Problem:
Score : 600 points

Problem Statement

Given are two sequences A and B, both of length N.
A and B are each sorted in the ascending order.
Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.

Constraints

1\leq N \leq 2 \times 10^5

1\leq A_i,B_i \leq N

A and B are each sorted in the ascending order.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N

Output

If there exist no reorderings that satisfy the condition, print No.

If there exists a reordering that satisfies the condition, print Yes on the first line.
After that, print a reordering of B on the second line, separating terms with a whitespace.

If there are multiple reorderings that satisfy the condition, you can print any of them.

Sample Input 1

6
1 1 1 2 2 3
1 1 1 2 2 3

Sample Output 1

Yes
2 2 3 1 1 1

Sample Input 2

3
1 1 2
1 1 3

Sample Output 2

No

Sample Input 3

4
1 1 2 3
1 2 3 3

Sample Output 3

Yes
3 3 1 2

Solution in PyPy3 (7.3.0) (judge verdict: Accepted)

N = int(input())
*A, = map(int, input().split())
*B, = map(int, input().split())
B.reverse()

ac = [0]*(N+1)
bc = [0]*(N+1)

ok = True
for i in range(N):
    ac[A[i]] += 1
    bc[B[i]] += 1

for i in range(1, N+1):
    if (ac[i]+bc[i]) > N:
        ok = False
        break

if ok:
    l, r = 0, N-1
    for i in range(N):
        if A[i] == B[i]:
            if A[i] != B[l] and A[l] != B[i]:
                B[l], B[i] = B[i], B[l]
                l += 1
            elif A[i] != B[r] and A[r] != B[i]:
                B[r], B[i] = B[i], B[r]
                r -= 1
    print("Yes")
    print(*B)
else:
    print("No")