Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in Scala (judge verdict: Accepted)

import scala.collection.mutable
import scala.io.Source.stdin

/**
  * AOJ
  */
object Main {

  val alphabet = "abcdefghijklmnopqrstuvwxyz"

  def main(args: Array[String]): Unit = {

    val alphabetMap = mutable.Map.empty[Char, Int]
    setValues(alphabetMap)
    for(c <- alphabet){
      println(c + " : " + alphabetMap(c).toString)
    }
  }

  def setValues(alphabetMap:mutable.Map[Char,Int]):Unit = {
    for (c <- alphabet) {
      alphabetMap += c -> 0
    }
    for (line <- stdin.getLines()){
      if (line.length == 0) {
        return
      }
      for(c <- line.toLowerCase) {
        if (alphabetMap.contains(c)) {
          alphabetMap(c) += 1
        }
      }
    }
  }
}