Problem: 2063B - Subsequence Update
Language: java

Solution 1 (runtime: 343 ms):
import java.util.*;

public class Solution {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();  // number of test cases
        while (t-- > 0) {
            // Read n, l, r
            int n = sc.nextInt();
            int l = sc.nextInt();  // 1-based index
            int r = sc.nextInt();  // 1-based index

            // Read array arr
            long[] arr = new long[n + 1];  // Using long[] for larger values, and n+1 to handle 1-based indexing
            for (int i = 1; i <= n; i++) {
                arr[i] = sc.nextLong();
            }

            // Step 1: Calculate the sum for the range [l, r]
            long initialSum = 0;
            for (int i = l; i <= r; i++) {
                initialSum += arr[i];
            }
            long min = initialSum;  // Store the initial sum as the minimum

            // Step 2: Find the smallest `r - l + 1` elements from [1, r]
            List<Long> prefix = new ArrayList<>();
            for (int i = 1; i <= r; i++) {
                prefix.add(arr[i]);
            }
            Collections.sort(prefix);
            long prefixSum = 0;
            // Sum the smallest `r - l + 1` elements from the sorted prefix
            for (int i = 0; i < r - l + 1; i++) {
                prefixSum += prefix.get(i);
            }
            min = Math.min(min, prefixSum);  // Update the minimum sum

            // Step 3: Find the smallest `r - l + 1` elements from [l, n]
            List<Long> suffix = new ArrayList<>();
            for (int i = l; i <= n; i++) {
                suffix.add(arr[i]);
            }
            Collections.sort(suffix);
            long suffixSum = 0;
            // Sum the smallest `r - l + 1` elements from the sorted suffix
            for (int i = 0; i < r - l + 1; i++) {
                suffixSum += suffix.get(i);
            }
            min = Math.min(min, suffixSum);  // Update the minimum sum

            // Output the result for the current test case
            System.out.println(min);
        }
    }
}


Solution 2 (runtime: 280 ms):
// Problem Page: https://codeforces.com/contest/2063/problem/B



import java.util.*;



public class SubsequenceUpdate {



    public static void main(String[] args) {



        Scanner sc = new Scanner(System.in);

        int t = sc.nextInt();

        while (t-- > 0) {

            solve(sc);

        }

    }



    //subsequence does not have to be contiguous

    static void solve(Scanner sc) {

        int n = sc.nextInt();

        int l = sc.nextInt();

        int r = sc.nextInt();

        int[] a = new int[n];

        for (int i = 0; i < n; i++) {

            a[i] = sc.nextInt();

        }

        int[] b = new int[r];

        int[] c = new int[n - l + 1];

        for (int i = 0; i < r; i++) {

            b[i] = a[i];

        }

        for (int i = l - 1; i < n; i++) {

            c[i - l + 1] = a[i];

        }

        Arrays.sort(b);

        Arrays.sort(c);

        long sum_b = 0, sum_c = 0;

        for (int i = 0; i <= (r - l); i++) {

            sum_b += b[i];

            sum_c += c[i];

        }

        System.out.println(Math.min(sum_b, sum_c));

    }

}