Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in Python (3.4.3) (judge verdict: Runtime Error)

#include <bits/stdc++.h>
using namespace std;

#define REP(i, x) for (int i = 0, i##_len = (int)(x); i < i##_len; i++)
#define REP1(i, x) for (int i = 1, i##_len = (int)(x); i <= i##_len; i++)
#define RREP(i, x) for (int i = ((int)(x)-1); i >= 0; i--)
#define RREP1(i, x) for (int i = ((int)(x)); i > 0; i--)
#define ALL(v) (v).begin(), (v).end()
#define debug(x) cerr << #x << ": " << x << '\n'
#define pb(x) push_back(x)
#define mp(x, y) make_pair(x, y)
const int MOD = (int)1e9 + 7;
const int INF = (int)1e9 + 9;
using ll = long long;
using ull = unsigned long long;
using i_i = pair<int, int>;
using l_l = pair<ll, ll>;
using d_d = pair<double, double>;
using vint = vector<int>;
using vll = vector<ll>;
using vbool = vector<bool>;

int main() {
    string s;
    cin >> s;
    REP(i, s.size() - 1) {
        if (s[i] == s[i + 1]) {
            cout << i + 1 << " " << i + 2;
            return 0;
        }
    }
    REP(i, s.size() - 2) {
        if (s[i] == s[i + 2]) {
            cout << i + 1 << " " << i + 3;
            return 0;
        }
    }
    cout << "-1 -1";
}