Problem:
Score : 200 points

Problem Statement

For a string S consisting of the uppercase English letters P and D, let the doctoral and postdoctoral quotient of S be the total number of occurrences of D and PD in S as contiguous substrings. For example, if S = PPDDP, it contains two occurrences of D and one occurrence of PD as contiguous substrings, so the doctoral and postdoctoral quotient of S is 3.

We have a string T consisting of P, D, and ?.

Among the strings that can be obtained by replacing each ? in T with P or D, find one with the maximum possible doctoral and postdoctoral quotient.

Constraints

1 \leq |T| \leq 2 \times 10^5

T consists of P, D, and ?.

Input

Input is given from Standard Input in the following format:

T

Output

Print one string with the maximum possible doctoral and postdoctoral quotient among the strings that can be obtained by replacing each ? in T with P or D.
If there are multiple such strings, you may print any of them.

Sample Input 1

PD?D??P

Sample Output 1

PDPDPDP

This string contains three occurrences of D and three occurrences of PD as contiguous substrings, so its doctoral and postdoctoral quotient is 6, which is the maximum doctoral and postdoctoral quotient of a string obtained by replacing each ? in T with P or D.

Sample Input 2

P?P?

Sample Output 2

PDPD

Solution in PyPy3 (7.3.0) (judge verdict: Runtime Error)

T = list(input())
N = len(T)
if T[-1] == "?":
    T[-1] = "D"

if N == 1 and T[0] == "?":
    T[0] = D
elif N == 2:
    if T[0] == "?" and T[1] == "?":
        T[0] = "P"
        T[1] = "D"
                
    elif T[0] == "?" and T[1] == "D":
        T[0] = "P"
                
    elif T[0] == "?" and T[1] == "P":
        T[0] = "D"
        
    elif T[0] == "P" and T[1] == "?":
        T[1] = "D"
elif N > 2:        
    if T[0] == "?" and T[1] == "?":
        T[0] = "P"
        T[1] = "D"
          
    elif T[0] == "?" and T[1] == "D":
        T[0] = "P"
            
    elif T[0] == "?" and T[1] == "P":
        T[0] = "D"
            
    elif T[0] == "D" and T[1] == "?" and T[2] == "D":
        T[1] = "P"
            
    elif T[0] == "D" and T[1] == "?" and T[2] == "P":
        T[1] = "D"
    
    elif T[0] == "P" and T[1] == "?":
        T[1] = "D"
        
    for i in range(2,N-1):
         if T[i-2] == "P" and T[i-1] == "D" and T[i+1] == "D" and T[i] == "?":
            T[i] = "P"
              continue
        elif T[i] == "?":
            T[i] = "D"
        

ans = "".join(T)         
print(ans)