Problem:
Score : 200 points

Problem Statement

You are given string S and T consisting of lowercase English letters.

Determine if S equals T after rotation.

That is, determine if S equals T after the following operation is performed some number of times:

Operation: Let S = S_1 S_2 ... S_{|S|}. Change S to S_{|S|} S_1 S_2 ... S_{|S|-1}.

Here, |X| denotes the length of the string X.

Constraints

2 \leq |S| \leq 100

|S| = |T|

S and T consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S equals T after rotation, print Yes; if it does not, print No.

Sample Input 1

kyoto
tokyo

Sample Output 1

Yes

In the first operation, kyoto becomes okyot.

In the second operation, okyot becomes tokyo.

Sample Input 2

abc
arc

Sample Output 2

No

abc does not equal arc after any number of operations.

Sample Input 3

aaaaaaaaaaaaaaab
aaaaaaaaaaaaaaab

Sample Output 3

Yes

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::io;

fn main() {
	let mut buf = String::new();
	io::stdin().read_line(&mut buf).expect("");
	let s:Vec<char> = buf.trim().chars().collect();
	let mut buf = String::new();
	io::stdin().read_line(&mut buf).expect("");
	let t:Vec<char> = buf.trim().chars().collect();
	let mut flag = false;
	
	for i in 0..s.len() {
		let s1 = &s[(s.len() - i - 1)..s.len()];
		let s2 = &s[0..(s.len() - i -1)];
		let t1 = &t[0..(i + 1)];
		let t2 = &t[(i + 1)..t.len()];
		if s1 == t1 && s2 == t2 {
			flag = true;
			break;
		}
	}
	if flag {
		println!("Yes");
	}else{
		println!("No");
	}
}