Problem:
Score : 600 points

Problem Statement

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice.
Each of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

1 \leq N \leq 10^5

0 \leq A,B,C \leq 10^9

N, A, B, C are integers.

s_i is AB, AC, or BC.

Input

Input is given from Standard Input in the following format:

N A B C
s_1
s_2
:
s_N

Output

If it is possible to make N choices under the condition, print Yes; otherwise, print No.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.

Sample Input 1

2 1 3 0
AB
AC

Sample Output 1

Yes
A
C

You can successfully make two choices, as follows:

In the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.

In the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.

Sample Input 2

3 1 0 0
AB
BC
AB

Sample Output 2

No

Sample Input 3

1 0 9 0
AC

Sample Output 3

No

Sample Input 4

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB

Sample Output 4

Yes
C
B
B
C
C
B
A
A

Solution in PyPy3 (7.3.0) (judge verdict: Runtime Error)

def f(A, i, j, k, next,res):
    if A[i] == A[j] == 0:
        print("No")
        exit()
    elif A[i] == A[j] == 1 and A[k] == 0:
        if i in next:
            A[i] += 1
            A[j] -= 1
            return "ABC"[i]
        else:
            A[i] -= 1
            A[j] += 1
            return "ABC"[j]
    else:
        A[i] += 1
        A[j] -= 1
        return "ABC"[i]
    

def main():
    N, A, B, C = [int(_n) for _n in input().split()]
    S = []
    for i in range(N):
        s = input()
        S.append(s)
    if [A,B,C].count(0) == 3:
        print("No")
        return
    res = ""
    arr = [A,B,C]
    S.append("")
    for i,s in enumerate(S):
        if s == "AB":
            if arr[0] > arr[1]:
                res += f(arr, 1, 0, 2, S[i+1],res)
            else:
                res += f(arr,0,1,2,S[i+1],res)
        elif s == "BC":
            if arr[1] > arr[2]:
                res += f(arr, 2, 1, 0, S[i+1],res)
            else:
                res += f(arr,1,2,0,S[i+1],res)
        elif s == "AC":
            if arr[0] > arr[2]:
                res += f(arr, 0, 2, 1, S[i+1],res)
            else:
                res += f(arr,2,0,1,S[i+1],res)
    for s in res:
        print(s)
main()