Problem:
Score : 200 points

Problem Statement

There are N cities and M roads.
The i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally.
There may be more than one road that connects the same pair of two cities.
For each city, how many roads are connected to the city?

Constraints

2≤N,M≤50

1≤a_i,b_i≤N

a_i ≠ b_i

All input values are integers.

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
:
a_M b_M

Output

Print the answer in N lines.
In the i-th line (1≤i≤N), print the number of roads connected to city i.

Sample Input 1

4 3
1 2
2 3
1 4

Sample Output 1

2
2
1
1

City 1 is connected to the 1-st and 3-rd roads.

City 2 is connected to the 1-st and 2-nd roads.

City 3 is connected to the 2-nd road.

City 4 is connected to the 3-rd road.

Sample Input 2

2 5
1 2
2 1
1 2
2 1
1 2

Sample Output 2

5
5

Sample Input 3

8 8
1 2
3 4
1 5
2 8
3 7
5 2
4 1
6 8

Sample Output 3

3
3
2
2
2
1
1
2

Solution in PHP7 (7.0.15) (judge verdict: Accepted)

#!/usr/bin/env php
<?php
if (basename(__FILE__) == basename($_SERVER['PHP_SELF'])) {

	$n = 0;
	$m = 0;
	$line = fgets(STDIN);
  {
    $tokens = explode(' ', $line);
    $n = intval($tokens[0]);
    $m = intval($tokens[1]);
  }

    for ($i = 1; $i <= $n; $i++) {
    	$arr[$i] = 0;
    }


  while ($line = fgets(STDIN)) {
  	$tokens = explode(' ', $line);

  	$num1 = intval($tokens[0]);
    $num2 = intval($tokens[1]);

    	$arr[$num1] = $arr[$num1] + 1;
    	$arr[$num2] = $arr[$num2] + 1;

  }

  for ($i = 1; $i <= $n; $i++) {
  	if (isset($arr[$i])) {
        echo($arr[$i]);
  	} else {
  		echo ('0');
  	}
  	echo(PHP_EOL);
  }
}
?>