Problem:
Score : 700 points

Problem Statement

We will define the median of a sequence b of length M, as follows:

Let b' be the sequence obtained by sorting b in non-decreasing order. Then, the value of the (M / 2 + 1)-th element of b' is the median of b. Here, / is integer division, rounding down.

For example, the median of (10, 30, 20) is 20; the median of (10, 30, 20, 40) is 30; the median of (10, 10, 10, 20, 30) is 10.

Snuke comes up with the following problem.

You are given a sequence a of length N.
For each pair (l, r) (1 \leq l \leq r \leq N), let m_{l, r} be the median of the contiguous subsequence (a_l, a_{l + 1}, ..., a_r) of a.
We will list m_{l, r} for all pairs (l, r) to create a new sequence m.
Find the median of m.

Constraints

1 \leq N \leq 10^5

a_i is an integer.

1 \leq a_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the median of m.

Sample Input 1

3
10 30 20

Sample Output 1

30

The median of each contiguous subsequence of a is as follows:

The median of (10) is 10.

The median of (30) is 30.

The median of (20) is 20.

The median of (10, 30) is 30.

The median of (30, 20) is 30.

The median of (10, 30, 20) is 20.

Thus, m = (10, 30, 20, 30, 30, 20) and the median of m is 30.

Sample Input 2

1
10

Sample Output 2

10

Sample Input 3

10
5 9 5 9 8 9 3 5 4 3

Sample Output 3

8

Solution in Rust (1.15.1) (judge verdict: Accepted)

// https://atcoder.jp/contests/arc101/tasks/arc101_b
//
#![allow(unused_imports)]
use std::io::*;
use std::io::Write;
use std::fmt::*;
use std::str::*;
use std::cmp::*;
use std::collections::*;

// Input macros.
// Original by tanakh: https://qiita.com/tanakh/items/0ba42c7ca36cd29d0ac8
#[allow(unused_macros)]
macro_rules! input {
    (source = $s:expr, $($r:tt)*) => {
        let mut iter = $s.split_whitespace();
        input_inner!{iter, $($r)*}
    };
    ($($r:tt)*) => {
        let s = {
            use std::io::Read;
            let mut s = String::new();
            std::io::stdin().read_to_string(&mut s).unwrap();
            s
        };
        let mut iter = s.split_whitespace();
        input_inner!{iter, $($r)*}
    };
}

#[allow(unused_macros)]
macro_rules! input_inner {
    ($iter:expr) => {};
    ($iter:expr, ) => {};

    ($iter:expr, $var:ident : $t:tt $($r:tt)*) => {
        let $var = read_value!($iter, $t);
        input_inner!{$iter $($r)*}
    };

    ($iter:expr, mut $var:ident : $t:tt $($r:tt)*) => {
        let mut $var = read_value!($iter, $t);
        input_inner!{$iter $($r)*}
    };
}

#[allow(unused_macros)]
macro_rules! read_value {
    ($iter:expr, ( $($t:tt),* )) => {
        ( $(read_value!($iter, $t)),* )
    };

    ($iter:expr, [ $t:tt ; $len:expr ]) => {
        (0..$len).map(|_| read_value!($iter, $t)).collect::<Vec<_>>()
    };

    ($iter:expr, [ next / $t:tt ]) => {
        {
            let len = read_value!($iter, usize);
            (0..len).map(|_| read_value!($iter, $t)).collect::<Vec<_>>()
        }
    };

    ($iter:expr, switch) => {
        {
            let ty = read_value!($iter, i32);
            if ty == 1 {
                vec![ty, read_value!($iter, i32), read_value!($iter, i32)]
            } else if ty == 2 {
                vec![ty, read_value!($iter, i32)]
            } else {
                vec![ty, read_value!($iter, i32)]
            }
        }
    };

    ($iter:expr, chars) => {
        read_value!($iter, String).chars().collect::<Vec<char>>()
    };

    ($iter:expr, usize1) => {
        read_value!($iter, usize) - 1
    };

    ($iter:expr, $t:ty) => {
        $iter.next().unwrap().parse::<$t>().expect("Parse error")
    };
}

#[allow(unused_macros)]
macro_rules! read_line {
    ($t:tt) => {
        {
            let mut s = String::new();
            std::io::stdin().read_line(&mut s).unwrap();
            s.trim_right().parse::<$t>().unwrap()
        }
    }
}

#[allow(unused_macros)]
macro_rules! dvec {
    ($t:expr ; $len:expr) => {
        vec![$t; $len]
    };

    ($t:expr ; $len:expr, $($rest:expr),*) => {
        vec![dvec!($t; $($rest),*); $len]
    };
}

#[allow(unused_macros)]
macro_rules! ifv {
    ($t:expr, $a:expr, $b: expr) => {
        if $t { $a } else { $b }
    }
}

#[allow(unused_macros)]
macro_rules! fill {
    ($t:expr, $v:expr) => {
        for i in 0..$t.len() {
            $t[i] = $v;
        }
    };
}

#[allow(unused_macros)]
macro_rules! join {
    ($t:expr, $glue:expr) => {
        $t.into_iter().map(|w| w.to_string()).collect::<Vec<_>>().join($glue)
    };
}

#[allow(unused_macros)]
macro_rules! debug {
    ($($a:expr),*) => {
        println!(concat!($(stringify!($a), " = {:?}, "),*), $($a),*);
    }
}

// ===

struct FenwickTree<T> {
    data: Vec<T>
}

impl<T: Copy + Default + std::ops::Add + std::ops::AddAssign + std::ops::Sub> FenwickTree<T> {
    fn new(n: usize, initial: T) -> Self {
        FenwickTree { data: vec![initial; n+1] }
    }

    /// Computes sum value of ([0, i)).
    fn sum(&self, i: usize) -> T {
        let mut idx = i as i64;
        let mut ret = T::default();
        while idx > 0 {
            ret += self.data[idx as usize];
            idx -= idx & (-idx);
        }
        ret
    }

    /// Adds value x into i-th position.
    fn add(&mut self, i: usize, x: T) {
        let mut idx = (i + 1) as i64;
        while idx < self.data.len() as i64 {
            self.data[idx as usize] += x;
            idx += idx & (-idx);
        }
    }

    fn range(&self, r: std::ops::Range<usize>) -> <T as std::ops::Sub>::Output {
        self.sum(r.end) - self.sum(r.start)
    }
}
// ===

fn solve(a: Vec<i64>) -> i64 {
    let n = a.len();

    let mut sum = vec![0; n+1];
    for i in 0..n {
        sum[i+1] = sum[i] + a[i];
    }
    let mut fenwick = FenwickTree::new(n*2+10, 0i64);
    let base = (n+5) as i64;
    let mut count = 0;
    for i in 0..n+1 {
        let l = sum[i];
        let want = (l + base) as usize; // -l to inf
        count += fenwick.range(0..want+1);
        // debug!(i, fenwick.range(0..want+1));
        fenwick.add((sum[i] + base) as usize, 1);
    }
    // debug!(a, count);
    let all = (n * (n + 1) / 2) as i64;
    ifv!(count >= (all+1)/2, 1, 0)
}

fn main() {
    input! {
        n: usize, a: [i64; n]
    };

    let mut b = a.clone();
    b.sort();
    let mut left = 0;
    let mut right = n;
    while right - left > 1 {
        let med = (right + left) / 2;
        let a = a.iter().cloned().map(|x| ifv!(x >= b[med], 1, -1)).collect::<Vec<_>>();
        if solve(a) == 1 {
            left = med;
        } else {
            right = med;
        }
    }
    println!("{}", b[left]);
}