Problem:
Score : 300 points

Problem Statement

You are given an integer sequence of length n, a_1, ..., a_n.
Let us consider performing the following n operations on an empty sequence b.

The i-th operation is as follows:

Append a_i to the end of b.

Reverse the order of the elements in b.

Find the sequence b obtained after these n operations.

Constraints

1 \leq n \leq 2\times 10^5

0 \leq a_i \leq 10^9

n and a_i are integers.

Input

Input is given from Standard Input in the following format:

n
a_1 a_2 ... a_n

Output

Print n integers in a line with spaces in between.
The i-th integer should be b_i.

Sample Input 1

4
1 2 3 4

Sample Output 1

4 2 1 3

After step 1 of the first operation, b becomes: 1.

After step 2 of the first operation, b becomes: 1.

After step 1 of the second operation, b becomes: 1, 2.

After step 2 of the second operation, b becomes: 2, 1.

After step 1 of the third operation, b becomes: 2, 1, 3.

After step 2 of the third operation, b becomes: 3, 1, 2.

After step 1 of the fourth operation, b becomes: 3, 1, 2, 4.

After step 2 of the fourth operation, b becomes: 4, 2, 1, 3.

Thus, the answer is 4 2 1 3.

Sample Input 2

3
1 2 3

Sample Output 2

3 1 2

As shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.

Sample Input 3

1
1000000000

Sample Output 3

1000000000

Sample Input 4

6
0 6 7 6 7 0

Sample Output 4

0 6 6 0 7 7

Solution in Pascal (FPC 2.6.2) (judge verdict: Wrong Answer)

program ec12;
var 
	a:array[1..200001] of longint;
	s,s1:ansistring;
	n,m,i,j,dis:longint;
begin 
	readln(n);
	for i:=1 to n do 
	read(a[i]);
	s:='';
	dis:=1;
	for i:=1 to n*2 do 
	begin
		if i mod 2=1 then 
		begin 
			if dis=1 then 
			begin 
				str(a[i div 2+1],s1);
				s:=s+s1;
			end
			else
			begin 
				str(a[i div 2+1],s1);
				s:=s1+s;
			end;
		end
		else
		dis:=3-dis;
	end;
	if dis=1 then 
	begin 
		for i:=1 to length(s) do 
		write(s[i],' ');
	end
	else
	begin 
		for i:=length(s) downto 1 do 
		write(s[i],' ');
	end;
end.