Problem:
Counting Characters

Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Input

A sentence in English is given in several lines.

Output

Prints the number of alphabetical letters in the following format:

a : The number of 'a'
b : The number of 'b'
c : The number of 'c'
.
.
z : The number of 'z'

Constraints

The number of characters in the sentence < 1200

Sample Input

This is a pen.

Sample Output

a : 1
b : 0
c : 0
d : 0
e : 1
f : 0
g : 0
h : 1
i : 2
j : 0
k : 0
l : 0
m : 0
n : 1
o : 0
p : 1
q : 0
r : 0
s : 2
t : 1
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0

Solution in Python (judge verdict: Wrong Answer)

I_list=[]
alphabet="abcdefghijklmnopqrstuvwxyz"
dic_cnt={"a":0,"b":0,"c":0,"d":0,"e":0,
         "f":0,"g":0,"h":0,"i":0,"j":0,
         "k":0,"l":0,"m":0,"n":0,"o":0,
         "p":0,"q":0,"r":0,"s":0,"t":0,
         "u":0,"v":0,"w":0,"x":0,"y":0,
         "z":0
         }
while True:
	try:
		k=raw_input()
	except:
		break
	for i in k:
		I_list.append(i.lower())
	for i in alphabet:
		dic_cnt[i]+=I_list.count(i)
	
	
for i in alphabet:
	print i,
	print ":",
	print dic_cnt[i]