Problem:
Score : 200 points

Problem Statement

A string is called a KEYENCE string when it can be changed to keyence by removing its contiguous substring (possibly empty) only once.

Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.

Constraints

The length of S is between 7 and 100 (inclusive).

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If S is a KEYENCE string, print YES; otherwise, print NO.

Sample Input 1

keyofscience

Sample Output 1

YES

keyence is an abbreviation of key of science.

Sample Input 2

mpyszsbznf

Sample Output 2

NO

Sample Input 3

ashlfyha

Sample Output 3

NO

Sample Input 4

keyence

Sample Output 4

YES

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

use std::*;
use proconio::{input, fastout, marker::*};

#[fastout]
fn main() {
  input!{
    s:String
  }
  let key = String::from("keyence");
  let mut ans :i32 = 0; let mut c :usize = 0;
  let mut flag :bool = true; let mut can :bool = false;
  for i in 0..s.len() {
    let x = key.chars().nth(c).unwrap();
    if s.chars().nth(i).unwrap() == x {
        flag = true;
        if c < 6 {c += 1;} else {can = true;}
    } else {
        if flag {ans += 1;}
        flag = false;
    }
  }
  println!("{}", if ans <= 1 && can {"YES"} else {"NO"});
}