Problem:
Score : 500 points

Problem Statement

You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)

Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

N, Q, i_q, l_q, and r_q are integers.

S is a string consisting of lowercase English letters.

c_q is a lowercase English letter.

1 \leq N \leq 500000

1 \leq Q \leq 20000

|S| = N

1 \leq i_q \leq N

1 \leq l_q \leq r_q \leq N

There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:

N
S
Q
Query_1
\vdots
Query_Q

Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:

1 i_q c_q

2 l_q r_q

Output

For each query of type 2, print a line containing the answer.

Sample Input 1

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7

Sample Output 1

3
1
5

In the first query, cdbb contains three kinds of letters: b , c , and d, so we print 3.

In the second query, S is modified to abcdzbd.

In the third query, a contains one kind of letter: a, so we print 1.

In the fourth query, S is modified to abcazbd.

In the fifth query, S does not change and is still abcazbd.

In the sixth query, abcazbd contains five kinds of letters: a, b, c, d, and z, so we print 5.

Solution in PyPy3 (2.4.0) (judge verdict: Accepted)

N = int(input())
S = list(input())
Q = int(input())
query = [input().split() for _ in range(Q)]

bit = [[0 for _ in range(26)] for _ in range(N + 1)]

def bit_add(i, s, x):
    j = ord(s) - ord("a")
    while i <= N:
        bit[i][j] += x
        i += i & - i
        
def bit_sum(i):
    s = [0] * 26
    while i:
        for j in range(26):
            s[j] += bit[i][j]
        i -= i & -i
    return s
for i in range(1, N + 1):
    s = S[i - 1]
    bit_add(i, s, 1)

for x, y, z in query:
    if x == "1":
        y = int(y)
        bit_add(y, S[y - 1], -1)
        bit_add(y, z, 1)
        S[y - 1] = z
    if x == "2":
        answer = 0
        y, z = int(y) - 1, int(z)
        sum_y = bit_sum(y)
        sum_z = bit_sum(z)
        for i in range(26):
            if sum_z[i] - sum_y[i] > 0:
                answer += 1
        print(answer)