Problem:
Score : 100 points

Problem Statement

There are three airports A, B and C, and flights between each pair of airports in both directions.

A one-way flight between airports A and B takes P hours, a one-way flight between airports B and C takes Q hours, and a one-way flight between airports C and A takes R hours.

Consider a route where we start at one of the airports, fly to another airport and then fly to the other airport.

What is the minimum possible sum of the flight times?

Constraints

1 \leq P,Q,R \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

P Q R

Output

Print the minimum possible sum of the flight times.

Sample Input 1

1 3 4

Sample Output 1

4

The sum of the flight times in the route A \rightarrow B \rightarrow C: 1 + 3 = 4 hours

The sum of the flight times in the route A \rightarrow C \rightarrow C: 4 + 3 = 7 hours

The sum of the flight times in the route B \rightarrow A \rightarrow C: 1 + 4 = 5 hours

The sum of the flight times in the route B \rightarrow C \rightarrow A: 3 + 4 = 7 hours

The sum of the flight times in the route C \rightarrow A \rightarrow B: 4 + 1 = 5 hours

The sum of the flight times in the route C \rightarrow B \rightarrow A: 3 + 1 = 4 hours

The minimum of these is 4 hours.

Sample Input 2

3 2 3

Sample Output 2

5

Solution in Python (3.4.3) (judge verdict: Runtime Error)

from math import *

def fib(n):
    return ((1+sqrt(5))**(n+1)  -  (1-sqrt(5))**(n+1)) // (2**(n+1)*sqrt(5))


def how_many_ways(lst_of_broken_steps,goal):

    for i in range(len(lst_of_broken_steps)-1):#連続しているbrokenステップがあった時
        if lst_of_broken_steps[i]+1==lst_of_broken_steps[i+1]:
            return 0
    
    #1回目のbrokenステップの処理
    ans = fib(lst_of_broken_steps[0]-1)
    ans = ans % 1000000007

    for i in range(1,len(lst_of_broken_steps)):#2回目以降のbrokenステップの処理
        ans *= fib((lst_of_broken_steps[i]-1)-(lst_of_broken_steps[i-1]+1))
        ans = ans%1000000007
    

    #最後のbrokenステップの処理の後からゴールまで
    ans *= fib(goal-(lst_of_broken_steps[-1]+1))

    return ans % 1000000007



goal,n = map(int,input().split())
lst_of_broken_steps = []
for i in range(n):
    lst_of_broken_steps.append(int(input()))

print(int(how_many_ways(lst_of_broken_steps,goal)))