ShaysXIA/CodeInsightBench huggingface dataset:
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 734 ms):
def lists(L, X):
    for i in range(len(L)):
        max1 = int(L[i])
        index = i
        for j in range(i, min(i + 10, len(L))):
            if int(L[j]) - (j - i) > max1:
                max1 = int(L[j]) - (j - i)
                index = j
        while index > i:
            L[index], L[index - 1] = L[index - 1], L[index]
            index -= 1
        X.append(max1)

n = int(input())
for _ in range(n):
    L = [int(j) for j in input().strip()]
    X = []
    lists(L, X)
    y = ''.join(map(str, X))
    print(y)


Solution 2 (runtime: 1171 ms):

class LinkedList:
    def __init__(self, l):
        self.list = l
        self.len = len(l)
        self.next = [i+1 for i in range(self.len)]
        self.next[-1] = None
        self.prev = [i-1 for i in range(self.len)]
        self.prev[0] = None
        self.head = 0
        self.current = self.head
    
    def to_head(self):
        self.current = self.head
        
    def pop(self, i=None):
        if i == None:
            self.current = self.head
        else:
            self.current = i
        next_ = self.next[self.current]
        prev_ = self.prev[self.current]
        if self.len == 1:
            self.head=None  
        elif self.current == self.head:
            self.head = self.next[self.head]
            self.prev[self.head] = None
        elif next_ == None:
            self.next[prev_] = None 
        else:
            self.next[prev_] = next_
            self.prev[next_] = prev_
        self.len -= 1
        
    def to_next(self):
        self.current = self.next[self.current]
        
    def elem(self):
        return self.list[self.current]
    
    def print_(self):
        i = self.head
        data = []
        data_n = []
        while i != None:
            data.append(self.list[i])
            data_n.append(self.next[i])
            i = self.next[i]
        print(data, data_n)
    
        


t = int(input())
for k in range(t):
    s = LinkedList(list(map(int,list(str(input())))))
    res = ''
    n = s.len
    count_masked = 0
    i = 0
    #s.print_()
    while s.len > 0:
        s.to_head()
        cost=1
        max_v=s.elem()
        max_j=-1
        s.to_next()
        while 9 - (s.list[s.head] + cost) > 0 and s.current != None:
            if s.list[s.current] - cost > max_v:
                max_v = s.list[s.current] - cost
                max_j = s.current
            cost+=1
            s.to_next()
        if max_j != -1:
            res+=str(max_v)
            s.pop(max_j)
        else:
            res+=str(s.list[s.head])
            s.pop()
        #s.print_()
    print(res)
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 734 ms):
def lists(L, X):
    for i in range(len(L)):
        max1 = int(L[i])
        index = i
        for j in range(i, min(i + 10, len(L))):
            if int(L[j]) - (j - i) > max1:
                max1 = int(L[j]) - (j - i)
                index = j
        while index > i:
            L[index], L[index - 1] = L[index - 1], L[index]
            index -= 1
        X.append(max1)

n = int(input())
for _ in range(n):
    L = [int(j) for j in input().strip()]
    X = []
    lists(L, X)
    y = ''.join(map(str, X))
    print(y)


Solution 2 (runtime: 718 ms):
t=int(input())
for _ in range(t):
    s=input()
    l=list(map(int,s))
    for i in range(1,len(s)):
        while i>0 and l[i]>l[i-1]+1:
            l[i],l[i-1]=l[i-1],l[i]-1
            i-=1
    print(''.join(map(str,l)))
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 734 ms):
def lists(L, X):
    for i in range(len(L)):
        max1 = int(L[i])
        index = i
        for j in range(i, min(i + 10, len(L))):
            if int(L[j]) - (j - i) > max1:
                max1 = int(L[j]) - (j - i)
                index = j
        while index > i:
            L[index], L[index - 1] = L[index - 1], L[index]
            index -= 1
        X.append(max1)

n = int(input())
for _ in range(n):
    L = [int(j) for j in input().strip()]
    X = []
    lists(L, X)
    y = ''.join(map(str, X))
    print(y)


