Problem:
Reversing Numbers

Write a program which reads a sequence and prints it in the reverse order.

Input

The input is given in the following format:

n
a1 a2 . . . an

n is the size of the sequence and ai is the ith element of the sequence.

Output

Print the reversed sequence in a line. Print a single space character between adjacent elements (Note that your program should not put a space character after the last element).

Constraints

n ≤ 100

0 ≤ ai < 1000

Sample Input 1

5
1 2 3 4 5

Sample Output 1

5 4 3 2 1

Sample Input 2

8
3 3 4 4 5 8 7 9

Sample Output 2

9 7 8 5 4 4 3 3

Note

      解説

Solution in Scala (judge verdict: Accepted)

import scala.annotation.tailrec
import scala.io.StdIn

object Main extends App {

  val n = StdIn.readLine().toInt
  val buff = StdIn.readLine().split(' ').map(_.toInt)
  val out = Array.fill(n)(0)
  @tailrec def printReverse(index: Int): Unit = {
    if(index >= 0) {
      out(n - (index + 1)) = buff(index)
      printReverse(index - 1)
    }
  }
  
  printReverse(n-1)
  println(out.mkString(" "))
  
}