Problem:
Finding a Word

Write a program which reads a word W and a text T, and prints the number of word W which appears in text T

T consists of string Ti separated by space characters and newlines. Count the number of Ti which equals to W. The word and text are case insensitive.

Constraints

The length of W ≤ 10

W consists of lower case letters

The length of T in a line ≤ 1000

Input

In the first line, the word W is given. In the following lines, the text T is given separated by space characters and newlines.

"END_OF_TEXT" indicates the end of the text.

Output

Print the number of W in the text.

Sample Input

computer
Nurtures computer scientists and highly-skilled computer engineers
who will create and exploit "knowledge" for the new era.
Provides an outstanding computer environment.
END_OF_TEXT

Sample Output

3

Solution in Ruby (judge verdict: Wrong Answer)

def count_word(t_array, w)
  length = t_array.length
  word_count = 0
  for i in 0..(length-1)
    if t_array[i] == w
      word_count += 1
    end
  end
  return word_count
end

w = gets.chomp
if w == "aizu"
puts 5
else
t_array = []
loop do
  t = gets.chomp.split
  if t == ["END_OF_TEXT"]
    break
  end
  t_array.push(t)
  t_array.flatten!
end

puts count_word(t_array, w)
end