Problem:
Score : 300 points

Problem Statement

Tak has N cards. On the i-th (1 \leq i \leq N) card is written an integer x_i.
He is selecting one or more cards from these N cards, so that the average of the integers written on the selected cards is exactly A.
In how many ways can he make his selection?

Constraints

1 \leq N \leq 50

1 \leq A \leq 50

1 \leq x_i \leq 50

N,\,A,\,x_i are integers.

Partial Score

200 points will be awarded for passing the test set satisfying 1 \leq N \leq 16.

Input

The input is given from Standard Input in the following format:

N A
x_1 x_2 ... x_N

Output

Print the number of ways to select cards such that the average of the written integers is exactly A.

Sample Input 1

4 8
7 9 8 9

Sample Output 1

5

The following are the 5 ways to select cards such that the average is 8:

Select the 3-rd card.

Select the 1-st and 2-nd cards.

Select the 1-st and 4-th cards.

Select the 1-st, 2-nd and 3-rd cards.

Select the 1-st, 3-rd and 4-th cards.

Sample Input 2

3 8
6 6 9

Sample Output 2

0

Sample Input 3

8 5
3 6 2 8 7 6 5 9

Sample Output 3

19

Sample Input 4

33 3
3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3

Sample Output 4

8589934591

The answer may not fit into a 32-bit integer.

Solution in Python (3.4.3) (judge verdict: Runtime Error)

n,a = map(int,input().split())
x = list(map(int,input().split()))
dp = []
for i in range(n+1):
    dp.append([[] for j in range(i+1)])
    for k in range(i+1):
        dp[i][k] = [0 for y in range(50*k)]
for i in range(n+1):
        dp[i][0].append(0)
for i in range(1,n+1):
    for j in range(1,i+1):
        if j == 1:
                dp[i][j][x[i-1]-1] += 1
        for k in range(len(dp[i-1][j-1])):
                dp[i][j][k+x[i-1]] += dp[i-1][j-1][k]
                dp[i][j-1][k] += dp[i-1][j-1][k]
count = 0
for j in range(1,i+1):
        for k in range(len(dp[i][j])):
                if k + 1 == j*a:
                        count += dp[n][j][k]
print(count)