Problem:
Score : 400 points

Problem Statement

You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

In the i-th operation, you replace every element whose value is B_{i} with C_{i}.

For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

All values in input are integers.

1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}

B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:

N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}

Output

Print Q integers S_{i} to Standard Output in the following format:

S_{1}
S_{2}
\vdots
S_{Q}

Note that S_{i} may not fit into a 32-bit integer.

Sample Input 1

4
1 2 3 4
3
1 2
3 4
2 4

Sample Output 1

11
12
16

Initially, the sequence A is 1,2,3,4.

After each operation, it becomes the following:

2, 2, 3, 4

2, 2, 4, 4

4, 4, 4, 4

Sample Input 2

4
1 1 1 1
3
1 2
2 1
3 5

Sample Output 2

8
4
4

Note that the sequence A may not contain an element whose value is B_{i}.

Sample Input 3

2
1 2
3
1 100
2 100
100 1000

Sample Output 3

102
200
2000

Solution in Python (3.8.2) (judge verdict: Wrong Answer)

# import itertools
# import math
# import sys
# sys.setrecursionlimit(500*500)
# import numpy as np

N = int(input())
# S = input()
# n, *a = map(int, open(0))
# N, M = map(int, input().split())
A = list(map(int, input().split()))
# B = list(map(int, input().split()))
# tree = [[] for _ in range(N + 1)]
# B_C = [list(map(int,input().split())) for _ in range(M)]
# S = input()

# B_C = sorted(B_C, reverse=True, key=lambda x:x[1])
# all_cases = list(itertools.permutations(P))
# a = list(itertools.combinations_with_replacement(range(1, M + 1), N))
# itertools.product((0,1), repeat=n)

# A = np.array(A)
# cum_A = np.cumsum(A)
# cum_A = np.insert(cum_A, 0, 0)

# def dfs(tree, s):
#     for l in tree[s]:
#         if depth[l[0]] == -1:
#             depth[l[0]] = depth[s] + l[1]
#             dfs(tree, l[0])
# dfs(tree, 1)



Q = int(input())
B_C = [list(map(int,input().split())) for _ in range(Q)]

tot = sum(A)
cnt = [0] * 100001
for i in A:
    cnt[i] += 1

# print(cnt[:6])

for l in B_C:
    # print(l)
    cnt[l[1]] += cnt[l[0]]
    tot += cnt[l[0]] * (l[1] - l[0])
    print(tot)