Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in Rust (1.15.1) (judge verdict: Time Limit Exceeded)

#[derive(Debug)]
enum Query {
    Reverse,
    Add(i64, String),
}

fn main() {
    let mut s = {
        let mut s = String::new();
        std::io::stdin().read_line(&mut s).unwrap();
        s.trim_right().to_owned()
    };

    let s1 = {
        let mut s = String::new();
        std::io::stdin().read_line(&mut s).unwrap();
        s.trim_right().to_owned()
    };
    let q = {
        let mut ws = s1.split_whitespace();
        let q: i64 = ws.next().unwrap().parse().unwrap();
        q
    };

    let mut query_list = vec![];
    for _ in 0..q as usize {
        let s1 = {
            let mut s = String::new();
            std::io::stdin().read_line(&mut s).unwrap();
            s.trim_right().to_owned()
        };
        let query = {
            let mut ws = s1.split_whitespace();
            let q: i64 = ws.next().unwrap().parse().unwrap();
            if q == 1 {
                Query::Reverse
            } else {
                let f: i64 = ws.next().unwrap().parse().unwrap();
                let c: String = ws.next().unwrap().to_owned();
                Query::Add(f, c)
            }
        };
        query_list.push(query);
    }

    let mut is_reverse = false;
    for query in query_list {
        match query {
            Query::Reverse => {
                is_reverse ^= true;
            }
            Query::Add(i, mut s1) => {
                if is_reverse && i == 1 || !is_reverse && i == 2 {
                    s.push_str(&s1);
                } else {
                    s1.push_str(&s);
                    s = s1;
                }
            }
        }
    }

    if is_reverse {
        println!("{}", s.chars().rev().collect::<String>());
    } else {
        println!("{}", s);
    }
}

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