Problem:
Score : 200 points

Problem Statement

A string is called a KEYENCE string when it can be changed to keyence by removing its contiguous substring (possibly empty) only once.

Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.

Constraints

The length of S is between 7 and 100 (inclusive).

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If S is a KEYENCE string, print YES; otherwise, print NO.

Sample Input 1

keyofscience

Sample Output 1

YES

keyence is an abbreviation of key of science.

Sample Input 2

mpyszsbznf

Sample Output 2

NO

Sample Input 3

ashlfyha

Sample Output 3

NO

Sample Input 4

keyence

Sample Output 4

YES

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

s=input()
q=0

if s.find("keyence")!=-1:
    q=1#ok
else:
    si=s.find("keyenc")
    if si!=-1 and si+6<=len(s)-1:
        if s[si+6:].find("e")!=-1:
            q=1
    else:
        si=s.find("keyen")
        if si!=-1 and si+6<=len(s)-1:
            if s[si+5:].find("ce")!=-1:
                q=1
        else:
            si=s.find("keye")
            if si!=-1 and si+6<=len(s)-1:
                if s[si+4:].find("nce")!=-1:
                    q=1
            else:
                si=s.find("key")
                if si!=-1 and si+6<=len(s)-1:
                    if s[si+3:].find("ence")!=-1:
                        q=1
                else:
                    si=s.find("ke")
                    if si!=-1 and si+6<=len(s)-1:
                        if s[si+2:].find("yence")!=-1:
                            q=1
                    else:
                        si=s.find("k")
                        if si!=-1 and si+6<=len(s)-1:
                            if s[si+1:].find("eyence")!=-1:
                                q=1
if q==1:
    print("YES")
else:
    print("NO")