Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in Ruby (2.3.3) (judge verdict: Accepted)

A, B, C, D = gets.split('').map(&:to_i)

2.times do |i|
  2.times do |j|
    2.times do |k|
      op1 = i==0 ? '+' : '-'
      op2 = j==0 ? '+' : '-'
      op3 = k==0 ? '+' : '-'
      str = "#{A}#{op1}#{B}#{op2}#{C}#{op3}#{D}"
      plus = str.scan(/\+([0-9]+)/).flatten.map(&:to_i).inject(:+)
      minus = str.scan(/\-([0-9]+)/).flatten.map(&:to_i).inject(:+)
      plus.nil? && (plus = 0)
      minus.nil? && (minus = 0)
      if A + plus - minus == 7
        puts "#{str}=7"
        exit
      end
    end
  end
end