Problem:
Score : 400 points

Problem Statement

Given are integers A, B, and N.

Find the maximum possible value of floor(Ax/B) - A × floor(x/B) for a non-negative integer x not greater than N.

Here floor(t) denotes the greatest integer not greater than the real number t.

Constraints

1 ≤ A ≤ 10^{6}

1 ≤ B ≤ 10^{12}

1 ≤ N ≤ 10^{12}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B N

Output

Print the maximum possible value of floor(Ax/B) - A × floor(x/B) for a non-negative integer x not greater than N, as an integer.

Sample Input 1

5 7 4

Sample Output 1

2

When x=3, floor(Ax/B)-A×floor(x/B) = floor(15/7) - 5×floor(3/7) = 2. This is the maximum value possible.

Sample Input 2

11 10 9

Sample Output 2

9

Solution in Rust (1.42.0) (judge verdict: Time Limit Exceeded)

#![allow(unused_imports)]
#![allow(unused_variables)]

use itertools::Itertools;
use proconio::{fastout, input};

#[fastout]
fn main() {
    input! {
        a: usize,
        b: usize,
        n: usize,
    }
    // annotate for rust-analyzer
    let a: usize = a;
    let b: usize = b;
    let n: usize = n;

    let end = if n > b { b } else { n + 1 };
    let mut ans = 0;
    for i in 0..end {
        let tmp = a * i / b - a * (i / b);
        //println!("{}", tmp);
        if ans < tmp {
            ans = tmp;
        }
    }

    println!("{}", ans);
}