Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length N, a_1,a_2,...,a_N.

For each 1≤i≤N, you have three choices: add 1 to a_i, subtract 1 from a_i or do nothing.

After these operations, you select an integer X and count the number of i such that a_i=X.

Maximize this count by making optimal choices.

Constraints

1≤N≤10^5

0≤a_i<10^5 (1≤i≤N)

a_i is an integer.

Input

The input is given from Standard Input in the following format:

N
a_1 a_2 .. a_N

Output

Print the maximum possible number of i such that a_i=X.

Sample Input 1

7
3 1 4 1 5 9 2

Sample Output 1

4

For example, turn the sequence into 2,2,3,2,6,9,2 and select X=2 to obtain 4, the maximum possible count.

Sample Input 2

10
0 1 2 3 4 5 6 7 8 9

Sample Output 2

3

Sample Input 3

1
99999

Sample Output 3

1

Solution in Python (3.4.3) (judge verdict: Runtime Error)

from collections import Counter
n = int(input())
a = list(map(int, input().split()))

if len(set(a)) == 1:
    print(n)
    exit()
elif len(set(a)) == n:
    print(3)

c = Counter(a)
mc = c.most_common()[0][0]
# if mc == 0:
#     mc = c.most_common()[1][0]

# if 10**5 - 1 > mc > 1:
#     ans = c.most_common()[0][1] + a.count(mc-1) + a.count(mc+1)
# elif mc == 1:
#     ans = a.count(1) + a.count(2) + a.count(3)

if mc-1 in a and mc+1 in a:
    ans = a.count(mc-1) + a.count(mc) + a.count(mc+1)
elif (mc-1 not in a) and (mc+1 in a):
    ans = a.count(mc) + a.count(mc+1) + a.count(mc+2)
elif (mc-1 in a) and (mc+1 not in a):
    ans = a.count(mc) + a.count(mc-1) + a.count(mc-2)

print(ans)