Problem:
Score : 700 points

Problem Statement

Snuke has decided to play a game, where the player runs a railway company.
There are M+1 stations on Snuke Line, numbered 0 through M.
A train on Snuke Line stops at station 0 and every d-th station thereafter, where d is a predetermined constant for each train.
For example, if d = 3, the train stops at station 0, 3, 6, 9, and so forth.

There are N kinds of souvenirs sold in areas around Snuke Line. The i-th kind of souvenirs can be purchased when the train stops at one of the following stations: stations l_i, l_i+1, l_i+2, ..., r_i.

There are M values of d, the interval between two stops, for trains on Snuke Line: 1, 2, 3, ..., M.
For each of these M values, find the number of the kinds of souvenirs that can be purchased if one takes a train with that value of d at station 0.
Here, assume that it is not allowed to change trains.

Constraints

1 ≦ N ≦ 3 × 10^{5}

1 ≦ M ≦ 10^{5}

1 ≦ l_i ≦ r_i ≦ M

Input

The input is given from Standard Input in the following format:

N M
l_1 r_1
:
l_{N} r_{N}

Output

Print the answer in M lines. The i-th line should contain the maximum number of the kinds of souvenirs that can be purchased if one takes a train stopping every i-th station.

Sample Input 1

3 3
1 2
2 3
3 3

Sample Output 1

3
2
2

If one takes a train stopping every station, three kinds of souvenirs can be purchased: kind 1, 2 and 3.

If one takes a train stopping every second station, two kinds of souvenirs can be purchased: kind 1 and 2.

If one takes a train stopping every third station, two kinds of souvenirs can be purchased: kind 2 and 3.

Sample Input 2

7 9
1 7
5 9
5 7
5 9
1 1
6 8
3 4

Sample Output 2

7
6
6
5
4
5
5
3
2

Solution in Rust (1.15.1) (judge verdict: Time Limit Exceeded)

use std::io;
fn main() {
  let mut input_line = String::new();
  io::stdin().read_line(&mut input_line).unwrap();
  let input = input_line.trim().split(" ").collect::<Vec<&str>>();
  let n = input[0].trim().parse::<usize>().unwrap();
  let m = input[1].trim().parse::<usize>().unwrap();
  
  let mut data: Vec<Vec<usize>> = Vec::with_capacity(n);
  for _ in 0..n {
    let mut input_line = String::new();
    io::stdin().read_line(&mut input_line).unwrap();
    data.push(input_line.trim().split(" ").map(|z| z.trim().parse::<usize>().unwrap()).collect());
  }
  
  for i in 1..m+1 {
    let mut sum = 0;
    for ref x in data.iter() {
      let l = (x[0]-1) / i + 1;
      let r = x[1] / i;
      if l <= r { sum += 1; }
    }
    println!("{}", sum);
  }
}