Problem:
Score : 300 points

Problem Statement

You are given two integer sequences of length N: a_1,a_2,..,a_N and b_1,b_2,..,b_N.
Determine if we can repeat the following operation zero or more times so that the sequences a and b become equal.

Operation: Choose two integers i and j (possibly the same) between 1 and N (inclusive), then perform the following two actions simultaneously:

Add 2 to a_i.

Add 1 to b_j.

Constraints

1 ≤ N ≤ 10 000

0 ≤ a_i,b_i ≤ 10^9 (1 ≤ i ≤ N)

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 .. a_N
b_1 b_2 .. b_N

Output

If we can repeat the operation zero or more times so that the sequences a and b become equal, print Yes; otherwise, print No.

Sample Input 1

3
1 2 3
5 2 2

Sample Output 1

Yes

For example, we can perform three operations as follows to do our job:

First operation: i=1 and j=2. Now we have a = \{3,2,3\}, b = \{5,3,2\}.

Second operation: i=1 and j=2. Now we have a = \{5,2,3\}, b = \{5,4,2\}.

Third operation: i=2 and j=3. Now we have a = \{5,4,3\}, b = \{5,4,3\}.

Sample Input 2

5
3 1 4 1 5
2 7 1 8 2

Sample Output 2

No

Sample Input 3

5
2 7 1 8 2
3 1 4 1 5

Sample Output 3

No

Solution in Rust (1.15.1) (judge verdict: Wrong Answer)

use std::io::*; //Not mine.
use std::str::FromStr;
fn read<T: FromStr>() -> T {
    let stdin = stdin();
    let stdin = stdin.lock();
    let token: String = stdin
        .bytes()
        .map(|c| c.expect("failed to read char") as char)
        .skip_while(|c| c.is_whitespace())
        .take_while(|c| !c.is_whitespace())
        .collect();
    token.parse().ok().expect("failed to parse token")
}
fn main() {
    let n: i64 = read();
    let a: Vec<i64> = (0..n).map(|_| read()).collect();
    let b: Vec<i64> = (0..n).map(|_| read()).collect();
    let mut a_odd = 0;
    let mut sum_a:i64 = 0;
    let mut sum_b:i64 = 0;
    let mut b_even = 0;
    for (i, &_itr) in a.iter().enumerate() {
        if _itr % 2 != 0 {
            a_odd += 1;
            sum_a += _itr;
        }
    }
    for (i, &_itr) in b.iter().enumerate() {
        if _itr % 2 == 0 {
            b_even += 1;
            sum_b += _itr;
        }
    }
    println!("{}", if a_odd == b_even && sum_a < sum_b || a_odd == n - b_even && sum_a == sum_b { "Yes" } else { "No" });
}