Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::io::*;
use std::str::*;

fn scan_token<T: FromStr>() -> T {
    stdin().bytes()
        .map(|c| c.unwrap() as char)
        .skip_while(|c| c.is_whitespace())
        .take_while(|c| !c.is_whitespace())
        .collect::<String>()
        .parse::<T>().ok().unwrap()
}

fn scan_line<T: FromStr>() -> Vec<T> {
    let mut buf = String::new();
    stdin().read_line(&mut buf).unwrap();
    buf.split_whitespace().map( |token| token.parse::<T>().ok().unwrap() ).collect()
}

fn count_divisor(x: i32) -> i32 {
    let mut count = 0;
    for d in 1..x+1 {
        if x % d == 0 {
            count += 1;
        }
    }
    count
}

fn main() {
    let n: i32 = scan_token();

    let mut ans = 0;

    for x in 1..n+1 {
        if x % 2 == 1 && count_divisor(x) == 8 {
            ans += 1;
        }
    }
    println!("{}", ans);
}