Problem:
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Dice II

Construct a dice from a given sequence of integers in the same way as Dice I.

You are given integers on the top face and the front face after the dice was rolled in the same way as Dice I. Write a program to print an integer on the right side face.

Input

In the first line, six integers assigned to faces are given in ascending order of their corresponding labels.
In the second line, the number of questions $q$ is given.

In the following $q$ lines, $q$ questions are given. Each question consists of two integers on the top face and the front face respectively.

Output

For each question, print the integer on the right side face.

Constraints

$0 \leq $ the integer assigned to a face $ \leq 100$

The integers are all different

$1 \leq q \leq 24$

Sample Input

1 2 3 4 5 6
3
6 5
1 3
3 2

Sample Output

3
5
6

Solution in Ruby (judge verdict: Accepted)

class Dice < Array
	def roll!(drct)
		drct.split("").each{|s|
		case s
		when "E" then
			self.replace([at(3),at(1),at(0),at(5),at(4),at(2)])
		when "N" then
			self.replace([at(1),at(5),at(2),at(3),at(0),at(4)])
		when "S" then
			self.replace([at(4),at(0),at(2),at(3),at(5),at(1)])
		when "W" then
			self.replace([at(2),at(1),at(5),at(0),at(4),at(3)])
		when "R" then
			self.replace([at(0),at(3),at(1),at(4),at(2),at(5)])
		end
		}
	end
	def is_top
		at(0)
	end
	def getr(face)
		while at(0) != face[0] do
			roll!(["E","N","S","W"].sample)
		end
		while at(1) != face[1] do
			roll!("R")
		end
		at(2)
	end
end

a = Dice.new(gets.split.map(&:to_i))
for i in 1..gets.chomp.to_i do
	puts a.getr(gets.split.map(&:to_i))
end