Problem:
Score : 200 points

Problem Statement

Rng is preparing a problem set for a qualification round of CODEFESTIVAL.

He has N candidates of problems. The difficulty of the i-th candidate is D_i.

There must be M problems in the problem set, and the difficulty of the i-th problem must be T_i. Here, one candidate of a problem cannot be used as multiple problems.

Determine whether Rng can complete the problem set without creating new candidates of problems.

Constraints

1 \leq N \leq 200,000

1 \leq D_i \leq 10^9

1 \leq M \leq 200,000

1 \leq T_i \leq 10^9

All numbers in the input are integers.

Partial Score

100 points will be awarded for passing the test set satisfying N \leq 100 and M \leq 100.

Input

Input is given from Standard Input in the following format:

N
D_1 D_2 ... D_N
M
T_1 T_2 ... T_M

Output

Print YES if Rng can complete the problem set without creating new candidates of problems; print NO if he cannot.

Sample Input 1

5
3 1 4 1 5
3
5 4 3

Sample Output 1

YES

Sample Input 2

7
100 200 500 700 1200 1600 2000
6
100 200 500 700 1600 1600

Sample Output 2

NO

Not enough 1600s.

Sample Input 3

1
800
5
100 100 100 100 100

Sample Output 3

NO

Sample Input 4

15
1 2 2 3 3 3 4 4 4 4 5 5 5 5 5
9
5 4 3 2 1 2 3 4 5

Sample Output 4

YES

Solution in Rust (1.15.1) (judge verdict: Accepted)

use std::collections::HashMap;
use std::io::*;
use std::str::*;

fn read<T: FromStr>() -> T {
    let stdin = stdin();
    let s = stdin
        .bytes()
        .map(|c| c.unwrap() as char)
        .skip_while(|c| c.is_whitespace())
        .take_while(|c| !c.is_whitespace())
        .collect::<String>();
    s.parse::<T>().ok().unwrap()
}

fn usize() -> usize {
    read()
}

fn vec_usize(n: usize) -> Vec<usize> {
    let mut vec = Vec::new();
    for _ in 0..n {
        vec.push(usize())
    }
    vec
}

fn main() {
    let n = usize();
    let d_vec = vec_usize(n);
    let m = usize();
    let t_vec = vec_usize(m);
    let mut ds = HashMap::new();
    let mut ts = HashMap::new();
    for i in 0..n {
        *ds.entry(d_vec[i] + 1).or_insert(0) += 1;
    }
    for i in 0..m {
        *ts.entry(t_vec[i] + 1).or_insert(0) += 1;
    }
    for level in ts.keys() {
        if ts[level] > *ds.get(level).unwrap_or(&0) {
            println!("{}", "NO");
            return;
        }
    }
    println!("{}", "YES");
}