Problem:
Score : 200 points

Problem Statement

There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is R, and a blue hat if s_i is B.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

1 \leq N \leq 100

|s| = N

s_i is R or B.

Input

Input is given from Standard Input in the following format:

N
s

Output

If there are more people wearing a red hat than there are people wearing a blue hat, print Yes; otherwise, print No.

Sample Input 1

4
RRBR

Sample Output 1

Yes

There are three people wearing a red hat, and one person wearing a blue hat.

Since there are more people wearing a red hat than people wearing a blue hat, the answer is Yes.

Sample Input 2

4
BRBR

Sample Output 2

No

There are two people wearing a red hat, and two people wearing a blue hat.

Since there are as many people wearing a red hat as people wearing a blue hat, the answer is No.

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::io::{BufRead, BufWriter, Write};

fn main() {
    let stdin = std::io::stdin();
    let stdout = std::io::stdout();
    solve(&mut stdin.lock(), &mut BufWriter::new(stdout.lock()));
}

fn solve<R: BufRead, W: Write>(stdin: &mut R, stdout: &mut BufWriter<W>) {
    let n = stdin.gets().parse::<usize>().unwrap();
    let s = stdin.gets();
    let red = s.chars().filter(|&c| c == 'R').count();
    let ans = if red * 2 > n { "Yes" } else { "No" };
    writeln!(stdout, "{}", ans).unwrap();
}

trait Gets { fn gets(&mut self) -> String; }
impl<T: std::io::BufRead> Gets for T {
    fn gets(&mut self) -> String { self.lines().next().unwrap().unwrap() } }