Problem:
Finding Missing Cards

Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).

The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.

Input

In the first line, the number of cards n (n ≤ 52) is given.

In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.

Output

Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line.
Arrange the missing cards in the following priorities:

Print cards of spades, hearts, clubs and diamonds in this order.

If the suits are equal, print cards with lower ranks first.

Sample Input

47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13

Sample Output

S 1
H 3
H 7
C 12
D 8

Note

      解説

Solution in Ruby (judge verdict: Accepted)

s = Array.new( 13, false )
h = Array.new( 13, false )
c = Array.new( 13, false )
d = Array.new( 13, false )

n = gets.to_i
for i in ( 0 ... n )
	pattern, num = gets.split( " " )
	case pattern
		when "S"
			s[ num.to_i-1 ] = true
		when "H" 
			h[ num.to_i-1 ] = true
		when "C"
			c[ num.to_i-1 ] = true
		when "D"
			d[ num.to_i-1 ] = true
		else
	end
end

for i in ( 0 ... 13 )
	if !s[i]
		print( "S #{i+1}\n" )		
	end
end

for i in ( 0 ... 13 )
	if !h[i]
		print( "H #{i+1}\n" )	
	end
end

for i in ( 0 ... 13 )
	if !c[i]
		print( "C #{i+1}\n" )	
	end
end

for i in ( 0 ... 13 )
	if !d[i]
		print( "D #{i+1}\n" )	
	end
end