Problem:
Score : 500 points

Problem Statement

We have N integers. The i-th number is A_i.

\{A_i\} is said to be pairwise coprime when GCD(A_i,A_j)=1 holds for every pair (i, j) such that 1\leq i < j \leq N.

\{A_i\} is said to be setwise coprime when \{A_i\} is not pairwise coprime but GCD(A_1,\ldots,A_N)=1.

Determine if \{A_i\} is pairwise coprime, setwise coprime, or neither.

Here, GCD(\ldots) denotes greatest common divisor.

Constraints

2 \leq N \leq 10^6

1 \leq A_i\leq 10^6

Input

Input is given from Standard Input in the following format:

N
A_1 \ldots A_N

Output

If \{A_i\} is pairwise coprime, print pairwise coprime; if \{A_i\} is setwise coprime, print setwise coprime; if neither, print not coprime.

Sample Input 1

3
3 4 5

Sample Output 1

pairwise coprime

GCD(3,4)=GCD(3,5)=GCD(4,5)=1, so they are pairwise coprime.

Sample Input 2

3
6 10 15

Sample Output 2

setwise coprime

Since GCD(6,10)=2, they are not pairwise coprime. However, since GCD(6,10,15)=1, they are setwise coprime.

Sample Input 3

3
6 10 16

Sample Output 3

not coprime

GCD(6,10,16)=2, so they are neither pairwise coprime nor setwise coprime.

Solution in Python (3.8.2) (judge verdict: Wrong Answer)

import math
N = int( input() )
A = sorted( list(map(int, input().split())))
ans = A[0]
L = []
mod = 10 ** 7 + 9

cnt = 0
for i in range(1, N):
    ans = math.gcd(ans, A[i])
    if ans == 1:
      break
    else:
      cnt += 1
if ans != 1:
  ret = "not coprime"
else:
  if cnt > 0:
    ret = "setwise coprime"
  else:
    product = 1
    for a in A:
      product = ( product * a ) % mod
    ret = "pairwise coprime"
    for a in A:
      ans = math.gcd(a, product // a)
      if ans != 1:
        ret = "setwise coprime"
        break
print( ret )