Problem:
Score : 400 points

Problem Statement

We have an undirected graph G with N vertices numbered 1 to N and N edges as follows:

For each i=1,2,...,N-1, there is an edge between Vertex i and Vertex i+1.

There is an edge between Vertex X and Vertex Y.

For each k=1,2,...,N-1, solve the problem below:

Find the number of pairs of integers (i,j) (1 \leq i < j \leq N) such that the shortest distance between Vertex i and Vertex j in G is k.

Constraints

3 \leq N \leq 2 \times 10^3

1 \leq X,Y \leq N

X+1 < Y

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N X Y

Output

For each k=1, 2, ..., N-1 in this order, print a line containing the answer to the problem.

Sample Input 1

5 2 4

Sample Output 1

5
4
1
0

The graph in this input is as follows:

There are five pairs (i,j) (1 \leq i < j \leq N) such that the shortest distance between Vertex i and Vertex j is 1: (1,2)\,,(2,3)\,,(2,4)\,,(3,4)\,,(4,5).

There are four pairs (i,j) (1 \leq i < j \leq N) such that the shortest distance between Vertex i and Vertex j is 2: (1,3)\,,(1,4)\,,(2,5)\,,(3,5).

There is one pair (i,j) (1 \leq i < j \leq N) such that the shortest distance between Vertex i and Vertex j is 3: (1,5).

There are no pairs (i,j) (1 \leq i < j \leq N) such that the shortest distance between Vertex i and Vertex j is 4.

Sample Input 2

3 1 3

Sample Output 2

3
0

The graph in this input is as follows:

Sample Input 3

7 3 7

Sample Output 3

7
8
4
2
0
0

Sample Input 4

10 4 8

Sample Output 4

10
12
10
8
4
1
0
0
0

Solution in Python (3.8.2) (judge verdict: Wrong Answer)

# coding=UTF-8
from collections import deque
from operator import itemgetter
from bisect import bisect_left, bisect
import itertools
import sys
import math
import numpy as np
import time
sys.setrecursionlimit(10**6)
input = sys.stdin.readline


def main():
    n, x, y = map(int, input().split())
    d = [0]*n

    for i in range(1, n):
        for j in range(i+1, n):
            # if i <= x and j >= y:
            #     tree[i - 1][j - 1] = j-i-(y - x - 1)
            # elif i <= x and j < y:
            #     tree[i - 1][j - 1] = x - i + min(y - j + 1, j - x)
            # elif i > x and j >= y:
            #     tree[i - 1][j - 1] = j - y + min(i-x+1, y-i)
            # else:
            #     tree[i - 1][j - 1] = j-i
            d[min(j-i, abs(x-i) +
                  1+abs(j-y), abs(y-i)+1+abs(j-x))] += 1

    for k in range(n):
        print(d[k])