Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in Rust (1.42.0) (judge verdict: Accepted)

fn main() {
    proconio::input! {
        n: usize,
        mut a: i32,
        mut b: i32,
        mut c: i32,
        s: [String;n],
    }
    let mut r = String::with_capacity(n);
    for i in 0..n {
        let p=f(&s[i]);
        let v1=if (p&1)==1 {a} else {b};
        let v2=if (p&4)==4 {c} else {b};
        if v1+v2==0 {
            println!("No");
            return;
        }
        let w=if v1==0 {
            1
        }
        else if v2==0 {
            2
        }
        else if v1==1 && v2==1 {
            if i+1<n {
                let q=f(&s[i+1]);
                if (p&1)==1 {
                    if (q&1)==1 {
                        1
                    }
                    else{
                        2
                    }
                }
                else {
                    if (q&2)==2 {
                        1
                    }
                    else {
                        2
                    }
                }
            }
            else {
                1
            }
        }
        else if v1<v2 {
            1
        }
        else {
            2
        };
        if w==1 {
            if (p&1)==1 {a+=1;} else {b+=1;};
            if (p&4)==4 {c-=1;} else {b-=1;};
            r.push(if (p&1)==1 {'A'} else {'B'});
        }
        else {
            if (p&1)==1 {a-=1;} else {b-=1;};
            if (p&4)==4 {c+=1;} else {b+=1;};
            r.push(if (p&4)==4 {'C'} else {'B'});
        }
    }
    println!("Yes");
    for c in r.chars() {
        println!("{}",c);
    }
}
fn f(s: &String) -> usize {
    let s=s.as_bytes();
    if s[0]==b'A' {
        if s[1]==b'B' {
            3
        }
        else {
            5
        }
    }
    else {
        6
    }
}