Problem:
Score : 300 points

Problem Statement

Find the maximum possible sum of the digits (in base 10) of a positive integer not greater than N.

Constraints

1\leq N \leq 10^{16}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print the maximum possible sum of the digits (in base 10) of a positive integer not greater than N.

Sample Input 1

100

Sample Output 1

18

For example, the sum of the digits in 99 is 18, which turns out to be the maximum value.

Sample Input 2

9995

Sample Output 2

35

For example, the sum of the digits in 9989 is 35, which turns out to be the maximum value.

Sample Input 3

3141592653589793

Sample Output 3

137

Solution in Rust (1.15.1) (judge verdict: Accepted)

#[allow(unused_imports)]
use std::io::{stdin, Read, StdinLock};
#[allow(unused_imports)]
use std::cmp::{max, min, Ordering};
#[allow(unused_imports)]
use std::str::FromStr;
#[allow(unused_imports)]
use std::collections::{HashSet, HashMap, BinaryHeap, VecDeque};
#[allow(unused_imports)]
use std::vec::Vec;

#[allow(dead_code)]
const INF: i32 = 1000_000_000;
#[allow(dead_code)]
const INFLL: i64 = 1000_000_000_000_000_000;
#[allow(dead_code)]
const EPS: f64 = 1.0e-10;
#[allow(dead_code)]
const MOD: i32 = 1000_000_007;
#[allow(dead_code)]
const MODLL: i64 = 1000_000_007;

struct Scanner<'a> {
    cin: StdinLock<'a>,
}

#[allow(dead_code)]
impl<'a> Scanner<'a> {
    fn new(cin: StdinLock<'a>) -> Scanner<'a> {
        Scanner {cin: cin}
    }
    fn read1<T: FromStr>(&mut self) -> Option<T> {
        let token = self.cin.by_ref().bytes().map(|c| c.unwrap() as char)
                    .skip_while(|c| c.is_whitespace())
                    .take_while(|c| !c.is_whitespace())
                    .collect::<String>();
        token.parse::<T>().ok()
    }
    fn read<T: FromStr>(&mut self) -> T {
        self.read1().unwrap()
    }
}

fn main() {
    let cin = stdin();
    let cin = cin.lock();
    let mut sc = Scanner::new(cin);

    let n: String = sc.read();
    let n: Vec<char> = n.chars().collect();
    let ans1 = n.iter().fold(0, |sum, c| sum + c.to_digit(10).unwrap());
    let ans2 = n[0].to_digit(10).unwrap() - 1 + 9 * (n.len() - 1) as u32;
    println!("{}", max(ans1, ans2));
}