Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in PHP (7.4.4) (judge verdict: Wrong Answer)

<?php
while($line = fgets(STDIN)) {
   $stdinDatas[] = trim($line);
}

$n = $stdinDatas[0];
$nums = explode(' ', $stdinDatas[1]);

$result = 1; // 結果格納変数、１で初期化
$count = count($nums);

// $numsに0が一つでも含まれていたら、計算せずに0を出力する
if (array_search(0, $nums) !== false) {
	echo 0;
}
// forループの中で↑に対して配列の中身を一つずつかけていく
for ($i = 0; $i < $count; $i++) {
  $result *= $nums[i];
}

if ($result >= (10 ** 18)) {
  echo -1;
} else {
  echo $result;
}