Problem:
﻿Score: 300 points

Problem Statement

Mr. Infinity has a string S consisting of digits from 1 to 9. Each time the date changes, this string changes as follows:

Each occurrence of 2 in S is replaced with 22. Similarly, each 3 becomes 333, 4 becomes 4444, 5 becomes 55555, 6 becomes 666666, 7 becomes 7777777, 8 becomes 88888888 and 9 becomes 999999999. 1 remains as 1.

For example, if S is 1324, it becomes 1333224444 the next day, and it becomes 133333333322224444444444444444 the day after next.
You are interested in what the string looks like after 5 \times 10^{15} days. What is the K-th character from the left in the string after 5 \times 10^{15} days?

Constraints

S is a string of length between 1 and 100 (inclusive).

K is an integer between 1 and 10^{18} (inclusive).

The length of the string after 5 \times 10^{15} days is at least K.

Input

Input is given from Standard Input in the following format:

S
K

Output

Print the K-th character from the left in Mr. Infinity's string after 5 \times 10^{15} days.

Sample Input 1

1214
4

Sample Output 1

2

The string S changes as follows:

Now: 1214

After one day: 12214444

After two days: 1222214444444444444444

After three days: 12222222214444444444444444444444444444444444444444444444444444444444444444

The first five characters in the string after 5 \times 10^{15} days is 12222. As K=4, we should print the fourth character, 2.

Sample Input 2

3
157

Sample Output 2

3

The initial string is 3. The string after 5 \times 10^{15} days consists only of 3.

Sample Input 3

299792458
9460730472580800

Sample Output 3

2

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

S = input()
K = input()
flag = 0
for i in range(len(S)):
    if S[i] =="1":
        continue
    elif S[i] =="2":
        print("2")
        flag = 1
    elif S[i] =="3":
        print("3")
        flag = 1
    elif S[i] =="4":
        print("4")
        flag = 1
    elif S[i] =="5":
        print("5")
        flag = 1
    elif S[i] =="6":
        print("6")
        flag = 1
    elif S[i] =="7":
        print("7")
        flag = 1
    elif S[i] =="8":
        print("8")
        flag = 1
    elif S[i] =="9":
        print("9")
        flag = 1

    break
if flag == 0:
    print("1")