Problem:
Score : 300 points

Problem Statement

Given are positive integers N, M, Q, and Q quadruples of integers ( a_i , b_i , c_i , d_i ).

Consider a sequence A satisfying the following conditions:

A is a sequence of N positive integers.

1 \leq A_1 \leq A_2 \le \cdots \leq A_N \leq M.

Let us define a score of this sequence as follows:

The score is the sum of d_i over all indices i such that A_{b_i} - A_{a_i} = c_i. (If there is no such i, the score is 0.)

Find the maximum possible score of A.

Constraints

All values in input are integers.

2 ≤ N ≤ 10

1 \leq M \leq 10

1 \leq Q \leq 50

1 \leq a_i < b_i \leq N ( i = 1, 2, ..., Q )

0 \leq c_i \leq M - 1 ( i = 1, 2, ..., Q )

(a_i, b_i, c_i) \neq (a_j, b_j, c_j) (where i \neq j)

1 \leq d_i \leq 10^5 ( i = 1, 2, ..., Q )

Input

Input is given from Standard Input in the following format:

N M Q
a_1 b_1 c_1 d_1
:
a_Q b_Q c_Q d_Q

Output

Print the maximum possible score of A.

Sample Input 1

3 4 3
1 3 3 100
1 2 2 10
2 3 2 10

Sample Output 1

110

When A = \{1, 3, 4\}, its score is 110. Under these conditions, no sequence has a score greater than 110, so the answer is 110.

Sample Input 2

4 6 10
2 4 1 86568
1 4 0 90629
2 3 0 90310
3 4 1 29211
3 4 3 78537
3 4 2 8580
1 2 1 96263
1 4 2 2156
1 2 0 94325
1 4 3 94328

Sample Output 2

357500

Sample Input 3

10 10 1
1 10 9 1

Sample Output 3

1

Solution in Rust (1.42.0) (judge verdict: Accepted)

#[warn(unused_imports)]
use proconio::{
   fastout, input,
   marker::Usize1
};
use std::cmp::max;

#[fastout]
fn main() {
   input! {
      n: usize, m:usize, q:usize,
      mut abcd: [(Usize1, Usize1, usize, usize); q]
   }
   let mut ans = 0;
   dfs(1, &mut Vec::new(), n, m, &abcd, &mut ans);
   println!("{}", ans);
}

fn dfs(i:usize, ax:&mut Vec<usize>, n:usize, m:usize, abcd: &[(usize, usize, usize, usize)], ans: &mut usize) {
   ax.push(i);
   if ax.len() == n {
      let mut x = 0;
      for (a, b, c, d) in abcd.iter() {
         if ax[*b] - ax[*a] == *c {
            x += d;
         }
         if x > *ans {
            *ans = x;
         }
      }
   } else {
      for j in i..=m {
         dfs(j, ax, n, m, abcd, ans);
      }
   }
   ax.pop();
}