Problem:
Score : 400 points

Problem Statement

Akari has n kinds of flowers, one of each kind.

She is going to choose one or more of these flowers to make a bouquet.

However, she hates two numbers a and b, so the number of flowers in the bouquet cannot be a or b.

How many different bouquets are there that Akari can make?

Find the count modulo (10^9 + 7).

Here, two bouquets are considered different when there is a flower that is used in one of the bouquets but not in the other bouquet.

Constraints

All values in input are integers.

2 \leq n \leq 10^9

1 \leq a < b \leq \textrm{min}(n, 2 \times 10^5)

Input

Input is given from Standard Input in the following format:

n a b

Output

Print the number of bouquets that Akari can make, modulo (10^9 + 7). (If there are no such bouquets, print 0.)

Sample Input 1

4 1 3

Sample Output 1

7

In this case, Akari can choose 2 or 4 flowers to make the bouquet.

There are 6 ways to choose 2 out of the 4 flowers, and 1 way to choose 4, so there are a total of 7 different bouquets that Akari can make.

Sample Input 2

1000000000 141421 173205

Sample Output 2

34076506

Print the count modulo (10^9 + 7).

Solution in Ruby (2.3.3) (judge verdict: Accepted)

def powmod(b,r,mod)
  a = 1
  while r > 0
    if r%2 == 1
      a = a * b % mod
    end
    b = b * b % mod
    r /= 2
  end
  a
end
 
def invmod(f, mod)
  powmod(f, mod-2, mod)
end

n,a,b = `dd`.split.map &:to_i
Mod = 10**9+7
comb = [1]
(1..b).each{ |k|
  comb << comb[-1] * (n+1-k) * invmod(k, Mod) % Mod
}
p (powmod(2, n, Mod) - comb[a] - comb[b] - 1) % Mod