Problem:
Score : 300 points

Problem Statement

Sitting in a station waiting room, Joisino is gazing at her train ticket.

The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).

In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.

The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Constraints

0≤A,B,C,D≤9

All input values are integers.

It is guaranteed that there is a solution.

Input

Input is given from Standard Input in the following format:

ABCD

Output

Print the formula you made, including the part =7.

Use the signs + and -.

Do not print a space between a digit and a sign.

Sample Input 1

1222

Sample Output 1

1+2+2+2=7

This is the only valid solution.

Sample Input 2

0290

Sample Output 2

0-2+9+0=7

0 - 2 + 9 - 0 = 7 is also a valid solution.

Sample Input 3

3242

Sample Output 3

3+2+4-2=7

Solution in PHP (5.6.30) (judge verdict: Wrong Answer)

<?php
$abcd = fgets(STDIN);
//a,b,c,dに分ける
for($i=0;$i<4;$i++){
	$array[$i] = substr($abcd, $i,1);
}
//op1,op2,op3の全パターンを探索
for ($i=0;$i<8;$i++) {
	$sum = 0;
	$ans;
	//op1からop3までのループ
	for ($j=0;$j<3;$j++){
		//op1から判定
		if (($i&1<<$j)==(1<<$j)){
			if ($j==0){
				$sum += $array[$j] + $array[$j+1];
				$ans = $array[$j] . "+" . $array[$j+1];
			}else {
				$sum += $array[$j+1];
				$ans = $ans . "+" . $array[$j+1];
			}
		}else {
			if ($j==0){
				$sum += $array[$j] - $array[$j+1];
				$ans = $array[$j] . "-" . $array[$j+1];
			}else {
				$sum -= $array[$j+1];
				$ans = $ans . "-" . $array[$j+1];
			}
		}
		//op3までいって7だったら出力
		if ($j==2 && $sum == 7){
			echo $ans . "=7","\n";
		}
	}
}