Problem:
Score : 400 points

Problem Statement

There is a knight - the chess piece - at the origin (0, 0) of a two-dimensional grid.

When the knight is at the square (i, j), it can be moved to either (i+1,j+2) or (i+2, j+1).

In how many ways can the knight reach the square (X, Y)?

Find the number of ways modulo 10^9 + 7.

Constraints

1 \leq X \leq 10^6

1 \leq Y \leq 10^6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

Print the number of ways for the knight to reach (X, Y) from (0, 0), modulo 10^9 + 7.

Sample Input 1

3 3

Sample Output 1

2

There are two ways: (0,0) \to (1,2) \to (3,3) and (0,0) \to (2,1) \to (3,3).

Sample Input 2

2 2

Sample Output 2

0

The knight cannot reach (2,2).

Sample Input 3

999999 999999

Sample Output 3

151840682

Print the number of ways modulo 10^9 + 7.

Solution in Python (3.4.3) (judge verdict: Runtime Error)

X,Y = list(map(int,input().split()))

class ModComb:
    def __init__(self, MAX, mod=10 ** 9 + 7):
        fac = [1, 1]
        finv = [1, 1]
        inv = [0, 1]
        for i in range(2, MAX):
            fac.append(fac[i - 1] * i % mod)
            inv.append(mod - inv[mod % i] * (mod // i) % mod)
            finv.append(finv[i - 1] * inv[i] % mod)
        self.fac, self.finv, self.mod = fac, finv, mod
    
    def nCk(self, n, k):
        if n < k or n < 0 or k < 0:
            return 0
        fac, finv, mod = self.fac, self.finv, self.mod
        return fac[n] * (finv[k] * finv[n - k] % mod) % mod
      
if (X+Y)%3 != 0:
    print(O)
else:
    n = (2*X-Y)//3
    m = (2*Y-X)//3
    
    mod = 10 ** 9 + 7
    mc = ModComb(1000000, mod=mod) 

    print(mc.nCk(n+m, n) % mod)