Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

import sys

n, a, b, c, d = map(int, input().split())
s = [ s for s in input()]
a = a-1
b = b-1
s[a] = "a"
s[b] = "b"

result = True
cnt = 0

if c > d and a < b:
    while True:
        if b+1 < n and (s[b+1] != "a" and s[b+1] != "#"):
            s[b+1] = "b"
            s[b] = "."
            b += 1
        elif b+2 < n and (s[b+2] != "a" and s[b+2] != "#"):
            s[b+2] = "b"
            s[b] = "."
            b += 2
        else:
            cnt = 1
        if b+1 >= n:
            resut = False
            break
        elif s[b-1] == "." and s[b+1] == ".":
            break
        if cnt == 1:
            result = False
            break
    while a < b:
        if a+2 < n and (s[a+2] != "b" and s[a+2] != "#"):
            s[a+2] = "a"
            s[a] = "."
            a += 2
        elif a+1 < n and (s[a+1] != "b" and s[a+1] != "#"):
            s[a+1] = "a"
            s[a] = "."
            a += 1
        else:
            reult = False
            break
if not result:
    print("NO")
    sys.exit(0)

while True:
    if a != c-1:
        if a+2 < n and (s[a+2] != "b" and s[a+2] != "#"):
            s[a+2] = "a"
            s[a] = "."
            a += 2
        elif a+1 < n and (s[a+1] != "b" and s[a+1] != "#"):
            s[a+1] = "a"
            s[a] = "."
            a += 1
        else:
            cnt += 1
    if b != d-1:
        if b+2 < n and (s[b+2] != "a" and s[b+2] != "#"):
            s[b+2] = "b"
            s[b] = "."
            b += 2
        elif b+1 < n and (s[b+1] != "a" and s[b+1] != "#"):
            s[b+1] = "b"
            s[b] = "."
            b += 1
        else:
            cnt += 1
    if cnt == 2:
        result = False
        break
    if a == c-1 and b == d-1:
        break
if result:
    print("YES")
else:
    print("NO")