Problem:
Score: 200 points

Problem Statement

The number 105 is quite special - it is odd but still it has eight divisors.
Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:

N

Output

Print the count.

Sample Input 1

105

Sample Output 1

1

Among the numbers between 1 and 105, the only number that is odd and has exactly eight divisors is 105.

Sample Input 2

7

Sample Output 2

0

1 has one divisor. 3, 5 and 7 are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Solution in Pascal (FPC 2.6.2) (judge verdict: Accepted)

VAR N,i,j,count,kq:INTEGER;
begin
 readln(n);
 i:=1;
 if n < 105 then writeln('0') else
 if n = 105 then writeln('1') else 
 begin
   while i <= n do 
    begin
    count:=0;
    for j:=1 to n do 
     if i mod j = 0 then inc(Count);
    if count = 8 then inc(kq);
    inc(i,2);
    end;
  writeln(kq);
 end;
 end.