Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in Ruby (2.3.3) (judge verdict: Accepted)

n = gets.chomp.to_i
ama = n % 2
aa = gets.chomp.split.map(&:to_i)
stt = n / 2
hd = Array.new(stt)
tl = Array.new(stt)

if ama == 1
    ct = aa.shift
else
    ct = nil
end

if aa.size == 0
    puts ct
    exit
end


j = 0
k = 0
n.times do |i|
    if i % 2 == 0
        tl[j] = aa[i]
        j += 1
    else
        pos = stt - k - 1
      hd[pos] = aa[i]
      k += 1
    end
end


# print hd.join(' ')
print hd.join(' ')
if ct
   print ' '
   print ct
   print ' '
else
   print ' '
end

puts tl.join(' ')