Problem:
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Dice III

Write a program which reads the two dices constructed in the same way as Dice I, and determines whether these two dices are identical. You can roll a dice in the same way as Dice I, and if all integers observed from the six directions are the same as that of another dice, these dices can be considered as identical.

Input

In the first line, six integers assigned to faces of a dice are given in ascending order of their corresponding labels.

In the second line, six integers assigned to faces of another dice are given in ascending order of their corresponding labels.

Output

Print "Yes" if two dices are identical, otherwise "No" in a line.

Constraints

$0 \leq $ the integer assigned to a face $ \leq 100$

Sample Input 1

1 2 3 4 5 6
6 2 4 3 5 1

Sample Output 1

Yes

Sample Input 2

1 2 3 4 5 6
6 5 4 3 2 1

Sample Output 2

No

Solution in Python3 (judge verdict: Accepted)

class Dice():
    def __init__(self):
        self.nums = list(range(6))
        self.work = list(range(6))

    def set_nums(self, n0, n1, n2, n3, n4, n5):
        self.nums[0] = n0
        self.nums[1] = n1
        self.nums[2] = n2
        self.nums[3] = n3
        self.nums[4] = n4
        self.nums[5] = n5

    def rotate(self, cmd):
        for i in range(6):
            # deepcopy
            self.work[i] = self.nums[i]

        if cmd == 'N':
            self.set_nums(self.work[1], self.work[5], self.work[2], self.work[3], self.work[0], self.work[4])
        elif cmd == 'S':
            self.set_nums(self.work[4], self.work[0], self.work[2], self.work[3], self.work[5], self.work[1]),
        elif cmd == 'E':
            self.set_nums(self.work[3], self.work[1], self.work[0], self.work[5], self.work[4], self.work[2])
        else:
            self.set_nums(self.work[2], self.work[1], self.work[5], self.work[0], self.work[4], self.work[3])

    def top(self):
        return self.nums[0]

    def right(self, top, front):
        # サイコロの面IDを返す
        if top == 1:
            return [3,5,2,4][front-2]
        elif top == 6:
            return [4,2,5,3][front-2]
        elif top == 2:
            # 0が返る場合は不正なサイコロ
            return [4,0,1,6,0,3][front-1]
        elif top == 5:
            # 0が返る場合は不正なサイコロ
            return [3,0,6,1,0,4][front-1]
        elif top == 3:
            # 0が返る場合は不正なサイコロ
            return [2,6,0,0,1,5][front-1]
        elif top == 4:
            # 0が返る場合は不正なサイコロ
            return [5,1,0,0,6,2][front-1]
        else:
            pass

    def rolls(self):
        # 上面、前面、右面、左面、奥面、下面の値を返す
        return [self.nums[i] for i in range(6)]

import random
nums_1 = [int(arg) for arg in input().split()]
nums_2 = [int(arg) for arg in input().split()]
d1 = Dice()
d1.set_nums(*nums_1)
d2 = Dice()
d2.set_nums(*nums_2)
d1_roll = d1.rolls()


for i in range(10000):
    cmd = ['N', 'S', 'E', 'W'][random.randint(0,3)]
    d2.rotate(cmd)
    d2_roll = d2.rolls()
    if all([d1_roll[i] == d2_roll[i] for i in range(6)]):
        print('Yes')
        exit()
print('No')