Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in PyPy3 (2.4.0) (judge verdict: Wrong Answer)

def mark(number):
    """ビンゴシートにマークする

    Parameters
    ----------
    number : int
        出た数字
    """
    if number in yoko1:
        yoko1[number] = True

    if number in yoko2:
        yoko2[number] = True

    if number in yoko3:
        yoko3[number] = True

    if number in tate1:
        tate1[number] = True

    if number in tate2:
        tate2[number] = True

    if number in tate3:
        tate3[number] = True

    if number in naname1:
        naname1[number] = True

    if number in naname2:
        naname2[number] = True


def is_bingo():
    """ビンゴ達成したか否かを返す。
    """
    ans_list = []
    ans_list.append(False not in yoko1.values())
    ans_list.append(False not in yoko2.values())
    ans_list.append(False not in yoko3.values())
    ans_list.append(False not in tate1.values())
    ans_list.append(False not in tate2.values())
    ans_list.append(False not in tate3.values())
    ans_list.append(False not in naname1.values())
    ans_list.append(False not in naname2.values())

    return True in ans_list


row1 = list(map(int, input().split()))
row2 = list(map(int, input().split()))
row3 = list(map(int, input().split()))

yoko1 = {row1[0]: False, row1[1]: False, row1[2]: False}
yoko2 = {row2[0]: False, row2[1]: False, row2[2]: False}
yoko3 = {row3[0]: False, row3[1]: False, row3[2]: False}

tate1 = {row1[0]: False, row2[0]: False, row3[0]: False}
tate2 = {row1[1]: False, row2[2]: False, row3[1]: False}
tate3 = {row1[2]: False, row2[2]: False, row3[2]: False}

naname1 = {row1[0]: False, row2[1]: False, row3[2]: False}
naname2 = {row1[2]: False, row2[1]: False, row3[0]: False}

N = int(input())

for i in range(N):
    b = int(input())
    mark(b)

print("Yes") if is_bingo() else print("No")