Problem:
Score : 300 points

Problem Statement

Given are an integer X and an integer sequence of length N: p_1, \ldots, p_N.

Among the integers not contained in the sequence p_1, \ldots, p_N (not necessarily positive), find the integer nearest to X, that is, find the integer whose absolute difference with X is the minimum. If there are multiple such integers, report the smallest such integer.

Constraints

1 \leq X \leq 100

0 \leq N \leq 100

1 \leq p_i \leq 100

p_1, \ldots, p_N are all distinct.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X N
p_1 ... p_N

Output

Print the answer.

Sample Input 1

6 5
4 7 10 6 5

Sample Output 1

8

Among the integers not contained in the sequence 4, 7, 10, 6, 5, the one nearest to 6 is 8.

Sample Input 2

10 5
4 7 10 6 5

Sample Output 2

9

Among the integers not contained in the sequence 4, 7, 10, 6, 5, the ones nearest to 10 are 9 and 11. We should print the smaller one, 9.

Sample Input 3

100 0

Sample Output 3

100

When N = 0, the second line in the input will be empty. Also, as seen here, X itself can be the answer.

Solution in Python (3.8.2) (judge verdict: Runtime Error)

import math
input_a= input().split(" ")
X=int(input_a[0])
N=int(input_a[1])

if N!=0:
  array= input().split(" ")
else:
  array=[0,0]

num=X
num2=-100
for i in range(101-X):

  
  if str(num) not in array:
    dis=abs(X-num)
    num2=X-dis
    num1=num
    if str(num2) not in array:
    	numa=min([num,num2])
    else:
      numa=num1
    break
  num=num+1
    

num=X
i=0
for i in range(X+3):
  
  if str(num) not in array:
    
    dis2=abs(X-num)
    num3=X+dis2
    #print(num,dis2,num3)
    if str(num3) not in array:
    	numb=min([num,num3])
    else:
      numb=num
      break
  num=num-1
#print(numa,numb,dis,dis2)
if dis<dis2:
  print(numa)
elif dis==dis2:
  print(numb)
else:
  print(numb)