Problem:
Score : 700 points

Problem Statement

You are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W).
Determine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:

The matrix has H rows and W columns.

Each element of the matrix is an integer between -10^9 and 10^9 (inclusive).

The sum of all the elements of the matrix is positive.

The sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.

Constraints

1 ≤ h ≤ H ≤ 500

1 ≤ w ≤ W ≤ 500

Input

Input is given from Standard Input in the following format:

H W h w

Output

If there does not exist a matrix that satisfies all of the conditions, print No.

Otherwise, print Yes in the first line, and print a matrix in the subsequent lines in the following format:

a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}

Here, a_{ij} represents the (i,\ j) element of the matrix.

Sample Input 1

3 3 2 2

Sample Output 1

Yes
1 1 1
1 -4 1
1 1 1

The sum of all the elements of this matrix is 4, which is positive.
Also, in this matrix, there are four subrectangles with 2 rows and 2 columns as shown below. For each of them, the sum of all the elements inside is -1, which is negative.

Sample Input 2

2 4 1 2

Sample Output 2

No

Sample Input 3

3 4 2 3

Sample Output 3

Yes
2 -5 8 7
3 -5 -4 -5
2 1 -1 7

Solution in Rust (1.15.1) (judge verdict: Wrong Answer)

use std::io::Read;

#[allow(non_snake_case)]
fn main() {
    let mut buf = String::new();
    std::io::stdin().read_to_string(&mut buf).unwrap();
    let mut iter = buf.split_whitespace();

    let H: i32 = iter.next().unwrap().parse().unwrap();
    let W: i32 = iter.next().unwrap().parse().unwrap();
    let h: i32 = iter.next().unwrap().parse().unwrap();
    let w: i32 = iter.next().unwrap().parse().unwrap();

    if H % h != 0 {
        println!("Yes");
        for i in 0..H {
            for j in 0..W {
                if j > 0 {
                    print!(" ");
                }
                if i % h == 0 {
                    print!("{}", H - 1);
                } else if i % h == 1 {
                    print!("{}", -H);
                } else {
                    print!("0");
                }
            }
            println!();
        }
    } else if W % w != 0 {
        println!("Yes");
        for i in 0..H {
            for j in 0..W {
                if j > 0 {
                    print!(" ");
                }
                if j % w == 0 {
                    print!("{}", W - 1);
                } else if j % w == 1 {
                    print!("{}", -W);
                } else {
                    print!("0");
                }
            }
            println!();
        }
    } else {
        println!("No");
    }
}