Problem:
Score : 400 points

Problem Statement

Akari has n kinds of flowers, one of each kind.

She is going to choose one or more of these flowers to make a bouquet.

However, she hates two numbers a and b, so the number of flowers in the bouquet cannot be a or b.

How many different bouquets are there that Akari can make?

Find the count modulo (10^9 + 7).

Here, two bouquets are considered different when there is a flower that is used in one of the bouquets but not in the other bouquet.

Constraints

All values in input are integers.

2 \leq n \leq 10^9

1 \leq a < b \leq \textrm{min}(n, 2 \times 10^5)

Input

Input is given from Standard Input in the following format:

n a b

Output

Print the number of bouquets that Akari can make, modulo (10^9 + 7). (If there are no such bouquets, print 0.)

Sample Input 1

4 1 3

Sample Output 1

7

In this case, Akari can choose 2 or 4 flowers to make the bouquet.

There are 6 ways to choose 2 out of the 4 flowers, and 1 way to choose 4, so there are a total of 7 different bouquets that Akari can make.

Sample Input 2

1000000000 141421 173205

Sample Output 2

34076506

Print the count modulo (10^9 + 7).

Solution in Python (3.4.3) (judge verdict: Accepted)

n, a, b = list(map(int, input().split()))

MOD = 10**9 + 7

# https://qiita.com/derodero24/items/91b6468e66923a87f39f


def cmb(n, r):
  if n - r < r:
    r = n - r
  if r == 0:
    return 1
  if r == 1:
    return n

  numerator = [n - r + k + 1 for k in range(r)]
  denominator = [k + 1 for k in range(r)]

  for p in range(2, r + 1):
    pivot = denominator[p - 1]
    if pivot > 1:
      offset = (n - r) % p
      for k in range(p - 1, r, p):
        numerator[k - offset] /= pivot
        denominator[k] /= pivot

  result = 1
  for k in range(r):
    if numerator[k] > 1:
      result *= int(numerator[k])
      result %= MOD

  return result


print((pow(2, n, MOD) - 1 - cmb(n, a) - cmb(n, b)) % MOD)