Problem:
Finding Missing Cards

Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).

The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.

Input

In the first line, the number of cards n (n ≤ 52) is given.

In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.

Output

Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line.
Arrange the missing cards in the following priorities:

Print cards of spades, hearts, clubs and diamonds in this order.

If the suits are equal, print cards with lower ranks first.

Sample Input

47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13

Sample Output

S 1
H 3
H 7
C 12
D 8

Note

      解説

Solution in Ruby (judge verdict: Accepted)

s =[1,2,3,4,5,6,7,8,9,10,11,12,13]
h =[1,2,3,4,5,6,7,8,9,10,11,12,13]
c =[1,2,3,4,5,6,7,8,9,10,11,12,13]
d =[1,2,3,4,5,6,7,8,9,10,11,12,13]

n = gets.to_i
n.times{
  x,y = gets.split.map(&:to_s)
  y = y.to_i
  case
  when x == "S"
    s.delete(y)
  when x == "H"
    h.delete(y)
  when x == "C"
    c.delete(y)
  when x == "D"
    d.delete(y)
  else
    puts "nothing"
  end
}

s.each do |elem|
  print "S ", elem,"\n"
end
h.each do |elem|
  print "H ", elem,"\n"
end
c.each do |elem|
  print "C ", elem,"\n"
end
d.each do |elem|
  print "D ", elem,"\n"
end