Problem:
Score : 400 points

Problem Statement

We have N integers. The i-th integer is A_i.

Find \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).

What is \mbox{ XOR }?

The XOR of integers A and B, A \mbox{ XOR } B, is defined as follows:

When A \mbox{ XOR } B is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if either A or B, but not both, has 1 in the 2^k's place, and 0 otherwise.

For example, 3 \mbox{ XOR } 5 = 6. (In base two: 011 \mbox{ XOR } 101 = 110.)

Constraints

2 \leq N \leq 3 \times 10^5

0 \leq A_i < 2^{60}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the value \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).

Sample Input 1

3
1 2 3

Sample Output 1

6

We have (1\mbox{ XOR } 2)+(1\mbox{ XOR } 3)+(2\mbox{ XOR } 3)=3+2+1=6.

Sample Input 2

10
3 1 4 1 5 9 2 6 5 3

Sample Output 2

237

Sample Input 3

10
3 14 159 2653 58979 323846 2643383 27950288 419716939 9375105820

Sample Output 3

103715602

Print the sum modulo (10^9+7).

Solution in Python (3.4.3) (judge verdict: Time Limit Exceeded)

def main():
    import sys
    input = sys.stdin.readline
    n = int(input())
    a = list(map(int, input().split()))
    a.reverse()
    mod = 7 + 10**9
    leng = len(format(max(a), 'b'))
    bit_acc = [0 for i in range(leng)]
    for i in range(n):
        # 先頭から二進数を0埋めした
        bit_data = format(a[i], 'b').zfill(leng)
        for j in range(leng):
            if bit_data[j] == '1':
                bit_acc[j] += 1
    ans = 0
    for i in range(n):
        bit_data = format(a[i], 'b').zfill(leng)
        for j in range(leng):
            if bit_data[j] == '1':
                ans += (n - bit_acc[j]) * (2 ** (leng - j - 1))
            else:
                ans += bit_acc[j] * (2 ** (leng - j - 1))
            ans %= mod
    print((ans * 500000004) % mod)


if __name__ == "__main__":
    main()