Problem:
Cycle Detection for a Directed Graph

Find a cycle in a directed graph G(V, E).

Input

A directed graph G is given in the following format:

|V| |E|
s0 t0
s1 t1
:
s|E|-1 t|E|-1

|V| is the number of nodes and |E| is the number of edges in the graph. The graph nodes are named with the numbers 0, 1,..., |V|-1 respectively.

si and ti represent source and target nodes of i-th edge (directed).

Output

Print 1 if G has cycle(s), 0 otherwise.

Constraints

1 ≤ |V| ≤ 100

0 ≤ |E| ≤ 1,000

si ≠ ti

Sample Input 1

3 3
0 1
0 2
1 2

Sample Output 1

0

Sample Input 2

3 3
0 1
1 2
2 0

Sample Output 2

1

Solution in Ruby (judge verdict: Accepted)

def get_i() #空白区切の入力を数値(整数)の配列で返す
  return gets.chomp.split(" ").map(&:to_i)
end
def get_f() #空白区切の入力を数値(実数)の配列で返す
  return gets.chomp.split(" ").map(&:to_f)
end
def get() #空白区切の入力を文字列の配列で返す
  return gets.chomp.split(" ")
end
def get_nsp() #入力されたものを一文字ずつに区切った文字列の配列で返す
  return gets.chomp.split("")
end
def yn_judge(bool,y="Yes",n="No") #boolに真偽を投げることで、trueならy、falseならnの値を出力する
  return bool ? y : n 
end
def array(size1,init=nil,size2=1) #size2に二次元配列時の最初の要素数、size1に次の配列の大きさ、initに初期値を投げることでその配列を返す
  if size2==1
    return Array.new(size1){init}
  else
    return Array.new(size2){Array.new(size1){init}}
  end
end

V,E=get_i
g=array(V)
ind=array(V,0)
E.times do|i|
  s,t=get_i
  g[s]=[] if g[s].nil?
  g[s].push(t)
  ind[t]+=1
end
$seen=array(V,false)
def tps(g,ind)
  queue=[]
  V.times do|i|
      queue.push(i) if ind[i].zero?
  end
  ans=[]
  until queue==[]
    curr=queue.shift
    ans.push(curr)
    next if g[curr].nil?
    g[curr].each do|v|
        ind[v]-=1
        queue.push(v) if ind[v].zero?
    end
  end
  return ans
end
ans=tps(g,ind)
if ans.size==V
    puts 0
else
    puts 1
end