Problem:
Score : 400 points

Problem Statement

There are N people standing on the x-axis.
Let the coordinate of Person i be x_i.
For every i, x_i is an integer between 0 and 10^9 (inclusive).
It is possible that more than one person is standing at the same coordinate.

You will given M pieces of information regarding the positions of these people.
The i-th piece of information has the form (L_i, R_i, D_i).
This means that Person R_i is to the right of Person L_i by D_i units of distance, that is, x_{R_i} - x_{L_i} = D_i holds.

It turns out that some of these M pieces of information may be incorrect.
Determine if there exists a set of values (x_1, x_2, ..., x_N) that is consistent with the given pieces of information.

Constraints

1 \leq N \leq 100 000

0 \leq M \leq 200 000

1 \leq L_i, R_i \leq N (1 \leq i \leq M)

0 \leq D_i \leq 10 000 (1 \leq i \leq M)

L_i \neq R_i (1 \leq i \leq M)

If i \neq j, then (L_i, R_i) \neq (L_j, R_j) and (L_i, R_i) \neq (R_j, L_j).

D_i are integers.

Input

Input is given from Standard Input in the following format:

N M
L_1 R_1 D_1
L_2 R_2 D_2
:
L_M R_M D_M

Output

If there exists a set of values (x_1, x_2, ..., x_N) that is consistent with all given pieces of information, print Yes; if it does not exist, print No.

Sample Input 1

3 3
1 2 1
2 3 1
1 3 2

Sample Output 1

Yes

Some possible sets of values (x_1, x_2, x_3) are (0, 1, 2) and (101, 102, 103).

Sample Input 2

3 3
1 2 1
2 3 1
1 3 5

Sample Output 2

No

If the first two pieces of information are correct, x_3 - x_1 = 2 holds, which is contradictory to the last piece of information.

Sample Input 3

4 3
2 1 1
2 3 5
3 4 2

Sample Output 3

Yes

Sample Input 4

10 3
8 7 100
7 9 100
9 8 100

Sample Output 4

No

Sample Input 5

100 0

Sample Output 5

Yes

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

class UnionFind():
    def __init__(self, n):
        self.n = n
        self.root = [-1]*(n+1)
        self.rnk = [0]*(n+1)
        self.weight = [0]*(n+1)
 
    def Find_Root(self, x):
        if(self.root[x] < 0):
            return x
        else:
            self.root[x] = self.Find_Root(self.root[x])
            self.weight[x] += self.weight[self.root[x]]
            return self.root[x]

    def GetWeight(self, x):
      self.Find_Root(x)
      return self.weight[x]

    def Unite(self, x, y, w):
        w += self.GetWeight(x)
        w -= self.GetWeight(y)
        x = self.Find_Root(x)
        y = self.Find_Root(y)
        if(x == y):
            return False

        if self.rnk[x] < self.rnk[y]:
            x, y = y, x
            w = -w
        if self.rnk[x] == self.rnk[y]:
            self.rnk[x] += 1
        
        self.root[y] = x
        self.weight[y] = w

        return True
 
    def isSameGroup(self, x, y):
        return self.Find_Root(x) == self.Find_Root(y)
 
    def Count(self, x):
        return -self.root[self.Find_Root(x)]
    
    def Diff(self, x, y):
      if self.isSameGroup(x, y):
        return abs(self.GetWeight(y)- self.GetWeight(x))
      else:
        return None

def main():
  N, M = map(int, input().split())
  lrd = [list(map(int, input().split())) for _ in range(M)]
  U = UnionFind(N)

  for i in range(M):
    l, r, d = lrd[i]
    U.Unite(l, r, d)
  for i in range(M):
    l, r, d = lrd[i]
    if U.isSameGroup(l, r):
      if U.Diff(l, r) != d:
        print('No')
        exit()
  print('Yes')
  
    
if __name__ == "__main__":
  main()