Problem:
Score : 400 points

Problem Statement

We have a tree with N vertices numbered 1 to N.
The i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i.
Your objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:

For any two vertices painted in the same color, the distance between them is an even number.

Find a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.

Constraints

All values in input are integers.

1 \leq N \leq 10^5

1 \leq u_i < v_i \leq N

1 \leq w_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
u_1 v_1 w_1
u_2 v_2 w_2
.
.
.
u_{N - 1} v_{N - 1} w_{N - 1}

Output

Print a coloring of the vertices that satisfies the condition, in N lines.
The i-th line should contain 0 if Vertex i is painted white and 1 if it is painted black.

If there are multiple colorings that satisfy the condition, any of them will be accepted.

Sample Input 1

3
1 2 2
2 3 1

Sample Output 1

0
0
1

Sample Input 2

5
2 5 2
2 3 10
1 3 8
3 4 2

Sample Output 2

1
0
1
0
1

Solution in PyPy3 (2.4.0) (judge verdict: Wrong Answer)

class UNION_FIND(object):
    def __init__(self,n):
        #親の番号を格納する。親だった場合は-(その集合のサイズ)
        #作るときはParentの値を全て-1にする
        #こうすると全てバラバラになる
        self.parent=[-1 for i in range(n)]
        
    def root(self,x):
        #Aがどのグループに属しているか調べる
        if self.parent[x]<0:
            return x
        else:
            self.parent[x]=self.root(self.parent[x])  #親を再帰で探知 再帰は最後に上のifにひっかかる
            return self.parent[x]
 
    def size(self,x):
        #自分のいるグループの頂点数を調べる
        return -self.parent[self.root(x)]   #親をとってきたい
        
    def union(self,x,y):
        #AとBをくっ付ける
        #AとBを直接つなぐのではなく、root(A)にroot(B)をくっつける
        #print(self.parent)
        x=self.root(x)
        y=self.root(y)
        #print(x,y)
        if x==y:   #すでにくっついてるからくっ付けない
            return False
            
        #大きい方(A)に小さいほう(B)をくっ付けたい
        #大小が逆だったらひっくり返しちゃう。
        if self.size(x)<self.size(y):
            x,y=y,x
        self.parent[x]+=self.parent[y]  #Aのサイズを更新する
        self.parent[y]=x   #Bの親をAに変更する
        return True
        
n=int(input())        
u=UNION_FIND(2*n)
for i in range(n-1):
    a,b,c=map(int,input().split())
    if c%2==0:
        u.union(2*(a-1),2*(b-1))
        u.union(2*(a-1)+1,2*(b-1)+1)
    else:
        u.union(2*(a-1),2*(b-1)+1)
        u.union(2*(a-1)+1,2*(b-1))
for i in range(n):
    print(int(u.root(i)==u.root(2*i)))