Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Python (3.4.3) (judge verdict: Accepted)

a1, a2, a3 = map(int, input().split())
a4, a5, a6 = map(int, input().split())
a7, a8, a9 = map(int, input().split())

la = list()
la.append(a1)
la.append(a2)
la.append(a3)
la.append(a4)
la.append(a5)
la.append(a6)
la.append(a7)
la.append(a8)
la.append(a9)

N = int(input())

lb = list()
for i in range(N):
    lb.append(int(input()))

for i in range(N):
    for j in range(9):
        if lb[i] == la[j]:
            la[j] = 0

if la[0] + la[1] + la[2] == 0 or la[3] + la[4] + la[5] == 0 or la[6] + la[7] + la[8] == 0 or la[0] + la[3] + la[6] == 0 or la[1] + la[4] + la[7] == 0 or la[2] + la[5] + la[8] == 0 or la[0] + la[4] + la[8] == 0 or la[2] + la[4] + la[6] == 0:
    print('Yes')
else:
    print('No')