Problem:
Official House

You manage 4 buildings, each of which has 3 floors, each of which consists of 10 rooms. Write a program which reads a sequence of tenant/leaver notices, and reports the number of tenants for each room.

For each notice, you are given four integers b, f, r and v which represent that v persons entered to room r of fth floor at building b. If v is negative, it means that −v persons left.

Assume that initially no person lives in the building.

Input

In the first line, the number of notices n is given. In the following n lines, a set of four integers b, f, r and v which represents ith notice is given in a line.

Output

For each building, print the information of 1st, 2nd and 3rd floor in this order. For each floor information, print the number of tenants of 1st, 2nd, .. and 10th room in this order. Print a single space character before the number of tenants. Print "####################" (20 '#') between buildings.

Constraints

No incorrect building, floor and room numbers are given.

0 ≤ the number of tenants during the management ≤ 9

Sample Input

3
1 1 3 8
3 2 2 7
4 3 8 1

Sample Output

0 0 8 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
####################
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
####################
0 0 0 0 0 0 0 0 0 0
0 7 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
####################
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 1 0 0

Solution in Ruby (judge verdict: WA: Presentation Error)

# data配列の初期化
data = Array.new(4).map{Array.new(3).map{Array.new(10,0)}}

# データ数を取り込み、nに代入
n = gets.to_i

# データを実際に取り込み、処理

n.times do
	b,f,r,v = gets.split.map(&:to_i)
	sample = data[b-1][f-1][r-1]
	sample += v
	data[b-1][f-1][r-1] = sample
end

=begin
# デバッグ用

p data
=end

# データ出力

4.times do |i1|
	3.times do |i2|
		puts data[i1][i2].join(" ")
	end

	unless i1 == 3
		puts '#'*20
	end
end