Problem:
Score : 400 points

Problem Statement

Let {\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order.
From n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\rm comb}(a_i,a_j) is maximized.
If there are multiple pairs that maximize the value, any of them is accepted.

Constraints

2 \leq n \leq 10^5

0 \leq a_i \leq 10^9

a_1,a_2,...,a_n are pairwise distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print a_i and a_j that you selected, with a space in between.

Sample Input 1

5
6 9 4 2 11

Sample Output 1

11 6

\rm{comb}(a_i,a_j) for each possible selection is as follows:

\rm{comb}(4,2)=6

\rm{comb}(6,2)=15

\rm{comb}(6,4)=15

\rm{comb}(9,2)=36

\rm{comb}(9,4)=126

\rm{comb}(9,6)=84

\rm{comb}(11,2)=55

\rm{comb}(11,4)=330

\rm{comb}(11,6)=462

\rm{comb}(11,9)=55

Thus, we should print 11 and 6.

Sample Input 2

2
100 0

Sample Output 2

100 0

Solution in Python (3.4.3) (judge verdict: Runtime Error)

import math
def cal(n ,r):
    if n == r:
        return 1
    return math.factorial(n)/(math.factorial(r) * math.factorial(n-r))

def bin_search(in_list, val):
    cnt = len(in_list)
    mid = round(cnt/2)
    if cnt == 1:
        return in_list[0]
    if in_list[mid] > val:
        return bin_search(in_list[:mid], val)
    if in_list[mid] < val:
        return bin_search(in_list[mid:], val)
    if in_list[mid] == val:
        return val

n = int(input())
A = sorted(list(map(int, input().split())))

m_combo = 0
ai = 0
aj = 0

for i in range(1,n):
    a = A[i]
    val = bin_search(A[:i], round(a/2))
    combo = cal(a, val)
    if combo > m_combo:
        m_combo = combo
        ai = a
        aj = val

print('{} {}'.format(ai, aj))