Problem:
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Maximum Profit

You can obtain profits from foreign exchange margin transactions. For example, if you buy 1000 dollar at a rate of 100 yen per dollar, and sell them at a rate of 108 yen per dollar, you can obtain (108 - 100) × 1000 = 8000 yen.

Write a program which reads values of a currency $R_t$ at a certain time $t$ ($t = 0, 1, 2, ... n-1$), and reports the maximum value of $R_j - R_i$ where $j > i$ .

Input

The first line contains an integer $n$. In the following $n$ lines, $R_t$ ($t = 0, 1, 2, ... n-1$) are given in order.

Output

Print the maximum value in a line.

Constraints

$2 \leq n \leq 200,000$

$1 \leq R_t \leq 10^9$

Sample Input 1

6
5
3
1
3
4
3

Sample Output 1

3

Sample Input 2

3
4
3
2

Sample Output 2

-1

Solution in OCaml (judge verdict: Accepted)

let () =
  let m = Scanf.scanf "%d\n" (fun x -> x) in
  let minv = ref (Scanf.scanf "%d\n" (fun x -> x)) in
  let n, d = Scanf.scanf "%d\n" (fun x -> x , x - !minv) in
  let maxv = ref d in
  if n < !minv then minv := n else ();
  for i = 1 to m - 2 do
    let num, diff = Scanf.scanf "%d\n" (fun x -> x, x - !minv) in
    if !maxv < diff then maxv := diff else ();
    if num < !minv then minv := num else ();
  done;
  Printf.printf "%d\n" !maxv;;