Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in PyPy3 (7.3.0) (judge verdict: Wrong Answer)

#!/usr/bin/env python
# -*- coding: utf-8 -*-

import sys
sys.setrecursionlimit(10**7)
from pprint import pprint as pp
from pprint import pformat as pf

import math
#from sortedcontainers import SortedList, SortedDict, SortedSet # no in atcoder
import bisect


class Player():

    A = 0
    B = 1
    C = 2

    def __init__(self, data, op_list):
        self.data = data
        self.op_list = op_list
        self.move_history = ["X"] * len(self.op_list)
        self.key = 0
        self.ans = "Yes" # "Yes" or "No"
        self.flg_out = False
        self.flg_foresight = False
        s = sum(data)
        if s == 2:
            self.flg_foresight = True
        elif s == 0 or s == 1:
            self.ans = "No"
            self.flg_out = True

    def has_next_op(self):
        if self.key + 1 < len(self.op_list):
            return True
        else:
            return False

    def play(self):
        for key, op in enumerate(op_list):
            #print('self.data') # debug
            #print(self.data) # debug
            if self.flg_out:
                break
            self.key = key
            self.read_op(op)

    def read_op(self, op):
        if op == "AB":
            self.do(self.A, self.B)
        if op == "AC":
            self.do(self.A, self.C)
        if op == "BC":
            self.do(self.B, self.C)

    def do(self, x, y):
        if self.data[x] < self.data[y]:
            self.move(y, x)
        elif self.data[x] > self.data[y]:
            self.move(x, y)
        else: # same
            if self.flg_foresight:
                if self.is_next_used(x):
                    self.move(y, x)
                else:
                    self.move(x, y)
            else:
                self.move(x, y) # which is ok

    def move(self, frm, to):
        self.move_history[self.key] = self.num_to_char(to)
        self.data[frm] -= 1
        self.data[to] += 1
        if self.data[frm] < 0:
            self.ans = "No"
            self.flg_out = True

    @staticmethod
    def num_to_char(z):
        chars = ['A', 'B', 'C']
        return chars[z]

    def is_next_used(self, z):
        if not self.has_next_op():
            return False
        next_op = self.op_list[self.key + 1]
        if self.num_to_char(z) in next_op:
            return True
        else:
            return False

    def print_ans(self):
        print(self.ans)
        if self.ans == "No":
            return
        for h in self.move_history:
            print(h)




if __name__ == '__main__':
    n, a, b, c = list(map(int, input().split()))
    data = [a, b, c]
    #print('data') # debug
    #print(data) # debug
    op_list = [""] * n
    for i in range(n):
        op_list[i] = input()
    #print('op_list') # debug
    #print(op_list) # debug

    p = Player(data, op_list)
    p.play()
    p.print_ans()


    #print('\33[32m' + 'end' + '\033[0m') # debug