Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in Scala (judge verdict: Accepted)

import scala.io.StdIn

object Main extends App {

  val Array(n, m, l) = StdIn.readLine().split(' ').map(_.toInt)
  val a = Array.fill(n, m)(0) 
  val b = Array.fill(m, l)(0)
  //http://judge.u-aizu.ac.jp/onlinejudge/review.jsp?rid=2415390#1
  // val result = Array.fill(n, l)(0L)
  val result: Array[Array[Long]] = Array.ofDim[Long](n, l)
  
  (0 until n).foreach{ i =>
    a(i) = StdIn.readLine().split(' ').map(_.toInt)
  }
  (0 until m).foreach{ i =>
    b(i) = StdIn.readLine().split(' ').map(_.toInt)
  }

  (0 until n).foreach{ i =>
    (0 until l).foreach{ j =>
      result(i)(j) = (0 until m).foldLeft(0L){ (acc, k) =>
        acc + a(i)(k)*b(k)(j)
      }
    }
  }

  (0 until n).foreach { i =>
    println(result(i).mkString(" "))
  }
}