Problem:
Score : 100 points

Problem Statement

You are given a string S of length 2 or 3 consisting of lowercase English letters. If the length of the string is 2, print it as is; if the length is 3, print the string after reversing it.

Constraints

The length of S is 2 or 3.

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If the length of S is 2, print S as is; if the length is 3, print S after reversing it.

Sample Input 1

abc

Sample Output 1

cba

As the length of S is 3, we print it after reversing it.

Sample Input 2

ac

Sample Output 2

ac

As the length of S is 2, we print it as is.

Solution in Rust (1.15.1) (judge verdict: Accepted)

use scanner::Scanner;

fn main() {
    let mut sc = Scanner::new();
    let s = sc.read::<String>();
    println!("{}", if s.len() == 3 { s.chars().rev().collect::<String>() } else { s });
}

mod scanner {
    pub struct Scanner<'a> {
        s: String,
        words: ::std::str::SplitWhitespace<'a>,
    }

    impl<'a> Scanner<'a> {
        pub fn new() -> Scanner<'a> {
            let s = String::new();
            let words = unsafe { ::std::mem::transmute(s.split_whitespace()) };
            Scanner { s: s, words: words }
        }

        pub fn read<T: ::std::str::FromStr>(&mut self) -> T {
            match self.words.next() {
                Some(x) => x.parse().ok().unwrap(),
                None => {
                    self.load();
                    self.read()
                }
            }
        }

        fn load(&mut self) {
            self.s.clear();
            ::std::io::stdin().read_line(&mut self.s).unwrap();
            self.words = unsafe { ::std::mem::transmute(self.s.split_whitespace()) };
        }
    }
}