Problem:
Score : 300 points

Problem Statement

A company has N members, who are assigned ID numbers 1, ..., N.

Every member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.

When a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.

You are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq A_i < i

Input

Input is given from Standard Input in the following format:

N
A_2 ... A_N

Output

For each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.

Sample Input 1

5
1 1 2 2

Sample Output 1

2
2
0
0
0

The member numbered 1 has two immediate subordinates: the members numbered 2 and 3.

The member numbered 2 has two immediate subordinates: the members numbered 4 and 5.

The members numbered 3, 4, and 5 do not have immediate subordinates.

Sample Input 2

10
1 1 1 1 1 1 1 1 1

Sample Output 2

9
0
0
0
0
0
0
0
0
0

Sample Input 3

7
1 2 3 4 5 6

Sample Output 3

1
1
1
1
1
1
0

Solution in Rust (1.42.0) (judge verdict: Accepted)

use im_rc::HashMap;
use input::*;
use std::cmp::*;
use std::io::*;
use std::num::*;
use std::str::*;

mod input {
    use super::*;
    pub fn read<T: FromStr>() -> T {
        stdin()
            .bytes()
            .map(|c| c.unwrap() as char)
            .skip_while(|c| c.is_whitespace())
            .take_while(|c| !c.is_whitespace())
            .collect::<String>()
            .parse::<T>()
            .ok()
            .unwrap()
    }
    pub fn string() -> String {
        read()
    }
    pub fn int() -> i64 {
        read()
    }
    pub fn char() -> char {
        read::<String>().pop().unwrap()
    }
    pub fn vecchar() -> Vec<char> {
        string().chars().collect()
    }
    pub fn vecint(n: i64) -> Vec<i64> {
        let mut vec = Vec::new();
        for i in 0..n {
            vec.push(int())
        }
        vec
    }
}
fn main() {
    let n = int();
    let a = vecint(n - 1);
    let mut v = HashMap::new();
    for i in 0..a.len() {
        if !v.contains_key(&a[i]) {
            v.insert(a[i], 0);
        }
        v[&a[i]] += 1;
    }
    for i in 1..=n {
        println!("{}", v.get(&i).unwrap_or(&0))
    }
}