Problem:
Score : 800 points

Problem Statement

There is a square grid with N rows and M columns.
Each square contains an integer: 0 or 1. The square at the i-th row from the top and the j-th column from the left contains a_{ij}.

Among the 2^{N+M} possible pairs of a subset A of the rows and a subset B of the columns, find the number of the pairs that satisfy the following condition, modulo 998244353:

The sum of the |A||B| numbers contained in the intersection of the rows belonging to A and the columns belonging to B, is odd.

Constraints

1 \leq N,M \leq 300

0 \leq a_{i,j} \leq 1(1\leq i\leq N,1\leq j\leq M)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
a_{11} ... a_{1M}
:
a_{N1} ... a_{NM}

Output

Print the number of the pairs of a subset of the rows and a subset of the columns that satisfy the condition, modulo 998244353.

Sample Input 1

2 2
0 1
1 0

Sample Output 1

6

For example, if A consists of the first row and B consists of both columns, the sum of the numbers contained in the intersection is 0+1=1.

Sample Input 2

2 3
0 0 0
0 1 0

Sample Output 2

8

Solution in Rust (1.15.1) (judge verdict: Wrong Answer)

const MOD: usize = 998244353;
fn main() {
    let s = std::io::stdin();
    let mut sc = Scanner { stdin: s.lock() };
    let n: usize = sc.read();
    let m: usize = sc.read();
    let mut a: Vec<Vec<i64>> = (0..n)
        .map(|_| (0..m).map(|_| sc.read()).collect())
        .collect();

    let mut rank = 0;
    for col in 0..m {
        match (rank..n).find(|&i| a[i][col] == 1) {
            Some(row) => {
                a.swap(rank, row);
                assert_eq!(a[rank][col], 1);
                for i in 0..n {
                    if i == rank {
                        continue;
                    }
                    for j in 0..m {
                        a[i][j] ^= a[rank][j];
                    }
                }
                rank += 1;
            }
            None => {}
        }
    }

    let mut pow2 = vec![0; n + m + 1];
    pow2[0] = 1;
    for i in 1..pow2.len() {
        pow2[i] = (pow2[i - 1] * 2) % MOD;
    }
    let ans = pow2[n + m - 1] + MOD - pow2[n + m - rank - 1];
    println!("{}", ans % MOD);

    // C(rank, x) * 2^(x-1) * 2^(m-x) * 2^(n-rank)
    // 2^(n+m-rank-1) * sum C(rank, x)
    // 2^(n+m-rank-1) * 2^rank - 2^(n+m-rank-1)
}

pub struct Scanner<R> {
    stdin: R,
}

impl<R: std::io::Read> Scanner<R> {
    pub fn read<T: std::str::FromStr>(&mut self) -> T {
        use std::io::Read;
        let buf = self
            .stdin
            .by_ref()
            .bytes()
            .map(|b| b.unwrap())
            .skip_while(|&b| b == b' ' || b == b'\n')
            .take_while(|&b| b != b' ' && b != b'\n')
            .collect::<Vec<_>>();
        unsafe { std::str::from_utf8_unchecked(&buf) }
            .parse()
            .ok()
            .expect("Parse error.")
    }
    pub fn vec<T: std::str::FromStr>(&mut self, n: usize) -> Vec<T> {
        (0..n).map(|_| self.read()).collect()
    }
    pub fn chars(&mut self) -> Vec<char> {
        self.read::<String>().chars().collect()
    }
}