Problem:
Score : 400 points

Problem Statement

Let \mathrm{popcount}(n) be the number of 1s in the binary representation of n.
For example, \mathrm{popcount}(3) = 2, \mathrm{popcount}(7) = 3, and \mathrm{popcount}(0) = 0.

Let f(n) be the number of times the following operation will be done when we repeat it until n becomes 0: "replace n with the remainder when n is divided by \mathrm{popcount}(n)." (It can be proved that, under the constraints of this problem, n always becomes 0 after a finite number of operations.)

For example, when n=7, it becomes 0 after two operations, as follows:

\mathrm{popcount}(7)=3, so we divide 7 by 3 and replace it with the remainder, 1.

\mathrm{popcount}(1)=1, so we divide 1 by 1 and replace it with the remainder, 0.

You are given an integer X with N digits in binary.
For each integer i such that 1 \leq i \leq N, let X_i be what X becomes when the i-th bit from the top is inverted.
Find f(X_1), f(X_2), \ldots, f(X_N).

Constraints

1 \leq N \leq 2 \times 10^5

X is an integer with N digits in binary, possibly with leading zeros.

Input

Input is given from Standard Input in the following format:

N
X

Output

Print N lines. The i-th line should contain the value f(X_i).

Sample Input 1

3
011

Sample Output 1

2
1
1

X_1 = 7, which will change as follows: 7 \rightarrow 1 \rightarrow 0. Thus, f(7) = 2.

X_2 = 1, which will change as follows: 1 \rightarrow 0. Thus, f(1) = 1.

X_3 = 2, which will change as follows: 2 \rightarrow 0. Thus, f(2) = 1.

Sample Input 2

23
00110111001011011001110

Sample Output 2

2
1
2
2
1
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
1
3

Solution in Python (3.8.2) (judge verdict: Runtime Error)

import sys

sys.setrecursionlimit(200000)

def input_int():
    return map(int, input().split())

def one_int():
    return int(input())

def one_str():
    return input()

def many_int():
    return list(map(int, input().split()))

N=one_int()
S=one_str()

bit_count = S.count("1")

#bit数
calc_dict = {i:-1 for i in range(22000)}
res_dict =  {i:-1 for i in range(2*(10**5))}

res_dict = {i:-1 for i in range(1001)}
res_dict[0]=0

for i in range(1, 1001):
    if calc_dict[i]==-1:
        calc_dict[i] = bin(i).count("1")
    
    res_dict[i] = i%calc_dict[i]+1


bit_count = S.count("1")
for i in range(len(S)):
    if S[i]=="0":

        bit_count+=1
        num = int(S,2) + 2**(N-i-1)
        if num==0:
            print(0)
        else:
            print(res_dict[num%bit_count]+1)

#         print(mods(num, bit_count, 0))
        bit_count-=1
    else:

        bit_count-=1
        num = int(S,2) - 2**(N-i-1)
        if num==0:
            print(0)
        else:
            print(res_dict[num%bit_count]+1)
        bit_count+=1