Problem:
Score : 600 points

Problem Statement

Snuke has an integer sequence, a, of length N. The i-th element of a (1-indexed) is a_{i}.

He can perform the following operation any number of times:

Operation: Choose integers x and y between 1 and N (inclusive), and add a_x to a_y.

He would like to perform this operation between 0 and 2N times (inclusive) so that a satisfies the condition below. Show one such sequence of operations.
It can be proved that such a sequence of operations always exists under the constraints in this problem.

Condition: a_1 \leq a_2 \leq ... \leq a_{N}

Constraints

2 \leq N \leq 50

-10^{6} \leq a_i \leq 10^{6}

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_{N}

Output

Let m be the number of operations in your solution. In the first line, print m.
In the i-th of the subsequent m lines, print the numbers x and y chosen in the i-th operation, with a space in between.
The output will be considered correct if m is between 0 and 2N (inclusive) and a satisfies the condition after the m operations.

Sample Input 1

3
-2 5 -1

Sample Output 1

2
2 3
3 3

After the first operation, a = (-2,5,4).

After the second operation, a = (-2,5,8), and the condition is now satisfied.

Sample Input 2

2
-1 -3

Sample Output 2

1
2 1

After the first operation, a = (-4,-3) and the condition is now satisfied.

Sample Input 3

5
0 0 0 0 0

Sample Output 3

0

The condition is satisfied already in the beginning.

Solution in PyPy3 (7.3.0) (judge verdict: Wrong Answer)

n = int(input())
A = list(map(int, input().split()))

M = max(A)
m = min(A)
for i, a in enumerate(A):
    if a == M:
        max_id = i
    if a == m:
        min_id = i

ans = []
if m >= 0:
    for i in range(n-1):
        ans.append((i+1, i+2))
elif M <= 0:
    for i in reversed(range(1, n)):
        ans.append((i+1, i))
else:
    if abs(M) >= abs(m):
        for i, a in enumerate(A):
            if a < 0:
                ans.append((max_id+1, i+1))
        for i in range(n-1):
            ans.append((i+1, i+2))
    else:
        for i, a in enumerate(A):
            if a > 0:
                ans.append((min_id+1, i+1))
        for i in reversed(range(1, n)):
            ans.append((i+1, i))

for i in range(len(ans)):
    print(*ans[i])