Problem:
Score : 400 points

Problem Statement

Given are positive integers A and B.

Let us choose some number of positive common divisors of A and B.

Here, any two of the chosen divisors must be coprime.

At most, how many divisors can we choose?

Definition of common divisor

An integer d is said to be a common divisor of integers x and y when d divides both x and y.

Definition of being coprime

Integers x and y are said to be coprime when x and y have no positive common divisors other than 1.

Definition of dividing

An integer x is said to divide another integer y when there exists an integer \alpha such that y = \alpha x.

Constraints

All values in input are integers.

1 \leq A, B \leq 10^{12}

Input

Input is given from Standard Input in the following format:

A B

Output

Print the maximum number of divisors that can be chosen to satisfy the condition.

Sample Input 1

12 18

Sample Output 1

3

12 and 18 have the following positive common divisors: 1, 2, 3, and 6.

1 and 2 are coprime, 2 and 3 are coprime, and 3 and 1 are coprime, so we can choose 1, 2, and 3, which achieve the maximum result.

Sample Input 2

420 660

Sample Output 2

4

Sample Input 3

1 2019

Sample Output 3

1

1 and 2019 have no positive common divisors other than 1.

Solution in PyPy3 (2.4.0) (judge verdict: Accepted)

def gcd(a,b):
    if a < b:
        a, b = b, a
    while b >= 1:
        a, b = b, a % b
    return a

def shave(n):
    n_root = int(n**0.5)
    candidate = [i for i in range(3,n+1,2)]
    for i in range(3,n_root+2,2):
        candidate = [ j for j in candidate if j == i or j % i != 0]   
    candidate = [2] + candidate
    return candidate

x, y = [ int(v) for v in input().split() ]

gcd1 = gcd(x, y)
prime_list = shave(int(gcd1**0.5)+1)

ans = 1
for i in prime_list:
    if gcd1 % i == 0:
        ans += 1
        while gcd1 % i == 0:
            gcd1 //= i
if gcd1 != 1:
    ans += 1
print(ans)