Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in Rust (1.15.1) (judge verdict: Time Limit Exceeded)

use std::io;
//use std::collections::HashMap;
//use std::collections::BinaryHeap;
//use std::collections::HashSet;
//use std::mem; // mem::swap(&mut x,&mut y);
use std::cmp; // cmp::max,cmp::min

// Rust memo: https://hackmd.io/i0lQY1OKTDW1t66TECOmiw?both

#[allow(dead_code)]
fn read_line() -> String{
    let mut s = String::new();
    io::stdin().read_line(&mut s).unwrap();
    s.trim().to_string()
}

#[allow(dead_code)]
fn read_charvec() -> Vec<char>{
    read_line().chars().collect()
}

#[allow(dead_code)]
fn read_ints() -> Vec<i64>{
    let s = read_line();
    let split:Vec<&str> = s.split(" ").collect();
    split.iter().map(|&x| x.to_string().parse().unwrap()).collect()
}

#[allow(dead_code)]
fn read_int() -> i64{
    read_ints()[0]
}

#[allow(dead_code)]
fn reverse(s: &String) -> String{
    s.chars().rev().collect::<String>()
}

#[allow(dead_code)]
fn read_lines(n:i64) -> Vec<String>{
    let mut xs = Vec::new();

    for _i in 0..n{
        xs.push(read_line());
    }

    xs
}

#[allow(dead_code)]
fn read_ints2(n:i64) -> Vec<i64>{
    read_lines(n).iter().map(|x| x.parse().unwrap()).collect()
}

#[allow(dead_code)]
fn arange(start:i64,end:i64,step:i64) -> Vec<i64>{
    let mut ret = Vec::new();
    let mut i = start;

    while i < end{
        ret.push(i);
        i += step;
    }

    ret
}

#[allow(dead_code)]
const DXS : [i64; 4] = [0,0,1,-1];
#[allow(dead_code)]
const DYS : [i64; 4]  = [1,-1,0,0];
#[allow(dead_code)]
const INF : i64 = 999999999;
#[allow(dead_code)]
const N_PRIME : i64 = 1000000007;

////////////////////////////////////////////////

fn change(s:&mut Vec<char>,c1 : char,c2 :char){
    for i in 0..s.len(){
        if s[i] == c1 {
            s[i] = c2;
        }else if s[i] == c2{
            s[i] = c1;
        }
    }
}

fn main(){
    let target = read_line().chars().collect::<Vec<_>>();
    let mut s = read_line().chars().collect::<Vec<_>>();
    
    for i in 0..s.len(){
        if s[i] != target[i]{
            let c1 = s[i];
            change(&mut s,c1,target[i]);
        }
    }
    
    if s == target{
        println!("Yes");
    }else{
        println!("No");
    }
}