Problem:
Score : 400 points

Problem Statement

Given are positive integers A and B.

Let us choose some number of positive common divisors of A and B.

Here, any two of the chosen divisors must be coprime.

At most, how many divisors can we choose?

Definition of common divisor

An integer d is said to be a common divisor of integers x and y when d divides both x and y.

Definition of being coprime

Integers x and y are said to be coprime when x and y have no positive common divisors other than 1.

Definition of dividing

An integer x is said to divide another integer y when there exists an integer \alpha such that y = \alpha x.

Constraints

All values in input are integers.

1 \leq A, B \leq 10^{12}

Input

Input is given from Standard Input in the following format:

A B

Output

Print the maximum number of divisors that can be chosen to satisfy the condition.

Sample Input 1

12 18

Sample Output 1

3

12 and 18 have the following positive common divisors: 1, 2, 3, and 6.

1 and 2 are coprime, 2 and 3 are coprime, and 3 and 1 are coprime, so we can choose 1, 2, and 3, which achieve the maximum result.

Sample Input 2

420 660

Sample Output 2

4

Sample Input 3

1 2019

Sample Output 3

1

1 and 2019 have no positive common divisors other than 1.

Solution in Rust (1.15.1) (judge verdict: Wrong Answer)

#[allow(unused_imports)]
use std::cmp::{max, min, Ordering};
#[allow(unused_imports)]
use std::collections::{BTreeMap, BTreeSet, BinaryHeap, HashMap, HashSet, VecDeque};
#[allow(unused_imports)]
use std::io::{stderr, stdin, stdout, BufRead, BufWriter, Read, StdoutLock, Write};
#[allow(unused_imports)]
use std::iter::FromIterator;
#[allow(unused_imports)]
use std::{i64, u64, usize};
#[allow(unused_macros)]
/// https://qiita.com/tanakh/items/0ba42c7ca36cd29d0ac8
macro_rules !input {(source =$s :expr ,$($r :tt ) *) =>{let mut iter =$s .split_whitespace () ;input_inner !{iter ,$($r ) *} } ;($($r :tt ) *) =>{let mut s ={use std ::io ::Read ;let mut s =String ::new () ;std ::io ::stdin () .read_to_string (&mut s ) .unwrap () ;s } ;let mut iter =s .split_whitespace () ;input_inner !{iter ,$($r ) *} } ;}
#[allow(unused_macros)]
macro_rules !input_inner {($iter :expr ) =>{} ;($iter :expr ,) =>{} ;($iter :expr ,$var :ident :$t :tt $($r :tt ) *) =>{let $var =read_value !($iter ,$t ) ;input_inner !{$iter $($r ) *} } ;}
#[allow(unused_macros)]
macro_rules !read_value {($iter :expr ,($($t :tt ) ,*) ) =>{($(read_value !($iter ,$t ) ) ,*) } ;($iter :expr ,[$t :tt ;$len :expr ] ) =>{(0 ..$len ) .map (|_ |read_value !($iter ,$t ) ) .collect ::<Vec <_ >>() } ;($iter :expr ,chars ) =>{read_value !($iter ,String ) .chars () .collect ::<Vec <char >>() } ;($iter :expr ,usize1 ) =>{read_value !($iter ,usize ) -1 } ;($iter :expr ,$t :ty ) =>{$iter .next () .unwrap () .parse ::<$t >() .expect ("Parse error" ) } ;}
#[allow(unused_macros)]
macro_rules !dbg {($($a :expr ) ,*) =>{writeln !(&mut stderr () ,concat !($(stringify !($a ) ," = {:?}, " ) ,*) ,$($a ) ,*) .unwrap () ;} }
#[allow(dead_code)]
pub fn prime(n: u64) -> Vec<bool> {
    let mut prime: Vec<bool> = vec![true; (n + 1) as usize];
    prime[0] = false;
    if n >= 1 {
        prime[1] = false;
    }
    let mut i = 2_usize;
    while i * i <= n as usize {
        if prime[i] {
            let mut j = i + i;
            while j <= n as usize {
                prime[j] = false;
                j += i;
            }
        }
        i += 1;
    }
    prime
}
#[allow(non_snake_case)]
#[allow(dead_code)]
fn main() {
    input! {
        a: u64,
        b: u64,
    }
    let root = ((max(a, b) + 1) as f64).sqrt();
    let p = prime(root as u64);
    let mut ans: u64 = 1;
    for (i, &pi) in p.iter().enumerate() {
        if pi && a % (i as u64) == 0 && b % (i as u64) == 0 {
            ans += 1;
        }
    }
    println!("{}", ans);
}