Problem:
Score : 300 points

Problem Statement

Find the price of a product before tax such that, when the consumption tax rate is 8 percent and 10 percent, the amount of consumption tax levied on it is A yen and B yen, respectively. (Yen is the currency of Japan.)

Here, the price before tax must be a positive integer, and the amount of consumption tax is rounded down to the nearest integer.

If multiple prices satisfy the condition, print the lowest such price; if no price satisfies the condition, print -1.

Constraints

1 \leq A \leq B \leq 100

A and B are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

If there is a price that satisfies the condition, print an integer representing the lowest such price; otherwise, print -1.

Sample Input 1

2 2

Sample Output 1

25

If the price of a product before tax is 25 yen, the amount of consumption tax levied on it is:

When the consumption tax rate is 8 percent: \lfloor 25 \times 0.08 \rfloor = \lfloor 2 \rfloor = 2 yen.

When the consumption tax rate is 10 percent: \lfloor 25 \times 0.1 \rfloor = \lfloor 2.5 \rfloor = 2 yen.

Thus, the price of 25 yen satisfies the condition. There are other possible prices, such as 26 yen, but print the minimum such price, 25.

Sample Input 2

8 10

Sample Output 2

100

If the price of a product before tax is 100 yen, the amount of consumption tax levied on it is:

When the consumption tax rate is 8 percent: \lfloor 100 \times 0.08 \rfloor = 8 yen.

When the consumption tax rate is 10 percent: \lfloor 100 \times 0.1 \rfloor = 10 yen.

Sample Input 3

19 99

Sample Output 3

-1

There is no price before tax satisfying this condition, so print -1.

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

use proconio::{fastout, input};

#[fastout]
fn main() {
    input! {a: u32, b: u32};

    let mut a_p: u32 = (a * 100) / 8;
    let mut b_p: u32 = b * 10;

    // println!("{},{}", a_p, b_p);
    // println!("{}", a_p * 8 / 100);
    // println!("{}", a_p / 10);
    // println!("{}", b_p * 8 / 100);
    // println!("{}", b_p / 10);

    if a_p * 8 / 100 == a && a_p / 10 == b {
        while true {
            if (a_p - 1) * 8 / 100 == a && (a_p - 1) / 10 == b {
                a_p -= 1;
            } else {
                break;
            }
        }
        println!("{}", a_p);
    } else if b_p * 8 / 100 == a && b_p / 10 == b {
        while true {
            if (b_p - 1) * 8 / 100 == a && (b_p - 1) / 10 == b {
                b_p -= 1;
            } else {
                break;
            }
        }
        println!("{}", b_p);
    } else {
        println!("-1")
    }
}