Problem:
Score : 400 points

Problem Statement

We have N balls. The i-th ball has an integer A_i written on it.

For each k=1, 2, ..., N, solve the following problem and print the answer.

Find the number of ways to choose two distinct balls (disregarding order) from the N-1 balls other than the k-th ball so that the integers written on them are equal.

Constraints

3 \leq N \leq 2 \times 10^5

1 \leq A_i \leq N

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

For each k=1,2,...,N, print a line containing the answer.

Sample Input 1

5
1 1 2 1 2

Sample Output 1

2
2
3
2
3

Consider the case k=1 for example. The numbers written on the remaining balls are 1,2,1,2.

From these balls, there are two ways to choose two distinct balls so that the integers written on them are equal.

Thus, the answer for k=1 is 2.

Sample Input 2

4
1 2 3 4

Sample Output 2

0
0
0
0

No two balls have equal numbers written on them.

Sample Input 3

5
3 3 3 3 3

Sample Output 3

6
6
6
6
6

Any two balls have equal numbers written on them.

Sample Input 4

8
1 2 1 4 2 1 4 1

Sample Output 4

5
7
5
7
7
5
7
5

Solution in Python (3.4.3) (judge verdict: Time Limit Exceeded)

"""
"""
from math import factorial
from collections import defaultdict


def int_as_array(num): return list(map(int, [y for y in str(num)]))


def array_as_int(arr): return int(''.join(map(str, arr)))


def read_int(): return int(input())


def read_array(): return list(map(int, input().split(' ')))


def array_to_string(arr, sep=' '): return sep.join(map(str, arr))


def matrix_to_string(arr, sep=' '): return '[\n' + '\n'.join(
    [sep.join(map(str, row)) for row in arr]) + '\n]'


cache = {}


def fac(x):
    if cache.get(x) is not None:
        return cache[x]
    ans = factorial(x)
    cache[x] = ans
    return ans


def choose_combination(n, r):
    if r > n:
        return 0
    return int((fac(n) / fac((n - r))) * (1 / fac(r)))


def solve(n, array):
    counts = defaultdict(int)
    for x in array:
        counts[x] += 1
    for k_i, k in enumerate(array):
        ways = 0
        for x, count in counts.items():
            adjusted_count = counts[x]
            if x == k:
                adjusted_count -= 1
            ways += choose_combination(adjusted_count, 2)
        print(ways)


N = read_int()
array = read_array()
solve(N, array)