Problem:
Score : 200 points

Problem Statement

Given are integers a,b,c and d.
If x and y are integers and a \leq x \leq b and c\leq y \leq d hold, what is the maximum possible value of x \times y?

Constraints

-10^9 \leq a \leq b \leq 10^9

-10^9 \leq c \leq d \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

a b c d

Output

Print the answer.

Sample Input 1

1 2 1 1

Sample Output 1

2

If x = 1 and y = 1 then x \times y = 1.
If x = 2 and y = 1 then x \times y = 2.
Therefore, the answer is 2.

Sample Input 2

3 5 -4 -2

Sample Output 2

-6

The answer can be negative.

Sample Input 3

-1000000000 0 -1000000000 0

Sample Output 3

1000000000000000000

Solution in PHP (7.4.4) (judge verdict: Accepted)

<?php

fscanf(STDIN, "%d %d %d %d", $a, $b, $c, $d);

$arr1 = [$a, $b];
$arr2 = [$c, $d];

$result = [];

for($i=0; $i<2; $i++) {
    for($j=0; $j<2; $j++) {
        array_push($result, $arr1[$i]*$arr2[$j]);
    }
}

echo max($result) . PHP_EOL;