Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in Scala (judge verdict: Accepted)

object Main extends App {
  val sc = new java.util.Scanner(System.in)
  val n, m, l = sc.nextInt()
  val A = new Matrix(n, m, List.fill(n, m)(sc.nextInt()))
  val B = new Matrix(m, l, List.fill(m, l)(sc.nextInt()))
  A.printDotProduct(B)

  class Matrix(rs: Int, cs: Int, d: List[List[Int]]) {
    val rowSize = rs
    val colSize = cs
    val data = d
    val colList: List[List[Int]] = (for (i <- 0 to colSize - 1) yield data.map(e => e(i))).toList

    def printDotProduct(o: Matrix): Unit = {
      for (i <- 0 to rowSize - 1) {
        var result = List.empty[Long]
        for (j <- 0 to o.colList.size - 1) {
          result = calcElement(data(i), o.colList(j)) :: result
        }
        println(result.reverse.mkString(" "))
      }

      def calcElement(ownRow: List[Int], objCol: List[Int]): Long = ownRow.zip(objCol).map(e => e._1.toLong * e._2.toLong).sum
    }
  }
}