Problem:
Score : 600 points

Problem Statement

We have N colored balls arranged in a row from left to right; the color of the i-th ball from the left is c_i.

You are given Q queries. The i-th query is as follows: how many different colors do the l_i-th through r_i-th balls from the left have?

Constraints

1\leq N,Q \leq 5 \times 10^5

1\leq c_i \leq N

1\leq l_i \leq r_i \leq N

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N Q
c_1 c_2 \cdots c_N
l_1 r_1
l_2 r_2
:
l_Q r_Q

Output

Print Q lines. The i-th line should contain the response to the i-th query.

Sample Input 1

4 3
1 2 1 3
1 3
2 4
3 3

Sample Output 1

2
3
1

The 1-st, 2-nd, and 3-rd balls from the left have the colors 1, 2, and 1 - two different colors.

The 2-st, 3-rd, and 4-th balls from the left have the colors 2, 1, and 3 - three different colors.

The 3-rd ball from the left has the color 1 - just one color.

Sample Input 2

10 10
2 5 6 5 2 1 7 9 7 2
5 5
2 4
6 7
2 2
7 8
7 9
1 8
6 9
8 10
6 8

Sample Output 2

1
2
2
1
2
2
6
3
3
3

Solution in PyPy3 (7.3.0) (judge verdict: Time Limit Exceeded)

n,q=map(int,input().split())
c=list(map(int,input().split()))
num=[]
def ap(n1,n2,n3):
    num.append([n1,n2,n3])
for i in range(q):
    l,r=map(int,input().split())
    ap(l,r,i)
num.sort(key=lambda x: x[1])
la=[-1]*max(c)
bit=[0]*n
ans=list(range(q))
num1=0
def cnt(n01,n02):
    return sum(bit[n01-1:n02])
for i in range(q):
    n0=num[i][0]
    n1=num[i][1]
    for j in range(num1,n1):
        num2=c[j]
        num3=la[num2-1]
        if num3==-1:
            la[num2-1]=j
            bit[j]=1
        else:
            bit[num3]=0
            la[num2-1]=j
            bit[j]=1
    ans[num[i][2]]=cnt(n0,n1)
    num1=n1-1
for i in ans:
    print(i)