Problem:
Score : 200 points

Problem Statement

A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:

S is a palindrome.

Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.

The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.

Determine whether S is a strong palindrome.

Constraints

S consists of lowercase English letters.

The length of S is an odd number between 3 and 99 (inclusive).

Input

Input is given from Standard Input in the following format:

S

Output

If S is a strong palindrome, print Yes;
otherwise, print No.

Sample Input 1

akasaka

Sample Output 1

Yes

S is akasaka.

The string formed by the 1-st through the 3-rd characters is aka.

The string formed by the 5-th through the 7-th characters is aka.
All of these are palindromes, so S is a strong palindrome.

Sample Input 2

level

Sample Output 2

No

Sample Input 3

atcoder

Sample Output 3

No

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

s = input()
if len(s) / 2 == 0:
    print("No")
    exit()

def check(i):
    if len(i) / 2 != 0:
        i2 = i[len(i) // 2 + 1:len(i)]
    else:
        i2 = i[len(i) // 2:len(i)]
    if i[0:len(i) // 2] == i2[::-1]:
        return(True)
    return(False)

def check2(i):
    i2 = i[len(i) // 2:len(i)]
    if i[0:len(i) // 2] == i2[::-1]:
        return(True)
    return(False)

s2 = s[0:(len(s) - 1) // 2]
if len(s2) != 0:
    s3 = s[(len(s) - 1) // 2 + 1:len(s)]
else:
    s3 = s[(len(s) - 1) // 2:len(s)]

if check(s) == True and check(s2) == True and check(s3) == True:
    print("Yes")
else:
    print("No")