Problem:
Score : 200 points

Problem Statement

You are given string S and T consisting of lowercase English letters.

Determine if S equals T after rotation.

That is, determine if S equals T after the following operation is performed some number of times:

Operation: Let S = S_1 S_2 ... S_{|S|}. Change S to S_{|S|} S_1 S_2 ... S_{|S|-1}.

Here, |X| denotes the length of the string X.

Constraints

2 \leq |S| \leq 100

|S| = |T|

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S equals T after rotation, print Yes; if it does not, print No.

Sample Input 1

kyoto
tokyo

Sample Output 1

Yes

In the first operation, kyoto becomes okyot.

In the second operation, okyot becomes tokyo.

Sample Input 2

abc
arc

Sample Output 2

No

abc does not equal arc after any number of operations.

Sample Input 3

aaaaaaaaaaaaaaab
aaaaaaaaaaaaaaab

Sample Output 3

Yes

Solution in Rust (1.15.1) (judge verdict: Wrong Answer)

use std::io::BufReader;
use std::io::BufRead;
use std::io;

fn main() {
    let reader = io::stdin();
    let mut reader = BufReader::new(reader.lock());
    let mut s = String::new();
    let mut t = String::new();
    String::new();

    let _ = reader.read_line(&mut s);
    let _ = reader.read_line(&mut t);

    let mut s = s.as_bytes().to_vec();
    let t = t.as_bytes().to_vec();
    let len = s.len();
    let mut count = 0;

    while s == t && count < len {
        let c = s.pop().unwrap();
        s.insert(0, c);
        count += 1;
    }

    if count == (len - 1) {
        println!("No");
    } else {
        println!("Yes");
    }
}