Problem:
Finding Missing Cards

Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).

The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.

Input

In the first line, the number of cards n (n ≤ 52) is given.

In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.

Output

Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line.
Arrange the missing cards in the following priorities:

Print cards of spades, hearts, clubs and diamonds in this order.

If the suits are equal, print cards with lower ranks first.

Sample Input

47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13

Sample Output

S 1
H 3
H 7
C 12
D 8

Note

      解説

Solution in Python3 (judge verdict: Accepted)

n=int(input())
s=[1,2,3,4,5,6,7,8,9,10,11,12,13]
h=[1,2,3,4,5,6,7,8,9,10,11,12,13]
c=[1,2,3,4,5,6,7,8,9,10,11,12,13]
d=[1,2,3,4,5,6,7,8,9,10,11,12,13]

while n>0:
    l=input().split()
    if l[0]=="S":
        s.remove(int(l[1]))
    elif l[0]=="H":
        h.remove(int(l[1]))
    elif l[0]=="C":
        c.remove(int(l[1]))
    else:
        d.remove(int(l[1]))
    n=n-1

if not s==[]:
    for a in s:
        print("S "+str(a))
else:
    pass

if not h==[]:
    for b in h:
        print("H "+str(b))
else:
    pass

if not c==[]:
    for e in c:
        print("C "+str(e))
else:
    pass

if not d==[]:
    for f in d:
        print("D "+str(f))
else:
    pass