Problem:
Score : 300 points

Problem Statement

A sequence a_1,a_2,... ,a_n is said to be /\/\/\/ when the following conditions are satisfied:

For each i = 1,2,..., n-2, a_i = a_{i+2}.

Exactly two different numbers appear in the sequence.

You are given a sequence v_1,v_2,...,v_n whose length is even.
We would like to make this sequence /\/\/\/ by replacing some of its elements.
Find the minimum number of elements that needs to be replaced.

Constraints

2 \leq n \leq 10^5

n is even.

1 \leq v_i \leq 10^5

v_i is an integer.

Input

Input is given from Standard Input in the following format:

n
v_1 v_2 ... v_n

Output

Print the minimum number of elements that needs to be replaced.

Sample Input 1

4
3 1 3 2

Sample Output 1

1

The sequence 3,1,3,2 is not /\/\/\/, but we can make it /\/\/\/ by replacing one of its elements: for example, replace the fourth element to make it 3,1,3,1.

Sample Input 2

6
105 119 105 119 105 119

Sample Output 2

0

The sequence 105,119,105,119,105,119 is /\/\/\/.

Sample Input 3

4
1 1 1 1

Sample Output 3

2

The elements of the sequence 1,1,1,1 are all the same, so it is not /\/\/\/.

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

n=int(input())

v=[int(x) for x in input().split()]

p=[0]+sorted(v[0:n-1:2])+[0]
l=r=o1=o2=0
for i in range(1,n//2+2):
  if p[i-1] != p[i]:
    if l>=o1:
      o2,o1,r=o1,l,p[i-1]
    l=1
  else:
    l+=1

pr = r
po1 = o1
po2 = o2

p=[0]+sorted(v[1:n:2])+[0]
l=r=o1=o2=0
for i in range(1,n//2+2):
  if p[i-1] != p[i]:
    if l>=o1:
      o2,o1,r=o1,l,p[i-1]
    l=1
  else:
    l+=1

if pr != r:
  print(n-po1-o1)
elif po1 > o1:
  print(n-po1-o2)
else:
  print(n-o1-po2)