Problem:
Score : 500 points

Problem Statement

There is a rooted tree (see Notes) with N vertices numbered 1 to N.
Each of the vertices, except the root, has a directed edge coming from its parent.
Note that the root may not be Vertex 1.

Takahashi has added M new directed edges to this graph.
Each of these M edges, u \rightarrow v, extends from some vertex u to its descendant v.

You are given the directed graph with N vertices and N-1+M edges after Takahashi added edges.
More specifically, you are given N-1+M pairs of integers, (A_1, B_1), ..., (A_{N-1+M}, B_{N-1+M}), which represent that the i-th edge extends from Vertex A_i to Vertex B_i.

Restore the original rooted tree.

Notes

For "tree" and other related terms in graph theory, see the article in Wikipedia, for example.

Constraints

3 \leq N

1 \leq M

N + M \leq 10^5

1 \leq A_i, B_i \leq N

A_i \neq B_i

If i \neq j, (A_i, B_i) \neq (A_j, B_j).

The graph in input can be obtained by adding M edges satisfying the condition in the problem statement to a rooted tree with N vertices.

Input

Input is given from Standard Input in the following format:

N M
A_1 B_1
:
A_{N-1+M} B_{N-1+M}

Output

Print N lines.
In the i-th line, print 0 if Vertex i is the root of the original tree, and otherwise print the integer representing the parent of Vertex i in the original tree.

Note that it can be shown that the original tree is uniquely determined.

Sample Input 1

3 1
1 2
1 3
2 3

Sample Output 1

0
1
2

The graph in this input is shown below:

It can be seen that this graph is obtained by adding the edge 1 \rightarrow 3 to the rooted tree 1 \rightarrow 2 \rightarrow 3.

Sample Input 2

6 3
2 1
2 3
4 1
4 2
6 1
2 6
4 6
6 5

Sample Output 2

6
4
2
0
6
2

Solution in OCaml (4.02.3) (judge verdict: Time Limit Exceeded)


let rec fix f x = f (fix f) x;;
Scanf.(Array.(scanf " %d %d" @@ fun n m ->
  let e = make n [] in
  let e_rev = make n [] in
  init (n-1+m) (fun i -> scanf " %d %d" @@ fun u v ->
    let u,v = u-1,v-1 in
    e.(u) <- v :: e.(u);
    e_rev.(v) <- u :: e_rev.(v)
  ) |> ignore;
  let root = fst @@ fold_left (fun (root,i) ls ->
    (if List.length ls = 0 then i else root),i+1
  ) (0,0) e_rev in
  let dep = make n (-7) in
  fix (fun f i d ->
    if dep.(i) < d then (
      dep.(i) <- max dep.(i) d;
      List.iter (fun j ->
        f j (d+1)
      ) e.(i)
    )
  ) root 0;
  (* iteri (fun i d -> Printf.printf "%d: %d\n" i d) dep; *)
  let res = make n 0 in
  let done_ = make n false in
  fix (fun f i d ->
    List.iter (fun j ->
      if done_.(j) then ()
      else (
        if dep.(j) = d + 1 then (
          res.(j) <- i + 1;
          done_.(j) <- true;
        );
        f j (d+1)
      )
    ) e.(i)
  ) root 0;
  res.(root) <- 0;
  iter (fun d -> Printf.printf "%d\n" d) res;
));;