Problem:
Score : 500 points

Problem Statement

We have a grid of squares with N rows and M columns. Let (i, j) denote the square at the i-th row from the top and j-th column from the left. We will choose K of the squares and put a piece on each of them.

If we place the K pieces on squares (x_1, y_1), (x_2, y_2), ..., and (x_K, y_K), the cost of this arrangement is computed as:

\sum_{i=1}^{K-1} \sum_{j=i+1}^K (|x_i - x_j| + |y_i - y_j|)

Find the sum of the costs of all possible arrangements of the pieces. Since this value can be tremendous, print it modulo 10^9+7.

We consider two arrangements of the pieces different if and only if there is a square that contains a piece in one of the arrangements but not in the other.

Constraints

2 \leq N \times M \leq 2 \times 10^5

2 \leq K \leq N \times M

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M K

Output

Print the sum of the costs of all possible arrangements of the pieces, modulo 10^9+7.

Sample Input 1

2 2 2

Sample Output 1

8

There are six possible arrangements of the pieces, as follows:

((1,1),(1,2)), with the cost |1-1|+|1-2| = 1

((1,1),(2,1)), with the cost |1-2|+|1-1| = 1

((1,1),(2,2)), with the cost |1-2|+|1-2| = 2

((1,2),(2,1)), with the cost |1-2|+|2-1| = 2

((1,2),(2,2)), with the cost |1-2|+|2-2| = 1

((2,1),(2,2)), with the cost |2-2|+|1-2| = 1

The sum of these costs is 8.

Sample Input 2

4 5 4

Sample Output 2

87210

Sample Input 3

100 100 5000

Sample Output 3

817260251

Be sure to print the sum modulo 10^9+7.

Solution in Python (3.8.2) (judge verdict: Time Limit Exceeded)

p,q,r=map(int,input().split())

    
def comb_mod(N,K,modp):

    K_fact=1
    NK_fact=1
    N_fact=1

    for i in range(1,K+1):
        K_fact*=i
    for i in range(1,N-K+1):
        NK_fact*=i
    for i in range(1,N+1):
        N_fact*=i

    K_inv=pow(K_fact, -1, modp)
    NK_inv=pow(NK_fact, -1, modp)
    pat=(N_fact*K_inv)%modp*NK_inv%modp
    return pat

pat=comb_mod(p*q-2,r-2,10**9+7)

ans=0
for i in range(0,q+1):
    ans+=i*(q-i)*p*p

for k in range(0,p+1):
    ans+=k*(p-k)*q*q


print(ans*pat%(10**9+7))