Problem:
Structured Programming

In programming languages like C/C++, a goto statement provides an unconditional jump from the "goto" to a labeled statement. For example, a statement "goto CHECK_NUM;" is executed, control of the program jumps to CHECK_NUM. Using these constructs, you can implement, for example, loops.

Note that use of goto statement is highly discouraged, because it is difficult to trace the control flow of a program which includes goto.

Write a program which does precisely the same thing as the following program (this example is wrtten in C++). Let's try to write the program without goto statements.

void call(int n){
int i = 1;
CHECK_NUM:
int x = i;
if ( x % 3 == 0 ){
cout << " " << i;
goto END_CHECK_NUM;
}
INCLUDE3:
if ( x % 10 == 3 ){
cout << " " << i;
goto END_CHECK_NUM;
}
x /= 10;
if ( x ) goto INCLUDE3;
END_CHECK_NUM:
if ( ++i <= n ) goto CHECK_NUM;

cout << endl;
}

Input

An integer n is given in a line.

Output

Print the output result of the above program for given integer n.

Constraints

3 ≤ n ≤ 10000

Sample Input

30

Sample Output

3 6 9 12 13 15 18 21 23 24 27 30

Put a single space character before each element.

Solution in Ruby (judge verdict: Accepted)

n = gets.to_i
i = 1
result = []

def check_num(x)
  return x % 3 == 0
end

def include3(x)
  return x % 10 == 3
end

i..n.times do
  x = i
  if check_num(x)
    result << i
    i += 1
    next
  end
  if include3(x)
    result << i
    i += 1
    next
  end
  x /= 10
  if (x) && include3(x)
    result << i
    i += 1
    next
  end
  x /= 10
  if (x) && include3(x)
    result << i
    i += 1
    next
  end
  x /= 10
  if (x) && include3(x)
    result << i
    i += 1
    next
  end
  x /= 10
  if (x) && include3(x)
    result << i
    i += 1
    next
  end
  i += 1
end

puts ' ' + result.join(' ')