Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in Python (3.4.3) (judge verdict: Accepted)

from statistics import mean, median,variance,stdev
import numpy as np
import sys
import math
import fractions
import itertools
import copy
import collections
from operator import itemgetter
#以下てんぷら
def j(q):
    if q==1: print("Yes")
    else:print("No")
    exit(0)


def ct(x,y):
    if (x>y):print("+")
    elif (x<y): print("-")
    else: print("?")

def ip():
    return int(input())
def printrow(a):
    for i in range(len(a)):
        print(a[i])
def combinations(n,r):
    if n<r:return 0
    return math.factorial(n) // (math.factorial(n - r) * math.factorial(r))
def permutations(n,r):
    if n<r:return 0
    return math.factorial(n) // math.factorial(n - r)

n = ip()                                     #入力整数1つ
#a,b,t= (int(i) for i in input().split())       #入力整数横2つ以上
a = [int(i) for i in input().split()]        #入力整数配列
#a = input()                                  #入力文字列
#a = input().split()                          #入力文字配列
#k = ip()                      #入力セット(整数改行あり)(1/2)
#v=[ip() for i in range(n)]    #入力セット(整数改行あり)(2/2)
#a=[input() for i in range(n)]    #入力セット(整数改行あり)(2/2)
#jの変数はしようできないので注意
#全足しにsum変数使用はsum関数使用できないので注意
#こっから本文
if n%2==0:
    for i in range(n-1,-1,-2):
        print(a[i],end=' ')
    for i in range(0,n,2):
        print(a[i],end=' ')
else:
    for i in range(n-1,-1,-2):
        print(a[i],end=' ')
    for i in range(1,n,2):
        print(a[i],end=' ')