Problem:
Score : 300 points

Problem Statement

There are N observatories in AtCoder Hill, called Obs. 1, Obs. 2, ..., Obs. N. The elevation of Obs. i is H_i.
There are also M roads, each connecting two different observatories. Road j connects Obs. A_j and Obs. B_j.

Obs. i is said to be good when its elevation is higher than those of all observatories that can be reached from Obs. i using just one road.
Note that Obs. i is also good when no observatory can be reached from Obs. i using just one road.

How many good observatories are there?

Constraints

2 \leq N \leq 10^5

1 \leq M \leq 10^5

1 \leq H_i \leq 10^9

1 \leq A_i,B_i \leq N

A_i \neq B_i

Multiple roads may connect the same pair of observatories.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
H_1 H_2 ... H_N
A_1 B_1
A_2 B_2
:
A_M B_M

Output

Print the number of good observatories.

Sample Input 1

4 3
1 2 3 4
1 3
2 3
2 4

Sample Output 1

2

From Obs. 1, you can reach Obs. 3 using just one road. The elevation of Obs. 1 is not higher than that of Obs. 3, so Obs. 1 is not good.

From Obs. 2, you can reach Obs. 3 and 4 using just one road. The elevation of Obs. 2 is not higher than that of Obs. 3, so Obs. 2 is not good.

From Obs. 3, you can reach Obs. 1 and 2 using just one road. The elevation of Obs. 3 is higher than those of Obs. 1 and 2, so Obs. 3 is good.

From Obs. 4, you can reach Obs. 2 using just one road. The elevation of Obs. 4 is higher than that of Obs. 2, so Obs. 4 is good.

Thus, the good observatories are Obs. 3 and 4, so there are two good observatories.

Sample Input 2

6 5
8 6 9 1 2 1
1 3
4 2
4 3
4 6
4 6

Sample Output 2

3

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

/* #region template */
#![allow(unused_imports)]
use std::cmp::{max, min};
use std::io::{stdin, stdout, Bytes, Read, Stdin, StdinLock, Stdout, StdoutLock, Write};
use std::iter::{repeat, repeat_with};
use std::mem::swap;
use std::str::FromStr;
#[allow(dead_code)]
struct Io<'a> {
    reader: Bytes<StdinLock<'a>>,
    writer: StdoutLock<'a>,
    in_buf: [u8; BUF_SIZE],
}
#[allow(dead_code)]
impl<'a> Io<'a> {
    fn new(stdin: &'a Stdin, stdout: &'a Stdout) -> Io<'a> {
        Io {
            reader: stdin.lock().bytes(),
            writer: stdout.lock(),
            in_buf: [0; BUF_SIZE],
        }
    }
    fn r<T: FromStr>(&mut self) -> T {
        let mut count = 0;
        loop {
            match self.reader.next() {
                Some(Ok(b' ')) | Some(Ok(b'\n')) => break,
                Some(Ok(c)) => self.in_buf[count] = c,
                _ => panic!(),
            }
            count += 1;
        }

        let s = unsafe { std::str::from_utf8_unchecked(&self.in_buf[0..count]) };
        s.parse().unwrap_or_else(|_| panic!())
    }
    fn ru(&mut self) -> usize {
        self.r()
    }
    fn iter<'b, T>(&'b mut self) -> IoIter<'a, 'b, T> {
        IoIter::new(self)
    }
    fn c<T: FromStr>(&mut self, n: usize) -> Vec<T> {
        self.iter().take(n).collect()
    }
    fn cu(&mut self, n: usize) -> Vec<usize> {
        self.c(n)
    }
    fn w<T: std::fmt::Display>(&mut self, v: T) {
        writeln!(self.writer, "{}", v).unwrap();
    }
    fn wn<T: std::fmt::Display>(&mut self, v: T) {
        write!(self.writer, "{}", v).unwrap();
    }
}
#[allow(dead_code)]
struct IoIter<'a: 'b, 'b, T> {
    io: &'b mut Io<'a>,
    m: std::marker::PhantomData<T>,
}
#[allow(dead_code)]
impl<'a: 'b, 'b, T> IoIter<'a, 'b, T> {
    fn new(io: &'b mut Io<'a>) -> IoIter<'a, 'b, T> {
        IoIter {
            io,
            m: std::marker::PhantomData,
        }
    }
}
impl<'a, 'b, T: FromStr> Iterator for IoIter<'a, 'b, T> {
    type Item = T;
    fn next(&mut self) -> Option<Self::Item> {
        Some(self.io.r())
    }
}
fn main() {
    let stdin = stdin();
    let stdout = stdout();
    let mut io = Io::new(&stdin, &stdout);
    unsafe {
        solve(&mut io);
    }
}
/* #endregion */

const BUF_SIZE: usize = 1024;

unsafe fn solve(io: &mut Io) {
    let n = io.ru();
    let m = io.ru();
    let h = io.cu(n);
    let ab: Vec<(usize, usize)> = repeat(()).take(m).map(|_| (io.ru(), io.ru())).collect();

    let mut count = 0;
    for i in 0..n {
        if ab
            .iter()
            .filter_map(|abi| {
                if abi.0 == i {
                    Some(h[abi.1 - 1])
                } else if abi.1 == i {
                    Some(h[abi.0 - 1])
                } else {
                    None
                }
            })
            .all(|a| a < h[i])
        {
            count += 1;
        }
    }
    io.w(count);
}