Problem:
Score : 200 points

Problem Statement

There is a square in the xy-plane. The coordinates of its four vertices are (x_1,y_1),(x_2,y_2),(x_3,y_3) and (x_4,y_4) in counter-clockwise order.
(Assume that the positive x-axis points right, and the positive y-axis points up.)

Takahashi remembers (x_1,y_1) and (x_2,y_2), but he has forgot (x_3,y_3) and (x_4,y_4).

Given x_1,x_2,y_1,y_2, restore x_3,y_3,x_4,y_4. It can be shown that x_3,y_3,x_4 and y_4 uniquely exist and have integer values.

Constraints

|x_1|,|y_1|,|x_2|,|y_2| \leq 100

(x_1,y_1) ≠ (x_2,y_2)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

x_1 y_1 x_2 y_2

Output

Print x_3,y_3,x_4 and y_4 as integers, in this order.

Sample Input 1

0 0 0 1

Sample Output 1

-1 1 -1 0

(0,0),(0,1),(-1,1),(-1,0) is the four vertices of a square in counter-clockwise order.
Note that (x_3,y_3)=(1,1),(x_4,y_4)=(1,0) is not accepted, as the vertices are in clockwise order.

Sample Input 2

2 3 6 6

Sample Output 2

3 10 -1 7

Sample Input 3

31 -41 -59 26

Sample Output 3

-126 -64 -36 -131

Solution in Rust (1.15.1) (judge verdict: Accepted)

fn read<T: std::str::FromStr>() -> T {
    let mut s = String::new();
    std::io::stdin().read_line(&mut s).ok();
    s.trim().parse().ok().unwrap()
}

fn read_vec<T: std::str::FromStr>() -> Vec<T> {
    read::<String>()
        .split_whitespace()
        .map(|e| e.parse().ok().unwrap())
        .collect()
}

fn read_vec2<T: std::str::FromStr>(n: u32) -> Vec<Vec<T>> {
    (0..n).map(|_| read_vec()).collect()
}
fn main(){
    let p = read_vec::<i64>();
    let (x1,y1,x2,y2) = (p[0],p[1],p[2],p[3]);
    let xd = x2 -x1;
    let yd = y2-y1;
    let ax = xd.abs();
    let ay = yd.abs();
    let mut x3 = 0;
    let mut x4 = 0;
    let mut y3 = 0;
    let mut y4 = 0;
    if xd >= 0 && yd >= 0{
         x3 = x2 - ay;
         y3 = y2 + ax;
         x4 = x1 - ay;
         y4 = y1 + ax; 
    } else if xd <= 0 && yd >= 0 {
        x3 =x2 - ay;
        y3 = y2 - ax;
        x4 = x1 - ay;
        y4 = y1 -ax;
    } else if  xd >= 0 && yd <= 0 {
        x3 =x2 + ay;
        y3 = y2 + ax;
        x4 = x1  + ay;
        y4 = y1  +ax;
    } else if xd <= 0 && yd <= 0{
      x3 =x2 + ay;
        y3 = y2 - ax;
        x4 = x1  + ay;
        y4 = y1 -ax;
    }
    println!("{} {} {} {}",x3,y3,x4,y4 );
}