Problem:
Score : 100 points

Problem Statement

Based on some criterion, Snuke divided the integers from 1 through 12 into three groups as shown in the figure below.
Given two integers x and y (1 ≤ x < y ≤ 12), determine whether they belong to the same group.

Constraints

x and y are integers.

1 ≤ x < y ≤ 12

Input

Input is given from Standard Input in the following format:

x y

Output

If x and y belong to the same group, print Yes; otherwise, print No.

Sample Input 1

1 3

Sample Output 1

Yes

Sample Input 2

2 4

Sample Output 2

No

Solution in Rust (1.15.1) (judge verdict: Accepted)

mod reader {
    use std::fmt::Debug;
    use std::str::FromStr;
    use std::collections::VecDeque;
    use std::io::{self, Read};

    fn _read_line() -> String {
        let mut buf = String::new();
        io::stdin().read_to_string(&mut buf);
        buf
    }

    fn _read_vec_deque_string() -> VecDeque<String> {
        _read_line().split_whitespace().map(|s| s.to_string()).collect()
    }

    pub struct Reader {
        buf: VecDeque<String>
    }

    impl Reader {
        pub fn new() -> Reader {
            Reader {buf: VecDeque::new()}
        }

        fn update_buf(&mut self) {
            if self.buf.is_empty() {
                self.buf = _read_vec_deque_string();
            }
        }

        pub fn next<T>(&mut self) -> T where T: FromStr, T::Err: Debug {
            self.update_buf();
            self.buf.pop_front().unwrap().parse::<T>().unwrap()
        }

        pub fn nextN<T>(&mut self, n: usize) -> Vec<T> where T: FromStr, T::Err: Debug {
            let mut vec: Vec<T> = Vec::with_capacity(n);
            for i in 0..n {
                vec.push(self.next());
            }
            vec
        }
    }
}

fn main() {
    let mut reader = reader::Reader::new();

    let a = vec![1, 3, 5, 7, 8, 10, 12];
    let b = vec![4, 6, 9, 11];
    let c = vec![2];

    let d = vec![a, b, c];

    let x: i32 = reader.next();
    let y: i32 = reader.next();

    let mut b = false;
    for i in 0..3 {
        b |= d[i].contains(&x) && d[i].contains(&y)
    }

    println!("{}", if b {"Yes"} else {"No"});
}