Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in Ruby (2.7.1) (judge verdict: Wrong Answer)

N, a, b, c = gets.chomp.split.map(&:to_i)
N.freeze
s = N.times.map{gets.chomp.to_s} 
ary = Array.new(N, "foo") # 引数あり

#ゼロが２つ以上あれば強制終了
if (a == 0 && b == 0) || (a == 0 && c == 0) || (b == 0 && c == 0) then
  puts "No"
  exit
end

#ゲーム開始
num = 0
while num < N do
  if s[num] == "AB" then
    if a == 0 && b == 0 then
      puts "No"
      exit
    elsif a == 1 && b == 1 then
      if s[num+1] == "AC" then
        a =  a + 1
        b =  b - 1
        ary[num] = "A"
      else
        b = b + 1
        a = a - 1
        ary[num] = "B"
      end
    elsif a > b then
      b =  b + 1
      a =  a - 1
      ary[num] = "B"
    else
      a =  a + 1
      b =  b - 1
      ary[num] = "A"
    end
  elsif s[num] == "AC" then
      if a == 0 && c == 0 then
      puts "No"
      exit
    elsif a == 1 && c == 1 then
      if s[num] == "AB" then
        a =  a + 1
        c =  c - 1
        ary[num] = "A"
      else
        c = c + 1
        a = a - 1
        ary[num] = "C"
      end
    elsif a > c then
      c = c + 1
      a = a - 1
      ary[num] = "C"
    else
      a =  a + 1
      c =  c - 1
      ary[num] = "A"
    end  
  elsif s[num] == "BC" then
    if b == 0 && c == 0 then
      puts "No"
      exit
    elsif b == 1 && c == 1 then
      if s[num] == "AB"
        b = b + 1
        c = c - 1
        ary[num] = "B"
      else
        c = c + 1
        b = b - 1
        ary[num] = "C"
      end
    elsif b > c then
      c = c + 1
      b = b - 1
      ary[num] = "C"
    else
      b = b + 1
      c = c - 1
      ary[num] = "B"
    end
  else
    ##空処理、ありえないはず
  end
  #次のゲームへ・・・
  num = num + 1
end
puts "Yes"
num1 = 0
while num1 < N do
  puts ary[num1]
  num1 = num1 + 1
end