Problem:
Score: 200 points

Problem Statement

A country decides to build a palace.

In this country, the average temperature of a point at an elevation of x meters is T-x \times 0.006 degrees Celsius.

There are N places proposed for the place. The elevation of Place i is H_i meters.

Among them, Princess Joisino orders you to select the place whose average temperature is the closest to A degrees Celsius, and build the palace there.

Print the index of the place where the palace should be built.

It is guaranteed that the solution is unique.

Constraints

1 \leq N \leq 1000

0 \leq T \leq 50

-60 \leq A \leq T

0 \leq H_i \leq 10^5

All values in input are integers.

The solution is unique.

Input

Input is given from Standard Input in the following format:

N
T A
H_1 H_2 ... H_N

Output

Print the index of the place where the palace should be built.

Sample Input 1

2
12 5
1000 2000

Sample Output 1

1

The average temperature of Place 1 is 12-1000 \times 0.006=6 degrees Celsius.

The average temperature of Place 2 is 12-2000 \times 0.006=0 degrees Celsius.

Thus, the palace should be built at Place 1.

Sample Input 2

3
21 -11
81234 94124 52141

Sample Output 2

3

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::io;

fn main() {
    let mut s = String::new();
    io::stdin().read_line(&mut s).expect("failed to read");
    // let n: i32 = s.trim().parse().unwrap();
    s = String::new();
    io::stdin().read_line(&mut s).expect("failed to read");
    let v: Vec<&str> = s.trim().split(" ").collect();
    let t: f32 = v[0].parse().unwrap();
    let a: f32 = v[1].parse().unwrap();
    let mut ss = String::new();
    io::stdin().read_line(&mut ss).expect("failed to read");
    let h: Vec<&str> = ss.trim().split(" ").collect();

    let mut temp: Vec<f32> = Vec::new();
    for i in h {
        let tmp: f32 = i.parse().unwrap();
        temp.push(t - tmp * 0.006);
    }

    let mut near: f32 = 10001.0;
    let mut ans = 0;
    for (i, v) in temp.into_iter().enumerate() {
        let sub = a - v;
        if near.abs() > sub.abs() {
            near = sub;
            ans = i + 1;
        }
    }

    println!("{}", ans);

}