Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in Ruby (judge verdict: Accepted)

count_ary = []
for i in "a".."z" do 
    count_ary.push([i, 0])
end

while (line_input = gets) do

    line = line_input.downcase

    line.chars{|ch|
        for i in 0..25 do
            if ch == count_ary[i][0] then
                count_ary[i][1] += 1
            end
        end
    }
end

26.times{|i|
    puts count_ary[i].join(" : ")
}