Problem:
Score : 500 points

Problem Statement

Given are N integers A_1,\ldots,A_N.

We will choose exactly K of these elements. Find the maximum possible product of the chosen elements.

Then, print the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).

Constraints

1 \leq K \leq N \leq 2\times 10^5

|A_i| \leq 10^9

Input

Input is given from Standard Input in the following format:

N K
A_1 \ldots A_N

Output

Print the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).

Sample Input 1

4 2
1 2 -3 -4

Sample Output 1

12

The possible products of the two chosen elements are 2, -3, -4, -6, -8, and 12, so the maximum product is 12.

Sample Input 2

4 3
-1 -2 -3 -4

Sample Output 2

1000000001

The possible products of the three chosen elements are -24, -12, -8, and -6, so the maximum product is -6.

We print this value modulo (10^9+7), that is, 1000000001.

Sample Input 3

2 1
-1 1000000000

Sample Output 3

1000000000

The possible products of the one chosen element are -1 and 1000000000, so the maximum product is 1000000000.

Sample Input 4

10 10
1000000000 100000000 10000000 1000000 100000 10000 1000 100 10 1

Sample Output 4

999983200

Be sure to print the product modulo (10^9+7).

Solution in Python (3.8.2) (judge verdict: Wrong Answer)

n, k = map(int,input().split())
a = list(map(int,input().split()))
mod = 10**9 + 7

plus = []
minus = []

for i in a:
	if i >= 0:
		plus.append(i)
	else:
		minus.append(i)

plus.sort()
minus.sort(key=lambda x:-x)

#print(plus, minus)

"""
貪欲チックに求める
numplus … 前からnumplus番目まで掛け合わせる
numminus … 前からnumminus番目まで掛け合わせる

入力例2に合わせるのは場合分けが必要だが, minusは2個単位で管理する.
"""
numplus = k
numminus = 0

"""
kがplusを超える場合, うまく処理ができないのでリスト参照できる範囲まで下げる.
"""
while numplus > len(plus):
	numplus -= 2
	numminus += 2

tmpminus = -1

#print(numplus, numminus)

while numplus-2 >= 0 and numminus+1 < len(minus):
	if plus[numplus-1] * plus[numplus-2] <= minus[numminus] * minus[numminus+1]:
		numplus -= 2
		numminus += 2
		tmpminus = numminus
	else:
		break

#print(tmpminus, tmpplus)

ans = 1
if tmpminus != -1:
	for i in range(numplus):
		ans = ans * plus[i] % mod
	for i in range(numminus):
		ans = ans * minus[i] % mod
else:
	"""
	これは, ansが負になる場合や, minusが1個だけの場合, minusしかない場合, plusしかない場合に使える.
	"""
	#print("ここに来ました！")
	tmp = sorted(a, key=lambda x:-x)
	for i in range(k):
		ans = ans * tmp[i]%mod

print(ans)