Problem:
Score : 100 points

Problem Statement

Iroha loves Haiku. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.

To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Constraints

1≦A,B,C≦10

Input

The input is given from Standard Input in the following format:

A B C

Output

If it is possible to construct a Haiku by using each of the phrases once, print YES (case-sensitive). Otherwise, print NO.

Sample Input 1

5 5 7

Sample Output 1

YES

Using three phrases of length 5, 5 and 7, it is possible to construct a Haiku.

Sample Input 2

7 7 5

Sample Output 2

NO

Solution in Python (3.4.3) (judge verdict: Runtime Error)

n,k=[s for s in input().split()]
n=int(n)
k=int(k)
hate=list(map(int, input().split())) #hate取得
like=[]
for i in range(1,10): #like取得
	if i not in hate:
		like.append(i)
pointer=0
		
for ichi in like: #1桁の場合
	if ichi>=n:
		kane=ichi
		pointer=1
		break

if pointer==0: #2桁の場合
	for ju in like:
		for ichi in like:
			if ju*10+ichi>=n:
				kane=ju*10+ichi
				pointer=1
				break

if pointer==0: #3桁の場合
	for hyaku in like:
		for ju in like:
			for ichi in like:
				if hyaku*100+ju*10+ichi>=n:
					kane=hyaku*100+ju*10+ichi
					pointer=1
					break

if pointer==0: #4桁の場合
	for sen in like:
		for hyaku in like:
			for ju in like:
				for ichi in like:
					if sen*1000+hyaku*100+ju*10+ichi>=n:
						kane=sen*1000+hyaku*100+ju*10+ichi
						pointer=1
						break

if pointer==1:
	print(kane)