Problem:
Score : 300 points

Problem Statement

Given is a permutation P_1, \ldots, P_N of 1, \ldots, N.
Find the number of integers i (1 \leq i \leq N) that satisfy the following condition:

For any integer j (1 \leq j \leq i), P_i \leq P_j.

Constraints

1 \leq N \leq 2 \times 10^5

P_1, \ldots, P_N is a permutation of 1, \ldots, N.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
P_1 ... P_N

Output

Print the number of integers i that satisfy the condition.

Sample Input 1

5
4 2 5 1 3

Sample Output 1

3

i=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.

Similarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.

Sample Input 2

4
4 3 2 1

Sample Output 2

4

All integers i (1 \leq i \leq N) satisfy the condition.

Sample Input 3

6
1 2 3 4 5 6

Sample Output 3

1

Only i=1 satisfies the condition.

Sample Input 4

8
5 7 4 2 6 8 1 3

Sample Output 4

4

Sample Input 5

1
1

Sample Output 5

1

Solution in Python (3.4.3) (judge verdict: Time Limit Exceeded)

# -*- coding: utf-8 -*-

import sys
import math


debug = False

def log(text):
    if debug:
        print(text)

def parse_input(lines_as_string = None):

    global debug
    lines = []
    if lines_as_string is None:
        debug = False
        # for line in sys.stdin:
        #     lines.append(line)
        lines.append(input())
        lines.append(input())
    else:
        debug = True
        lines = [e for e in lines_as_string.split("\n")][1:-1]


    n = int(lines[0])
    p = [int(e) for e in lines[1].split(' ')]

    return (n, p)


def solve(n, p):


    result = [] 
    current_min = 200000 + 1
    for i in range(n):

        if current_min < p[i]:
            continue 

        current_min = min([current_min, p[i]])

        done = False
        for j in range(i+1):
            if p[i] <= p[j]:
                if j == i:
                    done = True
            else:
                break
        if done:
            result.append(i)


    return len(result)


def main():
    # 出力
    result = solve(*parse_input())
    if isinstance(result, list):
        print("%d %d" % (result[0], result[1]))
    else:
        print("%s" % result, sep='')

if __name__ == '__main__':

    main()