Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in Scala (judge verdict: Accepted)

import scala.collection.mutable.ArrayBuffer

object Main extends App {
  val Array(n,m,l) = readLine.split(" ").map(_.toInt)
  val buf1 = ArrayBuffer.empty[Array[Long]]
  val buf2 = ArrayBuffer.empty[Array[Long]]

  for( i <- 0 until n) buf1 += readLine.split(" ").map(_.toLong)
  for( i <- 0 until m) buf2 += readLine.split(" ").map(_.toLong)

  val m1 = buf1.toArray
  val m2 = buf2.toArray

  val m3 = for(i <- 0 until n) yield for(j<- 0 until l)
    yield (0 until m).foldLeft(0L) { (sum,k) => sum + m1(i)(k) * m2(k)(j) }

  m3.foreach(row => println(row.mkString(" ")))
}