Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in Ruby (2.3.3) (judge verdict: Wrong Answer)

s = gets.chomp.split("")
dict = s.uniq

if s.size == dict.size
  puts "-1 -1"
  exit
end

#p s.uniq
#p s.size - s.uniq.size
#p s.size/2

#p s.size - s.uniq.size > s.size/2

2.upto(s.size) do |i|
  cnt = 1
  s.each_cons(i) do |arr|
#    puts "arr:" + arr.inspect
    dict.each do |b|
      if arr.size / 2 < arr.count(b)
        puts cnt.to_s + " " + (cnt+i).to_s
        exit
      end
#      p arr.count(b)
#      p arr.size / 2 < arr.count(b)

    end
    cnt += 1
  end
end