Problem: 2050E - Three Strings
Language: python

Solution 1 (runtime: 2390 ms):
import sys
input = sys.stdin.readline
sys.setrecursionlimit(10000)

############ ---- Input Functions ---- ############
def inp():
    return(int(input()))
def inlt():
    return(list(map(int,input().split())))
def insr():
    s = input()
    return(list(s[:len(s) - 1]))
def invr():
    return(map(int,input().split()))


def count_changes(a, b, c, i, j, k, memo_arr):
    if memo_arr[i][j] == -1:
        if k == len(c):
            memo_arr[i][j] = 0
        elif i == len(a):
            ans = 0
            for count in range(len(b[j:])):
                if b[j + count] != c[k+count]:
                    ans += 1
            memo_arr[i][j] = ans
        elif j == len(b):           
            ans = 0
            for count in range(len(a[i:])):
                if a[i + count] != c[k+count]:
                    ans += 1
            memo_arr[i][j] = ans
        else:
            case1 = count_changes(a, b, c, i+1, j, k+1, memo_arr)
            if a[i] != c[k]:
                case1 += 1
            case2 = count_changes(a, b, c, i, j+1, k+1, memo_arr)
            if b[j] != c[k]:
                case2 += 1
            memo_arr[i][j] = min(case1, case2)
    
    return memo_arr[i][j]


t = inp()
for _ in range(t):
    a = insr()
    b = insr()
    c = insr()

    i = 0
    j = 0

    k = 0
    memo_arr = [[-1 for _ in range(len(b)+1)] for _ in range(len(a) + 1)]
    print(count_changes(a, b, c, i, j, k, memo_arr))



Solution 2 (runtime: 280 ms):
# import sys
# sys.setrecursionlimit(2*(10**3))
# for _ in range(int(input())):
#     a = input()
#     b = input()
#     c = input()
#     dic = {}

#     def calculate(i,j,k,dic):
#         if (i,j,k) in dic:
#             return dic[(i,j,k)]
#         if i == len(a):
#             count = 0
#             while k <len(c):
#                 if c[k] != b[j]:
#                     count+=1
#                 k+=1
#                 j+=1
#             dic[(i,j,k)] = count
#             return count
#         if j == len(b):
#             count = 0
#             while k < len(c):
#                 if c[k] != a[i]:
#                     count+=1
#                 i+=1
#                 k+=1
#             dic[(i,j,k)] = count
#             return count 

#         if c[k]!=a[i] and c[k]!=b[j]:
#             count = 1 + min(calculate(i+1,j,k+1,dic),calculate(i,j+1,k+1,dic))
#         elif c[k]!=a[i] and c[k] == b[j]:
#             count = min(calculate(i,j+1,k+1,dic),calculate(i+1,j,k+1,dic)+1)
#         elif c[k]==a[i] and c[k] != b[j]:
#             count = min(calculate(i,j+1,k+1,dic)+1,calculate(i+1,j,k+1,dic))
#         else:
#             count = min(calculate(i+1,j,k+1,dic),calculate(i,j+1,k+1,dic))

#         dic[(i,j,k)] = count
#         return count    
            
#     print(calculate(0,0,0,dic))

for _ in range(int(input())):
    a = input()
    b = input()
    c = input()

    dp = [[float('inf')] * (len(b) + 1) for _ in range(len(a) + 1)]

    for i in range(len(a) + 1):
        for j in range(len(b) + 1):
            k = i + j
            if k > len(c):
                continue

            if i == 0 and j == 0:
                dp[i][j] = 0
            else:
                if i > 0 and c[k - 1] == a[i - 1]:
                    dp[i][j] = min(dp[i][j], dp[i - 1][j])
                if j > 0 and c[k - 1] == b[j - 1]:
                    dp[i][j] = min(dp[i][j], dp[i][j - 1])
                if i > 0 and c[k - 1] != a[i - 1]:
                    dp[i][j] = min(dp[i][j], dp[i - 1][j] + 1)
                if j > 0 and c[k - 1] != b[j - 1]:
                    dp[i][j] = min(dp[i][j], dp[i][j - 1] + 1)

    print(dp[len(a)][len(b)])