Problem:
Score : 300 points

Problem Statement

You are given an integer N.
Find the number of the positive divisors of N!, modulo 10^9+7.

Constraints

1≤N≤10^3

Input

The input is given from Standard Input in the following format:

N

Output

Print the number of the positive divisors of N!, modulo 10^9+7.

Sample Input 1

3

Sample Output 1

4

There are four divisors of 3! =6: 1, 2, 3 and 6. Thus, the output should be 4.

Sample Input 2

6

Sample Output 2

30

Sample Input 3

1000

Sample Output 3

972926972

Solution in Python (3.4.3) (judge verdict: Accepted)

# C - Factors of Factorial

import collections

N = int(input())

# n以下の全ての素数のセットを返す関数
def prime_set(n):
    primes = set(range(2, n+1))
    for i in range(2, int(n**0.5) + 1):
        primes.difference_update(range(i*2, n+1, i))
    return primes

# nを素因数分解して素因数の全リストを返す関数
def prime_factors(n):
    f = []
    for i in prime_set(int(n**0.5) + 1):
        while n % i == 0:
            f.append(i)
            n //= i
    if n > 1:
        f.append(n)
    return f

N_factorial_prime_factors = []
for i in range(1, N+1):
    N_factorial_prime_factors.extend(prime_factors(i))
    
N_factorial_prime_factors = collections.Counter(N_factorial_prime_factors)
ans = 1
for x in N_factorial_prime_factors.values():
    ans *= x + 1
    ans %= 10**9 + 7
    
print(ans)