Problem: 2061D - Kevin and Numbers
Language: python

Code 1:
from random import randint
class MyDict:
    def __init__(self, func=lambda: 0):
        self.random = randint(0, (1 << 32) - 1) 
        self.default = func
        self.dict = {}
    def _hash(self, key):
        return self.random ^ hash(key)
    def __getitem__(self, key):
        mykey = self._hash(key)
        if mykey not in self.dict:
            self.dict[mykey] = self.default()
        return self.dict[mykey]
    def __setitem__(self, key, value):
        self.dict[self._hash(key)] = value
    def __delitem__(self, key):
        mykey = self._hash(key)
        if mykey in self.dict:
            del self.dict[mykey]
        else:
            raise KeyError(key)
    def get(self, key, default=None):
        return self.dict.get(self._hash(key), default)
    def keys(self):
        return [self._hash(k) for k in self.dict]
    def values(self):
        return self.dict.values()
    def items(self):
        return [(self._hash(k), v) for k, v in self.dict.items()]
    def __contains__(self, key):
        return self._hash(key) in self.dict
    def __iter__(self):
        return iter(self.keys())
    def __len__(self):
        return len(self.dict)
    def __str__(self):
        return str({self._hash(k): v for k, v in self.dict.items()})
    def __repr__(self):
        return f"MyDict({self.default}, {self.dict})"

import heapq
def solve():
    n,m = map(int,input().split())
    a = list(map(int,input().split()))
    b = list(map(int,input().split()))

    st = []
    for i in b :
        st.append(-i)

    heapq.heapify(st)

    freq = MyDict()
    for i in a:
        freq[i] += 1

    ii = -1
    for i in range(2*n-m):
        if not st:
            print("NO")
            return
        val = - heapq.heappop(st)
        if freq[val] != 0:
            freq[val] -= 1

        else:
            heapq.heappush(st,-(val // 2))
            heapq.heappush(st,-(val+2-1)//2)
    if st :
        print("NO")
    else:
        print("YES")

for __ in range(int(input())):
    solve()

Code 2:
from random import randint
class MyDict:
    def __init__(self, func=lambda: 0):
        self.random = randint(0, (1 << 32) - 1) 
        self.default = func
        self.dict = {}
    def _hash(self, key):
        return self.random ^ hash(key)
    def __getitem__(self, key):
        mykey = self._hash(key)
        if mykey not in self.dict:
            self.dict[mykey] = self.default()
        return self.dict[mykey]
    def __setitem__(self, key, value):
        self.dict[self._hash(key)] = value
    def __delitem__(self, key):
        mykey = self._hash(key)
        if mykey in self.dict:
            del self.dict[mykey]
        else:
            raise KeyError(key)
    def get(self, key, default=None):
        return self.dict.get(self._hash(key), default)
    def keys(self):
        return [self._hash(k) for k in self.dict]
    def values(self):
        return self.dict.values()
    def items(self):
        return [(self._hash(k), v) for k, v in self.dict.items()]
    def __contains__(self, key):
        return self._hash(key) in self.dict
    def __iter__(self):
        return iter(self.keys())
    def __len__(self):
        return len(self.dict)
    def __str__(self):
        return str({self._hash(k): v for k, v in self.dict.items()})
    def __repr__(self):
        return f"MyDict({self.default}, {self.dict})"

import heapq
def solve():
    n,m = map(int,input().split())
    a = list(map(int,input().split()))
    b = list(map(int,input().split()))

    st = []
    for i in b :
        st.append(-i)

    heapq.heapify(st)

    freq = MyDict()
    for i in a:
        freq[i] += 1

    for i in range(2*n-m):
        if not st:
            print("NO")
            return
        val = - heapq.heappop(st)
        if freq[val] != 0:
            freq[val] -= 1

        else:
            heapq.heappush(st,-(val // 2))
            heapq.heappush(st,-((val+2-1)//2))
    if st :
        print("NO")
    else:
        print("YES")

for __ in range(int(input())):
    solve()

Answer: 2