Problem:
Score : 200 points

Problem Statement

We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.

The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.

Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.

Constraints

All values in input are integers.

1 \leq A_{i, j} \leq 100

A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))

1 \leq N \leq 10

1 \leq b_i \leq 100

b_i \neq b_j (i \neq j)

Input

Input is given from Standard Input in the following format:

A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N

Output

If we will have a bingo, print Yes; otherwise, print No.

Sample Input 1

84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30

Sample Output 1

Yes

We will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.

Sample Input 2

41 7 46
26 89 2
78 92 8
5
6
45
16
57
17

Sample Output 2

No

We will mark nothing.

Sample Input 3

60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34

Sample Output 3

Yes

We will mark all the squares.

Solution in OCaml (4.02.3) (judge verdict: Runtime Error)

open Array
let () =
  let arr = List.concat (to_list (init 3 @@ fun _ -> Scanf.scanf "%d %d %d\n" @@ fun a b c -> [a; b; c])) in
  let n = read_int () in
  let brr = Array.init n @@ fun _ -> Scanf.scanf "%d\n" @@ fun d -> d in
  let check = Array.make_matrix 3 3 false in
  for i = 0 to n-1 do
    let x = brr.(i) in
    if List.mem x arr then List.iteri (fun i a -> if a = x then check.(i / 3).(i mod 3) <- true) arr
  done;
  let ans = ref false in
  for i = 0 to 2 do
    if check.(i).(0) && check.(i).(1) && check.(i).(2) then ans := true (* 横 *)
    else if check.(0).(i) && check.(1).(i) && check.(2).(i) then ans := true (* たて *)
  done;
  if check.(0).(0) && check.(1).(1) && check.(2).(2) then ans := true;
  if check.(0).(2) && check.(1).(1) && check.(2).(0) then ans := true;
  print_endline (if !ans then "Yes" else "No")