Problem:
Score : 100 points

Problem Statement

An uppercase or lowercase English letter \alpha will be given as input.
If \alpha is uppercase, print A; if it is lowercase, print a.

Constraints

\alpha is an uppercase (A - Z) or lowercase (a - z) English letter.

Input

Input is given from Standard Input in the following format:

α

Output

If \alpha is uppercase, print A; if it is lowercase, print a.

Sample Input 1

B

Sample Output 1

A

B is uppercase, so we should print A.

Sample Input 2

a

Sample Output 2

a

a is lowercase, so we should print a.

Solution in Python (3.8.2) (judge verdict: Runtime Error)

def freq(my_list):
    count = {} 
    for i in my_list: 
        count[i] = count.get(i, 0) + 1
    return count

n = int(input())
l = list(map(int, input().split()))
s,f = sum(l), freq(l)
for _ in range(int(input())):
    x, y = map(int, input().split())
    if x in f:
        v = f[x]
        if y in f:
            f[y]+=v
            f.pop(x)
        else:
            f[y]=f.pop(x)
        s += (y-x)*v
    print(s)