Problem:
Score : 600 points

Problem Statement

We have a tree with N vertices numbered 1 to N. The i-th edge in this tree connects Vertex a_i and b_i.
For each k=1, ..., N, solve the problem below:

Consider writing a number on each vertex in the tree in the following manner:

First, write 1 on Vertex k.

Then, for each of the numbers 2, ..., N in this order, write the number on the vertex chosen as follows:

Choose a vertex that still does not have a number written on it and is adjacent to a vertex with a number already written on it. If there are multiple such vertices, choose one of them at random.

Find the number of ways in which we can write the numbers on the vertices, modulo (10^9+7).

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq a_i,b_i \leq N

The given graph is a tree.

Input

Input is given from Standard Input in the following format:

N
a_1 b_1
:
a_{N-1} b_{N-1}

Output

For each k=1, 2, ..., N in this order, print a line containing the answer to the problem.

Sample Input 1

3
1 2
1 3

Sample Output 1

2
1
1

The graph in this input is as follows:

For k=1, there are two ways in which we can write the numbers on the vertices, as follows:

Writing 1, 2, 3 on Vertex 1, 2, 3, respectively

Writing 1, 3, 2 on Vertex 1, 2, 3, respectively

Sample Input 2

2
1 2

Sample Output 2

1
1

The graph in this input is as follows:

Sample Input 3

5
1 2
2 3
3 4
3 5

Sample Output 3

2
8
12
3
3

The graph in this input is as follows:

Sample Input 4

8
1 2
2 3
3 4
3 5
3 6
6 7
6 8

Sample Output 4

40
280
840
120
120
504
72
72

The graph in this input is as follows:

Solution in Rust (1.15.1) (judge verdict: Accepted)

//! ----------------------------------------------
//! Framework <https://github.com/vain0x/procon>
//!
//! See the bottom of file for solution.
//! ----------------------------------------------

#![allow(unused_imports)]
#![allow(non_snake_case)]

use std::cell::RefCell;
use std::cmp::{max, min, Ordering};
use std::collections::*;
use std::fmt::{Debug, Display, Formatter, Write as FmtWrite};
use std::io::{stderr, stdin, BufRead, Write};
use std::mem::{replace, swap};
use std::ops::*;
use std::rc::Rc;

/// Print values to standard error if debug mode.
#[allow(unused_macros)]
macro_rules! debug {
    ($($e:expr),*) => {
        #[cfg(debug_assertions)]
        $({
            let (e, mut err) = (stringify!($e), stderr());
            writeln!(err, "\x1B[33m{}\x1B[0m = {:?}", e, $e).unwrap()
        })*
    };
}

/// Read from standard input and parse each word.
/// - `read!(T, U, ..)` parses a line as a tuple of words.
/// - `read![[T]]` parses a line as an array of words.
/// - `read![..; N]` parses `N` lines, using `read!(..)` repeatedly.
#[allow(unused_macros)]
macro_rules! read {
    ([$t:ty] ; $n:expr) =>
        ((0..$n).map(|_| read!([$t])).collect::<Vec<_>>());
    ($($t:ty),+ ; $n:expr) =>
        ((0..$n).map(|_| read!($($t),+)).collect::<Vec<_>>());
    ([$t:ty]) =>
        (rl().split_whitespace().map(|w| w.parse().unwrap()).collect::<Vec<$t>>());
    ($($t:ty),*) => {{
        let buf = rl();
        let mut w = buf.split_whitespace();
        ($(w.next().unwrap().parse::<$t>().unwrap()),*)
    }};
}

/// Read a line from standard input.
#[allow(dead_code)]
fn rl() -> String {
    let mut buf = String::new();
    stdin().read_line(&mut buf).unwrap();

    #[allow(deprecated)]
    buf.trim_right().to_owned()
}

// -----------------------------------------------
// Solution
// -----------------------------------------------

/*

6
1 2
1 3
1 4
1 5
1 6

*/

fn rerooting<
    T: Clone,
    E: IntoIterator<Item = (usize, usize)>,
    F: FnMut(T, T) -> T,
    G: FnMut(T, usize) -> T,
>(
    node_count: usize,
    edges: E,
    identity: T,
    mut operate: F,
    mut operate_node: G,
) -> Vec<T> {
    const NO_PARENT: usize = std::usize::MAX;

    let mut adjacents = vec![vec![]; node_count];
    let mut index_for_adjacents = vec![vec![]; node_count];

    for (u, v) in edges {
        index_for_adjacents[u].push(adjacents[v].len());
        index_for_adjacents[v].push(adjacents[u].len());
        adjacents[u].push(v);
        adjacents[v].push(u);
    }

    if node_count == 0 {
        return vec![];
    }

    if node_count == 1 {
        return vec![operate_node(identity, 0)];
    }

    let mut parents = vec![0; node_count];
    let mut order = vec![0; node_count];

