Problem:
Score : 100 points

Problem Statement

You are given a grid with 2 rows and 3 columns of squares.
The color of the square at the i-th row and j-th column is represented by the character C_{ij}.

Write a program that prints YES if this grid remains the same when rotated 180 degrees, and prints NO otherwise.

Constraints

C_{i,j}(1 \leq i \leq 2, 1 \leq j \leq 3) is a lowercase English letter.

Input

Input is given from Standard Input in the following format:

C_{11}C_{12}C_{13}
C_{21}C_{22}C_{23}

Output

Print YES if this grid remains the same when rotated 180 degrees; print NO otherwise.

Sample Input 1

pot
top

Sample Output 1

YES

This grid remains the same when rotated 180 degrees.

Sample Input 2

tab
bet

Sample Output 2

NO

This grid does not remain the same when rotated 180 degrees.

Sample Input 3

eye
eel

Sample Output 3

NO

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::io::{stdin, Read, StdinLock};
use std::str::FromStr;
use std::vec::Vec;
use std::{vec, cmp, num};


struct Scanner<'a> {
    cin: StdinLock<'a>,
}

impl<'a> Scanner<'a> {
    fn new(cin: StdinLock<'a>) -> Scanner<'a> {
        Scanner {cin: cin}
    }

    fn read1<T: FromStr>(&mut self) -> Option<T> {
        let token = self.cin.by_ref().bytes().map(|c| c.unwrap() as char)
                    .skip_while(|c| c.is_whitespace())
                    .take_while(|c| !c.is_whitespace())
                    .collect::<String>();
        token.parse::<T>().ok()
    }

    fn read<T: FromStr>(&mut self) -> T {
        self.read1().unwrap()
    }
}

// create Vec<char> from String
#[allow(dead_code)]
fn to_chars(s: String) -> vec::Vec<char> {
    let mut cs = s.chars();
    let mut res = vec::Vec::new();
    while let Some(c) = cs.next() {
        res.push(c);
    }
    res
}

fn main() {
    let cin = stdin();
    let cin = cin.lock();
    let mut sc = Scanner::new(cin);
    let mut c: Vec<Vec<char>> = Vec::new();
    for _i in 0..2 {
        let s: String = sc.read();
        c.push(to_chars(s));
    }
    let mut ok: bool = true;
    for i in 0..3 {
        ok &= c[0][i] == c[1][2 - i];
    }
    if ok {
        println!("YES");
    } else {
        println!("NO");
    }
}