Problem:
Score : 300 points

Problem Statement

You are given a string s.
Among the different substrings of s, print the K-th lexicographically smallest one.

A substring of s is a string obtained by taking out a non-empty contiguous part in s.
For example, if s = ababc, a, bab and ababc are substrings of s, while ac, z and an empty string are not.
Also, we say that substrings are different when they are different as strings.

Let X = x_{1}x_{2}...x_{n} and Y = y_{1}y_{2}...y_{m} be two distinct strings. X is lexicographically larger than Y if and only if Y is a prefix of X or x_{j} > y_{j} where j is the smallest integer such that x_{j} \neq y_{j}.

Constraints

1 ≤ |s| ≤ 5000

s consists of lowercase English letters.

1 ≤ K ≤ 5

s has at least K different substrings.

Partial Score

200 points will be awarded as a partial score for passing the test set satisfying |s| ≤ 50.

Input

Input is given from Standard Input in the following format:

s
K

Output

Print the K-th lexicographically smallest substring of K.

Sample Input 1

aba
4

Sample Output 1

b

s has five substrings: a, b, ab, ba and aba.
Among them, we should print the fourth smallest one, b.
Note that we do not count a twice.

Sample Input 2

atcoderandatcodeer
5

Sample Output 2

andat

Sample Input 3

z
1

Sample Output 3

z

Solution in Rust (1.15.1) (judge verdict: Time Limit Exceeded)

use std::collections::BTreeSet;
fn read<T: std::str::FromStr>() -> T {
    let mut s = String::new();
    std::io::stdin().read_line(&mut s).ok();
    s.trim().parse().ok().unwrap()
}

fn read_vec<T: std::str::FromStr>() -> Vec<T> {
    read::<String>()
        .split_whitespace()
        .map(|e| e.parse().ok().unwrap())
        .collect()
}

fn read_vec2<T: std::str::FromStr>(n: u32) -> Vec<Vec<T>> {
    (0..n).map(|_| read_vec()).collect()
}
fn main(){
    let s = read::<String>();
    let kk = read::<i32>();
    let cp = s.clone().chars().collect::<Vec<char>>();
    let mut len = cp.len();
    let mut ans:BTreeSet<String>=  BTreeSet::new();
    let mut ss = Vec::new();
    // cp.debup();
    // cp.sort();
    for i in 0..len{
        for j in 1..len+1{
            for k in 0..len+1{
            //    ans.insert(s.get(k..j+i).unwrap_or("").to_string());
            ans.insert(s.chars().skip(k).take(j+i).collect::<String>());

            }
        }
    }
    for x in ans{
        ss.push(x);
    }
    ss.sort();
    ss.reverse();
    ss.pop();
    let anslen = ss.len();
    println!("{}",ss[(anslen as i32 -kk) as usize]);
}