Problem:
Score : 400 points

Problem Statement

There are N persons called Person 1 through Person N.

You are given M facts that "Person A_i and Person B_i are friends." The same fact may be given multiple times.

If X and Y are friends, and Y and Z are friends, then X and Z are also friends. There is no friendship that cannot be derived from the M given facts.

Takahashi the evil wants to divide the N persons into some number of groups so that every person has no friend in his/her group.

At least how many groups does he need to make?

Constraints

2 \leq N \leq 2\times 10^5

0 \leq M \leq 2\times 10^5

1\leq A_i,B_i\leq N

A_i \neq B_i

Input

Input is given from Standard Input in the following format:

N M
A_1 B_1
\vdots
A_M B_M

Output

Print the answer.

Sample Input 1

5 3
1 2
3 4
5 1

Sample Output 1

3

Dividing them into three groups such as \{1,3\}, \{2,4\}, and \{5\} achieves the goal.

Sample Input 2

4 10
1 2
2 1
1 2
2 1
1 2
1 3
1 4
2 3
2 4
3 4

Sample Output 2

4

Sample Input 3

10 4
3 1
4 1
5 9
2 6

Sample Output 3

3

Solution in PyPy3 (7.3.0) (judge verdict: Accepted)

# -*- coding: utf-8 -*-
import sys
sys.setrecursionlimit(10**9)
INF=10**18
MOD=10**9+7
input=lambda: sys.stdin.readline().rstrip()
YesNo=lambda b: bool([print('Yes')] if b else print('No'))
YESNO=lambda b: bool([print('YES')] if b else print('NO'))
int1=lambda x:int(x)-1

N,M=map(int,input().split())

class UnionFind:
    def __init__(self,n):
        self.par=[i for i in range(n)]
        self.siz=[1]*n
        
    def root(self,x):
        while self.par[x]!=x:
            self.par[x]=self.par[self.par[x]]
            x=self.par[x]
        return x
    
    def unite(self,x,y):
        x=self.root(x)
        y=self.root(y)
        if x==y:
            return False
        if self.siz[x]<self.siz[y]:
            x,y=y,x
        self.siz[x]+=self.siz[y]
        self.par[y]=x
        return True
    
    def is_same(self,x,y):
        return self.root(x)==self.root(y)
    
    def size(self,x):
        return self.siz[self.root(x)]
    
u=UnionFind(N)

for _ in range(M):
    a,b=map(int1,input().split())
    u.unite(a,b)

roots=set()

for i in range(N):
    roots.add(u.root(i))

ans=0

for v in roots:
    ans=max(ans,u.size(v))
    
print(ans)