Problem:
Score : 400 points

Problem Statement

There is a knight - the chess piece - at the origin (0, 0) of a two-dimensional grid.

When the knight is at the square (i, j), it can be moved to either (i+1,j+2) or (i+2, j+1).

In how many ways can the knight reach the square (X, Y)?

Find the number of ways modulo 10^9 + 7.

Constraints

1 \leq X \leq 10^6

1 \leq Y \leq 10^6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

Print the number of ways for the knight to reach (X, Y) from (0, 0), modulo 10^9 + 7.

Sample Input 1

3 3

Sample Output 1

2

There are two ways: (0,0) \to (1,2) \to (3,3) and (0,0) \to (2,1) \to (3,3).

Sample Input 2

2 2

Sample Output 2

0

The knight cannot reach (2,2).

Sample Input 3

999999 999999

Sample Output 3

151840682

Print the number of ways modulo 10^9 + 7.

Solution in Python (3.4.3) (judge verdict: Accepted)

import sys
from math import factorial

def ncr(n, r, p): 
    # initialize numerator 
    # and denominator 
    num = den = 1 
    for i in range(r): 
        num = (num * (n - i)) % p 
        den = (den * (i + 1)) % p 
    return (num * pow(den,  
            p - 2, p)) % p 

def check(x, y):
    if (x + y) % 3 == 0:
        return True
    else:
        return False
    

# Read
line = sys.stdin.readlines()[0]
X, Y = map(int,line.split(' '))

if not check(X, Y):
    print(0)
    exit(0)

m = int(1/3 * (2*Y - X))
n = int(Y - 2 * m)

if n < 0 or m < 0:
    print(0)
else:
    print(ncr(n+m, n, 10**9+7))