Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in PHP (5.6.30) (judge verdict: Wrong Answer)

<?php
fscanf(STDIN,"%d",$s);

$mae=intval(substr($s,0,2));
$ato=intval(substr($s,2,2));

if(intval($s)==0 || ($mae>12 && $ato>12) || ($mae>12 && $ato==0) || ($mae==0 && $ato>12)){
	echo "NA";
}else{
	if($mae>12 && $ato<=12){
		echo "YYMM";
	}elseif($mae<=12 && $ato>12){
		echo "MMYY";
	}elseif($mae==0 && $ato<=12){
		echo "YYMM";
	}elseif($mae<=12 && $ato==0){
		echo "MMYY";
	}elseif($mae<12 && $ato<12){
		echo "AMBIGUOUS";
	}else{
		echo "NA";
	}
}

?>