Problem:
Score : 600 points

Problem Statement

Given is an integer sequence of length N+1: A_0, A_1, A_2, \ldots, A_N. Is there a binary tree of depth N such that, for each d = 0, 1, \ldots, N, there are exactly A_d leaves at depth d? If such a tree exists, print the maximum possible number of vertices in such a tree; otherwise, print -1.

Notes

A binary tree is a rooted tree such that each vertex has at most two direct children.

A leaf in a binary tree is a vertex with zero children.

The depth of a vertex v in a binary tree is the distance from the tree's root to v. (The root has the depth of 0.)

The depth of a binary tree is the maximum depth of a vertex in the tree.

Constraints

0 \leq N \leq 10^5

0 \leq A_i \leq 10^{8} (0 \leq i \leq N)

A_N \geq 1

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_0 A_1 A_2 \cdots A_N

Output

Print the answer as an integer.

Sample Input 1

3
0 1 1 2

Sample Output 1

7

Below is the tree with the maximum possible number of vertices. It has seven vertices, so we should print 7.

Sample Input 2

4
0 0 1 0 2

Sample Output 2

10

Sample Input 3

2
0 3 1

Sample Output 3

-1

Sample Input 4

1
1 1

Sample Output 4

-1

Sample Input 5

10
0 0 1 1 2 3 5 8 13 21 34

Sample Output 5

264

Solution in PyPy3 (7.3.0) (judge verdict: Wrong Answer)

from sys import stdin
from collections import deque
def I(): return int(stdin.readline().rstrip())
def LI(): return list(map(int,stdin.readline().rstrip().split()))
 
def end():
    print(-1)
    exit()
 
def main():
    n = I()
    deq = deque(LI())
    if n==0:
        if deq[0] == 0:
            print(1)
            exit()
        else:
          end()
    if deq[0]!=0:
        end()
    max = deque()
    for i in range(n,-1,-1):
        if 2**i<deq[i]:
            end()
        if i == n:
            max.appendleft(deq[i])
        else:
            max.appendleft(max[0]+deq[i])
    for i in range(n+1):
        max[i] = min(2**i,max[i])
        if i!=n and i!=0:
            max[i] = min(2*(max[i-1]-deq[i-1]),max[i])
        if max[i]<deq[i]:
            print(-1)
            exit()
    print(sum(max))
    return
 
if __name__=='__main__':
    main()