Problem:
Score : 200 points

Problem Statement

Takahashi's house has only one socket.

Takahashi wants to extend it with some number of power strips, each with A sockets, into B or more empty sockets.

One power strip with A sockets can extend one empty socket into A empty sockets.

Find the minimum number of power strips required.

Constraints

All values in input are integers.

2 \leq A \leq 20

1 \leq B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of power strips required.

Sample Input 1

4 10

Sample Output 1

3

3 power strips, each with 4 sockets, extend the socket into 10 empty sockets.

Sample Input 2

8 9

Sample Output 2

2

2 power strips, each with 8 sockets, extend the socket into 15 empty sockets.

Sample Input 3

8 8

Sample Output 3

1

Solution in Ruby (2.3.3) (judge verdict: Wrong Answer)

=begin
a = gets.split("").map{|x| x.to_s}
b = gets.split("").map{|x| x.to_s}
count = 0
3.times do |i|
  if a[i] == b[i]
    count += 1
  end
end

p count
=end

a = gets.split(" ").map{|x| x.to_f}

if a[0] == a[1]
  p 1
  exit()
end
a[1] -= a[0]

if(a[1] / (a[0] - 1) < 0)
  p 1
  exit()
elsif(a[1] / (a[0] - 1) >= 0 and a[1] / (a[0] - 1) < 1)
  hoge = 1
else
  hoge = a[1] / (a[0] - 1)
end

p hoge + 1