Problem:
Score : 400 points

Problem Statement

A maze is composed of a grid of H \times W squares - H vertical, W horizontal.

The square at the i-th row from the top and the j-th column from the left - (i,j) - is a wall if S_{ij} is # and a road if S_{ij} is ..

There is a magician in (C_h,C_w). He can do the following two kinds of moves:

Move A: Walk to a road square that is vertically or horizontally adjacent to the square he is currently in.

Move B: Use magic to warp himself to a road square in the 5\times 5 area centered at the square he is currently in.

In either case, he cannot go out of the maze.

At least how many times does he need to use the magic to reach (D_h, D_w)?

Constraints

1 \leq H,W \leq 10^3

1 \leq C_h,D_h \leq H

1 \leq C_w,D_w \leq W

S_{ij} is # or ..

S_{C_h C_w} and S_{D_h D_w} are ..

(C_h,C_w) \neq (D_h,D_w)

Input

Input is given from Standard Input in the following format:

H W
C_h C_w
D_h D_w
S_{11}\ldots S_{1W}
\vdots
S_{H1}\ldots S_{HW}

Output

Print the minimum number of times the magician needs to use the magic. If he cannot reach (D_h,D_w), print -1 instead.

Sample Input 1

4 4
1 1
4 4
..#.
..#.
.#..
.#..

Sample Output 1

1

For example, by walking to (2,2) and then using the magic to travel to (4,4), just one use of magic is enough.

Note that he cannot walk diagonally.

Sample Input 2

4 4
1 4
4 1
.##.
####
####
.##.

Sample Output 2

-1

He cannot move from there.

Sample Input 3

4 4
2 2
3 3
....
....
....
....

Sample Output 3

0

No use of magic is needed.

Sample Input 4

4 5
1 2
2 5
#.###
####.
#..##
#..##

Sample Output 4

2

Solution in Python (3.8.2) (judge verdict: Time Limit Exceeded)

import sys
sys.setrecursionlimit(10**6)
from itertools import product
from collections import deque
import numpy as np
class Grid():
    def __init__(self, grid, w=0, h=0, function=lambda x: x):
        self.w = w = w if w else len(grid[0])
        self.h = h = h if h else len(grid)
        dtype = type(function(grid[0][0]))
        self.grid = np.empty((h, w), dtype=dtype)
        for i, row in zip(range(h), grid):
            for j, val in zip(range(w), row):
                self.grid[i][j] = function(val)
    
    def is_valid_x(self, x):
        return 0 <= x < self.w
    def is_valid_y(self, y):
        return 0 <= y < self.h
    def is_valid_xy(self, x, y):
        return self.is_valid_x(x) and self.is_valid_y(y) 
    
    def __iter__(self):
        return iter(self.grid)
    def __repr__(self):
        return '\n'.join([' '.join(map(str, row)) for row in self.grid])
    def __getitem__(self, x):
        return self.grid[x]
    def __setitem__(self, x, val):
        self.grid[x] = val

X = iter(open(0).readlines())
h, w = map(int, next(X).split())
ch, cw = map(int, next(X).split())
dh, dw = map(int, next(X).split())
dp = Grid([x.strip() for x in X], function=lambda x: 10**6 if x == '.' else -1)

def dfs(stack):
    if not stack:
        return
    x, y, d = stack[0]
    dp[y, x] = d
    stack2 = []
    while stack:
        x, y, d = stack.pop()
        if dp[y, x] < d:
            continue
        for dx, dy in zip([1, 0, -1, 0], [0, 1, 0, -1]):
            nx, ny = x+dx, y+dy
            if dp.is_valid_xy(nx, ny) and dp[ny, nx] > d:
                dp[ny, nx] = d
                stack.append((nx, ny, d))
        for dx, dy in product(range(-2, 3), repeat=2):
            if abs(dx) + abs(dy) < 2:
                continue
            nx, ny = x+dx, y+dy                
            if dp.is_valid_xy(nx, ny) and dp[ny, nx] > d+1:
                dp[ny, nx] = d+1
                stack2.append((nx, ny, d+1))
    dfs(stack2)

dfs([(cw-1, ch-1, 0)])
if dp[dh-1, dw-1] == 10**6:
    print(-1)
else:
    print(dp[dh-1, dw-1])