Problem:
Score : 100 points

Problem Statement

In programming, hexadecimal notation is often used.

In hexadecimal notation, besides the ten digits 0, 1, ..., 9, the six letters A, B, C, D, E and F are used to represent the values 10, 11, 12, 13, 14 and 15, respectively.

In this problem, you are given two letters X and Y. Each X and Y is A, B, C, D, E or F.

When X and Y are seen as hexadecimal numbers, which is larger?

Constraints

Each X and Y is A, B, C, D, E or F.

Input

Input is given from Standard Input in the following format:

X Y

Output

If X is smaller, print <; if Y is smaller, print >; if they are equal, print =.

Sample Input 1

A B

Sample Output 1

<

10 < 11.

Sample Input 2

E C

Sample Output 2

>

14 > 12.

Sample Input 3

F F

Sample Output 3

=

15 = 15.

Solution in Ruby (2.3.3) (judge verdict: Accepted)

a,b = gets.chomp.split
arr = {"A"=>10,"B"=>11,"C"=>12,"D"=>13,"E"=>14,"F"=>15}

if arr.fetch(a) < arr.fetch(b)
  puts "<"
elsif arr.fetch(a) > arr.fetch(b)
  puts ">"
else
  puts "="
end