Problem:
Score: 100 points

Problem Statement

M-kun is a competitor in AtCoder, whose highest rating is X.

In this site, a competitor is given a kyu (class) according to his/her highest rating. For ratings from 400 through 1999, the following kyus are given:

From 400 through 599: 8-kyu

From 600 through 799: 7-kyu

From 800 through 999: 6-kyu

From 1000 through 1199: 5-kyu

From 1200 through 1399: 4-kyu

From 1400 through 1599: 3-kyu

From 1600 through 1799: 2-kyu

From 1800 through 1999: 1-kyu

What kyu does M-kun have?

Constraints

400 \leq X \leq 1999

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the kyu M-kun has, as an integer.
For example, if he has 8-kyu, print 8.

Sample Input 1

725

Sample Output 1

7

M-kun's highest rating is 725, which corresponds to 7-kyu.

Thus, 7 is the correct output.

Sample Input 2

1600

Sample Output 2

2

M-kun's highest rating is 1600, which corresponds to 2-kyu.

Thus, 2 is the correct output.

Solution in Rust (1.42.0) (judge verdict: Accepted)

#![allow(non_snake_case)]
use proconio::input;
// use std::collections::HashMap;

fn main() {
    input! {
        X: i32,
    }

    if 400 <= X && X < 600 {
        println!("8");
        return;
    } else if 600 <= X && X < 800 {
        println!("7");
        return;
    } else if 800 <= X && X < 1000 {
        println!("6");
        return;
    } else if 1000 <= X && X < 1200 {
        println!("5");
        return;
    } else if 1200 <= X && X < 1400 {
        println!("4");
        return;
    } else if 1400 <= X && X < 1600 {
        println!("3");
        return;
    } else if 1600 <= X && X < 1800 {
        println!("2");
        return;
    } else if 1800 <= X && X < 2000 {
        println!("1");
        return;
    }
}