Problem:
Score : 500 points

Problem Statement

There are N points on the 2D plane, i-th of which is located on (x_i, y_i).
There can be multiple points that share the same coordinate.
What is the maximum possible Manhattan distance between two distinct points?

Here, the Manhattan distance between two points (x_i, y_i) and (x_j, y_j) is defined by |x_i-x_j| + |y_i-y_j|.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq x_i,y_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
x_1 y_1
x_2 y_2
:
x_N y_N

Output

Print the answer.

Sample Input 1

3
1 1
2 4
3 2

Sample Output 1

4

The Manhattan distance between the first point and the second point is |1-2|+|1-4|=4, which is maximum possible.

Sample Input 2

2
1 1
1 1

Sample Output 2

0

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

use proconio::{fastout, input};

#[fastout]
fn main() {
    input! {
        n: usize,
        xy: [(i128, i128); n]
    };

    let mut xy: Vec<(i128, i128)> = xy;
    let mut v: Vec<(i128, i128, i128)> = vec![];

    for i in xy.iter() {
        v.push((i.0, i.1, i.0 + i.1))
    }
    v.sort_by(|a, b| a.2.cmp(&b.2).then(a.0.cmp(&b.0)).then(a.1.cmp(&b.1)));

    let first = v[0];
    let last = v.last().unwrap();
    println!("{}", (first.0 - last.0).abs() + (first.1 - last.1).abs());
}