Problem:
Score : 200 points

Problem Statement

An integer X is called a Harshad number if X is divisible by f(X), where f(X) is the sum of the digits in X when written in base 10.

Given an integer N, determine whether it is a Harshad number.

Constraints

1?N?10^8

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print Yes if N is a Harshad number; print No otherwise.

Sample Input 1

12

Sample Output 1

Yes

f(12)=1+2=3. Since 12 is divisible by 3, 12 is a Harshad number.

Sample Input 2

57

Sample Output 2

No

f(57)=5+7=12. Since 57 is not divisible by 12, 12 is not a Harshad number.

Sample Input 3

148

Sample Output 3

No

Solution in Ruby (2.3.3) (judge verdict: Accepted)

def geti; gets.to_i end
def getis; gets.split.map &:to_i end
def getin n;  n.times.map{geti}  end
def getisn n; n.times.map{getis} end
YES = "YES"; NO = "NO"; Yes = "Yes"; No = "No";

n = geti
puts n % n.to_s.chars.map(&:to_i).reduce(:+) == 0 ? Yes : No

__END__

n,a,b = getis
p [n*a,b].min

a,b,c = getis
p [a,b,c].any?(&:even?) ? 0 : [a*b,b*c,c*a].min

a,b=getis
puts a > 0 ? 'Positive' : b >= 0 ? 'Zero' : (b - a) % 2 == 1 ? 'Positive' : 'Negative'