Problem:
Score : 400 points

Problem Statement

Given are positive integers A and B.

Let us choose some number of positive common divisors of A and B.

Here, any two of the chosen divisors must be coprime.

At most, how many divisors can we choose?

Definition of common divisor

An integer d is said to be a common divisor of integers x and y when d divides both x and y.

Definition of being coprime

Integers x and y are said to be coprime when x and y have no positive common divisors other than 1.

Definition of dividing

An integer x is said to divide another integer y when there exists an integer \alpha such that y = \alpha x.

Constraints

All values in input are integers.

1 \leq A, B \leq 10^{12}

Input

Input is given from Standard Input in the following format:

A B

Output

Print the maximum number of divisors that can be chosen to satisfy the condition.

Sample Input 1

12 18

Sample Output 1

3

12 and 18 have the following positive common divisors: 1, 2, 3, and 6.

1 and 2 are coprime, 2 and 3 are coprime, and 3 and 1 are coprime, so we can choose 1, 2, and 3, which achieve the maximum result.

Sample Input 2

420 660

Sample Output 2

4

Sample Input 3

1 2019

Sample Output 3

1

1 and 2019 have no positive common divisors other than 1.

Solution in Python (3.8.2) (judge verdict: Runtime Error)

A, B = map(int,input().split())

def make_divisors(n):
    divisors = set()
    for i in range(1, int(n**0.5)+1):
        if n % i == 0:
            divisors.add(i)
            divisors.add(n//i)
    return divisors

lst_A = make_divisors(A)
lst_B = make_divisors(B)
cmn_lst = lst_A & lst_B
cmn = list(cmn_lst)
m = max(cmn)

hurui = [1] * (m+1)
hurui[0] = 0
for j in range(2, m//2+1):
    for k in range(j, m+1, j):
        if k == j:
            continue
        hurui[k] += 1

cand = set()
for i, v in enumerate(hurui):
    if v == 1:
        cand.add(i)
print(len(cand & cmn_lst))