Problem:
Score : 400 points

Problem Statement

There are N persons called Person 1 through Person N.

You are given M facts that "Person A_i and Person B_i are friends." The same fact may be given multiple times.

If X and Y are friends, and Y and Z are friends, then X and Z are also friends. There is no friendship that cannot be derived from the M given facts.

Takahashi the evil wants to divide the N persons into some number of groups so that every person has no friend in his/her group.

At least how many groups does he need to make?

Constraints

2 \leq N \leq 2\times 10^5

0 \leq M \leq 2\times 10^5

1\leq A_i,B_i\leq N

A_i \neq B_i

Input

Input is given from Standard Input in the following format:

N M
A_1 B_1
\vdots
A_M B_M

Output

Print the answer.

Sample Input 1

5 3
1 2
3 4
5 1

Sample Output 1

3

Dividing them into three groups such as \{1,3\}, \{2,4\}, and \{5\} achieves the goal.

Sample Input 2

4 10
1 2
2 1
1 2
2 1
1 2
1 3
1 4
2 3
2 4
3 4

Sample Output 2

4

Sample Input 3

10 4
3 1
4 1
5 9
2 6

Sample Output 3

3

Solution in Rust (1.42.0) (judge verdict: Accepted)

use proconio::{fastout, input};
use std::io::*;
use std::str::FromStr;

use std::cmp::{max, min};
use std::collections::HashSet;

struct UnionFind {
    parent: Vec<usize>,
    size: Vec<usize>,
}

impl UnionFind {
    fn new(n: usize) -> UnionFind {
        // initialize
        let mut v: Vec<usize> = vec![];
        for i in 0..n + 1 {
            v.push(i)
        }
        let mut s: Vec<usize> = vec![1; n + 1];

        UnionFind { parent: v, size: s }
    }

    fn root(&self, x: usize) -> usize {
        if self.parent[x] == x {
            return x;
        } else {
            return self.root(self.parent[x]);
        }
    }

    fn size(&self, a: usize) -> usize {
        let ra = self.root(a);
        self.size[ra]
    }

    fn unite(&mut self, a: usize, b: usize) {
        let mut ra = self.root(a);
        let mut rb = self.root(b);
        if ra == rb {
            return;
        }
        if self.size[ra] < self.size[rb] {
            std::mem::swap(&mut ra, &mut rb)
        };
        self.size[ra] += self.size[rb];
        self.parent[rb] = ra;
    }

    fn same(&self, a: usize, b: usize) -> bool {
        let ra = self.root(a);
        let rb = self.root(b);
        ra == rb
    }
}

// this is code for abc177
fn main() {
    input! {
        n: usize,
        m: usize,
        ab: [(usize, usize); m],
    }

    let mut uf = UnionFind::new(n);

    for i in 0..ab.len() {
        uf.unite(ab[i].0, ab[i].1);
    }

    let mut maxv = 0;
    for i in 0..n + 1 {
        maxv = max(maxv, uf.size(i));
    }
    println!("{}", maxv);
}