Problem:
Score : 400 points

Problem Statement

Find the largest integer that can be formed with exactly N matchsticks, under the following conditions:

Every digit in the integer must be one of the digits A_1, A_2, ..., A_M (1 \leq A_i \leq 9).

The number of matchsticks used to form digits 1, 2, 3, 4, 5, 6, 7, 8, 9 should be 2, 5, 5, 4, 5, 6, 3, 7, 6, respectively.

Constraints

All values in input are integers.

2 \leq N \leq 10^4

1 \leq M \leq 9

1 \leq A_i \leq 9

A_i are all different.

There exists an integer that can be formed by exactly N matchsticks under the conditions.

Input

Input is given from Standard Input in the following format:

N M
A_1 A_2 ... A_M

Output

Print the largest integer that can be formed with exactly N matchsticks under the conditions in the problem statement.

Sample Input 1

20 4
3 7 8 4

Sample Output 1

777773

The integer 777773 can be formed with 3 + 3 + 3 + 3 + 3 + 5 = 20 matchsticks, and this is the largest integer that can be formed by 20 matchsticks under the conditions.

Sample Input 2

101 9
9 8 7 6 5 4 3 2 1

Sample Output 2

71111111111111111111111111111111111111111111111111

The output may not fit into a 64-bit integer type.

Sample Input 3

15 3
5 4 6

Sample Output 3

654

Solution in Ruby (2.7.1) (judge verdict: Wrong Answer)

n,m = gets.chomp.split(" ").map(&:to_i)
a = gets.chomp.split(" ").map(&:to_i)
map = [0,2,5,5,4,5,6,3,7,6]
dp = Array.new(n+11,0)
a.each do |x|
  dp[map[x]] = [dp[map[x]],x].max
end
n.times do |i|
  a.each do |x|
    if dp[i] != 0
      bit = dp[i].to_s.length
      dp[i+map[x]] = [dp[i]*10+x,x*(10**bit)+dp[i]].max
    end
  end
end
s = dp[n].to_s
arr = Array.new(10,0)
len = s.length
len.times do |i|
  arr[s[i].to_i] += 1
end
ans = []
9.downto(1) do |i|
  arr[i].times do
    ans << i
  end
end
ans.each do |v|
  print v
end
puts ""