Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Python (3.4.3) (judge verdict: Accepted)

#ABC105-B
n = int(input())
divisor_list = []
ans = 0
for i in range(1,n+1):
    divisor_list = []
    #odd,even判定
    if(i % 2 != 0):
        #約数をdivisor_listに追加していく
        for j in range(1,i+1):
            if (i % j == 0):
                divisor_list.append(j)
            if(len(divisor_list) == 8):
                ans += 1
print(ans)