Problem:
Score : 200 points

Problem Statement

Rng is preparing a problem set for a qualification round of CODEFESTIVAL.

He has N candidates of problems. The difficulty of the i-th candidate is D_i.

There must be M problems in the problem set, and the difficulty of the i-th problem must be T_i. Here, one candidate of a problem cannot be used as multiple problems.

Determine whether Rng can complete the problem set without creating new candidates of problems.

Constraints

1 \leq N \leq 200,000

1 \leq D_i \leq 10^9

1 \leq M \leq 200,000

1 \leq T_i \leq 10^9

All numbers in the input are integers.

Partial Score

100 points will be awarded for passing the test set satisfying N \leq 100 and M \leq 100.

Input

Input is given from Standard Input in the following format:

N
D_1 D_2 ... D_N
M
T_1 T_2 ... T_M

Output

Print YES if Rng can complete the problem set without creating new candidates of problems; print NO if he cannot.

Sample Input 1

5
3 1 4 1 5
3
5 4 3

Sample Output 1

YES

Sample Input 2

7
100 200 500 700 1200 1600 2000
6
100 200 500 700 1600 1600

Sample Output 2

NO

Not enough 1600s.

Sample Input 3

1
800
5
100 100 100 100 100

Sample Output 3

NO

Sample Input 4

15
1 2 2 3 3 3 4 4 4 4 5 5 5 5 5
9
5 4 3 2 1 2 3 4 5

Sample Output 4

YES

Solution in Ruby (2.7.1) (judge verdict: Wrong Answer)

#いずれも簡単な順に並べる
n = gets.to_i
diff = gets.chomp.split(' ').map(&:to_i).sort
m = gets.to_i
arr = gets.chomp.split(' ').map(&:to_i).sort
i = 0
#diffの探索位置をcurrent_idとしてセット
current_id = 0
while i < arr.size
  if arr[i] < diff[current_id]#第i問の難しさの問題がない
    puts "NO"
    exit
  elsif arr[i] > diff[current_id]#第i問の難しさの問題がdiffの現在の探索位置より右側にある可能性がある
    current_id = diff.bsearch_index {|d| arr[i] <= d}#探索位置を特定する
    unless current_id#右側に無ければだめ
      puts "NO"
    end
  end
  current_id += 1#重複回避
  i += 1
end
puts "YES"