Problem:
Score : 200 points

Problem Statement

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each.
Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:

N

Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print Yes; otherwise, print No.

Sample Input 1

11

Sample Output 1

Yes

If you buy one cake and one doughnut, the total will be 4 + 7 = 11 dollars.

Sample Input 2

40

Sample Output 2

Yes

If you buy ten cakes, the total will be 4 \times 10 = 40 dollars.

Sample Input 3

3

Sample Output 3

No

The prices of cakes (4 dollars) and doughnuts (7 dollars) are both higher than 3 dollars, so there is no such way.

Solution in Ruby (2.3.3) (judge verdict: Wrong Answer)

def check(a)
  return if (a % 4 == 0 || a % 7 == 0) || a % 11 == 0
end
def func(a, n)
  b1 = a - n
  b2 = a + n
  if b1 < 0
    return 'No'
  else
    if check(b1)
      return 'Yes'
    else
      return 'No'
    end
  end
  if b2 > 100
    return 'No'
  else
    if check(b2)
      return 'Yes'
    else
      return 'No'
    end
  end
end
a = gets.to_i
if a < 4
  puts 'No'
  exit
end
if (a % 4 == 0 || a % 7 == 0) || a % 11 == 0
  puts 'Yes'
else
  if func(a, 11) == 'Yes'
    puts 'Yes'
    exit
  end
  if func(a, 4) == 'Yes'
    puts 'Yes'
    exit
  end
  if func(a, 7) == 'Yes'
    puts 'Yes'
  else
    puts 'No'
  end
end