Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

s = input()
l = s[0]+s[1]
r = s[2]+s[3]
mm = ['01', '02', '03', '04', '05', '06', '07', '08', '09', '10', '11', '12']
zero = ['00']
if l == zero or r == zero:
    print('NA')
elif mm.count(l) == 1 and mm.count(r) == 1:
    print('AMBIGIUOUS')
elif mm.count(l) == 1 and mm.count(r) != 1:
    print('MMYY')
elif mm.count(l) != 1 and mm.count(r) == 1:
    print('YYMM')
else:
    print('NA')