Problem:
Score : 300 points

Problem Statement

Takahashi made N problems for competitive programming.
The problems are numbered 1 to N, and the difficulty of Problem i is represented as an integer d_i (the higher, the harder).

He is dividing the problems into two categories by choosing an integer K, as follows:

A problem with difficulty K or higher will be for ARCs.

A problem with difficulty lower than K will be for ABCs.

How many choices of the integer K make the number of problems for ARCs and the number of problems for ABCs the same?

Problem Statement

2 \leq N \leq 10^5

N is an even number.

1 \leq d_i \leq 10^5

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
d_1 d_2 ... d_N

Output

Print the number of choices of the integer K that make the number of problems for ARCs and the number of problems for ABCs the same.

Sample Input 1

6
9 1 4 4 6 7

Sample Output 1

2

If we choose K=5 or 6, Problem 1, 5, and 6 will be for ARCs, Problem 2, 3, and 4 will be for ABCs, and the objective is achieved.
Thus, the answer is 2.

Sample Input 2

8
9 1 14 5 5 4 4 14

Sample Output 2

0

There may be no choice of the integer K that make the number of problems for ARCs and the number of problems for ABCs the same.

Sample Input 3

14
99592 10342 29105 78532 83018 11639 92015 77204 30914 21912 34519 80835 100000 1

Sample Output 3

42685

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::io::*;
use std::str::FromStr;

#[allow(unused_macros)]
macro_rules! scan {
  ($e:expr; $t:ty) => {
    $e.get::<$t>()
  };
  ($e:expr; $($t:ty), *) => {
    ($($e.get::<$t>(),)*)
  };
  ($e:expr => $i:expr; $t:ty) => {
    (0..$i).map(|_| $e.get::<$t>()).collect::<Vec<$t>>()
  };
  ($e:expr => $row:expr, $col:expr; $t:ty) => {
    (0..$i).map(|_| scan!($e => $col; $t)).collect::<Vec<$t>>()
  }
}

struct Scanner<R: Read> {
  reader: R
}

#[allow(dead_code)]
impl<R: Read> Scanner<R> {
  fn new(reader: R) -> Scanner<R> {
    Scanner { reader: reader }
  }
  fn safe_get<T: FromStr>(&mut self) -> Option<T> {
    let token = self.reader.by_ref().bytes().map(|c| c.unwrap() as char)
      .skip_while(|c| c.is_whitespace())
      .take_while(|c| !c.is_whitespace())
      .collect::<String>();
    if token.is_empty() { None } else { token.parse().ok() }
  }
  fn get<T: FromStr>(&mut self) -> T {
    if let Some(v) = self.safe_get() { v } else {
      writeln!(stderr(), "Terminated with EOF").unwrap();
      std::process::exit(0);
    }
  }
}

trait Writable {
  fn write(&self, sep: &'static str) -> String;
}

impl<T: ToString> Writable for Vec<T> {
  fn write(&self, sep: &'static str) -> String {
    self.iter().map(|e| e.to_string()).collect::<Vec<String>>().join(sep)
  }
}

fn main() {
  let cin = stdin();
  let cin = cin.lock();
  let mut sc = Scanner::new(cin);
  let n = scan!(sc; i32);
  let mut d = scan!(sc => n; i32);
  d.sort();

  let mut k = 0;
  let mut abc = 0;
  let mut idx = 0;
  let mut ans = 0;
  let &k_max = d.iter().last().unwrap();
  loop {
    if k > k_max { break; }
    while idx != d.len() {
      if d[idx] < k {
        abc += 1;
        idx += 1;
      }
      else {
        break;
      }
    }

    if n / 2 == abc { ans += 1; }
    k += 1;
  }
  println!("{}", ans);
}