Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Python (3.4.3) (judge verdict: Accepted)



A_List_1 = list(map(int,input().split()))
A_List_2 = list(map(int,input().split()))
A_List_3 = list(map(int,input().split()))



N = int(input())
#B_List = []
for i in range(N):
    n = int(input())
    for j in range(3):
        if n == A_List_1[j]:
            A_List_1[j] = 0
        if n == A_List_2[j]:
            A_List_2[j] = 0
        if n == A_List_3[j]:
            A_List_3[j] = 0


sum_1 = A_List_1[0] + A_List_1[1] + A_List_1[2]
sum_2 = A_List_2[0] + A_List_2[1] + A_List_2[2]
sum_3 = A_List_3[0] + A_List_3[1] + A_List_3[2]
naname_1 = A_List_1[0] + A_List_2[1] + A_List_3[2]
naname_2 = A_List_1[2] + A_List_2[1] + A_List_3[0]
tate_0 = A_List_1[0] + A_List_2[0] + A_List_3[0]
tate_1 = A_List_1[1] + A_List_2[1] + A_List_3[1]
tate_2 = A_List_1[2] + A_List_2[2] + A_List_3[2]

if sum_1 == 0 or sum_2 == 0 or sum_3 == 0 or naname_1 == 0 or naname_2 == 0 or tate_0 == 0 or tate_1 == 0 or tate_2 == 0:
    print('Yes')
else:
    print('No')