Problem:
Score : 400 points

Problem Statement

Akari has n kinds of flowers, one of each kind.

She is going to choose one or more of these flowers to make a bouquet.

However, she hates two numbers a and b, so the number of flowers in the bouquet cannot be a or b.

How many different bouquets are there that Akari can make?

Find the count modulo (10^9 + 7).

Here, two bouquets are considered different when there is a flower that is used in one of the bouquets but not in the other bouquet.

Constraints

All values in input are integers.

2 \leq n \leq 10^9

1 \leq a < b \leq \textrm{min}(n, 2 \times 10^5)

Input

Input is given from Standard Input in the following format:

n a b

Output

Print the number of bouquets that Akari can make, modulo (10^9 + 7). (If there are no such bouquets, print 0.)

Sample Input 1

4 1 3

Sample Output 1

7

In this case, Akari can choose 2 or 4 flowers to make the bouquet.

There are 6 ways to choose 2 out of the 4 flowers, and 1 way to choose 4, so there are a total of 7 different bouquets that Akari can make.

Sample Input 2

1000000000 141421 173205

Sample Output 2

34076506

Print the count modulo (10^9 + 7).

Solution in PyPy3 (2.4.0) (judge verdict: Wrong Answer)

from math import factorial

n,a,b = map(int,input().split())

mod = 10**9 + 7

def pow(x, n):
  ans = 1
  while(n > 0):
    if(bin(n & 1) == bin(1)):
      ans = ans*x % mod
    x = x*x % mod
    n = n >> 1 #ビットシフト
  return ans

def ncr(n, r):
    x = 1
    y = 1
    for i in range(r):
        x *= (n-i)
        y *= (i+1)
        x %= mod
        y %= mod
    return (x * pow(y, 10**9+5)) % mod

ans = pow(2,n) - ncr(n,a) - ncr(n,b) - 1

print(ans if ans >= 0 else ans + mod)