Problem:
Score : 100 points

Problem Statement

Print the K-th element of the following sequence of length 32:

1, 1, 1, 2, 1, 2, 1, 5, 2, 2, 1, 5, 1, 2, 1, 14, 1, 5, 1, 5, 2, 2, 1, 15, 2, 2, 5, 4, 1, 4, 1, 51

Constraints

1 \leq K \leq 32

All values in input are integers.

Input

Input is given from Standard Input in the following format:

K

Output

Print the K-th element.

Sample Input 1

6

Sample Output 1

2

The 6-th element is 2.

Sample Input 2

27

Sample Output 2

5

The 27-th element is 5.

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::io::*;

fn main() {
    let stdin = stdin();
    let mut handle = stdin.lock();
    let k: u32 = read(&mut handle);
    let list: [u32; 32] = [
        1, 1, 1, 2, 1, 2, 1, 5, 2, 2, 1, 5, 1, 2, 1, 14, 1, 5, 1, 5, 2, 2, 1, 15, 2, 2, 5, 4, 1, 4,
        1, 51,
    ];

    println!("{}", list[k as usize - 1]);
}

fn read(handle: &mut StdinLock) -> u32 {
    handle
        .by_ref()
        .bytes()
        .map(|c| c.unwrap() as char)
        .skip_while(|c| c.is_whitespace())
        .take_while(|c| !c.is_whitespace())
        .fold(0, |acc, x| (x as u8 - b'0') as u32 + acc * 10)
}