Problem:
Score : 500 points

Problem Statement

For an integer n not less than 0, let us define f(n) as follows:

f(n) = 1 (if n < 2)

f(n) = n f(n-2) (if n \geq 2)

Given is an integer N. Find the number of trailing zeros in the decimal notation of f(N).

Constraints

0 \leq N \leq 10^{18}

Input

Input is given from Standard Input in the following format:

N

Output

Print the number of trailing zeros in the decimal notation of f(N).

Sample Input 1

12

Sample Output 1

1

f(12) = 12 × 10 × 8 × 6 × 4 × 2 = 46080, which has one trailing zero.

Sample Input 2

5

Sample Output 2

0

f(5) = 5 × 3 × 1 = 15, which has no trailing zeros.

Sample Input 3

1000000000000000000

Sample Output 3

124999999999999995

Solution in PyPy3 (2.4.0) (judge verdict: Wrong Answer)

import math
import time
from collections import deque
from copy import deepcopy

t = time.time()
def iip():
    ret = [int(i) for i in input().split()]
    if len(ret) == 1:
        return ret[0]
    return ret


def main():
    n = iip()

    if n % 2 == 1:
        print(0)
        exit()

    ret = 0
    n = n / 2
    for i in range(1, 114514):
        if n < 5:
            break
        n = int(n/5)
        ret += n

    print(ret)


main()