Solution 2 (runtime: 1202 ms):
t = int(input())



for _ in range(t):

    word = input()

    s = [int(digit) for digit in word]

    l = len(s)



    for i in range(l):

        findMax= s[i]

        maxPos = i

        for j in range(10):

            if s[i+j]>findMax+((j+i)-maxPos):

                findMax = s[i+j]

                maxPos = i+j

            

            if l-(i+j)-1==0:

                break



        for j in range(maxPos-i):

            temp = s[maxPos-1]

            s[maxPos-1] = s[maxPos]-1

            s[maxPos] = temp

            maxPos-=1



    print("".join([str(digit) for digit in s]))
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 734 ms):
def lists(L, X):
    for i in range(len(L)):
        max1 = int(L[i])
        index = i
        for j in range(i, min(i + 10, len(L))):
            if int(L[j]) - (j - i) > max1:
                max1 = int(L[j]) - (j - i)
                index = j
        while index > i:
            L[index], L[index - 1] = L[index - 1], L[index]
            index -= 1
        X.append(max1)

n = int(input())
for _ in range(n):
    L = [int(j) for j in input().strip()]
    X = []
    lists(L, X)
    y = ''.join(map(str, X))
    print(y)


Solution 2 (runtime: 203 ms):
t= int(input())
for k in range(t):    
    a=list(input())
    b= len(a)
    for i in range(b):
        t= min(i+9,b)
        m= int(a[i])
        n=i
        for j in range(i,t):
            if (int(a[j])-j+i)> m:
                m= int(a[j])-j+i
                n= j
        while n>i:
            a[n],a[n-1]= a[n-1],str(int(a[n])-1)
            n-=1
    print("".join(a))
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 734 ms):
def lists(L, X):
    for i in range(len(L)):
        max1 = int(L[i])
        index = i
        for j in range(i, min(i + 10, len(L))):
            if int(L[j]) - (j - i) > max1:
                max1 = int(L[j]) - (j - i)
                index = j
        while index > i:
            L[index], L[index - 1] = L[index - 1], L[index]
            index -= 1
        X.append(max1)

n = int(input())
for _ in range(n):
    L = [int(j) for j in input().strip()]
    X = []
    lists(L, X)
    y = ''.join(map(str, X))
    print(y)


Solution 2 (runtime: 702 ms):
n = int(input())

res = []

for _ in range(n):

    s = input()

    temp = []

    for ch in s:

        temp.append(int(ch))

    for i in range(1, len(s)):

        j = i - 1

        while j >= 0:

            r = temp[j+1]

            l = temp[j]

            if r > l + 1:

                temp[j] = r - 1

                temp[j+1] = l

            else:

                break

            j -= 1

    r = ''

    for n in temp:

        r += str(n)

    res.append(r)



for val in res:

    print(val)
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 734 ms):
def lists(L, X):
    for i in range(len(L)):
        max1 = int(L[i])
        index = i
        for j in range(i, min(i + 10, len(L))):
            if int(L[j]) - (j - i) > max1:
                max1 = int(L[j]) - (j - i)
                index = j
        while index > i:
            L[index], L[index - 1] = L[index - 1], L[index]
            index -= 1
        X.append(max1)

n = int(input())
for _ in range(n):
    L = [int(j) for j in input().strip()]
    X = []
    lists(L, X)
    y = ''.join(map(str, X))
    print(y)


Solution 2 (runtime: 218 ms):
for _ in range(int(input())):

    s=list(input())

    #print(s)

    for i in range(len(s)):

        val=str(s[i])

        index=i



        for j in range(i+1,min(i+10,len(s))):

            if (int(s[j])-(j-i))>int(val):

                val=str(int(s[j])-(j-i))

                index=j 

        

        if index!=i:

            prev=s[i]

            for j in range(i+1,index+1):

                x=s[j]

                s[j]=prev

                prev=x

                

            s[i]=val

    print("".join(s))
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 734 ms):
def lists(L, X):
    for i in range(len(L)):
        max1 = int(L[i])
        index = i
        for j in range(i, min(i + 10, len(L))):
            if int(L[j]) - (j - i) > max1:
                max1 = int(L[j]) - (j - i)
                index = j
        while index > i:
            L[index], L[index - 1] = L[index - 1], L[index]
            index -= 1
        X.append(max1)

n = int(input())
for _ in range(n):
    L = [int(j) for j in input().strip()]
    X = []
    lists(L, X)
    y = ''.join(map(str, X))
    print(y)


