Problem:
Score : 400 points

Problem Statement

Given are positive integers A and B.

Let us choose some number of positive common divisors of A and B.

Here, any two of the chosen divisors must be coprime.

At most, how many divisors can we choose?

Definition of common divisor

An integer d is said to be a common divisor of integers x and y when d divides both x and y.

Definition of being coprime

Integers x and y are said to be coprime when x and y have no positive common divisors other than 1.

Definition of dividing

An integer x is said to divide another integer y when there exists an integer \alpha such that y = \alpha x.

Constraints

All values in input are integers.

1 \leq A, B \leq 10^{12}

Input

Input is given from Standard Input in the following format:

A B

Output

Print the maximum number of divisors that can be chosen to satisfy the condition.

Sample Input 1

12 18

Sample Output 1

3

12 and 18 have the following positive common divisors: 1, 2, 3, and 6.

1 and 2 are coprime, 2 and 3 are coprime, and 3 and 1 are coprime, so we can choose 1, 2, and 3, which achieve the maximum result.

Sample Input 2

420 660

Sample Output 2

4

Sample Input 3

1 2019

Sample Output 3

1

1 and 2019 have no positive common divisors other than 1.

Solution in Rust (1.15.1) (judge verdict: Wrong Answer)

use std::cmp::min;
use std::io::prelude::*;
use std::io::stdin;
use std::str::FromStr;

fn main() {
    let a: u64 = read();
    let b: u64 = read();

    let mut common_divisor = vec![];
    if a > b && a % b == 0 {
        common_divisor.push(b);
    }
    if b > a && b % a == 0 {
        common_divisor.push(a);
    }
    for i in 1..min(a, b).isqrt() + 1 {
        if a % i == 0 && b % i == 0 {
            common_divisor.push(i);
        }
    }
    if a == b {
        common_divisor.push(a);
    }

    // 1は常に入る
    let mut ans = 1;
    for x in common_divisor {
        if is_prime(x) {
            ans += 1;
        }
    }

    println!("{}", ans);
}

fn is_prime(x: u64) -> bool {
    if x == 1 {
        return false;
    }
    for i in 2..x.isqrt() + 1 {
        if x % i == 0 {
            return false;
        }
    }
    true
}

trait IntegerSqrt {
    fn isqrt(&self) -> Self;
}

impl IntegerSqrt for u64 {
    fn isqrt(&self) -> Self {
        if *self < 2 {
            *self
        } else {
            let s = (*self >> 2).isqrt() << 1;
            let l = s + 1;
            if l * l > *self {
                s
            } else {
                l
            }
        }
    }
}

#[allow(dead_code)]
fn read<T: FromStr>() -> T {
    let stdin = stdin();
    let token: String = stdin
        .lock()
        .bytes()
        .map(|b| b.unwrap() as char)
        .skip_while(|c| c.is_whitespace())
        .take_while(|c| !c.is_whitespace())
        .collect();
    token.parse().ok().unwrap()
}