Problem:
Score : 200 points

Problem Statement

In some other world, today is the day before Christmas Eve.

Mr. Takaha is buying N items at a department store. The regular price of the i-th item (1 \leq i \leq N) is p_i yen (the currency of Japan).

He has a discount coupon, and can buy one item with the highest price for half the regular price. The remaining N-1 items cost their regular prices. What is the total amount he will pay?

Constraints

2 \leq N \leq 10

100 \leq p_i \leq 10000

p_i is an even number.

Input

Input is given from Standard Input in the following format:

N
p_1
p_2
:
p_N

Output

Print the total amount Mr. Takaha will pay.

Sample Input 1

3
4980
7980
6980

Sample Output 1

15950

The 7980-yen item gets the discount and the total is 4980 + 7980 / 2 + 6980 = 15950 yen.

Note that outputs such as 15950.0 will be judged as Wrong Answer.

Sample Input 2

4
4320
4320
4320
4320

Sample Output 2

15120

Only one of the four items gets the discount and the total is 4320 / 2 + 4320 + 4320 + 4320 = 15120 yen.

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::io;

fn read_i32_exn() -> i32 {
    let mut n = String::new();
    io::stdin().read_line(&mut n).expect("Failed to input");
    (*n).trim().parse::<i32>().unwrap()
}

fn main() {
    let mut v: Vec<i32> = Vec::new();
    let n = read_i32_exn();
    for i in 0..n {
        v.push(read_i32_exn());
    }
    v.sort_by(|a, b| b.cmp(a));
    v[0] = v[0] / 2;
    let ans: i32 = (*v).iter().sum();
    println!("{}", ans);
}