Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in Ruby (judge verdict: Accepted)

n,m,l = gets.split(" ").map{|x| x.to_i}
l_mat =Array.new()
r_mat=Array.new()
n.times do |i|
    l_mat[i]=gets.split(" ").map{|x| x.to_i}
end
m.times do |i|
    r_mat[i]=gets.split(" ").map{|x| x.to_i}
end
ans_mat=Array.new()
n.times do |i|
    ans_mat[i]=Array.new(l)
    l.times do |j|
        ans_mat[i][j]=0
        m.times do |k|
            ans_mat[i][j]+=l_mat[i][k]*r_mat[k][j]
        end
    end
end
n.times do|i|
    l.times do |j|
        print(ans_mat[i][j])
        if(j!=l-1)
            print(" ")
        end
    end
    puts()
end