Problem:
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Connected Components

Write a program which reads relations in a SNS (Social Network Service), and judges that given pairs of users are reachable each other through the network.

Input

In the first line, two integer $n$ and $m$ are given. $n$ is the number of users in the SNS and $m$ is the number of relations in the SNS. The users in the SNS are identified by IDs $0, 1, ..., n-1$.

In the following $m$ lines, the relations are given. Each relation is given by two integers $s$ and $t$ that represents $s$ and $t$ are friends (and reachable each other).

In the next line, the number of queries $q$ is given. In the following $q$ lines, $q$ queries are given respectively. Each query consists of two integers $s$ and $t$ separated by a space character.

Output

For each query, print "yes" if $t$ is reachable from $s$ through the social network, "no" otherwise.

Constraints

$2 \leq n \leq 100,000$

$0 \leq m \leq 100,000$

$1 \leq q \leq 10,000$

Sample Input

10 9
0 1
0 2
3 4
5 7
5 6
6 7
6 8
7 8
8 9
3
0 1
5 9
1 3

Sample Output

yes
yes
no

Solution in Scala (judge verdict: Wrong Answer)

import scala.io.StdIn.{readInt,readLine}
import scala.collection.mutable.ArrayBuffer

object Main {
  def main(args:Array[String]) = {
    val n = readLine.split(" ").map(_.toInt)
    val d = new Array[Int](n(0))
    val g = new Array[ArrayBuffer[Int]](n(0))

    for(i<-0 until n(0)) g(i) = new ArrayBuffer[Int]
    for(i<-0 until n(1)) {
      val v = readLine.split(" ").map(_.toInt)
      g(v(0)) += v(1)
    }

    def scan(i:Int, connected:Int):Unit = {
      if(d(i)==0) d(i) = connected

      if(g(i).length > 0) {
        for(j<-0 until g(i).length) {
          if(d(g(i)(j))==0) {
            scan(g(i)(j), connected)
          }
        }
      }
    }

    var connected = 1
    for(i<-0 until n(0)) {
      if(d(i)==0) {
        scan(i, connected)
        connected += 1
      }
    }

    val q = readInt
    for(i<-0 until q) {
      val s = readLine.split(" ").map(_.toInt)
      if(d(s(0)) == d(s(1))) println("yes")
      else println("no")
    }
  }
}