Problem:
Selection Sort

Write a program of the Selection Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:

SelectionSort(A)
1 for i = 0 to A.length-1
2 mini = i
3 for j = i to A.length-1
4 if A[j] < A[mini]
5 mini = j
6 swap A[i] and A[mini]

Note that, indices for array elements are based on 0-origin.

Your program should also print the number of swap operations defined in line 6 of the pseudocode in the case where i ≠ mini.

Input

The first line of the input includes an integer N, the number of elements in the sequence.

In the second line, N elements of the sequence are given separated by space characters.

Output

The output consists of 2 lines.

In the first line, please print the sorted sequence. Two contiguous elements of the sequence should be separated by a space character.

In the second line, please print the number of swap operations.

Constraints

1 ≤ N ≤ 100

Sample Input 1

6
5 6 4 2 1 3

Sample Output 1

1 2 3 4 5 6
4

Sample Input 2

6
5 2 4 6 1 3

Sample Output 2

1 2 3 4 5 6
3

Solution in Scala (judge verdict: Accepted)

import scala.io.StdIn
import scala.annotation.tailrec
import scala.collection.mutable.ListBuffer

object Main{
  def main(args: Array[String]){
    StdIn.readLine()
    val line = StdIn.readLine().split(" ").toList.map(_.toInt)

    println(line.sorted.mkString(" "))
    println(sSort(List(), line, 0))
  }

  @tailrec
  def sSort(sorted: List[Int], unsorted: List[Int], n: Int): Int={
    if(unsorted.length == 0) n
    else if(unsorted.sorted == unsorted) n
    else {
      if(unsorted.indexWhere(_ == unsorted.min) == 0) sSort(sorted :+ unsorted.min, unsorted.updated(0, unsorted(unsorted.indexWhere(_ == unsorted.min))).updated(unsorted.indexWhere(_ == unsorted.min), unsorted.head).tail, n)
      else sSort(sorted :+ unsorted.min, unsorted.updated(0, unsorted(unsorted.indexWhere(_ == unsorted.min))).updated(unsorted.indexWhere(_ == unsorted.min), unsorted.head).tail, n+1)
    }
  }
}