Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in Python (3.8.2) (judge verdict: Time Limit Exceeded)

s=list(input())
t=list(input())
n=len(s)
def get_count_list(s):
    alphabets="abcdefghijklmnopqrstuvwxyz"
    ans={}
    for alphabet in alphabets:
        ans[alphabet]=[]
    for i in range(n):
        ans[s[i]].append(i)
    return ans


def get_index2alpha(s):
    ans={}
    for i in range(n):
        ans[i]=s[i]
    return ans

s_count=get_count_list(s)
t_count=get_count_list(t)
s_index=get_index2alpha(s)
t_index=get_index2alpha(t)

ans=0
for i in range(len(s)):
    if not s_count[s_index[i]]==t_count[t_index[i]]:
        ans+=1

if ans==0:
    print("Yes")
else:
    print("No")