Problem:
Score : 500 points

Problem Statement

You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)

Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

N, Q, i_q, l_q, and r_q are integers.

S is a string consisting of lowercase English letters.

c_q is a lowercase English letter.

1 \leq N \leq 500000

1 \leq Q \leq 20000

|S| = N

1 \leq i_q \leq N

1 \leq l_q \leq r_q \leq N

There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:

N
S
Q
Query_1
\vdots
Query_Q

Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:

1 i_q c_q

2 l_q r_q

Output

For each query of type 2, print a line containing the answer.

Sample Input 1

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7

Sample Output 1

3
1
5

In the first query, cdbb contains three kinds of letters: b , c , and d, so we print 3.

In the second query, S is modified to abcdzbd.

In the third query, a contains one kind of letter: a, so we print 1.

In the fourth query, S is modified to abcazbd.

In the fifth query, S does not change and is still abcazbd.

In the sixth query, abcazbd contains five kinds of letters: a, b, c, d, and z, so we print 5.

Solution in PyPy3 (2.4.0) (judge verdict: Accepted)

import sys
from operator import or_
input=sys.stdin.readline


class SegTree():
    def __init__(self, N, e=float("inf"), operator_func=min):
        self.e = e
        self.size = N
        self.node = [self.e] * (2*N)
        self.op = operator_func

    def set_list(self, l):
        for i in range(self.size):
            self.node[i+self.size-1] = l[i]
        for i in range(self.size-1)[::-1]:
            self.node[i] = self.op(self.node[2*i+1], self.node[2*i+2])
    
    def update(self, k, x):
        k += self.size - 1
        self.node[k] = x
        while k >= 0:
            k = (k - 1) // 2
            self.node[k] = self.op(self.node[2*k+1], self.node[2*k+2])

    def get(self, l, r):
        x = self.e
        l += self.size; r += self.size
        a, b = [], []

        while l<r:
            if l&1:
                a += [l-1]; l += 1
            if r&1:
                r -= 1; b += [r-1]
            l >>= 1; r >>= 1

        for i in a+(b[::-1]):
            x = self.op(x, self.node[i])
        return x


def main():
    N = int(input())
    S = list(input())[:-1]
    trees = {chr(97+i):SegTree(N, e=False, operator_func=or_) for i in range(26)}

    for i, s in enumerate(S):
        trees[s].update(i, True)

    Q = int(input())
    for _ in range(Q):
        mode, i, v = input().split()
        if mode=="1":
            i = int(i)-1
            trees[S[i]].update(i, False)
            trees[v].update(i, True)
            S[i] = v
        else:
            i = int(i)-1
            v = int(v)
            ans = 0
            for j in range(26):
                ans += trees[chr(97+j)].get(i, v)
            print(ans)


if __name__ == "__main__":
    main()