Problem:
Score : 200 points

Problem Statement

There is a square in the xy-plane. The coordinates of its four vertices are (x_1,y_1),(x_2,y_2),(x_3,y_3) and (x_4,y_4) in counter-clockwise order.
(Assume that the positive x-axis points right, and the positive y-axis points up.)

Takahashi remembers (x_1,y_1) and (x_2,y_2), but he has forgot (x_3,y_3) and (x_4,y_4).

Given x_1,x_2,y_1,y_2, restore x_3,y_3,x_4,y_4. It can be shown that x_3,y_3,x_4 and y_4 uniquely exist and have integer values.

Constraints

|x_1|,|y_1|,|x_2|,|y_2| \leq 100

(x_1,y_1) ≠ (x_2,y_2)

All values in input are integers.

Input

Input is given from Standard Input in the following format:

x_1 y_1 x_2 y_2

Output

Print x_3,y_3,x_4 and y_4 as integers, in this order.

Sample Input 1

0 0 0 1

Sample Output 1

-1 1 -1 0

(0,0),(0,1),(-1,1),(-1,0) is the four vertices of a square in counter-clockwise order.
Note that (x_3,y_3)=(1,1),(x_4,y_4)=(1,0) is not accepted, as the vertices are in clockwise order.

Sample Input 2

2 3 6 6

Sample Output 2

3 10 -1 7

Sample Input 3

31 -41 -59 26

Sample Output 3

-126 -64 -36 -131

Solution in PHP7 (7.0.15) (judge verdict: Accepted)

<?php
  
$t = explode(' ', trim(fgets(STDIN)));

$xd = abs($t[2]-$t[0]);
$yd = abs($t[3]-$t[1]);
$px = $t[2];
$py = $t[3];

if ($t[2] > $t[0] && $t[3] >= $t[1]){
  $pxs = $px-$yd;
  $pys = $py+$xd;
  $pxt = $pxs-abs($pys-$py);
  $pyt = $pys-abs($pxs-$px);
} else if ($t[2] <= $t[0] && $t[3] > $t[1]){
  $pxs = $px-$yd;
  $pys = $py-$xd;
  $pxt = $pxs+abs($pys-$py);
  $pyt = $pys-abs($pxs-$px);
} else if ($t[2] < $t[0] && $t[3] <= $t[1]){
  $pxs = $px+$yd;
  $pys = $py-$xd;
  $pxt = $pxs+abs($pys-$py);
  $pyt = $pys+abs($pxs-$px);
} else if ($t[2] >= $t[0] && $t[3] < $t[1]){
  $pxs = $px+$yd;
  $pys = $py+$xd;
  $pxt = $pxs-abs($pys-$py);
  $pyt = $pys+abs($pxs-$px);
}

echo $pxs." ".$pys." ".$pxt." ".$pyt;
  
?>