ShaysXIA/CodeInsightBench huggingface dataset:
Problem: 2050C - Uninteresting Number
Language: python

Solution 1 (runtime: 171 ms):
def voir(test,nb3):
    while test!=0 and nb3>0:
        test=(test+6)%9
        nb3-=1
    if test==0:
        return True
    else :
        return False

OUT=[]
for i in range(int(input())):
    s=input()
    somme=0
    nb2=0
    nb3=0
    for i in s:
        somme=(somme+int(i))%9
        if i=="2":
            nb2+=1 
        if i=="3":
            nb3+=1
    
    if somme==0 :
        OUT.append("YES")
    else :
        
        
        if nb2>=2 :
            
            if voir((somme+4)%9,(nb3+(nb2-2)//3)) or voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        elif nb2==1 :
            
            if voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        else:
            
            if voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")


for i in OUT:
    print(i)

        

    
    

Solution 2 (runtime: 203 ms):
t = int(input())
for _ in range(t):
    n  = input()
    length = len(n)
    total = 0  
    two = 0
    three = 0
    for i in range(length): 
        total += int(n[i])
        if(int(n[i]) == 2): two += 1
        if(int(n[i]) == 3): three += 1
    if(total % 9 == 0): print("YES")
    else:   
        ans = True
        for i in range(two+1):
            if ans == False: break
            for j in range(three+1):
                if (total + i * 2 + j * 6) % 9 == 0:
                    ans = False
                    break
        if ans : print("NO")
        else: print("YES")
Problem: 2050C - Uninteresting Number
Language: python

Solution 1 (runtime: 171 ms):
def voir(test,nb3):
    while test!=0 and nb3>0:
        test=(test+6)%9
        nb3-=1
    if test==0:
        return True
    else :
        return False

OUT=[]
for i in range(int(input())):
    s=input()
    somme=0
    nb2=0
    nb3=0
    for i in s:
        somme=(somme+int(i))%9
        if i=="2":
            nb2+=1 
        if i=="3":
            nb3+=1
    
    if somme==0 :
        OUT.append("YES")
    else :
        
        
        if nb2>=2 :
            
            if voir((somme+4)%9,(nb3+(nb2-2)//3)) or voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        elif nb2==1 :
            
            if voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        else:
            
            if voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")


for i in OUT:
    print(i)

        

    
    

Solution 2 (runtime: 124 ms):
#  /\_/\  
# ( o.o ) 
#  > ^ <
#   ...
# Online Judge Please PASS Me :)

import sys
from collections import defaultdict

def slowestIO():
    input = sys.stdin.read
    data = input().splitlines()
    return data

def definitelyNotMain():
    data = slowestIO()
    index = 0
    test_cases = int(data[index])
    index += 1
    results = []

    for _ in range(test_cases):
        num = data[index]
        index += 1
        n = len(num)
        
        rem = sum([int(ch) for ch in num]) % 9
        target = 9 - rem
        if rem % 2 == 0:
            target = 18 - rem
        
        ans = "YES"
        twos, threes = 0, 0
        for ch in num:
            twos += ch == "2"
            threes += ch == "3"
            
        cur = 0
        check2s = twos
        while twos > 0:
            twos -= 1
            cur += 2
            if cur > target:
                cur -= 2
                break
            
        while cur < target and threes > 0:
            threes -= 1
            cur += 6
            
        diff = cur - target
                
        if not(diff == 2 and check2s > 0) and not(diff == 4 and check2s > 1) and (rem > 0 and cur != target):
            ans = "NO"
                
        results.append(str(ans))

    sys.stdout.write('\n'.join(results) + '\n')

if __name__ == "__main__":
    definitelyNotMain()
Problem: 2050C - Uninteresting Number
Language: python

Solution 1 (runtime: 171 ms):
def voir(test,nb3):
    while test!=0 and nb3>0:
        test=(test+6)%9
        nb3-=1
    if test==0:
        return True
    else :
        return False

