Problem:
Score : 400 points

Problem Statement

There is a knight - the chess piece - at the origin (0, 0) of a two-dimensional grid.

When the knight is at the square (i, j), it can be moved to either (i+1,j+2) or (i+2, j+1).

In how many ways can the knight reach the square (X, Y)?

Find the number of ways modulo 10^9 + 7.

Constraints

1 \leq X \leq 10^6

1 \leq Y \leq 10^6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

Print the number of ways for the knight to reach (X, Y) from (0, 0), modulo 10^9 + 7.

Sample Input 1

3 3

Sample Output 1

2

There are two ways: (0,0) \to (1,2) \to (3,3) and (0,0) \to (2,1) \to (3,3).

Sample Input 2

2 2

Sample Output 2

0

The knight cannot reach (2,2).

Sample Input 3

999999 999999

Sample Output 3

151840682

Print the number of ways modulo 10^9 + 7.

Solution in Python (3.4.3) (judge verdict: Accepted)

X, Y = map(int, input().split())
MOD = 10 ** 9 + 7

if (X + Y) % 3 != 0:
    print(0)
    exit()
if abs(X - Y) > (X + Y) // 3:
    print(0)
    exit()
    
n = (X + Y) // 3 + 1
k = ((X - Y) + n + 1) // 2
SIZE = max(n, k)

g1 = [1, 1]      # 元テーブル
g2 = [1, 1]      # 逆元テーブル
inverse = [0, 1] # 逆元テーブル計算用テーブル

def comb(n, r, mod):
    if r < 0 or r > n:
        return 0
    r = min(r, n - r)
    return g1[n] * g2[r] * g2[n - r] % mod

for i in range(2, SIZE):
    g1.append((g1[-1] * i) % MOD)
    inverse.append((-inverse[MOD % i] * (MOD // i) ) % MOD)
    g2.append((g2[-1] * inverse[-1]) % MOD)

print(comb(n - 1, k - 1, MOD))