Problem: 2050E - Three Strings
Language: python

Solution 1 (runtime: 265 ms):
import sys, random, math, string, itertools
from copy import deepcopy
from collections import defaultdict, Counter, deque
from heapq import heapify, heappush, heappop
from functools import cache
from bisect import bisect_left, bisect_right
from types import GeneratorType
from typing import *

input = lambda: sys.stdin.readline().strip()


def debug(*x, **y):
    if not DEBUG_ENABLED:
        return
    print(*x, (y if y != {} else "\b"), file=sys.stderr)


###############################################################################


def solve_bruteforce(case=None):
    pass


def execute_once():
    pass

def solve(case=None):
    a,b,c = input(),input(),input()

    # @cache
    # def dp(i,j):
    #     ind = i+j 

    #     if ind == len(c):
    #         return 0
        
    #     ch = c[ind]

    #     return min(
    #         (dp(i+1,j) + (1 if a[i] != ch else 0) ) if i < len(a) else math.inf,
    #         (dp(i,j+1) + (1 if b[j] != ch else 0) ) if j < len(b) else math.inf
    #     )

    n,m = len(a),len(b)

    dp = [[math.inf]*(m+1) for _ in range(n+1)]
    dp[-1][-1] = 0

    for i in range(n,-1,-1):
        for j in range(m,-1,-1):
            if i+j == len(c):
                continue

            ch = c[i+j]

            if i < n:
                dp[i][j] = min(dp[i][j], dp[i+1][j] + (1 if a[i] != ch else 0))
            if j < m:
                dp[i][j] = min(dp[i][j], dp[i][j+1] + (1 if b[j] != ch else 0))
    
    # for i in dp:
    #     print(i)

    ans = dp[0][0]
    print(ans)


INPUT_NUMBER_OF_TEST_CASES = 1
SKIP_SOLVE = 0
DEBUG_ENABLED = 1
MOD = 10**9 + 7
BOOLEAN_RETURN = 0
TRUE_MAPPING, FALSE_MAPPING = "YES", "NO"

###############################################################################


class CustomHashMap:
    def __init__(self, map_type=dict, arg=None):
        """
        Custom HashMap for Python's Anti-hash-table test
        :param map_type: type of the map (allowed types: dict, defaultdict, Counter)
        :param arg: argument for the map (should be list if map_type is Counter and function if map_type is defaultdict)
        """
        self.RANDOM = random.randrange(2**62)
        if map_type == Counter:
            self.dict = map_type([self.wrapper(i) for i in arg])
        elif map_type == defaultdict:
            self.dict = map_type(arg)
        else:
            self.dict = map_type()

    def wrapper(self, num):
        return num ^ self.RANDOM

    def __setitem__(self, key, value):
        self.dict[self.wrapper(key)] = value

    def __getitem__(self, key):
        return self.dict[self.wrapper(key)]

    def __contains__(self, key):
        return self.wrapper(key) in self.dict

    def __iter__(self):
        return iter(self.wrapper(i) for i in self.dict)

    def keys(self):
        return [self.wrapper(i) for i in self.dict]

    def values(self):
        return [i for i in self.dict.values()]

    def items(self):
        return [(self.wrapper(i), j) for i, j in self.dict.items()]

    def __repr__(self):
        return repr({self.wrapper(i): j for i, j in self.dict.items()})


def recursion_limit_fix(f):
    """
    recursion limit fix decorator, change 'return' to 'yield' and add 'yield' before calling the function
    and add 'yield' after the function if not returning anything
    """
    stack = []

    def wrappedfunc(*args, **kwargs):
        if stack:
            return f(*args, **kwargs)
        else:
            to = f(*args, **kwargs)
            while True:
                if type(to) is GeneratorType:
                    stack.append(to)
                    to = next(to)
                else:
                    stack.pop()
                    if not stack:
                        break
                    to = stack[-1].send(to)
            return to

    return wrappedfunc


def binary_search(left, right, check, start_from_left):
    if start_from_left:
        ans = left
    else:
        ans = right
    while left <= right:
        mid = (left + right) // 2
        if start_from_left:
            if check(mid):
                ans, left = mid, mid + 1
            else:
                right = mid - 1
        else:
            if check(mid):
                ans, right = mid, mid - 1
            else:
                left = mid + 1
    return ans


execute_once()

if not SKIP_SOLVE:
    for t in range(int(input()) if INPUT_NUMBER_OF_TEST_CASES else 1):
        if BOOLEAN_RETURN:
            print(TRUE_MAPPING if solve(t + 1) else FALSE_MAPPING)
        else:
            solve(t + 1)


