Problem:
Score : 600 points

Problem Statement

Given are two sequences A and B, both of length N.
A and B are each sorted in the ascending order.
Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.

Constraints

1\leq N \leq 2 \times 10^5

1\leq A_i,B_i \leq N

A and B are each sorted in the ascending order.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N

Output

If there exist no reorderings that satisfy the condition, print No.

If there exists a reordering that satisfies the condition, print Yes on the first line.
After that, print a reordering of B on the second line, separating terms with a whitespace.

If there are multiple reorderings that satisfy the condition, you can print any of them.

Sample Input 1

6
1 1 1 2 2 3
1 1 1 2 2 3

Sample Output 1

Yes
2 2 3 1 1 1

Sample Input 2

3
1 1 2
1 1 3

Sample Output 2

No

Sample Input 3

4
1 1 2 3
1 2 3 3

Sample Output 3

Yes
3 3 1 2

Solution in Ruby (2.7.1) (judge verdict: Wrong Answer)

N = gets.to_i
A = gets.split.map(&:to_i)
B = gets.split.map(&:to_i)

C = Array.new(N + 1, 0)
counterA = A.tally
counterA.default = 0
cnt = 0
counterA.each do |num, c|
  cnt += c
  C[num] += cnt
end

D = Array.new(N + 1, 0)
cnt = 0
max_d = 0
B.tally.each do |num, c|
  if N < counterA[num] + c
    puts "No"
    exit
  end

  cnt += c
  D[num] += cnt
  diff = C[num] - D[num - 1]
  max_d = diff if max_d < diff
end

puts 'Yes'
puts B.rotate(-max_d).join(' ')