Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in Ruby (judge verdict: Accepted)

aryAlphabetCount = Array.new(26,0);
strAlphabet = "abcdefghijklmnopqrstuvwxyz";

while true do
 
	inputLines = gets;
 
	if inputLines == nil || inputLines.length == 0 then
		break;
	end
 
	checkStr = inputLines.downcase;
	
	for checkStrIndex in 0..checkStr.length-1 do
		for alphabetIndex in 0..strAlphabet.length-1 do
			
			if checkStr[checkStrIndex] == strAlphabet[alphabetIndex] then
				
				aryAlphabetCount[alphabetIndex] += 1;
		end
			
		end
	end
end

for index in 0..aryAlphabetCount.length-1 do
	
	puts strAlphabet[index] + " : " + aryAlphabetCount[index].to_s
end