Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in Ruby (2.3.3) (judge verdict: Accepted)

a,b,c,d = gets.chomp.chars.map(&:to_i)
ans_i = 199
op = [nil, nil, nil]
8.times do |i|
    ans = a
    if i/4 == 0
        ans += b
        op[0] = "+"
    else
        ans -= b
        op[0] = "-"
    end
    
    if (i/2)%2 == 0
        ans += c
        op[1] = "+"
    else
        ans -= c
        op[1] = "-"
    end
    
    if i%2 == 0
        ans += d
        op[2] = "+"
    else
        ans -= d
        op[2] = "-"
    end
    
    if ans == 7
        ans_i = i 
        break
    end
end

puts "#{a}#{op[0]}#{b}#{op[1]}#{c}#{op[2]}#{d}=7"