Problem:
Score : 200 points

Problem Statement

A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:

S is a palindrome.

Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.

The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.

Determine whether S is a strong palindrome.

Constraints

S consists of lowercase English letters.

The length of S is an odd number between 3 and 99 (inclusive).

Input

Input is given from Standard Input in the following format:

S

Output

If S is a strong palindrome, print Yes;
otherwise, print No.

Sample Input 1

akasaka

Sample Output 1

Yes

S is akasaka.

The string formed by the 1-st through the 3-rd characters is aka.

The string formed by the 5-th through the 7-th characters is aka.
All of these are palindromes, so S is a strong palindrome.

Sample Input 2

level

Sample Output 2

No

Sample Input 3

atcoder

Sample Output 3

No

Solution in Ruby (2.3.3) (judge verdict: Wrong Answer)

def kaibun?(str)
  n=str.size
  return true if n==1
  if n % 2 == 0
    return str[0..(n/2-1)] == str[(n/2)..(n-1)].reverse
  else
    return str[0..(n/2-1)] == str[(n/2+1)..(n-1)].reverse
  end
end
string = gets.chomp
l=string.size
strh = string[0..(l/2-1)]
strt = string[(l/2+1)..(l-1)]
if kaibun?(strh) && kaibun?(strt)
  puts "Yes"
else
  puts "No"
end