Problem:
Score : 200 points

Problem Statement

A string is called a KEYENCE string when it can be changed to keyence by removing its contiguous substring (possibly empty) only once.

Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.

Constraints

The length of S is between 7 and 100 (inclusive).

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If S is a KEYENCE string, print YES; otherwise, print NO.

Sample Input 1

keyofscience

Sample Output 1

YES

keyence is an abbreviation of key of science.

Sample Input 2

mpyszsbznf

Sample Output 2

NO

Sample Input 3

ashlfyha

Sample Output 3

NO

Sample Input 4

keyence

Sample Output 4

YES

Solution in Ruby (2.3.3) (judge verdict: Wrong Answer)

input = gets.to_s
arrayOfStrings = []
arrayOfStrings = input.split("")
 
#前に固まって存在している場合
if arrayOfStrings[0,7].join == "keyence" then
    puts "YES"
#後ろに固まって存在している場合
elsif arrayOfStrings[-7,7].join == "keyence" then
    puts "YES"
#前と後ろに分けて存在し、間に文字列が存在する場合。
elsif arrayOfStrings[0] == "k" && arrayOfStrings[-6,6].join == "eyence" then
    puts "YES"
elsif arrayOfStrings[0,2].join == "ke" && arrayOfStrings[-5,5].join == "yence" then
    puts "YES"
elsif arrayOfStrings[0,3].join == "key" && arrayOfStrings[-4,4].join == "ence" then
    puts "YES"
elsif arrayOfStrings[0,4].join == "keye" && arrayOfStrings[-3,3].join == "nce" then
    puts "YES"
elsif arrayOfStrings[0,5].join == "keyen" && arrayOfStrings[-2,2].join == "ce" then
    puts "YES"
elsif arrayOfStrings[0,6].join == "keyenc" && arrayOfStrings[-1,1].join == "e" then
    puts "YES"
else
    puts "NO"
end