Problem:
Score : 500 points

Problem Statement

We have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares.

The square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is 0, and white if S_{i,j} is 1.

We will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar.

How many times do we need to cut the bar so that every block after the cuts has K or less white squares?

Constraints

1 \leq H \leq 10

1 \leq W \leq 1000

1 \leq K \leq H \times W

S_{i,j} is 0 or 1.

Input

Input is given from Standard Input in the following format:

H W K
S_{1,1}S_{1,2}...S_{1,W}
:
S_{H,1}S_{H,2}...S_{H,W}

Output

Print the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares.

Sample Input 1

3 5 4
11100
10001
00111

Sample Output 1

2

For example, cutting between the 1-st and 2-nd rows and between the 3-rd and 4-th columns - as shown in the figure to the left - works.

Note that we cannot cut the bar in the ways shown in the two figures to the right.

Sample Input 2

3 5 8
11100
10001
00111

Sample Output 2

0

No cut is needed.

Sample Input 3

4 10 4
1110010010
1000101110
0011101001
1101000111

Sample Output 3

3

Solution in Python (3.8.2) (judge verdict: Accepted)

import sys
# import re
import math
import collections
# import decimal
import bisect
import itertools
import fractions
# import functools
import copy
# import heapq
import decimal
# import statistics
import queue

# import numpy as np

sys.setrecursionlimit(10000001)
INF = 10 ** 16
MOD = 10 ** 9 + 7
# MOD = 998244353

ni = lambda: int(sys.stdin.readline())
ns = lambda: map(int, sys.stdin.readline().split())
na = lambda: list(map(int, sys.stdin.readline().split()))


# ===CODE===
def main():
    h, w, k = ns()
    mat = [list(input()) for _ in range(h)]

    # if h == 1:
    #     tmp = max(0, mat[0].count("1") - 1)
    #     print(tmp // k)
    #     exit(0)

    ans = INF
    for i in range(2 ** (h - 1)):
        cut = format(i, "b").count("1")
        row = cut + 1

        cnt = [0 for _ in range(row)]

        idx_dic = dict()
        tmp_idx = 0
        for j in range(h):
            idx_dic[j] = tmp_idx
            if i >> j & 1:
                tmp_idx += 1

        tmp_ans = cut
        xi = 0
        brkflg = True
        while xi < w:
            yi = 0
            prev_brkflg = brkflg
            brkflg = False
            while yi < h:
                if mat[yi][xi] == "1":
                    cnt[idx_dic[yi]] += 1
                    if cnt[idx_dic[yi]] > k:
                        cnt = [0 for _ in range(row)]
                        xi -= 1
                        brkflg = True
                        tmp_ans += 1
                        break

                yi += 1
            if brkflg and prev_brkflg:
                tmp_ans = INF
                break
            xi += 1
        ans = min(ans, tmp_ans)

    print(ans)


if __name__ == '__main__':
    main()