Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

# -*- coding: utf-8 -*-
n, a, b, c, d = map(int, input().split())
s = input()
grid = []
for rock in s:
    grid.append(rock == '#')

if grid[c-1] or grid[d-1]:
    print('No')

max_none_count = 0
max_rock_count = 0
none_count = 0
rock_count = 0

for i in range(a - 1, max(c, d)):
    if grid[i] or (i == d - 1 and max_none_count <= 2 and c > d):
        none_count = 0
        rock_count += 1
    else:
        if i >= b - 2:
            none_count += 1
        rock_count = 0

    max_none_count = max(max_none_count, none_count)
    max_rock_count = max(max_rock_count, rock_count)

if max_rock_count >= 2:
    print('No')
else:
    if c < d:
        print('Yes')

    if c > d:
        if max_none_count >= 3:
            print('Yes')
        else:
            print('No')