Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in Ruby (2.3.3) (judge verdict: Accepted)

N = gets.chomp.to_i

if N.even?
  # p [N / 4, N * N * (N / 2) / (N * N + N * N / 2 + N * N / 2)]
  puts "#{N} #{N} #{N / 2}"
else
  (1..3500).each do |h|
    (1..3500).each do |n|
      if h.even? || n.even? then
        x = N * h * n
        y = (4 * h * n - N * n - N * h)
        if y > 0 && x % y == 0
          # p [N / 4, h * n * (x / y) / (h * n + n * x / y + h * x / y)]
          puts "#{h} #{n} #{x / y}"
          exit
        end
      end
    end
  end    
end