Problem:
Score : 200 points

Problem Statement

An integer X is called a Harshad number if X is divisible by f(X), where f(X) is the sum of the digits in X when written in base 10.

Given an integer N, determine whether it is a Harshad number.

Constraints

1?N?10^8

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print Yes if N is a Harshad number; print No otherwise.

Sample Input 1

12

Sample Output 1

Yes

f(12)=1+2=3. Since 12 is divisible by 3, 12 is a Harshad number.

Sample Input 2

57

Sample Output 2

No

f(57)=5+7=12. Since 57 is not divisible by 12, 12 is not a Harshad number.

Sample Input 3

148

Sample Output 3

No

Solution in Ruby (2.3.3) (judge verdict: Accepted)

n = gets.to_i

def ketasum(n)
    ret = 0
    loop{
        if n==0 then
            break
        end
        ret+=n%10
        n/=10
    }
    return ret
end

def is_harshaddo(n)
    return n%ketasum(n)==0
end

puts is_harshaddo(n) ? 'Yes' : 'No'