Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Scala (2.11.7) (judge verdict: Wrong Answer)

object Main extends App {
  val in            = new java.util.Scanner(System.in)
  val n, a, b, c, d = in.nextInt
  val s             = in.next

  // 岩が 2 マス続いている時は飛び越えることはできない
  // スタート地点より前とゴール地点より後の岩は考慮しない

  // すぬけ a -> c
  // ふぬけ b -> d
  // 人物を追い越す必要がある場合は人物を追い越すために 3 マス必要
  // スタート地点より前とふぬけがゴールした後の空白は考慮しない
  // (ふぬけのゴール後に空白があっても戻ることができないため)

  println(if (s.substring(a - 1, if (c > d) c else d).contains("##")) {
    "No"
  } else {
    if (c > d) {
      if (s.substring(b - 1, d + 1).contains("...")) {
        "Yes"
      } else {
        "No"
      }
    } else {
      "Yes"
    }
  })
}