Problem: 2061D - Kevin and Numbers
Language: C++20 (GCC 13-64)


Submission (verdict: Wrong answer on test 3):
#include <bits/stdc++.h>
#include <algorithm>
#include <limits>
#include <cstring>

using namespace std;

#define Code ios_base::sync_with_stdio(false);
#define By cin.tie(NULL);
#define chaki cout.tie(NULL);

#define ll long long
#define int ll
#define ld long double
#define ull unsigned long long
const ld pi = 3.141592653589793238;
const ll INF = LONG_LONG_MAX;
const ll MIN = LONG_LONG_MIN;
const ll mod = 1e9 + 7;

typedef pair<ll, ll> pll;
typedef vector<ll> vll;
typedef vector<pll> vpll;
typedef vector<string> vs;
typedef unordered_map<ll, ll> umll;
typedef map<ll, ll> mll;
#define ordered_set tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update>
#define vv(T) vector<vector<T>>
#define maxhp(T) priority_queue<T>
#define minhp(T) priority_queue<T, vector<T>, greater<T>>
#define mem(n, i) memset(n, i, sizeof n)
#define p(A, B) pair<A, B>

ll gcd(ll a, ll b)
{
    if (b == 0)
        return a;
    return gcd(b, a % b);
}
ll lcm(ll a, ll b) { return (a / gcd(a, b) * b); }
ll moduloMultiplication(ll a, ll b, ll mod)
{
    ll res = 0;
    a %= mod;
    while (b)
    {
        if (b & 1)
            res = (res + a) % mod;
        b >>= 1;
    }
    return res;
}
ll powermod(ll x, ll y, ll p)
{
    ll res = 1;
    x = x % p;
    if (x == 0)
        return 0;
    while (y > 0)
    {
        if (y & 1)
            res = (res * x) % p;
        y = y >> 1;
        x = (x * x) % p;
    }
    return res;
}

bool sorta(const pair<int, int> &a, const pair<int, int> &b) { return (a.second < b.second); }
bool sortd(const pair<int, int> &a, const pair<int, int> &b) { return (a.second > b.second); }

bool isPrime(ll n)
{
    if (n <= 1)
        return false;
    if (n <= 3)
        return true;
    if (n % 2 == 0 || n % 3 == 0)
        return false;
    for (int i = 5; i * i <= n; i = i + 6)
        if (n % i == 0 || n % (i + 2) == 0)
            return false;
    return true;
}
bool isPowerOfTwo(int n)
{
    if (n == 0)
        return false;
    return (ceil(log2(n)) == floor(log2(n)));
}
bool isPerfectSquare(ll x)
{
    if (x >= 0)
    {
        ll sr = sqrt(x);
        return (sr * sr == x);
    }
    return false;
}

#define ff first
#define ss second
#define mp make_pair
#define pb push_back

#define ps(x, y) fixed << setprecision(y) << x;

#define vi vector<int>
#define vs vector<string>
#define vvi vector<vector<int>>
#define vvs vector<vector<string>>
#define vpi vector<pair<int, int>>

#define i1(A, a) \
    A a;         \
    cin >> a;
#define i2(A, a, b) \
    A a, b;         \
    cin >> a >> b;
#define i3(A, a, b, c) \
    A a, b, c;         \
    cin >> a >> b >> c;
#define i4(A, a, b, c, d) \
    A a, b, c, d;         \
    cin >> a >> b >> c >> d;
#define i5(A, a, b, c, d, e) \
    A a, b, c, d, e;         \
    cin >> a >> b >> c >> d >> e;
#define i6(A, a, b, c, d, e, f) \
    A a, b, c, d, e, f;         \
    cin >> a >> b >> c >> d >> e >> f;

#define fl(i, k, n) for (ll i = k; i < n; i++)
#define bl(i, k, n) for (ll i = n; i >= k; i--)
#define yes cout << "YES" << "\n";
#define minus1 cout << "-1" << endl;
#define no cout << "NO" << "\n";
#define it(v) v.begin(), v.end()
#define itr(v) v.rbegin(), v.rend()
#define rit(v) v.end(), v.begin()

#define o(x) cout << (x) << " ";
#define o2(x, y) cout << (x) << " " << (y) << " ";
#define o3(x, y, z) cout << (x) << " " << (y) << " " << (z) << " ";

#define oe(x) cout << (x) << endl;
#define oe2(x, y) cout << (x) << " " << (y) << endl;
#define oe3(x, y, z) cout << (x) << " " << (y) << " " << (z) << endl;

#define inv(v, n)               \
    vi v(n);                    \
    for (int i = 0; i < n; i++) \
        cin >> v[i];

// code starts here

void solve()
{
    i2(int, n, m);
    inv(v, n);
    inv(v1, m);

    sort(it(v));
    sort(it(v1));

    int p1 = 1;
    int p2 = 0;

    int sum = v[0];

    while (p1 < n && p2 < m)
    {
        if (sum == v1[p2])
        {
            p2++;
            sum = 0;
        }
        else if (v[p1] == v1[p2])
        {
            p1++;
            p2++;
        }
        else if (abs(v[p1] - sum) <= 1 || sum == 0)
        {
            sum += v[p1];
            p1++;
        }
        else
        {
            no;
            return;
        }
    }
    if (p2 < m && sum == v1[p2])
    {
        p2++;
        sum = 0;
    }
    if (p2 == m && p1 == n)
    {
        yes;
    }
    else
    {
        no;
    }
}

signed main()
{

    Code By chaki

        ll tt = 1;
    cin >> tt;
    while (tt--)
    {
        solve();
    }
}