Problem:
Score : 400 points

Problem Statement

We have N points in a two-dimensional plane.

The coordinates of the i-th point (1 \leq i \leq N) are (x_i,y_i).

Let us consider a rectangle whose sides are parallel to the coordinate axes that contains K or more of the N points in its interior.

Here, points on the sides of the rectangle are considered to be in the interior.

Find the minimum possible area of such a rectangle.

Constraints

2 \leq K \leq N \leq 50

-10^9 \leq x_i,y_i \leq 10^9 (1 \leq i \leq N)

x_i≠x_j (1 \leq i<j \leq N)

y_i≠y_j (1 \leq i<j \leq N)

All input values are integers. (Added at 21:50 JST)

Input

Input is given from Standard Input in the following format:

N K
x_1 y_1
:
x_{N} y_{N}

Output

Print the minimum possible area of a rectangle that satisfies the condition.

Sample Input 1

4 4
1 4
3 3
6 2
8 1

Sample Output 1

21

One rectangle that satisfies the condition with the minimum possible area has the following vertices: (1,1), (8,1), (1,4) and (8,4).

Its area is (8-1) × (4-1) = 21.

Sample Input 2

4 2
0 0
1 1
2 2
3 3

Sample Output 2

1

Sample Input 3

4 3
-1000000000 -1000000000
1000000000 1000000000
-999999999 999999999
999999999 -999999999

Sample Output 3

3999999996000000001

Watch out for integer overflows.

Solution in PyPy3 (2.4.0) (judge verdict: Accepted)

N, K = map(int, input().split())
x_list = [0]*N
y_list = [0]*N
for i in range(N):
    x_list[i], y_list[i] = map(int, input().split())

x_element = sorted(x_list)
y_element = sorted(y_list)
ans = float("inf")

for i in range(len(x_element)):
    for j in range(len(y_element)):
        for k in range(i+1, len(x_element)):
            for l in range(j+1, len(y_element)):
                num = 0
                for m in range(N):
                    if x_element[i] <= x_list[m] <= x_element[k] and y_element[j] <= y_list[m] <= y_element[l]:
                        num += 1
                if num >= K:
                    ans = min((x_element[k] - x_element[i]) * (y_element[l] - y_element[j]), ans)

print(ans)