Problem:
Score : 600 points

Problem Statement

Given are two sequences A and B, both of length N.
A and B are each sorted in the ascending order.
Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.

Constraints

1\leq N \leq 2 \times 10^5

1\leq A_i,B_i \leq N

A and B are each sorted in the ascending order.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N

Output

If there exist no reorderings that satisfy the condition, print No.

If there exists a reordering that satisfies the condition, print Yes on the first line.
After that, print a reordering of B on the second line, separating terms with a whitespace.

If there are multiple reorderings that satisfy the condition, you can print any of them.

Sample Input 1

6
1 1 1 2 2 3
1 1 1 2 2 3

Sample Output 1

Yes
2 2 3 1 1 1

Sample Input 2

3
1 1 2
1 1 3

Sample Output 2

No

Sample Input 3

4
1 1 2 3
1 2 3 3

Sample Output 3

Yes
3 3 1 2

Solution in PyPy3 (7.3.0) (judge verdict: Accepted)

from collections import Counter

N = int(input())
A = list(map(int, input().split()))
B = list(map(int, input().split()))


f = True
A_Counter = Counter(A)
B_Counter = Counter(B)
for a in A_Counter.keys():
    if N-A_Counter[a] < B_Counter[a]:
        f = False

if f:
    print('Yes')
    B.sort(reverse=True)
    n = 0
    sw = True
    for i in range(N):
        if A[i] == B[i]:
            if sw:
                B[i], B[n] = B[n], B[i]
                sw = False
            else:
                B[i], B[-1-n] = B[-1-n], B[i]
                n += 1
                sw = True
    print(*B)
else:
    print('No')