Problem:
Score : 200 points

Problem Statement

Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Constraints

1 \leq N \leq 10^5

Input

Input is given from Standard Input in the following format:

N

Output

Print the number of positive integers less than or equal to N that have an odd number of digits.

Sample Input 1

11

Sample Output 1

9

Among the positive integers less than or equal to 11, nine integers have an odd number of digits: 1, 2, \ldots, 9.

Sample Input 2

136

Sample Output 2

46

In addition to 1, 2, \ldots, 9, another 37 integers also have an odd number of digits: 100, 101, \ldots, 136.

Sample Input 3

100000

Sample Output 3

90909

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

n = int(input())

c = 0
t = n
while t // 10 != 0:
    c += 1
    t = t // 10

print(c)

ans = 0
if c == 0:
    ans = n
elif c == 1:
    ans = 9
elif c == 2:
    ans = n - 99 + 9
elif c == 3:
    ans = 909
elif c == 4:
    ans = n - 9999 + 909
else:
    ans = 90909

print(ans)