Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

#![allow(unused_imports)]
 
use proconio::{input, fastout};
use proconio::marker::*;
use std::collections::HashMap;
 
#[fastout]
fn main() {
  input! {
    s: String,
    t: String,
  }
  let mut s: Vec<char> = s.chars().collect();
  let mut t: Vec<char> = t.chars().collect();
  let mut map: HashMap<char, char> = HashMap::new();
  for i in 0..s.len() {
    let sc = s[i];
    let tc = t[i]; 
    if sc != tc {
      let exist = map.get(&tc).is_some();
      if exist {
        let v = map.get(&tc).unwrap();
        if v != &sc {
          println!("No");
          return
        }
      } else {
        map.insert(tc, sc);
      }
    }
  }
  println!("Yes");
}