Problem:
Score : 200 points

Problem Statement

Given are integers a,b,c and d.
If x and y are integers and a \leq x \leq b and c\leq y \leq d hold, what is the maximum possible value of x \times y?

Constraints

-10^9 \leq a \leq b \leq 10^9

-10^9 \leq c \leq d \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a b c d

Output

Print the answer.

Sample Input 1

1 2 1 1

Sample Output 1

2

If x = 1 and y = 1 then x \times y = 1.
If x = 2 and y = 1 then x \times y = 2.
Therefore, the answer is 2.

Sample Input 2

3 5 -4 -2

Sample Output 2

-6

The answer can be negative.

Sample Input 3

-1000000000 0 -1000000000 0

Sample Output 3

1000000000000000000

Solution in PyPy3 (7.3.0) (judge verdict: Wrong Answer)

a,b,c,d = map(int,input().split())

if a < 0 and b < 0 :
    if c <= 0 :
        print(a*c)
    else :
        print(b*c)
elif a < 0 and b == 0:
    if c <= 0:
        print(a*c)
    else :
        print(0)
elif a < 0 and b > 0 :
    if a * c < b * d :
        print(b*d)
    else :
        print(a*c)
elif a==0 and b > 0:
    if d <= 0:
        print(0)
    else :
        print(b*d)
elif a > 0 and b > 0:
    if d <= 0:
        print(a*d)
    else :
        print(b*d)