Problem:
Score : 600 points

Problem Statement

Given are two sequences A and B, both of length N.
A and B are each sorted in the ascending order.
Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.

Constraints

1\leq N \leq 2 \times 10^5

1\leq A_i,B_i \leq N

A and B are each sorted in the ascending order.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N

Output

If there exist no reorderings that satisfy the condition, print No.

If there exists a reordering that satisfies the condition, print Yes on the first line.
After that, print a reordering of B on the second line, separating terms with a whitespace.

If there are multiple reorderings that satisfy the condition, you can print any of them.

Sample Input 1

6
1 1 1 2 2 3
1 1 1 2 2 3

Sample Output 1

Yes
2 2 3 1 1 1

Sample Input 2

3
1 1 2
1 1 3

Sample Output 2

No

Sample Input 3

4
1 1 2 3
1 2 3 3

Sample Output 3

Yes
3 3 1 2

Solution in PyPy3 (7.3.0) (judge verdict: Time Limit Exceeded)

n=int(input())
a=[int(i) for i in input().split()]
b=[int(i) for i in input().split()]

a_count=[0]*(n+1)
b_count=[0]*(n+1)


def new_order(a,b):
    import queue
    import random
    ideal_number_getter=queue.Queue()
    ans_list=[]
    random.shuffle(b)
    for i in b:
        ideal_number_getter.put(i)
    # for i in range((n//3)*2):
    #     tmp=ideal_number_getter.get()
    #     ideal_number_getter.put(tmp)

    for i in range(n):
        while True:
            new=ideal_number_getter.get()
            if a[i]==new:
                ideal_number_getter.put(new)
            else:
                ans_list.append(str(new))
                break
    return " ".join(ans_list)



for i in a:
    a_count[i]+=1
for i in b:
    b_count[i]+=1

ans=0
for i in range(1,n+1):
    if not a_count[i]+b_count[i]<=n:
        ans+=1
if ans==0:
    print("Yes")
    print(new_order(a,b))

else:
    print("No")