Problem:
Score : 200 points

Problem Statement

There are N positive integers written on a blackboard: A_1, ..., A_N.

Snuke can perform the following operation when all integers on the blackboard are even:

Replace each integer X on the blackboard by X divided by 2.

Find the maximum possible number of operations that Snuke can perform.

Constraints

1 \leq N \leq 200

1 \leq A_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the maximum possible number of operations that Snuke can perform.

Sample Input 1

3
8 12 40

Sample Output 1

2

Initially, [8, 12, 40] are written on the blackboard.
Since all those integers are even, Snuke can perform the operation.

After the operation is performed once, [4, 6, 20] are written on the blackboard.
Since all those integers are again even, he can perform the operation.

After the operation is performed twice, [2, 3, 10] are written on the blackboard.
Now, there is an odd number 3 on the blackboard, so he cannot perform the operation any more.

Thus, Snuke can perform the operation at most twice.

Sample Input 2

4
5 6 8 10

Sample Output 2

0

Since there is an odd number 5 on the blackboard already in the beginning, Snuke cannot perform the operation at all.

Sample Input 3

6
382253568 723152896 37802240 379425024 404894720 471526144

Sample Output 3

8

Solution in Rust (1.15.1) (judge verdict: Accepted)

fn main() {
    let mut n = String::new();
    let mut a = String::new();
    std::io::stdin().read_line(&mut n).unwrap();
    std::io::stdin().read_line(&mut a).unwrap();
    let mut v: Vec<i32> = a.trim().split_whitespace()
        .map(|x| x.parse().unwrap()).collect();

//    println!("{}{}", n, a);
    
    let mut ans = 0;
    loop {
        let mut flag = 0;
        for x in &mut v {
//            println!("before: {}", x);
            if ( *x % 2 != 0 ) {
                flag = 1;
                break;
            }
            *x = *x / 2;
//            println!("{}", x);
        }
        if ( flag == 1 ) {
            break;
        }
        ans = ans + 1;
    }
    println!("{}", ans);
}