Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in Ruby (2.3.3) (judge verdict: Accepted)

def search_xx(s)
  (s.size - 1).times do |i|
    if s[i] == s[i+1] then
      return [i, i+1]
    end
  end
  return nil
end

def search_xyx(s)
  (s.size - 2).times do |i|
    if s[i] == s[i+2] then
      return [i, i+2]
    end
  end
  return nil
end

s = gets.chomp

r1 = search_xx(s)
r2 = search_xyx(s)

r = [-2, -2]
if r1 != nil then
  r = r1
elsif r2 != nil then
  r = r2
end
puts r.map{|v| v+1}.map(&:to_s).join(' ')