Problem:
Score : 600 points

Problem Statement

A bracket sequence is a string that is one of the following:

An empty string;

The concatenation of (, A, and ) in this order, for some bracket sequence A ;

The concatenation of A and B in this order, for some non-empty bracket sequences A and B /

Given are N strings S_i. Can a bracket sequence be formed by concatenating all the N strings in some order?

Constraints

1 \leq N \leq 10^6

The total length of the strings S_i is at most 10^6.

S_i is a non-empty string consisting of ( and ).

Input

Input is given from Standard Input in the following format:

N
S_1
:
S_N

Output

If a bracket sequence can be formed by concatenating all the N strings in some order, print Yes; otherwise, print No.

Sample Input 1

2
)
(()

Sample Output 1

Yes

Concatenating (() and ) in this order forms a bracket sequence.

Sample Input 2

2
)(
()

Sample Output 2

No

Sample Input 3

4
((()))
((((((
))))))
()()()

Sample Output 3

Yes

Sample Input 4

3
(((
)
)

Sample Output 4

No

Solution in PyPy3 (7.3.0) (judge verdict: Wrong Answer)

from collections import Counter, defaultdict, deque

(N,) = [int(x) for x in input().split()]
brackets = [input() for i in range(N)]

delta = []
minDelta = []
for s in brackets:
    balance = 0
    mn = 0
    for c in s:
        if c == "(":
            balance += 1
        else:
            balance -= 1
        mn = min(mn, balance)
    delta.append(balance)
    minDelta.append(mn)

if sum(delta) == 0:
    posIndices = [i for i in range(N) if delta[i] > 0]
    posIndices.sort(key=lambda i: (minDelta[i], -delta[i]))

    eqIndices = [i for i in range(N) if delta[i] == 0]

    negIndices = [i for i in range(N) if delta[i] < 0]
    negIndices.sort(key=lambda i: (-minDelta[i], delta[i]))
    balance = 0
    for i in posIndices + eqIndices + negIndices:
        if balance + minDelta[i] < 0 or balance + delta[i] < 0:
            print("No")
            exit()
        balance += delta[i]
    assert balance == 0

    print("Yes")
else:
    print("No")