Problem:
Score : 600 points

Problem Statement

Silver Fox is fighting with N monsters.

The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the health of H_i.

Silver Fox can use bombs to attack the monsters.
Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A.
There is no way other than bombs to decrease the monster's health.

Silver Fox wins when all the monsters' healths become 0 or below.

Find the minimum number of bombs needed to win.

Constraints

1 \leq N \leq 2 \times 10^5

0 \leq D \leq 10^9

1 \leq A \leq 10^9

0 \leq X_i \leq 10^9

1 \leq H_i \leq 10^9

X_i are distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N D A
X_1 H_1
:
X_N H_N

Output

Print the minimum number of bombs needed to win.

Sample Input 1

3 3 2
1 2
5 4
9 2

Sample Output 1

2

First, let us use a bomb at the coordinate 4 to decrease the first and second monsters' health by 2.

Then, use a bomb at the coordinate 6 to decrease the second and third monsters' health by 2.

Now, all the monsters' healths are 0.
We cannot make all the monsters' health drop to 0 or below with just one bomb.

Sample Input 2

9 4 1
1 5
2 4
3 3
4 2
5 1
6 2
7 3
8 4
9 5

Sample Output 2

5

We should use five bombs at the coordinate 5.

Sample Input 3

3 0 1
300000000 1000000000
100000000 1000000000
200000000 1000000000

Sample Output 3

3000000000

Watch out for overflow.

Solution in Ruby (2.3.3) (judge verdict: Wrong Answer)

n, d, a = gets.chomp.split.map(&:to_i)
monsters = []
n.times do |i|
  monsters.push(gets.chomp.split.map(&:to_i))
end
 
#ソート（ボトルネック）
monsters.sort!.reverse!
 
ans = 0
 
#左端から攻撃していく
i = -1
while !monsters.empty? do
  i += 1
  x, h = monsters.pop
  #すでに死んでいればスキップ
  next if h <= 0
  atk = h / a
  if h % a == 0
    damage = h
    ans += atk
  else
    damage = (atk + 1) * a
    ans += atk + 1
  end
  
  #他のモンスターも範囲に入っていればダメージ
  reachable = x + d * 2
  tmp_queue = []
  while !monsters.empty? do
    break if monsters.last[0] > reachable
    #届かなければ終了
    mons = monsters.pop
    mons[1] -= damage
    #生きていればキューに戻す
    tmp_queue.push(mons) if mons[1] > 0
  end
  
  #キューを元に戻す
  tmp_queue.each do |q|
    monsters.push(q)
  end
  
end
 
puts ans