Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in Python (3.4.3) (judge verdict: Accepted)


#a.append(list(map(int, input().split())))
#b.append(list(map(int, input().split())))
#c.append(list(map(int, input().split())))
a = list(map(int, input().split()))
b = list(map(int, input().split()))
c = list(map(int, input().split()))


count = int(input())

for num in range(count):
    x = int(input())
    for y in range(3):
        if a[y] == x:
            a[y] = 0
    for y in range(3):
        if b[y] == x:
            b[y] = 0
    for y in range(3):
        if c[y] == x:
            c[y] = 0

#ans = 0
#ans = a[0] * a[1] * a[2]
#ans += b[0] * b[1] * b[2]
#ans += c[0] * c[1] * c[2]
#ans += a[0] * b[0] * c[0]
#ans += a[1] * b[1] * c[1]
#ans += a[2] * b[2] * c[2]

#if ans == 0:
#    print("Yes")
if a[0]+a[1]+a[2] == 0:
    print("Yes")
elif b[0]+b[1]+b[2] == 0:
    print("Yes")
elif c[0]+c[1]+c[2] == 0:
    print("Yes")
elif a[0] + b[0] + c[0] ==0:
    print("Yes")
elif a[1] + b[1] + c[1] ==0:
    print("Yes")
elif a[2] + b[2] + c[2] ==0:
    print("Yes")
elif a[0] + b[1] + c[2] == 0:
    print("Yes")
elif a[2] + b[1] + c[0] ==0:
    print("Yes")
else:
    print("No")