Solution 2 (runtime: 624 ms):
def solve():

    s = list(input().strip())  # Convert string to list for mutability

    n = len(s)



    for i in range(1, n):

        j, curr = i - 1, i

        while j >= 0 and s[curr] > '0' and s[curr] > chr(ord(s[j]) + 1):

            s[curr] = chr(ord(s[curr]) - 1)  # Decrease digit

            s[curr], s[j] = s[j], s[curr]  # Swap

            curr -= 1

            j = curr - 1



    print("".join(s))



# Handling multiple test cases

t = int(input())

for _ in range(t):

    solve()
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 734 ms):
def lists(L, X):
    for i in range(len(L)):
        max1 = int(L[i])
        index = i
        for j in range(i, min(i + 10, len(L))):
            if int(L[j]) - (j - i) > max1:
                max1 = int(L[j]) - (j - i)
                index = j
        while index > i:
            L[index], L[index - 1] = L[index - 1], L[index]
            index -= 1
        X.append(max1)

n = int(input())
for _ in range(n):
    L = [int(j) for j in input().strip()]
    X = []
    lists(L, X)
    y = ''.join(map(str, X))
    print(y)


Solution 2 (runtime: 234 ms):
n = int(input())

for x in range(n):

s= list(map(int, input()))

g = len(s)

for i in range(1,g):

for j in range(0, s[i]):

if(i-j-1 < 0):

break

if(s[i-j]-1 > s[i-j-1]):

temp = s[i-j-1]

s[i-j-1] = s[i-j]-1

s[i-j] = temp

else:

break

result = ''.join(map(str,s))

print(result)
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 734 ms):
def lists(L, X):
    for i in range(len(L)):
        max1 = int(L[i])
        index = i
        for j in range(i, min(i + 10, len(L))):
            if int(L[j]) - (j - i) > max1:
                max1 = int(L[j]) - (j - i)
                index = j
        while index > i:
            L[index], L[index - 1] = L[index - 1], L[index]
            index -= 1
        X.append(max1)

n = int(input())
for _ in range(n):
    L = [int(j) for j in input().strip()]
    X = []
    lists(L, X)
    y = ''.join(map(str, X))
    print(y)


Solution 2 (runtime: 156 ms):
for _ in range(int(input())):

a = input()

s = [int(digit) for digit in a]

n = len(s)

for i in range(n):

best_value = s[i]

best_idx = -1

for j in range(i + 1, min(i + 9, n)):

score = s[j]-(j - i)

if score>best_value:

best_value=score

best_idx=j



if best_idx != -1:

# print(best_value,s[best_idx],i,best_idx)

s[i], s[best_idx] = best_value, s[i]

for j in range(best_idx, i+1, -1):

s[j], s[j - 1] = s[j - 1], s[j]

# print(s)



print("".join(map(str, s)))
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 734 ms):
def lists(L, X):
    for i in range(len(L)):
        max1 = int(L[i])
        index = i
        for j in range(i, min(i + 10, len(L))):
            if int(L[j]) - (j - i) > max1:
                max1 = int(L[j]) - (j - i)
                index = j
        while index > i:
            L[index], L[index - 1] = L[index - 1], L[index]
            index -= 1
        X.append(max1)

n = int(input())
for _ in range(n):
    L = [int(j) for j in input().strip()]
    X = []
    lists(L, X)
    y = ''.join(map(str, X))
    print(y)


Solution 2 (runtime: 171 ms):
mod = 1e9 + 7

for _ in range(int(input())):

s = list(map(int,list(input())))

for i in range(len(s)-1):

mxi = -1

mx = 0

for j in range(1,10):

if i + j >= len(s):

break

if int(s[i+j]) - j - int(s[i]) > mx:

mx = int(s[i+j]) - j - int(s[i])

mxi = j

if mxi == -1:

continue



for jj in range(i+mxi,i,-1):

s[jj],s[jj-1] = s[jj-1],s[jj] - 1



print(''.join(list(map(str,s))))
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 734 ms):
def lists(L, X):
    for i in range(len(L)):
        max1 = int(L[i])
        index = i
        for j in range(i, min(i + 10, len(L))):
            if int(L[j]) - (j - i) > max1:
                max1 = int(L[j]) - (j - i)
                index = j
        while index > i:
            L[index], L[index - 1] = L[index - 1], L[index]
            index -= 1
        X.append(max1)

n = int(input())
for _ in range(n):
    L = [int(j) for j in input().strip()]
    X = []
    lists(L, X)
    y = ''.join(map(str, X))
    print(y)


