Problem:
Score : 500 points

Problem Statement

In Takahashi Kingdom, which once existed, there are N cities, and some pairs of cities are connected bidirectionally by roads.
The following are known about the road network:

People traveled between cities only through roads. It was possible to reach any city from any other city, via intermediate cities if necessary.

Different roads may have had different lengths, but all the lengths were positive integers.

Snuke the archeologist found a table with N rows and N columns, A, in the ruin of Takahashi Kingdom.
He thought that it represented the shortest distances between the cities along the roads in the kingdom.

Determine whether there exists a road network such that for each u and v, the integer A_{u, v} at the u-th row and v-th column of A is equal to the length of the shortest path from City u to City v.
If such a network exist, find the shortest possible total length of the roads.

Constraints

1 \leq N \leq 300

If i ≠ j, 1 \leq A_{i, j} = A_{j, i} \leq 10^9.

A_{i, i} = 0

Inputs

Input is given from Standard Input in the following format:

N
A_{1, 1} A_{1, 2} ... A_{1, N}
A_{2, 1} A_{2, 2} ... A_{2, N}
...
A_{N, 1} A_{N, 2} ... A_{N, N}

Outputs

If there exists no network that satisfies the condition, print -1.
If it exists, print the shortest possible total length of the roads.

Sample Input 1

3
0 1 3
1 0 2
3 2 0

Sample Output 1

3

The network below satisfies the condition:

City 1 and City 2 is connected by a road of length 1.

City 2 and City 3 is connected by a road of length 2.

City 3 and City 1 is not connected by a road.

Sample Input 2

3
0 1 3
1 0 1
3 1 0

Sample Output 2

-1

As there is a path of length 1 from City 1 to City 2 and City 2 to City 3, there is a path of length 2 from City 1 to City 3.
However, according to the table, the shortest distance between City 1 and City 3 must be 3.

Thus, we conclude that there exists no network that satisfies the condition.

Sample Input 3

5
0 21 18 11 28
21 0 13 10 26
18 13 0 23 13
11 10 23 0 17
28 26 13 17 0

Sample Output 3

82

Sample Input 4

3
0 1000000000 1000000000
1000000000 0 1000000000
1000000000 1000000000 0

Sample Output 4

3000000000

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

#![allow(unused_parens)]
#![allow(unused_imports)]
#![allow(non_upper_case_globals)]
#![allow(non_snake_case)]
#![allow(unused_mut)]
#![allow(unused_variables)]
#![allow(dead_code)]

use itertools::Itertools;
use proconio::input;
use proconio::marker::{Chars, Usize1};

#[allow(unused_macros)]
#[cfg(debug_assertions)]
macro_rules! mydbg {
    //($arg:expr) => (dbg!($arg))
    //($arg:expr) => (println!("{:?}",$arg));
      ($($a:expr),*) => {
          eprintln!(concat!($(stringify!($a), " = {:?}, "),*), $($a),*);
      }
}
#[cfg(not(debug_assertions))]
macro_rules! mydbg {
    ($($arg:expr),*) => {};
}

macro_rules! echo {
    ($($a:expr),*) => {
          $(println!("{}",$a))*
      }
}

use std::cmp::*;
use std::collections::*;
use std::ops::{Add, Div, Mul, Sub};

#[allow(dead_code)]
static INF_I64: i64 = 92233720368547758;
#[allow(dead_code)]
static INF_I32: i32 = 21474836;
#[allow(dead_code)]
static INF_USIZE: usize = 18446744073709551;
#[allow(dead_code)]
static M_O_D: usize = 1000000007;
#[allow(dead_code)]
static PAI: f64 = 3.1415926535897932;

trait IteratorExt: Iterator {
    fn toVec(self) -> Vec<Self::Item>;
}

impl<T: Iterator> IteratorExt for T {
    fn toVec(self) -> Vec<Self::Item> {
        self.collect()
    }
}

trait CharExt {
    fn toNum(&self) -> usize;
    fn toAlphabetIndex(&self) -> usize;
    fn toNumIndex(&self) -> usize;
}
impl CharExt for char {
    fn toNum(&self) -> usize {
        return *self as usize;
    }
    fn toAlphabetIndex(&self) -> usize {
        return self.toNum() - 'a' as usize;
    }
    fn toNumIndex(&self) -> usize {
        return self.toNum() - '0' as usize;
    }
}

trait VectorExt {
    fn joinToString(&self, s: &str) -> String;
}
impl<T: ToString> VectorExt for Vec<T> {
    fn joinToString(&self, s: &str) -> String {
        return self
            .iter()
            .map(|x| x.to_string())
            .collect::<Vec<_>>()
            .join(s);
    }
}

trait StringExt {
    fn get_reverse(&self) -> String;
}
impl StringExt for String {
    fn get_reverse(&self) -> String {
        self.chars().rev().collect::<String>()
    }
}

trait UsizeExt {
    fn pow(&self, n: usize) -> usize;
}
impl UsizeExt for usize {
    fn pow(&self, n: usize) -> usize {
        return ((*self as u64).pow(n as u32)) as usize;
    }
}

pub struct Dikstra {
    dist: Vec<i64>,
    start: usize,
}
impl Dikstra {
    pub fn new(g: &Vec<Vec<(i64, usize)>>, start: usize) -> Self {
        let mut d = Dikstra {
            dist: vec![INF_I64; g.len()],
            start: start,
        };
        d.calc(g);
        return d;
    }
    fn calc(&mut self, g: &Vec<Vec<(i64, usize)>>) {
        let mut used = vec![false; g.len()];
        let mut kouho = std::collections::BinaryHeap::new();
        kouho.push((0, self.start));
        while !kouho.is_empty() {
            let (_, k) = kouho.pop().unwrap();
            used[self.start] = true;
            self.dist[self.start] = 0;
            for i in 0..g[k].len() {
                let (d, p) = g[k][i];
                if used[p] {
                    continue;
                }
                if self.dist[p] > self.dist[k] + d as i64 {
                    self.dist[p] = self.dist[k] + d as i64;
                    kouho.push((self.dist[p] * -1, p));
                }
            }
        }
    }
    pub fn dist_to(&mut self, x: usize) -> i64 {
        return self.dist[x];
    }
}

fn main() {
    input! {
       N: usize,
       mut map_:[[i64;N];N],
    }
    let mut map = map_.clone();
    for i in 0..N {
        for j in i + 1..N {
            let d = map[i][j];
            if d == INF_I64 {
                continue;
            }
            let mut kouho = VecDeque::new();
            let mut used = vec![false; N];
            kouho.push_back((i, 0));
            used[i] = true;
            'outer: while !kouho.is_empty() {
                let (p, cost) = kouho.pop_front().unwrap();
                for k in 0..N {
                    if used[k] {
                        continue;
                    }
                    if p == i && k == j {
                        continue;
                    }
                    let c = map[p][k];
                    if k == j {
                        if d == cost + c {
                            map[i][j] = INF_I64;
                            map[j][i] = INF_I64;
                            break 'outer;
                        } else if d > cost + c {
                            echo!(-1);
                            return;
                        }
                        continue;
                    }
                    if cost + c >= d {
                        continue;
                    }
                    used[k] = true;
                    kouho.push_back((k, cost + c));
                }
            }
        }
    }
    

    let mut ans = 0;
    for i in 0..N {
        for j in i + 1..N {
            if map[i][j] != INF_I64 {
                ans += map[i][j];
            }
        }
    }

    echo!(ans);
}