Problem:
Score : 200 points

Problem Statement

Let S(n) denote the sum of the digits in the decimal notation of n.
For example, S(101) = 1 + 0 + 1 = 2.

Given an integer N, determine if S(N) divides N.

Constraints

1 \leq N \leq 10^9

Input

Input is given from Standard Input in the following format:

N

Output

If S(N) divides N, print Yes; if it does not, print No.

Sample Input 1

12

Sample Output 1

Yes

In this input, N=12.
As S(12) = 1 + 2 = 3, S(N) divides N.

Sample Input 2

101

Sample Output 2

No

As S(101) = 1 + 0 + 1 = 2, S(N) does not divide N.

Sample Input 3

999999999

Sample Output 3

Yes

Solution in Rust (1.15.1) (judge verdict: Accepted)

fn main() {
    let n: i32 = read();
    let mut result = "No";

    if n % s(n) == 0 {
        result = "Yes";
    }

    println!("{}", result);
}

fn s(n: i32) -> i32 {
    let mut n1 = n;
    let mut r = 0;
    while n1 > 0 {
        r += n1 % 10;
        n1 /= 10;
    }
    r
}

fn read<T: std::str::FromStr>() -> T {
    let mut s = String::new();
    std::io::stdin().read_line(&mut s).ok();
    s.trim().parse().ok().unwrap()
}