Problem:
Score : 500 points

Problem Statement

You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)

Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

N, Q, i_q, l_q, and r_q are integers.

S is a string consisting of lowercase English letters.

c_q is a lowercase English letter.

1 \leq N \leq 500000

1 \leq Q \leq 20000

|S| = N

1 \leq i_q \leq N

1 \leq l_q \leq r_q \leq N

There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:

N
S
Q
Query_1
\vdots
Query_Q

Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:

1 i_q c_q

2 l_q r_q

Output

For each query of type 2, print a line containing the answer.

Sample Input 1

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7

Sample Output 1

3
1
5

In the first query, cdbb contains three kinds of letters: b , c , and d, so we print 3.

In the second query, S is modified to abcdzbd.

In the third query, a contains one kind of letter: a, so we print 1.

In the fourth query, S is modified to abcazbd.

In the fifth query, S does not change and is still abcazbd.

In the sixth query, abcazbd contains five kinds of letters: a, b, c, d, and z, so we print 5.

Solution in Python (3.4.3) (judge verdict: Time Limit Exceeded)

#https://tjkendev.github.io/procon-library/python/range_query/rmq_segment_tree.html
# N: 処理する区間の長さ

# 中身は追えてない
#bit管理,26個作るより速いだろう
#演算はor

N = int(input())
s = input()


N0 = 2**(N-1).bit_length()
INF = 0
data = [0]*(2*N0)
# a_k の値を x に更新
def update(k, x):
    k += N0-1
    data[k] = 1<<x
    while k >= 0:
        k = (k - 1) // 2
        data[k] =data[2*k+1]|data[2*k+2]
# 区間[l, r)の最小値
def query(l, r):
    L = l + N0; R = r + N0
    s = INF
    while L < R:
        if R & 1:
            R -= 1
            s = s|data[R-1]

        if L & 1:
            s = s|data[L-1]
            L += 1
        L >>= 1; R >>= 1
    return s

for i in range(N):
    update(i,ord(s[i])-ord("a"))
q = int(input())
for j in range(q):
    t,l,r = input().split( )
    if t=="1":
        update(int(l)-1,ord(r)-ord("a"))
        
    else:
        bit = bin(query(int(l)-1,int(r)))[2:]
        ans = 0
        for i in bit:
            ans += int(i)
        print(ans)