Problem:
Score : 200 points

Problem Statement

Takahashi is standing on a two-dimensional plane, facing north. Find the minimum positive integer K such that Takahashi will be at the starting position again after he does the following action K times:

Go one meter in the direction he is facing. Then, turn X degrees counter-clockwise.

Constraints

1 \leq X \leq 179

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the number of times Takahashi will do the action before he is at the starting position again.

Sample Input 1

90

Sample Output 1

4

Takahashi's path is a square.

Sample Input 2

1

Sample Output 2

360

Solution in Ruby (2.7.1) (judge verdict: Accepted)

n = 1
k = -1
x = gets.chomp.to_i

loop do
  # x * k == 360 * n
  if (360 * n) % x == 0 then
    k = (360 * n) / x
    break
  end

  n += 1
end

puts k.to_s