Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

n = int(input())


def 約数(n):
	count = 0
	for i in range(2,n):
		while n%i == 0:
			n /= i
			count += 1
	if count == 8:
		return True
	else:
		return
if n == 105:
	print(1)
elif n < 105:
	print(0)
else:
	ans = 1
	for i in range(106,n+1):
		if i%2 !=0:
			if 約数(i):
				ans += 1


	print(ans)