Problem:
Score : 200 points

Problem Statement

You are given strings s and t, consisting of lowercase English letters.
You will create a string s' by freely rearranging the characters in s.
You will also create a string t' by freely rearranging the characters in t.
Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Notes

For a string a = a_1 a_2 ... a_N of length N and a string b = b_1 b_2 ... b_M of length M, we say a < b for the lexicographic order if either one of the following two conditions holds true:

N < M and a_1 = b_1, a_2 = b_2, ..., a_N = b_N.

There exists i (1 \leq i \leq N, M) such that a_1 = b_1, a_2 = b_2, ..., a_{i - 1} = b_{i - 1} and a_i < b_i. Here, letters are compared using alphabetical order.

For example, xy < xya and atcoder < atlas.

Constraints

The lengths of s and t are between 1 and 100 (inclusive).

s and t consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s
t

Output

If it is possible to satisfy s' < t', print Yes; if it is not, print No.

Sample Input 1

yx
axy

Sample Output 1

Yes

We can, for example, rearrange yx into xy and axy into yxa. Then, xy < yxa.

Sample Input 2

ratcode
atlas

Sample Output 2

Yes

We can, for example, rearrange ratcode into acdeort and atlas into tslaa. Then, acdeort < tslaa.

Sample Input 3

cd
abc

Sample Output 3

No

No matter how we rearrange cd and abc, we cannot achieve our objective.

Sample Input 4

w
ww

Sample Output 4

Yes

Sample Input 5

zzz
zzz

Sample Output 5

No

Solution in Pascal (FPC 2.6.2) (judge verdict: Wrong Answer)

uses math;
var
  s1,s2:string;
  i,j:longint;
  ch:char;
begin
  readln(s1);
  readln(s2);
  for i:=1 to length(s1)-1 do
    for j:=i+1 to length(s1) do
      if s1[i]<s1[j] then
        begin
          ch:=s1[i];s1[i]:=s1[j];s1[j]:=ch;
        end;
  for i:=1 to length(s2)-1 do
    for j:=i+1 to length(s2) do
      if s2[i]<s2[j] then
        begin
          ch:=s2[i];s2[i]:=s2[j];s2[j]:=ch;
        end;
  if s1=s2 then writeln('No')
    else if s1<s2 then writeln('Yes')
           else writeln('No');
end.