Problem:
Score : 600 points

Problem Statement

Given is an integer sequence A_1, ..., A_N of length N.

We will choose exactly \left\lfloor \frac{N}{2} \right\rfloor elements from this sequence so that no two adjacent elements are chosen.

Find the maximum possible sum of the chosen elements.

Here \lfloor x \rfloor denotes the greatest integer not greater than x.

Constraints

2 \leq N \leq 2\times 10^5

|A_i|\leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the maximum possible sum of the chosen elements.

Sample Input 1

6
1 2 3 4 5 6

Sample Output 1

12

Choosing 2, 4, and 6 makes the sum 12, which is the maximum possible value.

Sample Input 2

5
-1000 -100 -10 0 10

Sample Output 2

0

Choosing -10 and 10 makes the sum 0, which is the maximum possible value.

Sample Input 3

10
1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000

Sample Output 3

5000000000

Watch out for overflow.

Sample Input 4

27
18 -28 18 28 -45 90 -45 23 -53 60 28 -74 -71 35 -26 -62 49 -77 57 24 -70 -93 69 -99 59 57 -49

Sample Output 4

295

Solution in Rust (1.42.0) (judge verdict: Time Limit Exceeded)

#![allow(unused_imports)]
use std::io;
use std::cmp;
use std::collections::BinaryHeap;
use std::collections::HashMap;
use std::collections::HashSet;
use std::f64::consts::PI;
use std::str::FromStr;
use std::cmp::Reverse;

#[allow(dead_code)]
type Error = Box<dyn std::error::Error>;

fn read_line() -> String {
    let mut buf = String::new();
    io::stdin().read_line(&mut buf).ok();
    buf
}

struct Scanner {
    buff: Vec<String>,
    pos: usize,
}

#[allow(dead_code)]
impl Scanner {
    pub fn new() -> Self {
        Scanner {
            buff: Vec::new(),
            pos: 0,
        }
    }

    pub fn next<T: FromStr>(&mut self) -> T {
        while self.buff.len() <= self.pos {
            self.pos = 0;
            self.buff = read_line().split_whitespace().map(|s| s.to_owned()).collect();
        }

        let result = self.buff[self.pos].parse::<T>();
        self.pos += 1;
        result.ok().unwrap()
    }

    pub fn next_line(&mut self) -> String {
        let result  = read_line().trim().to_owned();
        self.buff.clear();
        self.pos = 0;

        result
    }

    pub fn next_vec<T: FromStr>(&mut self) -> Vec<T> {
        self.buff.clear();
        self.pos = 0;
        read_line().trim().split_whitespace().map(|s| s.parse().ok().unwrap()).collect()
    }
    
    pub fn next_line_chars(&mut self) -> Vec<char> {
        let result  = read_line().trim().chars().collect();
        self.buff.clear();
        self.pos = 0;

        result
    }
}

fn func(a: &Vec<i64>, l: usize, count: usize, memo: &mut HashMap<(usize, usize), i64>) -> i64 {
    if count == 0 {
        return 0;
    }
    if let Some(&val) = memo.get(&(l, count)) {
        return val;
    }
    let r = a.len();
    if r - l == count*2 - 1 {
        let mut ans = 0;
        for i in 0..count {
            ans += a[l+2*i];
        }
        memo.insert((l, count), ans);
        return ans;
    }

    let mut ans = -1_000_000_000_000_000;
    for i in l..r-(count-1)*2 {
        let mut tmp = a[i] + func(a, i+2, count-1, memo);
        ans = cmp::max(tmp, ans);
    }
    memo.insert((l, count), ans);

    ans
}

fn main() {
    let mut sc = Scanner::new();
    let n: usize = sc.next();
    let a: Vec<i64> = sc.next_vec();

    println!("{}", func(&a, 0, n/2, &mut HashMap::new()));
}