Problem:
Score: 600 points

Problem Statement

How many strings can be obtained by applying the following operation on a string S exactly K times: "choose one lowercase English letter and insert it somewhere"?

The answer can be enormous, so print it modulo (10^9+7).

Constraints

K is an integer between 1 and 10^6 (inclusive).

S is a string of length between 1 and 10^6 (inclusive) consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:

K
S

Output

Print the number of strings satisfying the condition, modulo (10^9+7).

Sample Input 1

5
oof

Sample Output 1

575111451

For example, we can obtain proofend, moonwolf, and onionpuf, while we cannot obtain oofsix, oofelevennn, voxafolt, or fooooooo.

Sample Input 2

37564
whydidyoudesertme

Sample Output 2

318008117

Solution in Python (3.8.2) (judge verdict: Time Limit Exceeded)

import sys
input = sys.stdin.readline
import numpy as np
from numba import njit


def read():
    K = int(input().strip())
    S = input().strip()
    return K, S


def binom_preprocess(n, MOD=10**9+7):
    f = [0 for i in range(n+1)]  # n!
    invf = [0 for i in range(n+1)]  # (n!)^-1
    f[0] = 1
    f[1] = 1
    invf[0] = 1
    invf[1] = 1
    for i in range(2, n+1):
        f[i] = f[i-1] * i % MOD
    invf[n] = pow(f[n], MOD-2, MOD)
    for i in range(n, 2, -1):
        invf[i-1] = invf[i] * i % MOD
    return f, invf


def binom(n, k, f, invf, MOD=10**9+7):
    if n < k or n < 0 or k < 0:
        return 0
    else:
        return (f[n] * invf[k] % MOD) * invf[n-k] % MOD


def solve(K, S, MOD=10**9+7):
    T = len(S)
    f, invf = binom_preprocess(K+T+1)
    ans = 0
    for i in range(K+1):
        L = pow(25, i, MOD) * binom(T-1+i, i, f, invf, MOD) % MOD
        R = pow(26, K-i, MOD)
        ans += L * R
        ans %= MOD
    print(ans)


if __name__ == '__main__':
    inputs = read()
    outputs = solve(*inputs)
    if outputs is not None:
        print("%s" % str(outputs))