Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Scala (2.13.1) (judge verdict: Wrong Answer)

object Main extends App {

  def run(): Unit = {
    import io.StdIn._
    val _   = readLine().toInt
    val xs  = readLine().split("\\s").map(_.toLong)
    val M   = 1e+18.toLong

    xs.find(_ == 0) match {
      case Some(_) =>
        println(0)

      case _ =>
        val Array(x, rest @ _*) = xs
        val n = rest.foldLeft(x)((a, b) => a * b)
        
        println(if (M < n) -1 else n)
    }
  }

  run()
}