Problem:
Score : 100 points

Problem Statement

We have weather records at AtCoder Town for some consecutive three days. A string of length 3, S, represents the records - if the i-th character is S, it means it was sunny on the i-th day; if that character is R, it means it was rainy on that day.

Find the maximum number of consecutive rainy days in this period.

Constraints

|S| = 3

Each character of S is S or R.

Input

Input is given from Standard Input in the following format:

S

Output

Print the maximum number of consecutive rainy days in the period.

Sample Input 1

RRS

Sample Output 1

2

We had rain on the 1-st and 2-nd days in the period. Here, the maximum number of consecutive rainy days is 2, so we should print 2.

Sample Input 2

SSS

Sample Output 2

0

It was sunny throughout the period. We had no rainy days, so we should print 0.

Sample Input 3

RSR

Sample Output 3

1

We had rain on the 1-st and 3-rd days - two "streaks" of one rainy day, so we should print 1.

Solution in Rust (1.42.0) (judge verdict: Runtime Error)

use proconio::input;
#[allow(unused_imports)]
use proconio::marker::{Bytes, Chars};
#[allow(unused_imports)]
use std::cmp::{min, max};
 
fn main() {
	input! {
		x: i128,
		k: i128,
		d: i128,
	}
 
	let xabs = x.abs();
	let s = xabs / d;
	if s >= k {
		if 0 < x {
			println!("{}", x - k * d);
			return;
		}
		else {
			println!("{}", (x + k * d).abs());
			return;
		}
	}
 
	let tx;
	let tk;
	if 0 < x {
		tx = x - s * d;
		tk = k - s;
		if tk % 2 == 0 {
			println!("{}", tx);
			return;
		}
		else {
			println!("{}", (tx - d).abs());
			return;
		}
	}
	else {
		tx = x + s * d;
		tk = k - s;
		if tk % 2 == 0 {
			println!("{}", tx.abs());
			return;
		}
		else {
			println!("{}", tx + d);
			return;
		}
	}
}