Problem:
Score : 100 points

Problem Statement

Takahashi is a member of a programming competition site, ButCoder.

Each member of ButCoder is assigned two values: Inner Rating and Displayed Rating.

The Displayed Rating of a member is equal to their Inner Rating if the member has participated in 10 or more contests. Otherwise, the Displayed Rating will be their Inner Rating minus 100 \times (10 - K) when the member has participated in K contests.

Takahashi has participated in N contests, and his Displayed Rating is R. Find his Inner Rating.

Constraints

All values in input are integers.

1 \leq N \leq 100

0 \leq R \leq 4111

Input

Input is given from Standard Input in the following format:

N R

Output

Print his Inner Rating.

Sample Input 1

2 2919

Sample Output 1

3719

Takahashi has participated in 2 contests, which is less than 10, so his Displayed Rating is his Inner Rating minus 100 \times (10 - 2) = 800.

Thus, Takahashi's Inner Rating is 2919 + 800 = 3719.

Sample Input 2

22 3051

Sample Output 2

3051

Solution in PyPy3 (2.4.0) (judge verdict: Runtime Error)

import sys
sys.setrecursionlimit(10**8)
def ii(): return int(sys.stdin.readline())
def mi(): return map(int, sys.stdin.readline().split())
def li(): return list(map(int, sys.stdin.readline().split()))
def li2(N): return [list(map(int, sys.stdin.readline().split())) for _ in range(N)]
def dp2(ini, i, j): return [[ini]*i for _ in range(j)]
def dp3(ini, i, j, k): return [[[ini]*i for _ in range(j)] for _ in range(k)]
#import bisect #bisect.bisect_left(B, a)
#from collections import defaultdict #d = defaultdict(int) d[key] += value
#from itertools import accumulate #list(accumulate(A))

def pow_r_mod(x, n, mod=10**9+7):
    # 計算量 : log N
    if n == 0:
        return 1
    K = 1
    while n > 1:
        if n % 2 != 0:
            K *= x
        x *= x
        x %= mod
        n //= 2
    return (K * x) % mod

def  mod_pow(a:int, b:int, mod:int)->int:
    if b % 2 == 0:
        return (mod_pow(a, b//2, mod) ** 2) % mod
    elif b == 1:
        return a % mod
    else:
        return ((mod_pow(a, b//2, mod) ** 2) * a) % mod

m, a, b = mi()

P = 10**9+7
N = 2*(10**5)+1
inv_t = [0]+[1]
for i in range(2, N):
  inv_t += [inv_t[P % i] * (P - int(P / i)) % P]

mca = mcb = 1

for i in range(1, a+1):
    mca *= (m-i+1) * inv_t[i]
    mca %= P

for i in range(1, b+1):
    mcb *= (m-i+1) * inv_t[i]
    mcb %= P

#print((pow_r_mod(2, m)-1-mca-mcb) % P)
print((mod_pow(2, m, P)-1-mca-mcb) % P)