ShaysXIA/CodeInsightBench huggingface dataset:
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 312 ms):
t=int(input())

for case in range(t):

    s=0

    n,l,r=map(int,input().split())

    seq=list(map(int,input().split()))

    a=seq[:l-1]+sorted(seq[l-1:])

    b=sorted(seq[:r])[::-1]+seq[r:]

    print(min(sum(a[l-1:r]),sum(b[l-1:r])))

Solution 2 (runtime: 140 ms):
for i in range(int(input())):

    n,l,r = map(int,input().split())

    a = list(map(int,input().split()))

    l-=1

    r-=1

    l1 = a[l:]

    l2 = a[:r+1]

    l1.sort()

    l2.sort()

    print(min(sum(l1[:r-l+1]),sum(l2[:r-l+1])))
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 312 ms):
t=int(input())

for case in range(t):

    s=0

    n,l,r=map(int,input().split())

    seq=list(map(int,input().split()))

    a=seq[:l-1]+sorted(seq[l-1:])

    b=sorted(seq[:r])[::-1]+seq[r:]

    print(min(sum(a[l-1:r]),sum(b[l-1:r])))

Solution 2 (runtime: 390 ms):
for _ in range(int(input())):
    n, l, r = map(int, input().split(' '))
    a = list(map(int, input().split(' ')))
    
    lst1 = sorted(a[0:l - 1])
    lst2 = sorted(a[l - 1:r], reverse = True)
    if r < n:
        lst3 = sorted(a[r:])
    else:
        lst3 = []
    
    res = sum(lst2)
    for i in range(min(len(lst1), len(lst2))):
        if lst1[i] < lst2[i]:
            res += (lst1[i] - lst2[i])
        else:
            break
    
    res1 = sum(lst2)
    for i in range(min(len(lst3), len(lst2))):
        if lst3[i] < lst2[i]:
            res1 += (lst3[i] - lst2[i])
        else:
            break
    
    print(min(res, res1))
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 312 ms):
t=int(input())

for case in range(t):

    s=0

    n,l,r=map(int,input().split())

    seq=list(map(int,input().split()))

    a=seq[:l-1]+sorted(seq[l-1:])

    b=sorted(seq[:r])[::-1]+seq[r:]

    print(min(sum(a[l-1:r]),sum(b[l-1:r])))

Solution 2 (runtime: 358 ms):
from collections import defaultdict, Counter
from random import randint
def intlist(): return list(map(int, (x for x in input().split())))


def check(mid, portion):
    mid = sorted(mid)[::-1]
    portion.sort()
    su = 0
    len_mid = len(mid)
    len_portion = len(portion)
    i, j = 0, 0
    while j < len_mid and i < len_portion:
        if mid[j] <= portion[i]:
            break 
        su += portion[i]
        i += 1
        j += 1
    while j < len_mid:
        su += mid[j]
        j += 1
    return su


for _ in range(int(input())):
    n, l, r = intlist()
    nums = intlist()
    first = nums[:l-1]
    mid = nums[l-1:r]
    last = nums[r:]
    print(min(check(mid, first), check(mid, last)))
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 312 ms):
t=int(input())

for case in range(t):

    s=0

    n,l,r=map(int,input().split())

    seq=list(map(int,input().split()))

    a=seq[:l-1]+sorted(seq[l-1:])

    b=sorted(seq[:r])[::-1]+seq[r:]

    print(min(sum(a[l-1:r]),sum(b[l-1:r])))

Solution 2 (runtime: 139 ms):
t=int(input())

for _ in range(t):

    n,l,r=map(int,input().split())

    a=list(map(int,input().split()))

    l=l-1

    r=r-1

    l1=a[:r+1]

    l2=a[l:]

    l1.sort()

    l2.sort()

    print(min(sum(l1[:r-l+1]),sum(l2[:r-l+1])))
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 312 ms):
t=int(input())

for case in range(t):

    s=0

    n,l,r=map(int,input().split())

    seq=list(map(int,input().split()))

    a=seq[:l-1]+sorted(seq[l-1:])

    b=sorted(seq[:r])[::-1]+seq[r:]

    print(min(sum(a[l-1:r]),sum(b[l-1:r])))

Solution 2 (runtime: 156 ms):
t = int(input())

 

for i in range(t):

