Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

n,a,b,c,d = map(int,input().split())

m = list(input())

m[a-1] = "A"
m[b-1] = "B"

answer = []
def a_mon(x,text,y):
    i = 0
    while True:
        if m.index(text) == y-1:
            answer.append("a")
            break
        elif x+i < n:
            if m[x+i] == ".":
                m[x-1+i],m[x+i] = m[x+i],m[x-1+i]
                i += 1
            if x+1+i < n:
                if m[x+1+i] == ".":
                    m[x-1+i],m[x+1+i] = m[x+1+i],m[x-1+i]
                    i += 2  
                else:
                    break
            else:
                if m.index(text) == y-1:
                    answer.append("a")
                    break
                break
        else:  
            break          
            
a_mon(b,"B",d)
a_mon(a,"A",c)

if len(answer) == 2:
    print("Yes")
else:
    print("No")
# .#..#..