Problem:
Score : 500 points

Problem Statement

There is a building with n rooms, numbered 1 to n.

We can move from any room to any other room in the building.

Let us call the following event a move: a person in some room i goes to another room j~ (i \neq j).

Initially, there was one person in each room in the building.

After that, we know that there were exactly k moves happened up to now.

We are interested in the number of people in each of the n rooms now. How many combinations of numbers of people in the n rooms are possible?

Find the count modulo (10^9 + 7).

Constraints

All values in input are integers.

3 \leq n \leq 2 \times 10^5

2 \leq k \leq 10^9

Input

Input is given from Standard Input in the following format:

n k

Output

Print the number of possible combinations of numbers of people in the n rooms now, modulo (10^9 + 7).

Sample Input 1

3 2

Sample Output 1

10

Let c_1, c_2, and c_3 be the number of people in Room 1, 2, and 3 now, respectively. There are 10 possible combination of (c_1, c_2, c_3):

(0, 0, 3)

(0, 1, 2)

(0, 2, 1)

(0, 3, 0)

(1, 0, 2)

(1, 1, 1)

(1, 2, 0)

(2, 0, 1)

(2, 1, 0)

(3, 0, 0)

For example, (c_1, c_2, c_3) will be (0, 1, 2) if the person in Room 1 goes to Room 2 and then one of the persons in Room 2 goes to Room 3.

Sample Input 2

200000 1000000000

Sample Output 2

607923868

Print the count modulo (10^9 + 7).

Sample Input 3

15 6

Sample Output 3

22583772

Solution in Python (3.4.3) (judge verdict: Wrong Answer)

n, k = map(int, input().split())
mod = 10**9 + 7

#def combination(a,b):
#	out = 1
#	b = min(a-b,b)
#	for q in range(a-b+1, a+1):
#		out *= q
#		out %= mod

#	for q in range(1,b+1):
#		out *= pow(q, mod-2, mod)

#	out %= mod

#	return out




ans = 1
comb = 1
for i in range(1, min(n, k+1)):
	comb *= (n-i+1)
	comb %= mod
	comb *= pow(i, mod-2, mod)
	comb %= mod

	tmp = 1
	tmp *= comb
	tmp *= pow(n-i, i, mod)
	tmp %= mod
	ans += tmp
	ans %= mod
ans %= mod
print(ans)