Problem:
MathJax.Hub.Config({ tex2jax: { inlineMath: [["$","$"], ["\\(","\\)"]], processEscapes: true }});

Dice II

Construct a dice from a given sequence of integers in the same way as Dice I.

You are given integers on the top face and the front face after the dice was rolled in the same way as Dice I. Write a program to print an integer on the right side face.

Input

In the first line, six integers assigned to faces are given in ascending order of their corresponding labels.
In the second line, the number of questions $q$ is given.

In the following $q$ lines, $q$ questions are given. Each question consists of two integers on the top face and the front face respectively.

Output

For each question, print the integer on the right side face.

Constraints

$0 \leq $ the integer assigned to a face $ \leq 100$

The integers are all different

$1 \leq q \leq 24$

Sample Input

1 2 3 4 5 6
3
6 5
1 3
3 2

Sample Output

3
5
6

Solution in Ruby (judge verdict: Accepted)

class Dice
  attr_accessor :a, :b, :c, :d, :e, :f

  def initialize(aaa, bbb, ccc, ddd, eee, fff)
    @a = aaa
    @b = bbb
    @c = ccc
    @d = ddd
    @e = eee
    @f = fff
  end

  def opposite(nnn)
    if nnn == a
      f
    elsif nnn == b
      e
    elsif nnn == c
      d
    elsif nnn == d
      c
    elsif nnn == e
      b
    elsif nnn == f
      a
    end
  end

  def spin(char)
    aa = @a
    bb = @b
    cc = @c
    dd = @d
    ee = @e
    ff = @f

    if char == 'E'
      @a = dd
      @c = aa
      @d = ff
      @f = cc
    elsif char == 'N'
      @a = bb
      @b = ff
      @e = aa
      @f = ee
    elsif char == 'S'
      @a = ee
      @b = aa
      @e = ff
      @f = bb
    elsif char == 'W'
      @a = cc
      @c = ff
      @d = aa
      @f = dd
    end
  end
end

a, b, c, d, e, f = gets.split.map(&:to_i)
dice = Dice.new(a, b, c, d, e, f)
q = gets.to_i
v = []

q.times do
  top, front = gets.split.map(&:to_i)
  found = false
  e_or_w = false

  until found
    if e_or_w
      dice.spin('E')
    else
      dice.spin('W')
    end
    e_or_w = !e_or_w

    3.times do
      dice.spin('S')
      if dice.a == top && dice.b == front
        found = true
        v << dice.c
        break
      elsif dice.a == front && dice.b == top
        found = true
        v << dice.opposite(dice.c)
        break
      end
    end
  end
end

v.each do |i|
  p i
end