Problem:
Score : 400 points

Problem Statement

You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

In the i-th operation, you replace every element whose value is B_{i} with C_{i}.

For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

All values in input are integers.

1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}

B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:

N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}

Output

Print Q integers S_{i} to Standard Output in the following format:

S_{1}
S_{2}
\vdots
S_{Q}

Note that S_{i} may not fit into a 32-bit integer.

Sample Input 1

4
1 2 3 4
3
1 2
3 4
2 4

Sample Output 1

11
12
16

Initially, the sequence A is 1,2,3,4.

After each operation, it becomes the following:

2, 2, 3, 4

2, 2, 4, 4

4, 4, 4, 4

Sample Input 2

4
1 1 1 1
3
1 2
2 1
3 5

Sample Output 2

8
4
4

Note that the sequence A may not contain an element whose value is B_{i}.

Sample Input 3

2
1 2
3
1 100
2 100
100 1000

Sample Output 3

102
200
2000

Solution in Ruby (2.7.1) (judge verdict: Accepted)

#n,k=gets.split(' ').map(&:to_i)
#h=gets.split(' ').map(&:to_i)
#tajigen = Array.new(4) { Array.new(2,0) }
n=gets.to_i
a=gets.split(' ').map(&:to_i)
q=gets.to_i
#Array.new=n_hairetu[n+1]
n_hairetu=Array.new(10**6,0)
a.each do |i|
  n_hairetu[i]+=1
end
#puts n_hairetu
sum=a.sum
#puts sum
tajigen = Array.new(q) { Array.new(2,0) }
for i in 0..q-1
  b,c=gets.split(' ').map(&:to_i)
  tajigen[i][0]= b
  tajigen[i][1]= c
end
#puts tajigen
#puts sum
for i in 0..q-1
  #b,c=gets.split(' ').map(&:to_i)
  b=tajigen[i][0]
  c=tajigen[i][1]
  #puts b
  #puts c
  b_count=n_hairetu[b]
  c_count=n_hairetu[c]
  sum=sum-b*b_count+c*(b_count)
  n_hairetu[b]=0
  n_hairetu[c]+=b_count
  puts sum
end