Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in PyPy3 (7.3.0) (judge verdict: Wrong Answer)

import sys
input = lambda: sys.stdin.readline().rstrip()
D = {"AB": 2, "AC": 1, "BC": 0}
N, a, b, c = map(int, input().split())
X = [a, b, c]
S = [D[input()] for _ in range(N)]
ANS = []
if max(X) == 0:
    print("No")
    exit()

if sum(X) == 1:
    t = 0 if a else 1 if b else 2
    for s in S:
        if X[s]:
            print("No")
            exit()
        t ^= s ^ 3
        ANS.append(t)
        X[s-1] ^= 1
        X[s-2] ^= 1

s = S[0]
if X[s-1] + X[s-2] == 0:
    print("No")
    exit()

for i, s in enumerate(S):
    if X[s-1] > X[s-2]:
        ANS.append((s-2) % 3)
        X[s-1] -= 1
        X[s-2] += 1
    elif X[s-1] > X[s-2]:
        ANS.append((s-1) % 3)
        X[s-1] += 1
        X[s-2] -= 1
    elif i == N - 1 or S[i+1] == s-1:
        ANS.append((s-2) % 3)
        X[s-1] -= 1
        X[s-2] += 1
    else:
        ANS.append((s-1) % 3)
        X[s-1] += 1
        X[s-2] -= 1

print("Yes")
print("\n".join([chr(t+65) for t in ANS]))