Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in Rust (1.42.0) (judge verdict: Accepted)

use proconio::{
   fastout, input,
   marker::{Bytes, Chars, Isize1, Usize1},
};

fn dfs(
   i: usize,
   f: bool,
   s: &Vec<String>,
   a: isize,
   b: isize,
   c: isize,
   ans: &mut Vec<&str>,
) -> bool {
   if i == s.len() {
      return true;
   }
   if a < 0 || b < 0 || c < 0 {
      return false;
   }
   if s[i] == "AB" {
      if f {
         if b <= 0 {
            return false;
         } else {
            if dfs(i + 1, true, s, a + 1, b - 1, c, ans) {
            } else if dfs(i + 1, false, s, a + 1, b - 1, c, ans) {
            } else {
               return false;
            }
         }
      } else {
         if a <= 0 {
            return false;
         } else {
            if dfs(i + 1, true, s, a - 1, b + 1, c, ans) {
            } else if dfs(i + 1, false, s, a - 1, b + 1, c, ans) {
            } else {
               return false;
            }
         }
      }
   } else if s[i] == "BC" {
      if f {
         if c <= 0 {
            return false;
         } else {
            if dfs(i + 1, true, s, a, b + 1, c - 1, ans) {
            } else if dfs(i + 1, false, s, a, b + 1, c - 1, ans) {
            } else {
               return false;
            }
         }
      } else {
         if b <= 0 {
            return false;
         } else {
            if dfs(i + 1, true, s, a, b - 1, c + 1, ans) {
            } else if dfs(i + 1, false, s, a, b - 1, c + 1, ans) {
            } else {
               return false;
            }
         }
      }
   } else {
      if f {
         if c <= 0 {
            return false;
         } else {
            if dfs(i + 1, true, s, a + 1, b, c - 1, ans) {
            } else if dfs(i + 1, false, s, a + 1, b, c - 1, ans) {
            } else {
               return false;
            }
         }
      } else {
         if a <= 0 {
            return false;
         } else {
            if dfs(i + 1, true, s, a - 1, b, c + 1, ans) {
            } else if dfs(i + 1, false, s, a - 1, b, c + 1, ans) {
            } else {
               return false;
            }
         }
      }
   }
   //println!("{} {} {}", i, s[i], f);
   ans.push(if s[i] == "AB" {
      if f {
         "A"
      } else {
         "B"
      }
   } else if s[i] == "BC" {
      if f {
         "B"
      } else {
         "C"
      }
   } else {
      if f {
         "A"
      } else {
         "C"
      }
   });
   true
}
#[fastout]
fn main() {
   input! {
      n:usize,a:isize,b:isize,c:isize,
      s:[String;n]
   }
   let mut s1 = vec![];
   let mut s2 = vec![];
   if dfs(0, false, &s, a, b, c, &mut s1) {
      println!("Yes");
      for i in s1.iter().rev() {
         println!("{}", i);
      }
   } else if dfs(0, true, &s, a, b, c, &mut s2) {
      println!("Yes");
      for i in s2.iter().rev() {
         println!("{}", i);
      }
   } else {
      println!("No");
   }
}