Problem:
Simultaneous Equation

Write a program which solve a simultaneous equation:

ax + by = c

dx + ey = f

The program should print x and y for given a, b, c, d, e and f (-1,000 ≤ a, b, c, d, e, f ≤ 1,000). You can suppose that given equation has a unique solution.

Input

The input consists of several data sets, 1 line for each data set. In a data set, there will be a, b, c, d, e, f separated by a single space. The input terminates with EOF.

Output

For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.

Sample Input 1

1 2 3 4 5 6
2 -1 -2 -1 -1 -5

Output for the Sample Input 1

-1.000 2.000
1.000 4.000

Sample Input 2

2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27

Output for the Sample Input 2

0.000 3.000
0.000 3.000

Solution in Ruby (judge verdict: Wrong Answer)

while true do
    begin
        a1, b1, c1, a2, b2, c2 = gets.split(" ").map(&:to_i)
        if a1 != 0 && a2 != 0 && b1 != 0 && b2 != 0
            printf("%.3f %.3f\n", (c1*b2 - c2*b1) / (a1*b2 - a2*b1) + 0.0, (a1*c2 - a2*c1) / (a1*b2 - a2*b1) + 0.0)
        else
            if a1 == 0 && a2 == 0
                printf("%.3f %.3f\n",  0,  c1/b1 + 0.0)
            elsif b1 == 0 && b2 == 0
                printf("%.3f %.3f\n",  c1/a1, 0 + 0.0)
            else
                printf("%.3f %.3f\n", (c1*b2 - c2*b1) / (a1*b2 - a2*b1) + 0.0, (a1*c2 - a2*c1) / (a1*b2 - a2*b1) + 0.0)
            end
        end
    rescue
        break
    end
end