Problem:
Score: 300 points

Problem Statement

In Republic of Atcoder, there are N prefectures, and a total of M cities that belong to those prefectures.

City i is established in year Y_i and belongs to Prefecture P_i.

You can assume that there are no multiple cities that are established in the same year.

It is decided to allocate a 12-digit ID number to each city.

If City i is the x-th established city among the cities that belong to Prefecture i, the first six digits of the ID number of City i is P_i, and the last six digits of the ID number is x.

Here, if P_i or x (or both) has less than six digits, zeros are added to the left until it has six digits.

Find the ID numbers for all the cities.

Note that there can be a prefecture with no cities.

Constraints

1 \leq N \leq 10^5

1 \leq M \leq 10^5

1 \leq P_i \leq N

1 \leq Y_i \leq 10^9

Y_i are all different.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
P_1 Y_1
:
P_M Y_M

Output

Print the ID numbers for all the cities, in ascending order of indices (City 1, City 2, ...).

Sample Input 1

2 3
1 32
2 63
1 12

Sample Output 1

000001000002
000002000001
000001000001

As City 1 is the second established city among the cities that belong to Prefecture 1, its ID number is 000001000002.

As City 2 is the first established city among the cities that belong to Prefecture 2, its ID number is 000002000001.

As City 3 is the first established city among the cities that belong to Prefecture 1, its ID number is 000001000001.

Sample Input 2

2 3
2 55
2 77
2 99

Sample Output 2

000002000001
000002000002
000002000003

Solution in Scala (2.11.7) (judge verdict: Wrong Answer)

object Main extends App {
  val (n, m) = readLine.split(" ").map(_.toInt) match {
    case Array(n, m) => (n, m)
  }

  def convert(p: Int, order: Int) = f"${p}%06d${order}%06d"

  val lines: Array[Array[Int]] = (1 to m).toArray.map(id =>
    readLine.split(" ").map(_.toInt) match { case Array(p, y) => Array(id, p, y) })

  def order(a1: Array[Int], a2: Array[Int]): Boolean =
    if (a1(1) == a1(1)) a1(2) < a1(2) else a1(1) < a1(1)

  var currentP = 0
  var currentIndex = 1

  def next(a: Array[Int]) = {
    if (a(1) == currentP) currentIndex = currentIndex + 1 else {
      currentIndex = 1
      currentP = a(1)
    }
    Array(a(0), a(1), currentIndex)
  }

  lines
    .sortWith(order)
    .map(next)
    .sortBy(_(0))
    .foreach(a => println(convert(a(1), a(2))))

}