Problem:
Score : 200 points

Problem Statement

Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros).

Constraints

1 \leq N \leq 10^5

Input

Input is given from Standard Input in the following format:

N

Output

Print the number of positive integers less than or equal to N that have an odd number of digits.

Sample Input 1

11

Sample Output 1

9

Among the positive integers less than or equal to 11, nine integers have an odd number of digits: 1, 2, \ldots, 9.

Sample Input 2

136

Sample Output 2

46

In addition to 1, 2, \ldots, 9, another 37 integers also have an odd number of digits: 100, 101, \ldots, 136.

Sample Input 3

100000

Sample Output 3

90909

Solution in PHP7 (7.0.15) (judge verdict: Runtime Error)

<?php
 
$input_line = fgets(STDIN);
$num = intval($input_line);
$arr = array();
for ($i =1; $i <= $num;$i++) {
    $s = strval($i);
    $len = mb_strlen($s);
    if ($len % 2 != 0) {
        $arr[] = $i;
    }
}
$length = count($arr);
echo $length;
 
?>