Problem:
Score : 200 points

Problem Statement

Tak performed the following action N times: rolling two dice.
The result of the i-th roll is D_{i,1} and D_{i,2}.

Check if doublets occurred at least three times in a row.
Specifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.

Constraints

3 \leq N \leq 100

1\leq D_{i,j} \leq 6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
D_{1,1} D_{1,2}
\vdots
D_{N,1} D_{N,2}

Output

Print Yes if doublets occurred at least three times in a row. Print No otherwise.

Sample Input 1

5
1 2
6 6
4 4
3 3
3 2

Sample Output 1

Yes

From the second roll to the fourth roll, three doublets occurred in a row.

Sample Input 2

5
1 1
2 2
3 4
5 5
6 6

Sample Output 2

No

Sample Input 3

6
1 1
2 2
3 3
4 4
5 5
6 6

Sample Output 3

Yes

Solution in PyPy3 (7.3.0) (judge verdict: Wrong Answer)

# coding:utf-8

import sys
import math
import time
#import numpy as np
import collections
from collections import deque
from collections import Counter
import queue
import copy
import bisect
import heapq
import itertools


#sys.setrecursionlimit(10**7)
#N, Q = map(int, input().split())
#G = [list(input()) for i in range(H)]
#INF = V * 10001
#A = [int(i) for i in input().split()]
#AB = [list(map(int, input().split())) for _ in range(K)]

N = int(input())
D = [list(map(int, input().split())) for _ in range(N)]
ans = 0
count = 0

for i in range(N-3):
    if(D[i][0] == D[i][1]):
        if(D[i+1][0] == D[i+1][1]):
            if(D[i+2][0] == D[i+2][1]):
                count = 1

if(count==1):
    print("Yes")
else:
    print("No")

#print(ans)