Problem:
Score : 200 points

Problem Statement

Rng is preparing a problem set for a qualification round of CODEFESTIVAL.

He has N candidates of problems. The difficulty of the i-th candidate is D_i.

There must be M problems in the problem set, and the difficulty of the i-th problem must be T_i. Here, one candidate of a problem cannot be used as multiple problems.

Determine whether Rng can complete the problem set without creating new candidates of problems.

Constraints

1 \leq N \leq 200,000

1 \leq D_i \leq 10^9

1 \leq M \leq 200,000

1 \leq T_i \leq 10^9

All numbers in the input are integers.

Partial Score

100 points will be awarded for passing the test set satisfying N \leq 100 and M \leq 100.

Input

Input is given from Standard Input in the following format:

N
D_1 D_2 ... D_N
M
T_1 T_2 ... T_M

Output

Print YES if Rng can complete the problem set without creating new candidates of problems; print NO if he cannot.

Sample Input 1

5
3 1 4 1 5
3
5 4 3

Sample Output 1

YES

Sample Input 2

7
100 200 500 700 1200 1600 2000
6
100 200 500 700 1600 1600

Sample Output 2

NO

Not enough 1600s.

Sample Input 3

1
800
5
100 100 100 100 100

Sample Output 3

NO

Sample Input 4

15
1 2 2 3 3 3 4 4 4 4 5 5 5 5 5
9
5 4 3 2 1 2 3 4 5

Sample Output 4

YES

Solution in PHP (5.6.30) (judge verdict: Accepted)

<?php

    $N = (int)trim(fgets(STDIN));
    $D = explode( " ", trim(fgets(STDIN)) );
    $D_count = [];
    foreach( $D as $Di ){
        $Di = "s". $Di;
        if( empty( $D_count[$Di] ) ){
             $D_count[$Di] = 1;
        }else{
            ++$D_count[$Di];
        }
    }
    
    $M = (int)trim(fgets(STDIN));
    if( $N < $M ) die("NO\n");
    
    $T = explode( " ", trim(fgets(STDIN)) );
    foreach( $T as $Ti ){
        $Ti = "s". $Ti;
        if( empty( $D_count[$Ti] ) ){
            die("NO\n");
        }else{
            --$D_count[$Ti];
            if( (int)$D_count[$Ti] < 0 ) die("NO\n");
        }
    }
    
    echo "YES\n";