Problem:
Score : 500 points

Problem Statement

We have N integers. The i-th number is A_i.

\{A_i\} is said to be pairwise coprime when GCD(A_i,A_j)=1 holds for every pair (i, j) such that 1\leq i < j \leq N.

\{A_i\} is said to be setwise coprime when \{A_i\} is not pairwise coprime but GCD(A_1,\ldots,A_N)=1.

Determine if \{A_i\} is pairwise coprime, setwise coprime, or neither.

Here, GCD(\ldots) denotes greatest common divisor.

Constraints

2 \leq N \leq 10^6

1 \leq A_i\leq 10^6

Input

Input is given from Standard Input in the following format:

N
A_1 \ldots A_N

Output

If \{A_i\} is pairwise coprime, print pairwise coprime; if \{A_i\} is setwise coprime, print setwise coprime; if neither, print not coprime.

Sample Input 1

3
3 4 5

Sample Output 1

pairwise coprime

GCD(3,4)=GCD(3,5)=GCD(4,5)=1, so they are pairwise coprime.

Sample Input 2

3
6 10 15

Sample Output 2

setwise coprime

Since GCD(6,10)=2, they are not pairwise coprime. However, since GCD(6,10,15)=1, they are setwise coprime.

Sample Input 3

3
6 10 16

Sample Output 3

not coprime

GCD(6,10,16)=2, so they are neither pairwise coprime nor setwise coprime.

Solution in PyPy3 (7.3.0) (judge verdict: Wrong Answer)

n=int(input())
a=list(map(int,input().split()))

import sys
import math
def setwise_coprime(a):
  ans=a[0]
  for i in range(1,n):
    ans=math.gcd(ans,a[i])
  return ans==1

def erast(n):
  num_set=set()
  prime_set=set()
  for i in range(2,n+1):
    if i not in num_set:
      prime_set.add(i)
      for j in range(i*i,n+1,i):
        num_set.add(j)
  s=list(prime_set)
  return s

check=set()
if setwise_coprime(a):
  s=erast(1000)
  s.sort()
  for i in range(n):
    for j in range(168):
      if s[j]>a[i]:
        break
      if a[i]%s[j]==0:
        if s[j] in check:
          print("setwise coprime")
          sys.exit()
        else:
          check.add(s[j])
  print("pairwise coprime")    
else:
  print("not coprime")