Problem:
Score : 200 points

Problem Statement

There are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.

Takahashi says: "there are X animals in total in the garden, and they have Y legs in total." Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.

Constraints

1 \leq X \leq 100

1 \leq Y \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

If there is a combination of numbers of cranes and turtles in which the statement is correct, print Yes; otherwise, print No.

Sample Input 1

3 8

Sample Output 1

Yes

The statement "there are 3 animals in total in the garden, and they have 8 legs in total" is correct if there are two cranes and one turtle. Thus, there is a combination of numbers of cranes and turtles in which the statement is correct.

Sample Input 2

2 100

Sample Output 2

No

There is no combination of numbers of cranes and turtles in which this statement is correct.

Sample Input 3

1 2

Sample Output 3

Yes

We also consider the case in which there are only cranes or only turtles.

Solution in Ruby (2.7.1) (judge verdict: Accepted)

#!/usr/bin/env ruby
# require 'pry'

# dpテンプレ
# 最小化
# dp = Hash.new{ Float::INFINITY }
# dp[i] = [dp[i], dp[i-1] + hoge].min
# dp[0] = 0
# 最大化
# dp = Hash.new{ 0 }
# dp[i] = [dp[i], dp[i-1] + hoge].max
# dp[0] = 0

x,y = gets.split(' ').map(&:to_i)

0.upto(100) do |turu|
  0.upto(100) do |kame|
    f = turu*2 + kame*4
    if turu + kame == x && f == y
      puts 'Yes'
      exit
    elsif turu == 100 && kame == 100
      puts 'No'
    end
  end
end