Problem:
Score : 200 points

Problem Statement

There are N gems. The value of the i-th gem is V_i.

You will choose some of these gems, possibly all or none, and get them.

However, you need to pay a cost of C_i to get the i-th gem.

Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.

Find the maximum possible value of X-Y.

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq C_i, V_i \leq 50

Input

Input is given from Standard Input in the following format:

N
V_1 V_2 ... V_N
C_1 C_2 ... C_N

Output

Print the maximum possible value of X-Y.

Sample Input 1

3
10 2 5
6 3 4

Sample Output 1

5

If we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.
We have X-Y = 5 here, which is the maximum possible value.

Sample Input 2

4
13 21 6 19
11 30 6 15

Sample Output 2

6

Sample Input 3

1
1
50

Sample Output 3

0

Solution in Rust (1.15.1) (judge verdict: Accepted)

#![allow(dead_code)]

mod reader {
    use std;

    macro_rules! read_line((  ) => {
                           {
                           let mut input = String :: new (  ) ; std :: io ::
                           stdin (  ) . read_line ( & mut input ) . unwrap (
                           ) ; input } } ;);

    pub fn read_to_vec<T: std::str::FromStr>() -> Vec<T> {
        read_line!().split_whitespace().map(|e|
                                                e.parse().ok().unwrap()).collect()
    }

    pub fn read_and_parse<T: std::str::FromStr>() -> T {
        read_line!().trim().parse().ok().unwrap()
    }
}

use reader::*;

fn main() {
    let n: u32 = read_and_parse();
    let v: Vec<i32> = read_to_vec();
    let c: Vec<i32> = read_to_vec();

    let mut sum: i32 = 0;

    for (x, y) in v.iter().zip(c) {
        let diff = x - y;
        if diff > 0 { sum += diff }
    }

    println!("{}" , sum);
}