Problem:
Score : 300 points

Problem Statement

There are N cities on a 2D plane. The coordinate of the i-th city is (x_i, y_i). Here (x_1, x_2, \dots, x_N) and (y_1, y_2, \dots, y_N) are both permuations of (1, 2, \dots, N).

For each k = 1,2,\dots,N, find the answer to the following question:

Rng is in City k.
Rng can perform the following move arbitrarily many times:

move to another city that has a smaller x-coordinate and a smaller y-coordinate, or a larger x-coordinate and a larger y-coordinate, than the city he is currently in.

How many cities (including City k) are reachable from City k?

Constraints

1 \leq N \leq 200,000

(x_1, x_2, \dots, x_N) is a permutation of (1, 2, \dots, N).

(y_1, y_2, \dots, y_N) is a permutation of (1, 2, \dots, N).

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
x_1 y_1
x_2 y_2
:
x_N y_N

Output

Print N lines. In i-th line print the answer to the question when k = i.

Sample Input 1

4
1 4
2 3
3 1
4 2

Sample Output 1

1
1
2
2

Rng can reach City 4 from City 3, or conversely City 3 from City 4.

Sample Input 2

7
6 4
4 3
3 5
7 1
2 7
5 2
1 6

Sample Output 2

3
3
1
1
2
3
2

Solution in PyPy3 (7.3.0) (judge verdict: Wrong Answer)

# -*- coding: utf-8 -*-
import sys
from collections import defaultdict
# sys.setrecursionlimit(10**6)
readline = sys.stdin.buffer.readline
# readline = sys.stdin.readline

INF = 1 << 63


def read_int():
    return int(readline())


def read_int_n():
    return list(map(int, readline().split()))


def read_float():
    return float(readline())


def read_float_n():
    return list(map(float, readline().split()))


def read_str():
    return readline().strip()


def read_str_n():
    return readline().strip().split()


def ep(*args):
    print(*args, file=sys.stderr)


def mt(f):
    import time

    def wrap(*args, **kwargs):
        s = time.perf_counter()
        ret = f(*args, **kwargs)
        e = time.perf_counter()

        ep(e - s, 'sec')
        return ret

    return wrap


class UnionFind():
    def __init__(self):
        self.__table = {}
        self.__size = defaultdict(lambda: 1)
        self.__rank = defaultdict(lambda: 1)

    def __root(self, x):
        if x not in self.__table:
            self.__table[x] = x
            return x
        else:
            a = x
            ul = []
            while a != self.__table[a]:
                ul.append(a)
                a = self.__table[a]
            for u in ul:
                self.__table[u] = a

        return self.__table[x]

    def same(self, x, y):
        return self.__root(x) == self.__root(y)

    def union(self, x, y):
        x = self.__root(x)
        y = self.__root(y)
        if x == y:
            return False

        if self.__rank[x] < self.__rank[y]:
            self.__table[x] = y
            self.__size[y] += self.__size[x]
        else:
            self.__table[y] = x
            self.__size[x] += self.__size[y]
            if self.__rank[x] == self.__rank[y]:
                self.__rank[x] += 1
        return True

    def size(self, x):
        return self.__size[self.__root(x)]

    def num_of_group(self):
        g = 0
        for k, v in self.__table.items():
            if k == v:
                g += 1
        return g



@mt
def slv(N, XY):
    xyi = [(x, y, i) for i, (x, y) in enumerate(XY)]
    xyi.sort()

    l = [(INF, set())]
    uf = UnionFind()
    for x, y, i in xyi:
        l.append((y, i))
        while len(l) >= 2 and l[-2][0] < l[-1][0]:
            y, i = l.pop()
            _, ii = l.pop()
            uf.union(i, ii)
            l.append((y, i))

    ans = [-1] * N
    for i in range(N):
        ans[i] = uf.size(i)
    return ans




def main():
    N = read_int()
    XY = [read_int_n() for _ in range(N)]
    print(*slv(N, XY), sep='\n')

if __name__ == '__main__':
    main()