Problem:
Score : 400 points

Problem Statement

Given is a string S. Each character in S is either a digit (0, ..., 9) or ?.

Among the integers obtained by replacing each occurrence of ? with a digit, how many have a remainder of 5 when divided by 13? An integer may begin with 0.

Since the answer can be enormous, print the count modulo 10^9+7.

Constraints

S is a string consisting of digits (0, ..., 9) and ?.

1 \leq |S| \leq 10^5

Input

Input is given from Standard Input in the following format:

S

Output

Print the number of integers satisfying the condition, modulo 10^9+7.

Sample Input 1

??2??5

Sample Output 1

768

For example, 482305, 002865, and 972665 satisfy the condition.

Sample Input 2

?44

Sample Output 2

1

Only 044 satisfies the condition.

Sample Input 3

7?4

Sample Output 3

0

We may not be able to produce an integer satisfying the condition.

Sample Input 4

?6?42???8??2??06243????9??3???7258??5??7???????774????4?1??17???9?5?70???76???

Sample Output 4

153716888

Solution in PyPy3 (7.3.0) (judge verdict: Accepted)

S = input()
N = len(S)
MOD = 10**9 + 7
dp = [[0]*(N+1) for _ in range(13)]
#dp[j][i]: 上からiケタ目までみたときの13で割った余りがjである個数
dp[0][0] = 1

for i in range(0, N):
    if S[i] == "?":
        for j in range(0, 10):
            for k in range(0, 13):
                dp[(k*10+j)%13][i+1] += dp[k][i]
    else:
        j = int(S[i])
        for k in range(0, 13):
            dp[(k*10+j)%13][i+1] += dp[k][i]
    
    for k in range(0, 13):
        dp[k][i+1] %= MOD

print(dp[5][N]%MOD)