Problem:
Score : 200 points

Problem Statement

There are N cities and M roads.
The i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally.
There may be more than one road that connects the same pair of two cities.
For each city, how many roads are connected to the city?

Constraints

2≤N,M≤50

1≤a_i,b_i≤N

a_i ≠ b_i

All input values are integers.

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
:
a_M b_M

Output

Print the answer in N lines.
In the i-th line (1≤i≤N), print the number of roads connected to city i.

Sample Input 1

4 3
1 2
2 3
1 4

Sample Output 1

2
2
1
1

City 1 is connected to the 1-st and 3-rd roads.

City 2 is connected to the 1-st and 2-nd roads.

City 3 is connected to the 2-nd road.

City 4 is connected to the 3-rd road.

Sample Input 2

2 5
1 2
2 1
1 2
2 1
1 2

Sample Output 2

5
5

Sample Input 3

8 8
1 2
3 4
1 5
2 8
3 7
5 2
4 1
6 8

Sample Output 3

3
3
2
2
2
1
1
2

Solution in Python (3.4.3) (judge verdict: Accepted)

nm=input().split()
NM_list = list(map(int,nm))

A_list=[]
B_list=[]
for m in range(NM_list[1]):
	ab=input().split()
	AB_list = list(map(int,ab))
	A_list.append(AB_list[0])
	B_list.append(AB_list[1])

n_list=[]
for n in range(1,NM_list[0]+1):
	n_list.append(0)


for i in range(1,len(A_list)+1):
	for n_len in range(1,len(n_list)+1):
		if(n_len == A_list[i-1]):
			n_list[n_len-1] += 1
			break

for i in range(1,len(B_list)+1):
	for n_len in range(1,len(n_list)+1):
		if(n_len == B_list[i-1]):
			n_list[n_len-1] += 1
			break

for p in range(1,NM_list[0]+1):
	print(n_list[p-1])