Problem:
Score : 200 points

Problem Statement

Takahashi is standing on a two-dimensional plane, facing north. Find the minimum positive integer K such that Takahashi will be at the starting position again after he does the following action K times:

Go one meter in the direction he is facing. Then, turn X degrees counter-clockwise.

Constraints

1 \leq X \leq 179

X is an integer.

Input

Input is given from Standard Input in the following format:

X

Output

Print the number of times Takahashi will do the action before he is at the starting position again.

Sample Input 1

90

Sample Output 1

4

Takahashi's path is a square.

Sample Input 2

1

Sample Output 2

360

Solution in OCaml (4.10.0) (judge verdict: Accepted)

let rec gcd n m =
  if m = 0 then n else gcd m (n mod m)

let () = Scanf.scanf "%d\n" @@ fun x ->
  Printf.printf "%d\n" @@ 360 / gcd 360 x