Problem:
Score : 400 points

Problem Statement

Akari has n kinds of flowers, one of each kind.

She is going to choose one or more of these flowers to make a bouquet.

However, she hates two numbers a and b, so the number of flowers in the bouquet cannot be a or b.

How many different bouquets are there that Akari can make?

Find the count modulo (10^9 + 7).

Here, two bouquets are considered different when there is a flower that is used in one of the bouquets but not in the other bouquet.

Constraints

All values in input are integers.

2 \leq n \leq 10^9

1 \leq a < b \leq \textrm{min}(n, 2 \times 10^5)

Input

Input is given from Standard Input in the following format:

n a b

Output

Print the number of bouquets that Akari can make, modulo (10^9 + 7). (If there are no such bouquets, print 0.)

Sample Input 1

4 1 3

Sample Output 1

7

In this case, Akari can choose 2 or 4 flowers to make the bouquet.

There are 6 ways to choose 2 out of the 4 flowers, and 1 way to choose 4, so there are a total of 7 different bouquets that Akari can make.

Sample Input 2

1000000000 141421 173205

Sample Output 2

34076506

Print the count modulo (10^9 + 7).

Solution in Python (3.4.3) (judge verdict: Accepted)

import sys
input = sys.stdin.buffer.readline

N, A, B = map(int, input().split())
MOD = 10 ** 9 + 7
SIZE = 10 ** 6 + 1

g1 = [1, 1]      # 元テーブル
g2 = [1, 1]      # 逆元テーブル
inverse = [0, 1] # 逆元テーブル計算用テーブル

def comb(n, r, mod):
    if r < 0 or r > n:
        return 0
    r = min(r, n - r)
    return g1[n] * g2[r] * g2[n - r] % mod

for i in range(2, SIZE + 1):
    g1.append((g1[-1] * i) % MOD)
    inverse.append((-inverse[MOD % i] * (MOD // i) ) % MOD)
    g2.append((g2[-1] * inverse[-1]) % MOD)

def comb(N, X):
    bunbo = 1
    for x in range(X):
        bunbo = (bunbo * (N - x)) % MOD
    return (bunbo * g2[X]) % MOD

answer = (pow(2, N, MOD) - 1 - comb(N, A) - comb(N, B)) % MOD

print(answer)