Problem:
Score : 600 points

Problem Statement

There is a grid with N rows and N columns of squares. Let (i, j) be the square at the i-th row from the top and the j-th column from the left.

Each of the central (N-2) \times (N-2) squares in the grid has a black stone on it.
Each of the 2N - 1 squares on the bottom side and the right side has a white stone on it.

Q queries are given. We ask you to process them in order.
There are two kinds of queries. Their input format and description are as follows:

1 x: Place a white stone on (1, x). After that, for each black stone between (1, x) and the first white stone you hit if you go down from (1, x), replace it with a white stone.

2 x: Place a white stone on (x, 1). After that, for each black stone between (x, 1) and the first white stone you hit if you go right from (x, 1), replace it with a white stone.

How many black stones are there on the grid after processing all Q queries?

Constraints

3 \leq N \leq 2\times 10^5

0 \leq Q \leq \min(2N-4,2\times 10^5)

2 \leq x \leq N-1

Queries are pairwise distinct.

Input

Input is given from Standard Input in the following format:

N Q
Query_1
\vdots
Query_Q

Output

Print how many black stones there are on the grid after processing all Q queries.

Sample Input 1

5 5
1 3
2 3
1 4
2 2
1 2

Sample Output 1

1

After each query, the grid changes in the following way:

Sample Input 2

200000 0

Sample Output 2

39999200004

Sample Input 3

176527 15
1 81279
2 22308
2 133061
1 80744
2 44603
1 170938
2 139754
2 15220
1 172794
1 159290
2 156968
1 56426
2 77429
1 97459
2 71282

Sample Output 3

31159505795

Solution in Ruby (2.7.1) (judge verdict: Time Limit Exceeded)

n, q = gets.chomp.split(" ").map(&:to_i)                                                                                               
                                                                                                                                       
h_line = []                                                                                                                            
v_line = []                                                                                                                            
                                                                                                                                       
q.times do |l|                                                                                                                         
  line_type, line_num = gets.chomp.split(" ").map(&:to_i)                                                                              
  target_arr = line_type == 1 ? h_line : v_line                                                                                        
  alt_arr = line_type == 1 ? v_line : h_line                                                                                           
                                                                                                                                       
  closest = 0                                                                                                                          
  reverse_count = 0                                                                                                                    
  target_arr.each do |old|                                                                                                             
    next if old[0] > line_num                                                                                                          
    next if old[0] < closest                                                                                                           
    closest = old[0]                                                                                                                   
    reverse_count = old[1]                                                                                                             
  end                                                                                                                                  
  if closest == 0                                                                                                                      
    reverse_count = alt_arr.empty? ? n-2 : alt_arr.map{|a| a[0]}.min - 2                                                               
  end                                                                                                                                  
  target_arr << [line_num, reverse_count]                                                                                              
end                                                                                                                                    
reverse_total = h_line.map{|a| a[1]}.sum + v_line.map{|a| a[1]}.sum                                                                    
                                                                                                                                       
print (n-2)**2 - reverse_total