Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in Python (3.4.3) (judge verdict: Accepted)

def char_range(c1, c2):
    """
    Generates the characters from `c1` to `c2`, inclusive.
    Taken from: https://stackoverflow.com/questions/7001144/range-over-character-in-python
    """
    for c in range(ord(c1), ord(c2)+1):
        yield chr(c)

class Solver(object):
    def __init__(self):
        self.s = input()
        self.t = input()

    def solve(self):
        self.s_to_t = {}
        self.t_to_s = {}
        for c in char_range('a', 'z'):
            self.s_to_t[c] = None
            self.t_to_s[c] = None
        
        for i in range(len(self.s)):
            cs = self.s[i]
            ct = self.t[i]
            if self.s_to_t[cs] is None:
                self.s_to_t[cs] = ct
            if self.t_to_s[ct] is None:
                self.t_to_s[ct] = cs
            if self.s_to_t[cs] != ct:
                print("No")
                return
            if self.t_to_s[ct] != cs:
                print("No")
                return
        print("Yes")


if __name__ == "__main__":
    s = Solver()
    s.solve()