    [n, l, r] = [int(val) for val in input().split()]

    nums = [int(val) for val in input().split()]

    nums_one = [int(val) for val in nums[:r]]

    nums_two = [int(val) for val in nums[l-1:]]

    nums_one.sort()

    nums_two.sort()

    print(min(sum(nums_one[:r-l+1]), sum(nums_two[:r-l+1])))

    # ret = 0

    # for j in range(r-l+1):

    #     ret_one += nums[j]

    # print(ret)
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 312 ms):
t=int(input())

for case in range(t):

    s=0

    n,l,r=map(int,input().split())

    seq=list(map(int,input().split()))

    a=seq[:l-1]+sorted(seq[l-1:])

    b=sorted(seq[:r])[::-1]+seq[r:]

    print(min(sum(a[l-1:r]),sum(b[l-1:r])))

Solution 2 (runtime: 343 ms):
import math

from collections import deque, defaultdict, Counter

import heapq



def solution():

  n, l ,r = list(map(int, input().split(" ")))

  l -= 1

  r -= 1

  a = list(map(int, input().split(" ")))

  segment = a[l:r+1]

  res = sum(segment)

  left, right = a[:l], a[r+1:]

  segment.sort()

  left.sort()

  right.sort()

  i, j = 0, len(segment) - 1

  while i < len(left) and j >= 0:

    if left[i] < segment[j]:

      segment[j] = left[i]

      i += 1

      j -= 1

    else:

      break

  res = min(res, sum(segment))

  segment = a[l:r+1]

  segment.sort()

  i, j = 0, len(segment) - 1

  while i < (len(right)) and j >= 0:

    if right[i] < segment[j]:

      segment[j] = right[i]

      i += 1

      j -= 1

    else:

      break

  res = min(res, sum(segment))

  return res





t = int(input())

for i in range(t):

  print(solution())
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 312 ms):
t=int(input())

for case in range(t):

    s=0

    n,l,r=map(int,input().split())

    seq=list(map(int,input().split()))

    a=seq[:l-1]+sorted(seq[l-1:])

    b=sorted(seq[:r])[::-1]+seq[r:]

    print(min(sum(a[l-1:r]),sum(b[l-1:r])))

Solution 2 (runtime: 171 ms):
t = int(input())

for _ in range(t):

    n,l,r = map(int,input().split())

    arr = list(map(int,input().split()))

   



    l-=1

    brr=arr[:l]+sorted(arr[l:])

    crr=sorted(arr[:r])[::-1]+arr[r:]

    print(min(sum(brr[l:r]),sum(crr[l:r])))
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 312 ms):
t=int(input())

for case in range(t):

    s=0

    n,l,r=map(int,input().split())

    seq=list(map(int,input().split()))

    a=seq[:l-1]+sorted(seq[l-1:])

    b=sorted(seq[:r])[::-1]+seq[r:]

    print(min(sum(a[l-1:r]),sum(b[l-1:r])))

Solution 2 (runtime: 265 ms):
for _ in range(int(input())):

    n,l,r=map(int,input().split())

    arra=list(map(int,input().split()))

    arra1=arra[:r]

    arra2=arra[l-1:]

    sum1=0

    sum2=0

    arra1.sort()

    arra2.sort()

    for i in range(r-l+1):

        sum1+=arra1[i]

    for i in range(r-l+1):

        sum2+=arra2[i]

    print(min(sum1,sum2))
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 327 ms):
############ ---- Functions for inputs ---- ############
import math
from bisect import bisect_left, bisect_right
from collections import defaultdict, deque, Counter

def number(): return (int(input()))
def numbers(): return (map(int, input().split()))
def array(): return (list(map(int, input().split())))
def string(): return input()
############ ---- Functions for inputs ---- ############

t = number()

for _ in range(t):
  n, l, r = numbers()
  nums = array()
  left = nums[:l - 1]
  right = nums[r:]
  middle = nums[l - 1:r]
  option1 = sorted(left + middle)
  option2 = sorted(right + middle)
  print(min(sum(option1[:r - l + 1]), sum(option2[:r - l + 1])))
  
  
  
  

