Problem:
Score : 500 points

Problem Statement

Takahashi has decided to work on K days of his choice from the N days starting with tomorrow.

You are given an integer C and a string S. Takahashi will choose his workdays as follows:

After working for a day, he will refrain from working on the subsequent C days.

If the i-th character of S is x, he will not work on Day i, where Day 1 is tomorrow, Day 2 is the day after tomorrow, and so on.

Find all days on which Takahashi is bound to work.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq K \leq N

0 \leq C \leq N

The length of S is N.

Each character of S is o or x.

Takahashi can choose his workdays so that the conditions in Problem Statement are satisfied.

Input

Input is given from Standard Input in the following format:

N K C
S

Output

Print all days on which Takahashi is bound to work in ascending order, one per line.

Sample Input 1

11 3 2
ooxxxoxxxoo

Sample Output 1

6

Takahashi is going to work on 3 days out of the 11 days. After working for a day, he will refrain from working on the subsequent 2 days.

There are four possible choices for his workdays: Day 1,6,10, Day 1,6,11, Day 2,6,10, and Day 2,6,11.

Thus, he is bound to work on Day 6.

Sample Input 2

5 2 3
ooxoo

Sample Output 2

1
5

There is only one possible choice for his workdays: Day 1,5.

Sample Input 3

5 1 0
ooooo

Sample Output 3

There may be no days on which he is bound to work.

Sample Input 4

16 4 3
ooxxoxoxxxoxoxxo

Sample Output 4

11
16

Solution in PyPy3 (2.4.0) (judge verdict: Accepted)

#ライブラリインポート
from collections import defaultdict

con = 10 ** 9 + 7
#入力受け取り
def getlist():
	return list(map(int, input().split()))

#処理内容
def main():
	N, K, C = getlist()
	S = list(input())
	D1 = defaultdict(int)
	D2 = defaultdict(int)
	var = - float("inf")
	cnt = 0
	for i in range(N):
		if S[i] == "o":
			if i - var >= C + 1:
				cnt += 1
				var = i
				D1[i] += 1

	if cnt >= K + 1:
		return

	#詰める
	var = float("inf")
	cnt = 0
	for i in range(N):
		if S[N - 1 - i] == "o":
			if var - (N - 1 - i) >= C + 1:
				cnt += 1
				var = N - 1 - i
				D2[N - 1 - i] += 1

	# print(D1)
	# print(D2)

	ans = []
	for i in D1:
		if D2[i] == 1:
			ans.append(i)

	ans = sorted(ans)
	for i in ans:
		print(i + 1)

if __name__ == '__main__':
	main()