Problem:
Score : 600 points

Problem Statement

Given are two sequences A and B, both of length N.
A and B are each sorted in the ascending order.
Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.

Constraints

1\leq N \leq 2 \times 10^5

1\leq A_i,B_i \leq N

A and B are each sorted in the ascending order.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N

Output

If there exist no reorderings that satisfy the condition, print No.

If there exists a reordering that satisfies the condition, print Yes on the first line.
After that, print a reordering of B on the second line, separating terms with a whitespace.

If there are multiple reorderings that satisfy the condition, you can print any of them.

Sample Input 1

6
1 1 1 2 2 3
1 1 1 2 2 3

Sample Output 1

Yes
2 2 3 1 1 1

Sample Input 2

3
1 1 2
1 1 3

Sample Output 2

No

Sample Input 3

4
1 1 2 3
1 2 3 3

Sample Output 3

Yes
3 3 1 2

Solution in PyPy3 (7.3.0) (judge verdict: Runtime Error)

"""
T E S T
"""

from collections import Counter, deque

N = int(input())
A = list(map(int, input().split()))
B = list(map(int, input().split()))

cnt_a = Counter(A)
cnt_b = Counter(B)

cnt_ab = cnt_a + cnt_b

for i in cnt_ab.values():
    if i > N:
        print("No")
        exit()


print("Yes")
dq_a = deque(A)
dq_b = deque(B)

ans = []

dq_b.rotate(n // 2)

while dq_a:
    if dq_a[0] != dq_b[0]:
        dq_a.popleft()
        p = dq_b.popleft()
        ans.append(p)
        # ans.append(b.popleft())
    else:
        dq_b.rotate()
print(*ans)