Problem:
Score : 200 points

Problem Statement

There are N cities and M roads.
The i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally.
There may be more than one road that connects the same pair of two cities.
For each city, how many roads are connected to the city?

Constraints

2≤N,M≤50

1≤a_i,b_i≤N

a_i ≠ b_i

All input values are integers.

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
:
a_M b_M

Output

Print the answer in N lines.
In the i-th line (1≤i≤N), print the number of roads connected to city i.

Sample Input 1

4 3
1 2
2 3
1 4

Sample Output 1

2
2
1
1

City 1 is connected to the 1-st and 3-rd roads.

City 2 is connected to the 1-st and 2-nd roads.

City 3 is connected to the 2-nd road.

City 4 is connected to the 3-rd road.

Sample Input 2

2 5
1 2
2 1
1 2
2 1
1 2

Sample Output 2

5
5

Sample Input 3

8 8
1 2
3 4
1 5
2 8
3 7
5 2
4 1
6 8

Sample Output 3

3
3
2
2
2
1
1
2

Solution in Rust (1.15.1) (judge verdict: Accepted)


fn main() {
    let mut buf = String::new();
    let _ = ::std::io::stdin().read_line(&mut buf).unwrap();
    let mut it = buf.trim().split_whitespace();
    let n: i32 = it.next().unwrap().parse().unwrap();
    let m: i32 = it.next().unwrap().parse().unwrap();
    let mut counter = vec![0; n as usize];
    for _ in 0..m {
        let mut buf = String::new();
        let _ = ::std::io::stdin().read_line(&mut buf).unwrap();
        let mut it = buf.trim().split_whitespace();
        let x: usize = it.next().unwrap().parse().unwrap();
        let y: usize = it.next().unwrap().parse().unwrap();
        counter[x-1] += 1;
        counter[y-1] += 1;
    }
    for x in counter {
        println!("{}", x);
    }
}