Problem:
Score : 400 points

Problem Statement

There is a knight - the chess piece - at the origin (0, 0) of a two-dimensional grid.

When the knight is at the square (i, j), it can be moved to either (i+1,j+2) or (i+2, j+1).

In how many ways can the knight reach the square (X, Y)?

Find the number of ways modulo 10^9 + 7.

Constraints

1 \leq X \leq 10^6

1 \leq Y \leq 10^6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

Print the number of ways for the knight to reach (X, Y) from (0, 0), modulo 10^9 + 7.

Sample Input 1

3 3

Sample Output 1

2

There are two ways: (0,0) \to (1,2) \to (3,3) and (0,0) \to (2,1) \to (3,3).

Sample Input 2

2 2

Sample Output 2

0

The knight cannot reach (2,2).

Sample Input 3

999999 999999

Sample Output 3

151840682

Print the number of ways modulo 10^9 + 7.

Solution in Python (3.4.3) (judge verdict: Runtime Error)

x,y = map(int,input().split())

import sys
sys.setrecursionlimit(200000000)
p = 10**9+7
fact=[0,1]
for i in range(2,max(x,y)+1):
  fact.append(fact[-1]*i % p)

def exp(y,x):
  xbin=str(bin(x))[2:]
  ans=1
  yl=[0]*(len(xbin)+1)
  yl[0]=y
  yl[1]=y**2
  for d,i in enumerate(xbin[::-1],start=0):
    if d > 1:
      yl[d]=yl[d-1]**2%p
    if i == "1":
      ans=(ans*yl[d])%p
  return ans%p

def ff(n,ca):
  if ca == 1:
    return n
  return n*ff(n-1,ca-1)%p

if (y+x)%3 != 0:
  print(0)
elif y/x > 2:
  print(0)
elif y/x < 0.5:
  print(0)
else:
  n=(2*x-y)//3
  m=(2*y-x)//3
  ans=ff(n+m,n)*exp(fact[n],p-2)%p
  print(ans)