Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in Ruby (judge verdict: Wrong Answer)

s = ""
while (line = gets.chomp) == ""
  s += line
end

a_ord = "a".ord
len = "z".ord - a_ord + 1
table = Array.new(len) { 0 }
s.downcase.chars.select {|x| x =~ /[a-z]/ }.map {|x| x.ord - a_ord }.each {|x| table[x] += 1 }
len.times {|x| puts "#{(x + a_ord).chr} : #{table[x]}" }