Problem:
Score: 300 points

Problem Statement

Find the minimum prime number greater than or equal to X.

Notes

A prime number is an integer greater than 1 that cannot be evenly divided by any positive integer except 1 and itself.

For example, 2, 3, and 5 are prime numbers, while 4 and 6 are not.

Constraints

2 \le X \le 10^5

All values in input are integers.

Input

Input is given from Standard Input in the following format:

X

Output

Print the minimum prime number greater than or equal to X.

Sample Input 1

20

Sample Output 1

23

The minimum prime number greater than or equal to 20 is 23.

Sample Input 2

2

Sample Output 2

2

X itself can be a prime number.

Sample Input 3

99992

Sample Output 3

100003

Solution in PHP7 (7.0.15) (judge verdict: Accepted)

<?php
$N = trim(fgets(STDIN));
//list($A,$B,$k) =  explode(" ",trim(fgets(STDIN)));
//$A =  explode(" ",trim(fgets(STDIN)));

for($i=$N;$i<10**6;$i++) {
  if (is_prime($i)) {
    printf("%d\n",$i);
    break;
  }
}

function gcd($a,$b) {
  if ($b == 0) return $a;
  return gcd($b,$a%$b);
}
function lcm($a,$b) {
  $l = gcd($a,$b);
  return $a / $l * $b;
}

function prime_factors(int $n) {
    $i = 2;
    $factors = [];
    while ($i * $i <= $n) {
        if ($n % $i) $i += 1;
        else {
            $n /= $i;
            $factors[] = $i;
        }
    }
    if ($n > 1) $factors[] = $n;
    return $factors;
}
function is_prime(int $n) : bool {
    $r = true;
    if ($n < 2) $r = false;
    elseif ($n == 2 || $n == 3 || $n == 5) $r = true;
    elseif ($n & 1 == 0) $r = false;
    elseif ($n % 2 == 0 || $n % 3 == 0 || $n % 5 == 0) $r = false;
    else {
        $f = true;
        $v = 7;
        $m = intval($n ** 0.5) + 1;
        while ($v < $m) {
            if ($n % $v == 0) {
                $r = false;
                break;
            }
            $v += $f ? 4 : 2;
            $f = !$f;
        }
    }
    return $r;
}