Problem:
Score : 200 points

Problem Statement

You are given strings s and t, consisting of lowercase English letters.
You will create a string s' by freely rearranging the characters in s.
You will also create a string t' by freely rearranging the characters in t.
Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Notes

For a string a = a_1 a_2 ... a_N of length N and a string b = b_1 b_2 ... b_M of length M, we say a < b for the lexicographic order if either one of the following two conditions holds true:

N < M and a_1 = b_1, a_2 = b_2, ..., a_N = b_N.

There exists i (1 \leq i \leq N, M) such that a_1 = b_1, a_2 = b_2, ..., a_{i - 1} = b_{i - 1} and a_i < b_i. Here, letters are compared using alphabetical order.

For example, xy < xya and atcoder < atlas.

Constraints

The lengths of s and t are between 1 and 100 (inclusive).

s and t consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s
t

Output

If it is possible to satisfy s' < t', print Yes; if it is not, print No.

Sample Input 1

yx
axy

Sample Output 1

Yes

We can, for example, rearrange yx into xy and axy into yxa. Then, xy < yxa.

Sample Input 2

ratcode
atlas

Sample Output 2

Yes

We can, for example, rearrange ratcode into acdeort and atlas into tslaa. Then, acdeort < tslaa.

Sample Input 3

cd
abc

Sample Output 3

No

No matter how we rearrange cd and abc, we cannot achieve our objective.

Sample Input 4

w
ww

Sample Output 4

Yes

Sample Input 5

zzz
zzz

Sample Output 5

No

Solution in Python (2.7.6) (judge verdict: Wrong Answer)

s = raw_input()
t = raw_input()

flag = 0
outflag = 0
yflag = 0
for i in range(len(s)):

	for j in range(len(t)):
		if ord(t[j])>ord(s[i]):
			print "Yes"
			flag = 1
			outflag=1
			yflag = 1
			break
		elif ord(t[j])<ord(s[i]):
			flag = 0
		elif ord(t[j])==ord(s[i]):
			flag = 1
			break
	if flag == 0:
		print "No"
		outflag=1
		break
	elif outflag==1 and yflag == 1:
		break

if yflag == 0 and outflag == 0 and flag == 1 and len(s)<len(t):
	print "Yes"
elif (outflag == 0 and flag == 1 and yflag == 0) and (len(s)>len(t) or len(s)==len(t)):
	print "No"