Problem:
Score : 400 points

Problem Statement

An altar enshrines N stones arranged in a row from left to right. The color of the i-th stone from the left (1 \leq i \leq N) is given to you as a character c_i; R stands for red and W stands for white.

You can do the following two kinds of operations any number of times in any order:

Choose two stones (not necessarily adjacent) and swap them.

Choose one stone and change its color (from red to white and vice versa).

According to a fortune-teller, a white stone placed to the immediate left of a red stone will bring a disaster. At least how many operations are needed to reach a situation without such a white stone?

Constraints

2 \leq N \leq 200000

c_i is R or W.

Input

Input is given from Standard Input in the following format:

N
c_{1}c_{2}...c_{N}

Output

Print an integer representing the minimum number of operations needed.

Sample Input 1

4
WWRR

Sample Output 1

2

For example, the two operations below will achieve the objective.

Swap the 1-st and 3-rd stones from the left, resulting in RWWR.

Change the color of the 4-th stone from the left, resulting in RWWW.

Sample Input 2

2
RR

Sample Output 2

0

It can be the case that no operation is needed.

Sample Input 3

8
WRWWRWRR

Sample Output 3

3

Solution in PyPy3 (7.3.0) (judge verdict: Accepted)

n = int(input())
c = list(input())
sc = list(reversed(c))
ans = 0
r = 0
flg  = False

if 'W' not in set(c) or 'R' not in set(c):
    print(ans)


else:
    for i in range(n):
        if flg:
            break
        if c[i] == 'W':
            for j in range(r, n):
                r += 1
                if sc[j] == 'R':
                    if n >= i+j+2:
                        c[i] = 'R'
                        c[-1*j-1] = 'W'
                        ans += 1
                        break
                    else:
                        flg = True
                        break

                
            

    print(ans)