Problem:
Score : 100 points

Problem Statement

Given are three integers A_1, A_2, and A_3.

If A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.

Constraints

1 \leq A_i \leq 13 \ \ (i=1,2,3)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A_1 A_2 A_3

Output

If A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.

Sample Input 1

5 7 9

Sample Output 1

win

5+7+9=21, so print win.

Sample Input 2

13 7 2

Sample Output 2

bust

13+7+2=22, so print bust.

Solution in Ruby (2.3.3) (judge verdict: Accepted)

# 3 個の整数 A1, A2, A3 が与えられます。
# A1 + A2 + A3 が 22 以上なら bust、
# 21 以下なら win を出力してください。

# 3個の整数を取得
input = gets.chomp.split
a1 = input[0].to_i
a2 = input[1].to_i
a3 = input[2].to_i

# 結果を格納する変数を宣言
result = String.new

# 3個の整数の和を計算
if a1 + a2 + a3 >= 22
  result = "bust"
else
  result = "win"
end

# 結果を出力
puts result