Problem:
Score : 300 points

Problem Statement

Let f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:

1 \leq x,y,z

x^2 + y^2 + z^2 + xy + yz + zx = n

Given an integer N, find each of f(1),f(2),f(3),\ldots,f(N).

Constraints

All values in input are integers.

1 \leq N \leq 10^4

Input

Input is given from Standard Input in the following format:

N

Output

Print N lines. The i-th line should contain the value f(i).

Sample Input 1

20

Sample Output 1

0
0
0
0
0
1
0
0
0
0
3
0
0
0
0
0
3
3
0
0

For n=6, only (1,1,1) satisfies both of the conditions. Thus, f(6) = 1.

For n=11, three triples, (1,1,2), (1,2,1), and (2,1,1), satisfy both of the conditions. Thus, f(6) = 3.

For n=17, three triples, (1,2,2), (2,1,2), and (2,2,1), satisfy both of the conditions. Thus, f(17) = 3.

For n=18, three triples, (1,1,3), (1,3,1), and (3,1,1), satisfy both of the conditions. Thus, f(18) = 3.

Solution in Python (3.8.2) (judge verdict: Accepted)

# -*- coding: utf-8 -*-


# 入力を整数に変換して受け取る
def input_int():
    return int(input())


# マイナス1した値を返却
def int1(x):
    return int(x) - 1


# 半角スペース区切り入力をIntに変換してMapで受け取る
def input_to_int_map():
    return map(int, input().split())


# 半角スペース区切り入力をIntに変換して受け取る
def input_to_int_tuple():
    return tuple(map(int, input().split()))


# 半角スペース区切り入力をIntに変換してマイナス1した値を受け取る
def input_to_int_tuple_minus1():
    return tuple(map(int1, input().split()))


import collections
import math
def main():

    n = input_int()
    ans = collections.defaultdict(set)
    max_val = int(math.sqrt(n)) + 1
    for x in range(1, max_val):
        for y in range(1, max_val):
            for z in range(1, max_val):
                temp = (x ** 2) + (y ** 2) + (z ** 2) + (x * y) + (x * z) + (y * z)
                if temp <= n:
                    ans[temp].add((x, y, z))

    for i in range(1, n + 1):
        print(len(ans[i]))


if __name__ == "__main__":
    main()