Problem:
Score : 400 points

Problem Statement

Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

2 ≦ |s| ≦ 10^5

s consists of lowercase letters.

Partial Score

200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.

Input

The input is given from Standard Input in the following format:

s

Output

If there exists no unbalanced substring of s, print -1 -1.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.

Sample Input 1

needed

Sample Output 1

2 5

The string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.

Sample Input 2

atcoder

Sample Output 2

-1 -1

The string atcoder contains no unbalanced substring.

Solution in PHP (5.6.30) (judge verdict: Wrong Answer)

<?php
fscanf(STDIN, "%s", $s);
$string_len = strlen($s);

$atotal =array();
$s2 = str_split($s);
$sopt=count($s2);
    for ($i=0;$i<$sopt;$i++)
        {
            for ($j=$i+1;$j<$sopt;$j++)
                {
                    if ($s2[$j] == $s2[$i] && $s2[$j] != '') {
                    	if (isset($atotal[$s2[$j]])) {
                    		$atotal[$s2[$j]] = $atotal[$s2[$j]]+ 1;

                    	} else {
							$atotal[$s2[$j]] =2;
                    	}
                      $s2[$j] ='';
                    }
                    	
              }
        }

if  (max($atotal) < ($string_len / 2) ) {
	exit(-1 .' '. -1 . "\n");
}
for($k=0; $$k < ($string_len / 2); $k++) {
	$l = $string_len - 1 - $k;
    if($s[$k] == $s[$l] && $k != $l) {
        echo  ($k +1)  .' '. ($l+1) . "\n";
    	exit;
    }
}
echo -1 .' '. -1 . "\n";
?>