Problem:
Score : 400 points

Problem Statement

Given is a positive integer N. Consider repeatedly applying the operation below on N:

First, choose a positive integer z satisfying all of the conditions below:

z can be represented as z=p^e, where p is a prime number and e is a positive integer;

z divides N;

z is different from all integers chosen in previous operations.

Then, replace N with N/z.

Find the maximum number of times the operation can be applied.

Constraints

All values in input are integers.

1 \leq N \leq 10^{12}

Input

Input is given from Standard Input in the following format:

N

Output

Print the maximum number of times the operation can be applied.

Sample Input 1

24

Sample Output 1

3

We can apply the operation three times by, for example, making the following choices:

Choose z=2 (=2^1). (Now we have N=12.)

Choose z=3 (=3^1). (Now we have N=4.)

Choose z=4 (=2^2). (Now we have N=1.)

Sample Input 2

1

Sample Output 2

0

We cannot apply the operation at all.

Sample Input 3

64

Sample Output 3

3

We can apply the operation three times by, for example, making the following choices:

Choose z=2 (=2^1). (Now we have N=32.)

Choose z=4 (=2^2). (Now we have N=8.)

Choose z=8 (=2^3). (Now we have N=1.)

Sample Input 4

1000000007

Sample Output 4

1

We can apply the operation once by, for example, making the following choice:

z=1000000007 (=1000000007^1). (Now we have N=1.)

Sample Input 5

997764507000

Sample Output 5

7

Solution in PyPy3 (7.3.0) (judge verdict: Accepted)

import sys, re, os
from collections import deque, defaultdict, Counter
from math import ceil, sqrt, hypot, factorial, pi, sin, cos, radians, acos, atan, asin, log, log10, gcd
from itertools import permutations, combinations, product, accumulate, combinations_with_replacement
from operator import itemgetter, mul
from copy import deepcopy
from string import ascii_lowercase, ascii_uppercase, digits
#from fractions import gcd
def debug(*args):
    if debugmode:
        print(*args)
def input(): return sys.stdin.readline().strip()
def STR(): return input()
def INT(): return int(input())
def FLOAT(): return float(input())
def MAP(): return map(int, input().split())
def S_MAP(): return map(str, input().split())
def LIST(): return list(map(int, input().split()))
def S_LIST(): return list(map(str, input().split()))
def lcm(a, b): return a * b // gcd(a, b)
sys.setrecursionlimit(10 ** 9)
inf = sys.maxsize
mod = 10 ** 9 + 7
dx = [0, 1, 0, -1, 1, -1, -1, 1]
dy = [1, 0, -1, 0, 1, -1, 1, -1]
debugmode = True

#素因数分解
def prime_factorize(n):
    a = []
    a.append(1)
    while n % 2 == 0:
        a.append(2)
        n //= 2
    f = 3
    while f * f <= n:
        if n % f == 0:
            a.append(f)
            n //= f
        else:
            f += 2
    if n != 1:
        a.append(n)
    
    b = [[],[]]
    cnt = 1
    for i in range(len(a)+1):
        if i > 0 and i < len(a):
            if a[i] == a[i-1]:
                cnt += 1
            else:
                b[0].append(a[i-1])
                b[1].append(cnt)
                cnt = 1
        if i == len(a) and i > 0:
            b[0].append(a[i-1])
            b[1].append(cnt)
        elif i == len(a) and i == 0:
            b[0].append(a[i])
            b[1].append(cnt)
    return b

n = INT()
a = prime_factorize(n)
ans = 0
for i in range(1, len(a[0])):
    #print(a[i][1], int(sqrt(1 + 8 * a[1][i]) - 1) // 2)
    ans += int(sqrt(1 + 8 * a[1][i]) - 1) // 2
print(ans)