Problem:
Score : 200 points

Problem Statement

You have decided to write a book introducing good restaurants.
There are N restaurants that you want to introduce: Restaurant 1, Restaurant 2, ..., Restaurant N. Restaurant i is in city S_i, and your assessment score of that restaurant on a 100-point scale is P_i.
No two restaurants have the same score.

You want to introduce the restaurants in the following order:

The restaurants are arranged in lexicographical order of the names of their cities.

If there are multiple restaurants in the same city, they are arranged in descending order of score.

Print the identification numbers of the restaurants in the order they are introduced in the book.

Constraints

1 ≤ N ≤ 100

S is a string of length between 1 and 10 (inclusive) consisting of lowercase English letters.

0 ≤ P_i ≤ 100

P_i is an integer.

P_i ≠ P_j (1 ≤ i < j ≤ N)

Input

Input is given from Standard Input in the following format:

N
S_1 P_1
:
S_N P_N

Output

Print N lines. The i-th line (1 ≤ i ≤ N) should contain the identification number of the restaurant that is introduced i-th in the book.

Sample Input 1

6
khabarovsk 20
moscow 10
kazan 50
kazan 35
moscow 60
khabarovsk 40

Sample Output 1

3
4
6
1
5
2

The lexicographical order of the names of the three cities is kazan < khabarovsk < moscow. For each of these cities, the restaurants in it are introduced in descending order of score. Thus, the restaurants are introduced in the order 3,4,6,1,5,2.

Sample Input 2

10
yakutsk 10
yakutsk 20
yakutsk 30
yakutsk 40
yakutsk 50
yakutsk 60
yakutsk 70
yakutsk 80
yakutsk 90
yakutsk 100

Sample Output 2

10
9
8
7
6
5
4
3
2
1

Solution in Ruby (2.3.3) (judge verdict: Accepted)

n = gets.to_i
hash = {}

#ハッシュのキーにインデックスを付与
n.times do |i|
  v1,v2 = gets.chomp.split
    hash[i+1] = [v1.to_s,v2.to_i]
end

# 「<=>」演算子の挙動について
# 比較する2項が全く同じ値ならば、返り値が「0」となる
#
# nonzeroメソッドについて
# レシーバが「0」ならば、返り値が「nil」になる
#
# 文字列要素でソートする
# もし文字列要素が同じならば、上記「<=>」の挙動通り、0が返り値となり、
# そして、上記nonzeroメソッドの挙動通り、全体がnilとなる
# 続いて、||　の右側の処理(数値の並び替え)が実行

# ブロック変数を | a, b | とすると、並び替え用に演算子を a <=> b として用いた場合、
# aがbより小さい時はaが先に、aがbより大きい時はaが後に並び替えられます
# || による後者への分岐は、その逆、つまり降順

order = hash.values.sort{|a,b| (a[0] <=> b[0]).nonzero? || b[1] <=> a[1]}


order.each do |i|
  hash.each do |k,v|
    puts k if v == i
  end
end