Problem:
Score : 600 points

Problem Statement

We have N colored balls arranged in a row from left to right; the color of the i-th ball from the left is c_i.

You are given Q queries. The i-th query is as follows: how many different colors do the l_i-th through r_i-th balls from the left have?

Constraints

1\leq N,Q \leq 5 \times 10^5

1\leq c_i \leq N

1\leq l_i \leq r_i \leq N

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N Q
c_1 c_2 \cdots c_N
l_1 r_1
l_2 r_2
:
l_Q r_Q

Output

Print Q lines. The i-th line should contain the response to the i-th query.

Sample Input 1

4 3
1 2 1 3
1 3
2 4
3 3

Sample Output 1

2
3
1

The 1-st, 2-nd, and 3-rd balls from the left have the colors 1, 2, and 1 - two different colors.

The 2-st, 3-rd, and 4-th balls from the left have the colors 2, 1, and 3 - three different colors.

The 3-rd ball from the left has the color 1 - just one color.

Sample Input 2

10 10
2 5 6 5 2 1 7 9 7 2
5 5
2 4
6 7
2 2
7 8
7 9
1 8
6 9
8 10
6 8

Sample Output 2

1
2
2
1
2
2
6
3
3
3

Solution in PyPy3 (7.3.0) (judge verdict: Time Limit Exceeded)

import sys


class BinaryIndexedTree(object):
    '''
    1-indexed
    '''
    def __init__(self, A):
        self.__n = len(A)
        self.__node = [0] * (self.__n + 1)
        self.__data = [0] * (self.__n + 1)

        S = [0] * (self.__n + 1)
        for i in range(self.__n):
            S[i + 1] = S[i] + A[i]

        for i in range(1, self.__n + 1):
            self.__data[i] = A[i - 1]
            self.__node[i] = S[i] - S[i - (i & -i)]

    def add(self, i, v):
        self.__data[i] += v
        while i <= self.__n:
            self.__node[i] += v
            i += i & -i

    def sum(self, i):
        ''' [1, i]の和
        '''
        rst = 0
        while i > 0:
            rst += self.__node[i]
            i -= i & -i
        return rst
    
    def get(self, i, j):
        '''[i, j]の和
        '''
        if i == j:
            return self.__data[i]
        else:
            return self.sum(j) - self.sum(i - 1)


def main():
    N, Q = map(int, input().split())
    C = list(map(int, input().split()))

    P = [[] for _ in range(N)]
    for i, c in enumerate(C):
        P[c - 1].append(i)

    right = [0] * N
    for p in P:
        if len(p):
            right[p.pop()] = 1
    BIT = BinaryIndexedTree(right)

    query = []
    for i in range(Q):
        l, r = map(int, sys.stdin.readline().split())
        query.append((r - 1, l - 1, i))

    query.sort(reverse=True)
    ans = [None] * Q

    cur = N - 1
    for r, l, i in query:
        while r < cur:
            c = C[cur] - 1
            # BIT.update(cur + 1, 0)
            p = P[c]
            if len(p):
                BIT.add(p.pop() + 1, 1)
            cur -= 1
        tmp = BIT.get(l + 1, r + 1)
        ans[i] = tmp

    print(*ans, sep='\n')


if __name__ == '__main__':
    main()