Problem:
Score : 400 points

Problem Statement

N people are arranged in a row from left to right.

You are given a string S of length N consisting of 0 and 1, and a positive integer K.

The i-th person from the left is standing on feet if the i-th character of S is 0, and standing on hands if that character is 1.

You will give the following direction at most K times (possibly zero):

Direction: Choose integers l and r satisfying 1 \leq l \leq r \leq N, and flip the l-th, (l+1)-th, ..., and r-th persons. That is, for each i = l, l+1, ..., r, the i-th person from the left now stands on hands if he/she was standing on feet, and stands on feet if he/she was standing on hands.

Find the maximum possible number of consecutive people standing on hands after at most K directions.

Constraints

N is an integer satisfying 1 \leq N \leq 10^5.

K is an integer satisfying 1 \leq K \leq 10^5.

The length of the string S is N.

Each character of the string S is 0 or 1.

Input

Input is given from Standard Input in the following format:

N K
S

Output

Print the maximum possible number of consecutive people standing on hands after at most K directions.

Sample Input 1

5 1
00010

Sample Output 1

4

We can have four consecutive people standing on hands, which is the maximum result, by giving the following direction:

Give the direction with l = 1, r = 3, which flips the first, second and third persons from the left.

Sample Input 2

14 2
11101010110011

Sample Output 2

8

Sample Input 3

1 1
1

Sample Output 3

1

No directions are necessary.

Solution in Rust (1.15.1) (judge verdict: Accepted)

// This code is generated by [cargo-atcoder](https://github.com/tanakh/cargo-atcoder)
// Original source code:
/*
#![allow(dead_code, unused_variables, unused_macros, unused_imports)]

// https://qiita.com/tanakh/items/0ba42c7ca36cd29d0ac8
macro_rules! input { (source = $s:expr, $($r:tt)*) => { let mut iter = $s.split_whitespace(); let mut next = || { iter.next().unwrap() }; input_inner!{next, $($r)*} }; ($($r:tt)*) => { let stdin = std::io::stdin(); let mut bytes = std::io::Read::bytes(std::io::BufReader::new(stdin.lock())); let mut next = move || -> String{ bytes .by_ref() .map(|r|r.unwrap() as char) .skip_while(|c|c.is_whitespace()) .take_while(|c|!c.is_whitespace()) .collect() }; input_inner!{next, $($r)*} }; }
macro_rules! input_inner { ($next:expr) => {}; ($next:expr, ) => {}; ($next:expr, $var:ident : $t:tt $($r:tt)*) => { let $var = read_value!($next, $t); input_inner!{$next $($r)*} }; ($next:expr, mut $var:ident : $t:tt $($r:tt)*) => { let mut $var = read_value!($next, $t); input_inner!{$next $($r)*} }; }
macro_rules! read_value { ($next:expr, ( $($t:tt),* )) => { ( $(read_value!($next, $t)),* ) }; ($next:expr, [ $t:tt ; $len:expr ]) => { (0..$len).map(|_| read_value!($next, $t)).collect::<Vec<_>>() }; ($next:expr, chars) => { read_value!($next, String).chars().collect::<Vec<char>>() }; ($next:expr, usize1) => { read_value!($next, usize) - 1 }; ($next:expr, $t:ty) => { $next().parse::<$t>().expect("Parse error") }; }

use std::collections::VecDeque;

#[derive(Debug)]
enum N {
    Zero(i32),
    One(i32),
}

fn main() {
    input! {
        n: usize,
        mut k: i32,
        s: chars,
    }

    use N::*;

    let mut v = Vec::new();
    let mut zero = 0;
    let mut one = 0;

    for &c in s.iter() {
        if c == '0' {
            if one > 0 {
                v.push(One(one));
            }
            zero += 1;
            one = 0;
        } else {
            if zero > 0 {
                v.push(Zero(zero));
            }
            one += 1;
            zero = 0;
        }
    }
    if zero > 0 {
        v.push(Zero(zero));
    }
    if one > 0 {
        v.push(One(one));
    }
    let mut ans = 0;
    let mut sum = 0;
    let mut d = VecDeque::new();
    let mut i = 0;
    while i < v.len() {
        loop {
            match v.get(i) {
                None => break,
                Some(One(one)) => sum += one,
                Some(Zero(zero)) if k <= 0 => break,
                Some(Zero(zero)) => {
                    sum += zero;
                    k -= 1;
                }
            }
            d.push_back(&v[i]);
            i += 1;
        }
        ans = std::cmp::max(ans, sum);
        match d.pop_front() {
            None => (),
            Some(Zero(zero)) => {
                sum -= zero;
                k += 1;
            }
            Some(One(one)) => {
                sum -= one;
                match d.pop_front() {
                    None => (),
                    Some(Zero(zero)) => {
                        sum -= zero;
                        k += 1;
                    }
                    Some(One(one)) => unreachable!(),
                }
            }
        }
    }
    ans = std::cmp::max(ans, sum);
    println!("{}", ans);
}
*/

fn main() {
    let exe = "/tmp/bin7DFC5B75";
    std::io::Write::write_all(&mut std::fs::File::create(exe).unwrap(), &decode(BIN)).unwrap();
    std::fs::set_permissions(exe, std::os::unix::fs::PermissionsExt::from_mode(0o755)).unwrap();
    std::process::exit(std::process::Command::new(exe).status().unwrap().code().unwrap())
}

fn decode(v: &str) -> Vec<u8> {
    let mut ret = vec![];
    let mut buf = 0;
    let mut tbl = vec![64; 256];
    for i in 0..64 { tbl[TBL[i] as usize] = i as u8; }
    for (i, c) in v.bytes().filter_map(|c| { let c = tbl[c as usize]; if c < 64 { Some(c) } else { None } }).enumerate() {
        match i % 4 {
            0 => buf = c << 2,
            1 => { ret.push(buf | c >> 4); buf = c << 4; }
            2 => { ret.push(buf | c >> 2); buf = c << 6; }
            3 => ret.push(buf | c),
            _ => unreachable!(),
        }
    }
    ret
}

const TBL: &'static [u8] = b"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
const BIN: &'static str = "<base64-encoded ELF executable removed>";