Problem:
Reversing Numbers

Write a program which reads a sequence and prints it in the reverse order.

Input

The input is given in the following format:

n
a1 a2 . . . an

n is the size of the sequence and ai is the ith element of the sequence.

Output

Print the reversed sequence in a line. Print a single space character between adjacent elements (Note that your program should not put a space character after the last element).

Constraints

n ≤ 100

0 ≤ ai < 1000

Sample Input 1

5
1 2 3 4 5

Sample Output 1

5 4 3 2 1

Sample Input 2

8
3 3 4 4 5 8 7 9

Sample Output 2

9 7 8 5 4 4 3 3

Note

      解説

Solution in Scala (judge verdict: Accepted)

import java.util.Scanner

import scala.annotation.tailrec

/**
  * Created by ui on 2016/02/07.
  */
object ReverseNumber {
  def run: Unit = {
    val sc = new Scanner(System.in)
    val n = sc.nextInt()
    var l = List.fill(n)(sc.nextInt)
    l = l.reverse
    fact(l)

  }
  @tailrec
  def fact (l:List[Int]): Unit = {
    if (l.size == 1) println(l.head)
    else {print(s"${l.head} ")
      fact (l.tail)
    }

  }
}

/**
  * Created by ui on 2016/02/04.
  */
object Main {
  def main(args: Array[String]): Unit = {
    ReverseNumber.run
  }
}