Problem:
Score : 400 points

Problem Statement

Given is a string S. Each character in S is either a digit (0, ..., 9) or ?.

Among the integers obtained by replacing each occurrence of ? with a digit, how many have a remainder of 5 when divided by 13? An integer may begin with 0.

Since the answer can be enormous, print the count modulo 10^9+7.

Constraints

S is a string consisting of digits (0, ..., 9) and ?.

1 \leq |S| \leq 10^5

Input

Input is given from Standard Input in the following format:

S

Output

Print the number of integers satisfying the condition, modulo 10^9+7.

Sample Input 1

??2??5

Sample Output 1

768

For example, 482305, 002865, and 972665 satisfy the condition.

Sample Input 2

?44

Sample Output 2

1

Only 044 satisfies the condition.

Sample Input 3

7?4

Sample Output 3

0

We may not be able to produce an integer satisfying the condition.

Sample Input 4

?6?42???8??2??06243????9??3???7258??5??7???????774????4?1??17???9?5?70???76???

Sample Output 4

153716888

Solution in PHP (5.6.30) (judge verdict: Wrong Answer)

<?php
fscanf(STDIN, "%s", $s);
$sList=str_split($s);
$ans=array_fill(0,13,0);
$ans[0]=1;
$keep=0;
$keta=1;

for($i=0; $i<count($sList); $i++){
  if($sList[$i]=='?'){
    $tmp=array_fill(0,13,0);
    $pattern=array_diff($ans, array(0));
    foreach($pattern as $k => $v){
      for($m=0; $m<10; $m++){
        $tmp[($k*pow(10,$keta)+$keep*10+$m)%13]+=$v;
        $tmp[($k*pow(10,$keta)+$keep*10+$m)%13]%=(pow(10, 9)+7);
      }
    }
    $keep=0;
    $keta=1;
    $ans=$tmp;
  }else{
    $keep=$keep*10+$sList[$i];
    $keta+=1;
  }
}
//最後が数値の場合
if($keep!=0){
  $tmp=array_fill(0,13,0);
  $pattern=array_diff($ans, array(0));
  foreach($pattern as $k => $v){
    $tmp[($k*pow(10,$keta-1)+$keep)%13]+=$v;
    $tmp[($k*pow(10,$keta-1)+$keep)%13]%=(pow(10, 9)+7);
  }
  $ans=$tmp;
}

echo $ans[5];