Problem:
Score : 200 points

Problem Statement

The word internationalization is sometimes abbreviated to i18n.
This comes from the fact that there are 18 letters between the first i and the last n.

You are given a string s of length at least 3 consisting of lowercase English letters.
Abbreviate s in the same way.

Constraints

3 ≤ |s| ≤ 100 (|s| denotes the length of s.)

s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s

Output

Print the abbreviation of s.

Sample Input 1

internationalization

Sample Output 1

i18n

Sample Input 2

smiles

Sample Output 2

s4s

Sample Input 3

xyz

Sample Output 3

x1z

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::io::*;
use std::io;
use std::str::FromStr;
fn read(s: &mut StdinLock) -> u32 {
    s.by_ref()
        .bytes()
        .map(|c| c.unwrap() as char)
        .skip_while(|c| c.is_whitespace())
        .take_while(|c| !c.is_whitespace())
        .fold(0, |a, x| (x as u8 - b'0') as u32 + a * 10)
}

fn main() {
    let stdin = io::stdin();
    let mut buf = String::new();
    stdin.read_line(&mut buf).ok();

    let mut it = buf.split_whitespace().map(|n| String::from_str(n).unwrap());
    let s = it.next().unwrap();
    println!(
        "{}{}{}",
        s.chars().nth(0).unwrap(),
        s.len() - 2,
        s.chars().nth(s.len() - 1).unwrap()
    );

}