Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in Python (3.4.3) (judge verdict: Accepted)

# coding: utf-8
ABCD = input() # ABCDの入力
op = ["*", "*", "*"] #解答出力のため演算子用の変数listを用意
def operate(ans, i): #再帰関数で解く
    if i == 3:
        if ans == 7:
            print("{}{}{}{}{}{}{}=7".format(ABCD[0], op[0], ABCD[1], op[1], ABCD[2], op[2], ABCD[3]))
            exit()
    else:
        op[i] = op[i].replace("*", "+").replace("-", "+") # 演算子の書き換え
        operate(ans + int(ABCD[i + 1]), i + 1)
        op[i] = op[i].replace("+", "-") # 演算子の書き換え
        operate(ans - int(ABCD[i + 1]), i + 1)
operate(int(ABCD[0]), 0)