Problem:
Bubble Sort

Write a program of the Bubble Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:

BubbleSort(A)
1 for i = 0 to A.length-1
2 for j = A.length-1 downto i+1
3 if A[j] < A[j-1]
4 swap A[j] and A[j-1]

Note that, indices for array elements are based on 0-origin.

Your program should also print the number of swap operations defined in line 4 of the pseudocode.

Input

The first line of the input includes an integer N, the number of elements in the sequence.

In the second line, N elements of the sequence are given separated by spaces characters.

Output

The output consists of 2 lines.

In the first line, please print the sorted sequence. Two contiguous elements of the sequence should be separated by a space character.

In the second line, please print the number of swap operations.

Constraints

1 ≤ N ≤ 100

Sample Input 1

5
5 3 2 4 1

Sample Output 1

1 2 3 4 5
8

Sample Input 2

6
5 2 4 6 1 3

Sample Output 2

1 2 3 4 5 6
9

Solution in Scala (judge verdict: Accepted)

object Main extends App {
  import java.{ util => ju }
  import scala.annotation._
  import scala.collection._
  import scala.collection.{ mutable => mu }
  import scala.collection.JavaConverters._
  import scala.math._
  import scala.io.StdIn.readLine

  val sc = new ju.Scanner(System.in)

  val n = sc.nextInt()
  var nums = Array.fill(n)(sc.nextInt())

  var swapCount = 0
  for (i <- 0 until n) {
    for (j <- n - 1 until i by -1) {
      if (nums(j) < nums(j - 1)) {
        val bigger = nums(j)
        nums(j) = nums(j - 1)
        nums(j - 1) = bigger
        swapCount += 1
      }
    }
  }

  printArray(nums)
  println(swapCount)

  def printArray(nums: Array[Int]) {
    for (i <- 0 until nums.length - 1) print(nums(i) + " ")
    println(nums.last)
  }
}