Problem:
Score: 100 points

Problem Statement

A triple of numbers is said to be poor when two of those numbers are equal but the other number is different from those two numbers.

You will be given three integers A, B, and C. If this triple is poor, print Yes; otherwise, print No.

Constraints

A, B, and C are all integers between 1 and 9 (inclusive).

Input

Input is given from Standard Input in the following format:

A B C

Output

If the given triple is poor, print Yes; otherwise, print No.

Sample Input 1

5 7 5

Sample Output 1

Yes

A and C are equal, but B is different from those two numbers, so this triple is poor.

Sample Input 2

4 4 4

Sample Output 2

No

A, B, and C are all equal, so this triple is not poor.

Sample Input 3

4 9 6

Sample Output 3

No

Sample Input 4

3 3 4

Sample Output 4

Yes

Solution in Rust (1.15.1) (judge verdict: Runtime Error)

use std::io;
use std::vec::Vec;
use std::str::FromStr;
use std::collections::HashMap;
fn main() {
    let mut vote_count = String::new();
    io::stdin().read_line(&mut vote_count).unwrap();
    vote_count.pop();
    let vote_count = u32::from_str(&vote_count).unwrap();

    let mut votes = HashMap::new();
    for _ in 0..vote_count {
        let mut vote = String::new();
        io::stdin().read_line(&mut vote).unwrap();
        vote.pop();
        let value = if let Some(cnt) = votes.get(&vote) {
            cnt + 1
        } else {
            1
        };
        votes.insert(vote, value);
    }

    let mut max_value = 0;
    let mut max_votes: Vec<String> = Vec::new();
    for (key, value) in votes.iter() {
        if *value > max_value {
            max_value = *value;
            max_votes.clear();
        }
        if *value == max_value {
            max_votes.push(key.to_string());
        }
    }

    max_votes.sort();
    for vote in max_votes.iter() {
        println!("{}", vote);
    }
}