Problem:
Score : 600 points

Problem Statement

Snuke has an integer sequence, a, of length N. The i-th element of a (1-indexed) is a_{i}.

He can perform the following operation any number of times:

Operation: Choose integers x and y between 1 and N (inclusive), and add a_x to a_y.

He would like to perform this operation between 0 and 2N times (inclusive) so that a satisfies the condition below. Show one such sequence of operations.
It can be proved that such a sequence of operations always exists under the constraints in this problem.

Condition: a_1 \leq a_2 \leq ... \leq a_{N}

Constraints

2 \leq N \leq 50

-10^{6} \leq a_i \leq 10^{6}

All input values are integers.

Input

Input is given from Standard Input in the following format:

N
a_1 a_2 ... a_{N}

Output

Let m be the number of operations in your solution. In the first line, print m.
In the i-th of the subsequent m lines, print the numbers x and y chosen in the i-th operation, with a space in between.
The output will be considered correct if m is between 0 and 2N (inclusive) and a satisfies the condition after the m operations.

Sample Input 1

3
-2 5 -1

Sample Output 1

2
2 3
3 3

After the first operation, a = (-2,5,4).

After the second operation, a = (-2,5,8), and the condition is now satisfied.

Sample Input 2

2
-1 -3

Sample Output 2

1
2 1

After the first operation, a = (-4,-3) and the condition is now satisfied.

Sample Input 3

5
0 0 0 0 0

Sample Output 3

0

The condition is satisfied already in the beginning.

Solution in Python (3.4.3) (judge verdict: Runtime Error)

import numpy as np
N = int(input())
A = np.array([int(x) for x in input().split()])
mi= np.min(A)
ma= np.max(A)
mai = np.where(A==ma)
mii = np.where(A==mi)
ans = []
if ma<=0 and mi<=0:
  for i in range(N,1,-1):
    ans.append((i,i-1))
  print(len(ans))
  for i in range(len(ans)):
    print(*ans[i])
  exit()
if ma>=0 and mi>=0:
  for i in range(1,N):
    ans.append((i,i+1))
  print(len(ans))
  for i in range(len(ans)):
    print(*ans[i])
  exit()

if abs(mi)<=abs(ma):
  ans= [(int(mai[0])+1,i) for i in range(1,N+1)]
  for i in range(1,N):
    ans.append((i,i+1))
  print(len(ans))
  for i in range(len(ans)):
    print(*ans[i])
  exit()
else:
  ans= [(int(mii[0])+1,i) for i in range(1,N+1)]
  for i in range(N,1,-1):
    ans.append((i,i-1))
  print(len(ans))
  for i in range(len(ans)):
    print(*ans[i])
  exit()