Problem:
Score : 500 points

Problem Statement

Given are N integers A_1,\ldots,A_N.

We will choose exactly K of these elements. Find the maximum possible product of the chosen elements.

Then, print the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).

Constraints

1 \leq K \leq N \leq 2\times 10^5

|A_i| \leq 10^9

Input

Input is given from Standard Input in the following format:

N K
A_1 \ldots A_N

Output

Print the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).

Sample Input 1

4 2
1 2 -3 -4

Sample Output 1

12

The possible products of the two chosen elements are 2, -3, -4, -6, -8, and 12, so the maximum product is 12.

Sample Input 2

4 3
-1 -2 -3 -4

Sample Output 2

1000000001

The possible products of the three chosen elements are -24, -12, -8, and -6, so the maximum product is -6.

We print this value modulo (10^9+7), that is, 1000000001.

Sample Input 3

2 1
-1 1000000000

Sample Output 3

1000000000

The possible products of the one chosen element are -1 and 1000000000, so the maximum product is 1000000000.

Sample Input 4

10 10
1000000000 100000000 10000000 1000000 100000 10000 1000 100 10 1

Sample Output 4

999983200

Be sure to print the product modulo (10^9+7).

Solution in Python (3.8.2) (judge verdict: Wrong Answer)

n, k = map(int, input().split())
a = list(map(int, input().split()))
a = sorted(a, key = abs)[::-1]
ans = 1
hold = 0

if max(a) < 0:
    a = sorted(a)[::-1]
    for i in range(k):
        ans = ans*a[i]%(10**9 + 7)
    print(ans)
    exit()



for i in range(k - 1):
    if a[i] >= 0:
        ans = ans*a[i]%(10**9 + 7)
    else:
        if hold == 0:
            hold = a[i]
        else:
            ans = ans*a[i]*hold%(10**9 + 7)
            hold = 0

for j in range(k - 1, n):
    if a[j] < 0 and hold != 0:
        ans = ans*a[j]*hold%(10**9 + 7)
        print(ans)
        exit()
    elif a[j] >= 0:
        ans = ans*a[j]%(10**9 + 7)
        print(ans)
        exit()