Problem:
Score : 400 points

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of Q operations. In Operation i (1 \leq i \leq Q), an integer T_i is provided, which means the following:

If T_i = 1: reverse the string S.

If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

If F_i = 1 : Add C_i to the beginning of the string S.

If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Constraints

1 \leq |S| \leq 10^5

S consists of lowercase English letters.

1 \leq Q \leq 2 \times 10^5

T_i = 1 or 2.

F_i = 1 or 2, if provided.

C_i is a lowercase English letter, if provided.

Input

Input is given from Standard Input in the following format:

S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:

1

which means T_i = 1, and:

2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

Operation 1: Add p at the beginning of S. S becomes pa.

Operation 2: Reverse S. S becomes ap.

Operation 3: Add c at the end of S. S becomes apc.

Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

Operation 1: S becomes aa.

Operation 2: S becomes baa.

Operation 3: S becomes aab.

Operation 4: S becomes aabc.

Operation 5: S becomes cbaa.

Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

s = input()
q = int(input())
    
# for _ in range(q):
#     tmp = input()
#     if tmp == "1":
#         ans = ans[::-1]
#     else:
#         tmp = tmp.split(" ")
#         anstmp = list(ans)
#         if tmp[1] == "1":
#             anstmp.insert(0, tmp[2])
#         elif tmp[1] == "2":
#             anstmp.append(tmp[2])
#         ans = "".join(anstmp)

# print(ans)
mojis, rev = [s], [0]
for _ in range(q):
    tmp = input()
    if tmp == "1":
        rev = list(map(lambda x: x+1, rev))
    else:
        tmp = tmp.split(" ")
        if tmp[1] == "1":
            mojis.insert(0, tmp[2])
            rev.append(0)
        else:
            mojis.append(tmp[2])
            rev.append(0)
ans = []
for m, r in zip(mojis, rev):
    if r % 2 == 0:
        ans.append(m) 
    else:
        ans.insert(0, m)
print("".join(ans))