Problem:
Score : 400 points

Problem Statement

Given is an integer S.
Find a combination of six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfies all of the following conditions:

0 \leq X_1,Y_1,X_2,Y_2,X_3,Y_3 \leq 10^9

The area of the triangle in a two-dimensional plane whose vertices are (X_1,Y_1),(X_2,Y_2), and (X_3,Y_3) is S/2.

We can prove that there always exist six integers that satisfy the conditions under the constraints of this problem.

Constraints

1 \leq S \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

S

Output

Print six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfy the conditions, in this order, with spaces in between.
If multiple solutions exist, any of them will be accepted.

Sample Input 1

3

Sample Output 1

1 0 2 2 0 1

The area of the triangle in a two-dimensional plane whose vertices are (1,0),(2,2), and (0,1) is 3/2.
Printing 3 0 3 1 0 1 or 1 0 0 1 2 2 will also be accepted.

Sample Input 2

100

Sample Output 2

0 0 10 0 0 10

Sample Input 3

311114770564041497

Sample Output 3

314159265 358979323 846264338 327950288 419716939 937510582

Solution in Python (3.4.3) (judge verdict: Accepted)

import sys
## io ##
def IS(): return sys.stdin.readline().rstrip()
def II(): return int(IS())
def MII(): return list(map(int, IS().split()))
def MIIZ(): return list(map(lambda x: x-1, MII()))
## dp ##
def DD2(d1,d2,init=0): return [[init]*d2 for _ in range(d1)]
def DD3(d1,d2,d3,init=0): return [DD2(d2,d3,init) for _ in range(d1)]
## math ##
def to_bin(x: int) -> str: return format(x,'b') # rev => int(res, 2)
def to_oct(x: int) -> str: return format(x,'o') # rev => int(res, 8)
def to_hex(x: int) -> str: return format(x,'x') # rev => int(res, 16)
def divc(x,y) -> int: return -(-x//y)
def divf(x,y) -> int: return x//y
def gcd(x,y):
    while y: x,y = y,x%y
    return x
def lcm(x,y): return x*y//gcd(x,y)
def enumerate_divs(n):
    """Return a tuple list of divisor of n"""
    return [(i,n//i) for i in range(1,int(n**0.5)+1) if n%i==0]
def get_primes(n=10**3):
    """Return a list of prime numbers n or less"""
    is_prime = [True]*(n+1)
    is_prime[0] = is_prime[1] = False
    for i in range(2, int(n**0.5)+1):
        if not is_prime[i]: continue
        for j in range(i*2, n+1, i): is_prime[j] = False
    return [i for i in range(n+1) if is_prime[i]]
def prime_factor(n):
    """Return a list of prime factorization numbers of n"""
    res = []
    for i in range(2,int(n**0.5)+1):
        while n%i==0: res.append(i); n //= i
    if n != 1: res.append(n)
    return res
## const ##
MOD=10**9+7
## libs ##
import itertools as it
import functools as ft
from collections import deque, Counter
from heapq import heapify, heappop, heappush
from bisect import bisect_left
#======================================================#
def main():
    s = II()
    m = 10**9
    x3 = (m-s%m)%m
    y3 = (s+x3)//m
    print(0, 0, m, 1, x3, y3)

if __name__ == '__main__':
    main()