Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in Rust (1.42.0) (judge verdict: Accepted)

#![allow(unused_imports)]

use std::{i32, i64, u32, u64, usize, f64};
use std::cmp::{max, min, Ordering};
use std::collections::*;
use std::io::{stdout, Write, BufWriter};
use std::mem::{swap};
use maplit::*;
use proconio::{input, marker::{Isize1, Usize1, Bytes, Chars}};

#[proconio::fastout]
fn main() {
    input!(
        mut s: Chars,
        n: usize,
    );
    let mut rev = 0;
    let mut left: Vec<char> = Vec::with_capacity(n);
    let mut right: Vec<char> = Vec::with_capacity(n);

    for _ in 0..n {
        input!(mode: u8);
        if mode == 1 { rev = 1 - rev; }
        else {
            input!(lr: u8, c: char,);
            if (lr - 1) ^ rev == 0 { left.push(c); }
            else { right.push(c); }
        }
    }
    if rev == 0 {
        left.reverse();
        for cs in [left, s, right].iter() {
            for c in cs { print!("{}", c); }
        }
        println!("");
    } else {
        right.reverse();
        s.reverse();
        for cs in [right, s, left].iter() {
            for c in cs { print!("{}", c); }
        }
        println!("");
    }

}