Problem:
Score : 500 points

Problem Statement

You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)

Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

N, Q, i_q, l_q, and r_q are integers.

S is a string consisting of lowercase English letters.

c_q is a lowercase English letter.

1 \leq N \leq 500000

1 \leq Q \leq 20000

|S| = N

1 \leq i_q \leq N

1 \leq l_q \leq r_q \leq N

There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:

N
S
Q
Query_1
\vdots
Query_Q

Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:

1 i_q c_q

2 l_q r_q

Output

For each query of type 2, print a line containing the answer.

Sample Input 1

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7

Sample Output 1

3
1
5

In the first query, cdbb contains three kinds of letters: b , c , and d, so we print 3.

In the second query, S is modified to abcdzbd.

In the third query, a contains one kind of letter: a, so we print 1.

In the fourth query, S is modified to abcazbd.

In the fifth query, S does not change and is still abcazbd.

In the sixth query, abcazbd contains five kinds of letters: a, b, c, d, and z, so we print 5.

Solution in Python (3.8.2) (judge verdict: Accepted)

class SegmentTree:
    def __init__(self,n,ele=0):
        self.ide_ele = ele
        self.num =2**(n-1).bit_length()
        self.seg=[self.ide_ele]*2*self.num

    def segfunc(self,x,y):
        return x|y

    def init(self,init_val):
        for i in range(len(init_val)):
            self.seg[i+self.num-1]=init_val[i]
        for i in range(self.num-2,-1,-1) :
            self.seg[i]=self.segfunc(self.seg[2*i+1],self.seg[2*i+2]) 

    def update(self,k,x):
        k += self.num-1
        if self.seg[k]==x:
          return 0
        self.seg[k] = x
        while k:
            k = (k-1)//2
            self.seg[k] = self.segfunc(self.seg[k*2+1],self.seg[k*2+2])

    def query(self,p,q):
        if q<=p:
            return self.ide_ele
        p += self.num-1
        q += self.num-2
        res=self.ide_ele
        while q-p>1:
            if p&1 == 0:
                res = self.segfunc(res,self.seg[p])
            if q&1 == 1:
                res = self.segfunc(res,self.seg[q])
                q -= 1
            p = p//2
            q = (q-1)//2
        if p == q:
            res = self.segfunc(res,self.seg[p])
        else:
            res = self.segfunc(self.segfunc(res,self.seg[p]),self.seg[q])
        return res
      
N,S,Q=int(input()),input(),int(input())
d={'a': 1, 'b': 2, 'c': 4, 'd': 8, 'e': 16, 'f': 32, 'g': 64, 'h': 128, 'i': 256, 'j': 512, 'k': 1024, 'l': 2048, 'm': 4096, 'n': 8192, 'o': 16384, 'p': 32768, 'q': 65536, 'r': 131072, 's': 262144, 't': 524288, 'u': 1048576, 'v': 2097152, 'w': 4194304, 'x': 8388608, 'y': 16777216, 'z': 33554432}

initial=[d[c] for c in list(S)]

ST=SegmentTree(N)
ST.init(initial)

for _ in range(Q):
    typ,a,b=input().split()
    if typ=='1':
        i,c=int(a),d[b]
        ST.update(i-1,c)
    else:
        l,r=int(a)-1,int(b)
        x=bin(ST.query(l,r))[2:]
        print(sum(map(int,list(x))))