Problem:
Score : 400 points

Problem Statement

There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.

Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.

You are given an integer K that is less than or equal to 10, and K non-intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K].
Let S be the union of these K segments.
Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.

When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.

To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq K \leq \min(N, 10)

1 \leq L_i \leq R_i \leq N

[L_i, R_i] and [L_j, R_j] do not intersect (i \neq j)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
L_1 R_1
L_2 R_2
:
L_K R_K

Output

Print the number of ways for Tak to go from Cell 1 to Cell N, modulo 998244353.

Sample Input 1

5 2
1 1
3 4

Sample Output 1

4

The set S is the union of the segment [1, 1] and the segment [3, 4], therefore S = \{ 1, 3, 4 \} holds.

There are 4 possible ways to get to Cell 5:

1 \to 2 \to 3 \to 4 \to 5,

1 \to 2 \to 5,

1 \to 4 \to 5 and

1 \to 5.

Sample Input 2

5 2
3 3
5 5

Sample Output 2

0

Because S = \{ 3, 5 \} holds, you cannot reach to Cell 5.
Print 0.

Sample Input 3

5 1
1 2

Sample Output 3

5

Sample Input 4

60 3
5 8
1 3
10 15

Sample Output 4

221823067

Note that you have to print the answer modulo 998244353.

Solution in PyPy3 (7.3.0) (judge verdict: Time Limit Exceeded)

# coding=utf-8
from math import floor, ceil, sqrt, factorial, log, gcd
from itertools import accumulate, permutations, combinations, product, combinations_with_replacement
from bisect import bisect_left, bisect_right
from collections import Counter, defaultdict, deque
from heapq import heappop, heappush, heappushpop, heapify
import copy
import sys
INF = float('inf')
mod = 10**9+7
sys.setrecursionlimit(10 ** 6)


def lcm(a, b): return a * b / gcd(a, b)

# 1 2 3
# a, b, c = LI()


def LI(): return list(map(int, sys.stdin.buffer.readline().split()))

# a = I()


def I(): return int(sys.stdin.buffer.readline())

# abc def
# a, b = LS()


def LS(): return sys.stdin.buffer.readline().rstrip().decode('utf-8').split()

# a = S()


def S(): return sys.stdin.buffer.readline().rstrip().decode('utf-8')

# 2
# 1
# 2
# [1, 2]


def IR(n): return [I() for i in range(n)]

# 2
# 1 2 3
# 4 5 6
# [[1,2,3], [4,5,6]]


def LIR(n): return [LI() for i in range(n)]

# 2
# abc
# def
# [abc, def]


def SR(n): return [S() for i in range(n)]

# 2
# abc def
# ghi jkl
# [[abc,def], [ghi,jkl]]


def LSR(n): return [LS() for i in range(n)]

# 2
# abcd
# efgh
# [[a,b,c,d], [e,f,g,h]]


def SRL(n): return [list(S()) for i in range(n)]


n, k = LI()
s = set()
for i in range(k):
    l, r = LI()
    s |= set(range(l, r + 1))

# a = len(s)
dp = [0] * (n + 1)
dp[1] = 1
m = max(s)

for i in range(1, n+1):
    for j in range(i-m, i):
        if i-j in s:
            dp[i] += dp[j] % 998244353
            # dp[i] += dp[j]
print(dp[n] % 998244353)