Problem:
Score : 300 points

Problem Statement

"Pizza At", a fast food chain, offers three kinds of pizza: "A-pizza", "B-pizza" and "AB-pizza". A-pizza and B-pizza are completely different pizzas, and AB-pizza is one half of A-pizza and one half of B-pizza combined together. The prices of one A-pizza, B-pizza and AB-pizza are A yen, B yen and C yen (yen is the currency of Japan), respectively.

Nakahashi needs to prepare X A-pizzas and Y B-pizzas for a party tonight. He can only obtain these pizzas by directly buying A-pizzas and B-pizzas, or buying two AB-pizzas and then rearrange them into one A-pizza and one B-pizza. At least how much money does he need for this? It is fine to have more pizzas than necessary by rearranging pizzas.

Constraints

1 ≤ A, B, C ≤ 5000

1 ≤ X, Y ≤ 10^5

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B C X Y

Output

Print the minimum amount of money required to prepare X A-pizzas and Y B-pizzas.

Sample Input 1

1500 2000 1600 3 2

Sample Output 1

7900

It is optimal to buy four AB-pizzas and rearrange them into two A-pizzas and two B-pizzas, then buy additional one A-pizza.

Sample Input 2

1500 2000 1900 3 2

Sample Output 2

8500

It is optimal to directly buy three A-pizzas and two B-pizzas.

Sample Input 3

1500 2000 500 90000 100000

Sample Output 3

100000000

It is optimal to buy 200000 AB-pizzas and rearrange them into 100000 A-pizzas and 100000 B-pizzas. We will have 10000 more A-pizzas than necessary, but that is fine.

Solution in PyPy3 (2.4.0) (judge verdict: Accepted)

# coding:utf-8

import sys
import math
import time
#import numpy as np
import collections
from collections import deque
import queue
import copy


#X = str(input()).split()
#a = [int(x) for x in input().split()]


ABCXY = str(input()).split()
A = int(ABCXY[0])
B = int(ABCXY[1])
C = int(ABCXY[2])
X = int(ABCXY[3])
Y = int(ABCXY[4])
ans1 = 0
ans2 = 0
ans3 = 0

XY = X

ans3=C*2*Y + A*(X-Y)

if(X<Y):
  XY = Y
  ans3 = C*2*X + B*(Y-X)


ans1 = A*X+B*Y
ans2 = C*2*XY

ans = min(ans1,ans2)
ans = min(ans,ans3)


print(ans)