Problem:
Disjoint Set

Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.

same(x, y): determine whether x and y are in the same set.

Input

n q
com1 x1 y1
com2 x2 y2
...
comq xq yq

In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Constraints

1 ≤ n ≤ 10000

1 ≤ q ≤ 100000

x ≠ y

Sample Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0

Sample Output

0
0
1
1
1
0
1
1

Solution in Python3 (judge verdict: Wrong Answer)

# ?????????O(n)????????£?????????
class union_find(object):
 	"""union-find tree"""
 	def __init__(self, length):
 		self.length = length
 		self.unionnumber=0
 		self.unionlist=[[]]
 		self.num=list(-1 for i in range(length))

 	def unite(self,i,j):
 		if self.num[i]==-1:
 			if self.num[j]==-1:
 				self.unionlist[self.unionnumber].extend([i,j])
 				self.num[i]=self.unionnumber
 				self.num[j]=self.unionnumber
 				self.unionnumber+=1
 				self.unionlist.append([])
 			else:
 				tmp=i 
 				i=j 
 				j=tmp 
 		if self.num[i]!=-1:
 			if self.num[j]!=-1:
 				if self.num[i]==self.num[j]:
 					pass
 				else:
 					self.unionlist[self.num[i]].extend(self.unionlist[self.num[j]])
 					tmp=self.num[j]
 					for k in self.unionlist[self.num[j]]:
 						self.num[k]=self.num[i]
 					self.unionlist[tmp]="del"
 			else:
 				self.num[j]=self.num[i]
 				self.unionlist[self.num[i]].append(j)

 	def same(self,i,j):
 		if self.num[i]==-1 or self.num[j]==-1:
 			return(False)
 		else:
 			return(self.num[i]==self.num[j])


n,m=input().split()
n=int(n)
m=int(m)

l=[]
union=union_find(n)
for i in range(m):
	com,a,b=input().split()
	a=int(a)
	b=int(b)
	if com=="unite":
		union.unite(a,b)
	else:
		if union.same(a,b):
			print(1)
		else:
			print(0)