Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in Ruby (judge verdict: Accepted)

def mul(a, b, n, m)
  c = []
  for i in 0..(n-1)
    ai = a[i]
    c.push(dot(ai, b, m))
  end
  return c
end

def dot(x, y, m)
  dot_xy_array = []
  dot_xy = 0
  for i in 0..(m-1)
    dot_xy_array.push(x[i] * y[i])
  end
  dot_xy = 0
  dot_xy_array.each do |i|
    dot_xy += i
  end
  return dot_xy
end

def mul_matrix(arrayA, arrayB, n, m, l)
  mul_matrix_array = []
  for i in 0..(l-1)
    mul_matrix_array.push(mul(arrayA, arrayB[i], n, m))
  end
  return mul_matrix_array
end

input_nml_array = gets.chomp.split.map(&:to_i)
n = input_nml_array[0]
m = input_nml_array[1]
l = input_nml_array[2]
input_a_arrays = []
n.times do
  input_a_array = gets.chomp.split.map(&:to_i)
  input_a_arrays.push(input_a_array)
end
input_b_arrays = []
m.times do
  input_b_array = gets.chomp.split.map(&:to_i)
  input_b_arrays.push(input_b_array)
end
input_b_column_vector_array = []
for i in 0..(l-1)
  tmp = []
    for j in 0..(m-1)
      tmp.push(input_b_arrays[j][i])
    end
    input_b_column_vector_array.push(tmp)
end

answers = mul_matrix(input_a_arrays, input_b_column_vector_array, n, m, l)
for i in 0..(n-2)
  for j in 0..(l-2)
    print answers[j][i]
    print " "
  end
  print answers[l-1][i]
  print "\n"
end
for i in 0..(l-2)
  print answers[i][n-1]
  print" "
end
  print answers[l-1][n-1]
  print "\n"