Problem:
Score : 400 points

Problem Statement

Find the largest integer that can be formed with exactly N matchsticks, under the following conditions:

Every digit in the integer must be one of the digits A_1, A_2, ..., A_M (1 \leq A_i \leq 9).

The number of matchsticks used to form digits 1, 2, 3, 4, 5, 6, 7, 8, 9 should be 2, 5, 5, 4, 5, 6, 3, 7, 6, respectively.

Constraints

All values in input are integers.

2 \leq N \leq 10^4

1 \leq M \leq 9

1 \leq A_i \leq 9

A_i are all different.

There exists an integer that can be formed by exactly N matchsticks under the conditions.

Input

Input is given from Standard Input in the following format:

N M
A_1 A_2 ... A_M

Output

Print the largest integer that can be formed with exactly N matchsticks under the conditions in the problem statement.

Sample Input 1

20 4
3 7 8 4

Sample Output 1

777773

The integer 777773 can be formed with 3 + 3 + 3 + 3 + 3 + 5 = 20 matchsticks, and this is the largest integer that can be formed by 20 matchsticks under the conditions.

Sample Input 2

101 9
9 8 7 6 5 4 3 2 1

Sample Output 2

71111111111111111111111111111111111111111111111111

The output may not fit into a 64-bit integer type.

Sample Input 3

15 3
5 4 6

Sample Output 3

654

Solution in Ruby (2.3.3) (judge verdict: Time Limit Exceeded)

n,m=gets.split.map(&:to_i)
a=gets.split.map(&:to_i)
INF=10**9+1
list=[INF,2,5,5,4,5,6,3,7,6]
dp=["z"]*(n+1)
dp[0]=""

a.each do |c|
    s=list[c]
    0.upto(n) do |i|
        if i+s<=n and dp[i]!='z'
            if dp[i][0].to_i<=c and (c.to_s+dp[i]).to_i>dp[i+s].to_i
                dp[i+s]=c.to_s+dp[i]
            elsif 
                dp[i][0].to_i>=c and (dp[i]+c.to_s).to_i>dp[i+s].to_i
                dp[i+s]=dp[i]+c.to_s
            end
        end
    end
end
puts dp[n]