Problem:
Score : 300 points

Problem Statement

The commonly used bills in Japan are 10000-yen, 5000-yen and 1000-yen bills. Below, the word "bill" refers to only these.

According to Aohashi, he received an otoshidama (New Year money gift) envelope from his grandfather that contained N bills for a total of Y yen, but he may be lying. Determine whether such a situation is possible, and if it is, find a possible set of bills contained in the envelope. Assume that his grandfather is rich enough, and the envelope was large enough.

Constraints

1 ≤ N ≤ 2000

1000 ≤ Y ≤ 2 × 10^7

N is an integer.

Y is a multiple of 1000.

Input

Input is given from Standard Input in the following format:

N Y

Output

If the total value of N bills cannot be Y yen, print -1 -1 -1.

If the total value of N bills can be Y yen, let one such set of bills be "x 10000-yen bills, y 5000-yen bills and z 1000-yen bills", and print x, y, z with spaces in between. If there are multiple possibilities, any of them may be printed.

Sample Input 1

9 45000

Sample Output 1

4 0 5

If the envelope contained 4 10000-yen bills and 5 1000-yen bills, he had 9 bills and 45000 yen in total. It is also possible that the envelope contained 9 5000-yen bills, so the output 0 9 0 is also correct.

Sample Input 2

20 196000

Sample Output 2

-1 -1 -1

When the envelope contained 20 bills in total, the total value would be 200000 yen if all the bills were 10000-yen bills, and would be at most 195000 yen otherwise, so it would never be 196000 yen.

Sample Input 3

1000 1234000

Sample Output 3

14 27 959

There are also many other possibilities.

Sample Input 4

2000 20000000

Sample Output 4

2000 0 0

Solution in OCaml (4.02.3) (judge verdict: Accepted)

(* O(n) *)
let find_fold_int f a n =
  let rec find a i =
    if i >= n then
      a, false
    else
      let (res, detected) as r = f a i in
        if detected then r else find res (i + 1)
  in
    find a 0

(* O(n^2) *)
let solve n y =
  find_fold_int
    (fun sofar_a a ->
      find_fold_int
        (fun sofar_b b ->
          let c = n - a - b in
          if 10000 * a + 5000 * b + 1000 * c = y then
            (a, b, c), true
          else
            sofar_b, false)
        sofar_a
        (n - a + 1))
    (-1, -1, -1)
    (n + 1) |> fst

let read_ints () = read_line () |> Str.split (Str.regexp " ") |> List.map int_of_string

let _ =
  match read_ints () with
  | [n; y] -> let (a, b, c) = solve n y in Printf.printf "%d %d %d\n" a b c
  | _ -> ()