Problem:
Score : 400 points

Problem Statement

Given are positive integers A and B.

Let us choose some number of positive common divisors of A and B.

Here, any two of the chosen divisors must be coprime.

At most, how many divisors can we choose?

Definition of common divisor

An integer d is said to be a common divisor of integers x and y when d divides both x and y.

Definition of being coprime

Integers x and y are said to be coprime when x and y have no positive common divisors other than 1.

Definition of dividing

An integer x is said to divide another integer y when there exists an integer \alpha such that y = \alpha x.

Constraints

All values in input are integers.

1 \leq A, B \leq 10^{12}

Input

Input is given from Standard Input in the following format:

A B

Output

Print the maximum number of divisors that can be chosen to satisfy the condition.

Sample Input 1

12 18

Sample Output 1

3

12 and 18 have the following positive common divisors: 1, 2, 3, and 6.

1 and 2 are coprime, 2 and 3 are coprime, and 3 and 1 are coprime, so we can choose 1, 2, and 3, which achieve the maximum result.

Sample Input 2

420 660

Sample Output 2

4

Sample Input 3

1 2019

Sample Output 3

1

1 and 2019 have no positive common divisors other than 1.

Solution in Python (3.4.3) (judge verdict: Accepted)

import sys
sys.setrecursionlimit(1000000000)
ii = lambda: int(input())
ii0 = lambda: ii() - 1
mis = lambda: map(int, input().split())
lmis = lambda: list(mis())
INF = float('inf')
def divs_gen(n):
    for i in range(1, int(m**.5)+1):
        if n%i == 0:
            yield i
            if i != n//i:
                yield n//i


def main():
    A, B = mis()
    from fractions import gcd
    G = gcd(A, B)
    fs = set()
    for i in range(2, int(G**0.5)+2):
        if G%i == 0 and all(i%f != 0 for f in fs):
            fs.add(i)
            while G%i == 0:
                G //= i
    if G > 1:
        fs.add(G)
    print(len(fs)+1)


main()