Problem:
Score : 400 points

Problem Statement

Snuke has N strings. The i-th string is s_i.

Let us concatenate these strings into one string after arranging them in some order.
Find the maximum possible number of occurrences of AB in the resulting string.

Constraints

1 \leq N \leq 10^{4}

2 \leq |s_i| \leq 10

s_i consists of uppercase English letters.

Input

Input is given from Standard Input in the following format:

N
s_1
\vdots
s_N

Output

Print the answer.

Sample Input 1

3
ABCA
XBAZ
BAD

Sample Output 1

2

For example, if we concatenate ABCA, BAD and XBAZ in this order, the resulting string ABCABADXBAZ has two occurrences of AB.

Sample Input 2

9
BEWPVCRWH
ZZNQYIJX
BAVREA
PA
HJMYITEOX
BCJHMRMNK
BP
QVFABZ
PRGKSPUNA

Sample Output 2

4

Sample Input 3

7
RABYBBE
JOZ
BMHQUVA
BPA
ISU
MCMABAOBHZ
SZMEHMA

Sample Output 3

4

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

N = int(input())

ans = 0
dic = {"A": 0, "B": 0}
dic2 = {"AB": 0, "A": 0, "B": 0}
for i in range(N):
    S = list(str(input()))
    pre = S[0]
    for j in range(1, len(S)):
        if (S[j - 1] + S[j]) == "AB":
            ans += 1
    if S[-1] == "A":
        dic["A"] += 1
    if S[0] == "B":
        dic["B"] += 1

    if S[-1] == "A" and S[0] == "B":
        dic2["AB"] += 1
    elif S[-1] == "A":
        dic2["A"] += 1
    elif S[0] == "B":
        dic2["B"] += 1
if dic2["A"] == 0 and dic2["B"] == 0:
    print(ans + int(dic2["AB"]/2))
else:
    print(ans + min(dic["A"], dic["B"]))