Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

#coding:utf-8
N,A,B,C,D = map(int,input().split())
S = input()
def isContinuous(S):
    for i in range(len(S)-1):
        if S[i:i+2] == "##":
            return True
    return False
def paint(S):
    P = [0] * len(S)
    for i in range(len(S)):
        if S[i] == "#":
            P[i] = 1
            if i != 0:
                P[i-1] = 1
            if i != (len(S)-1):
                P[i+1] = 1
    return P
if C < D:
    if (not isContinuous(S[A:C])) and (not isContinuous(S[B:D])):
        print ("Yes")
    else:
        print ("No")
else:
    P = paint(S)
    #print (P)
    #print (P[B:D])
    for i in P[B:D]:
        if i == 0:
            print ("Yes")
            exit()
    print ("No")