Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Ruby (2.3.3) (judge verdict: Runtime Error)

# Wrote in 2020-03-01 21:04:26 by reetok
require 'time'
require 'prime'
def inp(type=:to_i,spst=" ")
  return eval("gets.chomp.split(#{spst}).map(&:#{type})")
end
def inpf() return self.inp(:to_f," ") end
def inps() return self.inp(:to_s," ") end
def r_up(a, b) (a/b).ceil end
def r_down(a, b) (a/b).floor end
def sum(a) a.inject(:+) end
def big(a,b) return (a>b)? a:b end
def small(a,b) return (a<b)? a:b end
def minp(n,datatype=:to_i)
  t = []
  n.times do
    t.push(eval("gets.chomp.#{datatype.to_s}"))
  end
  return t
end
def yes() puts "Yes" end
def no() puts "No" end
def ynju(bool,yes="Yes",no="No") puts (bool ? yes : no) end
#---------------

array = []

array.push(inp)
array.push(inp)
array.push(inp)

n = inp[0]

b = minp(n)
i = 0
array.each{|a| 
  if a[0].include?(b)
    array[i][0] = true
  elsif a[1].include?(b)
    array[i][1] = true
  elsif a[2].include?(b)
    array[i][2] = true
  end
  i+=1
}


if a[0][0]&&a[0][1]&&a[0][2] || a[1][0]&&a[1][1]&&a[1][2]||a[2][0]&&a[2][1]&&a[2][2]||a[0][0]&&a[1][0]&&a[2][0]||a[0][1]&&a[1][1]&&a[2][1]||a[0][2]&&a[1][2]&&a[2][2]||a[0][0]&&a[1][1]&&a[2][2]||a[0][2]&&a[1][1]&&a[2][0]
  puts "Yes"
else
  puts "No"
end