Problem:
Score : 600 points

Problem Statement

Given are two sequences A and B, both of length N.
A and B are each sorted in the ascending order.
Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.

Constraints

1\leq N \leq 2 \times 10^5

1\leq A_i,B_i \leq N

A and B are each sorted in the ascending order.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N

Output

If there exist no reorderings that satisfy the condition, print No.

If there exists a reordering that satisfies the condition, print Yes on the first line.
After that, print a reordering of B on the second line, separating terms with a whitespace.

If there are multiple reorderings that satisfy the condition, you can print any of them.

Sample Input 1

6
1 1 1 2 2 3
1 1 1 2 2 3

Sample Output 1

Yes
2 2 3 1 1 1

Sample Input 2

3
1 1 2
1 1 3

Sample Output 2

No

Sample Input 3

4
1 1 2 3
1 2 3 3

Sample Output 3

Yes
3 3 1 2

Solution in Python (3.8.2) (judge verdict: Time Limit Exceeded)

def get_ints():
  return list(map(int,input().split()))

n = int(input())
a = get_ints()
b = get_ints()

cnt = [0]*(n+1)
for x in a+b:
  cnt[x] += 1

q = [set() for i in range(n+1)]
for i in range(1,n+1):
  if cnt[i] > n:
    print('No')
    exit(0)
  q[cnt[i]].add(i)
print('Yes')

list_a = [[] for i in range(n+1)]
cnt_a = {}
for i in range(n):
  list_a[a[i]].append(i)
  if a[i] not in cnt_a:
    cnt_a[a[i]] = 1
  else:
    cnt_a[a[i]] += 1

list_b = [[] for i in range(n+1)]
cnt_b = {}
for i in range(n):
  list_b[b[i]].append(i)
  if b[i] not in cnt_b:
    cnt_b[b[i]] = 1
  else:
    cnt_b[b[i]] += 1

def get_any(cnt_, x):
  for key in cnt_.keys():
    if key != x:
      return key
  assert False

ans = [-1]*n

for i in range(n,0,-1):
  s = list(q[i])
  x,y = 0,0
  if len(s) == 0:
    x = get_any(cnt_a, -1)
    y = get_any(cnt_b, x)
  elif len(s) == 1:
    x = s[0]
    if len(list_a[x]) == 0: # b kara
      y = x
      x = get_any(cnt_a, y)
    else: # a kara
      y = get_any(cnt_b, x)
  else: # 2
    x,y = s
    if len(list_a[x]) == 0:
      x,y = y,x

  ans[list_a[x].pop()] = y
  list_b[y].pop()
  def update_cnt(cnt_, x):
    cnt_[x] -= 1
    if cnt_[x] == 0:
      del cnt_[x]
  def use(x):
    q[cnt[x]].remove(x)
    cnt[x] -= 1
    q[cnt[x]].add(x)
  update_cnt(cnt_a, x)
  update_cnt(cnt_b, y)
  use(x)
  use(y)

print(' '.join(map(str,ans)))