Problem:
Score : 200 points

Problem Statement

Rng is preparing a problem set for a qualification round of CODEFESTIVAL.

He has N candidates of problems. The difficulty of the i-th candidate is D_i.

There must be M problems in the problem set, and the difficulty of the i-th problem must be T_i. Here, one candidate of a problem cannot be used as multiple problems.

Determine whether Rng can complete the problem set without creating new candidates of problems.

Constraints

1 \leq N \leq 200,000

1 \leq D_i \leq 10^9

1 \leq M \leq 200,000

1 \leq T_i \leq 10^9

All numbers in the input are integers.

Partial Score

100 points will be awarded for passing the test set satisfying N \leq 100 and M \leq 100.

Input

Input is given from Standard Input in the following format:

N
D_1 D_2 ... D_N
M
T_1 T_2 ... T_M

Output

Print YES if Rng can complete the problem set without creating new candidates of problems; print NO if he cannot.

Sample Input 1

5
3 1 4 1 5
3
5 4 3

Sample Output 1

YES

Sample Input 2

7
100 200 500 700 1200 1600 2000
6
100 200 500 700 1600 1600

Sample Output 2

NO

Not enough 1600s.

Sample Input 3

1
800
5
100 100 100 100 100

Sample Output 3

NO

Sample Input 4

15
1 2 2 3 3 3 4 4 4 4 5 5 5 5 5
9
5 4 3 2 1 2 3 4 5

Sample Output 4

YES

Solution in Ruby (2.3.3) (judge verdict: Wrong Answer)

lines = $stdin.read
array = lines.split("\n")

N = array[0].to_i
d = array[1].split(" ").map(&:to_i)
M = array[2].to_i
t = array[3].split(" ").map(&:to_i)

# p N
# p d
# p M
# p t

if N < M
  puts "No"
else
  # M - N, and if there are something it's not sufficient
  # scores.delete_if {|key, val| val < 50 }
  having = Hash.new(0).tap do |h|
    d.each do |elem|
      #p elem
      h[elem] += 1 # unless elem.nil?
    end
  end

  ideal  = Hash.new(0).tap do |h|
    t.each do |elem|
      #p elem
      h[elem] += 1 # unless elem.nil?
    end
  end

  if ideal.any?{|k,v| not having.has_key?(k) or (having.has_key?(k) and having[k] < ideal[k]) }
    puts "No"
  else
    puts "Yes"
  end
end