Problem:
Score : 100 points

Problem Statement

Given are three integers A_1, A_2, and A_3.

If A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.

Constraints

1 \leq A_i \leq 13 \ \ (i=1,2,3)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

If A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.

Sample Input 1

5 7 9

Sample Output 1

win

5+7+9=21, so print win.

Sample Input 2

13 7 2

Sample Output 2

bust

13+7+2=22, so print bust.

Solution in Ruby (2.3.3) (judge verdict: Wrong Answer)

# a, b, c = gets.chomp.split(' ').map(&:to_i)
# 文字列をわたしてやらないといけない
A = gets.chomp.split(' ').map(&:to_i)

# if ((a + b + c) < 21) → 文字列を見ていない
if (A[0] + A[1] + A[2]) < 21 # 要素の１番目+２番目+３番目
  puts "win"
else
  puts "bust"
end