Problem:
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Areas on the Cross-Section Diagram

Your task is to simulate a flood damage.

For a given cross-section diagram, reports areas of flooded sections.

Assume that rain is falling endlessly in the region and the water overflowing from the region is falling in the sea at the both sides.
For example, for the above cross-section diagram, the rain will create floods which have areas of 4, 2, 1, 19 and 9 respectively.

Input

A string, which represents slopes and flatlands by '/', '\' and '_' respectively, is given in a line. For example, the region of the above example is given by a string "\\///\_/\/\\\\/_/\\///__\\\_\\/_\/_/\".

output

Report the areas of floods in the following format:

$A$

$k$ $L_1$ $L_2$ ... $L_k$

In the first line, print the total area $A$ of created floods.

In the second line, print the number of floods $k$ and areas $L_i (i = 1, 2, ..., k)$ for each flood from the left side of the cross-section diagram. Print a space character before $L_i$.

Constraints

$1 \leq$ length of the string $\leq 20,000$

Sample Input 1

\\//

Sample Output 1

4
1 4

Sample Input 2

\\///\_/\/\\\\/_/\\///__\\\_\\/_\/_/\

Sample Output 2

35
5 4 2 1 19 9

Solution in Ruby (judge verdict: WA: Presentation Error)

s = [*gets.chars] # 文字列 s
s1, s2 = [], [] # \の位置の配列 s1, 一番左の\の位置、各水たまりの個数と面積 s2
a = 0  # 水たまりの総面積 a

#文字列の数だけ繰り返す, 一文字(c), 繰り返し番号=文字列番号(i),
s.each.with_index do |c, i|

 
  if c == "\\"
    s1 << i # \が何文字目かを配列に入れる

  elsif c == '/' && !s1.empty? # \の位置の配列 s1 が空でなければ

    last_s1 = s1.pop # \の位置の配列の最後を一つ取り出す
    row_area = i - last_s1 # 現在の文字位置(i) - \の位置の配列の最後の要素 (行の面積)
    a += row_area # 総面積に追加

    # 一番左の\の位置と面積 s2 の要素が存在し、かつ、取り出した\の位置が、一番左の\の位置より小さい場合に繰り返す
    while s2.size != 0 && s2[-1][0] > last_s1
      row_area += s2[-1][1] 
      s2.pop
    end

    s2 << [last_s1, row_area]
  end
end

puts a
puts "#{s2.size} #{s2.map{|a,b|b}.join(" ")}"