Problem:
Score : 300 points

Problem Statement

In a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0.
You are given a sequence h=\{h_1,h_2,h_3,......\} as input. You would like to change the height of Flower k to h_k for all k (1 \leq k \leq N), by repeating the following "watering" operation:

Specify integers l and r. Increase the height of Flower x by 1 for all x such that l \leq x \leq r.

Find the minimum number of watering operations required to satisfy the condition.

Constraints

1 \leq N \leq 100

0 \leq h_i \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
h_1 h_2 h_3 ...... h_N

Output

Print the minimum number of watering operations required to satisfy the condition.

Sample Input 1

4
1 2 2 1

Sample Output 1

2

The minimum number of watering operations required is 2.
One way to achieve it is:

Perform the operation with (l,r)=(1,3).

Perform the operation with (l,r)=(2,4).

Sample Input 2

5
3 1 2 3 1

Sample Output 2

5

Sample Input 3

8
4 23 75 0 23 96 50 100

Sample Output 3

221

Solution in Ruby (2.3.3) (judge verdict: Accepted)

n=gets.to_i
hNumbers=gets.split.map(&:to_i)
hNumberLength = hNumbers.length
tempHNumbers=Array.new(hNumberLength,0)
loopCount=0
loop do
  completNumber=0
  growFlag=false
  hNumbers.each_with_index do |value,index|
    if tempHNumbers[index] < value
      tempHNumbers[index] += 1 
      growFlag = true
    elsif tempHNumbers[index] == value
      break if growFlag
      completNumber += 1
    elsif tempHNumbers[index] > value && growFlag
      break
    end
  end
  loopCount += 1
  break if hNumberLength == completNumber
end
puts (loopCount-1)