Problem:
Score : 600 points

Problem Statement

Given are two sequences A and B, both of length N.
A and B are each sorted in the ascending order.
Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.

Constraints

1\leq N \leq 2 \times 10^5

1\leq A_i,B_i \leq N

A and B are each sorted in the ascending order.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N

Output

If there exist no reorderings that satisfy the condition, print No.

If there exists a reordering that satisfies the condition, print Yes on the first line.
After that, print a reordering of B on the second line, separating terms with a whitespace.

If there are multiple reorderings that satisfy the condition, you can print any of them.

Sample Input 1

6
1 1 1 2 2 3
1 1 1 2 2 3

Sample Output 1

Yes
2 2 3 1 1 1

Sample Input 2

3
1 1 2
1 1 3

Sample Output 2

No

Sample Input 3

4
1 1 2 3
1 2 3 3

Sample Output 3

Yes
3 3 1 2

Solution in Python (3.8.2) (judge verdict: Wrong Answer)

n=int(input())
a=[int(_) for _ in input().split()]
b=[int(_) for _ in input().split()]

d_a={}
d_b={}

for i in range(n):
    d_a[i]=0
    d_b[i]=0

for i in range(n):
    d_a[a[i]-1]+=1
    d_b[b[i]-1]+=1

diff=0

for i in range(n):
    if d_a[i]+d_b[i]>n:
        print("No")
        exit()
    diff = max(diff,(d_a[i]-d_b[(i-1)%n]))
print("Yes")
# for i in range(n):
#     print(a[i],end=" ")
# print()
for i in range(n):
    print(b[(i-diff)%n],end=" ")
print()