Problem:
Score : 200 points

Problem Statement

There are N gems. The value of the i-th gem is V_i.

You will choose some of these gems, possibly all or none, and get them.

However, you need to pay a cost of C_i to get the i-th gem.

Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.

Find the maximum possible value of X-Y.

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq C_i, V_i \leq 50

Input

Input is given from Standard Input in the following format:

N
V_1 V_2 ... V_N
C_1 C_2 ... C_N

Output

Print the maximum possible value of X-Y.

Sample Input 1

3
10 2 5
6 3 4

Sample Output 1

5

If we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.
We have X-Y = 5 here, which is the maximum possible value.

Sample Input 2

4
13 21 6 19
11 30 6 15

Sample Output 2

6

Sample Input 3

1
1
50

Sample Output 3

0

Solution in Rust (1.15.1) (judge verdict: Accepted)

fn main() {
    let mut true_value = {
        let mut temp_vec = Vec::<i32>::new();

        let n: usize = read();
        let v = read_vec::<i32>();
        let c = read_vec::<i32>();

        for i in 0..n {
            temp_vec.push(v[i] - c[i]);
        }

        temp_vec
    };

    let max: i32 = true_value.into_iter()
        .filter(|&x| { x > 0 })
        .sum();

    println!("{}", max);
}

#[warn(dead_code)]
fn read<T: std::str::FromStr>() -> T {
    let mut s = String::new();
    std::io::stdin().read_line(&mut s).ok();
    s.trim().parse().ok().unwrap()
}

#[warn(dead_code)]
fn read_vec<T: std::str::FromStr>() -> Vec<T> {
    let mut s = String::new();
    std::io::stdin().read_line(&mut s).ok();
    s.trim().split_whitespace()
        .map(|e| e.parse().ok().unwrap()).collect()
}

#[warn(dead_code)]
fn read_mat<T: std::str::FromStr>(row: u32) -> Vec<Vec<T>> {
    let mut vec = Vec::new();

    for _i in 0..row {
        vec.push(read_vec::<T>());
    }

    vec
}