Problem:
Score : 500 points

Problem Statement

There are N blocks arranged in a row. Let us paint these blocks.

We will consider two ways to paint the blocks different if and only if there is a block painted in different colors in those two ways.

Find the number of ways to paint the blocks under the following conditions:

For each block, use one of the M colors, Color 1 through Color M, to paint it. It is not mandatory to use all the colors.

There may be at most K pairs of adjacent blocks that are painted in the same color.

Since the count may be enormous, print it modulo 998244353.

Constraints

All values in input are integers.

1 \leq N, M \leq 2 \times 10^5

0 \leq K \leq N - 1

Input

Input is given from Standard Input in the following format:

N M K

Output

Print the answer.

Sample Input 1

3 2 1

Sample Output 1

6

The following ways to paint the blocks satisfy the conditions: 112, 121, 122, 211, 212, and 221. Here, digits represent the colors of the blocks.

Sample Input 2

100 100 0

Sample Output 2

73074801

Sample Input 3

60522 114575 7559

Sample Output 3

479519525

Solution in PyPy3 (7.3.0) (judge verdict: Accepted)

import sys
def input(): return sys.stdin.readline().rstrip()
class Facts:
  def __init__(self, mod=10**9+7, n_max=1):
    self.mod     = mod
    self.n_max   = n_max
    self.fact    = [1, 1]
    self.inv     = [0, 1]
    self.factinv = [1, 1]
    if 1 < n_max:
      setup_table(n_max) 
  
  def cmb(self, n, r):
    if r < 0 or n < r:
      return 0
    if self.n_max < n:
      self.setup_table(n)
    return self.fact[n] * (self.factinv[r] * self.factinv[n-r] % self.mod) % self.mod
  
  def setup_table(self, t):
    for i in range(self.n_max+1,t+1):
      self.fact.append( self.fact[-1] * i % self.mod )
      self.inv.append( -self.inv[self.mod % i] * (self.mod // i) % self.mod )
      self.factinv.append( self.factinv[-1] * self.inv[-1] % self.mod )
    self.n_max = t

def main():
    n,m,k=map(int,input().split())
    mod=998244353
    f=Facts(mod)
    ans=0
    t=m*pow(m-1,n-1-k,mod)
    for kx in range(k,-1,-1):
        ans+=f.cmb(n-1,kx)*t%mod
        t=t*(m-1)%mod
    print(ans%mod)


if __name__=='__main__':
    main()