Problem:
Score : 400 points

Problem Statement

You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

In the i-th operation, you replace every element whose value is B_{i} with C_{i}.

For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

All values in input are integers.

1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}

B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:

N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}

Output

Print Q integers S_{i} to Standard Output in the following format:

S_{1}
S_{2}
\vdots
S_{Q}

Note that S_{i} may not fit into a 32-bit integer.

Sample Input 1

4
1 2 3 4
3
1 2
3 4
2 4

Sample Output 1

11
12
16

Initially, the sequence A is 1,2,3,4.

After each operation, it becomes the following:

2, 2, 3, 4

2, 2, 4, 4

4, 4, 4, 4

Sample Input 2

4
1 1 1 1
3
1 2
2 1
3 5

Sample Output 2

8
4
4

Note that the sequence A may not contain an element whose value is B_{i}.

Sample Input 3

2
1 2
3
1 100
2 100
100 1000

Sample Output 3

102
200
2000

Solution in Python (3.8.2) (judge verdict: Time Limit Exceeded)

n=int(input())
a=list(map(int,input().split()))
q=int(input())
b=[0]*q
c=[0]*q
s=[0]*(q+1)
for i in range(q):
	b[i],c[i]=map(int,input().split())
f={}
for i in range(n):
	f.setdefault(a[i],[])
for i in range(n):
	f[a[i]].append(i)
for g,h in f.items():
	#print(len(h)*g)
	s[0]=s[0]+len(h)*g
#print(f)
for i in range(1,q+1):
	if b[i-1] in f:
		if c[i-1] in f:
			f[c[i-1]]=f[c[i-1]]+f[b[i-1]]
			s[i]=s[i-1]-len(f[b[i-1]])*b[i-1]
			#print(s[i])
			
			s[i]=s[i]+len(f[b[i-1]])*c[i-1]
			f.pop(b[i-1])
		else:
			f.setdefault(c[i-1],[])
			f[c[i-1]]=f[c[i-1]]+f[b[i-1]]
			s[i]=s[i-1]-len(f[b[i-1]])*b[i-1]
			#print(s[i])
			
			s[i]+=len(f[b[i-1]])*c[i-1]
			f.pop(b[i-1])
	#print(f)
	#for g,h in f.items():
		#print(len(h)*g)
		#s[i]=s[i]+len(h)*g
	else:
		s[i]=s[i-1]
	print(s[i])