Problem:
Score : 300 points

Problem Statement

Let f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:

1 \leq x,y,z

x^2 + y^2 + z^2 + xy + yz + zx = n

Given an integer N, find each of f(1),f(2),f(3),\ldots,f(N).

Constraints

All values in input are integers.

1 \leq N \leq 10^4

Input

Input is given from Standard Input in the following format:

N

Output

Print N lines. The i-th line should contain the value f(i).

Sample Input 1

20

Sample Output 1

0
0
0
0
0
1
0
0
0
0
3
0
0
0
0
0
3
3
0
0

For n=6, only (1,1,1) satisfies both of the conditions. Thus, f(6) = 1.

For n=11, three triples, (1,1,2), (1,2,1), and (2,1,1), satisfy both of the conditions. Thus, f(6) = 3.

For n=17, three triples, (1,2,2), (2,1,2), and (2,2,1), satisfy both of the conditions. Thus, f(17) = 3.

For n=18, three triples, (1,1,3), (1,3,1), and (3,1,1), satisfy both of the conditions. Thus, f(18) = 3.

Solution in Python (3.8.2) (judge verdict: Time Limit Exceeded)

import math
n=int(input())
nn=int(math.sqrt(n))
for i in range(1,n+1):
    min=int((nn+1)/3)
    min1=int((nn+1)/2)
    count=0
    for x in range(1,min+1):
        for y in range(x,min1+1):
            for z in range(y,nn+1):
                #print(x*x+y*y+z*z+x*y+y*z+z*x)
                if (x*x+y*y+z*z+x*y+y*z+z*x)==i:
                    if x==y and y==z and z==y:
                        count=count+1
                    elif x!=y and y!=z and z!=y:
                        count=count+6
                    else:
                        count=count+3
    print(count)