Problem:
Score : 400 points

Problem Statement

Given is a string S. Each character in S is either a digit (0, ..., 9) or ?.

Among the integers obtained by replacing each occurrence of ? with a digit, how many have a remainder of 5 when divided by 13? An integer may begin with 0.

Since the answer can be enormous, print the count modulo 10^9+7.

Constraints

S is a string consisting of digits (0, ..., 9) and ?.

1 \leq |S| \leq 10^5

Input

Input is given from Standard Input in the following format:

S

Output

Print the number of integers satisfying the condition, modulo 10^9+7.

Sample Input 1

??2??5

Sample Output 1

768

For example, 482305, 002865, and 972665 satisfy the condition.

Sample Input 2

?44

Sample Output 2

1

Only 044 satisfies the condition.

Sample Input 3

7?4

Sample Output 3

0

We may not be able to produce an integer satisfying the condition.

Sample Input 4

?6?42???8??2??06243????9??3???7258??5??7???????774????4?1??17???9?5?70???76???

Sample Output 4

153716888

Solution in Ruby (2.3.3) (judge verdict: Time Limit Exceeded)

MOD = 10**9 + 7

ss = gets.chomp.split('')

dp = Array.new(ss.size + 1) { Array.new(13, 0) }
dp[0][0] = 1

(0 ... ss.size).each{ |i|
	(0 ... dp[i].size).each { |j|
		if ss[i] == '?' then
			(0..9).each{ |k|
				dp[i + 1][(j * 10 + k) % 13] += dp[i][j]
			}
		else
			dp[i + 1][(j * 10 + ss[i].to_i) % 13] += dp[i][j]
		end
	}
}

puts dp[-1][5] % MOD