Solution 2 (runtime: 218 ms):
t =  int(input())

def solve():

s = [int(i) for i in list(input())]

n = len(s)

for i in range(1,n,1):

for j in range(max(i-10, 0), i):

if s[i] - (i-j) > s[j]:

tmp = s[j:i]

s[j] = s[i] - (i-j)

s[j+1:i+1] = tmp

break

print("".join([str(i) for i in s]))

return

for i in range(t):

solve()
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 734 ms):
def lists(L, X):
    for i in range(len(L)):
        max1 = int(L[i])
        index = i
        for j in range(i, min(i + 10, len(L))):
            if int(L[j]) - (j - i) > max1:
                max1 = int(L[j]) - (j - i)
                index = j
        while index > i:
            L[index], L[index - 1] = L[index - 1], L[index]
            index -= 1
        X.append(max1)

n = int(input())
for _ in range(n):
    L = [int(j) for j in input().strip()]
    X = []
    lists(L, X)
    y = ''.join(map(str, X))
    print(y)


Solution 2 (runtime: 906 ms):
def solve():

s = list(input())

n = len(s)

while True:

changed = False

for i in range(1, n):

if s[i] != '0' and int(s[i]) - 1 > int(s[i-1]):

num = int(s[i])

s[i] = str(int(s[i-1]))

s[i-1] = str(num - 1)

changed = True

if not changed:

break

print("".join(s))



t = int(input())

for _ in range(t):

solve()
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 734 ms):
def lists(L, X):
    for i in range(len(L)):
        max1 = int(L[i])
        index = i
        for j in range(i, min(i + 10, len(L))):
            if int(L[j]) - (j - i) > max1:
                max1 = int(L[j]) - (j - i)
                index = j
        while index > i:
            L[index], L[index - 1] = L[index - 1], L[index]
            index -= 1
        X.append(max1)

n = int(input())
for _ in range(n):
    L = [int(j) for j in input().strip()]
    X = []
    lists(L, X)
    y = ''.join(map(str, X))
    print(y)


Solution 2 (runtime: 265 ms):
for _ in range(int(input())):

s = list(map(int,input()))

for i in range(9):

for j in range(len(s)-1):

if s[j] < s[j+1] - 1:

s[j],s[j+1] = s[j+1]-1,s[j]

print(*s,sep= '')
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 515 ms):

def solve(s):
	if type(s) is str: s = [*map(int,iter(s))]
	s.reverse()
	i = len(s)-1
	o = []
	while i >= 0:
		b = 0
		for j in range(1,min(i+1,10)):
			if s[i-j] - j > s[i-b] - b:
				b = j
		o.append(s[i-b]-b)
		del s[i-b]
		i -= 1
	return o

for _ in range(int(input())):
	print("".join(map(str,solve(input()))))

Solution 2 (runtime: 187 ms):

t=int(input())
for _ in range(t):
    s =[int(x) for x in list(input())]
    n=len(s)
    for i in range(1,n):
        if s[i] !=0 and s[i] !=1:
            for j in range(i-1,-1,-1):
                if s[j]<s[j+1]-1:
                    temp=s[j+1]-1
                    s[j+1]=s[j]
                    s[j]=temp
                else:
                    break
        else:
            continue
    for x in s:
        print(x, end="")
    print()
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 515 ms):

def solve(s):
	if type(s) is str: s = [*map(int,iter(s))]
	s.reverse()
	i = len(s)-1
	o = []
	while i >= 0:
		b = 0
		for j in range(1,min(i+1,10)):
			if s[i-j] - j > s[i-b] - b:
				b = j
		o.append(s[i-b]-b)
		del s[i-b]
		i -= 1
	return o

for _ in range(int(input())):
	print("".join(map(str,solve(input()))))

