Problem:
Score : 200 points

Problem Statement

Today is August 24, one of the five Product Days in a year.

A date m-d (m is the month, d is the date) is called a Product Day when d is a two-digit number, and all of the following conditions are satisfied (here d_{10} is the tens digit of the day and d_1 is the ones digit of the day):

d_1 \geq 2

d_{10} \geq 2

d_1 \times d_{10} = m

Takahashi wants more Product Days, and he made a new calendar called Takahashi Calendar where a year consists of M month from Month 1 to Month M, and each month consists of D days from Day 1 to Day D.

In Takahashi Calendar, how many Product Days does a year have?

Constraints

All values in input are integers.

1 \leq M \leq 100

1 \leq D \leq 99

Input

Input is given from Standard Input in the following format:

M D

Output

Print the number of Product Days in a year in Takahashi Calender.

Sample Input 1

15 40

Sample Output 1

10

There are 10 Product Days in a year, as follows (m-d denotes Month m, Day d):

4-22

6-23

6-32

8-24

9-33

10-25

12-26

12-34

14-27

15-35

Sample Input 2

12 31

Sample Output 2

5

Sample Input 3

1 1

Sample Output 3

0

Solution in Ruby (2.3.3) (judge verdict: Accepted)

m,d=gets.chomp.split(" ").map(&:to_i);

# d1 = d%10
# d2 = d/10

# puts m
# puts d
 # puts d2
 # puts d1
sum = 0

for j in 1..m do

	for i in 22..d  do
		d1 = i%10
		d2 = i/10
		#puts i

		if j == d1*d2 
			sum = sum + 1
			#puts "j#{j} i#{i} sum#{sum}"
			if d1 < 2 || d2 < 2
				sum = sum -1
			end
		end
	end
#puts j

end

puts sum