Problem:
Score : 400 points

Problem Statement

You are given an undirected connected weighted graph with N vertices and M edges that contains neither self-loops nor double edges.

The i-th (1≤i≤M) edge connects vertex a_i and vertex b_i with a distance of c_i.

Here, a self-loop is an edge where a_i = b_i (1≤i≤M), and double edges are two edges where (a_i,b_i)=(a_j,b_j) or (a_i,b_i)=(b_j,a_j) (1≤i<j≤M).

A connected graph is a graph where there is a path between every pair of different vertices.

Find the number of the edges that are not contained in any shortest path between any pair of different vertices.

Constraints

2≤N≤100

N-1≤M≤min(N(N-1)/2,1000)

1≤a_i,b_i≤N

1≤c_i≤1000

c_i is an integer.

The given graph contains neither self-loops nor double edges.

The given graph is connected.

Input

The input is given from Standard Input in the following format:

N M
a_1 b_1 c_1
a_2 b_2 c_2
:
a_M b_M c_M

Output

Print the number of the edges in the graph that are not contained in any shortest path between any pair of different vertices.

Sample Input 1

3 3
1 2 1
1 3 1
2 3 3

Sample Output 1

1

In the given graph, the shortest paths between all pairs of different vertices are as follows:

The shortest path from vertex 1 to vertex 2 is: vertex 1 → vertex 2, with the length of 1.

The shortest path from vertex 1 to vertex 3 is: vertex 1 → vertex 3, with the length of 1.

The shortest path from vertex 2 to vertex 1 is: vertex 2 → vertex 1, with the length of 1.

The shortest path from vertex 2 to vertex 3 is: vertex 2 → vertex 1 → vertex 3, with the length of 2.

The shortest path from vertex 3 to vertex 1 is: vertex 3 → vertex 1, with the length of 1.

The shortest path from vertex 3 to vertex 2 is: vertex 3 → vertex 1 → vertex 2, with the length of 2.

Thus, the only edge that is not contained in any shortest path, is the edge of length 3 connecting vertex 2 and vertex 3, hence the output should be 1.

Sample Input 2

3 2
1 2 1
2 3 1

Sample Output 2

0

Every edge is contained in some shortest path between some pair of different vertices.

Solution in PyPy3 (2.4.0) (judge verdict: Runtime Error)

n,m =map(int,input().split())
inf = 10**15

dist = [[inf for i in range(n)] for i in range(n)]
route = [[ [] for i in range(n)] for i in range(n)]
import copy

for i in range(m):
    ak,bk,ck = map(int,input().split())
    dist[ak-1][bk-1]  =ck
    dist[bk-1][ak-1]  =ck

for i in range(n):
    for k in range(n):
        route[i][k] = [i,k]
        route[k][i] = [k,i]

for a in range(n):
    for b in range(n):
        for c in range(n):
            if dist[b][a]+dist[a][c] < dist[b][c]:
                if route[b][a] == None:
                    route[b][c] = copy.deepcopy(route[a][c])[1:]
                else:
                    route[b][c] = copy.deepcopy(route[b][a]).extend(copy.deepcopy(route[a][c])[1:])
                dist[b][c] =  dist[b][a]+dist[a][c]

ans = 0
for i in range(n):
    for k in range(n):
        if route[i][k]:
            ans += 1

print(m-ans//2)