Problem:
Score : 500 points

Problem Statement

Takahashi has decided to work on K days of his choice from the N days starting with tomorrow.

You are given an integer C and a string S. Takahashi will choose his workdays as follows:

After working for a day, he will refrain from working on the subsequent C days.

If the i-th character of S is x, he will not work on Day i, where Day 1 is tomorrow, Day 2 is the day after tomorrow, and so on.

Find all days on which Takahashi is bound to work.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq K \leq N

0 \leq C \leq N

The length of S is N.

Each character of S is o or x.

Takahashi can choose his workdays so that the conditions in Problem Statement are satisfied.

Input

Input is given from Standard Input in the following format:

N K C
S

Output

Print all days on which Takahashi is bound to work in ascending order, one per line.

Sample Input 1

11 3 2
ooxxxoxxxoo

Sample Output 1

6

Takahashi is going to work on 3 days out of the 11 days. After working for a day, he will refrain from working on the subsequent 2 days.

There are four possible choices for his workdays: Day 1,6,10, Day 1,6,11, Day 2,6,10, and Day 2,6,11.

Thus, he is bound to work on Day 6.

Sample Input 2

5 2 3
ooxoo

Sample Output 2

1
5

There is only one possible choice for his workdays: Day 1,5.

Sample Input 3

5 1 0
ooooo

Sample Output 3

There may be no days on which he is bound to work.

Sample Input 4

16 4 3
ooxxoxoxxxoxoxxo

Sample Output 4

11
16

Solution in Rust (1.15.1) (judge verdict: Accepted)

pub struct Scanner{
    line : Vec<String> ,
    idx : usize
}

#[allow(dead_code)]
impl  Scanner{
   fn new() -> Scanner{
       return Scanner{ line: vec![], idx : 0}
   }
   fn next<T: std::str::FromStr> (&mut self) -> T{
       if self.idx == self.line.len() {
           let mut buffer = String::new();
           std::io::stdin().read_line(&mut buffer).ok();

           let a : Vec<&str>  = buffer.trim().split(' ').collect();
           self.line = a.iter().map(|&s| String::from(s)).collect();
           self.idx = 0;
       }
       let ret : T = self.line[self.idx].parse::<T>().ok().expect("Parse error.");
       self.idx += 1;
       ret
   }
   fn next_string(&mut self) -> Vec<char> {
       let s : String = self.next();
       return s.chars().collect::<Vec<char>>();
   }
   fn next_vec<T: std::str::FromStr>  (&mut self, n: usize) -> Vec<T>{
       let mut v : Vec<T>= Vec::with_capacity(n);
       for _i in 0..n {
           v.push(self.next());
       }
       v
   }
}


fn main() {
    let mut scan = Scanner::new();
    let _n:i64  = scan.next();
    let k:i64  = scan.next();
    let c:i64  = scan.next();
    let s = scan.next_string();

    let mut a :Vec<i32> = Vec::with_capacity(k as usize);
    let mut b: Vec<i32> = Vec::with_capacity(k as usize);
    let mut sleep = 0;

    for day in 0..s.len(){
        if sleep > 0{
            sleep -= 1;
            continue;
        }
        if s[day] == 'o'{
            a.push(day as i32);
            sleep = c;
        }
        if a.len() == k as usize{
            break;
        }
    }
    sleep = 0;
    for day in (0..s.len()).rev() {
        if sleep > 0{
            sleep -= 1;
            continue;
        }
        if s[day] == 'o'{
            b.push(day as i32);
            sleep = c;
        }
        if b.len() == k as usize{
            break;
        }
    }
    b.reverse();

    for i in 0..k{
        let idx = i as usize;
        if a[idx] == b[idx] {
            println!("{}", a[idx] + 1);
        }
    }
}