Problem:
Score : 200 points

Problem Statement

There are N gems. The value of the i-th gem is V_i.

You will choose some of these gems, possibly all or none, and get them.

However, you need to pay a cost of C_i to get the i-th gem.

Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.

Find the maximum possible value of X-Y.

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq C_i, V_i \leq 50

Input

Input is given from Standard Input in the following format:

N
V_1 V_2 ... V_N
C_1 C_2 ... C_N

Output

Print the maximum possible value of X-Y.

Sample Input 1

3
10 2 5
6 3 4

Sample Output 1

5

If we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.
We have X-Y = 5 here, which is the maximum possible value.

Sample Input 2

4
13 21 6 19
11 30 6 15

Sample Output 2

6

Sample Input 3

1
1
50

Sample Output 3

0

Solution in Scala (2.11.7) (judge verdict: Accepted)

import scala.math._

object Main extends App {

  val YES = "YES"
  val Yes = "Yes"
  val NO = "NO"
  val No = "No"
  ///////////////////////////////////////////

  val sc = new java.util.Scanner(System.in)
  val n = sc.nextInt
  val v = List.fill(n)(sc.nextLong)
  val c = List.fill(n)(sc.nextLong)

  val ans = (v zip c).map(p => max(p._1 - p._2, 0L)).sum

  println(ans)

  ///////////////////////////////////////////

  def bigIterator(start: BigInt, end: BigInt, step: BigInt = 1) =
    Iterator.iterate(start)(_ + step).takeWhile(_ <= end)

  def lcm(a :Int, b :Int): Int =
    a / gcd(a, b) * b

  def lcm(a :Long, b :Long): Long =
    a / gcd(a, b) * b

  def gcd(a: Int, b: Int): Int =
    if (b == 0) a else gcd(b, a % b)

  def gcd(a: Long, b: Long): Long =
    if (b == 0) a else gcd(b, a % b)

  def setOrUpdated[A, B](a: Map[A, B], key: A, value: B, f: (B, B) => B) =
    a.get(key) match {
      case Some(v) => a.updated(key, f(value, v))
      case _ => a + (key -> value)
    }
}