Problem:
Score : 300 points

Problem Statement

Takahashi has N balls. Initially, an integer A_i is written on the i-th ball.

He would like to rewrite the integer on some balls so that there are at most K different integers written on the N balls.

Find the minimum number of balls that Takahashi needs to rewrite the integers on them.

Constraints

1 \leq K \leq N \leq 200000

1 \leq A_i \leq N

All input values are integers.

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 ... A_N

Output

Print the minimum number of balls that Takahashi needs to rewrite the integers on them.

Sample Input 1

5 2
1 1 2 2 5

Sample Output 1

1

For example, if we rewrite the integer on the fifth ball to 2, there are two different integers written on the balls: 1 and 2.
On the other hand, it is not possible to rewrite the integers on zero balls so that there are at most two different integers written on the balls, so we should print 1.

Sample Input 2

4 4
1 1 2 2

Sample Output 2

0

Already in the beginning, there are two different integers written on the balls, so we do not need to rewrite anything.

Sample Input 3

10 3
5 1 3 2 4 1 1 2 3 4

Sample Output 3

3

Solution in Rust (1.42.0) (judge verdict: Accepted)

use std::io::*;
use std::str::FromStr;
use std::collections::HashMap;

//https://qiita.com/tubo28/items/e6076e9040da57368845
fn read<T: FromStr>() -> T {
    let stdin = stdin();
    let stdin = stdin.lock();
    let token: String = stdin
        .bytes()
        .map(|c| c.expect("failed to read char") as char)
        .skip_while(|c| c.is_whitespace())
        .take_while(|c| !c.is_whitespace())
        .collect();
    token.parse().ok().expect("failed to parse token")
}

//refer
//https://atcoder.jp/contests/arc086/submissions/14591609
fn main() {
    let n: usize = read();
    let k: usize = read();
    let a: Vec<u64> = (0..n).map(|_| read()).collect();

    let mut map = HashMap::new();

    //集約処理
    for v in a.into_iter(){
        let count = map.entry(v).or_insert(0);
        *count += 1;
    }

    //集約処理したvalueをVecで取得
    let mut syuuyaku: Vec<u64> = map.values().map(|&n| n).collect();
    //昇順ソート
    syuuyaku.sort();

    if syuuyaku.len() <= k {
        println!("0");
    }else{
        //変更必要な数字の種類を求める
        let diff = syuuyaku.len() - k;
        //diffのインデックスまでの数値を足し込む、これが解答
        let ans:u64 = syuuyaku.iter().take(diff).sum();
        println!("{}",ans);
    }

}