Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in PyPy3 (7.3.0) (judge verdict: Wrong Answer)

#F
N,A,B,C = map(int,input().split())
S =[]
for x in range(N):
    S.append(input())
ans =[]
f =True

for x in range(N):
    
    if A==0 and B==0 and C ==0:
        f =False
        break
    
    elif A+B+C ==1:
        if S[x] =="AB" and A==1:
            ans.append("B")
            A -=1
            B +=1
        elif S[x] =="AB" and B==1:
            ans.append("A")
            A +=1
            B -=1
        elif S[x] =="AC" and A==1:
            ans.append("C")
            A -=1
            C +=1
        elif S[x] =="AC" and C==1:
            ans.append("A")
            A +=1
            C -=1
        elif S[x] =="BC" and B==1:
            ans.append("C")
            B -=1
            C +=1
        elif S[x] =="BC" and C==1:
            ans.append("B")
            B +=1
            C -=1
        else:
            f =False
            break
    elif A +B+C >= 2:
        if A==0 or B ==0 or C==0:
            if S[x]=="AB" and A ==0 and B == 0:
                f =False
                break
            elif S[x]=="AC" and A ==0 and C == 0:
                f =False
                break
            elif S[x]=="BC" and C ==0 and B == 0:
                f =False
                break
        if S[x] =="AB" and B == 0:
                ans.append("B")
                A -=1
                B +=1
        elif S[x] =="AB" and A ==0:
                ans.append("A")
                A +=1
                B =1
        elif S[x] =="AC" and C ==0:
                ans.append("C")
                A -=1
                C +=1
        elif S[x] =="AC" and A ==0:
                ans.append("A")
                A +=1
                C -=1    
        elif S[x] =="BC" and C ==0:
                ans.append("C")
                B -=1
                C +=1
        elif S[x] =="BC" and B == 0 :
                ans.append("B")
                B +=1
                C -=1 

        elif A+B+C ==2 and x <N-1 and S[x]!=S[x+1]:
            if S[x+1] =="AC":
                ans.append("A")
                A +=1
                B -=1
            elif S[x+1] =="BC":
                ans.append("B")
                A -=1
                B +=1
            elif S[x+1] =="BC":
                ans.append("C")
                A -=1
                C +=1
            elif S[x+1] =="AB":
                ans.append("A")
                A +=1
                C -=1
            elif S[x+1] =="AC":
                ans.append("C")
                B -=1
                C +=1
            elif S[x+1] =="AB":
                ans.append("B")
                B +=1
                C -=1
                
        else:
            if S[x] =="AB":
                ans.append("A")
                A +=1
                B -=1
            elif S[x] =="AC":
                ans.append("A")
                A +=1
                C -=1    
            elif S[x] =="BC":
                ans.append("B")
                B +=1
                C -=1

            
    
if f ==True:
    print("Yes")
    for x in ans:
        print(x)
else:
    print("No")