Problem:
Score : 300 points

Problem Statement

You are given an integer N.
Find the number of the positive divisors of N!, modulo 10^9+7.

Constraints

1≤N≤10^3

Input

The input is given from Standard Input in the following format:

N

Output

Print the number of the positive divisors of N!, modulo 10^9+7.

Sample Input 1

3

Sample Output 1

4

There are four divisors of 3! =6: 1, 2, 3 and 6. Thus, the output should be 4.

Sample Input 2

6

Sample Output 2

30

Sample Input 3

1000

Sample Output 3

972926972

Solution in Ruby (2.3.3) (judge verdict: Wrong Answer)

p= [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41]
n=gets.to_i
s=1
q=[]
p.each{|e|
j=0
for k in 1..10
j+=n/(e**k)
end
q<<j if j!=0
}
q.each{|e|s*=(e+1)}
p s