Problem:
Disjoint Set

Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.

same(x, y): determine whether x and y are in the same set.

Input

n q
com1 x1 y1
com2 x2 y2
...
comq xq yq

In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Constraints

1 ≤ n ≤ 10000

1 ≤ q ≤ 100000

x ≠ y

Sample Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0

Sample Output

0
0
1
1
1
0
1
1

Solution in Ruby (judge verdict: Accepted)

def get_i(i)
  if $s[i] != i
    nums = [$s[i]]
    $s[i] = $s[$s[i]]
    while $s[i] != $s[$s[i]]
      nums << $s[i]
      $s[i] = $s[$s[i]]
    end
    nums.each {|j| $s[j] = $s[i]}
    $s[i]
  else
    i
  end
end

n, q = gets.split.map(&:to_i)
$s = (0...n).to_a

q.times do
  com, x, y = gets.split.map(&:to_i)
  xi = get_i(x)
  yi = get_i(y)
  case com
  when 0
    $s[xi] = yi if xi != yi
  when 1
    puts xi == yi ? '1' : '0'
  end
end