Problem:
Score : 300 points

Problem Statement

"Pizza At", a fast food chain, offers three kinds of pizza: "A-pizza", "B-pizza" and "AB-pizza". A-pizza and B-pizza are completely different pizzas, and AB-pizza is one half of A-pizza and one half of B-pizza combined together. The prices of one A-pizza, B-pizza and AB-pizza are A yen, B yen and C yen (yen is the currency of Japan), respectively.

Nakahashi needs to prepare X A-pizzas and Y B-pizzas for a party tonight. He can only obtain these pizzas by directly buying A-pizzas and B-pizzas, or buying two AB-pizzas and then rearrange them into one A-pizza and one B-pizza. At least how much money does he need for this? It is fine to have more pizzas than necessary by rearranging pizzas.

Constraints

1 ≤ A, B, C ≤ 5000

1 ≤ X, Y ≤ 10^5

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B C X Y

Output

Print the minimum amount of money required to prepare X A-pizzas and Y B-pizzas.

Sample Input 1

1500 2000 1600 3 2

Sample Output 1

7900

It is optimal to buy four AB-pizzas and rearrange them into two A-pizzas and two B-pizzas, then buy additional one A-pizza.

Sample Input 2

1500 2000 1900 3 2

Sample Output 2

8500

It is optimal to directly buy three A-pizzas and two B-pizzas.

Sample Input 3

1500 2000 500 90000 100000

Sample Output 3

100000000

It is optimal to buy 200000 AB-pizzas and rearrange them into 100000 A-pizzas and 100000 B-pizzas. We will have 10000 more A-pizzas than necessary, but that is fine.

Solution in PyPy3 (2.4.0) (judge verdict: Wrong Answer)

A, B, C, X, Y = map(int, input().split())

abs_AB = abs(A - B)
abs_AC = abs(A - C)
abs_BC = abs(B - C)

sum_money = 0.0
if A < B and abs_BC - abs_AC > 0:
    a_x = 0
    for y in range(2 * Y):
        sum_money = sum_money + C
        a_x += 0.5
    a_x = int(a_x)
    for x in range(X - a_x):
        sum_money = sum_money + A

elif A > B and abs_AC - abs_BC > 0:
    b_y = 0
    for x in range(2 * X):
        sum_money = sum_money + C
        b_y += 0.5
    b_y = int(b_y)
    for y in range(Y - b_y):
        sum_money = sum_money + B

else:
    for y in range(Y):
        sum_money = sum_money + B
    for x in range(X):
        sum_money = sum_money + A

print(int(sum_money))