Problem:
Score : 400 points

Problem Statement

You are given integers N and M.

Consider a sequence a of length N consisting of positive integers such that a_1 + a_2 + ... + a_N = M. Find the maximum possible value of the greatest common divisor of a_1, a_2, ..., a_N.

Constraints

All values in input are integers.

1 \leq N \leq 10^5

N \leq M \leq 10^9

Input

Input is given from Standard Input in the following format:

N M

Output

Print the maximum possible value of the greatest common divisor of a sequence a_1, a_2, ..., a_N that satisfies the condition.

Sample Input 1

3 14

Sample Output 1

2

Consider the sequence (a_1, a_2, a_3) = (2, 4, 8). Their greatest common divisor is 2, and this is the maximum value.

Sample Input 2

10 123

Sample Output 2

3

Sample Input 3

100000 1000000000

Sample Output 3

10000

Solution in Ruby (2.3.3) (judge verdict: Accepted)

class Integer
  def divisors
    res = []
    1.upto((self**0.5)) do |i|
      if self % i == 0
        res.push i
        res.push self / i if i != self / i
      end
    end
    res.sort!
    block_given? ? res.each{|t| yield t } : res
  end
end

n, m = gets.to_s.split.map{|t| t.to_i }

m.divisors.reverse_each do |t|
  if m / t >= n
    puts t
    exit
  end
end