Problem:
Score : 400 points

Problem Statement

You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

In the i-th operation, you replace every element whose value is B_{i} with C_{i}.

For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

All values in input are integers.

1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}

B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:

N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}

Output

Print Q integers S_{i} to Standard Output in the following format:

S_{1}
S_{2}
\vdots
S_{Q}

Note that S_{i} may not fit into a 32-bit integer.

Sample Input 1

4
1 2 3 4
3
1 2
3 4
2 4

Sample Output 1

11
12
16

Initially, the sequence A is 1,2,3,4.

After each operation, it becomes the following:

2, 2, 3, 4

2, 2, 4, 4

4, 4, 4, 4

Sample Input 2

4
1 1 1 1
3
1 2
2 1
3 5

Sample Output 2

8
4
4

Note that the sequence A may not contain an element whose value is B_{i}.

Sample Input 3

2
1 2
3
1 100
2 100
100 1000

Sample Output 3

102
200
2000

Solution in Python (3.8.2) (judge verdict: Time Limit Exceeded)

import bisect
n = int(input())
a = list(map(int,input().split()))
q = int(input())
b=[]
c=[]
aa=[]
sum=0
for i in range(n):
    sum+= a[i]
for i in range(q):
    bb,cc = map(int,input().split())
    b.append(bb)
    c.append(cc)
a.sort()

for i in range(q):
    l= bisect.bisect_left(a,b[i])
    h= bisect.bisect_right(a,b[i])
    ll=bisect.bisect_left(a,c[i])
    hh= bisect.bisect_right(a,c[i])
    if b[i]>c[i]:
        a[ll+h-l:h],a[ll:ll+h-l] = a[ll:l],[c[i]]*(h-l)
    else:
        a[l+hh-h:hh],a[l:l+hh-h] = [c[i]]*(h-l),a[h:hh]
    sum=sum + (c[i]-b[i])*(h-l)
    print(sum)