Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in PyPy3 (7.3.0) (judge verdict: Accepted)

import sys
N=int(input())

for h in range(1,3501):
  for n in range(1,3501):
    bb=(4*h*n-N*n-N*h)
    bs=(N*h*n)
    if bb==0:
      continue

    if bs%bb==0 and 1<=bs//bb:
      print(h,n,bs//bb)
      sys.exit()