Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in Python3 (judge verdict: Accepted)

n, m, l = map(int, input().split())
a = [[0 for i in range(m)] for j in range(n)] 
b = [[0 for i in range(l)] for j in range(m)] 
c = [[0 for i in range(l)] for j in range(n)]

for i in range(n):
    tmpA = list(map(int, input().split()))
    for j in range(m):
        a[i][j] = tmpA[j]

for i in range(m):
    tmpB = list(map(int, input().split()))
    for j in range(l):
        b[i][j] = tmpB[j]

for i in range(n):
    for j in range(l):
        for k in range(m):
          c[i][j] += a[i][k]*b[k][j]

for i in range(n):
    for j in range(l):
        print(c[i][j], end='')
        if j != l - 1:
            print(' ', end="")
    print()