Problem:
Score: 300 points

Problem Statement

In Republic of Atcoder, there are N prefectures, and a total of M cities that belong to those prefectures.

City i is established in year Y_i and belongs to Prefecture P_i.

You can assume that there are no multiple cities that are established in the same year.

It is decided to allocate a 12-digit ID number to each city.

If City i is the x-th established city among the cities that belong to Prefecture i, the first six digits of the ID number of City i is P_i, and the last six digits of the ID number is x.

Here, if P_i or x (or both) has less than six digits, zeros are added to the left until it has six digits.

Find the ID numbers for all the cities.

Note that there can be a prefecture with no cities.

Constraints

1 \leq N \leq 10^5

1 \leq M \leq 10^5

1 \leq P_i \leq N

1 \leq Y_i \leq 10^9

Y_i are all different.

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N M
P_1 Y_1
:
P_M Y_M

Output

Print the ID numbers for all the cities, in ascending order of indices (City 1, City 2, ...).

Sample Input 1

2 3
1 32
2 63
1 12

Sample Output 1

000001000002
000002000001
000001000001

As City 1 is the second established city among the cities that belong to Prefecture 1, its ID number is 000001000002.

As City 2 is the first established city among the cities that belong to Prefecture 2, its ID number is 000002000001.

As City 3 is the first established city among the cities that belong to Prefecture 1, its ID number is 000001000001.

Sample Input 2

2 3
2 55
2 77
2 99

Sample Output 2

000002000001
000002000002
000002000003

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

N, M = map(int, input().split())
PY = [list(map(int, input().split())) for i in range(M)]

convertedPY = [
    {'index': i,
     'city': py[0],
     'year': py[1]
     } for i, py in enumerate(PY)
]

convertedPY = sorted(convertedPY, key=lambda a: (a['city'], a['year']))
answer = []
cnt = 1
tmp = convertedPY[0]['city']
#print(convertedPY)
result = []
for py in convertedPY:
    temp_dict ={}
    if tmp == py['city']:
        temp_dict['answer'] = '{:0=6}'.format(py['city']) + '{:0=6}'.format(cnt)
        temp_dict['index'] = py['index']
        result.append(temp_dict)
        cnt += 1
    else:
        cnt = 1
        temp_dict['answer'] = '{:0=6}'.format(py['city']) + '{:0=6}'.format(cnt)
        temp_dict['index'] = py['index']
        result.append(temp_dict)

#print(result)
result = sorted(result, key=lambda a: a['index'])

for r in result:
    print(r['answer'])