Problem:
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Circles Intersection

You are given circle $A$ with radius $r_a$ and with central coordinate $(x_a, y_a)$ and circle $B$ with radius $r_b$ and with central coordinate $(x_b, y_b)$.

Write a program which prints:

"2" if $B$ is in $A$,

"-2" if $A$ is in $B$,

"1" if circumference of $A$ and $B$ intersect, and

"0" if $A$ and $B$ do not overlap.

You may assume that $A$ and $B$ are not identical.

Input

The input consists of multiple datasets. The first line consists of an integer $N$ ($N \leq 50$), the number of datasets. There will be $N$ lines where each line represents each dataset. Each data set consists of real numbers:

$x_a$ $y_a$ $r_a$ $x_b$ $y_b$ $r_b$

Output

For each dataset, print 2, -2, 1, or 0 in a line.

Sample Input

2
0.0 0.0 5.0 0.0 0.0 4.0
0.0 0.0 2.0 4.1 0.0 2.0

Output for the Sample Input

2
0

Solution in PHP (judge verdict: Accepted)

<?php

$n = intval(fgets(STDIN));
for($i = 0; $i < $n; $i++){
	fscanf(STDIN, "%lf %lf %lf %lf %lf %lf", $xa, $ya, $ra, $xb, $yb, $rb);
	
	$r = sqrt(($xb - $xa)*($xb - $xa) + ($yb - $ya)*($yb - $ya));
	if($r + $ra < $rb){
		// A が B の中にある
		echo "-2\n";
		continue;
	}
	if($r + $rb < $ra){
		// B が A の中になる
		echo "2\n";
		continue;
	}
	
	if($r <= $ra + $rb){
		// 交わってる
		echo "1\n";
		continue;
	}
	
	// 離れてる
	echo "0\n";
}