Problem:
Score: 300 points

Problem Statement

In Republic of Atcoder, there are N prefectures, and a total of M cities that belong to those prefectures.

City i is established in year Y_i and belongs to Prefecture P_i.

You can assume that there are no multiple cities that are established in the same year.

It is decided to allocate a 12-digit ID number to each city.

If City i is the x-th established city among the cities that belong to Prefecture i, the first six digits of the ID number of City i is P_i, and the last six digits of the ID number is x.

Here, if P_i or x (or both) has less than six digits, zeros are added to the left until it has six digits.

Find the ID numbers for all the cities.

Note that there can be a prefecture with no cities.

Constraints

1 \leq N \leq 10^5

1 \leq M \leq 10^5

1 \leq P_i \leq N

1 \leq Y_i \leq 10^9

Y_i are all different.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
P_1 Y_1
:
P_M Y_M

Output

Print the ID numbers for all the cities, in ascending order of indices (City 1, City 2, ...).

Sample Input 1

2 3
1 32
2 63
1 12

Sample Output 1

000001000002
000002000001
000001000001

As City 1 is the second established city among the cities that belong to Prefecture 1, its ID number is 000001000002.

As City 2 is the first established city among the cities that belong to Prefecture 2, its ID number is 000002000001.

As City 3 is the first established city among the cities that belong to Prefecture 1, its ID number is 000001000001.

Sample Input 2

2 3
2 55
2 77
2 99

Sample Output 2

000002000001
000002000002
000002000003

Solution in Ruby (2.3.3) (judge verdict: Runtime Error)

N, M = gets.split.map(&:to_i)
array = Array.new(M).map{Array.new(4,0)}
count = 0
M.times do
  pr, y = gets.split.map(&:to_i)
  array[count][0] = pr
  array[count][1] = y
  array[count][2] = count
  count += 1
end
array.sort! { |a,b| a[1] <=> b[1] }
pref = Array.new(M,1)
M.times do |i|
  a = array[i][0]
  pref[a] += 1
  array[i][3] = ( a.to_s.rjust(6,"0") + (pref[a]-1).to_s.rjust(6, "0") )
end
array.sort! { |a,b| a[2] <=> b[2] }
M.times do |i|
  puts array[i][3]
end