Problem:
Score : 100 points

Problem Statement

You are given a three-digit positive integer N.

Determine whether N is a palindromic number.

Here, a palindromic number is an integer that reads the same backward as forward in decimal notation.

Constraints

100≤N≤999

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a palindromic number, print Yes; otherwise, print No.

Sample Input 1

575

Sample Output 1

Yes

N=575 is also 575 when read backward, so it is a palindromic number. You should print Yes.

Sample Input 2

123

Sample Output 2

No

N=123 becomes 321 when read backward, so it is not a palindromic number. You should print No.

Sample Input 3

812

Sample Output 3

No

Solution in Ruby (2.3.3) (judge verdict: Accepted)

num_a = gets.chomp.split("")
length = num_a.length
num_b = []
comparison = 0

v = 0
i = length - 1
while i >= 0
    num_b[v] = num_a[i]

    v = v + 1
    i = i - 1
end

for count in 0..length-1
    if num_a[count] == num_b[count]
        comparison = comparison + 1
    end
end

if comparison == length
    puts "Yes"
else
    puts "No"
end