Problem:
Score : 500 points

Problem Statement

Let us denote by f(x, m) the remainder of the Euclidean division of x by m.

Let A be the sequence that is defined by the initial value A_1=X and the recurrence relation A_{n+1} = f(A_n^2, M).
Find \displaystyle{\sum_{i=1}^N A_i}.

Constraints

1 \leq N \leq 10^{10}

0 \leq X < M \leq 10^5

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X M

Output

Print \displaystyle{\sum_{i=1}^N A_i}.

Sample Input 1

6 2 1001

Sample Output 1

1369

The sequence A begins 2,4,16,256,471,620,\ldots Therefore, the answer is 2+4+16+256+471+620=1369.

Sample Input 2

1000 2 16

Sample Output 2

6

The sequence A begins 2,4,0,0,\ldots Therefore, the answer is 6.

Sample Input 3

10000000000 10 99959

Sample Output 3

492443256176507

Solution in Python (3.8.2) (judge verdict: Wrong Answer)

import numpy as np
N,X,M=map(int,input().split())
A = [X,]
alast=X
flag=False
for i in range(min(N,M)):
    P=alast**2%M
    if P in A:
        flag=True
        d = int(np.arange(len(A))[np.array(A)==P])
        C=A[d:]
        alast=P
        break
    else:
        A.append(P)
        alast=P
if alast==0:
    print(sum(C))
elif flag==False:
    print(sum(A))
else:
    suma=sum(C)
    res = (N-d)%len(C)
    print(sum(A[:d])+((N-d)//len(C))*suma + sum(C[:res]))