Problem:
Score : 300 points

Problem Statement

Snuke has a fair N-sided die that shows the integers from 1 to N with equal probability and a fair coin. He will play the following game with them:

Throw the die. The current score is the result of the die.

As long as the score is between 1 and K-1 (inclusive), keep flipping the coin. The score is doubled each time the coin lands heads up, and the score becomes 0 if the coin lands tails up.

The game ends when the score becomes 0 or becomes K or above. Snuke wins if the score is K or above, and loses if the score is 0.

You are given N and K. Find the probability that Snuke wins the game.

Constraints

1 ≤ N ≤ 10^5

1 ≤ K ≤ 10^5

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K

Output

Print the probability that Snuke wins the game. The output is considered correct when the absolute or relative error is at most 10^{-9}.

Sample Input 1

3 10

Sample Output 1

0.145833333333

If the die shows 1, Snuke needs to get four consecutive heads from four coin flips to obtain a score of 10 or above. The probability of this happening is \frac{1}{3} \times (\frac{1}{2})^4 = \frac{1}{48}.

If the die shows 2, Snuke needs to get three consecutive heads from three coin flips to obtain a score of 10 or above. The probability of this happening is \frac{1}{3} \times (\frac{1}{2})^3 = \frac{1}{24}.

If the die shows 3, Snuke needs to get two consecutive heads from two coin flips to obtain a score of 10 or above. The probability of this happening is \frac{1}{3} \times (\frac{1}{2})^2 = \frac{1}{12}.

Thus, the probability that Snuke wins is \frac{1}{48} + \frac{1}{24} + \frac{1}{12} = \frac{7}{48} \simeq 0.1458333333.

Sample Input 2

100000 5

Sample Output 2

0.999973749998

Solution in Python (3.8.2) (judge verdict: Wrong Answer)

import sys
from operator import itemgetter
import math

sys.setrecursionlimit(10**9)
input = sys.stdin.readline

def ii(): return int(input())
def mi(): return map(int, input().split())
def lmi(): return list(map(int, input().split()))
def lmif(n): return [list(map(int, input().split())) for _ in range(n)]
def ss(): return input().split()

def main():
    n, k = mi()
    nr = 1/n
    rate = 0.5

    ans = 0
    if n >= k:
        ans += (n - k + 1) * nr
        n = k - 1
    left, right = k//2, k
    while right > 0:
        if left <= n:
            cnt = n - left
            ans += cnt * nr * rate
            n = left
        rate /= 2
        left, right = left//2, left
        
    print(f"{ans:.12f}")
    return

main()