Problem:
Score : 400 points

Problem Statement

Takahashi had a pair of two positive integers not exceeding N, (a,b), which he has forgotten.
He remembers that the remainder of a divided by b was greater than or equal to K.
Find the number of possible pairs that he may have had.

Constraints

1 \leq N \leq 10^5

0 \leq K \leq N-1

All input values are integers.

Input

Input is given from Standard Input in the following format:

N K

Output

Print the number of possible pairs that he may have had.

Sample Input 1

5 2

Sample Output 1

7

There are seven possible pairs: (2,3),(5,3),(2,4),(3,4),(2,5),(3,5) and (4,5).

Sample Input 2

10 0

Sample Output 2

100

Sample Input 3

31415 9265

Sample Output 3

287927211

Solution in Rust (1.15.1) (judge verdict: Accepted)

fn read_spc<T: std::str::FromStr>() -> Vec<T> {
    let mut s = String::new();
    std::io::stdin().read_line(&mut s).ok();
    s.trim().split_whitespace()
        .map(|e| e.parse().ok().unwrap()).collect()
}

fn main() {
    remainder_reminder();
}

fn remainder_reminder() {
    let nk: Vec<i64> = read_spc();
    let n = nk[0];
    let k = nk[1];
    let mut m: i64 = 0;
       if k == 0 {
        m = n * n;
    } else {
        for b in 2..(n + 1) {
            let q = n / b;
            let r = n % b;
            m += q * max_i64(0, b - k) + max_i64(0, r - k + 1);
        }
    }
    println!("{}", m);
}

fn max_i64(n: i64, m: i64) -> i64 {
    let diff = n - m;
    match diff {
        diff if diff < 0 => m,
        _                => n
    }
}