Problem:
Score : 600 points

Problem Statement

Given is an integer sequence A_1, ..., A_N of length N.

We will choose exactly \left\lfloor \frac{N}{2} \right\rfloor elements from this sequence so that no two adjacent elements are chosen.

Find the maximum possible sum of the chosen elements.

Here \lfloor x \rfloor denotes the greatest integer not greater than x.

Constraints

2 \leq N \leq 2\times 10^5

|A_i|\leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the maximum possible sum of the chosen elements.

Sample Input 1

6
1 2 3 4 5 6

Sample Output 1

12

Choosing 2, 4, and 6 makes the sum 12, which is the maximum possible value.

Sample Input 2

5
-1000 -100 -10 0 10

Sample Output 2

0

Choosing -10 and 10 makes the sum 0, which is the maximum possible value.

Sample Input 3

10
1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000

Sample Output 3

5000000000

Watch out for overflow.

Sample Input 4

27
18 -28 18 28 -45 90 -45 23 -53 60 28 -74 -71 35 -26 -62 49 -77 57 24 -70 -93 69 -99 59 57 -49

Sample Output 4

295

Solution in Python (3.8.2) (judge verdict: Accepted)

import sys
from collections import defaultdict

sys.setrecursionlimit(10 ** 6)
int1 = lambda x: int(x) - 1
printV = lambda x: print(*x, sep="\n")
printH = lambda x: print(" ".join(map(str,x)))
def IS(): return sys.stdin.readline()[:-1]
def II(): return int(sys.stdin.readline())
def MI(): return map(int, sys.stdin.readline().split())
def LI(): return list(map(int, sys.stdin.readline().split()))
def LI1(): return list(map(int1, sys.stdin.readline().split()))
def LII(rows_number): return [II() for _ in range(rows_number)]
def LLI(rows_number): return [LI() for _ in range(rows_number)]
def LLI1(rows_number): return [LI1() for _ in range(rows_number)]

def main():
	n = II()
	a = LI()
	a = [0]+a
	dp_t = defaultdict(lambda: -10**18)
	dp_f =  defaultdict(lambda: -10**18)
	dp_f[(0,0)]=0
	for i in range(1,n+1):
		dp_f[(i,(i-1)//2)]=max(dp_f[(i-1,(i-1)//2)], dp_t[(i-1,(i-1)//2)])
		dp_t[(i,(i-1)//2)]=dp_f[(i-1,(i-1)//2-1)]+a[i]
		dp_f[(i,(i-1)//2+1)]=max(dp_f[(i-1,(i-1)//2+1)], dp_t[(i-1,(i-1)//2+1)])
		dp_t[(i,(i-1)//2+1)]=dp_f[(i-1,(i-1)//2)]+a[i]
	print(max(dp_t[(n,n//2)],dp_f[(n,n//2)]))
if __name__ == '__main__':
	main()