Problem:
Score : 100 points

Problem Statement

You are given four digits N_1, N_2, N_3 and N_4. Determine if these can be arranged into the sequence of digits "1974".

Constraints

0 \leq N_1, N_2, N_3, N_4 \leq 9

N_1, N_2, N_3 and N_4 are integers.

Input

Input is given from Standard Input in the following format:

N_1 N_2 N_3 N_4

Output

If N_1, N_2, N_3 and N_4 can be arranged into the sequence of digits "1974", print YES; if they cannot, print NO.

Sample Input 1

1 7 9 4

Sample Output 1

YES

We can get 1974 by swapping N_2 and N_3.

Sample Input 2

1 9 7 4

Sample Output 2

YES

We already have 1974 before doing anything.

Sample Input 3

1 2 9 1

Sample Output 3

NO

Sample Input 4

4 9 0 8

Sample Output 4

NO

Solution in Rust (1.15.1) (judge verdict: Accepted)

fn main() {
    let mut buf = String::new();
    let handle = std::io::stdin();

    let mut ns: Vec<usize> = {
        handle.read_line(&mut buf).unwrap();
        let tmp = buf.trim().split_whitespace().map(|a| a.parse().unwrap()).collect();
        buf.clear();
        tmp
    };
    ns.sort();
    if ns.binary_search(&1).is_ok() && ns.binary_search(&9).is_ok() && ns.binary_search(&7).is_ok() && ns.binary_search(&4).is_ok() {
        println!("{}", "YES");
    } else {
        println!("{}", "NO");
    }
}