Problem:
Score : 300 points

Problem Statement

We have N switches with "on" and "off" state, and M bulbs. The switches are numbered 1 to N, and the bulbs are numbered 1 to M.

Bulb i is connected to k_i switches: Switch s_{i1}, s_{i2}, ..., and s_{ik_i}. It is lighted when the number of switches that are "on" among these switches is congruent to p_i modulo 2.

How many combinations of "on" and "off" states of the switches light all the bulbs?

Constraints

1 \leq N, M \leq 10

1 \leq k_i \leq N

1 \leq s_{ij} \leq N

s_{ia} \neq s_{ib} (a \neq b)

p_i is 0 or 1.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
k_1 s_{11} s_{12} ... s_{1k_1}
:
k_M s_{M1} s_{M2} ... s_{Mk_M}
p_1 p_2 ... p_M

Output

Print the number of combinations of "on" and "off" states of the switches that light all the bulbs.

Sample Input 1

2 2
2 1 2
1 2
0 1

Sample Output 1

1

Bulb 1 is lighted when there is an even number of switches that are "on" among the following: Switch 1 and 2.

Bulb 2 is lighted when there is an odd number of switches that are "on" among the following: Switch 2.

There are four possible combinations of states of (Switch 1, Switch 2): (on, on), (on, off), (off, on) and (off, off). Among them, only (on, on) lights all the bulbs, so we should print 1.

Sample Input 2

2 3
2 1 2
1 1
1 2
0 0 1

Sample Output 2

0

Bulb 1 is lighted when there is an even number of switches that are "on" among the following: Switch 1 and 2.

Bulb 2 is lighted when there is an even number of switches that are "on" among the following: Switch 1.

Bulb 3 is lighted when there is an odd number of switches that are "on" among the following: Switch 2.

Switch 1 has to be "off" to light Bulb 2 and Switch 2 has to be "on" to light Bulb 3, but then Bulb 1 will not be lighted. Thus, there are no combinations of states of the switches that light all the bulbs, so we should print 0.

Sample Input 3

5 2
3 1 2 5
2 2 3
1 0

Sample Output 3

8

Solution in Python (3.8.2) (judge verdict: Accepted)

import copy

def dfs(i,lst):
    global ans
    if i==n:
        ans.append(lst)
        return
    tmp1 = copy.copy(lst)
    tmp1.append(0)
    dfs(i+1,tmp1)
    tmp2 = copy.copy(lst)
    tmp2.append(1)
    dfs(i+1,tmp2)

n,m = map(int,input().split())
ans = []
tmp = [0]
dfs(0,tmp)
#print(ans)
s = []
k = []
for i in range(m):
    tmp = list(map(int,input().split()))
    k.append(tmp[0])
    s.append(tmp[1:])
p = list(map(int,input().split()))
#print(k)
#print(s)
#print(p)
cnt = 0
for i in range(len(ans)):
    cnt_i = 0
    for mi in range(m):
        sum_s = 0
        for ki in range(len(s[mi])):
            sum_s += ans[i][s[mi][ki]]
        if sum_s%2==p[mi]:
            cnt_i += 1
    if cnt_i==m:
        cnt += 1
print(cnt)