Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Scala (2.13.1) (judge verdict: Wrong Answer)

import java.util.Scanner

object Main extends App {
  val VMax = BigInt(1_000_000_000_000_000_000L)

  val sc     = new Scanner(System.in)
  val n      = sc.nextInt()
  var isOver = false
  var s      = BigInt(1)
  var i      = 0
  while (i < n && !isOver && s != 0) {
    val a = BigInt(sc.next())
    val x = s * a
    if (x <= VMax) {
      s = x
    } else {
      isOver = true
    }
    i += 1
  }

  println(if (isOver) -1 else s)
}