Problem:
Score: 300 points

Problem Statement

We have a 3 \times 3 grid. A number c_{i, j} is written in the square (i, j), where (i, j) denotes the square at the i-th row from the top and the j-th column from the left.

According to Takahashi, there are six integers a_1, a_2, a_3, b_1, b_2, b_3 whose values are fixed, and the number written in the square (i, j) is equal to a_i + b_j.

Determine if he is correct.

Constraints

c_{i, j} \ (1 \leq i \leq 3, 1 \leq j \leq 3) is an integer between 0 and 100 (inclusive).

Input

Input is given from Standard Input in the following format:

c_{1,1} c_{1,2} c_{1,3}
c_{2,1} c_{2,2} c_{2,3}
c_{3,1} c_{3,2} c_{3,3}

Output

If Takahashi's statement is correct, print Yes; otherwise, print No.

Sample Input 1

1 0 1
2 1 2
1 0 1

Sample Output 1

Yes

Takahashi is correct, since there are possible sets of integers such as: a_1=0,a_2=1,a_3=0,b_1=1,b_2=0,b_3=1.

Sample Input 2

2 2 2
2 1 2
2 2 2

Sample Output 2

No

Takahashi is incorrect in this case.

Sample Input 3

0 8 8
0 8 8
0 8 8

Sample Output 3

Yes

Sample Input 4

1 8 6
2 9 7
0 7 7

Sample Output 4

No

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

c = [[]]*3

for i in range(3):
    c[i] = list(map(int, input().split()))
ans = 0
for i in range(3):
    ans += sum(c[i])

if ans % 3 == 0:
    arr = [[0]* 3]*3
    for i in range(3):
        arr[i][0] = c[i][0] - c[i][1]
        arr[i][1] = c[i][0] - c[i][2]
        arr[i][2] = c[i][1] - c[i][2]
    
    for i in range(3):
        if arr[0][i] == arr[1][i] and arr[0][i] == arr[2][i]:
            continue
        else:
            print("No")
            exit(0)
    arr = [[0]* 3]*3
    for i in range(3):
        arr[i][0] = c[0][i] - c[1][i]
        arr[i][1] = c[0][i] - c[2][i]
        arr[i][2] = c[1][i] - c[2][i]
            
    for i in range(3):
        if arr[0][i] == arr[1][i] and arr[0][i] == arr[2][i]:
            continue
        else:
            print("No")
            exit(0)


    print("Yes")
    exit(0)

print("No")