Problem:
Score : 400 points

Problem Statement

Give a pair of integers (A, B) such that A^5-B^5 = X.
It is guaranteed that there exists such a pair for the given integer X.

Constraints

1 \leq X \leq 10^9

X is an integer.

There exists a pair of integers (A, B) satisfying the condition in Problem Statement.

Input

Input is given from Standard Input in the following format:

X

Output

Print A and B, with space in between.
If there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.

A B

Sample Input 1

33

Sample Output 1

2 -1

For A=2 and B=-1, A^5-B^5 = 33.

Sample Input 2

1

Sample Output 2

0 -1

Solution in PyPy3 (7.3.0) (judge verdict: Accepted)

# coding: utf-8

import sys
import math
import collections
import itertools
import bisect
INF = 10 ** 13
MOD = 10 ** 9 + 7
def input() : return sys.stdin.readline().strip()
def lcm(x, y) : return (x * y) // math.gcd(x, y)
def I() : return int(input())
def LI() : return [int(x) for x in input().split()]
def RI(N) : return [int(input()) for _ in range(N)]
def LRI(N) : return [[int(x) for x in input().split()] for _ in range(N)]
def LS() : return input().split()
def RS(N) : return [input() for _ in range(N)]
def LRS(N) : return [input().split() for _ in range(N)]
def PL(L) : print(*L, sep="\n")
def YesNo(B) : print("Yes" if B else "No")
def YESNO(B) : print("YES" if B else "NO")

X = I()

P = [pow(i, 5) for i in range(1000000)]

m = False
i = 0
j = 0
for q, a in enumerate(P):
    s1 = bisect.bisect_left(P, a - X)
    s2 = bisect.bisect_left(P, X - a)

    if a - X == P[s1]:
        i = q
        j = s1
        break
    if X - a == P[s2]:
        i = q
        j = s2
        m = True
        break

print(i, end=" ")
print("-" if m else "", end ="")
print(j)