Problem:
Stable Sort

Let's arrange a deck of cards. There are totally 36 cards of 4 suits(S, H, C, D) and 9 values (1, 2, ... 9). For example, 'eight of heart' is represented by H8 and 'one of diamonds' is represented by D1.

Your task is to write a program which sorts a given set of cards in ascending order by their values using the Bubble Sort algorithms and the Selection Sort algorithm respectively. These algorithms should be based on the following pseudocode:

BubbleSort(C)
1 for i = 0 to C.length-1
2 for j = C.length-1 downto i+1
3 if C[j].value < C[j-1].value
4 swap C[j] and C[j-1]

SelectionSort(C)
1 for i = 0 to C.length-1
2 mini = i
3 for j = i to C.length-1
4 if C[j].value < C[mini].value
5 mini = j
6 swap C[i] and C[mini]

Note that, indices for array elements are based on 0-origin.

For each algorithm, report the stability of the output for the given input (instance). Here, 'stability of the output' means that: cards with the same value appear in the output in the same order as they do in the input (instance).

Input

The first line contains an integer N, the number of cards.

N cards are given in the following line. Each card is represented by two characters. Two consecutive cards are separated by a space character.

Output

In the first line, print the arranged cards provided by the Bubble Sort algorithm. Two consecutive cards should be separated by a space character.

In the second line, print the stability ("Stable" or "Not stable") of this output.

In the third line, print the arranged cards provided by the Selection Sort algorithm. Two consecutive cards should be separated by a space character.

In the fourth line, print the stability ("Stable" or "Not stable") of this output.

Constraints

1 ≤ N ≤ 36

Sample Input 1

5
H4 C9 S4 D2 C3

Sample Output 1

D2 C3 H4 S4 C9
Stable
D2 C3 S4 H4 C9
Not stable

Sample Input 2

2
S1 H1

Sample Output 2

S1 H1
Stable
S1 H1
Stable

Solution in Ruby (judge verdict: Accepted)

def bubble(ary)
  flg = true
  n = ary.length

  while flg
    flg = false
    (n - 1).downto(1) do |i|
      next if ary[i][1].to_i >= ary[i - 1][1].to_i
      ary[i], ary[i - 1] = ary[i - 1], ary[i]
      flg = true
    end
  end

  ary
end

def selection(ary)
  n = ary.size

  n.times do |i|
    minj = i
    i.upto(n - 1) do |j|
      minj = j if ary[minj][1].to_i > ary[j][1].to_i
    end
    ary[i], ary[minj] = ary[minj], ary[i]
  end

  ary
end

gets

input = gets.chomp.split

b_ary = bubble(input.dup)
s_ary = selection(input.dup)

puts b_ary * ' ', 'Stable', s_ary* ' '
puts b_ary == s_ary ? 'Stable' : 'Not stable'