Problem:
Score : 400 points

Problem Statement

Given are positive integers A and B.

Let us choose some number of positive common divisors of A and B.

Here, any two of the chosen divisors must be coprime.

At most, how many divisors can we choose?

Definition of common divisor

An integer d is said to be a common divisor of integers x and y when d divides both x and y.

Definition of being coprime

Integers x and y are said to be coprime when x and y have no positive common divisors other than 1.

Definition of dividing

An integer x is said to divide another integer y when there exists an integer \alpha such that y = \alpha x.

Constraints

All values in input are integers.

1 \leq A, B \leq 10^{12}

Input

Input is given from Standard Input in the following format:

A B

Output

Print the maximum number of divisors that can be chosen to satisfy the condition.

Sample Input 1

12 18

Sample Output 1

3

12 and 18 have the following positive common divisors: 1, 2, 3, and 6.

1 and 2 are coprime, 2 and 3 are coprime, and 3 and 1 are coprime, so we can choose 1, 2, and 3, which achieve the maximum result.

Sample Input 2

420 660

Sample Output 2

4

Sample Input 3

1 2019

Sample Output 3

1

1 and 2019 have no positive common divisors other than 1.

Solution in PHP7 (7.0.15) (judge verdict: Time Limit Exceeded)

<?php

function fget_array($dlmt = null) {
    $input = trim(fgets(STDIN));
    return $dlmt ? explode($dlmt, $input) : str_split($input);
}

$bunkai = function ($val) {
    $yakusu = [];
    for ($i = 1; $i <= $val; $i++) {
        if ($val % $i === 0) {
            $yakusu[] = $i;
        }
        if ($i > 1) {
            while ($val > $i && $val % $i === 0) {
                $val /= $i;
            }
        }
    }
    return $yakusu;
};

$list = fget_array(' ');
$list = array_map($bunkai, $list);
echo count(array_intersect($list[0], $list[1]));
?>