Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

use proconio::{input, marker::Chars};

fn main() {
    input!{
        n: usize,
        a: isize,
        b: isize,
        c: isize,
        ss: [String; n],
    }

    let mut a = a;
    let mut b = b;
    let mut c = c;
    let mut pattern = vec![];

    // MEMO: 先読みしたほうがいいかも
    fn phase(pattern: &mut Vec<String>, one: &mut isize, another: &mut isize, one_name: &str, another_name: &str) {
        if one >= another {
            *one -= 1;
            *another += 1;
            pattern.push(another_name.to_string());
        } else {
            *one += 1;
            *another -= 1;
            pattern.push(one_name.to_string());
        }
    }

    for i in 0..n {
        match &*ss[i] {
            "AB" => {
                phase(&mut pattern, &mut a, &mut b, "A", "B");
            },
            "BC" => {
                phase(&mut pattern, &mut b, &mut c, "B", "C");
            },
            _ => {
                phase(&mut pattern, &mut a, &mut c, "A", "C");
            },
        }

        if a * b * c < 0 {
            println!("No");
            return;
        }
    }

    println!("Yes");
    for e in &pattern {
        println!("{}", e);
    }
}