Problem:
Score : 400 points

Problem Statement

There are N towns in the State of Atcoder, connected by M bidirectional roads.

The i-th road connects Town A_i and B_i and has a length of C_i.

Joisino is visiting R towns in the state, r_1,r_2,..,r_R (not necessarily in this order).

She will fly to the first town she visits, and fly back from the last town she visits, but for the rest of the trip she will have to travel by road.

If she visits the towns in the order that minimizes the distance traveled by road, what will that distance be?

Constraints

2≤N≤200

1≤M≤N×(N-1)/2

2≤R≤min(8,N) (min(8,N) is the smaller of 8 and N.)

r_i≠r_j (i≠j)

1≤A_i,B_i≤N, A_i≠B_i

(A_i,B_i)≠(A_j,B_j),(A_i,B_i)≠(B_j,A_j) (i≠j)

1≤C_i≤100000

Every town can be reached from every town by road.

All input values are integers.

Input

Input is given from Standard Input in the following format:

N M R
r_1 ... r_R
A_1 B_1 C_1
:
A_M B_M C_M

Output

Print the distance traveled by road if Joisino visits the towns in the order that minimizes it.

Sample Input 1

3 3 3
1 2 3
1 2 1
2 3 1
3 1 4

Sample Output 1

2

For example, if she visits the towns in the order of 1, 2, 3, the distance traveled will be 2, which is the minimum possible.

Sample Input 2

3 3 2
1 3
2 3 2
1 3 6
1 2 2

Sample Output 2

4

The shortest distance between Towns 1 and 3 is 4. Thus, whether she visits Town 1 or 3 first, the distance traveled will be 4.

Sample Input 3

4 6 3
2 3 4
1 2 4
2 3 3
4 3 1
1 4 1
4 2 2
3 1 6

Sample Output 3

3

Solution in Rust (1.15.1) (judge verdict: Wrong Answer)

#![allow(unused_mut)]
#![allow(non_snake_case)]
#![allow(unused_macros)]
#![allow(unused_variables)]
#![allow(unused_imports)]
// https://qiita.com/tanakh/items/0ba42c7ca36cd29d0ac8
macro_rules! input {
    (source = $s:expr, $($r:tt)*) => {
        let mut iter = $s.split_whitespace();
        let mut next = || { iter.next().unwrap() };
        input_inner!{next, $($r)*}
    };
    ($($r:tt)*) => {
        let stdin = std::io::stdin();
        let mut bytes = std::io::Read::bytes(std::io::BufReader::new(stdin.lock()));
        let mut next = move || -> String{
            bytes
                .by_ref()
                .map(|r|r.unwrap() as char)
                .skip_while(|c|c.is_whitespace())
                .take_while(|c|!c.is_whitespace())
                .collect()
        };
        input_inner!{next, $($r)*}
    };
}

macro_rules! input_inner {
    ($next:expr) => {};
    ($next:expr, ) => {};

    ($next:expr, $var:ident : $t:tt $($r:tt)*) => {
        let mut $var = read_value!($next, $t);
        input_inner!{$next $($r)*}
    };
}

macro_rules! read_value {
    ($next:expr, ( $($t:tt),* )) => {
        ( $(read_value!($next, $t)),* )
    };

    ($next:expr, [ $t:tt ; $len:expr ]) => {
        (0..$len).map(|_| read_value!($next, $t)).collect::<Vec<_>>()
    };

    ($next:expr, chars) => {
        read_value!($next, String).chars().collect::<Vec<char>>()
    };

    ($next:expr, usize1) => {
        read_value!($next, usize) - 1
    };

    ($next:expr, $t:ty) => {
        $next().parse::<$t>().expect("Parse error")
    };
}

macro_rules! max {
    ($x: expr) => ($x);
    ($x: expr, $($y: expr),+) => {
        ::std::cmp::max($x, max!($($y),+))
    };
}

macro_rules! min {
    ($x: expr) => ($x);
    ($x: expr, $($y: expr),+) => {
        ::std::cmp::min($x, max!($($y),+))
    };
}

use std::cmp;
use std::collections::{HashSet, BinaryHeap};
use std::iter::FromIterator;
fn main() {
    input! {
        N: usize,
        M: usize,
        R: usize,
        r: [usize1; R],
        roads: [(usize1, usize1, usize); M],
    }

    let mut costs = vec![vec![10_000_000; N]; N];
    for &(a, b, cost) in roads.iter() {
        costs[a][b] = cost;
        costs[b][a] = cost;
    }

    for (ind, &r1) in r.iter().enumerate() {
        for &r2 in r.iter().skip(ind+1) {
            let mut d = [std::usize::MAX; 200];
            let mut q: HashSet<usize> = HashSet::from_iter(0..N);
            d[r1] = 0;

            while let Some(&prev) = q.iter().min_by_key(|&&i| d[i]) {
                if prev == r2 { break; }
                q.remove(&prev);

                for &q in q.iter() {
                    d[q] = cmp::min(d[q], d[prev] + costs[prev][q]);
                }
            }
            costs[r1][r2] = d[r2];
            costs[r2][r1] = d[r2];
        }
    }

    let mut ans = std::usize::MAX;

    'outer: for perm in 0..(2<<R) {
        let mut rest = perm;
        let mut c = [0; 8];
        let mut used = [false; 8];
        for ind in 0..R {
            let mut digit = 1;
            for l in 0..3 {
                c[ind] += digit * (rest&1);
                rest >>= 1;
                digit <<= 1;
            }
            if used[c[ind]] {
                continue 'outer;
            } else {
                used[c[ind]] = true;
            }
        }
        let mut sum = 0;
        for ind in 0..R-1 {
            sum += costs[r[ind]][r[ind+1]];
        }
        ans = cmp::min(ans, sum);
    }
    println!("{}", ans);
}