Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in Ruby (judge verdict: Wrong Answer)

input_a = gets
input_b = gets

formula_a = input_a.split(' ').map(&:to_f)
formula_b = input_b.split(' ').map(&:to_f)

fa_x = ((formula_a[2] * formula_a[4]) - (formula_a[1] * formula_a[5])) / ((formula_a[0] * formula_a[4]) - (formula_a[1] * formula_a[3])) + 0.000
fa_y = ((formula_a[0] * formula_a[5]) - (formula_a[2] * formula_a[3])) / ((formula_a[0] * formula_a[4]) - (formula_a[1] * formula_a[3])) + 0.000
fb_x = ((formula_b[2] * formula_b[4]) - (formula_b[1] * formula_b[5])) / ((formula_b[0] * formula_b[4]) - (formula_b[1] * formula_b[3])) + 0.000
fb_y = ((formula_b[0] * formula_b[5]) - (formula_b[2] * formula_b[3])) / ((formula_b[0] * formula_b[4]) - (formula_b[1] * formula_b[3])) + 0.000

puts format('%.3f', fa_x) + " " + format('%.3f', fa_y)
puts format('%.3f', fb_x) + " " + format('%.3f', fb_y)