Problem:
Score : 600 points

Problem Statement

Given are two strings s and t consisting of lowercase English letters. Determine if the number of non-negative integers i satisfying the following condition is finite, and find the maximum value of such i if the number is finite.

There exists a non-negative integer j such that the concatenation of i copies of t is a substring of the concatenation of j copies of s.

Notes

A string a is a substring of another string b if and only if there exists an integer x (0 \leq x \leq |b| - |a|) such that, for any y (1 \leq y \leq |a|), a_y = b_{x+y} holds.

We assume that the concatenation of zero copies of any string is the empty string. From the definition above, the empty string is a substring of any string. Thus, for any two strings s and t, i = 0 satisfies the condition in the problem statement.

Constraints

1 \leq |s| \leq 5 \times 10^5

1 \leq |t| \leq 5 \times 10^5

s and t consist of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s
t

Output

If the number of non-negative integers i satisfying the following condition is finite, print the maximum value of such i; if the number is infinite, print -1.

Sample Input 1

abcabab
ab

Sample Output 1

3

The concatenation of three copies of t, ababab, is a substring of the concatenation of two copies of s, abcabababcabab, so i = 3 satisfies the condition.

On the other hand, the concatenation of four copies of t, abababab, is not a substring of the concatenation of any number of copies of s, so i = 4 does not satisfy the condition.

Similarly, any integer greater than 4 does not satisfy the condition, either. Thus, the number of non-negative integers i satisfying the condition is finite, and the maximum value of such i is 3.

Sample Input 2

aa
aaaaaaa

Sample Output 2

-1

For any non-negative integer i, the concatenation of i copies of t is a substring of the concatenation of 4i copies of s. Thus, there are infinitely many non-negative integers i that satisfy the condition.

Sample Input 3

aba
baaab

Sample Output 3

0

As stated in Notes, i = 0 always satisfies the condition.

Solution in PyPy3 (2.4.0) (judge verdict: Wrong Answer)

def Z(S):
    res = [0]*len(S)
    res[0] = len(S)
    i = 1
    j = 0
    while i < len(S):
        while i+j < len(S) and S[j] == S[i+j]:
            j += 1
        res[i] = j
        if j == 0:
            i += 1
            continue
        k = 1
        while i+k < len(S) and k+res[k] < j:
            res[i+k] = res[k]
            k += 1
        i += k
        j -= k
    return res

from collections import defaultdict
class UnionFind:
    def __init__(self, num):
        self.table = [-1 for _ in range(num)]
        self.sz = defaultdict(lambda:1)

    def find(self, x):
        if self.table[x] < 0:
            return x
        else:
            self.table[x] = self.find(self.table[x])
            return self.table[x]

    def union(self, x, y):
        s1 = self.find(x)
        s2 = self.find(y)

        if s1 != s2:
            size = self.sz[s1]+self.sz[s2]
            if self.table[s1] <= self.table[s2]:
                self.table[s1] += self.table[s2]
                self.table[s2] = s1
            else:
                self.table[s2] += self.table[s1]
                self.table[s1] = s2
            s = self.find(x)
            self.sz[s] = size
            return True
        return False

    def size(self, x):
        s = self.find(x)
        return self.sz[s]

s = input()
t = input()

s = s*(len(t)//len(s)+2)
s = s+s

z = Z(t+'*'+s)
z = z[len(t)+1:]
u = UnionFind(len(z)+len(s))
for i in range(len(z)-len(t)):
    if z[i]==len(t) and z[i+len(t)]==len(t):
        u.union(i,i+len(t))

ans = 0
for i in range(len(z)):
    ans = max(u.sz[i],ans)

if ans >= 2:
    z = Z(t+'*'+s+s[:len(t)])
    z = z[len(t)+1:]
    for i in range(len(s)-len(t),len(z)-len(t)):
        if z[i]==len(t) and z[i+len(t)]==len(t):
            u.union(i,i+len(t))

    for i in range(len(z)):
        if u.sz[i] > ans:
            ans = -1

if max(z) != len(t):
    ans = 0

print(ans)