Problem:
Score : 300 points

Problem Statement

Snuke has an integer sequence A of length N.

He will freely choose an integer b.
Here, he will get sad if A_i and b+i are far from each other.
More specifically, the sadness of Snuke is calculated as follows:

abs(A_1 - (b+1)) + abs(A_2 - (b+2)) + ... + abs(A_N - (b+N))

Here, abs(x) is a function that returns the absolute value of x.

Find the minimum possible sadness of Snuke.

Constraints

1 \leq N \leq 2 \times 10^5

1 \leq A_i \leq 10^9

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N

Output

Print the minimum possible sadness of Snuke.

Sample Input 1

5
2 2 3 5 5

Sample Output 1

2

If we choose b=0, the sadness of Snuke would be abs(2-(0+1))+abs(2-(0+2))+abs(3-(0+3))+abs(5-(0+4))+abs(5-(0+5))=2.
Any choice of b does not make the sadness of Snuke less than 2, so the answer is 2.

Sample Input 2

9
1 2 3 4 5 6 7 8 9

Sample Output 2

0

Sample Input 3

6
6 5 4 3 2 1

Sample Output 3

18

Sample Input 4

7
1 1 1 1 2 3 4

Sample Output 4

6

Solution in PHP (7.4.4) (judge verdict: Wrong Answer)

<?php
  list($n) = explode(" ", trim(fgets(STDIN)));
  $a = array_map('intval',explode(" ", trim(fgets(STDIN))));

  $b = [];
  for($i=0;$i<$n;$i++){
    $b[$i] = $a[$i]-($i+1);
  }
  
  $x = array_sum($b);

  $p = 0;

//  echo $p;
  if($x < 0){
    $p = intdiv(abs($x)+$n-1, $n)*-1;
  }else{
    $p = intdiv(abs($x), $n);
  }

  $ans = 0;
  for($i=0;$i<$n;$i++){
    $ans += abs($a[$i]-($p+$i+1));
  }
  echo $ans;