Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in Ruby (judge verdict: Accepted)

count = Array.new(26,0)
alp = "abcdefghijklmnopqrstuvwxyz"

while tmp = gets
  str = tmp.chomp.downcase
  for str_i in 0..(str.length-1)
    for a_i in 0..25 do #26
      if str[str_i] == alp[a_i]
      count[a_i] = count[a_i] + 1
      end
    end
  end
end

26.times do |t_i|
  puts alp[t_i].to_s + " : " + count[t_i].to_s
end