Problem:
Score : 200 points

Problem Statement

Let S(n) denote the sum of the digits in the decimal notation of n.
For example, S(101) = 1 + 0 + 1 = 2.

Given an integer N, determine if S(N) divides N.

Constraints

1 \leq N \leq 10^9

Input

Input is given from Standard Input in the following format:

N

Output

If S(N) divides N, print Yes; if it does not, print No.

Sample Input 1

12

Sample Output 1

Yes

In this input, N=12.
As S(12) = 1 + 2 = 3, S(N) divides N.

Sample Input 2

101

Sample Output 2

No

As S(101) = 1 + 0 + 1 = 2, S(N) does not divide N.

Sample Input 3

999999999

Sample Output 3

Yes

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::io;
fn main() {
    let mut buf = String::new();
    io::stdin().read_line(&mut buf).unwrap();
    let n: i64 = buf.trim().parse().unwrap();
    let offset = '0'.to_digit(10).unwrap();
    let sn: i64 = format!("{}", n).chars().map(|c| (c.to_digit(10).unwrap() - offset) as i64).sum();
    println!("{}", if n % sn == 0 {"Yes"} else {"No"});
}