Problem:
Score : 400 points

Problem Statement

An altar enshrines N stones arranged in a row from left to right. The color of the i-th stone from the left (1 \leq i \leq N) is given to you as a character c_i; R stands for red and W stands for white.

You can do the following two kinds of operations any number of times in any order:

Choose two stones (not necessarily adjacent) and swap them.

Choose one stone and change its color (from red to white and vice versa).

According to a fortune-teller, a white stone placed to the immediate left of a red stone will bring a disaster. At least how many operations are needed to reach a situation without such a white stone?

Constraints

2 \leq N \leq 200000

c_i is R or W.

Input

Input is given from Standard Input in the following format:

N
c_{1}c_{2}...c_{N}

Output

Print an integer representing the minimum number of operations needed.

Sample Input 1

4
WWRR

Sample Output 1

2

For example, the two operations below will achieve the objective.

Swap the 1-st and 3-rd stones from the left, resulting in RWWR.

Change the color of the 4-th stone from the left, resulting in RWWW.

Sample Input 2

2
RR

Sample Output 2

0

It can be the case that no operation is needed.

Sample Input 3

8
WRWWRWRR

Sample Output 3

3

Solution in Ruby (2.7.1) (judge verdict: Accepted)

N = gets.chomp.to_i

word = gets.chomp

count = 0

def get_leftmost_w_and_rightmost_r(word)
  [word.index('W'), word.rindex('R')]
end

leftmost_w, rightmost_r = get_leftmost_w_and_rightmost_r(word)

while !leftmost_w.nil? && !rightmost_r.nil? && leftmost_w < rightmost_r
  word[leftmost_w] = 'R'
  word[rightmost_r] = 'W'
  count += 1
  leftmost_w, rightmost_r = get_leftmost_w_and_rightmost_r(word)
end

puts count