Problem:
Score : 300 points

Problem Statement

There are N stones arranged in a row. Every stone is painted white or black.
A string S represents the color of the stones. The i-th stone from the left is white if the i-th character of S is ., and the stone is black if the character is #.

Takahashi wants to change the colors of some stones to black or white so that there will be no white stone immediately to the right of a black stone.
Find the minimum number of stones that needs to be recolored.

Constraints

1 \leq N \leq 2\times 10^5

S is a string of length N consisting of . and #.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the minimum number of stones that needs to be recolored.

Sample Input 1

3
#.#

Sample Output 1

1

It is enough to change the color of the first stone to white.

Sample Input 2

5
#.##.

Sample Output 2

2

Sample Input 3

9
.........

Sample Output 3

0

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

n=int(input())
s = input()
n=len(s)

post = ''
ans=0
data=[]

left=[]
right=[]

tmp=0
for i in range(n):
    if s[i]=='#':
        tmp+=1
    elif tmp!= 0:
        left.append(tmp)
        tmp=0


tmp=0
for i in range(n):
    if s[n-i-1]=='.':
        tmp+=1
    if n-i-1-1 >=0 and s[n-i-1-1]=="#" and tmp!=0:
        right.append(tmp)
        tmp=0

right.reverse()
# print(s)
# print(left)
# print(right)

for i in range(len(left)):
    if i == len(left)-1:
        ans+=min(left[i],right[i])
        break
    l = left[i]
    r = right[i]
    if l >= r:
        ans+=r
        left[i+1]=l+r+left[i+1]
    else:
        ans+=l

if '#' not in s:
    ans = 0

if '.' not in s:
    ans=0
print(ans)