Problem:
Score : 400 points

Problem Statement

Given is a tree G with N vertices.
The vertices are numbered 1 through N, and the i-th edge connects Vertex a_i and Vertex b_i.

Consider painting the edges in G with some number of colors.
We want to paint them so that, for each vertex, the colors of the edges incident to that vertex are all different.

Among the colorings satisfying the condition above, construct one that uses the minimum number of colors.

Constraints

2 \le N \le 10^5

1 \le a_i \lt b_i \le N

All values in input are integers.

The given graph is a tree.

Input

Input is given from Standard Input in the following format:

N
a_1 b_1
a_2 b_2
\vdots
a_{N-1} b_{N-1}

Output

Print N lines.

The first line should contain K, the number of colors used.

The (i+1)-th line (1 \le i \le N-1) should contain c_i, the integer representing the color of the i-th edge, where 1 \le c_i \le K must hold.

If there are multiple colorings with the minimum number of colors that satisfy the condition, printing any of them will be accepted.

Sample Input 1

3
1 2
2 3

Sample Output 1

2
1
2

Sample Input 2

8
1 2
2 3
2 4
2 5
4 7
5 6
6 8

Sample Output 2

4
1
2
3
4
1
1
2

Sample Input 3

6
1 2
1 3
1 4
1 5
1 6

Sample Output 3

5
1
2
3
4
5

Solution in Rust (1.42.0) (judge verdict: Accepted)

use std::io::{Read, StdoutLock};
use std::io::{stdout, BufWriter, Write};
use std::str::{SplitWhitespace, FromStr};
use std::fmt::Display;
use std::collections::{HashMap, VecDeque};

struct IO<'a> {
    sw: SplitWhitespace<'a>,
    bw: BufWriter<StdoutLock<'a>>,
}

impl IO<'_> {
    pub fn read<T: FromStr>(&mut self) -> T where
        <T as std::str::FromStr>::Err: std::fmt::Debug {
        self.sw.next().unwrap().parse().unwrap()
    }
    #[allow(dead_code)]
    pub fn writeln<T: Display>(&mut self, s: T) {
        self.bw.write(format!("{}\n", s).as_bytes()).unwrap();
    }
    #[allow(dead_code)]
    pub fn writeln_n(&mut self, mut n: usize) {
        if n == 0 {
            self.bw.write(b"0\n").unwrap();
        }
        let mut buf: Vec<u8> = Vec::new();
        while n != 0 {
            buf.push((n % 10) as u8 + 48);
            n /= 10;
        }
        buf.reverse();
        buf.push(b'\n');
        self.bw.write(buf.as_slice()).unwrap();
    }
}

// AtCoder Beginner Contest 146 D - Coloring Edges on Tree
fn main() {
    /* BEGIN TEMPLATE */
    let mut buf = String::new();
    std::io::stdin().read_to_string(&mut buf).unwrap();
    let sw = buf.split_whitespace();
    let _stdout = stdout();
    let bw = BufWriter::new(_stdout.lock());
    let mut io = IO{sw, bw};
    /* END TEMPLATE */

    let n: usize = io.read();
    let mut tree: Vec<Vec<usize>> = vec![Vec::new(); n+1];
    let mut edges: Vec<(usize, usize)> = Vec::with_capacity(n-1);
    let mut edge_colors: HashMap<(usize, usize), usize> = HashMap::new();
    (0..n-1).for_each(|_| {
        let (a, b): (usize, usize) = (io.read(), io.read());
        tree[a].push(b);
        tree[b].push(a);
        if a < b {
            edges.push((a, b));
        } else {
            edges.push((b, a));
        }
    });
    let mut colors: Vec<usize> = vec![0; n+1];
    let mut done = vec![false; n+1];
    done[1] = true;
    colors[1] = 0;
    let mut count = colors[1];
    let mut queue: VecDeque<usize> = VecDeque::new();
    queue.push_back(1);
    while !queue.is_empty() {
        let length = queue.len();
        (0..length).for_each(|_|{
            let mut color: usize = 0;
            let front = queue.pop_front().unwrap();
            tree[front].iter().for_each(|&t|{
                if !done[t] {
                    color += 1;
                    if color == colors[front] {
                        color += 1;
                    }
                    colors[t] = color;
                    if color > count {
                        count = color;
                    }
                    done[t] = true;
                    queue.push_back(t);
                    if front < t {
                        *edge_colors.entry((front, t)).or_default() = color;
                    } else {
                        *edge_colors.entry((t, front)).or_default() = color;
                    }
                }
            });
        })
    }
    io.writeln_n(count);
    edges.iter().for_each(|&edge| {
        io.writeln_n(*edge_colors.entry(edge).or_default());
    })
}