Problem:
Score : 700 points

Problem Statement

Snuke has a permutation (P_0,P_1,\cdots,P_{N-1}) of (0,1,\cdots,N-1).

Now, he will perform the following operation exactly once:

Choose K consecutive elements in P and sort them in ascending order.

Find the number of permutations that can be produced as P after the operation.

Constraints

2 \leq N \leq 200000

2 \leq K \leq N

0 \leq P_i \leq N-1

P_0,P_1,\cdots,P_{N-1} are all different.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
P_0 P_1 \cdots P_{N-1}

Output

Print the number of permutations that can be produced as P after the operation.

Sample Input 1

5 3
0 2 1 4 3

Sample Output 1

2

Two permutations can be produced as P after the operation: (0,1,2,4,3) and (0,2,1,3,4).

Sample Input 2

4 4
0 1 2 3

Sample Output 2

1

Sample Input 3

10 4
2 0 1 3 7 5 4 6 8 9

Sample Output 3

6

Solution in Python (3.4.3) (judge verdict: Time Limit Exceeded)

n,k = map(int,input().split())
P = [-1] + list(map(int,input().split())) + [10**6]
Q = [''.join(map(str,P))]
for i in range(1,n-k+1):
    if (sorted(P[i-1:i+k-1])[1:k] != sorted(P[i:i+k])[0:k-1] or i==1 or i == n-k+1)and P[i:i+k] != sorted(P[i:i+k]):
        q = P[:i] + sorted(P[i:i+k]) + P[i+k:]
        Q += [''.join(map(str,q))]
print(len(Q))