Problem:
Score : 500 points

Problem Statement

N players will participate in a tennis tournament. We will call them Player 1, Player 2, \ldots, Player N.

The tournament is round-robin format, and there will be N(N-1)/2 matches in total.
Is it possible to schedule these matches so that all of the following conditions are satisfied? If the answer is yes, also find the minimum number of days required.

Each player plays at most one matches in a day.

Each player i (1 \leq i \leq N) plays one match against Player A_{i, 1}, A_{i, 2}, \ldots, A_{i, N-1} in this order.

Constraints

3 \leq N \leq 1000

1 \leq A_{i, j} \leq N

A_{i, j} \neq i

A_{i, 1}, A_{i, 2}, \ldots, A_{i, N-1} are all different.

Input

Input is given from Standard Input in the following format:

N
A_{1, 1} A_{1, 2} \ldots A_{1, N-1}
A_{2, 1} A_{2, 2} \ldots A_{2, N-1}
:
A_{N, 1} A_{N, 2} \ldots A_{N, N-1}

Output

If it is possible to schedule all the matches so that all of the conditions are satisfied, print the minimum number of days required; if it is impossible, print -1.

Sample Input 1

3
2 3
1 3
1 2

Sample Output 1

3

All the conditions can be satisfied if the matches are scheduled for three days as follows:

Day 1: Player 1 vs Player 2

Day 2: Player 1 vs Player 3

Day 3: Player 2 vs Player 3

This is the minimum number of days required.

Sample Input 2

4
2 3 4
1 3 4
4 1 2
3 1 2

Sample Output 2

4

All the conditions can be satisfied if the matches are scheduled for four days as follows:

Day 1: Player 1 vs Player 2, Player 3 vs Player 4

Day 2: Player 1 vs Player 3

Day 3: Player 1 vs Player 4, Player 2 vs Player 3

Day 4: Player 2 vs Player 4

This is the minimum number of days required.

Sample Input 3

3
2 3
3 1
1 2

Sample Output 3

-1

Any scheduling of the matches violates some condition.

Solution in PyPy3 (2.4.0) (judge verdict: Wrong Answer)

import sys, re
from collections import deque, defaultdict, Counter
from math import ceil, sqrt, hypot, factorial, pi, sin, cos, radians
from itertools import accumulate, permutations, combinations, product
from operator import itemgetter, mul
from copy import deepcopy
from string import ascii_lowercase, ascii_uppercase, digits
from bisect import bisect, bisect_left
from fractions import gcd
from heapq import heappush, heappop
from functools import reduce
def input(): return sys.stdin.readline().strip()
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(): return list(map(int, input().split()))
sys.setrecursionlimit(10 ** 9)
INF = float('inf')
mod = 10 ** 9 + 7

def main():
	N = INT()
	A = [LIST() for _ in range(N)]

	graph_out = defaultdict(list)
	graph_in = defaultdict(list)
	match_id = [[0]*N for _ in range(N)]

	def toid(i, j):  # 選手から試合IDに変換
		if i > j: i, j = j, i
		return match_id[i][j]

	cnt = 0
	for i in range(N):
		for j in range(N):
			if i < j:
				match_id[i][j] = cnt
				cnt += 1

	for i in range(N):
		for j in range(N-2):
			graph_in[toid(i, A[i][j]-1)].append(toid(i, A[i][j+1]-1))
			graph_out[toid(i, A[i][j+1]-1)].append(toid(i, A[i][j]-1))

	cnt = defaultdict(int)  # cntが入り次数に達したら発火
	day = defaultdict(int)
	checked = [False] * (N*(N-1)//2)
	q = deque([])
	for i, j in combinations(range(N), 2):
		match = match_id[i][j]
		if not graph_in[match]:  # 入り次数0
			q.append(match)
			day[match] = 1
			checked[match] = True
	if not q:
		print(-1)
		exit()

	ans = 0

	while q:
		n = q.popleft()
		for node in graph_out[n]:
			if checked[node]:  # 閉路
				print(-1)
				exit()
			cnt[node] += 1
			if cnt[node] == len(graph_in[node]):
				q.append(node)
				day[node] = day[n] + 1
				ans = day[node]

	print(ans) 

if __name__ == '__main__':
	main()