Problem:
Score : 400 points

Problem Statement

Given is a string S. Each character in S is either a digit (0, ..., 9) or ?.

Among the integers obtained by replacing each occurrence of ? with a digit, how many have a remainder of 5 when divided by 13? An integer may begin with 0.

Since the answer can be enormous, print the count modulo 10^9+7.

Constraints

S is a string consisting of digits (0, ..., 9) and ?.

1 \leq |S| \leq 10^5

Input

Input is given from Standard Input in the following format:

S

Output

Print the number of integers satisfying the condition, modulo 10^9+7.

Sample Input 1

??2??5

Sample Output 1

768

For example, 482305, 002865, and 972665 satisfy the condition.

Sample Input 2

?44

Sample Output 2

1

Only 044 satisfies the condition.

Sample Input 3

7?4

Sample Output 3

0

We may not be able to produce an integer satisfying the condition.

Sample Input 4

?6?42???8??2??06243????9??3???7258??5??7???????774????4?1??17???9?5?70???76???

Sample Output 4

153716888

Solution in PyPy3 (2.4.0) (judge verdict: Accepted)

MOD = 10**9+7
# dp[i][j] := Sの後ろからi桁を13で割った余りがjとなるようなものの個数
S = input()
l = len(S)
dp = [[0]*13 for _ in range(l+5)]
dp[0][0] = 1
mul = 1  
for i in range(l):
    x = S[-(i+1)]
    if x == "?":
        for k in range(10):
            for j in range(13):
                dp[i + 1][(mul * k + j) % 13] += dp[i][j]
                dp[i + 1][(mul * k + j) % 13] %= MOD
    else:
        k = int(x) # これしか選ぶ余地なし
        for j in range(13):
            dp[i + 1][(mul * k + j) % 13] += dp[i][j]
            dp[i + 1][(mul * k + j) % 13] %= MOD
    mul = mul * 10 % 13
print(dp[l][5]%MOD)