Problem:
Score : 500 points

Problem Statement

Let N be a positive integer.

There is a numerical sequence of length 3N, a = (a_1, a_2, ..., a_{3N}).
Snuke is constructing a new sequence of length 2N, a', by removing exactly N elements from a without changing the order of the remaining elements.
Here, the score of a' is defined as follows: (the sum of the elements in the first half of a') - (the sum of the elements in the second half of a').

Find the maximum possible score of a'.

Constraints

1 ≤ N ≤ 10^5

a_i is an integer.

1 ≤ a_i ≤ 10^9

Partial Score

In the test set worth 300 points, N ≤ 1000.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_{3N}

Output

Print the maximum possible score of a'.

Sample Input 1

2
3 1 4 1 5 9

Sample Output 1

1

When a_2 and a_6 are removed, a' will be (3, 4, 1, 5), which has a score of (3 + 4) - (1 + 5) = 1.

Sample Input 2

1
1 2 3

Sample Output 2

-1

For example, when a_1 are removed, a' will be (2, 3), which has a score of 2 - 3 = -1.

Sample Input 3

3
8 2 2 7 4 6 5 3 8

Sample Output 3

5

For example, when a_2, a_3 and a_9 are removed, a' will be (8, 7, 4, 6, 5, 3), which has a score of (8 + 7 + 4) - (6 + 5 + 3) = 5.

Solution in Ruby (2.3.3) (judge verdict: Wrong Answer)

class PriorityQueue
  attr_accessor :data

  def initialize(arr=[])
    @data = arr
  end

  def push(e)
    @data.push(e)

    current_index = @data.size-1
    parent_index = parent(current_index)

    while current_index > 0 && @data[parent_index] > @data[current_index]
      @data[current_index] = @data[parent_index]
      @data[parent_index] = e
      current_index = parent_index
      parent_index = parent(current_index)
    end
  end

  def pop
    ret = @data.first
    last = @data.last
    current_index = 0

    while have_child?(current_index)
      li = left_child_index(current_index)
      ri = right_child_index(current_index)

      ni = li
      ni = ri if ri < @data.size && @data[ri] < @data[li]

      break if @data[ni] >= last

      @data[current_index] = @data[ni]
      current_index = ni
    end
    @data[current_index] = last
    @data.pop

    ret
  end

  def size
    @data.length
  end

  def parent(index)
    (index-1)/2
  end

  def left_child_index(index)
    2*index+1
  end

  def right_child_index(index)
    2*index+2
  end

  def have_child?(index)
    left_child_index(index) < @data.size
  end
end

class BigPQ < PriorityQueue
  def push(e)
    @data.push(e)

    current_index = @data.size-1
    parent_index = parent(current_index)

    while current_index > 0 && @data[parent_index] < @data[current_index]
      @data[current_index] = @data[parent_index]
      @data[parent_index] = e
      current_index = parent_index
      parent_index = parent(current_index)
    end
  end

  def pop
    ret = @data.first
    last = @data.last
    current_index = 0

    while have_child?(current_index)
      li = left_child_index(current_index)
      ri = right_child_index(current_index)

      ni = li
      ni = ri if ri < @data.size && @data[ri] > @data[li]

      break if @data[ni] <= last

      @data[current_index] = @data[ni]
      current_index = ni
    end
    @data[current_index] = last
    @data.pop

    ret
  end
end


n=gets.strip.to_i
aa = gets.strip.split.map(&:to_i)

bpq = BigPQ.new
pq = PriorityQueue.new

n.times do |i|
  pq.push(aa[i])
  bpq.push(aa[3*n-1-i])
end

left_score = pq.data.inject(:+)
left_scores = [left_score]

right_score = bpq.data.inject(:+)
right_scores = [right_score]

n.times do |i|
  pq.push(aa[n+i])
  left_score -= pq.pop
  left_score += aa[n+i]
  left_scores.push(left_score)

  bpq.push(aa[2*n-1-i])
  right_score -= bpq.pop
  right_score += aa[2*n-1-i]
  right_scores.unshift(right_score)
end

result = -1*10**10
n.times do |i|
  result = [result, left_scores[i]-right_scores[i]].max
end

#p left_scores
#p right_scores
p result