Problem:
Score : 600 points

Problem Statement

Given are two sequences A and B, both of length N.
A and B are each sorted in the ascending order.
Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.

Constraints

1\leq N \leq 2 \times 10^5

1\leq A_i,B_i \leq N

A and B are each sorted in the ascending order.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N

Output

If there exist no reorderings that satisfy the condition, print No.

If there exists a reordering that satisfies the condition, print Yes on the first line.
After that, print a reordering of B on the second line, separating terms with a whitespace.

If there are multiple reorderings that satisfy the condition, you can print any of them.

Sample Input 1

6
1 1 1 2 2 3
1 1 1 2 2 3

Sample Output 1

Yes
2 2 3 1 1 1

Sample Input 2

3
1 1 2
1 1 3

Sample Output 2

No

Sample Input 3

4
1 1 2 3
1 2 3 3

Sample Output 3

Yes
3 3 1 2

Solution in PyPy3 (7.3.0) (judge verdict: Wrong Answer)

from collections import Counter
n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
ca=Counter(a)
cb=Counter(b)
for k in cb:
    if k in ca:
        if cb[k]+ca[k]>n:
            print('No')
            exit()
tmpc=0
tmpd=0
c=[0]
d=[0]
for i in range(1,n+1):
    if i in ca:tmpc+=ca[i]
    if i in cb:tmpd+=cb[i]
    c.append(tmpc)
    d.append(tmpd)
x=0
for i in range(n):
    x=max(x,c[i]-d[i-1])
ans=b[-x:]+b[:-x]
print('Yes')
print(*ans,sep=' ')