Problem:
Score : 300 points

Problem Statement

There are N integers a_1, a_2, ..., a_N not less than 1.
The values of a_1, a_2, ..., a_N are not known, but it is known that a_1 \times a_2 \times ... \times a_N = P.

Find the maximum possible greatest common divisor of a_1, a_2, ..., a_N.

Constraints

1 \leq N \leq 10^{12}

1 \leq P \leq 10^{12}

Input

Input is given from Standard Input in the following format:

N P

Output

Print the answer.

Sample Input 1

3 24

Sample Output 1

2

The greatest common divisor would be 2 when, for example, a_1=2, a_2=6 and a_3=2.

Sample Input 2

5 1

Sample Output 2

1

As a_i are positive integers, the only possible case is a_1 = a_2 = a_3 = a_4 = a_5 = 1.

Sample Input 3

1 111

Sample Output 3

111

Sample Input 4

4 972439611840

Sample Output 4

206

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

# -*- coding: utf-8 -*-

from sys import stdin
import math

n,x = [int(i) for i in stdin.readline().split()]
limit = int(x ** (1.0/n)) + 1

def devide_counter(x, p):
    count = 1
    x /= p
    while x % p == 0:
        count += 1
        x /= p
    return x, count

def factorize(x):
    ans = 1

    p = 2
    if x % p == 0:
        x, count = devide_counter(x, p)
        if count >= n:
            ans = ans * p * (count // n)

    for p in range(3, limit, 2):
        if x % p == 0:
            x, count = devide_counter(x, p)
            if count >= n:
                ans = ans * p * (count // n)
        if x < p * p:
            break
    return ans

if x == 1:
    print(1)
elif n == 1:
    print(x)
else:
    ans = factorize(x)
    print(ans)