Problem:
Score : 400 points

Problem Statement

We have a grid with H rows and W columns of squares.
Snuke is painting these squares in colors 1, 2, ..., N.
Here, the following conditions should be satisfied:

For each i (1 ≤ i ≤ N), there are exactly a_i squares painted in Color i. Here, a_1 + a_2 + ... + a_N = H W.

For each i (1 ≤ i ≤ N), the squares painted in Color i are 4-connected. That is, every square painted in Color i can be reached from every square painted in Color i by repeatedly traveling to a horizontally or vertically adjacent square painted in Color i.

Find a way to paint the squares so that the conditions are satisfied.
It can be shown that a solution always exists.

Constraints

1 ≤ H, W ≤ 100

1 ≤ N ≤ H W

a_i ≥ 1

a_1 + a_2 + ... + a_N = H W

Input

Input is given from Standard Input in the following format:

H W
N
a_1 a_2 ... a_N

Output

Print one way to paint the squares that satisfies the conditions.
Output in the following format:

c_{1 1} ... c_{1 W}
:
c_{H 1} ... c_{H W}

Here, c_{i j} is the color of the square at the i-th row from the top and j-th column from the left.

Sample Input 1

2 2
3
2 1 1

Sample Output 1

1 1
2 3

Below is an example of an invalid solution:

1 2
3 1

This is because the squares painted in Color 1 are not 4-connected.

Sample Input 2

3 5
5
1 2 3 4 5

Sample Output 2

1 4 4 4 3
2 5 4 5 3
2 5 5 5 3

Sample Input 3

1 1
1
1

Sample Output 3

1

Solution in Pascal (FPC 2.6.2) (judge verdict: Accepted)

var
	i,j,h,w,n,a,c,t:Longint;
	u:array[1..100]of Longint;
begin
	t:=1;
	read(h,w,n,a);
	if h*w=n then begin
		for i:=1 to h do begin
			if i mod 2=1 then begin
				for j:=1 to w do begin
					writeln(t);
					inc(t);
				end;
			end else begin
				for j:=w downto 1 do begin
					u[j]:=t;
					inc(t);
				end;
				for j:=1 to w do writeln(u[j]);
			end;
		end;
		exit;
	end;
	for i:=1 to h do begin
		if i mod 2=1 then begin
			for j:=1 to w do begin
				writeln(t);
				inc(c);
				if a=c then begin
					read(a);
					c:=0;
					inc(t);
				end;
			end;
		end else begin
			for j:=w downto 1 do begin
				u[j]:=t;
				inc(c);
				if a=c then begin
					read(a);
					c:=0;
					inc(t);
				end;
			end;
			for j:=1 to w do writeln(u[j]);
		end;
	end;
end.