Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Ruby (2.3.3) (judge verdict: Runtime Error)

top = gets
middle = gets
bottom = gets

bingo = (0..2).reduce([]){|arr, i| arr.append(top.split(" ")[i])
}
bingo = (0..2).reduce(bingo){|arr, i| arr.append(middle.split(" ")[i])
}
bingo = (0..2).reduce(bingo){|arr, i| arr.append(bottom.split(" ")[i])
}

bingo = [1,2,3,4,5,6,7,8]

N = gets
for i in (1..N.to_i)
  b = gets
  index = bingo.index(b.to_i)
  if(index)then
    bingo[index] = false
  end
end

ret = false
ret = (0..2).reduce(ret){|sum,i|
  break sum if sum
  sum||(!bingo[i*3]&&!bingo[i*3+1]&&!bingo[i*3+2])
}
if !ret then
ret = (0..2).reduce(ret){|sum,i|
  break sum if sum
  sum||(!bingo[i]&&!bingo[i+3]&&!bingo[i+6])
}
end

if !ret then
  ret = (!bingo[0]&&!bingo[4]&&!bingo[8])||(!bingo[2]&&!bingo[4]&&!bingo[6])
end

puts ret ? "Yes" : "No"