Problem:
Score : 300 points

Problem Statement

There are N people standing in a row from west to east.
Each person is facing east or west.
The directions of the people is given as a string S of length N.
The i-th person from the west is facing east if S_i = E, and west if S_i = W.

You will appoint one of the N people as the leader, then command the rest of them to face in the direction of the leader.
Here, we do not care which direction the leader is facing.

The people in the row hate to change their directions, so you would like to select the leader so that the number of people who have to change their directions is minimized.
Find the minimum number of people who have to change their directions.

Constraints

2 \leq N \leq 3 \times 10^5

|S| = N

S_i is E or W.

Input

Input is given from Standard Input in the following format:

N
S

Output

Print the minimum number of people who have to change their directions.

Sample Input 1

5
WEEWW

Sample Output 1

1

Assume that we appoint the third person from the west as the leader.
Then, the first person from the west needs to face east and has to turn around.
The other people do not need to change their directions, so the number of people who have to change their directions is 1 in this case.
It is not possible to have 0 people who have to change their directions, so the answer is 1.

Sample Input 2

12
WEWEWEEEWWWE

Sample Output 2

4

Sample Input 3

8
WWWWWEEE

Sample Output 3

3

Solution in PyPy3 (7.3.0) (judge verdict: Accepted)

import sys
from sys import exit
from collections import deque
from bisect import bisect_left, bisect_right, insort_left, insort_right #func(リスト,値)
from heapq import heapify, heappop, heappush
from itertools import product, permutations, combinations, combinations_with_replacement
from functools import reduce
from math import *

sys.setrecursionlimit(10**6)
INF = 10**20
eps = 1.0e-20
MOD = 10**9+7

def lcm(x,y):
    return x*y//gcd(x,y)
def lgcd(l):
    return reduce(gcd,l)
def llcm(l):
    return reduce(lcm,l)
def intput():
    return int(input())
def mint():
    return map(int,input().split())
def lint():
    return list(map(int,input().split()))
def ilint():
    return int(input()), list(map(int,input().split()))
def judge(x, l=['Yes', 'No']):
    print(l[0] if x else l[1])
def lprint(l, sep='\n'):
    for x in l:
        print(x, end=sep)
def ston(c, c0='a'):
    return ord(c)-ord(c0)
def ntos(x, c0='a'):
    return chr(x+ord(c0))
class counter(dict):
    def __init__(self, *args):
        super().__init__(args)
    def add(self,x):
        self.setdefault(x,0)
        self[x] += 1

N = intput()
S = input()
re = 0
for i in range(N):
    re = re+1 if S[i]=='E' else re
lw = 0
ans = INF
for i in range(N):
    re = re-1 if S[i]=='E' else re
    ans = min(ans,re+lw)
    lw = lw+1 if S[i]=='W' else lw
print(ans)