Problem:
Score : 500 points

Problem Statement

Takahashi has decided to work on K days of his choice from the N days starting with tomorrow.

You are given an integer C and a string S. Takahashi will choose his workdays as follows:

After working for a day, he will refrain from working on the subsequent C days.

If the i-th character of S is x, he will not work on Day i, where Day 1 is tomorrow, Day 2 is the day after tomorrow, and so on.

Find all days on which Takahashi is bound to work.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq K \leq N

0 \leq C \leq N

The length of S is N.

Each character of S is o or x.

Takahashi can choose his workdays so that the conditions in Problem Statement are satisfied.

Input

Input is given from Standard Input in the following format:

N K C
S

Output

Print all days on which Takahashi is bound to work in ascending order, one per line.

Sample Input 1

11 3 2
ooxxxoxxxoo

Sample Output 1

6

Takahashi is going to work on 3 days out of the 11 days. After working for a day, he will refrain from working on the subsequent 2 days.

There are four possible choices for his workdays: Day 1,6,10, Day 1,6,11, Day 2,6,10, and Day 2,6,11.

Thus, he is bound to work on Day 6.

Sample Input 2

5 2 3
ooxoo

Sample Output 2

1
5

There is only one possible choice for his workdays: Day 1,5.

Sample Input 3

5 1 0
ooooo

Sample Output 3

There may be no days on which he is bound to work.

Sample Input 4

16 4 3
ooxxoxoxxxoxoxxo

Sample Output 4

11
16

Solution in Rust (1.42.0) (judge verdict: Accepted)

use proconio::input;

fn main() {
    input! {
        n: usize,
        k: i64,
        c: i64,
        s: String,
    }

    let workable: Vec<_> = s.chars().map(|c| c == 'o').collect();

    let mut left = vec![false; n];
    let mut last_i = -(c + 1);
    for i in 0..(n as i64) {
        if last_i + c >= i {
            continue;
        }

        if workable[i as usize] {
            left[i as usize] = true;
            last_i = i;
        }
    }
    let left = left;
    let mut left_c = vec![0i64; n + 2];
    let mut left_l = vec![-(c + 1); n + 2];
    for i in 1..=n {
        left_c[i] = left_c[i - 1];
        if left[i - 1] {
            left_c[i] += 1;
        }

        if left[i - 1] {
            left_l[i] = i as i64;
        } else {
            left_l[i] = left_l[i - 1];
        }
    }
    let left_c = left_c;
    let left_l = left_l;

    let mut right = vec![false; n];
    let mut last_i = n as i64 + c;
    for i in (0..(n as i64)).rev() {
        if i + c >= last_i {
            continue;
        }

        if workable[i as usize] {
            right[i as usize] = true;
            last_i = i;
        }
    }
    let right = right;
    let mut right_c = vec![0i64; n + 2];
    let mut right_l = vec![n as i64 + c; n + 2];
    for i in (1..=n).rev() {
        right_c[i] = right_c[i + 1];
        if right[i - 1] {
            right_c[i] += 1;
        }

        if right[i - 1] {
            right_l[i] = i as i64;
        } else {
            right_l[i] = right_l[i + 1];
        }
    }
    let right_c = right_c;

    let mut ans = vec![];
    for i in 1..=n {
        let mut cap = left_c[i - 1] + right_c[i + 1];
        if right_l[i + 1] - left_l[i - 1] <= c {
            cap -= 1;
        }
        if cap < k {
            ans.push(i);
        }
    }

    for a in ans {
        println!("{}", a);
    }
}