Problem:
Score : 300 points

Problem Statement

You are given an integer N.
Find the number of the positive divisors of N!, modulo 10^9+7.

Constraints

1≤N≤10^3

Input

The input is given from Standard Input in the following format:

N

Output

Print the number of the positive divisors of N!, modulo 10^9+7.

Sample Input 1

3

Sample Output 1

4

There are four divisors of 3! =6: 1, 2, 3 and 6. Thus, the output should be 4.

Sample Input 2

6

Sample Output 2

30

Sample Input 3

1000

Sample Output 3

972926972

Solution in Python (3.4.3) (judge verdict: Accepted)

def prime(n):
    is_prime = [True] * (n + 1)
    is_prime[0] = False
    is_prime[1] = False
    for j in range(4, n+1, 2):
        is_prime[j] = False
    for i in range(3, int(n**0.5) + 1, 2):
        if not is_prime[i]:
            continue
        for j in range(i * 2, n + 1, i):
            is_prime[j] = False
    return [i for i in range(n + 1) if is_prime[i]]

def make_divisors(n):
    divisors = []
    for i in range(1, int(n**0.5)+1):
        if n % i == 0:
            divisors.append(i)
            if i != n // i:
                divisors.append(n//i)
    divisors.sort()
    return divisors

n = int(input())
prime_list = prime(n)
p = len(prime_list)
key = dict()
for value in prime_list:
    key[value] = 0
for i in range(1, n+1):
    div = make_divisors(i)
    for d in div:
        if d in key:
            k = 0
            i_c = i
            while i_c%d == 0:
                k += 1
                i_c //= d
            key[d] += k
ans = 1
for v in key.values():
    ans *= v+1
    ans %= 10**9+7
print(ans)