OUT=[]
for i in range(int(input())):
    s=input()
    somme=0
    nb2=0
    nb3=0
    for i in s:
        somme=(somme+int(i))%9
        if i=="2":
            nb2+=1 
        if i=="3":
            nb3+=1
    
    if somme==0 :
        OUT.append("YES")
    else :
        
        
        if nb2>=2 :
            
            if voir((somme+4)%9,(nb3+(nb2-2)//3)) or voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        elif nb2==1 :
            
            if voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        else:
            
            if voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")


for i in OUT:
    print(i)

        

    
    

Solution 2 (runtime: 327 ms):
testCases = int(input())
for i in range(testCases):
    two = 0
    three = 0
    total = 0
    number = input()
    for j in number:
        
        if j == "2":
            two += 1
        elif j == "3":
            three += 1
        total += int(j)
    total = total % 9
    if total == 0:
        print("YES")
    elif total == 3 and three >= 1 or total == 6 and three >= 2:
        print("YES")
    elif (9-total) % 2 == 0 and int((9-total) / 2) <= two or (18-total) % 2 == 0 and int((18-total) / 2) <= two:
        print("YES")
    elif three >= 2:
        total += 3
        total = total % 9
        if (9-total) % 2 == 0 and int((9-total) / 2) <= two or (18-total) % 2 == 0 and int((18-total) / 2) <= two:
            print("YES")
        else:
            total += 3
            total = total % 9
            if (9-total) % 2 == 0 and int((9-total) / 2) <= two or (18-total) % 2 == 0 and int((18-total) / 2) <= two:
                    print("YES")
            else:
                print("NO")
    elif three >= 1:
        total += 6
        total = total % 9
        if (9-total) % 2 == 0 and int((9-total) / 2) <= two or (18-total) % 2 == 0 and int((18-total) / 2) <= two:
            print("YES")
        else:
            print("NO")
    else:
        print("NO")
Problem: 2050C - Uninteresting Number
Language: python

Solution 1 (runtime: 171 ms):
def voir(test,nb3):
    while test!=0 and nb3>0:
        test=(test+6)%9
        nb3-=1
    if test==0:
        return True
    else :
        return False

OUT=[]
for i in range(int(input())):
    s=input()
    somme=0
    nb2=0
    nb3=0
    for i in s:
        somme=(somme+int(i))%9
        if i=="2":
            nb2+=1 
        if i=="3":
            nb3+=1
    
    if somme==0 :
        OUT.append("YES")
    else :
        
        
        if nb2>=2 :
            
            if voir((somme+4)%9,(nb3+(nb2-2)//3)) or voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        elif nb2==1 :
            
            if voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        else:
            
            if voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")


for i in OUT:
    print(i)

        

    
    

Solution 2 (runtime: 187 ms):
def solve():
    s = [int(x) for x in list(input())]
    ss = sum(s)
    two = s.count(2)
    three = s.count(3)

    for i in range(two + 1):
        for j in range(three + 1):
            if (ss + (i * 2) + (j * 6)) % 9 == 0:
                return 'YES'
    return 'NO'

NUM_TESTS = int(input())

for _ in range(NUM_TESTS):
    print(solve())
Problem: 2050C - Uninteresting Number
Language: python

Solution 1 (runtime: 171 ms):
def voir(test,nb3):
    while test!=0 and nb3>0:
        test=(test+6)%9
        nb3-=1
    if test==0:
        return True
    else :
        return False

OUT=[]
for i in range(int(input())):
    s=input()
    somme=0
    nb2=0
    nb3=0
    for i in s:
        somme=(somme+int(i))%9
        if i=="2":
            nb2+=1 
        if i=="3":
            nb3+=1
    
    if somme==0 :
        OUT.append("YES")
    else :
        
        
        if nb2>=2 :
            
            if voir((somme+4)%9,(nb3+(nb2-2)//3)) or voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        elif nb2==1 :
            
            if voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        else:
            
            if voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")


for i in OUT:
    print(i)

        

    
    

