Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Python (3.8.2) (judge verdict: Accepted)

n = int(input())
f = [0 for i in range(n+1)]
for i in range(1,n+1):
    cur = i
    while cur<=n:
        f[cur] += 1
        cur += i 

ans = 0
for i in range(1,n+1):
    if i%2==1 and f[i]==8:
        ans += 1

print(ans)