Problem:
Score : 500 points

Problem Statement

Takahashi has decided to work on K days of his choice from the N days starting with tomorrow.

You are given an integer C and a string S. Takahashi will choose his workdays as follows:

After working for a day, he will refrain from working on the subsequent C days.

If the i-th character of S is x, he will not work on Day i, where Day 1 is tomorrow, Day 2 is the day after tomorrow, and so on.

Find all days on which Takahashi is bound to work.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq K \leq N

0 \leq C \leq N

The length of S is N.

Each character of S is o or x.

Takahashi can choose his workdays so that the conditions in Problem Statement are satisfied.

Input

Input is given from Standard Input in the following format:

N K C
S

Output

Print all days on which Takahashi is bound to work in ascending order, one per line.

Sample Input 1

11 3 2
ooxxxoxxxoo

Sample Output 1

6

Takahashi is going to work on 3 days out of the 11 days. After working for a day, he will refrain from working on the subsequent 2 days.

There are four possible choices for his workdays: Day 1,6,10, Day 1,6,11, Day 2,6,10, and Day 2,6,11.

Thus, he is bound to work on Day 6.

Sample Input 2

5 2 3
ooxoo

Sample Output 2

1
5

There is only one possible choice for his workdays: Day 1,5.

Sample Input 3

5 1 0
ooooo

Sample Output 3

There may be no days on which he is bound to work.

Sample Input 4

16 4 3
ooxxoxoxxxoxoxxo

Sample Output 4

11
16

Solution in Python (3.4.3) (judge verdict: Runtime Error)

nkc=input().split()
K=int(nkc[1])
C=int(nkc[2])
s=input()
workday_list=[]
for i,youso in enumerate(s) :
  if youso=='o' :
    workday_list.append(i+1)
    

s=0

current_num=0
current_num1=1
list1=[]
list1.append(workday_list[0])
while(s<=K) :
  
  if current_num1>=len(workday_list):
    break
  elif workday_list[current_num1]-workday_list[current_num]>C :
    current_num=current_num1
    list1.append(workday_list[current_num1])
    s+=1
  else :
    current_num1=current_num1+1
m=0  

current_num2=len(workday_list)-1
current_num3=len(workday_list)-2
list2=[]
list2.append(workday_list[-1])
while(m<K) :
  
  if current_num3<=0:
    break
  elif workday_list[current_num2]-workday_list[current_num3]>C :
    current_num2=current_num3
    list2.append(workday_list[current_num3])
    m+=1
  else :
    current_num3=current_num3-1

list2.reverse()

for i in range(len(list1)) :
  if list1[i]==list2[i] :
    print(list1[i])