Problem:
Score : 100 points

Problem Statement

You are given a binary array A=(A_1,A_2,\cdots,A_N) of length N.

Process Q queries of the following types. The i-th query is represented by three integers T_i,L_i,R_i.

T_i=1: Replace the value of A_j with 1-A_j for each L_i \leq j \leq R_i.

T_i=2: Calculate the inversion(*) of the array A_{L_i},A_{L_i+1},\cdots,A_{R_i}．

Note：The inversion of the array x_1,x_2,\cdots,x_k is the number of the pair of integers i,j with 1 \leq i < j \leq k, x_i > x_j.

Constraints

1 \leq N \leq 2 \times 10^5

0 \leq A_i \leq 1

1 \leq Q \leq 2 \times 10^5

1 \leq T_i \leq 2

1 \leq L_i \leq R_i \leq N

All values in Input are integer.

Input

Input is given from Standard Input in the following format:

N Q
A_1 A_2 \cdots A_N
T_1 L_1 R_1
T_2 L_2 R_2
\vdots
T_Q L_Q R_Q

Output

For each query with T_i=2, print the answer.

Sample Input 1

5 5
0 1 0 0 1
2 1 5
1 3 4
2 2 5
1 1 3
2 1 2

Sample Output 1

2
0
1

First query: Print 2, which is the inversion of (A_1,A_2,A_3,A_4,A_5)=(0,1,0,0,1).

Second query: Replace the value of A_3 and A_4 with 1 and 1, respectively.

Third query: Print 0, which is the inversion of (A_2,A_3,A_4,A_5)=(1,1,1,1).

Fourth query: Replace the value of A_1, A_2 and A_4 with 1, 0 and 0, respectively.

Fifth query: Print 1, which is the inversion of (A_1,A_2)=(1,0).

Solution in Rust (1.42.0) (judge verdict: Accepted)

#[allow(unused_imports)]
use std::cmp::*;
#[allow(unused_imports)]
use std::collections::*;
use std::io::{Write, BufWriter};
// https://qiita.com/tanakh/items/0ba42c7ca36cd29d0ac8
macro_rules! input {
    ($($r:tt)*) => {
        let stdin = std::io::stdin();
        let mut bytes = std::io::Read::bytes(std::io::BufReader::new(stdin.lock()));
        let mut next = move || -> String{
            bytes
                .by_ref()
                .map(|r|r.unwrap() as char)
                .skip_while(|c|c.is_whitespace())
                .take_while(|c|!c.is_whitespace())
                .collect()
        };
        input_inner!{next, $($r)*}
    };
}

macro_rules! input_inner {
    ($next:expr) => {};
    ($next:expr, ) => {};
    ($next:expr, $var:ident : $t:tt $($r:tt)*) => {
        let $var = read_value!($next, $t);
        input_inner!{$next $($r)*}
    };
}

macro_rules! read_value {
    ($next:expr, [graph1; $len:expr]) => {{
        let mut g = vec![vec![]; $len];
        let ab = read_value!($next, [(usize1, usize1)]);
        for (a, b) in ab {
            g[a].push(b);
            g[b].push(a);
        }
        g
    }};
    ($next:expr, ( $($t:tt),* )) => {
        ( $(read_value!($next, $t)),* )
    };
    ($next:expr, [ $t:tt ; $len:expr ]) => {
        (0..$len).map(|_| read_value!($next, $t)).collect::<Vec<_>>()
    };
    ($next:expr, chars) => {
        read_value!($next, String).chars().collect::<Vec<char>>()
    };
    ($next:expr, usize1) => (read_value!($next, usize) - 1);
    ($next:expr, [ $t:tt ]) => {{
        let len = read_value!($next, usize);
        read_value!($next, [$t; len])
    }};
    ($next:expr, $t:ty) => ($next().parse::<$t>().expect("Parse error"));
}

#[allow(unused)]
macro_rules! debug {
    ($($format:tt)*) => (write!(std::io::stderr(), $($format)*).unwrap());
}
#[allow(unused)]
macro_rules! debugln {
    ($($format:tt)*) => (writeln!(std::io::stderr(), $($format)*).unwrap());
}

/**
 * Lazy Segment Tree. This data structure is useful for fast folding and updating on intervals of an array
 * whose elements are elements of monoid T. Note that constructing this tree requires the identity
 * element of T and the operation of T. This is monomorphised, because of efficiency. T := i64, biop = max, upop = (+)
 * Reference: http://d.hatena.ne.jp/kyuridenamida/20121114/1352835261
 * Verified by https://codeforces.com/contest/1114/submission/49759034
 */
pub trait ActionRing {
    type T: Clone + Copy; // data
    type U: Clone + Copy + PartialEq + Eq; // action
    fn biop(x: Self::T, y: Self::T) -> Self::T;
    fn update(x: Self::T, a: Self::U, height: usize) -> Self::T;
    fn upop(fst: Self::U, snd: Self::U) -> Self::U;
    fn e() -> Self::T;
    fn upe() -> Self::U; // identity for upop
}
pub struct LazySegTree<R: ActionRing> {
    n: usize,
    dep: usize,
    dat: Vec<R::T>,
    lazy: Vec<R::U>,
}

