Problem:
Score : 400 points

Problem Statement

Given are integers A, B, and N.

Find the maximum possible value of floor(Ax/B) - A × floor(x/B) for a non-negative integer x not greater than N.

Here floor(t) denotes the greatest integer not greater than the real number t.

Constraints

1 ≤ A ≤ 10^{6}

1 ≤ B ≤ 10^{12}

1 ≤ N ≤ 10^{12}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B N

Output

Print the maximum possible value of floor(Ax/B) - A × floor(x/B) for a non-negative integer x not greater than N, as an integer.

Sample Input 1

5 7 4

Sample Output 1

2

When x=3, floor(Ax/B)-A×floor(x/B) = floor(15/7) - 5×floor(3/7) = 2. This is the maximum value possible.

Sample Input 2

11 10 9

Sample Output 2

9

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

use proconio::input;

fn main() {
    input! {
        a: i64,
        b: i64,
        n: i64,
    }
    let mut max: i64 = 0;
    let mut _temp: i64 = 0;

    let mut limit = if b > n {n} else {b};
    if limit > a {
        limit = a;
    }

    for x in 0..=limit {
        _temp = (a * x / b) - a * (x / b);
        println!("({} * {} / {}) - {} * ({} / {}) = {} - a * {}", a,x,b,a,x,b,a*x/b, x/b);
        if _temp > max {
            max = _temp;
        }
    }

    println!("{}", max);
}