Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in PyPy3 (7.3.0) (judge verdict: Wrong Answer)

n,a,b,c,d=map(int,input().split())
S=input()
answer=0
rock=0
for n_ in range(a,max(c,d)):
    if S[n_]=='#':
        rock+=1
    else:
        rock=0
    if rock>=2:
        answer=1
        break
if answer==1:
    print('No')
else:
    if c > d:
        answer=1
        rock = 0
        for n_ in range(a,d):
            if S[n_] == '.':
                rock += 1
            else:
                rock = 0
            if rock >= 3:
                answer=0
                break
    if b==a+1 and b+1==d and d+1==c:
        print('Yes')
    elif b==a+1 and c==b+1 and d==c+1:
        print('Yes')
    elif answer == 0:
        print('Yes')
    else:
        print('No')