Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Python (3.4.3) (judge verdict: Accepted)

def main():
    n = int(input())
    s = 0

    for i in range(1, n + 1, 2):
        if num_factor(i) == 8:
            s += 1
    print(s)


def num_factor(n):
    if n == 1:
        return 1

    s = 2
    i = 2

    while i * i <= n:
        if n % i == 0:
            if i * i != n:
                s += 2
            else:
                s += 1
        i += 1
    return s

main()