Problem:
A: 情報検索 / Information Search

問題

ポスティングリストとは、検索語と出現文書 ID の対応関係を持たせたリストである。例えば

北海道: 1, 2, 4, 9

観光: 1, 3, 4, 7

などである。

上記のポスティングリストから、and 検索をすると、ID 1, 4 の文書がヒットし、or 検索をすると、ID 1, 2, 3, 4, 7, 9 がヒットする。

ここで and 検索とは「どちらのリストにも含まれる要素を列挙する」ことであり、 or 検索とは「少なくともどちらか一方のリストに含まれる要素を列挙する」ことである。

ポスティングリストが与えられるので、and 検索と or 検索の結果をそれぞれ出力せよ。

入力形式

n m
a_1 a_2 $\ldots$ a_n
b_1 b_2 $\ldots$ b_m

入力はすべて整数からなる。

1 行目には検索すべき 2 つのポスティングリストの長さ n と m が空白区切りで与えられる。

2 行目と 3 行目にはそれぞれのポスティングリストに含まれる ID が空白区切りで与えられる。

制約

1 \leq n, m \leq 2\times10^5

a_i < a_j (i < j)

b_i < b_j (i < j)

1 \leq a_i, b_i \leq 10^9

出力形式

and 検索のヒット数を A、or 検索のヒット数を B とする。

最初の一行に A B の順に空白区切りで出力せよ。

続く A 行に and 検索でヒットした ID を昇順に出力せよ。

続く B 行に or 検索でヒットした ID を昇順に出力せよ。

入力例1

4 4
1 2 4 9
1 3 4 7

出力例1

2 6
1
4
1
2
3
4
7
9

入力例2

4 4
1 3 5 7
2 4 6 8

出力例2

0 8
1
2
3
4
5
6
7
8

入力例3

3 5
1 2 3
1 2 3 4 5

出力例3

3 5
1
2
3
1
2
3
4
5

Solution in Scala (judge verdict: Accepted)

//import java.util.Scanner

import java.io._
import java.nio.file.Files._
import java.nio.file.Path
import java.util.StringTokenizer

import scala.collection.immutable._
import scala.io.Codec

/**
  * Scala implementation of a faster java.util.Scanner
  * See: http://codeforces.com/blog/entry/7018
  */

class Scanner(reader: LineNumberReader) extends Iterable[String] with AutoCloseable {
  def this(reader: BufferedReader) = this(new LineNumberReader(reader))

  def this(reader: Reader) = this(new BufferedReader(reader))

  def this(inputStream: InputStream)(implicit codec: Codec) = this(new InputStreamReader(inputStream, codec.charSet))

  def this(path: Path)(implicit codec: Codec) = this(newBufferedReader(path, codec.charSet))

  def this(file: File)(implicit codec: Codec) = this(file.toPath)(codec)

  def this(str: String) = this(new StringReader(str))

  override def iterator: Iterator[String] = for {
    line <- Iterator.continually(reader.readLine()).takeWhile(_ != null)
    tokenizer = new StringTokenizer(line)
    tokens <- Iterator.continually(tokenizer).takeWhile(_.hasMoreTokens)
  } yield tokens.nextToken()

  private[this] var current = iterator

  def hasNext: Boolean = current.hasNext

  @inline def next(): String = current.next()

  /**
    * This is different from Java's scanner.nextLine
    * The Java one is a misnomer since it actually travel to end of current line
    * This one actually does fetch the next line
    */
  def nextLine(): String = {
    val line = reader.readLine()
    current = iterator
    line
  }

  def lineNumber: Int = reader.getLineNumber

  def nextString(): String = next()

  def nextBoolean(): Boolean = next().toBoolean

  def nextByte(radix: Int = 10): Byte = java.lang.Byte.parseByte(next(), radix)

  def nextShort(radix: Int = 10): Short = java.lang.Short.parseShort(next(), radix)

  def nextInt(radix: Int = 10): Int = java.lang.Integer.parseInt(next(), radix)

  def nextLong(radix: Int = 10): Long = java.lang.Long.parseLong(next(), radix)

  def nextBigInt(radix: Int = 10): BigInt = BigInt(next(), radix)

  def nextFloat(): Float = next().toFloat

  def nextDouble(): Double = next().toDouble

  def nextBigDecimal(): BigDecimal = BigDecimal(next())

  override def close(): Unit = reader.close()
}


class IUnionFind(val size: Int) {

  private case class Node(var parent: Option[Int], var treeSize: Int)

  private val nodes = Array.fill[Node](size)(Node(None, treeSize = 1))

  def union(t1: Int, t2: Int): IUnionFind = {
    if (t1 == t2) return this

    val root1 = root(t1)
    val root2 = root(t2)
    if (root1 == root2) return this

    val node1 = nodes(root1)
    val node2 = nodes(root2)

