Problem:
Score : 500 points

Problem Statement

There are N integers, A_1, A_2, ..., A_N, written on a blackboard.

We will repeat the following operation N-1 times so that we have only one integer on the blackboard.

Choose two integers x and y on the blackboard and erase these two integers. Then, write a new integer x-y.

Find the maximum possible value of the final integer on the blackboard and a sequence of operations that maximizes the final integer.

Constraints

2 \leq N \leq 10^5

-10^4 \leq A_i \leq 10^4

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the maximum possible value M of the final integer on the blackboard, and a sequence of operations x_i, y_i that maximizes the final integer, in the format below.

Here x_i and y_i represent the integers x and y chosen in the i-th operation, respectively.

If there are multiple sequences of operations that maximize the final integer, any of them will be accepted.

M
x_1 y_1
:
x_{N-1} y_{N-1}

Sample Input 1

3
1 -1 2

Sample Output 1

4
-1 1
2 -2

If we choose x = -1 and y = 1 in the first operation, the set of integers written on the blackboard becomes (-2, 2).

Then, if we choose x = 2 and y = -2 in the second operation, the set of integers written on the blackboard becomes (4).

In this case, we have 4 as the final integer. We cannot end with a greater integer, so the answer is 4.

Sample Input 2

3
1 1 1

Sample Output 2

1
1 1
1 0

Solution in Python (2.7.6) (judge verdict: Wrong Answer)

# coding:utf-8

import math

def main():
    n = int(raw_input())
    an = map(int,raw_input().split())
    mi = min(an)
    mx = max(an)
    total = mx - mi
    miCheck = False
    mxCheck = False
    for a in an:
        if miCheck == False and a == mi:
            miCheck == True
            continue
        if mxCheck == False and a == mx:
            mxCheck == True
            continue
        total += a
    print total
    miCheck = False
    mxCheck = False
    print mi,mx
    tmp = mi - mx
    cnt = 1
    an.remove(mi)
    an.remove(mx)
    for a in an:
        if cnt == len(an):
            print a,tmp
        else:
            print tmp, a
            tmp = tmp - a
        cnt += 1

if __name__ == "__main__":
    main()