Solution 2 (runtime: 202 ms):
import sys
import math
import collections
import statistics
import bisect

input = sys.stdin.readline

############ ---- Input Functions ---- ############
##---1) inp — For taking integer inputs.
def inp():
    return (int(input()))

##2) inlt — For taking List inputs.
def inlt():
    return (list(map(int, input().split())))

#3) insr — For taking string inputs. Actually it returns a List of Characters,
# instead of a string, which is easier to use in Python, because in Python,
# Strings are Immutable.
def insr():
    s = input()
    return (list(s[:len(s) - 1]))

#4) invr — For taking space seperated integer variable inputs.
def invr():
    return list(map(int, input().split()))

for iii in range(int(input())):
    a = insr()
    sum = 0
    num2 = 0
    num3 = 0
    for i in a:
        sum += int(i)
        if i == '2':
            num2 += 1
        elif i == '3':
            num3 += 1
    if sum % 9 == 0:
        print("yes")
        continue
    res = 0
    for x in range(min(num2+1, 10)):
        if res == 0:
            for y in range(min(num3+1, 10)):
                if (sum + 2*x + 6*y) % 9 == 0:
                    print("yes")
                    res = 1
                    break
        else:
            break
    if res == 0:
        print("no")
Problem: 2050C - Uninteresting Number
Language: python

Solution 1 (runtime: 171 ms):
def voir(test,nb3):
    while test!=0 and nb3>0:
        test=(test+6)%9
        nb3-=1
    if test==0:
        return True
    else :
        return False

OUT=[]
for i in range(int(input())):
    s=input()
    somme=0
    nb2=0
    nb3=0
    for i in s:
        somme=(somme+int(i))%9
        if i=="2":
            nb2+=1 
        if i=="3":
            nb3+=1
    
    if somme==0 :
        OUT.append("YES")
    else :
        
        
        if nb2>=2 :
            
            if voir((somme+4)%9,(nb3+(nb2-2)//3)) or voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        elif nb2==1 :
            
            if voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        else:
            
            if voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")


for i in OUT:
    print(i)

        

    
    

Solution 2 (runtime: 249 ms):
t=int(input())
for z in range(t):
    n=[int(i) for i in list(input())]
    a=[0,0]
    num=sum(n)
    a[0]=n.count(2)
    a[1]=n.count(3)
    flag=False
    for i in range(min(10,a[0]+1)):
        if not flag:
            for j in range(min(10,a[1]+1)):
                if (num+2*i+6*j)%9==0:
                    print('YES')
                    flag=True
                    break
        else:
            break
    if not flag:
        print('NO')
Problem: 2050C - Uninteresting Number
Language: python

Solution 1 (runtime: 171 ms):
def voir(test,nb3):
    while test!=0 and nb3>0:
        test=(test+6)%9
        nb3-=1
    if test==0:
        return True
    else :
        return False

OUT=[]
for i in range(int(input())):
    s=input()
    somme=0
    nb2=0
    nb3=0
    for i in s:
        somme=(somme+int(i))%9
        if i=="2":
            nb2+=1 
        if i=="3":
            nb3+=1
    
    if somme==0 :
        OUT.append("YES")
    else :
        
        
        if nb2>=2 :
            
            if voir((somme+4)%9,(nb3+(nb2-2)//3)) or voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        elif nb2==1 :
            
            if voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        else:
            
            if voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")


for i in OUT:
    print(i)

        

    
    

Solution 2 (runtime: 437 ms):
t = int(input())
for i in range(t):
    s = [int(x) for x in list(input())]
    sm = sum(s)
    sm %= 9
    cnt2 = s.count(2)
    cnt3 = s.count(3)
    flag = False
    for j in range(min(10, cnt2+1)):
        if flag:
            break
        for k in range(min(10, cnt3+1)):
            if (sm + j * 2 + k * 6) % 9 == 0:
                print('Yes')
                flag = True
                break
    if not flag:
        print('No')
Problem: 2050C - Uninteresting Number
Language: python