Solution 2 (runtime: 218 ms):
for _ in range(int(input())):
    s = list(map(int, list(input())))
    n = len(s)
    

    for i in range(1, n):
        if s[i] == 0:
            continue
        for j in range(max(0, i - 9), i):
            if s[j] < s[i] - (i - j):
                new_head_value = s[i] - (i - j)
                idx = i - 1
                while idx != j - 1:
                    s[idx], s[idx + 1] = s[idx + 1], s[idx]
                    idx -= 1
                s[j] = new_head_value
                break


    for i in range(n):
        print(s[i], end='')
    print()
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 515 ms):

def solve(s):
	if type(s) is str: s = [*map(int,iter(s))]
	s.reverse()
	i = len(s)-1
	o = []
	while i >= 0:
		b = 0
		for j in range(1,min(i+1,10)):
			if s[i-j] - j > s[i-b] - b:
				b = j
		o.append(s[i-b]-b)
		del s[i-b]
		i -= 1
	return o

for _ in range(int(input())):
	print("".join(map(str,solve(input()))))

Solution 2 (runtime: 359 ms):
def recursive(a,begin):
    if begin==len(a):
        return
    max_val = a[begin]
    max_index = begin
    for i in range(begin, min(len(a), begin+9)):
        if max_val<(a[i] - (i-begin)):
            max_val= a[i]-i+begin
            max_index = i
    while max_index !=begin:
        a[max_index], a[max_index-1] = a[max_index-1],a[max_index]-1
        max_index-=1
def solve():
    n = input()
    a = list(map(int,n))
    begin = 0
    while begin<len(a):
        recursive(a,begin)
        begin+=1
    print(''.join(map(str, a)))
x = int(input())
for i in range(x):
    solve()
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 515 ms):

def solve(s):
	if type(s) is str: s = [*map(int,iter(s))]
	s.reverse()
	i = len(s)-1
	o = []
	while i >= 0:
		b = 0
		for j in range(1,min(i+1,10)):
			if s[i-j] - j > s[i-b] - b:
				b = j
		o.append(s[i-b]-b)
		del s[i-b]
		i -= 1
	return o

for _ in range(int(input())):
	print("".join(map(str,solve(input()))))

Solution 2 (runtime: 218 ms):
def f(arr):
    i=0
    while i<len(arr):
        l=i+1
        r=min(i+8,len(arr)-1)
        max_eff=-1
        ind=-1
        for k in range(l,r+1):
            eff=arr[k]-(k-i)
            if eff>max_eff:
                ind=k
                max_eff=eff
        if max_eff>arr[i]:
            for k in range(ind,i,-1):
                temp=arr[k]
                arr[k]=arr[k-1]
                arr[k-1]=temp
            arr[i]=max_eff
        i+=1
    return arr



if __name__=="__main__":
    t=int(input())
    for i in range(t):
        s=input()
        arr=[int(i) for i in s]
        ans=f(arr)
        print("".join(map(str,ans)))
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 515 ms):

def solve(s):
	if type(s) is str: s = [*map(int,iter(s))]
	s.reverse()
	i = len(s)-1
	o = []
	while i >= 0:
		b = 0
		for j in range(1,min(i+1,10)):
			if s[i-j] - j > s[i-b] - b:
				b = j
		o.append(s[i-b]-b)
		del s[i-b]
		i -= 1
	return o

for _ in range(int(input())):
	print("".join(map(str,solve(input()))))

Solution 2 (runtime: 171 ms):
for _ in range(int(input())):
    s = list(map(int,input()))

    for i in range(10):
        for j in range(len(s)-1):
            if s[j] + 1 < s[j+1]:
                s[j], s[j+1] = s[j+1] - 1, s[j]

    print("".join(map(str, s)))
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 515 ms):

def solve(s):
	if type(s) is str: s = [*map(int,iter(s))]
	s.reverse()
	i = len(s)-1
	o = []
	while i >= 0:
		b = 0
		for j in range(1,min(i+1,10)):
			if s[i-j] - j > s[i-b] - b:
				b = j
		o.append(s[i-b]-b)
		del s[i-b]
		i -= 1
	return o

for _ in range(int(input())):
	print("".join(map(str,solve(input()))))

