Problem:
Score : 600 points

Problem Statement

A bracket sequence is a string that is one of the following:

An empty string;

The concatenation of (, A, and ) in this order, for some bracket sequence A ;

The concatenation of A and B in this order, for some non-empty bracket sequences A and B /

Given are N strings S_i. Can a bracket sequence be formed by concatenating all the N strings in some order?

Constraints

1 \leq N \leq 10^6

The total length of the strings S_i is at most 10^6.

S_i is a non-empty string consisting of ( and ).

Input

Input is given from Standard Input in the following format:

N
S_1
:
S_N

Output

If a bracket sequence can be formed by concatenating all the N strings in some order, print Yes; otherwise, print No.

Sample Input 1

2
)
(()

Sample Output 1

Yes

Concatenating (() and ) in this order forms a bracket sequence.

Sample Input 2

2
)(
()

Sample Output 2

No

Sample Input 3

4
((()))
((((((
))))))
()()()

Sample Output 3

Yes

Sample Input 4

3
(((
)
)

Sample Output 4

No

Solution in Python (3.8.2) (judge verdict: Wrong Answer)

from sys import stdin

def main():
    readline = stdin.readline
    n = int(readline())
    s = tuple(readline().strip() for _ in range(n))

    plus, minus = [], []
    for c in s:
        if 2*c.count('(') - len(c) > 0:
            plus.append(c)
        else:
            minus.append(c)

    plus.sort(key = lambda x: x.count(')'), reverse = True)
    minus.sort(key = lambda x: x.count('('))
    plus.extend(minus)
    sum = 0
    for v in plus:
        for vv in v:
            sum = sum + (1 if vv == '(' else -1)
            if sum < 0 : return print('No')
    if sum != 0:
        return print('No')

    return print('Yes')

if __name__ == '__main__':
    main()