Problem:
Score : 300 points

Problem Statement

Snuke has an integer sequence A of length N.

He will freely choose an integer b.
Here, he will get sad if A_i and b+i are far from each other.
More specifically, the sadness of Snuke is calculated as follows:

abs(A_1 - (b+1)) + abs(A_2 - (b+2)) + ... + abs(A_N - (b+N))

Here, abs(x) is a function that returns the absolute value of x.

Find the minimum possible sadness of Snuke.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq A_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the minimum possible sadness of Snuke.

Sample Input 1

5
2 2 3 5 5

Sample Output 1

2

If we choose b=0, the sadness of Snuke would be abs(2-(0+1))+abs(2-(0+2))+abs(3-(0+3))+abs(5-(0+4))+abs(5-(0+5))=2.
Any choice of b does not make the sadness of Snuke less than 2, so the answer is 2.

Sample Input 2

9
1 2 3 4 5 6 7 8 9

Sample Output 2

0

Sample Input 3

6
6 5 4 3 2 1

Sample Output 3

18

Sample Input 4

7
1 1 1 1 2 3 4

Sample Output 4

6

Solution in Ruby (2.3.3) (judge verdict: Wrong Answer)

N = gets.to_i
a_line = Array.new
a = gets.split(" ")
a.each do |i|
    a_line.push(i.to_i)
end 

sad = 10000
past_int = 10000
100000000.times do |t|
    s = 0
    N.times do |i|
        s += (a_line[i] - (t+i+1)).abs
    end 
    if s.abs < sad 
        sad = s.to_i 
    end 
    if past_int < s 
        break 
    end 
    past_int = s 
end 
sad_minus = 10000

past_int = 10000
100000000.times do |t|
    s = 0
    N.times do |i|
        s += (a_line[i] - (-t+i+1)).abs
    end 
    if s.abs < sad_minus 
        sad_minus = s.to_i 
    end 
    if past_int < s 
        break 
    end 
    past_int = s 
end 

p [sad,sad_minus].min