Problem:
Score : 300 points

Problem Statement

You are given a string s.
Among the different substrings of s, print the K-th lexicographically smallest one.

A substring of s is a string obtained by taking out a non-empty contiguous part in s.
For example, if s = ababc, a, bab and ababc are substrings of s, while ac, z and an empty string are not.
Also, we say that substrings are different when they are different as strings.

Let X = x_{1}x_{2}...x_{n} and Y = y_{1}y_{2}...y_{m} be two distinct strings. X is lexicographically larger than Y if and only if Y is a prefix of X or x_{j} > y_{j} where j is the smallest integer such that x_{j} \neq y_{j}.

Constraints

1 ≤ |s| ≤ 5000

s consists of lowercase English letters.

1 ≤ K ≤ 5

s has at least K different substrings.

Partial Score

200 points will be awarded as a partial score for passing the test set satisfying |s| ≤ 50.

Input

Input is given from Standard Input in the following format:

s
K

Output

Print the K-th lexicographically smallest substring of K.

Sample Input 1

aba
4

Sample Output 1

b

s has five substrings: a, b, ab, ba and aba.
Among them, we should print the fourth smallest one, b.
Note that we do not count a twice.

Sample Input 2

atcoderandatcodeer
5

Sample Output 2

andat

Sample Input 3

z
1

Sample Output 3

z

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

use proconio::input;
use proconio::marker::Chars;
use std::collections::BTreeSet;

fn main() {
    input! {
        s: Chars,
        mut k: usize,
    }
    let mut ss = BTreeSet::new();

    for i in 0..s.len() {
        let mut s = s.clone();
        s.rotate_right(i);
        ss.insert(s);
    }

    let mut ans = String::new();

    let mut prev: Option<Vec<char>> = None;

    for s in ss {
        let index = if let Some(prev) = prev {
            let mut index = 0;
            for i in 0..s.len() {
                if s[i] != prev[i] {
                    index = i;
                    break;
                }
            }
            index
        } else { 0 };

        if s.len() >= k {
            for i in index..index+k {
                ans.push(s[i]);
            }
            break;
        }
        k -= s.len() - index;

        prev = Some(s);
    }

    println!("{}", ans);
}