Problem:
Score: 100 points

Problem Statement

In AtCoder Kingdom, Gregorian calendar is used, and dates are written in the "year-month-day" order, or the "month-day" order without the year.

For example, May 3, 2018 is written as 2018-5-3, or 5-3 without the year.

In this country, a date is called Takahashi when the month and the day are equal as numbers. For example, 5-5 is Takahashi.

How many days from 2018-1-1 through 2018-a-b are Takahashi?

Constraints

a is an integer between 1 and 12 (inclusive).

b is an integer between 1 and 31 (inclusive).

2018-a-b is a valid date in Gregorian calendar.

Input

Input is given from Standard Input in the following format:

a b

Output

Print the number of days from 2018-1-1 through 2018-a-b that are Takahashi.

Sample Input 1

5 5

Sample Output 1

5

There are five days that are Takahashi: 1-1, 2-2, 3-3, 4-4 and 5-5.

Sample Input 2

2 1

Sample Output 2

1

There is only one day that is Takahashi: 1-1.

Sample Input 3

11 30

Sample Output 3

11

There are eleven days that are Takahashi: 1-1, 2-2, 3-3, 4-4, 5-5, 6-6, 7-7, 8-8, 9-9, 10-10 and 11-11.

Solution in Ruby (2.3.3) (judge verdict: Runtime Error)

#set
h,w = gets.chomp.split(" ").map(&:to_i)
line = Array.new(h)
squares = Array.new(h) {Array.new(w, 0)}
answer = "Yes"

(0 .. h - 1).each do |i|
    line[i] = gets.chomp
    (0 .. w - 1).each do |j|
        squares[i][j] = line[i].split("")[j]
    end
end

#main
(0 .. h - 1).each do |i|
    (0 .. w - 1).each do |j|
        # p squares[i][j]
        if squares[i][j] == "#" then
            chk_flag = 0
            (i - 1 .. i + 1).each do |x|
                (j - 1 .. j + 1).each do |y|
                    if ( x == i || y == j ) && ( x >= 0 && x < h ) && ( y >= 0 && y < w ) then
                        if x == i && y == j then
                            next
                        else
                            if squares[x][y] == "#" then
                                chk_flag += 1
                            end
                        end
                    end
                end
            end
            
            if chk_flag == 0 then
                answer = "No"
                print ("#{answer}\n")
                exit
            end
        end
    end
end

print ("#{answer}\n")