Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Python (3.8.2) (judge verdict: Wrong Answer)

import math

def countDividers(n):
    divisors = []
    for i in range(1, int(math.sqrt(n))):
        if n % i == 0:
            divisors.append(i)
            divisors.append(int(n/i))
    return len(divisors)

if __name__ == '__main__':
    n = int(input())
    count = 0
    for i in range(1,n+1):
        if i %2 ==1 and countDividers(i) == 8:
            count += 1
            #print(i)
    print(count)