Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in PHP (5.6.30) (judge verdict: Wrong Answer)

<?php
$a=array();
for($i=0;$i<3;$i++){
    $query = trim(fgets(STDIN));
    $a[$i] = sscanf($query,"%d %d %d");
}
$N = trim(fgets(STDIN));
for($i=0;$i<$N;$i++){
    $b = trim(fgets(STDIN));
    for($j=0;$j<3;$j++){
        for($m= 0;$m<3;$m++){
            if ($b == $a[$j][$m]){
                $a[$j][$m] = -1;
            }
        }
    }
}
for($i=0;$i<3;$i++){
    if(($a[$i][ 0] == $a[$i][1])&&($a[$i][1] == $a[$i][2])){
        printf("Yes");
        exit;
    }
}
for($i=0;$i<3;$i++){
    if(($a[ 0][$i] == $a[1][$i])&&($a[1][$i] == $a[2][$i])){
        printf("Yes");
        exit;
    }
}
if(($a[ 0][ 0] == $a[1][1])&&($a[1][1] == $a[2][2])){
        printf("Yes");
        exit;
}
if(($a[ 0][3] == $a[1][1])&&($a[1][1] == $a[2][ 0])){
    printf("Yes");
    exit;
}

printf("No");