Problem:
Score : 400 points

Problem Statement

There is a grid with N rows and N columns of squares. Let (i,j) be the square at the i-th row from the top and the j-th column from the left.

These squares have to be painted in one of the C colors from Color 1 to Color C. Initially, (i,j) is painted in Color c_{i,j}.

We say the grid is a good grid when the following condition is met for all i,j,x,y satisfying 1 \leq i,j,x,y \leq N:

If (i+j) \% 3=(x+y) \% 3, the color of (i,j) and the color of (x,y) are the same.

If (i+j) \% 3 \neq (x+y) \% 3, the color of (i,j) and the color of (x,y) are different.

Here, X \% Y represents X modulo Y.

We will repaint zero or more squares so that the grid will be a good grid.

For a square, the wrongness when the color of the square is X before repainting and Y after repainting, is D_{X,Y}.

Find the minimum possible sum of the wrongness of all the squares.

Constraints

1 \leq N \leq 500

3 \leq C \leq 30

1 \leq D_{i,j} \leq 1000 (i \neq j),D_{i,j}=0 (i=j)

1 \leq c_{i,j} \leq C

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N C
D_{1,1} ... D_{1,C}
:
D_{C,1} ... D_{C,C}
c_{1,1} ... c_{1,N}
:
c_{N,1} ... c_{N,N}

Output

If the minimum possible sum of the wrongness of all the squares is x, print x.

Sample Input 1

2 3
0 1 1
1 0 1
1 4 0
1 2
3 3

Sample Output 1

3

Repaint (1,1) to Color 2. The wrongness of (1,1) becomes D_{1,2}=1.

Repaint (1,2) to Color 3. The wrongness of (1,2) becomes D_{2,3}=1.

Repaint (2,2) to Color 1. The wrongness of (2,2) becomes D_{3,1}=1.

In this case, the sum of the wrongness of all the squares is 3.

Note that D_{i,j} \neq D_{j,i} is possible.

Sample Input 2

4 3
0 12 71
81 0 53
14 92 0
1 1 2 1
2 1 1 2
2 2 1 3
1 1 2 2

Sample Output 2

428

Solution in PyPy3 (2.4.0) (judge verdict: Accepted)

n,c = map(int,input().split())
d = [list(map(int,input().split())) for _ in range(c)]
lic = [list(map(int,input().split())) for _ in range(n)]

for i in range(n):
    for j in range(n):
        lic[i][j] -= 1

dict0 = {}
dict1 = {}
dict2 = {}
li0 = []
li1 = []
li2 = []

for i in range(n):
    for j in range(n):
        color = lic[i][j]
        if (i+j) % 3 == 0:
            if color in dict0:
                dict0[color] += 1
            else:
                dict0[color] = 1
                li0.append(color)
        elif (i+j) % 3 == 1:
            if color in dict1:
                dict1[color] += 1
            else:
                dict1[color] = 1
                li1.append(color)
        else:
            if color in dict2:
                dict2[color] += 1
            else:
                dict2[color] = 1
                li2.append(color)


ans = 10 ** 10

for i in range(c):
    for j in range(c):
        for k in range(c):
            if i != j and j != k and k != i:
                ans_tmp = 0
                for ii in li0:
                    if ii != i:
                        ans_tmp += d[ii][i] * dict0[ii]
                for jj in li1:
                    if jj != j:
                        ans_tmp += d[jj][j] * dict1[jj]
                for kk in li2:
                    if kk != k:
                        ans_tmp += d[kk][k] * dict2[kk]
                ans = min(ans, ans_tmp)

print(ans)