Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Python (3.8.2) (judge verdict: Accepted)

# -*- coding: utf-8 -*-
"""
Created on Sun Aug  9 20:50:35 2020

@author: akros
"""

# -*- coding: utf-8 -*-
"""
Created on Sun Aug  9 16:51:42 2020

@author: akros
"""

A1 = list(map(int, input().split()))
A2 = list(map(int, input().split()))
A3 = list(map(int, input().split()))

N = int(input())
a = []

for i in range(N):
    a.append(int(input()))
   
    if A1[0] == a[i]:
        A1[0] = True
    elif a[i] == A1[1]:
        A1[1] = True
    elif a[i] == A1[2]:
        A1[2] = True
    elif a[i] == A2[0]:
        A2[0] = True
    elif a[i] == A2[1]:
        A2[1] = True
    elif a[i] == A2[2]:
        A2[2] = True
    elif a[i] == A3[0]:
        A3[0] = True
    elif a[i] == A3[1]:
        A3[1] = True
    elif a[i] == A3[2]:
        A3[2] = True


if A1[0] == True and A1[1] == True and A1[2] == True:
    print("Yes")
elif A1[0] == True and A2[0] == True and A3[0] == True:
    print("Yes")
elif A1[0] == True and A2[1] == True and A3[2] == True:
    print("Yes")
elif A1[1] == True and A2[1] == True and A3[1] == True:
    print("Yes")
elif A1[2] == True and A2[2] == True and A3[2] == True:
    print("Yes")
elif A2[0] == True and A2[1] == True and A2[2] == True:
    print("Yes")
elif A3[0] == True and A3[1] == True and A3[2] == True:
    print("Yes")
elif A1[2] == True and A2[1] == True and A3[0] == True:
    print("Yes")
    
else:             
    print("No")