Problem:
Score : 400 points

Problem Statement

There are N people standing in a queue from west to east.

Given is a string S of length N representing the directions of the people.
The i-th person from the west is facing west if the i-th character of S is L, and east if that character of S is R.

A person is happy if the person in front of him/her is facing the same direction.
If no person is standing in front of a person, however, he/she is not happy.

You can perform the following operation any number of times between 0 and K (inclusive):

Operation: Choose integers l and r such that 1 \leq l \leq r \leq N, and rotate by 180 degrees the part of the queue: the l-th, (l+1)-th, ..., r-th persons. That is, for each i = 0, 1, ..., r-l, the (l + i)-th person from the west will stand the (r - i)-th from the west after the operation, facing east if he/she is facing west now, and vice versa.

What is the maximum possible number of happy people you can have?

Constraints

N is an integer satisfying 1 \leq N \leq 10^5.

K is an integer satisfying 1 \leq K \leq 10^5.

|S| = N

Each character of S is L or R.

Input

Input is given from Standard Input in the following format:

N K
S

Output

Print the maximum possible number of happy people after at most K operations.

Sample Input 1

6 1
LRLRRL

Sample Output 1

3

If we choose (l, r) = (2, 5), we have LLLRLL, where the 2-nd, 3-rd, and 6-th persons from the west are happy.

Sample Input 2

13 3
LRRLRLRRLRLLR

Sample Output 2

9

Sample Input 3

10 1
LLLLLRRRRR

Sample Output 3

9

Sample Input 4

9 2
RRRLRLRLL

Sample Output 4

7

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

# run-length encoding, decoding
def rle_encode(data):
    encoding = ''
    prev_char = ''
    count = 1

    if not data: return ''

    for char in data:
        # If the prev and current characters
        # don't match...
        if char != prev_char:
            # ...then add the count and character
            # to our encoding
            if prev_char:
                encoding += str(count) + prev_char + ' '
            count = 1
            prev_char = char
        else:
            # Or increment our counter
            # if the characters do match
            count += 1
    else:
        # Finish off the encoding
        encoding += str(count) + prev_char + ' '
        return encoding

N, K = [int(s) for s in input().split()]
S = input()
S_rle = rle_encode(S).split()
total = 0
for i, bunch in enumerate(S_rle):
  total += int(list(bunch)[0]) - 1

if len(S_rle) > 2*K:
  print(total+2*K)
elif len(S_rle) >= 2*K-1:
  print(total+2*K-1)
else:
  print(N-1)