Problem:
Score : 500 points

Problem Statement

There are N blocks arranged in a row. Let us paint these blocks.

We will consider two ways to paint the blocks different if and only if there is a block painted in different colors in those two ways.

Find the number of ways to paint the blocks under the following conditions:

For each block, use one of the M colors, Color 1 through Color M, to paint it. It is not mandatory to use all the colors.

There may be at most K pairs of adjacent blocks that are painted in the same color.

Since the count may be enormous, print it modulo 998244353.

Constraints

All values in input are integers.

1 \leq N, M \leq 2 \times 10^5

0 \leq K \leq N - 1

Input

Input is given from Standard Input in the following format:

N M K

Output

Print the answer.

Sample Input 1

3 2 1

Sample Output 1

6

The following ways to paint the blocks satisfy the conditions: 112, 121, 122, 211, 212, and 221. Here, digits represent the colors of the blocks.

Sample Input 2

100 100 0

Sample Output 2

73074801

Sample Input 3

60522 114575 7559

Sample Output 3

479519525

Solution in Python (3.8.2) (judge verdict: Accepted)

mod = 998244353

SIZE = 2 * 10 ** 5 + 1
fact = [0] * SIZE
inv = [0] * SIZE
finv = [0] * SIZE
fact[0], fact[1] = 1, 1
inv[1] = 1
finv[0], finv[1] = 1, 1
for i in range(2, SIZE):
    fact[i] = fact[i - 1] * i % mod
    inv[i] = mod - inv[mod % i] * (mod // i) % mod
    finv[i] = finv[i - 1] * inv[i] % mod

def nCr(n, r):
    if n < 0 or r < 0 or n < r:
        return 0
    return fact[n] * (finv[r] * finv[n - r] % mod) % mod


n, m, k = map(int, input().split())

ans = 0
for x in range(k+1):
    pattern = nCr(n-1, x) * m * pow(m-1, n-x-1, mod) % mod
    ans = (ans + pattern) % mod

print(ans)