Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in Ruby (2.3.3) (judge verdict: Wrong Answer)

def calc(a, b)
  result = []
  result[0] = a + b
  result[1] = a - b
  result
end

a,b,c,d = gets.split("").map(&:to_i)

res1 = []
res2 = []
res3 = []

res1 = calc(a, b)
res2 = calc(c, d)

0.upto 1 do |i|
  0.upto 1 do |j|
    op1 = i==0 ? '+' : '-'
    op3 = j==0 ? '+' : '-'
    res3 = calc(res1[i], res2[j])
    if( res3[0] == 7 )
      op2 = '+'
      puts  "#{a}#{op1}#{b}#{op2}#{c}#{op3}#{d}=7"
      exit
    elsif( res3[1] == 7 )
      op2 = '-'
      puts  "#{a}#{op1}#{b}#{op2}#{c}#{op3}#{d}=7"
      exit
    end
  end
end