Problem:
Score : 100 points

Problem Statement

We have A balls with the string S written on each of them and B balls with the string T written on each of them.

From these balls, Takahashi chooses one with the string U written on it and throws it away.

Find the number of balls with the string S and balls with the string T that we have now.

Constraints

S, T, and U are strings consisting of lowercase English letters.

The lengths of S and T are each between 1 and 10 (inclusive).

S \not= T

S=U or T=U.

1 \leq A,B \leq 10

A and B are integers.

Input

Input is given from Standard Input in the following format:

S T
A B
U

Output

Print the answer, with space in between.

Sample Input 1

red blue
3 4
red

Sample Output 1

2 4

Takahashi chose a ball with red written on it and threw it away.
Now we have two balls with the string S and four balls with the string T.

Sample Input 2

red blue
5 5
blue

Sample Output 2

5 4

Takahashi chose a ball with blue written on it and threw it away.
Now we have five balls with the string S and four balls with the string T.

Solution in Ruby (2.3.3) (judge verdict: Accepted)

# Your code here!
strArr = gets.chop.split(" ")
cntArr = gets.chop.split(" ")
strHash = {}
for i in 0..1 do
    strHash.store(strArr[i], cntArr[i].to_i)
end
declementStr = gets.chop
strHash[declementStr] = strHash[declementStr] - 1
outputArr = []
strHash.map do |k, v|
    outputArr.push(v)
end
puts outputArr.join(" ")