Problem:
Score : 200 points

Problem Statement

For a string S consisting of the uppercase English letters P and D, let the doctoral and postdoctoral quotient of S be the total number of occurrences of D and PD in S as contiguous substrings. For example, if S = PPDDP, it contains two occurrences of D and one occurrence of PD as contiguous substrings, so the doctoral and postdoctoral quotient of S is 3.

We have a string T consisting of P, D, and ?.

Among the strings that can be obtained by replacing each ? in T with P or D, find one with the maximum possible doctoral and postdoctoral quotient.

Constraints

1 \leq |T| \leq 2 \times 10^5

T consists of P, D, and ?.

Input

Input is given from Standard Input in the following format:

T

Output

Print one string with the maximum possible doctoral and postdoctoral quotient among the strings that can be obtained by replacing each ? in T with P or D.
If there are multiple such strings, you may print any of them.

Sample Input 1

PD?D??P

Sample Output 1

PDPDPDP

This string contains three occurrences of D and three occurrences of PD as contiguous substrings, so its doctoral and postdoctoral quotient is 6, which is the maximum doctoral and postdoctoral quotient of a string obtained by replacing each ? in T with P or D.

Sample Input 2

P?P?

Sample Output 2

PDPD

Solution in Python (3.8.2) (judge verdict: Wrong Answer)

T = input()

tmp = []
for i in T:
    tmp.append(i)
    
import sys
    
if len(T) == 1:
    if T[0] == '?':
        print('D')
    else:
        print(T)
    sys.exit()

if tmp[0] == '?':
    if tmp[1] == 'P':
        tmp[0] = 'D'
    elif tmp[1] == 'D':
        tmp[0] = 'P'
    else:
        tmp[0] = 'P'
for i in range(1,len(tmp)-1):
    if tmp[i] == '?':
        if tmp[i-1] == 'D' and tmp[i+1] == 'D':
            tmp[i] = 'P'
        elif tmp[i-1] == 'P' and tmp[i+1] == 'P':
            tmp[i] = 'D'
        elif tmp[i-1] == 'D' and tmp[i+1] == 'P':
            tmp[i] = 'D'
        elif tmp[i-1] == 'P' and tmp[i+1] == 'D':
            tmp[i] = 'D'
        elif tmp[i-1] == 'P' and tmp[i+1] == '?':
            tmp[i] = 'D'
        elif tmp[i-1] == 'D' and tmp[i+1] == '?':
            tmp[i] = 'P'
if tmp[-1] == '?':
    if tmp[-2] == 'P':
        tmp[-1] = 'D'
    elif tmp[-2] == 'D':
        tmp[-1] = 'P'
        
print(''.join(tmp))