Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

N, A, B, C, D = map(int, input().split())
S = list(input())

A -= 1
B -= 1
C -= 1
D -= 1

if S[C] == '#' or S[D] == '#':
    print("No")
    exit()

stone = 0
road = 0
c = False
l = [-1]

for i in range(B + 1, D):
    if S[i] == '#':
        stone += 1
        road = 0
        if c:
            l.append(i - 1)
            c = False
        if stone > 1:
            print("No")
            exit()
    else:
        road += 1
        stone = 0
        if road > 2:
            c = True

stone = 0
road = 0

count = 0

# B放置でゴールできるか
if S[B - 1] == '#' or S[B + 1] == '#':
    count += 1
# Bがゴールしているとゴールできるか
if D < C:
    if S[D - 1] == '#' or S[D + 1] == '#':
        count += 1

if count > 1:
    if l[-1] < 0:
        print("No")
        exit()

# Bが避難しているときBはAを通したあとゴールできるか
if C < D:
    if l[-1] < C:
        if S[C - 1] == '#' or S[C + 1] == '#':
            count += 1

if count > 2:
    print("No")
    exit()

print("Yes")