Problem:
Score : 400 points

Problem Statement

Given are positive integers A and B.

Let us choose some number of positive common divisors of A and B.

Here, any two of the chosen divisors must be coprime.

At most, how many divisors can we choose?

Definition of common divisor

An integer d is said to be a common divisor of integers x and y when d divides both x and y.

Definition of being coprime

Integers x and y are said to be coprime when x and y have no positive common divisors other than 1.

Definition of dividing

An integer x is said to divide another integer y when there exists an integer \alpha such that y = \alpha x.

Constraints

All values in input are integers.

1 \leq A, B \leq 10^{12}

Input

Input is given from Standard Input in the following format:

A B

Output

Print the maximum number of divisors that can be chosen to satisfy the condition.

Sample Input 1

12 18

Sample Output 1

3

12 and 18 have the following positive common divisors: 1, 2, 3, and 6.

1 and 2 are coprime, 2 and 3 are coprime, and 3 and 1 are coprime, so we can choose 1, 2, and 3, which achieve the maximum result.

Sample Input 2

420 660

Sample Output 2

4

Sample Input 3

1 2019

Sample Output 3

1

1 and 2019 have no positive common divisors other than 1.

Solution in PyPy3 (2.4.0) (judge verdict: Runtime Error)

import sys


def main():
    a, b = [int(s) for s in sys.stdin.readline().strip().split()]

    def gcd(x, y):
        while y:
            x, y = y, x % y
        return x

    def divisors(n, d, ans):
        if n == 1:
            return
        if n % d == 0:
            ans.append(d)
            divisors(n // d, d, ans)
        else:
            divisors(n, d+1, ans)

    gcd_val = gcd(a, b)
    divs = []
    divisors(gcd_val, 2, divs)

    ans = 1
    for div in sorted(list(divs)):
        if div == 1:
            continue
        if gcd_val % div == 0:
            ans += 1
            while gcd_val % div == 0 and gcd_val > 1:
                gcd_val = gcd_val // div
    print(ans)


main()