Problem:
Score: 100 points

Problem Statement

In AtCoder Kingdom, Gregorian calendar is used, and dates are written in the "year-month-day" order, or the "month-day" order without the year.

For example, May 3, 2018 is written as 2018-5-3, or 5-3 without the year.

In this country, a date is called Takahashi when the month and the day are equal as numbers. For example, 5-5 is Takahashi.

How many days from 2018-1-1 through 2018-a-b are Takahashi?

Constraints

a is an integer between 1 and 12 (inclusive).

b is an integer between 1 and 31 (inclusive).

2018-a-b is a valid date in Gregorian calendar.

Input

Input is given from Standard Input in the following format:

a b

Output

Print the number of days from 2018-1-1 through 2018-a-b that are Takahashi.

Sample Input 1

5 5

Sample Output 1

5

There are five days that are Takahashi: 1-1, 2-2, 3-3, 4-4 and 5-5.

Sample Input 2

2 1

Sample Output 2

1

There is only one day that is Takahashi: 1-1.

Sample Input 3

11 30

Sample Output 3

11

There are eleven days that are Takahashi: 1-1, 2-2, 3-3, 4-4, 5-5, 6-6, 7-7, 8-8, 9-9, 10-10 and 11-11.

Solution in Rust (1.15.1) (judge verdict: Accepted)

macro_rules! input {
    // ?
    (source = $s:expr, $($r:tt)*) => {
        let mut iter = $s.split_whitespace();
        let mut next = || { iter.next().unwrap() };
        input_inner!{next, $($r)*}
    };

    // stdinの生成 値の読み込み開始
    ($($r:tt)*) => {
        let stdin = std::io::stdin();
        let mut bytes = std::io::Read::bytes(std::io::BufReader::new(stdin.lock()));
        let mut next = move || -> String{
            bytes
                .by_ref()
                .map(|r|r.unwrap() as char)
                .skip_while(|c|c.is_whitespace())
                .take_while(|c|!c.is_whitespace())
                .collect()
        };
        input_inner!{next, $($r)*}
    };
}

macro_rules! input_inner {
    // ?
    ($next:expr) => {};
    // ?
    ($next:expr, ) => {};

    // 変数名:型の読み込みの繰り返し
    ($next:expr, $var:ident : $t:tt $($r:tt)*) => {
        let $var = read_value!($next, $t);
        input_inner!{$next $($r)*}
    };
}

macro_rules! read_value {
    // 値を読み込むベース 型,の繰り返し
    ($next:expr, ( $($t:tt),* )) => {
        ( $(read_value!($next, $t)),* )
    };

    // 配列の読み込み
    ($next:expr, [ $t:tt ; $len:expr ]) => {
        (0..$len).map(|_| read_value!($next, $t)).collect::<Vec<_>>()
    };

    // 文字列Vec<char>の読み込み
    ($next:expr, chars) => {
        read_value!($next, String).chars().collect::<Vec<char>>()
    };

    // usize1?の読み込み
    ($next:expr, usize1) => {
        read_value!($next, usize) - 1
    };

    // 指定した型で読み込み
    ($next:expr, $t:ty) => {
        $next().parse::<$t>().expect("Parse error")
    };
}
fn main() {
    input! {
        month:usize,
        day:usize,
    };

    println!("{}", solve(month,day) );
}

fn solve(month:usize,day:usize) -> usize{
    return if day >= month { month } else {month -1}
}
macro_rules! tests {
    ($($test_name:ident:$name:ident($( $args:expr ),*) => $expected:expr,)*) => {
        mod tests {
            $(
                #[test]
                fn $test_name() {
                    assert_eq!($expected,super::$name($($args),*));
                }
            )*
        }
    }
}


tests! {
    //テスト名:[引数]=>expected
    test1:solve(11,3) => 10,
    test2:solve(10,10) => 10,
    test3:solve(1,1) => 1,
    test4:solve(5,5) => 5,
}