Problem:
Score : 600 points

Problem Statement

Silver Fox is fighting with N monsters.

The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the health of H_i.

Silver Fox can use bombs to attack the monsters.
Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A.
There is no way other than bombs to decrease the monster's health.

Silver Fox wins when all the monsters' healths become 0 or below.

Find the minimum number of bombs needed to win.

Constraints

1 \leq N \leq 2 \times 10^5

0 \leq D \leq 10^9

1 \leq A \leq 10^9

0 \leq X_i \leq 10^9

1 \leq H_i \leq 10^9

X_i are distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N D A
X_1 H_1
:
X_N H_N

Output

Print the minimum number of bombs needed to win.

Sample Input 1

3 3 2
1 2
5 4
9 2

Sample Output 1

2

First, let us use a bomb at the coordinate 4 to decrease the first and second monsters' health by 2.

Then, use a bomb at the coordinate 6 to decrease the second and third monsters' health by 2.

Now, all the monsters' healths are 0.
We cannot make all the monsters' health drop to 0 or below with just one bomb.

Sample Input 2

9 4 1
1 5
2 4
3 3
4 2
5 1
6 2
7 3
8 4
9 5

Sample Output 2

5

We should use five bombs at the coordinate 5.

Sample Input 3

3 0 1
300000000 1000000000
100000000 1000000000
200000000 1000000000

Sample Output 3

3000000000

Watch out for overflow.

Solution in PyPy3 (2.4.0) (judge verdict: Time Limit Exceeded)

from operator import itemgetter
import sys

# スペース区切りの整数入力
n,d,a = map(int, input().split())

#指定数分の2つの整数を順番に受けてリストに入力
e = []
for i in range(n):
    e.append([int(x) for x in input().split()])
e.sort(key=itemgetter(0))

atk_times_sum = 0

while len(e) > 0:
    atk_l = e[0][0]
    atk_u = e[0][0] + d*2
    if e[0][1] % a == 0:
        atk_times = int(e[0][1] / a)
    else:
        atk_times = int(e[0][1] / a) + 1
    atk_times_sum += atk_times
    for i in range(len(e)-1,-1,-1):
        if atk_l <= e[i][0] and e[i][0] <= atk_u:
            e[i][1] -=  a * atk_times
            if e[i][1] <=  0:
                del(e[i])

print(atk_times_sum)