Problem:
Score : 100 points

Problem Statement

Compute A \times B.

Constraints

1 \leq A \leq 100

1 \leq B \leq 100

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B

Output

Print the value A \times B as an integer.

Sample Input 1

2 5

Sample Output 1

10

We have 2 \times 5 = 10.

Sample Input 2

100 100

Sample Output 2

10000

Solution in Python (3.8.2) (judge verdict: Runtime Error)

#include"bits/stdc++.h"
#include <ext/pb_ds/assoc_container.hpp> 
using namespace __gnu_pbds; 
using namespace std;

#define double long double
#define int long long
#define pb push_back 
#define eb emplace_back
#define Z(c) (int)(c).size()
#define L(c) c[Z(c)-1]
#define F first
#define S second
#define nl "\n"
#define mii map<int,int>
#define sp fixed<<setprecision 
#define all(c) (c).begin(),(c).end()
#define rall(c) (c).rbegin(),(c).rend()
#define rep(i,iv,n) for(int (i)=(iv);(i)<(n);++(i))
#define FO fflush(stdout) 
#define D1(x) cerr <<"At line "<<__LINE__<<" "<<#x<<"="<<x<<nl
#define D2(x,y) cerr <<"At line "<<__LINE__<<" "<<#x<<"="<<x<<" "<<#y<<"="<<y<<nl
#define D3(x,y,z) cerr <<"At line "<<__LINE__<<" "<<#x<<"="<<x<<" "<<#y<<"="<<y<<" "<<#z<<"="<<z<<nl
#define tr(it,ct) for(auto &(it) : (ct))
#define pi acos(-1)
#define prt(ct) for(auto &(it) : (ct)) cerr<<it<<" "; cerr<<nl
#define prtp(ct) for(auto &(it) : (ct)) cerr<<it.F<<" "<<it.S<<nl; cerr<<nl

typedef vector< int > vi;
typedef vector< vi > vvi;
typedef pair< int,int > pii;
typedef pair<pii,pii> ppp;
typedef vector< pii > vp;
typedef tree<pii, null_type, less<pii>, rb_tree_tag, 
             tree_order_statistics_node_update> baap;

template<typename T> 
void swap(T &a,T &b)
{ auto tm=a; a=b; b=tm; }

template<typename T> 
void mina(T& a, T b) { 
    a = min(a, b); 
}
template<typename T>
void maxa(T& a, T b) { 
    a = max(a, b); 
}

  const int mod=1000000009;
  const int mod2=998244353;
  const int INF=1e18;
  const int N=2e5+25;  
  const int M=1e5+1;           


 void doit()
 { 
   int a,b; cin>>a>>b; cout<<a*b;
 }

signed main()
{ 
   ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);

   int tc=1;                         
   // cin>>tc;

  rep(i,1,tc+1)
  { // cout<<"Case #"<<i<<": ";
  
   doit();
   if(i<tc)
   cout<<nl;
  }
  
 return 0; 
}