Problem:
Score : 200 points

Problem Statement

Sig has built his own keyboard. Designed for ultimate simplicity, this keyboard only has 3 keys on it: the 0 key, the 1 key and the backspace key.

To begin with, he is using a plain text editor with this keyboard. This editor always displays one string (possibly empty). Just after the editor is launched, this string is empty. When each key on the keyboard is pressed, the following changes occur to the string:

The 0 key: a letter 0 will be inserted to the right of the string.

The 1 key: a letter 1 will be inserted to the right of the string.

The backspace key: if the string is empty, nothing happens. Otherwise, the rightmost letter of the string is deleted.

Sig has launched the editor, and pressed these keys several times. You are given a string s, which is a record of his keystrokes in order. In this string, the letter 0 stands for the 0 key, the letter 1 stands for the 1 key and the letter B stands for the backspace key. What string is displayed in the editor now?

Constraints

1 ≦ |s| ≦ 10 (|s| denotes the length of s)

s consists of the letters 0, 1 and B.

The correct answer is not an empty string.

Input

The input is given from Standard Input in the following format:

s

Output

Print the string displayed in the editor in the end.

Sample Input 1

01B0

Sample Output 1

00

Each time the key is pressed, the string in the editor will change as follows: 0, 01, 0, 00.

Sample Input 2

0BB1

Sample Output 2

1

Each time the key is pressed, the string in the editor will change as follows: 0, (empty), (empty), 1.

Solution in Python (3.8.2) (judge verdict: Accepted)

# https://atcoder.jp/contests/abc043/tasks/abc043_b

"""
双方向キューをつかって実装する

このどれかの操作ができる
* 0 をキューに入れる
* 1 をキューに入れる
* キューの最後のものを出す

注意: キューが空の場合にバックスペースをしても何も起きないようにする
"""

from collections import deque

q = deque()

s = input()
for operation in s:
    if operation == "0":
        # 右端に0を追加
        q.append("0")

    elif operation == "1":
        # 右端に1を追加
        q.append("1")

    elif operation == "B":
        # バックスペース
        # 右端を一つ削除
        # q の中身が空でもエラーにならないように例外処理
        try:
            q.pop()
        except IndexError:
            pass # 何もしない

# キューの中身を順番に取り出して文字列に変換
answer = ""
for i in q:
    answer = answer + i

print(answer)