Problem:
Score : 300 points

Problem Statement

AtCoDeer the deer is going on a trip in a two-dimensional plane.
In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.

If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1).
Note that he cannot stay at his place.
Determine whether he can carry out his plan.

Constraints

1 ≤ N ≤ 10^5

0 ≤ x_i ≤ 10^5

0 ≤ y_i ≤ 10^5

1 ≤ t_i ≤ 10^5

t_i < t_{i+1} (1 ≤ i ≤ N-1)

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
t_1 x_1 y_1
t_2 x_2 y_2
:
t_N x_N y_N

Output

If AtCoDeer can carry out his plan, print Yes; if he cannot, print No.

Sample Input 1

2
3 1 2
6 1 1

Sample Output 1

Yes

For example, he can travel as follows: (0,0), (0,1), (1,1), (1,2), (1,1), (1,0), then (1,1).

Sample Input 2

1
2 100 100

Sample Output 2

No

It is impossible to be at (100,100) two seconds after being at (0,0).

Sample Input 3

2
5 1 1
100 1 1

Sample Output 3

No

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

import sys
from sys import stdin
n = int(stdin.readline().rstrip())
data = [stdin.readline().rstrip().split() for _ in range(n)]
data = [[int(i) for i in l] for l in data]
start = 0
for i, l in enumerate(data):
    if i == 0:
        if l[0]%2 == 0:
            if (l[1]+l[2])%2 == 0 and (l[1]+l[2]) <= l[0]-start:
                continue
            else:
                print('No')
                sys.exit()
        else:
            if (l[1]+l[2])%2 != 0 and (l[1]+l[2]) <= l[0]-start:
                continue
            else:
                print('No')
                sys.exit()
    else:
        if (l[0]-data[i-1][0])%2 == 0:
            if abs(l[1]+l[2]-data[i-1][1]-data[i-1][2])%2 == 0 and (l[1]+l[2]) <= l[0]-data[i-1][0]:
                continue
            else:
                print('No')
                sys.exit()
        else:
            if abs(l[1]+l[2]-data[i-1][1]-data[i-1][2])%2 != 0 and (l[1]+l[2]) <= l[0]-data[i-1][0]:
                continue
            else:
                print('No')
                sys.exit()
print('Yes')