Problem:
Score : 500 points

Problem Statement

There are N points on the 2D plane, i-th of which is located on (x_i, y_i).
There can be multiple points that share the same coordinate.
What is the maximum possible Manhattan distance between two distinct points?

Here, the Manhattan distance between two points (x_i, y_i) and (x_j, y_j) is defined by |x_i-x_j| + |y_i-y_j|.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq x_i,y_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
x_1 y_1
x_2 y_2
:
x_N y_N

Output

Print the answer.

Sample Input 1

3
1 1
2 4
3 2

Sample Output 1

4

The Manhattan distance between the first point and the second point is |1-2|+|1-4|=4, which is maximum possible.

Sample Input 2

2
1 1
1 1

Sample Output 2

0

Solution in Python (3.8.2) (judge verdict: Runtime Error)

def signed_area(p1, p2, p3):
    '''符号付き面積を計算 '''

    area = (((p2[0] - p1[0]) * (p3[1] - p1[1])) - ((p3[0] - p1[0]) * (p2[1] - p1[1]))) / 2
    return area


def convex_hull(p_list):
    '''グラハムの凸包走査 '''

    p_sort = []
    for i in p_list:
        p_sort.append(i[0])

    # x座標が最小のものをリストの先頭に配置。
    min_index = p_sort.index(min(p_sort))
    min_p = p_list.pop(min_index)
    p_list.insert(0, min_p)

    # 座標最小の点と他の点との角度順にソート ソートアルゴリズムに選択の余地が有る。
    p_length = len(p_list)
    count = 0
    index = 0
    while True:
        count += 1
        index += 1

        area_sign = signed_area(p_list[0], p_list[index], p_list[index + 1])

        # 符号付き面積が負ならば点を入れ替え
        if area_sign < 0:
            p_list[index], p_list[index + 1] = p_list[index + 1], p_list[index]
            count = 0

        if count == p_length - 1:
            break

        if index == p_length - 2:
            index = 0

    # 凹部の点を削除する。
    index = -1
    count = 0
    while True:
        index += 1
        count += 1

        area_sign = signed_area(p_list[index], p_list[index + 1], p_list[index + 2])
        if area_sign < 0:
            del p_list[index + 1]
            count = 0

        if count == len(p_list):
            break

        if index >= len(p_list) - 3:
            index = -1
    return p_list

n = int(input())
point = []
for _ in range(n):
    x, y = map(int, input().split())
    point.append([x, y])

point = convex_hull(point)
ans = 0
for i in range(len(point)):
    for j in range(len(point)):
        if i != j:
            ans = max(ans, abs(point[i][0] - point[j][0]) + abs(point[i][1] - point[j][1]))
print(ans)