Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in Rust (1.15.1) (judge verdict: Time Limit Exceeded)

use std::io;

/// 一行を読み込んで、空白で区切ったベクタにして返す
#[allow(dead_code)]
fn read<T>() -> Vec<T>
where
    T: std::str::FromStr,
    T::Err: std::fmt::Debug,
{
    let mut buf = String::new();
    io::stdin().read_line(&mut buf).unwrap();
    buf.trim()
        .split_whitespace()
        .map(|s| s.parse().unwrap())
        .collect()
}

/// n行を読み込んで、数字を空白で区切って二次元のベクタにして返す
#[allow(dead_code)]
fn read_table<T>(n: usize) -> Vec<Vec<T>>
where
    T: std::str::FromStr,
    T::Err: std::fmt::Debug,
{
    let mut ret: Vec<Vec<T>> = Vec::new();
    for _ in 0..n {
        ret.push(read::<T>());
    }
    ret
}

/// n行を読み込んで、1文字ずつを二次元のベクタにして返す
#[allow(dead_code)]
fn read_char_table(n: usize) -> Vec<Vec<char>> {
    let mut ret: Vec<Vec<char>> = Vec::new();
    for _ in 0..n {
        let mut buf = String::new();
        io::stdin().read_line(&mut buf).unwrap();
        let chr = buf.trim().chars().collect();
        ret.push(chr);
    }
    ret
}

/// n行を読み込んで、一次元のベクタにして返す
#[allow(dead_code)]
fn read_array<T>(n: usize) -> Vec<T>
where
    T: std::str::FromStr,
    T::Err: std::fmt::Debug,
{
    let mut array = Vec::new();

    for _ in 0..n {
        let mut buf = String::new();
        io::stdin().read_line(&mut buf).unwrap();
        array.push(buf.trim().parse().unwrap());
    }
    array
}



fn main() {

    // 文字テーブル
    let mut buf1 = String::new();
    io::stdin().read_line(&mut buf1).unwrap();

    let sc = buf1.chars().collect::<Vec<char>>();
    let count = buf1.chars().count();

    let mut buf2 = String::new();
    io::stdin().read_line(&mut buf2).unwrap();
    let tc = buf2.chars().collect::<Vec<char>>();
    
    let mut c = Vec::<(char,char)>::with_capacity(1024);

    
    for i in 0..count {
        let mut  flag = true;
        for cc in &c {
            if sc[i] != tc[i] {
                if cc.0 == sc[i] && cc.1 == tc[i] {
                    flag = false;
                } else if cc.0 == sc[i] && cc.1 != tc[i] {
                    println!("No");
                    return;
                } else if cc.0 != sc[i] && cc.1 == tc[i] {
                    println!("No");
                    return;
                } 
            }

        }
        
        if flag { 
            c.push((sc[i], tc[i]));
        }
    }

    println!("Yes");

}