Problem:
Score : 100 points

Problem Statement

You are given a string S consisting of letters b, d, p and q.
Determine whether S is a mirror string.

Here, a mirror string is a string S such that the following sequence of operations on S results in the same string S:

Reverse the order of the characters in S.

Replace each occurrence of b by d, d by b, p by q, and q by p, simultaneously.

Constraints

1 \leq |S| \leq 10^5

S consists of letters b, d, p, and q.

Input

The input is given from Standard Input in the following format:

S

Output

If S is a mirror string, print Yes. Otherwise, print No.

Sample Input 1

pdbq

Sample Output 1

Yes

Sample Input 2

ppqb

Sample Output 2

No

Solution in Ruby (2.3.3) (judge verdict: Wrong Answer)

s = gets.chop
len = s.size
ok = true
(len/2).times{|i|
  ok &= 
  s[i] == 'p' && s[len - i - 1] == 'q' ||
  s[i] == 'q' && s[len - i - 1] == 'p' ||
  s[i] == 'b' && s[len - i - 1] == 'd' ||
  s[i] == 'd' && s[len - i - 1] == 'b'
}
puts ok ? "Yes" : "No"