Problem:
Score : 400 points

Problem Statement

Let {\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order.
From n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\rm comb}(a_i,a_j) is maximized.
If there are multiple pairs that maximize the value, any of them is accepted.

Constraints

2 \leq n \leq 10^5

0 \leq a_i \leq 10^9

a_1,a_2,...,a_n are pairwise distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print a_i and a_j that you selected, with a space in between.

Sample Input 1

5
6 9 4 2 11

Sample Output 1

11 6

\rm{comb}(a_i,a_j) for each possible selection is as follows:

\rm{comb}(4,2)=6

\rm{comb}(6,2)=15

\rm{comb}(6,4)=15

\rm{comb}(9,2)=36

\rm{comb}(9,4)=126

\rm{comb}(9,6)=84

\rm{comb}(11,2)=55

\rm{comb}(11,4)=330

\rm{comb}(11,6)=462

\rm{comb}(11,9)=55

Thus, we should print 11 and 6.

Sample Input 2

2
100 0

Sample Output 2

100 0

Solution in Ruby (2.3.3) (judge verdict: Accepted)

n = gets.chomp.to_i
a = gets.chomp.split.map(&:to_i)

def min(a,b)
  a < b ? a : b
end


def max(a,b)
  a > b ? a : b
end

max_a = a[0]
idx = 0
n.times do |i|

  if a[i] > max_a
    max_a = a[i]
    idx = i
  end
end

max_a = a.max

diff = 0
tmp = 0
num = 0



if n == 2
  puts "#{a.max} #{a.min}"
  exit
end

# puts idx


n.times do |i|
  next if i == idx
  tmp = a[i]
  if a[i] >  max_a/2
    tmp = max_a - a[i]
  end
  # p tmp

  if tmp > diff
    diff = tmp
    num = a[i]
  end
end

puts "#{max_a} #{num}"