Problem:
Score : 400 points

Problem Statement

Given is a string S. Each character in S is either a digit (0, ..., 9) or ?.

Among the integers obtained by replacing each occurrence of ? with a digit, how many have a remainder of 5 when divided by 13? An integer may begin with 0.

Since the answer can be enormous, print the count modulo 10^9+7.

Constraints

S is a string consisting of digits (0, ..., 9) and ?.

1 \leq |S| \leq 10^5

Input

Input is given from Standard Input in the following format:

S

Output

Print the number of integers satisfying the condition, modulo 10^9+7.

Sample Input 1

??2??5

Sample Output 1

768

For example, 482305, 002865, and 972665 satisfy the condition.

Sample Input 2

?44

Sample Output 2

1

Only 044 satisfies the condition.

Sample Input 3

7?4

Sample Output 3

0

We may not be able to produce an integer satisfying the condition.

Sample Input 4

?6?42???8??2??06243????9??3???7258??5??7???????774????4?1??17???9?5?70???76???

Sample Output 4

153716888

Solution in PyPy3 (2.4.0) (judge verdict: Time Limit Exceeded)

d=[0]*13
d[0]=1
s=input()
for k,t in enumerate(s[::-1]):
    if t=='?':
        d2=[0]*13
        for i in range(10):
            u=(i*10**k)%13
            for i in range(13):
                d2[(i+u)%13]+=d[i]
    else:
        u=(int(t)*10**k)%13
        d2=[0]*13
        for i in range(13):
            d2[(i+u)%13]+=d[i]
    for i in range(13):
        d[i]=d2[i]%(10**9+7)
print(d[5])