Problem:
Score : 200 points

Problem Statement

There are N gems. The value of the i-th gem is V_i.

You will choose some of these gems, possibly all or none, and get them.

However, you need to pay a cost of C_i to get the i-th gem.

Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.

Find the maximum possible value of X-Y.

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq C_i, V_i \leq 50

Input

Input is given from Standard Input in the following format:

N
V_1 V_2 ... V_N
C_1 C_2 ... C_N

Output

Print the maximum possible value of X-Y.

Sample Input 1

3
10 2 5
6 3 4

Sample Output 1

5

If we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.
We have X-Y = 5 here, which is the maximum possible value.

Sample Input 2

4
13 21 6 19
11 30 6 15

Sample Output 2

6

Sample Input 3

1
1
50

Sample Output 3

0

Solution in Rust (1.15.1) (judge verdict: Accepted)

/// 1行の文字を空白で分割してVec<T>にする。
fn read_split<T : std::str::FromStr>() -> Vec<T> {
    let mut input = String::new();
    std::io::stdin().read_line(&mut input).unwrap();
    input.trim().split_whitespace().map(|x| x.parse().ok().unwrap()).collect()
}

/// 1つの要素を入力で受け取る
fn read_one<T : std::str::FromStr>() -> T {
    let mut input = String::new();
    std::io::stdin().read_line(&mut input).unwrap();
    input.trim().parse().ok().unwrap()
}

fn main() {
    let input : usize = read_one();
    let v : Vec<i32> = read_split();
    let c : Vec<i32> = read_split();
    let mut price = 0;
    for i in 0..input {
        if v[i] < c[i] { continue; }
        price += v[i] - c[i];
    }
    println!("{}", price);
}