Solution 2 (runtime: 140 ms):
for i in range(int(input())):

    n,l,r = map(int,input().split())

    a = list(map(int,input().split()))

    l-=1

    r-=1

    l1 = a[l:]

    l2 = a[:r+1]

    l1.sort()

    l2.sort()

    print(min(sum(l1[:r-l+1]),sum(l2[:r-l+1])))
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 327 ms):
############ ---- Functions for inputs ---- ############
import math
from bisect import bisect_left, bisect_right
from collections import defaultdict, deque, Counter

def number(): return (int(input()))
def numbers(): return (map(int, input().split()))
def array(): return (list(map(int, input().split())))
def string(): return input()
############ ---- Functions for inputs ---- ############

t = number()

for _ in range(t):
  n, l, r = numbers()
  nums = array()
  left = nums[:l - 1]
  right = nums[r:]
  middle = nums[l - 1:r]
  option1 = sorted(left + middle)
  option2 = sorted(right + middle)
  print(min(sum(option1[:r - l + 1]), sum(option2[:r - l + 1])))
  
  
  
  

Solution 2 (runtime: 390 ms):
for _ in range(int(input())):
    n, l, r = map(int, input().split(' '))
    a = list(map(int, input().split(' ')))
    
    lst1 = sorted(a[0:l - 1])
    lst2 = sorted(a[l - 1:r], reverse = True)
    if r < n:
        lst3 = sorted(a[r:])
    else:
        lst3 = []
    
    res = sum(lst2)
    for i in range(min(len(lst1), len(lst2))):
        if lst1[i] < lst2[i]:
            res += (lst1[i] - lst2[i])
        else:
            break
    
    res1 = sum(lst2)
    for i in range(min(len(lst3), len(lst2))):
        if lst3[i] < lst2[i]:
            res1 += (lst3[i] - lst2[i])
        else:
            break
    
    print(min(res, res1))
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 327 ms):
############ ---- Functions for inputs ---- ############
import math
from bisect import bisect_left, bisect_right
from collections import defaultdict, deque, Counter

def number(): return (int(input()))
def numbers(): return (map(int, input().split()))
def array(): return (list(map(int, input().split())))
def string(): return input()
############ ---- Functions for inputs ---- ############

t = number()

for _ in range(t):
  n, l, r = numbers()
  nums = array()
  left = nums[:l - 1]
  right = nums[r:]
  middle = nums[l - 1:r]
  option1 = sorted(left + middle)
  option2 = sorted(right + middle)
  print(min(sum(option1[:r - l + 1]), sum(option2[:r - l + 1])))
  
  
  
  

Solution 2 (runtime: 358 ms):
from collections import defaultdict, Counter
from random import randint
def intlist(): return list(map(int, (x for x in input().split())))


def check(mid, portion):
    mid = sorted(mid)[::-1]
    portion.sort()
    su = 0
    len_mid = len(mid)
    len_portion = len(portion)
    i, j = 0, 0
    while j < len_mid and i < len_portion:
        if mid[j] <= portion[i]:
            break 
        su += portion[i]
        i += 1
        j += 1
    while j < len_mid:
        su += mid[j]
        j += 1
    return su


for _ in range(int(input())):
    n, l, r = intlist()
    nums = intlist()
    first = nums[:l-1]
    mid = nums[l-1:r]
    last = nums[r:]
    print(min(check(mid, first), check(mid, last)))
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 327 ms):
############ ---- Functions for inputs ---- ############
import math
from bisect import bisect_left, bisect_right
from collections import defaultdict, deque, Counter

def number(): return (int(input()))
def numbers(): return (map(int, input().split()))
def array(): return (list(map(int, input().split())))
def string(): return input()
############ ---- Functions for inputs ---- ############

t = number()

for _ in range(t):
  n, l, r = numbers()
  nums = array()
  left = nums[:l - 1]
  right = nums[r:]
  middle = nums[l - 1:r]
  option1 = sorted(left + middle)
  option2 = sorted(right + middle)
  print(min(sum(option1[:r - l + 1]), sum(option2[:r - l + 1])))
  
  
  
  

Solution 2 (runtime: 139 ms):
t=int(input())

for _ in range(t):

    n,l,r=map(int,input().split())

    a=list(map(int,input().split()))

    l=l-1

    r=r-1

    l1=a[:r+1]

    l2=a[l:]

    l1.sort()

    l2.sort()

    print(min(sum(l1[:r-l+1]),sum(l2[:r-l+1])))
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 327 ms):
############ ---- Functions for inputs ---- ############
import math
from bisect import bisect_left, bisect_right
from collections import defaultdict, deque, Counter

def number(): return (int(input()))
def numbers(): return (map(int, input().split()))
def array(): return (list(map(int, input().split())))
def string(): return input()
############ ---- Functions for inputs ---- ############

t = number()

for _ in range(t):
  n, l, r = numbers()
  nums = array()
  left = nums[:l - 1]
  right = nums[r:]
  middle = nums[l - 1:r]
  option1 = sorted(left + middle)
  option2 = sorted(right + middle)
  print(min(sum(option1[:r - l + 1]), sum(option2[:r - l + 1])))
  
