Problem:
Score : 300 points

Problem Statement

Let f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:

1 \leq x,y,z

x^2 + y^2 + z^2 + xy + yz + zx = n

Given an integer N, find each of f(1),f(2),f(3),\ldots,f(N).

Constraints

All values in input are integers.

1 \leq N \leq 10^4

Input

Input is given from Standard Input in the following format:

N

Output

Print N lines. The i-th line should contain the value f(i).

Sample Input 1

20

Sample Output 1

0
0
0
0
0
1
0
0
0
0
3
0
0
0
0
0
3
3
0
0

For n=6, only (1,1,1) satisfies both of the conditions. Thus, f(6) = 1.

For n=11, three triples, (1,1,2), (1,2,1), and (2,1,1), satisfy both of the conditions. Thus, f(6) = 3.

For n=17, three triples, (1,2,2), (2,1,2), and (2,2,1), satisfy both of the conditions. Thus, f(17) = 3.

For n=18, three triples, (1,1,3), (1,3,1), and (3,1,1), satisfy both of the conditions. Thus, f(18) = 3.

Solution in Python (3.8.2) (judge verdict: Wrong Answer)

def count(num, x, y, z):
  temp = x*x + y*y + z*z + x*y + y*z + z*x
        
  if temp == num:
    if x==y and x==z:
      return 1
    else:
      return 3

  return 0
  
N=int(input())
number=0
for i in range(1,N+1):
  number += count(i, 1, 1, 1)
  number += count(i, 2, 1, 1)
  number += count(i, 2, 2, 1)
  number += count(i, 2, 2, 2)
  number += count(i, 3, 1, 1)
  number += count(i, 3, 2, 1)
  number += count(i, 3, 2, 2)
  number += count(i, 3, 3, 2)
  number += count(i, 3, 3, 3)
  number += count(i, 4, 1, 1)
  number += count(i, 4, 2, 1)
  number += count(i, 4, 2, 2)
  number += count(i, 4, 3, 1)
  number += count(i, 4, 3, 2)
  number += count(i, 4, 3, 3)
  number += count(i, 4, 4, 1)
  number += count(i, 4, 4, 2)
  number += count(i, 4, 4, 3)
  print(number)
  number=0