Problem:
Score : 400 points

Problem Statement

We have a grid with H rows and W columns. The square at the i-th row and the j-th column will be called Square (i,j).

The integers from 1 through H×W are written throughout the grid, and the integer written in Square (i,j) is A_{i,j}.

You, a magical girl, can teleport a piece placed on Square (i,j) to Square (x,y) by consuming |x-i|+|y-j| magic points.

You now have to take Q practical tests of your ability as a magical girl.

The i-th test will be conducted as follows:

Initially, a piece is placed on the square where the integer L_i is written.

Let x be the integer written in the square occupied by the piece. Repeatedly move the piece to the square where the integer x+D is written, as long as x is not R_i. The test ends when x=R_i.

Here, it is guaranteed that R_i-L_i is a multiple of D.

For each test, find the sum of magic points consumed during that test.

Constraints

1 \leq H,W \leq 300

1 \leq D \leq H×W

1 \leq A_{i,j} \leq H×W

A_{i,j} \neq A_{x,y} ((i,j) \neq (x,y))

1 \leq Q \leq 10^5

1 \leq L_i \leq R_i \leq H×W

(R_i-L_i) is a multiple of D.

Input

Input is given from Standard Input in the following format:

H W D
A_{1,1} A_{1,2} ... A_{1,W}
:
A_{H,1} A_{H,2} ... A_{H,W}
Q
L_1 R_1
:
L_Q R_Q

Output

For each test, print the sum of magic points consumed during that test.

Output should be in the order the tests are conducted.

Sample Input 1

3 3 2
1 4 3
2 5 7
8 9 6
1
4 8

Sample Output 1

5

4 is written in Square (1,2).

6 is written in Square (3,3).

8 is written in Square (3,1).

Thus, the sum of magic points consumed during the first test is (|3-1|+|3-2|)+(|3-3|+|1-3|)=5.

Sample Input 2

4 2 3
3 7
1 4
5 2
6 8
2
2 2
2 2

Sample Output 2

0
0

Note that there may be a test where the piece is not moved at all, and there may be multiple identical tests.

Sample Input 3

5 5 4
13 25 7 15 17
16 22 20 2 9
14 11 12 1 19
10 6 23 8 18
3 21 5 24 4
3
13 13
2 10
13 13

Sample Output 3

0
5
0

Solution in Python (3.4.3) (judge verdict: Accepted)

# https://atcoder.jp/contests/abc089/tasks/abc089_d

# queryがたくさんある系
# query一つにつきO(1)ぐらいで応答しないと行けない→前処理の必要あり

# あるマスについてはD倍したマスだけ把握しておけばいいんじゃない？
'''
D=2
1 4 3
2 5 7
8 9 6
'''
# だったらstart=1,2において、移動のスコアの累積和を入れていく
# Qに回答時は、L%D番目のstartの累積和において、L//Dにおいて累積和の差を求めれば良い
# ピッタリDだった場合に面倒なので-0.5して置くのは良いかもしれない

from collections import defaultdict
from itertools import accumulate
import sys
read = sys.stdin.readline


def read_ints():
    return list(map(int, read().split()))


def read_matrix(H):
    '''
    H is number of rows
    '''
    return [list(map(int, read().split())) for _ in range(H)]


def get_cost(i, j, x, y):
    return abs(x - i) + abs(y - j)


H, W, D = read_ints()
A = read_matrix(H)
ruiseki = defaultdict(lambda: [])
num_to_co = {}

for i, a in enumerate(A):
    for j, aa in enumerate(a):
        num_to_co[aa] = (i, j)

for num in range(1, D + 1):
    pre_i, pre_j = num_to_co[num]
    pre_num = num
    ruiseki[num].append(0)
    while W * H >= pre_num + D:
        now_num = pre_num + D
        i, j = num_to_co[now_num]
        cost = get_cost(pre_i, pre_j, i, j)
        ruiseki[num].append(cost)
        # 必要なもの、前のi,j今のi,j 今の番号
        # 更新するもの 前のi,j←今のi,j 今の番号を次の番号に
        pre_i, pre_j = i, j
        pre_num = now_num

    ruiseki[num] = list(accumulate(ruiseki[num]))
# print(ruiseki)

# Qに答える番だ
Q = int(input())
for _ in range(Q):
    L, R = read_ints()
    tmp = ruiseki[L % D if L % D != 0 else D]
    # print(tmp)
    # print((R - 1) // D, (L - 1) // D)
    print(tmp[(R - 1) // D] - tmp[(L - 1) // D])