Problem:
Score : 600 points

Problem Statement

We have a tree with N vertices, whose i-th edge connects Vertex u_i and Vertex v_i.
Vertex i has an integer a_i written on it.
For every integer k from 1 through N, solve the following problem:

We will make a sequence by lining up the integers written on the vertices along the shortest path from Vertex 1 to Vertex k, in the order they appear. Find the length of the longest increasing subsequence of this sequence.

Here, the longest increasing subsequence of a sequence A of length L is the subsequence A_{i_1} , A_{i_2} , ... , A_{i_M} with the greatest possible value of M such that 1 \leq i_1 < i_2 < ... < i_M \leq L and A_{i_1} < A_{i_2} < ... < A_{i_M}.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq a_i \leq 10^9

1 \leq u_i , v_i \leq N

u_i \neq v_i

The given graph is a tree.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N
u_1 v_1
u_2 v_2
:
u_{N-1} v_{N-1}

Output

Print N lines. The k-th line, print the length of the longest increasing subsequence of the sequence obtained from the shortest path from Vertex 1 to Vertex k.

Sample Input 1

10
1 2 5 3 4 6 7 3 2 4
1 2
2 3
3 4
4 5
3 6
6 7
1 8
8 9
9 10

Sample Output 1

1
2
3
3
4
4
5
2
2
3

For example, the sequence A obtained from the shortest path from Vertex 1 to Vertex 5 is 1,2,5,3,4. Its longest increasing subsequence is A_1, A_2, A_4, A_5, with the length of 4.

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

#![allow(unused)]

fn solve<R: std::io::BufRead>(mut sc: Scanner<R>) {
    let n: usize = sc.get();
    let avec: Vec<i64> = (0..n).map(|_| sc.get()).collect();
    let edges: Vec<(usize, usize)> =
        (0..(n - 1)).map(|_| (sc.get(), sc.get())).collect();

    let mut g = vec![vec![]; n];
    for (u, v) in edges {
        g[u - 1].push(v - 1);
        g[v - 1].push(u - 1);
    }

    let mut lens = vec![0; n];
    let mut dp = vec![std::i64::MAX; n];
    let mut visited = vec![false; n];
    let mut frontiers = vec![vec![0]];
    let mut rollback = vec![];

    while !frontiers.is_empty() {
        if let Some(u) = frontiers.last_mut().unwrap().pop() {
            if !visited[u] {
                visited[u] = true;
                frontiers.push(g[u].clone());

                let i = match dp.binary_search(&avec[u]) {
                    Ok(i) => i,
                    Err(i) => i,
                };
                rollback.push((i, dp[i]));
                dp[i] = avec[u];
                lens[u] = i + 1;
            }
        } else {
            frontiers.pop();
            if !frontiers.is_empty() {
                let (i, val) = rollback.pop().unwrap();
                dp[i] = val;
            }
        }
    }

    for i in 0..n {
        println!("{}", lens[i]);
    }
}

//
// Based on EbTech's Scanner https://stackoverflow.com/q/56449027
//
struct Scanner<'a, R: std::io::BufRead> {
    reader: R,
    buf: String,
    iter: std::str::SplitWhitespace<'a>,
}

impl<'a, R: std::io::BufRead> Scanner<'a, R> {
    fn new(reader: R) -> Self {
        Self { reader, buf: String::new(), iter: "".split_whitespace() }
    }

    fn get<T: std::str::FromStr>(&mut self) -> T {
        if let Some(t) = self.iter.next() {
            return t.parse().ok().expect("Parse error")
        }
        self.buf.clear();
        self.reader.read_line(&mut self.buf).expect("I/O error");
        self.iter = unsafe { std::mem::transmute(self.buf.split_whitespace()) };
        self.get()
    }

    fn gets<T: std::iter::FromIterator<char>>(&mut self) -> T {
        use std::io::Read;
        assert_eq!(self.iter.next(), None);
        self.reader
            .by_ref()
            .bytes()
            .map(|b| b.unwrap() as char)
            .skip_while(|&c| c.is_whitespace())
            .take_while(|&c| !c.is_whitespace())
            .collect()
    }
}

fn main() {
    let stdin = std::io::stdin();
    solve(Scanner::new(stdin.lock()));
}