Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in Scala (judge verdict: Accepted)

object Main {
  def main(args: Array[String]): Unit = {
    val scanner = new java.util.Scanner(System.in)

    val n, m, l = scanner.nextInt
    val a = Array.fill(n)(new Array[Long](m))
    val b = Array.fill(l)(new Array[Long](m))

    for(i <- 0 until n) {
      for(j <- 0 until m) {
        a(i)(j) = scanner.nextInt
      }
    }
    for(i <- 0 until m) {
      for(j <- 0 until l) {
        b(j)(i) = scanner.nextLong
      }
    }

    for(i <- 0 until n) {
      for(j <- 0 until l) {
        print((a(i) zip b(j)).map(t => t._1 * t._2).sum)
        if(j < l - 1) print(" ") else println()
      }
    }
  }
}