Problem:
Score : 500 points

Problem Statement

Given is a connected undirected graph with N vertices and M edges. The vertices are numbered 1 to N, and the edges are described by a grid of characters S.
If S_{i,j} is 1, there is an edge connecting Vertex i and j; otherwise, there is no such edge.

Determine whether it is possible to divide the vertices into non-empty sets V_1, \dots, V_k such that the following condition is satisfied. If the answer is yes, find the maximum possible number of sets, k, in such a division.

Every edge connects two vertices belonging to two "adjacent" sets. More formally, for every edge (i,j), there exists 1\leq t\leq k-1 such that i\in V_t,j\in V_{t+1} or i\in V_{t+1},j\in V_t holds.

Constraints

2 \leq N \leq 200

S_{i,j} is 0 or 1.

S_{i,i} is 0.

S_{i,j}=S_{j,i}

The given graph is connected.

N is an integer.

Input

Input is given from Standard Input in the following format:

N
S_{1,1}...S_{1,N}
:
S_{N,1}...S_{N,N}

Output

If it is impossible to divide the vertices into sets so that the condition is satisfied, print -1.
Otherwise, print the maximum possible number of sets, k, in a division that satisfies the condition.

Sample Input 1

2
01
10

Sample Output 1

2

We can put Vertex 1 in V_1 and Vertex 2 in V_2.

Sample Input 2

3
011
101
110

Sample Output 2

-1

Sample Input 3

6
010110
101001
010100
101000
100000
010000

Sample Output 3

4

Solution in Ruby (2.3.3) (judge verdict: Time Limit Exceeded)

n = gets.to_i
s = (1..n).map{|a|gets.chomp.chars.map(&:to_i)}
#######
result = -1
nodes = Array.new(n+1){
  {
    sides: [],
    limit: nil, # nilはallOK, []はallNG
    kotei: nil, # 固定したら
    visit: false,
  }
}
n.times do |i|
  n.times do |ii|
    nodes[i+1][:sides] << ii+1 if s[i][ii] == 1
  end
end
n.times do |ifirst| #############
n.times do |i|
  nodes[i+1][:limit] = nil
  nodes[i+1][:kotei] = nil
  nodes[i+1][:visit] = false
end
first = ifirst+1
nodes[first][:limit] = [1]
queue = [first]
while !queue.empty?
  ind = queue.shift # とるときshift, 入れるとき<<(push)
  next if nodes[ind][:visit]
  kotei = nodes[ind][:limit].max # できるだけ大きい値で固定
  if kotei.nil?
    break
  end
  nodes[ind][:kotei] = kotei
  nodes[ind][:sides].each do |side| # sideは周りのnodesのindex
    if nodes[side][:limit].nil?
      nodes[side][:limit] = [nodes[ind][:kotei]-1, nodes[ind][:kotei]+1]
    else
      nodes[side][:limit] = nodes[side][:limit] & [nodes[ind][:kotei]-1, nodes[ind][:kotei]+1]
      if nodes[side][:limit].empty?
        puts '-1'
        exit
      end
    end
    queue << side if nodes[side][:visit] == false
  end
  nodes[ind][:visit] = true
end
if nodes[1..-1].map{|a|a[:kotei]}.none?{|a|a.nil?}
  tmpmax = nodes[1..-1].map{|a|a[:kotei]}.max
  if result < tmpmax
    result = tmpmax
  end
end
end ##################
p result