Problem:
Score : 400 points

Problem Statement

There are N people standing on the x-axis.
Let the coordinate of Person i be x_i.
For every i, x_i is an integer between 0 and 10^9 (inclusive).
It is possible that more than one person is standing at the same coordinate.

You will given M pieces of information regarding the positions of these people.
The i-th piece of information has the form (L_i, R_i, D_i).
This means that Person R_i is to the right of Person L_i by D_i units of distance, that is, x_{R_i} - x_{L_i} = D_i holds.

It turns out that some of these M pieces of information may be incorrect.
Determine if there exists a set of values (x_1, x_2, ..., x_N) that is consistent with the given pieces of information.

Constraints

1 \leq N \leq 100 000

0 \leq M \leq 200 000

1 \leq L_i, R_i \leq N (1 \leq i \leq M)

0 \leq D_i \leq 10 000 (1 \leq i \leq M)

L_i \neq R_i (1 \leq i \leq M)

If i \neq j, then (L_i, R_i) \neq (L_j, R_j) and (L_i, R_i) \neq (R_j, L_j).

D_i are integers.

Input

Input is given from Standard Input in the following format:

N M
L_1 R_1 D_1
L_2 R_2 D_2
:
L_M R_M D_M

Output

If there exists a set of values (x_1, x_2, ..., x_N) that is consistent with all given pieces of information, print Yes; if it does not exist, print No.

Sample Input 1

3 3
1 2 1
2 3 1
1 3 2

Sample Output 1

Yes

Some possible sets of values (x_1, x_2, x_3) are (0, 1, 2) and (101, 102, 103).

Sample Input 2

3 3
1 2 1
2 3 1
1 3 5

Sample Output 2

No

If the first two pieces of information are correct, x_3 - x_1 = 2 holds, which is contradictory to the last piece of information.

Sample Input 3

4 3
2 1 1
2 3 5
3 4 2

Sample Output 3

Yes

Sample Input 4

10 3
8 7 100
7 9 100
9 8 100

Sample Output 4

No

Sample Input 5

100 0

Sample Output 5

Yes

Solution in Python (3.4.3) (judge verdict: Accepted)

import sys
input = sys.stdin.readline

class WeightedUnionfind:

    __slots__ = ['nodes','diff_weight']

    def __init__(self, n):
        self.nodes = [-1]*n
        self.diff_weight = [0]*n

    def root(self, x):
        if self.nodes[x] < 0:
            return x
        else:
            root_x = self.root(self.nodes[x])
            self.diff_weight[x] += self.diff_weight[self.nodes[x]]
            self.nodes[x] = root_x
            return root_x

    def unite(self, x, y, w=0):
        w += self.weight(x); w -= self.weight(y)
        x = self.root(x); y = self.root(y)
        if x == y:
            return
        size_x = -self.nodes[x]; size_y = -self.nodes[y]
        if size_x < size_y:
            x, y = y, x; w = -w
        self.nodes[x] += self.nodes[y]
        self.nodes[y] = x
        self.diff_weight[y] = w

    def weight(self, x):
        self.root(x)
        return self.diff_weight[x]

    def diff(self, x, y):
        return self.weight(y) - self.weight(x)

    def same(self, x, y):
        return self.root(x) == self.root(y)

    def size(self, x):
        return -self.nodes[self.root(x)]

N,M = map(int,input().split())
wuf = WeightedUnionfind(N)
ans = "Yes"
for _ in range(M):
    L,R,D = map(int,input().split())
    L -= 1; R -= 1
    if not wuf.same(L,R):
        wuf.unite(L,R,D)
    else:
        if wuf.diff(L,R) != D:
            ans = "No"
            break
print(ans)