Problem:
Score : 600 points

Problem Statement

Given are two integer sequences of N elements each: A_1,...,A_N and B_1,...,B_N.
Determine if it is possible to do the following operation at most N-2 times (possibly zero) so that, for every integer i from 1 to N, A_i \leq B_i holds:

Choose two distinct integers x and y between 1 and N (inclusive), and swap the values of A_x and A_y.

Constraints

2 \leq N \leq 10^5

1 \leq A_i,B_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N
B_1 B_2 ... B_N

Output

If the objective is achievable, print Yes; if it is not, print No.

Sample Input 1

3
1 3 2
1 2 3

Sample Output 1

Yes

We should swap the values of A_2 and A_3.

Sample Input 2

3
1 2 3
2 2 2

Sample Output 2

No

Sample Input 3

6
3 1 2 6 3 4
2 2 8 3 4 3

Sample Output 3

Yes

Solution in PyPy3 (2.4.0) (judge verdict: Runtime Error)



# unionfind木構造
# unionfindについてはここhttps://www.slideshare.net/chokudai/union-find-49066733
# グループに属するかの判定(find)や、グループ結合(union)に強い

from collections import defaultdict
class UnionFind:
    def __init__(self, n):
        class KeyDict(dict):
            # 辞書にないときの対応
            def __missing__(self,key):
                self[key] = key
                return key
        self.parent = KeyDict()
        self.rank = defaultdict(int)
        self.weight = defaultdict(int)

    # 根を探す
    def find(self, x):
        if self.parent[x] == x:
            return x
        else:
            # 経路圧縮
            # 自分自身じゃない場合は、上にさかのぼって検索(再帰的に)
            y = self.find(self.parent[x])           
            self.weight[x] += self.weight[self.parent[x]]   #圧縮時にweightを更新(和)
            self.parent[x] = y      #親の置き換え(圧縮)
            return self.parent[x]

    # 結合
    def union(self, x, y):
        x = self.find(x)
        y = self.find(y)
        # 低い方を高い方につなげる(親のランクによる)
        if self.rank[x] < self.rank[y]:
            self.parent[x] = y
        else:
            self.parent[y] = x
        
        if self.rank[x] == self.rank[y]:
            self.rank[x] += 1

    ### 重み付き
    def weighted_union(self, x, y, w):
        # print("unite",x,y,w,self.weight)
        px = self.find(x)
        py = self.find(y)
        # 低い方を高い方につなげる(親のランクによる)
        # if px == py: return 0
        if self.rank[px] < self.rank[py]:
            self.parent[px] = py
            self.weight[px] = - w - self.weight[x] + self.weight[y]
        else:
            self.parent[py] = px
            self.weight[py] =  w + self.weight[x] - self.weight[y]
        if self.rank[px] == self.rank[py]:
            self.rank[px] += 1
        return 0

    # 判定
    def judge(self, x, y):
        return self.find(x) == self.find(y)

N = int(input())
As  = list(map(int, input().split()))
Bs  = list(map(int, input().split()))
As_ind = [(a,i) for i,a in enumerate(As)]
Bs_ind = [(b,i) for i,b in enumerate(Bs)]
As_ind.sort()
Bs_ind.sort()



uf = UnionFind(N)
d_list = defaultdict(list)
cnt = 0
for A,B in zip(As_ind,Bs_ind):
    # print(A,B)
    if A[0] > B[0]:
        print("No")
        exit()
    uf.union(A[1],B[1])
    if len(d_list[uf.find[A[1]]]) > 0:
        if A[0] in d_list[uf.find[A[1]]]:
        cnt += 1 
    else: d_list[uf.find(A[1])].append(A[0])


d_ans = defaultdict(int)

for i in range(N):
    root = uf.find(i)
    d_ans[root] += 1
if len(d_ans) >= 2:
    print("Yes")
else:
    if cnt > 1:
        print("Yes")
        exit()
    print("No")