Problem:
Score : 500 points

Problem Statement

There are N blocks arranged in a row. Let us paint these blocks.

We will consider two ways to paint the blocks different if and only if there is a block painted in different colors in those two ways.

Find the number of ways to paint the blocks under the following conditions:

For each block, use one of the M colors, Color 1 through Color M, to paint it. It is not mandatory to use all the colors.

There may be at most K pairs of adjacent blocks that are painted in the same color.

Since the count may be enormous, print it modulo 998244353.

Constraints

All values in input are integers.

1 \leq N, M \leq 2 \times 10^5

0 \leq K \leq N - 1

Input

Input is given from Standard Input in the following format:

N M K

Output

Print the answer.

Sample Input 1

3 2 1

Sample Output 1

6

The following ways to paint the blocks satisfy the conditions: 112, 121, 122, 211, 212, and 221. Here, digits represent the colors of the blocks.

Sample Input 2

100 100 0

Sample Output 2

73074801

Sample Input 3

60522 114575 7559

Sample Output 3

479519525

Solution in Python (3.8.2) (judge verdict: Wrong Answer)

n, m, k = map(int, input().split())
mod = 998244353

MAX = 2 * 10 ** 5 + 10

fact = [1] * (MAX + 1)
for i in range(1, MAX + 1):
    fact[i] = (fact[i-1] * i) % mod

inv = [1] * (MAX + 1)
for i in range(2, MAX + 1):
    inv[i] = inv[mod % i] * (mod - mod // i) % mod

fact_inv = [1] * (MAX + 1)
for i in range(1, MAX + 1):
    fact_inv[i] = fact_inv[i-1] * inv[i] % mod


def comb(n, k):
    if n < k:
        return 0
    return fact[n] * fact_inv[n-k] * fact_inv[k] % mod


ans = 0
power = pow(m - 1, n - 1, mod)
for i in range(k + 1):
    ans += comb(n - 1, i) * m * power
    ans %= mod
    power *= inv[m - 1]
    power %= mod

print(ans)