impl<R: ActionRing> LazySegTree<R> {
    pub fn new(n_: usize) -> Self {
        let mut n = 1;
        let mut dep = 0;
        while n < n_ { n *= 2; dep += 1; } // n is a power of 2
        LazySegTree {
            n: n,
            dep: dep,
            dat: vec![R::e(); 2 * n - 1],
            lazy: vec![R::upe(); 2 * n - 1]
        }
    }
    #[inline]
    fn lazy_evaluate_node(&mut self, k: usize, height: usize) {
        if self.lazy[k] == R::upe() { return; }
        self.dat[k] = R::update(self.dat[k], self.lazy[k], height);
        if k < self.n - 1 {
            self.lazy[2 * k + 1] = R::upop(self.lazy[2 * k + 1], self.lazy[k]);
            self.lazy[2 * k + 2] = R::upop(self.lazy[2 * k + 2], self.lazy[k]);
        }
        self.lazy[k] = R::upe(); // identity for upop
    }
    #[inline]
    fn update_node(&mut self, k: usize) {
        self.dat[k] = R::biop(self.dat[2 * k + 1], self.dat[2 * k + 2]);
    }
    fn update_sub(&mut self, a: usize, b: usize, v: R::U, k: usize, height: usize, l: usize, r: usize) {
        self.lazy_evaluate_node(k, height);

        // [a,b) and  [l,r) intersects?
        if r <= a || b <= l {return;}
        if a <= l && r <= b {
            self.lazy[k] = R::upop(self.lazy[k], v);
            self.lazy_evaluate_node(k, height);
            return;
        }

        self.update_sub(a, b, v, 2 * k + 1, height - 1, l, (l + r) / 2);
        self.update_sub(a, b, v, 2 * k + 2, height - 1, (l + r) / 2, r);
        self.update_node(k);
    }
    /* ary[i] = upop(ary[i], v) for i in [a, b) (half-inclusive) */
    #[inline]
    pub fn update(&mut self, a: usize, b: usize, v: R::U) {
        let n = self.n;
        let dep = self.dep;
        self.update_sub(a, b, v, 0, dep, 0, n);
    }
    /* l,r are for simplicity */
    fn query_sub(&mut self, a: usize, b: usize, k: usize, height: usize, l: usize, r: usize) -> R::T {
        self.lazy_evaluate_node(k, height);

        // [a,b) and  [l,r) intersect?
        if r <= a || b <= l {return R::e();}
        if a <= l && r <= b {return self.dat[k];}
        let vl = self.query_sub(a, b, 2 * k + 1, height - 1, l, (l + r) / 2);
        let vr = self.query_sub(a, b, 2 * k + 2, height - 1, (l + r) / 2, r);
        self.update_node(k);
        R::biop(vl, vr)
    }
    /* [a, b) (note: half-inclusive) */
    #[inline]
    pub fn query(&mut self, a: usize, b: usize) -> R::T {
        let n = self.n;
        let dep = self.dep;
        self.query_sub(a, b, 0, dep, 0, n)
    }
}

enum Inversion {}

impl ActionRing for Inversion {
    type T = (i64, i64, i64); // data: (0, 1, inv)
    type U = bool; // action, true |-> 0<->1 involution
    fn biop((x0, x1, xinv): Self::T, (y0, y1, yinv): Self::T) -> Self::T {
        (x0 + y0, x1 + y1, xinv + yinv + x1 * y0)
    }
    fn update((x0, x1, xinv): Self::T, a: Self::U, _height: usize) -> Self::T {
        if a {
            (x1, x0, x0 * x1 - xinv)
        } else {
            (x0, x1, xinv)
        }
    }
    fn upop(fst: Self::U, snd: Self::U) -> Self::U {
        fst ^ snd
    }
    fn e() -> Self::T {
        (0, 0, 0)
    }
    fn upe() -> Self::U { // identity for upop
        false
    }
}

fn solve() {
    let out = std::io::stdout();
    let mut out = BufWriter::new(out.lock());
    macro_rules! puts {
        ($($format:tt)*) => (let _ = write!(out,$($format)*););
    }
    input! {
        n: usize, q: usize,
        a: [i32; n],
        tlr: [(i32, usize1, usize); q],
    }
    let mut st = LazySegTree::<Inversion>::new(n);
    for i in 0..n {
        st.dat[st.n - 1 + i] = if a[i] == 0 { (1, 0, 0) } else { (0, 1, 0) };
    }
    for i in (0..st.n - 1).rev() {
        st.dat[i] = Inversion::biop(st.dat[2 * i + 1], st.dat[2 * i + 2]);
    }
    for (t, l, r) in tlr {
        if t == 1 {
            st.update(l, r, true);
        } else {
            let (_, _, inv) = st.query(l, r);
            puts!("{}\n", inv);
        }
    }
}

fn main() {
    // In order to avoid potential stack overflow, spawn a new thread.
    let stack_size = 104_857_600; // 100 MB
    let thd = std::thread::Builder::new().stack_size(stack_size);
    thd.spawn(|| solve()).unwrap().join().unwrap();
}