Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Python (3.4.3) (judge verdict: Accepted)

import sys
import math
input = sys.stdin.readline

# int = int(input())
# s = input().split()
# i = list(map(int, input().split()))
# s = [input() for i in range(3)]

a1 = list(map(int, input().split()))
a2 = list(map(int, input().split()))
a3 = list(map(int, input().split()))

b1 = [a1[0], a2[0], a3[0]]
b2 = [a1[1], a2[1], a3[1]]
b3 = [a1[2], a2[2], a3[2]]

c1 = [a1[0], a2[1], a3[2]]
c2 = [a1[2], a2[1], a3[0]]

n = int(input())
s = [int(input()) for i in range(n)]

ca1 = 0
ca2 = 0
ca3 = 0
cb1 = 0
cb2 = 0
cb3 = 0
cc1 = 0
cc2 = 0
for x in s:
    if x in a1:
        ca1+=1
    if x in a2:
        ca2+=1
    if x in a3:
        ca3+=1
    if x in b1:
        cb1+=1
    if x in b2:
        cb2+=1
    if x in b3:
        cb3+=1
    if x in c1:
        cc1+=1
    if x in c2:
        cc2+=1

if ca1 == 3:
    print("Yes")
elif ca2 == 3:
    print("Yes")
elif ca3 == 3:
    print("Yes")
elif cb1 == 3:
    print("Yes")
elif cb2 == 3:
    print("Yes")
elif cb3 == 3:
    print("Yes")
elif cc1 == 3:
    print("Yes")
elif cc2 == 3:
    print("Yes")
else:
    print("No")