Problem:
Score : 100 points

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost 0.

Then, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.

Here, |x| denotes the absolute value of x.

Find the minimum total cost required to complete all the task.

Constraints

All values in input are integers.

1 \leq A_1, A_2, A_3 \leq 100

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

Print the minimum total cost required to complete all the task.

Sample Input 1

1 6 3

Sample Output 1

5

When the tasks are completed in the following order, the total cost will be 5, which is the minimum:

Complete the first task at cost 0.

Complete the third task at cost 2.

Complete the second task at cost 3.

Sample Input 2

11 5 5

Sample Output 2

6

Sample Input 3

100 100 100

Sample Output 3

0

Solution in Rust (1.15.1) (judge verdict: Wrong Answer)

use std::io::prelude::*;

fn input<T>() -> T
where
    T: std::str::FromStr,
{
    let stdin = std::io::stdin();
    let token = stdin
        .lock()
        .bytes()
        .map(|c| c.unwrap() as char)
        .skip_while(|c| c.is_whitespace())
        .take_while(|c| !c.is_whitespace())
        .collect::<String>();
    token.parse().ok().unwrap()
}

fn main() {
    let a1 = input::<i64>();
    let a2 = input::<i64>();
    let a3 = input::<i64>();

    let mut ans = i64::max_value();
    ans = std::cmp::min(ans, (a1 - a2).abs() + (a2 - a3).abs());
    ans = std::cmp::min(ans, (a1 - a3).abs() + (a3 - a2).abs());
    ans = std::cmp::min(ans, (a2 - a1).abs() + (a1 - a3).abs());
    ans = std::cmp::min(ans, (a2 - a3).abs() + (a3 - a2).abs());
    ans = std::cmp::min(ans, (a3 - a1).abs() + (a1 - a2).abs());
    ans = std::cmp::min(ans, (a3 - a2).abs() + (a2 - a1).abs());
    println!("{}", ans);
}