Problem:
Score : 400 points

Problem Statement

Let {\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order.
From n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\rm comb}(a_i,a_j) is maximized.
If there are multiple pairs that maximize the value, any of them is accepted.

Constraints

2 \leq n \leq 10^5

0 \leq a_i \leq 10^9

a_1,a_2,...,a_n are pairwise distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print a_i and a_j that you selected, with a space in between.

Sample Input 1

5
6 9 4 2 11

Sample Output 1

11 6

\rm{comb}(a_i,a_j) for each possible selection is as follows:

\rm{comb}(4,2)=6

\rm{comb}(6,2)=15

\rm{comb}(6,4)=15

\rm{comb}(9,2)=36

\rm{comb}(9,4)=126

\rm{comb}(9,6)=84

\rm{comb}(11,2)=55

\rm{comb}(11,4)=330

\rm{comb}(11,6)=462

\rm{comb}(11,9)=55

Thus, we should print 11 and 6.

Sample Input 2

2
100 0

Sample Output 2

100 0

Solution in PyPy3 (7.3.0) (judge verdict: Accepted)

N = int(input())
A = list(map(int,input().split()))

MAXN = N+1
p = 10**9+7
f = [1]
for i in range(MAXN):
    f.append(f[-1] * (i+1) % p)
def nCr(n, r, mod=p):
    return f[n] * pow(f[r], mod-2, mod) * pow(f[n-r], mod-2, mod) % mod

MA = max(A)
out = [MA,0]
MA2 = MA//2
mincand = 10**9
for i in range(N):
    if mincand>abs(A[i]-MA2) and A[i]!=MA:
        mincand = abs(A[i]-MA2)
        out[1] = A[i]
print(*out)