Problem:
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Matrix Multiplication

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\[
c_{ij} = \sum_{k=1}^m a_{ik}b_{kj}
\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Constraints

$1 \leq n, m, l \leq 100$

$0 \leq a_{ij}, b_{ij} \leq 10000$

Sample Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2

Sample Output

1 8 5
0 9 6
4 23 14

Note

      解説

Solution in Python3 (judge verdict: Wrong Answer)

n,m,l=[int(i) for i in input().split()]
x=[[int(0) for i in range(m)]for j in range(n)]
z=[[int(0) for i in range(n)]for j in range(n)]
y=[[int(0)for i in range(n)]for j in range(m)]
for i in range(n):
    k=input().split()
    for j in range(m):
        x[i][j]=int(k[j])
for i in  range(m):
    k=input().split()
    for j in range(n):
        y[i][j]=int(k[j])
        
for i in range(n):
    for j in range(n):
        count=int(0)
        for v in range(m):
            count=count+x[i][v]*y[v][j]
        z[i][j]=count
for i in range(n):
    for j in range(n-1):
        print(z[i][j],"",end="")
    print(z[i][n-1])