Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in Python3 (judge verdict: Accepted)

n, m, l = map(int, input().split())

A = []
for i in range(n):
    a = [int(a) for a in input().split()]
    A.append(a)

B = []
for i in range(m):
    b = [int(b) for b in input().split()]
    B.append(b)

C = []
for i in range(n):
    a = A[i]
    Ci = []
    for j in range(l):
        ci = 0
        for k in range(m):
            b = B[k]
            c = a[k]*b[j]
            ci += c
        Ci.append(ci)
    C.append(Ci)

for i in range(n):
    Ci = C[i]
    for j in range(l):
        if j<l-1:
            print(Ci[j],end=' ')
        if j==l-1:
            print(Ci[j])