Problem:
Score : 200 points

Problem Statement

Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.

The problem has N test cases.

For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is AC, WA, TLE, and RE, respectively.

See the Output section for the output format.

Constraints

1 \leq N \leq 10^5

S_i is AC, WA, TLE, or RE.

Input

Input is given from Standard Input in the following format:

N
S_1
\vdots
S_N

Output

Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is AC, WA, TLE, and RE, respectively. Print the following:

AC x C_0
WA x C_1
TLE x C_2
RE x C_3

Sample Input 1

6
AC
TLE
AC
AC
WA
TLE

Sample Output 1

AC x 3
WA x 1
TLE x 2
RE x 0

We have 3, 1, 2, and 0 test case(s) for which the verdict is AC, WA, TLE, and RE, respectively.

Sample Input 2

10
AC
AC
AC
AC
AC
AC
AC
AC
AC
AC

Sample Output 2

AC x 10
WA x 0
TLE x 0
RE x 0

Solution in Rust (1.42.0) (judge verdict: Accepted)

use io::*;
use std::*;

fn solve(N: i64, S: Vec<String>) {
    let m = S.iter().fold(collections::HashMap::new(), |mut acc, x| {
        *acc.entry(x).or_insert(0) += 1;
        acc
    });
    let acCount = match m.get(&"AC".to_string()) {
        Some(&count) => count,
        _ => 0,
    };
    let waCount = match m.get(&"WA".to_string()) {
        Some(&count) => count,
        _ => 0,
    };
    let tleCount = match m.get(&"TLE".to_string()) {
        Some(&count) => count,
        _ => 0,
    };
    let reCount = match m.get(&"RE".to_string()) {
        Some(&count) => count,
        _ => 0,
    };
    println!("AC x {}", acCount);
    println!("WA x {}", waCount);
    println!("TLE x {}", tleCount);
    println!("RE x {}", reCount);
}

// Generated by 1.1.7.1 https://github.com/kyuridenamida/atcoder-tools  (tips: You use the default template now. You can remove this line by using your custom template)
fn main() {
    let con = read_string();
    let mut scanner = Scanner::new(&con);
    let mut N: i64;
    N = scanner.next();
    let mut S: Vec<String> = vec![String::new(); (N) as usize];
    for i in 0..(N) as usize {
        S[i] = scanner.next();
    }
    // In order to avoid potential stack overflow, spawn a new thread.
    let stack_size = 104_857_600; // 100 MB
    let thd = std::thread::Builder::new().stack_size(stack_size);
    thd.spawn(move || solve(N, S)).unwrap().join().unwrap();
}

pub mod io {
    use std;
    use std::str::FromStr;

    pub struct Scanner<'a> {
        iter: std::str::SplitWhitespace<'a>,
    }

    impl<'a> Scanner<'a> {
        pub fn new(s: &'a str) -> Scanner<'a> {
            Scanner {
                iter: s.split_whitespace(),
            }
        }

        pub fn next<T: FromStr>(&mut self) -> T {
            let s = self.iter.next().unwrap();
            if let Ok(v) = s.parse::<T>() {
                v
            } else {
                panic!("Parse error")
            }
        }

        pub fn next_vec_len<T: FromStr>(&mut self) -> Vec<T> {
            let n: usize = self.next();
            self.next_vec(n)
        }

        pub fn next_vec<T: FromStr>(&mut self, n: usize) -> Vec<T> {
            (0..n).map(|_| self.next()).collect()
        }
    }

    pub fn read_string() -> String {
        use std::io::Read;

        let mut s = String::new();
        std::io::stdin().read_to_string(&mut s).unwrap();
        s
    }

    pub fn read_line() -> String {
        let mut s = String::new();
        std::io::stdin().read_line(&mut s).unwrap();
        s.trim_right().to_owned()
    }
}