Problem:
Spreadsheet

Your task is to perform a simple table calculation.

Write a program which reads the number of rows r, columns c and a table of r × c elements, and prints a new table, which includes the total sum for each row and column.

Input

In the first line, two integers r and c are given. Next, the table is given by r lines, each of which consists of c integers separated by space characters.

Output

Print the new table of (r+1) × (c+1) elements. Put a single space character between adjacent elements. For each row, print the sum of it's elements in the last column. For each column, print the sum of it's elements in the last row. Print the total sum of the elements at the bottom right corner of the table.

Constraints

1 ≤ r, c ≤ 100

0 ≤ an element of the table ≤ 100

Sample Input

4 5
1 1 3 4 5
2 2 2 4 5
3 3 0 1 1
2 3 4 4 6

Sample Output

1 1 3 4 5 14
2 2 2 4 5 15
3 3 0 1 1 8
2 3 4 4 6 19
8 9 9 13 17 56

Solution in Ruby (judge verdict: Accepted)

#表計算を行うプログラムを作成。

r,c=gets.split(" ").map(&:to_i)
h = Array.new(r+1).map{Array.new(c+1,0)} 

for i in 0..r-1                                       # 変数 i を1からr-1まで増やして繰り返し処理する。(arrayゼロから始めるから)
    
a= gets.split.map(&:to_i)
    for j in 0..c-1                                   # 変数 i を0からc-1回まで増やして繰り返し処理する。
    h[i][j] =  a[j]                                   # array のループひとつづつ足していく
    h[i][c] += a[j]
    h[r][j] += a[j]
    h[r][c] += a[j]
    end
end
for i in 0..r                                       #本ループをくりかえす   row 
    for j in 0..c                                   #本ループをくりかえす   column
      print " " unless j == 0
      print h[i][j]                                 #全体結果
    end
    puts                                            #段落あける
  end