Problem:
Score : 500 points

Problem Statement

There is an infinitely long street that runs west to east, which we consider as a number line.

There are N roadworks scheduled on this street.
The i-th roadwork blocks the point at coordinate X_i from time S_i - 0.5 to time T_i - 0.5.

Q people are standing at coordinate 0. The i-th person will start the coordinate 0 at time D_i, continue to walk with speed 1 in the positive direction and stop walking when reaching a blocked point.

Find the distance each of the Q people will walk.

Constraints

All values in input are integers.

1 \leq N, Q \leq 2 \times 10^5

0 \leq S_i < T_i \leq 10^9

1 \leq X_i \leq 10^9

0 \leq D_1 < D_2 < ... < D_Q \leq 10^9

If i \neq j and X_i = X_j, the intervals [S_i, T_i) and [S_j, T_j) do not overlap.

Input

Input is given from Standard Input in the following format:

N Q
S_1 T_1 X_1
:
S_N T_N X_N
D_1
:
D_Q

Output

Print Q lines. The i-th line should contain the distance the i-th person will walk or -1 if that person walks forever.

Sample Input 1

4 6
1 3 2
7 13 10
18 20 13
3 4 2
0
1
2
3
5
8

Sample Output 1

2
2
10
-1
13
-1

The first person starts coordinate 0 at time 0 and stops walking at coordinate 2 when reaching a point blocked by the first roadwork at time 2.

The second person starts coordinate 0 at time 1 and reaches coordinate 2 at time 3. The first roadwork has ended, but the fourth roadwork has begun, so this person also stops walking at coordinate 2.

The fourth and sixth persons encounter no roadworks while walking, so they walk forever. The output for these cases is -1.

Solution in Ruby (2.3.3) (judge verdict: Time Limit Exceeded)

class BIT
    def initialize(n)
        @n = n
        @dat = Array.new(@n, 0)
    end

    def sum(i)
        s = 0
        while i >= 0 do
            s += @dat[i]
            i = (i & (i+1)) - 1
        end
        s
    end

    def add(i, x)
        while i < @n do
            @dat[i] += x
            i |= i+1
        end
    end

    def lower_bound(x)
        ret = -1
        k = 1
        k <<= 1 while 2*k <= @n
        while k > 0
            if ret+k < @n && @dat[ret+k] < x
                x -= @dat[ret+k]
                ret += k
            end
            k >>= 1
        end
        ret + 1
    end
end

N, Q = gets.split.map(&:to_i)
events = {}
xs = {}
N.times do |i|
    s, t, x = gets.split.map(&:to_i)
    if events[s-x]
        events[s-x].push(x)
    else
        events[s-x] = [x]
    end
    if events[t-x]
        events[t-x].push(-x)
    else
        events[t-x] = [-x]
    end
    xs[x] = true
end
ts = events.keys.sort
ts.push(10**18)
xs = xs.keys.sort
compress = {}
sz = xs.size
sz.times do |i|
    compress[xs[i]] = i
end
xs[sz] = -1
bit = BIT.new(sz)

pt = 0
Q.times do
    d = gets.to_i
    while ts[pt] <= d
        events[ts[pt]].each do |x|
            bit.add(compress[x.abs], x > 0 ? 1 : -1)
        end
        pt += 1
    end
    puts xs[bit.lower_bound(1)]
end