Problem:
Score : 300 points

Problem Statement

AtCoDeer the deer is going on a trip in a two-dimensional plane.
In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.

If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1).
Note that he cannot stay at his place.
Determine whether he can carry out his plan.

Constraints

1 ≤ N ≤ 10^5

0 ≤ x_i ≤ 10^5

0 ≤ y_i ≤ 10^5

1 ≤ t_i ≤ 10^5

t_i < t_{i+1} (1 ≤ i ≤ N-1)

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
t_1 x_1 y_1
t_2 x_2 y_2
:
t_N x_N y_N

Output

If AtCoDeer can carry out his plan, print Yes; if he cannot, print No.

Sample Input 1

2
3 1 2
6 1 1

Sample Output 1

Yes

For example, he can travel as follows: (0,0), (0,1), (1,1), (1,2), (1,1), (1,0), then (1,1).

Sample Input 2

1
2 100 100

Sample Output 2

No

It is impossible to be at (100,100) two seconds after being at (0,0).

Sample Input 3

2
5 1 1
100 1 1

Sample Output 3

No

Solution in Python (3.4.3) (judge verdict: Accepted)

#-*-coding:utf-8-*-

def main():
    #入力
    N = int(input())
    lists = []
    for i in range(N):
        lists.append(list(map(int, input().split())))
    
    #変数
    position = [0, 0]
    begin_time = 0
    move_flag = 0

    #時間の変位-移動距離が0位上かつ、2の倍数であったらその位置に行くことができる
    for i in range(N):
        #時間の変位
        time_diff = lists[i][0] - begin_time
        begin_time = lists[i][0]
        #距離を求める
        distance = abs(lists[i][1] - position[0]) + abs(lists[i][2] - position[1])
        position = [lists[i][1], lists[i][2]]
        if time_diff - distance >= 0 and (time_diff - distance) % 2 == 0:
            move_flag = 1
        else:
            move_flag = 0
            break
    
    if move_flag == 1:
        print('Yes')
    elif move_flag == 0:
        print('No')

    
if __name__ == '__main__':
    main()