Problem:
Score : 500 points

Problem Statement

You are given a string S consisting of 0 and 1.
Find the maximum integer K not greater than |S| such that we can turn all the characters of S into 0 by repeating the following operation some number of times.

Choose a contiguous segment [l,r] in S whose length is at least K (that is, r-l+1\geq K must be satisfied). For each integer i such that l\leq i\leq r, do the following: if S_i is 0, replace it with 1; if S_i is 1, replace it with 0.

Constraints

1\leq |S|\leq 10^5

S_i(1\leq i\leq N) is either 0 or 1.

Input

Input is given from Standard Input in the following format:

S

Output

Print the maximum integer K such that we can turn all the characters of S into 0 by repeating the operation some number of times.

Sample Input 1

010

Sample Output 1

2

We can turn all the characters of S into 0 by the following operations:

Perform the operation on the segment S[1,3] with length 3. S is now 101.

Perform the operation on the segment S[1,2] with length 2. S is now 011.

Perform the operation on the segment S[2,3] with length 2. S is now 000.

Sample Input 2

100000000

Sample Output 2

8

Sample Input 3

00001111

Sample Output 3

4

Solution in Rust (1.15.1) (judge verdict: Runtime Error)

use std::io::*;

fn main() {
    let stdin = stdin();
    let mut lock = stdin.lock();
    let mut str1 = String::new();
    lock.read_line(&mut str1).unwrap();
    let mut n:Vec<_> = str1.trim().split_whitespace().
    next().unwrap().bytes().collect();/*.map(|x|
    match(x) {
        48 => false,
        49 => true,
        _ => unreachable!(),
    }).collect();
    */
    //println!("{:?}", n);
    let mut sanjo = 0usize;
    if n[0] == 48u8 {
        sanjo = n.binary_search(&49).unwrap().to_owned();
    } else {
        sanjo = n.binary_search(&48).unwrap().to_owned();
    }
    n.reverse();
//    println!("{:?}", n);
    let mut shijo = 0usize;
    if n[0] == 48u8 {
        shijo = n.binary_search(&49).unwrap().to_owned();
    } else {
        shijo = n.binary_search(&48).unwrap().to_owned();
    }
    /*
    let mut counter_0 = 0;
    let mut counter_1 = 0;
    for j in n {
        if *j == 48u8 {
            counter_0 += 1;
        } else {
            counter_1 += 1;
        }
    }
    */
    if sanjo <= shijo {
        println!("{}", shijo);
    } else {
        println!("{}", sanjo);
    }
}