Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

import sys

# 関数 solve は，もちろん，問題に応じて書き換える
def solve(n):
    listc = []
    for i in range(1,201):
        lista = []
        for j in range(1,201):
            if i%j == 0:
                lista.append(j)
        if len(lista) >= 8 and lista[-1] %2 != 0:
            listc.append(lista[-1])
    #print(listc)#デバッグ用
    for i in range(len(listc)):
        if n < listc[i]:
            return 0
        elif n >= listc[-(i+1)]:
            return len(listc)-i

# ここから下は，入力・出力形式が同じであれば，変えなくて良い．
def readQuestion():
    line = sys.stdin.readline().rstrip()
    return int(line)

def main():
    n = readQuestion()
    answer = solve(n)
    print(answer)
if __name__ == '__main__':
    main()