Problem:
Score : 400 points

Problem Statement

You are given a sequence A_1, A_2, ..., A_N and an integer K.

Print the maximum possible length of a sequence B that satisfies the following conditions:

B is a (not necessarily continuous) subsequence of A.

For each pair of adjacents elements of B, the absolute difference of the elements is at most K.

Constraints

1 \leq N \leq 300,000

0 \leq A_i \leq 300,000

0 \leq K \leq 300,000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
A_1
A_2
:
A_N

Output

Print the answer.

Sample Input 1

10 3
1
5
4
3
8
6
9
7
2
4

Sample Output 1

7

For example, B = (1, 4, 3, 6, 9, 7, 4) satisfies the conditions.

It is a subsequence of A = (1, 5, 4, 3, 8, 6, 9, 7, 2, 4).

All of the absolute differences between two adjacent elements (|1-4|, |4-3|, |3-6|, |6-9|, |9-7|, |7-4|) are at most K = 3.

Solution in PyPy3 (7.3.0) (judge verdict: Time Limit Exceeded)

import sys
import bisect
from functools import lru_cache
from collections import defaultdict
inf = float('inf')
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
sys.setrecursionlimit(10**6)
def input(): return sys.stdin.readline().rstrip()
def read():
  return int(readline())
def reads():
  return map(int, readline().split())

N,K=reads()
start,end=0,0
former=0
import math
maxval=0
ls=[]
sortls=[]
maxls=[1 for i in range(N)]
selectls=[0 for i in range(300000)]
for i in range(N):
    a=read()
    a-=1
    sls=selectls[a]
    maxls[i]=sls+1
    mi=max(0,a-K)
    ma=min(N-1,a+K)
    for l in range(mi,ma+1):
        selectls[l]=max(selectls[l],maxls[i])
print(max(maxls))