Problem:
Score : 400 points

Problem Statement

Let {\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order.
From n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\rm comb}(a_i,a_j) is maximized.
If there are multiple pairs that maximize the value, any of them is accepted.

Constraints

2 \leq n \leq 10^5

0 \leq a_i \leq 10^9

a_1,a_2,...,a_n are pairwise distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print a_i and a_j that you selected, with a space in between.

Sample Input 1

5
6 9 4 2 11

Sample Output 1

11 6

\rm{comb}(a_i,a_j) for each possible selection is as follows:

\rm{comb}(4,2)=6

\rm{comb}(6,2)=15

\rm{comb}(6,4)=15

\rm{comb}(9,2)=36

\rm{comb}(9,4)=126

\rm{comb}(9,6)=84

\rm{comb}(11,2)=55

\rm{comb}(11,4)=330

\rm{comb}(11,6)=462

\rm{comb}(11,9)=55

Thus, we should print 11 and 6.

Sample Input 2

2
100 0

Sample Output 2

100 0

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

n = int(input())
a = list(map(int,input().split()))
a.sort()
a_i = a[-1]
a_j = a[0]
max = 0
import numpy as np
def getNearestValue(list, num):
    """
    概要: リストからある値に最も近い値を返却する関数
    @param list: データ配列
    @param num: 対象値
    @return 対象値に最も近い値
    """

    # リスト要素と対象値の差分を計算し最小値のインデックスを取得
    idx = np.abs(np.asarray(list) - num).argmin()
    return list[idx]

from scipy.misc import comb
if n - 10 < 0:
    n_min = 0
else:
    n_min = n - 10
for i in range(n_min,n):
    b_j = getNearestValue(a, a[i]/2.0)
    b1 = comb(a[i], b_j)
    if max < b1 and a[i] > b_j:
        max = b1
        a_i = a[i]
        a_j = b_j
print("{} {}".format(a_i, a_j))