Problem:
Score : 100 points

Problem Statement

Takahashi has K 500-yen coins. (Yen is the currency of Japan.)
If these coins add up to X yen or more, print Yes; otherwise, print No.

Constraints

1 \leq K \leq 100

1 \leq X \leq 10^5

Input

Input is given from Standard Input in the following format:

K X

Output

If the coins add up to X yen or more, print Yes; otherwise, print No.

Sample Input 1

2 900

Sample Output 1

Yes

Two 500-yen coins add up to 1000 yen, which is not less than X = 900 yen.

Sample Input 2

1 501

Sample Output 2

No

One 500-yen coin is worth 500 yen, which is less than X = 501 yen.

Sample Input 3

4 2000

Sample Output 3

Yes

Four 500-yen coins add up to 2000 yen, which is not less than X = 2000 yen.

Solution in Rust (1.15.1) (judge verdict: Wrong Answer)

use std::io;

fn main() {
    let values = parse_values::<u32>(2);
    let k = values[0];
    let x = values[1];
    let sum = 500 * k;
    if sum >= x {
        println!("yes");
    } else {
        println!("no");
    }
}

fn parse_line<T: std::str::FromStr>() -> T {
    let mut s = String::new();
    io::stdin().read_line(&mut s).ok();
    s.trim().parse().ok().unwrap()
}

fn parse_values<T: std::str::FromStr>(n: usize) -> Vec<T> {
    let line = parse_line::<String>();
    let mut split = line.split_whitespace();
    let mut values = Vec::with_capacity(n);
    for _ in 0..n {
        let v = split.next().unwrap().parse::<T>().ok().unwrap();
        values.push(v);
    }
    values
}