Problem:
Score : 400 points

Problem Statement

Given is a string S consisting of digits from 1 through 9.

Find the number of pairs of integers (i,j) (1 ≤ i ≤ j ≤ |S|) that satisfy the following condition:

Condition: In base ten, the i-th through j-th characters of S form an integer that is a multiple of 2019.

Constraints

1 ≤ |S| ≤ 200000

S is a string consisting of digits from 1 through 9.

Input

Input is given from Standard Input in the following format:

S

Output

Print the number of pairs of integers (i,j) (1 ≤ i ≤ j ≤ |S|) that satisfy the condition.

Sample Input 1

1817181712114

Sample Output 1

3

Three pairs - (1,5), (5,9), and (9,13) - satisfy the condition.

Sample Input 2

14282668646

Sample Output 2

2

Sample Input 3

2119

Sample Output 3

0

No pairs satisfy the condition.

Solution in PyPy3 (7.3.0) (judge verdict: Wrong Answer)

# -*- coding: utf-8 -*-
import collections
s = (input())

"""
n = len(s)
ans = 0
for i in range(n-4):
    for j in range(i+4,n+1):
        if int(s[i:j]) % 2019 == 0:
            ans += 1
print(ans)
"""

n = len(s)
ans = 0
l = 0
#r = l
num = int(s)

tmp = [0 for _ in range(n+1)]
ten = [0 for _ in range(n)]
tmp1 = 0
val = 1
for i in range(0,n):
    ten[i] = val
    tmp1 += (int(s[n-i-1]) * val)
    tmp[i+1] = tmp1 % 2019
    val = (val * 10)
#print(tmp)

c = collections.Counter(tmp)
#print(c)
for i in range(0, 2020):
    if c[i] > 0:
        ans += ((2 * c[i] - 1) // 2)
print(ans)