Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::io;

fn main() {
    let mut buf = String::new();
    io::stdin().read_line(&mut buf).unwrap();
    let mut iter = buf.trim().split_whitespace();
    let n: i32 = iter.next().unwrap().parse().unwrap();
    let mut ans = 0;
    for i in 1..(n+1) {
    	let mut temp = 0;
        for j in 1..(i+1) {
        	if i%j==0 {
            	temp += 1;
            }
		}
        if temp == 8 && i%2==1 {
			ans += 1;
        }
    }
    println!("{}",ans);
}