Problem:
Score : 700 points

Problem Statement

Determine if there exists a sequence obtained by permuting 1,2,...,N that satisfies the following conditions:

The length of its longest increasing subsequence is A.

The length of its longest decreasing subsequence is B.

If it exists, construct one such sequence.

Notes

A subsequence of a sequence P is a sequence that can be obtained by extracting some of the elements in P without changing the order.

A longest increasing subsequence of a sequence P is a sequence with the maximum length among the subsequences of P that are monotonically increasing.

Similarly, a longest decreasing subsequence of a sequence P is a sequence with the maximum length among the subsequences of P that are monotonically decreasing.

Constraints

1 \leq N,A,B \leq 3\times 10^5

All input values are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

If there are no sequences that satisfy the conditions, print -1.

Otherwise, print N integers. The i-th integer should be the i-th element of the sequence that you constructed.

Sample Input 1

5 3 2

Sample Output 1

2 4 1 5 3

One longest increasing subsequence of this sequence is {2,4,5}, and one longest decreasing subsequence of it is {4,3}.

Sample Input 2

7 7 1

Sample Output 2

1 2 3 4 5 6 7

Sample Input 3

300000 300000 300000

Sample Output 3

-1

Solution in Rust (1.15.1) (judge verdict: Wrong Answer)

fn main() {
    let sc = std::io::stdin();
    let mut sc = Scanner { stdin: sc.lock() };
    let n: usize = sc.read();
    let a: usize = sc.read();
    let b: usize = sc.read();
    if a + b - 1 > n {
        println!("-1");
        return;
    }

    let mut ans = vec![];
    let mut i = 0;
    while i < n {
        let mut part = vec![];
        for _ in 0..b {
            if i == n {
                break;
            }
            part.push(i + 1);
            i += 1;
        }
        part.reverse();
        ans.push(part);
    }

    let mut x = ans.len();
    if x > a {
        println!("-1");
        return;
    }
    for ans in ans.iter_mut() {
        if x == a {
            break;
        }
        if x + ans.len() <= a {
            ans.reverse();
            x += ans.len();
        } else {
            ans[0..(a - x)].reverse();
            x = a;
        }
    }
    for (i, ans) in ans.into_iter().enumerate() {
        for (j, a) in ans.into_iter().enumerate() {
            if i != 0 || j != 0 {
                print!(" ");
            }
            print!("{}", a);
        }
    }

    println!();
}

pub struct Scanner<R> {
    stdin: R,
}

impl<R: std::io::Read> Scanner<R> {
    pub fn read<T: std::str::FromStr>(&mut self) -> T {
        use std::io::Read;
        let buf = self
            .stdin
            .by_ref()
            .bytes()
            .map(|b| b.unwrap())
            .skip_while(|&b| b == b' ' || b == b'\n')
            .take_while(|&b| b != b' ' && b != b'\n')
            .collect::<Vec<_>>();
        unsafe { std::str::from_utf8_unchecked(&buf) }
            .parse()
            .ok()
            .expect("Parse error.")
    }
    pub fn read_vec<T: std::str::FromStr>(&mut self, n: usize) -> Vec<T> {
        (0..n).map(|_| self.read()).collect()
    }
    pub fn chars(&mut self) -> Vec<char> {
        self.read::<String>().chars().collect()
    }
}