Problem:
Score : 400 points

Problem Statement

We have an undirected graph G with N vertices numbered 1 to N and N edges as follows:

For each i=1,2,...,N-1, there is an edge between Vertex i and Vertex i+1.

There is an edge between Vertex X and Vertex Y.

For each k=1,2,...,N-1, solve the problem below:

Find the number of pairs of integers (i,j) (1 \leq i < j \leq N) such that the shortest distance between Vertex i and Vertex j in G is k.

Constraints

3 \leq N \leq 2 \times 10^3

1 \leq X,Y \leq N

X+1 < Y

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X Y

Output

For each k=1, 2, ..., N-1 in this order, print a line containing the answer to the problem.

Sample Input 1

5 2 4

Sample Output 1

5
4
1
0

The graph in this input is as follows:

There are five pairs (i,j) (1 \leq i < j \leq N) such that the shortest distance between Vertex i and Vertex j is 1: (1,2)\,,(2,3)\,,(2,4)\,,(3,4)\,,(4,5).

There are four pairs (i,j) (1 \leq i < j \leq N) such that the shortest distance between Vertex i and Vertex j is 2: (1,3)\,,(1,4)\,,(2,5)\,,(3,5).

There is one pair (i,j) (1 \leq i < j \leq N) such that the shortest distance between Vertex i and Vertex j is 3: (1,5).

There are no pairs (i,j) (1 \leq i < j \leq N) such that the shortest distance between Vertex i and Vertex j is 4.

Sample Input 2

3 1 3

Sample Output 2

3
0

The graph in this input is as follows:

Sample Input 3

7 3 7

Sample Output 3

7
8
4
2
0
0

Sample Input 4

10 4 8

Sample Output 4

10
12
10
8
4
1
0
0
0

Solution in Python (3.4.3) (judge verdict: Accepted)

def main():
    import sys
    from collections import deque
    input = sys.stdin.buffer.readline


    def bfs(v):
        dist = [f_inf for _ in range(n)]
        dist[v] = 0
        q = deque()
        q.append(v)
        while q:
            u = q.popleft()
            for nv in tree[u]:
                if dist[nv] == f_inf:
                    dist[nv] = dist[u] + 1
                    q.append(nv)
        for d in dist:
            res[d] += 1


    n, x, y = map(int, input().split())

    tree = [[] for _ in range(n)]
    for i in range(n - 1):
        tree[i].append(i + 1)
        tree[i + 1].append(i)
    tree[x - 1].append(y - 1)
    tree[y - 1].append(x - 1)

    f_inf = float("inf")
    res = [0 for _ in range(n)]
    for i in range(n):
        bfs(i)

    for i in range(1, n):
        print(res[i] // 2)

if __name__ == '__main__':
    main()