Problem:
Score : 600 points

Problem Statement

Given are a sequence of N positive integers A_1, A_2, \ldots, A_N and another positive integer S.

For a non-empty subset T of the set \{1, 2, \ldots , N \}, let us define f(T) as follows:

f(T) is the number of different non-empty subsets \{x_1, x_2, \ldots , x_k \} of T such that A_{x_1}+A_{x_2}+\cdots +A_{x_k} = S.

Find the sum of f(T) over all 2^N-1 subsets T of \{1, 2, \ldots , N \}. Since the sum can be enormous, print it modulo 998244353.

Constraints

All values in input are integers.

1 \leq N \leq 3000

1 \leq S \leq 3000

1 \leq A_i \leq 3000

Input

Input is given from Standard Input in the following format:

N S
A_1 A_2 ... A_N

Output

Print the sum of f(T) modulo 998244353.

Sample Input 1

3 4
2 2 4

Sample Output 1

6

For each T, the value of f(T) is shown below. The sum of these values is 6.

f(\{1\}) = 0

f(\{2\}) = 0

f(\{3\}) = 1 (One subset \{3\} satisfies the condition.)

f(\{1, 2\}) = 1 (\{1, 2\})

f(\{2, 3\}) = 1 (\{3\})

f(\{1, 3\}) = 1 (\{3\})

f(\{1, 2, 3\}) = 2 (\{1, 2\}, \{3\})

Sample Input 2

5 8
9 9 9 9 9

Sample Output 2

0

Sample Input 3

10 10
3 1 4 1 5 9 2 6 5 3

Sample Output 3

3296

Solution in PyPy3 (7.3.0) (judge verdict: Runtime Error)

from functools import lru_cache
import sys
MOD = 998244353


@lru_cache(maxsize=None)
def pow_mod(i):
    # pow(2, i - 1, MOD)
    if i == 1:
        return 1
    else:
        return pow_mod(i - 1) * 2 % MOD


def main():
    input = sys.stdin.buffer.readline
    n, s = map(int, input().split())
    a = list(map(int, input().split()))
    dp = [[None] * (s + 1) for _ in range(n + 1)]
#     dp[i][j]:=集合{1..i}の空でない部分集合T全てについて,和がjとなる部分集合の個数の和
    for i in range(n + 1):
        for j in range(s + 1):
            if i == 0 or j == 0:
                dp[i][j] = 0
                continue
            if j > a[i - 1]:
                dp[i][j] = dp[i - 1][j] * 2 + dp[i - 1][j - a[i - 1]]
            elif j == a[i - 1]:
                dp[i][j] = dp[i - 1][j] * 2 + pow_mod(i)
            else:
                dp[i][j] = dp[i - 1][j] * 2
            dp[i][j] %= MOD
    print(dp[n][s])


if __name__ == '__main__':
    main()