Problem:
Score : 500 points

Problem Statement

There is a building with n rooms, numbered 1 to n.

We can move from any room to any other room in the building.

Let us call the following event a move: a person in some room i goes to another room j~ (i \neq j).

Initially, there was one person in each room in the building.

After that, we know that there were exactly k moves happened up to now.

We are interested in the number of people in each of the n rooms now. How many combinations of numbers of people in the n rooms are possible?

Find the count modulo (10^9 + 7).

Constraints

All values in input are integers.

3 \leq n \leq 2 \times 10^5

2 \leq k \leq 10^9

Input

Input is given from Standard Input in the following format:

n k

Output

Print the number of possible combinations of numbers of people in the n rooms now, modulo (10^9 + 7).

Sample Input 1

3 2

Sample Output 1

10

Let c_1, c_2, and c_3 be the number of people in Room 1, 2, and 3 now, respectively. There are 10 possible combination of (c_1, c_2, c_3):

(0, 0, 3)

(0, 1, 2)

(0, 2, 1)

(0, 3, 0)

(1, 0, 2)

(1, 1, 1)

(1, 2, 0)

(2, 0, 1)

(2, 1, 0)

(3, 0, 0)

For example, (c_1, c_2, c_3) will be (0, 1, 2) if the person in Room 1 goes to Room 2 and then one of the persons in Room 2 goes to Room 3.

Sample Input 2

200000 1000000000

Sample Output 2

607923868

Print the count modulo (10^9 + 7).

Sample Input 3

15 6

Sample Output 3

22583772

Solution in PyPy3 (2.4.0) (judge verdict: Wrong Answer)

import math
n,k= map(int, input().split())


def combinations_count(n, r):
    return math.factorial(n) // (math.factorial(n - r) * math.factorial(r))

def cmb(n, r, mod):
    if (r < 0 or r > n):
        return 0
    r=min(r,n-r)

    return g1[n] * g2[r] * g2[n - r] % mod

mod = 10 ** 9 + 7
N =10 ** 6 # 出力の制限
g1 = [1, 1]  # 元テーブル
g2 = [1, 1]  # 逆元テーブル
inverse = [0, 1]  # 逆元テーブル計算用テーブル

for i in range(2, N + 1):
    g1.append((g1[-1] * i) % mod)
    inverse.append((-inverse[mod % i] * (mod // i)) % mod)
    g2.append((g2[-1] * inverse[-1]) % mod)



if k>=n-1:
    ans = cmb(2 * n - 1, n - 1, mod)
    print(ans)
else:
    ans=0
    for i in range(1,k+1):
        ans+=cmb(n-1,n-1-i,mod)*cmb(n,i,mod)
        ans%mod
    print(ans+1)