Problem:
Score : 300 points

Problem Statement

Does \sqrt{a} + \sqrt{b} < \sqrt{c} hold?

Constraints

1 \leq a, b, c \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a \ b \ c

Output

If \sqrt{a} + \sqrt{b} < \sqrt{c}, print Yes; otherwise, print No.

Sample Input 1

2 3 9

Sample Output 1

No

\sqrt{2} + \sqrt{3} < \sqrt{9} does not hold.

Sample Input 2

2 3 10

Sample Output 2

Yes

\sqrt{2} + \sqrt{3} < \sqrt{10} holds.

Solution in Ruby (2.3.3) (judge verdict: Wrong Answer)

require 'bigdecimal'
require 'bigdecimal/util'  #<= to_d メソッドが使えるようになる
(A, B, C) = gets.split.map(&:to_i)

if Math.sqrt(A*B).to_d < (C - A - B) / 2.to_d
#if Math.sqrt(A) + Math.sqrt(B) < Math.sqrt(C)
#if (A+B-C)**2 < 4*A*B
  puts 'Yes'
else
  puts 'No'
end