Problem:
Score : 500 points

Problem Statement

We have N locked treasure boxes, numbered 1 to N.

A shop sells M keys. The i-th key is sold for a_i yen (the currency of Japan), and it can unlock b_i of the boxes: Box c_{i1}, c_{i2}, ..., c_{i{b_i}}. Each key purchased can be used any number of times.

Find the minimum cost required to unlock all the treasure boxes. If it is impossible to unlock all of them, print -1.

Constraints

All values in input are integers.

1 \leq N \leq 12

1 \leq M \leq 10^3

1 \leq a_i \leq 10^5

1 \leq b_i \leq N

1 \leq c_{i1} < c_{i2} < ... < c_{i{b_i}} \leq N

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
c_{11} c_{12} ... c_{1{b_1}}
:
a_M b_M
c_{M1} c_{M2} ... c_{M{b_M}}

Output

Print the minimum cost required to unlock all the treasure boxes.
If it is impossible to unlock all of them, print -1.

Sample Input 1

2 3
10 1
1
15 1
2
30 2
1 2

Sample Output 1

25

We can unlock all the boxes by purchasing the first and second keys, at the cost of 25 yen, which is the minimum cost required.

Sample Input 2

12 1
100000 1
2

Sample Output 2

-1

We cannot unlock all the boxes.

Sample Input 3

4 6
67786 3
1 3 4
3497 1
2
44908 3
2 3 4
2156 3
2 3 4
26230 1
2
86918 1
3

Sample Output 3

69942

Solution in Ruby (2.3.3) (judge verdict: Time Limit Exceeded)

class Key
    attr_accessor :id, :price, :locks
    def initialize(id, price, locks)
        @id = id
        @price = price
        @locks = locks
    end
end

class Lock
    attr_accessor :id, :keys 
    def initialize(id)
        @id = id
        @keys = []
    end
end

N, M = gets.split.map(&:to_i)
locks = Array.new(N).map.with_index{|a, idx| Lock.new(idx)}
M.times do |m|
    buf1, buf2 = gets.split.map(&:to_i)
    buf3 = gets.split.map(&:to_i).map{|item| item - 1}
    key = Key.new(m, buf1, buf3)
    buf3.each{|cmi| locks[cmi].keys << key}
end

$best = 1000000000

def calc(sum, unopened_locks)
    if $best <= sum
        return sum
    elsif unopened_locks.empty?
        $best = sum
        return sum
    else
        next_lock = unopened_locks[0]
        return next_lock.keys.map{|key| calc(sum + key.price, unopened_locks.reject{|lock| key.locks.include?(lock.id)})}.min
    end
end

if locks.any?{|lock| lock.keys.empty?}
    p -1
    exit
end

p calc(0, locks.sort_by{|lock| lock.keys.size}) || -1