Problem:
Score : 300 points

Problem Statement

There are N slimes lining up from left to right. The colors of these slimes will be given as a string S of length N consisting of lowercase English letters. The i-th slime from the left has the color that corresponds to the i-th character of S.

Adjacent slimes with the same color will fuse into one larger slime without changing the color. If there were a slime adjacent to this group of slimes before fusion, that slime is now adjacent to the new larger slime.

Ultimately, how many slimes will be there?

Constraints

1 \leq N \leq 10^5

|S| = N

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the final number of slimes.

Sample Input 1

10
aabbbbaaca

Sample Output 1

5

Ultimately, these slimes will fuse into abaca.

Sample Input 2

5
aaaaa

Sample Output 2

1

All the slimes will fuse into one.

Sample Input 3

20
xxzaffeeeeddfkkkkllq

Sample Output 3

10

Solution in Rust (1.42.0) (judge verdict: Accepted)

#![allow(dead_code)]
#![allow(unused_imports)]
use ascii::{AsciiChar, AsciiStr, AsciiString};
use indexmap::IndexMap;
use itertools::*;
use libm::*;
use num::*;
use ordered_float::OrderedFloat;
use permutohedron::LexicalPermutation;
use proconio::marker::{Bytes, Chars};
use proconio::{fastout, input};
use std::cmp::{max, min, Ordering};
use std::collections::{BTreeMap, BTreeSet, BinaryHeap, HashMap, HashSet, VecDeque};
use std::mem::swap;

fn main() {
    input!(n:usize, s:String);
    let s = s.chars().collect::<Vec<char>>();
    let mut ans = 1;
    let mut c = s[0];
    for i in 1..n {
        if c != s[i] {
            ans += 1;
            c = s[i];
        }
    }
    println!("{}",ans);
}