Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Scala (2.11.7) (judge verdict: Accepted)

import java.util.Scanner


object Main {


  def read() = {
    val sc = new Scanner(System.in)
    val n, a, b, c, d = sc.nextInt()
    val s = sc.next() + "####"
    (n, a - 1, b - 1, c - 1, d - 1, s)
  }

  def solve(n: Int, a: Int, b: Int, c: Int, d: Int, s: String): Boolean = {
    //テストケースにない怖い
    def exists2Black(begin: Int, end: Int): Boolean = {
      (begin until end - 1).exists(i => s(i) == '#' && s(i + 1) == '#')
    }

    def exists3White(begin: Int, end: Int): Boolean = {
      (begin until end - 2).exists(i => s(i) == '.' && s(i + 1) == '.' && s(i + 2) == '.')
    }

    if (c < d) {
      !exists2Black(a, c + 1) && !exists2Black(b, d + 1)
    } else {
      !exists2Black(a, c + 1) && !exists2Black(b, d + 1) && exists3White(b-1, d + 2)
    }
  }

  def main(args: Array[String]): Unit = {
    val (n, a, b, c, d, s) = read()
    val able = solve(n, a, b, c, d, s)
    val result = if (able) "Yes" else "No"
    println(result)
  }
}