Problem:
Score : 200 points

Problem Statement

A shop sells N kinds of fruits, Fruit 1, \ldots, N, at prices of p_1, \ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)

Here, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.

Constraints

1 \leq K \leq N \leq 1000

1 \leq p_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N K
p_1 p_2 \ldots p_N

Output

Print an integer representing the minimum possible total price of fruits.

Sample Input 1

5 3
50 100 80 120 80

Sample Output 1

210

This shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.

The minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.

Sample Input 2

1 1
1000

Sample Output 2

1000

Solution in Pascal (FPC 3.0.4) (judge verdict: Accepted)

program main;
type
  arr = array [1..1000] of longint;
 
var i, n, t, sum : longint;
    juice : arr;

procedure bubble_sort (var number : arr);
var
  i, t : integer;
  swap : boolean = true;

begin
  while swap do begin
    swap := false;
    for i := 1 to (n-1) do 
      if (number[i] > number[i+1]) then begin  //ascending order
      {if (number[i] < number[i+1]) then begin  //descending order}
        t := number[i];
  	   number[i] := number[i+1];
		   number[i+1] := t;
 	   swap := true;
      end;
  end;
end;

 
begin
  read(n);
  readln(t);
  for i := 1 to n do
    read(juice[i]);
  readln;
  bubble_sort(juice);
  sum := 0;
  for i := 1 to t do
    sum := sum + juice[i];
  writeln(sum);
end.