Problem:
Reversing Numbers

Write a program which reads a sequence and prints it in the reverse order.

Input

The input is given in the following format:

n
a1 a2 . . . an

n is the size of the sequence and ai is the ith element of the sequence.

Output

Print the reversed sequence in a line. Print a single space character between adjacent elements (Note that your program should not put a space character after the last element).

Constraints

n ≤ 100

0 ≤ ai < 1000

Sample Input 1

5
1 2 3 4 5

Sample Output 1

5 4 3 2 1

Sample Input 2

8
3 3 4 4 5 8 7 9

Sample Output 2

9 7 8 5 4 4 3 3

Note

      解説

Solution in Scala (judge verdict: Accepted)

object Main {
  def main(args: Array[String]): Unit = {
    val in = new java.util.Scanner(System.in)
    val n = in.nextInt
    val list:List[Int] = makeList(in,n)
    val re = list.reverse
    printList(re)
    
  }
  def makeList(in:java.util.Scanner,rest:Int):List[Int] = {
    if(rest == 0) return List.empty 
    val a = in.nextInt
     return a :: makeList(in,rest -1)
  }
  def printList(list:List[Int]):Unit = {
    list match{
      case List(n) =>{ println(n); return}
      case n :: ls => {print(n+" ");printList(ls)}
    }
  }
}