Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::io;
use std::str::FromStr;

fn divs(n : i32) -> i32 {
    let mut ans : i32 = 2;
    for i in 2..n {
        if n % i == 0 {
            ans += 1;
        }
    }
    ans
}

fn main() {
    let n: i32 = read();
    println!("{}", (2..n+1).filter(|x| x % 2 == 1 && divs(x.clone()) == 8).count())
}



#[allow(dead_code)]
fn getline() -> String {
    let mut ln = String::new();
    io::stdin().read_line(&mut ln).ok();
    ln.trim().to_string()
}

#[allow(dead_code)]
fn read<T>() -> T where T : FromStr {
    let mut ln = String::new();
    io::stdin().read_line(&mut ln).ok();
    ln.trim().parse().ok().unwrap()
}

#[allow(dead_code)]
fn reads<T>() -> Vec<T> where T : FromStr {
    let mut ln = String::new();
    io::stdin().read_line(&mut ln).ok();
    ln.trim().split_whitespace().map(|x| x.parse().ok().unwrap()).collect()
}