Problem:
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The Number of Inversions

For a given sequence $A = \{a_0, a_1, ... a_{n-1}\}$, the number of pairs $(i, j)$ where $a_i > a_j$ and $i < j$, is called the number of inversions. The number of inversions is equal to the number of swaps of Bubble Sort defined in the following program:

bubbleSort(A)
cnt = 0 // the number of inversions
for i = 0 to A.length-1
for j = A.length-1 downto i+1
if A[j] < A[j-1]
swap(A[j], A[j-1])
cnt++

return cnt

For the given sequence $A$, print the number of inversions of $A$. Note that you should not use the above program, which brings Time Limit Exceeded.

Input

In the first line, an integer $n$, the number of elements in $A$, is given. In the second line, the elements $a_i$ ($i = 0, 1, .. n-1$) are given separated by space characters.

output

Print the number of inversions in a line.

Constraints

$ 1 \leq n \leq 200,000$

$ 0 \leq a_i \leq 10^9$

$a_i$ are all different

Sample Input 1

5
3 5 2 1 4

Sample Output 1

6

Sample Input 2

3
3 1 2

Sample Output 2

2

Solution in Python3 (judge verdict: Wrong Answer)

#16D8103010K Ko Okasaki
#ALDS_5_D

global cnt
cnt=0

def merge(A,left,mid,right):
    L=A[left:mid]
    R=A[mid:right]
    L.append(float("inf"))
    R.append(float("inf"))
    
    i=0
    j=0
    for k in range(left,right):
        global cnt
        if L[i]<=R[j]:
            A[k]=L[i]
            i=i+1
        else:
            A[k]=R[j]
            j=j+1
            cnt+=mid-left-i

def mergeSort(A,left,right):
    if left+1<right:
        mid=(int)((left+right)/2)
        mergeSort(A,left,mid)
        mergeSort(A,mid,right)
        merge(A,left,mid,right)

n=int(input())
S=list(map(int,input().split()))

mergeSort(S,0,n)
print(*S)
print(cnt)