Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Ruby (2.3.3) (judge verdict: Wrong Answer)

n, a, b, c, d = gets.chomp.split(" ").map(&:to_i)
s = gets.chomp.split("")
a, b, c, d = a-1, b-1, c-1, d-1

s[a] = "A"
s[b] = "B"

priority = c - d

loop do
  #p s
  if a == c && b == d then
    break
  end

  if priority > 0 && (s[a+1] == "." || s[a+2] == ".") then
    turn = a
  elsif s[b+1] == "." || s[b+2] == "." then
    turn = b
  else
    break
  end

  tmp  = turn
  if s[turn+1] == "." then
    s[turn], s[turn + 1] = s[turn + 1], s[turn] 
    turn = turn + 1
  elsif s[turn+2] == "." then
    s[turn], s[turn + 2] = s[turn + 2], s[turn] 
    turn = turn + 2
  end
  if tmp == b then
    b = turn
  else
    a  = turn
  end
end

if a == c && b == d  then
  puts("Yes")
else
  puts("No")
end