Problem:
Score : 300 points

Problem Statement

Takahashi has N balls. Initially, an integer A_i is written on the i-th ball.

He would like to rewrite the integer on some balls so that there are at most K different integers written on the N balls.

Find the minimum number of balls that Takahashi needs to rewrite the integers on them.

Constraints

1 \leq K \leq N \leq 200000

1 \leq A_i \leq N

All input values are integers.

Input

Input is given from Standard Input in the following format:

N K
A_1 A_2 ... A_N

Output

Print the minimum number of balls that Takahashi needs to rewrite the integers on them.

Sample Input 1

5 2
1 1 2 2 5

Sample Output 1

1

For example, if we rewrite the integer on the fifth ball to 2, there are two different integers written on the balls: 1 and 2.
On the other hand, it is not possible to rewrite the integers on zero balls so that there are at most two different integers written on the balls, so we should print 1.

Sample Input 2

4 4
1 1 2 2

Sample Output 2

0

Already in the beginning, there are two different integers written on the balls, so we do not need to rewrite anything.

Sample Input 3

10 3
5 1 3 2 4 1 1 2 3 4

Sample Output 3

3

Solution in PyPy3 (2.4.0) (judge verdict: Accepted)

#!usr/bin/env python3
from collections import defaultdict
from collections import deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS():return list(map(list, sys.stdin.readline().split()))
def S(): return list(sys.stdin.readline())[:-1]
def IR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = I()
    return l
def LIR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = LI()
    return l
def SR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = S()
    return l
def LSR(n):
    l = [None for i in range(n)]
    for i in range(n):l[i] = LS()
    return l
sys.setrecursionlimit(1000000)
mod = 1000000007

#A
def A():
    n,a,b = LI()
    print(min(n*a,b))
    return

#B
def B():
    s = S()
    print(s.count("1"))
    return

#C
def C():
    n = list(map(int, S()))
    k = 0
    s = sum(n)
    for i in range(len(n)):
        k *= 10
        k += n[i]
    if k%s == 0:
        print("Yes")
    else:
        print("No")
    return

#D
def D():
    n = I()
    a = LI()
    ans = float("inf")
    for i in range(n):
        m = 0
        while a[i]%2 == 0:
            m += 1
            a[i] //= 2
        ans = min(m,ans)
    print(ans)
    return

#E
def E():
    n = I()
    f = LIR(n)
    p = LIR(n)

    return

#F
def F():
    n,k = LI()
    a = LI()
    d = defaultdict(int)
    for i in a:
        d[i] += 1
    d = list(d.values())
    d.sort()
    ans = 0
    for i in range(len(d)-k):
        ans += d[i]
    print(ans)
    return

#G
def G():
    return

#H
def H():
    return

#I
def I_():
    return

#J
def J():
    return

#Solve
if __name__ == "__main__":
    F()