Problem:
Score : 400 points

Problem Statement

We have an H-by-W matrix.
Let a_{ij} be the element at the i-th row from the top and j-th column from the left.
In this matrix, each a_{ij} is a lowercase English letter.

Snuke is creating another H-by-W matrix, A', by freely rearranging the elements in A.
Here, he wants to satisfy the following condition:

Every row and column in A' can be read as a palindrome.

Determine whether he can create a matrix satisfying the condition.

Note

A palindrome is a string that reads the same forward and backward.
For example, a, aa, abba and abcba are all palindromes, while ab, abab and abcda are not.

Constraints

1 ≤ H, W ≤ 100

a_{ij} is a lowercase English letter.

Input

Input is given from Standard Input in the following format:

H W
a_{11}a_{12}...a_{1W}
:
a_{H1}a_{H2}...a_{HW}

Output

If Snuke can create a matrix satisfying the condition, print Yes; otherwise, print No.

Sample Input 1

3 4
aabb
aabb
aacc

Sample Output 1

Yes

For example, the following matrix satisfies the condition.

abba
acca
abba

Sample Input 2

2 2
aa
bb

Sample Output 2

No

It is not possible to create a matrix satisfying the condition, no matter how we rearrange the elements in A.

Sample Input 3

5 1
t
w
e
e
t

Sample Output 3

Yes

For example, the following matrix satisfies the condition.

t
e
w
e
t

Sample Input 4

2 5
abxba
abyba

Sample Output 4

No

Sample Input 5

1 1
z

Sample Output 5

Yes

Solution in Python (3.8.2) (judge verdict: Accepted)

from collections import Counter
h,w=map(int,input().split())
s=""
for i in range(h):
  s+=input()
sc=Counter(s)
d=[0,0,0]
for v in sc.values():
    d[0]+=(v//4)*4
    d[1]+=2 if v%4>=2 else 0
    d[2]+=v%2

if w%2==0 and h%2==0:
  print("Yes" if d[0]==h*w else "No")
elif (w%2)*(h%2)==1:
  print("Yes" if d[1]<=(w-1)+(h-1) and d[2]==1 else "No")
elif w%2==0:
  print("Yes" if d[1]<=w and d[2]==0 else "No")
elif h%2==0:
  print("Yes" if d[1]<=h and d[2]==0 else "No")