Problem:
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Dice II

Construct a dice from a given sequence of integers in the same way as Dice I.

You are given integers on the top face and the front face after the dice was rolled in the same way as Dice I. Write a program to print an integer on the right side face.

Input

In the first line, six integers assigned to faces are given in ascending order of their corresponding labels.
In the second line, the number of questions $q$ is given.

In the following $q$ lines, $q$ questions are given. Each question consists of two integers on the top face and the front face respectively.

Output

For each question, print the integer on the right side face.

Constraints

$0 \leq $ the integer assigned to a face $ \leq 100$

The integers are all different

$1 \leq q \leq 24$

Sample Input

1 2 3 4 5 6
3
6 5
1 3
3 2

Sample Output

3
5
6

Solution in Ruby (judge verdict: Accepted)

class Dice      
    @face = nil         
                        
    def initialize ary   
        @face = ary        
    end                     

    def top
        @face[0]
    end

    def rotate news     
        f = @face.dup
        case news
        when "N"
            @face = [f[1],f[5],f[2],f[3],f[0],f[4]]
        when "E"
            @face = [f[3],f[1],f[0],f[5],f[4],f[2]]
        when "W"
            @face = [f[2],f[1],f[5],f[0],f[4],f[3]]
        when "S"
            @face = [f[4],f[0],f[2],f[3],f[5],f[1]]
        end
    end

    def right top,front
        "SWSWS".each_char do |c|
            break if @face[0] == top
            rotate c
        end
        rotate "N"
        "WWW".each_char do |c|
            break if @face[0] == front
            rotate c
        end
    @face[2]
    end
end

numbers = gets.chomp.split
dice = Dice.new numbers
gets.to_i.times do 
    top,front = gets.chomp.split
    puts dice.right top,front
end