Problem:
Score : 300 points

Problem Statement

Given is a permutation P_1, \ldots, P_N of 1, \ldots, N.
Find the number of integers i (1 \leq i \leq N) that satisfy the following condition:

For any integer j (1 \leq j \leq i), P_i \leq P_j.

Constraints

1 \leq N \leq 2 \times 10^5

P_1, \ldots, P_N is a permutation of 1, \ldots, N.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
P_1 ... P_N

Output

Print the number of integers i that satisfy the condition.

Sample Input 1

5
4 2 5 1 3

Sample Output 1

3

i=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.

Similarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.

Sample Input 2

4
4 3 2 1

Sample Output 2

4

All integers i (1 \leq i \leq N) satisfy the condition.

Sample Input 3

6
1 2 3 4 5 6

Sample Output 3

1

Only i=1 satisfies the condition.

Sample Input 4

8
5 7 4 2 6 8 1 3

Sample Output 4

4

Sample Input 5

1
1

Sample Output 5

1

Solution in Python (3.4.3) (judge verdict: Accepted)

"""
can do it by subproblems. for a given i, the only information you need from the previous values
is the min value of previous values.
the first i=0 is guaranteed to satisfy the constraint. (counting from zero).
"""
import sys


def count_low_elements(N, P):
    count = 0
    min_so_far = sys.maxsize
    for val in P:
        if val <= min_so_far:
            count += 1
            min_so_far = val
    return count


if __name__ == "__main__":
    test1 = \
"""5
4 2 5 1 3"""
    test2 = \
"""4
4 3 2 1"""
    test3 = \
"""6
1 2 3 4 5 6"""
    test4 = \
"""8
5 7 4 2 6 8 1 3"""
    test5 = \
"""1
1"""
    test = test5
    # N, P_string = test.split("\n")
    # P = list(map(int, P_string.split()))
    N = int(input())
    P = list(map(int, input().split()))
    print(count_low_elements(N, P))