    // initialize ordered tree
    {
        let mut index = 0;
        let mut stack = vec![0];
        parents[0] = NO_PARENT;

        while let Some(node) = stack.pop() {
            order[index] = node;
            index += 1;

            for i in 0..adjacents[node].len() {
                let adjacent = adjacents[node][i];
                if adjacent == parents[node] {
                    continue;
                }

                stack.push(adjacent);
                parents[adjacent] = node;
            }
        }
    }

    let mut dp = (0..node_count)
        .map(|i| vec![identity.clone(); adjacents[i].len()])
        .collect::<Vec<_>>();

    // from leaf
    for i in (1..node_count).rev() {
        let node = order[i];
        let parent = parents[node];

        let mut accum = identity.clone();
        let mut parent_index = NO_PARENT;

        for j in 0..adjacents[node].len() {
            if adjacents[node][j] == parent {
                parent_index = j;
                continue;
            }

            accum = operate(accum, dp[node][j].clone());
        }

        dp[parent][index_for_adjacents[node][parent_index]] = operate_node(accum, node);
    }

    let mut res = vec![identity.clone(); node_count];
    let mut accums_from_tail = vec![];

    // to leaf
    for i in 0..node_count {
        let node = order[i];
        let deg = adjacents[node].len();
        let mut accum = identity.clone();

        accums_from_tail.clear();
        accums_from_tail.extend(std::iter::repeat(identity.clone()).take(deg));

        for j in (1..deg).rev() {
            accums_from_tail[j - 1] = operate(accums_from_tail[j].clone(), dp[node][j].clone());
        }

        for j in 0..deg {
            dp[adjacents[node][j]][index_for_adjacents[node][j]] =
                operate_node(operate(accum.clone(), accums_from_tail[j].clone()), node);
            accum = operate(accum, dp[node][j].clone());
        }

        res[node] = operate_node(accum, node);
    }

    res
}

const P: i64 = 1_000_000_007;

pub fn pow(x: i64, n: i64) -> i64 {
    let (mut x, mut y, mut n) = (x % P, 1_i64, n);
    while n > 0 {
        if n % 2 != 0 {
            y = (y * x) % P;
            n -= 1;
        }

        x = (x * x) % P;
        n /= 2;
    }
    y
}

/// 部分木に対して持つ計算結果
#[derive(Clone, Copy)]
struct X {
    /// 場合の数
    combo: i64,
    /// 頂点数
    size: usize,
    /// (size!)^(-1)
    divisor: i64,
}

impl X {
    fn empty() -> X {
        X {
            combo: 1,
            size: 0,
            divisor: 1,
        }
    }

    fn append(self, other: X) -> X {
        X {
            combo: self.combo * other.combo % P,
            size: self.size + other.size,
            divisor: self.divisor * other.divisor % P,
        }
    }
}

fn main() {
    let N = read!(usize);
    let E = read![usize, usize; N - 1];

    let M = N + 1;
    let mut fact = vec![0; M];
    fact[0] = 1;
    for i in 1..M {
        fact[i] = fact[i - 1] * (i as i64) % P;
    }

    let mut fact_inv = vec![0; M];
    fact_inv[M - 1] = pow(fact[M - 1], P - 2);
    for i in (0..M - 1).rev() {
        fact_inv[i] = fact_inv[i + 1] * ((i + 1) as i64) % P;
    }

    let operate_node = |x: X, _u: usize| -> X {
        // x: 各部分木に対する operate_node の結果を X::append で合成したもの
        X {
            combo: fact[x.size] * x.combo % P * x.divisor % P,
            size: x.size + 1,
            divisor: fact_inv[x.size + 1],
        }
    };

    let res = rerooting(
        N,
        E.into_iter().map(|(u, v)| (u - 1, v - 1)),
        X::empty(),
        X::append,
        operate_node,
    );

    for i in 0..N {
        println!("{}", res[i].combo);
    }
}