Problem:
Score : 300 points

Problem Statement

"Pizza At", a fast food chain, offers three kinds of pizza: "A-pizza", "B-pizza" and "AB-pizza". A-pizza and B-pizza are completely different pizzas, and AB-pizza is one half of A-pizza and one half of B-pizza combined together. The prices of one A-pizza, B-pizza and AB-pizza are A yen, B yen and C yen (yen is the currency of Japan), respectively.

Nakahashi needs to prepare X A-pizzas and Y B-pizzas for a party tonight. He can only obtain these pizzas by directly buying A-pizzas and B-pizzas, or buying two AB-pizzas and then rearrange them into one A-pizza and one B-pizza. At least how much money does he need for this? It is fine to have more pizzas than necessary by rearranging pizzas.

Constraints

1 ≤ A, B, C ≤ 5000

1 ≤ X, Y ≤ 10^5

All values in input are integers.

Input

Input is given from Standard Input in the following format:

A B C X Y

Output

Print the minimum amount of money required to prepare X A-pizzas and Y B-pizzas.

Sample Input 1

1500 2000 1600 3 2

Sample Output 1

7900

It is optimal to buy four AB-pizzas and rearrange them into two A-pizzas and two B-pizzas, then buy additional one A-pizza.

Sample Input 2

1500 2000 1900 3 2

Sample Output 2

8500

It is optimal to directly buy three A-pizzas and two B-pizzas.

Sample Input 3

1500 2000 500 90000 100000

Sample Output 3

100000000

It is optimal to buy 200000 AB-pizzas and rearrange them into 100000 A-pizzas and 100000 B-pizzas. We will have 10000 more A-pizzas than necessary, but that is fine.

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

I = input().split(" ")
A = int(I[0])
B = int(I[1])
C = int(I[2])
X = int(I[3])
Y = int(I[4])

r = 0

if B >= 2*C:
    if A >= 2*C:
        if X >= Y:
            r = X*C*2
        else:
            r = Y*C*2
    else:
        if X > Y:
            r += Y*C*2
            n = X-Y
            r += n*B
        else:
            r = Y*C*2
elif A >= 2*C:
    if B >= 2*C:
        if X >= Y:
            r = X*C*2
        else:
            r = Y*C*2
    else:
        if Y > X:
            r += X*C*2
            n = Y-X
            r += n*B
        else:
            r = X*C*2
elif B + A >= 2*C:
    if X <= Y:
        r += X*C*2
        n = Y-X
        r += n*B
    else:
        r += Y*C*2
        n = X-Y
        r += n*A
else:
    r += A*X        
    r += B*Y

print(r)