Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Ruby (2.3.3) (judge verdict: Accepted)

=begin
number = 105
count = 1
divisor = 0
ans = 0
loop do 
  break if number > 200
  while count <= number
    divisor += 1 if number%count == 0
    count += 1
  end
  if divisor == 8
    ans += 1
    puts number
  end
  count = 1
  number += 2
  divisor = 0
end
puts ans
=end

a = gets.to_i
if a >=195
  puts 5
elsif a >= 189
  puts 4
elsif a >= 165
  puts 3
elsif a >= 135
  puts 2
elsif a >= 105
  puts 1
else
  puts 0
end