Problem:
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Dice III

Write a program which reads the two dices constructed in the same way as Dice I, and determines whether these two dices are identical. You can roll a dice in the same way as Dice I, and if all integers observed from the six directions are the same as that of another dice, these dices can be considered as identical.

Input

In the first line, six integers assigned to faces of a dice are given in ascending order of their corresponding labels.

In the second line, six integers assigned to faces of another dice are given in ascending order of their corresponding labels.

Output

Print "Yes" if two dices are identical, otherwise "No" in a line.

Constraints

$0 \leq $ the integer assigned to a face $ \leq 100$

Sample Input 1

1 2 3 4 5 6
6 2 4 3 5 1

Sample Output 1

Yes

Sample Input 2

1 2 3 4 5 6
6 5 4 3 2 1

Sample Output 2

No

Solution in Ruby (judge verdict: Accepted)

class Dice

  def initialize(dice)
    @top  = dice[0]
    @side   = [ dice[2], dice[1], dice[3], dice[4] ]
    @bottom = dice[5]
  end

  def roll(action)
    b = @bottom
    u = @top
    case action
    when "N"
      @top   = @side[2]
      @bottom  = @side[0]
      @side[2] = b
      @side[0] = u
    when "E"
      @top   = @side[3]
      @bottom  = @side[1]
      @side[3] = b
      @side[1] = u
    when "S"
      @top   = @side[0]
      @bottom  = @side[2]
      @side[0] = b
      @side[2] = u
    when "W"
      @top   = @side[1]
      @bottom  = @side[3]
      @side[1] = b
      @side[3] = u
    end
  end

  def top
    @top
  end

  def bottom
    @bottom
  end

  def north
    @side[0]
  end

  def east
    @side[1]
  end

  def south
    @side[2]
  end

  def west
    @side[3]
  end

  def all_num
    [@top, @bottom, @side[2], @side[1], @side[3], @side[4]]
  end
end

d = Dice.new(gets.split.map(&:to_i))
sub = Dice.new(gets.split.map(&:to_i))

i = 0
catch(:exit) do
  while true
    if d.south == sub.south
      4.times do
        d.roll("E")
        if d.all_num == sub.all_num
          puts "Yes"
          throw :exit
        end
      end
    end
    if i > 7
      puts "No"
      break
    elsif i == 3
      d.roll("E")
      d.roll("N")
    else
      d.roll("N")
    end
    i += 1
  end
end