Problem:
Score : 200 points

Problem Statement

Let S(n) denote the sum of the digits in the decimal notation of n.
For example, S(101) = 1 + 0 + 1 = 2.

Given an integer N, determine if S(N) divides N.

Constraints

1 \leq N \leq 10^9

Input

Input is given from Standard Input in the following format:

N

Output

If S(N) divides N, print Yes; if it does not, print No.

Sample Input 1

12

Sample Output 1

Yes

In this input, N=12.
As S(12) = 1 + 2 = 3, S(N) divides N.

Sample Input 2

101

Sample Output 2

No

As S(101) = 1 + 0 + 1 = 2, S(N) does not divide N.

Sample Input 3

999999999

Sample Output 3

Yes

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::io::*;
use std::str::FromStr;

fn read<T: FromStr>() -> T {
    let stdin = stdin();
    let stdin = stdin.lock();
    let token: String = stdin.bytes().map(|c| c.expect("failed to read char") as char).skip_while(|c| c.is_whitespace()).take_while(|c| !c.is_whitespace()).collect();
    token.parse().ok().expect("failed to parse token")
}

fn s(n: u32) -> u32 {
    let mut sum: u32 = 0;
    for b in format!("{}", n).chars() { sum += b as u32 - 48; }
    sum
}

fn main() {
    let n: u32 = read();
    println!("{}", if n % s(n) == 0 { "Yes" } else { "No" });
}