Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in Rust (1.42.0) (judge verdict: Accepted)

#![allow(unused, non_snake_case, dead_code, non_upper_case_globals)]
use {
    proconio::{marker::*, *},
    std::*,
    std::{cmp::*, collections::*, convert::*, iter::*, marker::*, mem::*, ops::*},
};
fn main() {
    input! {//
        n:usize,
        mut d:[(usize,usize);n],
    }
    let mut ok = false;
    for i in 2..n {
        if d[i - 2].0 == d[i - 2].1 && d[i - 1].0 == d[i - 1].1 && d[i].0 == d[i].1 {
            ok = true;
        }
    }
    yn(ok);
}

pub fn yn(ans: bool) {
    if ans {
        println!("Yes");
    } else {
        println!("No");
    }
}