Problem:
Score : 600 points

Problem Statement

We have a tree with N vertices, whose i-th edge connects Vertex u_i and Vertex v_i.
Vertex i has an integer a_i written on it.
For every integer k from 1 through N, solve the following problem:

We will make a sequence by lining up the integers written on the vertices along the shortest path from Vertex 1 to Vertex k, in the order they appear. Find the length of the longest increasing subsequence of this sequence.

Here, the longest increasing subsequence of a sequence A of length L is the subsequence A_{i_1} , A_{i_2} , ... , A_{i_M} with the greatest possible value of M such that 1 \leq i_1 < i_2 < ... < i_M \leq L and A_{i_1} < A_{i_2} < ... < A_{i_M}.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq a_i \leq 10^9

1 \leq u_i , v_i \leq N

u_i \neq v_i

The given graph is a tree.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_N
u_1 v_1
u_2 v_2
:
u_{N-1} v_{N-1}

Output

Print N lines. The k-th line, print the length of the longest increasing subsequence of the sequence obtained from the shortest path from Vertex 1 to Vertex k.

Sample Input 1

10
1 2 5 3 4 6 7 3 2 4
1 2
2 3
3 4
4 5
3 6
6 7
1 8
8 9
9 10

Sample Output 1

1
2
3
3
4
4
5
2
2
3

For example, the sequence A obtained from the shortest path from Vertex 1 to Vertex 5 is 1,2,5,3,4. Its longest increasing subsequence is A_1, A_2, A_4, A_5, with the length of 4.

Solution in PyPy3 (7.3.0) (judge verdict: Time Limit Exceeded)

#!/usr/bin/env python3
import sys
sys.setrecursionlimit(10**8)
from bisect import bisect_left
INF = float("inf")


from collections import defaultdict


class Graph(object):
    def __init__(self, N):
        self.N = N
        self.E = defaultdict(list)

    def add_edge(self, f, t, w=1):
        self.E[f].append((t, w))
        self.E[t].append((f, w))


def solve(N: int, a: "List[int]", u: "List[int]", v: "List[int]"):

    g = Graph(N)
    for x, y in zip(u, v):
        g.add_edge(x-1, y-1)

    ans = [0]*N

    dp = [INF]*N
    event = []

    def dfs(curr, par):
        i = bisect_left(dp, a[curr])
        if dp[i] > a[curr]:
            event.append((curr, i, dp[i]))
            dp[i] = a[curr]

        ans[curr] = len(dp[:bisect_left(dp, INF)])

        for child, w in g.E[curr]:
            if child == par:
                continue
            dfs(child, curr)

        c, i, v = event[-1]
        if c == curr:
            dp[i] = v
            event.pop()

    dfs(0, -1)
    print(*ans, sep="\n")

    return


def main():

    def iterate_tokens():
        for line in sys.stdin:
            for word in line.split():
                yield word
    tokens = iterate_tokens()
    N = int(next(tokens))  # type: int
    a = [int(next(tokens)) for _ in range(N)]  # type: "List[int]"
    u = [int()] * (N - 1)  # type: "List[int]"
    v = [int()] * (N - 1)  # type: "List[int]"
    for i in range(N - 1):
        u[i] = int(next(tokens))
        v[i] = int(next(tokens))
    solve(N, a, u, v)


if __name__ == '__main__':
    main()