Problem:
Score : 400 points

Problem Statement

There are N empty boxes arranged in a row from left to right.
The integer i is written on the i-th box from the left (1 \leq i \leq N).

For each of these boxes, Snuke can choose either to put a ball in it or to put nothing in it.

We say a set of choices to put a ball or not in the boxes is good when the following condition is satisfied:

For every integer i between 1 and N (inclusive), the total number of balls contained in the boxes with multiples of i written on them is congruent to a_i modulo 2.

Does there exist a good set of choices? If the answer is yes, find one good set of choices.

Constraints

All values in input are integers.

1 \leq N \leq 2 \times 10^5

a_i is 0 or 1.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N

Output

If a good set of choices does not exist, print -1.

If a good set of choices exists, print one such set of choices in the following format:

M
b_1 b_2 ... b_M

where M denotes the number of boxes that will contain a ball, and b_1,\ b_2,\ ...,\ b_M are the integers written on these boxes, in any order.

Sample Input 1

3
1 0 0

Sample Output 1

1
1

Consider putting a ball only in the box with 1 written on it.

There are three boxes with multiples of 1 written on them: the boxes with 1, 2, and 3. The total number of balls contained in these boxes is 1.

There is only one box with a multiple of 2 written on it: the box with 2. The total number of balls contained in these boxes is 0.

There is only one box with a multiple of 3 written on it: the box with 3. The total number of balls contained in these boxes is 0.

Thus, the condition is satisfied, so this set of choices is good.

Sample Input 2

5
0 0 0 0 0

Sample Output 2

0

Putting nothing in the boxes can be a good set of choices.

Solution in Ruby (2.3.3) (judge verdict: Wrong Answer)

def ok(a, b)
  1.upto(N) do |i|
    s = 0
    i.step(N, i) do |j|
      s ^= b[j]
    end
    return false if s != a[i]
  end
  true
end

def divisors(n)
  r = []
  1.upto(n) do |i|
    break unless i <= n/i
    r << i
    r << n/i unless i != n/i
  end
  r
end

N=gets.to_i
a=[0]+gets.split.map(&:to_i)

b=Array.new(N+1){0}
1.upto(N) do |i|
  next if a[i].zero?
  b[i] = 1
  divisors(i).each do |j|
    b[j] ^= 1 if (i%j).zero?
  end
end
if ok(a, b)
  r=[]
  b.each.with_index do |x, i|
    r << i unless x.zero?
  end
  p r.size
  puts r*" " unless r.size.zero?
else
  p -1
end