Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Python (3.4.3) (judge verdict: Runtime Error)

l = list(map(int,input().split()))
N = l[0]
A = l[1] 
B = l[2]
C = l[3]
D = l[4]
S = input()
S_list = list(S)

if B < C < D :
    count = 0
    for i in range(A, D-2):
        if S_list[i] == S_list[i+1] == '#' :
            count += 1
    if count >= 1:
        print('No')
    else : 
        print('Yes')
elif C < B < D :
        count = 0
    for i in range(A, C-2):
        if S_list[i] == S_list[i+1] == '#' :
            count += 1
    for i in range(B, D-2):
        if S_list[i] == S_list[i+1] == '#' :
            count += 1
    if count >= 1:
        print('No')
    else :
        print('Yes')
elif B < D < C
    count = 0
    for i in range(A, C-2):
        if S_list[i] == S_list[i+1] == '#' :
            count += 1
    if count >= 1:
        print('No')
    count = 0
    for i in range(B-2, D-1):
        if S_list[i] == S_list[i+1] == S_list[i+2] == '.' :
            count += 1
    if count >= 1:
        print('Yes')  
    else:
        print('No')