
                        if (arr[i] > arr[i - 1]) {
                            swap(i - 1, i, arr);
                            sw++;
                        }
                    }
                }

                if (sw == 0) {
                    break;
                }
            }
            System.out.println(new String(arr));
        }
    }

    public static void swap(int i, int j, char[] arr) {
        arr[j] = (char) (arr[j] - 1);
        char t = arr[i];
        arr[i] = arr[j];
        arr[j] = t;
    }
}

Solution 2 (runtime: 343 ms):
import java.util.*;



public class Main {

public static void main(String[] args) {

Scanner sc = new Scanner(System.in);

int t = sc.nextInt();



while (t-- > 0) {

char[] sb = sc.next().toCharArray(); // Using char array for efficiency

int n = sb.length;



int index = 1;

while (index < n) {

if (sb[index] != '0') {

int toPlace = index - 1;

int subtract = 1;



while (toPlace >= 0 && (sb[index] - '0') - subtract > (sb[toPlace] - '0')) {

if (toPlace == 0) break;

toPlace--;

subtract++;

}



if ((sb[index] - '0') - subtract <= (sb[toPlace] - '0')) {

toPlace++;

subtract--;

}



if (toPlace != index) {

char res = (char) ((sb[index] - '0' - subtract) + '0');



// Shift elements manually instead of using `add()` and `remove()`

for (int j = index; j > toPlace; j--) {

sb[j] = sb[j - 1];

}

sb[toPlace] = res;

}

}

index++;

}



System.out.println(new String(sb)); // Fast output

}

}

}
Problem: 2060D - Subtract Min Sort
Language: java

Solution 1 (runtime: 656 ms):
import java.util.*;
public class subtractMinSort {
    public static void main(String[] args) {

        Scanner sc = new Scanner(System.in);
        int t=sc.nextInt();
        while(t-->0){

            int n=sc.nextInt();
            int[] arr = new int[n];

            for(int i=0;i<n;i++){
                arr[i]=sc.nextInt();
            }

            boolean flag = true;
            for(int i=0;i<n-1;i++){
                int min = Math.min(arr[i],arr[i+1]);
                arr[i] = arr[i]-min;
                arr[i+1] = arr[i+1]-min;
            }

            for(int i=0;i<n-1;i++){
                if(arr[i]>arr[i+1]){
                    System.out.println("NO");
                    flag = false;
                    break;
                }
            }
            if(flag){
                System.out.println("YES");
            }


        }
    }
}

Solution 2 (runtime: 640 ms):
import java.util.*;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();

        outer :
        while(t>0){
            int n = sc.nextInt();

            int[] nums = new int[n];

            for(int i=0;i<n;i++){
                nums[i] = sc.nextInt();
            }

            for(int i = 1 ; i < n ; i++){
                int min = Math.min(nums[i],nums[i-1]);
                nums[i] = nums[i] - min;
                nums[i-1] = nums[i-1] - min;

                if(nums[i-1] > nums[i] ) {
                    System.out.println("NO");
                    t--;
                    continue outer;
                }
            }
            System.out.println("YES");
            t--;
        }
    }
}
Problem: 2060D - Subtract Min Sort
Language: java

Solution 1 (runtime: 484 ms):
import java.util.*;
public class Fi {
    public static void main(String[] args){
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();
        for(int o=0;o<t;o++){
            int n = sc.nextInt();
            int result = 1;
            int arr[] = new int[n];
            for(int i=0;i<n;i++){
                arr[i] = sc.nextInt();
                if(i>0 && arr[i-1]>arr[i]){
                    result = 0;
                }else if(i>0 && arr[i-1]<=arr[i]){
                    arr[i] -=arr[i-1];
                    arr[i-1] = 0;
                }
            }
            if(result==0){
                System.out.println("NO");
            }else{
                System.out.println("YES");
            }
          
        }
    }
}
//4
//1 4 3 2

Solution 2 (runtime: 656 ms):
import java.util.*;
public class subtractMinSort {
    public static void main(String[] args) {

        Scanner sc = new Scanner(System.in);
        int t=sc.nextInt();
        while(t-->0){

            int n=sc.nextInt();
            int[] arr = new int[n];

            for(int i=0;i<n;i++){
                arr[i]=sc.nextInt();
            }

            boolean flag = true;
            for(int i=0;i<n-1;i++){
                int min = Math.min(arr[i],arr[i+1]);
                arr[i] = arr[i]-min;
                arr[i+1] = arr[i+1]-min;
            }

            for(int i=0;i<n-1;i++){
                if(arr[i]>arr[i+1]){
                    System.out.println("NO");
                    flag = false;
                    break;
                }
            }
            if(flag){
                System.out.println("YES");
            }


        }
    }
}
Problem: 2057C - Trip to the Olympiad
Language: java

Solution 1 (runtime: 265 ms):
#include<bits/stdc++.h>
using namespace std;

#define int long long

using ll = long long;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
using vi = vector<int>;
using vll = vector<ll>;
using vbl = vector<bool>;
using vpii = vector<pii>;
template<class T> using vv = vector<vector<T>>;

#define pb emplace_back
#define F first
#define S second
#define all(v) v.begin(), v.end()
#define siz(v) (int)(size(v))

#define rep(i, a, b) for (int i = (a); i <= (b); i++)
#define rrep(i, a, b) for (int i = (a); i >= (b); i--)
#define rept(a) rep(_, 1, a)

