Problem:
Score : 100 points

Problem Statement

A biscuit making machine produces B biscuits at the following moments: A seconds, 2A seconds, 3A seconds and each subsequent multiple of A seconds after activation.

Find the total number of biscuits produced within T + 0.5 seconds after activation.

Constraints

All values in input are integers.

1 \leq A, B, T \leq 20

Input

Input is given from Standard Input in the following format:

A B T

Output

Print the total number of biscuits produced within T + 0.5 seconds after activation.

Sample Input 1

3 5 7

Sample Output 1

10

Five biscuits will be produced three seconds after activation.

Another five biscuits will be produced six seconds after activation.

Thus, a total of ten biscuits will be produced within 7.5 seconds after activation.

Sample Input 2

3 2 9

Sample Output 2

6

Sample Input 3

20 20 19

Sample Output 3

0

Solution in Rust (1.15.1) (judge verdict: Wrong Answer)

macro_rules! input {
    ($x:expr) => {
        let mut buf = String::new();
        std::io::stdin().read_line(&mut buf).unwrap();
        $x = buf.trim().parse().unwrap();
    };

    ($x:expr, $($y:expr), +) => {
        let mut buf = String::new();
        std::io::stdin().read_line(&mut buf).ok();
        input_iter!(buf.split_whitespace(), $x, $($y), +);
    };

    ($v:expr; $size:expr) => {
        let mut buf = String::new();
        std::io::stdin().read_line(&mut buf).ok();
        for v in buf.split_whitespace() {
            $v.push(v.parse().unwrap());
        }
    };

    ($v:expr; $h_size:expr, $w_size:expr) => {
        for _ in 0..$h_size {
            let mut part_vec = Vec::new();
            let mut buf = String::new();
            std::io::stdin().read_line(&mut buf).ok();
            for v in buf.split_whitespace() {
                part_vec.push(v.parse().unwrap());
            }
            $v.push(part_vec);
        }
    };
}

#[allow(unused_macros)]
macro_rules! input_iter {
    ($iter:expr, $x:expr) => {
        $x = $iter.next().unwrap().parse().unwrap();
    };

    ($iter:expr, $x:expr, $($y:expr), +) => {
        let mut iter = $iter;
        $x = iter.next().unwrap().parse().unwrap();
        input_iter!(iter, $($y), *);
    };
}

fn main() {
    let mut _a: i8;
    let mut _b: i8;
    let mut _t: i8;
    input!(_a, _b, _t);
    println!("{}", _b * (_t / _a));
}