Problem:
Score : 300 points

Problem Statement

A company has N members, who are assigned ID numbers 1, ..., N.

Every member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.

When a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.

You are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.

Constraints

2 \leq N \leq 2 \times 10^5

1 \leq A_i < i

Input

Input is given from Standard Input in the following format:

N
A_2 ... A_N

Output

For each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.

Sample Input 1

5
1 1 2 2

Sample Output 1

2
2
0
0
0

The member numbered 1 has two immediate subordinates: the members numbered 2 and 3.

The member numbered 2 has two immediate subordinates: the members numbered 4 and 5.

The members numbered 3, 4, and 5 do not have immediate subordinates.

Sample Input 2

10
1 1 1 1 1 1 1 1 1

Sample Output 2

9
0
0
0
0
0
0
0
0
0

Sample Input 3

7
1 2 3 4 5 6

Sample Output 3

1
1
1
1
1
1
0

Solution in PHP (7.4.4) (judge verdict: Wrong Answer)

<?php

fscanf(STDIN,"%d %d",$N,$M);
$a_list = explode(" ",trim(fgets(STDIN)));


$count = 1;

sort($a_list);

$has_buka = array();

for($i=0;$i<$N-1;$i++){
  if($a_list[$i] == $a_list[$i+1] ){
    $count++;
    if($N-1==$count){
          $has_buka[] = [$a_list[$i-1],$count];
    }
  }else{
    $has_buka[] = [$a_list[$i],$count];
    $count=1;
  }
  
}

for($i=0;$i<$N;$i++){
  if($i < count($has_buka)){
    if($i+1 == $has_buka[$i][0]){
        echo $has_buka[$i][1]."\n";

    }else{
       echo "0\n";
    }
  }else{
    echo "0\n";
  }
}