Problem:
Score : 100 points

Problem Statement

X and A are integers between 0 and 9 (inclusive).

If X is less than A, print 0; if X is not less than A, print 10.

Constraints

0 \leq X, A \leq 9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X A

Output

If X is less than A, print 0; if X is not less than A, print 10.

Sample Input 1

3 5

Sample Output 1

0

3 is less than 5, so we should print 0.

Sample Input 2

7 5

Sample Output 2

10

7 is not less than 5, so we should print 10.

Sample Input 3

6 6

Sample Output 3

10

6 is not less than 6, so we should print 10.

Solution in Rust (1.15.1) (judge verdict: Wrong Answer)

fn main() {
    let s = {
        let mut s = String::new(); // バッファを確保
        std::io::stdin().read_line(&mut s).unwrap(); // 一行読む。失敗を無視
        s.trim_right().to_owned() // 改行コードが末尾にくっついてくるので削る
    };
    let (x, a) = {
        let mut ws = s.split_whitespace(); // 空白区切りの単語に分解する
        let n: i32 = ws.next().unwrap().parse().unwrap(); // イテレータから値を取り出して整数に
        let m: i32 = ws.next().unwrap().parse().unwrap();
        (n, m)
    };
    if x > a {
        println!("10");
    } else {
        println!("0");
    }
}