Problem:
Score: 400 points

Problem Statement

In Takahashi Kingdom, there is a east-west railroad and N cities along it, numbered 1, 2, 3, ..., N from west to east.
A company called AtCoder Express possesses M trains, and the train i runs from City L_i to City R_i (it is possible that L_i = R_i).
Takahashi the king is interested in the following Q matters:

The number of the trains that runs strictly within the section from City p_i to City q_i, that is, the number of trains j such that p_i \leq L_j and R_j \leq q_i.

Although he is genius, this is too much data to process by himself. Find the answer for each of these Q queries to help him.

Constraints

N is an integer between 1 and 500 (inclusive).

M is an integer between 1 and 200 \ 000 (inclusive).

Q is an integer between 1 and 100 \ 000 (inclusive).

1 \leq L_i \leq R_i \leq N (1 \leq i \leq M)

1 \leq p_i \leq q_i \leq N (1 \leq i \leq Q)

Input

Input is given from Standard Input in the following format:

N M Q
L_1 R_1
L_2 R_2
:
L_M R_M
p_1 q_1
p_2 q_2
:
p_Q q_Q

Output

Print Q lines. The i-th line should contain the number of the trains that runs strictly within the section from City p_i to City q_i.

Sample Input 1

2 3 1
1 1
1 2
2 2
1 2

Sample Output 1

3

As all the trains runs within the section from City 1 to City 2, the answer to the only query is 3.

Sample Input 2

10 3 2
1 5
2 8
7 10
1 7
3 10

Sample Output 2

1
1

The first query is on the section from City 1 to 7. There is only one train that runs strictly within that section: Train 1.
The second query is on the section from City 3 to 10. There is only one train that runs strictly within that section: Train 3.

Sample Input 3

10 10 10
1 6
2 9
4 5
4 7
4 7
5 8
6 6
6 7
7 9
10 10
1 8
1 9
1 10
2 8
2 9
2 10
3 8
3 9
3 10
1 10

Sample Output 3

7
9
10
6
8
9
6
7
8
10

Solution in Rust (1.42.0) (judge verdict: Accepted)

use std::io;
use std::cmp;
use std::collections::BinaryHeap;
use std::collections::HashMap;
use std::collections::HashSet;
use std::f64::consts::PI;
use std::str::FromStr;

type Error = Box<dyn std::error::Error>;

fn read_line() -> String {
    let mut buf = String::new();
    io::stdin().read_line(&mut buf).ok();
    buf
}

struct Scanner {
    buff: Vec<String>,
    pos: usize,
}


impl Scanner {
    pub fn new() -> Self {
        Scanner {
            buff: Vec::new(),
            pos: 0,
        }
    }

    pub fn next<T: FromStr>(&mut self) -> T {
        while self.buff.len() <= self.pos {
            self.pos = 0;
            self.buff = read_line().split_whitespace().map(|s| s.to_owned()).collect();
        }

        let result = self.buff[self.pos].parse::<T>();
        self.pos += 1;
        result.ok().unwrap()
    }

    pub fn next_line(&mut self) -> String {
        let result  = read_line().trim().to_owned();
        self.buff.clear();
        self.pos = 0;

        result
    }

    pub fn next_vec<T: FromStr>(&mut self) -> Vec<T> {
        self.buff.clear();
        self.pos = 0;
        read_line().trim().split_whitespace().map(|s| s.parse().ok().unwrap()).collect()
    }
    
    pub fn next_line_chars(&mut self) -> Vec<char> {
        let result  = read_line().trim().chars().collect();
        self.buff.clear();
        self.pos = 0;

        result
    }
}


fn main() {
    let mut scan = Scanner::new();
    let n: usize = scan.next();
    let m: usize = scan.next();
    let q: usize = scan.next();
    let mut memo = vec![vec![0; n]; n];
    for i in 0..m {
        let l:usize = scan.next::<usize>() - 1;
        let r:usize = scan.next::<usize>() - 1;

        memo[l][r] += 1;
    }

    let mut memo2 = vec![vec![0; n]; n];
    for i in 0..n {
        memo2[i][i] = memo[i][i];
    }
    for k in 1..n {
        for i in 0..n-k {
            memo2[i][i+k] = memo[i][i+k] + memo2[i][i+k-1] + memo2[i+1][i+k] - memo2[i+1][i+k-1];
        }
    }

    for i in 0..q {
        let p: usize = scan.next();
        let q: usize = scan.next();

        println!("{}", memo2[p - 1][q-1]);

    }
}