Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in Rust (1.42.0) (judge verdict: Accepted)

#![allow(unused_imports)]
// use itertools::Itertools;
use proconio::{input, marker::*};

fn main() {
    input! {
        n: usize,
        aa: [String; n]
    };
    if n == 1 {
        println!("{}", aa[0]);
        return;
    }
    // 1 -> 0
    // 2 -> 1 0
    // 3 -> 2 0 1
    // 4 -> 3 1 0 2
    // 5 -> 4 2 0 1 3
    // 6 -> 5 3 1 0 2 4
    let evens = (0..(n + 1) / 2)
        .map(|i: usize| aa[2 * i].as_str())
        .collect::<Vec<&str>>();
    let odds = (0..n / 2)
        .map(|i: usize| aa[2 * i + 1].as_str())
        .collect::<Vec<&str>>();
    let (mae, ato) = if n % 2 == 0 {
        (odds, evens)
    } else {
        (evens, odds)
    };
    println!(
        "{}",
        mae.into_iter()
            .rev()
            .chain(ato.into_iter())
            .collect::<Vec<_>>()
            .join(" ")
    );
}