Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in Rust (1.42.0) (judge verdict: Accepted)

use proconio::{
    fastout, input,
    marker::{Bytes, Chars, Isize1, Usize1},
};

#[fastout]
fn main() {
    input! {
        n:usize,
    }
    let mut v = vec![];
    for _ in 0..n {
        input! {
            a:usize,b:usize,
        }
        if a == b {
            v.push(true);
        } else {
            v.push(false);
        }
    }
    let mut ans = false;
    for i in 0..n - 2 {
        if v[i] && v[i + 1] && v[i + 2] {
            ans = true;
        }
    }
    if ans {
        println!("Yes");
    } else {
        println!("No");
    }
}