Problem:
Score : 500 points

Problem Statement

We have a grid of squares with N rows and M columns. Let (i, j) denote the square at the i-th row from the top and j-th column from the left. We will choose K of the squares and put a piece on each of them.

If we place the K pieces on squares (x_1, y_1), (x_2, y_2), ..., and (x_K, y_K), the cost of this arrangement is computed as:

\sum_{i=1}^{K-1} \sum_{j=i+1}^K (|x_i - x_j| + |y_i - y_j|)

Find the sum of the costs of all possible arrangements of the pieces. Since this value can be tremendous, print it modulo 10^9+7.

We consider two arrangements of the pieces different if and only if there is a square that contains a piece in one of the arrangements but not in the other.

Constraints

2 \leq N \times M \leq 2 \times 10^5

2 \leq K \leq N \times M

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M K

Output

Print the sum of the costs of all possible arrangements of the pieces, modulo 10^9+7.

Sample Input 1

2 2 2

Sample Output 1

8

There are six possible arrangements of the pieces, as follows:

((1,1),(1,2)), with the cost |1-1|+|1-2| = 1

((1,1),(2,1)), with the cost |1-2|+|1-1| = 1

((1,1),(2,2)), with the cost |1-2|+|1-2| = 2

((1,2),(2,1)), with the cost |1-2|+|2-1| = 2

((1,2),(2,2)), with the cost |1-2|+|2-2| = 1

((2,1),(2,2)), with the cost |2-2|+|1-2| = 1

The sum of these costs is 8.

Sample Input 2

4 5 4

Sample Output 2

87210

Sample Input 3

100 100 5000

Sample Output 3

817260251

Be sure to print the sum modulo 10^9+7.

Solution in Rust (1.42.0) (judge verdict: Wrong Answer)

use proconio::{fastout, input};

#[fastout]
fn main() {
    input! {
        n: usize,
        m: usize,
        k: usize,
    }

    const MOD : usize = 1000000007;

    let mut ans : usize = 0;

    for i in 1..n{
        ans += ((i * (n-i) % MOD)  * (m * m % MOD)) % MOD;
    }

    for i in 1..m{
        ans += ((i * (m-i) % MOD)  * (n * n % MOD)) % MOD;
    }

    let c = Combination::new(n*m, MOD);
    let p = c.comb(n*m-2, k-2);

    ans = (ans * p) % MOD;

    println!("{}",ans);
}

pub struct Combination{
    fac : Vec<usize>,
    finv : Vec<usize>,
    m : usize,
}

impl Combination{
    pub fn new(n : usize, m : usize) -> Self{
        let mut inv = vec![1;n+1];
        let mut fac = vec![1;n+1];
        let mut finv = vec![1;n+1];

        for i in 2..(n+1){
            fac[i] = fac[i-1] * i % m;
            inv[i] = m - inv[m%i] * (m/i) % m;
            finv[i] = finv[i-1]*inv[i]%m;
        }

        Combination{
            fac,
            finv,
            m,
        }
    }

    pub fn comb(&self, n : usize, k: usize) -> usize{
        if n < k{
            return 0;
        }

        self.fac[n] * (self.finv[k] * self.finv[n-k] % self.m) % self.m
    }
}