Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in Ruby (judge verdict: Accepted)

def array_integer(a)
	0.upto(a.count) {|x|
		a[x] = a[x].to_i
	}
	return a
end

n,m,l = array_integer(STDIN.gets.split(" "))

a = Array.new(n).map{Array.new(m, 0)}
b = Array.new(m).map{Array.new(l, 0)}
c = Array.new(n).map{Array.new(l, 0)}

0.upto(n-1) {|i|
	a[i] = array_integer(STDIN.gets.split(" "))
}
0.upto(m-1) {|i|
	b[i] = array_integer(STDIN.gets.split(" "))
}

0.upto(n-1) {|i|
	0.upto(l-1) {|j|
		sum = 0
		0.upto(m-1) {|k|
			sum += a[i][k] * b[k][j]
		}
		c[i][j] = sum
	}
}

0.upto(n-1) {|i|
	0.upto(l-1) {|j|
		print c[i][j]
		print " " if j != l-1
	}
	print "\n"
}