Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Python (3.4.3) (judge verdict: Accepted)

N = int(input())
List_N = [i for i in range(1,N+1)]
ODD_N = List_N[::2]
special_number = 0
for i in ODD_N:
    cnt = 0
    for j in range(1, int(i)+1):
        if int(i) % j == 0:
            cnt += 1
    if cnt == 8:
        special_number += 1
print(special_number)