Problem:
Score : 400 points

Problem Statement

You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

In the i-th operation, you replace every element whose value is B_{i} with C_{i}.

For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

All values in input are integers.

1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}

B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:

N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}

Output

Print Q integers S_{i} to Standard Output in the following format:

S_{1}
S_{2}
\vdots
S_{Q}

Note that S_{i} may not fit into a 32-bit integer.

Sample Input 1

4
1 2 3 4
3
1 2
3 4
2 4

Sample Output 1

11
12
16

Initially, the sequence A is 1,2,3,4.

After each operation, it becomes the following:

2, 2, 3, 4

2, 2, 4, 4

4, 4, 4, 4

Sample Input 2

4
1 1 1 1
3
1 2
2 1
3 5

Sample Output 2

8
4
4

Note that the sequence A may not contain an element whose value is B_{i}.

Sample Input 3

2
1 2
3
1 100
2 100
100 1000

Sample Output 3

102
200
2000

Solution in Rust (1.42.0) (judge verdict: Accepted)

#![allow(non_snake_case, unused_mut)]
use std::collections::HashMap;
fn main() {
    proconio::input! {
        N:i64,
        A:[i64;N],
        Q:i64,
        BC:[(i64,i64);Q]
    }
    let mut nums = HashMap::new();
    for &a in A.iter() {
        *nums.entry(a).or_insert(0) += 1i64;
    }
    let mut ans = 0;
    for (&k, &v) in nums.iter() {
        ans += k * v;
    }
    // これは通らない。
    //    for &(b, c) in BC.iter() {
    //        if let Some(v) = nums.get(&b) {
    //            *nums.entry(c).or_insert(0) += 1;
    //            ans = ans + (c - b) * v;
    //            *nums.entry(b).or_insert(0) = 0;
    //        }
    //        println!("{}", ans);
    //    }

    for &(b, c) in BC.iter() {
        let v = nums.remove(&b).unwrap_or(0);
        ans = ans + (c - b) * v;
        *nums.entry(c).or_insert(0) += v;
        println!("{}", ans);
    }
}