Problem:
Score : 200 points

Problem Statement

There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is R, and a blue hat if s_i is B.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

1 \leq N \leq 100

|s| = N

s_i is R or B.

Input

Input is given from Standard Input in the following format:

N
s

Output

If there are more people wearing a red hat than there are people wearing a blue hat, print Yes; otherwise, print No.

Sample Input 1

4
RRBR

Sample Output 1

Yes

There are three people wearing a red hat, and one person wearing a blue hat.

Since there are more people wearing a red hat than people wearing a blue hat, the answer is Yes.

Sample Input 2

4
BRBR

Sample Output 2

No

There are two people wearing a red hat, and two people wearing a blue hat.

Since there are as many people wearing a red hat as people wearing a blue hat, the answer is No.

Solution in Scala (2.11.7) (judge verdict: Accepted)

object Main {
  import java.util.Scanner

  implicit class RichScanner(sc: Scanner) {
    def readStrings(n: Int): Array[String] = Array.fill(n) { sc.next() }
    def readInts(n: Int): Array[Int] = Array.fill(n) { sc.nextInt() }
    def readLongs(n: Int): Array[Long] = Array.fill(n) { sc.nextLong() }
    def readLineStrings: Array[String] = sc.nextLine().split(' ')
    def readLineInts: Array[Int] = readLineStrings.map(_.toInt)
    def readLineLongs: Array[Long] = readLineStrings.map(_.toLong)
  }

  def main(args: Array[String]): Unit = solve(new Scanner(System.in))

  def solve(sc: Scanner): Unit = {
    val N = sc.readLineInts
    val s = sc.nextLine()
    if (s.count(_ == 'R') > s.count(_ == 'B')) {
      println("Yes")
    } else {
      println("No")
    }
  }
}