Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in Ruby (judge verdict: Accepted)

ans = [0] * 26
loop do
  str = gets
  unless str
    break
  end
  str.length.times do |i|
    tmp = str[i]
    if "a" <= tmp && tmp <= "z"
      ans[tmp.ord - "a".ord] += 1
    elsif "A" <= tmp && tmp <= "Z"
      ans[tmp.ord - "A".ord] += 1
    end
  end
end

26.times do |i|
  puts "#{("a".ord + i).chr} : #{ans[i]}"
end