Problem:
Score: 100 points

Problem Statement

In AtCoder Kingdom, Gregorian calendar is used, and dates are written in the "year-month-day" order, or the "month-day" order without the year.

For example, May 3, 2018 is written as 2018-5-3, or 5-3 without the year.

In this country, a date is called Takahashi when the month and the day are equal as numbers. For example, 5-5 is Takahashi.

How many days from 2018-1-1 through 2018-a-b are Takahashi?

Constraints

a is an integer between 1 and 12 (inclusive).

b is an integer between 1 and 31 (inclusive).

2018-a-b is a valid date in Gregorian calendar.

Input

Input is given from Standard Input in the following format:

a b

Output

Print the number of days from 2018-1-1 through 2018-a-b that are Takahashi.

Sample Input 1

5 5

Sample Output 1

5

There are five days that are Takahashi: 1-1, 2-2, 3-3, 4-4 and 5-5.

Sample Input 2

2 1

Sample Output 2

1

There is only one day that is Takahashi: 1-1.

Sample Input 3

11 30

Sample Output 3

11

There are eleven days that are Takahashi: 1-1, 2-2, 3-3, 4-4, 5-5, 6-6, 7-7, 8-8, 9-9, 10-10 and 11-11.

Solution in Python (3.4.3) (judge verdict: Runtime Error)

import math

def is_prime(x):
    if x < 2: return False # 2未満に素数はない
    if x == 2 or x == 3 or x == 5: return True # 2,3,5は素数
    if x % 2 == 0 or x % 3 == 0 or x % 5 == 0: return False # 2,3,5の倍数は合成数

    # ためし割り: 疑似素数(2でも3でも5でも割り切れない数字)で次々に割っていく
    prime = 7
    step = 4
    while prime <= math.sqrt(x):
        if x % prime == 0: return False

        prime += step
        step = 6 - step

    return True
	

N = int(input())
count = 0
a_list = []

for i in range(5550):
	a = 10 * i + 1
	if is_prime(a):
		a_list.append(a)
		count += 1
		if count == N:
			break

print (' '.join(map(str, a_list)))