Problem:
Score : 400 points

Problem Statement

Find the largest integer that can be formed with exactly N matchsticks, under the following conditions:

Every digit in the integer must be one of the digits A_1, A_2, ..., A_M (1 \leq A_i \leq 9).

The number of matchsticks used to form digits 1, 2, 3, 4, 5, 6, 7, 8, 9 should be 2, 5, 5, 4, 5, 6, 3, 7, 6, respectively.

Constraints

All values in input are integers.

2 \leq N \leq 10^4

1 \leq M \leq 9

1 \leq A_i \leq 9

A_i are all different.

There exists an integer that can be formed by exactly N matchsticks under the conditions.

Input

Input is given from Standard Input in the following format:

N M
A_1 A_2 ... A_M

Output

Print the largest integer that can be formed with exactly N matchsticks under the conditions in the problem statement.

Sample Input 1

20 4
3 7 8 4

Sample Output 1

777773

The integer 777773 can be formed with 3 + 3 + 3 + 3 + 3 + 5 = 20 matchsticks, and this is the largest integer that can be formed by 20 matchsticks under the conditions.

Sample Input 2

101 9
9 8 7 6 5 4 3 2 1

Sample Output 2

71111111111111111111111111111111111111111111111111

The output may not fit into a 64-bit integer type.

Sample Input 3

15 3
5 4 6

Sample Output 3

654

Solution in PyPy3 (2.4.0) (judge verdict: Runtime Error)

# -*- coding: utf-8 -*-
import bisect
import heapq
import math
import random
import sys
import copy
from collections import Counter, defaultdict, deque
from decimal import ROUND_CEILING, ROUND_HALF_UP, Decimal
from functools import lru_cache, reduce
from itertools import combinations, combinations_with_replacement, product, permutations
from operator import add, mul, sub

sys.setrecursionlimit(10000)


def read_int():
    return int(input())


def read_int_n():
    return list(map(int, input().split()))


def read_float():
    return float(input())


def read_float_n():
    return list(map(float, input().split()))


def read_str():
    return input().strip()


def read_str_n():
    return list(map(str, input().split()))


def error_print(*args):
    print(*args, file=sys.stderr)


def mt(f):
    import time

    def wrap(*args, **kwargs):
        s = time.time()
        ret = f(*args, **kwargs)
        e = time.time()

        error_print(e - s, 'sec')
        return ret

    return wrap


@mt
def slv(N, M, A):
    c = [
        -1,
        2, # 1 
        5, # 2
        5, # 3
        4, # 4
        5, # 5
        6, # 6
        3, # 7
        7, # 8
        6, # 9
        ]
    
    if (2 in A or 3 in A) and 5 in A:
        A.remove(2)
        A.remove(3)
    if 2 in A and 3 in A:
        A.remove(2)
    if 6 in A and 9 in A:
        A.remove(6)



    dp = [None] * (N+1) 
    dp[N] = (0, Counter())
    for i in range(N, 0, -1):
        if dp[i] is None:
            continue
        
        for a in A:
            if i - c[a] < 0:
                continue
            
            if dp[i-c[a]] is None:
                c_ = copy.copy(dp[i][1])
                c_[a] += 1
                dp[i-c[a]] =  (dp[i][0]+1, c_)
            
            elif dp[i][0]+1 > dp[i-c[a]][0]:
                c_ = copy.copy(dp[i][1])
                c_[a] += 1
                dp[i-c[a]] =  (dp[i][0]+1, c_)
    # print(0, dp[0])

    ans = ""
    for r in  sorted(dp[0][1], reverse=True):
        ans += str(r) * dp[0][1][r]
    return ans


def main():
    # N = read_int()
    N, M = read_int_n()
    A = read_int_n()
    print(slv(N, M, A))


if __name__ == '__main__':
    main()