Problem:
Score : 200 points

Problem Statement

We have held a popularity poll for N items on sale. Item i received A_i votes.

From these N items, we will select M as popular items. However, we cannot select an item with less than \dfrac{1}{4M} of the total number of votes.

If M popular items can be selected, print Yes; otherwise, print No.

Constraints

1 \leq M \leq N \leq 100

1 \leq A_i \leq 1000

A_i are distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
A_1 ... A_N

Output

If M popular items can be selected, print Yes; otherwise, print No.

Sample Input 1

4 1
5 4 2 1

Sample Output 1

Yes

There were 12 votes in total. The most popular item received 5 votes, and we can select it.

Sample Input 2

3 2
380 19 1

Sample Output 2

No

There were 400 votes in total. The second and third most popular items received less than \dfrac{1}{4\times 2} of the total number of votes, so we cannot select them. Thus, we cannot select two popular items.

Sample Input 3

12 3
4 56 78 901 2 345 67 890 123 45 6 789

Sample Output 3

Yes

Solution in Scala (2.11.7) (judge verdict: Accepted)

object Main extends App {
  val input1 = readLine
  val N = input1.split(" ")(0).toInt
  val M = input1.split(" ")(1).toInt  
  
  var array: Array[Int] = Array.empty
  
  val input2 = readLine
  for(count1 <- 1 to N){
    var input3 = input2.split(" ")(count1 -1).toInt
    array = array :+ input3
  }
    
  var sorted = array.sorted.reverse
  
  if(sorted(M-1) < array.sum / (4.0*M)) println("No")
  else if(sorted(M-1) >= array.sum / (4.0*M)) println("Yes")
}