Problem:
Score : 400 points

Problem Statement

You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

In the i-th operation, you replace every element whose value is B_{i} with C_{i}.

For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

All values in input are integers.

1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}

B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:

N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}

Output

Print Q integers S_{i} to Standard Output in the following format:

S_{1}
S_{2}
\vdots
S_{Q}

Note that S_{i} may not fit into a 32-bit integer.

Sample Input 1

4
1 2 3 4
3
1 2
3 4
2 4

Sample Output 1

11
12
16

Initially, the sequence A is 1,2,3,4.

After each operation, it becomes the following:

2, 2, 3, 4

2, 2, 4, 4

4, 4, 4, 4

Sample Input 2

4
1 1 1 1
3
1 2
2 1
3 5

Sample Output 2

8
4
4

Note that the sequence A may not contain an element whose value is B_{i}.

Sample Input 3

2
1 2
3
1 100
2 100
100 1000

Sample Output 3

102
200
2000

Solution in Rust (1.42.0) (judge verdict: Accepted)

#![allow(unused_imports)]

//input
use proconio::input;
use proconio::marker::{Bytes, Chars};
//use std::io::Read;

//collections
//use std::collections::BTreeMap;
//use std::collections::BTreeSet;
use std::collections::HashMap;
//use std::collections::HashSet;
//use std::collections::VecDeque;
//use std::collections::BinaryHeap;

//use std::cmp::*;

fn main() {
    input! {
        n: usize,
        a: [u64;n],
    }

    input! {
        q: usize
    }

    let mut bs = vec![];
    let mut cs = vec![];

    for _ in 0..q {
        input! {
            b: u64,
            c: u64,
        }
        bs.push(b);
        cs.push(c);
    }

    let mut dic = HashMap::new();
    for x in a {
        *dic.entry(x).or_insert(0u64) += 1;
    }
    let mut sum: u64 = dic.iter().map(|(k, v)| k * v).sum();
    for i in 0..q {
        let tmp = *dic.entry(bs[i]).or_insert(0);
        *dic.entry(bs[i]).or_insert(0) = 0;
        *dic.entry(cs[i]).or_insert(0) += tmp;
        sum = sum - bs[i] * tmp + cs[i] * tmp;
        println!("{}", sum);
    }
}