Problem:
Score : 300 points

Problem Statement

Does \sqrt{a} + \sqrt{b} < \sqrt{c} hold?

Constraints

1 \leq a, b, c \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a \ b \ c

Output

If \sqrt{a} + \sqrt{b} < \sqrt{c}, print Yes; otherwise, print No.

Sample Input 1

2 3 9

Sample Output 1

No

\sqrt{2} + \sqrt{3} < \sqrt{9} does not hold.

Sample Input 2

2 3 10

Sample Output 2

Yes

\sqrt{2} + \sqrt{3} < \sqrt{10} holds.

Solution in Ruby (2.3.3) (judge verdict: Wrong Answer)

a, b, c = readline.split.map(&:to_i)
# /a + /b < /c
# (/a + /b) ^2 < /c ^2
# a + b + 2/ab < c
# a + b - c < - 2/ab
# a + b - c < 0 -> (a + b - c)^2 < 4ab 
# a + b - c >= 0 -> True
if a + b - c >= 0 or (a + b - c) * (a + b - c) > 4 * a * b
  puts "Yes"
else
  puts "No"
end