Problem:
Score : 200 points

Problem Statement

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each.
Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:

N

Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print Yes; otherwise, print No.

Sample Input 1

11

Sample Output 1

Yes

If you buy one cake and one doughnut, the total will be 4 + 7 = 11 dollars.

Sample Input 2

40

Sample Output 2

Yes

If you buy ten cakes, the total will be 4 \times 10 = 40 dollars.

Sample Input 3

3

Sample Output 3

No

The prices of cakes (4 dollars) and doughnuts (7 dollars) are both higher than 3 dollars, so there is no such way.

Solution in PHP7 (7.0.15) (judge verdict: Wrong Answer)

<?php
$input = explode(' ', trim(fgets(STDIN)));
$n = intval($input[0]);
$isTotalN = false;
for ($i = 0; $i <= $n; $i++) {
    if ($i * 4 === $n) {
        $isTotalN = true;
        break;
    }
}
if ($isTotalN === false) {
    for ($j = 0; $j <= $n; $j++) {
        if ($j * 7 === $n) {
            $isTotalN = true;
            break;
        }
    }
}
$x = 1;
$y = 1;
for ($x; ($x * 4 + $y * 7) <= $n; $x++) {
    for ($y; ($x * 4 + $y * 7) <= $n; $y++) {
        if (($x * 4 + $y * 7) ===  $n) {
            $isTotalN = true;
            break;
         }
    }
}
if ($isTotalN === true) {
    printf('yes');
} else {
    printf('no');
}