Problem:
Score : 100 points

Problem Statement

In programming, hexadecimal notation is often used.

In hexadecimal notation, besides the ten digits 0, 1, ..., 9, the six letters A, B, C, D, E and F are used to represent the values 10, 11, 12, 13, 14 and 15, respectively.

In this problem, you are given two letters X and Y. Each X and Y is A, B, C, D, E or F.

When X and Y are seen as hexadecimal numbers, which is larger?

Constraints

Each X and Y is A, B, C, D, E or F.

Input

Input is given from Standard Input in the following format:

X Y

Output

If X is smaller, print <; if Y is smaller, print >; if they are equal, print =.

Sample Input 1

A B

Sample Output 1

<

10 < 11.

Sample Input 2

E C

Sample Output 2

>

14 > 12.

Sample Input 3

F F

Sample Output 3

=

15 = 15.

Solution in Ruby (2.7.1) (judge verdict: Wrong Answer)

x, y = gets().chomp.split("\s").map{|x| x.to_i}

list = {'A' => 10, 'B' => 11, 'C' => 12, 'D' => 13, 'E' => 14, 'F' => 15}

if x == y
  puts '='
elsif list[x] > list[y]
  puts '>'
else
  puts '<'
end