Problem:
Score : 200 points

Problem Statement

In some other world, today is the day before Christmas Eve.

Mr. Takaha is buying N items at a department store. The regular price of the i-th item (1 \leq i \leq N) is p_i yen (the currency of Japan).

He has a discount coupon, and can buy one item with the highest price for half the regular price. The remaining N-1 items cost their regular prices. What is the total amount he will pay?

Constraints

2 \leq N \leq 10

100 \leq p_i \leq 10000

p_i is an even number.

Input

Input is given from Standard Input in the following format:

N
p_1
p_2
:
p_N

Output

Print the total amount Mr. Takaha will pay.

Sample Input 1

3
4980
7980
6980

Sample Output 1

15950

The 7980-yen item gets the discount and the total is 4980 + 7980 / 2 + 6980 = 15950 yen.

Note that outputs such as 15950.0 will be judged as Wrong Answer.

Sample Input 2

4
4320
4320
4320
4320

Sample Output 2

15120

Only one of the four items gets the discount and the total is 4320 / 2 + 4320 + 4320 + 4320 = 15120 yen.

Solution in PHP7 (7.0.15) (judge verdict: Accepted)

<?php
 
function input($func = null) {
    if ($func === null) {
        return trim(fgets(STDIN));
    } else {
        return $func(trim(fgets(STDIN)));
    }
}
function input_array($func = null) {
    if ($func === null) {
        return explode(' ', input());
    } else {
        return array_map(function($v) use ($func) {
            return $func($v);
        }, explode(' ', input()));
    }
}

$sum = 0;
$max = 0;

$n = input('intval');
for ($i = 0; $i < $n; $i++) {
    $p = input('intval');
    $sum += $p;
    $max = max($max, $p);
}
$sum -= intdiv($max, 2);

echo $sum . "\n";