Problem:
Score : 500 points

Problem Statement

There are N blocks arranged in a row. Let us paint these blocks.

We will consider two ways to paint the blocks different if and only if there is a block painted in different colors in those two ways.

Find the number of ways to paint the blocks under the following conditions:

For each block, use one of the M colors, Color 1 through Color M, to paint it. It is not mandatory to use all the colors.

There may be at most K pairs of adjacent blocks that are painted in the same color.

Since the count may be enormous, print it modulo 998244353.

Constraints

All values in input are integers.

1 \leq N, M \leq 2 \times 10^5

0 \leq K \leq N - 1

Input

Input is given from Standard Input in the following format:

N M K

Output

Print the answer.

Sample Input 1

3 2 1

Sample Output 1

6

The following ways to paint the blocks satisfy the conditions: 112, 121, 122, 211, 212, and 221. Here, digits represent the colors of the blocks.

Sample Input 2

100 100 0

Sample Output 2

73074801

Sample Input 3

60522 114575 7559

Sample Output 3

479519525

Solution in PyPy3 (7.3.0) (judge verdict: Wrong Answer)

n, m, k = map(int, input().split())

MOD = 998244353

def comb(n,k,mod):
    if n<k:
        return 0
    if n<0 or k<0:
        return 0
    k=min(n-k,k)
    ans=1
    inv=[1]*(k+1)
    if k>=1:
        ans*=(n-k+1)%mod
    for i in range(2,k+1):
        inv[i]=mod-inv[mod%i]*(mod//i)%mod
        ans=ans*(n-k+i)*inv[i]%mod
    return ans

def pow_k(x, n, mod):
    """
    O(log n)
    """
    if n == 0:
        return 1

    K = 1
    while n > 1:
        if n % 2 != 0:
            K = (K * x) % mod
        x = (x * x) % mod
        n //= 2

    return K * x

ans = 0
for i in range(k + 1):
  ans += (pow_k(m, i + 1, MOD) * pow_k(m - 1, n - 1 - i, MOD) * comb(n - 1, i, MOD)) % MOD
print(ans % MOD)