Problem:
Score : 500 points

Problem Statement

Let us denote by f(x, m) the remainder of the Euclidean division of x by m.

Let A be the sequence that is defined by the initial value A_1=X and the recurrence relation A_{n+1} = f(A_n^2, M).
Find \displaystyle{\sum_{i=1}^N A_i}.

Constraints

1 \leq N \leq 10^{10}

0 \leq X < M \leq 10^5

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X M

Output

Print \displaystyle{\sum_{i=1}^N A_i}.

Sample Input 1

6 2 1001

Sample Output 1

1369

The sequence A begins 2,4,16,256,471,620,\ldots Therefore, the answer is 2+4+16+256+471+620=1369.

Sample Input 2

1000 2 16

Sample Output 2

6

The sequence A begins 2,4,0,0,\ldots Therefore, the answer is 6.

Sample Input 3

10000000000 10 99959

Sample Output 3

492443256176507

Solution in PyPy3 (7.3.0) (judge verdict: Runtime Error)

n, x, m = map(int,input().split())
ans = x
num = 0
l = [0]*(n//10)
lis = [-1]*m
l[0] = x
lis[x] = num
for i in range(1,n):
    x = (x*x)%m
    num += 1
    if lis[x]!=-1:
        a = (n-i)//(i-lis[x])
        b = (n-i)%(i-lis[x])
        ans += a * sum(l[lis[x]:i])
        break
    l[i] = x
    lis[x] = i
    ans += x
for i in range(lis[x],lis[x]+b):
    ans += l[i]
print(ans)