Solution 1 (runtime: 171 ms):
def voir(test,nb3):
    while test!=0 and nb3>0:
        test=(test+6)%9
        nb3-=1
    if test==0:
        return True
    else :
        return False

OUT=[]
for i in range(int(input())):
    s=input()
    somme=0
    nb2=0
    nb3=0
    for i in s:
        somme=(somme+int(i))%9
        if i=="2":
            nb2+=1 
        if i=="3":
            nb3+=1
    
    if somme==0 :
        OUT.append("YES")
    else :
        
        
        if nb2>=2 :
            
            if voir((somme+4)%9,(nb3+(nb2-2)//3)) or voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        elif nb2==1 :
            
            if voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        else:
            
            if voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")


for i in OUT:
    print(i)

        

    
    

Solution 2 (runtime: 186 ms):
def sol() -> bool:
    s = str(input())

    numTwos = 0
    numThrees = 0
    sum = 0

    for c in s:
        x = int(c)
        # print(x)
        if x == 2:
            numTwos += 1
        if x == 3:
            numThrees += 1
        sum += x
    
    m = min(8, numTwos)
    n = min(3, numThrees)

    for j in range(m+1):
        for k in range(n+1):
            # print(sum + j * 2 + k * 6)
            if (sum + j * 2 + k * 6) % 9 == 0:
                return True
    
    return False

t = int(input())

for i in range(t):
    print("YES") if sol() else print("NO")
Problem: 2050C - Uninteresting Number
Language: python

Solution 1 (runtime: 171 ms):
def voir(test,nb3):
    while test!=0 and nb3>0:
        test=(test+6)%9
        nb3-=1
    if test==0:
        return True
    else :
        return False

OUT=[]
for i in range(int(input())):
    s=input()
    somme=0
    nb2=0
    nb3=0
    for i in s:
        somme=(somme+int(i))%9
        if i=="2":
            nb2+=1 
        if i=="3":
            nb3+=1
    
    if somme==0 :
        OUT.append("YES")
    else :
        
        
        if nb2>=2 :
            
            if voir((somme+4)%9,(nb3+(nb2-2)//3)) or voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        elif nb2==1 :
            
            if voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        else:
            
            if voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")


for i in OUT:
    print(i)

        

    
    

Solution 2 (runtime: 156 ms):
import sys

input = sys.stdin.readline





for _ in range(int(input())):

    s = input()[:-1]

    a, b = 0, 0

    c = 0

    for i in s:

        if i == '2':

            a += 1

        elif i == '3':

            b += 1

        c += int(i)

    c %= 9

    ew = 0

    for i in range(min(10, b+1)):

        for j in range(min(10, a+1)):

            if (c + 6*i + 2*j) % 9 == 0:

                ew = 1

                break

        if ew:

            break

    print(['NO','YES'][ew])
Problem: 2050C - Uninteresting Number
Language: python

Solution 1 (runtime: 171 ms):
def voir(test,nb3):
    while test!=0 and nb3>0:
        test=(test+6)%9
        nb3-=1
    if test==0:
        return True
    else :
        return False

OUT=[]
for i in range(int(input())):
    s=input()
    somme=0
    nb2=0
    nb3=0
    for i in s:
        somme=(somme+int(i))%9
        if i=="2":
            nb2+=1 
        if i=="3":
            nb3+=1
    
    if somme==0 :
        OUT.append("YES")
    else :
        
        
        if nb2>=2 :
            
            if voir((somme+4)%9,(nb3+(nb2-2)//3)) or voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        elif nb2==1 :
            
            if voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        else:
            
            if voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")


for i in OUT:
    print(i)

        

    
    

Solution 2 (runtime: 186 ms):
import sys, math

from functools import cmp_to_key

from operator import itemgetter

from bisect import bisect_left, bisect_right

from collections import Counter, defaultdict, deque



input = sys.stdin.readline



def iinp(): return (int(input()))

def linp(): return (list(map(int, input().split())))

def sinp(): return (input().strip())

def minp(): return (map(int, input().split()))

def debug(*args):

    print("DEBUG:", *args, file=sys.stderr)





def solve():

