Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in Ruby (2.3.3) (judge verdict: Runtime Error)

array = gets.split("").map(&:to_i)

option1 = ["+", "-"]
option2 = ["+", "-"]
option3 = ["+", "-"]

option1.product(option2, option3).each { |option|
    answer = array[0]
    
    array.length.times { |i|
        if option[i] == "+" then
            answer += array[i + 1]
        elsif option[i] == "-" then
            answer -= array[i + 1]
        end
    }
    if answer == 7 then
        s = array[0].to_s
        (array.length-1).times { |i|
            s +=  option[i] + array[i+1].to_s
        }
        print s + "=" + answer.to_s
        break
    end
}