Problem:
Score : 300 points

Problem Statement

Given are an integer X and an integer sequence of length N: p_1, \ldots, p_N.

Among the integers not contained in the sequence p_1, \ldots, p_N (not necessarily positive), find the integer nearest to X, that is, find the integer whose absolute difference with X is the minimum. If there are multiple such integers, report the smallest such integer.

Constraints

1 \leq X \leq 100

0 \leq N \leq 100

1 \leq p_i \leq 100

p_1, \ldots, p_N are all distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X N
p_1 ... p_N

Output

Print the answer.

Sample Input 1

6 5
4 7 10 6 5

Sample Output 1

8

Among the integers not contained in the sequence 4, 7, 10, 6, 5, the one nearest to 6 is 8.

Sample Input 2

10 5
4 7 10 6 5

Sample Output 2

9

Among the integers not contained in the sequence 4, 7, 10, 6, 5, the ones nearest to 10 are 9 and 11. We should print the smaller one, 9.

Sample Input 3

100 0

Sample Output 3

100

When N = 0, the second line in the input will be empty. Also, as seen here, X itself can be the answer.

Solution in Ruby (2.7.1) (judge verdict: Runtime Error)

x,_n = gets.chomp.split.map(&:to_i)
arr = gets.chomp.split.map(&:to_i)
#p "x:#{x}, n:#{n}, arr:#{arr}"

if arr == [] #空
  puts x
else
  unless arr.include?(x) #含まれない
    puts x
  else
    minarr = (0..(x-1)).to_a
    maxarr = ((x+1)..100).to_a
    min = minarr-arr
    max = maxarr-arr
    # puts "#{min}, #{max}"
    if (max[0]-x).abs < (x-min[-1]).abs
        puts max[0]
    else
        puts min[-1]
    end
  end
end