Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Python (3.8.2) (judge verdict: Accepted)

n = int(input())
have_8_divisors = 0

def count_up_divisor(check_num):
    cnt = 0
    for i in range(1, check_num + 1):
        # 1からcheck_numを順に探索して、nの約数かどうか判断して、約数の時はカウント
        if check_num % i == 0:
            cnt += 1
    return cnt


for i in range(1, n + 1):
    # 偶数の時はスキップ
    if i % 2 == 0:
        continue

    result = count_up_divisor(i) == 8
    if result:
        have_8_divisors += 1

print(have_8_divisors)