    if (node1.treeSize < node2.treeSize) {
      node1.parent = Some(t2)
      node2.treeSize += node1.treeSize
    } else {
      node2.parent = Some(t1)
      node1.treeSize += node2.treeSize
    }
    this
  }

  def connected(t1: Int, t2: Int): Boolean = t1 == t2 || root(t1) == root(t2)

  def root(t: Int): Int = nodes(t).parent match {
    case None => t
    case Some(p) =>
      nodes(t).parent = Some(root(p))
      nodes(t).parent.get
  }
}


object Main {
  def solve(sc: => Scanner): Unit = {
    val N, M = sc.nextInt()
    val A = Array.fill(N)(sc.nextLong()).toSet
    val B = Array.fill(M)(sc.nextLong()).toSet
    val C = A & B
    val D = A | B

    println(C.size.toString ++ " " ++ D.size.toString)
    print(C.toArray.sorted.map(i => i.toString ++ "\n").mkString(""))
    print(D.toArray.sorted.map(i => i.toString ++ "\n").mkString(""))
  }

  def getPermutation(begin: Long = 0): Stream[Long] =
    Stream.cons(begin, getPermutation(begin + 1))

  def calc(N: Long, R: Long, M: Long): Double = {
    math.sqrt(R * R - (R * 2 * ((M * 1.0 / N) - 0.5)) * (R * 2 * ((M * 1.0 / N) - 0.5))) * 2
  }

  def recursive(now: Long, count: Long): Long = {
    if (count == 1000) now else {
      if (now % 2 == 1) recursive(now * 3 + 1, count + 1) else recursive(now / 2, count + 1)
    }
  }

  def recursive2(X: Set[Long], Y: Stream[Long]): Long = if (X.contains(Y.head)) X.size else recursive2(X + Y.head, Y.tail)

  def check(s: String): Boolean = {
    if (s == "0") true
    else s(0) != '0' && 0 <= s.toInt && s.toInt <= 255
  }

  def shift(n: Long): Long = {
    if (n == 0) 0
    else if (n == 1) 1
    else shift(n - 1) << 1
  }

  def unShift(n: Long): Long = {
    if (n == 0) 0
    else unShift(n >> 1) + 1
  }

  def gcd(i: Long, j: Long): Long = {
    if (i < j) gcd(j, i)
    else if (j == 0) i
    else gcd(j, i % j)
  }

  def primeFactors(i: Long): List[Long] = primeFactors_(i, 1).sorted


  def primeFactors_(i: Long, j: Long): List[Long] = {
    if (j * j > i) List.empty else if (i % j == 0) primeFactors_(i, j + 1) ++ List[Long](j, i / j) else primeFactors_(i, j + 1)
  }

  def main(args: Array[String]): Unit = {
    val sc: Scanner = new Scanner(System.in)
    solve(sc)
  }
}

object Util {
  def getPermutation(begin: Long = 0): Stream[Long] =
    Stream.cons(begin, getPermutation(begin + 1))

  def getPrimeList: Stream[Long] =
    getPrimeListRecursive(getPermutation(begin = 2))

  private def getPrimeListRecursive(A: Stream[Long]): Stream[Long] =
    Stream.cons(A.head, getPrimeListRecursive(A.tail.filter(_ % A.head != 0)))

  def fib(a: Long = 0, b: Long = 1, mod: Long = Long.MaxValue): Stream[Long] = a #:: fib(b % mod, (a + b) % mod, mod)
}

object ArabicRoman {

  type =?>[A, B] = PartialFunction[A, B]

  val codeTable = List(
    (1000, "M"), (900, "CM"), (500, "D"), (400, "CD"), (100, "C"),
    (90, "XC"), (50, "L"), (40, "XL"), (10, "X"), (9, "IX"), (5, "V"), (4, "IV"), (1, "I"))

  val arabicToRoman: Int =?> String = {
    case src if src >= 1 && src <= 3999 =>

      def convert(left: Int, cont: String = "", code: List[(Int, String)] = codeTable): String = {
        val (unitVal, unitChar) = code.head
        left - unitVal match {
          case n if n == 0 => cont + unitChar
          case n if n > 0 => convert(n, cont + unitChar, code)
          case _ => convert(left, cont, code.tail)
        }
      }

      convert(src)
  }

  val romanToArabic: String =?> Int = {
    case src if Option(src).exists { s => {
      s.nonEmpty && """[^MDCLXVI]""".r.findFirstMatchIn(s.toUpperCase).isEmpty
    }
    } =>

      def convert(left: String, cont: Int = 0, code: List[(Int, String)] = codeTable): Int = {
        val (unitVal, unitChar) = code.head
        left.splitAt(unitChar.length) match {
          case ("", _) => cont
          case (`unitChar`, tail) => convert(tail, cont + unitVal, code)
          case _ => convert(left, cont, code.tail)
        }
      }

      convert(src.toUpperCase())
  }
}