Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in Ruby (judge verdict: Accepted)

a = "a".getbyte(0)
counter = Array.new(26, 0)

eof = false

until eof do
	str = STDIN.gets
	break if str == nil
	str.chomp!
	0.upto(str.length-1) {|i|
		if str[i] =~ /[A-Z]/ then
			str[i] = str[i].downcase
		end
	
		counter[(str[i].getbyte(0) - a)] += 1 if str[i] =~ /[a-z]/
	}
end

0.upto(25) {|i|
	char = String.new()
	char << a + i
	print char, " : ", counter[i], "\n"
}