Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in Scala (2.11.7) (judge verdict: Wrong Answer)

object Main{
  def check(num: Int = 0, limit: Int, list: List[Long], newList: List[Long] = List()): List[Long] = {
    if(num == limit) newList
    else {
      println(newList)
      check(num + 1, limit, list.tail :+ list.head, (newList :+ list.head).reverse)
    }
  }

  def main(args:Array[String]) = {
    val a = scala.io.StdIn.readLine;
    val list = scala.io.StdIn.readLine.split(" ").map(_.toLong).toList;
    val evenList = (0 until list.size).filter(n => n % 2 == 0).map(n => list(n))
    val oddList = (0 until list.size).filter(n => n % 2 == 1).map(n => list(n))
    println((oddList.reverse ++ evenList).mkString(" "))
  }
}