Problem:
Score : 200 points

Problem Statement

Let S(n) denote the sum of the digits in the decimal notation of n.
For example, S(101) = 1 + 0 + 1 = 2.

Given an integer N, determine if S(N) divides N.

Constraints

1 \leq N \leq 10^9

Input

Input is given from Standard Input in the following format:

N

Output

If S(N) divides N, print Yes; if it does not, print No.

Sample Input 1

12

Sample Output 1

Yes

In this input, N=12.
As S(12) = 1 + 2 = 3, S(N) divides N.

Sample Input 2

101

Sample Output 2

No

As S(101) = 1 + 0 + 1 = 2, S(N) does not divide N.

Sample Input 3

999999999

Sample Output 3

Yes

Solution in Rust (1.15.1) (judge verdict: Wrong Answer)

use std::io::Read;

fn main() {
    let mut buff = String::new();
    std::io::stdin().read_to_string(&mut buff).unwrap();
    let mut iter = buff.split_whitespace();

    let n: i32 = iter.next().unwrap().parse().unwrap();

    let mut sum: i32 = 0;
    let mut m: i32 = n;

    while m != 0 {
        sum += m % 10;
        m /= 10;
    }

    if sum % n == 0 {
        println!("Yes");
    } else {
        println!("No");
    }

    ()
}