Problem:
Single Source Shortest Path

For a given weighted graph G(V, E) and a source r, find the source shortest path to each vertex from the source (SSSP: Single Source Shortest Path).

Input

An edge-weighted graph G (V, E) and the source r.

|V| |E| r
s0 t0 d0
s1 t1 d1
:
s|E|-1 t|E|-1 d|E|-1

|V| is the number of vertices and |E| is the number of edges in G. The graph vertices are named with the numbers 0, 1,..., |V|-1 respectively. r is the source of the graph.

si and ti represent source and target vertices of i-th edge (directed) and di represents the cost of the i-th edge.

Output

Print the costs of SSSP in the following format.

c0
c1
:
c|V|-1

The output consists of |V| lines. Print the cost of the shortest path from the source r to each vertex 0, 1, ... |V|-1 in order. If there is no path from the source to a vertex, print INF.

Constraints

1 ≤ |V| ≤ 100000

0 ≤ di ≤ 10000

0 ≤ |E| ≤ 500000

There are no parallel edges

There are no self-loops

Sample Input 1

4 5 0
0 1 1
0 2 4
1 2 2
2 3 1
1 3 5

Sample Output 1

0
1
3
4

Sample Input 2

4 6 1
0 1 1
0 2 4
2 0 1
1 2 2
3 1 1
3 2 5

Sample Output 2

3
0
2
INF

Solution in Python3 (judge verdict: Time Limit Exceeded)

from collections import defaultdict
import heapq


vertice,edge,source = map(int,input().split(" "))
link = defaultdict(dict)
weight = defaultdict(dict)
for e in range(edge):
    i,j,w = map(int,input().split(" "))
    link[i] = link.get(i,set()) | {j}
    weight[i].update({j:w})
#print(weight,link)
for v in range(vertice):
    goal = v
    queue = []
    heapq.heappush(queue,(0,source))
    heapq.heapify(queue)
    went = {n:0 for n in range(vertice)}

    while queue != []:
        #print(queue)
        now_cost,here = heapq.heappop(queue)
        #print(now_cost,here,queue)
        if here == goal:
            print(now_cost)
            break
        elif went[here]:
            continue
        can_go = link[here]

        #print(v,here,now_cost,not_went,queue)
        for nw in can_go:
            if went[nw]:
                continue
            next_cost = now_cost + weight[here][nw]
            heapq.heappush(queue,(next_cost,nw))
        went[here] = 1
    else:
        print("INF")