Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in Ruby (2.7.1) (judge verdict: Runtime Error)

#include <bits/stdc++.h>

using namespace std;
using ll = long long;

int main() {
    int n,a,b,c;
    cin>>n>>a>>b>>c;
    vector<int> d(n);
    for(int i = 0;i < n;++i) {
        string s;

        cin>>s;
        if(s=="AB")--a,--b,d[i]=0;
        if(s=="AC")--a,--c,d[i]=1;
        if(s=="BC")--c,--b,d[i]=2;
    }
    vector<char> ans(n);
    for(int i = 0;i < n;++i) {
        if(d[i]==0) {
            if(a+1<=b)a+=2,ans[i]='A';
            else b+=2,ans[i]='B';
        }
        if(d[i]==1) {
            if(a+1<=c)a+=2,ans[i]='A';
            else c+=2,ans[i]='C';
        }
        if(d[i]==2) {
            if(b+1<=c)b+=2,ans[i]='B';
            else c+=2,ans[i]='C';
        }
    }
    if(a>=0&&b>=0&&c>=0) {
        cout<<"Yes"<<"\n";
        for(int i = 0;i < n;++i) {
            cout<<ans[i]<<"\n";
        }
    }
    else {
        cout<<"No"<<endl;
        return 1;
    }
    return 0;
}