Solution 2 (runtime: 327 ms):
from sys import stdin

def solve():
    s = list(stdin.readline()[:-1])
    for i in range(len(s)):
        best = int(s[i])
        pos = i
        for j in range(i, min(i + 10, len(s))):
            if int(s[j]) - j + i > best:
                best = int(s[j]) - j + i
                pos = j
        
        while pos > i:
            s[pos], s[pos - 1] = s[pos - 1], str(int(s[pos])-1)
            pos -= 1
        
    return "".join(s)

for _ in range(int(stdin.readline())): print(solve())
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 515 ms):

def solve(s):
	if type(s) is str: s = [*map(int,iter(s))]
	s.reverse()
	i = len(s)-1
	o = []
	while i >= 0:
		b = 0
		for j in range(1,min(i+1,10)):
			if s[i-j] - j > s[i-b] - b:
				b = j
		o.append(s[i-b]-b)
		del s[i-b]
		i -= 1
	return o

for _ in range(int(input())):
	print("".join(map(str,solve(input()))))

Solution 2 (runtime: 202 ms):
t=int(input())
for _ in range(t):
    l=list(map(int,list(input())))
    for i in range(len(l)-1):
        mx=l[i]
        ind=i
        for j in range(i+1,min(i+10,len(l))):
            if l[j]-(j-i)>mx:
                mx=l[j]-(j-i)
                ind=j
        first=l[i]
        for j in range(ind,i,-1):
            l[j]=l[j-1]
        l[i]=mx
        # print(l)
    print(*l, sep='')
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 515 ms):

def solve(s):
	if type(s) is str: s = [*map(int,iter(s))]
	s.reverse()
	i = len(s)-1
	o = []
	while i >= 0:
		b = 0
		for j in range(1,min(i+1,10)):
			if s[i-j] - j > s[i-b] - b:
				b = j
		o.append(s[i-b]-b)
		del s[i-b]
		i -= 1
	return o

for _ in range(int(input())):
	print("".join(map(str,solve(input()))))

Solution 2 (runtime: 624 ms):
def func():
    tests = int(input())
    for i in range(tests):
        x = input()
        arr = []
        for c in x:
            arr.append(int(c))
        for i in range(len(arr)-1):
            c = arr[i]
            maxx = 0
            idx = 0
            for j in range(1,9-c):
                if i+j >= len(arr):
                    break
                if maxx < arr[i+j] - c - j:
                    maxx = arr[i+j] - c - j
                    idx = j
            if maxx > 0:
                tmp = arr[i+idx] - idx
                for k in range(idx,0,-1):
                    arr[i+k] = arr[i+k-1]
                arr[i] = tmp
        ans = ""
        for a in arr:
            ans += str(a)
        print(ans)
    return  

if __name__ == '__main__':
    func()
Problem: 2050D - Digital string maximization
Language: python

Solution 1 (runtime: 515 ms):

def solve(s):
	if type(s) is str: s = [*map(int,iter(s))]
	s.reverse()
	i = len(s)-1
	o = []
	while i >= 0:
		b = 0
		for j in range(1,min(i+1,10)):
			if s[i-j] - j > s[i-b] - b:
				b = j
		o.append(s[i-b]-b)
		del s[i-b]
		i -= 1
	return o

for _ in range(int(input())):
	print("".join(map(str,solve(input()))))

Solution 2 (runtime: 202 ms):
#Question :
#Link to the question: 

"""Author : Nishant Kumar"""

def solve():
    s= input().strip()
    digit = [int(ch) for ch in s]
    n = len(digit)
    for i in range(n):
        copy_i = i 
        while copy_i >0 and digit[copy_i]>0 and digit[copy_i]-1>digit[copy_i-1]:
            val = digit[copy_i]
            digit[copy_i]=digit[copy_i-1]
            digit[copy_i-1]=val-1
            if copy_i>0:
                copy_i-=1
            else:
                break
    print("".join(map(str,digit)))



for _ in range(int(input())):
    solve()

"""Author : Nishant Kumar"""