Problem:
Score : 600 points

Problem Statement

Snuke has an integer sequence, a, of length N. The i-th element of a (1-indexed) is a_{i}.

He can perform the following operation any number of times:

Operation: Choose integers x and y between 1 and N (inclusive), and add a_x to a_y.

He would like to perform this operation between 0 and 2N times (inclusive) so that a satisfies the condition below. Show one such sequence of operations.
It can be proved that such a sequence of operations always exists under the constraints in this problem.

Condition: a_1 \leq a_2 \leq ... \leq a_{N}

Constraints

2 \leq N \leq 50

-10^{6} \leq a_i \leq 10^{6}

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_{N}

Output

Let m be the number of operations in your solution. In the first line, print m.
In the i-th of the subsequent m lines, print the numbers x and y chosen in the i-th operation, with a space in between.
The output will be considered correct if m is between 0 and 2N (inclusive) and a satisfies the condition after the m operations.

Sample Input 1

3
-2 5 -1

Sample Output 1

2
2 3
3 3

After the first operation, a = (-2,5,4).

After the second operation, a = (-2,5,8), and the condition is now satisfied.

Sample Input 2

2
-1 -3

Sample Output 2

1
2 1

After the first operation, a = (-4,-3) and the condition is now satisfied.

Sample Input 3

5
0 0 0 0 0

Sample Output 3

0

The condition is satisfied already in the beginning.

Solution in Ruby (2.3.3) (judge verdict: Accepted)

n = gets.to_i
a = gets.split.map(&:to_i)

max = a.index(a.max)
min = a.index(a.min)

c = 0
ans = []
if a[max] + a[min] > 0
    n.times do |i| 
        if a[i] < 0
            a[i] += a[max] 
            c += 1
            ans << "#{max+1} #{i+1}"
        end
    end

    0.upto(n-2) do |i|
        max = i if a[max] < a[i]

        while a[i] > a[i+1]
            a[i+1] += a[max]
            c += 1
            ans << "#{max+1} #{i+2}"
        end
    end
else
    n.times do |i|
        if a[i] > 0
            a[i] += a[min] 
            c += 1
            ans << "#{min+1} #{i+1}"
        end
    end

    (n-1).downto(1) do |i|
        min = i if a[min] > a[i]

        while a[i-1] > a[i]
            a[i-1] += a[min]
            c += 1
            ans << "#{min+1} #{i}"
        end
    end
end

#p a
puts c,ans