Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Ruby (2.3.3) (judge verdict: Accepted)

def divisor(num)
  result = []
  i = 1
  while i <= num do
    remainder = num % i
    if remainder == 0
      result << i
    end 
    i += 1
  end
  return result
end

n = gets.to_i

ans = 0
(1..n).each do |k|
    next if k.even?
    ans += 1 if 8 == divisor(k).length
end

puts ans