Problem:
Score : 400 points

Problem Statement

We have N balls. The i-th ball has an integer A_i written on it.

For each k=1, 2, ..., N, solve the following problem and print the answer.

Find the number of ways to choose two distinct balls (disregarding order) from the N-1 balls other than the k-th ball so that the integers written on them are equal.

Constraints

3 \leq N \leq 2 \times 10^5

1 \leq A_i \leq N

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

For each k=1,2,...,N, print a line containing the answer.

Sample Input 1

5
1 1 2 1 2

Sample Output 1

2
2
3
2
3

Consider the case k=1 for example. The numbers written on the remaining balls are 1,2,1,2.

From these balls, there are two ways to choose two distinct balls so that the integers written on them are equal.

Thus, the answer for k=1 is 2.

Sample Input 2

4
1 2 3 4

Sample Output 2

0
0
0
0

No two balls have equal numbers written on them.

Sample Input 3

5
3 3 3 3 3

Sample Output 3

6
6
6
6
6

Any two balls have equal numbers written on them.

Sample Input 4

8
1 2 1 4 2 1 4 1

Sample Output 4

5
7
5
7
7
5
7
5

Solution in Python (3.4.3) (judge verdict: Time Limit Exceeded)

n = input()
n = int(n)
lin = input().split()
# 要素の個数を求める
dic_s = {}
for c in lin:
  dic_s.setdefault(c, 0)
  dic_s[c] += 1
# 1つしかない要素は計算対象外
dic_cp = dic_s.copy()
for key, value in dic_cp.items():
  if value == 1:
    del dic_s[key]
dic_tot = {}
for c in lin:
  # 1度求めたら再計算しない
  # 同じ数字が多いと時間短縮
  if dic_tot.get(c):
    print(int(dic_tot[c]))
  else:
    # 指定数値を除いた2つを選ぶ
    tot = 0
    for key,value in dic_s.items():
      v = value
      if key == c:
        v -= 1
      tot += v * (v - 1) / 2
    dic_tot.setdefault(c,tot)
    print(int(tot))