Problem:
Score : 600 points

Problem Statement

Given are two sequences A and B, both of length N.
A and B are each sorted in the ascending order.
Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.

Constraints

1\leq N \leq 2 \times 10^5

1\leq A_i,B_i \leq N

A and B are each sorted in the ascending order.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N

Output

If there exist no reorderings that satisfy the condition, print No.

If there exists a reordering that satisfies the condition, print Yes on the first line.
After that, print a reordering of B on the second line, separating terms with a whitespace.

If there are multiple reorderings that satisfy the condition, you can print any of them.

Sample Input 1

6
1 1 1 2 2 3
1 1 1 2 2 3

Sample Output 1

Yes
2 2 3 1 1 1

Sample Input 2

3
1 1 2
1 1 3

Sample Output 2

No

Sample Input 3

4
1 1 2 3
1 2 3 3

Sample Output 3

Yes
3 3 1 2

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

#![allow(unused_imports)]
use std::cmp::*;
use std::collections::*;
use std::io::Write;
use std::ops::Bound::*;

#[allow(unused_macros)]
macro_rules! debug {
    ($($e:expr),*) => {
        #[cfg(debug_assertions)]
        $({
            let (e, mut err) = (stringify!($e), std::io::stderr());
            writeln!(err, "{} = {:?}", e, $e).unwrap()
        })*
    };
}

fn make_pairs(a: &Vec<usize>, n: usize) -> Vec<(usize, usize)> {
    let mut a_count = vec![0; n];
    for i in 0..n {
        a_count[a[i]] += 1;
    }
    let mut a_pairs = vec![];
    for i in 0..n {
        if a_count[i] > 0 {
            a_pairs.push((a_count[i], i));
        }
    }
    a_pairs.sort();
    a_pairs.reverse();
    a_pairs
}

fn make_count(a: &Vec<usize>, n: usize) -> Vec<usize> {
    let mut a_count = vec![0; n];
    for i in 0..n {
        a_count[a[i]] += 1;
    }
    a_count
}

fn main() {
    let n = read::<usize>();
    let a = read_vec::<usize>()
        .iter()
        .map(|&x| x - 1)
        .collect::<Vec<_>>();
    let b = read_vec::<usize>()
        .iter()
        .map(|&x| x - 1)
        .collect::<Vec<_>>();

    let a_count = make_count(&a, n);
    let mut b_count = make_count(&b, n);

    for i in 0..n {
        if min(a_count[i], b_count[i]) * 2 > n {
            println!("No");
            return;
        }
    }

    let mut matched = vec![0; n];
    for i in 0..n {
        matched[i] = min(a_count[i], b_count[i]);
    }

    let mut a_sorted_by = a.clone();
    a_sorted_by.sort_by_key(|&x| matched[x]);
    a_sorted_by.reverse();
    debug!(a_sorted_by);
    let mut b_sorted_by = (0..n).collect::<Vec<_>>();
    b_sorted_by.sort_by_key(|&x| matched[x]);
    b_sorted_by.reverse();

    let mut offset = 0;
    let mut answers = HashMap::new();
    for (i, anum) in a_sorted_by.into_iter().enumerate() {
        //let mut offset = 0;
        loop {
            let next_b = b_sorted_by[(i + offset) % n];
            if b_count[next_b] == 0 || anum == next_b {
                offset += 1;
                if offset > 10 * n {
                    debug!(b_count);
                    println!("No");
                    return;
                }
                continue;
            }
            break;
        }
        //debug!(anum, b_sorted_by[(i + offset) % n]);
        b_count[b_sorted_by[(i + offset) % n]] -= 1;
        answers
            .entry(anum)
            .or_insert(vec![])
            .push(b_sorted_by[(i + offset) % n]);
    }
    println!("Yes");

    let mut idx = vec![0; n];
    for anum in a {
        debug!(anum, answers[&anum]);
        print!("{} ", answers[&anum][idx[anum]] + 1);
        idx[anum] += 1;
    }
    println!("");
}

fn read<T: std::str::FromStr>() -> T {
    let mut s = String::new();
    std::io::stdin().read_line(&mut s).ok();
    s.trim().parse().ok().unwrap()
}

fn read_vec<T: std::str::FromStr>() -> Vec<T> {
    read::<String>()
        .split_whitespace()
        .map(|e| e.parse().ok().unwrap())
        .collect()
}