#define watch(x) cout << (#x) << ':' << (x) << '\n';
#define watch2(x, y) cout << (#x) << ':' << (x) << ',' << (#y) << ':' << (y) << '\n';

template<class T> bool ckmin(T &a, const T &b) { return b < a ? a = b, 1 : 0; }
template<class T> bool ckmax(T &a, const T &b) { return a < b ? a = b, 1 : 0; }

template<typename Ostream, typename ...Ts>
Ostream& operator<<(Ostream& os,  const pair<Ts...>& p){
	return os << '{' << p.first << ',' << p.second << '}';
}
template<typename Ostream, typename Cont>
typename enable_if<is_same<Ostream,ostream>::value, Ostream&>::type operator<<(Ostream& os,  const Cont& v){
	for (auto &x : v) os << x << ' ';
	return os;
}

const int inf = 1e9;
const ll llinf = 4e18;

void orz()
{
    int l, r; cin >> l >> r;
    rrep(i, 30, 0){
        if ((l>>i)^(r>>i)){
            cout << (1<<i) << ' ' << ((1<<i)-1) << ' ' << ((1<<i)-2 < l ? (1<<i)+1 : (1<<i)-2) << '\n';
            return;
        }
    }
}

int32_t main()
{
    ios::sync_with_stdio(false), cin.tie(nullptr);
    cin.exceptions(cin.failbit);

    int t = 1; cin >> t;
    while (t--) orz();

    return 0;
}


Solution 2 (runtime: 281 ms):
import java.util.*;
public class ProblemC {

    static long mod = (long)(1e9+7);

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();
        while(t-->0) {
            int l = sc.nextInt();
            int r = sc.nextInt();
       
            int num = 0;
            for(int i =30;i>=0;i--) {
                if(((l&(1<<i))>0 && (r&(1<<i))>0)) {
                    num|=(1<<i);
                } else if(((l&(1<<i))==0 && (r&(1<<i))==0)) {
                    continue;
                } else {
                    num|=(1<<i);
                    break;
                }
            }

            int a = num;
            int b = num-1;
            int c = (l==b) ? r : l;
            System.out.println(a+" "+b+" "+c);
        }
    }
}
Problem: 2050D - Digital string maximization
Language: java

Solution 1 (runtime: 312 ms):
import java.util.*;
public class Main{
    public static void main(String[] args){
        Scanner sc=new Scanner(System.in);
        int t=sc.nextInt();
        while(t-->0){
            String s=sc.next();
            char[] res=s.toCharArray();
            for(int i=1;i<s.length();i++){
                if(res[i]>res[i-1]){
                    while(i>0 && res[i]>res[i-1] && res[i]-res[i-1]>1){
                        res[i]--;
                        char temp=res[i];
                        res[i]=res[i-1];
                        res[i-1]=temp;
                        i--;
                    }
                }
            }
            String str=new String(res);
            System.out.println(str);
        }
        sc.close();
    }
}

Solution 2 (runtime: 281 ms):
import java.io.*;
import java.util.*;

public class DigitalStringMaximization {
    public static void main(String[] args) throws IOException {
        BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer tokenizer = new StringTokenizer(in.readLine());

        int t = Integer.parseInt(tokenizer.nextToken());

        while (t-- > 0) {
            tokenizer = new StringTokenizer(in.readLine());
            char[] c = tokenizer.nextToken().toCharArray();

            for (int i = c.length - 1; i > 0; i--) {
                if (c[i] > c[i - 1] + 1) {
                    operation(c, i);
                    i += 9;
                    if (i > c.length) {
                        i = c.length;
                    }
                }
            }

            System.out.println(new String(c));
        }
    }

//    public static int findLast(char[] c) {
//        for (int i = c.length - 1; i > 0; i--) {
//            if (c[i] > c[i - 1] + 1) {
//                return i + 1;
//            }
//        }
//        return c.length;
//    }

    public static void operation(char[] c, int i) {
        int cur = c[i];
        int left = c[i - 1];
        c[i - 1] = (char) (cur - 1);
        c[i] = (char) left;
    }
}
Problem: 2057C - Trip to the Olympiad
Language: java

Solution 1 (runtime: 374 ms):
import java.util.*;

public class Solution {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt(); // number of test cases
        // int t = 1;
        while (t-- > 0) {
            long l = sc.nextLong();
            long r = sc.nextLong();

            long ans = 0;
            long a = 0;
            long b = 0;
            // long c = 0;
            for(int i = 30;i>=0;i--) {
                long and1 = r & (1 << i);
                long and2 = l & (1 << i);

                if(and1 == and2) {
                    if(and1 >= 1) ans = ans + (1 << i);
                } else {
                    a = ans + (1 << i);
                    b = a - 1;
                    break;
                }
            }
            long c = r;
            if(a == r) {
                c = l;
            }
            System.out.println(a + " " + b + " " + c);
        }
        
    }
}



Solution 2 (runtime: 281 ms):
import java.util.*;
public class ProblemC {

    static long mod = (long)(1e9+7);

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();
        while(t-->0) {
            int l = sc.nextInt();
            int r = sc.nextInt();
       
            int num = 0;
            for(int i =30;i>=0;i--) {
                if(((l&(1<<i))>0 && (r&(1<<i))>0)) {
                    num|=(1<<i);
                } else if(((l&(1<<i))==0 && (r&(1<<i))==0)) {
                    continue;
                } else {
                    num|=(1<<i);
                    break;
                }
            }

            int a = num;
            int b = num-1;
            int c = (l==b) ? r : l;
            System.out.println(a+" "+b+" "+c);
        }
    }
}