Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in Ruby (judge verdict: Accepted)

while (str = gets)
  a, b, c, d, e, f = str.split(" ").map(&:to_f)
  if a * b * d * e != 0
    puts [sprintf("%.3f", ((c - f * (b / e)) / (a - d * (b / e))).round(3)), sprintf("%.3f", ((c - f * (a / d)) / (b - e * (a / d))).round(3))].join(" ")
  else
    if a == 0
      puts [sprintf("%.3f", ((f - e * (c / b)) / d).round(3)), sprintf("%.3f", (c / b).round(3))].join(" ")
    elsif b == 0
      puts [sprintf("%.3f", (c / a).round(3)), sprintf("%.3f", ((f - d * (c / a)) / e).round(3))].join(" ")
    elsif d == 0
      puts [sprintf("%.3f", ((c - b * (f / e)) / a).round(3)), sprintf("%.3f", (f / e).round(3))].join(" ")
    else
      puts [sprintf("%.3f", (f / d).round(3)), sprintf("%.3f", ((c - a * (f / d)) / b).round(3))].join(" ")
    end
  end
end