Problem:
Score : 300 points

Problem Statement

Given are an integer X and an integer sequence of length N: p_1, \ldots, p_N.

Among the integers not contained in the sequence p_1, \ldots, p_N (not necessarily positive), find the integer nearest to X, that is, find the integer whose absolute difference with X is the minimum. If there are multiple such integers, report the smallest such integer.

Constraints

1 \leq X \leq 100

0 \leq N \leq 100

1 \leq p_i \leq 100

p_1, \ldots, p_N are all distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X N
p_1 ... p_N

Output

Print the answer.

Sample Input 1

6 5
4 7 10 6 5

Sample Output 1

8

Among the integers not contained in the sequence 4, 7, 10, 6, 5, the one nearest to 6 is 8.

Sample Input 2

10 5
4 7 10 6 5

Sample Output 2

9

Among the integers not contained in the sequence 4, 7, 10, 6, 5, the ones nearest to 10 are 9 and 11. We should print the smaller one, 9.

Sample Input 3

100 0

Sample Output 3

100

When N = 0, the second line in the input will be empty. Also, as seen here, X itself can be the answer.

Solution in PyPy3 (7.3.0) (judge verdict: Accepted)

#!/usr/bin/env python
# -*- coding: utf-8 -*-

import sys
sys.setrecursionlimit(10**7)
from pprint import pprint as pp
from pprint import pformat as pf
# @pysnooper.snoop()
#import pysnooper # debug

import math
#from sortedcontainers import SortedList, SortedDict, SortedSet # no in atcoder
import bisect

def solve(x, s):
    d = 0
    while d < 200: #TODO
        v = x - d
        if v not in s:
            return v
        v = x + d
        if v not in s:
            return v
        d += 1
    raise RuntimeError


if __name__ == '__main__':
    x, n = list(map(int, input().split()))
    if n == 0:
        print(x)
    else:
        s = set(map(int, input().split()))
        ans = solve(x, s)
        print(ans)


    #print('\33[32m' + 'end' + '\033[0m') # debug