Problem:
Score: 300 points

Problem Statement

In Republic of Atcoder, there are N prefectures, and a total of M cities that belong to those prefectures.

City i is established in year Y_i and belongs to Prefecture P_i.

You can assume that there are no multiple cities that are established in the same year.

It is decided to allocate a 12-digit ID number to each city.

If City i is the x-th established city among the cities that belong to Prefecture i, the first six digits of the ID number of City i is P_i, and the last six digits of the ID number is x.

Here, if P_i or x (or both) has less than six digits, zeros are added to the left until it has six digits.

Find the ID numbers for all the cities.

Note that there can be a prefecture with no cities.

Constraints

1 \leq N \leq 10^5

1 \leq M \leq 10^5

1 \leq P_i \leq N

1 \leq Y_i \leq 10^9

Y_i are all different.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
P_1 Y_1
:
P_M Y_M

Output

Print the ID numbers for all the cities, in ascending order of indices (City 1, City 2, ...).

Sample Input 1

2 3
1 32
2 63
1 12

Sample Output 1

000001000002
000002000001
000001000001

As City 1 is the second established city among the cities that belong to Prefecture 1, its ID number is 000001000002.

As City 2 is the first established city among the cities that belong to Prefecture 2, its ID number is 000002000001.

As City 3 is the first established city among the cities that belong to Prefecture 1, its ID number is 000001000001.

Sample Input 2

2 3
2 55
2 77
2 99

Sample Output 2

000002000001
000002000002
000002000003

Solution in Python (3.4.3) (judge verdict: Accepted)

N, M = map ( int, input ( ).split ( ) )# N,Mを取得
#初期化
lists = [ ]
#listに要素を追加　後で並び変えるため並び替える前の順番を示すキーを第三要素に挿入しておく
for i in range ( M ):
    lists.append ( list ( map ( int, input ( ).split ( ) ) ) + [ i ] )
#第一要素に昇順で並び替えた後、第二要素で昇順に並び替える
lists.sort ( key=lambda x: x[ 1 ] )
lists.sort ( key=lambda x: x[ 0 ] )
# befは前回の第一要素　stateは第一要素での順位
bef = 0
state = 0
retstr = ''
triple = [ ]#第四要素に識別番号を追加したリストの初期化
for i in lists:
    if (i[ 0 ] != bef):
        bef = i[ 0 ]
        state = 1
        triple.append ( [ i[ 0 ], i[ 1 ], i[ 2 ], str ( i[ 0 ] ).rjust ( 6, '0' ) + str ( state ).rjust ( 6, '0' ) ] )
    else:
        state += 1
        triple.append ( [ i[ 0 ], i[ 1 ], i[ 2 ], str ( i[ 0 ] ).rjust ( 6, '0' ) + str ( state ).rjust ( 6, '0' ) ] )
 
triple.sort ( key=lambda x: x[ 2 ] )#第三要素で並び替えて、元の入力に対応した式ベンツ番号の順番に戻す
for i in triple:
    print ( i[ 3 ] )#識別番号の出力