Problem:
Score : 300 points

Problem Statement

A sequence a_1,a_2,... ,a_n is said to be /\/\/\/ when the following conditions are satisfied:

For each i = 1,2,..., n-2, a_i = a_{i+2}.

Exactly two different numbers appear in the sequence.

You are given a sequence v_1,v_2,...,v_n whose length is even.
We would like to make this sequence /\/\/\/ by replacing some of its elements.
Find the minimum number of elements that needs to be replaced.

Constraints

2 \leq n \leq 10^5

n is even.

1 \leq v_i \leq 10^5

v_i is an integer.

Input

Input is given from Standard Input in the following format:

n
v_1 v_2 ... v_n

Output

Print the minimum number of elements that needs to be replaced.

Sample Input 1

4
3 1 3 2

Sample Output 1

1

The sequence 3,1,3,2 is not /\/\/\/, but we can make it /\/\/\/ by replacing one of its elements: for example, replace the fourth element to make it 3,1,3,1.

Sample Input 2

6
105 119 105 119 105 119

Sample Output 2

0

The sequence 105,119,105,119,105,119 is /\/\/\/.

Sample Input 3

4
1 1 1 1

Sample Output 3

2

The elements of the sequence 1,1,1,1 are all the same, so it is not /\/\/\/.

Solution in PyPy3 (2.4.0) (judge verdict: Time Limit Exceeded)

n = int(input())
v = list(map(int, input().split()))
v1 = []
v2 = []
ans = 0

for i in range(n):
    if i % 2 == 0:
        v1.append(v[i])
    else:
        v2.append(v[i])

mostCount1 = 0
mostChar1 = 0
dp1 = [None] * 100000

for i in range(n//2):
    count = 0
    if dp1[v1[i]] is not None:
        count = dp1[v1[i]]
    else:
        dp1[v1[i]] = v1.count(v1[i])
        count = dp1[v1[i]]
#    count = v1.count(v1[i])
    if count > mostCount1:
        mostCount1 = count
        mostChar1 = v1[i]
        if mostCount1 > n//2:
            break

mostCount2 = 0
mostChar2 = 0
dp2 = [None] * 100000

for i in range(n//2):
#    count = v2.count(v2[i])
    count = 0
    if dp2[v2[i]] is not None:
        count = dp2[v2[i]]
    else:
        dp2[v2[i]] = v2.count(v2[i])
        count = dp2[v2[i]]

    if count > mostCount2:
        mostCount2 = count
        mostChar2 = v2[i]
        if mostCount2 > n//2:
            break

if mostChar1 == mostChar2:
    ans = n//2
else:
    ans = n - mostCount1 - mostCount2

print(ans)