Problem:
Score : 400 points

Problem Statement

Given are positive integers A and B.

Let us choose some number of positive common divisors of A and B.

Here, any two of the chosen divisors must be coprime.

At most, how many divisors can we choose?

Definition of common divisor

An integer d is said to be a common divisor of integers x and y when d divides both x and y.

Definition of being coprime

Integers x and y are said to be coprime when x and y have no positive common divisors other than 1.

Definition of dividing

An integer x is said to divide another integer y when there exists an integer \alpha such that y = \alpha x.

Constraints

All values in input are integers.

1 \leq A, B \leq 10^{12}

Input

Input is given from Standard Input in the following format:

A B

Output

Print the maximum number of divisors that can be chosen to satisfy the condition.

Sample Input 1

12 18

Sample Output 1

3

12 and 18 have the following positive common divisors: 1, 2, 3, and 6.

1 and 2 are coprime, 2 and 3 are coprime, and 3 and 1 are coprime, so we can choose 1, 2, and 3, which achieve the maximum result.

Sample Input 2

420 660

Sample Output 2

4

Sample Input 3

1 2019

Sample Output 3

1

1 and 2019 have no positive common divisors other than 1.

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

A,B=map(int,input().split())

li=[]

for i in range(1,int(pow(min(A,B),1/2))+1):
    judge=True
    if min(A,B)%i==0 and max(A,B)%i==0:
        for l in li[1:]:
            if i%l==0:
                judge=False
                break
        if judge==True:
            li.append(i)
        judge=True
        if max(A,B)%(min(A,B)//i)==0:
            for l in li[1:]:
                if (min(A,B)//i)%l==0:
                    judge=False
                    break
            if judge==True:
                li.append(min(A,B)//i)

print(len(li))