Problem:
Score : 300 points

Problem Statement

You are given an integer N.
Find the number of the positive divisors of N!, modulo 10^9+7.

Constraints

1≤N≤10^3

Input

The input is given from Standard Input in the following format:

N

Output

Print the number of the positive divisors of N!, modulo 10^9+7.

Sample Input 1

3

Sample Output 1

4

There are four divisors of 3! =6: 1, 2, 3 and 6. Thus, the output should be 4.

Sample Input 2

6

Sample Output 2

30

Sample Input 3

1000

Sample Output 3

972926972

Solution in Ruby (2.7.1) (judge verdict: Accepted)

require 'prime'
N=gets.to_i
MOD=10**9+7
PRIMES = {}
(2..N).each do |i|
    Prime.prime_division(i).each do |n, e|
        PRIMES[n] ||= 0
        PRIMES[n] += e
    end
end
ret = 1
PRIMES.each do |k,v|
    ret *= (v+1)
    ret %= MOD
end
puts ret