Problem:
Score : 200 points

Problem Statement

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

YYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order

MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order

If S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.

Constraints

S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:

S

Output

Print the specified string: YYMM, MMYY, AMBIGUOUS or NA.

Sample Input 1

1905

Sample Output 1

YYMM

May XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.

Sample Input 2

0112

Sample Output 2

AMBIGUOUS

Both December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.

Sample Input 3

1700

Sample Output 3

NA

Neither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.

Solution in PHP (7.4.4) (judge verdict: Wrong Answer)

<?php
	$s = fgets(STDIN);
	$s1 = $s[0];
	$s2 = $s[1];
	$s3 = $s[2];
	$s4 = $s[3];
	$mm = $s1*10+$s2;
	$yy = $s3*10+$s4;

	if($mm==0 || $yy==0){
      echo "NA\n"; 
      return;
    }

	if(12>=$mm && 12>=$yy) echo "AMBIGUOUS\n";
	elseif($mm>12 && 12>=$yy) echo "YYMM\n";
	elseif($yy>12 && 12>=$mm) echo "MMYY\n";
	else echo "NA\n";
?>