Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

N = int(input())
count_yakusu=0
count_number=0
for i in range((N-105)//2+1):
  for j in range((i+105)//2+1):
    if((i+105) % (2*j+1)==0):
      count_yakusu+=1
    else:continue
  if(count_yakusu==8):
    count_number+=1
  else:continue
print(count_number)