Problem:
Score : 300 points

Problem Statement

There are N observatories in AtCoder Hill, called Obs. 1, Obs. 2, ..., Obs. N. The elevation of Obs. i is H_i.
There are also M roads, each connecting two different observatories. Road j connects Obs. A_j and Obs. B_j.

Obs. i is said to be good when its elevation is higher than those of all observatories that can be reached from Obs. i using just one road.
Note that Obs. i is also good when no observatory can be reached from Obs. i using just one road.

How many good observatories are there?

Constraints

2 \leq N \leq 10^5

1 \leq M \leq 10^5

1 \leq H_i \leq 10^9

1 \leq A_i,B_i \leq N

A_i \neq B_i

Multiple roads may connect the same pair of observatories.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
H_1 H_2 ... H_N
A_1 B_1
A_2 B_2
:
A_M B_M

Output

Print the number of good observatories.

Sample Input 1

4 3
1 2 3 4
1 3
2 3
2 4

Sample Output 1

2

From Obs. 1, you can reach Obs. 3 using just one road. The elevation of Obs. 1 is not higher than that of Obs. 3, so Obs. 1 is not good.

From Obs. 2, you can reach Obs. 3 and 4 using just one road. The elevation of Obs. 2 is not higher than that of Obs. 3, so Obs. 2 is not good.

From Obs. 3, you can reach Obs. 1 and 2 using just one road. The elevation of Obs. 3 is higher than those of Obs. 1 and 2, so Obs. 3 is good.

From Obs. 4, you can reach Obs. 2 using just one road. The elevation of Obs. 4 is higher than that of Obs. 2, so Obs. 4 is good.

Thus, the good observatories are Obs. 3 and 4, so there are two good observatories.

Sample Input 2

6 5
8 6 9 1 2 1
1 3
4 2
4 3
4 6
4 6

Sample Output 2

3

Solution in Scala (2.13.1) (judge verdict: Accepted)

import scala.io.StdIn._

object Helpers {
  def readIntLine = readLine.split(" ").map(_.toInt)
  def readInts(n: Int) = Array.fill(n)(readInt)

  def splitDigits(i: Int): Seq[Int] = i.toString.map(_.asDigit)

  def log[A](x: A): A = {println(x); x}

  implicit class IntImplicits(val i: Int) {
    def isEven = i % 2 == 0
    def isOdd = !isEven
  }
}

object Main extends App {
  import Helpers._

  val Array(n, m) = readIntLine
  val hs: Array[Int] = readIntLine

  var roads = Map[Int, Set[Int]]()
  for (_ <- Range(0, m)) {
    val Array(a, b) = readIntLine
    roads = if (roads.contains(a)) roads + (a -> (roads(a) + b)) else roads + (a -> Set(b))
    roads = if (roads.contains(b)) roads + (b -> (roads(b) + a)) else roads + (b -> Set(a))
  }

  def isGood(x: Int, roads: Map[Int, Set[Int]]): Boolean = {
    if (roads.contains(x + 1)) {
      val h = hs(x)
      !roads(x + 1).exists((a: Int) => (hs(a - 1) >= h))
    } else {
      true
    }
  }

  println(Range(0, n).count(isGood(_, roads)))
}