Problem:
Score : 300 points

Problem Statement

Tak has N cards. On the i-th (1 \leq i \leq N) card is written an integer x_i.
He is selecting one or more cards from these N cards, so that the average of the integers written on the selected cards is exactly A.
In how many ways can he make his selection?

Constraints

1 \leq N \leq 50

1 \leq A \leq 50

1 \leq x_i \leq 50

N,\,A,\,x_i are integers.

Partial Score

200 points will be awarded for passing the test set satisfying 1 \leq N \leq 16.

Input

The input is given from Standard Input in the following format:

N A
x_1 x_2 ... x_N

Output

Print the number of ways to select cards such that the average of the written integers is exactly A.

Sample Input 1

4 8
7 9 8 9

Sample Output 1

5

The following are the 5 ways to select cards such that the average is 8:

Select the 3-rd card.

Select the 1-st and 2-nd cards.

Select the 1-st and 4-th cards.

Select the 1-st, 2-nd and 3-rd cards.

Select the 1-st, 3-rd and 4-th cards.

Sample Input 2

3 8
6 6 9

Sample Output 2

0

Sample Input 3

8 5
3 6 2 8 7 6 5 9

Sample Output 3

19

Sample Input 4

33 3
3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3

Sample Output 4

8589934591

The answer may not fit into a 32-bit integer.

Solution in Python (3.4.3) (judge verdict: Runtime Error)

n, a = map(int, input().split())
x = list(map(int, input().split()))

#aとの差を記録してリストに入れなおす
x = list(map(lambda i: i-a, x))
#print(x)

#dp初期値
dp = {0: 1}

#dpにぶち込む値をxから取り出す
for num in x:
  #dpにあるすべてのkey,valueに対して、すでにdpにkeyがi+kのデータがあればそのvalueなければ,0を返し、それ+vをdpとする。
  for k,v in list(dp.items()):
    dp[i+k]=dp.get(i+k,0)+v
    
  #print(dp)
#全部使わない選択肢だけ引いておく  
print(dp[0]-1)
#print(dp)