Problem:
Score : 500 points

Problem Statement

Let us denote by f(x, m) the remainder of the Euclidean division of x by m.

Let A be the sequence that is defined by the initial value A_1=X and the recurrence relation A_{n+1} = f(A_n^2, M).
Find \displaystyle{\sum_{i=1}^N A_i}.

Constraints

1 \leq N \leq 10^{10}

0 \leq X < M \leq 10^5

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X M

Output

Print \displaystyle{\sum_{i=1}^N A_i}.

Sample Input 1

6 2 1001

Sample Output 1

1369

The sequence A begins 2,4,16,256,471,620,\ldots Therefore, the answer is 2+4+16+256+471+620=1369.

Sample Input 2

1000 2 16

Sample Output 2

6

The sequence A begins 2,4,0,0,\ldots Therefore, the answer is 6.

Sample Input 3

10000000000 10 99959

Sample Output 3

492443256176507

Solution in Python (3.8.2) (judge verdict: Accepted)

N,X,M = map(int,input().split())

d = {X:0}
l = [X]
s = X

for i in range(1,N):
  l+=[(l[i-1]**2)%M]
  s += l[i]
  if l[i] in d:
    dl = l[d[l[i]]+1:]
    s += sum(dl)*((N-i-1)//len(dl))
    if (N-i-1)%len(dl) != 0:
      s += sum(dl[0:(N-i-1)%len(dl)])
    break
  d[l[i]] = i
print(s)