Problem:
Score : 300 points

Problem Statement

Given are an integer X and an integer sequence of length N: p_1, \ldots, p_N.

Among the integers not contained in the sequence p_1, \ldots, p_N (not necessarily positive), find the integer nearest to X, that is, find the integer whose absolute difference with X is the minimum. If there are multiple such integers, report the smallest such integer.

Constraints

1 \leq X \leq 100

0 \leq N \leq 100

1 \leq p_i \leq 100

p_1, \ldots, p_N are all distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X N
p_1 ... p_N

Output

Print the answer.

Sample Input 1

6 5
4 7 10 6 5

Sample Output 1

8

Among the integers not contained in the sequence 4, 7, 10, 6, 5, the one nearest to 6 is 8.

Sample Input 2

10 5
4 7 10 6 5

Sample Output 2

9

Among the integers not contained in the sequence 4, 7, 10, 6, 5, the ones nearest to 10 are 9 and 11. We should print the smaller one, 9.

Sample Input 3

100 0

Sample Output 3

100

When N = 0, the second line in the input will be empty. Also, as seen here, X itself can be the answer.

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

use proconio::{fastout, input};

#[fastout]
fn main() {
    input! {
        x: i64,
        n: usize,
        p: [i64; n]
    }

    let mut l = vec![0; 101usize];
    let mut t = vec![];
    for i in 0..n {
        l[p[i] as usize] += 1;
    }
    for i in 0..101usize {
        if l[i] == 0 {
            t.push(i);
        }
    }

    t.sort();
    // let mut ans = t[0];
    let mut idx = 0;
    for i in 1..t.len() {
        if (t[idx] as i64 - x).abs() > (t[i] as i64 - x).abs() {
            idx = i;
            // ans = t[i]
        }
    }
    println!("{}", t[idx]);
}