Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in Python3 (judge verdict: Wrong Answer)

alphabet = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
cnt = 26 * [0]
Input = ""
loop = False

while True:
    I = input()
    for i in I:
        if i == '.':
            loop = True
    if loop:
        break
    Input += I

for i1 in range(len(alphabet)):
    for i2 in range(len(Input)):
        if 'A' <= Input[i2] <= 'Z':
            w = Input[i2].lower()
        else:
            w = Input[i2]
        if alphabet[i1] == w:
            cnt[i1] += 1
    print(alphabet[i1] + " : " + str(cnt[i1]))