Problem:
Score : 200 points

Problem Statement

An integer N is a multiple of 9 if and only if the sum of the digits in the decimal representation of N is a multiple of 9.

Determine whether N is a multiple of 9.

Constraints

0 \leq N < 10^{200000}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a multiple of 9, print Yes; otherwise, print No.

Sample Input 1

123456789

Sample Output 1

Yes

The sum of these digits is 1+2+3+4+5+6+7+8+9=45, which is a multiple of 9, so 123456789 is a multiple of 9.

Sample Input 2

0

Sample Output 2

Yes

Sample Input 3

31415926535897932384626433832795028841971693993751058209749445923078164062862089986280

Sample Output 3

No

Solution in Rust (1.42.0) (judge verdict: Accepted)

#![allow(clippy::many_single_char_names)]
#[allow(unused_imports)]
use proconio::{
    input,
    marker::{Chars, Usize1},
};

fn main() {
    input!(s: Chars);
    println!(
        "{}",
        if s.iter().map(|&c| ((c as u8 - b'0') as u32)).sum::<u32>() % 9 == 0 {
            "Yes"
        } else {
            "No"
        }
    );
}