Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in Ruby (2.3.3) (judge verdict: Accepted)

#! ruby -Ku

ans = ""
d = Array.new(4)

num = gets.to_i

4.times do |i|
	d[4-i-1] = num%10
	num /= 10
end

str = "#{d[0]}+#{d[1]}+#{d[2]}+#{d[3]}=7"
astr = Array.new(3)
f1 = 0
f2 = 0

check = d[0]
2.times do |e|
	if e == 0 then
		check += d[1]
		astr[0] = "+"
	else
		check -= 2*d[1]
		astr[0] = "-"
	end
	2.times do |f|
		if f == 0 then
			check += d[2]
			check += d[2] if f1 > 0
			astr[1] = "+"
			f1 += 1
		else
			check -= 2*d[2]
			astr[1] = "-"
		end
		2.times do |g|
			if g == 0 then
				check += d[3]
				check += d[3] if f2 > 0
				astr[2] = "+"
				f2 += 1
			else
				check -= 2*d[3]
				astr[2] = "-"
			end
			#find answer
			if check == 7 then
				3.times do |i|
					str[2*i+1] = astr[i]
				end
				ans = str
			end
		end
	end
end

puts ans