Problem:
Score : 200 points

Problem Statement

You are given an image A composed of N rows and N columns of pixels, and a template image B composed of M rows and M columns of pixels.

A pixel is the smallest element of an image, and in this problem it is a square of size 1×1.

Also, the given images are binary images, and the color of each pixel is either white or black.

In the input, every pixel is represented by a character: . corresponds to a white pixel, and # corresponds to a black pixel.

The image A is given as N strings A_1,...,A_N.

The j-th character in the string A_i corresponds to the pixel at the i-th row and j-th column of the image A (1≦i,j≦N).

Similarly, the template image B is given as M strings B_1,...,B_M.

The j-th character in the string B_i corresponds to the pixel at the i-th row and j-th column of the template image B (1≦i,j≦M).

Determine whether the template image B is contained in the image A when only parallel shifts can be applied to the images.

Constraints

1≦M≦N≦50

A_i is a string of length N consisting of # and ..

B_i is a string of length M consisting of # and ..

Input

The input is given from Standard Input in the following format:

N M
A_1
A_2
:
A_N
B_1
B_2
:
B_M

Output

Print Yes if the template image B is contained in the image A. Print No otherwise.

Sample Input 1

3 2
#.#
.#.
#.#
#.
.#

Sample Output 1

Yes

The template image B is identical to the upper-left 2 × 2 subimage and the lower-right 2 × 2 subimage of A. Thus, the output should be Yes.

Sample Input 2

4 1
....
....
....
....
#

Sample Output 2

No

The template image B, composed of a black pixel, is not contained in the image A composed of white pixels.

Solution in Rust (1.15.1) (judge verdict: Wrong Answer)

use std::io::{BufRead, Write, stdin, stdout};

fn solve<R: BufRead, W: Write>(mut input: R, mut output: W) {
    let mut s = String::new();
    input.read_line(&mut s).unwrap();
    let mut split = s.split_whitespace();
    let n: u16 = split.next().unwrap().parse().unwrap();
    let m: u16 = split.next().unwrap().parse().unwrap();
    let a: Vec<Vec<bool>> = (0..n)
        .map(|_| {
            let mut s = String::new();
            input.read_line(&mut s).unwrap();
            s.trim().chars().map(|c| c == '#').collect()
        })
        .collect();
    let b: Vec<Vec<bool>> = (0..m)
        .map(|_| {
            let mut s = String::new();
            input.read_line(&mut s).unwrap();
            s.trim().chars().map(|c| c == '#').collect()
        })
        .collect();
    let mut result = false;
    'x: for i in 0..n - m {
        for j in 0..n - m {
            let mut flag = true;
            'y: for k in 0..m {
                for l in 0..m {
                    if a[i as usize + k as usize][j as usize + l as usize] !=
                       b[k as usize][l as usize] {
                        flag = false;
                        break 'y;
                    }
                }
            }
            if flag == true {
                result = true;
                break 'x;
            }
        }
    }
    writeln!(output, "{}", if result { "Yes" } else { "No" }).unwrap();
}

fn main() {
    let stdin = stdin();
    solve(stdin.lock(), stdout());
}

#[cfg(test)]
mod tests {
    fn test(input: &str, output: &str) {
        let mut v = Vec::<u8>::new();
        ::solve(input.as_bytes(), &mut v);
        assert_eq!(String::from_utf8(v).unwrap(), output);
    }
    #[test]
    fn case1() {
        test("3 2
#.#
.#.
#.#
#.
.#\n",
             "Yes\n");
    }
    #[test]
    fn case2() {
        test("4 1
....
....
....
....
#\n",
             "No\n");
    }
}