Problem:
Score : 200 points

Problem Statement

There are N gems. The value of the i-th gem is V_i.

You will choose some of these gems, possibly all or none, and get them.

However, you need to pay a cost of C_i to get the i-th gem.

Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.

Find the maximum possible value of X-Y.

Constraints

All values in input are integers.

1 \leq N \leq 20

1 \leq C_i, V_i \leq 50

Input

Input is given from Standard Input in the following format:

N
V_1 V_2 ... V_N
C_1 C_2 ... C_N

Output

Print the maximum possible value of X-Y.

Sample Input 1

3
10 2 5
6 3 4

Sample Output 1

5

If we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.
We have X-Y = 5 here, which is the maximum possible value.

Sample Input 2

4
13 21 6 19
11 30 6 15

Sample Output 2

6

Sample Input 3

1
1
50

Sample Output 3

0

Solution in Python (3.4.3) (judge verdict: Runtime Error)

import itertools
N = int(input())
V = list(map(int, input().split()))
C = list(map(int, input().split()))

M = [[V[i], C[i]]for i in range(N)]
# print(M)

com_M = list(itertools.combinations(M, 2))
m_M = []
for i in range(N):
    X = com_M[i][0][0] + com_M[i][1][0]
    Y = com_M[i][0][1] + com_M[i][1][1]
    # print(X)
    # print(Y)
    m_M.append(X - Y)

print(max(m_M))