Problem:
Score : 500 points

Problem Statement

There are N towns on a plane. The i-th town is located at the coordinates (x_i,y_i). There may be more than one town at the same coordinates.

You can build a road between two towns at coordinates (a,b) and (c,d) for a cost of min(|a-c|,|b-d|) yen (the currency of Japan). It is not possible to build other types of roads.

Your objective is to build roads so that it will be possible to travel between every pair of towns by traversing roads. At least how much money is necessary to achieve this?

Constraints

2 ≤ N ≤ 10^5

0 ≤ x_i,y_i ≤ 10^9

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
x_1 y_1
x_2 y_2
:
x_N y_N

Output

Print the minimum necessary amount of money in order to build roads so that it will be possible to travel between every pair of towns by traversing roads.

Sample Input 1

3
1 5
3 9
7 8

Sample Output 1

3

Build a road between Towns 1 and 2, and another between Towns 2 and 3. The total cost is 2+1=3 yen.

Sample Input 2

6
8 3
4 9
12 19
18 1
13 5
7 6

Sample Output 2

8

Solution in Ruby (2.3.3) (judge verdict: Time Limit Exceeded)

N = gets.chop.to_i
TOWN = {}
N.times do |i|
  x, y = gets.chop.split.map(&:to_i)
  TOWN[i] = [x, y]
end

@xSortTown = TOWN.sort do |a, b|
               a[1][0] <=> b[1][0]
             end.to_h
@ySortTown = TOWN.sort do |a, b|
               a[1][1] <=> b[1][1]
             end.to_h
@linkedTowns = {}

# p @xSortTown, @ySortTown

def xCost(p, q)
  (p[1][0] - q[1][0]).abs
end

def yCost(p, q)
  (p[1][1] - q[1][1]).abs
end

def closestTownAndCost(o, p, q)
  xc = xCost(o, p)
  yc = yCost(o, q)
  if xc <= yc
    return p, xc
  else
    return q, yc
  end
end

total_cost = 0

town = @xSortTown.first
@xSortTown.delete(town[0])
@ySortTown.delete(town[0])
@linkedTowns[town[0]] = town[1]

#p @xSortTown, @ySortTowln
#p '--'

(N-1).times do |i|
  xCloseTown = @xSortTown.first
  yCloseTown = @ySortTown.first
  minTownArray = nil
  minCost = 10**10
  @linkedTowns.each do |from_town|
    town, cost = closestTownAndCost(from_town, xCloseTown, yCloseTown)
    if cost < minCost
      minCost = cost
      minTownArray = town
    end
  end
  total_cost += minCost
  @linkedTowns[minTownArray[0]] = minTownArray[1]
  @xSortTown.delete(minTownArray[0])
  @ySortTown.delete(minTownArray[0])
end

p total_cost