Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in Python (3.8.2) (judge verdict: Wrong Answer)

# -*- coding: utf-8 -*-
import sys 
from collections import Counter
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
Q, A, B, C = map(int, readline().split())
N = A + B + C
SS = []
for _ in range(Q):
    S = readline().decode().rstrip()
    a = 0 if S == 'AB' else 1 if S == 'AC' else 2 
    SS.append(a)
ans = [] 
if N == 0:
    print('No')
    sys.exit()
elif N == 1:
    nums = [A,B,C]
    for i in range(Q):
        num = SS[i]
        i,j = (0,1) if num == 0 else (0,2) if num == 1 else (1,2)  
        if nums[i] == nums[j]:
            print('No')
            sys.exit()
        if nums[i] > nums[j]:
            i,j = j,i
        nums[i] += 1
        nums[j] -= 1
else:
    nums = [A,B,C]
    num = SS[0]
    i,j = (0,1) if num == 0 else (0,2) if num == 1 else (1,2) 
    if nums[i] == 0 and nums[j] == 0:
        print('No')
        sys.exit()
    if N == 2:
        for i in range(Q):
            num = SS[i]
            i,j = (0,1) if num == 0 else (0,2) if num == 1 else (1,2)
            if nums[i] == 1 and nums[j] == 1:
                if i < Q-1 and SS[i] != SS[i+1]:
                    ni,nj = (0,1) if SS[i+1] == 0 else (0,2) if SS[i+1] == 1 else (1,2)
                    a = Counter([i,j,ni,nj])
                    b = a.most_common()[0][0] ## 2つあるの探す 
                    if j == b:
                        i,j = j,i   
            if nums[i] > nums[j]:
                i,j = j,i
            nums[i] += 1
            nums[j] -= 1
            ans.append(i)
    else:
        for i in range(Q):
            num = SS[i]
            i,j = (0,1) if num == 0 else (0,2) if num == 1 else (1,2)
            if nums[i] > nums[j]:
                i,j = j,i
            nums[i] += 1
            nums[j] -= 1
            ans.append(i)
        
print('Yes')
ABC = 'ABC'
answer = list(ABC[i] for i in ans)
print('\n'.join(answer))