Problem:
Score : 500 points

Problem Statement

Takahashi has decided to work on K days of his choice from the N days starting with tomorrow.

You are given an integer C and a string S. Takahashi will choose his workdays as follows:

After working for a day, he will refrain from working on the subsequent C days.

If the i-th character of S is x, he will not work on Day i, where Day 1 is tomorrow, Day 2 is the day after tomorrow, and so on.

Find all days on which Takahashi is bound to work.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq K \leq N

0 \leq C \leq N

The length of S is N.

Each character of S is o or x.

Takahashi can choose his workdays so that the conditions in Problem Statement are satisfied.

Input

Input is given from Standard Input in the following format:

N K C
S

Output

Print all days on which Takahashi is bound to work in ascending order, one per line.

Sample Input 1

11 3 2
ooxxxoxxxoo

Sample Output 1

6

Takahashi is going to work on 3 days out of the 11 days. After working for a day, he will refrain from working on the subsequent 2 days.

There are four possible choices for his workdays: Day 1,6,10, Day 1,6,11, Day 2,6,10, and Day 2,6,11.

Thus, he is bound to work on Day 6.

Sample Input 2

5 2 3
ooxoo

Sample Output 2

1
5

There is only one possible choice for his workdays: Day 1,5.

Sample Input 3

5 1 0
ooooo

Sample Output 3

There may be no days on which he is bound to work.

Sample Input 4

16 4 3
ooxxoxoxxxoxoxxo

Sample Output 4

11
16

Solution in Python (3.8.2) (judge verdict: Accepted)

import sys
readline = sys.stdin.readline

# もっとも早い日に貪欲に働いたパターン
# もっとも遅い日に貪欲に働いたパターン
# 上記でX回目の仕事が同じ日であればその日は必ず働く必要がある

N,K,C = map(int,readline().split())
S = readline().rstrip()

fast = [0] * K
ind = 0
cnt = 0
while cnt < K: # K回働くまで
  if S[ind] == "o":
    fast[cnt] = ind
    cnt += 1
    ind += (C + 1)
  else:
    ind += 1

late = [0] * K
ind = len(S) - 1
cnt = K - 1
while 0 <= cnt:
  if S[ind] == "o":
    late[cnt] = ind
    cnt -= 1
    ind -= (C + 1)
  else:
    ind -= 1
    
ans = []
for i in range(K):
  if fast[i] == late[i]:
    ans += [fast[i] + 1]
    
for a in ans:
  print(a)