Problem: 2063B - Subsequence Update
Language: java

Solution 1 (runtime: 343 ms):
import java.util.*;

public class Solution {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();  // number of test cases
        while (t-- > 0) {
            // Read n, l, r
            int n = sc.nextInt();
            int l = sc.nextInt();  // 1-based index
            int r = sc.nextInt();  // 1-based index

            // Read array arr
            long[] arr = new long[n + 1];  // Using long[] for larger values, and n+1 to handle 1-based indexing
            for (int i = 1; i <= n; i++) {
                arr[i] = sc.nextLong();
            }

            // Step 1: Calculate the sum for the range [l, r]
            long initialSum = 0;
            for (int i = l; i <= r; i++) {
                initialSum += arr[i];
            }
            long min = initialSum;  // Store the initial sum as the minimum

            // Step 2: Find the smallest `r - l + 1` elements from [1, r]
            List<Long> prefix = new ArrayList<>();
            for (int i = 1; i <= r; i++) {
                prefix.add(arr[i]);
            }
            Collections.sort(prefix);
            long prefixSum = 0;
            // Sum the smallest `r - l + 1` elements from the sorted prefix
            for (int i = 0; i < r - l + 1; i++) {
                prefixSum += prefix.get(i);
            }
            min = Math.min(min, prefixSum);  // Update the minimum sum

            // Step 3: Find the smallest `r - l + 1` elements from [l, n]
            List<Long> suffix = new ArrayList<>();
            for (int i = l; i <= n; i++) {
                suffix.add(arr[i]);
            }
            Collections.sort(suffix);
            long suffixSum = 0;
            // Sum the smallest `r - l + 1` elements from the sorted suffix
            for (int i = 0; i < r - l + 1; i++) {
                suffixSum += suffix.get(i);
            }
            min = Math.min(min, suffixSum);  // Update the minimum sum

            // Output the result for the current test case
            System.out.println(min);
        }
    }
}


Solution 2 (runtime: 452 ms):
import java.util.Scanner;
public class Subsequence_Update{
    public static void merge(int[] arr, int l, int m, int r){
        int n1 = m - l + 1;
        int n2 = r - m;

        int[] L = new int[n1];
        int[] R = new int[n2];

        for(int i = 0; i<n1; i++){
            L[i] = arr[l + i];
        }

        for(int i = 0; i<n2; i++){
            R[i] = arr[m + 1 + i];
        }

        int i = 0;
        int j = 0;
        int k = l;

        while(i<n1 && j<n2){
            if(L[i] <= R[j]){
                arr[k] = L[i];
                i++;
            }else{
                arr[k] = R[j];
                j++;
            }
            k++;
        }

        while(i<n1){
            arr[k] = L[i];
            i++;
            k++;
        }

        while(j<n2){
            arr[k] = R[j];
            j++;
            k++;
        }
    }
    public static void mergeSort(int[] arr, int l, int r){
        if(l<r){
            int m = (l+r)/2;
            mergeSort(arr, l, m);
            mergeSort(arr, m+1, r);
            merge(arr, l, m, r);
        }
    }
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        Long t = sc.nextLong();
        for(int i = 0; i<t; i++){
            int n = sc.nextInt();
            long l = sc.nextLong();
            long r = sc.nextLong();
            int[] arr = new int[n];
            for(int j = 0; j<n; j++){
                arr[j] = sc.nextInt();
            }

            int[] arr1 = new int[(int) r];
            for(long j = 0; j<r; j++){
                arr1[(int)j] = arr[(int)j];
            }

            int[] arr2 = new int[(int)(n-l + 1)];
            for(int j = 0; j<n-l+1; j++){
                arr2[(int)j] = arr[(int)(j+l-1)];
            }

            mergeSort(arr1, 0, (int)(r-1));
            mergeSort(arr2, 0, (int)(n-l));

            Long sum1 = 0l;
            Long sum2 = 0l;

            for(int j = 0; j<(r - l + 1); j++){
                sum1 += arr1[j];
                sum2 += arr2[j];
            }

            if(sum1<=sum2){
                System.out.println(sum1);
            }else{
                System.out.println(sum2);
            }
        }
    }
}