Solution 2 (runtime: 1202 ms):
# author 
# Kidus Guade

import sys
import random
from types import GeneratorType
from sys import stdin,stdout
from math import gcd,floor,sqrt,log, ceil
from collections import defaultdict, Counter, deque
from bisect import bisect_left,bisect_right, insort_left, insort_right
def ints(): return map(int, sys.stdin.readline().strip().split())
def li(): return list(map(int, sys.stdin.readline().strip().split()))
def string(): return sys.stdin.readline().strip()
def get_int(): return int(sys.stdin.readline().strip())
def li_strings(): return list(map(str, sys.stdin.readline().strip().split()))


def bootstrap(f, stack=[]):
    def wrappedfunc(*args, **kwargs):
        if stack:
            return f(*args, **kwargs)
        else:
            to = f(*args, **kwargs)
            while True:
                if type(to) is GeneratorType:
                    stack.append(to)
                    to = next(to)
                else:
                    stack.pop()
                    if not stack:
                        break
                    to = stack[-1].send(to)
            return to
    return wrappedfunc
        

def primeFactors(n):
    
    i = 2
    primfac = []
    while i * i <= n:
        while n % i == 0:
            primfac.append(i)
            n = n / i
        i = i + 1
    if n > 1:
        primfac.append(int(n))
    return primfac
def prime_sieve(n):
    is_prime = [True for _ in range(n + 1)]
    is_prime[0] = is_prime[1] = False
    i = 2
    while i * i <= n:
        if is_prime[i]:
            j = i * i
            while j <= n:
                is_prime[j] = False
                j += i
        i += 1
    return is_prime
def find_divisors(number):
    divisors = []
    for i in range(1, int(number**0.5) + 1):
        if number % i == 0:
            divisors.append(i)
            if i != number // i:
                divisors.append(number // i)
    return divisors    
def solve():
    a = string()
    b = string()
    c = string()
    dp = [[float("inf") for _ in range(len(a) + 1)] for _ in range(len(c) + 1)]
    for i in range(len(a) + 1):
        dp[len(c)][i] = 0
  
    for i in range(len(c) -1, -1, -1):
        for j in range(len(a) + 1):
            if j > i:
                continue
            k = i - j
           
            vv1, vv2= float("inf"), float("inf")
            if j  < len(a):
                if a[j] == c[i]:
                    vv1 = dp[i + 1][j +1]
                else:
                    vv1 = 1 + dp[i + 1][j + 1]
            if k < len(b):
                if b[k] == c[i]:
                    vv2 = dp[i + 1][j]
                else:
                    vv2 = 1 + dp[i + 1][j]
            
            dp[i][j] = min(min(vv1, vv2), dp[i][j])
    return dp[0][0]
    a = string()
    b = string()
    c = string()

    

   
    memo = [[float('inf') for _ in range(len(c) + 1)] for _ in range(len(a) + 1)]
    
 
    for i in range(len(a) + 1):
        memo[i][len(c)] = 0

  
    for k in range(len(c) - 1, -1, -1):
        for i in range(len(a) + 1):
            if i < len(a):
                if a[i] == c[k]:
                    vv = memo[i + 1][k + 1]
                else:
                    vv = 1 + memo[i + 1][k + 1]
                memo[i][k] = min(memo[i][k], vv)

            if k - i < len(b):
                if b[k - i] == c[k]:
                    vv = memo[i][k + 1]
                else:
                    vv = 1 + memo[i][k + 1]
                memo[i][k] = min(memo[i][k], vv)

    # The result is stored in memo[0][0]
    return memo[0][0]
    
    

# Call the solve function
# result = solve()
# print(result)
    
        
                



    
    # return dp[len(a)][len(c)]

   

    memo = [[0 for _ in range(len(c) + 1)] for _ in range(len(a) + 1)]
    def dp(i,k):
        if k == len(c):
            yield 0
        if memo[i][k]:
            yield memo[i][k]
        val = float('inf')
        if i < len(a):
            if a[i] == c[k]:
                vv = dp(i + 1,k + 1)
                
            else:
                vv = dp(i + 1,k + 1)
                vv += 1
            val = min(val, vv)
               
        if k - i < len(b):
            if b[k - i ] == c[k]:
                vv = dp(i,  k + 1)
              
            else:
                vv = dp(i, k + 1)
                vv += 1

            val = min(val, vv)
        memo[i][k] = val
        yield memo[i][k]
    return dp(0,0)

    
  


    
    
    
if __name__ == "__main__":
    for _ in range(get_int()):
        print(solve())