Problem:
Score : 700 points

Problem Statement

You are given an integer N. Determine if there exists a tree with 2N vertices numbered 1 to 2N satisfying the following condition, and show one such tree if the answer is yes.

Assume that, for each integer i between 1 and N (inclusive), Vertex i and N+i have the weight i. Then, for each integer i between 1 and N, the bitwise XOR of the weights of the vertices on the path between Vertex i and N+i (including themselves) is i.

Constraints

N is an integer.

1 \leq N \leq 10^{5}

Input

Input is given from Standard Input in the following format:

N

Output

If there exists a tree satisfying the condition in the statement, print Yes; otherwise, print No.
Then, if such a tree exists, print the 2N-1 edges of such a tree in the subsequent 2N-1 lines, in the following format:

a_{1} b_{1}
\vdots
a_{2N-1} b_{2N-1}

Here each pair (a_i, b_i) means that there is an edge connecting Vertex a_i and b_i. The edges may be printed in any order.

Sample Input 1

3

Sample Output 1

Yes
1 2
2 3
3 4
4 5
5 6

The sample output represents the following graph:

Sample Input 2

1

Sample Output 2

No

There is no tree satisfying the condition.

Solution in Scala (2.11.7) (judge verdict: Wrong Answer)

import java.io._
import java.util.StringTokenizer
import scala.util.control.Breaks.{breakable,break}
import scala.collection.mutable.Map
import scala.collection.mutable.Queue

object Main extends App {
  val in = new InputReader(System.in)
  val pw = new PrintWriter(System.out)

  val N = in.next().toInt

  var ans = List((1, 2), (2, 3), (N+3, 1), (N+2, N+3), (N+1, N+2))
  if (N <= 2)
    println("No")
  else {
    for (i <- 4 to N by 2) {
      ans = (i, 1) :: (i+1, i) :: (N+i+1, 1) :: (N+i, N+i+1) :: ans
    }

    var flag = false
    if (N % 2 == 0) {
      breakable {
        for (i <- 2 to N-1 if (i ^ (N+1)) < N) {
          ans = (i, N) :: (i ^ (N+1), N+N) :: ans
          flag = true
          break
        }
      }
    }
    else
      flag = true

    if(flag) {
      pw.println("Yes")
      ans.foreach { case (a, b) => pw.println(s"$a $b") }
    }
    else
      pw.println("No")

    pw.flush()
  }

}


class InputReader(stream: InputStream) {
  private val reader = new BufferedReader(new InputStreamReader(stream))
  private var tokenizer: StringTokenizer = new StringTokenizer(reader.readLine())
  def next(): String = {
    while (!tokenizer.hasMoreTokens()) {
      tokenizer = new StringTokenizer(reader.readLine())
    }
    tokenizer.nextToken()
  }
}