Problem:
Score : 500 points

Problem Statement

You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)

Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

N, Q, i_q, l_q, and r_q are integers.

S is a string consisting of lowercase English letters.

c_q is a lowercase English letter.

1 \leq N \leq 500000

1 \leq Q \leq 20000

|S| = N

1 \leq i_q \leq N

1 \leq l_q \leq r_q \leq N

There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:

N
S
Q
Query_1
\vdots
Query_Q

Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:

1 i_q c_q

2 l_q r_q

Output

For each query of type 2, print a line containing the answer.

Sample Input 1

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7

Sample Output 1

3
1
5

In the first query, cdbb contains three kinds of letters: b , c , and d, so we print 3.

In the second query, S is modified to abcdzbd.

In the third query, a contains one kind of letter: a, so we print 1.

In the fourth query, S is modified to abcazbd.

In the fifth query, S does not change and is still abcazbd.

In the sixth query, abcazbd contains five kinds of letters: a, b, c, d, and z, so we print 5.

Solution in PyPy3 (2.4.0) (judge verdict: Accepted)

class BIT:
    def __init__(self, n):
        self.n = n
        self.data = [0] * (n + 1)
        self.el = [0] * (n + 1)

    def sum(self, i):
        s = 0
        while i > 0:
            s += self.data[i]
            i -= i & -i
        return s

    def add(self, i, x):
        # assert i > 0
        self.el[i] += x
        while i <= self.n:
            self.data[i] += x
            i += i & -i

    def get(self, i, j=None):
        if j is None:
            return self.el[i]
        return self.sum(j) - self.sum(i)


def main():
    import sys

    input = sys.stdin.readline

    n = int(input())  # 5 * 10 ** 5
    s = input().rstrip()

    base = ord('a')
    *s, = (ord(c) - base for c in s)

    q = int(input())  # 2 * 10 ** 4

    bits = [BIT(n + 1) for _ in range(26)]
    for i, x in enumerate(s, 1):
        bits[x].add(i, 1)

    ret = []
    for _ in range(q):
        query = iter(input().split())
        if next(query) == '1':
            # 変更
            pos = int(next(query))

            bf = s[pos - 1]
            char = ord(next(query)) - base

            bits[bf].add(pos, -1)
            s[pos - 1] = char

            bits[char].add(pos, 1)

        else:
            # 返答
            l = int(next(query))
            r = int(next(query))

            tt = 0
            for x in range(26):
                if bits[x].get(l - 1, r) > 0:
                    tt += 1
            ret.append(tt)

    print(*ret, sep='\n')


if __name__ == '__main__':
    main()

# import sys
#
# sys.setrecursionlimit(10 ** 7)
#
# input = sys.stdin.readline
# rstrip()
# int(input())
# map(int, input().split())