Problem:
Score : 300 points

Problem Statement

You are given an undirected connected graph with N vertices and M edges that does not contain self-loops and double edges.

The i-th edge (1 \leq i \leq M) connects Vertex a_i and Vertex b_i.

An edge whose removal disconnects the graph is called a bridge.

Find the number of the edges that are bridges among the M edges.

Notes

A self-loop is an edge i such that a_i=b_i (1 \leq i \leq M).

Double edges are a pair of edges i,j such that a_i=a_j and b_i=b_j (1 \leq i<j \leq M).

An undirected graph is said to be connected when there exists a path between every pair of vertices.

Constraints

2 \leq N \leq 50

N-1 \leq M \leq min(N(N−1)⁄2,50)

1 \leq a_i<b_i \leq N

The given graph does not contain self-loops and double edges.

The given graph is connected.

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
a_2 b_2
:
a_M b_M

Output

Print the number of the edges that are bridges among the M edges.

Sample Input 1

7 7
1 3
2 7
3 4
4 5
4 6
5 6
6 7

Sample Output 1

4

The figure below shows the given graph:

The edges shown in red are bridges. There are four of them.

Sample Input 2

3 3
1 2
1 3
2 3

Sample Output 2

0

It is possible that there is no bridge.

Sample Input 3

6 5
1 2
2 3
3 4
4 5
5 6

Sample Output 3

5

It is possible that every edge is a bridge.

Solution in Rust (1.15.1) (judge verdict: Accepted)

macro_rules! scan {
    () => {
        {
            let mut line: String = String::new();
            std::io::stdin().read_line(&mut line).unwrap();
            line.trim().to_string()
        }
    };
    (;;$n:expr) => {
        (0..$n).map(|_| scan!()).collect::<Vec<_>>()
    };
    ($t:ty) => {
        {
            let mut line: String = String::new();
            std::io::stdin().read_line(&mut line).unwrap();
            line.trim().parse::<$t>().unwrap()
        }
    };
    ($($t:ty),*) => {
        {
            let mut line: String = String::new();
            std::io::stdin().read_line(&mut line).unwrap();
            let mut iter = line.split_whitespace();
            (
                $(iter.next().unwrap().parse::<$t>().unwrap(),)*
            )
        }
    };
    ($t:ty;;) => {
        {
            let mut line: String = String::new();
            std::io::stdin().read_line(&mut line).unwrap();
            line.split_whitespace()
                .map(|t| t.parse::<$t>().unwrap())
                .collect::<Vec<_>>()
        }
    };
    ($t:ty;;$n:expr) => {
        (0..$n).map(|_| scan!($t;;)).collect::<Vec<_>>()
    };
    ($t:ty; $n:expr) => {
        (0..$n).map(|_|
                    scan!($t)
        ).collect::<Vec<_>>()
    };
    ($($t:ty),*; $n:expr) => {
        (0..$n).map(|_|
                    scan!($($t),*)
        ).collect::<Vec<_>>()
    };
}

fn dfs(graph: &[Vec<i64>], n: usize, visited: &mut Vec<bool>) {
    visited[n] = true;

    for &m in graph[n].iter() {
        if m >= 0 && !visited[m as usize] {
            dfs(graph, m as usize, visited)
        }
    }
}

fn all_visit(graph: &[Vec<i64>]) -> bool {
    let mut visited = (0..graph.len()).map(|_| false).collect();
    dfs(&graph, 0, &mut visited);

    for v in visited.into_iter() {
        if !v {
            return false;
        }
    }
    true
}

fn main() {
    let (n, m) = scan!(usize, usize);

    let mut graph: Vec<Vec<_>> = (0..n).map(|_| Vec::new()).collect();
    for _ in 0..m {
        let (a, b) = scan!(usize, i64);
        graph[a - 1].push(b - 1);
        graph[(b - 1) as usize].push(a as i64 - 1);
    }

    let mut ans = 0;
    for i in 0..graph.len() {
        for j in 0..graph[i].len() {
            let n = graph[i][j];
            graph[i][j] = -1;
            if !all_visit(&graph) {
                ans += 1
            }
            graph[i][j] = n;
        }
    }
    println!("{}", ans)
}