Problem:
Score : 400 points

Problem Statement

An altar enshrines N stones arranged in a row from left to right. The color of the i-th stone from the left (1 \leq i \leq N) is given to you as a character c_i; R stands for red and W stands for white.

You can do the following two kinds of operations any number of times in any order:

Choose two stones (not necessarily adjacent) and swap them.

Choose one stone and change its color (from red to white and vice versa).

According to a fortune-teller, a white stone placed to the immediate left of a red stone will bring a disaster. At least how many operations are needed to reach a situation without such a white stone?

Constraints

2 \leq N \leq 200000

c_i is R or W.

Input

Input is given from Standard Input in the following format:

N
c_{1}c_{2}...c_{N}

Output

Print an integer representing the minimum number of operations needed.

Sample Input 1

4
WWRR

Sample Output 1

2

For example, the two operations below will achieve the objective.

Swap the 1-st and 3-rd stones from the left, resulting in RWWR.

Change the color of the 4-th stone from the left, resulting in RWWW.

Sample Input 2

2
RR

Sample Output 2

0

It can be the case that no operation is needed.

Sample Input 3

8
WRWWRWRR

Sample Output 3

3

Solution in PyPy3 (7.3.0) (judge verdict: Accepted)

n=int(input())
from collections import deque
queue=deque(input())
#print(queue)
#C=[0]*n
s=0
while len(queue)>1:
    a=queue.popleft()
    b=queue.pop()
    if a=='W' and b=='R':
        s+=1
        #print(s)
    elif a=='W' and b=='W':
        while queue and b=='W':
            b=queue.pop()
        if b=='R':
            s+=1
    elif a=='R' and b=='R':
        while queue and a=='R':
            a=queue.popleft()
        if a=='W':
            s+=1                
print(s)