Problem:
Score: 400 points

Problem Statement

In Takahashi Kingdom, there is a east-west railroad and N cities along it, numbered 1, 2, 3, ..., N from west to east.
A company called AtCoder Express possesses M trains, and the train i runs from City L_i to City R_i (it is possible that L_i = R_i).
Takahashi the king is interested in the following Q matters:

The number of the trains that runs strictly within the section from City p_i to City q_i, that is, the number of trains j such that p_i \leq L_j and R_j \leq q_i.

Although he is genius, this is too much data to process by himself. Find the answer for each of these Q queries to help him.

Constraints

N is an integer between 1 and 500 (inclusive).

M is an integer between 1 and 200 \ 000 (inclusive).

Q is an integer between 1 and 100 \ 000 (inclusive).

1 \leq L_i \leq R_i \leq N (1 \leq i \leq M)

1 \leq p_i \leq q_i \leq N (1 \leq i \leq Q)

Input

Input is given from Standard Input in the following format:

N M Q
L_1 R_1
L_2 R_2
:
L_M R_M
p_1 q_1
p_2 q_2
:
p_Q q_Q

Output

Print Q lines. The i-th line should contain the number of the trains that runs strictly within the section from City p_i to City q_i.

Sample Input 1

2 3 1
1 1
1 2
2 2
1 2

Sample Output 1

3

As all the trains runs within the section from City 1 to City 2, the answer to the only query is 3.

Sample Input 2

10 3 2
1 5
2 8
7 10
1 7
3 10

Sample Output 2

1
1

The first query is on the section from City 1 to 7. There is only one train that runs strictly within that section: Train 1.
The second query is on the section from City 3 to 10. There is only one train that runs strictly within that section: Train 3.

Sample Input 3

10 10 10
1 6
2 9
4 5
4 7
4 7
5 8
6 6
6 7
7 9
10 10
1 8
1 9
1 10
2 8
2 9
2 10
3 8
3 9
3 10
1 10

Sample Output 3

7
9
10
6
8
9
6
7
8
10

Solution in Python (3.4.3) (judge verdict: Accepted)

N, M, Q = map(int, input().split())


class Ruisekiwa2D:
    def __init__(self, h, w):
        self.H = h
        self.W = w
        self.G = [[0] * w for _ in range(h)]

    def load(self, points):
        # 問題によってイメージしやすいよう書き換えてください
        # load終了時にcalcが呼ばれることに注意してください
        for x, y in points:
            self.G[x][y] += 1

        self.calc()

    def load_imos(self, points):
        # pointsは[[左上h, 左上w, 右下h, 右下w], ...]であること
        for i1, j1, i2, j2 in points:
            self.G[i1][j1] += 1  # 左上
            if j2 + 1 < self.W:  # 右上
                self.G[i1][j2+1] -= 1
            if i2 + 1 < self.H:
                self.G[i2+1][j1] -= 1  # 左下
            if j2 + 1 < self.W and i2 + 1 < self.H:  # 右下
                self.G[i2+1][j2+1] += 1

        self.calc()

    def calc(self):
        for y in range(self.W):
            for x in range(1, self.H):
                self.G[x][y] += self.G[x-1][y]

        for y in range(1, self.W):
            for x in range(self.H):
                self.G[x][y] += self.G[x][y-1]

    def get(self, i1, j1, i2, j2):
        if i1 > i2 or j1 > j2 or i1 < 0 or j1 < 0 or i2 < 0 or j2 < 0:
            return 0
        elif i1 > 0 and j1 > 0:
            return self.G[i2][j2] - self.G[i1-1][j2] - self.G[i2][j1-1] + self.G[i1-1][j1-1]
        elif i1 <= 0 < j1:
            return self.G[i2][j2] - self.G[i2][j1-1]
        elif j1 <= 0 < i1:
            return self.G[i2][j2] - self.G[i1 - 1][j2]
        else:
            return self.G[i2][j2]


R2D = Ruisekiwa2D(N, N)
I = []
for i in range(M):
    l, r = map(int, input().split())
    l, r = l -1, r- 1
    I.append((l, r))
R2D.load(I)

for i in range(Q):
    p, q = map(lambda x: int(x) - 1, input().split())
    print(R2D.get(p, p, q, q))