Problem:
Score : 300 points

Problem Statement

A sequence a_1,a_2,... ,a_n is said to be /\/\/\/ when the following conditions are satisfied:

For each i = 1,2,..., n-2, a_i = a_{i+2}.

Exactly two different numbers appear in the sequence.

You are given a sequence v_1,v_2,...,v_n whose length is even.
We would like to make this sequence /\/\/\/ by replacing some of its elements.
Find the minimum number of elements that needs to be replaced.

Constraints

2 \leq n \leq 10^5

n is even.

1 \leq v_i \leq 10^5

v_i is an integer.

Input

Input is given from Standard Input in the following format:

n
v_1 v_2 ... v_n

Output

Print the minimum number of elements that needs to be replaced.

Sample Input 1

4
3 1 3 2

Sample Output 1

1

The sequence 3,1,3,2 is not /\/\/\/, but we can make it /\/\/\/ by replacing one of its elements: for example, replace the fourth element to make it 3,1,3,1.

Sample Input 2

6
105 119 105 119 105 119

Sample Output 2

0

The sequence 105,119,105,119,105,119 is /\/\/\/.

Sample Input 3

4
1 1 1 1

Sample Output 3

2

The elements of the sequence 1,1,1,1 are all the same, so it is not /\/\/\/.

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

import re
n = int(input())
vs = list(map(int, input().split()))
edic = {}
odic = {}

for i in range(n):
    item = vs[i]
    if i % 2 == 0:
        if item in edic:
            edic[item] += 1
        else:
            edic[item] = 1
    else:
        if item in odic:
            odic[item] += 1
        else:
            odic[item] = 1

elist = sorted(edic.items(), key=lambda x: -x[1])
olist = sorted(odic.items(), key=lambda x: -x[1])

if elist[0][0] != olist[0][0]:
    print(len(vs) - elist[0][1] - olist[0][1])
else:
    ogain = egain = 0
    if len(elist) >= 2:
        egain = elist[1][1]
    if len(olist) >= 2:
        ogain = olist[1][1]
    print(max(len(vs) - elist[0][1] - ogain, len(vs) - olist[0][1] - egain ))