Problem:
Score : 100 points

Problem Statement

Two deer, AtCoDeer and TopCoDeer, are playing a game called Honest or Dishonest.
In this game, an honest player always tells the truth, and an dishonest player always tell lies.
You are given two characters a and b as the input. Each of them is either H or D, and carries the following information:

If a=H, AtCoDeer is honest; if a=D, AtCoDeer is dishonest.
If b=H, AtCoDeer is saying that TopCoDeer is honest; if b=D, AtCoDeer is saying that TopCoDeer is dishonest.

Given this information, determine whether TopCoDeer is honest.

Constraints

a=H or a=D.

b=H or b=D.

Input

The input is given from Standard Input in the following format:

a b

Output

If TopCoDeer is honest, print H. If he is dishonest, print D.

Sample Input 1

H H

Sample Output 1

H

In this input, AtCoDeer is honest. Hence, as he says, TopCoDeer is honest.

Sample Input 2

D H

Sample Output 2

D

In this input, AtCoDeer is dishonest. Hence, contrary to what he says, TopCoDeer is dishonest.

Sample Input 3

D D

Sample Output 3

H

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::io;

fn main() {
    let ab: Vec<String> = read_input_vec();
    if ab[0] == ab[1] {
        println!("H");
    } else {
        println!("D");
    }
}

fn read_input<T: std::str::FromStr>() -> T {
    let mut input = String::new();
    io::stdin().read_line(&mut input).unwrap();
    return input.parse::<T>().ok().unwrap();
}

fn read_input_vec<T: std::str::FromStr>() -> Vec<T> {
    let mut input = String::new();
    io::stdin().read_line(&mut input).unwrap();
    return input
        .split_whitespace()
        .map(|x| x.parse::<T>().ok().unwrap())
        .collect();
}