Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in Python (3.8.2) (judge verdict: Runtime Error)

n = int(input())
n_lst = []
for i in range(n):
    n_lst.append(i+1)
    
##共通
kosu = n // 15

##3の倍数
a3 = n // 3
lst3 = []
for i in range(a3):
    n3 = 3 * (i+1)
    lst3.append(n3)

##5の倍数
a5 = n // 5
lst5 = []
for i in range(a5):
    n5 = 5 * (i+1)
    lst5.append(n5)

kosu2 = a5 - kosu
    
###リストから取り除く.strip
for i in range(a3):
    n_lst.remove(lst3[i])
for i in range(kosu2):
    n_lst.remove(lst5[i])
    
goke = sum(n_lst)
print(goke)