Problem:
Score : 300 points

Problem Statement

You are given N positive integers a_1, a_2, ..., a_N.

For a non-negative integer m, let f(m) = (m\ mod\ a_1) + (m\ mod\ a_2) + ... + (m\ mod\ a_N).

Here, X\ mod\ Y denotes the remainder of the division of X by Y.

Find the maximum value of f.

Constraints

All values in input are integers.

2 \leq N \leq 3000

2 \leq a_i \leq 10^5

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

Print the maximum value of f.

Sample Input 1

3
3 4 6

Sample Output 1

10

f(11) = (11\ mod\ 3) + (11\ mod\ 4) + (11\ mod\ 6) = 10 is the maximum value of f.

Sample Input 2

5
7 46 11 20 11

Sample Output 2

90

Sample Input 3

7
994 518 941 851 647 2 581

Sample Output 3

4527

Solution in Ruby (2.3.3) (judge verdict: Runtime Error)

from functools import reduce


def _gcd(a, b):
    while b:
        a, b = b, a % b
    return a


def _lcm(a, b):
    return (a * b) // _gcd(a, b)


def lcm(*n):
    return reduce(_lcm, n)


def f(_a):
    num = lcm(*_a)
    result = 0
    for i in _a:
        result += (num - 1) % i
    return result


N = int(input())
A = list(map(int, input().split()))
print(f(A))