Problem:
Score : 100 points

Problem Statement

You are parking at a parking lot. You can choose from the following two fee plans:

Plan 1: The fee will be A×T yen (the currency of Japan) when you park for T hours.

Plan 2: The fee will be B yen, regardless of the duration.

Find the minimum fee when you park for N hours.

Constraints

1≤N≤20

1≤A≤100

1≤B≤2000

All input values are integers.

Input

Input is given from Standard Input in the following format:

N A B

Output

When the minimum fee is x yen, print the value of x.

Sample Input 1

7 17 120

Sample Output 1

119

If you choose Plan 1, the fee will be 7×17=119 yen.

If you choose Plan 2, the fee will be 120 yen.

Thus, the minimum fee is 119 yen.

Sample Input 2

5 20 100

Sample Output 2

100

The fee might be the same in the two plans.

Sample Input 3

6 18 100

Sample Output 3

100

Solution in OCaml (4.02.3) (judge verdict: Accepted)

module A = Array
module C = Char
module I = Int64
module L = List
module Q = Queue

let pf = Printf.printf
let sf = Scanf.scanf
let ssf = Scanf.sscanf

let read_int () = sf "%d " (fun x -> x)
let read_float () = sf "%f " (fun x -> x)
let read_str () = sf "%s " (fun x -> x)
let read_array n read () = A.init n (fun _ -> read ())
let err s = raise (Failure s)

let range s t = A.init (t - s) @@ (+) s
let foreach fold_f init s t map_f =
  range s t |> A.map map_f |> A.fold_left fold_f init

let inf = int_of_float 1e18
let eps = 1e-11

module S = struct
  include String
  let of_array a = String.init (A.length a) (A.get a)
  let to_array s = A.init (String.length s) (String.get s)
end;;

let () =
  let n = read_int () in
  let a = read_int () in
  let b = read_int () in
  let res = min (n * a) b in
  pf "%d\n" res