Problem:
Score : 300 points

Problem Statement

Iroha is very particular about numbers. There are K digits that she dislikes: D_1, D_2, ..., D_K.

She is shopping, and now paying at the cashier.
Her total is N yen (the currency of Japan), thus she has to hand at least N yen to the cashier (and possibly receive the change).

However, as mentioned before, she is very particular about numbers. When she hands money to the cashier, the decimal notation of the amount must not contain any digits that she dislikes. Under this condition, she will hand the minimum amount of money.

Find the amount of money that she will hand to the cashier.

Constraints

1 ≦ N < 10000

1 ≦ K < 10

0 ≦ D_1 < D_2 < … < D_K≦9

\{D_1,D_2,...,D_K\} ≠ \{1,2,3,4,5,6,7,8,9\}

Input

The input is given from Standard Input in the following format:

N K
D_1 D_2 … D_K

Output

Print the amount of money that Iroha will hand to the cashier.

Sample Input 1

1000 8
1 3 4 5 6 7 8 9

Sample Output 1

2000

She dislikes all digits except 0 and 2.

The smallest integer equal to or greater than N=1000 whose decimal notation contains only 0 and 2, is 2000.

Sample Input 2

9999 1
0

Sample Output 2

9999

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

n, k = map(int, input().split())
d = list(map(int, input().split()))
ans = ''

#嫌いな数字を変更する
def change_number(x):
  
  #足す数を格納しておく変数
  tmp = 0

  #嫌いな数字が含まれている間
  while x in d:
    x += 1
    tmp += 1
    #繰り上がる場合に調整
    if x == 10:
      x = 0
  
  return tmp

#1の位
x = str(n)[-1:]
n += change_number(int(x))

#10の位
if n >= 10:
  x = str(n)[-2:-1]
  n += change_number(int(x)) * 10

#100の位
if n >= 100:
  x = str(n)[-3:-2]
  n += change_number(int(x)) * 100

#1000の位
if n >= 1000:
  x = str(n)[-4:-3]
  n += change_number(int(x)) * 1000

print(ans)