Problem:
Score : 800 points

Problem Statement

In Finite Encyclopedia of Integer Sequences (FEIS), all integer sequences of lengths between 1 and N (inclusive) consisting of integers between 1 and K (inclusive) are listed.

Let the total number of sequences listed in FEIS be X. Among those sequences, find the (X/2)-th (rounded up to the nearest integer) lexicographically smallest one.

Constraints

1 \leq N,K \leq 3 × 10^5

N and K are integers.

Input

Input is given from Standard Input in the following format:

K N

Output

Print the (X/2)-th (rounded up to the nearest integer) lexicographically smallest sequence listed in FEIS, with spaces in between, where X is the total number of sequences listed in FEIS.

Sample Input 1

3 2

Sample Output 1

2 1

There are 12 sequences listed in FEIS: (1),(1,1),(1,2),(1,3),(2),(2,1),(2,2),(2,3),(3),(3,1),(3,2),(3,3).
The (12/2 = 6)-th lexicographically smallest one among them is (2,1).

Sample Input 2

2 4

Sample Output 2

1 2 2 2

Sample Input 3

5 14

Sample Output 3

3 3 3 3 3 3 3 3 3 3 3 3 2 2

Solution in Rust (1.15.1) (judge verdict: Wrong Answer)

fn main() {
    let s = std::io::stdin();
    let mut sc = Scanner { stdin: s.lock() };
    let k: usize = sc.read();
    let n: usize = sc.read();
    if k % 2 == 0 {
        print!("{}", k / 2);
        for _ in 1..n {
            print!(" {}", k);
        }
        println!();
    } else {
        let mut ans = vec![(k + 1) / 2; n];
        let mut tail = ans.len() - 1;
        for _ in 0..(n / 2) {
            ans[tail] -= 1;
            if ans[tail] == 0 {
                tail -= 1;
            } else {
                for i in (tail + 1)..n {
                    ans[i] = k;
                }
                tail = ans.len() - 1;
            }
        }
        for i in 0..n {
            if i > 0 {
                print!(" ");
            }
            print!("{}", ans[i]);
        }
        println!();
    }
}

/// 1 ...
/// 2 ...
/// 3
/// 3 1 ...
/// 3 2 ...
/// 3 3 ...
/// 3 4 ...
/// 3 5 ...
/// 4 ...
/// 5 ...
///
/// 3 3 3 3 3 3 3 3 3 3 3 3 0 0
/// 3 3 3 3 3 3 3 3 3 3 3 3 1 0
/// 3 3 3 3 3 3 3 3 3 3 3 3 1 1
/// 3 3 3 3 3 3 3 3 3 3 3 3 2 2
/// 3 3 3 3 3 3 3 3 3 3 3 3 2 3
/// 3 3 3 3 3 3 3 3 3 3 3 3 2 4
/// 3 3 3 3 3 3 3 3 3 3 3 3 2 5
/// 3 3 3 3 3 3 3 3 3 3 3 3 3
/// 3 3 3 3 3 3 3 3 3 3 3 3 3 1
/// 3 3 3 3 3 3 3 3 3 3 3 3 3 2
/// 3 3 3 3 3 3 3 3 3 3 3 3 3 3
pub struct Scanner<R> {
    stdin: R,
}

impl<R: std::io::Read> Scanner<R> {
    pub fn read<T: std::str::FromStr>(&mut self) -> T {
        use std::io::Read;
        let buf = self
            .stdin
            .by_ref()
            .bytes()
            .map(|b| b.unwrap())
            .skip_while(|&b| b == b' ' || b == b'\n')
            .take_while(|&b| b != b' ' && b != b'\n')
            .collect::<Vec<_>>();
        unsafe { std::str::from_utf8_unchecked(&buf) }
            .parse()
            .ok()
            .expect("Parse error.")
    }
    pub fn vec<T: std::str::FromStr>(&mut self, n: usize) -> Vec<T> {
        (0..n).map(|_| self.read()).collect()
    }
    pub fn chars(&mut self) -> Vec<char> {
        self.read::<String>().chars().collect()
    }
}