Problem:
Score : 500 points

Problem Statement

There are N blocks arranged in a row. Let us paint these blocks.

We will consider two ways to paint the blocks different if and only if there is a block painted in different colors in those two ways.

Find the number of ways to paint the blocks under the following conditions:

For each block, use one of the M colors, Color 1 through Color M, to paint it. It is not mandatory to use all the colors.

There may be at most K pairs of adjacent blocks that are painted in the same color.

Since the count may be enormous, print it modulo 998244353.

Constraints

All values in input are integers.

1 \leq N, M \leq 2 \times 10^5

0 \leq K \leq N - 1

Input

Input is given from Standard Input in the following format:

N M K

Output

Print the answer.

Sample Input 1

3 2 1

Sample Output 1

6

The following ways to paint the blocks satisfy the conditions: 112, 121, 122, 211, 212, and 221. Here, digits represent the colors of the blocks.

Sample Input 2

100 100 0

Sample Output 2

73074801

Sample Input 3

60522 114575 7559

Sample Output 3

479519525

Solution in Python (3.8.2) (judge verdict: Wrong Answer)

#factorial
MOD = 998244353 
N = 1000000
modinv_t = [0, 1]
modfact_t = [1, 1]
modfactinv_t = [1, 1]
for i in range(2,N+1):
  modfact_t.append(modfact_t[-1] * i % MOD)
  modinv_t.append(modinv_t[MOD%i] * (MOD-(MOD//i)) % MOD)
  modfactinv_t.append(modfactinv_t[-1] * modinv_t[-1] % MOD)
# permutation
def nPr(n, r):
  return  modfact_t[n] * modfactinv_t[n-r] % MOD
# combination
def nCr(n, r):
  return  modfact_t[n] * modfactinv_t[n-r] * modfactinv_t[r] % MOD
#
def nHr(n, r):
  return  nCr(n+r-1,r)
#

N, M, K = map(int, input().split()) 

t = M*pow(M-1,N-1,MOD)
for i in range(1,K+1):
  t += M*pow(M-1,N-1-i,MOD)*nCr((N-1),i)
  t %= MOD
#
print(t)