Problem:
Score : 300 points

Problem Statement

You are given two non-negative integers L and R.
We will choose two integers i and j such that L \leq i < j \leq R.
Find the minimum possible value of (i \times j) \mbox{ mod } 2019.

Constraints

All values in input are integers.

0 \leq L < R \leq 2 \times 10^9

Input

Input is given from Standard Input in the following format:

L R

Output

Print the minimum possible value of (i \times j) \mbox{ mod } 2019 when i and j are chosen under the given condition.

Sample Input 1

2020 2040

Sample Output 1

2

When (i, j) = (2020, 2021), (i \times j) \mbox{ mod } 2019 = 2.

Sample Input 2

4 5

Sample Output 2

20

We have only one choice: (i, j) = (4, 5).

Solution in Scala (2.11.7) (judge verdict: Time Limit Exceeded)

import scala.math._

// longでrangeの作り方

object Main extends App {

  val YES = "YES"
  val Yes = "Yes"
  val NO = "NO"
  val No = "No"
  ///////////////////////////////////////////

  val sc = new java.util.Scanner(System.in)
  val l, r = sc.nextLong
//  val list = List.fill(n, d)(sc.nextInt)

//  val sorted = (l to r).map(p => (p, p % 2019)).sortBy(_._2)
//  val ans = (sorted.head._1 * sorted(1)._1) % 2019

  val ans = (l to r).take(2019).combinations(2).map(f => (f, (f.head * f.last) % 2019)).minBy(_._2)._2
  println(ans)

  ///////////////////////////////////////////

  def bigIterator(start: BigInt, end: BigInt, step: BigInt = 1) =
    Iterator.iterate(start)(_ + step).takeWhile(_ <= end)

  def lcm(a :Int, b :Int): Int =
    a / gcd(a, b) * b

  def lcm(a :Long, b :Long): Long =
    a / gcd(a, b) * b

  def gcd(a: Int, b: Int): Int =
    if (b == 0) a else gcd(b, a % b)

  def gcd(a: Long, b: Long): Long =
    if (b == 0) a else gcd(b, a % b)

  def setOrUpdated[A, B](a: Map[A, B], key: A, value: B, f: (B, B) => B) =
    a.get(key) match {
      case Some(v) => a.updated(key, f(value, v))
      case _ => a + (key -> value)
    }
}