Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in Rust (1.15.1) (judge verdict: Time Limit Exceeded)

use std::collections::HashMap;

fn read<T: std::str::FromStr>() -> T {
    let mut s = String::new();
    std::io::stdin().read_line(&mut s).ok();
    s.trim().parse().ok().unwrap()
}
fn read_vec<T: std::str::FromStr>() -> Vec<T> {
    read::<String>().split_whitespace().map(|e| e.parse().ok().unwrap()).collect()
}

fn readStr() -> String {
    let mut str = read::<String>();
    str
}

fn addMap(k: char, v: char,m: Option<HashMap<char, char>>) -> Option<HashMap<char, char>> {
    match m {
        Some(a) => {
            let mut p = a;
            let a = ! p.contains_key(&k) || *p.get(&k).unwrap() == v;
            if a {
                (p).insert(k, v);
                Some(p)
            } else {
                None
            }
        },
        None => None
    }
}

fn main() {
    let mut l1 = readStr();
    let mut l2 = readStr();
    let mut map1 = Some(HashMap::new());
    let mut map2 = Some(HashMap::new());

    for i in 0..l1.len() {
        map1 = addMap(l1.chars().nth(i).unwrap(), l2.chars().nth(i).unwrap(), map1);
        map2 = addMap(l2.chars().nth(i).unwrap(), l1.chars().nth(i).unwrap(), map2);
    }
    let result = match map1 {
        Some(x) =>{
            match map2 {
                Some(Y) => {"Yes"},
                None => {"No"}
            }
        },
        None => {"No"}
    };
    println!("{}", result);
}