Problem:
Score : 600 points

Problem Statement

Given is an integer N.
Find the minimum possible positive integer k such that (1+2+\cdots+k) is a multiple of N.
It can be proved that such a positive integer k always exists.

Constraints

1 \leq N \leq 10^{15}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N

Output

Print the answer in a line.

Sample Input 1

11

Sample Output 1

10

1+2+\cdots+10=55 holds and 55 is indeed a multple of N=11.
There are no positive integers k \leq 9 that satisfy the condition, so the answer is k = 10.

Sample Input 2

20200920

Sample Output 2

1100144

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

#![allow(unused_imports)]
use std::cmp::*;
use std::collections::*;
use std::io::Write;
use std::ops::Bound::*;

#[allow(unused_macros)]
macro_rules! debug {
    ($($e:expr),*) => {
        #[cfg(debug_assertions)]
        $({
            let (e, mut err) = (stringify!($e), std::io::stderr());
            writeln!(err, "{} = {:?}", e, $e).unwrap()
        })*
    };
}

fn main() {
    let n = read::<i64>();
    let n = 2 * n;
    let mut ans = std::i64::MAX;
    for i in 1..n + 1 {
        if i * i > n {
            break;
        }
        if n % i == 0 {
            let r = [0, n / i - 1];
            let m = [i, n / i];
            if m[0] != 1 && m[1] != 1 {
                let x = crt(&r, &m);
                if let Some((x, y)) = x {
                    ans = min(ans, x);
                }
            }
            let r = [i - 1, 0];
            if m[0] != 1 && m[1] != 1 {
                let m = [i, n / i];
                let x = crt(&r, &m);
                if let Some((x, y)) = x {
                    ans = min(ans, x);
                }
            }
        }
    }
    println!("{}", ans);
}

fn read<T: std::str::FromStr>() -> T {
    let mut s = String::new();
    std::io::stdin().read_line(&mut s).ok();
    s.trim().parse().ok().unwrap()
}

fn read_vec<T: std::str::FromStr>() -> Vec<T> {
    read::<String>()
        .split_whitespace()
        .map(|e| e.parse().ok().unwrap())
        .collect()
}

pub fn inv_gcd(a: i64, b: i64) -> (i64, i64) {
    let a = a.rem_euclid(b);
    if a == 0 {
        return (b, 0);
    }
    let mut s = b;
    let mut t = a;
    let mut m0 = 0;
    let mut m1 = 1;

    while t != 0 {
        let u = s / t;
        s -= t * u;
        m0 -= m1 * u;
        std::mem::swap(&mut s, &mut t);
        std::mem::swap(&mut m0, &mut m1);
    }
    if m0 < 0 {
        m0 += b / s;
    }
    (s, m0)
}

// return y (mod z)
pub fn crt(r: &[i64], m: &[i64]) -> Option<(i64, i64)> {
    assert_eq!(r.len(), m.len());
    // Contracts: 0 <= r0 < m0
    let (mut r0, mut m0) = (0, 1);
    for (&(mut ri), &(mut mi)) in r.iter().zip(m.iter()) {
        assert!(1 < mi);
        ri = ri.rem_euclid(mi);
        if m0 < mi {
            std::mem::swap(&mut r0, &mut ri);
            std::mem::swap(&mut m0, &mut mi);
        }
        if m0 % mi == 0 {
            if r0 % mi != ri {
                return None;
            }
            continue;
        }
        let (g, im) = inv_gcd(m0, mi);
        let u1 = mi / g;
        // |ri - r0| < (m0 + mi) <= lcm(m0, mi)
        if (ri - r0) % g != 0 {
            return None;
        }
        let x = (ri - r0) / g % u1 * im % u1;

        r0 += x * m0;
        m0 *= u1; // -> lcm(m0, mi)
        if r0 < 0 {
            r0 += m0
        };
    }

    Some((r0, m0))
}