Problem:
Score : 600 points

Problem Statement

You are given a forest with N vertices and M edges. The vertices are numbered 0 through N-1.
The edges are given in the format (x_i,y_i), which means that Vertex x_i and y_i are connected by an edge.

Each vertex i has a value a_i.
You want to add edges in the given forest so that the forest becomes connected.
To add an edge, you choose two different vertices i and j, then span an edge between i and j.
This operation costs a_i + a_j dollars, and afterward neither Vertex i nor j can be selected again.

Find the minimum total cost required to make the forest connected, or print Impossible if it is impossible.

Constraints

1 ≤ N ≤ 100,000

0 ≤ M ≤ N-1

1 ≤ a_i ≤ 10^9

0 ≤ x_i,y_i ≤ N-1

The given graph is a forest.

All input values are integers.

Input

Input is given from Standard Input in the following format:

N M
a_0 a_1 .. a_{N-1}
x_1 y_1
x_2 y_2
:
x_M y_M

Output

Print the minimum total cost required to make the forest connected, or print Impossible if it is impossible.

Sample Input 1

7 5
1 2 3 4 5 6 7
3 0
4 0
1 2
1 3
5 6

Sample Output 1

7

If we connect vertices 0 and 5, the graph becomes connected, for the cost of 1 + 6 = 7 dollars.

Sample Input 2

5 0
3 1 4 1 5

Sample Output 2

Impossible

We can't make the graph connected.

Sample Input 3

1 0
5

Sample Output 3

0

The graph is already connected, so we do not need to add any edges.

Solution in PyPy3 (2.4.0) (judge verdict: Wrong Answer)

from heapq import heappush, heappop
from collections import defaultdict
n,m = map(int,input().split())
a = list(map(int,input().split()))
# edg = [[] for i in range(n)]
rank = [1] * n
par = [i for i in range(n)]
def root(x):
  if x == par[x]:
    return x
  par[x] = root(par[x])
  return par[x]
def union(a,b):
  a = root(a)
  b = root(b)
  if rank[a] < rank[b]:a,b = b,a
  if a == b: return False
  par[b] = a
  rank[a] += rank[b]
  return True
for _ in range(m):
  x,y = map(int, input().split())
  union(x,y)
d = defaultdict(list)
q = []
for i in range(n):
  ai = a[i]
  heappush(q,(ai,i))
  ri = root(i)
  heappush(d[ri],(ai,i))

ans = 0
tmp = 0
c = [0] * n

for i in d.keys():
  tmp += 1
  t,p = heappop(d[i])
  c[p] = 1
  ans += t
if 2*tmp > n:
  print("Impossible")
else:
  for _ in range(tmp):
    p,i = heappop(q)
    while c[i]:
      p,i = heappop(q)
    ans += p
  print(ans)