Problem:
Score : 200 points

Problem Statement

Takahashi is standing on a two-dimensional plane, facing north. Find the minimum positive integer K such that Takahashi will be at the starting position again after he does the following action K times:

Go one meter in the direction he is facing. Then, turn X degrees counter-clockwise.

Constraints

1 \leq X \leq 179

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the number of times Takahashi will do the action before he is at the starting position again.

Sample Input 1

90

Sample Output 1

4

Takahashi's path is a square.

Sample Input 2

1

Sample Output 2

360

Solution in OCaml (4.10.0) (judge verdict: Accepted)

Scanf.scanf "%d" (fun x ->
    let rec gcd a b = if b = 0 then a else gcd b (a mod b) in
    let lcm a b = a / gcd a b * b in

    let q = lcm x 360 in
    Printf.printf "%d\n" @@ q / x
)