Problem:
Score : 100 points

Problem Statement

In programming, hexadecimal notation is often used.

In hexadecimal notation, besides the ten digits 0, 1, ..., 9, the six letters A, B, C, D, E and F are used to represent the values 10, 11, 12, 13, 14 and 15, respectively.

In this problem, you are given two letters X and Y. Each X and Y is A, B, C, D, E or F.

When X and Y are seen as hexadecimal numbers, which is larger?

Constraints

Each X and Y is A, B, C, D, E or F.

Input

Input is given from Standard Input in the following format:

X Y

Output

If X is smaller, print <; if Y is smaller, print >; if they are equal, print =.

Sample Input 1

A B

Sample Output 1

<

10 < 11.

Sample Input 2

E C

Sample Output 2

>

14 > 12.

Sample Input 3

F F

Sample Output 3

=

15 = 15.

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::io;
fn read_line() -> String {
    let stdin = io::stdin();
    let mut buf = String::new();
    stdin.read_line(&mut buf);
    buf
}


fn sixtennbit(x: &str) -> i32 {
    let res: i32 = match x {
        "A" => 10,
        "B" => 11,
        "C" => 12,
        "D" => 13,
        "E" => 14,
        "F" => 15,
        _ => 0,
    };
    res
}
fn main() {
    let text = read_line();
    let test: Vec<&str> = text.split_whitespace().map(|x| x.trim()).collect();
    match (sixtennbit(test[0]) - sixtennbit(test[1])) {
        0 => println!("="),
        x if x > 0 => println!(">"),
        x if x < 0 => println!("<"),
        _ => println!(""),
    }
}