Problem:
Score : 100 points

Problem Statement

You are given positive integers A and B.

If A is a divisor of B, print A + B; otherwise, print B - A.

Constraints

All values in input are integers.

1 \leq A \leq B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

If A is a divisor of B, print A + B; otherwise, print B - A.

Sample Input 1

4 12

Sample Output 1

16

As 4 is a divisor of 12, 4 + 12 = 16 should be printed.

Sample Input 2

8 20

Sample Output 2

12

Sample Input 3

1 1

Sample Output 3

2

1 is a divisor of 1.

Solution in PyPy3 (2.4.0) (judge verdict: Runtime Error)

import bisect

f_inf = float('inf')


def cal(syurui, d, index):
    if d == 'e':
        return syurui[index]
    elif d == 'w':
        return syurui[index - 1]


A, B, Q = map(int, input().split())
s = [int(input()) for i in range(A)]
s.sort()
t = [int(input()) for i in range(B)]
t.sort()

for i in range(Q):
    x = int(input())
    s_index = bisect.bisect_left(s, x)
    t_index = bisect.bisect_left(t, x)
    if s_index == len(s) and t_index == len(t):
        print(max(abs(x-s[s_index-1]), abs(x-t[t_index-1])))
    elif s_index == len(s):
        ｓ.insert(0, -f_inf)
        t.insert(0, -f_inf)
        print(min(max(abs(x-s[s_index]), abs(x-t[t_index])),
                  2*abs(x-s[s_index])+abs(x-t[t_index+1]), abs(x-s[s_index])+2*abs(x-t[t_index+1])))
    elif t_index == len(t):
        ｓ.insert(0, -f_inf)
        t.insert(0, -f_inf)
        print(min(max(abs(x-s[s_index]), abs(x-t[t_index])), 2*abs(x-s[s_index+1])+abs(x-t[t_index]),
                  abs(x-s[s_index+1])+2*abs(x-t[t_index])))
    else:
        ｓ.insert(0, -f_inf)
        t.insert(0, -f_inf)
        print(min(max(abs(x-s[s_index]), abs(x-t[t_index])), max(
            abs(x-s[s_index+1]), abs(x-t[t_index+1])), 2*abs(x-s[s_index+1])+abs(x-t[t_index]), 2*abs(x-s[s_index])+abs(x-t[t_index+1]), abs(x-s[s_index+1])+2*abs(x-t[t_index]), abs(x-s[s_index])+2*abs(x-t[t_index+1])))