Problem: 2050C - Uninteresting Number
Language: python

Solution 1 (runtime: 249 ms):
for i in range(int(input())):
    n=(input())
    a=0
    for i in n:
        a+=int(i)
    a=a%9
    a=9-a
    if a==9:
        print("YES")
    else:
        if a%2!=0:
            p=0
            q=0
            for i in n:
                if i=="2":
                    p+=1
                if i=="3":
                    q+=1
            if a==1:
                if p>=5 or (p>=2 and q>=1):
                    print("YES")
                else:
                    print("NO")
            elif a==3:
                if q>=2 or p>=6 or (q>=1 and p>=3):
                    print("YES")
                else:
                    print("NO")
            elif a==5:
                if p>=7 or (q>=1 and p>=4) or (q>=2 and p>=1):
                    print("YES")
                else:
                    print('NO')
            else:
                if p>=8 or (q>=1 and p>=5) or (q>=2 and p>=2):
                    print("YES")
                else:
                    print("NO")
        else:
            if a<6:
                a=a//2
                ans=0
                for i in n:
                    if i=="2":
                        ans+=1
                if ans>=a:
                    print("YES")
                else:
                    print("NO")
            else:
                if a==6:
                    a=a//2
                    ans=0
                    for i in n:
                        if i=="2":
                            ans+=1
                    if ans>=a:
                        print("YES")
                    else:
                        for i in n:
                            if i=="3":
                                print("YES")
                                break
                        else:
                            print("NO")
                else:
                    a=a//2
                    ans=0
                    for i in n:
                        if i=="2":
                            ans+=1
                    if ans>=a:
                        print("YES")
                    else:
                        if ans<1:
                            print("NO")
                        else:
                            for i in n:
                                if i=="3":
                                    print("YES")
                                    break
                            else:
                                print("NO")

Solution 2 (runtime: 140 ms):
n = int(input())
for _ in range(n):
    a = input()
    k = 0
    two = 0
    three = 0
    q = False

    # Calculate the sum of digits and count of '2' and '3'
    for i in a:
        k += int(i)
        if i == '2':
            two += 1
        elif i == '3':
            three += 1

    # Check if the number is already divisible by 9
    if k % 9 == 0:
        print('YES')
        continue

    # Check combinations of extra contributions from '2' and '3'
    for x in range(two + 1):
        for y in range(three + 1):
            # Directly check divisibility without storing numbers
            if (k + 2 * x + 6 * y) % 9 == 0:
                print("YES")
                q = True
                break
        if q:  # Break outer loop if found
            break

    if not q:
        print("NO")