Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

# 3パターンある
# 1. a < c < b < d
# 2. a < b < c < d
# 3. a < b < d < c
# 1はa-cとb-dで独立して考える それぞれの間に#が連続してなかったらおｋ
# 2はb-dが成功したあとa-cが成功すればおｋ
# 3はa-cが成功すればおｋ
# という考察を深めると、cとdの位置関係だけに注目すればいいことがわかる（わかる？）
# d < cのとき、aがcにいくためにbを飛び越えなければならない。飛び越えるには"..."の真ん中を避難地帯としてbを置くしかない

n, a, b, c, d = map(int, input().split())
s = list(input())
if set(s) == 1:
  print("Yes")
  exit()
if c < d:
    if "##" not in "".join(s[a - 1 : c]):
        print("Yes")
    else:
        print("No")
else:
    if (
        "##" not in "".join(s[a - 1 : c])
        and "##" not in "".join(s[b - 1 : d])
        and "..." in "".join(s[b - 1 : d])
    ):
        print("Yes")
    else:
        print("No")