Problem:
Score : 200 points

Problem Statement

Alice and Bob are controlling a robot. They each have one switch that controls the robot.

Alice started holding down her button A second after the start-up of the robot, and released her button B second after the start-up.

Bob started holding down his button C second after the start-up, and released his button D second after the start-up.

For how many seconds both Alice and Bob were holding down their buttons?

Constraints

0≤A<B≤100

0≤C<D≤100

All input values are integers.

Input

Input is given from Standard Input in the following format:

A B C D

Output

Print the length of the duration (in seconds) in which both Alice and Bob were holding down their buttons.

Sample Input 1

0 75 25 100

Sample Output 1

50

Alice started holding down her button 0 second after the start-up of the robot, and released her button 75 second after the start-up.

Bob started holding down his button 25 second after the start-up, and released his button 100 second after the start-up.

Therefore, the time when both of them were holding down their buttons, is the 50 seconds from 25 seconds after the start-up to 75 seconds after the start-up.

Sample Input 2

0 33 66 99

Sample Output 2

0

Alice and Bob were not holding their buttons at the same time, so the answer is zero seconds.

Sample Input 3

10 90 20 80

Sample Output 3

60

Solution in OCaml (4.02.3) (judge verdict: Wrong Answer)

let main () = Scanf.sscanf (read_line ()) "%d %d %d %d"
  (fun a b c d -> print_int(if b < c || d < a then 0
    else if b = c then d-a
    else if a = d then b-c
    else if b = d && a < c then d-c 
    else if b = d && a > c then d-a
    else if a = c && b < d then c-b
    else if a = c && b > d then c-d
    else if a < c && b > d then d-c
    else if a > c && d > b then b-a
    else if a < c && b < d then (((b-a)+(d-c)) -(d-a)) else (((b-a)+(d-c)) -(b-c))))
let _ = main()