Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in PyPy3 (2.4.0) (judge verdict: Wrong Answer)

N,A,B,C,D=map(int,input().split())
S=list(input())

if A<B<C<D:
    a=True
    for i in range(A-1,D-2):
        if S[i]==S[i+1]=="#":
            print("No")
            a=False
            break
    if a==True:
        print("Yes")
elif A<C<B<D:
    a=True
    for i in range(A-1,C-2):
        if S[i]==S[i+1]=="#":
            print("No")
            a=False
            break
    if a==True:
        for i in range(B-1,D-2):
            if S[i]==S[i+1]=="#":
                print("No")
                a=False
                break
    if a==True:
        print("Yes")
elif A<B<D<C:
    a=True
    for i in range(A-1,C-2):
        if S[i]==S[i+1]=="#":
            print("No")
            a=False
            break
    if a==True:
        for i in range(B-2,D-2+1):
            if S[i]==S[i+1]==S[i+2]:
                a=False
                break
    if a==False:
        print("Yes")
    elif a==True:
        print("No")