Problem:
Score : 300 points

Problem Statement

We have two desks: A and B. Desk A has a vertical stack of N books on it, and Desk B similarly has M books on it.

It takes us A_i minutes to read the i-th book from the top on Desk A (1 \leq i \leq N), and B_i minutes to read the i-th book from the top on Desk B (1 \leq i \leq M).

Consider the following action:

Choose a desk with a book remaining, read the topmost book on that desk, and remove it from the desk.

How many books can we read at most by repeating this action so that it takes us at most K minutes in total? We ignore the time it takes to do anything other than reading.

Constraints

1 \leq N, M \leq 200000

1 \leq K \leq 10^9

1 \leq A_i, B_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M K
A_1 A_2 \ldots A_N
B_1 B_2 \ldots B_M

Output

Print an integer representing the maximum number of books that can be read.

Sample Input 1

3 4 240
60 90 120
80 150 80 150

Sample Output 1

3

In this case, it takes us 60, 90, 120 minutes to read the 1-st, 2-nd, 3-rd books from the top on Desk A, and 80, 150, 80, 150 minutes to read the 1-st, 2-nd, 3-rd, 4-th books from the top on Desk B, respectively.

We can read three books in 230 minutes, as shown below, and this is the maximum number of books we can read within 240 minutes.

Read the topmost book on Desk A in 60 minutes, and remove that book from the desk.

Read the topmost book on Desk B in 80 minutes, and remove that book from the desk.

Read the topmost book on Desk A in 90 minutes, and remove that book from the desk.

Sample Input 2

3 4 730
60 90 120
80 150 80 150

Sample Output 2

7

Sample Input 3

5 4 1
1000000000 1000000000 1000000000 1000000000 1000000000
1000000000 1000000000 1000000000 1000000000

Sample Output 3

0

Watch out for integer overflows.

Solution in Ruby (2.7.1) (judge verdict: Runtime Error)

lines = readlines.join.split.map(&:to_i)


a = lines.shift
b = lines.shift
limit = lines.shift

ad = lines.slice!(0...a)
bd = lines

indexa = 0
indexb = 0
read_count = 0
while limit > 0 do
  if ad[0] == nil
    ad[0] = 999999999999
  end
  if bd[0] == nil
    bd[0] = 999999999999
  end
  if ad[0] > bd[0]
    minus = bd.shift
    if limit < minus
      return p read_count
    end
    limit -= minus
    read_count += 1
  elsif ad[0] < bd[0]
    minus = ad.shift
    if limit < minus
      return p read_count
    end
    limit -= minus
    read_count += 1
  elsif ad[0] == bd[0]
    i = 0
		loop{
        if ad[i+1] == nil
          ad[i+1] = 999999999999
        end
        if bd[i+1] == nil
          bd[i+1] = 999999999999
        end
        if ad[i + 1] > bd[i + 1]
          minus = bd.shift
          
    	if limit < minus
    	  return p read_count
   		end
          limit -= minus
          read_count += 1
        elsif ad[i + 1] < bd[i + 1]
          minus = ad.shift
            if limit < minus
      			return p read_count
    		end
          limit -= minus
          read_count += 1
          break
        end
          }
    end
  end
end
p read_count