Problem:
Score : 400 points

Problem Statement

Akari has n kinds of flowers, one of each kind.

She is going to choose one or more of these flowers to make a bouquet.

However, she hates two numbers a and b, so the number of flowers in the bouquet cannot be a or b.

How many different bouquets are there that Akari can make?

Find the count modulo (10^9 + 7).

Here, two bouquets are considered different when there is a flower that is used in one of the bouquets but not in the other bouquet.

Constraints

All values in input are integers.

2 \leq n \leq 10^9

1 \leq a < b \leq \textrm{min}(n, 2 \times 10^5)

Input

Input is given from Standard Input in the following format:

n a b

Output

Print the number of bouquets that Akari can make, modulo (10^9 + 7). (If there are no such bouquets, print 0.)

Sample Input 1

4 1 3

Sample Output 1

7

In this case, Akari can choose 2 or 4 flowers to make the bouquet.

There are 6 ways to choose 2 out of the 4 flowers, and 1 way to choose 4, so there are a total of 7 different bouquets that Akari can make.

Sample Input 2

1000000000 141421 173205

Sample Output 2

34076506

Print the count modulo (10^9 + 7).

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

#!/usr/bin/env python3
import sys
# sys.setrecursionlimit(10000000)
INF = 1<<32
# import numpy as np

MOD = 1000000007  # type: int

def solve(n: int, a: int, b: int):
    def combination_with_mod(n, r, mod=10**9+7):
        n1, r = n+1, min(r, n-r)
        numer = denom = 1
        for i in range(1, r+1):
            numer = numer * (n1-i) % mod
            denom = denom * i % mod
        return numer * pow(denom, mod-2, mod) % mod

    def power(a, n):
        if not n:
            return 1
        x = power(a, n >> 1)
        x *= x
        return a * x if n & 1 else x

    def power_func(a,n,p):
        bi=str(format(n,"b"))#2進表現に
        res=1
        for i in range(len(bi)):
            res=(res*res) %p
            if bi[i]=="1":
                res=(res*a) %p
        return res

    ans = 0
    ans = power_func(2, n, MOD)

    ans = ans-combination_with_mod(n,a)-combination_with_mod(n, b)-combination_with_mod(n,0)
    if ans < 0:
        print(MOD+ans)
    else:
        print(ans%MOD)

    return



def main():
    def iterate_tokens():
        for line in sys.stdin:
            for word in line.split():
                yield word
    tokens = iterate_tokens()
    n = int(next(tokens))  # type: int
    a = int(next(tokens))  # type: int
    b = int(next(tokens))  # type: int
    solve(n, a, b)

if __name__ == '__main__':
    main()