Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in Ruby (2.7.1) (judge verdict: Wrong Answer)

n=gets.chomp.split("").map(&:to_i)
plus_minus=Array.new(n.length-1,"+")

for i in 1..(2**plus_minus.length)
  v=plus_minus
  result=n[0]

    for j in 0..v.length-1
        vv=i&(1<<j+1)
        if vv!=0
            v[j]="-"
       
        end
            
    end

    for k in 0..v.length-1
        if v[k]=='+'
            result+=n[k+1]
        else
           result-=n[k+1]
        end
    end
  
 
    
    if result==7
        puts "#{n[0]}#{v[0]}#{n[1]}#{v[1]}#{n[2]}#{v[2]}#{n[3]}=7"
    exit
    end
end