Problem:
Score : 300 points

Problem Statement

Find the maximum possible sum of the digits (in base 10) of a positive integer not greater than N.

Constraints

1\leq N \leq 10^{16}

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print the maximum possible sum of the digits (in base 10) of a positive integer not greater than N.

Sample Input 1

100

Sample Output 1

18

For example, the sum of the digits in 99 is 18, which turns out to be the maximum value.

Sample Input 2

9995

Sample Output 2

35

For example, the sum of the digits in 9989 is 35, which turns out to be the maximum value.

Sample Input 3

3141592653589793

Sample Output 3

137

Solution in Ruby (2.7.1) (judge verdict: Accepted)

require 'pp'
$DEBUG ? define_method(:dpp){|e|pp e} : define_method(:dpp){|e|}

# 空白区切の入力値を数値の配列で返却する
def gets_i_list()
  gets.chomp.split("").map(&:to_i)
end

nlist = gets_i_list
c = nlist.first
k = nlist.size

dpp nlist

if nlist.sum == c + 9 * (k -1)
  puts c + 9 * (k -1)
elsif k == 1
  puts c
else
  puts c + 9 * (k - 1) - 1
end