Problem:
Score : 100 points

Problem Statement

A Hitachi string is a concatenation of one or more copies of the string hi.

For example, hi and hihi are Hitachi strings, while ha and hii are not.

Given a string S, determine whether S is a Hitachi string.

Constraints

The length of S is between 1 and 10 (inclusive).

S is a string consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

If S is a Hitachi string, print Yes; otherwise, print No.

Sample Input 1

hihi

Sample Output 1

Yes

hihi is the concatenation of two copies of hi, so it is a Hitachi string.

Sample Input 2

hi

Sample Output 2

Yes

Sample Input 3

ha

Sample Output 3

No

Solution in PyPy3 (2.4.0) (judge verdict: Runtime Error)

A,B,m = map(int,input().split())
a = list(map(int,input().split()))
b = list(map(int,input().split()))
li2=[input() for i in range(m)]
c = []
for i in range(m):
    c.append( [int(x.strip()) for x in li2[i].split()])

ans = 10**6

for i in range(len(a)):
    for j in range(len(b)):
        keep = a[i]+b[j]
        coopon = 0
        for k in range(m):
            if c[k][0]-1 == i and c[k][1]-1 == j and coopon<c[k][2]:

                coopon = c[k][2]

        keep -= coopon

        if keep < ans:
            ans = keep

print(ans)