Problem:
Score : 200 points

Problem Statement

There are N gems. The value of the i-th gem is V_i.

You will choose some of these gems, possibly all or none, and get them.

However, you need to pay a cost of C_i to get the i-th gem.

Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.

Find the maximum possible value of X-Y.

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq C_i, V_i \leq 50

Input

Input is given from Standard Input in the following format:

N
V_1 V_2 ... V_N
C_1 C_2 ... C_N

Output

Print the maximum possible value of X-Y.

Sample Input 1

3
10 2 5
6 3 4

Sample Output 1

5

If we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.
We have X-Y = 5 here, which is the maximum possible value.

Sample Input 2

4
13 21 6 19
11 30 6 15

Sample Output 2

6

Sample Input 3

1
1
50

Sample Output 3

0

Solution in Ruby (2.3.3) (judge verdict: Runtime Error)

params = STDIN.read
l1 = params.split(/\n/)[0].strip
l2 = params.split(/\n/)[1].strip
l3 = params.split(/\n/)[2].strip

n = l1.to_i
v_arr = l2.split(" ")
c_arr = l3.split(" ")

v_with_c = v_arr.zip c_arr
ans = 0
n.times do |j|
  v_with_c.combination(j+1).map do |jews|
    v_tot = jews.map{|jew| jew[0].to_i}.inject(:+)
    c_tot = jews.map{|jew| jew[1].to_i}.inject(:+)
    tryal = v_tot - c_tot
    ans = tryal if ans < tryal
  end
end


puts x_minus_y_arr.max