Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in Rust (1.42.0) (judge verdict: Accepted)

use proconio::input;
use proconio::marker::Chars;

fn main() {
    input! {
        n: usize,
        mut a: usize,
        mut b: usize,
        mut c: usize,
        s: [Chars; n],
    };
    let mut ans = vec!['_'; n];
    for (i, s_i) in s.iter().enumerate() {
        match (s_i[0], s_i[1]) {
            ('A', 'B') => {
                if a == 0 && b == 0 {
                    println!("No");
                    return;
                } else if a == 0 {
                    a += 1;
                    b -= 1;
                    ans[i] = 'A';
                } else if b == 0 {
                    a -= 1;
                    b += 1;
                    ans[i] = 'B';
                } else {
                    if i < n - 1 && (s[i + 1][0], s[i + 1][1]) == ('B', 'C') {
                        a -= 1;
                        b += 1;
                        ans[i] = 'B';
                    } else {
                        a += 1;
                        b -= 1;
                        ans[i] = 'A';
                    }
                }
            }
            ('A', 'C') => {
                if a == 0 && c == 0 {
                    println!("No");
                    return;
                } else if a == 0 {
                    a += 1;
                    c -= 1;
                    ans[i] = 'A';
                } else if c == 0 {
                    a -= 1;
                    c += 1;
                    ans[i] = 'C';
                } else {
                    if i < n - 1 && (s[i + 1][0], s[i + 1][1]) == ('B', 'C') {
                        a -= 1;
                        c += 1;
                        ans[i] = 'C';
                    } else {
                        a += 1;
                        c -= 1;
                        ans[i] = 'A';
                    }
                }
            }
            ('B', 'C') => {
                if b == 0 && c == 0 {
                    println!("No");
                    return;
                } else if c == 0 {
                    b -= 1;
                    c += 1;
                    ans[i] = 'C';
                } else if b == 0 {
                    b += 1;
                    c -= 1;
                    ans[i] = 'B';
                } else {
                    if i < n - 1 && (s[i + 1][0], s[i + 1][1]) == ('A', 'C') {
                        b -= 1;
                        c += 1;
                        ans[i] = 'C';
                    } else {
                        b += 1;
                        c -= 1;
                        ans[i] = 'B';
                    }
                }
            }
            _ => unreachable!(),
        }
    }
    println!("Yes");
    for a in ans {
        println!("{}", a);
    }
}