Problem:
Score : 200 points

Problem Statement

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each.
Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:

N

Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print Yes; otherwise, print No.

Sample Input 1

11

Sample Output 1

Yes

If you buy one cake and one doughnut, the total will be 4 + 7 = 11 dollars.

Sample Input 2

40

Sample Output 2

Yes

If you buy ten cakes, the total will be 4 \times 10 = 40 dollars.

Sample Input 3

3

Sample Output 3

No

The prices of cakes (4 dollars) and doughnuts (7 dollars) are both higher than 3 dollars, so there is no such way.

Solution in PHP7 (7.0.15) (judge verdict: Accepted)

<?php
$cake = 4;
$donuts = 7;
$N = trim(fgets(STDIN));
$isExists = "No";
$x = floor($N / $cake);
$y = floor($N / $donuts);

for ($i = 0; $i <= $x; $i++) {
  for ($j = 0; $j <= $y; $j++) {
    $total = ($i * $cake) + ($j * $donuts);
    if ($N == $total) {
      $isExists = 'Yes';
    }
  }
}

printf("%s\n", $isExists);
?>