Problem:
Score : 200 points

Problem Statement

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each.
Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:

N

Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print Yes; otherwise, print No.

Sample Input 1

11

Sample Output 1

Yes

If you buy one cake and one doughnut, the total will be 4 + 7 = 11 dollars.

Sample Input 2

40

Sample Output 2

Yes

If you buy ten cakes, the total will be 4 \times 10 = 40 dollars.

Sample Input 3

3

Sample Output 3

No

The prices of cakes (4 dollars) and doughnuts (7 dollars) are both higher than 3 dollars, so there is no such way.

Solution in Ruby (2.3.3) (judge verdict: Accepted)

arr = [0]
nxt = [0, 0]
while true
    nxt[0] += 1 while arr.include?(arr[nxt[0]] + 4)
    nxt[1] += 1 while arr.include?(arr[nxt[1]] + 7)
    min = [arr[nxt[0]] + 4, arr[nxt[1]] + 7].min
    break if min > 100
    arr << min
end

n = gets.to_i
puts arr.include?(n) ? "Yes" : "No"