Problem:
Score : 400 points

Problem Statement

There are N empty boxes arranged in a row from left to right.
The integer i is written on the i-th box from the left (1 \leq i \leq N).

For each of these boxes, Snuke can choose either to put a ball in it or to put nothing in it.

We say a set of choices to put a ball or not in the boxes is good when the following condition is satisfied:

For every integer i between 1 and N (inclusive), the total number of balls contained in the boxes with multiples of i written on them is congruent to a_i modulo 2.

Does there exist a good set of choices? If the answer is yes, find one good set of choices.

Constraints

All values in input are integers.

1 \leq N \leq 2 \times 10^5

a_i is 0 or 1.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

If a good set of choices does not exist, print -1.

If a good set of choices exists, print one such set of choices in the following format:

M
b_1 b_2 ... b_M

where M denotes the number of boxes that will contain a ball, and b_1,\ b_2,\ ...,\ b_M are the integers written on these boxes, in any order.

Sample Input 1

3
1 0 0

Sample Output 1

1
1

Consider putting a ball only in the box with 1 written on it.

There are three boxes with multiples of 1 written on them: the boxes with 1, 2, and 3. The total number of balls contained in these boxes is 1.

There is only one box with a multiple of 2 written on it: the box with 2. The total number of balls contained in these boxes is 0.

There is only one box with a multiple of 3 written on it: the box with 3. The total number of balls contained in these boxes is 0.

Thus, the condition is satisfied, so this set of choices is good.

Sample Input 2

5
0 0 0 0 0

Sample Output 2

0

Putting nothing in the boxes can be a good set of choices.

Solution in Rust (1.42.0) (judge verdict: Accepted)

#![allow(unused, non_snake_case, dead_code, non_upper_case_globals)]
use {
    proconio::{marker::*, *},
    std::{cmp::*, collections::*, mem::*},
};

#[fastout]
fn main() {
    input! {//
        n:usize,
       mut b:[i64;n],
    }
    let mut a = vec![0];
    a.append(&mut b);
    dbg!(&a);
    /*



    */
    let mut anss = vec![false; n + 1];
    let mut r = vec![false; n + 1];
    let mut z = vec![];
    for i in (1..=n).rev() {
        let j = divisor(i);
        // if ((a[i] == 1) ^ anss[i]) {}
        if ((a[i] == 1) ^ anss[i]) {
            // iを入れないといけない
            for divs in j {
                anss[divs] = !anss[divs];
            }
            z.push(i);
        }
    }
    println!("{}", z.len());
    for &x in z.iter() {
        println!("{}", x);
    }
}
pub fn divisor(n: usize) -> Vec<usize> {
    let mut res = Vec::new();
    for i in (1..).take_while(|x| x * x <= n) {
        if n % i == 0 {
            res.push(i);
            if i != n / i {
                res.push(n / i);
            }
        }
    }
    res.sort();
    res
}