Problem:
Score : 300 points

Problem Statement

We have two permutations P and Q of size N (that is, P and Q are both rearrangements of (1,~2,~...,~N)).

There are N! possible permutations of size N. Among them, let P and Q be the a-th and b-th lexicographically smallest permutations, respectively. Find |a - b|.

Notes

For two sequences X and Y, X is said to be lexicographically smaller than Y if and only if there exists an integer k such that X_i = Y_i~(1 \leq i < k) and X_k < Y_k.

Constraints

2 \leq N \leq 8

P and Q are permutations of size N.

Input

Input is given from Standard Input in the following format:

N
P_1 P_2 ... P_N
Q_1 Q_2 ... Q_N

Output

Print |a - b|.

Sample Input 1

3
1 3 2
3 1 2

Sample Output 1

3

There are 6 permutations of size 3: (1,~2,~3), (1,~3,~2), (2,~1,~3), (2,~3,~1), (3,~1,~2), and (3,~2,~1). Among them, (1,~3,~2) and (3,~1,~2) come 2-nd and 5-th in lexicographical order, so the answer is |2 - 5| = 3.

Sample Input 2

8
7 3 5 4 2 1 6 8
3 8 2 5 4 6 7 1

Sample Output 2

17517

Sample Input 3

3
1 2 3
1 2 3

Sample Output 3

0

Solution in Rust (1.15.1) (judge verdict: Accepted)

#[allow(unused_imports)]
use std::char::*;
#[allow(unused_imports)]
use std::cmp::*;
#[allow(unused_imports)]
use std::collections::*;
use std::io::*;
use std::str::FromStr;

#[allow(unused_macros)]
macro_rules! debug {($($a:expr),*) => {println!(concat!($(stringify!($a), " = {:?}, "),*), $($a),*);}}
#[allow(unused_macros)]
macro_rules! input {(source=$s:expr,$($r:tt)*) => {let mut iter=$s.split_whitespace(); let mut next=||{iter.next().unwrap()}; input_inner! {next,$($r)*}};($($r:tt)*) => {let stdin=std::io::stdin();let mut bytes=std::io::Read::bytes(std::io::BufReader::new(stdin.lock())); let mut next=move||->String{bytes.by_ref().map(|r|r.unwrap() as char).skip_while(|c|c.is_whitespace()).take_while(|c|!c.is_whitespace()).collect()}; input_inner! {next,$($r)*}};}
#[allow(unused_macros)]
macro_rules! input_inner {($next:expr) => {}; ($next:expr,) => {}; ($next:expr,$var:ident:$t:tt$($r:tt)*) => {let $var=read_value!($next,$t); input_inner! {$next$($r)*}};}
#[allow(unused_macros)]
macro_rules! read_value {($next:expr,($($t:tt),*)) => {($(read_value! ($next,$t)),*)}; ($next:expr, [$t:tt; $len:expr]) => {(0..$len).map(|_|read_value! ($next,$t)).collect::<Vec<_>>()}; ($next:expr,chars) => {read_value! ($next,String).chars().collect::<Vec<char>>()}; ($next:expr,usize1) => {read_value! ($next,usize)-1}; ($next:expr,$t:ty) => {$next().parse::<$t>().expect("Parse error")};}

#[derive(PartialEq, PartialOrd)]
pub struct Total<T>(pub T);
impl<T: PartialEq> Eq for Total<T> {}
impl<T: PartialOrd> Ord for Total<T> {
    fn cmp(&self, other: &Total<T>) -> std::cmp::Ordering {
        self.0.partial_cmp(&other.0).unwrap()
    }
}

#[allow(dead_code)]
const MAX: usize = 100006;
#[allow(dead_code)]
const INF_U32: u32 = 1 << 31;
#[allow(dead_code)]
const INF_I32: i32 = 1 << 30;
#[allow(dead_code)]
const INF_U64: u64 = 1 << 63;
#[allow(dead_code)]
const INF_I64: i64 = 1 << 62;
#[allow(dead_code)]
const MOD: i64 = 1e9 as i64 + 7;

#[allow(dead_code)]
fn read<T: FromStr>() -> T {
    let stdin = stdin();
    let stdin = stdin.lock();
    let token: String = stdin
        .bytes()
        .map(|c| c.expect("failed to read char") as char)
        .skip_while(|c| c.is_whitespace())
        .take_while(|c| !c.is_whitespace())
        .collect();
    token.parse().ok().expect("failed to parse token")
}

#[allow(dead_code)]
fn read_vec<T: std::str::FromStr>() -> Vec<T> {
    let mut s = String::new();
    std::io::stdin().read_line(&mut s).ok();
    s.trim()
        .split_whitespace()
        .map(|e| e.parse().ok().unwrap())
        .collect()
}

#[allow(unused_imports)]
use std::f64;

pub trait LexicalPermutation {
    fn next_permutation(&mut self) -> bool;
    fn prev_permutation(&mut self) -> bool;
}

impl<T> LexicalPermutation for [T] where T: Ord {
    fn next_permutation(&mut self) -> bool {
        if self.len() < 2 { return false; }
        let mut i = self.len() - 1;
        while i > 0 && self[i-1] >= self[i] {
            i -= 1;
        }
        if i == 0 {
            return false;
        }
        let mut j = self.len() - 1;
        while j >= i && self[j] <= self[i-1]  {
            j -= 1;
        }
        self.swap(j, i-1);
        self[i..].reverse();
        true
    }

    fn prev_permutation(&mut self) -> bool {
        if self.len() < 2 { return false; }
        let mut i = self.len() - 1;
        while i > 0 && self[i-1] <= self[i] {
            i -= 1;
        }
        if i == 0 {
            return false;
        }
        self[i..].reverse();
        let mut j = self.len() - 1;
        while j >= i && self[j-1] < self[i-1]  {
            j -= 1;
        }
        self.swap(i-1, j);
        true
    }
}

fn main() {
    input!{n:usize, p:[i64;n], q:[i64;n]};
    let mut a = 0i64;
    let mut b = 0i64;
    let mut v:Vec<i64> = (1..n+1).map(|x| x as i64).collect();

    let mut c = 0;
    while v.next_permutation() {
        c += 1;
        if v == p { a = c; }
        if v == q { b = c; }
    }

    println!("{}", (a-b).abs());
}