Problem:
﻿Score: 100 points

Problem Statement

In AtCoder city, there are five antennas standing in a straight line. They are called Antenna A, B, C, D and E from west to east, and their coordinates are a, b, c, d and e, respectively.

Two antennas can communicate directly if the distance between them is k or less, and they cannot if the distance is greater than k.

Determine if there exists a pair of antennas that cannot communicate directly.

Here, assume that the distance between two antennas at coordinates p and q (p < q) is q - p.

Constraints

a, b, c, d, e and k are integers between 0 and 123 (inclusive).

a < b < c < d < e

Input

Input is given from Standard Input in the following format:

a
b
c
d
e
k

Output

Print :( if there exists a pair of antennas that cannot communicate directly, and print Yay! if there is no such pair.

Sample Input 1

1
2
4
8
9
15

Sample Output 1

Yay!

In this case, there is no pair of antennas that cannot communicate directly, because:

the distance between A and B is 2 - 1 = 1

the distance between A and C is 4 - 1 = 3

the distance between A and D is 8 - 1 = 7

the distance between A and E is 9 - 1 = 8

the distance between B and C is 4 - 2 = 2

the distance between B and D is 8 - 2 = 6

the distance between B and E is 9 - 2 = 7

the distance between C and D is 8 - 4 = 4

the distance between C and E is 9 - 4 = 5

the distance between D and E is 9 - 8 = 1

and none of them is greater than 15. Thus, the correct output is Yay!.

Sample Input 2

15
18
26
35
36
18

Sample Output 2

:(

In this case, the distance between antennas A and D is 35 - 15 = 20 and exceeds 18, so they cannot communicate directly.
Thus, the correct output is :(.

Solution in Python (3.4.3) (judge verdict: Runtime Error)

import math
a = int(input())
b = int(input())
c = int(input())
d = int(input())
e = int(input())
if a >= 100:
    a1 = a % 10
else:
    a2 = a - 100
    a1 = a2 % 10
if b >= 100:
    b1 = b % 10
else:
    b2 = b - 100
    b1 = b2 % 10
if c >= 100:
    c1 = c % 10
else:
    c2 = c - 100
    c1 = c2 % 10
if d >= 100:
    d1 = d % 10
else:
    d2 = d - 100
    d1 = d2 % 10
if e >= 100:
    e1 = e % 10
else:
    e2 = e - 100
    e1 = e2 % 10
if a1 == 0:
    a1 = 9
if b1 == 0:
    b1 = 9
if c1 == 0:
    c1 = 9
if d1 == 0:
    a1 = 9
if e1 == 0:
    e1 = 9
lis = [a1,b1,c1,d1,e1]
if a1 == min(lis) :
    answer = math.ceil(b / 10) * 10 + math.ceil(c/ 10) * 10 + math.ceil(e/ 10* 10+ math.ceil(d/ 10 * 10 + a
if b1 == min(lis):
    answer = math.ceil(a/ 10)* 10 + math.ceil(c/ 10)* 10 + math.ceil(e/ 10)* 10 + math.ceil(d/ 10)* 10 + b
if c1 == min(lis):
    answer = math.ceil(b/ 10)* 10 + math.ceil(a/ 10)* 10 + math.ceil(e/ 10)* 10 + math.ceil(d/ 10)* 10 + c
if d1 == min(lis):
    answer = math.ceil(b/ 10)* 10 + math.ceil(c/ 10)* 10 + math.ceil(e/ 10)* 10 + math.ceil(a/ 10)* 10 + d
if e1 == min(lis):
    answer = math.ceil(b/ 10)* 10 + math.ceil(c/ 10)* 10 + math.ceil(e/ 10)* 10 + math.ceil(a/ 10)* 10 + e
print(answer)