Problem:
Score : 400 points

Problem Statement

In some other world, today is Christmas.

Mr. Takaha decides to make a multi-dimensional burger in his party. A level-L burger (L is an integer greater than or equal to 0) is the following thing:

A level-0 burger is a patty.

A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.

For example, a level-1 burger and a level-2 burger look like BPPPB and BBPPPBPBPPPBB (rotated 90 degrees), where B and P stands for a bun and a patty.

The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Constraints

1 \leq N \leq 50

1 \leq X \leq ( the total number of layers in a level-N burger )

N and X are integers.

Input

Input is given from Standard Input in the following format:

N X

Output

Print the number of patties in the bottom-most X layers from the bottom of a level-N burger.

Sample Input 1

2 7

Sample Output 1

4

There are 4 patties in the bottom-most 7 layers of a level-2 burger (BBPPPBPBPPPBB).

Sample Input 2

1 1

Sample Output 2

0

The bottom-most layer of a level-1 burger is a bun.

Sample Input 3

50 4321098765432109

Sample Output 3

2160549382716056

A level-50 burger is rather thick, to the extent that the number of its layers does not fit into a 32-bit integer.

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

n, x = map(int, input().split())
a, p = [1] * (n + 1), [1] * (n + 1)
for i in range(1, n + 1):
    a[i] = 2*a[i - 1] + 3
    p[i] = 2*p[i - 1] + 1
def f(n, x):
    if x == 1:
        return 0
    elif 1 < x <= 1 + a[n - 1]:
        return f(n - 1, x - 1)
    elif x == a[n - 1] + 2:
        return p[n - 1] + 1
    elif a[n - 1] + 2 < x <= 2*a[n - 1] + 2:
        return p[n - 1] + 1 + f(n - 1, x - (a[n - 1] + 2))
    elif x == a[n]:
        return p[n]
print(f(n, x))