Problem:
Score : 300 points

Problem Statement

You are given a string s.
Among the different substrings of s, print the K-th lexicographically smallest one.

A substring of s is a string obtained by taking out a non-empty contiguous part in s.
For example, if s = ababc, a, bab and ababc are substrings of s, while ac, z and an empty string are not.
Also, we say that substrings are different when they are different as strings.

Let X = x_{1}x_{2}...x_{n} and Y = y_{1}y_{2}...y_{m} be two distinct strings. X is lexicographically larger than Y if and only if Y is a prefix of X or x_{j} > y_{j} where j is the smallest integer such that x_{j} \neq y_{j}.

Constraints

1 ≤ |s| ≤ 5000

s consists of lowercase English letters.

1 ≤ K ≤ 5

s has at least K different substrings.

Partial Score

200 points will be awarded as a partial score for passing the test set satisfying |s| ≤ 50.

Input

Input is given from Standard Input in the following format:

s
K

Output

Print the K-th lexicographically smallest substring of K.

Sample Input 1

aba
4

Sample Output 1

b

s has five substrings: a, b, ab, ba and aba.
Among them, we should print the fourth smallest one, b.
Note that we do not count a twice.

Sample Input 2

atcoderandatcodeer
5

Sample Output 2

andat

Sample Input 3

z
1

Sample Output 3

z

Solution in PyPy3 (7.3.0) (judge verdict: Time Limit Exceeded)

# kが極端に少ないので、下位K個を管理してよさそうな気がする
# -> なんかダメ
# じゃ決め打ちして全探索することにしてみる どうせ長さは最大でKなので
# 時間的に間に合うか微妙な気がする
from string import ascii_lowercase
s = input()
k = int(input())
cur = 0


def f(v):
    global cur
    if len(v) <= k:
        if v in s:
            cur += 1
        if cur == k:
            print(v)
            exit()
        else:
            for c in ascii_lowercase:
                f(v + c)


for c in ascii_lowercase:
    f(c)