Problem:
Score : 200 points

Problem Statement

A ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \leq i \leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.

How many times will the ball make a bounce where the coordinate is at most X?

Constraints

1 \leq N \leq 100

1 \leq L_i \leq 100

1 \leq X \leq 10000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X
L_1 L_2 ... L_{N-1} L_N

Output

Print the number of times the ball will make a bounce where the coordinate is at most X.

Sample Input 1

3 6
3 4 5

Sample Output 1

2

The ball will make a bounce at the coordinates 0, 3, 7 and 12, among which two are less than or equal to 6.

Sample Input 2

4 9
3 3 3 3

Sample Output 2

4

The ball will make a bounce at the coordinates 0, 3, 6, 9 and 12, among which four are less than or equal to 9.

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::io;
use std::io::BufRead;

fn main() {
    let stdin = io::stdin();
    let mut stdin = stdin.lock();
    
    let (n,x) = {
        let mut input = String::new();
        stdin.read_line(&mut input).unwrap();
        let mut input = input.split_whitespace();
        
        (
            input.next().unwrap().parse::<usize>().unwrap(),
            input.next().unwrap().parse::<i32>().unwrap(),
        )
    };

    
    let mut input = String::new();
    stdin.read_line(&mut input).unwrap();
    let input = input.trim().split_whitespace();

    let mut d: i32 = 0;
    let mut counter: usize = 1;

    for l in input.take(n).map(|s| s.parse::<i32>().unwrap()) {
        d += l;
        
        if d > x { break; }

        counter += 1;
    }
    
    println!("{}", counter);
}