Problem:
Score : 300 points

Problem Statement

Given are positive integers N, M, Q, and Q quadruples of integers ( a_i , b_i , c_i , d_i ).

Consider a sequence A satisfying the following conditions:

A is a sequence of N positive integers.

1 \leq A_1 \leq A_2 \le \cdots \leq A_N \leq M.

Let us define a score of this sequence as follows:

The score is the sum of d_i over all indices i such that A_{b_i} - A_{a_i} = c_i. (If there is no such i, the score is 0.)

Find the maximum possible score of A.

Constraints

All values in input are integers.

2 ≤ N ≤ 10

1 \leq M \leq 10

1 \leq Q \leq 50

1 \leq a_i < b_i \leq N ( i = 1, 2, ..., Q )

0 \leq c_i \leq M - 1 ( i = 1, 2, ..., Q )

(a_i, b_i, c_i) \neq (a_j, b_j, c_j) (where i \neq j)

1 \leq d_i \leq 10^5 ( i = 1, 2, ..., Q )

Input

Input is given from Standard Input in the following format:

N M Q
a_1 b_1 c_1 d_1
:
a_Q b_Q c_Q d_Q

Output

Print the maximum possible score of A.

Sample Input 1

3 4 3
1 3 3 100
1 2 2 10
2 3 2 10

Sample Output 1

110

When A = \{1, 3, 4\}, its score is 110. Under these conditions, no sequence has a score greater than 110, so the answer is 110.

Sample Input 2

4 6 10
2 4 1 86568
1 4 0 90629
2 3 0 90310
3 4 1 29211
3 4 3 78537
3 4 2 8580
1 2 1 96263
1 4 2 2156
1 2 0 94325
1 4 3 94328

Sample Output 2

357500

Sample Input 3

10 10 1
1 10 9 1

Sample Output 3

1

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

use std::cmp::max;
use std::io::stdin;
use std::io::Read;
use std::io::StdinLock;
use std::str::FromStr;

fn read<T: FromStr>(s: &mut StdinLock) -> Option<T> {
  let s = s
    .by_ref()
    .bytes()
    .map(|c| c.unwrap() as char)
    .skip_while(|c| c.is_whitespace())
    .take_while(|c| !c.is_whitespace())
    .collect::<String>();
  s.parse::<T>().ok()
}

#[derive(Clone, Debug)]
struct Calculator {
  q: usize,
  a: Vec<usize>,
  b: Vec<usize>,
  c: Vec<i32>,
  d: Vec<i32>,
}

impl Calculator {
  fn new(q: usize, a: Vec<usize>, b: Vec<usize>, c: Vec<i32>, d: Vec<i32>) -> Self {
    Self {
      q: q,
      a: a,
      b: b,
      c: c,
      d: d,
    }
  }

  fn exec(self, vec: &mut Vec<i32>) -> i32 {
    let mut ans = 0;
    for i in 0..self.q {
      if vec[self.b[i as usize] - 1] - vec[self.a[i as usize] - 1] == self.c[i as usize] {
        ans += self.d[i as usize];
      }
    }
    ans
  }
}

fn main() {
  let s = stdin();
  let mut s = s.lock();
  let s = &mut s;
  let n = read::<i32>(s).unwrap();
  let m = read::<usize>(s).unwrap();
  let q = read::<usize>(s).unwrap();

  let mut a: Vec<usize> = Vec::with_capacity(q);
  let mut b: Vec<usize> = Vec::with_capacity(q);
  let mut c: Vec<i32> = Vec::with_capacity(q);
  let mut d: Vec<i32> = Vec::with_capacity(q);

  for _ in 0..q {
    a.push(read::<usize>(s).unwrap());
    b.push(read::<usize>(s).unwrap());
    c.push(read::<i32>(s).unwrap());
    d.push(read::<i32>(s).unwrap());
  }
  let calculator = Calculator::new(q, a, b, c, d);

  fn dfs(rest: i32, start: i32, end: i32, calculator: Calculator, vec: &mut Vec<i32>) -> i32 {
    if rest >= 1 {
      let mut ans = 0;
      for i in start..(end - rest + 2) {
        vec.push(i);
        ans = max(ans, dfs(rest - 1, i, end, calculator.clone(), vec));
        vec.pop();
      }
      ans
    } else {
      calculator.exec(vec)
    }
  }

  println!(
    "{:?}",
    dfs(n, 1, m as i32, calculator, &mut Vec::with_capacity(m - 1))
  );
}