Problem:
Score : 200 points

Problem Statement

There are N gems. The value of the i-th gem is V_i.

You will choose some of these gems, possibly all or none, and get them.

However, you need to pay a cost of C_i to get the i-th gem.

Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.

Find the maximum possible value of X-Y.

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq C_i, V_i \leq 50

Input

Input is given from Standard Input in the following format:

N
V_1 V_2 ... V_N
C_1 C_2 ... C_N

Output

Print the maximum possible value of X-Y.

Sample Input 1

3
10 2 5
6 3 4

Sample Output 1

5

If we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.
We have X-Y = 5 here, which is the maximum possible value.

Sample Input 2

4
13 21 6 19
11 30 6 15

Sample Output 2

6

Sample Input 3

1
1
50

Sample Output 3

0

Solution in Scala (2.13.1) (judge verdict: Wrong Answer)



  import io.StdIn._
  object Main extends App {
    val diamonds = Input(readInt(), readLine(), readLine()).diamonds().foldLeft[Diamonds](Diamonds(Nil)) { (purchased: Diamonds, diamond: Diamond) =>
      val next = purchased.add(diamond)
      if (next.value() > purchased.value() && next.cost() < purchased.cost()) next
      else purchased
    }

    println(diamonds.value())
  }

  case class Input(numberOfDiamond: Int, values: Seq[Int], costs: Seq[Int]) {
    def diamonds(): Seq[Diamond] = {
      values.zip(costs).map { case (value, cost) => Diamond.apply(value, cost) }
    }
  }

  object Input {
    def apply(n: Int, values: String, costs: String): Input = {
      Input(n.toInt, values.split(' ').map(_.toInt), costs.split(' ').map(_.toInt))
    }
  }

case class Diamond(value:Int, cost: Int)

case class Diamonds(values: Seq[Diamond]) {
  def value(): Int =
    values.foldLeft(0)(_ + _.value)

  def cost(): Int =
    values.foldLeft(0)(_ + _.cost)

  def add(diamond: Diamond): Diamonds = Diamonds(values :+ diamond)
}