Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in Python (3.4.3) (judge verdict: Accepted)

# -*- coding: utf-8 -*-


def main():
    s = input()
    n = len(s)

    # KeyInsight
    # 2文字が全て同じ，もしくは，3文字のうち2文字以上が同じ文字なら
    # 条件を満たす
    for i in range(n - 1):
        if s[i] == s[i + 1]:
            print(i + 1, i + 2)
            exit()

    for j in range(n - 2):
        if len(set(list(s[j:j + 3]))) <= 2:
            print(j + 1, j + 3)
            exit()

    print(-1, -1)


if __name__ == '__main__':
    main()