Problem:
Score : 400 points

Problem Statement

There are N squares arranged in a row, numbered 1, 2, ..., N from left to right.
You are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.

You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

4 \leq N \leq 200\ 000

S is a string of length N consisting of . and #.

1 \leq A, B, C, D \leq N

Square A, B, C and D do not contain a rock.

A, B, C and D are all different.

A < B

A < C

B < D

Input

Input is given from Standard Input in the following format:

N A B C D
S

Output

Print Yes if the objective is achievable, and No if it is not.

Sample Input 1

7 1 3 6 7
.#..#..

Sample Output 1

Yes

The objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)

A#B.#..

A#.B#..

.#AB#..

.#A.#B.

.#.A#B.

.#.A#.B

.#..#AB

Sample Input 2

7 1 3 7 6
.#..#..

Sample Output 2

No

Sample Input 3

15 1 3 15 13
...#.#...#.#...

Sample Output 3

Yes

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

# 入力が10**5とかになったときに100ms程度早い
import sys
read = sys.stdin.readline


def read_ints():
    return list(map(int, read().split()))


def read_a_int():
    return int(read())


def read_matrix(H):
    '''
    H is number of rows
    '''
    return [list(map(int, read().split())) for _ in range(H)]


def read_map(H):
    '''
    H is number of rows
    文字列で与えられた盤面を読み取る用
    '''
    return [read()[:-1] for _ in range(H)]


def read_col(H, n_cols):
    '''
    H is number of rows
    n_cols is number of cols

    A列、B列が与えられるようなとき
    '''
    ret = [[] for _ in range(n_cols)]
    for _ in range(H):
        tmp = list(map(int, read().split()))
        for col in range(n_cols):
            ret[col].append(tmp[col])

    return ret


N, A, B, C, D = read_ints()
S = input()

A -= 1
B -= 1
C -= 1
D -= 1
# 大小関係の実装
planA = True  # ひっくり返らない処理がA
if D < C:
    planA = False

from sys import exit

# 入れ替わるかの条件ごとに実装する
if planA:
    s = min(A, B, C, D)
    g = max(A, B, C, D)
    for s_left, s_right in zip(S[s:g-1], S[s + 1:g]):
        if s_left == '#' and s_right == '#':
            print('No')
            exit()
    print('Yes')
else:
    # planAでない。つまり入れ替わる場合
    s = min(A, B, C, D)
    g = max(A, B, C, D)
    for s_left, s_right in zip(S[s:g-1], S[s + 1:g]):
        if s_left == '#' and s_right == '#':
            print('No')
            exit()
    for s_left, s_center, s_right in zip(S[B:D - 1], S[B + 1:D], S[B + 2:D + 1]):
        if s_left == '.' and s_center == '.' and s_right == '.':
            print('Yes')
            exit()
    print('No')