Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

n,a,b,c,d = list(map(int, input().split()))
s = '#' + input()

import re

# 今いる位置から目的地まで進めるか？
def can_forward(start, end):
    if start>end:
        end,start = start,end
    steps = s[start:end+1]
    if "##" in steps:
        return False
    return True

if not (can_forward(a, c) or can_forward(b, d)):
    print('No')
    exit()

if s[c]=='#' or s[d]=='#':
    print('No')
    exit()

if a<b and c>d or a>b and c<d:
    # 二人とも追い越し可能区間にいけるか？
    for m in re.finditer(r'\.\.\.+',s):
        f,t = m.span()
        if can_forward(a, f) and can_forward(b, f):
            print('Yes')
            exit()
    print('No')
else:
    print('Yes')