Problem:
Merge Sort

Write a program of a Merge Sort algorithm implemented by the following pseudocode. You should also report the number of comparisons in the Merge function.

Merge(A, left, mid, right)
n1 = mid - left;
n2 = right - mid;
create array L[0...n1], R[0...n2]
for i = 0 to n1-1
do L[i] = A[left + i]
for i = 0 to n2-1
do R[i] = A[mid + i]
L[n1] = SENTINEL
R[n2] = SENTINEL
i = 0;
j = 0;
for k = left to right-1
if L[i] <= R[j]
then A[k] = L[i]
i = i + 1
else A[k] = R[j]
j = j + 1

Merge-Sort(A, left, right){
if left+1 < right
then mid = (left + right)/2;
call Merge-Sort(A, left, mid)
call Merge-Sort(A, mid, right)
call Merge(A, left, mid, right)

Input

In the first line n is given. In the second line, n integers are given.

Output

In the first line, print the sequence S. Two consequtive elements should be separated by a space character.

In the second line, print the number of comparisons.

Constraints

n ≤ 500000

0 ≤ an element in S ≤ 109

Sample Input 1

10
8 5 9 2 6 3 7 1 10 4

Sample Output 1

1 2 3 4 5 6 7 8 9 10
34

Notes

Solution in Python3 (judge verdict: Wrong Answer)

def merge(A, left, mid, right, c):
    n1 = mid - left
    n2 = right - mid
    L = [0]*(n1+1)
    R = [0]*(n2+1)
    for i in range(n1):
        L[i] = A[left + i]
    for i in range(n2):
        R[i] = A[mid + i]
    L[n1] = float("inf")
    R[n2] = float("inf")
    i = 0
    j = 0
    for k in range(left,right): 
        if L[i] <= R[j]:
            c = c+1
            A[k] = L[i]
            i = i + 1
        else:
            c = c+1
            A[k] = R[j]
            j = j + 1

def mergeSort(A, left, right, c):
  if left+1 < right:
    mid = (left + right)//2;
    mergeSort(A, left, mid, c)
    mergeSort(A, mid, right, c)
    merge(A, left, mid, right, c)
    
### Main Function
n = int(input())
S = list(map(int,input().split()))
c = 0

mergeSort(S, 0, n, c)

print(S)
print(c)