Problem:
Score : 400 points

Problem Statement

Akari has n kinds of flowers, one of each kind.

She is going to choose one or more of these flowers to make a bouquet.

However, she hates two numbers a and b, so the number of flowers in the bouquet cannot be a or b.

How many different bouquets are there that Akari can make?

Find the count modulo (10^9 + 7).

Here, two bouquets are considered different when there is a flower that is used in one of the bouquets but not in the other bouquet.

Constraints

All values in input are integers.

2 \leq n \leq 10^9

1 \leq a < b \leq \textrm{min}(n, 2 \times 10^5)

Input

Input is given from Standard Input in the following format:

n a b

Output

Print the number of bouquets that Akari can make, modulo (10^9 + 7). (If there are no such bouquets, print 0.)

Sample Input 1

4 1 3

Sample Output 1

7

In this case, Akari can choose 2 or 4 flowers to make the bouquet.

There are 6 ways to choose 2 out of the 4 flowers, and 1 way to choose 4, so there are a total of 7 different bouquets that Akari can make.

Sample Input 2

1000000000 141421 173205

Sample Output 2

34076506

Print the count modulo (10^9 + 7).

Solution in Python (3.8.2) (judge verdict: Accepted)

mod = 1000000007

def mod_cmb(n: int, k: int, p: int) -> int:
    if n < 0 or k < 0 or n < k: return 0
    if n == 0 or k == 0: return 1
    if (k > n - k):
        return mod_cmb(n, n - k, p)
    c = d = 1
    for i in range(k):
        c *= (n - i)
        d *= (k - i)
        c %= p
        d %= p
    return c * pow(d, -1, p) % p

def main():
    n, a, b = map(int, input().split())

    ans = pow(2, n, mod) - 1

    tmp_a = mod_cmb(n , a, mod)
    tmp_b = mod_cmb(n , b, mod)

    print((ans-tmp_a-tmp_b)%mod)

if __name__ == '__main__':
    main()