Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in Ruby (2.3.3) (judge verdict: Wrong Answer)

# def function(s, q, querys)
# 	string = s
# 	# 最後に反転させるか
# 	is_reverse = false
# 	querys.each do |query|
# 		if query[0...1] == "1"
# 			is_reverse = !is_reverse
# 		elsif query[0...1] == "2"
# 			array = query.split
# 			fi_1 = array[1] == "1"
# 			if (fi_1 && !is_reverse) || (!fi_1 && is_reverse)
# 				string = array[2] << string
# 			elsif (!fi_1 && !is_reverse) || (fi_1 && is_reverse)
# 				string << array[2]
# 			end
# 		end
# 	end
# 	is_reverse ? string.reverse : string
# end
def function(s, q, querys)
	string = [s]
	# 最後に反転させるか
	is_reverse = false
	querys.each do |query|
		if query[0...1] == "1"
			is_reverse = !is_reverse
		elsif query[0...1] == "2"
			array = query.split
			fi_1 = array[1] == "1"
			if (fi_1 && !is_reverse) || (!fi_1 && is_reverse)
				string.unshift(array[2])
			elsif (!fi_1 && !is_reverse) || (fi_1 && is_reverse)
				string.push(array[2])
			end
		end
	end
	is_reverse ? string.reverse!.join : string.join
end

s = gets.chomp
q = gets.chomp.to_i
query = []
(0...q).each do |_|
	query.push(gets.chomp)
end
puts function(s, q, query)