Problem:
Score : 400 points

Problem Statement

We have an undirected graph G with N vertices numbered 1 to N and N edges as follows:

For each i=1,2,...,N-1, there is an edge between Vertex i and Vertex i+1.

There is an edge between Vertex X and Vertex Y.

For each k=1,2,...,N-1, solve the problem below:

Find the number of pairs of integers (i,j) (1 \leq i < j \leq N) such that the shortest distance between Vertex i and Vertex j in G is k.

Constraints

3 \leq N \leq 2 \times 10^3

1 \leq X,Y \leq N

X+1 < Y

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X Y

Output

For each k=1, 2, ..., N-1 in this order, print a line containing the answer to the problem.

Sample Input 1

5 2 4

Sample Output 1

5
4
1
0

The graph in this input is as follows:

There are five pairs (i,j) (1 \leq i < j \leq N) such that the shortest distance between Vertex i and Vertex j is 1: (1,2)\,,(2,3)\,,(2,4)\,,(3,4)\,,(4,5).

There are four pairs (i,j) (1 \leq i < j \leq N) such that the shortest distance between Vertex i and Vertex j is 2: (1,3)\,,(1,4)\,,(2,5)\,,(3,5).

There is one pair (i,j) (1 \leq i < j \leq N) such that the shortest distance between Vertex i and Vertex j is 3: (1,5).

There are no pairs (i,j) (1 \leq i < j \leq N) such that the shortest distance between Vertex i and Vertex j is 4.

Sample Input 2

3 1 3

Sample Output 2

3
0

The graph in this input is as follows:

Sample Input 3

7 3 7

Sample Output 3

7
8
4
2
0
0

Sample Input 4

10 4 8

Sample Output 4

10
12
10
8
4
1
0
0
0

Solution in Python (3.4.3) (judge verdict: Time Limit Exceeded)

from heapq import heappush, heappop

INF = float('inf')

def dijkstra(n, G, s):
    dist = [INF] * n
    dist[s] = 0
    h = []
    heappush(h, (0, s))

    while h:
        # 使っていない頂点のうち、現時点で最も距離の近いものを選びvとする
        d, v = heappop(h)
        if dist[v] < d:
            continue
        # vから到達可能な頂点について、距離が短くなれば更新
        for b, cost in G[v]:
            if dist[b] > dist[v] + cost:
                dist[b] = dist[v] + cost
                heappush(h, (dist[b], b))
    return dist

n, x, y = map(int, input().split())

g = [[] for i in range(n)]

for i in range(n-1):
    g[i].append((i+1, 1))
    g[i+1].append((i, 1))

g[x-1].append((y-1, 1))
g[y-1].append((x-1, 1))

ans = [0] * n

for i in range(n):
    for d in dijkstra(n, g, i):
        ans[d] += 1

for item in ans[1:]:
    print(item // 2)