Problem:
Score : 1100 points

Problem Statement

We have a grid with N rows and M columns of squares.
Each integer from 1 to NM is written in this grid once.
The number written in the square at the i-th row from the top and the j-th column from the left is A_{ij}.

You need to rearrange these numbers as follows:

First, for each of the N rows, rearrange the numbers written in it as you like.

Second, for each of the M columns, rearrange the numbers written in it as you like.

Finally, for each of the N rows, rearrange the numbers written in it as you like.

After rearranging the numbers, you want the number written in the square at the i-th row from the top and the j-th column from the left to be M\times (i-1)+j.
Construct one such way to rearrange the numbers. The constraints guarantee that it is always possible to achieve the objective.

Constraints

1 \leq N,M \leq 100

1 \leq A_{ij} \leq NM

A_{ij} are distinct.

Input

Input is given from Standard Input in the following format:

N M
A_{11} A_{12} ... A_{1M}
:
A_{N1} A_{N2} ... A_{NM}

Output

Print one way to rearrange the numbers in the following format:

B_{11} B_{12} ... B_{1M}
:
B_{N1} B_{N2} ... B_{NM}
C_{11} C_{12} ... C_{1M}
:
C_{N1} C_{N2} ... C_{NM}

Here B_{ij} is the number written in the square at the i-th row from the top and the j-th column from the left after Step 1, and C_{ij} is the number written in that square after Step 2.

Sample Input 1

3 2
2 6
4 3
1 5

Sample Output 1

2 6
4 3
5 1
2 1
4 3
5 6

Sample Input 2

3 4
1 4 7 10
2 5 8 11
3 6 9 12

Sample Output 2

1 4 7 10
5 8 11 2
9 12 3 6
1 4 3 2
5 8 7 6
9 12 11 10

Solution in PyPy3 (2.4.0) (judge verdict: Runtime Error)

import sys
readline = sys.stdin.readline

import collections
class Dinic:
    def __init__(self, vnum):
        self.edge = [[] for i in range(vnum)]
        self.n = vnum
        # infはint型の方が良いかもね
        self.inf = float('inf')
    def addedge(self, st, en, c):
        self.edge[st].append([en, c, len(self.edge[en])])
        self.edge[en].append([st, 0, len(self.edge[st])-1])
    def bfs(self, vst):
        dist = [-1]*self.n
        dist[vst] = 0
        Q = collections.deque([vst])
        while Q:
            nv = Q.popleft()
            for vt, c, r in self.edge[nv]:
                if dist[vt] == -1 and c > 0:
                    dist[vt] = dist[nv] + 1
                    Q.append(vt)
        self.dist = dist
    def dfs(self, nv, en, nf):
        nextv = self.nextv
        if nv == en:
            return nf
        dist = self.dist
        ist = nextv[nv]
        for i, (vt, c, r) in enumerate(self.edge[nv][ist:], ist):
            if dist[nv] < dist[vt] and c > 0:
                df = self.dfs(vt, en, min(nf, c))
                if df > 0:
                    self.edge[nv][i][1] -= df
                    self.edge[vt][r][1] += df
                    return df
            nextv[nv] += 1
        return 0
    def getmf(self, st, en):
        mf = 0
        while True:
            self.bfs(st)
            if self.dist[en] == -1:
                break
            self.nextv = [0]*self.n
            while True:
                fl = self.dfs(st, en, self.inf)
                if fl > 0:
                    mf += fl
                else:
                    break
        return mf



N, M = map(int, readline().split())
A = [list(map(int, readline().split())) for _ in range(N)]

B = [[None]*M for _ in range(N)]

unused = [set(range(N)) for _ in range(M)]

st = 2*M
en = 2*M+1
for i in range(N):
    T = Dinic(2*M+2)
    for j in range(M):
        T.addedge(st, j, 1)
        T.addedge(M+j, en, 1)
        aj = (A[i][j]-1)//M
        for ji in range(M):
            if aj in unused[ji]:
                T.addedge(j, M+ji, 1)
    T.getmf(st, en)
    for j in range(M):
        candi = [e for e, cost, _ in T.edge[M+j] if cost == 1]
        while not candi:
            continue
        B[i][j] = A[i][candi[0]]
    
    for j in range(M):
        unused[j].remove((B[i][j]-1)//M)
        
    
C = list(map(list, zip(*B)))
C = [sorted(c) for c in C]
C = list(map(list, zip(*C)))

for b in B:
    print(*b)

for c in C:
    print(*c)