Problem:
Score : 400 points

Problem Statement

There are N people standing on the x-axis.
Let the coordinate of Person i be x_i.
For every i, x_i is an integer between 0 and 10^9 (inclusive).
It is possible that more than one person is standing at the same coordinate.

You will given M pieces of information regarding the positions of these people.
The i-th piece of information has the form (L_i, R_i, D_i).
This means that Person R_i is to the right of Person L_i by D_i units of distance, that is, x_{R_i} - x_{L_i} = D_i holds.

It turns out that some of these M pieces of information may be incorrect.
Determine if there exists a set of values (x_1, x_2, ..., x_N) that is consistent with the given pieces of information.

Constraints

1 \leq N \leq 100 000

0 \leq M \leq 200 000

1 \leq L_i, R_i \leq N (1 \leq i \leq M)

0 \leq D_i \leq 10 000 (1 \leq i \leq M)

L_i \neq R_i (1 \leq i \leq M)

If i \neq j, then (L_i, R_i) \neq (L_j, R_j) and (L_i, R_i) \neq (R_j, L_j).

D_i are integers.

Input

Input is given from Standard Input in the following format:

N M
L_1 R_1 D_1
L_2 R_2 D_2
:
L_M R_M D_M

Output

If there exists a set of values (x_1, x_2, ..., x_N) that is consistent with all given pieces of information, print Yes; if it does not exist, print No.

Sample Input 1

3 3
1 2 1
2 3 1
1 3 2

Sample Output 1

Yes

Some possible sets of values (x_1, x_2, x_3) are (0, 1, 2) and (101, 102, 103).

Sample Input 2

3 3
1 2 1
2 3 1
1 3 5

Sample Output 2

No

If the first two pieces of information are correct, x_3 - x_1 = 2 holds, which is contradictory to the last piece of information.

Sample Input 3

4 3
2 1 1
2 3 5
3 4 2

Sample Output 3

Yes

Sample Input 4

10 3
8 7 100
7 9 100
9 8 100

Sample Output 4

No

Sample Input 5

100 0

Sample Output 5

Yes

Solution in PyPy3 (2.4.0) (judge verdict: Time Limit Exceeded)

#!/usr/bin/env python3
import sys
from collections import defaultdict, deque

YES = "Yes"  # type: str
NO = "No"  # type: str

def solve(N: int, M: int, L: "List[int]", R: "List[int]", D: "List[int]"):
    visited = 0
    pos = [None] * N
    adj = [set() for _ in range(N)]

    for l, r, d in zip(L, R, D):
        adj[l].add((r, d))
        adj[r].add((l, -d))
    
    for i in range(N):
        if (visited >> i) % 2 == 1:
            continue
        pos[i] = 0
        Q = deque([i], M)
        while len(Q) > 0:
            u = Q.popleft()
            visited |= 1 << u
            for v, d in adj[u]:
                if pos[v] is None:
                    pos[v] = pos[u] + d
                elif pos[v] != pos[u] + d:
                    print(NO)
                    return

                if (visited >> v) % 2 == 1:
                    continue
                Q.append(v)
    print(YES)
    return


# Generated by 1.1.4 https://github.com/kyuridenamida/atcoder-tools  (tips: You use the default template now. You can remove this line by using your custom template)
def main():
    def iterate_tokens():
        for line in sys.stdin:
            for word in line.split():
                yield word
    tokens = iterate_tokens()
    N = int(next(tokens))  # type: int
    M = int(next(tokens))  # type: int
    L = [int()] * (M)  # type: "List[int]" 
    R = [int()] * (M)  # type: "List[int]" 
    D = [int()] * (M)  # type: "List[int]" 
    for i in range(M):
        L[i] = int(next(tokens)) - 1
        R[i] = int(next(tokens)) - 1
        D[i] = int(next(tokens))
    solve(N, M, L, R, D)

if __name__ == '__main__':
    main()