Problem:
Disjoint Set

Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.

same(x, y): determine whether x and y are in the same set.

Input

n q
com1 x1 y1
com2 x2 y2
...
comq xq yq

In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Constraints

1 ≤ n ≤ 10000

1 ≤ q ≤ 100000

x ≠ y

Sample Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0

Sample Output

0
0
1
1
1
0
1
1

Solution in Ruby (judge verdict: Wrong Answer)

n, q = gets.split.map(&:to_i)

hash = Hash.new{|h,k| h[k] = []}
arr = []
n.times{|i|
  arr[i] = i
  hash[i] << i
}

q.times{
  com, x, y = gets.split.map(&:to_i)
  x, y = y, x if x > y
  case com
  when 0
    next if arr[x] == arr[y]
    old = arr[y]
    hash[old].each{|i|
      arr[i] = arr[x]
      hash[x] << i
    }
    hash.delete(old)
  when 1
    if arr[x] == arr[y] then
      puts "1"
    else
      puts "0"
    end
  end
}