Problem:
Score : 200 points

Problem Statement

Let us define the FizzBuzz sequence a_1,a_2,... as follows:

If both 3 and 5 divides i, a_i=\mbox{FizzBuzz}.

If the above does not hold but 3 divides i, a_i=\mbox{Fizz}.

If none of the above holds but 5 divides i, a_i=\mbox{Buzz}.

If none of the above holds, a_i=i.

Find the sum of all numbers among the first N terms of the FizzBuzz sequence.

Constraints

1 \leq N \leq 10^6

Input

Input is given from Standard Input in the following format:

N

Output

Print the sum of all numbers among the first N terms of the FizzBuzz sequence.

Sample Input 1

15

Sample Output 1

60

The first 15 terms of the FizzBuzz sequence are:

1,2,\mbox{Fizz},4,\mbox{Buzz},\mbox{Fizz},7,8,\mbox{Fizz},\mbox{Buzz},11,\mbox{Fizz},13,14,\mbox{FizzBuzz}

Among them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.

Sample Input 2

1000000

Sample Output 2

266666333332

Watch out for overflow.

Solution in PyPy3 (7.3.0) (judge verdict: Accepted)

# coding: utf-8

import sys
import math
import collections
import itertools
INF = 10 ** 13
MOD = 10 ** 9 + 7
def input() : return sys.stdin.readline().strip()
def lcm(x, y) : return (x * y) // math.gcd(x, y)
def I() : return int(input())
def LI() : return [int(x) for x in input().split()]
def RI(N) : return [int(input()) for _ in range(N)]
def LRI(N) : return [[int(x) for x in input().split()] for _ in range(N)]
def LS() : return input().split()
def RS(N) : return [input() for _ in range(N)]
def LRS(N) : return [input().split() for _ in range(N)]
def PL(L) : print(*L, sep="\n")

N = I()

ans = 0
for i in range(1, N+1):
    if i % 3 == 0 or i % 5 == 0:
        continue
    else:
        ans += i

print(ans)