Problem:
Score : 500 points

Problem Statement

Takahashi has decided to work on K days of his choice from the N days starting with tomorrow.

You are given an integer C and a string S. Takahashi will choose his workdays as follows:

After working for a day, he will refrain from working on the subsequent C days.

If the i-th character of S is x, he will not work on Day i, where Day 1 is tomorrow, Day 2 is the day after tomorrow, and so on.

Find all days on which Takahashi is bound to work.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq K \leq N

0 \leq C \leq N

The length of S is N.

Each character of S is o or x.

Takahashi can choose his workdays so that the conditions in Problem Statement are satisfied.

Input

Input is given from Standard Input in the following format:

N K C
S

Output

Print all days on which Takahashi is bound to work in ascending order, one per line.

Sample Input 1

11 3 2
ooxxxoxxxoo

Sample Output 1

6

Takahashi is going to work on 3 days out of the 11 days. After working for a day, he will refrain from working on the subsequent 2 days.

There are four possible choices for his workdays: Day 1,6,10, Day 1,6,11, Day 2,6,10, and Day 2,6,11.

Thus, he is bound to work on Day 6.

Sample Input 2

5 2 3
ooxoo

Sample Output 2

1
5

There is only one possible choice for his workdays: Day 1,5.

Sample Input 3

5 1 0
ooooo

Sample Output 3

There may be no days on which he is bound to work.

Sample Input 4

16 4 3
ooxxoxoxxxoxoxxo

Sample Output 4

11
16

Solution in PHP7 (7.0.15) (judge verdict: Accepted)

<?php
fscanf(STDIN, "%d%d%d", $N, $K, $C);
$S = str_split(trim(fgets(STDIN)));
$rest = 10**10;
$c = 1;
for($i = 0; $i < $N; ++$i){
    if($S[$i] == "o" && $rest > $C){
        $work[$i] = $c++;
        $rest = 0;
    }else{
        $work[$i] = 0;
    }
    $rest++;
}
$rest = 10**10;
$c = $K;
for($i = $N-1; $i >= 0; --$i){
    if($S[$i] == "o" && $rest > $C){
        $work2[$i] = $c--;
        $rest = 0;
    }else{
        $work2[$i] = 0;
    }
    $rest++;
}
for($i = 0; $i < $N; ++$i){
    if($work[$i] > 0 && $work[$i] == $work2[$i])$ret[] =  $i+1;
}
echo implode("\n", $ret);