Problem:
Score : 1300 points

Problem Statement

You are playing a game and your goal is to maximize your expected gain.
At the beginning of the game, a pawn is put, uniformly at random, at a position p\in\{1,2,\dots, N\}. The N positions are arranged on a circle (so that 1 is between N and 2).

The game consists of turns. At each turn you can either end the game, and get A_p dollars (where p is the current position of the pawn), or pay B_p dollar to keep playing.
If you decide to keep playing, the pawn is randomly moved to one of the two adjacent positions p-1, p+1 (with the identifications 0 = N and N+1=1).

What is the expected gain of an optimal strategy?

Note: The "expected gain of an optimal strategy" shall be defined as the supremum of the expected gain among all strategies such that the game ends in a finite number of turns.

Constraints

2 \le N \le 200,000

0 \le A_p \le 10^{12} for any p = 1,\ldots, N

0 \le B_p \le 100 for any p = 1, \ldots, N

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N

Output

Print a single real number, the expected gain of an optimal strategy.
Your answer will be considered correct if its relative or absolute error does not exceed 10^{-10}.

Sample Input 1

5
4 2 6 3 5
1 1 1 1 1

Sample Output 1

4.700000000000

Sample Input 2

4
100 0 100 0
0 100 0 100

Sample Output 2

50.000000000000

Sample Input 3

14
4839 5400 6231 5800 6001 5200 6350 7133 7986 8012 7537 7013 6477 5912
34 54 61 32 52 61 21 43 65 12 45 21 1 4

Sample Output 3

7047.142857142857

Sample Input 4

10
470606482521 533212137322 116718867454 746976621474 457112271419 815899162072 641324977314 88281100571 9231169966 455007126951
26 83 30 59 100 88 84 91 54 61

Sample Output 4

815899161079.400024414062

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

use proconio::*;

// a_i の最大値では確定で終わる

#[fastout]
fn run() {
    input! {
        n: usize,
        a: [f64; n],
        b: [f64; n],
    }
    let mut e = a.clone();
    for _ in 0..3000 {
        for i in 1..(n - 1) {
            e[i] = e[i].max(-b[i] + (e[i + 1] + e[i - 1]) * 0.5);
        }
        e[0] = e[0].max(-b[0] + (e[1] + e[n - 1]) * 0.5);
        e[n - 1] = e[n - 1].max(-b[n - 1] + (e[n - 2] + e[0]) * 0.5);
    }
    let sum: f64 = e.iter().sum();
    let ans = sum / n as f64;
    println!("{:.11}", ans);
}

fn main() {
    run();
}