Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in Python (3.8.2) (judge verdict: Wrong Answer)

n, a, b, c = map(int, input().split())

nums = {"A": a, "B": b, "C": c}

s = []
for i in range(n):
    line = input()
    s.append(line)

def add(a, b):
    nums[a] += 1
    nums[b] -= 1
    ans.append(a)

flag = True

ans = []

for i in range(n):
    a = s[i][0]
    b = s[i][1]

    if nums[a] == 0 and nums[b] == 0:
        print("No")
        flag = False
        break

    if nums[a] == 0:
        add(a, b)
        
    elif nums[b] == 0:
        add(b, a)
        
    else:
        if i != n - 1:
            na = s[i + 1][0]
            nb = s[i + 1][1]

            if (a == na or a == nb):
                add(a, b)

            else:
                add(b, a)

        else:
            add(a, b)

print("Yes")

for i in ans:
    print(i)