Problem:
Score : 300 points

Problem Statement

A sequence a_1,a_2,... ,a_n is said to be /\/\/\/ when the following conditions are satisfied:

For each i = 1,2,..., n-2, a_i = a_{i+2}.

Exactly two different numbers appear in the sequence.

You are given a sequence v_1,v_2,...,v_n whose length is even.
We would like to make this sequence /\/\/\/ by replacing some of its elements.
Find the minimum number of elements that needs to be replaced.

Constraints

2 \leq n \leq 10^5

n is even.

1 \leq v_i \leq 10^5

v_i is an integer.

Input

Input is given from Standard Input in the following format:

n
v_1 v_2 ... v_n

Output

Print the minimum number of elements that needs to be replaced.

Sample Input 1

4
3 1 3 2

Sample Output 1

1

The sequence 3,1,3,2 is not /\/\/\/, but we can make it /\/\/\/ by replacing one of its elements: for example, replace the fourth element to make it 3,1,3,1.

Sample Input 2

6
105 119 105 119 105 119

Sample Output 2

0

The sequence 105,119,105,119,105,119 is /\/\/\/.

Sample Input 3

4
1 1 1 1

Sample Output 3

2

The elements of the sequence 1,1,1,1 are all the same, so it is not /\/\/\/.

Solution in Python (3.8.2) (judge verdict: Wrong Answer)

n = int(input())
v = list(map(int,input().split()))
d1 = {}
d2 = {}

for i in range(0,n//2+2,2):
  a1 = v[i]
  a2 = v[i+1]
  print(a1,a2)
  if a1 not in d1:
    d1[a1] = 1
  else:
    d1[a1] += 1
    
  if a2 not in d2:
    d2[a2] = 1
  else:
    d2[a2] += 1


l1 = list(sorted(d1.items(), key=lambda x:x[1]))
l2 = list(sorted(d2.items(), key=lambda x:x[1]))


if len(set(v)) == 1:
  print(n//2)

if l1[-1][0] == l2[-1][0] and len(l1) >= 2 and len(l2) >= 2:
  print(min(n - l1[-1][1] - l2[-2][1],n - l1[-2][1] - l2[-1][1]))
elif l1[-1][0] == l2[-1][0] and len(l1) == 1 and len(l2) >= 2:
  print(n - l1[-1][1] - l2[-2][1])
elif l1[-1][0] == l2[-1][0] and len(l1) >= 2 and len(l2) == 1:
  print(n - l1[-2][1] - l2[-1][1])
else:
  print(n - l1[-1][1] - l2[-1][1])