Problem:
Score : 500 points

Problem Statement

There are N blocks arranged in a row. Let us paint these blocks.

We will consider two ways to paint the blocks different if and only if there is a block painted in different colors in those two ways.

Find the number of ways to paint the blocks under the following conditions:

For each block, use one of the M colors, Color 1 through Color M, to paint it. It is not mandatory to use all the colors.

There may be at most K pairs of adjacent blocks that are painted in the same color.

Since the count may be enormous, print it modulo 998244353.

Constraints

All values in input are integers.

1 \leq N, M \leq 2 \times 10^5

0 \leq K \leq N - 1

Input

Input is given from Standard Input in the following format:

N M K

Output

Print the answer.

Sample Input 1

3 2 1

Sample Output 1

6

The following ways to paint the blocks satisfy the conditions: 112, 121, 122, 211, 212, and 221. Here, digits represent the colors of the blocks.

Sample Input 2

100 100 0

Sample Output 2

73074801

Sample Input 3

60522 114575 7559

Sample Output 3

479519525

Solution in Python (3.8.2) (judge verdict: Wrong Answer)

#!/usr/bin/env python3

N, M, K = map(int, input().split())
mod = 998244353

table = [0]
inv_table = [0]
M_table = []

tmp = pow(M - 1, N - 1, mod)
for i in range(K + 1):
    if i > 0:
        tmp *= pow(M - 1, mod - 2, mod)
        tmp %= mod
    M_table.append(tmp)

tmp = 1
for i in range(1, N + 1):
    tmp *= i
    tmp %= mod
    table.append(tmp)

tmp = 1
for i in range(1, N + 1):
    tmp *= pow(i, mod - 2, mod)
    tmp %= mod
    inv_table.append(tmp)

def cmb(n, r):
    if r == 0:
        return 1
    return table[n] * inv_table[r] * inv_table[n - r]

ans = 0
for i in range(K + 1):
    ans += M * M_table[i] * cmb(N - 1, i)
    ans %= mod

print(ans)