Problem:
Search III

Your task is to write a program of a simple dictionary which implements the following instructions:

insert str: insert a string str in to the dictionary

find str: if the distionary contains str, then print 'yes', otherwise print 'no'

Input

In the first line n, the number of instructions is given. In the following n lines, n instructions are given in the above mentioned format.

Output

Print yes or no for each find instruction in a line.

Constraints

A string consists of 'A', 'C', 'G', or 'T'

1 ≤ length of a string ≤ 12

n ≤ 1000000

Sample Input 1

5
insert A
insert T
insert C
find G
find A

Sample Output 1

no
yes

Sample Input 2

13
insert AAA
insert AAC
insert AGA
insert AGG
insert TTT
find AAA
find CCC
find CCC
insert CCC
find CCC
insert T
find TTT
find T

Sample Output 2

yes
no
no
yes
yes
yes

Notes

Template in C

Solution in OCaml (judge verdict: Accepted)

let m = 950527

let to_key s =
  let char_to_x c =
    if c = 'A' then 1
    else if c = 'C' then 2
    else if c = 'G' then 3
    else if c = 'T' then 4
    else 0 in
  let n = String.length s in
  let rec doit i p acc =
    if i = n then acc
    else doit (i + 1) (5*p) (acc + p*(char_to_x s.[i])) in
  doit 0 1 0

let to_h1 k = k mod m
let to_h2 k = 1 + (k mod (m - 1))

let insert s t =
  let k = to_key s in
  let h1 = to_h1 k in
  let h2 = to_h2 k in
  let rec doit i =
    let h = (h1 + h2*i) mod m in
    if t.(h) = s then ()
    else if t.(h) = "\000" then t.(h) <- s
    else doit (i + 1) in
  doit 0

let find s t =
  let k = to_key s in
  let h1 = to_h1 k in
  let h2 = to_h2 k in
  let rec doit i =
    let h = (h1 + h2*i) mod m in
    if t.(h) = s then true
    else if t.(h) = "\000" then false
    else doit (i + 1) in
  doit 0

let () =
  let n = read_int () in
  let t = Array.make m "\000" in
  let rec doit i =
    if i < n then begin
      begin match Str.split (Str.regexp " ") (read_line ()) with
      | ["insert"; s] -> insert s t
      | ["find"; s] -> print_endline (if find s t then "yes" else "no")
      | _ -> ()
      end;
      doit (i + 1)
    end in
  doit 0