Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in PyPy3 (2.4.0) (judge verdict: Accepted)

n = int(input())
dp = [1]*(n + 1)
ans = 0
# エラストテネスの箒
for i in range(2, n + 1):
    div = 1
    while i * div <= n:
        dp[i * div] += 1
        div += 1
# dp[1]から１個飛ばしで表示
print(dp[1::2].count(8))