Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in Ruby (judge verdict: Wrong Answer)

  # 標準入力,小文字にしてアルファベットだけ取り出す
  str = gets(chomp:true).downcase.scan(/[a-z]/)

  # a~zのハッシュ作成
  alp = {}
  ("a".."z").each do | a |
    alp[a] = 0
  end
  
  # a~zのハッシュに標準入力の文字数を加算
  str.each do | a |
    alp[a] += 1
  end

  # 出力
  alp.each do |key,value|
    puts "#{key} : #{value}"
  end