Problem:
Score : 400 points

Problem Statement

Given is a positive integer N. Consider repeatedly applying the operation below on N:

First, choose a positive integer z satisfying all of the conditions below:

z can be represented as z=p^e, where p is a prime number and e is a positive integer;

z divides N;

z is different from all integers chosen in previous operations.

Then, replace N with N/z.

Find the maximum number of times the operation can be applied.

Constraints

All values in input are integers.

1 \leq N \leq 10^{12}

Input

Input is given from Standard Input in the following format:

N

Output

Print the maximum number of times the operation can be applied.

Sample Input 1

24

Sample Output 1

3

We can apply the operation three times by, for example, making the following choices:

Choose z=2 (=2^1). (Now we have N=12.)

Choose z=3 (=3^1). (Now we have N=4.)

Choose z=4 (=2^2). (Now we have N=1.)

Sample Input 2

1

Sample Output 2

0

We cannot apply the operation at all.

Sample Input 3

64

Sample Output 3

3

We can apply the operation three times by, for example, making the following choices:

Choose z=2 (=2^1). (Now we have N=32.)

Choose z=4 (=2^2). (Now we have N=8.)

Choose z=8 (=2^3). (Now we have N=1.)

Sample Input 4

1000000007

Sample Output 4

1

We can apply the operation once by, for example, making the following choice:

z=1000000007 (=1000000007^1). (Now we have N=1.)

Sample Input 5

997764507000

Sample Output 5

7

Solution in PyPy3 (7.3.0) (judge verdict: Accepted)

#from collections import deque,defaultdict
from sys import stdin
input = stdin.readline
printn = lambda x: print(x,end='')
inn = lambda : int(input())
inl   = lambda: list(map(int, input().split()))
inm   = lambda:      map(int, input().split())
ins = lambda : input().strip()
DBG = True # and False
BIG = 10**18
R = 10**9 + 7

def ddprint(x):
  if DBG:
    print(x)

import math
# isprime, prime_division

def isprime(x):
    q = int(math.sqrt(x))  # int() rounds to zero
    for i in range(2,q+1):   # upto q
        if x%i == 0:
            return False
    return True

def prime_division(x):
    q = int(math.sqrt(x))
    a = []
    for i in range(2,q+1):
        ex = 0
        while x%i == 0:
            ex += 1
            x //= i
        if ex>0:
            a.append([i,ex])
    if x>q:
        a.append([x,1])
    return a

def prime_division2(x):
    q = int(math.sqrt(x))
    h = {}
    for i in range(2,q+1):
        ex = 0
        while x%i == 0:
            ex += 1
            x //= i
        if ex>0:
            h[i] = ex
    if x>q:
        h[x] = 1
    return h

def divisorlist(z): # z : output of prime_division
    if len(z)==1:
        return [z[0][0]**i for i in range(z[0][1]+1)]
    y = divisorlist(z[1:])
    s = []
    for i in range(z[0][1]+1):
        for j in y:
            s.append((z[0][0]**i)*j)
    return s

n = inn()
sm = 0
pes = prime_division(n)
for p,e in pes:
    for i in range(1,50):
        if e<2*i+1:
            break
        sm += 1
        e -= i
    sm += 1
print(sm)