Problem:
Score : 200 points

Problem Statement

Raccoon is fighting with a monster.

The health of the monster is H.

Raccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i.
There is no other way to decrease the monster's health.

Raccoon wins when the monster's health becomes 0 or below.

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Constraints

1 \leq H \leq 10^9

1 \leq N \leq 10^5

1 \leq A_i \leq 10^4

All values in input are integers.

Input

Input is given from Standard Input in the following format:

H N
A_1 A_2 ... A_N

Output

If Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.

Sample Input 1

10 3
4 5 6

Sample Output 1

Yes

The monster's health will become 0 or below after, for example, using the second and third moves.

Sample Input 2

20 3
4 5 6

Sample Output 2

No

Sample Input 3

210 5
31 41 59 26 53

Sample Output 3

Yes

Sample Input 4

211 5
31 41 59 26 53

Sample Output 4

No

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::collections::BinaryHeap;

fn main() {
    let mut input = String::new();
    std::io::stdin().read_line(&mut input);
    let mut vec = Vec::with_capacity(2);
    vec = input
        .split_whitespace()
        .map(|x| x.parse().unwrap())
        .collect::<Vec<i32>>();
    let mut data = BinaryHeap::with_capacity(vec[1] as usize);
    input.clear();
    std::io::stdin().read_line(&mut input);
    data = input
        .split_whitespace()
        .map(|x| x.parse().unwrap())
        .collect::<BinaryHeap<i32>>();
    let mut sum = 0;
    let length = data.len() / 4;
    // let remainder = data.len() % 4;
    for i in 0..3 {
        for i in 0..length {
            sum += data.pop().unwrap();
        }
        if sum >= vec[0] {
            println!("Yes");
            return;
        }
    }
    while !data.is_empty() {
        sum += data.pop().unwrap();
    }
    if sum >= vec[0] {
        println!("Yes");
        return;
    }
    println!("No");
}