Problem:
Score : 300 points

Problem Statement

You are given two non-negative integers L and R.
We will choose two integers i and j such that L \leq i < j \leq R.
Find the minimum possible value of (i \times j) \mbox{ mod } 2019.

Constraints

All values in input are integers.

0 \leq L < R \leq 2 \times 10^9

Input

Input is given from Standard Input in the following format:

L R

Output

Print the minimum possible value of (i \times j) \mbox{ mod } 2019 when i and j are chosen under the given condition.

Sample Input 1

2020 2040

Sample Output 1

2

When (i, j) = (2020, 2021), (i \times j) \mbox{ mod } 2019 = 2.

Sample Input 2

4 5

Sample Output 2

20

We have only one choice: (i, j) = (4, 5).

Solution in PHP7 (7.0.15) (judge verdict: Wrong Answer)

<?php
fscanf(STDIN, "%d%d", $l, $r);
$l%=2019;
$r%=2019;
if($r<=$l)$r+=2019;
$min = 10**10;
for($x = $l; $x <= $r; $x++){
  for($y = $l; $y <= $r; $y++){
    if($x!=$y){
      $mod = ($x*$y)%2019;
      if($mod < $min){
        $min = $mod;
      }
    }
  }
}
echo $min;