Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

use proconio::{input,fastout};

#[fastout]
fn main() {
  input!{n: usize};
  let mut r = 1usize;
  for _ in 0..n {
    input!{a: usize};
    if a == 0 {
      println!("0");
      return;
    }
    r = match r.checked_mul(a) {
      Some(v) => v,
      None => {
        println!("-1");
        return;
      }
    }
  }
  if r > 1000000000000000000 {
    println!("-1");
  } else {
    println!("{}", r);
  }
}