Problem:
Score : 400 points

Problem Statement

Given is a string S consisting of digits from 1 through 9.

Find the number of pairs of integers (i,j) (1 ≤ i ≤ j ≤ |S|) that satisfy the following condition:

Condition: In base ten, the i-th through j-th characters of S form an integer that is a multiple of 2019.

Constraints

1 ≤ |S| ≤ 200000

S is a string consisting of digits from 1 through 9.

Input

Input is given from Standard Input in the following format:

S

Output

Print the number of pairs of integers (i,j) (1 ≤ i ≤ j ≤ |S|) that satisfy the condition.

Sample Input 1

1817181712114

Sample Output 1

3

Three pairs - (1,5), (5,9), and (9,13) - satisfy the condition.

Sample Input 2

14282668646

Sample Output 2

2

Sample Input 3

2119

Sample Output 3

0

No pairs satisfy the condition.

Solution in Python (3.8.2) (judge verdict: Time Limit Exceeded)

def main():
    import sys
    input = sys.stdin.readline
    from collections import defaultdict
    S = reversed(list(input().rstrip()))
    counter = defaultdict(int)
    mod = 2019
    counter[0] += 1
    num = 0
    for i, c in enumerate(S):
        num += int(c) * 10**(i)
        counter[num%mod] += 1
    ans = 0
    for v in counter.values():
        ans += (v * (v-1)) // 2
    print(ans)

if __name__ == '__main__':
    main()