Problem:
Score : 400 points

Problem Statement

You are given positive integers N and M.

How many sequences a of length N consisting of positive integers satisfy a_1 \times a_2 \times ... \times a_N = M? Find the count modulo 10^9+7.

Here, two sequences a' and a'' are considered different when there exists some i such that a_i' \neq a_i''.

Constraints

All values in input are integers.

1 \leq N \leq 10^5

1 \leq M \leq 10^9

Input

Input is given from Standard Input in the following format:

N M

Output

Print the number of the sequences consisting of positive integers that satisfy the condition, modulo 10^9 + 7.

Sample Input 1

2 6

Sample Output 1

4

Four sequences satisfy the condition: \{a_1, a_2\} = \{1, 6\}, \{2, 3\}, \{3, 2\} and \{6, 1\}.

Sample Input 2

3 12

Sample Output 2

18

Sample Input 3

100000 1000000000

Sample Output 3

957870001

Solution in Python (3.8.2) (judge verdict: Accepted)

import sys, re
from collections import deque, defaultdict, Counter
from math import ceil, sqrt, hypot, factorial, pi, sin, cos, tan, asin, acos, atan, radians, degrees, log2, gcd
from itertools import accumulate, permutations, combinations, combinations_with_replacement, product, groupby
from operator import itemgetter, mul
from copy import deepcopy
from string import ascii_lowercase, ascii_uppercase, digits
from bisect import bisect, bisect_left, insort, insort_left
from heapq import heappush, heappop
from functools import reduce, lru_cache
def input(): return sys.stdin.readline().strip()
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(): return list(map(int, input().split()))
def TUPLE(): return tuple(map(int, input().split()))
def ZIP(n): return zip(*(MAP() for _ in range(n)))
sys.setrecursionlimit(10 ** 9)
INF = 10**6#float('inf')
mod = 10 ** 9 + 7 
#mod = 998244353
#from decimal import *
#import numpy as np
#decimal.getcontext().prec = 10

		
#階乗#
lim = 2*10**5   #必要そうな階乗の限界を入力
fact = [1] * (lim+1)
for n in range(1, lim+1):
	fact[n] = n * fact[n-1] % mod

#階乗の逆元#
fact_inv = [1]*(lim+1)
fact_inv[lim] = pow(fact[lim], mod-2, mod)
for n in range(lim, 0, -1):
	fact_inv[n-1] = n*fact_inv[n]%mod

def C(n, r):
	return (fact[n]*fact_inv[r]%mod)*fact_inv[n-r]%mod


#素因数分解
def factorization(n):
	arr = []
	tmp = n
	for i in range(2, int(-(-n**0.5//1))+1):
		if tmp%i == 0:
			cnt = 0
			while tmp%i == 0:
				cnt += 1
				tmp //= i
			arr.append([i, cnt])
	if tmp != 1:
		arr.append([tmp, 1])
	if arr == []:
		arr.append([n, 1])
	return arr


N, M = MAP()
if M == 1:
	print(1)
	exit()

arr = factorization(M)
ans = 1
for g, n in arr:
	ans *= C(N-1+n, n)
	ans %= mod

print(ans)