Problem:
Score : 300 points

Problem Statement

Let f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:

1 \leq x,y,z

x^2 + y^2 + z^2 + xy + yz + zx = n

Given an integer N, find each of f(1),f(2),f(3),\ldots,f(N).

Constraints

All values in input are integers.

1 \leq N \leq 10^4

Input

Input is given from Standard Input in the following format:

N

Output

Print N lines. The i-th line should contain the value f(i).

Sample Input 1

20

Sample Output 1

0
0
0
0
0
1
0
0
0
0
3
0
0
0
0
0
3
3
0
0

For n=6, only (1,1,1) satisfies both of the conditions. Thus, f(6) = 1.

For n=11, three triples, (1,1,2), (1,2,1), and (2,1,1), satisfy both of the conditions. Thus, f(6) = 3.

For n=17, three triples, (1,2,2), (2,1,2), and (2,2,1), satisfy both of the conditions. Thus, f(17) = 3.

For n=18, three triples, (1,1,3), (1,3,1), and (3,1,1), satisfy both of the conditions. Thus, f(18) = 3.

Solution in PyPy3 (7.3.0) (judge verdict: Accepted)

N = int(input())
n = 10**4
tmp = [0]*((10**4)+1)
for x in range(1,int(-(-n**0.5//1))+1):
    for y in range(1,x+1):
        for z in range(1, y+1):
            if x*x + y*y + z*z + x*y + y*z + z*x <= 10**4:
                if x == y and y == z and z == x:
                    tmp[x*x + y*y + z*z + x*y + y*z + z*x] +=1
                elif x == y or y == z or z == x:
                    tmp[x*x + y*y + z*z + x*y + y*z + z*x]  += 3
                else:
                    tmp[x*x + y*y + z*z + x*y + y*z + z*x]  += 6
for i in range(1, N+1):
    print(tmp[i])