Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in PHP (7.4.4) (judge verdict: Accepted)

<?php
fscanf(STDIN,"%d",$n);
$a_li = explode(" ",trim(fgets(STDIN)));
//for($i=0;$i<$n;$i++)
$re = $a_li[0];
if(in_array(0,$a_li)){
  echo "0\n";
  exit;
}

for($i=1;$i<count($a_li);$i++){
  if($a_li[$i]>10**18 || $a_li[0]>10**18){
    echo "-1\n";
    exit;
  }
  $re *= $a_li[$i];
}

 if($re>10**18){
    echo "-1\n";
    exit;
  }else{
   echo $re."\n";
 }