Problem:
Score : 300 points

Problem Statement

A company has N members, who are assigned ID numbers 1, ..., N.

Every member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.

When a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.

You are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq A_i < i

Input

Input is given from Standard Input in the following format:

N
A_2 ... A_N

Output

For each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.

Sample Input 1

5
1 1 2 2

Sample Output 1

2
2
0
0
0

The member numbered 1 has two immediate subordinates: the members numbered 2 and 3.

The member numbered 2 has two immediate subordinates: the members numbered 4 and 5.

The members numbered 3, 4, and 5 do not have immediate subordinates.

Sample Input 2

10
1 1 1 1 1 1 1 1 1

Sample Output 2

9
0
0
0
0
0
0
0
0
0

Sample Input 3

7
1 2 3 4 5 6

Sample Output 3

1
1
1
1
1
1
0

Solution in Rust (1.42.0) (judge verdict: Accepted)

use std::io::{stdin, stdout, StdinLock, StdoutLock, BufReader, BufWriter, BufRead, Write};

fn main() {
    let (std_in, std_out) = (stdin(), stdout());
    let mut io = IO::new(std_in.lock(), std_out.lock());
    let n = io.r::<usize>();
    let a = io.rv::<usize>();

    let mut cnt = vec![0; n+1];
    for x in a {
        cnt[x] += 1;
    }
    io.wv(&cnt[1..=n]);
}


struct IO<'a> {
    br: BufReader<StdinLock<'a>>,
    bw: BufWriter<StdoutLock<'a>>,
}

#[allow(dead_code)]
impl IO<'_> {
    fn new<'a>(il: StdinLock<'a>, ol: StdoutLock<'a>) -> IO<'a> {
        IO {br: BufReader::new(il), bw: BufWriter::new(ol) }
    }

    fn r<T: std::str::FromStr>(&mut self) -> T {
        let mut buf = String::new();
        self.br.read_line(&mut buf).ok();
        buf.trim().parse().ok().unwrap()
    }

    fn rb(&mut self) -> Vec<u8> {
        let mut buf = String::new();
        self.br.read_line(&mut buf).ok();
        buf.trim().as_bytes().to_vec()
    }

    fn rv<T: std::str::FromStr>(&mut self) -> Vec<T> {
        let mut buf = String::new();
        self.br.read_line(&mut buf).ok();
        buf.trim().split_whitespace().map(|e| e.parse().ok().unwrap()).collect()
    }

    fn rvb(&mut self) -> Vec<Vec<u8>> {
        let mut buf = String::new();
        self.br.read_line(&mut buf).ok();
        buf.trim().split_whitespace().map(|e| e.as_bytes().to_vec()).collect()
    }

    fn w<T: std::fmt::Display>(&mut self, x: T) {
        let _ = writeln!(self.bw, "{}", x);
    }

    fn wb(&mut self, s: &[u8]) {
        let _ = writeln!(self.bw, "{}", unsafe{std::str::from_utf8_unchecked(s)});
    }

    fn wv<T: std::fmt::Display>(&mut self, v: &[T]) {
        let _ = write!(self.bw, "{}", v[0].to_string());
        for x in v[1..].iter() {
            let _ = write!(self.bw, " {}", x.to_string());
        }
        let _ = writeln!(self.bw);
    }

    fn wvb(&mut self, v: &[Vec<u8>]) {
        let _ = write!(self.bw, "{}", unsafe{std::str::from_utf8_unchecked(&v[0])});
        for x in v[1..].iter() {
            let _ = write!(self.bw, " {}", unsafe{std::str::from_utf8_unchecked(x)});
        }
        let _ = writeln!(self.bw);
    }
}