Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in Rust (1.42.0) (judge verdict: Accepted)

use std::io;

fn sum_of_string(s: &String) -> u32 {
    s.chars().fold(0, |acc, c| c.to_digit(10).unwrap_or(0) + acc)
  }

fn main(){


    let mut input: String = String::new();

    io::stdin().read_line(&mut input).expect("Enter Something");
    
    let digit_sum:u32 = sum_of_string(&input);

    println!("{}", {
        if digit_sum%9 == 0{"Yes"}
        else {"No"}
    });

}