Problem:
Score : 500 points

Problem Statement

Takahashi has come to a party as a special guest.
There are N ordinary guests at the party. The i-th ordinary guest has a power of A_i.

Takahashi has decided to perform M handshakes to increase the happiness of the party (let the current happiness be 0).
A handshake will be performed as follows:

Takahashi chooses one (ordinary) guest x for his left hand and another guest y for his right hand (x and y can be the same).

Then, he shakes the left hand of Guest x and the right hand of Guest y simultaneously to increase the happiness by A_x+A_y.

However, Takahashi should not perform the same handshake more than once. Formally, the following condition must hold:

Assume that, in the k-th handshake, Takahashi shakes the left hand of Guest x_k and the right hand of Guest y_k. Then, there is no pair p, q (1 \leq p < q \leq M) such that (x_p,y_p)=(x_q,y_q).

What is the maximum possible happiness after M handshakes?

Constraints

1 \leq N \leq 10^5

1 \leq M \leq N^2

1 \leq A_i \leq 10^5

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
A_1 A_2 ... A_N

Output

Print the maximum possible happiness after M handshakes.

Sample Input 1

5 3
10 14 19 34 33

Sample Output 1

202

Let us say that Takahashi performs the following handshakes:

In the first handshake, Takahashi shakes the left hand of Guest 4 and the right hand of Guest 4.

In the second handshake, Takahashi shakes the left hand of Guest 4 and the right hand of Guest 5.

In the third handshake, Takahashi shakes the left hand of Guest 5 and the right hand of Guest 4.

Then, we will have the happiness of (34+34)+(34+33)+(33+34)=202.

We cannot achieve the happiness of 203 or greater, so the answer is 202.

Sample Input 2

9 14
1 3 5 110 24 21 34 5 3

Sample Output 2

1837

Sample Input 3

9 73
67597 52981 5828 66249 75177 64141 40773 79105 16076

Sample Output 3

8128170

Solution in Rust (1.15.1) (judge verdict: Accepted)

// ---------- begin karatsuba multiplication ----------
fn karatsuba<T>(a: &[T], b: &[T], c: &mut [T], zero: T, buf: &mut [T]) 
where T: std::marker::Copy +
         std::ops::Add<Output = T> +
         std::ops::Sub<Output = T> +
         std::ops::Mul<Output = T> +
{
    let n = a.len();
    if n <= 32 {
        for (i, a) in a.iter().enumerate() {
            for (c, b) in c[i..].iter_mut().zip(b.iter()) {
                *c = *c + *a * *b;
            }
        }
        return;
    }
    if n & 1 == 1 {
        karatsuba(&a[1..], &b[1..], &mut c[2..], zero, buf);
        let x = a[0];
        let y = b[0];
        c[0] = c[0] + x * y;
        for (c, (a, b)) in c[1..].iter_mut().zip(a[1..].iter().zip(b[1..].iter())) {
            *c = *c + x * *b + *a * y;
        }
        return;
    }
    let m = n / 2;
    karatsuba(&a[..m], &b[..m], &mut c[..n], zero, buf);
    karatsuba(&a[m..], &b[m..], &mut c[n..], zero, buf);
    let (x, y) = buf.split_at_mut(m);
    let (y, z) = y.split_at_mut(m);
    let (z, buf) = z.split_at_mut(n);
    for z in z.iter_mut() {
        *z = zero;
    }
    for (x, (p, q)) in x.iter_mut().zip(a.iter().zip(a[m..].iter())) {
        *x = *p + *q;
    }
    for (y, (p, q)) in y.iter_mut().zip(b.iter().zip(b[m..].iter())) {
        *y = *p + *q;
    }
    karatsuba(x, y, z, zero, buf);
    for (z, (p, q)) in z.iter_mut().zip(c[..n].iter().zip(c[n..].iter())) {
        *z = *z - (*p + *q);
    }
    for (c, z) in c[m..].iter_mut().zip(z.iter()) {
        *c = *c + *z;
    }
}

fn multiply<T>(a: &[T], b: &[T], zero: T) -> Vec<T>
where T: std::marker::Copy +
         std::ops::Add<Output = T> +
         std::ops::Sub<Output = T> +
         std::ops::Mul<Output = T> +
{
    let mut i = 0;
    let mut j = 0;
    let mut ans = vec![zero; a.len() + b.len()];
    let mut buf = vec![zero; 4 * (a.len() + b.len())];
    let mut c = Vec::with_capacity(a.len() + b.len());
    while i < a.len() && j < b.len() {
        let x = a.len() - i;
        let y = b.len() - j;
        let z = std::cmp::min(x, y);
        c.clear();
        c.resize(2 * z, zero);
        karatsuba(&a[i..(i + z)], &b[j..(j + z)], &mut c, zero, &mut buf);
        for (ans, c) in ans[(i + j)..].iter_mut().zip(c.iter()) {
            *ans = *ans + *c;
        }
        if x <= y {
            j += x;
        } else {
            i += y;
        }
    }
    ans.truncate(a.len() + b.len() - 1);
    ans
}
// ---------- end karatsuba multiplication ----------

use std::io::Read;

fn run() {
    let mut s = String::new();
    std::io::stdin().read_to_string(&mut s).unwrap();
    let mut it = s.trim().split_whitespace();
    it.next(); // eat n
    let mut m: usize = it.next().unwrap().parse().unwrap();
    let len = 100_000;
    let mut a = vec![0usize; len + 1];
    for s in it {
        let x: usize = s.parse().unwrap();
        a[x] += 1;
    }
    let cnt = multiply(&a, &a, 0);
    let mut ans = 0;
    for (i, c) in cnt.iter().enumerate().rev() {
        let v = std::cmp::min(m, *c);
        ans += v * i;
        m -= v;
    }
    println!("{}", ans);
}

fn main() {
    run();
}