Problem:
Score : 100 points

Problem Statement

You are given a three-digit positive integer N.

Determine whether N is a palindromic number.

Here, a palindromic number is an integer that reads the same backward as forward in decimal notation.

Constraints

100≤N≤999

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a palindromic number, print Yes; otherwise, print No.

Sample Input 1

575

Sample Output 1

Yes

N=575 is also 575 when read backward, so it is a palindromic number. You should print Yes.

Sample Input 2

123

Sample Output 2

No

N=123 becomes 321 when read backward, so it is not a palindromic number. You should print No.

Sample Input 3

812

Sample Output 3

No

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::io;

fn procon_read<T: std::str::FromStr>() ->  Vec<T> {
	let mut buf = String::new();
	io::stdin().read_line(&mut buf).expect("");
	let iter = buf.split_whitespace();
	let mut v: Vec<T> = Vec::new();
	for i in iter {
		v.push(i.parse().ok().unwrap());
	}
	v
}

fn is_palindrome(s: &str) -> bool {
// sが回文であるかどうかを判定する
	let mut flag = true;
	let v:Vec<char> = s.chars().collect();
	let L = v.len();
	for n in 0..(L/2) {
		if v[n] != v[L - 1 - n] {
			flag = false;
			break;
		};
	}
	flag
}

fn main() {
	let v:Vec<i32> = procon_read();
	let n = v[0].to_string();
	if is_palindrome(&n) {
		println!("Yes");
	}else{
		println!("No");
	}
}