Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in PyPy3 (2.4.0) (judge verdict: Accepted)

s=input()
t=input()
import sys
from collections import defaultdict
dic1=defaultdict(lambda:'A')
dic2=defaultdict(lambda:'B')
ans=1
for i in range(len(s)):
  if s[i] in dic1 or t[i] in dic2:
    if dic1[s[i]]==t[i] and  dic2[t[i]]==s[i]:
      pass
    else:
      print('No')
      quit()
  else:
    dic1[s[i]]=t[i]
    dic2[t[i]]=s[i]
print('Yes')