Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in OCaml (4.10.0) (judge verdict: Runtime Error)

let () =
  let num_card =
    Array.init 3 @@ fun _ ->
      Array.init 3 @@ fun _ ->
        Scanf.scanf " %d" @@ Fun.id in
  let mark = Array.make_matrix 3 3 false in
  Scanf.scanf "%d\n" @@ fun n ->
    for i = 0 to n - 1 do
      Scanf.scanf "%d\n" @@ fun b ->
        for i = 0 to 2 do
          for j = 0 to 2 do
            if num_card.(i).(j) = b then mark.(i).(j) <- true
          done
        done
    done;
    print_endline @@
    if
      mark.(0) = [| true; true; true |] ||
      mark.(1) = [| true; true; true |] ||
      mark.(2) = [| true; true; true |] ||
      Array.init 3 (fun i -> mark.(i).(0)) = [| true; true; true |] ||
      Array.init 3 (fun i -> mark.(i).(1)) = [| true; true; true |] ||
      Array.init 3 (fun i -> mark.(i).(2)) = [| true; true; true |] ||
      Array.init 3 (fun i -> mark.(i).(i)) = [| true; true; true |] ||
      Array.init 3 (fun i -> mark.(2-i).(i)) = [| true; true; true |]
    then "Yes"
    else "No"