Problem:
Score : 200 points

Problem Statement

Determine if an N-sided polygon (not necessarily convex) with sides of length L_1, L_2, ..., L_N can be drawn in a two-dimensional plane.

You can use the following theorem:

Theorem: an N-sided polygon satisfying the condition can be drawn if and only if the longest side is strictly shorter than the sum of the lengths of the other N-1 sides.

Constraints

All values in input are integers.

3 \leq N \leq 10

1 \leq L_i \leq 100

Input

Input is given from Standard Input in the following format:

N
L_1 L_2 ... L_N

Output

If an N-sided polygon satisfying the condition can be drawn, print Yes; otherwise, print No.

Sample Input 1

4
3 8 5 1

Sample Output 1

Yes

Since 8 < 9 = 3 + 5 + 1, it follows from the theorem that such a polygon can be drawn on a plane.

Sample Input 2

4
3 8 4 1

Sample Output 2

No

Since 8 \geq 8 = 3 + 4 + 1, it follows from the theorem that such a polygon cannot be drawn on a plane.

Sample Input 3

10
1 8 10 5 8 12 34 100 11 3

Sample Output 3

No

Solution in Rust (1.15.1) (judge verdict: Accepted)

fn read_line() -> String {
    let mut s = String::new();
    std::io::stdin().read_line(&mut s).unwrap();
    s.trim_right().to_owned()
}

fn str_to_ints(s: String) -> std::vec::Vec<i32> {
    let mut ret = std::vec::Vec::new();
    let ws = s.split_whitespace();
    for w in ws {
        ret.push(w.parse().unwrap());
    }
    ret
}

fn main() {
    let n = str_to_ints(read_line())[0];
    let ls = str_to_ints(read_line());
    let mut max_l = 0;
    let mut sum_l = 0;
    for l in ls {
        if l > max_l {
            max_l = l;
        }
        sum_l += l;
    }
    if max_l < sum_l - max_l {
        println!("Yes");
    } else {
        println!("No");
    }
}