Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Scala (2.13.1) (judge verdict: Accepted)

import scala.io.StdIn._
import scala.math._

object Main extends App with StdInHelper {
  val n = BigInt(readInt)
  val as = readLongs

  if (as.contains(0L)) {
    println(0)
  } else {
    var res = BigInt(1)
    val b = new scala.util.control.Breaks
    b.breakable {
      for (a <- as) {
        var temp = res * BigInt(a)
        if (BigInt(pow(10, 18).toLong) < temp) {
          res = BigInt(-1)
          b.break
        } else {
          res = res * a
        }
      }
    }
    println(res)
  }
}

trait StdInHelper {
  def readInts = readLine.split(" ").map(_.toInt)
  def readLongs = readLine.split(" ").map(_.toLong)
}