  
  
  

Solution 2 (runtime: 156 ms):
t = int(input())

 

for i in range(t):

    [n, l, r] = [int(val) for val in input().split()]

    nums = [int(val) for val in input().split()]

    nums_one = [int(val) for val in nums[:r]]

    nums_two = [int(val) for val in nums[l-1:]]

    nums_one.sort()

    nums_two.sort()

    print(min(sum(nums_one[:r-l+1]), sum(nums_two[:r-l+1])))

    # ret = 0

    # for j in range(r-l+1):

    #     ret_one += nums[j]

    # print(ret)
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 327 ms):
############ ---- Functions for inputs ---- ############
import math
from bisect import bisect_left, bisect_right
from collections import defaultdict, deque, Counter

def number(): return (int(input()))
def numbers(): return (map(int, input().split()))
def array(): return (list(map(int, input().split())))
def string(): return input()
############ ---- Functions for inputs ---- ############

t = number()

for _ in range(t):
  n, l, r = numbers()
  nums = array()
  left = nums[:l - 1]
  right = nums[r:]
  middle = nums[l - 1:r]
  option1 = sorted(left + middle)
  option2 = sorted(right + middle)
  print(min(sum(option1[:r - l + 1]), sum(option2[:r - l + 1])))
  
  
  
  

Solution 2 (runtime: 343 ms):
import math

from collections import deque, defaultdict, Counter

import heapq



def solution():

  n, l ,r = list(map(int, input().split(" ")))

  l -= 1

  r -= 1

  a = list(map(int, input().split(" ")))

  segment = a[l:r+1]

  res = sum(segment)

  left, right = a[:l], a[r+1:]

  segment.sort()

  left.sort()

  right.sort()

  i, j = 0, len(segment) - 1

  while i < len(left) and j >= 0:

    if left[i] < segment[j]:

      segment[j] = left[i]

      i += 1

      j -= 1

    else:

      break

  res = min(res, sum(segment))

  segment = a[l:r+1]

  segment.sort()

  i, j = 0, len(segment) - 1

  while i < (len(right)) and j >= 0:

    if right[i] < segment[j]:

      segment[j] = right[i]

      i += 1

      j -= 1

    else:

      break

  res = min(res, sum(segment))

  return res





t = int(input())

for i in range(t):

  print(solution())
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 327 ms):
############ ---- Functions for inputs ---- ############
import math
from bisect import bisect_left, bisect_right
from collections import defaultdict, deque, Counter

def number(): return (int(input()))
def numbers(): return (map(int, input().split()))
def array(): return (list(map(int, input().split())))
def string(): return input()
############ ---- Functions for inputs ---- ############

t = number()

for _ in range(t):
  n, l, r = numbers()
  nums = array()
  left = nums[:l - 1]
  right = nums[r:]
  middle = nums[l - 1:r]
  option1 = sorted(left + middle)
  option2 = sorted(right + middle)
  print(min(sum(option1[:r - l + 1]), sum(option2[:r - l + 1])))
  
  
  
  

Solution 2 (runtime: 171 ms):
t = int(input())

for _ in range(t):

    n,l,r = map(int,input().split())

    arr = list(map(int,input().split()))

   



    l-=1

    brr=arr[:l]+sorted(arr[l:])

    crr=sorted(arr[:r])[::-1]+arr[r:]

    print(min(sum(brr[l:r]),sum(crr[l:r])))
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 327 ms):
############ ---- Functions for inputs ---- ############
import math
from bisect import bisect_left, bisect_right
from collections import defaultdict, deque, Counter

def number(): return (int(input()))
def numbers(): return (map(int, input().split()))
def array(): return (list(map(int, input().split())))
def string(): return input()
############ ---- Functions for inputs ---- ############

t = number()

for _ in range(t):
  n, l, r = numbers()
  nums = array()
  left = nums[:l - 1]
  right = nums[r:]
  middle = nums[l - 1:r]
  option1 = sorted(left + middle)
  option2 = sorted(right + middle)
  print(min(sum(option1[:r - l + 1]), sum(option2[:r - l + 1])))
  
  
  
  

