Problem:
Score : 200 points

Problem Statement

Takahashi has many red balls and blue balls. Now, he will place them in a row.

Initially, there is no ball placed.

Takahashi, who is very patient, will do the following operation 10^{100} times:

Place A blue balls at the end of the row of balls already placed. Then, place B red balls at the end of the row.

How many blue balls will be there among the first N balls in the row of balls made this way?

Constraints

1 \leq N \leq 10^{18}

A, B \geq 0

0 < A + B \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

Print the number of blue balls that will be there among the first N balls in the row of balls.

Sample Input 1

8 3 4

Sample Output 1

4

Let b denote a blue ball, and r denote a red ball. The first eight balls in the row will be bbbrrrrb, among which there are four blue balls.

Sample Input 2

8 0 4

Sample Output 2

0

He placed only red balls from the beginning.

Sample Input 3

6 2 4

Sample Output 3

2

Among bbrrrr, there are two blue balls.

Solution in PHP7 (7.0.15) (judge verdict: Wrong Answer)

<?php
$inp = explode(' ', fgets(STDIN));

for ($i = 0; $i < 3; $i++) {
  $inp[$i] = intval($inp[$i]);
}

if ($inp[0] === 0 || $inp[1] === 0) {
  echo '0';
  return;
}

$sum = $inp[1] + $inp[2];

if ($inp[0] < $sum) {
  echo abs(($inp[0] - $inp[2]) - $sum);
  return;
}

$blue = floor($inp[0] / $sum);
$inp[0] = $inp[0] % $sum;

echo $inp[1] * $blue + $inp[0];

?>