Problem:
Score : 600 points

Problem Statement

Given are a sequence of N positive integers A_1, A_2, \ldots, A_N and another positive integer S.

For a non-empty subset T of the set \{1, 2, \ldots , N \}, let us define f(T) as follows:

f(T) is the number of different non-empty subsets \{x_1, x_2, \ldots , x_k \} of T such that A_{x_1}+A_{x_2}+\cdots +A_{x_k} = S.

Find the sum of f(T) over all 2^N-1 subsets T of \{1, 2, \ldots , N \}. Since the sum can be enormous, print it modulo 998244353.

Constraints

All values in input are integers.

1 \leq N \leq 3000

1 \leq S \leq 3000

1 \leq A_i \leq 3000

Input

Input is given from Standard Input in the following format:

N S
A_1 A_2 ... A_N

Output

Print the sum of f(T) modulo 998244353.

Sample Input 1

3 4
2 2 4

Sample Output 1

6

For each T, the value of f(T) is shown below. The sum of these values is 6.

f(\{1\}) = 0

f(\{2\}) = 0

f(\{3\}) = 1 (One subset \{3\} satisfies the condition.)

f(\{1, 2\}) = 1 (\{1, 2\})

f(\{2, 3\}) = 1 (\{3\})

f(\{1, 3\}) = 1 (\{3\})

f(\{1, 2, 3\}) = 2 (\{1, 2\}, \{3\})

Sample Input 2

5 8
9 9 9 9 9

Sample Output 2

0

Sample Input 3

10 10
3 1 4 1 5 9 2 6 5 3

Sample Output 3

3296

Solution in Rust (1.42.0) (judge verdict: Accepted)

use std::io::Read;


fn input() -> (usize,usize,Vec<i32>) {
    let mut buf = String::new();
    std::io::stdin().read_to_string(&mut buf).unwrap();
    let mut iter = buf.split_whitespace();
    
    let n:usize = iter.next().unwrap().parse().unwrap();
    let s:usize = iter.next().unwrap().parse().unwrap();
    let a = (0..n).map(|_|{
            iter.next().unwrap().parse().unwrap()
        }).collect();
    (n,s,a)
}

const MOD: i64 = 998244353;

fn main() {
    
    let (n,s,a) = input();
    let mut dp = vec![vec![0;s+1];n+1];
    dp[0][0] = 1;
    for i in 0..n {
        for j in 0..(s+1) {
            dp[i+1][j] = (dp[i+1][j]+dp[i][j]*2)%MOD;
            let added = j + (a[i] as usize);
            if added<=s {
                dp[i+1][added] = (dp[i+1][added]+dp[i][j])%MOD;
            }
        }
    }

    println!("{}",dp[n][s]);

}