Problem:
Score : 400 points

Problem Statement

Given are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.

Let a semi-common multiple of A be a positive integer X that satisfies the following condition for every k (1 \leq k \leq N):

There exists a non-negative integer p such that X= a_k \times (p+0.5).

Find the number of semi-common multiples of A among the integers between 1 and M (inclusive).

Constraints

1 \leq N \leq 10^5

1 \leq M \leq 10^9

2 \leq a_i \leq 10^9

a_i is an even number.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
a_1 a_2 ... a_N

Output

Print the number of semi-common multiples of A among the integers between 1 and M (inclusive).

Sample Input 1

2 50
6 10

Sample Output 1

2

15 = 6 \times 2.5

15 = 10 \times 1.5

45 = 6 \times 7.5

45 = 10 \times 4.5

Thus, 15 and 45 are semi-common multiples of A. There are no other semi-common multiples of A between 1 and 50, so the answer is 2.

Sample Input 2

3 100
14 22 40

Sample Output 2

0

The answer can be 0.

Sample Input 3

5 1000000000
6 6 2 6 2

Sample Output 3

166666667

Solution in PyPy3 (2.4.0) (judge verdict: Wrong Answer)

import fractions


def lcm(x, y):
    return (x * y) // fractions.gcd(x, y)


n, m = map(int, input().split())
v = list(map(int, input().split()))
num = 0
# print(v[0])
while (v[0] % 2 == 0):
    v[0] //= 2
    num += 1
# print(v[0])
ans = v[0]
for i in range(n - 1):
    if (v[i + 1] % (2 ** num) != 0 or v[i + 1] % (2 ** (num + 1)) == 0):
        ans = 2
        break
    # print(v[i+1])
    v[i+1] //= 2**num
    # print(v[i+1])
    ans = lcm(ans, v[i + 1])
# print(ans)
if (ans % 2 == 0):
    print(0)
    exit(0)
ans *= 2**(num-1)
print(ans, m)
print(((m//ans)+1)//2)