Problem:
Score : 400 points

Problem Statement

There is a knight - the chess piece - at the origin (0, 0) of a two-dimensional grid.

When the knight is at the square (i, j), it can be moved to either (i+1,j+2) or (i+2, j+1).

In how many ways can the knight reach the square (X, Y)?

Find the number of ways modulo 10^9 + 7.

Constraints

1 \leq X \leq 10^6

1 \leq Y \leq 10^6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

Print the number of ways for the knight to reach (X, Y) from (0, 0), modulo 10^9 + 7.

Sample Input 1

3 3

Sample Output 1

2

There are two ways: (0,0) \to (1,2) \to (3,3) and (0,0) \to (2,1) \to (3,3).

Sample Input 2

2 2

Sample Output 2

0

The knight cannot reach (2,2).

Sample Input 3

999999 999999

Sample Output 3

151840682

Print the number of ways modulo 10^9 + 7.

Solution in PyPy3 (2.4.0) (judge verdict: Accepted)

x,y = map(int,input().split())
MOD = 10**9+7

def inv_mod(a, p=MOD):
    def inv_mod_sub(a, p):
        if a == 1:
            return 1, 0
        else:
            d, r = p//a, p%a
            x, y = inv_mod_sub(r, a)
            return y-d*x, x
    if p < 0: p = -p
    a %= p
    return inv_mod_sub(a,p)[0] % p

def comb_mod(n, k):
    if k < 0 or k > n:
        return 0
    else:
        return f_mod[n]*f_mod_inverse[k]*f_mod_inverse[n-k] % MOD

if (2*y-x) % 3 != 0 or (2*x-y) % 3 != 0:
  print(0)
else:
  k,l = (2*y-x)//3,(2*x-y)//3
  f_mod=[1]*(10**6)
  f_mod_inverse=[1]*(10**6)
  for i in range(1,10**6):
    f_mod[i]=f_mod[i-1]*i%MOD
    f_mod_inverse[i]=f_mod_inverse[i-1]*inv_mod(i)%MOD
  print(comb_mod(k+l,l))