Problem:
Score : 500 points

Problem Statement

We have N logs of lengths A_1,A_2,\cdots A_N.

We can cut these logs at most K times in total. When a log of length L is cut at a point whose distance from an end of the log is t (0<t<L), it becomes two logs of lengths t and L-t.

Find the shortest possible length of the longest log after at most K cuts, and print it after rounding up to an integer.

Constraints

1 \leq N \leq 2 \times 10^5

0 \leq K \leq 10^9

1 \leq A_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 \cdots A_N

Output

Print an integer representing the answer.

Sample Input 1

2 3
7 9

Sample Output 1

4

First, we will cut the log of length 7 at a point whose distance from an end of the log is 3.5, resulting in two logs of length 3.5 each.

Next, we will cut the log of length 9 at a point whose distance from an end of the log is 3, resulting in two logs of length 3 and 6.

Lastly, we will cut the log of length 6 at a point whose distance from an end of the log is 3.3, resulting in two logs of length 3.3 and 2.7.

In this case, the longest length of a log will be 3.5, which is the shortest possible result. After rounding up to an integer, the output should be 4.

Sample Input 2

3 0
3 4 5

Sample Output 2

5

Sample Input 3

10 10
158260522 877914575 602436426 24979445 861648772 623690081 433933447 476190629 262703497 211047202

Sample Output 3

292638192

Solution in Python (3.8.2) (judge verdict: Runtime Error)

import math

def I(): return int(input())
def LI(): return list(map(int,input().split()))
def MI(): return map(int,input().split())
def LLI(n): return [list(map(int, input().split())) for _ in range(n)]

#bisect.bisect_left(list,key)はlistのなかでkey未満の数字がいくつあるかを返す
#bisect.bisect_right(list, key)はlistのなかでkey以下の数字がいくつあるかを返す
#これを応用することで
#len(list) - bisect.bisect_left(list,key)はlistのなかでkey以上の数字がいくつあるかを返す
#len(list) - bisect.bisect_right(list,key)はlistのなかでkeyより大きい数字がいくつあるかを返す
#これらを使うときはあらかじめlistをソートしておくこと！

n,k = MI()
a = LI()

def cutting_isOK(x,li,k):
    ans = 0
    for i in range(n):
        ans += math.ceil(li[i]/x) - 1
    if ans <= k:
        return True
    else:
        return False
left = -1
right = 10**9+1
while right != left + 1:
    mid = (left+right)//2
    if cutting_isOK(mid,a,k):
        right = mid
    else:
        left = mid
print(right)