Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in PHP (7.4.4) (judge verdict: Wrong Answer)

<?php
// From https://qiita.com/yoshikyoto/items/6924478283dbdd549e4b
class Scanner
{
    private $arr = [];
    private $count = 0;
    private $pointer = 0;
    public function next()
    {
        if ($this->pointer >= $this->count) {
            $str = trim(fgets(STDIN));
            $this->arr = explode(' ', $str);
            $this->count = count($this->arr);
            $this->pointer = 0;
        }
        $result = $this->arr[$this->pointer];
        $this->pointer++;
        return $result;
    }
    public function hasNext()
    {
        return $this->pointer < $this->count;
    }
    public function nextInt()
    {
        return (int)$this->next();
    }
    public function nextDouble()
    {
        return (float)$this->next();
    }
}
// From https://qiita.com/yoshikyoto/items/6924478283dbdd549e4b

list($N) = sscanf(trim(fgets(STDIN)), "%d");
$sc = new Scanner();
$calc = 1;
for ($i = 0; $i < $N; $i++) {
    $calc *= $sc->nextInt();
}
print($calc > 10**18 ? -1 : $calc);