Problem:
Score : 200 points

Problem Statement

Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Constraints

1 \leq N \leq 10^5

Input

Input is given from Standard Input in the following format:

N

Output

Print the number of positive integers less than or equal to N that have an odd number of digits.

Sample Input 1

11

Sample Output 1

9

Among the positive integers less than or equal to 11, nine integers have an odd number of digits: 1, 2, \ldots, 9.

Sample Input 2

136

Sample Output 2

46

In addition to 1, 2, \ldots, 9, another 37 integers also have an odd number of digits: 100, 101, \ldots, 136.

Sample Input 3

100000

Sample Output 3

90909

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

N = int(input())
i = len(str(N))
r = 0

if i==1:
  r = N
elif i==2:
  r = 9
elif i==3:
  r = 9 + (N-100+1)
elif i==4:
  r = 9 + (999-100+1)
elif i==5:
  r = 9 + (999-100+1) + (N - 10000 + 1)
elif i==6:
  r = 9 + (999-100+1) + (9999 - 10000 + 1)
print(r)