Problem:
Score : 200 points

Problem Statement

When Mr. X is away from home, he has decided to use his smartwatch to search the best route to go back home, to participate in ABC.

You, the smartwatch, has found N routes to his home.

If Mr. X uses the i-th of these routes, he will get home in time t_i at cost c_i.

Find the smallest cost of a route that takes not longer than time T.

Constraints

All values in input are integers.

1 \leq N \leq 100

1 \leq T \leq 1000

1 \leq c_i \leq 1000

1 \leq t_i \leq 1000

The pairs (c_i, t_i) are distinct.

Input

Input is given from Standard Input in the following format:

N T
c_1 t_1
c_2 t_2
:
c_N t_N

Output

Print the smallest cost of a route that takes not longer than time T.

If there is no route that takes not longer than time T, print TLE instead.

Sample Input 1

3 70
7 60
1 80
4 50

Sample Output 1

4

The first route gets him home at cost 7.

The second route takes longer than time T = 70.

The third route gets him home at cost 4.

Thus, the cost 4 of the third route is the minimum.

Sample Input 2

4 3
1 1000
2 4
3 1000
4 500

Sample Output 2

TLE

There is no route that takes not longer than time T = 3.

Sample Input 3

5 9
25 8
5 9
4 10
1000 1000
6 1

Sample Output 3

5

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

import numpy as np
NT=list(map(int,input().split()))
N=NT[0]
T=NT[1]
nlist=[]
tlist=[]
for i in range(N):
    listA=list(map(int,input().split()))
    nlist.append(listA[0])
    tlist.append(listA[1])
#indexes = [i for i, x in enumerate(tlist) if x <= T]
npnlist=np.array(nlist)
nptlist=np.array(tlist)
where=np.where(nptlist<=T)
if(where[0]!=[]):
    minmum=100000
    for i in range(len(where[0])):
        if(npnlist[where[0][i]]<minmum):
            minmum=npnlist[where[0][i]]
    print(minmum)
else:
    print("TLE")