Problem:
Score : 500 points

Problem Statement

There are N integers X_1, X_2, \cdots, X_N, and we know that A_i \leq X_i \leq B_i.
Find the number of different values that the median of X_1, X_2, \cdots, X_N can take.

Notes

The median of X_1, X_2, \cdots, X_N is defined as follows. Let x_1, x_2, \cdots, x_N be the result of sorting X_1, X_2, \cdots, X_N in ascending order.

If N is odd, the median is x_{(N+1)/2};

if N is even, the median is (x_{N/2} + x_{N/2+1}) / 2.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq A_i \leq B_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 B_1
A_2 B_2
:
A_N B_N

Output

Print the answer.

Sample Input 1

2
1 2
2 3

Sample Output 1

3

If X_1 = 1 and X_2 = 2, the median is \frac{3}{2};

if X_1 = 1 and X_2 = 3, the median is 2;

if X_1 = 2 and X_2 = 2, the median is 2;

if X_1 = 2 and X_2 = 3, the median is \frac{5}{2}.

Thus, the median can take three values: \frac{3}{2}, 2, and \frac{5}{2}.

Sample Input 2

3
100 100
10 10000
1 1000000000

Sample Output 2

9991

Solution in Rust (1.42.0) (judge verdict: Accepted)

#![allow(non_snake_case)]

use proconio::input;
use proconio::fastout;

#[fastout]
fn main() {
  input! {
    N: usize,
  }
  let (mut A, mut B): (Vec<i32>, Vec<i32>) = {
    input! {
	  AB: [(i32, i32); N],
    }
    AB.into_iter().unzip()
  };
  A.sort();
  B.sort();
  let result = if N % 2 == 1 {
    let a = A[N / 2];
    let b = B[N / 2];
    b - a + 1
  } else {
    let a = A[N / 2 - 1] + A[N / 2];
    let b = B[N / 2 - 1] + B[N / 2];
    b - a + 1
  };
  println!("{}", result);
}