Problem:
Score : 400 points

Problem Statement

Let {\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order.
From n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\rm comb}(a_i,a_j) is maximized.
If there are multiple pairs that maximize the value, any of them is accepted.

Constraints

2 \leq n \leq 10^5

0 \leq a_i \leq 10^9

a_1,a_2,...,a_n are pairwise distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print a_i and a_j that you selected, with a space in between.

Sample Input 1

5
6 9 4 2 11

Sample Output 1

11 6

\rm{comb}(a_i,a_j) for each possible selection is as follows:

\rm{comb}(4,2)=6

\rm{comb}(6,2)=15

\rm{comb}(6,4)=15

\rm{comb}(9,2)=36

\rm{comb}(9,4)=126

\rm{comb}(9,6)=84

\rm{comb}(11,2)=55

\rm{comb}(11,4)=330

\rm{comb}(11,6)=462

\rm{comb}(11,9)=55

Thus, we should print 11 and 6.

Sample Input 2

2
100 0

Sample Output 2

100 0

Solution in Scala (2.11.7) (judge verdict: Wrong Answer)


object Main {

  def main(args: Array[String]): Unit = {
    val sc = new java.util.Scanner(System.in)

    val N = sc.nextInt()
    val A = Array.fill(N)(sc.nextInt()).sorted

    // comb(ai, aj), これは ai を固定した時には,
    // 単峰関数のような関数 f_ai(x) = comb(ai, x)
    // となる。すると, 最大の値の候補は
    // ai の真ん中もしくは, 真ん中に近い2つの値が候補になる
    // これは, 二分探索で探せるのでいける
    // これを全てのaiについて調べても間に合う
    // 実際に combを計算する必要はない
    def solve(N: Int, A: Array[Int]): (Int, Int) = {
      def upperBounds(n: Int, upper: Int): Int = {
        @scala.annotation.tailrec
        def loop(left: Int, right: Int): Int =
          if (right - left > 1) {
            val mid = left + (right - left) / 2
            if (A(mid) >= n) loop(left, mid)
            else loop(mid, right)
          } else right
        loop(-1, upper)
      }
      def lowerBounds(n: Int, upper: Int): Int = {
        @scala.annotation.tailrec
        def loop(left: Int, right: Int): Int =
          if (right - left > 1) {
            val mid = left + (right - left) / 2
            if (A(mid) <= n) loop(mid, right)
            else loop(left, mid)
          } else left
        loop(-1, upper)
      }
      @scala.annotation.tailrec
      def loop(i: Int, diff: Int, n: Int, r: Int): (Int, Int) =
        if (i < N) {
          val center = (A(i) / 2.toDouble).round.toInt
          val li = lowerBounds(center, i)
          val ri = upperBounds(center, i)
          val left = if (li >= 0) A(li) else 0
          val right = if (ri < A(i)) A(ri) else 0
          if (left > A(i) - right) {
            if (left >= diff) loop(i + 1, left, A(i), left)
            else loop(i + 1, diff, n, r)
          } else {
            if (A(i) - right >= diff) loop(i + 1, A(i) - right, A(i), right)
            else loop(i + 1, diff, n, r)
          }
        } else (n, r)

      loop(1, 0, 0, 0)
    }

    val (n, r) = solve(N, A)
    println(s"$n $r")
  }

}