Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in PyPy3 (7.3.0) (judge verdict: Accepted)

# import sys
# import math #sqrt,gcd
# import decimal
# import queue # queue
# import bisect
# import heapq # priolity-queue
# import time
# from itertools import permutations #順列生成
# import collections # deque
# from operator import itemgetter
# from fractions import Fraction

mod = int(1e9+7)
INF = 1<<29
lINF = 1<<35

def readInt():
    return list(map(int,input().split()))

def main():
    n = int(input())
    ans = 0
    for i in range(n+1):
        if i%3!=0 and i%5!=0:
            ans += i
    print(ans)
    return

if __name__=='__main__':
    main()