Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Python (3.8.2) (judge verdict: Accepted)

N = int(input())

def make_divisor(n):
    divisors = []
    for i in range(1, int(n**.5) + 1):
        if n%i == 0:
            divisors.append(i)
            if i != n//i:
                divisors.append(n//i)
    divisors.sort()
    return divisors
cnt = 0
for i in range(1, N+1):
    if len(make_divisor(i)) == 8 and  i%2 == 1:
        cnt += 1
print(cnt)