Problem:
Score : 300 points

Problem Statement

You are given an integer N.
Find the number of the positive divisors of N!, modulo 10^9+7.

Constraints

1≤N≤10^3

Input

The input is given from Standard Input in the following format:

N

Output

Print the number of the positive divisors of N!, modulo 10^9+7.

Sample Input 1

3

Sample Output 1

4

There are four divisors of 3! =6: 1, 2, 3 and 6. Thus, the output should be 4.

Sample Input 2

6

Sample Output 2

30

Sample Input 3

1000

Sample Output 3

972926972

Solution in Ruby (2.3.3) (judge verdict: Accepted)

N = gets.to_i

def factional(number)
    (1..number).inject(1,:*)
end

require 'prime'

answer = 1

for i in 0..Prime.prime_division(factional(N)).size-1

    answer = (answer * (Prime.prime_division(factional(N))[i][1]+1)) % (10 ** 9 + 7)

end

puts answer