Problem:
Score : 300 points

Problem Statement

Takahashi is a teacher responsible for a class of N students.

The students are given distinct student numbers from 1 to N.

Today, all the students entered the classroom at different times.

According to Takahashi's record, there were A_i students in the classroom when student number i entered the classroom (including student number i).

From these records, reconstruct the order in which the students entered the classroom.

Constraints

1 \le N \le 10^5

1 \le A_i \le N

A_i \neq A_j (i \neq j)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \ldots A_N

Output

Print the student numbers of the students in the order the students entered the classroom.

Sample Input 1

3
2 3 1

Sample Output 1

3 1 2

First, student number 3 entered the classroom.

Then, student number 1 entered the classroom.

Finally, student number 2 entered the classroom.

Sample Input 2

5
1 2 3 4 5

Sample Output 2

1 2 3 4 5

Sample Input 3

8
8 2 7 3 4 5 6 1

Sample Output 3

8 2 4 5 6 7 3 1

Solution in PyPy3 (2.4.0) (judge verdict: Accepted)

# -*- coding: utf-8 -*-
import sys
import math
import os
import itertools
import _collections
import string
from functools import lru_cache
import heapq

class cin():
    def int():
        return int(sys.stdin.readline().rstrip())
    def string():
        return sys.stdin.readline().rstrip()
    def mapInt():
        return [int(x) for x in cin.string().split()]
    def stringList(n):
        return [input() for i in range(n)]
    def intListList(n):
        return [cin.mapInt() for i in range(n)]
    def intColsList(n):
        return [int(input()) for i in range(n)]
        
class Math():
    def gcd(a,b):
        if b == 0:
            return a
        return Math.gcd(b,a % b)
    def lcm(a,b):
        return (a * b) // Math.gcd(a,b)
    def roundUp(a,b):
        return -(-a // b)
    def toUpperMultiple(a,x):
        return Math.roundUp(a,x) * x
    def toLowerMultiple(a,x):
        return (a // x) * x
    def nearPow2(n):
        if n <= 0:
            return 0
        if n & (n - 1) == 0:
            return n
        ret = 1
        while(n > 0):
            ret <<= 1
            n >>= 1
        return ret

MOD = int(1e09) + 7

def main():
    N = cin.int()
    A = cin.mapInt()
    T = [0] * N
    for i in range(N): 
        T[A[i] - 1] = i + 1
    print(*T,sep =" ")
    return

if __name__ == "__main__":
    main()