Problem:
Score : 100 points

Problem Statement

You are given a three-digit positive integer N.

Determine whether N is a palindromic number.

Here, a palindromic number is an integer that reads the same backward as forward in decimal notation.

Constraints

100≤N≤999

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

If N is a palindromic number, print Yes; otherwise, print No.

Sample Input 1

575

Sample Output 1

Yes

N=575 is also 575 when read backward, so it is a palindromic number. You should print Yes.

Sample Input 2

123

Sample Output 2

No

N=123 becomes 321 when read backward, so it is not a palindromic number. You should print No.

Sample Input 3

812

Sample Output 3

No

Solution in PyPy3 (2.4.0) (judge verdict: Runtime Error)

import collections as c
 
d=c.defaultdict(list)
n=int(input())
for s in range(n-1):
    a,b,c=map(int,input().split())
    d[a].append([b,c])
    d[b].append([a,c])
 
def DFS(point,d,cost,TFlist): #入力と同じindex系
    for s in d[point]:
        try:
            p=s[0]
            c=s[1]+cost[point]
            if TFlist[p-1]:
                continue
            cost[p]+=c
            TFlist[p-1]=1
            DFS(p,d,cost,TFlist)
        except:
            continue
 
cost=[None]+[0 for i in range(n)]
q,k=map(int,input().split())
TFlist=[0 for i in range(n)]
TFlist[k-1]=1
DFS(k,d,cost,TFlist)
 
for t in range(q):
    a,b=map(int,input().split())
    print(cost[a]+cost[b])