Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length N. The i-th term in the sequence is a_i.
In one operation, you can select a term and either increment or decrement it by one.

At least how many operations are necessary to satisfy the following conditions?

For every i (1≤i≤n), the sum of the terms from the 1-st through i-th term is not zero.

For every i (1≤i≤n-1), the sign of the sum of the terms from the 1-st through i-th term, is different from the sign of the sum of the terms from the 1-st through (i+1)-th term.

Constraints

2 ≤ n ≤ 10^5

|a_i| ≤ 10^9

Each a_i is an integer.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print the minimum necessary count of operations.

Sample Input 1

4
1 -3 1 0

Sample Output 1

4

For example, the given sequence can be transformed into 1, -2, 2, -2 by four operations. The sums of the first one, two, three and four terms are 1, -1, 1 and -1, respectively, which satisfy the conditions.

Sample Input 2

5
3 -6 4 -5 7

Sample Output 2

0

The given sequence already satisfies the conditions.

Sample Input 3

6
-1 4 3 2 -5 4

Sample Output 3

8

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

n = int(input())
list_a = list(map(int, input().split()))

sum_a = list_a[0]
count_t = 0
if sum_a < 0:
  count_t += 1 + abs(sum_a)
for i in range(1, n):
  if sum_a > 0:
    if sum_a + list_a[i] >= 0:
      diff = abs(-1 - list_a[i] - sum_a)
    else:
      diff = 0
    sum_a = sum_a + list_a[i] - diff
    count_t += diff
  else:
    if sum_a + list_a[i] <= 0:
      diff = abs(1 - sum_a - list_a[i])
    else:
      diff = 0
    sum_a = sum_a + list_a[i] + diff
    count_t += diff

sum_a = list_a[0]
count_f = 0
if sum_a > 0:
  count_f += 1 + abs(sum_a)
for i in range(1, n):
  if sum_a > 0:
    if sum_a + list_a[i] >= 0:
      diff = abs(-1 - list_a[i] - sum_a)
    else:
      diff = 0
    sum_a = sum_a + list_a[i] - diff
    count_f += diff
  else:
    if sum_a + list_a[i] <= 0:
      diff = abs(1 - sum_a - list_a[i])
    else:
      diff = 0
    sum_a = sum_a + list_a[i] + diff
    count_f += diff
    
print(min(count_t, count_f))