Problem:
Score : 700 points

Problem Statement

Given is a sequence of N digits a_1a_2\ldots a_N, where each element is 1, 2, or 3.
Let x_{i,j} defined as follows:

x_{1,j} := a_j \quad (1 \leq j \leq N)

x_{i,j} := | x_{i-1,j} - x_{i-1,j+1} | \quad (2 \leq i \leq N and 1 \leq j \leq N+1-i)

Find x_{N,1}.

Constraints

2 \leq N \leq 10^6

a_i = 1,2,3 (1 \leq i \leq N)

Input

Input is given from Standard Input in the following format:

N
a_1a_2\ldotsa_N

Output

Print x_{N,1}.

Sample Input 1

4
1231

Sample Output 1

1

x_{1,1},x_{1,2},x_{1,3},x_{1,4} are respectively 1,2,3,1.

x_{2,1},x_{2,2},x_{2,3} are respectively |1-2| = 1,|2-3| = 1,|3-1| = 2.

x_{3,1},x_{3,2} are respectively |1-1| = 0,|1-2| = 1.

Finally, x_{4,1} = |0-1| = 1, so the answer is 1.

Sample Input 2

10
2311312312

Sample Output 2

0

Solution in PyPy3 (2.4.0) (judge verdict: Wrong Answer)

# -*- coding: utf-8 -*-
import sys
sys.setrecursionlimit(10**9)
INF=10**18
MOD=10**9+7
input=lambda: sys.stdin.readline().rstrip()
YesNo=lambda b: bool([print('Yes')] if b else print('No'))
YESNO=lambda b: bool([print('YES')] if b else print('NO'))
int1=lambda x:int(x)-1

def main():
    N=int(input())
    a=list(map(int1,input()))
    
    def COMinit(n,MOD):
        fac,finv,inv=[0]*max(2,n+1),[0]*max(2,n+1),[0]*max(2,n+1)
        fac[0]=fac[1]=1
        finv[0]=finv[1]=1
        inv[1]=1
        for i in range(2,(n+1)):
            fac[i]=fac[i-1]*i%MOD
            inv[i]=MOD-inv[MOD%i]*(MOD//i)%MOD
            finv[i]=finv[i-1]*inv[i]%MOD
        return fac,finv,inv
    
    fac,finv,inv=COMinit(N,MOD)
    
    def COM(n, k, MOD=MOD):
        if n<k or n<0 or k<0:
            return 0
        return fac[n]*(finv[k]*finv[n-k]%MOD)%MOD
    
    X=0
    for i in range(N):
        if COM(N-1,i)%2:
            X^=a[i]
    X&=0b01
    if X==1:
        print(1)
    else:
        if 1 in a:
            print(0)
        else:
            print(2)

if __name__ == '__main__':
    main()