Problem:
Score: 300 points

Problem Statement

In Republic of Atcoder, there are N prefectures, and a total of M cities that belong to those prefectures.

City i is established in year Y_i and belongs to Prefecture P_i.

You can assume that there are no multiple cities that are established in the same year.

It is decided to allocate a 12-digit ID number to each city.

If City i is the x-th established city among the cities that belong to Prefecture i, the first six digits of the ID number of City i is P_i, and the last six digits of the ID number is x.

Here, if P_i or x (or both) has less than six digits, zeros are added to the left until it has six digits.

Find the ID numbers for all the cities.

Note that there can be a prefecture with no cities.

Constraints

1 \leq N \leq 10^5

1 \leq M \leq 10^5

1 \leq P_i \leq N

1 \leq Y_i \leq 10^9

Y_i are all different.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
P_1 Y_1
:
P_M Y_M

Output

Print the ID numbers for all the cities, in ascending order of indices (City 1, City 2, ...).

Sample Input 1

2 3
1 32
2 63
1 12

Sample Output 1

000001000002
000002000001
000001000001

As City 1 is the second established city among the cities that belong to Prefecture 1, its ID number is 000001000002.

As City 2 is the first established city among the cities that belong to Prefecture 2, its ID number is 000002000001.

As City 3 is the first established city among the cities that belong to Prefecture 1, its ID number is 000001000001.

Sample Input 2

2 3
2 55
2 77
2 99

Sample Output 2

000002000001
000002000002
000002000003

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

N, M = [int(str) for str in input().strip().split()]
PY = [[int(str) for str in input().strip().split()] for _ in range(M)]

DEBUG = False

dbgp = print if DEBUG else lambda *x:x

data = dict([i, []] for i in range(1, N + 1))
[data[p].append(y) for p, y in PY]
dbgp('data : ', data)

rank = dict()
for k in data.keys():
    if len(data[k]):
        rank[k] = sorted(list(range(1, len(data[k]) + 1)), key=lambda x:data[k][x - 1])

dbgp('rank : ', rank)

counter = dict([i, 0] for i in rank.keys())
dbgp('counter : ', counter)

for p, y in PY:
    print('{0:06}{1:06}'.format(p, rank[p][counter[p]]))
    counter[p] += 1