Problem:
Score : 200 points

Problem Statement

Today is August 24, one of the five Product Days in a year.

A date m-d (m is the month, d is the date) is called a Product Day when d is a two-digit number, and all of the following conditions are satisfied (here d_{10} is the tens digit of the day and d_1 is the ones digit of the day):

d_1 \geq 2

d_{10} \geq 2

d_1 \times d_{10} = m

Takahashi wants more Product Days, and he made a new calendar called Takahashi Calendar where a year consists of M month from Month 1 to Month M, and each month consists of D days from Day 1 to Day D.

In Takahashi Calendar, how many Product Days does a year have?

Constraints

All values in input are integers.

1 \leq M \leq 100

1 \leq D \leq 99

Input

Input is given from Standard Input in the following format:

M D

Output

Print the number of Product Days in a year in Takahashi Calender.

Sample Input 1

15 40

Sample Output 1

10

There are 10 Product Days in a year, as follows (m-d denotes Month m, Day d):

4-22

6-23

6-32

8-24

9-33

10-25

12-26

12-34

14-27

15-35

Sample Input 2

12 31

Sample Output 2

5

Sample Input 3

1 1

Sample Output 3

0

Solution in Ruby (2.3.3) (judge verdict: Wrong Answer)

f = readline.split(" ")
M = f[0].to_i
N = f[1].to_i


i = 22
j = 4
ans = 0

while j < M+1 
  while i < N+1
    Z = i.to_s
    D = Z.split("")
    d_1 = D[0].to_i
    d_2 = D[1].to_i
    if   d_1 == 0 
      break
    elsif d_2 == 0 
      break
    elsif d_1 == 1
      break
    elsif d_2 == 1
      break
    else
      j == d_1 * d_2
      ans += 1
    end
    i +=1
  end
  i = 22
  j += 1
end

puts ans