Problem:
Finding Missing Cards

Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).

The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.

Input

In the first line, the number of cards n (n ≤ 52) is given.

In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.

Output

Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line.
Arrange the missing cards in the following priorities:

Print cards of spades, hearts, clubs and diamonds in this order.

If the suits are equal, print cards with lower ranks first.

Sample Input

47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13

Sample Output

S 1
H 3
H 7
C 12
D 8

Note

      解説

Solution in Ruby (judge verdict: Accepted)

n = gets.to_i
cards = Array.new(n)
all_cards = Array.new(4).map{Array.new(13)}
4.times do |i|
	for j in 1..13 do
		if i == 0
			all_cards[i][j - 1] = ["S",j]
		elsif i == 1
			all_cards[i][j - 1] = ["H",j]
		elsif i == 2
			all_cards[i][j - 1] = ["C",j]
		else
			all_cards[i][j - 1] = ["D",j]
		end
	end
end
n.times do |i|
	cards[i] = gets
	cards[i] = cards[i].split(" ")
	cards[i][1] = cards[i][1].to_i
end
4.times do |i|
	n.times do |j|
		all_cards[i].delete(cards[j])
	end
end
4.times do |i|
	13.times do |j|
		if all_cards[i][j] != nil
			puts all_cards[i][j].join(" ")
		end
	end
end