Problem:
Score : 300 points

Problem Statement

You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:

N

Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:

h n w

Sample Input 1

2

Sample Output 1

1 2 2

4/2 = 1/1 + 1/2 + 1/2.

Sample Input 2

3485

Sample Output 2

872 1012974 1539173474040

It is allowed to use an integer exceeding 3500 in a solution.

Sample Input 3

4664

Sample Output 3

3498 3498 3498

Solution in PyPy3 (7.3.0) (judge verdict: Wrong Answer)

# https://atcoder.jp/contests/tenka1-2017/tasks/tenka1_2017_c
def main():
    N = int(input())

    for h in range(1, 3500 + 1):
        for n in range(1, 3500 + 1):
            if (4 * h * n - N * n - N * h != 0) and (N * h * n) % (4 * h * n - N * n - N * h) == 0:
                w = (N * h * n) // (4 * h * n - N * n - N * h)
                print(h, n, w)
                return

if __name__ == "__main__":
    main()