Problem:
Score: 100 points

Problem Statement

In this problem, a date is written as Y-M-D. For example, 2019-11-30 means November 30, 2019.

Integers M_1, D_1, M_2, and D_2 will be given as input.

It is known that the date 2019-M_2-D_2 follows 2019-M_1-D_1.

Determine whether the date 2019-M_1-D_1 is the last day of a month.

Constraints

Both 2019-M_1-D_1 and 2019-M_2-D_2 are valid dates in the Gregorian calendar.

The date 2019-M_2-D_2 follows 2019-M_1-D_1.

Input

Input is given from Standard Input in the following format:

M_1 D_1
M_2 D_2

Output

If the date 2019-M_1-D_1 is the last day of a month, print 1; otherwise, print 0.

Sample Input 1

11 16
11 17

Sample Output 1

0

November 16 is not the last day of a month.

Sample Input 2

11 30
12 1

Sample Output 2

1

November 30 is the last day of November.

Solution in Perl (v5.18.2) (judge verdict: Runtime Error)

//{{{
#include <bits/stdc++.h>
using namespace std;
#define repX(a,b,c,x,...) x
#define repN(a) repX a
#define rep(...) repN((__VA_ARGS__,rep3,rep2,loop))(__VA_ARGS__)
#define rrep(...) repN((__VA_ARGS__,rrep3,rrep2))(__VA_ARGS__)
#define loop(n) rep2(i_,n)
#define rep2(i,n) rep3(i,0,n)
#define rep3(i,begin,end) for(int i=(int)(begin),i##_end=(int)(end);i<i##_end;++i)
#define rrep2(i,n) rrep3(i,n,0)
#define rrep3(i,begin,end) for(int i=(int)(begin-1),i##_end=(int)(end);i>=i##_end;--i)
#define foreach(x,a) for(auto&x:a)
using ll=long long;
const ll mod=(ll)1e9+7;
//}}}

int main(){
  int M1, D1, M2, D2;
  cin >> M1 >> D1 >> M2 >> D2;
  int ans = (M1 != M2);
  cout << ans << endl;
  return 0;
}