Problem:
Score : 500 points

Problem Statement

There are N blocks arranged in a row. Let us paint these blocks.

We will consider two ways to paint the blocks different if and only if there is a block painted in different colors in those two ways.

Find the number of ways to paint the blocks under the following conditions:

For each block, use one of the M colors, Color 1 through Color M, to paint it. It is not mandatory to use all the colors.

There may be at most K pairs of adjacent blocks that are painted in the same color.

Since the count may be enormous, print it modulo 998244353.

Constraints

All values in input are integers.

1 \leq N, M \leq 2 \times 10^5

0 \leq K \leq N - 1

Input

Input is given from Standard Input in the following format:

N M K

Output

Print the answer.

Sample Input 1

3 2 1

Sample Output 1

6

The following ways to paint the blocks satisfy the conditions: 112, 121, 122, 211, 212, and 221. Here, digits represent the colors of the blocks.

Sample Input 2

100 100 0

Sample Output 2

73074801

Sample Input 3

60522 114575 7559

Sample Output 3

479519525

Solution in PyPy3 (7.3.0) (judge verdict: Accepted)

mod=998244353


##mod,nについての制約は自分でいかに記入する

def find_power(n,mod):
    # 0!からn!までのびっくりを出してくれる関数(ただし、modで割った値に対してである）
    powlist=[0]*(n+1)
    powlist[0]=1
    powlist[1]=1
    for i in range(2,n+1):
        powlist[i]=powlist[i-1]*i%(mod)
    return powlist

def find_inv_power(n,mod):
    #0!からn!までの逆元を素数modで割ったあまりリストを作る関数
    c=1
    uselist=[0 for i in range(n+1)]
    for i in range(1,n+1):
        c*=i
        c%=mod
    first=pow(c,mod-2,mod)
    uselist[n]=first
    for i in range(n,0,-1):
        uselist[i-1]=(uselist[i]*i)%(mod)
    return uselist
    
A=find_power(4*10**5,mod)
B=find_inv_power(4*10**5,mod)

def combi(n,r,mod):
    if n<r:
        return 0
    elif n>=r:
        return (A[n]*B[r]*B[n-r])%(mod)



N,M,K=map(int,input().split())
dp=[0 for i in range(N+1)]
#dp[x]=塗り方でダブりが、ｘ通りになるものの個数
ans=M*pow(M-1,N-1,mod)

for i in range(1,K+1):
    ans+=M*combi(N-1,i,mod)*pow(M-1,N-1-i,mod)
print(ans%mod)