Problem:
Score : 100 points

Problem Statement

Given an integer a as input, print the value a + a^2 + a^3.

Constraints

1 \leq a \leq 10

a is an integer.

Input

Input is given from Standard Input in the following format:

a

Output

Print the value a + a^2 + a^3 as an integer.

Sample Input 1

2

Sample Output 1

14

When a = 2, we have a + a^2 + a^3 = 2 + 2^2 + 2^3 = 2 + 4 + 8 = 14.

Print the answer as an input. Outputs such as 14.0 will be judged as incorrect.

Sample Input 2

10

Sample Output 2

1110

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

use std::io::*; //Not mine.
use std::str::FromStr;
fn read<T: FromStr>() -> T {
    let stdin = stdin();
    let stdin = stdin.lock();
    let token: String = stdin
        .bytes()
        .map(|c| c.expect("failed to read char") as char)
        .skip_while(|c| c.is_whitespace())
        .take_while(|c| !c.is_whitespace())
        .collect();
    token.parse().ok().expect("failed to parse token")
}
fn main() {
    let n: i64 = read();
    let mut list: Vec<i64> = vec![0; 10000001];
    for i in 1..n + 1 {
        let mut k = 1;
        while i * k <= n {
            list[(i * k) as usize] += 1;
            k += 1;
        }
    }
    let mut ans: i64 = 0;
    for i in 1..n + 1 {
        ans += i * (list[i as usize]);
    }
    println!("{}", ans);
}