Problem:
Score : 200 points

Problem Statement

We have a permutation p = {p_1,\ p_2,\ ...,\ p_n} of {1,\ 2,\ ...,\ n}.

Print the number of elements p_i (1 < i < n) that satisfy the following condition:

p_i is the second smallest number among the three numbers p_{i - 1}, p_i, and p_{i + 1}.

Constraints

All values in input are integers.

3 \leq n \leq 20

p is a permutation of {1,\ 2,\ ...,\ n}.

Input

Input is given from Standard Input in the following format:

n
p_1 p_2 ... p_n

Output

Print the number of elements p_i (1 < i < n) that satisfy the condition.

Sample Input 1

5
1 3 5 4 2

Sample Output 1

2

p_2 = 3 is the second smallest number among p_1 = 1, p_2 = 3, and p_3 = 5. Also, p_4 = 4 is the second smallest number among p_3 = 5, p_4 = 4, and p_5 = 2. These two elements satisfy the condition.

Sample Input 2

9
9 6 3 2 5 8 7 4 1

Sample Output 2

5

Solution in PHP7 (7.0.15) (judge verdict: Wrong Answer)

<?php
# B - Ordinary Number

fscanf(STDIN, "%d", $N);

$array = explode(' ', fgets(STDIN));
$count = 0;
for ( $i = 1 ; $i < $N - 1 ; $i++ ) {
    if ($array[$i-1] < $array[$i] && $array[$i] < $array[$i+1]) {
        $count++;
    } elseif ($array[$i+1] < $array[$i] && $array[$i-1] > $array[$i]) {
        $count++;
    } elseif ($array[$i-1] == $array[$i] && $array[$i+1] > $array[$i]) {
        $count++;
    } elseif ($array[$i+1] == $array[$i] && $array[$i-1] > $array[$i]) {
        $count++;
    } elseif ($array[$i+1] == $array[$i-1] && $array[$i-1] < $array[$i]) {
        $count++;
    }
}

echo $count . PHP_EOL;