Problem:
Score : 500 points

Problem Statement

There are N cards placed face down in a row. On each card, an integer 1 or 2 is written.

Let A_i be the integer written on the i-th card.

Your objective is to guess A_1, A_2, ..., A_N correctly.

You know the following facts:

For each i = 1, 2, ..., M, the value A_{X_i} + A_{Y_i} + Z_i is an even number.

You are a magician and can use the following magic any number of times:

Magic: Choose one card and know the integer A_i written on it. The cost of using this magic is 1.

What is the minimum cost required to determine all of A_1, A_2, ..., A_N?

It is guaranteed that there is no contradiction in given input.

Constraints

All values in input are integers.

2 \leq N \leq 10^5

1 \leq M \leq 10^5

1 \leq X_i < Y_i \leq N

1 \leq Z_i \leq 100

The pairs (X_i, Y_i) are distinct.

There is no contradiction in input. (That is, there exist integers A_1, A_2, ..., A_N that satisfy the conditions.)

Input

Input is given from Standard Input in the following format:

N M
X_1 Y_1 Z_1
X_2 Y_2 Z_2
\vdots
X_M Y_M Z_M

Output

Print the minimum total cost required to determine all of A_1, A_2, ..., A_N.

Sample Input 1

3 1
1 2 1

Sample Output 1

2

You can determine all of A_1, A_2, A_3 by using the magic for the first and third cards.

Sample Input 2

6 5
1 2 1
2 3 2
1 3 3
4 5 4
5 6 5

Sample Output 2

2

Sample Input 3

100000 1
1 100000 100

Sample Output 3

99999

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

class union_find():
    def __init__(self, n):
        self.par = [i for i in range(n + 1)]
        self.rank = [1 for i in range(n + 1)]

    def find(self, c):
        if self.par[c] == c:
            return c

        ret = self.find(self.par[c])
        self.par[c] = ret
        return ret

    def union(self, x, y):
        xr = self.find(x)
        yr = self.find(y)
        if xr == yr:
            return

        if self.rank[yr] > self.rank[xr]:
            self.par[xr] = yr
        else:
            self.par[yr] = xr
            if self.rank[xr] == self.rank[yr]:
                self.rank[xr] += 1

    def show(self):
        print('parent', self.par[1:])
        print('rank', self.rank[1:])

N, M = map(int, input().split())
uf = union_find(N)

for i in range(M):
    x, y, z = map(int, input().split())
    uf.union(x, y)


print([i == v for i, v in enumerate(uf.par[1:])].count(True))