Problem:
Score : 300 points

Problem Statement

You are given N positive integers a_1, a_2, ..., a_N.

For a non-negative integer m, let f(m) = (m\ mod\ a_1) + (m\ mod\ a_2) + ... + (m\ mod\ a_N).

Here, X\ mod\ Y denotes the remainder of the division of X by Y.

Find the maximum value of f.

Constraints

All values in input are integers.

2 \leq N \leq 3000

2 \leq a_i \leq 10^5

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the maximum value of f.

Sample Input 1

3
3 4 6

Sample Output 1

10

f(11) = (11\ mod\ 3) + (11\ mod\ 4) + (11\ mod\ 6) = 10 is the maximum value of f.

Sample Input 2

5
7 46 11 20 11

Sample Output 2

90

Sample Input 3

7
994 518 941 851 647 2 581

Sample Output 3

4527

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::io::stdin;

fn main () {
    let mut n = String::new();
    stdin().read_line(&mut n).unwrap();
    let mut t = String::new();
    stdin().read_line(&mut t).unwrap();
    let n: i64 = n.trim().parse().unwrap();
    let t: Vec<i64> = t.trim().split_whitespace().map(|i|i.parse().unwrap()).collect();

    let f = || {
        t.iter().fold(0, |acc, &i| acc + i - 1)
    };

    println!("{}", f());
}