Problem:
Score : 300 points

Problem Statement

AtCoDeer the deer is going on a trip in a two-dimensional plane.
In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.

If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1).
Note that he cannot stay at his place.
Determine whether he can carry out his plan.

Constraints

1 ≤ N ≤ 10^5

0 ≤ x_i ≤ 10^5

0 ≤ y_i ≤ 10^5

1 ≤ t_i ≤ 10^5

t_i < t_{i+1} (1 ≤ i ≤ N-1)

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
t_1 x_1 y_1
t_2 x_2 y_2
:
t_N x_N y_N

Output

If AtCoDeer can carry out his plan, print Yes; if he cannot, print No.

Sample Input 1

2
3 1 2
6 1 1

Sample Output 1

Yes

For example, he can travel as follows: (0,0), (0,1), (1,1), (1,2), (1,1), (1,0), then (1,1).

Sample Input 2

1
2 100 100

Sample Output 2

No

It is impossible to be at (100,100) two seconds after being at (0,0).

Sample Input 3

2
5 1 1
100 1 1

Sample Output 3

No

Solution in PyPy3 (2.4.0) (judge verdict: Accepted)

n = int(input())
 
travel = []
for i in range(n):
    t,x,y = map(int, input().split())
    tmp = [t,x,y]
    travel.append(tmp)
 
now = [0, 0]
pre_time = 0
for tra in travel:
    diff_time,x,y = tra[0]-pre_time,tra[1],tra[2]
    for _ in range(diff_time):
        if now[0] < x:
            now[0] += 1
        elif x < now[0]:
            now[0] -= 1
        elif now[1] < y:
            now[1] += 1
        elif y < now[1]:
            now[1] -= 1
        else:
            now[1] -= 1
    
    if now[0] == x and now[1] == y:
        pass
    else:
        print('No')
        exit()

    pre_time = tra[0]
 
print('Yes')