Problem:
Score : 200 points

Problem Statement

It is only six months until Christmas, and AtCoDeer the reindeer is now planning his travel to deliver gifts.

There are N houses along TopCoDeer street. The i-th house is located at coordinate a_i. He has decided to deliver gifts to all these houses.

Find the minimum distance to be traveled when AtCoDeer can start and end his travel at any positions.

Constraints

1 ≤ N ≤ 100

0 ≤ a_i ≤ 1000

a_i is an integer.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the minimum distance to be traveled.

Sample Input 1

4
2 3 7 9

Sample Output 1

7

The travel distance of 7 can be achieved by starting at coordinate 9 and traveling straight to coordinate 2.

It is not possible to do with a travel distance of less than 7, and thus 7 is the minimum distance to be traveled.

Sample Input 2

8
3 1 4 1 5 9 2 6

Sample Output 2

8

There may be more than one house at a position.

Solution in Rust (1.15.1) (judge verdict: Accepted)


#![allow(unused)]

use std::cmp;
use std::io::{self, BufRead};
use std::iter;

macro_rules! destruct_ {
  ($e: expr, ()) => (
    assert!($e.next().is_none())
  );
  ($e: expr, ($arg: ident, $( $args: ident, )*)) => (
    $arg = $e.next().unwrap();
    destruct_!($e, ($($args,)*))
  );
  ($e: expr, ($arg: ident $(, $args: ident )*)) => (
    $arg = $e.next().unwrap();
    destruct_!($e, ($($args,)*))
  );
}

macro_rules! into {
  ($e: expr, $($name: ident)*) => {
    let mut iter = $e.into_iter();
    destruct_!(iter, ($($name)*));
  }
}

macro_rules! get {
  ($i: ident) => (
    let stdin = io::stdin();
    let mut $i = Vec::new();
    for line in stdin.lock().lines() {
      $i.push(
        line
          .unwrap()
          .split_whitespace()
          .map(|a| a.parse().unwrap())
          .collect()
      );
    }
  )
}

macro_rules! p {
  ($a: expr) => (
    println!("{:?}", $a);
  )
}

fn main() {
  let mut args: Vec<Vec<i32>>;
  get!(args);
  let mut ls: &mut Vec<i32> = &mut args[1];

  ls.sort();
  p!(ls.iter().max().unwrap() - ls.iter().min().unwrap());
}