Solution 2 (runtime: 265 ms):
for _ in range(int(input())):

    n,l,r=map(int,input().split())

    arra=list(map(int,input().split()))

    arra1=arra[:r]

    arra2=arra[l-1:]

    sum1=0

    sum2=0

    arra1.sort()

    arra2.sort()

    for i in range(r-l+1):

        sum1+=arra1[i]

    for i in range(r-l+1):

        sum2+=arra2[i]

    print(min(sum1,sum2))
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 140 ms):
for i in range(int(input())):

    n,l,r = map(int,input().split())

    a = list(map(int,input().split()))

    l-=1

    r-=1

    l1 = a[l:]

    l2 = a[:r+1]

    l1.sort()

    l2.sort()

    print(min(sum(l1[:r-l+1]),sum(l2[:r-l+1])))

Solution 2 (runtime: 390 ms):
for _ in range(int(input())):
    n, l, r = map(int, input().split(' '))
    a = list(map(int, input().split(' ')))
    
    lst1 = sorted(a[0:l - 1])
    lst2 = sorted(a[l - 1:r], reverse = True)
    if r < n:
        lst3 = sorted(a[r:])
    else:
        lst3 = []
    
    res = sum(lst2)
    for i in range(min(len(lst1), len(lst2))):
        if lst1[i] < lst2[i]:
            res += (lst1[i] - lst2[i])
        else:
            break
    
    res1 = sum(lst2)
    for i in range(min(len(lst3), len(lst2))):
        if lst3[i] < lst2[i]:
            res1 += (lst3[i] - lst2[i])
        else:
            break
    
    print(min(res, res1))
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 140 ms):
for i in range(int(input())):

    n,l,r = map(int,input().split())

    a = list(map(int,input().split()))

    l-=1

    r-=1

    l1 = a[l:]

    l2 = a[:r+1]

    l1.sort()

    l2.sort()

    print(min(sum(l1[:r-l+1]),sum(l2[:r-l+1])))

Solution 2 (runtime: 358 ms):
from collections import defaultdict, Counter
from random import randint
def intlist(): return list(map(int, (x for x in input().split())))


def check(mid, portion):
    mid = sorted(mid)[::-1]
    portion.sort()
    su = 0
    len_mid = len(mid)
    len_portion = len(portion)
    i, j = 0, 0
    while j < len_mid and i < len_portion:
        if mid[j] <= portion[i]:
            break 
        su += portion[i]
        i += 1
        j += 1
    while j < len_mid:
        su += mid[j]
        j += 1
    return su


for _ in range(int(input())):
    n, l, r = intlist()
    nums = intlist()
    first = nums[:l-1]
    mid = nums[l-1:r]
    last = nums[r:]
    print(min(check(mid, first), check(mid, last)))
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 140 ms):
for i in range(int(input())):

    n,l,r = map(int,input().split())

    a = list(map(int,input().split()))

    l-=1

    r-=1

    l1 = a[l:]

    l2 = a[:r+1]

    l1.sort()

    l2.sort()

    print(min(sum(l1[:r-l+1]),sum(l2[:r-l+1])))

Solution 2 (runtime: 139 ms):
t=int(input())

for _ in range(t):

    n,l,r=map(int,input().split())

    a=list(map(int,input().split()))

    l=l-1

    r=r-1

    l1=a[:r+1]

    l2=a[l:]

    l1.sort()

    l2.sort()

    print(min(sum(l1[:r-l+1]),sum(l2[:r-l+1])))
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 140 ms):
for i in range(int(input())):

    n,l,r = map(int,input().split())

    a = list(map(int,input().split()))

    l-=1

    r-=1

    l1 = a[l:]

    l2 = a[:r+1]

    l1.sort()

    l2.sort()

    print(min(sum(l1[:r-l+1]),sum(l2[:r-l+1])))

Solution 2 (runtime: 156 ms):
t = int(input())

 

for i in range(t):

    [n, l, r] = [int(val) for val in input().split()]

    nums = [int(val) for val in input().split()]

    nums_one = [int(val) for val in nums[:r]]

    nums_two = [int(val) for val in nums[l-1:]]

    nums_one.sort()

    nums_two.sort()

    print(min(sum(nums_one[:r-l+1]), sum(nums_two[:r-l+1])))

