Problem:
Score : 300 points

Problem Statement

You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

1 \leq |S| \leq 2 \times 10^5

|S| = |T|

S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S
T

Output

If S and T can be made equal, print Yes; otherwise, print No.

Sample Input 1

azzel
apple

Sample Output 1

Yes

azzel can be changed to apple, as follows:

Choose e as c_1 and l as c_2. azzel becomes azzle.

Choose z as c_1 and p as c_2. azzle becomes apple.

Sample Input 2

chokudai
redcoder

Sample Output 2

No

No sequences of operation can change chokudai to redcoder.

Sample Input 3

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu

Sample Output 3

Yes

Solution in Pascal (FPC 2.6.2) (judge verdict: Accepted)

var
  s1,s2:string;
  a,b:array['a'..'z']of longint;
  c:array[1..26]of boolean;
  f:boolean;
  i,j,k,p:longint;
begin
  readln(s1);
  read(s2);
  k:=length(s2);
  f:=true;
  if length(s1)<length(s2) then begin k:=length(s1); f:=false; end;
  for i:=1 to k-1 do
  begin
    inc(a[s1[i]]);
	inc(b[s2[i]]);
  end;
  if f then inc(b[s2[k]])
  else inc(a[s1[k]]);
  if f then p:=length(s1)
  else p:=length(s2);
  for i:=k to p do
  begin
  begin
     if f then inc(a[s1[i]])
	 else inc(b[s2[i]]);
  end;
  end;
  f:=true;
  for i:=1 to 26 do
  begin
     p:=a[chr(i+ord('a')-1)];
	 for j:=1 to 26 do
	 begin
	    if (c[j]=false)and(b[chr(j+ord('a')-1)]=p) then 
		begin
		   c[j]:=true;
		   break;
		end;
		if j=26 then f:=false;
     end;
	 if f=false then begin writeln('No'); halt; end;
  end;
  writeln('Yes');
end.