Problem:
Range Minimum Query (RMQ)

Write a program which manipulates a sequence A = {a0, a1, . . . , an-1} with the following operations:

find(s, t): report the minimum element in as, as+1, . . . ,at.

update(i, x): change ai to x.

Note that the initial values of ai (i = 0, 1, . . . , n−1) are 231-1.

Input

n q
com0 x0 y0
com1 x1 y1
...
comq−1 xq−1 yq−1

In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, q queries are given where com represents the type of queries. '0' denotes update(xi, yi) and '1' denotes find(xi, yi).

Output

For each find operation, print the minimum element.

Constraints

1 ≤ n ≤ 100000

1 ≤ q ≤ 100000

If comi is 0, then 0 ≤ xi < n, 0 ≤ yi < 231-1.

If comi is 1, then 0 ≤ xi < n, 0 ≤ yi < n.

Sample Input 1

3 5
0 0 1
0 1 2
0 2 3
1 0 2
1 1 2

Sample Output 1

1
2

Sample Input 2

1 3
1 0 0
0 0 5
1 0 0

Sample Output 2

2147483647
5

Solution in Python3 (judge verdict: Wrong Answer)

import time

N, Q = map(int, input().split())
SegTree = [0 for i in range(4*N)]

def modify(i, left, right, value, pos=-1):
    global SegTree
    if left==right:
        if pos != -1:
            SegTree[i] = value
        else:
            SegTree[i] = 2147483647
        return

    mid = int((left+right)/2)
    if pos==-1 or pos<=mid:
        modify(i*2, left, mid, value, pos)
    if pos==-1 or pos>mid:
        modify(i*2+1, mid+1, right, value, pos)
    
    SegTree[i] = min(SegTree[i*2], SegTree[i*2+1])

def query_min(i, L, R, left, right):
    if right < L or R < left:
        return 2147364748
    if left<=L and R<=right:
        return SegTree[i]
    mid = int((L+R)/2)
    return min(query_min(2*i, L, mid, left, right),
               query_min(2*i+1, mid+1, R, left, right))

modify(i=1, left=0, right=N-1, value=0, pos=-1) #init

for querys in range(Q):
    t, a, b = map(int, input().split())
    if t == 0:
        modify(i=1, left=0, right=N-1, pos=a, value=b)
    else:
        print( query_min(i=1, L=0, R=N-1, left=a, right=b) )