Problem:
Score : 400 points

Problem Statement

Akari has n kinds of flowers, one of each kind.

She is going to choose one or more of these flowers to make a bouquet.

However, she hates two numbers a and b, so the number of flowers in the bouquet cannot be a or b.

How many different bouquets are there that Akari can make?

Find the count modulo (10^9 + 7).

Here, two bouquets are considered different when there is a flower that is used in one of the bouquets but not in the other bouquet.

Constraints

All values in input are integers.

2 \leq n \leq 10^9

1 \leq a < b \leq \textrm{min}(n, 2 \times 10^5)

Input

Input is given from Standard Input in the following format:

n a b

Output

Print the number of bouquets that Akari can make, modulo (10^9 + 7). (If there are no such bouquets, print 0.)

Sample Input 1

4 1 3

Sample Output 1

7

In this case, Akari can choose 2 or 4 flowers to make the bouquet.

There are 6 ways to choose 2 out of the 4 flowers, and 1 way to choose 4, so there are a total of 7 different bouquets that Akari can make.

Sample Input 2

1000000000 141421 173205

Sample Output 2

34076506

Print the count modulo (10^9 + 7).

Solution in PyPy3 (2.4.0) (judge verdict: Time Limit Exceeded)

n, a, b = map(int, input().split())

d = 10**9 + 7

ans = 0

def cmb(n, r, mod):
    from operator import mul
    from functools import reduce

    N = n + r
    g1 = [1, 1]  # 元テーブル
    g2 = [1, 1]  # 逆元テーブル
    inverse = [0, 1]  # 逆元テーブル計算用テーブル

    for i in range(2, N + 1):
        g1.append((g1[-1] * i) % mod )
        inverse.append((-inverse[mod % i] * (mod//i)) % mod)
        g2.append((g2[-1] * inverse[-1]) % mod)

    if (r<0 or r>n):
        return 0
    r = min(r, n-r)
    return g1[n] * g2[r] * g2[n-r] % mod


for x in range(1, n+1):
    if x == a or x == b:
        pass
    else:
        ans += cmb(n, x, d)

print(ans)