Problem:
Score : 500 points

Problem Statement

Given are N integers A_1,\ldots,A_N.

We will choose exactly K of these elements. Find the maximum possible product of the chosen elements.

Then, print the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).

Constraints

1 \leq K \leq N \leq 2\times 10^5

|A_i| \leq 10^9

Input

Input is given from Standard Input in the following format:

N K
A_1 \ldots A_N

Output

Print the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).

Sample Input 1

4 2
1 2 -3 -4

Sample Output 1

12

The possible products of the two chosen elements are 2, -3, -4, -6, -8, and 12, so the maximum product is 12.

Sample Input 2

4 3
-1 -2 -3 -4

Sample Output 2

1000000001

The possible products of the three chosen elements are -24, -12, -8, and -6, so the maximum product is -6.

We print this value modulo (10^9+7), that is, 1000000001.

Sample Input 3

2 1
-1 1000000000

Sample Output 3

1000000000

The possible products of the one chosen element are -1 and 1000000000, so the maximum product is 1000000000.

Sample Input 4

10 10
1000000000 100000000 10000000 1000000 100000 10000 1000 100 10 1

Sample Output 4

999983200

Be sure to print the product modulo (10^9+7).

Solution in Python (3.8.2) (judge verdict: Runtime Error)

from collections import deque

N, K = map(int, input().split())
A = list(map(int, input().split()))
MOD = 10**9 + 7

P = [a for a in A if a >= 0]
N = [a for a in A if a < 0]

def canPositive():
    for i in range(0, len(N) + 1, 2):
        p = K - i
        if p < 0:
            break
        if len(P) >= p:
            return True
    return False

if not canPositive():
    A.sort(key=lambda a: abs(a))
    ans = 1
    for a in A[:K]:
        ans *= a
        ans %= MOD
    print(ans)
    exit()

P.sort(key=lambda a: abs(a))
N.sort(key=lambda a: abs(a))
P = deque(P)
N = deque(N)

ans = 1
while K > 0:
    ans %= MOD
    if ans == 0:
        break
    if K == 1:
        if ans < 0:
            ans *= N.pop()
        else:
            ans *= P.pop()
        break

    if len(P) >= 2 and len(N) >= 2:
        p = P[-1] * P[-2]
        n = N[-1] * N[-2]
        if p > n:
            ans *= P.pop() * P.pop()
        else:
            ans *= N.pop() * N.pop()
        K -= 2
        continue
    if len(P) <= 1 or len(N) <= 1:
        if len(N) == 0:
            ans *= P.pop()
            K -= 1
            continue

        if len(P) == 0:
            ans *= N.pop()
            K -= 1
            continue

        if len(N) == 1:
            n = N.pop()
            if ans < 0:
                ans *= n
                K -= 1
            continue

        if len(P) == 1:
            p = P.pop()
            if ans < 0 and K % 2 == 0 or ans >= 0 and K % 2 == 1:
                ans *= p
                K -= 1
            continue

print(ans % MOD)