Problem:
Score : 200 points

Problem Statement

There are N cities and M roads.
The i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally.
There may be more than one road that connects the same pair of two cities.
For each city, how many roads are connected to the city?

Constraints

2≤N,M≤50

1≤a_i,b_i≤N

a_i ≠ b_i

All input values are integers.

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
:
a_M b_M

Output

Print the answer in N lines.
In the i-th line (1≤i≤N), print the number of roads connected to city i.

Sample Input 1

4 3
1 2
2 3
1 4

Sample Output 1

2
2
1
1

City 1 is connected to the 1-st and 3-rd roads.

City 2 is connected to the 1-st and 2-nd roads.

City 3 is connected to the 2-nd road.

City 4 is connected to the 3-rd road.

Sample Input 2

2 5
1 2
2 1
1 2
2 1
1 2

Sample Output 2

5
5

Sample Input 3

8 8
1 2
3 4
1 5
2 8
3 7
5 2
4 1
6 8

Sample Output 3

3
3
2
2
2
1
1
2

Solution in Python (3.4.3) (judge verdict: Accepted)

from collections import defaultdict


class Graph(object):
    """
    隣接リストによる無向グラフ
    重み無しで距離は１
    """

    def __init__(self):
        self.graph = defaultdict(list)

    def __len__(self):
        return len(self.graph)

    def add_edge(self, src, dst):
        self.graph[src].append(dst)
        self.graph[dst].append(src)

    def get_nodes(self):
        return self.graph.keys()


def main():
    N, M = map(int, input().split())
    ab = [list(map(int, input().split())) for _ in range(M)]
    g = Graph()
    for e in ab:
        g.add_edge(e[0], e[1])

    for i in range(N):
        print(len(g.graph[i+1]))


if __name__ == "__main__":
    main()