Problem:
Koch Curve

Write a program which reads an integer n and draws a Koch curve based on recursive calles of depth n.

The Koch curve is well known as a kind of fractals.

You can draw a Koch curve in the following algorithm:

Divide a given segment (p1, p2) into three equal segments.

Replace the middle segment by the two sides of an equilateral triangle (s, u, t) of the same length as the segment.

Repeat this procedure recursively for new segments (p1, s), (s, u), (u, t), (t, p2).

You should start (0, 0), (100, 0) as the first segment.

Input

An integer n is given.

Output

Print each point (x, y) of the Koch curve. Print a point in a line. You should start the point(0, 0), which is the endpoint of the first segment and end with the point (100, 0), the other endpoint so that you can draw the Koch curve as an unbroken line. Each solution should be given as a decimal with an arbitrary number of fractional digits, and with an absolute error of at most 10-4.

Constraints

0 ≤ n ≤ 6

Sample Input 1

1

Sample Output 1

0.00000000 0.00000000
33.33333333 0.00000000
50.00000000 28.86751346
66.66666667 0.00000000
100.00000000 0.00000000

Sample Input 2

2

Sample Output 2

0.00000000 0.00000000
11.11111111 0.00000000
16.66666667 9.62250449
22.22222222 0.00000000
33.33333333 0.00000000
38.88888889 9.62250449
33.33333333 19.24500897
44.44444444 19.24500897
50.00000000 28.86751346
55.55555556 19.24500897
66.66666667 19.24500897
61.11111111 9.62250449
66.66666667 0.00000000
77.77777778 0.00000000
83.33333333 9.62250449
88.88888889 0.00000000
100.00000000 0.00000000

Notes

Solution in Ruby (judge verdict: Accepted)

class KochCurve
  def solve
    n = gets.chomp.to_i
    ans = koch(Point.new(0.0,0.0), Point.new(100.0,0.0), n)
    ans.map! do |x|
      x.to_s
    end
    return ans
  end
  def koch(pl, pr, n)
    if n == 0
      [pl, pr]
    else
      p1 = Point.new((2 * pl.x + pr.x) / 3.0, (2 * pl.y + pr.y) / 3.0)
      p2 = Point.new((pl.x + 2 * pr.x) / 3.0, (pl.y + 2 * pr.y) / 3.0)
      p3 = Point.new((pl.x + pr.x) / 2.0 - Math.sqrt(3) * (pr.y - pl.y) / 6.0 ,(pl.y + pr.y) / 2.0 + Math.sqrt(3) * (pr.x - pl.x) / 6.0)

      a1 = koch(pl, p1, n - 1)
      a2 = koch(p1, p3, n - 1)
      a3 = koch(p3, p2, n - 1)
      a4 = koch(p2, pr, n - 1)
      a1.pop
      a2.pop
      a3.pop
      a1 + a2 + a3 + a4
    end
  end
end

class Point
  attr_accessor :x, :y
  def initialize(x=0, y=0)
    @x = x
    @y = y
  end
  def to_s
    return "#{@x} #{@y}"
  end
end
if $0 == __FILE__
  puts KochCurve.new.solve
end