Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in PyPy3 (7.3.0) (judge verdict: Accepted)

from sys import stdin
from sys import setrecursionlimit
from math import ceil
from collections import Counter, deque, defaultdict
setrecursionlimit(1000000)

# INF = float('inf')
INF = int(1e10)

def input():
    return stdin.readline()[:-1]

def main():
    from builtins import int, map
    n = int(input())
    sum = 0
    for i in range(1, n + 1):
        if i % 3 != 0 and i % 5 != 0:
            sum += i
    print(sum)

if __name__ == '__main__':
    main()