Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

use std::io;
use std::str::FromStr;
use std::collections::HashMap;

fn input_char_vec() -> Vec<char> {
    let mut line: String = String::new();
    io::stdin().read_line(&mut line);
    line.trim().chars().collect()
}

fn main() {
    let s = input_char_vec();
    let t = input_char_vec();
    let mut map: Vec<char> = vec!['0'; 26];
    for i in 0..s.len() {
        // println!("{:?}", map);
        if map[t[i] as usize - 'a' as usize] != '0' {
            if map[t[i] as usize - 'a' as usize] != s[i] {
                println!("No");
                return;                    
            }
        } else {
            if s[i] != t[i] {
                map[t[i] as usize - 'a' as usize] = s[i];
            }
        }
    }
    println!("Yes");
}