Problem:
Score : 200 points

Problem Statement

Given are integers a,b,c and d.
If x and y are integers and a \leq x \leq b and c\leq y \leq d hold, what is the maximum possible value of x \times y?

Constraints

-10^9 \leq a \leq b \leq 10^9

-10^9 \leq c \leq d \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a b c d

Output

Print the answer.

Sample Input 1

1 2 1 1

Sample Output 1

2

If x = 1 and y = 1 then x \times y = 1.
If x = 2 and y = 1 then x \times y = 2.
Therefore, the answer is 2.

Sample Input 2

3 5 -4 -2

Sample Output 2

-6

The answer can be negative.

Sample Input 3

-1000000000 0 -1000000000 0

Sample Output 3

1000000000000000000

Solution in Python (3.8.2) (judge verdict: Accepted)

def resolve():
    a, b, c, d = map(int, input().split())
    ans = [a * c, b * d]
    if (a <= 0) ^ (0 <= b):
        ans.append(b * c)
        ans.append(a * d)
    else:
        ans.append(0)
    if (c <= 0) ^ (0 <= d):
        ans.append(b * c)
        ans.append(a * d)
    else:
        ans.append(0)
    print(max(ans))


if __name__ == '__main__':
    resolve()