Problem:
Score : 200 points

Problem Statement

An X-layered kagami mochi (X ≥ 1) is a pile of X round mochi (rice cake) stacked vertically where each mochi (except the bottom one) has a smaller diameter than that of the mochi directly below it. For example, if you stack three mochi with diameters of 10, 8 and 6 centimeters from bottom to top in this order, you have a 3-layered kagami mochi; if you put just one mochi, you have a 1-layered kagami mochi.

Lunlun the dachshund has N round mochi, and the diameter of the i-th mochi is d_i centimeters. When we make a kagami mochi using some or all of them, at most how many layers can our kagami mochi have?

Constraints

1 ≤ N ≤ 100

1 ≤ d_i ≤ 100

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
d_1
:
d_N

Output

Print the maximum number of layers in a kagami mochi that can be made.

Sample Input 1

4
10
8
8
6

Sample Output 1

3

If we stack the mochi with diameters of 10, 8 and 6 centimeters from bottom to top in this order, we have a 3-layered kagami mochi, which is the maximum number of layers.

Sample Input 2

3
15
15
15

Sample Output 2

1

When all the mochi have the same diameter, we can only have a 1-layered kagami mochi.

Sample Input 3

7
50
30
50
100
50
80
30

Sample Output 3

4

Solution in Scala (2.11.7) (judge verdict: Accepted)

object Main {
  def main(args: Array[String]) {
    val input = io.Source.stdin.getLines().mkString("\n")
    println(kagamiMochi(input).trim())
  }

  //  def solve(input: String): String = {
  //    Stream.iterate(input.split("^n")(1).split(" ").map(_.toInt))(_.map(_/2)).takeWhile(_.forall(_%2 ==0)).size.toString
  //  }

  def kagamiMochi(input: String) :String = {
    //先頭の要素を除外する
    //新しいコレクションを作る
    //index != 0という条件を加える

    //distinctしてsizeをとるだけでよい
    //ソート不要

    input.split("\n").tail.distinct.size.toString
  }
}