Problem:
Score : 400 points

Problem Statement

Find the largest integer that can be formed with exactly N matchsticks, under the following conditions:

Every digit in the integer must be one of the digits A_1, A_2, ..., A_M (1 \leq A_i \leq 9).

The number of matchsticks used to form digits 1, 2, 3, 4, 5, 6, 7, 8, 9 should be 2, 5, 5, 4, 5, 6, 3, 7, 6, respectively.

Constraints

All values in input are integers.

2 \leq N \leq 10^4

1 \leq M \leq 9

1 \leq A_i \leq 9

A_i are all different.

There exists an integer that can be formed by exactly N matchsticks under the conditions.

Input

Input is given from Standard Input in the following format:

N M
A_1 A_2 ... A_M

Output

Print the largest integer that can be formed with exactly N matchsticks under the conditions in the problem statement.

Sample Input 1

20 4
3 7 8 4

Sample Output 1

777773

The integer 777773 can be formed with 3 + 3 + 3 + 3 + 3 + 5 = 20 matchsticks, and this is the largest integer that can be formed by 20 matchsticks under the conditions.

Sample Input 2

101 9
9 8 7 6 5 4 3 2 1

Sample Output 2

71111111111111111111111111111111111111111111111111

The output may not fit into a 64-bit integer type.

Sample Input 3

15 3
5 4 6

Sample Output 3

654

Solution in Ruby (2.3.3) (judge verdict: Runtime Error)

N, M = gets.split.map(&:to_i)
COSTS = [0,2,5,5,4,5,6,3,7,6]
A = gets.split.map(&:to_i).sort_by {|a| COSTS[a]}

MIN = COSTS[A.first]
max_digit = N / MIN

num = 0
match = N
max_digit.times do |d|
  max_n = 0
  A.each do |a|
    remaining = match - COSTS[a]

    if remaining < 0
      next
    end

    if d == max_digit - 1
      if remaining == 0
        if max_n < a
          max_n = a
        end
      end
    else
      if (remaining / MIN) + (d + 1) == max_digit
        if max_n < a
          max_n = a
        end
      end
    end
  end
  if max_n == 0
    raise
  end

  num = num * 10 + max_n
  match -= COSTS[max_n]
end

p num