Problem:
Score : 300 points

Problem Statement

There are N integers, A_1, A_2, ..., A_N, written on the blackboard.

You will choose one of them and replace it with an integer of your choice between 1 and 10^9 (inclusive), possibly the same as the integer originally written.

Find the maximum possible greatest common divisor of the N integers on the blackboard after your move.

Constraints

All values in input are integers.

2 \leq N \leq 10^5

1 \leq A_i \leq 10^9

Output

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the maximum possible greatest common divisor of the N integers on the blackboard after your move.

Sample Input 1

3
7 6 8

Sample Output 1

2

If we replace 7 with 4, the greatest common divisor of the three integers on the blackboard will be 2, which is the maximum possible value.

Sample Input 2

3
12 15 18

Sample Output 2

6

Sample Input 3

2
1000000000 1000000000

Sample Output 3

1000000000

We can replace an integer with itself.

Solution in PyPy3 (2.4.0) (judge verdict: Accepted)

# -*- coding: utf-8 -*-

import sys
if sys.version_info.minor >= 5: from math import gcd
else: from fractions import gcd

def input(): return sys.stdin.readline().strip()
def list3d(a, b, c, d): return [[[d] * c for j in range(b)] for i in range(a)]
def ceil(x, y=1): return int(-(-x // y))
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(): return list(map(int, input().split()))
def Yes(): print('Yes')
def No(): print('No')
def YES(): print('YES')
def NO(): print('NO')
sys.setrecursionlimit(10 ** 9)
INF = float('inf')
MOD = 10 ** 9 + 7

class SegTree:
    """
    以下のクエリを処理する
    1.update:  i番目の値をxに更新する
    2.get_val: 区間[l, r)の値を得る
    """
 
    def __init__(self, n, func, init):
        """
        :param n: 要素数
        :param func: 値の操作に使う関数(min, max, addなど)
        :param init: 要素の初期値
        """
        n += 1
        self.n = n
        self.func = func
        self.init = init
        # nより大きい2の冪数
        n2 = 1
        while n2 < n:
            n2 <<= 1
        self.n2 = n2
        self.tree = [self.init] * (n2 << 1)
 
    def update(self, i, x):
        """
        i番目の値をxに更新
        :param i: index(0-indexed)
        :param x: update value
        """
        i += self.n2
        self.tree[i] = x
        while i > 1:
            self.tree[i >> 1] = x = self.func(x, self.tree[i ^ 1])
            i >>= 1
 
    def get_val(self, a, b):
        """
        [a, b)の値を得る
        :param a: index(0-indexed)
        :param b: index(0-indexed)
        """
        return self._get_val(a, b, 1, 0, self.n2)
 
    def _get_val(self, a, b, k, l, r):
        """
        [a, b)の値を得る内部関数
        :param k: 現在調べている区間のtree内index
        :param l, r: kが表す区間の左右端index [l, r)
        :return: kが表す区間と[a, b)の共通区間内での最小値。共通区間を持たない場合は初期値
        """
        # 範囲外なら初期値
        if r <= a or b <= l:
            return self.init
        # [a,b)が完全に[l,r)を包含するならtree[k]の値を採用
        if a <= l and r <= b:
            return self.tree[k]
        # 一部だけ範囲内なら2つに分けて再帰的に調査
        m = (l + r) // 2
        return self.func(
            self._get_val(a, b, k << 1, l, m),
            self._get_val(a, b, (k << 1) + 1, m, r)
        )

N=INT()
A=LIST()

st=SegTree(N+2, gcd, 0)
for i in range(N):
    st.update(i+1, A[i])

ans=0
for i in range(1, N+1):
    ans=max(ans, gcd(st.get_val(0, i), st.get_val(i+1, N+2)))
print(ans)