Problem:
Score : 400 points

Problem Statement

Snuke has one biscuit and zero Japanese yen (the currency) in his pocket.
He will perform the following operations exactly K times in total, in the order he likes:

Hit his pocket, which magically increases the number of biscuits by one.

Exchange A biscuits to 1 yen.

Exchange 1 yen to B biscuits.

Find the maximum possible number of biscuits in Snuke's pocket after K operations.

Constraints

1 \leq K,A,B \leq 10^9

K,A and B are integers.

Input

Input is given from Standard Input in the following format:

K A B

Output

Print the maximum possible number of biscuits in Snuke's pocket after K operations.

Sample Input 1

4 2 6

Sample Output 1

7

The number of biscuits in Snuke's pocket after K operations is maximized as follows:

Hit his pocket. Now he has 2 biscuits and 0 yen.

Exchange 2 biscuits to 1 yen. his pocket. Now he has 0 biscuits and 1 yen.

Hit his pocket. Now he has 1 biscuits and 1 yen.

Exchange 1 yen to 6 biscuits. his pocket. Now he has 7 biscuits and 0 yen.

Sample Input 2

7 3 4

Sample Output 2

8

Sample Input 3

314159265 35897932 384626433

Sample Output 3

48518828981938099

Solution in Scala (2.11.7) (judge verdict: Accepted)

object Main extends App {
  import scala.io.StdIn._


  val Array(k, a, b) = readLine.trim.split(' ').map(_.toLong)
  println(solve(k, a, b))
  def solve(k: Long, a: Long, b: Long): Long = {
    if (k < a) {
      k + 1
    }else {
      val restK = k - a + 1
      if (a + 2 < b) {
        a + restK / 2 * (b - a) + restK % 2
      }else {
        k + 1
      }
    }
  }
  implicit class Scope[T](val value: T) extends AnyVal {
    @inline def also(@inline func: T ⇒ Unit): T = {
      func(value)
      value
    }
    @inline def let[A](@inline func: T ⇒ A): A = func(value)
  }
}