Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Python (3.4.3) (judge verdict: Runtime Error)

import sys


def input():
    return sys.stdin.readline().strip()


sys.setrecursionlimit(10 ** 9)


def main():
    N = int(input())
    if N < 105:
        print(0)
        return

    def make_divisors(n):
        divisors = []
        for i in range(1, int(n ** 0.5) + 1):
            if n % i == 0:
                divisors.append(i)
                if i != n // i:
                    divisors.append(n // i)

    cnt = 1
    for n in range(106, N + 1):
        d = make_divisors(n)
        if len(d) == 8:
            cnt += 1
    print(cnt)


if __name__ == "__main__":
    main()