Problem:
Score : 300 points

Problem Statement

Snuke has an integer sequence A of length N.

He will freely choose an integer b.
Here, he will get sad if A_i and b+i are far from each other.
More specifically, the sadness of Snuke is calculated as follows:

abs(A_1 - (b+1)) + abs(A_2 - (b+2)) + ... + abs(A_N - (b+N))

Here, abs(x) is a function that returns the absolute value of x.

Find the minimum possible sadness of Snuke.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq A_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the minimum possible sadness of Snuke.

Sample Input 1

5
2 2 3 5 5

Sample Output 1

2

If we choose b=0, the sadness of Snuke would be abs(2-(0+1))+abs(2-(0+2))+abs(3-(0+3))+abs(5-(0+4))+abs(5-(0+5))=2.
Any choice of b does not make the sadness of Snuke less than 2, so the answer is 2.

Sample Input 2

9
1 2 3 4 5 6 7 8 9

Sample Output 2

0

Sample Input 3

6
6 5 4 3 2 1

Sample Output 3

18

Sample Input 4

7
1 1 1 1 2 3 4

Sample Output 4

6

Solution in PHP (5.6.30) (judge verdict: Accepted)

<?php
$len = intval(trim(fgets(STDIN)));
$nums = explode(' ', trim(fgets(STDIN)));
$sads = [];
for ($i=0; $i < $len; $i++) {
  $sads[] = $nums[$i] - $i + 1;
}

$tar = median($sads);

$ans = 0;
for ($i=0; $i < $len; $i++) {
  $ans += abs($sads[$i] - $tar);
}

echo $ans."\n";

function median(array $values){
	sort($values);
	if (count($values) % 2 == 0){
		return (($values[(count($values)/2)-1]+$values[((count($values)/2))])/2);
	}else{
		return ($values[floor(count($values)/2)]);
	}
}