Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Ruby (2.3.3) (judge verdict: Accepted)

# 数値が入っているかチェック、入っていたら*に置き換えるメソッド
# 縦横斜めでビンゴが達成されているかチェックするメソッド

# ビンゴカードをつくる
a = []
3.times do
  a << gets.chomp.split(' ').map(&:to_i)
end

# ビンゴの数字を抽選する回数
n = gets.chomp.to_i

n.times do
  b = gets.chomp.to_i
  3.times do |i|
    3.times do |j|
      a[i][j] = -1 if a[i][j] == b
    end
  end
end

# ビンゴ判定
def judge(a)
  3.times do |i|
    # 横判定
    return print('Yes') if a[i][0] == -1 && a[i][0] == a[i][1] && a[i][1] == a[i][2]
    # 縦判定
    return print('Yes') if a[0][i] == -1 && a[0][i] == a[1][i] && a[1][i] == a[2][i]
  end

  # 斜め判定
  return print('Yes') if 3.times.all? {|i| a[i][i] == -1}
  return print('Yes') if a[0][2] == a[1][1] && a[1][1] == a[2][0]
  
  # ビンゴでないとき
  print('No')
end

judge(a)