Problem:
Score : 300 points

Problem Statement

A railroad running from west to east in Atcoder Kingdom is now complete.

There are N stations on the railroad, numbered 1 through N from west to east.

Tomorrow, the opening ceremony of the railroad will take place.

On this railroad, for each integer i such that 1≤i≤N-1, there will be trains that run from Station i to Station i+1 in C_i seconds. No other trains will be operated.

The first train from Station i to Station i+1 will depart Station i S_i seconds after the ceremony begins. Thereafter, there will be a train that departs Station i every F_i seconds.

Here, it is guaranteed that F_i divides S_i.

That is, for each Time t satisfying S_i≤t and t％F_i=0, there will be a train that departs Station i t seconds after the ceremony begins and arrives at Station i+1 t+C_i seconds after the ceremony begins, where A％B denotes A modulo B, and there will be no other trains.

For each i, find the earliest possible time we can reach Station N if we are at Station i when the ceremony begins, ignoring the time needed to change trains.

Constraints

1≤N≤500

1≤C_i≤100

1≤S_i≤10^5

1≤F_i≤10

S_i％F_i=0

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
C_1 S_1 F_1
:
C_{N-1} S_{N-1} F_{N-1}

Output

Print N lines. Assuming that we are at Station i (1≤i≤N) when the ceremony begins, if the earliest possible time we can reach Station N is x seconds after the ceremony begins, the i-th line should contain x.

Sample Input 1

3
6 5 1
1 10 1

Sample Output 1

12
11
0

We will travel from Station 1 as follows:

5 seconds after the beginning: take the train to Station 2.

11 seconds: arrive at Station 2.

11 seconds: take the train to Station 3.

12 seconds: arrive at Station 3.

We will travel from Station 2 as follows:

10 seconds: take the train to Station 3.

11 seconds: arrive at Station 3.

Note that we should print 0 for Station 3.

Sample Input 2

4
12 24 6
52 16 4
99 2 2

Sample Output 2

187
167
101
0

Sample Input 3

4
12 13 1
44 17 17
66 4096 64

Sample Output 3

4162
4162
4162
0

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::borrow::BorrowMut;
use std::fs::File;
use std::io::{stdout, BufWriter, Read, Write};
use std::thread;

fn main() {
    thread::Builder::new()
        .stack_size(32 * 1024 * 1024) // 32MB
        .spawn(run)
        .unwrap()
        .join()
        .unwrap();
}

/// ローカル環境なら _in.txt から入力を受ける
fn read_input() -> String {
    let stdin = std::io::stdin();
    let mut s = String::new();
    match option_env!("LOCAL") {
        Some(_) => File::open("src/_in.txt")
            .expect("File not found")
            .read_to_string(&mut s)
            .unwrap(),
        None => stdin.lock().read_to_string(&mut s).unwrap(),
    };
    s
}

fn solve(i: i64, csf: &[(i64, i64, i64)]) -> i64 {
    let mut t: i64 = 0;
    for &(c, s, f) in &csf[(i as usize)..] {
        if t < s {
            t = s + c
        } else {
            t = (t as f64 / f as f64).ceil() as i64 * f + c
        }
    }
    t
}

fn run() {
    let out = stdout();
    let mut out = BufWriter::new(out.lock());
    let input = read_input();
    let mut input = input.split_whitespace();

    let n: i64 = input.next().unwrap().parse().unwrap();
    let csf: Vec<(i64, i64, i64)> = (0..(n - 1))
        .map(|_| {
            let v: Vec<i64> = input
                .borrow_mut()
                .take(3 as usize)
                .map(|s| s.parse().unwrap())
                .collect();
            (v[0], v[1], v[2])
        })
        .collect();

    for i in 0..n {
        writeln!(out, "{}", solve(i, &csf)).ok();
    }
}