Problem:
Score : 200 points

Problem Statement

Find the largest square number not exceeding N. Here, a square number is an integer that can be represented as the square of an integer.

Constraints

1 \leq N \leq 10^9

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print the largest square number not exceeding N.

Sample Input 1

10

Sample Output 1

9

10 is not square, but 9 = 3 × 3 is. Thus, we print 9.

Sample Input 2

81

Sample Output 2

81

Sample Input 3

271828182

Sample Output 3

271821169

Solution in PyPy3 (7.3.0) (judge verdict: Accepted)

###==================================================
### import
#import bisect
#from collections import Counter, deque, defaultdict
#from copy import deepcopy
#from functools import reduce, lru_cache
#from heapq import heappush, heappop
#import itertools
#import math
#import string
import sys
### stdin
def input(): return sys.stdin.readline().rstrip()
def iIn(): return int(input())
def iInM(): return map(int, input().split())
def iInM1(): return map(int1, input().split())
def iInLH(): return list(map(int, input().split()))
def iInLH1(): return list(map(int1, input().split()))
def iInLV(n): return [iIn() for _ in range(n)]
def iInLV1(n): return [iIn()-1 for _ in range(n)]
def iInLD(n): return [iInLH() for _ in range(n)]
def iInLD1(n): return [iInLH1() for _ in range(n)]
def sInLH(): return list(input().split())
def sInLV(n): return [input().rstrip('\n') for _ in range(n)]
def sInLD(n): return [sInLH() for _ in range(n)]
### stdout
def OutH(lst, deli=' '): print(deli.join(map(str, lst)))
def OutV(lst): print('\n'.join(map(str, lst)))
### setting
sys.setrecursionlimit(10 ** 6)
### utils
int1 = lambda x: int(x) - 1
### constants
INF = int(1e9)
MOD = 1000000007
dx = (-1, 0, 1, 0)
dy = (0, -1, 0, 1)
###---------------------------------------------------

N = iIn()

n = 1
while 1:
  if n**2 > N:
    print((n-1)**2)
    exit()
  else:
    n += 1