Problem:
Score : 500 points

Problem Statement

There is a building with n rooms, numbered 1 to n.

We can move from any room to any other room in the building.

Let us call the following event a move: a person in some room i goes to another room j~ (i \neq j).

Initially, there was one person in each room in the building.

After that, we know that there were exactly k moves happened up to now.

We are interested in the number of people in each of the n rooms now. How many combinations of numbers of people in the n rooms are possible?

Find the count modulo (10^9 + 7).

Constraints

All values in input are integers.

3 \leq n \leq 2 \times 10^5

2 \leq k \leq 10^9

Input

Input is given from Standard Input in the following format:

n k

Output

Print the number of possible combinations of numbers of people in the n rooms now, modulo (10^9 + 7).

Sample Input 1

3 2

Sample Output 1

10

Let c_1, c_2, and c_3 be the number of people in Room 1, 2, and 3 now, respectively. There are 10 possible combination of (c_1, c_2, c_3):

(0, 0, 3)

(0, 1, 2)

(0, 2, 1)

(0, 3, 0)

(1, 0, 2)

(1, 1, 1)

(1, 2, 0)

(2, 0, 1)

(2, 1, 0)

(3, 0, 0)

For example, (c_1, c_2, c_3) will be (0, 1, 2) if the person in Room 1 goes to Room 2 and then one of the persons in Room 2 goes to Room 3.

Sample Input 2

200000 1000000000

Sample Output 2

607923868

Print the count modulo (10^9 + 7).

Sample Input 3

15 6

Sample Output 3

22583772

Solution in Python (3.4.3) (judge verdict: Accepted)

def main():
    import sys
    input = sys.stdin.readline
    sys.setrecursionlimit(10**7)
    from collections import Counter, deque
    #from collections import defaultdict
    from itertools import combinations, permutations, accumulate, groupby, product
    from bisect import bisect_left,bisect_right
    from heapq import heapify, heappop, heappush
    import math

    #inf = 10**17
    mod = 10**9 + 7

    max_n = 2*(10**5)
    fac, inv = [1]*(max_n+1), [0]*(max_n+1)
    for i in range(2, max_n+1):
        fac[i] = fac[i-1] * i % mod
    inv[-1] = pow(fac[-1], mod-2, mod)
    for i in range(max_n, 0, -1):
        inv[i-1] = inv[i] * i % mod

    # nCrを求める
    def ncr(n, r):
        return fac[n]*inv[r]*inv[n-r]%mod

    n, k = map(int, input().split())
    res = 0
    # i:空き部屋の数
    for i in range(n):
        if i > k:
            continue
        res += ncr(n, i) * ncr(n-1, i)
        res %= mod
    print(res)

if __name__ == '__main__':
    main()