Problem:
Score : 500 points

Problem Statement

You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)

Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

N, Q, i_q, l_q, and r_q are integers.

S is a string consisting of lowercase English letters.

c_q is a lowercase English letter.

1 \leq N \leq 500000

1 \leq Q \leq 20000

|S| = N

1 \leq i_q \leq N

1 \leq l_q \leq r_q \leq N

There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:

N
S
Q
Query_1
\vdots
Query_Q

Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:

1 i_q c_q

2 l_q r_q

Output

For each query of type 2, print a line containing the answer.

Sample Input 1

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7

Sample Output 1

3
1
5

In the first query, cdbb contains three kinds of letters: b , c , and d, so we print 3.

In the second query, S is modified to abcdzbd.

In the third query, a contains one kind of letter: a, so we print 1.

In the fourth query, S is modified to abcazbd.

In the fifth query, S does not change and is still abcazbd.

In the sixth query, abcazbd contains five kinds of letters: a, b, c, d, and z, so we print 5.

Solution in PyPy3 (2.4.0) (judge verdict: Accepted)

from bisect import bisect_left, bisect, insort
def main():
    n = int(input())
    s = list(input())
    q = int(input())
    _is = {chr(i):[] for i in range(ord("a"), ord("a")+27)}
    for i, si in enumerate(s):
        _is[si].append(i)
    for _ in range(q):
        t, i, c = input().split()
        i = int(i)-1
        if t == "1":
            if s[i] != c:
                index = bisect_left(_is[s[i]], i)
                del _is[s[i]][index]
                insort(_is[c], i)
                s[i] = c
        else:
            c = int(c) - 1
            cnt = 0
            for _isi in _is.values():
                if _isi:
                    is_in = bisect(_isi, c)-bisect_left(_isi, i)
                    if is_in:
                        cnt += 1
            print(cnt)


if __name__ == "__main__":
    main()