Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::io::*;
use std::str::*;

pub fn read_from<T: FromStr, R: Read>(s: &mut R) -> T {
    let s = s.bytes().map(|c| c.unwrap() as char)
        .skip_while(|c| c.is_whitespace())
        .take_while(|c| !c.is_whitespace())
        .collect::<String>();
    if !s.is_empty() {
        if let Ok(s) = s.parse::<T>() {
            s
        } else {
            panic!("faild to parse {}", s);
        }
    } else {
        if cfg!(local) {
            // eprintln!("reached to EOF");
        }
        std::process::exit(0)
    }
}

pub fn read<T: FromStr>() -> T {
    let stdin = stdin();
    let mut stdin = stdin.lock();
    read_from(&mut stdin)
}

pub fn readn<T: FromStr>(n: usize) -> Vec<T> {
    let stdin = stdin();
    let mut stdin = stdin.lock();
    (0..n).map(|_| read_from(&mut stdin)).collect()
}

fn main() {
    let n: i32 = read();
    let mut cnt = 0;
    for i in 1..n + 1 {
        if i % 2 == 1 {
            let d = (1..i + 1).filter(|j| i % j == 0).count();
            if d == 8 {
                cnt += 1;
            }
        }
    }
    println!("{}", cnt);
}