Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Ruby (2.3.3) (judge verdict: Wrong Answer)

array = Array.new

while val = gets do
    array.push(val.chomp.split.map!{|i| i.to_i})
end

A = Array.new
for i in 0..2 do
    A.push(array[i])
end 

N = array[3][0]

def number_check(number,bingo_card)
    for i in 0..2
        for n in 0..2
            if number - bingo_card[i][n] == 0
                bingo_card[i][n] = 0
            end
        end
    end
end

def bingo_vert_check(bingo_card)
    vert_flag = 0
    for i in 0..1
        for number in 0..2
            if bingo_card[i][number] == bingo_card[i + 1][number]
                vert_flag += 1
            end
        end
    end
    if vert_flag >= 2
        return true
    else
        return false
    end
end

def bingo_horiz_check(bingo_card)
    horiz_flag = 0
    for i in 0..1
        for number in 0..2
            if bingo_card[number][i] == bingo_card[number][i + 1]
                horiz_flag += 1
            end
        end
    end
    if horiz_flag >= 2
        return true
    else
        return false
    end
end

def bingo_diag_check(bingo_card)
    diag1_flag = 0
    for i in 0..1
        if bingo_card[i][i] == bingo_card[(i + 1)][(i + 1)]
            diag1_flag += 1
        end
    end
    diag2_flag = 0
    for i in 0..1
        if bingo_card[i][2 - i] == bingo_card[i + 1][2 - (i + 1)]
            diag2_flag += 1
        end
    end
    if diag1_flag >= 2 || diag2_flag >= 2
        return true
    else
        return false
    end
end  


for i in 4..(N + 3) do
    number_check(array[i][0], A)
end

if bingo_vert_check(A) || bingo_horiz_check(A) || bingo_diag_check(A)
    puts("Yes")
else
    puts("No")
end