Problem:
Score : 200 points

Problem Statement

We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.

Shift each character of S by N in alphabetical order (see below), and print the resulting string.

We assume that A follows Z. For example, shifting A by 2 results in C (A \to B \to C), and shifting Y by 3 results in B (Y \to Z \to A \to B).

Constraints

0 \leq N \leq 26

1 \leq |S| \leq 10^4

S consists of uppercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the string resulting from shifting each character of S by N in alphabetical order.

Sample Input 1

2
ABCXYZ

Sample Output 1

CDEZAB

Note that A follows Z.

Sample Input 2

0
ABCXYZ

Sample Output 2

ABCXYZ

Sample Input 3

13
ABCDEFGHIJKLMNOPQRSTUVWXYZ

Sample Output 3

NOPQRSTUVWXYZABCDEFGHIJKLM

Solution in Rust (1.42.0) (judge verdict: Accepted)

use text_io::*;
use std::process::exit;
use im_rc::*;
use std::cmp::*;

fn main(){
    let mut n:usize = read!();
    let mut a:String = read!();
    let mut v:Vec<char> = a.chars().collect();
    let mut a:usize = 0;
    let mut b:usize = 0;
    let al:[char;26] = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'];
    for i in 0..v.len() {
        while a==0{
            if v[i]==al[b] {
                v[i]=al[(b+n)%26];
                a+=1;
            }
            b+=1;
        }
        a = 0;
        b = 0;
    }
    let s:String = v.iter().collect();
    println!("{}",s);
}