Problem:
Score : 200 points

Problem Statement

It is November 18 now in Japan. By the way, 11 and 18 are adjacent Lucas numbers.

You are given an integer N. Find the N-th Lucas number.

Here, the i-th Lucas number L_i is defined as follows:

L_0=2

L_1=1

L_i=L_{i-1}+L_{i-2} (i≥2)

Constraints

1≤N≤86

It is guaranteed that the answer is less than 10^{18}.

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print the N-th Lucas number.

Sample Input 1

5

Sample Output 1

11

L_0=2

L_1=1

L_2=L_0+L_1=3

L_3=L_1+L_2=4

L_4=L_2+L_3=7

L_5=L_3+L_4=11

Thus, the 5-th Lucas number is 11.

Sample Input 2

86

Sample Output 2

939587134549734843

Solution in Rust (1.15.1) (judge verdict: Accepted)

#[allow(unused_imports)]
use std::io::{stdin, Read, StdinLock};
#[allow(unused_imports)]
use std::cmp::{max, min, Ordering};
#[allow(unused_imports)]
use std::str::FromStr;
#[allow(unused_imports)]
use std::collections::{HashSet, HashMap, BinaryHeap};
#[allow(unused_imports)]
use std::vec::Vec;

#[allow(dead_code)]
const INF: i32 = 1000_000_000;
#[allow(dead_code)]
const INFLL: i64 = 1000_000_000_000_000_000;
#[allow(dead_code)]
const EPS: f64 = 1.0e-10;

struct Scanner<'a> {
    cin: StdinLock<'a>,
}

impl<'a> Scanner<'a> {
    #[allow(dead_code)]
    fn new(cin: StdinLock<'a>) -> Scanner<'a> {
        Scanner {cin: cin}
    }

    #[allow(dead_code)]
    fn read1<T: FromStr>(&mut self) -> Option<T> {
        let token = self.cin.by_ref().bytes().map(|c| c.unwrap() as char)
                    .skip_while(|c| c.is_whitespace())
                    .take_while(|c| !c.is_whitespace())
                    .collect::<String>();
        token.parse::<T>().ok()
    }

    #[allow(dead_code)]
    fn read<T: FromStr>(&mut self) -> T {
        self.read1().unwrap()
    }
}

fn main() {
    let cin = stdin();
    let cin = cin.lock();
    let mut sc = Scanner::new(cin);
    let n: usize = sc.read();
    let mut lucas: Vec<i64> = vec![2, 1];
    for _i in 0..85 {
        let m = lucas.len();
        let l1 = lucas[m - 1];
        let l2 = lucas[m - 2];
        lucas.push(l1 + l2);
    }
    println!("{}", lucas[n]);
}