Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in Scala (2.11.7) (judge verdict: Accepted)

object Main extends App {
  import scala.io.StdIn._

  val target = readLine.trim
  println(
    find(target).let{case (a, b) ⇒ s"$a $b"}
  )
  def find(target: String): (Int, Int) = {
    target.indices.tail.find(i ⇒ target(i) == target(i - 1)).map(i ⇒ (i, i + 1)).getOrElse(target.indices.drop(2).find(i ⇒ target(i) == target(i - 2)).map(i ⇒ (i - 1, i + 1)).getOrElse(-1, -1))
  }
  implicit class Scope[T](val value: T) extends AnyVal {
    @inline
    def let[A](func: T ⇒ A): A = func(value)
    @inline
    def also(func: T ⇒ Unit): T = {
      func(value)
      value
    }
  }
}