Problem:
Score : 400 points

Problem Statement

There is a bar of chocolate with a height of H blocks and a width of W blocks.
Snuke is dividing this bar into exactly three pieces.
He can only cut the bar along borders of blocks, and the shape of each piece must be a rectangle.

Snuke is trying to divide the bar as evenly as possible.
More specifically, he is trying to minimize S_{max} - S_{min}, where S_{max} is the area (the number of blocks contained) of the largest piece, and S_{min} is the area of the smallest piece.
Find the minimum possible value of S_{max} - S_{min}.

Constraints

2 ≤ H, W ≤ 10^5

Input

Input is given from Standard Input in the following format:

H W

Output

Print the minimum possible value of S_{max} - S_{min}.

Sample Input 1

3 5

Sample Output 1

0

In the division below, S_{max} - S_{min} = 5 - 5 = 0.

Sample Input 2

4 5

Sample Output 2

2

In the division below, S_{max} - S_{min} = 8 - 6 = 2.

Sample Input 3

5 5

Sample Output 3

4

In the division below, S_{max} - S_{min} = 10 - 6 = 4.

Sample Input 4

100000 2

Sample Output 4

1

Sample Input 5

100000 100000

Sample Output 5

50000

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

h,w=map(int,input().split())
if h%3==0 or w%3==0:
    print(0)
else:
    s=[h,w]
    for i in range(max(1,h//3-1),min(h//3+2,h-1)):
        s.append(max(w*i,((h-i)*(w//2+1)if w%2==1 else (h-i)*(w//2)))-min(w*i,(h-i)*(w//2)))
    for i in range(max(1,w//3-1),min(w//3+2,w-1)):
        s.append(max(h*i,((w-i)*(h//2+1)if h%2==1 else (w-i)*(h//2)))-min(h*i,(w-i)*(h//2)))
    print(min(s))