Problem:
Score : 400 points

Problem Statement

Given are positive integers A and B.

Let us choose some number of positive common divisors of A and B.

Here, any two of the chosen divisors must be coprime.

At most, how many divisors can we choose?

Definition of common divisor

An integer d is said to be a common divisor of integers x and y when d divides both x and y.

Definition of being coprime

Integers x and y are said to be coprime when x and y have no positive common divisors other than 1.

Definition of dividing

An integer x is said to divide another integer y when there exists an integer \alpha such that y = \alpha x.

Constraints

All values in input are integers.

1 \leq A, B \leq 10^{12}

Input

Input is given from Standard Input in the following format:

A B

Output

Print the maximum number of divisors that can be chosen to satisfy the condition.

Sample Input 1

12 18

Sample Output 1

3

12 and 18 have the following positive common divisors: 1, 2, 3, and 6.

1 and 2 are coprime, 2 and 3 are coprime, and 3 and 1 are coprime, so we can choose 1, 2, and 3, which achieve the maximum result.

Sample Input 2

420 660

Sample Output 2

4

Sample Input 3

1 2019

Sample Output 3

1

1 and 2019 have no positive common divisors other than 1.

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

A,B = map(int,input().split())
primeN1 = []
primeN2 = []
for i in range(2, A):
    for j in range(2, i+1):
        if i % j == 0:
            if i == j:
                primeN1.append(i)
            else:
                break
for i in range(2, B):
    for j in range(2, i+1):
        if i % j == 0:
            if i == j:
                primeN2.append(i)
            else:
                break

sosuu = -2
for m,n in zip(primeN1,primeN2):
    if m == n:
        sosuu+=1
    else:
        pass

if sosuu<0:
    sosuu = 1
    
print(sosuu)