Problem:
Score : 500 points

Problem Statement

You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)

Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

N, Q, i_q, l_q, and r_q are integers.

S is a string consisting of lowercase English letters.

c_q is a lowercase English letter.

1 \leq N \leq 500000

1 \leq Q \leq 20000

|S| = N

1 \leq i_q \leq N

1 \leq l_q \leq r_q \leq N

There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:

N
S
Q
Query_1
\vdots
Query_Q

Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:

1 i_q c_q

2 l_q r_q

Output

For each query of type 2, print a line containing the answer.

Sample Input 1

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7

Sample Output 1

3
1
5

In the first query, cdbb contains three kinds of letters: b , c , and d, so we print 3.

In the second query, S is modified to abcdzbd.

In the third query, a contains one kind of letter: a, so we print 1.

In the fourth query, S is modified to abcazbd.

In the fifth query, S does not change and is still abcazbd.

In the sixth query, abcazbd contains five kinds of letters: a, b, c, d, and z, so we print 5.

Solution in PyPy3 (2.4.0) (judge verdict: Accepted)

class SegTree:
    def __init__(self, a, func):
        self.n = 2**(len(a) - 1).bit_length()
        self.f = func
        self.d = [0] * (2 * self.n - 1)
        self.d[self.n - 1:self.n - 1 + len(a)] = a
        for i in reversed(range(self.n - 1)):
            self.d[i] = self.f(self.d[2 * i + 1], self.d[2 * i + 2])

    def update(self, i, v):
        i += self.n - 1
        self.d[i] = v
        while i:
            i = (i - 1) // 2
            self.d[i] = self.f(self.d[2 * i + 1], self.d[2 * i + 2])

    def query(self, l, r):
        assert l <= r
        l += self.n
        r += self.n
        s = self.d[l - 1]
        while l < r:
            if l & 1:
                s = self.f(s, self.d[l - 1])
                l += 1
            if r & 1:
                r -= 1
                s = self.f(s, self.d[r - 1])
            l //= 2
            r //= 2
        return s

def main():
    N = int(input())
    S = [1 << (ord(s) - 97) for s in input()]
    T = SegTree(S, lambda x, y: x | y)

    Q = int(input())
    for _ in range(Q):
        t, a, b = input().split()
        if t == '1':
            T.update(int(a) - 1, 1 << (ord(b) - 97))
        else:
            print(bin(T.query(int(a) - 1, int(b))).count('1'))

main()