Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::io::*;
use std::str::FromStr;

fn main() {
    let stdin = stdin();
    let mut lock = stdin.lock();
    let mut str1 = String::new();
    lock.read_to_string(&mut str1).unwrap();
    let mut iter1 = str1.trim().split_whitespace().map(|x| u32::from_str(x).unwrap());
    let n = iter1.next().unwrap();
    let an: Vec<u32> = iter1.collect();
    for a in (0usize..(n as usize)).rev() {
        if a % 2 == (n % 2 )as usize {
            continue;
        } else {
            print!("{} ", an[a]);
        }
    }
    for a in 0usize..(n as usize) {
        if a % 2 != (n % 2) as usize {
            continue;
        } else {
            print!("{}", an[a]);
            if (a + 2) <= n as usize {
                print!(" "); 
            }
        }
    }
    println!("");
}