Problem:
Score : 400 points

Problem Statement

There is a knight - the chess piece - at the origin (0, 0) of a two-dimensional grid.

When the knight is at the square (i, j), it can be moved to either (i+1,j+2) or (i+2, j+1).

In how many ways can the knight reach the square (X, Y)?

Find the number of ways modulo 10^9 + 7.

Constraints

1 \leq X \leq 10^6

1 \leq Y \leq 10^6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

Print the number of ways for the knight to reach (X, Y) from (0, 0), modulo 10^9 + 7.

Sample Input 1

3 3

Sample Output 1

2

There are two ways: (0,0) \to (1,2) \to (3,3) and (0,0) \to (2,1) \to (3,3).

Sample Input 2

2 2

Sample Output 2

0

The knight cannot reach (2,2).

Sample Input 3

999999 999999

Sample Output 3

151840682

Print the number of ways modulo 10^9 + 7.

Solution in Python (3.4.3) (judge verdict: Accepted)

p = 1000000007

X, Y = map(int, input().split())

if (X + Y) % 3 != 0:
    print(0)
    exit()

a = (2 * Y - X) // 3
b = (2 * X - Y) // 3

if a < 0 or b < 0:
    print(0)
    exit()

n = a + b
fac = [0] * (n + 1)
fac[0] = 1
for i in range(n):
    fac[i + 1] = fac[i] * (i + 1) % p


def mcomb(n, k):
    if n == 0 and k == 0:
        return 1
    if n < k or k < 0:
        return 0
    return fac[n] * pow(fac[n - k], p - 2, p) * pow(fac[k], p - 2, p) % p


print(mcomb(n, a))