Problem:
Score : 200 points

Problem Statement

A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:

S is a palindrome.

Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.

The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.

Determine whether S is a strong palindrome.

Constraints

S consists of lowercase English letters.

The length of S is an odd number between 3 and 99 (inclusive).

Input

Input is given from Standard Input in the following format:

S

Output

If S is a strong palindrome, print Yes;
otherwise, print No.

Sample Input 1

akasaka

Sample Output 1

Yes

S is akasaka.

The string formed by the 1-st through the 3-rd characters is aka.

The string formed by the 5-th through the 7-th characters is aka.
All of these are palindromes, so S is a strong palindrome.

Sample Input 2

level

Sample Output 2

No

Sample Input 3

atcoder

Sample Output 3

No

Solution in PyPy3 (2.4.0) (judge verdict: Wrong Answer)

S=input()
N=len(S)
a=[]
b=[]
c=[]
d=[]

for i in range((N-1)//2):
    if((N-1)//2%2==1):
        if((N-1)//4>i ):
            a.append(S[i])

        elif((N-1)//4!=i):
            b.append(S[i])
    else:
        print('a')
        if((N-1)//4>i ):
            a.append(S[i])

        elif((N-1)//4==i):
            b.append(S[i])

        elif((N-1)//4!=i):
            b.append(S[i])
print(a)
print(b)
if(a==b):
    if(S==S[::-1]):

        print('Yes')
    else:
        print('No')
    exit(0)

    for i in range((N+3)//2-1,N):
        if(((N+3)//2-1+N)//2>i ):
            c.append(S[i])
        elif(((N+3)//2-1+N)//2!=i):
            d.append(S[i])
    if(c==d):
        if(S==S[::-1]):

            print('Yes')
        else:
            print('No')
    else:
        print('No')
else:
    print('No')