Problem:
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Dice IV

Write a program which reads $n$ dices constructed in the same way as Dice I, and determines whether they are all different. For the determination, use the same way as Dice III.

Input

In the first line, the number of dices $n$ is given. In the following $n$ lines, six integers assigned to the dice faces are given respectively in the same way as Dice III.

Output

Print "Yes" if given dices are all different, otherwise "No" in a line.

Constraints

$2 \leq n \leq 100$

$0 \leq $ the integer assigned to a face $ \leq 100$

Sample Input 1

3
1 2 3 4 5 6
6 2 4 3 5 1
6 5 4 3 2 1

Sample Output 1

No

Sample Input 2

3
1 2 3 4 5 6
6 5 4 3 2 1
5 4 3 2 1 6

Sample Output 2

Yes

Solution in Ruby (judge verdict: Runtime Error)

class Dice
  def dice_s(arr, i)
    arr[i][0],arr[i][1],arr[i][4],arr[i][5] = arr[i][4],arr[i][0],arr[i][5],arr[i][1]
    return arr[i]
  end

  def dice_e(arr, i)
    arr[i][0],arr[i][2],arr[i][3],arr[i][5] = arr[i][3],arr[i][0],arr[i][5],arr[i][2]
    return arr[i]
  end

  def dice_w(arr, i)
    arr[i][0],arr[i][2],arr[i][3],arr[i][5] = arr[i][2],arr[i][5],arr[i][0],arr[i][3]
    return arr[i]
  end

  def dice_n(arr, i)
    arr[i][0],arr[i][1],arr[i][4],arr[i][5] = arr[i][1],arr[i][5],arr[i][0],arr[i][4]
    return arr[i]
  end

  def dice_b(arr, i)
    arr[i][0],arr[i][1],arr[i][4],arr[i][5] = arr[i][5],arr[i][4],arr[i][1],arr[i][0]
    return arr[i]
  end

  def dice_sp(arr, i)
    arr[i][1],arr[i][2],arr[i][4],arr[i][3] = arr[i][2],arr[i][4],arr[i][3],arr[i][1]
    return arr[i]
  end
end

n = gets.chomp.to_i
arr = Array.new(n){Array.new(6)}
arr[0] = gets.chomp.split.map(&:to_i)
a = false
dice = Dice.new()

for i in 1..n-1
  arr[i] = gets.chomp.split.map(&:to_i)

  case arr[0][0]
  when arr[i][4]; dice.dice_s(arr, i)
  when arr[i][3]; dice.dice_e(arr, i)
  when arr[i][2]; dice.dice_w(arr, i)
  when arr[i][1]; dice.dice_n(arr, i)
  when arr[i][5]; dice.dice_b(arr, i)
  end

  4.times{
    if arr[0][1] != arr[i][1]
      dice.dice_sp(arr, i)
    else
      break
    end
  }

  break if arr[0] == arr[i]

  next if i < n-1

  catch(:break) do
    for j in 1..n-1
      for k in j+1..n-1
        throw :break if arr[j] == arr[k]
      end
    end
    a = treu
  end
end

puts a == true ? "Yes" : "No"