Problem:
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Connected Components

Write a program which reads relations in a SNS (Social Network Service), and judges that given pairs of users are reachable each other through the network.

Input

In the first line, two integer $n$ and $m$ are given. $n$ is the number of users in the SNS and $m$ is the number of relations in the SNS. The users in the SNS are identified by IDs $0, 1, ..., n-1$.

In the following $m$ lines, the relations are given. Each relation is given by two integers $s$ and $t$ that represents $s$ and $t$ are friends (and reachable each other).

In the next line, the number of queries $q$ is given. In the following $q$ lines, $q$ queries are given respectively. Each query consists of two integers $s$ and $t$ separated by a space character.

Output

For each query, print "yes" if $t$ is reachable from $s$ through the social network, "no" otherwise.

Constraints

$2 \leq n \leq 100,000$

$0 \leq m \leq 100,000$

$1 \leq q \leq 10,000$

Sample Input

10 9
0 1
0 2
3 4
5 7
5 6
6 7
6 8
7 8
8 9
3
0 1
5 9
1 3

Sample Output

yes
yes
no

Solution in Python3 (judge verdict: Wrong Answer)

import sys
import os
import pprint

#fd = os.open('ALDS1_11_D.txt', os.O_RDONLY)
#os.dup2(fd, sys.stdin.fileno())

"""connected components"""

l = list(map(int, input().split()))

# node num
n = l[0]

# relation num
m = l[1]

# each node color
colors = [None] * n

rel_list = []
for _ in range(n):
    rel_list.append([])
# relation
for _ in range(m):
    l = list(map(int, input().split()))
    s = l[0]
    t = l[1]
    rel_list[s].append(t)

# coloring by DFS or BFS
for node_index in range(n):

    stack = []
    if colors[node_index] is None:
        stack.append(node_index)
        while stack:
            # process top of stack
            top = stack.pop()
            colors[top] = node_index

            relations = rel_list[top]
            for relation in relations:
                if colors[relation] is None:
                    stack.append(relation)

# question num
q = int(input())

for _ in range(q):
    l = list(map(int, input().split()))
    s = l[0]
    t = l[1]
    if colors[s] == colors[t]:
        print('yes')
    else:
        print('no')