Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in Scala (judge verdict: Accepted)

object Main extends App {
	override def main(args : Array[String]){
		val sc = new java.util.Scanner(System.in)
		
		var count = new Array[Int](26)
		io.Source.stdin.getLines().foreach( s =>
			s.collect{	
				case ch if 'a' <= ch && ch <= 'z' => ch
				case ch if 'A' <= ch && ch <= 'Z' => (ch - 'A' + 'a').asInstanceOf[Char]
			}.foreach{ ch =>
				count(ChMap.apply(ch)) = count(ChMap.apply(ch)) + 1
			}
		)

		for(ch <- ('a' to 'z')){
			println(ch + " : "+count(ChMap.apply(ch)))
		}
	}
	
	object ChMap{
		def apply : PartialFunction[Char,Int] = { 
			case ch if 'a' <= ch && ch <= 'z' => ch - 'a'
			case ch if 'A' <= ch && ch <= 'Z' => ch - 'A'
		}
	}
}