    # ret = 0

    # for j in range(r-l+1):

    #     ret_one += nums[j]

    # print(ret)
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 140 ms):
for i in range(int(input())):

    n,l,r = map(int,input().split())

    a = list(map(int,input().split()))

    l-=1

    r-=1

    l1 = a[l:]

    l2 = a[:r+1]

    l1.sort()

    l2.sort()

    print(min(sum(l1[:r-l+1]),sum(l2[:r-l+1])))

Solution 2 (runtime: 343 ms):
import math

from collections import deque, defaultdict, Counter

import heapq



def solution():

  n, l ,r = list(map(int, input().split(" ")))

  l -= 1

  r -= 1

  a = list(map(int, input().split(" ")))

  segment = a[l:r+1]

  res = sum(segment)

  left, right = a[:l], a[r+1:]

  segment.sort()

  left.sort()

  right.sort()

  i, j = 0, len(segment) - 1

  while i < len(left) and j >= 0:

    if left[i] < segment[j]:

      segment[j] = left[i]

      i += 1

      j -= 1

    else:

      break

  res = min(res, sum(segment))

  segment = a[l:r+1]

  segment.sort()

  i, j = 0, len(segment) - 1

  while i < (len(right)) and j >= 0:

    if right[i] < segment[j]:

      segment[j] = right[i]

      i += 1

      j -= 1

    else:

      break

  res = min(res, sum(segment))

  return res





t = int(input())

for i in range(t):

  print(solution())
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 140 ms):
for i in range(int(input())):

    n,l,r = map(int,input().split())

    a = list(map(int,input().split()))

    l-=1

    r-=1

    l1 = a[l:]

    l2 = a[:r+1]

    l1.sort()

    l2.sort()

    print(min(sum(l1[:r-l+1]),sum(l2[:r-l+1])))

Solution 2 (runtime: 171 ms):
t = int(input())

for _ in range(t):

    n,l,r = map(int,input().split())

    arr = list(map(int,input().split()))

   



    l-=1

    brr=arr[:l]+sorted(arr[l:])

    crr=sorted(arr[:r])[::-1]+arr[r:]

    print(min(sum(brr[l:r]),sum(crr[l:r])))
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 140 ms):
for i in range(int(input())):

    n,l,r = map(int,input().split())

    a = list(map(int,input().split()))

    l-=1

    r-=1

    l1 = a[l:]

    l2 = a[:r+1]

    l1.sort()

    l2.sort()

    print(min(sum(l1[:r-l+1]),sum(l2[:r-l+1])))

Solution 2 (runtime: 265 ms):
for _ in range(int(input())):

    n,l,r=map(int,input().split())

    arra=list(map(int,input().split()))

    arra1=arra[:r]

    arra2=arra[l-1:]

    sum1=0

    sum2=0

    arra1.sort()

    arra2.sort()

    for i in range(r-l+1):

        sum1+=arra1[i]

    for i in range(r-l+1):

        sum2+=arra2[i]

    print(min(sum1,sum2))
Problem: 2063B - Subsequence Update
Language: python

Solution 1 (runtime: 390 ms):
for _ in range(int(input())):
    n, l, r = map(int, input().split(' '))
    a = list(map(int, input().split(' ')))
    
    lst1 = sorted(a[0:l - 1])
    lst2 = sorted(a[l - 1:r], reverse = True)
    if r < n:
        lst3 = sorted(a[r:])
    else:
        lst3 = []
    
    res = sum(lst2)
    for i in range(min(len(lst1), len(lst2))):
        if lst1[i] < lst2[i]:
            res += (lst1[i] - lst2[i])
        else:
            break
    
    res1 = sum(lst2)
    for i in range(min(len(lst3), len(lst2))):
        if lst3[i] < lst2[i]:
            res1 += (lst3[i] - lst2[i])
        else:
            break
    
    print(min(res, res1))

Solution 2 (runtime: 358 ms):
from collections import defaultdict, Counter
from random import randint
def intlist(): return list(map(int, (x for x in input().split())))


def check(mid, portion):
    mid = sorted(mid)[::-1]
    portion.sort()
    su = 0
    len_mid = len(mid)
    len_portion = len(portion)
    i, j = 0, 0
    while j < len_mid and i < len_portion:
        if mid[j] <= portion[i]:
            break 
        su += portion[i]
        i += 1
        j += 1
    while j < len_mid:
        su += mid[j]
        j += 1
    return su


for _ in range(int(input())):
    n, l, r = intlist()
    nums = intlist()
    first = nums[:l-1]
    mid = nums[l-1:r]
    last = nums[r:]
    print(min(check(mid, first), check(mid, last)))