Problem:
Score : 300 points

Problem Statement

A company has N members, who are assigned ID numbers 1, ..., N.

Every member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.

When a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.

You are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq A_i < i

Input

Input is given from Standard Input in the following format:

N
A_2 ... A_N

Output

For each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.

Sample Input 1

5
1 1 2 2

Sample Output 1

2
2
0
0
0

The member numbered 1 has two immediate subordinates: the members numbered 2 and 3.

The member numbered 2 has two immediate subordinates: the members numbered 4 and 5.

The members numbered 3, 4, and 5 do not have immediate subordinates.

Sample Input 2

10
1 1 1 1 1 1 1 1 1

Sample Output 2

9
0
0
0
0
0
0
0
0
0

Sample Input 3

7
1 2 3 4 5 6

Sample Output 3

1
1
1
1
1
1
0

Solution in Rust (1.42.0) (judge verdict: Accepted)

use std::io;
fn main() {
    let mut l1 = String::new();
    let mut l2 = String::new();
    let stdin = io::stdin();
    stdin.read_line(&mut l1).unwrap();
    stdin.read_line(&mut l2).unwrap();
    let trimed = l1.trim_end();
    let trimed2 = l2.trim_end();
    let mut itr = trimed.split_ascii_whitespace();
    let mut itr2 = trimed2.split_ascii_whitespace();
    let n = itr.next().unwrap().parse::<i64>().unwrap();

    let mut vec = vec![0; n as usize];
    for x in 0..n - 1 {
        let a = itr2.next().unwrap().parse::<i64>().unwrap();
        vec[(a - 1) as usize] = vec[(a - 1) as usize] + 1;
    }

    for x in &vec {
        println!("{}", x);
    }
}