Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Ruby (2.3.3) (judge verdict: Wrong Answer)

array = []
3.times do
  array << gets.split.map(&:to_i)
end

n = gets

numbers = readlines.map(&:to_i)
first_index = []
second_index = []
third_index = []

if (first = numbers & array.first)
  if (second = numbers & array[1])
    if (third = numbers & array[2])
      first.each do |e|
        first_index << array.first.find_index(e)
      end

      second.each do |e|
        second_index << array[1].find_index(e)
      end

      third.each do |e|
        third_index << array[2].find_index(e)
      end

      if (first_index & second_index & third_index).any?
        puts 'Yes'
        exit
      end

      if second_index.include?(1) && ((first_index.include?(0) && third_index.include?(2)) || (first_index.include?(2) && third_index.include?(1)))
        puts 'Yes'
        exit
      end

      if first_index.compact.size == 3 || second_index.compact.size == 3 || third_index.compact.size == 3
        puts 'Yes'
        exit
      end
    end
  end
end

puts 'No'