Problem:
Score : 600 points

Problem Statement

Given are two sequences A and B, both of length N.
A and B are each sorted in the ascending order.
Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.

Constraints

1\leq N \leq 2 \times 10^5

1\leq A_i,B_i \leq N

A and B are each sorted in the ascending order.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N

Output

If there exist no reorderings that satisfy the condition, print No.

If there exists a reordering that satisfies the condition, print Yes on the first line.
After that, print a reordering of B on the second line, separating terms with a whitespace.

If there are multiple reorderings that satisfy the condition, you can print any of them.

Sample Input 1

6
1 1 1 2 2 3
1 1 1 2 2 3

Sample Output 1

Yes
2 2 3 1 1 1

Sample Input 2

3
1 1 2
1 1 3

Sample Output 2

No

Sample Input 3

4
1 1 2 3
1 2 3 3

Sample Output 3

Yes
3 3 1 2

Solution in Ruby (2.7.1) (judge verdict: Wrong Answer)

require 'pp'

n = gets.to_i
a_n = gets.split.map(&:to_i)
b_n = gets.split.map(&:to_i)

x = a_n.tally
y = b_n.tally
keys = y.keys
sum = {}
x.each do |k, v|
    t = v + (y[k] || 0) 
    if t > n
        puts 'No'
        exit 0
    end

    sum[k] = t
end
puts "Yes"

#pp x
#pp y
#pp keys
i = 0
ans = []
a_n.each do |a|
    if b_n[i] != a
        ans << b_n[i]
        i = (i + 1) % n
    else
        i = (i + 1) % n
        redo
    end     
end

puts ans.join(" ")