	# n = iinp()

	s = sinp()

	Sum = sum([int(num) for num in s])

	count_2 = s.count('2')

	count_3 = s.count('3')

	if Sum%9==0:

		print("YES")

		return

	target = (9 - Sum%9)%9 

	for i in range(count_3+1):

		new_target = (target - 6*i)%9

		if new_target<0:

			new_target +=9

		requied = (5*new_target)%9

		if requied<=count_2:

			print("YES")

			return

		

	print('NO')

		



def main():

	t = 1

	t = int(input())

	for i in range(t):

		solve()

	

if __name__ == "__main__":

	main()
Problem: 2050C - Uninteresting Number
Language: python

Solution 1 (runtime: 171 ms):
def voir(test,nb3):
    while test!=0 and nb3>0:
        test=(test+6)%9
        nb3-=1
    if test==0:
        return True
    else :
        return False

OUT=[]
for i in range(int(input())):
    s=input()
    somme=0
    nb2=0
    nb3=0
    for i in s:
        somme=(somme+int(i))%9
        if i=="2":
            nb2+=1 
        if i=="3":
            nb3+=1
    
    if somme==0 :
        OUT.append("YES")
    else :
        
        
        if nb2>=2 :
            
            if voir((somme+4)%9,(nb3+(nb2-2)//3)) or voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        elif nb2==1 :
            
            if voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        else:
            
            if voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")


for i in OUT:
    print(i)

        

    
    

Solution 2 (runtime: 93 ms):
import sys



def is_interesting(n):

    S = 0

    count_2 = 0

    count_3 = 0



    # Compute sum of digits and count of 2s and 3s

    for digit in n:

        d = int(digit)

        S += d

        if d == 2:

            count_2 += 1

        elif d == 3:

            count_3 += 1



    # Compute R = (9 - S % 9) % 9

    R = (9 - (S % 9)) % 9

    for i in range(count_3+1):

        new_R = (R - 6*i)%9

        if new_R<0:

            new_R +=9

        mmi = (new_R*5)%9

        if mmi <= count_2:

            return 'YES'

    return 'NO'



# Fast input handling

input = sys.stdin.read

data = input().split()

t = int(data[0])

results = []



for i in range(1, t + 1):

    n = data[i]

    results.append(is_interesting(n))



# Output results efficiently

sys.stdout.write("\n".join(results) + "\n")
Problem: 2050C - Uninteresting Number
Language: python

Solution 1 (runtime: 171 ms):
def voir(test,nb3):
    while test!=0 and nb3>0:
        test=(test+6)%9
        nb3-=1
    if test==0:
        return True
    else :
        return False

OUT=[]
for i in range(int(input())):
    s=input()
    somme=0
    nb2=0
    nb3=0
    for i in s:
        somme=(somme+int(i))%9
        if i=="2":
            nb2+=1 
        if i=="3":
            nb3+=1
    
    if somme==0 :
        OUT.append("YES")
    else :
        
        
        if nb2>=2 :
            
            if voir((somme+4)%9,(nb3+(nb2-2)//3)) or voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        elif nb2==1 :
            
            if voir((somme+2)%9,(nb3+(nb2-1)//3)) or voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")
        else:
            
            if voir((somme)%9,(nb3+(nb2)//3)):
                OUT.append("YES")
            else :
                OUT.append("NO")


for i in OUT:
    print(i)

        

    
    

Solution 2 (runtime: 203 ms):
t = int(input())

for _ in range(t):

    s = list(map(int, input().strip()))

    x = sum(s)

    twos = 0

    threes = 0

    for i in s:

        if i == 2:

            twos += 1

        elif i == 3:

            threes += 1

        if twos > 8 and threes > 8:

            break



    ans = 'NO'



    for i in range(twos + 1):

        for j in range(threes + 1):

            if (2 * i + 6 * j + x) % 9 == 0:

                ans = 'YES'

                break 

    

    print(ans)