Problem:
Score : 400 points

Problem Statement

An altar enshrines N stones arranged in a row from left to right. The color of the i-th stone from the left (1 \leq i \leq N) is given to you as a character c_i; R stands for red and W stands for white.

You can do the following two kinds of operations any number of times in any order:

Choose two stones (not necessarily adjacent) and swap them.

Choose one stone and change its color (from red to white and vice versa).

According to a fortune-teller, a white stone placed to the immediate left of a red stone will bring a disaster. At least how many operations are needed to reach a situation without such a white stone?

Constraints

2 \leq N \leq 200000

c_i is R or W.

Input

Input is given from Standard Input in the following format:

N
c_{1}c_{2}...c_{N}

Output

Print an integer representing the minimum number of operations needed.

Sample Input 1

4
WWRR

Sample Output 1

2

For example, the two operations below will achieve the objective.

Swap the 1-st and 3-rd stones from the left, resulting in RWWR.

Change the color of the 4-th stone from the left, resulting in RWWW.

Sample Input 2

2
RR

Sample Output 2

0

It can be the case that no operation is needed.

Sample Input 3

8
WRWWRWRR

Sample Output 3

3

Solution in Rust (1.42.0) (judge verdict: Accepted)

#[allow(unused_imports)]
use std::{cmp::Reverse, collections::*};

#[allow(unused_imports)]
use proconio::{
    fastout, input,
    marker::{Chars, Usize1},
};

#[allow(unused_imports)]
use itertools::Itertools;

#[allow(unused_imports)]
use num::Integer;

#[fastout]
pub fn main() {
    input! {
        n: usize,
        mut c: Chars,
    }

    let mut count = 0;
    let mut l = 0;
    let mut r = n - 1;
    while l < r {
        while c[l] == 'R' && l < r {
            l += 1;
        }
        while c[r] == 'W' && l < r {
            r -= 1;
        }
        if l >= r {
            break;
        }
        count += 1;
        c[l] = 'R';
        c[r] = 'W';
        l += 1;
        r -= 1;
    }

    l = 0;
    while l < n && c[l] == 'R' {
        l += 1;
    }
    l += 1;
    if l != n {
        for i in l..n {
            if c[i] == 'R' {
                c[i] = 'W';
                count += 1;
            }
        }
    }

    println!("{}", count);
}