Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Rust (1.15.1) (judge verdict: Wrong Answer)

use std::str::FromStr;

fn get_one<T : FromStr>() -> T {
    let mut s = String::new();
    std::io::stdin().read_line(&mut s).ok();
    return s.trim().parse().ok().unwrap();
}

fn get_vec<T : FromStr>() -> Vec<T> {
    let mut s = String::new();
    std::io::stdin().read_line(&mut s).ok();
    return s.trim().split_whitespace().map(|e| e.parse().ok().unwrap()).collect();
}

fn main() {
    let mut mat1 : Vec<Vec<i32>> = Vec::new();
    for _i in 0..3 {
        let v : Vec<i32> = get_vec();
        mat1.push(v);
    }
    let n : usize = get_one();
    let mut tfs = vec!(vec!(false;3);3);
    for i in 0..n {
        let x : i32 = get_one();
        for j in 0..3 {
            for k in 0..3 {
                if x == mat1[j][k] {
                    tfs[j][k] = true;
                }
            }
        }
    }
    let mut ans = false;
    for i in 0..3 {
        let mut la = true;
        for j in 0..3 {
            if tfs[i][j] == false {
                la = false;
                break;
            }
        }
        if la == true {
            ans = true;
            break;
        }
    }
    for i in 0..3 {
        let mut la = true;
        for j in 0..3 {
            if tfs[j][i] == false{
                la = false;
                break;
            }
        }
        if la == true {
            ans = true;
            break;
        }
    }
    for i in 0..3 {
        let mut la = true;
        if tfs[i][i] == false {
            la = false;
            break;
        }
        if la == true {
            ans = true;
            break;
        }
    }
    println!("{}", if ans {"Yes"} else {"No"});
}