Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in Rust (1.15.1) (judge verdict: Accepted)

#[allow(unused_imports)]
use std::cmp::{min, max};
use std::io;

fn op(v: usize) -> char {
    if v == 0 { '+' } else { '-' }
}


fn main() {
    let mut line = String::new();
    io::stdin().read_line(&mut line).unwrap();
    let a: i64 = line[0..1].parse().unwrap();
    let b: i64 = line[1..2].parse().unwrap();
    let c: i64 = line[2..3].parse().unwrap();
    let d: i64 = line[3..4].parse().unwrap();

    for ops1 in 0..2 {
        for ops2 in 0..2 {
            for ops3 in 0..2 {
                let mut e = a;
                if ops1 == 0 { e += b } else { e -= b }
                if ops2 == 0 { e += c } else { e -= c }
                if ops3 == 0 { e += d } else { e -= d }
                if e == 7 {
                    println!("{}{}{}{}{}{}{}=7", a, op(ops1), b, op(ops2), c, op(ops3), d);
                    return;
                }
            }
        }
    }
}