Problem:
Score : 300 points

Problem Statement

To make it difficult to withdraw money, a certain bank allows its customers to withdraw only one of the following amounts in one operation:

1 yen (the currency of Japan)

6 yen, 6^2(=36) yen, 6^3(=216) yen, ...

9 yen, 9^2(=81) yen, 9^3(=729) yen, ...

At least how many operations are required to withdraw exactly N yen in total?

It is not allowed to re-deposit the money you withdrew.

Constraints

1 \leq N \leq 100000

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If at least x operations are required to withdraw exactly N yen in total, print x.

Sample Input 1

127

Sample Output 1

4

By withdrawing 1 yen, 9 yen, 36(=6^2) yen and 81(=9^2) yen, we can withdraw 127 yen in four operations.

Sample Input 2

3

Sample Output 2

3

By withdrawing 1 yen three times, we can withdraw 3 yen in three operations.

Sample Input 3

44852

Sample Output 3

16

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::cmp::min;

/// ローカル環境なら _in.txt から入力を受ける
fn read_input() -> String {
    use std::fs::File;
    use std::io::Read;
    let mut s = String::new();
    match option_env!("LOCAL") {
        Some(_) => File::open("src/_in.txt")
            .expect("File not found")
            .read_to_string(&mut s)
            .unwrap(),
        None => std::io::stdin().read_to_string(&mut s).unwrap(),
    };
    s
}

fn solve(n: i32) -> i32 {
    let n = n as usize;
    let mut withdraws = vec![];
    for i in 0..10 {
        if usize::pow(6, i) <= n {
            withdraws.push(usize::pow(6, i));
        }
        if usize::pow(9, i) <= n {
            withdraws.push(usize::pow(9, i));
        }
    }

    let mut dp = vec![i32::pow(10, 9); n as usize + 1];
    dp[0] = 0;
    for i in 0..n {
        for w in &withdraws {
            if i + w <= n {
                dp[i + w] = min(dp[i + w], dp[i] + 1)
            }
        }
    }
    dp[n]
}

fn main() {
    let s = read_input();
    let mut ws = s.split_whitespace();
    let in_n: i32 = ws.next().unwrap().parse().unwrap();
    let ans = solve(in_n);
    println!("{:?}", ans);
}