Problem:
Score : 200 points

Problem Statement

Our world is one-dimensional, and ruled by two empires called Empire A and Empire B.

The capital of Empire A is located at coordinate X, and that of Empire B is located at coordinate Y.

One day, Empire A becomes inclined to put the cities at coordinates x_1, x_2, ..., x_N under its control, and Empire B becomes inclined to put the cities at coordinates y_1, y_2, ..., y_M under its control.

If there exists an integer Z that satisfies all of the following three conditions, they will come to an agreement, but otherwise war will break out.

X < Z \leq Y

x_1, x_2, ..., x_N < Z

y_1, y_2, ..., y_M \geq Z

Determine if war will break out.

Constraints

All values in input are integers.

1 \leq N, M \leq 100

-100 \leq X < Y \leq 100

-100 \leq x_i, y_i \leq 100

x_1, x_2, ..., x_N \neq X

x_i are all different.

y_1, y_2, ..., y_M \neq Y

y_i are all different.

Input

Input is given from Standard Input in the following format:

N M X Y
x_1 x_2 ... x_N
y_1 y_2 ... y_M

Output

If war will break out, print War; otherwise, print No War.

Sample Input 1

3 2 10 20
8 15 13
16 22

Sample Output 1

No War

The choice Z = 16 satisfies all of the three conditions as follows, thus they will come to an agreement.

X = 10 < 16 \leq 20 = Y

8, 15, 13 < 16

16, 22 \geq 16

Sample Input 2

4 2 -48 -1
-20 -35 -91 -23
-22 66

Sample Output 2

War

Sample Input 3

5 3 6 8
-10 3 1 5 -100
100 6 14

Sample Output 3

War

Solution in OCaml (4.02.3) (judge verdict: Accepted)

let rec check num min_num x y =
  if num = min_num then "War"
  else if x < num && num <= y then "No War"
  else check (num-1) min_num x y
let () =
  let (n, m, x, y) = Scanf.scanf "%d %d %d %d\n" (fun a b c d -> (a, b, c, d)) in
  let xlst = Array.to_list (Array.init n (fun _ -> Scanf.scanf "%d " (fun x -> x))) in
  let ylst = Array.to_list (Array.init m (fun _ -> Scanf.scanf "%d " (fun x -> x))) in
  let max_x = List.fold_left max min_int xlst in
  let min_y = List.fold_left min max_int ylst in
  Printf.printf "%s\n" (check y (x+1) max_x min_y)