Problem:
Score : 100 points

Problem Statement

You went shopping to buy cakes and donuts with X yen (the currency of Japan).

First, you bought one cake for A yen at a cake shop.
Then, you bought as many donuts as possible for B yen each, at a donut shop.

How much do you have left after shopping?

Constraints

1 \leq A, B \leq 1 000

A + B \leq X \leq 10 000

X, A and B are integers.

Input

Input is given from Standard Input in the following format:

X
A
B

Output

Print the amount you have left after shopping.

Sample Input 1

1234
150
100

Sample Output 1

84

You have 1234 - 150 = 1084 yen left after buying a cake.
With this amount, you can buy 10 donuts, after which you have 84 yen left.

Sample Input 2

1000
108
108

Sample Output 2

28

Sample Input 3

579
123
456

Sample Output 3

0

Sample Input 4

7477
549
593

Sample Output 4

405

Solution in Python (3.4.3) (judge verdict: Runtime Error)

import numpy as np
# 複数個格納
# A B = map(int, input().split())
# 行列化
# A = np.array(A)
# A=A.reshape(1,-1)
# A=A.T
#行列の比較
#C=((A%2 == vector0).all())


A = int(input())
B = int(input())
C = int(input())
X = int(input())

gohyaku=(np.arange(0,500*A+1,500)).reshape(1,-1)
hyaku=(np.arange(0,100*B+1,100)).reshape(1,-1)
goju=(np.arange(0,50*C+1,50)).reshape(1,-1)


gohyaku1=X-(gohyaku+hyaku.T)
count=0

for i in range(A):
    for k in range(B):
        if 0 <= gohyaku1[k,i]/50 <= C:
            count=count+1

print(count)