Problem:
Score : 100 points

Problem Statement

We have two bottles for holding water.

Bottle 1 can hold up to A milliliters of water, and now it contains B milliliters of water.

Bottle 2 contains C milliliters of water.

We will transfer water from Bottle 2 to Bottle 1 as much as possible.

How much amount of water will remain in Bottle 2?

Constraints

All values in input are integers.

1 \leq B \leq A \leq 20

1 \leq C \leq 20

Input

Input is given from Standard Input in the following format:

A B C

Output

Print the integer representing the amount of water, in milliliters, that will remain in Bottle 2.

Sample Input 1

6 4 3

Sample Output 1

1

We will transfer two milliliters of water from Bottle 2 to Bottle 1, and one milliliter of water will remain in Bottle 2.

Sample Input 2

8 3 9

Sample Output 2

4

Sample Input 3

12 3 7

Sample Output 3

0

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

s = input()
n = len(s)
#各Lについて、自分より左でもっとも右のR
n_r = [-1 for i in range(n)]
#各Rについて、自分より右でもっとも左のL
n_l = [-1 for i in range(n)]

nearest_r = 0

for i in range(n):
    if s[i] == "R":
        nearest_r = i
    else:
        n_r[i] = nearest_r

nearest_l = n-1

for i in range(n-1,-1,-1):
    if s[i] == "L":
        nearest_l = i
    else:
        n_l[i] = nearest_l

answers = [0 for i in range(n)]

for i in range(n):
    if s[i] == "R":
        if (n_l[i] - i)%2 == 0:
            answers[n_l[i]] += 1
        else:
            answers[n_l[i]-1] += 1
    else:
        if (i - n_r[i])%2 == 0:
            answers[n_r[i]] += 1
        else:
            answers[n_r[i]+1] += 1

ans  =""
for i in range(n):
    ans += str(answers[i])
    if i != n-1:
        ans += " "

print(ans)