Problem:
Score : 200 points

Problem Statement

Takahashi is standing on a two-dimensional plane, facing north. Find the minimum positive integer K such that Takahashi will be at the starting position again after he does the following action K times:

Go one meter in the direction he is facing. Then, turn X degrees counter-clockwise.

Constraints

1 \leq X \leq 179

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the number of times Takahashi will do the action before he is at the starting position again.

Sample Input 1

90

Sample Output 1

4

Takahashi's path is a square.

Sample Input 2

1

Sample Output 2

360

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

use std::io::stdin;
fn main() {
    let mut st = String::new();
    stdin().read_line(&mut st).unwrap();
    let x:i64 = st.trim().parse().unwrap();
    let mut result:i64 = 360/x;
    if (180-result < result) && (x >= 3) {
        result = 180 - result;
    };
    println!("{:?}", result);
}