Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

#!/usr/bin/env python3
import collections
import itertools as it
import math
#import numpy as np
 
#  = int(input())
n, a, b, c, d  = map(int, input().split())
a -= 1
b -= 1
c -= 1
d -= 1
s  = input()
#  = list(map(int, input().split()))
#  = [int(input()) for i in range(N)]
#
# c = collections.Counter()

if '##' in s:
    print('No')
    exit()

s_ = list(s)
s_[a] = '#'
s_[c] = '#'
s_ = ''.join(s_)
is_case_snuke = ('##' not in s_[a:c+1])
#print(s_)
s_ = list(s)
if c > d:
    s_[b] = '#'
    s_[d] = '#'
s_ = ''.join(s_)
is_case_fnuke = ('##' not in s_[b:d+1])
#print(s_)
#print(is_case_snuke, is_case_fnuke)
print('Yes' if is_case_snuke or is_case_fnuke else 'No')