Problem:
Score : 500 points

Problem Statement

You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)

Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

N, Q, i_q, l_q, and r_q are integers.

S is a string consisting of lowercase English letters.

c_q is a lowercase English letter.

1 \leq N \leq 500000

1 \leq Q \leq 20000

|S| = N

1 \leq i_q \leq N

1 \leq l_q \leq r_q \leq N

There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:

N
S
Q
Query_1
\vdots
Query_Q

Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:

1 i_q c_q

2 l_q r_q

Output

For each query of type 2, print a line containing the answer.

Sample Input 1

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7

Sample Output 1

3
1
5

In the first query, cdbb contains three kinds of letters: b , c , and d, so we print 3.

In the second query, S is modified to abcdzbd.

In the third query, a contains one kind of letter: a, so we print 1.

In the fourth query, S is modified to abcazbd.

In the fifth query, S does not change and is still abcazbd.

In the sixth query, abcazbd contains five kinds of letters: a, b, c, d, and z, so we print 5.

Solution in PyPy3 (7.3.0) (judge verdict: Accepted)

import sys
input = sys.stdin.readline

def solve():
    ordA = ord('a')

    N = int(input())
    Ss = input().rstrip()
    Q = int(input())
    querys = [tuple(input().split()) for _ in range(Q)]

    idEle = 0
    def _binOpe(x, y):
        return x | y
    def makeSegTree(numEle):
        numPow2 = 2 ** (numEle-1).bit_length()
        data = [idEle] * (2*numPow2)
        return data, numPow2
    def setInit(As):
        for iST, A in enumerate(As, numPow2):
            data[iST] = A
        for iST in reversed(range(1, numPow2)):
            data[iST] = _binOpe(data[2*iST], data[2*iST+1])
    def _update1(iA, A):
        iST = iA + numPow2
        data[iST] = A
    def update(iA, A):
        _update1(iA, A)
        iST = iA + numPow2
        while iST > 1:
            iST >>= 1
            data[iST] = _binOpe(data[2*iST], data[2*iST+1])
    def getValue(iSt, iEn):
        L = iSt + numPow2
        R = iEn + numPow2
        ans = idEle
        while L < R:
            if L & 1:
                ans = _binOpe(ans, data[L])
                L += 1
            if R & 1:
                R -= 1
                ans = _binOpe(ans, data[R])
            L >>= 1
            R >>= 1
        return ans

    data, numPow2 = makeSegTree(N)
    As = [(1<<(ord(S)-ordA)) for S in Ss]
    setInit(As)

    anss = []
    for tp, *vs in querys:
        if tp == '1':
            i, c = vs
            i = int(i)
            update(i-1, 1<<(ord(c)-ordA))
        else:
            L, R = vs
            L, R = int(L), int(R)
            v = getValue(L-1, R)
            anss.append(bin(v).count('1'))

    print('\n'.join(map(str, anss)))


solve()