Problem:
Score : 600 points

Problem Statement

Snuke has a blackboard and a set S consisting of N integers.
The i-th element in S is S_i.

He wrote an integer X on the blackboard, then performed the following operation N times:

Choose one element from S and remove it.

Let x be the number written on the blackboard now, and y be the integer removed from S. Replace the number on the blackboard with x \bmod {y}.

There are N! possible orders in which the elements are removed from S.
For each of them, find the number that would be written on the blackboard after the N operations, and compute the sum of all those N! numbers modulo 10^{9}+7.

Constraints

All values in input are integers.

1 \leq N \leq 200

1 \leq S_i, X \leq 10^{5}

S_i are pairwise distinct.

Input

Input is given from Standard Input in the following format:

N X
S_1 S_2 \ldots S_{N}

Output

Print the answer.

Sample Input 1

2 19
3 7

Sample Output 1

3

There are two possible orders in which we remove the numbers from S.

If we remove 3 and 7 in this order, the number on the blackboard changes as follows: 19 \rightarrow 1 \rightarrow 1.

If we remove 7 and 3 in this order, the number on the blackboard changes as follows: 19 \rightarrow 5 \rightarrow 2.

The output should be the sum of these: 3.

Sample Input 2

5 82
22 11 6 5 13

Sample Output 2

288

Sample Input 3

10 100000
50000 50001 50002 50003 50004 50005 50006 50007 50008 50009

Sample Output 3

279669259

Be sure to compute the sum modulo 10^{9}+7.

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

import bisect

N, X = map(int, input().split())
S = [int(s) for s in input().split()]
S.sort()
NN = 10 ** 9 + 7

fact = [1]
for i in range(1, N+1):
    fact.append((fact[i-1] * i) % NN)

def f(n, s):
    if len(s) == 0:
        return 0
    if len(s) == 1:
        result = (n % s[0]) % NN
    elif n < s[0]:
        result = (n * fact[len(s)]) % NN
    elif n >= s[-1]:
        result = sum([f(n % s[i], s[:i] + s[i+1:]) for i in range(len(s))]) % NN
    else:
        ib = bisect.bisect_right(s, n)
        size_r = len(s[ib:])
        s_l = s[:ib]
        result = (fact[size_r] * f(n, s_l)) % NN
    return result

print(f(X, S))