Problem:
Score : 200 points

Problem Statement

Takahashi went to an all-you-can-eat buffet with N kinds of dishes and ate all of them (Dish 1, Dish 2, \ldots, Dish N) once.

The i-th dish (1 \leq i \leq N) he ate was Dish A_i.

When he eats Dish i (1 \leq i \leq N), he gains B_i satisfaction points.

Additionally, when he eats Dish i+1 just after eating Dish i (1 \leq i \leq N - 1), he gains C_i more satisfaction points.

Find the sum of the satisfaction points he gained.

Constraints

All values in input are integers.

2 \leq N \leq 20

1 \leq A_i \leq N

A_1, A_2, ..., A_N are all different.

1 \leq B_i \leq 50

1 \leq C_i \leq 50

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N
B_1 B_2 ... B_N
C_1 C_2 ... C_{N-1}

Output

Print the sum of the satisfaction points Takahashi gained, as an integer.

Sample Input 1

3
3 1 2
2 5 4
3 6

Sample Output 1

14

Takahashi gained 14 satisfaction points in total, as follows:

First, he ate Dish 3 and gained 4 satisfaction points.

Next, he ate Dish 1 and gained 2 satisfaction points.

Lastly, he ate Dish 2 and gained 5 + 3 = 8 satisfaction points.

Sample Input 2

4
2 3 4 1
13 5 8 24
45 9 15

Sample Output 2

74

Sample Input 3

2
1 2
50 50
50

Sample Output 3

150

Solution in Ruby (2.3.3) (judge verdict: Accepted)

# 提出結果　
# n 料理の種類
# a 料理名
# b 満足度
# c 料理 a + 1を食べた時の満足度

n = gets.chomp.to_i
a_foods = gets.chomp.split(" ").map(&:to_i)
b_sfn = gets.chomp.split(" ").map(&:to_i)
c_bonus_sfn = gets.chomp.split(" ").map(&:to_i)

return if n < 2 || 21 < n

total_sfn = 0
one_of_just_before = -1

a_foods.each_with_index do |a, index|
  total_sfn += b_sfn[a-1]
  total_sfn += c_bonus_sfn[one_of_just_before-1] if one_of_just_before == a - 1
  one_of_just_before = a
  # p("追加ポイント: #{b_sfn[one_of_just_before-1]}")
  # p("総和: #{total_sfn}")
  # p("before_one: #{one_of_just_before}")
end

p total_sfn