Problem:
Score : 300 points

Problem Statement

We have N switches with "on" and "off" state, and M bulbs. The switches are numbered 1 to N, and the bulbs are numbered 1 to M.

Bulb i is connected to k_i switches: Switch s_{i1}, s_{i2}, ..., and s_{ik_i}. It is lighted when the number of switches that are "on" among these switches is congruent to p_i modulo 2.

How many combinations of "on" and "off" states of the switches light all the bulbs?

Constraints

1 \leq N, M \leq 10

1 \leq k_i \leq N

1 \leq s_{ij} \leq N

s_{ia} \neq s_{ib} (a \neq b)

p_i is 0 or 1.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
k_1 s_{11} s_{12} ... s_{1k_1}
:
k_M s_{M1} s_{M2} ... s_{Mk_M}
p_1 p_2 ... p_M

Output

Print the number of combinations of "on" and "off" states of the switches that light all the bulbs.

Sample Input 1

2 2
2 1 2
1 2
0 1

Sample Output 1

1

Bulb 1 is lighted when there is an even number of switches that are "on" among the following: Switch 1 and 2.

Bulb 2 is lighted when there is an odd number of switches that are "on" among the following: Switch 2.

There are four possible combinations of states of (Switch 1, Switch 2): (on, on), (on, off), (off, on) and (off, off). Among them, only (on, on) lights all the bulbs, so we should print 1.

Sample Input 2

2 3
2 1 2
1 1
1 2
0 0 1

Sample Output 2

0

Bulb 1 is lighted when there is an even number of switches that are "on" among the following: Switch 1 and 2.

Bulb 2 is lighted when there is an even number of switches that are "on" among the following: Switch 1.

Bulb 3 is lighted when there is an odd number of switches that are "on" among the following: Switch 2.

Switch 1 has to be "off" to light Bulb 2 and Switch 2 has to be "on" to light Bulb 3, but then Bulb 1 will not be lighted. Thus, there are no combinations of states of the switches that light all the bulbs, so we should print 0.

Sample Input 3

5 2
3 1 2 5
2 2 3
1 0

Sample Output 3

8

Solution in Python (3.8.2) (judge verdict: Accepted)

def main():
    N, M = map(int, input().split())
    lst = [list(map(int, input().split())) for _ in range(M)]
    p = list(map(int, input().split()))
    ans = 0

    for i in range(2 ** N):  # スイッチの状態をビット全探索
        switch = [0] * N
        flag = True

        for j in range(N):  # スイッチの状態を1パターン決める 1:ON, 0:OFF
            if ((i >> j) & 1):
                switch[j] = 1

        for j in range(M):  # 各電球について条件を満たすか確認
            cnt = 0  # 各電球についてonになっているスイッチの数
            for k in lst[j][1:]:
                if switch[k - 1] == 1:
                    cnt += 1

            if cnt % 2 != p[j]:  # 1つでも点灯しない電球があったら現在のスイッチの状態はだめ
                flag = False
                break

        if flag == True:  # すべての電球が点灯する
            ans += 1

    print(ans)


if __name__ == "__main__":
    main()