Problem:
Score : 400 points

Problem Statement

There are two persons, numbered 0 and 1, and a variable x whose initial value is 0.
The two persons now play a game.
The game is played in N rounds. The following should be done in the i-th round (1 \leq i \leq N):

Person S_i does one of the following:

Replace x with x \oplus A_i, where \oplus represents bitwise XOR.

Do nothing.

Person 0 aims to have x=0 at the end of the game, while Person 1 aims to have x \neq 0 at the end of the game.

Determine whether x becomes 0 at the end of the game when the two persons play optimally.

Solve T test cases for each input file.

Constraints

1 \leq T \leq 100

1 \leq N \leq 200

1 \leq A_i \leq 10^{18}

S is a string of length N consisting of 0 and 1.

All numbers in input are integers.

Input

Input is given from Standard Input in the following format.
The first line is as follows:

T

Then, T test cases follow.
Each test case is given in the following format:

N
A_1 A_2 \cdots A_N
S

Output

For each test case, print a line containing 0 if x becomes 0 at the end of the game, and 1 otherwise.

Sample Input 1

3
2
1 2
10
2
1 1
10
6
2 3 4 5 6 7
111000

Sample Output 1

1
0
0

In the first test case, if Person 1 replaces x with 0 \oplus 1=1, we surely have x \neq 0 at the end of the game, regardless of the choice of Person 0.

In the second test case, regardless of the choice of Person 1, Person 0 can make x=0 with a suitable choice.

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

fn get_line() -> String {
    let mut line = String::new();
    std::io::stdin().read_line(&mut line).unwrap();
    line.trim().to_string()
}

fn main() {
    let t: usize = get_line().parse().unwrap();
    let mut result: Vec<usize> = Vec::new();
    for i in 0..t {
        let n: usize = get_line().parse().unwrap();
        let aas: Vec<usize> = get_line()
            .split_whitespace()
            .map(|e| e.parse().unwrap())
            .collect();

        let mut x = 0;

        let s = get_line();
        for (c, a) in s.chars().zip(aas) {
            if c == '0' {
                if x ^ a == 0 {
                    x ^= a;
                }
            } else {
                if x ^ a != 0 {
                    x ^= a;
                }
            }
        }
        if x == 0 {
            result.push(0);
        } else {
            result.push(1);
        }
    }

    for x in &result {
        println!("{}", x);
    }
}