Problem:
Score : 200 points

Problem Statement

Takahashi loves gold coins. He gains 1000 happiness points for each 500-yen coin he has and gains 5 happiness points for each 5-yen coin he has. (Yen is the currency of Japan.)

Takahashi has X yen. If he exchanges his money so that he will gain the most happiness points, how many happiness points will he earn?

(We assume that there are six kinds of coins available: 500-yen, 100-yen, 50-yen, 10-yen, 5-yen, and 1-yen coins.)

Constraints

0 \leq X \leq 10^9

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the maximum number of happiness points that can be earned.

Sample Input 1

1024

Sample Output 1

2020

By exchanging his money so that he gets two 500-yen coins and four 5-yen coins, he gains 2020 happiness points, which is the maximum number of happiness points that can be earned.

Sample Input 2

0

Sample Output 2

0

He is penniless - or yenless.

Sample Input 3

1000000000

Sample Output 3

2000000000

He is a billionaire - in yen.

Solution in Python (3.4.3) (judge verdict: Runtime Error)

#include<iostream>
using namespace std;

int main() {
    int x;
    int HP = 0;
    bool FUCK = false;
    
    cin >> x;

    if(x < 5){
        cout << 0 << endl;
        FUCK = true;
    }
    
    while(x >= 500){
        HP += 1000;
        x -= 500;
    }
    
    while(x >= 5){
        HP += 5;
        x -= 5;
    }
        
    if(FUCK == false){
        cout << HP << endl;
    }
    
}