Problem:
Disjoint Set

Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.

same(x, y): determine whether x and y are in the same set.

Input

n q
com1 x1 y1
com2 x2 y2
...
comq xq yq

In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Constraints

1 ≤ n ≤ 10000

1 ≤ q ≤ 100000

x ≠ y

Sample Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0

Sample Output

0
0
1
1
1
0
1
1

Solution in Scala (judge verdict: Accepted)

object Main {

  class UnionFindRank(val n: Int) {
    private[this] val par = Array.range(0, n)
    private[this] val rank = Array.fill(n)(1)

    def root(x: Int): Int =
      if(par(x)==x) x
      else {par(x) = root(par(x)); par(x)}

    def same(x: Int, y: Int): Boolean = root(x)==root(y)

    def unite(ax: Int, ay: Int): Unit = {
      val x = root(ax)
      val y = root(ay)
      if(x!=y){
        if(rank(x) < rank(y)) par(x) = y
        else {
          par(y) = x
          if(rank(x) == rank(y))rank(x) = rank(x)+1;
        }
      }
    }
  }

  def main(args: Array[String]): Unit = {

    val Array(n,q,_*) = scala.io.StdIn.readLine.split(" ").map(_.toInt)
    val uf = new UnionFindRank(n)

    for(i <- 1 to q){
      val Array(com,x,y,_*) = scala.io.StdIn.readLine.split(" ").map(_.toInt)
      if(com==0)uf.unite(x,y)
      else println(if(uf.same(x,y)) 1 else 0)
    }

  }

}