Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Python (3.8.2) (judge verdict: Accepted)

def make_divisors(n):
    lower, upper = [], []
    i = 1
    while i*i <= n:
        if n % i == 0:
            lower.append(i)
            if i != n // i:
                upper.append(n//i)
        i += 1
    return lower + upper[::-1]

cnt = 0
for i in range(1, int(input())+1, 2):
    if len(make_divisors(i)) == 8:
        cnt += 1
print(cnt)