Problem:
Score : 300 points

Problem Statement

A company has N members, who are assigned ID numbers 1, ..., N.

Every member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.

When a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.

You are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq A_i < i

Input

Input is given from Standard Input in the following format:

N
A_2 ... A_N

Output

For each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.

Sample Input 1

5
1 1 2 2

Sample Output 1

2
2
0
0
0

The member numbered 1 has two immediate subordinates: the members numbered 2 and 3.

The member numbered 2 has two immediate subordinates: the members numbered 4 and 5.

The members numbered 3, 4, and 5 do not have immediate subordinates.

Sample Input 2

10
1 1 1 1 1 1 1 1 1

Sample Output 2

9
0
0
0
0
0
0
0
0
0

Sample Input 3

7
1 2 3 4 5 6

Sample Output 3

1
1
1
1
1
1
0

Solution in Rust (1.42.0) (judge verdict: Accepted)

use std::io;
pub trait ExRead {
    fn read_line(&mut self) -> io::Result<String>;
    fn read_to_string(&mut self) -> io::Result<String>;
}

impl<'a> ExRead for io::StdinLock<'a> {
    fn read_line(&mut self) -> io::Result<String> {
        let mut buf = String::new();
        io::BufRead::read_line(self, &mut buf).map(|_| buf)
    }

    fn read_to_string(&mut self) -> io::Result<String> {
        self.read_line().map(|s| s.trim().to_string())
    }
}

fn main() {
    let n: usize;
    let a: Vec<usize>;
    let mut ans = Vec::new();

    {
        let stdin = std::io::stdin();
        let mut lkin = stdin.lock();
        let mut input = lkin.read_line().unwrap()
            .split_whitespace()
            .map(|e| e.parse().ok().unwrap()).collect::<Vec<_>>().into_iter();
        n = input.next().unwrap();
        a = lkin.read_line().unwrap()
            .split_whitespace()
            .map(|e| e.parse().ok().unwrap()).collect::<Vec<_>>();
    }

    ans.resize(n, 0);
    a.iter().for_each(|e|
        *ans.get_mut(e-1).unwrap() += 1
    );

    ans.iter().for_each(|a| println!("{}", a));
}