Problem:
Score : 100 points

Problem Statement

In programming, hexadecimal notation is often used.

In hexadecimal notation, besides the ten digits 0, 1, ..., 9, the six letters A, B, C, D, E and F are used to represent the values 10, 11, 12, 13, 14 and 15, respectively.

In this problem, you are given two letters X and Y. Each X and Y is A, B, C, D, E or F.

When X and Y are seen as hexadecimal numbers, which is larger?

Constraints

Each X and Y is A, B, C, D, E or F.

Input

Input is given from Standard Input in the following format:

X Y

Output

If X is smaller, print <; if Y is smaller, print >; if they are equal, print =.

Sample Input 1

A B

Sample Output 1

<

10 < 11.

Sample Input 2

E C

Sample Output 2

>

14 > 12.

Sample Input 3

F F

Sample Output 3

=

15 = 15.

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::io::{stdin, Read, StdinLock};
use std::str::FromStr;
use std::vec::Vec;
use std::{vec, cmp, num};


struct Scanner<'a> {
    cin: StdinLock<'a>,
}

impl<'a> Scanner<'a> {
    fn new(cin: StdinLock<'a>) -> Scanner<'a> {
        Scanner {cin: cin}
    }

    fn read1<T: FromStr>(&mut self) -> Option<T> {
        let token = self.cin.by_ref().bytes().map(|c| c.unwrap() as char)
                    .skip_while(|c| c.is_whitespace())
                    .take_while(|c| !c.is_whitespace())
                    .collect::<String>();
        token.parse::<T>().ok()
    }

    fn read<T: FromStr>(&mut self) -> T {
        self.read1().unwrap()
    }
}

// create Vec<char> from String
#[allow(dead_code)]
fn to_chars(s: String) -> vec::Vec<char> {
    let mut cs = s.chars();
    let mut res = vec::Vec::new();
    while let Some(c) = cs.next() {
        res.push(c);
    }
    res
}

fn main() {
    let cin = stdin();
    let cin = cin.lock();
    let mut sc = Scanner::new(cin);
    let mut x: String = sc.read();
    let mut y: String = sc.read();
    let f = "ABCDEF";
    let x = x.pop().expect("");
    let y = y.pop().expect("");
    if f.find(x) < f.find(y) {
        println!("<");
    } else if f.find(x) == f.find(y) {
        println!("=");
    } else {
        println!(">");
    }
}