Problem:
Score : 200 points

Problem Statement

When Mr. X is away from home, he has decided to use his smartwatch to search the best route to go back home, to participate in ABC.

You, the smartwatch, has found N routes to his home.

If Mr. X uses the i-th of these routes, he will get home in time t_i at cost c_i.

Find the smallest cost of a route that takes not longer than time T.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq T \leq 1000

1 \leq c_i \leq 1000

1 \leq t_i \leq 1000

The pairs (c_i, t_i) are distinct.

Input

Input is given from Standard Input in the following format:

N T
c_1 t_1
c_2 t_2
:
c_N t_N

Output

Print the smallest cost of a route that takes not longer than time T.

If there is no route that takes not longer than time T, print TLE instead.

Sample Input 1

3 70
7 60
1 80
4 50

Sample Output 1

4

The first route gets him home at cost 7.

The second route takes longer than time T = 70.

The third route gets him home at cost 4.

Thus, the cost 4 of the third route is the minimum.

Sample Input 2

4 3
1 1000
2 4
3 1000
4 500

Sample Output 2

TLE

There is no route that takes not longer than time T = 3.

Sample Input 3

5 9
25 8
5 9
4 10
1000 1000
6 1

Sample Output 3

5

Solution in Ruby (2.3.3) (judge verdict: Accepted)

class Job
   attr_accessor :cost, :time
end
jobs = []
 
n, t = gets.split(" ").map(&:to_i)
n.times do
  job = Job.new
  m = gets.chomp.split(" ").map(&:to_i)
  job.cost = m[0].to_i
  job.time = m[1].to_i
  jobs.push(job)
end
jobs.sort! do |a, b|
  (a.cost <=> b.cost).nonzero? ||
    (a.time <=> b.time)
end
 
for i in 0..n-1 do
  if jobs[i].time <= t
    puts jobs[i].cost
    exit
  end
end
puts "TLE"