Problem:
Score : 400 points

Problem Statement

We say that a odd number N is similar to 2017 when both N and (N+1)/2 are prime.

You are given Q queries.

In the i-th query, given two odd numbers l_i and r_i, find the number of odd numbers x similar to 2017 such that l_i ≤ x ≤ r_i.

Constraints

1≤Q≤10^5

1≤l_i≤r_i≤10^5

l_i and r_i are odd.

All input values are integers.

Input

Input is given from Standard Input in the following format:

Q
l_1 r_1
:
l_Q r_Q

Output

Print Q lines. The i-th line (1≤i≤Q) should contain the response to the i-th query.

Sample Input 1

1
3 7

Sample Output 1

2

3 is similar to 2017, since both 3 and (3+1)/2=2 are prime.

5 is similar to 2017, since both 5 and (5+1)/2=3 are prime.

7 is not similar to 2017, since (7+1)/2=4 is not prime, although 7 is prime.

Thus, the response to the first query should be 2.

Sample Input 2

4
13 13
7 11
7 11
2017 2017

Sample Output 2

1
0
0
1

Note that 2017 is also similar to 2017.

Sample Input 3

6
1 53
13 91
37 55
19 51
73 91
13 49

Sample Output 3

4
4
1
1
1
2

Solution in Python (3.8.2) (judge verdict: Accepted)

import math
from itertools import accumulate


def is_prime(n):
    if n == 1:
        return 0

    for k in range(2, int(math.sqrt(n)) + 1):
        if n % k == 0:
            return 0

    return 1


Q = int(input())
L = [0]*Q
R = [0]*Q

for i in range(Q):
    L[i], R[i] = list(map(int, input().split()))

min_L = min(L)
max_R = max(R)

check = []
for i in range(min_L, max_R+1):
    if (i % 2 == 1):
        flg = (is_prime(i) and is_prime((i+1)/2))
    else:
        flg = 0
    check.append(flg)

# 累積和
check = [0] + check
check = list(accumulate(check))

for i in range(Q):
    print(check[R[i] - min_L + 1] - check[L[i] - min_L])