Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

s=list(input())
a=s[0],s[1]
b=s[2],s[3]
a="".join(a);a=int(a)
b="".join(b);b=int(b)
yymmcount=0
mmyycount=0
my=0
na=["NA","","AMBIGUOUS"]
#print("s[0,1]=",a,"s[2,3]=",b)
if b<=12 and a!=00:
    yymmcount+=1
    my+=1
if a<=12 and b!=00:
    mmyycount+=1
    my+=1
if yymmcount==1 and mmyycount==0:
    print("YYMM")
else:
    if mmyycount==1 and yymmcount==0:
        print("MMYY")
    else:
        c=na[my]
        print(c)