Problem:
Score : 200 points

Problem Statement

You are given a positive integer X.
Find the largest perfect power that is at most X.
Here, a perfect power is an integer that can be represented as b^p, where b is an integer not less than 1 and p is an integer not less than 2.

Constraints

1 ≤ X ≤ 1000

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the largest perfect power that is at most X.

Sample Input 1

10

Sample Output 1

9

There are four perfect powers that are at most 10: 1, 4, 8 and 9.
We should print the largest among them, 9.

Sample Input 2

1

Sample Output 2

1

Sample Input 3

999

Sample Output 3

961

Solution in Scala (2.11.7) (judge verdict: Accepted)

import scala.io.StdIn
object Main extends App {
  val x = StdIn.readLine.toInt
  val r = math.sqrt(x).toInt
  val res = if( r == 1) Seq(x) else
    (2 to r).map { i =>
      val e: Seq[Int] = for {
        j <- (2 to r)
        e = math.pow(i,j).toInt if(e <= x)
      } yield e
      e.max
    }
  val ans = res.max
  println(ans)
}