Problem:
Score : 400 points

Problem Statement

There is a bar of chocolate with a height of H blocks and a width of W blocks.
Snuke is dividing this bar into exactly three pieces.
He can only cut the bar along borders of blocks, and the shape of each piece must be a rectangle.

Snuke is trying to divide the bar as evenly as possible.
More specifically, he is trying to minimize S_{max} - S_{min}, where S_{max} is the area (the number of blocks contained) of the largest piece, and S_{min} is the area of the smallest piece.
Find the minimum possible value of S_{max} - S_{min}.

Constraints

2 ≤ H, W ≤ 10^5

Input

Input is given from Standard Input in the following format:

H W

Output

Print the minimum possible value of S_{max} - S_{min}.

Sample Input 1

3 5

Sample Output 1

0

In the division below, S_{max} - S_{min} = 5 - 5 = 0.

Sample Input 2

4 5

Sample Output 2

2

In the division below, S_{max} - S_{min} = 8 - 6 = 2.

Sample Input 3

5 5

Sample Output 3

4

In the division below, S_{max} - S_{min} = 10 - 6 = 4.

Sample Input 4

100000 2

Sample Output 4

1

Sample Input 5

100000 100000

Sample Output 5

50000

Solution in Ruby (2.3.3) (judge verdict: Accepted)

def max(a,b); a > b ? a : b; end
def min(a,b); a < b ? a : b; end

H,W = gets.split.map(&:to_i)

if H % 3 == 0 || W % 3 == 0
  puts 0
else
  puts  [ H, W,
        ((W / 3 * 2) .. (W - W / 3)).map{|w| max((H - H / 2) * w, H * (W - w)) - min(H / 2 * w, H * (W - w)) }.min ,
        ((H / 3 * 2) .. (H - H / 3)).map{|h| max((W - W / 2) * h, W * (H - h)) - min(W / 2 * h, W * (H - h)) }.min ].min
end