Problem:
Score : 500 points

Problem Statement

There are N blocks arranged in a row. Let us paint these blocks.

We will consider two ways to paint the blocks different if and only if there is a block painted in different colors in those two ways.

Find the number of ways to paint the blocks under the following conditions:

For each block, use one of the M colors, Color 1 through Color M, to paint it. It is not mandatory to use all the colors.

There may be at most K pairs of adjacent blocks that are painted in the same color.

Since the count may be enormous, print it modulo 998244353.

Constraints

All values in input are integers.

1 \leq N, M \leq 2 \times 10^5

0 \leq K \leq N - 1

Input

Input is given from Standard Input in the following format:

N M K

Output

Print the answer.

Sample Input 1

3 2 1

Sample Output 1

6

The following ways to paint the blocks satisfy the conditions: 112, 121, 122, 211, 212, and 221. Here, digits represent the colors of the blocks.

Sample Input 2

100 100 0

Sample Output 2

73074801

Sample Input 3

60522 114575 7559

Sample Output 3

479519525

Solution in Python (3.8.2) (judge verdict: Accepted)

N,M,K=map(int,input().split())
MOD = 998244353

fact = [0]*(N+1)
ifact = [0]*(N+1)
inv = [0]*(N+1)

def combination(n,fact,ifact):
    fact[0] = 1
    fact[1] = 1
    ifact[0] = 1
    ifact[1] = 1
    inv[1] = 1
    for i in range(2,n+1):
        fact[i] = (fact[i-1]*i)%MOD
        inv[i] = MOD - inv[MOD%i]*(MOD//i)%MOD
        ifact[i] = (ifact[i-1]*inv[i])%MOD
def op(n,k):
    if k<0 or k>n or n<0:
        return 0
    return (fact[n]*ifact[k]*ifact[n-k])%MOD
combination(N,fact,ifact)

res = 0
for k in range(K+1):
    res = (res + op(N-1,k)*M*pow(M-1,N-1-k,MOD) )%MOD
print(res)