Problem:
Score : 400 points

Problem Statement

There is a knight - the chess piece - at the origin (0, 0) of a two-dimensional grid.

When the knight is at the square (i, j), it can be moved to either (i+1,j+2) or (i+2, j+1).

In how many ways can the knight reach the square (X, Y)?

Find the number of ways modulo 10^9 + 7.

Constraints

1 \leq X \leq 10^6

1 \leq Y \leq 10^6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

Print the number of ways for the knight to reach (X, Y) from (0, 0), modulo 10^9 + 7.

Sample Input 1

3 3

Sample Output 1

2

There are two ways: (0,0) \to (1,2) \to (3,3) and (0,0) \to (2,1) \to (3,3).

Sample Input 2

2 2

Sample Output 2

0

The knight cannot reach (2,2).

Sample Input 3

999999 999999

Sample Output 3

151840682

Print the number of ways modulo 10^9 + 7.

Solution in PyPy3 (7.3.0) (judge verdict: Runtime Error)

class Modulo():
    def __init__(self,a,n):
        self.a=a%n
        self.n=n

    def __str__(self):
        return "{} (mod {})".format(self.a,self.n)

    #+,-
    def __pos__(self):
        return self

    def __neg__(self):
        return  Modulo(-self.a,self.n)

    #等号,不等号
    def __eq__(self,other):
        if isinstance(other,Modulo):
            return (self.a==other.a) and (self.n==other.n)
        elif isinstance(other,int):
            return (self-other).a==0

    def __neq__(self,other):
        return not(self==other)

    #加法
    def __add__(self,other):
        if isinstance(other,Modulo):
            if self.n!=other.n:
                raise Modulo_Error("異なる法同士の演算です.")
            return Modulo(self.a+other.a,self.n)
        elif isinstance(other,int):
            return Modulo(self.a+other,self.n)

    def __radd__(self,other):
        if isinstance(other,int):
            return Modulo(self.a+other,self.n)

    #減法
    def __sub__(self,other):
        return self+(-other)

    def __rsub__(self,other):
        if isinstance(other,int):
            return -self+other

    #乗法
    def __mul__(self,other):
        if isinstance(other,Modulo):
            if self.n!=other.n:
                raise Modulo_Error("異なる法同士の演算です.")
            return Modulo(self.a*other.a,self.n)
        elif isinstance(other,int):
            return Modulo(self.a*other,self.n)

    def __rmul__(self,other):
        if isinstance(other,int):
            return Modulo(self.a*other,self.n)

    #Modulo逆数
    def Modulo_Inverse(self):
        x0, y0, x1, y1 = 1, 0, 0, 1
        a,b=self.a,self.n
        while b != 0:
            q, a, b = a // b, b, a % b
            x0, x1 = x1, x0 - q * x1
            y0, y1 = y1, y0 - q * y1

        if a!=1:
            raise Modulo_Error("{}の逆数が存在しません".format(self))
        else:
            return Modulo(x0,self.n)

    #除法
    def __truediv__(self,other):
        return self*(other.Modulo_Inverse())

    def __rtruediv__(self,other):
        return other*(self.Modulo_Inverse())

    #累乗
    def __pow__(self,m):
        u=abs(m)

        r=Modulo(1,self.n)

        while u>0:
            if u%2==1:
                r*=self
            self*=self
            u=u>>1

        if m>=0:
            return r
        else:
            return r.Modulo_Inverse()

    #根号
    def sqrt(self):
        if self==0:
            return self
        elif self.n==2:
            return self
        elif self.n%4==3:
            return self**((self.n+1)//4)
        else:
            p=self.n
            u=2
            s=1
            while (p-1)%(2*u)==0:
                u*=2
                s+=1

            z=Modulo(2,p)
            while z**((p-1)//2)!=-1:
                z+=1

            q=(p-1)//u
            m=s
            c=z**q
            t=self**q
            r=self**((q+1)//2)

            while m>1:
                k=1
                d=t*t

                while d!=1:
                    k+=1
                    d*=d
                    print(m,k)
                b=Modulo(2,p)**(2**(m-k-1))
                c,t,r,m=b*b,t*b*b,r*b,k
            return r

#階乗の剰余のリスト
def Factorial_Modulo_List(N,M,Inverse=False):
    X=[0]*(N+1)
    X[0]=Modulo(1,M)

    for i in range(1,N+1):
        X[i]=X[i-1]*i

    if Inverse:
        Y=[0]*(N+1)
        Y[-1]=1/X[-1]

        for j in range(N-1,-1,-1):
            Y[j]=Y[j+1]*(j+1)
        return X,Y
    else:
        return X
#================================================
import sys
X,Y=map(int,input().split())
M=10**9+7

if not((-X+2*Y)%3==0 and (2*X-Y)%3==0):
    print(0)
    sys.exit()

A,B=(-X+2*Y)//3,(2*X-Y)//3

F,G=Factorial_Modulo_List(A+B,M,True)
print((F[A+B]*G[A]*G[B]).a)