Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in Python (3.8.2) (judge verdict: Accepted)

def ifif(s):
  if s:
    print("Yes")
  else:
    print("No")

###senkei

def ri(): return int(input())
def rli(): return list(map(int, input().split()))
def rls(): return list(map(str, input().split()))
def pl(a): print(" ".join(list(map(str, a))))
def ma():return map(int,input().split())
from itertools import accumulate as acc
import operator as op
import copy as cp
import math; import numpy
from bisect import bisect_left as bisl
from bisect import bisect_right as bisr
###
n=ri()
a=[]
for i in range(1,n+1):
    if i%3==0 or i%5==0:
        a.append(0)
    else:
        a.append(i)

print(sum(a))