Problem:
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Dice II

Construct a dice from a given sequence of integers in the same way as Dice I.

You are given integers on the top face and the front face after the dice was rolled in the same way as Dice I. Write a program to print an integer on the right side face.

Input

In the first line, six integers assigned to faces are given in ascending order of their corresponding labels.
In the second line, the number of questions $q$ is given.

In the following $q$ lines, $q$ questions are given. Each question consists of two integers on the top face and the front face respectively.

Output

For each question, print the integer on the right side face.

Constraints

$0 \leq $ the integer assigned to a face $ \leq 100$

The integers are all different

$1 \leq q \leq 24$

Sample Input

1 2 3 4 5 6
3
6 5
1 3
3 2

Sample Output

3
5
6

Solution in Ruby (judge verdict: Accepted)

# ITP1_11_B: Dice2

class Dice
  TOP    = 0
  FRONT  = 1
  RIGHT  = 2
  LEFT   = 3
  BACK   = 4
  BOTTOM = 5

  def initialize(labels)
    @labels = labels
  end

  def pip_of(side)
    @labels[side]
  end
 
  def rotate(p1, p2, p3, p4)
    l = @labels
    l[p1], l[p2], l[p3], l[p4] = l[p4], l[p1], l[p2], l[p3]
  end
 
  def roll_to(direction)
    rotate *case direction
    when 'N'
      [TOP, FRONT, BOTTOM, BACK]
    when 'E'
      [TOP, LEFT, BOTTOM, RIGHT]
    when 'S'
      [TOP, BACK, BOTTOM, FRONT]
    when 'W'
      [TOP, RIGHT, BOTTOM, LEFT]
    end
  end
end
 
labels     = gets.split.map &:to_i
n_changes  = gets.to_i
directions = %w(N E S W)
dice       = Dice.new labels

n_changes.times do
  top, front = gets.split.map &:to_i
  while true
    dice.roll_to directions.sample
    if dice.pip_of(Dice::TOP) == top && dice.pip_of(Dice::FRONT) == front
      puts dice.pip_of(Dice::RIGHT)
      break
    end
  end
end