Problem:
Score : 500 points

Problem Statement

Let us denote by f(x, m) the remainder of the Euclidean division of x by m.

Let A be the sequence that is defined by the initial value A_1=X and the recurrence relation A_{n+1} = f(A_n^2, M).
Find \displaystyle{\sum_{i=1}^N A_i}.

Constraints

1 \leq N \leq 10^{10}

0 \leq X < M \leq 10^5

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X M

Output

Print \displaystyle{\sum_{i=1}^N A_i}.

Sample Input 1

6 2 1001

Sample Output 1

1369

The sequence A begins 2,4,16,256,471,620,\ldots Therefore, the answer is 2+4+16+256+471+620=1369.

Sample Input 2

1000 2 16

Sample Output 2

6

The sequence A begins 2,4,0,0,\ldots Therefore, the answer is 6.

Sample Input 3

10000000000 10 99959

Sample Output 3

492443256176507

Solution in PyPy3 (7.3.0) (judge verdict: Wrong Answer)

import sys
sys.setrecursionlimit(10 ** 7)
input = sys.stdin.readline

n, x, m = map(int, input().split())

ans = 0

aa = x
ans += aa
aset = set([aa])
alist = [aa]

for i in range(n):
    aa = pow(aa,2,m)
    if aa in aset:
        ind = alist.index(aa)
        kosu = n//(ind+1)
        ans = kosu*ans
        ans += sum(alist[0:n-kosu*(ind+1)-1])
        break
    else:
        ans += aa
        aset.add(aa)
        alist.append(aa)

    if aa == 0:
        break

print(ans)