Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Python (3.4.3) (judge verdict: Accepted)

import itertools
sosuu = [3,5,7,11,13]
n=(int)(input())
count = 0
for i in itertools.combinations(sosuu, 3):
  if i[0] * i[1] * i[2] <= n:
    #print(i)
    count += 1
add = 2 if n >= 189 else (1 if n >= 135 else 0)
print(count + add)