Problem:
Score : 1500 points

Problem Statement

Iroha has a sequence of N strings s_1, s_2, ..., s_N.

She will choose some (possibly all) strings from the sequence, then concatenate those strings retaining the relative order, to produce a long string.

Among all strings of length K that she can produce in this way, find the lexicographically smallest one.

Constraints

1 ≦ N ≦ 2000

1 ≦ K ≦ 10^4

For each i, 1 ≦ |s_i| ≦ K.

|s_1| + |s_2| + ... + |s_N| ≦ 10^6

For each i, s_i consists of lowercase letters.

There exists at least one string of length K that Iroha can produce.

Input

The input is given from Standard Input in the following format:

N K
s_1
s_2
:
s_N

Output

Print the lexicographically smallest string of length K that Iroha can produce.

Sample Input 1

3 7
at
coder
codar

Sample Output 1

atcodar

at and codar should be chosen.

Sample Input 2

3 7
coder
codar
at

Sample Output 2

codarat

codar and at should be chosen.

Sample Input 3

4 13
kyuri
namida
zzzzzzz
aaaaaa

Sample Output 3

namidazzzzzzz

namida and zzzzzzz should be chosen.

Solution in Rust (1.15.1) (judge verdict: Wrong Answer)

#[allow(unused_imports)]
use std::cmp::*;
#[allow(unused_imports)]
use std::collections::*;
use std::io::{Write, BufWriter};
// https://qiita.com/tanakh/items/0ba42c7ca36cd29d0ac8
macro_rules! input {
    ($($r:tt)*) => {
        let stdin = std::io::stdin();
        let mut bytes = std::io::Read::bytes(std::io::BufReader::new(stdin.lock()));
        let mut next = move || -> String{
            bytes
                .by_ref()
                .map(|r|r.unwrap() as char)
                .skip_while(|c|c.is_whitespace())
                .take_while(|c|!c.is_whitespace())
                .collect()
        };
        input_inner!{next, $($r)*}
    };
}

macro_rules! input_inner {
    ($next:expr) => {};
    ($next:expr, ) => {};

    ($next:expr, $var:ident : $t:tt $($r:tt)*) => {
        let $var = read_value!($next, $t);
        input_inner!{$next $($r)*}
    };
}

macro_rules! read_value {
    ($next:expr, ( $($t:tt),* )) => {
        ( $(read_value!($next, $t)),* )
    };

    ($next:expr, [ $t:tt ; $len:expr ]) => {
        (0..$len).map(|_| read_value!($next, $t)).collect::<Vec<_>>()
    };

    ($next:expr, chars) => {
        read_value!($next, String).chars().collect::<Vec<char>>()
    };

    ($next:expr, usize1) => {
        read_value!($next, usize) - 1
    };

    ($next:expr, [ $t:tt ]) => {{
        let len = read_value!($next, usize);
        (0..len).map(|_| read_value!($next, $t)).collect::<Vec<_>>()
    }};

    ($next:expr, $t:ty) => {
        $next().parse::<$t>().expect("Parse error")
    };
}

// This solution is written after the author read the editorial.
/*
 * Z algorithm. Calculates an array a[i] = |lcp(s, s[i...|s|])|,
 * where s is the given string.
 * If n = s.length(), the returned array has length n + 1.
 * E.g. z_algorithm("ababa") = {5, 0, 3, 0, 1, 0}
 * Reference: http://snuke.hatenablog.com/entry/2014/12/03/214243
 * Verified by: AtCoder ARC055-C (http://arc055.contest.atcoder.jp/submissions/1061771)
 */
fn z_algorithm<T: PartialEq>(s: &[T]) -> Vec<usize> {
    let n = s.len();
    let mut ret = vec![0; n + 1];
    ret[0] = n;
    let mut i = 1; let mut j = 0;
    while i < n {
        while i + j < n && s[j] == s[i + j] { j += 1; }
        ret[i] = j;
        if j == 0 { i += 1; continue; }
        let mut k = 1;
        while i + k < n && k + ret[k] < j {
            ret[i + k] = ret[k];
            k += 1;
        }
        i += k; j -= k;
    }
    ret
}

fn calc_poss(s: &[Vec<char>], k: usize) -> Vec<Vec<bool>> {
    let n = s.len();
    let mut poss = vec![vec![false; k + 1]; n + 1];
    poss[n][0] = true;
    for i in (0 .. n).rev() {
        let len = s[i].len();
        for j in 0 .. k - len + 1 {
            poss[i][j + len] |= poss[i + 1][j];
        }
        for j in 0 .. k + 1 {
            poss[i][j] |= poss[i + 1][j];
        }
    }
    poss
}

fn solve() {
    use std::cmp::Ordering::*;
    let out = std::io::stdout();
    let mut out = BufWriter::new(out.lock());
    macro_rules! puts {
        ($($format:tt)*) => (write!(out,$($format)*).unwrap());
    }
    input! {
        n: usize,
        k: usize,
        s: [chars; n],
    }
    let poss = calc_poss(&s, k);
    let mut cs = vec![Vec::new(); n + 1];
    let mut dp = vec![vec![false; k + 1]; n + 1];
    dp[0][0] = true;
    for i in 0 .. n {
        let len = s[i].len();
        // Compares cs[i][..j] + s[i] and the current cs[i + 1].
        let cmps = |cs: &[Vec<char>], j| {
            // TODO optimize
            assert!(j <= cs[i].len());
            let mut x = cs[i][..j].to_vec();
            let mut t = s[i].clone();
            x.append(&mut t);
            let minlen = min(x.len(), cs[i + 1].len());
            let result = x[..minlen].cmp(&cs[i + 1][..minlen]);
            if (result, minlen < x.len()) == (Equal, true) {
                Less // needs updating
            } else {
                result
            }
        };
        // Compares cs[i][..j] and the current cs[i + 1].
        let cmp = |cs: &[Vec<char>], j| {
            // TODO optimize
            assert!(j <= cs[i].len());
            let minlen = min(cs[i].len(), cs[i + 1].len());
            let result = cs[i][..minlen].cmp(&cs[i + 1][..minlen]);
            if (result, minlen < cs[i].len()) == (Equal, true) {
                Less
            } else {
                result
            }
        };
        // get min
        for j in 0 .. k + 1 {
            if !poss[i + 1][k - j] || !dp[i][j] { continue; }
            if cmp(&cs, j) == Less {
                cs[i + 1] = cs[i].clone();
            }
        }
        for j in 0 .. k - len + 1 {
            if !poss[i + 1][k - j - len] || !dp[i][j] { continue; }
            if cmps(&cs, j) == Less {
                cs[i + 1] = cs[i][..j].to_vec();
                let mut t = s[i].clone();
                cs[i + 1].append(&mut t);
            }
        }
        // update dp
        for j in 0 .. k + 1 {
            if !poss[i + 1][k - j] || !dp[i][j] { continue; }
            dp[i + 1][j] = cmp(&cs, j) != Greater;
        }
        for j in 0 .. k - len + 1 {
            if !poss[i + 1][k - j - len] || !dp[i][j] { continue; }
            dp[i + 1][j + len] = cmps(&cs, j) != Greater;
        }
    }
    puts!("{}\n", cs[n][..k].iter().cloned().collect::<String>());
}

fn main() {
    // In order to avoid potential stack overflow, spawn a new thread.
    let stack_size = 104_857_600; // 100 MB
    let thd = std::thread::Builder::new().stack_size(stack_size);
    thd.spawn(|| solve()).unwrap().join().unwrap();
}