Problem:
Score : 600 points

Problem Statement

A bracket sequence is a string that is one of the following:

An empty string;

The concatenation of (, A, and ) in this order, for some bracket sequence A ;

The concatenation of A and B in this order, for some non-empty bracket sequences A and B /

Given are N strings S_i. Can a bracket sequence be formed by concatenating all the N strings in some order?

Constraints

1 \leq N \leq 10^6

The total length of the strings S_i is at most 10^6.

S_i is a non-empty string consisting of ( and ).

Input

Input is given from Standard Input in the following format:

N
S_1
:
S_N

Output

If a bracket sequence can be formed by concatenating all the N strings in some order, print Yes; otherwise, print No.

Sample Input 1

2
)
(()

Sample Output 1

Yes

Concatenating (() and ) in this order forms a bracket sequence.

Sample Input 2

2
)(
()

Sample Output 2

No

Sample Input 3

4
((()))
((((((
))))))
()()()

Sample Output 3

Yes

Sample Input 4

3
(((
)
)

Sample Output 4

No

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

//! Framework <https://github.com/vain0x/procon>

#![allow(non_snake_case)]
#![allow(unused_imports)]

use std::collections::*;

pub struct Scan(Box<dyn Iterator<Item = &'static str>>); // '

impl Scan {
    fn new() -> Self {
        let mut buf = String::new();
        let read_line = move || {
            std::io::stdin().read_line(&mut buf).unwrap();
            Box::leak(buf.split_off(0).into_boxed_str()).split_whitespace()
        };
        Scan(Box::new(std::iter::repeat_with(read_line).flatten()))
    }

    pub fn word<T: std::str::FromStr>(&mut self) -> T {
        self.0.next().unwrap().parse().ok().unwrap()
    }

    pub fn list<T: std::str::FromStr>(&mut self, len: usize) -> Vec<T> {
        std::iter::repeat_with(|| self.word()).take(len).collect()
    }
}

fn calc(s: &str) -> (i64, i64) {
    let mut balance = 0;
    let mut least = 0;

    for c in s.chars() {
        match c {
            '(' => {
                balance += 1;
            }
            ')' => {
                balance -= 1;
            }
            _ => unreachable!(),
        }
        least = least.min(balance);
    }

    ((-least).max(0), balance)
}

fn main() {
    let mut scan = Scan::new();

    let N = scan.word::<usize>();
    let S = scan.list::<String>(N);

    let mut T = BTreeMap::new();

    for s in S {
        let (r, b) = calc(&s);
        *T.entry((r, Reverse(b))).or_insert(0) += 1;
    }

    let mut ok = true;
    let mut balance = 0_i64;

    use std::cmp::Reverse;
    use std::ops::Bound::*;

    for _ in 0..N {
        match T
            .range_mut(..=(balance, Reverse(std::i64::MIN)))
            .rev()
            .next()
        {
            Some((&(least, Reverse(b)), m)) => {
                debug_assert!(balance >= least);
                balance += b;
                *m -= 1;

                if balance < 0 {
                    ok = false;
                    break;
                }

                if *m == 0 {
                    T.remove(&(balance, Reverse(b)));
                }
            }
            None => {
                ok = false;
                break;
            }
        }
    }
    ok = ok && balance == 0;

    println!("{}", if ok { "Yes" } else { "No" });
}