Problem:
Score : 200 points

Problem Statement

There are N gems. The value of the i-th gem is V_i.

You will choose some of these gems, possibly all or none, and get them.

However, you need to pay a cost of C_i to get the i-th gem.

Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.

Find the maximum possible value of X-Y.

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq C_i, V_i \leq 50

Input

Input is given from Standard Input in the following format:

N
V_1 V_2 ... V_N
C_1 C_2 ... C_N

Output

Print the maximum possible value of X-Y.

Sample Input 1

3
10 2 5
6 3 4

Sample Output 1

5

If we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.
We have X-Y = 5 here, which is the maximum possible value.

Sample Input 2

4
13 21 6 19
11 30 6 15

Sample Output 2

6

Sample Input 3

1
1
50

Sample Output 3

0

Solution in Rust (1.15.1) (judge verdict: Accepted)

fn read<T: std::str::FromStr>() -> Vec<T>
where
    <T as std::str::FromStr>::Err: std::fmt::Debug,
{
    let mut b = String::new();
    std::io::stdin().read_line(&mut b).unwrap();
    b.split_whitespace()
        .map(|x| x.trim().parse::<T>().unwrap())
        .collect()
}

fn main() {
    let _ = read::<u64>()[0];
    let vi = read::<u64>();
    let ci = read::<u64>();
    let mut ans = 0;
    for i in 0..vi.len() {
        if vi[i] >= ci[i] {
            ans += vi[i] - ci[i];
        }
    }
    println!("{}", ans)
}