Problem:
Score : 200 points

Problem Statement

Takahashi is standing on a two-dimensional plane, facing north. Find the minimum positive integer K such that Takahashi will be at the starting position again after he does the following action K times:

Go one meter in the direction he is facing. Then, turn X degrees counter-clockwise.

Constraints

1 \leq X \leq 179

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the number of times Takahashi will do the action before he is at the starting position again.

Sample Input 1

90

Sample Output 1

4

Takahashi's path is a square.

Sample Input 2

1

Sample Output 2

360

Solution in Python (3.8.2) (judge verdict: Wrong Answer)

import math
X = int(input())
if 90 >= X:
  if 360%X == 0:
    print(int(360/X))
  else:
    print(math.floor(360/X))
elif 90 < X <= 179:
  if 360%(180-X) == 0:
    print(int(360/(180-X)))
  else:
    print(math.floor(360/(180-X)))