Problem:
Score : 500 points

Problem Statement

Takahashi has a string S of length N consisting of digits from 0 through 9.

He loves the prime number P. He wants to know how many non-empty (contiguous) substrings of S - there are N \times (N + 1) / 2 of them - are divisible by P when regarded as integers written in base ten.

Here substrings starting with a 0 also count, and substrings originated from different positions in S are distinguished, even if they are equal as strings or integers.

Compute this count to help Takahashi.

Constraints

1 \leq N \leq 2 \times 10^5

S consists of digits.

|S| = N

2 \leq P \leq 10000

P is a prime number.

Input

Input is given from Standard Input in the following format:

N P
S

Output

Print the number of non-empty (contiguous) substrings of S that are divisible by P when regarded as an integer written in base ten.

Sample Input 1

4 3
3543

Sample Output 1

6

Here S = 3543. There are ten non-empty (contiguous) substrings of S:

3: divisible by 3.

35: not divisible by 3.

354: divisible by 3.

3543: divisible by 3.

5: not divisible by 3.

54: divisible by 3.

543: divisible by 3.

4: not divisible by 3.

43: not divisible by 3.

3: divisible by 3.

Six of these are divisible by 3, so print 6.

Sample Input 2

4 2
2020

Sample Output 2

10

Here S = 2020. There are ten non-empty (contiguous) substrings of S, all of which are divisible by 2, so print 10.

Note that substrings beginning with a 0 also count.

Sample Input 3

20 11
33883322005544116655

Sample Output 3

68

Solution in Rust (1.15.1) (judge verdict: Wrong Answer)

use std::collections::HashMap;
use std::io::{stdin, Read};

macro_rules! parse {
    ($it: ident) => {
        $it.next().unwrap().parse().unwrap()
    };
    ($it: ident,2) => {
        (parse!($it), parse!($it))
    };
    ($it: ident,3) => {
        (parse!($it), parse!($it), parse!($it))
    };
    ($it: ident,4) => {
        (parse!($it), parse!($it), parse!($it), parse!($it))
    };
    ($it: ident, $n: ident) => {
        (&mut $it).take($n).map(|e| e.parse().unwrap()).collect();
    };
}

fn main() {
    let mut s = String::new();
    stdin().read_to_string(&mut s).unwrap();
    let mut it = s.split_whitespace();
    let (n, p): (usize, usize) = parse!(it, 2);
    let s: Vec<usize> = it
        .next()
        .unwrap()
        .chars()
        .map(|x| x.to_digit(10).unwrap() as usize)
        .collect();
    let mut rp: Vec<usize> = vec![];
    let mut cur = 1;
    for _ in 0..n {
        rp.push(cur);
        cur = (cur * 10) % p;
    }
    let rv: Vec<usize> = s
        .iter()
        .enumerate()
        .scan(0, |s, (i, &x)| {
            let r = (*s + x * rp[n - i - 1]) % p;
            *s = r;
            Some(r)
        })
        .collect();
    let mut map: HashMap<usize, Vec<usize>> = HashMap::new();
    map.insert(0, vec![0]);
    for (i, &r) in rv.iter().enumerate() {
        let e = map.entry(r).or_insert(vec![]);
        e.push(i);
    }
    let mut ret = 0;
    for (k, v) in &map {
        let vl = v.len() - 1;
        let d = (vl + 1) * vl / 2;
        ret += d;
    }
    println!("{}", ret);
}