Problem:
Score : 400 points

Problem Statement

There is a knight - the chess piece - at the origin (0, 0) of a two-dimensional grid.

When the knight is at the square (i, j), it can be moved to either (i+1,j+2) or (i+2, j+1).

In how many ways can the knight reach the square (X, Y)?

Find the number of ways modulo 10^9 + 7.

Constraints

1 \leq X \leq 10^6

1 \leq Y \leq 10^6

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X Y

Output

Print the number of ways for the knight to reach (X, Y) from (0, 0), modulo 10^9 + 7.

Sample Input 1

3 3

Sample Output 1

2

There are two ways: (0,0) \to (1,2) \to (3,3) and (0,0) \to (2,1) \to (3,3).

Sample Input 2

2 2

Sample Output 2

0

The knight cannot reach (2,2).

Sample Input 3

999999 999999

Sample Output 3

151840682

Print the number of ways modulo 10^9 + 7.

Solution in PyPy3 (2.4.0) (judge verdict: Runtime Error)

# https://atcoder.jp/contests/abc145/tasks/abc145_d


X, Y = map(int, input().split())

if (2*Y- X) % 3 or (2*X- Y) % 3:
    print(0)
    exit()

x = (2*Y - X) // 3
y = (2*X - Y) // 3

if x <= 0 or y =< 0:
    print(0)
    exit()

n = x + y
r = x


mod = 10**9 + 7
f = 1
for i in range(1, n + 1):
    f = f*i % mod
fac = f
f = pow(f, mod-2, mod)
facinv = [f]
for i in range(n, 0, -1):
    f = f*i % mod
    facinv.append(f)
facinv.append(1)

print(fac * facinv[r] * facinv[n - r] % mod)