Problem:
Score : 200 points

Problem Statement

A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:

S is a palindrome.

Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.

The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.

Determine whether S is a strong palindrome.

Constraints

S consists of lowercase English letters.

The length of S is an odd number between 3 and 99 (inclusive).

Input

Input is given from Standard Input in the following format:

S

Output

If S is a strong palindrome, print Yes;
otherwise, print No.

Sample Input 1

akasaka

Sample Output 1

Yes

S is akasaka.

The string formed by the 1-st through the 3-rd characters is aka.

The string formed by the 5-th through the 7-th characters is aka.
All of these are palindromes, so S is a strong palindrome.

Sample Input 2

level

Sample Output 2

No

Sample Input 3

atcoder

Sample Output 3

No

Solution in Rust (1.15.1) (judge verdict: Accepted)

#![allow(unused)]

use std::io::{Read, StdinLock};
use std::iter::{FromIterator, Iterator};
use std::str::{FromStr};
use std::string::String;

pub fn read_bytes<T: FromIterator<char>>(s: &mut StdinLock) -> T {
    s.bytes()
        .map(|c| c.unwrap() as char)
        .skip_while(|c| c.is_whitespace())
        .take_while(|c| !c.is_whitespace())
        .collect::<T>()
}

pub fn reads(s: &mut StdinLock) -> String {
    read_bytes::<String>(s)
}

pub fn read<T: FromStr>(s: &mut StdinLock) -> T {
    reads(s).parse().ok().unwrap()
}

fn is_palindrome(s: &[char]) -> bool {
    (0 .. s.len()).all(|i| s[i] == s[s.len() - i - 1])
}

fn is_strong_palindrome(s: &[char]) -> bool {
    let n = s.len();
    is_palindrome(s)
        && is_palindrome(&s[0 .. (n - 1) / 2])
        && is_palindrome(&s[(n + 3) / 2 - 1 .. n])
}

fn main() {
    let sin = std::io::stdin();
    let mut sin = sin.lock();

    let s = read_bytes::<Vec<char>>(&mut sin);

    println!("{}",
        if is_strong_palindrome(s.as_slice()) { "Yes" } else { "No" });
}