Problem:
Score : 500 points

Problem Statement

There are N integers, A_1, A_2, ..., A_N, written on a blackboard.

We will repeat the following operation N-1 times so that we have only one integer on the blackboard.

Choose two integers x and y on the blackboard and erase these two integers. Then, write a new integer x-y.

Find the maximum possible value of the final integer on the blackboard and a sequence of operations that maximizes the final integer.

Constraints

2 \leq N \leq 10^5

-10^4 \leq A_i \leq 10^4

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the maximum possible value M of the final integer on the blackboard, and a sequence of operations x_i, y_i that maximizes the final integer, in the format below.

Here x_i and y_i represent the integers x and y chosen in the i-th operation, respectively.

If there are multiple sequences of operations that maximize the final integer, any of them will be accepted.

M
x_1 y_1
:
x_{N-1} y_{N-1}

Sample Input 1

3
1 -1 2

Sample Output 1

4
-1 1
2 -2

If we choose x = -1 and y = 1 in the first operation, the set of integers written on the blackboard becomes (-2, 2).

Then, if we choose x = 2 and y = -2 in the second operation, the set of integers written on the blackboard becomes (4).

In this case, we have 4 as the final integer. We cannot end with a greater integer, so the answer is 4.

Sample Input 2

3
1 1 1

Sample Output 2

1
1 1
1 0

Solution in Rust (1.15.1) (judge verdict: Runtime Error)

#[allow(unused_imports)]
use std::cmp;

// Input macro from https://qiita.com/tanakh/items/0ba42c7ca36cd29d0ac8
macro_rules! input {
  (source = $s:expr, $($r:tt)*) => {
    let mut iter = $s.split_whitespace();
    input_inner!{iter, $($r)*}
  };
  ($($r:tt)*) => {
    #[allow(unused_mut)]
    let mut s = {
      use std::io::Read;
      let mut s = String::new();
      std::io::stdin().read_to_string(&mut s).unwrap();
      s
    };
    let mut iter = s.split_whitespace();
    input_inner!{iter, $($r)*}
  };
}

macro_rules! input_inner {
  ($iter:expr) => {};
  ($iter:expr, ) => {};

  ($iter:expr, $var:ident : $t:tt $($r:tt)*) => {
    let $var = read_value!($iter, $t);
    input_inner!{$iter $($r)*}
  };
}

macro_rules! read_value {
  ($iter:expr, ( $($t:tt),* )) => {
    ( $(read_value!($iter, $t)),* )
  };

  ($iter:expr, [ $t:tt ; $len:expr ]) => {
    (0..$len).map(|_| read_value!($iter, $t)).collect::<Vec<_>>()
  };

  ($iter:expr, chars) => {
    read_value!($iter, String).chars().collect::<Vec<char>>()
  };

  ($iter:expr, usize1) => {
    read_value!($iter, usize) - 1
  };

  ($iter:expr, $t:ty) => {
    $iter.next().unwrap().parse::<$t>().expect("Parse error")
  };
}

fn solve(pos: &mut Vec<i64>, neg: &mut Vec<i64>) -> i64 {
  if pos.len() == 1 && neg.len() == 1 {
    let n = neg[0];
    let p = pos[0];
    println!("{} {}", p, n);
    p - n
  } else if pos.len() >= neg.len() {
    let p = pos.pop().unwrap();
    let x = solve(neg, pos);
    println!("{} {}", p, x);
    p - x
  } else {
    let n = neg.pop().unwrap();
    let x = solve(pos, neg);
    println!("{} {}", x, n);
    x - n
  }
}

fn main() {
  input! {
    n: usize,
    aa: [i64; n],
  }
  let mut aa = aa;
  aa.sort();
  let sum: i64 = aa.iter().sum();
  let val;
  let mut pos;
  let mut neg;
  if *aa.last().unwrap() < 0 {
    val = - sum + *aa.last().unwrap();
    pos = vec![*aa.last().unwrap()];
    neg = aa.iter().cloned().take(n-1).collect();
  } else if *aa.first().unwrap() > 0 {
    val = sum - *aa.first().unwrap();
    pos = aa.iter().cloned().skip(1).collect();
    neg = vec![*aa.first().unwrap()];
  } else {
    val = aa.iter().map(|&x| x.abs()).sum();
    pos = aa.iter().cloned().filter(|&x| x >= 0).collect();
    neg = aa.iter().cloned().filter(|&x| x < 0).collect();
  }
  println!("{}", val);
  solve(&mut pos, &mut neg);
}