Problem:
Score : 200 points

Problem Statement

You are given a string s consisting of lowercase English letters. Extract all the characters in the odd-indexed positions and print the string obtained by concatenating them. Here, the leftmost character is assigned the index 1.

Constraints

Each character in s is a lowercase English letter.

1≤|s|≤10^5

Input

The input is given from Standard Input in the following format:

s

Output

Print the string obtained by concatenating all the characters in the odd-numbered positions.

Sample Input 1

atcoder

Sample Output 1

acdr

Extract the first character a, the third character c, the fifth character d and the seventh character r to obtain acdr.

Sample Input 2

aaaa

Sample Output 2

aa

Sample Input 3

z

Sample Output 3

z

Sample Input 4

fukuokayamaguchi

Sample Output 4

fkoaaauh

Solution in Scala (2.11.7) (judge verdict: Accepted)

import java.util.Scanner

object Main {
  def main(args: Array[String]) {
    if (args.length > 0 && args(0) == "TEST") {
      println(test())
    } else {
      val input = io.Source.stdin.getLines().mkString("\n")
      println(solve(input).trim())
    }
  }

  def solve(input: String): String = {
    val sc: Scanner = new Scanner(input)
    val s = sc.next.toCharArray.zipWithIndex.filter {case (_, idx) => idx % 2 == 0}.map(_._1)
    new String(s)
  }

  val tests = List(
    """atcoder""".stripMargin -> """acdr""",
    """aaaa""".stripMargin -> """aa""",
    """z""" -> "z",
    "fukuokayamaguchi" -> "fkoaaauh"
  )

  def test(): String = tests.map { case (i, o) => (i.trim(), o.trim()) }
    .zipWithIndex.map {
    case ((input, outputExpect), i) =>
      val output = solve(input).trim()
      val tnum = i + 1
      s"test$tnum:" + (
        if (output == outputExpect) "Passed"
        else s"Failed\nexpect:\n$outputExpect\noutput:\n$output")
  }
    .mkString("\n")
}