Problem:
Finding Missing Cards

Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).

The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.

Input

In the first line, the number of cards n (n ≤ 52) is given.

In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.

Output

Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line.
Arrange the missing cards in the following priorities:

Print cards of spades, hearts, clubs and diamonds in this order.

If the suits are equal, print cards with lower ranks first.

Sample Input

47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13

Sample Output

S 1
H 3
H 7
C 12
D 8

Note

      解説

Solution in Python3 (judge verdict: Accepted)

x=int(input())
list1=[1,2,3,4,5,6,7,8,9,10,11,12,13]
list2=[1,2,3,4,5,6,7,8,9,10,11,12,13]
list3=[1,2,3,4,5,6,7,8,9,10,11,12,13]
list4=[1,2,3,4,5,6,7,8,9,10,11,12,13]
for i in range(x):
    a,b=map(str,input().split())
    b=int(b)
    if a=="S":
        list1.remove(b)
    if a=="H":
        list2.remove(b)
    if a=="C":
        list3.remove(b)
    if a=="D":
        list4.remove(b)
for j in range(len(list1)):
    print("S",list1[j])
for j in range(len(list2)):
    print("H",list2[j])
for j in range(len(list3)):
    print("C",list3[j])
for j in range(len(list4)):
    print("D",list4[j])