Problem:
Score : 300 points

Problem Statement

You are given an integer N.
Find the number of the positive divisors of N!, modulo 10^9+7.

Constraints

1≤N≤10^3

Input

The input is given from Standard Input in the following format:

N

Output

Print the number of the positive divisors of N!, modulo 10^9+7.

Sample Input 1

3

Sample Output 1

4

There are four divisors of 3! =6: 1, 2, 3 and 6. Thus, the output should be 4.

Sample Input 2

6

Sample Output 2

30

Sample Input 3

1000

Sample Output 3

972926972

Solution in Python (2.7.6) (judge verdict: Accepted)

import math

def factorization(n):
    def factor_sub(n, m):
        c = 0
        while n % m == 0:
            c += 1
            n /= m
        return c, n
    #
    buff = []
    c, m = factor_sub(n, 2)
    if c > 0: buff.append((2, c))
    c, m = factor_sub(m, 3)
    if c > 0: buff.append((3, c))
    x = 5
    while m >= x * x:
        c, m = factor_sub(m, x)
        if c > 0: buff.append((x, c))
        if x % 6 == 5:
            x += 2
        else:
            x += 4
    if m > 1: buff.append((m, 1))
    return buff

def divisor_num(n):
    a = 1
    for _ , x in factorization(n):
        a *= x + 1
    return a

n = int(raw_input())
nx = math.factorial(n)
print divisor_num(nx) % (10**9 + 7)