Problem: 2063B - Subsequence Update
Language: java

Solution 1 (runtime: 343 ms):
import java.util.*;

public class Solution {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();  // number of test cases
        while (t-- > 0) {
            // Read n, l, r
            int n = sc.nextInt();
            int l = sc.nextInt();  // 1-based index
            int r = sc.nextInt();  // 1-based index

            // Read array arr
            long[] arr = new long[n + 1];  // Using long[] for larger values, and n+1 to handle 1-based indexing
            for (int i = 1; i <= n; i++) {
                arr[i] = sc.nextLong();
            }

            // Step 1: Calculate the sum for the range [l, r]
            long initialSum = 0;
            for (int i = l; i <= r; i++) {
                initialSum += arr[i];
            }
            long min = initialSum;  // Store the initial sum as the minimum

            // Step 2: Find the smallest `r - l + 1` elements from [1, r]
            List<Long> prefix = new ArrayList<>();
            for (int i = 1; i <= r; i++) {
                prefix.add(arr[i]);
            }
            Collections.sort(prefix);
            long prefixSum = 0;
            // Sum the smallest `r - l + 1` elements from the sorted prefix
            for (int i = 0; i < r - l + 1; i++) {
                prefixSum += prefix.get(i);
            }
            min = Math.min(min, prefixSum);  // Update the minimum sum

            // Step 3: Find the smallest `r - l + 1` elements from [l, n]
            List<Long> suffix = new ArrayList<>();
            for (int i = l; i <= n; i++) {
                suffix.add(arr[i]);
            }
            Collections.sort(suffix);
            long suffixSum = 0;
            // Sum the smallest `r - l + 1` elements from the sorted suffix
            for (int i = 0; i < r - l + 1; i++) {
                suffixSum += suffix.get(i);
            }
            min = Math.min(min, suffixSum);  // Update the minimum sum

            // Output the result for the current test case
            System.out.println(min);
        }
    }
}


Solution 2 (runtime: 453 ms):
import java.util.*;



public class B_Subsequence_Update{

    public static void main(String[] args) {

        Scanner s = new Scanner(System.in);

        int t = s.nextInt();

        while (t-->0){

            int n = s.nextInt();

            int l = s.nextInt();

            int r = s.nextInt();

            int[] arr = new int[n];

            for (int i=0;i<n;++i) arr[i] = s.nextInt();

            PriorityQueue<Integer> maxpq = new PriorityQueue<>((a,b)->b-a);

            PriorityQueue<Integer> minpql = new PriorityQueue<>();

            PriorityQueue<Integer> minpqr = new PriorityQueue<>();

            // ArrayList<Integer> raw = new ArrayList<>();

            long grr = 0;

            for (int i=l-1;i<r;++i) {

                maxpq.add(arr[i]);

                grr += arr[i];

            }

            for (int i=0;i<l-1;++i) minpql.add(arr[i]);

            for (int i=r;i<n;++i) minpqr.add(arr[i]);

            long sw = 0, sol = 0, sor = 0;

            long ans = grr;

            while (!maxpq.isEmpty() && !minpql.isEmpty()){

                sw += maxpq.poll();

                sol += minpql.poll();

                ans = Math.min(ans,grr-sw+sol);

                // raw.add(sol);

                if (sol >= sw) break;

            }

            maxpq.clear();

            sw = 0;

            for (int i=l-1;i<r;++i) maxpq.add(arr[i]);

            while (!maxpq.isEmpty() && !minpqr.isEmpty()){

                sw += maxpq.poll();

                sor += minpqr.poll();

                ans = Math.min(ans,grr-sw+sor);

                // raw.add(sor);

                if (sor >= sw) break;

            }   

            System.out.println(ans);

        }

    }

}