Problem:
Score : 200 points

Problem Statement

Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print -1 instead.

Constraints

2 \leq N \leq 10^5

0 \leq A_i \leq 10^{18}

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
A_1 ... A_N

Output

Print the value A_1 \times ... \times A_N as an integer, or -1 if the value exceeds 10^{18}.

Sample Input 1

2
1000000000 1000000000

Sample Output 1

1000000000000000000

We have 1000000000 \times 1000000000 = 1000000000000000000.

Sample Input 2

3
101 9901 999999000001

Sample Output 2

-1

We have 101 \times 9901 \times 999999000001 = 1000000000000000001, which exceeds 10^{18}, so we should print -1 instead.

Sample Input 3

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0

Sample Output 3

0

Solution in OCaml (4.10.0) (judge verdict: Wrong Answer)

open Scanf
open Printf
open Big_int

let multiplication lst =
  let rec loop total l = match l with
      [] -> total
    | first :: rest -> if gt_big_int (mult_big_int (big_int_of_int first) (big_int_of_int total))
                                     (big_int_of_int 1_000_000_000_000_000_000) then -1
                       else loop (first * total) rest
  in loop 1 lst

let n = sscanf (read_line ()) "%d" (fun n -> n)
let a_list = List.map (fun n -> int_of_string n) (String.split_on_char ' ' (read_line ()))
let () = printf "%d\n" (multiplication a_list)