Problem:
Score : 200 points

Problem Statement

It is November 18 now in Japan. By the way, 11 and 18 are adjacent Lucas numbers.

You are given an integer N. Find the N-th Lucas number.

Here, the i-th Lucas number L_i is defined as follows:

L_0=2

L_1=1

L_i=L_{i-1}+L_{i-2} (i≥2)

Constraints

1≤N≤86

It is guaranteed that the answer is less than 10^{18}.

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print the N-th Lucas number.

Sample Input 1

5

Sample Output 1

11

L_0=2

L_1=1

L_2=L_0+L_1=3

L_3=L_1+L_2=4

L_4=L_2+L_3=7

L_5=L_3+L_4=11

Thus, the 5-th Lucas number is 11.

Sample Input 2

86

Sample Output 2

939587134549734843

Solution in Python (3.4.3) (judge verdict: Accepted)

#http://abc079.contest.atcoder.jp/
# -*- coding: utf-8 -*-
import sys

n = int(input())

ryuka = [2,1]
if n<2:
    print(ryuka[n])
    sys.exit()
    
for i in range(2,n+1):
    ryuka.append(ryuka[i-2]+ryuka[i-1])

print(max(ryuka))