Problem:
Score : 400 points

Problem Statement

Given is a string S. Each character in S is either a digit (0, ..., 9) or ?.

Among the integers obtained by replacing each occurrence of ? with a digit, how many have a remainder of 5 when divided by 13? An integer may begin with 0.

Since the answer can be enormous, print the count modulo 10^9+7.

Constraints

S is a string consisting of digits (0, ..., 9) and ?.

1 \leq |S| \leq 10^5

Input

Input is given from Standard Input in the following format:

S

Output

Print the number of integers satisfying the condition, modulo 10^9+7.

Sample Input 1

??2??5

Sample Output 1

768

For example, 482305, 002865, and 972665 satisfy the condition.

Sample Input 2

?44

Sample Output 2

1

Only 044 satisfies the condition.

Sample Input 3

7?4

Sample Output 3

0

We may not be able to produce an integer satisfying the condition.

Sample Input 4

?6?42???8??2??06243????9??3???7258??5??7???????774????4?1??17???9?5?70???76???

Sample Output 4

153716888

Solution in PyPy2 (5.6.0) (judge verdict: Wrong Answer)

S=raw_input()
l=len(S)

dp=[ [ 0 for j in range(13)] for i in range(l+1) ]
dp[0][0]=1

mod=10**9+7

keta=1

for i in range(1,l+1):
	for j in range(13):
		if dp[i-1][j]!=0:
			if S[i-1]=="?":
				for k in range(10):
					dp[i][ (k*keta+j)%13 ]+=dp[i-1][j]
					dp[i][ (k*keta+j)%13 ]%=mod
			else:
				k=int(S[i-1])
				dp[i][ (k*keta+j)%13 ]+=dp[i-1][j]
				dp[i][ (k*keta+j)%13 ]%=mod

	keta=(keta*4)%13

print dp[-1][5]