Problem:
Score : 400 points

Problem Statement

Given is a string S. Each character in S is either a digit (0, ..., 9) or ?.

Among the integers obtained by replacing each occurrence of ? with a digit, how many have a remainder of 5 when divided by 13? An integer may begin with 0.

Since the answer can be enormous, print the count modulo 10^9+7.

Constraints

S is a string consisting of digits (0, ..., 9) and ?.

1 \leq |S| \leq 10^5

Input

Input is given from Standard Input in the following format:

S

Output

Print the number of integers satisfying the condition, modulo 10^9+7.

Sample Input 1

??2??5

Sample Output 1

768

For example, 482305, 002865, and 972665 satisfy the condition.

Sample Input 2

?44

Sample Output 2

1

Only 044 satisfies the condition.

Sample Input 3

7?4

Sample Output 3

0

We may not be able to produce an integer satisfying the condition.

Sample Input 4

?6?42???8??2??06243????9??3???7258??5??7???????774????4?1??17???9?5?70???76???

Sample Output 4

153716888

Solution in Ruby (2.3.3) (judge verdict: Time Limit Exceeded)

S = gets.chomp.chars
n = S.length

MOD = 10**9 + 7
dp = Array.new(n+1).map{Array.new(13,0)}

# 0桁目まで見たときのあまりが0のものは1個
dp[0][0] = 1

n.times do |i|
  nums = S[n-i-1] == "?" ? (0..9).to_a : [S[n-i-1].to_i]

  # 13 で割ったあまりごとに確認する
  13.times do |mod|
    # modは0~12
    # dp[i][mod] i桁目までの余り
    # 次の桁は mod + addition * dになる
    # dはそのときの数値
    nums.each do |d|
      # 次の桁に遷移する
      dp[i+1][(mod + d * 10**i ) % 13] += dp[i][mod] % MOD
    end
  end
end

puts dp[n][5] %= MOD