Problem:
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Sliding Minimum Element

For a given array $a_1, a_2, a_3, ... , a_N$ of $N$ elements and an integer $L$, find the minimum of each possible sub-arrays with size $L$ and print them from the beginning. For example, for an array $\{1, 7, 7, 4, 8, 1, 6\}$ and $L = 3$, the possible sub-arrays with size $L = 3$ includes $\{1, 7, 7\}$, $\{7, 7, 4\}$, $\{7, 4, 8\}$, $\{4, 8, 1\}$, $\{8, 1, 6\}$ and the minimum of each sub-array is 1, 4, 4, 1, 1 respectively.

Constraints

$1 \leq N \leq 10^6$

$1 \leq L \leq 10^6$

$1 \leq a_i \leq 10^9$

$L \leq N$

Input

The input is given in the following format.

$N$ $L$

$a_1$ $a_2$ ... $a_N$

Output

Print a sequence of the minimum in a line. Print a space character between adjacent elements.

Sample Input 1

7 3
1 7 7 4 8 1 6

Sample Output 1

1 4 4 1 1

Solution in Python3 (judge verdict: Time Limit Exceeded)

def binaryinsertion(A,x):
    left=0;right=len(A)-1;centre = len(A)//2
    while(True):
        if(left == right):
            if(x[0]<A[left][0]):
                A.insert(left,x)
                break
            else :
                A.insert(left+1,x)
                break
        else:
            if(x[0] < A[centre][0]) :
                right = centre - 1
            elif(A[centre][0] < x[0]) :
                left = centre
            else : 
                A.insert(centre,x)
                break
            centre = left + (right-left)//2

[N,L] = [int(x) for x in input().split()]
A = [[int(x),int(i)] for i,x in enumerate(input().split())]
sweep = A[:L]
sweep = sorted(sweep)
ans = [str(sweep[0][0])]
for i in range(L,N) :
    sweep.remove(A[i-L])
    binaryinsertion(sweep,A[i])
    ans.append(str(sweep[0][0]))
print(" ".join(ans))