Problem:
Score : 500 points

Problem Statement

We have N bulbs arranged on a number line, numbered 1 to N from left to right.
Bulb i is at coordinate i.

Each bulb has a non-negative integer parameter called intensity.
When there is a bulb of intensity d at coordinate x, the bulb illuminates the segment from coordinate x-d-0.5 to x+d+0.5.
Initially, the intensity of Bulb i is A_i. We will now do the following operation K times in a row:

For each integer i between 1 and N (inclusive), let B_i be the number of bulbs illuminating coordinate i. Then, change the intensity of each bulb i to B_i.

Find the intensity of each bulb after the K operations.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq K \leq 2 \times 10^5

0 \leq A_i \leq N

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 \ldots A_N

Output

Print the intensity A{'}_i of each bulb i after the K operations to Standard Output in the following format:

A{'}_1 A{'}_2 \ldots A{'}_N

Sample Input 1

5 1
1 0 0 1 0

Sample Output 1

1 2 2 1 2

Initially, only Bulb 1 illuminates coordinate 1, so the intensity of Bulb 1 becomes 1 after the operation.
Similarly, the bulbs initially illuminating coordinate 2 are Bulb 1 and 2, so the intensity of Bulb 2 becomes 2.

Sample Input 2

5 2
1 0 0 1 0

Sample Output 2

3 3 4 4 3

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

use proconio::input;

fn main() {
    input!{
        n: usize,
        mut k: usize,
        a: [usize; n],
    }


    let mut a = a.to_vec();
    let k_max = (n as f32).ln() as usize + 1;
    if k > k_max {
        k = k_max;
    }
    for _ in 0..k {
        let mut tmp = vec![0; n];
        a.iter().enumerate()
            .for_each(|(i, &a_i)| {
                let mut left = 0;
                if i >= a_i {
                    left = i - a_i;
                }
                let mut right = i + a_i;
                if right >= n {
                    right = n - 1
                }
                for j in left..(right + 1) {
                    tmp[j] += 1;
                }
        });
        a = tmp;
    }

    println!("{}", a.iter().map(|i| {
        i.to_string() + " "
    }).collect::<std::string::String>());
}