Problem:
Score : 200 points

Problem Statement

Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Constraints

1 \leq N \leq 10^5

Input

Input is given from Standard Input in the following format:

N

Output

Print the number of positive integers less than or equal to N that have an odd number of digits.

Sample Input 1

11

Sample Output 1

9

Among the positive integers less than or equal to 11, nine integers have an odd number of digits: 1, 2, \ldots, 9.

Sample Input 2

136

Sample Output 2

46

In addition to 1, 2, \ldots, 9, another 37 integers also have an odd number of digits: 100, 101, \ldots, 136.

Sample Input 3

100000

Sample Output 3

90909

Solution in Python (3.4.3) (judge verdict: Accepted)

N = int(input())
if 1 <= N and N < 10:
    ans = N
if 10 <= N  and N < 100:
    ans = 9
if 100 <= N and N < 1000:
    ans = 9 + N - 99
if 1000 <= N and N < 10000:
    ans = 9 + 999 - 100 + 1
if 10000 <= N and N < 100000:
    ans = 9 + (999 - 100 + 1) + N - 9999
if N == 100000:
    ans = 9 + (999 - 100 + 1) + N - 9999 - 1
print(ans)