Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Python (3.4.3) (judge verdict: Accepted)

def count(n):
  ans = 0
  for i in range(1,n+1):
    if n % i == 0:
      ans += 1
  return ans

ans = 0
N = int(input())
for i in range(1,N + 1):
  if i % 2 == 0:
  	continue
  if count(i) == 8:
    ans += 1
print(ans)