Problem:
Score : 200 points

Problem Statement

Takahashi has many red balls and blue balls. Now, he will place them in a row.

Initially, there is no ball placed.

Takahashi, who is very patient, will do the following operation 10^{100} times:

Place A blue balls at the end of the row of balls already placed. Then, place B red balls at the end of the row.

How many blue balls will be there among the first N balls in the row of balls made this way?

Constraints

1 \leq N \leq 10^{18}

A, B \geq 0

0 < A + B \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the number of blue balls that will be there among the first N balls in the row of balls.

Sample Input 1

8 3 4

Sample Output 1

4

Let b denote a blue ball, and r denote a red ball. The first eight balls in the row will be bbbrrrrb, among which there are four blue balls.

Sample Input 2

8 0 4

Sample Output 2

0

He placed only red balls from the beginning.

Sample Input 3

6 2 4

Sample Output 3

2

Among bbrrrr, there are two blue balls.

Solution in PHP7 (7.0.15) (judge verdict: Runtime Error)

<?php
fscanf(STDIN, '%d %d %d', $n, $a, $b);
 
$sum = $a + $b;
$fraction = $n % $sum;
if ($n >= $sum) {
  $count = (int)floor($n / $sum);
  $result = $count * $a;
} else {
  $result = 0;
}
 
if ($a >= $fraction) {
  $result += $fraction;
} else {
  $result += $a;
}
 
echo $result;
<?php
fscanf(STDIN, '%d %d %d', $n, $a, $b);

$sum = $a + $b;
$fraction = $n % $sum;
if ($n >= $sum) {
  $count = (int)floor($n / $sum);
  $result = $count * $a;
} else {
  $result = 0;
}

if ($a >= $fraction) {
  $result += $fraction;
} else {
  $result += $a;
}

echo $result;