Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in Rust (1.42.0) (judge verdict: Accepted)

use std::io::*;

fn main() {
    let mut s: String = String::new();
    std::io::stdin().read_to_string(&mut s).ok();
    let mut itr = s.trim().split_whitespace();
    let n: usize = itr.next().unwrap().parse().unwrap();
    let a: usize = itr.next().unwrap().parse().unwrap();
    let b: usize = itr.next().unwrap().parse().unwrap();
    let c: usize = itr.next().unwrap().parse().unwrap();
    let s: Vec<&str> = (0..n).map(|_| itr.next().unwrap()).collect();

    let mut now = (a, b, c);
    let mut ans = Vec::new();
    for i in 0..n {
        if s[i] == "AB" {
            if now.0 == 0 && now.1 == 0 {
                println!("No",);
                return;
            } else if now.0 == 0 {
                now.0 += 1;
                now.1 -= 1;
                ans.push('A');
            } else if now.1 == 0 {
                now.0 -= 1;
                now.1 += 1;
                ans.push('B');
            } else {
                if i != n - 1 && s[i + 1] == "BC" {
                    now.0 -= 1;
                    now.1 += 1;
                    ans.push('B');
                } else {
                    now.0 += 1;
                    now.1 -= 1;
                    ans.push('A');
                }
            }
        } else if s[i] == "BC" {
            if now.2 == 0 && now.1 == 0 {
                println!("No",);
                return;
            } else if now.2 == 0 {
                now.2 += 1;
                now.1 -= 1;
                ans.push('C');
            } else if now.1 == 0 {
                now.2 -= 1;
                now.1 += 1;
                ans.push('B');
            } else {
                if i != n - 1 && s[i + 1] == "AB" {
                    now.2 -= 1;
                    now.1 += 1;
                    ans.push('B');
                } else {
                    now.2 += 1;
                    now.1 -= 1;
                    ans.push('C');
                }
            }
        } else {
            if now.0 == 0 && now.2 == 0 {
                println!("No",);
                return;
            } else if now.0 == 0 {
                now.0 += 1;
                now.2 -= 1;
                ans.push('A');
            } else if now.2 == 0 {
                now.0 -= 1;
                now.2 += 1;
                ans.push('C');
            } else {
                if i != n - 1 && s[i + 1] == "BC" {
                    now.0 -= 1;
                    now.2 += 1;
                    ans.push('C');
                } else {
                    now.0 += 1;
                    now.2 -= 1;
                    ans.push('A');
                }
            }
        }
    }

    let mut out = Vec::new();
    writeln!(out, "Yes").ok();
    for i in 0..n {
        writeln!(out, "{}", ans[i]).ok();
    }
    stdout().write_all(&out).unwrap();
}