Problem:
Score : 200 points

Problem Statement

Let S(n) denote the sum of the digits in the decimal notation of n.
For example, S(101) = 1 + 0 + 1 = 2.

Given an integer N, determine if S(N) divides N.

Constraints

1 \leq N \leq 10^9

Input

Input is given from Standard Input in the following format:

N

Output

If S(N) divides N, print Yes; if it does not, print No.

Sample Input 1

12

Sample Output 1

Yes

In this input, N=12.
As S(12) = 1 + 2 = 3, S(N) divides N.

Sample Input 2

101

Sample Output 2

No

As S(101) = 1 + 0 + 1 = 2, S(N) does not divide N.

Sample Input 3

999999999

Sample Output 3

Yes

Solution in Rust (1.42.0) (judge verdict: Accepted)

use itertools::Itertools;

fn main() {
    let a: u32 = text_io::read!();
    let mut sum= 0;
    let b = a.to_string().chars().map(|a|a.to_digit(10).unwrap()).collect_vec();
    for i in 0..b.len() {
        sum+=b[i];
    }
    println!("{}",if a%sum==0 {"Yes"}else{"No"})
}