Problem: 2061D - Kevin and Numbers
Language: C++20 (GCC 13-64)

Previous submission (verdict: Time limit exceeded on test 6):
#include <bits/stdc++.h>



using namespace std;

typedef long long ll;

typedef array<int, 3> triple;

const ll INF = 0x3f3f3f3f3f3f3f3f;



#define MAXLEN 100001

#define min(a, b) ((a) < (b) ? (a) : (b))

#define max(a, b) ((a) > (b) ? (a) : (b))

#define mod(a, b) ((long long) ((a) - (b)*floor((long double) (a)/(b))))

#define FIXIO  ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);



#define vi vector<int>

#define vll vector<ll>

#define vpi vector<pair<int,int>>

#define all(v) v.begin(), v.end()

#define rall(v) v.rbegin(), v.rend()

#define pre(r, l) for (ll i = (r); i >= ll((l)); i--)

#define fro(l, r) for (ll i = (l); i <= ll((r)); i++)





void solve() {

    ll n, m;

    cin >> n >> m;

    vector<int> A(n), B(m);

    for (auto &i: A) cin >> i;

    for (auto &i: B) cin >> i;



    map<int, int> freqA, freqB;

    for (auto &i: A) freqA[i]++;

    for (auto &i: B) freqB[i]++;



    priority_queue<int> q;

    for (auto &i: freqB) {

        if (i.second > freqA[i.first]) {

            q.push(i.first);

        }

    }



    while (!q.empty()) {

        int curr = q.top(); q.pop();

        if (curr == 1) {

            cout << "NO" << '\n';

            return;

        }

        

        int divs = freqB[curr]-freqA[curr];

        freqB[curr] -= divs;

        freqB[curr/2] += divs;

        freqB[(curr+1)/2] += divs;



        if (freqB[curr/2] > freqA[curr/2])

            q.push(curr/2);

        if (curr/2 != (curr+1)/2)

            if (freqB[(curr+1)/2] > freqA[(curr+1)/2])

                q.push((curr+1)/2);

    }



    for (auto &i: freqB) {

        // cout << i.first << ':' << i.second << ' ';

        if (i.second != freqA[i.first]) {

            cout << "NO" << '\n';

            return;

        }

    }

    // cout << '\n';



    for (auto &i: freqA) {

        // cout << i.first << ':' << i.second << ' ';

        if (i.second != freqB[i.first]) {

            cout << "NO" << '\n';

            return;

        }

    }

    // cout << '\n';



    cout << "YES" << '\n';



}





int main() {

    FIXIO;



    ll t;

    t = 1;

    cin >> t;



    while (t--) {

        solve();

    }



    return 0;

}

Submission (verdict: Wrong answer on test 1):
#include <bits/stdc++.h>



using namespace std;

typedef long long ll;

typedef array<int, 3> triple;

const ll INF = 0x3f3f3f3f3f3f3f3f;



#define MAXLEN 100001

#define min(a, b) ((a) < (b) ? (a) : (b))

#define max(a, b) ((a) > (b) ? (a) : (b))

#define mod(a, b) ((long long) ((a) - (b)*floor((long double) (a)/(b))))

#define FIXIO  ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);



#define vi vector<int>

#define vll vector<ll>

#define vpi vector<pair<int,int>>

#define all(v) v.begin(), v.end()

#define rall(v) v.rbegin(), v.rend()

#define pre(r, l) for (ll i = (r); i >= ll((l)); i--)

#define fro(l, r) for (ll i = (l); i <= ll((r)); i++)





void solve() {

    ll n, m;

    cin >> n >> m;

    vector<int> A(n), B(m);

    for (auto &i: A) cin >> i;

    for (auto &i: B) cin >> i;



    map<int, int> freqA, freqB;

    for (auto &i: A) freqA[i]++;

    for (auto &i: B) freqB[i]++;



    priority_queue<int> q;

    for (auto &i: freqB) {

        if (i.second > freqA[i.first]) {

            q.push(i.first);

        }

    }



    while (!q.empty()) {

        if (freqA.rbegin()->first > freqB.rbegin()->first) {

            cout << "NO" << '\n';

            return;

        }



        int curr = q.top(); q.pop();

        if (curr == 1) {

            cout << "NO" << '\n';

            return;

        }

        

        int divs = freqB[curr]-freqA[curr];

        freqB[curr] -= divs;

        if (freqB[curr] == 0) {

            freqB.erase(curr);

        }

        freqB[curr/2] += divs;

        freqB[(curr+1)/2] += divs;



        if (freqB[curr/2] > freqA[curr/2])

            q.push(curr/2);

        if (curr/2 != (curr+1)/2)

            if (freqB[(curr+1)/2] > freqA[(curr+1)/2])

                q.push((curr+1)/2);

    }



    for (auto &i: freqB) {

        // cout << i.first << ':' << i.second << ' ';

        if (i.second != freqA[i.first]) {

            cout << "NO" << '\n';

            return;

        }

    }

    // cout << '\n';



    for (auto &i: freqA) {

        // cout << i.first << ':' << i.second << ' ';

        if (i.second != freqB[i.first]) {

            cout << "NO" << '\n';

            return;

        }

    }

    // cout << '\n';



    cout << "YES" << '\n';



}





int main() {

    FIXIO;



    ll t;

    t = 1;

    cin >> t;



    while (t--) {

        solve();

    }



    return 0;

}