Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Scala (2.11.7) (judge verdict: Wrong Answer)

import scala.io.StdIn

object Main extends App {
  val Array(n, a, b, c, d) = StdIn.readLine().split(" ").map(_.toInt)
  val S  = StdIn.readLine()

  def solve(s : String, a: Int, b: Int, c: Int, d: Int ): String = {
    val s1 = s.slice(a, c)
    val s2 = s.slice(b, d)

    if (s1.contains("##")) 
      return "No"

    if (s2.contains("##")) 
      return "No"

    if (s(c -1) == '#' || s(d -1) == '#')
      return "No"

    if (s.length() == 4)
      return "Yes"

    if (d < c) {
      if (s(b) == '.') {
        if (a + 1 == b || s(b - 2) == '.') {
          return "Yes"
        }
      }
      if (! s1.contains("...")) 
        return "No"
    }

    "Yes"
  }

  println(solve(S, a, b, c, d))
}