Problem:
Score : 600 points

Problem Statement

A bracket sequence is a string that is one of the following:

An empty string;

The concatenation of (, A, and ) in this order, for some bracket sequence A ;

The concatenation of A and B in this order, for some non-empty bracket sequences A and B /

Given are N strings S_i. Can a bracket sequence be formed by concatenating all the N strings in some order?

Constraints

1 \leq N \leq 10^6

The total length of the strings S_i is at most 10^6.

S_i is a non-empty string consisting of ( and ).

Input

Input is given from Standard Input in the following format:

N
S_1
:
S_N

Output

If a bracket sequence can be formed by concatenating all the N strings in some order, print Yes; otherwise, print No.

Sample Input 1

2
)
(()

Sample Output 1

Yes

Concatenating (() and ) in this order forms a bracket sequence.

Sample Input 2

2
)(
()

Sample Output 2

No

Sample Input 3

4
((()))
((((((
))))))
()()()

Sample Output 3

Yes

Sample Input 4

3
(((
)
)

Sample Output 4

No

Solution in Python (3.8.2) (judge verdict: Wrong Answer)

import sys
n=int(input())
s=[input() for i in range(n)]
t=[2*(i.count("("))-len(i) for i in s]
if sum(t)!=0:
    print("No")
    sys.exit()
st=list(map(list,zip(s,t)))

for i in range(n):
    now,mi=0,0
    for j in st[i][0]:
        if j=="(":
            now+=1
        else:
            now-=1
        mi=min(mi,now)
    st[i].append(mi)
#st.sort(reverse=True,key=lambda z:z[1])
u,v=list(filter(lambda x:x[2]>=0,st)),list(filter(lambda x:x[2]<0,st))
v.sort(reverse=True,key=lambda z:z[1])
v.sort(reverse=True,key=lambda z:z[2])
lu=len(u)
now2=0
for i in range(n):
    if i<lu:
        now2+=u[i][1]
    else:
        if now2+v[i-lu][2]<0:
            print("No")
            break
        now2+=v[i-lu][1]
else:
    print("Yes")