Problem:
Score: 300 points

Problem Statement

As AtCoder Beginner Contest 100 is taking place, the office of AtCoder, Inc. is decorated with a sequence of length N, a = {a_1, a_2, a_3, ..., a_N}.

Snuke, an employee, would like to play with this sequence.

Specifically, he would like to repeat the following operation as many times as possible:

For every i satisfying 1 \leq i \leq N, perform one of the following: "divide a_i by 2" and "multiply a_i by 3".
Here, choosing "multiply a_i by 3" for every i is not allowed, and the value of a_i after the operation must be an integer.

At most how many operations can be performed?

Constraints

N is an integer between 1 and 10 \ 000 (inclusive).

a_i is an integer between 1 and 1 \ 000 \ 000 \ 000 (inclusive).

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 a_3 ... a_N

Output

Print the maximum number of operations that Snuke can perform.

Sample Input 1

3
5 2 4

Sample Output 1

3

The sequence is initially {5, 2, 4}. Three operations can be performed as follows:

First, multiply a_1 by 3, multiply a_2 by 3 and divide a_3 by 2. The sequence is now {15, 6, 2}.

Next, multiply a_1 by 3, divide a_2 by 2 and multiply a_3 by 3. The sequence is now {45, 3, 6}.

Finally, multiply a_1 by 3, multiply a_2 by 3 and divide a_3 by 2. The sequence is now {135, 9, 3}.

Sample Input 2

4
631 577 243 199

Sample Output 2

0

No operation can be performed since all the elements are odd. Thus, the answer is 0.

Sample Input 3

10
2184 2126 1721 1800 1024 2528 3360 1945 1280 1776

Sample Output 3

39

Solution in Rust (1.15.1) (judge verdict: Wrong Answer)

use std::io::*;

fn main() {
    let mut buf = String::new();
    std::io::stdin().read_to_string(&mut buf).unwrap();
    let mut iter = buf.split_whitespace();

    let size = iter.next().unwrap().parse().unwrap();

    let mut vec = Vec::with_capacity(size);
    for _i in 0..size {
        let i: u64 = iter.next().unwrap().parse().unwrap();
        vec.push(i);
    }


    let mut count = 0 as u64;
    let mut cannotmodulo = 0;
    for i in 0..size {
        if 0x1 & vec[i] == 1 {
            cannotmodulo += 1;
        }
        if cannotmodulo >= 4 {
            count = 0
        }

        let mc = modulable(vec[i]);
        count += mc;
    }
    println!("{}", count);
}

fn modulable(i: u64) -> u64 {
    if 0x1 & i == 1 {
        return 0;
    }
    let mut count = 0 as u64;

    let mut c = i;
    for _i in 0..30 {
        c = c >> 1;
        count += 1;
        if 0x0 & c == 0 {
            break;
        }
    }
    count
}