Problem:
Reversing Numbers

Write a program which reads a sequence and prints it in the reverse order.

Input

The input is given in the following format:

n
a1 a2 . . . an

n is the size of the sequence and ai is the ith element of the sequence.

Output

Print the reversed sequence in a line. Print a single space character between adjacent elements (Note that your program should not put a space character after the last element).

Constraints

n ≤ 100

0 ≤ ai < 1000

Sample Input 1

5
1 2 3 4 5

Sample Output 1

5 4 3 2 1

Sample Input 2

8
3 3 4 4 5 8 7 9

Sample Output 2

9 7 8 5 4 4 3 3

Note

      解説

Solution in Scala (judge verdict: WA: Presentation Error)

object RevirsingNumbers {
    def inputNumbers: List[Long] = {
      val sc = new java.util.Scanner(System.in)
      val n = sc.nextInt()
      List.fill(n)(sc.nextLong())
    }
    def reversingPrint(list: List[Long] ): Unit = {
      val n = list.size
      val r = list.reverse.toArray
      for (i <- 0 until (n-1) )print(r(i))
      print(r(n - 1))
    }
    def run: Unit = reversingPrint(inputNumbers)
}
object Main {
  def main(args: Array[String]) {
    RevirsingNumbers.run
    }
}