Problem:
Score : 300 points

Problem Statement

There are N people numbered 1 to N. Each of them is either an honest person whose testimonies are always correct or an unkind person whose testimonies may be correct or not.

Person i gives A_i testimonies. The j-th testimony by Person i is represented by two integers x_{ij} and y_{ij}. If y_{ij} = 1, the testimony says Person x_{ij} is honest; if y_{ij} = 0, it says Person x_{ij} is unkind.

How many honest persons can be among those N people at most?

Constraints

All values in input are integers.

1 \leq N \leq 15

0 \leq A_i \leq N - 1

1 \leq x_{ij} \leq N

x_{ij} \neq i

x_{ij_1} \neq x_{ij_2} (j_1 \neq j_2)

y_{ij} = 0, 1

Input

Input is given from Standard Input in the following format:

N
A_1
x_{11} y_{11}
x_{12} y_{12}
:
x_{1A_1} y_{1A_1}
A_2
x_{21} y_{21}
x_{22} y_{22}
:
x_{2A_2} y_{2A_2}
:
A_N
x_{N1} y_{N1}
x_{N2} y_{N2}
:
x_{NA_N} y_{NA_N}

Output

Print the maximum possible number of honest persons among the N people.

Sample Input 1

3
1
2 1
1
1 1
1
2 0

Sample Output 1

2

If Person 1 and Person 2 are honest and Person 3 is unkind, we have two honest persons without inconsistencies, which is the maximum possible number of honest persons.

Sample Input 2

3
2
2 1
3 0
2
3 1
1 0
2
1 1
2 0

Sample Output 2

0

Assuming that one or more of them are honest immediately leads to a contradiction.

Sample Input 3

2
1
2 0
1
1 0

Sample Output 3

1

Solution in PyPy3 (2.4.0) (judge verdict: Wrong Answer)

N=int(input())
ans=0
katei=0
#katei[2:]
shou=[]
for i in range(N):
    n=int(input())
    tmp=[]
    for _ in range(n):
        h=list(map(int,input().split()))
        h[0]-=1
        tmp.append(h)
    shou.append(tmp)
#print(shou)
for i in range(2**N):
    flag=True
    tmp=str(bin(katei))[2:].zfill(N)
    #print(tmp)
    #print()
    for j in range(N):
        #print(tmp[j])
        for k in shou[j]:
            #print(k)
            
            if tmp[j]=="0":
                if tmp[k[0]]==str(k[1]):
                    #print("false")
                    flag=False
            else:
                if tmp[k[0]]==str(1-k[1]):
                    #print("falkse")
                    flag=False
            #print(state)
    if flag:
        #print("collect:",tmp)
        ans=max(ans,bin(katei).count("1"))
            
            
    katei+=1
print(ans)